WO2023151359A1 - Tetrahydrocarbazole derivative as well as preparation method therefor and use thereof - Google Patents
Tetrahydrocarbazole derivative as well as preparation method therefor and use thereof Download PDFInfo
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- WO2023151359A1 WO2023151359A1 PCT/CN2022/136302 CN2022136302W WO2023151359A1 WO 2023151359 A1 WO2023151359 A1 WO 2023151359A1 CN 2022136302 W CN2022136302 W CN 2022136302W WO 2023151359 A1 WO2023151359 A1 WO 2023151359A1
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- C—CHEMISTRY; METALLURGY
- C07—ORGANIC CHEMISTRY
- C07D—HETEROCYCLIC COMPOUNDS
- C07D209/00—Heterocyclic compounds containing five-membered rings, condensed with other rings, with one nitrogen atom as the only ring hetero atom
- C07D209/56—Ring systems containing three or more rings
- C07D209/80—[b, c]- or [b, d]-condensed
- C07D209/82—Carbazoles; Hydrogenated carbazoles
- C07D209/88—Carbazoles; Hydrogenated carbazoles with hetero atoms or with carbon atoms having three bonds to hetero atoms with at the most one bond to halogen, e.g. ester or nitrile radicals, directly attached to carbon atoms of the ring system
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- A—HUMAN NECESSITIES
- A61—MEDICAL OR VETERINARY SCIENCE; HYGIENE
- A61P—SPECIFIC THERAPEUTIC ACTIVITY OF CHEMICAL COMPOUNDS OR MEDICINAL PREPARATIONS
- A61P31/00—Antiinfectives, i.e. antibiotics, antiseptics, chemotherapeutics
- A61P31/04—Antibacterial agents
- A61P31/06—Antibacterial agents for tuberculosis
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- C—CHEMISTRY; METALLURGY
- C07—ORGANIC CHEMISTRY
- C07D—HETEROCYCLIC COMPOUNDS
- C07D401/00—Heterocyclic compounds containing two or more hetero rings, having nitrogen atoms as the only ring hetero atoms, at least one ring being a six-membered ring with only one nitrogen atom
- C07D401/14—Heterocyclic compounds containing two or more hetero rings, having nitrogen atoms as the only ring hetero atoms, at least one ring being a six-membered ring with only one nitrogen atom containing three or more hetero rings
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- C—CHEMISTRY; METALLURGY
- C07—ORGANIC CHEMISTRY
- C07D—HETEROCYCLIC COMPOUNDS
- C07D409/00—Heterocyclic compounds containing two or more hetero rings, at least one ring having sulfur atoms as the only ring hetero atoms
- C07D409/14—Heterocyclic compounds containing two or more hetero rings, at least one ring having sulfur atoms as the only ring hetero atoms containing three or more hetero rings
Definitions
- the application belongs to the technical field of medicinal chemistry, and specifically relates to tetrahydrocarbazole derivatives and their preparation methods and applications.
- Tuberculosis is an infectious disease caused by airborne transmission of its pathogen, Mycobacterium tuberculosis.
- drug-resistant tuberculosis especially multidrug-resistant and extensively drug-resistant tuberculosis, poses a serious threat to human health and even life, and has become a major challenge facing the world.
- WWO World Health Organization
- tuberculosis has become the number one deadly infectious disease. my country is one of the countries with a high burden of tuberculosis in the world and one of the countries with the most serious problem of tuberculosis drug resistance.
- DHFR dihydrofolate reductase
- DHFR inhibitors can specifically combine with DHFR to inhibit its activity, so that dihydrofolate cannot be converted into tetrahydrofolate, hinder the metabolism of folic acid, and produce anti-tuberculosis and anti-cancer effects.
- the purpose of this application is to overcome the above-mentioned deficiencies in the prior art, provide a tetrahydrocarbazole derivative and its preparation method, to solve the existing anti-tuberculosis drugs have unsatisfactory anti-tuberculosis Mycobacterium effect or lead to the existence of drug resistance, etc. Inadequate technical issues.
- the first aspect of the present application provides a tetrahydrocarbazole derivative.
- the molecular structural formula of the tetrahydrocarbazole derivatives of the present application is shown in the following general formula I:
- R1 and R2 in the general formula I are any one of aryl and heteroaryl.
- the second aspect of the present application provides the preparation method of the tetrahydrocarbazole derivatives of the present application.
- the preparation method of tetrahydrocarbazole derivative of the present application comprises the steps:
- the reactant A shown in the following structural formula I A and the reactant B shown in the following structural formula I B and the base catalyst are carried out in the first reaction solvent for the first substitution reaction, generating the first intermediate product shown in the following structural formula I Z1;
- the first intermediate product, reducing agent and acidic additive are reversely carried out redox reaction in the second reaction solvent to generate the second intermediate product shown in the following structural formula I Z2;
- the second intermediate product is carried out with the reactant C shown in the following structural formula I C and the composite catalyst in the third reaction solvent to carry out the second substitution reaction to generate the third intermediate product shown in the following structural formula I Z3;
- the third intermediate product is condensed with aminoguanidine bicarbonate in a fourth reaction solvent to generate a tetrahydrocarbazole derivative shown in the following structural formula I;
- the same or different M1 in the formula I B and the M2 in the formula I c are halogen atoms
- the same or different R1 in the formula I B and the R2 in the formula I C are aryl, hetero Any of the aryl groups.
- the third aspect of the present application provides the application of the tetrahydrocarbazole derivatives of the present application.
- the application of tetrahydrocarbazole derivatives as Mycobacterium tuberculosis inhibitors or in the preparation of anti-tuberculosis drugs.
- the tetrahydrocarbazole derivative provided by the first aspect of the present application has excellent anti-tuberculosis effect through the design of its molecular structure, and its anti-tuberculosis effect is even excellent for isoniazid, and it is effective for most Mycobacterium tuberculosis does not develop drug resistance.
- the method for preparing tetrahydrocarbazole derivatives provided in the second aspect of the present application can synthesize the target product by designing the synthesis route of the reactant, so that the synthesized target product has excellent anti-tuberculosis effect.
- the yield of the target product is high, the side reactions are few, the process conditions are easy to control, and the yield and performance of the tetrahydrocarbazole derivatives prepared by the preparation are stable.
- the tetrahydrocarbazole derivatives of the present application provided by the third aspect of the present application can effectively inhibit and kill Mycobacterium tuberculosis when used as Mycobacterium tuberculosis inhibitors or in the preparation of anti-tuberculosis drugs, the anti-tuberculosis effect is remarkable, and the anti-tuberculosis The MIC value of Mycobacterium tuberculosis is low; And most of Mycobacterium tuberculosis will not produce drug resistance.
- sequence numbers of the above-mentioned processes do not mean the order of execution, and some or all steps may be executed in parallel or sequentially, and the execution order of each process shall be based on its functions and The internal logic is determined and should not constitute any limitation to the implementation process of the embodiment of the present application.
- the weight of the relevant components mentioned in the description of the embodiments of the present application can not only refer to the specific content of each component, but also represent the proportional relationship between the weights of the various components.
- the scaling up or down of the content of the fraction is within the scope disclosed in the description of the embodiments of the present application.
- the mass in the description of the embodiments of the present application may be ⁇ g, mg, g, kg and other well-known mass units in the chemical industry.
- the embodiment of the present application provides a tetrahydrocarbazole derivative.
- the molecular structural formula of the tetrahydrocarbazole derivative of the embodiment of the present application is shown in the following general formula I:
- the same or different R1 and R2 in the general formula I are any one of aryl and heteroaryl.
- the tetrahydrocarbazole derivatives in the examples of the present application have excellent anti-tuberculosis effects through the design of their molecular structures. It is known from the test that the tetrahydrocarbazole derivatives of the present application have low anti-tuberculosis MIC values, and their anti-tuberculosis effects are even superior to isoniazid, and they will not produce drug resistance to most tuberculosis bacteria.
- the inventor found in the research that the types of R1 and R2 contained in the tetrahydrocarbazole derivatives of the embodiments of the present application have an impact on their anti-tuberculosis effect, such as R1 and R2 are the same or different for aryl, hetero
- R1 and R2 are the same or different for aryl, hetero
- the anti-tuberculosis effect of the tetrahydrocarbazole derivatives in the examples of the present application can be further optimized and improved.
- the aryl groups may include any of phenyl, monosubstituted phenyl, and polysubstituted phenyl.
- the substituent group in the monosubstituted phenyl group may include any one of a halogen atom, -CF3, -C ⁇ CH, -C ⁇ N, -NO2, -OCH3.
- the substituent groups in the polysubstituted phenyl group may include at least one of halogen atoms and -OCH3.
- the anti-tuberculosis activity further reduces the MIC value of its anti-tuberculosis.
- the heteroaryl may include any of pyrrole, substituted pyrrole, thiophene, substituted thiophene, pyridine, substituted pyridine, pyrimidine, and substituted pyrimidine kind.
- the substituent group in the substituted pyrrole may include -OCH3.
- Substituent groups in substituted thiophenes may include -C ⁇ N.
- Heteroaryl or further control and optimize the substituent groups of these substituted pyrroles, substituted thiophenes, substituted pyridines, and substituted pyrimidines to further improve the anti-tuberculosis activity of tetrahydrocarbazole derivatives in the examples of the present application, and further reduce their MIC value against tuberculosis is low.
- the tetrahydrocarbazole derivatives in the embodiments of the present application can at least be at least one of the following molecular structural formulas I 1 to structural formula I 10:
- Each tetrahydrocarbazole derivative mentioned above has high anti-tuberculosis activity, and its anti-tuberculosis MIC value is low.
- the activities of I 3 to I 5 and I 8 are equivalent to isoniazid, and the activities of I 6 and I 7 are equivalent to those of isoniazid. Activity is better than isoniazid.
- the examples of the present application provide the preparation method of tetrahydrocarbazole derivatives in the above examples of the application.
- the preparation method of the tetrahydrocarbazole derivative of the embodiment of the present application comprises the following steps:
- reactant A and reaction B in step S01 can be obtained according to existing methods.
- the reactant A (Chinese name: 2(6-nitro-7-fluoro-2,3,4,9-tetrahydrocarbazol-1-one)) shown in structural formula I A can but not only Synthesize only as follows:
- reaction product A1 4-nitro-5-fluorophenylhydrazine (reaction product A1) shown in the following structural formula I A1, 2-cyclohexanedione (reaction product A2) shown in structural formula I A2 in the first acid reaction solution Carry out substitution reaction in, generate the reaction product A3 shown in structural formula I A3;
- reaction formula (1) the total synthetic chemical reaction formula of reactant A is shown in the following reaction formula (1):
- the mixing ratio of 4-nitro-5-fluorophenylhydrazine and 2-cyclohexanedione in step S011 can be mixed according to the molar ratio shown in chemical reaction formula (1), in order to improve the yield of reaction product A3 , wherein one of the reactants 4-nitro-5-fluorophenylhydrazine or 2-cyclohexanedione can be in excess.
- the first acid reaction solution includes one or more of hydrochloric acid, sulfuric acid, nitric acid, acetic acid, etc., and hydrochloric acid is further selected. The concentration of the first acid reaction solution should be conducive to the yield of the reaction product A3 and the forward reaction rate.
- the first acid reaction solution when the first acid reaction solution is hydrochloric acid, its concentration can be but not only 1moL/L.
- the addition amount of reactant 4-nitro-5-fluorophenylhydrazine can also be mixed according to the hydrochloric acid solution mixing ratio of 30g 4-nitro-5-fluorophenylhydrazine and 700mL (1moL/L).
- the substitution reaction in step S011 may be under reflux conditions and the temperature may be 30°C to 150°C, further 105°C. Fully react, such as stirring at reflux for 20 hours.
- S011 can be carried out as follows:
- reaction Product A3 According to the ratio of 30g of 4-nitro-5-fluorophenylhydrazine, 21g of 1,2-cyclohexanedione and 700mL of 1moL/L hydrochloric acid solution, the components were mixed, and then refluxed and stirred for 12 hours to form a reaction Product A3.
- the second acid reaction solution in step S012 may include one or more of hydrochloric acid, sulfuric acid, nitric acid, acetic acid, etc., and further be a mixed solvent of hydrochloric acid and acetic acid.
- concentrated hydrochloric acid and glacial acetic acid in the mixed solvent of hydrochloric acid and acetic acid, concentrated hydrochloric acid and glacial acetic acid can be but not only according to 400mL: 100mL.
- the concentration of the reaction product A3 in the mixture reaction solution of concentrated hydrochloric acid and glacial acetic acid can be, but not only mixed according to the mixing ratio of 30 g of 4-nitro-5-fluorophenylhydrazine reactant in step S011 and 400 mL of concentrated hydrochloric acid.
- the temperature of the reflux reaction in step S012 is controlled at 20°C to 200°C, further to 90°C.
- S012 can be carried out as follows:
- reaction product A3 in step S011 was mixed with concentrated hydrochloric acid and glacial acetic acid at a volume ratio of 400:100, and stirred under reflux for 20 hours to generate reactant A.
- the R1 contained in the reactant B in step S01 is the R1 contained in the general formula I of the tetrahydrocarbazole derivative molecular structure in the above application example. Therefore, R1 is any of aryl and heteroaryl.
- the M1 contained in the reactant B is a halogen atom, specifically but not only a bromine atom (Br). Therefore, reactant B may be a benzyl bromide compound. Then, during the first substitution reaction between the reactant A and the reactant B in step S01, the R1 contained in the reactant B replaces the hydrogen atom of the secondary amine contained in the reactant A.
- the first reaction solvent in step S01 may include N,N-dimethylformamide, tetrahydrofuran, 2-methyltetrahydrofuran, acetone, 1,4-dioxane, acetonitrile, diethylene glycol dimethyl At least one of ether, toluene and methylene chloride.
- the base catalyst includes at least one of cesium carbonate, potassium carbonate, sodium carbonate, sodium bicarbonate, and sodium hydroxide, and is further cesium carbonate.
- the concentration of the base catalyst in the first reaction solvent can be but not only 0.025moL/L.
- the reactant B can be slightly excessive relative to the reactant, as in the example, the reactant A and the reactant B can be mixed according to the molar ratio of 5:5.1, but not only.
- the concentration of reactant A in the first reaction solvent can be but not only 0.025 moL/L.
- the temperature of the first substitution reaction may range from 0°C to 100°C.
- the first substitution reaction in step S01 can be carried out as follows:
- the first intermediate product can be separated and purified.
- the method for separating and purifying the first intermediate product includes the following steps:
- step S02 according to the second intermediate product shown in the structural formula I Z2 generated, the chemical reaction formula of the redox reaction is shown in the following reaction formula (3):
- the nitro group contained in the first intermediate product reacts to generate -NH2, that is, to generate aniline.
- the acidic additive in step S02 adjusts the pH value of the second reaction solvent, if it is acidic, it ensures that the nitro group finally generates -NH2.
- the acidic additive may include ammonium chloride.
- the concentration of the acidic additive in the second reaction solvent may be 1moL/L.
