CN109191345A - A kind of cognitive diagnosis method of Student oriented cognitive process - Google Patents
A kind of cognitive diagnosis method of Student oriented cognitive process Download PDFInfo
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Abstract
The invention discloses a kind of cognitive diagnosis methods of Student oriented cognitive process, comprising the following steps: the cognitive diagnosis analysis of the representing multiple graininess model of building knowledge point and exercise, the school work state table representation model for constructing student's node, student's node.The school work state that the present invention can use the more granularity earth's surface dendrographies of the method for knowledge mapping raw corresponds to the Grasping level of knowledge point according to the answer situation analysis student of student so as to be in different cognitive processes for student.
Description
Technical field
The present invention relates to educational data excavation applications, in particular to more granularities cognition of a kind of Student oriented cognitive process is examined
Disconnected method.
Background technique
With the development for admiring the open educational resources platform such as class, " internet+education " is promoted to obtain the height of State-level
Degree concern and attention.That educational researcher passes through cognitive diagnosis (Cognitive Diagnosis) quantitative assessment student
Property difference and human-subject test.There are the magnanimity learning datas of student on internet, and know involved by most of topics
Know point and all shows different granularity levels.In the cognitive process of student, student knows grasp in the different study stages
The granularity layers time requirement for knowing point is also different.
Therefore, by analyzing real-time learning data, real-time tracking is carried out to the learning state of student, and targetedly
It carries out individual instructions and alarming system has great importance.Currently, the DINA model based on knowledge-ID incidence matrix
It is the cognitive diagnosis model of mainstream, however, the existing method based on knowledge-ID incidence matrix causes model abundant
Indicate the different grain size of knowledge point.
Based on the above circumstances, a kind of more granularity cognitive diagnosis methods for designing reasonable Student oriented cognitive process are especially heavy
It wants.
Summary of the invention
The present invention is to propose a kind of reasonable Student oriented cognition to solve above-mentioned the shortcomings of the prior art place
The cognitive diagnosis method of process, to the school work state that the more granularity earth's surface dendrographies of method of knowledge mapping can be used raw, so as to
It is in different cognitive processes for student, the Grasping level of knowledge point is corresponded to according to the answer situation analysis student of student.
In order to achieve the above object, the technical scheme adopted by the invention is as follows:
A kind of the characteristics of cognitive diagnosis method of Student oriented cognitive process of the present invention, is, comprising the following steps:
(1), the representing multiple graininess model of knowledge point and exercise is constructed:
(1.1), setting knowledge point number is P, exercise number is Q, student's number is M;
(1.2), creation of knowledge point node K={ K1,K2,…,Kp,…,KP, exercise node J={ J1,J2,…,Jq,…,
JQ, student node I={ I1,I2,…,Im,…,IM};Wherein, KpIndicate p-th of knowledge point node, JqIndicate q-th of exercise section
Point, ImIndicate m-th of student's node, p=1,2 ..., P, q=1,2 ..., Q, m=1,2 ..., M;
(1.3), p-th of knowledge point node K is definedpAttribute include: knowledge point title Kp.name, detailed content
Kp.context, difficulty value Kp.difficuty;To define the attribute of P knowledge point node;
Define q-th of exercise node JqAttribute include: exercise content Jq.name, exercise option Jq.option, exercise is answered
Case Jq.answer;To define the attribute of Q exercise node;
Define m-th of student's node ImAttribute be student name Im.name;To define the attribute of M student's node;
(1.4), the attribute value of P knowledge point node, Q exercise node and M student's node is set;
(1.5) if, p-th of knowledge point node KpInclude v-th of knowledge point node Kv, then it represents that p-th of knowledge point node Kp
