WO2018108007A1 - Method and apparatus for generating data, device, computer storage medium - Google Patents

Method and apparatus for generating data, device, computer storage medium Download PDF

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Publication number
WO2018108007A1
WO2018108007A1 PCT/CN2017/114801 CN2017114801W WO2018108007A1 WO 2018108007 A1 WO2018108007 A1 WO 2018108007A1 CN 2017114801 W CN2017114801 W CN 2017114801W WO 2018108007 A1 WO2018108007 A1 WO 2018108007A1
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Prior art keywords
sequence
sequence set
sequences
specified
data
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PCT/CN2017/114801
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French (fr)
Chinese (zh)
Inventor
袁志锋
李卫敏
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中兴通讯股份有限公司
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Publication of WO2018108007A1 publication Critical patent/WO2018108007A1/en

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    • HELECTRICITY
    • H04ELECTRIC COMMUNICATION TECHNIQUE
    • H04WWIRELESS COMMUNICATION NETWORKS
    • H04W72/00Local resource management
    • H04W72/20Control channels or signalling for resource management
    • H04W72/21Control channels or signalling for resource management in the uplink direction of a wireless link, i.e. towards the network
    • HELECTRICITY
    • H04ELECTRIC COMMUNICATION TECHNIQUE
    • H04WWIRELESS COMMUNICATION NETWORKS
    • H04W72/00Local resource management
    • H04W72/04Wireless resource allocation

Definitions

  • the present invention relates to the field of wireless communication technologies, and in particular, to a data generation method and apparatus, a device, and a computer storage medium.
  • the application scenarios of the 5th-generation (5G) communication technology include enhanced mobile broadband (eMBB), massive machine type communication (mMTC), and high reliability low latency communication (Ultra Reliability Low). Latency Communication, URLLC).
  • eMBB enhanced mobile broadband
  • mMTC massive machine type communication
  • URLLC high reliability low latency communication
  • the eMBB scenario is used to support mobile broadband.
  • the main service requirements are large data packet transmission, high data rate, and high spectrum efficiency.
  • the mMTC scenario is used to support mass device communication.
  • the main service requirements are mass equipment and small data packet transmission.
  • ITU International Telecommunications Union
  • 3GPP 3rd Generation Partnership Project
  • the URLLC scenario is used to support high Reliable low-latency communication
  • the main business demand is high reliability, low latency transmission.
  • the traditional communication process design based on terminal random access and base station scheduling control cannot be satisfied.
  • the system access device has limited capacity, the access and data transmission process takes a long time, and the signaling overhead is large.
  • a scheduling-based transmission method can be considered.
  • data transmission can be performed, thereby eliminating a long and complicated random access process and scheduling control process, thereby greatly reducing Transmission delay and signaling overhead.
  • the traditional orthogonal access method based on semi-persistent periodic resource scheduling/reservation can be considered as an efficient dynamic scheduling-free, low-latency delay.
  • Access method Periodic resource scheduling/reservation matching the service occurrence period can ensure efficient resource utilization, and each user monopolizes resources without inter-user interference, and performance can be guaranteed.
  • the traditional periodic scheduling/reserved orthogonal resources are often not fully utilized. If the scheduling/reservation period of orthogonal resources is longer, the resource utilization ratio is higher, but the longer the average time that terminal access needs to wait, the more difficult it is to ensure ultra-low latency demand; if the orthogonal resource scheduling/reservation period The shorter the average time that terminal access needs to wait, the easier it is to ensure ultra-low latency requirements, but the higher the vacancy rate of resources and the lower the utilization rate.
  • one method is that multiple event-triggered service users share the same transmission resource (for example, a time-frequency resource block), which can reduce the vacancy rate of resources, but multiple multiple occurrences occur.
  • a transmission resource for example, a time-frequency resource block
  • an embodiment of the present invention provides a data generation method and apparatus, a device, and a computer storage medium, which can be used to implement scheduling-free transmission, and have lower sequence storage requirements and computational complexity.
  • an embodiment of the present invention provides a data generating method, including:
  • the first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set;
  • the second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set;
  • the third sequence set includes at least one of: a third specified sequence set including P sequences of length W; the second specified sequence set; and a sequence obtained by processing the second specified sequence set a set of sequences obtained from the first set of sequences and the second set of sequences;
  • M, L, N, C, P, and W are positive integers.
  • ⁇ 1,1i,-1,-1i ⁇ ; ⁇ 1,-1 ⁇ ; ⁇ 1i,-1i ⁇ ; ⁇ 1 ⁇ ; ⁇ -1 ⁇ ; ⁇ 1i ⁇ ; ⁇ -1i ⁇ ; ⁇ 1+1i,- 1+1i, -1-1i, 1-1i ⁇ ; ⁇ 0 ⁇ ; ⁇ 1, 1i, -1, -1i, 0 ⁇ ; ⁇ 1+1i, -1+1i, -1-1i, 1-1i , 0 ⁇ ; ⁇ 1, 1i, -1, -1i, 2, 2i, -2, -2i, 0 ⁇ ; where i is an imaginary unit and i sqrt(-1).
  • the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set
  • the first specified sequence set includes at least one of the following sequence sets:
  • the sequence set 1 includes four sequences of length 4, wherein
  • the first sequence is [1,1,1,1],
  • the second sequence is [1,1,1i,-1i],
  • the third sequence is [1, 1i, 1, -1i],
  • the fourth sequence is [1, 1i, 1i, -1];
  • the sequence set 2 includes four sequences of length 4, wherein
  • the first sequence is [1,1,1,-1],
  • the second sequence is [1,1,1i,1i],
  • the third sequence is [1, 1i, 1, 1i],
  • the fourth sequence is [1, 1i, 1i, 1];
  • the sequence set 2 includes four sequences of length 4, wherein
  • the first sequence is [1,1,1,1i],
  • the second sequence is [1,1,1i,1],
  • the third sequence is [1, 1i, 1, 1],
  • the fourth sequence is [1, 1i, 1i, -1i];
  • the sequence set 4 includes four sequences of length 4, wherein
  • the first sequence is [1,1,1,-1i],
  • the second sequence is [1,1,1i,-1],
  • the third sequence is [1, 1i, 1, -1],
  • the fourth sequence is [1, 1i, 1i, 1i];
  • the sequence set 5 includes a sequence of length 2, wherein
  • the first sequence is [1,1];
  • the sequence set 6 includes a sequence of length 2, wherein
  • the first sequence is [1,-1];
  • the sequence set 7 includes a sequence of length 2, wherein
  • the first sequence is [1, 1i];
  • the sequence set 8 includes a sequence of length 2, wherein
  • the first sequence is [1,-1i];
  • the sequence set 9 includes four sequences of length 1, wherein
  • the first sequence is [1]
  • the third sequence is [-1],
  • the fourth sequence is [-1i];
  • the sequence set 10 includes four sequences of length 1, wherein
  • the first sequence is [1+1i]
  • the second sequence is [-1+1i]
  • the third sequence is [-1-1i]
  • the fourth sequence is [1-1i];
  • the sequence set 11 includes two sequences of length 1, wherein
  • the first sequence is [1]
  • the second sequence is [-1];
  • the sequence set 12 includes two sequences of length 1, wherein
  • the first sequence is [1i]
  • the second sequence is [-1i];
  • the sequence set 13 includes a sequence of length 1, wherein
  • the first sequence is [1];
  • the sequence set 14 includes a sequence of length 1, wherein
  • the first sequence is [-1];
  • the sequence set 15 includes a sequence of length 1, wherein
  • the first sequence is [1i];
  • the sequence set 16 includes a sequence of length 1, wherein
  • the first sequence is [-1i];
  • the sequence set 17 includes four sequences of length 3, wherein
  • the first sequence is [1,1,1];
  • the second sequence is [1,-1,-1],
  • the third sequence is [-1, 1, -1],
  • the fourth sequence is [-1, 1, 1];
  • the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set
  • the processing of the sequence in the first specified sequence set includes:
  • X is an integer greater than or equal to 1 and less than or equal to L
  • A is an integer
  • B is a real number
  • the third sequence set includes a second specified sequence set, a sequence set obtained by processing the second specified sequence set, according to the first sequence set and the second sequence set When at least one of the sequence sets obtained by the sequence set,
  • the second specified sequence set includes at least one of the following:
  • the third sequence set includes a second specified sequence set, a sequence set obtained by processing the second specified sequence set, according to the first sequence set and the second sequence set When at least one of the resulting sequence sets is obtained,
  • the second specified sequence set includes at least one of the following sequence sets; wherein
  • the sequence set 1 includes four sequences of length 4, wherein
  • the first sequence is [1,1,1,1],
  • the second sequence is [1,1,-1,-1],
  • the third sequence is [1,-1,1,-1],
  • the fourth sequence is [1, -1, -1, 1];
  • the sequence set 2 includes four sequences of length 4, wherein
  • the first sequence is [1,1,1,1],
  • the second sequence is [1, 1i, -1, -1i],
  • the third sequence is [1,-1,1,-1],
  • the fourth sequence is [1,-1i,-1,1i];
  • the sequence set 3 includes two sequences of length 2, wherein
  • the first sequence is [1,1],
  • the second sequence is [1,-1];
  • the sequence set 4 includes a sequence of length 1, wherein
  • the first sequence is [1];
  • the sequence set 5 includes six sequences of length 4, wherein
  • the first sequence is [1,1,0,0],
  • the second sequence is [1,0,1,0],
  • the third sequence is [1,0,0,1],
  • the fourth sequence is [0, 1, 1, 0],
  • the fifth sequence is [0, 1, 0, 1],
  • the sixth sequence is [0,0,1,1];
  • the sequence set 6 includes four sequences of length 6, wherein
  • the first sequence is [1,1,1,0,0,0]
  • the second sequence is [1,0,0,1,1,0],
  • the third sequence is [0, 1, 0, 0, 1, 1],
  • the fourth sequence is [0,0,1,1,0,1],
  • the sequence set 7 includes four sequences of length 6, wherein
  • the first sequence is [1,0,1,0,1,0],
  • the second sequence is [1,0,0,1,0,1],
  • the third sequence is [0,1,1,0,0,1]
  • the fourth sequence is [0,1,0,1,1,0],
  • the sequence set 8 includes four sequences of length 4, wherein
  • the first sequence is [1,0,0,0],
  • the second sequence is [0,1,0,0],
  • the third sequence is [0,0,1,0],
  • the fourth sequence is [0,0,0,1];
  • the sequence set 9 includes six sequences of length 6, wherein
  • the first sequence is [1,1,1,1,1],
  • the second sequence is [1,1,1i,-1,-1,-1i],
  • the third sequence is [1, 1i, -1i, 1i, -1i, -1],
  • the fourth sequence is [1,-1,1,-1i,-1,1i],
  • the fifth sequence is [1,-1,-1,1,1i,-1i],
  • the sixth sequence is [1,-1i,-1,-1,1,1i];
  • the third sequence set includes a second specified sequence set, a sequence set obtained by processing the second specified sequence set, according to the first sequence set and the second sequence set When at least one of the resulting sequence sets is obtained,
  • the processing of the sequence in the second specified sequence set includes:
  • Y is an integer greater than or equal to 1 and less than or equal to C
  • E is an integer
  • F is a real number
  • the third specified sequence set includes at least one of the following sequence sets:
  • the sequence set 1 comprises 16 sequences of length 4, wherein
  • the first sequence is [1,1,1,1],
  • the second sequence is [1,1,-1,-1],
  • the third sequence is [1,-1,1,-1],
  • the fourth sequence is [1,-1,-1,1],
  • the fifth sequence is [1,1,1i,-1i],
  • the sixth sequence is [1,1,-1i,1i],
  • the seventh sequence is [1,-1,1i,1i],
  • the eighth sequence is [1,-1,-1i,-1i],
  • the ninth sequence is [1, 1i, 1, -1i],
  • the tenth sequence is [1, 1i, -1, 1i],
  • the eleventh sequence is [1,-1i,1,1i],
  • the twelfth sequence is [1,-1i,-1,-1i],
  • the thirteenth sequence is [1, 1i, 1i, -1],
  • the fourteenth sequence is [1, 1i, -1i, 1],
  • the fifteenth sequence is [1,-1i,1i,1],
  • the sixteenth sequence is [1,-1i,-1i,-1];
  • the sequence set 2 includes 16 sequences of length 4, wherein
  • the first sequence is [1,1,1,-1],
  • the second sequence is [1,1,-1,1],
  • the third sequence is [1,-1,1,1],
  • the fourth sequence is [1,-1,-1,-1],
  • the fifth sequence is [1,1,1i,1i],
  • the sixth sequence is [1,1,-1i,-1i],
  • the seventh sequence is [1,-1,1i,-1i],
  • the eighth sequence is [1,-1,-1i,1i],
  • the ninth sequence is [1, 1i, 1, 1i],
  • the tenth sequence is [1, 1i, -1, -1i],
  • the eleventh sequence is [1,-1i,1,-1i],
  • the twelfth sequence is [1,-1i,-1,1i],
  • the thirteenth sequence is [1, 1i, 1i, 1],
  • the fourteenth sequence is [1, 1i, -1i, -1],
  • the fifteenth sequence is [1,-1i,1i,-1],
  • the sixteenth sequence is [1,-1i,-1i,1];
  • the sequence set 3 includes 16 sequences of length 4, wherein
  • the first sequence is [1,1,1,1i],
  • the second sequence is [1,1,-1,-1i],
  • the third sequence is [1,-1,1,-1i],
  • the fourth sequence is [1,-1,-1,1i],
  • the fifth sequence is [1,1,1i,1],
  • the sixth sequence is [1,1,-1i,-1],
  • the seventh sequence is [1,-1,1i,-1],
  • the eighth sequence is [1,-1,-1i,1],
  • the ninth sequence is [1, 1i, 1, 1],
  • the tenth sequence is [1, 1i, -1, -1],
  • the eleventh sequence is [1,-1i,1,-1],
  • the twelfth sequence is [1,-1i,-1,1],
  • the thirteenth sequence is [1, 1i, 1i, -1i],
  • the fourteenth sequence is [1, 1i, -1i, 1i],
  • the fifteenth sequence is [1,-1i,1i,1i],
  • the sixteenth sequence is [1,-1i,-1i,-1i];
  • the sequence set 4 includes 16 sequences of length 4, wherein
  • the first sequence is [1,1,1,-1i],
  • the second sequence is [1,1,-1,1i],
  • the third sequence is [1,-1,1,1i],
  • the fourth sequence is [1,-1,-1,-1i],
  • the fifth sequence is [1,1,1i,-1],
  • the sixth sequence is [1,1,-1i,1],
  • the seventh sequence is [1,-1,1i,1],
  • the eighth sequence is [1,-1,-1i,-1],
  • the ninth sequence is [1, 1i, 1, -1],
  • the tenth sequence is [1, 1i, -1, 1],
  • the eleventh sequence is [1,-1i,1,1],
  • the twelfth sequence is [1,-1i,-1,-1],
  • the thirteenth sequence is [1, 1i, 1i, 1i],
  • the fourteenth sequence is [1, 1i, -1i, -1i],
  • the fifteenth sequence is [1,-1i,1i,-1i],
  • the sixteenth sequence is [1,-1i,-1i,1i];
  • the sequence set 5 includes 32 sequences of length 4, wherein
  • the first sequence is [1,1,1,1],
  • the second sequence is [1, 1i, -1, -1i],
  • the third sequence is [1,-1,1,-1],
  • the fourth sequence is [1,-1i,-1,1i],
  • the fifth sequence is [1,1,1i,-1i],
  • the sixth sequence is [1, 1i, -1i, -1],
  • the seventh sequence is [1,-1,1i,1i],
  • the eighth sequence is [1,-1i,-1i,1],
  • the ninth sequence is [1, 1i, 1, -1i],
  • the tenth sequence is [1,-1,-1,-1],
  • the eleventh sequence is [1,-1i,1,1i],
  • the thirteenth sequence is [1, 1i, 1i, -1],
  • the fourteenth sequence is [1,-1,-1i,1i],
  • the fifteenth sequence is [1,-1i,1i,1],
  • the sixteenth sequence is [1,1,-1i,-1i],
  • the seventeenth sequence is [1,1,1,-1],
  • the eighteenth sequence is [1, 1i, -1, 1i],
  • the nineteenth sequence is [1,-1,1,1],
  • the twentieth sequence is [1,-1i,-1,-1i],
  • the twenty-first sequence is [1,1,1i,1i],
  • the twenty-second sequence is [1, 1i, -1i, 1],
  • the twenty-third sequence is [1,-1,1i,-1i],
  • the twenty-fourth sequence is [1,-1i,-1i,-1],
  • the twenty-fifth sequence is [1,1i,1,1i],
  • the twenty-sixth sequence is [1,-1,-1,1],
  • the twenty-seventh sequence is [1,-1i,1,-1i],
  • the twenty-eighth sequence is [1,1,-1,-1],
  • the twenty-ninth sequence is [1, 1i, 1i, 1],
  • the thirtieth sequence is [1,-1,-1i,-1i],
  • the thirty-first sequence is [1,-1i,1i,-1],
  • the thirty-second sequence is [1,1,-1i,1i];
  • the sequence set 6 includes 32 sequences of length 4, wherein
  • the first sequence is [1,1,1,1i],
  • the second sequence is [1, 1i, -1, 1],
  • the third sequence is [1,-1,1,-1i],
  • the fourth sequence is [1,-1i,-1,-1],
  • the fifth sequence is [1,1,1i,1],
  • the sixth sequence is [1, 1i, -1i, -1i],
  • the seventh sequence is [1,-1,1i,-1],
  • the eighth sequence is [1,-1i,-1i,1i],
  • the ninth sequence is [1, 1i, 1, 1],
  • the tenth sequence is [1,-1,-1,-1i],
  • the eleventh sequence is [1,-1i,1,-1],
  • the thirteenth sequence is [1, 1i, 1i, -1i],
  • the fourteenth sequence is [1,-1,-1i,-1],
  • the fifteenth sequence is [1,-1i,1i,i],
  • the seventeenth sequence is [1,1,1,-1i],
  • the eighteenth sequence is [1,1i,-1,-1],
  • the nineteenth sequence is [1,-1,1,1i],
  • the twentieth sequence is [1,-1i,-1,1],
  • the twenty-first sequence is [1,1,1i,-1],
  • the twenty-second sequence is [1, 1i, -1i, 1i],
  • the twenty-third sequence is [1,-1,1i,1],
  • the twenty-fourth sequence is [1,-1i,-1i,-1i],
  • the twenty-fifth sequence is [1, 1i, 1, -1],
  • the twenty-sixth sequence is [1,-1,-1,1i],
  • the twenty-seventh sequence is [1,-1i,1,1],
  • the twenty-eighth sequence is [1,1,-1,-1i],
  • the twenty-ninth sequence is [1, 1i, 1i, 1i],
  • the thirtieth sequence is [1,-1,-1i,1],
  • the thirty-first sequence is [1,-1i,1i,-1i],
  • the thirty-second sequence is [1, 1, -1i, -1];
  • the sequence set 7 includes four sequences of length 4, wherein
  • the first sequence is [1,0,0,0],
  • the second sequence is [0,1,0,0],
  • the third sequence is [0,0,1,0],
  • the fourth sequence is [0,0,0,1];
  • the sequence set 8 includes 16 sequences of length 6, wherein
  • the first sequence is [1,0,1,0,1,0],
  • the second sequence is [-1,0,1,0,-1,0],
  • the third sequence is [1,0,-1,0,-1,0],
  • the fourth sequence is [-1,0,-1,0,1,0],
  • the fifth sequence is [1,0,0,1,0,1],
  • the sixth sequence is [-1,0,0,1,0,-1],
  • the seventh sequence is [1,0,0,-1,0,-1],
  • the eighth sequence is [-1,0,0,-1,0,1],
  • the ninth sequence is [0, 1, 1, 0, 0, 1],
  • the tenth sequence is [0, -1, 1, 0, 0, -1],
  • the eleventh sequence is [0, 1, -1, 0, 0, -1],
  • the twelfth sequence is [0,-1,-1,0,0,1],
  • the thirteenth sequence is [0,1,0,1,1,0],
  • the fourteenth sequence is [0, -1, 0, 1, -1, 0],
  • the fifteenth sequence is [0,1,0,-1,-1,0],
  • the sixteenth sequence is [0, -1, 0, -1, 1, 0];
  • the sequence set 9 includes 16 sequences of length 6, wherein
  • the first sequence is [1,1,1,0,0,0]
  • the second sequence is [-1,1,-1,0,0,0],
  • the third sequence is [1,-1,-1,0,0,0],
  • the fourth sequence is [-1,-1,1,0,0,0],
  • the fifth sequence is [0,0,1,1,1,0],
  • the sixth sequence is [0,0,-1,-1,1,0],
  • the seventh sequence is [0,0,-1,1,-1,0],
  • the eighth sequence is [0,0,1,-1,-1,0],
  • the ninth sequence is [1,0,0,0,1,1],
  • the tenth sequence is [-1,0,0,0,1,-1],
  • the eleventh sequence is [1,0,0,0,-1,-1],
  • the twelfth sequence is [-1,0,0,0,-1,1],
  • the thirteenth sequence is [0, 1, 0, 1, 0, 1],
  • the fourteenth sequence is [0,1,0,-1,0,-1],
  • the fifteenth sequence is [0, -1, 0, 1, 0, -1],
  • the sixteenth sequence is [0, -1, 0, -1, 0, 1];
  • the sequence set 10 includes 16 sequences of length 6, wherein
  • the first sequence is [1,1,1,1,1],
  • the second sequence is [1,1,1,1,-1,-1],
  • the third sequence is [1,1,1,-1,1,-1],
  • the fourth sequence is [1,1,1,-1,-1,1],
  • the fifth sequence is [1,1,-1,1,1,-1],
  • the sixth sequence is [1,1,-1,1,-1,1],
  • the seventh sequence is [1,1,-1,-1,1,1],
  • the eighth sequence is [1,1,-1,-1,-1,-1],
  • the ninth sequence is [1,-1,1,1,1,-1],
  • the tenth sequence is [1,-1,1,1,-1,1],
  • the eleventh sequence is [1,-1,1,-1,1,1],
  • the twelfth sequence is [1,-1,1,-1,-1,-1],
  • the thirteenth sequence is [1,-1,-1,1,1,1],
  • the fourteenth sequence is [1,-1,-1,1,-1,-1],
  • the fifteenth sequence is [1,-1,-1,-1,1,-1],
  • the sixteenth sequence is [1,-1,-1,-1,-1,1];
  • the sequence set 11 includes 32 sequences of length 4, wherein
  • the first sequence is [1+0i, 1+0i, 1+0i, 1+0i],
  • the second sequence is [1+0i, 0+1i, -1+0i, -0-1i],
  • the third sequence is [1+0i, -1+0i, 1+0i, -1+0i],
  • the fourth sequence is [1+0i, -0-1i, -1+0i, 0+1i],
  • the fifth sequence is [0+2i, -0-1i, 0+2i, 0+1i],
  • the sixth sequence is [0+2i, 1+0i, -0-2i, 1+0i],
  • the seventh sequence is [0+2i, 0+1i, 0+2i, -0-1i],
  • the eighth sequence is [0+2i, -1+0i, -0-2i, -1+0i],
  • the ninth sequence is [0+2i, -0-1i, -1+0i, 2+0i],
  • the tenth sequence is [0+2i, 1+0i, 1+0i-0-2i],
  • the eleventh sequence is [0+2i, 0+1i, -1+0i, -2+0i],
  • the twelfth sequence is [0+2i, -1+0i, 1+0i, 0+2i],
  • the thirteenth sequence is [0+2i, -0-1i, 0+0i, -1+0i],
  • the fourteenth sequence is [0+2i, 1+0i, 0+0i, 0+1i],
  • the fifteenth sequence is [0+2i, 0+1i, 0+0i, 1+0i],
  • the sixteenth sequence is [0+2i, -1+0i, 0+0i, -0-1i],
  • the seventeenth sequence is [-1+0i, -0-1i, -0-2i, -2+0i],
  • the eighteenth sequence is [-1+0i, 1+0i, 0+2i, 0+2i],
  • the nineteenth sequence is [-1+0i, 0+1i, -0-2i, 2+0i],
  • the twentieth sequence is [-1+0i, -1+0i, 0+2i, -0-2i],
  • the twenty-first sequence is [-1+0i, -2+0i, 0+2i, 0+1i],
  • the twenty-second sequence is [-1+0i,-0-2i,-0-2i, 1+0i],
  • the twenty-third sequence is [-1+0i, 2+0i, 0+2i, -0-1i],
  • the twenty-fourth sequence is [-1+0i, 0+2i, -0-2i, -1+0i],
  • the twenty-fifth sequence is [-1+0i, -2+0i, 1+0i, -2+0i],
  • the twenty-sixth sequence is [-1+0i, -0-2i, -1+0i, 0+2i],
  • the twenty-seventh sequence is [-1+0i, 2+0i, 1+0i, 2+0i],
  • the twenty-eighth sequence is [-1+0i, 0+2i, -1+0i, -0-2i],
  • the twenty-ninth sequence is [-1+0i, -2+0i, -0-1i, 0+0i],
  • the thirtieth sequence is [-1+0i,-0-2i, 0+1i, 0+0i],
  • the thirty-first sequence is [-1+0i, 2+0i, -0-1i, 0+0i],
  • the thirty-second sequence is [-1+0i, 0+2i, 0+1i, 0+0i];
  • sequence in the process is a collection obtained by any of the following processes:
  • S is an integer greater than or equal to 1 and less than or equal to W
  • Q is an integer
  • R is a real number
  • the third sequence is determined from a third sequence set, and the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set,
  • the sequence set obtained according to the first sequence set and the second sequence set includes at least one of the following:
  • the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set
  • the first sequence is obtained from the first sequence set, including one of the following:
  • the third sequence set includes a second specified sequence set, a sequence set obtained by processing the second specified sequence set, according to the first sequence set and the second sequence set When at least one of the resulting sequence sets is obtained,
  • the second sequence is obtained from the second sequence set, including one of the following:
  • the determining the third sequence according to the first sequence and the second sequence comprises:
  • Determining the third sequence from the third sequence set includes:
  • the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set
  • the method also includes one of the following:
  • the method also includes one of the following:
  • the third sequence is subjected to energy adjustment or energy normalization.
  • the method further includes:
  • V is an integer greater than or equal to 1 and less than or equal to the length of the third sequence
  • G is an integer
  • H is a real number
  • the processing, by using the third sequence, the first data to generate the second data includes:
  • the first data is modulated using the third sequence to generate second data.
  • the method further includes:
  • the first data includes at least identifier information of a transmitter or a terminal; or
  • At least the identity information and the cell identification information of the transmitter or the terminal are included; or
  • At least the identity information, cell identification information, data information and signaling information of the transmitter or the terminal are included.
  • the second data includes at least the identity information of the transmitter or the terminal;
  • the identity information, signaling information, and data information of the transmitter or the terminal Or at least the identity information, signaling information, and data information of the transmitter or the terminal; or,
  • At least the identity information and the cell identification information of the transmitter or the terminal are included; or
  • At least the identity information, cell identification information, data information and signaling information of the transmitter or the terminal are included.
  • the specified transmission resource includes at least one of the following: a carrier, a time slot, a time-frequency resource, an airspace resource, a code domain resource, a frequency hopping mode, and an antenna port.
  • the time-frequency resource is an uplink data channel, or an uplink control channel, or a random access channel.
  • the first data includes at least one of the following: vehicle condition information, driver operation information, information sensed by the vehicle sensor, and control signaling; wherein the vehicle condition information includes the following: At least one of: a vehicle tool identification, a current geographic location of the vehicle, a traveling speed of the vehicle, a size of the vehicle, a color of the vehicle; the operational information comprising at least one of: the driver's office The ongoing operation of the vehicle, the driver preparing an operation on the vehicle.
  • vehicle condition information includes the following: At least one of: a vehicle tool identification, a current geographic location of the vehicle, a traveling speed of the vehicle, a size of the vehicle, a color of the vehicle
  • the operational information comprising at least one of: the driver's office The ongoing operation of the vehicle, the driver preparing an operation on the vehicle.
  • the embodiment of the present invention further provides a data generating apparatus, where the apparatus includes:
  • a determining unit configured to determine a third sequence according to the first sequence and the second sequence, wherein the first sequence is obtained from a first sequence set, and the second sequence is obtained from a second sequence set; or, from Determining the third sequence in a three-sequence set;
  • a generating unit configured to process the first data by using the third sequence to generate second data
  • the first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set;
  • the second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set;
  • the third sequence set includes at least one of: a third specified sequence set including P sequences of length W; the second specified sequence set; and a sequence obtained by processing the second specified sequence set a set of sequences obtained from the first set of sequences and the second set of sequences;
  • M, L, N, C, P, and W are positive integers.
  • the determining unit determines, according to the first sequence and the second sequence, a value of a sequence element in the first specified sequence set when the third sequence is determined, or
  • the determining unit determines the third specified sequence when the third sequence is determined from the third sequence set
  • the values of the sequence elements in the column set are all from at least one of the following sets:
  • ⁇ 1,1i,-1,-1i ⁇ ; ⁇ 1,-1 ⁇ ; ⁇ 1i,-1i ⁇ ; ⁇ 1 ⁇ ; ⁇ -1 ⁇ ; ⁇ 1i ⁇ ; ⁇ -1i ⁇ ; ⁇ 1+1i,- 1+1i, -1-1i, 1-1i ⁇ ; ⁇ 0 ⁇ ; ⁇ 1, 1i, -1, -1i, 0 ⁇ ; ⁇ 1+1i, -1+1i, -1-1i, 1-1i , 0 ⁇ ; ⁇ 1, 1i, -1, -1i, 2, 2i, -2, -2i, 0 ⁇ ; where i is an imaginary unit and i sqrt(-1).
  • the determining unit determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set Including a sequence set obtained from the first sequence set and the second sequence set,
  • the first specified sequence set includes at least one of the following sequence sets:
  • the sequence set 1 includes four sequences of length 4, wherein
  • the first sequence is [1,1,1,1],
  • the second sequence is [1,1,1i,-1i],
  • the third sequence is [1, 1i, 1, -1i],
  • the fourth sequence is [1, 1i, 1i, -1];
  • the sequence set 2 includes four sequences of length 4, wherein
  • the first sequence is [1,1,1,-1],
  • the second sequence is [1,1,1i,1i],
  • the third sequence is [1, 1i, 1, 1i],
  • the fourth sequence is [1, 1i, 1i, 1];
  • the sequence set 2 includes four sequences of length 4, wherein
  • the first sequence is [1,1,1,1i],
  • the second sequence is [1,1,1i,1],
  • the third sequence is [1, 1i, 1, 1],
  • the fourth sequence is [1, 1i, 1i, -1i];
  • the sequence set 4 includes four sequences of length 4, wherein
  • the first sequence is [1,1,1,-1i],
  • the second sequence is [1,1,1i,-1],
  • the third sequence is [1, 1i, 1, -1],
  • the fourth sequence is [1, 1i, 1i, 1i];
  • the sequence set 5 includes a sequence of length 2, wherein
  • the first sequence is [1,1];
  • the sequence set 6 includes a sequence of length 2, wherein
  • the first sequence is [1,-1];
  • the sequence set 7 includes a sequence of length 2, wherein
  • the first sequence is [1, 1i];
  • the sequence set 8 includes a sequence of length 2, wherein
  • the first sequence is [1,-1i];
  • the sequence set 9 includes four sequences of length 1, wherein
  • the first sequence is [1]
  • the third sequence is [-1],
  • the fourth sequence is [-1i];
  • the sequence set 10 includes four sequences of length 1, wherein
  • the first sequence is [1+1i]
  • the second sequence is [-1+1i]
  • the third sequence is [-1-1i]
  • the fourth sequence is [1-1i];
  • the sequence set 11 includes two sequences of length 1, wherein
  • the first sequence is [1]
  • the second sequence is [-1];
  • the sequence set 12 includes two sequences of length 1, wherein
  • the first sequence is [1i]
  • the second sequence is [-1i];
  • the sequence set 13 includes a sequence of length 1, wherein
  • the first sequence is [1];
  • the sequence set 14 includes a sequence of length 1, wherein
  • the first sequence is [-1];
  • the sequence set 15 includes a sequence of length 1, wherein
  • the first sequence is [1i];
  • the sequence set 16 includes a sequence of length 1, wherein
  • the first sequence is [-1i];
  • the sequence set 17 includes four sequences of length 3, wherein
  • the first sequence is [1,1,1];
  • the second sequence is [1,-1,-1],
  • the third sequence is [-1, 1, -1],
  • the fourth sequence is [-1, 1, 1];
  • the determining unit determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set
  • the sequence set obtained according to the first sequence set and the second sequence set is included, it is further configured as:
  • X is an integer greater than or equal to 1 and less than or equal to L
  • A is an integer
  • B is a real number
  • the determining unit determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set And including a second specified sequence set, a sequence set obtained by processing the second specified sequence set, and at least one of the sequence set obtained according to the first sequence set and the second sequence set,
  • the second specified sequence set includes at least one of the following:
  • the determining unit determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set And including a second specified sequence set, a sequence set obtained by processing the second specified sequence set, and at least one of the sequence set obtained according to the first sequence set and the second sequence set,
  • the second specified sequence set includes at least one of the following sequence sets; wherein
  • the sequence set 1 includes four sequences of length 4, wherein
  • the first sequence is [1,1,1,1],
  • the second sequence is [1,1,-1,-1],
  • the third sequence is [1,-1,1,-1],
  • the fourth sequence is [1, -1, -1, 1];
  • the sequence set 2 includes four sequences of length 4, wherein
  • the first sequence is [1,1,1,1],
  • the second sequence is [1, 1i, -1, -1i],
  • the third sequence is [1,-1,1,-1],
  • the fourth sequence is [1,-1i,-1,1i];
  • the sequence set 3 includes two sequences of length 2, wherein
  • the first sequence is [1,1],
  • the second sequence is [1,-1];
  • the sequence set 4 includes a sequence of length 1, wherein
  • the first sequence is [1];
  • the sequence set 5 includes six sequences of length 4, wherein
  • the first sequence is [1,1,0,0],
  • the second sequence is [1,0,1,0],
  • the third sequence is [1,0,0,1],
  • the fourth sequence is [0, 1, 1, 0],
  • the fifth sequence is [0, 1, 0, 1],
  • the sixth sequence is [0,0,1,1];
  • the sequence set 6 includes four sequences of length 6, wherein
  • the first sequence is [1,1,1,0,0,0]
  • the second sequence is [1,0,0,1,1,0],
  • the third sequence is [0, 1, 0, 0, 1, 1],
  • the fourth sequence is [0,0,1,1,0,1],
  • the sequence set 7 includes four sequences of length 6, wherein
  • the first sequence is [1,0,1,0,1,0],
  • the second sequence is [1,0,0,1,0,1],
  • the third sequence is [0,1,1,0,0,1]
  • the fourth sequence is [0,1,0,1,1,0],
  • the sequence set 8 includes four sequences of length 4, wherein
  • the first sequence is [1,0,0,0],
  • the second sequence is [0,1,0,0],
  • the third sequence is [0,0,1,0],
  • the fourth sequence is [0,0,0,1];
  • the sequence set 9 includes six sequences of length 6, wherein
  • the first sequence is [1,1,1,1,1],
  • the second sequence is [1,1,1i,-1,-1,-1i],
  • the third sequence is [1, 1i, -1i, 1i, -1i, -1],
  • the fourth sequence is [1,-1,1,-1i,-1,1i],
  • the fifth sequence is [1,-1,-1,1,1i,-1i],
  • the sixth sequence is [1,-1i,-1,-1,1,1i];
  • the determining unit determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set
  • the sequence set obtained by processing the second specified sequence set, and the sequence set obtained according to the first sequence set and the second sequence set are at least one of:
  • Y is an integer greater than or equal to 1 and less than or equal to C
  • E is an integer
  • F is a real number
  • the determining unit determines the third sequence from the third sequence set
  • the third specified sequence set includes at least one of the following sequence sets:
  • the sequence set 1 comprises 16 sequences of length 4, wherein
  • the first sequence is [1,1,1,1],
  • the second sequence is [1,1,-1,-1],
  • the third sequence is [1,-1,1,-1],
  • the fourth sequence is [1,-1,-1,1],
  • the fifth sequence is [1,1,1i,-1i],
  • the sixth sequence is [1,1,-1i,1i],
  • the seventh sequence is [1,-1,1i,1i],
  • the eighth sequence is [1,-1,-1i,-1i],
  • the ninth sequence is [1, 1i, 1, -1i],
  • the tenth sequence is [1, 1i, -1, 1i],
  • the eleventh sequence is [1,-1i,1,1i],
  • the twelfth sequence is [1,-1i,-1,-1i],
  • the thirteenth sequence is [1, 1i, 1i, -1],
  • the fourteenth sequence is [1, 1i, -1i, 1],
  • the fifteenth sequence is [1,-1i,1i,1],
  • the sixteenth sequence is [1,-1i,-1i,-1];
  • the sequence set 2 includes 16 sequences of length 4, wherein
  • the first sequence is [1,1,1,-1],
  • the second sequence is [1,1,-1,1],
  • the third sequence is [1,-1,1,1],
  • the fourth sequence is [1,-1,-1,-1],
  • the fifth sequence is [1,1,1i,1i],
  • the sixth sequence is [1,1,-1i,-1i],
  • the seventh sequence is [1,-1,1i,-1i],
  • the eighth sequence is [1,-1,-1i,1i],
  • the ninth sequence is [1, 1i, 1, 1i],
  • the tenth sequence is [1, 1i, -1, -1i],
  • the eleventh sequence is [1,-1i,1,-1i],
  • the twelfth sequence is [1,-1i,-1,1i],
  • the thirteenth sequence is [1, 1i, 1i, 1],
  • the fourteenth sequence is [1, 1i, -1i, -1],
  • the fifteenth sequence is [1,-1i,1i,-1],
  • the sixteenth sequence is [1,-1i,-1i,1];
  • the sequence set 3 includes 16 sequences of length 4, wherein
  • the first sequence is [1,1,1,1i],
  • the second sequence is [1,1,-1,-1i],
  • the third sequence is [1,-1,1,-1i],
  • the fourth sequence is [1,-1,-1,1i],
  • the fifth sequence is [1,1,1i,1],
  • the sixth sequence is [1,1,-1i,-1],
  • the seventh sequence is [1,-1,1i,-1],
  • the eighth sequence is [1,-1,-1i,1],
  • the ninth sequence is [1, 1i, 1, 1],
  • the tenth sequence is [1, 1i, -1, -1],
  • the eleventh sequence is [1,-1i,1,-1],
  • the twelfth sequence is [1,-1i,-1,1],
  • the thirteenth sequence is [1, 1i, 1i, -1i],
  • the fourteenth sequence is [1, 1i, -1i, 1i],
  • the fifteenth sequence is [1,-1i,1i,1i],
  • the sixteenth sequence is [1,-1i,-1i,-1i];
  • the sequence set 4 includes 16 sequences of length 4, wherein
  • the first sequence is [1,1,1,-1i],
  • the second sequence is [1,1,-1,1i],
  • the third sequence is [1,-1,1,1i],
  • the fourth sequence is [1,-1,-1,-1i],
  • the fifth sequence is [1,1,1i,-1],
  • the sixth sequence is [1,1,-1i,1],
  • the seventh sequence is [1,-1,1i,1],
  • the eighth sequence is [1,-1,-1i,-1],
  • the ninth sequence is [1, 1i, 1, -1],
  • the tenth sequence is [1, 1i, -1, 1],
  • the eleventh sequence is [1,-1i,1,1],
  • the twelfth sequence is [1,-1i,-1,-1],
  • the thirteenth sequence is [1, 1i, 1i, 1i],
  • the fourteenth sequence is [1, 1i, -1i, -1i],
  • the fifteenth sequence is [1,-1i,1i,-1i],
  • the sixteenth sequence is [1,-1i,-1i,1i];
  • the sequence set 5 includes 16 sequences of length 4, wherein
  • the first sequence is [1,1,1,1],
  • the second sequence is [1, 1i, -1, -1i],
  • the third sequence is [1,-1,1,-1],
  • the fourth sequence is [1,-1i,-1,1i],
  • the fifth sequence is [1,1,1i,-1i],
  • the sixth sequence is [1, 1i, -1i, -1],
  • the seventh sequence is [1,-1,1i,1i],
  • the eighth sequence is [1,-1i,-1i,1],
  • the ninth sequence is [1, 1i, 1, -1i],
  • the tenth sequence is [1,-1,-1,-1],
  • the eleventh sequence is [1,-1i,1,1i],
  • the thirteenth sequence is [1, 1i, 1i, -1],
  • the fourteenth sequence is [1,-1,-1i,1i],
  • the fifteenth sequence is [1,-1i,1i,1],
  • the sixteenth sequence is [1,1,-1i,-1i];
  • the seventeenth sequence is [1,1,1,-1],
  • the eighteenth sequence is [1, 1i, -1, 1i],
  • the nineteenth sequence is [1,-1,1,1],
  • the twentieth sequence is [1,-1i,-1,-1i],
  • the twenty-first sequence is [1,1,1i,1i],
  • the twenty-second sequence is [1, 1i, -1i, 1],
  • the twenty-third sequence is [1,-1,1i,-1i],
  • the twenty-fourth sequence is [1,-1i,-1i,-1],
  • the twenty-fifth sequence is [1,1i,1,1i],
  • the twenty-sixth sequence is [1,-1,-1,1],
  • the twenty-seventh sequence is [1,-1i,1,-1i],
  • the twenty-eighth sequence is [1,1,-1,-1],
  • the twenty-ninth sequence is [1, 1i, 1i, 1],
  • the thirtieth sequence is [1,-1,-1i,-1i],
  • the thirty-first sequence is [1,-1i,1i,-1],
  • the thirty-second sequence is [1,1,-1i,1i];
  • the sequence set 6 includes 32 sequences of length 4, wherein
  • the first sequence is [1,1,1,1i],
  • the second sequence is [1, 1i, -1, 1],
  • the third sequence is [1,-1,1,-1i],
  • the fourth sequence is [1,-1i,-1,-1],
  • the fifth sequence is [1,1,1i,1],
  • the sixth sequence is [1, 1i, -1i, -1i],
  • the seventh sequence is [1,-1,1i,-1],
  • the eighth sequence is [1,-1i,-1i,1i],
  • the ninth sequence is [1, 1i, 1, 1],
  • the tenth sequence is [1,-1,-1,-1i],
  • the eleventh sequence is [1,-1i,1,-1],
  • the thirteenth sequence is [1, 1i, 1i, -1i],
  • the fourteenth sequence is [1,-1,-1i,-1],
  • the fifteenth sequence is [1,-1i,1i,i],
  • the seventeenth sequence is [1,1,1,-1i],
  • the eighteenth sequence is [1,1i,-1,-1],
  • the nineteenth sequence is [1,-1,1,1i],
  • the twentieth sequence is [1,-1i,-1,1],
  • the twenty-first sequence is [1,1,1i,-1],
  • the twenty-second sequence is [1, 1i, -1i, 1i],
  • the twenty-third sequence is [1,-1,1i,1],
  • the twenty-fourth sequence is [1,-1i,-1i,-1i],
  • the twenty-fifth sequence is [1, 1i, 1, -1],
  • the twenty-sixth sequence is [1,-1,-1,1i],
  • the twenty-seventh sequence is [1,-1i,1,1],
  • the twenty-eighth sequence is [1,1,-1,-1i],
  • the twenty-ninth sequence is [1, 1i, 1i, 1i],
  • the thirtieth sequence is [1,-1,-1i,1],
  • the thirty-first sequence is [1,-1i,1i,-1i],
  • the thirty-second sequence is [1, 1, -1i, -1];
  • the sequence set 7 includes four sequences of length 4, wherein
  • the first sequence is [1,0,0,0],
  • the second sequence is [0,1,0,0],
  • the third sequence is [0,0,1,0],
  • the fourth sequence is [0,0,0,1];
  • the sequence set 8 includes 16 sequences of length 6, wherein
  • the first sequence is [1,0,1,0,1,0],
  • the second sequence is [-1,0,1,0,-1,0],
  • the third sequence is [1,0,-1,0,-1,0],
  • the fourth sequence is [-1,0,-1,0,1,0],
  • the fifth sequence is [1,0,0,1,0,1],
  • the sixth sequence is [-1,0,0,1,0,-1],
  • the seventh sequence is [1,0,0,-1,0,-1],
  • the eighth sequence is [-1,0,0,-1,0,1],
  • the ninth sequence is [0, 1, 1, 0, 0, 1],
  • the tenth sequence is [0, -1, 1, 0, 0, -1],
  • the eleventh sequence is [0, 1, -1, 0, 0, -1],
  • the twelfth sequence is [0,-1,-1,0,0,1],
  • the thirteenth sequence is [0,1,0,1,1,0],
  • the fourteenth sequence is [0, -1, 0, 1, -1, 0],
  • the fifteenth sequence is [0,1,0,-1,-1,0],
  • the sixteenth sequence is [0, -1, 0, -1, 1, 0];
  • the sequence set 9 includes 16 sequences of length 6, wherein
  • the first sequence is [1,1,1,0,0,0]
  • the second sequence is [-1,1,-1,0,0,0],
  • the third sequence is [1,-1,-1,0,0,0],
  • the fourth sequence is [-1,-1,1,0,0,0],
  • the fifth sequence is [0,0,1,1,1,0],
  • the sixth sequence is [0,0,-1,-1,1,0],
  • the seventh sequence is [0,0,-1,1,-1,0],
  • the eighth sequence is [0,0,1,-1,-1,0],
  • the ninth sequence is [1,0,0,0,1,1],
  • the tenth sequence is [-1,0,0,0,1,-1],
  • the eleventh sequence is [1,0,0,0,-1,-1],
  • the twelfth sequence is [-1,0,0,0,-1,1],
  • the thirteenth sequence is [0, 1, 0, 1, 0, 1],
  • the fourteenth sequence is [0,1,0,-1,0,-1],
  • the fifteenth sequence is [0, -1, 0, 1, 0, -1],
  • the sixteenth sequence is [0, -1, 0, -1, 0, 1];
  • the sequence set 10 includes 16 sequences of length 6, wherein
  • the first sequence is [1,1,1,1,1],
  • the second sequence is [1,1,1,1,-1,-1],
  • the third sequence is [1,1,1,-1,1,-1],
  • the fourth sequence is [1,1,1,-1,-1,1],
  • the fifth sequence is [1,1,-1,1,1,-1],
  • the sixth sequence is [1,1,-1,1,-1,1],
  • the seventh sequence is [1,1,-1,-1,1,1],
  • the eighth sequence is [1,1,-1,-1,-1,-1],
  • the ninth sequence is [1,-1,1,1,1,-1],
  • the tenth sequence is [1,-1,1,1,-1,1],
  • the eleventh sequence is [1,-1,1,-1,1,1],
  • the twelfth sequence is [1,-1,1,-1,-1,-1],
  • the thirteenth sequence is [1,-1,-1,1,1,1],
  • the fourteenth sequence is [1,-1,-1,1,-1,-1],
  • the fifteenth sequence is [1,-1,-1,-1,1,-1],
  • the sixteenth sequence is [1,-1,-1,-1,-1,1];
  • the sequence set 11 includes 32 sequences of length 4, wherein
  • the first sequence is [1+0i, 1+0i, 1+0i, 1+0i],
  • the second sequence is [1+0i, 0+1i, -1+0i, -0-1i],
  • the third sequence is [1+0i, -1+0i, 1+0i, -1+0i],
  • the fourth sequence is [1+0i, -0-1i, -1+0i, 0+1i],
  • the fifth sequence is [0+2i, -0-1i, 0+2i, 0+1i],
  • the sixth sequence is [0+2i, 1+0i, -0-2i, 1+0i],
  • the seventh sequence is [0+2i, 0+1i, 0+2i, -0-1i],
  • the eighth sequence is [0+2i, -1+0i, -0-2i, -1+0i],
  • the ninth sequence is [0+2i, -0-1i, -1+0i, 2+0i],
  • the tenth sequence is [0+2i, 1+0i, 1+0i-0-2i],
  • the eleventh sequence is [0+2i, 0+1i, -1+0i, -2+0i],
  • the twelfth sequence is [0+2i, -1+0i, 1+0i, 0+2i],
  • the thirteenth sequence is [0+2i, -0-1i, 0+0i, -1+0i],
  • the fourteenth sequence is [0+2i, 1+0i, 0+0i, 0+1i],
  • the fifteenth sequence is [0+2i, 0+1i, 0+0i, 1+0i],
  • the sixteenth sequence is [0+2i, -1+0i, 0+0i, -0-1i],
  • the seventeenth sequence is [-1+0i, -0-1i, -0-2i, -2+0i],
  • the eighteenth sequence is [-1+0i, 1+0i, 0+2i, 0+2i],
  • the nineteenth sequence is [-1+0i, 0+1i, -0-2i, 2+0i],
  • the twentieth sequence is [-1+0i, -1+0i, 0+2i, -0-2i],
  • the twenty-first sequence is [-1+0i, -2+0i, 0+2i, 0+1i],
  • the twenty-second sequence is [-1+0i,-0-2i,-0-2i, 1+0i],
  • the twenty-third sequence is [-1+0i, 2+0i, 0+2i, -0-1i],
  • the twenty-fourth sequence is [-1+0i, 0+2i, -0-2i, -1+0i],
  • the twenty-fifth sequence is [-1+0i, -2+0i, 1+0i, -2+0i],
  • the twenty-sixth sequence is [-1+0i, -0-2i, -1+0i, 0+2i],
  • the twenty-seventh sequence is [-1+0i, 2+0i, 1+0i, 2+0i],
  • the twenty-eighth sequence is [-1+0i, 0+2i, -1+0i, -0-2i],
  • the twenty-ninth sequence is [-1+0i, -2+0i, -0-1i, 0+0i],
  • the thirtieth sequence is [-1+0i,-0-2i, 0+1i, 0+0i],
  • the thirty-first sequence is [-1+0i, 2+0i, -0-1i, 0+0i],
  • the thirty-second sequence is [-1+0i, 0+2i, 0+1i, 0+0i];
  • sequence in the process is a collection obtained by any of the following processes:
  • S is an integer greater than or equal to 1 and less than or equal to W
  • Q is an integer
  • R is a real number
  • the determining unit determines the third sequence from a third sequence set, and the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set.
