CN101350582A - Nuclear force constrain inertial guidance cold nucleus fusion stack and ion speed-governing dc transformer - Google Patents

Abstract

The present invention relates to a nuclear-constraining inertial-guidance cold nuclear fusion stack and ionic speed-regulating DC transformer, which are expected to completely solve the problems of energy and environmental protection which human beings are confronted with. The DC transformer can provide clean, secure and limitless nuclear-powered energy for all spacecrafts, aircrafts, ships, vehicles, power plants and other power-consuming device, so that human beings can really enter the age of nuclear energy. And the DC transformer has the following characteristics: under the condition of normal temperature, a special combined electromagnetic field is arranged in the space; according to the inherent magnetic moment and internal electric field of the light nucleus, two nucleuses to be fused are constrained within the same section; the vector of the inherent spinning moment of momentum of the nucleus is adopted to form the inertial-guidance characteristic of the ultra-powerful spinning top which can spin at a speed similar to the light velocity, so as to overcome the deflection of Coulomb barrier and to realize the fusion of direct collision; the similar nuclear-constraining inertial guidance mode is adopted to complete mixed speed regulation of ion beams of different velocities and different types of energy; then the ionic speed-regulating DC transformer is formed and provides significant auxiliary equipment of cold nuclear fusion stack, nuclear engine, and similar nuclear power plant which is used for starting the nuclear fusion and electrical energy conveying system. Therefore, a combined patent right is applied for.

Description

Nuclear force constrain inertial guidance cold nucleus fusion stack and ion speed-governing dc transformer

Technical field

Under normal temperature condition,, realize deuterium, tritium, helium, lithium by the associated form of nuclear force constraint inertial guidance ... examine controlled cold checking and hit fusion Deng the light atom that has certain magnetic moment, belong to " the cold fusion heap " of nuclear power source research and development applied technical field.The nuclear force constraint inertial guidance system of applications similar, ion beam mixing speed governing to friction speed and energy, the ion speed-governing dc transformer that is developed into, be the important corollary equipment that cold fusion heap, atomic propulsion nuclear engine and such nuclear power station start nuclear fusion and power delivery system, so merge patent right of application.

Note that this patent is expected to once and for all and thoroughly solves the energy and the environmental protection difficult problem that the whole mankind faces, so the every delay of its research and development progress one day, the whole mankind must bear one day high energy expenditure and heavy environmental protection pressure more.Energy industry is the engine that promotes the national economic development, and petroleum resources are the strategic materials of each big country's contention control especially.This patented invention relates to the vital interests of national defense safety and national economy.According to the condition that the Patent Law of the People's Republic of China chapter 2 is granted patent, the 25 clause of not granting patent, first item () scientific discovery; The material that the 5th section (five) obtain with the nuclear fission method.Suggestion is classified this patent of invention as national top secret patent, prioritizes support, and conducts a research as early as possible.

Background technology

Construction is obtained the nuclear reactor or the nuclear power station of nuclear power source by heavy nucleus fission mode, and the last century is just succeedd the forties.But the uranium ore resource of occurring in nature is also limited, can only satisfy the demand in hundreds of years of the whole mankind at most.Moreover, the difficult problem that this class nuclear reactor also exists the pollution post-processed of level radioactive nuclear waste to bury.

When scientific circles found the energy of the sun be exactly produce by thermonuclear fusion after.Unremitting effort research through several generations is explored, and it seems at present to be hopeful relatively to realize reluctantly that have only the magnetic field force constraint thermonuclear fusion and the inertia force of controlled nuclear fusion retrain thermonuclear fusion.Because the basic physical condition of magnetic field force constraint thermonuclear fusion, must with thin, up to 10 ⁸The plasma of superhigh temperature more than ℃ constrains in certain spatial dimension with high-intensity magnetic field power.The basic physical condition of inertia force constraint thermonuclear fusion must provide multidirectional light laser energy stream moment, synchronously to the pellet compression of diameter less than 1 millimeter.Overcome the basic physical and chemical condition estimation that coulomb electric field force potential barrier realizes nuclear fusion from nucleon, the two all needs the energy of the above particle warm-up movement of tens million of degree.So:

1. how the nuclear fusion material is heated to so superhigh temperature?

2. how to retrain the plasma of superhigh temperature like this long-term and stably? and reduce the energy dissipation loss as far as possible, how to realize continous-stable, high efficiency nuclear fusion?

3. how to develop can stand for a long time superhigh temperature like this and superenergy particle radiation (especially the kinetic energy of plasma temperature behind the high efficiency nuclear fusion and ion will improve several times again! ) be material as the border of constraint control?

4. how to realize conveying and heat energy---the conversion of electric energy of the continous-stable of ultra-high temperature plasma like this smoothly?

……。

All these be we can say, the so harsh superhigh temperature and the condition of superenergy with the existing scientific and technological level of the mankind, with all materials that is made of atom or molecule, all are difficult to for a long time stably bear! Although in carrying out now, the United States, Russia, seal, Japan and Korea S. and whole European Union strong-unite international large-scale cooperation by force, in following 30～50 years, also be difficult to realize lasting, reliable, stable and high efficiency commercialization generator operation.

The equipment of the nuclear reaction system of above-mentioned three class nuclear reactors, Conversion of energy system and security protection system is all quite huge, complicated, heavy, can't use as the engine of aircraft or spaceship at space flight, aviation field.More can not popularize and use as the power of conventional vehicles.Nuclear fusion stack has become the whole mankind and has faced the heavy energy, environmental protection pressure, presses for as early as possible to solve, and goes through surplus in the of 60 and year still attacks an international No.1 science difficult problem of being unable to for a long time.

Project of the present invention " nuclear force constrain inertial guidance cold nucleus fusion stack and ion speed-governing dc transformer ", thoroughly solve the energy and the environmental protection difficult problem that the whole mankind faces for once and for all exactly, fully from another approach, under the prerequisite that existing manufacturing process technology can be competent at, this patent of invention design.

Summary of the invention

The main research contents of " nuclear force constrain inertial guidance cold nucleus fusion stack and ion speed-governing dc transformer ", be with hydrogen, deuterium, tritium, lithium ... Deng the light atom nuclear that has certain magnetic moment, in the controlled cold fusion reaction chamber of my nuclear force constraint inertial guidance invention, specific, implement cold checking and hit fusion.The author in the monograph of " modern physics classical particle quantization orbital motion model general solution ", tight proof accurately: (see Email for details: Gw49060527iy82@yahoo.com.cn, the password of unpacking: 276894.) intranuclear nuclear force, comprise so-called strong interaction power and weak interaction force, all be the summation of mutual equilibrium relation between the electricity that forms under the atomic nucleus microcosmic certain conditions, magnetic field force.So cold the checking of nuclear force constraint inertial guidance hit the fusion patent of invention, is exactly with existing dynamo-electric manufacturing technology level, under macroscopical specified conditions, specific electromagnetic force is set earlier the fusion atomic nucleus for the treatment of of two string move toward one another is constrained in a certain the line segment; Utilize the intrinsic spin momentum moment vector of elementary particle and atomic nucleus to form the HHT higher high tensile rotation gyroscopic inertia guidance characteristic of dipped beam speed spin again, the nuclear fusion of realizing directly clashing normal temperature condition under.

At first, with the conductor of a positively charged tabular conductor and one group of equal and opposite in direction, thin cylindric band equivalent positive charge, by specific space combining setting, in the positive electrostatic field background of high electric field strength and energy of position, set up the equipotential surface of long rectangle plane shape.The mutual electrostatic field repulsive force of light atom nuclear string self of fusion is treated in utilization, is extruded to the both sides of long rectangle plane automatically, forms two nucleon strings that are arranged in parallel.Thereby set up wire zero electrostatic field of a group or array boundling.(the electric field strength equal and opposite in direction on this cross section, wire district, direction vector is opposite, just cancels each other, static potential energy is minimum).Charged light atom nuclear is sprayed into this electrostatic field force along two ends at a high speed in opposite directions with electrostatic particle linear pattern accelerator acceleration back to be retrained in the zero electric field line segment that forms.According to the light atom nuclear natural magnetic moments for the treatment of fusion, the strong external magnetic field of additional parallel this line segment is set again, the magnetic dipole moment of light atom nuclear all is along this line segment and aligns magnetization under strong external magnetic field effect.It can reduce the electrostatic field repulsive force between the adjacent atom nuclear, the guidance direction that can proofread and correct gyro again effectively.Finally form under the HHT higher high tensile rotation gyroscopic inertia guidance function of dipped beam speed spin with the spin momentum moment vector that has, overcome the deflection effect of Coulomb force potential barrier, realize the fusion of directly clashing of cold nuclear at atomic nucleus.New atomic nucleus after the fusion such as helium atomic nucleus, because self does not have magnetic moment, has 2 * 10 again ⁷The kinetic energy that ev is above can be broken through the constraint of electrostatic field force potential barrier and magnetic field force voluntarily, penetrates at a high speed.Directly change into voltage for (10～1000) * 10 through importing multistage ion speed-governing dc transformer ³The direct current energy output of volt.