With v-th of knowledge point node KvBetween there are sides, be denoted as L1(Kp,Kv), and L1(Kp,Kv)=1;
If p-th of knowledge point node KpNot comprising v-th of knowledge point node Kv, then L is enabled1(Kp,Kv)=0;V=1,2 ...,
P, and v ≠ p;
The knowledge point node division that side is interconnected is a knowledge cluster, to be R by all knowledge point node divisions
A knowledge cluster C={ C1,C2,…,Cr,…,CR};CrIndicate r-th of knowledge cluster, r=1,2 ..., R;
(1.6) if, p-th of knowledge point node KpBelong to r-th of knowledge cluster Cr, and be r-th of knowledge cluster CrLeaf section
Point, and q-th of exercise node JqIt is related to p-th of knowledge point node Kp, then it represents that q-th of exercise node JqIt is saved with p-th of knowledge point
Point KpBetween there are sides, be denoted as L2(Jq,Kp), and L2(Jq,Kp)=1;Otherwise, L is enabled2(Jq,Kp)=0;
(1.7) if, p-th of knowledge point node KpBelong to r-th of knowledge cluster Cr, but be not r-th of knowledge cluster CrLeaf section
Point, and i-th of knowledge point node KiIt is r-th of knowledge cluster CrLeaf node, and p-th of knowledge point node KpKnow comprising i-th
Know point node Ki, q-th of exercise node JqIt is related to p-th of knowledge point node Kp, then q-th of exercise node JqWith i-th of leaf section
Point KiBetween there are side L2(Jp,Ki), and L2(Jp,Ki)=1;Otherwise, L is enabled2(Jq,Kp)=0;
(1.8) if, m-th of student's node ImComplete q-th of exercise node JqAnswer, then it represents that m-th of student's node Im
With q-th of exercise node JqBetween there are side L3(Im,Jq), and L3(Im,Jq)=1, otherwise L3(Im,Jq)=0;
Side L is set3(Im,Jq) attribute be L3(Im,Jq).ansm, indicate m-th of student's node ImIt answers q-th of exercise section
Point JqAnswer;
(1.9), side L is set3(Im,Jq) attribute be L3(Im,Jq) .flag, indicate m-th of student's node ImAnswer q
A exercise node JqAnswer it is whether correct;If L3(Im,Jq).ansm=Jq.answer, then L is enabled3(Im,Jq) .flag=1, it is no
Then enable L3(Im,Jq) .flag=0;
(1.10), it calculates and q-th of exercise node JqThere are student's node number n on sideq, to obtain and all exercise J
There are the student node number n={ n on side1,n2,…,nq,…,nQ};
It calculates and q-th of exercise node JqThere are student's node number n on sideqIn, m-th of student's node ImIt is practised with q-th
Inscribe node JqBetween there are side L3(Im,Jq) attribute L3(Im,Jq) .flag=1 student's node numberTo obtain and institute
With the presence of exercise J while attribute be " 1 " student's node number while number
(2), m-th of student's node I is constructedmSchool work state table representation model:
(2.1), knowledge point node K={ K is re-created1,K2,…,Kp,…,KP, exercise node J={ J1,J2,…,
Jq,…,JQ, the side L between the node of knowledge point1, side L between exercise node and knowledge point2;
(2.2), p-th of knowledge point node K is definedpAttribute include: knowledge point title Kp.name, detailed content
Kp.context, m-th of student ImTo p-th of knowledge point node KpGrasping level Kp.cognitionm;
Define q-th of exercise node JqAttribute include: exercise content Jq.name, exercise option Jq.option, exercise is answered
Case Jq.answer, m-th of student ImAnswer Jq.ansm, m-th of student ImReaction time Jq.timem;
(2.3), the attribute value of P knowledge point node, Q exercise node and M student's node is set;
By m-th of student's node ImTo p-th of knowledge point node KpGrasping level Kp.cognition it is set as " -1 ";
Thus by m-th of student's node Im" -1 " is disposed as to the Grasping level of all knowledge point nodes;
(3), m-th of student's node ImCognitive diagnosis analysis:
(3.1), q-th of exercise node J is setqInitial difficulty coefficient beTo which the initial difficulty of all exercise J be arranged
Spending coefficient is
(3.2), setting iteration total degree is T, and current iteration number is t, and initializes t=1;
(3.3), q-th of exercise node J is calculated by formula (1)qRegulation coefficient wq', to obtain the tune of all exercise J
Integral coefficient w '={ w1′,w2′,…,wq′,…,wQ' }:
(3.4), q-th of exercise node J of the t times iteration is updated by formula (2)qDegree-of-difficulty factorTo update t
The degree-of-difficulty factor of all exercise J of secondary iteration
(3.5), t+1 is assigned to t, and judges whether t=T is true, if so, then follow the steps (3.6);Otherwise, it holds
Row step (3.4);
