CN109714818A - Power distribution method in single cell NOMA system - Google Patents
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Abstract
The invention discloses the power distribution method in a kind of single cell NOMA system, be suitable for include 1 base station andMKThe downlink NOMA system of a user, base station and user configure single antenna.Orthogonal frequency sub-band is distributed by user's sub-clustering and for user's cluster in base station, minimum general power needed for base station calculates when meeting serial interference elimination minimum general power needed for each cluster and system according to channel condition base station, using lowest power needed for single cluster as constraint condition, calculate all users in the cluster rate it is all identical when for each user distribution power and the cluster general power between relationship, based on this result, minimum general power needed for using system is solved as constraint conditionMKIt is the power of each cluster distribution when the rate of a user is all identical, is finally each user's distribution power in each cluster.
Description
Technical field
The invention belongs to the power distribution methods in the communications field more particularly to a kind of single cell NOMA system.
Background technique
Non-orthogonal multiple access (Non-Orthogonal Multiple Access, NOMA) technology is the key technology of 5G
One of, throughput of system with higher and spectrum efficiency are able to satisfy the explosive growth of wireless data service amount.NOMA technology
Transmitting terminal be user's distribution power and by their signal multiplexing on same running time-frequency resource, actively introduce multi-access inference, connect
Receiving end eliminates interference simultaneously by serial interference elimination (Successive Interference Cancellation, SIC) technology
Detection expectation received signal.Power distribution is not only related to the detection order of each subscriber signal, also affects the reliable of system
Property and validity, therefore, the power distribution in NOMA system is one of research hotspot in recent years.
Many documents study power allocation scheme in single cell downlink NOMA system, wherein the mesh of power distribution
Mark is broadly divided into three classes: maximizing rate, maximum energy efficiency and maximum justice.Maximize rate power allocation scheme with
General power or the rate of single user can maximize all users using water-filling algorithm or the solution of other algorithms as constraint condition
And rate power distribution.The power allocation scheme of maximum energy efficiency also using general power or the rate of single user as
Constraint condition is the power of each user's distribution to maximize user's and rate and general power ratio as object solving.Document
“On optimal power allocation for downlink non-orthogonal multiple access
Systems ", which proposes maximum fair power allocation scheme, realizes user in rate so that the rate of all users is all identical
On fairness.However, the program, which is only limitted to each cluster, includes the scene of two users, and do not account for when meeting SIC
Constraint to system total power, it is possible to lead to not correctly detect signal.
Summary of the invention
The invention proposes the power distribution method in single cell NOMA system, it is suitable for including 1 base station and MK use
The single antenna downlink NOMA system at family and user and base station all configure single antenna.
Realizing technical thought of the invention is: orthogonal frequency sub-band, base station are distributed by user's sub-clustering and for user's cluster in base station
It is calculated according to channel condition base station when meeting serial interference elimination needed for minimum general power needed for each cluster and system most
Low general power, using lowest power needed for single cluster as constraint condition, calculate all users in the cluster rate it is all identical when
Relationship between the general power of the power and the cluster that are distributed for each user, based on this result, with minimum total work needed for system
Rate is the power of each cluster distribution when the rate of MK user of solution is all identical, finally in each cluster as constraint condition
Each user's distribution power.
