CN103091758A - Color light filter plate and display panel and display device - Google Patents

Abstract

The invention discloses a color light filter plate, a display panel and a display device and relates to the field of displaying technology. The color light filter plate comprises a transparent substrate, a first semi-reflective and semi-transparent thin film and a second semi-reflective and semi-transparent thin film which are positioned on the transparent substrate, a gap layer is arranged between the first semi-reflective and semi-transparent thin film and the second semi-reflective and semi-transparent thin film and is provided with different thicknesses corresponding to different color display areas, and black matrixes are arranged between adjacent color display areas. The display panel comprises the color light filter plate. According to the color light filter plate, base on the light interference theory, due to the fact that the gap layer with different thicknesses is arranged between the two semi-reflective and semi-transparent thin films, the technical effect of color display is achieved, the color light filter plate is simple in structure and low in cost and has broad prospects for development.

Description

Color filter, display panel and display device

Technical field

The present invention relates to the display technique field, be specifically related to a kind of color filter and display panel, display device.

Background technology

Traditional display panel is realized colored the demonstration by colored filter (Color Filter), and Fig. 1 is a kind of structural drawing of existing colored filter, comprises transparency carrier 1, black matrix unit 2, color resin 3.Existing colored filter utilizes photoetching process or printing technology is made on transparency carrier, and then each pixel of display panel is presented enrich beautiful color.Realize that colored principle is after white light passes through the color resin filtration of different colours, presents the light of different colours.Concrete making step is generally first to form black matrix on transparency carrier, more corresponding different pixel cell forms corresponding color resin layer.Above-mentioned traditional colorful filter structure is complicated, manufacture craft is loaded down with trivial details and cost is high.

Summary of the invention

The technical matters that (one) will solve

The technical problem to be solved in the present invention is: provide a kind of based on the interference of light principle, simple in structure, cost is low and can replace new type colorful filter and the corresponding display panel of existing colored filter.

(2) technical scheme

For addressing the above problem, the invention provides a kind of color filter, comprise a plurality of sub-pixel area that limited by black matrix unit, this color filter also comprises: substrate and be positioned at the first semi-reflective and semitransmittable thin film and the second semi-reflective and semitransmittable thin film on this substrate, comprise clearance layer between described the first semi-reflective and semitransmittable thin film and described the second semi-reflective and semitransmittable thin film, the corresponding described clearance layer of the sub-pixel area of different colours has different thickness.

Optionally, described clearance layer is transparent dielectric layer.

Optionally, described transparent dielectric layer is air layer, transparent resin layer or transparent metal oxide layer.

Optionally, when the thickness of described clearance layer satisfies following formula, regional shown in red corresponding to this thickness of this color filter:

${\mathrm{<figure-callout\; id="1"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_1={\mathrm{<figure-callout\; id="1"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_1{\mathrm{\&lambda;}}_1/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)=[({2\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_2+1){\mathrm{\&lambda;}}_2/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

$=[(2{\mathrm{<figure-callout\; id="3"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_3+1){\mathrm{\&lambda;}}_3/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

Wherein, e ₁When expression shows ruddiness, the thickness of described clearance layer; λ ₁Wavelength for ruddiness; λ ₂Wavelength for green glow; λ ₃Wavelength for blue light; n ₁Refractive index for described clearance layer; n ₂Refractive index for outside air; γ is that light is at the refraction angle of described the second semi-reflective and semitransmittable thin film inside surface; K wherein ₁, k ₂, k ₃Be non-negative integer, and k ₁=1,2, k ₂=0,1,2 k ₃=0,1,2 ...