(3.6), enabling condition S is L3(Im,Jq∧ { the L of)=13(Jq,Kp∨ { the L of)=13(Jq,KiThe ∧ K of)=1pInclude Ki}};Item
Part S+For L3(Im,Jq∧ { the L of)=13(Im,Jq) .flag=1 ∧ { L3(Jq,Kp∨ { the L of)=13(Jq,KiThe ∧ K of)=1pInclude Ki}};
(3.7), m-th of student's node I is calculated by formula (3)mTo p-th of knowledge point node KpGrasping level
Kp.cognitionm:
Compared with prior art, the beneficial effects of the present invention are:
1, present invention employs the method for knowledge mapping, representing multiple graininess model and the student of knowledge point and exercise are constructed
School work state table representation model solves knowledge point node in the prior art so as to carry out cognitive diagnosis analysis to student
Without granularity hierarchy, so that it can be directed to cognitive process different at student when to student's cognitive diagnosis, at many levels,
The school work state status of the student is analyzed in all directions;
2, for exercise, knowledge point and student data extensive in open education platform, lead to the pass in model between data
System is far less than data number.The prior art indicates the school work of knowledge point and exercise model and student using the representation method of matrix
State model causes matrix sparse.The present invention is based on the representing multiple graininess moulds of the method for knowledge mapping building knowledge point and exercise
Type and the school work state table representation model of student, alleviate the Sparse Problems of data, effectively reduce the space complexity of data;
3, since the Different Cognitive stage in student, such as student are respectively at unit test, interim test, final test
When, emphasis and have larger difference, more granularities proposed by the present invention to the granularity level of the knowledge point of grasp that student learns
Indicate that model shows knowledge point with different granularity levels, so that the model can be for Different Cognitive process student's
Emphasis difference carries out diagnostic analysis.
Detailed description of the invention
Fig. 1 is a kind of cognitive diagnosis method flow diagram of Student oriented cognitive process of the invention;
Fig. 2 is the representing multiple graininess model schematic of knowledge point of the invention, exercise;
Fig. 3 is student's school work state table representation model schematic diagram of the invention;
Fig. 4 is exercise, the knowledge dot matrix schematic diagram that traditional teacher uses;
Fig. 5 is the exercise of Student oriented cognitive process of the invention, knowledge dot matrix schematic diagram;
Fig. 6 is the relational graph of " sequence " knowledge cluster and exercise 1,2 in the specific embodiment of the invention.
Specific embodiment
In the present embodiment, a kind of cognitive diagnosis method of Student oriented cognitive process is: being primarily based on knowledge mapping method
Construct the representing multiple graininess model of knowledge point and exercise;Secondly based on the representing multiple graininess model of knowledge point and exercise, building is learned
Raw school work state table representation model;Again, for cognitive process at student, more granularity cognitive diagnosis point are carried out to student
Analysis.Algorithm flow chart is as shown in Figure 1.Specifically, being to carry out as follows:
(1), the representing multiple graininess model of knowledge point and exercise is constructed:
The relationship between knowledge point and the relationship between exercise and knowledge point are indicated using the method for knowledge mapping.Such as Fig. 2
Shown, there are three types of the nodes of type, respectively knowledge point node, exercise node and student's node in knowledge mapping;Side then indicates
Between node there are relationships.
(1.1), setting knowledge point number is P, exercise number is Q, student's number is M;
(1.2), creation of knowledge point node K={ K1,K2,…,Kp,…,KP, exercise node J={ J1,J2,…,Jq,…,
JQ, student node I={ I1,I2,…,Im,…,IM};Wherein, KpIndicate p-th of knowledge point node, JqIndicate q-th of exercise section
Point, ImIndicate m-th of student's node, p=1,2 ..., P, q=1,2 ..., Q, m=1,2 ..., M;
Specifically, as shown in Fig. 2, rectangle node table shows that knowledge point node, oval node indicate exercise node, pentagon
Node table dendrography tight knot point.
