WO2017157152A1 - Access processing method and apparatus - Google Patents
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- WO2017157152A1 WO2017157152A1 PCT/CN2017/074599 CN2017074599W WO2017157152A1 WO 2017157152 A1 WO2017157152 A1 WO 2017157152A1 CN 2017074599 W CN2017074599 W CN 2017074599W WO 2017157152 A1 WO2017157152 A1 WO 2017157152A1
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- subcarrier
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- 230000011664 signaling Effects 0.000 claims description 44
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- 230000004044 response Effects 0.000 claims description 11
- 239000000969 carrier Substances 0.000 claims description 7
- 238000012545 processing Methods 0.000 claims description 7
- 239000013256 coordination polymer Substances 0.000 claims 49
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- 238000010586 diagram Methods 0.000 description 39
- 238000004891 communication Methods 0.000 description 15
- 238000005516 engineering process Methods 0.000 description 8
- 101100121125 Drosophila melanogaster RasGAP1 gene Proteins 0.000 description 6
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- 238000005259 measurement Methods 0.000 description 5
- 230000008569 process Effects 0.000 description 5
- 238000013468 resource allocation Methods 0.000 description 5
- 230000008054 signal transmission Effects 0.000 description 5
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- 101100274486 Mus musculus Cited2 gene Proteins 0.000 description 2
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- H—ELECTRICITY
- H04—ELECTRIC COMMUNICATION TECHNIQUE
- H04W—WIRELESS COMMUNICATION NETWORKS
- H04W72/00—Local resource management
- H04W72/04—Wireless resource allocation
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- H—ELECTRICITY
- H04—ELECTRIC COMMUNICATION TECHNIQUE
- H04W—WIRELESS COMMUNICATION NETWORKS
- H04W74/00—Wireless channel access
- H04W74/08—Non-scheduled access, e.g. ALOHA
Definitions
- the present invention relates to the field of communications, and in particular to an access processing method and apparatus.
- MTC UE Machine Type Communication
- M2M Machine to Machine
- 3GPP 3rd Generation Partnership Project
- NB-IoT cellular-based narrowband Internet of Things
- NB-IoT narrowband Internet of Things
- the present invention provides an access processing method and apparatus to solve at least the problem that the related technologies cannot guarantee that all types of terminals successfully access the system.
- an access processing method including: selecting, by a terminal, a sequence corresponding to the terminal in a sequence set; the terminal generating a random access signal according to at least the corresponding sequence; Sending the random access signal to the base station.
- the sequence set includes a sequence of J sequences having a length of N, wherein the sequence of the index of j is expressed as J is a positive integer and N is a positive integer.
- the sequence set includes R sequence subsets, and the R sequence subsets are configured to different terminal sets; where R is a positive integer.
- the sequence corresponding to the terminal in the terminal selection sequence set includes: the terminal determining, from the R sequence subsets, a sequence subset corresponding to a terminal set to which the terminal belongs; the terminal determining One of the sequence sub-sets is selected as the corresponding sequence.
- the determining, by the terminal, the sequence sub-set corresponding to the terminal set to which the terminal belongs to the terminal includes: the terminal selecting the (Y+1)th of the R sequence sub-sets
- the R sequence subsets are respectively configured to R different terminal sets.
- the method includes at least one of: when the number of terminal sets is 2, 2 different terminal sets are a first terminal set and a second terminal set, the first terminal set and the second The terminal set satisfies at least one of the following conditions: the terminal included in the first terminal set is a terminal that supports simultaneous transmission of multiple subcarriers, and the terminal included in the second terminal set is a terminal that supports only single subcarrier transmission; The terminal included in the first terminal set is a terminal that transmits uplink data by using multiple subcarriers, and the terminal included in the second terminal set is a terminal that transmits uplink data by using a single subcarrier; a terminal that simultaneously transmits an Msg3 message, and the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier; the terminal included in the first terminal set is a Msg3 message bearer transmitted on multiple subcarriers.
- Terminal, and the terminal included in the second terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission;
- the set of terminals comprising a terminal support and a single sub-carrier transmission subcarrier spacing f sc1 terminal, the second set of terminals including a terminal support and a single sub-carrier transmission subcarrier spacing f sc2 terminal;
- the first The terminal included in the terminal set is a terminal that transmits uplink data by using a single subcarrier and has a subcarrier spacing of f sc1 ;
- the terminal included in the second terminal set is a terminal that transmits uplink data by using a single subcarrier and has a subcarrier spacing of f sc2 ;
- the terminal included in the first terminal set is a terminal that uses a single subcarrier to transmit an Msg3 message and has a subcarrier spacing of f sc1
- the second terminal set includes a terminal that uses a single subcar
- the terminal included in the first terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc1
- the terminal included in the second terminal set is a Msg3 message carried only in a single sub a terminal that transmits a carrier and has a subcarrier spacing of f sc2
- the terminal included in the first terminal set is that the amount of information carried in the Msg3 message is Si
- the terminal of the ze1 is a terminal that carries the amount of information in the Msg3 message is Size2, where Size1 is not equal to Size2; when the number of terminal sets is 3, three different terminal sets are a terminal set, a second terminal set, and a third terminal set, where the first terminal set, the second terminal set, and the third terminal set meet at least one of the following conditions: the first terminal set includes a terminal To support a terminal that transmits multiple subcarriers simultaneously
- the terminal includes a terminal that is included in the Msg3 message and whose amount of information is Size3, where Size1, Size2, and Size3 are different from each other. And when the number of terminal sets is 4, the four different terminal sets are a first terminal set, a second terminal set, a third terminal set, and a fourth terminal set, and the first terminal set, the second terminal.
- the set, the third terminal set, and the fourth terminal set meet at least one of the following conditions: the terminal included in the first terminal set is a terminal that supports simultaneous transmission of multiple subcarriers and a subcarrier spacing of f sc1 ,
- the second terminal set includes a terminal that supports simultaneous transmission of multiple subcarriers and a subcarrier spacing of f sc2 , and the terminal included in the third terminal set is a terminal that supports only a single subcarrier transmission and has a subcarrier spacing of f sc3 .
- the terminal included in the fourth terminal set is a terminal that supports only a single subcarrier transmission and the subcarrier spacing is f sc4 ; the terminal included in the first terminal set transmits uplink data by using multiple subcarriers and the subcarrier spacing is f sc1 terminal, the terminal comprises a second set of terminals using a plurality of sub-carriers to transmit the uplink data and the subcarrier spacing f sc2 terminal, the third terminal set Including using a single terminal is transmitting uplink data subcarriers and subcarrier spacing f sc3 terminal; said fourth set of terminals including a terminal for the use of a single subcarrier for transmitting uplink data and the subcarrier spacing f sc4 terminal; said The terminal included in the first terminal set is a terminal that uses multiple subcarriers to transmit Msg3 messages and the subcarrier spacing is f sc1 , and the second terminal set includes terminals that transmit Msg3 messages by using multiple subcarriers and the sub
- the terminal included in the third terminal set is a terminal that transmits an Msg3 message by using a single subcarrier and has a subcarrier spacing of f sc3
- the terminal included in the fourth terminal set transmits a Msg3 message by using a single subcarrier and the subcarrier spacing a terminal that is f sc4
- the terminal that is included in the first terminal set is a terminal that transmits Msg3 messages on multiple subcarriers and has a subcarrier spacing of f sc1
- the terminal included in the second terminal set is a Msg3 message bearer.
- the third terminal is a set of terminals included in the Msg3 message carries only a single sub- Wave transmission and the subcarrier spacing f sc3 terminal
- said fourth terminal is a terminal set includes a message Msg3 carrying only a single sub-carrier transmission and the subcarrier spacing f sc4 terminal; the first set of terminals including a terminal
- the terminal that is included in the Msg3 message is a terminal that is in the Msg3 message
- the terminal that is included in the Msg3 message is a terminal that is carried in the Msg3 message.
- the terminal having the information amount of Size3, the terminal included in the fourth terminal set is a terminal that carries the amount of information in the Msg3 message is Size4, where Size1, Size2, Size3, and Size4 are not equal to each other.
- the sequence of the J sequences having a length of N satisfies at least one of the following: the length of the J sequences is N
- the sequence is an orthogonal codeword sequence; the sequence in which the J sequences are all N is a quasi-orthogonal codeword sequence; and the sequence in which the J sequences are all N is a predefined sequence.
- N is one of the following: 2, 4, 6, and 8.
- the J sequence sequence length N includes at least one of the following: Among them, A is C is a constant,
- the terminal determines a subcarrier with an index of f n in the frequency domain, and occupies consecutive K symbols in the time domain.
- the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is
- the frequency domain expression of the K symbol and the signal transmitted on the subcarrier f n is Wherein, 0 ⁇ k ⁇ K-1; the terminal is at least according to the Determining the random access signal.
- the terminal is at least according to the Determining the random access signal includes:
- the corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol, For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset; and/or, when the current domain sampling interval is T s , Corresponding time domain
- the expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol, 0 ⁇ k ⁇ K-1, 0 ⁇ q ⁇ Q-1, Number of samples in the time domain; the terminal is sent on consecutive K symbols
- the time domain expression is Said terminal according to at least said Determining the random access signal.
- the group 0 to the group N-1 are the unit units constituting the random access signal
- the terminal sending the random access signal to the base station includes: the terminal determining that the unit is the random connection Transmitting a signal and repeating the random access signal H times for transmission; and/or, the terminal repeating the unit H times in the time domain to form the random access signal, and transmitting the random access signal.
- the terminal needs to introduce an interval of a time length of Gap.
- N gap Y / y.
- end start+y-1.
- the terminal After the terminal sends a random access signal of the unit, it is required to introduce an interval of a time length of Gap.
- the H-repetition index of the unit is defined as Unit 0 to Unit H-1 .
- a total of y units of random access signals are sent, and the length of time required to be introduced is The interval of Gap; where 0 ⁇ start ⁇ end ⁇ Y-1, y ⁇ Y.
- N gap Y / y.
- end start+y-1.
- the unit of measurement; y ⁇ L_U + Gap T ⁇ TimeUnit, where L_G is the length of time of the Unit, Gap ⁇ 0, T is a positive integer and T is the minimum value that satisfies T ⁇ TimeUnit > y ⁇ L_U, TimeUnit is A measure of the length of time.
- the time domain length of P n is 266.7us.
- the time domain length of Gap is 0.6ms.
- the time domain length of Gap is 0.2ms or 1.2ms.
- the value of the H is determined according to at least a level of the terminal.
- the level of the terminal includes at least one of: a coverage enhancement level; a physical channel repetition transmission level; and a repeated transmission level of a message or signaling carried on the physical channel.
- the sending, by the terminal, the random access signal to the base station includes: determining, by the terminal, a random access channel for sending the random access signal; and using, by using the random access channel, the terminal The base station transmits the random access signal.
- the random access channel resource includes one or more time-frequency resource sets Set m , wherein the Set m includes F sub-carriers or sub-channels in the frequency domain, and has a length of at least P units in the time domain.
- the length, m is the index of the Set m in the time domain, F is a positive integer, and P is a positive integer.
- the Set m includes P subset subsets, wherein the subset is configured with the same subcarriers in the frequency domain as the Set m , and the subset has a length of 1 Unit in the time domain.
- a 7.5 kHz protection bandwidth is configured on each of the frequency resources of the frequency resource occupied by the Set m ; and/or when the subcarrier spacing is 3.75 kHz.
- the spacing between two adjacent time-domain Set m V of first time units comprises at least one of: when one or more frames of field length Time domain length of one or more subframes, Z 1 second, Z 2 milliseconds, time domain length of Z 3 Set m , time domain length of Z 4 Units, where Z 1 , Z 2 , Z 3 , Z 4 are positive integers.
- V first time units are separated between two sets of m adjacent to each other in the time domain, where V is an integer, and the first time unit includes a time domain length of Z 5 subsets, where Z 5 is A positive integer.
- the configuration period of Set m is L first time units, where L is a positive integer, and the first time unit includes at least one of: a time domain length of one or more frames, one or more sub- The time domain length of the frame, Z 1 second, Z 2 milliseconds, the time domain length of Z 3 Set m , the time domain length of Z 4 Units, where Z 1 , Z 2 , Z 3 , Z 4 are positive integers .
- Set m arranged a first period of L time units, where, L is a positive integer, said first unit of time length field comprises a subset of Z 5, Z 5 being a positive integer.
- L 2 z , where z is an integer greater than or equal to zero.
- the method includes at least one of: the 2 z first time units are continuously distributed or discretely distributed in the time domain; and the z values are ⁇ 0, 1, 2, 3, 4, 5, 6 , 7 ⁇ ; two Set m adjacent in the time domain occupy the same F subcarriers or subchannels in the frequency domain.
- At least one of the subsets is configured in a configuration period of the Set m , and an index of the subset is a subset0 to a subset (L 1 -1), wherein a subset configuration corresponding to a terminal with a level index g
- the solution includes: the terminal with the level index g is configured to repeat the Repetition g times in the time domain, and configure a continuous Repetition g subset for the terminal with the level index g in a configuration period of the Set m , and
- the starting subset index StartingSubsetIndex g is calculated according to the following formula: Where 0 ⁇ g ⁇ G-1, and G is the number of levels of the divided terminals.
- the configuration of the subset corresponding to the terminal with the level index g is the same between the configuration periods of different Set m .
- At least one of the subsets is configured in a configuration period of the Set m , and an index of the subset is a subset0 to a subset (L 1 -1), wherein a subset configuration corresponding to a terminal with a level index g
- the solution includes: the terminal with the level index g sends the unit repeating Repetition g times in the time domain, and configures the terminal with the level index g to consecutive consecutive ChanceNum g ⁇ Repetition g subsets, where ChanceNum g ⁇ 1.
- the starting subset index StartingSubsetIndex g in the ChanceNum g ⁇ Repetition g subsets is calculated according to the following formula: Where 0 ⁇ g ⁇ G-1, and G is the number of levels of the divided terminals.
- the starting index of the subset of first transmission resource ChanceNum g in the c-th first transmission resources Calculate according to the following formula:
- At least one of the subsets is configured in a configuration period of the Set m , and an index of the subset is a subset0 to a subset (L 1 -1), wherein a subset configuration corresponding to a terminal with a level index g
- the solution includes: the terminal with the level index g sends the unit to repeat the Repetition g times in the time domain, and the terminal with the level index g is configured with ChanceNum g ⁇ Repetition g subsets, and ChanceNum g ⁇ 1.
- the configuration within a period of Set m is a subset of the indices 0 to subset (ChanceNum g ⁇ Repetition g -1 ), and start from 0 subset index contiguous Repetition g subsets is a first sending resource, wherein the first sending resource is used by the unit to repeat Repetition g times in the time domain, and one Repetition g subset in the first sending resource is in the time domain.
- the packets are consecutively distributed, and different subsets corresponding to the first sending resource are discretely distributed in the time domain.
- the first sending resource corresponding to the terminal of the G level is included in the configuration period of the Set m , where the first sending resource corresponding to the terminal with the level index g is used in the time domain of the unit.
- the first sending resource corresponding to the terminal with the level index g is N g Set m corresponding to the terminal whose index is g, 0 ⁇ g ⁇ G-1.
- the terminal sequentially allocates N g according to the rank index g from small to large. Resources.
- N g configured for the terminal with the level index g Two adjacent in the resource
- the time domain interval is L g second time units, where L g ⁇ 0.
- terminals of different levels of indexing have the same L g .
- the interval L ⁇ is a second time unit, where L ⁇ ⁇ 0.
- the interval L g is a second time unit.
- N g corresponding to the terminal with the level index g The first in the resource Time domain starting resource location with the stated The time domain starting resource location is the same in the configuration period; or the N g corresponding to the terminal with the level index g The first in the resource Time domain starting resource location with the stated There is an offset in the time domain starting resource location within the configuration period, wherein the offset is predetermined or configured for the base station.
- the terminals of different levels of index correspond to the same.
- the configuration of the cycle length D Set m is the length of the time domain Set m, wherein, D is a positive integer.
- D 2 x , x is an integer greater than or equal to zero.
- a maximum of D*P of the subsets are configured in a configuration period of the set m , and an index of the subset is a subset0 to a subset (D*P-1), where a terminal with a level index of g corresponds to
- the subset configuration scheme includes: the terminal with the level index g sends the unit to repeat the Repetition g times in the time domain, and configures a continuous Repetition g subset for the terminal with the level index g in a configuration period of the Set m .
- the starting subset index StartingSubsetIndex g is calculated according to the following formula: Where 0 ⁇ g ⁇ G-1, and G is the number of levels of the divided terminals.
- the subset configuration scheme corresponding to the terminal with the level index g is the same.
- the subcarrier index is 0 to 47, where the index is 0, 1, 14, 15, 16, 17, 30, 31,
- the subcarriers of 32, 33, 46, 47 are not allocated to the Set m .
- the Set m is the subcarrier configuration with an index of 2 to 25.
- the proportion of the number of subcarriers Num occupied by the random access channel in the F subcarriers is Ratio in the F subcarriers in the Set m , where the Ratio is sent by the base station The order is sent to the terminal.
- the value of F is ⁇ 12, 24, 36, 48 ⁇ .
- the value of the Ratio is ⁇ 1/6, 2/6, 3/6, 4/6, 5/6, 6/6 ⁇ or ⁇ 1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12, 9/12, 10/12, 11/12, 12/12 ⁇ or ⁇ 0/12, 1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12, 9/12, 10/12, 11/12, 12/12 ⁇ or ⁇ 0/6, 1/6, 2/6, 3/6, 4/6, 5/6, 6/6 ⁇ .
- the number of subcarriers occupied by the random access channel for transmitting the random access signal is Num.
- the value of F is ⁇ 12, 24, 36, 48 ⁇ .
- the Num value is ⁇ 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48 ⁇ or ⁇ 3, 6, 9, 12, 15, 18, 21 , 24,27,30,33,36,39,42,45,48 ⁇ or ⁇ 0,4,8,12,16,20,24,28,32,36,40,44,48 ⁇ or ⁇ 0 , 3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48 ⁇ .
- the random access channel that the terminal sends the random access signal to the base station is allocated by the base station to the terminal by using signaling.
- the signaling includes at least one of the following: an initial level index; frequency domain location information of the random access channel allocated by the base station to the terminal; The time domain location information of the random access channel of the terminal.
- the frequency domain location information of the random access channel allocated by the base station to the terminal includes: a subcarrier or a subchannel index where the group 0 of the unit that constitutes the random access signal is sent. .
- the 6bits indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal.
- said information further indicating 6bits F subcarriers in the Set m in a randomly selected sub-carrier frequency domain position as said random access channel is used to indicate the location of the terminal.
- the indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal.
- said Indication information indicating that the terminal is further configured to F subcarriers in the Set m in a randomly selected sub-carriers of the frequency domain position of the terminal as a random access channel is located.
- the indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal, where the Num is the number of subcarriers occupied by the random access channel.
- the time domain location information of the random access channel allocated by the base station to the terminal includes: configuration period indication information n of the second Set m , where the base station allocates to the terminal
- the Set m where the random access channel is located is defined as the second Set m ; the second Set m is selected from the first Set m ; and the configuration period length of the second Set m is the configuration period of the first Set m n times, n is a positive integer; the first Set m is one or more time-frequency resource sets Set m , n of the random access channel resource, and n is a positive integer.
- At least one of the following is included: when the value of n is described by 3 bits, the value of n is ⁇ 1, 2, 3, 4, 5, 6, 7, 8 ⁇ or ⁇ 1, 2, 4, 8,16,32,64,128 ⁇ or ⁇ 1,2,4,8,10,12,14,16 ⁇ ; when the value of n is described by 2 bits, the value of n is ⁇ 1, 2, 3 , 4 ⁇ or ⁇ 1, 2, 4, 8 ⁇ or ⁇ 1, 4, 6, 8 ⁇ .
- the base station allocates to the time domain position of the random access channel, where the terminal is: a first configuration in a first Set m periods of the second Set m.
- the base station allocates to the time domain information of the random access channel position where said terminal further comprises: a second location information Offset Set m disposed within said second period of Set m; wherein said n first Offset Set m for the configuration of the second period indication Set m, the index information allocated to the random access channel, where the first terminal of the Set m.
- the time domain location information of the random access channel allocated by the base station to the terminal includes: two consecutive second set m time domain interval information Interval; the base station allocates to the terminal m is defined above the Set random access channel where the Set second m; the second from the first to select the Set m m in the Set and the Set successive intervals of first m interval between two second m the Set;
- the first set m is shown as one or more time-frequency resource sets Set m included in the random access channel resource.
- the signaling further includes: triggering positioning operation indication information.
- the terminal when the trigger positioning operation indication information is a trigger positioning operation, the terminal sends the random access signal on the random access channel allocated by the signaling.
- the method further includes: receiving, by the terminal, the random connection sent by the base station after detecting the random access signal according to the detection result. And a response message, where the random access response message includes at least one of the following information: subcarrier spacing indication information; configured subcarrier number indication information.
- the subcarrier spacing indication information and the configured subcarrier number indication information are indicated by a joint coding manner.
- an access processing apparatus being applied to a terminal, including: selecting And the generating module is configured to select a sequence corresponding to the terminal in the sequence set; the generating module is configured to generate a random access signal according to at least the corresponding sequence; and the sending module is configured to send the random access signal to the base station.
- the terminal when the terminal generates a random access signal for accessing the base station, it selects a sequence corresponding to the terminal itself to generate, so that the random access signal is a characteristic (eg, type) of the terminal to be accessed. It is matched to ensure that different types of terminals can successfully access the system, thereby solving the problem that the related technologies cannot guarantee that various types of terminals can successfully access the system, thereby realizing various types of terminals. The ability to successfully access the system.
- a characteristic eg, type
- FIG. 1 is a flowchart of an access processing method according to an embodiment of the present invention.
- FIG. 2 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 1 of the present invention
- FIG. 3 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 1 of the present invention
- FIG. 4 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 2 of the present invention.
- FIG. 5 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 2 of the present invention.
- FIG. 6 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 3 of the present invention.
- FIG. 7 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 3 of the present invention.
- FIG. 8 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 4 of the present invention.
- FIG. 9 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 4 of the present invention.
- Figure 10 is a diagram showing a bitmap indication of Set m according to a fourth embodiment of the present invention.
- FIG. 11 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 5 of the present invention.
- Figure 12 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to a fifth embodiment of the present invention.
- FIG. 13 is a schematic diagram showing the interval between two sets of adjacent time-frequency resources, Set m and Set m+1 , according to Embodiment 5 of the present invention.
- FIG. 14 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 6 of the present invention.
- FIG. 16 is a schematic diagram of a configuration period of a time-frequency resource set Set m according to Embodiment 6 of the present invention.
- FIG. 17 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 7 of the present invention.
- Figure 18 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to a seventh embodiment of the present invention.
- FIG. 20 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 8 of the present invention.
- FIG. 21 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 8 of the present invention.
- FIG. 22 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 9 of the present invention.
- FIG. 23 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 9 of the present invention.
- 24 is a schematic diagram of allocation of consecutive Repetition g subsets for a terminal with a level index of g according to a specific embodiment 9 of the present invention.
- 25 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to a tenth embodiment of the present invention.
- 26 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 10 of the present invention.
- FIG. 27 is a schematic diagram of allocation of consecutive Repetition g subsets for a terminal with a level index of g according to a tenth embodiment of the present invention.
- FIG. 29 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 11 of the present invention.
- FIG. 30 is a schematic diagram of resource allocation for transmitting a random access signal by a terminal with a level index of g according to Embodiment 11 of the present invention.
- FIG. 31 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 12 of the present invention.
- Figure 32 is a structural diagram of a GT 2 according to a specific embodiment 13 of the present invention.
- FIG. 33 is a schematic diagram of a 64-time repeated transmission structure of a basic unit of a Preamble according to Embodiment 13 of the present invention.
- Figure 34 is a structural diagram of a GT 2 according to a specific embodiment 14 of the present invention.
- 35 is a schematic diagram of a 64-time repeated transmission structure of a basic unit of a Preamble according to Embodiment 14 of the present invention.
- FIG. 36 is a structural diagram of a Subcarrior sent by a terminal selection group according to Embodiment 15 of the present invention.
- FIG. 37 is a structural diagram of a Subcarrior transmitted by a terminal selection group according to a specific embodiment 16 of the present invention.
- FIG. 38 is a block diagram showing the structure of an access processing apparatus according to an embodiment of the present invention.
- FIG. 1 is a flowchart of an access processing method according to an embodiment of the present invention. As shown in FIG. 1, the process includes the following steps:
- Step S102 the terminal selects a sequence corresponding to the terminal in the sequence set
- Step S104 The terminal generates a random access signal according to at least a corresponding sequence.
- Step S106 the terminal sends the random access signal to the base station.
- the sequence corresponding to the terminal may be a sequence corresponding to the type of the terminal. Because the terminal has multiple types, the terminal may select a random connection according to its own type feature when performing random access. a sequence of incoming signals. Therefore, before performing random access, the terminal may select a sequence corresponding to itself from a sequence set consisting of multiple sequences, and generate a corresponding random access signal, and access the system accordingly.
- the above-mentioned base station solves the problem that the related technologies cannot ensure that all types of terminals successfully access the system, thereby achieving the effect that various types of terminals can successfully access the system.
- the sequence set includes a sequence of J sequences having a length of N, wherein the sequence of the index of j is expressed as J is a positive integer and N is a positive integer.
- the sequence set includes R sequence subsets, that is, R sequence subsets in which J sequences included in the sequence set are divided, and R sequence subsets can be configured. Give a different set of terminals, where R is a positive integer.
- the terminal may adopt the following selection manner: the terminal determines a sequence subset corresponding to the terminal set to which the terminal belongs by the terminal from the R sequence subsets; A sequence is selected in the sequence sub-set as the corresponding sequence.
- the terminal selects the one sequence in the sequence subset as the corresponding sequence; when there are multiple sequences in the sequence subset determined by the terminal, The terminal randomly selects a sequence from the determined sequence subset as a corresponding sequence; wherein R is a positive integer.
- the foregoing sequence set may be divided into R sequence sub-sets. Therefore, when selecting a sequence corresponding to the terminal, the terminal may first select a sequence sub-set that is configured for the terminal set to which the terminal belongs, and then A corresponding sequence is selected from the selected subset of sequences.
- the determining, by the terminal, the sequence subset corresponding to the terminal set to which the terminal belongs from the R sequence subsets includes: the terminal selecting the (Y+1)th sequence from the R sequence subsets
- the base station may configure a subsequence for the terminal set to which the terminal belongs, in combination with the Mod (Cell ID, R) described above as a remnant algorithm, that is, Y is a remainder obtained by dividing the Cell ID by R.
- the R sequence subsets may be respectively configured to R different terminal sets, that is, the sequence subset and the terminal set are in one-to-one correspondence.
- a sequence of sub-sets and terminal sets may also be a many-to-one or one-to-many relationship.
- the terminal set may be divided into multiple modes. The following describes different terminal set division modes:
- the two different terminal sets are the first terminal set and the second terminal set, and the first terminal set and the second terminal set satisfy at least one of the following conditions: the terminal included in the first terminal set A terminal that supports simultaneous transmission of multiple subcarriers, and the terminal included in the second terminal set is a terminal that supports only one subcarrier transmission; the terminal included in the first terminal set is a terminal that uses multiple subcarriers to transmit uplink data, and the second terminal The terminal included in the set is a terminal that transmits uplink data by using a single subcarrier; the terminal included in the first terminal set is a terminal that simultaneously transmits an Msg3 message by using multiple subcarriers, and the terminal included in the second terminal set transmits the Msg3 message by using a single subcarrier.
- the terminal included in the first terminal set is a terminal that transmits the Msg3 message on the multiple subcarriers, and the terminal included in the second terminal set is that the Msg3 message is only carried in the terminal of the single subcarrier transmission;
- the first terminal set includes a terminal support and a single sub-carrier transmission subcarrier spacing f sc1 terminal, the second terminal sets Comprising a terminal support and a single sub-carrier transmission subcarrier spacing f sc2 terminal; a first set of terminals including a terminal for the use of a single subcarrier for transmitting uplink data and the subcarrier spacing f sc1 terminal; a second set of terminals included
- the terminal is a terminal that uses a single subcarrier to transmit uplink data and has a subcarrier spacing of f sc2 ;
- the terminal included in the first terminal set is a terminal that transmits an Msg3 message by using a single subcarrier and has a subcarrier spacing of f
- the terminal included in the first terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc1 , and the second terminal is set.
- the terminal included is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc2 ;
- the terminal included in the first terminal set is a terminal in which the amount of information carried in the Msg3 message is Size1, and the second terminal set includes
- the terminal is a terminal that carries the amount of information in the Msg3 message is Size2, where Size1 is not equal to Size2;
- the three different terminal sets are the first terminal set, the second terminal set, and the third terminal set, and the first terminal set, the second terminal set, and the third terminal set satisfy at least the following conditions:
- the first terminal set includes terminals that support simultaneous transmission of multiple subcarriers
- the second terminal set includes terminals that support only a single subcarrier transmission and the subcarrier spacing is f sc1
- the third terminal set includes terminals.
- the terminal included in the first terminal set is a terminal that transmits uplink data by using multiple subcarriers
- the terminal included in the second terminal set transmits uplink data by using a single subcarrier.
- the terminal with the subcarrier spacing is f sc1 ;
- the terminal included in the third terminal set is a terminal that uses one subcarrier to transmit uplink data and the subcarrier spacing is f sc2 ;
- the terminal included in the first terminal set is to transmit the Msg3 message by using multiple subcarriers.
- the second terminal set includes terminals for transmitting Msg3 messages by using a single subcarrier and the subcarrier spacing is f
- the terminal of the sc1 , the terminal included in the third terminal set is a terminal that transmits the Msg3 message by using a single subcarrier and the subcarrier spacing is f sc2 ;
- the terminal included in the first terminal set is a terminal that the Msg3 message carries on the multiple subcarriers
- the terminal included in the second terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc1
- the terminal included in the third terminal set is that the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc2.
- the terminal included in the first terminal set is a terminal that has the information amount of the S1 in the Msg3 message
- the terminal in the second terminal set is a terminal that has the information amount of the S2 in the Msg3 message
- the third terminal set includes The terminal is a terminal that carries information in the Msg3 message with a size of Size3, where Size1, Size2, and Size3 are not equal to each other;
- the four different terminal sets are a first terminal set, a second terminal set, a third terminal set, and a fourth terminal set, and the first terminal set, the second terminal set, and the third terminal set.
- the fourth terminal set satisfies at least one of the following conditions: the terminal included in the first terminal set is a terminal that supports simultaneous transmission of multiple subcarriers and the subcarrier spacing is f sc1 , and the terminal included in the second terminal set supports simultaneous transmission of multiple subcarriers.
- the terminal with the subcarrier spacing is f sc2
- the terminal included in the third terminal set is a terminal that supports only a single subcarrier transmission and the subcarrier spacing is f sc3
- the terminal included in the fourth terminal set supports only a single subcarrier transmission and the sub
- the terminal with the carrier spacing is f sc4
- the terminal included in the first terminal set is a terminal that uses multiple subcarriers to transmit uplink data and the subcarrier spacing is f sc1
- the second terminal set includes terminals that use multiple subcarriers to transmit uplink data and carrier spacing for f sc2 set includes a terminal, a third terminal is a terminal using a single subcarrier, and the subcarrier for transmitting uplink data between F sc3 terminal; and a fourth set of terminals including a terminal for the use of a single subcarrier for transmitting uplink data and the subcarrier spacing f sc4 terminal; a first set of terminals including a terminal using
- the terminal includes a terminal that is a terminal that has a quantity of information carried in the Msg3 message, and a terminal that is included in the fourth terminal set is a terminal that has an information amount of Size4 in the Msg3 message, where Size1, Size2, Size3 Size4 is not equal to each other. It should be noted that the foregoing several terminal set division manners are only a few examples, and other reasonable division manners may also be used to divide the terminal set.
- the values of f sc1 and f sc2 are different.
- f sc1 can take a value of 15 kHz
- f sc2 can take a value of 3.75 kHz
- the above f sc3 and f sc4 have different values, for example, f sc3 can be The value is 15 kHz, and f sc4 can be 3.75 kHz.
- the types of the J sequences in the sequence set may be multiple.
- the sequence of the J sequences whose lengths are all N meets the following At least one of the J sequences having a length of N is an orthogonal codeword sequence; the sequence of J sequences having a length of N is a quasi-orthogonal codeword sequence; and the sequence of J sequences having a length of N is predefined.
- the predefined sequence includes an all-one sequence of length N, or a sequence of all As of length N, which may be a positive integer.
- the above Satisfy at least one of the following: J of different values corresponding to Code j Mutual orthogonal code words, or quasi-orthogonal code words; mutually different values of j corresponding to Code j Mutual orthogonal code words, or quasi-orthogonal code words; mutually different values of j corresponding to Code j They are orthogonal code words, or mutually quasi-orthogonal code words, where 0 ⁇ i ⁇ N / 2-1.
- the value of N may be one of the following: 2, 4, 6, and 8.
- the J sequence sequence length N includes at least one of the following:
- the sequence of strip length N includes at least one of the following: Wherein one of Code 0 and Code 1 is configured to the terminal in the first terminal set, and the other is configured to the terminal in the second terminal set;
- sequence of J sequences of length N includes at least one of the following: Any three of them; Any three of them; wherein three sequences of sequence length N are respectively allocated to terminals in three terminal sets, that is, three sequences of sequence length N and three terminal sets can be configured in any one-to-one combination ;
- the sequence of J sequence lengths of N includes at least one of the following:
- the four sequences of length N are respectively allocated to the terminals in the four terminal sets, that is, four sequences of sequence length N and four terminal sets can be configured in any one-to-one combination;
- C is a constant,
- the terminal determines the subcarrier with the index f n in the frequency domain, and occupies consecutive K symbol transmissions in the time domain.
- the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is
- the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is Where 0 ⁇ k ⁇ K-1; the above terminal is based at least Determine the random access signal.
- the foregoing terminal is based at least according to Determining the random access signal includes:
- the corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol, For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset; and/or, when the current domain sampling interval is T s , Corresponding time domain
- the expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol, 0 ⁇ k ⁇ K-1, 0 ⁇ q ⁇ Q-1, Number of samples in the time domain; the terminal is sent on consecutive K symbols
- the time domain expression is The terminal is based at least on the above Determine the random access signal.
- the expression of the random access signal transmitted on -1 is ⁇ Group 0 , Group 1 , ... Group N-1 ⁇ ; wherein Group n with different values of n occupy different symbols in the time domain.
- the group 0 to the group N-1 are the unit units constituting the random access signal
- the terminal sending the random access signal to the base station includes: the terminal determines that a unit is a random access signal, and The random access signal is repeated H times for transmission; and/or, the terminal repeats the unit H times in the time domain to form a random access signal, and transmits the random access signal.
- the interval of the time length Gap needs to be introduced, where the terminal is no longer in the interval of the Gap interval.
- the random access signal after the group n is sent, and the terminal continues to send the random access signal after the group n after the interval of the time length Gap.
- the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz
- N gap Y / y.
- end start + y-1.
- the unit of measurement of the length of time; y ⁇ L_G + Gap T ⁇ TimeUnit, where L_G is the length of the Group, Gap ⁇ 0, T is a positive integer and T is the minimum value of T ⁇ TimeUnit > y ⁇ L_G, TimeUnit is a The unit of measure of the length of time.
- the TimeUnit may be seconds, milliseconds, microseconds, nanoseconds, frames, subframes, slots.
- the terminal after the terminal sends a random access signal of a unit, the terminal needs to be introduced.
- the time interval is the gap of the gap, wherein the terminal does not send the random access signal after the unit in the interval where the time is Gap, and the terminal continues to send the random access signal after the unit after the interval of the time length of Gap.
- the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz
- the bandwidth is 3.75 k
- the index of the H repetitions of the above unit is defined as Unit 0 to Unit H-1 , and the terminal completes the unit start to the unit end by a total of y units (the index numbers of the y units may be consecutive)
- the interval of the time length Gap needs to be introduced, wherein the terminal does not send the random access signal during the time interval of the gap, and the terminal continues to send after the interval of the time length of Gap. Random access signal after unit end ; where 0 ⁇ start ⁇ end ⁇ Y-1, y ⁇ Y.
- N gap Y / y.
- end start + y-1.
- the unit of measurement of the length of time; y ⁇ L_U + Gap T ⁇ TimeUnit, where L_G is the length of time of Unit, Gap ⁇ 0, T is a positive integer and T is the minimum value of T ⁇ TimeUnit > y ⁇ L_U, TimeUnit is A measure of the length of time.
- the TimeUnit may be seconds, milliseconds, microseconds, nanoseconds, frames, subframes, slots.
- the time domain length of CP n is 8192*Ts
- the subcarrier spacing or subcarrier bandwidth for transmitting the random access signal is 3.75 kHz.
- the subcarrier spacing or subcarrier bandwidth of the signal is 3.75 kHz
- the time domain length of CP n is 8192*Ts.
- the time domain of Gap is long.
- the value of the above H is determined according to at least the level of the terminal, that is, the H corresponding to the terminals of different levels may be different.
- the level of the foregoing terminal may include at least one of the following: an coverage enhancement level; a physical channel repetition transmission level; and a repeated transmission level of a message or signaling carried on the physical channel.
- the sending, by the terminal, the random access signal to the base station includes: determining, by the terminal, a random access channel for transmitting the random access signal; and transmitting, by the terminal, the random access signal to the base station by using a random access channel.
- the random access channel used by the terminal to perform random access signal transmission may be part of a random access channel resource, and the random access channel resource may include multiple random accesses for different terminals. A random access channel for signal transmission.
- the random access channel resource includes one or more time-frequency resource sets Set m , where the set m includes F sub-carriers or sub-channels in the frequency domain, and the length is at least in the time domain.
- m is the index of Set m in the time domain
- F is a positive integer
- P is a positive integer.
- the random access channel resource may include a random access channel in which multiple terminals send random access signals, and the foregoing set m may be used by one terminal or may be used by multiple terminals. Or multiple Set m are used by one terminal.
- the Set m includes P subset subsets, wherein the subset is configured with the same subcarriers in the frequency domain as the Set m , and the subset has a length of 1 Unit in the time domain.
- the protection bandwidth is configured before and after the frequency resource occupied by the Set m , and/or the protection bandwidth is configured on the upper and lower sides of the frequency resource occupied by the Set m .
- a first time interval of a V-domain unit time between two adjacent Set m wherein, V is an integer
- the first unit of time comprises at least one of the following: one or more The time domain length of the frame, the time domain length of one or more subframes, Z 1 second, Z 2 milliseconds, the time domain length of Z 3 Set m , the time domain length of Z 4 Units, and the time domain of Z 5 subsets
- the configuration period of the Set m is L first time units, where L is a positive integer, and the first time unit includes at least one of: a time domain length of one or more frames Time domain length of one or more subframes, Z 1 second, Z 2 milliseconds, time domain length of Z 3 Set m , time domain length of Z 4 Units, time domain length of Z 5 subsets, where Z 1 , Z 2 , Z 3 , Z 4 , and Z 5 are all positive integers.
- L 2 z , where z is an integer greater than or equal to zero.
- 2 z first time units are continuously distributed or discretely distributed in the time domain; z is taken as ⁇ 0, 1, 2, 3, 4, 5, 6, 7 ⁇ ; time domain adjacent Two Set m occupy the same F subcarriers or subchannels in the frequency domain.
- the subset configuration scheme includes: the terminal with the level index g transmits the Repetition g times in the time domain, and configures consecutive Repetition g subsets for the terminal with the level index g in the configuration period of a Set m , and starts
- the subset index StartingSubsetIndex g is calculated according to the following formula: Where 0 ⁇ g ⁇ G-1, and G is the number of levels of the divided terminals.
- G may also be the number of levels of terminals that need to configure resources in Set m .
- the above G may each be 1.
- the configuration of the subset corresponding to the terminal with the level index g is the same between the configuration periods of different Set m .
- At most L 1 subsets are configured in the configuration period of the Set m , and the index of the subset is subset 0 to subset (L 1 -1), wherein the subset corresponding to the terminal with the level index g is
- the configuration scheme includes: the terminal with the level index g sends the Unit repeating Repetition g times in the time domain, and configures the consecutive ChanceNum g ⁇ Repetition g subsets for the terminal with the level index g, where ChanceNum g ⁇ 1.
- the starting subset index StartingSubsetIndex g in ChanceNum g ⁇ Repetition g subsets can be calculated according to the following formula: Where 0 ⁇ g ⁇ G-1, and G is the number of levels of the divided terminals.
- the foregoing G may be the number of levels of terminals configured by the base station, or may be the number of levels of terminals that send random access signals on the Set m resource.
- G may also be the number of levels of terminals that need to configure resources in Set m .
- the above G may each be 1.
- the starting subset index is ChanceNum g ⁇ Repetition g subsets of StartingSubsetIndex g , and is configured with ChanceNum g first sending resources, where the first sending resource is used for Unit in the time domain.
- Repeat Repetition g times that is, Unit repeats Repetition g times in the time domain and can be executed on the first resource.
- the above-described ChanceNum g of first transmission resources in the c-th starting index of the first subset of transmission resources It can be calculated according to the following formula:
- At most L 1 subsets are configured in the configuration period of the Set m , and the index of the subset is subset 0 to subset (L 1 -1), wherein the terminal with the level index g corresponds to
- the subset configuration scheme includes: the terminal with the level index g sends the Unit repeating Repetition g times in the time domain, and the terminal with the level index g is configured with ChanceNum g ⁇ Repetition g subsets, and ChanceNum g ⁇ 1.
- ChanceNum g ⁇ Repetition g subset is a subset of the indices 0 to subset (ChanceNum g ⁇ Repetition g -1 ), and starts from the subset 0, continuous index
- the Repetition g subset is a first transmission resource, wherein the first transmission resource is used for the Unit to repeat the Repetition g transmission in the time domain, and the Repetition g subsets in the first transmission resource are continuously distributed in the time domain.
- the subsets corresponding to different first transmission resources are discretely distributed in the time domain.
- the first sending resource corresponding to the terminals of the G levels is included in the configuration period of the Set m , wherein the first sending resource corresponding to the terminal with the level index g is used for the Unit in the time domain.
- the first sending resource corresponding to the terminal with the level index g is N g Set m corresponding to the terminal whose index is g, 0 ⁇ g ⁇ G-1.
- the terminal sequentially allocates N g according to the rank index g from small to large. Resources.
- N g configured for the terminal with the level index g in the configuration period of Set m Two adjacent in the resource
- the time domain interval is L g second time units, where L g ⁇ 0.
- the N g corresponding to the terminals of different levels of indexing Between resources the interval L ⁇ is a second time unit, where L ⁇ ⁇ 0.
- N g of terminals corresponding to different levels of indexing The interval between resources L ⁇ second time units refers to the corresponding level of a terminal
- the resource corresponds to another level of terminal
- the interval between resources is L ⁇ second time units.
- the interval L g is a second time unit.
- the first time unit and the second time unit may be the same or different.
- the N g corresponding to the terminal whose rank index is g The first in the resource Time domain starting resource location with the stated The time domain starting resource location is the same in the configuration period; or the N g corresponding to the terminal with the level index g The first in the resource Time domain starting resource location with the stated There is an offset in the time domain starting resource location within the configuration period, wherein the offset is predetermined or configured for the base station.
- terminals of different levels of index correspond to the same.
- the length of the time domain In an alternative embodiment, the length of the arrangement period of the D Set m Set m, wherein, D is a positive integer.
- D 2 x and x is an integer greater than or equal to zero.
- a maximum of D*P subsets are configured in the configuration period of the Set m , and an index of the subset is a subset 0 to a subset (D*P-1), where the terminal with a level index of g corresponds to
- the subset configuration scheme includes: the terminal with the level index g is configured to repeat the Repetition g times in the time domain, and configure a continuous Repetition g subset for the terminal with the level index g in a configuration period of the set m , and
- the starting subset index StartingSubsetIndex g is calculated according to the following formula:
- G is the number of levels of the divided terminals.
- the configuration of the subset corresponding to the terminal with the level index g is the same between the configuration periods of different Set m .
- the subcarrier index is 0 to 47, where the index is 0, 1, 14, 15, 16, 17,
- the subcarriers of 30, 31, 32, 33, 46, 47 are not configured for Set m .
- the subcarriers are configured for the Set m .
- the meaning of "to” means “to”.
- the subcarriers with an index of 2 to 25 are 24 subcarriers whose indices are from 2 to 25. The following embodiments are similar and will not be described again.
- the subcarriers are configured for the Set m .
- the carrier is configured to the Set m .
- the ratio of the number of subcarriers Num occupied by the random access channel in the F subcarriers is Ratio, wherein the Ratio is sent by the base station to the signaling.
- the value of F above is ⁇ 12, 24, 36, 48 ⁇ .
- the value of the Ratio is ⁇ 1/6, 2/6, 3/6, 4/6, 5/6, 6/6 ⁇ or ⁇ 1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12, 9/12, 10/12, 11/12, 12/12 ⁇ or ⁇ 0/12, 1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12, 9/12, 10/12, 11/12, 12/12 ⁇ or ⁇ 0/6, 1/6, 2/6, 3/6, 4/6, 5/6, 6/6 ⁇ .
- the number of subcarriers occupied by the random access channel for transmitting the random access signal is Num.
- the value of F above is ⁇ 12, 24, 36, 48 ⁇ .
- the value of Num is ⁇ 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48 ⁇ or ⁇ 3, 6, 9, 12, 15 ,18,21,24,27,30,33,36,39,42,45,48 ⁇ or ⁇ 0,4,8,12,16,20,24,28,32,36,40,44,48 ⁇ or ⁇ 0,3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48 ⁇ .
- the random access channel that the terminal sends a random access signal to the base station is allocated by the base station to the terminal by using signaling.
- the signaling may include at least one of: signaling for a single terminal, signaling for a single terminal in a connected state, and signaling transmitted on a control channel.
- the signaling includes at least one of the following: a starting level index; frequency domain location information of the random access channel allocated by the base station to the terminal; and the random number allocated by the base station to the terminal Time domain location information of the access channel.
- the frequency domain location information of the random access channel allocated by the base station to the terminal includes: a subcarrier or a subchannel index where the group 0 of the unit that constitutes the random access signal is sent.
- the frequency domain resources of several groups other than Group 0 in the unit are indicated by the frequency domain location of Group 0 (for example, according to a predefined rule, determined according to the frequency domain of Group 0 ).
- the 6bits indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal.
- “000000” represents a Subcarrior whose index is 0, and the index "101111” represents a Subcarrior whose index is 47.
- the foregoing 6 bits indication information is further used to indicate that the terminal randomly selects one subcarrier among the F subcarriers in Set m as the frequency domain location where the random access channel is located. For example, “110000” may indicate that the terminal randomly selects one subcarrier among the F subcarriers in Set m as the frequency domain location where the random access channel is located.
- the indication information when included in Set m F subcarriers or subchannels, by The indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal. In this embodiment, Is the rounding operation operator.
- the indication information is further used to indicate that the terminal randomly selects one subcarrier among the F subcarriers in the Set m as the frequency domain location where the random access channel of the terminal is located.
- the indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal, where Num is the number of subcarriers occupied by the random access channel.
- the time domain location information of the random access channel allocated by the base station to the terminal includes: configuration period indication information n of the second Set m ; wherein the base station is allocated to the terminal Set m of the random access channel is defined as a second location Set m; the second Set m is selected from the first Set m; the length of the second period, and arranged Set m as a first configuration Set m n times the period, n is a positive integer; the first Set m is one or more time-frequency resource sets Set m included in the random access channel resource, and n is a positive integer.
- At least one of the following is included: when the value of n is described by 3 bits, the value of n is ⁇ 1, 2, 3, 4, 5, 6, 7, 8 ⁇ or ⁇ 1 , 2, 4, 8, 16, 32, 64, 128 ⁇ or ⁇ 1, 2, 4, 8, 10, 12, 14, 16 ⁇ ; when the value of n is described by 2 bits, the value of n is ⁇ 1,2,3,4 ⁇ or ⁇ 1,2,4,8 ⁇ or ⁇ 1,4,6,8 ⁇ .
- the time domain location of the random access channel allocated by the base station to the terminal is: the first first Set m in the configuration period of the second Set m .
- the base station assigned to the time domain location of the random access channel terminal is located further comprising: a second position information Offset Set m arranged in a period of the second Set m; wherein the Offset Set m for n first configuration in a second period indicative of Set m, allocated to the index information of the random access channel where the first terminal of the Set m.
- the base station assigned to the domain location information of the random access channel where a terminal comprising: a field interval information Interval Set m consecutive two second time; and the base station allocates to the terminal Set m of the random access channel is defined as a second location Set m; Set m between the second selected Set m from the first, and the second two consecutive first-Set m interval interval Set m
- the first set m is shown as one or more time-frequency resource sets Set m included in the random access channel resource.
- the signaling further includes: triggering positioning operation indication information. For example, “0” means that the positioning operation is not triggered; “1” means that the positioning operation is triggered.
- the terminal when the trigger location operation indication information is a trigger location operation, the terminal sends the random access signal on the signaling random access channel.
- the random access signal sent by the terminal is used by the base station to perform location location use of the terminal.
- the method further includes: receiving, by the terminal, a random access response message sent by the base station according to the detection result after detecting the random access signal.
- the random access response message includes at least one of the following information: subcarrier spacing indication information; configured subcarrier number indication information.
- the subcarrier spacing indication information may be used to indicate the subcarrier spacing configuration when the Msg3 message is sent.
- the foregoing subcarrier spacing indication information and the configured subcarrier number indication information are indicated by a joint coding manner.
- the terminal may select a corresponding sequence from the sequence set according to the first rule, and generate a random access signal according to at least the selected sequence; the terminal transmits the random access signal to the base station through the random access channel.
- the terminal may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set may satisfy the following conditions:
- the terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers
- the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier.
- the terminal selects a corresponding sequence from the sequence set according to the first rule, including:
- terminal selection sequence Code 0 belonging to the first terminal set
- terminal selection sequence Code 1 belonging to the second terminal set
- Step 1 Subcarriers indexed as f n (0 ⁇ n ⁇ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
- Step 2 The corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol.
- F Offset is the frequency domain offset.
- Step 4 Define Group n as ⁇ CP n , S n ⁇ , that is, send the terminal (0 ⁇ j ⁇ J-1, 0 ⁇ n ⁇ N-1) the expression form of the corresponding time domain signal; and Group n with different values of n occupy different symbols in the time domain.
- Step 5 Define Group 0 to Group N-1 as the basic unit (corresponding to the above unit) constituting the random access signal.
- Step 6 The random access signal sent by the terminal is formed by the Unit repeating H times in the time domain, or the random access signal sent by the terminal is formed by a Unit, where when the random access signal is formed by a Unit, it is sent. When the random access signal is used, the random access signal is repeated H times and then sent;
- the number of repetitions H of different levels of terminal configurations is different.
- the foregoing level may include at least one of the following: an coverage enhancement level; a physical channel repetition transmission level; and a repeated transmission level of a message or signaling carried on the physical channel.
- the subcarrier spacing ⁇ f of the random access channel configured by the system may be 3.75 kHz, and the time domain symbol length is (microseconds).
- the length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
- Group 0 ⁇ Group 3 corresponding to frequency domain subcarrier index f 0 ⁇ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially
- the two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 2, the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the group 1 and Group 2 are configured.
- the subcarriers are separated by 6 subcarriers.
- the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
- the random access channel resource occupied by the terminal transmitting the random access signal is included in one time-frequency resource set Set m , where m is an index of the Set m .
- the set m includes 12 subcarriers in the frequency domain, which are respectively Subcarrior0-Subcarrior11, and the set m is at least four times longer than the time domain length of the unit in the time domain.
- Set m has a time domain length of 26ms. In addition to the time domain length of 4 Units, it also includes a guard time of 0.4ms.
- the terminal sends a Unit on Resource 0 in Set m .
- the actions performed by the receiving end include:
- Step 1 The base station receives the data on Group 0 to Group 3 , and combines the data received on the five symbols in each group to obtain the combined received data Y0, Y1, Y2 on Group 0 to Group 3 .
- Step 2 Calculate according to the following formula to get [Corr1, Corr 2]:
- Step 3 The base station performs coherent detection with [1, 1] and [1, -1] and [Corr1, Corr 2], respectively, when the energy values detected by [1, 1] and [Corr1, Corr 2] are greater than [1, -1] and the energy value detected by [Corr1, Corr 2], it is determined that the code transmitted by the terminal is code0; otherwise, it is determined that the code transmitted by the UE is code1.
- Step 4 After determining the code sent by the terminal, the base station further completes the estimation of the terminal uplink synchronization timing error.
- the base station After successfully completing the random access signal detection sent by the terminal and the uplink timing synchronization deviation estimation of the terminal, the base station sends a random access response message (RAR, also referred to as message 2, Message 2, referred to as Msg2) to the base station. terminal.
- RAR random access response message
- Msg2 message 2
- the terminal receives the RAR message, and obtains uplink timing synchronization information and uplink resources.
- Msg3 message 3
- Msg3 carries a specific ID of a terminal to distinguish different terminals.
- the terminal sends an Msg3 message on the Msg3 message resource configured by the base station. After receiving the Msg3 sent by the terminal, the base station finally solves such a random access conflict by sending a message 4 (Message4, referred to as Msg4).
- Msg4 will carry a specific ID sent by the terminal in Msg3.
- the terminal receives the Msg4 message sent by the base station, and the ID carried in the terminal matches the specific ID reported to the base station in Msg3, the terminal considers that it has won the random access collision and the random access succeeds; otherwise, the terminal It is considered that the access fails and the random access process is re-executed.
- A is C is a constant
- the first terminal set and the second terminal set may also be at least one of the following:
- the terminal included in the first terminal set is a terminal that supports simultaneous transmission of multiple subcarriers, and the terminal included in the second terminal set is a terminal that supports only single subcarrier transmission;
- the terminal included in the first terminal set is a terminal that uses multiple subcarriers to transmit uplink data
- the terminal included in the second terminal set is a terminal that transmits uplink data by using a single subcarrier
- the terminal included in the first terminal set is a terminal that is transmitted by the Msg3 message on multiple subcarriers
- the terminal included in the second terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission.
- the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
- the multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set.
- the terminal selects a corresponding sequence from the sequence set, including:
- terminal selection sequence Code 0 belonging to the first terminal set
- terminal selection sequence Code 1 belonging to the second terminal set
- the random access signal can be generated as follows:
- Step 1 Subcarriers indexed as f n (0 ⁇ n ⁇ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
- Step 2 The corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol.
- F Offset is the frequency domain offset.
- Step 3 In addition to sending S n , the above terminal sends:
- Step 4 You can define Group n as ⁇ CP n , S n ⁇ , which is sent by the terminal.
- the expression of the corresponding time domain signal; and the Group n with different values of n occupy different symbols in the time domain.
- Step 5 Define Group 0 to Group N-1 as a basic unit (Unit) for generating the random access signal by the terminal;
- Step 6 The random access signal sent by the terminal is repeated by the Unit H in the time domain;
- the number of repetitions H of different levels of terminal configurations is different.
- the level of the terminal includes at least one of the following:
- the subcarrier spacing ⁇ f of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds).
- the length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
- Group 0 ⁇ Group 3 corresponding to frequency domain subcarrier index f 0 ⁇ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, the basic unit of the terminal generates a random access signal
- the two-dimensional structure of the time domain and the frequency domain of (Unit) is as shown in FIG. 4, the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the configurations of Group 1 and Group 2 are configured.
- the subcarriers are separated by 6 subcarriers. Further, the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
- the random access channel resource occupied by the terminal transmitting the random access signal is included in one time-frequency resource set Set m , where m is an index of the Set m .
- the set m includes 12 subcarriers in the frequency domain, which are respectively Subcarrior0-Subcarrior11, and the set m is at least four times longer than the time domain length of the unit in the time domain.
- Set m has a time domain length of 26ms. In addition to the time domain length of 4 Units, it also includes a guard time of 0.4ms.
- the upper and lower frequency resources occupied by Set m are configured with 7.5 kHz guard bandwidth; the terminal sends Units on subset 0 in Set m .
- the base station can receive the random access signal sent by the terminal according to the following steps:
- Step 1 The base station receives the data on Group 0 to Group 3 , and combines the data received on the five symbols in each group to obtain the combined received data Y0, Y1, Y2 on Group 0 to Group 3 .
- Step 2 After [Y0, Y1], [Y2, Y3] are coherently detected with [1, 1], the detection results are added together as Corr1; [Y0, Y1], [Y2, Y3] and [1, respectively -1] After performing coherent detection, the detection results are added as Corr2; when Corr1 is larger than Corr2, it is determined that the code transmitted by the terminal is code0; otherwise, it is determined that the code transmitted by the UE is code1.
- Step 3 After determining the code sent by the terminal, the base station further completes the uplink timing synchronization deviation estimation of the terminal.
- the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
- the multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set.
- the terminal selects a corresponding sequence from the sequence set, including:
- terminal selection sequence Code 0 belonging to the first terminal set
- terminal selection sequence Code 1 belonging to the second terminal set
- the random access signal can be generated as follows:
- Step 1 Subcarriers indexed as f n (0 ⁇ n ⁇ 7) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
- Step 2 The corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol.
- F Offset is the frequency domain offset.
- the corresponding time domain expression is The number of sampling points in the time domain
- Step 4 You can define that Group n is ⁇ CP n , S n ⁇ The expression of the corresponding time domain signal; and the Group n with different values of n occupy different symbols in the time domain.
- Step 5 Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
- Step 6 The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
- the number of repetitions H of different levels of terminal configurations is different.
- the level of the above terminal may include at least one of the following:
- the subcarrier spacing ⁇ f of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds).
- the length of the basic unit (Unit) that the group 0 to the group 7 generates the random access signal is 11.2 ms;
- Group 0 ⁇ Group 7 corresponding to frequency domain subcarrier index f 0 ⁇ f 7 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, subcarrior 2, subcarrior 3, subcarrior 9, subcarrior 8, then the The two-dimensional structure of the time domain and the frequency domain of the basic unit (Unit) in which the terminal generates the random access signal is as shown in FIG. 6, and the subcarriers configured by Group 0 and Group 1 are adjacent, and the Group 2 and Group 3 are configured.
- the subcarriers are adjacent to each other, and the subcarriers configured by Group 4 and Group 5 are adjacent to each other, and the subcarriers configured by Group 6 and Group 7 are adjacent.
- the subcarriers configured in Group 1 and Group 2 are separated by 6 subcarriers, and the subcarriers configured in Group 5 and Group 6 are separated by 6 subcarriers.
- Group 0 and Group 4 subcarrier index is determined according to a predefined interval rules Examples Group 0 and Group 4 subcarrier index interval is two subcarriers of the present embodiment;
- the random access channel resource occupied by the terminal transmitting the random access signal is included in one time-frequency resource set Set m , where m is an index of the Set m .
- the Set m includes 12 subcarriers in the frequency domain, which are respectively Subcarrior 0 ⁇ Subcarrior 11 , and the Set m is at least 3 times longer than the time domain length of the Unit in the time domain.
- Set m has a time domain length of 34ms. In addition to the time domain length of 3 Units, it also includes a guard time of 0.4ms.
- the frequency resources occupied by Set m are respectively configured with 7.5 kHz guard bandwidth in the upper and lower sidebands; the terminal sends a Unit on subset 0 in Set m .
- the base station can receive the random access signal sent by the terminal according to the following steps:
- Step 1 The base station receives the data on Group 0 to Group 7 , and combines the data received on the five symbols in each group to obtain the combined received data Y0, Y1, Y2 on Group 0 to Group 7 . Y3, Y4, Y5, Y6, Y7.
- Step 2 [Y0, Y1, Y2, Y3, Y4, Y5, Y6, Y7] After coherent detection with [1,1,1,1,1,1,1], the test results are added together as Corr1 ;[Y0,Y1,Y2,Y3,Y4,Y5,Y6,Y7] and [1,1,1,1,-1,-1,-1,-1] after coherent detection, the test results are added together Corr2; when Corr1 is greater than Corr2, it is determined that the code sent by the terminal is code0; otherwise, it is determined that the code sent by the UE is code1.
- Step 3 After determining the code sent by the terminal, the base station further completes the uplink timing synchronization deviation estimation of the terminal.
- the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
- the multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set meet the following conditions:
- the terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers
- the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier.
- the terminal selects a corresponding sequence from the sequence set, including:
- terminal selection sequence Code 0 belonging to the first terminal set
- terminal selection sequence Code 1 belonging to the second terminal set
- the random access signal can be generated as follows:
- Step 1 Subcarriers indexed as f n (0 ⁇ n ⁇ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
- Step 2 The corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol.
- F Offset is the frequency domain offset.
- the corresponding time domain expression is The number of sampling points in the time domain
- Step 4 You can define Group n as ⁇ CP n , S n ⁇ , which is sent by the terminal.
- the expression of the corresponding time domain signal; and the Group n with different values of n occupy different symbols in the time domain.
- Step 5 Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
- Step 6 The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
- the number of repetitions H of different levels of terminal configurations is different.
- the level of the terminal may include at least one of the following:
- the subcarrier spacing ⁇ f of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds).
- Group 0 ⁇ Group 3 corresponding to frequency domain subcarrier index f 0 ⁇ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially
- the two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 8.
- the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the Group 1 and Group 2 are configured.
- the subcarriers are separated by 6 subcarriers.
- the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
- the random access channel resource occupied by the terminal transmitting the random access signal is included in one time-frequency resource set Set m , where m is an index of the Set m .
- the Set m includes 12 subcarriers in the frequency domain, which are respectively Subcarrior 0 ⁇ Subcarrior 11 , and the Set m is at least 4 times longer than the time domain length of the Unit in the time domain.
- Set m has a time domain length of 26ms. In addition to the time domain length of 4 Units, it also includes 0.4ms Guard Time. The terminal sends a Unit on the subset 0 in Set m .
- up to 4 Set m can be configured.
- 2bit indicated by the frequency domain location of the terminal configuration Set m e.g. Configuration "00" indicates that the terminal is configured Set m Configuration "01” indicates that the terminal is configured Set m Configuration "10" Set m indicates the terminal is configured Configuration "11" Set m indicates the terminal is configured
- the base station can receive the random access signal sent by the terminal according to the following steps:
- Step 1 The base station receives the data on Group 0 to Group 3 , and combines the data received on the five symbols in each group to obtain the combined received data Y0, Y1, Y2 on Group 0 to Group 3 . Y3.
- Step 2 Calculate according to the following formula to obtain [Corr1, Corr 2].
- Step 3 The base station performs coherent detection with [1, 1] and [1, -1] and [Corr1, Corr 2], respectively, when the energy values detected by [1, 1] and [Corr1, Corr 2] are greater than [1, -1] and the energy value detected by [Corr1, Corr 2], it is determined that the code transmitted by the terminal is code0; otherwise, it is determined that the code transmitted by the UE is code1.
- Step 4 After determining the code sent by the terminal, the base station further completes the uplink timing synchronization deviation estimation of the terminal.
- the set m configured for the terminal may also be indicated by a bitmap bitmap.
- a bitmap bitmap For example, when the uplink bandwidth includes 48 subcarriers, a maximum of 4 Set m may be configured.
- 4bit bitmap indicated by a frequency domain location of the terminal configuration Set m e.g. Configuration "0001" indicates that the terminal is configured Set m Configuration "0010" Set m indicates the terminal is configured Configuration "0100” Set m indicates the terminal is configured Configuration "1000" Set m indicates the terminal is configured Configuration "1100” Set m indicates the terminal is configured
- the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
- the multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set meet the following conditions:
- the terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers
- the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier.
- the terminal selects a corresponding sequence from the sequence set, including:
- terminal selection sequence Code 0 belonging to the first terminal set
- terminal selection sequence Code 1 belonging to the second terminal set
- the random access signal can be generated as follows:
- Step 1 Subcarriers indexed as f n (0 ⁇ n ⁇ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
- Step 2 The corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol.
- F Offset is the frequency domain offset.
- the corresponding time domain expression is The number of sampling points in the time domain
- Step 4 You can define Group n as ⁇ CP n , S n ⁇ , which is sent by the terminal.
- the expression of the corresponding time domain signal; and the Group n with different values of n occupy different symbols in the time domain.
- Step 5 Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
- Step 6 The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
- the number of repetitions H of the terminal configurations of different levels is different.
- the level of the foregoing terminal may include at least one of the following:
- the subcarrier spacing ⁇ f of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds).
- the length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
- Group 0 ⁇ Group 3 corresponding to frequency domain subcarrier index f 0 ⁇ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially
- the two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 11 , the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the group 1 and Group 2 are configured.
- the subcarriers are separated by 6 subcarriers.
- the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
- the random access channel resource includes a plurality of time-frequency resource sets Set m , where m is an index of the Set m . 12, the Set m includes 12 subcarriers in the frequency domain, respectively Subcarrior0 ⁇ Subcarrior11, time domain Set m length is 26ms, the length of the time domain in addition contains Unit 4, further comprising 0.4ms Guard Time.
- Vms The interval between the adjacent two time-frequency resource sets Set m and Set m+1 is Vms, as shown in FIG. 13 , where V is at least one of the following:
- V 2 y , where y is a positive integer greater than or equal to 0;
- y can take a value range of ⁇ 1, 2, 3, 4, 5, 6, 7 ⁇ .
- the terminal repeats the transmission of the Unit 8 times in Set m and Set m+1 .
- Vms can also be determined as follows:
- V is at least one of the following:
- V B ⁇ 2 y , where y is a positive integer greater than or equal to 0; B is the time domain length of Set m .
- the value of y may be ⁇ 1, 2, 3, 4, 5, 6, 7 ⁇ .
- the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
- the multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set meet the following conditions:
- the terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers
- the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier.
- the terminal selects a corresponding sequence from the sequence set, including:
- terminal selection sequence Code 0 belonging to the first terminal set
- terminal selection sequence Code 1 belonging to the second terminal set
- the random access signal can be generated as follows:
- Step 1 Subcarriers indexed as f n (0 ⁇ n ⁇ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
- Step 2 The corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol.
- F Offset is the frequency domain offset.
- Step 4 Define that Group n is ⁇ CP n , S n ⁇ is sent by the terminal. (0 ⁇ j ⁇ J-1, 0 ⁇ n ⁇ N-1) the expression form of the corresponding time domain signal; and Group n with different values of n occupy different symbols in the time domain.
- Step 5 Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal;
- Step 6 The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
- the number of repetitions H of the terminal configurations of different levels is different.
- the level of the foregoing terminal may include at least one of the following:
- the subcarrier spacing ⁇ f of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds).
- the length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
- Group 0 ⁇ Group 3 corresponding to frequency domain subcarrier index f 0 ⁇ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially
- the two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 14 , the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the group 1 and Group 2 are configured.
- the subcarriers are separated by 6 subcarriers.
- the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
- the random access channel resource includes a plurality of time-frequency resource sets Set m , where m is an index of the Set m .
- the Set m includes 12 subcarriers in the frequency domain, respectively Subcarrior0 ⁇ Subcarrior11, time domain Set m length is 26ms, the length of the time domain in addition contains Unit 4, further comprising 0.4ms Guard Time.
