CN100401665C - A method for judging the byte loss of reverse data packet - Google Patents
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Abstract
本发明公开了一种判断反向数据包字节丢失的方法,该方法的一种实现方式为:确定当前解码成功的反向数据包的等待时长,并判断在等待时长之内,是否收到在当前反向数据包中的字节之前发送的反向字节,如果没有收到则认为发生反向字节丢失。该方法的另一种实现方式为设置包缓存队列,包括:确定当前解码成功的反向数据包的等待时长,并将该反向数据包放入包缓存队列,在等待时长到达时,将包缓存队列中,上述解码成功的反向数据包及其之前的反向数据包选出,作为排好序的反向数据包,并判断在排好序的反向数据包中是否有字节缺失,如果是则认为发生反向字节丢失。采用本发明提供的技术方案,可以避免错误的将乱序反向数据包认定为反向字节丢失。
The invention discloses a method for judging the byte loss of a reverse data packet. An implementation of the method is to determine the waiting time of the currently decoded reverse data packet, and judge whether it is received within the waiting time. The reverse byte sent before the byte in the current reverse packet, if it is not received, it is considered to have occurred reverse byte loss. Another implementation of this method is to set the packet buffer queue, including: determine the waiting time of the reverse data packet that is currently decoded successfully, and put the reverse data packet into the packet buffer queue. When the waiting time arrives, the packet In the buffer queue, the above-mentioned successfully decoded reverse data packets and their previous reverse data packets are selected as sorted reverse data packets, and it is judged whether there are any missing bytes in the sorted reverse data packets , if it is, it is considered that a reverse byte loss has occurred. By adopting the technical scheme provided by the invention, it is possible to avoid mistakenly identifying the out-of-sequence reverse data packet as reverse byte loss.
Description
技术领域 technical field
本发明涉及移动通信技术,特别是涉及一种判断反向数据包字节丢失的方法。The invention relates to mobile communication technology, in particular to a method for judging the byte loss of reverse data packets.
背景技术 Background technique
码分多址(Code Division Multiple Access,CDMA)2000系统的新型数据业务(Evolution Data Optimized,EV-DO)已经由最初的Rev 0版本发展到了Rev A版本。图1示意了在EV-DO Rev A中,作为接受方的基站收到作为发送方的移动终端发来的反向数据包时的效果。The new data service (Evolution Data Optimized, EV-DO) of Code Division Multiple Access (CDMA) 2000 system has been developed from the
在EV-DO Rev A中,在移动终端上,每个要发送的反向数据包被分成4个子包,其中第一个子包携带了原数据包的所有有效信息和部分冗余信息,其他3个数据包均携带帮助解码的冗余信息;同时,有三个交织号分别为0、1、2的三个交织,这三个交织用于发送分属三个不同反向数据包的子包。一个反向数据包的所有子包,由交织号相同的交织发送。由于移动终端到基站之间的无线信道的变化很剧烈,在基站上,对于每个数据包而言,有可能收到第一个子包就能成功解码,也有可能在收到第二、第三、第四子包后才能解码成功,甚至最终都没有解码成功。如果基站在收到第一子包后没有解码成功,那么会通过由基站到移动终端的前向反馈发送Nak给移动终端,让移动终端再发第二个子包;如果基站在收到第一子包后解码成功,那么会通过前向反馈发Ack给移动终端,移动终端开始第一子包所在交织发送一个新的数据包,依此类推。在图1中,反向数据包A由交织号为0的交织发送,并且在第一个子包A0就解码成功,基站通过前向反馈发送Ack给移动终端,这样移动终端下一次在交织号为0的交织发送的就是反向数据包D的第一个子包D0;反向数据包B的4个子包B0、B1、B2、和B3,全部由交织号为1的交织发送,在第四个子包B3才解码成功,因此在基站收到B0、B1和B2后都会通过前向反馈发送Nak给移动终端,让移动终端接着发下一个子包;反向数据包C由交织号为2的交织发送,并且在第一个子包C0就解码成功,基站通过前向反馈发送Ack给移动终端,这样下一次在交织号为2的交织发送的就是反向数据包E的第一个子包E0,等等。采用这种交织发送的方法,可以实现反向数据包的提前终止,提高了反向数据速率,但同时也使得反向数据包可能出现顺序错乱。例如在图1中,在发送端,反向数据包B是在反向数据包C之前开始发送的;但是在接受端,由于反向数据包B在第四个子包才解码成功,而反向数据包C在第一个子包就解码成功,因此C比B先完成解码。In EV-DO Rev A, on the mobile terminal, each reverse data packet to be sent is divided into 4 sub-packets, the first sub-packet carries all the valid information and some redundant information of the original data packet, and the other The three data packets all carry redundant information to help decoding; at the same time, there are three interleaving numbers of 0, 1, and 2, which are used to send sub-packets belonging to three different reverse data packets . All subpackets of a reverse data packet are sent by the same interleave with the same interleave number. Since the wireless channel between the mobile terminal and the base station changes drastically, on the base station, for each data packet, it is possible to successfully decode the first subpacket received, and it is also possible to decode it successfully after receiving the second and second packets. 3. Only after the fourth subpackage can the decoding be successful, and even the decoding is not successful in the end. If the base station does not decode successfully after receiving the first subpacket, it will send Nak to the mobile terminal through the forward feedback from the base station to the mobile terminal, so that the mobile terminal can send the second subpacket; if the base station receives the first subpacket After the packet is successfully decoded, an Ack will be sent to the mobile terminal through forward feedback, and the mobile terminal will start interleaving and sending a new data packet at the location of the first subpacket, and so on. In Figure 1, the reverse data packet A is sent by the
反向数据包的解码工作是由基站收发信机(Base Transceiver Station,BTS)完成的,BTS将解码完成的反向数据包传送到基站控制器(Base StationController,BSC)。在现有技术中,如果出现上述的反向数据包C比反向数据包B先完成解码的情况,BSC上的无线链路协议(Radio Link Protocol,RLP)模块在处理反向数据包的字节时,发现反向数据包A所包含的字节后面紧跟的是反向数据包C所包含的字节,则认为反向数据包B所包含的字节丢失,通知移动终端重发反向数据包B。实际上反向数据包B只是延迟到达而已,这样就会造成不必要的反向数据包重发,影响反向通信的速率。The decoding of the reverse data packet is completed by the base transceiver station (Base Transceiver Station, BTS), and the BTS transmits the decoded reverse data packet to the base station controller (Base Station Controller, BSC). In the prior art, if the above-mentioned reverse data packet C is decoded earlier than the reverse data packet B, the radio link protocol (Radio Link Protocol, RLP) module on the BSC is processing the word of the reverse data packet. When it is found that the byte contained in the reverse data packet A is followed by the byte contained in the reverse data packet C, it is considered that the byte contained in the reverse data packet B is lost, and the mobile terminal is notified to resend the reverse data packet. To packet B. In fact, the reverse data packet B is only delayed in arrival, which will cause unnecessary retransmission of the reverse data packet and affect the rate of reverse communication.
