CN101277177B - Transmission method for determining transmission module size and modulation system by multiplexing scheduling and non-scheduling - Google Patents

Transmission method for determining transmission module size and modulation system by multiplexing scheduling and non-scheduling Download PDF

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CN101277177B
CN101277177B CN 200710087586 CN200710087586A CN101277177B CN 101277177 B CN101277177 B CN 101277177B CN 200710087586 CN200710087586 CN 200710087586 CN 200710087586 A CN200710087586 A CN 200710087586A CN 101277177 B CN101277177 B CN 101277177B
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tbs
scheduled
scheduling
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resource
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CN101277177A (en
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刘虎
李轶
殷玮玮
费佩燕
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中兴通讯股份有限公司
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Abstract

The invention discloses a transmission method for confirming size and modulation method of a transmission module by scheduling un-scheduling multiplexing. The method unifies all possible resource of scheduling and un-scheduling by using basic resource unit RU, and grades to N resource grades, I TBS values are set in each resource grade, and N*1 resource grade tables are established. UE calculatesfactual distributed scheduling and un-scheduling resource amount when multiplexing, and selects the transmission module size, namely TBS value. UE transmits index corresponding selected TBS value to a node B, namely NodeB, then, NodeB calculates factual distributed scheduling and un-scheduling resource amount, confirms modulation method according with calculated resource amount and received TBS and processes demodulation. The method provided by the invention can avoid un-scheduling physical resource waste, and does not change prior signaling structure.

Description

调度非调度复用确定传输模块大小和调制方式的传输方法 Scheduling non-scheduled transmission method of multiplexing transmission module determines a modulation scheme and size

技术领域 FIELD

[0001] 本发明涉及无线通讯系统中的高速上行分组接入技术,尤其涉及时分同步码分多址接入系统中,HSUPA (高速上行分组接入)的MAC层调度和非调度复用传输的方法。 [0001] The present invention relates to high speed uplink packet access technology in wireless communication systems, and particularly to time division Synchronous Code Division Multiple Access system, HSUPA (High Speed ​​Uplink Packet Access) in the MAC layer scheduling and non-scheduled multiplexed transmission method.

背景技术 Background technique

[0002] 在第三代移动通信系统中,为了提供更高速率的上行分组业务,提高频谱利用效率,3GPP(3rd Generation Partnership Project)在WCDMA 和TD-CDMA 系统的规范中引入了高速上行分组接入(HSUPA,High Speed Uplink Packet Access)特性,即上行增强特性。 [0002] In the third generation mobile communication system, in order to provide a higher rate of uplink packet traffic, improving spectral efficiency, 3GPP (3rd Generation Partnership Project) is introduced in a high-speed uplink packet access specification WCDMA and TD-CDMA system into (HSUPA, High Speed ​​uplink Packet Access) characteristics, i.e., the uplink enhancements. HSUPA系统又被称为上行增强系统,简称为E-DCH系统。 HSUPA is also known system uplink enhanced system, referred to as E-DCH system. 在TD-CDMA系统中,HSUPA系统物理层引入E-PUCH物理信道,用于传输E-DCH类型的CCTrCH。 In the TD-CDMA system, HSUPA system physical layer into a physical channel E-PUCH, E-DCH transmission for the type of CCTrCH.

[0003] HSUPA中存在两种业务:调度业务和非调度业务。 [0003] There are two operations in HSUPA: scheduling service and non-scheduling service. 调度业务是由节点B(NodeB)来分配码道、时隙和功率资源;而非调度业务是由服务无线网络控制器(SRNC)来分配资源的。 Scheduling service is assigned to code channel, timeslot and power resources by the Node B (NodeB); dispatch services are not allocating resources by a serving radio network controller (SRNC). 非调度资源一般是周期出现的,因此,当分配了非调度资源却没有非调度业务或者非调度业务的数据量非常小时,如果利用多余的非调度资源来传输调度业务,则可以最大程度的避免资源浪费。 Non-scheduled resources generally occur periodically, and therefore, when the non-scheduled resources are allocated but not the non-scheduled traffic or non-scheduled data amount of traffic is very small, if the use of excess non-scheduled resources transmission schedule service, can avoid the maximum waste of resources. 这就是调度和非调度复用的意义所在。 This is the significance of scheduled and non-scheduled reuse.

[0004] 调度和非调度在MAC层的复用是指将调度和非调度业务的数据在MAC层中合并为一个TBS (传输块大小,Transport Block Size)进行传输。 [0004] In the scheduled and non-scheduled MAC layer multiplexing refers to non-scheduled data and scheduled services combined into a TBS (transport block size, Transport Block Size) in the MAC layer for transmission. 在物理层,对这个复用的TBS进行统一的CRC (循环冗余校验)校验和编译码,因此调度和非调度业务的数据混合在一起进行传输,不可分割。 In the physical layer, this multiplexed TBS unified CRC (Cyclic Redundancy Check) checksum and encoding and decoding, therefore non-scheduled traffic scheduling and data transmission are mixed together and inseparable.

[0005] 现有技术中,调度业务和非调度业务分开传输,由于调度和非调度资源使用的SF(扩频因子)可能不同,时隙数不同,从而导致资源的浪费。 [0005] In the prior art, scheduling service and non-scheduling service transmitted separately, since the scheduled and non-scheduled resources used by SF (spreading factor) may be different, different number of slots, resulting in a waste of resources.

发明内容 SUMMARY

[0006] 本发明所要解决的技术问题在于,提供一种高速上行分组接入中实现调度和非调度复用时确定传输模块大小和调制方式的方法,解决时分同步码分多址系统中HSUPA技术中调度和非调度业务在MAC层复用的问题,避免非调度物理资源的浪费。 [0006] The present invention solves the technical problem is to provide a high-speed uplink packet access scheduling and non-scheduling implemented method for determining a transmission block size and a modulation scheme when multiplexing, time division synchronous code division multiple access system to solve the technical HSUPA in the scheduled and non-scheduled traffic problem in the MAC layer multiplexing non-scheduled physical resources to avoid waste.

[0007] 为解决上述问题,本发明提供了一种调度非调度复用确定传输模块大小和调制方式的传输方法,包括如下步骤: [0007] In order to solve the above problems, the present invention provides a scheduled and non-scheduled transmission block size mode transmission method of multiplexing modulation determined, comprising the steps of:

[0008] (1)设置基本资源单位,根据资源单元归一化计算调度和非调度总共可能的码道时隙资源数量C,将C按照归一化等价的方式,分为N个资源等级,N能被80整除; [0008] (1) The basic resource unit is provided, according to the resource calculating unit normalization scheduled and non-scheduled total possible number of code channel resource slot C, C in accordance with the normalized equivalent manner, it is divided into N resource levels , N can be divided by 80;

[0009] (2)计算步骤(1)所述的N个资源等级中每一资源等级内的最大和最小的TBS值, 确定每一等级内具有的I个TBS可选值,在MAC层建立一个NX I的TBS资源表; [0009] (2) calculation step (1) of the N resource levels of the maximum and minimum values ​​within each resource TBS levels to determine the level within each of the I TBS having selectable values, based on the MAC layer NX I of a TBS resource table;

[0010] (3)当调度和非调度业务同时存在且非调度业务数据量小于配置的无线资源所能承载的比特数时,MAC层确定采用非调度传输,将调度和非调度业务传输复用; [0010] (3) when the scheduled and non-scheduled traffic exist traffic data is less than the number of bits of a radio resource configuration and can carry a non-scheduled, the MAC layer determines non-scheduled transmission, scheduling and non-scheduling service transport multiplex ;

[0011] (4)用户设备UE根据所述资源单元分别独立计算实际分配的调度和非调度资源总量,并据此以及功率授权情况从所述TBS资源表中独立选择不同传输方式下对应的TBS值,所述传输方式指调度传输或非调度传输,并根据两种传输方式的TBS值所对应的调制方式是否相同来确定最终的TBS值,以及确定调制方式。 [0011] (4) which are independent of the user equipment UE calculates the actual distribution of scheduled and non-scheduled total amount of resources according to the resource unit, and accordingly the power and authorization independently selected from the TBS resource table corresponding to the different transmission TBS value, the scheduled transmission or transmission mode scheduled transmission means, and to determine the final value in accordance with whether the same TBS TBS values ​​of the two corresponding to the transmission modulation scheme and the modulation mode.

[0012] 进一步地,上述方法还具有以下特点: [0012] Furthermore, the above method also has the following characteristics:

[0013] 进一步包括, [0013] further comprising,

[0014] (5)用户设备UE将所选TBS值对应的索引及调制方式传输给节点B ; [0014] (5) the user equipment UE transmits the selected index and TBS corresponding to the value of the modulation scheme to the Node B;

[0015] (6)节点B计算实际分配的调度和非调度资源总量,并据此和接收到的TBS值对应的索引获得节点B的TBS值,利用接收的调制方式进行解调。 The total amount of non-scheduled and scheduled resources [0015] (6) calculates the actual distribution of the Node B, and accordingly, and TBS corresponding to a value received index value obtained TBS Node B, performs demodulation using the modulation scheme received.

[0016] 进一步地,上述方法还具有以下特点: [0016] Furthermore, the above method also has the following characteristics:

[0017]步骤(1)中: [0017] Step (1):

[0018] 所述资源单位是扩频因子SF = 16的单码道; [0018] The resource unit is a single code spreading factor SF = 16, channel;

[0019] 所述总共可能的码道时隙资源数量C为1至80个资源单元。 [0019] The total possible number of code channel resource slot C is from 1 to 80 resource units.

