CN103679549B - Energy-saving for Thermal Power Units Potentials method - Google Patents

Abstract

The invention discloses a kind of Energy-saving for Thermal Power Units Potentials method, including step: calculate the boiler loss energy of fired power generating unit, boiler total losses energy, steam turbine input energy, steam turbine off-energy, generating input energy, station service energy and the actual motion value of power supply output energy indexes and desired value respectively；The relatively difference of the desired value of each energy indexes and actual motion value, show that energy-saving potential, compared with the fired power generating unit position big, loss ratio is serious, then is found out affect in the conversion of fired power generating unit energy and lost maximum key factor；By power consumption analysis method quantitative draw the key factor impact on net coal consumption rate and the size of influence amount, then carry out technological transformation to affecting bigger factor；Finally combine Analysis of Energy Loss method and power consumption analysis method, finally draw the key parameter amount affecting fired power generating unit power consumption, provide foundation for optimizing fired power generating unit.The present invention is used for optimizing Fossil-fired Unit Performance, thus improves the economy of fired power generating unit.

Description

Energy-saving for Thermal Power Units Potentials method

[technical field]

The invention belongs to thermal power generating technology field, be specifically related to a kind of Energy-saving for Thermal Power Units Potentials method.

[background technology]

Energy-saving for Thermal Power Units Potentials mainly uses consumption difference index analysis method at present, by thermal power unit operation Key parameter exercise supervision analysis, and the actual motion value of these parameters is compared with reference value, by both differences Calculate the impact on Based Coal Cost of each parameter.But, individually can only judge that a certain parameter is to economy with power consumption analysis method Influence amount, it is impossible to system analyze all factors to the impact of whole unit energy and situation of change.

[summary of the invention]

The purpose of the present invention is for deficiency of the prior art, it is provided that a kind of Energy-saving for Thermal Power Units Potentials side Method, the method utilizes the method that Analysis of Energy Loss and power consumption analysis combine, calculate fired power generating unit per hour, every day each equipment joint Can potential value the and affect amount of key factor of energy loss, thus for optimizing fired power generating unit offer foundation.

For achieving the above object, the present invention adopts the following technical scheme that

Energy-saving for Thermal Power Units Potentials method, comprises the following steps:

1) fired power generating unit real-time furnace coal weight F is gathered_Coal, low heat valve Q of t/h and in real time as-fired coal_r, kJ/kG；Meter Calculate boiler loss q_i, %；Boiler efficiency η_b, %；Turbine thermodynamic efficiency η_t, %；And station service power consumption rate δ_u, %；Wherein, i=2,4,5 and 6；

2) according to law of conservation of energy integrating step 1) the real-time furnace coal weight F that draws_Coal, the low level of real-time as-fired coal Caloric value Q_r, boiler loss q_i, boiler efficiency η_b, turbine thermodynamic efficiency η_tAnd station service power consumption rate δ_uNumerical value, calculate thermoelectricity respectively The boiler input energy Q of unit_b, boiler loss energy Q_i,s, boiler total losses energy Q_bs, steam turbine input energy Q_t, steam turbine loss Energy Q_ts, generating input energy Q_g, station service energy Q_gsAnd power supply output energy Q_eThe actual motion value of index, wherein, i=2, 4,5 and 6, its computing formula is as follows:

$Q_b=\frac{F_{\mathrm{Coal}}\×Q_r}{3600}---\left(2\right)$

In formula: Q_bEnergy, MJ/s is inputted for boiler；

F_CoalFor real-time furnace coal weight, t/h；

Q_rFor the low heat valve of real-time as-fired coal, kJ/kG；

$Q_{i,s}=\frac{Q_b\×q_i}{100}---\left(3\right)$

In formula: Q_i,sFor boiler loss energy, MJ/s；

Q_bEnergy, MJ/s is inputted for boiler；

q_iFor boiler loss, %；

Wherein, i=2,4,5 and 6；

$Q_{\mathrm{bs}}=Q_b-\frac{{\mathrm{\η}}_b{Q}_b}{100}---\left(4\right)$

In formula: Q_bsFor boiler total losses energy, MJ/s；

Q_bEnergy, MJ/s is inputted for boiler；

η_bFor boiler efficiency, %；

$Q_t=\frac{{\mathrm{\η}}_b{\mathrm{\η}}_p{Q}_b}{10000}---\left(5\right)$

In formula: Q_tEnergy, MJ/s is inputted for steam turbine；

η_bFor boiler efficiency, %；

η_pFor pipeline efficiency, %；

Q_bEnergy, MJ/s is inputted for boiler；

$Q_{\mathrm{ts}}=Q_t-\frac{{\mathrm{\η}}_t{Q}_t}{100}---\left(6\right)$

In formula: Q_tsFor steam turbine off-energy, MJ/s；

Q_tEnergy, MJ/s is inputted for steam turbine；

η_tFor turbine thermodynamic efficiency, %；

Q_g=Q_t-Q_ts(7)