Optionally, when the thickness of described clearance layer satisfies following formula, regional shown in green corresponding to this thickness of this color filter:

${\mathrm{<figure-callout\; id="2"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_2={{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_2}^{\&prime;}\mathrm{\&lambda;}}_2/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)=[({{2\mathrm{<figure-callout\; id="1"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_1}^{\&prime;}+1){\mathrm{\&lambda;}}_1/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

$=[({{2\mathrm{<figure-callout\; id="3"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_3}^{\&prime;}+1){\mathrm{\&lambda;}}_3/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

Wherein, e ₂When expression shows green glow, the thickness of described clearance layer; λ ₁Wavelength for ruddiness; λ ₂Wavelength for green glow; λ ₃Wavelength for blue light; n ₁Refractive index for described clearance layer; n ₂Refractive index for outside air; γ is that light is at the refraction angle of described the second semi-reflective and semitransmittable thin film inside surface; K wherein ₁', k ₂', k ₃' be non-negative integer, and k ₂'=1,2, k ₁'=0,1,2 k ₃'=0,1,2 ...

Optionally, when the thickness of described clearance layer satisfied following formula, this color filter was shown as blueness in the zone corresponding to this thickness:

${\mathrm{<figure-callout\; id="3"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_3={{\mathrm{<figure-callout\; id="3"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_3}^{\&prime;\&prime;}{\mathrm{\&lambda;}}_3/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)=[({{2\mathrm{<figure-callout\; id="1"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_1}^{\&prime;\&prime;}+1){\mathrm{\&lambda;}}_1/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

$=[({{2\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_2}^{\&prime;\&prime;}+1){\mathrm{\&lambda;}}_2/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

Wherein, e ₃When expression shows blue light, the thickness of described clearance layer; λ ₁Wavelength for ruddiness; λ ₂Wavelength for green glow; λ ₃Wavelength for blue light; n ₁Refractive index for described clearance layer; n ₂Refractive index for outside air; γ is that light is at the refraction angle of described the second semi-reflective and semitransmittable thin film inside surface; K wherein ₁", k ₂", k ₃" be non-negative integer, and k ₃"=1,2 ...; k ₂"=0,1,2 ...; k ₁"=0,1,2 ....

Optionally, the side at described substrate is provided with antireflection film.

Optionally, described first semi-reflective and semitransmittable thin film of the pixel region of corresponding different colours or described the second semi-reflective and semitransmittable thin film have identical thickness.

The present invention also provides a kind of display panel, and this display panel comprises above-mentioned color filter.

The present invention also provides a kind of display device, and this display device comprises above-mentioned display panel.

(3) beneficial effect

The color filter that the present invention proposes by the different clearance layer of thickness is set, has reached the technique effect of colored demonstration based on the interference of light principle between two-layer semi-reflective and semitransmittable thin film, it is simple in structure, cost is low, has vast potential for future development.

Description of drawings

Fig. 1 is a kind of structural drawing of existing colored filter;

Fig. 2 is the structural drawing of the color filter that the present invention relates to;

Fig. 3 is two bundle refract light α in the embodiment of the present invention ₁(R ₁, G ₁, B ₁) and α ₂(R ₂, G ₂, B ₂) when interference of light occurs, the waveform schematic diagram that each wavelength period phase appearance disappears;

Fig. 4 is two bundle refract light β in the embodiment of the present invention ₁(R ₁, G ₁, B ₁) and β ₂(R ₂, G ₂, B ₂) when interference of light occurs, the waveform schematic diagram that each wavelength period phase appearance disappears;

Fig. 5 is two bundle refract light δ in the embodiment of the present invention ₁(R ₁, G ₁, B ₁) and δ ₂(R ₂, G ₂, B ₂) when interference of light occurs, the waveform schematic diagram that each wavelength period phase appearance disappears.

Wherein: 1,6: transparency carrier; 2,9: black matrix unit; 3: color resin; 7: the first semi-reflective and semitransmittable thin films; 8: the second semi-reflective and semitransmittable thin films; 10: clearance layer.

Embodiment

Below in conjunction with drawings and Examples, the specific embodiment of the present invention is described in further detail.Following examples are used for explanation the present invention, but are not used for limiting the scope of the invention.

Fig. 2 is the structural drawing of the color filter that the present invention relates to, comprise a plurality of sub-pixel area that limited by black matrix unit 9, this color filter also comprises: substrate 6 and be positioned at the first semi-reflective and semitransmittable thin film 7 and the second semi-reflective and semitransmittable thin film 8 on this substrate, comprise clearance layer 10 between described the first semi-reflective and semitransmittable thin film 7 and described the second semi-reflective and semitransmittable thin film 8, the corresponding described clearance layer 10 of the sub-pixel area of different colours has different thickness, as shown in Figure 2.Described substrate is generally transparent glass substrate.