One, the physical model and the theoretical foundation of nuclear force constrain inertial guidance cold nucleus fusion stack and ion speed-governing dc transformer invention design

Key foundation theory of the present invention is from " modern physics classical particle quantization orbital motion model general solution " new modern physics monograph of the author, the HHT higher high tensile of the particle of systematic analysis, atomic nucleus inside spin gyroscopic inertia constant-bearing guidance characteristic in the 1st～14 chapter, strong, weak, electric, magnetic interaction principle of integrity proves and accurate computational methods.Now the parameter of earlier analog computation of Main physical model, theorem, formula and the relevant nucleon relevant with patent of the present invention being verified is taken passages as follows:

(P2～3), Broglie just proposes in one's early years and confirms that through the descendant all there is fluctuation in microcosmic particle, its wavelength

Particle momentum $\stackrel{\→}{P}=m\stackrel{\→}{v}$ With the pass of Planck's constant h be:

$\stackrel{\→}{\mathrm{\λ}}=\frac{h}{\stackrel{\→}{P}}---\left(1.1\right)$

Law of conservation of moment of momentum according to quantum-mechanical particle wave equation and Newtonian mechanics, as long as we determine the motion feature of particle with fluctuation, the vertical two-orbit motion mode of spin quantization stationary state simultaneous, static elementary particle inner tracks motion feature just as shown in Figure 1, equation group is:

In (1.2) equation group, order ${\stackrel{\→}{v}}_{\mathrm{\θ}}/{\stackrel{\→}{v}}_{\mathrm{\α}}=E_{\mathrm{\α\θ}}\≤1$ Be constant, just can directly derive:

$\left\{\begin{array}{cc}{\stackrel{\→}{R}}_{\mathrm{\α}}=\frac{{\stackrel{\→}{R}}_{\mathrm{\θ}0}{E}_{\mathrm{\α\θ}}}{1+E_{\mathrm{\α\θ}}\cos \mathrm{\α}}& (1.3-1)\\ {\stackrel{\→}{R}}_{\mathrm{\θ}}=\frac{{\stackrel{\→}{R}}_{\mathrm{\θ}0}}{1+E_{\mathrm{\α\θ}}\cos \mathrm{\α}}& (1.3-2)\end{array}\right.$

Two kinds of orthogonal tracks of The above results proof all are elliptic orbits!

(P5), to particle or the atomic nucleus along the straight line ejection-type, its precession direction also is the moment of momentum direction vector (or in the other direction) of spin.This spin precession orbital motion model tightly accurately proves at P26～33 the 4th chapters, sees Fig. 2:

(P41～42), proton inside is by π ⁺Meson and nuclear core are formed, and structure is seen Fig. 3, and each parameter simulation result of calculation is as follows:

π ⁺The spin motion speed of meson: v _θ=0.6389682138c

R _θ2(0)＝0.331292×10 ^-15m

π ⁺The orbit radius of meson spin motion:

R _θ2(π)＝1.507187×10 ^-15m

The magnetic moment of proton: Up=1.4106171 * 10 ^-26J/T

The velocity of wave motion of proton nuclei core: v _α=β _iC ≈ c

(p43～44), neutron inside is by π ^-Form with positively charged nuclear core, structure is seen Fig. 3, and each parameter simulation result of calculation is as follows:

π ^-The spin motion speed of meson: v _θ=0.6389682138c

R _θ2(0)＝0.415254×10 ^-15m

π ^-The orbit radius of meson spin motion:

R _θ2(π)＝1.889164×10 ^-15m

The magnetic moment of neutron: Un=-0.9661136 * 10 ^-26J/T

The velocity of wave motion of middle daughter nucleus core: v _α=β _iC ≈ c

Because D-atom nuclear (is called for short D nuclear, down together.) form by proton and neutron, magnetic moment is: Ud=0.4330574 * 10 ^-26J/T approximates magnetic moment difference DELTA U=0.4445035 * 10 of proton neutron ^-26J/T.The tritium atomic nucleus is made up of proton and two neutrons, and magnetic moment is: Ut=1.504553 * 10 ^-26J/T, almost equal with proton moment.Just can judge from their magnetic moment: D-atom nuclear is formed along the spin axis serial connection by the proton neutron; In the middle of tritium atomic nucleus inner proton was positioned at, the neutron magnetic moment spin direction that both sides are symmetrically distributed was opposite, just offset, and saw Fig. 4.

According to the definition of electrodynamics to magnetic moment, by (1.3) equation group, nuclear moments is moved along closed orbit by charged elementary particle and is formed, and the D-atom nuclear magnetic moment is obviously mainly formed by the surge movement of the nuclear core particle of tape unit electric charge in the neutron.Its equivalent current I ₀With the current element radius r ₀Be respectively:

$U_d=\mathrm{\&pi;}{\stackrel{\&OverBar;}{r}}_0^2{\mathrm{<figure-callout\; id="0"\; label="I"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">I</figure-callout>}}_0=\mathrm{\&pi;}{\stackrel{\&OverBar;}{r}}_0^2\frac{e{v}_{\mathrm{\&alpha;}}}{2\mathrm{\&pi;}{\stackrel{\&OverBar;}{r}}_0}=\frac{e{v}_{\mathrm{\&alpha;}}{\stackrel{\&OverBar;}{r}}_0}{2}---\left(1.4\right)$

With U _d, v _αValue is brought following formula into: r ₀=2.82205 * 10 ^-16M, I ₀=17308.75A

Two, the density estimation of head-on collision nuclear fusion D nucleon string and ion speed-governing dc transformer electric current

(1), the density estimation of head-on collision nuclear fusion D nucleon string

Suppose that the effective energy that each D nucleon head-on collision fusion discharges is 10 ⁷Ev, the number N of the D particle that the fusion reactor per second of 100 kw of power needs _d/ s is:

N _d=10 ⁵/ e * 10 ⁷=6.24 * 10 ¹⁶(individual/second)

The total current intensity that is equivalent to the D nucleon beam is 0.01 ampere.Then Dui Zhuan every D nucleon string is 3.12 * 10 ¹⁶(individual/second).

The startup energy of supposing the electrostatic accelerator of two D nucleon strings all is 6.5 * 10 ⁵Ev, the orientation that deducts reactor head-on collision nuclear fusion district retrains original energy of position 100000ev.So, remaining kinetic energy should be 5.5 * 10 ⁵Ev.Then the movement velocity of D nucleon string should be:

$v_{d1}=\sqrt{2e\&times;5.5\&times;{10}^5/m_d}=5.133\&times;{10}^6(m/s)=0.01712c$

The line density δ of each bar D nucleon string _eL is respectively with the nucleon separation delta:

${\mathrm{\&delta;}}_e=\frac{3.12\&times;{10}^{16}}{v_{d1}}=6.078\&times;{10}^9$ (individual/m), Δ L=1/ δ _e=1.645 * 10 ^-10(m/)

Energy of position W between each D nucleon _e:

$W_e=\frac{e}{4\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0\mathrm{\&Delta;L}}=8.7536\left(\mathrm{ev}\right)$

If the line density δ of D nucleon string _e=6.078 * 10 ⁹(individual/m), Δ L=R ₀, $\ln \frac{\mathrm{<figure-callout\; id="0"\; label="R\; R"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">R</figure-callout>}}{R_{}}=2,$ Every D nucleon line outside cylindrical surface radius is that electric field strength, the energy of position at R place is respectively:

$E_e=\frac{e{\mathrm{\&delta;}}_e}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0\mathrm{\&Delta;L}}=1.064\&times;{10}^{11}$ (volts/meter) $V_e=\frac{e{\mathrm{\&delta;}}_e}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0}\mathrm{<figure-callout\; id="0"\; label="ln\; R\; R"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">ln</figure-callout>}\frac{R}{R_{}}\frac{{}_0}{}=12.133$ (volt)

By distance values and the above-mentioned estimation result of Δ L, on the spacing of this Δ L, it is feasible making D nucleon string density improve 10～100 times, and the power that can estimate single bundle head-on collision fusion thus has the adjustable constant interval of (0.1～10) MW (megawatt).

If the nuclear force constraint inertial guidance head-on collision cold fusion experiment of above-mentioned single bundle two string D nucleons can be successful, we just can consider to adopt multi beam to be arranged in parallel, divide into groups side by side with this arrangement again, merge corollary equipments such as using a cover electrostatic particle accelerator and ion speed-governing dc transformer.So that make gross power be the geometric progression expansion.