- the second reaction solvent can be a solution that can effectively dissolve the reactants and acidic compounds, such as dichloromethane, acetone, 1,4-dioxane, acetonitrile, ethanol, isopropanol, isopropanol and water One or more of the mixed solutions.
- the volume ratio of isopropanol to water may be but not only 4:1.
- the reducing agent may include at least one of iron powder and zinc powder.
- the reducing agent can be mixed with the reducing agent in a molar ratio of 25:5 according to the molar ratio of the first intermediate product.
- the concentration of the reducing agent in the second reaction solvent may be 0.5 moL/L.
- the temperature of the redox reaction may be 20°C to 200°C.
- step S02 the redox reaction in step S02 can be carried out as follows:
- the second intermediate product can be separated and purified.
- the method for separating and purifying the second intermediate product includes the following steps:
- the R2 contained in the reactant C in step S03 is the R2 contained in the general formula I of the tetrahydrocarbazole derivative molecular structure in the above application example. Therefore, R2 is any of aryl and heteroaryl.
- the M2 contained in the reactant C is a halogen atom, specifically but not only a bromine atom (Br). Thus, reactant C may be an aryl bromide.
- the R2 contained in the reactant C replaces the hydrogen atom of -NH2 contained in the second intermediate product.
- the composite catalyst includes at least one or a mixture of palladium catalyst, ligand and base.
- the palladium catalyst may include at least one of palladium acetate, tetrakistriphenylphosphine palladium and palladium dichloride, and its concentration in the third reaction solvent may be 0.0002 mol/L.
- the ligand may include at least one of binaphthol and bipyridine.
- the base may include at least one of sodium tert-butoxide, sodium hydride and potassium tert-butoxide, and its concentration in the third reaction solvent may be 0.02moL/L.
- the third reaction solvent should be a solvent that can effectively dissolve each reactant, such as including N,N-dimethylformamide, tetrahydrofuran, 2-methyltetrahydrofuran, acetone, 1,4-dioxane, acetonitrile, diethyl At least one of glycol dimethyl ether, toluene and methylene chloride.
- the reactant C may be in a slight excess relative to the reactant.
- the second intermediate product and the reactant C may be mixed in a molar ratio of 1:1.
- the concentration of the second intermediate product in the third reaction solvent may be 0.02 moL/L.
- the temperature of the second substitution reaction is 20°C to 200°C.
- step S03 the second substitution reaction in step S03 can be carried out as follows:
- the third intermediate product can be separated and purified.
- the method for separating and purifying the third intermediate product includes the following steps:
- step S04 the chemical reaction formula of the condensation reaction between the third intermediate product and aminoguanidine bicarbonate in the fourth reaction solvent is shown in the following reaction formula (5):
- the concentration of the aminoguanidine bicarbonate in the fourth reaction solvent may be 0.05moL/L.
- the fourth reaction solvent may be a solution capable of effectively dissolving various reactants, for example, may include one or more of methanol, ethanol, acetone, 1,4-dioxane, acetonitrile, toluene and methylene chloride.
- the aminoguanidine bicarbonate can be slightly excessive relative to the third intermediate product.
- the aminoguanidine bicarbonate and the third intermediate product can be mixed in a molar ratio of 2:1.5.
- the temperature of the condensation reaction may be 20°C to 200°C.
- condensation reaction in step S04 can be carried out as follows:
- the method for separating and purifying the final product tetrahydrocarbazole derivative includes the following steps:
- the target product can be synthesized by designing the synthesis route of the reactant, so that the synthesized target product has excellent anti-tuberculosis effect.
- the yield of the target product is high, the side reactions are few, the process conditions are easy to control, and the yield and performance of the tetrahydrocarbazole derivatives prepared by the preparation are stable.
- tuberculosis can be effectively inhibited and killed, and the effect of anti-tuberculosis is remarkable, and it is known through experiments that the MIC value of anti-tuberculosis is low, and drug resistance to most tuberculosis will not be produced.
- This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof.
- the structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I1.
- the preparation method of 2,3,4,9-tetrahydrocarbazole derivatives shown in above formula I 1 comprises the steps:
- This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof.
- the structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I 2.
- the preparation method of 2,3,4,9-tetrahydrocarbazole derivatives shown in above formula I 2 comprises the steps:
- step S5 Referring to step S5 in Example 1, 0.64 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized with a yield of 85%. The obtained product confirms the structure through high-resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I2 are as follows:
- This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof.
- the structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I 3.
- step S5 Referring to step S5 in Example 1, 0.77 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized; the yield was 95%.
- the obtained product confirms the structure through high-resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I are as follows:
- This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof.
- the structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I 4.
- step S5 Referring to step S5 in Example 1, 0.70 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized; the yield was 93%.
- the obtained product confirms the structure through high-resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I are as follows:
- This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof.
- the structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I5.
- step S5 Referring to step S5 in Example 1, 0.62 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized, with a yield of 89%.
- the obtained product confirms the structure through high-resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I are as follows:
- This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof.
- the structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I 6.
- step S5 Referring to step S5 in Example 1, 0.75 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized with a yield of 92%. The obtained product confirms the structure through high-resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I6 are as follows:
- This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof.
- the structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I 7.
- step S5 Referring to step S5 in Example 1, 0.72 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized; the yield was 87%.
- the obtained product confirms the structure through high resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I are as follows:
- This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof.
- the structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I 8.
- step S5 Referring to step S5 in Example 1, 0.71 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized with a yield of 85%. The obtained product confirms the structure through high-resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I8 are as follows:
- This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof.
- the structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in Formula I 9 above.
- step S5 Referring to step S5 in Example 1, 0.58 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized; the yield was 92%. The resulting product is confirmed by high-resolution mass spectrometry and nuclear magnetic resonance.
- the mass spectrometry and nuclear magnetic resonance results of 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I9 are as follows:
- This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof.
- the structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in Formula I 9 above.
- step S5 Referring to step S5 in Example 1, 0.59 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized; the yield was 84%. The resulting product is confirmed by high-resolution mass spectrometry and nuclear magnetic resonance.
- the mass spectrometry and nuclear magnetic resonance results of 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I9 are as follows:
- the types of the group R1 contained in the reactant B and the group R2 contained in the reactant C can be selected, such as the group R1 contained in the reactant B in the above-mentioned embodiment 1
- the same or different group R2 contained in reactant C is replaced by substituted or unsubstituted pyrrole, pyrimidine and other groups to synthesize the corresponding tetrahydrocarbazole derivatives.
- the final concentrations of each test drug were set as follows: 0.0039 ⁇ g/mL, 0.0078 ⁇ g/mL, 0.0156 ⁇ g/mL, 0.03125 ⁇ g/mL, 0.0625 ⁇ g/mL, 0.125 ⁇ g/mL ⁇ g/mL, 0.25 ⁇ g/mL, 0.5 ⁇ g/mL, 1.0 ⁇ g/mL, 2.0 ⁇ g/mL, 4.0 ⁇ g/mL, 11 concentration gradients in total.
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Abstract
Provided are a tetrahydrocarbazole derivative represented by general formula (I) as well as a preparation method therefor and the use thereof. By means of design of the molecular structure, the tetrahydrocarbazole derivative has an excellent anti-mycobacterium tuberculosis effect which is even better than that of isoniazid, and does not generate drug resistance to most mycobacterium tuberculosis. The preparation method has a high target product yield, few side reactions and controllable process conditions, and the tetrahydrocarbazole derivative prepared by the method has stable yield and performances.
Description
本申请要求于2022年2月11日在中国专利局提交的、申请号为202210131202.4、发明名称为“四氢咔唑衍生物及其制备方法和应用”的中国专利申请的优先权,其全部内容通过引用结合在本申请中。This application claims the priority of the Chinese patent application with the application number 202210131202.4 and the title of the invention "tetrahydrocarbazole derivatives and their preparation methods and applications" filed at the China Patent Office on February 11, 2022, the entire content of which Incorporated in this application by reference.
本申请属于药物化学技术领域,具体涉及四氢咔唑衍生物及其制备方法和应用。The application belongs to the technical field of medicinal chemistry, and specifically relates to tetrahydrocarbazole derivatives and their preparation methods and applications.
结核病(Tuberculosis,TB)是由其病原体——结核分枝杆菌(Mycobacterium tuberculosis)经空气传播而引起的传染病。目前耐药结核病,尤其是耐多药和广泛耐药结核病,对人类健康乃至生命构成严重威胁,成为全球面临的一大挑战。据世界卫生组织(WHO)报道,结核病已成为排在首位的致死性传染病。我国是全球结核病高负担国家之一,也是结核耐药问题最为严重的国家之一。Tuberculosis (TB) is an infectious disease caused by airborne transmission of its pathogen, Mycobacterium tuberculosis. At present, drug-resistant tuberculosis, especially multidrug-resistant and extensively drug-resistant tuberculosis, poses a serious threat to human health and even life, and has become a major challenge facing the world. According to the World Health Organization (WHO), tuberculosis has become the number one deadly infectious disease. my country is one of the countries with a high burden of tuberculosis in the world and one of the countries with the most serious problem of tuberculosis drug resistance.
叶酸参与核酸和蛋白质的合成,是抗结核杆菌药物的一个重要靶点。DHFR(二氢叶酸还原酶)是生物体内一种重要的酶,可催化二氢叶酸还原成四氢叶酸。不同来源的DHFR,其蛋白质一级结构不同。DHFR抑制剂能特异性地与DHFR结合,抑制其活性,使二氢叶酸不能转变成四氢叶酸,阻碍叶酸代谢,产生抗结核杆菌、抗癌等作用。Folic acid is involved in the synthesis of nucleic acid and protein, and is an important target of anti-tuberculosis drugs. DHFR (dihydrofolate reductase) is an important enzyme in organisms, which can catalyze the reduction of dihydrofolate to tetrahydrofolate. Different sources of DHFR have different primary protein structures. DHFR inhibitors can specifically combine with DHFR to inhibit its activity, so that dihydrofolate cannot be converted into tetrahydrofolate, hinder the metabolism of folic acid, and produce anti-tuberculosis and anti-cancer effects.
自抗结核药物相继问世,使结核病的治疗起到划时代的变化。然而由于结核病患者的治疗管理尚不十分规范,不规则化疗,滥用抗结核药物,使结核病耐药情况日益严重,且耐药性的变化更趋向于多种药物同时耐药,这给结核病的防治工作造成极大困难。因此寻找新的抗结核药物,尤其是抗多药耐药性的抗结核药物对保护人民身体健康,具有重要意义。Since the advent of anti-tuberculosis drugs one after another, the treatment of tuberculosis has played an epoch-making change. However, due to the irregular treatment and management of tuberculosis patients, irregular chemotherapy and abuse of anti-tuberculosis drugs, the drug resistance of tuberculosis is becoming more and more serious, and the change of drug resistance tends to be multi-drug resistance at the same time. work caused great difficulty. Therefore, finding new anti-tuberculosis drugs, especially anti-multidrug resistance anti-tuberculosis drugs, is of great significance to protect people's health.
目前虽然也有公开报道抗结核药物,如异烟肼。但是在临床应用中发现如异烟肼等现有抗结核药物存在抗结核效果不理想或导致存在耐药性等不足。Although there are also public reports of anti-tuberculosis drugs, such as isoniazid. However, in clinical application, it is found that existing anti-tuberculosis drugs such as isoniazid have unsatisfactory anti-tuberculosis effects or lead to drug resistance and other deficiencies.
本申请的目的在于克服现有技术的上述不足,提供一种四氢咔唑衍生物及其制备方法,以解决现有抗结核药物存在抗结核分枝杆菌效果不理想或导致存在耐药性等不足的技术问题。The purpose of this application is to overcome the above-mentioned deficiencies in the prior art, provide a tetrahydrocarbazole derivative and its preparation method, to solve the existing anti-tuberculosis drugs have unsatisfactory anti-tuberculosis Mycobacterium effect or lead to the existence of drug resistance, etc. Inadequate technical issues.
为了实现上述申请目的,本申请的第一方面,提供了一种四氢咔唑衍生物。本申请四氢咔唑衍生物的分子结构式如下述通式Ⅰ所示:In order to achieve the purpose of the above application, the first aspect of the present application provides a tetrahydrocarbazole derivative. The molecular structural formula of the tetrahydrocarbazole derivatives of the present application is shown in the following general formula I:
其中,通式Ⅰ中的R1、R2相同或不相同的为芳基、杂芳基中的任一种。Wherein, the same or different R1 and R2 in the general formula I are any one of aryl and heteroaryl.
本申请的第二方面,提供了本申请四氢咔唑衍生物的制备方法。本申请四氢咔唑衍生物的制备方法包括如下步骤:The second aspect of the present application provides the preparation method of the tetrahydrocarbazole derivatives of the present application. The preparation method of tetrahydrocarbazole derivative of the present application comprises the steps:
将如下结构式Ⅰ A所示的反应物A与如下结构式Ⅰ B所示的反应物B和碱催化剂于第一 反应溶剂中进行第一取代反应,生成如下结构式Ⅰ Z1所示的第一中间产物;The reactant A shown in the following structural formula I A and the reactant B shown in the following structural formula I B and the base catalyst are carried out in the first reaction solvent for the first substitution reaction, generating the first intermediate product shown in the following structural formula I Z1;
将所述第一中间产物与还原剂、酸性添加剂在第二反应溶剂中反进行氧化还原反应,生成如下结构式Ⅰ Z2所示的第二中间产物;The first intermediate product, reducing agent and acidic additive are reversely carried out redox reaction in the second reaction solvent to generate the second intermediate product shown in the following structural formula I Z2;
将所述第二中间产物与如下结构式Ⅰ C所示的反应物C和复合催化剂于第三反应溶剂中进行第二取代反应,生成如下结构式Ⅰ Z3所示的第三中间产物;The second intermediate product is carried out with the reactant C shown in the following structural formula I C and the composite catalyst in the third reaction solvent to carry out the second substitution reaction to generate the third intermediate product shown in the following structural formula I Z3;
在保护气氛中,将所述第三中间产物与氨基胍碳酸氢盐于第四反应溶剂中进行缩合反应,生成如下结构式Ⅰ所示的四氢咔唑衍生物;In a protective atmosphere, the third intermediate product is condensed with aminoguanidine bicarbonate in a fourth reaction solvent to generate a tetrahydrocarbazole derivative shown in the following structural formula I;
其中,所述式Ⅰ B中的M1和式Ⅰ c中的M2相同或不相同的为卤素原子,所述式Ⅰ B中的R1和式Ⅰ C的R2相同或不相同的为芳基、杂芳基中的任一种。Wherein, the same or different M1 in the formula I B and the M2 in the formula I c are halogen atoms, and the same or different R1 in the formula I B and the R2 in the formula I C are aryl, hetero Any of the aryl groups.