Wherein, described clearance layer 10 is transparent dielectric layer, and described transparent dielectric layer can be air layer, transparent resin layer or transparent metal oxide layer.

Suppose from display light source only from as the incident of α Fig. 2 (R, G, B) direction of light the time, when the thickness of described clearance layer 10 satisfies following formula, regional shown in red corresponding to this thickness of this color filter:

${\mathrm{<figure-callout\; id="1"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_1={\mathrm{<figure-callout\; id="1"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_1{\mathrm{\&lambda;}}_1/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)=[({2\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_2+1){\mathrm{\&lambda;}}_2/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

$=[(2{\mathrm{<figure-callout\; id="3"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_3+1){\mathrm{\&lambda;}}_3/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

Wherein, e ₁When expression shows ruddiness, the thickness of described clearance layer; λ ₁Wavelength for ruddiness; λ ₂Wavelength for green glow; λ ₃Wavelength for blue light; n ₁Refractive index for described clearance layer; n ₂Refractive index for outside air; γ is that light is at the refraction angle of described the second semi-reflective and semitransmittable thin film inside surface; K wherein ₁, k ₂, k ₃Be non-negative integer, and k ₁=1,2, k ₂=0,1,2 k ₃=0,1,2 ...

When the thickness of described clearance layer 10 satisfies following formula, regional shown in green corresponding to this thickness of this color filter:

${\mathrm{<figure-callout\; id="2"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_2={{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_2}^{\&prime;}\mathrm{\&lambda;}}_2/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)=[({{2\mathrm{<figure-callout\; id="1"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_1}^{\&prime;}+1){\mathrm{\&lambda;}}_1/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

$=[({{2\mathrm{<figure-callout\; id="3"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_3}^{\&prime;}+1){\mathrm{\&lambda;}}_3/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

Wherein, e ₂When expression shows green glow, the thickness of described clearance layer; λ ₁Wavelength for ruddiness; λ ₂Wavelength for green glow; λ ₃Wavelength for blue light; n ₁Refractive index for described clearance layer; n ₂Refractive index for outside air; γ is that light is at the refraction angle of described the second semi-reflective and semitransmittable thin film inside surface; K wherein ₁', k ₂', k ₃' be non-negative integer, and k ₂'=1,2, k ₁'=0,1,2 k ₃'=0,1,2 ...

When the thickness of described clearance layer 10 satisfied following formula, this color filter was shown as blueness in the zone corresponding to this thickness:

${\mathrm{<figure-callout\; id="3"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_3={{\mathrm{<figure-callout\; id="3"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_3}^{\&prime;\&prime;}{\mathrm{\&lambda;}}_3/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)=[({{2\mathrm{<figure-callout\; id="1"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_1}^{\&prime;\&prime;}+1){\mathrm{\&lambda;}}_1/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

$=[({{2\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_2}^{\&prime;\&prime;}+1){\mathrm{\&lambda;}}_2/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

Wherein, e ₃When expression shows blue light, the thickness of described clearance layer; λ ₁Wavelength for ruddiness; λ ₂Wavelength for green glow; λ ₃Wavelength for blue light; n ₁Refractive index for described clearance layer; n ₂Refractive index for outside air; γ is that light is at the refraction angle of described the second semi-reflective and semitransmittable thin film inside surface; K wherein ₁", k ₂", k ₃" be non-negative integer, and k ₃"=1,2 ...; k ₂"=0,1,2 ...; k ₁"=0,1,2 ....

Preferably, be provided with anti-reflection layer in a side of described substrate 6, be used for preventing the interference of ambient light when this color filter is used for display panel.Concrete, in Fig. 2, external environment is only injected from the side that the second semi-reflective and semitransmittable thin film 8 deviates from clearance layer, and this moment, antireflection film should be arranged on the side that the second semi-reflective and semitransmittable thin film 8 deviates from clearance layer.Also have two outer a kind of situations, if surround lighting is to inject from the side that substrate 6 deviates from clearance layer, this moment, antireflection film was arranged on the side that substrate 6 deviates from clearance layer.