发明内容 Contents of the invention
有鉴于此,本发明的主要目的在于提供一种反向判断数据包字节丢失的方法,以防止在乱序反向数据包的情况下基站控制器错误认为反向数据包中的字节丢失,从而避免不必要的反向数据包重复发送。In view of this, the main purpose of the present invention is to provide a method for reverse judgment data packet byte loss, to prevent the base station controller from mistakenly thinking that the byte in the reverse data packet is lost under the situation of out-of-order reverse data packet , so as to avoid unnecessary repeated sending of reverse data packets.
为了达到上述目的,本发明提供了一种判断反向数据包字节丢失的方法,该方法的第一种实现方式包括:In order to achieve the above object, the present invention provides a method for judging the loss of reverse data packet bytes, the first implementation of the method includes:
步骤A1,确定当前解码成功的反向数据包的等待时长,并判断在当前反向数据包中的字节之前发送的反向字节是否缺失,如果有则执行步骤B 1;Step A1, determine the waiting period of the current reverse data packet successfully decoded, and judge whether the reverse byte sent before the byte in the current reverse data packet is missing, and if so, perform step B1;
步骤B1,判断在步骤A1中得到的等待时长之内,是否收到在当前反向数据包中的字节之前发送的反向字节,如果没有收到则认为发生反向字节丢失,通知发送方重发丢失的反向字节。Step B1, judge whether the reverse byte sent before the byte in the current reverse data packet is received within the waiting time length obtained in step A1, if not received, it is considered that the reverse byte is lost, and the notification The sender resends the lost reverse bytes.
其中,步骤A1所述确定当前解码成功的反向数据包的等待时长包括:Wherein, the waiting period of determining the reverse data packet that is currently successfully decoded in step A1 includes:
步骤A11,基站收发信机将当前解码成功的反向数据包,以及当前反向数据包解码成功时产生的交织信息传送给基站控制器;Step A11, the base transceiver station transmits the currently successfully decoded reverse data packet and the interleaving information generated when the current reverse data packet is successfully decoded to the base station controller;
步骤A12,基站控制器判断当前反向数据包是否提前结束,如果是则执行步骤A13,否则认为等待时长为0;Step A12, the base station controller judges whether the current reverse data packet is terminated ahead of schedule, and if so, executes Step A13; otherwise, it is considered that the waiting time is 0;
步骤A13,基站控制器根据当前反向数据包解码成功时产生的交织信息,计算当前反向数据包的等待时长。Step A13, the base station controller calculates the waiting time of the current reverse data packet according to the interleaving information generated when the current reverse data packet is successfully decoded.
其中,步骤A1所述确定当前解码成功的反向数据包的等待时长包括:Wherein, the waiting period of determining the reverse data packet that is currently successfully decoded in step A1 includes:
步骤A21,基站收发信机判断当前反向数据包是否提前结束,如果是则执行步骤A22,否则认为等待时长为0;Step A21, the base transceiver station judges whether the current reverse data packet ends ahead of time, if so, executes step A22, otherwise considers that the waiting time is 0;
步骤A22,基站收发信机根据当前反向数据包解码成功时产生的交织信息,计算当前反向数据包的等待时长;Step A22, the base transceiver station calculates the waiting time of the current reverse data packet according to the interleaving information generated when the current reverse data packet is successfully decoded;
步骤A23,基站收发信机将解码成功的反向数据包,以及计算出的等待时长传送给基站控制器。Step A23, the base transceiver station transmits the successfully decoded reverse data packet and the calculated waiting time to the base station controller.
其中,步骤B1所述判断在步骤A1中得到的等待时长之内,是否收到在当前反向数据包中的字节之前发送的反向字节由基站控制器完成。Wherein, the judgment in step B1 whether the reverse byte sent before the byte in the current reverse data packet is received is completed by the base station controller within the waiting time obtained in step A1.
该方法的第二种实施方式为,设置包缓存队列,该方法包括:The second implementation manner of the method is to set a packet cache queue, and the method includes:
步骤A2,确定当前解码成功的反向数据包的等待时长,并将当前解码成功的反向数据包放入包缓存队列,然后开始为当前解码成功的反向数据包计时;Step A2, determine the waiting time of the current successfully decoded reverse data packet, put the current successfully decoded reverse data packet into the packet buffer queue, and then start timing the current successfully decoded reverse data packet;
步骤B2,在步骤A2中得到的等待时长到达时,将包缓存队列中,步骤A2中解码成功的反向数据包及其之前的反向数据包选出,作为排好序的反向数据包;Step B2, when the waiting time obtained in step A2 arrives, select the reverse data packet successfully decoded in step A2 and the previous reverse data packet in the packet cache queue as the sorted reverse data packet ;
步骤C2,判断在排好序的反向数据包中是否有字节缺失,如果是则认为发生反向字节丢失,通知发送方重发丢失的反向字节。Step C2, judging whether any byte is missing in the sorted reverse data packet, if so, consider that the reverse byte is lost, and notify the sender to resend the lost reverse byte.