本申请的第三方面,提供了本申请四氢咔唑衍生物的应用。本申请四氢咔唑衍生物作为结核分枝杆菌抑制剂或在制备抗结核药物中的应用。The third aspect of the present application provides the application of the tetrahydrocarbazole derivatives of the present application. The application of tetrahydrocarbazole derivatives as Mycobacterium tuberculosis inhibitors or in the preparation of anti-tuberculosis drugs.
与现有技术相比,本申请第一方面提供的四氢咔唑衍生物通过其分子结构的设计,具有优异的抗结核菌效果,其抗结核菌效果甚至优异异烟肼,而且对大多数结核杆菌不会产 生耐药性。Compared with the prior art, the tetrahydrocarbazole derivative provided by the first aspect of the present application has excellent anti-tuberculosis effect through the design of its molecular structure, and its anti-tuberculosis effect is even excellent for isoniazid, and it is effective for most Mycobacterium tuberculosis does not develop drug resistance.
本申请第二方面提供的四氢咔唑衍生物制备方法通过对反应物合成路线的设计,能够合成目标产物,使得合成的目标产物具有优异的抗结核菌效果。另外,目标产物得率高,副反应少,工艺条件易控,其制备获得的四氢咔唑衍生物的得率和性能稳定。The method for preparing tetrahydrocarbazole derivatives provided in the second aspect of the present application can synthesize the target product by designing the synthesis route of the reactant, so that the synthesized target product has excellent anti-tuberculosis effect. In addition, the yield of the target product is high, the side reactions are few, the process conditions are easy to control, and the yield and performance of the tetrahydrocarbazole derivatives prepared by the preparation are stable.
本申请第三方面提供的本申请四氢咔唑衍生物作为结核分枝杆菌抑制剂或在制备抗结核药物中的应用时,能够有效抑制、杀灭结核菌,抗结核菌效果显著,且抗结核菌的MIC值低;而且对大多数结核杆菌不会产生耐药性。The tetrahydrocarbazole derivatives of the present application provided by the third aspect of the present application can effectively inhibit and kill Mycobacterium tuberculosis when used as Mycobacterium tuberculosis inhibitors or in the preparation of anti-tuberculosis drugs, the anti-tuberculosis effect is remarkable, and the anti-tuberculosis The MIC value of Mycobacterium tuberculosis is low; And most of Mycobacterium tuberculosis will not produce drug resistance.
为了使本申请要解决的技术问题、技术方案及有益效果更加清楚明白,以下结合实施例,对本申请进行进一步详细说明。应当理解,此处所描述的具体实施例仅仅用以解释本申请,并不用于限定本申请。In order to make the technical problems, technical solutions and beneficial effects to be solved in the present application clearer, the present application will be further described in detail below in conjunction with the embodiments. It should be understood that the specific embodiments described here are only used to explain the present application, and are not intended to limit the present application.
本申请中,术语“和/或”,描述关联对象的关联关系,表示可以存在三种关系,例如,A和/或B,可以表示:单独存在A,同时存在A和B,单独存在B的情况。其中A,B可以是单数或者复数。字符“/”一般表示前后关联对象是一种“或”的关系。In this application, the term "and/or" describes the association relationship of associated objects, indicating that there may be three relationships, for example, A and/or B may mean: A exists alone, A and B exist simultaneously, and B exists alone Condition. Among them, A and B can be singular or plural. The character "/" generally indicates that the contextual objects are an "or" relationship.
本申请中,“至少一个”是指一个或者多个,“多个”是指两个或两个以上。“以下至少一项(个)”或其类似表达,是指的这些项中的任意组合,包括单项(个)或复数项(个)的任意组合。例如,“a,b,或c中的至少一项(个)”,或,“a,b,和c中的至少一项(个)”,均可以表示:a,b,c,a-b(即a和b),a-c,b-c,或a-b-c,其中a,b,c分别可以是单个,也可以是多个。In this application, "at least one" means one or more, and "multiple" means two or more. "At least one of the following" or similar expressions refer to any combination of these items, including any combination of single or plural items. For example, "at least one item (unit) of a, b, or c", or "at least one item (unit) of a, b, and c" can mean: a, b, c, a-b( That is, a and b), a-c, b-c, or a-b-c, where a, b, and c can be single or multiple.
应理解,在本申请的各种实施例中,上述各过程的序号的大小并不意味着执行顺序的先后,部分或全部步骤可以并行执行或先后执行,各过程的执行顺序应以其功能和内在逻辑确定,而不应对本申请实施例的实施过程构成任何限定。It should be understood that in various embodiments of the present application, the sequence numbers of the above-mentioned processes do not mean the order of execution, and some or all steps may be executed in parallel or sequentially, and the execution order of each process shall be based on its functions and The internal logic is determined and should not constitute any limitation to the implementation process of the embodiment of the present application.
在本申请实施例中使用的术语是仅仅出于描述特定实施例的目的,而非旨在限制本申请。在本申请实施例和所附权利要求书中所使用的单数形式的“一种”和“该”也旨在包括多数形式,除非上下文清楚地表示其他含义。Terms used in the embodiments of the present application are only for the purpose of describing specific embodiments, and are not intended to limit the present application. The singular forms "a" and "the" used in the embodiments of this application and the appended claims are also intended to include plural forms unless the context clearly indicates otherwise.
本申请实施例说明书中所提到的相关成分的重量不仅仅可以指代各组分的具体含量,也可以表示各组分间重量的比例关系,因此,只要是按照本申请实施例说明书相关组分的含量按比例放大或缩小均在本申请实施例说明书公开的范围之内。具体地,本申请实施例说明书中的质量可以是μg、mg、g、kg等化工领域公知的质量单位。The weight of the relevant components mentioned in the description of the embodiments of the present application can not only refer to the specific content of each component, but also represent the proportional relationship between the weights of the various components. The scaling up or down of the content of the fraction is within the scope disclosed in the description of the embodiments of the present application. Specifically, the mass in the description of the embodiments of the present application may be μg, mg, g, kg and other well-known mass units in the chemical industry.
第一方面,本申请实施例提供了一种四氢咔唑衍生物。本申请实施例四氢咔唑衍生物的分子结构式如下述通式Ⅰ所示:In the first aspect, the embodiment of the present application provides a tetrahydrocarbazole derivative. The molecular structural formula of the tetrahydrocarbazole derivative of the embodiment of the present application is shown in the following general formula I:
其中,通式Ⅰ中的R1、R2相同或不相同的为芳基、杂芳基中的任一种。这样,本申请实施例四氢咔唑衍生物通过其分子结构的设计,具有优异的抗结核菌效果。经检测得知,本申请实施例四氢咔唑衍生物抗结核菌的MIC值低,其抗结核菌效果甚至优异异烟肼,而且对大多数结核杆菌不会产生耐药性。Wherein, the same or different R1 and R2 in the general formula I are any one of aryl and heteroaryl. In this way, the tetrahydrocarbazole derivatives in the examples of the present application have excellent anti-tuberculosis effects through the design of their molecular structures. It is known from the test that the tetrahydrocarbazole derivatives of the present application have low anti-tuberculosis MIC values, and their anti-tuberculosis effects are even superior to isoniazid, and they will not produce drug resistance to most tuberculosis bacteria.
其中,发明人在研究中发现,本申请实施例四氢咔唑衍生物所含的R1、R2的种类对其抗结核菌效果有影响,如R1、R2相同或不相同的为芳基、杂芳基中的任一种的基础上,通过进一步优化R1、R2所示的基团,能够进一步优化提高本申请实施例四氢咔唑衍生物的抗结核菌效果。Among them, the inventor found in the research that the types of R1 and R2 contained in the tetrahydrocarbazole derivatives of the embodiments of the present application have an impact on their anti-tuberculosis effect, such as R1 and R2 are the same or different for aryl, hetero On the basis of any one of the aryl groups, by further optimizing the groups represented by R1 and R2, the anti-tuberculosis effect of the tetrahydrocarbazole derivatives in the examples of the present application can be further optimized and improved.
如实施例中,R1、R2相同或不相同的为芳基时,该芳基可以包括苯基、单取代苯基、多取代苯基中的任一种。在具体实施例中,单取代苯基中的取代基团可以包括卤素原子、-CF3、-C≡CH、-C≡N、-NO2、-OCH3中的任一种。在另些具体实施例中,该多取代苯基中的取代基团可以包括卤素原子、-OCH3中的至少一种。选用该些苯基、单取代苯基、多取代苯基,或进一步对该单取代苯基、多取代苯基的取代基团进行控制和优化,进一步提高本申请实施例四氢咔唑衍生物的抗结核菌活性,进一步降低其抗结核菌的MIC值低。As in the embodiment, when the same or different R1 and R2 are aryl groups, the aryl groups may include any of phenyl, monosubstituted phenyl, and polysubstituted phenyl. In a specific embodiment, the substituent group in the monosubstituted phenyl group may include any one of a halogen atom, -CF3, -C≡CH, -C≡N, -NO2, -OCH3. In other specific embodiments, the substituent groups in the polysubstituted phenyl group may include at least one of halogen atoms and -OCH3. Select these phenyls, monosubstituted phenyls, polysubstituted phenyls, or further control and optimize the substituting groups of the monosubstituted phenyls, polysubstituted phenyls, and further improve the tetrahydrocarbazole derivatives of the present application examples. The anti-tuberculosis activity further reduces the MIC value of its anti-tuberculosis.
如另些实施例中,R1、R2相同或不相同的为杂芳基时,该杂芳基可以包括吡咯、取代吡咯、噻吩、取代噻吩、吡啶、取代吡啶、嘧啶、取代嘧啶中的任一种。在具体实施例中,取代吡咯中的取代基团可以包括-OCH3。取代噻吩中的取代基团可以包括-C≡N。杂芳基,或进一步对该些取代吡咯、取代噻吩、取代吡啶、取代嘧啶的取代基团进行控制和优化,进一步提高本申请实施例四氢咔唑衍生物的抗结核菌活性,进一步降低其抗结核菌的MIC值低。As in other embodiments, when R1 and R2 are identical or not identical to heteroaryl, the heteroaryl may include any of pyrrole, substituted pyrrole, thiophene, substituted thiophene, pyridine, substituted pyridine, pyrimidine, and substituted pyrimidine kind. In a specific embodiment, the substituent group in the substituted pyrrole may include -OCH3. Substituent groups in substituted thiophenes may include -C≡N. Heteroaryl, or further control and optimize the substituent groups of these substituted pyrroles, substituted thiophenes, substituted pyridines, and substituted pyrimidines to further improve the anti-tuberculosis activity of tetrahydrocarbazole derivatives in the examples of the present application, and further reduce their MIC value against tuberculosis is low.
基于上述各实施例中R1、R2所示的基团,在具体实施例中,本申请实施例四氢咔唑衍生物至少可以是如下分子结构式Ⅰ 1至结构式Ⅰ 10中的至少一种:Based on the groups represented by R1 and R2 in the above-mentioned embodiments, in specific embodiments, the tetrahydrocarbazole derivatives in the embodiments of the present application can at least be at least one of the following molecular structural formulas I 1 to structural formula I 10:
上述各四氢咔唑衍生物具有高的抗结核菌活性,且其抗结核菌的MIC值低。如对上述Ⅰ 1至Ⅰ 10所示四氢咔唑衍生物进行体外抗结核分枝杆菌活性测试得知,Ⅰ 3至Ⅰ 5、Ⅰ 8的活性与异烟肼相当,Ⅰ 6、Ⅰ 7的活性优于异烟肼。Each tetrahydrocarbazole derivative mentioned above has high anti-tuberculosis activity, and its anti-tuberculosis MIC value is low. As shown in the in vitro anti-mycobacterium tuberculosis activity test of the tetrahydrocarbazole derivatives shown in I 1 to I 10 above, the activities of I 3 to I 5 and I 8 are equivalent to isoniazid, and the activities of I 6 and I 7 are equivalent to those of isoniazid. Activity is better than isoniazid.
另一方面,本申请实施例提供了上文本申请实施例四氢咔唑衍生物的制备方法。本申请实施例四氢咔唑衍生物的制备方法包括如下步骤:On the other hand, the examples of the present application provide the preparation method of tetrahydrocarbazole derivatives in the above examples of the application. The preparation method of the tetrahydrocarbazole derivative of the embodiment of the present application comprises the following steps:
S01:将如下结构式Ⅰ A所示的反应物A与如下结构式Ⅰ B所示的反应物B和碱催化剂于第一反应溶剂中进行第一取代反应,生成如下结构式Ⅰ Z1所示的第一中间产物;S01: The reactant A shown in the following structural formula I A, the reactant B shown in the following structural formula I B and the base catalyst are subjected to the first substitution reaction in the first reaction solvent to generate the first intermediate shown in the following structural formula I Z1 product;
S02:将所述第一中间产物与还原剂、酸性添加剂在第二反应溶剂中反进行氧化还原反应,生成如下结构式Ⅰ Z2所示的第二中间产物;S02: the first intermediate product, reducing agent, and acidic additive are reversely carried out in a second reaction solvent for oxidation-reduction reaction to generate the second intermediate product shown in the following structural formula I Z2;
S03:将所述第二中间产物与如下结构式Ⅰ C所示的反应物C和复合催化剂于第三反应溶剂中进行第二取代反应,生成如下结构式Ⅰ Z3所示的第三中间产物;S03: the second intermediate product is carried out with the reactant C shown in the following structural formula I C and the composite catalyst in the third reaction solvent for the second substitution reaction, generating the third intermediate product shown in the following structural formula I Z3;
S04:在保护气氛中,将所述第三中间产物与氨基胍碳酸氢盐于第四反应溶剂中进行缩合反应,生成如下结构式Ⅰ所示的四氢咔唑衍生物。S04: In a protective atmosphere, the third intermediate product is condensed with aminoguanidine bicarbonate in a fourth reaction solvent to generate a tetrahydrocarbazole derivative shown in the following structural formula I.
其中,步骤S01中的反应物A和反应B可以按照现有方法获得。如实施例中,结构式Ⅰ A所示的反应物A(中文名称:2(6-硝基-7-氟-2,3,4,9-四氢咔唑-1-酮))可以但不仅仅按照如下方法合成:Wherein, reactant A and reaction B in step S01 can be obtained according to existing methods. As in the examples, the reactant A (Chinese name: 2(6-nitro-7-fluoro-2,3,4,9-tetrahydrocarbazol-1-one)) shown in structural formula I A can but not only Synthesize only as follows:
S011:将下述结构式Ⅰ A1所示的4-硝基-5-氟苯肼(反应产物A1)、结构式Ⅰ A2所示的2-环己二酮(反应产物A2)在第一酸反应溶液中进行取代反应,生成结构式Ⅰ A3所示的反应产物A3;S011: 4-nitro-5-fluorophenylhydrazine (reaction product A1) shown in the following structural formula I A1, 2-cyclohexanedione (reaction product A2) shown in structural formula I A2 in the first acid reaction solution Carry out substitution reaction in, generate the reaction product A3 shown in structural formula Ⅰ A3;
S012:将反应产物A3与第二酸反应溶液进行回流反应,生成反应物A。S012: Refluxing the reaction product A3 with the second acid reaction solution to generate reactant A.
