CN100473220C - Realizing method for TD-SCDMA receiving timed error LCR measurement - Google Patents

Abstract

The present invention is LCR measurement method of reception timing deviation in TD-SCDMA. LCR measurement of reception timing deviation is realized through calculating the difference between the starting time corresponding to the time slot of the user's equipment and the first received upwards multipath timing, and is used in providing the user's equipment with time preact information and location service. The starting time corresponding to the time slot is calculated with the timing GPS, the first received upwards multipath timing is obtained through processing the channel impact response peak the user's equipment receives in the time slot, and the impact response peak is extracted from the first upward time slot in the first upward frame the user's equipment receives in the time slot. The present invention can reach measurement accuracy of 1/ 8 chip.

Description

A kind of TD-SCDMA receives the implementation method that timing offset LCR measures

Technical field

The present invention relates to the radio mobile communication field to the timing advance calculating of subscriber equipment (UE) with to the subscriber equipment orientation problem, relate in particular to the implementation method that the low spreading rate (LCR) of a kind of reception timing offset based on impulse response is measured.

Background technology

In the radio mobile communication field, the difference that receives method that timing offset LCR measures and be the timing of first up multipath that time started of the corresponding time slot by calculating subscriber equipment and UE receive at this time slot realizes.Fig. 1 is for describing the structure chart of the implication that receives timing offset.

The reception timing offset is defined as:

TRXdev=TTS-TRXpath, unit are chip.

TRXpath: in testing process, the timing of first up multipath that Node B receives.

TTS: the time started of the corresponding time slot that calculates according to Node B internal timing.

TTS can regularly calculate according to the GPS of base station, and the implementation of the timing of first up multipath that Node B receives can be different.

In the prior art, also do not find a kind of good realization to receive the timing offset Calculation Method, implementation method of the present invention can satisfy the requirement on the agreement.

Summary of the invention

The object of the present invention is to provide a kind of TD-SCDMA to receive the implementation method that timing offset LCR measures, can reach the certainty of measurement of 1/8chip, realize receiving the calculating of timing offset, be used to solve to the timing advance calculating of subscriber equipment with to the subscriber equipment orientation problem.

The object of the present invention is achieved like this:

The invention discloses a kind of TD-SCDMA and receive the implementation method that timing offset LCR measures, the difference of the timing of first up multipath that the time started of the corresponding time slot by calculating subscriber equipment and UE receive at this time slot realizes receiving timing offset LCR and measures, thereby be used to provide subscriber equipment Timing Advance information and positioning service, the time started of described corresponding time slot calculates by the timing of GPS, and the timing of the up multipath signal of first that receives is handled by the channel impulse response peak value that described time slot is received subscriber equipment and obtained; Wherein, the channel impulse response of subscriber equipment being obtained peak value may further comprise the steps:

1.1) calculate the channel impulse response of coded combination channel CCTrCH of first time slot of first subframe that subscriber equipment uses;

1.2) described channel impulse response is carried out 2 times of interpolation;

1.3) calculate the average power on each antenna of the channel impulse response after 2 times of interpolation, obtain being used for the channel impulse response of peak value coarse scanning:

1.4) value that is used for each point on the channel impulse response of peak value coarse scanning carries out the peak value coarse scanning, obtains peak point.

Described TD-SCDMA receives the implementation method that timing offset LCR measures, also comprise: with the coded combination channel CCTrCH of UE finish after average impulse response regularly CIR as input, from the mapping table of UE and Midamble sign indicating number skew original position, obtain a Midamble sign indicating number skew original position of current UE, as the impulse response of a plurality of antennas in the Midamble sign indicating number skew of the CCTrCH of this UE CIR series regularly.

Described antenna number can value 1,2,4 or 8.

