WO2017020283A1 - He-ltf sequence generation method, processing device, access point, and station - Google Patents

He-ltf sequence generation method, processing device, access point, and station Download PDF

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Publication number
WO2017020283A1
WO2017020283A1 PCT/CN2015/086184 CN2015086184W WO2017020283A1 WO 2017020283 A1 WO2017020283 A1 WO 2017020283A1 CN 2015086184 W CN2015086184 W CN 2015086184W WO 2017020283 A1 WO2017020283 A1 WO 2017020283A1
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ltf
papr value
ltf sequence
subcarrier
resource block
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PCT/CN2015/086184
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French (fr)
Chinese (zh)
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薛鑫
王宁娟
刘乐
林伟
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华为技术有限公司
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Priority to PCT/CN2015/086184 priority Critical patent/WO2017020283A1/en
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    • H—ELECTRICITY
    • H04—ELECTRIC COMMUNICATION TECHNIQUE
    • H04L—TRANSMISSION OF DIGITAL INFORMATION, e.g. TELEGRAPHIC COMMUNICATION
    • H04L5/00—Arrangements affording multiple use of the transmission path
    • H—ELECTRICITY
    • H04—ELECTRIC COMMUNICATION TECHNIQUE
    • H04W—WIRELESS COMMUNICATION NETWORKS
    • H04W72/00—Local resource management

Definitions

  • the present invention relates to the field of wireless communication technologies and, more particularly, to a method, an access point, and a station for transmitting information.
  • WLAN Wireless Local Area Network
  • Orthogonal Frequency Division Multiplexing OFDM
  • OFDMA Orthogonal Frequency Division Multiple Access
  • the OFDMA technology divides the air interface time-frequency resources into a plurality of orthogonal time-frequency resource blocks (RBs).
  • the RBs may be shared in time and orthogonal in the frequency domain.
  • the LTF of 80 MHz or the LTF of 160 MHz in the 802.11ac standard is used as a basic template, and the value of the carrier part corresponding to the resource block scheduled by the user in the OFDMA mode is extracted therefrom, and the value of the carrier part not corresponding to the resource block is padded with 0.
  • Embodiments of the present invention provide a method, an access point, and a station for transmitting LTF, which can reduce a peak average power ratio and improve channel estimation accuracy.
  • a method of transmitting an HE-LTF sequence comprising:
  • the HE-LTF sequence comprising a continuous sub-sequence Ga and a sub-sequence Gb, and +1 or -1 at a position of the spare leftover subcarrier; wherein Ga and Gb are complementary ;
  • the HE-LTF sequence is transmitted according to the RU size and the RU location in the resource allocation information.
  • the HE-LTF sequence further comprises: continuous -Ga and -Gb, or continuous +Ga and -Gb, or continuous -Ga and +Gb, or, or, continuous +Gb and -Ga, or part of Ga, Gb, -Ga, or -Gb.
  • the HE-LTF sequence is a downlink HE-LTF sequence sent by the AP, or is an uplink HE-LTF sequence sent by the STA.
  • an apparatus that can be used to perform the above method.
  • a site or access point containing the aforementioned means is also provided.
  • the foregoing method or device can solve the problem that in the 802.11ax standard scheme, in the OFDMA multi-user mode, the STA sends a HE-LTF sequence with a high PAPR, so that the PAPR value of the HE or LTF sequence sent by the STA or the AP is lower than the PAPR value of the data part. .
  • Figures 1a, 1b, and 1c are tone plans in an OFDMA transmission mode in 802.11ax.
  • 2a, 2b are schematic diagrams of PAPR if LTFs of 802.11ac are used.
  • FIG. 3 is a schematic diagram of a system architecture applicable to an embodiment of the present invention.
  • 4 and 5 are schematic flow charts of an embodiment of the present invention, respectively.
  • FIGS 6a-6d are schematic illustrations of various PAPRs in accordance with one embodiment of the present invention.
  • FIGS 7a-7d are schematic illustrations of various PAPRs in accordance with one embodiment of the present invention.
  • FIGS 8a-8e are schematic diagrams of various PAPRs in accordance with another embodiment of the present invention.
  • FIG. 9 is a block diagram of an access point in accordance with an embodiment of the present invention.
  • FIG. 10 is a block diagram of a station in accordance with an embodiment of the present invention.
  • An Access Point which can also be called a wireless access point or bridge or hotspot, can access a server or a communication network.
  • a station which may also be referred to as a user, may be a wireless sensor, a wireless communication terminal, or a mobile terminal, such as a mobile phone (or "cellular" phone) that supports WiFi communication functions and a computer with wireless communication capabilities.
  • a mobile phone or "cellular" phone
  • it may be a portable, pocket-sized, handheld, computer-built, wearable, or in-vehicle wireless communication device that supports WiFi communication functions, and exchanges communication data such as voice and data with the wireless access network.
  • 802.11ax is dedicated to further improving WLAN spectrum efficiency, regional throughput, actual user experience, and performance in a variety of indoor and outdoor dense network deployment environments.
  • the solution also requires suppression of inter-device interference to meet large-scale, high-load networking requirements. Wait.
  • OFDM symbols are constructed with 64-FFT in 20 MHz, 52 data subcarriers and 4 subcarriers in 56 subcarriers in total, and OFDM symbols are constructed with 128-FFT in 40 MHz, and 108 data subcarriers and 6 subcarriers in total 128 subcarriers
  • the carrier, while the 256-FFT constructs an OFDM symbol, has 234 data subcarriers and 8 subcarriers out of a total of 256 subcarriers.
  • the following tone plan (subcarrier distribution of data carrying) is adopted, and the positional relationship of different resource blocks (RU: resource unit) is as shown in FIG. 1a-1c, wherein the arrow indicates the residual subcarrier between the RUs.
  • the location, the number of large RU subcarriers and the corresponding number of small RUs that can be accommodated therein and the number of residual subcarriers between small RUs are the same. Referring to FIG.
  • FIG. 1a it is a simple schematic diagram of the location of an OFDMA resource block in a 20 MHz
  • FIG. 1b is a simplified location of an OFDMA resource block in a 40 MHz
  • a single schematic diagram, Figure 1c, is a simplified schematic diagram of the location of an OFDMA resource block within 80 MHz.
  • the OFDMA multi-user data packet in 802.11ax is a combination of multiple resource blocks (RU: resource unit).
  • the AP allocates one RU to each user.
  • the optional RUs that may be assigned to the user are:
  • RU consisting of 106 consecutive subcarriers: 24 data subcarriers and 2 pilot pilot subcarriers
  • RU consisting of 242 consecutive subcarriers: 234 data subcarriers and 8 pilot pilot subcarriers
  • RU consisting of 484 consecutive subcarriers: 468 data subcarriers and 16 pilot pilot subcarriers
  • RU consisting of 996 consecutive subcarriers: 980 data subcarriers and 16 pilot pilot subcarriers
  • 484-RU is used in 40MHz multi-user transmission
  • 996-RU is used in 80/160MHz multi-user transmission.
  • 160MHz can be seen as a combination of two 80MHz tone plans.
  • the HE-LTF for channel estimation in the 802.11ax system adopts two modes of 2x and 4x, the subcarrier number index of the 4x HE-LTF sequence mapping is the same as the data part tone plan, and the 2x HE-LTF serial number corresponds to 4x.
  • the number of HE-LTF numbers is divided by 2.
  • the tone plan of the OFDMA transmission in the 802.11ax system is different from the tone plan of the OFDM in the existing 802.11ac system. Therefore, the 20/40 VHT-LTF sequence defined in 802.11ac itself cannot be applied.
  • the total number of subcarriers of 80 MHz in 802.11ac is the same as the total number of subcarriers of 20 MHz in 802.11ax, but the peak value and the mean ratio (PAPR: Peak-to) are found directly in the 802.11ax 20 MHz bandwidth using the VHT-LTF sequence. -average power ratio) is relatively high. Referring to FIGS.
  • 802.11ax is in 40/80MHz tone plan, the number of subcarriers has exceeded the traditional sequence, and the VHT-LTF sequence of 802.11ac cannot be reused.
  • FIG. 3 is a simplified schematic diagram of a WLAN system to which an embodiment of the present invention is applied.
  • the system of Figure 3 includes one or more access points AP 101 and one or more stations STA 102.
  • the OFDMA technology is used for wireless communication between the access point 101 and the station 102.
  • 2x and 4x HE-LTF sequences that can be applied to the 20 MHz/40 MHz/80 MHz subcarrier plan of the aforementioned 802.11ax system.
  • the RUs of different sizes satisfy the low PAPR sequence, especially for the small RU (26/52-).
  • the edge user, the transmit power itself is close to the maximum value, and the lower PAPR can guarantee the working range of the amplifier.
  • at least part of the sequence in the present embodiment can also make the storage amount on the product low and easy to implement.
  • a method of transmitting an HE-LTF sequence including:
  • the HE-LTF sequence comprising a continuous sub-sequence Ga and a sub-sequence Gb, and +1 or -1 at a position of the spare leftover subcarrier; wherein Ga and Gb are complementary ;
  • the HE-LTF sequence is transmitted according to the RU size and the RU location in the resource allocation information.
  • the HE-LTF sequence further comprises: continuous -Ga and -Gb, or continuous +Ga and -Gb, or continuous -Ga and +Gb, or, or, continuous +Gb and -Ga.
  • the foregoing method may be a downlink HE-LTF sequence sent by the AP, or may be an uplink HE-LTF sequence sent by the STA.
  • a method is provided in which the receiving side receives and processes the corresponding HE-LTF sequence.
  • the access point AP sends a data packet PPDU (for example, 802.11ax), and the PPDU includes HE-LTF, HE-SIG-A, and HE-SIG-B, where the HE-SIG-A is included to indicate the downlink user.
  • the information of the STA transmission bandwidth includes information indicating the downlink scheduled STA ID and the RU size and location allocated for the STA, and the stream number in the HE-SIG-B.
  • the HE-LTF length that is, the number of symbols N, for indicating alignment of a plurality of users may be included in the HE-SIG-A or HE-SIG-B.
  • the process of sending the HE-LTF sequence in the process of sending the PPDU includes:
  • the AP selects a HE-LTF sequence corresponding to the bandwidth according to the transmission bandwidth size (refer to the total bandwidth shared by multiple users).
  • the AP selects a corresponding HE-LTF sequence segment from the HE-LTF sequence for each resource block RU size and RU location allocated by each downlink scheduled user, and each HE- The LTF sequence segments are mapped at the assigned RU subcarrier locations.
  • a scrambling Mask matrix of size NxN for example, P-matrix
  • Matrix or Walsh matrix or other suitable A row in the matrix is used as a signature for distinguishing the spatial stream.
  • the tone plan on the nth symbol of the HE-LTF removes the portion other than the pilot subcarrier position, multiplied by Corresponding to the nth bit codeword that distinguishes the feature code of the stream.
  • the protocol stipulates that the pilot participates in the scrambling, when the AP transmits the HE-LTF sequence of each stream on the RU, the subcarriers in the tone plan on the nth symbol of the HE-LTF are multiplied by the nth corresponding to the signature of the stream. Bit code word.
  • the scheduled STA receives the data packet PPDU (for example, 802.11ax), including the following processing:
  • the scheduled STA receives the HE-SIG-A, and obtains the total transmission bandwidth indicated in the HE-SIG-A.
  • S202 Select an HE-LTF sequence corresponding to the bandwidth according to the total bandwidth of the transmission
  • the scheduled STA receives the HE-SIG-B, and uses its own STA ID to identify its own scheduled indication information, where the AP allocates the RU size and the RU location allocated to the user.
  • Corresponding HE-LTF sequence segments are selected from the HE-LTF sequence according to the indicated RU size and location as a channel estimation reference sequence corresponding to the RU of the receiving end.
  • the scheduled STA receives the HE-LTF length N included in the HE-SIG-A or HE-SIG-B, and selects a scrambling Mask matrix of NxN (English may be Scramble) (for example, a P-matrix matrix or a Walsh matrix) As a code matrix for distinguishing spatial streams.
  • a scrambling Mask matrix of NxN English may be Scramble
  • a P-matrix matrix or a Walsh matrix for example, a P-matrix matrix or a Walsh matrix
  • the estimated reference sequence is multiplied by the nth codeword in the reference codeword corresponding to the stream, and constitutes a receiver reference sequence for receiving the nth HE-LTF symbol for channel estimation.
  • the AP indicates the uplink scheduling information by using the trigger frame, including the uplink user STA transmission bandwidth, the uplink scheduled STA ID, the RU size and location allocated for the STA, and the HE-LTF length of the uplink user aligned.
  • the STA transmits a data packet PPDU (for example, 802.11ax) according to the uplink scheduling information.
  • the STA selects a pair according to the indicated transmission bandwidth size (refer to the total bandwidth shared by multiple users).
  • the bandwidth should be HE-LTF sequence.
  • the STA selects a corresponding HE-LTF sequence segment from the HE-LTF sequence to be mapped on the allocated RU subcarrier position in the resource block RU size and the RU location allocated in the bandwidth (total bandwidth).
  • the STA repeats the HE-LTF sequence N times in time according to the indicated HE-LTF length. If the RU where the user is located includes multiple spatial streams or multi-user transmission, when the STA transmits the corresponding stream, the STA allocates according to the AP.
  • the i-th stream selects the i-th row in the scrambled Mask matrix of NxN (English may be Scramble) (for example, P-matrix matrix or Walsh matrix) as the signature of the distinguishing stream.
  • the subcarriers in the tone plan on the nth symbol of the HE-LTF are multiplied by the corresponding feature code corresponding to the stream. N-bit code word.
  • the method includes
  • the AP selects a HE-LTF sequence corresponding to the bandwidth according to the size of the transmission bandwidth.
  • the AP selects a corresponding HE-LTF sequence segment from the HE-LTF sequence in the resource block RU size and the RU location allocated to each uplink scheduled user in the total bandwidth as a reference sequence of the RU.
  • the HE-LTF reference sequence needs to be repeated N times in time, and the AP allocates one line in the P-matrix matrix of size NxN to each stream on the RU as a distinction.
  • the signature of the stream Specifically, the reference sequence on the nth HE-LTF symbol of each stream on the RU is multiplied by the nth bit codeword corresponding to the feature code used to distinguish the stream, and is used as a channel estimation for receiving the ith stream corresponding to the RU. Reference sequence for channel estimation.
  • the transmitter sends different HE-LTF sequences according to different bandwidth sizes, RU positions, and RU sizes, including (can be applied to 802.11ax).
  • the solution of this embodiment in the standard or other feasible standards may be combined with the foregoing embodiment 1 or embodiment 2) (not shown):
  • an LTF sequence (or a sequence for channel estimation, such as HE-LTF, which is a possible name) according to the bandwidth, the LTF sequence including a continuous sub-sequence Ga and a sub-sequence Gb, located at +1 or -1 on the leftover subcarrier position; the Ga and Gb sequences have a sequence pair of complementary characteristics.
  • the Ga and Gb sequences are a length of 26 or 13 or other lengths, and have mutual A sequence pair of complementary features.
  • Ga and Gb sequences are:
  • Ga ⁇ +1 +1 +1 +1 +1 -1 +1 +1 -1 +1 -1 +1 -1 +1 -1 +1 +1 +1 +1 -1 -1 + 1 +1 +1 ⁇
  • Gb ⁇ +1 -1 +1 +1 -1 -1 +1 -1 -1 -1 +1 +1 +1 +1 +1 +1 -1 -1 +1 +1 - 1 +1 -1 ⁇
  • the HE-LTF sequence may further include: continuous -Ga and -Gb, or continuous Ga and - Gb, or, continuous -Ga and Gb, or, continuous -Gb and Ga, or a portion of Ga, Gb, -Ga, or -Gb. Specifically, half of them such as Ga (1:13) and Ga (14:26), Gb (1:13), and Gb (14:26) can be omitted.
  • a method for constructing an HE-LTF sequence for the size and location of different resource blocks RU in an 802.11ax OFDMA tone plan including:
  • the length of the basic HE-LTF sequence being the same as the length of the small RU in the OFDMA transmission mode, such as 26, or 52.
  • the basic HE-LTF sequence is, for example, the aforementioned Ga or Gb.
  • HE-LTF sequence of a large RU by cascading a number of basic HE-LTF sequences after the phase rotation; further, fill the +1 or the position of the residual subcarriers between the small RUs corresponding to the large RU or -1.
  • the small RU is cascaded to the large RU, and the PAPR optimal PAPR sequence of each RU is selected as the HE-LTF sequence corresponding to the bandwidth.
  • the HE-LTF sequence constructed according to the foregoing method may be separately stored on the AP and the STA, so as to facilitate subsequent transmission.
  • the transmission process reference may be made to Embodiment 2 of the foregoing Embodiment.
  • a subcarrier allocation mode of 20 MHz bandwidth is used.
  • the RU size may be 26, 52, 106, 242 subcarriers as shown in FIG. 1a.
  • a plurality of HE-LTF sequences on the 4X symbol of the 20 MHz 242 subcarrier are provided in this embodiment, and only a few of them are listed below:
  • the HE-LTF sequence is as follows:
  • He_ltf_20mhz [ ⁇ 0,0,0,0,0 ⁇ ,...
  • HELTF -122,122 ⁇ +1,+Gb,-Ga,-1,+Gb,+Ga,+Ga(1:13),-1,-1,
  • the HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive +Gb and -Ga, or consecutive +Gb and +Ga, or continuous +Gb And -Ga, or, -Gb and -Ga, or Ga (1:13) and Ga (14:26).
  • Figure 6a is a schematic diagram of the PAPR (peak-to-average ratio) values of the HE-LTF sequence at 20 MHz bandwidth.
  • the first line of numbers is 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, which in turn
  • the PAPR value corresponding to the first row 26 subcarrier resource block, that is, 3.01 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 2.97 refers to the second 26 subcarrier resources from left to right.
  • the block corresponds to the PAPR value, and so on; the second row number is 3.01, 3.00, 3.01, 3.00, which in turn is the PAPR value corresponding to the second row 52 subcarrier resource block, that is, the first 3.01 refers to the first from left to right.
  • the 52 subcarrier resource blocks correspond to the PAPR value, 3.00 refers to the PAPR value corresponding to the second 52 subcarrier resource blocks from left to right; the third row number is 4.00, 3.52, which in turn is the third row 106 subcarrier resource block corresponding
  • the PAPR value that is, the first 4.00 refers to the corresponding PAPR value of the first 106 subcarrier resource block from left to right, and 3.52 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right; the third row of numbers 4.28 corresponds to the PAPR value of the 242 subcarrier resource block.
  • the HE-LTF sequence is as follows:
  • He_ltf_20mhz [ ⁇ 0,0,0,0,0 ⁇ ,...
  • HELTF -122,122 ⁇ +1,-Ga,+Gb,-1,+Ga,+Gb,+Ga(1:13),+1,+1,
  • the HE-LTF sequence includes consecutive Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive -Ga and +Gb, or consecutive +Ga and +Gb, or continuous -Ga and -Gb, or, Ga (1:13) and Ga (14:26).
  • Figure 6b shows the PAPR value of the HE-LTF sequence at 20 MHz bandwidth.
  • the first row of numbers is 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, which in turn is the PAPR value corresponding to the first row of 26 subcarrier resource blocks, that is, 2.97 refers to the first 26 from left to right.
  • the subcarrier resource block corresponds to the PAPR value
  • the next 3.01 refers to the PAPR value corresponding to the second 26 subcarrier resource block from left to right.
  • the second row of numbers is 3.00, 3.01, 3.00, 3.01, which in turn is the PAPR value corresponding to the second row 52 subcarrier resource block, that is, the first 3.00 refers to the first 52 subcarrier resources from left to right.
  • the block corresponds to the PAPR value, and 3.01 refers to the PAPR value corresponding to the second 52 subcarrier resource block from left to right; the third row number is 3.81 and 3.90, which in turn is the PAPR value corresponding to the third row 106 subcarrier resource block, that is,
  • the first 3.81 refers to the corresponding PAPR value of the first 106 subcarrier resource blocks from left to right
  • 3.90 refers to the corresponding PAPR value of the second 106 subcarrier resource blocks from left to right
  • the third row of numbers 4.29 corresponds to 242.
  • the PAPR value of the subcarrier resource block 3.01 refers to the PAPR value corresponding to the second 52 subcarrier resource block from left to right
  • the third row number is 3.81 and 3.90, which in turn is the PAPR value corresponding to the third row 106 subcarrier resource block, that is,
  • the first 3.81 refers to the corresponding PAPR value of the first 106 subcarrier resource blocks from left to right
  • 3.90 refers to the
  • the HE-LTF sequence is as follows:
  • He_ltf_20mhz [ ⁇ 0,0,0,0,0 ⁇ ,...
  • HELTF -122,122 ⁇ +1,-Ga,+Gb,+1,+Ga,+Gb,+Gb(1:13),+1,-1,
  • the HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive -Ga and +Gb, or continuous +Ga and +Gb, or continuous -Ga And -Gb, or, Gb (1:13) and Gb (14:26).
  • Figure 6c shows the PAPR value of the HE-LTF sequence in the 20MHz bandwidth.
  • the first row of numbers is 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, which in turn is the PAPR corresponding to the first row 26 subcarrier resource blocks.
  • the value, that is, 2.97 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 3.01 refers to the PAPR value corresponding to the second 26 subcarrier resource blocks from left to right, and so on;
  • the numbers are 3.00, 3.01, 3.00, 3.01, which in turn are the PAPR values corresponding to the second row 52 subcarrier resource blocks, that is, the first 3.00 refers to the first 52 subcarrier resource blocks from left to right.
  • the PAPR value corresponds to the PAPR value corresponding to the second 52 subcarrier resource block from left to right; the third row number is 3.94, 3.89, which in turn is the PAPR value corresponding to the third row 106 subcarrier resource block, that is, the first A 3.94 refers to the corresponding PAPR value of the first 106 subcarrier resource blocks from left to right, 3.89 refers to the corresponding PAPR value of the second 106 subcarrier resource blocks from left to right; the third line number 4.30 corresponds to 242 sub The PAPR value of the carrier resource block.
  • the HE-LTF sequence is as follows:
  • He_ltf_20mhz [ ⁇ 0,0,0,0,0 ⁇ ,...
  • HELTF -122,122 ⁇ +1,-Gb,+Ga,+1,+Gb,+Ga,+Gb(1:13),+1,-1,
  • the HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive -Gb and +Ga, or consecutive +Gb and +Ga, or continuous +Gb And -Ga, or, Gb (1:13) and Gb (14:26).
  • Figure 6d shows the PAPR value of the HE-LTF sequence in the 20 MHz bandwidth.
  • the first row of numbers is 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, which in turn is the PAPR corresponding to the first row 26 subcarrier resource blocks.
  • the value, that is, 3.01 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 2.97 refers to the corresponding PAPR value of the second 26 subcarrier resource blocks from left to right, and so on;
  • the numbers are 3.01, 3.01, 3.01, and 3.01, which in turn are the PAPR values corresponding to the second row 52 subcarrier resource blocks, that is, the first 3.01 refers to the corresponding PAPR value of the first 52 subcarrier resource blocks from left to right.
  • Two 3.01 means that the second 52 subcarrier resource blocks correspond to PAPR from left to right.
  • the third row number is 3.69, 3.81, which in turn is the PAPR value corresponding to the third row 106 subcarrier resource block, that is, the first 3.69 refers to the PAPR value corresponding to the first 106 subcarrier resource block from left to right. 3.81 refers to the PAPR value corresponding to the second 106 subcarrier resource block from left to right; the third row number 4.45 corresponds to the PAPR value of the 242 subcarrier resource block.
  • FIG. 1b a schematic diagram of a subcarrier allocation manner of a possible 40 MHz bandwidth in the 802.11ax standard:
  • the RU size may be 26, 52, 106, 242, 484 subcarriers as shown.
  • HELTF -244,244 ⁇ +1,+Ga,-Gb,+1,-1,-Ga,-Gb,-1,+Ga,+1,+Ga,-Gb,+1,+1,+Ga, +Gb, -1,
  • the HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, continuous -Ga and -Gb, or continuous +Ga and +Gb, or continuous +Ga And -Gb, or, continuous -Ga and +Gb.
  • the first row number is 2.97, 3.01, 2.97, 3.01, etc., which in turn is the PAPR value corresponding to the first row 26 subcarrier resource block, ie 2.97 refers to The first 26 subcarrier resource blocks from left to right correspond to the PAPR value, and the next 3.01 refers to the PAPR value corresponding to the second 26 subcarrier resource blocks from left to right, and so on; the second row number is 3.01, 3.01.
  • 3.01, 3.01, etc. which in turn are the PAPR values corresponding to the second row 52 subcarrier resource blocks, that is, the first 3.01 refers to the corresponding PAPR value of the first 52 subcarrier resource blocks from left to right, and 3.01 refers to the left.