根据上述实施例中反应物A合成路线,反应物A总的合成化学反应式如下反应式(1)所示:According to the synthesis route of reactant A in the above-mentioned embodiment, the total synthetic chemical reaction formula of reactant A is shown in the following reaction formula (1):
其中,步骤S011中4-硝基-5-氟苯肼与2-环己二酮的混合比例可以根据化学反应式(1)所示的摩尔比例进行混合处理,为了提高反应产物A3的得率,其中,反应物4-硝基-5-氟苯肼或2-环己二酮其中一组分可以适当的过量。实施例中,第一酸反应溶液包括盐酸、硫酸、硝酸、醋酸等的一种或多种,进一步选用盐酸。第一酸反应溶液的浓度应该是有利于反应产物A3得率和正向反应速率,如具体实施例中,该第一酸反应溶液为盐酸时,其浓度可以但不仅仅为1moL/L。反应物4-硝基-5-氟苯肼的添加量也可以按照30g 4-硝基-5-氟苯肼与700mL(1moL/L)的盐酸溶液混合比例混合。另外,步骤S011中的取代反应可以是在回流条件的温度可以是30℃~150℃,进一步为105℃。进行充分反应,如回流搅拌20小时。Wherein, the mixing ratio of 4-nitro-5-fluorophenylhydrazine and 2-cyclohexanedione in step S011 can be mixed according to the molar ratio shown in chemical reaction formula (1), in order to improve the yield of reaction product A3 , wherein one of the reactants 4-nitro-5-fluorophenylhydrazine or 2-cyclohexanedione can be in excess. In an embodiment, the first acid reaction solution includes one or more of hydrochloric acid, sulfuric acid, nitric acid, acetic acid, etc., and hydrochloric acid is further selected. The concentration of the first acid reaction solution should be conducive to the yield of the reaction product A3 and the forward reaction rate. As in a specific embodiment, when the first acid reaction solution is hydrochloric acid, its concentration can be but not only 1moL/L. The addition amount of reactant 4-nitro-5-fluorophenylhydrazine can also be mixed according to the hydrochloric acid solution mixing ratio of 30g 4-nitro-5-fluorophenylhydrazine and 700mL (1moL/L). In addition, the substitution reaction in step S011 may be under reflux conditions and the temperature may be 30°C to 150°C, further 105°C. Fully react, such as stirring at reflux for 20 hours.
在具体实施例中,S011可以按照如下方法进行:In a specific embodiment, S011 can be carried out as follows:
按照30g的4-硝基-5-氟苯肼、21g的1,2-环己二酮和1moL/L的盐酸溶液700mL的比例将各组分进行混合处理,再回流搅拌12小时,生成反应产物A3。According to the ratio of 30g of 4-nitro-5-fluorophenylhydrazine, 21g of 1,2-cyclohexanedione and 700mL of 1moL/L hydrochloric acid solution, the components were mixed, and then refluxed and stirred for 12 hours to form a reaction Product A3.
步骤S012中的第二酸反应溶液可以包括盐酸、硫酸、硝酸、醋酸等的一种或多种,进一步为盐酸和醋酸的混合溶剂。具体实施例中,盐酸和醋酸的混合溶剂中,浓盐酸和冰醋酸可以但不仅仅按照400mL:100mL。反应产物A3在浓盐酸和冰醋酸的混合物反应溶液中的浓度可以但不仅仅按照步骤S011中的4-硝基-5-氟苯肼反应物30g添加400mL浓盐酸的混合比例混合。步骤S012中回流反应的温度控制控制在20℃~200℃,进一步为90℃。The second acid reaction solution in step S012 may include one or more of hydrochloric acid, sulfuric acid, nitric acid, acetic acid, etc., and further be a mixed solvent of hydrochloric acid and acetic acid. In a specific embodiment, in the mixed solvent of hydrochloric acid and acetic acid, concentrated hydrochloric acid and glacial acetic acid can be but not only according to 400mL: 100mL. The concentration of the reaction product A3 in the mixture reaction solution of concentrated hydrochloric acid and glacial acetic acid can be, but not only mixed according to the mixing ratio of 30 g of 4-nitro-5-fluorophenylhydrazine reactant in step S011 and 400 mL of concentrated hydrochloric acid. The temperature of the reflux reaction in step S012 is controlled at 20°C to 200°C, further to 90°C.
在具体实施例中,S012可以按照如下方法进行:In a specific embodiment, S012 can be carried out as follows:
将步骤S011的反应产物A3与体积比为400:100的浓盐酸与冰醋酸进行混合处理,并回流搅拌20小时,生成反应物A。The reaction product A3 in step S011 was mixed with concentrated hydrochloric acid and glacial acetic acid at a volume ratio of 400:100, and stirred under reflux for 20 hours to generate reactant A.
步骤S01中的反应物B所含的R1为上文本申请实施例四氢咔唑衍生物分子结构通式Ⅰ所含的R1。因此,R1为芳基、杂芳基中的任一种。反应物B所含的M1为卤素原子,具体可以但不仅仅是溴原子(Br)。因此,反应物B可以为苄溴类化合物。那么步骤S01中反应物A与反应物B在进行第一取代反应过程中,反应物B所含的R1取代反应物A所含仲胺的氢原子。The R1 contained in the reactant B in step S01 is the R1 contained in the general formula I of the tetrahydrocarbazole derivative molecular structure in the above application example. Therefore, R1 is any of aryl and heteroaryl. The M1 contained in the reactant B is a halogen atom, specifically but not only a bromine atom (Br). Therefore, reactant B may be a benzyl bromide compound. Then, during the first substitution reaction between the reactant A and the reactant B in step S01, the R1 contained in the reactant B replaces the hydrogen atom of the secondary amine contained in the reactant A.
实施例中,步骤S01中第一反应溶剂可以包括N,N-二甲基甲酰胺、四氢呋喃、2-甲基四氢呋喃、丙酮、1,4-二氧六环、乙腈、二乙二醇二甲醚、甲苯和二氯甲烷中的至少一种。碱催化剂包括碳酸铯、碳酸钾、碳酸钠、碳酸氢钠、氢氧化钠中的至少一种,进一步为碳酸铯。碱催化剂在第一反应溶剂中的浓度可以但不仅仅为0.025moL/L。在第一取代反应体系中,反应物B可以相对反应物稍过量,如实施例中,反应物A与反应物B可以但不仅仅是按照5:5.1的摩尔比混合。反应物A在第一反应溶剂中的浓度可以但不仅仅是0.025moL/L。第一取代反应的温度可以为0℃~100℃。通过对第一取代反应体系的反应物、溶剂和种类控制与选择,能够提高第一中间产物的得率,并提高正向反应的速率。In an embodiment, the first reaction solvent in step S01 may include N,N-dimethylformamide, tetrahydrofuran, 2-methyltetrahydrofuran, acetone, 1,4-dioxane, acetonitrile, diethylene glycol dimethyl At least one of ether, toluene and methylene chloride. The base catalyst includes at least one of cesium carbonate, potassium carbonate, sodium carbonate, sodium bicarbonate, and sodium hydroxide, and is further cesium carbonate. The concentration of the base catalyst in the first reaction solvent can be but not only 0.025moL/L. In the first substitution reaction system, the reactant B can be slightly excessive relative to the reactant, as in the example, the reactant A and the reactant B can be mixed according to the molar ratio of 5:5.1, but not only. The concentration of reactant A in the first reaction solvent can be but not only 0.025 moL/L. The temperature of the first substitution reaction may range from 0°C to 100°C. By controlling and selecting the reactants, solvents and types of the first substitution reaction system, the yield of the first intermediate product can be increased, and the rate of the forward reaction can be increased.
因此,步骤S01中反应物A和反应物B之间的第一取代反应化学反应式如下反应式(2)所示:Therefore, the chemical reaction formula of the first substitution reaction between reactant A and reactant B in step S01 is shown in the following reaction formula (2):
在具体实施例中,步骤S01中的第一取代反应可以按照如下方法进行:In a specific embodiment, the first substitution reaction in step S01 can be carried out as follows:
按照5mmol化合物A,200mL DMF、5mmol碳酸铯和5.1mmol反应物B的混合比例混合各组分,室温反应,生成第一中间产物。According to the mixing ratio of 5mmol compound A, 200mL DMF, 5mmol cesium carbonate and 5.1mmol reactant B, the components were mixed and reacted at room temperature to generate the first intermediate product.
待第一取代反应结束后,可以对第一中间产物进行分离纯化。实施例中,对第一中间产物进行分离纯化方法包括如下步骤:After the first substitution reaction is completed, the first intermediate product can be separated and purified. In an embodiment, the method for separating and purifying the first intermediate product includes the following steps:
对经第一取代反应后的混合溶液进行固液分离,滤除固体,加入饱和氯化铵溶液,调整溶液pH为6-7,用乙酸乙酯萃取三次,合并有机相,用饱和氯化钠溶液洗涤,有机相旋蒸,得第一中间产物固体物。Carry out solid-liquid separation to the mixed solution after the first substitution reaction, filter out the solid, add saturated ammonium chloride solution, adjust the pH of the solution to 6-7, extract three times with ethyl acetate, combine the organic phases, and wash with saturated sodium chloride The solution was washed, and the organic phase was rotary evaporated to obtain the first intermediate product as a solid.
步骤S02中,根据生成的结构式Ⅰ Z2所示第二中间产物,该氧化还原反应的化学反应式如下反应式(3)所示:In step S02, according to the second intermediate product shown in the structural formula I Z2 generated, the chemical reaction formula of the redox reaction is shown in the following reaction formula (3):
步骤S02中的第一中间产物在还原剂和酸性添加剂存在前提下,第一中间产物所含的硝基发生反应生成-NH2,也即是生成苯胺。实施例中,步骤S02中的酸性添加剂调节第二 反应溶剂的pH值,如呈酸性,保证硝基最终生成-NH2。因此,实施例中,酸性添加剂可以包括氯化铵。实施例中,该酸性添加剂在第二反应溶剂中的浓度可以是1moL/L。该第二反应溶剂可以是能够有效溶解各反应物和酸性化合物的溶液,如可以是二氯甲烷、丙酮、1,4-二氧六环、乙腈、乙醇、异丙醇、异丙醇与水的混合溶液中的一种或多种。其中,在异丙醇与水的混合溶液中,异丙醇与水的体积比可以但不仅仅为4:1。In the first intermediate product in step S02, in the presence of a reducing agent and an acidic additive, the nitro group contained in the first intermediate product reacts to generate -NH2, that is, to generate aniline. In an embodiment, the acidic additive in step S02 adjusts the pH value of the second reaction solvent, if it is acidic, it ensures that the nitro group finally generates -NH2. Thus, in embodiments, the acidic additive may include ammonium chloride. In an embodiment, the concentration of the acidic additive in the second reaction solvent may be 1moL/L. The second reaction solvent can be a solution that can effectively dissolve the reactants and acidic compounds, such as dichloromethane, acetone, 1,4-dioxane, acetonitrile, ethanol, isopropanol, isopropanol and water One or more of the mixed solutions. Wherein, in the mixed solution of isopropanol and water, the volume ratio of isopropanol to water may be but not only 4:1.
实施例中,还原剂可以包括铁粉、锌粉中的至少一种。在氧化还原反应体系中,该还原剂可以还原剂与按照第一中间产物的摩尔比为25:5的摩尔比混合。还原剂在第二反应溶剂中的浓度可以是0.5moL/L。另外,氧化还原反应的温度可以为20℃~200℃。通过对氧化还原反应的反应物、浓度和种类控制与选择,能够提高第二中间产物的得率,并提高氧化还原反应正向反应的速率。In an embodiment, the reducing agent may include at least one of iron powder and zinc powder. In the oxidation-reduction reaction system, the reducing agent can be mixed with the reducing agent in a molar ratio of 25:5 according to the molar ratio of the first intermediate product. The concentration of the reducing agent in the second reaction solvent may be 0.5 moL/L. In addition, the temperature of the redox reaction may be 20°C to 200°C. By controlling and selecting the reactants, concentrations and types of the redox reaction, the yield of the second intermediate product can be increased, and the rate of the forward reaction of the redox reaction can be increased.
在具体实施例中,步骤S02中的氧化还原反应可以按照如下方法进行:In a specific embodiment, the redox reaction in step S02 can be carried out as follows:
按照第一中间产物5mmoL、铁粉25mmol和氯化铵50mmoL、异丙醇-水(4:1)50ml的比例将各组分混合处理,90℃回流搅拌反应15小时。According to the ratio of 5mmoL of the first intermediate product, 25mmol of iron powder, 50mmoL of ammonium chloride, and 50ml of isopropanol-water (4:1), the components were mixed and reacted at 90°C for 15 hours under reflux and stirring.
待氧化还原反应结束后,可以对第二中间产物进行分离纯化。实施例中,对第二中间产物进行分离纯化方法包括如下步骤:After the redox reaction is finished, the second intermediate product can be separated and purified. In an embodiment, the method for separating and purifying the second intermediate product includes the following steps:
待经氧化还原反应后的混合溶液冷却后,减压旋蒸出溶剂,残渣中加入水溶解,用碳酸氢钠调pH值至8-9,用乙酸乙酯萃取,有机层用水洗涤两次,饱和氯化钠溶液洗涤,无水硫酸钠干燥,减压蒸出溶剂;残余物用硅胶柱层析纯化,淋洗剂为乙酸乙酯,得到第二中间产物。After the mixed solution after redox reaction was cooled, the solvent was evaporated under reduced pressure, water was added to dissolve the residue, the pH value was adjusted to 8-9 with sodium bicarbonate, extracted with ethyl acetate, and the organic layer was washed twice with water. Wash with saturated sodium chloride solution, dry over anhydrous sodium sulfate, and distill off the solvent under reduced pressure; the residue is purified by silica gel column chromatography with ethyl acetate as the eluent to obtain the second intermediate product.
步骤S03中的反应物C所含的R2为上文本申请实施例四氢咔唑衍生物分子结构通式Ⅰ所含的R2。因此,R2为芳基、杂芳基中的任一种。反应物C所含的M2为卤素原子,具体可以但不仅仅是溴原子(Br)。因此,反应物C可以是芳基溴。那么步骤S03中第二中间产物与反应物C在进行第二取代反应过程中,反应物C所含的R2取代第二中间产物所含-NH2的氢原子。根据其反应类型,实施例中,在该第二取代反应体系中,实施例中,复合催化剂包括钯催化剂、配体和碱中的至少一种或三者混合物。其中,钯催化剂可以包括醋酸钯、四三苯基膦钯和二氯化钯中的至少一种,其在第三反应溶剂中的浓度可以是0.0002moL/L。配体可以包括联萘酚、联吡啶中的至少一种。碱可以包括叔丁醇钠、氢化钠、叔丁醇钾中的至少一种,其在第三反应溶剂中的浓度可以是0.02moL/L。The R2 contained in the reactant C in step S03 is the R2 contained in the general formula I of the tetrahydrocarbazole derivative molecular structure in the above application example. Therefore, R2 is any of aryl and heteroaryl. The M2 contained in the reactant C is a halogen atom, specifically but not only a bromine atom (Br). Thus, reactant C may be an aryl bromide. Then in step S03, during the second substitution reaction between the second intermediate product and the reactant C, the R2 contained in the reactant C replaces the hydrogen atom of -NH2 contained in the second intermediate product. According to the reaction type, in the embodiment, in the second substitution reaction system, in the embodiment, the composite catalyst includes at least one or a mixture of palladium catalyst, ligand and base. Wherein, the palladium catalyst may include at least one of palladium acetate, tetrakistriphenylphosphine palladium and palladium dichloride, and its concentration in the third reaction solvent may be 0.0002 mol/L. The ligand may include at least one of binaphthol and bipyridine. The base may include at least one of sodium tert-butoxide, sodium hydride and potassium tert-butoxide, and its concentration in the third reaction solvent may be 0.02moL/L.