(2), the current strength of ion speed-governing dc transformer estimation

In like manner, if power output is 100 kilowatts, voltage is 1000 volts direct current energy, and then current strength is 100A.The electric current of supposing this 100A is that a particle by cold fusion forms after the continuous step-down of multistage ion speed-governing dc transformer, and then in the final stage step-down, a particle movement speed is:

$v_{\mathrm{\&alpha;}}=\sqrt{4e\&times;1000/m_{\mathrm{\&alpha;}}}=3.105198\&times;{10}^5(m/s)=0.001036c$

The line density δ of each bar a particle string _eL is respectively with the interparticle distance Δ:

${\mathrm{\&delta;}}_e=\frac{100}{e{v}_{\mathrm{\&alpha;}}}==201002\&times;{10}^{15}$ (individual/m), Δ L=1/ δ _e=4.97508 * 10 ^-16(m/)

The interparticle distance Δ L of a particle string of above-mentioned estimation is also littler than nuclear spacing! Obviously, this is impossible.Fortunately the requirement of the electromagnetic field constraint strength in the ion speed-governing dc transformer is not high, and the problem that does not exist the nucleon behind the nuclear fusion vertically to spray.We could design intensive cellular combining structure in the commutator transformer step-down of the high-pressure section more than 10000 volts, and the boundling number is directly improved up to ten thousand times! (seeing the back demonstration for details).Low-pressure section is taked conventional means step-down.Perhaps directly research and develop high voltage withstanding high rotating speed DC motor.

Three, the design principle of wire zero electric field

(1), electrostatic field force is treated the estimation of fusion light atom nuclear restriction ability

If the thin cylinder of two endless uniform chargeds is arranged, is parallel distribution as shown in Figure 5.There are two deuterium light atom nuclears head-on head-on collision or rear-end impact in the centre, but because coulomb barrier repulsive force effect meeting causes deflection " to wipe shoulder " and mistake.If thin cylindrical electric charge line density is δ _Ced, by Coulomb's law and Gauss theorem, electrostatic field intensity E _eFor:

$E_e=\frac{{\mathrm{\&delta;}}_{\mathrm{ced}}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{R}_x}---\left(1.5\right)$

Two light atom nuclears " wiping shoulder " and cross are under the squeezing action of comprehensive thin cylindrical conductor electrostatic field force, and equilibrium condition is:

$\frac{e{\mathrm{\&delta;}}_{\mathrm{ced}}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0(R_x-0.5\mathrm{\&Delta;H})}=\frac{e{\mathrm{\&delta;}}_{\mathrm{ced}}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0(R_x+0.5\mathrm{\&Delta;H})}+\frac{e^2}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0\mathrm{\&Delta;L\&Delta;H}}---\left(1.6\right)$

Work as R _xDuring＞＞Δ H → Δ L, make Δ H → 2r ₀(the nuclear diameter 2r of D ₀=2 * 10 ^-15M) time, get by (1.6) formula:

${\mathrm{\&delta;}}_{\mathrm{ced}}=\frac{e{R}_x^2}{8{\mathrm{<figure-callout\; id="0"\; label="r"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">r</figure-callout>}}_0^3}---\left(1.7\right)$

If R _x=0.1m brings following formula into and gets: δ _Ced=2.00272 * 10 ²³(storehouse, storehouse/rice).If thin cylinder radius R ₀=0.05m, then the electromotive force V of periphery must greater than:

$V=\underset{R_0}{\overset{R_x}{\&Integral;}}\frac{{\mathrm{\&delta;}}_{\mathrm{ced}}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{R}_x}d{R}_x=\frac{{\mathrm{\&delta;}}_{\mathrm{ced}}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0}\ln \frac{R_x}{{\mathrm{<figure-callout\; id="0"\; label="R"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">R</figure-callout>}}_0}=2.49527\&times;{10}^{33}$ (volt) (1.8)

Shown by top simple estimation result: this almost is other magnitude of voltage of astronomical grade! The pure electrostatic field that explanation is combined to form with the right circular cylinder of simple parallel uniform charged, realizing overcoming between the light atom nuclear surging base of Coulomb field heads on or the head-on collision fusion of knocking into the back, its electric field and electromotive force intensity are all quite high, and we may not rely on the level of existing electromechanical equipment manufacturing process to charge and produce so high voltage!

If the D nucleon string of Fig. 5 directly is divided into two bundles by the internal electric field of self, establishes R _x＞Δ H＞＞during Δ L, then still get by (1.6) formula:

${\mathrm{\&delta;}}_{\mathrm{ecd}}=\frac{e{R}_x^2}{\mathrm{\&Delta;L\&Delta;}{H}^2}---\left(1.9\right)$

Make Δ H=10 ^-2M, Δ L=10 ^-10M brings following formula into and gets: δ _Ecd=1.6022 * 10 ^-7(storehouse, storehouse/rice), the V=1996 volt.This magnitude of voltage is that the level of existing electromechanical equipment manufacturing process is easy to accomplish.Here it is makes full use of the internal electric field physical model and the theoretical foundation of D nucleon string.

(2), the wire of the positively charged conductor of tabular and one group of thin cylindric positively charged conductor zero electric field forms principle

By the electrostatic field physical characteristic as can be known, under the electrostatic equilibrium state, electric charge all is distributed in conductive surface, and power line is all perpendicular to conductive surface, and conductive surface is an equipotential volume.In order to realize designing the desired wire of patent of the present invention zero electric field, at first must realize having a certain size circular, tabular and the thin cylindrical conductor of finite length in electrostatic field interacts, the original isodensity of whole conductive surface electrostatic charge distributes, and perhaps approximate isodensity distributes.For this reason, to circular conductor, can earlier conductive surface be separated into 6～N circular ring plate along the parallel circle loop wire.(the N value does not have the upper limit, equates to be as the criterion with the initial charge surface density that can realize whole conductive surface as far as possible).Separate into sub-conductor with dielectric between the circular ring plate.To the tabular conductor, can be divided into several strip sub-conductors, limit portion with elongated semi-cylindrical sub-conductor around, between all separate with dielectric.In like manner, to time-limited thin cylindrical conductor, can be at two ends the sub-conductor of the hemispherical or semielliptical shape of attached single raise, see Fig. 6.In case of necessity, segmentation or cut along axis and to be 2～N sub-conductor again, between also all separate equally with dielectric.Like this, as long as interact according to the electric field of each conductor in the electrostatic field, calculate auxiliary voltage, the sub-conductor of each conductor is filled with the voltage of different value respectively again, we just can realize the initial charge surface density of each conductive surface or line density about equally.

According to the electrostatic field feature, the thin cylindrical conductor of the endless of two parallel distributions of equal and opposite in direction, when they all were with the equivalent positive charge, on cross section, its electric force lines distribution was just as shown in Figure 7.

On the middle ABC plane of symmetry, the electric charge line density that makes thin cylindrical conductor is δ _Ce,, close electric field strength E by Gauss theorem _AFor:

$E_A=\frac{{\mathrm{\&delta;}}_{\mathrm{ce}}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{\mathrm{<figure-callout\; id="0"\; label="R"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">R</figure-callout>}}_0}\&CenterDot;2\sin \mathrm{\&alpha;}\cos \mathrm{\&alpha;}=\frac{{\mathrm{\&delta;}}_{\mathrm{ce}}\sin 2\mathrm{\&alpha;}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{R}_0}---\left(1.10\right)$

Along the ABC symmetrical plane, when α=0 °, at the B point, electric field strength is 0, but energy of position is a maximum.Homocharge is all repelled toward A, C direction.When α=45 °, $E_A=\frac{{\mathrm{\&delta;}}_{\mathrm{ce}}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{\mathrm{<figure-callout\; id="0"\; label="R"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">R</figure-callout>}}_0}$ Be maximum, as the A point place of Fig. 7, (please note:

Be the cross section symbol of wire zero electric field, down together).When our conductor that tabular is positively charged and thin cylindric positively charged conductor shown in Figure 7 are provided with by space shown in Figure 8, as long as the uniform electric field strength E of tabular energized conductor one side _EPBe slightly less than (1.10) formula $E_A=\frac{{\mathrm{\&delta;}}_{\mathrm{ce}}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{\mathrm{<figure-callout\; id="0"\; label="R"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">R</figure-callout>}}_0}$ Maximum, then just can form the zero electric field of two wire near the A of Fig. 8 point place.