[0020] 进一步地,上述方法还具有以下特点: [0020] Furthermore, the above method also has the following characteristics:

[0021]步骤(2)中: [0021] Step (2):

[0022] 所述每一资源等级中的最小TBS值是调度信息的比特数23 ; [0022] TBS minimum value of the level of each resource is the number of 23-bit scheduling information;

[0023] 所述每一资源等级中的最大TBS值是对应扩频因子SF = 1、调制方式为16QAM时可能传输的最大比特数,对于第N个资源等级内最大TBS值满足下式: [0023] The maximum TBS value in each resource level corresponding spreading factor SF = 1, the maximum number of bits possible modulation scheme is 16QAM transmission, the maximum TBS value for the N-level resource to satisfy the following formula:

[0024] [0024]

Figure CN101277177BD00061

[0025] 其中,17是UCCH占用的17个符号,24对应的是CRC校验比特的个数,4对应的是Turbo编码并经过打孔遗留下来的尾比特,M为调制方式对应的值,QPSK时,M = 2,16QAM 时,M = 4,Ceil为向上取整数,t为时隙数;ENI为E-UCCH个数。 [0025] where 17 is occupied UCCH 17 symbols, 24 corresponds to the number of CRC check bits, corresponding to 4 and Turbo Coding is left after punching down tail bits, M being a value corresponding to the modulation scheme, when QPSK, M = 2,16QAM, M = 4, Ceil is rounded up, t is the number of slots; ENI is the number of E-UCCH.

[0026] 进一步地,上述方法还具有以下特点: [0026] Furthermore, the above method also has the following characteristics:

[0027] 步骤(2)中设计TBS资源表,包括以下步骤: [0027] Step design TBS resource table (2), comprising the steps of:

[0028] (2-1)将扩频因子SF = 16的单码道确定为基本的资源单位RU ; [0028] (2-1) The single code spreading factor SF = 16 channel determined as a basic resource unit RU;

[0029] (2-2)根据基本资源单位RU,确定调度和非调度可能的总资源数量; [0029] (2-2) The basic resource unit RU, to determine the total number of possible resource scheduling and non-scheduling;

[0030] (2-3)将所有可能资源分为N个资源等级; [0030] (2-3) all possible resources are divided into N resource levels;

[0031] (2-4)在每一资源等级内,确定每一资源等级中的最大TBS值和最小TBS值; [0031] (2-4) in each resource level, determining a maximum TBS value for each resource level and minimum TBS value;

[0032] (2-5)在对数域空间对每一资源等级中的TBS最大值和最小值取对数,于两者之间进行均勻插值,再将插值所得对数值转换为对应的TBS值,确定每一资源等级中具有的I 个TBS值,生成一个NX I的TBS资源表。 [0032] (2-5) in the logarithmic domain to logarithmic space TBS maximum and minimum values ​​of each resource level, uniform interpolation performed in between, and then interpolating the resulting value is converted to the corresponding TBS value determined for each resource having a level of the I TBS value, generating a resource table NX I in TBS.

[0033] 进一步地,上述方法还具有以下特点: [0033] Furthermore, the above method also has the following characteristics:

[0034]步骤(4): [0034] Step (4):

[0035] (4-1)根据所述资源单元,利用以下两个公式分别对实际分配的调度和非调度资源进行归一化,计算后,得到调度资源和非调度资源各自总的资源数目: [0035] (4-1) according to the resource units are assigned to the actual scheduled and non-scheduled resources is normalized by the following two formulas, the calculation, the total number of resource scheduling each resource and non-scheduled resources:

Figure CN101277177BD00062

[0037] 其中,SF= 16,i_s表示第i个调度时隙,上式中应该是i_s = 1,类似地,i_ns表示第i个非调度时隙,i_ns = 1,整个公式表示的是从1叠加到ts—s或者ts_ns,即多个时隙的和,sf_s为调度对应的扩频因子,ts_s为调度对应的时隙资源,sf_ns为非调度对应的扩频因子,ts_ns为非调度对应的时隙资源; [0037] where, SF = 16, i_s denotes the i-th scheduled time slots, the formula should be i_s = 1, similarly, I_ns denotes the i th non-scheduled time slots, i_ns = 1, represents the whole formula is from 1 or ts-s superimposed ts_ns, i.e., a plurality of slots and, sf_s scheduling corresponding spreading factor, ts_s time slot corresponding to the resource scheduling, sf_ns non-scheduled corresponding to the spreading factor, ts_ns the corresponding non-scheduled slot resources;

[0038] (4-2)根据实际的调度和非调度的资源数目N_s和N_ns,分别从所述TBS资源表中查找各自对应的资源等级,根据资源等级得到调度和非调度对应的TBS组; [0038] (4-2) The actual number of scheduled and non-scheduled resources N_s and N_ns, respectively corresponding to each level to find the resources from the resource table TBS, TBS been scheduled and non-scheduled corresponding to the group according to a resource level;

[0039] (4-3)利用步骤(4-1)、(4_2)中所述资源数目、所述TBS值,根据不同的调制方式和传输方式,计算不同调制方式和传输方式对应的码率λ值,其中,所述调制方式是QPSK 调制或16QAM调制; [0039] (4-3) using the step (4-1), (4_2) in the number of resources, the TBS value, depending on the modulation method and transmission mode, and calculate different modulation scheme corresponding to the transmission rate λ value, wherein the modulation scheme is QPSK modulation or 16QAM modulation;

[0040] (4-4)在调度和非调度对应的TBS资源等级中选择所述码率λ在指定范围内的TBS值,所述指定范围为节点B配置给用户设备UE的一组最大/最小码率λ _max/ λ _min ; [0041] (4-5)根据节点B分配给用户设备的8个参考码率λ值和8个参考功率偏置,根据码率插值计算对应的子TBS需要的功率偏置; [0040] (4-4) to select the code rate TBS [lambda] value within the specified range in TBS resources scheduled and non-scheduled level corresponding to the maximum specified range set Node B is configured to the user equipment UE / the minimum rate λ _max / λ _min; [0041] (4-5) to the user equipment according to the allocation rate reference node B 8 8 [lambda] value and the reference power offset, an interpolation rate is calculated according to the corresponding sub needed TBS power offset;

[0042] (4-6)分别比较不同传输类型对应的TBS相应功率是否小于或等于该传输类型的授权功率; [0042] (4-6) were compared TBS corresponding to different transmission types is less than or equal to the respective power transmission of the type authorized power;

[0043] (4-7)将满足小于或等于授权功率的相应TBS与用户设备缓存内的数据进行比较,选择小于或等于,或者大于但最接近用户设备缓存数据的TBS值; [0043] (4-7) satisfies the data within the corresponding user equipment TBS buffer equal to or less than the authorized power is compared, the less than or equal to, or greater than but closest to the value of the user equipment TBS buffer data;

[0044] (4-8)分别从两种传输方式、两种调制方式中选择满足授权功率要求且对应TBS 值最大的调制方式,当两种调制方式中选择的最大TBS相同时,比较对应的需要的功率配置偏移选择功率配置偏移小的调制方式; [0044] (4-8) respectively, from the two transmission modes, the modulation methods that satisfies the power requirement, and authorization TBS corresponding to the maximum value of the modulation scheme, when two modulation modes selected maximum TBS same, comparing the corresponding power required power offset selector configured small offset modulation configuration;

[0045] (4-9)如果调度,非调度的调制方式相同,则将两种传输方式选定的TBS直接相加,作为最终的TBS值; [0045] (4-9) If the scheduling, non-scheduled the same modulation scheme, then the two transmission modes selected TBS added directly, as a final TBS value;

[0046] (4-10)在所述TBS资源表中选择基本资源单位RU折算后对应的TBS组内,与步骤(4-9)中选择出来的最终TBS最接近且小于等于该最终TBS的TBS值,作为复用时选定的TBS值。 [0046] (4-10) corresponding to the group selected in the TBS basic resource unit RU after conversion, and the step (4-9) in the resource table TBS selected from the nearest final TBS and TBS is less than or equal to the final TBS value, as selected when multiplexing TBS value.

[0047] 进一步地,上述方法还具有以下特点: [0047] Furthermore, the above method also has the following characteristics:

[0048] 步骤(4-9)进一步可分为: [0048] Step (4-9) can be further divided into:

[0049] 调度和非调度选择的调制方式不同时: [0049] scheduled and non-scheduled modulation mode selection are not simultaneously:

[0050] 如果调度选择的TBS无效,则最终选择的TBS为非调度的TBS,调制方式为非调度选择的调制方式; [0050] If the scheduling invalid TBS selected, the final selection of the non-scheduled TBS TBS, the modulation scheme selected modulation scheme, non-scheduled;

[0051] 如果非调度选择的TBS无效,则最终选择的TBS为调度的TBS,调制方式为调度选择的调制方式; [0051] If the non-selected in the scheduling TBS is not valid, then the final selection is scheduled TBS TBS, the modulation scheme is a modulation scheme selected in the scheduling;

[0052] 如果调度和非调度选择的TBS都有效,则: [0052] If the selection of scheduled and non-scheduled TBS are valid, then:

[0053] 如果非调度的TBS大于调度的TBS,则最终的TBS为非调度TBS与调度选择的TBS 中与非调度调制方式相同的且最大的TBS之和,或者最终的TBS为非调度TBS ;最终的调制方式为非调度选择的调制方式; [0053] If the non-scheduled TBS TBS greater than scheduled, the final non-scheduled TBS TBS TBS scheduling the selected non-scheduled with the same modulation scheme and the TBS and the maximum, or the non-scheduled final TBS TBS; the final non-scheduled modulation scheme selected modulation mode;

[0054] 如果调度的TBS大于非调度的TBS,则最终的TBS为调度TBS与非调度选择的TBS 中与调度调制方式相同的且最大的TBS之和,或者最终的TBS为调度TBS ;最终的调制方式为调度选择的调制方式。 [0054] If the scheduling of TBS greater than unscheduled TBS, the final TBS scheduling TBS and non-scheduled selected in TBS and scheduling a modulation scheme identical and maximum TBS sum, or the final TBS scheduling TBS; final the modulation scheme is the modulation scheme selected in the scheduling.