- the configuration period of the time-frequency resource set Set m is Vms, as shown in Figure 16, where the value of V is:
- V 2 y , where y is a positive integer
- the value of y may be ⁇ 5, 6, 7, 8, 9, 10, 11, 12 ⁇ .
- the terminal repeats the transmission of the Unit 8 times in Set m and Set m+1 .
- the configuration period of the time-frequency resource set Set m is Vms, where Vms can also be determined as follows:
- V B ⁇ 2 y , where y is an integer greater than or equal to 0; B is the time domain length of Set m .
- the value of y may be ⁇ 0, 1, 2, 3, 4, 5, 6, 7 ⁇ .
- the terminal repeats the transmission of the Unit 8 times in Set m and Set m+1 .
- the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
- the multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set meet the following conditions:
- the terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers
- the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier.
- the terminal selects a corresponding sequence from the sequence set, including:
- terminal selection sequence Code 0 belonging to the first terminal set
- terminal selection sequence Code 1 belonging to the second terminal set
- the random access signal can be generated as follows:
- Step 1 Subcarriers indexed as f n (0 ⁇ n ⁇ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
- Step 2 The corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol.
- F Offset is the frequency domain offset.
- Step 4 You can define that Group n is ⁇ CP n , S n ⁇ (0 ⁇ j ⁇ J-1, 0 ⁇ n ⁇ N-1) the expression form of the corresponding time domain signal; and Group n with different values of n occupy different symbols in the time domain.
- Step 5 Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
- Step 6 The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
- the number of repetitions H of different levels of terminal configurations is different.
- the foregoing terminal level may include at least one of the following:
- the subcarrier spacing ⁇ f of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds).
- the length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
- Group 0 ⁇ Group 3 corresponding to frequency domain subcarrier index f 0 ⁇ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially
- the two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 17, the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the Group 1 and Group 2 are configured.
- the subcarriers are separated by 6 subcarriers.
- the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
- the random access channel resource includes a plurality of time-frequency resource sets Set m , where m is an index of the Set m .
- the Set m includes 12 subcarriers in the frequency domain, respectively Subcarrior0 ⁇ Subcarrior11, time domain Set m length is 26ms, the length of the time domain in addition contains Unit 4, further comprising 0.4ms Guard Time.
- the value of y may be ⁇ 0, 1, 2, 3, 4, 5, 6, 7 ⁇ .
- y 2, that is, up to 4 Set m can be configured in Vms.
- each Set m includes 4 subsets, up to 16 subsets can be configured in Vms, and the index of the subset is defined.
- the terminal is divided into three levels, level 1, level 2, and level 3.
- the number of repeated transmissions of the unit in the time domain is 2, 4, and 8 times, respectively.
- subset 0 to subset 1 are assigned to the terminal of level 1
- subset 2 to subset 5 are assigned to the terminal of level 2
- subset 6 to subset 13 are assigned to the terminal of level 3.
- the same subset allocation method is adopted between the configuration periods of different time-frequency resource sets Set m .
- the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
- the multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set meet the following conditions:
- the terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers
- the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier.
- the terminal selects a corresponding sequence from the sequence set, including:
- terminal selection sequence Code 0 belonging to the first terminal set
- terminal selection sequence Code 1 belonging to the second terminal set
- the random access signal can be generated as follows:
- Step 1 Subcarriers indexed as f n (0 ⁇ n ⁇ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
- Step 2 The corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol.
- F Offset is the frequency domain offset.
- Step 4 You can define that Group n is ⁇ CP n , S n ⁇ (0 ⁇ j ⁇ J-1, 0 ⁇ n ⁇ N-1) the expression form of the corresponding time domain signal; and Group n with different values of n occupy different symbols in the time domain.
- Step 5 Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
- Step 6 The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
- the number of repetitions H of the terminal configurations of different levels is different.
- the level of the foregoing terminal may include at least one of the following:
- the subcarrier spacing ⁇ f of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds).
- the length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
- Group 0 ⁇ Group 3 corresponding to frequency domain subcarrier index f 0 ⁇ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially
- the two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 20, the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the Group 1 and Group 2 are configured.
- the subcarriers are separated by 6 subcarriers.
- the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
- the random access channel resource includes a plurality of time-frequency resource sets Set m , where m is an index of the Set m .
- the Set m includes 12 subcarriers in the frequency domain, respectively Subcarrior0 ⁇ Subcarrior11, time domain Set m length is 26ms, the length of the time domain in addition contains Unit 4, further comprising 0.4ms Guard Time.
- D is preferably 2 x , wherein x is an integer greater than or equal to 0;
- up to D Set m can be configured in Vms. Since each Set m includes 4 subsets, up to 4*D subsets can be configured in Vms, and the index of the defined subset is subset 0 to subset (4*D-1).
- the terminal may be divided into G levels, which are respectively level 0 to level (G-1), wherein the level g (0 ⁇ g ⁇ G-1) (corresponding to the above-mentioned level index is g
- the terminal sends a random access signal, and the number of times that the Unit repeats the transmission in the time domain is Repetition g . Therefore, in one of the configuration periods, consecutive Repetition g subsets are configured for the level g terminals, and the starting subset index StartingSubsetIndex g is calculated according to the following formula:
- the same subset allocation method can be adopted between different configuration periods.
- the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
- the multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set meet the following conditions:
- the first terminal set includes terminals that support single subcarrier transmission and have a subcarrier spacing of 3.75 kHz
- the second terminal set includes terminals that support single subcarrier transmission and subcarrier spacing of 15 kHz.
- the terminal selects a corresponding sequence from the sequence set, including:
- terminal selection sequence Code 0 belonging to the first terminal set
- terminal selection sequence Code 1 belonging to the second terminal set
- the random access signal can be generated as follows:
- Step 1 Subcarriers indexed as f n (0 ⁇ n ⁇ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
- Step 2 The corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol.
- F Offset is the frequency domain offset.
- Step 4 You can define that Group n is ⁇ CP n , S n ⁇ (0 ⁇ j ⁇ J-1, 0 ⁇ n ⁇ N-1) the expression form of the corresponding time domain signal; and Group n with different values of n occupy different symbols in the time domain.
- Step 5 Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
- Step 6 The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
- the number of repetitions H of different levels of terminal configurations is different.
- the level of the foregoing terminal includes at least one of the following:
- the subcarrier spacing ⁇ f of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds).
- the length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
- Group 0 ⁇ Group 3 corresponding to frequency domain subcarrier index f 0 ⁇ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially
- the two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 22, the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the Group 1 and Group 2 are configured.
- the subcarriers are separated by 6 subcarriers.
- the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
- the random access channel resource includes a plurality of time-frequency resource sets Set m , where m is an index of the Set m .
- the Set m includes 12 subcarriers in the frequency domain, which are Subcarrior0 ⁇ Subcarrior11, and the Set m time domain length is a time domain length of 1 Unit.
- the Set m includes a subset, wherein the subset is configured with the same subcarrier in the frequency domain as the Set m , and the subset has a length of 1 Unit in the time domain;
- D 2 y , where y is an integer greater than or equal to 0;
- y 4, that is, up to 16 Set m can be configured in Vms. Since each Set m includes 1 subset, up to 16 subsets can be configured in Vms, and the index of the defined subset is subset 0 to subset. 15.
- the terminal is divided into three levels, which are level 0, level 1, and level 2.
- the terminal of level g (0 ⁇ g ⁇ 2) needs to repeat the number of times that the Unit repeats the transmission in the time domain is Repetition g .
- consecutive Repetition g subsets are configured for the level g terminals, and the starting subset index StartingSubsetIndex g can be calculated according to the following formula:
- StartingSubsetIndex 0 0
- StartingSubsetIndex 1 2
- StartingSubsetIndex 2 6.
- the subset configuration scheme corresponding to the terminal with the level index g may be the same.
- the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
- the multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set meet the following conditions:
- the terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers
- the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier.
- the terminal selects a corresponding sequence from the sequence set, including:
- terminal selection sequence Code 0 belonging to the first terminal set
- terminal selection sequence Code 1 belonging to the second terminal set
- the random access signal can be generated as follows:
- Step 1 Subcarriers indexed as f n (0 ⁇ n ⁇ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
- Step 2 The corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol.
- F Offset is the frequency domain offset.
- the corresponding time domain expression is The number of sampling points in the time domain
- Step 4 You can define that Group n is ⁇ CP n , S n ⁇ The expression of the corresponding time domain signal; and the Group n with different values of n occupy different symbols in the time domain.
- Step 5 Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
- Step 6 The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
- the number of repetitions H of the terminal configurations of different levels is different.
- the level of the foregoing terminal may include at least one of the following:
- the subcarrier spacing ⁇ f of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is
- the length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
- Group 0 ⁇ Group 3 corresponding to frequency domain subcarrier index f 0 ⁇ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially
- the two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 25, the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the Group 1 and Group 2 are configured.
- the subcarriers are separated by 6 subcarriers.
- the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
- the random access channel resource includes a plurality of time-frequency resource sets Set m , where m is an index of the Set m .
- the Set m includes 12 subcarriers in the frequency domain, which are Subcarrior0 ⁇ Subcarrior11, and the Set m time domain length is a time domain length of 1 Unit.
- the Set m includes a subset, wherein the subset is configured with the same subcarrier in the frequency domain as the Set m , and the subset has a length of 1 Unit in the time domain;
- the configuration period of the time-frequency resource set Set m is Vms.
- V 2 y , where y is an integer greater than or equal to 0;
- the terminal is divided into three levels, which are level 0, level 1, and level 2.
- the terminal g of the level g (0 ⁇ g ⁇ 2) needs to repeat the number of times that the unit repeats the transmission in the time domain is Repetition g .
- startingSubsetIndex 0 0
- StartingSubsetIndex 1 1
- StartingSubsetIndex 2 3
- the allocation of consecutive Repetition g subsets for the terminal with the level index g is as shown in FIG. 27 .
- the subset configuration scheme corresponding to the terminal with the level index g may be the same.
- the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
- the terminal selects a corresponding sequence from the sequence set, including:
- the random access signal can be generated as follows:
- Step 1 Subcarriers indexed as f n (0 ⁇ n ⁇ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
- Step 2 The corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol.
- F Offset is the frequency domain offset.
- the corresponding time domain expression is The number of sampling points in the time domain
- Step 4 You can define that Group n is ⁇ CP n , S n ⁇ The expression of the corresponding time domain signal; and the Group n with different values of n occupy different symbols in the time domain.
- Step 5 Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
- Step 6 The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
- the number of repetitions H of the terminal configurations of different levels is different.
- the level of the foregoing terminal may include at least one of the following:
- the subcarrier spacing ⁇ f of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is
- the length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
- Group 0 ⁇ Group 3 corresponding to frequency domain subcarrier index f 0 ⁇ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially
- the two-dimensional structure of the time domain and frequency domain of the unit is shown in FIG.
- the subcarriers configured in Group 0 and Group 1 are adjacent to each other.
- the subcarriers configured in Group 2 and Group 3 are adjacent to each other.
- the subcarriers configured in Group 1 and Group 2 are separated by 6 subcarriers. Further, the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
- the random access channel resource includes a plurality of time-frequency resource sets Set m , where m is an index of the Set m . As shown in Figure 29.
- the Set m includes 12 subcarriers in the frequency domain, respectively Subcarrior0 ⁇ Subcarrior11, and the set m time domain length is 26ms, including the time domain length of 4 Units and the guard time of 0.4ms.
- the Set m includes four subsets, wherein the subset is configured with the same subcarriers in the frequency domain as the Set m , and the subset has a length of 4 Units in the time domain;
- the configuration period of the time-frequency resource set Set m is Vms.
- V 2 y , where y is an integer greater than or equal to 0;
- the terminal is divided into three levels, namely level 0, level 1, level 2, respectively. .
- the terminal g of the level g (0 ⁇ g ⁇ 2) needs to repeat the number of times that the unit repeats the transmission in the time domain is Repetition g .
- the N g Set m resources allocated for the terminal (0 ⁇ g ⁇ 2) whose rank index is g are 2 Set m , 2 Set m, and 4 Set m, respectively .
- the time domain interval between Set m configured for the terminal with the level index g is L g ms.
- the same index different levels corresponding to the terminal L g; the present embodiment, L g 32ms.
- corresponding resources are: Set 4 in the subset0, subset0 in 6 subset1, subset2, subset3, Set 5 in subset0, subset1, subset2, subset3, Set, subset0 in 7 subset1, subset2, subset3, Set , subset1, subset2, subset3;
- terminal of the four A resource is randomly selected from the resources as a transmission resource of the random access signal;
- the resource allocation scheme corresponding to the terminal with the level index g may be the same between the configuration periods of different Set m .
- the terminal may select a corresponding sequence from the sequence set according to the first rule, and generate a random access signal according to at least the selected sequence; the terminal transmits the random access signal to the base station through the random access channel.
- the terminal may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set may satisfy the following conditions:
- the terminal included in the first terminal set is a terminal that has the information amount of the S1 in the Msg3 message
- the terminal in the second terminal set is a terminal that has the information amount of the S2 in the Msg3 message, where Size1 is not equal to Size2.
- the terminal selects a corresponding sequence from the sequence set according to the first rule, including:
- terminal selection sequence Code 0 belonging to the first terminal set
- terminal selection sequence Code 1 belonging to the second terminal set
- Step 1 Subcarriers indexed as f n (0 ⁇ n ⁇ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
- Step 2 The corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol.
- F Offset is the frequency domain offset.
- the corresponding time domain expression is The number of sampling points in the time domain
- Step 4 Define Group n as ⁇ CP n , S n ⁇ , that is, send the terminal The expression of the corresponding time domain signal; and the Group n with different values of n occupy different symbols in the time domain.
- Step 5 Define Group 0 to Group N-1 as the basic unit (corresponding to the above unit) constituting the random access signal.
- Step 6 The random access signal sent by the terminal is formed by the Unit repeating H times in the time domain, or the random access signal sent by the terminal is formed by a Unit, where when the random access signal is formed by a Unit, it is sent. When the random access signal is used, the random access signal is repeated H times and then sent;
- the number of repetitions H of different levels of terminal configurations is different.
- the foregoing level may include at least one of the following: an coverage enhancement level; a physical channel repetition transmission level; and a repeated transmission level of a message or signaling carried on the physical channel.
- the subcarrier spacing ⁇ f of the random access channel configured by the system may be 3.75 kHz, and the time domain symbol length is
- the length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
- Group 0 ⁇ Group 3 corresponding to frequency domain subcarrier index f 0 ⁇ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially
- the two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 2, the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the group 1 and Group 2 are configured.
- the subcarriers are separated by 6 subcarriers.
- the subcarrier indices of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
- the random access channel resource occupied by the terminal transmitting the random access signal is included in one time-frequency resource set Set m , where m is an index of the Set m .
- the Set m in the frequency domain comprises 12 subcarriers (Subcarrior), respectively Subcarrior0 ⁇ Subcarrior11, the arrangement period Set m to 40ms.
- Subcarrior0 ⁇ Subcarrior9, the Subcarrior0 ⁇ Subcarrior9 are subcarrier indexes in which the Group 0 in the unit unit constituting the random access signal is transmitted, and Group 1 and Group 2 in the Unit except Group 0 and The frequency domain resource where Group 3 is located is determined by the frequency domain location of Group 0 and according to predefined rules.
- Group 0 , Group 1 , Group 2, and Group 3 respectively correspond to subcarrier indexes of Subcarrior0, Subcarrior1, Subcarrior7, and Subcarrior6.
- the base station After successfully completing the random access signal detection sent by the terminal and the uplink timing synchronization deviation estimation of the terminal, the base station sends a random access response message (RAR, also referred to as message 2, Message 2, referred to as Msg2) to the base station. terminal.
- RAR random access response message
- Msg2 message 2
- the terminal receives the RAR message, and obtains uplink timing synchronization information and uplink resources.
- Msg3 message 3
- Msg3 carries a specific ID of a terminal to distinguish different terminals.
- the terminal sends an Msg3 message on the Msg3 message resource configured by the base station. After receiving the Msg3 sent by the terminal, the base station finally solves such a random access conflict by sending a message 4 (Message4, referred to as Msg4).
- Msg4 will carry a specific ID sent by the terminal in Msg3.
- the terminal receives the Msg4 message sent by the base station, and the ID carried in the terminal matches the specific ID reported to the base station in Msg3, the terminal considers that it has won the random access collision and the random access succeeds; otherwise, the terminal It is considered that the access fails and the random access process is re-executed.
- the RAR message sent to the terminal includes the following information:
- the indication information of the subcarrier spacing used when Msg3 is transmitted and the indication information of the number of subcarriers when the Msg3 is transmitted are indicated by a joint coding manner.
- the single subcarriers When the terminal transmits the Msg3 message by using a single subcarrier transmission manner, the single subcarriers have two configurations of 3.75 kHz and 15 kHz.
- the uplink available bandwidth is 180 kHz
- for a single subcarrier interval of 3.75 kHz up to 48 subcarriers can be configured in the uplink available bandwidth, and the subcarrier index is A0 to A47; for a single subcarrier of 15 kHz
- a maximum of 12 subcarriers can be configured in the uplink available bandwidth, and the subcarrier index is B0 to B11.
- the joint coding mode indication is:
- the subcarrier spacing is 15 kHz.
- the uplink available bandwidth is 180 kHz, a maximum of 12 subcarriers can be configured in the uplink available bandwidth, and the subcarrier index is 0 to 11.
- the frequency domain resource allocation of the Msg3 message has the following configurations:
- Configure joint coding indication information of 3 bits where "000” indicates occupied subcarrier index ⁇ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 ⁇ ; "001" and “010” respectively Indicates 6 subcarriers occupying the subcarrier index ⁇ 0, 1, 2, 3, 4, 5 ⁇ and 6 subcarriers occupying the subcarrier index ⁇ 6, 7, 8, 9, 10, 11 ⁇ ; "011” "100 "101” and “110” respectively indicate 3 subcarriers occupying the subcarrier index ⁇ 0, 1, 2 ⁇ , 3 subcarriers occupying the subcarrier index ⁇ 3, 4, 5 ⁇ , and the occupied subcarrier index ⁇ 6, 7, 3 subcarriers of 8 ⁇ and 3 subcarriers of ⁇ 9, 10, 11 ⁇ .
- the uplink system bandwidth is 180 kHz.
- the uplink access bandwidth (PRACH) configured by the base station occupies an uplink bandwidth of 45 kHz, and the PRACH subcarrier spacing ⁇ f is 3.75 kHz.
- a total of 12 PRACH subcarriers are configured, respectively, which are Subcarrior 0 ⁇ Subcarrior 11.
- Group 1 to Group 4 are defined as the basic unit (Unit) that constitutes a random access signal (Preamble). Group 1 to Group 4 are respectively sent on different subcarriers; each group includes one cyclic prefix (CP) and five Preamble symbols (symbol), and one Preamble symbol time domain symbol length.
- CP cyclic prefix
- symbol symbol time domain symbol length
- the length of the CP is 0.2667ms
- the CP length is 0.2667 ms, and the unit length is 6.4 ms;
- the terminal selects the Subcarrior sent by Group 1 as Subcarrior0, the Subcarrior sent by Group 2 is Subcarrior1, the Subcarrior sent by Group 3 is Subcarrior7, and the Subcarrior sent by Group 4 is Subcarrior6, as shown in Figure 32.
- the NB-IoT system PRACH The second protection time (Guard Time 2, GT2 for short) is added to the resource configuration.
- the SRS is from the LTE system, and after the terminal completes the transmission of the random access signal of one group, the GT2 with a time length of 0.4 ms needs to be introduced. As shown in FIG. 32, the unit length becomes 8 ms.
- the time length of the basic unit of the random access signal (Preamble) T_Unit1 is 8 ms;
- the transmission period of the random access signal (Preamble) transmitted on the PRACH is 1280 ms;
- the starting position offset of the Preamble transmission is 128ms.
- the 64-time repeated transmission of the basic unit of the Preamble transmission has a total length of 512 ms
- the Preamble transmission interval Gap1 needs to be introduced, and the Preamble is not transmitted during the Gap1 time.
- the 64-time repeated transmission structure of the basic unit of the Preamble is as shown in FIG.
- the uplink system bandwidth is 180 kHz.
- the uplink access bandwidth (PRACH) configured by the base station occupies an uplink bandwidth of 45 kHz, and the PRACH subcarrier spacing ⁇ f is 3.75 kHz.
- a total of 12 PRACH subcarriers are configured, respectively, which are Subcarrior 0 ⁇ Subcarrior 11.
- Group 1 to Group 4 are defined as the basic unit (Unit) that constitutes a random access signal (Preamble). Group 1 to Group 4 are respectively sent on different subcarriers; each group includes one cyclic prefix (CP) and five Preamble symbols (symbol), and one Preamble symbol time domain symbol length.
- CP cyclic prefix
- symbol symbol time domain symbol length
- the length of the CP is 0.2667ms
- the length of the CP is 0.0667ms
- the CP length is 0.2667 ms, and the unit length is 6.4 ms;
- Subcarrior sent by Group 1 When the terminal selects Subcarrior sent by Group 1 as Subcarrior0, the Subcarrior sent by Group 2 is Subcarrior1, the Subcarrior sent by Group 3 is Subcarrior7, and the Subcarrior sent by Group 4 is Subcarrior6, as shown in Figure 34.
- the NB-IoT system PRACH The second protection time (Guard Time 2, GT2 for short) is added to the resource configuration.
- the SRS is from the LTE system, and after the terminal completes the transmission of the random access signals of the two groups, the GT2 with a length of 0.8 ms needs to be introduced. As shown in FIG. 34, the unit length becomes 8 ms.
- the time length of the basic unit of the random access signal (Preamble) T_Unit1 is 8 ms;
- the transmission period of the random access signal (Preamble) transmitted on the PRACH is 1280 ms;
- the starting position offset of the Preamble transmission is 128ms.
- the 64-time repeated transmission of the basic unit of the Preamble transmission has a total length of 512 ms
- the Preamble transmission interval Gap1 needs to be introduced, and the Preamble is not transmitted during the Gap1 time.
- the 64-time repeated transmission structure of the basic unit of the Preamble is as shown in FIG. 35.
- the uplink system bandwidth is 180 kHz.
- the uplink access bandwidth (PRACH) configured by the base station occupies an uplink bandwidth of 45 kHz, and the PRACH subcarrier spacing ⁇ f is 3.75 kHz.
- a total of 12 PRACH subcarriers are configured, respectively, which are Subcarrior 0 ⁇ Subcarrior 11.
- Group 1 to Group 4 are defined as the basic unit (Unit) that constitutes a random access signal (Preamble). Group 1 to Group 4 are respectively sent on different subcarriers; each group includes one cyclic prefix (CP) and five Preamble symbols (symbol), and one Preamble symbol time domain symbol length.
- CP cyclic prefix
- symbol symbol time domain symbol length
- the terminal selects the Subcarrior sent by Group 1 as Subcarrior0, the Subcarrior sent by Group 2 is Subcarrior1, the Subcarrior sent by Group 3 is Subcarrior7, and the Subcarrior sent by Group 4 is Subcarrior6, as shown in Figure 36.
- the NB-IoT system PRACH Increase the time interval (Gap) in the resource configuration.
- the SRS from the LTE system, and is completed when the terminal transmits a random access signal of Group 6, the length of time necessary to introduce the Gap 0.4ms; the introduction of the number N gap Gap
- the uplink system bandwidth is 180 kHz.
- the uplink access bandwidth (PRACH) configured by the base station occupies an uplink bandwidth of 45 kHz, and the PRACH subcarrier spacing ⁇ f is 3.75 kHz.
- a total of 12 PRACH subcarriers are configured, respectively, which are Subcarrior 0 ⁇ Subcarrior 11.
- Group 1 to Group 4 are defined as the basic unit (Unit) that constitutes a random access signal (Preamble). Group 1 to Group 4 are respectively sent on different subcarriers; each group includes one cyclic prefix (CP) and five Preamble symbols (symbol), and one Preamble symbol time domain symbol length.
- CP cyclic prefix
- symbol symbol time domain symbol length
- the terminal selects the Subcarrior sent by Group 1 as Subcarrior0, the Subcarrior sent by Group 2 is Subcarrior1, the Subcarrior sent by Group 3 is Subcarrior7, and the Subcarrior sent by Group 4 is Subcarrior6, as shown in Figure 37.
- the NB-IoT system PRACH Increase the time interval (Gap) in the resource configuration.
- the SRS from the LTE system, and is completed when the terminal transmits a random access signal Unit 4, the length of time necessary to introduce the Gap 0.4ms; the introduction of the number N gap Gap
- the method according to the above embodiment can be implemented by means of software plus a necessary general hardware platform, and of course, by hardware, but in many cases, the former is A better implementation.
- the technical solution of the present invention which is essential or contributes to the prior art, may be embodied in the form of a software product stored in a storage medium (such as ROM/RAM, disk,
- the optical disc includes a number of instructions for causing a terminal device (which may be a cell phone, a computer, a server, or a network device, etc.) to perform the methods described in various embodiments of the present invention.
- an access processing device is also provided, which is used to implement the foregoing embodiments and preferred embodiments, and details are not described herein.
- the term "module” may implement a combination of software and/or hardware of a predetermined function.
- the apparatus described in the following embodiments is preferably implemented in software, hardware, or a combination of software and hardware, is also possible and contemplated.
- FIG. 38 is a structural block diagram of an access processing apparatus according to an embodiment of the present invention.
- the apparatus may be applied to a terminal.
- the apparatus includes a selection module 382, a generating module 384, and a sending module 386. Description of the device:
- the selecting module 382 is configured to select a sequence corresponding to the terminal in the sequence set; the generating module 384 is connected to the selecting module 382, configured to generate a random access signal according to at least the corresponding sequence; and the sending module 386 is connected to the generating module 384. And configured to send the random access signal to the base station.
- the sequence set includes a sequence of J sequences having a length of N, wherein the sequence of the index of j is expressed as J is a positive integer and N is a positive integer.
- the sequence set includes R sequence subsets, that is, R sequence subsets in which J sequences included in the sequence set are divided, and R sequence subsets can be configured. Give a different set of terminals, where R is a positive integer.
- the selection module 382 may select a sequence corresponding to the terminal in the sequence set by: determining a sequence subset corresponding to the terminal set to which the terminal belongs to the R sequence subsets; and selecting a piece from the determined sequence subset The sequence acts as the corresponding sequence.
- the one sequence in the sequence subset is selected as a corresponding sequence; when there are multiple sequences in the determined sequence subset, the determined sequence is determined A sequence is randomly selected in the subset as a corresponding sequence; where R is a positive integer.
- the foregoing sequence set may be divided into R sequence sub-sets. Therefore, when selecting a sequence corresponding to the terminal, the terminal may first select a sequence sub-set that is configured for the terminal set to which the terminal belongs, and then A corresponding sequence is selected from the selected subset of sequences.
- the selecting module 382 may determine a sequence subset corresponding to the terminal set to which it belongs from the R sequence subsets by selecting the (Y+) from the R sequence subsets.
- the base station may configure a subsequence for the terminal set to which the terminal belongs, in combination with the Mod (Cell ID, R) described above as a remnant algorithm, that is, Y is a remainder obtained by dividing the Cell ID by R.
- the R sequence subsets may be respectively configured to R different terminal sets, that is, the sequence subset and the terminal set are in one-to-one correspondence.
- a sequence of sub-sets and terminal sets may also be a many-to-one or one-to-many relationship.
- the terminal set may be divided into multiple modes. The following describes different terminal set division modes:
- the two different terminal sets are the first terminal set and the second terminal set, and the first terminal set and the second terminal set satisfy at least one of the following conditions: the terminal included in the first terminal set A terminal that supports simultaneous transmission of multiple subcarriers, and the terminal included in the second terminal set is a terminal that supports only one subcarrier transmission; the terminal included in the first terminal set is a terminal that uses multiple subcarriers to transmit uplink data, and the second terminal The terminal included in the set is a terminal that transmits uplink data by using a single subcarrier; the terminal included in the first terminal set is a terminal that simultaneously transmits an Msg3 message by using multiple subcarriers, and the terminal included in the second terminal set transmits the Msg3 message by using a single subcarrier.
- the terminal included in the first terminal set is a terminal that transmits the Msg3 message on the multiple subcarriers, and the terminal included in the second terminal set is that the Msg3 message is only carried in the terminal of the single subcarrier transmission;
- the first terminal set includes a terminal support and a single sub-carrier transmission subcarrier spacing f sc1 terminal, the second terminal sets Comprising a terminal support and a single sub-carrier transmission subcarrier spacing f sc2 terminal; a first set of terminals including a terminal for the use of a single subcarrier for transmitting uplink data and the subcarrier spacing f sc1 terminal; a second set of terminals included
- the terminal is a terminal that uses a single subcarrier to transmit uplink data and has a subcarrier spacing of f sc2 ;
- the terminal included in the first terminal set is a terminal that transmits an Msg3 message by using a single subcarrier and has a subcarrier spacing of f
- the terminal included in the first terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc1 , and the second terminal is set.
- the terminal included is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc2 ;
- the terminal included in the first terminal set is a terminal in which the amount of information carried in the Msg3 message is Size1, and the second terminal set includes
- the terminal is a terminal that carries the amount of information in the Msg3 message is Size2, where Size1 is not equal to Size2;
- the three different terminal sets are the first terminal set, the second terminal set, and the third terminal set, and the first terminal set, the second terminal set, and the third terminal set satisfy at least the following conditions:
- the first terminal set includes terminals that support simultaneous transmission of multiple subcarriers
- the second terminal set includes terminals that support only a single subcarrier transmission and the subcarrier spacing is f sc1
- the third terminal set includes terminals.
- the terminal included in the first terminal set is a terminal that transmits uplink data by using multiple subcarriers
- the terminal included in the second terminal set transmits uplink data by using a single subcarrier.
- the terminal with the subcarrier spacing is f sc1 ;
- the terminal included in the third terminal set is a terminal that uses one subcarrier to transmit uplink data and the subcarrier spacing is f sc2 ;
- the terminal included in the first terminal set is to transmit the Msg3 message by using multiple subcarriers.
- the second terminal set includes terminals for transmitting Msg3 messages by using a single subcarrier and the subcarrier spacing is f
- the terminal of the sc1 , the terminal included in the third terminal set is a terminal that transmits the Msg3 message by using a single subcarrier and the subcarrier spacing is f sc2 ;
- the terminal included in the first terminal set is a terminal that the Msg3 message carries on the multiple subcarriers
- the terminal included in the second terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc1
- the terminal included in the third terminal set is that the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc2.
- the terminal included in the first terminal set is a terminal that has the information amount of the S1 in the Msg3 message
- the terminal in the second terminal set is a terminal that has the information amount of the S2 in the Msg3 message
- the third terminal set includes The terminal is a terminal that carries information in the Msg3 message with a size of Size3, where Size1, Size2, and Size3 are not equal to each other;
- the four different terminal sets are a first terminal set, a second terminal set, a third terminal set, and a fourth terminal set, and the first terminal set, the second terminal set, and the third terminal set.
- the fourth terminal set satisfies at least one of the following conditions: the terminal included in the first terminal set is a terminal that supports simultaneous transmission of multiple subcarriers and the subcarrier spacing is f sc1 , and the terminal included in the second terminal set supports simultaneous transmission of multiple subcarriers.
- the terminal with the subcarrier spacing is f sc2
- the terminal included in the third terminal set is a terminal supporting only a single subcarrier transmission and the subcarrier spacing is f sc3
- the terminal included in the fourth terminal set is only supporting a single subcarrier transmission and the sub
- the terminal with the carrier spacing is f sc4
- the terminal included in the first terminal set is a terminal that uses multiple subcarriers to transmit uplink data and the subcarrier spacing is f sc1
- the second terminal set includes terminals that use multiple subcarriers to transmit uplink data and carrier spacing for f sc2 set includes a terminal, a third terminal is a terminal using a single subcarrier, and the subcarrier for transmitting uplink data between F sc3 terminal; and a fourth set of terminals including a terminal for the use of a single subcarrier for transmitting uplink data and the subcarrier spacing f sc4 terminal; a first set of terminals including a terminal using
- the terminal includes a terminal that is a terminal that has a quantity of information carried in the Msg3 message, and a terminal that is included in the fourth terminal set is a terminal that has an information amount of Size4 in the Msg3 message, where Size1, Size2, Size3 Size4 is not equal to each other. It should be noted that the foregoing several terminal set division manners are only a few examples, and other reasonable division manners may also be used to divide the terminal set.
- the values of f sc1 and f sc2 are different.
- f sc1 can take a value of 15 kHz
- f sc2 can take a value of 3.75 kHz
- the above f sc3 and f sc4 have different values, for example, f sc3 can be The value is 15 kHz, and f sc4 can be 3.75 kHz.
- the types of the J sequences in the sequence set may be multiple.
- the above Satisfy at least one of the following: J of different values corresponding to Code j Mutual orthogonal code words, or quasi-orthogonal code words; mutually different values of j corresponding to Code j Mutual orthogonal code words, or quasi-orthogonal code words; mutually different values of j corresponding to Code j They are orthogonal code words, or mutually quasi-orthogonal code words, where 0 ⁇ i ⁇ N / 2-1.
- the value of N may be one of the following: 2, 4, 6, and 8.
- the J sequence sequence length N includes at least one of the following:
- the sequence of strip length N includes at least one of the following: Wherein one of Code 0 and Code 1 is configured to the terminal in the first terminal set, and the other is configured to the terminal in the second terminal set;
- sequence of J sequences of length N includes at least one of the following: Any three of them; Any three of them; wherein three sequences of sequence length N are respectively allocated to terminals in three terminal sets, that is, three sequences of sequence length N and three terminal sets can be configured in any one-to-one combination ;
- the sequence of J sequence lengths of N includes at least one of the following:
- the four sequences of length N are respectively allocated to the terminals in the four terminal sets, that is, four sequences of sequence length N and four terminal sets can be configured in any one-to-one combination;
- C is a constant,
- the generating module 384 may generate a random access signal by determining a subcarrier indexed as f n in the frequency domain and occupying consecutive K symbol transmissions in the time domain.
- the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is
- the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is Where 0 ⁇ k ⁇ K-1; at least according to Determine the random access signal.
- the generating module 384 may be configured as follows. Determine the random access signal: The corresponding time domain expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol, For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset; and/or, when the current domain sampling interval is T s , Corresponding time domain The expression is Where 0 ⁇ t ⁇ T k , T k is the length of the kth time domain symbol, 0 ⁇ k ⁇ K-1, 0 ⁇ q ⁇ Q-1, Number of samples in the time domain; the terminal is sent on consecutive K symbols
- the time domain expression is At least according to the above Determine the random access signal.
- L represents a time domain sample included in CP n
- the expression of the random access signal transmitted on N-1 is ⁇ Group 0 , Group 1 , ... Group N-1 ⁇ ; wherein Group n with different values of n occupy different symbols in the time domain.
- Group 0 to Group N-1 are unit units constituting the random access signal
- the sending module 386 may send a random access signal to the base station by: determining that a unit is random access. Signaling, and repeating the random access signal for H times; and/or, repeating the unit H times in the time domain to form a random access signal, and transmitting the random access signal.
- the interval of the time length Gap needs to be introduced, where the terminal is no longer in the interval of the Gap interval.
- the random access signal after the group n is sent, and the terminal continues to send the random access signal after the group n after the interval of the time length of the gap.
- the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz
- N gap Y / y.
- end start + y-1.
- the unit of measurement of the length of time; y ⁇ L_G + Gap T ⁇ TimeUnit, where L_G is the length of the Group, Gap ⁇ 0, T is a positive integer and T is the minimum value of T ⁇ TimeUnit > y ⁇ L_G, TimeUnit is a The unit of measure of the length of time.
- the TimeUnit may be seconds, milliseconds, microseconds, nanoseconds, frames, subframes, slots.
- the terminal after the terminal sends a random access signal of a unit, the terminal needs to introduce a time interval of Gap, where the terminal does not send the unit after the time interval is Gap.
- the random access signal the terminal continues to send the random access signal after the unit after the interval of the time length of Gap.
- the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz
- the bandwidth is 3.75 k
- the index of the H repetitions of the above unit is defined as Unit 0 to Unit H-1 , and the terminal completes the unit start to the unit end by a total of y units (the index numbers of the y units may be consecutive)
- the interval of the time length Gap needs to be introduced, wherein the terminal does not send the random access signal during the time interval of the gap, and the terminal continues to send after the interval of the time length of Gap. Random access signal after unit end ; where 0 ⁇ start ⁇ end ⁇ Y-1, y ⁇ Y.
- N gap Y / y.
- end start + y-1.
- the unit of measurement of the length of time; y ⁇ L_U + Gap T ⁇ TimeUnit, where L_G is the length of time of Unit, Gap ⁇ 0, T is a positive integer and T is the minimum value of T ⁇ TimeUnit > y ⁇ L_U, TimeUnit is A measure of the length of time.
- the TimeUnit may be seconds, milliseconds, microseconds, nanoseconds, frames, subframes, slots.
- the time domain length of CP n is 8192*Ts
- the subcarrier spacing or subcarrier bandwidth for transmitting the random access signal is 3.75 kHz.
- the subcarrier spacing or subcarrier bandwidth of the signal is 3.75 kHz
- the time domain length of CP n is 8192*Ts.
- the time domain of Gap is long.
- the value of the above H is determined according to at least the level of the terminal, that is, the H corresponding to the terminals of different levels may be different.
- the level of the foregoing terminal may include at least one of the following: an coverage enhancement level; a physical channel repetition transmission level; and a repeated transmission level of a message or signaling carried on the physical channel.
- the sending module 386 may send a random access signal to the base station by: determining a random access channel for transmitting the random access signal; and sending a random connection to the base station by using a random access channel.
- the random access channel used by the terminal to perform random access signal transmission may be part of a random access channel resource, and the random access channel resource may include multiple random accesses for different terminals. A random access channel for signal transmission.
- the random access channel resource includes one or more time-frequency resource sets Set m , where the set m includes F sub-carriers or sub-channels in the frequency domain, and the length is at least in the time domain.
- m is the index of Set m in the time domain
- F is a positive integer
- P is a positive integer.
- the random access channel resource may include a random access channel in which multiple terminals send random access signals, and the foregoing set m may be used by one terminal or may be used by multiple terminals. Or multiple Set m are used by one terminal.
- the Set m includes P subset subsets, wherein the subset is configured with the same subcarriers in the frequency domain as the Set m , and the subset has a length of 1 Unit in the time domain.
- the protection bandwidth is configured before and after the frequency resource occupied by the Set m , and/or the protection bandwidth is configured on the upper and lower sides of the frequency resource occupied by the Set m .
- a first time interval of a V-domain unit time between two adjacent Set m wherein, V is an integer
- the first unit of time comprises at least one of the following: one or more The time domain length of the frame, the time domain length of one or more subframes, Z 1 second, Z 2 milliseconds, the time domain length of Z 3 Set m , the time domain length of Z 4 Units, and the time domain of Z 5 subsets
- the configuration period of the Set m is L first time units, where L is a positive integer, and the first time unit includes at least one of: a time domain length of one or more frames Time domain length of one or more subframes, Z 1 second, Z 2 milliseconds, time domain length of Z 3 Set m , time domain length of Z 4 Units, time domain length of Z 5 subsets, where Z 1 , Z 2 , Z 3 , Z 4 , and Z 5 are all positive integers.
- L 2 z , where z is an integer greater than or equal to zero.
- 2 z first time units are continuously distributed or discretely distributed in the time domain; z is taken as ⁇ 0, 1, 2, 3, 4, 5, 6, 7 ⁇ ; time domain adjacent Two Set m occupy the same F subcarriers or subchannels in the frequency domain.
- the subset configuration scheme includes: the terminal with the level index g transmits the Repetition g times in the time domain, and configures consecutive Repetition g subsets for the terminal with the level index g in the configuration period of a Set m , and starts
- the subset index StartingSubsetIndex g is calculated according to the following formula: Where 0 ⁇ g ⁇ G-1, and G is the number of levels of the divided terminals.
- the configuration of the subset corresponding to the terminal with the level index g is the same between the configuration periods of different Set m .
- At most L 1 subsets are configured in the configuration period of the Set m , and the index of the subset is subset 0 to subset (L 1 -1), wherein the subset corresponding to the terminal with the level index g is
- the configuration scheme includes: the terminal with the level index g sends the Unit repeating Repetition g times in the time domain, and configures the consecutive ChanceNum g ⁇ Repetition g subsets for the terminal with the level index g, where ChanceNum g ⁇ 1.
- the starting subset index StartingSubsetIndex g in ChanceNum g ⁇ Repetition g subsets can be calculated according to the following formula: Where 0 ⁇ g ⁇ G-1, and G is the number of levels of the divided terminals.
- G may be the number of levels of the terminal configured by the base station, or may be the number of levels of the terminal that sends the random access signal on the Set m resource.
- the starting subset index is ChanceNum g ⁇ Repetition g subsets of StartingSubsetIndex g , and is configured with ChanceNum g first sending resources, where the first sending resource is used for Unit in the time domain.
- Repeat Repetition g times that is, Unit repeats Repetition g times in the time domain and can be executed on the first resource.
- the above-described ChanceNum g of first transmission resources in the c-th starting index of the first subset of transmission resources It can be calculated according to the following formula:
- At most L 1 subsets are configured in the configuration period of the Set m , and the index of the subset is subset 0 to subset (L 1 -1), wherein the terminal with the level index g corresponds to
- the subset configuration scheme includes: the terminal with the level index g sends the Unit repeating Repetition g times in the time domain, and the terminal with the level index g is configured with ChanceNum g ⁇ Repetition g subsets, and ChanceNum g ⁇ 1.
- ChanceNum g ⁇ Repetition g subset is a subset of the indices 0 to subset (ChanceNum g ⁇ Repetition g -1 ), and starts from the subset 0, continuous index
- the Repetition g subset is a first transmission resource, wherein the first transmission resource is used for the Unit to repeat the Repetition g transmission in the time domain, and the Repetition g subsets in the first transmission resource are continuously distributed in the time domain.
- the subsets corresponding to different first transmission resources are discretely distributed in the time domain.
- the first sending resource corresponding to the terminals of the G levels is included in the configuration period of the Set m , wherein the first sending resource corresponding to the terminal with the level index g is used for the Unit in the time domain.
- the first sending resource corresponding to the terminal with the level index g is N g Set m corresponding to the terminal whose index is g, 0 ⁇ g ⁇ G-1.
- the terminal sequentially allocates N g according to the rank index g from small to large. Resources.
- N g configured for the terminal with the level index g in the configuration period of Set m Two adjacent in the resource
- the time domain interval is L g second time units, where L g ⁇ 0.
- the N g corresponding to the terminals of different levels of indexing Between resources the interval L ⁇ is a second time unit, where L ⁇ ⁇ 0.
- N g of terminals corresponding to different levels of indexing The interval between resources L ⁇ second time units refers to the corresponding level of a terminal
- the resource corresponds to another level of terminal
- the interval between resources is L ⁇ second time units.
- the interval L g is a second time unit.
- the first time unit and the second time unit may be the same or different.
- the N g corresponding to the terminal whose rank index is g The first in the resource Time domain starting resource location with the stated The time domain starting resource location is the same in the configuration period; or the N g corresponding to the terminal with the level index g The first in the resource Time domain starting resource location with the stated There is an offset in the time domain starting resource location within the configuration period, wherein the offset is predetermined or configured for the base station.
- terminals of different levels of index correspond to the same.
- the length of the time domain In an alternative embodiment, the length of the arrangement period of the D Set m Set m, wherein, D is a positive integer.
- D 2 x and x is an integer greater than or equal to zero.
- a maximum of D*P subsets are configured in the configuration period of the Set m , and an index of the subset is a subset 0 to a subset (D*P-1), where the terminal with a level index of g corresponds to
- the subset configuration scheme includes: the terminal with the level index g is configured to repeat the Repetition g times in the time domain, and configure a continuous Repetition g subset for the terminal with the level index g in a configuration period of the set m , and
- the starting subset index StartingSubsetIndex g is calculated according to the following formula:
- G is the number of levels of the divided terminals.
- the configuration of the subset corresponding to the terminal with the level index g is the same between the configuration periods of different Set m .
- the subcarrier index is 0 to 47, where the index is 0, 1, 14, 15, 16, 17,
- the subcarriers of 30, 31, 32, 33, 46, 47 are not configured for Set m .
- the subcarriers are configured for the Set m .
- the meaning of "to” means “to”.
- the subcarriers with an index of 2 to 25 are 24 subcarriers whose indices are from 2 to 25. The following embodiments are similar and will not be described again.
- the subcarriers are configured for the Set m .
- the carrier is configured to the Set m .
- the ratio of the number of subcarriers Num occupied by the random access channel in the F subcarriers is Ratio, wherein the Ratio is sent by the base station to the signaling.
- the value of F above is ⁇ 12, 24, 36, 48 ⁇ .
- the value of the Ratio is ⁇ 1/6, 2/6, 3/6, 4/6, 5/6, 6/6 ⁇ or ⁇ 1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12, 9/12, 10/12, 11/12, 12/12 ⁇ or ⁇ 0/12, 1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12, 9/12, 10/12, 11/12, 12/12 ⁇ or ⁇ 0/6, 1/6, 2/6, 3/6, 4/6, 5/6, 6/6 ⁇ .
- the number of subcarriers occupied by the random access channel for transmitting the random access signal is Num.
- the value of F above is ⁇ 12, 24, 36, 48 ⁇ .
- the value of Num is ⁇ 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48 ⁇ or ⁇ 3, 6, 9, 12, 15 ,18,21,24,27,30,33,36,39,42,45,48 ⁇ or ⁇ 0,4,8,12,16,20,24,28,32,36,40,44,48 ⁇ or ⁇ 0,3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48 ⁇ .
- the random access channel that the terminal sends a random access signal to the base station is allocated by the base station to the terminal by using signaling.
- the signaling may include at least one of: signaling for a single terminal, signaling for a single terminal in a connected state, and signaling transmitted on a control channel.
- the signaling includes at least one of the following: a starting level index; frequency domain location information of the random access channel allocated by the base station to the terminal; and the random number allocated by the base station to the terminal Time domain location information of the access channel.
- the frequency domain location information of the random access channel allocated by the base station to the terminal includes: a subcarrier or a subchannel index where the group 0 of the unit that constitutes the random access signal is sent.
- the frequency domain resources of several groups other than Group 0 in the unit are indicated by the frequency domain location of Group 0 (for example, according to a predefined rule, determined according to the frequency domain of Group 0 ).
- the 6bits indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal.
- “000000” represents a Subcarrior whose index is 0, and the index "101111” represents a Subcarrior whose index is 47.
- the foregoing 6 bits indication information is further used to indicate that the terminal randomly selects one subcarrier among the F subcarriers in Set m as the frequency domain location where the random access channel is located. For example, “110000” may indicate that the terminal randomly selects one subcarrier among the F subcarriers in Set m as the frequency domain location where the random access channel is located.
- the indication information when included in Set m F subcarriers or subchannels, by The indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal. In this embodiment, Is the rounding operation operator.
- the indication information is further used to indicate that the terminal randomly selects one subcarrier among the F subcarriers in the Set m as the frequency domain location where the random access channel of the terminal is located.
- the indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal, where Num is the number of subcarriers occupied by the random access channel.
- the time domain location information of the random access channel allocated by the base station to the terminal includes: configuration period indication information n of the second Set m ; wherein the base station is allocated to the terminal Set m of the random access channel is defined as a second location Set m; the second Set m is selected from the first Set m; the length of the second period, and arranged Set m as a first configuration Set m n times the period, n is a positive integer; the first Set m is one or more time-frequency resource sets Set m included in the random access channel resource, and n is a positive integer.
- At least one of the following is included: when the value of n is described by 3 bits, the value of n is ⁇ 1, 2, 3, 4, 5, 6, 7, 8 ⁇ or ⁇ 1 , 2, 4, 8, 16, 32, 64, 128 ⁇ or ⁇ 1, 2, 4, 8, 10, 12, 14, 16 ⁇ ; when the value of n is described by 2 bits, the value of n is ⁇ 1,2,3,4 ⁇ or ⁇ 1,2,4,8 ⁇ or ⁇ 1,4,6,8 ⁇ .
- the time domain location of the random access channel allocated by the base station to the terminal is: the first first Set m in the configuration period of the second Set m .
- the base station assigned to the time domain location of the random access channel terminal is located further comprising: a second position information Offset Set m arranged in a period of the second Set m; wherein the Offset Set m for n first configuration in a second period indicative of Set m, allocated to the index information of the random access channel where the first terminal of the Set m.
- the base station assigned to the domain location information of the random access channel where a terminal comprising: a field interval information Interval Set m consecutive two second time; and the base station allocates to the terminal Set m of the random access channel is defined as a second location Set m; Set m between the second selected Set m from the first, and the second two consecutive first-Set m interval interval Set m
- the first set m is shown as one or more time-frequency resource sets Set m included in the random access channel resource.
- the signaling further includes: triggering positioning operation indication information. For example, “0” means that the positioning operation is not triggered; “1” means that the positioning operation is triggered.
- the terminal when the trigger location operation indication information is a trigger location operation, the terminal sends the random access signal on the signaling random access channel.
- the random access signal sent by the terminal is used by the base station to perform location location use of the terminal.
- the apparatus further includes a random access response receiving module, configured to: after the terminal sends the random access signal to the base station, the receiving base station detects the random access signal, according to the detection result. And the received random access response message, where the random access response message includes at least one of the following information: subcarrier spacing indication information; configured subcarrier number indication information.
- the subcarrier spacing indication information may be used to indicate the subcarrier spacing configuration when the Msg3 message is sent.
- the foregoing subcarrier spacing indication information and the configured subcarrier number indication information are connected Coding mode indication.
- each of the above modules may be implemented by software or hardware.
- the foregoing may be implemented by, but not limited to, the foregoing modules are all located in the same processor; or, the modules are located in multiple In the processor.
- Embodiments of the present invention also provide a storage medium.
- the foregoing storage medium may be configured to store program code for performing the following steps:
- the terminal selects a sequence corresponding to the terminal in the sequence set
- the foregoing terminal generates a random access signal according to at least a corresponding sequence.
- the terminal sends the random access signal to the base station.
- the foregoing storage medium may include, but is not limited to, a USB flash drive, a Read-Only Memory (ROM), and a Random Access Memory (RAM).
- ROM Read-Only Memory
- RAM Random Access Memory
- the processor performs the above steps according to the stored program code in the storage medium.
- modules or steps of the present invention described above can be implemented by a general-purpose computing device that can be centralized on a single computing device or distributed across a network of multiple computing devices. Alternatively, they may be implemented by program code executable by the computing device such that they may be stored in the storage device by the computing device and, in some cases, may be different from the order herein.
- the steps shown or described are performed, or they are separately fabricated into individual integrated circuit modules, or a plurality of modules or steps thereof are fabricated as a single integrated circuit module.
- the invention is not limited to any specific combination of hardware and software.
- an access processing method and apparatus provided by the embodiments of the present invention have the following beneficial effects: solving the problem that the related technologies cannot ensure that all types of terminals successfully access the system, thereby implementing various Types of terminals can successfully access the system.
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Abstract
The present invention provides an access processing method and apparatus. The method comprises: a terminal selects a sequence corresponding to the terminal in a sequence set; the terminal generates a random access signal at least according to the corresponding sequence; and the terminal sends the random access signal to a base station. By means of the present invention, the problem in the related art of failure to ensure a variety of terminals can all successfully access a system, thereby achieving the effect that the variety of terminals can all successfully access the system.
Description
本发明涉及通信领域,具体而言,涉及一种接入处理方法及装置。The present invention relates to the field of communications, and in particular to an access processing method and apparatus.
机器类型通信(Machine Type Communication,简称为MTC)用户终端(User Equipment,简称为UE)(以下简称为MTC UE),又称机器到机器(Machine to Machine,简称为M2M)用户终端,是现阶段物联网的主要应用形式。在第三代合作项目组织(The 3rd Generation Partnership Project,简称为3GPP)技术报告TR45.820V200中公开了几种适用于蜂窝级物联网的技术,其中,基于蜂窝的窄带物联网(Narrow Band Internet of Things,简称为NB-IoT)技术最为引人注目。考虑到物联网中支持的用户通信设备的数量是非常巨大的,支持的终端类型也会非常多,包括仅仅支持单个子载波基带处理能力的终端以及可以支持多个子载波基带处理能力的终端。那么基站如何能够保证各种类型的终端都成功接入系统,NB-IoT技术目前还缺乏一个有效的解决方案。Machine Type Communication (MTC) User Equipment (UE) (hereinafter referred to as MTC UE), also known as Machine to Machine (M2M) user terminal, is the current stage. The main application form of the Internet of Things. In the 3rd Generation Partnership Project (3GPP) Technical Report TR45.820V200, several technologies suitable for cellular-level Internet of Things are disclosed, in which a cellular-based narrowband Internet of Things (Narrow Band Internet of Things, referred to as NB-IoT, are the most compelling technologies. Considering that the number of user communication devices supported in the Internet of Things is very large, there are many types of terminals supported, including terminals that support only a single subcarrier baseband processing capability and terminals that can support multiple subcarrier baseband processing capabilities. Then how can the base station ensure that all types of terminals are successfully connected to the system, and NB-IoT technology currently lacks an effective solution.
针对相关技术中存在的无法保证各种类型的终端都成功接入系统的问题,目前尚未提出有效的解决方案。For the problem that the related technologies cannot guarantee that various types of terminals are successfully connected to the system, an effective solution has not been proposed yet.
发明内容Summary of the invention
本发明提供了一种接入处理方法及装置,以至少解决相关技术中存在的无法保证各种类型的终端都成功接入系统的问题。The present invention provides an access processing method and apparatus to solve at least the problem that the related technologies cannot guarantee that all types of terminals successfully access the system.
根据本发明的一个方面,提供了一种接入处理方法,包括:终端选择序列集合中与所述终端对应的序列;所述终端至少根据所述对应的序列生成随机接入信号;所述终端发送所述随机接入信号给基站。According to an aspect of the present invention, an access processing method is provided, including: selecting, by a terminal, a sequence corresponding to the terminal in a sequence set; the terminal generating a random access signal according to at least the corresponding sequence; Sending the random access signal to the base station.
可选地,所述序列集合中包括J条序列长度均为N的序列,其中,索引为j的序列的表达形式为J为正整数,N为正整数。Optionally, the sequence set includes a sequence of J sequences having a length of N, wherein the sequence of the index of j is expressed as J is a positive integer and N is a positive integer.
可选地,所述序列集合包括R个序列子集合,所述R个序列子集合配置给不同的终端集合;其中,R为正整数。Optionally, the sequence set includes R sequence subsets, and the R sequence subsets are configured to different terminal sets; where R is a positive integer.
可选地,所述终端选择序列集合中与所述终端对应的序列包括:所述终端从所述R个序列子集合中确定与自身所属的终端集合对应的序列子集合;所述终端从确定的序列子集合中选择一条序列作为所述对应的序列。
Optionally, the sequence corresponding to the terminal in the terminal selection sequence set includes: the terminal determining, from the R sequence subsets, a sequence subset corresponding to a terminal set to which the terminal belongs; the terminal determining One of the sequence sub-sets is selected as the corresponding sequence.
可选地,所述终端从所述R个序列子集合中确定与自身所属的终端集合对应的序列子集合包括:所述终端从所述R个序列子集合中选择第(Y+1)个序列子集合作为与自身所属的终端集合对应的序列子集合,其中Y=Mod(Cell ID,R),Cell ID为所述终端接入的小区标识索引。Optionally, the determining, by the terminal, the sequence sub-set corresponding to the terminal set to which the terminal belongs to the terminal includes: the terminal selecting the (Y+1)th of the R sequence sub-sets The sequence sub-set is a sequence sub-set corresponding to the terminal set to which the terminal belongs, where Y=Mod (Cell ID, R), and the Cell ID is the cell identity index accessed by the terminal.
可选地,所述R个序列子集合分别被配置给R个不同的终端集合。Optionally, the R sequence subsets are respectively configured to R different terminal sets.
可选地,所述方法包括以下至少之一:当终端集合的数量为2时,2个不同的终端集合为第一终端集合和第二终端集合,所述第一终端集合和所述第二终端集合满足以下条件至少之一:所述第一终端集合包括的终端为支持多个子载波同时传输的终端,且所述第二终端集合包括的终端为仅支持单个子载波传输的终端;所述第一终端集合包括的终端为采用多个子载波传输上行数据的终端,且所述第二终端集合包括的终端为采用单个子载波传输上行数据的终端;所述第一终端集合包括的终端为采用多个子载波同时传输Msg3消息的终端,且所述第二终端集合包括的终端为采用单个子载波传输Msg3消息的终端;所述第一终端集合包括的终端为Msg3消息承载在多个子载波上传输的终端,且所述第二终端集合包括的终端为Msg3消息仅承载在单个子载波传输的终端;所述第一终端集合包括的终端为支持单个子载波传输且子载波间隔为fsc1的终端,所述第二终端集合包括的终端为支持单个子载波传输且子载波间隔为fsc2的终端;所述第一终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc1的终端;所述第二终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc2的终端;所述第一终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc1的终端,所述第二终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc2的终端;所述第一终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc1的终端,所述第二终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc2的终端;所述第一终端集合包括的终端为Msg3消息中承载的信息量为Size1的终端,所述第二终端集合包括的终端为Msg3消息中承载的信息量为Size2的终端,其中,Size1不等于Size2;当终端集合的数量为3时,3个不同的终端集合为第一终端集合、第二终端集合和第三终端集合,所述第一终端集合、所述第二终端集合和所述第三终端集合满足以下条件至少之一:所述第一终端集合包括的终端为支持多个子载波同时传输的终端,所述第二终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc1的终端,所述第三终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc2的终端;所述第一终端集合包括的终端为采用多个子载波传输上行数据的终端,所述第二终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc1的终端;所述第三终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc2的终端;所述第一终端集合包括的终端为采用多个子载波传输Msg3消息的终端,所述第二终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc1的终端,所述第三终端集合包括的终端为采用单个子载波传输Msg3消息且子载波
间隔为fsc2的终端;所述第一终端集合包括的终端为Msg3消息承载在多个子载波上传输的终端,所述第二终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc1的终端,所述第三终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc2的终端;所述第一终端集合包括的终端为Msg3消息中承载的信息量为Size1的终端,所述第二终端集合包括的终端为Msg3消息中承载的信息量为Size2的终端,所述第三终端集合包括的终端为Msg3消息中承载的信息量为Size3的终端,其中,Size1、Size2、Size3互不相等;当终端集合的数量为4时,4个不同的终端集合为第一终端集合、第二终端集合、第三终端集合和第四终端集合,所述第一终端集合、所述第二终端集合、所述第三终端集合和所述第四终端集合满足以下条件至少之一:所述第一终端集合包括的终端为支持多个子载波同时传输且子载波间隔为fsc1的终端,所述第二终端集合包括的终端为支持多个子载波同时传输且子载波间隔为fsc2的终端,所述第三终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc3的终端,所述第四终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc4的终端;所述第一终端集合包括的终端为采用多个子载波传输上行数据且子载波间隔为fsc1的终端,所述第二终端集合包括的终端为采用多个子载波传输上行数据且子载波间隔为fsc2的终端,所述第三终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc3的终端;所述第四终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc4的终端;所述第一终端集合包括的终端为采用多个子载波传输Msg3消息且子载波间隔为fsc1的终端,所述第二终端集合包括的终端为采用多个子载波传输Msg3消息且子载波间隔为fsc2的终端,所述第三终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc3的终端,所述第四终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc4的终端;所述第一终端集合包括的终端为Msg3消息承载在多个子载波上传输且子载波间隔为fsc1的终端,所述第二终端集合包括的终端为Msg3消息承载在多个子载波上传输且子载波间隔为fsc2的终端,所述第三终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc3的终端,所述第四终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc4的终端;所述第一终端集合包括的终端为Msg3消息中承载的信息量为Size1的终端,所述第二终端集合包括的终端为Msg3消息中承载的信息量为Size2的终端,所述第三终端集合包括的终端为Msg3消息中承载的信息量为Size3的终端,所述第四终端集合包括的终端为Msg3消息中承载的信息量为Size4的终端,其中,Size1、Size2、Size3、Size4互不相等。Optionally, the method includes at least one of: when the number of terminal sets is 2, 2 different terminal sets are a first terminal set and a second terminal set, the first terminal set and the second The terminal set satisfies at least one of the following conditions: the terminal included in the first terminal set is a terminal that supports simultaneous transmission of multiple subcarriers, and the terminal included in the second terminal set is a terminal that supports only single subcarrier transmission; The terminal included in the first terminal set is a terminal that transmits uplink data by using multiple subcarriers, and the terminal included in the second terminal set is a terminal that transmits uplink data by using a single subcarrier; a terminal that simultaneously transmits an Msg3 message, and the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier; the terminal included in the first terminal set is a Msg3 message bearer transmitted on multiple subcarriers. Terminal, and the terminal included in the second terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission; The set of terminals comprising a terminal support and a single sub-carrier transmission subcarrier spacing f sc1 terminal, the second set of terminals including a terminal support and a single sub-carrier transmission subcarrier spacing f sc2 terminal; the first The terminal included in the terminal set is a terminal that transmits uplink data by using a single subcarrier and has a subcarrier spacing of f sc1 ; the terminal included in the second terminal set is a terminal that transmits uplink data by using a single subcarrier and has a subcarrier spacing of f sc2 ; The terminal included in the first terminal set is a terminal that uses a single subcarrier to transmit an Msg3 message and has a subcarrier spacing of f sc1 , and the second terminal set includes a terminal that uses a single subcarrier to transmit an Msg3 message and the subcarrier spacing is f. a terminal of the sc2 ; the terminal included in the first terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc1 , and the terminal included in the second terminal set is a Msg3 message carried only in a single sub a terminal that transmits a carrier and has a subcarrier spacing of f sc2 ; the terminal included in the first terminal set is that the amount of information carried in the Msg3 message is Si The terminal of the ze1, the terminal included in the second terminal set is a terminal that carries the amount of information in the Msg3 message is Size2, where Size1 is not equal to Size2; when the number of terminal sets is 3, three different terminal sets are a terminal set, a second terminal set, and a third terminal set, where the first terminal set, the second terminal set, and the third terminal set meet at least one of the following conditions: the first terminal set includes a terminal To support a terminal that transmits multiple subcarriers simultaneously, the terminal included in the second terminal set is a terminal that supports only a single subcarrier transmission and the subcarrier spacing is f sc1 , and the terminal included in the third terminal set only supports a single sub a terminal that is transmitted by a carrier and has a subcarrier spacing of f sc2 ; the terminal included in the first terminal set is a terminal that transmits uplink data by using multiple subcarriers, and the terminal included in the second terminal set transmits uplink data by using a single subcarrier and a terminal with a subcarrier spacing of f sc1 ; the terminal included in the third terminal set transmits uplink data by using a single subcarrier and the subcarrier spacing is f sc 2 terminal; the first terminal comprises a set of terminals using a plurality of subcarriers to transmit the message Msg3 terminal, said second terminal is a terminal set includes a single sub-carrier transmission using message Msg3 terminal and subcarrier spacing of f sc1 The terminal included in the third terminal set is a terminal that uses a single subcarrier to transmit an Msg3 message and the subcarrier spacing is f sc2 ; the terminal included in the first terminal set is a terminal that the Msg3 message carries on multiple subcarriers, The terminal included in the second terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc1 , and the terminal included in the third terminal set is that the Msg3 message is only carried in a single subcarrier transmission and the sub a terminal with a carrier spacing of f sc2 ; the terminal included in the first terminal set is a terminal that carries information in the Msg3 message is Size1, and the terminal included in the second terminal set is that the amount of information carried in the Msg3 message is Size2. The terminal includes a terminal that is included in the Msg3 message and whose amount of information is Size3, where Size1, Size2, and Size3 are different from each other. And when the number of terminal sets is 4, the four different terminal sets are a first terminal set, a second terminal set, a third terminal set, and a fourth terminal set, and the first terminal set, the second terminal The set, the third terminal set, and the fourth terminal set meet at least one of the following conditions: the terminal included in the first terminal set is a terminal that supports simultaneous transmission of multiple subcarriers and a subcarrier spacing of f sc1 , The second terminal set includes a terminal that supports simultaneous transmission of multiple subcarriers and a subcarrier spacing of f sc2 , and the terminal included in the third terminal set is a terminal that supports only a single subcarrier transmission and has a subcarrier spacing of f sc3 . The terminal included in the fourth terminal set is a terminal that supports only a single subcarrier transmission and the subcarrier spacing is f sc4 ; the terminal included in the first terminal set transmits uplink data by using multiple subcarriers and the subcarrier spacing is f sc1 terminal, the terminal comprises a second set of terminals using a plurality of sub-carriers to transmit the uplink data and the subcarrier spacing f sc2 terminal, the third terminal set Including using a single terminal is transmitting uplink data subcarriers and subcarrier spacing f sc3 terminal; said fourth set of terminals including a terminal for the use of a single subcarrier for transmitting uplink data and the subcarrier spacing f sc4 terminal; said The terminal included in the first terminal set is a terminal that uses multiple subcarriers to transmit Msg3 messages and the subcarrier spacing is f sc1 , and the second terminal set includes terminals that transmit Msg3 messages by using multiple subcarriers and the subcarrier spacing is f sc2 . a terminal, where the terminal included in the third terminal set is a terminal that transmits an Msg3 message by using a single subcarrier and has a subcarrier spacing of f sc3 , where the terminal included in the fourth terminal set transmits a Msg3 message by using a single subcarrier and the subcarrier spacing a terminal that is f sc4 ; the terminal that is included in the first terminal set is a terminal that transmits Msg3 messages on multiple subcarriers and has a subcarrier spacing of f sc1 , and the terminal included in the second terminal set is a Msg3 message bearer. and transmitting the subcarriers for the subcarrier spacing f sc2 terminal, the third terminal is a set of terminals included in the Msg3 message carries only a single sub- Wave transmission and the subcarrier spacing f sc3 terminal, said fourth terminal is a terminal set includes a message Msg3 carrying only a single sub-carrier transmission and the subcarrier spacing f sc4 terminal; the first set of terminals including a terminal And the terminal that is included in the Msg3 message is a terminal that is in the Msg3 message, and the terminal that is included in the Msg3 message is a terminal that is carried in the Msg3 message. The terminal having the information amount of Size3, the terminal included in the fourth terminal set is a terminal that carries the amount of information in the Msg3 message is Size4, where Size1, Size2, Size3, and Size4 are not equal to each other.
可选地,所述J条序列长度均为N的序列满足以下至少之一:所述J条序列长度均为N
的序列为正交码字序列;所述J条序列长度均为N的序列为准正交码字序列;所述J条序列长度均为N的序列为预定义的序列。Optionally, the sequence of the J sequences having a length of N satisfies at least one of the following: the length of the J sequences is N
The sequence is an orthogonal codeword sequence; the sequence in which the J sequences are all N is a quasi-orthogonal codeword sequence; and the sequence in which the J sequences are all N is a predefined sequence.
