CN106311761A - Method for reducing mill load fluctuations - Google Patents
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- CN106311761A CN106311761A CN201510371386.1A CN201510371386A CN106311761A CN 106311761 A CN106311761 A CN 106311761A CN 201510371386 A CN201510371386 A CN 201510371386A CN 106311761 A CN106311761 A CN 106311761A
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Abstract
The invention relates to a method for reducing mill load fluctuations. The method comprises the following steps that 1, initial press loads of first-fifth machine frames are calculated; 2, the roll force P1-P5 of the first-fifth machine frames is calculated according to deformation impedance, tension, friction coefficients and roll force self-adaptive coefficients; 3, roll force balance coefficients are calculated; 4, the roll force balance coefficient Bal is examined; 5, the loads of the first machine frame and the second machine frame are examined, and roll force balance coefficient ComPa is compensated for; if the loads of the first machine frame and the second machine frame meet the conditions, after compensation, the step 1 is executed again; and if not, calculation is ended. By means of the method, the acid mill load setting precision is improved, load fluctuations are reduced, and the acid mill product yield is improved.
Description
Technical field
The present invention relates to a kind of method reducing mill load fluctuation, belong to cold continuous rolling automation field.
Background technology
nullThe balance controlling parameter can play the maximum capacity of equipment on the premise of ensureing product quality,From the point of view of the ability of equipment,As long as the balance taking power is the most permissible,But for producing the unit of Thin Strip Steel,Due to suitable big of deflection,Particularly 1 frame,The contact arc angle causing roll and strip steel becomes big,If only taking motor power to balance,Roll marks can be produced on the surface of strip steel after 1 frame,Generation in order to avoid this situation,Roll in prunus mume (sieb.) sieb.et zucc. steel acid and the power of motor and the roll-force of 1 frame are mainly balanced by Process Control System calculate,2 frames are given by the roll-force reasonable distribution of 1 frame,The method simultaneously each frame of 2 frames to 5 frames being taked power-balance,This problem can be solved well,But this mode is owing to being affected by tube rolling simulation result,Load fluctuation is bigger,Before and after the independent roll change of particularly 1# or 2# frame,1、The load of 2 frames is more than 50% or less than 35%.
According to tube rolling simulation formula: p=f (r, sk, ten, sr, myu, zp)
Wherein: r is roller footpath
Sk is material deformation resistance
Ten is tension force
Sr is relative deformation's (load)
Myu is coefficient of friction
Zp is roll-force adaptation coefficient
Roll-force is proportional with coefficient of friction myu and adaptation coefficient zp
The principal element affecting mill load fluctuation has two:
1) roll-force self adaptation
2) fluctuation of coefficient of friction before and after roll change
It is illustrated as a example by the independent roll change of 2# frame below:
Coefficient of friction is correlated with rolling quantity, after roll change, 2# frame coefficient of friction compensates and becomes 1.3 from 1.0,2# frame calculates roll-force to be increased, according to 1,2 frame roll-forces balance (0.98 < P1/P2/A < 1.02), A is a constant, now P1/P2/Bal < 0.98, can only realize, so the load of 1# frame can reach more than 50 by increasing the load of 1# frame.Automatically the result calculated by model at all cannot steel rolling, can only manually intervene, manual intervention rate is more than 95%, and operative employee's labor intensity is big, and deformed steel strip enclosed is high.
Through retrieval, the patent of the load distribution method relevant with this case is as follows: number of patent application is CN200910057514.X, the invention discloses a kind of rustless steel Load Distribution for Tandem Cold Rolling method of adjustment, first each frame is initialized as setting value relative to reduction ratio, then the roll-force equilibrium valve of the 1st frame is calculated, calculate the 2nd frame motor power equilibrium valve to M frame respectively, roll-force equilibrium valve, the motor power equilibrium valve of the 2nd frame to M frame according to calculated 1st frame judge, are adjusted each frame relative to reduction ratio.The method, can adjust the relative reduction ratio of each frame, reach each frame sharing of load balance according to physical condition in the actual operation of rolling.