In formula: Q_gFor generating input energy, MJ/s；

Q_tEnergy, MJ/s is inputted for steam turbine；

Q_tsFor steam turbine off-energy, MJ/s；

$Q_{\mathrm{gs}}=\frac{{\mathrm{\δ}}_u\×Q_g}{100}---\left(8\right)$

In formula: Q_gsFor station service energy, MJ/s；

δ_uFor station service power consumption rate, %；

Q_gFor generating input energy, MJ/s；

$Q_e=\frac{{\mathrm{\η}}_e\×(Q_g-Q_{\mathrm{gs}})}{100}---\left(9\right)$

In formula: Q_eFor power supply output energy, MJ/s；

η_eFor generator efficiency, %；

Q_gFor generating input energy, MJ/s；

Q_gsFor station service energy, MJ/s；

3) from fired power generating unit design instruction and performance test thereof are reported, fired power generating unit is obtained under 30%～100% load Boiler efficiency η_b, boiler loss q_i, turbine thermodynamic efficiency η_tAnd station service power consumption rate δ_uDesired value, then count respectively according to interpolation method Calculate boiler efficiency η under fired power generating unit actual motion load_b, boiler loss q_i, turbine thermodynamic efficiency η_tAnd station service power consumption rate δ_uMesh Scale value, finally boiler efficiency η obtained after interpolation_b, boiler loss q_i, turbine thermodynamic efficiency η_tAnd station service power consumption rate δ_uTarget Value brings step 2 respectively into) in energy indexes formula (3)～(9), obtain fired power generating unit boiler loss energy under actual motion load Amount Q_i,s, boiler total losses energy Q_bs, steam turbine input energy Q_t, steam turbine off-energy Q_ts, generating input energy Q_g, station-service electric energy Amount Q_gs, power supply output energy indexes Q_eDesired value, wherein, i=2,4,5 and 6；

4) the boiler loss energy of fired power generating unit, steam turbine input energy, steam turbine off-energy, generating input are calculated respectively The desired value of energy, station service energy and supply input energy indexes and the difference of actual motion value；

5) by comparing the boiler loss energy of fired power generating unit, steam turbine input energy, steam turbine off-energy, generating input energy The difference of desired value and the actual motion value of amount, station service energy and power supply energy indexes, show that fired power generating unit energy loss is Big position.

The present invention further improvement is that, further comprising the steps of:

6) draw, according to step 5), the position that fired power generating unit energy loss is maximum, find out and affect fired power generating unit energy loss The key factor at big position；

7) the quantitative key factor drawing fired power generating unit energy loss maximum position of power consumption analysis method is passed through to power supply The impact of mark coal consumption and the size of influence amount, then carry out technological transformation to the key factor that impact is maximum.

The present invention further improvement is that, in step 1), according to " GB10184-88 station boiler performance test code " and " GB/T10180-2003 Industrial Boiler Thermal Performance Test code " calculates boiler loss q_i, %, wherein, i=2,4,5 and 6；Pot Efficiency of furnace η_b, %；According to " GB8117-87 power station steam turbine acceptance test code ", " ASME PTC6-1996 steamer Machine performance test code " and " IAPWS-IF97 water and steam character equation " calculate turbine thermodynamic efficiency η_t, %；Station service Rate δ_uComputing formula as follows:

${\mathrm{\δ}}_u=100\×\frac{N_{\mathrm{CGB}}+N_{\mathrm{QBB}}+N_{\mathrm{TLB}}}{N_e}---\left(1\right)$

In formula: N_CGBFactory's height Variable power of unit, MW；

N_QGBOpening for Variable power, MW of unit；

N_TLBThe desulfurization Variable power of unit, MW；

N_eGenerated output, MW；

The present invention further improvement is that, in step 6), uses power consumption analysis methods analyst boiler parameter to power supply mark coal The impact of consumption, its computing formula is as follows:

$\frac{\∂b}{\∂\mathrm{Eff}\_\mathrm{Boiler}}=\frac{\mathrm{Heat}\_\mathrm{Rate}}{0.29105\mathrm{Eff}\_\mathrm{Boile}{r}^2\×(1-\mathrm{PEC}\_\mathrm{Rate}/100)}---\left(10\right)$

