CN107703740A - A kind of robust interval sensor fault diagnosis method of bullet train critical system - Google Patents
A kind of robust interval sensor fault diagnosis method of bullet train critical system Download PDFInfo
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Abstract
The invention discloses a kind of robust interval sensor fault diagnosis method of bullet train critical system, belong to field of signal processing, this method includes:Establish bullet train critical system discrete-time state-space model step;Design bullet train critical system robust Residual Generation device step;Design bullet train critical system robust interval Transducer-fault Detecting Method step;Design the separation of bullet train critical system robust interval sensor fault and method of estimation step.The effective guarantee of the present invention practical application request of bullet train critical system interval sensor fault diagnosis.
Description
Technical Field
The invention belongs to the field of signal processing, and particularly relates to a robust intermittent sensor fault diagnosis method for a key system of a high-speed train.
Background
The high-speed train is the system which is most closely related to passengers in the high-speed rail technology, and the safe and stable running of the high-speed train is the basis and the premise of the healthy and rapid development of the high-speed rail. The fault diagnosis technology is a key technology for guaranteeing the safe operation of the high-speed train. At present, a plurality of technical measures and systems are adopted by high-speed trains to improve the reliability and safety of train operation.
However, the existing high-speed train fault diagnosis technology has many limitations, such as mostly simple threshold comparison, and matching with strategic operation steps, redundant information which can be used for fault diagnosis is not sufficiently discovered; the diagnosis function depends heavily on the richness of the fault code table, only common faults existing in the fault code table can be diagnosed, and new faults generated in the actual operation of the train cannot be diagnosed; permanent faults are considered in the coping process, and intermittent sensor faults caused by electromagnetic interference and the like are not considered.
Based on the above situation, a robust intermittent sensor fault diagnosis method for a key system of a high-speed train is needed to implement real-time online diagnosis of the intermittent sensor fault of the key system of the high-speed train by a fault diagnosis system.
Disclosure of Invention
Aiming at the technical problems in the prior art, the invention provides the robust intermittent sensor fault diagnosis method for the key system of the high-speed train, which is reasonable in design, overcomes the defects of the prior art and has a good effect.
In order to achieve the purpose, the invention adopts the following technical scheme:
a robust intermittent sensor fault diagnosis method for a key system of a high-speed train specifically comprises the following steps:
step 1: establishing a discrete time state space model of a key system of a high-speed train and identifying model parameters
Wherein,respectively, the system state, the control input and the measurement output; respectively, process noise and measurement noise;is a sensor failure; is a system parameter;is the parameter uncertainty; the following conditions are satisfied: the mean, covariance, and second moment of the initial state x (0) areP0,Σ0(ii) a The mean values of the noises w (k), v (k) are zero, and the covariance matrices are respectively sigmaw(k),Σv(k)(ii) a Uncertainty of parameter Aδ(k),Bδ(k),Cδ(k) Has a mean value of zero and a covariance matrix of
Step 2: the method for designing the robust residual error generator of the key system of the high-speed train specifically comprises the following steps:
step 2.1: off-line computing gain matrix K (k)
K(k)=G(k)Cc(k)TQ(k)-1, (2);
Wherein,
step 2.2: computing robust residuals r (k) on-line
Wherein,
and step 3: the method for detecting the fault of the robust intermittent sensor of the key system of the high-speed train comprises the following steps:
step 3.1: calculating intermittent fault detection statistic TD(k)
Step 3.2: setting an intermittent fault detection false alarm rate Pfa
Pfa=αfa, (12);
Step 3.3: design intermittent Fault detection threshold JD
Wherein,
step 3.4: intermittent fault detection according to the following criteria
If TD(k-1)≤JD,TD(k)>JDIf so, a fault occurs at the moment k, and the fault alarm indication quantity Ia=1;
If TD(k-1)>JD,TD(k)≤JDIf so, the fault disappears at the moment k, and the fault release indication quantity Ir=1;
Accordingly, the fault alarm time and the fault release time of the ith intermittent fault are respectively
kalarm,i=min(k|TD(k)>JD,k≥krelease,i-1+1), (15);
krelease,i=min(k|TD(k)≤JD,k≥kalarm,i+1), (16);
And 4, step 4: the method for designing the fault separation and estimation of the robust intermittent sensor of the key system of the high-speed train specifically comprises the following steps:
step 4.1: calculating intermittent fault separation statistic TI(i,j)
Wherein,
L(i,j)11=G(i,j)11 TT(i)-1G(i,j)11, (18);
L(i,j)12=G(i,j)11 TT(i)-1G(i,j)12, (19);
L(i,j)21=G(i,j)12 TT(i)-1G(i,j)11, (20);
L(i,j)22=G(i,j)12 TT(i)-1G(i,j)12, (21);
d(i,j)1=G(i,j)11 TT(i)-1r(kalarm,i,krelease,i-1), (22);
d(i,j)2=G(i,j)12 TT(i)-1r(kalarm,i,krelease,i-1), (23);
r(kalarm,i,krelease,i-1)=[r(kalarm,i)Tr(kalarm,i+1)T… r(krelease,i-1)T], (24);
T(i)=diag(S(kalarm,i) S(kalarm,i+1) … S(krelease,i-1)), (26);
G(i,j)11=G(i,j){1:ny(krelease,i-kalarm,i),1}, (27);
G(i,j)12=G(i,j){1:ny(krelease,i-kalarm,i),2:ny}, (28);
step 4.2: setting intermittent fault separation error fraction
Step 4.3: design intermittent fault separation threshold JI(j)
Wherein,
step 4.4: intermittent fault separation according to the following criteria
If TI(i,j)>JI(j) If yes, the sensor j has a fault;
if TI(i,j)≤JI(j) Then sensor j has no fault;
step 4.5: calculating intermittent fault estimates
Wherein,
the invention has the following beneficial technical effects:
the method and the device fully explore redundant information which can be used for fault diagnosis, can detect, separate and estimate the fault of the intermittent sensor on line in real time, do not depend on a fault code table, and effectively meet the actual application requirement of the fault diagnosis of the intermittent sensor of the key system of the high-speed train.