In conclusion the power distribution method in a kind of list cell NOMA system, is suitable for including 1 base station and MK use
The single antenna downlink NOMA system at family and user and base station all configure single antenna, includes the following steps:
MK user is divided into K cluster by A, base station, and each cluster includes M user, and base station is that each cluster distributes a son frequency
Section, frequency sub-band is orthogonal between cluster；
B uses ukmIndicate m-th of user in k-th of cluster, k=1,2 ..., K, m=1,2 ..., M, base station to ukmLetter
Road is hkm, | hk1|2≥|hk2|2≥…≥|hkM|2, use r0To Signal to Interference plus Noise Ratio (Signal to when indicating correctly to detect signal
Interference and Noise Ratio, SINR) minimum requirements, base station is according to hkmAnd r0Calculating meets serial interference and disappears
U when except (Serial Interference Cancellation, SIC)kmRequired lowest power, uses pkm0It indicates, when m=1,When,σ2It is the noise side that user receives
Difference, K are the sums of cluster, and M is the number of users for including in each cluster；
C, base station calculate minimum general power p needed for k-th of cluster when meeting SICk0And minimum general power needed for system
Pmin, K is the sum of cluster, M
It is the number of users for including in each cluster；
D uses pkIndicate the general power of all users in k-th of cluster, k=1,2 ..., K enable pk≥pk0, pk0It is that step C is asked
Lowest power needed for k-th of the cluster obtained, using minimum general power needed for each cluster as constraint condition, base station is solved in the cluster
The relationship when rate of all users is all equal between the power of each user distribution and the general power of the cluster；
E uses pkThe general power for indicating all users in k-th of cluster, uses PmaxThe general power for indicating base station, enables Pmax≥Pmin,
PminMinimum general power needed for the system that step C is acquired, using system needed for minimum general power as constraint condition, base station
The relationship when rate of MK user of solution is all equal between the power and system total power of the distribution of each cluster；
F, by p obtained in step Ek' substitute into function fp obtained in step Dkm(pk), obtain fpkm(pk'), fpkm
(pk') it is exactly the power distributed for m-th of user in k-th of cluster, k=1,2 ..., K, m=1,2 ..., M, K are the total of cluster
Number, M is the number of users for including in each cluster.
Further, the step D is specifically included:
D1 uses pkmIt is expressed as ukmThe power of distribution, by pkIt is considered as known variables, by pkmIt is considered as known variables, base station solves
Equation group (1) obtains multiple groups solution, k=1,2 ..., K, m=1, and 2 ..., M, K are the sums of cluster, and M is the use for including in each cluster
Amount；
D2 selects p from the multiple groups solution that step D1 is obtainedk1、pk2、…、pkMIt is positive number and both less than pkOne group, use
Function fpkm(pk) indicate the p that solution formula (1) obtainskmWith pkRelationship, the function is related with the value of M, k=1,2 ..., K, m
=1,2 ..., M, K are the sums of cluster, and M is the number of users for including in each cluster.
Further, the step E is specifically included:
E1, by PmaxIt is considered as known variables, by pkIt is considered as known variables, base station solve system of equation (2) obtains multiple groups solution, k
=1,2 ..., K, K are the sums of cluster；
E2, the general power that each cluster is selected from the multiple groups solution that step E1 is obtained is positive number and both less than PmaxOne group
Solution, uses p1′、p2′、…、pK' indicate the group solution.
The utility model has the advantages that it includes any that maximum fair power allocation scheme is expanded to each cluster by method disclosed by the invention
The scene of user has derived the minimum general power needed for minimum general power and system needed for each cluster when meeting SIC,
While meeting SIC, fairness of the user in rate is realized.
Detailed description of the invention
Fig. 1 is the system model of the embodiment of the present invention；
Fig. 2 is flow chart of the invention.
Specific embodiment
A kind of embodiment of the invention is given below, the present invention will be further described in detail.As shown in Figure 1, considering
Downlink NOMA system comprising 1 base station and MK user, base station and user configure single antenna.User is divided into K cluster,
Each cluster includes M user, uses ukmIndicate m-th of user in k-th of cluster, k=1,2 ..., K, m=1,2 ..., M.Base station is arrived
ukmChannel be hkm, | hk1|2≥|hk2|2≥…≥|hkM|2.Base station is that the general power of k-th of cluster distribution is pk, wherein ukm's
Power is pkm, pk1≤pk2≤…≤pkM,Base station is that each cluster distributes a frequency sub-band, frequency sub-band between cluster
It is orthogonal.