Preferably, described the first semi-reflective and semitransmittable thin film 7 or described second semi-reflective and semitransmittable thin film 8 of corresponding different colours display unit have identical thickness, can realize better color display effect like this.

The present invention will be further elaborated with embodiment for the below:

As shown in Figure 2, as a branch of white light α (R, G, B) during incident, when this white light during from clearance layer 10 directive outside air layer, because clearance layer 10 has different refractive indexes from the outside air layer, this incident light α (R, G, B) is through the second semi-reflective and semitransmittable thin film 8 time, can refraction and reflection occur at A point place, produce refract light α ₁(R ₁, G ₁, B ₁) and reflected light AC, when reflected light through the C point directive substrate 6 of the first semi-reflective and semitransmittable thin film 7 time, a part of light transmission, part light reflects, refraction and reflection can occur in reflected light CB at B point place through the second semi-reflective and semitransmittable thin film 8 time, produce refract light α ₂(R ₂, G ₂, B ₂).Need to prove in said process, due to the very thin thickness of the first semi-reflective and semitransmittable thin film 7 and the second semi-reflective and semitransmittable thin film 8, in nanometer scale, so light is when the double-layer films, and the refraction effect of generation can be ignored.If the refractive index of clearance layer 10 is n ₁, the refractive index of outside air is n ₂, refract light α so ₁(R ₁, G ₁, B ₁) and refract light α ₂(R ₂, G ₂, B ₂) optical path difference be:

Δ=n ₁(AC+CB)-n ₂AD。

Further, can be drawn by geometric relationship in refraction law and Fig. 2:

n ₁* sini=n ₂* sin γ, when wherein i and γ were respectively incident light α (R, G, B) from clearance layer 10 directive outside air layer, incident light α (R, G, B) was through incident angle and the refraction angle of the second semi-reflective and semitransmittable thin film 8 at A point place;

AD=AB*sinγ；

AC=CB=e ₁/cosi；

AB=2e ₁*tan?i；

And then derive $\mathrm{\&Delta;}={2\mathrm{<figure-callout\; id="1"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_1*{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1*\cos i={2\mathrm{<figure-callout\; id="1"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_1*\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\sin }^2\mathrm{\&gamma;})}.$

According to the interference of light condition:

1) long mutually: optical path difference Δ=k λ; (k=1,2 ...) → strengthen (bright);

2) disappear mutually: optical path difference Δ=(2k+1) λ/2; (k=0,1,2 ...) → weaken (secretly);

White light α (R, G, B) is that the RGB light by different-waveband combines.If the wave band of red light is λ ₁The wave band of green light is λ ₂The wave band of blue light is λ ₃Be e at clearance layer thickness ₁The two bundle refract light α in zone ₁(R ₁, G ₁, B ₁) and α ₂(R ₂, G ₂, B ₂) long mutually in red light wave band formation interference, and interfere the condition that disappears mutually to be in green light and the formation of blue light wave band:

$\mathrm{\&Delta;}={2\mathrm{<figure-callout\; id="1"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_1*\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}={\mathrm{<figure-callout\; id="1"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_1{\mathrm{\&lambda;}}_1;$ → red light is interfered long → reinforcement (bright) mutually

$\mathrm{\&Delta;}={2\mathrm{<figure-callout\; id="1"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_1*\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}=({2\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_2+1){\mathrm{\&lambda;}}_2/2;$ The interference of → green light disappears mutually → weakens (secretly)

$\mathrm{\&Delta;}={2\mathrm{<figure-callout\; id="1"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_1*\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}=({2\mathrm{<figure-callout\; id="3"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_3+1){\mathrm{\&lambda;}}_3/2;$ The interference of → blue light disappears mutually → weakens (secretly)

K wherein ₁=1,2, k ₂=0,1,2 k ₃=0,1,2

And then draw:

$e_1={\mathrm{<figure-callout\; id="1"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_1{\mathrm{\&lambda;}}_1/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}\right)=[({2\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_2+1){\mathrm{\&lambda;}}_2/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}\right)$ ①

$=[(2{\mathrm{<figure-callout\; id="3"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_3+1){\mathrm{\&lambda;}}_3/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}\right)$

Therefore, two bundle refract lights are through after interfering, and what human eye was seen in this zone is red light.Fig. 3 is above-mentioned two bundle refract light α ₁(R ₁, G ₁, B ₁) and α ₂(R ₂, G ₂, B ₂) the generation interference of light, the waveform schematic diagram that each wavelength period phase appearance disappears.