第三反应溶剂应该是能够有效溶解各反应物的溶剂,如包括N,N-二甲基甲酰胺、四氢呋喃、2-甲基四氢呋喃、丙酮、1,4-二氧六环、乙腈、二乙二醇二甲醚、甲苯和二氯甲烷中的至少一种。The third reaction solvent should be a solvent that can effectively dissolve each reactant, such as including N,N-dimethylformamide, tetrahydrofuran, 2-methyltetrahydrofuran, acetone, 1,4-dioxane, acetonitrile, diethyl At least one of glycol dimethyl ether, toluene and methylene chloride.
在第二取代反应体系中,反应物C可以相对反应物稍过量,如实施例中,第二中间产物与反应物C按照可以是1:1的摩尔比混合。第二中间产物在第三反应溶剂中的浓度可以是0.02moL/L。另外,第二取代反应的温度为20℃~200℃。通过对第二取代反应体系的反应物、溶剂浓度和种类控制与选择,能够提高第三中间产物的得率,并提高正向反应的速率。因此,步骤S03中第二中间产物和反应物C之间的第二取代反应化学反应式如下反应式(4)所示:In the second substitution reaction system, the reactant C may be in a slight excess relative to the reactant. As in the embodiment, the second intermediate product and the reactant C may be mixed in a molar ratio of 1:1. The concentration of the second intermediate product in the third reaction solvent may be 0.02 moL/L. In addition, the temperature of the second substitution reaction is 20°C to 200°C. By controlling and selecting the reactant, solvent concentration and type of the second substitution reaction system, the yield of the third intermediate product can be increased, and the rate of the forward reaction can be increased. Therefore, the second substitution reaction chemical reaction formula between the second intermediate product and reactant C in step S03 is shown in the following reaction formula (4):
在具体实施例中,步骤S03中的第二取代反应可以按照如下方法进行:In a specific embodiment, the second substitution reaction in step S03 can be carried out as follows:
氩气保护下,按照第二中间产物(2mmoL)、反应物C(2mmol)、醋酸钯(0.02mmoL)、联萘酚(0.04mmoL)、叔丁醇钠(2mmol)和甲苯100ml的混合比例将各反应物和溶剂混合处理,100℃反应10小时。Under argon protection, according to the mixing ratio of the second intermediate product (2mmoL), reactant C (2mmol), palladium acetate (0.02mmoL), binaphthol (0.04mmoL), sodium tert-butoxide (2mmol) and toluene 100ml The reactants were mixed with the solvent and reacted at 100°C for 10 hours.
待第二取代反应结束后,可以对第三中间产物进行分离纯化。实施例中,对第三中间产物进行分离纯化方法包括如下步骤:After the second substitution reaction is completed, the third intermediate product can be separated and purified. In an embodiment, the method for separating and purifying the third intermediate product includes the following steps:
对经第二取代反应后的混合溶液用硅藻土过滤,再加饱和氯化铵溶液调pH值为6-7,用乙酸乙酯萃取后用饱和食盐水洗涤;有机相减压旋蒸出溶剂,残余物用硅胶柱层析,淋洗液为二氯甲烷与甲醇的混合溶剂;收集纯品馏分,减压旋蒸出溶剂得纯品第三中间产物。Filter the mixed solution after the second substitution reaction with diatomaceous earth, add saturated ammonium chloride solution to adjust the pH value to 6-7, extract with ethyl acetate and wash with saturated brine; the organic phase is evaporated under reduced pressure. Solvent, the residue was subjected to silica gel column chromatography, and the eluent was a mixed solvent of dichloromethane and methanol; the pure product fractions were collected, and the solvent was rotary evaporated under reduced pressure to obtain the pure product third intermediate product.
步骤S04中,第三中间产物与氨基胍碳酸氢盐于第四反应溶剂中进行缩合反应的化学反应式如下反应式(5)所示:In step S04, the chemical reaction formula of the condensation reaction between the third intermediate product and aminoguanidine bicarbonate in the fourth reaction solvent is shown in the following reaction formula (5):
实施例中,该氨基胍碳酸氢盐在第四反应溶剂中的浓度可以是0.05moL/L。该第四反应溶剂可以是能够有效溶解各反应物的溶液,如可以包括甲醇、乙醇、丙酮、1,4-二氧六环、乙腈、甲苯和二氯甲烷中的一种或多种。在缩合反应体系中,氨基胍碳酸氢盐可以相对第三中间产物稍过量,如实施例中,氨基胍碳酸氢盐与第三中间产物按照摩尔比可以是2:1.5的摩尔比混合。另外,缩合反应的温度可以为20℃~200℃。通过对缩合反应体系的反应物和其浓度控制与选择,能够提高终产物四氢咔唑衍生物的得率,并提高正向反应的 速率。In an embodiment, the concentration of the aminoguanidine bicarbonate in the fourth reaction solvent may be 0.05moL/L. The fourth reaction solvent may be a solution capable of effectively dissolving various reactants, for example, may include one or more of methanol, ethanol, acetone, 1,4-dioxane, acetonitrile, toluene and methylene chloride. In the condensation reaction system, the aminoguanidine bicarbonate can be slightly excessive relative to the third intermediate product. As in the embodiment, the aminoguanidine bicarbonate and the third intermediate product can be mixed in a molar ratio of 2:1.5. In addition, the temperature of the condensation reaction may be 20°C to 200°C. By controlling and selecting the reactants and their concentrations in the condensation reaction system, the yield of the final product tetrahydrocarbazole derivatives can be increased, and the rate of the forward reaction can be increased.
在具体实施例中,步骤S04中的缩合反应可以按照如下方法进行:In a specific embodiment, the condensation reaction in step S04 can be carried out as follows:
按照2mmol氨基胍碳酸氢盐、1.5mmoL第三中间产物、40ml乙醇溶液的混合比例将各组分混合处理,氩气保护,回流反应10小时。According to the mixing ratio of 2mmol aminoguanidine bicarbonate, 1.5mmoL of the third intermediate product, and 40ml of ethanol solution, the components were mixed and treated, protected by argon, and refluxed for 10 hours.
待缩合反应结束后,可以对终产物四氢咔唑衍生物进行分离纯化。实施例中,对终产物四氢咔唑衍生物进行分离纯化方法包括如下步骤:After the condensation reaction is finished, the final product tetrahydrocarbazole derivatives can be separated and purified. In the embodiment, the method for separating and purifying the final product tetrahydrocarbazole derivative includes the following steps:
待经缩合反应反应后的混合溶液冷却后,减压蒸出溶剂,得棕色残余物;用硅胶柱层析(二氯甲烷:甲醇=10:1)分离后,得到纯品结构式Ⅰ所示的四氢咔唑衍生物。After cooling the mixed solution after the condensation reaction, the solvent was distilled off under reduced pressure to obtain a brown residue; after separation by silica gel column chromatography (dichloromethane:methanol=10:1), the pure product represented by structural formula I was obtained. Tetrahydrocarbazole derivatives.
由上述本申请实施例四氢咔唑衍生物制备方法可知,通过对反应物合成路线的设计,能够合成目标产物,使得合成的目标产物具有优异的抗结核菌效果。另外,目标产物得率高,副反应少,工艺条件易控,其制备获得的四氢咔唑衍生物的得率和性能稳定。From the above-mentioned preparation method of tetrahydrocarbazole derivatives in the examples of the present application, it can be seen that the target product can be synthesized by designing the synthesis route of the reactant, so that the synthesized target product has excellent anti-tuberculosis effect. In addition, the yield of the target product is high, the side reactions are few, the process conditions are easy to control, and the yield and performance of the tetrahydrocarbazole derivatives prepared by the preparation are stable.
发明人在研究中发现上文本申请实施例四氢咔唑衍生物具有抑制和杀灭结核分枝杆菌的作用,而且效果优异。因此,基于上文本申请实施例四氢咔唑衍生物及其制备方法,本申请实施例还提供了上文本申请实施例四氢咔唑衍生物的应用方法。基于本申请实施例四氢咔唑衍生物具有抑制和杀灭结核分枝杆菌的作用,其可以作为结核分枝杆菌抑制剂或在制备抗结核药物中的应用。这样,能够有效抑制、杀灭结核菌,抗结核菌效果显著,而且经实验得知,抗结核菌的MIC值低,对大多数结核杆菌不会产生耐药性。In the research, the inventor found that the tetrahydrocarbazole derivatives in the above application examples have the effect of inhibiting and killing Mycobacterium tuberculosis, and the effect is excellent. Therefore, based on the tetrahydrocarbazole derivative and its preparation method in the above application example, the application method of the tetrahydrocarbazole derivative in the above application example is also provided in the example of the present application. Based on the examples of the present application, tetrahydrocarbazole derivatives have the effect of inhibiting and killing Mycobacterium tuberculosis, and can be used as Mycobacterium tuberculosis inhibitors or in the preparation of anti-tuberculosis drugs. In this way, tuberculosis can be effectively inhibited and killed, and the effect of anti-tuberculosis is remarkable, and it is known through experiments that the MIC value of anti-tuberculosis is low, and drug resistance to most tuberculosis will not be produced.
为使本申请上述实施细节和操作能清楚地被本领域技术人员理解,以及本申请实施例四氢咔唑衍生物及其制备方法和应用的进步性能显著的体现,以下通过多个实施例来举例说明上述技术方案。In order to make the above-mentioned implementation details and operations of the present application clearly understood by those skilled in the art, as well as the remarkable performance of the tetrahydrocarbazole derivatives and their preparation methods and applications in the embodiments of the present application, the following are described through multiple examples Give an example to illustrate the above-mentioned technical solution.
1.四氢咔唑衍生物及其制备方法及其制备方法1. Tetrahydrocarbazole derivatives and their preparation methods and their preparation methods
实施例1Example 1
本实施例提供一种2,3,4,9-四氢咔唑衍生物及其制备方法。该2,3,4,9-四氢咔唑衍生物的结构式为上文式Ⅰ 1所示。This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof. The structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I1.
上文式Ⅰ 1所示2,3,4,9-四氢咔唑衍生物制备方法包括如下步骤:The preparation method of 2,3,4,9-tetrahydrocarbazole derivatives shown in above formula I 1 comprises the steps:
S1:上文反应物A3和反应物A的合成:S1: Synthesis of reactant A3 and reactant A above:
反应物A3的合成:按照上文反应式(1)所示的合成路线,在1000mL的圆底烧瓶中,依次加入30g 4-硝基-5-氟苯肼、21g 1,2-环己二酮和1M的盐酸溶液700mL,然后回流搅拌12小时;冷却过滤,得粗品1,未经纯化,直接进行下一步。Synthesis of reactant A3: According to the synthetic route shown in the above reaction formula (1), in a 1000mL round bottom flask, add 30g of 4-nitro-5-fluorophenylhydrazine, 21g of 1,2-cyclohexanedi Ketone and 1M hydrochloric acid solution 700mL, then refluxed and stirred for 12 hours; cooled and filtered to obtain crude product 1, which was directly carried out to the next step without purification.
反应物A的合成:按照上文反应式(1)所示的合成路线,往合成反应物A3粗品中分 别加入浓盐酸400mL、冰醋酸100mL,回流搅拌20小时;反应结束后,减压旋蒸出溶剂,用乙醇重结晶得固体反应物A(2(6-硝基-7-氟-2,3,4,9-四氢咔唑-1-酮))15g。Synthesis of reactant A: According to the synthetic route shown in the above reaction formula (1), add 400 mL of concentrated hydrochloric acid and 100 mL of glacial acetic acid to the crude product of synthetic reactant A3, and stir at reflux for 20 hours; The solvent was removed and recrystallized from ethanol to obtain 15 g of solid reactant A (2(6-nitro-7-fluoro-2,3,4,9-tetrahydrocarbazol-1-one)).
S2:上文结构式Ⅰ Z1所示的第一中间产物的合成:S2: Synthesis of the first intermediate product shown in the above structural formula Ⅰ Z1:
取5mmol反应物A,依次加入DMF 200mL、碳酸铯5mmol和相应得对氟苄溴5.1mmol,室温反应。反应完成后,滤除固体,加入饱和氯化铵溶液200mL,调整溶液pH为6-7,用乙酸乙酯萃取三次,合并有机相,用饱和氯化钠溶液洗涤一次。有机相旋蒸,得固体残余物,也即是上文结构式Ⅰ Z1所示的第一中间产物,未经纯化,直接进行下一步。Take 5mmol of reactant A, add DMF 200mL, cesium carbonate 5mmol and corresponding p-fluorobenzyl bromide 5.1mmol, and react at room temperature. After the reaction was complete, filter out the solid, add 200 mL of saturated ammonium chloride solution, adjust the pH of the solution to 6-7, extract three times with ethyl acetate, combine the organic phases, and wash once with saturated sodium chloride solution. The organic phase was rotary evaporated to obtain a solid residue, that is, the first intermediate product shown in the above structural formula I Z1, without purification, directly proceed to the next step.
S3:上文结构式Ⅰ Z2所示的第二中间产物的合成:S3: Synthesis of the second intermediate product shown in the above structural formula I Z2:
将第一中间产物(5mmoL)、铁粉(25mmol)和氯化铵(50mmoL)加入异丙醇-水(4:1)50ml中,90℃回流搅拌反应15小时;冷却,减压旋蒸出溶剂,残渣中加入水溶解,用碳酸氢钠调pH值至8-9,用乙酸乙酯萃取,有机层用水洗涤两次,饱和氯化钠溶液洗涤一次,无水硫酸钠干燥,减压蒸出溶剂;残余物用硅胶柱层析纯化,淋洗剂为乙酸乙酯,得纯品为第二中间产物。Add the first intermediate product (5mmoL), iron powder (25mmol) and ammonium chloride (50mmoL) into 50ml of isopropanol-water (4:1), and react under reflux at 90°C for 15 hours; Solvent, add water to the residue to dissolve, adjust the pH value to 8-9 with sodium bicarbonate, extract with ethyl acetate, wash the organic layer twice with water, wash once with saturated sodium chloride solution, dry over anhydrous sodium sulfate, evaporate under reduced pressure The solvent was removed; the residue was purified by silica gel column chromatography, the eluent was ethyl acetate, and the pure product was the second intermediate product.