  • the determining unit is further configured to obtain a sequence set according to the first sequence set and the second sequence set by at least one of:
  • the determining unit determines the third sequence according to the first sequence and the second sequence, or
  • the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set
  • the determining unit is further configured to obtain the first sequence from the first sequence set by one of:
  • the determining unit determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set And including a second specified sequence set, a sequence set obtained by processing the second specified sequence set, and at least one of the sequence set obtained according to the first sequence set and the second sequence set,
  • the determining unit is further configured to obtain the second sequence from the second sequence set by one of:
  • the determining unit determines the third sequence according to the first sequence and the second sequence, the determining unit is further configured to:
  • the determining unit determines the third sequence from the third sequence set, the determining unit is further configured to:
  • the apparatus further includes a normalization processing unit, where
  • the normalization processing unit is configured to:
  • the normalization processing unit configured as:
  • the third sequence is subjected to energy adjustment or energy normalization.
  • the determining unit is further configured to:
  • V is an integer greater than or equal to 1 and less than or equal to the length of the third sequence
  • G is an integer
  • H is a real number
  • the generating unit is further configured to:
  • the first data is modulated using the third sequence to generate second data.
  • the device further includes:
  • mapping unit configured to map the second data onto a designated transmission resource for forming a transmit signal and transmitting.
  • the first data includes at least identifier information of a transmitter or a terminal; or
  • At least the identity information and the cell identification information of the transmitter or the terminal are included; or
  • At least the identity information, cell identification information, data information and signaling information of the transmitter or the terminal are included.
  • the second data includes at least the identity information of the transmitter or the terminal;
  • the identity information, signaling information, and data information of the transmitter or the terminal Or at least the identity information, signaling information, and data information of the transmitter or the terminal; or,
  • At least the identity information and the cell identification information of the transmitter or the terminal are included; or
  • At least the identity information, the cell identification information and the signaling information of the transmitter or the terminal are included; or,
  • At least the identity information, cell identification information, data information and signaling information of the transmitter or the terminal are included.
  • the specified transmission resource includes at least one of the following: a carrier, a time slot, a time-frequency resource, an airspace resource, a code domain resource, a frequency hopping mode, and an antenna port.
  • the time-frequency resource is an uplink data channel, or an uplink control channel, or a random access channel.
  • the first data includes at least one of the following: vehicle condition information, driver operation information, information sensed by the vehicle sensor, and control signaling; wherein the vehicle condition information includes the following: At least one of: a vehicle tool identification, a current geographic location of the vehicle, a traveling speed of the vehicle, a size of the vehicle, a color of the vehicle; the operational information comprising at least one of: the driver's office The ongoing operation of the vehicle, the driver preparing an operation on the vehicle.
  • vehicle condition information includes the following: At least one of: a vehicle tool identification, a current geographic location of the vehicle, a traveling speed of the vehicle, a size of the vehicle, a color of the vehicle
  • the operational information comprising at least one of: the driver's office The ongoing operation of the vehicle, the driver preparing an operation on the vehicle.
  • an embodiment of the present invention further provides an apparatus, where the apparatus includes a processor and a memory storing the processor executable instructions, and when the instructions are executed by the processor, performing the following operations:
  • the first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set;
  • the second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set;
  • the third sequence set includes at least one of: a third specified sequence set including P sequences of length W; the second specified sequence set; and a sequence obtained by processing the second specified sequence set a set of sequences obtained from the first set of sequences and the second set of sequences;
  • M, L, N, C, P, and W are positive integers.
  • the determining, by the processor, the value of the sequence element in the first specified sequence set when determining the third sequence according to the first sequence and the second sequence, or from the third sequence set Determining the value of the sequence element in the third specified sequence set when determining the third sequence is from at least one of the following sets:
  • ⁇ 1,1i,-1,-1i ⁇ ; ⁇ 1,-1 ⁇ ; ⁇ 1i,-1i ⁇ ; ⁇ 1 ⁇ ; ⁇ -1 ⁇ ; ⁇ 1i ⁇ ; ⁇ -1i ⁇ ; ⁇ 1+1i,- 1+1i, -1-1i, 1-1i ⁇ ; ⁇ 0 ⁇ ; ⁇ 1, 1i, -1, -1i, 0 ⁇ ; ⁇ 1+1i, -1+1i, -1-1i, 1-1i , 0 ⁇ ; ⁇ 1, 1i, -1, -1i, 2, 2i, -2, -2i, 0 ⁇ ; where i is an imaginary unit and i sqrt(-1).
  • the processor determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set
  • the processor determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set
  • the processor determines the third sequence from the third sequence set, and the third sequence set does not include the sequence set obtained according to the first sequence set and the second sequence set, the processor is further configured to:
  • the third sequence is subjected to energy adjustment or energy normalization.
  • the processor is further configured to multiply each element or the Vth element of the third sequence by 1, 1i, -1, or -1i, or multiply by 1i. Gth power; or,
  • V is an integer greater than or equal to 1 and less than or equal to the length of the third sequence
  • G is an integer
  • H is a real number
  • the processor is further configured to perform the expansion process on the first data to generate the second data by using the third sequence;
  • the first data is modulated using the third sequence to generate second data.
  • the processor is further configured to map the second data to a specified transmission resource, for forming a transmission signal and transmitting.
  • an embodiment of the present invention further provides a computer storage medium, where the computer storage medium stores computer executable instructions, and the computer executable instructions are used to execute the data generation method according to the embodiment of the present invention.
  • the third sequence is determined according to the first sequence and the second sequence, where the first sequence is obtained from the first sequence set, and the second sequence is obtained from the second sequence set; Or determining the third sequence from the third sequence set; processing the first data by using the third sequence to generate second data; wherein the first sequence set comprises M sequences of length L a first specified sequence set, and/or a sequence set obtained by processing the first specified sequence set; wherein the second sequence set comprises a second specified sequence set comprising N sequences of length C, and/ Or a sequence set obtained by processing the second specified sequence set; wherein the third sequence set includes at least one of: a third specified sequence set including a P-length W sequence; the second designation a sequence set; a sequence set obtained by processing the second specified sequence set; a sequence set obtained according to the first sequence set and the second sequence set; wherein, M, L , N, C, P, W are positive integers.
  • the data generation method proposed by the embodiment of the present invention can be used to implement scheduling-
  • FIG. 1 is a schematic flowchart diagram of a data generating method according to an embodiment of the present invention
  • FIG. 2 is a schematic diagram of an application of a data generating method according to an embodiment of the present invention.
  • FIG. 3 is a schematic diagram of a sequence element set according to an embodiment of the present invention.
  • FIG. 4 is a schematic diagram of another application of a data generating method according to an embodiment of the present invention.
  • FIG. 5 is another schematic diagram of a sequence element set according to an embodiment of the present invention.
  • FIG. 6 is still another schematic diagram of a sequence element set according to an embodiment of the present invention.
  • FIG. 7 is a schematic flowchart diagram of another data generating method according to an embodiment of the present invention.
  • FIG. 8 is a schematic flowchart diagram of a data transmission method according to an embodiment of the present invention.
  • FIG. 9 is a schematic structural diagram of a data generating apparatus according to an embodiment of the present invention.
  • FIG. 10 is a schematic structural diagram of hardware components of a data generating apparatus according to an embodiment of the present invention.
  • the embodiment of the present invention provides a data generating method, which is applied to a terminal side or a base station side. As shown in FIG. 1 , the data generating method includes the following steps:
  • Step 101 Determine a third sequence according to the first sequence and the second sequence, where the first sequence is obtained from a first sequence set, and the second sequence is obtained from a second sequence set; or The third sequence is determined from a third set of sequences.
  • the first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set;
  • the second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set;
  • the third sequence set includes at least one of: a third specified sequence set including P sequences of length W; the second specified sequence set; and a sequence obtained by processing the second specified sequence set a set of sequences obtained from the first set of sequences and the second set of sequences;
  • M, L, N, C, P, and W are positive integers.
  • the third sequence has at least two determination manners, one is to determine a third sequence according to the first sequence and the second sequence, wherein the first sequence is from the first sequence set, and the second sequence is from the first sequence The second sequence set; the other is to determine the third sequence from the third sequence set.
  • processing the sequence in the first specified sequence set includes:
  • X is an integer greater than or equal to 1 and less than or equal to L, A is an integer, and B is a real number;
  • X may be a plurality of values greater than or equal to 1 and less than or equal to L.
  • the second specified sequence set includes at least one of the following:
  • DFT Discrete Fourier Transform
  • processing the sequence in the second specified sequence set includes:
  • Y is an integer greater than or equal to 1 and less than or equal to C, E is an integer, and F is a real number;

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Abstract

Disclosed in the embodiments of the present invention are a method and an apparatus for generating data, a device, and a computer storage medium. The method comprises: determining a third sequence according to a first sequence and a second sequence, the first sequence being acquired from a first sequence set, the second sequence being acquired from a second sequence set; or determining the third sequence from a third sequence set; and using the third sequence to process first data to generate second data.

Description

一种数据生成方法及装置、设备、计算机存储介质Data generation method and device, device and computer storage medium
相关申请的交叉引用Cross-reference to related applications
本申请基于申请号为201611170042.5、申请日为2016年12月16日的中国专利申请提出,并要求该中国专利申请的优先权,该中国专利申请的全部内容在此引入本申请作为参考。The present application is based on a Chinese patent application filed on Jan. 16, 2016, the entire disclosure of which is hereby incorporated by reference.
技术领域Technical field
本发明涉及无线通信技术领域,尤其涉及一种数据生成方法及装置、设备、计算机存储介质。The present invention relates to the field of wireless communication technologies, and in particular, to a data generation method and apparatus, a device, and a computer storage medium.
背景技术Background technique
第五代(5th-Generation,5G)通信技术的应用场景包括增强移动宽带(enhanced Mobile Broadband,eMBB)、海量机器类型通信(massive Machine Type communication,mMTC)、高可靠低时延通信(Ultra Reliability Low Latency Communication,URLLC)。其中,eMBB场景用于支持移动宽带,主要业务需求是大数据包传输、高数据速率、高频谱效率;mMTC场景用于支持海量设备通信,主要业务需求是海量设备、小数据包传输。目前,国际电信联盟(International Telecommunications Union,ITU)和第三代合作伙伴计划(3rd Generation Partnership Project,3GPP)确定的设计目标是支持100万个设备/平方公里的连接密度;URLLC场景用于支持高可靠低时延通信,主要业务需求是高可靠、低时延传输。The application scenarios of the 5th-generation (5G) communication technology include enhanced mobile broadband (eMBB), massive machine type communication (mMTC), and high reliability low latency communication (Ultra Reliability Low). Latency Communication, URLLC). The eMBB scenario is used to support mobile broadband. The main service requirements are large data packet transmission, high data rate, and high spectrum efficiency. The mMTC scenario is used to support mass device communication. The main service requirements are mass equipment and small data packet transmission. Currently, the International Telecommunications Union (ITU) and the 3rd Generation Partnership Project (3GPP) have determined the design goal of supporting a connection density of 1 million devices per square kilometer; the URLLC scenario is used to support high Reliable low-latency communication, the main business demand is high reliability, low latency transmission.
对于5G通信技术mMTC场景海量设备、小数据包传输的需求,以及URLLC场景高可靠、低时延传输的需求,传统的基于终端随机接入、基站调度控制等通信流程设计已无法满足,主要原因是系统接入设备容量有限、接入与数据传输过程耗时长、信令开销大等。 For the demand of massive equipment and small data packet transmission in the 5G communication technology mMTC scenario, and the high reliability and low latency transmission of the URLLC scenario, the traditional communication process design based on terminal random access and base station scheduling control cannot be satisfied. The system access device has limited capacity, the access and data transmission process takes a long time, and the signaling overhead is large.
为了满足这些5G通信技术需求,可以考虑采用基于免调度的传输方法,当终端设备需要发送数据时,即可进行数据发送,省去漫长复杂的随机接入过程和调度控制过程,从而可以大大降低传输时延和信令开销。In order to meet the requirements of these 5G communication technologies, a scheduling-based transmission method can be considered. When the terminal device needs to transmit data, data transmission can be performed, thereby eliminating a long and complicated random access process and scheduling control process, thereby greatly reducing Transmission delay and signaling overhead.
对于URLLC场景中的周期类业务,传统的基于半静态周期资源调度/预留(例如,Semi-Persistent Scheduling,SPS)的正交接入方式可以认为是一种高效的免动态调度、低时延接入方式。与业务发生周期匹配的周期资源调度/预留可以保证高效的资源利用率,并且,各用户独占资源,没有用户间干扰,性能也可以得到保证。For periodic services in a URLLC scenario, the traditional orthogonal access method based on semi-persistent periodic resource scheduling/reservation (for example, Semi-Persistent Scheduling, SPS) can be considered as an efficient dynamic scheduling-free, low-latency delay. Access method. Periodic resource scheduling/reservation matching the service occurrence period can ensure efficient resource utilization, and each user monopolizes resources without inter-user interference, and performance can be guaranteed.
而对于URLLC场景中的事件触发类业务,传统的周期调度/预留的正交资源往往得不到充分利用。如果正交资源的调度/预留周期越长,资源利用率越高,但终端接入需要等待的平均时间越长,越难保证超低时延需求;如果正交资源的调度/预留周期越短,终端接入需要等待的平均时间越短,越容易保证超低时延需求,但资源的空置率就会越高,利用率也就越低。For the event-triggered service in the URLLC scenario, the traditional periodic scheduling/reserved orthogonal resources are often not fully utilized. If the scheduling/reservation period of orthogonal resources is longer, the resource utilization ratio is higher, but the longer the average time that terminal access needs to wait, the more difficult it is to ensure ultra-low latency demand; if the orthogonal resource scheduling/reservation period The shorter the average time that terminal access needs to wait, the easier it is to ensure ultra-low latency requirements, but the higher the vacancy rate of resources and the lower the utilization rate.
为了提高周期调度/预留资源的利用率,一种方法是多个事件触发类业务用户共享使用同样的传输资源(例如时频资源块),这样可以降低资源的空置率,但是会出现多个用户同时在该传输资源上进行接入和传输的情况,即发生碰撞,这会严重影响URLLC业务传输的可靠性。In order to improve the utilization of periodic scheduling/reserved resources, one method is that multiple event-triggered service users share the same transmission resource (for example, a time-frequency resource block), which can reduce the vacancy rate of resources, but multiple multiple occurrences occur. When a user simultaneously accesses and transmits on the transmission resource, a collision occurs, which seriously affects the reliability of the URLLC service transmission.
发明内容Summary of the invention
为解决上述技术问题,本发明实施例提供了一种数据生成方法及装置、设备、计算机存储介质,能够用于实现免调度传输,并且,具有较低的序列存储需求和运算复杂度。To solve the above technical problem, an embodiment of the present invention provides a data generation method and apparatus, a device, and a computer storage medium, which can be used to implement scheduling-free transmission, and have lower sequence storage requirements and computational complexity.
为达到上述目的,本发明实施例的技术方案是这样实现的:To achieve the above objective, the technical solution of the embodiment of the present invention is implemented as follows:
一方面,本发明实施例提供了一种数据生成方法,包括:In one aspect, an embodiment of the present invention provides a data generating method, including:
根据第一序列和第二序列确定第三序列,其中,所述第一序列从第一序列集合中获取,所述第二序列从第二序列集合中获取;或者,从第三序 列集合中确定所述第三序列;Determining a third sequence according to the first sequence and the second sequence, wherein the first sequence is obtained from a first sequence set, the second sequence is obtained from a second sequence set; or, from a third sequence Determining the third sequence in the set of columns;
使用所述第三序列对第一数据进行处理生成第二数据;Processing the first data by using the third sequence to generate second data;
其中,所述第一序列集合包括包含M条长度为L的序列的第一指定序列集合、和/或对所述第一指定序列集合进行处理得到的序列集合;The first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set;
其中,所述第二序列集合包括包含N条长度为C的序列的第二指定序列集合、和/或对所述第二指定序列集合进行处理得到的序列集合;The second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set;
其中,所述第三序列集合包括以下至少之一:包含P条长度为W的序列的第三指定序列集合;所述第二指定序列集合;对所述第二指定序列集合进行处理得到的序列集合;根据所述第一序列集合和所述第二序列集合得到的序列集合;The third sequence set includes at least one of: a third specified sequence set including P sequences of length W; the second specified sequence set; and a sequence obtained by processing the second specified sequence set a set of sequences obtained from the first set of sequences and the second set of sequences;
其中,M、L、N、C、P、W为正整数。Among them, M, L, N, C, P, and W are positive integers.
本发明实施例中,可选地,根据第一序列和第二序列确定第三序列时所述第一指定序列集合中的序列元素的取值,或者In the embodiment of the present invention, optionally, determining a value of a sequence element in the first specified sequence set when determining the third sequence according to the first sequence and the second sequence, or
从第三序列集合中确定所述第三序列时所述第三指定序列集合中的序列元素的取值,Determining the value of the sequence element in the third specified sequence set when the third sequence is determined from the third sequence set,
均来自于以下集合至少之一:Both come from at least one of the following collections:
{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,-1+1i,-1-1i,1-1i};{0};{1,1i,-1,-1i,0};{1+1i,-1+1i,-1-1i,1-1i,0};{1,1i,-1,-1i,2,2i,-2,-2i,0};其中,i为虚数单位,i=sqrt(-1)。{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,- 1+1i, -1-1i, 1-1i}; {0}; {1, 1i, -1, -1i, 0}; {1+1i, -1+1i, -1-1i, 1-1i , 0}; {1, 1i, -1, -1i, 2, 2i, -2, -2i, 0}; where i is an imaginary unit and i = sqrt(-1).
本发明实施例中,可选地,根据第一序列和第二序列确定第三序列时,或者In the embodiment of the present invention, optionally, when the third sequence is determined according to the first sequence and the second sequence, or
从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,Determining the third sequence from a third sequence set, and the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set,
所述第一指定序列集合,包括下述序列集合至少之一:The first specified sequence set includes at least one of the following sequence sets:
序列集合1:Sequence set 1:
所述序列集合1,包含4条长度为4的序列,其中, The sequence set 1 includes four sequences of length 4, wherein
第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
第二序列为[1,1,1i,-1i],The second sequence is [1,1,1i,-1i],
第三序列为[1,1i,1,-1i],The third sequence is [1, 1i, 1, -1i],
第四序列为[1,1i,1i,-1];The fourth sequence is [1, 1i, 1i, -1];
序列集合2:Sequence collection 2:
所述序列集合2,包含4条长度为4的序列,其中,The sequence set 2 includes four sequences of length 4, wherein
第一序列为[1,1,1,-1],The first sequence is [1,1,1,-1],
第二序列为[1,1,1i,1i],The second sequence is [1,1,1i,1i],
第三序列为[1,1i,1,1i],The third sequence is [1, 1i, 1, 1i],
第四序列为[1,1i,1i,1];The fourth sequence is [1, 1i, 1i, 1];
序列集合3:Sequence Collection 3:
所述序列集合2,包含4条长度为4的序列,其中,The sequence set 2 includes four sequences of length 4, wherein
第一序列为[1,1,1,1i],The first sequence is [1,1,1,1i],
第二序列为[1,1,1i,1],The second sequence is [1,1,1i,1],
第三序列为[1,1i,1,1],The third sequence is [1, 1i, 1, 1],
第四序列为[1,1i,1i,-1i];The fourth sequence is [1, 1i, 1i, -1i];
序列集合4:Sequence Collection 4:
所述序列集合4,包含4条长度为4的序列,其中,The sequence set 4 includes four sequences of length 4, wherein
第一序列为[1,1,1,-1i],The first sequence is [1,1,1,-1i],
第二序列为[1,1,1i,-1],The second sequence is [1,1,1i,-1],
第三序列为[1,1i,1,-1],The third sequence is [1, 1i, 1, -1],
第四序列为[1,1i,1i,1i];The fourth sequence is [1, 1i, 1i, 1i];
序列集合5:Sequence Collection 5:
所述序列集合5,包含1条长度为2的序列,其中,The sequence set 5 includes a sequence of length 2, wherein
第一序列为[1,1];The first sequence is [1,1];
序列集合6: Sequence set 6:
所述序列集合6,包含1条长度为2的序列,其中,The sequence set 6 includes a sequence of length 2, wherein
第一序列为[1,-1];The first sequence is [1,-1];
序列集合7:Sequence collection 7:
所述序列集合7,包含1条长度为2的序列,其中,The sequence set 7 includes a sequence of length 2, wherein
第一序列为[1,1i];The first sequence is [1, 1i];
序列集合8:Sequence set 8:
所述序列集合8,包含1条长度为2的序列,其中,The sequence set 8 includes a sequence of length 2, wherein
第一序列为[1,-1i];The first sequence is [1,-1i];
序列集合9:Sequence set 9:
所述序列集合9,包含4条长度为1的序列,其中,The sequence set 9 includes four sequences of length 1, wherein
第一序列为[1],The first sequence is [1],
第二序列为[1i],The second sequence is [1i],
第三序列为[-1],The third sequence is [-1],
第四序列为[-1i];The fourth sequence is [-1i];
序列集合10:Sequence collection 10:
所述序列集合10,包含4条长度为1的序列,其中,The sequence set 10 includes four sequences of length 1, wherein
第一序列为[1+1i],The first sequence is [1+1i],
第二序列为[-1+1i],The second sequence is [-1+1i],
第三序列为[-1-1i],The third sequence is [-1-1i],
第四序列为[1-1i];The fourth sequence is [1-1i];
序列集合11:Sequence collection 11:
所述序列集合11,包含2条长度为1的序列,其中,The sequence set 11 includes two sequences of length 1, wherein
第一序列为[1],The first sequence is [1],
第二序列为[-1];The second sequence is [-1];
序列集合12:Sequence set 12:
所述序列集合12,包含2条长度为1的序列,其中, The sequence set 12 includes two sequences of length 1, wherein
第一序列为[1i],The first sequence is [1i],
第二序列为[-1i];The second sequence is [-1i];
序列集合13:Sequence Set 13:
所述序列集合13,包含1条长度为1的序列,其中,The sequence set 13 includes a sequence of length 1, wherein
第一序列为[1];The first sequence is [1];
序列集合14:Sequence Set 14:
所述序列集合14,包含1条长度为1的序列,其中,The sequence set 14 includes a sequence of length 1, wherein
第一序列为[-1];The first sequence is [-1];
序列集合15:Sequence set 15:
所述序列集合15,包含1条长度为1的序列,其中,The sequence set 15 includes a sequence of length 1, wherein
第一序列为[1i];The first sequence is [1i];
序列集合16:Sequence set 16:
所述序列集合16,包含1条长度为1的序列,其中,The sequence set 16 includes a sequence of length 1, wherein
第一序列为[-1i];The first sequence is [-1i];
序列集合17:Sequence set 17:
所述序列集合17,包含4条长度为3的序列,其中,The sequence set 17 includes four sequences of length 3, wherein
第一序列为[1,1,1];The first sequence is [1,1,1];
第二序列为[1,-1,-1],The second sequence is [1,-1,-1],
第三序列为[-1,1,-1],The third sequence is [-1, 1, -1],
第四序列为[-1,1,1];The fourth sequence is [-1, 1, 1];
其中,i为虚数单位,i=sqrt(-1)。Where i is an imaginary unit and i=sqrt(-1).
本发明实施例中,可选地,根据第一序列和第二序列确定第三序列时,或者In the embodiment of the present invention, optionally, when the third sequence is determined according to the first sequence and the second sequence, or
从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,Determining the third sequence from a third sequence set, and the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set,
所述对所述第一指定序列集合中的序列进行处理,包括: The processing of the sequence in the first specified sequence set includes:
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素乘以1、1i、-1、或-1i,或者乘以1i的A次方;或者,Multiplying the Xth sequence element of each sequence or each sequence in the first specified sequence set by 1, 1i, -1, or -1i, or multiplying by the 1st power of A; or
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素进行B*π的相位调整或旋转,或者乘以exp(j*B*π),j为虚数单位,j=sqrt(-1);或者,Performing B*π phase adjustment or rotation for each sequence in the first specified sequence set or the Xth sequence element of each sequence, or multiplying exp(j*B*π), j is an imaginary unit, j=sqrt(-1); or,
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素乘以指定值,或者分别乘以指定值;Multiplying the Xth sequence element of each sequence or each sequence in the first specified sequence set by a specified value, or multiplying by a specified value;
其中,X为大于或等于1且小于或等于L的整数,A为整数,B为实数。Where X is an integer greater than or equal to 1 and less than or equal to L, A is an integer, and B is a real number.
本发明实施例中,可选地,根据第一序列和第二序列确定第三序列时,或者In the embodiment of the present invention, optionally, when the third sequence is determined according to the first sequence and the second sequence, or
从第三序列集合中确定所述第三序列,且所述第三序列集合包括第二指定序列集合、对所述第二指定序列集合进行处理得到的序列集合、根据第一序列集合和第二序列集合得到的序列集合至少之一时,Determining the third sequence from a third sequence set, and the third sequence set includes a second specified sequence set, a sequence set obtained by processing the second specified sequence set, according to the first sequence set and the second sequence set When at least one of the sequence sets obtained by the sequence set,
所述第二指定序列集合包括以下至少之一:The second specified sequence set includes at least one of the following:
哈达玛序列集合;Hadamard sequence collection;
沃尔什序列集合;Walsh sequence collection;
离散傅里叶变换序列集合;a set of discrete Fourier transform sequences;
包含指定数量或指定比例的0元素的序列的集合;a collection of sequences containing a specified number or a specified proportion of 0 elements;
单位矩阵序列集合。A collection of unit matrix sequences.
本发明实施例中,可选地,根据第一序列和第二序列确定第三序列时,或者In the embodiment of the present invention, optionally, when the third sequence is determined according to the first sequence and the second sequence, or
从第三序列集合中确定所述第三序列,且所述第三序列集合包括第二指定序列集合、对第二指定序列集合进行处理得到的序列集合、根据第一序列集合和第二序列集合得到的序列集合至少之一时,Determining the third sequence from the third sequence set, and the third sequence set includes a second specified sequence set, a sequence set obtained by processing the second specified sequence set, according to the first sequence set and the second sequence set When at least one of the resulting sequence sets is obtained,
所述第二指定序列集合,包括下述序列集合至少之一;其中, The second specified sequence set includes at least one of the following sequence sets; wherein
序列集合1:Sequence set 1:
所述序列集合1,包含4条长度为4的序列,其中,The sequence set 1 includes four sequences of length 4, wherein
第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
第二序列为[1,1,-1,-1],The second sequence is [1,1,-1,-1],
第三序列为[1,-1,1,-1],The third sequence is [1,-1,1,-1],
第四序列为[1,-1,-1,1];The fourth sequence is [1, -1, -1, 1];
序列集合2:Sequence collection 2:
所述序列集合2,包含4条长度为4的序列,其中,The sequence set 2 includes four sequences of length 4, wherein
第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
第二序列为[1,1i,-1,-1i],The second sequence is [1, 1i, -1, -1i],
第三序列为[1,-1,1,-1],The third sequence is [1,-1,1,-1],
第四序列为[1,-1i,-1,1i];The fourth sequence is [1,-1i,-1,1i];
序列集合3:Sequence Collection 3:
所述序列集合3,包含2条长度为2的序列,其中,The sequence set 3 includes two sequences of length 2, wherein
第一序列为[1,1],The first sequence is [1,1],
第二序列为[1,-1];The second sequence is [1,-1];
序列集合4:Sequence Collection 4:
所述序列集合4,包含1条长度为1的序列,其中,The sequence set 4 includes a sequence of length 1, wherein
第一序列为[1];The first sequence is [1];
序列集合5:Sequence Collection 5:
所述序列集合5,包含6条长度为4的序列,其中,The sequence set 5 includes six sequences of length 4, wherein
第一序列为[1,1,0,0],The first sequence is [1,1,0,0],
第二序列为[1,0,1,0],The second sequence is [1,0,1,0],
第三序列为[1,0,0,1],The third sequence is [1,0,0,1],
第四序列为[0,1,1,0],The fourth sequence is [0, 1, 1, 0],
第五序列为[0,1,0,1], The fifth sequence is [0, 1, 0, 1],
第六序列为[0,0,1,1];The sixth sequence is [0,0,1,1];
序列集合6:Sequence set 6:
所述序列集合6,包含4条长度为6的序列,其中,The sequence set 6 includes four sequences of length 6, wherein
第一序列为[1,1,1,0,0,0],The first sequence is [1,1,1,0,0,0],
第二序列为[1,0,0,1,1,0],The second sequence is [1,0,0,1,1,0],
第三序列为[0,1,0,0,1,1],The third sequence is [0, 1, 0, 0, 1, 1],
第四序列为[0,0,1,1,0,1],The fourth sequence is [0,0,1,1,0,1],
序列集合7:Sequence collection 7:
所述序列集合7,包含4条长度为6的序列,其中,The sequence set 7 includes four sequences of length 6, wherein
第一序列为[1,0,1,0,1,0],The first sequence is [1,0,1,0,1,0],
第二序列为[1,0,0,1,0,1],The second sequence is [1,0,0,1,0,1],
第三序列为[0,1,1,0,0,1],The third sequence is [0,1,1,0,0,1],
第四序列为[0,1,0,1,1,0],The fourth sequence is [0,1,0,1,1,0],
序列集合8:Sequence set 8:
所述序列集合8,包含4条长度为4的序列,其中,The sequence set 8 includes four sequences of length 4, wherein
第一序列为[1,0,0,0],The first sequence is [1,0,0,0],
第二序列为[0,1,0,0],The second sequence is [0,1,0,0],
第三序列为[0,0,1,0],The third sequence is [0,0,1,0],
第四序列为[0,0,0,1];The fourth sequence is [0,0,0,1];
序列集合9:Sequence set 9:
所述序列集合9,包含6条长度为6的序列,其中,The sequence set 9 includes six sequences of length 6, wherein
第一序列为[1,1,1,1,1,1],The first sequence is [1,1,1,1,1,1],
第二序列为[1,1,1i,-1,-1,-1i],The second sequence is [1,1,1i,-1,-1,-1i],
第三序列为[1,1i,-1i,1i,-1i,-1],The third sequence is [1, 1i, -1i, 1i, -1i, -1],
第四序列为[1,-1,1,-1i,-1,1i],The fourth sequence is [1,-1,1,-1i,-1,1i],
第五序列为[1,-1,-1,1,1i,-1i], The fifth sequence is [1,-1,-1,1,1i,-1i],
第六序列为[1,-1i,-1,-1,1,1i];The sixth sequence is [1,-1i,-1,-1,1,1i];
其中,i为虚数单位,i=sqrt(-1)。Where i is an imaginary unit and i=sqrt(-1).
本发明实施例中,可选地,根据第一序列和第二序列确定第三序列时,或者In the embodiment of the present invention, optionally, when the third sequence is determined according to the first sequence and the second sequence, or
从第三序列集合中确定所述第三序列,且所述第三序列集合包括第二指定序列集合、对第二指定序列集合进行处理得到的序列集合、根据第一序列集合和第二序列集合得到的序列集合至少之一时,Determining the third sequence from the third sequence set, and the third sequence set includes a second specified sequence set, a sequence set obtained by processing the second specified sequence set, according to the first sequence set and the second sequence set When at least one of the resulting sequence sets is obtained,
所述对所述第二指定序列集合中的序列进行处理,包括:The processing of the sequence in the second specified sequence set includes:
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素乘以1、1i、-1、或-1i,或者乘以1i的E次方;或者,Multiplying the Yth sequence element of each sequence or each sequence in the second specified sequence set by 1, 1i, -1, or -1i, or multiplying by 1i to the power of E; or
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素进行F*π的相位调整或旋转,或者,乘以exp(j*F*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of F*π for each sequence in the second specified sequence set or the Yth sequence element of each sequence, or multiply exp(j*F*π), j is an imaginary unit , j=sqrt(-1); or,
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素乘以指定值,或者分别乘以指定值;Multiplying each of the sequence of the second specified sequence set or the Yth sequence element of each sequence by a specified value, or multiplying by a specified value;
其中,Y为大于或等于1且小于或等于C的整数,E为整数,F为实数。Wherein Y is an integer greater than or equal to 1 and less than or equal to C, E is an integer, and F is a real number.
本发明实施例中,可选地,从第三序列集合中确定所述第三序列时,In the embodiment of the present invention, optionally, when determining the third sequence from the third sequence set,
所述第三指定序列集合包括下述序列集合至少之一:The third specified sequence set includes at least one of the following sequence sets:
序列集合1:Sequence set 1:
所述序列集合1,包含16条长度为4的序列,其中,The sequence set 1 comprises 16 sequences of length 4, wherein
第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
第二序列为[1,1,-1,-1],The second sequence is [1,1,-1,-1],
第三序列为[1,-1,1,-1],The third sequence is [1,-1,1,-1],
第四序列为[1,-1,-1,1],The fourth sequence is [1,-1,-1,1],
第五序列为[1,1,1i,-1i],The fifth sequence is [1,1,1i,-1i],
第六序列为[1,1,-1i,1i], The sixth sequence is [1,1,-1i,1i],
第七序列为[1,-1,1i,1i],The seventh sequence is [1,-1,1i,1i],
第八序列为[1,-1,-1i,-1i],The eighth sequence is [1,-1,-1i,-1i],
第九序列为[1,1i,1,-1i],The ninth sequence is [1, 1i, 1, -1i],
第十序列为[1,1i,-1,1i],The tenth sequence is [1, 1i, -1, 1i],
第十一序列为[1,-1i,1,1i],The eleventh sequence is [1,-1i,1,1i],
第十二序列为[1,-1i,-1,-1i],The twelfth sequence is [1,-1i,-1,-1i],
第十三序列为[1,1i,1i,-1],The thirteenth sequence is [1, 1i, 1i, -1],
第十四序列为[1,1i,-1i,1],The fourteenth sequence is [1, 1i, -1i, 1],
第十五序列为[1,-1i,1i,1],The fifteenth sequence is [1,-1i,1i,1],
第十六序列为[1,-1i,-1i,-1];The sixteenth sequence is [1,-1i,-1i,-1];
序列集合2:Sequence collection 2:
所述序列集合2,包含16条长度为4的序列,其中,The sequence set 2 includes 16 sequences of length 4, wherein
第一序列为[1,1,1,-1],The first sequence is [1,1,1,-1],
第二序列为[1,1,-1,1],The second sequence is [1,1,-1,1],
第三序列为[1,-1,1,1],The third sequence is [1,-1,1,1],
第四序列为[1,-1,-1,-1],The fourth sequence is [1,-1,-1,-1],
第五序列为[1,1,1i,1i],The fifth sequence is [1,1,1i,1i],
第六序列为[1,1,-1i,-1i],The sixth sequence is [1,1,-1i,-1i],
第七序列为[1,-1,1i,-1i],The seventh sequence is [1,-1,1i,-1i],
第八序列为[1,-1,-1i,1i],The eighth sequence is [1,-1,-1i,1i],
第九序列为[1,1i,1,1i],The ninth sequence is [1, 1i, 1, 1i],
第十序列为[1,1i,-1,-1i],The tenth sequence is [1, 1i, -1, -1i],
第十一序列为[1,-1i,1,-1i],The eleventh sequence is [1,-1i,1,-1i],
第十二序列为[1,-1i,-1,1i],The twelfth sequence is [1,-1i,-1,1i],
第十三序列为[1,1i,1i,1],The thirteenth sequence is [1, 1i, 1i, 1],
第十四序列为[1,1i,-1i,-1], The fourteenth sequence is [1, 1i, -1i, -1],
第十五序列为[1,-1i,1i,-1],The fifteenth sequence is [1,-1i,1i,-1],
第十六序列为[1,-1i,-1i,1];The sixteenth sequence is [1,-1i,-1i,1];
序列集合3:Sequence Collection 3:
所述序列集合3,包含16条长度为4的序列,其中,The sequence set 3 includes 16 sequences of length 4, wherein
第一序列为[1,1,1,1i],The first sequence is [1,1,1,1i],
第二序列为[1,1,-1,-1i],The second sequence is [1,1,-1,-1i],
第三序列为[1,-1,1,-1i],The third sequence is [1,-1,1,-1i],
第四序列为[1,-1,-1,1i],The fourth sequence is [1,-1,-1,1i],
第五序列为[1,1,1i,1],The fifth sequence is [1,1,1i,1],
第六序列为[1,1,-1i,-1],The sixth sequence is [1,1,-1i,-1],
第七序列为[1,-1,1i,-1],The seventh sequence is [1,-1,1i,-1],
第八序列为[1,-1,-1i,1],The eighth sequence is [1,-1,-1i,1],
第九序列为[1,1i,1,1],The ninth sequence is [1, 1i, 1, 1],
第十序列为[1,1i,-1,-1],The tenth sequence is [1, 1i, -1, -1],
第十一序列为[1,-1i,1,-1],The eleventh sequence is [1,-1i,1,-1],
第十二序列为[1,-1i,-1,1],The twelfth sequence is [1,-1i,-1,1],
第十三序列为[1,1i,1i,-1i],The thirteenth sequence is [1, 1i, 1i, -1i],
第十四序列为[1,1i,-1i,1i],The fourteenth sequence is [1, 1i, -1i, 1i],
第十五序列为[1,-1i,1i,1i],The fifteenth sequence is [1,-1i,1i,1i],
第十六序列为[1,-1i,-1i,-1i];The sixteenth sequence is [1,-1i,-1i,-1i];
序列集合4:Sequence Collection 4:
所述序列集合4,包含16条长度为4的序列,其中,The sequence set 4 includes 16 sequences of length 4, wherein
第一序列为[1,1,1,-1i],The first sequence is [1,1,1,-1i],
第二序列为[1,1,-1,1i],The second sequence is [1,1,-1,1i],
第三序列为[1,-1,1,1i],The third sequence is [1,-1,1,1i],
第四序列为[1,-1,-1,-1i], The fourth sequence is [1,-1,-1,-1i],
第五序列为[1,1,1i,-1],The fifth sequence is [1,1,1i,-1],
第六序列为[1,1,-1i,1],The sixth sequence is [1,1,-1i,1],
第七序列为[1,-1,1i,1],The seventh sequence is [1,-1,1i,1],
第八序列为[1,-1,-1i,-1],The eighth sequence is [1,-1,-1i,-1],
第九序列为[1,1i,1,-1],The ninth sequence is [1, 1i, 1, -1],
第十序列为[1,1i,-1,1],The tenth sequence is [1, 1i, -1, 1],
第十一序列为[1,-1i,1,1],The eleventh sequence is [1,-1i,1,1],
第十二序列为[1,-1i,-1,-1],The twelfth sequence is [1,-1i,-1,-1],
第十三序列为[1,1i,1i,1i],The thirteenth sequence is [1, 1i, 1i, 1i],
第十四序列为[1,1i,-1i,-1i],The fourteenth sequence is [1, 1i, -1i, -1i],
第十五序列为[1,-1i,1i,-1i],The fifteenth sequence is [1,-1i,1i,-1i],
第十六序列为[1,-1i,-1i,1i];The sixteenth sequence is [1,-1i,-1i,1i];
序列集合5:Sequence Collection 5:
所述序列集合5,包含32条长度为4的序列,其中,The sequence set 5 includes 32 sequences of length 4, wherein
第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
第二序列为[1,1i,-1,-1i],The second sequence is [1, 1i, -1, -1i],
第三序列为[1,-1,1,-1],The third sequence is [1,-1,1,-1],
第四序列为[1,-1i,-1,1i],The fourth sequence is [1,-1i,-1,1i],
第五序列为[1,1,1i,-1i],The fifth sequence is [1,1,1i,-1i],
第六序列为[1,1i,-1i,-1],The sixth sequence is [1, 1i, -1i, -1],
第七序列为[1,-1,1i,1i],The seventh sequence is [1,-1,1i,1i],
第八序列为[1,-1i,-1i,1],The eighth sequence is [1,-1i,-1i,1],
第九序列为[1,1i,1,-1i],The ninth sequence is [1, 1i, 1, -1i],
第十序列为[1,-1,-1,-1],The tenth sequence is [1,-1,-1,-1],
第十一序列为[1,-1i,1,1i],The eleventh sequence is [1,-1i,1,1i],
第十二序列为[1,1,-1,1], The twelfth sequence is [1,1,-1,1],
第十三序列为[1,1i,1i,-1],The thirteenth sequence is [1, 1i, 1i, -1],
第十四序列为[1,-1,-1i,1i],The fourteenth sequence is [1,-1,-1i,1i],
第十五序列为[1,-1i,1i,1],The fifteenth sequence is [1,-1i,1i,1],
第十六序列为[1,1,-1i,-1i],The sixteenth sequence is [1,1,-1i,-1i],
第十七序列为[1,1,1,-1],The seventeenth sequence is [1,1,1,-1],
第十八序列为[1,1i,-1,1i],The eighteenth sequence is [1, 1i, -1, 1i],
第十九序列为[1,-1,1,1],The nineteenth sequence is [1,-1,1,1],
第二十序列为[1,-1i,-1,-1i],The twentieth sequence is [1,-1i,-1,-1i],
第二十一序列为[1,1,1i,1i],The twenty-first sequence is [1,1,1i,1i],
第二十二序列为[1,1i,-1i,1],The twenty-second sequence is [1, 1i, -1i, 1],
第二十三序列为[1,-1,1i,-1i],The twenty-third sequence is [1,-1,1i,-1i],
第二十四序列为[1,-1i,-1i,-1],The twenty-fourth sequence is [1,-1i,-1i,-1],
第二十五序列为[1,1i,1,1i],The twenty-fifth sequence is [1,1i,1,1i],
第二十六序列为[1,-1,-1,1],The twenty-sixth sequence is [1,-1,-1,1],
第二十七序列为[1,-1i,1,-1i],The twenty-seventh sequence is [1,-1i,1,-1i],
第二十八序列为[1,1,-1,-1],The twenty-eighth sequence is [1,1,-1,-1],
第二十九序列为[1,1i,1i,1],The twenty-ninth sequence is [1, 1i, 1i, 1],
第三十序列为[1,-1,-1i,-1i],The thirtieth sequence is [1,-1,-1i,-1i],
第三十一序列为[1,-1i,1i,-1],The thirty-first sequence is [1,-1i,1i,-1],
第三十二序列为[1,1,-1i,1i];The thirty-second sequence is [1,1,-1i,1i];
序列集合6:Sequence set 6:
所述序列集合6,包含32条长度为4的序列,其中,The sequence set 6 includes 32 sequences of length 4, wherein
第一序列为[1,1,1,1i],The first sequence is [1,1,1,1i],
第二序列为[1,1i,-1,1],The second sequence is [1, 1i, -1, 1],
第三序列为[1,-1,1,-1i],The third sequence is [1,-1,1,-1i],
第四序列为[1,-1i,-1,-1], The fourth sequence is [1,-1i,-1,-1],
第五序列为[1,1,1i,1],The fifth sequence is [1,1,1i,1],
第六序列为[1,1i,-1i,-1i],The sixth sequence is [1, 1i, -1i, -1i],
第七序列为[1,-1,1i,-1],The seventh sequence is [1,-1,1i,-1],
第八序列为[1,-1i,-1i,1i],The eighth sequence is [1,-1i,-1i,1i],
第九序列为[1,1i,1,1],The ninth sequence is [1, 1i, 1, 1],
第十序列为[1,-1,-1,-1i],The tenth sequence is [1,-1,-1,-1i],
第十一序列为[1,-1i,1,-1],The eleventh sequence is [1,-1i,1,-1],
第十二序列为[1,1,-1,i],The twelfth sequence is [1,1,-1,i],
第十三序列为[1,1i,1i,-1i],The thirteenth sequence is [1, 1i, 1i, -1i],
第十四序列为[1,-1,-1i,-1],The fourteenth sequence is [1,-1,-1i,-1],
第十五序列为[1,-1i,1i,i],The fifteenth sequence is [1,-1i,1i,i],
第十六序列为[1,1,-1i,1],The sixteenth sequence is [1,1,-1i,1],
第十七序列为[1,1,1,-1i],The seventeenth sequence is [1,1,1,-1i],
第十八序列为[1,1i,-1,-1],The eighteenth sequence is [1,1i,-1,-1],
第十九序列为[1,-1,1,1i],The nineteenth sequence is [1,-1,1,1i],
第二十序列为[1,-1i,-1,1],The twentieth sequence is [1,-1i,-1,1],
第二十一序列为[1,1,1i,-1],The twenty-first sequence is [1,1,1i,-1],
第二十二序列为[1,1i,-1i,1i],The twenty-second sequence is [1, 1i, -1i, 1i],
第二十三序列为[1,-1,1i,1],The twenty-third sequence is [1,-1,1i,1],
第二十四序列为[1,-1i,-1i,-1i],The twenty-fourth sequence is [1,-1i,-1i,-1i],
第二十五序列为[1,1i,1,-1],The twenty-fifth sequence is [1, 1i, 1, -1],
第二十六序列为[1,-1,-1,1i],The twenty-sixth sequence is [1,-1,-1,1i],
第二十七序列为[1,-1i,1,1],The twenty-seventh sequence is [1,-1i,1,1],
第二十八序列为[1,1,-1,-1i],The twenty-eighth sequence is [1,1,-1,-1i],
第二十九序列为[1,1i,1i,1i],The twenty-ninth sequence is [1, 1i, 1i, 1i],
第三十序列为[1,-1,-1i,1], The thirtieth sequence is [1,-1,-1i,1],
第三十一序列为[1,-1i,1i,-1i],The thirty-first sequence is [1,-1i,1i,-1i],
第三十二序列为[1,1,-1i,-1];The thirty-second sequence is [1, 1, -1i, -1];
序列集合7:Sequence collection 7:
所述序列集合7,包含4条长度为4的序列,其中,The sequence set 7 includes four sequences of length 4, wherein
第一序列为[1,0,0,0],The first sequence is [1,0,0,0],
第二序列为[0,1,0,0],The second sequence is [0,1,0,0],
第三序列为[0,0,1,0],The third sequence is [0,0,1,0],
第四序列为[0,0,0,1];The fourth sequence is [0,0,0,1];
序列集合8:Sequence set 8:
所述序列集合8,包含16条长度为6的序列,其中,The sequence set 8 includes 16 sequences of length 6, wherein
第一序列为[1,0,1,0,1,0],The first sequence is [1,0,1,0,1,0],
第二序列为[-1,0,1,0,-1,0],The second sequence is [-1,0,1,0,-1,0],
第三序列为[1,0,-1,0,-1,0],The third sequence is [1,0,-1,0,-1,0],
第四序列为[-1,0,-1,0,1,0],The fourth sequence is [-1,0,-1,0,1,0],
第五序列为[1,0,0,1,0,1],The fifth sequence is [1,0,0,1,0,1],
第六序列为[-1,0,0,1,0,-1],The sixth sequence is [-1,0,0,1,0,-1],
第七序列为[1,0,0,-1,0,-1],The seventh sequence is [1,0,0,-1,0,-1],
第八序列为[-1,0,0,-1,0,1],The eighth sequence is [-1,0,0,-1,0,1],
第九序列为[0,1,1,0,0,1],The ninth sequence is [0, 1, 1, 0, 0, 1],
第十序列为[0,-1,1,0,0,-1],The tenth sequence is [0, -1, 1, 0, 0, -1],
第十一序列为[0,1,-1,0,0,-1],The eleventh sequence is [0, 1, -1, 0, 0, -1],
第十二序列为[0,-1,-1,0,0,1],The twelfth sequence is [0,-1,-1,0,0,1],
第十三序列为[0,1,0,1,1,0],The thirteenth sequence is [0,1,0,1,1,0],
第十四序列为[0,-1,0,1,-1,0],The fourteenth sequence is [0, -1, 0, 1, -1, 0],
第十五序列为[0,1,0,-1,-1,0],The fifteenth sequence is [0,1,0,-1,-1,0],
第十六序列为[0,-1,0,-1,1,0]; The sixteenth sequence is [0, -1, 0, -1, 1, 0];
序列集合9:Sequence set 9:
所述序列集合9,包含16条长度为6的序列,其中,The sequence set 9 includes 16 sequences of length 6, wherein
第一序列为[1,1,1,0,0,0],The first sequence is [1,1,1,0,0,0],
第二序列为[-1,1,-1,0,0,0],The second sequence is [-1,1,-1,0,0,0],
第三序列为[1,-1,-1,0,0,0],The third sequence is [1,-1,-1,0,0,0],
第四序列为[-1,-1,1,0,0,0],The fourth sequence is [-1,-1,1,0,0,0],
第五序列为[0,0,1,1,1,0],The fifth sequence is [0,0,1,1,1,0],
第六序列为[0,0,-1,-1,1,0],The sixth sequence is [0,0,-1,-1,1,0],
第七序列为[0,0,-1,1,-1,0],The seventh sequence is [0,0,-1,1,-1,0],
第八序列为[0,0,1,-1,-1,0],The eighth sequence is [0,0,1,-1,-1,0],
第九序列为[1,0,0,0,1,1],The ninth sequence is [1,0,0,0,1,1],
第十序列为[-1,0,0,0,1,-1],The tenth sequence is [-1,0,0,0,1,-1],
第十一序列为[1,0,0,0,-1,-1],The eleventh sequence is [1,0,0,0,-1,-1],
第十二序列为[-1,0,0,0,-1,1],The twelfth sequence is [-1,0,0,0,-1,1],
第十三序列为[0,1,0,1,0,1],The thirteenth sequence is [0, 1, 0, 1, 0, 1],
第十四序列为[0,1,0,-1,0,-1],The fourteenth sequence is [0,1,0,-1,0,-1],
第十五序列为[0,-1,0,1,0,-1],The fifteenth sequence is [0, -1, 0, 1, 0, -1],
第十六序列为[0,-1,0,-1,0,1];The sixteenth sequence is [0, -1, 0, -1, 0, 1];
序列集合10:Sequence collection 10:
所述序列集合10,包含16条长度为6的序列,其中,The sequence set 10 includes 16 sequences of length 6, wherein
第一序列为[1,1,1,1,1,1],The first sequence is [1,1,1,1,1,1],
第二序列为[1,1,1,1,-1,-1],The second sequence is [1,1,1,1,-1,-1],
第三序列为[1,1,1,-1,1,-1],The third sequence is [1,1,1,-1,1,-1],
第四序列为[1,1,1,-1,-1,1],The fourth sequence is [1,1,1,-1,-1,1],
第五序列为[1,1,-1,1,1,-1],The fifth sequence is [1,1,-1,1,1,-1],
第六序列为[1,1,-1,1,-1,1], The sixth sequence is [1,1,-1,1,-1,1],
第七序列为[1,1,-1,-1,1,1],The seventh sequence is [1,1,-1,-1,1,1],
第八序列为[1,1,-1,-1,-1,-1],The eighth sequence is [1,1,-1,-1,-1,-1],
第九序列为[1,-1,1,1,1,-1],The ninth sequence is [1,-1,1,1,1,-1],
第十序列为[1,-1,1,1,-1,1],The tenth sequence is [1,-1,1,1,-1,1],
第十一序列为[1,-1,1,-1,1,1],The eleventh sequence is [1,-1,1,-1,1,1],
第十二序列为[1,-1,1,-1,-1,-1],The twelfth sequence is [1,-1,1,-1,-1,-1],
第十三序列为[1,-1,-1,1,1,1],The thirteenth sequence is [1,-1,-1,1,1,1],
第十四序列为[1,-1,-1,1,-1,-1],The fourteenth sequence is [1,-1,-1,1,-1,-1],
第十五序列为[1,-1,-1,-1,1,-1],The fifteenth sequence is [1,-1,-1,-1,1,-1],
第十六序列为[1,-1,-1,-1,-1,1];The sixteenth sequence is [1,-1,-1,-1,-1,1];
序列集合11:Sequence collection 11:
所述序列集合11,包含32条长度为4的序列,其中,The sequence set 11 includes 32 sequences of length 4, wherein
第一序列为[1+0i,1+0i,1+0i,1+0i],The first sequence is [1+0i, 1+0i, 1+0i, 1+0i],
第二序列为[1+0i,0+1i,-1+0i,-0-1i],The second sequence is [1+0i, 0+1i, -1+0i, -0-1i],
第三序列为[1+0i,-1+0i,1+0i,-1+0i],The third sequence is [1+0i, -1+0i, 1+0i, -1+0i],
第四序列为[1+0i,-0-1i,-1+0i,0+1i],The fourth sequence is [1+0i, -0-1i, -1+0i, 0+1i],
第五序列为[0+2i,-0-1i,0+2i,0+1i],The fifth sequence is [0+2i, -0-1i, 0+2i, 0+1i],
第六序列为[0+2i,1+0i,-0-2i,1+0i],The sixth sequence is [0+2i, 1+0i, -0-2i, 1+0i],
第七序列为[0+2i,0+1i,0+2i,-0-1i],The seventh sequence is [0+2i, 0+1i, 0+2i, -0-1i],
第八序列为[0+2i,-1+0i,-0-2i,-1+0i],The eighth sequence is [0+2i, -1+0i, -0-2i, -1+0i],
第九序列为[0+2i,-0-1i,-1+0i,2+0i],The ninth sequence is [0+2i, -0-1i, -1+0i, 2+0i],
第十序列为[0+2i,1+0i,1+0i-0-2i],The tenth sequence is [0+2i, 1+0i, 1+0i-0-2i],
第十一序列为[0+2i,0+1i,-1+0i,-2+0i],The eleventh sequence is [0+2i, 0+1i, -1+0i, -2+0i],
第十二序列为[0+2i,-1+0i,1+0i,0+2i],The twelfth sequence is [0+2i, -1+0i, 1+0i, 0+2i],
第十三序列为[0+2i,-0-1i,0+0i,-1+0i],The thirteenth sequence is [0+2i, -0-1i, 0+0i, -1+0i],
第十四序列为[0+2i,1+0i,0+0i,0+1i], The fourteenth sequence is [0+2i, 1+0i, 0+0i, 0+1i],
第十五序列为[0+2i,0+1i,0+0i,1+0i],The fifteenth sequence is [0+2i, 0+1i, 0+0i, 1+0i],
第十六序列为[0+2i,-1+0i,0+0i,-0-1i],The sixteenth sequence is [0+2i, -1+0i, 0+0i, -0-1i],
第十七序列为[-1+0i,-0-1i,-0-2i,-2+0i],The seventeenth sequence is [-1+0i, -0-1i, -0-2i, -2+0i],
第十八序列为[-1+0i,1+0i,0+2i,0+2i],The eighteenth sequence is [-1+0i, 1+0i, 0+2i, 0+2i],
第十九序列为[-1+0i,0+1i,-0-2i,2+0i],The nineteenth sequence is [-1+0i, 0+1i, -0-2i, 2+0i],
第二十序列为[-1+0i,-1+0i,0+2i,-0-2i],The twentieth sequence is [-1+0i, -1+0i, 0+2i, -0-2i],
第二十一序列为[-1+0i,-2+0i,0+2i,0+1i],The twenty-first sequence is [-1+0i, -2+0i, 0+2i, 0+1i],
第二十二序列为[-1+0i,-0-2i,-0-2i,1+0i],The twenty-second sequence is [-1+0i,-0-2i,-0-2i, 1+0i],
第二十三序列为[-1+0i,2+0i,0+2i,-0-1i],The twenty-third sequence is [-1+0i, 2+0i, 0+2i, -0-1i],
第二十四序列为[-1+0i,0+2i,-0-2i,-1+0i],The twenty-fourth sequence is [-1+0i, 0+2i, -0-2i, -1+0i],
第二十五序列为[-1+0i,-2+0i,1+0i,-2+0i],The twenty-fifth sequence is [-1+0i, -2+0i, 1+0i, -2+0i],
第二十六序列为[-1+0i,-0-2i,-1+0i,0+2i],The twenty-sixth sequence is [-1+0i, -0-2i, -1+0i, 0+2i],
第二十七序列为[-1+0i,2+0i,1+0i,2+0i],The twenty-seventh sequence is [-1+0i, 2+0i, 1+0i, 2+0i],
第二十八序列为[-1+0i,0+2i,-1+0i,-0-2i],The twenty-eighth sequence is [-1+0i, 0+2i, -1+0i, -0-2i],
第二十九序列为[-1+0i,-2+0i,-0-1i,0+0i],The twenty-ninth sequence is [-1+0i, -2+0i, -0-1i, 0+0i],
第三十序列为[-1+0i,-0-2i,0+1i,0+0i],The thirtieth sequence is [-1+0i,-0-2i, 0+1i, 0+0i],
第三十一序列为[-1+0i,2+0i,-0-1i,0+0i],The thirty-first sequence is [-1+0i, 2+0i, -0-1i, 0+0i],
第三十二序列为[-1+0i,0+2i,0+1i,0+0i];The thirty-second sequence is [-1+0i, 0+2i, 0+1i, 0+0i];
其中,i为虚数单位,i=sqrt(-1);或者Where i is an imaginary unit, i=sqrt(-1); or
对序列集合1、序列集合2、序列集合3、序列集合4、序列集合5、序列集合6、序列集合7、序列集合8、序列集合9、序列集合10、序列集合11这十一个序列集合中的序列,分别进行下述任一处理得到的集合:11 sequence sets of sequence set 1, sequence set 2, sequence set 3, sequence set 4, sequence set 5, sequence set 6, sequence set 7, sequence set 8, sequence set 9, sequence set 10, sequence set 11 The sequence in the process, respectively, is a collection obtained by any of the following processes:
其中,所述任一处理,包括:Wherein, any of the processes described includes:
对序列集合中的每条序列或每条序列的第S个序列元素乘以1、1i、-1、或-1i,或者乘以1i的Q次方;或者,Multiply the S-th sequence element of each sequence or each sequence in the sequence set by 1, 1i, -1, or -1i, or multiply by the Q-th power of 1i; or,
对序列集合中的每条序列或每条序列的第S个序列元素进行R*π的相 位调整或旋转,或者,乘以exp(j*R*π),j为虚数单位,j=sqrt(-1);或者,R*π phase for each sequence in the sequence set or the Sth sequence element of each sequence Bit adjustment or rotation, or, multiplied by exp(j*R*π), j is the imaginary unit, j=sqrt(-1); or,
对序列集合中的每条序列或每条序列的第S个序列元素乘以指定值,或者分别乘以指定值;Multiplying each sequence in the sequence set or the Sth sequence element of each sequence by a specified value, or multiplying by a specified value;
其中,S为大于或等于1且小于或等于W的整数,Q为整数,R为实数。Wherein S is an integer greater than or equal to 1 and less than or equal to W, Q is an integer, and R is a real number.
