CN104518488A - Load point fault area type division method for reliability analysis on power distribution network - Google Patents
Load point fault area type division method for reliability analysis on power distribution network Download PDFInfo
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- CN104518488A CN104518488A CN201410839623.8A CN201410839623A CN104518488A CN 104518488 A CN104518488 A CN 104518488A CN 201410839623 A CN201410839623 A CN 201410839623A CN 104518488 A CN104518488 A CN 104518488A
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Abstract
The invention provides a load point fault area type division method for reliability analysis on a power distribution network. The method comprises the concrete steps as follows: establishing the set of all elements in the target power distribution network; constructing an adjacent matrix of the target power distribution network; conducting area division on the target power distribution network by taking a switch as a boundary; conducting area division on the power distribution network by taking an automatic switch as a boundary; conducting load point fault area division and load point fault arc division. The target power distribution network is divided into four fault areas through intersection, subtraction and union operations of a shortest-path set and a switch-boundary set. The method doesn't need load flow calculation, is convenient for analysis on the problem about network topology of a radial power distribution network with sub feeders, can quickly finish fault area type division and can be applied to reliability evaluation of the power distribution network.
Description
Technical field
The present invention relates to distribution network reliability analysis field, specifically for the load point fault zone Type division method of distribution network reliability analysis.
Background technology
Distribution system has the advantages that node is many, grid structure is complicated, realizes by grid structure the difficult point that Reliability evaluation is evaluating reliability of distribution network fast.At present, evaluating reliability of distribution network mainly adopts the fault mode consequences analysis method in analytic method, under considering distributed power source situation, then adopt Monte Carlo simulation method.All need the analysis realizing power distribution network network topology in two kinds of methods, analysis of networks topology mainly contains BFS method based on incidence matrices and depth-first search, and these two kinds of searching methods are comparatively complicated.
Summary of the invention
The present invention is directed to the deficiencies in the prior art, have radial and without the feature of parallel line according to power distribution network, adopt the Topology Analysis of Power Distribution Network based on set operation, be provided for the load point fault zone Type division method that distribution network reliability is analyzed, to realize the division of system failure influence area fast.
To achieve these goals, present invention employs following technical scheme:
For the load point fault zone Type division method that distribution network reliability is analyzed, comprise the steps:
(1) according to the annexation of elements all in target power distribution network, the topological diagram that the principle equivalence formed according to node becomes to represent with summit and limit, and serial number is carried out to all nodes, set up the set U of all nodes
aLL=[1 23 ... n];
(2) adjacency matrix of target power distribution network is constructed:
Also comprise the steps:
(3) be that Region dividing is carried out to target power distribution network in border with switch, concrete grammar is as follows:
Step1: make K
x(x=1,2,3) are for being the node set that the xth on a border region comprises with switch in target power distribution network;
Step2: in adjacency matrix, a line that any selection did not judge as starting point, by the line number of this row stored in set K
xin, and by the row of all elements 2 column in this row number stored in set K
xin;
Step3: using the row of element 2 column in this row as the line number judged next time, jumps to the corresponding row do not judged and by the row of all elements 2 column in the row of correspondence number stored in set K
xin;
Step4: repeat Step3, until do not need only to jump to new behavior;
Step5: repeat element is only got once by the element heterogeneite principle according to set, obtaining take switch as the xth region K on border
x;
Step6: make x=x+1, returns Step2, judges remaining row in adjacency matrix, till all provisional capitals of adjacency matrix carried out once judging;
(4) be that Region dividing is carried out to power distribution network in border with automatic switch, concrete grammar is as follows:
Step1: make G
x(x=1,2,3) are for being the node set that the xth on a border region comprises with automatic switch in target power distribution network;
Step2: in adjacency matrix, a line that any selection did not judge as starting point, by the line number of this row stored in set G
xin, and by the row of all elements 2 in this row and element-1 column number stored in set G
xin;
Step3: using the row of element 2 in this row and element-1 column as the line number judged next time, jumps to the corresponding row do not judged and by the row of all elements 2 in the row of correspondence and element-1 column number stored in set G