S4:上文结构式Ⅰ Z3所示的第三中间产物的合成:S4: Synthesis of the third intermediate product shown in the above structural formula I Z3:
氩气保护下,在250mL的圆底烧瓶中顺次加入步骤S3合成的第二中间产物(2mmoL)、溴苯(2mmol)、醋酸钯(0.02mmoL)、联萘酚(0.04mmoL)、叔丁醇钠(2mmol)和甲苯100ml,100℃反应10小时;反应结束后,溶液用硅藻土过滤,然后加饱和氯化铵溶液调pH值为6-7;用乙酸乙酯萃取三次,饱和食盐水洗涤一次;有机相减压旋蒸出溶剂,残余物用硅胶柱层析,淋洗液为二氯甲烷与甲醇的混合溶剂;收集纯品馏分,减压旋蒸出溶剂得纯品为第三中间产物(结构式Ⅰ Z3所含的R2为苯基)。Under argon protection, in a 250mL round bottom flask, add the second intermediate product (2mmoL) synthesized in step S3, bromobenzene (2mmol), palladium acetate (0.02mmoL), binaphthol (0.04mmoL), tert-butyl Sodium alkoxide (2mmol) and 100ml of toluene were reacted at 100°C for 10 hours; after the reaction, the solution was filtered with diatomaceous earth, and then saturated ammonium chloride solution was added to adjust the pH value to 6-7; extracted three times with ethyl acetate, saturated salt Wash once with water; the organic phase was evaporated under reduced pressure to remove the solvent, and the residue was subjected to silica gel column chromatography, and the eluent was a mixed solvent of dichloromethane and methanol; Three intermediate products (R2 contained in the structural formula I Z3 is phenyl).
S5:上文结构式Ⅰ 1所示的2,3,4,9-四氢咔唑衍生物的合成:S5: Synthesis of 2,3,4,9-tetrahydrocarbazole derivatives shown in the above structural formula I 1:
将2mmol氨基胍碳酸氢盐与1.5mmoL步骤S4合成的第三中间产物共同置于50mL圆底烧瓶中,氩气保护,再加入乙醇溶液40ml,回流反应10小时;TLC检测,原料消失后,冷却,减压蒸出溶剂,得棕色残余物。用硅胶柱层析(二氯甲烷:甲醇=10:1)分离后,得上文结构式Ⅰ 1所示目标化合物0.62g,收率为90%。所得到的产物经高分辨质谱和核磁共振确认结构,结构式Ⅰ 1所示的2,3,4,9-四氢咔唑衍生物的质谱和核磁共振结果如下:Put 2mmol of aminoguanidine bicarbonate and 1.5mmol of the third intermediate product synthesized in step S4 into a 50mL round-bottomed flask, protect with argon, then add 40ml of ethanol solution, and reflux for 10 hours; TLC detection, after the disappearance of raw materials, cool , the solvent was distilled off under reduced pressure to obtain a brown residue. After separation by silica gel column chromatography (dichloromethane:methanol=10:1), 0.62 g of the target compound represented by the above structural formula I1 was obtained with a yield of 90%. The obtained product confirms the structure through high-resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I1 are as follows:
1HNMR(400MHz,DMSO-d6)11.01(s,1H),8.02(d,J=9.4Hz,1H),7.25-7.45(m,5H),7.22-7.34(m,4H),7.18(s,1H),6.92(s,1H),5.20(s,2H),4.20(m,1H),1.70-2.84(m,6H).HRMS理论值C27H26F2N6[M+H]+:理论值:472.2234,实测值:472.2237。1H NMR (400MHz, DMSO-d6) 11.01(s, 1H), 8.02(d, J=9.4Hz, 1H), 7.25-7.45(m, 5H), 7.22-7.34(m, 4H), 7.18(s, 1H ),6.92(s,1H),5.20(s,2H),4.20(m,1H),1.70-2.84(m,6H).HRMS theoretical value C27H26F2N6[M+H]+: theoretical value: 472.2234, measured value : 472.2237.
实施例2Example 2
本实施例提供一种2,3,4,9-四氢咔唑衍生物及其制备方法。该2,3,4,9-四氢咔唑衍生物的结构式为上文式Ⅰ 2所示。This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof. The structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I 2.
上文式Ⅰ 2所示2,3,4,9-四氢咔唑衍生物制备方法包括如下步骤:The preparation method of 2,3,4,9-tetrahydrocarbazole derivatives shown in above formula I 2 comprises the steps:
S1:参照实施例1中步骤S1分别合成反应物A3和反应物A的合成:S1: Synthesis of reactant A3 and reactant A respectively with reference to step S1 in Example 1:
S2:参照实施例1中步骤S2合成上文结构式Ⅰ Z1所示的第一中间产物。不同在于将反应物对氟苄溴替换成对硝基苄溴。S2: Synthesize the first intermediate product shown in the above structural formula IZ1 with reference to step S2 in Example 1. The difference is that the reactant p-fluorobenzyl bromide is replaced by p-nitrobenzyl bromide.
S3:参照实施例1中步骤S3合成上文结构式Ⅰ Z3所示的第二中间产物。S3: Synthesize the second intermediate product shown in the above structural formula I Z3 with reference to step S3 in Example 1.
S4:参照实施例1中步骤S4合成上文结构式Ⅰ Z3所示的第三中间产物。不同在于将反应物溴苯替换成对氟溴苯。S4: Synthesize the third intermediate product shown in the above structural formula IZ3 with reference to step S4 in Example 1. The difference is that the reactant bromobenzene is replaced by p-fluorobromobenzene.
S5:参照实施例1中步骤S5合成上文结构式Ⅰ 2所示的2,3,4,9-四氢咔唑衍生物0.64g,收率85%。所得到的产物经高分辨质谱和核磁共振确认结构,结构式Ⅰ 2所示的2,3,4,9-四氢咔唑衍生物的质谱和核磁共振结果如下:S5: Referring to step S5 in Example 1, 0.64 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized with a yield of 85%. The obtained product confirms the structure through high-resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I2 are as follows:
1HNMR(400MHz,DMSO-d6)11.01(s,1H),8.16(d,J=15Hz,2H),8.03(d,J=9.4Hz,1H),7.42(d,J=15Hz,2H),7.39(d,J=9.6Hz,2H),7.28(d,J=9.6Hz,2H),7.18(s,1H),6.92(s,1H),5.18(s,2H),4.21(m,1H),1.70-2.84(m,6H).HRMS理论值C27H25F2N7O2[M+H]+:517.2014,实测值:517.2016。1H NMR (400MHz, DMSO-d6) 11.01 (s, 1H), 8.16 (d, J = 15Hz, 2H), 8.03 (d, J = 9.4Hz, 1H), 7.42 (d, J = 15Hz, 2H), 7.39 (d,J=9.6Hz,2H),7.28(d,J=9.6Hz,2H),7.18(s,1H),6.92(s,1H),5.18(s,2H),4.21(m,1H) ,1.70-2.84(m,6H). HRMS theoretical value C27H25F2N7O2[M+H]+: 517.2014, measured value: 517.2016.
实施例3Example 3
本实施例提供一种2,3,4,9-四氢咔唑衍生物及其制备方法。该2,3,4,9-四氢咔唑衍生物的结构式为上文式Ⅰ 3所示。This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof. The structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I 3.
上文式Ⅰ 3所示2,3,4,9-四氢咔唑衍生物制备方法包括如下步骤:The preparation method of 2,3,4,9-tetrahydrocarbazole derivatives shown in formula I 3 above comprises the steps:
S1:参照实施例1中步骤S1分别合成反应物A3和反应物A的合成:S1: Synthesis of reactant A3 and reactant A respectively with reference to step S1 in Example 1:
S2:参照实施例1中步骤S2合成上文结构式Ⅰ Z1所示的第一中间产物。不同在于将反应物对氟苄溴替换成对甲氧基苄溴。S2: Synthesize the first intermediate product shown in the above structural formula IZ1 with reference to step S2 in Example 1. The difference is that the reactant p-fluorobenzyl bromide is replaced by p-methoxybenzyl bromide.
S3:参照实施例1中步骤S3合成上文结构式Ⅰ Z3所示的第二中间产物。S3: Synthesize the second intermediate product shown in the above structural formula I Z3 with reference to step S3 in Example 1.
S4:参照实施例1中步骤S4合成上文结构式Ⅰ Z3所示的第三中间产物。不同在于将反应物溴苯替换成对三氟甲基溴苯。S4: Synthesize the third intermediate product shown in the above structural formula IZ3 with reference to step S4 in Example 1. The difference is that the reactant bromobenzene is replaced by p-trifluoromethyl bromobenzene.
S5:参照实施例1中步骤S5合成上文结构式Ⅰ 2所示的2,3,4,9-四氢咔唑衍生物0.77g;收率95%。所得到的产物经高分辨质谱和核磁共振确认结构,结构式Ⅰ 3所示的2,3,4,9-四氢咔唑衍生物的质谱和核磁共振结果如下:S5: Referring to step S5 in Example 1, 0.77 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized; the yield was 95%. The obtained product confirms the structure through high-resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I are as follows:
1HNMR(400MHz,DMSO-d6)11.03(s,1H),8.03(d,J=9.4Hz,1H),7.52(d,J=13Hz,2H),7.39 (d,J=13Hz,2H),7.29(d,J=9.2Hz,2H),7.18(s,1H),6.92(s,1H),6.78(d,J=9.2Hz,2H),5.18(s,2H),4.21(m,1H),3.80(s,3H),1.70-2.84(m,6H).HRMS理论值C29H28F4N6O[M+H]+:552.2304,实测值:552.2305。1H NMR (400MHz, DMSO-d6) 11.03 (s, 1H), 8.03 (d, J = 9.4Hz, 1H), 7.52 (d, J = 13Hz, 2H), 7.39 (d, J = 13Hz, 2H), 7.29 (d,J=9.2Hz,2H),7.18(s,1H),6.92(s,1H),6.78(d,J=9.2Hz,2H),5.18(s,2H),4.21(m,1H) ,3.80(s,3H),1.70-2.84(m,6H).HRMS theoretical value C29H28F4N6O[M+H]+: 552.2304, found value: 552.2305.
实施例4Example 4
本实施例提供一种2,3,4,9-四氢咔唑衍生物及其制备方法。该2,3,4,9-四氢咔唑衍生物的结构式为上文式Ⅰ 4所示。This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof. The structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I 4.
上文式Ⅰ 4所示2,3,4,9-四氢咔唑衍生物制备方法包括如下步骤:The preparation method of 2,3,4,9-tetrahydrocarbazole derivatives shown in above formula I 4 comprises the steps:
S1:参照实施例1中步骤S1分别合成反应物A3和反应物A的合成:S1: Synthesis of reactant A3 and reactant A respectively with reference to step S1 in Example 1:
S2:参照实施例1中步骤S2合成上文结构式Ⅰ Z1所示的第一中间产物。不同在于将反应物对氟苄溴替换成对乙炔基苄溴。S2: Synthesize the first intermediate product shown in the above structural formula IZ1 with reference to step S2 in Example 1. The difference is that the reactant p-fluorobenzyl bromide is replaced by p-ethynylbenzyl bromide.
S3:参照实施例1中步骤S3合成上文结构式Ⅰ Z3所示的第二中间产物。S3: Synthesize the second intermediate product shown in the above structural formula I Z3 with reference to step S3 in Example 1.
S4:参照实施例1中步骤S4合成上文结构式Ⅰ Z3所示的第三中间产物。不同在于将反应物溴苯替换成3,4-二氟溴苯。S4: Synthesize the third intermediate product shown in the above structural formula IZ3 with reference to step S4 in Example 1. The difference is that the reactant bromobenzene is replaced by 3,4-difluorobromobenzene.
S5:参照实施例1中步骤S5合成上文结构式Ⅰ 2所示的2,3,4,9-四氢咔唑衍生物0.70g;收率93%。所得到的产物经高分辨质谱和核磁共振确认结构,结构式Ⅰ 4所示的2,3,4,9-四氢咔唑衍生物的质谱和核磁共振结果如下:S5: Referring to step S5 in Example 1, 0.70 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized; the yield was 93%. The obtained product confirms the structure through high-resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I are as follows:
1HNMR(400MHz,DMSO-d6)11.03(s,1H),8.03(d,J=9.4Hz,1H),7.20-7.44(m,7H),7.18(s,1H),6.92(s,1H),5.18(s,2H),4.21(m,1H),3.04(s,1H),1.72-2.83(m,6H).HRMS理论值C29H25F3N6[M+H]+:514.2104,实测值:514.2105。1HNMR (400MHz, DMSO-d6) 11.03(s, 1H), 8.03(d, J=9.4Hz, 1H), 7.20-7.44(m, 7H), 7.18(s, 1H), 6.92(s, 1H), 5.18(s,2H), 4.21(m,1H), 3.04(s,1H), 1.72-2.83(m,6H). HRMS theoretical value C29H25F3N6[M+H]+: 514.2104, measured value: 514.2105.
实施例5Example 5
本实施例提供一种2,3,4,9-四氢咔唑衍生物及其制备方法。该2,3,4,9-四氢咔唑衍生物的结构式为上文式Ⅰ 5所示。This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof. The structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I5.
上文式Ⅰ 5所示2,3,4,9-四氢咔唑衍生物制备方法包括如下步骤:The preparation method of 2,3,4,9-tetrahydrocarbazole derivatives shown in formula I 5 above comprises the steps:
S1:参照实施例1中步骤S1分别合成反应物A3和反应物A的合成:S1: Synthesis of reactant A3 and reactant A respectively with reference to step S1 in Example 1:
S2:参照实施例1中步骤S2合成上文结构式Ⅰ Z1所示的第一中间产物。不同在于将反应物对氟苄溴替换成1,4-二苄溴。S2: Synthesize the first intermediate product shown in the above structural formula IZ1 with reference to step S2 in Example 1. The difference is that the reactant p-fluorobenzyl bromide is replaced by 1,4-dibenzyl bromide.
S3:参照实施例1中步骤S3合成上文结构式Ⅰ Z3所示的第二中间产物。S3: Synthesize the second intermediate product shown in the above structural formula I Z3 with reference to step S3 in Example 1.
S4:参照实施例1中步骤S4合成上文结构式Ⅰ Z3所示的第三中间产物。不同在于将反应物溴苯替换成3,4-二氟溴苯。S4: Synthesize the third intermediate product shown in the above structural formula IZ3 with reference to step S4 in Example 1. The difference is that the reactant bromobenzene is replaced by 3,4-difluorobromobenzene.