本发明实施例中,可选地,从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,In the embodiment of the present invention, optionally, the third sequence is determined from a third sequence set, and the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set,
所述根据所述第一序列集合和所述第二序列集合得到的序列集合,包括以下至少之一:The sequence set obtained according to the first sequence set and the second sequence set includes at least one of the following:
所述第一序列集合中的任意一条序列与所述第二序列集合中的任意一条序列进行点乘处理得到的序列构成的序列集合;a sequence set formed by a sequence obtained by performing dot multiplication processing on any one of the first sequence set and any one of the second sequence sets;
所述第一序列集合中的任意一条序列与所述第二序列集合中的任意一条序列进行乘法处理得到的序列构成的序列集合;a sequence set formed by a sequence obtained by multiplying any one of the first sequence set and any one of the second sequence sets;
所述第一序列集合中的任意一条序列的元素替换所述第二序列集合中的任意一条序列的非零元素得到的序列构成的序列集合;And deleting, by the element of any one of the first sequence sets, a sequence set formed by a sequence obtained by replacing a non-zero element of any one of the second sequence sets;
所述第一序列集合中的任意一条序列的元素与所述第二序列集合中的任意一条序列的非零元素进行点乘处理得到的序列构成的序列集合。a sequence set formed by a sequence obtained by performing dot multiplication processing on an element of any one of the first sequence sets and a non-zero element of any one of the second sequence sets.
本发明实施例中,可选地,根据第一序列和第二序列确定第三序列时,或者In the embodiment of the present invention, optionally, when the third sequence is determined according to the first sequence and the second sequence, or
从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,Determining the third sequence from a third sequence set, and the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set,
所述第一序列从第一序列集合中获取,包括以下之一:The first sequence is obtained from the first sequence set, including one of the following:
采用随机选择的方式从所述第一序列集合中获取第一序列;Obtaining the first sequence from the first sequence set in a random selection manner;
根据第一预设规则从所述第一序列集合中获取第一序列;Obtaining a first sequence from the first sequence set according to a first preset rule;
根据系统配置信息从所述第一序列集合中获取第一序列。 Acquiring the first sequence from the first sequence set according to system configuration information.
本发明实施例中,可选地,根据第一序列和第二序列确定第三序列时,或者In the embodiment of the present invention, optionally, when the third sequence is determined according to the first sequence and the second sequence, or
从第三序列集合中确定所述第三序列,且所述第三序列集合包括第二指定序列集合、对第二指定序列集合进行处理得到的序列集合、根据第一序列集合和第二序列集合得到的序列集合至少之一时,Determining the third sequence from the third sequence set, and the third sequence set includes a second specified sequence set, a sequence set obtained by processing the second specified sequence set, according to the first sequence set and the second sequence set When at least one of the resulting sequence sets is obtained,
所述第二序列从第二序列集合中获取,包括以下之一:The second sequence is obtained from the second sequence set, including one of the following:
采用随机选择的方式从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second set of sequences in a randomly selected manner;
根据第二预设规则从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second sequence set according to a second preset rule;
根据系统配置信息从所述第二序列集合中获取第二序列。Obtaining a second sequence from the second set of sequences according to system configuration information.
本发明实施例中,可选地,根据第一序列和第二序列确定第三序列时,In the embodiment of the present invention, optionally, when the third sequence is determined according to the first sequence and the second sequence,
所述根据第一序列和第二序列确定第三序列,包括:The determining the third sequence according to the first sequence and the second sequence comprises:
将所述第一序列与所述第二序列进行点乘处理,生成第三序列;或者,Performing point-multiplication processing on the first sequence and the second sequence to generate a third sequence; or
将所述第一序列与所述第二序列进行乘法处理,生成第三序列;或者,Multiplying the first sequence and the second sequence to generate a third sequence; or
使用所述第一序列中的元素替换所述第二序列中的非零元素,生成第三序列;或者,Substituting an element in the first sequence for a non-zero element in the second sequence to generate a third sequence; or
将所述第一序列中的元素与所述第二序列中的非零元素进行点乘处理后得到的值替换所述第二序列中的非零元素,生成第三序列。Substituting a value obtained by dot-multiplying an element in the first sequence with a non-zero element in the second sequence to replace a non-zero element in the second sequence to generate a third sequence.
本发明实施例中,可选地,从第三序列集合中确定所述第三序列时,In the embodiment of the present invention, optionally, when determining the third sequence from the third sequence set,
所述从第三序列集合中确定所述第三序列,包括:Determining the third sequence from the third sequence set includes:
采用随机选择的方式从所述第三序列集合中获取所述第三序列;Obtaining the third sequence from the third sequence set in a randomly selected manner;
根据第三预设规则从所述第三序列集合中获取所述第三序列;Obtaining the third sequence from the third sequence set according to a third preset rule;
根据系统配置信息从所述第三序列集合中获取所述第三序列。Obtaining the third sequence from the third sequence set according to system configuration information.
本发明实施例中,可选地,根据第一序列和第二序列确定第三序列时,或者In the embodiment of the present invention, optionally, when the third sequence is determined according to the first sequence and the second sequence, or
从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时, Determining the third sequence from a third sequence set, and the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set,
所述方法还包括以下之一:The method also includes one of the following:
对所述第一序列集合中的序列进行能量调整或能量归一化处理;Performing energy adjustment or energy normalization processing on the sequence in the first sequence set;
对所述第一序列进行能量调整或能量归一化处理;Performing energy adjustment or energy normalization on the first sequence;
对所述第三序列进行能量调整或能量归一化处理;Performing energy adjustment or energy normalization on the third sequence;
从第三序列集合中确定所述第三序列,且所述第三序列集合不包括根据第一序列集合和第二序列集合得到的序列集合时,Determining the third sequence from a third sequence set, and the third sequence set does not include a sequence set obtained according to the first sequence set and the second sequence set,
所述方法还包括以下之一:The method also includes one of the following:
对所述第三序列进行能量调整或能量归一化处理。The third sequence is subjected to energy adjustment or energy normalization.
本发明实施例中,可选地,所述方法还包括:In the embodiment of the present invention, optionally, the method further includes:
对所述第三序列的每个元素或第V个元素乘以1、1i、-1、或-1i,或者,乘以1i的G次方;或者,Multiplying each element or the Vth element of the third sequence by 1, 1i, -1, or -1i, or multiplying by the G of 1i; or
对所述第三序列的每个元素或第V个元素进行H*π的相位调整或旋转,或者,乘以exp(j*H*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of H*π for each element or Vth element of the third sequence, or multiply exp(j*H*π), j is an imaginary unit, j=sqrt(-1) ;or,
对所述第三序列的每个元素或第V个元素乘以指定值;Multiplying each element or the Vth element of the third sequence by a specified value;
其中,V为大于或等于1且小于或等于所述第三序列的长度的整数,G为整数,H为实数。Wherein V is an integer greater than or equal to 1 and less than or equal to the length of the third sequence, G is an integer, and H is a real number.
本发明实施例中,可选地,所述使用所述第三序列对第一数据进行处理生成第二数据,包括:In the embodiment of the present invention, optionally, the processing, by using the third sequence, the first data to generate the second data includes:
使用所述第三序列对第一数据进行扩展处理生成第二数据;或,And expanding, by using the third sequence, the first data to generate second data; or
使用所述第三序列对第一数据进行映射处理生成第二数据;或,Performing mapping processing on the first data by using the third sequence to generate second data; or
使用所述第三序列对第一数据进行调制处理生成第二数据。The first data is modulated using the third sequence to generate second data.
本发明实施例中,可选地,所述方法还包括:In the embodiment of the present invention, optionally, the method further includes:
将所述第二数据映射到指定的传输资源上,用于形成发射信号以及发送。Mapping the second data to a designated transmission resource for forming a transmit signal and transmitting.
本发明实施例中,可选地,In the embodiment of the present invention, optionally,
所述第一数据至少包含发射机或终端的身份标识信息;或者, The first data includes at least identifier information of a transmitter or a terminal; or
至少包含有发射机或终端的身份标识信息和信令信息;或者,Containing at least the identity information and signaling information of the transmitter or terminal; or,
至少包含有发射机或终端的身份标识信息和数据信息;或者,Include at least the identity information and data information of the transmitter or terminal; or,
至少包含有发射机或终端的身份标识信息、信令信息和数据信息;或者,Containing at least the identity information, signaling information, and data information of the transmitter or terminal; or,
至少包含有发射机或终端的身份标识信息和小区标识信息;或者,At least the identity information and the cell identification information of the transmitter or the terminal are included; or
至少包含有发射机或终端的身份标识信息、小区标识信息和信令信息;或者,Include at least the identity information, cell identification information, and signaling information of the transmitter or the terminal; or,
至少包含有发射机或终端的身份标识信息、小区标识信息和数据信息;或者,Include at least the identity information, cell identification information, and data information of the transmitter or the terminal; or,
至少包含有发射机或终端的身份标识信息、小区标识信息、数据信息和信令信息。At least the identity information, cell identification information, data information and signaling information of the transmitter or the terminal are included.
本发明实施例中,可选地,In the embodiment of the present invention, optionally,
第二数据至少包含发射机或终端的身份标识信息;The second data includes at least the identity information of the transmitter or the terminal;
或者,至少包含有发射机或终端的身份标识信息和信令信息;Or at least including identity information and signaling information of the transmitter or the terminal;
或者,至少包含有发射机或终端的身份标识信息和数据信息;Or at least the identity information and the data information of the transmitter or the terminal;
或者,至少包含有发射机或终端的身份标识信息、信令信息和数据信息;或者,Or at least the identity information, signaling information, and data information of the transmitter or the terminal; or,
至少包含有发射机或终端的身份标识信息和小区标识信息;或者,At least the identity information and the cell identification information of the transmitter or the terminal are included; or
至少包含有发射机或终端的身份标识信息、小区标识信息和信令信息;或者,Include at least the identity information, cell identification information, and signaling information of the transmitter or the terminal; or,
至少包含有发射机或终端的身份标识信息、小区标识信息和数据信息;或者,Include at least the identity information, cell identification information, and data information of the transmitter or the terminal; or,
至少包含有发射机或终端的身份标识信息、小区标识信息、数据信息和信令信息。At least the identity information, cell identification information, data information and signaling information of the transmitter or the terminal are included.
本发明实施例中,可选地,所述指定的传输资源包括下述至少之一:载波、时隙、时频资源、空域资源、码域资源、跳频模式、天线端口。 In the embodiment of the present invention, optionally, the specified transmission resource includes at least one of the following: a carrier, a time slot, a time-frequency resource, an airspace resource, a code domain resource, a frequency hopping mode, and an antenna port.
本发明实施例中,可选地,所述时频资源为上行数据信道,或者上行控制信道,或者随机接入信道。In the embodiment of the present invention, optionally, the time-frequency resource is an uplink data channel, or an uplink control channel, or a random access channel.
本发明实施例中,可选地,所述第一数据包括以下至少之一信息:车况信息、驾驶员的操作信息,车辆传感器所感知的信息和控制信令;其中,所述车况信息包括以下至少之一:车辆工具标识、所述车辆当前地理位置、所述车辆的行驶速度、所述车辆的大小、所述车辆的颜色;所述操作信息包括以下至少之一:所述驾驶员对所述车辆正在进行的操作,所述驾驶员准备对所述车辆进行的操作。In the embodiment of the present invention, optionally, the first data includes at least one of the following: vehicle condition information, driver operation information, information sensed by the vehicle sensor, and control signaling; wherein the vehicle condition information includes the following: At least one of: a vehicle tool identification, a current geographic location of the vehicle, a traveling speed of the vehicle, a size of the vehicle, a color of the vehicle; the operational information comprising at least one of: the driver's office The ongoing operation of the vehicle, the driver preparing an operation on the vehicle.
另一方面,本发明实施例还提供了一种数据生成装置,所述装置包括:In another aspect, the embodiment of the present invention further provides a data generating apparatus, where the apparatus includes:
确定单元,配置为根据第一序列和第二序列确定第三序列,其中,所述第一序列从第一序列集合中获取,所述第二序列从第二序列集合中获取;或者,从第三序列集合中确定所述第三序列;a determining unit, configured to determine a third sequence according to the first sequence and the second sequence, wherein the first sequence is obtained from a first sequence set, and the second sequence is obtained from a second sequence set; or, from Determining the third sequence in a three-sequence set;
生成单元,配置为使用所述第三序列对第一数据进行处理生成第二数据;a generating unit, configured to process the first data by using the third sequence to generate second data;
其中,所述第一序列集合包括包含M条长度为L的序列的第一指定序列集合、和/或对所述第一指定序列集合进行处理得到的序列集合;The first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set;
其中,所述第二序列集合包括包含N条长度为C的序列的第二指定序列集合、和/或对所述第二指定序列集合进行处理得到的序列集合;The second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set;
其中,所述第三序列集合包括以下至少之一:包含P条长度为W的序列的第三指定序列集合;所述第二指定序列集合;对所述第二指定序列集合进行处理得到的序列集合;根据所述第一序列集合和所述第二序列集合得到的序列集合;The third sequence set includes at least one of: a third specified sequence set including P sequences of length W; the second specified sequence set; and a sequence obtained by processing the second specified sequence set a set of sequences obtained from the first set of sequences and the second set of sequences;
其中,M、L、N、C、P、W为正整数。Among them, M, L, N, C, P, and W are positive integers.
本发明实施例中,可选地,所述确定单元根据第一序列和第二序列确定第三序列时所述第一指定序列集合中的序列元素的取值,或者In an embodiment of the present invention, optionally, the determining unit determines, according to the first sequence and the second sequence, a value of a sequence element in the first specified sequence set when the third sequence is determined, or
所述确定单元从第三序列集合中确定所述第三序列时所述第三指定序 列集合中的序列元素的取值,均来自于以下集合至少之一:The determining unit determines the third specified sequence when the third sequence is determined from the third sequence set The values of the sequence elements in the column set are all from at least one of the following sets:
{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,-1+1i,-1-1i,1-1i};{0};{1,1i,-1,-1i,0};{1+1i,-1+1i,-1-1i,1-1i,0};{1,1i,-1,-1i,2,2i,-2,-2i,0};其中,i为虚数单位,i=sqrt(-1)。{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,- 1+1i, -1-1i, 1-1i}; {0}; {1, 1i, -1, -1i, 0}; {1+1i, -1+1i, -1-1i, 1-1i , 0}; {1, 1i, -1, -1i, 2, 2i, -2, -2i, 0}; where i is an imaginary unit and i = sqrt(-1).
本发明实施例中,可选地,所述确定单元根据第一序列和第二序列确定第三序列时,或者,从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,In the embodiment of the present invention, optionally, the determining unit determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set Including a sequence set obtained from the first sequence set and the second sequence set,
所述第一指定序列集合,包括下述序列集合至少之一:The first specified sequence set includes at least one of the following sequence sets:
序列集合1:Sequence set 1:
所述序列集合1,包含4条长度为4的序列,其中,The sequence set 1 includes four sequences of length 4, wherein
第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
第二序列为[1,1,1i,-1i],The second sequence is [1,1,1i,-1i],
第三序列为[1,1i,1,-1i],The third sequence is [1, 1i, 1, -1i],
第四序列为[1,1i,1i,-1];The fourth sequence is [1, 1i, 1i, -1];
序列集合2:Sequence collection 2:
所述序列集合2,包含4条长度为4的序列,其中,The sequence set 2 includes four sequences of length 4, wherein
第一序列为[1,1,1,-1],The first sequence is [1,1,1,-1],
第二序列为[1,1,1i,1i],The second sequence is [1,1,1i,1i],
第三序列为[1,1i,1,1i],The third sequence is [1, 1i, 1, 1i],
第四序列为[1,1i,1i,1];The fourth sequence is [1, 1i, 1i, 1];
序列集合3:Sequence Collection 3:
所述序列集合2,包含4条长度为4的序列,其中,The sequence set 2 includes four sequences of length 4, wherein
第一序列为[1,1,1,1i],The first sequence is [1,1,1,1i],
第二序列为[1,1,1i,1],The second sequence is [1,1,1i,1],
第三序列为[1,1i,1,1],The third sequence is [1, 1i, 1, 1],
第四序列为[1,1i,1i,-1i]; The fourth sequence is [1, 1i, 1i, -1i];
序列集合4:Sequence Collection 4:
所述序列集合4,包含4条长度为4的序列,其中,The sequence set 4 includes four sequences of length 4, wherein
第一序列为[1,1,1,-1i],The first sequence is [1,1,1,-1i],
第二序列为[1,1,1i,-1],The second sequence is [1,1,1i,-1],
第三序列为[1,1i,1,-1],The third sequence is [1, 1i, 1, -1],
第四序列为[1,1i,1i,1i];The fourth sequence is [1, 1i, 1i, 1i];
序列集合5:Sequence Collection 5:
所述序列集合5,包含1条长度为2的序列,其中,The sequence set 5 includes a sequence of length 2, wherein
第一序列为[1,1];The first sequence is [1,1];
序列集合6:Sequence set 6:
所述序列集合6,包含1条长度为2的序列,其中,The sequence set 6 includes a sequence of length 2, wherein
第一序列为[1,-1];The first sequence is [1,-1];
序列集合7:Sequence collection 7:
所述序列集合7,包含1条长度为2的序列,其中,The sequence set 7 includes a sequence of length 2, wherein
第一序列为[1,1i];The first sequence is [1, 1i];
序列集合8:Sequence set 8:
所述序列集合8,包含1条长度为2的序列,其中,The sequence set 8 includes a sequence of length 2, wherein
第一序列为[1,-1i];The first sequence is [1,-1i];
序列集合9:Sequence set 9:
所述序列集合9,包含4条长度为1的序列,其中,The sequence set 9 includes four sequences of length 1, wherein
第一序列为[1],The first sequence is [1],
第二序列为[1i],The second sequence is [1i],
第三序列为[-1],The third sequence is [-1],
第四序列为[-1i];The fourth sequence is [-1i];
序列集合10:Sequence collection 10:
所述序列集合10,包含4条长度为1的序列,其中, The sequence set 10 includes four sequences of length 1, wherein
第一序列为[1+1i],The first sequence is [1+1i],
第二序列为[-1+1i],The second sequence is [-1+1i],
第三序列为[-1-1i],The third sequence is [-1-1i],
第四序列为[1-1i];The fourth sequence is [1-1i];
序列集合11:Sequence collection 11:
所述序列集合11,包含2条长度为1的序列,其中,The sequence set 11 includes two sequences of length 1, wherein
第一序列为[1],The first sequence is [1],
第二序列为[-1];The second sequence is [-1];
序列集合12:Sequence set 12:
所述序列集合12,包含2条长度为1的序列,其中,The sequence set 12 includes two sequences of length 1, wherein
第一序列为[1i],The first sequence is [1i],
第二序列为[-1i];The second sequence is [-1i];
序列集合13:Sequence Set 13:
所述序列集合13,包含1条长度为1的序列,其中,The sequence set 13 includes a sequence of length 1, wherein
第一序列为[1];The first sequence is [1];
序列集合14:Sequence Set 14:
所述序列集合14,包含1条长度为1的序列,其中,The sequence set 14 includes a sequence of length 1, wherein
第一序列为[-1];The first sequence is [-1];
序列集合15:Sequence set 15:
所述序列集合15,包含1条长度为1的序列,其中,The sequence set 15 includes a sequence of length 1, wherein
第一序列为[1i];The first sequence is [1i];
序列集合16:Sequence set 16:
所述序列集合16,包含1条长度为1的序列,其中,The sequence set 16 includes a sequence of length 1, wherein
第一序列为[-1i];The first sequence is [-1i];
序列集合17:Sequence set 17:
所述序列集合17,包含4条长度为3的序列,其中, The sequence set 17 includes four sequences of length 3, wherein
第一序列为[1,1,1];The first sequence is [1,1,1];
第二序列为[1,-1,-1],The second sequence is [1,-1,-1],
第三序列为[-1,1,-1],The third sequence is [-1, 1, -1],
第四序列为[-1,1,1];The fourth sequence is [-1, 1, 1];
其中,i为虚数单位,i=sqrt(-1)。Where i is an imaginary unit and i=sqrt(-1).
本发明实施例中,可选地,所述确定单元根据第一序列和第二序列确定第三序列时,或者,从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,还配置为:In the embodiment of the present invention, optionally, the determining unit determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set When the sequence set obtained according to the first sequence set and the second sequence set is included, it is further configured as:
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素乘以1、1i、-1、或-1i,或者乘以1i的A次方;或者,Multiplying the Xth sequence element of each sequence or each sequence in the first specified sequence set by 1, 1i, -1, or -1i, or multiplying by the 1st power of A; or
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素进行B*π的相位调整或旋转,或者乘以exp(j*B*π),j为虚数单位,j=sqrt(-1);或者,Performing B*π phase adjustment or rotation for each sequence in the first specified sequence set or the Xth sequence element of each sequence, or multiplying exp(j*B*π), j is an imaginary unit, j=sqrt(-1); or,
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素乘以指定值,或者分别乘以指定值;Multiplying the Xth sequence element of each sequence or each sequence in the first specified sequence set by a specified value, or multiplying by a specified value;
其中,X为大于或等于1且小于或等于L的整数,A为整数,B为实数。Where X is an integer greater than or equal to 1 and less than or equal to L, A is an integer, and B is a real number.
本发明实施例中,可选地,所述确定单元根据第一序列和第二序列确定第三序列时,或者,从第三序列集合中确定所述第三序列,且所述第三序列集合包括第二指定序列集合、对所述第二指定序列集合进行处理得到的序列集合、根据第一序列集合和第二序列集合得到的序列集合至少之一时,In the embodiment of the present invention, optionally, the determining unit determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set And including a second specified sequence set, a sequence set obtained by processing the second specified sequence set, and at least one of the sequence set obtained according to the first sequence set and the second sequence set,
所述第二指定序列集合包括以下至少之一:The second specified sequence set includes at least one of the following:
哈达玛序列集合;Hadamard sequence collection;
沃尔什序列集合; Walsh sequence collection;
离散傅里叶变换序列集合;a set of discrete Fourier transform sequences;
包含指定数量或指定比例的0元素的序列的集合;a collection of sequences containing a specified number or a specified proportion of 0 elements;
单位矩阵序列集合。A collection of unit matrix sequences.
本发明实施例中,可选地,所述确定单元根据第一序列和第二序列确定第三序列时,或者,从第三序列集合中确定所述第三序列,且所述第三序列集合包括第二指定序列集合、对第二指定序列集合进行处理得到的序列集合、根据第一序列集合和第二序列集合得到的序列集合至少之一时,In the embodiment of the present invention, optionally, the determining unit determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set And including a second specified sequence set, a sequence set obtained by processing the second specified sequence set, and at least one of the sequence set obtained according to the first sequence set and the second sequence set,
所述第二指定序列集合,包括下述序列集合至少之一;其中,The second specified sequence set includes at least one of the following sequence sets; wherein
序列集合1:Sequence set 1:
所述序列集合1,包含4条长度为4的序列,其中,The sequence set 1 includes four sequences of length 4, wherein
第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
第二序列为[1,1,-1,-1],The second sequence is [1,1,-1,-1],
第三序列为[1,-1,1,-1],The third sequence is [1,-1,1,-1],
第四序列为[1,-1,-1,1];The fourth sequence is [1, -1, -1, 1];
序列集合2:Sequence collection 2:
所述序列集合2,包含4条长度为4的序列,其中,The sequence set 2 includes four sequences of length 4, wherein
第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
第二序列为[1,1i,-1,-1i],The second sequence is [1, 1i, -1, -1i],
第三序列为[1,-1,1,-1],The third sequence is [1,-1,1,-1],
第四序列为[1,-1i,-1,1i];The fourth sequence is [1,-1i,-1,1i];
序列集合3:Sequence Collection 3:
所述序列集合3,包含2条长度为2的序列,其中,The sequence set 3 includes two sequences of length 2, wherein
第一序列为[1,1],The first sequence is [1,1],
第二序列为[1,-1];The second sequence is [1,-1];
序列集合4:Sequence Collection 4:
所述序列集合4,包含1条长度为1的序列,其中, The sequence set 4 includes a sequence of length 1, wherein
第一序列为[1];The first sequence is [1];
序列集合5:Sequence Collection 5:
所述序列集合5,包含6条长度为4的序列,其中,The sequence set 5 includes six sequences of length 4, wherein
第一序列为[1,1,0,0],The first sequence is [1,1,0,0],
第二序列为[1,0,1,0],The second sequence is [1,0,1,0],
第三序列为[1,0,0,1],The third sequence is [1,0,0,1],
第四序列为[0,1,1,0],The fourth sequence is [0, 1, 1, 0],
第五序列为[0,1,0,1],The fifth sequence is [0, 1, 0, 1],
第六序列为[0,0,1,1];The sixth sequence is [0,0,1,1];
序列集合6:Sequence set 6:
所述序列集合6,包含4条长度为6的序列,其中,The sequence set 6 includes four sequences of length 6, wherein
第一序列为[1,1,1,0,0,0],The first sequence is [1,1,1,0,0,0],
第二序列为[1,0,0,1,1,0],The second sequence is [1,0,0,1,1,0],
第三序列为[0,1,0,0,1,1],The third sequence is [0, 1, 0, 0, 1, 1],
第四序列为[0,0,1,1,0,1],The fourth sequence is [0,0,1,1,0,1],
序列集合7:Sequence collection 7:
所述序列集合7,包含4条长度为6的序列,其中,The sequence set 7 includes four sequences of length 6, wherein
第一序列为[1,0,1,0,1,0],The first sequence is [1,0,1,0,1,0],
第二序列为[1,0,0,1,0,1],The second sequence is [1,0,0,1,0,1],
第三序列为[0,1,1,0,0,1],The third sequence is [0,1,1,0,0,1],
第四序列为[0,1,0,1,1,0],The fourth sequence is [0,1,0,1,1,0],
序列集合8:Sequence set 8:
所述序列集合8,包含4条长度为4的序列,其中,The sequence set 8 includes four sequences of length 4, wherein
第一序列为[1,0,0,0],The first sequence is [1,0,0,0],
第二序列为[0,1,0,0],The second sequence is [0,1,0,0],
第三序列为[0,0,1,0], The third sequence is [0,0,1,0],
第四序列为[0,0,0,1];The fourth sequence is [0,0,0,1];
序列集合9:Sequence set 9:
所述序列集合9,包含6条长度为6的序列,其中,The sequence set 9 includes six sequences of length 6, wherein
第一序列为[1,1,1,1,1,1],The first sequence is [1,1,1,1,1,1],
第二序列为[1,1,1i,-1,-1,-1i],The second sequence is [1,1,1i,-1,-1,-1i],
第三序列为[1,1i,-1i,1i,-1i,-1],The third sequence is [1, 1i, -1i, 1i, -1i, -1],
第四序列为[1,-1,1,-1i,-1,1i],The fourth sequence is [1,-1,1,-1i,-1,1i],
第五序列为[1,-1,-1,1,1i,-1i],The fifth sequence is [1,-1,-1,1,1i,-1i],
第六序列为[1,-1i,-1,-1,1,1i];The sixth sequence is [1,-1i,-1,-1,1,1i];
其中,i为虚数单位,i=sqrt(-1)。Where i is an imaginary unit and i=sqrt(-1).
本发明实施例中,可选地,所述确定单元根据第一序列和第二序列确定第三序列时,或者,从第三序列集合中确定所述第三序列,且所述第三序列集合包括第二指定序列集合、对第二指定序列集合进行处理得到的序列集合、根据第一序列集合和第二序列集合得到的序列集合至少之一时,还配置为:In the embodiment of the present invention, optionally, the determining unit determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set And when the second specified sequence set, the sequence set obtained by processing the second specified sequence set, and the sequence set obtained according to the first sequence set and the second sequence set are at least one of:
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素乘以1、1i、-1、或-1i,或者乘以1i的E次方;或者,Multiplying the Yth sequence element of each sequence or each sequence in the second specified sequence set by 1, 1i, -1, or -1i, or multiplying by 1i to the power of E; or
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素进行F*π的相位调整或旋转,或者,乘以exp(j*F*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of F*π for each sequence in the second specified sequence set or the Yth sequence element of each sequence, or multiply exp(j*F*π), j is an imaginary unit , j=sqrt(-1); or,
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素乘以指定值,或者分别乘以指定值;Multiplying each of the sequence of the second specified sequence set or the Yth sequence element of each sequence by a specified value, or multiplying by a specified value;
其中,Y为大于或等于1且小于或等于C的整数,E为整数,F为实数。Wherein Y is an integer greater than or equal to 1 and less than or equal to C, E is an integer, and F is a real number.