  • the second 52 subcarrier resource block to the right corresponds to the PAPR value;
  • the third row number is 3.92, 3.96, etc., which in turn is the PAPR value corresponding to the third row 106 subcarrier resource block, that is, the first 3.92 refers to the leftward direction.
  • the first 106 subcarrier resource block corresponds to the PAPR value, and 3.96 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right; the fourth row number is 4.48 and 4.46, which in turn is 242 subcarrier resource block corresponding
  • the PAPR value corresponds to the PAPR value of the 242 subcarrier resource block; the fifth line number 4.64 is the 484 subcarrier resource. Corresponding PAPR value.
  • He_ltf_40Mhz [ ⁇ 0,0,0,0,0,0,0,0,0,0,0,0 ⁇ ,...
  • HELTF -244,244 ⁇ +1,-Ga,-Gb,-1,-1,+Ga,-Gb,+1,-Gb,-1,-Ga,-Gb,+1,-1,-Ga, +Gb, -1,
  • the HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, continuous -Ga and -Gb, or continuous +Ga and +Gb, or continuous +Ga And -Gb, or, continuous -Ga and +Gb.
  • the first line number is 2.97, 3.01, 2.97, 3.01, etc., which is the PAPR value corresponding to the first row 26 subcarrier resource block from left to right. That is, 2.97 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 3.01 refers to the corresponding PAPR value of the second 26 subcarrier resource blocks from left to right, and so on; the second line is 3.01, 3.01, 3.01, 3.01, etc., from left to right, the PAPR value corresponding to the second row 52 subcarrier resource block, that is, the first 3.01 refers to the first 52 subcarrier resource block corresponding from left to right.
  • the PAPR value, 3.01 refers to the PAPR value corresponding to the second 52 subcarrier resource block from left to right; the third row number is 3.74, 3.81, etc., which is the PAPR corresponding to the third row 106 subcarrier resource block from left to right.
  • the value, that is, the first 3.74 refers to the PAPR value corresponding to the first 106 subcarrier resource block from left to right, and the 3.81 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right; the fourth line number is 4.59. 4.30, which is the PAPR value corresponding to the 242 subcarrier resource block from left to right, and 4.59 refers to the first 242 subcarrier from left to right.
  • the wave resource block corresponds to the PAPR value; the fifth row number 4.60 is the PAPR value corresponding to the 484 subcarrier resource block.
  • He_ltf_40Mhz [ ⁇ 0,0,0,0,0,0,0,0,0,0,0,0 ⁇ ,...
  • HELTF -244,244 ⁇ +1,-Gb,-Ga,+1,-1,-Gb,+Ga,-1,-Ga,+1,+Gb,+Ga,+1,+1,-Gb, +Ga, +1,
  • the HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive -Gb and -Ga, or consecutive -Gb and +Ga, or continuous +Gb And +Ga, or, continuous +Gb and -Ga.
  • the first row number is 3.01, 2.97, 3.01, 2.97, etc., which is the PAPR value corresponding to the first row 26 subcarrier resource block from left to right. That is, 3.0072 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 2.97 refers to the corresponding PAPR value of the second 26 subcarrier resource blocks from left to right, and so on; the second line is 3.01, 3.01, 3.01, 3.01, etc., from left to right, the PAPR value corresponding to the second row 52 subcarrier resource block, that is, the first 3.01 refers to the first 52 subcarrier resource block corresponding from left to right.
  • the PAPR value, 3.01 refers to the PAPR value corresponding to the second 52 subcarrier resource block from left to right; the third row number is 3.76, 3.87, etc., which is the PAPR corresponding to the third row 106 subcarrier resource block from left to right.
  • the value, that is, the first 3.76 refers to the PAPR value corresponding to the first 106 subcarrier resource block from left to right, and 3.87 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right;
  • the fourth line number is 4.59. 4.57, which is the PAPR value corresponding to the 242 subcarrier resource block from left to right, and 4.59 refers to the first 242 subtitle from left to right.
  • Wave PAPR value corresponding to the resource blocks; fifth line 484 is 4.59 digital value PAPR sub-carriers corresponding to the resource blocks.
  • He_ltf_40Mhz [ ⁇ 0,0,0,0,0,0,0,0,0,0,0,0 ⁇ ,...
  • HELTF -244,244 ⁇ +1,+Gb,+Ga,-1,-1,-Gb,+Ga,+1,-Gb,+1,-Gb,-Ga,-1,+1,-Gb, +Ga, -1,
  • the HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive -Gb and -Ga, or consecutive -Gb and +Ga, or continuous +Gb And +Ga, or, continuous +Gb and -Ga.
  • the first row number is 3.01, 2.97, 3.01, 2.97, etc., which is the PAPR value corresponding to the first row 26 subcarrier resource block from left to right. That is, 3.0072 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 2.97 refers to the corresponding PAPR value of the second 26 subcarrier resource blocks from left to right, and so on; the second line is 3.01, 3.01, 3.01, 3.01, etc., from left to right, the PAPR value corresponding to the second row 52 subcarrier resource block, that is, the first 3.01 refers to the first 52 subcarrier resource block corresponding from left to right.
  • the PAPR value, the second 3.01 refers to the second 52 subcarrier resource block corresponding to the PAPR value from left to right; the third row number is 3.65, 3.88, etc., which is the third row 106 subcarrier resource block from left to right.
  • the corresponding PAPR value that is, the first 3.65 refers to the corresponding PAPR value of the first 106 subcarrier resource block from left to right, and 3.88 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right; the fourth row
  • the numbers are 4.57 and 4.52, which are the PAPR values corresponding to the 242 subcarrier resource blocks from left to right, and 4.57 refers to the first from left to right.
  • fifth line 484 is 4.62 digital subcarrier resource block corresponding PAPR value.
  • FIG. 1c it is a simple schematic diagram of a subcarrier allocation manner of an 80 MHz bandwidth in the 802.11ax standard.
  • the RU size may be 26, 52, 106, 242, 484, 996 subcarriers as shown in FIG. 1c.
  • He_ltf_80mhz [ ⁇ 0,0,0,0,0,0,0,0,0,0,0,0 ⁇ ,...
  • HELTF -500,500 ⁇ -1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Gb,-1,-Ga,+Gb,+1,+1,-Ga, -Gb, -1,
  • the HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive -Gb and -Ga, or consecutive -Gb and +Ga, or continuous +Gb And +Ga, or consecutive +Gb and -Ga, and the two lines of the red mark in the HE-LTF sequence are identical, and the two lines of the blue mark are opposite in polarity.
  • the 8a shows the PAPR value of the HE-LTF sequence in the 80 MHz bandwidth, the first line number is 2.97, 3.01, 2.97, 3.01, etc., which is the PAPR value corresponding to the first row 26 subcarrier resource block from left to right.
  • 2.97 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right
  • the next 3.01 refers to the corresponding PAPR value of the second 26 subcarrier resource blocks from left to right, and so on
  • the second line is 3.01, 3.01, etc., from left to right
  • the PAPR value corresponding to the second row 52 subcarrier resource block that is, the first 3.01 refers to the PAPR value corresponding to the first 52 subcarrier resource block from left to right
  • the two 3.01s refer to the PAPR value corresponding to the second 52 subcarrier resource block from left to right
  • the third row number is 3.91, 3.91, etc., which is the PAPR value corresponding to the third row 106 subcarrier resource block from left to right.
  • the first 3.91 refers to the PAPR value corresponding to the first 106 subcarrier resource block from left to right
  • the second 3.91 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right
  • the fourth row of numbers Is 4.51, 4.56, etc., from left to right, the PAPR value corresponding to the 242 subcarrier resource block, and 4.51 refers to the first from left to right.
  • the 242 subcarrier resource block corresponds to the PAPR value
  • the fifth row number is 4.70, 4.77, etc., which is the PAPR value corresponding to the 242 subcarrier resource block from left to right
  • 4.70 refers to the first 484 subcarrier resource from left to right.
  • the block corresponds to the PAPR value
  • the sixth line number 4.91 is the PAPR value corresponding to the 996 subcarrier subcarrier resource block.
  • He_ltf_80mhz [ ⁇ 0,0,0,0,0,0,0,0,0,0,0,0 ⁇ ,...
  • HELTF -500,500 ⁇ -1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Gb,-1,-Ga,+Gb,+1,+1,-Ga, -Gb, -1,
  • the HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive -Ga and +Gb, or continuous +Ga and +Gb, or continuous -Ga And +Gb, or, consecutive -Ga and -Gb, or, Gb (1:13) and Gb (14:26).
  • Figure 8b shows the PAPR value of the HE-LTF sequence in the 80MHz bandwidth.
  • the first row of numbers is 2.97, 3.01, 2.97, 3.01, etc., which is the PAPR value corresponding to the first row of 26 subcarrier resource blocks from left to right.
  • 2.97 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right
  • the next 3.01 refers to the corresponding PAPR value of the second 26 subcarrier resource blocks from left to right, and so on
  • the second line is 3.01, 3.01, etc., from left to right
  • the PAPR value corresponding to the second row 52 subcarrier resource block that is, the first 3.01 refers to the PAPR value corresponding to the first 52 subcarrier resource block from left to right
  • the two 3.01s refer to the PAPR value corresponding to the second 52 subcarrier resource block from left to right
  • the third row number is 3.91, 3.91, etc., which is the PAPR value corresponding to the third row 106 subcarrier resource block from left to right.
  • the first 3.91 refers to the PAPR value corresponding to the first 106 subcarrier resource block from left to right
  • the second 3.91 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right
  • the fourth row of numbers It is 4.50, 4.56, etc., which is the PAPR value corresponding to the 242 subcarrier resource block from left to right
  • 4.50 refers to the first from left to right.
  • the 242 subcarrier resource block corresponds to the PAPR value
  • the fifth row number is 4.70, 4.76, etc., which is the PAPR value corresponding to the 242 subcarrier resource block from left to right
  • 4.70 refers to the first 484 subcarrier resource from left to right.
  • the block corresponds to the PAPR value
  • the sixth line number 4.92 is the PAPR value corresponding to the 996 subcarrier subcarrier resource block.
  • He_ltf_80mhz [ ⁇ 0,0,0,0,0,0,0,0,0,0,0,0 ⁇ ,...
  • HE LTF -500,500 ⁇ +1,+Ga,-Gb,-1,-1,-Ga,-Gb,+1,-Ga,-1,+Ga,-Gb,+1,+1,+Ga , +Gb, -1,
  • the HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, +Ga and -Gb consecutive, or continuous -Ga and -Gb, or continuous +Ga And +Gb, or, consecutive -Ga and +Gb, or, Gb (1:13) and Gb (14:26).
  • Figure 8c shows the PAPR value of the HE-LTF sequence at 80MHz bandwidth.
  • the first line number is 2.97, 3.01. 2.97, 3.01, etc., from left to right, is the PAPR value corresponding to the first row 26 subcarrier resource block, that is, 2.97 refers to the PAPR value corresponding to the first 26 subcarrier resource block from left to right, and the next 3.01 It refers to the PAPR value corresponding to the second 26 subcarrier resource block from left to right, and so on; the second row number is 3.01, 3.01, etc., which is the PAPR corresponding to the second row 52 subcarrier resource block from left to right.
  • the value of the first 3.01 refers to the corresponding PAPR value of the first 52 subcarrier resource block from left to right, and the second 3.01 refers to the corresponding PAPR value of the second 52 subcarrier resource block from left to right; the third line
  • the number is 3.91, 3.96, etc., which is the PAPR value corresponding to the third row 106 subcarrier resource block from left to right, that is, the first 3.91 refers to the corresponding PAPR value of the first 106 subcarrier resource block from left to right.
  • 3.96 refers to the PAPR value corresponding to the second 106 subcarrier resource block from left to right; the fourth row number is 4.53, 4.56, etc., which is the PAPR value corresponding to the 242 subcarrier resource block from left to right, and 4.53 refers to The first 242 subcarrier resource block from left to right corresponds to the PAPR value; the fifth row number is 4.90, 4.82, etc., from left to right. In turn, it is the PAPR value corresponding to the 242 subcarrier resource block, 4.90 refers to the PAPR value corresponding to the first 484 subcarrier resource block from left to right, and the sixth line number 4.97 is the PAPR value corresponding to the 996 subcarrier subcarrier resource block.
  • He_ltf_80mhz [ ⁇ 0,0,0,0,0,0,0,0,0,0,0,0 ⁇ ,...
  • HE LTF -500,500 ⁇ -1,+Gb,+Ga,-1,-1,-Gb,+Ga,-1,-Ga,-1,+Gb,+Ga,-1,+1,+Gb , -Ga, +1,
  • the HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive +Gb and +Ga, or consecutive -Gb and +Ga, or continuous +Gb And +Ga, or, continuous -Gb and -Ga, or Ga (1:13) and Ga (14:26).
  • Figure 8d shows the PAPR value of the HE-LTF sequence in the 80MHz bandwidth.
  • the first row of numbers is 3.01, 2.97, 3.01, 2.97, etc., which is the PAPR value corresponding to the first row 26 subcarrier resource blocks from left to right.
  • 3.01 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right
  • the next 2.97 refers to the corresponding PAPR value of the second 26 subcarrier resource blocks from left to right, and so on
  • the second line is 3.01, 3.01, etc., from left to right
  • the PAPR value corresponding to the second row 52 subcarrier resource block that is, the first 3.01 refers to the PAPR value corresponding to the first 52 subcarrier resource block from left to right
  • the two 3.01s refer to the PAPR value corresponding to the second 52 subcarrier resource block from left to right
  • the third row number is 3.66, 3.77, etc., which is the PAPR value corresponding to the third row 106 subcarrier resource block from left to right.
  • the first 3.66 refers to the PAPR value corresponding to the first 106 subcarrier resource blocks from left to right
  • 3.77 refers to the corresponding PAPR value of the second 106 subcarrier resource blocks from left to right
  • the fourth row number is 4.53. 4.54 and so on, from left to right, the PAPR value corresponding to the 242 subcarrier resource block
  • 4.53 refers to the first 242 subtitle from left to right.
  • the wave resource block corresponds to the PAPR value;
  • the fifth row number is 4.88, 4.86, etc., which is the PAPR value corresponding to the 242 subcarrier resource block from left to right, and 4.88 refers to the first 484 subcarrier resource block corresponding from left to right.
  • the PAPR value; the sixth line number 4.97 is the PAPR value corresponding to the 996 subcarrier subcarrier resource block.
  • He_ltf_80mhz [ ⁇ 0,0,0,0,0,0,0,0,0,0,0,0 ⁇ ,...
  • HE LTF -500,500 ⁇ -1,+Ga,+Gb,+1,-1,-Ga,+Gb,+1,-Ga,-1,-Ga,-Gb,+1,-1,-Ga , +Gb, +1,
  • the HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, +Ga and +Gb consecutive, or continuous -Ga and +Gb, or continuous -Ga And -Gb, or, continuous +Ga and -Gb, or Ga (1:13) and Ga (14:26).
  • Figure 8e shows the PAPR value of the HE-LTF sequence in the 80MHz bandwidth.
  • the first row of numbers is 2.97, 3.01, 2.97, 3.01, etc., which is the PAPR corresponding to the first row 26 subcarrier resource blocks from left to right.
  • the value, that is, 2.97 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 3.01 refers to the PAPR value corresponding to the second 26 subcarrier resource blocks from left to right, and so on;
  • the number is 3.01, 3.01, etc., which is the PAPR value corresponding to the second row 52 subcarrier resource block from left to right, that is, the first 3.01 refers to the corresponding PAPR value of the first 52 subcarrier resource block from left to right.
  • the second 3.01 refers to the second 52 subcarrier resource block corresponding to the PAPR value from left to right;
  • the third row number is 3.83, 3.81, etc., which is from the left to the right is the third row 106 subcarrier resource block corresponding to
  • the PAPR value that is, the first 3.83 refers to the PAPR value corresponding to the first 106 subcarrier resource blocks from left to right, and the 3.81 refers to the corresponding PAPR value of the second 106 subcarrier resource blocks from left to right;
  • the fourth line is 4.41, 4.59, etc., from left to right, the PAPR value corresponding to the 242 subcarrier resource block, and 4.41 refers to the PAPR value corresponding to the first 242 subcarrier resource block from left to right;
  • the fifth line number is 4.89, 4.90, etc.
  • Etc. from left to right, is the PAPR value corresponding to the 242 subcarrier resource block, and 4.89 refers to the first 484 from left to right.
  • the carrier resource block corresponds to the PAPR value; the sixth line number 4.99 is the PAPR value corresponding to the 996 subcarrier subcarrier resource block.
  • a method in which an STA transmits an HE-LTF sequence according to a RU size and a RU location in resource allocation information.
  • the HE-LTF sequence may be a HE-LTF sequence corresponding to a bandwidth of 20 MHz, 40 MHz, and 80 MHz, that is, an HE-LTF sequence given in each of the foregoing embodiments 1, 2, 3, 5, and 6;
  • the minimum resource block size at which the STA transmits data is represented by RU size ;
  • the RU location refers to the subcarrier position at which the STA transmits data, which is represented by RU idx .
  • the STA processes the sending HE-LTF sequence according to the following procedure:
  • the STA selects the HE-LTF sequence according to the bandwidth information, that is, when the bandwidth is 20 MHz, the STA selects the HE-LTF- 122 , 122 sequence, and when the bandwidth is 40 MHz, the STA selects the HE-LTF- 244 , 244 sequence, and when the bandwidth is 80 MHz, the STA selects the HE- LTF- 498,498 sequence;
  • S702 Select, according to the RU size and the RU location, a part of information transmission from the selected HE-LTF sequence, where the partial information may be an entire HE-LTF sequence, or may be part of information in the HE-LTF sequence. Let us take the 20MHz bandwidth and the RU size as 26, 52, 106, 242 as an example. The specific operations are as follows:
  • the HE-LTF sequence corresponding to the 20MHz bandwidth is:
  • HE-LTF -122,122 [+1,+Gb,-Ga,-1,+Gb,+Ga,+Ga(1:13),-1,-1,0,0,0,
  • HE-LTF -122,122 [0,+Gb,0 26 ,0,0 26 ,0 26 ,0 13 ,0,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 , 0 26 , 0];
  • 0 26 represents a continuous 26 0
  • 0 13 represents a continuous 13 0
  • HE-LTF -122,122 [0,0 26 ,-Ga,0,0 26 ,0 26 ,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 , 0 26 , 0];
  • 0 26 represents a continuous 26 0
  • 0 13 represents a continuous 13 0
  • HE-LTF -122,122 [0,0 26 ,0 26 ,0,+Gb,0 26 ,0 13 ,0,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 , 0 26 , 0];
  • 0 26 represents a continuous 26 0
  • 0 13 represents a continuous 13 0
  • HE-LTF -122,122 [0,0 26 ,0 26 ,0,0 26 ,+Ga,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 , 0 26 , 0];
  • 0 26 represents a continuous 26 0
  • 0 13 represents a continuous 13 0
  • HE-LTF -122,122 [0,0 26 ,0 26 ,0,0 26 ,0 26 ,+Ga(1:13),0,0,0,0,0,0,0,...
  • HE-LTF -122,122 [0,0 26 ,0 26 ,0,0 26 ,0 26 ,0 13 ,0,0,0,0,0,0,0,0 13 ,+Gb,0 26 ,0 , 0 26 , 0 26 , 0];
  • 0 26 represents a continuous 26 0
  • 0 13 represents a continuous 13 0
  • HE-LTF -122,122 [0,0 26 ,0 26 ,0,0 26 ,+Ga,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,-Ga,0 , 0 26 , 0 26 , 0];
  • 0 26 represents a continuous 26 0
  • 0 13 represents a continuous 13 0
  • HE-LTF -122,122 [0,0 26 ,0 26 ,0,0 26 ,+Ga,0 13 ,0,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 ,-Gb,0 26 ,0];
  • 0 26 represents a continuous 26 0
  • 0 13 represents a continuous 13 0
  • HE-LTF -122,122 [0,0 26 ,0 26 ,0,0 26 ,+Ga,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 ,0 26 ,-Ga,0];
  • 0 26 represents a continuous 26 0
  • 0 13 represents a continuous 13 0
  • HE-LTF -122,122 [0,+Gb,-Ga,0,0 26 ,0 26 ,0 13 ,0,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 , 0 26 , 0];
  • HE-LTF -122,122 [0,0 26 ,0 26 ,0,+Gb,+Ga,0 13 ,0,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 , 0 26 , 0];
  • HE-LTF -122,122 [0,0 26 ,0 26 ,0,0 26 ,0 26 ,0 13 ,0,0,0,0,0,0,0,0 13 ,+Gb,-Ga,0 , 0 26 , 0 26 , 0];
  • HE-LTF -122,122 [0,0 26 ,0 26 ,0,0 26 ,0 26 ,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 ,-Gb,-Ga,0];
  • HE-LTF -122,122 [0,+Gb,-Ga,0,+Gb,+Ga,0 13 ,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 , 0 26 , 0 26 , 0 26 , 0 26 , 0 26 , 0 26 , 0];
  • HE-LTF -122,122 [0,0 26 ,0 26 ,0,0 26 ,0 26 ,0 13 ,0,0,0,0,0,0,0,0 13 ,+Gb,-Ga,0 ,-Gb,-Ga,0];
  • HE-LTF -122,122 [+1,+Gb,-Ga,-1,+Gb,+Ga,+Ga(1:13),-1,-1,0,0,0,
  • the effective subcarrier position of the HE-LTF sequence on the 20x bandwidth 2x symbol is: -122:2:122.
  • it can be obtained by transforming the HE-LTF sequence on the 4x symbol. Listed below are several:
  • HELTF 2x (-122:2:122) HELTF 4x (-122:2:122)
  • HELTF 2x (-122:2:-2) HELTF 4x (-122:2:-2)
  • HELTF 2x (2:2:122) -HELTF 4x (2:2:122)
  • HELTF 2x (2:2:122) HELTF 4x (62:122)
  • HELTF 2x (2:2:122) -HELTF 4x (62:122)
  • the effective subcarrier position of the HE-LTF sequence on the 40x bandwidth 2x symbol is: -244:2:244.
  • sequence transformation on the 4x symbol can be obtained according to the HE-LTF sequence transformation on the 4x symbol:
  • HELTF 2x (4:2:244) -HELTF 4x (4:2:244)
  • HELTF 2x (-244:2:-4) HELTF 4x ((-244:2:-4)+0)
  • HELTF 2x (4:2:244) HELTF 4x ((-244:2:-4)+1)
  • HELTF 2x (-244:2:-4) HELTF 4x ((-244:2:-4)+0)
  • HELTF 2x (4:2:244) -HELTF 4x ((-244:2:-4)+1)
  • the effective subcarrier position of the HE-LTF sequence on the 80x bandwidth 2x symbol is: -500:2:500.
  • sequence transformation on the 4x symbol can be obtained according to the HE-LTF sequence transformation on the 4x symbol:
  • HELTF 2x (-500:2:500) HELTF 4x (-500:2:500)
  • HELTF 2x (4:2:500) -HELTF 4x (4:2:500)
  • HELTF 2x (-500:2:-4) HELTF 4x ((-500:2:-4)+1)
  • HELTF 2x (4:2:500) HELTF 4x (4:2:500)
  • HELTF 2x (-500:2:-4) HELTF 4x ((-500:2:-4)+1)
  • HELTF 2x (4:2:500) -HELTF 4x (4:2:500)
  • HELTF 2x (-500:2:-4) HELTF 4x ((4:2:500)-1)
  • HELTF 2x (4:2:500) HELTF 4x (4:2:500)
  • HELTF 2x (-500:2:-4) HELTF 4x ((4:2:500)-1)
  • HELTF 2x (4:2:500) -HELTF 4x (4:2:500)
  • a resource indication processing device (not shown) applied to a wireless local area network employing OFDMA technology, including a processing unit for performing the method in the foregoing implementation.
  • the processing unit may be a general purpose processor, a digital signal processor, an application specific integrated circuit, a field programmable gate array or other programmable logic device, a discrete gate or transistor logic device, a discrete hardware component, or may implement or perform the embodiments of the present invention.
  • a general purpose processor can be a microprocessor or any conventional processor or the like.
  • the steps of the method disclosed in the embodiments of the present invention may be directly implemented as a hardware processor, or may be performed by a combination of hardware and software modules in the processor. It is easy to understand that the processing device indicated by the above resource may be located at an access point or a site.
  • FIG. 9 is a block diagram of an access point in accordance with another embodiment of the present invention.
  • the access point of Figure 9 includes an interface 101, a processing unit 102, and a memory 103.
  • Processing unit 102 controls the operation of access point 100.
  • Memory 103 can include read only memory and random access memory and provides instructions and data to processing unit 102.
  • a portion of the memory 103 may also include non-volatile line random access memory (NVRAM).