Drawings
FIG. 1 is a flow chart of the method of the present invention.
Fig. 2 is a schematic diagram of a fault curve of an intermittent sensor of a key system of the high-speed train.
Fig. 3 is a schematic diagram of a fault detection result of an intermittent sensor of a key system of the high-speed train.
Fig. 4 is a schematic diagram of a fault separation result of an intermittent sensor of a key system of the high-speed train.
FIG. 5 is a schematic diagram of the fault estimation result of the intermittent sensor of the critical system of the high-speed train.
Detailed Description
The invention is described in further detail below with reference to the following figures and detailed description:
a robust intermittent sensor fault diagnosis method for a key system of a high-speed train is disclosed, the flow of which is shown in figure 1, and the method specifically comprises the following steps:
step 1: establishing a discrete time state space model of a key system of a high-speed train and identifying model parameters
Wherein,respectively, the system state, the control input and the measurement output; respectively, process noise and measurement noise;is a sensor failure; is a system parameter;is the parameter uncertainty; the following conditions are satisfied: the mean, covariance, and second moment of the initial state x (0) areP0,Σ0(ii) a The mean values of the noises w (k), v (k) are zero, and the covariance matrices are respectively sigmaw(k),Σv(k)(ii) a Uncertainty of parameter Aδ(k),Bδ(k),Cδ(k) Has a mean value of zero and a covariance matrix of
Step 2: the method for designing the robust residual error generator of the key system of the high-speed train specifically comprises the following steps:
step 2.1: off-line computing gain matrix K (k)
K(k)=G(k)Cc(k)TQ(k)-1, (2);
Wherein,
step 2.2: computing robust residuals r (k) on-line
Wherein,
and step 3: the method for detecting the fault of the robust intermittent sensor of the key system of the high-speed train comprises the following steps:
step 3.1: calculating intermittent fault detection statistic TD(k)
Step 3.2: setting an intermittent fault detection false alarm rate Pfa
Pfa=αfa, (12);
Step 3.3: design intermittent Fault detection threshold JD
Wherein,
step 3.4: intermittent fault detection according to the following criteria
If TD(k-1)≤JD,TD(k)>JDIf so, a fault occurs at the moment k, and the fault alarm indication quantity Ia=1;
If TD(k-1)>JD,TD(k)≤JDIf so, the fault disappears at the moment k, and the fault release indication quantity Ir=1;
Accordingly, the fault alarm time and the fault release time of the ith intermittent fault are respectively
kalarm,i=min(k|TD(k)>JD,k≥krelease,i-1+1), (15);
krelease,i=min(k|TD(k)≤JD,k≥kalarm,i+1), (16);
The failure is shown in fig. 2, and the failure detection result is shown in fig. 3.
And 4, step 4: the method for designing the fault separation and estimation of the robust intermittent sensor of the key system of the high-speed train specifically comprises the following steps:
step 4.1: calculating intermittent fault separation statistic TI(i,j)
Wherein,
L(i,j)11=G(i,j)11 TT(i)-1G(i,j)11, (18);
L(i,j)12=G(i,j)11 TT(i)-1G(i,j)12, (19);
L(i,j)21=G(i,j)12 TT(i)-1G(i,j)11, (20);
L(i,j)22=G(i,j)12 TT(i)-1G(i,j)12, (21);
d(i,j)1=G(i,j)11 TT(i)-1r(kalarm,i,krelease,i-1), (22);
d(i,j)2=G(i,j)12 TT(i)-1r(kalarm,i,krelease,i-1), (23);
r(kalarm,i,krelease,i-1)=[r(kalarm,i)Tr(kalarm,i+1)T… r(krelease,i-1)T], (24);
T(i)=diag(S(kalarm,i) S(kalarm,i+1) … S(krelease,i-1)), (26);
G(i,j)11=G(i,j){1:ny(krelease,i-kalarm,i),1}, (27);
G(i,j)12=G(i,j){1:ny(krelease,i-kalarm,i),2:ny}, (28);
step 4.2: setting intermittent fault separation error fraction
Step 4.3: design intermittent fault separation threshold JI(j)
Wherein,
step 4.4: intermittent fault separation according to the following criteria
If TI(i,j)>JI(j) If yes, the sensor j has a fault;
if TI(i,j)≤JI(j) Then sensor j has no fault;
step 4.5: calculating intermittent fault estimates
Wherein,
the results of fault isolation and fault estimation are shown in fig. 4 and 5, respectively.