本发明实施例中,可选地,所述确定单元从第三序列集合中确定所述第三序列时,In the embodiment of the present invention, optionally, when the determining unit determines the third sequence from the third sequence set,
所述第三指定序列集合包括下述序列集合至少之一: The third specified sequence set includes at least one of the following sequence sets:
序列集合1:Sequence set 1:
所述序列集合1,包含16条长度为4的序列,其中,The sequence set 1 comprises 16 sequences of length 4, wherein
第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
第二序列为[1,1,-1,-1],The second sequence is [1,1,-1,-1],
第三序列为[1,-1,1,-1],The third sequence is [1,-1,1,-1],
第四序列为[1,-1,-1,1],The fourth sequence is [1,-1,-1,1],
第五序列为[1,1,1i,-1i],The fifth sequence is [1,1,1i,-1i],
第六序列为[1,1,-1i,1i],The sixth sequence is [1,1,-1i,1i],
第七序列为[1,-1,1i,1i],The seventh sequence is [1,-1,1i,1i],
第八序列为[1,-1,-1i,-1i],The eighth sequence is [1,-1,-1i,-1i],
第九序列为[1,1i,1,-1i],The ninth sequence is [1, 1i, 1, -1i],
第十序列为[1,1i,-1,1i],The tenth sequence is [1, 1i, -1, 1i],
第十一序列为[1,-1i,1,1i],The eleventh sequence is [1,-1i,1,1i],
第十二序列为[1,-1i,-1,-1i],The twelfth sequence is [1,-1i,-1,-1i],
第十三序列为[1,1i,1i,-1],The thirteenth sequence is [1, 1i, 1i, -1],
第十四序列为[1,1i,-1i,1],The fourteenth sequence is [1, 1i, -1i, 1],
第十五序列为[1,-1i,1i,1],The fifteenth sequence is [1,-1i,1i,1],
第十六序列为[1,-1i,-1i,-1];The sixteenth sequence is [1,-1i,-1i,-1];
序列集合2:Sequence collection 2:
所述序列集合2,包含16条长度为4的序列,其中,The sequence set 2 includes 16 sequences of length 4, wherein
第一序列为[1,1,1,-1],The first sequence is [1,1,1,-1],
第二序列为[1,1,-1,1],The second sequence is [1,1,-1,1],
第三序列为[1,-1,1,1],The third sequence is [1,-1,1,1],
第四序列为[1,-1,-1,-1],The fourth sequence is [1,-1,-1,-1],
第五序列为[1,1,1i,1i],The fifth sequence is [1,1,1i,1i],
第六序列为[1,1,-1i,-1i], The sixth sequence is [1,1,-1i,-1i],
第七序列为[1,-1,1i,-1i],The seventh sequence is [1,-1,1i,-1i],
第八序列为[1,-1,-1i,1i],The eighth sequence is [1,-1,-1i,1i],
第九序列为[1,1i,1,1i],The ninth sequence is [1, 1i, 1, 1i],
第十序列为[1,1i,-1,-1i],The tenth sequence is [1, 1i, -1, -1i],
第十一序列为[1,-1i,1,-1i],The eleventh sequence is [1,-1i,1,-1i],
第十二序列为[1,-1i,-1,1i],The twelfth sequence is [1,-1i,-1,1i],
第十三序列为[1,1i,1i,1],The thirteenth sequence is [1, 1i, 1i, 1],
第十四序列为[1,1i,-1i,-1],The fourteenth sequence is [1, 1i, -1i, -1],
第十五序列为[1,-1i,1i,-1],The fifteenth sequence is [1,-1i,1i,-1],
第十六序列为[1,-1i,-1i,1];The sixteenth sequence is [1,-1i,-1i,1];
序列集合3:Sequence Collection 3:
所述序列集合3,包含16条长度为4的序列,其中,The sequence set 3 includes 16 sequences of length 4, wherein
第一序列为[1,1,1,1i],The first sequence is [1,1,1,1i],
第二序列为[1,1,-1,-1i],The second sequence is [1,1,-1,-1i],
第三序列为[1,-1,1,-1i],The third sequence is [1,-1,1,-1i],
第四序列为[1,-1,-1,1i],The fourth sequence is [1,-1,-1,1i],
第五序列为[1,1,1i,1],The fifth sequence is [1,1,1i,1],
第六序列为[1,1,-1i,-1],The sixth sequence is [1,1,-1i,-1],
第七序列为[1,-1,1i,-1],The seventh sequence is [1,-1,1i,-1],
第八序列为[1,-1,-1i,1],The eighth sequence is [1,-1,-1i,1],
第九序列为[1,1i,1,1],The ninth sequence is [1, 1i, 1, 1],
第十序列为[1,1i,-1,-1],The tenth sequence is [1, 1i, -1, -1],
第十一序列为[1,-1i,1,-1],The eleventh sequence is [1,-1i,1,-1],
第十二序列为[1,-1i,-1,1],The twelfth sequence is [1,-1i,-1,1],
第十三序列为[1,1i,1i,-1i],The thirteenth sequence is [1, 1i, 1i, -1i],
第十四序列为[1,1i,-1i,1i], The fourteenth sequence is [1, 1i, -1i, 1i],
第十五序列为[1,-1i,1i,1i],The fifteenth sequence is [1,-1i,1i,1i],
第十六序列为[1,-1i,-1i,-1i];The sixteenth sequence is [1,-1i,-1i,-1i];
序列集合4:Sequence Collection 4:
所述序列集合4,包含16条长度为4的序列,其中,The sequence set 4 includes 16 sequences of length 4, wherein
第一序列为[1,1,1,-1i],The first sequence is [1,1,1,-1i],
第二序列为[1,1,-1,1i],The second sequence is [1,1,-1,1i],
第三序列为[1,-1,1,1i],The third sequence is [1,-1,1,1i],
第四序列为[1,-1,-1,-1i],The fourth sequence is [1,-1,-1,-1i],
第五序列为[1,1,1i,-1],The fifth sequence is [1,1,1i,-1],
第六序列为[1,1,-1i,1],The sixth sequence is [1,1,-1i,1],
第七序列为[1,-1,1i,1],The seventh sequence is [1,-1,1i,1],
第八序列为[1,-1,-1i,-1],The eighth sequence is [1,-1,-1i,-1],
第九序列为[1,1i,1,-1],The ninth sequence is [1, 1i, 1, -1],
第十序列为[1,1i,-1,1],The tenth sequence is [1, 1i, -1, 1],
第十一序列为[1,-1i,1,1],The eleventh sequence is [1,-1i,1,1],
第十二序列为[1,-1i,-1,-1],The twelfth sequence is [1,-1i,-1,-1],
第十三序列为[1,1i,1i,1i],The thirteenth sequence is [1, 1i, 1i, 1i],
第十四序列为[1,1i,-1i,-1i],The fourteenth sequence is [1, 1i, -1i, -1i],
第十五序列为[1,-1i,1i,-1i],The fifteenth sequence is [1,-1i,1i,-1i],
第十六序列为[1,-1i,-1i,1i];The sixteenth sequence is [1,-1i,-1i,1i];
序列集合5:Sequence Collection 5:
所述序列集合5,包含16条长度为4的序列,其中,The sequence set 5 includes 16 sequences of length 4, wherein
第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
第二序列为[1,1i,-1,-1i],The second sequence is [1, 1i, -1, -1i],
第三序列为[1,-1,1,-1],The third sequence is [1,-1,1,-1],
第四序列为[1,-1i,-1,1i], The fourth sequence is [1,-1i,-1,1i],
第五序列为[1,1,1i,-1i],The fifth sequence is [1,1,1i,-1i],
第六序列为[1,1i,-1i,-1],The sixth sequence is [1, 1i, -1i, -1],
第七序列为[1,-1,1i,1i],The seventh sequence is [1,-1,1i,1i],
第八序列为[1,-1i,-1i,1],The eighth sequence is [1,-1i,-1i,1],
第九序列为[1,1i,1,-1i],The ninth sequence is [1, 1i, 1, -1i],
第十序列为[1,-1,-1,-1],The tenth sequence is [1,-1,-1,-1],
第十一序列为[1,-1i,1,1i],The eleventh sequence is [1,-1i,1,1i],
第十二序列为[1,1,-1,1],The twelfth sequence is [1,1,-1,1],
第十三序列为[1,1i,1i,-1],The thirteenth sequence is [1, 1i, 1i, -1],
第十四序列为[1,-1,-1i,1i],The fourteenth sequence is [1,-1,-1i,1i],
第十五序列为[1,-1i,1i,1],The fifteenth sequence is [1,-1i,1i,1],
第十六序列为[1,1,-1i,-1i];The sixteenth sequence is [1,1,-1i,-1i];
第十七序列为[1,1,1,-1],The seventeenth sequence is [1,1,1,-1],
第十八序列为[1,1i,-1,1i],The eighteenth sequence is [1, 1i, -1, 1i],
第十九序列为[1,-1,1,1],The nineteenth sequence is [1,-1,1,1],
第二十序列为[1,-1i,-1,-1i],The twentieth sequence is [1,-1i,-1,-1i],
第二十一序列为[1,1,1i,1i],The twenty-first sequence is [1,1,1i,1i],
第二十二序列为[1,1i,-1i,1],The twenty-second sequence is [1, 1i, -1i, 1],
第二十三序列为[1,-1,1i,-1i],The twenty-third sequence is [1,-1,1i,-1i],
第二十四序列为[1,-1i,-1i,-1],The twenty-fourth sequence is [1,-1i,-1i,-1],
第二十五序列为[1,1i,1,1i],The twenty-fifth sequence is [1,1i,1,1i],
第二十六序列为[1,-1,-1,1],The twenty-sixth sequence is [1,-1,-1,1],
第二十七序列为[1,-1i,1,-1i],The twenty-seventh sequence is [1,-1i,1,-1i],
第二十八序列为[1,1,-1,-1],The twenty-eighth sequence is [1,1,-1,-1],
第二十九序列为[1,1i,1i,1],The twenty-ninth sequence is [1, 1i, 1i, 1],
第三十序列为[1,-1,-1i,-1i], The thirtieth sequence is [1,-1,-1i,-1i],
第三十一序列为[1,-1i,1i,-1],The thirty-first sequence is [1,-1i,1i,-1],
第三十二序列为[1,1,-1i,1i];The thirty-second sequence is [1,1,-1i,1i];
序列集合6:Sequence set 6:
所述序列集合6,包含32条长度为4的序列,其中,The sequence set 6 includes 32 sequences of length 4, wherein
第一序列为[1,1,1,1i],The first sequence is [1,1,1,1i],
第二序列为[1,1i,-1,1],The second sequence is [1, 1i, -1, 1],
第三序列为[1,-1,1,-1i],The third sequence is [1,-1,1,-1i],
第四序列为[1,-1i,-1,-1],The fourth sequence is [1,-1i,-1,-1],
第五序列为[1,1,1i,1],The fifth sequence is [1,1,1i,1],
第六序列为[1,1i,-1i,-1i],The sixth sequence is [1, 1i, -1i, -1i],
第七序列为[1,-1,1i,-1],The seventh sequence is [1,-1,1i,-1],
第八序列为[1,-1i,-1i,1i],The eighth sequence is [1,-1i,-1i,1i],
第九序列为[1,1i,1,1],The ninth sequence is [1, 1i, 1, 1],
第十序列为[1,-1,-1,-1i],The tenth sequence is [1,-1,-1,-1i],
第十一序列为[1,-1i,1,-1],The eleventh sequence is [1,-1i,1,-1],
第十二序列为[1,1,-1,i],The twelfth sequence is [1,1,-1,i],
第十三序列为[1,1i,1i,-1i],The thirteenth sequence is [1, 1i, 1i, -1i],
第十四序列为[1,-1,-1i,-1],The fourteenth sequence is [1,-1,-1i,-1],
第十五序列为[1,-1i,1i,i],The fifteenth sequence is [1,-1i,1i,i],
第十六序列为[1,1,-1i,1],The sixteenth sequence is [1,1,-1i,1],
第十七序列为[1,1,1,-1i],The seventeenth sequence is [1,1,1,-1i],
第十八序列为[1,1i,-1,-1],The eighteenth sequence is [1,1i,-1,-1],
第十九序列为[1,-1,1,1i],The nineteenth sequence is [1,-1,1,1i],
第二十序列为[1,-1i,-1,1],The twentieth sequence is [1,-1i,-1,1],
第二十一序列为[1,1,1i,-1],The twenty-first sequence is [1,1,1i,-1],
第二十二序列为[1,1i,-1i,1i], The twenty-second sequence is [1, 1i, -1i, 1i],
第二十三序列为[1,-1,1i,1],The twenty-third sequence is [1,-1,1i,1],
第二十四序列为[1,-1i,-1i,-1i],The twenty-fourth sequence is [1,-1i,-1i,-1i],
第二十五序列为[1,1i,1,-1],The twenty-fifth sequence is [1, 1i, 1, -1],
第二十六序列为[1,-1,-1,1i],The twenty-sixth sequence is [1,-1,-1,1i],
第二十七序列为[1,-1i,1,1],The twenty-seventh sequence is [1,-1i,1,1],
第二十八序列为[1,1,-1,-1i],The twenty-eighth sequence is [1,1,-1,-1i],
第二十九序列为[1,1i,1i,1i],The twenty-ninth sequence is [1, 1i, 1i, 1i],
第三十序列为[1,-1,-1i,1],The thirtieth sequence is [1,-1,-1i,1],
第三十一序列为[1,-1i,1i,-1i],The thirty-first sequence is [1,-1i,1i,-1i],
第三十二序列为[1,1,-1i,-1];The thirty-second sequence is [1, 1, -1i, -1];
序列集合7:Sequence collection 7:
所述序列集合7,包含4条长度为4的序列,其中,The sequence set 7 includes four sequences of length 4, wherein
第一序列为[1,0,0,0],The first sequence is [1,0,0,0],
第二序列为[0,1,0,0],The second sequence is [0,1,0,0],
第三序列为[0,0,1,0],The third sequence is [0,0,1,0],
第四序列为[0,0,0,1];The fourth sequence is [0,0,0,1];
序列集合8:Sequence set 8:
所述序列集合8,包含16条长度为6的序列,其中,The sequence set 8 includes 16 sequences of length 6, wherein
第一序列为[1,0,1,0,1,0],The first sequence is [1,0,1,0,1,0],
第二序列为[-1,0,1,0,-1,0],The second sequence is [-1,0,1,0,-1,0],
第三序列为[1,0,-1,0,-1,0],The third sequence is [1,0,-1,0,-1,0],
第四序列为[-1,0,-1,0,1,0],The fourth sequence is [-1,0,-1,0,1,0],
第五序列为[1,0,0,1,0,1],The fifth sequence is [1,0,0,1,0,1],
第六序列为[-1,0,0,1,0,-1],The sixth sequence is [-1,0,0,1,0,-1],
第七序列为[1,0,0,-1,0,-1],The seventh sequence is [1,0,0,-1,0,-1],
第八序列为[-1,0,0,-1,0,1], The eighth sequence is [-1,0,0,-1,0,1],
第九序列为[0,1,1,0,0,1],The ninth sequence is [0, 1, 1, 0, 0, 1],
第十序列为[0,-1,1,0,0,-1],The tenth sequence is [0, -1, 1, 0, 0, -1],
第十一序列为[0,1,-1,0,0,-1],The eleventh sequence is [0, 1, -1, 0, 0, -1],
第十二序列为[0,-1,-1,0,0,1],The twelfth sequence is [0,-1,-1,0,0,1],
第十三序列为[0,1,0,1,1,0],The thirteenth sequence is [0,1,0,1,1,0],
第十四序列为[0,-1,0,1,-1,0],The fourteenth sequence is [0, -1, 0, 1, -1, 0],
第十五序列为[0,1,0,-1,-1,0],The fifteenth sequence is [0,1,0,-1,-1,0],
第十六序列为[0,-1,0,-1,1,0];The sixteenth sequence is [0, -1, 0, -1, 1, 0];
序列集合9:Sequence set 9:
所述序列集合9,包含16条长度为6的序列,其中,The sequence set 9 includes 16 sequences of length 6, wherein
第一序列为[1,1,1,0,0,0],The first sequence is [1,1,1,0,0,0],
第二序列为[-1,1,-1,0,0,0],The second sequence is [-1,1,-1,0,0,0],
第三序列为[1,-1,-1,0,0,0],The third sequence is [1,-1,-1,0,0,0],
第四序列为[-1,-1,1,0,0,0],The fourth sequence is [-1,-1,1,0,0,0],
第五序列为[0,0,1,1,1,0],The fifth sequence is [0,0,1,1,1,0],
第六序列为[0,0,-1,-1,1,0],The sixth sequence is [0,0,-1,-1,1,0],
第七序列为[0,0,-1,1,-1,0],The seventh sequence is [0,0,-1,1,-1,0],
第八序列为[0,0,1,-1,-1,0],The eighth sequence is [0,0,1,-1,-1,0],
第九序列为[1,0,0,0,1,1],The ninth sequence is [1,0,0,0,1,1],
第十序列为[-1,0,0,0,1,-1],The tenth sequence is [-1,0,0,0,1,-1],
第十一序列为[1,0,0,0,-1,-1],The eleventh sequence is [1,0,0,0,-1,-1],
第十二序列为[-1,0,0,0,-1,1],The twelfth sequence is [-1,0,0,0,-1,1],
第十三序列为[0,1,0,1,0,1],The thirteenth sequence is [0, 1, 0, 1, 0, 1],
第十四序列为[0,1,0,-1,0,-1],The fourteenth sequence is [0,1,0,-1,0,-1],
第十五序列为[0,-1,0,1,0,-1],The fifteenth sequence is [0, -1, 0, 1, 0, -1],
第十六序列为[0,-1,0,-1,0,1]; The sixteenth sequence is [0, -1, 0, -1, 0, 1];
序列集合10:Sequence collection 10:
所述序列集合10,包含16条长度为6的序列,其中,The sequence set 10 includes 16 sequences of length 6, wherein
第一序列为[1,1,1,1,1,1],The first sequence is [1,1,1,1,1,1],
第二序列为[1,1,1,1,-1,-1],The second sequence is [1,1,1,1,-1,-1],
第三序列为[1,1,1,-1,1,-1],The third sequence is [1,1,1,-1,1,-1],
第四序列为[1,1,1,-1,-1,1],The fourth sequence is [1,1,1,-1,-1,1],
第五序列为[1,1,-1,1,1,-1],The fifth sequence is [1,1,-1,1,1,-1],
第六序列为[1,1,-1,1,-1,1],The sixth sequence is [1,1,-1,1,-1,1],
第七序列为[1,1,-1,-1,1,1],The seventh sequence is [1,1,-1,-1,1,1],
第八序列为[1,1,-1,-1,-1,-1],The eighth sequence is [1,1,-1,-1,-1,-1],
第九序列为[1,-1,1,1,1,-1],The ninth sequence is [1,-1,1,1,1,-1],
第十序列为[1,-1,1,1,-1,1],The tenth sequence is [1,-1,1,1,-1,1],
第十一序列为[1,-1,1,-1,1,1],The eleventh sequence is [1,-1,1,-1,1,1],
第十二序列为[1,-1,1,-1,-1,-1],The twelfth sequence is [1,-1,1,-1,-1,-1],
第十三序列为[1,-1,-1,1,1,1],The thirteenth sequence is [1,-1,-1,1,1,1],
第十四序列为[1,-1,-1,1,-1,-1],The fourteenth sequence is [1,-1,-1,1,-1,-1],
第十五序列为[1,-1,-1,-1,1,-1],The fifteenth sequence is [1,-1,-1,-1,1,-1],
第十六序列为[1,-1,-1,-1,-1,1];The sixteenth sequence is [1,-1,-1,-1,-1,1];
序列集合11:Sequence collection 11:
所述序列集合11,包含32条长度为4的序列,其中,The sequence set 11 includes 32 sequences of length 4, wherein
第一序列为[1+0i,1+0i,1+0i,1+0i],The first sequence is [1+0i, 1+0i, 1+0i, 1+0i],
第二序列为[1+0i,0+1i,-1+0i,-0-1i],The second sequence is [1+0i, 0+1i, -1+0i, -0-1i],
第三序列为[1+0i,-1+0i,1+0i,-1+0i],The third sequence is [1+0i, -1+0i, 1+0i, -1+0i],
第四序列为[1+0i,-0-1i,-1+0i,0+1i],The fourth sequence is [1+0i, -0-1i, -1+0i, 0+1i],
第五序列为[0+2i,-0-1i,0+2i,0+1i],The fifth sequence is [0+2i, -0-1i, 0+2i, 0+1i],
第六序列为[0+2i,1+0i,-0-2i,1+0i], The sixth sequence is [0+2i, 1+0i, -0-2i, 1+0i],
第七序列为[0+2i,0+1i,0+2i,-0-1i],The seventh sequence is [0+2i, 0+1i, 0+2i, -0-1i],
第八序列为[0+2i,-1+0i,-0-2i,-1+0i],The eighth sequence is [0+2i, -1+0i, -0-2i, -1+0i],
第九序列为[0+2i,-0-1i,-1+0i,2+0i],The ninth sequence is [0+2i, -0-1i, -1+0i, 2+0i],
第十序列为[0+2i,1+0i,1+0i-0-2i],The tenth sequence is [0+2i, 1+0i, 1+0i-0-2i],
第十一序列为[0+2i,0+1i,-1+0i,-2+0i],The eleventh sequence is [0+2i, 0+1i, -1+0i, -2+0i],
第十二序列为[0+2i,-1+0i,1+0i,0+2i],The twelfth sequence is [0+2i, -1+0i, 1+0i, 0+2i],
第十三序列为[0+2i,-0-1i,0+0i,-1+0i],The thirteenth sequence is [0+2i, -0-1i, 0+0i, -1+0i],
第十四序列为[0+2i,1+0i,0+0i,0+1i],The fourteenth sequence is [0+2i, 1+0i, 0+0i, 0+1i],
第十五序列为[0+2i,0+1i,0+0i,1+0i],The fifteenth sequence is [0+2i, 0+1i, 0+0i, 1+0i],
第十六序列为[0+2i,-1+0i,0+0i,-0-1i],The sixteenth sequence is [0+2i, -1+0i, 0+0i, -0-1i],
第十七序列为[-1+0i,-0-1i,-0-2i,-2+0i],The seventeenth sequence is [-1+0i, -0-1i, -0-2i, -2+0i],
第十八序列为[-1+0i,1+0i,0+2i,0+2i],The eighteenth sequence is [-1+0i, 1+0i, 0+2i, 0+2i],
第十九序列为[-1+0i,0+1i,-0-2i,2+0i],The nineteenth sequence is [-1+0i, 0+1i, -0-2i, 2+0i],
第二十序列为[-1+0i,-1+0i,0+2i,-0-2i],The twentieth sequence is [-1+0i, -1+0i, 0+2i, -0-2i],
第二十一序列为[-1+0i,-2+0i,0+2i,0+1i],The twenty-first sequence is [-1+0i, -2+0i, 0+2i, 0+1i],
第二十二序列为[-1+0i,-0-2i,-0-2i,1+0i],The twenty-second sequence is [-1+0i,-0-2i,-0-2i, 1+0i],
第二十三序列为[-1+0i,2+0i,0+2i,-0-1i],The twenty-third sequence is [-1+0i, 2+0i, 0+2i, -0-1i],
第二十四序列为[-1+0i,0+2i,-0-2i,-1+0i],The twenty-fourth sequence is [-1+0i, 0+2i, -0-2i, -1+0i],
第二十五序列为[-1+0i,-2+0i,1+0i,-2+0i],The twenty-fifth sequence is [-1+0i, -2+0i, 1+0i, -2+0i],
第二十六序列为[-1+0i,-0-2i,-1+0i,0+2i],The twenty-sixth sequence is [-1+0i, -0-2i, -1+0i, 0+2i],
第二十七序列为[-1+0i,2+0i,1+0i,2+0i],The twenty-seventh sequence is [-1+0i, 2+0i, 1+0i, 2+0i],
第二十八序列为[-1+0i,0+2i,-1+0i,-0-2i],The twenty-eighth sequence is [-1+0i, 0+2i, -1+0i, -0-2i],
第二十九序列为[-1+0i,-2+0i,-0-1i,0+0i],The twenty-ninth sequence is [-1+0i, -2+0i, -0-1i, 0+0i],
第三十序列为[-1+0i,-0-2i,0+1i,0+0i],The thirtieth sequence is [-1+0i,-0-2i, 0+1i, 0+0i],
第三十一序列为[-1+0i,2+0i,-0-1i,0+0i],The thirty-first sequence is [-1+0i, 2+0i, -0-1i, 0+0i],
第三十二序列为[-1+0i,0+2i,0+1i,0+0i]; The thirty-second sequence is [-1+0i, 0+2i, 0+1i, 0+0i];
其中,i为虚数单位,i=sqrt(-1);Where i is an imaginary unit, i=sqrt(-1);
对序列集合1、序列集合2、序列集合3、序列集合4、序列集合5、序列集合6、序列集合7、序列集合8、序列集合9、序列集合10、序列集合11这十一个序列集合中的序列,分别进行下述任一处理得到的集合:11 sequence sets of sequence set 1, sequence set 2, sequence set 3, sequence set 4, sequence set 5, sequence set 6, sequence set 7, sequence set 8, sequence set 9, sequence set 10, sequence set 11 The sequence in the process, respectively, is a collection obtained by any of the following processes:
其中,所述任一处理,包括:Wherein, any of the processes described includes:
对序列集合中的每条序列或每条序列的第S个序列元素乘以1、1i、-1、或-1i,或者乘以1i的Q次方;或者,Multiply the S-th sequence element of each sequence or each sequence in the sequence set by 1, 1i, -1, or -1i, or multiply by the Q-th power of 1i; or,
对序列集合中的每条序列或每条序列的第S个序列元素进行R*π的相位调整或旋转,或者,乘以exp(j*R*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of R*π for each sequence in the sequence set or the Sth sequence element of each sequence, or multiply exp(j*R*π), j is an imaginary unit, j=sqrt( -1); or,
对序列集合中的每条序列或每条序列的第S个序列元素乘以指定值,或者分别乘以指定值;Multiplying each sequence in the sequence set or the Sth sequence element of each sequence by a specified value, or multiplying by a specified value;
其中,S为大于或等于1且小于或等于W的整数,Q为整数,R为实数。Wherein S is an integer greater than or equal to 1 and less than or equal to W, Q is an integer, and R is a real number.
本发明实施例中,可选地,所述确定单元从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,In the embodiment of the present invention, optionally, the determining unit determines the third sequence from a third sequence set, and the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set. ,
所述确定单元还配置为通过以下至少之一方式根据所述第一序列集合和所述第二序列集合得到的序列集合:The determining unit is further configured to obtain a sequence set according to the first sequence set and the second sequence set by at least one of:
所述第一序列集合中的任意一条序列与所述第二序列集合中的任意一条序列进行点乘处理得到的序列构成的序列集合;a sequence set formed by a sequence obtained by performing dot multiplication processing on any one of the first sequence set and any one of the second sequence sets;
所述第一序列集合中的任意一条序列与所述第二序列集合中的任意一条序列进行乘法处理得到的序列构成的序列集合;a sequence set formed by a sequence obtained by multiplying any one of the first sequence set and any one of the second sequence sets;
所述第一序列集合中的任意一条序列的元素替换所述第二序列集合中的任意一条序列的非零元素得到的序列构成的序列集合;And deleting, by the element of any one of the first sequence sets, a sequence set formed by a sequence obtained by replacing a non-zero element of any one of the second sequence sets;
所述第一序列集合中的任意一条序列的元素与所述第二序列集合中的任意一条序列的非零元素进行点乘处理得到的序列构成的序列集合。 a sequence set formed by a sequence obtained by performing dot multiplication processing on an element of any one of the first sequence sets and a non-zero element of any one of the second sequence sets.
本发明实施例中,可选地,所述确定单元根据第一序列和第二序列确定第三序列时,或者In the embodiment of the present invention, optionally, the determining unit determines the third sequence according to the first sequence and the second sequence, or
从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,Determining the third sequence from a third sequence set, and the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set,
所述确定单元还配置为通过以下之一方式从第一序列集合中获取第一序列:The determining unit is further configured to obtain the first sequence from the first sequence set by one of:
采用随机选择的方式从所述第一序列集合中获取第一序列;Obtaining the first sequence from the first sequence set in a random selection manner;
根据第一预设规则从所述第一序列集合中获取第一序列;Obtaining a first sequence from the first sequence set according to a first preset rule;
根据系统配置信息从所述第一序列集合中获取第一序列。Acquiring the first sequence from the first sequence set according to system configuration information.
本发明实施例中,可选地,所述确定单元根据第一序列和第二序列确定第三序列时,或者,从第三序列集合中确定所述第三序列,且所述第三序列集合包括第二指定序列集合、对第二指定序列集合进行处理得到的序列集合、根据第一序列集合和第二序列集合得到的序列集合至少之一时,In the embodiment of the present invention, optionally, the determining unit determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set And including a second specified sequence set, a sequence set obtained by processing the second specified sequence set, and at least one of the sequence set obtained according to the first sequence set and the second sequence set,
所述确定单元,还配置为通过包括下述之一方式从第二序列集合中获取第二序列:The determining unit is further configured to obtain the second sequence from the second sequence set by one of:
采用随机选择的方式从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second set of sequences in a randomly selected manner;
根据第二预设规则从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second sequence set according to a second preset rule;
根据系统配置信息从所述第二序列集合中获取第二序列。Obtaining a second sequence from the second set of sequences according to system configuration information.
本发明实施例中,可选地,所述确定单元根据第一序列和第二序列确定第三序列时,还配置为:In the embodiment of the present invention, optionally, when the determining unit determines the third sequence according to the first sequence and the second sequence, the determining unit is further configured to:
将所述第一序列与所述第二序列进行点乘处理,生成第三序列;或者,Performing point-multiplication processing on the first sequence and the second sequence to generate a third sequence; or
将所述第一序列与所述第二序列进行乘法处理,生成第三序列;或者,Multiplying the first sequence and the second sequence to generate a third sequence; or
使用所述第一序列中的元素替换所述第二序列中的非零元素,生成第三序列;或者,Substituting an element in the first sequence for a non-zero element in the second sequence to generate a third sequence; or
将所述第一序列中的元素与所述第二序列中的非零元素进行点乘处理后得到的值替换所述第二序列中的非零元素,生成第三序列。 Substituting a value obtained by dot-multiplying an element in the first sequence with a non-zero element in the second sequence to replace a non-zero element in the second sequence to generate a third sequence.
本发明实施例中,可选地,所述确定单元从第三序列集合中确定所述第三序列时,还配置为:In the embodiment of the present invention, optionally, when the determining unit determines the third sequence from the third sequence set, the determining unit is further configured to:
采用随机选择的方式从所述第三序列集合中获取所述第三序列;Obtaining the third sequence from the third sequence set in a randomly selected manner;
根据第三预设规则从所述第三序列集合中获取所述第三序列;Obtaining the third sequence from the third sequence set according to a third preset rule;
根据系统配置信息从所述第三序列集合中获取所述第三序列。Obtaining the third sequence from the third sequence set according to system configuration information.
本发明实施例中,可选地,所述装置还包括归一化处理单元,其中,In an embodiment of the present invention, optionally, the apparatus further includes a normalization processing unit, where
在所述确定单元根据第一序列和第二序列确定第三序列时,或者,从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,所述归一化处理单元,配置为:When the determining unit determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set includes according to the first sequence set and the second sequence When the sequence set is obtained by the sequence set, the normalization processing unit is configured to:
对所述第一序列集合中的序列进行能量调整或能量归一化处理;或Performing energy adjustment or energy normalization on the sequences in the first set of sequences; or
对所述第一序列进行能量调整或能量归一化处理;或Performing energy adjustment or energy normalization on the first sequence; or
对所述第三序列进行能量调整或能量归一化处理;Performing energy adjustment or energy normalization on the third sequence;
在所述确定单元从第三序列集合中确定所述第三序列,且所述第三序列集合不包括根据第一序列集合和第二序列集合得到的序列集合时,所述归一化处理单元,配置为:When the determining unit determines the third sequence from the third sequence set, and the third sequence set does not include the sequence set obtained according to the first sequence set and the second sequence set, the normalization processing unit , configured as:
对所述第三序列进行能量调整或能量归一化处理。The third sequence is subjected to energy adjustment or energy normalization.
本发明实施例中,可选地,所述确定单元,还配置为:In the embodiment of the present invention, optionally, the determining unit is further configured to:
对所述第三序列的每个元素或第V个元素乘以1、1i、-1、或-1i,或者,乘以1i的G次方;或者,Multiplying each element or the Vth element of the third sequence by 1, 1i, -1, or -1i, or multiplying by the G of 1i; or
对所述第三序列的每个元素或第V个元素进行H*π的相位调整或旋转,或者,乘以exp(j*H*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of H*π for each element or Vth element of the third sequence, or multiply exp(j*H*π), j is an imaginary unit, j=sqrt(-1) ;or,
对所述第三序列的每个元素或第V个元素乘以指定值;Multiplying each element or the Vth element of the third sequence by a specified value;
其中,V为大于或等于1且小于或等于所述第三序列的长度的整数,G为整数,H为实数。Wherein V is an integer greater than or equal to 1 and less than or equal to the length of the third sequence, G is an integer, and H is a real number.
本发明实施例中,可选地,所述生成单元,还配置为:In the embodiment of the present invention, optionally, the generating unit is further configured to:
使用所述第三序列对第一数据进行扩展处理生成第二数据;或, And expanding, by using the third sequence, the first data to generate second data; or
使用所述第三序列对第一数据进行映射处理生成第二数据;或,Performing mapping processing on the first data by using the third sequence to generate second data; or
使用所述第三序列对第一数据进行调制处理生成第二数据。The first data is modulated using the third sequence to generate second data.
本发明实施例中,可选地,所述装置还包括:In the embodiment of the present invention, optionally, the device further includes:
映射单元,配置为将所述第二数据映射到指定的传输资源上,用于形成发射信号以及发送。a mapping unit configured to map the second data onto a designated transmission resource for forming a transmit signal and transmitting.
本发明实施例中,可选地,In the embodiment of the present invention, optionally,
所述第一数据至少包含发射机或终端的身份标识信息;或者,The first data includes at least identifier information of a transmitter or a terminal; or
至少包含有发射机或终端的身份标识信息和信令信息;或者,Containing at least the identity information and signaling information of the transmitter or terminal; or,
至少包含有发射机或终端的身份标识信息和数据信息;或者,Include at least the identity information and data information of the transmitter or terminal; or,
至少包含有发射机或终端的身份标识信息、信令信息和数据信息;或者,Containing at least the identity information, signaling information, and data information of the transmitter or terminal; or,
至少包含有发射机或终端的身份标识信息和小区标识信息;或者,At least the identity information and the cell identification information of the transmitter or the terminal are included; or
至少包含有发射机或终端的身份标识信息、小区标识信息和信令信息;或者,Include at least the identity information, cell identification information, and signaling information of the transmitter or the terminal; or,
至少包含有发射机或终端的身份标识信息、小区标识信息和数据信息;或者,Include at least the identity information, cell identification information, and data information of the transmitter or the terminal; or,
至少包含有发射机或终端的身份标识信息、小区标识信息、数据信息和信令信息。At least the identity information, cell identification information, data information and signaling information of the transmitter or the terminal are included.
本发明实施例中,可选地,In the embodiment of the present invention, optionally,
第二数据至少包含发射机或终端的身份标识信息;The second data includes at least the identity information of the transmitter or the terminal;
或者,至少包含有发射机或终端的身份标识信息和信令信息;Or at least including identity information and signaling information of the transmitter or the terminal;
或者,至少包含有发射机或终端的身份标识信息和数据信息;Or at least the identity information and the data information of the transmitter or the terminal;
或者,至少包含有发射机或终端的身份标识信息、信令信息和数据信息;或者,Or at least the identity information, signaling information, and data information of the transmitter or the terminal; or,
至少包含有发射机或终端的身份标识信息和小区标识信息;或者,At least the identity information and the cell identification information of the transmitter or the terminal are included; or
至少包含有发射机或终端的身份标识信息、小区标识信息和信令信息; 或者,At least the identity information, the cell identification information and the signaling information of the transmitter or the terminal are included; or,
至少包含有发射机或终端的身份标识信息、小区标识信息和数据信息;或者,Include at least the identity information, cell identification information, and data information of the transmitter or the terminal; or,
至少包含有发射机或终端的身份标识信息、小区标识信息、数据信息和信令信息。At least the identity information, cell identification information, data information and signaling information of the transmitter or the terminal are included.
本发明实施例中,可选地,所述指定的传输资源包括下述至少之一:载波、时隙、时频资源、空域资源、码域资源、跳频模式、天线端口。In the embodiment of the present invention, optionally, the specified transmission resource includes at least one of the following: a carrier, a time slot, a time-frequency resource, an airspace resource, a code domain resource, a frequency hopping mode, and an antenna port.
本发明实施例中,可选地,所述时频资源为上行数据信道,或者上行控制信道,或者随机接入信道。In the embodiment of the present invention, optionally, the time-frequency resource is an uplink data channel, or an uplink control channel, or a random access channel.
本发明实施例中,可选地,所述第一数据包括以下至少之一信息:车况信息、驾驶员的操作信息,车辆传感器所感知的信息和控制信令;其中,所述车况信息包括以下至少之一:车辆工具标识、所述车辆当前地理位置、所述车辆的行驶速度、所述车辆的大小、所述车辆的颜色;所述操作信息包括以下至少之一:所述驾驶员对所述车辆正在进行的操作,所述驾驶员准备对所述车辆进行的操作。In the embodiment of the present invention, optionally, the first data includes at least one of the following: vehicle condition information, driver operation information, information sensed by the vehicle sensor, and control signaling; wherein the vehicle condition information includes the following: At least one of: a vehicle tool identification, a current geographic location of the vehicle, a traveling speed of the vehicle, a size of the vehicle, a color of the vehicle; the operational information comprising at least one of: the driver's office The ongoing operation of the vehicle, the driver preparing an operation on the vehicle.
再一方面,本发明实施例还提供了一种设备,所述设备包括处理器以及存储有所述处理器可执行指令的存储器,当所述指令被处理器执行时,执行如下操作:In still another aspect, an embodiment of the present invention further provides an apparatus, where the apparatus includes a processor and a memory storing the processor executable instructions, and when the instructions are executed by the processor, performing the following operations:
根据第一序列和第二序列确定第三序列,其中,所述第一序列从第一序列集合中获取,所述第二序列从第二序列集合中获取;或者,从第三序列集合中确定所述第三序列;Determining a third sequence according to the first sequence and the second sequence, wherein the first sequence is obtained from a first sequence set, the second sequence is obtained from a second sequence set; or, determined from a third sequence set The third sequence;
使用所述第三序列对第一数据进行处理生成第二数据;Processing the first data by using the third sequence to generate second data;
其中,所述第一序列集合包括包含M条长度为L的序列的第一指定序列集合、和/或对所述第一指定序列集合进行处理得到的序列集合;The first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set;
其中,所述第二序列集合包括包含N条长度为C的序列的第二指定序列集合、和/或对所述第二指定序列集合进行处理得到的序列集合; The second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set;
其中,所述第三序列集合包括以下至少之一:包含P条长度为W的序列的第三指定序列集合;所述第二指定序列集合;对所述第二指定序列集合进行处理得到的序列集合;根据所述第一序列集合和所述第二序列集合得到的序列集合;The third sequence set includes at least one of: a third specified sequence set including P sequences of length W; the second specified sequence set; and a sequence obtained by processing the second specified sequence set a set of sequences obtained from the first set of sequences and the second set of sequences;
其中,M、L、N、C、P、W为正整数。Among them, M, L, N, C, P, and W are positive integers.
本发明实施例中,可选地,所述处理器根据第一序列和第二序列确定第三序列时所述第一指定序列集合中的序列元素的取值,或者,从第三序列集合中确定所述第三序列时所述第三指定序列集合中的序列元素的取值,均来自于以下集合至少之一:In an embodiment of the present invention, optionally, the determining, by the processor, the value of the sequence element in the first specified sequence set when determining the third sequence according to the first sequence and the second sequence, or from the third sequence set Determining the value of the sequence element in the third specified sequence set when determining the third sequence is from at least one of the following sets:
{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,-1+1i,-1-1i,1-1i};{0};{1,1i,-1,-1i,0};{1+1i,-1+1i,-1-1i,1-1i,0};{1,1i,-1,-1i,2,2i,-2,-2i,0};其中,i为虚数单位,i=sqrt(-1)。{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,- 1+1i, -1-1i, 1-1i}; {0}; {1, 1i, -1, -1i, 0}; {1+1i, -1+1i, -1-1i, 1-1i , 0}; {1, 1i, -1, -1i, 2, 2i, -2, -2i, 0}; where i is an imaginary unit and i = sqrt(-1).
本发明实施例中,可选地,所述处理器根据第一序列和第二序列确定第三序列时,或者,从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,还配置为:In the embodiment of the present invention, optionally, when the processor determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set When the sequence set obtained according to the first sequence set and the second sequence set is included, it is further configured as:
对所述第一序列集合中的序列进行能量调整或能量归一化处理;或Performing energy adjustment or energy normalization on the sequences in the first set of sequences; or
对所述第一序列进行能量调整或能量归一化处理;或Performing energy adjustment or energy normalization on the first sequence; or
对所述第三序列进行能量调整或能量归一化处理;Performing energy adjustment or energy normalization on the third sequence;
所述处理器从第三序列集合中确定所述第三序列,且所述第三序列集合不包括根据第一序列集合和第二序列集合得到的序列集合时,还配置为:When the processor determines the third sequence from the third sequence set, and the third sequence set does not include the sequence set obtained according to the first sequence set and the second sequence set, the processor is further configured to:
对所述第三序列进行能量调整或能量归一化处理。The third sequence is subjected to energy adjustment or energy normalization.
本发明实施例中,可选地,所述处理器还配置为对所述第三序列的每个元素或第V个元素乘以1、1i、-1、或-1i,或者,乘以1i的G次方;或者,In an embodiment of the present invention, optionally, the processor is further configured to multiply each element or the Vth element of the third sequence by 1, 1i, -1, or -1i, or multiply by 1i. Gth power; or,
对所述第三序列的每个元素或第V个元素进行H*π的相位调整或旋转, 或者,乘以exp(j*H*π),j为虚数单位,j=sqrt(-1);或者,Performing phase adjustment or rotation of H*π for each element or the Vth element of the third sequence, Or, multiply exp(j*H*π), j is the imaginary unit, j=sqrt(-1); or,
对所述第三序列的每个元素或第V个元素乘以指定值;Multiplying each element or the Vth element of the third sequence by a specified value;
其中,V为大于或等于1且小于或等于所述第三序列的长度的整数,G为整数,H为实数。Wherein V is an integer greater than or equal to 1 and less than or equal to the length of the third sequence, G is an integer, and H is a real number.
本发明实施例中,可选地,所述处理器还配置为使用所述第三序列对第一数据进行扩展处理生成第二数据;或,In the embodiment of the present invention, optionally, the processor is further configured to perform the expansion process on the first data to generate the second data by using the third sequence; or
使用所述第三序列对第一数据进行映射处理生成第二数据;或,Performing mapping processing on the first data by using the third sequence to generate second data; or
使用所述第三序列对第一数据进行调制处理生成第二数据。The first data is modulated using the third sequence to generate second data.
本发明实施例中,可选地,所述处理器还配置为将所述第二数据映射到指定的传输资源上,用于形成发射信号以及发送。In an embodiment of the present invention, optionally, the processor is further configured to map the second data to a specified transmission resource, for forming a transmission signal and transmitting.
又一方面,本发明实施例还提供了一种计算机存储介质,所述计算机存储介质中存储有计算机可执行指令,所述计算机可执行指令用于执行本发明实施例所述的数据生成方法。In another aspect, an embodiment of the present invention further provides a computer storage medium, where the computer storage medium stores computer executable instructions, and the computer executable instructions are used to execute the data generation method according to the embodiment of the present invention.
本发明实施例的技术方案中,根据第一序列和第二序列确定第三序列,其中,所述第一序列从第一序列集合中获取,所述第二序列从第二序列集合中获取;或者,从第三序列集合中确定所述第三序列;使用所述第三序列对第一数据进行处理生成第二数据;其中,所述第一序列集合包括包含M条长度为L的序列的第一指定序列集合、和/或对所述第一指定序列集合进行处理得到的序列集合;其中,所述第二序列集合包括包含N条长度为C的序列的第二指定序列集合、和/或对所述第二指定序列集合进行处理得到的序列集合;其中,所述第三序列集合包括以下至少之一:包含P条长度为W的序列的第三指定序列集合;所述第二指定序列集合;对所述第二指定序列集合进行处理得到的序列集合;根据所述第一序列集合和所述第二序列集合得到的序列集合;其中,M、L、N、C、P、W为正整数。通过本发明实施例提出的数据生成方法,能够用于实现免调度传输,并且,具有较低的序列存储需求和运算复杂度。 In the technical solution of the embodiment of the present invention, the third sequence is determined according to the first sequence and the second sequence, where the first sequence is obtained from the first sequence set, and the second sequence is obtained from the second sequence set; Or determining the third sequence from the third sequence set; processing the first data by using the third sequence to generate second data; wherein the first sequence set comprises M sequences of length L a first specified sequence set, and/or a sequence set obtained by processing the first specified sequence set; wherein the second sequence set comprises a second specified sequence set comprising N sequences of length C, and/ Or a sequence set obtained by processing the second specified sequence set; wherein the third sequence set includes at least one of: a third specified sequence set including a P-length W sequence; the second designation a sequence set; a sequence set obtained by processing the second specified sequence set; a sequence set obtained according to the first sequence set and the second sequence set; wherein, M, L , N, C, P, W are positive integers. The data generation method proposed by the embodiment of the present invention can be used to implement scheduling-free transmission, and has lower sequence storage requirements and computational complexity.
附图说明DRAWINGS
图1为本发明实施例的一种数据生成方法的流程示意图;FIG. 1 is a schematic flowchart diagram of a data generating method according to an embodiment of the present invention;
图2为本发明实施例的数据生成方法的一种应用示意图;2 is a schematic diagram of an application of a data generating method according to an embodiment of the present invention;
图3为本发明实施例的序列元素集合的一种示意图;3 is a schematic diagram of a sequence element set according to an embodiment of the present invention;
图4为本发明实施例的数据生成方法的另一种应用示意图;FIG. 4 is a schematic diagram of another application of a data generating method according to an embodiment of the present invention; FIG.
图5为本发明实施例的序列元素集合的另一种示意图;FIG. 5 is another schematic diagram of a sequence element set according to an embodiment of the present invention; FIG.
图6为本发明实施例的序列元素集合的又一种示意图;FIG. 6 is still another schematic diagram of a sequence element set according to an embodiment of the present invention; FIG.
图7为本发明实施例的另一种数据生成方法的流程示意图;FIG. 7 is a schematic flowchart diagram of another data generating method according to an embodiment of the present invention;
图8为本发明实施例的一种数据传输方法的流程示意图;FIG. 8 is a schematic flowchart diagram of a data transmission method according to an embodiment of the present invention;
图9为本发明实施例的一种数据生成装置的结构组成示意图;FIG. 9 is a schematic structural diagram of a data generating apparatus according to an embodiment of the present invention; FIG.
图10为本发明实施例的数据生成装置的硬件组成结构示意图。FIG. 10 is a schematic structural diagram of hardware components of a data generating apparatus according to an embodiment of the present invention.
具体实施方式detailed description
为了能够更加详尽地了解本发明实施例的特点与技术内容,下面结合附图对本发明实施例的实现进行详细阐述,所附附图仅供参考说明之用,并非用来限定本发明实施例。The embodiments of the present invention are described in detail below with reference to the accompanying drawings.
需要说明的是,在不冲突的情况下,本申请中的实施例及实施例中的特征可以相互组合。It should be noted that the embodiments in the present application and the features in the embodiments may be combined with each other without conflict.
需要说明的是,本发明的说明书和权利要求书及上述附图中的术语“第一”、“第二”等是用于区别类似的对象,并不一定用于描述特定的顺序或先后次序。It should be noted that the terms "first", "second" and the like in the specification and claims of the present invention and the above-mentioned drawings are used to distinguish similar objects, and are not necessarily used to describe a specific order or order. .
实施例一 Embodiment 1
本发明实施例提供了一种数据生成方法,应用于终端侧或基站侧,如图1所示,所述数据生成方法包括以下步骤:The embodiment of the present invention provides a data generating method, which is applied to a terminal side or a base station side. As shown in FIG. 1 , the data generating method includes the following steps:
步骤101:根据第一序列和第二序列确定第三序列,其中,所述第一序列从第一序列集合中获取,所述第二序列从第二序列集合中获取;或者, 从第三序列集合中确定所述第三序列。Step 101: Determine a third sequence according to the first sequence and the second sequence, where the first sequence is obtained from a first sequence set, and the second sequence is obtained from a second sequence set; or The third sequence is determined from a third set of sequences.
其中,所述第一序列集合包括包含M条长度为L的序列的第一指定序列集合、和/或对所述第一指定序列集合进行处理得到的序列集合;The first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set;
其中,所述第二序列集合包括包含N条长度为C的序列的第二指定序列集合、和/或对所述第二指定序列集合进行处理得到的序列集合;The second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set;
其中,所述第三序列集合包括以下至少之一:包含P条长度为W的序列的第三指定序列集合;所述第二指定序列集合;对所述第二指定序列集合进行处理得到的序列集合;根据所述第一序列集合和所述第二序列集合得到的序列集合;The third sequence set includes at least one of: a third specified sequence set including P sequences of length W; the second specified sequence set; and a sequence obtained by processing the second specified sequence set a set of sequences obtained from the first set of sequences and the second set of sequences;
其中,M、L、N、C、P、W为正整数。Among them, M, L, N, C, P, and W are positive integers.
这里,第三序列至少有两种确定方式,一种是根据第一序列和第二序列确定第三序列,其中,所述第一序列来自于第一序列集合,所述第二序列来自于第二序列集合;另一种是从第三序列集合中确定所述第三序列。Here, the third sequence has at least two determination manners, one is to determine a third sequence according to the first sequence and the second sequence, wherein the first sequence is from the first sequence set, and the second sequence is from the first sequence The second sequence set; the other is to determine the third sequence from the third sequence set.
可选地,所述第一指定序列集合或所述第三指定序列集合中的序列元素的取值来自于以下集合至少之一:{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,-1+1i,-1-1i,1-1i};{0};{1,1i,-1,-1i,0};{1+1i,-1+1i,-1-1i,1-1i,0};{1,1i,-1,-1i,2,2i,-2,-2i,0};其中,i为虚数单位,i=sqrt(-1)。Optionally, the value of the sequence element in the first specified sequence set or the third specified sequence set is from at least one of the following sets: {1, 1i, -1, -1i}; {1,- 1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,-1+1i,-1-1i,1-1i};{0 };{1,1i,-1,-1i,0}; {1+1i,-1+1i,-1-1i,1-1i,0}; {1,1i,-1,-1i,2 , 2i, -2, -2i, 0}; where i is an imaginary unit and i = sqrt(-1).
可选地,所述对所述第一指定序列集合中的序列进行处理,包括:Optionally, the processing the sequence in the first specified sequence set includes:
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素乘以1、1i、-1、或-1i,或者乘以1i的A次方;或者,Multiplying the Xth sequence element of each sequence or each sequence in the first specified sequence set by 1, 1i, -1, or -1i, or multiplying by the 1st power of A; or
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素进行B*π的相位调整或旋转,或者乘以exp(j*B*π),j为虚数单位,j=sqrt(-1);或者,Performing B*π phase adjustment or rotation for each sequence in the first specified sequence set or the Xth sequence element of each sequence, or multiplying exp(j*B*π), j is an imaginary unit, j=sqrt(-1); or,
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素乘以指定值,或者分别乘以指定值; Multiplying the Xth sequence element of each sequence or each sequence in the first specified sequence set by a specified value, or multiplying by a specified value;
其中,X为大于或等于1且小于或等于L的整数,A为整数,B为实数;Where X is an integer greater than or equal to 1 and less than or equal to L, A is an integer, and B is a real number;
其中,X可以为大于或等于1且小于或等于L的多个值。Wherein X may be a plurality of values greater than or equal to 1 and less than or equal to L.
可选地,所述第二指定序列集合包括以下至少之一:Optionally, the second specified sequence set includes at least one of the following:
哈达玛(Hadamard)序列集合;Hadamard sequence set;
沃尔什(Walsh)序列集合;Walsh sequence collection;
离散傅里叶变换(Discrete Fourier Transform,DFT)序列集合;Discrete Fourier Transform (DFT) sequence set;
包含指定数量或指定比例的0元素的序列的集合;a collection of sequences containing a specified number or a specified proportion of 0 elements;
单位矩阵序列集合。A collection of unit matrix sequences.
可选地,所述对所述第二指定序列集合中的序列进行处理,包括:Optionally, the processing the sequence in the second specified sequence set includes:
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素乘以1、1i、-1、或-1i,或者,乘以1i的E次方;或者,Multiplying the Yth sequence element of each sequence or each sequence in the second specified sequence set by 1, 1i, -1, or -1i, or multiplying by the E-th power of 1i; or
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素进行F*π的相位调整或旋转,或者,乘以exp(j*F*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of F*π for each sequence in the second specified sequence set or the Yth sequence element of each sequence, or multiply exp(j*F*π), j is an imaginary unit , j=sqrt(-1); or,
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素乘以指定值,或者分别乘以指定值;Multiplying each of the sequence of the second specified sequence set or the Yth sequence element of each sequence by a specified value, or multiplying by a specified value;
其中,Y为大于或等于1且小于或等于C的整数,E为整数,F为实数;Wherein Y is an integer greater than or equal to 1 and less than or equal to C, E is an integer, and F is a real number;
其中,Y可以为大于或等于1且小于或等于C的多个值。Wherein Y may be a plurality of values greater than or equal to 1 and less than or equal to C.
可选地,所述根据所述第一序列集合和所述第二序列集合得到的序列集合,包括以下至少之一:Optionally, the sequence set obtained according to the first sequence set and the second sequence set includes at least one of the following:
所述第一序列集合中的任意一条序列与所述第二序列集合中的任意一条序列进行点乘处理得到的序列构成的序列集合;这里,两条序列点乘运算是指两条序列相同位置的元素相乘;例如序列a=(a1,a2,a3,a4);序列b=(b1,b2,b3,b4),则序列a与序列b的点乘运算结果是(a1*b1,a2*b2,a3*b3,a4*b4);一般来说,L=C; a sequence set formed by a sequence obtained by performing a dot multiplication process on any one of the first sequence set and any one of the second sequence sets; here, the two sequence point multiplication operations refer to the same position of the two sequences The elements are multiplied; for example, the sequence a = (a1, a2, a3, a4); the sequence b = (b1, b2, b3, b4), then the point multiplication of sequence a and sequence b is (a1*b1, a2) *b2, a3*b3, a4*b4); in general, L=C;
所述第一序列集合中的任意一条序列与所述第二序列集合中的任意一条序列进行乘法处理得到的序列构成的序列集合;a sequence set formed by a sequence obtained by multiplying any one of the first sequence set and any one of the second sequence sets;
所述第一序列集合中的任意一条序列的元素替换所述第二序列集合中的任意一条序列的非零元素得到的序列构成的序列集合;And deleting, by the element of any one of the first sequence sets, a sequence set formed by a sequence obtained by replacing a non-zero element of any one of the second sequence sets;
所述第一序列集合中的任意一条序列的元素与所述第二序列集合中的任意一条序列的非零元素进行点乘处理得到的序列构成的序列集合。a sequence set formed by a sequence obtained by performing dot multiplication processing on an element of any one of the first sequence sets and a non-zero element of any one of the second sequence sets.
需要说明的是,根据第一序列和第二序列确定第三序列;如何根据所述第一序列集合和所述第二序列集合得到第三序列集合,本质上仍然是第一序列和第二序列之间的操作;It should be noted that the third sequence is determined according to the first sequence and the second sequence; how to obtain the third sequence set according to the first sequence set and the second sequence set, which is still the first sequence and the second sequence in essence Operation between
因此,序列点乘主要是第一序列和第二序列之间的操作,可以不涉及W;Therefore, the sequence point multiplication is mainly an operation between the first sequence and the second sequence, and may not involve W;
如果是第一序列和第二序列点乘,则要求L=C;If it is the first sequence and the second sequence point multiplication, then L=C is required;
如果是第一序列和“第二序列的非零元素”点乘,则L<=C。If it is the first sequence and the "non-zero element of the second sequence" point multiplication, then L <= C.
可选地,所述第一序列从第一序列集合中获取,包括以下之一:Optionally, the first sequence is obtained from the first sequence set, including one of the following:
采用随机选择的方式从所述第一序列集合中获取第一序列;Obtaining the first sequence from the first sequence set in a random selection manner;
根据预设规则从所述第一序列集合中获取第一序列;Obtaining a first sequence from the first sequence set according to a preset rule;
根据系统配置信息从所述第一序列集合中获取第一序列;Obtaining a first sequence from the first sequence set according to system configuration information;
其中,所述预设规则包括按照预设参数和/或预设公式进行计算,或者预设的对应关系或映射关系。The preset rule includes performing calculation according to a preset parameter and/or a preset formula, or a preset correspondence or mapping relationship.
可选地,所述第二序列从第二序列集合中获取,包括以下之一:Optionally, the second sequence is obtained from the second sequence set, including one of the following:
采用随机选择的方式从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second set of sequences in a randomly selected manner;
根据预设规则从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second sequence set according to a preset rule;
根据系统配置信息从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second sequence set according to system configuration information;
其中,所述预设规则包括按照预设参数和/或预设公式进行计算,或者预设的对应关系或映射关系。The preset rule includes performing calculation according to a preset parameter and/or a preset formula, or a preset correspondence or mapping relationship.
可选地,根据所述第一序列和所述第二序列确定第三序列,包括: Optionally, determining the third sequence according to the first sequence and the second sequence, including:
将所述第一序列与所述第二序列进行点乘处理,生成第三序列;或者,Performing point-multiplication processing on the first sequence and the second sequence to generate a third sequence; or
将所述第一序列与所述第二序列进行乘法处理,生成第三序列;或者,Multiplying the first sequence and the second sequence to generate a third sequence; or
使用所述第一序列中的元素替换所述第二序列中的非零元素,生成第三序列;或者,Substituting an element in the first sequence for a non-zero element in the second sequence to generate a third sequence; or
将所述第一序列中的元素与所述第二序列中的非零元素进行点乘处理后得到的值替换所述第二序列中的非零元素,生成第三序列。Substituting a value obtained by dot-multiplying an element in the first sequence with a non-zero element in the second sequence to replace a non-zero element in the second sequence to generate a third sequence.
可选地,所述从第三序列集合中确定所述第三序列,包括:Optionally, the determining the third sequence from the third sequence set includes:
采用随机选择的方式从所述第三序列集合中获取所述第三序列;Obtaining the third sequence from the third sequence set in a randomly selected manner;
根据预设规则从所述第三序列集合中获取所述第三序列;Obtaining the third sequence from the third sequence set according to a preset rule;
根据系统配置信息从所述第三序列集合中获取所述第三序列;Obtaining the third sequence from the third sequence set according to system configuration information;
其中,所述预设规则至少包括:按照预设参数和/或预设公式进行计算,或者,预设的对应关系或映射关系。The preset rule includes at least: performing calculation according to a preset parameter and/or a preset formula, or a preset correspondence or mapping relationship.
上述方案中,可选地,所述方法还包括以下之一:In the above solution, optionally, the method further includes one of the following:
对所述第一序列集合中的序列进行能量调整或能量归一化处理;Performing energy adjustment or energy normalization processing on the sequence in the first sequence set;
对所述第一序列进行能量调整或能量归一化处理;Performing energy adjustment or energy normalization on the first sequence;
对所述第三序列进行能量调整或能量归一化处理;Performing energy adjustment or energy normalization on the third sequence;
其中,对序列进行能量调整或能量归一化处理,可以使得序列每个元素的能量为1,或者序列的总能量为1,或者序列的总能量等于序列长度,或者序列的总能量为指定值。Wherein, the energy adjustment or energy normalization process of the sequence may be such that the energy of each element of the sequence is 1, or the total energy of the sequence is 1, or the total energy of the sequence is equal to the length of the sequence, or the total energy of the sequence is a specified value. .
可选地,所述方法还包括:Optionally, the method further includes:
对所述第三序列的每个元素或第V个元素乘以1、1i、-1、或-1i,或者,乘以1i的G次方;或者,Multiplying each element or the Vth element of the third sequence by 1, 1i, -1, or -1i, or multiplying by the G of 1i; or
对所述第三序列的每个元素或第V个元素进行H*π的相位调整或旋转,或者,乘以exp(j*H*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of H*π for each element or Vth element of the third sequence, or multiply exp(j*H*π), j is an imaginary unit, j=sqrt(-1) ;or,
对所述第三序列的每个元素或第V个元素乘以指定值;Multiplying each element or the Vth element of the third sequence by a specified value;
其中,V为大于或等于1且小于或等于所述第三序列的长度的整数,G 为整数,H为实数。Wherein V is an integer greater than or equal to 1 and less than or equal to the length of the third sequence, G Is an integer and H is a real number.
步骤102:使用所述第三序列对第一数据进行处理生成第二数据。Step 102: Process the first data by using the third sequence to generate second data.
可选地,所述使用所述第三序列对第一数据进行处理生成第二数据,包括:Optionally, the processing, by using the third sequence, the first data to generate the second data includes:
使用所述第三序列对第一数据进行扩展处理生成第二数据;或,And expanding, by using the third sequence, the first data to generate second data; or
使用所述第三序列对第一数据进行映射处理生成第二数据;或,Performing mapping processing on the first data by using the third sequence to generate second data; or
使用所述第三序列对第一数据进行调制处理生成第二数据;Performing modulation processing on the first data using the third sequence to generate second data;
其中,所述第一数据至少包括比特、编码后的比特、或调制符号;The first data includes at least a bit, an encoded bit, or a modulation symbol;
其中,所述第二数据至少包括符号、复数符号、或数据符号。The second data includes at least a symbol, a complex symbol, or a data symbol.
进一步地,可选地,所述方法还包括:Further, optionally, the method further includes:
步骤103:将所述第二数据映射到指定的传输资源上,用于形成发射信号以及发送。Step 103: Map the second data to a specified transmission resource for forming a transmission signal and transmitting.
