CN104808111B - Distribution line fault section location method based on energy function of releasing - Google Patents

Distribution line fault section location method based on energy function of releasing Download PDF

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CN104808111B
CN104808111B CN201510210537.5A CN201510210537A CN104808111B CN 104808111 B CN104808111 B CN 104808111B CN 201510210537 A CN201510210537 A CN 201510210537A CN 104808111 B CN104808111 B CN 104808111B
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releasing
fault
section
current
phase
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CN104808111A (en
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李广林
刁慕檩
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Shanghai feiyouche Energy Technology Co.,Ltd.
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SHANGHAI LOADING ENERGY TECHNOLOGY Co Ltd
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    • YGENERAL TAGGING OF NEW TECHNOLOGICAL DEVELOPMENTS; GENERAL TAGGING OF CROSS-SECTIONAL TECHNOLOGIES SPANNING OVER SEVERAL SECTIONS OF THE IPC; TECHNICAL SUBJECTS COVERED BY FORMER USPC CROSS-REFERENCE ART COLLECTIONS [XRACs] AND DIGESTS
    • Y04INFORMATION OR COMMUNICATION TECHNOLOGIES HAVING AN IMPACT ON OTHER TECHNOLOGY AREAS
    • Y04SSYSTEMS INTEGRATING TECHNOLOGIES RELATED TO POWER NETWORK OPERATION, COMMUNICATION OR INFORMATION TECHNOLOGIES FOR IMPROVING THE ELECTRICAL POWER GENERATION, TRANSMISSION, DISTRIBUTION, MANAGEMENT OR USAGE, i.e. SMART GRIDS
    • Y04S10/00Systems supporting electrical power generation, transmission or distribution
    • Y04S10/50Systems or methods supporting the power network operation or management, involving a certain degree of interaction with the load-side end user applications
    • Y04S10/52Outage or fault management, e.g. fault detection or location

Abstract

The invention discloses a kind of distribution line fault section location method based on energy function of releasing, for non-faulting section, its energy of releasing is kept approximately constant in normal operation and failure generating process, and numerical value is a minimum positive number;For fault section, energy function DC component of releasing variation tendency subtracts afterwards first to increase, and occurs to arc suppression coil to act in failure and reach maximum in output stabilization compensation current interval;Therefore fault section can determine whether according to increase multiple of the energy after failure generation of releasing, realizes fault location.The present invention occurs using failure and arc-extinction device acts the Wave data of overall process, avoid using zero-sequence current, can very well solve the problems, such as during the single-phase grounded malfunction in grounded system of low current of current generally existing that faint fault current, poor reliability, sensitivity are low, while system will not be introduced disturbing.