S5:参照实施例1中步骤S5合成上文结构式Ⅰ 2所示的2,3,4,9-四氢咔唑衍生物 0.62g,收率89%。所得到的产物经高分辨质谱和核磁共振确认结构,结构式Ⅰ 5所示的2,3,4,9-四氢咔唑衍生物的质谱和核磁共振结果如下:S5: Referring to step S5 in Example 1, 0.62 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized, with a yield of 89%. The obtained product confirms the structure through high-resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I are as follows:
1HNMR(400MHz,DMSO-d6)11.01(s,1H),8.17(d,J=15Hz,2H),8.01(d,J=10.4Hz,2H),7.21-7.42(m,,3H),7.18(s,1H),7.05(d,J=10.4Hz,2H),6.92(s,1H),5.11(s,2H),4.21(m,1H),1.70-2.84(m,6H).HRMS理论值C27H24BrF3N6.[M+H]+:568.1210,实测值:568.1211。1H NMR (400MHz, DMSO-d6) 11.01 (s, 1H), 8.17 (d, J = 15Hz, 2H), 8.01 (d, J = 10.4Hz, 2H), 7.21-7.42 (m,, 3H), 7.18 ( s,1H),7.05(d,J=10.4Hz,2H),6.92(s,1H),5.11(s,2H),4.21(m,1H),1.70-2.84(m,6H).HRMS theoretical value C27H24BrF3N6.[M+H]+: 568.1210, found: 568.1211.
实施例6Example 6
本实施例提供一种2,3,4,9-四氢咔唑衍生物及其制备方法。该2,3,4,9-四氢咔唑衍生物的结构式为上文式Ⅰ 6所示。This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof. The structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I 6.
上文式Ⅰ 6所示2,3,4,9-四氢咔唑衍生物制备方法包括如下步骤:The preparation method of 2,3,4,9-tetrahydrocarbazole derivatives shown in formula I 6 above comprises the steps:
S1:参照实施例1中步骤S1分别合成反应物A3和反应物A的合成:S1: Synthesis of reactant A3 and reactant A respectively with reference to step S1 in Example 1:
S2:参照实施例1中步骤S2合成上文结构式Ⅰ Z1所示的第一中间产物。不同在于将反应物对氟苄溴替换成1,4-二苄溴。S2: Synthesize the first intermediate product shown in the above structural formula IZ1 with reference to step S2 in Example 1. The difference is that the reactant p-fluorobenzyl bromide is replaced by 1,4-dibenzyl bromide.
S3:参照实施例1中步骤S3合成上文结构式Ⅰ Z3所示的第二中间产物。S3: Synthesize the second intermediate product shown in the above structural formula I Z3 with reference to step S3 in Example 1.
S4:参照实施例1中步骤S4合成上文结构式Ⅰ Z3所示的第三中间产物。不同在于将反应物溴苯替换成对乙炔基溴苯。S4: Synthesize the third intermediate product shown in the above structural formula IZ3 with reference to step S4 in Example 1. The difference is that the reactant bromobenzene is replaced by p-ethynyl bromobenzene.
S5:参照实施例1中步骤S5合成上文结构式Ⅰ 2所示的2,3,4,9-四氢咔唑衍生物0.75g,收率92%。所得到的产物经高分辨质谱和核磁共振确认结构,结构式Ⅰ 6所示的2,3,4,9-四氢咔唑衍生物的质谱和核磁共振结果如下:S5: Referring to step S5 in Example 1, 0.75 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized with a yield of 92%. The obtained product confirms the structure through high-resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I6 are as follows:
1HNMR(400MHz,DMSO-d6)11.01(s,1H),7.89(d,J=14Hz,2H),8.03(d,J=9.4Hz,1H),7.42(d,J=10Hz,2H),7.25(d,J=10Hz,2H),7.15(s,1H),7.05(d,J=14Hz,2H),6.93(s,1H),5.19(s,2H),4.21(m,1H),3.01(s,1H),1.70-2.84(m,6H).HRMS理论值C29H26BrFN6[M+H]+:556.1421,实测值:556.1420。1H NMR (400MHz, DMSO-d6) 11.01 (s, 1H), 7.89 (d, J = 14Hz, 2H), 8.03 (d, J = 9.4Hz, 1H), 7.42 (d, J = 10Hz, 2H), 7.25 (d,J=10Hz,2H),7.15(s,1H),7.05(d,J=14Hz,2H),6.93(s,1H),5.19(s,2H),4.21(m,1H),3.01 (s, 1H), 1.70-2.84 (m, 6H). HRMS theoretical value C29H26BrFN6[M+H]+: 556.1421, found value: 556.1420.
实施例7Example 7
本实施例提供一种2,3,4,9-四氢咔唑衍生物及其制备方法。该2,3,4,9-四氢咔唑衍生物的结构式为上文式Ⅰ 7所示。This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof. The structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I 7.
上文式Ⅰ 7所示2,3,4,9-四氢咔唑衍生物制备方法包括如下步骤:The preparation method of 2,3,4,9-tetrahydrocarbazole derivatives shown in formula I 7 above comprises the steps:
S1:参照实施例1中步骤S1分别合成反应物A3和反应物A的合成:S1: Synthesis of reactant A3 and reactant A respectively with reference to step S1 in Example 1:
S2:参照实施例1中步骤S2合成上文结构式Ⅰ Z1所示的第一中间产物。不同在于将反应物对氟苄溴替换成1-溴-3,4,5-三甲氧基苄。S2: Synthesize the first intermediate product shown in the above structural formula IZ1 with reference to step S2 in Example 1. The difference is that the reactant p-fluorobenzyl bromide is replaced by 1-bromo-3,4,5-trimethoxybenzyl.
S3:参照实施例1中步骤S3合成上文结构式Ⅰ Z3所示的第二中间产物。S3: Synthesize the second intermediate product shown in the above structural formula I Z3 with reference to step S3 in Example 1.
S4:参照实施例1中步骤S4合成上文结构式Ⅰ Z3所示的第三中间产物。不同在于将反应物溴苯替换成对乙炔基溴苯。S4: Synthesize the third intermediate product shown in the above structural formula IZ3 with reference to step S4 in Example 1. The difference is that the reactant bromobenzene is replaced by p-ethynyl bromobenzene.
S5:参照实施例1中步骤S5合成上文结构式Ⅰ 2所示的2,3,4,9-四氢咔唑衍生物0.72g;收率87%。所得到的产物经高分辨质谱和核磁共振确认结构,结构式Ⅰ 7所示的2,3,4,9-四氢咔唑衍生物的质谱和核磁共振结果如下:S5: Referring to step S5 in Example 1, 0.72 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized; the yield was 87%. The obtained product confirms the structure through high resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I are as follows:
1HNMR(400MHz,DMSO-d6)11.01(s,1H),8.03(d,J=9.4Hz,1H),7.44(d,J=10Hz,2H),7.23(d,J=10Hz,2H),7.15(s,1H),6.93(s,1H),6.54(s,2H),4.21(m,1H),3.78(s,9H),3.03(s,1H),1.70-2.84(m,6H).HRMS理论值C32H33FN6O3[M+H]+:568.2610,实测值:568.2613。1H NMR (400MHz, DMSO-d6) 11.01(s, 1H), 8.03(d, J=9.4Hz, 1H), 7.44(d, J=10Hz, 2H), 7.23(d, J=10Hz, 2H), 7.15 (s,1H),6.93(s,1H),6.54(s,2H),4.21(m,1H),3.78(s,9H),3.03(s,1H),1.70-2.84(m,6H). HRMS theoretical value C32H33FN6O3[M+H]+: 568.2610, found value: 568.2613.
实施例8Example 8
本实施例提供一种2,3,4,9-四氢咔唑衍生物及其制备方法。该2,3,4,9-四氢咔唑衍生物的结构式为上文式Ⅰ 8所示。This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof. The structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in the above formula I 8.
上文式Ⅰ 8所示2,3,4,9-四氢咔唑衍生物制备方法包括如下步骤:The preparation method of 2,3,4,9-tetrahydrocarbazole derivatives shown in above formula I 8 comprises the steps:
S1:参照实施例1中步骤S1分别合成反应物A3和反应物A的合成:S1: Synthesis of reactant A3 and reactant A respectively with reference to step S1 in Example 1:
S2:参照实施例1中步骤S2合成上文结构式Ⅰ Z1所示的第一中间产物。不同在于将反应物对氟苄溴替换成1-溴-3,4,5-三甲氧基苄。S2: Synthesize the first intermediate product shown in the above structural formula IZ1 with reference to step S2 in Example 1. The difference is that the reactant p-fluorobenzyl bromide is replaced by 1-bromo-3,4,5-trimethoxybenzyl.
S3:参照实施例1中步骤S3合成上文结构式Ⅰ Z3所示的第二中间产物。S3: Synthesize the second intermediate product shown in the above structural formula I Z3 with reference to step S3 in Example 1.
S4:参照实施例1中步骤S4合成上文结构式Ⅰ Z3所示的第三中间产物。不同在于将反应物溴苯替换成对氰基溴苯。S4: Synthesize the third intermediate product shown in the above structural formula IZ3 with reference to step S4 in Example 1. The difference is that the reactant bromobenzene is replaced by p-cyanobromobenzene.
S5:参照实施例1中步骤S5合成上文结构式Ⅰ 2所示的2,3,4,9-四氢咔唑衍生物0.71g,收率85%。所得到的产物经高分辨质谱和核磁共振确认结构,结构式Ⅰ 8所示的2,3,4,9-四氢咔唑衍生物的质谱和核磁共振结果如下:S5: Referring to step S5 in Example 1, 0.71 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized with a yield of 85%. The obtained product confirms the structure through high-resolution mass spectrometry and nuclear magnetic resonance, and the mass spectrometry and nuclear magnetic resonance results of the 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I8 are as follows:
1HNMR(400MHz,DMSO-d6)10.98(s,1H),8.04(d,J=9.4Hz,1H),7.48(d,J=10Hz,2H),7.23(d,J=10Hz,2H),7.15(s,1H),6.93(s,1H),6.55(s,2H),4.21(m,1H),3.78(s,9H),1.70-2.84(m,6H).HRMS理论值C31H32FN7O3[M+H]+:理论值:569.2620,实测值:568.2618。1H NMR (400MHz, DMSO-d6) 10.98(s, 1H), 8.04(d, J=9.4Hz, 1H), 7.48(d, J=10Hz, 2H), 7.23(d, J=10Hz, 2H), 7.15 (s,1H),6.93(s,1H),6.55(s,2H),4.21(m,1H),3.78(s,9H),1.70-2.84(m,6H).HRMS theoretical value C31H32FN7O3[M+ H]+: theoretical value: 569.2620, measured value: 568.2618.
实施例9Example 9
本实施例提供一种2,3,4,9-四氢咔唑衍生物及其制备方法。该2,3,4,9-四氢咔唑衍生物的结构式为上文式Ⅰ 9所示。This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof. The structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in Formula I 9 above.
上文式Ⅰ 9所示2,3,4,9-四氢咔唑衍生物制备方法包括如下步骤:The preparation method of 2,3,4,9-tetrahydrocarbazole derivatives shown in formula I 9 above comprises the steps:
S1:参照实施例1中步骤S1分别合成反应物A3和反应物A的合成:S1: Synthesis of reactant A3 and reactant A respectively with reference to step S1 in Example 1:
S2:参照实施例1中步骤S2合成上文结构式Ⅰ Z1所示的第一中间产物。不同在于将反应物对氟苄溴替换成2-溴-6-甲氧基吡啶。S2: Synthesize the first intermediate product shown in the above structural formula IZ1 with reference to step S2 in Example 1. The difference is that the reactant p-fluorobenzyl bromide is replaced by 2-bromo-6-methoxypyridine.
S3:参照实施例1中步骤S3合成上文结构式Ⅰ Z3所示的第二中间产物。S3: Synthesize the second intermediate product shown in the above structural formula I Z3 with reference to step S3 in Example 1.
S4:参照实施例1中步骤S4合成上文结构式Ⅰ Z3所示的第三中间产物。不同在于将反应物溴苯替换成3-溴吡啶。S4: Synthesize the third intermediate product shown in the above structural formula IZ3 with reference to step S4 in Example 1. The difference is that the reactant bromobenzene is replaced by 3-bromopyridine.
S5:参照实施例1中步骤S5合成上文结构式Ⅰ 2所示的2,3,4,9-四氢咔唑衍生物0.58g;收率92%。所得到的产物经高分辨质谱和核磁共振确认结构,结构式Ⅰ 9所示的2,3,4,9-四氢咔唑衍生物的质谱和核磁共振结果如下:S5: Referring to step S5 in Example 1, 0.58 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized; the yield was 92%. The resulting product is confirmed by high-resolution mass spectrometry and nuclear magnetic resonance. The mass spectrometry and nuclear magnetic resonance results of 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I9 are as follows:
1HNMR(400MHz,DMSO-d6)11.03(s,1H),8.05(s,1H),8.03(d,J=9.4Hz,1H),7.30-7.92(m,8H),5.01(s,2H),4.21(m,1H),3.80(s,3H),1.70-2.84(m,6H).HRMS理论值C26H27FN8O[M+H]+:理论值:486.2304,实测值:486.2303。1HNMR (400MHz, DMSO-d6) 11.03(s, 1H), 8.05(s, 1H), 8.03(d, J=9.4Hz, 1H), 7.30-7.92(m, 8H), 5.01(s, 2H), 4.21 (m, 1H), 3.80 (s, 3H), 1.70-2.84 (m, 6H). HRMS theoretical value C26H27FN8O[M+H]+: theoretical value: 486.2304, measured value: 486.2303.
实施例10Example 10
本实施例提供一种2,3,4,9-四氢咔唑衍生物及其制备方法。该2,3,4,9-四氢咔唑衍生物的结构式为上文式Ⅰ 9所示。This example provides a 2,3,4,9-tetrahydrocarbazole derivative and a preparation method thereof. The structural formula of the 2,3,4,9-tetrahydrocarbazole derivative is shown in Formula I 9 above.
上文式Ⅰ 9所示2,3,4,9-四氢咔唑衍生物制备方法包括如下步骤:The preparation method of 2,3,4,9-tetrahydrocarbazole derivatives shown in formula I 9 above comprises the steps:
S1:参照实施例1中步骤S1分别合成反应物A3和反应物A的合成:S1: Synthesis of reactant A3 and reactant A respectively with reference to step S1 in Example 1:
S2:参照实施例1中步骤S2合成上文结构式Ⅰ Z1所示的第一中间产物。不同在于将反应物对氟苄溴替换成2-溴代甲基-6-氰基噻吩。S2: Synthesize the first intermediate product shown in the above structural formula IZ1 with reference to step S2 in Example 1. The difference is that the reactant p-fluorobenzyl bromide is replaced by 2-bromomethyl-6-cyanothiophene.
S3:参照实施例1中步骤S3合成上文结构式Ⅰ Z3所示的第二中间产物。S3: Synthesize the second intermediate product shown in the above structural formula I Z3 with reference to step S3 in Example 1.
S4:参照实施例1中步骤S4合成上文结构式Ⅰ Z3所示的第三中间产物。不同在于将反应物溴苯替换成3-溴吡啶。S4: Synthesize the third intermediate product shown in the above structural formula IZ3 with reference to step S4 in Example 1. The difference is that the reactant bromobenzene is replaced by 3-bromopyridine.