可选地,所述满足以下至少之一:不同取值的j对应的Codej中互为正交码字,或互为准正交码字;不同取值的j对应的Codej中互为正交码字,或互为准正交码字;不同取值的j对应的Codej中互为正交码字,或互为准正交码字,其中,0≤i≤N/2-1。Optionally, said Satisfy at least one of the following: J of different values corresponding to Code j Mutual orthogonal code words, or quasi-orthogonal code words; mutually different values of j corresponding to Code j Mutual orthogonal code words, or quasi-orthogonal code words; mutually different values of j corresponding to Code j They are orthogonal code words, or mutually quasi-orthogonal code words, where 0 ≤ i ≤ N / 2-1.
可选地,上述N的取值为以下之一:2,4,6,8。Optionally, the value of N is one of the following: 2, 4, 6, and 8.
可选地,当J=1,且N=4时,J条序列长度为N的序列包括以下至少之一:其中,A为C为常数,
Optionally, when J=1, and N=4, the J sequence sequence length N includes at least one of the following: Among them, A is C is a constant,
可选地,所述方法包括以下至少之一:当J=1,且N=4时,J条序列长度为N的序列包括以下至少之一:当R=2,J=2,且N=4时,J条序列长度为N的序列包括以下至少之一:
其中,Code0和Code1中的一个被配置给第一终端集合中的终端,另一个被配置给第二终端集合中的终端;当R=2,J=2,且N=8时,J条序列长度为N的序列包括以下至少之一:
其中,Code0和Code1中的一个被配置给第一终端集合中的终端,另一个被配置给第二终端集合中的终端;当R=3,J=3,且N=4时,J条序列长度为N的序列包括以下至少之一:
中任意3个;
中任意3个;其中,3条序列长度为N的序列被分别配置给3个终端集合中的终端;当R=4,J=4,且N=4时,J条序列长度为N的序列包括以下至少之一:
其中,4条序列长度为N的序列被分别配置给4个终端集合中的终端;其中,A为C为常数,
Optionally, the method includes at least one of the following: when J=1, and N=4, the J sequence sequence length N includes at least one of the following: When R=2, J=2, and N=4, the sequence of J sequence lengths of N includes at least one of the following: Wherein, one of Code 0 and Code 1 is configured to the terminal in the first terminal set, and the other is configured to the terminal in the second terminal set; when R=2, J=2, and N=8, J The sequence of strip length N includes at least one of the following: Wherein, one of Code 0 and Code 1 is configured to the terminal in the first terminal set, and the other is configured to the terminal in the second terminal set; when R=3, J=3, and N=4, J The sequence of strip length N includes at least one of the following: Any three of them; Any three of them; wherein three sequences of sequence length N are respectively allocated to terminals in three terminal sets; when R=4, J=4, and N=4, J sequences of sequence length N are N Includes at least one of the following: Wherein, four sequences of sequence length N are respectively allocated to terminals in the four terminal sets; wherein A is C is a constant,
可选地,当与所述终端对应的序列为时,所述终端至少根据所述对应的序列生成随机接入信号包括:所述终端确定频域上索引为fn的子载波且时域上占用连续的K个符号发送第k个符号且子载波fn上发送的信号的频域表达式为所述K个符号且子载波fn上发送的信号的频域表达式为其中,0≤k≤K-1;所述终端至少根据所述确定所述随机接入信号。Optionally, when the sequence corresponding to the terminal is And generating, by the terminal, the random access signal according to the corresponding sequence at least: the terminal determines a subcarrier with an index of f n in the frequency domain, and occupies consecutive K symbols in the time domain. The frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is The frequency domain expression of the K symbol and the signal transmitted on the subcarrier f n is Wherein, 0≤k≤K-1; the terminal is at least according to the Determining the random access signal.
可选地,所述终端至少根据所述确定所述随机接入信号包括:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度,为索引为fn的子载波占用的频域资源,FOffset为频域偏移量;和/或,当时域采样间隔为Ts时,对应的时域的表达式为其中,0≤t≤Tk,Tk为第k个时域符号的长度,0≤k≤K-1,0≤q≤Q-1,为时域采样点数量;所述终端在连续的K个符号上发送的时域表达式为所述终端至少根据所述确定所述随机接入信号。
Optionally, the terminal is at least according to the Determining the random access signal includes: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol, For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset; and/or, when the current domain sampling interval is T s , Corresponding time domain The expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol, 0 ≤ k ≤ K-1, 0 ≤ q ≤ Q-1, Number of samples in the time domain; the terminal is sent on consecutive K symbols The time domain expression is Said terminal according to at least said Determining the random access signal.
可选地,所述终端至少根据所述确定所述随机接入信号包括:所述终端按照下式生成循环前缀CPn,CPn={Sn[QK-L+1],…,Sn[QK]},L表示CPn中包括的时域采样间隔Ts的数量;则所述终端在子载波fn上发送的随机接入信号的表达式为Groupn={CPn,Sn},所述终端在子载波f0,f1,…,fN-1上发送的随机接入信号的表达式为{Group0,Group1,…GroupN-1};其中,n取值不同的Groupn在时域上占用不同的时域符号。Optionally, the terminal is at least according to the Determining the random access signal comprises: the terminal generating a cyclic prefix CP n according to the following formula, CP n ={S n [QK-L+1],...,S n [QK]}, where L indicates that the CP n is included The number of time domain sampling intervals T s ; then the expression of the random access signal transmitted by the terminal on the subcarrier f n is Group n = {CP n , S n }, and the terminal is in the subcarrier f 0 , The expression of the random access signal transmitted on f 1 , . . . , f N-1 is {Group 0 , Group 1 , ... Group N-1 }; wherein Group n with different values of n occupy different time domains. Time domain symbol.
可选地,Group0~GroupN-1为组成所述随机接入信号的单元Unit,所述终端发送所述随机接入信号给基站包括:所述终端确定一个所述Unit为所述随机接入信号,并将所述随机接入信号重复H次进行发送;和/或,所述终端将所述Unit在时域上重复H次形成所述随机接入信号,并发送所述随机接入信号。Optionally, the group 0 to the group N-1 are the unit units constituting the random access signal, and the terminal sending the random access signal to the base station includes: the terminal determining that the unit is the random connection Transmitting a signal and repeating the random access signal H times for transmission; and/or, the terminal repeating the unit H times in the time domain to form the random access signal, and transmitting the random access signal.
可选地,所述终端在子载波fn上发送完成随机接入信号Groupn之后,需要引入时间长度为Gap的间隔。Optionally, after the terminal sends the random access signal Group n on the subcarrier f n , the terminal needs to introduce an interval of a time length of Gap.
可选地,包括以下至少之一:当N=4,K=5,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,所述Gap的时域长度为0.4ms;当N=4,K=5,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,所述Gap的时域长度为0.6ms;当N=4,K=5,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;当N=4,K=5,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns。Optionally, at least one of the following is included: when N=4, K=5, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the Gap The length of the time domain is 0.4 ms; when N=4, K=5, the time domain length of CP n is 66.7 us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time of the Gap The length of the domain is 0.6ms; when N=4, K=5, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time domain length of Gap is 12288*Ts, where Ts=32.55 ns; when N=4, K=5, the time domain length of CP n is 2048*Ts, and the subcarrier spacing or subcarrier bandwidth for transmitting random access signals is 3.75 kHz, Gap The time domain length is 18432*Ts, where Ts=32.55 ns.
可选地,所述Unit的H次重复包括Y个Group,定义Y个Group的索引为Group0~GroupY-1,其中,Y=H*N;当所述终端完成Groupstart到Groupend一共y个Group的随机接入信号的发送之后,需要引入时间长度为Gap的间隔;其中,0≤start≤end≤Y-1,y≤Y。Optionally, the H repetitions of the unit include Y groups, and the indexes defining the Y groups are Group 0 to Group Y-1 , where Y=H*N; when the terminal completes the Group start to the Group end After the transmission of the random access signals of the y groups, it is necessary to introduce an interval of a time length of Gap; wherein, 0≤start≤end≤Y-1, y≤Y.
可选地,start=offset+y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量;offset为第一个Groupstart的索引的偏置量;或者,start=y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量。Optionally, start=offset+y×N gap , where N gap is the number of intervals in which the length of the introduction time is Gap; offset is the offset of the index of the first group start ; or, start=y×N gap Where N gap is the number of intervals in which the length of time is introduced as Gap.
可选地,end=start+y-1。
Optionally, end=start+y-1.
可选地,所述Gap满足以下条件至少之一:y×L_G+Gap=T×TimeUnit,其中,L_G为所述Group的时间长度,Gap≥0,T为正整数,TimeUnit为一种时间长度的度量单位;y×L_G+Gap=T×TimeUnit,其中L_G为所述Group的时间长度,Gap≥0,T为正整数且T为满足T×TimeUnit>y×L_G的最小值,TimeUnit为一种时间长度的度量单位。Optionally, the Gap satisfies at least one of the following conditions: y×L_G+Gap=T×TimeUnit, where L_G is the length of time of the group, Gap≥0, T is a positive integer, and TimeUnit is a length of time. Unit of measure; y × L_G + Gap = T × TimeUnit, where L_G is the length of time of the Group, Gap ≥ 0, T is a positive integer and T is the minimum value that satisfies T × TimeUnit > y × L_G, and TimeUnit is one The unit of measure of the length of time.
可选地,所述终端在发送完成一个所述Unit的随机接入信号之后,需要引入时间长度为Gap的间隔。Optionally, after the terminal sends a random access signal of the unit, it is required to introduce an interval of a time length of Gap.
可选地,包括以下至少之一:当N=4,K=5,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,所述Gap的时域长度为0.6ms;当N=4,K=5,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,所述Gap的时域长度为0.4ms;当N=4,K=5,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;当N=4,K=5,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns。Optionally, at least one of the following is included: when N=4, K=5, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the Gap The length of the time domain is 0.6 ms; when N=4, K=5, the time domain length of CP n is 66.7 us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time of the Gap The length of the domain is 0.4 ms; when N=4, K=5, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 18432*Ts, where Ts=32.55 ns; when N=4, K=5, the time domain length of CP n is 2048*Ts, and the subcarrier spacing or subcarrier bandwidth for transmitting random access signals is 3.75 kHz, Gap The time domain length is 12288*Ts, where Ts=32.55 ns.
可选地,定义所述Unit的H次重复的索引为Unit0~UnitH-1,当所述终端完成Unitstart到Unitend一共y个Unit的随机接入信号发送之后,需要引入时间长度为Gap的间隔;其中,0≤start≤end≤Y-1,y≤Y。Optionally, the H-repetition index of the unit is defined as Unit 0 to Unit H-1 . After the terminal completes the unit start to unit end, a total of y units of random access signals are sent, and the length of time required to be introduced is The interval of Gap; where 0≤start≤end≤Y-1, y≤Y.
可选地,start=offset+y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量;offset为第一个Unitstart的索引的偏置量;或者,start=y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量。Optionally, start=offset+y×N gap , where N gap is the number of intervals in which the length of the introduction time is Gap; offset is the offset of the index of the first unit start ; or, start=y×N gap Where N gap is the number of intervals in which the length of time is introduced as Gap.
可选地,end=start+y-1。Optionally, end=start+y-1.
可选地,所述Gap满足以下条件至少之一:y×L_U+Gap=T×TimeUnit,其中,L_G为所述Unit的时间长度,gap≥0,T为正整数,TimeUnit为一种时间长度的度量单位;y×L_U+Gap=T×TimeUnit,其中,L_G为所述Unit的时间长度,Gap≥0,T为正整数且T为满足T×TimeUnit>y×L_U的最小值,TimeUnit为一种时间长度的度量单位。Optionally, the Gap satisfies at least one of the following conditions: y×L_U+Gap=T×TimeUnit, where L_G is the length of time of the unit, gap≥0, T is a positive integer, and TimeUnit is a length of time. The unit of measurement; y × L_U + Gap = T × TimeUnit, where L_G is the length of time of the Unit, Gap ≥ 0, T is a positive integer and T is the minimum value that satisfies T × TimeUnit > y × L_U, TimeUnit is A measure of the length of time.
可选地,包括以下至少之一:当N=4,K=5,H=1,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,
Ts=32.55ns;当N=4,K=5,H=2,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为6144*Ts或36864*Ts,其中,Ts=32.55ns;当N=4,K=5,H=4,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;当N=4,K=5,H=8,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为24576*Ts,其中,Ts=32.55ns;当N=4,K=5,H=16,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;当N=4,K=5,H=1,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;当N=4,K=5,H=2,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为24576*Ts,其中,Ts=32.55ns;当N=4,K=5,H=4,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;当N=4,K=5,H=8,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为6144*Ts或36864*Ts,其中,Ts=32.55ns;当N=4,K=5,H=16,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;当N=4,K=5,H=1,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.6ms;当N=4,K=5,H=2,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.2ms或1.2ms;当N=4,K=5,H=4,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.4ms;当N=4,K=5,H=8,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.8ms;当N=4,K=5,H=16,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.6ms;当N=4,K=5,H=1,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.4ms;当N=4,K=5,H=2,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.8ms;当N=4,K=5,H=4,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.6ms;当N=4,K=5,H=8,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.2ms或1.2ms;当N=4,K=5,H=16,CPn的
时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.4ms。Optionally, at least one of the following is included: when N=4, K=5, H=1, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth for transmitting the random access signal is 3.75 kHz. The time domain length of Gap is 18432*Ts, where Ts=32.55 ns; when N=4, K=5, H=2, the time domain length of CP n is 8192*Ts, and the sender of the random access signal is sent. When the carrier spacing or subcarrier bandwidth is 3.75 kHz, the time domain length of Gap is 6144*Ts or 36864*Ts, where Ts=32.55 ns; when N=4, K=5, H=4, the time domain of CP n The length is 8192*Ts. When the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 12288*Ts, where Ts=32.55 ns; when N=4, K=5, H=8, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 24576*Ts, where Ts=32.55 ns; When N=4, K=5, H=16, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 18432*. Ts, where Ts=32.5 5 ns; when N=4, K=5, H=1, the time domain length of CP n is 2048*Ts, and the sub-carrier spacing or sub-carrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 12288*Ts, where Ts=32.55 ns; when N=4, K=5, H=2, the time domain length of CP n is 2048*Ts, and the subcarrier spacing or subcarrier bandwidth for transmitting random access signals is 3.75. In kHz, the time domain length of Gap is 24576*Ts, where Ts=32.55 ns; when N=4, K=5, H=4, the time domain length of CP n is 2048*Ts, and the random access signal is transmitted. When the subcarrier spacing or subcarrier bandwidth is 3.75 kHz, the time domain length of Gap is 18432*Ts, where Ts=32.55 ns; when N=4, K=5, H=8, the time domain length of CP n is 2048. *Ts, when the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 6144*Ts or 36864*Ts, where Ts=32.55 ns; when N=4, K=5 , H=16, the time domain length of CP n is 2048*Ts. When the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 12288*Ts, where Ts=32.55 ns. ; when N=4, K=5, H=1, C The time domain length of P n is 266.7us. When the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time domain length of Gap is 0.6ms; when N=4, K=5, H=2, The time domain length of CP n is 266.7us. When the subcarrier spacing or subcarrier bandwidth for transmitting random access signals is 3.75kHz, the time domain length of Gap is 0.2ms or 1.2ms; when N=4, K=5, H =4, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time domain length of Gap is 0.4ms; when N=4, K=5, H =8, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time domain length of Gap is 0.8ms; when N=4, K=5, H =16, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time domain length of Gap is 0.6ms; when N=4, K=5, H =1, the time domain length of CP n is 66.7us, and when the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 0.4 ms; when N=4, K=5, H = 2, CP n of Field length of 66.7us, when transmitting a random access signal or subcarrier spacing subcarrier bandwidth is 3.75kHz, the time domain Gap length is 0.8ms; if N = 4, K = 5, H = 4, when the CP n The length of the domain is 66.7us. When the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time domain length of Gap is 0.6ms. When N=4, K=5, H=8, CP n The length of the domain is 66.7us. When the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time domain length of Gap is 0.2ms or 1.2ms. When N=4, K=5, H=16, CP The time domain length of n is 66.7us, and the time domain length of Gap is 0.4ms when the subcarrier spacing or subcarrier bandwidth for transmitting random access signals is 3.75kHz.
可选地,所述H的取值至少根据所述终端的等级确定。Optionally, the value of the H is determined according to at least a level of the terminal.
可选地,所述终端的等级包括以下至少之一:覆盖增强等级;物理信道重复发送等级;物理信道上承载的消息或信令的重复发送等级。Optionally, the level of the terminal includes at least one of: a coverage enhancement level; a physical channel repetition transmission level; and a repeated transmission level of a message or signaling carried on the physical channel.
可选地,所述终端发送所述随机接入信号给所述基站包括:所述终端确定用于发送所述随机接入信号的随机接入信道;所述终端通过所述随机接入信道向所述基站发送所述随机接入信号。Optionally, the sending, by the terminal, the random access signal to the base station includes: determining, by the terminal, a random access channel for sending the random access signal; and using, by using the random access channel, the terminal The base station transmits the random access signal.
可选地,随机接入信道资源包括一个或多个时频资源集合Setm,其中,所述Setm在频域上包括F个子载波或子信道,在时域上长度至少为P个Unit的长度,m为所述Setm在时域的索引,F为正整数,P为正整数。Optionally, the random access channel resource includes one or more time-frequency resource sets Set m , wherein the Set m includes F sub-carriers or sub-channels in the frequency domain, and has a length of at least P units in the time domain. The length, m is the index of the Set m in the time domain, F is a positive integer, and P is a positive integer.
可选地,所述Setm包括P个子集subset,其中,所述subset在频域上与所述Setm配置相同的子载波,所述subset在时域上长度为1个Unit的长度。Optionally, the Set m includes P subset subsets, wherein the subset is configured with the same subcarriers in the frequency domain as the Set m , and the subset has a length of 1 Unit in the time domain.
可选地,当子载波间隔为3.75kHz,F=12时,在所述Setm占用的频率资源的前后频率资源上各配置有7.5kHz保护带宽;和/或,当子载波间隔为3.75kHz,F=16时,在所述Setm占用的频率资源中上下边带各预留有7.5kHz保护带宽。Optionally, when the subcarrier spacing is 3.75 kHz and F=12, a 7.5 kHz protection bandwidth is configured on each of the frequency resources of the frequency resource occupied by the Set m ; and/or when the subcarrier spacing is 3.75 kHz. When F=16, the upper and lower sidebands each reserve a 7.5 kHz protection bandwidth in the frequency resource occupied by the Set m .
可选地,当上行带宽包括48个子载波,且F=12时,上行带宽最多配置4个Setm,且每个Setm在频域上包括F=12个子载波或子信道,不同Setm在频域上包括的子载波或子信道不重叠。Optionally, when the uplink bandwidth includes 48 subcarriers, and F=12, the uplink bandwidth is configured with a maximum of 4 Set m , and each Set m includes F=12 subcarriers or subchannels in the frequency domain, and different Set m is in the Subcarriers or subchannels included in the frequency domain do not overlap.
可选地,通过U个比特信息指示为同一个等级的终端或终端组分配的Setm的频域位置,其中,不同等级的终端配置的Setm的频域位置相同,U=2或4。Alternatively, by the U-bit information indicating a frequency domain location of the terminal or group of terminals assigned the same level Set m, wherein the different levels of the same terminal configuration of the frequency domain position Set m, U = 2 or 4.
可选地,当上行带宽包括48个子载波,且F=16时,上行带宽最多配置3个Setm,且每个Setm在频域上包括F=16个子载波或子信道,不同Setm在频域上包括的子载波或子信道不重叠。Optionally, when the uplink bandwidth includes 48 subcarriers, and F=16, the uplink bandwidth is configured with a maximum of 3 Set m , and each Set m includes F=16 subcarriers or subchannels in the frequency domain, and different Set m Subcarriers or subchannels included in the frequency domain do not overlap.
可选地,通过U个比特信息指示为同一个等级的终端或终端组分配的Setm的频域位置,其中,不同等级的终端配置的Setm的频域位置相同,U=2或3。
Alternatively, by the U-bit information indicating a frequency domain location of the terminal or group of terminals assigned the same level Set m, wherein the different levels of the same terminal configuration of the frequency domain position Set m, U = 2 or 3.
可选地,所述方法包括以下至少之一:当N=4,K=5时,所述Setm在时域上长度为7ms,所述CPn的时域长度为266.7us,P=1;当N=4,K=5时,所述Setm在时域上长度为13ms,所述CPn的时域长度为266.7us,P=2;当N=8,K=5时,所述Setm在时域上长度为13ms,所述CPn的时域长度为266.7us,P=1;当N=4,K=5时,所述Setm在时域上长度为26ms,所述CPn的时域长度为266.7us,P=4;当N=8,K=5时,所述Setm在时域上长度为26ms,所述CPn的时域长度为266.7us,P=2;当N=4,K=5时,所述Setm在时域上长度为32ms,所述CPn的时域长度为266.7us,P=5;当N=4,K=5时,所述Setm在时域上长度为64ms,所述CPn的时域长度为266.7us,P=10;当N=8,K=5时,所述Setm在时域上长度为64ms,所述CPn的时域长度为266.7us,P=5;当N=4,K=5时,所述Setm在时域上长度为6ms,所述CPn的时域长度为66.7us,P=1;当N=4,K=5时,所述Setm在时域上长度为12ms,所述CPn的时域长度为66.7us,P=2;当N=8,K=5时,所述Setm在时域上长度为12ms,所述CPn的时域长度为66.7us,P=1;当N=4,K=5时,所述Setm在时域上长度为17ms,所述CPn的时域长度为66.7us,P=3;当N=4,K=5时,所述Setm在时域上长度为23ms,所述CPn的时域长度为66.7us,P=4;当N=8,K=5时,所述Setm在时域上长度为23ms,所述CPn的时域长度为66.7us,P=2;当N=4,K=5时,所述Setm在时域上长度为28ms,所述CPn的时域长度为66.7us,P=5;当N=4,K=5时,所述Setm在时域上长度为34ms,所述CPn的时域长度为66.7us,P=6;当N=8,K=5时,所述Setm在时域上长度为34ms,所述CPn的时域长度为66.7us,P=3。Optionally, the method includes at least one of the following: when N=4, K=5, the set m is 7 ms in the time domain, and the time domain length of the CP n is 266.7 us, P=1. When N=4, K=5, the set m has a length of 13 ms in the time domain, the time domain length of the CP n is 266.7 us, P=2; when N=8, K=5, The set m has a length of 13 ms in the time domain, the time domain length of the CP n is 266.7 us, P=1; when N=4, K=5, the set m has a length of 26 ms in the time domain. The time domain length of CP n is 266.7us, P=4; when N=8, K=5, the length of the Set m is 26ms in the time domain, and the time domain length of the CP n is 266.7us, P =2; when N=4, K=5, the set m has a length of 32 ms in the time domain, the time domain length of the CP n is 266.7 us, P=5; when N=4, K=5 The set m has a length of 64 ms in the time domain, the time domain length of the CP n is 266.7 us, P=10; when N=8, K=5, the set m has a length of 64 ms in the time domain. The time domain length of the CP n is 266.7us, P=5; when N=4, K=5, the set m is 6ms in the time domain, and the time domain length of the CP n is 66.7u. s, P=1; when N=4, K=5, the set m has a length of 12 ms in the time domain, the time domain length of the CP n is 66.7 us, P=2; when N=8, K When set to 5, the set m has a length of 12 ms in the time domain, the time domain length of the CP n is 66.7 us, P=1; when N=4, K=5, the set m is in the time domain. The length of the CP n is 66.7us, P=3; when N=4, K=5, the length of the Set m is 23ms in the time domain, and the time domain length of the CP n 66.7us, P=4; when N=8, K=5, the set m is 23ms in the time domain, the time domain length of the CP n is 66.7us, P=2; when N=4 When K=5, the set m has a length of 28 ms in the time domain, the time domain length of the CP n is 66.7 us, P=5; when N=4, K=5, the set m is at the time The length of the domain is 34 ms, the time domain length of the CP n is 66.7 us, P=6; when N=8, K=5, the length of the Set m is 34 ms in the time domain, and the time of the CP n The domain length is 66.7us, P=3.
可选地,所述的方法包括以下至少之一:当N=4,K=5时,所述Setm在时域上长度为7ms时,所述随机接入信道资源包括0.6ms的保护时间;当N=4,K=5时,所述Setm在时域上长度为26ms时,所述随机接入信道资源包括0.4ms的保护时间;当N=8,K=5时,所述Setm在时域上长度为26ms时,所述随机接入信道资源包括0.4ms的保护时间;当N=4,K=5时,所述Setm在时域上长度为6ms时,所述随机接入信道资源包括0.4ms的保护时间;当N=4,K=5时,所述Setm在时域上长度为12ms时,所述随机接入信道资源包括0.8ms的保护时间;当N=8,K=5时,所述Setm在时域上长度为12ms时,所述随机接入信道资源包括0.8ms的保护时间;当N=4,K=5时,所述Setm在时域上长度为17ms时,所述随机接入信道资源包括0.2ms的保护时间;当N=4,K=5时,所述Setm在时域上长度为23ms时,所述随机接入信道资源
包括0.6ms的保护时间;当N=8,K=5时,所述Setm在时域上长度为23ms时,所述随机接入信道资源包括0.6ms的保护时间;当N=4,K=5时,所述Setm在时域上长度为34ms时,所述随机接入信道资源包括0.4ms的保护时间;当N=8,K=5时,所述Setm在时域上长度为34ms时,所述随机接入信道资源包括0.4ms的保护时间。Optionally, the method includes at least one of the following: when N=4, K=5, when the set m is 7 ms in the time domain, the random access channel resource includes a guard time of 0.6 ms. When N=4, K=5, when the set m is 26 ms in the time domain, the random access channel resource includes a guard time of 0.4 ms; when N=8, K=5, the When the set m is 26 ms in the time domain, the random access channel resource includes a guard time of 0.4 ms; when N=4, K=5, when the set m is 6 ms in the time domain, the The random access channel resource includes a guard time of 0.4 ms; when N=4, K=5, when the set m is 12 ms in the time domain, the random access channel resource includes a guard time of 0.8 ms; When N=8, K=5, when the set m has a length of 12 ms in the time domain, the random access channel resource includes a guard time of 0.8 ms; when N=4, K=5, the set m When the length in the time domain is 17 ms, the random access channel resource includes a guard time of 0.2 ms; when N=4, K=5, when the set m is 23 ms in the time domain, the random access Letter Resources include a guard time 0.6ms; when N = 8, K = 5, said Set m length in the time domain is 23ms, the random access channel resource comprises a guard time of 0.6ms; if N = 4, When K=5, when the set m has a length of 34 ms in the time domain, the random access channel resource includes a guard time of 0.4 ms; when N=8, K=5, the set m is in the time domain. When the length is 34 ms, the random access channel resource includes a guard time of 0.4 ms.
可选地,时域相邻的两个Setm之间间隔V个第一时间单位,其中,V为整数,所述第一时间单位包括以下至少之一:一个或多个帧的时域长度、一个或多个子帧的时域长度、Z1秒、Z2毫秒、Z3个Setm的时域长度,Z4个Unit的时域长度,其中,Z1、Z2、Z3、Z4均为正整数。Alternatively, the spacing between two adjacent time-domain Set m V of first time units, wherein, V is an integer, the first unit of time comprises at least one of: when one or more frames of field length Time domain length of one or more subframes, Z 1 second, Z 2 milliseconds, time domain length of Z 3 Set m , time domain length of Z 4 Units, where Z 1 , Z 2 , Z 3 , Z 4 are positive integers.
可选地,时域相邻的两个Setm之间间隔V个第一时间单位,其中,V为整数,所述第一时间单位包括Z5个subset的时域长度,其中,Z5为正整数。Optionally, V first time units are separated between two sets of m adjacent to each other in the time domain, where V is an integer, and the first time unit includes a time domain length of Z 5 subsets, where Z 5 is A positive integer.
可选地,所述方法包括以下至少之一:V的取值包括以下至少之一:V=0;V=2y,其中,y为大于或等于0的整数;所述V个第一时间单位在时域上连续分布或离散分布;所述时域相邻的两个Setm在频域上占用相同的所述F个子载波或子信道。Optionally, the method includes at least one of the following: the value of V includes at least one of: V=0; V=2 y , where y is an integer greater than or equal to 0; the V first time The units are continuously distributed or discretely distributed in the time domain; the two Set m adjacent to the time domain occupy the same F subcarriers or subchannels in the frequency domain.
可选地,Setm的配置周期为L个第一时间单位,其中,L为正整数,所述第一时间单位包括以下至少之一:一个或多个帧的时域长度、一个或多个子帧的时域长度、Z1秒、Z2毫秒、Z3个Setm的时域长度,Z4个Unit的时域长度,其中,Z1、Z2、Z3、Z4均为正整数。Optionally, the configuration period of Set m is L first time units, where L is a positive integer, and the first time unit includes at least one of: a time domain length of one or more frames, one or more sub- The time domain length of the frame, Z 1 second, Z 2 milliseconds, the time domain length of Z 3 Set m , the time domain length of Z 4 Units, where Z 1 , Z 2 , Z 3 , Z 4 are positive integers .
可选地,Setm的配置周期为L个第一时间单位,其中,L为正整数,所述第一时间单位包括Z5个subset的时域长度,Z5为正整数。Alternatively, Set m arranged a first period of L time units, where, L is a positive integer, said first unit of time length field comprises a subset of Z 5, Z 5 being a positive integer.
可选地,L=2z,其中,z为大于或等于0的整数。Alternatively, L = 2 z , where z is an integer greater than or equal to zero.
可选地,所述方法包括以下至少之一:所述2z个第一时间单位在时域上连续分布或离散分布;z取值为{0,1,2,3,4,5,6,7};时域相邻的两个Setm在频域上占用相同的所述F个子载波或子信道。Optionally, the method includes at least one of: the 2 z first time units are continuously distributed or discretely distributed in the time domain; and the z values are {0, 1, 2, 3, 4, 5, 6 , 7}; two Set m adjacent in the time domain occupy the same F subcarriers or subchannels in the frequency domain.
可选地,在所述Setm的配置周期内最多配置L1个所述subset,所述subset的索引为subset0至subset(L1-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将所述Unit在时域上重复Repetitiong次发送,在一个所述Setm的配置周期内,为等级
索引为g的终端配置连续的Repetitiong个subset,且起始subset索引StartingSubsetIndexg按照下面公式计算:其中,0≤g≤G-1,G为划分的终端的等级的数量。Optionally, at least one of the subsets is configured in a configuration period of the Set m , and an index of the subset is a subset0 to a subset (L 1 -1), wherein a subset configuration corresponding to a terminal with a level index g The solution includes: the terminal with the level index g is configured to repeat the Repetition g times in the time domain, and configure a continuous Repetition g subset for the terminal with the level index g in a configuration period of the Set m , and The starting subset index StartingSubsetIndex g is calculated according to the following formula: Where 0 ≤ g ≤ G-1, and G is the number of levels of the divided terminals.
可选地,不同的Setm的配置周期之间,等级索引为g的终端对应的subset配置方案是相同的。Optionally, the configuration of the subset corresponding to the terminal with the level index g is the same between the configuration periods of different Set m .
可选地,在所述Setm的配置周期内最多配置L1个所述subset,所述subset的索引为subset0至subset(L1-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将所述Unit在时域上重复Repetitiong次发送,且为所述等级索引为g的终端配置连续的ChanceNumg×Repetitiong个subset,其中ChanceNumg≥1。Optionally, at least one of the subsets is configured in a configuration period of the Set m , and an index of the subset is a subset0 to a subset (L 1 -1), wherein a subset configuration corresponding to a terminal with a level index g The solution includes: the terminal with the level index g sends the unit repeating Repetition g times in the time domain, and configures the terminal with the level index g to consecutive consecutive ChanceNum g ×Repetition g subsets, where ChanceNum g ≥1.
可选地,在一个所述Setm的配置周期内,所述ChanceNumg×Repetitiong个subset中起始subset索引StartingSubsetIndexg按照下面公式计算:其中,0≤g≤G-1,G为划分的终端的等级的数量。Optionally, in a configuration period of the Set m , the starting subset index StartingSubsetIndex g in the ChanceNum g ×Repetition g subsets is calculated according to the following formula: Where 0 ≤ g ≤ G-1, and G is the number of levels of the divided terminals.
可选地,起始subset索引为StartingSubsetIndexg的ChanceNumg×Repetitiong个subset中,配置有ChanceNumg个第一发送资源,其中,所述第一发送资源用于所述Unit在时域上重复Repetitiong次发送。Alternatively, the starting index subset ChanceNum g × Repetition g in a subset StartingSubsetIndex g disposed ChanceNum g of first transmission resource, wherein the first transmission resource for the Unit Repetition repeated in the time domain G times to send.
可选地,所述ChanceNumg个第一发送资源中的第c个第一发送资源的起始subset索引按照下面公式计算:
Alternatively, the starting index of the subset of first transmission resource ChanceNum g in the c-th first transmission resources Calculate according to the following formula:
可选地,在所述Setm的配置周期内最多配置L1个所述subset,所述subset的索引为subset0至subset(L1-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将所述Unit在时域上重复Repetitiong次发送,且所述等级索引为g的终端配置有
ChanceNumg×Repetitiong个subset,ChanceNumg≥1。Optionally, at least one of the subsets is configured in a configuration period of the Set m , and an index of the subset is a subset0 to a subset (L 1 -1), wherein a subset configuration corresponding to a terminal with a level index g The solution includes: the terminal with the level index g sends the unit to repeat the Repetition g times in the time domain, and the terminal with the level index g is configured with ChanceNum g ×Repetition g subsets, and ChanceNum g ≥1.
可选地,在一个所述Setm的配置周期内,所述ChanceNumg×Repetitiong个subset的索引为subset 0至subset(ChanceNumg×Repetitiong-1),且从subset 0开始,索引连续的Repetitiong个subset为一个第一发送资源,其中,所述第一发送资源用于所述Unit在时域上重复Repetitiong次发送,一个所述第一发送资源内的Repetitiong个subset在时域上连续分布,不同的所述第一发送资源对应的subset在时域上离散分布。Alternatively, the configuration within a period of Set m, the ChanceNum g × Repetition g subset is a subset of the indices 0 to subset (ChanceNum g × Repetition g -1 ), and start from 0 subset index contiguous Repetition g subsets is a first sending resource, wherein the first sending resource is used by the unit to repeat Repetition g times in the time domain, and one Repetition g subset in the first sending resource is in the time domain. The packets are consecutively distributed, and different subsets corresponding to the first sending resource are discretely distributed in the time domain.
可选地,在所述Setm的配置周期内包括G个等级的终端对应的第一发送资源,其中,等级索引为g的终端对应的所述第一发送资源用于所述Unit在时域上重复Repetitiong次发送,等级索引为g的终端对应的所述第一发送资源大小为Ng个
为级索引为g的终端对应的Setm,0≤g≤G-1。Optionally, the first sending resource corresponding to the terminal of the G level is included in the configuration period of the Set m , where the first sending resource corresponding to the terminal with the level index g is used in the time domain of the unit. Repeating the Repetition g times, the first sending resource corresponding to the terminal with the level index g is N g Set m corresponding to the terminal whose index is g, 0 ≤ g ≤ G-1.
可选地,在所述Setm的配置周期内,终端按照等级索引g由小到大的顺序依次分配有Ng个资源。Optionally, in the configuration period of the Set m , the terminal sequentially allocates N g according to the rank index g from small to large. Resources.
可选地,Ng≥1或Ng≥0,且当Ng=0时,表示在所述Setm的配置周期内没有配置等级索引为g的终端对应的所述第一发送资源。Optionally, N g ≥ 1 or N g ≥ 0, and when N g =0, indicating that the first transmission resource corresponding to the terminal with the level index g is not configured in the configuration period of the Set m .
可选的,在所述Setm的配置周期内,为等级索引为g的终端配置的Ng个资源中相邻的两个之间时域间隔为Lg个第二时间单位,其中,Lg≥0。Optionally, in the configuration period of the Set m , N g configured for the terminal with the level index g Two adjacent in the resource The time domain interval is L g second time units, where L g ≥ 0.
可选的,不同等级索引的终端对应的Lg相同。Optionally, terminals of different levels of indexing have the same L g .
可选的,在所述Setm的配置周期内,不同等级索引的终端对应的Ng个资源之间,间隔Lβ个第二时间单位,其中,Lβ≥0。Optionally, in the configuration period of the Set m , N g corresponding to the terminals of different levels of indexing Between resources, the interval L β is a second time unit, where L β ≥ 0.
可选的,在所述Setm的配置周期内,不同等级索引的终端对应的Ng个资源之间,间隔Lg个第二时间单位。Optionally, in the configuration period of the Set m , N g corresponding to the terminals of different levels of indexing Between resources, the interval L g is a second time unit.
可选的,等级索引为g的终端对应的Ng个资源中第一个的时域起始资源位置与所述的配置周期内时域起始资源位置相同;或者,等级索引为g的终端对应的Ng个
资源中第一个的时域起始资源位置与所述的配置周期内时域起始资源位置存在偏移量,其中,所述偏移量为预定的或者为基站配置的。Optionally, N g corresponding to the terminal with the level index g The first in the resource Time domain starting resource location with the stated The time domain starting resource location is the same in the configuration period; or the N g corresponding to the terminal with the level index g The first in the resource Time domain starting resource location with the stated There is an offset in the time domain starting resource location within the configuration period, wherein the offset is predetermined or configured for the base station.
可选地,所述Setm的配置周期长度为D个Setm的时域长度,其中,D为正整数。Alternatively, the configuration of the cycle length D Set m is the length of the time domain Set m, wherein, D is a positive integer.
可选地,D=2x,x为大于或等于0的整数。Optionally, D = 2 x , x is an integer greater than or equal to zero.
可选地,在所述Setm的配置周期内最多配置D*P个所述subset,所述subset的索引为subset0至subset(D*P-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将所述Unit在时域上重复Repetitiong次发送,在一个所述Setm的配置周期内,为等级索引为g的终端配置连续的Repetitiong个subset,且起始subset索引StartingSubsetIndexg按照下面公式计算:其中,0≤g≤G-1,G为划分的终端的等级的数量。Optionally, a maximum of D*P of the subsets are configured in a configuration period of the set m , and an index of the subset is a subset0 to a subset (D*P-1), where a terminal with a level index of g corresponds to The subset configuration scheme includes: the terminal with the level index g sends the unit to repeat the Repetition g times in the time domain, and configures a continuous Repetition g subset for the terminal with the level index g in a configuration period of the Set m . And the starting subset index StartingSubsetIndex g is calculated according to the following formula: Where 0 ≤ g ≤ G-1, and G is the number of levels of the divided terminals.
可选地,不同的所述Setm的配置周期之间,等级索引为g的终端对应的subset配置方案是相同的。Optionally, between different configuration periods of the Set m , the subset configuration scheme corresponding to the terminal with the level index g is the same.
可选地,当上行带宽包括48个子载波间隔为3.75kHz的子载波时,所述子载波索引为0~47,其中,索引为0,1,14,15,16,17,30,31,32,33,46,47的子载波不配置给所述Setm。Optionally, when the uplink bandwidth includes 48 subcarriers with a subcarrier spacing of 3.75 kHz, the subcarrier index is 0 to 47, where the index is 0, 1, 14, 15, 16, 17, 30, 31, The subcarriers of 32, 33, 46, 47 are not allocated to the Set m .
可选地,当上行带宽包括48个子载波,所述子载波索引为0~47,F=24,且所述Setm的起始子载波索引为2时,索引为2~25的子载波配置给所述Setm。Optionally, when the uplink bandwidth includes 48 subcarriers, the subcarrier index is 0 to 47, F=24, and the initial subcarrier index of the Set m is 2, the subcarrier configuration with an index of 2 to 25 is configured. Give the Set m .
可选地,当上行带宽包括48个子载波,所述子载波索引为0~47,F=36,且所述Setm的起始子载波索引为2时,索引为2~37的子载波配置给所述Setm。Optionally, when the uplink bandwidth includes 48 subcarriers, the subcarrier index is 0 to 47, F=36, and the initial subcarrier index of the Set m is 2, the subcarrier configuration with an index of 2 to 37 is configured. Give the Set m .
可选地,当上行带宽包括48个子载波,所述子载波索引为0~47,F=24,且所述Setm的起始子载波索引为18时,索引为18~41的子载波配置给所述Setm。Optionally, when the uplink bandwidth includes 48 subcarriers, the subcarrier index is 0 to 47, F=24, and the initial subcarrier index of the Set m is 18, the subcarrier configuration with an index of 18 to 41 Give the Set m .
可选地,所述Setm中的所述F个子载波中,随机接入信道占用的子载波数量Num在所述F个子载波中的比例为Ratio,其中,所述Ratio由所述基站通过信令发送给所述终端。
Optionally, the proportion of the number of subcarriers Num occupied by the random access channel in the F subcarriers is Ratio in the F subcarriers in the Set m , where the Ratio is sent by the base station The order is sent to the terminal.
可选地,所述F的取值为{12,24,36,48}。Optionally, the value of F is {12, 24, 36, 48}.
可选地,所述Ratio的取值为{1/6,2/6,3/6,4/6,5/6,6/6}或{1/12,2/12,3/12,4/12,5/12,6/12,7/12,8/12,9/12,10/12,11/12,12/12}或{0/12,1/12,2/12,3/12,4/12,5/12,6/12,7/12,8/12,9/12,10/12,11/12,12/12}或{0/6,1/6,2/6,3/6,4/6,5/6,6/6}。Optionally, the value of the Ratio is {1/6, 2/6, 3/6, 4/6, 5/6, 6/6} or {1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12, 9/12, 10/12, 11/12, 12/12} or {0/12, 1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12, 9/12, 10/12, 11/12, 12/12} or {0/6, 1/6, 2/6, 3/6, 4/6, 5/6, 6/6}.
可选地,所述Setm中的所述F个子载波中,用于发送随机接入信号的随机接入信道占用的子载波数量为Num。Optionally, among the F subcarriers in the Set m , the number of subcarriers occupied by the random access channel for transmitting the random access signal is Num.
可选地,所述F的取值为{12,24,36,48}。Optionally, the value of F is {12, 24, 36, 48}.
可选地,所述Num取值为{4,8,12,16,20,24,28,32,36,40,44,48}或{3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48}或{0,4,8,12,16,20,24,28,32,36,40,44,48}或{0,3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48}。Optionally, the Num value is {4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48} or {3, 6, 9, 12, 15, 18, 21 , 24,27,30,33,36,39,42,45,48} or {0,4,8,12,16,20,24,28,32,36,40,44,48} or {0 , 3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48}.
可选地,所述终端向所述基站发送所述随机接入信号的所述随机接入信道由所述基站通过信令分配给所述终端。Optionally, the random access channel that the terminal sends the random access signal to the base station is allocated by the base station to the terminal by using signaling.
可选地,所述信令中包括以下信息至少之一:起始的等级索引;所述基站分配给所述终端的所述随机接入信道所在的频域位置信息;所述基站分配给所述终端的所述随机接入信道所在的时域位置信息。Optionally, the signaling includes at least one of the following: an initial level index; frequency domain location information of the random access channel allocated by the base station to the terminal; The time domain location information of the random access channel of the terminal.
可选地,所述基站分配给所述终端的所述随机接入信道所在的频域位置信息包括:组成所述随机接入信号的单元Unit的Group0发送时所在的子载波或子信道索引。Optionally, the frequency domain location information of the random access channel allocated by the base station to the terminal includes: a subcarrier or a subchannel index where the group 0 of the unit that constitutes the random access signal is sent. .
可选地,当上行带宽包括48个子载波或子信道时,通过6bits指示信息指示基站分配给所述终端的所述随机接入信道所在的频域位置信息。Optionally, when the uplink bandwidth includes 48 subcarriers or subchannels, the 6bits indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal.
可选地,所述6bits指示信息还用于指示所述终端在所述Setm中的F个子载波中随机选择一个子载波作为所述随机接入信道所在的频域位置。Alternatively, said information further indicating 6bits F subcarriers in the Set m in a randomly selected sub-carrier frequency domain position as said random access channel is used to indicate the location of the terminal.
可选地,当所述Setm中包括F个子载波或子信道时,通过指示信息指示基站分配给所述终端的所述随机接入信道所在的频域位置信息。Optionally, when the Set m includes F subcarriers or subchannels, The indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal.
可选地,所述指示信息还用于指示所述终端在所述Setm中的F个子载波中随机选择一个子载波作为所述终端的所述随机接入信道所在的频域位置。Optionally, said Indication information indicating that the terminal is further configured to F subcarriers in the Set m in a randomly selected sub-carriers of the frequency domain position of the terminal as a random access channel is located.
可选地,当所述Setm中包括F个子载波或子信道时,通过指示信息指示基站分配给所述终端的所述随机接入信道所在的频域位置信息,其中,所述Num为所述随机接入信道占用的子载波数量。Optionally, when the Set m includes F subcarriers or subchannels, The indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal, where the Num is the number of subcarriers occupied by the random access channel.
可选地,所述基站分配给所述终端的所述随机接入信道所在的时域位置信息包括:第二
Setm的配置周期指示信息n;其中,所述基站分配给所述终端的所述随机接入信道所在的Setm定义为第二Setm;所述第二Setm为从第一Setm中选择的;且第二Setm的配置周期长度为第一Setm的配置周期的n倍,n为正整数;所述第一Setm为所述随机接入信道资源包括的一个或多个时频资源集合Setm,n为正整数。Optionally, the time domain location information of the random access channel allocated by the base station to the terminal includes: configuration period indication information n of the second Set m , where the base station allocates to the terminal The Set m where the random access channel is located is defined as the second Set m ; the second Set m is selected from the first Set m ; and the configuration period length of the second Set m is the configuration period of the first Set m n times, n is a positive integer; the first Set m is one or more time-frequency resource sets Set m , n of the random access channel resource, and n is a positive integer.
可选地,包括以下至少之一:当n的取值由3bit描述时,n的取值为{1,2,3,4,5,6,7,8}或{1,2,4,8,16,32,64,128}或{1,2,4,8,10,12,14,16};当n的取值由2bit描述时,n的取值为{1,2,3,4}或{1,2,4,8}或{1,4,6,8}。Optionally, at least one of the following is included: when the value of n is described by 3 bits, the value of n is {1, 2, 3, 4, 5, 6, 7, 8} or {1, 2, 4, 8,16,32,64,128} or {1,2,4,8,10,12,14,16}; when the value of n is described by 2 bits, the value of n is {1, 2, 3 , 4} or {1, 2, 4, 8} or {1, 4, 6, 8}.
可选地,所述基站分配给所述终端的所述随机接入信道所在的时域位置为:所述第二Setm的配置周期内的第一个第一Setm。Alternatively, the base station allocates to the time domain position of the random access channel, where the terminal is: a first configuration in a first Set m periods of the second Set m.
可选地,所述基站分配给所述终端的所述随机接入信道所在的时域位置信息还包括:所述第二Setm在所述第二Setm的配置周期内的位置信息Offset;其中,所述Offset用于指示所述第二Setm的配置周期内的n个第一Setm中,分配给所述终端的所述随机接入信道所在的第一Setm的索引信息。Alternatively, the base station allocates to the time domain information of the random access channel position where said terminal further comprises: a second location information Offset Set m disposed within said second period of Set m; wherein said n first Offset Set m for the configuration of the second period indication Set m, the index information allocated to the random access channel, where the first terminal of the Set m.
可选地,所述基站分配给所述终端的所述随机接入信道所在的时域位置信息包括:连续两个第二Setm时域间隔信息Interval;所述基站分配给所述终端的所述随机接入信道所在的Setm定义为第二Setm;所述第二Setm为从第一Setm中选择的,且连续两个第二Setm之间间隔Interval个第一Setm;所示第一Setm为所述随机接入信道资源包括的一个或多个时频资源集合Setm。Optionally, the time domain location information of the random access channel allocated by the base station to the terminal includes: two consecutive second set m time domain interval information Interval; the base station allocates to the terminal m is defined above the Set random access channel where the Set second m; the second from the first to select the Set m m in the Set and the Set successive intervals of first m interval between two second m the Set; The first set m is shown as one or more time-frequency resource sets Set m included in the random access channel resource.
可选地,所述信令中还包括:触发定位操作指示信息。Optionally, the signaling further includes: triggering positioning operation indication information.
可选地,所述触发定位操作指示信息为触发定位操作时,所述终端在所述信令分配的随机接入信道上发送所述随机接入信号。Optionally, when the trigger positioning operation indication information is a trigger positioning operation, the terminal sends the random access signal on the random access channel allocated by the signaling.
可选地,所述终端在发送所述随机接入信号给所述基站之后,所述方法还包括:所述终端接收所述基站检测所述随机接入信号后,根据检测结果发送的随机接入响应消息;其中,所述随机接入响应消息中包括以下信息中至少之一:子载波间隔指示信息;配置的子载波数量指示信息。Optionally, after the terminal sends the random access signal to the base station, the method further includes: receiving, by the terminal, the random connection sent by the base station after detecting the random access signal according to the detection result. And a response message, where the random access response message includes at least one of the following information: subcarrier spacing indication information; configured subcarrier number indication information.
可选地,所述子载波间隔指示信息和所述配置的子载波数量指示信息通过联合编码方式指示。Optionally, the subcarrier spacing indication information and the configured subcarrier number indication information are indicated by a joint coding manner.
根据本发明的另一方面,提供了一种接入处理装置,所述装置应用于终端中,包括:选
择模块,设置为选择序列集合中与所述终端对应的序列;生成模块,设置为至少根据所述对应的序列生成随机接入信号;发送模块,设置为发送所述随机接入信号给基站。According to another aspect of the present invention, an access processing apparatus is provided, the apparatus being applied to a terminal, including: selecting
And the generating module is configured to select a sequence corresponding to the terminal in the sequence set; the generating module is configured to generate a random access signal according to at least the corresponding sequence; and the sending module is configured to send the random access signal to the base station.
通过本发明,采用终端在生成用于接入基站的随机接入信号时,会选择与终端自身对应的序列进行生成,从而使得随机接入信号是与待接入终端的特性(如,类型)是相匹配的,保证了不同类型的终端都能够成功接入系统,从而解决了相关技术中存在的无法保证各种类型的终端都成功接入系统的问题,进而实现了各种类型的终端都能够成功接入系统的效果。According to the present invention, when the terminal generates a random access signal for accessing the base station, it selects a sequence corresponding to the terminal itself to generate, so that the random access signal is a characteristic (eg, type) of the terminal to be accessed. It is matched to ensure that different types of terminals can successfully access the system, thereby solving the problem that the related technologies cannot guarantee that various types of terminals can successfully access the system, thereby realizing various types of terminals. The ability to successfully access the system.
此处所说明的附图用来提供对本发明的进一步理解,构成本申请的一部分,本发明的示意性实施例及其说明用于解释本发明,并不构成对本发明的不当限定。在附图中:The drawings described herein are intended to provide a further understanding of the invention, and are intended to be a part of the invention. In the drawing:
图1是根据本发明实施例的接入处理方法的流程图;1 is a flowchart of an access processing method according to an embodiment of the present invention;
图2是根据本发明具体实施例1的随机接入信号的基本单元的时域和频域的二维结构图;2 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 1 of the present invention;
图3是根据本发明具体实施例1的Setm的时域和频域的二维结构图;3 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 1 of the present invention;
图4是根据本发明具体实施例2的随机接入信号的基本单元的时域和频域的二维结构图;4 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 2 of the present invention;
图5是根据本发明具体实施例2的Setm的时域和频域的二维结构图;5 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 2 of the present invention;
图6是根据本发明具体实施例3的随机接入信号的基本单元的时域和频域的二维结构图;6 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 3 of the present invention;
图7是根据本发明具体实施例3的Setm的时域和频域的二维结构图;7 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 3 of the present invention;
图8是根据本发明具体实施例4的随机接入信号的基本单元的时域和频域的二维结构图;8 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 4 of the present invention;
图9是根据本发明具体实施例4的Setm的时域和频域的二维结构图;9 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 4 of the present invention;
图10是根据本发明具体实施例4的Setm的位图指示示意图;Figure 10 is a diagram showing a bitmap indication of Set m according to a fourth embodiment of the present invention;
图11是根据本发明具体实施例5的随机接入信号的基本单元的时域和频域的二维结构图;11 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 5 of the present invention;
图12是根据本发明具体实施例5的Setm的时域和频域的二维结构图;Figure 12 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to a fifth embodiment of the present invention;
图13是根据本发明具体实施例5的相邻的两个时频资源集合Setm和Setm+1之间间隔示意图;13 is a schematic diagram showing the interval between two sets of adjacent time-frequency resources, Set m and Set m+1 , according to Embodiment 5 of the present invention;
图14是根据本发明具体实施例6的随机接入信号的基本单元的时域和频域的二维结构图;
14 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 6 of the present invention;
图15是根据本发明具体实施例6的Setm的时域和频域的二维结构图;15 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 6 of the present invention;
图16是根据本发明具体实施例6的时频资源集合Setm的配置周期示意图;16 is a schematic diagram of a configuration period of a time-frequency resource set Set m according to Embodiment 6 of the present invention;
图17是根据本发明具体实施例7的随机接入信号的基本单元的时域和频域的二维结构图;17 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 7 of the present invention;
图18是根据本发明具体实施例7的Setm的时域和频域的二维结构图;Figure 18 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to a seventh embodiment of the present invention;
图19是根据本发明具体实施例7的Vms内配置的Setm示意图;19 is a schematic diagram of Set m configured in Vms according to Embodiment 7 of the present invention;
图20是根据本发明具体实施例8的随机接入信号的基本单元的时域和频域的二维结构图;20 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 8 of the present invention;
图21是根据本发明具体实施例8的Setm的时域和频域的二维结构图;21 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 8 of the present invention;
图22是根据本发明具体实施例9的随机接入信号的基本单元的时域和频域的二维结构图;22 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 9 of the present invention;
图23是根据本发明具体实施例9的Setm的时域和频域的二维结构图;23 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 9 of the present invention;
图24是根据本发明具体实施例9的为等级索引为g的终端配置连续的Repetitiong个subset的分配示意图;24 is a schematic diagram of allocation of consecutive Repetition g subsets for a terminal with a level index of g according to a specific embodiment 9 of the present invention;
图25是根据本发明具体实施例10的随机接入信号的基本单元的时域和频域的二维结构图;25 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to a tenth embodiment of the present invention;
图26是根据本发明具体实施例10的Setm的时域和频域的二维结构图;26 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 10 of the present invention;
图27是根据本发明具体实施例10的为等级索引为g的终端配置连续的Repetitiong个subset的分配示意图;27 is a schematic diagram of allocation of consecutive Repetition g subsets for a terminal with a level index of g according to a tenth embodiment of the present invention;
图28是根据本发明具体实施例11的随机接入信号的基本单元的时域和频域的二维结构图;28 is a two-dimensional structural diagram of a time domain and a frequency domain of a basic unit of a random access signal according to Embodiment 11 of the present invention;
图29是根据本发明具体实施例11的Setm的时域和频域的二维结构图;29 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 11 of the present invention;
图30是根据本发明具体实施例11的等级索引为g的终端发送随机接入信号的资源分配示意图;30 is a schematic diagram of resource allocation for transmitting a random access signal by a terminal with a level index of g according to Embodiment 11 of the present invention;
图31是根据本发明具体实施例12的Setm的时域和频域的二维结构图;
31 is a two-dimensional structural diagram of a time domain and a frequency domain of Set m according to Embodiment 12 of the present invention;
图32是根据本发明具体实施例13的GT2的结构图;Figure 32 is a structural diagram of a GT 2 according to a specific embodiment 13 of the present invention;
图33是根据本发明具体实施例13的Preamble的基本单元的64次重复传输结构示意图;33 is a schematic diagram of a 64-time repeated transmission structure of a basic unit of a Preamble according to Embodiment 13 of the present invention;
图34是根据本发明具体实施例14的GT2的结构图;Figure 34 is a structural diagram of a GT 2 according to a specific embodiment 14 of the present invention;
图35是根据本发明具体实施例14的Preamble的基本单元的64次重复传输结构示意图;35 is a schematic diagram of a 64-time repeated transmission structure of a basic unit of a Preamble according to Embodiment 14 of the present invention;
图36是根据本发明具体实施例15的终端选择Group发送的Subcarrior的结构图;36 is a structural diagram of a Subcarrior sent by a terminal selection group according to Embodiment 15 of the present invention;
图37是根据本发明具体实施例16的终端选择Group发送的Subcarrior的结构图;37 is a structural diagram of a Subcarrior transmitted by a terminal selection group according to a specific embodiment 16 of the present invention;
图38是根据本发明实施例的接入处理装置的结构框图。FIG. 38 is a block diagram showing the structure of an access processing apparatus according to an embodiment of the present invention.
下文中将参考附图并结合实施例来详细说明本发明。需要说明的是,在不冲突的情况下,本申请中的实施例及实施例中的特征可以相互组合。The invention will be described in detail below with reference to the drawings in conjunction with the embodiments. It should be noted that the embodiments in the present application and the features in the embodiments may be combined with each other without conflict.
需要说明的是,本发明的说明书和权利要求书及上述附图中的术语“第一”、“第二”等是用于区别类似的对象,而不必用于描述特定的顺序或先后次序。It is to be understood that the terms "first", "second" and the like in the specification and claims of the present invention are used to distinguish similar objects, and are not necessarily used to describe a particular order or order.
在本实施例中提供了一种接入处理方法,图1是根据本发明实施例的接入处理方法的流程图,如图1所示,该流程包括如下步骤:An access processing method is provided in this embodiment. FIG. 1 is a flowchart of an access processing method according to an embodiment of the present invention. As shown in FIG. 1, the process includes the following steps:
步骤S102,终端选择序列集合中与终端对应的序列;Step S102, the terminal selects a sequence corresponding to the terminal in the sequence set;
步骤S104,上述终端至少根据对应的序列生成随机接入信号;Step S104: The terminal generates a random access signal according to at least a corresponding sequence.
步骤S106,上述终端发送所述随机接入信号给基站。Step S106, the terminal sends the random access signal to the base station.
其中,上述的与终端对应的序列可以是与终端的类型相对应的序列,由于终端的类型有多种,终端在进行随机接入时,可以根据自身的类型特征选择用于生成相应的随机接入信号的序列,因此,终端在进行随机接入之前,可以从由多个序列组成的序列集合中选择与自身对应的序列,并生成对应的随机接入信号,并据此接入系统(即,上述的基站),从而解决了相关技术中存在的无法保证各种类型的终端都成功接入系统的问题,进而实现了各种类型的终端都能够成功接入系统的效果。The sequence corresponding to the terminal may be a sequence corresponding to the type of the terminal. Because the terminal has multiple types, the terminal may select a random connection according to its own type feature when performing random access. a sequence of incoming signals. Therefore, before performing random access, the terminal may select a sequence corresponding to itself from a sequence set consisting of multiple sequences, and generate a corresponding random access signal, and access the system accordingly. The above-mentioned base station) solves the problem that the related technologies cannot ensure that all types of terminals successfully access the system, thereby achieving the effect that various types of terminals can successfully access the system.
在一个可选的实施例中,上述序列集合中包括J条序列长度均为N的序列,其中,索引为j的序列的表达形式为J为正整数,N为正整数。In an optional embodiment, the sequence set includes a sequence of J sequences having a length of N, wherein the sequence of the index of j is expressed as J is a positive integer and N is a positive integer.
在一个可选的实施例中,上述序列集合中包括R个序列子集合,即,序列集合中包括的J条序列被划分为的R个序列子集合,并且,R个序列子集合可以被配置给不同的终端集合,其中,R为正整数。
In an optional embodiment, the sequence set includes R sequence subsets, that is, R sequence subsets in which J sequences included in the sequence set are divided, and R sequence subsets can be configured. Give a different set of terminals, where R is a positive integer.
在上述步骤S102中,终端在选择序列集合中与终端对应的序列时,可以采用如下选择方式:终端从上述R个序列子集合中确定与自身所属的终端集合对应的序列子集合;终端从确定的序列子集合中选择一条序列作为对应的序列。可选地,当终端确定的序列子集合中只有1条序列时,该终端选择该序列子集合中的这1条序列作为对应的序列;当终端确定的序列子集合中有多条序列时,终端从确定的序列子集合中随机的选择一条序列作为对应的序列;其中,R为正整数。在本实施例中,上述的序列集合可以被分为R个序列子集合,因此,在选择与终端对应的序列时,终端可以首先选择配置给自身所属的终端集合的序列子集合,进而再从该选择的序列子集合中选择对应的序列。In the above step S102, when the terminal selects a sequence corresponding to the terminal in the sequence set, the terminal may adopt the following selection manner: the terminal determines a sequence subset corresponding to the terminal set to which the terminal belongs by the terminal from the R sequence subsets; A sequence is selected in the sequence sub-set as the corresponding sequence. Optionally, when there is only one sequence in the sequence subset determined by the terminal, the terminal selects the one sequence in the sequence subset as the corresponding sequence; when there are multiple sequences in the sequence subset determined by the terminal, The terminal randomly selects a sequence from the determined sequence subset as a corresponding sequence; wherein R is a positive integer. In this embodiment, the foregoing sequence set may be divided into R sequence sub-sets. Therefore, when selecting a sequence corresponding to the terminal, the terminal may first select a sequence sub-set that is configured for the terminal set to which the terminal belongs, and then A corresponding sequence is selected from the selected subset of sequences.
在一个可选的实施例中,上述终端从R个序列子集合中确定与自身所属的终端集合对应的序列子集合包括:上述终端从R个序列子集合中选择第(Y+1)个序列子集合作为与自身所属的终端集合对应的序列子集合,其中,Y=Mod(Cell ID,R),Cell ID为终端接入的小区标识索引。在本实施例中,可以是基站为终端所属的终端集合配置子序列结合上述的Mod(Cell ID,R)为取余算法,即,Y为Cell ID除以R之后得到的余数。In an optional embodiment, the determining, by the terminal, the sequence subset corresponding to the terminal set to which the terminal belongs from the R sequence subsets includes: the terminal selecting the (Y+1)th sequence from the R sequence subsets The sub-set is a sequence sub-set corresponding to the terminal set to which the user belongs, where Y=Mod (Cell ID, R), and the Cell ID is a cell identity index accessed by the terminal. In this embodiment, the base station may configure a subsequence for the terminal set to which the terminal belongs, in combination with the Mod (Cell ID, R) described above as a remnant algorithm, that is, Y is a remainder obtained by dividing the Cell ID by R.
在一个可选的实施例中,上述R个序列子集合可以分别被配置给R个不同的终端集合,即,序列子集合和终端集合是一一对应的。当然,在应用中,序列子集合和终端集合之间还可以是多对一或一对多的关系。In an optional embodiment, the R sequence subsets may be respectively configured to R different terminal sets, that is, the sequence subset and the terminal set are in one-to-one correspondence. Of course, in an application, a sequence of sub-sets and terminal sets may also be a many-to-one or one-to-many relationship.