(1.3), p-th of knowledge point node K is definedpAttribute include: knowledge point title Kp.name, detailed content
Kp.context, difficulty value Kp.difficuty;To define the attribute of P knowledge point node;
Define q-th of exercise node JqAttribute include: exercise content Jq.name, exercise option Jq.option, exercise is answered
Case Jq.answer;To define the attribute of Q exercise node;
Define m-th of student's node ImAttribute be student name Im.name;To define the attribute of M student's node;
(1.4), the attribute value of P knowledge point node, Q exercise node and M student's node is set;
(1.5) if, p-th of knowledge point node KpInclude v-th of knowledge point node Kv, then it represents that p-th of knowledge point node Kp
With v-th of knowledge point node KvBetween there are sides, be denoted as L1(Kp,Kv), and L1(Kp,Kv)=1;
If p-th of knowledge point node KpNot comprising v-th of knowledge point node Kv, then L is enabled1(Kp,Kv)=0;V=1,2 ...,
P, and v ≠ p;
The knowledge point node division that side is interconnected is a knowledge cluster, to be R by all knowledge point node divisions
A knowledge cluster C={ C1,C2,…,Cr,…,CR};CrIndicate r-th of knowledge cluster, r=1,2 ..., R;
Due to knowledge point node may comprising several sub- knowledge points, then by knowledge point and it includes sub- knowledge point formed
The knowledge cluster of tree, that is, form the knowledge point structure of different grain size level.Minimum knowledge point in each knowledge cluster is known as
Leaf node, i.e., the sub- knowledge point that can not be further segmented in knowledge cluster.
Specifically, as shown in Fig. 2, C1Comprising with knowledge point node K1For six knowledge points of father node, i.e. C1={ K1,K3,
K4,K5,K8,K9};C2Comprising with knowledge point node K2For three knowledge points of father node, i.e. C2={ K2,K6,K7}.Wherein, knowledge
Point node K1Include knowledge point node K3、K4、K5, i.e. L1(K1,K3)=1, L1(K1,K4)=1, L1(K1,K5)=1;Knowledge point section
Point K4Include knowledge point node K8、K9, i.e. L1(K4,K8)=1, L1(K4,K9)=1;Knowledge point node K2Include knowledge point node K6、
K7, i.e. L1(K2,K6)=1, L1(K2,K7)=1.But knowledge point node K1Not comprising knowledge point node K6And K8, then L1(K1,
K6)=0, L1(K1,K8)=0, remaining knowledge point node do not include relationship similarly.
(1.6) if, p-th of knowledge point node KpBelong to r-th of knowledge cluster Cr, and be r-th of knowledge cluster CrLeaf section
Point, and q-th of exercise node JqIt is related to p-th of knowledge point node Kp, then it represents that q-th of exercise node JqIt is saved with p-th of knowledge point
Point KpBetween there are sides, be denoted as L2(Jq,Kp), and L2(Jq,Kp)=1;Otherwise, L is enabled2(Jq,Kp)=0;
Specifically, as shown in Fig. 2, knowledge point node K3It is knowledge cluster C1Leaf node, knowledge point node K6、K7It is to know
Know cluster C2Leaf node;Exercise node J1It is related to knowledge point node K3、K6, then exercise node J1With knowledge point node K3、K6It
Between there are sides, i.e. L2(J1,K3)=1, L2(J1,K6)=1.Knowledge point node K4It is not knowledge cluster C1Leaf node, then while
Exercise node J1It is related to knowledge point node K4, but exercise node J1With knowledge point node K4Between be not present side, i.e. L2(J1,K4)=
0, remaining similar situation is similarly.Exercise node J1It is not related to knowledge point node K5, i.e. L2(J1,K5)=0, remaining similar situation are same
Reason.
(1.7) if, p-th of knowledge point node KpBelong to r-th of knowledge cluster Cr, but be not r-th of knowledge cluster CrLeaf section
Point, and i-th of knowledge point node KiIt is r-th of knowledge cluster CrLeaf node, and p-th of knowledge point node KpKnow comprising i-th
Know point node Ki, q-th of exercise node JqIt is related to p-th of knowledge point node Kp, then q-th of exercise node JqWith i-th of leaf section
Point KiBetween there are side L2(Jp,Ki), and L2(Jp,Ki)=1;Otherwise, L is enabled2(Jq,Kp)=0;
Since per pass exercise is related to one or more knowledge points, only student is in all knowledge points that grasp exercise is related to
In the case of could correct answer, therefore, each exercise node is associated with the minimum knowledge point that it is related to.
Specifically, as shown in Fig. 2, knowledge point node K4It is not knowledge cluster C1Leaf node, knowledge point node K4Comprising knowing
Know point node K8And K9, and knowledge point node K8And K9It is knowledge cluster C1Leaf node, if exercise node J1It is related to knowledge point section
Point K4, then exercise node J1With knowledge point node K8And K9Between there are sides, i.e. L2(J1,K8)=1, L2(J1,K9)=1.Remaining feelings
It is 0 under condition.