Description

Distribution line fault section location method based on energy function of releasing
Technical field
The present invention relates to distribution network line fault diagnostic method, specifically a kind of distribution line based on energy function of releasing Fault section location method.
Background technology
According to statistics, in the process of running, the power outage caused by Distribution Network Failure accounts for total power outage for power system More than 95%, wherein 70% accident is triggered by singlephase earth fault or bus-bar fault.And distribution neutral point is adopted extensively both at home and abroad With non-effective earthing (small current neutral grounding) mode, to avoid occurring causing power failure during singlephase earth fault.For distribution Singlephase earth fault, because fault characteristic value is faint, lacks reliable fault line selection and fault locating method always.As people are to matching somebody with somebody The raising of automation level requirement, more in the urgent need to fundamentally solving the fault-location problem of distribution.
The Fault Locating Method that current domestic and foreign scholars are proposed is roughly divided into two classes:One is injecting signal, and two is to be based on The section positioning of fault characteristic value.Injecting signal includes " S " injection method, alternating current-direct current synthesis injection method and parallel medium resistance method, Such method increases the interference to system, and can not detect instantaneity and intermittent grounding fault.Based on fault characteristic value Section positioning include zero mould electric current comparison method, section zero sequence admittance method, zero sequence reactive power direction method, based on difference of phase currents Positioning, residual method of addition, traveling wave method etc., such method existing characteristics amount obtains the keys such as difficulty, signal precise synchronization difficulty Sex chromosome mosaicism, and Part Methods reliability in high resistance ground is extremely low.
Current localization method have ignored the utilization to information before failure only using the data after failure generation.Meanwhile, Most of localization methods only consider zero-sequence current information (needing three phase informations), and high to transformer request, acquisition of information is complicated, and These methods will fail in the case of data phase shortage.
The content of the invention
It is an object of the invention to overcome above-mentioned the deficiencies in the prior art, it is proposed that a kind of matching somebody with somebody based on energy function of releasing Netting twine road fault section location method.
Principle of the invention:
In continuous-time domain, section Defining Instantaneous Power Components are
ΔpA(t)=p1A(t)-p2A(t)=u1A(t)·i1A(t)-u2A(t)·i2A(t)
In formula, ukA(t)、ikAT () is respectively test point k (k=1,2) place's failure phase phase voltage and phase current.Definition is released Energy function
In formula, T is a power frequency period (0.02s).
Make Δ u (t)=u1A(t)+u2A(t), Δ i (t)=i1A(t)+i2A(t), then
ΔpA(t)=u2A(t)·Δi(t)+i2A(t)·Δu(t)+Δu(t)·Δi(t) (1)
In formula, Section 3 is higher-order shear deformation relative to first two, negligible.
1) for non-faulting section (Fig. 1), Δ i (t) is section capacitive earth current.First two of analysis mode (1) below Size order.
The amplitude of section two ends difference between currentWherein b is the susceptance of circuit 1km, and the order of magnitude is about 10-6.Therefore the order of magnitude of section two ends difference between current amplitude is about 10-5(kA)。
Due to Load flow calculation pair as if three-phase symmetrical operation circuit, three-phase is reduced to a phase during analysis, because This part of theory is equally applicable to uniline.If U2APhase angle be 0 °, section both end voltage difference can be according to Load flow calculation phase Theoretical calculation is closed to draw
In formula, S=P2+jQ2To flow through the trend of the A phases of test point 2, and there is P2=| U2A||I2A| cos φ, Q2=| U2A| |I2A| sin φ (φ is line power factor angle);Z=R+jX is the complex impedance of section, and the order of magnitude is about 100~10-1.Section two Terminal voltage difference amplitude be
It can be seen that the order of magnitude of section both end voltage spread value is about 10-1(kV)。
Analyzed according to more than, u2A(t) Δ i (t) and i2AT the order of magnitude of () Δ u (t) ratio is about 10-2, Qian Zheke Ignore.Therefore, the section instantaneous power of non-faulting section can be reduced to
ΔpA(t)=i2A(t)·Δu(t)
For small current neutral grounding system, due to non-zero-sequence current path, when there is singlephase earth fault, fault current is far small In load current, load current amplitude can be regarded as constant.According to formula (2), section both end voltage spread value is in normal operation and event It is kept approximately constant in barrier overall process.On the other hand, the phase angle tangent of segment voltage difference
There is θ<90 °-φ, if θ+ε=90 °-φ, because line impedance meets R<<X, From left side close to 1, therefore ε is a minimum angle more than zero.That is segment voltage difference is advancedAngle be 90 ° of-φ- ε.And becauseAdvanced phase currentAngle is φ, thereforeIn advanceSummarize conclusion, i.e. Δ u (t) Amplitude it is constant, phase angle is constant and advanced phase current i2A(t)90°-ε。
If
Section instantaneous power is
Release energy function
It can be seen that, non-faulting section energy function of releasing is kept approximately constant in normal operation and failure generating process, and Numerical value is a minimum positive number.
2) for fault section (Fig. 2), the Section 2 of formula (4) derive and 1) in it is identical.Difference is section two ends Phase current difference is equal to section capacitance current and current in the fault point sum, i.e.,
Δ i (t)=Δ iC(t)+if(t)≈if(t)
Can not ignore.
Faulted phase voltage u2AT fundametal compoment is occupied an leading position in (), for ease of analysis, fundamental wave component is only considered below, Ignore the influence of harmonic wave and DC component.Then faulted phase voltage is represented by
Wherein U2mT () > 0 changes with time function for phase voltage fundamental voltage amplitude.
The electric current of trouble point is flowed through for system-wide capacitance current is multiplied by system off resonance degree v, is represented by
In formula, CΣIt is total system total ground capacitance, u0T () is the residual voltage of the period system, negative sign represents failure electricity Stream is opposite with capacitance current flow direction.Because residual voltage is ahead of 90 ° of faulted phase voltage, residual voltage can be expressed as
Wherein U0mT () >=0 is the function that residual voltage fundamental voltage amplitude is changed over time.Then
Section 1 is oscillating component in formula, and when energy function is released in calculating, oscillating component integrates in a cycle and is Zero.Therefore