在一个可选的实施例中,终端集合的划分方式可以为多种,下面对不同的终端集合划分方式进行说明:In an optional embodiment, the terminal set may be divided into multiple modes. The following describes different terminal set division modes:
当终端集合的数量为2时,2个不同的终端集合为第一终端集合和第二终端集合,该第一终端集合和第二终端集合满足以下条件至少之一:第一终端集合包括的终端为支持多个子载波同时传输的终端,且第二终端集合包括的终端为仅支持单个子载波传输的终端;第一终端集合包括的终端为采用多个子载波传输上行数据的终端,且第二终端集合包括的终端为采用单个子载波传输上行数据的终端;第一终端集合包括的终端为采用多个子载波同时传输Msg3消息的终端,且第二终端集合包括的终端为采用单个子载波传输Msg3消息的终端;第一终端集合包括的终端为Msg3消息承载在多个子载波上传输的终端,且第二终端集合包括的终端为Msg3消息仅承载在单个子载波传输的终端;第一终端集合包括的终端为支持单个子载波传输且子载波间隔为fsc1的终端,第二终端集合包括的终端为支持单个子载波传输且子载波间隔为fsc2的终端;第一终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc1的终端;第二终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc2的终端;第一终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc1的终端,第二终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc2的终端;第一终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc1的终端,第二终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc2的终端;上述第一
终端集合包括的终端为Msg3消息中承载的信息量为Size1的终端,第二终端集合包括的终端为Msg3消息中承载的信息量为Size2的终端,其中,Size1不等于Size2;When the number of terminal sets is 2, the two different terminal sets are the first terminal set and the second terminal set, and the first terminal set and the second terminal set satisfy at least one of the following conditions: the terminal included in the first terminal set A terminal that supports simultaneous transmission of multiple subcarriers, and the terminal included in the second terminal set is a terminal that supports only one subcarrier transmission; the terminal included in the first terminal set is a terminal that uses multiple subcarriers to transmit uplink data, and the second terminal The terminal included in the set is a terminal that transmits uplink data by using a single subcarrier; the terminal included in the first terminal set is a terminal that simultaneously transmits an Msg3 message by using multiple subcarriers, and the terminal included in the second terminal set transmits the Msg3 message by using a single subcarrier. The terminal included in the first terminal set is a terminal that transmits the Msg3 message on the multiple subcarriers, and the terminal included in the second terminal set is that the Msg3 message is only carried in the terminal of the single subcarrier transmission; the first terminal set includes a terminal support and a single sub-carrier transmission subcarrier spacing f sc1 terminal, the second terminal sets Comprising a terminal support and a single sub-carrier transmission subcarrier spacing f sc2 terminal; a first set of terminals including a terminal for the use of a single subcarrier for transmitting uplink data and the subcarrier spacing f sc1 terminal; a second set of terminals included The terminal is a terminal that uses a single subcarrier to transmit uplink data and has a subcarrier spacing of f sc2 ; the terminal included in the first terminal set is a terminal that transmits an Msg3 message by using a single subcarrier and has a subcarrier spacing of f sc1 , and the second terminal set includes The terminal is a terminal that uses a single subcarrier to transmit an Msg3 message and the subcarrier spacing is f sc2 . The terminal included in the first terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc1 , and the second terminal is set. The terminal included is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc2 ; the terminal included in the first terminal set is a terminal in which the amount of information carried in the Msg3 message is Size1, and the second terminal set includes The terminal is a terminal that carries the amount of information in the Msg3 message is Size2, where Size1 is not equal to Size2;
当终端集合的数量为3时,3个不同的终端集合为第一终端集合、第二终端集合和第三终端集合,第一终端集合、第二终端集合和第三终端集合满足以下条件至少之一:第一终端集合包括的终端为支持多个子载波同时传输的终端,第二终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc1的终端,第三终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc2的终端;第一终端集合包括的终端为采用多个子载波传输上行数据的终端,第二终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc1的终端;第三终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc2的终端;第一终端集合包括的终端为采用多个子载波传输Msg3消息的终端,第二终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc1的终端,第三终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc2的终端;第一终端集合包括的终端为Msg3消息承载在多个子载波上传输的终端,第二终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc1的终端,第三终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc2的终端;上述第一终端集合包括的终端为Msg3消息中承载的信息量为Size1的终端,第二终端集合包括的终端为Msg3消息中承载的信息量为Size2的终端,第三终端集合包括的终端为Msg3消息中承载的信息量为Size3的终端,其中,Size1、Size2、Size3互不相等;When the number of terminal sets is 3, the three different terminal sets are the first terminal set, the second terminal set, and the third terminal set, and the first terminal set, the second terminal set, and the third terminal set satisfy at least the following conditions: The first terminal set includes terminals that support simultaneous transmission of multiple subcarriers, and the second terminal set includes terminals that support only a single subcarrier transmission and the subcarrier spacing is f sc1 , and the third terminal set includes terminals. A terminal that supports only a single subcarrier transmission and has a subcarrier spacing of f sc2 ; the terminal included in the first terminal set is a terminal that transmits uplink data by using multiple subcarriers, and the terminal included in the second terminal set transmits uplink data by using a single subcarrier. And the terminal with the subcarrier spacing is f sc1 ; the terminal included in the third terminal set is a terminal that uses one subcarrier to transmit uplink data and the subcarrier spacing is f sc2 ; the terminal included in the first terminal set is to transmit the Msg3 message by using multiple subcarriers. Terminal, the second terminal set includes terminals for transmitting Msg3 messages by using a single subcarrier and the subcarrier spacing is f The terminal of the sc1 , the terminal included in the third terminal set is a terminal that transmits the Msg3 message by using a single subcarrier and the subcarrier spacing is f sc2 ; the terminal included in the first terminal set is a terminal that the Msg3 message carries on the multiple subcarriers, The terminal included in the second terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc1 , and the terminal included in the third terminal set is that the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc2. The terminal included in the first terminal set is a terminal that has the information amount of the S1 in the Msg3 message, and the terminal in the second terminal set is a terminal that has the information amount of the S2 in the Msg3 message, and the third terminal set includes The terminal is a terminal that carries information in the Msg3 message with a size of Size3, where Size1, Size2, and Size3 are not equal to each other;
当终端集合的数量为4时,4个不同的终端集合为第一终端集合、第二终端集合、第三终端集合和第四终端集合,第一终端集合、第二终端集合、第三终端集合和第四终端集合满足以下条件至少之一:第一终端集合包括的终端为支持多个子载波同时传输且子载波间隔为fsc1的终端,第二终端集合包括的终端为支持多个子载波同时传输且子载波间隔为fsc2的终端,第三终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc3的终端,第四终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc4的终端;第一终端集合包括的终端为采用多个子载波传输上行数据且子载波间隔为fsc1的终端,第二终端集合包括的终端为采用多个子载波传输上行数据且子载波间隔为fsc2的终端,第三终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc3的终端;第四终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc4的终端;第一终端集合包括的终端为采用多个子载波传输Msg3消息且子载波间隔为fsc1的终端,第二终端集合包括的终端为采用多个子载波传输Msg3消息且子载波间隔为fsc2的终端,第三终端集合包括的终端为采用单个子载波传输Msg3消息且子载
波间隔为fsc3的终端,第四终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc4的终端;第一终端集合包括的终端为Msg3消息承载在多个子载波上传输且子载波间隔为fsc1的终端,第二终端集合包括的终端为Msg3消息承载在多个子载波上传输且子载波间隔为fsc2的终端,第三终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc3的终端,第四终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc4的终端;上述第一终端集合包括的终端为Msg3消息中承载的信息量为Size1的终端,第二终端集合包括的终端为Msg3消息中承载的信息量为Size2的终端,第三终端集合包括的终端为Msg3消息中承载的信息量为Size3的终端,第四终端集合包括的终端为Msg3消息中承载的信息量为Size4的终端,其中,Size1、Size2、Size3、Size4互不相等。需要说明的是,上述的几种终端集合划分方式仅是几种示例,也可以采用其他的合理划分方式对终端集合进行划分。在上述实施例中,fsc1和fsc2取值不同,例如,fsc1可以取值为15kHz,fsc2可以取值为3.75kHz;上述的fsc3和fsc4取值不同,例如,fsc3可以取值为15kHz,fsc4可以取值为3.75kHz。When the number of terminal sets is 4, the four different terminal sets are a first terminal set, a second terminal set, a third terminal set, and a fourth terminal set, and the first terminal set, the second terminal set, and the third terminal set. And the fourth terminal set satisfies at least one of the following conditions: the terminal included in the first terminal set is a terminal that supports simultaneous transmission of multiple subcarriers and the subcarrier spacing is f sc1 , and the terminal included in the second terminal set supports simultaneous transmission of multiple subcarriers. And the terminal with the subcarrier spacing is f sc2 , the terminal included in the third terminal set is a terminal that supports only a single subcarrier transmission and the subcarrier spacing is f sc3 , and the terminal included in the fourth terminal set supports only a single subcarrier transmission and the sub The terminal with the carrier spacing is f sc4 ; the terminal included in the first terminal set is a terminal that uses multiple subcarriers to transmit uplink data and the subcarrier spacing is f sc1 , and the second terminal set includes terminals that use multiple subcarriers to transmit uplink data and carrier spacing for f sc2 set includes a terminal, a third terminal is a terminal using a single subcarrier, and the subcarrier for transmitting uplink data between F sc3 terminal; and a fourth set of terminals including a terminal for the use of a single subcarrier for transmitting uplink data and the subcarrier spacing f sc4 terminal; a first set of terminals including a terminal using a plurality of sub-carrier transmission and the subcarrier spacing message Msg3 For the terminal of the f sc1 , the terminal included in the second terminal set is a terminal that transmits the Msg3 message by using multiple subcarriers and the subcarrier spacing is f sc2 , and the terminal included in the third terminal set transmits the Msg3 message by using a single subcarrier and the subcarrier spacing For the terminal of the f sc3 , the terminal included in the fourth terminal set is a terminal that transmits the Msg3 message by using a single subcarrier and the subcarrier spacing is f sc4 ; the terminal included in the first terminal set is the Msg3 message bearer transmitted on multiple subcarriers and the sub The terminal with the carrier spacing is f sc1 , and the terminal included in the second terminal set is a terminal that transmits the Msg3 message on multiple subcarriers and the subcarrier spacing is f sc2 , and the terminal included in the third terminal set is that the Msg3 message is only carried in a single sub A terminal that transmits a carrier and has a subcarrier spacing of f sc3 , and the terminal included in the fourth terminal set is a Msg3 message that is only carried in a single subcarrier. A terminal that transmits a wave and has a subcarrier spacing of f sc4 ; the terminal included in the first terminal set is a terminal that carries information in the Msg3 message is Size1, and the terminal included in the second terminal set is that the amount of information carried in the Msg3 message is Size2 The terminal includes a terminal that is a terminal that has a quantity of information carried in the Msg3 message, and a terminal that is included in the fourth terminal set is a terminal that has an information amount of Size4 in the Msg3 message, where Size1, Size2, Size3 Size4 is not equal to each other. It should be noted that the foregoing several terminal set division manners are only a few examples, and other reasonable division manners may also be used to divide the terminal set. In the above embodiment, the values of f sc1 and f sc2 are different. For example, f sc1 can take a value of 15 kHz, and f sc2 can take a value of 3.75 kHz; the above f sc3 and f sc4 have different values, for example, f sc3 can be The value is 15 kHz, and f sc4 can be 3.75 kHz.
在一个可选的实施例中,上述的序列集合中的J条序列的类型可以是多种,下面对序列集合中的序列的类型进行说明:上述J条序列长度均为N的序列满足以下至少之一:J条序列长度均为N的序列为正交码字序列;J条序列长度均为N的序列为准正交码字序列;J条序列长度均为N的序列为预定义的序列。在本实施例中,预定义的序列包括长度为N的全1序列,或者长度为N的全A的序列,该A可以为正整数。In an optional embodiment, the types of the J sequences in the sequence set may be multiple. The following describes the types of the sequences in the sequence set: the sequence of the J sequences whose lengths are all N meets the following At least one of the J sequences having a length of N is an orthogonal codeword sequence; the sequence of J sequences having a length of N is a quasi-orthogonal codeword sequence; and the sequence of J sequences having a length of N is predefined. sequence. In this embodiment, the predefined sequence includes an all-one sequence of length N, or a sequence of all As of length N, which may be a positive integer.
在一个可选的实施例中,上述满足以下至少之一:不同取值的j对应的Codej中互为正交码字,或互为准正交码字;不同取值的j对应的Codej中互为正交码字,或互为准正交码字;不同取值的j对应的Codej中互为正交码字,或互为准正交码字,其中,0≤i≤N/2-1。In an alternative embodiment, the above Satisfy at least one of the following: J of different values corresponding to Code j Mutual orthogonal code words, or quasi-orthogonal code words; mutually different values of j corresponding to Code j Mutual orthogonal code words, or quasi-orthogonal code words; mutually different values of j corresponding to Code j They are orthogonal code words, or mutually quasi-orthogonal code words, where 0 ≤ i ≤ N / 2-1.
在一个可选的实施例中,上述N的取值可以为以下之一:2,4,6,8。In an optional embodiment, the value of N may be one of the following: 2, 4, 6, and 8.
下面对序列集合中的各序列进行举例说明:The following is an example of each sequence in a sequence set:
可选地,当J=1,且N=4时,J条序列长度为N的序列包括以下至少之一:
Optionally, when J=1, and N=4, the J sequence sequence length N includes at least one of the following:
当R=2,J=2,且N=4时,J条序列长度为N的序列包括以下至少之一:
其中,Code0和Code1中的一个被配置给第一终端集合中的终端,另一个被配置给第二终端集合中的终端;当R=2,J=2,且N=8时,J条序列长度为N的序列包括以下至少之一:
其中,Code0和Code1中的一个被配置给第一终端集合中的终端,另一个被配置给第二终端集合中的终端;When R=2, J=2, and N=4, the sequence of J sequence lengths of N includes at least one of the following: Wherein, one of Code 0 and Code 1 is configured to the terminal in the first terminal set, and the other is configured to the terminal in the second terminal set; when R=2, J=2, and N=8, J The sequence of strip length N includes at least one of the following: Wherein one of Code 0 and Code 1 is configured to the terminal in the first terminal set, and the other is configured to the terminal in the second terminal set;
当R=3,J=3,且N=4时,J条序列长度为N的序列包括以下至少之一:
中任意3个;
中任意3个;其中,3条序列长度为N的序列被分别配置给3个终端集合中的终端,即,3条序列长度为N的序列和3个终端集合可以进行任意一对一组合配置;When R=3, J=3, and N=4, the sequence of J sequences of length N includes at least one of the following: Any three of them; Any three of them; wherein three sequences of sequence length N are respectively allocated to terminals in three terminal sets, that is, three sequences of sequence length N and three terminal sets can be configured in any one-to-one combination ;
当R=4,J=4,且N=4时,J条序列长度为N的序列包括以下至少之一:
其中,4条序列长度为N的序列被分别配置给4个终端集合中的终端,即,4条序列长度为N的序列和4个终端集合可以进行任意一对一组合配置;其中,A为C为常数,
When R=4, J=4, and N=4, the sequence of J sequence lengths of N includes at least one of the following: The four sequences of length N are respectively allocated to the terminals in the four terminal sets, that is, four sequences of sequence length N and four terminal sets can be configured in any one-to-one combination; C is a constant,
在一个可选的实施例中,当与终端对应的序列为时,上述终端至少根据对应的序列生成随机接入信号包括:终端确定频域上索引为fn的子载波且
时域上占用连续的K个符号发送第k个符号且子载波fn上发送的信号的频域表达式为上述K个符号且子载波fn上发送的信号的频域表达式为其中,0≤k≤K-1;上述终端至少根据确定随机接入信号。In an optional embodiment, when the sequence corresponding to the terminal is And generating, by the terminal, the random access signal according to the corresponding sequence at least: the terminal determines the subcarrier with the index f n in the frequency domain, and occupies consecutive K symbol transmissions in the time domain. The frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is The frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is Where 0 ≤ k ≤ K-1; the above terminal is based at least Determine the random access signal.
在一个可选的实施例中,上述终端至少根据确定所述随机接入信号包括:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度,为索引为fn的子载波占用的频域资源,FOffset为频域偏移量;和/或,当时域采样间隔为Ts时,对应的时域的表达式为其中,0≤t≤Tk,Tk为第k个时域符号的长度,0≤k≤K-1,0≤q≤Q-1,为时域采样点数量;所述终端在连续的K个符号上发送的时域表达式为终端至少根据上述确定随机接入信号。In an optional embodiment, the foregoing terminal is based at least according to Determining the random access signal includes: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol, For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset; and/or, when the current domain sampling interval is T s , Corresponding time domain The expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol, 0 ≤ k ≤ K-1, 0 ≤ q ≤ Q-1, Number of samples in the time domain; the terminal is sent on consecutive K symbols The time domain expression is The terminal is based at least on the above Determine the random access signal.
在一个可选的实施例中,上述终端至少根据确定随机接入信号包括:上述终端按照下式生成循环前缀CPn,CPn={Sn[QK-L+1],…,Sn[QK]},L表示CPn中包括的时域采样间隔Ts的数量;则终端在子载波fn上发送的随机接入信号的表达式为Groupn={CPn,Sn},终端在子载波f0,f1,…,fN-1上发送的随机接入信号的表达式为{Group0,Group1,…GroupN-1};其中,n取值不同的Groupn在时域上占用不同的符号。In an optional embodiment, the foregoing terminal is based at least according to Determining the random access signal includes: the terminal generates a cyclic prefix CP n according to the following formula, CP n ={S n [QK-L+1],...,S n [QK]}, where L represents a time domain included in the CP n The number of sampling intervals T s ; then the expression of the random access signal transmitted by the terminal on the subcarrier f n is Group n = {CP n , S n }, and the terminal is in the subcarriers f 0 , f 1 , ..., f N The expression of the random access signal transmitted on -1 is {Group 0 , Group 1 , ... Group N-1 }; wherein Group n with different values of n occupy different symbols in the time domain.
在一个可选的实施例中,Group0~GroupN-1为组成上述随机接入信号的单元Unit,上述终端发送随机接入信号给基站包括:上述终端确定一个Unit为随机接入信号,并将随机接入信号重复H次进行发送;和/或,上述终端将Unit在时域上重复H次形成随机接入信号,并发送上述随机接入信号。In an optional embodiment, the group 0 to the group N-1 are the unit units constituting the random access signal, and the terminal sending the random access signal to the base station includes: the terminal determines that a unit is a random access signal, and The random access signal is repeated H times for transmission; and/or, the terminal repeats the unit H times in the time domain to form a random access signal, and transmits the random access signal.
在一个可选的实施例中,上述终端在子载波fn上发送完成随机接入信号Groupn之后,需要引入时间长度为Gap的间隔,其中,在该时间长度为Gap的间隔内终端不再发送Groupn之
后的随机接入信号,上述终端在时间长度为Gap的间隔之后继续发送Groupn之后的随机接入信号。In an optional embodiment, after the terminal sends the random access signal Group n on the sub-carrier f n , the interval of the time length Gap needs to be introduced, where the terminal is no longer in the interval of the Gap interval. The random access signal after the group n is sent, and the terminal continues to send the random access signal after the group n after the interval of the time length Gap.
在一个可选的实施例中,当N=4,K=5,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,上述Gap的时域长度为0.4ms;和/或,当N=4,K=5,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,上述Gap的时域长度为0.6ms;和/或,当N=4,K=5,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns。In an optional embodiment, when N=4, K=5, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time of the Gap is The length of the domain is 0.4 ms; and/or, when N=4, K=5, the time domain length of CP n is 66.7 us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the above Gap The time domain length is 0.6 ms; and/or, when N=4, K=5, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth for transmitting the random access signal is 3.75 kHz, Gap The time domain length is 12288*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, the time domain length of CP n is 2048*Ts, the subcarrier spacing of the random access signal is transmitted or When the subcarrier bandwidth is 3.75 kHz, the time domain length of Gap is 18432*Ts, where Ts=32.55 ns.
在一个可选的实施例中,上述Unit的H次重复包括Y个Group(Y个Group即为Group0~GroupN-1、Group0~GroupN-1、Group0~GroupN-1……,一共重复了H次),可以定义Y个Group的索引为Group0~GroupY-1,其中,Y=H*N;当终端完成Groupstart到Groupend一共y个Group(y个Group的索引号可以是连续的)的随机接入信号的发送之后,需要引入时间长度为Gap的间隔,其中,在时间长度为Gap的间隔内终端不再发送随机接入信号,所述终端在所述时间长度为Gap的间隔之后继续发送Groupend之后的随机接入信号;其中,0≤start≤end≤Y-1,y≤Y。In an optional embodiment, the H repetitions of the above unit include Y groups (Y groups are Group 0 to Group N-1 , Group 0 to Group N-1 , Group 0 to Group N-1, ...) , a total of H times), you can define the index of Y groups as Group 0 ~ Group Y-1 , where Y = H * N; when the terminal completes Group start to Group end a total of y Group (y group index After the transmission of the random access signal, which may be continuous, it is necessary to introduce an interval of time Gap, wherein the terminal no longer transmits a random access signal in the interval of time Gap, and the terminal is at the time The random access signal after the group end is transmitted after the interval of the gap of Gap; wherein 0≤start≤end≤Y-1, y≤Y.
在一个可选的实施例中,start=offset+y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量;offset为第一个Groupstart的索引的偏置量;或者,start=y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量。In an optional embodiment, start=offset+y×N gap , where N gap is the number of intervals in which the length of the introduction time is Gap; offset is the offset of the index of the first group start ; or, start = y × N gap , where N gap is the number of intervals in which the introduction time length is Gap.
在一个可选的实施例中,end=start+y-1。In an alternative embodiment, end = start + y-1.
在一个可选的实施例中,上述Gap满足以下条件至少之一:y×L_G+Gap=T×TimeUnit,其中,L_G为Group的时间长度,Gap≥0,T为正整数,TimeUnit为一种时间长度的度量单位;y×L_G+Gap=T×TimeUnit,其中L_G为Group的时间长度,Gap≥0,T为正整数且T为满足T×TimeUnit>y×L_G的最小值,TimeUnit为一种时间长度的度量单位。在本实施例中,TimeUnit可以是秒、毫秒、微秒、纳秒、帧(frame)、子帧(Subframe)、时隙(slot)。In an optional embodiment, the Gap satisfies at least one of the following conditions: y×L_G+Gap=T×TimeUnit, where L_G is the length of the group, Gap≥0, T is a positive integer, and TimeUnit is a type. The unit of measurement of the length of time; y × L_G + Gap = T × TimeUnit, where L_G is the length of the Group, Gap ≥ 0, T is a positive integer and T is the minimum value of T × TimeUnit > y × L_G, TimeUnit is a The unit of measure of the length of time. In this embodiment, the TimeUnit may be seconds, milliseconds, microseconds, nanoseconds, frames, subframes, slots.
在一个可选的实施例中,上述终端在发送完成一个Unit的随机接入信号之后,需要引入
时间长度为Gap的间隔,其中,在该时间长度为Gap的间隔内终端不再发送Unit之后的随机接入信号,终端在上述时间长度为Gap的间隔之后继续发送Unit之后的随机接入信号。In an optional embodiment, after the terminal sends a random access signal of a unit, the terminal needs to be introduced.
The time interval is the gap of the gap, wherein the terminal does not send the random access signal after the unit in the interval where the time is Gap, and the terminal continues to send the random access signal after the unit after the interval of the time length of Gap.
在一个可选的实施例中,当N=4,K=5,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.6ms;和/或,当N=4,K=5,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.4ms;和/或,当N=4,K=5,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns。In an optional embodiment, when N=4, K=5, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain of Gap The length is 0.6ms; and/or, when N=4, K=5, the time domain length of CP n is 66.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time domain of Gap The length is 0.4ms; and/or, when N=4, K=5, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time of Gap The length of the field is 18432*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, the time domain length of CP n is 2048*Ts, and the subcarrier spacing or subcarrier of the random access signal is transmitted. When the bandwidth is 3.75 kHz, the time domain length of Gap is 12288*Ts, where Ts=32.55 ns.
在一个可选的实施例中,定义上述Unit的H次重复的索引为Unit0~UnitH-1,当终端完成Unitstart到Unitend一共y个Unit(y个Unit的索引号可以是连续的)的随机接入信号发送之后,需要引入时间长度为Gap的间隔,其中,在该时间长度为Gap的间隔内终端不再发送随机接入信号,终端在上述时间长度为Gap的间隔之后继续发送Unitend之后的随机接入信号;其中,0≤start≤end≤Y-1,y≤Y。In an optional embodiment, the index of the H repetitions of the above unit is defined as Unit 0 to Unit H-1 , and the terminal completes the unit start to the unit end by a total of y units (the index numbers of the y units may be consecutive) After the random access signal is sent, the interval of the time length Gap needs to be introduced, wherein the terminal does not send the random access signal during the time interval of the gap, and the terminal continues to send after the interval of the time length of Gap. Random access signal after unit end ; where 0≤start≤end≤Y-1, y≤Y.
在一个可选的实施例中,start=offset+y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量;offset为第一个Unitstart的索引的偏置量;或者,start=y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量。In an optional embodiment, start=offset+y×N gap , where N gap is the number of intervals in which the length of the introduction time is Gap; offset is the offset of the index of the first unit start ; or, start = y × N gap , where N gap is the number of intervals in which the introduction time length is Gap.
在一个可选的实施例中,end=start+y-1。In an alternative embodiment, end = start + y-1.
在一个可选的实施例中,上述Gap满足以下条件至少之一:y×L_U+Gap=T×TimeUnit,其中,L_G为Unit的时间长度,gap≥0,T为正整数,TimeUnit为一种时间长度的度量单位;y×L_U+Gap=T×TimeUnit,其中,L_G为Unit的时间长度,Gap≥0,T为正整数且T为满足T×TimeUnit>y×L_U的最小值,TimeUnit为一种时间长度的度量单位。在本实施例中,TimeUnit可以是秒、毫秒、微秒、纳秒、帧(frame)、子帧(Subframe)、时隙(slot)。In an optional embodiment, the Gap satisfies at least one of the following conditions: y×L_U+Gap=T×TimeUnit, where L_G is the length of time of the unit, gap≥0, T is a positive integer, and TimeUnit is a type. The unit of measurement of the length of time; y × L_U + Gap = T × TimeUnit, where L_G is the length of time of Unit, Gap ≥ 0, T is a positive integer and T is the minimum value of T × TimeUnit > y × L_U, TimeUnit is A measure of the length of time. In this embodiment, the TimeUnit may be seconds, milliseconds, microseconds, nanoseconds, frames, subframes, slots.
在一个可选的实施例中,当N=4,K=5,H=1,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=2,CPn的时域长度为8192*Ts,发送随机接入信号的
子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为6144*Ts或36864*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=4,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=8,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为24576*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=16,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=1,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=2,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为24576*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=4,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=8,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为6144*Ts或36864*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=16,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=1,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.6ms;和/或,当N=4,K=5,H=2,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.2ms或1.2ms;和/或,当N=4,K=5,H=4,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.4ms;和/或,当N=4,K=5,H=8,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.8ms;和/或,当N=4,K=5,H=16,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.6ms;和/或,当N=4,K=5,H=1,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.4ms;和/或,当N=4,K=5,H=2,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.8ms;和/或,当N=4,K=5,H=4,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.6ms;和/或,当N=4,K=5,H=8,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.2ms或
1.2ms;和/或,当N=4,K=5,H=16,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.4ms。In an optional embodiment, when N=4, K=5, H=1, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth for transmitting the random access signal is 3.75 kHz. The time domain length of Gap is 18432*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, H=2, the time domain length of CP n is 8192*Ts, and random access is sent. When the subcarrier spacing or subcarrier bandwidth of the signal is 3.75 kHz, the time domain length of Gap is 6144*Ts or 36864*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, H= 4. The time domain length of CP n is 8192*Ts. When the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 12288*Ts, where Ts=32.55 ns; and / Or, when N=4, K=5, H=8, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 24576*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, H=16, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or sub-send of the random access signal is transmitted. When the carrier bandwidth is 3.75kHz, the time domain of Gap is long. To 18432 * Ts, where, Ts = 32.55ns; and / or, if N = 4, K = 5, H = 1, the length of the time domain CP n is 2048 * Ts, transmitting a random access signal or subcarrier spacing When the subcarrier bandwidth is 3.75 kHz, the time domain length of Gap is 12288*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, H=2, the time domain length of CP n is 2048. *Ts, when the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 24576*Ts, where Ts=32.55 ns; and/or, when N=4, K=5 , H=4, the time domain length of CP n is 2048*Ts. When the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 18432*Ts, where Ts=32.55 ns. And/or, when N=4, K=5, H=8, the time domain length of CP n is 2048*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, Gap time The length of the field is 6144*Ts or 36864*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, H=16, the time domain length of CP n is 2048*Ts, and random access is sent. When the subcarrier spacing or subcarrier bandwidth of the signal is 3.75 kHz, The time domain length of Gap is 12288*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, H=1, the time domain length of CP n is 266.7us, and the random access signal is transmitted. When the subcarrier spacing or subcarrier bandwidth is 3.75 kHz, the time domain length of Gap is 0.6 ms; and/or, when N=4, K=5, H=2, the time domain length of CP n is 266.7us, and the transmission is random. When the subcarrier spacing or subcarrier bandwidth of the access signal is 3.75 kHz, the time domain length of Gap is 0.2 ms or 1.2 ms; and/or, when N=4, K=5, H=4, the time domain of CP n The length is 266.7us. When the subcarrier spacing or subcarrier bandwidth for transmitting the random access signal is 3.75kHz, the time domain length of Gap is 0.4ms; and/or, when N=4, K=5, H=8, CP The time domain length of n is 266.7us, and the time domain length of Gap is 0.8ms when the subcarrier spacing or subcarrier bandwidth for transmitting random access signals is 3.75kHz; and/or, when N=4, K=5, H =16, the time domain length of CP n is 266.7us, and the time domain length of Gap is 0.6ms when the subcarrier spacing or subcarrier bandwidth for transmitting random access signals is 3.75kHz; and/or, when N=4, K =5, H=1, the time domain length of CP n is 66.7us When the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 0.4 ms; and/or, when N=4, K=5, H=2, the time domain of CP n The length is 66.7us. When the subcarrier spacing or subcarrier bandwidth for transmitting the random access signal is 3.75kHz, the time domain length of Gap is 0.8ms; and/or, when N=4, K=5, H=4, CP The time domain length of n is 66.7us, and when the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 0.6 ms; and/or, when N=4, K=5, H =8, the time domain length of CP n is 66.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time domain length of Gap is 0.2ms or 1.2ms; and/or when N= 4, K=5, H=16, the time domain length of CP n is 66.7us, and the sub-carrier spacing or sub-carrier bandwidth of the random access signal is 3.75 kHz, and the time domain length of Gap is 0.4 ms.
在一个可选的实施例中,上述H的取值至少根据终端的等级确定,即,不同等级的终端对应的H可以是不同的。In an optional embodiment, the value of the above H is determined according to at least the level of the terminal, that is, the H corresponding to the terminals of different levels may be different.
在一个可选的实施例中,上述终端的等级可以包括以下至少之一:覆盖增强等级;物理信道重复发送等级;物理信道上承载的消息或信令的重复发送等级。In an optional embodiment, the level of the foregoing terminal may include at least one of the following: an coverage enhancement level; a physical channel repetition transmission level; and a repeated transmission level of a message or signaling carried on the physical channel.
在一个可选的实施例中,上述终端发送随机接入信号给基站包括:终端确定用于发送上述随机接入信号的随机接入信道;终端通过随机接入信道向基站发送随机接入信号。在本实施例中,终端用于进行随机接入信号发送的随机接入信道可以是随机接入信道资源中的一部分,该随机接入信道资源可以包括多个用于不同的终端进行随机接入信号发送的随机接入信道。In an optional embodiment, the sending, by the terminal, the random access signal to the base station includes: determining, by the terminal, a random access channel for transmitting the random access signal; and transmitting, by the terminal, the random access signal to the base station by using a random access channel. In this embodiment, the random access channel used by the terminal to perform random access signal transmission may be part of a random access channel resource, and the random access channel resource may include multiple random accesses for different terminals. A random access channel for signal transmission.
在一个可选的实施例中,上述随机接入信道资源包括一个或多个时频资源集合Setm,其中,该Setm在频域上包括F个子载波或子信道,在时域上长度至少为P个Unit的长度,m为Setm在时域的索引,F为正整数,P为正整数。在本实施例中,上述的随机接入信道资源可以包括多个终端发送随机接入信号的随机接入信道,并且,上述的一个Setm可以由一个终端使用,也可以由多个终端使用,或者多个Setm由一个终端使用。In an optional embodiment, the random access channel resource includes one or more time-frequency resource sets Set m , where the set m includes F sub-carriers or sub-channels in the frequency domain, and the length is at least in the time domain. For the length of P units, m is the index of Set m in the time domain, F is a positive integer, and P is a positive integer. In this embodiment, the random access channel resource may include a random access channel in which multiple terminals send random access signals, and the foregoing set m may be used by one terminal or may be used by multiple terminals. Or multiple Set m are used by one terminal.
在一个可选的实施例中,上述Setm包括P个子集subset,其中,该subset在频域上与Setm配置相同的子载波,subset在时域上长度为1个Unit的长度。In an optional embodiment, the Set m includes P subset subsets, wherein the subset is configured with the same subcarriers in the frequency domain as the Set m , and the subset has a length of 1 Unit in the time domain.
在一个可选的实施例中,在上述Setm占用的频率资源的前后各配置有保护带宽,和/或,在Setm占用的频率资源的上下各配置有保护带宽。下面对Setm占用的频率资源配置的保护带宽进行说明:In an optional embodiment, the protection bandwidth is configured before and after the frequency resource occupied by the Set m , and/or the protection bandwidth is configured on the upper and lower sides of the frequency resource occupied by the Set m . The following describes the protection bandwidth of the frequency resource configuration occupied by Set m :
当子载波间隔为3.75kHz,F=12时,在Setm占用的频率资源的前后频率资源上各配置有7.5kHz保护带宽;和/或,当子载波间隔为3.75kHz,F=16时,在Setm占用的频率资源中上下边带各预留有7.5kHz保护带宽。When the subcarrier spacing is 3.75 kHz, F=12, the 7.5 kHz protection bandwidth is configured on the frequency resources before and after the frequency resource occupied by Set m ; and/or, when the subcarrier spacing is 3.75 kHz, F=16, In the frequency resource occupied by Set m , the upper and lower sidebands each have a reserved bandwidth of 7.5 kHz.
在一个可选的实施例中,当上行带宽包括48个子载波,且F=12时,上行带宽最多配置4个Setm,且每个Setm在频域上包括F=12个子载波或子信道,不同Setm在频域上包括的子载波或子信道不重叠。In an optional embodiment, when the uplink bandwidth includes 48 subcarriers, and F=12, the uplink bandwidth is configured with a maximum of 4 Set m , and each Set m includes F=12 subcarriers or subchannels in the frequency domain. The subcarriers or subchannels included in the frequency domain of different Set m do not overlap.
可选地,可以通过U个比特信息指示为同一个等级的终端或终端组分配的Setm的频域位
置,其中,不同等级的终端配置的Setm的频域位置相同,U=2或4。Optionally, the frequency domain positions of the Set m allocated to the terminal or the terminal group of the same level may be indicated by the U bit information, where the frequency domain positions of the Set m configured by the different levels are the same, U=2 or 4 .
在一个可选的实施例中,当上行带宽包括48个子载波,且F=16时,上行带宽最多配置3个Setm,且每个Setm在频域上包括F=16个子载波或子信道,不同Setm在频域上包括的子载波或子信道不重叠。In an optional embodiment, when the uplink bandwidth includes 48 subcarriers, and F=16, the uplink bandwidth is configured with a maximum of 3 Set m , and each Set m includes F=16 subcarriers or subchannels in the frequency domain. The subcarriers or subchannels included in the frequency domain of different Set m do not overlap.
可选地,可以通过U个比特信息指示为同一个等级的终端或终端组分配的Setm的频域位置,其中,不同等级的终端配置的Setm的频域位置相同,U=2或3。Optionally, the frequency domain locations of the Set m allocated to the terminal or the terminal group of the same level may be indicated by the U bit information, where the frequency domain locations of the Set m configured by the different levels are the same, U=2 or 3 .
在一个可选的实施例中,上述方法可以包括如下至少之一:当N=4,K=5时,所述Setm在时域上长度为7ms,所述CPn的时域长度为266.7us,P=1;当N=4,K=5时,所述Setm在时域上长度为13ms,所述CPn的时域长度为266.7us,P=2;当N=8,K=5时,所述Setm在时域上长度为13ms,所述CPn的时域长度为266.7us,P=1;当N=4,K=5时,所述Setm在时域上长度为26ms,所述CPn的时域长度为266.7us,P=4;当N=8,K=5时,所述Setm在时域上长度为26ms,所述CPn的时域长度为266.7us,P=2;当N=4,K=5时,所述Setm在时域上长度为32ms,所述CPn的时域长度为266.7us,P=5;当N=4,K=5时,所述Setm在时域上长度为64ms,所述CPn的时域长度为266.7us,P=10;当N=8,K=5时,所述Setm在时域上长度为64ms,所述CPn的时域长度为266.7us,P=5;当N=4,K=5时,所述Setm在时域上长度为6ms,所述CPn的时域长度为66.7us,P=1;当N=4,K=5时,所述Setm在时域上长度为12ms,所述CPn的时域长度为66.7us,P=2;当N=8,K=5时,所述Setm在时域上长度为12ms,所述CPn的时域长度为66.7us,P=1;当N=4,K=5时,所述Setm在时域上长度为17ms,所述CPn的时域长度为66.7us,P=3;当N=4,K=5时,所述Setm在时域上长度为23ms,所述CPn的时域长度为66.7us,P=4;当N=8,K=5时,所述Setm在时域上长度为23ms,所述CPn的时域长度为66.7us,P=2;当N=4,K=5时,所述Setm在时域上长度为28ms,所述CPn的时域长度为66.7us,P=5;当N=4,K=5时,所述Setm在时域上长度为34ms,所述CPn的时域长度为66.7us,P=6;当N=8,K=5时,所述Setm在时域上长度为34ms,所述CPn的时域长度为66.7us,P=3。In an optional embodiment, the foregoing method may include at least one of the following: when N=4, K=5, the set m is 7 ms in the time domain, and the time domain length of the CP n is 266.7. Us, P=1; when N=4, K=5, the set m is 13ms in the time domain, the time domain length of the CP n is 266.7us, P=2; when N=8, K When set to 5, the set m has a length of 13 ms in the time domain, the time domain length of the CP n is 266.7 us, P=1; when N=4, K=5, the set m is in the time domain. The length of the CP n is 266.7us, P=4; when N=8, K=5, the length of the Set m is 26ms in the time domain, and the time domain length of the CP n 266.7us, P=2; when N=4, K=5, the set m has a length of 32ms in the time domain, the time domain length of the CP n is 266.7us, P=5; when N=4 When K=5, the set m has a length of 64 ms in the time domain, the time domain length of the CP n is 266.7 us, P=10; when N=8, K=5, the set m is at the time The length of the domain is 64 ms, the length of the time domain of the CP n is 266.7us, P=5; when N=4, K=5, the length of the Set m is 6 ms in the time domain, The time domain length of CP n is 66.7us, P=1; when N=4, K=5, the length of the Set m in the time domain is 12ms, and the time domain length of the CP n is 66.7us, P= 2; when N=8, K=5, the set m has a length of 12 ms in the time domain, the time domain length of the CP n is 66.7 us, P=1; when N=4, K=5, The set m has a length of 17 ms in the time domain, the time domain length of the CP n is 66.7 us, P=3; when N=4, K=5, the set m has a length of 23 ms in the time domain. The time domain length of the CP n is 66.7us, P=4; when N=8, K=5, the set m is 23ms in the time domain, and the time domain length of the CP n is 66.7us. P=2; when N=4, K=5, the set m has a length of 28 ms in the time domain, the time domain length of the CP n is 66.7 us, P=5; when N=4, K=5 The set m has a length of 34 ms in the time domain, the time domain length of the CP n is 66.7 us, P=6; when N=8, K=5, the length of the Set m in the time domain is 34ms, the time domain length of the CP n is 66.7us, P=3.
其中,在上述实施例中,当N=4,K=5时,Setm在时域上长度为7ms时,上述随机接入信道资源包括0.6ms的保护时间;当N=4,K=5时,Setm在时域上长度为26ms时,上述
随机接入信道资源包括0.4ms的保护时间;当N=8,K=5时,Setm在时域上长度为26ms时,上述随机接入信道资源包括0.4ms的保护时间;当N=4,K=5时,Setm在时域上长度为6ms时,上述随机接入信道资源包括0.4ms的保护时间;当N=4,K=5时,Setm在时域上长度为12ms时,上述随机接入信道资源包括0.8ms的保护时间;当N=8,K=5时,Setm在时域上长度为12ms时,上述随机接入信道资源包括0.8ms的保护时间;当N=4,K=5时,Setm在时域上长度为17ms时,上述随机接入信道资源包括0.2ms的保护时间;当N=4,K=5时,Setm在时域上长度为23ms时,上述随机接入信道资源包括0.6ms的保护时间;当N=8,K=5时,Setm在时域上长度为23ms时,上述随机接入信道资源包括0.6ms的保护时间;当N=4,K=5时,Setm在时域上长度为34ms时,上述随机接入信道资源包括0.4ms的保护时间;当N=8,K=5时,Setm在时域上长度为34ms时,上述随机接入信道资源包括0.4ms的保护时间。In the foregoing embodiment, when N=4, K=5, when Set m is 7 ms in the time domain, the random access channel resource includes a guard time of 0.6 ms; when N=4, K=5 When Set m has a length of 26 ms in the time domain, the random access channel resource includes a guard time of 0.4 ms; when N=8, K=5, when Set m is 26 ms in the time domain, the random connection is performed. The inbound channel resource includes a guard time of 0.4 ms; when N=4, K=5, when the set m is 6 ms in the time domain, the random access channel resource includes a guard time of 0.4 ms; when N=4, K =5, when Set m is 12 ms in the time domain, the random access channel resource includes a guard time of 0.8 ms; when N=8, K=5, when Set m is 12 ms in the time domain, the above The random access channel resource includes a guard time of 0.8 ms; when N=4, K=5, when the set m is 17 ms in the time domain, the random access channel resource includes a guard time of 0.2 ms; when N=4 , K = 5 when, Set m of length 23ms in time domain, the random access channel resource comprises a guard time of 0.6ms; if N = 8, K = 5 when, Set m in Domain length is 23ms, the random access channel resource comprises a guard time of 0.6ms; when N = 4, K = 5 when, Set m length in the time domain is 34ms, the random access channel resource comprises 0.4ms The guard time; when N=8, K=5, when the set m is 34 ms in the time domain, the random access channel resource includes a guard time of 0.4 ms.
在一个可选的实施例中,时域相邻的两个Setm之间间隔V个第一时间单位,其中,V为整数,所述第一时间单位包括以下至少之一:一个或多个帧的时域长度、一个或多个子帧的时域长度、Z1秒、Z2毫秒、Z3个Setm的时域长度,Z4个Unit的时域长度,Z5个subset的时域长度,其中,Z1、Z2、Z3、Z4、Z5均为正整数。In an alternative embodiment, a first time interval of a V-domain unit time between two adjacent Set m, wherein, V is an integer, the first unit of time comprises at least one of the following: one or more The time domain length of the frame, the time domain length of one or more subframes, Z 1 second, Z 2 milliseconds, the time domain length of Z 3 Set m , the time domain length of Z 4 Units, and the time domain of Z 5 subsets The length, wherein Z 1 , Z 2 , Z 3 , Z 4 , and Z 5 are all positive integers.
在上述实施例中,可以包括如下至少之一:V的取值包括以下至少之一:V=0;V=2y,其中,y为大于或等于0的整数;V个第一时间单位在时域上连续分布或离散分布;时域相邻的两个Setm在频域上占用相同的所述F个子载波或子信道。In the above embodiment, at least one of the following may be included: the value of V includes at least one of the following: V=0; V=2 y , where y is an integer greater than or equal to 0; V first time units are The time domain is continuously distributed or discretely distributed; two Set m adjacent in the time domain occupy the same F subcarriers or subchannels in the frequency domain.
在一个可选的实施例中,Setm的配置周期为L个第一时间单位,其中,L为正整数,所述第一时间单位包括以下至少之一:一个或多个帧的时域长度、一个或多个子帧的时域长度、Z1秒、Z2毫秒、Z3个Setm的时域长度,Z4个Unit的时域长度,Z5个subset的时域长度,其中,Z1、Z2、Z3、Z4、Z5均为正整数。In an optional embodiment, the configuration period of the Set m is L first time units, where L is a positive integer, and the first time unit includes at least one of: a time domain length of one or more frames Time domain length of one or more subframes, Z 1 second, Z 2 milliseconds, time domain length of Z 3 Set m , time domain length of Z 4 Units, time domain length of Z 5 subsets, where Z 1 , Z 2 , Z 3 , Z 4 , and Z 5 are all positive integers.
在一个可选的实施例中,L=2z,其中,z为大于或等于0的整数。In an alternative embodiment, L = 2 z , where z is an integer greater than or equal to zero.
在上述实施例中,2z个第一时间单位在时域上连续分布或离散分布;z取值为{0,1,2,3,4,5,6,7};时域相邻的两个Setm在频域上占用相同的所述F个子载波或子信道。In the above embodiment, 2 z first time units are continuously distributed or discretely distributed in the time domain; z is taken as {0, 1, 2, 3, 4, 5, 6, 7}; time domain adjacent Two Set m occupy the same F subcarriers or subchannels in the frequency domain.
在一个可选的实施例中,在上述Setm的配置周期内最多配置L1个subset,该subset的索引为subset 0至subset(L1-1),其中,等级索引为g的终端对应的subset配置方案包括:等
级索引为g的终端将Unit在时域上重复Repetitiong次发送,在一个Setm的配置周期内,为等级索引为g的终端配置连续的Repetitiong个subset,且起始subset索引StartingSubsetIndexg按照下面公式计算:其中,0≤g≤G-1,G为划分的终端的等级的数量。可选地,在本实施例中,G还可以为需要在Setm中配置资源的终端的等级的数量。上述的G均可以为1。In an optional embodiment, at most L 1 subsets are configured in the configuration period of the Set m , and the index of the subset is subset 0 to subset (L 1 -1), wherein the terminal with the level index g corresponds to The subset configuration scheme includes: the terminal with the level index g transmits the Repetition g times in the time domain, and configures consecutive Repetition g subsets for the terminal with the level index g in the configuration period of a Set m , and starts The subset index StartingSubsetIndex g is calculated according to the following formula: Where 0 ≤ g ≤ G-1, and G is the number of levels of the divided terminals. Optionally, in this embodiment, G may also be the number of levels of terminals that need to configure resources in Set m . The above G may each be 1.
在一个可选的实施例中,不同的Setm的配置周期之间,等级索引为g的终端对应的subset配置方案是相同的。In an optional embodiment, the configuration of the subset corresponding to the terminal with the level index g is the same between the configuration periods of different Set m .
在一个可选的实施例中,在上述Setm的配置周期内最多配置L1个subset,subset的索引为subset 0至subset(L1-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将Unit在时域上重复Repetitiong次发送,且为等级索引为g的终端配置连续的ChanceNumg×Repetitiong个subset,其中ChanceNumg≥1。In an optional embodiment, at most L 1 subsets are configured in the configuration period of the Set m , and the index of the subset is subset 0 to subset (L 1 -1), wherein the subset corresponding to the terminal with the level index g is The configuration scheme includes: the terminal with the level index g sends the Unit repeating Repetition g times in the time domain, and configures the consecutive ChanceNum g ×Repetition g subsets for the terminal with the level index g, where ChanceNum g ≥1.
在一个可选的实施例中,在一个Setm的配置周期内,ChanceNumg×Repetitiong个subset中起始subset索引StartingSubsetIndexg可以按照下面公式计算:其中,0≤g≤G-1,G为划分的终端的等级的数量。可选地,上述G可以是基站配置的终端的等级的数量,也可以是在Setm资源上发送随机接入信号的终端的等级的数量。可选地,在本实施例中,G还可以为需要在Setm中配置资源的终端的等级的数量。上述的G均可以为1。In an optional embodiment, in a configuration period of Set m , the starting subset index StartingSubsetIndex g in ChanceNum g ×Repetition g subsets can be calculated according to the following formula: Where 0 ≤ g ≤ G-1, and G is the number of levels of the divided terminals. Optionally, the foregoing G may be the number of levels of terminals configured by the base station, or may be the number of levels of terminals that send random access signals on the Set m resource. Optionally, in this embodiment, G may also be the number of levels of terminals that need to configure resources in Set m . The above G may each be 1.
在一个可选的实施例中,起始subset索引为StartingSubsetIndexg的ChanceNumg×Repetitiong个subset中,配置有ChanceNumg个第一发送资源,其中,该第一发送资源用于Unit在时域上重复Repetitiong次发送,即,Unit在时域上重复Repetitiong次发送可以在第一资源上执行。In an optional embodiment, the starting subset index is ChanceNum g ×Repetition g subsets of StartingSubsetIndex g , and is configured with ChanceNum g first sending resources, where the first sending resource is used for Unit in the time domain. Repeat Repetition g times, that is, Unit repeats Repetition g times in the time domain and can be executed on the first resource.
在一个可选的实施例中,上述ChanceNumg个第一发送资源中的第c个第一发送资源的起始subset索引可以按照下面公式计算:
In an alternative embodiment, the above-described ChanceNum g of first transmission resources in the c-th starting index of the first subset of transmission resources It can be calculated according to the following formula:
在一个可选的实施例中,在上述Setm的配置周期内最多配置L1个subset,该subset的索引为subset 0至subset(L1-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将Unit在时域上重复Repetitiong次发送,且等级索引为g的终端配置有ChanceNumg×Repetitiong个subset,ChanceNumg≥1。In an optional embodiment, at most L 1 subsets are configured in the configuration period of the Set m , and the index of the subset is subset 0 to subset (L 1 -1), wherein the terminal with the level index g corresponds to The subset configuration scheme includes: the terminal with the level index g sends the Unit repeating Repetition g times in the time domain, and the terminal with the level index g is configured with ChanceNum g ×Repetition g subsets, and ChanceNum g ≥1.
在一个可选的实施例中,在一个Setm的配置周期内,ChanceNumg×Repetitiong个subset的索引为subset 0至subset(ChanceNumg×Repetitiong-1),且从subset 0开始,索引连续的Repetitiong个subset为一个第一发送资源,其中,该第一发送资源用于Unit在时域上重复Repetitiong次发送,一个第一发送资源内的Repetitiong个subset在时域上连续分布,不同的第一发送资源对应的subset在时域上离散分布。In an alternative embodiment, in a configuration cycle of Set m, ChanceNum g × Repetition g subset is a subset of the indices 0 to subset (ChanceNum g × Repetition g -1 ), and starts from the subset 0, continuous index The Repetition g subset is a first transmission resource, wherein the first transmission resource is used for the Unit to repeat the Repetition g transmission in the time domain, and the Repetition g subsets in the first transmission resource are continuously distributed in the time domain. The subsets corresponding to different first transmission resources are discretely distributed in the time domain.
在一个可选的实施例中,在上述Setm的配置周期内包括G个等级的终端对应的第一发送资源,其中,等级索引为g的终端对应的第一发送资源用于Unit在时域上重复Repetitiong次发送,等级索引为g的终端对应的所述第一发送资源大小为Ng个
为级索引为g的终端对应的Setm,0≤g≤G-1。In an optional embodiment, the first sending resource corresponding to the terminals of the G levels is included in the configuration period of the Set m , wherein the first sending resource corresponding to the terminal with the level index g is used for the Unit in the time domain. Repeating the Repetition g times, the first sending resource corresponding to the terminal with the level index g is N g Set m corresponding to the terminal whose index is g, 0 ≤ g ≤ G-1.
在一个可选的实施例中,在上述Setm的配置周期内,终端按照等级索引g由小到大的顺序依次分配有Ng个资源。In an optional embodiment, during the configuration period of the Set m , the terminal sequentially allocates N g according to the rank index g from small to large. Resources.
在一个可选的实施例中,Ng≥1或Ng≥0,且当Ng=0时,表示在Setm的配置周期内没有配置等级索引为g的终端对应的第一发送资源。In an optional embodiment, N g ≥ 1 or N g ≥ 0, and when N g =0, it indicates that the first transmission resource corresponding to the terminal with the level index g is not configured in the configuration period of Set m .
在一个可选的实施例中,在Setm的配置周期内,为等级索引为g的终端配置的Ng个资源中相邻的两个之间时域间隔为Lg个第二时间单位,其中,Lg≥0。In an optional embodiment, N g configured for the terminal with the level index g in the configuration period of Set m Two adjacent in the resource The time domain interval is L g second time units, where L g ≥ 0.
在一个可选的实施例中,不同等级索引的终端对应的Lg相同。In an alternative embodiment, the same index different levels corresponding to the terminal L g.
在一个可选的实施例中,在上述Setm的配置周期内,不同等级索引的终端对应的Ng个资源之间,间隔Lβ个第二时间单位,其中,Lβ≥0。其中,不同等级索引的终端对应的
Ng个资源之间间隔Lβ个第二时间单位是指一个等级的终端对应的资源与另一个等级的终端对应的资源之间间隔Lβ个第二时间单位。In an optional embodiment, in the configuration period of the Set m , the N g corresponding to the terminals of different levels of indexing Between resources, the interval L β is a second time unit, where L β ≥ 0. Wherein, N g of terminals corresponding to different levels of indexing The interval between resources L β second time units refers to the corresponding level of a terminal The resource corresponds to another level of terminal The interval between resources is L β second time units.
在一个可选的实施例中,在Setm的配置周期内,不同等级索引的终端对应的Ng个资源之间,间隔Lg个第二时间单位。In an optional embodiment, in the configuration period of Set m , N g of terminals corresponding to different levels of indexing Between resources, the interval L g is a second time unit.
在一个可选的实施例中,上述的第一时间单位和第二时间单位可以相同也可以不同。In an optional embodiment, the first time unit and the second time unit may be the same or different.
在一个可选的实施例中,等级索引为g的终端对应的Ng个资源中第一个的时域起始资源位置与所述的配置周期内时域起始资源位置相同;或者,等级索引为g的终端对应的Ng个资源中第一个的时域起始资源位置与所述的配置周期内时域起始资源位置存在偏移量,其中,所述偏移量为预定的或者为基站配置的。In an optional embodiment, the N g corresponding to the terminal whose rank index is g The first in the resource Time domain starting resource location with the stated The time domain starting resource location is the same in the configuration period; or the N g corresponding to the terminal with the level index g The first in the resource Time domain starting resource location with the stated There is an offset in the time domain starting resource location within the configuration period, wherein the offset is predetermined or configured for the base station.
在一个可选的实施例中,不同等级索引的终端对应的相同。In an optional embodiment, terminals of different levels of index correspond to the same.
在一个可选的实施例中,上述Setm的配置周期长度为D个Setm的时域长度,其中,D为正整数。The length of the time domain In an alternative embodiment, the length of the arrangement period of the D Set m Set m, wherein, D is a positive integer.
在一个可选的实施例中,D=2x,x为大于或等于0的整数。In an alternative embodiment, D = 2 x and x is an integer greater than or equal to zero.
在一个可选的实施例中,在上述Setm的配置周期内最多配置D*P个subset,subset的索引为subset 0至subset(D*P-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将Unit在时域上重复Repetitiong次发送,在一个Setm的配置周期内,为等级索引为g的终端配置连续的Repetitiong个subset,且起始subset索引StartingSubsetIndexg按照下面公式计算:In an optional embodiment, a maximum of D*P subsets are configured in the configuration period of the Set m , and an index of the subset is a subset 0 to a subset (D*P-1), where the terminal with a level index of g corresponds to The subset configuration scheme includes: the terminal with the level index g is configured to repeat the Repetition g times in the time domain, and configure a continuous Repetition g subset for the terminal with the level index g in a configuration period of the set m , and The starting subset index StartingSubsetIndex g is calculated according to the following formula:
其中,0≤g≤G-1,G为划分的终端的等级的数量。Where 0 ≤ g ≤ G-1, and G is the number of levels of the divided terminals.
在一个可选的实施例中,不同的Setm的配置周期之间,等级索引为g的终端对应的subset配置方案是相同的。In an optional embodiment, the configuration of the subset corresponding to the terminal with the level index g is the same between the configuration periods of different Set m .
在一个可选的实施例中,当上行带宽包括48个子载波间隔为3.75kHz的子载波时,该子载波索引为0~47,其中,索引为0,1,14,15,16,17,30,31,32,33,46,47的子载波
不配置给Setm。In an optional embodiment, when the uplink bandwidth includes 48 subcarriers with a subcarrier spacing of 3.75 kHz, the subcarrier index is 0 to 47, where the index is 0, 1, 14, 15, 16, 17, The subcarriers of 30, 31, 32, 33, 46, 47 are not configured for Set m .
在一个可选的实施例中,当上行带宽包括48个子载波,该子载波索引为0~47,F=24,且所述Setm的起始子载波索引为2时,索引为2~25的子载波配置给所述Setm。其中,“~”的意思是“至”的意思,例如,索引为2~25的子载波为索引从2至25的24个子载波,下述的实施例中均是类似的,不再赘述。In an optional embodiment, when the uplink bandwidth includes 48 subcarriers, the subcarrier index is 0 to 47, F=24, and the initial subcarrier index of the Set m is 2, the index is 2-25. The subcarriers are configured for the Set m . The meaning of "to" means "to". For example, the subcarriers with an index of 2 to 25 are 24 subcarriers whose indices are from 2 to 25. The following embodiments are similar and will not be described again.
在一个可选的实施例中,当上行带宽包括48个子载波,该子载波索引为0~47,F=36,且所述Setm的起始子载波索引为2时,索引为2~37的子载波配置给所述Setm。In an optional embodiment, when the uplink bandwidth includes 48 subcarriers, the subcarrier index is 0 to 47, F=36, and the initial subcarrier index of the Set m is 2, the index is 2 to 37. The subcarriers are configured for the Set m .
在一个可选的实施例中,当上行带宽包括48个子载波,该子载波索引为0~47,F=24,且Setm的起始子载波索引为18时,索引为18~41的子载波配置给所述Setm。In an optional embodiment, when the uplink bandwidth includes 48 subcarriers, the subcarrier index is 0 to 47, F=24, and the initial subcarrier index of Set m is 18, the index is 18 to 41. The carrier is configured to the Set m .
在一个可选的实施例中,上述Setm中的F个子载波中,随机接入信道占用的子载波数量Num在F个子载波中的比例为Ratio,其中,该Ratio由基站通过信令发送给所述终端。In an optional embodiment, among the F subcarriers in the Set m , the ratio of the number of subcarriers Num occupied by the random access channel in the F subcarriers is Ratio, wherein the Ratio is sent by the base station to the signaling. The terminal.
在一个可选的实施例中,上述F的取值为{12,24,36,48}。In an alternative embodiment, the value of F above is {12, 24, 36, 48}.
在一个可选的实施例中,上述Ratio的取值为{1/6,2/6,3/6,4/6,5/6,6/6}或{1/12,2/12,3/12,4/12,5/12,6/12,7/12,8/12,9/12,10/12,11/12,12/12}或{0/12,1/12,2/12,3/12,4/12,5/12,6/12,7/12,8/12,9/12,10/12,11/12,12/12}或{0/6,1/6,2/6,3/6,4/6,5/6,6/6}。In an optional embodiment, the value of the Ratio is {1/6, 2/6, 3/6, 4/6, 5/6, 6/6} or {1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12, 9/12, 10/12, 11/12, 12/12} or {0/12, 1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12, 9/12, 10/12, 11/12, 12/12} or {0/6, 1/6, 2/6, 3/6, 4/6, 5/6, 6/6}.
在一个可选的实施例中,上述Setm中的F个子载波中,用于发送随机接入信号的随机接入信道占用的子载波数量为Num。In an optional embodiment, among the F subcarriers in the Set m , the number of subcarriers occupied by the random access channel for transmitting the random access signal is Num.
在一个可选的实施例中,上述F的取值为{12,24,36,48}。In an alternative embodiment, the value of F above is {12, 24, 36, 48}.
在一个可选的实施例中,上述Num取值为{4,8,12,16,20,24,28,32,36,40,44,48}或{3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48}或{0,4,8,12,16,20,24,28,32,36,40,44,48}或{0,3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48}。In an optional embodiment, the value of Num is {4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48} or {3, 6, 9, 12, 15 ,18,21,24,27,30,33,36,39,42,45,48} or {0,4,8,12,16,20,24,28,32,36,40,44,48 } or {0,3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48}.
在一个可选的实施例中,上述终端向基站发送随机接入信号的所述随机接入信道由所述基站通过信令分配给所述终端。在本实施例中,信令可以包括以下至少之一:针对单个终端的信令、针对单个处于连接状态的终端的信令、承载在控制信道上发送的信令。In an optional embodiment, the random access channel that the terminal sends a random access signal to the base station is allocated by the base station to the terminal by using signaling. In this embodiment, the signaling may include at least one of: signaling for a single terminal, signaling for a single terminal in a connected state, and signaling transmitted on a control channel.
在一个可选的实施例中,上述信令中包括以下信息至少之一:起始的等级索引;基站分配给终端的上述随机接入信道所在的频域位置信息;基站分配给终端的上述随机接入信道所在的时域位置信息。In an optional embodiment, the signaling includes at least one of the following: a starting level index; frequency domain location information of the random access channel allocated by the base station to the terminal; and the random number allocated by the base station to the terminal Time domain location information of the access channel.
在一个可选的实施例中,上述基站分配给终端的随机接入信道所在的频域位置信息包括:组成所述随机接入信号的单元Unit的Group0发送时所在的子载波或子信道索引。可选地,Unit
中除Group0之外的其他几个Group所在的频域资源由Group0的频域位置指示(例如,可以按照预定义规则,根据Group0的频域确定)。In an optional embodiment, the frequency domain location information of the random access channel allocated by the base station to the terminal includes: a subcarrier or a subchannel index where the group 0 of the unit that constitutes the random access signal is sent. . Optionally, the frequency domain resources of several groups other than Group 0 in the unit are indicated by the frequency domain location of Group 0 (for example, according to a predefined rule, determined according to the frequency domain of Group 0 ).
在一个可选的实施例中,当上行带宽包括48个子载波或子信道时,通过6bits指示信息指示基站分配给所述终端的所述随机接入信道所在的频域位置信息。在本实施例中,例如“000000”代表索引为0的Subcarrior,索引“101111”代表索引为47的Subcarrior。In an optional embodiment, when the uplink bandwidth includes 48 subcarriers or subchannels, the 6bits indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal. In the present embodiment, for example, "000000" represents a Subcarrior whose index is 0, and the index "101111" represents a Subcarrior whose index is 47.
在一个可选的实施例中,上述6bits指示信息还用于指示终端在Setm中的F个子载波中随机选择一个子载波作为随机接入信道所在的频域位置。例如,“110000”可以指示所述终端在Setm中的F个子载波中随机选择一个子载波作为随机接入信道所在的频域位置。In an optional embodiment, the foregoing 6 bits indication information is further used to indicate that the terminal randomly selects one subcarrier among the F subcarriers in Set m as the frequency domain location where the random access channel is located. For example, “110000” may indicate that the terminal randomly selects one subcarrier among the F subcarriers in Set m as the frequency domain location where the random access channel is located.
在一个可选的实施例中,当Setm中包括F个子载波或子信道时,通过指示信息指示基站分配给终端的随机接入信道所在的频域位置信息。在本实施例中,是向上取整操作运算符。In an alternative embodiment, when included in Set m F subcarriers or subchannels, by The indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal. In this embodiment, Is the rounding operation operator.
在一个可选的实施例中,指示信息还用于指示终端在Setm中的F个子载波中随机选择一个子载波作为终端的随机接入信道所在的频域位置。在本实施例中,是向上取整操作运算符。In an alternative embodiment, The indication information is further used to indicate that the terminal randomly selects one subcarrier among the F subcarriers in the Set m as the frequency domain location where the random access channel of the terminal is located. In this embodiment, Is the rounding operation operator.
在一个可选的实施例中,当上述Setm中包括F个子载波或子信道时,通过指示信息指示基站分配给所述终端的所述随机接入信道所在的频域位置信息,其中,Num为随机接入信道占用的子载波数量。In an optional embodiment, when the above set M includes F subcarriers or subchannels, The indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal, where Num is the number of subcarriers occupied by the random access channel.
在一个可选的实施例中,上述基站分配给终端的所述随机接入信道所在的时域位置信息包括:第二Setm的配置周期指示信息n;其中,所述基站分配给所述终端的所述随机接入信道所在的Setm定义为第二Setm;所述第二Setm为从第一Setm中选择的;且第二Setm的配置周期长度为第一Setm的配置周期的n倍,n为正整数;所述第一Setm为所述随机接入信道资源包括的一个或多个时频资源集合Setm,n为正整数。当n=1时,说明第一Setm与第二Setm是相等的。In an optional embodiment, the time domain location information of the random access channel allocated by the base station to the terminal includes: configuration period indication information n of the second Set m ; wherein the base station is allocated to the terminal Set m of the random access channel is defined as a second location Set m; the second Set m is selected from the first Set m; the length of the second period, and arranged Set m as a first configuration Set m n times the period, n is a positive integer; the first Set m is one or more time-frequency resource sets Set m included in the random access channel resource, and n is a positive integer. When n=1, it is stated that the first Set m and the second Set m are equal.
在一个可选的实施例中,包括以下至少之一:当n的取值由3bit描述时,n的取值为{1,2,3,4,5,6,7,8}或{1,2,4,8,16,32,64,128}或{1,2,4,8,10,12,14,16};当n的取值由2bit描述时,n的取值为{1,2,3,4}或{1,2,4,8}或{1,4,6,8}。In an optional embodiment, at least one of the following is included: when the value of n is described by 3 bits, the value of n is {1, 2, 3, 4, 5, 6, 7, 8} or {1 , 2, 4, 8, 16, 32, 64, 128} or {1, 2, 4, 8, 10, 12, 14, 16}; when the value of n is described by 2 bits, the value of n is { 1,2,3,4} or {1,2,4,8} or {1,4,6,8}.
在一个可选的实施例中,上述基站分配给终端的随机接入信道所在的时域位置为:第二
Setm的配置周期内的第一个第一Setm。In an optional embodiment, the time domain location of the random access channel allocated by the base station to the terminal is: the first first Set m in the configuration period of the second Set m .
在一个可选的实施例中,上述基站分配给终端的随机接入信道所在的时域位置信息还包括:第二Setm在第二Setm的配置周期内的位置信息Offset;其中,该Offset用于指示第二Setm的配置周期内的n个第一Setm中,分配给所述终端的所述随机接入信道所在的第一Setm的索引信息。In an alternative embodiment, the base station assigned to the time domain location of the random access channel terminal is located further comprising: a second position information Offset Set m arranged in a period of the second Set m; wherein the Offset Set m for n first configuration in a second period indicative of Set m, allocated to the index information of the random access channel where the first terminal of the Set m.
在一个可选的实施例中,上述基站分配给终端的所述随机接入信道所在的时域位置信息包括:连续两个第二Setm时域间隔信息Interval;上述基站分配给所述终端的所述随机接入信道所在的Setm定义为第二Setm;所述第二Setm为从第一Setm中选择的,且连续两个第二Setm之间间隔Interval个第一Setm;所示第一Setm为所述随机接入信道资源包括的一个或多个时频资源集合Setm。In an alternative embodiment, the base station assigned to the domain location information of the random access channel where a terminal comprising: a field interval information Interval Set m consecutive two second time; and the base station allocates to the terminal Set m of the random access channel is defined as a second location Set m; Set m between the second selected Set m from the first, and the second two consecutive first-Set m interval interval Set m The first set m is shown as one or more time-frequency resource sets Set m included in the random access channel resource.
在一个可选的实施例中,上述信令中还包括:触发定位操作指示信息。例如“0”表示不触发定位操作;“1”表示触发定位操作。In an optional embodiment, the signaling further includes: triggering positioning operation indication information. For example, “0” means that the positioning operation is not triggered; “1” means that the positioning operation is triggered.
在一个可选的实施例中,上述触发定位操作指示信息为触发定位操作时,所述终端在所述信令分配的随机接入信道上发送所述随机接入信号。在本实施例中,终端发送的上述随机接入信号用来供基站进行终端的位置定位使用。In an optional embodiment, when the trigger location operation indication information is a trigger location operation, the terminal sends the random access signal on the signaling random access channel. In this embodiment, the random access signal sent by the terminal is used by the base station to perform location location use of the terminal.
在一个可选的实施例中,终端在发送所述随机接入信号给所述基站之后,上述方法还包括:终端接收基站在检测随机接入信号后,根据检测结果发送的随机接入响应消息;其中,该随机接入响应消息中包括以下信息中至少之一:子载波间隔指示信息;配置的子载波数量指示信息。在本实施例中,子载波间隔指示信息可以用来指示Msg3消息发送时子载波间隔配置。In an optional embodiment, after the terminal sends the random access signal to the base station, the method further includes: receiving, by the terminal, a random access response message sent by the base station according to the detection result after detecting the random access signal. The random access response message includes at least one of the following information: subcarrier spacing indication information; configured subcarrier number indication information. In this embodiment, the subcarrier spacing indication information may be used to indicate the subcarrier spacing configuration when the Msg3 message is sent.
在一个可选的实施例中,上述子载波间隔指示信息和配置的子载波数量指示信息通过联合编码方式指示。In an optional embodiment, the foregoing subcarrier spacing indication information and the configured subcarrier number indication information are indicated by a joint coding manner.
下面结合具体实施例对本发明进行说明:The present invention will be described below in conjunction with specific embodiments:
具体实施例1 Specific embodiment 1
在通信系统中,终端可以跟据第一规则从序列集合中选择对应的序列,并且至少根据选择的序列生成随机接入信号;终端通过随机接入信道发送随机接入信号至基站。In the communication system, the terminal may select a corresponding sequence from the sequence set according to the first rule, and generate a random access signal according to at least the selected sequence; the terminal transmits the random access signal to the base station through the random access channel.
在本实施例中,可以将终端划分为2个集合,即第一终端集合和第二终端集合,且第一终端集合和第二终端集合可以满足以下条件:In this embodiment, the terminal may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set may satisfy the following conditions:
第一终端集合包括的终端为采用多个子载波传输Msg3消息的终端,第二终端集合包括的终端为采用单个子载波传输Msg3消息的终端。
The terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers, and the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier.
下面首先对发送端的操作进行说明:The following first describes the operation of the sender:
终端跟据第一规则从序列集合中选择对应的序列,包括:The terminal selects a corresponding sequence from the sequence set according to the first rule, including:
属于第一终端集合的终端选择序列Code0;属于第二终端集合的终端选择序列Code1;a terminal selection sequence Code 0 belonging to the first terminal set; a terminal selection sequence Code 1 belonging to the second terminal set;
终端跟据第一规则从序列集合中选择对应的序列(j=0或1)之后,按照如下步骤生成随机接入信号:The terminal selects a corresponding sequence from the sequence set according to the first rule After (j=0 or 1), generate a random access signal as follows:
步骤1:频域上索引为fn(0≤n≤3)的子载波且时域上占用连续的K个符号发送则第k个符号且子载波fn上发送的信号的频域表达式为则上述K个符号且子载波fn上发送的信号的频域表达式为
Step 1: Subcarriers indexed as f n (0 ≤ n ≤ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
步骤2:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度。为索引为fn的子载波占用的频域资源,FOffset为频域偏移量。Step 2: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol. For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset.