(1.8) if, m-th of student's node ImComplete q-th of exercise node JqAnswer, then it represents that m-th of student's node Im
With q-th of exercise node JqBetween there are side L3(Im,Jq), and L3(Im,Jq)=1, otherwise L3(Im,Jq)=0;
Side L is set3(Im,Jq) attribute be L3(Im,Jq).ansm, indicate m-th of student's node ImIt answers q-th of exercise section
Point JqAnswer;
Specifically, as shown in Fig. 2, student's node I1Complete exercise node J1Answer, then student's node I1With exercise section
Point J1Between there are side L3(I1,J1), i.e. L3(I1,J1)=1;It can similarly obtain, L3(I2,J1)=1, L3(I2,J2)=1, L3(I3,
J2)=1.Due to student's node I1Exercise node J is not completed2Answer, then student's node I1With exercise node J2Between be not present
Side, i.e. L3(I1,J2)=0;It can similarly obtain, L3(I3,J1)=0.
Side L is respectively set3(I1,J1)、L3(I2,J1)、L3(I2,J2)、L3(I3,J2) attribute L3(I1,J1).ans1、L3
(I2,J1).ans2、L3(I2,J2).ans2、L3(I3,J2).ans3, and by student's node I1、I2、I3The answer of corresponding exercise of answering
It is assigned to above four attribute values.
(1.9), side L is set3(Im,Jq) attribute be L3(Im,Jq) .flag, indicate m-th of student's node ImAnswer q
A exercise node JqAnswer it is whether correct;If L3(Im,Jq).ansm=Jq.answer, then L is enabled3(Im,Jq) .flag=1, it is no
Then enable L3(Im,Jq) .flag=0;
Specifically, as shown in Fig. 2, side L is respectively set3(I1,J1)、L3(I2,J1)、L3(I2,J2)、L3(I3,J2) attribute
L3(I1,J1).flag、L3(I2,J1).flag、L3(I2,J2).flag、L3(I3,J2).flag.If student's node I1Correctly answer
Exercise node J1, i.e. L3(I1,J1).ans1=J1.answer, then L3(I1,J1) .flag=1;If student's node I1Mistake is made
Exercise node J is answered1, i.e. L3(I1,J1).ans1≠J1.answer, then L3(I1,J1) .flag=0;Remaining category similarly can be obtained
Property value.
(1.10), it calculates and q-th of exercise node JqThere are student's node number n on sideq, to obtain and all exercise J
There are the student node number n={ n on side1,n2,…,nq,…,nQ};
It calculates and q-th of exercise node JqThere are student's node number n on sideqIn, m-th of student's node ImIt is practised with q-th
Inscribe node JqBetween there are side L3(Im,Jq) attribute L3(Im,Jq) .flag=1 student's node numberTo obtain and institute
With the presence of exercise J while attribute be " 1 " student's node number while number
Specifically, as shown in Fig. 2, with exercise node J1There are student's node number n on side1=2;N can similarly be obtained2=2.
If L3(I1,J1) .flag=1, L3(I2,J1) .flag=1, L3(I2,J2) .flag=0, L3(I3,J2) .flag=
1, then
(2), m-th of student's node I is constructedmSchool work state table representation model:
The relationship between student's exercise answered and knowledge point is indicated using the method for knowledge mapping.As shown in figure 3, knowledge
There are two types of the nodes of type, respectively knowledge point node, exercise node in map;Side then indicate between node there are relationships.
Assuming that building student's node I2School work state table representation model.
(2.1), knowledge point node K={ K is re-created1,K2,…,Kp,…,KP, exercise node J={ J1,J2,…,
Jq,…,JQ, the side L between the node of knowledge point1, side L between exercise node and knowledge point2;
Side between knowledge point node shown in Fig. 3, exercise node and node is multiplexed knowledge point node shown in Fig. 2, practises
Inscribe the side between node and node.