$\frac{\∂b}{\∂T\_\mathrm{AHGasOut}}=\frac{\∂b}{\∂\mathrm{Eff}\_\mathrm{Boiler}}\×\frac{\∂\mathrm{Eff}\_\mathrm{Boiler}}{\∂T\_\mathrm{AHGasOut}}---\left(11\right)$

$\frac{\∂b}{\∂\mathrm{Cfh}}=\frac{\∂b}{\∂\mathrm{Eff}\_\mathrm{Boiler}}\×\frac{\∂\mathrm{Eff}\_\mathrm{Boiler}}{\∂\mathrm{Cfh}}---\left(12\right)$

$\frac{\∂b}{\∂O_2\_\mathrm{AHOut}}=\frac{\∂b}{\∂\mathrm{Eff}\_\mathrm{Boiler}}\×\frac{\∂\mathrm{Eff}\_\mathrm{Boiler}}{\∂O_2\_\mathrm{AHOut}}---\left(13\right)$

$\frac{\∂b}{\∂\mathrm{Qdwy}}=\frac{\∂b}{\∂\mathrm{Eff}\_\mathrm{Boiler}}\×\frac{\∂\mathrm{Eff}\_\mathrm{Boiler}}{\∂\mathrm{Qdwy}}---\left(14\right)$

In formula: b is coal consumption of power supply, g marks coal/kWh；Eff_Boiler is boiler efficiency, %；Heat_Rate is steam turbine heat Consumption, kJ/kg；PEC_Rate is station service power consumption rate, %；T_AHGasOut is exhaust gas temperature, DEG C；C_fhFor unburned carbon in flue dust, %；O₂_ AHOut is oxygen content in exhaust gas, %；Q_dwyFor fuel low heat valve, kJ/kg.

The present invention further improvement is that, in step 6), uses power consumption analysis methods analyst steam turbine consumption difference to power supply mark coal The impact of consumption, its computing formula is as follows:

Steam turbine consumption poor=deviation factor × (actual value-desired value) × net coal consumption rate (15)

In formula: steam turbine consumption difference includes main steam pressure, main steam temperature, reheat steam temperature degree, reheating spray flow, crosses thermal jet The consumption of discharge, condenser vacuum and final feed temperature is poor；

Deviation factor is that actual value deviates the desired value factor of influence to turbine heat rate rate, and deviation factor passes through equivalent enthalpy drop The design curve that method and manufacturer provide is calculated；

Net coal consumption rate, its unit is g/k/Wh.

Relative to prior art, the present invention has the following technical effect that

One Energy-saving for Thermal Power Units Potentials method of the present invention, this analysis method, on the basis of power consumption analysis method, is tied Close Analysis of Energy Loss fired power generating unit energy loss situation is dissected in detail, can not only the energy loss feelings of W-response fired power generating unit Condition, and the key factor affecting fired power generating unit energy loss can be found out, and the size of quantitative analyzing influence amount.The present invention both may be used Grasp each several part energy loss situation and energy-saving potential in fired power generating unit system in real time, find out the key factor affecting energy loss, can determine again Adjusting key parameter according to influence amount size or the equipment affecting this key parameter carrying out technological transformation of amount, optimizes fired power generating unit Can, thus improve the economy of fired power generating unit.

[detailed description of the invention]

Below in conjunction with specific embodiment, the invention will be further described.

Energy-saving for Thermal Power Units Potentials method, comprises the following steps:

1) fired power generating unit real-time furnace coal weight F is gathered_Coal, low heat valve Q of t/h and in real time as-fired coal_r, kJ/kG；Root According to " GB10184-88 station boiler performance test code " and " GB/T10180-2003 Industrial Boiler Thermal Performance Test code " Calculate boiler loss q_i, %, wherein, i=2,4,5 and 6；Boiler efficiency η_b, %；According to " GB8117-87 power station steam turbine heating power Can proof test code ", " ASME PTC6-1996 Turbine Performance Test code " and " IAPWS-IF97 water and steam character Equation " calculate turbine thermodynamic efficiency η_t, %；And calculate station service power consumption rate δ_u, %；Wherein, station service power consumption rate δ_uComputing formula such as Under:

${\mathrm{\δ}}_u=100\×\frac{N_{\mathrm{CGB}}+N_{\mathrm{QBB}}+N_{\mathrm{TLB}}}{N_e}---\left(1\right)$