当时域采样间隔为Ts时,对应的时域的表达式为0≤k≤K-1,0≤q≤Q-1,为时域采样点数量;When the domain sampling interval is T s , The corresponding time domain expression is 0 ≤ k ≤ K-1, 0 ≤ q ≤ Q-1, The number of sampling points in the time domain;
则终端在连续的K个符号上发送的时域信号表达式为
Then the terminal sends on consecutive K symbols The time domain signal expression is
步骤3:上述终端除了发送Sn之外,还发送:循环前缀CPn,其中,该循环前缀CPn={Sn[QK-L+1],…,Sn[QK]},L表示CP中包括的时域采样间隔Ts的数量。Step 3: The terminal sends a cyclic prefix CP n in addition to the S n , wherein the cyclic prefix CP n ={S n [QK-L+1],...,S n [QK]}, L represents The number of time domain sampling intervals T s included in the CP.
步骤4:定义Groupn为{CPn,Sn},即为终端发送(0≤j≤J-1,0≤n≤N-1)对应的时域信号的表达形式;且n取值不同的Groupn在时域上占用不同的符号。Step 4: Define Group n as {CP n , S n }, that is, send the terminal (0 ≤ j ≤ J-1, 0 ≤ n ≤ N-1) the expression form of the corresponding time domain signal; and Group n with different values of n occupy different symbols in the time domain.
步骤5:定义Group0~GroupN-1作为组成随机接入信号的基本单元(Unit)(对应于上述的单元)。
Step 5: Define Group 0 to Group N-1 as the basic unit (corresponding to the above unit) constituting the random access signal.
步骤6:终端发送的随机接入信号由Unit在时域上重复H次形成,或者,终端发送的随机接入信号由一个Unit形成,其中,当随机接入信号由一个Unit形成时,在发送该随机接入信号时将随机接入信号重复H次再进行发送;Step 6: The random access signal sent by the terminal is formed by the Unit repeating H times in the time domain, or the random access signal sent by the terminal is formed by a Unit, where when the random access signal is formed by a Unit, it is sent. When the random access signal is used, the random access signal is repeated H times and then sent;
其中,不同等级的终端配置的重复次数H不同。Among them, the number of repetitions H of different levels of terminal configurations is different.
可选地,上述等级可以包括以下至少之一:覆盖增强等级;物理信道重复发送等级;物理信道上承载的消息或信令的重复发送等级。Optionally, the foregoing level may include at least one of the following: an coverage enhancement level; a physical channel repetition transmission level; and a repeated transmission level of a message or signaling carried on the physical channel.
在本实施例中,系统配置的随机接入信道的子载波间隔Δf可以为3.75KHz,时域符号长度(微秒)。循环前缀CPn长度配置为266.7us,K=5,则Groupn时域长度为1.6ms(毫秒)。由于N=4,则Group0~Group3作为所述终端生成所述随机接入信号的基本单元(Unit)的长度为6.4ms;In this embodiment, the subcarrier spacing Δf of the random access channel configured by the system may be 3.75 kHz, and the time domain symbol length is (microseconds). The cyclic prefix CP n length is configured to be 266.7us, K=5, and the Group n time domain length is 1.6ms (milliseconds). The length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
在本实施例中,Group0~Group3对应的频域子载波索引f0~f3分别为subcarrior0,subcarrior1,subcarrior7,subcarrior6,则所述终端生成所述随机接入信号的基本单元(Unit)的时域和频域的二维结构如图2所示,Group0和Group1配置的子载波相邻,Group2和Group3配置的子载波相邻,Group1和Group2配置的子载波间隔6个子载波。进一步,根据Group0的子载波索引可以确定Group1、Group2和Group3的子载波索引。In the present embodiment, Group 0 ~ Group 3 corresponding to frequency domain subcarrier index f 0 ~ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially The two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 2, the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the group 1 and Group 2 are configured. The subcarriers are separated by 6 subcarriers. Further, the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
在本实施例中,所述终端配置的重复次数为1次,则只需要发送基本单元(Unit)一次。In this embodiment, if the number of repetitions of the terminal configuration is one, only the basic unit (Unit) needs to be sent once.
在本实施例中,所述终端发送随机接入信号占用的随机接入信道资源包含在1个时频资源集合Setm中,m为所述Setm的索引。如图3所示,所述Setm在频域上包括12个子载波,分别为Subcarrior0~Subcarrior11,所述Setm在时域上长度至少为Unit的时域长度的4倍,本实施例中,Setm的时域长度为26ms,除了包含4个Unit的时域长度之外,还包括0.4ms的保护时间(Guard Time)。所述终端在Setm中的Resource 0上分别发送Unit。In this embodiment, the random access channel resource occupied by the terminal transmitting the random access signal is included in one time-frequency resource set Set m , where m is an index of the Set m . As shown in FIG. 3, the set m includes 12 subcarriers in the frequency domain, which are respectively Subcarrior0-Subcarrior11, and the set m is at least four times longer than the time domain length of the unit in the time domain. In this embodiment, Set m has a time domain length of 26ms. In addition to the time domain length of 4 Units, it also includes a guard time of 0.4ms. The terminal sends a Unit on Resource 0 in Set m .
下面对接收端的操作进行说明:The following describes the operation of the receiving end:
接收端所执行的动作包括:The actions performed by the receiving end include:
步骤1:基站接收Group0~Group3上的数据,并且对每个group中的5个符号上接收到的数据进行合并,得到Group0~Group3上合并后的接收数据Y0,Y1,Y2,Y3;Step 1: The base station receives the data on Group 0 to Group 3 , and combines the data received on the five symbols in each group to obtain the combined received data Y0, Y1, Y2 on Group 0 to Group 3 . Y3;
步骤2:按照下面公式计算,得到[Corr1,Corr 2]:
Step 2: Calculate according to the following formula to get [Corr1, Corr 2]:
步骤3:基站分别用[1,1]和[1,-1]与接收到的[Corr1,Corr 2]进行相干检测,当[1,1]与[Corr1,Corr 2]检测的能量值大于[1,-1]与[Corr1,Corr 2]检测的能量值,则判定终端发送的code为code0;否则,判定UE发送的code为code1。Step 3: The base station performs coherent detection with [1, 1] and [1, -1] and [Corr1, Corr 2], respectively, when the energy values detected by [1, 1] and [Corr1, Corr 2] are greater than [1, -1] and the energy value detected by [Corr1, Corr 2], it is determined that the code transmitted by the terminal is code0; otherwise, it is determined that the code transmitted by the UE is code1.
步骤4:基站在判断出来终端发送的code之后,进一步完成终端上行同步定时误差的估计。Step 4: After determining the code sent by the terminal, the base station further completes the estimation of the terminal uplink synchronization timing error.
基站在成功完成终端发送的随机接入信号检测以及终端的上行定时同步偏差估计后,就会发送随机接入响应消息(Random Access Response,简称为RAR,又叫做消息2,Message2,简称Msg2)给终端。终端接收到RAR消息,获得上行定时同步信息和上行资源。但此时并不能确定RAR消息是发送给终端自己而不是发送给其他的终端的,因为存在着不同的终端在相同的时间-频率资源上发送相同随机接入信号的可能性(这种情况叫做随机接入冲突),为此终端需要在RAR中分配的上行资源上发送消息3(Message3,简称为Msg3)来解决随机接入冲突。在初始随机接入过程中,Msg3中会携带一个终端的特定的ID,用于区分不同的终端。After successfully completing the random access signal detection sent by the terminal and the uplink timing synchronization deviation estimation of the terminal, the base station sends a random access response message (RAR, also referred to as message 2, Message 2, referred to as Msg2) to the base station. terminal. The terminal receives the RAR message, and obtains uplink timing synchronization information and uplink resources. However, it is not certain at this time that the RAR message is sent to the terminal itself rather than to other terminals because there is a possibility that different terminals transmit the same random access signal on the same time-frequency resource (this case is called For random access conflicts, the terminal needs to send a message 3 (Message3, referred to as Msg3) on the uplink resource allocated in the RAR to solve the random access conflict. In the initial random access process, Msg3 carries a specific ID of a terminal to distinguish different terminals.
终端在基站配置的Msg3消息资源上发送Msg3消息,基站在接收到终端发送的Msg3后,通过发送消息4(Message4,简称为Msg4)最终解决这样的随机接入冲突。其中,Msg4中会携带终端在Msg3中发送的特定的ID。终端接收到基站发送的Msg4消息,并且其中携带的ID与自己在Msg3中上报给基站的特定ID相符,那么终端就认为自己赢得了此次的随机接入冲突,随机接入成功;否则,终端认为此次接入失败,并重新进行随机接入过程。The terminal sends an Msg3 message on the Msg3 message resource configured by the base station. After receiving the Msg3 sent by the terminal, the base station finally solves such a random access conflict by sending a message 4 (Message4, referred to as Msg4). Among them, Msg4 will carry a specific ID sent by the terminal in Msg3. When the terminal receives the Msg4 message sent by the base station, and the ID carried in the terminal matches the specific ID reported to the base station in Msg3, the terminal considers that it has won the random access collision and the random access succeeds; otherwise, the terminal It is considered that the access fails and the random access process is re-executed.
可选地,序列集合中2条长度为N=4的序列包括以下至少之一:
Optionally, two sequences of length N=4 in the sequence set include at least one of the following:
可选地,第一终端集合和第二终端集合还可以是以下至少之一:Optionally, the first terminal set and the second terminal set may also be at least one of the following:
第一终端集合包括的终端为支持多个子载波同时传输的终端,且第二终端集合包括的终端为仅支持单个子载波传输的终端;
The terminal included in the first terminal set is a terminal that supports simultaneous transmission of multiple subcarriers, and the terminal included in the second terminal set is a terminal that supports only single subcarrier transmission;
第一终端集合包括的终端为采用多个子载波传输上行数据的终端,且第二终端集合包括的终端为采用单个子载波传输上行数据的终端;The terminal included in the first terminal set is a terminal that uses multiple subcarriers to transmit uplink data, and the terminal included in the second terminal set is a terminal that transmits uplink data by using a single subcarrier;
第一终端集合包括的终端为Msg3消息承载在多个子载波上传输的终端,且第二终端集合包括的终端为Msg3消息仅承载在单个子载波传输的终端。The terminal included in the first terminal set is a terminal that is transmitted by the Msg3 message on multiple subcarriers, and the terminal included in the second terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission.
具体实施例2 Specific embodiment 2
通信系统中,终端从序列集合中选择对应的序列,并且至少根据选择的对应的序列生成随机接入信号;终端通过随机接入信道发送随机接入信号至基站。In the communication system, the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
其中,可以将多个终端划分为2个集合,即第一终端集合和第二终端集合。The multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set.
终端从序列集合中选择对应的序列,包括:The terminal selects a corresponding sequence from the sequence set, including:
属于第一终端集合的终端选择序列Code0;属于第二终端集合的终端选择序列Code1;a terminal selection sequence Code 0 belonging to the first terminal set; a terminal selection sequence Code 1 belonging to the second terminal set;
终端选择序列(j=0或1)之后,可以按照如下步骤生成随机接入信号:Terminal selection sequence After (j=0 or 1), the random access signal can be generated as follows:
步骤1:频域上索引为fn(0≤n≤3)的子载波且时域上占用连续的K个符号发送则第k个符号且子载波fn上发送的信号的频域表达式为则上述K个符号且子载波fn上发送的信号的频域表达式为
Step 1: Subcarriers indexed as f n (0 ≤ n ≤ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
步骤2:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度。为索引为fn的子载波占用的频域资源,FOffset为频域偏移量。Step 2: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol. For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset.
当时域采样间隔为Ts时,对应的时域的表达式为0≤k≤K-1,0≤q≤Q-1,为时域采样点数量;
When the domain sampling interval is T s , The corresponding time domain expression is 0 ≤ k ≤ K-1, 0 ≤ q ≤ Q-1, The number of sampling points in the time domain;
则终端在连续的K个符号上发送的时域信号表达式为
Then the terminal sends on consecutive K symbols The time domain signal expression is
步骤3:上述终端除了发送Sn之外,还发送:Step 3: In addition to sending S n , the above terminal sends:
循环前缀CPn,其中,该循环前缀CPn={Sn[QK-L+1],…,Sn[QK]},L表示CP中包括的时域采样间隔Ts的数量。The cyclic prefix CP n , wherein the cyclic prefix CP n = {S n [QK-L+1], ..., S n [QK]}, L represents the number of time domain sampling intervals T s included in the CP.
步骤4:可以定义Groupn为{CPn,Sn},即为终端发送对应的时域信号的表达形式;且n取值不同的Groupn在时域上占用不同的符号。Step 4: You can define Group n as {CP n , S n }, which is sent by the terminal. The expression of the corresponding time domain signal; and the Group n with different values of n occupy different symbols in the time domain.
步骤5:定义Group0~GroupN-1作为所述终端生成所述随机接入信号的基本单元(Unit);Step 5: Define Group 0 to Group N-1 as a basic unit (Unit) for generating the random access signal by the terminal;
步骤6:上述终端发送的随机接入信号由Unit在时域上重复H次组成;Step 6: The random access signal sent by the terminal is repeated by the Unit H in the time domain;
可选地,不同等级的终端配置的重复次数H不同。Optionally, the number of repetitions H of different levels of terminal configurations is different.
可选地,终端的等级包括以下至少之一:Optionally, the level of the terminal includes at least one of the following:
覆盖增强等级;Coverage enhancement level;
物理信道重复发送等级;Physical channel repeat transmission level;
物理信道上承载的消息或信令的重复发送等级。Repeated transmission level of messages or signaling carried on the physical channel.
在本实施例中,系统配置的随机接入信道的子载波间隔Δf为3.75KHz,时域符号长度(微秒)。循环前缀CPn长度配置为266.7us,K=5,则Groupn时域长度为1.6ms(毫秒)。由于N=4,则Group0~Group3作为所述终端生成所述随机接入信号的基本单元(Unit)的长度为6.4ms;In this embodiment, the subcarrier spacing Δf of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds). The cyclic prefix CP n length is configured to be 266.7us, K=5, and the Group n time domain length is 1.6ms (milliseconds). The length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
本实施例中,Group0~Group3对应的频域子载波索引f0~f3分别为subcarrior0,subcarrior1,subcarrior7,subcarrior6,则所述终端生成所述随机接入信号的基本单元(Unit)的时域和频域的二维结构如图4所示,Group0和Group1配置的子载波相邻,Group2和Group3配置的子载波相邻,Group1和Group2配置的子载波间隔6个子载波。进一步,根据Group0的子载波索引可以确定Group1、Group2和Group3的子载波索引。In this embodiment, Group 0 ~ Group 3 corresponding to frequency domain subcarrier index f 0 ~ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, the basic unit of the terminal generates a random access signal The two-dimensional structure of the time domain and the frequency domain of (Unit) is as shown in FIG. 4, the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the configurations of Group 1 and Group 2 are configured. The subcarriers are separated by 6 subcarriers. Further, the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
在本实施例中,终端配置的重复次数H=1,则只需要发送基本单元(Unit)一次。In this embodiment, if the number of repetitions of the terminal configuration is H=1, only the basic unit (Unit) needs to be transmitted once.
在本实施例中,终端发送随机接入信号占用的随机接入信道资源包含在1个时频资源集
合Setm中,m为所述Setm的索引。如图5所示,所述Setm在频域上包括12个子载波,分别为Subcarrior0~Subcarrior11,所述Setm在时域上长度至少为Unit的时域长度的4倍,本实施例中,Setm的时域长度为26ms,除了包含4个Unit的时域长度之外,还包括0.4ms的保护时间(Guard Time)。Setm占用的频率资源的上下各配置有7.5kHz保护带宽(Guard band);所述终端在Setm中的subset 0上分别发送Unit。In this embodiment, the random access channel resource occupied by the terminal transmitting the random access signal is included in one time-frequency resource set Set m , where m is an index of the Set m . As shown in FIG. 5, the set m includes 12 subcarriers in the frequency domain, which are respectively Subcarrior0-Subcarrior11, and the set m is at least four times longer than the time domain length of the unit in the time domain. In this embodiment, Set m has a time domain length of 26ms. In addition to the time domain length of 4 Units, it also includes a guard time of 0.4ms. The upper and lower frequency resources occupied by Set m are configured with 7.5 kHz guard bandwidth; the terminal sends Units on subset 0 in Set m .
基站可以按照下面的步骤接收终端发送的随机接入信号:The base station can receive the random access signal sent by the terminal according to the following steps:
步骤1:基站接收Group0~Group3上的数据,并且对每个group中的5个符号上接收到的数据进行合并,得到Group0~Group3上合并后的接收数据Y0,Y1,Y2,Y3;Step 1: The base station receives the data on Group 0 to Group 3 , and combines the data received on the five symbols in each group to obtain the combined received data Y0, Y1, Y2 on Group 0 to Group 3 . Y3;
步骤2:[Y0,Y1]、[Y2,Y3]分别与[1,1]进行相干检测后,检测结果相加记作Corr1;[Y0,Y1]、[Y2,Y3]分别与[1,-1]进行相干检测后,检测结果相加记作Corr2;当Corr1大于Corr2时,则判定终端发送的code为code0;否则,判定UE发送的code为code1。Step 2: After [Y0, Y1], [Y2, Y3] are coherently detected with [1, 1], the detection results are added together as Corr1; [Y0, Y1], [Y2, Y3] and [1, respectively -1] After performing coherent detection, the detection results are added as Corr2; when Corr1 is larger than Corr2, it is determined that the code transmitted by the terminal is code0; otherwise, it is determined that the code transmitted by the UE is code1.
步骤3:基站在判断出来终端发送的code之后,进一步完成终端的上行定时同步偏差估计。Step 3: After determining the code sent by the terminal, the base station further completes the uplink timing synchronization deviation estimation of the terminal.
具体实施例3 Specific embodiment 3
在通信系统中,终端从序列集合中选择对应的序列,并且至少根据选择的对应的序列生成随机接入信号;终端通过随机接入信道发送随机接入信号至基站。In the communication system, the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
其中,可以将多个终端划分为2个集合,即第一终端集合和第二终端集合。The multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set.
终端从序列集合中选择对应的序列,包括:The terminal selects a corresponding sequence from the sequence set, including:
属于第一终端集合的终端选择序列Code0;属于第二终端集合的终端选择序列Code1;a terminal selection sequence Code 0 belonging to the first terminal set; a terminal selection sequence Code 1 belonging to the second terminal set;
终端选择序列(j=0或1)之后,可以按照如下步骤生成所述随机接入信号:Terminal selection sequence After (j=0 or 1), the random access signal can be generated as follows:
步骤1:频域上索引为fn(0≤n≤7)的子载波且时域上占用连续的K个符号发送则第k个符号且子载波fn上发送的信号的频域表达式为则上述K
个符号且子载波fn上发送的信号的频域表达式为
Step 1: Subcarriers indexed as f n (0 ≤ n ≤ 7) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
步骤2:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度。为索引为fn的子载波占用的频域资源,FOffset为频域偏移量。Step 2: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol. For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset.
当时域采样间隔为Ts时,对应的时域的表达式为
为时域采样点数量;When the domain sampling interval is T s , The corresponding time domain expression is The number of sampling points in the time domain;
则终端在连续的K个符号上发送的时域信号表达式为
Then the terminal sends on consecutive K symbols The time domain signal expression is
步骤3:所述终端除了发送Sn之外,还发送:循环前缀CPn,其中,该循环前缀CPn={Sn[QK-L+1],…,Sn[QK]},L表示CP中包括的时域采样间隔Ts的数量。Step 3: The terminal sends a cyclic prefix CP n in addition to the S n , wherein the cyclic prefix CP n = {S n [QK-L+1], ..., S n [QK]}, L Indicates the number of time domain sampling intervals T s included in the CP.
步骤4:可以定义Groupn为{CPn,Sn}即为终端发送对应的时域信号的表达形式;且n取值不同的Groupn在时域上占用不同的符号。Step 4: You can define that Group n is {CP n , S n } The expression of the corresponding time domain signal; and the Group n with different values of n occupy different symbols in the time domain.
步骤5:可以定义Group0~GroupN-1作为所述终端生成所述随机接入信号的基本单元(Unit)。Step 5: Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
步骤6:所述终端发送的随机接入信号由所述Unit在时域上重复H次组成;Step 6: The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
其中,不同等级的终端配置的重复次数H不同。Among them, the number of repetitions H of different levels of terminal configurations is different.
上述终端的等可以级包括以下至少之一:The level of the above terminal may include at least one of the following:
覆盖增强等级;Coverage enhancement level;
物理信道重复发送等级;Physical channel repeat transmission level;
物理信道上承载的消息或信令的重复发送等级。Repeated transmission level of messages or signaling carried on the physical channel.
在本实施例中,系统配置的随机接入信道的子载波间隔Δf为3.75KHz,时域符号长度(微秒)。循环前缀CPn长度配置为66.7us,K=5,则Groupn时域长度为1.4ms
(毫秒)。由于N=8,则Group0~Group7作为所述终端生成所述随机接入信号的基本单元(Unit)的长度为11.2ms;In this embodiment, the subcarrier spacing Δf of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds). The cyclic prefix CP n length is configured to be 66.7us, K=5, and the Group n time domain length is 1.4ms (milliseconds). The length of the basic unit (Unit) that the group 0 to the group 7 generates the random access signal is 11.2 ms;
本实施例中,Group0~Group7对应的频域子载波索引f0~f7分别为subcarrior0,subcarrior1,subcarrior7,subcarrior6,subcarrior2,subcarrior3,subcarrior9,subcarrior8,则所述终端生成所述随机接入信号的基本单元(Unit)的时域和频域的二维结构如图6所示,Group0和Group1配置的子载波相邻,Group2和Group3配置的子载波相邻,Group4和Group5配置的子载波相邻,Group6和Group7配置的子载波相邻。In this embodiment, Group 0 ~ Group 7 corresponding to frequency domain subcarrier index f 0 ~ f 7 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, subcarrior 2, subcarrior 3, subcarrior 9, subcarrior 8, then the The two-dimensional structure of the time domain and the frequency domain of the basic unit (Unit) in which the terminal generates the random access signal is as shown in FIG. 6, and the subcarriers configured by Group 0 and Group 1 are adjacent, and the Group 2 and Group 3 are configured. The subcarriers are adjacent to each other, and the subcarriers configured by Group 4 and Group 5 are adjacent to each other, and the subcarriers configured by Group 6 and Group 7 are adjacent.
Group1和Group2配置的子载波间隔6个子载波,Group5和Group6配置的子载波间隔6个子载波。Group0和Group4的子载波索引间隔按照预定义规则确定,本实施例中Group0和Group4的子载波索引间隔为2个子载波;The subcarriers configured in Group 1 and Group 2 are separated by 6 subcarriers, and the subcarriers configured in Group 5 and Group 6 are separated by 6 subcarriers. Group 0 and Group 4 subcarrier index is determined according to a predefined interval rules Examples Group 0 and Group 4 subcarrier index interval is two subcarriers of the present embodiment;
在本实施例中,所述终端配置的重复次数H=1,则只需要发送基本单元(Unit)一次。In this embodiment, if the number of repetitions of the terminal configuration is H=1, only the basic unit (Unit) needs to be sent once.
在本实施例中,所述终端发送随机接入信号占用的随机接入信道资源包含在1个时频资源集合Setm中,m为所述Setm的索引。如图7所示,所述Setm在频域上包括12个子载波,分别为Subcarrior0~Subcarrior11,所述Setm在时域上长度至少为Unit的时域长度的3倍,本实施例中,Setm的时域长度为34ms,除了包含3个Unit的时域长度之外,还包括0.4ms的保护时间(Guard Time)。Setm占用的频率资源中分别在上下边带配置有7.5kHz保护带宽(Guard band);所述终端在Setm中的subset 0上发送Unit。In this embodiment, the random access channel resource occupied by the terminal transmitting the random access signal is included in one time-frequency resource set Set m , where m is an index of the Set m . As shown in FIG. 7 , the Set m includes 12 subcarriers in the frequency domain, which are respectively Subcarrior 0 ~ Subcarrior 11 , and the Set m is at least 3 times longer than the time domain length of the Unit in the time domain. In this embodiment, Set m has a time domain length of 34ms. In addition to the time domain length of 3 Units, it also includes a guard time of 0.4ms. The frequency resources occupied by Set m are respectively configured with 7.5 kHz guard bandwidth in the upper and lower sidebands; the terminal sends a Unit on subset 0 in Set m .
基站可以按照下面的步骤接收终端发送的随机接入信号:The base station can receive the random access signal sent by the terminal according to the following steps:
步骤1:基站接收Group0~Group7上的数据,并且对每个group中的5个符号上接收到的数据进行合并,得到Group0~Group7上合并后的接收数据Y0,Y1,Y2,Y3,Y4,Y5,Y6,Y7。Step 1: The base station receives the data on Group 0 to Group 7 , and combines the data received on the five symbols in each group to obtain the combined received data Y0, Y1, Y2 on Group 0 to Group 7 . Y3, Y4, Y5, Y6, Y7.
步骤2:[Y0,Y1,Y2,Y3,Y4,Y5,Y6,Y7]与[1,1,1,1,1,1,1,1]进行相干检测后,检测结果相加记作Corr1;[Y0,Y1,Y2,Y3,Y4,Y5,Y6,Y7]与[1,1,1,1,-1,-1,-1,-1]进行相干检测后,检测结果相加记作Corr2;当Corr1大于Corr2时,则判定终端发送的code为code0;否则,判定UE发送的code为code1。Step 2: [Y0, Y1, Y2, Y3, Y4, Y5, Y6, Y7] After coherent detection with [1,1,1,1,1,1,1,1], the test results are added together as Corr1 ;[Y0,Y1,Y2,Y3,Y4,Y5,Y6,Y7] and [1,1,1,1,-1,-1,-1,-1] after coherent detection, the test results are added together Corr2; when Corr1 is greater than Corr2, it is determined that the code sent by the terminal is code0; otherwise, it is determined that the code sent by the UE is code1.
步骤3:基站在判断出来终端发送的code之后,进一步完成终端的上行定时同步偏差估计。
Step 3: After determining the code sent by the terminal, the base station further completes the uplink timing synchronization deviation estimation of the terminal.
具体实施例4 Specific embodiment 4
在通信系统中,终端从序列集合中选择对应的序列,并且至少根据选择的对应的序列生成随机接入信号;终端通过随机接入信道发送随机接入信号至基站。In the communication system, the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
其中,可以将多个终端划分为2个集合,即第一终端集合和第二终端集合,且第一终端集合和第二终端集合满足以下条件:The multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set meet the following conditions:
所述第一终端集合包括的终端为采用多个子载波传输Msg3消息的终端,所述第二终端集合包括的终端为采用单个子载波传输Msg3消息的终端。The terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers, and the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier.
终端从序列集合中选择对应的序列,包括:The terminal selects a corresponding sequence from the sequence set, including:
属于第一终端集合的终端选择序列Code0;属于第二终端集合的终端选择序列Code1;a terminal selection sequence Code 0 belonging to the first terminal set; a terminal selection sequence Code 1 belonging to the second terminal set;
终端选择序列(j=0或1)之后,可以按照如下步骤生成所述随机接入信号:Terminal selection sequence After (j=0 or 1), the random access signal can be generated as follows:
步骤1:频域上索引为fn(0≤n≤3)的子载波且时域上占用连续的K个符号发送则第k个符号且子载波fn上发送的信号的频域表达式为则上述K个符号且子载波fn上发送的信号的频域表达式为
Step 1: Subcarriers indexed as f n (0 ≤ n ≤ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
步骤2:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度。为索引为fn的子载波占用的频域资源,FOffset为频域偏移量。Step 2: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol. For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset.
当时域采样间隔为Ts时,对应的时域的表达式为
为时域采样点数量;When the domain sampling interval is T s , The corresponding time domain expression is The number of sampling points in the time domain;
则终端在连续的K个符号上发送的时域信号表达式为
Then the terminal sends on consecutive K symbols The time domain signal expression is
步骤3:所述终端除了发送Sn之外,还发送:循环前缀CPn,其中,该循环前缀
CPn={Sn[QK-L+1],…,Sn[QK]},L表示CP中包括的时域采样间隔Ts的数量。Step 3: The terminal sends a cyclic prefix CP n in addition to the S n , wherein the cyclic prefix CP n ={S n [QK-L+1],...,S n [QK]},L Indicates the number of time domain sampling intervals T s included in the CP.
步骤4:可以定义Groupn为{CPn,Sn},即为终端发送对应的时域信号的表达形式;且n取值不同的Groupn在时域上占用不同的符号。Step 4: You can define Group n as {CP n , S n }, which is sent by the terminal. The expression of the corresponding time domain signal; and the Group n with different values of n occupy different symbols in the time domain.
步骤5:可以定义Group0~GroupN-1作为所述终端生成所述随机接入信号的基本单元(Unit)。Step 5: Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
步骤6:所述终端发送的随机接入信号由所述Unit在时域上重复H次组成;Step 6: The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
可选地,不同等级的终端配置的重复次数H不同。Optionally, the number of repetitions H of different levels of terminal configurations is different.
可选地,终端的等级可以包括以下至少之一:Optionally, the level of the terminal may include at least one of the following:
覆盖增强等级;Coverage enhancement level;
物理信道重复发送等级;Physical channel repeat transmission level;
物理信道上承载的消息或信令的重复发送等级。Repeated transmission level of messages or signaling carried on the physical channel.
在本实施例中,系统配置的随机接入信道的子载波间隔Δf为3.75KHz,时域符号长度(微秒)。循环前缀CPn长度配置为266.7us,K=5,则Groupn时域长度为1.6ms(毫秒)。由于N=4,则Group0~Group3作为所述终端生成所述随机接入信号的基本单元(Unit)的长度为6.4ms。In this embodiment, the subcarrier spacing Δf of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds). The cyclic prefix CP n length is configured to be 266.7us, K=5, and the Group n time domain length is 1.6ms (milliseconds). Since N=4, the length of the basic unit (Unit) that Group 0 to Group 3 generates as the random access signal is 6.4 ms.
在本实施例中,Group0~Group3对应的频域子载波索引f0~f3分别为subcarrior0,subcarrior1,subcarrior7,subcarrior6,则所述终端生成所述随机接入信号的基本单元(Unit)的时域和频域的二维结构如图8所示,Group0和Group1配置的子载波相邻,Group2和Group3配置的子载波相邻,Group1和Group2配置的子载波间隔6个子载波。进一步,根据Group0的子载波索引可以确定Group1、Group2和Group3的子载波索引。In the present embodiment, Group 0 ~ Group 3 corresponding to frequency domain subcarrier index f 0 ~ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially The two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 8. The subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the Group 1 and Group 2 are configured. The subcarriers are separated by 6 subcarriers. Further, the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
在本实施例中,所述终端配置的重复次数H=1,则只需要发送基本单元(Unit)一次。In this embodiment, if the number of repetitions of the terminal configuration is H=1, only the basic unit (Unit) needs to be sent once.
在本实施例中,所述终端发送随机接入信号占用的随机接入信道资源包含在1个时频资源集合Setm中,m为所述Setm的索引。如图9所示,所述Setm在频域上包括12个子载波,分别为Subcarrior0~Subcarrior11,所述Setm在时域上长度至少为Unit的时域长度的4倍,本实施例中,Setm的时域长度为26ms,除了包含4个Unit的时域长度之外,还包括0.4ms的保
护时间(Guard Time)。所述终端在Setm中的subset 0上分别发送Unit。In this embodiment, the random access channel resource occupied by the terminal transmitting the random access signal is included in one time-frequency resource set Set m , where m is an index of the Set m . As shown in FIG. 9 , the Set m includes 12 subcarriers in the frequency domain, which are respectively Subcarrior 0 ~ Subcarrior 11 , and the Set m is at least 4 times longer than the time domain length of the Unit in the time domain. In this embodiment, Set m has a time domain length of 26ms. In addition to the time domain length of 4 Units, it also includes 0.4ms Guard Time. The terminal sends a Unit on the subset 0 in Set m .
当上行带宽包括48个子载波,最多可以配置4个Setm,即如图10所示。通过2bit指示为终端配置的Setm的频域位置,例如配置“00”指示终端配置的Setm为配置“01”指示终端配置的Setm为配置“10”指示终端配置的Setm为配置“11”指示终端配置的Setm为
When the uplink bandwidth includes 48 subcarriers, up to 4 Set m can be configured. As shown in Figure 10. 2bit indicated by the frequency domain location of the terminal configuration Set m, e.g. Configuration "00" indicates that the terminal is configured Set m Configuration "01" indicates that the terminal is configured Set m Configuration "10" Set m indicates the terminal is configured Configuration "11" Set m indicates the terminal is configured
基站可以按照下面的步骤接收终端发送的随机接入信号:The base station can receive the random access signal sent by the terminal according to the following steps:
步骤1:基站接收Group0~Group3上的数据,并且对每个group中的5个符号上接收到的数据进行合并,得到Group0~Group3上合并后的接收数据Y0,Y1,Y2,Y3。Step 1: The base station receives the data on Group 0 to Group 3 , and combines the data received on the five symbols in each group to obtain the combined received data Y0, Y1, Y2 on Group 0 to Group 3 . Y3.
步骤2:按照下面公式计算,得到[Corr1,Corr 2]。Step 2: Calculate according to the following formula to obtain [Corr1, Corr 2].
步骤3:基站分别用[1,1]和[1,-1]与接收到的[Corr1,Corr 2]进行相干检测,当[1,1]与[Corr1,Corr 2]检测的能量值大于[1,-1]与[Corr1,Corr 2]检测的能量值,则判定终端发送的code为code0;否则,判定UE发送的code为code1。Step 3: The base station performs coherent detection with [1, 1] and [1, -1] and [Corr1, Corr 2], respectively, when the energy values detected by [1, 1] and [Corr1, Corr 2] are greater than [1, -1] and the energy value detected by [Corr1, Corr 2], it is determined that the code transmitted by the terminal is code0; otherwise, it is determined that the code transmitted by the UE is code1.
步骤4:基站在判断出来终端发送的code之后,进一步完成终端的上行定时同步偏差估计。Step 4: After determining the code sent by the terminal, the base station further completes the uplink timing synchronization deviation estimation of the terminal.
可选地,还可以通过位图bitmap来指示为终端配置的Setm,例如,当上行带宽包括48个子载波,最多可以配置4个Setm,即如图10所示。通过4bit的bitmap指示为终端配置的Setm的频域位置,例如配置“0001”指示终端配置的Setm为配置“0010”指示终端配置的Setm为配置“0100”指示终端配置的Setm为配置“1000”指示终端配置的Setm为配置“1100”指示终端配置的Setm为
Optionally, the set m configured for the terminal may also be indicated by a bitmap bitmap. For example, when the uplink bandwidth includes 48 subcarriers, a maximum of 4 Set m may be configured. As shown in Figure 10. 4bit bitmap indicated by a frequency domain location of the terminal configuration Set m, e.g. Configuration "0001" indicates that the terminal is configured Set m Configuration "0010" Set m indicates the terminal is configured Configuration "0100" Set m indicates the terminal is configured Configuration "1000" Set m indicates the terminal is configured Configuration "1100" Set m indicates the terminal is configured
具体实施例5 Specific embodiment 5
在通信系统中,终端从序列集合中选择对应的序列,并且至少根据选择的对应的序列生成随机接入信号;终端通过随机接入信道发送随机接入信号至基站。
In the communication system, the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
其中,可以将多个终端划分为2个集合,即第一终端集合和第二终端集合,且第一终端集合和第二终端集合满足以下条件:The multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set meet the following conditions:
所述第一终端集合包括的终端为采用多个子载波传输Msg3消息的终端,所述第二终端集合包括的终端为采用单个子载波传输Msg3消息的终端。The terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers, and the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier.
终端从序列集合中选择对应的序列,包括:The terminal selects a corresponding sequence from the sequence set, including:
属于第一终端集合的终端选择序列Code0;属于第二终端集合的终端选择序列Code1;a terminal selection sequence Code 0 belonging to the first terminal set; a terminal selection sequence Code 1 belonging to the second terminal set;
终端选择序列(j=0或1)之后,可以按照如下步骤生成所述随机接入信号:Terminal selection sequence After (j=0 or 1), the random access signal can be generated as follows:
步骤1:频域上索引为fn(0≤n≤3)的子载波且时域上占用连续的K个符号发送则第k个符号且子载波fn上发送的信号的频域表达式为则上述K个符号且子载波fn上发送的信号的频域表达式为
Step 1: Subcarriers indexed as f n (0 ≤ n ≤ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
步骤2:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度。为索引为fn的子载波占用的频域资源,FOffset为频域偏移量。Step 2: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol. For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset.
当时域采样间隔为Ts时,对应的时域的表达式为
为时域采样点数量;When the domain sampling interval is T s , The corresponding time domain expression is The number of sampling points in the time domain;
则终端在连续的K个符号上发送的时域信号表达式为
Then the terminal sends on consecutive K symbols The time domain signal expression is
步骤3:所述终端除了发送Sn之外,还发送:循环前缀CPn,其中,该循环前缀CPn={Sn[QK-L+1],…,Sn[QK]},L表示CP中包括的时域采样间隔Ts的数量。Step 3: The terminal sends a cyclic prefix CP n in addition to the S n , wherein the cyclic prefix CP n = {S n [QK-L+1], ..., S n [QK]}, L Indicates the number of time domain sampling intervals T s included in the CP.
步骤4:可以定义Groupn为{CPn,Sn},即为终端发送
对应的时域信号的表达形式;且n取值不同的Groupn在时域上占用不同的符号。Step 4: You can define Group n as {CP n , S n }, which is sent by the terminal. The expression of the corresponding time domain signal; and the Group n with different values of n occupy different symbols in the time domain.
步骤5:可以定义Group0~GroupN-1作为所述终端生成所述随机接入信号的基本单元(Unit)。Step 5: Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
步骤6:所述终端发送的随机接入信号由所述Unit在时域上重复H次组成;Step 6: The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
可选地,不同等级的所述终端配置的重复次数H不同。Optionally, the number of repetitions H of the terminal configurations of different levels is different.
可选地,上述终端的等级可以包括以下至少之一:Optionally, the level of the foregoing terminal may include at least one of the following:
覆盖增强等级;Coverage enhancement level;
物理信道重复发送等级;Physical channel repeat transmission level;
物理信道上承载的消息或信令的重复发送等级。Repeated transmission level of messages or signaling carried on the physical channel.
在本实施例中,系统配置的随机接入信道的子载波间隔Δf为3.75KHz,时域符号长度(微秒)。循环前缀CPn长度配置为266.7us,K=5,则Groupn时域长度为1.6ms(毫秒)。由于N=4,则Group0~Group3作为所述终端生成所述随机接入信号的基本单元(Unit)的长度为6.4ms;In this embodiment, the subcarrier spacing Δf of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds). The cyclic prefix CP n length is configured to be 266.7us, K=5, and the Group n time domain length is 1.6ms (milliseconds). The length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
在本实施例中,Group0~Group3对应的频域子载波索引f0~f3分别为subcarrior0,subcarrior1,subcarrior7,subcarrior6,则所述终端生成所述随机接入信号的基本单元(Unit)的时域和频域的二维结构如图11所示,Group0和Group1配置的子载波相邻,Group2和Group3配置的子载波相邻,Group1和Group2配置的子载波间隔6个子载波。进一步,根据Group0的子载波索引可以确定Group1、Group2和Group3的子载波索引。In the present embodiment, Group 0 ~ Group 3 corresponding to frequency domain subcarrier index f 0 ~ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially The two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 11 , the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the group 1 and Group 2 are configured. The subcarriers are separated by 6 subcarriers. Further, the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
在本实施例中,所述终端配置的重复次数H=8,则需要重复8次发送基本单元(Unit)。In this embodiment, if the number of repetitions of the terminal configuration is H=8, the basic unit (Unit) needs to be repeated 8 times.
在本实施例中,随机接入信道资源包含多个时频资源集合Setm,m为所述Setm的索引。如图12所示,所述Setm在频域上包括12个子载波,分别为Subcarrior0~Subcarrior11,Setm的时域长度为26ms,除了包含4个Unit的时域长度之外,还包括0.4ms的保护时间(Guard Time)。In this embodiment, the random access channel resource includes a plurality of time-frequency resource sets Set m , where m is an index of the Set m . 12, the Set m includes 12 subcarriers in the frequency domain, respectively Subcarrior0 ~ Subcarrior11, time domain Set m length is 26ms, the length of the time domain in addition contains Unit 4, further comprising 0.4ms Guard Time.
相邻的两个时频资源集合Setm和Setm+1之间间隔Vms,如图13所示,其中V的取值为以下至少之一:
The interval between the adjacent two time-frequency resource sets Set m and Set m+1 is Vms, as shown in FIG. 13 , where V is at least one of the following:
V=0;V=0;
V=2y,其中,y为大于或等于0的正整数;V=2 y , where y is a positive integer greater than or equal to 0;
在本实施例中y可以取值范围为{1,2,3,4,5,6,7}。In this embodiment, y can take a value range of {1, 2, 3, 4, 5, 6, 7}.
在本实施例中,所述终端在Setm和Setm+1中上重复8次发送Unit。In this embodiment, the terminal repeats the transmission of the Unit 8 times in Set m and Set m+1 .
可选地,相邻的两个时频资源集合Setm和Setm+1之间间隔Vms,其中Vms还可以按照如下方式确定:Optionally, the adjacent two time-frequency resource sets Set m and Set m+1 are separated by Vms, wherein Vms can also be determined as follows:
V的取值为以下至少之一:The value of V is at least one of the following:
V=0;V=0;
V=B×2y,其中,y为大于或等于0的正整数;B为Setm的时域长度。V=B×2 y , where y is a positive integer greater than or equal to 0; B is the time domain length of Set m .
在本实施例中y的取值范围可以为{1,2,3,4,5,6,7}。In this embodiment, the value of y may be {1, 2, 3, 4, 5, 6, 7}.
具体实施例6 Specific embodiment 6
在通信系统中,终端从序列集合中选择对应的序列,并且至少根据选择的对应的序列生成随机接入信号;终端通过随机接入信道发送随机接入信号至基站。In the communication system, the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
其中,可以将多个终端划分为2个集合,即第一终端集合和第二终端集合,且第一终端集合和第二终端集合满足以下条件:The multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set meet the following conditions:
所述第一终端集合包括的终端为采用多个子载波传输Msg3消息的终端,所述第二终端集合包括的终端为采用单个子载波传输Msg3消息的终端。The terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers, and the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier.
终端从序列集合中选择对应的序列,包括:The terminal selects a corresponding sequence from the sequence set, including:
属于第一终端集合的终端选择序列Code0;属于第二终端集合的终端选择序列Code1;a terminal selection sequence Code 0 belonging to the first terminal set; a terminal selection sequence Code 1 belonging to the second terminal set;
终端选择序列(j=0或1)之后,可以按照如下步骤生成所述随机接入信号:Terminal selection sequence After (j=0 or 1), the random access signal can be generated as follows:
步骤1:频域上索引为fn(0≤n≤3)的子载波且时域上占用连续的K个符号发送
则第k个符号且子载波fn上发送的信号的频域表达式为则上述K个符号且子载波fn上发送的信号的频域表达式为
Step 1: Subcarriers indexed as f n (0 ≤ n ≤ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
步骤2:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度。为索引为fn的子载波占用的频域资源,FOffset为频域偏移量。Step 2: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol. For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset.
当时域采样间隔为Ts时,对应的时域的表达式为0≤k≤K-1,0≤q≤Q-1,为时域采样点数量;When the domain sampling interval is T s , The corresponding time domain expression is 0 ≤ k ≤ K-1, 0 ≤ q ≤ Q-1, The number of sampling points in the time domain;
则终端在连续的K个符号上发送的时域信号表达式为
Then the terminal sends on consecutive K symbols The time domain signal expression is
步骤3:所述终端除了发送Sn之外,还发送:循环前缀CPn,其中,该循环前缀CPn={Sn[QK-L+1],…,Sn[QK]},L表示CP中包括的时域采样间隔Ts的数量。Step 3: The terminal sends a cyclic prefix CP n in addition to the S n , wherein the cyclic prefix CP n = {S n [QK-L+1], ..., S n [QK]}, L Indicates the number of time domain sampling intervals T s included in the CP.
步骤4:定义Groupn为{CPn,Sn}即为终端发送(0≤j≤J-1,0≤n≤N-1)对应的时域信号的表达形式;且n取值不同的Groupn在时域上占用不同的符号。Step 4: Define that Group n is {CP n , S n } is sent by the terminal. (0 ≤ j ≤ J-1, 0 ≤ n ≤ N-1) the expression form of the corresponding time domain signal; and Group n with different values of n occupy different symbols in the time domain.
步骤5:可以定义Group0~GroupN-1作为所述终端生成所述随机接入信号的基本单元(Unit);Step 5: Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal;
步骤6:所述终端发送的随机接入信号由所述Unit在时域上重复H次组成;Step 6: The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
可选地,不同等级的所述终端配置的重复次数H不同。Optionally, the number of repetitions H of the terminal configurations of different levels is different.
可选地,上述终端的等级可以包括以下至少之一:Optionally, the level of the foregoing terminal may include at least one of the following:
覆盖增强等级;Coverage enhancement level;
物理信道重复发送等级;Physical channel repeat transmission level;
物理信道上承载的消息或信令的重复发送等级。Repeated transmission level of messages or signaling carried on the physical channel.
在本实施例中,系统配置的随机接入信道的子载波间隔Δf为3.75KHz,时域符号长度
(微秒)。循环前缀CPn长度配置为266.7us,K=5,则Groupn时域长度为1.6ms(毫秒)。由于N=4,则Group0~Group3作为所述终端生成所述随机接入信号的基本单元(Unit)的长度为6.4ms;In this embodiment, the subcarrier spacing Δf of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds). The cyclic prefix CP n length is configured to be 266.7us, K=5, and the Group n time domain length is 1.6ms (milliseconds). The length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
在本实施例中,Group0~Group3对应的频域子载波索引f0~f3分别为subcarrior0,subcarrior1,subcarrior7,subcarrior6,则所述终端生成所述随机接入信号的基本单元(Unit)的时域和频域的二维结构如图14所示,Group0和Group1配置的子载波相邻,Group2和Group3配置的子载波相邻,Group1和Group2配置的子载波间隔6个子载波。进一步,根据Group0的子载波索引可以确定Group1、Group2和Group3的子载波索引。In the present embodiment, Group 0 ~ Group 3 corresponding to frequency domain subcarrier index f 0 ~ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially The two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 14 , the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the group 1 and Group 2 are configured. The subcarriers are separated by 6 subcarriers. Further, the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
在本实施例中,所述终端配置的重复次数H=8,则需要重复8次发送基本单元(Unit)。In this embodiment, if the number of repetitions of the terminal configuration is H=8, the basic unit (Unit) needs to be repeated 8 times.
在本实施例中,随机接入信道资源包含多个时频资源集合Setm,m为所述Setm的索引。如图15所示,所述Setm在频域上包括12个子载波,分别为Subcarrior0~Subcarrior11,Setm的时域长度为26ms,除了包含4个Unit的时域长度之外,还包括0.4ms的保护时间(Guard Time)。In this embodiment, the random access channel resource includes a plurality of time-frequency resource sets Set m , where m is an index of the Set m . Shown in Figure 15, the Set m includes 12 subcarriers in the frequency domain, respectively Subcarrior0 ~ Subcarrior11, time domain Set m length is 26ms, the length of the time domain in addition contains Unit 4, further comprising 0.4ms Guard Time.
时频资源集合Setm的配置周期为Vms,如图16所示,其中V的取值为:The configuration period of the time-frequency resource set Set m is Vms, as shown in Figure 16, where the value of V is:
V=2y,其中,y为正整数;V=2 y , where y is a positive integer;
在本实施例中,y的取值范围可以为{5,6,7,8,9,10,11,12}。In this embodiment, the value of y may be {5, 6, 7, 8, 9, 10, 11, 12}.
在本实施例中,所述终端在Setm和Setm+1中上重复8次发送Unit。In this embodiment, the terminal repeats the transmission of the Unit 8 times in Set m and Set m+1 .
可选地,时频资源集合Setm的配置周期为Vms,其中Vms还可以按照如下方式确定:Optionally, the configuration period of the time-frequency resource set Set m is Vms, where Vms can also be determined as follows:
V的取值为:The value of V is:
V=B×2y,其中,y为大于或等于0的整数;B为Setm的时域长度。V=B×2 y , where y is an integer greater than or equal to 0; B is the time domain length of Set m .
在本实施例中y的取值范围可以为{0,1,2,3,4,5,6,7}。In this embodiment, the value of y may be {0, 1, 2, 3, 4, 5, 6, 7}.
所述终端在Setm和Setm+1中上重复8次发送Unit。The terminal repeats the transmission of the Unit 8 times in Set m and Set m+1 .
具体实施例7
Specific embodiment 7
在通信系统中,终端从序列集合中选择对应的序列,并且至少根据选择的对应的序列生成随机接入信号;终端通过随机接入信道发送随机接入信号至基站。In the communication system, the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
其中,可以将多个终端划分为2个集合,即第一终端集合和第二终端集合,且第一终端集合和第二终端集合满足以下条件:The multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set meet the following conditions:
所述第一终端集合包括的终端为采用多个子载波传输Msg3消息的终端,所述第二终端集合包括的终端为采用单个子载波传输Msg3消息的终端。The terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers, and the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier.
终端从序列集合中选择对应的序列,包括:The terminal selects a corresponding sequence from the sequence set, including:
属于第一终端集合的终端选择序列Code0;属于第二终端集合的终端选择序列Code1;a terminal selection sequence Code 0 belonging to the first terminal set; a terminal selection sequence Code 1 belonging to the second terminal set;
终端选择序列(j=0或1)之后,可以按照如下步骤生成所述随机接入信号:Terminal selection sequence After (j=0 or 1), the random access signal can be generated as follows:
步骤1:频域上索引为fn(0≤n≤3)的子载波且时域上占用连续的K个符号发送则第k个符号且子载波fn上发送的信号的频域表达式为则上述K个符号且子载波fn上发送的信号的频域表达式为
Step 1: Subcarriers indexed as f n (0 ≤ n ≤ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
步骤2:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度。为索引为fn的子载波占用的频域资源,FOffset为频域偏移量。Step 2: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol. For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset.
当时域采样间隔为Ts时,对应的时域的表达式为0≤k≤K-1,0≤q≤Q-1,为时域采样点数量;When the domain sampling interval is T s , The corresponding time domain expression is 0 ≤ k ≤ K-1, 0 ≤ q ≤ Q-1, The number of sampling points in the time domain;
则终端在连续的K个符号上发送的时域信号表达式为
Then the terminal sends on consecutive K symbols The time domain signal expression is
步骤3:所述终端除了发送Sn之外,还发送:循环前缀CPn,其中,该循环前缀CPn={Sn[QK-L+1],…,Sn[QK]},L表示CP中包括的时域采样间隔Ts的数量。
Step 3: The terminal sends a cyclic prefix CP n in addition to the S n , wherein the cyclic prefix CP n = {S n [QK-L+1], ..., S n [QK]}, L Indicates the number of time domain sampling intervals T s included in the CP.
步骤4:可以定义Groupn为{CPn,Sn}即为终端发送(0≤j≤J-1,0≤n≤N-1)对应的时域信号的表达形式;且n取值不同的Groupn在时域上占用不同的符号。Step 4: You can define that Group n is {CP n , S n } (0 ≤ j ≤ J-1, 0 ≤ n ≤ N-1) the expression form of the corresponding time domain signal; and Group n with different values of n occupy different symbols in the time domain.
步骤5:可以定义Group0~GroupN-1作为所述终端生成所述随机接入信号的基本单元(Unit)。Step 5: Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
步骤6:所述终端发送的随机接入信号由所述Unit在时域上重复H次组成;Step 6: The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
可选地,不同等级的终端配置的重复次数H不同。Optionally, the number of repetitions H of different levels of terminal configurations is different.
可选地,上述终端等级可以包括以下至少之一:Optionally, the foregoing terminal level may include at least one of the following:
覆盖增强等级;Coverage enhancement level;
物理信道重复发送等级;Physical channel repeat transmission level;
物理信道上承载的消息或信令的重复发送等级。Repeated transmission level of messages or signaling carried on the physical channel.
在本实施例中,系统配置的随机接入信道的子载波间隔Δf为3.75KHz,时域符号长度(微秒)。循环前缀CPn长度配置为266.7us,K=5,则Groupn时域长度为1.6ms(毫秒)。由于N=4,则Group0~Group3作为所述终端生成所述随机接入信号的基本单元(Unit)的长度为6.4ms;In this embodiment, the subcarrier spacing Δf of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds). The cyclic prefix CP n length is configured to be 266.7us, K=5, and the Group n time domain length is 1.6ms (milliseconds). The length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
在本实施例中,Group0~Group3对应的频域子载波索引f0~f3分别为subcarrior0,subcarrior1,subcarrior7,subcarrior6,则所述终端生成所述随机接入信号的基本单元(Unit)的时域和频域的二维结构如图17所示,Group0和Group1配置的子载波相邻,Group2和Group3配置的子载波相邻,Group1和Group2配置的子载波间隔6个子载波。进一步,根据Group0的子载波索引可以确定Group1、Group2和Group3的子载波索引。In the present embodiment, Group 0 ~ Group 3 corresponding to frequency domain subcarrier index f 0 ~ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially The two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 17, the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the Group 1 and Group 2 are configured. The subcarriers are separated by 6 subcarriers. Further, the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
在本实施例中,随机接入信道资源包含多个时频资源集合Setm,m为所述Setm的索引。如图18所示,所述Setm在频域上包括12个子载波,分别为Subcarrior0~Subcarrior11,Setm的时域长度为26ms,除了包含4个Unit的时域长度之外,还包括0.4ms的保护时间(Guard Time)。In this embodiment, the random access channel resource includes a plurality of time-frequency resource sets Set m , where m is an index of the Set m . 18, the Set m includes 12 subcarriers in the frequency domain, respectively Subcarrior0 ~ Subcarrior11, time domain Set m length is 26ms, the length of the time domain in addition contains Unit 4, further comprising 0.4ms Guard Time.
时频资源集合Setm的配置周期为Vms,V=B×2y,其中,y为大于或等于0的正整数;B为Setm的时域长度。
The configuration period of the time-frequency resource set Set m is Vms, V=B×2 y , where y is a positive integer greater than or equal to 0; B is the time domain length of Set m .
在本实施例中y的取值范围可以为{0,1,2,3,4,5,6,7}。In this embodiment, the value of y may be {0, 1, 2, 3, 4, 5, 6, 7}.
在本实施例中y=2,即Vms内最多可以配置4个Setm,如图19所示,由于每个Setm包括4个subset,则Vms内最多可以配置16个subset,定义subset的索引为subset 0至subset 15。本实施例中,终端一共划分为3个等级,等级1,等级2和等级3,分别对应Unit在时域上重复发送次数为2次,4次和8次。则将subset 0至subset 1分配给等级1的终端,将subset 2至subset 5分配给等级2的终端,将subset 6至subset 13分配给等级3的终端。不同的时频资源集合Setm的配置周期之间采用相同的subset分配方式。In this embodiment, y=2, that is, up to 4 Set m can be configured in Vms. As shown in FIG. 19, since each Set m includes 4 subsets, up to 16 subsets can be configured in Vms, and the index of the subset is defined. For subset 0 to subset 15. In this embodiment, the terminal is divided into three levels, level 1, level 2, and level 3. The number of repeated transmissions of the unit in the time domain is 2, 4, and 8 times, respectively. Then, subset 0 to subset 1 are assigned to the terminal of level 1, subset 2 to subset 5 are assigned to the terminal of level 2, and subset 6 to subset 13 are assigned to the terminal of level 3. The same subset allocation method is adopted between the configuration periods of different time-frequency resource sets Set m .
具体实施例8 Specific embodiment 8
在通信系统中,终端从序列集合中选择对应的序列,并且至少根据选择的对应的序列生成随机接入信号;终端通过随机接入信道发送随机接入信号至基站。In the communication system, the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
其中,可以将多个终端划分为2个集合,即第一终端集合和第二终端集合,且第一终端集合和第二终端集合满足以下条件:The multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set meet the following conditions:
所述第一终端集合包括的终端为采用多个子载波传输Msg3消息的终端,所述第二终端集合包括的终端为采用单个子载波传输Msg3消息的终端。The terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers, and the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier.
终端从序列集合中选择对应的序列,包括:The terminal selects a corresponding sequence from the sequence set, including:
属于第一终端集合的终端选择序列Code0;属于第二终端集合的终端选择序列Code1;a terminal selection sequence Code 0 belonging to the first terminal set; a terminal selection sequence Code 1 belonging to the second terminal set;
终端选择序列(j=0或1)之后,可以按照如下步骤生成所述随机接入信号:Terminal selection sequence After (j=0 or 1), the random access signal can be generated as follows:
步骤1:频域上索引为fn(0≤n≤3)的子载波且时域上占用连续的K个符号发送则第k个符号且子载波fn上发送的信号的频域表达式为则上述K个符号且子载波fn上发送的信号的频域表达式为
Step 1: Subcarriers indexed as f n (0 ≤ n ≤ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
步骤2:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度。为索引为fn的子载波占用的频域资源,FOffset
为频域偏移量。Step 2: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol. For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset.
当时域采样间隔为Ts时,对应的时域的表达式为0≤k≤K-1,0≤q≤Q-1,为时域采样点数量;When the domain sampling interval is T s , The corresponding time domain expression is 0 ≤ k ≤ K-1, 0 ≤ q ≤ Q-1, The number of sampling points in the time domain;
则终端在连续的K个符号上发送的时域信号表达式为
Then the terminal sends on consecutive K symbols The time domain signal expression is
步骤3:所述终端除了发送Sn之外,还发送:循环前缀CPn,其中,该循环前缀CPn={Sn[QK-L+1],…,Sn[QK]},L表示CP中包括的时域采样间隔Ts的数量。Step 3: The terminal sends a cyclic prefix CP n in addition to the S n , wherein the cyclic prefix CP n = {S n [QK-L+1], ..., S n [QK]}, L Indicates the number of time domain sampling intervals T s included in the CP.
步骤4:可以定义Groupn为{CPn,Sn}即为终端发送(0≤j≤J-1,0≤n≤N-1)对应的时域信号的表达形式;且n取值不同的Groupn在时域上占用不同的符号。Step 4: You can define that Group n is {CP n , S n } (0 ≤ j ≤ J-1, 0 ≤ n ≤ N-1) the expression form of the corresponding time domain signal; and Group n with different values of n occupy different symbols in the time domain.
步骤5:可以定义Group0~GroupN-1作为所述终端生成所述随机接入信号的基本单元(Unit)。Step 5: Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
步骤6:所述终端发送的随机接入信号由所述Unit在时域上重复H次组成;Step 6: The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
可选地,不同等级的所述终端配置的重复次数H不同。Optionally, the number of repetitions H of the terminal configurations of different levels is different.
可选地,上述终端的等级可以包括以下至少之一:Optionally, the level of the foregoing terminal may include at least one of the following:
覆盖增强等级;Coverage enhancement level;
物理信道重复发送等级;Physical channel repeat transmission level;
物理信道上承载的消息或信令的重复发送等级。Repeated transmission level of messages or signaling carried on the physical channel.
在本实施例中,系统配置的随机接入信道的子载波间隔Δf为3.75KHz,时域符号长度(微秒)。循环前缀CPn长度配置为266.7us,K=5,则Groupn时域长度为1.6ms(毫秒)。由于N=4,则Group0~Group3作为所述终端生成所述随机接入信号的基本单元(Unit)的长度为6.4ms;In this embodiment, the subcarrier spacing Δf of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds). The cyclic prefix CP n length is configured to be 266.7us, K=5, and the Group n time domain length is 1.6ms (milliseconds). The length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
在本实施例中,Group0~Group3对应的频域子载波索引f0~f3分别为subcarrior0,subcarrior1,subcarrior7,subcarrior6,则所述终端生成所述随机接入信号的基
本单元(Unit)的时域和频域的二维结构如图20所示,Group0和Group1配置的子载波相邻,Group2和Group3配置的子载波相邻,Group1和Group2配置的子载波间隔6个子载波。进一步,根据Group0的子载波索引可以确定Group1、Group2和Group3的子载波索引。In the present embodiment, Group 0 ~ Group 3 corresponding to frequency domain subcarrier index f 0 ~ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially The two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 20, the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the Group 1 and Group 2 are configured. The subcarriers are separated by 6 subcarriers. Further, the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
在本实施例中,随机接入信道资源包含多个时频资源集合Setm,m为所述Setm的索引。如图21所示,所述Setm在频域上包括12个子载波,分别为Subcarrior0~Subcarrior11,Setm的时域长度为26ms,除了包含4个Unit的时域长度之外,还包括0.4ms的保护时间(Guard Time)。In this embodiment, the random access channel resource includes a plurality of time-frequency resource sets Set m , where m is an index of the Set m . 21, the Set m includes 12 subcarriers in the frequency domain, respectively Subcarrior0 ~ Subcarrior11, time domain Set m length is 26ms, the length of the time domain in addition contains Unit 4, further comprising 0.4ms Guard Time.
时频资源集合Setm的配置周期为Vms,V=B×D,其中,D为大于等于1的正整数;B为Setm的时域长度。The configuration period of the time-frequency resource set Set m is Vms, V=B×D, where D is a positive integer greater than or equal to 1; B is a time domain length of Set m .
D优选为2x,其中,x为大于或等于0的整数;D is preferably 2 x , wherein x is an integer greater than or equal to 0;
即Vms内最多可以配置D个Setm,由于每个Setm包括4个subset,则Vms内最多可以配置4*D个subset,定义subset的索引为subset 0至subset(4*D-1)。在本实施例中,终端一共可以被划分为G个等级,分别为等级0~等级(G-1),其中,等级g(0≤g≤G-1)(对应于上述的等级索引为g)的终端发送随机接入信号需要Unit在时域上重复发送次数为Repetitiong。因此,在一个所述配置周期内,为等级g的终端配置连续的Repetitiong个subset,且起始subset索引StartingSubsetIndexg按照下面公式计算:That is, up to D Set m can be configured in Vms. Since each Set m includes 4 subsets, up to 4*D subsets can be configured in Vms, and the index of the defined subset is subset 0 to subset (4*D-1). In this embodiment, the terminal may be divided into G levels, which are respectively level 0 to level (G-1), wherein the level g (0 ≤ g ≤ G-1) (corresponding to the above-mentioned level index is g The terminal sends a random access signal, and the number of times that the Unit repeats the transmission in the time domain is Repetition g . Therefore, in one of the configuration periods, consecutive Repetition g subsets are configured for the level g terminals, and the starting subset index StartingSubsetIndex g is calculated according to the following formula:
其中,不同的配置周期之间可以采用相同的subset分配方式。The same subset allocation method can be adopted between different configuration periods.
具体实施例9 Specific embodiment 9
在通信系统中,终端从序列集合中选择对应的序列,并且至少根据选择的对应的序列生成随机接入信号;终端通过随机接入信道发送随机接入信号至基站。In the communication system, the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
其中,可以将多个终端划分为2个集合,即第一终端集合和第二终端集合,且第一终端集合和第二终端集合满足以下条件:The multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set meet the following conditions:
所述第一终端集合包括的终端为支持单个子载波传输且子载波间隔为3.75kHz的终端,所述第二终端集合包括的终端为支持单个子载波传输且子载波间隔为15kHz的终端。
The first terminal set includes terminals that support single subcarrier transmission and have a subcarrier spacing of 3.75 kHz, and the second terminal set includes terminals that support single subcarrier transmission and subcarrier spacing of 15 kHz.
终端从序列集合中选择对应的序列,包括:The terminal selects a corresponding sequence from the sequence set, including:
属于第一终端集合的终端选择序列Code0;属于第二终端集合的终端选择序列Code1;a terminal selection sequence Code 0 belonging to the first terminal set; a terminal selection sequence Code 1 belonging to the second terminal set;
终端选择序列(j=0或1)之后,可以按照如下步骤生成所述随机接入信号:Terminal selection sequence After (j=0 or 1), the random access signal can be generated as follows:
步骤1:频域上索引为fn(0≤n≤3)的子载波且时域上占用连续的K个符号发送则第k个符号且子载波fn上发送的信号的频域表达式为则上述K个符号且子载波fn上发送的信号的频域表达式为
Step 1: Subcarriers indexed as f n (0 ≤ n ≤ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
步骤2:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度。为索引为fn的子载波占用的频域资源,FOffset为频域偏移量。Step 2: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol. For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset.
当时域采样间隔为Ts时,对应的时域的表达式为0≤k≤K-1,0≤q≤Q-1,为时域采样点数量;When the domain sampling interval is T s , The corresponding time domain expression is 0 ≤ k ≤ K-1, 0 ≤ q ≤ Q-1, The number of sampling points in the time domain;
则终端在连续的K个符号上发送的时域信号表达式为
Then the terminal sends on consecutive K symbols The time domain signal expression is
步骤3:所述终端除了发送Sn之外,还发送:循环前缀CPn,其中,该循环前缀CPn={Sn[QK-L+1],…,Sn[QK]},L表示CP中包括的时域采样间隔Ts的数量。Step 3: The terminal sends a cyclic prefix CP n in addition to the S n , wherein the cyclic prefix CP n = {S n [QK-L+1], ..., S n [QK]}, L Indicates the number of time domain sampling intervals T s included in the CP.
步骤4:可以定义Groupn为{CPn,Sn}即为终端发送(0≤j≤J-1,0≤n≤N-1)对应的时域信号的表达形式;且n取值不同的Groupn在时域上占用不同的符号。Step 4: You can define that Group n is {CP n , S n } (0 ≤ j ≤ J-1, 0 ≤ n ≤ N-1) the expression form of the corresponding time domain signal; and Group n with different values of n occupy different symbols in the time domain.
步骤5:可以定义Group0~GroupN-1作为所述终端生成所述随机接入信号的基本单元(Unit)。
Step 5: Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
步骤6:所述终端发送的随机接入信号由所述Unit在时域上重复H次组成;Step 6: The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
可选地,不同等级的终端配置的重复次数H不同。Optionally, the number of repetitions H of different levels of terminal configurations is different.
可选地,上述终端的等级包括以下至少之一:Optionally, the level of the foregoing terminal includes at least one of the following:
覆盖增强等级;Coverage enhancement level;
物理信道重复发送等级;Physical channel repeat transmission level;
物理信道上承载的消息或信令的重复发送等级。Repeated transmission level of messages or signaling carried on the physical channel.