CN200910235653.7, the present invention relates to a kind of pressing load distribution method for double-stander medium plate production line, belongs to Medium and Heavy Plate Rolling Production line production process optimization control field.The present invention meet treat temperature condition on the basis of, the basic thought of belt restraining problem is solved according to penalty function, construct the majorized function being up to optimization aim based on rolling line production efficiency, Fibonacci method is used to be iterated optimizing, achieve the sharing of load carrying out overall reduction between Stand Mill, effectively raise the production efficiency of rolling line.
Above two patents calculate the sharing of load of each frame of milling train on the basis of being all based on playing milling train maximum production capacity, but roll load setting precision for how improving acid, reduce load fluctuation, improve acid and roll product lumber recovery, prior art never has good solution.
Summary of the invention
The present invention is just for technical problem present in prior art, it is provided that a kind of method reducing mill load fluctuation, and the method improves acid and rolls load setting precision, reduces load fluctuation, improves acid and rolls product lumber recovery.
To achieve these goals, the technical solution used in the present invention is as follows, a kind of method reducing mill load fluctuation, it is characterised in that said method comprising the steps of:
1) the initial depression load sr of 1-5 frame is calculatedi
According to formula above, calculate the initial outlet thickness of each frame, wherein H1For supplied materials thickness, HLFor product outlet thickness, srtriFor the material rate according to strip steel and specification, from pressure loading data sheet (table 5), read identical material and specification pressure data
Further according to the exit thickness of individual frame, calculating the initial depression load of each frame, computing formula is as follows:
2) roll-force P1 of 1,2 frames, P2 are calculated according to deformation resistance, tension force, coefficient of friction, roll-force adaptation coefficient;
Wherein: in formula, kp is average resistance of deformation, Dp is the frictional force impact on roll-force, and k is the tension force impact on roll-forceB is the width of strip steel, and zp is roll-force adaptation coefficient, and R ' is for flattening radius, and H is frame inlet thickness, and h is rack outlet thickness;
3) roll-force coefficient of balance is calculated;
Bal=100*P1/P2/ (A+ComPa) wherein P1 is the roll-force that 1# frame calculates, and P2 is the roll-force that 2# frame calculates, and A is a fixed value at 50-150, obtains from data form, and ComPa is roll-force coefficient of balance, is initially 0;
4) roll-force coefficient of balance Bal is checked;1-α≤Bal≤1+α
Wherein, α takes 2%, if coefficient of balance Bal meets above-mentioned condition, then calculates and forwards the 4th step to, otherwise revise load sr1, sr2 of 1,2 frames, and correction is ± sr/ (1+3*loop), and loop is cycle-index, starts to recalculate from the first step;
5) check the load of 1,2 frames, compensate roll-force coefficient of balance ComPa
Compensation principle: following sr1 is the load of 1# frame, sr2 is the load of 2# frame:
Under smooth roll rolling mode, exit thickness is less than 0.35mm,
Sr1-sr2 > 1, reduces roll-force coefficient of balance ComPa=ComPa-1 automatically;
Sr2-sr1 > 4, increases roll-force coefficient of balance ComPa=ComPa+1 automatically;
Under hair roller rolling mode, exit thickness is under permanent roll-force constant voltage more than 0.35mm, 5# frame,
Sr1-sr2 > 3, reduces roll-force coefficient of balance ComPa=ComPa-1 automatically
Sr1-sr2 < 1, increases roll-force coefficient of balance ComPa=ComPa+1 automatically
If 1, the load of 2 frames meets the most several situations, after compensation, forward second step to and recalculate, otherwise calculate and terminate.
Relative to prior art, advantages of the present invention is as follows, this method increase roll-force coefficient of balance automatic compensatory technique, guarantee that the load fluctuation of each frame of same specification is within 2%, manual intervention rate from original 95% reduce to current 1% within, exit thickness deviation improves 2.1% less than the ratio of exit thickness 0.5%, exit thickness deviation improves 1.5% less than the ratio of exit thickness 1%, achieve acid and roll the stable rolling of thin gauge strip, improve for plate shape and provide precondition, improve sour rolling mill lumber recovery.
Accompanying drawing explanation
Fig. 1 is volume 100 T4 material, the sharing of load result figure often rolled up.