It is to be understood that the above description is not intended to limit the present invention, and the present invention is not limited to the above examples, and those skilled in the art may make modifications, alterations, additions or substitutions within the spirit and scope of the present invention.
Claims (1)
1. A robust intermittent sensor fault diagnosis method for a key system of a high-speed train is characterized by comprising the following steps: the method specifically comprises the following steps:
step 1: establishing a discrete time state space model of a key system of a high-speed train and identifying model parameters
<mrow> <mtable> <mtr> <mtd> <mrow> <mi>x</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>+</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>=</mo> <mrow> <mo>(</mo> <msub> <mi>A</mi> <mi>c</mi> </msub> <mo>(</mo> <mi>k</mi> <mo>)</mo> <mo>+</mo> <msub> <mi>A</mi> <mi>&delta;</mi> </msub> <mo>(</mo> <mi>k</mi> <mo>)</mo> <mo>)</mo> </mrow> <mi>x</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>+</mo> <mrow> <mo>(</mo> <msub> <mi>B</mi> <mi>c</mi> </msub> <mo>(</mo> <mi>k</mi> <mo>)</mo> <mo>+</mo> <msub> <mi>B</mi> <mi>&delta;</mi> </msub> <mo>(</mo> <mi>k</mi> <mo>)</mo> <mo>)</mo> </mrow> <mi>u</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>+</mo> <mi>w</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>,</mo> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <mi>y</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>=</mo> <mrow> <mo>(</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <mo>(</mo> <mi>k</mi> <mo>)</mo> <mo>+</mo> <msub> <mi>C</mi> <mi>&delta;</mi> </msub> <mo>(</mo> <mi>k</mi> <mo>)</mo> <mo>)</mo> </mrow> <mi>x</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>+</mo> <mi>v</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>+</mo> <mi>f</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>,</mo> </mrow> </mtd> </mtr> </mtable> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
Wherein,respectively, the system state, the control input and the measurement output; respectively, process noise and measurement noise;is a sensor failure; is a system parameter;is the parameter uncertainty; the following conditions are satisfied: the mean value of the initial state x (0),covariance, second moment ofP0,Σ0(ii) a The mean values of the noises w (k), v (k) are zero, and the covariance matrices are respectively sigmaw(k),Σv(k)(ii) a Uncertainty of parameter Aδ(k),Bδ(k),Cδ(k) Has a mean value of zero and a covariance matrix of
Step 2: the method for designing the robust residual error generator of the key system of the high-speed train specifically comprises the following steps:
step 2.1: off-line computing gain matrix K (k)
K(k)=G(k)Cc(k)TQ(k)-1, (2);
Wherein,
<mrow> <mi>G</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>=</mo> <msub> <mi>A</mi> <mi>c</mi> </msub> <mrow> <mo>(</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mi>P</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <msub> <mi>A</mi> <mi>c</mi> </msub> <msup> <mrow> <mo>(</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mi>T</mi> </msup> <mo>+</mo> <msub> <mi>&Sigma;</mi> <mrow> <msub> <mi>A</mi> <mi>&delta;</mi> </msub> <mrow> <mo>(</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mi>x</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> </mrow> </msub> <mo>+</mo> <msub> <mi>&Sigma;</mi> <mrow> <msub> <mi>B</mi> <mi>&delta;</mi> </msub> <mrow> <mo>(</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mi>u</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> </mrow> </msub> <mo>+</mo> <msub> <mi>&Sigma;</mi> <mrow> <mi>w</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> </mrow> </msub> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>3</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
<mrow> <mi>Q</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>=</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mi>G</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <msub> <mi>C</mi> <mi>c</mi> </msub> <msup> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mi>T</mi> </msup> <mo>+</mo> <msub> <mi>&Sigma;</mi> <mrow> <msub> <mi>C</mi> <mi>&delta;</mi> </msub> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <msub> <mi>&Sigma;</mi> <mrow> <mi>x</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> </mrow> </msub> </mrow> </msub> <mo>+</mo> <msub> <mi>&Sigma;</mi> <mrow> <mi>v</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> </mrow> </msub> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>4</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