在本实施例中,系统配置的随机接入信道的子载波间隔Δf为3.75KHz,时域符号长度(微秒)。循环前缀CPn长度配置为266.7us,K=5,则Groupn时域长度为1.6ms(毫秒)。由于N=4,则Group0~Group3作为所述终端生成所述随机接入信号的基本单元(Unit)的长度为6.4ms;In this embodiment, the subcarrier spacing Δf of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is (microseconds). The cyclic prefix CP n length is configured to be 266.7us, K=5, and the Group n time domain length is 1.6ms (milliseconds). The length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
在本实施例中,Group0~Group3对应的频域子载波索引f0~f3分别为subcarrior0,subcarrior1,subcarrior7,subcarrior6,则所述终端生成所述随机接入信号的基本单元(Unit)的时域和频域的二维结构如图22所示,Group0和Group1配置的子载波相邻,Group2和Group3配置的子载波相邻,Group1和Group2配置的子载波间隔6个子载波。进一步,根据Group0的子载波索引可以确定Group1、Group2和Group3的子载波索引。In the present embodiment, Group 0 ~ Group 3 corresponding to frequency domain subcarrier index f 0 ~ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially The two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 22, the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the Group 1 and Group 2 are configured. The subcarriers are separated by 6 subcarriers. Further, the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
在本实施例中,随机接入信道资源包含多个时频资源集合Setm,m为所述Setm的索引。如图23所示,所述Setm在频域上包括12个子载波,分别为Subcarrior0~Subcarrior11,Setm时域长度为1个Unit的时域长度。所述Setm包括1个subset,其中,subset在频域上与Setm配置相同的子载波,subset在时域上长度为1个Unit的长度;In this embodiment, the random access channel resource includes a plurality of time-frequency resource sets Set m , where m is an index of the Set m . As shown in FIG. 23, the Set m includes 12 subcarriers in the frequency domain, which are Subcarrior0~Subcarrior11, and the Set m time domain length is a time domain length of 1 Unit. The Set m includes a subset, wherein the subset is configured with the same subcarrier in the frequency domain as the Set m , and the subset has a length of 1 Unit in the time domain;
时频资源集合Setm的配置周期为Vms,V=B×D,其中,D为大于或等于1的整数;B为Setm的时域长度。The configuration period of the time-frequency resource set Set m is Vms, V=B×D, where D is an integer greater than or equal to 1; B is the time domain length of Set m .
在本实施例中,D=2y,其中,y为大于或等于0的整数;In this embodiment, D=2 y , where y is an integer greater than or equal to 0;
在本实施例中,y=4,即Vms内最多可以配置16个Setm,由于每个Setm包括1个subset,则Vms内最多可以配置16个subset,定义subset的索引为subset 0至subset 15。本实施例中,所述终端一共划分为3个等级,分别为等级0、等级1、等级2。等级g(0≤g≤2)的终端
发送随机接入信号需要Unit在时域上重复发送次数为Repetitiong,本实施例中,Repetition0=2,Repetition1=4,Repetition2=8。In this embodiment, y=4, that is, up to 16 Set m can be configured in Vms. Since each Set m includes 1 subset, up to 16 subsets can be configured in Vms, and the index of the defined subset is subset 0 to subset. 15. In this embodiment, the terminal is divided into three levels, which are level 0, level 1, and level 2. The terminal of level g (0 ≤ g ≤ 2) needs to repeat the number of times that the Unit repeats the transmission in the time domain is Repetition g . In this embodiment, Repetition 0 = 2, Repetition 1 = 4, and Repetition 2 = 8.
在一个所述配置周期内,为等级g的终端配置连续的Repetitiong个subset,且起始subset索引StartingSubsetIndexg可以按照下面公式计算:During one of the configuration periods, consecutive Repetition g subsets are configured for the level g terminals, and the starting subset index StartingSubsetIndex g can be calculated according to the following formula:
即StartingSubsetIndex0=0,StartingSubsetIndex1=2,StartingSubsetIndex2=6。That is, StartingSubsetIndex 0 =0, StartingSubsetIndex 1 = 2, StartingSubsetIndex 2 = 6.
则为等级索引为g的终端配置连续的Repetitiong个subset的分配示意图如图24所示。Level index was assigned to the terminal disposed contiguous g Repetition g of a subset of the diagram shown in Figure 24.
不同的所述Setm的配置周期之间,等级索引为g的终端对应的subset配置方案可以是相同的。Between different configuration periods of the Set m , the subset configuration scheme corresponding to the terminal with the level index g may be the same.
具体实施例10 Specific embodiment 10
在通信系统中,终端从序列集合中选择对应的序列,并且至少根据选择的对应的序列生成随机接入信号;终端通过随机接入信道发送随机接入信号至基站。In the communication system, the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
其中,可以将多个终端划分为2个集合,即第一终端集合和第二终端集合,且第一终端集合和第二终端集合满足以下条件:The multiple terminals may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set meet the following conditions:
所述第一终端集合包括的终端为采用多个子载波传输Msg3消息的终端,所述第二终端集合包括的终端为采用单个子载波传输Msg3消息的终端。The terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers, and the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier.
终端从序列集合中选择对应的序列,包括:The terminal selects a corresponding sequence from the sequence set, including:
属于第一终端集合的终端选择序列Code0;属于第二终端集合的终端选择序列Code1;a terminal selection sequence Code 0 belonging to the first terminal set; a terminal selection sequence Code 1 belonging to the second terminal set;
终端选择序列(j=0或1)之后,可以按照如下步骤生成所述随机接入信号:Terminal selection sequence After (j=0 or 1), the random access signal can be generated as follows:
步骤1:频域上索引为fn(0≤n≤3)的子载波且时域上占用连续的K个符号发送
则第k个符号且子载波fn上发送的信号的频域表达式为则上述K个符号且子载波fn上发送的信号的频域表达式为
Step 1: Subcarriers indexed as f n (0 ≤ n ≤ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
步骤2:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度。为索引为fn的子载波占用的频域资源,FOffset为频域偏移量。Step 2: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol. For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset.
当时域采样间隔为Ts时,对应的时域的表达式为
为时域采样点数量;When the domain sampling interval is T s , The corresponding time domain expression is The number of sampling points in the time domain;
则终端在连续的K个符号上发送的时域信号表达式为
Then the terminal sends on consecutive K symbols The time domain signal expression is
步骤3:所述终端除了发送Sn之外,还发送:循环前缀CPn,其中,该循环前缀CPn={Sn[QK-L+1],…,Sn[QK]},L表示CP中包括的时域采样间隔Ts的数量。Step 3: The terminal sends a cyclic prefix CP n in addition to the S n , wherein the cyclic prefix CP n = {S n [QK-L+1], ..., S n [QK]}, L Indicates the number of time domain sampling intervals T s included in the CP.
步骤4:可以定义Groupn为{CPn,Sn}即为终端发送对应的时域信号的表达形式;且n取值不同的Groupn在时域上占用不同的符号。Step 4: You can define that Group n is {CP n , S n } The expression of the corresponding time domain signal; and the Group n with different values of n occupy different symbols in the time domain.
步骤5:可以定义Group0~GroupN-1作为所述终端生成所述随机接入信号的基本单元(Unit)。Step 5: Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
步骤6:所述终端发送的随机接入信号由所述Unit在时域上重复H次组成;Step 6: The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
可选地,不同等级的所述终端配置的重复次数H不同。Optionally, the number of repetitions H of the terminal configurations of different levels is different.
可选地,上述终端的等级可以包括以下至少之一:Optionally, the level of the foregoing terminal may include at least one of the following:
覆盖增强等级;Coverage enhancement level;
物理信道重复发送等级;Physical channel repeat transmission level;
物理信道上承载的消息或信令的重复发送等级。Repeated transmission level of messages or signaling carried on the physical channel.
在本实施例中,系统配置的随机接入信道的子载波间隔Δf为3.75KHz,时域符号长度
循环前缀CPn长度配置为266.7us,K=5,则Groupn时域长度为1.6ms(毫秒)。由于N=4,则Group0~Group3作为所述终端生成所述随机接入信号的基本单元(Unit)的长度为6.4ms;In this embodiment, the subcarrier spacing Δf of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is The cyclic prefix CP n length is configured to be 266.7us, K=5, and the Group n time domain length is 1.6ms (milliseconds). The length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
在本实施例中,Group0~Group3对应的频域子载波索引f0~f3分别为subcarrior0,subcarrior1,subcarrior7,subcarrior6,则所述终端生成所述随机接入信号的基本单元(Unit)的时域和频域的二维结构如图25所示,Group0和Group1配置的子载波相邻,Group2和Group3配置的子载波相邻,Group1和Group2配置的子载波间隔6个子载波。进一步,根据Group0的子载波索引可以确定Group1、Group2和Group3的子载波索引。In the present embodiment, Group 0 ~ Group 3 corresponding to frequency domain subcarrier index f 0 ~ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially The two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 25, the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the Group 1 and Group 2 are configured. The subcarriers are separated by 6 subcarriers. Further, the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
在本实施例中,随机接入信道资源包含多个时频资源集合Setm,m为所述Setm的索引。如图26所示,所述Setm在频域上包括12个子载波,分别为Subcarrior0~Subcarrior11,Setm时域长度为1个Unit的时域长度。所述Setm包括1个subset,其中,subset在频域上与Setm配置相同的子载波,subset在时域上长度为1个Unit的长度;In this embodiment, the random access channel resource includes a plurality of time-frequency resource sets Set m , where m is an index of the Set m . As shown in FIG. 26, the Set m includes 12 subcarriers in the frequency domain, which are Subcarrior0~Subcarrior11, and the Set m time domain length is a time domain length of 1 Unit. The Set m includes a subset, wherein the subset is configured with the same subcarrier in the frequency domain as the Set m , and the subset has a length of 1 Unit in the time domain;
时频资源集合Setm的配置周期为Vms,在本实施例中,V=2y,其中,y为大于或等于0的整数;The configuration period of the time-frequency resource set Set m is Vms. In this embodiment, V=2 y , where y is an integer greater than or equal to 0;
在本实施例中y=6,则V=64ms;则Vms内最多可以配置10个Setm,由于每个Setm包括1个subset,则Vms内最多可以配置10个subset,定义subset的索引为subset 0至subset 9。本实施例中,所述终端一共划分为3个等级,分别为等级0、等级1、等级2。等级g(0≤g≤2)的终端发送随机接入信号需要Unit在时域上重复发送次数为Repetitiong,本实施例中,Repetition0=1,Repetition1=2,Repetition2=4。In this embodiment, y=6, then V=64ms; then up to 10 Set m can be configured in Vms. Since each Set m includes 1 subset, up to 10 subsets can be configured in Vms, and the index of the defined subset is Subset 0 to subset 9. In this embodiment, the terminal is divided into three levels, which are level 0, level 1, and level 2. The terminal g of the level g (0 ≤ g ≤ 2) needs to repeat the number of times that the unit repeats the transmission in the time domain is Repetition g . In this embodiment, Repetition 0 =1, Repetition 1 = 2, and Repetition 2 = 4.
在一个所述配置周期内,为等级g的终端配置连续的Repetitiong个subset,且起始subset索引StartingSubsetIndexg按照下面公式计算:During one of the configuration periods, consecutive Repetition g subsets are configured for the level g terminals, and the starting subset index StartingSubsetIndex g is calculated according to the following formula:
即StartingSubsetIndex0=0,StartingSubsetIndex1=1,StartingSubsetIndex2=3,则
为等级索引为g的终端配置连续的Repetitiong个subset的分配示意图如图27所示。That is, startingSubsetIndex 0 =0, StartingSubsetIndex 1 =1, StartingSubsetIndex 2 = 3, the allocation of consecutive Repetition g subsets for the terminal with the level index g is as shown in FIG. 27 .
不同的所述Setm的配置周期之间,等级索引为g的终端对应的subset配置方案可以是相同的。Between different configuration periods of the Set m , the subset configuration scheme corresponding to the terminal with the level index g may be the same.
具体实施例11 Specific embodiment 11
在通信系统中,终端从序列集合中选择对应的序列,并且至少根据选择的对应的序列生成随机接入信号;终端通过随机接入信道发送随机接入信号至基站。In the communication system, the terminal selects a corresponding sequence from the sequence set, and generates a random access signal according to at least the selected corresponding sequence; the terminal transmits the random access signal to the base station through the random access channel.
其中,所述序列集合包括1条长度为N=4的序列,即其中j=0;Wherein the sequence set comprises a sequence of length N=4, ie Where j=0;
终端从序列集合中选择对应的序列,包括:The terminal selects a corresponding sequence from the sequence set, including:
终端选择序列之后,可以按照如下步骤生成所述随机接入信号:Terminal selection sequence After that, the random access signal can be generated as follows:
步骤1:频域上索引为fn(0≤n≤3)的子载波且时域上占用连续的K个符号发送则第k个符号且子载波fn上发送的信号的频域表达式为则上述K个符号且子载波fn上发送的信号的频域表达式为
Step 1: Subcarriers indexed as f n (0 ≤ n ≤ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
步骤2:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度。为索引为fn的子载波占用的频域资源,FOffset为频域偏移量。Step 2: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol. For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset.
当时域采样间隔为Ts时,对应的时域的表达式为
为时域采样点数量;When the domain sampling interval is T s , The corresponding time domain expression is The number of sampling points in the time domain;
则终端在连续的K个符号上发送的时域信号表达式为
Then the terminal sends on consecutive K symbols The time domain signal expression is
步骤3:所述终端除了发送Sn之外,还发送:循环前缀CPn,其中,该循环前缀CPn={Sn[QK-L+1],…,Sn[QK]},L表示CP中包括的时域采样间隔Ts的数量。
Step 3: The terminal sends a cyclic prefix CP n in addition to the S n , wherein the cyclic prefix CP n = {S n [QK-L+1], ..., S n [QK]}, L Indicates the number of time domain sampling intervals T s included in the CP.
步骤4:可以定义Groupn为{CPn,Sn}即为终端发送对应的时域信号的表达形式;且n取值不同的Groupn在时域上占用不同的符号。Step 4: You can define that Group n is {CP n , S n } The expression of the corresponding time domain signal; and the Group n with different values of n occupy different symbols in the time domain.
步骤5:可以定义Group0~GroupN-1作为所述终端生成所述随机接入信号的基本单元(Unit)。Step 5: Group 0 to Group N-1 may be defined as a basic unit (Unit) for generating the random access signal by the terminal.
步骤6:所述终端发送的随机接入信号由所述Unit在时域上重复H次组成;Step 6: The random access signal sent by the terminal is composed of the Unit repeating H times in the time domain;
可选地,不同等级的所述终端配置的重复次数H不同。Optionally, the number of repetitions H of the terminal configurations of different levels is different.
可选地,上述终端的等级可以包括以下至少之一:Optionally, the level of the foregoing terminal may include at least one of the following:
覆盖增强等级;Coverage enhancement level;
物理信道重复发送等级;Physical channel repeat transmission level;
物理信道上承载的消息或信令的重复发送等级。Repeated transmission level of messages or signaling carried on the physical channel.
在本实施例中,系统配置的随机接入信道的子载波间隔Δf为3.75KHz,时域符号长度循环前缀CPn长度配置为266.7us,K=5,则Groupn时域长度为1.6ms(毫秒)。由于N=4,则Group0~Group3作为所述终端生成所述随机接入信号的基本单元(Unit)的长度为6.4ms;In this embodiment, the subcarrier spacing Δf of the random access channel configured by the system is 3.75 KHz, and the time domain symbol length is The cyclic prefix CP n length is configured to be 266.7us, K=5, and the Group n time domain length is 1.6ms (milliseconds). The length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
在本实施例中,Group0~Group3对应的频域子载波索引f0~f3分别为subcarrior0,subcarrior1,subcarrior7,subcarrior6,则所述终端生成所述随机接入信号的基本单元(Unit)的时域和频域的二维结构如图28所示。In the present embodiment, Group 0 ~ Group 3 corresponding to frequency domain subcarrier index f 0 ~ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially The two-dimensional structure of the time domain and frequency domain of the unit is shown in FIG.
Group0和Group1配置的子载波相邻,Group2和Group3配置的子载波相邻,Group1和Group2配置的子载波间隔6个子载波。进一步,根据Group0的子载波索引可以确定Group1、Group2和Group3的子载波索引。The subcarriers configured in Group 0 and Group 1 are adjacent to each other. The subcarriers configured in Group 2 and Group 3 are adjacent to each other. The subcarriers configured in Group 1 and Group 2 are separated by 6 subcarriers. Further, the subcarrier indexes of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
在本实施例中,随机接入信道资源包含多个时频资源集合Setm,m为所述Setm的索引。如图29所示。In this embodiment, the random access channel resource includes a plurality of time-frequency resource sets Set m , where m is an index of the Set m . As shown in Figure 29.
上述Setm在频域上包括12个子载波,分别为Subcarrior0~Subcarrior11,Setm时域长度为26ms,其中包括4个Unit的时域长度以及0.4ms的保护时间(Guard Time)。所述Setm中包括4个subset,其中,subset在频域上与Setm配置相同的子载波,subset在时域上长度为4
个Unit的长度;The Set m includes 12 subcarriers in the frequency domain, respectively Subcarrior0~Subcarrior11, and the set m time domain length is 26ms, including the time domain length of 4 Units and the guard time of 0.4ms. The Set m includes four subsets, wherein the subset is configured with the same subcarriers in the frequency domain as the Set m , and the subset has a length of 4 Units in the time domain;
时频资源集合Setm的配置周期为Vms,在本实施例中,V=2y,其中,y为大于或等于0的整数;The configuration period of the time-frequency resource set Set m is Vms. In this embodiment, V=2 y , where y is an integer greater than or equal to 0;
在本实施例中y=10,则V=1024ms;则Vms内最多可以配置39个Setm,本实施例中,所述终端一共划分为3个等级,分别为等级0、等级1、等级2。等级g(0≤g≤2)的终端发送随机接入信号需要Unit在时域上重复发送次数为Repetitiong,本实施例中,Repetition0=1,Repetition1=2,Repetition2=4。In this embodiment, y=10, then V=1024 ms; then, up to 39 Set m can be configured in Vms. In this embodiment, the terminal is divided into three levels, namely level 0, level 1, level 2, respectively. . The terminal g of the level g (0 ≤ g ≤ 2) needs to repeat the number of times that the unit repeats the transmission in the time domain is Repetition g . In this embodiment, Repetition 0 =1, Repetition 1 = 2, and Repetition 2 = 4.
在本实施例中以Setm=26ms作为等级g(0≤g≤2)的终端发送随机接入信号的资源分配的基本单位。在本实施例中为等级索引为g的终端(0≤g≤2)分配的Ng个Setm资源分别为2个Setm,2个Setm和4个Setm。In the present embodiment, the terminal allocates a basic unit of resource allocation of the random access signal with Set m = 26 ms as the level g (0 ≤ g ≤ 2). In the present embodiment, the N g Set m resources allocated for the terminal (0 ≤ g ≤ 2) whose rank index is g are 2 Set m , 2 Set m, and 4 Set m, respectively .
在本实施例中,为等级索引为g的终端配置的Setm之间时域间隔为Lgms。In this embodiment, the time domain interval between Set m configured for the terminal with the level index g is L g ms.
在本实施例中,不同等级索引的终端对应的Lg相同;本实施例中Lg=32ms。In the present embodiment, the same index different levels corresponding to the terminal L g; the present embodiment, L g = 32ms.
在本实施例中,不同等级索引的终端对应的Ng个Setm资源之间,间隔Lβ=Lg。In this embodiment, between the N g Set m resources corresponding to the terminals of different level indexes, the interval L β = L g .
本实施例中,为等级索引g=0的终端配置的第一个Setm的起始时刻与时频资源集合Setm的配置周期的起始时刻相同。In this embodiment, the start time of the first Set m configured for the terminal with the level index g=0 is the same as the start time of the configuration period of the time-frequency resource set Set m .
则在V=1024ms内,等级索引为g(0≤g≤2)的终端发送随机接入信号的资源分配如图30所示。Then, in V=1024 ms, the resource allocation of the random access signal transmitted by the terminal whose rank index is g (0≤g≤2) is as shown in FIG.
对于等级索引g=0的终端,2个Setm中一共配置了8个subset,则等级索引g=0的终端一共有8个发送随机接入信号的机会,对应的资源分别是:Set0中的subset0,Set0中的subset1,Set0中的subset2,Set0中的subset3,Set1中的subset0,Set1中的subset1,Set1中的subset2,Set1中的subset3;终端在上述8个资源中随机选择一个资源作为随机接入信号的发送资源;For the terminal with the level index g=0, a total of 8 subsets are configured in the two Set m , and the terminal with the level index g=0 has a total of 8 opportunities to send random access signals, and the corresponding resources are: Set 0 the subset0, Set 0 in subset1, Set 0 in subset2, Set 0 in subset3, Set 1 in subset0, Set 1 in subset1, Set 1 in subset2, Set 1 in subset3; terminal in the above 8 A resource is randomly selected from the resources as a transmission resource of the random access signal;
对于等级索引g=1的终端,2个Setm中一共配置了8个subset,则等级索引g=1的终端一共有4个发送随机接入信号的机会,对应的资源分别是:Set2中的subset0、subset1,Set2中的subset2、subset3,Set3中的subset0、subset1,Set3中的subset2、subset3;终端在上述4个资源中随机选择一个资源作为随机接入信号的发送资源;
For a terminal with a level index g=1, a total of 8 subsets are configured in the two Set m , and the terminal with the level index g=1 has a total of 4 opportunities for transmitting random access signals, and the corresponding resources are: Set 2 the subset0, subset1, subset2 in 2 Set, subset0 in 3 subset3, Set, subset1, subset2 in 3 Set, subset3; terminal randomly selects one of the four resource transmission resource as the resource of the random access signal;
对于等级索引g=2的终端,4个Setm中一共配置了16个subset,则等级索引g=2的终端一共有4个发送随机接入信号的机会,对应的资源分别是:Set4中的subset0、subset1、subset2、subset3,Set5中的subset0、subset1、subset2、subset3,Set6中的subset0、subset1、subset2、subset3,Set7中的subset0、subset1、subset2、subset3;终端在上述4个资源中随机选择一个资源作为随机接入信号的发送资源;For the terminal level index g = 2, a total of four arranged in a Set m Subset 16, the terminal level index g = 2, a total of four random access signal transmission opportunity, corresponding resources are: Set 4 in the subset0, subset0 in 6 subset1, subset2, subset3, Set 5 in subset0, subset1, subset2, subset3, Set, subset0 in 7 subset1, subset2, subset3, Set , subset1, subset2, subset3; terminal of the four A resource is randomly selected from the resources as a transmission resource of the random access signal;
不同的Setm的配置周期之间,等级索引为g的终端对应的资源配置方案可以是相同的。The resource allocation scheme corresponding to the terminal with the level index g may be the same between the configuration periods of different Set m .
具体实施例12 Specific embodiment 12
在通信系统中,终端可以跟据第一规则从序列集合中选择对应的序列,并且至少根据选择的序列生成随机接入信号;终端通过随机接入信道发送随机接入信号至基站。In the communication system, the terminal may select a corresponding sequence from the sequence set according to the first rule, and generate a random access signal according to at least the selected sequence; the terminal transmits the random access signal to the base station through the random access channel.
在本实施例中,可以将终端划分为2个集合,即第一终端集合和第二终端集合,且第一终端集合和第二终端集合可以满足以下条件:In this embodiment, the terminal may be divided into two sets, that is, the first terminal set and the second terminal set, and the first terminal set and the second terminal set may satisfy the following conditions:
所述第一终端集合包括的终端为Msg3消息中承载的信息量为Size1的终端,所述第二终端集合包括的终端为Msg3消息中承载的信息量为Size2的终端,其中Size1不等于Size2。The terminal included in the first terminal set is a terminal that has the information amount of the S1 in the Msg3 message, and the terminal in the second terminal set is a terminal that has the information amount of the S2 in the Msg3 message, where Size1 is not equal to Size2.
下面首先对发送端的操作进行说明:The following first describes the operation of the sender:
终端跟据第一规则从序列集合中选择对应的序列,包括:The terminal selects a corresponding sequence from the sequence set according to the first rule, including:
属于第一终端集合的终端选择序列Code0;属于第二终端集合的终端选择序列Code1;a terminal selection sequence Code 0 belonging to the first terminal set; a terminal selection sequence Code 1 belonging to the second terminal set;
终端跟据第一规则从序列集合中选择对应的序列(j=0或1)之后,按照如下步骤生成随机接入信号:The terminal selects a corresponding sequence from the sequence set according to the first rule After (j=0 or 1), generate a random access signal as follows:
步骤1:频域上索引为fn(0≤n≤3)的子载波且时域上占用连续的K个符号发送则第k个符号且子载波fn上发送的信号的频域表达式为则上述K个符号且子载波fn上发送的信号的频域表达式为
Step 1: Subcarriers indexed as f n (0 ≤ n ≤ 3) in the frequency domain and occupying consecutive K symbols in the time domain Then the frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is Then the frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is
步骤2:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度。为索引为fn的子载波占用的频域资源,FOffset
为频域偏移量。Step 2: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol. For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset.
当时域采样间隔为Ts时,对应的时域的表达式为
为时域采样点数量;When the domain sampling interval is T s , The corresponding time domain expression is The number of sampling points in the time domain;
则终端在连续的K个符号上发送的时域信号表达式为
Then the terminal sends on consecutive K symbols The time domain signal expression is
步骤3:上述终端除了发送Sn之外,还发送:循环前缀CPn,其中,该循环前缀CPn={Sn[QK-L+1],…,Sn[QK]},L表示CP中包括的时域采样间隔Ts的数量。Step 3: The terminal sends a cyclic prefix CP n in addition to the S n , wherein the cyclic prefix CP n ={S n [QK-L+1],...,S n [QK]}, L represents The number of time domain sampling intervals T s included in the CP.
步骤4:定义Groupn为{CPn,Sn},即为终端发送对应的时域信号的表达形式;且n取值不同的Groupn在时域上占用不同的符号。Step 4: Define Group n as {CP n , S n }, that is, send the terminal The expression of the corresponding time domain signal; and the Group n with different values of n occupy different symbols in the time domain.
步骤5:定义Group0~GroupN-1作为组成随机接入信号的基本单元(Unit)(对应于上述的单元)。Step 5: Define Group 0 to Group N-1 as the basic unit (corresponding to the above unit) constituting the random access signal.
步骤6:终端发送的随机接入信号由Unit在时域上重复H次形成,或者,终端发送的随机接入信号由一个Unit形成,其中,当随机接入信号由一个Unit形成时,在发送该随机接入信号时将随机接入信号重复H次再进行发送;Step 6: The random access signal sent by the terminal is formed by the Unit repeating H times in the time domain, or the random access signal sent by the terminal is formed by a Unit, where when the random access signal is formed by a Unit, it is sent. When the random access signal is used, the random access signal is repeated H times and then sent;
其中,不同等级的终端配置的重复次数H不同。Among them, the number of repetitions H of different levels of terminal configurations is different.
可选地,上述等级可以包括以下至少之一:覆盖增强等级;物理信道重复发送等级;物理信道上承载的消息或信令的重复发送等级。Optionally, the foregoing level may include at least one of the following: an coverage enhancement level; a physical channel repetition transmission level; and a repeated transmission level of a message or signaling carried on the physical channel.
在本实施例中,系统配置的随机接入信道的子载波间隔Δf可以为3.75KHz,时域符号长度循环前缀CPn长度配置为266.7us,K=5,则Groupn时域长度为1.6ms(毫秒)。由于N=4,则Group0~Group3作为所述终端生成所述随机接入信号的基本单元(Unit)的长度为6.4ms;In this embodiment, the subcarrier spacing Δf of the random access channel configured by the system may be 3.75 kHz, and the time domain symbol length is The cyclic prefix CP n length is configured to be 266.7us, K=5, and the Group n time domain length is 1.6ms (milliseconds). The length of the basic unit (Unit) in which the group 0 to the group 3 generates the random access signal is 6.4 ms;
在本实施例中,Group0~Group3对应的频域子载波索引f0~f3分别为subcarrior0,subcarrior1,subcarrior7,subcarrior6,则所述终端生成所述随机接入信号的基本单元(Unit)的时域和频域的二维结构如图2所示,Group0和Group1配置的子载波相邻,Group2和Group3配置的子载波相邻,Group1和Group2配置的子载波间隔6个子载波。进
一步,根据Group0的子载波索引可以确定Group1、Group2和Group3的子载波索引。In the present embodiment, Group 0 ~ Group 3 corresponding to frequency domain subcarrier index f 0 ~ f 3 are subcarrior 0, subcarrior 1, subcarrior 7 , subcarrior 6, then the terminal generates a random access signal substantially The two-dimensional structure of the time domain and the frequency domain of the unit is as shown in FIG. 2, the subcarriers configured by Group 0 and Group 1 are adjacent, the subcarriers configured by Group 2 and Group 3 are adjacent, and the group 1 and Group 2 are configured. The subcarriers are separated by 6 subcarriers. Further, the subcarrier indices of Group 1 , Group 2, and Group 3 can be determined according to the subcarrier index of Group 0 .
在本实施例中,所述终端配置的重复次数为1次,则只需要发送基本单元(Unit)一次。In this embodiment, if the number of repetitions of the terminal configuration is one, only the basic unit (Unit) needs to be sent once.
在本实施例中,所述终端发送随机接入信号占用的随机接入信道资源包含在1个时频资源集合Setm中,m为所述Setm的索引。如图31所示,所述Setm在频域上包括12个子载波(Subcarrior),分别为Subcarrior0~Subcarrior11,所述Setm的配置周期为40ms。本实施例中用于发送随机接入信号的随机接入信道占用的子载波数量为Num,且Num=10,则默认子载波索引最小的10个Subcarrior作为随机接入信道占用的子载波,本实施例中即为Subcarrior0~Subcarrior9,所述Subcarrior0~Subcarrior9为组成所述随机接入信号的单元Unit中Group0发送时所在的子载波索引,Unit中除Group0之外的Group1、Group2和Group3所在的频域资源由Group0的频域位置且按照预定义规则确定。本实施例中,Group0、Group1、Group2和Group3分别对应子载波索引为Subcarrior0、Subcarrior1、Subcarrior7、Subcarrior6。In this embodiment, the random access channel resource occupied by the terminal transmitting the random access signal is included in one time-frequency resource set Set m , where m is an index of the Set m . 31, the Set m in the frequency domain comprises 12 subcarriers (Subcarrior), respectively Subcarrior0 ~ Subcarrior11, the arrangement period Set m to 40ms. In this embodiment, the number of subcarriers occupied by the random access channel for transmitting the random access signal is Num, and Num=10, and the 10 subcarriors with the smallest default subcarrier index are used as the subcarriers occupied by the random access channel. In the embodiment, Subcarrior0~Subcarrior9, the Subcarrior0~Subcarrior9 are subcarrier indexes in which the Group 0 in the unit unit constituting the random access signal is transmitted, and Group 1 and Group 2 in the Unit except Group 0 and The frequency domain resource where Group 3 is located is determined by the frequency domain location of Group 0 and according to predefined rules. In this embodiment, Group 0 , Group 1 , Group 2, and Group 3 respectively correspond to subcarrier indexes of Subcarrior0, Subcarrior1, Subcarrior7, and Subcarrior6.
基站在成功完成终端发送的随机接入信号检测以及终端的上行定时同步偏差估计后,就会发送随机接入响应消息(Random Access Response,简称为RAR,又叫做消息2,Message2,简称Msg2)给终端。终端接收到RAR消息,获得上行定时同步信息和上行资源。但此时并不能确定RAR消息是发送给终端自己而不是发送给其他的终端的,因为存在着不同的终端在相同的时间-频率资源上发送相同随机接入信号的可能性(这种情况叫做随机接入冲突),为此终端需要在RAR中分配的上行资源上发送消息3(Message3,简称为Msg3)来解决随机接入冲突。在初始随机接入过程中,Msg3中会携带一个终端的特定的ID,用于区分不同的终端。After successfully completing the random access signal detection sent by the terminal and the uplink timing synchronization deviation estimation of the terminal, the base station sends a random access response message (RAR, also referred to as message 2, Message 2, referred to as Msg2) to the base station. terminal. The terminal receives the RAR message, and obtains uplink timing synchronization information and uplink resources. However, it is not certain at this time that the RAR message is sent to the terminal itself rather than to other terminals because there is a possibility that different terminals transmit the same random access signal on the same time-frequency resource (this case is called For random access conflicts, the terminal needs to send a message 3 (Message3, referred to as Msg3) on the uplink resource allocated in the RAR to solve the random access conflict. In the initial random access process, Msg3 carries a specific ID of a terminal to distinguish different terminals.
终端在基站配置的Msg3消息资源上发送Msg3消息,基站在接收到终端发送的Msg3后,通过发送消息4(Message4,简称为Msg4)最终解决这样的随机接入冲突。其中,Msg4中会携带终端在Msg3中发送的特定的ID。终端接收到基站发送的Msg4消息,并且其中携带的ID与自己在Msg3中上报给基站的特定ID相符,那么终端就认为自己赢得了此次的随机接入冲突,随机接入成功;否则,终端认为此次接入失败,并重新进行随机接入过程。The terminal sends an Msg3 message on the Msg3 message resource configured by the base station. After receiving the Msg3 sent by the terminal, the base station finally solves such a random access conflict by sending a message 4 (Message4, referred to as Msg4). Among them, Msg4 will carry a specific ID sent by the terminal in Msg3. When the terminal receives the Msg4 message sent by the base station, and the ID carried in the terminal matches the specific ID reported to the base station in Msg3, the terminal considers that it has won the random access collision and the random access succeeds; otherwise, the terminal It is considered that the access fails and the random access process is re-executed.
本实施例中,发送给终端的RAR消息中包括以下信息:In this embodiment, the RAR message sent to the terminal includes the following information:
Msg3发送时使用的子载波间隔的指示信息;The indication information of the subcarrier spacing used when transmitting Msg3;
Msg3发送时子载波数量指示信息;The number of subcarriers indication information when Msg3 is sent;
本实施例中,所述“Msg3发送时使用的子载波间隔的指示信息”和“Msg3发送时子载波数量指示信息”通过联合编码方式指示;In this embodiment, the indication information of the subcarrier spacing used when Msg3 is transmitted and the indication information of the number of subcarriers when the Msg3 is transmitted are indicated by a joint coding manner.
当终端采用单个子载波的传输方式发送所述Msg3消息,且所述单个子载波的间隔有3.75kHz和15kHz两种配置。当上行可用带宽为180kHz时,针对3.75kHz的单个子载波间隔,上行可用带宽中可以配置最多48个子载波,子载波索引为A0~A47;针对15kHz的单个子载
波间隔,上行可用带宽中可以配置最多12个子载波,子载波索引为B0~B11;则所述联合编码方式指示为:When the terminal transmits the Msg3 message by using a single subcarrier transmission manner, the single subcarriers have two configurations of 3.75 kHz and 15 kHz. When the uplink available bandwidth is 180 kHz, for a single subcarrier interval of 3.75 kHz, up to 48 subcarriers can be configured in the uplink available bandwidth, and the subcarrier index is A0 to A47; for a single subcarrier of 15 kHz
A maximum of 12 subcarriers can be configured in the uplink available bandwidth, and the subcarrier index is B0 to B11. The joint coding mode indication is:
配置6bits的联合编码指示信息,其中“000000”~“101111”指示子载波索引A0~A47,Configure joint coding indication information of 6 bits, where "000000" to "101111" indicate subcarrier indexes A0 to A47,
“110000”~“111011”指示子载波索引B0~B11。"110000" to "111011" indicate subcarrier indexes B0 to B11.
当终端采用多个子载波的传输方式发送所述Msg3消息,且子载波的间隔为15kHz。当上行可用带宽为180kHz时,上行可用带宽中可以配置最多12个子载波,子载波索引为0~11,所述Msg3消息的频域资源分配有以下几种配置:When the terminal transmits the Msg3 message by using multiple subcarrier transmission modes, the subcarrier spacing is 15 kHz. When the uplink available bandwidth is 180 kHz, a maximum of 12 subcarriers can be configured in the uplink available bandwidth, and the subcarrier index is 0 to 11. The frequency domain resource allocation of the Msg3 message has the following configurations:
1、占用子载波索引{0,1,2,3,4,5,6,7,8,9,10,11}全部的12个子载波,1. All 12 subcarriers occupying the subcarrier index {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11},
2、占用子载波索引{0,1,2,3,4,5}的6个子载波,或占用子载波索引{6,7,8,9,10,11}的6个子载波;2. 6 subcarriers occupying the subcarrier index {0, 1, 2, 3, 4, 5}, or 6 subcarriers occupying the subcarrier index {6, 7, 8, 9, 10, 11};
3、占用子载波索引{0,1,2}的3个子载波,或占用子载波索引{3,4,5}的3个子载波,或占用子载波索引{6,7,8}的3个子载波,或占用子载波索引{9,10,11}的3个子载波。3. 3 subcarriers occupying the subcarrier index {0, 1, 2}, or 3 subcarriers occupying the subcarrier index {3, 4, 5}, or 3 subcarriers occupying the subcarrier index {6, 7, 8} Carrier, or 3 subcarriers occupying subcarrier index {9, 10, 11}.
则所述联合编码方式指示为:Then the joint coding mode indication is:
配置3bits的联合编码指示信息,其中“000”指示占用子载波索引{0,1,2,3,4,5,6,7,8,9,10,11};“001”“010”分别指示占用子载波索引{0,1,2,3,4,5}的6个子载波和占用子载波索引{6,7,8,9,10,11}的6个子载波;“011”“100”“101”“110”分别指示占用子载波索引{0,1,2}的3个子载波、占用子载波索引{3,4,5}的3个子载波、占用子载波索引{6,7,8}的3个子载波和{9,10,11}的3个子载波。Configure joint coding indication information of 3 bits, where "000" indicates occupied subcarrier index {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11}; "001" and "010" respectively Indicates 6 subcarriers occupying the subcarrier index {0, 1, 2, 3, 4, 5} and 6 subcarriers occupying the subcarrier index {6, 7, 8, 9, 10, 11}; "011" "100 "101" and "110" respectively indicate 3 subcarriers occupying the subcarrier index {0, 1, 2}, 3 subcarriers occupying the subcarrier index {3, 4, 5}, and the occupied subcarrier index {6, 7, 3 subcarriers of 8} and 3 subcarriers of {9, 10, 11}.
具体实施例13 Specific embodiment 13
NB-IoT系统中,上行系统带宽为180kHz。如图32所示,本实施例中,基站配置的随机接入信道(PRACH)占用的上行带宽为45kHz,PRACH子载波间隔Δf为3.75kHz,一共配置12个PRACH子载波,分别为Subcarrior 0~Subcarrior 11。In the NB-IoT system, the uplink system bandwidth is 180 kHz. As shown in FIG. 32, in this embodiment, the uplink access bandwidth (PRACH) configured by the base station occupies an uplink bandwidth of 45 kHz, and the PRACH subcarrier spacing Δf is 3.75 kHz. A total of 12 PRACH subcarriers are configured, respectively, which are Subcarrior 0 ~ Subcarrior 11.
定义Group1~Group4作为组成随机接入信号(Preamble)的基本单元(Unit)。其中,Group1~Group4分别在不同的子载波上发送;每个Group上包括1个循环前缀(CP)和5个Preamble符号(symbol),一个Preamble symbol时域符号长度
Group 1 to Group 4 are defined as the basic unit (Unit) that constitutes a random access signal (Preamble). Group 1 to Group 4 are respectively sent on different subcarriers; each group includes one cyclic prefix (CP) and five Preamble symbols (symbol), and one Preamble symbol time domain symbol length.
当CP长度为0.2667ms时,每个Group长度为0.2667+0.2667*5=1.6ms,Unit长度为1.6*4=6.4ms;When the length of the CP is 0.2667ms, the length of each group is 0.2667+0.2667*5=1.6ms, and the length of the Unit is 1.6*4=6.4ms.
当CP长度为0.0667ms时,每个Group长度为0.0667+0.2667*5=1.4ms,Unit长度为
1.4*4=5.6ms;When the length of the CP is 0.0667ms, the length of each group is 0.0667+0.2667*5=1.4ms, and the length of the unit is
1.4*4=5.6ms;
本实施例中,CP长度为0.2667ms,则Unit长度为6.4ms;In this embodiment, the CP length is 0.2667 ms, and the unit length is 6.4 ms;
当终端选择Group1发送的Subcarrior为Subcarrior0时,Group2发送的Subcarrior为Subcarrior1,Group3发送的Subcarrior为Subcarrior7,Group4发送的Subcarrior为Subcarrior6,如图32所示。When the terminal selects the Subcarrior sent by Group 1 as Subcarrior0, the Subcarrior sent by Group 2 is Subcarrior1, the Subcarrior sent by Group 3 is Subcarrior7, and the Subcarrior sent by Group 4 is Subcarrior6, as shown in Figure 32.
为了避免NB-IoT系统中PRACH与探测信号(Sounding Reference Signal,简称为SRS)之间的干扰(所述SRS可以是NB-IoT系统配置的,或者是其他系统配置的),NB-IoT系统PRACH资源配置中要增加第二保护时间(Guard Time 2,简称为GT2)。本实施例中,SRS来自LTE系统,且当终端完成1个Group的随机接入信号发送之后,需要引入时间长度为0.4ms的GT2,如图32所示,则Unit长度变为8ms;In order to avoid interference between the PRACH and the Sounding Reference Signal (SRS) in the NB-IoT system (the SRS may be configured by the NB-IoT system or configured by other systems), the NB-IoT system PRACH The second protection time (Guard Time 2, GT2 for short) is added to the resource configuration. In this embodiment, the SRS is from the LTE system, and after the terminal completes the transmission of the random access signal of one group, the GT2 with a time length of 0.4 ms needs to be introduced. As shown in FIG. 32, the unit length becomes 8 ms.
随机接入信号(Preamble)的基本单元(Unit)的时间长度T_Unit1为8ms;The time length of the basic unit of the random access signal (Preamble) T_Unit1 is 8 ms;
在本实施例中,PRACH上发送的随机接入信号(Preamble)的发送周期为1280ms;In this embodiment, the transmission period of the random access signal (Preamble) transmitted on the PRACH is 1280 ms;
Preamble发送的起始位置偏移量为128ms。The starting position offset of the Preamble transmission is 128ms.
Preamble传输的基本单元的重复发送次数,R1;R1由{1,2,4,8,16,32,64,128}中选择,本实施例中R1=64;The number of repeated transmissions of the basic unit transmitted by the Preamble, R1; R1 is selected from {1, 2, 4, 8, 16, 32, 64, 128}, in this embodiment, R1=64;
Preamble传输的保护时间(Guard Time),GT1=1ms;Guard Time of Preamble transmission, GT1=1ms;
本实施例中Preamble传输的基本单元的64次重复发送一共长度为512ms;In this embodiment, the 64-time repeated transmission of the basic unit of the Preamble transmission has a total length of 512 ms;
当Preamble传输的基本单元的重复传输次数大于R1set时,完成R1set次Preamble基本单元的传输后,需要引入Preamble传输间隔Gap1,在Gap1时间内,并不传输Preamble。本实施例中R1set=32,Gap1=20ms,则Preamble的基本单元的64次重复传输结构如图33所示。When the number of repeated transmissions of the basic unit of the Preamble transmission is greater than R1set, after the transmission of the R1set secondary Preamble basic unit is completed, the Preamble transmission interval Gap1 needs to be introduced, and the Preamble is not transmitted during the Gap1 time. In this embodiment, R1set=32 and Gap1=20 ms, and the 64-time repeated transmission structure of the basic unit of the Preamble is as shown in FIG.
具体实施例14 Specific embodiment 14
NB-IoT系统中,上行系统带宽为180kHz。如图34所示,本实施例中,基站配置的随机接入信道(PRACH)占用的上行带宽为45kHz,PRACH子载波间隔Δf为3.75kHz,一共配置12个PRACH子载波,分别为Subcarrior 0~Subcarrior 11。In the NB-IoT system, the uplink system bandwidth is 180 kHz. As shown in FIG. 34, in this embodiment, the uplink access bandwidth (PRACH) configured by the base station occupies an uplink bandwidth of 45 kHz, and the PRACH subcarrier spacing Δf is 3.75 kHz. A total of 12 PRACH subcarriers are configured, respectively, which are Subcarrior 0 ~ Subcarrior 11.
定义Group1~Group4作为组成随机接入信号(Preamble)的基本单元(Unit)。其中,Group1~Group4分别在不同的子载波上发送;每个Group上包括1个循环前缀(CP)和5个Preamble符号(symbol),一个Preamble symbol时域符号长度
Group 1 to Group 4 are defined as the basic unit (Unit) that constitutes a random access signal (Preamble). Group 1 to Group 4 are respectively sent on different subcarriers; each group includes one cyclic prefix (CP) and five Preamble symbols (symbol), and one Preamble symbol time domain symbol length.
当CP长度为0.2667ms时,每个Group长度为0.2667+0.2667*5=1.6ms,Unit长度为1.6*4=6.4ms;When the length of the CP is 0.2667ms, the length of each group is 0.2667+0.2667*5=1.6ms, and the length of the Unit is 1.6*4=6.4ms.
当CP长度为0.0667ms时,每个Group长度为0.0667+0.2667*5=1.4ms,Unit长度为1.4*4=5.6ms;When the length of the CP is 0.0667ms, the length of each group is 0.0667+0.2667*5=1.4ms, and the length of the Unit is 1.4*4=5.6ms.
本实施例中,CP长度为0.2667ms,则Unit长度为6.4ms;In this embodiment, the CP length is 0.2667 ms, and the unit length is 6.4 ms;
当终端选择Group1发送的Subcarrior为Subcarrior0时,Group2发送的Subcarrior为Subcarrior1,Group3发送的Subcarrior为Subcarrior7,Group4发送的Subcarrior为Subcarrior6,如图34所示。When the terminal selects Subcarrior sent by Group 1 as Subcarrior0, the Subcarrior sent by Group 2 is Subcarrior1, the Subcarrior sent by Group 3 is Subcarrior7, and the Subcarrior sent by Group 4 is Subcarrior6, as shown in Figure 34.
为了避免NB-IoT系统中PRACH与探测信号(Sounding Reference Signal,简称为SRS)之间的干扰(所述SRS可以是NB-IoT系统配置的,或者是其他系统配置的),NB-IoT系统PRACH资源配置中要增加第二保护时间(Guard Time 2,简称为GT2)。本实施例中,SRS来自LTE系统,且当终端完成2个Group的随机接入信号发送之后,需要引入时间长度为0.8ms的GT2,如图34所示,则Unit长度变为8ms;In order to avoid interference between the PRACH and the Sounding Reference Signal (SRS) in the NB-IoT system (the SRS may be configured by the NB-IoT system or configured by other systems), the NB-IoT system PRACH The second protection time (Guard Time 2, GT2 for short) is added to the resource configuration. In this embodiment, the SRS is from the LTE system, and after the terminal completes the transmission of the random access signals of the two groups, the GT2 with a length of 0.8 ms needs to be introduced. As shown in FIG. 34, the unit length becomes 8 ms.
随机接入信号(Preamble)的基本单元(Unit)的时间长度T_Unit1为8ms;The time length of the basic unit of the random access signal (Preamble) T_Unit1 is 8 ms;
本实施例中,In this embodiment,
PRACH上发送的随机接入信号(Preamble)的发送周期为1280ms;The transmission period of the random access signal (Preamble) transmitted on the PRACH is 1280 ms;
Preamble发送的起始位置偏移量为128ms。The starting position offset of the Preamble transmission is 128ms.
Preamble传输的基本单元的重复发送次数,R1;R1由{1,2,4,8,16,32,64,128}中选择,本实施例中R1=64;The number of repeated transmissions of the basic unit transmitted by the Preamble, R1; R1 is selected from {1, 2, 4, 8, 16, 32, 64, 128}, in this embodiment, R1=64;
Preamble传输的保护时间(Guard Time),GT1=1ms;Guard Time of Preamble transmission, GT1=1ms;
本实施例中Preamble传输的基本单元的64次重复发送一共长度为512ms;In this embodiment, the 64-time repeated transmission of the basic unit of the Preamble transmission has a total length of 512 ms;
当Preamble传输的基本单元的重复传输次数大于R1set时,完成R1set次Preamble基本单元的传输后,需要引入Preamble传输间隔Gap1,在Gap1时间内,并不传输Preamble。本实施例中R1set=32,Gap1=20ms,则Preamble的基本单元的64次重复传输结构如图35所示。When the number of repeated transmissions of the basic unit of the Preamble transmission is greater than R1set, after the transmission of the R1set secondary Preamble basic unit is completed, the Preamble transmission interval Gap1 needs to be introduced, and the Preamble is not transmitted during the Gap1 time. In this embodiment, R1set=32 and Gap1=20 ms, and the 64-time repeated transmission structure of the basic unit of the Preamble is as shown in FIG. 35.
具体实施例15Specific embodiment 15
NB-IoT系统中,上行系统带宽为180kHz。如图36所示,本实施例中,基站配置的随机接入信道(PRACH)占用的上行带宽为45kHz,PRACH子载波间隔Δf为3.75kHz,一共配置12个PRACH子载波,分别为Subcarrior 0~Subcarrior 11。
In the NB-IoT system, the uplink system bandwidth is 180 kHz. As shown in FIG. 36, in this embodiment, the uplink access bandwidth (PRACH) configured by the base station occupies an uplink bandwidth of 45 kHz, and the PRACH subcarrier spacing Δf is 3.75 kHz. A total of 12 PRACH subcarriers are configured, respectively, which are Subcarrior 0 ~ Subcarrior 11.
定义Group1~Group4作为组成随机接入信号(Preamble)的基本单元(Unit)。其中,Group1~Group4分别在不同的子载波上发送;每个Group上包括1个循环前缀(CP)和5个Preamble符号(symbol),一个Preamble symbol时域符号长度
Group 1 to Group 4 are defined as the basic unit (Unit) that constitutes a random access signal (Preamble). Group 1 to Group 4 are respectively sent on different subcarriers; each group includes one cyclic prefix (CP) and five Preamble symbols (symbol), and one Preamble symbol time domain symbol length.
当CP长度为0.2667ms时,每个Group长度为0.2667+0.2667*5=1.6ms;When the CP length is 0.2667ms, each group length is 0.2667+0.2667*5=1.6ms;
当CP长度为0.0667ms时,每个Group长度为0.0667+0.2667*5=1.4ms;When the length of the CP is 0.0667ms, the length of each group is 0.0667+0.2667*5=1.4ms;
本实施例中,CP长度为0.2667ms,每个Group长度为0.2667+0.2667*5=1.6ms;In this embodiment, the length of the CP is 0.2667 ms, and the length of each group is 0.2667 + 0.2667 * 5 = 1.6 ms;
当终端选择Group1发送的Subcarrior为Subcarrior0时,Group2发送的Subcarrior为Subcarrior1,Group3发送的Subcarrior为Subcarrior7,Group4发送的Subcarrior为Subcarrior6,如图36所示。When the terminal selects the Subcarrior sent by Group 1 as Subcarrior0, the Subcarrior sent by Group 2 is Subcarrior1, the Subcarrior sent by Group 3 is Subcarrior7, and the Subcarrior sent by Group 4 is Subcarrior6, as shown in Figure 36.
本实施例中,Preamble传输的Unit的重复发送次数R1=64;64次Unit中包括Y(Y=64*4=256)个Group,定义256个Group的索引为Group0~Group255;In this embodiment, the number of repeated transmissions of the Unit transmitted by the Preamble is R1=64; the 64 units include Y (Y=64*4=256) Groups, and the indexes defining the 256 Groups are Group 0 to Group 255 ;
为了避免NB-IoT系统中PRACH与探测信号(Sounding Reference Signal,简称为SRS)之间的干扰(所述SRS可以是NB-IoT系统配置的,或者是其他系统配置的),NB-IoT系统PRACH资源配置中要增加时间间隔(Gap)。本实施例中,SRS来自LTE系统,且当终端完成6个Group的随机接入信号发送之后,需要引入时间长度为0.4ms的Gap;则引入Gap的数量Ngap为
In order to avoid interference between the PRACH and the Sounding Reference Signal (SRS) in the NB-IoT system (the SRS may be configured by the NB-IoT system or configured by other systems), the NB-IoT system PRACH Increase the time interval (Gap) in the resource configuration. After the present embodiment, the SRS from the LTE system, and is completed when the terminal transmits a random access signal of Group 6, the length of time necessary to introduce the Gap 0.4ms; the introduction of the number N gap Gap
所述6个Group的索引为Groupstart到Groupend;其中,start=6×ngap,0≤ngap≤Ngap-1;end=start+5。The index of the six groups is Group start to Group end ; where start=6×n gap , 0≤n gap ≤N gap −1; end=start+5.
具体实施例16Specific embodiment 16
NB-IoT系统中,上行系统带宽为180kHz。如图37所示,本实施例中,基站配置的随机接入信道(PRACH)占用的上行带宽为45kHz,PRACH子载波间隔Δf为3.75kHz,一共配置12个PRACH子载波,分别为Subcarrior 0~Subcarrior 11。In the NB-IoT system, the uplink system bandwidth is 180 kHz. As shown in FIG. 37, in this embodiment, the uplink access bandwidth (PRACH) configured by the base station occupies an uplink bandwidth of 45 kHz, and the PRACH subcarrier spacing Δf is 3.75 kHz. A total of 12 PRACH subcarriers are configured, respectively, which are Subcarrior 0 ~ Subcarrior 11.
定义Group1~Group4作为组成随机接入信号(Preamble)的基本单元(Unit)。其中,Group1~Group4分别在不同的子载波上发送;每个Group上包括1个循环前缀(CP)和5个
Preamble符号(symbol),一个Preamble symbol时域符号长度
Group 1 to Group 4 are defined as the basic unit (Unit) that constitutes a random access signal (Preamble). Group 1 to Group 4 are respectively sent on different subcarriers; each group includes one cyclic prefix (CP) and five Preamble symbols (symbol), and one Preamble symbol time domain symbol length.
当CP长度为0.2667ms时,每个Group长度为0.2667+0.2667*5=1.6ms;When the CP length is 0.2667ms, each group length is 0.2667+0.2667*5=1.6ms;
当CP长度为0.0667ms时,每个Group长度为0.0667+0.2667*5=1.4ms;When the length of the CP is 0.0667ms, the length of each group is 0.0667+0.2667*5=1.4ms;
本实施例中,CP长度为0.2667ms,每个Group长度为0.2667+0.2667*5=1.6ms;In this embodiment, the length of the CP is 0.2667 ms, and the length of each group is 0.2667 + 0.2667 * 5 = 1.6 ms;
当终端选择Group1发送的Subcarrior为Subcarrior0时,Group2发送的Subcarrior为Subcarrior1,Group3发送的Subcarrior为Subcarrior7,Group4发送的Subcarrior为Subcarrior6,如图37所示。When the terminal selects the Subcarrior sent by Group 1 as Subcarrior0, the Subcarrior sent by Group 2 is Subcarrior1, the Subcarrior sent by Group 3 is Subcarrior7, and the Subcarrior sent by Group 4 is Subcarrior6, as shown in Figure 37.
本实施例中,Preamble传输的Unit的重复发送次数R1=64;定义64个Unit的索引为Unit0~Unit63;In this embodiment, the number of repeated transmissions of the Unit transmitted by the Preamble is R1=64; the index defining the 64 Units is Unit 0 to Unit 63 ;
为了避免NB-IoT系统中PRACH与探测信号(Sounding Reference Signal,简称为SRS)之间的干扰(所述SRS可以是NB-IoT系统配置的,或者是其他系统配置的),NB-IoT系统PRACH资源配置中要增加时间间隔(Gap)。本实施例中,SRS来自LTE系统,且当终端完成4个Unit的随机接入信号发送之后,需要引入时间长度为0.4ms的Gap;则引入Gap的数量Ngap为
In order to avoid interference between the PRACH and the Sounding Reference Signal (SRS) in the NB-IoT system (the SRS may be configured by the NB-IoT system or configured by other systems), the NB-IoT system PRACH Increase the time interval (Gap) in the resource configuration. After the present embodiment, the SRS from the LTE system, and is completed when the terminal transmits a random access signal Unit 4, the length of time necessary to introduce the Gap 0.4ms; the introduction of the number N gap Gap
所述4个Unit的索引为Unitstart到Unitend;其中start=4×ngap,0≤ngap≤Ngap-1;end=start+3。The index of the 4 units is Unit start to Unit end ; where start=4×n gap , 0≤n gap ≤N gap −1; end=start+3.
通过以上的实施方式的描述,本领域的技术人员可以清楚地了解到根据上述实施例的方法可借助软件加必需的通用硬件平台的方式来实现,当然也可以通过硬件,但很多情况下前者是更佳的实施方式。基于这样的理解,本发明的技术方案本质上或者说对现有技术做出贡献的部分可以以软件产品的形式体现出来,该计算机软件产品存储在一个存储介质(如ROM/RAM、磁碟、光盘)中,包括若干指令用以使得一台终端设备(可以是手机,计算机,服务器,或者网络设备等)执行本发明各个实施例所述的方法。Through the description of the above embodiments, those skilled in the art can clearly understand that the method according to the above embodiment can be implemented by means of software plus a necessary general hardware platform, and of course, by hardware, but in many cases, the former is A better implementation. Based on such understanding, the technical solution of the present invention, which is essential or contributes to the prior art, may be embodied in the form of a software product stored in a storage medium (such as ROM/RAM, disk, The optical disc includes a number of instructions for causing a terminal device (which may be a cell phone, a computer, a server, or a network device, etc.) to perform the methods described in various embodiments of the present invention.
在本实施例中还提供了一种接入处理装置,该装置用于实现上述实施例及优选实施方式,已经进行过说明的不再赘述。如以下所使用的,术语“模块”可以实现预定功能的软件和/或硬件的组合。尽管以下实施例所描述的装置较佳地以软件来实现,但是硬件,或者软件和硬件的组合的实现也是可能并被构想的。In the embodiment, an access processing device is also provided, which is used to implement the foregoing embodiments and preferred embodiments, and details are not described herein. As used below, the term "module" may implement a combination of software and/or hardware of a predetermined function. Although the apparatus described in the following embodiments is preferably implemented in software, hardware, or a combination of software and hardware, is also possible and contemplated.
图38是根据本发明实施例的接入处理装置的结构框图,该装置可以应用于终端中,如图38所示,该装置包括选择模块382、生成模块384和发送模块386,下面对该装置进行说明:
FIG. 38 is a structural block diagram of an access processing apparatus according to an embodiment of the present invention. The apparatus may be applied to a terminal. As shown in FIG. 38, the apparatus includes a selection module 382, a generating module 384, and a sending module 386. Description of the device:
选择模块382,设置为选择序列集合中与终端对应的序列;生成模块384,连接至上述选择模块382,设置为至少根据对应的序列生成随机接入信号;发送模块386,连接至上述生成模块384,设置为发送上述随机接入信号给基站。The selecting module 382 is configured to select a sequence corresponding to the terminal in the sequence set; the generating module 384 is connected to the selecting module 382, configured to generate a random access signal according to at least the corresponding sequence; and the sending module 386 is connected to the generating module 384. And configured to send the random access signal to the base station.
在一个可选的实施例中,上述序列集合中包括J条序列长度均为N的序列,其中,索引为j的序列的表达形式为J为正整数,N为正整数。In an optional embodiment, the sequence set includes a sequence of J sequences having a length of N, wherein the sequence of the index of j is expressed as J is a positive integer and N is a positive integer.
在一个可选的实施例中,上述序列集合中包括R个序列子集合,即,序列集合中包括的J条序列被划分为的R个序列子集合,并且,R个序列子集合可以被配置给不同的终端集合,其中,R为正整数。In an optional embodiment, the sequence set includes R sequence subsets, that is, R sequence subsets in which J sequences included in the sequence set are divided, and R sequence subsets can be configured. Give a different set of terminals, where R is a positive integer.
上述的选择模块382可以通过如下方式选择序列集合中与终端对应的序列:从上述R个序列子集合中确定与自身所属的终端集合对应的序列子集合;终端从确定的序列子集合中选择一条序列作为对应的序列。可选地,当确定的序列子集合中只有1条序列时,选择该序列子集合中的这1条序列作为对应的序列;当确定的序列子集合中有多条序列时,从确定的序列子集合中随机的选择一条序列作为对应的序列;其中,R为正整数。在本实施例中,上述的序列集合可以被分为R个序列子集合,因此,在选择与终端对应的序列时,终端可以首先选择配置给自身所属的终端集合的序列子集合,进而再从该选择的序列子集合中选择对应的序列。The selection module 382 may select a sequence corresponding to the terminal in the sequence set by: determining a sequence subset corresponding to the terminal set to which the terminal belongs to the R sequence subsets; and selecting a piece from the determined sequence subset The sequence acts as the corresponding sequence. Optionally, when there are only one sequence in the determined sequence subset, the one sequence in the sequence subset is selected as a corresponding sequence; when there are multiple sequences in the determined sequence subset, the determined sequence is determined A sequence is randomly selected in the subset as a corresponding sequence; where R is a positive integer. In this embodiment, the foregoing sequence set may be divided into R sequence sub-sets. Therefore, when selecting a sequence corresponding to the terminal, the terminal may first select a sequence sub-set that is configured for the terminal set to which the terminal belongs, and then A corresponding sequence is selected from the selected subset of sequences.
在一个可选的实施例中,上述的选择模块382可以通过如下方式从R个序列子集合中确定与自身所属的终端集合对应的序列子集合:从R个序列子集合中选择第(Y+1)个序列子集合作为与自身所属的终端集合对应的序列子集合,其中,Y=Mod(Cell ID,R),Cell ID为终端接入的小区标识索引。在本实施例中,可以是基站为终端所属的终端集合配置子序列结合上述的Mod(Cell ID,R)为取余算法,即,Y为Cell ID除以R之后得到的余数。In an optional embodiment, the selecting module 382 may determine a sequence subset corresponding to the terminal set to which it belongs from the R sequence subsets by selecting the (Y+) from the R sequence subsets. 1) A sequence sub-set is a sequence sub-set corresponding to a terminal set to which it belongs, where Y=Mod (Cell ID, R), and the Cell ID is a cell identity index accessed by the terminal. In this embodiment, the base station may configure a subsequence for the terminal set to which the terminal belongs, in combination with the Mod (Cell ID, R) described above as a remnant algorithm, that is, Y is a remainder obtained by dividing the Cell ID by R.
在一个可选的实施例中,上述R个序列子集合可以分别被配置给R个不同的终端集合,即,序列子集合和终端集合是一一对应的。当然,在应用中,序列子集合和终端集合之间还可以是多对一或一对多的关系。In an optional embodiment, the R sequence subsets may be respectively configured to R different terminal sets, that is, the sequence subset and the terminal set are in one-to-one correspondence. Of course, in an application, a sequence of sub-sets and terminal sets may also be a many-to-one or one-to-many relationship.