其中,步骤A2所述将当前解码成功的反向数据包放入包缓存队列为:Wherein, the reverse data packets that are currently decoded successfully are put into the packet cache queue as described in step A2:
根据当前解码成功的反向数据包所携带的帧序号,判断当前解码成功的反向数据包,与包缓存队列中已有的反向数据包,在发送时的先后顺序,然后将当前解码成功的反向数据包放入包缓存队列。According to the frame sequence number carried by the currently decoded reverse data packet, judge the current successfully decoded reverse data packet and the existing reverse data packet in the packet buffer queue, in the order of sending, and then the current decoded successfully The reverse data packets are put into the packet buffer queue.
其中,步骤A2所述确定当前解码成功的反向数据包的等待时长包括:Wherein, the waiting period of determining the reverse data packet that is currently decoded successfully in step A2 includes:
步骤A31,基站收发信机将当前解码成功的反向数据包,以及当前反向数据包解码成功时产生的交织信息传送给基站控制器;Step A31, the base transceiver station transmits the currently successfully decoded reverse data packet and the interleaving information generated when the current reverse data packet is successfully decoded to the base station controller;
步骤A32,基站控制器判断当前反向数据包是否提前结束,如果是则执行步骤A33,否则认为等待时长为0;Step A32, the base station controller judges whether the current reverse data packet ends ahead of schedule, if so, executes step A33, otherwise considers that the waiting time is 0;
步骤A33,基站控制器根据当前反向数据包解码成功时产生的交织信息,计算当前反向数据包的等待时长。Step A33, the base station controller calculates the waiting time of the current reverse data packet according to the interleaving information generated when the current reverse data packet is successfully decoded.
其中,步骤A2所述确定当前解码成功的反向数据包的等待时长包括:Wherein, the waiting period of determining the reverse data packet that is currently decoded successfully in step A2 includes:
步骤A41,基站收发信机判断当前反向数据包是否提前结束,如果是则执行步骤A42,否则认为等待时长为0;Step A41, the base transceiver station judges whether the current reverse data packet ends ahead of schedule, if so, executes step A42, otherwise considers that the waiting time is 0;
步骤A42,基站收发信机根据当前反向数据包解码成功时产生的交织信息,计算当前反向数据包的等待时长。Step A42, the base transceiver station calculates the waiting time of the current reverse data packet according to the interleaving information generated when the current reverse data packet is successfully decoded.
其中,步骤A2所述将当前解码成功的反向数据包放入包缓存队列,然后开始为当前解码成功的反向数据包计时为:Wherein, as described in step A2, put the current successfully decoded reverse data packet into the packet buffer queue, and then start timing the current successfully decoded reverse data packet as:
基站收发信机将解码成功的反向数据包,以及步骤A42中计算出的等待时长传送给基站控制器,基站控制器将当前解码成功的反向数据包放入包缓存队列,然后开始为当前解码成功的反向数据包计时。The base transceiver station transmits the successful reverse data packet of decoding and the waiting period calculated in step A42 to the base station controller, and the base station controller puts the current reverse data packet of successful decoding into the packet buffer queue, and then starts to process the current Decoded successful reverse packet timing.
其中,步骤A2所述将当前解码成功的反向数据包放入包缓存队列,然后开始为当前解码成功的反向数据包计时为:Wherein, as described in step A2, put the current successfully decoded reverse data packet into the packet buffer queue, and then start timing the current successfully decoded reverse data packet as:
基站收发信机根据将当前解码成功的反向数据包放入包缓存队列,然后开始为当前解码成功的反向数据包计时;The base station transceiver puts the currently successfully decoded reverse data packet into the packet buffer queue, and then starts timing the current successfully decoded reverse data packet;
步骤B2所述将包缓存队列中,步骤A2中解码成功的反向数据包及其之前反向数据包选出,作为排好序的反向数据包为:In the packet cache queue described in step B2, the reverse data packets successfully decoded in step A2 and the previous reverse data packets are selected, and the reverse data packets that are sorted are:
基站收发信机将包缓存队列中,步骤A2中解码成功的反向数据包及其之前反向数据包选出,作为排好序的反向数据包传送给基站控制器。The base transceiver station selects the reverse data packets successfully decoded in step A2 and its previous reverse data packets from the packet buffer queue, and transmits them to the base station controller as sorted reverse data packets.
其中,步骤C2所述判断在排好序的反向数据包中是否有字节缺失由基站控制器完成。Wherein, the judgment in step C2 whether there is a byte missing in the sorted reverse data packet is completed by the base station controller.
采用本发明所提供的技术方案,对于乱序反向数据包,首先计算等待时长,只有在超出等待时长以后才认为发生反向数据包中所包含的字节丢失,这样就避免了错误的将乱序反向数据包认定为反向字节丢失。进一步,等待时长可以用于将乱序反向数据包排序,从而加快基站控制器中后续处理的速度。而计算等待时长和排序的工作可以由基站收发信机完成,这样就减轻了基站控制器的计算压力。By adopting the technical scheme provided by the present invention, for out-of-order reverse data packets, the waiting time is first calculated, and only after the waiting time is exceeded, it is considered that the bytes contained in the reverse data packets are lost, thus avoiding erroneous Out-of-order reverse packets are considered reverse byte loss. Further, the waiting time can be used to sort out-of-sequence reverse data packets, thereby speeding up the speed of subsequent processing in the base station controller. The work of calculating the waiting time and sorting can be completed by the base transceiver station, thus reducing the calculation pressure of the base station controller.
附图说明 Description of drawings
图1是CDMA2000 EV-DO Rev A中反向数据包的发送方案;Figure 1 is the sending scheme of the reverse data packet in CDMA2000 EV-DO Rev A;
图2是本发明提供的计算等待时长的流程图;Fig. 2 is the flow chart of calculating the waiting period provided by the present invention;
图3是本发明提供的判断反向数据包字节丢失方法实施例一的流程图;Fig. 3 is the flow chart of
图4是本发明提供的判断反向数据包字节丢失方法实施例二的流程图。Fig. 4 is a flow chart of
具体实施方式 Detailed ways
本发明的核心思想在于,对于乱序反向数据包,首先计算等待时长,根据等待时长来判断是否发生了数据包中的字节丢失。The core idea of the present invention is that, for out-of-order reverse data packets, firstly calculate the waiting time, and judge whether byte loss in the data packet occurs according to the waiting time.