Form in the schematic diagram at wire shown in Figure 8 zero electric field, the surface density of charge that makes the tabular conductor is δ _Ep, with the dielectric distance of bottom be d=0.20m, the electric charge line density of thin cylindrical conductor is δ _Ex, the D nucleon crosstalk lotus line density of arranging along wire zero electric field is δ _Ed1And δ _Ed2, spacing is Δ H, α ₀=45 °.Then according to the electrostatic field force equilibrium principle of electrostatic field force on symmetrical plane, we have:

$\left\{\begin{array}{cc}\frac{e{\mathrm{\&delta;}}_{\mathrm{ex}}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0}\&CenterDot;\frac{2\sin {\mathrm{\&alpha;}}_1\cos {\mathrm{\&alpha;}}_1}{R_{\mathrm{ex}}}=\frac{e{\mathrm{\&delta;}}_{\mathrm{ed}2}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0\mathrm{\&Delta;H}}+\frac{e{\mathrm{\&delta;}}_{\mathrm{ep}}}{{\mathrm{\&epsiv;}}_0}& (1.11-1)\\ \frac{e{\mathrm{\&delta;}}_{\mathrm{ex}}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0}\&CenterDot;\frac{2\sin {\mathrm{\&alpha;}}_2\cos {\mathrm{\&alpha;}}_2}{R_{\mathrm{ex}}}=\frac{e{\mathrm{\&delta;}}_{\mathrm{ed}1}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0\mathrm{\&Delta;H}}+\frac{e{\mathrm{\&delta;}}_{\mathrm{ep}}}{{\mathrm{\&epsiv;}}_0}& (1.11-2)\end{array}\right.$

(1.11) equation group can be reduced to:

$\left\{\begin{array}{cc}\frac{{\mathrm{\&delta;}}_{\mathrm{ex}}}{R_{\mathrm{ex}}}\sin 2{\mathrm{\&alpha;}}_1-2\mathrm{\&pi;}{\mathrm{\&delta;}}_{\mathrm{ep}}=\frac{{\mathrm{\&delta;}}_{\mathrm{ed}2}}{\mathrm{\&Delta;H}}& (1.12-1)\\ \frac{{\mathrm{\&delta;}}_{\mathrm{ex}}}{R_{\mathrm{ex}}}\sin 2{\mathrm{\&alpha;}}_2-2\mathrm{\&pi;}{\mathrm{\&delta;}}_{\mathrm{ep}}=\frac{{\mathrm{\&delta;}}_{\mathrm{ed}1}}{\mathrm{\&Delta;H}}& (1.12-2)\end{array}\right.$

The condenser voltage that makes plane conductor and following dielectric form is 40000 volts, then the surface density of charge δ of plane conductor _EpFor:

${\mathrm{\&delta;}}_{\mathrm{ep}}={\mathrm{\&epsiv;}}_0{E}_{\mathrm{ep}}={\mathrm{\&epsiv;}}_0\frac{U_{\mathrm{ep}}}{d}=1.7708\&times;{10}^{-6}$ (coulomb/rice ²) (1.13)

Order

R _Ex=0.04m, sin2 α ₁=sin (180 °-2 α ₁)=sin 2 α ₂, δ then _Ed1=δ _Ed2, (1.12)

Equation group further is reduced to:

${\mathrm{\&delta;}}_{\mathrm{ex}}\&CenterDot;\frac{\sin 2{\mathrm{\&alpha;}}_1}{R_{\mathrm{ex}}}-2\mathrm{\&pi;}{\mathrm{\&delta;}}_{\mathrm{ep}}=\frac{{\mathrm{\&delta;}}_{\mathrm{ed}1}}{\mathrm{\&Delta;H}}---\left(1.14\right)$

By (1.14) formula, we can extrapolate the electric charge line density δ of thin cylindrical conductor _ExVariation among a small circle to D nucleon string density δ _Ed1See Table 1 with the influence of separation delta H:

The electric charge line density δ of thin cylindrical conductor _ExVariation among a small circle to D nucleon string density δ _Ed1With separation delta H influence table table 1

Can find out from the result of table 1 analog computation,, just can adjust D nucleon string density and the internal electric field for the treatment of fusion significantly, adjust its initial charge line density δ as long as we suitably adjust the charging voltage of each sub-conductor in thin cylindrical conductor or the tabular conductor _ExThereby, can reach the power that large-scale adjustment cold fusion is piled easily! Also can spray the flow of D nucleon string, thereby reach the purpose of adjusting reactor capability significantly by adjustment.Can also be directly by being installed in the voltage sensor of fusion helium atomic nucleus jet both sides in advance, directly link to each other at the porch of wire zero electric field shunting deviating electrode with D nucleon string line, 4 string nucleon head-on collision fusion energies in two wire, zero electric field are carried out smoothly, be unlikely to take their own roads.

Wherein, if δ _Ex=4.65 * 10 ^-7→ 1.5 * 10 ^-6(storehouse, storehouse/rice), lnR _Ex/ R ₀=ln3, the then original charging voltage value of thin cylindrical conductor $U_{\mathrm{ex}}=\frac{{\mathrm{\&delta;}}_{\mathrm{ex}}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0}\ln 3=9182\&RightArrow;29621$ (volt) is also in the tolerance band of prior art level.

With table 1 data to δ _Ed1Value gets 2.2002 * 10 ^-9With 8.5269 * 10 ^-7Two extreme values are brought into $\mathrm{\&Delta;L}=\frac{e}{{\mathrm{\&delta;}}_{\mathrm{ed}1}}$ Formula:

Δ L is respectively 7.2820 * 10 ^-11M, 1.8790 * 10 ^-13M is also in comparatively ideal scope.

In like manner, 4 thin cylindric positively charged conductors just can synthesize three groups of our needed centres totally 6 zero electric fields of wire with the combined electrical line of force of tabular energized conductor, see Fig. 9.In the time of necessary, we can also arrange one group thin columned energized conductor in the both sides of dull and stereotyped energized conductor, make the bundle number of wire zero electric field double again.

Please note: in the actual design scheme, the α particle in fusion chamber perpendicular to D nucleon string eject position and near, carefully cylindric, the tabular energized conductor and the direction of magnetization that adds high-intensity magnetic field all should bendings protruding upward a little; The tabular energized conductor has long and narrow slit herein, and the α particle can only be convenient to alpha-particle energy and concentrate in the multistage continuous ion speed-governing dc voltage regulator of importing like this along this folk prescription to ejaculation.

(3), wire zero electric field of one group of circular energized conductor and several thin cylindric energized conductor combinations forms principle

1. at the electric field strength and the energy of position variation characteristic of circular conductor axis inboard

If the electric charge line density δ on the conductor loops _HeFor: ${\mathrm{\&delta;}}_{\mathrm{he}}=\frac{Q}{2\mathrm{\&pi;}{R}_{\mathrm{he}}}$ $\mathrm{dQ}={\mathrm{\&delta;}}_{\mathrm{he}}\mathrm{dl}=\frac{Q}{2\mathrm{\&pi;}}\mathrm{d\&beta;},$ See Figure 10.

We are divided into it two semi-rings with the OYZ plane symmetry earlier, make full use of the Gaussian symmetric principle, then:

$L=\sqrt{{\left(R_{\mathrm{he}}\sin \mathrm{\&beta;}\right)}^2+{(R_{\mathrm{he}}\cos \mathrm{\&beta;}-Y_0)}^2+{\mathrm{<figure-callout\; id="0"\; label="Z"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">Z</figure-callout>}}_0^2}$

Make Y ₀/ R _He=K _yZ ₀/ R _He=K _zBringing following formula into gets:

$L=\sqrt{R_{\mathrm{he}}^2-2R_{\mathrm{he}}{Y}_0\cos \mathrm{\&beta;}+{\mathrm{<figure-callout\; id="0"\; label="Y"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">Y</figure-callout>}}_0^2+{\mathrm{<figure-callout\; id="0"\; label="Z"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">Z</figure-callout>}}_0^2}$

$=R_{\mathrm{he}}\sqrt{1-2K_y\cos \mathrm{\&beta;}+K_y^2+K_z^2}$

Order: E _Z1/ E ₁=cos α $\cos \mathrm{\&alpha;}={\mathrm{<figure-callout\; id="0"\; label="Z"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">Z</figure-callout>}}_0/L=\frac{K_z}{\sqrt{1-2K_y\cos \mathrm{\&beta;}+K_y^2+K_z^2}}$

E _y1/E ₁＝cosθ $\cos \mathrm{\&theta;}=\frac{R_{\mathrm{he}}\cos \mathrm{\&beta;}-Y_0}{L}=\frac{\cos \mathrm{\&beta;}-K_y}{\sqrt{1-2K_y\cos \mathrm{\&beta;}+K_y^2+K_z^2}}$

$d{E}_{\mathrm{hy}}=\frac{\mathrm{dQ}}{4\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{L}^2}\cos \mathrm{\&theta;}$

$=\frac{Q}{4\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{R}_{\mathrm{he}}^2}\&CenterDot;\frac{\cos \mathrm{\&beta;}-K_y}{2\mathrm{\&pi;}{(1-2K_y\cos \mathrm{\&beta;}+K_y^2+K_z^2)}^{1.5}}\mathrm{d\&beta;}$

$E_{\mathrm{hy}}=\frac{Q}{4\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{R}_{\mathrm{he}}^2}\underset{0}{\overset{\mathrm{\&pi;}}{\&Integral;}}\frac{\cos \mathrm{\&beta;}-K_y}{\mathrm{\&pi;}{(1-2K_y\cos \mathrm{\&beta;}+K_y^2+K_z^2)}^{1.5}}\mathrm{d\&beta;}---\left(1.15\right)$

In like manner:

$E_{\mathrm{hz}}=\frac{Q}{4\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{R}_{\mathrm{he}}^2}\underset{0}{\overset{\mathrm{\&pi;}}{\&Integral;}}\frac{K_z}{\mathrm{\&pi;}{(1-2K_y\cos \mathrm{\&beta;}+K_y^2+K_z^2)}^{1.5}}\mathrm{d\&beta;}---\left(1.16\right)$

In like manner, energy of position should be expressed as:

$V_{\mathrm{hz}}=\frac{Q}{4\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{R}_{\mathrm{he}}}\underset{0}{\overset{\mathrm{\&pi;}}{\&Integral;}}\frac{1}{\mathrm{\&pi;}{(1-2K_y\cos \mathrm{\&beta;}+K_y^2+K_z^2)}^{0.5}}\mathrm{d\&beta;}---\left(1.17\right)$

E _HyIntegral coefficient $\underset{0}{\overset{\mathrm{\&pi;}}{\&Integral;}}\frac{\cos \mathrm{\&beta;}-K_y}{\mathrm{\&pi;}{(1-2K_y\cos \mathrm{\&beta;}+K_y^2+K_z^2)}^{1.5}}\mathrm{d\&beta;}$ Result of calculation table table 2

E _HzIntegral coefficient $\underset{0}{\overset{\mathrm{\&pi;}}{\&Integral;}}\frac{K_z}{\mathrm{\&pi;}{(1-2K_y\cos \mathrm{\&beta;}+K_y^2+K_z^2)}^{1.5}}\mathrm{d\&beta;}$ Result of calculation table table 3

Electromotive force V _HeIntegral coefficient $\underset{0}{\overset{\mathrm{\&pi;}}{\&Integral;}}\frac{1}{\mathrm{\&pi;}{(1-2K_y\cos \mathrm{\&beta;}+K_y^2+K_z^2)}^{0.5}}\mathrm{d\&beta;}$ Result of calculation table table 4

The variation tendency that electric field strength from above-mentioned along Y, 2 directions of Z axle is calculated the result is as can be seen: homocharge in the axially inboard certain limit of circular conductor, to the Z-direction motion, the negative value scope that is marked as the boldface type data of table 2.In electronic components such as existing electron gun, ion beam, often adopt the static focusing effect of this special bit shape.So according to above-mentioned primary Calculation result, we provide the axial inboard electric force lines distribution of conductor of one group of equal and opposite in direction coaxial circles endless belt equivalent positive charge earlier, as shown in figure 11.

2. wire zero electric field of the thin cylindric positively charged conductor combination of one group of circular positively charged conductor and 2 forms principle

In like manner, wire zero electric field of the thin cylindric positively charged conductor combination of one group of circular positively charged conductor and 2 forms principle and sees Figure 12.

3. wire zero electric field of the thin cylindric positively charged conductor combination of one group of circular positively charged conductor and 3 forms principle

If the radius of every charged thin cylindrical conductor all is R ₀, the electric charge line density all is δ _Ce(down together).3 parallel composition equilateral triangles of energized conductor are seen Figure 13.Then at AA Symmetrical plane on, the electric field strength of vertical direction is:

$E_{\mathrm{ce}}=\frac{{\mathrm{\&delta;}}_{\mathrm{ce}}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0}(\frac{2\sin \mathrm{\&alpha;}\cos \mathrm{\&alpha;}}{R_{\mathrm{ce}0}}-\frac{1}{\sqrt{3}{R}_{\mathrm{ce}0}-{\mathrm{<figure-callout\; id="0"\; label="R\; ce"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">R</figure-callout>}}_{\mathrm{ce}}\mathrm{tg\&alpha;}})---\left(1.18\right)$

$=\frac{{\mathrm{\&delta;}}_{\mathrm{ce}}}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{R}_{\mathrm{ce}0}}(\sin 2\mathrm{\&alpha;}-\frac{1}{\sqrt{3}-\mathrm{tg\&alpha;}})$

If order in the following formula $\sin 2\mathrm{\&alpha;}-\frac{1}{\sqrt{3}-\mathrm{tg\&alpha;}}=0,$ α=30 ° then.Explanation is at the center P point of equilateral triangle, the vector of total electric field intensity and be 0.Along AA Electric field strength coefficient on the symmetrical plane (in the bracket) result of calculation sees Table 5.By table 5 as seen, homocharge is unsettled at the P point, along AA On the symmetrical plane, all repelled to the A direction.By the angular bisector of equilateral triangle and the symmetry analysis decidable of Gauss theorem: when the conductor of two coaxial circles endless belt jack per line equivalent positive charges is parallel equilateral triangle, regular hexagon combination with the thin cylindrical conductor of Duo Gen, the wire that forms on the vertical axis cross section zero electric field boundling distribution characteristics will be as shown in figure 14.

Along AA Electric field strength coefficient on the symmetrical plane $(\sin 2\mathrm{\&alpha;}-\frac{1}{\sqrt{3}-\mathrm{tg\&alpha;}})$ Result of calculation table table 5

The α value (°)	0	5	10	15	20	25	30
								() coefficient	-0.5774	-0.4344	-0.3008	-0.1830	-0.0882	-0.0240	0.00
The α value (°)	35	40	45	50	55	60
								() coefficient	-0.0294	-0.1351	-0.3660	-0.8660	-2.3508	-∞

When we made up the conductor of the conductor of 4 thin cylindric band equivalent positive charges and two coaxial circles endless belt equivalent positive charges by Figure 15 mode, on the cross section of axis, its wire that is combined to form zero electric field just as shown in figure 16.

When we were the conductor of same group of coaxial circles endless belt of numerous thin cylindrical conductor jack per line equivalent positive charge parallel square combination, the wire that forms on the vertical axis cross section zero electric field just presented boundling cluster shown in Figure 180 and distributes.

Require emphasis and additional be: Figure 15,16,17 combined electric fields that show are the planar equipotential surface of quadrangular of the outer point of indent, are under the extruding situation of positive electricity field force around, the equipotential surface that positively charged ion can temporarily exist.Especially concentrate on AA ¹, BB ¹, CC ¹, DD ¹Article four, on the cusped edge linea angulata, the energy of position on the knuckle line extended line is to lean on the kinetic energy that nucleon or ion knock into the back at a high speed to transmit and keep.

From Figure 15,16,17 by the shape of one group of annulus of uniform charged and 4 inner equipotential surfaces of conductor combined electric field as can be seen: as key of the present invention, the equipotential surface indent evagination of about beam ion or nucleon line is the cusped edge horn shape.Make the electric charge in the electrostatic field cause mutual electrostatic repulsion forces because of self internal electric field, inevitable all be extruded separately respectively is the arris edge place at conductive surface.And no matter be electronics, ion or atomic nucleus, all can only be that one deck is stringing, the thickness of this charge layer can only be the thickness of electronics, ion or nuclear entity diameter.Surface of conductors remains equipotential volume, and the density distribution of electric charge is directly relevant with the curvature of conductive surface, so AA ¹, BB ¹, CC ¹, DD ¹Article four, the clean surplus positive charge at the most advanced and sophisticated crest line place on the cusped edge linea angulata will be along AA ¹, BB ¹, CC ¹, DD ¹Respectively be a wire and concentrate distribution.On the equipotential surface of other recess, there is not clean residual electricity lotus.If add the high-intensity magnetic field of parallel tines crest line again, will inevitably under strong magnetic line of force magnetization, be together in series, along four wire, zero electric field high concentration by ion or atomic nucleus self magnetic moment.Simultaneously, if the magnetization is enough big, also there is the attraction between sizable opposite pole between the head-on collision atomic nucleus.We are desirable just for this.

Four, parallel segment adds the high-intensity magnetic field magnetization the directed binding effect estimation for the treatment of fusion light atom nuclear is set

When the light atom nuclear D nucleon beam for the treatment of fusion, when being sprayed in the cold fusion reaction chamber that has wire zero electric field as shown in Figure 9, as long as adjacent light atom nuclear separation is much larger than nuclear radius r ₀, (Δ L＞＞r ₀), the light atom nuclear that electrostatic field force just is easy to treat fusion all constrains on this line segment.Under the directed magnetization of the high-intensity magnetic field of extraneous parallel segment, the whole natural magnetic moments of fusion light atom nuclear for the treatment of on the whole piece line segment will be to align to magnetize and gang up into a long electrical wave solenoid as shown in figure 19.This arrangement plays a crucial role to the accurate positioning and guiding of nuclear fusion.By electrodynamic electric current solenoidal magnetization formula, although the equivalent redius of the gap ratio nuclear moments of each current element much bigger (Δ L＞＞r ₀), but the total magnetic flux of passing whole all current element of solenoid does not reduce, ${\mathrm{\&Phi;}}_B=\&Integral;\&Integral;{\stackrel{\&RightArrow;}{B}}_0\&CenterDot;d\stackrel{\&RightArrow;}{s}=B_0\mathrm{\&pi;}{\stackrel{\&OverBar;}{r}}_0^2=B_x\mathrm{\&pi;}{\stackrel{\&OverBar;}{R}}_x^2,$ No matter be in the current element inboard or the outside, all be constant.The magnetic induction density B at solenoid two ends ₀For:

${\mathrm{<figure-callout\; id="0"\; label="B"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">B</figure-callout>}}_0=\frac{{\mathrm{\&mu;}}_{0}n{I}_0}{2(n-1)\mathrm{\&Delta;L}}\&ap;\frac{{\mathrm{\&mu;}}_0{I}_0}{2\mathrm{\&Delta;L}}---\left(1.19\right)$