在一个可选的实施例中,终端集合的划分方式可以为多种,下面对不同的终端集合划分方式进行说明:In an optional embodiment, the terminal set may be divided into multiple modes. The following describes different terminal set division modes:
当终端集合的数量为2时,2个不同的终端集合为第一终端集合和第二终端集合,该第一终端集合和第二终端集合满足以下条件至少之一:第一终端集合包括的终端为支持多个子载波同时传输的终端,且第二终端集合包括的终端为仅支持单个子载波传输的终端;第一终端集合包括的终端为采用多个子载波传输上行数据的终端,且第二终端集合包括的终端为采用单个子载波传输上行数据的终端;第一终端集合包括的终端为采用多个子载波同时传输Msg3消息的终端,且第二终端集合包括的终端为采用单个子载波传输Msg3消息的终端;第一终端集合包括的终端为Msg3消息承载在多个子载波上传输的终端,且第二终端集合包括的终端为
Msg3消息仅承载在单个子载波传输的终端;第一终端集合包括的终端为支持单个子载波传输且子载波间隔为fsc1的终端,第二终端集合包括的终端为支持单个子载波传输且子载波间隔为fsc2的终端;第一终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc1的终端;第二终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc2的终端;第一终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc1的终端,第二终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc2的终端;第一终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc1的终端,第二终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc2的终端;上述第一终端集合包括的终端为Msg3消息中承载的信息量为Size1的终端,第二终端集合包括的终端为Msg3消息中承载的信息量为Size2的终端,其中,Size1不等于Size2;When the number of terminal sets is 2, the two different terminal sets are the first terminal set and the second terminal set, and the first terminal set and the second terminal set satisfy at least one of the following conditions: the terminal included in the first terminal set A terminal that supports simultaneous transmission of multiple subcarriers, and the terminal included in the second terminal set is a terminal that supports only one subcarrier transmission; the terminal included in the first terminal set is a terminal that uses multiple subcarriers to transmit uplink data, and the second terminal The terminal included in the set is a terminal that transmits uplink data by using a single subcarrier; the terminal included in the first terminal set is a terminal that simultaneously transmits an Msg3 message by using multiple subcarriers, and the terminal included in the second terminal set transmits the Msg3 message by using a single subcarrier. The terminal included in the first terminal set is a terminal that transmits the Msg3 message on the multiple subcarriers, and the terminal included in the second terminal set is that the Msg3 message is only carried in the terminal of the single subcarrier transmission; the first terminal set includes a terminal support and a single sub-carrier transmission subcarrier spacing f sc1 terminal, the second terminal sets Comprising a terminal support and a single sub-carrier transmission subcarrier spacing f sc2 terminal; a first set of terminals including a terminal for the use of a single subcarrier for transmitting uplink data and the subcarrier spacing f sc1 terminal; a second set of terminals included The terminal is a terminal that uses a single subcarrier to transmit uplink data and has a subcarrier spacing of f sc2 ; the terminal included in the first terminal set is a terminal that transmits an Msg3 message by using a single subcarrier and has a subcarrier spacing of f sc1 , and the second terminal set includes The terminal is a terminal that uses a single subcarrier to transmit an Msg3 message and the subcarrier spacing is f sc2 . The terminal included in the first terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc1 , and the second terminal is set. The terminal included is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc2 ; the terminal included in the first terminal set is a terminal in which the amount of information carried in the Msg3 message is Size1, and the second terminal set includes The terminal is a terminal that carries the amount of information in the Msg3 message is Size2, where Size1 is not equal to Size2;
当终端集合的数量为3时,3个不同的终端集合为第一终端集合、第二终端集合和第三终端集合,第一终端集合、第二终端集合和第三终端集合满足以下条件至少之一:第一终端集合包括的终端为支持多个子载波同时传输的终端,第二终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc1的终端,第三终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc2的终端;第一终端集合包括的终端为采用多个子载波传输上行数据的终端,第二终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc1的终端;第三终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc2的终端;第一终端集合包括的终端为采用多个子载波传输Msg3消息的终端,第二终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc1的终端,第三终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc2的终端;第一终端集合包括的终端为Msg3消息承载在多个子载波上传输的终端,第二终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc1的终端,第三终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc2的终端;上述第一终端集合包括的终端为Msg3消息中承载的信息量为Size1的终端,第二终端集合包括的终端为Msg3消息中承载的信息量为Size2的终端,第三终端集合包括的终端为Msg3消息中承载的信息量为Size3的终端,其中,Size1、Size2、Size3互不相等;When the number of terminal sets is 3, the three different terminal sets are the first terminal set, the second terminal set, and the third terminal set, and the first terminal set, the second terminal set, and the third terminal set satisfy at least the following conditions: The first terminal set includes terminals that support simultaneous transmission of multiple subcarriers, and the second terminal set includes terminals that support only a single subcarrier transmission and the subcarrier spacing is f sc1 , and the third terminal set includes terminals. A terminal that supports only a single subcarrier transmission and has a subcarrier spacing of f sc2 ; the terminal included in the first terminal set is a terminal that transmits uplink data by using multiple subcarriers, and the terminal included in the second terminal set transmits uplink data by using a single subcarrier. And the terminal with the subcarrier spacing is f sc1 ; the terminal included in the third terminal set is a terminal that uses one subcarrier to transmit uplink data and the subcarrier spacing is f sc2 ; the terminal included in the first terminal set is to transmit the Msg3 message by using multiple subcarriers. Terminal, the second terminal set includes terminals for transmitting Msg3 messages by using a single subcarrier and the subcarrier spacing is f The terminal of the sc1 , the terminal included in the third terminal set is a terminal that transmits the Msg3 message by using a single subcarrier and the subcarrier spacing is f sc2 ; the terminal included in the first terminal set is a terminal that the Msg3 message carries on the multiple subcarriers, The terminal included in the second terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc1 , and the terminal included in the third terminal set is that the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc2. The terminal included in the first terminal set is a terminal that has the information amount of the S1 in the Msg3 message, and the terminal in the second terminal set is a terminal that has the information amount of the S2 in the Msg3 message, and the third terminal set includes The terminal is a terminal that carries information in the Msg3 message with a size of Size3, where Size1, Size2, and Size3 are not equal to each other;
当终端集合的数量为4时,4个不同的终端集合为第一终端集合、第二终端集合、第三终端集合和第四终端集合,第一终端集合、第二终端集合、第三终端集合和第四终端集合满足以下条件至少之一:第一终端集合包括的终端为支持多个子载波同时传输且子载波间隔为fsc1的终端,第二终端集合包括的终端为支持多个子载波同时传输且子载波间隔为fsc2的终端,第
三终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc3的终端,第四终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc4的终端;第一终端集合包括的终端为采用多个子载波传输上行数据且子载波间隔为fsc1的终端,第二终端集合包括的终端为采用多个子载波传输上行数据且子载波间隔为fsc2的终端,第三终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc3的终端;第四终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc4的终端;第一终端集合包括的终端为采用多个子载波传输Msg3消息且子载波间隔为fsc1的终端,第二终端集合包括的终端为采用多个子载波传输Msg3消息且子载波间隔为fsc2的终端,第三终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc3的终端,第四终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc4的终端;第一终端集合包括的终端为Msg3消息承载在多个子载波上传输且子载波间隔为fsc1的终端,第二终端集合包括的终端为Msg3消息承载在多个子载波上传输且子载波间隔为fsc2的终端,第三终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc3的终端,第四终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc4的终端;上述第一终端集合包括的终端为Msg3消息中承载的信息量为Size1的终端,第二终端集合包括的终端为Msg3消息中承载的信息量为Size2的终端,第三终端集合包括的终端为Msg3消息中承载的信息量为Size3的终端,第四终端集合包括的终端为Msg3消息中承载的信息量为Size4的终端,其中,Size1、Size2、Size3、Size4互不相等。需要说明的是,上述的几种终端集合划分方式仅是几种示例,也可以采用其他的合理划分方式对终端集合进行划分。在上述实施例中,fsc1和fsc2取值不同,例如,fsc1可以取值为15kHz,fsc2可以取值为3.75kHz;上述的fsc3和fsc4取值不同,例如,fsc3可以取值为15kHz,fsc4可以取值为3.75kHz。When the number of terminal sets is 4, the four different terminal sets are a first terminal set, a second terminal set, a third terminal set, and a fourth terminal set, and the first terminal set, the second terminal set, and the third terminal set. And the fourth terminal set satisfies at least one of the following conditions: the terminal included in the first terminal set is a terminal that supports simultaneous transmission of multiple subcarriers and the subcarrier spacing is f sc1 , and the terminal included in the second terminal set supports simultaneous transmission of multiple subcarriers. And the terminal with the subcarrier spacing is f sc2 , the terminal included in the third terminal set is a terminal supporting only a single subcarrier transmission and the subcarrier spacing is f sc3 , and the terminal included in the fourth terminal set is only supporting a single subcarrier transmission and the sub The terminal with the carrier spacing is f sc4 ; the terminal included in the first terminal set is a terminal that uses multiple subcarriers to transmit uplink data and the subcarrier spacing is f sc1 , and the second terminal set includes terminals that use multiple subcarriers to transmit uplink data and carrier spacing for f sc2 set includes a terminal, a third terminal is a terminal using a single subcarrier, and the subcarrier for transmitting uplink data between F sc3 terminal; and a fourth set of terminals including a terminal for the use of a single subcarrier for transmitting uplink data and the subcarrier spacing f sc4 terminal; a first set of terminals including a terminal using a plurality of sub-carrier transmission and the subcarrier spacing message Msg3 For the terminal of the f sc1 , the terminal included in the second terminal set is a terminal that transmits the Msg3 message by using multiple subcarriers and the subcarrier spacing is f sc2 , and the terminal included in the third terminal set transmits the Msg3 message by using a single subcarrier and the subcarrier spacing For the terminal of the f sc3 , the terminal included in the fourth terminal set is a terminal that transmits the Msg3 message by using a single subcarrier and the subcarrier spacing is f sc4 ; the terminal included in the first terminal set is the Msg3 message bearer transmitted on multiple subcarriers and the sub The terminal with the carrier spacing is f sc1 , and the terminal included in the second terminal set is a terminal that transmits the Msg3 message on multiple subcarriers and the subcarrier spacing is f sc2 , and the terminal included in the third terminal set is that the Msg3 message is only carried in a single sub A terminal that transmits a carrier and has a subcarrier spacing of f sc3 , and the terminal included in the fourth terminal set is a Msg3 message that is only carried in a single subcarrier. A terminal that transmits a wave and has a subcarrier spacing of f sc4 ; the terminal included in the first terminal set is a terminal that carries information in the Msg3 message is Size1, and the terminal included in the second terminal set is that the amount of information carried in the Msg3 message is Size2 The terminal includes a terminal that is a terminal that has a quantity of information carried in the Msg3 message, and a terminal that is included in the fourth terminal set is a terminal that has an information amount of Size4 in the Msg3 message, where Size1, Size2, Size3 Size4 is not equal to each other. It should be noted that the foregoing several terminal set division manners are only a few examples, and other reasonable division manners may also be used to divide the terminal set. In the above embodiment, the values of f sc1 and f sc2 are different. For example, f sc1 can take a value of 15 kHz, and f sc2 can take a value of 3.75 kHz; the above f sc3 and f sc4 have different values, for example, f sc3 can be The value is 15 kHz, and f sc4 can be 3.75 kHz.
在一个可选的实施例中,上述的序列集合中的J条序列的类型可以是多种,下面对序列集合中的序列的类型进行说明:上述J条序列长度均为N的序列满足以下至少之一:J条序列长度均为N的序列为正交码字序列;J条序列长度均为N的序列为准正交码字序列;J条序列长度均为N的序列为预定义的序列。In an optional embodiment, the types of the J sequences in the sequence set may be multiple. The following describes the types of the sequences in the sequence set: the sequence of the J sequences whose lengths are all N meets the following At least one of the J sequences having a length of N is an orthogonal codeword sequence; the sequence of J sequences having a length of N is a quasi-orthogonal codeword sequence; and the sequence of J sequences having a length of N is predefined. sequence.
在一个可选的实施例中,上述满足以下至少之一:不同取值的j对应的Codej中互为正交码字,或互为准正交码字;不同取值的j对应的Codej中互为正交码字,或互为准正交码字;不同取值的j对应的Codej中互为正交码字,或互为准正交码字,其中,0≤i≤N/2-1。
In an alternative embodiment, the above Satisfy at least one of the following: J of different values corresponding to Code j Mutual orthogonal code words, or quasi-orthogonal code words; mutually different values of j corresponding to Code j Mutual orthogonal code words, or quasi-orthogonal code words; mutually different values of j corresponding to Code j They are orthogonal code words, or mutually quasi-orthogonal code words, where 0 ≤ i ≤ N / 2-1.
在一个可选的实施例中,上述N的取值可以为以下之一:2,4,6,8。In an optional embodiment, the value of N may be one of the following: 2, 4, 6, and 8.
下面对序列集合中的各序列进行举例说明:The following is an example of each sequence in a sequence set:
可选地,当J=1,且N=4时,J条序列长度为N的序列包括以下至少之一:
Optionally, when J=1, and N=4, the J sequence sequence length N includes at least one of the following:
当R=2,J=2,且N=4时,J条序列长度为N的序列包括以下至少之一:
其中,Code0和Code1中的一个被配置给第一终端集合中的终端,另一个被配置给第二终端集合中的终端;当R=2,J=2,且N=8时,J条序列长度为N的序列包括以下至少之一:
其中,Code0和Code1中的一个被配置给第一终端集合中的终端,另一个被配置给第二终端集合中的终端;When R=2, J=2, and N=4, the sequence of J sequence lengths of N includes at least one of the following: Wherein, one of Code 0 and Code 1 is configured to the terminal in the first terminal set, and the other is configured to the terminal in the second terminal set; when R=2, J=2, and N=8, J The sequence of strip length N includes at least one of the following: Wherein one of Code 0 and Code 1 is configured to the terminal in the first terminal set, and the other is configured to the terminal in the second terminal set;
当R=3,J=3,且N=4时,J条序列长度为N的序列包括以下至少之一:
中任意3个;
中任意3个;其中,3条序列长度为N的序列被分别配置给3个终端集合中的终端,即,3条序列长度为N的序列和3个终端集合可以进行任意一对一组合配置;When R=3, J=3, and N=4, the sequence of J sequences of length N includes at least one of the following: Any three of them; Any three of them; wherein three sequences of sequence length N are respectively allocated to terminals in three terminal sets, that is, three sequences of sequence length N and three terminal sets can be configured in any one-to-one combination ;
当R=4,J=4,且N=4时,J条序列长度为N的序列包括以下至少之一:
其中,4条序列长度为N的序列被分别配置给4个终端集合中的终端,即,4条序列长度为N的序列和4个终端集合可以进行任意一对一组合配置;其中,A为C为常数,
When R=4, J=4, and N=4, the sequence of J sequence lengths of N includes at least one of the following: The four sequences of length N are respectively allocated to the terminals in the four terminal sets, that is, four sequences of sequence length N and four terminal sets can be configured in any one-to-one combination; C is a constant,
在一个可选的实施例中,当与终端对应的序列为时,上述生成模块384可以通过如下方式生成随机接入信号:确定频域上索引为fn的子载波且时域上占用连续的K个符号发送第k个符号且子载波fn上发送的信号的频域表达式为上述K个符号且子载波fn上发送的信号的频域表达式为其中,0≤k≤K-1;至少根据确定随机接入信号。In an optional embodiment, when the sequence corresponding to the terminal is The generating module 384 may generate a random access signal by determining a subcarrier indexed as f n in the frequency domain and occupying consecutive K symbol transmissions in the time domain. The frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is The frequency domain expression of the above K symbols and the signal transmitted on the subcarrier f n is Where 0 ≤ k ≤ K-1; at least according to Determine the random access signal.
在一个可选的实施例中,上述生成模块384可以通过如下方式根据确定随机接入信号:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度,为索引为fn的子载波占用的频域资源,FOffset为频域偏移量;和/或,当时域采样间隔为Ts时,对应的时域的表达式为其中,0≤t≤Tk,Tk为第k个时域符号的长度,0≤k≤K-1,0≤q≤Q-1,为时域采样点数量;所述终端在连续的K个符号上发送的时域表达式为至少根据上述确定随机接入信号。In an optional embodiment, the generating module 384 may be configured as follows. Determine the random access signal: The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol, For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset; and/or, when the current domain sampling interval is T s , Corresponding time domain The expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol, 0 ≤ k ≤ K-1, 0 ≤ q ≤ Q-1, Number of samples in the time domain; the terminal is sent on consecutive K symbols The time domain expression is At least according to the above Determine the random access signal.
在一个可选的实施例中,上述生成模块384可以通过如下方式至少根据确定随机接入信号:按照下式生成循环前缀CPn,CPn={Sn[QK-L+1],...,Sn[QK]},L表示CPn中包括的时域采样间隔Ts的数量;则终端在子载波fn上发送的随机接入信号的表达式为Groupn={CPn,Sn},终端在子载波
f0,f1,...,fN-1上发送的随机接入信号的表达式为{Group0,Group1,...GroupN-1};其中,n取值不同的Groupn在时域上占用不同的符号。In an optional embodiment, the generating module 384 may be based on at least Determining the random access signal: generating a cyclic prefix CP n according to the following equation, CP n ={S n [QK-L+1],...,S n [QK]}, where L represents a time domain sample included in CP n The number of intervals T s ; then the expression of the random access signal transmitted by the terminal on the subcarrier f n is Group n = {CP n , S n }, and the terminal is in the subcarrier f 0 , f 1 , ..., f The expression of the random access signal transmitted on N-1 is {Group 0 , Group 1 , ... Group N-1 }; wherein Group n with different values of n occupy different symbols in the time domain.
在一个可选的实施例中,Group0~GroupN-1为组成上述随机接入信号的单元Unit,上述发送模块386可以通过如下方式发送随机接入信号给基站:确定一个Unit为随机接入信号,并将随机接入信号重复H次进行发送;和/或,将Unit在时域上重复H次形成随机接入信号,并发送上述随机接入信号。In an optional embodiment, Group 0 to Group N-1 are unit units constituting the random access signal, and the sending module 386 may send a random access signal to the base station by: determining that a unit is random access. Signaling, and repeating the random access signal for H times; and/or, repeating the unit H times in the time domain to form a random access signal, and transmitting the random access signal.
在一个可选的实施例中,上述终端在子载波fn上发送完成随机接入信号Groupn之后,需要引入时间长度为Gap的间隔,其中,在该时间长度为Gap的间隔内终端不再发送Groupn之后的随机接入信号,上述终端在时间长度为Gap的间隔之后继续发送Groupn之后的随机接入信号。In an optional embodiment, after the terminal sends the random access signal Group n on the sub-carrier f n , the interval of the time length Gap needs to be introduced, where the terminal is no longer in the interval of the Gap interval. The random access signal after the group n is sent, and the terminal continues to send the random access signal after the group n after the interval of the time length of the gap.
在一个可选的实施例中,当N=4,K=5,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,上述Gap的时域长度为0.4ms;和/或,当N=4,K=5,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,上述Gap的时域长度为0.6ms;和/或,当N=4,K=5,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns。In an optional embodiment, when N=4, K=5, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time of the Gap is The length of the domain is 0.4 ms; and/or, when N=4, K=5, the time domain length of CP n is 66.7 us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the above Gap The time domain length is 0.6 ms; and/or, when N=4, K=5, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth for transmitting the random access signal is 3.75 kHz, Gap The time domain length is 12288*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, the time domain length of CP n is 2048*Ts, the subcarrier spacing of the random access signal is transmitted or When the subcarrier bandwidth is 3.75 kHz, the time domain length of Gap is 18432*Ts, where Ts=32.55 ns.
在一个可选的实施例中,上述Unit的H次重复包括Y个Group(Y个Group即为Group0~GroupN-1、Group0~GroupN-1、Group0~GroupN-1……,一共重复了H次),可以定义Y个Group的索引为Group0~GroupY-1,其中,Y=H*N;当终端完成Groupstart到Groupend一共y个Group(y个Group的索引号可以是连续的)的随机接入信号的发送之后,需要引入时间长度为Gap的间隔,其中,在时间长度为Gap的间隔内终端不再发送随机接入信号,所述终端在所述时间长度为Gap的间隔之后继续发送Groupend之后的随机接入信号;其中,0≤start≤end≤Y-1,y≤Y。In an optional embodiment, the H repetitions of the above unit include Y groups (Y groups are Group 0 to Group N-1 , Group 0 to Group N-1 , Group 0 to Group N-1, ...) , a total of H times), you can define the index of Y groups as Group 0 ~ Group Y-1 , where Y = H * N; when the terminal completes Group start to Group end a total of y Group (y group index After the transmission of the random access signal, which may be continuous, it is necessary to introduce an interval of time Gap, wherein the terminal no longer transmits a random access signal in the interval of time Gap, and the terminal is at the time The random access signal after the group end is transmitted after the interval of the gap of Gap; wherein 0≤start≤end≤Y-1, y≤Y.
在一个可选的实施例中,start=offset+y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量;offset为第一个Groupstart的索引的偏置量;或者,start=y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量。
In an optional embodiment, start=offset+y×N gap , where N gap is the number of intervals in which the length of the introduction time is Gap; offset is the offset of the index of the first group start ; or, start = y × N gap , where N gap is the number of intervals in which the introduction time length is Gap.
在一个可选的实施例中,end=start+y-1。In an alternative embodiment, end = start + y-1.
在一个可选的实施例中,上述Gap满足以下条件至少之一:y×L_G+Gap=T×TimeUnit,其中,L_G为Group的时间长度,Gap≥0,T为正整数,TimeUnit为一种时间长度的度量单位;y×L_G+Gap=T×TimeUnit,其中L_G为Group的时间长度,Gap≥0,T为正整数且T为满足T×TimeUnit>y×L_G的最小值,TimeUnit为一种时间长度的度量单位。在本实施例中,TimeUnit可以是秒、毫秒、微秒、纳秒、帧(frame)、子帧(Subframe)、时隙(slot)。In an optional embodiment, the Gap satisfies at least one of the following conditions: y×L_G+Gap=T×TimeUnit, where L_G is the length of the group, Gap≥0, T is a positive integer, and TimeUnit is a type. The unit of measurement of the length of time; y × L_G + Gap = T × TimeUnit, where L_G is the length of the Group, Gap ≥ 0, T is a positive integer and T is the minimum value of T × TimeUnit > y × L_G, TimeUnit is a The unit of measure of the length of time. In this embodiment, the TimeUnit may be seconds, milliseconds, microseconds, nanoseconds, frames, subframes, slots.
在一个可选的实施例中,上述终端在发送完成一个Unit的随机接入信号之后,需要引入时间长度为Gap的间隔,其中,在该时间长度为Gap的间隔内终端不再发送Unit之后的随机接入信号,终端在上述时间长度为Gap的间隔之后继续发送Unit之后的随机接入信号。In an optional embodiment, after the terminal sends a random access signal of a unit, the terminal needs to introduce a time interval of Gap, where the terminal does not send the unit after the time interval is Gap. The random access signal, the terminal continues to send the random access signal after the unit after the interval of the time length of Gap.
在一个可选的实施例中,当N=4,K=5,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.6ms;和/或,当N=4,K=5,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.4ms;和/或,当N=4,K=5,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns。In an optional embodiment, when N=4, K=5, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain of Gap The length is 0.6ms; and/or, when N=4, K=5, the time domain length of CP n is 66.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time domain of Gap The length is 0.4ms; and/or, when N=4, K=5, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time of Gap The length of the field is 18432*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, the time domain length of CP n is 2048*Ts, and the subcarrier spacing or subcarrier of the random access signal is transmitted. When the bandwidth is 3.75 kHz, the time domain length of Gap is 12288*Ts, where Ts=32.55 ns.
在一个可选的实施例中,定义上述Unit的H次重复的索引为Unit0~UnitH-1,当终端完成Unitstart到Unitend一共y个Unit(y个Unit的索引号可以是连续的)的随机接入信号发送之后,需要引入时间长度为Gap的间隔,其中,在该时间长度为Gap的间隔内终端不再发送随机接入信号,终端在上述时间长度为Gap的间隔之后继续发送Unitend之后的随机接入信号;其中,0≤start≤end≤Y-1,y≤Y。In an optional embodiment, the index of the H repetitions of the above unit is defined as Unit 0 to Unit H-1 , and the terminal completes the unit start to the unit end by a total of y units (the index numbers of the y units may be consecutive) After the random access signal is sent, the interval of the time length Gap needs to be introduced, wherein the terminal does not send the random access signal during the time interval of the gap, and the terminal continues to send after the interval of the time length of Gap. Random access signal after unit end ; where 0≤start≤end≤Y-1, y≤Y.
在一个可选的实施例中,start=offset+y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量;offset为第一个Unitstart的索引的偏置量;或者,start=y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量。In an optional embodiment, start=offset+y×N gap , where N gap is the number of intervals in which the length of the introduction time is Gap; offset is the offset of the index of the first unit start ; or, start = y × N gap , where N gap is the number of intervals in which the introduction time length is Gap.
在一个可选的实施例中,end=start+y-1。In an alternative embodiment, end = start + y-1.
在一个可选的实施例中,上述Gap满足以下条件至少之一:y×L_U+Gap=T×TimeUnit,其中,L_G为Unit的时间长度,gap≥0,T为正整数,TimeUnit为一种时间长度的度量单位;y×L_U+Gap=T×TimeUnit,其中,L_G为Unit的时间长度,Gap≥0,T为正整数且T为满足T×TimeUnit>y×L_U的最小值,TimeUnit为一种时间长度的度量单位。在本实施例中,TimeUnit可以是秒、毫秒、微秒、纳秒、帧(frame)、子帧(Subframe)、时隙(slot)。In an optional embodiment, the Gap satisfies at least one of the following conditions: y×L_U+Gap=T×TimeUnit, where L_G is the length of time of the unit, gap≥0, T is a positive integer, and TimeUnit is a type. The unit of measurement of the length of time; y × L_U + Gap = T × TimeUnit, where L_G is the length of time of Unit, Gap ≥ 0, T is a positive integer and T is the minimum value of T × TimeUnit > y × L_U, TimeUnit is A measure of the length of time. In this embodiment, the TimeUnit may be seconds, milliseconds, microseconds, nanoseconds, frames, subframes, slots.
在一个可选的实施例中,当N=4,K=5,H=1,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=2,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为6144*Ts或36864*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=4,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=8,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为24576*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=16,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=1,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=2,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为24576*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=4,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=8,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为6144*Ts或36864*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=16,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;和/或,当N=4,K=5,H=1,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.6ms;和/或,当N=4,K=5,H=2,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.2ms或1.2ms;和/或,当N=4,K=5,H=4,CPn的时域长度为266.7us,发送随机接入信号的子载波
间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.4ms;和/或,当N=4,K=5,H=8,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.8ms;和/或,当N=4,K=5,H=16,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.6ms;和/或,当N=4,K=5,H=1,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.4ms;和/或,当N=4,K=5,H=2,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.8ms;和/或,当N=4,K=5,H=4,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.6ms;和/或,当N=4,K=5,H=8,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.2ms或1.2ms;和/或,当N=4,K=5,H=16,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.4ms。In an optional embodiment, when N=4, K=5, H=1, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth for transmitting the random access signal is 3.75 kHz. The time domain length of Gap is 18432*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, H=2, the time domain length of CP n is 8192*Ts, and random access is sent. When the subcarrier spacing or subcarrier bandwidth of the signal is 3.75 kHz, the time domain length of Gap is 6144*Ts or 36864*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, H= 4. The time domain length of CP n is 8192*Ts. When the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 12288*Ts, where Ts=32.55 ns; and / Or, when N=4, K=5, H=8, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 24576*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, H=16, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or sub-send of the random access signal is transmitted. When the carrier bandwidth is 3.75kHz, the time domain of Gap is long. To 18432 * Ts, where, Ts = 32.55ns; and / or, if N = 4, K = 5, H = 1, the length of the time domain CP n is 2048 * Ts, transmitting a random access signal or subcarrier spacing When the subcarrier bandwidth is 3.75 kHz, the time domain length of Gap is 12288*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, H=2, the time domain length of CP n is 2048. *Ts, when the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 24576*Ts, where Ts=32.55 ns; and/or, when N=4, K=5 , H=4, the time domain length of CP n is 2048*Ts. When the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 18432*Ts, where Ts=32.55 ns. And/or, when N=4, K=5, H=8, the time domain length of CP n is 2048*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, Gap time The length of the field is 6144*Ts or 36864*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, H=16, the time domain length of CP n is 2048*Ts, and random access is sent. When the subcarrier spacing or subcarrier bandwidth of the signal is 3.75 kHz, G The time domain length of ap is 12288*Ts, where Ts=32.55 ns; and/or, when N=4, K=5, H=1, the time domain length of CP n is 266.7us, and the random access signal is transmitted. When the subcarrier spacing or subcarrier bandwidth is 3.75 kHz, the time domain length of Gap is 0.6 ms; and/or, when N=4, K=5, H=2, the time domain length of CP n is 266.7us, and the transmission is random. When the subcarrier spacing or subcarrier bandwidth of the access signal is 3.75 kHz, the time domain length of Gap is 0.2 ms or 1.2 ms; and/or, when N=4, K=5, H=4, the time domain of CP n The length is 266.7us. When the subcarrier spacing or subcarrier bandwidth for transmitting the random access signal is 3.75kHz, the time domain length of Gap is 0.4ms; and/or, when N=4, K=5, H=8, CP The time domain length of n is 266.7us, and the time domain length of Gap is 0.8ms when the subcarrier spacing or subcarrier bandwidth for transmitting random access signals is 3.75kHz; and/or, when N=4, K=5, H =16, the time domain length of CP n is 266.7us, and the time domain length of Gap is 0.6ms when the subcarrier spacing or subcarrier bandwidth for transmitting random access signals is 3.75kHz; and/or, when N=4, K =5, H=1, the time domain length of CP n is 66.7us When the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 0.4 ms; and/or, when N=4, K=5, H=2, the time domain of CP n The length is 66.7us. When the subcarrier spacing or subcarrier bandwidth for transmitting the random access signal is 3.75kHz, the time domain length of Gap is 0.8ms; and/or, when N=4, K=5, H=4, CP The time domain length of n is 66.7us, and when the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 0.6 ms; and/or, when N=4, K=5, H =8, the time domain length of CP n is 66.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time domain length of Gap is 0.2ms or 1.2ms; and/or when N= 4, K=5, H=16, the time domain length of CP n is 66.7us, and the sub-carrier spacing or sub-carrier bandwidth of the random access signal is 3.75 kHz, and the time domain length of Gap is 0.4 ms.
在一个可选的实施例中,上述H的取值至少根据终端的等级确定,即,不同等级的终端对应的H可以是不同的。In an optional embodiment, the value of the above H is determined according to at least the level of the terminal, that is, the H corresponding to the terminals of different levels may be different.
在一个可选的实施例中,上述终端的等级可以包括以下至少之一:覆盖增强等级;物理信道重复发送等级;物理信道上承载的消息或信令的重复发送等级。In an optional embodiment, the level of the foregoing terminal may include at least one of the following: an coverage enhancement level; a physical channel repetition transmission level; and a repeated transmission level of a message or signaling carried on the physical channel.
在一个可选的实施例中,上述发送模块386可以通过如下方式发送随机接入信号给基站:确定用于发送上述随机接入信号的随机接入信道;通过随机接入信道向基站发送随机接入信号。在本实施例中,终端用于进行随机接入信号发送的随机接入信道可以是随机接入信道资源中的一部分,该随机接入信道资源可以包括多个用于不同的终端进行随机接入信号发送的随机接入信道。In an optional embodiment, the sending module 386 may send a random access signal to the base station by: determining a random access channel for transmitting the random access signal; and sending a random connection to the base station by using a random access channel. Into the signal. In this embodiment, the random access channel used by the terminal to perform random access signal transmission may be part of a random access channel resource, and the random access channel resource may include multiple random accesses for different terminals. A random access channel for signal transmission.
在一个可选的实施例中,上述随机接入信道资源包括一个或多个时频资源集合Setm,其中,该Setm在频域上包括F个子载波或子信道,在时域上长度至少为P个Unit的长度,m为Setm在时域的索引,F为正整数,P为正整数。在本实施例中,上述的随机接入信道资源可以包括多个终端发送随机接入信号的随机接入信道,并且,上述的一个Setm可以由一个终端使用,也可以由多个终端使用,或者多个Setm由一个终端使用。In an optional embodiment, the random access channel resource includes one or more time-frequency resource sets Set m , where the set m includes F sub-carriers or sub-channels in the frequency domain, and the length is at least in the time domain. For the length of P units, m is the index of Set m in the time domain, F is a positive integer, and P is a positive integer. In this embodiment, the random access channel resource may include a random access channel in which multiple terminals send random access signals, and the foregoing set m may be used by one terminal or may be used by multiple terminals. Or multiple Set m are used by one terminal.
在一个可选的实施例中,上述Setm包括P个子集subset,其中,该subset在频域上与Setm配置相同的子载波,subset在时域上长度为1个Unit的长度。In an optional embodiment, the Set m includes P subset subsets, wherein the subset is configured with the same subcarriers in the frequency domain as the Set m , and the subset has a length of 1 Unit in the time domain.
在一个可选的实施例中,在上述Setm占用的频率资源的前后各配置有保护带宽,和/或,
在Setm占用的频率资源的上下各配置有保护带宽。下面对Setm占用的频率资源配置的保护带宽进行说明:In an optional embodiment, the protection bandwidth is configured before and after the frequency resource occupied by the Set m , and/or the protection bandwidth is configured on the upper and lower sides of the frequency resource occupied by the Set m . The following describes the protection bandwidth of the frequency resource configuration occupied by Set m :
当子载波间隔为3.75kHz,F=12时,在Setm占用的频率资源的前后频率资源上各配置有7.5kHz保护带宽;和/或,当子载波间隔为3.75kHz,F=16时,在Setm占用的频率资源中上下边带各预留有7.5kHz保护带宽。When the subcarrier spacing is 3.75 kHz, F=12, the 7.5 kHz protection bandwidth is configured on the frequency resources before and after the frequency resource occupied by Set m ; and/or, when the subcarrier spacing is 3.75 kHz, F=16, In the frequency resource occupied by Set m , the upper and lower sidebands each have a reserved bandwidth of 7.5 kHz.
在一个可选的实施例中,当上行带宽包括48个子载波,且F=12时,上行带宽最多配置4个Setm,且每个Setm在频域上包括F=12个子载波或子信道,不同Setm在频域上包括的子载波或子信道不重叠。In an optional embodiment, when the uplink bandwidth includes 48 subcarriers, and F=12, the uplink bandwidth is configured with a maximum of 4 Set m , and each Set m includes F=12 subcarriers or subchannels in the frequency domain. The subcarriers or subchannels included in the frequency domain of different Set m do not overlap.
可选地,可以通过U个比特信息指示为同一个等级的终端或终端组分配的Setm的频域位置,其中,不同等级的终端配置的Setm的频域位置相同,U=2或4。Alternatively, the U bit information indicating a frequency domain location of the terminal or group of terminals assigned the same level Set m, wherein the different levels of the same terminal configuration of the frequency domain position Set m, U = 2 or 4 .
在一个可选的实施例中,当上行带宽包括48个子载波,且F=16时,上行带宽最多配置3个Setm,且每个Setm在频域上包括F=16个子载波或子信道,不同Setm在频域上包括的子载波或子信道不重叠。In an optional embodiment, when the uplink bandwidth includes 48 subcarriers, and F=16, the uplink bandwidth is configured with a maximum of 3 Set m , and each Set m includes F=16 subcarriers or subchannels in the frequency domain. The subcarriers or subchannels included in the frequency domain of different Set m do not overlap.
可选地,可以通过U个比特信息指示为同一个等级的终端或终端组分配的Setm的频域位置,其中,不同等级的终端配置的Setm的频域位置相同,U=2或3。Optionally, the frequency domain locations of the Set m allocated to the terminal or the terminal group of the same level may be indicated by the U bit information, where the frequency domain locations of the Set m configured by the different levels are the same, U=2 or 3 .
在一个可选的实施例中,上述方法可以包括如下至少之一:当N=4,K=5时,所述Setm在时域上长度为7ms,所述CPn的时域长度为266.7us,P=1;当N=4,K=5时,所述Setm在时域上长度为13ms,所述CPn的时域长度为266.7us,P=2;当N=8,K=5时,所述Setm在时域上长度为13ms,所述CPn的时域长度为266.7us,P=1;当N=4,K=5时,所述Setm在时域上长度为26ms,所述CPn的时域长度为266.7us,P=4;当N=8,K=5时,所述Setm在时域上长度为26ms,所述CPn的时域长度为266.7us,P=2;当N=4,K=5时,所述Setm在时域上长度为32ms,所述CPn的时域长度为266.7us,P=5;当N=4,K=5时,所述Setm在时域上长度为64ms,所述CPn的时域长度为266.7us,P=10;当N=8,K=5时,所述Setm在时域上长度为64ms,所述CPn的时域长度为266.7us,P=5;当N=4,K=5时,所述Setm在时域上长度为6ms,所述CPn的时域长度为66.7us,P=1;当N=4,K=5时,所述Setm在时域上长度为12ms,所述CPn的时域长度为66.7us,P=2;当N=8,K=5时,所述Setm在时域上长度为12ms,所述CPn
的时域长度为66.7us,P=1;当N=4,K=5时,所述Setm在时域上长度为17ms,所述CPn的时域长度为66.7us,P=3;当N=4,K=5时,所述Setm在时域上长度为23ms,所述CPn的时域长度为66.7us,P=4;当N=8,K=5时,所述Setm在时域上长度为23ms,所述CPn的时域长度为66.7us,P=2;当N=4,K=5时,所述Setm在时域上长度为28ms,所述CPn的时域长度为66.7us,P=5;当N=4,K=5时,所述Setm在时域上长度为34ms,所述CPn的时域长度为66.7us,P=6;当N=8,K=5时,所述Setm在时域上长度为34ms,所述CPn的时域长度为66.7us,P=3。In an optional embodiment, the foregoing method may include at least one of the following: when N=4, K=5, the set m is 7 ms in the time domain, and the time domain length of the CP n is 266.7. Us, P=1; when N=4, K=5, the set m is 13ms in the time domain, the time domain length of the CP n is 266.7us, P=2; when N=8, K When set to 5, the set m has a length of 13 ms in the time domain, the time domain length of the CP n is 266.7 us, P=1; when N=4, K=5, the set m is in the time domain. The length of the CP n is 266.7us, P=4; when N=8, K=5, the length of the Set m is 26ms in the time domain, and the time domain length of the CP n 266.7us, P=2; when N=4, K=5, the set m has a length of 32ms in the time domain, the time domain length of the CP n is 266.7us, P=5; when N=4 When K=5, the set m has a length of 64 ms in the time domain, the time domain length of the CP n is 266.7 us, P=10; when N=8, K=5, the set m is at the time The length of the domain is 64 ms, the length of the time domain of the CP n is 266.7us, P=5; when N=4, K=5, the length of the Set m is 6 ms in the time domain, The time domain length of CP n is 66.7us, P=1; when N=4, K=5, the length of the Set m in the time domain is 12ms, and the time domain length of the CP n is 66.7us, P= 2; when N=8, K=5, the set m has a length of 12 ms in the time domain, the time domain length of the CP n is 66.7 us, P=1; when N=4, K=5, The set m has a length of 17 ms in the time domain, the time domain length of the CP n is 66.7 us, P=3; when N=4, K=5, the set m has a length of 23 ms in the time domain. The time domain length of the CP n is 66.7us, P=4; when N=8, K=5, the set m is 23ms in the time domain, and the time domain length of the CP n is 66.7us. P=2; when N=4, K=5, the set m has a length of 28 ms in the time domain, the time domain length of the CP n is 66.7 us, P=5; when N=4, K=5 The set m has a length of 34 ms in the time domain, the time domain length of the CP n is 66.7 us, P=6; when N=8, K=5, the length of the Set m in the time domain is 34ms, the time domain length of the CP n is 66.7us, P=3.
其中,在上述实施例中,当N=4,K=5时,Setm在时域上长度为7ms时,上述随机接入信道资源包括0.6ms的保护时间;当N=4,K=5时,Setm在时域上长度为26ms时,上述随机接入信道资源包括0.4ms的保护时间;当N=8,K=5时,Setm在时域上长度为26ms时,上述随机接入信道资源包括0.4ms的保护时间;当N=4,K=5时,Setm在时域上长度为6ms时,上述随机接入信道资源包括0.4ms的保护时间;当N=4,K=5时,Setm在时域上长度为12ms时,上述随机接入信道资源包括0.8ms的保护时间;当N=8,K=5时,Setm在时域上长度为12ms时,上述随机接入信道资源包括0.8ms的保护时间;当N=4,K=5时,Setm在时域上长度为17ms时,上述随机接入信道资源包括0.2ms的保护时间;当N=4,K=5时,Setm在时域上长度为23ms时,上述随机接入信道资源包括0.6ms的保护时间;当N=8,K=5时,Setm在时域上长度为23ms时,上述随机接入信道资源包括0.6ms的保护时间;当N=4,K=5时,Setm在时域上长度为34ms时,上述随机接入信道资源包括0.4ms的保护时间;当N=8,K=5时,Setm在时域上长度为34ms时,上述随机接入信道资源包括0.4ms的保护时间。In the foregoing embodiment, when N=4, K=5, when Set m is 7 ms in the time domain, the random access channel resource includes a guard time of 0.6 ms; when N=4, K=5 When Set m has a length of 26 ms in the time domain, the random access channel resource includes a guard time of 0.4 ms; when N=8, K=5, when Set m is 26 ms in the time domain, the random connection is performed. The inbound channel resource includes a guard time of 0.4 ms; when N=4, K=5, when the set m is 6 ms in the time domain, the random access channel resource includes a guard time of 0.4 ms; when N=4, K =5, when Set m is 12 ms in the time domain, the random access channel resource includes a guard time of 0.8 ms; when N=8, K=5, when Set m is 12 ms in the time domain, the above The random access channel resource includes a guard time of 0.8 ms; when N=4, K=5, when the set m is 17 ms in the time domain, the random access channel resource includes a guard time of 0.2 ms; when N=4 When K=5, when the length of Set m is 23 ms in the time domain, the random access channel resource includes a guard time of 0.6 ms; when N=8, K=5, Set m is in time. When the length of the domain is 23 ms, the random access channel resource includes a guard time of 0.6 ms; when N=4, K=5, when the set m is 34 ms in the time domain, the random access channel resource includes 0.4 ms. The guard time; when N=8, K=5, when the set m is 34 ms in the time domain, the random access channel resource includes a guard time of 0.4 ms.
在一个可选的实施例中,时域相邻的两个Setm之间间隔V个第一时间单位,其中,V为整数,所述第一时间单位包括以下至少之一:一个或多个帧的时域长度、一个或多个子帧的时域长度、Z1秒、Z2毫秒、Z3个Setm的时域长度,Z4个Unit的时域长度,Z5个subset的时域长度,其中,Z1、Z2、Z3、Z4、Z5均为正整数。In an alternative embodiment, a first time interval of a V-domain unit time between two adjacent Set m, wherein, V is an integer, the first unit of time comprises at least one of the following: one or more The time domain length of the frame, the time domain length of one or more subframes, Z 1 second, Z 2 milliseconds, the time domain length of Z 3 Set m , the time domain length of Z 4 Units, and the time domain of Z 5 subsets The length, wherein Z 1 , Z 2 , Z 3 , Z 4 , and Z 5 are all positive integers.
在上述实施例中,可以包括如下至少之一:V的取值包括以下至少之一:V=0;V=2y,其中,y为大于或等于0的整数;V个第一时间单位在时域上连续分布或离散分布;时域相邻的两个Setm在频域上占用相同的所述F个子载波或子信道。
In the above embodiment, at least one of the following may be included: the value of V includes at least one of the following: V=0; V=2 y , where y is an integer greater than or equal to 0; V first time units are The time domain is continuously distributed or discretely distributed; two Set m adjacent in the time domain occupy the same F subcarriers or subchannels in the frequency domain.
在一个可选的实施例中,Setm的配置周期为L个第一时间单位,其中,L为正整数,所述第一时间单位包括以下至少之一:一个或多个帧的时域长度、一个或多个子帧的时域长度、Z1秒、Z2毫秒、Z3个Setm的时域长度,Z4个Unit的时域长度,Z5个subset的时域长度,其中,Z1、Z2、Z3、Z4、Z5均为正整数。In an optional embodiment, the configuration period of the Set m is L first time units, where L is a positive integer, and the first time unit includes at least one of: a time domain length of one or more frames Time domain length of one or more subframes, Z 1 second, Z 2 milliseconds, time domain length of Z 3 Set m , time domain length of Z 4 Units, time domain length of Z 5 subsets, where Z 1 , Z 2 , Z 3 , Z 4 , and Z 5 are all positive integers.
在一个可选的实施例中,L=2z,其中,z为大于或等于0的整数。In an alternative embodiment, L = 2 z , where z is an integer greater than or equal to zero.
在上述实施例中,2z个第一时间单位在时域上连续分布或离散分布;z取值为{0,1,2,3,4,5,6,7};时域相邻的两个Setm在频域上占用相同的所述F个子载波或子信道。In the above embodiment, 2 z first time units are continuously distributed or discretely distributed in the time domain; z is taken as {0, 1, 2, 3, 4, 5, 6, 7}; time domain adjacent Two Set m occupy the same F subcarriers or subchannels in the frequency domain.
在一个可选的实施例中,在上述Setm的配置周期内最多配置L1个subset,该subset的索引为subset 0至subset(L1-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将Unit在时域上重复Repetitiong次发送,在一个Setm的配置周期内,为等级索引为g的终端配置连续的Repetitiong个subset,且起始subset索引StartingSubsetIndexg按照下面公式计算:其中,0≤g≤G-1,G为划分的终端的等级的数量。In an optional embodiment, at most L 1 subsets are configured in the configuration period of the Set m , and the index of the subset is subset 0 to subset (L 1 -1), wherein the terminal with the level index g corresponds to The subset configuration scheme includes: the terminal with the level index g transmits the Repetition g times in the time domain, and configures consecutive Repetition g subsets for the terminal with the level index g in the configuration period of a Set m , and starts The subset index StartingSubsetIndex g is calculated according to the following formula: Where 0 ≤ g ≤ G-1, and G is the number of levels of the divided terminals.
在一个可选的实施例中,不同的Setm的配置周期之间,等级索引为g的终端对应的subset配置方案是相同的。In an optional embodiment, the configuration of the subset corresponding to the terminal with the level index g is the same between the configuration periods of different Set m .
在一个可选的实施例中,在上述Setm的配置周期内最多配置L1个subset,subset的索引为subset 0至subset(L1-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将Unit在时域上重复Repetitiong次发送,且为等级索引为g的终端配置连续的ChanceNumg×Repetitiong个subset,其中ChanceNumg≥1。In an optional embodiment, at most L 1 subsets are configured in the configuration period of the Set m , and the index of the subset is subset 0 to subset (L 1 -1), wherein the subset corresponding to the terminal with the level index g is The configuration scheme includes: the terminal with the level index g sends the Unit repeating Repetition g times in the time domain, and configures the consecutive ChanceNum g ×Repetition g subsets for the terminal with the level index g, where ChanceNum g ≥1.
在一个可选的实施例中,在一个Setm的配置周期内,ChanceNumg×Repetitiong个subset中起始subset索引StartingSubsetIndexg可以按照下面公式计算:其中,0≤g≤G-1,G为划分的终端的等级的数量。可选地,上述G可以是基站配置的终端的等级的数量,也可以是在
Setm资源上发送随机接入信号的终端的等级的数量。In an optional embodiment, in a configuration period of Set m , the starting subset index StartingSubsetIndex g in ChanceNum g ×Repetition g subsets can be calculated according to the following formula: Where 0 ≤ g ≤ G-1, and G is the number of levels of the divided terminals. Optionally, the foregoing G may be the number of levels of the terminal configured by the base station, or may be the number of levels of the terminal that sends the random access signal on the Set m resource.
在一个可选的实施例中,起始subset索引为StartingSubsetIndexg的ChanceNumg×Repetitiong个subset中,配置有ChanceNumg个第一发送资源,其中,该第一发送资源用于Unit在时域上重复Repetitiong次发送,即,Unit在时域上重复Repetitiong次发送可以在第一资源上执行。In an optional embodiment, the starting subset index is ChanceNum g ×Repetition g subsets of StartingSubsetIndex g , and is configured with ChanceNum g first sending resources, where the first sending resource is used for Unit in the time domain. Repeat Repetition g times, that is, Unit repeats Repetition g times in the time domain and can be executed on the first resource.
在一个可选的实施例中,上述ChanceNumg个第一发送资源中的第c个第一发送资源的起始subset索引可以按照下面公式计算:
In an alternative embodiment, the above-described ChanceNum g of first transmission resources in the c-th starting index of the first subset of transmission resources It can be calculated according to the following formula:
在一个可选的实施例中,在上述Setm的配置周期内最多配置L1个subset,该subset的索引为subset 0至subset(L1-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将Unit在时域上重复Repetitiong次发送,且等级索引为g的终端配置有ChanceNumg×Repetitiong个subset,ChanceNumg≥1。In an optional embodiment, at most L 1 subsets are configured in the configuration period of the Set m , and the index of the subset is subset 0 to subset (L 1 -1), wherein the terminal with the level index g corresponds to The subset configuration scheme includes: the terminal with the level index g sends the Unit repeating Repetition g times in the time domain, and the terminal with the level index g is configured with ChanceNum g ×Repetition g subsets, and ChanceNum g ≥1.
在一个可选的实施例中,在一个Setm的配置周期内,ChanceNumg×Repetitiong个subset的索引为subset 0至subset(ChanceNumg×Repetitiong-1),且从subset 0开始,索引连续的Repetitiong个subset为一个第一发送资源,其中,该第一发送资源用于Unit在时域上重复Repetitiong次发送,一个第一发送资源内的Repetitiong个subset在时域上连续分布,不同的第一发送资源对应的subset在时域上离散分布。In an alternative embodiment, in a configuration cycle of Set m, ChanceNum g × Repetition g subset is a subset of the indices 0 to subset (ChanceNum g × Repetition g -1 ), and starts from the subset 0, continuous index The Repetition g subset is a first transmission resource, wherein the first transmission resource is used for the Unit to repeat the Repetition g transmission in the time domain, and the Repetition g subsets in the first transmission resource are continuously distributed in the time domain. The subsets corresponding to different first transmission resources are discretely distributed in the time domain.
在一个可选的实施例中,在上述Setm的配置周期内包括G个等级的终端对应的第一发送资源,其中,等级索引为g的终端对应的第一发送资源用于Unit在时域上重复Repetitiong次发送,等级索引为g的终端对应的所述第一发送资源大小为Ng个
为级索引为g的终端对应的Setm,0≤g≤G-1。In an optional embodiment, the first sending resource corresponding to the terminals of the G levels is included in the configuration period of the Set m , wherein the first sending resource corresponding to the terminal with the level index g is used for the Unit in the time domain. Repeating the Repetition g times, the first sending resource corresponding to the terminal with the level index g is N g Set m corresponding to the terminal whose index is g, 0 ≤ g ≤ G-1.
在一个可选的实施例中,在上述Setm的配置周期内,终端按照等级索引g由小到大的顺序依次分配有Ng个资源。In an optional embodiment, during the configuration period of the Set m , the terminal sequentially allocates N g according to the rank index g from small to large. Resources.
在一个可选的实施例中,Ng≥1或Ng≥0,且当Ng=0时,表示在Setm的配置周期内
没有配置等级索引为g的终端对应的第一发送资源。In an optional embodiment, N g ≥ 1 or N g ≥ 0, and when N g =0, it indicates that the first transmission resource corresponding to the terminal with the level index g is not configured in the configuration period of Set m .
在一个可选的实施例中,在Setm的配置周期内,为等级索引为g的终端配置的Ng个资源中相邻的两个之间时域间隔为Lg个第二时间单位,其中,Lg≥0。In an optional embodiment, N g configured for the terminal with the level index g in the configuration period of Set m Two adjacent in the resource The time domain interval is L g second time units, where L g ≥ 0.
在一个可选的实施例中,不同等级索引的终端对应的Lg相同。In an alternative embodiment, the same index different levels corresponding to the terminal L g.
在一个可选的实施例中,在上述Setm的配置周期内,不同等级索引的终端对应的Ng个资源之间,间隔Lβ个第二时间单位,其中,Lβ≥0。其中,不同等级索引的终端对应的Ng个资源之间间隔Lβ个第二时间单位是指一个等级的终端对应的资源与另一个等级的终端对应的资源之间间隔Lβ个第二时间单位。In an optional embodiment, in the configuration period of the Set m , the N g corresponding to the terminals of different levels of indexing Between resources, the interval L β is a second time unit, where L β ≥ 0. Wherein, N g of terminals corresponding to different levels of indexing The interval between resources L β second time units refers to the corresponding level of a terminal The resource corresponds to another level of terminal The interval between resources is L β second time units.
在一个可选的实施例中,在Setm的配置周期内,不同等级索引的终端对应的Ng个资源之间,间隔Lg个第二时间单位。In an optional embodiment, in the configuration period of Set m , N g of terminals corresponding to different levels of indexing Between resources, the interval L g is a second time unit.
在一个可选的实施例中,上述的第一时间单位和第二时间单位可以相同也可以不同。In an optional embodiment, the first time unit and the second time unit may be the same or different.
在一个可选的实施例中,等级索引为g的终端对应的Ng个资源中第一个的时域起始资源位置与所述的配置周期内时域起始资源位置相同;或者,等级索引为g的终端对应的Ng个资源中第一个的时域起始资源位置与所述的配置周期内时域起始资源位置存在偏移量,其中,所述偏移量为预定的或者为基站配置的。In an optional embodiment, the N g corresponding to the terminal whose rank index is g The first in the resource Time domain starting resource location with the stated The time domain starting resource location is the same in the configuration period; or the N g corresponding to the terminal with the level index g The first in the resource Time domain starting resource location with the stated There is an offset in the time domain starting resource location within the configuration period, wherein the offset is predetermined or configured for the base station.
在一个可选的实施例中,不同等级索引的终端对应的相同。In an optional embodiment, terminals of different levels of index correspond to the same.
在一个可选的实施例中,上述Setm的配置周期长度为D个Setm的时域长度,其中,D为正整数。The length of the time domain In an alternative embodiment, the length of the arrangement period of the D Set m Set m, wherein, D is a positive integer.
在一个可选的实施例中,D=2x,x为大于或等于0的整数。In an alternative embodiment, D = 2 x and x is an integer greater than or equal to zero.
在一个可选的实施例中,在上述Setm的配置周期内最多配置D*P个subset,subset的索引为subset 0至subset(D*P-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将Unit在时域上重复Repetitiong次发送,在一个Setm的配置周期内,为等级索引为g的终端配置连续的Repetitiong个subset,且起始subset索引StartingSubsetIndexg按照下面公式计算:
In an optional embodiment, a maximum of D*P subsets are configured in the configuration period of the Set m , and an index of the subset is a subset 0 to a subset (D*P-1), where the terminal with a level index of g corresponds to The subset configuration scheme includes: the terminal with the level index g is configured to repeat the Repetition g times in the time domain, and configure a continuous Repetition g subset for the terminal with the level index g in a configuration period of the set m , and The starting subset index StartingSubsetIndex g is calculated according to the following formula:
其中,0≤g≤G-1,G为划分的终端的等级的数量。Where 0 ≤ g ≤ G-1, and G is the number of levels of the divided terminals.
在一个可选的实施例中,不同的Setm的配置周期之间,等级索引为g的终端对应的subset配置方案是相同的。In an optional embodiment, the configuration of the subset corresponding to the terminal with the level index g is the same between the configuration periods of different Set m .
在一个可选的实施例中,当上行带宽包括48个子载波间隔为3.75kHz的子载波时,该子载波索引为0~47,其中,索引为0,1,14,15,16,17,30,31,32,33,46,47的子载波不配置给Setm。In an optional embodiment, when the uplink bandwidth includes 48 subcarriers with a subcarrier spacing of 3.75 kHz, the subcarrier index is 0 to 47, where the index is 0, 1, 14, 15, 16, 17, The subcarriers of 30, 31, 32, 33, 46, 47 are not configured for Set m .
在一个可选的实施例中,当上行带宽包括48个子载波,该子载波索引为0~47,F=24,且所述Setm的起始子载波索引为2时,索引为2~25的子载波配置给所述Setm。其中,“~”的意思是“至”的意思,例如,索引为2~25的子载波为索引从2至25的24个子载波,下述的实施例中均是类似的,不再赘述。In an optional embodiment, when the uplink bandwidth includes 48 subcarriers, the subcarrier index is 0 to 47, F=24, and the initial subcarrier index of the Set m is 2, the index is 2-25. The subcarriers are configured for the Set m . The meaning of "to" means "to". For example, the subcarriers with an index of 2 to 25 are 24 subcarriers whose indices are from 2 to 25. The following embodiments are similar and will not be described again.
在一个可选的实施例中,当上行带宽包括48个子载波,该子载波索引为0~47,F=36,且所述Setm的起始子载波索引为2时,索引为2~37的子载波配置给所述Setm。In an optional embodiment, when the uplink bandwidth includes 48 subcarriers, the subcarrier index is 0 to 47, F=36, and the initial subcarrier index of the Set m is 2, the index is 2 to 37. The subcarriers are configured for the Set m .
在一个可选的实施例中,当上行带宽包括48个子载波,该子载波索引为0~47,F=24,且Setm的起始子载波索引为18时,索引为18~41的子载波配置给所述Setm。In an optional embodiment, when the uplink bandwidth includes 48 subcarriers, the subcarrier index is 0 to 47, F=24, and the initial subcarrier index of Set m is 18, the index is 18 to 41. The carrier is configured to the Set m .
在一个可选的实施例中,上述Setm中的F个子载波中,随机接入信道占用的子载波数量Num在F个子载波中的比例为Ratio,其中,该Ratio由基站通过信令发送给所述终端。In an optional embodiment, among the F subcarriers in the Set m , the ratio of the number of subcarriers Num occupied by the random access channel in the F subcarriers is Ratio, wherein the Ratio is sent by the base station to the signaling. The terminal.
在一个可选的实施例中,上述F的取值为{12,24,36,48}。In an alternative embodiment, the value of F above is {12, 24, 36, 48}.
在一个可选的实施例中,上述Ratio的取值为{1/6,2/6,3/6,4/6,5/6,6/6}或{1/12,2/12,3/12,4/12,5/12,6/12,7/12,8/12,9/12,10/12,11/12,12/12}或{0/12,1/12,2/12,3/12,4/12,5/12,6/12,7/12,8/12,9/12,10/12,11/12,12/12}或{0/6,1/6,2/6,3/6,4/6,5/6,6/6}。In an optional embodiment, the value of the Ratio is {1/6, 2/6, 3/6, 4/6, 5/6, 6/6} or {1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12, 9/12, 10/12, 11/12, 12/12} or {0/12, 1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12, 9/12, 10/12, 11/12, 12/12} or {0/6, 1/6, 2/6, 3/6, 4/6, 5/6, 6/6}.
在一个可选的实施例中,上述Setm中的F个子载波中,用于发送随机接入信号的随机接入信道占用的子载波数量为Num。In an optional embodiment, among the F subcarriers in the Set m , the number of subcarriers occupied by the random access channel for transmitting the random access signal is Num.
在一个可选的实施例中,上述F的取值为{12,24,36,48}。In an alternative embodiment, the value of F above is {12, 24, 36, 48}.
在一个可选的实施例中,上述Num取值为{4,8,12,16,20,24,28,32,36,40,44,48}或{3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48}或{0,4,8,12,16,20,24,28,32,36,40,44,48}或
{0,3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48}。In an optional embodiment, the value of Num is {4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48} or {3, 6, 9, 12, 15 ,18,21,24,27,30,33,36,39,42,45,48} or {0,4,8,12,16,20,24,28,32,36,40,44,48 } or
{0,3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48}.
在一个可选的实施例中,上述终端向基站发送随机接入信号的所述随机接入信道由所述基站通过信令分配给所述终端。在本实施例中,信令可以包括以下至少之一:针对单个终端的信令、针对单个处于连接状态的终端的信令、承载在控制信道上发送的信令。In an optional embodiment, the random access channel that the terminal sends a random access signal to the base station is allocated by the base station to the terminal by using signaling. In this embodiment, the signaling may include at least one of: signaling for a single terminal, signaling for a single terminal in a connected state, and signaling transmitted on a control channel.
在一个可选的实施例中,上述信令中包括以下信息至少之一:起始的等级索引;基站分配给终端的上述随机接入信道所在的频域位置信息;基站分配给终端的上述随机接入信道所在的时域位置信息。In an optional embodiment, the signaling includes at least one of the following: a starting level index; frequency domain location information of the random access channel allocated by the base station to the terminal; and the random number allocated by the base station to the terminal Time domain location information of the access channel.
在一个可选的实施例中,上述基站分配给终端的随机接入信道所在的频域位置信息包括:组成所述随机接入信号的单元Unit的Group0发送时所在的子载波或子信道索引。可选地,Unit中除Group0之外的其他几个Group所在的频域资源由Group0的频域位置指示(例如,可以按照预定义规则,根据Group0的频域确定)。In an optional embodiment, the frequency domain location information of the random access channel allocated by the base station to the terminal includes: a subcarrier or a subchannel index where the group 0 of the unit that constitutes the random access signal is sent. . Optionally, the frequency domain resources of several groups other than Group 0 in the unit are indicated by the frequency domain location of Group 0 (for example, according to a predefined rule, determined according to the frequency domain of Group 0 ).
在一个可选的实施例中,当上行带宽包括48个子载波或子信道时,通过6bits指示信息指示基站分配给所述终端的所述随机接入信道所在的频域位置信息。在本实施例中,例如“000000”代表索引为0的Subcarrior,索引“101111”代表索引为47的Subcarrior。In an optional embodiment, when the uplink bandwidth includes 48 subcarriers or subchannels, the 6bits indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal. In the present embodiment, for example, "000000" represents a Subcarrior whose index is 0, and the index "101111" represents a Subcarrior whose index is 47.
在一个可选的实施例中,上述6bits指示信息还用于指示终端在Setm中的F个子载波中随机选择一个子载波作为随机接入信道所在的频域位置。例如,“110000”可以指示所述终端在Setm中的F个子载波中随机选择一个子载波作为随机接入信道所在的频域位置。In an optional embodiment, the foregoing 6 bits indication information is further used to indicate that the terminal randomly selects one subcarrier among the F subcarriers in Set m as the frequency domain location where the random access channel is located. For example, “110000” may indicate that the terminal randomly selects one subcarrier among the F subcarriers in Set m as the frequency domain location where the random access channel is located.
在一个可选的实施例中,当Setm中包括F个子载波或子信道时,通过指示信息指示基站分配给终端的随机接入信道所在的频域位置信息。在本实施例中,是向上取整操作运算符。In an alternative embodiment, when included in Set m F subcarriers or subchannels, by The indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal. In this embodiment, Is the rounding operation operator.
在一个可选的实施例中,指示信息还用于指示终端在Setm中的F个子载波中随机选择一个子载波作为终端的随机接入信道所在的频域位置。在本实施例中,是向上取整操作运算符。In an alternative embodiment, The indication information is further used to indicate that the terminal randomly selects one subcarrier among the F subcarriers in the Set m as the frequency domain location where the random access channel of the terminal is located. In this embodiment, Is the rounding operation operator.
在一个可选的实施例中,当上述Setm中包括F个子载波或子信道时,通过指示信息指示基站分配给所述终端的所述随机接入信道所在的频域位置信息,其中,Num为随机接入信道占用的子载波数量。In an optional embodiment, when the above set M includes F subcarriers or subchannels, The indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal, where Num is the number of subcarriers occupied by the random access channel.
在一个可选的实施例中,上述基站分配给终端的所述随机接入信道所在的时域位置信息包括:第二Setm的配置周期指示信息n;其中,所述基站分配给所述终端的所述随机接入信
道所在的Setm定义为第二Setm;所述第二Setm为从第一Setm中选择的;且第二Setm的配置周期长度为第一Setm的配置周期的n倍,n为正整数;所述第一Setm为所述随机接入信道资源包括的一个或多个时频资源集合Setm,n为正整数。当n=1时,说明第一Setm与第二Setm是相等的。In an optional embodiment, the time domain location information of the random access channel allocated by the base station to the terminal includes: configuration period indication information n of the second Set m ; wherein the base station is allocated to the terminal Set m of the random access channel is defined as a second location Set m; the second Set m is selected from the first Set m; the length of the second period, and arranged Set m as a first configuration Set m n times the period, n is a positive integer; the first Set m is one or more time-frequency resource sets Set m included in the random access channel resource, and n is a positive integer. When n=1, it is stated that the first Set m and the second Set m are equal.
在一个可选的实施例中,包括以下至少之一:当n的取值由3bit描述时,n的取值为{1,2,3,4,5,6,7,8}或{1,2,4,8,16,32,64,128}或{1,2,4,8,10,12,14,16};当n的取值由2bit描述时,n的取值为{1,2,3,4}或{1,2,4,8}或{1,4,6,8}。In an optional embodiment, at least one of the following is included: when the value of n is described by 3 bits, the value of n is {1, 2, 3, 4, 5, 6, 7, 8} or {1 , 2, 4, 8, 16, 32, 64, 128} or {1, 2, 4, 8, 10, 12, 14, 16}; when the value of n is described by 2 bits, the value of n is { 1,2,3,4} or {1,2,4,8} or {1,4,6,8}.
在一个可选的实施例中,上述基站分配给终端的随机接入信道所在的时域位置为:第二Setm的配置周期内的第一个第一Setm。In an optional embodiment, the time domain location of the random access channel allocated by the base station to the terminal is: the first first Set m in the configuration period of the second Set m .
在一个可选的实施例中,上述基站分配给终端的随机接入信道所在的时域位置信息还包括:第二Setm在第二Setm的配置周期内的位置信息Offset;其中,该Offset用于指示第二Setm的配置周期内的n个第一Setm中,分配给所述终端的所述随机接入信道所在的第一Setm的索引信息。In an alternative embodiment, the base station assigned to the time domain location of the random access channel terminal is located further comprising: a second position information Offset Set m arranged in a period of the second Set m; wherein the Offset Set m for n first configuration in a second period indicative of Set m, allocated to the index information of the random access channel where the first terminal of the Set m.
在一个可选的实施例中,上述基站分配给终端的所述随机接入信道所在的时域位置信息包括:连续两个第二Setm时域间隔信息Interval;上述基站分配给所述终端的所述随机接入信道所在的Setm定义为第二Setm;所述第二Setm为从第一Setm中选择的,且连续两个第二Setm之间间隔Interval个第一Setm;所示第一Setm为所述随机接入信道资源包括的一个或多个时频资源集合Setm。In an alternative embodiment, the base station assigned to the domain location information of the random access channel where a terminal comprising: a field interval information Interval Set m consecutive two second time; and the base station allocates to the terminal Set m of the random access channel is defined as a second location Set m; Set m between the second selected Set m from the first, and the second two consecutive first-Set m interval interval Set m The first set m is shown as one or more time-frequency resource sets Set m included in the random access channel resource.
在一个可选的实施例中,上述信令中还包括:触发定位操作指示信息。例如“0”表示不触发定位操作;“1”表示触发定位操作。In an optional embodiment, the signaling further includes: triggering positioning operation indication information. For example, “0” means that the positioning operation is not triggered; “1” means that the positioning operation is triggered.
在一个可选的实施例中,上述触发定位操作指示信息为触发定位操作时,所述终端在所述信令分配的随机接入信道上发送所述随机接入信号。在本实施例中,终端发送的上述随机接入信号用来供基站进行终端的位置定位使用。In an optional embodiment, when the trigger location operation indication information is a trigger location operation, the terminal sends the random access signal on the signaling random access channel. In this embodiment, the random access signal sent by the terminal is used by the base station to perform location location use of the terminal.
在一个可选的实施例中,上述装置还包括随机接入响应接收模块,设置为终端在发送所述随机接入信号给所述基站之后,接收基站在检测随机接入信号后,根据检测结果发送的随机接入响应消息;其中,该随机接入响应消息中包括以下信息中至少之一:子载波间隔指示信息;配置的子载波数量指示信息。在本实施例中,子载波间隔指示信息可以用来指示Msg3消息发送时子载波间隔配置。In an optional embodiment, the apparatus further includes a random access response receiving module, configured to: after the terminal sends the random access signal to the base station, the receiving base station detects the random access signal, according to the detection result. And the received random access response message, where the random access response message includes at least one of the following information: subcarrier spacing indication information; configured subcarrier number indication information. In this embodiment, the subcarrier spacing indication information may be used to indicate the subcarrier spacing configuration when the Msg3 message is sent.
在一个可选的实施例中,上述子载波间隔指示信息和配置的子载波数量指示信息通过联
合编码方式指示。In an optional embodiment, the foregoing subcarrier spacing indication information and the configured subcarrier number indication information are connected
Coding mode indication.
需要说明的是,上述各个模块是可以通过软件或硬件来实现的,对于后者,可以通过以下方式实现,但不限于此:上述模块均位于同一处理器中;或者,上述模块分别位于多个处理器中。It should be noted that each of the above modules may be implemented by software or hardware. For the latter, the foregoing may be implemented by, but not limited to, the foregoing modules are all located in the same processor; or, the modules are located in multiple In the processor.
本发明的实施例还提供了一种存储介质。可选地,在本实施例中,上述存储介质可以被设置为存储用于执行以下步骤的程序代码:Embodiments of the present invention also provide a storage medium. Optionally, in the embodiment, the foregoing storage medium may be configured to store program code for performing the following steps:
S1,终端选择序列集合中与终端对应的序列;S1. The terminal selects a sequence corresponding to the terminal in the sequence set;
S2,上述终端至少根据对应的序列生成随机接入信号;S2. The foregoing terminal generates a random access signal according to at least a corresponding sequence.
S3,上述终端发送所述随机接入信号给基站。S3. The terminal sends the random access signal to the base station.
可选地,在本实施例中,上述存储介质可以包括但不限于:U盘、只读存储器(Read-Only Memory,简称为ROM)、随机存取存储器(Random Access Memory,简称为RAM)、移动硬盘、磁碟或者光盘等各种可以存储程序代码的介质。Optionally, in the embodiment, the foregoing storage medium may include, but is not limited to, a USB flash drive, a Read-Only Memory (ROM), and a Random Access Memory (RAM). A variety of media that can store program code, such as a hard disk, a disk, or an optical disk.
可选地,在本实施例中,处理器根据存储介质中已存储的程序代码执行上述各步骤。Optionally, in the embodiment, the processor performs the above steps according to the stored program code in the storage medium.
可选地,本实施例中的具体示例可以参考上述实施例及可选实施方式中所描述的示例,本实施例在此不再赘述。For example, the specific examples in this embodiment may refer to the examples described in the foregoing embodiments and the optional embodiments, and details are not described herein again.
显然,本领域的技术人员应该明白,上述的本发明的各模块或各步骤可以用通用的计算装置来实现,它们可以集中在单个的计算装置上,或者分布在多个计算装置所组成的网络上,可选地,它们可以用计算装置可执行的程序代码来实现,从而,可以将它们存储在存储装置中由计算装置来执行,并且在某些情况下,可以以不同于此处的顺序执行所示出或描述的步骤,或者将它们分别制作成各个集成电路模块,或者将它们中的多个模块或步骤制作成单个集成电路模块来实现。这样,本发明不限制于任何特定的硬件和软件结合。It will be apparent to those skilled in the art that the various modules or steps of the present invention described above can be implemented by a general-purpose computing device that can be centralized on a single computing device or distributed across a network of multiple computing devices. Alternatively, they may be implemented by program code executable by the computing device such that they may be stored in the storage device by the computing device and, in some cases, may be different from the order herein. The steps shown or described are performed, or they are separately fabricated into individual integrated circuit modules, or a plurality of modules or steps thereof are fabricated as a single integrated circuit module. Thus, the invention is not limited to any specific combination of hardware and software.
以上所述仅为本发明的优选实施例而已,并不用于限制本发明,对于本领域的技术人员来说,本发明可以有各种更改和变化。凡在本发明的精神和原则之内,所作的任何修改、等同替换、改进等,均应包含在本发明的保护范围之内。The above description is only the preferred embodiment of the present invention, and is not intended to limit the present invention, and various modifications and changes can be made to the present invention. Any modifications, equivalent substitutions, improvements, etc. made within the spirit and scope of the present invention are intended to be included within the scope of the present invention.