[0055] 进一步地,上述方法还具有以下特点: [0055] Furthermore, the above method also has the following characteristics:

[0056] 步骤(6)进一步可分为: [0056] Step (6) can be further divided into:

7[0057] (6-1)根据所述资源单元,节点B利用下述两个公式分别对调度和非调度资源进行归一化,计算调度资源和非调度资源总的资源数目: 7 [0057] (6-1) according to the resource unit to the Node B are scheduled and non-scheduled resources normalized, computing resources scheduling resources and the total number of non-scheduled resources by the following two formulas:

Figure CN101277177BD00081

[0059] 其中,SF= 16,i_s表示第i个调度时隙,上式中应该是i_s = 1,类似地,i_ns表示第i个非调度时隙,i_ns = 1,整个公式表示的是从1叠加到ts_s或者ts_ns,即多个时隙的和,sf_s为调度对应的扩频因子,ts_s为调度对应的时隙资源,sf_ns为非调度对应的扩频因子,ts_ns为非调度对应的时隙资源; [0059] where, SF = 16, i_s denotes the i-th scheduled time slots, the formula should be i_s = 1, similarly, I_ns denotes the i th non-scheduled time slots, i_ns = 1, represents the whole formula is from 1 or superimposed ts_s ts_ns, i.e., a plurality of slots and, sf_s scheduling corresponding spreading factor, ts_s time slot corresponding to the resource scheduling, sf_ns non-scheduled corresponding to the spreading factor, ts_ns corresponding non-scheduled gap resources;

[0060] (6-2)将资源单位数目N折算得到TBS资源表中的所在资源等级的列数,结合用户设备UE上报的TBS索引,在TBS资源表中查到对应的节点B的TBS值,并采用UE上报的调制方式进行解调。 [0060] (6-2) The number of resource units to obtain N columns where conversion levels of resources in the resource table TBS, TBS index binding reported by the user equipment UE, found TBS corresponding to a value of the Node B resource table in TBS , and reported by the UE using the modulation scheme demodulated.

[0061] 由上可知,本发明可以在对具有不同SF,不同时隙数的调度和非调度业务复用时选取一个TBS,当调度和非调度资源的总和落在不同的等级时对应不同的TBS可选值,同UE 根据调度和非调度物理层资源分别选取TBS,之后将子TBS合并的方法,避免了物理信道资源的浪费,同时也不必改变现有的信令结构。 [0061] From the above, the present invention can be selected for having a different TBS SF, the number of different time slots scheduled and non-scheduled service multiplexing, corresponding to different when the sum of scheduled and non-scheduled resources fall different levels of Alternatively TBS value, according to the same TBS UE physical layer to select the resource scheduling and non-scheduling, respectively, after sub-TBS incorporated methods, to avoid the waste of physical channel resources, and also without changing the existing signaling structure.

附图说明 BRIEF DESCRIPTION

[0062] 图1是本发明中TD-SCDMA系统的HSUPA调度与非调度业务在MAC层复用的原理图; [0062] FIG. 1 is a present invention, the TD-SCDMA system HSUPA scheduling service and non-scheduling in the MAC layer schematic multiplexing;

[0063] 图2是本发明中调度非调度复用时选择TBS和调制方式的流程图; [0063] the present invention, FIG. 2 is a flowchart illustrating non-scheduled scheduling TBS and modulation scheme selected time multiplexed;

[0064] 图3是本发明中UE侧选择TBS和调制方式的流程图; [0064] FIG. 3 is a flowchart of selecting the modulation scheme and the TBS in the UE side according to the present invention;

[0065] 图4是本发明中物理层复用时NodeB侧判断TBS的流程图。 [0065] FIG. 4 is a side NodeB present invention, when the physical layer multiplexing flowchart TBS determination.

具体实施方式 Detailed ways

[0066] 下面结合附图及具体实施例对本发明技术方案作进一步详细描述。 [0066] Specific embodiments of the present invention, the technical solutions described in further detail below in conjunction with the accompanying drawings and.

[0067] 为了实现对调度和非调度资源进行复用,使得各种资源能有效利用,对于TBS的选择成为复用中的关键技术。 [0067] In order to achieve the scheduled and non-scheduled resources are multiplexed, so that resources can be effectively utilized for selection of TBS become a key technology in the multiplex.

[0068] 本实施例中,如图1所示,首先对调度业务和非调度业务进行区分。 [0068] In this embodiment, as shown, first, scheduling service and non-scheduling service distinguish 1. 如果有非调度业务,无论是否有调度业务,则称之为非调度传输,使用非调度的Process ID和E-HICH信道;如果只有调度业务,则称之为调度传输,使用调度的Process ID和E-HICH信道;也就是说当既有调度业务也有非调度业务时,传输层将所有业务合在一个TBS中作为非调度传输,对应的物理层和MAC结构如图1所示。 If the non-scheduling service, whether or not scheduling service, it is called non-scheduled transmission, using the Process ID and E-HICH channel unscheduled; if only dispatch services, is called scheduled transmission using scheduling Process ID and E-HICH channel; that is, when both the non-scheduling service has scheduled service, the transport layer services all together in a non-scheduled transmission as TBS, the corresponding physical layer and MAC shown in Figure 1.

[0069] 本实施例的总体思路如下:针对调度和非调度总共可能的码道时隙资源数量,将可能的总资源数量按照归一化等价的方式,分为N个资源等级,并确定每一等级内具有I个TBS可选值,在MAC层设计一个NX I的TBS资源表,在表中预先计算出各种可能的TBS值; 其次,当调度和非调度业务同时存在且非调度业务数据量小于配置的无线资源所能承载的比特数时,MAC层确定采用非调度传输,即需将调度和非调度业务传输复用;再次,用户设备UE计算实际分配的调度和资源总量,再考虑功率授权情况后,从设计的TBS表中选择对应的TBS作为复用时的TBS值,UE将所选的TBS索引传输给节点B(NodeB),节点B也计算实际分配的调度和非调度资源总量,并据此和接收到的TBS索引来确定节点B的TBS值,利用UE传送过来的调制方式进行解调。 [0069] The general idea of ​​this embodiment is as follows: for the scheduled and non-scheduled total number of possible code channel resource slot, the total number of possible resources in accordance with the normalized equivalent manner, resources are divided into N levels, and determines having the I TBS optional value within each level, in a MAC layer design NX I in TBS resource table, in the table of all possible precalculated TBS values; Secondly, when the scheduled and non-scheduled and non-scheduled traffic exist when the radio resource is smaller than the number of bits of configuration data traffic can carry, the MAC layer determines non-scheduled transmission, i.e. need to be scheduled and non-scheduled traffic transmission multiplexing; again, the user equipment UE calculates the actual amount of resources scheduling and allocation , consider the case where power is authorized, the corresponding selected from the TBS table designed as TBS TBS value when multiplexing, the UE transmit the TBS index to the selected node B (the NodeB), node B can calculate the actual allocation and scheduling the total amount of non-scheduled resources, and accordingly received and TBS index to determine the value of the node B is TBS, demodulating transmitted from UE by using the modulation scheme.

[0070] 如图2所示,显示了本实施例中实现调度和非调度复用时的TBS的设计方法,包括如下步骤: [0070] Figure 2, shows the scheduled and non embodiment implemented method for scheduling TBS design time multiplexed, the present embodiment comprises the steps of:

[0071] 步骤201 :计算调度和非调度总共可能的码道时隙资源数量,并将所得的码道时隙资源数量分为N个资源等级,设计每一资源等级内具有的I个TBS可选值,在MAC层设计TBS资源表。 [0071] Step 201: Calculate the scheduled and non-scheduled total number of possible code channel resource slot, the number of code channel slot resource and the resulting divided into N resource levels each resource level with the design of the I can TBS selected value, the MAC layer design TBS resource table.

[0072] 步骤202 :当调度和非调度业务同时存在时且非调度业务数据量小于配置的无线资源所能承载的比特数时,MAC层确定采用非调度传输,即需将调度和非调度业务传输复用。 [0072] Step 202: When scheduled and non-scheduled traffic exist and not less than the number of bits of data traffic can be carried by a radio resource configuration of the scheduling, the MAC layer determines non-scheduled transmission, i.e. need to be scheduled and non-scheduled traffic transport multiplex.

[0073] 步骤203 =UE计算实际分配的调度和非调度资源总量,并据此以及功率授权从TBS 资源表中选择TBS,并确定调制方式,具体步骤如图3所示。 The total amount of resources scheduled and non-scheduled [0073] Step 203 = UE calculate the actual distribution of power and accordingly authorization and resource table selected from TBS TBS, and the modulation mode, the specific steps shown in FIG.

[0074] 步骤204 :通过UCCH,UE将所选TBS的索引传输给NodeB。 [0074] Step 204: By UCCH, UE will transmit the selected TBS index to NodeB.

[0075] 步骤205 =NodeB计算实际分配的调度和非调度资源总量,并以接收到的调制方式进行解调,具体过程如图4所示。 205 = NodeB calculates the total amount of scheduled and non-scheduled resources actually allocated, modulation scheme and demodulates the received specific procedure shown in FIG. [0075] Step 4.