  • NVRAM non-volatile line random access memory
  • the various components of access point 100 are coupled together by a bus system 109, which in addition to the data bus includes a power bus, a control bus, and a status signal bus. However, for clarity of description, various buses are labeled as the bus system 109 in the figure.
  • the method for transmitting the foregoing various frames disclosed in the foregoing embodiments of the present invention may be applied to the processing unit 102 or implemented by the processing unit 102.
  • each step of the above method may be completed by an integrated logic circuit of hardware in the processing unit 102 or an instruction in the form of software.
  • the processing unit 102 can be a general purpose processor, a digital signal processor, an application specific integrated circuit, a field programmable gate array or other programmable logic device, a discrete gate or transistor logic device, a discrete hardware component, which can be implemented or executed in an embodiment of the invention.
  • a general purpose processor can be a microprocessor or any conventional processor or the like.
  • the steps of the method disclosed in the embodiments of the present invention may be directly implemented as a hardware processor, or may be performed by a combination of hardware and software modules in the processor.
  • Software modules can be located in random access memory, flash memory, read only Memory, programmable read only memory or electrically erasable programmable memory, registers, etc. are well-established in the field of storage media.
  • the storage medium is located in the memory 103, and the processing unit 102 reads the information in the memory 103 and completes the steps of the above method in combination with its hardware.
  • FIG. 10 is a block diagram of a station in accordance with another embodiment of the present invention.
  • the access point of FIG. 10 includes an interface 111, a processing unit 112, and a memory 113.
  • Processing unit 112 controls the operation of site 110.
  • Memory 113 can include read only memory and random access memory and provides instructions and data to processing unit 112.
  • a portion of the memory 113 may also include non-volatile line random access memory (NVRAM).
  • NVRAM non-volatile line random access memory
  • the various components of the site 110 are coupled together by a bus system 119, which in addition to the data bus includes a power bus, a control bus, and a status signal bus. However, for clarity of description, various buses are labeled as bus system 119 in the figure.
  • the method for receiving the foregoing various frames disclosed in the foregoing embodiments of the present invention may be applied to the processing unit 112 or implemented by the processing unit 112.
  • each step of the above method may be completed by an integrated logic circuit of hardware in the processing unit 112 or an instruction in a form of software.
  • the processing unit 112 can be a general purpose processor, a digital signal processor, an application specific integrated circuit, a field programmable gate array or other programmable logic device, a discrete gate or transistor logic device, a discrete hardware component, which can be implemented or executed in an embodiment of the invention.
  • a general purpose processor can be a microprocessor or any conventional processor or the like.
  • the steps of the method disclosed in the embodiments of the present invention may be directly implemented as a hardware processor, or may be performed by a combination of hardware and software modules in the processor.
  • the software module can be located in a conventional storage medium such as random access memory, flash memory, read only memory, programmable read only memory or electrically erasable programmable memory, registers, and the like.
  • the storage medium is located in the memory 113, and the processing unit 112 reads the information in the memory 113 and performs the steps of the above method in combination with its hardware.
  • the memory 113 stores an instruction that causes the processing unit 112 to perform resource status information indicating a busy state of a sub-resource of a channel resource for which the access point performs data transmission with the station; sending to the access point Resource status information, so that the access point performs resource allocation according to resource status information.
  • system and “network” are used interchangeably herein.
  • the term “and/or” in this context is merely an association describing the associated object, indicating that there may be three relationships, for example, A and / or B, which may indicate that A exists separately, and both A and B exist, respectively. B these three situations.
  • the character "/" in this article generally indicates that the contextual object is an "or" relationship.
  • B corresponding to A means that B is associated with A, and B can be determined according to A.
  • determining B from A does not mean that B is only determined based on A, and that B can also be determined based on A and/or other information.
  • the disclosed systems, devices, and methods may be implemented in other manners.
  • the device embodiments described above are merely illustrative.
  • the division of the unit is only a logical function division.
  • there may be another division manner for example, multiple units or components may be combined or Can be integrated into another system, or some features can be ignored or not executed.
  • the mutual coupling or direct coupling or communication connection shown or discussed may be an indirect coupling or communication connection through some interface, device or unit, or an electrical, mechanical or other form of connection.
  • the units described as separate components may or may not be physically separated, and the components displayed as units may or may not be physical units, that is, may be located in one place, or may be distributed to multiple network units. You can choose some of them according to actual needs or All units are used to achieve the objectives of the embodiments of the present invention.
  • each functional unit in each embodiment of the present invention may be integrated into one processing unit, or each unit may exist physically separately, or two or more units may be integrated into one unit.
  • the above integrated unit can be implemented in the form of hardware or in the form of a software functional unit.
  • Computer readable media includes both computer storage media and communication media including any medium that facilitates transfer of a computer program from one location to another.
  • a storage medium may be any available media that can be accessed by a computer.
  • computer readable media may comprise RAM, ROM, EEPROM, CD-ROM or other optical disk storage, disk storage media or other magnetic storage device, or can be used for carrying or storing in the form of an instruction or data structure.
  • connection may suitably be a computer readable medium.
  • the software is transmitted from a website, server, or other remote source using coaxial cable, fiber optic cable, twisted pair, digital STA line (DSL), or wireless technologies such as infrared, radio, and microwave
  • coaxial cable , fiber optic cable, twisted pair, DSL, or wireless technologies such as infrared, wireless, and microwave are included in the fixing of the associated media.
  • a disk and a disc include a compact disc (CD), a laser disc, a compact disc, a digital versatile disc (DVD), a floppy disk, and a Blu-ray disc, wherein the disc is usually magnetically copied, and the disc is The laser is used to optically replicate the data. Combinations of the above should also be included within the scope of the computer readable media.

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Abstract

A method for transmitting an HE-LTF sequence comprises: determining a corresponding HE-LTF sequence according to a size of a bandwidth, wherein the HE-LTF sequence comprises continuous subsequences Ga and Gb and +1 or -1 at a leftover subcarrier location, and Ga and Gb are complementary; and transmitting the HE-LTF sequence according to a size and a location of an RU in resource allocation information.

Description

生成HE-LTF序列方法、处理装置、接入点和站点Generating HE-LTF sequence methods, processing devices, access points, and sites 技术领域Technical field
本发明涉及无线通信技术领域，并且更具体地，涉及传输信息的方法、接入点和站点。The present invention relates to the field of wireless communication technologies and, more particularly, to a method, an access point, and a station for transmitting information.
背景技术Background technique
随着移动互联网的发展和智能终端的普及，数据流量快速增长。无线局域网(WLAN，Wireless Local Area Network)凭借高速率和低成本方面的优势，成为主流的移动宽带接入技术之一。With the development of the mobile Internet and the popularity of smart terminals, data traffic has grown rapidly. Wireless Local Area Network (WLAN) has become one of the mainstream mobile broadband access technologies due to its high speed and low cost.
为了大幅提升WLAN系统的业务传输速率，下一代电气和电子工程师协会(IEEE，Institute of Electrical and Electronics Engineers)802.11ax标准将会在现有正交频分复用(OFDM，Orthogonal Frequency Division Multiplexing)技术的基础上，进一步采用正交频分多址(OFDMA，Orthogonal Frequency Division Multiple Access)技术。OFDMA技术将空口无线信道时频资源划分成多个正交的时频资源块(RB，Resource Block)，RB之间在时间上可以是共享的，而在频域上是正交的。In order to greatly increase the service transmission rate of the WLAN system, the next generation of Institute of Electrical and Electronics Engineers (IEEE) 802.11ax standard will be in the existing Orthogonal Frequency Division Multiplexing (OFDM) technology. On the basis of the above, Orthogonal Frequency Division Multiple Access (OFDMA) technology is further adopted. The OFDMA technology divides the air interface time-frequency resources into a plurality of orthogonal time-frequency resource blocks (RBs). The RBs may be shared in time and orthogonal in the frequency domain.
在现有的WiFi系统(如11n或11ac)中，终端仍在使用载波侦听冲突避免的竞争方式进行信道接入。当用户数量增加时，由于信道接入冲突增加，使得系统平均吞吐量急速下降。在目前新的WiFi标准(11ax)工作中，已经决定将OFDMA技术引入到WiFi系统，以达成高密场景下提升系统平均吞吐量的目标。LTF作为现有WiFi系统中用于信道估计的重要部分，也被沿用到新WiFi标准中的OFDMA模式。因此，在OFDMA模式下，LTF的生成方式成为一个研究热点。In existing WiFi systems (such as 11n or 11ac), the terminal is still using the carrier mode of carrier sense collision avoidance for channel access. When the number of users increases, the average throughput of the system drops rapidly due to an increase in channel access conflicts. In the current work of the new WiFi standard (11ax), it has been decided to introduce OFDMA technology into the WiFi system to achieve the goal of increasing the average throughput of the system in a high-density scenario. As an important part of channel estimation in existing WiFi systems, LTF is also used in the OFDMA mode in the new WiFi standard. Therefore, in the OFDMA mode, the LTF generation method has become a research hotspot.
现有技术中，以802.11ac标准中80MHz的LTF或160MHz的LTF作为基本模板，从中抽取OFDMA模式中用户调度的资源块对应的载波部分的值，资源块未对应的载波部分的值用0填充，生成OFDMA模式下用户使用的LTF。In the prior art, the LTF of 80 MHz or the LTF of 160 MHz in the 802.11ac standard is used as a basic template, and the value of the carrier part corresponding to the resource block scheduled by the user in the OFDMA mode is extracted therefrom, and the value of the carrier part not corresponding to the resource block is padded with 0. Generate LTFs used by users in OFDMA mode.
然而，资源的调度模式多样化，采用现有技术的方法，峰值平均功率比(Peak to Average Power Ratio，以下简称：PAPR)较高。 However, the scheduling mode of resources is diversified, and the method of the prior art is adopted, and the Peak to Average Power Ratio (PAPR) is higher.
发明内容Summary of the invention
本发明实施例提供了一种发送LTF的方法、接入点和站点，能够降低峰值平均功率比，提高信道估计精度。Embodiments of the present invention provide a method, an access point, and a station for transmitting LTF, which can reduce a peak average power ratio and improve channel estimation accuracy.
一种发送HE-LTF序列的方法，包括：A method of transmitting an HE-LTF sequence, comprising:
根据带宽大小确定相应的HE-LTF序列,所述HE-LTF序列包含连续的子序列Ga和子序列Gb，和，位于空余leftover子载波位置上的+1或者-1；其中Ga与Gb具有互补性；Determining a corresponding HE-LTF sequence according to the bandwidth size, the HE-LTF sequence comprising a continuous sub-sequence Ga and a sub-sequence Gb, and +1 or -1 at a position of the spare leftover subcarrier; wherein Ga and Gb are complementary ;
根据资源分配信息中的RU大小和RU位置，发送所述HE-LTF序列。The HE-LTF sequence is transmitted according to the RU size and the RU location in the resource allocation information.
较优的，所述HE-LTF序列还包括：连续的-Ga和-Gb，或者，连续的+Ga和-Gb，或者，连续的-Ga和+Gb，或者，或者，连续的+Gb和-Ga，或者，部分的Ga，Gb，-Ga，或者-Gb。Preferably, the HE-LTF sequence further comprises: continuous -Ga and -Gb, or continuous +Ga and -Gb, or continuous -Ga and +Gb, or, or, continuous +Gb and -Ga, or part of Ga, Gb, -Ga, or -Gb.
具体的，所述HE-LTF序列是AP发送的下行的HE-LTF序列，或者，是STA发送的上行的HE-LTF序列。Specifically, the HE-LTF sequence is a downlink HE-LTF sequence sent by the AP, or is an uplink HE-LTF sequence sent by the STA.
相应的，提供了一种可以用于执行上述方法的装置。Accordingly, an apparatus is provided that can be used to perform the above method.
另外，还提供了包含前述的装置的站点或者接入点。In addition, a site or access point containing the aforementioned means is also provided.
上述方法或者装置，可以解决802.11ax标准方案中，OFDMA多用户模式下，STA发送HE-LTF序列出现PAPR高的问题，使得STA或者AP发送HE-LTF序列的PAPR值比数据部分的PAPR值低。The foregoing method or device can solve the problem that in the 802.11ax standard scheme, in the OFDMA multi-user mode, the STA sends a HE-LTF sequence with a high PAPR, so that the PAPR value of the HE or LTF sequence sent by the STA or the AP is lower than the PAPR value of the data part. .
附图说明DRAWINGS
为了更清楚地说明本发明实施例的技术方案，下面将对本发明实施例中所需要使用的附图作简单地介绍，显而易见地，下面所描述的附图仅仅是本发明的一些实施例，对于本领域普通技术人员来讲，在不付出创造性劳动的前提下，还可以根据这些附图获得其他的附图。In order to more clearly illustrate the technical solutions of the embodiments of the present invention, the drawings to be used in the embodiments of the present invention will be briefly described below. It is obvious that the drawings described below are only some embodiments of the present invention, Those skilled in the art can also obtain other drawings based on these drawings without paying any creative work.
图1a、1b、1c是802.11ax中OFDMA传输模式下的tone plan。Figures 1a, 1b, and 1c are tone plans in an OFDMA transmission mode in 802.11ax.
图2a、2b是如果沿用802.11ac的LTF的PAPR的示意图。2a, 2b are schematic diagrams of PAPR if LTFs of 802.11ac are used.
图3是本发明实施例可应用的系统构架的示意图。FIG. 3 is a schematic diagram of a system architecture applicable to an embodiment of the present invention.
图4、5分别是本发明一个实施例的流程示意图。4 and 5 are schematic flow charts of an embodiment of the present invention, respectively.
图6a-6d是本发明一个实施例的各种PAPR示意图。Figures 6a-6d are schematic illustrations of various PAPRs in accordance with one embodiment of the present invention.
图7a-7d是本发明一个实施例的各种PAPR示意图。 Figures 7a-7d are schematic illustrations of various PAPRs in accordance with one embodiment of the present invention.
图8a-8e是本发明另一实施例的各种PAPR示意图。8a-8e are schematic diagrams of various PAPRs in accordance with another embodiment of the present invention.
图9是本发明一实施例的接入点的框图。9 is a block diagram of an access point in accordance with an embodiment of the present invention.
图10是本发明一实施例的站点的框图。Figure 10 is a block diagram of a station in accordance with an embodiment of the present invention.
具体实施方式detailed description
下面将结合本发明实施例中的附图，对本发明实施例中的技术方案进行清楚、完整地描述，显然，所描述的实施例是本发明的一部分实施例，而不是全部实施例。基于本发明中的实施例，本领域普通技术人员在没有做出创造性劳动的前提下所获得的所有其他实施例，都应属于本发明保护的范围。The technical solutions in the embodiments of the present invention are clearly and completely described in the following with reference to the accompanying drawings in the embodiments of the present invention. It is obvious that the described embodiments are a part of the embodiments of the present invention, but not all embodiments. All other embodiments obtained by those skilled in the art based on the embodiments of the present invention without creative efforts shall fall within the scope of the present invention.
接入点(AP，Access Point)，也可称之为无线访问接入点或桥接器或热点等，其可以接入服务器或通信网络。An Access Point (AP), which can also be called a wireless access point or bridge or hotspot, can access a server or a communication network.
站点(STA，Station)，还可以称为用户，可以是无线传感器、无线通信终端或移动终端，如支持WiFi通讯功能的移动电话(或称为“蜂窝”电话)和具有无线通信功能的计算机。例如，可以是支持WiFi通讯功能的便携式、袖珍式、手持式、计算机内置的，可穿戴的，或者车载的无线通信装置，它们与无线接入网交换语音、数据等通信数据。A station (STA, Station), which may also be referred to as a user, may be a wireless sensor, a wireless communication terminal, or a mobile terminal, such as a mobile phone (or "cellular" phone) that supports WiFi communication functions and a computer with wireless communication capabilities. For example, it may be a portable, pocket-sized, handheld, computer-built, wearable, or in-vehicle wireless communication device that supports WiFi communication functions, and exchanges communication data such as voice and data with the wireless access network.
802.11ax致力于进一步提升WLAN频谱效率、区域吞吐量、实际用户体验以及各种室内外密集网络部署环境下的性能，同时该方案还要求能够抑制设备间干扰，满足大规模、高负载组网需求等。传统WiFi主要应用于室内信道，OFDM传输方式，符号长度为3.2us,子载波间隔为1/3.2us＝312.5kHz。20MHz内用64-FFT构造OFDM符号，总共56个子载波中有52个数据子载波和4个子载波，40MHz内用128-FFT构造OFDM符号，总共128个子载波中有108个数据子载波和6个子载波，而256-FFT构造OFDM符号，总共256个子载波中有234个数据子载波和8个子载波。802.11ax is dedicated to further improving WLAN spectrum efficiency, regional throughput, actual user experience, and performance in a variety of indoor and outdoor dense network deployment environments. The solution also requires suppression of inter-device interference to meet large-scale, high-load networking requirements. Wait. Traditional WiFi is mainly applied to indoor channels, OFDM transmission mode, symbol length is 3.2us, and subcarrier spacing is 1/3.2us=312.5kHz. OFDM symbols are constructed with 64-FFT in 20 MHz, 52 data subcarriers and 4 subcarriers in 56 subcarriers in total, and OFDM symbols are constructed with 128-FFT in 40 MHz, and 108 data subcarriers and 6 subcarriers in total 128 subcarriers The carrier, while the 256-FFT constructs an OFDM symbol, has 234 data subcarriers and 8 subcarriers out of a total of 256 subcarriers.
而802.11ax系统为了支持室内室外场景，可以采用4倍于802.11ac的符号长度(4x3.2us＝12.8us)，子载波间隔为312.5/4＝78.125kHz。并且为了支持OFDMA传输，采用以下tone plan(承载数据的子载波分布)，不同资源块(RU:resource unit)的位置关系如图1a-1c，其中箭头表示RU间残留子载波(leftover tone)的位置，大的RU子载波个数和对应其中可容纳的多个小RU以及小RU间残留子载波个数总和相同。参考图1a，为20MHz内OFDMA资源块位置的简单示意图，图1b，为40MHz内OFDMA资源块位置的简 单示意图，图1c，为80MHz内OFDMA资源块位置的简单示意图。802.11ax中OFDMA多用户数据包是多种大小的资源块(RU:resource unit)组合而成，AP分配给每个用户一个RU，可能分配给用户的可选RU有：In order to support indoor and outdoor scenes, the 802.11ax system can use 4 times the symbol length of 802.11ac (4x3.2us=12.8us) and the subcarrier spacing is 312.5/4=78.125kHz. And in order to support the OFDMA transmission, the following tone plan (subcarrier distribution of data carrying) is adopted, and the positional relationship of different resource blocks (RU: resource unit) is as shown in FIG. 1a-1c, wherein the arrow indicates the residual subcarrier between the RUs. The location, the number of large RU subcarriers and the corresponding number of small RUs that can be accommodated therein and the number of residual subcarriers between small RUs are the same. Referring to FIG. 1a, it is a simple schematic diagram of the location of an OFDMA resource block in a 20 MHz, and FIG. 1b is a simplified location of an OFDMA resource block in a 40 MHz. A single schematic diagram, Figure 1c, is a simplified schematic diagram of the location of an OFDMA resource block within 80 MHz. The OFDMA multi-user data packet in 802.11ax is a combination of multiple resource blocks (RU: resource unit). The AP allocates one RU to each user. The optional RUs that may be assigned to the user are:
1)连续26个子载波组成的RU：24个数据子载波和2个pilot导频子载波1) RU consisting of 26 consecutive subcarriers: 24 data subcarriers and 2 pilot pilot subcarriers
2)连续52个子载波组成的RU：48个数据子载波和4个pilot导频子载波2) RU consisting of 52 consecutive subcarriers: 48 data subcarriers and 4 pilot pilot subcarriers
3)连续106个子载波组成的RU：24个数据子载波和2个pilot导频子载波3) RU consisting of 106 consecutive subcarriers: 24 data subcarriers and 2 pilot pilot subcarriers
4)连续242个子载波组成的RU：234个数据子载波和8个pilot导频子载波4) RU consisting of 242 consecutive subcarriers: 234 data subcarriers and 8 pilot pilot subcarriers
5)连续484个子载波组成的RU：468个数据子载波和16个pilot导频子载波5) RU consisting of 484 consecutive subcarriers: 468 data subcarriers and 16 pilot pilot subcarriers
6)连续996个子载波组成的RU：980个数据子载波和16个pilot导频子载波6) RU consisting of 996 consecutive subcarriers: 980 data subcarriers and 16 pilot pilot subcarriers
其中484-RU是在40MHz的多用户传输中使用，而996-RU是在80/160MHz的多用户传输中使用。160MHz可以看作2个80MHz tone plan组成。Among them, 484-RU is used in 40MHz multi-user transmission, and 996-RU is used in 80/160MHz multi-user transmission. 160MHz can be seen as a combination of two 80MHz tone plans.
另外，802.11ax系统中用于信道估计的HE-LTF采用2x和4x两种模式，4x HE-LTF序列映射的子载波号index和数据部分tone plan相同，而2x HE-LTF序列号对应于4x HE-LTF序号数除以2。In addition, the HE-LTF for channel estimation in the 802.11ax system adopts two modes of 2x and 4x, the subcarrier number index of the 4x HE-LTF sequence mapping is the same as the data part tone plan, and the 2x HE-LTF serial number corresponds to 4x. The number of HE-LTF numbers is divided by 2.
802.11ax系统中OFDMA传输的tone plan(子载波分布)，和现有的802.11ac系统中OFDM的tone plan不同。所以802.11ac中定义的20/40的VHT-LTF序列本身不能适用。具体一个情况下，802.11ac中80MHz的子载波总数242和802.11ax中20MHz的子载波总数相同，但是直接在802.11ax 20MHz带宽内采用VHT-LTF序列发现能量峰值和均值比(PAPR：Peak-to-average power ratio)比较高。参考图2a、2b，可以看出，如果802.11ac 80MHz的VHT-LTF用于802.11ax 20MHz，其PAPR和传统LTF序列的PAPR相比显著提高，影响功控效率，进而降低信道估计精度。The tone plan of the OFDMA transmission in the 802.11ax system is different from the tone plan of the OFDM in the existing 802.11ac system. Therefore, the 20/40 VHT-LTF sequence defined in 802.11ac itself cannot be applied. In a specific case, the total number of subcarriers of 80 MHz in 802.11ac is the same as the total number of subcarriers of 20 MHz in 802.11ax, but the peak value and the mean ratio (PAPR: Peak-to) are found directly in the 802.11ax 20 MHz bandwidth using the VHT-LTF sequence. -average power ratio) is relatively high. Referring to FIGS. 2a and 2b, it can be seen that if the 802.11ac 80 MHz VHT-LTF is used for 802.11ax 20 MHz, the PAPR of the 802.11ac 80 MHz is significantly improved compared with the PAPR of the conventional LTF sequence, which affects the power control efficiency and thus the channel estimation accuracy.
另外802.11ax在40/80MHz tone plan，子载波个数已经超过传统序列，无法重用802.11ac的VHT-LTF序列。In addition, 802.11ax is in 40/80MHz tone plan, the number of subcarriers has exceeded the traditional sequence, and the VHT-LTF sequence of 802.11ac cannot be reused.
图3为一个本发明实施方式应用的WLAN系统的简单示意图。图3的系统包括一个或者多个接入点AP101和一个或者多个站点STA102。接入点101和站点102之间采用OFDMA技术进行无线通信。FIG. 3 is a simplified schematic diagram of a WLAN system to which an embodiment of the present invention is applied. The system of Figure 3 includes one or more access points AP 101 and one or more stations STA 102. The OFDMA technology is used for wireless communication between the access point 101 and the station 102.
本发明各实施方式中，关注可以应用于前述802.11ax系统的20MHz/40MHz/80MHz子载波规划(tone plan)的2x和4x HE-LTF序列。其中，可以根据OFDMA tone plan中RU的大小和位置以及RU间残留子载波的个数和位置，确定不同大小的RU都满足低PAPR的序列，尤其是针对只分配了小RU(26/52-RU) 的边缘用户，发射功率本身接近最大值，可以更低的PAPR保证功放工作范围。另外，本实施方式中的至少部分序列，还可以使得产品上存储量低，容易实现。In various embodiments of the present invention, attention is paid to 2x and 4x HE-LTF sequences that can be applied to the 20 MHz/40 MHz/80 MHz subcarrier plan of the aforementioned 802.11ax system. According to the size and location of the RU in the OFDMA tone plan and the number and location of the residual subcarriers between the RUs, it is determined that the RUs of different sizes satisfy the low PAPR sequence, especially for the small RU (26/52-). RU) The edge user, the transmit power itself is close to the maximum value, and the lower PAPR can guarantee the working range of the amplifier. In addition, at least part of the sequence in the present embodiment can also make the storage amount on the product low and easy to implement.