By the Gauss theorem in magnetic field, as shown in figure 19 the second left current element in the solenoid end is the center with this current element, and the magnetic line of force is hemisphere face shape and outwards disperses magnetic flux density left

But the vector approximate representation be:

${\stackrel{\&RightArrow;}{B}}_x=B_0\frac{{\stackrel{\&OverBar;}{r}}_0^2}{R_x^3}{\stackrel{\&RightArrow;}{R}}_x---(1.20)$

In the centre of line segment zero electric field, when the spacing of two D nucleons from Δ L → r ₀Head-on head-on collision before, as shown in figure 20.Make Δ L＞＞r ₀, by Coulomb's law and (1.19), (1.20) formula, the interactional electricity of its parallel D nucleon string direction, magnetic field potential energy U _e, U _bCan be expressed as:

$U_e={\&Integral;}_{{\stackrel{\&OverBar;}{r}}_0}^{\mathrm{\&Delta;L}}\frac{e^2}{4\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0\mathrm{\&Delta;}{L}^2}d\left(\mathrm{\&Delta;L}\right)=\frac{e^2}{4\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{\stackrel{\&OverBar;}{r}}_0}---\left(1.21\right)$

$U_b=-{\&Integral;}_{{\stackrel{\&OverBar;}{r}}_0}^{\mathrm{\&Delta;L}}2\mathrm{\&pi;}{\stackrel{\&OverBar;}{r}}_0{\stackrel{\&RightArrow;}{I}}_0\&times;{\stackrel{\&RightArrow;}{B}}_x\mathrm{tg\&alpha;d}\left(\mathrm{\&Delta;L}\right)=-{\&Integral;}_{{\stackrel{\&OverBar;}{r}}_0}^{\mathrm{\&Delta;L}}\mathrm{ec}\frac{{\mathrm{\&mu;}}_0{I}_0}{2\mathrm{\&Delta;L}}{\left(\frac{{\stackrel{\&OverBar;}{r}}_0}{\mathrm{\&Delta;L}}\right)}^{3}d\left(\mathrm{\&Delta;L}\right)=-{\&Integral;}_{{\stackrel{\&OverBar;}{r}}_0}^{\mathrm{\&Delta;L}}\frac{e^2{\stackrel{\&OverBar;}{r}}_0^2}{4\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0\mathrm{\&Delta;}{L}^4}d\left(\mathrm{\&Delta;L}\right)$

$=-\frac{e^2}{12\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{\stackrel{\&OverBar;}{r}}_0}---\left(1.22\right)$

Top derivation calculation proof: the energy of electrostatic field repulsive force and repulsion is much larger than the attraction in current element magnetic field and the energy of attraction.Minimum kinetic energy for providing two D nucleons head-on to clash nuclear fusion should be provided its gross energy.Because the D nucleon is composed in series by the proton neutron, the effect model of nuclear force is all 10 ^-15M can be used as r ₀Value.The starting voltage of supposing wire zero electric field is 100000 volts, and then the onset potential of electrostatic accelerator can be worth U ₀For:

${\mathrm{<figure-callout\; id="0"\; label="U"\; filenames="A20081008791100251.png"\; state="\{\{state\}\}">U</figure-callout>}}_0\&GreaterEqual;\frac{U_e+U_b}{2}+100000e\&GreaterEqual;\frac{e^2}{12\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{\stackrel{\&OverBar;}{r}}_0}+100000e\&GreaterEqual;579988\left(\mathrm{ev}\right)---\left(1.23\right)$

Five, the D atomic nucleus forms the inertial guidance effect of HHT higher high tensile rotation gyro with the spin of dipped beam speed

Suppose that a string D atomic nucleus moves along the rectilinear orbit of a wire zero electric field, under the double constraints effect of the zero electric field force of linearity and parallel strong external magnetic field power, their nuclear spin vector will overlap on same straight line, and parallel with strong external magnetic field.Any one atomic nucleus in the middle of the whole string D nucleon all is subjected to the repulsive interaction of both sides atomic nucleus electrostatic field force, and along the electrostatic field interaction force equal and opposite in direction of parallel lines direction, direction is opposite, cancels each other.Because the unit positive charge that middle daughter nucleus core has is the clean surplus positive charge of D nucleon, be again to make circular motion with identical dipped beam speed velocity of wave motion.Along with the fluctuation and the additional movement of middle daughter nucleus core, they are inevitable with mode collective motion shown in Figure 20, and its overall energy of position just can be reduced to minimum.By Coulomb's law, the electrostatic field force F of its vertical D atomic nucleus string direction _{E ⊥}For:

$F_{e\&perp;}=\underset{i=1}{\overset{n}{\mathrm{\&Sigma;}}}\frac{4{\stackrel{\&OverBar;}{r}}_0{e}^2}{4\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0{[{\left(2{\stackrel{\&OverBar;}{r}}_0\right)}^2+{(2n-1)}^2\mathrm{\&Delta;}{L}^2]}^{\frac{3}{2}}}$

$=\underset{i=1}{\overset{n}{\mathrm{\&Sigma;}}}\frac{e^2{\stackrel{\&OverBar;}{r}}_0}{4\sqrt{2}\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0\mathrm{\&Delta;}{L}^3{[{\left(\frac{{\stackrel{\&OverBar;}{r}}_0}{\mathrm{\&Delta;L}}\right)}^2+{(n-\frac{1}{2})}^2]}^{\frac{3}{2}}}---\left(1.24\right)$

In like manner, by Ampere's law, (1.19～20) formula, above-mentionedly make the unit positive charge of circular motion, the action of a magnetic field power F with the light velocity _{B ⊥}Should be:

$F_{b\&perp;}=2\mathrm{ec}\frac{{\mathrm{\&mu;}}_0{I}_0{\stackrel{\&OverBar;}{r}}_0^2}{2\mathrm{\&Delta;}{L}^3}=\frac{e^2{\stackrel{\&OverBar;}{r}}_0}{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0\mathrm{\&Delta;}{L}^3}---\left(1.25\right)$

Make Δ L in (1.24) formula＞＞r ₀, to simplify the analysis, n gets 2, F _{E ⊥}Be reduced to:

$F_{e\&perp;}=\frac{8.2963e^2{\stackrel{\&OverBar;}{r}}_0}{4\sqrt{2}\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0\mathrm{\&Delta;}{L}^3}---\left(1.26\right)$

Make Δ L → r in (1.24) formula ₀, F _{E ⊥}Can be reduced to again:

$F_{e\&perp;}=\frac{0.8862e^2{\stackrel{\&OverBar;}{r}}_0}{4\sqrt{2}\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0\mathrm{\&Delta;}{L}^3}---\left(1.27\right)$

No matter Δ L＞＞r ₀, or Δ L → r ₀, the coulomb repulsion power F of this vertical direction _{E ⊥}With magnetic field force F _{B ⊥}Can both stop two head-on head-on collisions of string D atomic nucleus easily.In order to have more convincingness, to the F of electromagnetic field _{E ⊥}And F _{B ⊥}Power, the author gets its maximum.If can not effectively overcome F _{E ⊥}And F _{B ⊥}The deflection effect of electromagnetic force before nucleon head-on collision, then cold checking hit fusion and all do not known where to begin.

Verified in front the author's the monograph, all elementary particle along the straight line ejection-type all has the quantization stationary state aggregate motion track of fluctuation+spin+precession.By parity of reasoning, all atomic nucleus, and when it moved in straight line ejection-type mode, its direction of motion is this nuclear spin momentum direction vector or opposite direction just.Cold checking in above-mentioned inertial guidance hit in the fusion modelling, before the D nucleon has just ejected in the accelerator or sprayed, just should determine that with the constraint of high-intensity magnetic field power each D nucleon string spin vector direction be to get positive direction earlier, still in the other direction.