其中,指定的传输资源可以是随机选择的、预设的或系统配置的。The designated transmission resource may be randomly selected, preset, or configured by the system.
其中,所述传输资源包括载波、时隙、时频资源、空域资源、码域资源、跳频模式、天线端口等至少之一,所述传输资源可以为资源单元、资源块、资源集合、资源图样的定义或形式。The transmission resource includes at least one of a carrier, a time slot, a time-frequency resource, a spatial domain resource, a code domain resource, a frequency hopping mode, and an antenna port, where the transmission resource may be a resource unit, a resource block, a resource set, and a resource. The definition or form of the drawing.
这里,所述时频资源为上行数据信道(或称为物理上行共享信道(PUSCH Physical Uplink Shared Channel)),或者上行控制信道(或称为物理上行控制信道(PUCCH Physical Uplink Control Channel)),或者随机接入信道RACH(Random Access Channel)(或称为物理随机接入信道PRACH Physical Random Access Channel)。Here, the time-frequency resource is an uplink data channel (or a PUSCH Physical Uplink Shared Channel) or an uplink control channel (or a PUCCH Physical Uplink Control Channel), or A Random Access Channel (RACH) (or a Random Access Channel).
对应地,将所述第二数据映射到目标时频资源上进行传输,包括:Correspondingly, the second data is mapped to the target time-frequency resource for transmission, including:
当所述传输信息包含有终端身份标识信息;或者,包含有终端身份标识信息和小区标识信息,或者包含有终端身份标识信息、小区标识信息和信令信息,或者包含有终端身份标识信息、小区标识信息、信令信息和数据信息时,发射机将所述传输信号载波调制到所述随机接入信道或物理随 机接入信道(PRACH),或者上行控制信道(或称为物理上行控制信道(PUCCH)上进行传输;When the transmission information includes terminal identity information; or includes terminal identity information and cell identity information, or includes terminal identity information, cell identity information, and signaling information, or includes terminal identity information, a cell When identifying information, signaling information, and data information, the transmitter modulates the transmission signal carrier to the random access channel or physical Machine access channel (PRACH), or uplink control channel (or called physical uplink control channel (PUCCH) for transmission;
也就是说,当所述传输信息包含有终端身份标识信息和数据信息,或者包含有终端身份标识信息、小区标识信息和数据信息,或者包含有终端身份标识信息、小区标识信息和信令信息,或者包含有终端身份标识信息、小区标识信息、数据信息和信令信息时,所述发射机将所述传输信号载波调制到所述上行数据信道或物理上行共享信道(PUSCH)上进行传输。That is, when the transmission information includes terminal identity information and data information, or includes terminal identity information, cell identity information, and data information, or includes terminal identity information, cell identity information, and signaling information, Or when the terminal identity information, the cell identity information, the data information, and the signaling information are included, the transmitter modulates the transmission signal carrier to the uplink data channel or a physical uplink shared channel (PUSCH) for transmission.
另外,可选地,第一数据包括以下至少之一信息:车况信息、驾驶员的操作信息,本车传感器所感知的信息(例如一辆大卡车挡住了后面的小车,则大卡车把它摄像头摄得的影像传给后面的小车,则就是本车图像传感器感知的信息)和控制信令;其中,所述车况信息包括以下至少之一:所述车辆标识、所述车辆当前地理位置、所述车辆的行驶速度、所述车辆的大小、所述车辆的颜色;所述操作信息包括以下至少之一:所述驾驶员对所述车辆正在进行的操作,所述驾驶员准备对所述车辆进行的操作。In addition, optionally, the first data includes at least one of the following information: vehicle condition information, driver's operation information, information sensed by the vehicle sensor (eg, a large truck blocks the rear car, then the big truck takes the camera) The captured image is transmitted to the following car, which is the information perceived by the image sensor of the vehicle, and the control signaling; wherein the vehicle condition information includes at least one of the following: the vehicle identifier, the current geographic location of the vehicle, and the location The traveling speed of the vehicle, the size of the vehicle, the color of the vehicle; the operation information includes at least one of: an operation that the driver is performing on the vehicle, the driver preparing to the vehicle The operation performed.
所述驾驶员对所述车辆正在进行的操作包括以下至少之一:刹车、启动、加速、变道和转向;The operation that the driver is performing on the vehicle includes at least one of: braking, starting, accelerating, lane changing, and steering;
驾驶员准备对所述车辆进行的操作包括以下至少之一:准备刹车、准备启动、准备加速、准备变道和准备转向。The driver's preparations for the vehicle include at least one of: preparing for braking, preparing for starting, preparing for acceleration, preparing for lane change, and preparing for steering.
本发明实施例中,从第一序列集合和第二序列集合中分别获取第一序列和第二序列,由第一序列和第二序列确定将要使用的第三序列;其中,第一序列集合中的序列的元素主要使用{1,1i,-1,-1i};或者,从第三序列集合中确定将要使用的第三序列。其中,第一序列集合中的序列的元素主要使用{1,1i,-1,-1i};第二序列集合为哈达玛序列集合、沃尔什序列集合、DFT序列集合、单位矩阵序列集合等;对第一序列集合中的序列进行处理,例如对每个序列的最后一个元素乘以-1,得到新的序列集合,可以将该新的序列集合作为第一序列集合,还可以将该新的序列集合与原来的第一序列 集合合并作为第一序列集合。第三序列集合中的序列的元素主要使用{1,1i,-1,-1i};可以为根据第一序列集合和第二序列集合生成的一个较大的序列集合,也可以为预设的一个较大的序列集合。本发明本实施例方案中,(发射机和接收机)可以仅存储2个较小的序列集合(即第一序列集合和第二序列集合),而不需要存储较大的包含全部可用序列的序列集合,具有较低的存储需求。序列元素使用{1,1i,-1,-1i},运算简单,复杂度较低,从而可以降低发射机扩展处理、接收机相关处理的运算复杂度,有利于满足URLLC场景的低时延需求。In the embodiment of the present invention, the first sequence and the second sequence are respectively obtained from the first sequence set and the second sequence set, and the third sequence to be used is determined by the first sequence and the second sequence; wherein, in the first sequence set The elements of the sequence mainly use {1, 1i, -1, -1i}; or, the third sequence to be used is determined from the third sequence set. The elements of the sequence in the first sequence set mainly use {1, 1i, -1, -1i}; the second sequence set is a Hadamard sequence set, a Walsh sequence set, a DFT sequence set, a unit matrix sequence set, etc. Processing the sequence in the first sequence set, for example, multiplying the last element of each sequence by -1 to obtain a new sequence set, which can be used as the first sequence set, and can also be new Sequence set with the original first sequence The collection is merged as the first sequence collection. The elements of the sequence in the third sequence set mainly use {1, 1i, -1, -1i}; may be a larger sequence set generated according to the first sequence set and the second sequence set, or may be preset A larger collection of sequences. In the solution of this embodiment of the present invention, (transmitter and receiver) may store only two smaller sequence sets (ie, the first sequence set and the second sequence set) without storing a larger one containing all available sequences. A collection of sequences with lower storage requirements. Sequence elements use {1,1i,-1,-1i}, which is simple in operation and low in complexity, which can reduce the computational complexity of transmitter extension processing and receiver-related processing, and is beneficial to meet the low latency requirements of URLLC scenarios. .
对于上述数据生成方法,本发明实施例对以下几个方面进行进一步解释说明:For the above data generation method, the following embodiments of the present invention further explain the following aspects:
(1)该数据生成方法可以应用于发射机和/或接收机中,可以应用于终端设备和/或基站设备中。(1) The data generating method can be applied to a transmitter and/or a receiver, and can be applied to a terminal device and/or a base station device.
(2)i和j均可以作为虚数单位,等于sqrt(-1),二者可以表示相同的含义,本发明描述中可能存在1i、1j、i、j等不同情形,可以认为是等同的。(2) Both i and j can be regarded as imaginary units, equal to sqrt(-1), and both can represent the same meaning. In the description of the present invention, there may be different situations such as 1i, 1j, i, j, etc., which can be considered equivalent.
(3)本发明及实施例给出的序列集合并不是唯一的,基于本发明及实施例中的描述,还可以获取其他类似的序列集合,本发明及实施例不一一描述。(3) The sequence set given by the present invention and the embodiment is not unique. Other similar sequence sets can be obtained based on the description in the present invention and the embodiments, and the present invention and the embodiments are not described one by one.
下面结合几个应用示例,对图1所述的数据生成方法进行详细说明。The data generation method described in FIG. 1 will be described in detail below with reference to several application examples.
应用示例1Application example 1
本实施例中,数据生成方法的一种示意图如图2所示。In this embodiment, a schematic diagram of a data generation method is shown in FIG. 2.
本实施例中,本发明提供的数据生成方法采用的第一序列集合如表1-1所示,该第一序列集合包括4条(序列索引为0-3)长度为4的序列(即每个序列有4个序列元素)。In this embodiment, the first sequence set used by the data generating method provided by the present invention is as shown in Table 1-1, and the first sequence set includes four sequences (the sequence index is 0-3) and the length is 4 (ie, each The sequence has 4 sequence elements).
表1-1 Table 1-1
Figure PCTCN2017114801-appb-000001
Figure PCTCN2017114801-appb-000001
本实施例中,本发明提供的数据生成方法采用的第二序列集合如表1-2所示,该第二序列集合包括4条长度为4的哈达玛(Hadamard)序列,这4条序列构成哈达玛矩阵。In this embodiment, the second sequence set used by the data generating method provided by the present invention is shown in Table 1-2, and the second sequence set includes four Hadamard sequences of length 4, and the four sequence components are configured. Hadamard matrix.
表1-2Table 1-2
Figure PCTCN2017114801-appb-000002
Figure PCTCN2017114801-appb-000002
本实施例中,本发明提供的数据生成方法从第一序列集合中获取第一序列,获取第一序列的方式包括:In this embodiment, the data generating method provided by the present invention obtains the first sequence from the first sequence set, and the manner of obtaining the first sequence includes:
(1)采用随机选择的方式从第一序列集合中获取第一序列;例如,通过随机数产生器产生一个随机数,将该随机数作为序列索引,或根据该随机数和预设规则确定序列索引(比如将该随机数对第一序列集合中的序列数量进行求余运算,将余数作为序列索引),根据该序列索引从第一序列集合中确定第一序列;(1) obtaining the first sequence from the first sequence set by using a random selection method; for example, generating a random number by using a random number generator, using the random number as a sequence index, or determining a sequence according to the random number and a preset rule; Indexing (such as performing a remainder operation on the number of sequences in the first sequence set and using the remainder as a sequence index), and determining the first sequence from the first sequence set according to the sequence index;
(2)根据预设规则从第一序列集合中获取第一序列;例如,使用指定参数的值对第一序列集合中的序列数量进行求余运算,将余数作为序列索引,根据该序列索引从第一序列集合中确定第一序列,其中,指定参数可以为设备身份识别信息等;(2) obtaining a first sequence from the first sequence set according to a preset rule; for example, performing a remainder operation on the number of sequences in the first sequence set by using a value of the specified parameter, using the remainder as a sequence index, according to the sequence index Determining a first sequence in the first sequence set, wherein the specified parameter may be device identification information, etc.;
(3)根据系统配置信息从第一序列集合中获取第一序列;例如,系统 固定配置、半静态配置、动态配置所使用的序列索引,则可以根据系统配置信息得到序列索引,然后根据该序列索引从第一序列集合中确定第一序列;由于第一序列集合中包含4条序列,当系统通过配置信令指示序列信息时,可以通过2比特进行指示。(3) acquiring the first sequence from the first sequence set according to the system configuration information; for example, the system The sequence index used in the fixed configuration, the semi-static configuration, and the dynamic configuration may be sequenced according to the system configuration information, and then the first sequence is determined from the first sequence set according to the sequence index; since the first sequence set includes four The sequence, when the system indicates sequence information through configuration signaling, can be indicated by 2 bits.
本实施例中,假设所获取的第一序列为表1-1中序列索引1所指示的序列,简称序列1,即[1,1,1i,-1i]。In this embodiment, it is assumed that the acquired first sequence is the sequence indicated by the sequence index 1 in Table 1-1, and is abbreviated as sequence 1, ie, [1, 1, 1i, -1i].
本发明提供的数据生成方法还从第二序列集合中获取第二序列,获取第二序列的方式包括:The data generating method provided by the present invention further obtains the second sequence from the second sequence set, and the manner of obtaining the second sequence includes:
(1)采用随机选择的方式从第二序列集合中获取第二序列;例如,通过随机数产生器产生一个随机数,将该随机数作为序列索引,或根据该随机数和预设规则确定序列索引(比如将该随机数对第二序列集合中的序列数量进行求余运算,将余数作为序列索引),根据该序列索引从第二序列集合中确定第二序列;(1) acquiring a second sequence from the second sequence set in a random selection manner; for example, generating a random number by using a random number generator, using the random number as a sequence index, or determining a sequence according to the random number and a preset rule; Indexing (such as performing a remainder operation on the number of sequences in the second sequence set, using the remainder as a sequence index), and determining a second sequence from the second sequence set according to the sequence index;
(2)根据预设规则从第二序列集合中获取第二序列;例如,使用指定参数的值对第二序列集合中的序列数量进行求余运算,将余数作为序列索引,根据该序列索引从第二序列集合中确定第二序列,其中,指定参数可以为设备身份识别信息等;(2) obtaining a second sequence from the second sequence set according to a preset rule; for example, performing a remainder operation on the number of sequences in the second sequence set using the value of the specified parameter, using the remainder as a sequence index, according to the sequence index Determining a second sequence in the second sequence set, wherein the specified parameter may be device identification information or the like;
(3)根据系统配置信息从第二序列集合中获取第二序列;例如,系统固定配置、半静态配置、动态配置所使用的序列索引,则可以根据系统配置信息得到序列索引,然后根据该序列索引从第二序列集合中确定第二序列;由于第二序列集合中包含4条序列,当系统通过配置信令指示序列信息时,可以通过2比特进行指示。(3) obtaining a second sequence from the second sequence set according to the system configuration information; for example, a sequence index used by the system fixed configuration, semi-static configuration, and dynamic configuration, the sequence index may be obtained according to the system configuration information, and then according to the sequence The index determines the second sequence from the second sequence set; since the second sequence set contains four sequences, when the system indicates the sequence information through configuration signaling, it can be indicated by 2 bits.
本实施例中,假设所获取的第二序列为表1-2中序列索引0所指示的序列,简称序列0,即[1,1,1,1]。In this embodiment, it is assumed that the acquired second sequence is the sequence indicated by the sequence index 0 in Table 1-2, and is abbreviated as sequence 0, that is, [1, 1, 1, 1].
然后,本发明提供的数据生成方法根据第一序列和第二序列生成第三序列,即将第一序列与第二序列进行点乘运算生成第三序列,那么,该第 三序列为:[1,1,1i,-1i]。Then, the data generating method provided by the present invention generates a third sequence according to the first sequence and the second sequence, that is, the first sequence and the second sequence are subjected to dot multiplication to generate a third sequence, then the first The three sequences are: [1, 1, 1i, -1i].
进一步地,本实施例中,本发明提供的数据生成方法使用所生成的第三序列对第一数据(例如调制符号)进行扩展处理生成第二数据(即处理后的数据符号),进一步可以将该第二数据映射到指定的传输资源上,用于形成发射信号以及发送。Further, in this embodiment, the data generating method provided by the present invention uses the generated third sequence to perform extension processing on the first data (for example, modulation symbols) to generate second data (ie, processed data symbols), and further The second data is mapped onto a designated transmission resource for forming a transmit signal and transmitting.
本实施例中,本发明提供的数据生成方法还可以将表1-1所示的第一序列集合中的序列进行能量调整或能量归一化处理,使得每个序列的总能量为1;或者,将所获取的第一序列进行能量调整或能量归一化处理,使得该序列的总能量为1;或者,将所生成的第三序列进行能量调整或能量归一化处理,使得该序列的总能量为1。In this embodiment, the data generating method provided by the present invention may further perform energy adjustment or energy normalization processing on the sequence in the first sequence set shown in Table 1-1, so that the total energy of each sequence is 1; or And performing the energy adjustment or energy normalization processing on the obtained first sequence, so that the total energy of the sequence is 1; or, the generated third sequence is subjected to energy adjustment or energy normalization processing, so that the sequence is The total energy is 1.
本实施例中,从表1-1所示的第一序列集合可以看出,该第一序列集合中的序列元素的取值来自于集合{1,1i,-1,-1i}。该元素集合{1,1i,-1,-1i}还可以表示为二维复数星座图的形成,如图3所示。In this embodiment, it can be seen from the first sequence set shown in Table 1-1 that the values of the sequence elements in the first sequence set are from the set {1, 1i, -1, -1i}. The set of elements {1, 1i, -1, -1i} can also be represented as a two-dimensional complex constellation diagram, as shown in FIG.
本实施例中,第一序列集合包含4条长度为4的序列,第二序列集合也包含4条长度为4的序列,将第一序列集合中的任意一条序列与第二序列集合中的任意一条序列进行点乘运算,共计可以产生16条长度为4的序列,如表1-3所示。In this embodiment, the first sequence set includes four sequences of length 4, and the second sequence set also includes four sequences of length 4, and any one of the first sequence set and any of the second sequence set. A sequence is multiplied to produce a total of 16 sequences of length 4, as shown in Table 1-3.
表1-3Table 1-3
Figure PCTCN2017114801-appb-000003
Figure PCTCN2017114801-appb-000003
Figure PCTCN2017114801-appb-000004
Figure PCTCN2017114801-appb-000004
从表1-3所示的序列集合可以看出,该序列集合中的序列元素的取值也来自于集合{1,1i,-1,-1i}。该序列集合还可以划分为四组序列,分别为序列0~3、序列4~7、序列8~11、序列12~15;这四组序列中,每组序列中的4条序列是相互正交的;四组序列之间是非正交的,来自于任意两组的两条序列在能量归一化之后的互相关的绝对值为0.5。因此,表1-3所示的序列集合中任意两条序列在能量归一化之后的互相关的绝对值不大于0.5。As can be seen from the sequence set shown in Table 1-3, the values of the sequence elements in the sequence set also come from the set {1, 1i, -1, -1i}. The sequence set can also be divided into four sets of sequences, which are sequence 0-3, sequence 4-7, sequence 8-11, and sequence 12-15; in the four sets of sequences, the four sequences in each set are mutually positive. The four sets of sequences are non-orthogonal, and the absolute value of the cross-correlation of the two sequences from any two sets after energy normalization is 0.5. Therefore, the absolute value of the cross-correlation of any two sequences in the sequence set shown in Tables 1-3 after energy normalization is not more than 0.5.
本实施例中,本发明提供的数据生成方法具有以下有益效果:In this embodiment, the data generating method provided by the present invention has the following beneficial effects:
(1)可以仅存储表1-1所示的第一序列集合和表1-2所示的第二序列集合,这两个序列集合分别包含4条长度为4的序列,而不需要存储表1-3所示的包含16条长度为4的序列集合,从而可以降低存储需求。(1) It is possible to store only the first sequence set shown in Table 1-1 and the second sequence set shown in Table 1-2, each of which contains four sequences of length 4, without requiring a storage table. The sequence shown in 1-3 contains 16 sequences of length 4, which can reduce storage requirements.
(2)序列元素使用{1,1i,-1,-1i},运算简单(例如当进行扩展处理时无需复杂的乘法操作,可以仅通过少量的加法操作实现),从而可以降低发射机和接收机的计算复杂度,有利于满足低复杂度、低时延、低成本、低功耗等系统设计需求。(2) The sequence elements use {1, 1i, -1, -1i}, and the operation is simple (for example, when performing the expansion processing without complicated multiplication operations, it can be realized by only a small number of addition operations), thereby reducing the transmitter and reception. The computational complexity of the machine is beneficial to meet the system design requirements of low complexity, low latency, low cost, and low power consumption.
应用示例2Application example 2
本实施例中,数据生成方法的另一种示意图如图4所示。 In this embodiment, another schematic diagram of the data generation method is shown in FIG. 4.
本实施例中,对第一序列集合中的序列进行处理,得到新的序列集合,可以将该新的序列集合作为第一序列集合。In this embodiment, the sequence in the first sequence set is processed to obtain a new sequence set, and the new sequence set can be used as the first sequence set.
本实施例中,本发明提供的数据生成方法采用的第一序列集合为对应用示例1中表1-1所示的序列集合进行处理得到的序列集合;具体地,对应用示例1中表1-1所示的序列集合中的每条序列的第4个序列元素乘以-1,或者相位调整或旋转π,得到如表2-1所示的序列集合,将该序列集合作为第一序列集合。In this embodiment, the first sequence set used by the data generating method provided by the present invention is a sequence set obtained by processing the sequence set shown in Table 1-1 of Application Example 1; specifically, Table 1 in Application Example 1 The fourth sequence element of each sequence in the sequence set shown by -1 is multiplied by -1, or the phase is adjusted or rotated by π to obtain a sequence set as shown in Table 2-1, and the sequence set is used as the first sequence. set.
表2-1table 2-1
Figure PCTCN2017114801-appb-000005
Figure PCTCN2017114801-appb-000005
本实施例中,本发明提供的数据生成方法采用的第二序列集合如应用示例1中的表1-2所示。In this embodiment, the second sequence set adopted by the data generating method provided by the present invention is shown in Table 1-2 in Application Example 1.
本实施例中,本发明提供的数据生成方法从第一序列集合中获取第一序列,获取第一序列的方式如应用示例1所述,不再赘述;本实施例中,假设所获取的第一序列为表2-1中序列索引1所指示的序列,即[1,1,1i,1i]。In this embodiment, the data generation method provided by the present invention obtains the first sequence from the first sequence set, and the manner of obtaining the first sequence is as described in the application example 1, and is not described again. In this embodiment, the acquired One sequence is the sequence indicated by the sequence index 1 in Table 2-1, namely [1, 1, 1i, 1i].
本发明提供的数据生成方法还从第二序列集合中获取第二序列,获取第二序列的方式如应用示例1所述,不再赘述;本实施例中,假设所获取的第二序列为表1-2中序列索引0所指示的序列,即[1,1,1,1]。The data generating method provided by the present invention also obtains the second sequence from the second sequence set, and the manner of obtaining the second sequence is as described in the application example 1, and is not described again. In this embodiment, the obtained second sequence is assumed to be a table. The sequence indicated by the sequence index 0 in 1-2, that is, [1, 1, 1, 1].
然后,本发明提供的数据生成方法根据第一序列和第二序列生成第三序列,即将第一序列与第二序列进行点乘运算生成第三序列,那么,该第三序列为:[1,1,1i,1i]。Then, the data generating method provided by the present invention generates a third sequence according to the first sequence and the second sequence, that is, the first sequence and the second sequence are subjected to dot multiplication to generate a third sequence, then the third sequence is: [1, 1,1i, 1i].
本实施例中,本发明提供的数据生成方法使用所生成的第三序列对第 一数据(例如调制符号)进行扩展处理生成第二数据(即处理后的数据符号),进一步可以将该第二数据映射到指定的传输资源上,用于形成发射信号以及发送。In this embodiment, the data generation method provided by the present invention uses the generated third sequence pair A data (e.g., modulation symbols) is subjected to an extension process to generate second data (i.e., processed data symbols), and the second data can be further mapped onto a designated transmission resource for forming a transmission signal and transmitting.
本实施例中,第一序列集合包含4条长度为4的序列,第二序列集合也包含4条长度为4的序列,将第一序列集合中的任意一条序列与第二序列集合中的任意一条序列进行点乘运算,共计可以产生16条长度为4的序列,如表2-2所示。In this embodiment, the first sequence set includes four sequences of length 4, and the second sequence set also includes four sequences of length 4, and any one of the first sequence set and any of the second sequence set. A sequence is multiplied to produce a total of 16 sequences of length 4, as shown in Table 2-2.
表2-2Table 2-2
Figure PCTCN2017114801-appb-000006
Figure PCTCN2017114801-appb-000006
与应用示例1类似,从表2-2所示的序列集合可以看出,该序列集合中的序列元素的取值同样来自于集合{1,1i,-1,-1i}。该序列集合同样可以 划分为四组序列,分别为序列0~3、序列4~7、序列8~11、序列12~15;这四组序列中,每组序列中的4条序列是相互正交的;四组序列之间是非正交的,来自于任意两组的两条序列在能量归一化之后的互相关的绝对值为0.5。因此,表2-2所示的序列集合中任意两条序列在能量归一化之后的互相关的绝对值不大于0.5。Similar to the application example 1, it can be seen from the sequence set shown in Table 2-2 that the values of the sequence elements in the sequence set are also derived from the set {1, 1i, -1, -1i}. The sequence set can also be Divided into four groups of sequences, which are sequences 0 to 3, sequences 4 to 7, sequences 8 to 11, and sequences 12 to 15; in the four sequences, four sequences in each group are orthogonal to each other; The sequences are non-orthogonal, and the absolute value of the cross-correlation after the energy normalization of the two sequences from any two groups is 0.5. Therefore, the absolute value of the cross-correlation of any two sequences in the sequence set shown in Table 2-2 after energy normalization is not more than 0.5.
表2-1所示的序列集合还可以与应用示例1中的表1-1所示的序列集合合并,产生一个包含8条长度为4的序列的序列集合,将该序列集合作为第一序列集合,然后将该第一序列集合中的任意一条序列与上述第二序列集合中的任意一条序列进行点乘运算,可以产生一个包含32条长度为4的序列的序列集合。这相当于将表2-2所示的序列集合与应用示例1中的表1-3所示的序列集合进行了合并。该序列集合中的任意两条序列在能量归一化之后的互相关的绝对值不大于sqrt(2)/2,其中,sqrt()为平方根函数。此时,本发明提供的数据生成方法可以存储该包含8条长度为4的序列的第一序列集合,当系统通过配置信令指示所使用的第一序列的信息时,可以通过3比特进行指示;或者,可以仅存储应用示例1中表1-1所示的包含4条长度为4的序列的序列集合,当系统通过配置信令指示所使用的第一序列的信息时,先通过2比特指示表1-1所示的序列集合中的序列,并通过1比特指示对该序列的第X个元素进行的处理(比如,该比特为0时表示对序列的第X个元素乘以1或相位旋转0,该比特为1时表示对序列的第X个元素乘以-1或相位旋转π;或者,将该比特表示为b0,将对序列的第X个元素的处理表示为乘以1i的(2*b0)次方或乘以exp(j*b0*π)),其中,X可以是固定的或预设的,例如X等于序列长度L,即最后一个序列元素,或者,X是系统配置的。The sequence set shown in Table 2-1 can also be combined with the sequence set shown in Table 1-1 in Application Example 1, to generate a sequence set containing eight sequences of length 4, which is used as the first sequence. The set is then subjected to a point multiplication of any one of the first sequence set and any one of the second sequence sets to generate a sequence set comprising 32 sequences of length 4. This is equivalent to combining the sequence set shown in Table 2-2 with the sequence set shown in Tables 1-3 in Application Example 1. The absolute value of the cross-correlation of any two sequences in the sequence after energy normalization is not greater than sqrt(2)/2, where sqrt() is a square root function. At this time, the data generating method provided by the present invention may store the first sequence set including eight sequences of length 4, and when the system indicates the information of the first sequence used by the configuration signaling, it may indicate by 3 bits. Or, it is possible to store only the sequence set including four sequences of length 4 as shown in Table 1-1 of Application Example 1, and when the system indicates the information of the first sequence used by the configuration signaling, first pass 2 bits. Indicates the sequence in the sequence set shown in Table 1-1, and indicates the processing of the Xth element of the sequence by 1 bit (for example, when the bit is 0, it means multiplying the Xth element of the sequence by 1 or The phase rotates by 0. When the bit is 1, it indicates that the Xth element of the sequence is multiplied by -1 or the phase is rotated by π; or, the bit is represented as b0, and the processing of the Xth element of the sequence is represented as multiplied by 1i. (2*b0) power or multiplied by exp(j*b0*π)), where X can be fixed or preset, for example, X is equal to the sequence length L, that is, the last sequence element, or, X is System configured.
类似地,本发明提供的数据生成方法采用的第一序列集合还可以为对应用示例1中表1-1所示的序列集合进行其他处理得到的序列集合;例如,对应用示例1中表1-1所示的序列集合中的每条序列的第4个序列元素乘以 1i,或者,相位调整或旋转π/2,得到如表2-3所示的序列集合,将该序列集合作为第一序列集合;Similarly, the first sequence set used by the data generating method provided by the present invention may also be a sequence set obtained by performing other processing on the sequence set shown in Table 1-1 of Application Example 1; for example, Table 1 in Application Example 1 Multiply the fourth sequence element of each sequence in the sequence set shown by -1 1i, or, phase adjustment or rotation π/2, to obtain a sequence set as shown in Table 2-3, the sequence set as the first sequence set;
表2-3Table 2-3
Figure PCTCN2017114801-appb-000007
Figure PCTCN2017114801-appb-000007
或者,例如,对应用示例1中表1-1所示的序列集合中的每条序列的第4个序列元素乘以-1i,或者,相位调整或旋转3*π/2,得到如表2-4所示的序列集合,将该序列集合作为第一序列集合。Or, for example, multiplying the 4th sequence element of each sequence in the sequence set shown in Table 1-1 of Application Example 1 by -1i, or phase adjustment or rotation 3*π/2, as shown in Table 2 A sequence set shown in -4, which is used as a first sequence set.
表2-4Table 2-4
Figure PCTCN2017114801-appb-000008
Figure PCTCN2017114801-appb-000008
类似地,表2-1、表2-3、表2-4所示的序列集合可以与应用示例1中的表1-1所示的序列集合合并,产生一个包含16条长度为4的序列的序列集合,将该序列集合作为第一序列集合,然后将该第一序列集合中的任意一条序列与上述第二序列集合中的任意一条序列进行点乘运算,可以产生一个包含64条长度为4的序列的序列集合。该序列集合中的任意两条序列在能量归一化之后的互相关的绝对值小于0.8。此时,本发明提供的数据生成方法可以存储该包含16条长度为4的序列的第一序列集合,当系统通过配置信令指示所使用的第一序列的信息时,可以通过4比特进行指示;或者,可以仅存储应用示例1中表1-1所示的包含4条长度为4的序列的序列 集合,当系统通过配置信令指示所使用的第一序列的信息时,先通过2比特指示表1-1所示的序列集合中的序列,并通过2比特指示对该序列的第X个元素进行的处理(比如,该2比特为00时表示对序列的第X个元素乘以1或相位旋转0,该2比特为01时表示对序列的第X个元素乘以1i或相位旋转π/2,该2比特为10时表示对序列的第X个元素乘以-1或相位旋转π,该2比特为11时表示对序列的第X个元素乘以-1i或相位旋转3*π/2;或者,将该2比特表示为b0b1,其对应的十进制数值表示为D,将对序列第X个元素的处理表示为乘以1i的D次方或乘以exp(j*D*π/2)),其中,X可以是固定的或预设的,例如X等于序列长度L,即最后一个序列元素,或者,X是系统配置的。Similarly, the sequence sets shown in Table 2-1, Table 2-3, and Table 2-4 can be combined with the sequence set shown in Table 1-1 of Application Example 1, to generate a sequence of 16 lengths of four. a sequence set, the sequence set is used as a first sequence set, and then any one of the first sequence set and any one of the second sequence set are subjected to a point multiplication operation, thereby generating a length of 64 A sequence set of 4 sequences. The absolute value of the cross-correlation of any two sequences in the set of sequences after energy normalization is less than 0.8. In this case, the data generating method provided by the present invention may store the first sequence set including 16 sequences of length 4, and when the system indicates the information of the first sequence used by the configuration signaling, it may indicate by 4 bits. Or, it is possible to store only the sequence including four sequences of length 4 as shown in Table 1-1 of Application Example 1. The set, when the system indicates the information of the first sequence used by the configuration signaling, first indicates the sequence in the sequence set shown in Table 1-1 by 2 bits, and indicates the Xth element of the sequence by 2 bits. The processing performed (for example, when the 2 bits are 00, it means that the Xth element of the sequence is multiplied by 1 or the phase is rotated by 0, and when the 2 bits are 01, the Xth element of the sequence is multiplied by 1i or the phase is rotated by π/ 2. When the 2 bits are 10, it means that the Xth element of the sequence is multiplied by -1 or the phase is rotated by π. When the 2 bits are 11, the Xth element of the sequence is multiplied by -1i or the phase is rotated by 3*π/. 2; or, the 2 bits are represented as b0b1, and the corresponding decimal value is represented as D, and the processing of the Xth element of the sequence is expressed as multiplied by the 1st power of D or multiplied by exp(j*D*π/ 2)), where X can be fixed or preset, for example X is equal to the sequence length L, ie the last sequence element, or X is system configured.
应用示例3Application example 3
本实施例中,本发明提供的数据生成方法采用的第一序列集合如应用示例1中的表1-1所示。In this embodiment, the first sequence set adopted by the data generating method provided by the present invention is shown in Table 1-1 in Application Example 1.
本实施例中,本发明提供的数据生成方法采用的第二序列集合如表3-1所示,该第二序列集合包括8条长度为4的序列,其中,序列0~3为4条长度为4的哈达玛序列,序列4~7为4条长度为4的单位矩阵序列。In this embodiment, the second sequence set used by the data generating method provided by the present invention is shown in Table 3-1, and the second sequence set includes eight sequences of length 4, wherein the sequence 0 to 3 is 4 lengths. For a Hadamard sequence of 4, sequences 4-7 are four unit matrix sequences of length 4.
表3-1Table 3-1
Figure PCTCN2017114801-appb-000009
Figure PCTCN2017114801-appb-000009
Figure PCTCN2017114801-appb-000010
Figure PCTCN2017114801-appb-000010
本实施例中,本发明提供的数据生成方法从第一序列集合中获取第一序列,获取第一序列的方式如应用示例1所述,不再赘述。In this embodiment, the data generating method provided by the present invention obtains the first sequence from the first sequence set, and the manner of obtaining the first sequence is as described in the application example 1, and details are not described herein again.
本发明提供的数据生成方法还从第二序列集合中获取第二序列,获取第二序列的方式如应用示例1所述,不再赘述。本实施例中,第二序列集合包含8条序列,当系统通过配置信令指示序列信息时,可以通过3比特进行指示。The data generating method provided by the present invention also obtains the second sequence from the second sequence set, and the manner of obtaining the second sequence is as described in the application example 1, and details are not described herein again. In this embodiment, the second sequence set includes eight sequences. When the system indicates sequence information through configuration signaling, it can be indicated by 3 bits.
本实施例中,当所获取的第二序列为序列4~7中的任意一条序列时,默认第一序列为应用示例1中表1-1所示的第一序列集合中的序列0,即[1,1,1,1];或者,默认第一序列为[1]。In this embodiment, when the acquired second sequence is any one of the sequences 4 to 7, the default first sequence is the sequence 0 in the first sequence set shown in Table 1-1 of the application example 1, that is, [ 1,1,1,1]; or, the default first sequence is [1].
然后,本发明提供的数据生成方法根据第一序列和第二序列生成第三序列,即将第一序列与第二序列进行点乘运算(当默认第一序列为[1]时也可以进行乘法运算)生成第三序列。Then, the data generating method provided by the present invention generates a third sequence according to the first sequence and the second sequence, that is, the first sequence and the second sequence are multiplied (when the default first sequence is [1], the multiplication operation can also be performed. ) Generate a third sequence.
本实施例中,本发明提供的数据生成方法使用所生成的第三序列对第一数据进行扩展处理生成第二数据,进一步可以将该第二数据映射到指定的传输资源上,用于形成发射信号以及发送。In this embodiment, the data generating method provided by the present invention uses the generated third sequence to perform extended processing on the first data to generate second data, and further may map the second data to a specified transmission resource for forming an emission. Signal and send.
本实施例中,第一序列集合包含4条长度为4的序列,第二序列集合包含8条长度为4的序列,由于第二序列为单位矩阵序列中的任意一条序列时第一序列默认为[1,1,1,1]或[1],那么,本实施例中总共有20条长度为4的序列,如表3-2所示。In this embodiment, the first sequence set includes four sequences of length 4, and the second sequence set includes eight sequences of length 4. When the second sequence is any sequence in the unit matrix sequence, the first sequence defaults to [1, 1, 1, 1] or [1], then there are a total of 20 sequences of length 4 in this embodiment, as shown in Table 3-2.
表3-2Table 3-2
Figure PCTCN2017114801-appb-000011
Figure PCTCN2017114801-appb-000011
Figure PCTCN2017114801-appb-000012
Figure PCTCN2017114801-appb-000012
表3-2所示的序列集合相当于在表1-3所示的序列集合基础上增加了单位矩阵序列。另外,可以看出,该序列集合中引入了0元素,可以认为序列元素的取值来自于集合{1,1i,-1,-1i,0}。该元素集合{1,1i,-1,-1i,0}还可以表示为二维复数星座图的形成,如图5所示。The sequence set shown in Table 3-2 is equivalent to the addition of the unit matrix sequence to the sequence set shown in Table 1-3. In addition, it can be seen that the 0 element is introduced in the sequence set, and the value of the sequence element can be considered to be from the set {1, 1i, -1, -1i, 0}. The set of elements {1, 1i, -1, -1i, 0} can also be represented as a two-dimensional complex constellation, as shown in FIG.
实际应用中,也可以直接使用表3-2所示的包含20条长度为4的序列的序列集合来获取所需要的第三序列;此时,当系统通过配置信令指示所使用的序列的信息时,可以通过5比特进行指示。In practical applications, the sequence set of 20 sequences of length 4 as shown in Table 3-2 can also be directly used to obtain the required third sequence; at this time, when the system indicates the sequence used by configuration signaling When the information is available, it can be indicated by 5 bits.
应用示例4Application example 4
本实施例中,本发明提供的数据生成方法采用的第一序列集合如表4-1 所示,该第一序列集合包括1条长度为2的序列。In this embodiment, the first sequence set used by the data generating method provided by the present invention is shown in Table 4-1. As shown, the first set of sequences includes one sequence of length 2.
表4-1Table 4-1
Figure PCTCN2017114801-appb-000013
Figure PCTCN2017114801-appb-000013
本实施例中,本发明提供的数据生成方法采用的第二序列集合如表4-2所示,该第二序列集合包括2条长度为2的哈达玛序列,这2条序列构成哈达玛矩阵。In this embodiment, the second sequence set used by the data generating method provided by the present invention is as shown in Table 4-2, and the second sequence set includes two Hadamard sequences of length 2, and the two sequences form a Hadamard matrix. .
表4-2Table 4-2
Figure PCTCN2017114801-appb-000014
Figure PCTCN2017114801-appb-000014
本实施例中,本发明提供的数据生成方法从第一序列集合中获取第一序列,由于表4-1所示的第一序列集合中仅有一条序列,那么,本实施例中,所获取的第一序列为[1,1]。这相当于第一序列是系统固定配置的或预设的,无需系统通过配置信令指示。In this embodiment, the data generating method provided by the present invention obtains the first sequence from the first sequence set. Since there is only one sequence in the first sequence set shown in Table 4-1, in this embodiment, the obtained method is obtained. The first sequence is [1,1]. This is equivalent to the first sequence being fixed or preset by the system, and the system does not need to be indicated by configuration signaling.
本发明提供的数据生成方法还从第二序列集合中获取第二序列,获取第二序列的方式如应用示例1所述,不再赘述。本实施例中,第二序列集合包含2条序列,当系统通过配置信令指示序列信息时,可以通过1比特进行指示。The data generating method provided by the present invention also obtains the second sequence from the second sequence set, and the manner of obtaining the second sequence is as described in the application example 1, and details are not described herein again. In this embodiment, the second sequence set includes two sequences. When the system indicates sequence information through configuration signaling, it may be indicated by 1 bit.
然后,本发明提供的数据生成方法根据第一序列和第二序列生成第三序列,即将第一序列与第二序列进行点乘运算生成第三序列。Then, the data generating method provided by the present invention generates a third sequence according to the first sequence and the second sequence, that is, the first sequence and the second sequence are subjected to dot multiplication to generate a third sequence.
本实施例中,本发明提供的数据生成方法使用所生成的第三序列对第一数据进行扩展处理生成第二数据,进一步可以将该第二数据映射到指定的传输资源上,用于形成发射信号以及发送。In this embodiment, the data generating method provided by the present invention uses the generated third sequence to perform extended processing on the first data to generate second data, and further may map the second data to a specified transmission resource for forming an emission. Signal and send.
本实施例中,本发明提供的数据生成方法采用的第一序列集合还可以 为对表4-1所示的序列集合进行处理得到的序列集合;例如,对表4-1所示的序列集合中的序列的最后一个元素乘以-1,或者相位调整或旋转π,得到如表4-3所示的序列集合,将该序列集合作为第一序列集合;In this embodiment, the first sequence set adopted by the data generating method provided by the present invention may also be a set of sequences obtained by processing the sequence set shown in Table 4-1; for example, multiplying the last element of the sequence in the sequence set shown in Table 4-1 by -1, or phase adjustment or rotation π, a sequence set as shown in Table 4-3, the sequence set is used as a first sequence set;
表4-3Table 4-3
Figure PCTCN2017114801-appb-000015
Figure PCTCN2017114801-appb-000015
或者,例如,对表4-1所示的序列集合中的序列的最后一个元素乘以1i,或者,相位调整或旋转π/2,得到如表4-4所示的序列集合,将该序列集合作为第一序列集合;Or, for example, multiplying the last element of the sequence in the sequence set shown in Table 4-1 by 1i, or phase adjustment or rotation π/2, resulting in a sequence set as shown in Table 4-4, the sequence The collection is the first sequence set;
表4-4Table 4-4
Figure PCTCN2017114801-appb-000016
Figure PCTCN2017114801-appb-000016
或者,例如,对表4-1所示的序列集合中的序列的最后一个元素乘以-1i,或者,相位调整或旋转3*π/2,得到如表4-5所示的序列集合,将该序列集合作为第一序列集合。Or, for example, multiplying the last element of the sequence in the sequence set shown in Table 4-1 by -1i, or phase adjustment or rotation 3*π/2, resulting in a sequence set as shown in Table 4-5. The sequence set is taken as the first sequence set.
表4-5Table 4-5
Figure PCTCN2017114801-appb-000017
Figure PCTCN2017114801-appb-000017
本实施例中,本发明提供的数据生成方法采用的第一序列集合还可以为表4-1、表4-4合并形成的序列集合,或表4-1、表4-5合并形成的序列集合,或表4-2、表4-4合并形成的序列集合,或表4-2、表4-5合并形成的序列集合。此时,该第一序列集合包含2条序列,当系统通过配置信令指示所使用的第一序列的信息时,可以通过1比特进行指示,或者,可以仅存储表4-1或表4-2所示的序列集合,当系统通过配置信令指示所使用的第一序列的信息时,通过1比特指示对序列的第X个元素进行的处理(比如, 该比特为0时表示对序列的第X个元素乘以1或相位旋转0,该比特为1时表示对序列的第X个元素乘以1i或相位旋转π/2;或者,将该比特表示为b0,将对序列的第X个元素的处理表示为乘以1i的b0次方或乘以exp(j*b0*π/2)),其中,X可以是固定的或预设的,例如X等于序列长度L,即最后一个序列元素,或者,X是系统配置的。In this embodiment, the first sequence set used by the data generating method provided by the present invention may also be a sequence set formed by combining Table 4-1 and Table 4-4, or a sequence formed by combining Table 4-1 and Table 4-5. The set, or the set of sequences formed by the combination of Tables 4-2 and 4-4, or the set of sequences formed by the combination of Tables 4-2 and 4-5. At this time, the first sequence set includes two sequences. When the system indicates the information of the first sequence used by the configuration signaling, the information may be indicated by 1 bit, or only Table 4-1 or Table 4 may be stored. The sequence set shown in 2, when the system indicates the information of the first sequence used by the configuration signaling, the processing of the Xth element of the sequence is indicated by 1 bit (for example, When the bit is 0, it means that the Xth element of the sequence is multiplied by 1 or the phase is rotated by 0. When the bit is 1, it means that the Xth element of the sequence is multiplied by 1i or the phase is rotated by π/2; or, the bit is represented. For b0, the processing of the Xth element of the sequence is represented as multiplying the b0 power of 1i or multiplied by exp(j*b0*π/2)), where X may be fixed or preset, for example X is equal to the sequence length L, which is the last sequence element, or X is system configured.
本实施例中,第一序列固定为[1,1],本发明提供的数据生成方法可以不再需要表4-1所示的第一序列集合,不再需要从该第一序列集合中获取第一序列,可以仅使用表4-2所示的第二序列集合,仅从该第二序列集合中获取第二序列,并将所获取的第二序列作为将要生成的第三序列;In this embodiment, the first sequence is fixed to [1, 1], and the data generation method provided by the present invention may no longer need the first sequence set shown in Table 4-1, and no longer needs to be obtained from the first sequence set. The first sequence may use only the second sequence set shown in Table 4-2, obtain only the second sequence from the second sequence set, and use the acquired second sequence as the third sequence to be generated;
进一步,当仅使用表4-2所示的第二序列集合时,上述对表4-1所示的序列集合进行处理得到新的序列集合的方法也可以作用于第二序列集合;例如,对表4-2所示的序列集合中的每个序列的最后一个元素乘以1i,或者,相位调整或旋转π/2,得到如表4-6所示的序列集合,将该序列集合作为第二序列集合;Further, when only the second sequence set shown in Table 4-2 is used, the above method of processing the sequence set shown in Table 4-1 to obtain a new sequence set may also be applied to the second sequence set; for example, The last element of each sequence in the sequence set shown in Table 4-2 is multiplied by 1i, or the phase is adjusted or rotated by π/2 to obtain a sequence set as shown in Table 4-6. Two sequence set;
表4-6Table 4-6
Figure PCTCN2017114801-appb-000018
Figure PCTCN2017114801-appb-000018
进一步,类似地,本发明提供的数据生成方法采用的第二序列集合还可以为表4-2、表4-6合并形成的序列集合。此时,该第二序列集合包含4条序列,当系统通过配置信令指示所使用的第二序列的信息时,可以通过2比特进行指示;或者,可以仅存储表4-2所示的序列集合,当系统通过配置信令指示所使用的第二序列的信息时,先通过1比特指示表4-2所示的序列集合中的序列,并通过1比特指示对该序列的第X个元素进行的处理(比如,该比特为0时表示对序列的第X个元素乘以1或相位旋转0,该比特 为1时表示对序列的第X个元素乘以1i或相位旋转π/2;或者,将该比特表示为b0,将对序列的第X个元素的处理表示为乘以1i的b0次方或乘以exp(j*b0*π/2)),其中,X可以是固定的或预设的,例如X等于序列长度L,即最后一个序列元素,或者,X是系统配置的。Further, similarly, the second sequence set adopted by the data generating method provided by the present invention may further be a sequence set formed by combining the table 4-2 and the table 4-6. At this time, the second sequence set includes four sequences. When the system indicates the information of the second sequence used by the configuration signaling, it may indicate by 2 bits; or, only the sequence shown in Table 4-2 may be stored. The set, when the system indicates the information of the second sequence used by the configuration signaling, first indicates the sequence in the sequence set shown in Table 4-2 by 1 bit, and indicates the Xth element of the sequence by 1 bit. The processing performed (for example, when the bit is 0, it means that the Xth element of the sequence is multiplied by 1 or the phase is rotated by 0, the bit A value of 1 indicates that the Xth element of the sequence is multiplied by 1i or the phase is rotated by π/2; or, the bit is represented as b0, and the processing of the Xth element of the sequence is represented as a b0 power of 1i or Multiply exp(j*b0*π/2)), where X can be fixed or preset, for example X is equal to the sequence length L, ie the last sequence element, or X is system configured.
应用示例5Application example 5
本实施例中,本发明提供的数据生成方法采用的第一序列集合如应用示例1中的表1-1所示。In this embodiment, the first sequence set adopted by the data generating method provided by the present invention is shown in Table 1-1 in Application Example 1.
本实施例中,本发明提供的数据生成方法采用的第二序列集合如表5-1所示,该第二序列集合包括4条长度为4的离散傅里叶变换序列,即exp(j*n*t*2π/N),其中,N=4,n={0,1,2,3},t={0,1,2,3}。In this embodiment, the second sequence set used by the data generating method provided by the present invention is shown in Table 5-1, and the second sequence set includes four discrete Fourier transform sequences of length 4, that is, exp(j* n*t*2π/N), where N=4, n={0,1,2,3}, t={0,1,2,3}.
表5-1Table 5-1
Figure PCTCN2017114801-appb-000019
Figure PCTCN2017114801-appb-000019
本实施例中,本发明提供的数据生成方法从第一序列集合中获取第一序列,获取第一序列的方式如应用示例1所述,不再赘述。In this embodiment, the data generating method provided by the present invention obtains the first sequence from the first sequence set, and the manner of obtaining the first sequence is as described in the application example 1, and details are not described herein again.
本发明提供的数据生成方法还从第二序列集合中获取第二序列,获取第二序列的方式如应用示例1所述,不再赘述。The data generating method provided by the present invention also obtains the second sequence from the second sequence set, and the manner of obtaining the second sequence is as described in the application example 1, and details are not described herein again.
然后,本发明提供的数据生成方法根据第一序列和第二序列生成第三序列,即将第一序列与第二序列进行点乘运算生成第三序列。Then, the data generating method provided by the present invention generates a third sequence according to the first sequence and the second sequence, that is, the first sequence and the second sequence are subjected to dot multiplication to generate a third sequence.
本实施例中,本发明提供的数据生成方法使用所生成的第三序列对第一数据进行扩展处理生成第二数据,进一步可以将该第二数据映射到指定的传输资源上,用于形成发射信号以及发送。 In this embodiment, the data generating method provided by the present invention uses the generated third sequence to perform extended processing on the first data to generate second data, and further may map the second data to a specified transmission resource for forming an emission. Signal and send.