为使本发明的目的、技术方案和优点更加清楚,下面结合附图及具体实施例对本发明作进一步地详细描述。In order to make the purpose, technical solution and advantages of the present invention clearer, the present invention will be further described in detail below in conjunction with the accompanying drawings and specific embodiments.
请参考图2,图2是本发明提供的计算等待时长的流程图。为了便于理解,且不失一般性,以图1所示的反向数据包C为例说明计算过程。根据图1,从直观上看,反向数据包C不需要等待反向数据包A,但需要等待反向数据包B。Please refer to FIG. 2 , which is a flow chart of calculating the waiting time provided by the present invention. For ease of understanding without loss of generality, the calculation process is described by taking the reverse data packet C shown in FIG. 1 as an example. According to FIG. 1 , intuitively, the reverse data packet C does not need to wait for the reverse data packet A, but needs to wait for the reverse data packet B.
步骤201,当前子包所在的反向数据包解码成功产生回调。In
这里,C0是当前子包,解码成功产生回调,启动对于反向数据包C的等待时长计算流程。Here, C0 is the current subpacket, and a callback is generated if the decoding is successful, and the waiting time calculation process for the reverse data packet C is started.
步骤202,获取当前子包、当前子包向前第一个子包和当前子包向前第二个子包的交织信息。
对于当前子包C0来说,当前子包向前第一个子包是子包B0,当前子包向前第二个子包是子包A0。For the current subpackage C0, the first subpackage before the current subpackage is subpackage B0, and the second subpackage before the current subpackage is subpackage A0.
所述的交织信息包括三个数据域:交织号、子包号和交织状态。The interleaving information includes three data fields: interleaving number, subpackage number and interleaving state.
交织号表示该子包位于哪个交织,其取值范围是0到2,因为总共有3个交织。在图1中,子包A0位于交织号0,子包B0位于交织号1,子包C0位于交织号2。The interlace number indicates which interlace the subpacket is in, and its value ranges from 0 to 2, because there are 3 interlaces in total. In FIG. 1 , subpacket A0 is located at
子包号表示该子包是所在反向数据包的第几个子包,其取值范围是0到3,因为对于作为接受端的基站来说,一个反向数据包最多包括4个子包。在图1中,A0、B0和C0都是各自所在的反向数据包的第0个子包。The subpacket number indicates which subpacket the subpacket belongs to in the reverse data packet, and its value ranges from 0 to 3, because for the base station as the receiving end, a reverse data packet includes at most 4 subpackets. In FIG. 1, A0, B0, and C0 are all the 0th subpackets of their respective reverse data packets.
子包状态表示该子包所在反向数据包的状态,可以是以下这四个值:Subpackage status indicates the status of the reverse data packet where the subpackage is located, which can be the following four values:
CRCPass,反向数据包解码成功,且该反向数据包是当前解码子包所在的反向数据包;CRCPass, the reverse data packet is successfully decoded, and the reverse data packet is the reverse data packet where the currently decoded sub-packet is located;
CRCFail,反向数据包没有解码成功;CRCFail, the reverse data packet was not decoded successfully;
Invalid,反向数据包解码成功,且该反向数据包不是当前解码子包所在的反向数据包;或者该反向数据包没有数据发送;或者第四子包解码失败,且该反向数据包不是当前解码子包所在的反向数据包;Invalid, the reverse data packet is successfully decoded, and the reverse data packet is not the reverse data packet where the currently decoded subpacket is located; or the reverse data packet has no data to send; or the fourth subpacket decoding fails, and the reverse data packet The packet is not the reverse data packet where the currently decoded subpacket is located;
SubPacketFail,该子包无效,不能用于所在反向数据包的解码。SubPacketFail, the subpacket is invalid and cannot be used for decoding the reverse data packet.
在图1中,子包A0的子包状态值为Invalid,子包B0的子包状态值为CRCFail,子包C0的子包状态值为CRCPass;In Figure 1, the subpackage status value of subpackage A0 is Invalid, the subpackage status value of subpackage B0 is CRCFail, and the subpackage status value of subpackage C0 is CRCPass;
需要说明的是,以上仅仅给出了子包状态的四种取值所表示的与计算等待时长有关的意义。It should be noted that the above only gives the meanings related to the calculation waiting time represented by the four values of the sub-packet status.
步骤203,判断当前子包是否提前终止,如果是则执行步骤204,否则执行步骤212。
判断当前子包是否提前终止的方法是看当前子包的交织信息中的子包号是否为3,如果为3表示没有提前终止,如果不为3表示提前终止。The method for judging whether the current sub-packet is terminated early is to check whether the sub-packet number in the interleaving information of the current sub-packet is 3. If it is 3, it means that it is not terminated early, and if it is not 3, it means that it is terminated early.
当前子包是C0时,当前子包的交织信息中的子包号为0,表示提前终止。When the current subpacket is C0, the subpacket number in the interleaving information of the current subpacket is 0, indicating early termination.
步骤204,判断当前子包所在反向数据包是否需要等待当前子包向前第一个子包所在反向数据包,如果是则执行步骤205,否则执行步骤206。
判断当前子包所在反向数据包是否需要等待当前子包向前第一个子包所反向在数据包的方法是,如果以下三个条件中的任意一个条件成立,则认为当前子包所在反向数据包不需要等待当前子包向前第一个子包所在反向数据包,否则认为当前子包所在反向数据包需要等待当前子包向前第一个子包所在反向数据包。这三个条件是:The method of judging whether the reverse data packet where the current subpacket is located needs to wait for the reverse data packet of the first subpacket before the current subpacket is, if any of the following three conditions is true, it is considered that the current subpacket is located The reverse data packet does not need to wait for the reverse data packet where the current subpacket is located forward, otherwise the reverse data packet where the current subpacket is located needs to wait for the reverse data packet where the first subpacket is located forward from the current subpacket . These three conditions are:
(1)当前子包交织信息中的子包号,大于当前子包向前第一个子包的交织信息中的子包号;(1) The sub-packet number in the current sub-packet interleaving information is greater than the sub-packet number in the interleaving information of the first sub-packet before the current sub-packet;
(2)当前子包向前第一个子包的交织信息中的子包状态为Invalid;(2) The subpackage status in the interleaving information of the first subpackage before the current subpackage is Invalid;
(3)当前子包向前第一个子包的交织信息中的子包状态为SubPacketFail,且当前子包向前第一个子包的交织信息中的子包号为3。(3) The subpacket status in the interleaving information of the first subpacket forward of the current subpacket is SubPacketFail, and the subpacket number in the interleaving information of the first subpacket forward of the current subpacket is 3.