<mrow> <mi>P</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>=</mo> <mrow> <mo>(</mo> <msub> <mi>I</mi> <mrow> <msub> <mi>n</mi> <mi>x</mi> </msub> <mo>&times;</mo> <msub> <mi>n</mi> <mi>x</mi> </msub> </mrow> </msub> <mo>-</mo> <mi>K</mi> <mo>(</mo> <mi>k</mi> <mo>)</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <mo>(</mo> <mi>k</mi> <mo>)</mo> <mo>)</mo> </mrow> <mi>G</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>5</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
step 2.2: computing robust residuals r (k) on-line
<mrow> <mi>r</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>=</mo> <mi>y</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>-</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mover> <mi>x</mi> <mo>^</mo> </mover> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>6</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
Wherein,
<mrow> <mover> <mi>x</mi> <mo>^</mo> </mover> <mrow> <mo>(</mo> <mn>0</mn> <mo>)</mo> </mrow> <mo>=</mo> <msub> <mover> <mi>x</mi> <mo>&OverBar;</mo> </mover> <mn>0</mn> </msub> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>7</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
<mrow> <mover> <mi>x</mi> <mo>^</mo> </mover> <mrow> <mo>(</mo> <mi>k</mi> <mo>|</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>=</mo> <msub> <mi>A</mi> <mi>c</mi> </msub> <mrow> <mo>(</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mover> <mi>x</mi> <mo>^</mo> </mover> <mrow> <mo>(</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>+</mo> <msub> <mi>B</mi> <mi>c</mi> </msub> <mrow> <mo>(</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mi>u</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>8</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
<mrow> <mi>r</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>|</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>=</mo> <mi>y</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>-</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mover> <mi>x</mi> <mo>^</mo> </mover> <mrow> <mo>(</mo> <mi>k</mi> <mo>|</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>9</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
<mrow> <mover> <mi>x</mi> <mo>^</mo> </mover> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>=</mo> <mover> <mi>x</mi> <mo>^</mo> </mover> <mrow> <mo>(</mo> <mi>k</mi> <mo>|</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>+</mo> <mi>K</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mi>r</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>|</mo> <mi>k</mi> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>10</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
and step 3: the method for detecting the fault of the robust intermittent sensor of the key system of the high-speed train comprises the following steps:
step 3.1: calculating intermittent fault detection statistic TD(k)
<mrow> <msub> <mi>T</mi> <mi>D</mi> </msub> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>=</mo> <mi>r</mi> <msup> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mi>T</mi> </msup> <msup> <mrow> <mo>(</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <mo>(</mo> <mi>k</mi> <mo>)</mo> <mi>P</mi> <mo>(</mo> <mi>k</mi> <mo>)</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <msup> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mi>T</mi> </msup> <mo>+</mo> <msub> <mi>&Sigma;</mi> <mrow> <msub> <mi>C</mi> <mi>&delta;</mi> </msub> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mi>x</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> </mrow> </msub> <mo>+</mo> <msub> <mi>&Sigma;</mi> <mrow> <mi>v</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> </mrow> </msub> <mo>)</mo> </mrow> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </msup> <mi>r</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>11</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