[0076] 在所述的步骤201中,设计TBS资源可选值的具体过程如下。 [0076] In the specific process, the design resources TBS optional value in step 201 as follows.

[0077] (1)首先,确定一个资源单位(RU,Resource Unit),本实施例中将SF = 16的单码道定义为基本的资源单位(RU)。 [0077] (1) First, to identify a resource unit (RU, Resource Unit), in the embodiment of the present embodiment a single code channel SF = 16 is defined as a basic resource unit (RU).

[0078] (2)然后,根据资源单元归一化确定可能的最大资源数量和最小的资源数量。 [0078] (2) Then, according to the resource unit normalization resources may determine the maximum number and minimum number of resources.

[0079] 因为调度和非调度总共占用的资源最多是5个时隙的满码道,最少是单个时隙的一条SF = 16的码道。 [0079] Because the scheduled and non-scheduled total occupied most resources is full channel 5 code slots, a single time slot is the minimum SF = 16 code channels. 也就是说最多占用80个基本RU,最少只占用1个基本RU。 That take up 80 basis RU, occupies only a minimum of basic RU.

[0080] (3)接下来,将步骤2种可能的总资源数量按照归一化等价的方式,分为N个资源等级,N与调制方式有关,且能被80整除。 [0080] (3) Next, the number of possible Step 2 according to the normalized total resources equivalent manner, resources are divided into N levels, N-related modulation scheme, and that can be divisible by 80.

[0081] 本实施例中N = 5,即划分5个资源等级: [0081] In the present embodiment, N = 5, i.e., divided into five grades resources:

[0082] 第一等级对应1〜16个RU ;第二等级对应17〜32个RU ;第三等级对应33〜48 个RU ;第四等级对应49〜64个RU ;第五等级对应65〜80个RU0 [0082] a first level corresponding to 1~16 RU; 17~32 a second level corresponding RU; 33~48 a third level corresponding RU; 49~64 a fourth level corresponding RU; the fifth level corresponds to 65~80 a RU0

[0083] (4)之后,针对每一个资源等级,需要确定每一等级中的最大TBS值和最小TBS值。 After [0083] (4), a resource for each level, a maximum TBS value is determined for each level and minimum values ​​TBS.

[0084] TBS的最小值取的是调度信息的比特数23 ; [0084] TBS minimum number of 23 bits is taken scheduling information;

[0085] TBS的最大值应该对应SF = 1、调制方式为16QAM时可能传输的最大比特数,因此,可以看出第N个资源等级内TBS的最大值满足下式: [0085] The maximum value of SF = TBS should correspond to the maximum number of bits of the modulation scheme is 16QAM transmission 1 may, therefore, be seen that the maximum level of resources TBS N satisfy the following formula:

_TBS/MxSF_ _TBS / MxSF_

[0086] 704-17 χ ENI xSF-(24 + ceil((TBS + 24)/ 5114)x 4)/ M χ <SF + 704 χ (ί — 1) _ [0086] 704-17 χ ENI xSF- (24 + ceil ((TBS + 24) / 5114) x 4) / M χ <SF + 704 χ (ί - 1) _

[0087] 其中,17是UCCH占用的17个符号,24对应的是CRC校验比特的个数,4对应的是Turbo编码并经过打孔遗留下来的尾比特,M为调制方式对应的值,QPSK时,M = 2,16QAM 时,M = 4,Ceil为向上取整数,t为时隙数;ENI为E-UCCH个数; [0087] where 17 is occupied UCCH 17 symbols, 24 corresponds to the number of CRC check bits, corresponding to 4 and Turbo Coding is left after punching down tail bits, M being a value corresponding to the modulation scheme, when is QPSK, M = 2,16QAM, M = 4, Ceil is rounded up, t is the number of slots; ENI is the number of E-UCCH;

[0088] 由上式可以获得N个不同资源等级中TBS的最大值: [0088] TBS can be obtained by the formula N different levels in the maximum resource:

[0089] 当N = 1 时,TBSmax = 2720 ; [0089] When N = 1, TBSmax = 2720;

[0090] 当N = 2 时,TBSmax = 5532 ; [0090] When N = 2, TBSmax = 5532;

[0091] 当N = 3 时,TBSmax = 8348 ;[0092] 当N = 4 时,TBSmax = 11160 ; [0091] When N = 3, TBSmax = 8348; [0092] When N = 4, TBSmax = 11160;

[0093] 当N = 5 时,TBSmax = 13976。 [0093] When N = 5 when, TBSmax = 13976.

[0094] (5)最后,在确定了每一资源等级中的TBS最大值和最小值后,需要在每一资源等级中的TBS最大值和最小值之间等间隔的插入若干TBS值,其中,根据爱立信公司的公开技术文献“Ericsson. R1-02-DRAFT,Signaling of Transport Block Sizes for HS-DSCH TBS应该在对数域内均勻分布,可以减少最坏情况下的padding的长度,因此在进行插值时,我们按照这个原则设计HSUPA系统中的每一资源等级中的I个TBS,即,插值时,对TBS 最大值和最小值取对数,在对数域内进行均勻插值,再将插值得到的对数值转换为对应的TBS数值,从而可以得到每一资源等级中具有的I个TBS值。 [0094] (5) Finally, after determining the TBS maximum and minimum levels in each resource, requires several TBS TBS values ​​into the interval between maximum and minimum values ​​and the like in each resource level, wherein the technical literature discloses Ericsson "Ericsson. R1-02-DRAFT, Signaling of Transport Block Sizes for HS-DSCH TBS should be distributed uniformly in the logarithmic domain, can reduce the length of the padding in the worst case, the interpolation is performed so when we follow this design principle each resource level in the HSUPA system, the I TBS, i.e., the time interpolation, the maximum and minimum of TBS logarithmic, uniform interpolation performed in the logarithmic domain, and then interpolated of TBS values ​​into corresponding values ​​can be obtained for each of the resource grade I having a TBS value.

[0095] 例如,本实施例中,如表1所示插入14个TBS值,即令每一资源等级中有16个TBS 值。 [0095] For example, in this embodiment, as shown in Table 1 is inserted into TBS value 14, and even if each resource level 16 in TBS values. 这样就获得了如表1所示的TBS资源表。 TBS is thus obtained resource table as shown in Table 1. 在本发明的其它实施例中可以是32个TBS 值,或2048个TBS值。 In other embodiments of the present invention may be TBS values ​​32, 2048, or TBS values.

[0096] 通过以上的步骤(1)〜(5),我们可以获得所有可能资源情况下对应的TBS资源表,如表1所示: [0096] By the above steps (1) to (5), we can obtain the corresponding TBS at all possible resource table resources, as shown in Table 1:

[0097] 表1 :HSUPAMAC复用时不同资源单位下的TBS值 [0097] Table 1: TBS values ​​for different resource units when multiplexed HSUPAMAC

[0098] [0098]

Figure CN101277177BD00101
Figure CN101277177BD00111

[0099] 在表1所示的TBS资源表中,第一列为TBS索引值,取值为0〜15,第二列到第六列分别对应5个资源等级。 [0099] In Table 1 shown TBS resource table, the first column TBS index value, a value of 0~15, the second column to the sixth column respectively corresponding to five levels of resources.

[0100] 由于我们采用SF = 16的单码道作为基本资源单位RU,那么具有不同SF的调度和非调度资源都可以归一化到基本RU上,相加即得到实际总共的资源数量,然后再根据资源总量来从表1所示的TBS资源表中选择对应的TBS。 [0100] Because we use a single code channel SF = 16 as a basic resource unit RU, SF, then the different scheduled and non-scheduled resources are normalized to the basic RU, i.e. the sum to obtain the actual total amount of resources, and and then selecting from the corresponding TBS TBS resource table shown in table 1 according to the total resources.

[0101] 在图2所示的步骤203中,UE计算实际分配的调度和非调度资源总量的步骤,并据此以及功率授权从TBS资源表中选择TBS,并确定调制方式,可以细分为以下具体步骤, 参照图3所示: [0101] In 203, the step of scheduling and the total amount of non-scheduled resources step shown in FIG. 2 UE calculate the actual distribution of power and accordingly authorization and resource table selected from TBS TBS, and the modulation mode, can be subdivided In particular the following steps, with reference to Figure 3:

[0102] 步骤301 :独立计算调度资源和非调度资源的RU资源量。 [0102] Step 301: standalone computing resources and scheduling resources RU non-scheduled resources.

[0103] 设调度资源为:ts_s(调度对应的时隙资源),sf_s (调度对应的扩频因子);设非调度资源为:ts_ns (非调度对应的时隙资源),sf_ns (非调度对应的扩频因子); [0103] scheduling resources provided: ts_s (scheduling resources corresponding to the slot), sf_s (spreading factor corresponding to the scheduling); non-scheduled resources provided: ts_ns (non-scheduled time slots corresponding to the resource), sf_ns (corresponding to non-scheduled spreading factor);

[0104] 将调度资源和非调度资源都折算到SF = 16的资源上,折算后调度/非调度RU资源分别为: [0104] The non-scheduled and scheduled resources are resources on the resource converted to SF = 16, the conversion scheduled / non-scheduled resources RU are:

Figure CN101277177BD00112

[0106] 上述两式所做处理为:利用SF = 16基本资源单元分别独立地对调度/非调度的时隙码道资源进行归一化处理,得到调度资源的RU数目N_s和非调度资源的RU数目N_ns。 [0106] The process is done two formula: SF = 16 using a basic resource unit independently of the scheduled / non-scheduled time slots code channel resource normalized, to obtain the number of RU N_s resource scheduling and non-scheduling of resources The number of RU N_ns. 其中,SF= 16,i_s表示第i个调度时隙,上式中应该是i_s = 1,类似地,i_ns表示第i个非调度时隙,i_ns = 1,整个公式表示的是从1叠加到ts_s或者ts_ns,即多个时隙的和。 Where, SF = 16, i_s denotes the i-th scheduled time slots, the formula should be i_s = 1, similarly, I_ns denotes the i th non-scheduled time slots, i_ns = 1, represents the whole formula is from 1 to superimposed ts_s or ts_ns, i.e., and a plurality of slots.