Make that nuclear spin momentum is J _m, intranuclear elementary particle adds up to N, and the moment of momentum of each elementary particle all is m _iv _θR _θ, by rational mechanics and (1.2-1), (1.2-2) formula gets:

$J_m=\underset{i=1}{\overset{N}{\mathrm{\&Sigma;}}}{m}_i{v}_{\mathrm{\&theta;i}}{R}_{\mathrm{\&theta;i}}=\underset{i=1}{\overset{N}{\mathrm{\&Sigma;}}}\frac{h}{2\mathrm{\&pi;}}=N\frac{h}{2\mathrm{\&pi;}}---\left(1.28\right)$

Because all D nucleons that move in the nuclear fusion reaction chamber, the velocity of wave motion of proton wherein, middle daughter nucleus core is all identical, so, if D nucleon string is at each nucleon mutual electromagnetic field force F _{E ⊥}And F _{B ⊥}Effect causes the deflection rotation of each D nucleonic momentum moment vector, the angular velocity omega of this deflection rotation so down ₂Should equate.And to keep this angular velocity omega ₂The gyroscopic inertia moment F of deflection rotation _{M ⊥}* Δ L is got by (1.28) formula:

$F_{m\&perp;}=\frac{J_m{\mathrm{\&omega;}}_2}{\mathrm{\&Delta;L}}=\frac{\mathrm{Nhc}}{2\mathrm{\&pi;}{\stackrel{\&OverBar;}{r}}_0\mathrm{\&Delta;L}}---\left(1.29\right)$

Because of F _{E ⊥}＞F _{B ⊥}, as long as we compare F _{M ⊥}And F _{E ⊥}+ F _{B ⊥}Ratio just can be judged the possibility of inertial guidance.As long as F _{M ⊥}＞F _{E ⊥}+ F _{B ⊥}, just illustrate that the gyroscopic inertia of D nucleon is guided restoring force F _{M ⊥}Can overcome electromagnetic field angular force F _{E ⊥}+ F _{B ⊥}Get by (1.25), (1.26) formula:

$\frac{F_{m\&perp;}}{F_{e\&perp;}+F_{b\&perp;}}=\frac{\mathrm{Nhc}}{2\mathrm{\&pi;}{\stackrel{\&OverBar;}{r}}_0\mathrm{\&Delta;L}}\&CenterDot;\frac{2\mathrm{\&pi;}{\mathrm{\&epsiv;}}_0\mathrm{\&Delta;}{L}^3}{3.9332e^2{\stackrel{\&OverBar;}{r}}_0}=\frac{N}{2\&times;3.9332}\left(\frac{2\mathrm{hc}{\mathrm{\&epsiv;}}_0}{e^2}\right){\left(\frac{\mathrm{\&Delta;L}}{{\stackrel{\&OverBar;}{r}}_0}\right)}^2---\left(1.30\right)$

In the bracket of following formula front is fine-structure constant, and its value is 137.0359907.N=4 illustrates F _{M ⊥}＞＞F _{E ⊥}+ F _{B ⊥}Value, judge the gyroscopic inertia guidance characteristic of self the superpower rotation utilize two D nucleon strings thus, realize that nuclear force constraint inertial guidance head-on collision cold fusion is not only feasible, and almost be so far for this reason the whole mankind can develop the unique channel of nuclear fusion energy!

Description of drawings

Fig. 1. be the inner fluctuation of static elementary particle, the vertical bielliptic(al) orbital motion of spin quantization stationary state schematic diagram

Fig. 2. be the duality principle feature schematic diagram that elementary particle forms during along fluctuation, spin, precession orbital motion

Fig. 3. be the inner p of proton, neutron ^±Fluctuation, the perspective view of spin motion track on XOY plane of meson, nuclear core

Fig. 4. be nuclear internal structure of proton, neutron, deuterium and tritium and magnetic moment composition principle schematic diagram

Fig. 5. be electrostatic field force constraint light atom nuclear capability estimation principle schematic

Fig. 6. be the surface charge original face density formation schematic diagram about equally of circular, tabular and thin cylindrical conductor

Fig. 7. be the conductor electric force lines distribution schematic diagram of two thin cylindric band equivalent positive charges of the endless that be arranged in parallel

Fig. 8. wire zero electric field that is the positively charged conductor of tabular and 2 thin cylindric positively charged conductors forms principle schematic

Fig. 9. be the combined electrical line of force of the positively charged conductor of tabular and one group of thin cylindric positively charged conductor and the wire zero principle of electric field schematic diagram of formation

Figure 10. be electric field strength E inboard in the round conductor ring _Hz, E _HyThe change calculations principle schematic

Figure 11. be the axial inboard electric force lines distribution schematic diagram of conductor of one group of equal and opposite in direction coaxial circles endless belt equivalent positive charge

Figure 12. be the thin cylindric wire zero principle of electric field schematic diagrames that on axial cross section, form with conductors two coaxial circles endless belt equivalent positive charges of two parallel endless

Figure 13. be the electric field strength calculating principle schematic that 3 thin cylindric energized conductors of endless are the equilateral triangle combination

Figure 14. the conductor that is two coaxial circles endless belt jack per line equivalent positive charges is parallel equilateral triangle with the thin cylindrical conductor of Duo Gen, regular hexagon is combined in the wire zero electric field boundling distribution schematic diagram that forms on the vertical axis cross section

Figure 15. be two annulus of uniform charged and the electric field schematic diagram of 4 conductor combinations

Figure 16. be the shape of the inner equipotential surface of combined electric field and the cross sectional representation that the indent evagination is cusped edge horn shape wire zero electric field

Figure 17. be planar equipotential surface of the outer spur quadrangular of combined electric field indent and nucleon ion by internal electric field form along the crest line distribution schematic diagram

Figure 18. be that conductor and the thin cylindrical conductor of Duo Gen of one group of coaxial circles endless belt jack per line equivalent positive charge is combined in wire zero electric field that forms on the vertical axis cross section with parallel square and is cluster boundling distribution schematic diagram

Figure 19. be to be under the magnetization of strong external magnetic field along the light atom nuclear magnetic moment that a certain line segment distributes to align schematic diagram

Figure 20. be electricity, the magnetic field interaction force principle schematic of vertical direction between two current element

Figure 21. be the operation principle schematic diagram of nuclear force constrain inertial guidance cold nucleus fusion reaction chamber

Figure 22. be the ion speed-governing dc reducing transformer operation principle schematic diagram of nuclear force constraint inertial guidance

Figure 23. be the ion speed-governing dc booster operation principle schematic diagram of nuclear force constraint inertial guidance

Figure 24. be " nuclear force constrain inertial guidance cold nucleus fusion stack and ion speed-governing dc transformer " Project design

General technical approach combinatorial principle schematic diagram

Figure: 1. Protons and spin magnetic moment vector 2 neutrons and spin magnetic moment vector 3. Deuterium nuclei internal structure and magnetic moments of synthesis principle 4. Tritium nuclei internal structure and magnetic moments of synthesis principle 5. Rings each flat plate-shaped conductors of the conductor 6 and the flat annular separation between the conductors of the dielectric 7. thin cylindrical-shaped conductor 8 on both sides of a dielectric separator. thin two ends of the cylindrical conductor of the conductor 9 and plate-shaped live conductors corresponding dielectric 10. nuclear restraint inertial guidance cold fusion reaction chamber constraints guided fusion channel 11.D colliding nuclei collision speed and direction of movement 12. fusion to form helium nuclei injection speed and direction of movement 13. ejected from the fusion reaction chamber high-energy helium nuclei speed and direction of motion 14. governor buck helium nuclei beam 15 after being mixed speed helium nuclei 16. nuclear restraint ion inertial guidance governor channel 17. protons or helium, lithium-ion beam and the direction of 18 high-speed movement. participate mixing speed, massive mercury ions 19 are mixed after the governor of protons or helium, lithium ion and mercury ion beam 20. fusion after the governor Buck transformation can output high voltage DC 21 Output power high-voltage capacitors 22. late stage ion governor buck 23. energy helium nuclei 24. supplied electrostatic linear ion accelerator power high-voltage capacitors 25. primary ion speed dc drop pressure 26. nuclear restraint inertial guidance cold fusion reaction chamber 27. electrostatic ion linear accelerator 28. Built-in start ion speed dc power supply high power booster...

Embodiment

Analyzed more all sidedly above and the summary of the invention of " nuclear force constrain inertial guidance cold nucleus fusion stack and ion speed-governing dc transformer " has been proved in analog computation.For brief overview the specific embodiment of the present invention, we quicken the technology combination of paths sketch of booster cavity and cold fusion reactor with Figure 21,22,23,24 reduced representation cold fusion reaction chambers, ion speed-governing pressure letdown chamber, ion.

Below, we give the concise and to the point demonstration of replenishing to the mechanical efficiency of the ion beam speed-governing dc transformer of nuclear force constraint inertial guidance.

One, the physical model and the theoretical foundation of " nuclear force constraint inertial guidance ion speed-governing dc transformer " Project design

The quality that is provided with two kinds of ions is respectively: m ₁, m ₂, with clean electric weight be: q ₁, q ₂, the ion beam flow of per second is N ₁, N ₂Order:

K _m＝m ₁/m ₂ K _q＝q ₁/q ₂

A. to ion retardation step-down campaign

If m ₁The equivalent voltage of ion original kinetic energy is V ₁, movement velocity is v ₁, electric current is I ₁=q ₁N ₁m ₂The toggle speed of speed governing ion can be ignored.Mix the speed governing section in initial sum, see Figure 22, by the gross energy law of conservation:

$\left\{\begin{array}{cc}{V}_1=\frac{1}{2q_1}{m}_1{v}_1^2& (1.31-1)\\ \frac{1}{2}{m}_1{N}_1{v}_1^2=\frac{1}{2}(m_1{N}_1+m_2{N}_2)v_2^2& (1.31-2)\end{array}\right.$