xin;
Step4: repeat Step3, until do not need only to jump to new behavior;
Step5: repeat element is only got once by the element heterogeneite principle according to set, obtaining take automatic switch as the xth region G on border
x;
Step6: make x=x+1, returns Step2, judges remaining row in adjacency matrix, till all provisional capitals of adjacency matrix carried out once judging;
(5) load point faulty section divides
If target power distribution network is single width penetrate network, then the stand-by power supply number n=0 in target power distribution network;
The first, determine the shortest path of required load point to main power source, the node on shortest path is formed a set FZ;
The second, load point faulty section divides
1. determine to take switch as the set on border in FZ belonging to each node, then get union and obtain target power distribution network category-A faulty section node set A;
2. determine to take automatic switch as the set on border in FZ belonging to each node, then get union C
1, then remove the node deleting category-A faulty section, obtain target power distribution network C class faulty section node set C=C
1-A;
3. target power distribution network D class faulty section node set D=U
aLL-A-C;
(5 ') load point faulty section divides
If target power distribution network is looped network network, then stand-by power supply number n >=1 in target power distribution network;
The first, determine the shortest path of required load point to main power source, the node on shortest path is formed a set FZ;
The second, determine the set FB of node on required load point to a first stand-by power supply shortest path
1, determine the set FB of node on required load point to a second stand-by power supply shortest path
2, the like, finally determine the set FB of node on required load point to the n-th stand-by power supply shortest path
n, order set FB=FB
1∩ FB
2∩ ∩ FB
n;
3rd, seek common ground J=FZ ∩ FB;
4th, load point faulty section divides
1. determine to take switch as the region on border in common factor J belonging to each node respectively, then get the node set A that union obtains power distribution network category-A faulty section;
2. determining respectively to gather in FZ belonging to each node take switch as the region on border, then gets union B
1, then delete the node of category-A faulty section, obtain the node set B=B of power distribution network category-B faulty section
1-A;
3. the set C of the node on the shortest path of last position node to the first stand-by power supply of common factor J is set up
11, set up the set C of the node on the shortest path of last position node to the second stand-by power supply of common factor J
12, the like, finally set up the set C of the node on the shortest path of last position node to the n-th stand-by power supply of common factor J
1n; C
1=C
11∪ C
12∪ ∪ C
1n, make C
2=C
1∪ FZ, determines C respectively
2in belonging to each node take automatic switch as the region on border, then get union C
3, then delete the node of category-A faulty section, the node of category-B faulty section and stand-by power supply, obtain the node set C=C of power distribution network C class faulty section
3-A-B-stand-by power supply;
4. the node set D=U of power distribution network D class faulty section
aLL-A-B-C;
(6) load point fault arc divides
Determine all connection arcs comprised in target power distribution network,
To the connection arc of category-A faulty section node be contained as target power distribution network category-A fault arc;
The connection arc of category-B faulty section node will be contained, after deleting category-A fault arc, as target power distribution network category-B fault arc;
The connection arc of C class faulty section node will be contained, after deleting category-A fault arc and category-B fault arc, as target power distribution network C class fault arc;
The connection arc of D class faulty section node will be contained, after deleting category-A fault arc, category-B fault arc and C class fault arc, as target power distribution network D class fault arc;
(7) repeat (5) or (5 ') and (6), faulty section division and the division of fault arc are carried out to each load point in power distribution network.
Described step (5) or in (5 '), the set FB of node on shortest paths
1, FB
2, FB
nand in FZ, element arranges according to the node sequencing of process in load point to the direction of main power source.
Hand switch comprises isolating switch, section breaker and interconnection switch; Automatic switch comprises circuit breaker and fuse.
Compared with prior art, the beneficial effect that possesses of the present invention:
By shortest path set, switch boundary intersection of sets, difference, union, target power distribution network is divided into four class faulty sections.The method, without the need to carrying out Load flow calculation, is convenient to the radial power distribution system network topological issues analyzing belt feeder line, is completed the division of fault zone type fast, and can be applicable in evaluating reliability of distribution network.
Accompanying drawing explanation
Fig. 1 is that the typical single width of embodiment 1 of the present invention penetrates power distribution network figure.
Fig. 2 is the typical Single-ring network power distribution network figure of embodiment 2 of the present invention.