Its impulse response peak value is extracted in first ascending time slot the inside that receives first uplink frame of subscriber equipment from described time slot, comprises the steps:

Step 1, the channel impulse response of the CCTrCH of first time slot of first subframe that calculating UE uses:

${h\′}^{\left(\mathrm{ka}\right)}=\mathrm{impulse}\_\mathrm{re}\_\mathrm{spons}{e}_{\mathrm{av}}^{(\mathrm{ka},\mathrm{km})},$ Km is km user;

Step 2, channel impulse response is carried out the twice interpolation, find out peak point, through becoming after 2 times of interpolation

Interpolating function is:

$f_{\mathrm{int}2}\left(\mathrm{jj}\right)=c\·[(1+\cos \left(\frac{2\mathrm{\π}\left(\mathrm{jj}\right)}{2M}\right))\·\frac{\sin \left(\frac{\mathrm{\π}\left(\mathrm{jj}\right)}{2}\right)}{\left(\frac{\mathrm{\π}\left(\mathrm{jj}\right)}{2}\right)}],$ $\mathrm{jj}=-\frac{2M}{2}\·\·\·\frac{2M}{2}$

Wherein, M is an even number, is the quantity that participates in the original sampling point of interpolation, and c is an interpolation factor, is used for the normalization interpolating function;

M is generally 6, and interpolation factor c is according to the relative position of f int2 (jj) and participate in the sampling point relative position of interpolation and correspondingly get certain numerical value.

Step 3, through after 2 times of interpolation, be output as:

$h_{\mathrm{ov},2i}^{\′\left(\mathrm{ka}\right)}=h_i^{\′\left(\mathrm{ka}\right)},$ i＝0，...，P-1

$h_{\mathrm{ov},2i+1}^{\′\left(\mathrm{ka}\right)}=\underset{i\′=-M/2+1}{\overset{M/2}{\mathrm{\Σ}}}{h}_{i\′+i}^{\′\left(\mathrm{ka}\right)}\·f_{\mathrm{int}2}(2i\′-1),$ i＝0，...，P-1

Step 4 is to the value after the twice interpolation

Handle, calculate the average power on each antenna, obtain being used for the channel impulse response of peak value coarse scanning

$h_{\mathrm{test},\mathrm{jj}}^{\left(\mathrm{km}\right)}=\frac{1}{K_a}\underset{\mathrm{ka}=0}{\overset{\mathrm{Ka}-1}{\mathrm{\Σ}}}{\left|\right|h_{\mathrm{ov},\mathrm{jj}}^{\′\left(\mathrm{ka}\right)}\left|\right|}^2,$ jj＝0…2P-1

Step 5 utilizes the value of each point in the impulse response to carry out the peak value coarse scanning; According to given power threshold

Peak point

Be to find out the formula that makes

The index i (i=0..2W-2) of value maximum;

By formula ${\mathrm{\ϵ}}_{\mathrm{thresh}}^2=\mathrm{Piip}\_\mathrm{rel}\×{10}^{n_{\mathrm{thresh}}^2/10}$ Obtain;

Wherein, P is that Midamble sign indicating number cycle, Piip_rel are the average interference power in each tap,

Default value is 6dB.

Described interpolation is to carry out in the cycle, for i＜0 and i〉index of p-1 handles as follows:

$i=\left\{\begin{array}{c}P+1;i<0\\ i-P;i>P-1\\ i;\mathrm{else}\end{array}\right.$

Step 6 is carried out 4 times of interpolation to the coarse scanning peak value of trying to achieve, and is used to reach the certainty of measurement of 1/8chip,

With

Between to carry out 4 times the interpolating function of interpolation as follows:

$f_{\mathrm{int}4}\left(x\right)=c\&CenterDot;[\frac{1}{2}(1+\cos \left(\frac{2\mathrm{\&pi;}\left(x\right)}{4M}\right))\&CenterDot;\frac{\sin \left(\frac{\mathrm{\&pi;}\left(x\right)}{4}\right)}{\left(\frac{\mathrm{\&pi;}\left(x\right)}{4}\right)}],$ $x=-\frac{4M}{2}\&CenterDot;\&CenterDot;\frac{4M}{2}---\left(9\right)$

Wherein, M is an even number, and c is an interpolation factor;

M is generally 6, and interpolation factor c is according to the relative position of fint4 (x) and participate in the sampling point relative position of interpolation and correspondingly get certain numerical value.