一种实施方式中，提供了一种发送HE-LTF序列的方法，包括：In one embodiment, a method of transmitting an HE-LTF sequence is provided, including:
根据带宽大小确定相应的HE-LTF序列,所述HE-LTF序列包含连续的子序列Ga和子序列Gb，和，位于空余leftover子载波位置上的+1或者-1；其中Ga与Gb具有互补性；Determining a corresponding HE-LTF sequence according to the bandwidth size, the HE-LTF sequence comprising a continuous sub-sequence Ga and a sub-sequence Gb, and +1 or -1 at a position of the spare leftover subcarrier; wherein Ga and Gb are complementary ;
根据资源分配信息中的RU大小和RU位置，发送所述HE-LTF序列。The HE-LTF sequence is transmitted according to the RU size and the RU location in the resource allocation information.
较优的，所述HE-LTF序列还包括：连续的-Ga和-Gb，或者，连续的+Ga和-Gb，或者，连续的-Ga和+Gb，或者，或者，连续的+Gb和-Ga。Preferably, the HE-LTF sequence further comprises: continuous -Ga and -Gb, or continuous +Ga and -Gb, or continuous -Ga and +Gb, or, or, continuous +Gb and -Ga.
具体的，上述方法可以是AP发送的下行的HE-LTF序列，也可以是STA发送的上行的HE-LTF序列。相应的，另一些实施中，提供了接收侧接收相应的HE-LTF序列并进行处理的办法。Specifically, the foregoing method may be a downlink HE-LTF sequence sent by the AP, or may be an uplink HE-LTF sequence sent by the STA. Correspondingly, in other implementations, a method is provided in which the receiving side receives and processes the corresponding HE-LTF sequence.
实施例一 Embodiment 1
发送802.11ax中发送下行LTF的实施例：Sending an embodiment of transmitting a downlink LTF in 802.11ax:
接入点AP发送数据包PPDU(例如802.11ax的)，该PPDU中包括HE-LTF，HE-SIG-A，HE-SIG-B，其中，在HE-SIG-A中包含用于指示下行用户STA传输带宽的信息，在HE-SIG-B中包含用于指示下行被调度的STA ID以及为该STA所分配的RU大小以及位置，以及流号的信息。另外，在HE-SIG-A或者HE-SIG-B中还可以包含用于指示多个用户对齐后的HE-LTF长度，即符号数N。其中，参考图4，上述发送PPDU的过程中发送HE-LTF序列的过程包括：The access point AP sends a data packet PPDU (for example, 802.11ax), and the PPDU includes HE-LTF, HE-SIG-A, and HE-SIG-B, where the HE-SIG-A is included to indicate the downlink user. The information of the STA transmission bandwidth includes information indicating the downlink scheduled STA ID and the RU size and location allocated for the STA, and the stream number in the HE-SIG-B. In addition, the HE-LTF length, that is, the number of symbols N, for indicating alignment of a plurality of users may be included in the HE-SIG-A or HE-SIG-B. With reference to FIG. 4, the process of sending the HE-LTF sequence in the process of sending the PPDU includes:
S101：AP根据传输带宽大小(指多用户共享的总带宽)选择对应该带宽的HE-LTF序列；S101: The AP selects a HE-LTF sequence corresponding to the bandwidth according to the transmission bandwidth size (refer to the total bandwidth shared by multiple users).
S102：AP在该带宽(总带宽)内，针对每一个下行被调度的用户所分配的资源块RU大小和RU位置，从HE-LTF序列中选择对应的HE-LTF序列段，将各HE-LTF序列段映射在分配的RU子载波位置上。S102: In the bandwidth (total bandwidth), the AP selects a corresponding HE-LTF sequence segment from the HE-LTF sequence for each resource block RU size and RU location allocated by each downlink scheduled user, and each HE- The LTF sequence segments are mapped at the assigned RU subcarrier locations.
S103：可选的，如果该PPDU包含多流或者多用户传输时，HE-LTF在时间上被重复N次(如果在每个RU上对应所分配用户的总流数的最大值为M，N>＝M,N＝1,2,4,6或8，M＝1～8)，AP给RU上的每个流顺序分配大小为NxN的加扰Mask矩阵(英语Scramble)(例如P-matrix矩阵或者Walsh矩阵或者其他合适的 矩阵)中的一行作为用于区分空间流的特征码。S103: Optionally, if the PPDU includes multi-stream or multi-user transmission, the HE-LTF is repeated N times in time (if the maximum number of total flows corresponding to the allocated users on each RU is M, N) >=M, N=1, 2, 4, 6 or 8, M=1~8), the AP assigns a scrambling Mask matrix of size NxN to each stream on the RU (for example, P-matrix) Matrix or Walsh matrix or other suitable A row in the matrix is used as a signature for distinguishing the spatial stream.
具体为，如果协议约定pilot不参与加扰，AP发送RU上每个流的HE-LTF序列时，HE-LTF的第n个符号上的tone plan除去导频子载波位置以外的部分，乘以对应区分该流的特征码的第n位码字。Specifically, if the protocol stipulates that the pilot does not participate in the scrambling, and the AP sends the HE-LTF sequence of each stream on the RU, the tone plan on the nth symbol of the HE-LTF removes the portion other than the pilot subcarrier position, multiplied by Corresponding to the nth bit codeword that distinguishes the feature code of the stream.
如果协议约定pilot参与加扰，AP发送RU上每个流的HE-LTF序列时，HE-LTF的第n个符号上的tone plan内的子载波乘以对应区分该流的特征码的第n位码字。If the protocol stipulates that the pilot participates in the scrambling, when the AP transmits the HE-LTF sequence of each stream on the RU, the subcarriers in the tone plan on the nth symbol of the HE-LTF are multiplied by the nth corresponding to the signature of the stream. Bit code word.
相应的，在接收侧，参考图4，被调度的STA接收数据包PPDU(例如802.11ax的)，包括如下处理：Correspondingly, on the receiving side, referring to FIG. 4, the scheduled STA receives the data packet PPDU (for example, 802.11ax), including the following processing:
S201：被调度的STA接收HE-SIG-A，得到HE-SIG-A中指示的传输总带宽；S201: The scheduled STA receives the HE-SIG-A, and obtains the total transmission bandwidth indicated in the HE-SIG-A.
S202：根据传输总带宽的大小选择对应该带宽的HE-LTF序列；S202: Select an HE-LTF sequence corresponding to the bandwidth according to the total bandwidth of the transmission;
S203：被调度的STA接收HE-SIG-B，用自己的STA ID识别出自己被调度的指示信息，其中得到AP给该用户分配的RU大小以及RU位置。按照指示的RU大小和位置从HE-LTF序列中选择对应的HE-LTF序列段，作为接收端对应RU的信道估计参考序列。S203: The scheduled STA receives the HE-SIG-B, and uses its own STA ID to identify its own scheduled indication information, where the AP allocates the RU size and the RU location allocated to the user. Corresponding HE-LTF sequence segments are selected from the HE-LTF sequence according to the indicated RU size and location as a channel estimation reference sequence corresponding to the RU of the receiving end.
S204：被调度的STA接收HE-SIG-A或者HE-SIG-B中包含的HE-LTF长度N，选择NxN的加扰Mask矩阵(英语可以是Scramble)(例如P-matrix矩阵或者Walsh矩阵)作为用于区分空间流的码矩阵。按照该用户被调度的指示信息中所指示的总流数中自己对应的第i个数据流来选择码矩阵中的第i行码字，所谓接收该流的参考码字，把对应RU的信道估计参考序列乘以对应该流的参考码字中的第n个码字，构成接收第n个HE-LTF符号的接收端参考序列，以进行信道估计。S204: The scheduled STA receives the HE-LTF length N included in the HE-SIG-A or HE-SIG-B, and selects a scrambling Mask matrix of NxN (English may be Scramble) (for example, a P-matrix matrix or a Walsh matrix) As a code matrix for distinguishing spatial streams. Selecting the i-th row codeword in the code matrix according to the i-th data stream corresponding to the total number of streams indicated by the user in the indication information scheduled by the user, so-called receiving the reference codeword of the stream, and setting the channel corresponding to the RU The estimated reference sequence is multiplied by the nth codeword in the reference codeword corresponding to the stream, and constitutes a receiver reference sequence for receiving the nth HE-LTF symbol for channel estimation.
实施例二Embodiment 2
本实施例主要针对发送上行LTF的过程：This embodiment is mainly directed to the process of transmitting an uplink LTF:
例如，AP通过触发帧指示上行调度信息，包含上行用户STA传输带宽，上行被调度的STA ID以及为该STA所分配的RU大小以及位置，以及上行多个用户对齐后的HE-LTF长度，即符号数N(如果在每个RU上对应所分配用户的总流数的最大值为M，N>＝M,N＝1,2,4,6或8，M＝1～8)。参考图5，STA根据上行调度信息发送数据包PPDU(例如802.11ax)。For example, the AP indicates the uplink scheduling information by using the trigger frame, including the uplink user STA transmission bandwidth, the uplink scheduled STA ID, the RU size and location allocated for the STA, and the HE-LTF length of the uplink user aligned. The number of symbols N (if the maximum number of total streams corresponding to the assigned user on each RU is M, N>=M, N=1, 2, 4, 6 or 8, M=1 to 8). Referring to FIG. 5, the STA transmits a data packet PPDU (for example, 802.11ax) according to the uplink scheduling information.
其中，上行STA发送数据包PPDU(例如802.11ax)时，Wherein, when the uplink STA sends a data packet PPDU (for example, 802.11ax),
S301：STA根据指示的传输带宽大小(指多用户共享的总带宽)选择对 应该带宽大小的HE-LTF序列.S301: The STA selects a pair according to the indicated transmission bandwidth size (refer to the total bandwidth shared by multiple users). The bandwidth should be HE-LTF sequence.
S302：STA在带宽(总带宽)内所分配的资源块RU大小和RU位置上，从HE-LTF序列中选择对应的HE-LTF序列段映射在分配的RU子载波位置上。S302: The STA selects a corresponding HE-LTF sequence segment from the HE-LTF sequence to be mapped on the allocated RU subcarrier position in the resource block RU size and the RU location allocated in the bandwidth (total bandwidth).
S303：STA按照指示的HE-LTF长度，在时间上重复N次HE-LTF序列，如果该用户所在RU包含多空间流或者多用户传输时，STA在传输其中对应的流时，按照AP所分配的第i个流选择大小为NxN的加扰Mask矩阵(英语可以是Scramble)(例如P-matrix矩阵或者Walsh矩阵)中的第i行作为区分流的特征码。S303: The STA repeats the HE-LTF sequence N times in time according to the indicated HE-LTF length. If the RU where the user is located includes multiple spatial streams or multi-user transmission, when the STA transmits the corresponding stream, the STA allocates according to the AP. The i-th stream selects the i-th row in the scrambled Mask matrix of NxN (English may be Scramble) (for example, P-matrix matrix or Walsh matrix) as the signature of the distinguishing stream.
具体的，发送相应的RU上的该STA所对应每个流的HE-LTF序列时，HE-LTF的第n个符号上的tone plan内的子载波乘以对应区分该流的特征码的第n位码字。Specifically, when the HE-LTF sequence of each stream corresponding to the STA on the corresponding RU is transmitted, the subcarriers in the tone plan on the nth symbol of the HE-LTF are multiplied by the corresponding feature code corresponding to the stream. N-bit code word.
在接收侧，AP接收802.11ax的数据包PPDU时，该方法包括On the receiving side, when the AP receives the 802.11ax packet PPDU, the method includes
S401：AP根据传输带宽大小选择对应该带宽的HE-LTF序列。S401: The AP selects a HE-LTF sequence corresponding to the bandwidth according to the size of the transmission bandwidth.
S402：AP在总带宽内给每一个上行被调度的用户所分配的资源块RU大小和RU位置上从HE-LTF序列中选择对应的HE-LTF序列段作为该RU的参考序列。S402: The AP selects a corresponding HE-LTF sequence segment from the HE-LTF sequence in the resource block RU size and the RU location allocated to each uplink scheduled user in the total bandwidth as a reference sequence of the RU.
S403：如果该PPDU包含多流/多用户传输时，HE-LTF参考序列需要在时间上重复N次，AP给RU上的每个流顺序分配大小为NxN的P-matrix矩阵中的一行作为区分流的特征码。具体为，RU上每个流的第n个HE-LTF符号上的参考序列乘以对应用于区分该流的特征码的第n位码字，作为接收该RU对应第i个流的信道估计参考序列，以进行信道估计。S403: If the PPDU includes multi-stream/multi-user transmission, the HE-LTF reference sequence needs to be repeated N times in time, and the AP allocates one line in the P-matrix matrix of size NxN to each stream on the RU as a distinction. The signature of the stream. Specifically, the reference sequence on the nth HE-LTF symbol of each stream on the RU is multiplied by the nth bit codeword corresponding to the feature code used to distinguish the stream, and is used as a channel estimation for receiving the ith stream corresponding to the RU. Reference sequence for channel estimation.
实施例三 Embodiment 3
与上述实施例一实施例二中的方案类似，不同OFDMA的子载波映射方式下，发射机按照不同的带宽大小、RU位置，RU大小发送不同的HE-LTF序列，包括(可以应用于802.11ax标准或者其他可行的标准中本实施例的方案可以结合于前述实施例一或者实施例二中)，(图中未示出)：Similar to the solution in the second embodiment of the foregoing embodiment, in different subcarrier mapping modes of OFDMA, the transmitter sends different HE-LTF sequences according to different bandwidth sizes, RU positions, and RU sizes, including (can be applied to 802.11ax). The solution of this embodiment in the standard or other feasible standards may be combined with the foregoing embodiment 1 or embodiment 2) (not shown):
501、根据带宽大小选个一个LTF序列(或称用于信道估计的序列，例如HE-LTF，为一种可能的名称)，所述一个LTF序列包含连续的子序列Ga与子序列Gb、位于空余leftover子载波位置上的+1或者-1；所述Ga与Gb序列具有互补特性的序列对。501. Select an LTF sequence (or a sequence for channel estimation, such as HE-LTF, which is a possible name) according to the bandwidth, the LTF sequence including a continuous sub-sequence Ga and a sub-sequence Gb, located at +1 or -1 on the leftover subcarrier position; the Ga and Gb sequences have a sequence pair of complementary characteristics.
具体的，Ga与Gb序列是一个长度为26或者13或者其他长度的，具有互 补特性的序列对。Specifically, the Ga and Gb sequences are a length of 26 or 13 or other lengths, and have mutual A sequence pair of complementary features.
具体的例子中，Ga与Gb序列为：In a specific example, the Ga and Gb sequences are:
Ga＝{+1 +1 +1 +1 -1 +1 +1 -1 -1 +1 -1 +1 -1 +1 -1 -1 +1 -1 +1 +1 +1 -1 -1 +1 +1 +1}Ga={+1 +1 +1 +1 -1 +1 +1 -1 -1 +1 -1 +1 -1 +1 -1 -1 +1 -1 +1 +1 +1 -1 -1 + 1 +1 +1}
Gb＝{+1 +1 +1 +1 -1 +1 +1 -1 -1 +1 -1 +1 +1 +1 +1 +1 -1 +1 -1 -1 -1 +1 +1 -1 -1 -1}Gb={+1 +1 +1 +1 -1 +1 +1 -1 -1 +1 -1 +1 +1 +1 +1 +1 -1 +1 -1 -1 -1 +1 +1 - 1 -1 -1}
或者为：Or for:
Ga＝{-1 +1 -1 -1 +1 +1 -1 +1 +1 +1 +1 -1 +1 -1 +1 +1 +1 +1 -1 -1 +1 +1 +1 -1 +1 -1}Ga={-1 +1 -1 -1 +1 +1 -1 +1 +1 +1 +1 -1 +1 -1 +1 +1 +1 +1 -1 -1 +1 +1 +1 - 1 +1 -1}
Gb＝{+1 -1 +1 +1 -1 -1 +1 -1 -1 -1 -1 +1 +1 +1 +1 +1 +1 +1 -1 -1 +1 +1 +1 -1 +1 -1}Gb={+1 -1 +1 +1 -1 -1 +1 -1 -1 -1 -1 +1 +1 +1 +1 +1 +1 +1 -1 -1 +1 +1 +1 - 1 +1 -1}
502、根据资源分配信息中的RU大小和RU位置，发送所述HE-LTF序列。502. Send the HE-LTF sequence according to the RU size and the RU location in the resource allocation information.
非常清楚的，上述LTF序列不同于现有的无线局域网中的LTF序列，更具体的路子中，所述HE-LTF序列还可以包括：连续的-Ga和-Gb，或者，连续的Ga和-Gb，或者，连续的-Ga和Gb，或者，连续的-Gb和Ga，或者，取部分的Ga，Gb，-Ga，或者-Gb。具体的，可以去一半的例如Ga(1:13)和Ga(14:26)，Gb(1:13)和Gb(14:26)等。It is very clear that the above LTF sequence is different from the LTF sequence in the existing wireless local area network. In a more specific way, the HE-LTF sequence may further include: continuous -Ga and -Gb, or continuous Ga and - Gb, or, continuous -Ga and Gb, or, continuous -Gb and Ga, or a portion of Ga, Gb, -Ga, or -Gb. Specifically, half of them such as Ga (1:13) and Ga (14:26), Gb (1:13), and Gb (14:26) can be omitted.
具体的例子中，提供一种针对802.11ax OFDMA tone plan中不同资源块RU的大小以及位置，构造HE-LTF序列的方法,包括：In a specific example, a method for constructing an HE-LTF sequence for the size and location of different resource blocks RU in an 802.11ax OFDMA tone plan is provided, including:
601，选取一个或者一组基本HE-LTF序列，该基本HE-LTF序列的长度与OFDMA传输模式中的小RU长度相同，例如26，或者52。其中基本HE-LTF序列例如前述Ga或者Gb。601. Select one or a set of basic HE-LTF sequences, the length of the basic HE-LTF sequence being the same as the length of the small RU in the OFDMA transmission mode, such as 26, or 52. Wherein the basic HE-LTF sequence is, for example, the aforementioned Ga or Gb.
602，利用OFDMA传输模式中不同RU的大小和位置，重复其中一个或者一组基本HE-LTF序列，以及，进行下述处理之一或者任意组合：以该基本HE-LTF序列为单位进行+1或者-1相位旋转，或者讲基本HE-LTF序列组中的基本HE-LTF序列的顺序调换，或者取部分的基本HE-LTF序列(例如Ga(1:13)和Ga(14:26)，Gb(1:13)和Gb(14:26))。602. Repeat one or a set of basic HE-LTF sequences by using different RU sizes and positions in the OFDMA transmission mode, and perform one or any combination of the following processes: +1 in units of the basic HE-LTF sequence Or a -1 phase rotation, or a sequential exchange of basic HE-LTF sequences in a basic HE-LTF sequence set, or a partial basic HE-LTF sequence (eg Ga(1:13) and Ga(14:26), Gb (1:13) and Gb (14:26)).
603，将通过相位旋转后的若干基本HE-LTF序列级联，构造出大RU的HE-LTF序列；进一步在大RU对应的若干小RU间的残留子载波的个数和位置填充+1或者-1。 603. Construct a HE-LTF sequence of a large RU by cascading a number of basic HE-LTF sequences after the phase rotation; further, fill the +1 or the position of the residual subcarriers between the small RUs corresponding to the large RU or -1.
604，传输带宽内，从小RU级联到大RU，选择各种RU的PAPR最优的PAPR序列，作为该带宽对应的HE-LTF序列。604. In the transmission bandwidth, the small RU is cascaded to the large RU, and the PAPR optimal PAPR sequence of each RU is selected as the HE-LTF sequence corresponding to the bandwidth.
对于不同带宽，按照上述方法所构造完成的HE-LTF序列可以分别存储在AP上和STA端，以便于后续的发送，其发送过程可以参考前述实施方式一实施方式二。For different bandwidths, the HE-LTF sequence constructed according to the foregoing method may be separately stored on the AP and the STA, so as to facilitate subsequent transmission. For the transmission process, reference may be made to Embodiment 2 of the foregoing Embodiment.
实施例四 Embodiment 4
802.11ax标准中，参考图1a，为20MHz带宽的子载波分配方式。In the 802.11ax standard, referring to FIG. 1a, a subcarrier allocation mode of 20 MHz bandwidth is used.
20MHz带宽4x符号上有256个子载波，按照不同的资源块大小，如图1a所示RU大小可以是26、52、106、242个子载波。There are 256 subcarriers on the 4x symbol of the 20MHz bandwidth. According to different resource block sizes, the RU size may be 26, 52, 106, 242 subcarriers as shown in FIG. 1a.
本实施方式中提供针对20MHz 242子载波4X符号上的多种HE-LTF序列，下面仅罗列出其中的几种：A plurality of HE-LTF sequences on the 4X symbol of the 20 MHz 242 subcarrier are provided in this embodiment, and only a few of them are listed below:
1、第一种HE-LTF序列1. The first HE-LTF sequence
HE-LTF序列如下：The HE-LTF sequence is as follows:
he_ltf_20mhz＝[{0,0,0,0,0,0},...He_ltf_20mhz=[{0,0,0,0,0,0},...
{+1,+Gb,-Ga,-1,+Gb,+Ga,+Ga(1:13),-1,-1},...{+1,+Gb,-Ga,-1,+Gb,+Ga,+Ga(1:13),-1,-1},...
{0,0,0},…{0,0,0},...
{+1,+1,+Ga(14:26),+Gb,-Ga,+1,-Gb,-Ga,-1},...{+1, +1, +Ga(14:26), +Gb, -Ga, +1, -Gb, -Ga,-1},...
{0,0,0,0,0}]；{0,0,0,0,0}];
也可以表示为：Can also be expressed as:
HELTF-122,122＝{+1,+Gb,-Ga,-1,+Gb,+Ga,+Ga(1:13),-1,-1,HELTF -122,122 ={+1,+Gb,-Ga,-1,+Gb,+Ga,+Ga(1:13),-1,-1,
0,0,0,0,0,0,
+1,+1,+Ga(14:26),+Gb,-Ga,+1,-Gb,-Ga,-1}+1, +1, +Ga(14:26), +Gb, -Ga, +1, -Gb, -Ga, -1}
该HE-LTF序列中包括Ga与Gb序列，位于空余leftover子载波位置上的+1或者-1，连续的+Gb和-Ga，或者，连续的+Gb和+Ga，或者，连续的+Gb和-Ga，或者，连续的-Gb和-Ga，或者，Ga(1:13)和Ga(14:26)。The HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive +Gb and -Ga, or consecutive +Gb and +Ga, or continuous +Gb And -Ga, or, -Gb and -Ga, or Ga (1:13) and Ga (14:26).
图6a为20MHz带宽下HE-LTF序列的PAPR(峰均比)值的示意图。其中第一行数字是3.01、2.97、3.01、2.97、3.01、2.97、3.01、2.97，其依次是 第一行26子载波资源块对应的PAPR值，即3.01是指从左向右第一个26子载波资源块对应PAPR值，接下来的2.97是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数字是3.01、3.00、3.01、3.00，其依次是第二行52子载波资源块对应的PAPR值，即第一个3.01是指从左向右第一个52子载波资源块对应PAPR值，3.00是指从左向右第二个52子载波资源块对应PAPR值；第三行数字是4.00、3.52，其依次是第三行106子载波资源块对应的PAPR值，即第一个4.00是指从左向右第一个106子载波资源块对应PAPR值，3.52是指从左向右第二个106子载波资源块对应PAPR值；第三行数字4.28对应的是242子载波资源块的PAPR值。Figure 6a is a schematic diagram of the PAPR (peak-to-average ratio) values of the HE-LTF sequence at 20 MHz bandwidth. The first line of numbers is 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, which in turn The PAPR value corresponding to the first row 26 subcarrier resource block, that is, 3.01 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 2.97 refers to the second 26 subcarrier resources from left to right. The block corresponds to the PAPR value, and so on; the second row number is 3.01, 3.00, 3.01, 3.00, which in turn is the PAPR value corresponding to the second row 52 subcarrier resource block, that is, the first 3.01 refers to the first from left to right. The 52 subcarrier resource blocks correspond to the PAPR value, 3.00 refers to the PAPR value corresponding to the second 52 subcarrier resource blocks from left to right; the third row number is 4.00, 3.52, which in turn is the third row 106 subcarrier resource block corresponding The PAPR value, that is, the first 4.00 refers to the corresponding PAPR value of the first 106 subcarrier resource block from left to right, and 3.52 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right; the third row of numbers 4.28 corresponds to the PAPR value of the 242 subcarrier resource block.
2、第二种HE-LTF序列2. The second HE-LTF sequence
HE-LTF序列如下：The HE-LTF sequence is as follows:
he_ltf_20mhz＝[{0,0,0,0,0,0},...He_ltf_20mhz=[{0,0,0,0,0,0},...