Use ykmIndicate ukmReception signal, ykmExpression-form be
Wherein, xkmIt is ukmExpectation receive signal, nkmIt is ukmThe white Gaussian noise received, mean value are that zero variance is σ2。
uk1It carries out serial interference elimination (Successive Interference Cancellation, SIC), i.e., examines first
Measure xkM, and the signal is eliminated to yk1Caused by interfere, then detect x againk(M-1), and the signal is eliminated to yk1Caused by do
It disturbs, successively detect other signals and eliminates these signals to yk1Caused by interfere, until detect xk1。uk1Detect xkmWhen letter
Dry make an uproar be than (Signal to Interference and Noise Ratio, SINR)
Similarly, ukjDetect xkmWhen SINR be
Wherein, j≤m, m=1,2 ..., M, j=1,2 ..., M.
It is assumed that r0Minimum requirements when being correct detection signal to SINR, in order to execute SIC, ukjDetect xkmWhen SINR must
R must be not less than0, it is therefore desirable to which following formula is set up
Thus it can release, pkmValue meet
It enablesl(|hkj|2) yes | hkj|2Monotonic decreasing function.By
In | hk1|2≥|hk2|2≥…≥|hkM|2, as j=m, l (| hkj|2) reaching maximum value, i.e. formula (5) can turn to
The m=1 in formula (6) is enabled, p is obtainedk1Value range be
The m=2 in formula (6) is enabled, p is obtainedk2Value range be
The m=3 in formula (6) is enabled, p is obtainedk3Value range be
The m=4 in formula (6) is enabled, p is obtainedk4Value range be
It can be obtained using induction, m=2, when 3 ..., M, pkmValue meet following formula
Use pkm0Indicate ukmLowest power needed for carrying out SIC and correct detection desired signal.When m=1,When m=2,3 ..., M, pkm0Value be
It can be obtained by formula (12), as i < j, pki0<pkj0, i.e., in the same cluster, the channel gain of user is lower, required
Lowest power it is higher.Use pk0Indicate that all users in k-th of cluster carry out needed for SIC and correct detection desired signal most
Low general power, then pk0Value be
If the general power of k-th of cluster is lower than pk0, then it cannot be guaranteed that in the cluster SIC smooth execution, to can not correctly examine
Survey all desired signals.Use PminMinimum general power needed for system when expression meets SIC and correct detection desired signal,
PminValue be
Use RkjIndicate ukjUnit bandwidth rate, RkjIt is expressed as
The sum of the unit bandwidth rate of all users is in k-th of cluster
The sum of the unit bandwidth rate of MK user is in system
It is assumed that the general power P of base stationmax≥Pmin, otherwise not can guarantee the smooth execution of SIC in each cluster.With maximum fair
It is formulated for the power distribution of target are as follows:
Wherein, constraint condition C1 indicates that the general power of system is Pmax, constraint condition C2 indicates that the general power of single cluster cannot
Lower than lowest power needed for the cluster, constraint condition C3 is used to guarantee the smooth execution of SIC.
Solution formula (18) can obtain Pmax≥PminWhen maximum fair power distribution.However, the solution of formula (18) needs
All possible power distribution is traversed, complexity is high, considers maximum fair power distribution in single cluster first thus, then
Consider further that maximum fair power distribution between cluster.
It is assumed that the general power p of k-th of clusterkNot less than pk0, solve the clusterWith the cluster
General power pkBetween relationship, be expressed as with formula
Wherein, constraint condition C1 indicates lowest power needed for the general power of the cluster cannot be below the cluster, constraint condition C2
Indicate the condition that the power of each user of k-th of cluster when meeting SIC needs to meet.Known by the analysis of front, in formula (19)
Constraint condition C2 is expressed equivalently as
In the general power p of k-th of clusterkIn the case where remaining unchanged, increase pkjWhen, ukjRate increase and at least have one
The rate of a user reduces, so only working as Rk1=Rk2=...=RkMWhen, min { R could be maximizedkj, j=1,2 ..., M }.When
The general power of the cluster is pk0And the power of m-th of user is pkm0When, the rate of all users is identical in the cluster, each user's
Rate is log2(1+r0), if the general power of the cluster is more than or equal to pk0, then when the rate of all users is all identical, the speed of user
Rate is not less than log2(1+r0).Therefore, as m >=j, convolution (6) derivation can be obtained,To meet the constraint condition C2 in formula (19).