Fig. 2 is volume 100 T5 material, the sharing of load result figure often rolled up.
Detailed description of the invention
In order to deepen the understanding of the present invention and understanding, the invention will be further described below in conjunction with the accompanying drawings and introduces.
The present invention is applied in prunus mume (sieb.) sieb.et zucc. steel 1,420 5 frame six roller UCM acid milling train automatically controls, it is possible to be applied to other kinds of milling train.
Milling equipment parameter is rolled in table 1: Mei Gang 1420 acid
Sequence number | Device name | Parameter |
1 | Working roll size mm | φ435/φ385X1420 |
2 | Intermediate calender rolls size mm | φ490/φ440X1400 |
3 | Support roller size mm | φ1300/φ1150×1420 |
4 | Power of motor kw | 4600 |
5 | Motor speed rpm | 400/1200 |
6 | Intermediate roll shifting amount mm | 0/380 |
7 | Work roll bending kn | -180/400 |
8 | Intermediate calender rolls roller kn | 10/500 |
Acid is rolled in production, product specification is a lot, for the ease of carry calculation, different with thickness according to product width, in conjunction with milling train product mix, it is divided into different brackets, division methods: be three width grades according to the width different demarcation of strip steel, in each width grade, is divided into 11 level of thickness according to exit thickness.
Embodiment 1: Fig. 1 is volume 100 T4 material, and entrance 2.0mm, width 800-900mm, the sharing of load result that exit thickness 0.201mm specification is often rolled up, sr1-sr5 is the load of 1-5 frame.
Table 2 width grade correspondence table;
Grade | Width range (mm) |
1 | 700≤width < 800 |
2 | 800≤width < 900 |
3 | 900≤width < 1000 |
Table 3 level of thickness correspondence table;
Grade | Thickness range (mm) |
1 | 0≤thickness < 0.17 |
2 | 0.17≤thickness < 0.18 |
3 | 0.18≤thickness < 0.19 |
4 | 0.19≤thickness < 0.20 |
5 | 0.20≤thickness < 0.22 |
6 | 0.22≤thickness < 0.25 |
7 | 0.25≤thickness < 0.30 |
8 | 0.30≤thickness < 0.35 |
9 | 0.35≤thickness < 0.40 |
10 | 0.40≤thickness < 0.45 |
11 | 0.45≤thickness < 0.55 |
Table 4 T4 expects 800-900mm width 1-5 coefficient of balance, wherein the 1st is classified as 1,2 frame roll-force coefficients of balance, and 2-5 is classified as 2-5 frame power-balance coefficient
Table 5 initial depression coefficient table
T4 expects, specification: inlet thickness is 2.0mm, and exit thickness is 0.201mm, and width is to be illustrated as a example by 856mm, 2# frame is individually replaced working roll, and calculation procedure is as follows:
1) the initial depression load of 1-5 frame is calculated
It is 0.2241,0.4591,0.6492,0.8294,1 that material rate according to T4 material, width, thickness check in the initial depression coefficient of this specification, and according to below equation, the exit thickness being calculated 1-5 frame is:
H1=2*e(0.2241*ln(0.201/2))=1.195
H2=2*e(0.4591*ln(0.201/2))=0.679
H3=2*e(0.6492*ln(0.201/2))=0.450
H4=2*e(0.8294*ln(0.201/2))=0.297
H5=2*e(1*ln(0.201/2))=0.201
Calculate the exit thickness of 1-5 frame, further according to formula
The load being calculated 1-5 frame is:
Sr1=(2-1.195)/2=40.2%
Sr2=(1.195-0.679)/1.195=41.7%
Sr3=(0.679-0.450)/0.679=35.4%
Sr4=(0.450-0.297)/0.450=33.9%
Sr5=(0.297-0.201)/0.297=32.4%
2) after the independent roll change of 2# frame, owing to 2# frame coefficient of friction changes, coefficient of friction penalty coefficient improves 30%, and the roll-force of 2# frame is greatly improved, according to tube rolling simulation formula, the roll-force being calculated 1,2 frames is respectively 847 tons, 889 tons;
3) roll-force coefficient of balance is calculated
According to width, thickness, checking in the coefficient of balance between 1,2 frames in table 4 is 110, then
Bal=100*847/889/ (110+0)
=0.86
4) roll-force coefficient of balance Bal is checked;
α takes 2%, due to bal < 0.98, if coefficient of balance Bal meets above-mentioned condition, then calculating and forward the 4th step to, otherwise revise load sr1, sr2 of 1,2 frames, correction is ± sr/ (10+3*loop), loop is cycle-index, starting to recalculate from second step, through 11 cycle calculations, the load of result 1-5 frame is 50.2,43.9,30.1,28.9,27.6;
Check the load of 1,2 frames, compensate roll-force coefficient of balance ComPa;
This steel grade exit thickness under smooth roll rolling mode is less than 0.35mm,
Sr1-sr2 > 1, reduces roll-force coefficient of balance ComPa=ComPa-1 automatically;
If 1, the load of 2 frames meets the most several situations, after compensation, forwarding the first step to and recalculate, otherwise calculate and terminate, the load finally giving 1-5 frame is 43.4,45.8,36.1,30.4,26.4.