Fig. 3 is the many segmentations of the typical case multi-joint network power distribution network figure of embodiment 3 of the present invention.
Embodiment
Below by embodiment, technical scheme of the present invention is further elaborated.
Embodiment 1
Choose typical single width and penetrate power distribution network, concrete wiring as shown in Figure 1, contains 5 load point in power distribution network.
(1) according to the annexation of elements all in target power distribution network, the topological diagram that the principle equivalence formed according to node becomes to represent with summit and limit, and serial number is carried out to all nodes, described typical single width penetrates the set U of all nodes of power distribution network
aLL=[1 23 456789 10 11 12 13 14 15 16 17 18 19 20 21].
(2) tectonic system adjacency matrix
(3) be that Region dividing is carried out to power distribution network in border with switch:
K
1＝[1]、K
2＝[2 3 4 5 6 7]、K
3＝[8 9]、K
4＝[10 11]、K
5＝[12 13]、K
6＝[14 15 16 17]、K
7＝[18 19 20 21]。
(4) be that Region dividing is carried out to power distribution network in border with automatic switch:
G
1＝[1]、G
2＝[2 3 4 5 6 7 8 9 10 11 14 15 16 17]、G
3＝[12 13]、G
4＝[18 19 20 21]。
(5) load point subregion
Load point 7:
The set FZ=[7 65432 1] of node on the shortest path of 1. load point 7 to main power source 1;
Load point faulty section divides
2. determining respectively to gather in FZ belonging to each node take switch as the region on border,
Region belonging to 7th node 7 is K
2,
Region belonging to 6th node 6 is K
2,
Region belonging to 5th node 5 is K
2,
Region belonging to 4th node 4 is K
2,
Region belonging to 3rd node 3 is K
2,
Region belonging to Section Point 2 is K
2,
Region belonging to first node 1 is K
1,
The then node set A=K of this power distribution network category-A faulty section
2∪ K
2∪ K
2∪ K
2∪ K
2∪ K
2∪ K
1=[1 23456 7];
3. determining respectively to gather in FZ belonging to each node take automatic switch as the region on border,
Region belonging to 7th node 7 is G
2,
Region belonging to 6th node 6 is G
2,
Region belonging to 5th node 5 is G
2,
Region belonging to 4th node 4 is G
2,
Region belonging to 3rd node 3 is G
2,
Region belonging to Section Point 2 is G
2,
Region belonging to first node 1 is G
1,
The then node set C=G of this power distribution network C class faulty section
2∪ G
2∪ G
2∪ G
2∪ G
2∪ G
2∪ G
1-A=[8 9 10 11 14 1,516 17];
4. the node set D=U of this power distribution network D class faulty section
aLL-A-C=[12 13 18 19 20 21];
Load point fault arc divides
It is (1-2), (3-10), (5-8), (11-12), (11-14) and (15-18) that the described typical single width of this enforcement penetrates connection arcs all in power distribution network, totally six.
5. the connection arc comprising category-A faulty section node is as follows:
Comprise the connection arc of first node 1 for (1-2),
Comprise the connection arc of Section Point 2 for (1-2),
Comprise the connection arc of the 3rd node 3 for (3-10),
Comprise the connection arc of the 5th node 5 for (5-8),
The 4th node 4, the 6th node 6 or the 7th node 7 is comprised without connecting arc,
To sum up, the described typical single width of this enforcement penetrates the category-A fault arc of power distribution network is (1-2), (3-10) and (5-8);
6. the connection arc containing C class faulty section node is as follows:
Comprise the connection arc of the 8th node 8 for (5-8),
Comprise the connection arc of protelum point 10 for (3-10),
Comprise the connection arc of the 11 node 11 for (11-12) and (11-14),
Comprise the connection arc of the 14 node 14 for (11-14),
Comprise the connection arc of the 15 node 15 for (15-18),
The 9th node the 9, the 16 node the 16 or the 17 node 17 is comprised without connecting arc,
After deleting category-A fault arc, to sum up, the C class fault arc that the described typical single width of this enforcement penetrates power distribution network is (11-12), (11-14) and (15-18);
7. the connection arc containing D class faulty section node is as follows:
Comprise the connection arc of the 12 node 12 for (11-12),
Comprise the connection arc of the 18 node 18 for (15-18),
The 13 node the 13, the 19 node the 19, the 20 node the 20 or the 21 node 21 is comprised without connecting arc,
After deleting category-A fault arc, category-B fault arc and C class fault arc, to sum up, the described typical single width of this enforcement penetrates power distribution network without D class fault arc.