In formula: N_CGBFactory's height Variable power of unit, MW；

N_QGBOpening for Variable power, MW of unit；

N_TLBThe desulfurization Variable power of unit, MW；

N_eGenerated output, MW；

In fired power generating unit actual motion, the data of the above-mentioned parameters by gathering or calculating are as shown in table 1:

Table 1:

Parameter name	Unit	Actual motion value
			Furnace coal weight F in real timeCoal	t/h	140.4
Boiler loss q2	%	4.85
			Boiler loss q4	%	1.06
Boiler loss q5	%	0.54
			Boiler loss q6	%	0.1
Boiler efficiency ηb	%	93.45
			Turbine thermodynamic efficiency ηt	%	39.2
Station service power consumption rate δu	%	6.77
			Low heat valve Qr	kJ/kG	20822

2) according to law of conservation of energy integrating step 1) the real-time furnace coal weight F that draws_Coal, the low level of real-time as-fired coal Caloric value Q_r, boiler loss q_i, boiler efficiency η_b, turbine thermodynamic efficiency η_tAnd station service power consumption rate δ_uNumerical value, calculate thermoelectricity respectively The boiler input energy Q of unit_b, boiler loss energy Q_i,s, boiler total losses energy Q_bs, steam turbine input energy Q_t, steam turbine loss Energy Q_ts, generating input energy Q_g, station service energy Q_gsAnd power supply output energy Q_eThe actual motion value of index, wherein, i=2, 4,5 and 6, its computing formula is as follows, and result of calculation is as shown in table 2:

$Q_b=\frac{F_{\mathrm{Coal}}\×Q_r}{3600}---\left(2\right)$

In formula: Q_bEnergy, MJ/s is inputted for boiler；

F_CoalFor real-time furnace coal weight, t/h；

Q_rFor the low heat valve of real-time as-fired coal, kJ/kG；

$Q_{i,s}=\frac{Q_b\×q_i}{100}---\left(3\right)$

In formula: Q_i,sFor boiler loss energy, MJ/s；

Q_bEnergy, MJ/s is inputted for boiler；

q_iFor boiler loss, %；

Wherein, i=2,4,5 and 6；

$Q_{\mathrm{bs}}=Q_b-\frac{{\mathrm{\η}}_b{Q}_b}{100}---\left(4\right)$

In formula: Q_bsFor boiler total losses energy, MJ/s；

Q_bEnergy, MJ/s is inputted for boiler；

η_bFor boiler efficiency, %；

$Q_t=\frac{{\mathrm{\η}}_b{\mathrm{\η}}_p{Q}_b}{10000}---\left(5\right)$

In formula: Q_tEnergy, MJ/s is inputted for steam turbine；

η_bFor boiler efficiency, %；

η_pFor pipeline efficiency, %；

Q_bEnergy, MJ/s is inputted for boiler；

$Q_{\mathrm{ts}}=Q_t-\frac{{\mathrm{\η}}_t{Q}_t}{100}---\left(6\right)$

In formula: Q_tsFor steam turbine off-energy, MJ/s；

Q_tEnergy, MJ/s is inputted for steam turbine；

η_tFor turbine thermodynamic efficiency, %；

Q_g=Q_t-Q_ts(7)

In formula: Q_gFor generating input energy, MJ/s；

Q_tEnergy, MJ/s is inputted for steam turbine；

Q_tsFor steam turbine off-energy, MJ/s；

$Q_{\mathrm{gs}}=\frac{{\mathrm{\δ}}_u\×Q_g}{100}---\left(8\right)$

In formula: Q_gsFor station service energy, MJ/s；

δ_uFor station service power consumption rate, %；

Q_gFor generating input energy, MJ/s；

$Q_e=\frac{{\mathrm{\η}}_e\×(Q_g-Q_{\mathrm{gs}})}{100}---\left(9\right)$

In formula: Q_eFor power supply output energy, MJ/s；

η_eFor generator efficiency, %；

Q_gFor generating input energy, MJ/s；

Q_gsFor station service energy, MJ/s；

Table 2:

Parameter name	Unit	Actual motion value
			Boiler input energy Qb	MJ/s	812.24
Boiler loss energy Q2,s	MJ/s	39.37
			Boiler loss energy Q4,s	MJ/s	8.59
Boiler loss energy Q5,s	MJ/s	4.42
			Boiler loss energy Q6,s	MJ/s	0.85
Boiler total losses energy Qbs	MJ/s	53.23
			Steam turbine input energy Qt	MJ/s	751.41
Steam turbine off-energy Qts	MJ/s	457.09
			Generating input energy Qg	MJ/s	288.43
Station service energy Qgs	MJ/s	19.52
			Power supply output energy Qe	MJ/s	268.91