Step 7, other 3 sampling points that insert between two tap j ' and j '+1 are obtained by following formula:

$x\left(j\right)=\underset{i\&prime;=-M/2+1}{\overset{M/2}{\mathrm{\&Sigma;}}}{h_{\mathrm{test},j\&prime;+i\&prime;}\&CenterDot;f}_{\mathrm{int}4}(4i\&prime;-j),$ j＝1··3 (10)

Step 8, to

With

Between 4 points carrying out after the interpolation carry out the close scanning of peak point again, find out the formula that makes

The index i (i=0..8W-2) of value maximum, wherein W ' is a natural number, obtains the peak point of 1/8chip precision

Described interpolation is to carry out in the cycle, for i＜0 and i〉index of P-1 handles as follows:

$i=\left\{\begin{array}{c}P+1;i<0\\ i-P;i>P-1\\ i;\mathrm{else}\end{array}\right.$

TD-SCDMA provided by the invention receives the implementation method that timing offset LCR measures, and can reach the certainty of measurement of 1/8chip, realizes receiving the calculating of timing offset, is used to solve to the timing advance calculating of subscriber equipment with to the subscriber equipment orientation problem.

Description of drawings

Fig. 1 is for describing the structure chart of the implication that receives timing offset;

Fig. 2 is the flow chart of method of the present invention.

Embodiment

Referring to Fig. 2, the flow chart of method of the present invention illustrates detailed implementation procedure of the present invention.The present invention is the timing of calculating first up multipath that Node B receives by the channel impulse response that utilizes Node B to receive UE.Its impulse response peak value is extracted in first ascending time slot the inside that receives first uplink frame of UE from Node B, by comparing peak value and system difference regularly, just can calculate reception timing offset LCR.System can calculate by the timing of GPS, and the Midamble sequence of the UE that receives with Node B is determined its impulse response peak value.Finally, can calculate the Timing Advance information of Node B by estimation, and can be used for the positioning service of UE to UE to reception timing offset LCR.

The CCTrCH (coded combination channel) of UE is finished CIR (impulse response regularly) after average as importing, from the mapping table of UE and Midamble sign indicating number skew original position, obtain a Midamble sign indicating number skew original position (no matter what CCTrCH this UE has) of current UE, the CIR series of a plurality of antennas during a Midamble sign indicating number that is used as the CCTrCH of this UE is offset (antenna number can value 1,2,4 or 8).

Describe treatment step of the present invention below in detail:

Whole process is divided into 2 times of interpolation, power calculation, time delay bigness scale, 4 times of interpolation, time delay accurate measurements and receives timing offset LCR to be calculated for six steps and finishes.

The first step, under the situation of twice interpolation, find out peak point:

1, the channel impulse response of the CCTrCH of first time slot of first subframe (i.e. processing unit) of calculating UE use, S100, S101:

(be designated as h ' ^(ka), km is km user) and (1)

2, through becoming behind 2 times of interpolation S102

Interpolating function is as follows:

$f_{\mathrm{int}2}\left(\mathrm{jj}\right)=c\&CenterDot;[(1+\cos \left(\frac{2\mathrm{\&pi;}\left(\mathrm{jj}\right)}{2M}\right))\&CenterDot;\frac{\sin \left(\frac{\mathrm{\&pi;}\left(\mathrm{jj}\right)}{2}\right)}{\left(\frac{\mathrm{\&pi;}\left(\mathrm{jj}\right)}{2}\right)}],$ $\mathrm{jj}=-\frac{2M}{2}\&CenterDot;\&CenterDot;\&CenterDot;\frac{2M}{2}---\left(2\right)$

Here M is an even number, is the quantity that participates in the original sampling point of interpolation, and recommendation is 6.C is used for the normalization interpolating function, and its value sees Table 1.

The interpolation factor c (M=6) of 2 times of interpolation of table 1

Index	Fint2 (jj) relative position	Participate in the sampling point relative position of interpolation	The value of c
				0	-5	-2	282
1	-3	-1	-3502
				2	-1	0	19604
3	1	1	19604
				4	3	2	-3502
5	5	3	282

3, through after 2 times of interpolation, output is expressed as:

$h_{\mathrm{ov},2i}^{\&prime;\left(\mathrm{ka}\right)}=h_i^{\&prime;\left(\mathrm{ka}\right)},$ i＝0，...，P-1 (3)

$h_{\mathrm{ov},2i+1}^{\&prime;\left(\mathrm{ka}\right)}=\underset{i\&prime;=-M/2+1}{\overset{M/2}{\mathrm{\&Sigma;}}}{h}_{i\&prime;+i}^{\&prime;\left(\mathrm{ka}\right)}\&CenterDot;f_{\mathrm{int}2}(2i\&prime;-1),$ i＝0，...，P-1 (4)

4, interpolation is to carry out in the cycle, promptly for i＜0 and i〉index of P-1 handles as follows:

$i=\left\{\begin{array}{c}P+1;i<0\\ i-P;i>P-1\\ i;\mathrm{else}\end{array}\right.---\left(5\right)$

In second step, utilize the value power after the twice interpolation to calculate S103.