本实施例中,第一序列集合包含4条长度为4的序列,第二序列集合也包含4条长度为4的序列,将第一序列集合中的任意一条序列与第二序列集合中的任意一条序列进行点乘运算,共计可以产生16条长度为4的序列,如表5-2所示。In this embodiment, the first sequence set includes four sequences of length 4, and the second sequence set also includes four sequences of length 4, and any one of the first sequence set and any of the second sequence set. A sequence is multiplied to produce a total of 16 sequences of length 4, as shown in Table 5-2.
表5-2Table 5-2
Figure PCTCN2017114801-appb-000020
Figure PCTCN2017114801-appb-000020
从表5-2所示的序列集合可以看出,该序列集合中的序列元素的取值来自于集合{1,1i,-1,-1i}。该序列集合还可以划分为四组序列,分别为序列0~3、序列4~7、序列8~11、序列12~15;这四组序列中,每组序列中的4条序列是相互正交的;四组序列之间是非正交的,来自于任意两组的两条序列在能量归一化之后的互相关的绝对值不大于sqrt(2)/2。因此,表5-2所 示的序列集合中任意两条序列在能量归一化之后的互相关的绝对值不大于sqrt(2)/2。As can be seen from the sequence set shown in Table 5-2, the value of the sequence elements in the sequence set comes from the set {1, 1i, -1, -1i}. The sequence set can also be divided into four sets of sequences, which are sequence 0-3, sequence 4-7, sequence 8-11, and sequence 12-15; in the four sets of sequences, the four sequences in each set are mutually positive. The four sets of sequences are non-orthogonal, and the absolute values of the cross-correlation after energy normalization of the two sequences from any two groups are not greater than sqrt(2)/2. Therefore, Table 5-2 The absolute value of the cross-correlation of any two sequences in the set of sequences after energy normalization is not greater than sqrt(2)/2.
本实施例中,与应用示例2类似,本发明提供的数据生成方法采用的第一序列集合还可以为对应用示例1中表1-1所示的序列集合进行处理得到的序列集合;例如,对应用示例1中表1-1所示的序列集合中的每条序列的第4个序列元素乘以-1、或相位调整或旋转π得到的序列集合;该序列集合还可以与应用示例1中的表1-1所示的序列集合合并,产生一个包含8条长度为4的序列的序列集合,将该合并后的序列集合作为第一序列集合,然后将该第一序列集合中的任意一条序列与上述第二序列集合中的任意一条序列进行点乘运算,可以产生一个包含32条长度为4的序列的序列集合。该序列集合中的任意两条序列在能量归一化之后的互相关的绝对值也不大于sqrt(2)/2。In this embodiment, similar to the application example 2, the first sequence set adopted by the data generating method provided by the present invention may also be a sequence set obtained by processing the sequence set shown in Table 1-1 in the application example 1; for example, The sequence set obtained by multiplying the fourth sequence element of each sequence in the sequence set shown in Table 1-1 in the application example 1 by -1, or phase adjustment or rotation π; the sequence set is also applicable to the application example 1 The sequence set shown in Table 1-1 is merged to generate a sequence set containing eight sequences of length 4, the merged sequence set is used as the first sequence set, and then any of the first sequence sets is A sequence is multiplied with any one of the above second sequence sets to produce a sequence set comprising 32 sequences of length 4. The absolute value of the cross-correlation of any two sequences in the sequence after energy normalization is also not greater than sqrt(2)/2.
进一步,与应用示例2类似,还可以对应用示例1中表1-1所示的序列集合中的每条序列的第4个序列元素乘以1i、或相位调整或旋转π/2,或者,对应用示例1中表1-1所示的序列集合中的每条序列的第4个序列元素乘以-1i、或相位调整或旋转3*π/2,分别得到包含4条长度为4的序列的序列集合,可以将分别得到的序列集合作为第一序列集合使用,还可以将得到的序列集合合并或与上述第一序列集合合并后作为第一序列集合使用。Further, similarly to the application example 2, the fourth sequence element of each sequence in the sequence set shown in Table 1-1 of Application Example 1 may be multiplied by 1i, or phase-adjusted or rotated by π/2, or, Multiplying the 4th sequence element of each sequence in the sequence set shown in Table 1-1 of Application Example 1 by -1i, or phase adjustment or rotation 3*π/2, respectively, to obtain 4 lengths of 4 The sequence set of the sequence may be used as a first sequence set, or may be combined with the obtained sequence set and used as the first sequence set.
本实施例中,与应用示例3类似,本发明提供的数据生成方法采用的第二序列集合还可以为表5-1所示的序列集合与单位矩阵序列集合合并后形成的序列集合。那么,类似地,可以得到一个包含20条长度为4的可用序列的序列集合,而且,该序列集合相当于在表5-2所示的序列集合基础上增加了单位矩阵序列。In this embodiment, similar to the application example 3, the second sequence set used by the data generation method provided by the present invention may also be a sequence set formed by combining the sequence set and the unit matrix sequence set shown in Table 5-1. Then, similarly, a sequence set containing 20 available sequences of length 4 can be obtained, and the sequence set is equivalent to adding a unit matrix sequence based on the sequence set shown in Table 5-2.
应用示例6Application example 6
本实施例中,本发明提供的数据生成方法采用的第一序列集合如表6-1 所示,该第一序列集合仅有一条序列[1]。In this embodiment, the first sequence set used by the data generating method provided by the present invention is shown in Table 6-1. As shown, the first sequence set has only one sequence [1].
表6-1Table 6-1
序列索引Sequence index 序列元素Sequence element
00 11
本实施例中,本发明提供的数据生成方法采用的第二序列集合如表6-2所示,该第二序列集合包括6条长度为4的序列,并且每个序列中有2个序列元素为0。In this embodiment, the second sequence set used by the data generating method provided by the present invention is as shown in Table 6-2. The second sequence set includes six sequences of length 4, and there are two sequence elements in each sequence. Is 0.
表6-2Table 6-2
Figure PCTCN2017114801-appb-000021
Figure PCTCN2017114801-appb-000021
本实施例中,本发明提供的数据生成方法从第一序列集合中获取第一序列,由于表6-1所示的第一序列集合中仅有一条序列,那么,本实施例中,所获取的第一序列为[1]。这相当于第一序列是系统固定配置的或预设的,无需系统通过配置信令指示。In this embodiment, the data generating method provided by the present invention obtains the first sequence from the first sequence set. Since there is only one sequence in the first sequence set shown in Table 6-1, in this embodiment, the obtained method is obtained. The first sequence is [1]. This is equivalent to the first sequence being fixed or preset by the system, and the system does not need to be indicated by configuration signaling.
本发明提供的数据生成方法还从第二序列集合中获取第二序列,获取第二序列的方式如应用示例1所述,不再赘述。本实施例中,第二序列集合包含6条序列,当系统通过配置信令指示序列信息时,可以通过3比特进行指示。本实施例中,假设所获取的第二序列为表6-2中序列索引0所指示的序列,即[1,1,0,0]。The data generating method provided by the present invention also obtains the second sequence from the second sequence set, and the manner of obtaining the second sequence is as described in the application example 1, and details are not described herein again. In this embodiment, the second sequence set includes six sequences. When the system indicates sequence information through configuration signaling, it can be indicated by 3 bits. In this embodiment, it is assumed that the acquired second sequence is the sequence indicated by the sequence index 0 in Table 6-2, that is, [1, 1, 0, 0].
然后,本发明提供的数据生成方法根据第一序列和第二序列生成第三序列,即将第一序列与第二序列进行乘法运算生成第三序列,那么,该第 三序列为:[1,1,0,0]。Then, the data generating method provided by the present invention generates a third sequence according to the first sequence and the second sequence, that is, multiplying the first sequence and the second sequence to generate a third sequence, then the first The three sequences are: [1, 1, 0, 0].
本实施例中,本发明提供的数据生成方法还可以将表6-1所示的第一序列集合中的序列或将所获取的第一序列进行能量调整或能量归一化处理,使得序列的总能量为1/Z,其中,Z为第二序列集合每个序列中的0元素的数量;本实施例中Z=2,那么,例如,将所获取的第一序列进行能量调整或能量归一化处理后得到的序列为[sqrt(2)/2];In this embodiment, the data generating method provided by the present invention may further perform energy adjustment or energy normalization processing on the sequence in the first sequence set shown in Table 6-1 or the obtained first sequence, so that the sequence is The total energy is 1/Z, where Z is the number of 0 elements in each sequence of the second sequence set; in this embodiment, Z=2, then, for example, the obtained first sequence is energy-adjusted or energy-returned. The sequence obtained after the processing is [sqrt(2)/2];
或者,将所生成的第三序列进行能量调整或能量归一化处理,使得该序列的总能量为1;以上述所生成的第三序列为例,对其进行能量调整或能量归一化处理后得到的序列为[sqrt(2)/2,sqrt(2)/2,0,0],该序列的总能量为1,可以将该序列作为最终生成的第三序列。Alternatively, the generated third sequence is subjected to energy adjustment or energy normalization such that the total energy of the sequence is 1; and the third sequence generated as an example is used for energy adjustment or energy normalization. The resulting sequence is [sqrt(2)/2, sqrt(2)/2, 0, 0], and the total energy of the sequence is 1, which can be used as the finally generated third sequence.
本实施例中,本发明提供的数据生成方法使用所生成的第三序列对第一数据进行扩展处理生成第二数据,进一步可以将该第二数据映射到指定的传输资源上,用于形成发射信号以及发送。In this embodiment, the data generating method provided by the present invention uses the generated third sequence to perform extended processing on the first data to generate second data, and further may map the second data to a specified transmission resource for forming an emission. Signal and send.
本实施例中,本发明提供的数据生成方法采用的第一序列集合还可以为对表6-1所示的序列集合进行处理得到的序列集合;例如,对表6-1所示的序列集合中的序列乘以指定实数或复数(比如1i,-1,-1i),或者,相位调整或旋转指定量(比如π/2,π,3*π/2),将处理后得到的序列集合作为第一序列集合。In this embodiment, the first sequence set used by the data generating method provided by the present invention may also be a sequence set obtained by processing the sequence set shown in Table 6-1; for example, the sequence set shown in Table 6-1. The sequence in the multiplication is multiplied by the specified real or complex number (such as 1i, -1, -1i), or the phase adjustment or rotation of the specified amount (such as π/2, π, 3 * π/2), the sequence set obtained after processing As a first sequence set.
本实施例中,第一序列固定为[1],本发明提供的数据生成方法可以不再需要表6-1所示的第一序列集合,不再需要从该第一序列集合中获取第一序列,可以仅使用表6-2所示的第二序列集合,仅从该第二序列集合中获取第二序列,并将所获取的第二序列作为将要生成的第三序列。In this embodiment, the first sequence is fixed to [1], and the data generation method provided by the present invention can eliminate the need for the first sequence set shown in Table 6-1, and no longer needs to obtain the first sequence from the first sequence set. For the sequence, only the second sequence set shown in Table 6-2 can be used, only the second sequence is obtained from the second sequence set, and the acquired second sequence is taken as the third sequence to be generated.
进一步地,当仅使用表6-2所示的第二序列集合时,上述对表6-1所示的序列集合进行处理得到新的序列集合的方法也可以作用于第二序列集合;例如,对表6-2所示的序列集合中的每个序列的各个元素乘以指定实数或复数(比如1i,-1,-1i),或者,相位调整或旋转指定量(比如π/2,π,3*π/2), 将处理后得到的序列集合作为第二序列集合。Further, when only the second sequence set shown in Table 6-2 is used, the above method of processing the sequence set shown in Table 6-1 to obtain a new sequence set may also be applied to the second sequence set; for example, Multiply each element of each sequence in the sequence set shown in Table 6-2 by the specified real or complex number (such as 1i, -1, -1i), or phase adjustment or rotation by a specified amount (such as π/2, π) , 3*π/2), The sequence set obtained after the processing is taken as the second sequence set.
应用示例7Application example 7
本实施例中,本发明提供的数据生成方法采用的第一序列集合如表7-1所示,该第一序列集合包括4条长度为1的序列。该第一序列集合也可以看作一个包含4个数值的数值集合。In this embodiment, the first sequence set used by the data generating method provided by the present invention is as shown in Table 7-1, and the first sequence set includes four sequences of length 1. The first set of sequences can also be viewed as a set of values containing four values.
表7-1Table 7-1
序列索引Sequence index 序列元素Sequence element
00 11
11 1i1i
22 -1-1
33 -1i-1i
本实施例中,本发明提供的数据生成方法采用的第二序列集合如应用示例6中的表6-2所示,该第二序列集合包括6条长度为4的序列,并且每个序列中有2个序列元素为0。In this embodiment, the second sequence set adopted by the data generating method provided by the present invention is as shown in Table 6-2 in Application Example 6, and the second sequence set includes six sequences of length 4, and in each sequence. There are 2 sequence elements with 0.
本实施例中,本发明提供的数据生成方法从第一序列集合中获取第一序列,具体地,将第一序列集合中的4条序列均作为第一序列,即获取4条第一序列。In this embodiment, the data generating method provided by the present invention obtains the first sequence from the first sequence set. Specifically, the four sequences in the first sequence set are used as the first sequence, that is, the four first sequences are obtained.
本发明提供的数据生成方法还从第二序列集合中获取第二序列,获取第二序列的方式如应用示例1所述,不再赘述。本实施例中,第二序列集合包含6条序列,当系统通过配置信令指示序列信息时,可以通过3比特进行指示。本实施例中,假设所获取的第二序列为表6-2中序列索引0所指示的序列,即[1,1,0,0]。The data generating method provided by the present invention also obtains the second sequence from the second sequence set, and the manner of obtaining the second sequence is as described in the application example 1, and details are not described herein again. In this embodiment, the second sequence set includes six sequences. When the system indicates sequence information through configuration signaling, it can be indicated by 3 bits. In this embodiment, it is assumed that the acquired second sequence is the sequence indicated by the sequence index 0 in Table 6-2, that is, [1, 1, 0, 0].
然后,本发明提供的数据生成方法根据第一序列和第二序列生成第三序列,即将第一序列与第二序列进行乘法运算生成第三序列,那么,可以生成4条第三序列,分别为:[1,1,0,0];[1i,1i,0,0];[-1,-1,0, 0];[-1i,-1i,0,0]。Then, the data generating method provided by the present invention generates a third sequence according to the first sequence and the second sequence, that is, multiplying the first sequence and the second sequence to generate a third sequence, then, four third sequences can be generated, respectively :[1,1,0,0];[1i,1i,0,0];[-1,-1,0, 0]; [-1i, -1i, 0, 0].
本实施例中,本发明提供的数据生成方法还可以将表7-1所示的第一序列集合中的序列或将所获取的第一序列进行能量调整或能量归一化处理,使得序列的总能量为1/Z,其中,Z为第二序列集合每个序列中的0元素的数量,本实施例中Z=2;或者,将所生成的第三序列进行能量调整或能量归一化处理,使得序列的总能量为1。In this embodiment, the data generating method provided by the present invention may further perform energy adjustment or energy normalization processing on the sequence in the first sequence set shown in Table 7-1 or the first sequence obtained in the present invention, so that the sequence is The total energy is 1/Z, where Z is the number of 0 elements in each sequence of the second sequence set, Z=2 in this embodiment; or, the generated third sequence is energy-adjusted or energy normalized. Processed so that the total energy of the sequence is one.
本实施例中,本发明提供的数据生成方法使用所生成的第三序列对第一数据(例如编码后的比特)进行映射处理(例如将2比特的四种组合00、01、11、10与上述生成的4条第三序列分别一一映射),生成第二数据,该第二数据可以称为处理后的数据符号,其值即进行映射处理时所使用的第三序列。进一步,本实施例可以将该第二数据映射到指定的传输资源上,用于形成发射信号以及发送。In this embodiment, the data generating method provided by the present invention performs mapping processing on the first data (for example, the encoded bits) using the generated third sequence (for example, combining four combinations of two bits 00, 01, 11, and 10) The four generated third sequences are mapped one by one, and the second data is generated. The second data may be referred to as a processed data symbol, and the value is the third sequence used in the mapping process. Further, this embodiment may map the second data to a specified transmission resource for forming a transmission signal and transmitting.
本实施例中,第一序列集合包含4条长度为1的序列,第二序列集合包含6条长度为4的序列,使用第二序列集合中的任意一条序列对第一序列集合中的4条序列进行处理,即第一序列集合中的4条序列分别与第二序列集合中的任意一条序列进行乘法运算,共计可以产生6组序列,每组序列包含4条序列,用于例如2比特数据映射。In this embodiment, the first sequence set includes four sequences of length 1, the second sequence set includes six sequences of length 4, and any one of the second sequence sets is used for four of the first sequence sets. The sequence is processed, that is, the four sequences in the first sequence set are respectively multiplied with any one of the second sequence sets, and a total of six sets of sequences can be generated, and each set of sequences includes four sequences for, for example, 2-bit data. Mapping.
本实施例中,本发明提供的数据生成方法采用的第一序列集合还可以为表7-2所示的序列集合,该序列集合包括4条长度为1的序列,或者可以看作一个包含4个数值的数值集合。表7-2所示的序列集合中的4条序列分别与第二序列集合中的任意一条序列进行乘法运算,可以产生6组序列,每组序列包含4条序列,用于例如2比特数据映射。In this embodiment, the first sequence set used by the data generating method provided by the present invention may also be a sequence set shown in Table 7-2, where the sequence set includes four sequences of length 1 or may be regarded as one containing 4 A collection of numerical values. The four sequences in the sequence set shown in Table 7-2 are respectively multiplied with any one of the second sequence sets, and six sets of sequences can be generated, each set consisting of four sequences for, for example, 2-bit data mapping. .
表7-2Table 7-2
序列索引Sequence index 序列元素Sequence element
00 1+1i1+1i
11 -1+1i-1+1i
22 -1-1i-1-1i
33 1-1i1-1i
本实施例中,本发明提供的数据生成方法采用的第一序列集合还可以为表7-3或表7-4所示的序列集合,这两个序列集合均包括2条长度为1的序列,或者均可以看作包含2个数值的数值集合。表7-3或表7-4所示的序列集合中的2条序列分别与第二序列集合中的任意一条序列进行乘法运算,可以产生6组序列,每组序列包含2条序列,用于例如1比特数据映射。In this embodiment, the first sequence set used by the data generating method provided by the present invention may also be a sequence set shown in Table 7-3 or Table 7-4, where the two sequence sets each include two sequences of length 1 , or both can be seen as a collection of values containing two values. The two sequences in the sequence set shown in Table 7-3 or Table 7-4 are respectively multiplied with any one of the second sequence sets, and six sets of sequences can be generated, and each set of sequences contains two sequences for For example, 1-bit data mapping.
表7-3Table 7-3
序列索引Sequence index 序列元素Sequence element
00 11
11 -1-1
表7-4Table 7-4
序列索引Sequence index 序列元素Sequence element
00 1i1i
11 -1i-1i
本实施例中,表7-1、表7-2、表7-3或表7-4所示的第一序列集合中的每个序列还可以扩展为长度为4的序列,序列每个元素相同,从而可以与第二序列集合中的任意一条序列进行点乘运算生成第三序列。In this embodiment, each sequence in the first sequence set shown in Table 7-1, Table 7-2, Table 7-3, or Table 7-4 can also be extended to a sequence of length 4, each element of the sequence. The same, so that a point multiplication operation can be performed with any one of the second sequence sets to generate a third sequence.
本实施例中,本发明提供的数据生成方法还可以不使用表7-1所示的第一序列集合,不再需要从该第一序列集合中获取第一序列,可以仅使用第二序列集合,仅从第二序列集合中获取第二序列,并将所获取的第二序列作为将要使用的序列;进一步,使用该将要使用的序列对数据(例如编码后的2比特b0b1)进行映射处理,即将数据映射为该将要使用的序列,并乘以1i的D次方或乘以exp(j*D*π/2),生成处理后的数据符号,然后将处理后的数据符号形成发射信号,用于发送;其中,D为2比特b0b1对应的 十进制数值;In this embodiment, the data generating method provided by the present invention may not use the first sequence set shown in Table 7-1, and the first sequence is not required to be obtained from the first sequence set, and only the second sequence set may be used. Obtaining the second sequence only from the second sequence set, and using the acquired second sequence as the sequence to be used; further, mapping the data (for example, the encoded 2-bit b0b1) using the sequence to be used, The data is mapped to the sequence to be used, multiplied by the D power of 1i or multiplied by exp(j*D*π/2) to generate the processed data symbols, and then the processed data symbols form a transmission signal. For sending; where D is 2 bits corresponding to b0b1 Decimal value;
类似地,也可以不使用表7-2所示的第一序列集合,可以仅从第二序列集合中获取第二序列,并将所获取的第二序列作为将要使用的序列;进一步,将数据(例如编码后的2比特b0b1)映射为该将要使用的序列,并乘以exp(j*(2D+1)*π/4),生成处理后的数据符号;其中,D为2比特b0b1对应的十进制数值;Similarly, instead of using the first sequence set shown in Table 7-2, the second sequence may be obtained only from the second sequence set, and the acquired second sequence is taken as the sequence to be used; further, the data is (for example, the encoded 2-bit b0b1) is mapped to the sequence to be used, and multiplied by exp(j*(2D+1)*π/4) to generate a processed data symbol; where D is a 2-bit b0b1 corresponding Decimal value;
类似地,也可以不使用表7-3所示的第一序列集合,可以仅从第二序列集合中获取第二序列,并将所获取的第二序列作为将要使用的序列;进一步,将数据(例如编码后的1比特b0)映射为该将要使用的序列,并乘以1i的2*b0次方或乘以exp(j*b0*π),生成处理后的数据符号;Similarly, instead of using the first sequence set shown in Table 7-3, the second sequence may be obtained only from the second sequence set, and the acquired second sequence is taken as the sequence to be used; further, the data is (for example, the encoded 1 bit b0) is mapped to the sequence to be used, and multiplied by 2*b0 power of 1i or multiplied by exp(j*b0*π) to generate a processed data symbol;
类似地,也可以不使用表7-4所示的第一序列集合,可以仅从第二序列集合中获取第二序列,并将所获取的第二序列作为将要使用的序列;进一步,将数据(例如编码后的1比特b0)映射为该将要使用的序列,并乘以1i的(2*b0+1)次方或乘以exp(j*(2*b0+1)*π/2),生成处理后的数据符号。Similarly, instead of using the first sequence set shown in Table 7-4, the second sequence may be obtained only from the second sequence set, and the acquired second sequence is taken as the sequence to be used; further, the data is (eg, the encoded 1 bit b0) is mapped to the sequence to be used, multiplied by 1i's (2*b0+1) power or multiplied by exp(j*(2*b0+1)*π/2) , generate processed data symbols.
应用示例8Application example 8
本实施例中,本发明提供的数据生成方法采用的第三序列集合表8-1所示。In this embodiment, the third sequence set table 8-1 used by the data generating method provided by the present invention is shown.
表8-1Table 8-1
Figure PCTCN2017114801-appb-000022
Figure PCTCN2017114801-appb-000022
Figure PCTCN2017114801-appb-000023
Figure PCTCN2017114801-appb-000023
本实施例中,本发明提供的数据生成方法从第三序列集合中确定第三序列,包括: In this embodiment, the data generating method provided by the present invention determines the third sequence from the third sequence set, including:
(1)采用随机选择的方式从第三序列集合中获取第三序列;例如,通过随机数产生器产生一个随机数,将该随机数作为序列索引,或根据该随机数和预设规则确定序列索引(比如将该随机数对第三序列集合中的序列数量进行求余运算,将余数作为序列索引),根据该序列索引从第三序列集合中确定第三序列;(1) obtaining a third sequence from the third sequence set by using a random selection method; for example, generating a random number by using a random number generator, using the random number as a sequence index, or determining a sequence according to the random number and a preset rule; Indexing (such as performing a remainder operation on the number of sequences in the third sequence set, using the remainder as a sequence index), and determining a third sequence from the third sequence set according to the sequence index;
(2)根据预设规则从第三序列集合中获取第三序列;例如,使用指定参数的值对第三序列集合中的序列数量进行求余运算,将余数作为序列索引,根据该序列索引从第三序列集合中确定第三序列,其中,指定参数可以为设备身份识别信息等;(2) obtaining a third sequence from the third sequence set according to a preset rule; for example, performing a remainder operation on the number of sequences in the third sequence set using the value of the specified parameter, using the remainder as a sequence index, according to the sequence index Determining a third sequence in the third sequence set, wherein the specified parameter may be device identification information or the like;
(3)根据系统配置信息从第三序列集合中获取第三序列;例如,系统固定配置、半静态配置、动态配置所使用的序列索引,则可以根据系统配置信息得到序列索引,然后根据该序列索引从第三序列集合中确定第三序列;由于第三序列集合中包含32条序列,当系统通过配置信令指示序列信息时,可以通过5比特进行指示。(3) obtaining a third sequence from the third sequence set according to the system configuration information; for example, a sequence index used by the system fixed configuration, semi-static configuration, and dynamic configuration, the sequence index may be obtained according to the system configuration information, and then according to the sequence The index determines the third sequence from the third sequence set; since the third sequence set contains 32 sequences, when the system indicates the sequence information through configuration signaling, it can be indicated by 5 bits.
本实施例中,本发明提供的数据生成方法使用所确定的第三序列对第一数据进行扩展处理生成第二数据,进一步可以将该第二数据映射到指定的传输资源上,用于形成发射信号以及发送。In this embodiment, the data generating method provided by the present invention uses the determined third sequence to perform extended processing on the first data to generate second data, and further may map the second data to a specified transmission resource for forming a transmission. Signal and send.
本实施例中,本发明提供的数据生成方法还可以将表8-1所示的第三序列集合中的序列进行能量调整或能量归一化处理,使得每个序列的总能量为1;或者,将所确定的第三序列进行能量调整或能量归一化处理,使得该序列的总能量为1。In this embodiment, the data generating method provided by the present invention may further perform energy adjustment or energy normalization processing on the sequence in the third sequence set shown in Table 8-1, so that the total energy of each sequence is 1; or The determined third sequence is subjected to energy adjustment or energy normalization such that the total energy of the sequence is 1.
本实施例中,从表8-1所示的第三序列集合可以看出,该第三序列集合中的序列元素的取值来自于集合{1,1i,-1,-1i,2,2i,-2,-2i,0}。该元素集合{1,1i,-1,-1i,2,2i,-2,-2i,0}还可以表示为二维复数星座图的形成,如图6所示。 In this embodiment, it can be seen from the third sequence set shown in Table 8-1 that the values of the sequence elements in the third sequence set are from the set {1, 1i, -1, -1i, 2, 2i , -2, -2i, 0}. The set of elements {1, 1i, -1, -1i, 2, 2i, -2, -2i, 0} can also be represented as a two-dimensional complex constellation, as shown in FIG.
实施例二 Embodiment 2
本发明实施例提供了一种数据生成方法,如图7所示,该方法包括:An embodiment of the present invention provides a data generating method. As shown in FIG. 7, the method includes:
步骤701:从第一序列集合中获取第一序列。Step 701: Acquire a first sequence from the first sequence set.
其中,所述第一序列集合包括包含M条长度为L的序列的第一指定序列集合、和/或对所述第一指定序列集合进行处理得到的序列集合;其中,M为正整数,L为正整数。The first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set; wherein M is a positive integer, L Is a positive integer.
可选地,所述第一指定序列集合中的序列元素的取值来自于以下集合至少之一:{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,-1+1i,-1-1i,1-1i};{0};{1,1i,-1,-1i,0};{1+1i,-1+1i,-1-1i,1-1i,0};{1,1i,-1,-1i,2,2i,-2,-2i,0};其中,i为虚数单位,i=sqrt(-1)。Optionally, the value of the sequence element in the first specified sequence set is from at least one of the following sets: {1, 1i, -1, -1i}; {1, -1}; {1i, -1i };{1};{-1};{1i};{-1i};{1+1i,-1+1i,-1-1i,1-1i};{0};{1,1i,- 1,-1i,0};{1+1i,-1+1i,-1-1i,1-1i,0}; {1,1i,-1,-1i,2,2i,-2,-2i , 0}; where i is an imaginary unit, i=sqrt(-1).
可选地,所述对所述第一指定序列集合中的序列进行处理,包括:Optionally, the processing the sequence in the first specified sequence set includes:
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素乘以1、1i、-1、或-1i,或者乘以1i的A次方;或者,Multiplying the Xth sequence element of each sequence or each sequence in the first specified sequence set by 1, 1i, -1, or -1i, or multiplying by the 1st power of A; or
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素进行B*π的相位调整或旋转,或者乘以exp(j*B*π),j为虚数单位,j=sqrt(-1);或者,Performing B*π phase adjustment or rotation for each sequence in the first specified sequence set or the Xth sequence element of each sequence, or multiplying exp(j*B*π), j is an imaginary unit, j=sqrt(-1); or,
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素乘以指定值,或者分别乘以指定值;Multiplying the Xth sequence element of each sequence or each sequence in the first specified sequence set by a specified value, or multiplying by a specified value;
其中,X为大于或等于1且小于或等于L的整数,A为整数,B为实数;Where X is an integer greater than or equal to 1 and less than or equal to L, A is an integer, and B is a real number;
其中,X可以为大于或等于1且小于或等于L的多个值。Wherein X may be a plurality of values greater than or equal to 1 and less than or equal to L.
可选地,从第一序列集合中获取第一序列,包括以下之一:Optionally, obtaining the first sequence from the first sequence set, including one of the following:
采用随机选择的方式从所述第一序列集合中获取第一序列;Obtaining the first sequence from the first sequence set in a random selection manner;
根据第一预设规则从所述第一序列集合中获取第一序列;Obtaining a first sequence from the first sequence set according to a first preset rule;
根据系统配置信息从所述第一序列集合中获取第一序列;Obtaining a first sequence from the first sequence set according to system configuration information;
其中,所述第一预设规则至少:包括按照预设参数和/或预设公式进行 计算,或者预设的对应关系或映射关系。The first preset rule includes at least: performing according to a preset parameter and/or a preset formula. Calculation, or a preset correspondence or mapping relationship.
步骤702:使用所述第一序列对第一数据进行处理,生成第二数据。Step 702: Process the first data by using the first sequence to generate second data.
其中,所述处理包括扩展处理、映射处理、或调制处理。Wherein, the processing includes an expansion process, a mapping process, or a modulation process.
其中,所述第一数据至少包括比特、编码后的比特、调制符号。The first data includes at least a bit, an encoded bit, and a modulation symbol.
步骤703:从第二序列集合中获取第二序列。Step 703: Acquire a second sequence from the second sequence set.
其中,所述第二序列集合包括包含N条长度为C的序列的第二指定序列集合、和/或对所述第二指定序列集合进行处理得到的序列集合;其中,N为正整数,C为正整数。The second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set; wherein N is a positive integer, C Is a positive integer.
可选地,所述第二指定序列集合包括以下至少之一:Optionally, the second specified sequence set includes at least one of the following:
哈达玛序列集合;Hadamard sequence collection;
沃尔什序列集合;Walsh sequence collection;
离散傅里叶变换序列集合;a set of discrete Fourier transform sequences;
包含指定数量或指定比例的0元素的序列的集合;a collection of sequences containing a specified number or a specified proportion of 0 elements;
单位矩阵序列集合。A collection of unit matrix sequences.
可选地,所述对所述第二指定序列集合中的序列进行处理,包括:Optionally, the processing the sequence in the second specified sequence set includes:
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素乘以1、1i、-1、或-1i,或者,乘以1i的E次方;或者,Multiplying the Yth sequence element of each sequence or each sequence in the second specified sequence set by 1, 1i, -1, or -1i, or multiplying by the E-th power of 1i; or
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素进行F*π的相位调整或旋转,或者,乘以exp(j*F*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of F*π for each sequence in the second specified sequence set or the Yth sequence element of each sequence, or multiply exp(j*F*π), j is an imaginary unit , j=sqrt(-1); or,
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素乘以指定值,或者分别乘以指定值;Multiplying each of the sequence of the second specified sequence set or the Yth sequence element of each sequence by a specified value, or multiplying by a specified value;
其中,Y为大于或等于1且小于或等于C的整数,E为整数,F为实数;Wherein Y is an integer greater than or equal to 1 and less than or equal to C, E is an integer, and F is a real number;
其中,Y可以为大于或等于1且小于或等于C的多个值。Wherein Y may be a plurality of values greater than or equal to 1 and less than or equal to C.
可选地,从第二序列集合中获取第二序列,包括以下之一:Optionally, the second sequence is obtained from the second sequence set, including one of the following:
采用随机选择的方式从所述第二序列集合中获取第二序列; Obtaining a second sequence from the second set of sequences in a randomly selected manner;
根据第二预设规则从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second sequence set according to a second preset rule;
根据系统配置信息从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second sequence set according to system configuration information;
其中,所述第二预设规则至少包括:按照预设参数和/或预设公式进行计算,或者预设的对应关系或映射关系。The second preset rule includes: performing calculation according to a preset parameter and/or a preset formula, or a preset correspondence or mapping relationship.
步骤704:使用所述第二序列对所述第二数据进行处理,生成第三数据。Step 704: Process the second data by using the second sequence to generate third data.
可选地,使用所述第二序列对所述第二数据进行处理,生成第三数据,包括:Optionally, the second data is processed by using the second sequence to generate third data, including:
将所述第二数据与所述第二序列进行点乘运算,生成第三数据,或者,Performing a dot multiplication operation on the second data and the second sequence to generate third data, or
将所述第二数据与所述第二序列进行乘法运算,生成第三数据,或者,Multiplying the second data and the second sequence to generate third data, or
使用所述第二数据替换所述第二序列中的非零元素,生成第三数据;或者,Replacing the non-zero elements in the second sequence with the second data to generate third data; or
将所述第二数据与所述第二序列中的非零元素进行点乘或乘法运算后得到的值替换所述第二序列中的非零元素,生成第三数据。Substituting a value obtained by dot-multiplying or multiplying the second data with a non-zero element in the second sequence by a non-zero element in the second sequence to generate third data.
进一步地,可选地,所述方法还包括:Further, optionally, the method further includes:
步骤705:将所述第三数据映射到指定的传输资源上,用于形成发射信号以及发送。Step 705: Map the third data to a specified transmission resource for forming a transmission signal and transmitting.
其中,指定的传输资源可以是随机选择的、预设的或系统配置的;The designated transmission resource may be randomly selected, preset, or configured by the system;
其中,所述传输资源包括载波、时隙、时频资源、空域资源、码域资源、跳频模式、天线端口等至少之一,可以为资源单元、资源块、资源集合、资源图样的定义或形式。The transmission resource includes at least one of a carrier, a time slot, a time-frequency resource, a spatial domain resource, a code domain resource, a frequency hopping mode, and an antenna port, and may be a resource unit, a resource block, a resource set, a resource pattern, or form.
其中,指定的传输资源为目标时频资源时,目标时频资源可以为上行数据信道(或称为物理上行共享信道),或者上行控制信道(或称为物理上行控制信道),或者随机接入信道(或称为物理随机接入信道);对应地,将传输信号载波调制到目标时频资源上进行传输,包括:When the specified transmission resource is the target time-frequency resource, the target time-frequency resource may be an uplink data channel (or a physical uplink shared channel), or an uplink control channel (or a physical uplink control channel), or random access. Channel (or called a physical random access channel); correspondingly, the transmission signal carrier is modulated onto the target time-frequency resource for transmission, including:
当传输信息包含有终端身份标识信息;或者,包含有终端身份标识信息和小区标识信息,或者包含有终端身份标识信息、小区标识信息和信令 信息,或者包含有终端身份标识信息、小区标识信息、信令信息和数据信息时,所述发射机将所述传输信号载波调制到所述随机接入信道或物理随机接入信道(PRACH),或者上行控制信道(或称为物理上行控制信道(PUCCH)上进行传输。When the transmission information includes terminal identity information; or includes terminal identity information and cell identity information, or includes terminal identity information, cell identity information, and signaling The transmitter, or the terminal identifier information, the cell identification information, the signaling information, and the data information, the transmitter modulates the transmission signal carrier to the random access channel or a physical random access channel (PRACH), Or transmitting on the uplink control channel (or called the Physical Uplink Control Channel (PUCCH).
本实施例中,从第一序列集合和第二序列集合中分别获取第一序列和第二序列;其中,第一序列集合中的序列的元素主要使用{1,1i,-1,-1i};第二序列集合为哈达玛序列集合、DFT序列集合、单位矩阵序列集合等。本发明本实施例方案中,(发射机和接收机)可以仅存储2个较小的序列集合(即第一序列集合和第二序列集合),而不需要存储较大的包含全部可用序列的序列集合,具有较低的存储需求。序列元素使用{1,1i-1,-1i},运算简单,复杂度较低,从而可以降低发射机扩展处理、接收机相关处理的运算复杂度,有利于满足URLLC场景的低时延需求。In this embodiment, the first sequence and the second sequence are respectively obtained from the first sequence set and the second sequence set; wherein the elements of the sequence in the first sequence set mainly use {1, 1i, -1, -1i} The second sequence set is a Hadamard sequence set, a DFT sequence set, an identity matrix sequence set, and the like. In the solution of this embodiment of the present invention, (transmitter and receiver) may store only two smaller sequence sets (ie, the first sequence set and the second sequence set) without storing a larger one containing all available sequences. A collection of sequences with lower storage requirements. The sequence elements use {1,1i-1,-1i}, which is simple in operation and low in complexity, which can reduce the computational complexity of transmitter extension processing and receiver-related processing, and is beneficial to meet the low latency requirement of the URLLC scenario.
实施例三 Embodiment 3
本发明实施例提供了一种数据传输方法,如图8所示,该方法包括:An embodiment of the present invention provides a data transmission method. As shown in FIG. 8, the method includes:
步骤801:从第一序列集合中获取第一序列。Step 801: Acquire a first sequence from the first sequence set.
其中,所述第一序列集合包括包含M条长度为L的序列的第一指定序列集合、和/或对所述第一指定序列集合进行处理得到的序列集合;其中,M为正整数,L为正整数。The first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set; wherein M is a positive integer, L Is a positive integer.
可选地,所述第一指定序列集合中的序列元素的取值来自于以下集合至少之一:{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,-1+1i,-1-1i,1-1i};{0};{1,1i,-1,-1i,0};{1+1i,-1+1i,-1-1i,1-1i,0};{1,1i,-1,-1i,2,2i,-2,-2i,0};其中,i为虚数单位,i=sqrt(-1)。Optionally, the value of the sequence element in the first specified sequence set is from at least one of the following sets: {1, 1i, -1, -1i}; {1, -1}; {1i, -1i };{1};{-1};{1i};{-1i};{1+1i,-1+1i,-1-1i,1-1i};{0};{1,1i,- 1,-1i,0};{1+1i,-1+1i,-1-1i,1-1i,0}; {1,1i,-1,-1i,2,2i,-2,-2i , 0}; where i is an imaginary unit, i=sqrt(-1).
可选地,所述对所述第一指定序列集合中的序列进行处理,包括:Optionally, the processing the sequence in the first specified sequence set includes:
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素乘以1、1i、-1、或-1i,或者乘以1i的A次方;或者, Multiplying the Xth sequence element of each sequence or each sequence in the first specified sequence set by 1, 1i, -1, or -1i, or multiplying by the 1st power of A; or
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素进行B*π的相位调整或旋转,或者乘以exp(j*B*π),j为虚数单位,j=sqrt(-1);或者,Performing B*π phase adjustment or rotation for each sequence in the first specified sequence set or the Xth sequence element of each sequence, or multiplying exp(j*B*π), j is an imaginary unit, j=sqrt(-1); or,
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素乘以指定值,或者分别乘以指定值;Multiplying the Xth sequence element of each sequence or each sequence in the first specified sequence set by a specified value, or multiplying by a specified value;
其中,X为大于或等于1且小于或等于L的整数,A为整数,B为实数;Where X is an integer greater than or equal to 1 and less than or equal to L, A is an integer, and B is a real number;
其中,X可以为大于或等于1且小于或等于L的多个值。Wherein X may be a plurality of values greater than or equal to 1 and less than or equal to L.
可选地,从第一序列集合中获取第一序列,包括以下之一:Optionally, obtaining the first sequence from the first sequence set, including one of the following:
采用随机选择的方式从所述第一序列集合中获取第一序列;Obtaining the first sequence from the first sequence set in a random selection manner;
根据第一预设规则从所述第一序列集合中获取第一序列;Obtaining a first sequence from the first sequence set according to a first preset rule;
根据系统配置信息从所述第一序列集合中获取第一序列;Obtaining a first sequence from the first sequence set according to system configuration information;
其中,所述第一预设规则至少包括:按照预设参数和/或预设公式进行计算,或者预设的对应关系或映射关系。The first preset rule includes: performing calculation according to a preset parameter and/or a preset formula, or a preset correspondence or mapping relationship.
步骤802:使用所述第一序列对第一数据进行处理,生成第二数据。Step 802: Process the first data by using the first sequence to generate second data.
其中,所述处理包括扩展处理、映射处理、或调制处理。Wherein, the processing includes an expansion process, a mapping process, or a modulation process.
其中,所述第一数据至少包括比特、编码后的比特、调制符号。The first data includes at least a bit, an encoded bit, and a modulation symbol.
步骤803:确定将要使用的传输资源。Step 803: Determine a transmission resource to be used.
可选地,所述确定将要使用的传输资源,包括:Optionally, the determining the transmission resource to be used includes:
根据系统配置信息确定将要使用的传输资源;Determine the transmission resources to be used according to the system configuration information;
根据预设规则确定将要使用的传输资源;Determining the transmission resources to be used according to preset rules;
采用随机选择的方式确定将要使用的传输资源;Determine the transmission resources to be used in a random selection manner;
从第二序列集合中获取第二序列,根据所述第二序列确定将要使用的传输资源。A second sequence is obtained from the second sequence set, and a transmission resource to be used is determined according to the second sequence.
其中,所述系统配置信息包括系统预配置的传输资源的信息、或系统调度的传输资源的信息。 The system configuration information includes information of a pre-configured transmission resource of the system or information of a transmission resource scheduled by the system.
其中,所述预设规则包括按照预设参数和/或预设公式进行计算,或者预设的对应关系或映射关系,或者预设的资源图样选择模式或跳转模式。The preset rule includes performing calculation according to a preset parameter and/or a preset formula, or a preset correspondence or mapping relationship, or a preset resource pattern selection mode or a jump mode.
其中,所述传输资源包括载波、时隙、时频资源、空域资源、码域资源、跳频模式、天线端口等至少之一,可以为资源单元、资源块、资源集合、资源图样的定义或形式。The transmission resource includes at least one of a carrier, a time slot, a time-frequency resource, a spatial domain resource, a code domain resource, a frequency hopping mode, and an antenna port, and may be a resource unit, a resource block, a resource set, a resource pattern, or form.
可选地,所述第二序列集合包括包含N条长度为C的序列的第二指定序列集合;其中,N为正整数,C为正整数。Optionally, the second sequence set includes a second specified sequence set comprising N sequences of length C; wherein N is a positive integer and C is a positive integer.
可选地,所述第二指定序列集合包括以下至少之一:Optionally, the second specified sequence set includes at least one of the following:
包含指定数量或指定比例的0元素的序列的集合;a collection of sequences containing a specified number or a specified proportion of 0 elements;
单位矩阵序列集合;Unit matrix sequence set;
其中,所述包含指定数量或指定比例的0元素的序列中的非零元素可以为1。Wherein, the non-zero element in the sequence containing the specified number or the specified 0 element may be 1.
可选地,所述从第二序列集合中获取第二序列,包括以下之一:Optionally, the obtaining the second sequence from the second sequence set includes one of the following:
采用随机选择的方式从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second set of sequences in a randomly selected manner;
根据第二预设规则从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second sequence set according to a second preset rule;
根据系统配置信息从所述第二序列集合中获取第二序列。Obtaining a second sequence from the second set of sequences according to system configuration information.
其中,所述第二预设规则至少包括:按照预设参数和/或预设公式进行计算,或者预设的对应关系或映射关系。The second preset rule includes: performing calculation according to a preset parameter and/or a preset formula, or a preset correspondence or mapping relationship.
可选地,所述根据所述第二序列确定将要使用的传输资源包括根据所述第二序列中的非零元素确定将要使用的传输资源位置;例如,根据所述第二序列中的非零元素的位置从一个资源集合、或一组资源块、或一组资源单元中确定将要使用的传输资源位置。Optionally, the determining, according to the second sequence, the transmission resource to be used comprises determining a location of a transmission resource to be used according to a non-zero element in the second sequence; for example, according to non-zero in the second sequence The location of an element determines the location of the transmission resource to be used from a collection of resources, or a set of resource blocks, or a set of resource elements.
进一步可选地,所述方法还包括:Further optionally, the method further includes:
步骤804:将所述第二数据映射到所述将要使用的传输资源上,用于形成发射信号以及发送。Step 804: Map the second data to the transmission resource to be used for forming a transmission signal and transmitting.
本实施例中,从第一序列集合获取第一序列,其中,第一序列集合中 的序列的元素主要使用{1,1i,-1,-1i}。本发明本实施例方案中,(发射机和接收机)可以仅存储2个较小的序列集合(即第一序列集合和第二序列集合),而不需要存储较大的包含全部可用序列的序列集合,具有较低的存储需求。序列元素使用{1,1i,-1,-1i},运算简单,复杂度较低,从而可以降低发射机扩展处理、接收机相关处理的运算复杂度,有利于满足URLLC场景的低时延需求。In this embodiment, the first sequence is obtained from the first sequence set, where the first sequence set is The elements of the sequence mainly use {1, 1i, -1, -1i}. In the solution of this embodiment of the present invention, (transmitter and receiver) may store only two smaller sequence sets (ie, the first sequence set and the second sequence set) without storing a larger one containing all available sequences. A collection of sequences with lower storage requirements. Sequence elements use {1,1i,-1,-1i}, which is simple in operation and low in complexity, which can reduce the computational complexity of transmitter extension processing and receiver-related processing, and is beneficial to meet the low latency requirements of URLLC scenarios. .
需要说明的是,本发明及上述各个实施例给出的序列集合并不一定是唯一的,基于本发明及上述各个实施例中的描述,还可以获取其他类似的序列集合,本发明及实施例不一一描述。另外,对于本发明及实施例描述的序列集合,序列的顺序可以与上述表格所示的顺序不同,序列元素的顺序也可以与上述表格所示的顺序不同。It should be noted that the sequence set given by the present invention and the foregoing various embodiments is not necessarily unique. According to the description of the present invention and the foregoing embodiments, other similar sequence sets may be obtained, and the present invention and the embodiment Not one by one. In addition, for the sequence set described in the present invention and the embodiments, the order of the sequences may be different from the order shown in the above table, and the order of the sequence elements may also be different from the order shown in the above table.
实施例四 Embodiment 4
本实施例提供了一种数据生成装置,所述数据生成装置的组成结构示意图如图9所示,所述数据生成装置包括:The embodiment provides a data generating device. The schematic structure of the data generating device is as shown in FIG. 9. The data generating device includes:
确定单元91,配置为根据第一序列和第二序列确定第三序列,其中,所述第一序列从第一序列集合中获取,所述第二序列从第二序列集合中获取;或者,从第三序列集合中确定所述第三序列;a determining unit 91, configured to determine a third sequence according to the first sequence and the second sequence, wherein the first sequence is obtained from a first sequence set, and the second sequence is obtained from a second sequence set; or Determining the third sequence in a third sequence set;
生成单元92,配置为使用所述第三序列对第一数据进行处理生成第二数据;The generating unit 92 is configured to process the first data to generate the second data by using the third sequence;
其中,所述第一序列集合包括包含M条长度为L的序列的第一指定序列集合、和/或对所述第一指定序列集合进行处理得到的序列集合;The first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set;
其中,所述第二序列集合包括包含N条长度为C的序列的第二指定序列集合、和/或对所述第二指定序列集合进行处理得到的序列集合;The second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set;
其中,所述第三序列集合包括以下至少之一:包含P条长度为W的序 列的第三指定序列集合;所述第二指定序列集合;对所述第二指定序列集合进行处理得到的序列集合;根据所述第一序列集合和所述第二序列集合得到的序列集合;The third sequence set includes at least one of the following: an order containing the length of the P strips a third specified sequence set of the column; the second specified sequence set; a sequence set obtained by processing the second specified sequence set; and a sequence set obtained according to the first sequence set and the second sequence set;
其中,M、L、N、C、P、W为正整数。Among them, M, L, N, C, P, and W are positive integers.
可选地,所述第一指定序列集合或所述第三指定序列集合中的序列元素的取值来自于以下集合至少之一:Optionally, the value of the sequence element in the first specified sequence set or the third specified sequence set is from at least one of the following sets:
{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,-1+1i,-1-1i,1-1i};{0};{1,1i,-1,-1i,0};{1+1i,-1+1i,-1-1i,1-1i,0};{1,1i,-1,-1i,2,2i,-2,-2i,0};其中,i为虚数单位,i=sqrt(-1)。{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,- 1+1i, -1-1i, 1-1i}; {0}; {1, 1i, -1, -1i, 0}; {1+1i, -1+1i, -1-1i, 1-1i , 0}; {1, 1i, -1, -1i, 2, 2i, -2, -2i, 0}; where i is an imaginary unit and i = sqrt(-1).