当前子包是C0时,当前子包向前第一个子包是B0,且上述三个条件均不满足,因此当前子包C0所在的反向数据包需要等待当前子包向前第一个子包B0所在的反向数据包。When the current subpacket is C0, the first forward subpacket of the current subpacket is B0, and none of the above three conditions are satisfied, so the reverse data packet where the current subpacket C0 is located needs to wait for the first forward subpacket of the current subpacket The reverse data packet where the subpacket B0 is located.
步骤205,计算当前子包所在反向数据包需要等待当前子包向前第一个子包所在反向数据包的等待时长,然后执行步骤207。Step 205: Calculate the waiting time for the reverse data packet where the current subpacket is located and the reverse data packet where the first subpacket is located before the current subpacket, and then perform
等待时长的计算方法是,首先将当前子包的交织信息中的交织号,减去当前子包向前第一个子包的交织信息中的交织号,再加上3,将加法所得的结果除以3以后取余数;然后用3减去当前子包向前第一个子包的交织信息中的子包号,将得到的差乘以3,并且用乘法的结果减去前面一步得到的余数,就是当前子包所在的反向数据包需要等待当前子包向前第一个子包所在的反向数据包的等待时长。The calculation method of the waiting time is: first subtract the interleaving number in the interleaving information of the current subpacket from the interleaving number in the interleaving information of the first subpacket before the current subpacket, add 3, and add the result After dividing by 3, take the remainder; then subtract the subpacket number in the interleaving information of the first subpacket forward from the current subpacket with 3, multiply the difference obtained by 3, and subtract the result obtained in the previous step from the result of the multiplication The remainder is the waiting time for the reverse data packet where the current subpacket is located to wait for the reverse data packet where the first subpacket is located before the current subpacket.
根据以上计算方法,子包C0所在的反向数据包应该等待子包B0所在的反向数据包的等待时长为8,单位是子包。According to the above calculation method, the reverse data packet containing the sub-packet C0 should wait for the reverse data packet containing the sub-packet B0 for a waiting time of 8, and the unit is a sub-packet.
步骤206,令当前子包所在反向数据包需要等待当前子包向前第一个子包所在反向数据包的等待时长为0。
步骤207,判断当前子包所在反向数据包是否需要等待当前子包向前第二个子包所在反向数据包,如果是则执行步骤208,否则执行步骤209。
判断当前子包所在反向数据包是否需要等待当前子包向前第二个子包所在反向数据包的方法是,如果以下三个条件中的任意一个条件成立,则认为当前子包所在反向数据包不需要等待当前子包向前第二个子包所在反向数据包,否则认为当前子包所在反向数据包需要等待当前子包向前第二个子包所在反向数据包。这三个条件是:The method of judging whether the reverse data packet where the current subpacket is located needs to wait for the reverse data packet where the current subpacket is forwarded is that if any of the following three conditions is true, it is considered that the current subpacket is located in the reverse direction The data packet does not need to wait for the reverse data packet where the current subpacket is forward and the second subpacket is located, otherwise it is considered that the reverse data packet where the current subpacket is located needs to wait for the reverse data packet where the current subpacket is forward and the second subpacket is located. These three conditions are:
(1)当前子包交织信息中的子包号,大于当前子包向前第二个子包的交织信息中的子包号;(1) The sub-packet number in the current sub-packet interleaving information is greater than the sub-packet number in the interleaving information of the second sub-packet before the current sub-packet;
(2)当前子包向前第二个子包的交织信息中的子包状态为Invalid;(2) The subpackage status in the interleaving information of the second subpackage ahead of the current subpackage is Invalid;
(3)当前子包向前第二个子包的交织信息中的子包状态为SubPacketFail,且当前子包向前第二个子包的交织信息中的子包号为3。(3) The subpacket status in the interleaving information of the second forward subpacket from the current subpacket is SubPacketFail, and the subpacket number in the interleaving information of the second subpacket forward from the current subpacket is 3.
当前子包是C0时,当前子包向前第二个子包是A0,且上述三个条件中的(2)满足,因此当前子包C0所在的反向数据包不需要等待当前子包向前第二个子包A0所在的反向数据包。When the current sub-packet is C0, the second sub-packet forward of the current sub-packet is A0, and (2) of the above three conditions are satisfied, so the reverse data packet where the current sub-packet C0 is located does not need to wait for the current sub-packet forward The reverse data packet where the second subpacket A0 is located.
步骤208,计算当前子包所在反向数据包需要等待当前子包向前第二个子包所在反向数据包的等待时长,然后执行步骤210。Step 208: Calculate the waiting time for the reverse data packet where the current subpacket is located and the reverse data packet where the second subpacket is located before the current subpacket, and then perform
等待时长的计算方法是,首先将当前子包的交织信息中的交织号,减去当前子包向前第二个子包的交织信息中的交织号,再加上3,将加法所得的结果除以3以后取余数;然后用3减去当前子包向前第二个子包的交织信息中的子包号,将得到的差乘以3,并且用乘法的结果减去前面一步得到的余数,就是当前子包所在的反向数据包需要等待当前子包向前第二个子包所在的反向数据包的等待时长。The calculation method of the waiting time is: first subtract the interleaving number in the interleaving information of the current subpacket from the interleaving number in the interleaving information of the second subpacket before the current subpacket, add 3, and divide the result obtained by the addition Take the remainder after 3; then use 3 to subtract the subpacket number in the interleaving information of the second subpacket forward from the current subpackage, multiply the difference obtained by 3, and subtract the remainder obtained in the previous step from the result of the multiplication, It is the waiting time for the reverse data packet where the current subpacket is located to wait for the reverse data packet where the second subpacket is located before the current subpacket.