1, the channel impulse response that is used for the peak value coarse scanning

Be right

The average power of calculating on each antenna obtains, that is:

$h_{\mathrm{test},\mathrm{jj}}^{\left(\mathrm{km}\right)}=\frac{1}{K_a}\underset{\mathrm{ka}=0}{\overset{\mathrm{Ka}-1}{\mathrm{\&Sigma;}}}{\left|\right|h_{\mathrm{ov},\mathrm{jj}}^{\&prime;\left(\mathrm{ka}\right)}\left|\right|}^2,$ jj＝0…2P-1 (6)

In the 3rd step, utilize the value of each point in the impulse response to carry out peak value coarse scanning, S104.

1, peak value coarse scanning part is according to given power threshold

Peak point

Be to find out the formula that makes

$h_{\mathrm{test},i}^{\left(\mathrm{km}\right)}+h_{\mathrm{test},i+1}^{\left(\mathrm{km}\right)}---\left(7\right)$

The index i (i=0..2W-2) of value maximum.

By formula

${\mathrm{\&epsiv;}}_{\mathrm{thresh}}^2=\mathrm{Piip}\_\mathrm{rel}\&times;{10}^{n_{\mathrm{thresh}}^2/10}---\left(8\right)$

Obtain.Wherein P is that Midamble sign indicating number cycle, Piip_rel are the average interference power in each tap,

Default value is 6dB.

In the 4th step, the coarse scanning peak value of trying to achieve is carried out 4 times of interpolation, S105.

In order to reach the certainty of measurement of 1/8chip, need

With

Between carry out 4 times interpolation.Interpolating function is as follows:

$f_{\mathrm{int}4}\left(x\right)=c\&CenterDot;[\frac{1}{2}(1+\cos \left(\frac{2\mathrm{\&pi;}\left(x\right)}{4M}\right))\&CenterDot;\frac{\sin \left(\frac{\mathrm{\&pi;}\left(x\right)}{4}\right)}{\left(\frac{\mathrm{\&pi;}\left(x\right)}{4}\right)}],$ $x=-\frac{4M}{2}\&CenterDot;\&CenterDot;\frac{4M}{2}---\left(9\right)$

Wherein M is an even number, and recommendation is 6.The value of c sees Table 2.

The interpolation factor c (M=6) of 4 times of interpolation of table 2

j	Fint4 (x) relative position	Participate in the sampling point relative position of interpolation	The value of c
				1	-9	-2	710
1	-5	-1	-4007
				1	-1	0	29149
1	3	1	8620
				1	7	2	-1858
1	11	3	154
				2	-10	-2	527
2	-6	-1	-3917
				2	-2	0	19774
2	2	1	19774
				2	6	2	-3917
2	10	3	527
				3	-11	-2	154
3	-7	-1	-1858
				3	-3	0	8620
3	1	1	29149
				3	5	2	-4007
3	9	3	710

Other 3 sampling points that insert between two tap j ' and j '+1 obtain (interpolation circulates equally) by following formula:

$x\left(j\right)=\underset{i\&prime;=-M/2+1}{\overset{M/2}{\mathrm{\&Sigma;}}}{h_{\mathrm{test},j\&prime;+i\&prime;}\&CenterDot;f}_{\mathrm{int}4}(4i\&prime;-j),$ j＝1··3 (10)

In the 5th step, the value after 4 times of interpolation is carried out close scanning, S106:

To

With Between 4 points carrying out after the interpolation carry out the close scanning of peak point again, obtain the peak point of 1/8 precision

Be to find out the formula that makes

The index i (i=0..8W-2) of value maximum.

In the 6th step, receive timing offset LCR and calculate.

At last, compare the result who obtains with according to the time slot time started that inside of base station regularly calculates, S107, difference is exactly the result that need report.