Rk1=Rk2=...=RkMIt is equivalent to formula (20) establishment
It considersFormula (20) is equivalent to following equation group
Solve equation group, can obtain all users in k-th of cluster rate it is equal when each user power, i.e.,
pk1、pk2、…、pkMWith pkRelationship.Specific formula is related with the value of M, and formula is longer, it is within the rule go out.It finds out
Solution has multiple groups, selects pk1、pk2、…、pkMIt is positive number and both less than pkOne group of solution as formula (19).With function fpkm(pk)
It indicates to solve the p that equation group obtainskmWith pkRelationship, the rate of all users is in the cluster at this time
After solving formula (19), formula (18) is equivalently represented to be
Wherein, constraint condition C1 indicates that the general power of system is Pmax, constraint condition C2 indicates the power constraint of single cluster.
The power distribution of MK user is sought in formula (18), the power distribution of K cluster is sought in formula (22), and formula (22) is the simplification table of formula (18)
Up to form.
In general power PmaxIn the case where remaining unchanged, pkWhen increase, k-th cluster
It will increase, but the maximum value at least having user's minimum speed limit in a cluster reduces, so only when the rate phase of all users
Meanwhile the minimum value of all user rates could be maximized, the rate of all users of all clusters is all equal at this time.It can be by asking
Equation group in solution formula (23) obtain all users rate it is all equal when power distribution.
Solve system of equation (23), can obtain multiple groups solution, and the general power for therefrom selecting each cluster is positive number and both less than Pmax
One group of solution, use p1′、p2′、…、pK' indicate the group solution.By pk' bring fp intokm(pk) obtained value is exactly in k-th of cluster
The power of m-th of user distribution, k=1,2 ..., K, m=1,2 ..., M, the power distribution can make the rate of MK user all
It is identical.
In conjunction with flow chart, that is, Fig. 2 of the invention, maximum fair power distribution method is specific in Dan little Qu NOMA system
Steps are as follows:
MK user is divided into K cluster by A, base station, and each cluster includes M user, and base station is that each cluster distributes a son frequency
Section, frequency sub-band is orthogonal between cluster；
B uses ukmIndicate m-th of user in k-th of cluster, k=1,2 ..., K, m=1,2 ..., M, base station to ukmLetter
Road is hkm, | hk1|2≥|hk2|2≥…≥|hkM|2, use r0To Signal to Interference plus Noise Ratio (Signal to when indicating correctly to detect signal
Interference and Noise Ratio, SINR) minimum requirements, base station is according to hkmAnd r0Calculating meets serial interference and disappears
U when except (Serial Interference Cancellation, SIC)kmRequired lowest power, uses pkm0It indicates, when m=1,When,σ2It is the noise side that user receives
Difference, K are the sums of cluster, and M is the number of users for including in each cluster；
C, base station calculate minimum general power p needed for k-th of cluster when meeting SICk0And minimum general power needed for system
Pmin, K is the sum of cluster, M
It is the number of users for including in each cluster；
D uses pkIndicate the general power of all users in k-th of cluster, k=1,2 ..., K enable pk≥pk0, pk0It is that step C is asked
Lowest power needed for k-th of the cluster obtained, using minimum general power needed for each cluster as constraint condition, base station is solved in the cluster
The relationship when rate of all users is all equal between the power of each user distribution and the general power of the cluster；
E uses pkThe general power for indicating all users in k-th of cluster, uses PmaxThe general power for indicating base station, enables Pmax≥Pmin,
PminMinimum general power needed for the system that step C is acquired, using system needed for minimum general power as constraint condition, base station
The relationship when rate of MK user of solution is all equal between the power and system total power of the distribution of each cluster；
F, by p obtained in step Ek' substitute into function fp obtained in step Dkm(pk), obtain fpkm(pk'), fpkm
(pk') it is exactly the power distributed for m-th of user in k-th of cluster, k=1,2 ..., K, m=1,2 ..., M, K are the total of cluster
Number, M is the number of users for including in each cluster.