可选地,所述第一指定序列集合,包括下述序列集合至少之一:Optionally, the first specified sequence set includes at least one of the following sequence sets:
序列集合1:如表101所示,Sequence Set 1: As shown in Table 101,
表101:Table 101:
Figure PCTCN2017114801-appb-000024
Figure PCTCN2017114801-appb-000024
序列集合2:如表102所示,Sequence set 2: as shown in Table 102,
表102:Table 102:
Figure PCTCN2017114801-appb-000025
Figure PCTCN2017114801-appb-000025
序列集合3:如表103所示,Sequence set 3: as shown in Table 103,
表103: Table 103:
Figure PCTCN2017114801-appb-000026
Figure PCTCN2017114801-appb-000026
序列集合4:如表104所示,Sequence set 4: as shown in Table 104,
表104:Table 104:
Figure PCTCN2017114801-appb-000027
Figure PCTCN2017114801-appb-000027
序列集合5:如表105所示,Sequence set 5: as shown in Table 105,
表105:Table 105:
Figure PCTCN2017114801-appb-000028
Figure PCTCN2017114801-appb-000028
序列集合6:如表106所示,Sequence set 6: as shown in Table 106,
表106:Table 106:
Figure PCTCN2017114801-appb-000029
Figure PCTCN2017114801-appb-000029
序列集合7:如表107所示,Sequence set 7: as shown in Table 107,
表107:Table 107:
Figure PCTCN2017114801-appb-000030
Figure PCTCN2017114801-appb-000030
序列集合8:如表108所示, Sequence set 8: as shown in Table 108,
表108:Table 108:
Figure PCTCN2017114801-appb-000031
Figure PCTCN2017114801-appb-000031
序列集合9:如表109所示,Sequence set 9: as shown in Table 109,
表109:Table 109:
序列索引Sequence index 序列元素Sequence element
00 11
11 1i1i
22 -1-1
33 -1i-1i
序列集合10:如表110所示,Sequence set 10: as shown in Table 110,
表110:Table 110:
序列索引Sequence index 序列元素Sequence element
00 1+1i1+1i
11 -1+1i-1+1i
22 -1-1i-1-1i
33 1-1i1-1i
序列集合11:如表111所示,Sequence set 11: as shown in Table 111,
表111:Table 111:
序列索引Sequence index 序列元素Sequence element
00 11
11 -1-1
序列集合12:如表112所示,Sequence set 12: as shown in Table 112,
表112:Table 112:
序列索引Sequence index 序列元素Sequence element
00 1i1i
11 -1i-1i
序列集合13:如表113所示,Sequence set 13: as shown in Table 113,
表113:Table 113:
序列索引Sequence index 序列元素Sequence element
00 11
序列集合14:如表114所示,Sequence set 14: as shown in Table 114,
表114:Table 114:
序列索引Sequence index 序列元素Sequence element
00 -1-1
序列集合15:如表115所示,Sequence set 15: as shown in Table 115,
表115:Table 115:
序列索引Sequence index 序列元素Sequence element
00 1i1i
序列集合16:如表116所示,Sequence set 16: as shown in Table 116,
表116:Table 116:
序列索引Sequence index 序列元素Sequence element
00 -1i-1i
序列集合17:如表117所示,Sequence set 17: as shown in Table 117,
表117Table 117
Figure PCTCN2017114801-appb-000032
Figure PCTCN2017114801-appb-000032
其中,i为虚数单位,i=sqrt(-1)。Where i is an imaginary unit and i=sqrt(-1).
可选地,所述确定单元91,还配置为:Optionally, the determining unit 91 is further configured to:
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素乘以1、1i、-1、或-1i,或者乘以1i的A次方;或者,Multiplying the Xth sequence element of each sequence or each sequence in the first specified sequence set by 1, 1i, -1, or -1i, or multiplying by the 1st power of A; or
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素进行B*π的相位调整或旋转,或者乘以exp(j*B*π),j为虚数单位,j=sqrt(-1);或者,Performing B*π phase adjustment or rotation for each sequence in the first specified sequence set or the Xth sequence element of each sequence, or multiplying exp(j*B*π), j is an imaginary unit, j=sqrt(-1); or,
对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素乘以指定值,或者分别乘以指定值;Multiplying the Xth sequence element of each sequence or each sequence in the first specified sequence set by a specified value, or multiplying by a specified value;
其中,X为大于或等于1且小于或等于L的整数,A为整数,B为实数。Where X is an integer greater than or equal to 1 and less than or equal to L, A is an integer, and B is a real number.
可选地,所述第二指定序列集合包括以下至少之一:Optionally, the second specified sequence set includes at least one of the following:
哈达玛序列集合;Hadamard sequence collection;
沃尔什序列集合;Walsh sequence collection;
离散傅里叶变换序列集合;a set of discrete Fourier transform sequences;
包含指定数量或指定比例的0元素的序列的集合;a collection of sequences containing a specified number or a specified proportion of 0 elements;
单位矩阵序列集合。A collection of unit matrix sequences.
可选地,所述第二指定序列集合,包括下述序列集合至少之一;其中,Optionally, the second specified sequence set includes at least one of the following sequence sets; wherein
序列集合1:如表201所示,Sequence Set 1: As shown in Table 201,
表201:Table 201:
Figure PCTCN2017114801-appb-000033
Figure PCTCN2017114801-appb-000033
序列集合2:如表202所示, Sequence Set 2: As shown in Table 202,
表202:Table 202:
Figure PCTCN2017114801-appb-000034
Figure PCTCN2017114801-appb-000034
序列集合3:如表203所示,Sequence set 3: as shown in Table 203,
表203Table 203
Figure PCTCN2017114801-appb-000035
Figure PCTCN2017114801-appb-000035
序列集合4:如表204所示,Sequence set 4: as shown in Table 204,
表204Table 204
序列索引Sequence index 序列元素Sequence element
00 11
序列集合5:如表205所示,Sequence set 5: as shown in Table 205,
表205:Table 205:
Figure PCTCN2017114801-appb-000036
Figure PCTCN2017114801-appb-000036
序列集合6:如表206所示,Sequence set 6: as shown in Table 206,
表206: Table 206:
Figure PCTCN2017114801-appb-000037
Figure PCTCN2017114801-appb-000037
序列集合7:如表207所示,Sequence set 7: as shown in Table 207,
表207:Table 207:
Figure PCTCN2017114801-appb-000038
Figure PCTCN2017114801-appb-000038
序列集合8:如表208所示,Sequence set 8: as shown in Table 208,
表208:Table 208:
Figure PCTCN2017114801-appb-000039
Figure PCTCN2017114801-appb-000039
序列集合9:如表209所示,Sequence set 9: as shown in Table 209,
表209:Table 209:
Figure PCTCN2017114801-appb-000040
Figure PCTCN2017114801-appb-000040
Figure PCTCN2017114801-appb-000041
Figure PCTCN2017114801-appb-000041
其中,i为虚数单位,i=sqrt(-1)。Where i is an imaginary unit and i=sqrt(-1).
可选地,所述确定单元91,还配置为:Optionally, the determining unit 91 is further configured to:
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素乘以1、1i、-1、或-1i,或者乘以1i的E次方;或者,Multiplying the Yth sequence element of each sequence or each sequence in the second specified sequence set by 1, 1i, -1, or -1i, or multiplying by 1i to the power of E; or
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素进行F*π的相位调整或旋转,或者,乘以exp(j*F*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of F*π for each sequence in the second specified sequence set or the Yth sequence element of each sequence, or multiply exp(j*F*π), j is an imaginary unit , j=sqrt(-1); or,
对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素乘以指定值,或者分别乘以指定值;Multiplying each of the sequence of the second specified sequence set or the Yth sequence element of each sequence by a specified value, or multiplying by a specified value;
其中,Y为大于或等于1且小于或等于C的整数,E为整数,F为实数。Wherein Y is an integer greater than or equal to 1 and less than or equal to C, E is an integer, and F is a real number.
可选地,所述第三指定序列集合包括下述序列集合至少之一:Optionally, the third specified sequence set includes at least one of the following sequence sets:
序列集合1:如表301所示,Sequence set 1: as shown in Table 301,
表301Table 301
Figure PCTCN2017114801-appb-000042
Figure PCTCN2017114801-appb-000042
Figure PCTCN2017114801-appb-000043
Figure PCTCN2017114801-appb-000043
序列集合2:如表302所示,Sequence Set 2: As shown in Table 302,
表302Table 302
Figure PCTCN2017114801-appb-000044
Figure PCTCN2017114801-appb-000044
序列集合3:如表303所示,Sequence set 3: as shown in Table 303,
表303 Table 303
Figure PCTCN2017114801-appb-000045
Figure PCTCN2017114801-appb-000045
序列集合4:如表304所示,Sequence set 4: as shown in Table 304,
表304Table 304
Figure PCTCN2017114801-appb-000046
Figure PCTCN2017114801-appb-000046
Figure PCTCN2017114801-appb-000047
Figure PCTCN2017114801-appb-000047
序列集合5:如表305所示,Sequence set 5: as shown in Table 305,
表305Table 305
Figure PCTCN2017114801-appb-000048
Figure PCTCN2017114801-appb-000048
Figure PCTCN2017114801-appb-000049
Figure PCTCN2017114801-appb-000049
序列集合6:如表306所示,Sequence set 6: as shown in Table 306,
表306Table 306
Figure PCTCN2017114801-appb-000050
Figure PCTCN2017114801-appb-000050
Figure PCTCN2017114801-appb-000051
Figure PCTCN2017114801-appb-000051
序列集合7:如表307所示,Sequence set 7: as shown in Table 307,
表307 Table 307
Figure PCTCN2017114801-appb-000052
Figure PCTCN2017114801-appb-000052
序列集合8:如表308所示,Sequence set 8: as shown in Table 308,
表308Table 308
Figure PCTCN2017114801-appb-000053
Figure PCTCN2017114801-appb-000053
序列集合9:如表309所示,Sequence set 9: as shown in Table 309,
表309Table 309
Figure PCTCN2017114801-appb-000054
Figure PCTCN2017114801-appb-000054
Figure PCTCN2017114801-appb-000055
Figure PCTCN2017114801-appb-000055
序列集合10:如表310所示,Sequence set 10: as shown in Table 310,
表310Table 310
Figure PCTCN2017114801-appb-000056
Figure PCTCN2017114801-appb-000056
Figure PCTCN2017114801-appb-000057
Figure PCTCN2017114801-appb-000057
序列集合11:如表311所示,Sequence set 11: as shown in Table 311,
表311Table 311
Figure PCTCN2017114801-appb-000058
Figure PCTCN2017114801-appb-000058
Figure PCTCN2017114801-appb-000059
Figure PCTCN2017114801-appb-000059
其中,i为虚数单位,i=sqrt(-1);或者Where i is an imaginary unit, i=sqrt(-1); or
对序列集合1、序列集合2、序列集合3、序列集合4、序列集合5、序列集合6、序列集合7、序列集合8、序列集合9、序列集合10、序列集合11这十一个序列集合中的序列,分别进行下述任一处理得到的集合:11 sequence sets of sequence set 1, sequence set 2, sequence set 3, sequence set 4, sequence set 5, sequence set 6, sequence set 7, sequence set 8, sequence set 9, sequence set 10, sequence set 11 The sequence in the process, respectively, is a collection obtained by any of the following processes:
其中,所述任一处理,包括:Wherein, any of the processes described includes:
对序列集合中的每条序列或每条序列的第S个序列元素乘以1、1i、-1、或-1i,或者乘以1i的Q次方;或者,Multiply the S-th sequence element of each sequence or each sequence in the sequence set by 1, 1i, -1, or -1i, or multiply by the Q-th power of 1i; or,
对序列集合中的每条序列或每条序列的第S个序列元素进行R*π的相位调整或旋转,或者,乘以exp(j*R*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of R*π for each sequence in the sequence set or the Sth sequence element of each sequence, or multiply exp(j*R*π), j is an imaginary unit, j=sqrt( -1); or,
对序列集合中的每条序列或每条序列的第S个序列元素乘以指定值,或者分别乘以指定值; Multiplying each sequence in the sequence set or the Sth sequence element of each sequence by a specified value, or multiplying by a specified value;
其中,S为大于或等于1且小于或等于W的整数,Q为整数,R为实数。Wherein S is an integer greater than or equal to 1 and less than or equal to W, Q is an integer, and R is a real number.
在一实施方式中,所述确定单元91根据所述第一序列集合和所述第二序列集合得到的序列集合,包括以下至少之一:In an embodiment, the determining unit 91 obtains a sequence set according to the first sequence set and the second sequence set, and includes at least one of the following:
所述第一序列集合中的任意一条序列与所述第二序列集合中的任意一条序列进行点乘处理得到的序列构成的序列集合;a sequence set formed by a sequence obtained by performing dot multiplication processing on any one of the first sequence set and any one of the second sequence sets;
所述第一序列集合中的任意一条序列与所述第二序列集合中的任意一条序列进行乘法处理得到的序列构成的序列集合;a sequence set formed by a sequence obtained by multiplying any one of the first sequence set and any one of the second sequence sets;
所述第一序列集合中的任意一条序列的元素替换所述第二序列集合中的任意一条序列的非零元素得到的序列构成的序列集合;And deleting, by the element of any one of the first sequence sets, a sequence set formed by a sequence obtained by replacing a non-zero element of any one of the second sequence sets;
所述第一序列集合中的任意一条序列的元素与所述第二序列集合中的任意一条序列的非零元素进行点乘处理得到的序列构成的序列集合。a sequence set formed by a sequence obtained by performing dot multiplication processing on an element of any one of the first sequence sets and a non-zero element of any one of the second sequence sets.
在一实施方式中,所述确定单元91从第一序列集合中获取第一序列,包括以下之一:In an embodiment, the determining unit 91 obtains the first sequence from the first sequence set, including one of the following:
采用随机选择的方式从所述第一序列集合中获取第一序列;Obtaining the first sequence from the first sequence set in a random selection manner;
根据第一预设规则从所述第一序列集合中获取第一序列;Obtaining a first sequence from the first sequence set according to a first preset rule;
根据系统配置信息从所述第一序列集合中获取第一序列。Acquiring the first sequence from the first sequence set according to system configuration information.
在一实施方式中,所述确定单元91从第二序列集合中获取第二序列,包括以下之一:In an embodiment, the determining unit 91 obtains the second sequence from the second sequence set, including one of the following:
采用随机选择的方式从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second set of sequences in a randomly selected manner;
根据第二预设规则从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second sequence set according to a second preset rule;
根据系统配置信息从所述第二序列集合中获取第二序列。Obtaining a second sequence from the second set of sequences according to system configuration information.
在一实施方式中,所述确定单元91,还配置为:In an embodiment, the determining unit 91 is further configured to:
将所述第一序列与所述第二序列进行点乘处理,生成第三序列;或者,Performing point-multiplication processing on the first sequence and the second sequence to generate a third sequence; or
将所述第一序列与所述第二序列进行乘法处理,生成第三序列;或者,Multiplying the first sequence and the second sequence to generate a third sequence; or
使用所述第一序列中的元素替换所述第二序列中的非零元素,生成第 三序列;或者,Replacing a non-zero element in the second sequence with an element in the first sequence to generate a Three sequences; or,
将所述第一序列中的元素与所述第二序列中的非零元素进行点乘处理后得到的值替换所述第二序列中的非零元素,生成第三序列。Substituting a value obtained by dot-multiplying an element in the first sequence with a non-zero element in the second sequence to replace a non-zero element in the second sequence to generate a third sequence.
在一实施方式中,所述确定单元91,还配置为:In an embodiment, the determining unit 91 is further configured to:
采用随机选择的方式从所述第三序列集合中获取所述第三序列;Obtaining the third sequence from the third sequence set in a randomly selected manner;
根据第三预设规则从所述第三序列集合中获取所述第三序列;Obtaining the third sequence from the third sequence set according to a third preset rule;
根据系统配置信息从所述第三序列集合中获取所述第三序列。Obtaining the third sequence from the third sequence set according to system configuration information.
在一实施例中,所述装置还包括归一化处理单元93,配置为:In an embodiment, the apparatus further includes a normalization processing unit 93 configured to:
对所述第一序列集合中的序列进行能量调整或能量归一化处理;或Performing energy adjustment or energy normalization on the sequences in the first set of sequences; or
对所述第一序列进行能量调整或能量归一化处理;或Performing energy adjustment or energy normalization on the first sequence; or
对所述第三序列进行能量调整或能量归一化处理。The third sequence is subjected to energy adjustment or energy normalization.
在一可选实施方式中,所述确定单元91,还配置为:In an optional implementation, the determining unit 91 is further configured to:
对所述第三序列的每个元素或第V个元素乘以1、1i、-1、或-1i,或者,乘以1i的G次方;或者,Multiplying each element or the Vth element of the third sequence by 1, 1i, -1, or -1i, or multiplying by the G of 1i; or
对所述第三序列的每个元素或第V个元素进行H*π的相位调整或旋转,或者,乘以exp(j*H*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of H*π for each element or Vth element of the third sequence, or multiply exp(j*H*π), j is an imaginary unit, j=sqrt(-1) ;or,
对所述第三序列的每个元素或第V个元素乘以指定值;Multiplying each element or the Vth element of the third sequence by a specified value;
其中,V为大于或等于1且小于或等于所述第三序列的长度的整数,G为整数,H为实数。Wherein V is an integer greater than or equal to 1 and less than or equal to the length of the third sequence, G is an integer, and H is a real number.
在一可选实施方式中,所述生成单元92,还配置为:In an optional implementation, the generating unit 92 is further configured to:
使用所述第三序列对第一数据进行扩展处理生成第二数据;或,And expanding, by using the third sequence, the first data to generate second data; or
使用所述第三序列对第一数据进行映射处理生成第二数据;或,Performing mapping processing on the first data by using the third sequence to generate second data; or
使用所述第三序列对第一数据进行调制处理生成第二数据。The first data is modulated using the third sequence to generate second data.
进一步可选地,所述装置还包括:Further optionally, the device further includes:
映射单元94,配置为将所述第二数据映射到指定的传输资源上,用于形成发射信号以及发送。 Mapping unit 94 is configured to map the second data onto a designated transmission resource for forming a transmit signal and transmitting.
本实施例中,所述数据生成装置可设置于终端中或网络侧设备如基站中。In this embodiment, the data generating apparatus may be disposed in a terminal or in a network side device such as a base station.
本领域技术人员应当理解,本发明实施例的数据生成装置中各处理单元的功能,可参照前述数据生成方法的相关描述而理解,本发明实施例的数据生成装置中各处理单元,可通过实现本发明实施例所述的功能的模拟电路而实现,也可以通过执行本发明实施例所述的功能的软件在智能终端上的运行而实现。It should be understood by those skilled in the art that the functions of the processing units in the data generating apparatus of the embodiments of the present invention can be understood by referring to the related description of the foregoing data generating method, and the processing units in the data generating apparatus of the embodiments of the present invention can be implemented. The function of the analog circuit of the embodiment of the present invention can be implemented by using the software of the function described in the embodiment of the present invention on the smart terminal.
本实施例中,所述数据生成装置中的确定单元91、生成92、归一化处理单元93、映射单元94,在实际应用中可由所述数据生成装置或所述数据生成装置所属设备中的中央处理器(CPU,Central Processing Unit)、数字信号处理器(DSP,Digital Signal Processor)或可编程门阵列(FPGA,Field-Programmable Gate Array)等实现。In this embodiment, the determining unit 91, the generating 92, the normalization processing unit 93, and the mapping unit 94 in the data generating device may be used in the actual application by the data generating device or the device to which the data generating device belongs. Realized by a central processing unit (CPU), a digital signal processor (DSP), or a field-programmable gate array (FPGA).
本发明实施例的数据生成装置,能够用于实现免调度传输,并且,具有较低的序列存储需求和运算复杂度。The data generating apparatus of the embodiment of the present invention can be used to implement scheduling-free transmission, and has lower sequence storage requirements and computational complexity.
本实施例提供了一种设备,所述设备包括数据生成装置,所述数据生成装置,配置为:The embodiment provides a device, where the device includes a data generating device, and the data generating device is configured to:
根据第一序列和第二序列确定第三序列,其中,所述第一序列从第一序列集合中获取,所述第二序列从第二序列集合中获取;或者,从第三序列集合中确定所述第三序列;Determining a third sequence according to the first sequence and the second sequence, wherein the first sequence is obtained from a first sequence set, the second sequence is obtained from a second sequence set; or, determined from a third sequence set The third sequence;
使用所述第三序列对第一数据进行处理生成第二数据;Processing the first data by using the third sequence to generate second data;
其中,所述第一序列集合包括包含M条长度为L的序列的第一指定序列集合、和/或对所述第一指定序列集合进行处理得到的序列集合;The first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set;
其中,所述第二序列集合包括包含N条长度为C的序列的第二指定序列集合、和/或对所述第二指定序列集合进行处理得到的序列集合;The second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set;
其中,所述第三序列集合包括以下至少之一:包含P条长度为W的序列的第三指定序列集合;所述第二指定序列集合;对所述第二指定序列集 合进行处理得到的序列集合;根据所述第一序列集合和所述第二序列集合得到的序列集合;The third sequence set includes at least one of: a third specified sequence set including P sequences of length W; the second specified sequence set; and the second specified sequence set a sequence set obtained by processing; a sequence set obtained according to the first sequence set and the second sequence set;
其中,M、L、N、C、P、W为正整数。Among them, M, L, N, C, P, and W are positive integers.
具体地,所述数据生成装置的组成结构如图9所示,在此不再赘述。Specifically, the composition of the data generating apparatus is as shown in FIG. 9, and details are not described herein again.
这里,所述设备可以是用户设备,也可以是网络侧设备,如基站设备。Here, the device may be a user equipment, or may be a network side device, such as a base station device.
本发明实施例的设备,能够用于实现免调度传输,并且,具有较低的序列存储需求和运算复杂度。The device of the embodiment of the invention can be used to implement scheduling-free transmission, and has lower sequence storage requirements and computational complexity.
为实现上述数据生成方法,本发明实施例还提供一种设备,所述设备的硬件组成结构,如图10所示,包括处理器20以及存储有所述处理器可执行指令的存储器30,当所述指令被处理器20执行时,执行如下操作:In order to implement the above data generation method, an embodiment of the present invention further provides a device. The hardware component structure of the device, as shown in FIG. 10, includes a processor 20 and a memory 30 storing the processor executable instructions. When the instructions are executed by the processor 20, the following operations are performed:
根据第一序列和第二序列确定第三序列,其中,所述第一序列从第一序列集合中获取,所述第二序列从第二序列集合中获取;或者,从第三序列集合中确定所述第三序列;Determining a third sequence according to the first sequence and the second sequence, wherein the first sequence is obtained from a first sequence set, the second sequence is obtained from a second sequence set; or, determined from a third sequence set The third sequence;
使用所述第三序列对第一数据进行处理生成第二数据;Processing the first data by using the third sequence to generate second data;
其中,所述第一序列集合包括包含M条长度为L的序列的第一指定序列集合、和/或对所述第一指定序列集合进行处理得到的序列集合;The first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set;
其中,所述第二序列集合包括包含N条长度为C的序列的第二指定序列集合、和/或对所述第二指定序列集合进行处理得到的序列集合;The second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set;
其中,所述第三序列集合包括以下至少之一:包含P条长度为W的序列的第三指定序列集合;所述第二指定序列集合;对所述第二指定序列集合进行处理得到的序列集合;根据所述第一序列集合和所述第二序列集合得到的序列集合;The third sequence set includes at least one of: a third specified sequence set including P sequences of length W; the second specified sequence set; and a sequence obtained by processing the second specified sequence set a set of sequences obtained from the first set of sequences and the second set of sequences;
其中,M、L、N、C、P、W为正整数。Among them, M, L, N, C, P, and W are positive integers.
在一可选实施方式中,所述处理器20根据第一序列和第二序列确定第三序列时所述第一指定序列集合中的序列元素的取值,或者,从第三序列集合中确定所述第三序列时所述第三指定序列集合中的序列元素的取值, 均来自于以下集合至少之一:In an optional implementation manner, the processor 20 determines, according to the first sequence and the second sequence, a value of a sequence element in the first specified sequence set when the third sequence is determined, or determines from the third sequence set. The value of the sequence element in the third specified sequence set when the third sequence is Both come from at least one of the following collections:
{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,-1+1i,-1-1i,1-1i};{0};{1,1i,-1,-1i,0};{1+1i,-1+1i,-1-1i,1-1i,0};{1,1i,-1,-1i,2,2i,-2,-2i,0};其中,i为虚数单位,i=sqrt(-1)。{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,- 1+1i, -1-1i, 1-1i}; {0}; {1, 1i, -1, -1i, 0}; {1+1i, -1+1i, -1-1i, 1-1i , 0}; {1, 1i, -1, -1i, 2, 2i, -2, -2i, 0}; where i is an imaginary unit and i = sqrt(-1).
可选地,所述处理器20根据第一序列和第二序列确定第三序列时,或者,从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,还配置为:Optionally, the processor 20 determines the third sequence according to the first sequence and the second sequence, or determines the third sequence from the third sequence set, and the third sequence set includes according to the first sequence When the set and the sequence set obtained by the second sequence set are also configured, it is also configured as:
对所述第一序列集合中的序列进行能量调整或能量归一化处理;或Performing energy adjustment or energy normalization on the sequences in the first set of sequences; or
对所述第一序列进行能量调整或能量归一化处理;或Performing energy adjustment or energy normalization on the first sequence; or
对所述第三序列进行能量调整或能量归一化处理;Performing energy adjustment or energy normalization on the third sequence;
所述处理器从第三序列集合中确定所述第三序列,且所述第三序列集合不包括根据第一序列集合和第二序列集合得到的序列集合时,还配置为:When the processor determines the third sequence from the third sequence set, and the third sequence set does not include the sequence set obtained according to the first sequence set and the second sequence set, the processor is further configured to:
对所述第三序列进行能量调整或能量归一化处理。The third sequence is subjected to energy adjustment or energy normalization.
在一可选实施方式中,所述处理器20还配置为对所述第三序列的每个元素或第V个元素乘以1、1i、-1、或-1i,或者,乘以1i的G次方;或者,In an optional implementation, the processor 20 is further configured to multiply each element or the Vth element of the third sequence by 1, 1i, -1, or -1i, or multiply by 1i. Gth power; or,
对所述第三序列的每个元素或第V个元素进行H*π的相位调整或旋转,或者,乘以exp(j*H*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of H*π for each element or Vth element of the third sequence, or multiply exp(j*H*π), j is an imaginary unit, j=sqrt(-1) ;or,
对所述第三序列的每个元素或第V个元素乘以指定值;Multiplying each element or the Vth element of the third sequence by a specified value;
其中,V为大于或等于1且小于或等于所述第三序列的长度的整数,G为整数,H为实数。Wherein V is an integer greater than or equal to 1 and less than or equal to the length of the third sequence, G is an integer, and H is a real number.
在一可选实施方式中,所述处理器20还配置为使用所述第三序列对第一数据进行扩展处理生成第二数据;或,In an optional implementation, the processor 20 is further configured to perform the extended processing on the first data to generate the second data by using the third sequence; or
使用所述第三序列对第一数据进行映射处理生成第二数据;或,Performing mapping processing on the first data by using the third sequence to generate second data; or
使用所述第三序列对第一数据进行调制处理生成第二数据。The first data is modulated using the third sequence to generate second data.
在一可选实施方式中,所述处理器20还配置为将所述第二数据映射到指定的传输资源上,用于形成发射信号以及发送。 In an optional implementation, the processor 20 is further configured to map the second data onto a designated transmission resource for forming a transmit signal and transmitting.
上述处理器20的功能可参照数据生成装置各个单元所具有的功能来理解,在此不再赘述。The functions of the processor 20 can be understood by referring to the functions of the units of the data generating device, and details are not described herein.
本发明实施例还记载了一种计算机存储介质,所述计算机存储介质中存储有计算机可执行指令,以及扩展序列集合,所述计算机可执行指令以及扩展序列集合用于执行前述各个实施例所述的数据生成方法。Embodiments of the present invention also describe a computer storage medium having stored therein computer executable instructions, and a set of extended sequences, the computer executable instructions and the set of extended sequences being used to perform the various embodiments described above Data generation method.
本发明实施例所记载的技术方案之间,在不冲突的情况下,可以任意组合。The technical solutions described in the embodiments of the present invention can be arbitrarily combined without conflict.
在本发明所提供的几个实施例中,应该理解到,所揭露的方法和智能设备,可以通过其它的方式实现。以上所描述的设备实施例仅仅是示意性的,例如,所述单元的划分,仅仅为一种逻辑功能划分,实际实现时可以有另外的划分方式,如:多个单元或组件可以结合,或可以集成到另一个系统,或一些特征可以忽略,或不执行。另外,所显示或讨论的各组成部分相互之间的耦合、或直接耦合、或通信连接可以是通过一些接口,设备或单元的间接耦合或通信连接,可以是电性的、机械的或其它形式的。In the several embodiments provided by the present invention, it should be understood that the disclosed method and smart device may be implemented in other manners. The device embodiments described above are merely illustrative. For example, the division of the unit is only a logical function division. In actual implementation, there may be another division manner, such as: multiple units or components may be combined, or Can be integrated into another system, or some features can be ignored or not executed. In addition, the coupling, or direct coupling, or communication connection of the components shown or discussed may be indirect coupling or communication connection through some interfaces, devices or units, and may be electrical, mechanical or other forms. of.
上述作为分离部件说明的单元可以是、或也可以不是物理上分开的,作为单元显示的部件可以是、或也可以不是物理单元,即可以位于一个地方,也可以分布到多个网络单元上;可以根据实际的需要选择其中的部分或全部单元来实现本实施例方案的目的。The units described above as separate components may or may not be physically separated, and the components displayed as the unit may or may not be physical units, that is, may be located in one place or distributed to multiple network units; Some or all of the units may be selected according to actual needs to achieve the purpose of the solution of the embodiment.
另外,在本发明各实施例中的各功能单元可以全部集成在一个第二处理单元中,也可以是各单元分别单独作为一个单元,也可以两个或两个以上单元集成在一个单元中;上述集成的单元既可以采用硬件的形式实现,也可以采用硬件加软件功能单元的形式实现。In addition, each functional unit in each embodiment of the present invention may be integrated into one second processing unit, or each unit may be separately used as one unit, or two or more units may be integrated into one unit; The above integrated unit can be implemented in the form of hardware or in the form of hardware plus software functional units.
以上所述,仅为本发明的具体实施方式,但本发明的保护范围并不局限于此,任何熟悉本技术领域的技术人员在本发明揭露的技术范围内,可轻易想到变化或替换,都应涵盖在本发明的保护范围之内。 The above is only a specific embodiment of the present invention, but the scope of the present invention is not limited thereto, and any person skilled in the art can easily think of changes or substitutions within the technical scope of the present invention. It should be covered by the scope of the present invention.
工业实用性Industrial applicability
本发明实施例的技术方案,根据第一序列和第二序列确定第三序列,其中,所述第一序列从第一序列集合中获取,所述第二序列从第二序列集合中获取;或者,从第三序列集合中确定所述第三序列;使用所述第三序列对第一数据进行处理生成第二数据;其中,所述第一序列集合包括包含M条长度为L的序列的第一指定序列集合、和/或对所述第一指定序列集合进行处理得到的序列集合;其中,所述第二序列集合包括包含N条长度为C的序列的第二指定序列集合、和/或对所述第二指定序列集合进行处理得到的序列集合;其中,所述第三序列集合包括以下至少之一:包含P条长度为W的序列的第三指定序列集合;所述第二指定序列集合;对所述第二指定序列集合进行处理得到的序列集合;根据所述第一序列集合和所述第二序列集合得到的序列集合;其中,M、L、N、C、P、W为正整数。通过本发明实施例提出的数据生成方法,能够用于实现免调度传输,并且,具有较低的序列存储需求和运算复杂度。 According to the technical solution of the embodiment of the present invention, the third sequence is determined according to the first sequence and the second sequence, where the first sequence is obtained from the first sequence set, and the second sequence is obtained from the second sequence set; or Determining the third sequence from the third sequence set; processing the first data using the third sequence to generate second data; wherein the first sequence set includes a sequence including M sequences of length L a set of specified sequences, and/or a set of sequences obtained by processing the first specified set of sequences; wherein the second set of sequences comprises a second set of specified sequences comprising N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set; wherein the third sequence set includes at least one of: a third specified sequence set including a P-length W sequence; the second specified sequence a set of sequences obtained by processing the second specified sequence set; a sequence set obtained according to the first sequence set and the second sequence set; wherein, M, L, N, C, P, and W are positive integers. The data generation method proposed by the embodiment of the present invention can be used to implement scheduling-free transmission, and has lower sequence storage requirements and computational complexity.

Claims (33)

  1. 一种数据生成方法,所述方法包括:A data generating method, the method comprising:
    根据第一序列和第二序列确定第三序列,其中,所述第一序列从第一序列集合中获取,所述第二序列从第二序列集合中获取;或者,从第三序列集合中确定所述第三序列;Determining a third sequence according to the first sequence and the second sequence, wherein the first sequence is obtained from a first sequence set, the second sequence is obtained from a second sequence set; or, determined from a third sequence set The third sequence;
    使用所述第三序列对第一数据进行处理生成第二数据;Processing the first data by using the third sequence to generate second data;
    其中,所述第一序列集合包括包含M条长度为L的序列的第一指定序列集合、和/或对所述第一指定序列集合进行处理得到的序列集合;The first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set;
    其中,所述第二序列集合包括包含N条长度为C的序列的第二指定序列集合、和/或对所述第二指定序列集合进行处理得到的序列集合;The second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set;
    其中,所述第三序列集合包括以下至少之一:包含P条长度为W的序列的第三指定序列集合;所述第二指定序列集合;对所述第二指定序列集合进行处理得到的序列集合;根据所述第一序列集合和所述第二序列集合得到的序列集合;The third sequence set includes at least one of: a third specified sequence set including P sequences of length W; the second specified sequence set; and a sequence obtained by processing the second specified sequence set a set of sequences obtained from the first set of sequences and the second set of sequences;
    其中,M、L、N、C、P、W为正整数。Among them, M, L, N, C, P, and W are positive integers.
  2. 根据权利要求1所述的数据生成方法,其中,根据第一序列和第二序列确定第三序列时所述第一指定序列集合中的序列元素的取值,或者The data generating method according to claim 1, wherein the value of the sequence element in the first specified sequence set when the third sequence is determined according to the first sequence and the second sequence, or
    从第三序列集合中确定所述第三序列时所述第三指定序列集合中的序列元素的取值,Determining the value of the sequence element in the third specified sequence set when the third sequence is determined from the third sequence set,
    均来自于以下集合至少之一:Both come from at least one of the following collections:
    {1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,-1+1i,-1-1i,1-1i};{0};{1,1i,-1,-1i,0};{1+1i,-1+1i,-1-1i,1-1i,0};{1,1i,-1,-1i,2,2i,-2,-2i,0};其中,i为虚数单位,i=sqrt(-1)。{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,- 1+1i, -1-1i, 1-1i}; {0}; {1, 1i, -1, -1i, 0}; {1+1i, -1+1i, -1-1i, 1-1i , 0}; {1, 1i, -1, -1i, 2, 2i, -2, -2i, 0}; where i is an imaginary unit and i = sqrt(-1).
  3. 根据权利要求1所述的数据生成方法,其中,根据第一序列和第二序列确定第三序列时,或者 The data generating method according to claim 1, wherein when the third sequence is determined based on the first sequence and the second sequence, or
    从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,Determining the third sequence from a third sequence set, and the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set,
    所述第一指定序列集合,包括下述序列集合至少之一:The first specified sequence set includes at least one of the following sequence sets:
    序列集合1:Sequence set 1:
    所述序列集合1,包含4条长度为4的序列,其中,The sequence set 1 includes four sequences of length 4, wherein
    第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
    第二序列为[1,1,1i,-1i],The second sequence is [1,1,1i,-1i],
    第三序列为[1,1i,1,-1i],The third sequence is [1, 1i, 1, -1i],
    第四序列为[1,1i,1i,-1];The fourth sequence is [1, 1i, 1i, -1];
    序列集合2:Sequence collection 2:
    所述序列集合2,包含4条长度为4的序列,其中,The sequence set 2 includes four sequences of length 4, wherein
    第一序列为[1,1,1,-1],The first sequence is [1,1,1,-1],
    第二序列为[1,1,1i,1i],The second sequence is [1,1,1i,1i],
    第三序列为[1,1i,1,1i],The third sequence is [1, 1i, 1, 1i],
    第四序列为[1,1i,1i,1];The fourth sequence is [1, 1i, 1i, 1];
    序列集合3:Sequence Collection 3:
    所述序列集合2,包含4条长度为4的序列,其中,The sequence set 2 includes four sequences of length 4, wherein
    第一序列为[1,1,1,1i],The first sequence is [1,1,1,1i],
    第二序列为[1,1,1i,1],The second sequence is [1,1,1i,1],
    第三序列为[1,1i,1,1],The third sequence is [1, 1i, 1, 1],
    第四序列为[1,1i,1i,-1i];The fourth sequence is [1, 1i, 1i, -1i];
    序列集合4:Sequence Collection 4:
    所述序列集合4,包含4条长度为4的序列,其中,The sequence set 4 includes four sequences of length 4, wherein
    第一序列为[1,1,1,-1i],The first sequence is [1,1,1,-1i],
    第二序列为[1,1,1i,-1],The second sequence is [1,1,1i,-1],
    第三序列为[1,1i,1,-1], The third sequence is [1, 1i, 1, -1],
    第四序列为[1,1i,1i,1i];The fourth sequence is [1, 1i, 1i, 1i];
    序列集合5:Sequence Collection 5:
    所述序列集合5,包含1条长度为2的序列,其中,The sequence set 5 includes a sequence of length 2, wherein
    第一序列为[1,1];The first sequence is [1,1];
    序列集合6:Sequence set 6:
    所述序列集合6,包含1条长度为2的序列,其中,The sequence set 6 includes a sequence of length 2, wherein
    第一序列为[1,-1];The first sequence is [1,-1];
    序列集合7:Sequence collection 7:
    所述序列集合7,包含1条长度为2的序列,其中,The sequence set 7 includes a sequence of length 2, wherein
    第一序列为[1,1i];The first sequence is [1, 1i];
    序列集合8:Sequence set 8:
    所述序列集合8,包含1条长度为2的序列,其中,The sequence set 8 includes a sequence of length 2, wherein
    第一序列为[1,-1i];The first sequence is [1,-1i];
    序列集合9:Sequence set 9:
    所述序列集合9,包含4条长度为1的序列,其中,The sequence set 9 includes four sequences of length 1, wherein
    第一序列为[1],The first sequence is [1],
    第二序列为[1i],The second sequence is [1i],
    第三序列为[-1],The third sequence is [-1],
    第四序列为[-1i];The fourth sequence is [-1i];
    序列集合10:Sequence collection 10:
    所述序列集合10,包含4条长度为1的序列,其中,The sequence set 10 includes four sequences of length 1, wherein
    第一序列为[1+1i],The first sequence is [1+1i],
    第二序列为[-1+1i],The second sequence is [-1+1i],
    第三序列为[-1-1i],The third sequence is [-1-1i],
    第四序列为[1-1i];The fourth sequence is [1-1i];
    序列集合11: Sequence collection 11:
    所述序列集合11,包含2条长度为1的序列,其中,The sequence set 11 includes two sequences of length 1, wherein
    第一序列为[1],The first sequence is [1],
    第二序列为[-1];The second sequence is [-1];
    序列集合12:Sequence set 12:
    所述序列集合12,包含2条长度为1的序列,其中,The sequence set 12 includes two sequences of length 1, wherein
    第一序列为[1i],The first sequence is [1i],
    第二序列为[-1i];The second sequence is [-1i];
    序列集合13:Sequence Set 13:
    所述序列集合13,包含1条长度为1的序列,其中,The sequence set 13 includes a sequence of length 1, wherein
    第一序列为[1];The first sequence is [1];
    序列集合14:Sequence Set 14:
    所述序列集合14,包含1条长度为1的序列,其中,The sequence set 14 includes a sequence of length 1, wherein
    第一序列为[-1];The first sequence is [-1];
    序列集合15:Sequence set 15:
    所述序列集合15,包含1条长度为1的序列,其中,The sequence set 15 includes a sequence of length 1, wherein
    第一序列为[1i];The first sequence is [1i];
    序列集合16:Sequence set 16:
    所述序列集合16,包含1条长度为1的序列,其中,The sequence set 16 includes a sequence of length 1, wherein
    第一序列为[-1i];The first sequence is [-1i];
    序列集合17:Sequence set 17:
    所述序列集合17,包含4条长度为3的序列,其中,The sequence set 17 includes four sequences of length 3, wherein
    第一序列为[1,1,1];The first sequence is [1,1,1];
    第二序列为[1,-1,-1],The second sequence is [1,-1,-1],
    第三序列为[-1,1,-1],The third sequence is [-1, 1, -1],
    第四序列为[-1,1,1];The fourth sequence is [-1, 1, 1];
    其中,i为虚数单位,i=sqrt(-1)。 Where i is an imaginary unit and i=sqrt(-1).
  4. 根据权利要求1所述的数据生成方法,其中,根据第一序列和第二序列确定第三序列时,或者The data generating method according to claim 1, wherein when the third sequence is determined based on the first sequence and the second sequence, or
    从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,Determining the third sequence from a third sequence set, and the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set,
    所述对所述第一指定序列集合中的序列进行处理,包括:The processing of the sequence in the first specified sequence set includes:
    对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素乘以1、1i、-1、或-1i,或者乘以1i的A次方;或者,Multiplying the Xth sequence element of each sequence or each sequence in the first specified sequence set by 1, 1i, -1, or -1i, or multiplying by the 1st power of A; or
    对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素进行B*π的相位调整或旋转,或者乘以exp(j*B*π),j为虚数单位,j=sqrt(-1);或者,Performing B*π phase adjustment or rotation for each sequence in the first specified sequence set or the Xth sequence element of each sequence, or multiplying exp(j*B*π), j is an imaginary unit, j=sqrt(-1); or,
    对所述第一指定序列集合中的每条序列或每条序列的第X个序列元素乘以指定值,或者分别乘以指定值;Multiplying the Xth sequence element of each sequence or each sequence in the first specified sequence set by a specified value, or multiplying by a specified value;
    其中,X为大于或等于1且小于或等于L的整数,A为整数,B为实数。Where X is an integer greater than or equal to 1 and less than or equal to L, A is an integer, and B is a real number.
  5. 根据权利要求1所述的数据生成方法,其中,根据第一序列和第二序列确定第三序列时,或者The data generating method according to claim 1, wherein when the third sequence is determined based on the first sequence and the second sequence, or
    从第三序列集合中确定所述第三序列,且所述第三序列集合包括第二指定序列集合、对所述第二指定序列集合进行处理得到的序列集合、根据第一序列集合和第二序列集合得到的序列集合至少之一时,Determining the third sequence from a third sequence set, and the third sequence set includes a second specified sequence set, a sequence set obtained by processing the second specified sequence set, according to the first sequence set and the second sequence set When at least one of the sequence sets obtained by the sequence set,
    所述第二指定序列集合包括以下至少之一:The second specified sequence set includes at least one of the following:
    哈达玛序列集合;Hadamard sequence collection;
    沃尔什序列集合;Walsh sequence collection;
    离散傅里叶变换序列集合;a set of discrete Fourier transform sequences;
    包含指定数量或指定比例的0元素的序列的集合;a collection of sequences containing a specified number or a specified proportion of 0 elements;
    单位矩阵序列集合。A collection of unit matrix sequences.
  6. 根据权利要求1所述的数据生成方法,其中,根据第一序列和第二 序列确定第三序列时,或者The data generating method according to claim 1, wherein according to the first sequence and the second When the sequence determines the third sequence, or
    从第三序列集合中确定所述第三序列,且所述第三序列集合包括第二指定序列集合、对第二指定序列集合进行处理得到的序列集合、根据第一序列集合和第二序列集合得到的序列集合至少之一时,Determining the third sequence from the third sequence set, and the third sequence set includes a second specified sequence set, a sequence set obtained by processing the second specified sequence set, according to the first sequence set and the second sequence set When at least one of the resulting sequence sets is obtained,
    所述第二指定序列集合,包括下述序列集合至少之一;其中,The second specified sequence set includes at least one of the following sequence sets; wherein
    序列集合1:Sequence set 1:
    所述序列集合1,包含4条长度为4的序列,其中,The sequence set 1 includes four sequences of length 4, wherein
    第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
    第二序列为[1,1,-1,-1],The second sequence is [1,1,-1,-1],
    第三序列为[1,-1,1,-1],The third sequence is [1,-1,1,-1],
    第四序列为[1,-1,-1,1];The fourth sequence is [1, -1, -1, 1];
    序列集合2:Sequence collection 2:
    所述序列集合2,包含4条长度为4的序列,其中,The sequence set 2 includes four sequences of length 4, wherein
    第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
    第二序列为[1,1i,-1,-1i],The second sequence is [1, 1i, -1, -1i],
    第三序列为[1,-1,1,-1],The third sequence is [1,-1,1,-1],
    第四序列为[1,-1i,-1,1i];The fourth sequence is [1,-1i,-1,1i];
    序列集合3:Sequence Collection 3:
    所述序列集合3,包含2条长度为2的序列,其中,The sequence set 3 includes two sequences of length 2, wherein
    第一序列为[1,1],The first sequence is [1,1],
    第二序列为[1,-1];The second sequence is [1,-1];
    序列集合4:Sequence Collection 4:
    所述序列集合4,包含1条长度为1的序列,其中,The sequence set 4 includes a sequence of length 1, wherein
    第一序列为[1];The first sequence is [1];
    序列集合5:Sequence Collection 5:
    所述序列集合5,包含6条长度为4的序列,其中, The sequence set 5 includes six sequences of length 4, wherein
    第一序列为[1,1,0,0],The first sequence is [1,1,0,0],
    第二序列为[1,0,1,0],The second sequence is [1,0,1,0],
    第三序列为[1,0,0,1],The third sequence is [1,0,0,1],
    第四序列为[0,1,1,0],The fourth sequence is [0, 1, 1, 0],
    第五序列为[0,1,0,1],The fifth sequence is [0, 1, 0, 1],
    第六序列为[0,0,1,1];The sixth sequence is [0,0,1,1];
    序列集合6:Sequence set 6:
    所述序列集合6,包含4条长度为6的序列,其中,The sequence set 6 includes four sequences of length 6, wherein
    第一序列为[1,1,1,0,0,0],The first sequence is [1,1,1,0,0,0],
    第二序列为[1,0,0,1,1,0],The second sequence is [1,0,0,1,1,0],
    第三序列为[0,1,0,0,1,1],The third sequence is [0, 1, 0, 0, 1, 1],
    第四序列为[0,0,1,1,0,1],The fourth sequence is [0,0,1,1,0,1],
    序列集合7:Sequence collection 7:
    所述序列集合7,包含4条长度为6的序列,其中,The sequence set 7 includes four sequences of length 6, wherein
    第一序列为[1,0,1,0,1,0],The first sequence is [1,0,1,0,1,0],
    第二序列为[1,0,0,1,0,1],The second sequence is [1,0,0,1,0,1],
    第三序列为[0,1,1,0,0,1],The third sequence is [0,1,1,0,0,1],
    第四序列为[0,1,0,1,1,0],The fourth sequence is [0,1,0,1,1,0],
    序列集合8:Sequence set 8:
    所述序列集合8,包含4条长度为4的序列,其中,The sequence set 8 includes four sequences of length 4, wherein
    第一序列为[1,0,0,0],The first sequence is [1,0,0,0],
    第二序列为[0,1,0,0],The second sequence is [0,1,0,0],
    第三序列为[0,0,1,0],The third sequence is [0,0,1,0],
    第四序列为[0,0,0,1];The fourth sequence is [0,0,0,1];
    序列集合9:Sequence set 9:
    所述序列集合9,包含6条长度为6的序列,其中, The sequence set 9 includes six sequences of length 6, wherein
    第一序列为[1,1,1,1,1,1],The first sequence is [1,1,1,1,1,1],
    第二序列为[1,1,1i,-1,-1,-1i],The second sequence is [1,1,1i,-1,-1,-1i],
    第三序列为[1,1i,-1i,1i,-1i,-1],The third sequence is [1, 1i, -1i, 1i, -1i, -1],
    第四序列为[1,-1,1,-1i,-1,1i],The fourth sequence is [1,-1,1,-1i,-1,1i],
    第五序列为[1,-1,-1,1,1i,-1i],The fifth sequence is [1,-1,-1,1,1i,-1i],
    第六序列为[1,-1i,-1,-1,1,1i];The sixth sequence is [1,-1i,-1,-1,1,1i];
    其中,i为虚数单位,i=sqrt(-1)。Where i is an imaginary unit and i=sqrt(-1).
  7. 根据权利要求1所述的数据生成方法,其中,根据第一序列和第二序列确定第三序列时,或者The data generating method according to claim 1, wherein when the third sequence is determined based on the first sequence and the second sequence, or
    从第三序列集合中确定所述第三序列,且所述第三序列集合包括第二指定序列集合、对第二指定序列集合进行处理得到的序列集合、根据第一序列集合和第二序列集合得到的序列集合至少之一时,Determining the third sequence from the third sequence set, and the third sequence set includes a second specified sequence set, a sequence set obtained by processing the second specified sequence set, according to the first sequence set and the second sequence set When at least one of the resulting sequence sets is obtained,
    所述对所述第二指定序列集合中的序列进行处理,包括:The processing of the sequence in the second specified sequence set includes:
    对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素乘以1、1i、-1、或-1i,或者乘以1i的E次方;或者,Multiplying the Yth sequence element of each sequence or each sequence in the second specified sequence set by 1, 1i, -1, or -1i, or multiplying by 1i to the power of E; or
    对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素进行F*π的相位调整或旋转,或者,乘以exp(j*F*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of F*π for each sequence in the second specified sequence set or the Yth sequence element of each sequence, or multiply exp(j*F*π), j is an imaginary unit , j=sqrt(-1); or,
    对所述第二指定序列集合中的每条序列或每条序列的第Y个序列元素乘以指定值,或者分别乘以指定值;Multiplying each of the sequence of the second specified sequence set or the Yth sequence element of each sequence by a specified value, or multiplying by a specified value;
    其中,Y为大于或等于1且小于或等于C的整数,E为整数,F为实数。Wherein Y is an integer greater than or equal to 1 and less than or equal to C, E is an integer, and F is a real number.