S5:参照实施例1中步骤S5合成上文结构式Ⅰ 2所示的2,3,4,9-四氢咔唑衍生物0.59g;收率84%。所得到的产物经高分辨质谱和核磁共振确认结构,结构式Ⅰ 9所示的2,3,4,9-四氢咔唑衍生物的质谱和核磁共振结果如下:S5: Referring to step S5 in Example 1, 0.59 g of the 2,3,4,9-tetrahydrocarbazole derivative shown in the above structural formula I2 was synthesized; the yield was 84%. The resulting product is confirmed by high-resolution mass spectrometry and nuclear magnetic resonance. The mass spectrometry and nuclear magnetic resonance results of 2,3,4,9-tetrahydrocarbazole derivatives shown in structural formula I9 are as follows:
1HNMR(400MHz,DMSO-d6)11.03(s,1H),8.05(s,1H),8.03(d,J=9.4Hz,1H),7.30-7.92(m,7H),5.14(s,2H),4.21(m,1H),1.70-2.84(m,6H).HRMSC25H23FN8S[M+H]+:理论值:486.1814,实测值:486.1815。1HNMR (400MHz, DMSO-d6) 11.03(s, 1H), 8.05(s, 1H), 8.03(d, J=9.4Hz, 1H), 7.30-7.92(m, 7H), 5.14(s, 2H), 4.21(m,1H),1.70-2.84(m,6H).HRMSC25H23FN8S[M+H]+: theoretical value: 486.1814, measured value: 486.1815.
其他实施例other embodiments
基于上述实施例1至实施例10的方法,可以对反应物B所含基团R1和反应物C所含基团R2的种类选择,如将上述实施例1中反应物B所含基团R1和反应物C所含基团R2相 同或不相同的替换成取代或未被取代的吡咯、嘧啶等基团,以可以合成对应的四氢咔唑衍生物。Based on the method of the above-mentioned embodiment 1 to embodiment 10, the types of the group R1 contained in the reactant B and the group R2 contained in the reactant C can be selected, such as the group R1 contained in the reactant B in the above-mentioned embodiment 1 The same or different group R2 contained in reactant C is replaced by substituted or unsubstituted pyrrole, pyrimidine and other groups to synthesize the corresponding tetrahydrocarbazole derivatives.
2.四氢咔唑衍生物抗结核分枝杆菌活性的测定2. Determination of the activity of tetrahydrocarbazole derivatives against Mycobacterium tuberculosis
(参考资料:《结核病诊断实验室检验规程》,中国防痨协会基础专业委员会编著,中国教育文化出版社,2006年1月)(Reference material: "Tuberculosis Diagnostic Laboratory Inspection Regulations", edited by the Basic Professional Committee of the Chinese Anti-tuberculosis Association, China Education and Culture Press, January 2006)
将受试菌株H37Rv转入液体培养基,于37℃培养2周,吸取培养菌液少许,置于4mL液体培养基中,加入直径2-3mm无菌玻璃珠10-20粒,振荡20-30S,静止沉淀10-20min,吸取菌悬液上清,用液体培养基调整比浊至1个麦氏单位,相当于1*107CFU/mL备用。每种药物用适量DMSO溶解至lmg/mL,0.22μm滤器过滤。再以液体培养基稀释至所需实验浓度。各受试药物(实施例1至实施例10以及对照组异烟肼)终浓度设置如下:0.0039μg/mL、0.0078μg/mL、0.0156μg/mL、0.03125μg/mL、0.0625μg/mL、0.125μg/mL、0.25μg/mL、0.5μg/mL、1.0μg/mL、2.0μg/mL、4.0μg/mL,共11个浓度梯度。各取上述各受试药物溶液l00μL,加到96孔微孔板中,再加入lmg/mL浓度的菌液l00μL,使药物浓度达到设置的终浓度,37℃培养。同一药物稀释度设三组平行对照,对照组不加药物,接菌量分别设置为100%、10%和1%。37℃培养14天后,观察各组菌落生长情况,以无菌落生长的药物组最低浓度作为测试化合物对该菌株的MIC值。观察各化合物对结核分枝杆菌的最低抑菌浓度(MIC),同时和对照药异烟肼的MIC结果进行比较。Transfer the tested strain H37Rv into a liquid medium, culture it at 37°C for 2 weeks, absorb a little culture liquid, put it in 4mL liquid medium, add 10-20 sterile glass beads with a diameter of 2-3mm, shake for 20-30S , static precipitation for 10-20min, absorb the supernatant of the bacterial suspension, and adjust the turbidity to 1 McFarland unit with liquid medium, which is equivalent to 1*107CFU/mL for later use. Each drug was dissolved to 1 mg/mL with an appropriate amount of DMSO, and filtered through a 0.22 μm filter. Then dilute to the required experimental concentration with liquid culture medium. The final concentrations of each test drug (Example 1 to Example 10 and isoniazid in the control group) were set as follows: 0.0039 μg/mL, 0.0078 μg/mL, 0.0156 μg/mL, 0.03125 μg/mL, 0.0625 μg/mL, 0.125 μg/mL μg/mL, 0.25μg/mL, 0.5μg/mL, 1.0μg/mL, 2.0μg/mL, 4.0μg/mL, 11 concentration gradients in total. Take 100 μL of each test drug solution above, add it to a 96-well microwell plate, and then add 100 μL of bacterial solution with a concentration of 1 mg/mL to make the drug concentration reach the set final concentration, and incubate at 37°C. Three groups of parallel controls were set up at the same drug dilution. The control group received no drug, and the inoculation amount was set to 100%, 10% and 1%, respectively. After culturing at 37°C for 14 days, observe the colony growth of each group, and take the lowest concentration of the drug group without colony growth as the MIC value of the test compound for the strain. Observe the minimum inhibitory concentration (MIC) of each compound against Mycobacterium tuberculosis, and compare it with the MIC result of the control drug isoniazid.
测得MIC结果如下表1所示:The measured MIC results are shown in Table 1 below:
表1Table 1
由表1可知,本申请实施例提供的Ⅰ 1至Ⅰ 10所示四氢咔唑衍生物均具有优异的抗结核菌效果,其中,Ⅰ 3至Ⅰ 5、Ⅰ 8的活性与异烟肼相当,Ⅰ 6、Ⅰ 7的活性优于异烟肼。进一步进行耐药性实验得知,本申请实施例提供的四氢咔唑衍生物抗结核菌对大多数结核杆菌没有产生耐药性。It can be seen from Table 1 that the tetrahydrocarbazole derivatives shown in I 1 to I 10 provided in the examples of the present application all have excellent anti-tuberculosis effects, and the activities of I 3 to I 5 and I 8 are equivalent to that of isoniazid , Ⅰ 6, Ⅰ 7 are more active than isoniazid. Further drug resistance experiments showed that the tetrahydrocarbazole derivative anti-tuberculosis bacteria provided in the examples of the present application did not produce drug resistance to most tubercle bacilli.
以上所述实施例仅表达了本申请的几种实施方式,其描述较为具体和详细,但并不能因此而理解为对本申请专利范围的限制。应当指出的是,对于本领域的普通技术人员来说,在不脱离本申请构思的前提下,还可以做出若干变形和改进,这些都属于本申请的保护范围。因此,本申请专利的保护范围应以所附权利要求为准。The above-mentioned embodiments only express several implementation modes of the present application, and the description thereof is relatively specific and detailed, but should not be construed as limiting the patent scope of the present application. It should be noted that those skilled in the art can make several modifications and improvements without departing from the concept of the present application, and these all belong to the protection scope of the present application. Therefore, the scope of protection of the patent application should be based on the appended claims.
Claims (10)
- 一种四氢咔唑衍生物,其特征在于,所述四氢咔唑衍生物的分子结构式如下述通式Ⅰ所示:A tetrahydrocarbazole derivative, characterized in that the molecular structural formula of the tetrahydrocarbazole derivative is as shown in the following general formula I:其中,所述通式Ⅰ中的R1、R2相同或不相同的为芳基、杂芳基中的任一种。Wherein, the same or different R1 and R2 in the general formula I are any one of aryl and heteroaryl.
- 根据权利要求1所述的四氢咔唑衍生物,其特征在于:所述芳基包括苯基、单取代苯基、多取代苯基中的任一种;The tetrahydrocarbazole derivative according to claim 1, wherein the aryl group includes any one of phenyl, monosubstituted phenyl, and polysubstituted phenyl;所述杂芳基包括吡咯、取代吡咯、噻吩、取代噻吩、吡啶、取代吡啶、嘧啶、取代嘧啶中的任一种。The heteroaryl group includes any one of pyrrole, substituted pyrrole, thiophene, substituted thiophene, pyridine, substituted pyridine, pyrimidine, and substituted pyrimidine.
- 根据权利要求2所述的四氢咔唑衍生物,其特征在于:所述单取代苯基中的取代基团包括卤素原子、-CF3、-C≡CH、-C≡N、-NO2、-OCH3中的任一种;Tetrahydrocarbazole derivatives according to claim 2, characterized in that: the substituting groups in the monosubstituted phenyl include halogen atoms, -CF3, -C≡CH, -C≡N, -NO2, - Any of OCH3;所述多取代苯基中的取代基团包括卤素原子、-OCH3中的至少一种。The substituent groups in the multi-substituted phenyl group include at least one of halogen atoms and -OCH3.
- 根据权利要求2所述的四氢咔唑衍生物,其特征在于:所述取代吡咯中的取代基团包括-OCH3;The tetrahydrocarbazole derivative according to claim 2, characterized in that: the substituting group in the substituted pyrrole comprises -OCH3;所述取代噻吩中的取代基团包括-C≡N。The substituent group in the substituted thiophene includes -C≡N.
- 一种四氢咔唑衍生物的制备方法,包括如下步骤:A preparation method of tetrahydrocarbazole derivatives, comprising the steps of:将如下结构式ⅠA所示的反应物A与如下结构式ⅠB所示的反应物B和碱催化剂于第一反应溶剂中进行第一取代反应,生成如下结构式ⅠZ1所示的第一中间产物;The reactant A shown in the following structural formula IA, the reactant B shown in the following structural formula IB and the base catalyst are subjected to the first substitution reaction in the first reaction solvent to generate the first intermediate product shown in the following structural formula IZ1;将所述第一中间产物与还原剂、酸性添加剂在第二反应溶剂中反进行氧化还原反应,生成如下结构式ⅠZ2所示的第二中间产物;Reverse redox reaction of the first intermediate product, reducing agent and acidic additive in the second reaction solvent to generate the second intermediate product shown in the following structural formula IZ2;将所述第二中间产物与如下结构式ⅠC所示的反应物C和复合催化剂于第三反应溶剂中进行第二取代反应,生成如下结构式ⅠZ3所示的第三中间产物;The second intermediate product is subjected to a second substitution reaction with reactant C shown in the following structural formula IC and a composite catalyst in a third reaction solvent to generate a third intermediate product shown in the following structural formula IZ3;在保护气氛中,将所述第三中间产物与氨基胍碳酸氢盐于第四反应溶剂中进行缩合反应,生成如下结构式Ⅰ所示的四氢咔唑衍生物;In a protective atmosphere, the third intermediate product is condensed with aminoguanidine bicarbonate in a fourth reaction solvent to generate a tetrahydrocarbazole derivative shown in the following structural formula I;其中,所述式ⅠB中的M1和式Ⅰc中的M2相同或不相同的为卤素原子,所述式ⅠB中的R1和式ⅠC的R2相同或不相同的为芳基、杂芳基中的任一种。Wherein, the same or different M1 in the formula IB and the M2 in the formula Ic are halogen atoms, and the same or different R1 in the formula IB and the R2 in the formula IC are aryl and heteroaryl any kind.
- 根据权利要求6所述的制备方法,其特征在于:所述第一反应溶剂包括N,N-二甲基甲酰胺、四氢呋喃、2-甲基四氢呋喃、丙酮、1,4-二氧六环、乙腈、二乙二醇二甲醚、甲苯和二氯甲烷中的至少一种;和/或The preparation method according to claim 6, characterized in that: the first reaction solvent comprises N,N-dimethylformamide, tetrahydrofuran, 2-methyltetrahydrofuran, acetone, 1,4-dioxane, At least one of acetonitrile, diglyme, toluene, and methylene chloride; and/or所述碱催化剂包括碳酸铯、碳酸钾、碳酸钠、碳酸氢钠、氢氧化钠中的至少一种;和/或The base catalyst includes at least one of cesium carbonate, potassium carbonate, sodium carbonate, sodium bicarbonate, sodium hydroxide; and/or所述第一取代反应的温度为0℃~100℃。The temperature of the first substitution reaction is 0°C to 100°C.
- 根据权利要求6所述的制备方法,其特征在于:The preparation method according to claim 6, characterized in that:所述第二反应溶剂包括二氯甲烷、丙酮、1,4-二氧六环、乙腈、乙醇、异丙醇、水中的至少一种;和/或The second reaction solvent includes at least one of dichloromethane, acetone, 1,4-dioxane, acetonitrile, ethanol, isopropanol, and water; and/or所述还原剂包括铁粉、锌粉中的至少一种;和/或The reducing agent includes at least one of iron powder and zinc powder; and/or所述酸性添加剂包括氯化铵;和/或The acidic additive comprises ammonium chloride; and/or所述氧化还原反应的温度为20℃~200℃。The temperature of the redox reaction is 20°C to 200°C.
- 根据权利要求6所述的制备方法,其特征在于:所述第三反应溶剂包括N,N-二甲基甲酰胺、四氢呋喃、2-甲基四氢呋喃、丙酮、1,4-二氧六环、乙腈、二乙二醇二甲醚、甲苯和二氯甲烷中的至少一种;和/或The preparation method according to claim 6, characterized in that: the third reaction solvent comprises N,N-dimethylformamide, tetrahydrofuran, 2-methyltetrahydrofuran, acetone, 1,4-dioxane, At least one of acetonitrile, diglyme, toluene, and methylene chloride; and/or所述复合催化剂包括钯催化剂、配体和碱;和/或The composite catalyst includes a palladium catalyst, a ligand and a base; and/or所述第二取代反应的温度为20℃~200℃;和/或The temperature of the second substitution reaction is 20°C to 200°C; and/or所述第四反应溶剂包括甲醇、乙醇、丙酮、1,4-二氧六环、乙腈、甲苯和二氯甲烷中的至少一种;和/或The fourth reaction solvent includes at least one of methanol, ethanol, acetone, 1,4-dioxane, acetonitrile, toluene and methylene chloride; and/or所述缩合反应的温度为20℃~200℃。The temperature of the condensation reaction is 20°C to 200°C.
- 根据权利要求1-5任一项所述的四氢咔唑衍生物在制备结核分枝杆菌抑制剂或在制备抗结核药物中的应用。Use of the tetrahydrocarbazole derivative according to any one of claims 1-5 in the preparation of Mycobacterium tuberculosis inhibitors or in the preparation of anti-tuberculosis drugs.
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