(2.2), p-th of knowledge point node K is definedpAttribute include: knowledge point title Kp.name, detailed content
Kp.context, m-th of student ImTo p-th of knowledge point node KpGrasping level Kp.cognitionm;
Define q-th of exercise node JqAttribute include: exercise content Jq.name, exercise option Jq.option, exercise is answered
Case Jq.answer, m-th of student ImAnswer Jq.ansm, m-th of student ImReaction time Jq.timem;
Compared with the representing multiple graininess model of knowledge point and exercise, in the school work state map of student, each knowledge point
Node increases student's node I newly other than knowledge point title and detailed content2To the Grasping level attribute of knowledge point node;Each
In exercise node other than storage topic information and answer, student's node I is increased newly2Answer and Reaction time attribute.
(2.3), the attribute value of P knowledge point node, Q exercise node and M student's node is set;
By m-th of student's node ImTo p-th of knowledge point node KpGrasping level Kp.cognition it is set as " -1 ";
Thus by m-th of student's node Im" -1 " is disposed as to the Grasping level of all knowledge point nodes;
(3), m-th of student's node ImCognitive diagnosis analysis:
(3.1), q-th of exercise node J is setqInitial difficulty coefficient beTo which the initial difficulty of all exercise J be arranged
Spending coefficient is
Knowledge point, the exercise matrix that traditional cognitive diagnosis process uses are as shown in figure 4, different grain size level cannot be embodied
Knowledge point grasp situation.Since each student cognitive process locating at present is different, in the new knowledge point study stage
The raw granularity layers grasped to knowledge point time requirement is thinner, grasps in knowledge point combing and the student in review stage to knowledge point
Granularity layers time require thicker.It therefore, can be according to different students to granularity level in the representing multiple graininess model that the present invention constructs
It is different require to targetedly select required granularity level (as shown in Figure 5), to be pointedly more student setting
The initial difficulty coefficient of exercise.
Contribution of the present invention on more granularity levels is illustrated as shown in fig. 6, exercise 1 and exercise 2 investigate student couple
In the Grasping level of sort algorithm correlated knowledge point, however exercise 1 is the exercise in the sort algorithm study stage, knowledge point
It should be divided into thinner granularity, i.e. { " Shell sorting basic conception ", " Shell sorting time complexity " }, to investigate student emphatically
For the grasp situation of every sub- knowledge point.And exercise 2 is the examination paper in final examination, due to what is be related in end of term paper
Knowledge point is more, if excessively high using the complexity that the knowledge point division methods of finer grain will lead to model solution, therefore, can make
It obtains dividing compared with the knowledge point of coarseness with the father node of leaf node in knowledge cluster.For example, divide can be with for the coarseness of exercise 2
For { " Shell sorting ", " bubble sort ", " quicksort ", " heapsort " };And if using most fine-grained division, every kind
" basic conception ", " algorithm description ", " stability " of sort algorithm all should be used as knowledge point relevant to the exercise, lead to model
Time complexity with higher when solution.It, can according to the proposed method, in Different Cognitive process based on this
In student carry out personality analysis, formulate the initial difficulty coefficient of all exercises.
Assuming that exercise node J shown in Fig. 31、J2Initial difficulty coefficient be respectively
(3.2), setting iteration total degree is T, and current iteration number is t, and initializes t=1;
For simple declaration, it is assumed that iteration total degree is T=3.
(3.3), q-th of exercise node J is calculated by formula (1)qRegulation coefficient wq', to obtain the tune of all exercise J
Integral coefficient w '={ w1′,w2′,…,wq′,…,wQ' }:
Exercise node J shown in Fig. 31Regulation coefficientExercise node J2Regulation coefficient
(3.4), q-th of exercise node J of the t times iteration is updated by formula (2)qDegree-of-difficulty factorTo update t
The degree-of-difficulty factor of all exercise J of secondary iteration
(3.5), t+1 is assigned to t, and judges whether t=T is true, if so, then follow the steps (3.6);Otherwise, it holds
Row step (3.4);
As shown in figure 3, exercise node J shown in Fig. 4 can be obtained by iteration T times1、J2Degree-of-difficulty factor As it can be seen that due to the exercise node J that answers1Student correctly answer the topic, exercise node J1Degree-of-difficulty factor substantially
Degree reduces;Due to the exercise node J that answers2Student exist and correctly answer and mistake is answered situation, then exercise node J2Difficulty system
Number decreases.