(7) repeat (5) and (6), each load point in power distribution network is penetrated to single width typical this enforcement described and carries out faulty section division and the division of fault arc.
Embodiment 2
Build typical Single-ring network power distribution network, it is identical that its structure and single width penetrate power distribution network, and draw interconnection in the 19 node 19 place and be connected with stand-by power supply, stand-by power supply is as the 22 node, and concrete wiring as shown in Figure 2.
(1) according to the annexation of all elements in typical Single-ring network power distribution network, the topological diagram that the principle equivalence formed according to node becomes to represent with summit and limit, and serial number is carried out to all nodes, the set of all nodes: U in described typical Single-ring network power distribution network
aLL=[1 23456789 10 11 12 13 14 15 16 17 18 19 20 21 22].
(2) tectonic system adjacency matrix
(3) be that Region dividing is carried out to power distribution network in border with switch:
K
1＝[1]、K
2＝[2 3 4 5 6 7]、K
3＝[8 9]、K
4＝[10 11]、K
5＝[12 13]、K
6＝[14 15 16 17]、K
7＝[1819 20 21]、K
7＝[22]。
(4) be that Region dividing is carried out to power distribution network in border with automatic switch:
G
1＝[1]、G
2＝[2 3 4 5 6 7 8 9 10 11 14 15 16 17]、G
3＝[12 13]、G
4＝[18 19 20 21 22]。
(5 ') load point subregion
Load point 7:
1. the set of minimal paths FZ=[7 65432 1] of load point 7 to main power source 1;
2. the set of minimal paths FB=[7 6543 10 11 14 15 18 19 22] of load point 7 to stand-by power supply 22;
3. get common factor J=FZ ∩ FB=[7 654 3], the last position node of common factor J is the 3rd node 3;
Load point faulty section divides
4. determine to take switch as the region on border in common factor J belonging to each node respectively,
Region belonging to 7th node 7 is K
2,
Region belonging to 6th node 6 is K
2,
Region belonging to 5th node 5 is K
2,
Region belonging to 4th node 4 is K
2,
Region belonging to 3rd node 3 is K
2,
Then the node set A=K that union obtains this power distribution network category-A faulty section is got
2∪ K
2∪ K
2∪ K
2∪ K
2=[2 3456 7];
5. determining respectively to gather in FZ belonging to each node take switch as the region on border,
Region belonging to 7th node 7 is K
2,
Region belonging to 6th node 6 is K
2,
Region belonging to 5th node 5 is K
2,
Region belonging to 4th node 4 is K
2,
Region belonging to 3rd node 3 is K
2,
Region belonging to Section Point 2 is K
2,
Region belonging to first node 1 is K
1,
Then union B is got
1=K
2∪ K
2∪ K
2∪ K
2∪ K
2∪ K
1, then delete the node of category-A faulty section, then the node set B=B of this power distribution network category-B faulty section
1-A=[1];
6. the set C of the node on the shortest path of the 3rd node 3 to stand-by power supply 22 of last position in common factor J is set up
1=[3 10 1,114 15 18 19 22], make C
2=C
1∪ FZ=[7 654321 10 11 14 15 18 19 22], determines common factor C respectively
2in belonging to each node take automatic switch as the region on border,
Region belonging to 7th node 7 is G
2,
Region belonging to 6th node 6 is G
2,
Region belonging to 5th node 5 is G
2,
Region belonging to 4th node 4 is G
2,
Region belonging to 3rd node 3 is G
2,
Region belonging to Section Point 2 is G
2,
Region belonging to first node 1 is G
1,
Region belonging to protelum point 10 is G
2,
Region belonging to 11 node 11 is G
2,
Region belonging to 14 node 14 is G
2,
Region belonging to 15 node 15 is G
2,
Region belonging to 18 node 18 is G
4,
Region belonging to 19 node 19 is G
4,
Region belonging to 22 node 22 is G
4,
Then union C is got
3=G
2∪ G
2∪ G
2∪ G
2∪ G
2∪ G
2∪ G
1∪ G
2∪ G
2∪ G
2∪ G
2∪ G
4∪ G
4∪ G
4, then delete the node of category-A faulty section, the node of category-B faulty section and stand-by power supply, then the node set C=C of this power distribution network C class faulty section
3-A-B-[22]=[8 9 10 11 14 15 16 17];
7. the node set D=U of this power distribution network D class faulty section
aLL-A-B-C=[12 13 18 19 20 21 22];
Fault arc divides
In the described typical Single-ring network power distribution network of this enforcement, all connection arcs are (1-2), (3-10), (5-8), (11-12), (11-14), (15-18) and (19-22), totally seven.