[0107] 步骤302 :独立计算调度资源和非调度资源对应的TBS。 [0107] Step 302: an independent computing resource scheduling and non-scheduling resources corresponding to TBS.

[0108] 根据折算的调度/非调度RU数目N_s和N_ns,分别从表1所示的5组TBS资源中选择调度和非调度各自对应的TBS组; [0108] The conversion of the scheduled / non-scheduled and the number of RU N_s N_ns, scheduled and non-scheduled were selected TBS corresponding to each group from the group in Table 5 shown in TBS resources;

[0109] 本实施例中,如表1所示,表1中TBS资源一共分为5个组,每组对应RU资源分别为: [0109] In this embodiment, as shown in Table 1, Table 1 TBS total resources divided into five groups, each corresponding to RU resources are:

[0110]第 ι 组:N = [1,16];第2 组:N= [7,32]; [0110] The first ι Group: N = [1,16]; Group 2: N = [7,32];

[0111]第 3 组:N = [33,48];第4 组:N = [49,64]; [0111] Group 3: N = [33,48]; Group 4: N = [49,64];

[0112]第 5 组:N = [65,80]; [0112] Group 5: N = [65,80];

[0113] 那么对应的调度/非调度TBS资源组分别为: [0113] then the corresponding scheduled / non-scheduled resources TBS groups were:

Figure CN101277177BD00113
Figure CN101277177BD00114

[0116]其中,index_group_TBS_s,index_group_TBS_ns 分别表示调度的TBS 资源组索引和非调度的TBS资源组索引,即对应的N值,也就是组号。 [0116] wherein, index_group_TBS_s, index_group_TBS_ns respectively scheduling resource groups TBS index and TBS unscheduled resource group index, i.e., a value corresponding to N, i.e. a group number.

[0117] 在上述步骤302中找到调度和非调度各自对应的资源组后,即获得对应的组号。 After the [0117] scheduled and non-scheduled resources find their corresponding groups in the above step 302, i.e., to obtain a corresponding group number. 下面的步骤将介绍如何在各自资源组中得到调度/非调度对应的TBS值,即在对应的组中查找TBS索引,找到表1中的行的位置。 The following steps describe how to obtain the value of TBS scheduled / non-scheduled resource corresponding to the respective groups, i.e., TBS index to find the corresponding group in Table 1 to find the location of the row.

[0118] 步骤303 :根据不同的调制方式和不同传输方式,计算不同调制方式和传输方式对应的码率λ值。 [0118] Step 303: according to different modulation schemes and different transmission mode, code rate λ calculated value of different modulation methods and transmission modes correspond.

[0119] 所述调制方式,可以是QPSK调制或16QAM调制;所述传输方式可以是调度传输或非调度传输。 [0119] The modulation scheme may be QPSK modulation or 16QAM modulation; the transmission may be scheduled transmission or a non-scheduled transmission. 利用下面四个公式,可以得到不同调制方式和不同传输方式下的4个λ值: Using the following four equations, values ​​of λ can be obtained in four different modulation methods and different forms of transmission:

[0120] λ _QPSK_ns = TBS_group_ns/N_ns/88 ; [0120] λ _QPSK_ns = TBS_group_ns / N_ns / 88;

[0121] λ _16QAM_ns = TBS_group_ns/N_ns/176 ; [0121] λ _16QAM_ns = TBS_group_ns / N_ns / 176;

[0122] λ_QPSK_s = TBS_group_s/N_s/88 ; [0122] λ_QPSK_s = TBS_group_s / N_s / 88;

[0123] λ _16QAM_s = TBS_group_s/N_s/176 ; [0123] λ _16QAM_s = TBS_group_s / N_s / 176;

[0124] 其中,指调度资源对应的组TBS (在表1中共是16个),TBS_group_ ns是指非调度资源对应的组TBS (在表1中共是16个)。 [0124] wherein, refers to the group corresponding to the resource scheduling TBS (Table 1 CCP 16), TBS_group_ ns TBS refers to groups corresponding non-scheduled resources (in Table 1 is a 16 CCP).

[0125]根据步骤 302 选择的组号index_group_TBS_s,index_group_TBS_ns,分别计算调度,非调度资源对应的该组TBS (16个TBS,对应表1中的某一行中的16列)的码率,由于调制方式有2种,因此,分别计算2种调制方式对应的码率。 [0125] According to step 302 the selected group number index_group_TBS_s, index_group_TBS_ns, calculates scheduling, the set non-scheduled resources corresponding TBS (TBS 16, corresponding to a line in Table 1 in 16) the code rate, the modulation scheme due there are two, therefore, it is calculated corresponding to the two kinds of modulation code rate.

[0126] 步骤304 :在调度和非调度各自对应的TBS资源组中选择码率λ在指定范围内的TBS 值。 [0126] Step 304: Select TBS rate [lambda] value within a specified range in the scheduled and non-scheduled TBS corresponding to each resource group.

[0127] 由于UE在申请UPA业务的时候,NodeB会配置一组最大/最小码率λ _max/ λ _ min给UE,需要选择λ满足λ _max/λ _min要求的TBS值,即第一次选择,从原来一组中的32个TBS值中选择满足码率要求的TBS,TBS范围=A,A < = 32,符号表达如下: [0127] Since the UE at the time of application UPA services, the NodeB configures a set maximum / minimum bit rate λ _max / λ _ min to the UE, necessary to select the value of [lambda] satisfying TBS λ _max / λ _min requirements, i.e., the first selected selecting from the original 32 in the TBS values ​​in a group satisfy a required bitrate TBS, TBS range = a, a <= 32, the symbol is expressed as follows:

[0128] 对于非调度: [0128] For non-scheduled:

[0129] QPSK_index_ns = find ( λ _QPSK_ns (find (( λ _QPSK_ns < λ _max) > λ _min))) [0129] QPSK_index_ns = find (λ _QPSK_ns (find ((λ _QPSK_ns <λ _max)> λ _min)))

[0130] 16QAM_index_ns = find ( λ _16QAM_ns (find (( λ _16QAM_ns < λ _max) > λ_ min))) [0130] 16QAM_index_ns = find (λ _16QAM_ns (find ((λ _16QAM_ns <λ _max)> λ_ min)))

[0131 ] λ _QPSK丄ns = λ _QPSK_ns (QPSK_index_ns) [0131] λ _QPSK Shang ns = λ _QPSK_ns (QPSK_index_ns)

[0132] λ_16QAM_l_ns = λ_16QAM_ns(16QAM_index_ns) [0132] λ_16QAM_l_ns = λ_16QAM_ns (16QAM_index_ns)

[0133] TBS_QPSK丄ns = TBS_QPSK_ns(QPSK_index_ns) [0133] TBS_QPSK Shang ns = TBS_QPSK_ns (QPSK_index_ns)

[0134] TBS_16QAM_l_ns = TBS_16QAM_ns(16QAM_index_ns) [0134] TBS_16QAM_l_ns = TBS_16QAM_ns (16QAM_index_ns)

[0135] 对于调度: [0135] For scheduling:

[0136] QPSK_index_s = find ( λ _QPSK_s (find (( λ _QPSK_s < λ _max) > λ _min))) [0136] QPSK_index_s = find (λ _QPSK_s (find ((λ _QPSK_s <λ _max)> λ _min)))

[0137] 16QAM_index_s = find ( λ _16QAM_s (find (( λ _16QAM_s < λ _max) > λ _min))) [0137] 16QAM_index_s = find (λ _16QAM_s (find ((λ _16QAM_s <λ _max)> λ _min)))

[0138] λ _QPSK_l_s = λ _QPSK_s (QPSK_index_s) [0138] λ _QPSK_l_s = λ _QPSK_s (QPSK_index_s)

[0139] λ _16QAM_l_s = λ _16QAM_s (16QAM_index_s) [0139] λ _16QAM_l_s = λ _16QAM_s (16QAM_index_s)

[0140] TBS_QPSK_l_s = TBS_QPSK_s(QPSK_index_s) [0140] TBS_QPSK_l_s = TBS_QPSK_s (QPSK_index_s)

[0141] TBS_16QAM_l_s = TBS_16QAM_s(16QAM_index_s) [0141] TBS_16QAM_l_s = TBS_16QAM_s (16QAM_index_s)

[0142] 步骤305 :根据8个参考码率λ值插值计算对应的子TBS需要的参考功率偏置。 [0142] Step 305: calculate the corresponding bit rate in accordance with 8 reference sub-λ-value interpolation TBS desired reference power offset.

[0143] UE在申请UPA业务时,Node B将配置8个参考λ值以及对应需要的功率,根据物 [0143] UE UPA in the application service, Node B will configure the λ value 8 and the reference power corresponding to the required, depending on the physical

12理层不同TBS,不同调制方式选择对应的码率在BLER = 0. 1处的Ior/Ioc计算得到。 12 different physical layer TBS, select different modulation code rate corresponding Ior at 0. 1 / Ioc calculated at BLER =.