In like manner, when a branch of white light β (R, G, B) incident, be e at clearance layer thickness ₂The two bundle refract light β in zone ₁(R ₁, G ₁, B ₁) and β ₂(R ₂, G ₂, B ₂) long mutually in green light wave band formation interference, and interfere the condition that disappears mutually to be in red light and the formation of blue light wave band:

$\mathrm{\&Delta;}={2\mathrm{<figure-callout\; id="2"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_2*\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}={{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_2}^{\&prime;}{\mathrm{\&lambda;}}_2;$ → green light is interfered long → reinforcement (bright) mutually

$\mathrm{\&Delta;}={2\mathrm{<figure-callout\; id="2"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_2*\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}=({{2\mathrm{<figure-callout\; id="1"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_1}^{\&prime;}+1){\mathrm{\&lambda;}}_1/2;$ The interference of → red light disappears mutually → weakens (secretly)

$\mathrm{\&Delta;}={2\mathrm{<figure-callout\; id="2"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_2*\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}=({{2\mathrm{<figure-callout\; id="3"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_3}^{\&prime;}+1){\mathrm{\&lambda;}}_3/2;$ The interference of → blue light disappears mutually → weakens (secretly)

K wherein ₂'=1,2, k ₁'=0,1,2 k ₃'=0,1,2 ...

And then draw:

$e_2={{{\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_2}^{\&prime;}\mathrm{\&lambda;}}_2/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}\right)=[({{2\mathrm{<figure-callout\; id="1"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_1}^{\&prime;}+1){\mathrm{\&lambda;}}_1/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}\right)$ ②

$=[({{2\mathrm{<figure-callout\; id="3"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_3}^{\&prime;}+1){\mathrm{\&lambda;}}_3/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}\right)$

Therefore, two bundle refract lights are through after interfering, and what human eye was seen in this zone is green light.Fig. 4 is above-mentioned two bundle refract light β ₁(R ₁, G ₁, B ₁) and β ₂(R ₂, G ₂, B ₂) the generation interference of light, the waveform schematic diagram that each wavelength period phase appearance disappears.

In like manner, when a branch of white light δ (R, G, B) incident, be e at clearance layer thickness ₃The two bundle refract light δ in zone ₁(R ₁, G ₁, B ₁) and δ ₂(R ₂, G ₂, B ₂) long mutually in blue light wave band formation interference, and interfere the condition that disappears mutually to be in red light and the formation of green light wave band:

$\mathrm{\&Delta;}={2\mathrm{<figure-callout\; id="3"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_3*\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}={{\mathrm{<figure-callout\; id="3"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_3}^{\&prime;\&prime;}{\mathrm{\&lambda;}}_3;$ → blue light is interfered long → reinforcement (bright) mutually

$\mathrm{\&Delta;}={2\mathrm{<figure-callout\; id="3"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_3*\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}=({{2\mathrm{<figure-callout\; id="1"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_1}^{\&prime;\&prime;}+1){\mathrm{\&lambda;}}_1/2;$ The interference of → red light disappears mutually → weakens (secretly)

$\mathrm{\&Delta;}={2\mathrm{<figure-callout\; id="3"\; label="e"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">e</figure-callout>}}_3*\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}=({{2\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_2}^{\&prime;\&prime;}+1){\mathrm{\&lambda;}}_2/2;$ The interference of → green light disappears mutually → weakens (secretly)

K wherein ₃"=1,2 ...; k ₂"=0,1,2 ...; k ₁"=0,1,2 ....