At the voltage that mixes speed governing section end is V ₂, (also can be set at a certain reference voltage).This moment, two kinds of ions all had identical movement velocity v ₂, making a concerted effort of inner each ionic interaction power is 0, each ion rectilinear motion that all remains a constant speed.When ion enters the orbital segment of contrary pressure retarded motion, (this orbital segment is made of the upside-down mounting of electrostatic ion linear accelerator), because the repulsive interaction of electric field force, quality ion retardation little, that have net charge amount people is fast; The ion retardation that big, the clean electric weight of quality is little is slow.The result of speed governing campaign in by the single channel track of nuclear force constraint inertial guidance comprehensive function is with the exchange process that is energy again.If last two kinds of ions are all with v ₃→ 0 speed is all clamp-oned the voltage chamber of spherical shell shape, because under vacuum state, energy loss does not nearly all take place in the centre, needn't consider electromagenetic wave radiation yet, gets from the gross energy law of conservation:

I ₁V ₁=I ₃V ₃Because: I ₃=q ₁N ₁+ q ₂N ₂So:

$\left\{\begin{array}{cc}{V}_3=\frac{I_1{V}_1}{I_3}=\frac{N_1{q}_1}{N_1{q}_1+N_2{q}_2}{V}_1=\frac{V_1}{1+\frac{N_2}{N_1{K}_q}}& (1.32-1)\\ {\left(\frac{v_1}{v_2}\right)}^2=\frac{m_1{N}_1+m_2{N}_2}{m_1{N}_1}=1+\frac{N_2}{N_1{K}_m}& (1.32-2)\end{array}\right.$

If K _m=K _q=1, promptly all be ion of the same race, then:

$\left\{\begin{array}{cc}{V}_3=\frac{V_1}{1+\frac{N_2}{N_1}}& (1.33-1)\\ {\left(\frac{v_1}{v_2}\right)}^2=1+\frac{N_2}{N_1}& (1.33-2)\end{array}\right.$

To ion of the same race, when entering,, just passable as long as common electromagnetic field focuses on pipe because acceleration is all identical against pressure retarded motion orbital segment.

If m ₁For ₉ ¹⁹F ^-Ion, m ₂Be electronics e ^-, because K _m=34630.Suppose that the voltage step-down amplitude reaches 10000 times, then:

${\left(\frac{v_1}{v_2}\right)}^2=1+\frac{N_2}{N_1{K}_m}\&ap;1+\frac{1}{3.463}=1.289---\left(1.34\right)$

Above-mentioned analysis result explanation ₉ ¹⁹F ^-The velocity variations in ion speed-governing stage is very little.Also continue electronics is played crucial progradation in the contrary pressure stage.

B. if quicken the supercharging campaign

As long as the direction of above-mentioned analytical calculation is turned around.But should get m ₁＜＜m ₂, to electronics and single ₉ ¹⁹F ^-Ion, probability at random is too big, for the whole piece pipeline, then can adjust the mass motion speed of ion beam mixing automatically, sees Figure 23.Only be the contrary pressure stage with the difference of decompression speed, the light ion that quality differs greatly, atomic nucleus or electronics must reflux cycle use.

Because all in 550～750 ℃ of scopes, mercury element is 357 ℃ to the vapourizing temperature of lithium, sodium, potassium, rubidium, caesium, francium element.At the vacuum ionic state, possible vapourizing temperature can reduce greatly.Cation adopts the combination of proton, lithium ion and mercury ion, also can consider with hydrogen, helium ion and mercury ion combination.If possible, heavy ion also can consider to adopt some gaseous compound.

Two, " nucleon constraint inertial guidance cold fusion heap and ion speed-governing dc transformer " general technical approach

Figure 24 is seen in " nucleon constraint inertial guidance cold fusion heap and ion speed-governing dc transformer " project overall study scheme, technological approaches combination.

As for other atomic nucleus or ion generator, ion or nuclear linear accelerator, the automatic balance control system of atomic nucleus supply of fuel and energy output ... Deng the corollary apparatus system, all can be according to this body items purpose research and design scheme and operational factor, on the basis of technology, equipment and the fabrication process condition of existing respective item, carry out preferred and improve.

Claims (10)

1. nuclear force constrain inertial guidance cold nucleus fusion stack and ion speed-governing dc transformer invention, it is characterized in that: under normal temperature condition, the electromagnetic field of space particular combinations is set,, earlier two strings is treated that the atomic nucleus of fusion constrains in the same line section according to intrinsic magnetic moment and the internal electric field of light atom nuclear; Utilize the intrinsic spin momentum moment vector of atomic nucleus to form the HHT higher high tensile rotation gyroscopic inertia guidance characteristic of dipped beam speed spin again, overcome a coulomb surging deflection effect of building, the nuclear fusion of realizing directly clashing; The nuclear force constraint inertial guidance system of applications similar, ion beam mixing speed governing to friction speed and energy, the ion speed-governing dc transformer that is developed into, be the important corollary equipment that cold fusion heap, atomic propulsion nuclear engine and such nuclear power station start nuclear fusion and power delivery system, so merge patent right of application.

2. shown in claim 1, the specific electromagnetic field in space is set, is provided with in the electrostatic field background that forms by the particular space combination by several or the difform energized conductor of array exactly, make its inner technical method that produces one group of wire, zero electric field; By each energized conductor all being separated into N sub-conductor, all separate between each sub-conductor with dielectric.The surface density of at first supposing the original net charge of a certain whole conductive surface is a certain constant, to surrounding space generation power line (electric field) symmetrically, examine the intrinsic internal electric field of string according to light atom, and invent desired wire in groups zero electric field with the synthetic jointly this patent of other energized conductor; And then consider the auxiliary voltage that each energized conductor and sub-conductor form because of the electrostatic field effect of interacting, fill each conductor and sub-conductor with corresponding separately total voltage value respectively according to the auxiliary voltage value at last.

3. in the cold fusion reaction chamber shown in claim 1,2, can be by adjusting the flow that sprays D nucleon string, change the charging voltage of sub-conductor in each conductor, just can adjust the D nucleon for the treatment of fusion get lines crossed density and internal electric field significantly, thereby reach the purpose of adjusting reactor capability significantly; The voltage sensor of the helium atomic nucleus jet both sides that can also be directly form by fusion, directly link to each other at the porch of wire zero electric field shunting deviating electrode with D nucleon string line, avoid two string nucleons to take their own roads, the head-on collision fusion of two string nucleons of move toward one another in every wire zero electric field can both be carried out smoothly.

4. the design of zero electric field of the wire shown in claim 2 can have multiple mode, removes the combination of the tabular energized conductor provided herein and the thin cylindric energized conductor of one group of 2～N parallel distribution; Outside one group of circular energized conductor and one group thin columned energized conductor make up; It is also conceivable that the thin cylindric energized conductor that one group of parallel distribution all is set between per two flat boards of one group of charged tabular conductor, form the wire zero electric field group of boundling cluster.

5. the constraint of the nuclear force shown in claim 1 inertial guidance ion speed-governing dc transformer is because the atomic nucleus injection problem vertically after not having fusion, but all along the bearing of trend single way jet of speed governing, so carry out the parallel set constriction group design of cluster wire zero electric field in groups easilier.As coaxial one group of circular energized conductor and 3～N thin cylindric energized conductor combination that be arranged in parallel, a plurality of thin cylindric energized conductors can distribute along the summit of positive triangle or positive 4 limit shapes, can also be the cellular combination of array or multi-turn.Can make wire zero electric field boundling in groups be the geometric progression surge like this.

6. nucleon beam shown in claim 1 or ion beam are before injection enters wire zero electric field, all should be earlier determine spin momentum direction or in the other direction with directional magnetic field, and all must be with the electric field of circular ring electrode plate and magnetic focusing lens to the focusing that comprehensively superposes of nucleon beam or ion beam.

Shown in claim 1 in the design of nucleon beam, ion beam speed-governing dc pressure reducer, can carry out the decompression speed of continuous multi-stage to nucleon beam or ion beam.Promptly at the prionotron end of each grade, the end of jet, all continue big flow ground and introduce low speed nucleon beam or ion beam,, change into direct current with certain voltage until at last the whole big flow nucleon beam or the ion beam of final stage low speed all being introduced in the spherical shell shape metal capacitor.Can omit electrostatic nucleon, the ion linear accelerator of a plurality of upside-down mountings like this.

8. the design to the ion speed-governing dc booster shown in claim 1 can should be adopted the mass discrepancy great disparity, easy generation and the more stable ion of exciting at a lower temperature, as electronics and F according to the multiple of supercharging as far as possible ^-, Cl ^-Anion, proton and Na ⁺, K ⁺, Hg ⁺⁺Make up in cation.

9. the external magnetic field design of zero direction of an electric field of the parallel wire shown in claim 1, the electric current solenoid that should as far as possible consider to adopt the non-conductive material segmentation of inner core high magnetic permeability to fill all leaves the access opening that sprays for nucleon beam or ion beam in the electromagnet part of wire zero initial end of electric field and outlet.

10. the acceleration of the nucleon beam of the present invention shown in claim 1, ion beam, head-on collision fusion, mixing speed governing campaign transform whole working spaces of exporting until electric energy, all are to implement in closed container that vacuumizes or pipeline.So whole system inside also must be equipped with a cover vaccum-pumping equipment, so that with the helium atomic nucleus that forms behind the nuclear fusion, finally finish the helium gas that is transformed into preciousness after electric energy transforms through speed governing, constantly extract out and collect from the service area.

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