Claims (10)

1. a TD-SCDMA receives the implementation method that timing offset LCR measures, the difference of the timing of first up multipath signal that the time started of the corresponding time slot by calculating subscriber equipment and subscriber equipment receive at this time slot realizes receiving timing offset LCR and measures, thereby be used to provide subscriber equipment Timing Advance information and positioning service, it is characterized in that, the time started of described corresponding time slot is regularly to calculate by system, and the timing of described first the up multipath signal that receives is that the peak value that obtains the channel impulse response by the subscriber equipment that receives from this time slot is handled and obtained;

Wherein, the step of obtaining peak value the channel impulse response of the subscriber equipment that receives from this time slot may further comprise the steps:

1.1) calculate the channel impulse response of coded combination channel CCTrCH of first time slot of first subframe that subscriber equipment uses;

1.2) described channel impulse response is carried out 2 times of interpolation;

1.3) calculate the average power on each antenna of the channel impulse response after 2 times of interpolation, obtain being used for the channel impulse response of peak value coarse scanning:

1.4) value that is used for each point on the channel impulse response of peak value coarse scanning carries out the peak value coarse scanning, obtains peak point.

2. TD-SCDMA as claimed in claim 1 receives the implementation method that timing offset LCR measures, it is characterized in that,

Step 1.1) channel impulse response h ' ^(ka)For: ${h\&prime;}^{\left(\mathrm{ka}\right)}=\mathrm{impulse}\_\mathrm{re}\_\mathrm{spons}{e}_{\mathrm{av}}^{(\mathrm{ka},\mathrm{km})},$

Wherein, km is km user; Av is average impulse response, and ka is 1,2,4 or 8;

Step 1.2) in through channel impulse response h ' after 2 times of interpolation ^(ka)Become

Interpolating function is:

$f_{\mathrm{int}2}\left(\mathrm{jj}\right)=c\&CenterDot;[(1+\cos \left(\frac{2\mathrm{\&pi;}\left(\mathrm{jj}\right)}{2M}\right))\&CenterDot;\frac{\sin \left(\frac{\mathrm{\&pi;}\left(\mathrm{jj}\right)}{2}\right)}{\left(\frac{\mathrm{\&pi;}\left(\mathrm{jj}\right)}{2}\right)}],\mathrm{jj}=-\frac{2M}{2}\&CenterDot;\&CenterDot;\&CenterDot;\frac{2M}{2}$

Wherein, M is an even number, is the quantity that participates in the original sampling point of interpolation, and c is an interpolation factor, is used for the normalization interpolating function;

After 2 times of interpolation, the value that the output impulse response is every is:

$h_{\mathrm{ov},2i}^{\&prime;\left(\mathrm{ka}\right)}=h_i^{\&prime;\left(\mathrm{ka}\right)},i=0,...,P-1$

$h_{\mathrm{ov},2i+1}^{\&prime;\left(\mathrm{ka}\right)}=\underset{i\&prime;=-M/2+1}{\overset{M/2}{\mathrm{\&Sigma;}}}{h}_{i\&prime;+i}^{\&prime;\left(\mathrm{ka}\right)}\&CenterDot;f_{\mathrm{int}2}(2i\&prime;-1),i=0,...,P-1$

Step 1.3) is used for the channel impulse response of peak value coarse scanning For:

$h_{\mathrm{test},\mathrm{jj}}^{\left(\mathrm{km}\right)}=\frac{1}{K_a}\underset{\mathrm{ks}=0}{\overset{\mathrm{Ka}-1}{\mathrm{\&Sigma;}}}{\left|\right|h_{\mathrm{ov},\mathrm{jj}}^{\&prime;\left(\mathrm{ka}\right)}\left|\right|}^2,\mathrm{jj}=0\&CenterDot;\&CenterDot;\&CenterDot;2P-1$

Wherein, Ka is an antenna number;

Step 1.4) be specially:

According to given power threshold

Peak point Be to find out to make formula The index i of value maximum, i=0..2W-2;

${\mathrm{\&epsiv;}}_{\mathrm{thresh}}^2=\mathrm{Piip}\_\mathrm{rel}\&times;{10}^{{\mathrm{\&eta;}}_{\mathrm{thresh}}^2/10};$

Wherein, W is a natural number, and P is that Midamble sign indicating number cycle, Piip_rel are the average interference power in each tap,

Default value is 6dB.