3) from fired power generating unit design instruction and performance test thereof are reported, fired power generating unit is obtained under 30%～100% load Boiler efficiency η_b, boiler loss q_i, turbine thermodynamic efficiency η_tAnd station service power consumption rate δ_uDesired value, then count respectively according to interpolation method Calculate boiler efficiency η under fired power generating unit actual motion load_b, boiler loss q_i, turbine thermodynamic efficiency η_tAnd station service power consumption rate δ_uMesh Scale value, finally boiler efficiency η obtained after interpolation_b, boiler loss q_i, turbine thermodynamic efficiency η_tAnd station service power consumption rate δ_uTarget Value (its result of calculation is as shown in table 3) brings step 2 respectively into) in energy indexes formula (3)～(9), obtain fired power generating unit in reality Boiler off-energy Q under the operating load of border_i,s, boiler total losses energy Q_bs, steam turbine input energy Q_t, steam turbine off-energy Q_ts, send out Electricity input energy Q_g, station service energy Q_gs, power supply output energy indexes Q_eDesired value, wherein, i=2,4,5 and 6；Above-mentioned each The desired value reflection of energy indexes is fired power generating unit each several part optimum under specific load, its result of calculation such as table 4 institute Show；

Table 3:

Parameter name	Unit	Desired value
			Furnace coal weight F in real timeCoal	t/h	140.4
Boiler loss q2	%	4.99
			Boiler loss q4	%	1.32
Boiler loss q5	%	0.39
			Boiler loss q6	%	0.3
Boiler efficiency ηb	%	93
			Turbine thermodynamic efficiency ηt	%	43.8
Go out station service power consumption rate δu	%	6.45
			Low heat valve Qr	kJ/kG	20822

Table 4:

Parameter name	Unit	Desired value
			Boiler input energy Qb	MJ/s	812.24
Boiler loss energy Q2,s	MJ/s	40.5

Boiler loss energy Q4,s	MJ/s	10.73
			Boiler loss energy Q5,s	MJ/s	3.21
Boiler loss energy Q6,s	MJ/s	2.46
			Boiler total losses energy Qbs	MJ/s	56.9
Steam turbine input energy Qt	MJ/s	747.78
			Steam turbine off-energy Qts	MJ/s	420.1
Generating input energy Qg	MJ/s	321.12
			Station service energy Qgs	MJ/s	20.73
Power supply output energy Qe	MJ/s	300.39

4) the boiler input energy of fired power generating unit, boiler loss energy, steam turbine input energy, steam turbine loss are calculated respectively The desired value of energy, generating input energy, station service energy and supply input energy indexes and the difference of actual motion value, its meter Calculation result is as shown in table 5, and this difference can reflect the size of fired power generating unit each device energy conservation potentiality, and then obtains unit energy damage The concrete position of consumption；

Table 5:

Parameter name	Unit	Desired value	Actual motion value	Difference
					Boiler loss energy Q2,s	MJ/s	40.5	39.37	1.13
Boiler loss energy Q4,s	MJ/s	10.73	8.59	2.14
					Boiler loss energy Q5,s	MJ/s	3.21	4.42	-1.21
Boiler loss energy Q6,s	MJ/s	2.46	0.85	1.61
					Boiler total losses energy Qbs	MJ/s	56.9	53.23	3.67
Steam turbine input energy Qt	MJ/s	747.78	751.41	-3.63
					Steam turbine off-energy Qts	MJ/s	420.1	457.09	-36.99
Generating input energy Qg	MJ/s	321.12	288.43	32.68
					Station service energy Qgs	MJ/s	20.73	19.52	1.21

Power supply output energy Qe

MJ/s

300.39

268.91

31.48

5) by comparing the boiler loss energy of fired power generating unit, steam turbine input energy, steam turbine off-energy, generating input energy The desired value of amount, station service energy and power supply energy indexes and the difference of actual motion value, show that energy-saving potential is relatively big, lose ratio The fired power generating unit position that example is serious is steam turbine；

6) find out again and the conversion of fired power generating unit energy affects the key factor that steam turbine loss is maximum；

7) by power consumption analysis method quantitative draw the key factor impact on coal consumption of power supply and the size of influence amount, Then the bigger key factor of impact is carried out technological transformation, thus reduce the energy loss of fired power generating unit, improve fired power generating unit Economic performance.