If fault moment is t1, arc suppression coil action after and output stabilization compensation electric current moment be t2, as t < t1When, U0mT ()=0, can obtain Eel(t)=0;Work as t1+ T < t < t2When, in integrating range, residual voltage and phase voltage amplitude are all higher than Zero, and v ≈ 1, then EelT () is a positive number more than zero;As t > t2During+T, auto-tracing arc-eliminating coil is close to be fully compensated, V ≈ 0, Eel(t)≈0;[t1,t1+ T] and [t2,t2+ T] it is transition interval.I.e. for fault section, have
Therefore, occurred to arc suppression coil to act and E in output stabilization compensation current interval according to failureelThe size of (t), i.e., Can determine that fault section.
Step of the invention:
Failure phase Defining Instantaneous Power Components are
P (n)=u (n) i (n)
Wherein, u (n) and i (n) is phase voltage and phase current sampling sequence.Section two ends test point 1,2 failure phases (A phases) Instantaneous power be respectively
p1A(n)=u1A(n)·i1A(n)
p2A(n)=u2A(n)·i2A(n)
According to fourier series formula, the energy function of releasing on Disgrete Time Domain is defined
N is a power frequency period data point, relevant with sample frequency.
Similarly, when normally running, energy function of releasing is defined as
In formula,Any one phase in desirable A, B, C three-phase. Respectively Phase voltage, current sampling data when normally being run for test point 1,2.
Technical solution of the invention is as follows:
A kind of distribution network line fault Section Location based on energy function of releasing, its feature is, methods described Comprise the following steps:
Step S1, according to the phase voltage current data that each test point is measured, calculates respectively releasing under normal operation Energy function Eel,normal
Step S2, determines failure phase and fault moment tf:After the generation of earth fault is detected, changed according to phase voltage Rule, selects failure mutually i.e. Earth Phase, is mutated the moment according to phase voltage or the arc-extinction device chugging moment determines fault moment tf
Step S3, firstly, since the maximum of energy function of releasing was appeared in the arc suppression coil not operating period, it is most Its maximum is measured to obtain, while reducing amount of calculation, automatic tracking and compensating arc distinction device operation time limit is being taken into full account (2~5 weeks Ripple) on the basis of choose detection means [tf,tf+ 0.04s] it is interval in common 2N point faulted phase voltage, phase current waveform data, Calculate the energy function E that respectively releaseselK (), k=0,1 ..., N, formula is as follows:
In formula:ujA(n) and ijAN () is the faulted phase voltage and faulted phase current sample sequence that test point j is measured, N is One power frequency period data point, k=0,1 ... j ... N, k represent ordered series of numbers subscript in a cycle;
Then, the energy function maximum E that releases is soughtel,max=max { Eel(k)};
Step S4, according to releasing, energy increase multiple judges whether each section is fault section, i.e., the energy that ought release increase Multiple Eel,max/Eel,normal> Kset, then it is judged as fault section, on the contrary it is then non-faulting section, wherein, KsetIt is action threshold Value, is a positive number more than 1, and data reasonable set of its size according to acquisition system under normal circumstances typically takes 1~3;
Step S5, is distributed according to each test point, untill traversal is until finding out fault section.
Compared with prior art, the beneficial effects of the invention are as follows:To earth fault, by analyzing faulted phase current in failure There is preceding and failure and the phase current feature before acting occurs to arc suppression coil, therefrom extract fault characteristic value, and use overall process Waveform Euclidean distance positioned.Thus, it is only required to the faulted phase current of measurement circuitry, only considers that zero sequence (is needed before having broken Want three phase informations) tradition, data acquisition is simple, strong applicability;From from the point of view of signal synchronization, total system is used by GPS Synchronous Monitoring Data so that the difference between different test points is sensitiveer.The small electricity of current generally existing can very well be solved The problem that fault current is faint during stream single-phase grounded malfunction in grounded system, poor reliability, sensitivity are low, while will not draw to system Enter interference.
Brief description of the drawings
Fig. 1 is failure phase non-faulting section schematic diagram
Fig. 2 is failure phase fault section schematic diagram
Fig. 3 is distributed fault section positioning system structure figure
Fig. 4 is 10kV system emulation figures
Fig. 5 is failure and non-faulting is released energy function DC component curve
Specific embodiment
Fault waveform needed for the present invention comes from distributed fault section alignment system, and system architecture is as shown in Figure 3.Match somebody with somebody Electric network fault section alignment system is by master station, transformer station's (bus) measurement apparatus and is distributed in distribution line section everywhere Point failure positioner is constituted.Circuit is divided into some sections by fault location node in topology, three groups of each node installation Measurement apparatus, real-time synchronization collection circuit three-phase current and voltage.
According to the Fault Locating Method of invention, in 10kV power distribution network analogue systems, different types of failure is set.System 1., 2., 3. structure chart as shown in figure 4, be sector number, failure is arranged on section and 2. goes up.Sample frequency is 20kHz (each cycles Data point N=400), there is the moment for 0.5s in failure, arc-extinction device actuation time is set to 0.04s during earth fault, energy of releasing The threshold value of amount DC component increase multiple is set to 3.
Illustrated for the implementation method that fault section judges:
Step S1, according to the phase voltage current data that test point is measured, calculates under normal operation according to formula (5) 1., 2., the energy of releasing of 3. section, respectively 0.9912MJ, 1.0180MJ, 0.9920MJ;
Step S2, after system starts the generation for detecting earth fault according to residual voltage, measures A in bus three-phase voltage Mutually reduce, B, C phase are raised, and are defined as A phase faults;Determine that fault moment is 0.51s according to the phase voltage mutation moment;
Step S3, chooses totally 800 faulted phase voltages of point, phase current waveforms in measurement apparatus [0,51,0.55] interval Data (are designated as zero) under the data point for setting the failure generation moment, according to formula (4), calculate Eel(k), k=0,1 ..., N, and ask Eel,max=max { Eel(k) }, as a result as shown in table 1;
Table 1 is singlephase earth fault simulation result
Wherein, fault section and non-faulting energy function curve of releasing are as shown in Figure 5 during 500 Ω earth resistances.
Step S4, section 2. release energy increase multipleIt is judged as its fault section, conversely, 1., 3. section is non-faulting section.