Above embodiments are only to of the invention for example, those skilled in the art can carry out respectively the present invention
Kind modification and variation is without departing from the spirit and scope of the present invention.In this way, if these modifications and changes of the present invention belongs to this
Within the scope of invention claim and its equivalent technologies, then the present invention is also intended to include these modifications and variations.
Claims (1)
1. the power distribution method in single cell NOMA system, suitable for the single antenna downlink including 1 base station and MK user
NOMA system and user and base station all configure single antenna, characterized by the following steps:
MK user is divided into K cluster by A, base station, and each cluster includes M user, and base station is that each cluster distributes a frequency sub-band, cluster
Between frequency sub-band it is orthogonal；
B uses ukmIndicate m-th of user in k-th of cluster, k=1,2 ..., K, m=1,2 ..., M, base station to ukmChannel be
hkm, | hk1|2≥|hk2|2≥…≥|hkM|2, use r0To Signal to Interference plus Noise Ratio (Signal to when indicating correctly to detect signal
Interference and Noise Ratio, SINR) minimum requirements, base station is according to hkmAnd r0Calculating meets serial interference and disappears
U when except (Serial Interference Cancellation, SIC)kmRequired lowest power, uses pkm0It indicates, when m=1,When,σ2It is the noise that user receives
Variance, K are the sums of cluster, and M is the number of users for including in each cluster；
C, base station calculate minimum general power p needed for k-th of cluster when meeting SICk0And minimum general power P needed for systemmin, K is cluster
Sum, M are the number of users for including in each cluster；
D uses pkIndicate the general power of all users in k-th of cluster, k=1,2 ..., K enable pk≥pk0, pk0It is that step C is acquired
Lowest power needed for k-th of cluster, using minimum general power needed for each cluster as constraint condition, base station, which solves in the cluster, to be owned
The relationship when rate of user is all equal between the power of each user distribution and the general power of the cluster, detailed process is as follows:
D1 uses pkmIt is expressed as ukmThe power of distribution, by pkIt is considered as known variables, by pkmIt is considered as known variables, base station solves equation
Group (1) obtains multiple groups solution, k=1,2 ..., K, m=1, and 2 ..., M, K are the sums of cluster, and M is the number of users for including in each cluster；
D2 selects p from the multiple groups solution that step D1 is obtainedk1、pk2、…、pkMIt is positive number and both less than pkOne group, use function
fpkm(pk) indicate the p that solution formula (1) obtainskmWith pkRelationship, the function is related with the value of M, k=1,2 ..., K, m=1,
2 ..., M, K are the sums of cluster, and M is the number of users for including in each cluster；
E uses pkThe general power for indicating all users in k-th of cluster, uses PmaxThe general power for indicating base station, enables Pmax≥Pmin, PminIt is
Minimum general power needed for the system that step C is acquired, using system needed for minimum general power as constraint condition, base station solves MK
The relationship when rate of a user is all equal between the power and system total power of the distribution of each cluster, detailed process is as follows,
E1, by PmaxIt is considered as known variables, by pkIt is considered as known variables, base station solve system of equation (2) obtains multiple groups solution, k=1,
2 ..., K, K are the sums of cluster；
E2, the general power that each cluster is selected from the multiple groups solution that step E1 is obtained is positive number and both less than PmaxOne group of solution, use
p1′、p2′、…、pK' indicate the group solution；
F, by p obtained in step Ek' substitute into function fp obtained in step Dkm(pk), obtain fpkm(pk'), fpkm(pk') be exactly
For the power of m-th of user distribution in k-th of cluster, k=1,2 ..., K, m=1,2 ..., M, K are the sums of cluster, and M is each
The number of users for including in cluster.
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