8. the connection arc comprising category-A faulty section node is as follows:
Comprise the connection arc of Section Point 2 for (1-2),
Comprise the connection arc of the 3rd node 3 for (3-10),
Comprise the connection arc of the 5th node 5 for (5-8),
The 4th node 4, the 6th node 6 or the 7th node 7 is comprised without connecting arc,
To sum up, the category-A fault arc of the described typical Single-ring network power distribution network of this enforcement is: (1-2), (3-10) and (5-8);
9. the connection arc containing category-B faulty section node is as follows:
Comprise the connection arc of first node 1 for (1-2),
Delete category-A fault arc, to sum up, the described typical Single-ring network power distribution network of this enforcement is without category-B fault arc.
10. the connection arc containing C class faulty section node is as follows:
Comprise the connection arc of the 8th node 8 for (5-8),
Comprise the connection arc of protelum point 10 for (3-10),
Comprise the connection arc of the 11 node 11 for (11-12) and (11-14),
Comprise the connection arc of the 14 node 14 for (11-14),
Comprise the connection arc of the 15 node 15 for (15-18);
The 9th node the 9, the 16 node the 16 or the 17 node 17 is comprised without connecting arc,
After deleting category-A fault arc and category-B fault arc, the C class fault arc of the described typical Single-ring network power distribution network of this enforcement is: (11-12), (11-14) and (15-18);
(11) the connection arc containing D class faulty section node is as follows:
Comprise the connection arc of the 12 node 12 for (11-12),
Comprise the 13 node the 13, the 20 node the 20, the 21 node 21 without connection arc,
Comprise the connection arc of the 18 node 18 for (15-18),
Comprise the connection arc of the 19 node 19 for (19-22),
Comprise the connection arc of the 22 node 22 for (19-22),
After deleting category-A fault arc, category-B fault arc and C class fault arc, the described typical Single-ring network power distribution network of this enforcement is (19-22) without D class fault arc.
(7) repeat (5 ') and (6), faulty section division and the division of fault arc are carried out to each load point in Single-ring network power distribution network typical this enforcement described.
Embodiment 3
Build the multi-joint network power distribution network of typical many segmentations, it is identical that system configuration and single width penetrate power distribution network, draws interconnection respectively with stand-by power supply to be connected in the 15 node the 15, the 19 node 19 place, and concrete wiring as shown in Figure 3.