As can be seen from Figure 1 volume 100 1-5 frame sharing of load situation, it is achieved that be held essentially constant with the load of steel grade same specification, on-the-spot without intervention, setting accuracy is improved.
Embodiment 2: Fig. 2 is volume 100 T5 material, and entrance 2.0mm, width 800-900mm, the sharing of load result that exit thickness 0.183mm specification is often rolled up, sr1-sr5 is the load of 1-5 frame.
Table 6 T5 expects 800-900mm width 1-5 coefficient of balance, wherein the 1st is classified as 1,2 frame roll-force coefficients of balance, and 2-5 is classified as 2-5 frame power-balance coefficient
Expecting with T5, specification: inlet thickness is 2.0mm, exit thickness is 0.183mm, and width is that 836mm is illustrated, and 1# frame is illustrated as a example by being individually replaced working roll, and calculation procedure is as follows:
1) the initial depression load of 1-5 frame is calculated
It is 0.2336,0.4751,0.6665,0.8356,1 that material rate according to T5 material, width, thickness check in the initial depression coefficient of this specification, and according to below equation, the exit thickness being calculated 1-5 frame is:
H1=2*e(0.2336*ln(0.201/2))=1.144
H2=2*e(0.4751*ln(0.201/2))=0.642
H3=2*e(0.6665*ln(0.201/2))=0.406
H4=2*e(0.8356*ln(0.201/2))=0.271
H5=2*e(1*ln(0.201/2))=0.183
Calculate the exit thickness of 1-5 frame, further according to formula
The load being calculated 1-5 frame is:
Sr1=(2-1.144)/2=42.8%
Sr2=(1.144-0.642)/1.144=43.9%
Sr3=(0.642-0.406)/0.642=36.7%
Sr4=(0.406-0.271)/0.406=33.3%
Sr5=(0.271-0.183)/0.271=32.5%
2) after the independent roll change of 1# frame, owing to 1# frame coefficient of friction changes, coefficient of friction penalty coefficient improves 30%, the roll-force of 2# frame is greatly improved, and the roll-force being calculated 1,2 frames according to deformation resistance, tension force, coefficient of friction, roll-force adaptation coefficient is respectively 1027 tons, 825 tons;
3) roll-force coefficient of balance is calculated;
According to width, thickness, checking in the coefficient of balance between 1,2 frames in table 6 is 105, then
Bal=100*1027/825/ (105+0)
=1.18
4) roll-force coefficient of balance Bal is checked;
α takes 2%, due to bal > 1.02, if coefficient of balance Bal meets above-mentioned condition, then calculating and forward the 4th step to, otherwise revise load sr1, sr2 of 1,2 frames, correction is ± sr/ (10+3*loop), loop is cycle-index, starting to recalculate from the first step, through 9 cycle calculations, the load of result 1-5 frame is 40.6,50.2,34.8,31.5,30.8
5) check the load of 1,2 frames, compensate roll-force coefficient of balance ComPa
This steel grade exit thickness under smooth roll rolling mode is less than 0.35mm;
Sr2-sr1 > 4, increases roll-force coefficient of balance ComPa=ComPa+1 automatically
After compensation, forwarding second step to and recalculate, otherwise calculate and terminate, the load finally giving 1-5 frame is 46.4,48.0,35.0,31.2,26.2.