Step 3.2: setting an intermittent fault detection false alarm rate Pfa
Pfa=αfa, (12);
Step 3.3: design intermittent Fault detection threshold JD
<mrow> <msub> <mi>J</mi> <mi>D</mi> </msub> <mo>=</mo> <msubsup> <mi>&chi;</mi> <msub> <mi>&alpha;</mi> <mrow> <mi>f</mi> <mi>a</mi> </mrow> </msub> <mn>2</mn> </msubsup> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>13</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
Wherein,
<mrow> <mi>P</mi> <mo>{</mo> <msub> <mi>T</mi> <mi>D</mi> </msub> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>></mo> <msubsup> <mi>&chi;</mi> <msub> <mi>&alpha;</mi> <mrow> <mi>f</mi> <mi>a</mi> </mrow> </msub> <mn>2</mn> </msubsup> <mo>|</mo> <mi>r</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mo>~</mo> <mi>N</mi> <mrow> <mo>(</mo> <msub> <mn>0</mn> <mrow> <msub> <mi>n</mi> <mi>y</mi> </msub> <mo>&times;</mo> <mn>1</mn> </mrow> </msub> <mo>,</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <mo>(</mo> <mi>k</mi> <mo>)</mo> <mi>P</mi> <mo>(</mo> <mi>k</mi> <mo>)</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <msup> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mi>T</mi> </msup> <mo>+</mo> <msub> <mi>&Sigma;</mi> <mrow> <msub> <mi>C</mi> <mi>&delta;</mi> </msub> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> <mi>x</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> </mrow> </msub> <mo>+</mo> <msub> <mi>&Sigma;</mi> <mrow> <mi>v</mi> <mrow> <mo>(</mo> <mi>k</mi> <mo>)</mo> </mrow> </mrow> </msub> <mo>)</mo> </mrow> <mo>}</mo> <mo>=</mo> <msub> <mi>&alpha;</mi> <mrow> <mi>f</mi> <mi>a</mi> </mrow> </msub> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>14</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
step 3.4: intermittent fault detection according to the following criteria
If TD(k-1)≤JD,TD(k)>JDIf so, a fault occurs at the moment k, and the fault alarm indication quantity Ia=1;
If TD(k-1)>JD,TD(k)≤JDIf so, the fault disappears at the moment k, and the fault release indication quantity Ir=1;
Accordingly, the fault alarm time and the fault release time of the ith intermittent fault are respectively
kalarm,i=min(k|TD(k)>JD,k≥krelease,i-1+1), (15);
krelease,i=min(k|TD(k)≤JD,k≥kalarm,i+1), (16);
And 4, step 4: the method for designing the fault separation and estimation of the robust intermittent sensor of the key system of the high-speed train specifically comprises the following steps:
step 4.1: calculating intermittent fault separation statistic TI(i,j)
<mrow> <mtable> <mtr> <mtd> <mrow> <msub> <mi>T</mi> <mi>I</mi> </msub> <mrow> <mo>(</mo> <mi>i</mi> <mo>,</mo> <mi>j</mi> <mo>)</mo> </mrow> <mo>=</mo> <msup> <mrow> <mo>(</mo> <mi>d</mi> <msub> <mrow> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mi>j</mi> </mrow> <mo>)</mo> </mrow> <mn>1</mn> </msub> <mo>-</mo> <mi>L</mi> <msub> <mrow> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mi>j</mi> </mrow> <mo>)</mo> </mrow> <mn>12</mn> </msub> <mi>L</mi> <msup> <msub> <mrow> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mi>j</mi> </mrow> <mo>)</mo> </mrow> <mn>22</mn> </msub> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </msup> <mi>d</mi> <msub> <mrow> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mi>j</mi> </mrow> <mo>)</mo> </mrow> <mn>2</mn> </msub> <mo>)</mo> </mrow> <mi>T</mi> </msup> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <mo>&times;</mo> <msup> <mrow> <mo>(</mo> <mi>L</mi> <msub> <mrow> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mi>j</mi> </mrow> <mo>)</mo> </mrow> <mn>11</mn> </msub> <mo>-</mo> <mi>L</mi> <msub> <mrow> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mi>j</mi> </mrow> <mo>)</mo> </mrow> <mn>12</mn> </msub> <mi>L</mi> <msup> <msub> <mrow> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mi>j</mi> </mrow> <mo>)</mo> </mrow> <mn>22</mn> </msub> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </msup> <mi>L</mi> <msub> <mrow> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mi>j</mi> </mrow> <mo>)</mo> </mrow> <mn>21</mn> </msub> <mo>)</mo> </mrow> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </msup> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <mo>&times;</mo> <mrow> <mo>(</mo> <mi>d</mi> <msub> <mrow> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mi>j</mi> </mrow> <mo>)</mo> </mrow> <mn>1</mn> </msub> <mo>-</mo> <mi>L</mi> <msub> <mrow> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mi>j</mi> </mrow> <mo>)</mo> </mrow> <mn>12</mn> </msub> <mi>L</mi> <msup> <msub> <mrow> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mi>j</mi> </mrow> <mo>)</mo> </mrow> <mn>22</mn> </msub> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </msup> <mi>d</mi> <msub> <mrow> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mi>j</mi> </mrow> <mo>)</mo> </mrow> <mn>2</mn> </msub> <mo>)</mo> </mrow> <mo>,</mo> </mrow> </mtd> </mtr> </mtable> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>17</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
Wherein,
L(i,j)11=G(i,j)11 TT(i)-1G(i,j)11, (18);
L(i,j)12=G(i,j)11 TT(i)-1G(i,j)12, (19);
L(i,j)21=G(i,j)12 TT(i)-1G(i,j)11, (20);
L(i,j)22=G(i,j)12 TT(i)-1G(i,j)12, (21);
d(i,j)1=G(i,j)11 TT(i)-1r(kalarm,i,krelease,i-1), (22);
d(i,j)2=G(i,j)12 TT(i)-1r(kalarm,i,krelease,i-1), (23);
r(kalarm,i,krelease,i-1)=[r(kalarm,i)Tr(kalarm,i+1)T…r(krelease,i-1)T], (24);
<mrow> <mi>G</mi> <mrow> <mo>(</mo> <mi>i</mi> <mo>,</mo> <mi>j</mi> <mo>)</mo> </mrow> <mo>=</mo> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <mrow> <msub> <mi>e</mi> <mrow> <mi>c</mi> <mi>o</mi> <mi>l</mi> </mrow> </msub> <mrow> <mo>(</mo> <msub> <mi>I</mi> <mrow> <msub> <mi>n</mi> <mi>y</mi> </msub> <mo>&times;</mo> <msub> <mi>n</mi> <mi>y</mi> </msub> </mrow> </msub> <mo>+</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <mo>(</mo> <msub> <mi>k</mi> <mrow> <mi>a</mi> <mi>l</mi> <mi>a</mi> <mi>r</mi> <mi>m</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>)</mo> <mi>Z</mi> <mo>(</mo> <msub> <mi>k</mi> <mrow> <mi>a</mi> <mi>l</mi> <mi>a</mi> <mi>r</mi> <mi>m</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>)</mo> <mo>,</mo> <mi>j</mi> <mo>,</mo> <mn>1</mn> <mo>)</mo> </mrow> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <msub> <mi>e</mi> <mrow> <mi>c</mi> <mi>o</mi> <mi>l</mi> </mrow> </msub> <mrow> <mo>(</mo> <msub> <mi>I</mi> <mrow> <msub> <mi>n</mi> <mi>y</mi> </msub> <mo>&times;</mo> <msub> <mi>n</mi> <mi>y</mi> </msub> </mrow> </msub> <mo>+</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <mo>(</mo> <mrow> <msub> <mi>k</mi> <mrow> <mi>a</mi> <mi>l</mi> <mi>a</mi> <mi>r</mi> <mi>m</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>+</mo> <mn>1</mn> </mrow> <mo>)</mo> <mi>Z</mi> <mo>(</mo> <mrow> <msub> <mi>k</mi> <mrow> <mi>a</mi> <mi>l</mi> <mi>a</mi> <mi>r</mi> <mi>m</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>+</mo> <mn>1</mn> </mrow> <mo>)</mo> <mo>,</mo> <mi>j</mi> <mo>,</mo> <mn>1</mn> <mo>)</mo> </mrow> </mrow> </mtd> </mtr> <mtr> <mtd> <mo>.</mo> </mtd> </mtr> <mtr> <mtd> <mo>.</mo> </mtd> </mtr> <mtr> <mtd> <mo>.</mo> </mtd> </mtr> <mtr> <mtd> <mrow> <msub> <mi>e</mi> <mrow> <mi>c</mi> <mi>o</mi> <mi>l</mi> </mrow> </msub> <mrow> <mo>(</mo> <msub> <mi>I</mi> <mrow> <msub> <mi>n</mi> <mi>y</mi> </msub> <mo>&times;</mo> <msub> <mi>n</mi> <mi>y</mi> </msub> </mrow> </msub> <mo>+</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <mo>(</mo> <mrow> <msub> <mi>k</mi> <mrow> <mi>r</mi> <mi>e</mi> <mi>l</mi> <mi>e</mi> <mi>a</mi> <mi>s</mi> <mi>e</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>-</mo> <mn>1</mn> </mrow> <mo>)</mo> <mi>Z</mi> <mo>(</mo> <mrow> <msub> <mi>k</mi> <mrow> <mi>r</mi> <mi>e</mi> <mi>l</mi> <mi>e</mi> <mi>a</mi> <mi>s</mi> <mi>e</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>-</mo> <mn>1</mn> </mrow> <mo>)</mo> <mo>,</mo> <mi>j</mi> <mo>,</mo> <mn>1</mn> <mo>)</mo> </mrow> </mrow> </mtd> </mtr> </mtable> </mfenced> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>25</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
T(i)=diag(S(kalarm,i) S(kalarm,i+1) … S(krelease,i-1)), (26);
G(i,j)11=G(i,j){1:ny(krelease,i-kalarm,i),1}, (27);
G(i,j)12=G(i,j){1:ny(krelease,i-kalarm,i),2:ny}, (28);
step 4.2: setting intermittent fault separation error fraction
<mrow> <msub> <mi>P</mi> <msubsup> <mi>f</mi> <mi>i</mi> <mrow> <mo>(</mo> <mi>j</mi> <mo>)</mo> </mrow> </msubsup> </msub> <mo>=</mo> <msub> <mi>&alpha;</mi> <msubsup> <mi>f</mi> <mi>i</mi> <mrow> <mo>(</mo> <mi>j</mi> <mo>)</mo> </mrow> </msubsup> </msub> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>29</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