{+1,-Ga,+Gb,-1,+Ga,+Gb,+Ga(1:13),+1,+1},...{+1, -Ga, +Gb, -1, +Ga, +Gb, +Ga(1:13), +1, +1},...
{0,0,0},…{0,0,0},...
{+1,-1,+Ga(14:26),-Ga,+Gb,-1,-Ga,-Gb,+1},...{+1,-1,+Ga(14:26), -Ga, +Gb, -1, -Ga, -Gb, +1},...
{0,0,0,0,0}]；{0,0,0,0,0}];
也可以表示为：Can also be expressed as:
HELTF-122,122＝{+1,-Ga,+Gb,-1,+Ga,+Gb,+Ga(1:13),+1,+1,HELTF -122,122 ={+1,-Ga,+Gb,-1,+Ga,+Gb,+Ga(1:13),+1,+1,
0,0,0,0,0,0,
+1,-1,+Ga(14:26),-Ga,+Gb,-1,-Ga,-Gb,+1}+1,-1,+Ga(14:26), -Ga, +Gb,-1,-Ga,-Gb,+1}
该HE-LTF序列中包括连续的Ga与Gb序列，位于空余leftover子载波位置上的+1或者-1，连续的-Ga和+Gb，或者，连续的+Ga和+Gb，或者，连续的-Ga和-Gb，或者，Ga(1:13)和Ga(14:26)。The HE-LTF sequence includes consecutive Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive -Ga and +Gb, or consecutive +Ga and +Gb, or continuous -Ga and -Gb, or, Ga (1:13) and Ga (14:26).
图6b示出20MHz带宽下HE-LTF序列的PAPR值。其中第一行数字是2.97、3.01、2.97、3.01、2.97、3.01、2.97、3.01，其依次是第一行26子载波资源块对应的PAPR值，即2.97是指从左向右第一个26子载波资源块对应PAPR值，接下来的3.01是指从左向右第二个26子载波资源块对应PAPR值， 依次类推；第二行数字是3.00、3.01、3.00、3.01，其依次是第二行52子载波资源块对应的PAPR值，即第一个3.00是指从左向右第一个52子载波资源块对应PAPR值，3.01是指从左向右第二个52子载波资源块对应PAPR值；第三行数字是3.81、3.90，其依次是第三行106子载波资源块对应的PAPR值，即第一个3.81是指从左向右第一个106子载波资源块对应PAPR值，3.90是指从左向右第二个106子载波资源块对应PAPR值；第三行数字4.29对应的是242子载波资源块的PAPR值。Figure 6b shows the PAPR value of the HE-LTF sequence at 20 MHz bandwidth. The first row of numbers is 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, which in turn is the PAPR value corresponding to the first row of 26 subcarrier resource blocks, that is, 2.97 refers to the first 26 from left to right. The subcarrier resource block corresponds to the PAPR value, and the next 3.01 refers to the PAPR value corresponding to the second 26 subcarrier resource block from left to right. And so on; the second row of numbers is 3.00, 3.01, 3.00, 3.01, which in turn is the PAPR value corresponding to the second row 52 subcarrier resource block, that is, the first 3.00 refers to the first 52 subcarrier resources from left to right. The block corresponds to the PAPR value, and 3.01 refers to the PAPR value corresponding to the second 52 subcarrier resource block from left to right; the third row number is 3.81 and 3.90, which in turn is the PAPR value corresponding to the third row 106 subcarrier resource block, that is, The first 3.81 refers to the corresponding PAPR value of the first 106 subcarrier resource blocks from left to right, 3.90 refers to the corresponding PAPR value of the second 106 subcarrier resource blocks from left to right; the third row of numbers 4.29 corresponds to 242. The PAPR value of the subcarrier resource block.
3、第三种HE-LTF序列3. The third HE-LTF sequence
HE-LTF序列如下：The HE-LTF sequence is as follows:
he_ltf_20mhz＝[{0,0,0,0,0,0},...He_ltf_20mhz=[{0,0,0,0,0,0},...
{+1,-Ga,+Gb,+1,+Ga,+Gb,+Gb(1:13),+1,-1},...{+1, -Ga, +Gb, +1, +Ga, +Gb, +Gb(1:13), +1,-1},...
{0,0,0},…{0,0,0},...
{-1,+1,+Gb(14:26),-Ga,+Gb,+1,-Ga,-Gb,+1},...{-1, +1, +Gb(14:26), -Ga, +Gb, +1, -Ga, -Gb, +1},...
{0,0,0,0,0}]；{0,0,0,0,0}];
也可以表示为：Can also be expressed as:
HELTF-122,122＝{+1,-Ga,+Gb,+1,+Ga,+Gb,+Gb(1:13),+1,-1,HELTF -122,122 ={+1,-Ga,+Gb,+1,+Ga,+Gb,+Gb(1:13),+1,-1,
0,0,0,0,0,0,
-1,+1,+Gb(14:26),-Ga,+Gb,+1,-Ga,-Gb,+1}-1, +1, +Gb(14:26), -Ga, +Gb, +1, -Ga, -Gb, +1}
该HE-LTF序列中包括Ga与Gb序列，位于空余leftover子载波位置上的+1或者-1，连续的-Ga和+Gb，或者，连续的+Ga和+Gb，或者，连续的-Ga和-Gb，或者，Gb(1:13)和Gb(14:26)。The HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive -Ga and +Gb, or continuous +Ga and +Gb, or continuous -Ga And -Gb, or, Gb (1:13) and Gb (14:26).
图6c示出20MHz带宽下HE-LTF序列的PAPR值，第一行数字是2.97、3.01、2.97、3.01、2.97、3.01、2.97、3.01，其依次是第一行26子载波资源块对应的PAPR值，即2.97是指从左向右第一个26子载波资源块对应PAPR值，接下来的3.01是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数字是3.00、3.01、3.00、3.01，其依次是第二行52子载波资源块对应的PAPR值，即第一个3.00是指从左向右第一个52子载波资源块 对应PAPR值，3.01是指从左向右第二个52子载波资源块对应PAPR值；第三行数字是3.94、3.89，其依次是第三行106子载波资源块对应的PAPR值，即第一个3.94是指从左向右第一个106子载波资源块对应PAPR值，3.89是指从左向右第二个106子载波资源块对应PAPR值；第三行数字4.30对应的是242子载波资源块的PAPR值。Figure 6c shows the PAPR value of the HE-LTF sequence in the 20MHz bandwidth. The first row of numbers is 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, which in turn is the PAPR corresponding to the first row 26 subcarrier resource blocks. The value, that is, 2.97 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 3.01 refers to the PAPR value corresponding to the second 26 subcarrier resource blocks from left to right, and so on; The numbers are 3.00, 3.01, 3.00, 3.01, which in turn are the PAPR values corresponding to the second row 52 subcarrier resource blocks, that is, the first 3.00 refers to the first 52 subcarrier resource blocks from left to right. Corresponding to the PAPR value, 3.01 refers to the PAPR value corresponding to the second 52 subcarrier resource block from left to right; the third row number is 3.94, 3.89, which in turn is the PAPR value corresponding to the third row 106 subcarrier resource block, that is, the first A 3.94 refers to the corresponding PAPR value of the first 106 subcarrier resource blocks from left to right, 3.89 refers to the corresponding PAPR value of the second 106 subcarrier resource blocks from left to right; the third line number 4.30 corresponds to 242 sub The PAPR value of the carrier resource block.
4、第三种HE-LTF序列4. The third HE-LTF sequence
HE-LTF序列如下：The HE-LTF sequence is as follows:
he_ltf_20mhz＝[{0,0,0,0,0,0},...He_ltf_20mhz=[{0,0,0,0,0,0},...
{+1,-Gb,+Ga,+1,+Gb,+Ga,+Gb(1:13),+1,-1},...{+1, -Gb, +Ga, +1, +Gb, +Ga, +Gb(1:13), +1,-1},...
{0,0,0},…{0,0,0},...
{-1,-1,+Gb(14:26),+Gb,-Ga,-1,+Gb,+Ga,+1},...{-1,-1,+Gb(14:26),+Gb,-Ga,-1,+Gb,+Ga,+1},...
{0,0,0,0,0}]；{0,0,0,0,0}];
也可以表示为：Can also be expressed as:
HELTF-122,122＝{+1,-Gb,+Ga,+1,+Gb,+Ga,+Gb(1:13),+1,-1,HELTF -122,122 ={+1,-Gb,+Ga,+1,+Gb,+Ga,+Gb(1:13),+1,-1,
0,0,0,0,0,0,
-1,-1,+Gb(14:26),+Gb,-Ga,-1,+Gb,+Ga,+1}-1, -1, +Gb(14:26), +Gb, -Ga, -1, +Gb, +Ga, +1}
该HE-LTF序列中包括Ga与Gb序列，位于空余leftover子载波位置上的+1或者-1，连续的-Gb和+Ga，或者，连续的+Gb和+Ga，或者，连续的+Gb和-Ga，或者，Gb(1:13)和Gb(14:26)。The HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive -Gb and +Ga, or consecutive +Gb and +Ga, or continuous +Gb And -Ga, or, Gb (1:13) and Gb (14:26).
图6d示出20MHz带宽下HE-LTF序列的PAPR值，第一行数字是3.01、2.97、3.01、2.97、3.01、2.97、3.01、2.97，其依次是第一行26子载波资源块对应的PAPR值，即3.01是指从左向右第一个26子载波资源块对应PAPR值，接下来的2.97是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数字是3.01、3.01、3.01、3.01，其依次是第二行52子载波资源块对应的PAPR值，即第一个3.01是指从左向右第一个52子载波资源块对应PAPR值，第二个3.01是指从左向右第二个52子载波资源块对应PAPR 值；第三行数字是3.69、3.81，其依次是第三行106子载波资源块对应的PAPR值，即第一个3.69是指从左向右第一个106子载波资源块对应PAPR值，3.81是指从左向右第二个106子载波资源块对应PAPR值；第三行数字4.45对应的是242子载波资源块的PAPR值。Figure 6d shows the PAPR value of the HE-LTF sequence in the 20 MHz bandwidth. The first row of numbers is 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, 3.01, 2.97, which in turn is the PAPR corresponding to the first row 26 subcarrier resource blocks. The value, that is, 3.01 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 2.97 refers to the corresponding PAPR value of the second 26 subcarrier resource blocks from left to right, and so on; The numbers are 3.01, 3.01, 3.01, and 3.01, which in turn are the PAPR values corresponding to the second row 52 subcarrier resource blocks, that is, the first 3.01 refers to the corresponding PAPR value of the first 52 subcarrier resource blocks from left to right. Two 3.01 means that the second 52 subcarrier resource blocks correspond to PAPR from left to right. The third row number is 3.69, 3.81, which in turn is the PAPR value corresponding to the third row 106 subcarrier resource block, that is, the first 3.69 refers to the PAPR value corresponding to the first 106 subcarrier resource block from left to right. 3.81 refers to the PAPR value corresponding to the second 106 subcarrier resource block from left to right; the third row number 4.45 corresponds to the PAPR value of the 242 subcarrier resource block.
实施例五 Embodiment 5
参考图1b，为802.11ax标准中可能的40MHz带宽的子载波分配方式的示意图：Referring to FIG. 1b, a schematic diagram of a subcarrier allocation manner of a possible 40 MHz bandwidth in the 802.11ax standard:
其中，40MHz带宽4x符号上有256个子载波，按照不同的资源块大小，如图所示RU大小可以是26、52、106、242、484个子载波。There are 256 subcarriers on the 40x bandwidth 4x symbol. According to different resource block sizes, the RU size may be 26, 52, 106, 242, 484 subcarriers as shown.
40MHz 484子载波4X符号上的HE-LTF序列有很多种，下面仅罗列出其中的几种：There are many HE-LTF sequences on the 4X symbol of the 40MHz 484 subcarrier. Only a few of them are listed below:
1.第一种HE-LTF序列1. The first HE-LTF sequence
he_ltf_40Mhz＝he_ltf_40Mhz=
[{0,0,0,0,0,0,0,0,0,0,0,0},...[{0,0,0,0,0,0,0,0,0,0,0,0},...
{+1,+Ga,-Gb,+1,-1,-Ga,-Gb,-1,+Ga,+1,+Ga,-Gb,+1,+1,+Ga,+Gb,-1},...{+1,+Ga,-Gb,+1,-1,-Ga,-Gb,-1,+Ga,+1,+Ga,-Gb,+1,+1,+Ga,+Gb,- 1},...
{0,0,0,0,0},...{0,0,0,0,0},...
{-1,+Ga,-Gb,+1,+1,-Ga,-Gb,+1,-Gb,+1,-Ga,+Gb,+1,-1,-Ga,-Gb,-1},...{-1, +Ga, -Gb, +1, +1, -Ga, -Gb, +1, -Gb, +1, -Ga, +Gb, +1, -1, -Ga, -Gb, - 1},...
{0,0,0,0,0,0,0,0,0,0,0}]；{0,0,0,0,0,0,0,0,0,0,0}];
也可以表示为：Can also be expressed as:
HELTF-244,244＝{+1,+Ga,-Gb,+1,-1,-Ga,-Gb,-1,+Ga,+1,+Ga,-Gb,+1,+1,+Ga,+Gb,-1,HELTF -244,244 ={+1,+Ga,-Gb,+1,-1,-Ga,-Gb,-1,+Ga,+1,+Ga,-Gb,+1,+1,+Ga, +Gb, -1,
0,0,0,0,0, 0,0,0,0,0,
-1,+Ga,-Gb,+1,+1,-Ga,-Gb,+1,-Gb,+1,-Ga,+Gb,+1,-1,-Ga,-Gb,-1}-1, +Ga, -Gb, +1, +1, -Ga, -Gb, +1, -Gb, +1, -Ga, +Gb, +1, -1, -Ga, -Gb, -1 }
该HE-LTF序列中包括Ga与Gb序列，位于空余leftover子载波位置上的+1或者-1，连续的-Ga和-Gb，或者，连续的+Ga和+Gb，或者，连续的+Ga和-Gb，或者，连续的-Ga和+Gb。The HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, continuous -Ga and -Gb, or continuous +Ga and +Gb, or continuous +Ga And -Gb, or, continuous -Ga and +Gb.
图7a示出40MHz带宽下HE-LTF序列的PAPR值，第一行数字是2.97、3.01、2.97、3.01等等，其依次是第一行26子载波资源块对应的PAPR值，即2.97是指从左向右第一个26子载波资源块对应PAPR值，接下来的3.01是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数字是3.01、3.01、3.01、3.01等等，其依次是第二行52子载波资源块对应的PAPR值，即第一个3.01是指从左向右第一个52子载波资源块对应PAPR值，3.01是指从左向右第二个52子载波资源块对应PAPR值；第三行数字是3.92、3.96等，其依次是第三行106子载波资源块对应的PAPR值，即第一个3.92是指从左向右第一个106子载波资源块对应PAPR值，3.96是指从左向右第二个106子载波资源块对应PAPR值；第四行数字是4.48、4.46，其依次是242子载波资源块对应的PAPR值，对应的是242子载波资源块的PAPR值；第五行数字4.64是484子载波资源块对应的PAPR值。7a shows the PAPR value of the HE-LTF sequence in the 40 MHz bandwidth, the first row number is 2.97, 3.01, 2.97, 3.01, etc., which in turn is the PAPR value corresponding to the first row 26 subcarrier resource block, ie 2.97 refers to The first 26 subcarrier resource blocks from left to right correspond to the PAPR value, and the next 3.01 refers to the PAPR value corresponding to the second 26 subcarrier resource blocks from left to right, and so on; the second row number is 3.01, 3.01. 3.01, 3.01, etc., which in turn are the PAPR values corresponding to the second row 52 subcarrier resource blocks, that is, the first 3.01 refers to the corresponding PAPR value of the first 52 subcarrier resource blocks from left to right, and 3.01 refers to the left. The second 52 subcarrier resource block to the right corresponds to the PAPR value; the third row number is 3.92, 3.96, etc., which in turn is the PAPR value corresponding to the third row 106 subcarrier resource block, that is, the first 3.92 refers to the leftward direction. The first 106 subcarrier resource block corresponds to the PAPR value, and 3.96 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right; the fourth row number is 4.48 and 4.46, which in turn is 242 subcarrier resource block corresponding The PAPR value corresponds to the PAPR value of the 242 subcarrier resource block; the fifth line number 4.64 is the 484 subcarrier resource. Corresponding PAPR value.
2.第二种HE-LTF序列2. The second HE-LTF sequence
he_ltf_40Mhz＝[{0,0,0,0,0,0,0,0,0,0,0,0},...He_ltf_40Mhz=[{0,0,0,0,0,0,0,0,0,0,0,0},...
{+1,-Ga,-Gb,-1,-1,+Ga,-Gb,+1,-Gb,-1,-Ga,-Gb,+1,-1,-Ga,+Gb,-1},...{+1, -Ga, -Gb, -1, -1, +Ga, -Gb, +1, -Gb, -1, -Ga, -Gb, +1, -1, -Ga, +Gb, - 1},...
{0,0,0,0,0},...{0,0,0,0,0},...
{-1,+Ga,+Gb,+1,-1,-Ga,+Gb,+1,-Ga,-1,-Ga,-Gb,+1,-1,-Ga,+Gb,+1},...{-1, +Ga, +Gb, +1, -1, -Ga, +Gb, +1, -Ga, -1, -Ga, -Gb, +1, -1, -Ga, +Gb, + 1},...
{0,0,0,0,0,0,0,0,0,0,0}]；{0,0,0,0,0,0,0,0,0,0,0}];
也可以表示为：Can also be expressed as:
HELTF-244,244＝{+1,-Ga,-Gb,-1,-1,+Ga,-Gb,+1,-Gb,-1,-Ga,-Gb,+1,-1,-Ga, +Gb,-1,HELTF -244,244 ={+1,-Ga,-Gb,-1,-1,+Ga,-Gb,+1,-Gb,-1,-Ga,-Gb,+1,-1,-Ga, +Gb, -1,
0,0,0,0,0,0,0,0,0,0,
-1,+Ga,+Gb,+1,-1,-Ga,+Gb,+1,-Ga,-1,-Ga,-Gb,+1,-1,-Ga,+Gb,+1}-1, +Ga, +Gb, +1, -1, -Ga, +Gb, +1, -Ga, -1, -Ga, -Gb, +1, -1, -Ga, +Gb, +1 }
该HE-LTF序列中包括Ga与Gb序列，位于空余leftover子载波位置上的+1或者-1，连续的-Ga和-Gb，或者，连续的+Ga和+Gb，或者，连续的+Ga和-Gb，或者，连续的-Ga和+Gb。The HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, continuous -Ga and -Gb, or continuous +Ga and +Gb, or continuous +Ga And -Gb, or, continuous -Ga and +Gb.
图7b示出40MHz带宽下HE-LTF序列的PAPR值，第一行数字是2.97、3.01、2.97、3.01等等，其从左向右依次是第一行26子载波资源块对应的PAPR值，即2.97是指从左向右第一个26子载波资源块对应PAPR值，接下来的3.01是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数字是3.01、3.01、3.01、3.01等等，其从左向右依次是第二行52子载波资源块对应的PAPR值，即第一个3.01是指从左向右第一个52子载波资源块对应PAPR值，3.01是指从左向右第二个52子载波资源块对应PAPR值；第三行数字是3.74、3.81等，其从左向右依次是第三行106子载波资源块对应的PAPR值，即第一个3.74是指从左向右第一个106子载波资源块对应PAPR值，3.81是指从左向右第二个106子载波资源块对应PAPR值；第四行数字是4.59、4.30，其从左向右依次是242子载波资源块对应的PAPR值，4.59是指从左向右第一个242子载波资源块对应PAPR值；第五行数字4.60是484子载波资源块对应的PAPR值。7b shows the PAPR value of the HE-LTF sequence in the 40 MHz bandwidth, the first line number is 2.97, 3.01, 2.97, 3.01, etc., which is the PAPR value corresponding to the first row 26 subcarrier resource block from left to right. That is, 2.97 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 3.01 refers to the corresponding PAPR value of the second 26 subcarrier resource blocks from left to right, and so on; the second line is 3.01, 3.01, 3.01, 3.01, etc., from left to right, the PAPR value corresponding to the second row 52 subcarrier resource block, that is, the first 3.01 refers to the first 52 subcarrier resource block corresponding from left to right. The PAPR value, 3.01 refers to the PAPR value corresponding to the second 52 subcarrier resource block from left to right; the third row number is 3.74, 3.81, etc., which is the PAPR corresponding to the third row 106 subcarrier resource block from left to right. The value, that is, the first 3.74 refers to the PAPR value corresponding to the first 106 subcarrier resource block from left to right, and the 3.81 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right; the fourth line number is 4.59. 4.30, which is the PAPR value corresponding to the 242 subcarrier resource block from left to right, and 4.59 refers to the first 242 subcarrier from left to right. The wave resource block corresponds to the PAPR value; the fifth row number 4.60 is the PAPR value corresponding to the 484 subcarrier resource block.
3.第三种HE-LTF序列3. The third HE-LTF sequence
he_ltf_40Mhz＝[{0,0,0,0,0,0,0,0,0,0,0,0},...He_ltf_40Mhz=[{0,0,0,0,0,0,0,0,0,0,0,0},...
{+1,-Gb,-Ga,+1,-1,-Gb,+Ga,-1,-Ga,+1,+Gb,+Ga,+1,+1,-Gb,+Ga,+1},...{+1, -Gb, -Ga, +1, -1, -Gb, +Ga, -1, -Ga, +1, +Gb, +Ga, +1, +1, -Gb, +Ga, + 1},...
{0,0,0,0,0},...{0,0,0,0,0},...
{-1,+Gb,+Ga,-1,-1,+Gb,-Ga,-1,-Gb,+1,+Gb,+Ga,+1,+1,-Gb,+Ga,+1},...{-1, +Gb, +Ga, -1, -1, +Gb, -Ga, -1, -Gb, +1, +Gb, +Ga, +1, +1, -Gb, +Ga, + 1},...
{0,0,0,0,0,0,0,0,0,0,0}]；{0,0,0,0,0,0,0,0,0,0,0}];
也可以表示为：Can also be expressed as:
HELTF-244,244＝{+1,-Gb,-Ga,+1,-1,-Gb,+Ga,-1,-Ga,+1,+Gb,+Ga,+1,+1,-Gb, +Ga,+1,HELTF -244,244 ={+1,-Gb,-Ga,+1,-1,-Gb,+Ga,-1,-Ga,+1,+Gb,+Ga,+1,+1,-Gb, +Ga, +1,
0,0,0,0,0,0,0,0,0,0,
-1,+Gb,+Ga,-1,-1,+Gb,-Ga,-1,-Gb,+1,+Gb,+Ga,+1,+1,-Gb,+Ga,+1}-1,+Gb,+Ga,-1,-1,+Gb,-Ga,-1,-Gb,+1,+Gb,+Ga,+1,+1,-Gb,+Ga,+1 }
该HE-LTF序列中包括Ga与Gb序列，位于空余leftover子载波位置上的+1或者-1，连续的-Gb和-Ga，或者，连续的-Gb和+Ga，或者，连续的+Gb和+Ga，或者，连续的+Gb和-Ga。The HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive -Gb and -Ga, or consecutive -Gb and +Ga, or continuous +Gb And +Ga, or, continuous +Gb and -Ga.
图7c示出40MHz带宽下HE-LTF序列的PAPR值，第一行数字是3.01、2.97、3.01、2.97等等，其从左向右依次是第一行26子载波资源块对应的PAPR值，即3.0072是指从左向右第一个26子载波资源块对应PAPR值，接下来的2.97是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数字是3.01、3.01、3.01、3.01等等，其从左向右依次是第二行52子载波资源块对应的PAPR值，即第一个3.01是指从左向右第一个52子载波资源块对应PAPR值，3.01是指从左向右第二个52子载波资源块对应PAPR值；第三行数字是3.76、3.87等，其从左向右依次是第三行106子载波资源块对应的PAPR值，即第一个3.76是指从左向右第一个106子载波资源块对应PAPR值，3.87是指从左向右第二个106子载波资源块对应PAPR值；第四行数字是4.59、4.57，其从左向右依次是242子载波资源块对应的PAPR值，4.59是指从左向右第一个242子载波资源块对应PAPR值；第五行数字4.59是484子载波资源块对应的PAPR值。7c shows the PAPR value of the HE-LTF sequence in the 40 MHz bandwidth, the first row number is 3.01, 2.97, 3.01, 2.97, etc., which is the PAPR value corresponding to the first row 26 subcarrier resource block from left to right. That is, 3.0072 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 2.97 refers to the corresponding PAPR value of the second 26 subcarrier resource blocks from left to right, and so on; the second line is 3.01, 3.01, 3.01, 3.01, etc., from left to right, the PAPR value corresponding to the second row 52 subcarrier resource block, that is, the first 3.01 refers to the first 52 subcarrier resource block corresponding from left to right. The PAPR value, 3.01 refers to the PAPR value corresponding to the second 52 subcarrier resource block from left to right; the third row number is 3.76, 3.87, etc., which is the PAPR corresponding to the third row 106 subcarrier resource block from left to right. The value, that is, the first 3.76 refers to the PAPR value corresponding to the first 106 subcarrier resource block from left to right, and 3.87 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right; the fourth line number is 4.59. 4.57, which is the PAPR value corresponding to the 242 subcarrier resource block from left to right, and 4.59 refers to the first 242 subtitle from left to right. Wave PAPR value corresponding to the resource blocks; fifth line 484 is 4.59 digital value PAPR sub-carriers corresponding to the resource blocks.