As can be seen from Figure 2 volume 100 1-5 frame sharing of load situation, it is achieved that be held essentially constant with the load of steel grade same specification, on-the-spot without intervention, setting accuracy is improved.
It should be noted that above-described embodiment, be not used for limiting protection scope of the present invention, equivalents done on the basis of technique scheme or replacement each fall within the scope that the claims in the present invention are protected.
Claims (1)
1. one kind reduce mill load fluctuation method, it is characterised in that said method comprising the steps of: 1) calculate 1-5 frame initial depression load, between 1-2 frame use roll-force balance mode, between 2-5 frame use power balance system;
2) according to deformation resistance, tension force, coefficient of friction, the roll-force P1 P5 of roll-force adaptation coefficient calculating 15 frames;
Wherein: in formula, kp is average resistance of deformation, Dp is the frictional force impact on roll-force, and k is the tension force impact on roll-forceB is the width of strip steel, and zp is roll-force adaptation coefficient, and R ' is for flattening radius, and H is frame inlet thickness, and h is rack outlet thickness;
3) roll-force coefficient of balance is calculated;
Wherein P1 is the roll-force that 1# frame calculates, and P2 is the roll-force that 2# frame calculates, and A is a fixed value at 50-150, obtains from data form, and ComPa is roll-force coefficient of balance, is initially 0;
Check roll-force coefficient of balance Bal;
Wherein, α takes 2%, if coefficient of balance Bal meets above-mentioned condition, then calculates and forwards the 4th step to, otherwise revise load sr1, sr2 of 1,2 frames, and correction is ± sr/ (1+3*loop), and loop is cycle-index, starts to recalculate from the first step;
Check the load of 1,2 frames, compensate roll-force coefficient of balance ComPa
Compensation principle: following sr1 is the load of 1# frame, sr2 is the load of 2# frame:
Under smooth roll rolling mode, exit thickness is less than 0.35mm,
Sr1-sr2 > 1, reduces roll-force coefficient of balance ComPa=ComPa-1 automatically;
Sr2-sr1 > 4, increases roll-force coefficient of balance ComPa=ComPa+1 automatically;
Under hair roller rolling mode, exit thickness is under permanent roll-force constant voltage more than 0.35mm, 5# frame,
Sr1-sr2 > 3, reduces roll-force coefficient of balance ComPa=ComPa-1 automatically
Sr1-sr2 < 1, increases roll-force coefficient of balance ComPa=ComPa+1 automatically
If 1, the load of 2 frames meets the most several situations, after compensation, forward the first step to and recalculate, otherwise calculate and terminate.
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CN103372575A (en) * | 2012-04-17 | 2013-10-30 | 上海梅山钢铁股份有限公司 | Pickling and rolling mill load distribution method |
CN103962392A (en) * | 2013-01-28 | 2014-08-06 | 宝山钢铁股份有限公司 | Dynamic load control method for hot continuous finishing mill group |
Family Cites Families (1)
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JP4356309B2 (en) * | 2002-12-03 | 2009-11-04 | セイコーエプソン株式会社 | Transistors, integrated circuits, electro-optical devices, electronic equipment |
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JPH04356309A (en) * | 1991-05-31 | 1992-12-10 | Nippon Steel Corp | Method for controlling load balance of plural lines of rolling mill |
JPH05177223A (en) * | 1992-01-06 | 1993-07-20 | Nippon Steel Corp | Method for adjusting running schedule of tandem rolling mill |
JPH11197726A (en) * | 1998-01-14 | 1999-07-27 | Hitachi Ltd | Method for correcting load distribution of tandem rolling mill and controller |
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CN103372575A (en) * | 2012-04-17 | 2013-10-30 | 上海梅山钢铁股份有限公司 | Pickling and rolling mill load distribution method |
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