[0144] E_PUCH 的功率为:PE_PUCH = Pe_base+L+ β e+KE_PUCH [0144] E_PUCH of power: PE_PUCH = Pe_base + L + β e + KE_PUCH

[0145] 其中,β 6是增益因子,从UE选择的E-TFC传输块长度、E-PUCH物理资源大小、 E-PUCH调制方式得到。 [0145] where, β 6 is a gain factor, the E-TFC transport block size selected by the UE, E-PUCH resources to the physical size, E-PUCH modulation obtained.

[0146] β e = β Q,e+ α e+ Δ —dB,其中A [0146] β e = β Q, e + α e + Δ -dB, wherein A

Figure CN101277177BD00131

(插值公式) (Interpolation formula)

[0147] 插值后得到: [0147] interpolated to give:

[0148] β c^QPSI^ns,表示非调度传输QPSK需要的参考功率; [0148] β c ^ QPSI ^ ns, showing non-scheduled transmission reference power required for QPSK;

[0149] β ^ieQAiLns,表示非调度传输16QAM需要的参考功率; [0149] β ^ ieQAiLns, represents non-scheduled transmission 16QAM desired reference power;

[0150] β dQPSKj,表示调度传输QPSK需要的参考功率; [0150] β dQPSKj, QPSK denotes scheduled transmission reference power required;

[0151] β &_160ΑΜ_8,表示调度传输16QAM需要的参考功率; [0151] β & _160ΑΜ_8, 16QAM indicates the reference power required for scheduled transmission;

[0152] 步骤306 :分别比较不同传输类型对应的TBS下的功率是否小于或等于该传输类型的授权功率;根据步骤305计算的插值结果,从步骤304中经过第一次选择的TBS (集合Α)中分别选择满足该类型(调动,非调度)的功率授权要求的TBS(集合B),即第二次选择, 得到集合B,使集合B <集合Α。 [0152] Step 306: comparing the power at each transmission of different types corresponding to the TBS that is less than or equal to authorized power transmission type; an interpolation calculation based step 305 from step 304 after the first selection in TBS (set Α ), respectively, that satisfies the type (transfer, non-scheduled) power authorization request TBS (set B), i.e., the second selection results in a set B, enable a set of B <set Α.

[0153] 符号表达方式如下: [0153] symbols expressed as follows:

[0154] β 0e_QPSK_ns_after_ β 0e NS = β 0e_QPSK_ns (find ( β 0e_QPSK_ns < β 0e NS)) [0154] β 0e_QPSK_ns_after_ β 0e NS = β 0e_QPSK_ns (find (β 0e_QPSK_ns <β 0e NS))

[0155] β 0e_16QAM_ns_after_ β 0e NS = β 0e_16QAM_ns (find ( β 0e_16QAM_ns < β 0e NS)) [0155] β 0e_16QAM_ns_after_ β 0e NS = β 0e_16QAM_ns (find (β 0e_16QAM_ns <β 0e NS))

[0156] β 0e_QPSK_s_after_ β 0e s = β 0e_QPSK_s (find ( β 0e_QPSK_s < β 0e s)) [0156] β 0e_QPSK_s_after_ β 0e s = β 0e_QPSK_s (find (β 0e_QPSK_s <β 0e s))

[0157] β 0e_16QAM_s_after_ β 0e s = β 0e_16QAM_s (find ( β 0e_16QAM_s < β 0e s)) [0157] β 0e_16QAM_s_after_ β 0e s = β 0e_16QAM_s (find (β 0e_16QAM_s <β 0e s))

[0158] 步骤307 :与UEBUFFER比较,选择小于UEBUFFER的TBS。 [0158] Step 307: Comparison with UEBUFFER, UEBUFFER less than the selected TBS. 其中,根据步骤306的结果,分别从集合B中选择该类型(调度,非调度)满足buffer要求的集合,即集合C,使集合C<集合B; Wherein the result of step 306, each type selected from the set B (scheduled, non-scheduled) buffer satisfies the requirements set, i.e. set of C, so that the set of C <B set;

[0159] 符号表达方式如下: [0159] symbols expressed as follows:

[0160] TBS_QPSK_after_buffer_ns = TBS_QPSK_ns(find(TBS_QPSK_l_ns < UE_ Buffer)) [0160] TBS_QPSK_after_buffer_ns = TBS_QPSK_ns (find (TBS_QPSK_l_ns <UE_ Buffer))

[0161] TBS_16QAM_after_buffer_ns = TBS_16QAM_ns(find(TBS_16QAM_l_ns < UE_ Buffer)) [0161] TBS_16QAM_after_buffer_ns = TBS_16QAM_ns (find (TBS_16QAM_l_ns <UE_ Buffer))

[0162] TBS_QPSK_after_buffer_s = TBS_QPSK_s(find(TBS_QPSK_l_s < UE_Buffer)) [0162] TBS_QPSK_after_buffer_s = TBS_QPSK_s (find (TBS_QPSK_l_s <UE_Buffer))

[0163] TBS_16QAM_after_buffer_s = TBS_16QAM_s(find(TBS_16QAM_l_s < UE_ Buffer)) [0163] TBS_16QAM_after_buffer_s = TBS_16QAM_s (find (TBS_16QAM_l_s <UE_ Buffer))

[0164] 步骤308:分别从两种传输方式,两种调制方式中选择满足授权功率要求,且TBS 最大的。 [0164] Step 308: the two transmission modes, respectively, two types of modulation authorized power that satisfies the requirements, and the maximum TBS. 当两种调制方式选择的最大TBS相同时,比较对应的需要的功率配置偏移,选择功率配置偏移小的。 When the maximum TBS with two modulation modes selected at the same time, comparing the required power corresponding to the offset configuration, a small offset of the selected power allocation.

[0165] 即,如果非调度资源的QPSK需要的功率小于等于非调度资源的16QAM需要的功率,则选择调制方式为QPSK,反之选择16QAM ; [0165] That is, if the power required for non-scheduled resources QPSK or less non-power required resource scheduling 16QAM, QPSK modulation scheme is selected, and vice versa selected 16QAM;

[0166] 如果调度资源的QPSK需要的功率小于等于调度资源的16QAM需要的功率,则选择调制方式为QPSK,反之选择16QAM。 [0166] If the power of QPSK required resource scheduling resource scheduling less power required 16QAM, QPSK modulation scheme is selected, and vice versa 16QAM selection.

[0167] 符号表达方式如下:[0168] if (^0e_QPSK_ns > β 0e_16QAM_ns) :type_mod_ns = 16QAM [0167] symbols expressed as follows: [0168] if (^ 0e_QPSK_ns> β 0e_16QAM_ns): type_mod_ns = 16QAM

[0169] if (^0e_QPSK_ns <= β 0e_16QAM_ns) :type_mod_ns = QPSK [0169] if (^ 0e_QPSK_ns <= β 0e_16QAM_ns): type_mod_ns = QPSK

[0170] if (^0e_QPSK_s > β 0e_16QAM_s) :type_mod_s = 16QAM [0170] if (^ 0e_QPSK_s> β 0e_16QAM_s): type_mod_s = 16QAM

[0171] if (β 0e_QPSK_s <= β 0e_16QAM_s) :type_mod_s = QPSK [0171] if (β 0e_QPSK_s <= β 0e_16QAM_s): type_mod_s = QPSK

[0172] 步骤309 :确定上传到nodeB的最终TBS值fimal_TBS和TFC值。 [0172] Step 309: determining the final upload TBS value fimal_TBS nodeB and the TFC value.

[0173] 如果调度,非调度选择的调制方式相同,则: [0173] If the scheduling, the same modulation scheme selected non-scheduled, then:

[0174] 将两个独立选择的TBS值直接相加,并在TBS表中查出最接近但小于叠加后的TBS 值作为最终TBS。 [0174] The two independently selected TBS value added directly, and isolated in TBS TBS table closest to but less than a value obtained by superimposing final TBS.

[0175] 如果调度,非调度选择的调制方式不同,则: [0175] If different scheduling, non-scheduled selected modulation mode, then:

[0176] 如果调度选择的TBS都无效,则 [0176] If the selected scheduled TBS is not valid, then

[0177] 最终选择的TBS为非调度的TBS,调制方式为非调度选择的调制方式; [0177] The final choice of the non-scheduled TBS TBS, the modulation scheme selected modulation scheme, non-scheduled;

[0178] 如果非调度选择的TBS无效,则 [0178] If the non-selected in the scheduling TBS is not valid,

[0179] 最终选择的TBS为调度的TBS,调制方式为调度选择的调制方式; [0179] The final choice is scheduled TBS TBS, the modulation scheme is a modulation scheme selected in the scheduling;

[0180] 如果调度,非调度选择的TBS都有效,则: [0180] If the scheduling, non-scheduled TBS selected are valid, then:

[0181] 如果非调度的TBS大于调度的TBSJU [0181] If the non-scheduled TBS greater than scheduled TBSJU

[0182] 最终的TBS为非调度TBS+(调度选择的TBS中与非调度调制方式相同的且最大的TBS),或者最终的TBS为非调度TBS ;最终的调制方式为非调度选择的调制方式; [0182] The final non-scheduled TBS + TBS (TBS selected in the scheduling and non-scheduling in the same modulation method and the maximum TBS), or non-scheduled final TBS TBS; non-scheduled final modulation scheme selected modulation mode;

[0183] 如果调度的TBS大于非调度的TBS,则 [0183] If the scheduling unscheduled greater than TBS TBS, then

[0184] 最终的TBS为调度TBS+(非调度选择的TBS中与调度调制方式相同的且最大的TBS),或者最终的TBS为调度TBS ;最终的调制方式为调度选择的调制方式。 [0184] The final scheduling TBS + TBS (TBS, non-scheduled and scheduling the selected modulation scheme and the same maximum TBS), TBS or the final scheduling TBS; final modulation scheme selected in the scheduling modulation.