Claims (3)

1. a kind of distribution network line fault Section Location based on energy function of releasing, it is characterised in that methods described bag Include following steps:
Step S1, according to the phase voltage current data that each test point is measured, calculates the energy of respectively releasing under normal operation Function DC component Eel,normal
Step S2, determines failure phase and fault moment tf
Step S3, first, chooses detection means [tf,tf+ 0.04s] it is interval in common 2N point faulted phase voltage, phase current waveform Data, calculate the energy function E that respectively releaseselK (), k=0,1 ..., N, formula is as follows:
E e l ( k ) = &Sigma; n = k k + N - 1 &lsqb; u 1 A ( n ) &CenterDot; i 1 A ( n ) - u 2 A ( n ) &CenterDot; i 2 A ( n ) &rsqb;
In formula:ujA(n) and ijAN () is the faulted phase voltage and faulted phase current sample sequence that test point j is measured, N is one Power frequency period data point, k=0,1 ... j ... N, k represent ordered series of numbers subscript in a cycle;
Then, the energy function maximum E that releases is soughtel,max=max { Eel(k)};
Step S4, according to releasing, energy increase multiple judges whether each section is fault section, i.e., the energy that ought release increase multiple Eel,max/Eel,normal> Kset, then it is judged as fault section, otherwise be then non-faulting section;
Step S5, is distributed according to each test point, untill traversal is until finding out fault section.
2. the distribution network line fault Section Location based on energy function of releasing according to claim 1, its feature It is that the step S2 includes:
After the generation of earth fault is detected, according to phase voltage Changing Pattern, failure mutually i.e. Earth Phase is selected, according to phase voltage Mutation moment or arc-extinction device chugging moment determine fault moment tf
3. the distribution network line fault Section Location based on energy function of releasing according to claim 1, its feature It is K in the step S4setIt is the artificial action threshold value for setting, takes 1~3.
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CN111596170A (en) * 2020-05-27 2020-08-28 国网上海市电力公司 Fault diagnosis comprehensive positioning method for intelligent distribution network

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Publication number Priority date Publication date Assignee Title
CN2158545Y (en) * 1993-04-24 1994-03-09 天津电力试验研究所 Instrument for indicating fault in low-voltage cable
CN101576597A (en) * 2008-05-08 2009-11-11 李尔公司 Ground-fault detection system for vehicles with a high-voltage power net
CN102809714A (en) * 2012-08-02 2012-12-05 兰州交通大学 Method for diagnosing corrosion fault of grounding grid of traction substation
CN102830328A (en) * 2012-08-23 2012-12-19 上海交通大学 Distributed fault location method for T-circuit
CN103645422A (en) * 2013-12-18 2014-03-19 国家电网公司 Online analyzing method for grid forced power oscillation caused by internal disturbance of power plant
CN104155582A (en) * 2014-08-29 2014-11-19 上海交通大学 Distribution network line fault section positioning method based on full-waveform information

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