4.第四种HE-LTF序列4. The fourth HE-LTF sequence
he_ltf_40Mhz＝[{0,0,0,0,0,0,0,0,0,0,0,0},...He_ltf_40Mhz=[{0,0,0,0,0,0,0,0,0,0,0,0},...
{+1,+Gb,+Ga,-1,-1,-Gb,+Ga,+1,-Gb,+1,-Gb,-Ga,-1,+1,-Gb,+Ga,-1},...{+1,+Gb,+Ga,-1,-1,-Gb,+Ga,+1,-Gb,+1,-Gb,-Ga,-1,+1,-Gb,+Ga,- 1},...
{0,0,0,0,0},...{0,0,0,0,0},...
{+1,-Gb,-Ga,+1,+1,+Gb,-Ga,+1,+Ga,+1,-Gb,-Ga,+1,-1,-Gb,+Ga,-1},...{+1, -Gb, -Ga, +1, +1, +Gb, -Ga, +1, +Ga, +1, -Gb, -Ga, +1, -1, -Gb, +Ga, - 1},...
{0,0,0,0,0,0,0,0,0,0,0}]； {0,0,0,0,0,0,0,0,0,0,0}];
也可以表示为：Can also be expressed as:
HELTF-244,244＝{+1,+Gb,+Ga,-1,-1,-Gb,+Ga,+1,-Gb,+1,-Gb,-Ga,-1,+1,-Gb,+Ga,-1,HELTF -244,244 ={+1,+Gb,+Ga,-1,-1,-Gb,+Ga,+1,-Gb,+1,-Gb,-Ga,-1,+1,-Gb, +Ga, -1,
0,0,0,0,0,0,0,0,0,0,
+1,-Gb,-Ga,+1,+1,+Gb,-Ga,+1,+Ga,+1,-Gb,-Ga,+1,-1,-Gb,+Ga,-1}+1, -Gb, -Ga, +1, +1, +Gb, -Ga, +1, +Ga, +1, -Gb, -Ga, +1, -1, -Gb, +Ga, -1 }
该HE-LTF序列中包括Ga与Gb序列，位于空余leftover子载波位置上的+1或者-1，连续的-Gb和-Ga，或者，连续的-Gb和+Ga，或者，连续的+Gb和+Ga，或者，连续的+Gb和-Ga。The HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive -Gb and -Ga, or consecutive -Gb and +Ga, or continuous +Gb And +Ga, or, continuous +Gb and -Ga.
图7d示出40MHz带宽下HE-LTF序列的PAPR值，第一行数字是3.01、2.97、3.01、2.97等等，其从左向右依次是第一行26子载波资源块对应的PAPR值，即3.0072是指从左向右第一个26子载波资源块对应PAPR值，接下来的2.97是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数字是3.01、3.01、3.01、3.01等等，其从左向右依次是第二行52子载波资源块对应的PAPR值，即第一个3.01是指从左向右第一个52子载波资源块对应PAPR值，第二个3.01是指从左向右第二个52子载波资源块对应PAPR值；第三行数字是3.65、3.88等，其从左向右依次是第三行106子载波资源块对应的PAPR值，即第一个3.65是指从左向右第一个106子载波资源块对应PAPR值，3.88是指从左向右第二个106子载波资源块对应PAPR值；第四行数字是4.57、4.52，其从左向右依次是242子载波资源块对应的PAPR值，4.57是指从左向右第一个242子载波资源块对应PAPR值；第五行数字4.62是484子载波资源块对应的PAPR值。7d shows the PAPR value of the HE-LTF sequence in the 40 MHz bandwidth, the first row number is 3.01, 2.97, 3.01, 2.97, etc., which is the PAPR value corresponding to the first row 26 subcarrier resource block from left to right. That is, 3.0072 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 2.97 refers to the corresponding PAPR value of the second 26 subcarrier resource blocks from left to right, and so on; the second line is 3.01, 3.01, 3.01, 3.01, etc., from left to right, the PAPR value corresponding to the second row 52 subcarrier resource block, that is, the first 3.01 refers to the first 52 subcarrier resource block corresponding from left to right. The PAPR value, the second 3.01 refers to the second 52 subcarrier resource block corresponding to the PAPR value from left to right; the third row number is 3.65, 3.88, etc., which is the third row 106 subcarrier resource block from left to right. The corresponding PAPR value, that is, the first 3.65 refers to the corresponding PAPR value of the first 106 subcarrier resource block from left to right, and 3.88 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right; the fourth row The numbers are 4.57 and 4.52, which are the PAPR values corresponding to the 242 subcarrier resource blocks from left to right, and 4.57 refers to the first from left to right. 242 subcarrier resource block corresponding PAPR value; fifth line 484 is 4.62 digital subcarrier resource block corresponding PAPR value.
实施例六 Embodiment 6
参考图1c，为802.11ax标准中，80MHz带宽的子载波分配方式的简单示意图。Referring to FIG. 1c, it is a simple schematic diagram of a subcarrier allocation manner of an 80 MHz bandwidth in the 802.11ax standard.
80MHz带宽4x符号上有256个子载波，按照不同的资源块大小，如图1c所示RU大小可以是26、52、106、242、484、996个子载波。There are 256 subcarriers on the 4x symbol of the 80MHz bandwidth. According to different resource block sizes, the RU size may be 26, 52, 106, 242, 484, 996 subcarriers as shown in FIG. 1c.
80MHz 996子载波4X符号上的HE-LTF序列有很多种，下面罗列中几种： There are many HE-LTF sequences on the 4X symbol of the 80MHz 996 subcarrier, and several of them are listed below:
1.80MHz 996子载波4X符号上的第一种HE-LTF序列The first HE-LTF sequence on the 1.XMHz 996 subcarrier 4X symbol
he_ltf_80mhz＝[{0,0,0,0,0,0,0,0,0,0,0,0},...He_ltf_80mhz=[{0,0,0,0,0,0,0,0,0,0,0,0},...
{-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Gb,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,-1},...{-1, -Ga, +Gb, +1, +1, +Ga, +Gb, -1, +Gb, -1, -Ga, +Gb, +1, +1, -Ga, -Gb, - 1},...
{-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Ga,+1,+Ga,-Gb,-1,-1,+Ga,+Gb,+1},...{-1, -Ga, +Gb, +1, +1, +Ga, +Gb, -1, +Ga, +1, +Ga, -Gb, -1, -1, +Ga, +Gb, + 1},...
{+Ga(1:13),+1},...{+Ga(1:13), +1},...
{0,0,0,0,0},...{0,0,0,0,0},...
{-1,+Ga(14:26)},...{-1, +Ga(14:26)},...
{-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Gb,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,-1},...{-1, -Ga, +Gb, +1, +1, +Ga, +Gb, -1, +Gb, -1, -Ga, +Gb, +1, +1, -Ga, -Gb, - 1},...
{+1,+Ga,-Gb,-1,-1,-Ga,-Gb,+1,-Ga,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,-1},...{+1,+Ga,-Gb,-1,-1,-Ga,-Gb,+1,-Ga,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,- 1},...
{0,0,0,0,0,0,0,0,0,0,0},...]；{0,0,0,0,0,0,0,0,0,0,0},...];
也可以表示为：Can also be expressed as:
HELTF-500,500＝{-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Gb,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,-1,HELTF -500,500 ={-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Gb,-1,-Ga,+Gb,+1,+1,-Ga, -Gb, -1,
-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Ga,+1,+Ga,-Gb,-1,-1,+Ga,+Gb,+1,-1, -Ga, +Gb, +1, +1, +Ga, +Gb, -1, +Ga, +1, +Ga, -Gb, -1, -1, +Ga, +Gb, +1 ,
+Ga(1:13),+1,+Ga(1:13), +1,
0,0,0,0,0,0,0,0,0,0,
-1,+Ga(14:26),-1, +Ga(14:26),
-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Gb,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,-1,-1, -Ga, +Gb, +1, +1, +Ga, +Gb, -1, +Gb, -1, -Ga, +Gb, +1, +1, -Ga, -Gb, -1 ,
+1,+Ga,-Gb,-1,-1,-Ga,-Gb,+1,-Ga,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,-1}+1,+Ga,-Gb,-1,-1,-Ga,-Gb,+1,-Ga,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,-1 }
该HE-LTF序列中包括Ga与Gb序列，位于空余leftover子载波位置上的+1或者-1，连续的-Gb和-Ga，或者，连续的-Gb和+Ga，或者，连续的+Gb和+Ga，或者，连续的+Gb和-Ga，并且HE-LTF序列中红色标识的两行完全相同，蓝色标识的两行极性相反。 The HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive -Gb and -Ga, or consecutive -Gb and +Ga, or continuous +Gb And +Ga, or consecutive +Gb and -Ga, and the two lines of the red mark in the HE-LTF sequence are identical, and the two lines of the blue mark are opposite in polarity.
图8a示出80MHz带宽下HE-LTF序列的PAPR值，第一行数字是2.97、3.01、2.97、3.01等等，其从左向右依次是第一行26子载波资源块对应的PAPR值，即2.97是指从左向右第一个26子载波资源块对应PAPR值，接下来的3.01是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数字是3.01、3.01等等，其从左向右依次是第二行52子载波资源块对应的PAPR值，即第一个3.01是指从左向右第一个52子载波资源块对应PAPR值，第二个3.01是指从左向右第二个52子载波资源块对应PAPR值；第三行数字是3.91、3.91等，其从左向右依次是第三行106子载波资源块对应的PAPR值，即第一个3.91是指从左向右第一个106子载波资源块对应PAPR值，第二个3.91是指从左向右第二个106子载波资源块对应PAPR值；第四行数字是4.51、4.56等等，其从左向右依次是242子载波资源块对应的PAPR值，4.51是指从左向右第一个242子载波资源块对应PAPR值；第五行数字是4.70、4.77等等，其从左向右依次是242子载波资源块对应的PAPR值，4.70是指从左向右第一个484子载波资源块对应PAPR值；第六行数字4.91是996子载波子载波资源块对应的PAPR值。8a shows the PAPR value of the HE-LTF sequence in the 80 MHz bandwidth, the first line number is 2.97, 3.01, 2.97, 3.01, etc., which is the PAPR value corresponding to the first row 26 subcarrier resource block from left to right. That is, 2.97 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 3.01 refers to the corresponding PAPR value of the second 26 subcarrier resource blocks from left to right, and so on; the second line is 3.01, 3.01, etc., from left to right, the PAPR value corresponding to the second row 52 subcarrier resource block, that is, the first 3.01 refers to the PAPR value corresponding to the first 52 subcarrier resource block from left to right, The two 3.01s refer to the PAPR value corresponding to the second 52 subcarrier resource block from left to right; the third row number is 3.91, 3.91, etc., which is the PAPR value corresponding to the third row 106 subcarrier resource block from left to right. , that is, the first 3.91 refers to the PAPR value corresponding to the first 106 subcarrier resource block from left to right, and the second 3.91 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right; the fourth row of numbers Is 4.51, 4.56, etc., from left to right, the PAPR value corresponding to the 242 subcarrier resource block, and 4.51 refers to the first from left to right. The 242 subcarrier resource block corresponds to the PAPR value; the fifth row number is 4.70, 4.77, etc., which is the PAPR value corresponding to the 242 subcarrier resource block from left to right, and 4.70 refers to the first 484 subcarrier resource from left to right. The block corresponds to the PAPR value; the sixth line number 4.91 is the PAPR value corresponding to the 996 subcarrier subcarrier resource block.
2.第二种HE-LTF序列2. The second HE-LTF sequence
he_ltf_80mhz＝[{0,0,0,0,0,0,0,0,0,0,0,0},...He_ltf_80mhz=[{0,0,0,0,0,0,0,0,0,0,0,0},...
{-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Gb,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,-1},...{-1, -Ga, +Gb, +1, +1, +Ga, +Gb, -1, +Gb, -1, -Ga, +Gb, +1, +1, -Ga, -Gb, - 1},...
{-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Ga,+1,+Ga,-Gb,-1,-1,+Ga,+Gb,+1},...{-1, -Ga, +Gb, +1, +1, +Ga, +Gb, -1, +Ga, +1, +Ga, -Gb, -1, -1, +Ga, +Gb, + 1},...
{+Gb(1:13),+1},...{+Gb(1:13), +1},...
{0,0,0,0,0},...{0,0,0,0,0},...
{-1,+Gb(14:26)},...{-1, +Gb(14:26)},...
{-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Gb,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,-1},...{-1, -Ga, +Gb, +1, +1, +Ga, +Gb, -1, +Gb, -1, -Ga, +Gb, +1, +1, -Ga, -Gb, - 1},...
{+1,+Ga,-Gb,-1,-1,-Ga,-Gb,+1,-Ga,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,-1},...{+1,+Ga,-Gb,-1,-1,-Ga,-Gb,+1,-Ga,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,- 1},...
{0,0,0,0,0,0,0,0,0,0,0},...]；{0,0,0,0,0,0,0,0,0,0,0},...];
也可以表示为Can also be expressed as
HELTF-500,500＝{-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Gb,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,-1， HELTF -500,500 ={-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Gb,-1,-Ga,+Gb,+1,+1,-Ga, -Gb, -1,
-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Ga,+1,+Ga,-Gb,-1,-1,+Ga,+Gb,+1，-1, -Ga, +Gb, +1, +1, +Ga, +Gb, -1, +Ga, +1, +Ga, -Gb, -1, -1, +Ga, +Gb, +1 ,
+Gb(1:13),+1，+Gb(1:13), +1,
0,0,0,0,0，0,0,0,0,0,
-1,+Gb(14:26)，-1, +Gb (14:26),
-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Gb,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,-1，-1, -Ga, +Gb, +1, +1, +Ga, +Gb, -1, +Gb, -1, -Ga, +Gb, +1, +1, -Ga, -Gb, -1 ,
+1,+Ga,-Gb,-1,-1,-Ga,-Gb,+1,-Ga,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,-1}+1,+Ga,-Gb,-1,-1,-Ga,-Gb,+1,-Ga,-1,-Ga,+Gb,+1,+1,-Ga,-Gb,-1 }
该HE-LTF序列中包括Ga与Gb序列，位于空余leftover子载波位置上的+1或者-1，连续的-Ga和+Gb，或者，连续的+Ga和+Gb，或者，连续的-Ga和+Gb，或者，连续的-Ga和-Gb，或者，Gb(1:13)和Gb(14:26)。The HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive -Ga and +Gb, or continuous +Ga and +Gb, or continuous -Ga And +Gb, or, consecutive -Ga and -Gb, or, Gb (1:13) and Gb (14:26).
图8b给出80MHz带宽下HE-LTF序列的PAPR值，第一行数字是2.97、3.01、2.97、3.01等等，其从左向右依次是第一行26子载波资源块对应的PAPR值，即2.97是指从左向右第一个26子载波资源块对应PAPR值，接下来的3.01是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数字是3.01、3.01等等，其从左向右依次是第二行52子载波资源块对应的PAPR值，即第一个3.01是指从左向右第一个52子载波资源块对应PAPR值，第二个3.01是指从左向右第二个52子载波资源块对应PAPR值；第三行数字是3.91、3.91等，其从左向右依次是第三行106子载波资源块对应的PAPR值，即第一个3.91是指从左向右第一个106子载波资源块对应PAPR值，第二个3.91是指从左向右第二个106子载波资源块对应PAPR值；第四行数字是4.50、4.56等等，其从左向右依次是242子载波资源块对应的PAPR值，4.50是指从左向右第一个242子载波资源块对应PAPR值；第五行数字是4.70、4.76等等，其从左向右依次是242子载波资源块对应的PAPR值，4.70是指从左向右第一个484子载波资源块对应PAPR值；第六行数字4.92是996子载波子载波资源块对应的PAPR值。Figure 8b shows the PAPR value of the HE-LTF sequence in the 80MHz bandwidth. The first row of numbers is 2.97, 3.01, 2.97, 3.01, etc., which is the PAPR value corresponding to the first row of 26 subcarrier resource blocks from left to right. That is, 2.97 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 3.01 refers to the corresponding PAPR value of the second 26 subcarrier resource blocks from left to right, and so on; the second line is 3.01, 3.01, etc., from left to right, the PAPR value corresponding to the second row 52 subcarrier resource block, that is, the first 3.01 refers to the PAPR value corresponding to the first 52 subcarrier resource block from left to right, The two 3.01s refer to the PAPR value corresponding to the second 52 subcarrier resource block from left to right; the third row number is 3.91, 3.91, etc., which is the PAPR value corresponding to the third row 106 subcarrier resource block from left to right. , that is, the first 3.91 refers to the PAPR value corresponding to the first 106 subcarrier resource block from left to right, and the second 3.91 refers to the corresponding PAPR value of the second 106 subcarrier resource block from left to right; the fourth row of numbers It is 4.50, 4.56, etc., which is the PAPR value corresponding to the 242 subcarrier resource block from left to right, and 4.50 refers to the first from left to right. The 242 subcarrier resource block corresponds to the PAPR value; the fifth row number is 4.70, 4.76, etc., which is the PAPR value corresponding to the 242 subcarrier resource block from left to right, and 4.70 refers to the first 484 subcarrier resource from left to right. The block corresponds to the PAPR value; the sixth line number 4.92 is the PAPR value corresponding to the 996 subcarrier subcarrier resource block.
3.第三种HE-LTF序列 3. The third HE-LTF sequence
he_ltf_80mhz＝[{0,0,0,0,0,0,0,0,0,0,0,0},...He_ltf_80mhz=[{0,0,0,0,0,0,0,0,0,0,0,0},...
{+1,+Ga,-Gb,-1,-1,-Ga,-Gb,+1,-Ga,-1,+Ga,-Gb,+1,+1,+Ga,+Gb,-1},...{+1,+Ga,-Gb,-1,-1,-Ga,-Gb,+1,-Ga,-1,+Ga,-Gb,+1,+1,+Ga,+Gb,- 1},...
{+1,-Ga,+Gb,+1,-1,+Ga,+Gb,+1,-Gb,+1,+Ga,-Gb,+1,+1,+Ga,+Gb,+1},...{+1,-Ga,+Gb,+1,-1,+Ga,+Gb,+1,-Gb,+1,+Ga,-Gb,+1,+1,+Ga,+Gb,+ 1},...
{+Gb(1:13),+1},...{+Gb(1:13), +1},...
{0,0,0,0,0},...{0,0,0,0,0},...
{-1,+Gb(14:26)},...{-1, +Gb(14:26)},...
{-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Ga,+1,-Ga,+Gb,-1,-1,-Ga,-Gb,+1},...{-1, -Ga, +Gb, +1, +1, +Ga, +Gb, -1, +Ga, +1, -Ga, +Gb, -1, -1, -Ga, -Gb, + 1},...
{+1,-Ga,+Gb,-1,-1,+Ga,+Gb,+1,-Gb,+1,+Ga,-Gb,+1,-1,+Ga,+Gb,+1},...{+1, -Ga, +Gb, -1, -1, +Ga, +Gb, +1, -Gb, +1, +Ga, -Gb, +1, -1, +Ga, +Gb, + 1},...
{0,0,0,0,0,0,0,0,0,0,0},...]；{0,0,0,0,0,0,0,0,0,0,0},...];
也可以表示为Can also be expressed as
HE LTF-500,500＝{+1,+Ga,-Gb,-1,-1,-Ga,-Gb,+1,-Ga,-1,+Ga,-Gb,+1,+1,+Ga,+Gb,-1，HE LTF -500,500 ={+1,+Ga,-Gb,-1,-1,-Ga,-Gb,+1,-Ga,-1,+Ga,-Gb,+1,+1,+Ga , +Gb, -1,
+1,-Ga,+Gb,+1,-1,+Ga,+Gb,+1,-Gb,+1,+Ga,-Gb,+1,+1,+Ga,+Gb,+1，+1, -Ga, +Gb, +1, -1, +Ga, +Gb, +1, -Gb, +1, +Ga, -Gb, +1, +1, +Ga, +Gb, +1 ,
+Gb(1:13),+1，+Gb(1:13), +1,
0,0,0,0,0，0,0,0,0,0,
-1,+Gb(14:26)，-1, +Gb (14:26),
-1,-Ga,+Gb,+1,+1,+Ga,+Gb,-1,+Ga,+1,-Ga,+Gb,-1,-1,-Ga,-Gb,+1，-1, -Ga, +Gb, +1, +1, +Ga, +Gb, -1, +Ga, +1, -Ga, +Gb, -1, -1, -Ga, -Gb, +1 ,
+1,-Ga,+Gb,-1,-1,+Ga,+Gb,+1,-Gb,+1,+Ga,-Gb,+1,-1,+Ga,+Gb,+1}+1, -Ga, +Gb, -1, -1, +Ga, +Gb, +1, -Gb, +1, +Ga, -Gb, +1, -1, +Ga, +Gb, +1 }
该HE-LTF序列中包括Ga与Gb序列，位于空余leftover子载波位置上的+1或者-1，连续的+Ga和-Gb，或者，连续的-Ga和-Gb，或者，连续的+Ga和+Gb，或者，连续的-Ga和+Gb，或者，Gb(1:13)和Gb(14:26)。The HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, +Ga and -Gb consecutive, or continuous -Ga and -Gb, or continuous +Ga And +Gb, or, consecutive -Ga and +Gb, or, Gb (1:13) and Gb (14:26).
图8c给出80MHz带宽下HE-LTF序列的PAPR值，第一行数字是2.97、3.01、 2.97、3.01等等，其从左向右依次是第一行26子载波资源块对应的PAPR值，即2.97是指从左向右第一个26子载波资源块对应PAPR值，接下来的3.01是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数字是3.01、3.01等等，其从左向右依次是第二行52子载波资源块对应的PAPR值，即第一个3.01是指从左向右第一个52子载波资源块对应PAPR值，第二个3.01是指从左向右第二个52子载波资源块对应PAPR值；第三行数字是3.91、3.96等，其从左向右依次是第三行106子载波资源块对应的PAPR值，即第一个3.91是指从左向右第一个106子载波资源块对应PAPR值，3.96是指从左向右第二个106子载波资源块对应PAPR值；第四行数字是4.53、4.56等等，其从左向右依次是242子载波资源块对应的PAPR值，4.53是指从左向右第一个242子载波资源块对应PAPR值；第五行数字是4.90、4.82等等，其从左向右依次是242子载波资源块对应的PAPR值，4.90是指从左向右第一个484子载波资源块对应PAPR值；第六行数字4.97是996子载波子载波资源块对应的PAPR值。Figure 8c shows the PAPR value of the HE-LTF sequence at 80MHz bandwidth. The first line number is 2.97, 3.01. 2.97, 3.01, etc., from left to right, is the PAPR value corresponding to the first row 26 subcarrier resource block, that is, 2.97 refers to the PAPR value corresponding to the first 26 subcarrier resource block from left to right, and the next 3.01 It refers to the PAPR value corresponding to the second 26 subcarrier resource block from left to right, and so on; the second row number is 3.01, 3.01, etc., which is the PAPR corresponding to the second row 52 subcarrier resource block from left to right. The value of the first 3.01 refers to the corresponding PAPR value of the first 52 subcarrier resource block from left to right, and the second 3.01 refers to the corresponding PAPR value of the second 52 subcarrier resource block from left to right; the third line The number is 3.91, 3.96, etc., which is the PAPR value corresponding to the third row 106 subcarrier resource block from left to right, that is, the first 3.91 refers to the corresponding PAPR value of the first 106 subcarrier resource block from left to right. 3.96 refers to the PAPR value corresponding to the second 106 subcarrier resource block from left to right; the fourth row number is 4.53, 4.56, etc., which is the PAPR value corresponding to the 242 subcarrier resource block from left to right, and 4.53 refers to The first 242 subcarrier resource block from left to right corresponds to the PAPR value; the fifth row number is 4.90, 4.82, etc., from left to right. In turn, it is the PAPR value corresponding to the 242 subcarrier resource block, 4.90 refers to the PAPR value corresponding to the first 484 subcarrier resource block from left to right, and the sixth line number 4.97 is the PAPR value corresponding to the 996 subcarrier subcarrier resource block.