[0185] 符号表达方式如下: [0185] symbols expressed as follows:

[0186] if (type_mod_ns Φ· type_mod_s) [0186] if (type_mod_ns Φ · type_mod_s)

[0187] if (TBS_ns ^ 0&TBS_s = 0) [0187] if (TBS_ns ^ 0 & TBS_s = 0)

[0188] then :final_TBS = TBS_ns, type_mod = type_mod_ns ; [0188] then: final_TBS = TBS_ns, type_mod = type_mod_ns;

[0189] if (TBS_ns = = 0&TBS_s Φ 0) [0189] if (TBS_ns = = 0 & TBS_s Φ 0)

[0190] then :final_TBS = TBS_s, type_mod = type_mod_s ; [0191 ] if (TBS_ns Φ 0&TBS_s Φ 0) [0190] then: final_TBS = TBS_s, type_mod = type_mod_s; [0191] if (TBS_ns Φ 0 & TBS_s Φ 0)

[0192] if (TBS_ns > TBS_s),then :final_TBS = TBS_ns+max (TBS_s (type_mod_ns)) [0192] if (TBS_ns> TBS_s), then: final_TBS = TBS_ns + max (TBS_s (type_mod_ns))

[0193] type_mod = type_mod_ns ; [0193] type_mod = type_mod_ns;

[0194] if (TBS_ns < = TBS_s),then :final_TBS = TBS_s+max (TBS_ns (type_mod_s)), [0194] if (TBS_ns <= TBS_s), then: final_TBS = TBS_s + max (TBS_ns (type_mod_s)),

[0195] type_mod = type_mod_s ; [0195] type_mod = type_mod_s;

[0196] 步骤310 :在TBS集合中选择RU折算后对应组内与上述步骤309中选择出来的final_TBS最接近且小于等于该final_TBS的值: [0196] Step 310: After selecting the conversion RU selected from the group corresponding to the above-described step 309 final_TBS in TBS set equal to the value closest to and smaller than the final_TBS of:

[0197] final_TBS_index = max(find((final_TBS-TBS_group) > = 0)) [0197] final_TBS_index = max (find ((final_TBS-TBS_group)> = 0))

[0198] 如图4所示,在图2所示的步骤205中,NodeB也根据图3所示各步骤的一部分, 得到TBS值,过程如下: [0198] As shown in FIG. 4, in the step shown in FIG. 2 205, NodeB also part according to the steps shown in FIG. 3, the TBS value obtained, as follows:

[0199]步骤 401:折算RU。 [0199] Step 401: conversion RU.

[0200] 总的RU资源折算方法如下: [0200] Total RU resource conversion method is as follows:

[0201] 设调度资源为:ts_s,sf_s ;[0202]非调度资源为:ts_ns,sf_ns ; [0201] scheduling resources provided: ts_s, sf_s; [0202] non-scheduled resources: ts_ns, sf_ns;

[0203] 将调度和非调度资源都折算到SF = 16的资源单位上,折算后总的资源为: [0203] The scheduled and non-scheduled resources are converted to the resource unit SF = 16, total conversion of the resource:

Figure CN101277177BD00151

[0205] 步骤402 :根据折算的总RU资源数目N,以及UE发送给NodeB的TBS索引final_ TBS_index,从5组TBS资源中选择对应的TBS值; [0205] Step 402: The conversion of the total transmission resources RU number N, and the UE to the NodeB TBS index final_ TBS_index, TBS corresponding to a value selected from the 5 group TBS resources;

[0206] index_TBS_NodeB = ceil (Ν/16) [0206] index_TBS_NodeB = ceil (Ν / 16)

[0207] TBS_nodeB = TBS_set (index_TBS_NodeB, f inal_TBS_index) [0207] TBS_nodeB = TBS_set (index_TBS_NodeB, f inal_TBS_index)

[0208] 根据步骤401计算的资源N折算到16个码道上,且向上取整,确定表1中TBS选择的列号。 [0208] calculated according to step 401 the resource converted to N 16 code channels, and the rounded up number determination table in column 1 the selected TBS. 由于最终的TBS(从表1中的16个里面选择的一个,即行号)已经通过E-UCCH 上报Node B,因此,Node B根据上述两个信息,可以知道所选的TBS。 Since the final TBS (from Table 1 16 inside a selected, i.e., line number) has been reported to Node B through the E-UCCH, therefore, two Node B based on the information, can know the selected TBS. 由于调制方式是显示传递,因此Node B侧不需要再计算调制方式。 Since the modulation scheme is a transfer, thus Node B side does not need to calculate the modulation scheme.

Claims (8)