步骤209,令当前子包所在反向数据包需要等待当前子包向前第二个子包所在反向数据包的等待时长为0。In
步骤210,判断当前子包所在的反向数据包分别需要等待的两个等待时长是否均为0,如果是则执行步骤212,否则执行步骤211。
步骤211,以当前子包所在的反向数据包分别需要等待的两个等待时长中较大的一个作为当前子包所在反向数据包的等待时长。Step 211: Use the larger one of the two waiting times for the reverse data packet where the current subpacket is located as the waiting time for the reverse data packet where the current subpacket is located.
由于当前子包C0所在的反向数据包C需要等待当前子包向前第一个子包B0所在的数据包B,且等待时长为8;而当前子包C0所在的反向数据包C需要等待当前子包向前第二个子包A0所在的数据包A的等待时长为0,因此当前子包C0所在的反向数据包的等待时长为8。Because the reverse data packet C where the current subpacket C0 is located needs to wait for the data packet B where the first subpacket B0 is located ahead of the current subpacket, and the waiting time is 8; while the reverse data packet C where the current subpacket C0 is located needs to The waiting time for data packet A containing the second subpacket A0 in the current subpacket is 0, so the waiting time for the reverse data packet containing the current subpacket C0 is 8.
步骤212,当前子包所在的反向数据包不需要等待,也就是说当前子包的等待时长为0。
请参考图3,图3是本发明提供的判断反向数据包字节丢失方法实施例一的流程图。Please refer to FIG. 3 . FIG. 3 is a flow chart of
步骤301,BTS将反向数据包解码,并将交织信息传送给BSC。
在移动通信基站系统中,对反向数据包进行解码是由BTS完成的。在对计算等待时长的流程的描述中提到,在BTS对当前子包所在的反向数据包解码成功后,会得到当前子包、当前子包向前第一个子包和当前子包向前第二个子包的交织信息,BTS将成功解码的反向数据包,以及对应的三个交织信息都传送给BSC。In the mobile communication base station system, decoding the reverse data packet is done by the BTS. As mentioned in the description of the process of calculating the waiting time, after the BTS successfully decodes the reverse data packet where the current subpacket is located, it will get the current subpacket, the first subpacket before the current subpacket, and the current subpacket direction. For the interleaving information of the first second subpacket, the BTS transmits the successfully decoded reverse data packet and the corresponding three interleaving information to the BSC.
步骤302,BSC根据交织信息,计算当前反向数据包的等待时长。In
步骤302就是步骤201至步骤212所进行的流程。Step 302 is the process of
步骤303,BSC将当前反向数据包中的字节放入重排缓冲区。In
重排缓冲区是现有技术的RLP协议所用来对反向数据包中的字节进行排序用的。移动终端会按照RLP协议为所发送的每个字节分配一个RLP序号,RLP序号按照字节发送的先后顺序递增;BSC在接收到反向数据包以后,将反向数据包所包含的字节,根据RLP序号放入重排缓冲区中。只有连续的、超过一定长度门限的、且最早进入重排缓冲区的一段字节才能被送入后续处理模块。The rearrangement buffer is used by the prior art RLP protocol to sort the bytes in the reverse data packet. The mobile terminal will assign an RLP sequence number to each byte sent according to the RLP protocol, and the RLP sequence number will increase according to the order in which the bytes are sent; , put it into the rearrangement buffer according to the RLP serial number. Only a segment of bytes that are continuous, exceed a certain length threshold, and enter the rearrangement buffer at the earliest can be sent to the subsequent processing module.
例如,假设长度门限是20字节,重排缓冲区中现有字节为RLP序号从30到35的总共6个连续字节,由于连续字节的长度没有超过长度门限,因此不能送入后续处理模块。现在收到第一个反向数据包,其中包括RLP序号为40到50的11个连续字节。按照RLP序号放入重排缓冲区后,连续字节的数目仍然没有超过20个。如果又收到第二个反向数据包,其中包括RLP序号为36到39的4个连续字节。按照RLP序号放入重排缓冲区后,连续字节的RLP序号从30到40,连续字节的数目为21个,超过了长度门限,则将这21个字节全部发送到后续处理模块。For example, assuming that the length threshold is 20 bytes, the existing bytes in the rearrangement buffer are a total of 6 consecutive bytes with RLP sequence numbers from 30 to 35. Since the length of the consecutive bytes does not exceed the length threshold, they cannot be sent to the subsequent processing module. Now the first reverse packet is received, which includes 11 consecutive bytes with RLP sequence numbers 40 to 50. After being put into the rearrangement buffer according to the RLP serial number, the number of consecutive bytes still does not exceed 20. If a second reverse data packet is received, it includes 4 consecutive bytes with RLP sequence numbers from 36 to 39. After being put into the rearrangement buffer according to the RLP serial number, the RLP serial number of consecutive bytes is from 30 to 40, and the number of consecutive bytes is 21, which exceeds the length threshold, and all 21 bytes are sent to the subsequent processing module.