Step 4.3: design intermittent fault separation threshold JI(j)
<mrow> <mi>P</mi> <mo>{</mo> <msub> <mi>T</mi> <mi>I</mi> </msub> <mrow> <mo>(</mo> <mi>i</mi> <mo>,</mo> <mi>j</mi> <mo>)</mo> </mrow> <mo>></mo> <msubsup> <mi>&chi;</mi> <msub> <mi>&alpha;</mi> <mrow> <mi>f</mi> <mi>a</mi> </mrow> </msub> <mn>2</mn> </msubsup> <mo>|</mo> <msubsup> <mi>f</mi> <mi>i</mi> <mrow> <mo>(</mo> <mi>j</mi> <mo>)</mo> </mrow> </msubsup> <mo>=</mo> <mn>0</mn> <mo>}</mo> <mo>=</mo> <msub> <mi>&alpha;</mi> <msubsup> <mi>f</mi> <mi>i</mi> <mrow> <mo>(</mo> <mi>j</mi> <mo>)</mo> </mrow> </msubsup> </msub> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>30</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
Wherein,
<mrow> <msub> <mi>J</mi> <mi>I</mi> </msub> <mrow> <mo>(</mo> <mi>j</mi> <mo>)</mo> </mrow> <mo>=</mo> <msub> <mi>&alpha;</mi> <msubsup> <mi>f</mi> <mi>i</mi> <mrow> <mo>(</mo> <mi>j</mi> <mo>)</mo> </mrow> </msubsup> </msub> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>31</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
step 4.4: intermittent fault separation according to the following criteria
If TI(i,j)>JI(j) If yes, the sensor j has a fault;
if TI(i,j)≤JI(j) Then sensor j has no fault;
step 4.5: calculating intermittent fault estimates
<mrow> <mtable> <mtr> <mtd> <mrow> <msub> <mover> <mi>f</mi> <mo>^</mo> </mover> <mi>i</mi> </msub> <mo>=</mo> <mi>d</mi> <mi>i</mi> <mi>a</mi> <mi>g</mi> <mo>{</mo> <msup> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <mrow> <msub> <mn>1</mn> <msup> <mi>R</mi> <mo>+</mo> </msup> </msub> <mrow> <mo>(</mo> <mi>&xi;</mi> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mn>1</mn> </mrow> <mo>)</mo> <mo>-</mo> <msub> <mi>J</mi> <mi>I</mi> </msub> <mo>(</mo> <mn>1</mn> <mo>)</mo> <mo>)</mo> </mrow> </mrow> </mtd> <mtd> <mrow> <msub> <mn>1</mn> <msup> <mi>R</mi> <mo>+</mo> </msup> </msub> <mrow> <mo>(</mo> <mi>&xi;</mi> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mn>2</mn> </mrow> <mo>)</mo> <mo>-</mo> <msub> <mi>J</mi> <mi>I</mi> </msub> <mo>(</mo> <mn>2</mn> <mo>)</mo> <mo>)</mo> </mrow> </mrow> </mtd> <mtd> <mn>...</mn> </mtd> <mtd> <mrow> <msub> <mn>1</mn> <msup> <mi>R</mi> <mo>+</mo> </msup> </msub> <mrow> <mo>(</mo> <mi>&xi;</mi> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <msub> <mi>n</mi> <mi>y</mi> </msub> </mrow> <mo>)</mo> <mo>-</mo> <msub> <mi>J</mi> <mi>I</mi> </msub> <mo>(</mo> <msub> <mi>n</mi> <mi>y</mi> </msub> <mo>)</mo> <mo>)</mo> </mrow> </mrow> </mtd> </mtr> </mtable> </mfenced> <mi>T</mi> </msup> <mo>}</mo> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <mo>&times;</mo> <mi>arg</mi> <munder> <mi>max</mi> <mi>&beta;</mi> </munder> <mi>ln</mi> <mrow> <mo>(</mo> <mi>p</mi> <mo>(</mo> <mrow> <mi>r</mi> <mrow> <mo>(</mo> <msub> <mi>k</mi> <mrow> <mi>a</mi> <mi>l</mi> <mi>a</mi> <mi>r</mi> <mi>m</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>)</mo> </mrow> <mo>,</mo> <mi>r</mi> <mrow> <mo>(</mo> <mrow> <msub> <mi>k</mi> <mrow> <mi>a</mi> <mi>l</mi> <mi>a</mi> <mi>r</mi> <mi>m</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>+</mo> <mn>1</mn> </mrow> <mo>)</mo> </mrow> <mo>,</mo> <mn>...</mn> <mo>,</mo> <mi>r</mi> <mrow> <mo>(</mo> <mrow> <msub> <mi>k</mi> <mrow> <mi>r</mi> <mi>e</mi> <mi>l</mi> <mi>e</mi> <mi>a</mi> <mi>s</mi> <mi>e</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>-</mo> <mn>1</mn> </mrow> <mo>)</mo> </mrow> <mo>|</mo> <msub> <mi>f</mi> <mi>i</mi> </msub> <mo>=</mo> <mi>&beta;</mi> </mrow> <mo>)</mo> <mo>)</mo> </mrow> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <mo>=</mo> <mi>d</mi> <mi>i</mi> <mi>a</mi> <mi>g</mi> <mo>{</mo> <msup> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <mrow> <msub> <mn>1</mn> <msup> <mi>R</mi> <mo>+</mo> </msup> </msub> <mrow> <mo>(</mo> <mi>&xi;</mi> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mn>1</mn> </mrow> <mo>)</mo> <mo>-</mo> <msub> <mi>J</mi> <mi>I</mi> </msub> <mo>(</mo> <mn>1</mn> <mo>)</mo> <mo>)</mo> </mrow> </mrow> </mtd> <mtd> <mrow> <msub> <mn>1</mn> <msup> <mi>R</mi> <mo>+</mo> </msup> </msub> <mrow> <mo>(</mo> <mi>&xi;</mi> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <mn>2</mn> </mrow> <mo>)</mo> <mo>-</mo> <msub> <mi>J</mi> <mi>I</mi> </msub> <mo>(</mo> <mn>2</mn> <mo>)</mo> <mo>)</mo> </mrow> </mrow> </mtd> <mtd> <mn>...