(3.6), enabling condition S is L3(Im,Jq∧ { the L of)=13(Jq,Kp∨ { the L of)=13(Jq,KiThe ∧ K of)=1pInclude Ki}};Item
Part S+For L3(Im,Jq∧ { the L of)=13(Im,Jq) .flag=1 ∧ { L3(Jq,Kp∨ { the L of)=13(Jq,KiThe ∧ K of)=1pInclude Ki}};
Condition S is meant that: student's node ImAnswered knowledge point node KpThe exercise node J being related toq, or answer
Knowledge point node KiThe exercise node J being related toqAnd knowledge point node KpInclude knowledge point node Ki。
Condition S+It is meant that: student's node ImCorrectly answered knowledge point node KpThe exercise node J being related toq, Huo Zhezheng
Really answered knowledge point node KiThe exercise node J being related toqAnd knowledge point node KpInclude knowledge point node Ki。
As shown in figure 3, condition S are as follows: for student's node I2, answered and knowledge point node K4Included knowledge point node
K8、K9The exercise node J being related to1;Condition S+Are as follows: for student's node I2, correctly answered and knowledge point node K4It include to know
Know point node K8、K9The exercise node J being related to1;Student's node I similarly can be obtained2For the condition of other knowledge point nodes.
(3.7), m-th of student's node I is calculated by formula (3)mTo p-th of knowledge point node KpGrasping level
Kp.cognitionm:
It can thus be concluded that student's node I2For knowledge point node K4Grasping level
Again as shown in fig. 6, exercise associated there has exercise by taking " basic conception " knowledge point of " Shell sorting " as an example
1, exercise 2, then according to formulaGrasp of this stage of the student to the knowledge point can be calculated
Situation.If assuming, the student is in stage learning period Mo, need to have global grasp to " sequence " knowledge point, then should analyze this stage
Grasp situation of the student to the knowledge point of " exchange sort " this kind of granularity.It is associated therewith by taking " exchange sort " knowledge point as an example
The exercise of connection only has exercise 2, then according to formulaThe student stage in the end of term can be calculated to this
The grasp situation of knowledge point.
Claims (1)
1. a kind of cognitive diagnosis method of Student oriented cognitive process, which comprises the following steps:
(1), the representing multiple graininess model of knowledge point and exercise is constructed:
(1.1), setting knowledge point number is P, exercise number is Q, student's number is M;
(1.2), creation of knowledge point node K={ K1,K2,…,Kp,…,KP, exercise node J={ J1,J2,…,Jq,…,JQ, learn
Tight knot point I={ I1,I2,…,Im,…,IM};Wherein, KpIndicate p-th of knowledge point node, JqIndicate q-th of exercise node, Im
Indicate m-th of student's node, p=1,2 ..., P, q=1,2 ..., Q, m=1,2 ..., M;
(1.3), p-th of knowledge point node K is definedpAttribute include: knowledge point title Kp.name, detailed content
Kp.context, difficulty value Kp.difficuty;To define the attribute of P knowledge point node;
Define q-th of exercise node JqAttribute include: exercise content Jq.name, exercise option Jq.option, exercise answer
Jq.answer;To define the attribute of Q exercise node;
Define m-th of student's node ImAttribute be student name Im.name;To define the attribute of M student's node;
(1.4), the attribute value of P knowledge point node, Q exercise node and M student's node is set;
(1.5) if, p-th of knowledge point node KpInclude v-th of knowledge point node Kv, then it represents that p-th of knowledge point node KpWith
V knowledge point node KvBetween there are sides, be denoted as L1(Kp,Kv), and L1(Kp,Kv)=1;
If p-th of knowledge point node KpNot comprising v-th of knowledge point node Kv, then L is enabled1(Kp,Kv)=0;V=1,2 ..., P, and v
≠p;
The knowledge point node division that side is interconnected is a knowledge cluster, is known to be R for all knowledge point node divisions
Know cluster C={ C1,C2,…,Cr,…,CR};CrIndicate r-th of knowledge cluster, r=1,2 ..., R;
(1.6) if, p-th of knowledge point node KpBelong to r-th of knowledge cluster Cr, and be r-th of knowledge cluster CrLeaf node, and