步骤304,判断重排缓冲区中当前反向数据包中的字节之前是否有字节缺失,如果有则执行步骤305,否则执行步骤308。
所谓的字节缺失,即步骤303所举的例子中,收到第二个反向数据包之前的情况,RLP序号为36到39的字节就是缺失字节。The so-called missing byte refers to the situation before receiving the second reverse data packet in the example given in
步骤305,BSC将计时器置零后启动计时器。In
计时器的作用在于,字节缺失有可能是由乱序反向数据包造成的,也有可能是反向数据包丢失造成的。如果是由乱序反向数据包造成的,则在步骤302所计算出的等待时长内,就应该收到包含缺失字节的反向数据包。如果超过这个时间还没有收到,则该反向数据包在从移动终端到基站的通信路径上丢失,需要移动终端重新发送该缺失字节。The role of the timer is that missing bytes can be caused by out-of-order reverse packets, or by reverse packet loss. If it is caused by out-of-order reverse data packets, within the waiting period calculated in
步骤306,BSC判断计时器是否到达等待时长,如果是则执行步骤311,否则执行步骤307。In
步骤307,BSC判断是否收到BTS传来的包含缺失字节的反向数据包,如果收到则执行步骤308,否则返回执行步骤306。In
步骤308,BSC判断重排缓冲区中当前反向数据包中的字节所在的一段连续字节的长度是否超过长度门限,如果是则执行步骤309,否则执行步骤310。In
步骤309,BSC将重排缓冲区中当前反向数据包中的字节所在的一段连续字节进行后续处理。In
步骤310,BSC准备处理下一个反向数据包。In
步骤311,认为BTS未能成功解码缺失字节所在的反向数据包,要求移动终端重发缺失字节。In
在实施例一中,从步骤302到步骤311,都是由BSC完成的。在实际的移动通信基站系统中,一个BSC往往有很多个BTS,对于每个BTS传送来的反向数据包,BSC都要进行步骤302到步骤311的流程。这样就占用了BSC的大量处理能力。另一方面,BSC计算等待时长需要BTS在传送当前反向数据包的同时发送交织信息,这会降低BTS和BSC之间接口的利用效率。例如,三个子包的交织信息大约为3字节,而在基于互联网协议的语音业务(Voice on Internet Protocol,VoIP)中,一个反向数据包的长度才22字节,传送交织信息使得BTS和BSC之间的接口利用率降低了近10%。In the first embodiment, the steps from
作为实施例一的一种改进,步骤301中,BTS可以先不将解码后的反向数据包以及交织信息传送给BSC,而是由BTS自身执行步骤302,然后将解码后的反向数据包和计算出的等待时长一起传送给BSC。这样就可以提高BTS和BSC之间接口的利用效率。同时也分担了BSC的一部分计算量。As an improvement of the first embodiment, in
但是,对于反向数据包中字节的处理只能在BSC进行,这样就使得无法将步骤303到步骤311移到BTS中进行。这样,BSC的计算量还是很大,并且传送等待时长还是需要占用BTS和BSC之间接口的资源。However, the processing of bytes in the reverse data packet can only be performed at the BSC, so that
本发明的实施例二可以解决这个问题。请参考图4,图4是本发明提供的判断反向数据包字节丢失方法实施例二的流程图。
为了对反向数据包排序,BTS为三个交织各维护一个定时器,每个定时器的初始值都是0。每个定时器还各自对应一个启动帧序号(Frame SequenceNumber,FSN),表示启动这个定时器的子包所在反向数据包的FSN。FSN是移动终端在发送反向数据包时为每个数据包分配的编号,FSN与数据包是一一对应的关系,分配FSN是按照发送数据包的先后顺序。BTS还为维护一个反向数据包缓存队列,简称包缓存队列,包缓存队列中的反向数据包FSN由小到大排列。In order to sort the reverse data packets, the BTS maintains a timer for each of the three interleaves, and the initial value of each timer is 0. Each timer also corresponds to a start frame sequence number (Frame SequenceNumber, FSN), indicating the FSN of the reverse data packet where the subpacket that starts the timer is located. FSN is the serial number assigned to each data packet by the mobile terminal when sending the reverse data packet. The FSN and the data packet have a one-to-one correspondence, and the allocation of the FSN is based on the order in which the data packets are sent. The BTS also maintains a reverse data packet buffer queue, referred to as the packet buffer queue, and the reverse data packet FSNs in the packet buffer queue are arranged from small to large.
步骤401,BTS收到子包。In step 401, the BTS receives the subpacket.
步骤402,BTS判断是否在当前子包完成当前子包所在反向数据包的解码,如果是则执行步骤410,否则执行步骤403。Step 402 , the BTS judges whether the decoding of the reverse data packet where the current subpacket is located is completed in the current subpacket, and if so, executes step 410 , otherwise executes step 403 .
步骤403,判断当前子包所在交织的定时器是否为0,如果是则执行步骤405,否则执行步骤404。Step 403, judging whether the timer of the interlace where the current subpacket is located is 0, if yes, execute step 405, otherwise execute step 404.
步骤404,执行步骤420。Step 404, execute step 420.
步骤405,判断除当前子包所在的交织外,其他两个交织的定时器是否都不为0,如果是则执行步骤407;如果除当前子包所在的交织外,其他两个交织的定时器中的任意一个为0则执行步骤406。Step 405, judging whether except the interleaving where the current subpackage is located, whether the other two interleaved timers are all 0, if yes, then perform step 407; if except the interleaving where the current subpacket is located, the other two interleaved timers If any one of them is 0, step 406 is executed.
步骤406,判断除当前子包所在的交织外,其他两个交织的定时器是否都为0,如果是则执行步骤409;如果除当前子包所在的交织外,其他两个交织的定时器中有且只有一个为0则执行步骤408。Step 406, judging whether except the interleaving where the current subpackage is located, whether the other two interleaving timers are all 0, if yes, then perform step 409; If one and only one is 0, step 408 is executed.
步骤407,比较判断除当前子包所在的交织外,其他两个交织的定时器的启动FSN,将包缓存队列中,值较小的启动FSN所对应的反向数据包之前的反向数据包发送到BSC,执行步骤420。Step 407, comparing and judging the starting FSNs of the timers of the other two interleavings except the interleaving where the current subpacket is located, and storing the reverse data packets before the reverse data packets corresponding to the starting FSNs with smaller values in the packet cache queue sent to the BSC and go to step 420.
步骤408,将包缓存队列中,不为0的定时器的启动FSN所对应的反向数据包之前的反向数据包发送到BSC,执行步骤420。Step 408: Send the reverse data packet before the reverse data packet corresponding to the start FSN of the timer that is not 0 in the packet buffer queue to the BSC, and execute step 420.
步骤409,将包缓存队列中的反向数据包全部发送到BSC,执行步骤420。Step 409, send all the reverse data packets in the packet buffer queue to the BSC, and execute step 420.