</mn> </mtd> <mtd> <mrow> <msub> <mn>1</mn> <msup> <mi>R</mi> <mo>+</mo> </msup> </msub> <mrow> <mo>(</mo> <mi>&xi;</mi> <mo>(</mo> <mrow> <mi>i</mi> <mo>,</mo> <msub> <mi>n</mi> <mi>y</mi> </msub> </mrow> <mo>)</mo> <mo>-</mo> <msub> <mi>J</mi> <mi>I</mi> </msub> <mo>(</mo> <msub> <mi>n</mi> <mi>y</mi> </msub> <mo>)</mo> <mo>)</mo> </mrow> </mrow> </mtd> </mtr> </mtable> </mfenced> <mi>T</mi> </msup> <mo>}</mo> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <mo>&times;</mo> <mi>S</mi> <msup> <mrow> <mo>(</mo> <msub> <mi>k</mi> <mrow> <mi>a</mi> <mi>l</mi> <mi>a</mi> <mi>r</mi> <mi>m</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>k</mi> <mrow> <mi>r</mi> <mi>e</mi> <mi>l</mi> <mi>e</mi> <mi>a</mi> <mi>s</mi> <mi>e</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </msup> <mi>h</mi> <mrow> <mo>(</mo> <msub> <mi>k</mi> <mrow> <mi>a</mi> <mi>l</mi> <mi>a</mi> <mi>r</mi> <mi>m</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>k</mi> <mrow> <mi>r</mi> <mi>e</mi> <mi>l</mi> <mi>e</mi> <mi>a</mi> <mi>s</mi> <mi>e</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>,</mo> </mrow> </mtd> </mtr> </mtable> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>32</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
Wherein,
<mrow> <mi>S</mi> <mrow> <mo>(</mo> <msub> <mi>k</mi> <mrow> <mi>a</mi> <mi>l</mi> <mi>a</mi> <mi>r</mi> <mi>m</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>k</mi> <mrow> <mi>r</mi> <mi>e</mi> <mi>l</mi> <mi>e</mi> <mi>a</mi> <mi>s</mi> <mi>e</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>=</mo> <munderover> <mo>&Sigma;</mo> <mrow> <mi>l</mi> <mo>=</mo> <msub> <mi>k</mi> <mrow> <mi>a</mi> <mi>l</mi> <mi>a</mi> <mi>r</mi> <mi>m</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> </mrow> <mrow> <msub> <mi>k</mi> <mrow> <mi>r</mi> <mi>e</mi> <mi>l</mi> <mi>e</mi> <mi>a</mi> <mi>s</mi> <mi>e</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>-</mo> <mn>1</mn> </mrow> </munderover> <msup> <mrow> <mo>(</mo> <msub> <mi>I</mi> <mrow> <msub> <mi>n</mi> <mi>y</mi> </msub> <mo>&times;</mo> <msub> <mi>n</mi> <mi>y</mi> </msub> </mrow> </msub> <mo>+</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <mo>(</mo> <mi>l</mi> <mo>)</mo> <mi>Z</mi> <mo>(</mo> <mi>l</mi> <mo>)</mo> <mo>)</mo> </mrow> <mi>T</mi> </msup> <mi>Q</mi> <msup> <mrow> <mo>(</mo> <mi>l</mi> <mo>)</mo> </mrow> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </msup> <mrow> <mo>(</mo> <msub> <mi>I</mi> <mrow> <msub> <mi>n</mi> <mi>y</mi> </msub> <mo>&times;</mo> <msub> <mi>n</mi> <mi>y</mi> </msub> </mrow> </msub> <mo>+</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <mo>(</mo> <mi>l</mi> <mo>)</mo> <mi>Z</mi> <mo>(</mo> <mi>l</mi> <mo>)</mo> <mo>)</mo> </mrow> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>33</mn> <mo>)</mo> </mrow> <mo>;</mo> </mrow>
<mrow> <mi>h</mi> <mrow> <mo>(</mo> <msub> <mi>k</mi> <mrow> <mi>a</mi> <mi>l</mi> <mi>a</mi> <mi>r</mi> <mi>m</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>,</mo> <msub> <mi>k</mi> <mrow> <mi>r</mi> <mi>e</mi> <mi>l</mi> <mi>e</mi> <mi>a</mi> <mi>s</mi> <mi>e</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>-</mo> <mn>1</mn> <mo>)</mo> </mrow> <mo>=</mo> <munderover> <mo>&Sigma;</mo> <mrow> <mi>l</mi> <mo>=</mo> <msub> <mi>k</mi> <mrow> <mi>a</mi> <mi>l</mi> <mi>a</mi> <mi>r</mi> <mi>m</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> </mrow> <mrow> <msub> <mi>k</mi> <mrow> <mi>r</mi> <mi>e</mi> <mi>l</mi> <mi>e</mi> <mi>a</mi> <mi>s</mi> <mi>e</mi> <mo>,</mo> <mi>i</mi> </mrow> </msub> <mo>-</mo> <mn>1</mn> </mrow> </munderover> <msup> <mrow> <mo>(</mo> <msub> <mi>I</mi> <mrow> <msub> <mi>n</mi> <mi>y</mi> </msub> <mo>&times;</mo> <msub> <mi>n</mi> <mi>y</mi> </msub> </mrow> </msub> <mo>+</mo> <msub> <mi>C</mi> <mi>c</mi> </msub> <mo>(</mo> <mi>l</mi> <mo>)</mo> <mi>Z</mi> <mo>(</mo> <mi>l</mi> <mo>)</mo> <mo>)</mo> </mrow> <mi>T</mi> </msup> <mi>Q</mi> <msup> <mrow> <mo>(</mo> <mi>l</mi> <mo>)</mo> </mrow> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </msup> <mi>r</mi> <mrow> <mo>(</mo> <mi>l</mi> <mo>)</mo> </mrow> <mo>,</mo> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mrow> <mo>(</mo> <mn>34</mn> <mo>)</mo> </mrow> <mo>.</mo> </mrow>
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