And then draw:

$e_3={{\mathrm{<figure-callout\; id="3"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_3}^{\&prime;\&prime;}{\mathrm{\&lambda;}}_3/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}\right)=[({{2\mathrm{<figure-callout\; id="1"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_1}^{\&prime;\&prime;}+1){\mathrm{\&lambda;}}_1/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}\right)$ ③

$=[({{2\mathrm{<figure-callout\; id="2"\; label="k"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">k</figure-callout>}}_2}^{\&prime;\&prime;}+1){\mathrm{\&lambda;}}_2/2]/\left(2\sqrt{({{\mathrm{<figure-callout\; id="1"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_1}^2-{{\mathrm{<figure-callout\; id="2"\; label="n"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">n</figure-callout>}}_2}^2*{\mathrm{<figure-callout\; id="2"\; label="sin"\; filenames="HDA00002781280200011.png"\; state="\{\{state\}\}">sin</figure-callout>}}^2\mathrm{\&gamma;})}\right)$

Therefore, two bundle refract lights are through after interfering, and what human eye was seen in this zone is blue light.Fig. 5 is above-mentioned two bundle refract light δ ₁(R ₁, G ₁, B ₁) and δ ₂(R ₂, G ₂, B ₂) the generation interference of light, the waveform schematic diagram that each wavelength period phase appearance disappears.

Usually, in white visible light, red light λ ₁Wavelength coverage be 622 ~ 770nm; Green light λ ₂Wavelength coverage be 492 ~ 577nm; Blue light λ ₃Wavelength coverage be 435 ~ 480nm; Therefore can obtain at least one group of clearance layer one-tenth-value thickness 1/10 e ₁, e ₂, e ₃Satisfy the above-mentioned relation formula.

The present invention also provides a kind of display panel, and this display panel comprises the color filter that the invention described above provides.

Display panel described here comprises display panels, organic electroluminescence display panel etc.

The present invention also provides a kind of display device, and this display device comprises the display panel that the invention described above provides.

Concrete, in liquid crystal indicator, if in the spectrum of LED-backlit, red light wavelength is 630nm; Green light wavelength is 525nm; Blue light wavelength is 450nm.Distinguish value k ₁=8; k ₂=9; k ₃=11; k ₁'=7; k ₂'=9; k ₃'=10; k ₁"=6; k ₂"=7; k ₃"=9; Can be similar to simultaneously satisfy 1. above-mentioned, 2., 3. equation.Therefore, by selecting different clearance layer thickness e ₁, e ₂, e ₃And the LED-backlit source that is complementary, can satisfy human eye is e at clearance layer thickness ₁The zone sees is red light; Be e at clearance layer thickness ₂The zone sees is green light; Be e at clearance layer thickness ₃The zone sees is blue light, thereby realize colored the demonstration.

Especially, if clearance layer is air, n so ₁=n ₂, the optical path difference of above-mentioned two bundle refract lights can be reduced to Δ=2e ₁* n ₁* cos γ, occur after interference of light mutually long with disappear mutually be equal to above-mentioned.

Further, by color filter provided by the present invention is set in liquid crystal indicator, utilize the array matrix on liquid crystal molecule and array base palte to regulate and control GTG, just can realize full-color demonstration.

The above is only the preferred embodiment of the present invention; should be pointed out that for those skilled in the art, under the prerequisite that does not break away from the technology of the present invention principle; can also make some improvement and replacement, these improvement and replacement also should be considered as protection scope of the present invention.

Claims (10)

1. color filter, comprise a plurality of sub-pixel area that limited by black matrix unit, it is characterized in that, this color filter also comprises: substrate and be positioned at the first semi-reflective and semitransmittable thin film and the second semi-reflective and semitransmittable thin film on this substrate, comprise clearance layer between described the first semi-reflective and semitransmittable thin film and described the second semi-reflective and semitransmittable thin film, the corresponding described clearance layer of the sub-pixel area of different colours has different thickness.

2. color filter as claimed in claim 1, is characterized in that, described clearance layer is transparent dielectric layer.

3. color filter as claimed in claim 2, is characterized in that, described transparent dielectric layer is air layer, transparent resin layer or transparent metal oxide layer.