3. TD-SCDMA as claimed in claim 2 receives the implementation method that timing offset LCR measures, and it is characterized in that described interpolation is to carry out in the cycle, for i＜0 and i〉index of P-1 handles as follows:

$i=\left\{\begin{array}{c}P+1;i<0\\ i-P;i>P-1\\ i;\mathrm{else}\end{array}\right..$

4. TD-SCDMA as claimed in claim 2 receives the implementation method that timing offset LCR measures, and it is characterized in that M is 6, and interpolation factor c is according to f _Int2(jj) relative position and participate in the sampling point relative position of interpolation and correspondingly get certain numerical value.

5. TD-SCDMA as claimed in claim 2 receives the implementation method that timing offset LCR measures, and it is characterized in that, also comprises:

Step 1.6 is carried out 4 times of interpolation to the coarse scanning peak value of trying to achieve, and is used to reach the certainty of measurement of 1/8chip,

With

Between to carry out 4 times the interpolating function of interpolation as follows:

$f_{\mathrm{int}4}\left(x\right)=c\&CenterDot;[\frac{1}{2}(1+\cos \left(\frac{2\mathrm{\&pi;}\left(x\right)}{4M}\right))\&CenterDot;\frac{\sin \left(\frac{\mathrm{\&pi;}\left(x\right)}{4}\right)}{\left(\frac{\mathrm{\&pi;}\left(x\right)}{4}\right)}],x=-\frac{4M}{2}\&CenterDot;\&CenterDot;\frac{4M}{2}---\left(9\right)$

Wherein, M is an even number, and c is an interpolation factor;

Step 1.7, other 3 sampling points that insert between two tap j ' and j '+1 are obtained by following formula:

$x\left(j\right)=\underset{i\&prime;=-M/2+1}{\overset{M/2}{\mathrm{\&Sigma;}}}{h}_{\mathrm{test},j\&prime;+i\&prime;}\&CenterDot;f_{\mathrm{int}4}(4i\&prime;-j),j=1\&CenterDot;\&CenterDot;3---\left(10\right)$

Wherein, tap j ' is 0～255;

Step 1.8, to

With

Between 4 points carrying out after the interpolation carry out the close scanning of peak point again, find out the formula that makes

The index i of value maximum, i=0..8W '-2, wherein W ' is a natural number, to obtain the peak point of 1/8chip precision

6. TD-SCDMA as claimed in claim 5 receives the implementation method that timing offset LCR measures, and it is characterized in that described interpolation is to carry out in the cycle, for i＜0 and i〉index of P-1 handles as follows:

$i=\left\{\begin{array}{c}P+1;i<0\\ i-P;i>P-1\\ i;\mathrm{else}\end{array}\right..$

7. TD-SCDMA as claimed in claim 5 receives the implementation method that timing offset LCR measures, and it is characterized in that M is 6, and interpolation factor c is according to f _Int4(x) relative position and participate in the sampling point relative position of interpolation and corresponding value.

8. receive the implementation method that timing offset LCR measures as claim 2 or 5 described TD-SCDMA, it is characterized in that, this method also comprises: with the average impulse response CIR of the coded combination channel CCTrCH of subscriber equipment as input, from the mapping table of subscriber equipment and Midamble sign indicating number skew original position, obtain a Midamble sign indicating number skew original position of current user equipment, will be offset the impulse response CIR series of the CIR of original position correspondence with this Midamble sign indicating number as a plurality of antennas in the Midamble sign indicating number skew of a coded combination channel CCTrCH of this subscriber equipment.

9. realize that TD-SCDMA receives first up multipath signal method regularly for one kind,

It is characterized in that, extract the impulse response peak value from first ascending time slot the inside that receives first subframe of subscriber equipment, comprise the steps: step 1, the channel impulse response of the coded combination channel CCTrCH of first time slot of first subframe that the calculating subscriber equipment uses:

${h\&prime;}^{\left(\mathrm{ka}\right)}=\mathrm{impulse}\_\mathrm{re}\_\mathrm{spons}{e}_{\mathrm{av}}^{(\mathrm{ka},\mathrm{km})}$

Km is km user, and av is average impulse response, and ka is 1,2,4 or 8;

Step 2, channel impulse response is carried out the twice interpolation, through becoming after 2 times of interpolation Interpolating function is:

$f_{\mathrm{int}2}\left(\mathrm{jj}\right)=c\&CenterDot;[(1+\cos \left(\frac{2\mathrm{\&pi;}\left(\mathrm{jj}\right)}{2M}\right))\&CenterDot;\frac{\sin \left(\frac{\mathrm{\&pi;}\left(\mathrm{jj}\right)}{2}\right)}{\left(\frac{\mathrm{\&pi;}\left(\mathrm{jj}\right)}{2}\right)}],\mathrm{jj}=-\frac{2M}{2}\&CenterDot;\&CenterDot;\&CenterDot;\frac{2M}{2}$

Wherein, M is the quantity of the original sampling point of participation interpolation, and c is an interpolation factor;

Step 3, through after 2 times of interpolation, the value of every of impulse response of output is:

$h_{\mathrm{ov},2i}^{\&prime;\left(\mathrm{ka}\right)}=h_i^{\&prime;\left(\mathrm{ka}\right)},i=0,...,P-1$

$h_{\mathrm{ov},2i+1}^{\&prime;\left(\mathrm{ka}\right)}=\underset{i\&prime;=-M/2+1}{\overset{M/2}{\mathrm{\&Sigma;}}}{h}_{i\&prime;+i}^{\&prime;\left(\mathrm{ka}\right)}\&CenterDot;f_{\mathrm{int}2}(2i\&prime;-1),i=0,...,P-1$

Step 4 is to the value after the twice interpolation

Handle, calculate the average power on each antenna, obtain being used for the channel impulse response of peak value coarse scanning

$h_{\mathrm{test},\mathrm{jj}}^{\left(\mathrm{km}\right)}=\frac{1}{K_a}\underset{\mathrm{ks}=0}{\overset{\mathrm{Ka}-1}{\mathrm{\&Sigma;}}}{\left|\right|h_{\mathrm{ov},\mathrm{jj}}^{\&prime;\left(\mathrm{ka}\right)}\left|\right|}^2,\mathrm{jj}=0\&CenterDot;\&CenterDot;\&CenterDot;2P-1$

Wherein, Ka is an antenna number;

Step 5 utilizes the value of each point in the impulse response to carry out the peak value coarse scanning; According to given power threshold Peak point

Be to find out the formula that makes

The index i of value maximum, i=0..2W-2;

By formula ${\mathrm{\&epsiv;}}_{\mathrm{thresh}}^2=\mathrm{Piip}\_\mathrm{rel}\&times;{10}^{{\mathrm{\&eta;}}_{\mathrm{thresh}}^2/10}$ Obtain;

Wherein, P is that Midamble sign indicating number cycle, Piip_rel are the average interference power in each tap,

Default value is 6dB.

10. as described in claim 9, realize that TD-SCDMA receives first up multipath signal method regularly, it is characterized in that, also comprise:

Step 6 is carried out 4 times of interpolation to the coarse scanning peak value of trying to achieve, and is used to reach the certainty of measurement of 1/8chip,

With

Between to carry out 4 times the interpolating function of interpolation as follows:

$f_{\mathrm{int}4}\left(x\right)=c\&CenterDot;[\frac{1}{2}(1+\cos \left(\frac{2\mathrm{\&pi;}\left(x\right)}{4M}\right))\&CenterDot;\frac{\sin \left(\frac{\mathrm{\&pi;}\left(x\right)}{4}\right)}{\left(\frac{\mathrm{\&pi;}\left(x\right)}{4}\right)}],x=-\frac{4M}{2}\&CenterDot;\&CenterDot;\frac{4M}{2}$

Wherein, M is an even number, and c is an interpolation factor;

Step 7, other 3 sampling points that insert between two tap j ' and j '+1 are obtained by following formula:

$x\left(j\right)=\underset{i\&prime;=-M/2+1}{\overset{M/2}{\mathrm{\&Sigma;}}}{h}_{\mathrm{test},j\&prime;+i\&prime;}\&CenterDot;f_{\mathrm{int}4}(4i\&prime;-j),j=1\&CenterDot;\&CenterDot;3$

Wherein, tap j ' is 0～255;

Step 8, to With Between 4 points carrying out after the interpolation carry out the close scanning of peak point again, find out the formula that makes

The index i of value maximum, i=0..8W '-2, wherein W ' is a natural number, to obtain the peak point of 1/8chip precision

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