(1) according to the annexation of all elements in the many segmentations of typical case multi-joint network power distribution network, the topological diagram that the principle equivalence formed according to node becomes to represent with summit and limit, and serial number is carried out to all nodes, the set of all nodes: U in the many segmentations of described typical case multi-joint network power distribution network
aLL=[1 23456789 10 11 12 13 14 15 16 17 18 19 20 21 22 23];
(2) tectonic system adjacency matrix
(3) be that Region dividing is carried out to power distribution network in border with switch:
K
1＝[1]、K
2＝[2 3 4 5 6 7]、K
3＝[8 9]、K
4＝[10 11]、K
5＝[12 13]、K
6＝[14 15 16 17]、K
7＝[1819 20 21]、K
8＝[22]、K
9＝[23]。
(4) be that Region dividing is carried out to power distribution network in border with automatic switch:
G
1＝[1]、G
2＝[2 3 4 5 6 7 8 9 10 11 14 15 16 17 23]、G
3＝[12 13]、G
4＝[18 19 20 21 22]。
(5 ') load point subregion
Load point 7:
The set FZ=[7 65432 1] of node on the shortest path of 1. load point 7 to main power source 1;
The set FB of node on the shortest path of 2. load point 7 to the first stand-by power supplies 22
1=[7 6543 10 11 14 15 1,819 22],
The set FB of node on the shortest path of load point 7 to the second stand-by power supplies 23
2=[7 6543 10 11 14 15 23],
Then FB=FB
2∩ FB
1=[7 6543 10 11 14 15];
3. the last position node of common factor J=FZ ∩ FB=[7 654 3], common factor J is the 3rd node 3;
Load point faulty section divides
4. determine to take switch as the region on border in common factor J belonging to each node respectively,
Region belonging to 7th node 7 is K
2,
Region belonging to 6th node 6 is K
2,
Region belonging to 5th node 5 is K
2,
Region belonging to 4th node 4 is K
2,
Region belonging to 3rd node 3 is K
2,
Then the node set A=K that union obtains this power distribution network category-A faulty section is got
2∪ K
2∪ K
2∪ K
2∪ K
2=[2 3456 7];
5. determining respectively to gather in FZ belonging to each node take switch as the region on border,
Region belonging to 7th node 7 is K
2,
Region belonging to 6th node 6 is K
2,
Region belonging to 5th node 5 is K
2,
Region belonging to 4th node 4 is K
2,
Region belonging to 3rd node 3 is K
2,
Region belonging to Section Point 2 is K
2,
Region belonging to first node 1 is K
1,
Then union B is got
1=K
2∪ K
2∪ K
2∪ K
2∪ K
2∪ K
2∪ K
1, then delete the node of category-A faulty section, then the node set B=B of this power distribution network category-B faulty section
1-A=[1];
6. the set C of the node on the shortest path of the 3rd node 3 to the first stand-by power supplies 22 of last position in common factor J is set up
11=[3 10 11 14 15 18 19 22], set up the set C of the node on the shortest path of last position the 3rd node 3 to the second stand-by power supplies 23 of common factor J
12=[3 10 11 14 15 23]; C
1=C
11∪ C
12=[3 10 11 14 15 18 19 22 23], make C
2=C
1∪ FZ=[7 654321 10 11 14 15 18 19 22 23], determines union C respectively
2in belonging to each node take automatic switch as the region on border,
Region belonging to 7th node 7 is G
2,
Region belonging to 6th node 6 is G
2,
Region belonging to 5th node 5 is G
2,
Region belonging to 4th node 4 is G
2,
Region belonging to 3rd node 3 is G
2,
Region belonging to Section Point 2 is G
2,
Region belonging to first node 1 is G
1,
Region belonging to protelum point 10 is G
2,
Region belonging to 11 node 11 is G
2,
Region belonging to 14 node 14 is G
2,
Region belonging to 15 node 15 is G
2,
Region belonging to 18 node 18 is G
4,
Region belonging to 19 node 19 is G
4,
Region belonging to 22 node 22 is G
4,
Region belonging to 23 node 23 is G
2,
Then union C is got
3=G
2∪ G
2∪ G
2∪ G
2∪ G
2∪ G
2∪ G
1∪ G
2∪ G
2∪ G
2∪ G
2∪ G
4∪ G
4∪ G
4∪ G
2, then delete the node of category-A faulty section, the node of category-B faulty section and stand-by power supply, then the node set C=C of this power distribution network C class faulty section
3-A-B-[22]-[23]=[8 9 10 11 14 15 16 17];
7. the node set D=U of this power distribution network D class faulty section
aLL-A-B-C=[12 13 18 19 20 21 22 23];
Load point fault arc divides
This implements that connection arcs all in the many segmentations of described typical case multi-joint network power distribution network is (1-2), (3-10), (5-8), (11-12), (11-14), (15-18) (19-22) and (15-23), totally seven.