4. color filter as described in any one in claim 1-3, is characterized in that, when the thickness of described clearance layer satisfies following formula, and regional shown in red corresponding to this thickness of this color filter:

$e_1=k_1{\mathrm{\&lambda;}}_1/\left(2\sqrt{({n_1}^2-{n_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)=[({2k}_2+1){\mathrm{\&lambda;}}_2/2]/\left(2\sqrt{({n_1}^2-{n_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

$=[(2k_3+1){\mathrm{\&lambda;}}_3/2]/\left(2\sqrt{({n_1}^2-{n_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

Wherein, e ₁When expression shows ruddiness, the thickness of described clearance layer; λ ₁Wavelength for ruddiness; λ ₂Wavelength for green glow; λ ₃Wavelength for blue light; N1 is the refractive index of described clearance layer; n ₂Refractive index for outside air; γ is that light is at the refraction angle of described the second semi-reflective and semitransmittable thin film inside surface; K wherein ₁, k ₂, k ₃Be non-negative integer, and k ₁=1,2, k ₂=0,1,2 k ₃=0,1,2 ...

5. color filter as described in any one in claim 1-3, is characterized in that, when the thickness of described clearance layer satisfies following formula, and regional shown in green corresponding to this thickness of this color filter:

$e_2={{k_2}^{\&prime;}\mathrm{\&lambda;}}_2/\left(2\sqrt{({n_1}^2-{n_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)=[({{2k}_1}^{\&prime;}+1){\mathrm{\&lambda;}}_1/2]/\left(2\sqrt{({n_1}^2-{n_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

$=[({{2k}_3}^{\&prime;}+1){\mathrm{\&lambda;}}_3/2]/\left(2\sqrt{({n_1}^2-{n_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

Wherein, e ₂When expression shows green glow, the thickness of described clearance layer; λ ₁Wavelength for ruddiness; λ ₂Wavelength for green glow; λ ₃Wavelength for blue light; n ₁Refractive index for described clearance layer; n ₂Refractive index for outside air; γ is that light is at the refraction angle of described the second semi-reflective and semitransmittable thin film inside surface; K wherein ₁', k ₂', k ₃' be non-negative integer, and k ₂'=1,2, k ₁'=0,1,2 k ₃'=0,1,2 ...

6. color filter as described in any one in claim 1-3, is characterized in that, when the thickness of described clearance layer satisfied following formula, this color filter was shown as blueness in the zone corresponding to this thickness:

$e_3={k_3}^{\&prime;\&prime;}{\mathrm{\&lambda;}}_3/\left(2\sqrt{({n_1}^2-{n_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)=[({{2k}_1}^{\&prime;\&prime;}+1){\mathrm{\&lambda;}}_1/2]/\left(2\sqrt{({n_1}^2-{n_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

$=[({{2k}_2}^{\&prime;\&prime;}+1){\mathrm{\&lambda;}}_2/2]/\left(2\sqrt{({n_1}^2-{n_2}^2*{\sin }^2\mathrm{\&gamma;})}\right)$

Wherein, e ₃When expression shows blue light, the thickness of described clearance layer; λ ₁Wavelength for ruddiness; λ ₂Wavelength for green glow; λ ₃Wavelength for blue light; n ₁Refractive index for described clearance layer; n ₂Refractive index for outside air; γ is that light is at the refraction angle of described the second semi-reflective and semitransmittable thin film inside surface; K wherein ₁", k ₂", k ₃" be non-negative integer, and k ₃"=1,2 ...; k ₂"=0,1,2 ...; k ₁"=0,1,2 ....

7. color filter as described in any one in claim 1-3, is characterized in that, is provided with antireflection film in a side of described substrate.

8. color filter as described in any one in claim 1-3, is characterized in that, described the first semi-reflective and semitransmittable thin film or described second semi-reflective and semitransmittable thin film of the pixel region of corresponding different colours have identical thickness.

9. a display panel, is characterized in that, comprises the described color filter of any one in claim 1-8.

10. a display device, comprise display panel claimed in claim 9.

Images