4.第四种HE-LTF序列4. The fourth HE-LTF sequence
he_ltf_80mhz＝[{0,0,0,0,0,0,0,0,0,0,0,0},...He_ltf_80mhz=[{0,0,0,0,0,0,0,0,0,0,0,0},...
{-1,+Gb,+Ga,-1,-1,-Gb,+Ga,-1,-Ga,-1,+Gb,+Ga,-1,+1,+Gb,-Ga,+1},...{-1, +Gb, +Ga, -1, -1, -Gb, +Ga, -1, -Ga, -1, +Gb, +Ga, -1, +1, +Gb, -Ga, + 1},...
{-1,-Gb,-Ga,-1,-1,+Gb,-Ga,+1,-Gb,-1,+Gb,+Ga,-1,+1,+Gb,-Ga,-1},...{-1, -Gb, -Ga, -1, -1, +Gb, -Ga, +1, -Gb, -1, +Gb, +Ga, -1, +1, +Gb, -Ga, - 1},...
{+Ga(1:13),+1},...{+Ga(1:13), +1},...
{0,0,0,0,0},...{0,0,0,0,0},...
{-1,+Ga(14:26)},...{-1, +Ga(14:26)},...
{+1,+Gb,+Ga,+1,+1,-Gb,+Ga,-1,-Ga,-1,+Gb,+Ga,-1,+1,+Gb,-Ga,+1},...{+1,+Gb,+Ga,+1,+1,-Gb,+Ga,-1,-Ga,-1,+Gb,+Ga,-1,+1,+Gb,-Ga,+ 1},...
{-1,+Gb,+Ga,-1,+1,-Gb,+Ga,+1,+Gb,+1,-Gb,-Ga,+1,-1,-Gb,+Ga,-1},...{-1, +Gb, +Ga, -1, +1, -Gb, +Ga, +1, +Gb, +1, -Gb, -Ga, +1, -1, -Gb, +Ga, - 1},...
{0,0,0,0,0,0,0,0,0,0,0},...]；{0,0,0,0,0,0,0,0,0,0,0},...];
也可以表示为 Can also be expressed as
HE LTF-500,500＝{-1,+Gb,+Ga,-1,-1,-Gb,+Ga,-1,-Ga,-1,+Gb,+Ga,-1,+1,+Gb,-Ga,+1，HE LTF -500,500 ={-1,+Gb,+Ga,-1,-1,-Gb,+Ga,-1,-Ga,-1,+Gb,+Ga,-1,+1,+Gb , -Ga, +1,
-1,-Gb,-Ga,-1,-1,+Gb,-Ga,+1,-Gb,-1,+Gb,+Ga,-1,+1,+Gb,-Ga,-1，-1, -Gb, -Ga, -1, -1, +Gb, -Ga, +1, -Gb, -1, +Gb, +Ga, -1, +1, +Gb, -Ga, -1 ,
+Ga(1:13),+1，+Ga(1:13), +1,
0,0,0,0,0，0,0,0,0,0,
-1,+Ga(14:26)，-1, +Ga(14:26),
+1,+Gb,+Ga,+1,+1,-Gb,+Ga,-1,-Ga,-1,+Gb,+Ga,-1,+1,+Gb,-Ga,+1，+1,+Gb,+Ga,+1,+1,-Gb,+Ga,-1,-Ga,-1,+Gb,+Ga,-1,+1,+Gb,-Ga,+1 ,
-1,+Gb,+Ga,-1,+1,-Gb,+Ga,+1,+Gb,+1,-Gb,-Ga,+1,-1,-Gb,+Ga,-1}-1,+Gb,+Ga,-1,+1,-Gb,+Ga,+1,+Gb,+1,-Gb,-Ga,+1,-1,-Gb,+Ga,-1 }
该HE-LTF序列中包括Ga与Gb序列，位于空余leftover子载波位置上的+1或者-1，连续的+Gb和+Ga，或者，连续的-Gb和+Ga，或者，连续的+Gb和+Ga，或者，连续的-Gb和-Ga，或者，Ga(1:13)和Ga(14:26)。The HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, consecutive +Gb and +Ga, or consecutive -Gb and +Ga, or continuous +Gb And +Ga, or, continuous -Gb and -Ga, or Ga (1:13) and Ga (14:26).
图8d给出80MHz带宽下HE-LTF序列的PAPR值，第一行数字是3.01、2.97、3.01、2.97等等，其从左向右依次是第一行26子载波资源块对应的PAPR值，即3.01是指从左向右第一个26子载波资源块对应PAPR值，接下来的2.97是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数字是3.01、3.01等等，其从左向右依次是第二行52子载波资源块对应的PAPR值，即第一个3.01是指从左向右第一个52子载波资源块对应PAPR值，第二个3.01是指从左向右第二个52子载波资源块对应PAPR值；第三行数字是3.66、3.77等，其从左向右依次是第三行106子载波资源块对应的PAPR值，即第一个3.66是指从左向右第一个106子载波资源块对应PAPR值，3.77是指从左向右第二个106子载波资源块对应PAPR值；第四行数字是4.53、4.54等等，其从左向右依次是242子载波资源块对应的PAPR值，4.53是指从左向右第一个242子载波资源块对应PAPR值；第五行数字是4.88、4.86等等，其从左向右依次是242子载波资源块对应的PAPR值，4.88是指从左向右第一个484子载波资源块对应PAPR值；第六行数字4.97是996子载波子载波资源块对应的PAPR值。Figure 8d shows the PAPR value of the HE-LTF sequence in the 80MHz bandwidth. The first row of numbers is 3.01, 2.97, 3.01, 2.97, etc., which is the PAPR value corresponding to the first row 26 subcarrier resource blocks from left to right. That is, 3.01 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 2.97 refers to the corresponding PAPR value of the second 26 subcarrier resource blocks from left to right, and so on; the second line is 3.01, 3.01, etc., from left to right, the PAPR value corresponding to the second row 52 subcarrier resource block, that is, the first 3.01 refers to the PAPR value corresponding to the first 52 subcarrier resource block from left to right, The two 3.01s refer to the PAPR value corresponding to the second 52 subcarrier resource block from left to right; the third row number is 3.66, 3.77, etc., which is the PAPR value corresponding to the third row 106 subcarrier resource block from left to right. , that is, the first 3.66 refers to the PAPR value corresponding to the first 106 subcarrier resource blocks from left to right, and 3.77 refers to the corresponding PAPR value of the second 106 subcarrier resource blocks from left to right; the fourth row number is 4.53. 4.54 and so on, from left to right, the PAPR value corresponding to the 242 subcarrier resource block, and 4.53 refers to the first 242 subtitle from left to right. The wave resource block corresponds to the PAPR value; the fifth row number is 4.88, 4.86, etc., which is the PAPR value corresponding to the 242 subcarrier resource block from left to right, and 4.88 refers to the first 484 subcarrier resource block corresponding from left to right. The PAPR value; the sixth line number 4.97 is the PAPR value corresponding to the 996 subcarrier subcarrier resource block.
5.第五种HE-LTF序列 5. The fifth HE-LTF sequence
he_ltf_80mhz＝[{0,0,0,0,0,0,0,0,0,0,0,0},...He_ltf_80mhz=[{0,0,0,0,0,0,0,0,0,0,0,0},...
{-1,+Ga,+Gb,+1,-1,-Ga,+Gb,+1,-Ga,-1,-Ga,-Gb,+1,-1,-Ga,+Gb,+1},...{-1, +Ga, +Gb, +1, -1, -Ga, +Gb, +1, -Ga, -1, -Ga, -Gb, +1, -1, -Ga, +Gb, + 1},...
{-1,-Ga,-Gb,-1,-1,+Ga,-Gb,+1,-Gb,-1,-Ga,-Gb,+1,-1,-Ga,+Gb,-1},...{-1, -Ga, -Gb, -1, -1, +Ga, -Gb, +1, -Gb, -1, -Ga, -Gb, +1, -1, -Ga, +Gb, - 1},...
{+Ga(1:13),+1},...{+Ga(1:13), +1},...
{0,0,0,0,0},...{0,0,0,0,0},...
{-1,+Ga(14:26)},...{-1, +Ga(14:26)},...
{-1,+Ga,+Gb,+1,-1,-Ga,+Gb,+1,-Ga,-1,-Ga,-Gb,+1,-1,-Ga,+Gb,+1},...{-1, +Ga, +Gb, +1, -1, -Ga, +Gb, +1, -Ga, -1, -Ga, -Gb, +1, -1, -Ga, +Gb, + 1},...
{-1,+Ga,+Gb,-1,+1,-Ga,+Gb,-1,+Gb,+1,+Ga,+Gb,-1,-1,+Ga,-Gb,+1},...{-1, +Ga, +Gb, -1, +1, -Ga, +Gb, -1, +Gb, +1, +Ga, +Gb, -1, -1, +Ga, -Gb, + 1},...
{0,0,0,0,0,0,0,0,0,0,0},...]；{0,0,0,0,0,0,0,0,0,0,0},...];
也可以表示为Can also be expressed as
HE LTF-500,500＝{-1,+Ga,+Gb,+1,-1,-Ga,+Gb,+1,-Ga,-1,-Ga,-Gb,+1,-1,-Ga,+Gb,+1，HE LTF -500,500 ={-1,+Ga,+Gb,+1,-1,-Ga,+Gb,+1,-Ga,-1,-Ga,-Gb,+1,-1,-Ga , +Gb, +1,
-1,-Ga,-Gb,-1,-1,+Ga,-Gb,+1,-Gb,-1,-Ga,-Gb,+1,-1,-Ga,+Gb,-1，-1, -Ga, -Gb, -1, -1, +Ga, -Gb, +1, -Gb, -1, -Ga, -Gb, +1, -1, -Ga, +Gb, -1 ,
+Ga(1:13),+1，+Ga(1:13), +1,
0,0,0,0,0，0,0,0,0,0,
-1,+Ga(14:26)，-1, +Ga(14:26),
-1,+Ga,+Gb,+1,-1,-Ga,+Gb,+1,-Ga,-1,-Ga,-Gb,+1,-1,-Ga,+Gb,+1，-1, +Ga, +Gb, +1, -1, -Ga, +Gb, +1, -Ga, -1, -Ga, -Gb, +1, -1, -Ga, +Gb, +1 ,
-1,+Ga,+Gb,-1,+1,-Ga,+Gb,-1,+Gb,+1,+Ga,+Gb,-1,-1,+Ga,-Gb,+1}-1, +Ga, +Gb, -1, +1, -Ga, +Gb, -1, +Gb, +1, +Ga, +Gb, -1, -1, +Ga, -Gb, +1 }
该HE-LTF序列中包括Ga与Gb序列，位于空余leftover子载波位置上的+1或者-1，连续的+Ga和+Gb，或者，连续的-Ga和+Gb，或者，连续的-Ga和-Gb，或者，连续的+Ga和-Gb，或者，Ga(1:13)和Ga(14:26)。The HE-LTF sequence includes Ga and Gb sequences, +1 or -1 at the left leftover subcarrier position, +Ga and +Gb consecutive, or continuous -Ga and +Gb, or continuous -Ga And -Gb, or, continuous +Ga and -Gb, or Ga (1:13) and Ga (14:26).
图8e给出80MHz带宽下HE-LTF序列的PAPR值，第一行数字是2.97、3.01、2.97、3.01等等，其从左向右依次是第一行26子载波资源块对应的PAPR 值，即2.97是指从左向右第一个26子载波资源块对应PAPR值，接下来的3.01是指从左向右第二个26子载波资源块对应PAPR值，依次类推；第二行数字是3.01、3.01等等，其从左向右依次是第二行52子载波资源块对应的PAPR值，即第一个3.01是指从左向右第一个52子载波资源块对应PAPR值，第二个3.01是指从左向右第二个52子载波资源块对应PAPR值；第三行数字是3.83、3.81等，其从左向右依次是第三行106子载波资源块对应的PAPR值，即第一个3.83是指从左向右第一个106子载波资源块对应PAPR值，3.81是指从左向右第二个106子载波资源块对应PAPR值；第四行数字是4.41、4.59等等，其从左向右依次是242子载波资源块对应的PAPR值，4.41是指从左向右第一个242子载波资源块对应PAPR值；第五行数字是4.89、4.90等等，其从左向右依次是242子载波资源块对应的PAPR值，4.89是指从左向右第一个484子载波资源块对应PAPR值；第六行数字4.99是996子载波子载波资源块对应的PAPR值。Figure 8e shows the PAPR value of the HE-LTF sequence in the 80MHz bandwidth. The first row of numbers is 2.97, 3.01, 2.97, 3.01, etc., which is the PAPR corresponding to the first row 26 subcarrier resource blocks from left to right. The value, that is, 2.97 refers to the PAPR value corresponding to the first 26 subcarrier resource blocks from left to right, and the next 3.01 refers to the PAPR value corresponding to the second 26 subcarrier resource blocks from left to right, and so on; The number is 3.01, 3.01, etc., which is the PAPR value corresponding to the second row 52 subcarrier resource block from left to right, that is, the first 3.01 refers to the corresponding PAPR value of the first 52 subcarrier resource block from left to right. The second 3.01 refers to the second 52 subcarrier resource block corresponding to the PAPR value from left to right; the third row number is 3.83, 3.81, etc., which is from the left to the right is the third row 106 subcarrier resource block corresponding to The PAPR value, that is, the first 3.83 refers to the PAPR value corresponding to the first 106 subcarrier resource blocks from left to right, and the 3.81 refers to the corresponding PAPR value of the second 106 subcarrier resource blocks from left to right; the fourth line is 4.41, 4.59, etc., from left to right, the PAPR value corresponding to the 242 subcarrier resource block, and 4.41 refers to the PAPR value corresponding to the first 242 subcarrier resource block from left to right; the fifth line number is 4.89, 4.90, etc. Etc., from left to right, is the PAPR value corresponding to the 242 subcarrier resource block, and 4.89 refers to the first 484 from left to right. The carrier resource block corresponds to the PAPR value; the sixth line number 4.99 is the PAPR value corresponding to the 996 subcarrier subcarrier resource block.
实施例七Example 7
提供一种方法，STA根据资源分配信息中的RU大小和RU位置，发送HE-LTF序列。所述HE-LTF序列可以是20MHz、40MHz、80MHz带宽对应的HE-LTF序列，即前述各实施例1、2、3，5,6中给出的HE-LTF序列；所述RU大小是指STA发送数据的最小资源块大小，使用RUsize表示；RU位置是指STA发送数据的子载波位置，使用RUidx表示。A method is provided in which an STA transmits an HE-LTF sequence according to a RU size and a RU location in resource allocation information. The HE-LTF sequence may be a HE-LTF sequence corresponding to a bandwidth of 20 MHz, 40 MHz, and 80 MHz, that is, an HE-LTF sequence given in each of the foregoing embodiments 1, 2, 3, 5, and 6; The minimum resource block size at which the STA transmits data is represented by RU size ; the RU location refers to the subcarrier position at which the STA transmits data, which is represented by RU idx .
STA按照下面的流程处理发送HE-LTF序列：The STA processes the sending HE-LTF sequence according to the following procedure:
S701：STA根据带宽信息选择HE-LTF序列，即带宽是20MHz时，STA选择HE-LTF-122,122序列，带宽是40MHz时，STA选择HE-LTF-244,244序列，带宽是80MHz时，STA选择HE-LTF-498,498序列；S701: The STA selects the HE-LTF sequence according to the bandwidth information, that is, when the bandwidth is 20 MHz, the STA selects the HE-LTF- 122 , 122 sequence, and when the bandwidth is 40 MHz, the STA selects the HE-LTF- 244 , 244 sequence, and when the bandwidth is 80 MHz, the STA selects the HE- LTF- 498,498 sequence;
S702：根据RU大小和RU位置，从所选择的HE-LTF序列中选中一部分信息发送，所述部分信息可以是整个HE-LTF序列，也可以是HE-LTF序列中的一部分信息。我们以20MHz带宽,RUsize为26、52、106、242为例，具体操作如下：S702: Select, according to the RU size and the RU location, a part of information transmission from the selected HE-LTF sequence, where the partial information may be an entire HE-LTF sequence, or may be part of information in the HE-LTF sequence. Let us take the 20MHz bandwidth and the RU size as 26, 52, 106, 242 as an example. The specific operations are as follows:
20MHz带宽对应的HE-LTF序列为：The HE-LTF sequence corresponding to the 20MHz bandwidth is:
HE-LTF-122,122＝[+1,+Gb,-Ga,-1,+Gb,+Ga,+Ga(1:13),-1,-1,0,0,0, HE-LTF -122,122 =[+1,+Gb,-Ga,-1,+Gb,+Ga,+Ga(1:13),-1,-1,0,0,0,
+1,+1,+Ga(14:26),+Gb,-Ga,+1,-Gb,-Ga,-1]；+1, +1, +Ga(14:26), +Gb, -Ga, +1, -Gb, -Ga, -1];
1、当RUsize＝26时，RUidx的值可以是1、2、…、9。对应的HE-LTF有9种1. When RU size = 26, the value of RU idx can be 1, 2, ..., 9. There are 9 kinds of corresponding HE-LTF
–RUsize＝26，RUidx＝1时对应的HE-LTF序列–RUsize=26, the corresponding HE-LTF sequence when RUidx=1
HE-LTF-122,122＝[0,+Gb,026,0,026,026,013,0,0,0,0,0,0,0,013,026,026,0,026,026,0]；HE-LTF -122,122 =[0,+Gb,0 26 ,0,0 26 ,0 26 ,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 , 0 26 , 0 26 , 0];
其中026表示连续的26个0；013表示连续的13个0Where 0 26 represents a continuous 26 0; 0 13 represents a continuous 13 0
–RUsize＝26，RUidx＝2时对应的HE-LTF序列–RU size =26, the corresponding HE-LTF sequence when RU idx =2
HE-LTF-122,122＝[0,026,-Ga,0,026,026,013,0,0,0,0,0,0,0,013,026,026,0,026,026,0]；HE-LTF -122,122 =[0,0 26 ,-Ga,0,0 26 ,0 26 ,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 , 0 26 , 0 26 , 0];
其中026表示连续的26个0；013表示连续的13个0Where 0 26 represents a continuous 26 0; 0 13 represents a continuous 13 0
–RUsize＝26，RUidx＝3时对应的HE-LTF序列–RU size =26, the corresponding HE-LTF sequence when RU idx =3
HE-LTF-122,122＝[0,026,026,0,+Gb,026,013,0,0,0,0,0,0,0,013,026,026,0,026,026,0]；HE-LTF -122,122 =[0,0 26 ,0 26 ,0,+Gb,0 26 ,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 , 0 26 , 0 26 , 0];
其中026表示连续的26个0；013表示连续的13个0Where 0 26 represents a continuous 26 0; 0 13 represents a continuous 13 0
–当RUsize＝26，RUidx＝4时对应的HE-LTF序列为：– When RUsize=26 and RUidx=4, the corresponding HE-LTF sequence is:
HE-LTF-122,122＝[0,026,026,0,026,+Ga,013,0,0,0,0,0,0,0,013,026,026,0,026,026,0]；HE-LTF -122,122 =[0,0 26 ,0 26 ,0,0 26 ,+Ga,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 , 0 26 , 0 26 , 0];
其中026表示连续的26个0；013表示连续的13个0Where 0 26 represents a continuous 26 0; 0 13 represents a continuous 13 0
–当RUsize＝26，RUidx＝5时对应的HE-LTF序列为：– When RUsize=26 and RUidx=5, the corresponding HE-LTF sequence is:
HE-LTF-122,122＝[0,026,026,0,026,026,+Ga(1:13),0,0,0,0,0,0,0,…HE-LTF -122,122 =[0,0 26 ,0 26 ,0,0 26 ,0 26 ,+Ga(1:13),0,0,0,0,0,0,0,...
+Ga(14:26),026,026,0,026,026,0]；+Ga(14:26),0 26 ,0 26 ,0,0 26 ,0 26 ,0];
其中026表示连续的26个0Where 0 26 represents a continuous 26 0
–当RUsize＝26，RUidx＝6时对应的HE-LTF序列为：– When RUsize=26 and RUidx=6, the corresponding HE-LTF sequence is:
HE-LTF-122,122＝[0,026,026,0,026,026,013,0,0,0,0,0,0,0,013,+Gb,026,0,026,026,0]；HE-LTF -122,122 =[0,0 26 ,0 26 ,0,0 26 ,0 26 ,0 13 ,0,0,0,0,0,0,0,0 13 ,+Gb,0 26 ,0 , 0 26 , 0 26 , 0];
其中026表示连续的26个0；013表示连续的13个0 Where 0 26 represents a continuous 26 0; 0 13 represents a continuous 13 0
–当RUsize＝26，RUidx＝7时对应的HE-LTF序列为：– When RUsize=26 and RUidx=7, the corresponding HE-LTF sequence is:
HE-LTF-122,122＝[0,026,026,0,026,+Ga,013,0,0,0,0,0,0,0,013,026,-Ga,0,026,026,0]；HE-LTF -122,122 =[0,0 26 ,0 26 ,0,0 26 ,+Ga,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,-Ga,0 , 0 26 , 0 26 , 0];
其中026表示连续的26个0；013表示连续的13个0Where 0 26 represents a continuous 26 0; 0 13 represents a continuous 13 0
–当RUsize＝26，RUidx＝8时对应的HE-LTF序列为：– When RUsize=26 and RUidx=8, the corresponding HE-LTF sequence is:
HE-LTF-122,122＝[0,026,026,0,026,+Ga,013,0,0,0,0,0,0,0,013,026,026,0,-Gb,026,0]；HE-LTF -122,122 =[0,0 26 ,0 26 ,0,0 26 ,+Ga,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 ,-Gb,0 26 ,0];
其中026表示连续的26个0；013表示连续的13个0Where 0 26 represents a continuous 26 0; 0 13 represents a continuous 13 0
–当RUsize＝26，RUidx＝9时对应的HE-LTF序列为：– When RUsize=26 and RUidx=9, the corresponding HE-LTF sequence is:
HE-LTF-122,122＝[0,026,026,0,026,+Ga,013,0,0,0,0,0,0,0,013,026,026,0,026,-Ga,0]；HE-LTF -122,122 =[0,0 26 ,0 26 ,0,0 26 ,+Ga,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 ,0 26 ,-Ga,0];
其中026表示连续的26个0；013表示连续的13个0Where 0 26 represents a continuous 26 0; 0 13 represents a continuous 13 0
2、当RUsize＝52时，RUidx的值可以是1、2、3、4。对应的HE-LTF有4种2. When RU size = 52, the value of RU idx can be 1, 2, 3, 4. There are 4 kinds of corresponding HE-LTF
–当RUsize＝52，RUidx＝1时对应的HE-LTF序列– the corresponding HE-LTF sequence when RUsize=52, RUidx=1
HE-LTF-122,122＝[0,+Gb,-Ga,0,026,026,013,0,0,0,0,0,0,0,013,026,026,0,026,026,0]；HE-LTF -122,122 =[0,+Gb,-Ga,0,0 26 ,0 26 ,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 , 0 26 , 0 26 , 0];
–当RUsize＝52，RUidx＝2时对应的HE-LTF序列– When RUsize=52, RUidx=2, the corresponding HE-LTF sequence
HE-LTF-122,122＝[0,026,026,0,+Gb,+Ga,013,0,0,0,0,0,0,0,013,026,026,0,026,026,0]；HE-LTF -122,122 =[0,0 26 ,0 26 ,0,+Gb,+Ga,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 , 0 26 , 0 26 , 0];
–当RUsize＝52，RUidx＝3时对应的HE-LTF序列– the corresponding HE-LTF sequence when RUsize=52, RUidx=3
HE-LTF-122,122＝[0,026,026,0,026,026,013,0,0,0,0,0,0,0,013,+Gb,-Ga,0,026,026,0]；HE-LTF -122,122 =[0,0 26 ,0 26 ,0,0 26 ,0 26 ,0 13 ,0,0,0,0,0,0,0,0 13 ,+Gb,-Ga,0 , 0 26 , 0 26 , 0];
–当RUsize＝52，RUidx＝4时对应的HE-LTF序列– the corresponding HE-LTF sequence when RUsize=52 and RUidx=4
HE-LTF-122,122＝[0,026,026,0,026,026,013,0,0,0,0,0,0,0,013,026,026,0,-Gb,-Ga,0]；HE-LTF -122,122 =[0,0 26 ,0 26 ,0,0 26 ,0 26 ,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 ,-Gb,-Ga,0];
3、当RUsize＝106时，RUidx的值可以是1、2。对应的HE-LTF有2种 3. When RU size = 106, the value of RU idx can be 1, 2. There are 2 kinds of corresponding HE-LTF
–当RUsize＝106，RUidx＝1时对应的HE-LTF序列为：– When RUsize=106, RUidx=1, the corresponding HE-LTF sequence is:
HE-LTF-122,122＝[0,+Gb,-Ga,0,+Gb,+Ga,013,0,0,0,0,0,0,0,013,026,026,0,026,026,0]；HE-LTF -122,122 =[0,+Gb,-Ga,0,+Gb,+Ga,0 13 ,0,0,0,0,0,0,0,0 13 ,0 26 ,0 26 ,0 , 0 26 , 0 26 , 0];
–当RUsize＝106，RUidx＝1时对应的HE-LTF序列为：– When RUsize=106, RUidx=1, the corresponding HE-LTF sequence is:
HE-LTF-122,122＝[0,026,026,0,026,026,013,0,0,0,0,0,0,0,013,+Gb,-Ga,0,-Gb,-Ga,0]；HE-LTF -122,122 =[0,0 26 ,0 26 ,0,0 26 ,0 26 ,0 13 ,0,0,0,0,0,0,0,0 13 ,+Gb,-Ga,0 ,-Gb,-Ga,0];
4、当RUsize＝242时，RUidx的值1。对应的HE-LTF有1种4. When RU size = 242, the value of RU idx is 1. There is one corresponding HE-LTF
–当RUsize＝242，RUidx＝1时对应的HE-LTF序列为：– When RUsize=242, RUidx=1, the corresponding HE-LTF sequence is:
HE-LTF-122,122＝[+1,+Gb,-Ga,-1,+Gb,+Ga,+Ga(1:13),-1,-1,0,0,0,HE-LTF -122,122 =[+1,+Gb,-Ga,-1,+Gb,+Ga,+Ga(1:13),-1,-1,0,0,0,
+1,+1,+Ga(14:26),+Gb,-Ga,+1,-Gb,-Ga,-1]。+1, +1, +Ga(14:26), +Gb, -Ga, +1, -Gb, -Ga, -1].