步骤410,将当前子包所在交织的定时器清零,并将当前子包按照FSN的顺序插入包缓存队列。Step 410, clear the timer of the interleave where the current sub-packet is located, and insert the current sub-packet into the packet buffer queue in the order of FSN.
步骤411,BTS根据在成功解码反向数据包时获取的当前子包、当前子包向前第一个子包和当前子包向前第二个子包的交织信息,分别计算出当前子包所在反向数据包需要等待当前子包向前第一个子包的等待时长t1,和当前子包所在反向数据包需要等待当前子包向前第二个子包的等待时长t2。In step 411, the BTS calculates the location of the current subpacket according to the interleaving information of the current subpacket, the first subpacket forward of the current subpacket, and the second subpacket forward of the current subpacket obtained when the reverse data packet is successfully decoded. The reverse data packet needs to wait for the waiting time t1 of the first subpacket forward of the current subpacket, and the waiting time t2 of the second subpacket forward of the current subpacket for the reverse data packet of the current subpacket.
步骤412,判断t1和t2是否均为0,如果是则执行步骤414,如果t1和t2中任意一个不为0则执行步骤413。Step 412, judging whether t1 and t2 are both 0, if yes, execute step 414, if any one of t1 and t2 is not 0, execute step 413.
步骤413,判断t1是否为0,如果是则t2必然不为0,执行步骤418,否则执行步骤415。Step 413, judge whether t1 is 0, if yes, t2 must not be 0, go to step 418, otherwise go to step 415.
步骤414,返回执行步骤405。Step 414 , return to step 405 .
步骤415,判断当前子包向前第一个子包所在交织的定时器是否为0,如果是则执行步骤416,否则执行步骤417。In step 415, it is judged whether the timer of the interlace of the first subpacket before the current subpacket is 0, if yes, go to step 416, otherwise go to step 417.
步骤416,将当前子包向前第一个子包所在交织的定时器的值设为t1的值,并将当前子包向前第一个子包所在交织的定时器的启动FSN设为当前子包所在数据包的FSN。Step 416, set the value of the timer interleaving where the first subpacket of the current subpackage is located to the value of t1, and set the start FSN of the timer interleaved where the first subpacket is located forward of the current subpacket to the current The FSN of the packet in which the subpacket resides.
步骤417,判断t2是否为0,如果是则执行步骤420,否则执行步骤418。Step 417, judge whether t2 is 0, if yes, execute step 420, otherwise execute step 418.
步骤418,判断当前子包向前第二个子包所在交织的定时器是否为0,如果是则执行步骤419,否则执行步骤420。Step 418 , judging whether the timer of the interleaving of the second subpacket before the current subpacket is 0, if yes, go to step 419 , otherwise go to step 420 .
步骤419,将当前子包向前第二个子包所在交织的定时器的值设为t2的值,并将当前子包向前第二个子包所在交织的定时器的启动FSN设为当前子包所在数据包的FSN。Step 419, the value of the interleaving timer where the second subpacket is located in the current subpacket is set to the value of t2, and the start FSN of the interleaved timer where the second subpacket is located in the current subpacket is set to the current subpacket The FSN of the contained packet.
步骤420,将不为0的定时器减1后结束对当前子包的处理流程,准备处理下一个子包。In step 420, the timer that is not 0 is decremented by 1, and then the processing flow for the current subpacket is ended, and the next subpacket is ready to be processed.
这样,从BTS传送到BSC的反向数据包都是按照发射端的发射顺序排好的。BSC虽然仍然要执行步骤303到步骤310,但是由于反向数据包都是经过排序的,所以BSC不用对从BTS传送来的反向数据包中的字节做任何重排缓冲处理,这样就减少了BSC的计算量,基本上不用BSC进行计算。又由于BTS只需要将数据包本身传送给BSC,这样就可以进一步提高BTS和BSC接口的利用效率。当然,如果基于其他考虑,也完全可以将对反向数据包进行排序的工作放到BSC中进行。在这种情况下,步骤407、步骤408和步骤409中所述将反向数据包发送到BSC则应该为将反向数据包从包缓存队列中发送到后续处理模块。In this way, the reverse data packets transmitted from the BTS to the BSC are arranged according to the transmission order of the transmitting end. Although the BSC still needs to perform
以上所述仅为本发明的较佳实施例而已,并非用于限定本发明的保护范围。凡在本发明的精神和原则之内,所作的任何修改、等同替换、改进等,均应包含在本发明的保护范围之内。The above descriptions are only preferred embodiments of the present invention, and are not intended to limit the protection scope of the present invention. Any modifications, equivalent replacements, improvements, etc. made within the spirit and principles of the present invention shall be included within the protection scope of the present invention.
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US20020045449A1 (en) * | 2000-10-02 | 2002-04-18 | Mamiko Oobayashi | Mobile communication terminal apparatus, control circuit, and handoff control method |
US20020167926A1 (en) * | 2001-05-14 | 2002-11-14 | Samsung Electronics Co., Ltd. | Apparatus and method for controlling packet data transmission between BSC and BTS |
US20030086427A1 (en) * | 2001-11-08 | 2003-05-08 | Samsung Electronics Co., Ltd. | Method and apparatus for retransmitting packet data between base station controller and base transceiver system in a mobile communication system |
GB2396998A (en) * | 2003-01-06 | 2004-07-07 | Roke Manor Research | Handover method for packet streaming data |
CN1551552A (en) * | 2003-05-10 | 2004-12-01 | Lg电子株式会社 | Method for transmitting control signal for reverse chain packet transmission |
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US20020167926A1 (en) * | 2001-05-14 | 2002-11-14 | Samsung Electronics Co., Ltd. | Apparatus and method for controlling packet data transmission between BSC and BTS |
US20030086427A1 (en) * | 2001-11-08 | 2003-05-08 | Samsung Electronics Co., Ltd. | Method and apparatus for retransmitting packet data between base station controller and base transceiver system in a mobile communication system |
GB2396998A (en) * | 2003-01-06 | 2004-07-07 | Roke Manor Research | Handover method for packet streaming data |
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