Consumption difference calculating is generally divided into boiler parameter and steam turbine parameter consumption difference calculates.The impact of boiler efficiency is by boiler parameter Interact, may result in increase and the reduction of fly ash combustible material of exhaust gas temperature such as the increase of deoxygenation oxygen amount.But due to Every loss of boiler can be described by simple data formula, therefore employing general to boiler parameter " little deviation principle " Calculating, i.e. suppose that the boiler parameter run fluctuates in the certain limit of respective desired value, that ignores between parameter is mutual Impact, calculates the impact on coal consumption of power supply after desired value of the boiler each parameter drift-out respectively.

Using the impact on coal consumption of power supply of the power consumption analysis methods analyst boiler parameter, its computing formula is as follows:

$\frac{\∂b}{\∂\mathrm{Eff}\_\mathrm{Boiler}}=\frac{\mathrm{Heat}\_\mathrm{Rate}}{0.29105\mathrm{Eff}\_\mathrm{Boile}{r}^2\×(1-\mathrm{PEC}\_\mathrm{Rate}/100)}---\left(10\right)$

$\frac{\∂b}{\∂T\_\mathrm{AHGasOut}}=\frac{\∂b}{\∂\mathrm{Eff}\_\mathrm{Boiler}}\×\frac{\∂\mathrm{Eff}\_\mathrm{Boiler}}{\∂T\_\mathrm{AHGasOut}}---\left(11\right)$

$\frac{\∂b}{\∂\mathrm{Cfh}}=\frac{\∂b}{\∂\mathrm{Eff}\_\mathrm{Boiler}}\×\frac{\∂\mathrm{Eff}\_\mathrm{Boiler}}{\∂\mathrm{Cfh}}---\left(12\right)$

$\frac{\∂b}{\∂O_2\_\mathrm{AHOut}}=\frac{\∂b}{\∂\mathrm{Eff}\_\mathrm{Boiler}}\×\frac{\∂\mathrm{Eff}\_\mathrm{Boiler}}{\∂O_2\_\mathrm{AHOut}}---\left(13\right)$

$\frac{\∂b}{\∂\mathrm{Qdwy}}=\frac{\∂b}{\∂\mathrm{Eff}\_\mathrm{Boiler}}\×\frac{\∂\mathrm{Eff}\_\mathrm{Boiler}}{\∂\mathrm{Qdwy}}---\left(14\right)$

In formula: b is coal consumption of power supply, g marks coal/kWh；Eff_Boiler is boiler efficiency, %；Heat_Rate is steam turbine heat Consumption, kJ/kg；PEC_Rate is station service power consumption rate, %；T_AHGasOut is exhaust gas temperature, DEG C；C_fhFor unburned carbon in flue dust, %；O₂_ AHOut is oxygen content in exhaust gas, %；Q_dwyFor fuel low heat valve, kJ/kg；

Steam turbine parameter consumption difference mainly reacts the contributive rate to net coal consumption rate by the difference of actual motion value Yu desired value, Using the impact on coal consumption of power supply of the power consumption analysis methods analyst steam turbine consumption difference, its computing formula is as follows:

Steam turbine consumption poor=deviation factor × (actual value-desired value) × net coal consumption rate (15)

In formula: steam turbine consumption difference includes main steam pressure, main steam temperature, reheat steam temperature degree, reheating spray flow, crosses thermal jet The consumption of discharge, condenser vacuum, overheated attemperation water flow, reheating attemperation water flow, feedwater flow and final feed temperature is poor；

Deviation factor is that actual value deviates the desired value factor of influence to turbine heat rate rate, and deviation factor passes through equivalent enthalpy drop The design curve that method and manufacturer provide is calculated；

Net coal consumption rate, its unit is g/k/Wh；

In fired power generating unit actual motion, poor by power consumption analysis methods analyst steam turbine consumption, draw and affect fired power generating unit energy The key factor that in conversion, steam turbine loss is maximum is as shown in table 6:

Table 6:

Parameter name	Unit	Desired value	Actual motion value
				Feedwater flow	t/h	1011	1125
Overheated attemperation water flow	t/h	41.3	194.2
				Reheating attemperation water flow	t/h	0	36.1
Feedwater flow consumption is poor	g/kWh	0	1.84
				Overheated attemperation water flow consumption is poor	g/kWh	0	7.77
Reheating attemperation water flow consumption is poor	g/kWh	0	3.32

7) integrating step 1) to 5) Analysis of Energy Loss method and the power consumption analysis method of step 6), finally draw and affect thermoelectricity The key parameter amount of unit power consumption, provides foundation for optimizing fired power generating unit.