如上所述,本发明实施例提供的一种接入处理方法及装置具有以下有益效果:解决了相关技术中存在的无法保证各种类型的终端都成功接入系统的问题,进而实现了各种类型的终端都能够成功接入系统的效果。
As described above, an access processing method and apparatus provided by the embodiments of the present invention have the following beneficial effects: solving the problem that the related technologies cannot ensure that all types of terminals successfully access the system, thereby implementing various Types of terminals can successfully access the system.
Claims (99)
- 一种接入处理方法,包括:An access processing method includes:终端选择序列集合中与所述终端对应的序列;The terminal selects a sequence corresponding to the terminal in the sequence set;所述终端至少根据所述对应的序列生成随机接入信号;Generating, by the terminal, a random access signal according to at least the corresponding sequence;所述终端发送所述随机接入信号给基站。The terminal sends the random access signal to a base station.
- 根据权利要求1所述的方法,其中,所述序列集合中包括J条序列长度均为N的序列,其中,索引为j的序列的表达形式为0≤j≤J-1,0≤n≤N-1,J为正整数,N为正整数。The method according to claim 1, wherein said sequence set comprises J sequences of sequence length N, wherein the sequence of index j is expressed as 0 ≤ j ≤ J-1, 0 ≤ n ≤ N-1, J is a positive integer, and N is a positive integer.
- 根据权利要求2所述的方法,其中,所述序列集合包括R个序列子集合,所述R个序列子集合配置给不同的终端集合;其中,R为正整数。The method of claim 2, wherein the set of sequences comprises R sequence subsets, the R sequence subsets being configured for different sets of terminals; wherein R is a positive integer.
- 根据权利要求3所述的方法,其中,所述终端选择序列集合中与所述终端对应的序列包括:The method according to claim 3, wherein the sequence corresponding to the terminal in the terminal selection sequence set comprises:所述终端从所述R个序列子集合中确定与自身所属的终端集合对应的序列子集合;Determining, by the terminal, a sequence sub-set corresponding to the terminal set to which the UE belongs, from the R sequence sub-sets;所述终端从确定的序列子集合中选择一条序列作为所述对应的序列。The terminal selects a sequence from the determined sequence subset as the corresponding sequence.
- 根据权利要求4所述的方法,其中,所述终端从所述R个序列子集合中确定与自身所属的终端集合对应的序列子集合包括:The method according to claim 4, wherein the determining, by the terminal, the sequence subset corresponding to the terminal set to which the terminal belongs is determined by the terminal from the R sequence subsets includes:所述终端从所述R个序列子集合选择第(Y+1)个序列子集合作为与自身所属的终端集合对应的序列子集合,其中Y=Mod(Cell ID,R),Cell ID为所述终端接入的小区标识索引。The terminal selects the (Y+1)th sequence sub-set from the R sequence subsets as a sequence subset corresponding to the terminal set to which the UE belongs, where Y=Mod(Cell ID, R), and the Cell ID is The cell identification index of the terminal access.
- 根据权利要求3所述的方法,其中,所述R个序列子集合分别被配置给R个不同的终端集合。The method of claim 3, wherein the R sequence subsets are each configured for R different terminal sets.
- 根据权利要求3所述的方法,其中,包括以下至少之一:The method of claim 3, comprising at least one of the following:当终端集合的数量为2时,2个不同的终端集合为第一终端集合和第二终端集合,所述第一终端集合和所述第二终端集合满足以下条件至少之一:所述第一终端集合包括的终端为支持多个子载波同时传输的终端,且所述第二终端集合包括的终端为仅支持单个子载波传输的终端;所述第一终端集合包括的终端为采用多个子载波传输上行数据的终端,且所述第二终端集合包括的终端为采用单个子载波传输上行数据的终端;所述第一终端集合包括的终端为采用多个子载波同时传输Msg3消息的终端,且所述第二终端集合包括的终端为采用单个子载波传输Msg3消息的终端;所述第一终端集合包括的终端为Msg3消息承载在多个子载波上传输的终端,且所述第二终端集合包括的终端为Msg3消息仅承载在单个子载波传输的终端;所述第一终端集合包括的终端为支持单个子载波传输且子载波间隔为fsc1的终端,所述第二终端集合包括的终端为支持单个子载波传输且子 载波间隔为fsc2的终端;所述第一终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc1的终端;所述第二终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc2的终端;所述第一终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc1的终端,所述第二终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc2的终端;所述第一终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc1的终端,所述第二终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc2的终端;所述第一终端集合包括的终端为Msg3消息中承载的信息量为Size1的终端,所述第二终端集合包括的终端为Msg3消息中承载的信息量为Size2的终端,其中,Size1不等于Size2;When the number of terminal sets is 2, the two different terminal sets are the first terminal set and the second terminal set, and the first terminal set and the second terminal set satisfy at least one of the following conditions: the first The terminal set includes a terminal that supports simultaneous transmission of multiple subcarriers, and the terminal included in the second terminal set is a terminal that supports only a single subcarrier transmission; the terminal included in the first terminal set is transmitted by using multiple subcarriers. a terminal of the uplink data, and the terminal included in the second terminal set is a terminal that transmits uplink data by using a single subcarrier; the terminal included in the first terminal set is a terminal that simultaneously transmits an Msg3 message by using multiple subcarriers, and the terminal The terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier; the terminal included in the first terminal set is a terminal that the Msg3 message carries on a plurality of subcarriers, and the terminal that is included in the second terminal set The Msg3 message is only carried in the terminal of the single subcarrier transmission; the first terminal set includes the terminal to support a single subcarrier. And a transmission subcarrier spacing f sc1 terminal, the second set of terminals including a terminal support and a single sub-carrier transmission subcarrier spacing f sc2 terminal; the first set of terminals including a terminal employing a single subcarrier a terminal that transmits uplink data and has a subcarrier spacing of f sc1 ; the terminal included in the second terminal set is a terminal that transmits uplink data by using a single subcarrier and has a subcarrier spacing of f sc2 ; the terminal included in the first terminal set is a terminal that transmits an Msg3 message with a single subcarrier and has a subcarrier spacing of f sc1 , where the terminal included in the second terminal set is a terminal that transmits an Msg3 message by using a single subcarrier and has a subcarrier spacing of f sc2 ; the first terminal set The terminal included is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc1 , and the second terminal set includes a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc2 . a terminal that is included in the first terminal set is a terminal that has a quantity of information carried in the Msg3 message, and the second terminal set includes End of message information carried in Msg3 size2 terminal, wherein, Size1 is not equal size2;当终端集合的数量为3时,3个不同的终端集合为第一终端集合、第二终端集合和第三终端集合,所述第一终端集合、所述第二终端集合和所述第三终端集合满足以下条件至少之一:所述第一终端集合包括的终端为支持多个子载波同时传输的终端,所述第二终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc1的终端,所述第三终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc2的终端;所述第一终端集合包括的终端为采用多个子载波传输上行数据的终端,所述第二终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc1的终端;所述第三终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc2的终端;所述第一终端集合包括的终端为采用多个子载波传输Msg3消息的终端,所述第二终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc1的终端,所述第三终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc2的终端;所述第一终端集合包括的终端为Msg3消息承载在多个子载波上传输的终端,所述第二终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc1的终端,所述第三终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc2的终端;所述第一终端集合包括的终端为Msg3消息中承载的信息量为Size1的终端,所述第二终端集合包括的终端为Msg3消息中承载的信息量为Size2的终端,所述第三终端集合包括的终端为Msg3消息中承载的信息量为Size3的终端,其中,Size1、Size2、Size3互不相等;When the number of terminal sets is 3, the three different terminal sets are a first terminal set, a second terminal set, and a third terminal set, the first terminal set, the second terminal set, and the third terminal. The set meets at least one of the following conditions: the terminal included in the first terminal set is a terminal that supports simultaneous transmission of multiple subcarriers, and the second terminal set includes terminals that support only a single subcarrier transmission and the subcarrier spacing is f sc1 The terminal included in the third terminal set is a terminal that supports only a single subcarrier transmission and the subcarrier spacing is f sc2 ; the terminal included in the first terminal set is a terminal that uses multiple subcarriers to transmit uplink data. The terminal included in the second terminal set is a terminal that transmits uplink data by using a single subcarrier and has a subcarrier spacing of f sc1 ; the terminal included in the third terminal set transmits uplink data by using a single subcarrier and the subcarrier spacing is f sc2 The terminal included in the first terminal set is a terminal that transmits an Msg3 message by using multiple subcarriers, and the second terminal set includes End for the introduction of a single subcarrier message Msg3 transmission and subcarrier spacing f sc1 terminal, the third terminal is a terminal set includes a single subcarrier using message Msg3 transmission and the subcarrier spacing f sc2 terminal; the first The terminal set includes a terminal that is a Msg3 message that is transmitted on a plurality of subcarriers, and the second terminal set includes a terminal that is a Msg3 message that is only carried in a single subcarrier transmission and has a subcarrier spacing of f sc1 . The terminal included in the three-terminal set is a terminal in which the Msg3 message is only carried in a single sub-carrier transmission and the sub-carrier spacing is f sc2 ; the terminal included in the first terminal set is a terminal in which the amount of information carried in the Msg3 message is Size1, The terminal included in the second terminal set is a terminal that has the information amount of the S2 in the Msg3 message, and the terminal included in the third terminal set is a terminal that has the information amount of the S3 in the Msg3 message, where Size1, Size2, and Size3 are mutually not equal;当终端集合的数量为4时,4个不同的终端集合为第一终端集合、第二终端集合、第三终端集合和第四终端集合,所述第一终端集合、所述第二终端集合、所述第三终端集合和所述第四终端集合满足以下条件至少之一:所述第一终端集合包括的终端为支持多个子载波同时传输且子载波间隔为fsc1的终端,所述第二终端集合包括的终端为支持多个 子载波同时传输且子载波间隔为fsc2的终端,所述第三终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc3的终端,所述第四终端集合包括的终端为仅支持单个子载波传输且子载波间隔为fsc4的终端;所述第一终端集合包括的终端为采用多个子载波传输上行数据且子载波间隔为fsc1的终端,所述第二终端集合包括的终端为采用多个子载波传输上行数据且子载波间隔为fsc2的终端,所述第三终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc3的终端;所述第四终端集合包括的终端为采用单个子载波传输上行数据且子载波间隔为fsc4的终端;所述第一终端集合包括的终端为采用多个子载波传输Msg3消息且子载波间隔为fsc1的终端,所述第二终端集合包括的终端为采用多个子载波传输Msg3消息且子载波间隔为fsc2的终端,所述第三终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc3的终端,所述第四终端集合包括的终端为采用单个子载波传输Msg3消息且子载波间隔为fsc4的终端;所述第一终端集合包括的终端为Msg3消息承载在多个子载波上传输且子载波间隔为fsc1的终端,所述第二终端集合包括的终端为Msg3消息承载在多个子载波上传输且子载波间隔为fsc2的终端,所述第三终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc3的终端,所述第四终端集合包括的终端为Msg3消息仅承载在单个子载波传输且子载波间隔为fsc4的终端;所述第一终端集合包括的终端为Msg3消息中承载的信息量为Size1的终端,所述第二终端集合包括的终端为Msg3消息中承载的信息量为Size2的终端,所述第三终端集合包括的终端为Msg3消息中承载的信息量为Size3的终端,所述第四终端集合包括的终端为Msg3消息中承载的信息量为Size4的终端,其中,Size1、Size2、Size3、Size4互不相等。When the number of terminal sets is 4, the four different terminal sets are a first terminal set, a second terminal set, a third terminal set, and a fourth terminal set, the first terminal set, the second terminal set, The third terminal set and the fourth terminal set meet at least one of the following conditions: the terminal included in the first terminal set is a terminal that supports simultaneous transmission of multiple subcarriers and has a subcarrier spacing of f sc1 , and the second The terminal set includes a terminal that supports simultaneous transmission of multiple subcarriers and a subcarrier spacing of f sc2 , and the terminal included in the third terminal set is a terminal that supports only a single subcarrier transmission and has a subcarrier spacing of f sc3 . The terminal included in the fourth terminal set is a terminal that supports only a single subcarrier transmission and the subcarrier spacing is f sc4 ; the terminal included in the first terminal set is a terminal that uses multiple subcarriers to transmit uplink data and the subcarrier spacing is f sc1 said second set of terminals including a terminal using a plurality of subcarriers to transmit the uplink data and the sub-carrier spacing f sc2 terminal, the third terminal set comprises Using a single terminal is transmitting uplink data subcarriers and subcarrier spacing f sc3 terminal; a fourth set of terminals including the terminal is using a single subcarrier for transmitting uplink data and the subcarrier spacing f sc4 terminal; the first The terminal included in the terminal set is a terminal that uses a plurality of subcarriers to transmit an Msg3 message and the subcarrier spacing is f sc1 , and the terminal included in the second terminal set is a terminal that uses a plurality of subcarriers to transmit an Msg3 message and the subcarrier spacing is f sc2 . The terminal included in the third terminal set is a terminal that transmits an Msg3 message by using a single subcarrier and has a subcarrier spacing of f sc3 , and the terminal included in the fourth terminal set transmits a Msg3 message by using a single subcarrier and the subcarrier spacing is f. a terminal of the sc4 ; the terminal included in the first terminal set is a terminal in which the Msg3 message is transmitted on multiple subcarriers and the subcarrier spacing is f sc1 , and the terminal included in the second terminal set is a Msg3 message carried on multiple subcarriers. a terminal that transmits and has a subcarrier spacing of f sc2 , and the third terminal set includes a terminal that the Msg3 message is carried only on a single subcarrier. a terminal that transmits and has a subcarrier spacing of f sc3 , where the terminal included in the fourth terminal set is a terminal in which the Msg3 message is only carried in a single subcarrier transmission and the subcarrier spacing is f sc4 ; the terminal included in the first terminal set is The terminal that is included in the Msg3 message is the terminal of the Size1, and the terminal that is included in the second terminal set is the terminal that has the information amount of the S2 in the Msg3 message, and the terminal included in the third terminal set is the information carried in the Msg3 message. The terminal of the third terminal set is a terminal that is in the Msg3 message and whose amount of information is Size4, where Size1, Size2, Size3, and Size4 are not equal to each other.
- 根据权利要求2至7中任一项所述的方法,其中,所述J条序列长度均为N的序列满足以下至少之一:The method according to any one of claims 2 to 7, wherein the sequence of J sequences having a length of N satisfies at least one of the following:所述J条序列长度均为N的序列为正交码字序列;The sequence in which the J sequences are all N in length is an orthogonal codeword sequence;所述J条序列长度均为N的序列为准正交码字序列;The sequence in which the J sequences are all N in length is a quasi-orthogonal codeword sequence;所述J条序列长度均为N的序列为预定义的序列。The sequence in which the J sequences are all N in length is a predefined sequence.
- 根据权利要求2至7中任一项所述的方法,其中,所述满足以下至少之一:The method according to any one of claims 2 to 7, wherein said Meet at least one of the following:不同取值的j对应的Codej中互为正交码字,或互为准正交码字; Different values of j corresponding to Code j Mutual orthogonal code words, or mutually quasi-orthogonal code words;不同取值的j对应的Codej中互为正交码字,或互为准正交码字;Different values of j corresponding to Code j Mutual orthogonal code words, or mutually quasi-orthogonal code words;
- 根据权利要求8或9所述的方法,其中,所述N的取值为以下之一:2,4,6,8。The method according to claim 8 or 9, wherein the value of N is one of the following: 2, 4, 6, 8.
- 根据权利要求3至7中任一项所述的方法,其中,包括以下至少之一:The method according to any one of claims 3 to 7, wherein at least one of the following is included:当J=1,且N=4时,J条序列长度为N的序列包括以下至少之一: When J=1, and N=4, the J sequence sequence length N includes at least one of the following:当R=2,J=2,且N=4时,J条序列长度为N的序列包括以下至少之一: 其中,Code0和Code1中的一个被配置给第一终端集合中的终端,另一个被配置给第二终端集合中的终端;When R=2, J=2, and N=4, the sequence of J sequence lengths of N includes at least one of the following: Wherein one of Code 0 and Code 1 is configured to the terminal in the first terminal set, and the other is configured to the terminal in the second terminal set;当R=2,J=2,且N=8时,J条序列长度为N的序列包括以下至少之一: 其中,Code0和Code1中的一个被配置给第一终端集合中的终端,另一个被配置给第二终端集合中的终端;When R=2, J=2, and N=8, the sequence of J sequence lengths of N includes at least one of the following: Wherein one of Code 0 and Code 1 is configured to the terminal in the first terminal set, and the other is configured to the terminal in the second terminal set;当R=3,J=3,且N=4时,J条序列长度为N的序列包括以下至少之一: 中任意3个; 中任意3个;其中,3条序列长度为N的序列被分别配置给3个终端集合中的终端;When R=3, J=3, and N=4, the sequence of J sequences of length N includes at least one of the following: Any three of them; Any three of them; wherein three sequences of sequence length N are respectively allocated to terminals in three terminal sets;当R=4,J=4,且N=4时,J条序列长度为N的序列包括以下至少之一: 其中,4条序列长度为N的序列被分别配置给4个终端集合中的终端;When R=4, J=4, and N=4, the sequence of J sequence lengths of N includes at least one of the following: Wherein, four sequences of sequence length N are respectively allocated to terminals in the four terminal sets;
- 根据权利要求2至12中任一项所述的方法,其中,当与所述终端对应的序列为时,所述终端至少根据所述对应的序列生成随机接入信号包括:The method according to any one of claims 2 to 12, wherein when the sequence corresponding to the terminal is And generating, by the terminal, the random access signal according to the corresponding sequence at least:所述终端确定频域上索引为fn的子载波且时域上占用连续的K个符号发送第k个符号且子载波fn上发送的信号的频域表达式为所述K个符号且子载波fn上发送的信号的频域表达式为其中,0≤k≤K-1;The terminal determines a subcarrier indexed as f n in the frequency domain and occupies consecutive K symbols in the time domain. The frequency domain expression of the signal transmitted on the kth symbol and on the subcarrier f n is The frequency domain expression of the K symbol and the signal transmitted on the subcarrier f n is Where 0 ≤ k ≤ K-1;
- 根据权利要求13所述的方法,其中,所述终端至少根据所述确定所述随机接入信号包括:The method of claim 13 wherein said terminal is based at least on said Determining the random access signal includes:对应的时域的表达式为其中0≤t≤Tk,Tk为第k个时域符号的长度,为索引为fn的子载波占用的频域资源,FOffset为频域偏移量;和/或, The corresponding time domain expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol, For the frequency domain resource occupied by the subcarrier indexed as f n , F Offset is the frequency domain offset; and/or,当时域采样间隔为Ts时,对应的时域的表达式为其中,0≤t≤Tk,Tk为第k个时域符号的长度,0≤k≤K-1,0≤q≤Q-1,为时域采样点数量;所述终端在连续的K个符号上发送的时域表达式为 When the domain sampling interval is T s , Corresponding time domain The expression is Where 0 ≤ t ≤ T k , T k is the length of the kth time domain symbol, 0 ≤ k ≤ K-1, 0 ≤ q ≤ Q-1, Number of samples in the time domain; the terminal is sent on consecutive K symbols The time domain expression is
- 根据权利要求14所述的方法,其中,所述终端至少根据所述确定所述随机接入信号包括:The method of claim 14, wherein the terminal is at least according to the Determining the random access signal includes:所述终端按照下式生成循环前缀CPn,CPn={Sn[QK-L+1],…,Sn[QK]},L表示CPn中包括的时域采样间隔Ts的数量;The terminal generates a cyclic prefix CP n , CP n ={S n [QK-L+1],...,S n [QK]} according to the following formula, where L represents the number of time domain sampling intervals T s included in the CP n ;则所述终端在子载波fn上发送的随机接入信号的表达式为Groupn={CPn,Sn},所述终端在子载波f0,f1,…,fN-1上发送的随机接入信号的表达式为{Group0,Group1,…GroupN-1};The expression of the random access signal sent by the terminal on the subcarrier f n is Group n = {CP n , S n }, and the terminal is on the subcarriers f 0 , f 1 , ..., f N-1 The expression of the random access signal sent is {Group 0 , Group 1 , ... Group N-1 };其中,n取值不同的Groupn在时域上占用不同的时域符号。Among them, Group n with different values of n occupy different time domain symbols in the time domain.
- 根据权利要求15所述的方法,其中,Group0~GroupN-1为组成所述随机接入信号的单元Unit,所述终端发送所述随机接入信号给基站包括:The method according to claim 15, wherein the group 0 to the group N-1 are the unit units constituting the random access signal, and the terminal transmitting the random access signal to the base station includes:所述终端确定一个所述Unit为所述随机接入信号,并将所述随机接入信号重复H次进行发送;和/或,Determining, by the terminal, that the unit is the random access signal, and repeating the random access signal for H times; and/or,所述终端将所述Unit在时域上重复H次形成所述随机接入信号,并发送所述随机接入信号。The terminal repeats the H times in the time domain to form the random access signal, and sends the random access signal.
- 根据权利要求16所述的方法,其中,The method of claim 16 wherein所述终端在子载波fn上发送完成随机接入信号Groupn之后,需要引入时间长度为Gap的间隔。After completion of the terminal transmits a random access signal on sub-carriers Group n f n, the length of time necessary to introduce the interval Gap.
- 根据权利要求17所述的方法,其中,包括以下至少之一: The method of claim 17 comprising at least one of:当N=4,K=5,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,所述Gap的时域长度为0.4ms;When N=4, K=5, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of the Gap is 0.4 ms;当N=4,K=5,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,所述Gap的时域长度为0.6ms;When N=4, K=5, the time domain length of CP n is 66.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of the Gap is 0.6 ms;当N=4,K=5,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;When N=4, K=5, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 12288*Ts, where Ts=32.55ns;当N=4,K=5,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns。When N=4, K=5, the time domain length of CP n is 2048*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 18432*Ts, where Ts = 32.55 ns.
- 根据权利要求16所述的方法,其中,The method of claim 16 wherein所述Unit的H次重复包括Y个Group,定义Y个Group的索引为Group0~GroupY-1,其中,Y=H*N;当所述终端完成Groupstart到Groupend一共y个Group的随机接入信号的发送之后,需要引入时间长度为Gap的间隔;The H repetitions of the Unit include Y groups, and the indexes defining the Y groups are Group 0 to Group Y-1 , where Y=H*N; when the terminal completes Group start to Group end, a total of y Groups After the random access signal is sent, it is necessary to introduce an interval of time Gap;其中,0≤start≤end≤Y-1,y≤Y。Among them, 0 ≤ start ≤ end ≤ Y-1, y ≤ Y.
- 根据权利要求19所述的方法,其中,The method of claim 19, whereinstart=offset+y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量;offset为第一个Groupstart的索引的偏置量;或者,Start=offset+y×N gap , where N gap is the number of intervals in which the length of the introduction time is Gap; offset is the offset of the index of the first group start ; orstart=y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量。Start=y×N gap , where N gap is the number of intervals in which the introduction time length is Gap.
- 根据权利要求19至21中任一项所述的方法,其中,end=start+y-1。The method according to any one of claims 19 to 21, wherein end = start + y-1.
- 根据权利要求19所述的方法,其中,所述Gap满足以下条件至少之一:The method of claim 19, wherein the Gap satisfies at least one of the following conditions:y×L_G+Gap=T×TimeUnit,其中,L_G为所述Group的时间长度,Gap≥0,T为正整数,TimeUnit为一种时间长度的度量单位;y×L_G+Gap=T×TimeUnit, where L_G is the length of time of the group, Gap ≥ 0, T is a positive integer, and TimeUnit is a unit of measure of time length;y×L_G+Gap=T×TimeUnit,其中L_G为所述Group的时间长度,Gap≥0,T为正整数且T为满足T×TimeUnit>y×L_G的最小值,TimeUnit为一种时间长度的度量单位。 y×L_G+Gap=T×TimeUnit, where L_G is the length of time of the group, Gap ≥ 0, T is a positive integer and T is a minimum value satisfying T×TimeUnit>y×L_G, and TimeUnit is a time length Unit of measure.
- 根据权利要求16所述的方法,其中,The method of claim 16 wherein所述终端在发送完成一个所述Unit的随机接入信号之后,需要引入时间长度为Gap的间隔。After the terminal completes the random access signal of the unit, it needs to introduce an interval of time Gap.
- 根据权利要求24所述的方法,其中,包括以下至少之一:The method of claim 24, comprising at least one of the following:当N=4,K=5,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,所述Gap的时域长度为0.6ms;When N=4, K=5, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of the Gap is 0.6 ms;当N=4,K=5,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,所述Gap的时域长度为0.4ms;When N=4, K=5, the time domain length of CP n is 66.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of the Gap is 0.4 ms;当N=4,K=5,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;When N=4, K=5, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 18432*Ts, where Ts=32.55ns;当N=4,K=5,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns。When N=4, K=5, the time domain length of CP n is 2048*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 12288*Ts, where Ts = 32.55 ns.
- 根据权利要求16所述的方法,其中,The method of claim 16 wherein定义所述Unit的H次重复的索引为Unit0~UnitH-1,当所述终端完成Unitstart到Unitend一共y个Unit的随机接入信号发送之后,需要引入时间长度为Gap的间隔;The H-repetition index of the unit is defined as Unit 0 to Unit H-1 . After the terminal completes the unit start to unit end and sends a total of y units of random access signals, it is necessary to introduce an interval of time Gap.其中,0≤start≤end≤Y-1,y≤Y。Among them, 0 ≤ start ≤ end ≤ Y-1, y ≤ Y.
- 根据权利要求26所述的方法,其中,The method of claim 26, whereinstart=offset+y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量;offset为第一个Unitstart的索引的偏置量;或者,Start=offset+y×N gap , where N gap is the number of intervals in which the length of the introduction time is Gap; offset is the offset of the index of the first unit start ; orstart=y×Ngap,其中,Ngap为引入时间长度为Gap的间隔的数量。Start=y×N gap , where N gap is the number of intervals in which the introduction time length is Gap.
- 根据权利要求26至28中任一项所述的方法,其中,end=start+y-1。A method according to any one of claims 26 to 28, wherein end = start + y-1.
- 根据权利要求26所述的方法,其中,所述Gap满足以下条件至少之一:The method of claim 26, wherein the Gap satisfies at least one of the following conditions:y×L_U+Gap=T×TimeUnit,其中,L_G为所述Unit的时间长度,gap≥0,T为正整数,TimeUnit为一种时间长度的度量单位;y×L_U+Gap=T×TimeUnit, where L_G is the length of time of the unit, gap≥0, T is a positive integer, and TimeUnit is a unit of measure of time length;y×L_U+Gap=T×TimeUnit,其中,L_G为所述Unit的时间长度,Gap≥0,T 为正整数且T为满足T×TimeUnit>y×L_U的最小值,TimeUnit为一种时间长度的度量单位。y×L_U+Gap=T×TimeUnit, where L_G is the length of time of the unit, Gap ≥ 0, T A positive integer and T is the minimum value that satisfies T×TimeUnit>y×L_U, which is a unit of measure of time length.
- 根据权利要求26至29中任一项所述的方法,其中,包括以下至少之一:A method according to any one of claims 26 to 29, comprising at least one of the following:当N=4,K=5,H=1,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;When N=4, K=5, H=1, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 18432*. Ts, where Ts=32.55 ns;当N=4,K=5,H=2,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为6144*Ts或36864*Ts,其中,Ts=32.55ns;When N=4, K=5, H=2, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 6144*. Ts or 36864*Ts, where Ts=32.55 ns;当N=4,K=5,H=4,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;When N=4, K=5, H=4, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 12288*. Ts, where Ts=32.55 ns;当N=4,K=5,H=8,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为24576*Ts,其中,Ts=32.55ns;When N=4, K=5, H=8, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 24576*. Ts, where Ts=32.55 ns;当N=4,K=5,H=16,CPn的时域长度为8192*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;When N=4, K=5, H=16, the time domain length of CP n is 8192*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 18432*. Ts, where Ts=32.55 ns;当N=4,K=5,H=1,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;When N=4, K=5, H=1, the time domain length of CP n is 2048*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 12288*. Ts, where Ts=32.55 ns;当N=4,K=5,H=2,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为24576*Ts,其中,Ts=32.55ns;When N=4, K=5, H=2, the time domain length of CP n is 2048*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 24576*. Ts, where Ts=32.55 ns;当N=4,K=5,H=4,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为18432*Ts,其中,Ts=32.55ns;When N=4, K=5, H=4, the time domain length of CP n is 2048*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 18432* Ts, where Ts=32.55 ns;当N=4,K=5,H=8,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为6144*Ts或36864*Ts,其中,Ts=32.55ns;When N=4, K=5, H=8, the time domain length of CP n is 2048*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 6144*. Ts or 36864*Ts, where Ts=32.55 ns;当N=4,K=5,H=16,CPn的时域长度为2048*Ts,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为12288*Ts,其中,Ts=32.55ns;When N=4, K=5, H=16, the time domain length of CP n is 2048*Ts, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 12288*. Ts, where Ts=32.55 ns;当N=4,K=5,H=1,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.6ms; When N=4, K=5, H=1, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 0.6 ms;当N=4,K=5,H=2,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.2ms或1.2ms;When N=4, K=5, H=2, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time domain length of Gap is 0.2ms or 1.2ms;当N=4,K=5,H=4,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.4ms;When N=4, K=5, H=4, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 0.4 ms;当N=4,K=5,H=8,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.8ms;When N=4, K=5, H=8, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 0.8 ms;当N=4,K=5,H=16,CPn的时域长度为266.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.6ms;When N=4, K=5, H=16, the time domain length of CP n is 266.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 0.6 ms;当N=4,K=5,H=1,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.4ms;When N=4, K=5, H=1, the time domain length of CP n is 66.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time domain length of Gap is 0.4ms;当N=4,K=5,H=2,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.8ms;When N=4, K=5, H=2, the time domain length of CP n is 66.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 0.8 ms;当N=4,K=5,H=4,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.6ms;When N=4, K=5, H=4, the time domain length of CP n is 66.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 0.6 ms;当N=4,K=5,H=8,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.2ms或1.2ms;When N=4, K=5, H=8, the time domain length of CP n is 66.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75kHz, the time domain length of Gap is 0.2ms or 1.2ms;当N=4,K=5,H=16,CPn的时域长度为66.7us,发送随机接入信号的子载波间隔或子载波带宽为3.75kHz时,Gap的时域长度为0.4ms。When N=4, K=5, H=16, the time domain length of CP n is 66.7us, and the subcarrier spacing or subcarrier bandwidth of the random access signal is 3.75 kHz, the time domain length of Gap is 0.4 ms.
- 根据权利要求16所述的方法,其中,所述H的取值至少根据所述终端的等级确定。The method of claim 16 wherein the value of H is determined at least according to a level of the terminal.
- 根据权利要求32所述的方法,其中,所述终端的等级包括以下至少之一:The method of claim 32, wherein the rating of the terminal comprises at least one of:覆盖增强等级;Coverage enhancement level;物理信道重复发送等级;Physical channel repeat transmission level;物理信道上承载的消息或信令的重复发送等级。Repeated transmission level of messages or signaling carried on the physical channel.
- 根据权利要求16所述的方法,其中,所述终端发送所述随机接入信号给所述基站包括:The method of claim 16, wherein the transmitting, by the terminal, the random access signal to the base station comprises:所述终端确定用于发送所述随机接入信号的随机接入信道;Determining, by the terminal, a random access channel for transmitting the random access signal;所述终端通过所述随机接入信道向所述基站发送所述随机接入信号。 Transmitting, by the terminal, the random access signal to the base station by using the random access channel.
- 根据权利要求34所述的方法,其中,随机接入信道资源包括一个或多个时频资源集合Setm,其中,所述Setm在频域上包括F个子载波或子信道,在时域上长度至少为P个Unit的长度,m为所述Setm在时域的索引,F为正整数,P为正整数。The method of claim 34, wherein the random access channel resource comprises one or more time-frequency resource sets Set m, wherein F comprises the Set m subcarriers or subchannels in the frequency domain, in time domain The length is at least the length of P units, m is the index of the Set m in the time domain, F is a positive integer, and P is a positive integer.
- 根据权利要求35所述的方法,其中,所述Setm包括P个子集subset,其中,所述subset在频域上与所述Setm配置相同的子载波,所述subset在时域上长度为1个Unit的长度。The method according to claim 35, wherein said Set m comprises P subset subsets, wherein said subset is configured in the frequency domain with the same subcarriers as said Set m , said subset being length in time domain The length of 1 unit.
- 根据权利要求35所述的方法,其中,The method of claim 35, wherein当子载波间隔为3.75kHz,F=12时,在所述Setm占用的频率资源的前后频率资源上各配置有7.5kHz保护带宽;和/或,When the subcarrier spacing is 3.75 kHz and F=12, a 7.5 kHz protection bandwidth is configured on each of the frequency resources before and after the frequency resource occupied by the Set m ; and/or,当子载波间隔为3.75kHz,F=16时,在所述Setm占用的频率资源中上下边带各预留有7.5kHz保护带宽。When the subcarrier spacing is 3.75 kHz and F=16, the upper and lower sidebands each reserve a 7.5 kHz protection bandwidth in the frequency resources occupied by the Set m .
- 根据权利要求35所述的方法,其中,当上行带宽包括48个子载波,且F=12时,上行带宽最多配置4个Setm,且每个Setm在频域上包括F=12个子载波或子信道,不同Setm在频域上包括的子载波或子信道不重叠。The method according to claim 35, wherein when the uplink bandwidth comprises 48 subcarriers, and F=12, the uplink bandwidth is configured with a maximum of 4 Set m , and each Set m includes F=12 subcarriers in the frequency domain or Subchannels, different Set m subcarriers or subchannels included in the frequency domain do not overlap.
- 根据权利要求38所述的方法,其中,通过U个比特信息指示为同一个等级的终端或终端组分配的Setm的频域位置,其中,不同等级的终端配置的Setm的频域位置相同,U=2或4。The method according to claim 38, wherein, the U bit information indicating a frequency domain location of the terminal or group of terminals assigned the same level Set m, wherein the different levels of the same terminal configuration of the frequency domain position Set m , U=2 or 4.
- 根据权利要求35所述的方法,其中,当上行带宽包括48个子载波,且F=16时,上行带宽最多配置3个Setm,且每个Setm在频域上包括F=16个子载波或子信道,不同Setm在频域上包括的子载波或子信道不重叠。The method according to claim 35, wherein when the uplink bandwidth comprises 48 subcarriers, and F=16, the uplink bandwidth is configured with a maximum of 3 Set m , and each Set m includes F=16 subcarriers in the frequency domain or Subchannels, different Set m subcarriers or subchannels included in the frequency domain do not overlap.
- 根据权利要求40所述的方法,其中,通过U个比特信息指示为同一个等级的终端或终端组分配的Setm的频域位置,其中,不同等级的终端配置的Setm的频域位置相同,U=2或3。The method according to claim 40, wherein, the U bit information indicating a frequency domain location of the terminal or group of terminals assigned the same level Set m, wherein the different levels of the same terminal configuration of the frequency domain position Set m , U=2 or 3.
- 根据权利要求35所述的方法,其中,包括以下至少之一:The method of claim 35, comprising at least one of the following:当N=4,K=5时,所述Setm在时域上长度为7ms,所述CPn的时域长度为266.7us,P=1;When N=4, K=5, the set m has a length of 7 ms in the time domain, and the time domain length of the CP n is 266.7 us, P=1;当N=4,K=5时,所述Setm在时域上长度为13ms,所述CPn的时域长度为266.7us,P=2; When N=4, K=5, the set m has a length of 13 ms in the time domain, and the time domain length of the CP n is 266.7 uss, P=2;当N=8,K=5时,所述Setm在时域上长度为13ms,所述CPn的时域长度为266.7us,P=1;When N=8, K=5, the set m has a length of 13 ms in the time domain, and the time domain length of the CP n is 266.7 us, P=1;当N=4,K=5时,所述Setm在时域上长度为26ms,所述CPn的时域长度为266.7us,P=4;When N=4, K=5, the set m has a length of 26 ms in the time domain, and the time domain length of the CP n is 266.7 uss, P=4;当N=8,K=5时,所述Setm在时域上长度为26ms,所述CPn的时域长度为266.7us,P=2;When N=8, K=5, the set m has a length of 26 ms in the time domain, and the time domain length of the CP n is 266.7 uss, P=2;当N=4,K=5时,所述Setm在时域上长度为32ms,所述CPn的时域长度为266.7us,P=5;When N=4, K=5, the set m has a length of 32 ms in the time domain, and the time domain length of the CP n is 266.7 uss, P=5;当N=4,K=5时,所述Setm在时域上长度为64ms,所述CPn的时域长度为266.7us,P=10;When N=4, K=5, the set m has a length of 64 ms in the time domain, and the time domain length of the CP n is 266.7 uss, P=10;当N=8,K=5时,所述Setm在时域上长度为64ms,所述CPn的时域长度为266.7us,P=5;When N=8, K=5, the set m has a length of 64 ms in the time domain, and the time domain length of the CP n is 266.7 uss, P=5;当N=4,K=5时,所述Setm在时域上长度为6ms,所述CPn的时域长度为66.7us,P=1;When N=4, K=5, the set m has a length of 6 ms in the time domain, and the time domain length of the CP n is 66.7 us, P=1;当N=4,K=5时,所述Setm在时域上长度为12ms,所述CPn的时域长度为66.7us,P=2;When N=4, K=5, the set m has a length of 12 ms in the time domain, and the time domain length of the CP n is 66.7 uss, P=2;当N=8,K=5时,所述Setm在时域上长度为12ms,所述CPn的时域长度为66.7us,P=1;When N=8, K=5, the set m has a length of 12 ms in the time domain, and the time domain length of the CP n is 66.7 us, P=1;当N=4,K=5时,所述Setm在时域上长度为17ms,所述CPn的时域长度为66.7us,P=3;When N=4, K=5, the set m has a length of 17 ms in the time domain, and the time domain length of the CP n is 66.7 uss, P=3;当N=4,K=5时,所述Setm在时域上长度为23ms,所述CPn的时域长度为66.7us,P=4;When N=4, K=5, the set m has a length of 23 ms in the time domain, and the time domain length of the CP n is 66.7 uss, P=4;当N=8,K=5时,所述Setm在时域上长度为23ms,所述CPn的时域长度为66.7us,P=2;When N=8, K=5, the set m has a length of 23 ms in the time domain, and the time domain length of the CP n is 66.7 uss, P=2;当N=4,K=5时,所述Setm在时域上长度为28ms,所述CPn的时域长度为66.7us,P=5; When N=4, K=5, the set m has a length of 28 ms in the time domain, and the time domain length of the CP n is 66.7 uss, P=5;当N=4,K=5时,所述Setm在时域上长度为34ms,所述CPn的时域长度为66.7us,P=6;When N=4, K=5, the set m has a length of 34 ms in the time domain, and the time domain length of the CP n is 66.7 uss, P=6;当N=8,K=5时,所述Setm在时域上长度为34ms,所述CPn的时域长度为66.7us,P=3。When N=8 and K=5, the set m has a length of 34 ms in the time domain, and the time domain length of the CP n is 66.7 uss, P=3.
- 根据权利要求42所述的方法,其中,包括以下至少之一:The method of claim 42 comprising at least one of the following:当N=4,K=5时,所述Setm在时域上长度为7ms时,所述随机接入信道资源包括0.6ms的保护时间;When N=4, K=5, when the set m is 7 ms in the time domain, the random access channel resource includes a guard time of 0.6 ms;当N=4,K=5时,所述Setm在时域上长度为26ms时,所述随机接入信道资源包括0.4ms的保护时间;When N=4, K=5, when the set m is 26 ms in the time domain, the random access channel resource includes a guard time of 0.4 ms;当N=8,K=5时,所述Setm在时域上长度为26ms时,所述随机接入信道资源包括0.4ms的保护时间;When N=8, K=5, when the set m is 26 ms in the time domain, the random access channel resource includes a guard time of 0.4 ms;当N=4,K=5时,所述Setm在时域上长度为6ms时,所述随机接入信道资源包括0.4ms的保护时间;When N=4, K=5, when the set m is 6 ms in the time domain, the random access channel resource includes a guard time of 0.4 ms;当N=4,K=5时,所述Setm在时域上长度为12ms时,所述随机接入信道资源包括0.8ms的保护时间;When N=4, K=5, when the set m is 12 ms in the time domain, the random access channel resource includes a guard time of 0.8 ms;当N=8,K=5时,所述Setm在时域上长度为12ms时,所述随机接入信道资源包括0.8ms的保护时间;When N=8, K=5, when the set m is 12 ms in the time domain, the random access channel resource includes a guard time of 0.8 ms;当N=4,K=5时,所述Setm在时域上长度为17ms时,所述随机接入信道资源包括0.2ms的保护时间;When N=4, K=5, when the set m is 17 ms in the time domain, the random access channel resource includes a guard time of 0.2 ms;当N=4,K=5时,所述Setm在时域上长度为23ms时,所述随机接入信道资源包括0.6ms的保护时间;When N=4, K=5, when the set m is 23 ms in the time domain, the random access channel resource includes a guard time of 0.6 ms;当N=8,K=5时,所述Setm在时域上长度为23ms时,所述随机接入信道资源包括0.6ms的保护时间;When N=8, K=5, when the set m is 23 ms in the time domain, the random access channel resource includes a guard time of 0.6 ms;当N=4,K=5时,所述Setm在时域上长度为34ms时,所述随机接入信道资源包括0.4ms的保护时间;When N=4, K=5, when the set m is 34 ms in the time domain, the random access channel resource includes a guard time of 0.4 ms;当N=8,K=5时,所述Setm在时域上长度为34ms时,所述随机接入信道资源包括 0.4ms的保护时间。When N=8, K=5, when the set m has a length of 34 ms in the time domain, the random access channel resource includes a guard time of 0.4 ms.
- 根据权利要求35,38至41中任一项所述的方法,其中,时域相邻的两个Setm之间间隔V个第一时间单位,其中,V为整数,所述第一时间单位包括以下至少之一:一个或多个帧的时域长度、一个或多个子帧的时域长度、Z1秒、Z2毫秒、Z3个Setm的时域长度,Z4个Unit的时域长度,其中,Z1、Z2、Z3、Z4均为正整数。The method according to any one of claims 35, 38 to 41, wherein V first time units are spaced between two Set m adjacent to each other in the time domain, wherein V is an integer, the first time unit Including at least one of: time domain length of one or more frames, time domain length of one or more subframes, Z 1 second, Z 2 milliseconds, time domain length of Z 3 Set m , time of Z 4 Units The length of the domain, wherein Z 1 , Z 2 , Z 3 , and Z 4 are all positive integers.
- 根据权利要求36所述的方法,其中,时域相邻的两个Setm之间间隔V个第一时间单位,其中,V为整数,所述第一时间单位包括Z5个subset的时域长度,其中,Z5为正整数。The method according to claim 36, wherein V first time units are adjacent between two Set m adjacent to each other, wherein V is an integer, and said first time unit includes a time domain of Z 5 subsets Length, where Z 5 is a positive integer.
- 根据权利要求44或45所述的方法,其中,包括以下至少之一:A method according to claim 44 or 45, comprising at least one of the following:V的取值包括以下至少之一:V=0;V=2y,其中,y为大于或等于0的整数;The value of V includes at least one of the following: V=0; V=2 y , where y is an integer greater than or equal to 0;所述V个第一时间单位在时域上连续分布或离散分布;The V first time units are continuously distributed or discretely distributed in the time domain;所述时域相邻的两个Setm在频域上占用相同的所述F个子载波或子信道。The two Set m adjacent to the time domain occupy the same F subcarriers or subchannels in the frequency domain.
- 根据权利要求35,38至41中任一项所述的方法,其中,Setm的配置周期为L个第一时间单位,其中,L为正整数,所述第一时间单位包括以下至少之一:一个或多个帧的时域长度、一个或多个子帧的时域长度、Z1秒、Z2毫秒、Z3个Setm的时域长度,Z4个Unit的时域长度,其中,Z1、Z2、Z3、Z4均为正整数。The method according to any one of claims 35, 38 to 41, wherein the configuration period of Set m is L first time units, wherein L is a positive integer, and the first time unit comprises at least one of the following : the time domain length of one or more frames, the time domain length of one or more subframes, Z 1 second, Z 2 milliseconds, the time domain length of Z 3 Set m , the time domain length of Z 4 units, wherein Z 1 , Z 2 , Z 3 and Z 4 are all positive integers.
- 根据权利要求36所述的方法,其中,Setm的配置周期为L个第一时间单位,其中,L为正整数,所述第一时间单位包括Z5个subset的时域长度,Z5为正整数。A method according to claim 36, wherein, Set m arranged a first period of L time units, where, L is a positive integer, the unit includes first time domain length of a subset of Z 5, Z 5 is A positive integer.
- 根据权利要求47或48所述的方法,其中,L=2z,其中,z为大于或等于0的整数。A method according to claim 47 or 48, wherein L = 2 z , wherein z is an integer greater than or equal to zero.
- 根据权利要求49所述的方法,其中,包括以下至少之一:The method of claim 49, comprising at least one of the following:所述2z个第一时间单位在时域上连续分布或离散分布;The 2 z first time units are continuously distributed or discretely distributed in the time domain;z取值为{0,1,2,3,4,5,6,7};The value of z is {0,1,2,3,4,5,6,7};时域相邻的两个Setm在频域上占用相同的所述F个子载波或子信道。Two Set m adjacent in the time domain occupy the same F subcarriers or subchannels in the frequency domain.
- 根据权利要求36、47、48、49、50中任一项所述的方法,其中,在所述Setm的配置周期内最多配置L1个所述subset,所述subset的索引为subset0至subset(L1-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将所述Unit在时域 上重复Repetitiong次发送,在一个所述Setm的配置周期内,为等级索引为g的终端配置连续的Repetitiong个subset,且起始subset索引StartingSubsetIndexg按照下面公式计算:A method according to any one of claims 36,47,48,49,50, wherein L configuration. 1 and a maximum of the subset disposed within said period of Set m, indexes for the subset to subset subset0 (L 1 -1), wherein the subset configuration scheme corresponding to the terminal with the level index g includes: the terminal with the level index g sends the unit to repeat the Repetition g times in the time domain, and the configuration in one of the Set m During the period, consecutive Repetition g subsets are configured for the terminal with the level index g, and the starting subset index StartingSubsetIndex g is calculated according to the following formula:其中,0≤g≤G-1,G为划分的终端的等级的数量。Where 0 ≤ g ≤ G-1, and G is the number of levels of the divided terminals.
- 根据权利要求51所述的方法,其中,不同的所述Setm的配置周期之间,等级索引为g的终端对应的subset配置方案是相同的。The method according to claim 51, wherein between the configuration periods of the different Set m , the subset configuration scheme corresponding to the terminal with the level index g is the same.
- 根据权利要求36、47、48、49、50中任一项所述的方法,其中,在所述Setm的配置周期内最多配置L1个所述subset,所述subset的索引为subset0至subset(L1-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将所述Unit在时域上重复Repetitiong次发送,且为所述等级索引为g的终端配置连续的ChanceNumg×Repetitiong个subset,其中ChanceNumg≥1。A method according to any one of claims 36,47,48,49,50, wherein L configuration. 1 and a maximum of the subset disposed within said period of Set m, indexes for the subset to subset subset0 (L 1 -1), wherein the subset configuration scheme corresponding to the terminal with the level index g includes: the terminal with the level index g sends the unit to repeat the Repetition g times in the time domain, and the level index is g The terminal is configured with consecutive ChanceNum g ×Repetition g subsets, where ChanceNum g ≥1.
- 根据权利要求53所述的方法,其中,在一个所述Setm的配置周期内,所述ChanceNumg×Repetitiong个subset中起始subset索引StartingSubsetIndexg按照下面公式计算:The method according to claim 53, wherein, in a configuration period of said Set m , said starting subset index StartingSubsetIndex g in said ChanceNum g ×Repetition g subsets is calculated according to the following formula:其中,0≤g≤G-1,G为划分的终端的等级的数量。Where 0 ≤ g ≤ G-1, and G is the number of levels of the divided terminals.
- 根据权利要求54所述的方法,其中,起始subset索引为StartingSubsetIndexg的ChanceNumg×Repetitiong个subset中,配置有ChanceNumg个第一发送资源,其中,所述第一发送资源用于所述Unit在时域上重复Repetitiong次发送。The method according to claim 54, wherein the starting subset index is ChanceNum g × Repetition g subsets of StartingSubsetIndex g , and the first transmission resource is configured with ChanceNum g , wherein the first sending resource is used for the Unit repeats Repetition g times in the time domain.
- 根据权利要求36、47、48、49、50中任一项所述的方法,其中,在所述Setm的配置周期内最多配置L1个所述subset,所述subset的索引为subset0至subset(L1-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将所述Unit在时域上重复Repetitiong次发送,且所述等级索引为g的终端配置有ChanceNumg×Repetitiong个subset,ChanceNumg≥1。A method according to any one of claims 36,47,48,49,50, wherein L configuration. 1 and a maximum of the subset disposed within said period of Set m, indexes for the subset to subset subset0 (L 1 -1), wherein the subset configuration scheme corresponding to the terminal with the level index g includes: the terminal with the level index g sends the unit to repeat the Repetition g times in the time domain, and the level index is g The terminal is configured with ChanceNum g ×Repetition g subsets, and ChanceNum g ≥1.
- 根据权利要求57所述的方法,其中,在一个所述Setm的配置周期内,所述ChanceNumg×Repetitiong个subset的索引为subset0至subset(ChanceNumg×Repetitiong-1),且从subset0开始,索引连续的Repetitiong个subset为一个第一发送资源,其中,所述第一发送资源用于所述Unit在时域上重复Repetitiong次发送,一个所述第一发送资源内的Repetitiong个subset在时域上连续分布,不同的所述第一发送资源对应的subset在时域上离散分布。The method according to claim 57, wherein, in a configuration period of said Set m , an index of said ChanceNum g × Repetition g subsets is subset0 to subset (ChanceNum g × Repetition g -1), and from subset0 starts, a continuous index repetition g a subset of a first transmission resource, wherein the first transmission resource for the Unit on a time domain repetition times sent repetition g, within a repetition g of the first transmission resource The subsets are continuously distributed in the time domain, and different subsets corresponding to the first sending resource are discretely distributed in the time domain.
- 根据权利要求36、47、48、49、50中任一项所述的方法,其中,在所述Setm的配置周期内包括G个等级的终端对应的第一发送资源,其中,等级索引为g的终端对应的所述第一发送资源用于所述Unit在时域上重复Repetitiong次发送,等级索引为g的终端对应的所述第一发送资源大小为Ng个为级索引为g的终端对应的Setm,0≤g≤G-1。The method according to any one of claims 36, 47, 48, 49, 50, wherein the first transmission resource corresponding to the terminals of the G levels is included in the configuration period of the Set m , wherein the level index is The first transmission resource corresponding to the terminal of the g is used by the unit to repeat the Repetition g transmission in the time domain, and the size of the first transmission resource corresponding to the terminal with the level index g is N g Set m corresponding to the terminal whose index is g, 0 ≤ g ≤ G-1.
- 根据权利要求59所述的方法,其中,Ng≥1或Ng≥0,且当Ng=0时,表示在所述Setm的配置周期内没有配置等级索引为g的终端对应的所述第一发送资源。The method according to claim 59, wherein N g ≥ 1 or N g ≥ 0, and when N g =0, indicating that the terminal corresponding to the level index g is not configured in the configuration period of the Set m The first transmission resource is described.
- 根据权利要求59所述的方法,其中,在所述Setm的配置周期内,为等级索引为g的终端配置的Ng个资源中相邻的两个之间时域间隔为Lg个第二时间单位,其中,Lg≥0。The method according to claim 59, wherein, in the configuration period of said Set m , N g configured for a terminal having a level index of g Two adjacent in the resource The time domain interval is L g second time units, where L g ≥ 0.
- 根据权利要求62所述的方法,其中,不同等级索引的终端对应的Lg相同。 The method according to claim 62, wherein the same index different levels corresponding to the terminal L g.
- 根据权利要求59所述的方法,其中,The method of claim 59, wherein等级索引为g的终端对应的Ng个资源中第一个的时域起始资源位置与所述的配置周期内时域起始资源位置相同;或者,N g corresponding to the terminal whose rank index is g The first in the resource Time domain starting resource location with the stated The time domain starting resource location is the same during the configuration period; or,等级索引为g的终端对应的Ng个资源中第一个的时域起始资源位置与所述的配置周期内时域起始资源位置存在偏移量,其中,所述偏移量为预定的或者为基站配置的。N g corresponding to the terminal whose rank index is g The first in the resource Time domain starting resource location with the stated There is an offset in the time domain starting resource location within the configuration period, wherein the offset is predetermined or configured for the base station.
- 根据权利要求36所述的方法,其中,所述Setm的配置周期长度为D个Setm的时域长度,其中D为正整数。The length of the time-domain method according to claim 36, wherein the length of the arrangement period Set m is a Set m D, where D is a positive integer.
- 根据权利要求68所述的方法,其中,D=2x,x为大于或等于0的整数。The method of claim 68, wherein D = 2 x , x is an integer greater than or equal to zero.
- 根据权利要求68或69所述的方法,其中,在所述Setm的配置周期内最多配置D*P个所述subset,所述subset的索引为subset0至subset(D*P-1),其中,等级索引为g的终端对应的subset配置方案包括:等级索引为g的终端将所述Unit在时域上重复Repetitiong次发送,在一个所述Setm的配置周期内,为等级索引为g的终端配置连续的Repetitiong个subset,且起始subset索引StartingSubsetIndexg按照下面公式计算:The method according to claim 68 or 69, wherein a maximum of D*P of the subsets are configured in a configuration period of the Set m , and an index of the subset is subset0 to subset (D*P-1), wherein The subset configuration scheme corresponding to the terminal with the level index g includes: the terminal with the level index g sends the unit to repeat the Repetition g times in the time domain, and in the configuration period of the Set m , the level index is g. The terminal is configured with consecutive Repetition g subsets, and the starting subset index StartingSubsetIndex g is calculated according to the following formula:其中,0≤g≤G-1,G为划分的终端的等级的数量。Where 0 ≤ g ≤ G-1, and G is the number of levels of the divided terminals.
- 根据权利要求70所述的方法,其中,不同的所述Setm的配置周期之间,等级索引为g的终端对应的subset配置方案是相同的。 The method according to claim 70, wherein between the configuration periods of the different Set m , the subset configuration scheme corresponding to the terminal with the level index g is the same.
- 根据权利要求35所述的方法,其中,当上行带宽包括48个子载波间隔为3.75kHz的子载波时,所述子载波索引为0~47,其中,索引为0,1,14,15,16,17,30,31,32,33,46,47的子载波不配置给所述Setm。The method according to claim 35, wherein when the uplink bandwidth comprises 48 subcarriers with a subcarrier spacing of 3.75 kHz, the subcarrier index is 0 to 47, wherein the index is 0, 1, 14, 15, 16 The subcarriers of 17, 30, 31, 32, 33, 46, 47 are not allocated to the Set m .
- 根据权利要求35所述的方法,其中,当上行带宽包括48个子载波,所述子载波索引为0~47,F=24,且所述Setm的起始子载波索引为2时,索引为2~25的子载波配置给所述Setm。The method according to claim 35, wherein when the uplink bandwidth includes 48 subcarriers, the subcarrier index is 0 to 47, F=24, and the initial subcarrier index of the Set m is 2, the index is The subcarriers of 2 to 25 are allocated to the Set m .
- 根据权利要求35所述的方法,其中,当上行带宽包括48个子载波,所述子载波索引为0~47,F=36,且所述Setm的起始子载波索引为2时,索引为2~37的子载波配置给所述Setm。The method according to claim 35, wherein when the uplink bandwidth includes 48 subcarriers, the subcarrier index is 0 to 47, F=36, and the initial subcarrier index of the Set m is 2, the index is The subcarriers of 2 to 37 are allocated to the Set m .
- 根据权利要求35所述的方法,其中,当上行带宽包括48个子载波,所述子载波索引为0~47,F=24,且所述Setm的起始子载波索引为18时,索引为18~41的子载波配置给所述Setm。The method according to claim 35, wherein when the uplink bandwidth includes 48 subcarriers, the subcarrier index is 0 to 47, F=24, and the initial subcarrier index of the Set m is 18, the index is The subcarriers of 18 to 41 are allocated to the Set m .
- 根据权利要求72至75中任一项所述的方法,其中,所述Setm中的所述F个子载波中,随机接入信道占用的子载波数量Num在所述F个子载波中的比例为Ratio,其中,所述Ratio由所述基站通过信令发送给所述终端。The method according to any one of claims 72 to 75, wherein, among the F subcarriers in the Set m , the proportion of the number of subcarriers Num occupied by the random access channel in the F subcarriers is Ratio, wherein the Ratio is sent by the base station to the terminal by signaling.
- 根据权利要求76所述的方法,其中,所述F的取值为{12,24,36,48}。The method of claim 76, wherein the value of F is {12, 24, 36, 48}.
- 根据权利要求75或76所述的方法,其中,所述Ratio的取值为{1/6,2/6,3/6,4/6,5/6,6/6}或{1/12,2/12,3/12,4/12,5/12,6/12,7/12,8/12,9/12,10/12,11/12,12/12}或{0/12,1/12,2/12,3/12,4/12,5/12,6/12,7/12,8/12,9/12,10/12,11/12,12/12}或{0/6,1/6,2/6,3/6,4/6,5/6,6/6}。The method according to claim 75 or 76, wherein the ratio of the Ratio is {1/6, 2/6, 3/6, 4/6, 5/6, 6/6} or {1/12 , 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12, 9/12, 10/12, 11/12, 12/12} or {0/12 , 1/12, 2/12, 3/12, 4/12, 5/12, 6/12, 7/12, 8/12, 9/12, 10/12, 11/12, 12/12} or {0/6, 1/6, 2/6, 3/6, 4/6, 5/6, 6/6}.
- 根据权利要求35、72至75中任一项所述的方法,其中,所述Setm中的所述F个子载波中,用于发送随机接入信号的随机接入信道占用的子载波数量为Num。The method according to any one of claims 35, 72 to 75, wherein, among the F subcarriers in the Set m , the number of subcarriers occupied by the random access channel for transmitting the random access signal is Num.
- 根据权利要求79所述的方法,其中,所述F的取值为{12,24,36,48}。The method of claim 79, wherein the value of F is {12, 24, 36, 48}.
- 根据权利要求79或80所述的方法,其中,所述Num取值为{4,8,12,16,20,24,28,32,36,40,44,48}或{3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48}或{0,4,8,12,16,20,24,28,32,36,40,44,48}或{0,3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48}。The method according to claim 79 or 80, wherein said Num is {4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48} or {3, 6, 9,12,15,18,21,24,27,30,33,36,39,42,45,48} or {0,4,8,12,16,20,24,28,32,36, 40,44,48} or {0,3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48}.
- 根据权利要求35所述的方法,其中,所述终端向所述基站发送所述随机接入信号的所述随机接入信道由所述基站通过信令分配给所述终端。The method according to claim 35, wherein said random access channel in which said terminal transmits said random access signal to said base station is allocated to said terminal by said base station by signaling.
- 根据权利要求82所述的方法,其中,所述信令中包括以下信息至少之一: The method of claim 82, wherein the signaling includes at least one of the following information:起始的等级索引;Starting level index;所述基站分配给所述终端的所述随机接入信道所在的频域位置信息;Frequency domain location information of the random access channel allocated by the base station to the terminal;所述基站分配给所述终端的所述随机接入信道所在的时域位置信息。The time domain location information of the random access channel allocated by the base station to the terminal.
- 根据权利要求83所述的方法,其中,所述基站分配给所述终端的所述随机接入信道所在的频域位置信息包括:The method according to claim 83, wherein the frequency domain location information of the random access channel allocated by the base station to the terminal comprises:组成所述随机接入信号的单元Unit的Group0发送时所在的子载波或子信道索引。The subcarrier or subchannel index in which the Group 0 constituting the unit of the random access signal is transmitted.
- 根据权利要求83或84所述的方法,其中,当上行带宽包括48个子载波或子信道时,通过6bits指示信息指示基站分配给所述终端的所述随机接入信道所在的频域位置信息。The method according to claim 83 or 84, wherein when the uplink bandwidth comprises 48 subcarriers or subchannels, the frequency domain location information of the random access channel allocated by the base station to the terminal is indicated by the 6bits indication information.
- 根据权利要求85所述的方法,其中,所述6bits指示信息还用于指示所述终端在所述Setm中的F个子载波中随机选择一个子载波作为所述随机接入信道所在的频域位置。The method according to claim 85, wherein the 6bits indication information is further used to indicate that the terminal randomly selects one subcarrier among F subcarriers in the Set m as a frequency domain in which the random access channel is located. position.
- 根据权利要求83或84所述的方法,其中,当所述Setm中包括F个子载波或子信道时,通过指示信息指示基站分配给所述终端的所述随机接入信道所在的频域位置信息。The method according to claim 83 or 84, wherein when the Set m includes F subcarriers or subchannels, The indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal.
- 根据权利要求87所述的方法,其中,所述指示信息还用于指示所述终端在所述Setm中的F个子载波中随机选择一个子载波作为所述终端的所述随机接入信道所在的频域位置。The method of claim 87, wherein said Indication information indicating that the terminal is further configured to F subcarriers in the Set m in a randomly selected sub-carriers of the frequency domain position of the terminal as a random access channel is located.
- 根据权利要求83或84所述的方法,其中,当所述Setm中包括F个子载波或子信道时,通过指示信息指示基站分配给所述终端的所述随机接入信道所在的频域位置信息,其中,所述Num为所述随机接入信道占用的子载波数量。The method according to claim 83 or 84, wherein when the Set m includes F subcarriers or subchannels, The indication information indicates frequency domain location information of the random access channel allocated by the base station to the terminal, where the Num is the number of subcarriers occupied by the random access channel.
- 根据权利要求83所述的方法,其中,所述基站分配给所述终端的所述随机接入信道所在的时域位置信息包括:The method according to claim 83, wherein the time domain location information of the random access channel allocated by the base station to the terminal comprises:第二Setm的配置周期指示信息n;The configuration period indication information n of the second Set m ;其中,所述基站分配给所述终端的所述随机接入信道所在的Setm定义为第二Setm;所述第二Setm为从第一Setm中选择的;且第二Setm的配置周期长度为第一Setm的配置周期的n倍,n为正整数;所述第一Setm为所述随机接入信道资源包括的一个或多个时频资源集合Setm,n为正整数。 The Set m where the random access channel allocated by the base station to the terminal is defined as a second Set m ; the second Set m is selected from the first Set m ; and the second Set m The configuration period length is n times the configuration period of the first Set m , and n is a positive integer; the first Set m is one or more time-frequency resource sets Set m , n is positive for the random access channel resource Integer.
- 根据权利要求90所述的方法,其中,包括以下至少之一:The method of claim 90, comprising at least one of the following:当n的取值由3bit描述时,n的取值为{1,2,3,4,5,6,7,8}或{1,2,4,8,16,32,64,128}或{1,2,4,8,10,12,14,16};When the value of n is described by 3 bits, the value of n is {1, 2, 3, 4, 5, 6, 7, 8} or {1, 2, 4, 8, 16, 32, 64, 128} Or {1,2,4,8,10,12,14,16};当n的取值由2bit描述时,n的取值为{1,2,3,4}或{1,2,4,8}或{1,4,6,8}。When the value of n is described by 2 bits, the value of n is {1, 2, 3, 4} or {1, 2, 4, 8} or {1, 4, 6, 8}.
- 根据权利要求90或91所述的方法,其中,所述基站分配给所述终端的所述随机接入信道所在的时域位置为:所述第二Setm的配置周期内的第一个第一Setm。The method according to claim 90 or 91, wherein the time domain location of the random access channel allocated by the base station to the terminal is: the first one of the configuration periods of the second Set m A set of m .
- 根据权利要求90或91所述的方法,其中,所述基站分配给所述终端的所述随机接入信道所在的时域位置信息还包括:The method according to claim 90 or 91, wherein the time domain location information of the random access channel allocated by the base station to the terminal further includes:所述第二Setm在所述第二Setm的配置周期内的位置信息Offset;The second location information Offset Set m disposed within said second period of Set m;其中,所述Offset用于指示所述第二Setm的配置周期内的n个第一Setm中,分配给所述终端的所述随机接入信道所在的第一Setm的索引信息。Wherein said n first Offset Set m for the configuration of the second period indication Set m, the index information allocated to the random access channel, where the first terminal of the Set m.
- 根据权利要求83所述的方法,其中,所述基站分配给所述终端的所述随机接入信道所在的时域位置信息包括:The method according to claim 83, wherein the time domain location information of the random access channel allocated by the base station to the terminal comprises:连续两个第二Setm时域间隔信息Interval;Two consecutive second Set m time domain interval information Interval;所述基站分配给所述终端的所述随机接入信道所在的Setm定义为第二Setm;所述第二Setm为从第一Setm中选择的,且连续两个第二Setm之间间隔Interval个第一Setm;所示第一Setm为所述随机接入信道资源包括的一个或多个时频资源集合Setm。Set m of the random access channel allocated by the base station to the terminal is defined as a second Set m ; the second Set m is selected from the first Set m , and two second Set m are consecutive set m-frequency resource set first set m shows the random access channel resource comprises one or more; an interval between a first interval set m.
- 根据权利要求82至94中任一项所述的方法,其中,所述信令中还包括:触发定位操作指示信息。The method according to any one of claims 82 to 94, wherein the signaling further comprises: triggering positioning operation indication information.
- 根据权利要求95所述的方法,其中,所述触发定位操作指示信息为触发定位操作时,所述终端在所述信令分配的随机接入信道上发送所述随机接入信号。The method according to claim 95, wherein, when the trigger positioning operation indication information is a trigger positioning operation, the terminal transmits the random access signal on the random access channel allocated by the signaling.
- 根据权利要求1所述的方法,其中,所述终端在发送所述随机接入信号给所述基站之后,所述方法还包括:The method according to claim 1, wherein after the terminal sends the random access signal to the base station, the method further includes:所述终端接收所述基站检测所述随机接入信号后,根据检测结果发送的随机接入响应消息;其中,所述随机接入响应消息中包括以下信息中至少之一:Receiving, by the terminal, the random access response message that is sent according to the detection result after the base station detects the random access signal, where the random access response message includes at least one of the following information:子载波间隔指示信息; Subcarrier spacing indication information;配置的子载波数量指示信息。The configured number of subcarriers indicates information.
- 根据权利要求97所述的方法,其中,所述子载波间隔指示信息和所述配置的子载波数量指示信息通过联合编码方式指示。The method of claim 97, wherein the subcarrier spacing indication information and the configured subcarrier number indication information are indicated by joint coding.
- 一种接入处理装置,应用于终端中,包括:An access processing device is applied to the terminal, including:选择模块,设置为选择序列集合中与所述终端对应的序列;a selection module, configured to select a sequence corresponding to the terminal in the sequence set;生成模块,设置为至少根据所述对应的序列生成随机接入信号;Generating a module, configured to generate a random access signal according to at least the corresponding sequence;发送模块,设置为发送所述随机接入信号给基站。 And a sending module, configured to send the random access signal to the base station.
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