  8. 根据权利要求1所述的数据生成方法,其中,从第三序列集合中确定所述第三序列时,The data generating method according to claim 1, wherein when the third sequence is determined from the third sequence set,
    所述第三指定序列集合包括下述序列集合至少之一:The third specified sequence set includes at least one of the following sequence sets:
    序列集合1:Sequence set 1:
    所述序列集合1,包含16条长度为4的序列,其中, The sequence set 1 comprises 16 sequences of length 4, wherein
    第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
    第二序列为[1,1,-1,-1],The second sequence is [1,1,-1,-1],
    第三序列为[1,-1,1,-1],The third sequence is [1,-1,1,-1],
    第四序列为[1,-1,-1,1],The fourth sequence is [1,-1,-1,1],
    第五序列为[1,1,1i,-1i],The fifth sequence is [1,1,1i,-1i],
    第六序列为[1,1,-1i,1i],The sixth sequence is [1,1,-1i,1i],
    第七序列为[1,-1,1i,1i],The seventh sequence is [1,-1,1i,1i],
    第八序列为[1,-1,-1i,-1i],The eighth sequence is [1,-1,-1i,-1i],
    第九序列为[1,1i,1,-1i],The ninth sequence is [1, 1i, 1, -1i],
    第十序列为[1,1i,-1,1i],The tenth sequence is [1, 1i, -1, 1i],
    第十一序列为[1,-1i,1,1i],The eleventh sequence is [1,-1i,1,1i],
    第十二序列为[1,-1i,-1,-1i],The twelfth sequence is [1,-1i,-1,-1i],
    第十三序列为[1,1i,1i,-1],The thirteenth sequence is [1, 1i, 1i, -1],
    第十四序列为[1,1i,-1i,1],The fourteenth sequence is [1, 1i, -1i, 1],
    第十五序列为[1,-1i,1i,1],The fifteenth sequence is [1,-1i,1i,1],
    第十六序列为[1,-1i,-1i,-1];The sixteenth sequence is [1,-1i,-1i,-1];
    序列集合2:Sequence collection 2:
    所述序列集合2,包含16条长度为4的序列,其中,The sequence set 2 includes 16 sequences of length 4, wherein
    第一序列为[1,1,1,-1],The first sequence is [1,1,1,-1],
    第二序列为[1,1,-1,1],The second sequence is [1,1,-1,1],
    第三序列为[1,-1,1,1],The third sequence is [1,-1,1,1],
    第四序列为[1,-1,-1,-1],The fourth sequence is [1,-1,-1,-1],
    第五序列为[1,1,1i,1i],The fifth sequence is [1,1,1i,1i],
    第六序列为[1,1,-1i,-1i],The sixth sequence is [1,1,-1i,-1i],
    第七序列为[1,-1,1i,-1i],The seventh sequence is [1,-1,1i,-1i],
    第八序列为[1,-1,-1i,1i], The eighth sequence is [1,-1,-1i,1i],
    第九序列为[1,1i,1,1i],The ninth sequence is [1, 1i, 1, 1i],
    第十序列为[1,1i,-1,-1i],The tenth sequence is [1, 1i, -1, -1i],
    第十一序列为[1,-1i,1,-1i],The eleventh sequence is [1,-1i,1,-1i],
    第十二序列为[1,-1i,-1,1i],The twelfth sequence is [1,-1i,-1,1i],
    第十三序列为[1,1i,1i,1],The thirteenth sequence is [1, 1i, 1i, 1],
    第十四序列为[1,1i,-1i,-1],The fourteenth sequence is [1, 1i, -1i, -1],
    第十五序列为[1,-1i,1i,-1],The fifteenth sequence is [1,-1i,1i,-1],
    第十六序列为[1,-1i,-1i,1];The sixteenth sequence is [1,-1i,-1i,1];
    序列集合3:Sequence Collection 3:
    所述序列集合3,包含16条长度为4的序列,其中,The sequence set 3 includes 16 sequences of length 4, wherein
    第一序列为[1,1,1,1i],The first sequence is [1,1,1,1i],
    第二序列为[1,1,-1,-1i],The second sequence is [1,1,-1,-1i],
    第三序列为[1,-1,1,-1i],The third sequence is [1,-1,1,-1i],
    第四序列为[1,-1,-1,1i],The fourth sequence is [1,-1,-1,1i],
    第五序列为[1,1,1i,1],The fifth sequence is [1,1,1i,1],
    第六序列为[1,1,-1i,-1],The sixth sequence is [1,1,-1i,-1],
    第七序列为[1,-1,1i,-1],The seventh sequence is [1,-1,1i,-1],
    第八序列为[1,-1,-1i,1],The eighth sequence is [1,-1,-1i,1],
    第九序列为[1,1i,1,1],The ninth sequence is [1, 1i, 1, 1],
    第十序列为[1,1i,-1,-1],The tenth sequence is [1, 1i, -1, -1],
    第十一序列为[1,-1i,1,-1],The eleventh sequence is [1,-1i,1,-1],
    第十二序列为[1,-1i,-1,1],The twelfth sequence is [1,-1i,-1,1],
    第十三序列为[1,1i,1i,-1i],The thirteenth sequence is [1, 1i, 1i, -1i],
    第十四序列为[1,1i,-1i,1i],The fourteenth sequence is [1, 1i, -1i, 1i],
    第十五序列为[1,-1i,1i,1i],The fifteenth sequence is [1,-1i,1i,1i],
    第十六序列为[1,-1i,-1i,-1i]; The sixteenth sequence is [1,-1i,-1i,-1i];
    序列集合4:Sequence Collection 4:
    所述序列集合4,包含16条长度为4的序列,其中,The sequence set 4 includes 16 sequences of length 4, wherein
    第一序列为[1,1,1,-1i],The first sequence is [1,1,1,-1i],
    第二序列为[1,1,-1,1i],The second sequence is [1,1,-1,1i],
    第三序列为[1,-1,1,1i],The third sequence is [1,-1,1,1i],
    第四序列为[1,-1,-1,-1i],The fourth sequence is [1,-1,-1,-1i],
    第五序列为[1,1,1i,-1],The fifth sequence is [1,1,1i,-1],
    第六序列为[1,1,-1i,1],The sixth sequence is [1,1,-1i,1],
    第七序列为[1,-1,1i,1],The seventh sequence is [1,-1,1i,1],
    第八序列为[1,-1,-1i,-1],The eighth sequence is [1,-1,-1i,-1],
    第九序列为[1,1i,1,-1],The ninth sequence is [1, 1i, 1, -1],
    第十序列为[1,1i,-1,1],The tenth sequence is [1, 1i, -1, 1],
    第十一序列为[1,-1i,1,1],The eleventh sequence is [1,-1i,1,1],
    第十二序列为[1,-1i,-1,-1],The twelfth sequence is [1,-1i,-1,-1],
    第十三序列为[1,1i,1i,1i],The thirteenth sequence is [1, 1i, 1i, 1i],
    第十四序列为[1,1i,-1i,-1i],The fourteenth sequence is [1, 1i, -1i, -1i],
    第十五序列为[1,-1i,1i,-1i],The fifteenth sequence is [1,-1i,1i,-1i],
    第十六序列为[1,-1i,-1i,1i];The sixteenth sequence is [1,-1i,-1i,1i];
    序列集合5:Sequence Collection 5:
    所述序列集合5,包含32条长度为4的序列,其中,The sequence set 5 includes 32 sequences of length 4, wherein
    第一序列为[1,1,1,1],The first sequence is [1,1,1,1],
    第二序列为[1,1i,-1,-1i],The second sequence is [1, 1i, -1, -1i],
    第三序列为[1,-1,1,-1],The third sequence is [1,-1,1,-1],
    第四序列为[1,-1i,-1,1i],The fourth sequence is [1,-1i,-1,1i],
    第五序列为[1,1,1i,-1i],The fifth sequence is [1,1,1i,-1i],
    第六序列为[1,1i,-1i,-1], The sixth sequence is [1, 1i, -1i, -1],
    第七序列为[1,-1,1i,1i],The seventh sequence is [1,-1,1i,1i],
    第八序列为[1,-1i,-1i,1],The eighth sequence is [1,-1i,-1i,1],
    第九序列为[1,1i,1,-1i],The ninth sequence is [1, 1i, 1, -1i],
    第十序列为[1,-1,-1,-1],The tenth sequence is [1,-1,-1,-1],
    第十一序列为[1,-1i,1,1i],The eleventh sequence is [1,-1i,1,1i],
    第十二序列为[1,1,-1,1],The twelfth sequence is [1,1,-1,1],
    第十三序列为[1,1i,1i,-1],The thirteenth sequence is [1, 1i, 1i, -1],
    第十四序列为[1,-1,-1i,1i],The fourteenth sequence is [1,-1,-1i,1i],
    第十五序列为[1,-1i,1i,1],The fifteenth sequence is [1,-1i,1i,1],
    第十六序列为[1,1,-1i,-1i],The sixteenth sequence is [1,1,-1i,-1i],
    第十七序列为[1,1,1,-1],The seventeenth sequence is [1,1,1,-1],
    第十八序列为[1,1i,-1,1i],The eighteenth sequence is [1, 1i, -1, 1i],
    第十九序列为[1,-1,1,1],The nineteenth sequence is [1,-1,1,1],
    第二十序列为[1,-1i,-1,-1i],The twentieth sequence is [1,-1i,-1,-1i],
    第二十一序列为[1,1,1i,1i],The twenty-first sequence is [1,1,1i,1i],
    第二十二序列为[1,1i,-1i,1],The twenty-second sequence is [1, 1i, -1i, 1],
    第二十三序列为[1,-1,1i,-1i],The twenty-third sequence is [1,-1,1i,-1i],
    第二十四序列为[1,-1i,-1i,-1],The twenty-fourth sequence is [1,-1i,-1i,-1],
    第二十五序列为[1,1i,1,1i],The twenty-fifth sequence is [1,1i,1,1i],
    第二十六序列为[1,-1,-1,1],The twenty-sixth sequence is [1,-1,-1,1],
    第二十七序列为[1,-1i,1,-1i],The twenty-seventh sequence is [1,-1i,1,-1i],
    第二十八序列为[1,1,-1,-1],The twenty-eighth sequence is [1,1,-1,-1],
    第二十九序列为[1,1i,1i,1],The twenty-ninth sequence is [1, 1i, 1i, 1],
    第三十序列为[1,-1,-1i,-1i],The thirtieth sequence is [1,-1,-1i,-1i],
    第三十一序列为[1,-1i,1i,-1],The thirty-first sequence is [1,-1i,1i,-1],
    第三十二序列为[1,1,-1i,1i]; The thirty-second sequence is [1,1,-1i,1i];
    序列集合6:Sequence set 6:
    所述序列集合6,包含32条长度为4的序列,其中,The sequence set 6 includes 32 sequences of length 4, wherein
    第一序列为[1,1,1,1i],The first sequence is [1,1,1,1i],
    第二序列为[1,1i,-1,1],The second sequence is [1, 1i, -1, 1],
    第三序列为[1,-1,1,-1i],The third sequence is [1,-1,1,-1i],
    第四序列为[1,-1i,-1,-1],The fourth sequence is [1,-1i,-1,-1],
    第五序列为[1,1,1i,1],The fifth sequence is [1,1,1i,1],
    第六序列为[1,1i,-1i,-1i],The sixth sequence is [1, 1i, -1i, -1i],
    第七序列为[1,-1,1i,-1],The seventh sequence is [1,-1,1i,-1],
    第八序列为[1,-1i,-1i,1i],The eighth sequence is [1,-1i,-1i,1i],
    第九序列为[1,1i,1,1],The ninth sequence is [1, 1i, 1, 1],
    第十序列为[1,-1,-1,-1i],The tenth sequence is [1,-1,-1,-1i],
    第十一序列为[1,-1i,1,-1],The eleventh sequence is [1,-1i,1,-1],
    第十二序列为[1,1,-1,i],The twelfth sequence is [1,1,-1,i],
    第十三序列为[1,1i,1i,-1i],The thirteenth sequence is [1, 1i, 1i, -1i],
    第十四序列为[1,-1,-1i,-1],The fourteenth sequence is [1,-1,-1i,-1],
    第十五序列为[1,-1i,1i,i],The fifteenth sequence is [1,-1i,1i,i],
    第十六序列为[1,1,-1i,1],The sixteenth sequence is [1,1,-1i,1],
    第十七序列为[1,1,1,-1i],The seventeenth sequence is [1,1,1,-1i],
    第十八序列为[1,1i,-1,-1],The eighteenth sequence is [1,1i,-1,-1],
    第十九序列为[1,-1,1,1i],The nineteenth sequence is [1,-1,1,1i],
    第二十序列为[1,-1i,-1,1],The twentieth sequence is [1,-1i,-1,1],
    第二十一序列为[1,1,1i,-1],The twenty-first sequence is [1,1,1i,-1],
    第二十二序列为[1,1i,-1i,1i],The twenty-second sequence is [1, 1i, -1i, 1i],
    第二十三序列为[1,-1,1i,1],The twenty-third sequence is [1,-1,1i,1],
    第二十四序列为[1,-1i,-1i,-1i], The twenty-fourth sequence is [1,-1i,-1i,-1i],
    第二十五序列为[1,1i,1,-1],The twenty-fifth sequence is [1, 1i, 1, -1],
    第二十六序列为[1,-1,-1,1i],The twenty-sixth sequence is [1,-1,-1,1i],
    第二十七序列为[1,-1i,1,1],The twenty-seventh sequence is [1,-1i,1,1],
    第二十八序列为[1,1,-1,-1i],The twenty-eighth sequence is [1,1,-1,-1i],
    第二十九序列为[1,1i,1i,1i],The twenty-ninth sequence is [1, 1i, 1i, 1i],
    第三十序列为[1,-1,-1i,1],The thirtieth sequence is [1,-1,-1i,1],
    第三十一序列为[1,-1i,1i,-1i],The thirty-first sequence is [1,-1i,1i,-1i],
    第三十二序列为[1,1,-1i,-1];The thirty-second sequence is [1, 1, -1i, -1];
    序列集合7:Sequence collection 7:
    所述序列集合7,包含4条长度为4的序列,其中,The sequence set 7 includes four sequences of length 4, wherein
    第一序列为[1,0,0,0],The first sequence is [1,0,0,0],
    第二序列为[0,1,0,0],The second sequence is [0,1,0,0],
    第三序列为[0,0,1,0],The third sequence is [0,0,1,0],
    第四序列为[0,0,0,1];The fourth sequence is [0,0,0,1];
    序列集合8:Sequence set 8:
    所述序列集合8,包含16条长度为6的序列,其中,The sequence set 8 includes 16 sequences of length 6, wherein
    第一序列为[1,0,1,0,1,0],The first sequence is [1,0,1,0,1,0],
    第二序列为[-1,0,1,0,-1,0],The second sequence is [-1,0,1,0,-1,0],
    第三序列为[1,0,-1,0,-1,0],The third sequence is [1,0,-1,0,-1,0],
    第四序列为[-1,0,-1,0,1,0],The fourth sequence is [-1,0,-1,0,1,0],
    第五序列为[1,0,0,1,0,1],The fifth sequence is [1,0,0,1,0,1],
    第六序列为[-1,0,0,1,0,-1],The sixth sequence is [-1,0,0,1,0,-1],
    第七序列为[1,0,0,-1,0,-1],The seventh sequence is [1,0,0,-1,0,-1],
    第八序列为[-1,0,0,-1,0,1],The eighth sequence is [-1,0,0,-1,0,1],
    第九序列为[0,1,1,0,0,1],The ninth sequence is [0, 1, 1, 0, 0, 1],
    第十序列为[0,-1,1,0,0,-1], The tenth sequence is [0, -1, 1, 0, 0, -1],
    第十一序列为[0,1,-1,0,0,-1],The eleventh sequence is [0, 1, -1, 0, 0, -1],
    第十二序列为[0,-1,-1,0,0,1],The twelfth sequence is [0,-1,-1,0,0,1],
    第十三序列为[0,1,0,1,1,0],The thirteenth sequence is [0,1,0,1,1,0],
    第十四序列为[0,-1,0,1,-1,0],The fourteenth sequence is [0, -1, 0, 1, -1, 0],
    第十五序列为[0,1,0,-1,-1,0],The fifteenth sequence is [0,1,0,-1,-1,0],
    第十六序列为[0,-1,0,-1,1,0];The sixteenth sequence is [0, -1, 0, -1, 1, 0];
    序列集合9:Sequence set 9:
    所述序列集合9,包含16条长度为6的序列,其中,The sequence set 9 includes 16 sequences of length 6, wherein
    第一序列为[1,1,1,0,0,0],The first sequence is [1,1,1,0,0,0],
    第二序列为[-1,1,-1,0,0,0],The second sequence is [-1,1,-1,0,0,0],
    第三序列为[1,-1,-1,0,0,0],The third sequence is [1,-1,-1,0,0,0],
    第四序列为[-1,-1,1,0,0,0],The fourth sequence is [-1,-1,1,0,0,0],
    第五序列为[0,0,1,1,1,0],The fifth sequence is [0,0,1,1,1,0],
    第六序列为[0,0,-1,-1,1,0],The sixth sequence is [0,0,-1,-1,1,0],
    第七序列为[0,0,-1,1,-1,0],The seventh sequence is [0,0,-1,1,-1,0],
    第八序列为[0,0,1,-1,-1,0],The eighth sequence is [0,0,1,-1,-1,0],
    第九序列为[1,0,0,0,1,1],The ninth sequence is [1,0,0,0,1,1],
    第十序列为[-1,0,0,0,1,-1],The tenth sequence is [-1,0,0,0,1,-1],
    第十一序列为[1,0,0,0,-1,-1],The eleventh sequence is [1,0,0,0,-1,-1],
    第十二序列为[-1,0,0,0,-1,1],The twelfth sequence is [-1,0,0,0,-1,1],
    第十三序列为[0,1,0,1,0,1],The thirteenth sequence is [0, 1, 0, 1, 0, 1],
    第十四序列为[0,1,0,-1,0,-1],The fourteenth sequence is [0,1,0,-1,0,-1],
    第十五序列为[0,-1,0,1,0,-1],The fifteenth sequence is [0, -1, 0, 1, 0, -1],
    第十六序列为[0,-1,0,-1,0,1];The sixteenth sequence is [0, -1, 0, -1, 0, 1];
    序列集合10:Sequence collection 10:
    所述序列集合10,包含16条长度为6的序列,其中, The sequence set 10 includes 16 sequences of length 6, wherein
    第一序列为[1,1,1,1,1,1],The first sequence is [1,1,1,1,1,1],
    第二序列为[1,1,1,1,-1,-1],The second sequence is [1,1,1,1,-1,-1],
    第三序列为[1,1,1,-1,1,-1],The third sequence is [1,1,1,-1,1,-1],
    第四序列为[1,1,1,-1,-1,1],The fourth sequence is [1,1,1,-1,-1,1],
    第五序列为[1,1,-1,1,1,-1],The fifth sequence is [1,1,-1,1,1,-1],
    第六序列为[1,1,-1,1,-1,1],The sixth sequence is [1,1,-1,1,-1,1],
    第七序列为[1,1,-1,-1,1,1],The seventh sequence is [1,1,-1,-1,1,1],
    第八序列为[1,1,-1,-1,-1,-1],The eighth sequence is [1,1,-1,-1,-1,-1],
    第九序列为[1,-1,1,1,1,-1],The ninth sequence is [1,-1,1,1,1,-1],
    第十序列为[1,-1,1,1,-1,1],The tenth sequence is [1,-1,1,1,-1,1],
    第十一序列为[1,-1,1,-1,1,1],The eleventh sequence is [1,-1,1,-1,1,1],
    第十二序列为[1,-1,1,-1,-1,-1],The twelfth sequence is [1,-1,1,-1,-1,-1],
    第十三序列为[1,-1,-1,1,1,1],The thirteenth sequence is [1,-1,-1,1,1,1],
    第十四序列为[1,-1,-1,1,-1,-1],The fourteenth sequence is [1,-1,-1,1,-1,-1],
    第十五序列为[1,-1,-1,-1,1,-1],The fifteenth sequence is [1,-1,-1,-1,1,-1],
    第十六序列为[1,-1,-1,-1,-1,1];The sixteenth sequence is [1,-1,-1,-1,-1,1];
    序列集合11:Sequence collection 11:
    所述序列集合11,包含32条长度为4的序列,其中,The sequence set 11 includes 32 sequences of length 4, wherein
    第一序列为[1+0i,1+0i,1+0i,1+0i],The first sequence is [1+0i, 1+0i, 1+0i, 1+0i],
    第二序列为[1+0i,0+1i,-1+0i,-0-1i],The second sequence is [1+0i, 0+1i, -1+0i, -0-1i],
    第三序列为[1+0i,-1+0i,1+0i,-1+0i],The third sequence is [1+0i, -1+0i, 1+0i, -1+0i],
    第四序列为[1+0i,-0-1i,-1+0i,0+1i],The fourth sequence is [1+0i, -0-1i, -1+0i, 0+1i],
    第五序列为[0+2i,-0-1i,0+2i,0+1i],The fifth sequence is [0+2i, -0-1i, 0+2i, 0+1i],
    第六序列为[0+2i,1+0i,-0-2i,1+0i],The sixth sequence is [0+2i, 1+0i, -0-2i, 1+0i],
    第七序列为[0+2i,0+1i,0+2i,-0-1i],The seventh sequence is [0+2i, 0+1i, 0+2i, -0-1i],
    第八序列为[0+2i,-1+0i,-0-2i,-1+0i], The eighth sequence is [0+2i, -1+0i, -0-2i, -1+0i],
    第九序列为[0+2i,-0-1i,-1+0i,2+0i],The ninth sequence is [0+2i, -0-1i, -1+0i, 2+0i],
    第十序列为[0+2i,1+0i,1+0i-0-2i],The tenth sequence is [0+2i, 1+0i, 1+0i-0-2i],
    第十一序列为[0+2i,0+1i,-1+0i,-2+0i],The eleventh sequence is [0+2i, 0+1i, -1+0i, -2+0i],
    第十二序列为[0+2i,-1+0i,1+0i,0+2i],The twelfth sequence is [0+2i, -1+0i, 1+0i, 0+2i],
    第十三序列为[0+2i,-0-1i,0+0i,-1+0i],The thirteenth sequence is [0+2i, -0-1i, 0+0i, -1+0i],
    第十四序列为[0+2i,1+0i,0+0i,0+1i],The fourteenth sequence is [0+2i, 1+0i, 0+0i, 0+1i],
    第十五序列为[0+2i,0+1i,0+0i,1+0i],The fifteenth sequence is [0+2i, 0+1i, 0+0i, 1+0i],
    第十六序列为[0+2i,-1+0i,0+0i,-0-1i],The sixteenth sequence is [0+2i, -1+0i, 0+0i, -0-1i],
    第十七序列为[-1+0i,-0-1i,-0-2i,-2+0i],The seventeenth sequence is [-1+0i, -0-1i, -0-2i, -2+0i],
    第十八序列为[-1+0i,1+0i,0+2i,0+2i],The eighteenth sequence is [-1+0i, 1+0i, 0+2i, 0+2i],
    第十九序列为[-1+0i,0+1i,-0-2i,2+0i],The nineteenth sequence is [-1+0i, 0+1i, -0-2i, 2+0i],
    第二十序列为[-1+0i,-1+0i,0+2i,-0-2i],The twentieth sequence is [-1+0i, -1+0i, 0+2i, -0-2i],
    第二十一序列为[-1+0i,-2+0i,0+2i,0+1i],The twenty-first sequence is [-1+0i, -2+0i, 0+2i, 0+1i],
    第二十二序列为[-1+0i,-0-2i,-0-2i,1+0i],The twenty-second sequence is [-1+0i,-0-2i,-0-2i, 1+0i],
    第二十三序列为[-1+0i,2+0i,0+2i,-0-1i],The twenty-third sequence is [-1+0i, 2+0i, 0+2i, -0-1i],
    第二十四序列为[-1+0i,0+2i,-0-2i,-1+0i],The twenty-fourth sequence is [-1+0i, 0+2i, -0-2i, -1+0i],
    第二十五序列为[-1+0i,-2+0i,1+0i,-2+0i],The twenty-fifth sequence is [-1+0i, -2+0i, 1+0i, -2+0i],
    第二十六序列为[-1+0i,-0-2i,-1+0i,0+2i],The twenty-sixth sequence is [-1+0i, -0-2i, -1+0i, 0+2i],
    第二十七序列为[-1+0i,2+0i,1+0i,2+0i],The twenty-seventh sequence is [-1+0i, 2+0i, 1+0i, 2+0i],
    第二十八序列为[-1+0i,0+2i,-1+0i,-0-2i],The twenty-eighth sequence is [-1+0i, 0+2i, -1+0i, -0-2i],
    第二十九序列为[-1+0i,-2+0i,-0-1i,0+0i],The twenty-ninth sequence is [-1+0i, -2+0i, -0-1i, 0+0i],
    第三十序列为[-1+0i,-0-2i,0+1i,0+0i],The thirtieth sequence is [-1+0i,-0-2i, 0+1i, 0+0i],
    第三十一序列为[-1+0i,2+0i,-0-1i,0+0i],The thirty-first sequence is [-1+0i, 2+0i, -0-1i, 0+0i],
    第三十二序列为[-1+0i,0+2i,0+1i,0+0i];The thirty-second sequence is [-1+0i, 0+2i, 0+1i, 0+0i];
    其中,i为虚数单位,i=sqrt(-1);或者Where i is an imaginary unit, i=sqrt(-1); or
    对序列集合1、序列集合2、序列集合3、序列集合4、序列集合5、序 列集合6、序列集合7、序列集合8、序列集合9、序列集合10、序列集合11这十一个序列集合中的序列,分别进行下述任一处理得到的集合:Pair sequence set 1, sequence set 2, sequence set 3, sequence set 4, sequence set 5, order The sequences in the eleven sequence sets of the column set 6, the sequence set 7, the sequence set 8, the sequence set 9, the sequence set 10, and the sequence set 11 are each subjected to any of the following processes:
    其中,所述任一处理,包括:Wherein, any of the processes described includes:
    对序列集合中的每条序列或每条序列的第S个序列元素乘以1、1i、-1、或-1i,或者乘以1i的Q次方;或者,Multiply the S-th sequence element of each sequence or each sequence in the sequence set by 1, 1i, -1, or -1i, or multiply by the Q-th power of 1i; or,
    对序列集合中的每条序列或每条序列的第S个序列元素进行R*π的相位调整或旋转,或者,乘以exp(j*R*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of R*π for each sequence in the sequence set or the Sth sequence element of each sequence, or multiply exp(j*R*π), j is an imaginary unit, j=sqrt( -1); or,
    对序列集合中的每条序列或每条序列的第S个序列元素乘以指定值,或者分别乘以指定值;Multiplying each sequence in the sequence set or the Sth sequence element of each sequence by a specified value, or multiplying by a specified value;
    其中,S为大于或等于1且小于或等于W的整数,Q为整数,R为实数。Wherein S is an integer greater than or equal to 1 and less than or equal to W, Q is an integer, and R is a real number.
  9. 根据权利要求1所述的数据生成方法,其中,从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,The data generating method according to claim 1, wherein the third sequence is determined from a third sequence set, and the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set,
    所述根据所述第一序列集合和所述第二序列集合得到的序列集合,包括以下至少之一:The sequence set obtained according to the first sequence set and the second sequence set includes at least one of the following:
    所述第一序列集合中的任意一条序列与所述第二序列集合中的任意一条序列进行点乘处理得到的序列构成的序列集合;a sequence set formed by a sequence obtained by performing dot multiplication processing on any one of the first sequence set and any one of the second sequence sets;
    所述第一序列集合中的任意一条序列与所述第二序列集合中的任意一条序列进行乘法处理得到的序列构成的序列集合;a sequence set formed by a sequence obtained by multiplying any one of the first sequence set and any one of the second sequence sets;
    所述第一序列集合中的任意一条序列的元素替换所述第二序列集合中的任意一条序列的非零元素得到的序列构成的序列集合;And deleting, by the element of any one of the first sequence sets, a sequence set formed by a sequence obtained by replacing a non-zero element of any one of the second sequence sets;
    所述第一序列集合中的任意一条序列的元素与所述第二序列集合中的任意一条序列的非零元素进行点乘处理得到的序列构成的序列集合。a sequence set formed by a sequence obtained by performing dot multiplication processing on an element of any one of the first sequence sets and a non-zero element of any one of the second sequence sets.
  10. 根据权利要求1所述的数据生成方法,其中,根据第一序列和第二序列确定第三序列时,或者 The data generating method according to claim 1, wherein when the third sequence is determined based on the first sequence and the second sequence, or
    从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,Determining the third sequence from a third sequence set, and the third sequence set includes a sequence set obtained according to the first sequence set and the second sequence set,
    所述第一序列从第一序列集合中获取,包括以下之一:The first sequence is obtained from the first sequence set, including one of the following:
    采用随机选择的方式从所述第一序列集合中获取第一序列;Obtaining the first sequence from the first sequence set in a random selection manner;
    根据第一预设规则从所述第一序列集合中获取第一序列;Obtaining a first sequence from the first sequence set according to a first preset rule;
    根据系统配置信息从所述第一序列集合中获取第一序列。Acquiring the first sequence from the first sequence set according to system configuration information.
  11. 根据权利要求1所述的数据生成方法,其中,根据第一序列和第二序列确定第三序列时,或者The data generating method according to claim 1, wherein when the third sequence is determined based on the first sequence and the second sequence, or
    从第三序列集合中确定所述第三序列,且所述第三序列集合包括第二指定序列集合、对第二指定序列集合进行处理得到的序列集合、根据第一序列集合和第二序列集合得到的序列集合至少之一时,Determining the third sequence from the third sequence set, and the third sequence set includes a second specified sequence set, a sequence set obtained by processing the second specified sequence set, according to the first sequence set and the second sequence set When at least one of the resulting sequence sets is obtained,
    所述所述第二序列从第二序列集合中获取,包括以下之一:The second sequence is obtained from a second sequence set, including one of the following:
    采用随机选择的方式从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second set of sequences in a randomly selected manner;
    根据第二预设规则从所述第二序列集合中获取第二序列;Obtaining a second sequence from the second sequence set according to a second preset rule;
    根据系统配置信息从所述第二序列集合中获取第二序列。Obtaining a second sequence from the second set of sequences according to system configuration information.
  12. 根据权利要求1所述的数据生成方法,其中,根据第一序列和第二序列确定第三序列时,The data generating method according to claim 1, wherein when the third sequence is determined based on the first sequence and the second sequence,
    所述所述根据第一序列和第二序列确定第三序列,包括:The determining the third sequence according to the first sequence and the second sequence includes:
    将所述第一序列与所述第二序列进行点乘处理,生成第三序列;或者,Performing point-multiplication processing on the first sequence and the second sequence to generate a third sequence; or
    将所述第一序列与所述第二序列进行乘法处理,生成第三序列;或者,Multiplying the first sequence and the second sequence to generate a third sequence; or
    使用所述第一序列中的元素替换所述第二序列中的非零元素,生成第三序列;或者,Substituting an element in the first sequence for a non-zero element in the second sequence to generate a third sequence; or
    将所述第一序列中的元素与所述第二序列中的非零元素进行点乘处理后得到的值替换所述第二序列中的非零元素,生成第三序列。Substituting a value obtained by dot-multiplying an element in the first sequence with a non-zero element in the second sequence to replace a non-zero element in the second sequence to generate a third sequence.
  13. 根据权利要求1所述的数据生成方法,其中,从第三序列集合中确定所述第三序列时, The data generating method according to claim 1, wherein when the third sequence is determined from the third sequence set,
    所述从第三序列集合中确定所述第三序列,包括:Determining the third sequence from the third sequence set includes:
    采用随机选择的方式从所述第三序列集合中获取所述第三序列;Obtaining the third sequence from the third sequence set in a randomly selected manner;
    根据第三预设规则从所述第三序列集合中获取所述第三序列;Obtaining the third sequence from the third sequence set according to a third preset rule;
    根据系统配置信息从所述第三序列集合中获取所述第三序列。Obtaining the third sequence from the third sequence set according to system configuration information.
  14. 根据权利要求1所述的数据生成方法,其中,The data generating method according to claim 1, wherein
    根据第一序列和第二序列确定第三序列时,或者,从第三序列集合中确定所述第三序列,且所述第三序列集合包括根据第一序列集合和第二序列集合得到的序列集合时,所述方法还包括以下之一:Determining the third sequence according to the first sequence and the second sequence, or determining the third sequence from the third sequence set, and the third sequence set includes a sequence obtained according to the first sequence set and the second sequence set When collecting, the method further includes one of the following:
    对所述第一序列集合中的序列进行能量调整或能量归一化处理;Performing energy adjustment or energy normalization processing on the sequence in the first sequence set;
    对所述第一序列进行能量调整或能量归一化处理;Performing energy adjustment or energy normalization on the first sequence;
    对所述第三序列进行能量调整或能量归一化处理;Performing energy adjustment or energy normalization on the third sequence;
    从第三序列集合中确定所述第三序列,且所述第三序列集合不包括根据第一序列集合和第二序列集合得到的序列集合时,所述方法还包括以下之一:When the third sequence is determined from the third sequence set, and the third sequence set does not include the sequence set obtained according to the first sequence set and the second sequence set, the method further includes one of the following:
    对所述第三序列进行能量调整或能量归一化处理。The third sequence is subjected to energy adjustment or energy normalization.
  15. 根据权利要求1所述的数据生成方法,其中,所述方法还包括:The data generating method according to claim 1, wherein the method further comprises:
    对所述第三序列的每个元素或第V个元素乘以1、1i、-1、或-1i,或者,乘以1i的G次方;或者,Multiplying each element or the Vth element of the third sequence by 1, 1i, -1, or -1i, or multiplying by the G of 1i; or
    对所述第三序列的每个元素或第V个元素进行H*π的相位调整或旋转,或者,乘以exp(j*H*π),j为虚数单位,j=sqrt(-1);或者,Perform phase adjustment or rotation of H*π for each element or Vth element of the third sequence, or multiply exp(j*H*π), j is an imaginary unit, j=sqrt(-1) ;or,
    对所述第三序列的每个元素或第V个元素乘以指定值;Multiplying each element or the Vth element of the third sequence by a specified value;
    其中,V为大于或等于1且小于或等于所述第三序列的长度的整数,G为整数,H为实数。Wherein V is an integer greater than or equal to 1 and less than or equal to the length of the third sequence, G is an integer, and H is a real number.
  16. 根据权利要求1所述的数据生成方法,其中,所述使用所述第三序列对第一数据进行处理生成第二数据,包括:The data generating method according to claim 1, wherein the processing the first data by using the third sequence to generate the second data comprises:
    使用所述第三序列对第一数据进行扩展处理生成第二数据;或, And expanding, by using the third sequence, the first data to generate second data; or
    使用所述第三序列对第一数据进行映射处理生成第二数据;或,Performing mapping processing on the first data by using the third sequence to generate second data; or
    使用所述第三序列对第一数据进行调制处理生成第二数据。The first data is modulated using the third sequence to generate second data.
  17. 根据权利要求1所述的数据生成方法,其中,所述方法还包括:The data generating method according to claim 1, wherein the method further comprises:
    将所述第二数据映射到指定的传输资源上,用于形成发射信号以及发送。Mapping the second data to a designated transmission resource for forming a transmit signal and transmitting.
  18. 根据权利要求1所述的数据生成方法,其中,The data generating method according to claim 1, wherein
    所述第一数据至少包含发射机或终端的身份标识信息;或者,The first data includes at least identifier information of a transmitter or a terminal; or
    至少包含有发射机或终端的身份标识信息和信令信息;或者,Containing at least the identity information and signaling information of the transmitter or terminal; or,
    至少包含有发射机或终端的身份标识信息和数据信息;或者,Include at least the identity information and data information of the transmitter or terminal; or,
    至少包含有发射机或终端的身份标识信息、信令信息和数据信息;或者,Containing at least the identity information, signaling information, and data information of the transmitter or terminal; or,
    至少包含有发射机或终端的身份标识信息和小区标识信息;或者,At least the identity information and the cell identification information of the transmitter or the terminal are included; or
    至少包含有发射机或终端的身份标识信息、小区标识信息和信令信息;或者,Include at least the identity information, cell identification information, and signaling information of the transmitter or the terminal; or,
    至少包含有发射机或终端的身份标识信息、小区标识信息和数据信息;或者,Include at least the identity information, cell identification information, and data information of the transmitter or the terminal; or,
    至少包含有发射机或终端的身份标识信息、小区标识信息、数据信息和信令信息。At least the identity information, cell identification information, data information and signaling information of the transmitter or the terminal are included.
  19. 根据权利要求1所述的数据生成方法,其中,The data generating method according to claim 1, wherein
    第二数据至少包含发射机或终端的身份标识信息;The second data includes at least the identity information of the transmitter or the terminal;
    或者,至少包含有发射机或终端的身份标识信息和信令信息;Or at least including identity information and signaling information of the transmitter or the terminal;
    或者,至少包含有发射机或终端的身份标识信息和数据信息;Or at least the identity information and the data information of the transmitter or the terminal;
    或者,至少包含有发射机或终端的身份标识信息、信令信息和数据信息;或者,Or at least the identity information, signaling information, and data information of the transmitter or the terminal; or,
    至少包含有发射机或终端的身份标识信息和小区标识信息;或者,At least the identity information and the cell identification information of the transmitter or the terminal are included; or
    至少包含有发射机或终端的身份标识信息、小区标识信息和信令信息; 或者,At least the identity information, the cell identification information and the signaling information of the transmitter or the terminal are included; or,
    至少包含有发射机或终端的身份标识信息、小区标识信息和数据信息;或者,Include at least the identity information, cell identification information, and data information of the transmitter or the terminal; or,
    至少包含有发射机或终端的身份标识信息、小区标识信息、数据信息和信令信息。At least the identity information, cell identification information, data information and signaling information of the transmitter or the terminal are included.
  20. 根据权利要求17所述的数据生成方法,其中,所述指定的传输资源包括下述至少之一:载波、时隙、时频资源、空域资源、码域资源、跳频模式、天线端口。The data generating method according to claim 17, wherein the specified transmission resource comprises at least one of: a carrier, a time slot, a time-frequency resource, a spatial domain resource, a code domain resource, a frequency hopping mode, and an antenna port.
  21. 根据权利要求20所述的数据生成方法,其中,所述时频资源为上行数据信道,或者上行控制信道,或者随机接入信道。The data generating method according to claim 20, wherein the time-frequency resource is an uplink data channel, or an uplink control channel, or a random access channel.
  22. 根据权利要求1所述的数据生成方法,其中,所述第一数据包括以下至少之一信息:车况信息、驾驶员的操作信息,车辆传感器所感知的信息和控制信令;其中,所述车况信息包括以下至少之一:车辆工具标识、所述车辆当前地理位置、所述车辆的行驶速度、所述车辆的大小、所述车辆的颜色;所述操作信息包括以下至少之一:所述驾驶员对所述车辆正在进行的操作,所述驾驶员准备对所述车辆进行的操作。The data generating method according to claim 1, wherein the first data includes at least one of: vehicle condition information, driver's operation information, information sensed by a vehicle sensor, and control signaling; wherein the vehicle condition The information includes at least one of: a vehicle tool identification, a current geographic location of the vehicle, a traveling speed of the vehicle, a size of the vehicle, a color of the vehicle; the operational information including at least one of: the driving An operation performed by the driver on the vehicle, the driver preparing an operation on the vehicle.
  23. 一种数据生成装置,其中,所述装置包括:A data generating device, wherein the device comprises:
    确定单元,配置为根据第一序列和第二序列确定第三序列,其中,所述第一序列从第一序列集合中获取,所述第二序列从第二序列集合中获取;或者,从第三序列集合中确定所述第三序列;a determining unit, configured to determine a third sequence according to the first sequence and the second sequence, wherein the first sequence is obtained from a first sequence set, and the second sequence is obtained from a second sequence set; or, from Determining the third sequence in a three-sequence set;
    生成单元,配置为使用所述第三序列对第一数据进行处理生成第二数据;a generating unit, configured to process the first data by using the third sequence to generate second data;
    其中,所述第一序列集合包括包含M条长度为L的序列的第一指定序列集合、和/或对所述第一指定序列集合进行处理得到的序列集合;The first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set;
    其中,所述第二序列集合包括包含N条长度为C的序列的第二指定序列集合、和/或对所述第二指定序列集合进行处理得到的序列集合; The second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set;
    其中,所述第三序列集合包括以下至少之一:包含P条长度为W的序列的第三指定序列集合;所述第二指定序列集合;对所述第二指定序列集合进行处理得到的序列集合;根据所述第一序列集合和所述第二序列集合得到的序列集合;The third sequence set includes at least one of: a third specified sequence set including P sequences of length W; the second specified sequence set; and a sequence obtained by processing the second specified sequence set a set of sequences obtained from the first set of sequences and the second set of sequences;
    其中,M、L、N、C、P、W为正整数。Among them, M, L, N, C, P, and W are positive integers.
  24. 根据权利要求23所述的数据生成装置,其中,所述确定单元根据第一序列和第二序列确定第三序列时所述第一指定序列集合中的序列元素的取值,或者The data generating apparatus according to claim 23, wherein said determining unit determines a value of a sequence element in said first specified sequence set when said third sequence is determined based on said first sequence and said second sequence, or
    所述确定单元从第三序列集合中确定所述第三序列时所述第三指定序列集合中的序列元素的取值,均来自于以下集合至少之一:And determining, by the determining unit, the values of the sequence elements in the third specified sequence set when determining the third sequence from the third sequence set, all from at least one of the following sets:
    {1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,-1+1i,-1-1i,1-1i};{0};{1,1i,-1,-1i,0};{1+1i,-1+1i,-1-1i,1-1i,0};{1,1i,-1,-1i,2,2i,-2,-2i,0};其中,i为虚数单位,i=sqrt(-1)。{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i,- 1+1i, -1-1i, 1-1i}; {0}; {1, 1i, -1, -1i, 0}; {1+1i, -1+1i, -1-1i, 1-1i , 0}; {1, 1i, -1, -1i, 2, 2i, -2, -2i, 0}; where i is an imaginary unit and i = sqrt(-1).
  25. 根据权利要求23所述的数据生成装置,其中,所述确定单元根据第一序列和第二序列确定第三序列时,或者,从第三序列集合中确定所述第三序列,且所述第三序列集合包括第二指定序列集合、对所述第二指定序列集合进行处理得到的序列集合、根据第一序列集合和第二序列集合得到的序列集合至少之一时,The data generating apparatus according to claim 23, wherein said determining unit determines the third sequence from the first sequence and the second sequence, or determines the third sequence from the third sequence set, and said The three-sequence set includes a second specified sequence set, a sequence set obtained by processing the second specified sequence set, and at least one of the sequence set obtained according to the first sequence set and the second sequence set,
    所述第二指定序列集合包括以下至少之一:The second specified sequence set includes at least one of the following:
    哈达玛序列集合;Hadamard sequence collection;
    沃尔什序列集合;Walsh sequence collection;
    离散傅里叶变换序列集合;a set of discrete Fourier transform sequences;
    包含指定数量或指定比例的0元素的序列的集合;a collection of sequences containing a specified number or a specified proportion of 0 elements;
    单位矩阵序列集合。A collection of unit matrix sequences.
  26. 根据权利要求23所述的数据生成装置,其中,所述生成单元,还配置为: The data generating apparatus according to claim 23, wherein the generating unit is further configured to:
    使用所述第三序列对第一数据进行扩展处理生成第二数据;或,And expanding, by using the third sequence, the first data to generate second data; or
    使用所述第三序列对第一数据进行映射处理生成第二数据;或,Performing mapping processing on the first data by using the third sequence to generate second data; or
    使用所述第三序列对第一数据进行调制处理生成第二数据。The first data is modulated using the third sequence to generate second data.
  27. 根据权利要求23所述的数据生成装置,其中,所述装置还包括:The data generating device of claim 23, wherein the device further comprises:
    映射单元,配置为将所述第二数据映射到指定的传输资源上,用于形成发射信号以及发送。a mapping unit configured to map the second data onto a designated transmission resource for forming a transmit signal and transmitting.
  28. 一种设备,所述设备包括处理器以及存储有所述处理器可执行指令的存储器,当所述指令被处理器执行时,执行如下操作:An apparatus comprising a processor and a memory storing the processor-executable instructions, when the instructions are executed by the processor, performing the following operations:
    根据第一序列和第二序列确定第三序列,其中,所述第一序列从第一序列集合中获取,所述第二序列从第二序列集合中获取;或者,从第三序列集合中确定所述第三序列;Determining a third sequence according to the first sequence and the second sequence, wherein the first sequence is obtained from a first sequence set, the second sequence is obtained from a second sequence set; or, determined from a third sequence set The third sequence;
    使用所述第三序列对第一数据进行处理生成第二数据;Processing the first data by using the third sequence to generate second data;
    其中,所述第一序列集合包括包含M条长度为L的序列的第一指定序列集合、和/或对所述第一指定序列集合进行处理得到的序列集合;The first sequence set includes a first specified sequence set including M sequences of length L, and/or a sequence set obtained by processing the first specified sequence set;
    其中,所述第二序列集合包括包含N条长度为C的序列的第二指定序列集合、和/或对所述第二指定序列集合进行处理得到的序列集合;The second sequence set includes a second specified sequence set including N sequences of length C, and/or a sequence set obtained by processing the second specified sequence set;
    其中,所述第三序列集合包括以下至少之一:包含P条长度为W的序列的第三指定序列集合;所述第二指定序列集合;对所述第二指定序列集合进行处理得到的序列集合;根据所述第一序列集合和所述第二序列集合得到的序列集合;The third sequence set includes at least one of: a third specified sequence set including P sequences of length W; the second specified sequence set; and a sequence obtained by processing the second specified sequence set a set of sequences obtained from the first set of sequences and the second set of sequences;
    其中,M、L、N、C、P、W为正整数。Among them, M, L, N, C, P, and W are positive integers.
  29. 根据权利要求28所述的设备,其中,所述处理器根据第一序列和第二序列确定第三序列时所述第一指定序列集合中的序列元素的取值,或者,从第三序列集合中确定所述第三序列时所述第三指定序列集合中的序列元素的取值,均来自于以下集合至少之一:The apparatus according to claim 28, wherein said processor determines a value of a sequence element in said first specified sequence set when said third sequence is determined according to said first sequence and said second sequence, or from said third sequence set The values of the sequence elements in the third specified sequence set when determining the third sequence are all from at least one of the following sets:
    {1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i, -1+1i,-1-1i,1-1i};{0};{1,1i,-1,-1i,0};{1+1i,-1+1i,-1-1i,1-1i,0};{1,1i,-1,-1i,2,2i,-2,-2i,0};其中,i为虚数单位,i=sqrt(-1)。{1,1i,-1,-1i};{1,-1};{1i,-1i};{1};{-1};{1i};{-1i};{1+1i, -1+1i, -1-1i, 1-1i}; {0}; {1, 1i, -1, -1i, 0}; {1+1i, -1+1i, -1-1i, 1- 1i, 0}; {1, 1i, -1, -1i, 2, 2i, -2, -2i, 0}; where i is an imaginary unit and i = sqrt(-1).
  30. 根据权利要求28所述的设备,其中,所述处理器根据第一序列和第二序列确定第三序列时,或者,从第三序列集合中确定所述第三序列,且所述第三序列集合包括第二指定序列集合、对所述第二指定序列集合进行处理得到的序列集合、根据第一序列集合和第二序列集合得到的序列集合至少之一时,The apparatus according to claim 28, wherein said processor determines said third sequence from said first sequence and said second sequence, or determines said third sequence from said third sequence set, and said third sequence The set includes a second specified sequence set, a sequence set obtained by processing the second specified sequence set, and at least one of the sequence set obtained according to the first sequence set and the second sequence set,
    所述第二指定序列集合包括以下至少之一:The second specified sequence set includes at least one of the following:
    哈达玛序列集合;Hadamard sequence collection;
    沃尔什序列集合;Walsh sequence collection;
    离散傅里叶变换序列集合;a set of discrete Fourier transform sequences;
    包含指定数量或指定比例的0元素的序列的集合;a collection of sequences containing a specified number or a specified proportion of 0 elements;
    单位矩阵序列集合。A collection of unit matrix sequences.
  31. 根据权利要求28所述的设备,其中,所述处理器还配置为:The device of claim 28, wherein the processor is further configured to:
    使用所述第三序列对第一数据进行扩展处理生成第二数据;或,And expanding, by using the third sequence, the first data to generate second data; or
    使用所述第三序列对第一数据进行映射处理生成第二数据;或,Performing mapping processing on the first data by using the third sequence to generate second data; or
    使用所述第三序列对第一数据进行调制处理生成第二数据。The first data is modulated using the third sequence to generate second data.
  32. 根据权利要求28所述的设备,其中,所述处理器还配置为将所述第二数据映射到指定的传输资源上,用于形成发射信号以及发送。The device of claim 28, wherein the processor is further configured to map the second data onto a designated transmission resource for forming a transmit signal and transmitting.
  33. 一种计算机存储介质,所述计算机存储介质中存储有计算机可执行指令,所述计算机可执行指令用于执行权利要求1至22任一项所述的数据生成方法。 A computer storage medium having stored therein computer executable instructions for performing the data generation method of any one of claims 1 to 22.
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* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
CN101232482A (en) * 2007-01-25 2008-07-30 华为技术有限公司 Method and apparatus for generating synchronizing sequence
CN105391545A (en) * 2015-11-27 2016-03-09 东南大学 Method of generating pseudo-random sequence in LTE system
CN105991159A (en) * 2015-02-13 2016-10-05 中兴通讯股份有限公司 Data transmission method and apparatus

Family Cites Families (2)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
CN105515713B (en) * 2014-09-25 2018-11-30 中兴通讯股份有限公司 A kind of multi-user's CDMA communication method and corresponding transmitter, receiver
CN106160787B (en) * 2015-04-02 2019-02-15 中兴通讯股份有限公司 A kind of data transmission method and device

Patent Citations (3)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
CN101232482A (en) * 2007-01-25 2008-07-30 华为技术有限公司 Method and apparatus for generating synchronizing sequence
CN105991159A (en) * 2015-02-13 2016-10-05 中兴通讯股份有限公司 Data transmission method and apparatus
CN105391545A (en) * 2015-11-27 2016-03-09 东南大学 Method of generating pseudo-random sequence in LTE system

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