Claims (3)

1. Energy-saving for Thermal Power Units Potentials method, it is characterised in that comprise the following steps:

1) fired power generating unit real-time furnace coal weight F is gathered_Coal, low heat valve Q of t/h and in real time as-fired coal_r, kJ/kG；Calculate Boiler loss q_i, %；Boiler efficiency η_b, %；Turbine thermodynamic efficiency η_t, %；And station service power consumption rate δ_u, %；Wherein, i=2,4,5 and 6；

2) according to law of conservation of energy integrating step 1) the real-time furnace coal weight F that draws_Coal, real-time as-fired coal low level heating Amount Q_r, boiler loss q_i, boiler efficiency η_b, turbine thermodynamic efficiency η_tAnd station service power consumption rate δ_uNumerical value, calculate fired power generating unit respectively Boiler input energy Q_b, boiler loss energy Q_i,s, boiler total losses energy Q_bs, steam turbine input energy Q_t, steam turbine off-energy Q_ts, generating input energy Q_g, station service energy Q_gsAnd power supply output energy Q_eThe actual motion value of index, wherein, i=2,4,5 And 6, its computing formula is as follows:

$Q_b=\frac{F_{Coal}\×Q_r}{3600}---\left(2\right)$

In formula: Q_bEnergy, MJ/s is inputted for boiler；

F_CoalFor real-time furnace coal weight, t/h；

Q_rFor the low heat valve of real-time as-fired coal, kJ/kG；

$Q_{i,s}=\frac{Q_b\×q_i}{100}---\left(3\right)$

In formula: Q_i,sFor boiler loss energy, MJ/s；

Q_bEnergy, MJ/s is inputted for boiler；

q_iFor boiler loss, %；

Wherein, i=2,4,5 and 6；

$Q_{bs}=Q_b-\frac{{\mathrm{\η}}_b{Q}_b}{100}---\left(4\right)$

In formula: Q_bsFor boiler total losses energy, MJ/s；

Q_bEnergy, MJ/s is inputted for boiler；

η_bFor boiler efficiency, %；

$Q_t=\frac{{\mathrm{\η}}_b{\mathrm{\η}}_p{Q}_b}{10000}---\left(5\right)$

In formula: Q_tEnergy, MJ/s is inputted for steam turbine；

η_bFor boiler efficiency, %；

η_pFor pipeline efficiency, %；

Q_bEnergy, MJ/s is inputted for boiler；

$Q_{ts}=Q_t-\frac{{\mathrm{\η}}_t{Q}_t}{100}---\left(6\right)$

In formula: Q_tsFor steam turbine off-energy, MJ/s；

Q_tEnergy, MJ/s is inputted for steam turbine；

η_tFor turbine thermodynamic efficiency, %；

Q_g=Q_t-Q_ts (7)

In formula: Q_gFor generating input energy, MJ/s；

Q_tEnergy, MJ/s is inputted for steam turbine；

Q_tsFor steam turbine off-energy, MJ/s；

$Q_{gs}=\frac{{\mathrm{\δ}}_u\×Q_g}{100}---\left(8\right)$

In formula: Q_gsFor station service energy, MJ/s；

δ_uFor station service power consumption rate, %；

Q_gFor generating input energy, MJ/s；

$Q_e=\frac{{\mathrm{\η}}_e\×(Q_g-Q_{gs})}{100}---\left(9\right)$

In formula: Q_eFor power supply output energy, MJ/s；

η_eFor generator efficiency, %；

Q_gFor generating input energy, MJ/s；

Q_gsFor station service energy, MJ/s；

3) from fired power generating unit design instruction and performance test thereof are reported, obtain fired power generating unit to cook at 30%～100% load Efficiency of furnace η_b, boiler loss q_i, turbine thermodynamic efficiency η_tAnd station service power consumption rate δ_uDesired value, then calculate respectively according to interpolation method Go out boiler efficiency η under fired power generating unit actual motion load_b, boiler loss q_i, turbine thermodynamic efficiency η_tAnd station service power consumption rate δ_uTarget Value, finally boiler efficiency η obtained after interpolation_b, boiler loss q_i, turbine thermodynamic efficiency η_tAnd station service power consumption rate δ_uDesired value Bring step 2 respectively into) in energy indexes formula (3)～(9), obtain fired power generating unit boiler off-energy under actual motion load Q_i,s, boiler total losses energy Q_bs, steam turbine input energy Q_t, steam turbine off-energy Q_ts, generating input energy Q_g, station service energy Q_gs, power supply output energy indexes Q_eDesired value, wherein, i=2,4,5 and 6；