  1. 一种调度非调度复用确定传输模块大小和调制方式的方法,其特征在于,包括如下步骤:(1)设置基本资源单位,根据资源单元归一化计算调度和非调度总共可能的码道时隙资源数量C,将C按照归一化等价的方式,分为N个资源等级,N能被80整除;(2)计算步骤(1)所述的N个资源等级中每一资源等级内的最大和最小的传输模块大小即TBS值,确定每一等级内具有的I个TBS可选值,在MAC层建立一个N×I的TBS资源表;(3)当调度和非调度业务同时存在且非调度业务数据量小于配置的无线资源所能承载的比特数时,MAC层确定采用非调度传输,将调度和非调度业务传输复用;(4)用户设备UE根据所述资源单元分别独立计算实际分配的调度和非调度资源总量,并据此以及功率授权情况从所述TBS资源表中独立选择不同传输方式下对应的TBS值,所述传输方式指调度传输或非调度传 A method of scheduling transmission of non-scheduled multiplexed block size and a modulation scheme determination method, characterized by comprising the steps of: (1) basic resource unit arranged to calculate a possible total of scheduled and non-scheduled code channel according to the resource unit normalization gap resource quantity C, C in accordance with the normalized equivalent manner, resources are divided into N levels, N be divisible 80; (2) calculation step (1) the resources within each level of the N resource hierarchy maximum and minimum transport block size TBS i.e. values ​​determined within each level having selectable values ​​of the I TBS, TBS establish a resource table of N × I in the MAC layer; (3) when the scheduled and non-scheduled traffic exist when the number of bits and the non-scheduled traffic data is smaller than a radio resource configuration can carry, the MAC layer determines non-scheduled transmission, scheduling and non-scheduling service transport multiplex; (4) user equipment UE according to the resource units are each independently the total amount of scheduled and non-scheduled resources actually allocated is calculated, and a power and accordingly select the authorization TBS corresponding to a value different from the TBS transmission resource table independently of the scheduled transmission or transmission mode scheduled transmission means ,并根据两种传输方式下的TBS值所对应的调制方式是否相同来确定最终的TBS值,以及确定调制方式。 And to determine the final value in accordance with TBS TBS values ​​are the same in both transmission mode corresponding to the modulation scheme, and determining the modulation scheme.
  2. 2.如权利要求1所述的方法,其特征在于,进一步包括,(5)用户设备UE将所选的TBS值对应的索引及调制方式传输给节点B ;(6)节点B计算实际分配的调度和非调度资源总量,并据此和接收到的对应TBS值的索引获得节点B的TBS值,利用接收的调制方式进行解调。 2. The method according to claim 1, characterized by further comprising, (5) the user equipment UE transmits the selected value of the index corresponding to the TBS and modulation scheme to the Node B; (. 6) calculates the actual distribution of the Node B the total amount of scheduled and non-scheduled resources, and accordingly the corresponding TBS value index and to obtain the TBS value received node B, performs demodulation by using the modulation scheme received.
  3. 3.如权利要求1所述的方法,其特征在于,步骤(1)中:所述资源单位是扩频因子SF = 16的单码道;所述总共可能的码道时隙资源数量C为1至80个资源单元。 3. The method according to claim 1, wherein the step (1): is the resource unit spreading factor SF = 16 a single code channel; the total possible number of code channel slot resource is C 1 to 80 resource units.
  4. 4.如权利要求1所述的方法,其特征在于,步骤(2)中:所述每一资源等级中的最小TBS值是调度信息的比特数23 ;所述每一资源等级中的最大TBS值是对应扩频因子SF = 1、调制方式为16QAM时可能传输的最大比特数,对于第N个资源等级内最大TBS值满足下式: 4. The method according to claim 1, wherein the step (2) in which: said minimum level in each resource TBS value is the number of 23-bit scheduling information; resource level in each of said maximum TBS value corresponding to a spreading factor SF = 1, the maximum number of bits possible modulation scheme is 16QAM transmission, the maximum TBS value for the N-level resource to satisfy the following formula:
    Figure CN101277177BC00021
    其中,17是UCCH占用的17个符号,24对应的是CRC校验比特的个数,4对应的是Turbo 编码并经过打孔遗留下来的尾比特,M为调制方式对应的值,QPSK时,M = 2,16QAM时,M = 4,Ceil为向上取整数,t为时隙数;ENI为E-UCCH个数。 Wherein UCCH 17 is occupied by symbols 17, 24 corresponds to the number of CRC check bits, corresponding to 4 and Turbo Coding is left after punching down tail bits, M being a value corresponding to a modulation scheme, is QPSK, when M = 2,16QAM, M = 4, Ceil rounded upwards, t is the number of slots; ENI is the number of E-UCCH.
  5. 5.如权利要求1所述的方法,其特征在于,步骤(2)中建立TBS资源表,进一步可分为:(2-1)将扩频因子SF = 16的单码道确定为基本的资源单位RU ;(2-2)根据基本资源单位RU,确定调度和非调度可能的总资源数量;(2-3)将所有可能资源分为N个资源等级;(2-4)在每一资源等级内,确定每一资源等级中的最大TBS值和最小TBS值;(2-5)在对数域空间对每一资源等级中的TBS最大值和最小值取对数,于两者之间进行均勻插值,再将插值所得对数值转换为对应的TBS值,确定每一资源等级中具有的I个TBS值,生成一个NX I的TBS资源表。 5. The method according to claim 1, characterized in that the establishment of TBS resource table (2) step, is further divided into: (2-1) a single code spreading factor SF = 16 channel determined as the basic resource unit RU; (2-2) the basic resource unit RU, to determine the total number of possible resource scheduling and non-scheduling; (2-3) all possible resources are divided into N resource levels; (2-4) in each the level of resources, each resource determines the maximum TBS value and a minimum level of TBS value; (2-5) in the logarithmic domain maximum TBS space for each resource and the minimum level of the logarithmic, in both the interpolating between the uniform, then the resulting interpolation of values ​​into corresponding TBS value is determined for each resource having a level of the I TBS value, generating a resource table NX I in TBS.
  6. 6.如权利要求1或3所述的方法,其特征在于,步骤(4)进一步可分为:(4-1)根据所述资源单元,利用以下两个公式分别对实际分配的调度和非调度资源进行归一化,计算后,得到调度资源和非调度资源各自总的资源数目:其中,SF= 16,i_s表示第i个调度时隙,上式中应该是i_s= 1,类似地,i_ns表示第i个非调度时隙,i_ns = 1,整个公式表示的是从1叠加到ts_s或者ts_ns,即多个时隙的和,sf_s为调度对应的扩频因子,ts_s为调度对应的时隙资源,sf_ns为非调度对应的扩频因子,ts_ns为非调度对应的时隙资源;(4-2)根据实际的调度和非调度的资源数目N_s *N_ns,分别从所述TBS资源表中查找各自对应的资源等级,根据资源等级得到调度和非调度对应的TBS组;(4-3)利用步骤(4-1)、(4-2)中所述资源数目、所述TBS值,根据不同的调制方式和传输方式,计算不同调制方式和传输 The two equations actually allocated scheduling and non (4-1) according to the resource units using: the method as claimed in claim 1 or 3, wherein step (4) is further divided into scheduling resources normalized, after calculation, the total number of resources, each resource scheduling and non-scheduling resources: where, SF = 16, i_s denotes the i-th scheduled time slots, the formula should be i_s = 1, similarly, when I_ns denotes the i th non-scheduled time slots, i_ns = 1, represents the whole formula is from 1 to ts_s superimposed or ts_ns, i.e., a plurality of slots and, sf_s scheduling corresponding spreading factor, ts_s corresponding scheduling gap resource, sf_ns non-scheduled corresponding to the spreading factor, ts_ns corresponding to a non-timeslot resource scheduling; (4-2) according to the actual number of scheduled and non-scheduled resources n_s * N_ns, respectively, from the resource table TBS Find resource corresponding to each level, scheduled and non-scheduled to give a corresponding level of resources according to the TBS group; (4-3) using the step (4-1), (4-2) in the number of resources, the TBS value, in accordance different modulation and transmission, and transmission is calculated different modulation 式对应的码率λ值,其中,所述调制方式是QPSK调制或16QAM调制;(4-4)在调度和非调度对应的TBS资源等级中选择所述码率λ在指定范围内的TBS 值,所述指定范围为B节点配置给用户设备UE的一组最大/最小码率λ _max/ λ _min ;(4-5)根据B节点分配给用户设备的8个参考码率λ值和8个参考功率偏置,根据码率插值计算对应的子TBS需要的功率偏置;(4-6)分别比较不同传输类型对应的TBS相应功率是否小于或等于该传输类型的授权功率;(4-7)将满足小于或等于授权功率的相应TBS与用户设备的缓存内的数据进行比较, 选择小于或等于,或者大于但最接近用户设备缓存数据的TBS值;(4-8)分别从两种传输方式、两种调制方式中选择满足授权功率要求且对应TBS值最大的调制方式,当两种调制方式中选择的最大TBS相同时,比较对应的需要的功率配置偏移选择功率配置偏移小的调制 Corresponding to the formula [lambda] value of the code rate, wherein the modulation scheme is QPSK modulation or 16QAM modulation; (4-4) to select the code rate in TBS and non-scheduled resource scheduling level corresponding to the [lambda] value within a specified range TBS of the specified range configured for the user equipment UE to a node B set maximum / minimum bit rate λ _max / λ _min; (4-5) to the user equipment according to a reference node B rate assigned [lambda] value of 8 and 8 a reference power offset, the calculated power offset corresponding to a sub-code rate according to the interpolation required TBS; TBS respective power (4-6) were compared corresponding to the different transmission types is less than or equal to the authorized power transmission type; (4-7 ) will meet in the cache data corresponding to the TBS of the user equipment is authorized power is less than or equal to compare, select or less, but greater than or TBS value closest to the user equipment's data buffer; (4-8), respectively, from the two transmission embodiment, the modulation methods that satisfies the power requirement, and authorization TBS corresponding to the maximum value of the modulation scheme, when two modulation modes selected maximum TBS same, comparing the required power corresponding to the selected power offset configuration arranged offset small modulation 方式;(4-9)如果调度,非调度的调制方式相同,则将两种传输方式选定的TBS直接相加,作为最终的TBS值;(4-10)在所述TBS资源表中选择基本资源单位RU折算后对应的TBS组内,与步骤(4-9)中选择出来的最终TBS最接近且小于等于该最终TBS的TBS值,作为复用时选定的TBS 值。 Manner; (4-9) If the scheduling, non-scheduled the same modulation scheme, then the two transmission modes selected TBS added directly as the final value TBS; (4-10) in the selected resource table TBS selected from the (4-9) of the TBS group corresponding to the basic resource unit RU after conversion, and the final step TBS TBS value closest to and smaller than or equal to the final TBS as a selected value when multiplexing with TBS.
  7. 7.如权利要求6所述的方法,其特征在于,步骤(4-9)进一步可分为: 在调度和非调度选择的调制方式不同时:如果调度选择的TBS都无效,则最终选择的TBS为非调度的TBS,调制方式为非调度选择的调制方式;如果非调度选择的TBS无效,则最终选择的TBS为调度的TBS,调制方式为调度选择的调制方式;如果调度和非调度选择的TBS都有效:则:如果非调度的TBS大于调度的TBS,则最终的TBS为非调度TBS与调度选择的TBS中与非调度调制方式相同的且最大的TBS之和,或者最终的TBS为非调度TBS ;最终的调制方式为非调度选择的调制方式;如果调度的TBS大于非调度的TBS,则最终的TBS为调度TBS与非调度选择的TBS中与调度调制方式相同的且最大的TBS之和,或者最终的TBS为调度TBS ;最终的调制方式为调度选择的调制方式。 7. The method according to claim 6, wherein the step (4-9) is further divided into: the modulation scheme selected in the scheduling and non-scheduling is not the same: if the selected scheduled TBS is not valid, then the final selection of TBS TBS non-scheduling, non-scheduled modulation scheme selected modulation mode; if the non-scheduled invalid TBS selected, the final selection for the scheduled TBS TBS, the modulation scheme is a modulation scheme selected in the scheduling; if the scheduled and non-scheduled selection in TBS are valid: then: If the non-scheduled TBS TBS greater than scheduled, the final non-scheduled TBS TBS TBS scheduling the selected non-scheduled with the same modulation scheme and a sum of maximum TBS or TBS to a final the non-scheduled TBS; non-scheduled final modulation scheme selected modulation mode; if scheduling unscheduled TBS TBS greater than, the final scheduling TBS TBS TBS and non-scheduled with scheduling the selected modulation scheme and the same maximum TBS and the sum, or the final scheduling TBS TBS; final modulation scheme selected in the scheduling modulation.
  8. 8.如权利要求2所述的方法,其特征在于,步骤(6)进一步可分为: (6-1)根据所述资源单元,节点B利用下述两个公式分别对调度和非调度资源进行归一化,计算调度资源和非调度资源总的资源数目: 8. The method according to claim 2, wherein step (6) is further divided into: (6-1) according to the resource unit, a Node B by the following two formulas are scheduled and non-scheduled resources normalized to calculate the total number of non-scheduled resources and resource scheduling resources:
    Figure CN101277177BC00041
    其中,SF= 16,i_s表示第i个调度时隙,上式中应该是i_s= 1,类似地,i_ns表示第i个非调度时隙,i_ns = 1,整个公式表示的是从1叠加到ts_s或者ts_ns,即多个时隙的和,sf_s为调度对应的扩频因子,ts_s为调度对应的时隙资源,sf_ns为非调度对应的扩频因子,ts_ns为非调度对应的时隙资源;(6-2)将资源单位数目N折算得到TBS资源表中所在资源等级的列数,结合用户设备UE上报的TBS值的索引,在TBS资源表中查到对应的节点B的TBS值,并采用UE上报的调制方式进行解调。 Where, SF = 16, i_s denotes the i-th scheduled time slots, the formula should be i_s = 1, similarly, I_ns denotes the i th non-scheduled time slots, i_ns = 1, represents the whole formula is from 1 to superimposed ts_s or ts_ns, i.e., a plurality of slots and, sf_s scheduling corresponding spreading factor, ts_s corresponding slot resource scheduling, sf_ns non-scheduled corresponding to the spreading factor, ts_ns non-scheduled time slots corresponding to the resource; (6-2) the number of resource units converted to give the number of columns N TBS resource table resides resource level, in conjunction with TBS index values ​​reported by the user equipment UE, found TBS corresponding to a value of the node B in TBS resource table, and reported by the UE using the modulation scheme is demodulated.
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