8. the connection arc comprising category-A faulty section node is as follows:
Comprise the connection arc of Section Point 2 for (1-2),
Comprise the connection arc of the 3rd node 3 for (3-10),
Comprise the connection arc of the 5th node 5 for (5-8),
The 4th node 4, the 6th node 6 or the 7th node 7 is comprised without connecting arc,
To sum up, this category-A fault arc implementing the multi-joint network power distribution network of the many segmentations of described typical case is: (1-2), (3-10), (5-8);
9. the connection arc comprising category-B faulty section node is as follows:
Comprise the connection arc of first node 1 for (1-2),
Delete category-A fault arc, to sum up, this implements the category-B fault arc of the multi-joint network power distribution network of the many segmentations of described typical case: (empty set);
10. the connection arc comprising C class faulty section node is as follows:
Comprise the connection arc of the 8th node 8 for (5-8),
Comprise the connection arc of protelum point 10 for (3-10),
Comprise the connection arc of the 11 node 11 for (11-12) and (11-14),
Comprise the connection arc of the 14 node 14 for (11-14),
Comprise the connection arc of the 15 node 15 for (15-18);
The 9th node the 9, the 16 node the 16, the 17 node 17 is comprised without connecting arc,
Delete category-A fault arc and category-B fault arc, to sum up, this C class fault arc implementing the multi-joint network power distribution network of the many segmentations of described typical case is (11-12), (11-14) and (15-18);
(11) the connection arc comprising D class faulty section node is as follows:
Comprise the connection arc of the 12 node 12 for (11-12),
Comprise the connection arc of the 18 node 18 for (15-18),
Comprise the connection arc of the 19 node 19 for (19-22),
Comprise the connection arc of the 22 node 22 for (19-22),
Comprise the connection arc of the 23 node 23 for (15-23),
The 13 node the 13, the 20 node the 20 or the 21 node 21 is comprised without connecting arc,
Delete category-A fault arc, category-B fault arc and C class fault arc, to sum up, this implements the D class fault arc of the multi-joint network power distribution network of the many segmentations of described typical case for (19-22) and (15-23).
(7) repeat (5 ') and (6), each load point in the multi-joint network power distribution network of the many segmentations of described typical case is implemented to this and carries out faulty section division and the division of fault arc.
In sum, the faulty section obtained according to the method for the invention and fault arc, the analytical calculation of each load point index in evaluating reliability of distribution network can be realized fast, be summarized as follows: load point annual fault outage number of times equals the cumulative of category-A, category-B and C class faulty section and fault arc corresponding node failure rate; The load point annual fault outage time equals category-A faulty section and category-A fault arc corresponding node failure rate and is multiplied by node failure repair time, category-B faulty section and category-B fault arc corresponding node failure rate and is multiplied by node failure and isolates and interconnection switch grid switching operation time, C class faulty section and C class fault arc corresponding node failure rate are multiplied by node failure isolation time three sum, finally calculates acquisition system System average interruption frequency, system System average interruption duration and system according to the frequency of power cut of all load point and interruption duration and on average to power Availability Index.
Claims (2)
1., for the load point fault zone Type division method that distribution network reliability is analyzed, comprise the steps:
(1) according to the annexation of elements all in target power distribution network, the topological diagram that the principle equivalence formed according to node becomes to represent with summit and limit, and serial number is carried out to all nodes, set up the set U of all nodes
aLL=[123 ... n];
(2) adjacency matrix of target power distribution network is constructed:
It is characterized in that, also comprise the steps:
(3) be that Region dividing is carried out to target power distribution network in border with switch, concrete grammar is as follows:
Step1: make K
x(x=1,2,3) are for being the node set that the xth on a border region comprises with switch in target power distribution network;
Step2: in adjacency matrix, a line that any selection did not judge as starting point, by the line number of this row stored in set K
xin, and by the row of all elements 2 column in this row number stored in set K
xin;
Step3: using the row of element 2 column in this row as the line number judged next time, jumps to the corresponding row do not judged and by the row of all elements 2 column in the row of correspondence number stored in set K
xin;
Step4: repeat Step3, until do not need only to jump to new behavior;
Step5: repeat element is only got once by the element heterogeneite principle according to set, obtaining take switch as the xth region K on border
x;
Step6: make x=x+1, returns Step2, judges remaining row in adjacency matrix, till all provisional capitals of adjacency matrix carried out once judging;
(4) be that Region dividing is carried out to power distribution network in border with automatic switch, concrete grammar is as follows:
Step1: make G
x(x=1,2,3) are for being the node set that the xth on a border region comprises with automatic switch in target power distribution network;
Step2: in adjacency matrix, a line that any selection did not judge as starting point, by the line number of this row stored in set G
xin, and by the row of all elements 2 in this row and element-1 column number stored in set G
xin;
Step3: using the row of element 2 in this row and element-1 column as the line number judged next time, jumps to the corresponding row do not judged and by the row of all elements 2 in the row of correspondence and element-1 column number stored in set G
xin;
Step4: repeat Step3, until do not need only to jump to new behavior;
Step5: repeat element is only got once by the element heterogeneite principle according to set, obtaining take automatic switch as the xth region G on border
x;
Step6: make x=x+1, returns Step2, judges remaining row in adjacency matrix, till all provisional capitals of adjacency matrix carried out once judging;
(5) load point faulty section divides
If target power distribution network is single width penetrate network, then the stand-by power supply number n=0 in target power distribution network;
The first, determine the shortest path of required load point to main power source, the node on shortest path is formed a set FZ;
The second, load point faulty section divides
1. determine to take switch as the set on border in FZ belonging to each node, then get union and obtain target power distribution network category-A faulty section node set A;
2. determine to take automatic switch as the set on border in FZ belonging to each node, then get union C
1, then remove the node deleting category-A faulty section, obtain target power distribution network C class faulty section node set C=C
1-A;
3. target power distribution network D class faulty section node set D=U
aLL-A-C;
(5 ') load point faulty section divides
If target power distribution network is looped network network, then stand-by power supply number n >=1 in target power distribution network;
The first, determine the shortest path of required load point to main power source, the node on shortest path is formed a set FZ;
The second, determine the set FB of node on required load point to a first stand-by power supply shortest path
1, determine the set FB of node on required load point to a second stand-by power supply shortest path
2, the like, finally determine the set FB of node on required load point to the n-th stand-by power supply shortest path
n, order set FB=FB
1∩ FB
2∩ ∩ FB
n;
3rd, seek common ground J=FZ ∩ FB;
4th, load point faulty section divides
1. determine to take switch as the region on border in common factor J belonging to each node respectively, then get the node set A that union obtains power distribution network category-A faulty section;
2. determining respectively to gather in FZ belonging to each node take switch as the region on border, then gets union B
1, then delete the node of category-A faulty section, obtain the node set B=B of power distribution network category-B faulty section
1-A;
3. the set C of the node on the shortest path of last position node to the first stand-by power supply of common factor J is set up
11, set up the set C of the node on the shortest path of last position node to the second stand-by power supply of common factor J
12, the like, finally set up the set C of the node on the shortest path of last position node to the n-th stand-by power supply of common factor J
1n; C
1=C
11∪ C
12∪ ∪ C
1n, make C
2=C
1∪ FZ, determines C respectively
2in belonging to each node take automatic switch as the region on border, then get union C
3, then delete the node of category-A faulty section, the node of category-B faulty section and stand-by power supply, obtain the node set C=C of power distribution network C class faulty section
3-A-B-stand-by power supply;
4. the node set D=U of power distribution network D class faulty section
aLL-A-B-C;
(6) load point fault arc divides
Determine all connection arcs comprised in target power distribution network,
To the connection arc of category-A faulty section node be contained as target power distribution network category-A fault arc;
The connection arc of category-B faulty section node will be contained, after deleting category-A fault arc, as target power distribution network category-B fault arc;
The connection arc of C class faulty section node will be contained, after deleting category-A fault arc and category-B fault arc, as target power distribution network C class fault arc;
The connection arc of D class faulty section node will be contained, after deleting category-A fault arc, category-B fault arc and C class fault arc, as target power distribution network D class fault arc;
(7) repeat (5) or (5 ') and (6), faulty section division and the division of fault arc are carried out to each load point in power distribution network.
2. as claimed in claim 1 for the load point fault zone Type division method that distribution network reliability is analyzed, it is characterized in that, described step (5) or in (5 '), the set FB of node on shortest paths
1, FB
2, FB
nand in FZ, element arranges according to the node sequencing of process in load point to the direction of main power source.
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