4) the boiler loss energy of fired power generating unit, steam turbine input energy, steam turbine off-energy, generating input energy are calculated respectively The desired value of amount, station service energy and supply input energy indexes and the difference of actual motion value；

5) by compare fired power generating unit boiler input energy, boiler loss energy, steam turbine input energy, steam turbine off-energy, The desired value of generating input energy, station service energy and power supply energy indexes and the difference of actual motion value, draw fired power generating unit The position that energy loss is maximum；

6) according to step 5) draw the position that fired power generating unit energy loss is maximum, find out and affect fired power generating unit energy loss maximum The key factor at position；

7) by the key factor drawing fired power generating unit energy loss maximum position that power consumption analysis method is quantitative, coal is marked in power supply The impact of consumption and the size of influence amount, then carry out technological transformation to the key factor that impact is maximum；

Wherein, step 1) in, according to " GB 10184-88 station boiler performance test code " and " GB/T 10180-2003 industry Boiler thermal technology's performance test code " calculate boiler loss q_i, %, wherein, i=2,4,5 and 6；Boiler efficiency η_b, %；According to " GB 8117-87 power station steam turbine acceptance test code ", " ASME PTC6-1996 Turbine Performance Test code " And " IAPWS-IF97 water and steam character equation " calculates turbine thermodynamic efficiency η_t, %；Station service power consumption rate δ_uComputing formula such as Under:

${\mathrm{\δ}}_u=100\×\frac{N_{CGB}+N_{QBB}+N_{TLB}}{N_e}---\left(1\right)$

In formula: N_CGBFactory's height Variable power of unit, MW；

N_QGBOpening for Variable power, MW of unit；

N_TLBThe desulfurization Variable power of unit, MW；

N_eGenerated output, MW.

Energy-saving for Thermal Power Units Potentials method the most according to claim 1, it is characterised in that step 6) in, use consumption The impact on coal consumption of power supply of the difference analysis methods analyst boiler parameter, its computing formula is as follows:

$\frac{\∂b}{\∂Eff\_Boiler}=\frac{Heat\_Rate}{0.29105Eff\_{\mathrm{Boiler}}^2\×(1-PEC\_Rate/100)}---\left(10\right)$

$\frac{\∂b}{\∂T\_AHGasOut}=\frac{\∂b}{\∂Eff\_Boiler}\×\frac{\∂Eff\_Boiler}{\∂T\_AHGasOut}---\left(11\right)$

$\frac{\∂b}{\∂Cfh}=\frac{\∂b}{\∂Eff\_Boiler}\×\frac{\∂Eff\_Boiler}{\∂Cfh}---\left(12\right)$

$\frac{\∂b}{\∂O_2\_AHOut}=\frac{\∂b}{\∂Eff\_Boiler}\×\frac{\∂Eff\_Boiler}{\∂O_2\_AHOut}---\left(13\right)$

$\frac{\∂b}{\∂Qdwy}=\frac{\∂b}{\∂Eff\_Boiler}\×\frac{\∂Eff\_Boiler}{\∂Qdwy}---\left(14\right)$

In formula: b is coal consumption of power supply, g marks coal/kWh；Eff_Boiler is boiler efficiency, %；Heat_Rate is turbine heat rate, kJ/kg；PEC_Rate is station service power consumption rate, %；T_AHGasOut is exhaust gas temperature, DEG C；C_fhFor unburned carbon in flue dust, %；O₂_ AHOut is oxygen content in exhaust gas, %；Q_dwyFor fuel low heat valve, kJ/kg.

Energy-saving for Thermal Power Units Potentials method the most according to claim 1, it is characterised in that step 6) in, use consumption The impact on coal consumption of power supply of the difference analysis methods analyst steam turbine consumption difference, its computing formula is as follows:

Steam turbine consumption poor=deviation factor × (actual value-desired value) × net coal consumption rate (15)

In formula: steam turbine consumption difference includes main steam pressure, main steam temperature, reheat steam temperature degree, reheating spray flow, overheated water jet The consumption of amount, condenser vacuum and final feed temperature is poor；

Deviation factor is that actual value deviates the desired value factor of influence to turbine heat rate rate, deviation factor by equivalent enthalpy drop method and The design curve that manufacturer provides is calculated；

Net coal consumption rate, its unit is g/k/Wh.