Q-th of exercise node JqIt is related to p-th of knowledge point node Kp, then it represents that q-th of exercise node JqWith p-th of knowledge point node Kp
Between there are sides, be denoted as L2(Jq,Kp), and L2(Jq,Kp)=1;Otherwise, L is enabled2(Jq,Kp)=0;
(1.7) if, p-th of knowledge point node KpBelong to r-th of knowledge cluster Cr, but be not r-th of knowledge cluster CrLeaf node,
And i-th of knowledge point node KiIt is r-th of knowledge cluster CrLeaf node, and p-th of knowledge point node KpInclude i-th of knowledge
Point node Ki, q-th of exercise node JqIt is related to p-th of knowledge point node Kp, then q-th of exercise node JqWith i-th of leaf node
KiBetween there are side L2(Jp,Ki), and L2(Jp,Ki)=1;Otherwise, L is enabled2(Jq,Kp)=0;
(1.8) if, m-th of student's node ImComplete q-th of exercise node JqAnswer, then it represents that m-th of student's node ImWith
Q exercise node JqBetween there are side L3(Im,Jq), and L3(Im,Jq)=1, otherwise L3(Im,Jq)=0;
Side L is set3(Im,Jq) attribute be L3(Im,Jq).ansm, indicate m-th of student's node ImAnswer q-th of exercise node Jq
Answer;
(1.9), side L is set3(Im,Jq) attribute be L3(Im,Jq) .flag, indicate m-th of student's node ImIt answers q-th of exercise
Node JqAnswer it is whether correct;If L3(Im,Jq).ansm=Jq.answer, then L is enabled3(Im,Jq) .flag=1, otherwise enable L3
(Im,Jq) .flag=0;
(1.10), it calculates and q-th of exercise node JqThere are student's node number n on sideq, to obtain existing with all exercise J
The student node number n={ n on side1,n2,…,nq,…,nQ};
It calculates and q-th of exercise node JqThere are student's node number n on sideqIn, m-th of student's node ImWith q-th of exercise section
Point JqBetween there are side L3(Im,Jq) attribute L3(Im,Jq) .flag=1 student's node numberTo obtain and all habits
Inscribe J there are while attribute be " 1 " student's node number while number
(2), m-th of student's node I is constructedmSchool work state table representation model:
(2.1), knowledge point node K={ K is re-created1,K2,…,Kp,…,KP, exercise node J={ J1,J2,…,Jq,…,
JQ, the side L between the node of knowledge point1, side L between exercise node and knowledge point2;
(2.2), p-th of knowledge point node K is definedpAttribute include: knowledge point title Kp.name, detailed content
Kp.context, m-th of student ImTo p-th of knowledge point node KpGrasping level Kp.cognitionm;
Define q-th of exercise node JqAttribute include: exercise content Jq.name, exercise option Jq.option, exercise answer
Jq.answer, m-th of student ImAnswer Jq.ansm, m-th of student ImReaction time Jq.timem;
(2.3), the attribute value of P knowledge point node, Q exercise node and M student's node is set;
By m-th of student's node ImTo p-th of knowledge point node KpGrasping level Kp.cognition it is set as " -1 ";To
By m-th of student's node Im" -1 " is disposed as to the Grasping level of all knowledge point nodes;
(3), m-th of student's node ImCognitive diagnosis analysis:
(3.1), q-th of exercise node J is setqInitial difficulty coefficient beTo which the initial difficulty system of all exercise J be arranged
Number is
(3.2), setting iteration total degree is T, and current iteration number is t, and initializes t=1;
(3.3), q-th of exercise node J is calculated by formula (1)qRegulation coefficient wq', to obtain the adjustment system of all exercise J
Number w '={ w1′,w2′,…,wq′,…,wQ' }:
(3.4), q-th of exercise node J of the t times iteration is updated by formula (2)qDegree-of-difficulty factorTo update the t times repeatedly
The degree-of-difficulty factor of all exercise J in generation
(3.5), t+1 is assigned to t, and judges whether t=T is true, if so, then follow the steps (3.6);Otherwise, step is executed
Suddenly (3.4);
(3.6), enabling condition S is L3(Im,Jq∧ { the L of)=13(Jq,Kp∨ { the L of)=13(Jq,KiThe ∧ K of)=1pInclude Ki}};Condition S+
For L3(Im,Jq∧ { the L of)=13(Im,Jq) .flag=1 ∧ { L3(Jq,Kp∨ { the L of)=13(Jq,KiThe ∧ K of)=1pInclude Ki}};
(3.7), m-th of student's node I is calculated by formula (3)mTo p-th of knowledge point node KpGrasping level
Kp.cognitionm:
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