实施例八Example eight
802.11ax标准中，20MHz带宽2x符号上的HE-LTF序列的有效子载波位置为：-122:2:122。这种序列的生成方式有很多种，一般的，可以根据4x符号上的HE-LTF序列变换得到。下面罗列几种：In the 802.11ax standard, the effective subcarrier position of the HE-LTF sequence on the 20x bandwidth 2x symbol is: -122:2:122. There are many ways to generate such a sequence. In general, it can be obtained by transforming the HE-LTF sequence on the 4x symbol. Listed below are several:
HELTF2x(-122:2:122)＝HELTF4x(-122:2:122)HELTF 2x (-122:2:122)=HELTF 4x (-122:2:122)
或者：or:
HELTF2x(-122:2:-2)＝HELTF4x(-122:2:-2)HELTF 2x (-122:2:-2)=HELTF 4x (-122:2:-2)
HELTF2x(2:2:122)＝-HELTF4x(2:2:122)HELTF 2x (2:2:122)=-HELTF 4x (2:2:122)
或者：or:
HELTF2x(-122:2:-2)＝HELTF4x(-122:-62)HELTF 2x (-122:2:-2)=HELTF 4x (-122:-62)
HELTF2x(2:2:122)＝HELTF4x(62:122)HELTF 2x (2:2:122)=HELTF 4x (62:122)
或者：or:
HELTF2x(-122:2:-2)＝HELTF4x(-122:-62)HELTF 2x (-122:2:-2)=HELTF 4x (-122:-62)
HELTF2x(2:2:122)＝-HELTF4x(62:122)HELTF 2x (2:2:122)=-HELTF 4x (62:122)
实施例九 Example nine
802.11ax标准中，40MHz带宽2x符号上的HE-LTF序列的有效子载波位置为：-244:2:244。这种序列的生成方式有很多种，，一般的，可以根据4x符号上的HE-LTF序列变换得到下面罗列几种：In the 802.11ax standard, the effective subcarrier position of the HE-LTF sequence on the 40x bandwidth 2x symbol is: -244:2:244. There are many ways to generate such a sequence. In general, several types of sequences can be obtained according to the HE-LTF sequence transformation on the 4x symbol:
HELTF2x(-244:2:244)＝HELTF4x(-244:2:244)HELTF 2x (-244:2:244)=HELTF 4x (-244:2:244)
或者：or:
HELTF2x(-244:2:-4)＝HELTF4x(-244:2:-4)HELTF 2x (-244:2:-4)=HELTF 4x (-244:2:-4)
HELTF2x(4:2:244)＝-HELTF4x(4:2:244)HELTF 2x (4:2:244)=-HELTF 4x (4:2:244)
或者：or:
HELTF2x(-244:2:-4)＝HELTF4x((-244:2:-4)+0)HELTF 2x (-244:2:-4)=HELTF 4x ((-244:2:-4)+0)
HELTF2x(4:2:244)＝HELTF4x((-244:2:-4)+1)HELTF 2x (4:2:244)=HELTF 4x ((-244:2:-4)+1)
或者：or:
HELTF2x(-244:2:-4)＝HELTF4x((-244:2:-4)+0)HELTF 2x (-244:2:-4)=HELTF 4x ((-244:2:-4)+0)
HELTF2x(4:2:244)＝-HELTF4x((-244:2:-4)+1)HELTF 2x (4:2:244)=-HELTF 4x ((-244:2:-4)+1)
实施例十Example ten
802.11ax标准中，80MHz带宽2x符号上的HE-LTF序列的有效子载波位置为：-500:2:500。这种序列的生成方式有很多种，一般的，可以根据4x符号上的HE-LTF序列变换得到下面罗列几种：In the 802.11ax standard, the effective subcarrier position of the HE-LTF sequence on the 80x bandwidth 2x symbol is: -500:2:500. There are many ways to generate such a sequence. In general, several types of sequences can be obtained according to the HE-LTF sequence transformation on the 4x symbol:
HELTF2x(-500:2:500)＝HELTF4x(-500:2:500)HELTF 2x (-500:2:500)=HELTF 4x (-500:2:500)
或者：or:
HELTF2x(-500:2:-4)＝HELTF4x(-500:2:-4)HELTF 2x (-500:2:-4)=HELTF 4x (-500:2:-4)
HELTF2x(4:2:500)＝-HELTF4x(4:2:500)HELTF 2x (4:2:500)=-HELTF 4x (4:2:500)
或者：or:
HELTF2x(-500:2:-4)＝HELTF4x((-500:2:-4)+1)HELTF 2x (-500:2:-4)=HELTF 4x ((-500:2:-4)+1)
HELTF2x(4:2:500)＝HELTF4x(4:2:500)HELTF 2x (4:2:500)=HELTF 4x (4:2:500)
或者：or:
HELTF2x(-500:2:-4)＝HELTF4x((-500:2:-4)+1)HELTF 2x (-500:2:-4)=HELTF 4x ((-500:2:-4)+1)
HELTF2x(4:2:500)＝-HELTF4x(4:2:500)HELTF 2x (4:2:500)=-HELTF 4x (4:2:500)
或者：or:
HELTF2x(-500:2:-4)＝HELTF4x((4:2:500)-1)HELTF 2x (-500:2:-4)=HELTF 4x ((4:2:500)-1)
HELTF2x(4:2:500)＝HELTF4x(4:2:500) HELTF 2x (4:2:500)=HELTF 4x (4:2:500)
或者：or:
HELTF2x(-500:2:-4)＝HELTF4x((4:2:500)-1)HELTF 2x (-500:2:-4)=HELTF 4x ((4:2:500)-1)
HELTF2x(4:2:500)＝-HELTF4x(4:2:500)HELTF 2x (4:2:500)=-HELTF 4x (4:2:500)
相应的，另一实施方式提供了一种资源指示的处理装置(未示出)，应用于采用OFDMA技术的无线局域网，包含处理单元，用于执行前述实施中的方法。具体的帧的结构与内容，可以参考前述各实施方式，此处不再赘述。处理单元可以是通用处理器、数字信号处理器、专用集成电路、现场可编程门阵列或者其他可编程逻辑器件、分立门或者晶体管逻辑器件、分立硬件组件，可以实现或者执行本发明实施例中的公开的各方法、步骤及逻辑框图。通用处理器可以是微处理器或者任何常规的处理器等。结合本发明实施例所公开的方法的步骤可以直接体现为硬件处理器执行完成，或者用处理器中的硬件及软件模块组合执行完成。容易理解的，上述资源指示的处理装置，可以位于接入点或者站点。Correspondingly, another embodiment provides a resource indication processing device (not shown) applied to a wireless local area network employing OFDMA technology, including a processing unit for performing the method in the foregoing implementation. For the structure and content of the specific frame, reference may be made to the foregoing embodiments, and details are not described herein again. The processing unit may be a general purpose processor, a digital signal processor, an application specific integrated circuit, a field programmable gate array or other programmable logic device, a discrete gate or transistor logic device, a discrete hardware component, or may implement or perform the embodiments of the present invention. Various methods, steps, and logic blocks are disclosed. A general purpose processor can be a microprocessor or any conventional processor or the like. The steps of the method disclosed in the embodiments of the present invention may be directly implemented as a hardware processor, or may be performed by a combination of hardware and software modules in the processor. It is easy to understand that the processing device indicated by the above resource may be located at an access point or a site.
图9是本发明另一实施例的接入点的框图。图9的接入点包括接口101、处理单元102和存储器103。处理单元102控制接入点100的操作。存储器103可以包括只读存储器和随机存取存储器，并向处理单元102提供指令和数据。存储器103的一部分还可以包括非易失行随机存取存储器(NVRAM)。接入点100的各个组件通过总线系统109耦合在一起，其中总线系统109除包括数据总线之外，还包括电源总线、控制总线和状态信号总线。但是为了清楚说明起见，在图中将各种总线都标为总线系统109。9 is a block diagram of an access point in accordance with another embodiment of the present invention. The access point of Figure 9 includes an interface 101, a processing unit 102, and a memory 103. Processing unit 102 controls the operation of access point 100. Memory 103 can include read only memory and random access memory and provides instructions and data to processing unit 102. A portion of the memory 103 may also include non-volatile line random access memory (NVRAM). The various components of access point 100 are coupled together by a bus system 109, which in addition to the data bus includes a power bus, a control bus, and a status signal bus. However, for clarity of description, various buses are labeled as the bus system 109 in the figure.
上述本发明实施例揭示的发送前述各种帧的方法可以应用于处理单元102中，或者由处理单元102实现。在实现过程中，上述方法的各步骤可以通过处理单元102中的硬件的集成逻辑电路或者软件形式的指令完成。处理单元102可以是通用处理器、数字信号处理器、专用集成电路、现场可编程门阵列或者其他可编程逻辑器件、分立门或者晶体管逻辑器件、分立硬件组件，可以实现或者执行本发明实施例中的公开的各方法、步骤及逻辑框图。通用处理器可以是微处理器或者任何常规的处理器等。结合本发明实施例所公开的方法的步骤可以直接体现为硬件处理器执行完成，或者用处理器中的硬件及软件模块组合执行完成。软件模块可以位于随机存储器，闪存、只读 存储器，可编程只读存储器或者电可擦写可编程存储器、寄存器等本领域成熟的存储介质中。该存储介质位于存储器103，处理单元102读取存储器103中的信息，结合其硬件完成上述方法的步骤。The method for transmitting the foregoing various frames disclosed in the foregoing embodiments of the present invention may be applied to the processing unit 102 or implemented by the processing unit 102. In the implementation process, each step of the above method may be completed by an integrated logic circuit of hardware in the processing unit 102 or an instruction in the form of software. The processing unit 102 can be a general purpose processor, a digital signal processor, an application specific integrated circuit, a field programmable gate array or other programmable logic device, a discrete gate or transistor logic device, a discrete hardware component, which can be implemented or executed in an embodiment of the invention. Various methods, steps, and logic blocks of the disclosure. A general purpose processor can be a microprocessor or any conventional processor or the like. The steps of the method disclosed in the embodiments of the present invention may be directly implemented as a hardware processor, or may be performed by a combination of hardware and software modules in the processor. Software modules can be located in random access memory, flash memory, read only Memory, programmable read only memory or electrically erasable programmable memory, registers, etc. are well-established in the field of storage media. The storage medium is located in the memory 103, and the processing unit 102 reads the information in the memory 103 and completes the steps of the above method in combination with its hardware.
图10是本发明另一实施例的站点的框图。图10的接入点包括接口111、处理单元112和存储器113。处理单元112控制站点110的操作。存储器113可以包括只读存储器和随机存取存储器，并向处理单元112提供指令和数据。存储器113的一部分还可以包括非易失行随机存取存储器(NVRAM)。站点110的各个组件通过总线系统119耦合在一起，其中总线系统119除包括数据总线之外，还包括电源总线、控制总线和状态信号总线。但是为了清楚说明起见，在图中将各种总线都标为总线系统119。Figure 10 is a block diagram of a station in accordance with another embodiment of the present invention. The access point of FIG. 10 includes an interface 111, a processing unit 112, and a memory 113. Processing unit 112 controls the operation of site 110. Memory 113 can include read only memory and random access memory and provides instructions and data to processing unit 112. A portion of the memory 113 may also include non-volatile line random access memory (NVRAM). The various components of the site 110 are coupled together by a bus system 119, which in addition to the data bus includes a power bus, a control bus, and a status signal bus. However, for clarity of description, various buses are labeled as bus system 119 in the figure.
上述本发明实施例揭示的接收前述各种帧的方法可以应用于处理单元112中，或者由处理单元112实现。在实现过程中，上述方法的各步骤可以通过处理单元112中的硬件的集成逻辑电路或者软件形式的指令完成。处理单元112可以是通用处理器、数字信号处理器、专用集成电路、现场可编程门阵列或者其他可编程逻辑器件、分立门或者晶体管逻辑器件、分立硬件组件，可以实现或者执行本发明实施例中的公开的各方法、步骤及逻辑框图。通用处理器可以是微处理器或者任何常规的处理器等。结合本发明实施例所公开的方法的步骤可以直接体现为硬件处理器执行完成，或者用处理器中的硬件及软件模块组合执行完成。软件模块可以位于随机存储器，闪存、只读存储器，可编程只读存储器或者电可擦写可编程存储器、寄存器等本领域成熟的存储介质中。该存储介质位于存储器113，处理单元112读取存储器113中的信息，结合其硬件完成上述方法的步骤。The method for receiving the foregoing various frames disclosed in the foregoing embodiments of the present invention may be applied to the processing unit 112 or implemented by the processing unit 112. In the implementation process, each step of the above method may be completed by an integrated logic circuit of hardware in the processing unit 112 or an instruction in a form of software. The processing unit 112 can be a general purpose processor, a digital signal processor, an application specific integrated circuit, a field programmable gate array or other programmable logic device, a discrete gate or transistor logic device, a discrete hardware component, which can be implemented or executed in an embodiment of the invention. Various methods, steps, and logic blocks of the disclosure. A general purpose processor can be a microprocessor or any conventional processor or the like. The steps of the method disclosed in the embodiments of the present invention may be directly implemented as a hardware processor, or may be performed by a combination of hardware and software modules in the processor. The software module can be located in a conventional storage medium such as random access memory, flash memory, read only memory, programmable read only memory or electrically erasable programmable memory, registers, and the like. The storage medium is located in the memory 113, and the processing unit 112 reads the information in the memory 113 and performs the steps of the above method in combination with its hardware.
具体地，存储器113存储使得处理单元112执行如下操作的指令：确定资源状态信息，该资源状态信息指示接入点与站点进行数据传输的信道资源的子资源的忙闲状态；向接入点发送资源状态信息，以便于该接入点根据资源状态信息进行资源分配。Specifically, the memory 113 stores an instruction that causes the processing unit 112 to perform resource status information indicating a busy state of a sub-resource of a channel resource for which the access point performs data transmission with the station; sending to the access point Resource status information, so that the access point performs resource allocation according to resource status information.
应理解，说明书通篇中提到的“一个实施例”或“一实施例”意味着与实施例有关的特定特征、结构或特性包括在本发明的至少一个实施例中。因此，在整个说明书各处出现的“在一个实施例中”或“在一实施例中”未必一定指相同的实施例。此外，这些特定的特征、结构或特性可以任意适合 的方式结合在一个或多个实施例中。在本发明的各种实施例中，上述各过程的序号的大小并不意味着执行顺序的先后，各过程的执行顺序应以其功能和内在逻辑确定，而不应对本发明实施例的实施过程构成任何限定。It is to be understood that the phrase "one embodiment" or "an embodiment" or "an" Thus, "in one embodiment" or "in an embodiment" or "an" In addition, these specific features, structures or characteristics can be adapted to any The manner is combined in one or more embodiments. In various embodiments of the present invention, the size of the sequence numbers of the above processes does not mean the order of execution, and the order of execution of each process should be determined by its function and internal logic, and should not be implemented in the embodiment of the present invention. Form any limit.
另外，本文中术语“系统”和“网络”在本文中常被可互换使用。本文中术语“和/或”，仅仅是一种描述关联对象的关联关系，表示可以存在三种关系，例如，A和/或B，可以表示：单独存在A，同时存在A和B，单独存在B这三种情况。另外，本文中字符“/”，一般表示前后关联对象是一种“或”的关系。Additionally, the terms "system" and "network" are used interchangeably herein. The term "and/or" in this context is merely an association describing the associated object, indicating that there may be three relationships, for example, A and / or B, which may indicate that A exists separately, and both A and B exist, respectively. B these three situations. In addition, the character "/" in this article generally indicates that the contextual object is an "or" relationship.
应理解，在本发明实施例中，“与A相应的B”表示B与A相关联，根据A可以确定B。但还应理解，根据A确定B并不意味着仅仅根据A确定B，还可以根据A和/或其它信息确定B。It should be understood that in the embodiment of the present invention, "B corresponding to A" means that B is associated with A, and B can be determined according to A. However, it should also be understood that determining B from A does not mean that B is only determined based on A, and that B can also be determined based on A and/or other information.
本领域普通技术人员可以意识到，结合本文中所公开的实施例描述的各示例的单元及算法步骤，能够以电子硬件、计算机软件或者二者的结合来实现，为了清楚地说明硬件和软件的可互换性，在上述说明中已经按照功能一般性地描述了各示例的组成及步骤。这些功能究竟以硬件还是软件方式来执行，取决于技术方案的特定应用和设计约束条件。专业技术人员可以对每个特定的应用来使用不同方法来实现所描述的功能，但是这种实现不应认为超出本发明的范围。Those of ordinary skill in the art will appreciate that the elements and algorithm steps of the various examples described in connection with the embodiments disclosed herein can be implemented in electronic hardware, computer software, or a combination of both, for clarity of hardware and software. Interchangeability, the composition and steps of the various examples have been generally described in terms of function in the above description. Whether these functions are performed in hardware or software depends on the specific application and design constraints of the solution. A person skilled in the art can use different methods for implementing the described functions for each particular application, but such implementation should not be considered to be beyond the scope of the present invention.
所属领域的技术人员可以清楚地了解到，为了描述的方便和简洁，上述描述的系统、装置和单元的具体工作过程，可以参考前述方法实施例中的对应过程，在此不再赘述。A person skilled in the art can clearly understand that, for the convenience and brevity of the description, the specific working process of the system, the device and the unit described above can refer to the corresponding process in the foregoing method embodiment, and details are not described herein again.
在本申请所提供的几个实施例中，应该理解到，所揭露的系统、装置和方法，可以通过其它的方式实现。例如，以上所描述的装置实施例仅仅是示意性的，例如，所述单元的划分，仅仅为一种逻辑功能划分，实际实现时可以有另外的划分方式，例如多个单元或组件可以结合或者可以集成到另一个系统，或一些特征可以忽略，或不执行。另外，所显示或讨论的相互之间的耦合或直接耦合或通信连接可以是通过一些接口、装置或单元的间接耦合或通信连接，也可以是电的，机械的或其它的形式连接。In the several embodiments provided by the present application, it should be understood that the disclosed systems, devices, and methods may be implemented in other manners. For example, the device embodiments described above are merely illustrative. For example, the division of the unit is only a logical function division. In actual implementation, there may be another division manner, for example, multiple units or components may be combined or Can be integrated into another system, or some features can be ignored or not executed. In addition, the mutual coupling or direct coupling or communication connection shown or discussed may be an indirect coupling or communication connection through some interface, device or unit, or an electrical, mechanical or other form of connection.
所述作为分离部件说明的单元可以是或者也可以不是物理上分开的，作为单元显示的部件可以是或者也可以不是物理单元，即可以位于一个地方，或者也可以分布到多个网络单元上。可以根据实际的需要选择其中的部分或 者全部单元来实现本发明实施例方案的目的。The units described as separate components may or may not be physically separated, and the components displayed as units may or may not be physical units, that is, may be located in one place, or may be distributed to multiple network units. You can choose some of them according to actual needs or All units are used to achieve the objectives of the embodiments of the present invention.
另外，在本发明各个实施例中的各功能单元可以集成在一个处理单元中，也可以是各个单元单独物理存在，也可以是两个或两个以上单元集成在一个单元中。上述集成的单元既可以采用硬件的形式实现，也可以采用软件功能单元的形式实现。In addition, each functional unit in each embodiment of the present invention may be integrated into one processing unit, or each unit may exist physically separately, or two or more units may be integrated into one unit. The above integrated unit can be implemented in the form of hardware or in the form of a software functional unit.
通过以上的实施方式的描述，所属领域的技术人员可以清楚地了解到本发明可以用硬件实现，或固件实现，或它们的组合方式来实现。当使用软件实现时，可以将上述功能存储在计算机可读介质中或作为计算机可读介质上的一个或多个指令或代码进行传输。计算机可读介质包括计算机存储介质和通信介质，其中通信介质包括便于从一个地方向另一个地方传送计算机程序的任何介质。存储介质可以是计算机能够存取的任何可用介质。以此为例但不限于：计算机可读介质可以包括RAM、ROM、EEPROM、CD-ROM或其他光盘存储、磁盘存储介质或者其他磁存储设备、或者能够用于携带或存储具有指令或数据结构形式的期望的程序代码并能够由计算机存取的任何其他介质。此外。任何连接可以适当的成为计算机可读介质。例如，如果软件是使用同轴电缆、光纤光缆、双绞线、数字STA线(DSL)或者诸如红外线、无线电和微波之类的无线技术从网站、服务器或者其他远程源传输的，那么同轴电缆、光纤光缆、双绞线、DSL或者诸如红外线、无线和微波之类的无线技术包括在所属介质的定影中。如本发明所使用的，盘(Disk)和碟(disc)包括压缩光碟(CD)、激光碟、光碟、数字通用光碟(DVD)、软盘和蓝光光碟，其中盘通常磁性的复制数据，而碟则用激光来光学的复制数据。上面的组合也应当包括在计算机可读介质的保护范围之内。Through the description of the above embodiments, those skilled in the art can clearly understand that the present invention can be implemented in hardware, firmware implementation, or a combination thereof. When implemented in software, the functions described above may be stored in or transmitted as one or more instructions or code on a computer readable medium. Computer readable media includes both computer storage media and communication media including any medium that facilitates transfer of a computer program from one location to another. A storage medium may be any available media that can be accessed by a computer. By way of example and not limitation, computer readable media may comprise RAM, ROM, EEPROM, CD-ROM or other optical disk storage, disk storage media or other magnetic storage device, or can be used for carrying or storing in the form of an instruction or data structure. The desired program code and any other medium that can be accessed by the computer. Also. Any connection may suitably be a computer readable medium. For example, if the software is transmitted from a website, server, or other remote source using coaxial cable, fiber optic cable, twisted pair, digital STA line (DSL), or wireless technologies such as infrared, radio, and microwave, then the coaxial cable , fiber optic cable, twisted pair, DSL, or wireless technologies such as infrared, wireless, and microwave are included in the fixing of the associated media. As used in the present invention, a disk and a disc include a compact disc (CD), a laser disc, a compact disc, a digital versatile disc (DVD), a floppy disk, and a Blu-ray disc, wherein the disc is usually magnetically copied, and the disc is The laser is used to optically replicate the data. Combinations of the above should also be included within the scope of the computer readable media.
总之，以上所述仅为本发明技术方案的较佳实施例而已，并非用于限定本发明的保护范围。凡在本发明的精神和原则之内，所作的任何修改、等同替换、改进等，均应包含在本发明的保护范围之内。 In summary, the above description is only a preferred embodiment of the technical solution of the present invention, and is not intended to limit the scope of the present invention. Any modifications, equivalent substitutions, improvements, etc. made within the spirit and scope of the present invention are intended to be included within the scope of the present invention.

Claims (6)

  1. 一种发送HE-LTF序列的方法，包括：A method of transmitting an HE-LTF sequence, comprising:
    根据带宽大小确定相应的HE-LTF序列,所述HE-LTF序列包含连续的子序列Ga和子序列Gb，和，位于空余leftover子载波位置上的+1或者-1；其中Ga与Gb具有互补性；Determining a corresponding HE-LTF sequence according to the bandwidth size, the HE-LTF sequence comprising a continuous sub-sequence Ga and a sub-sequence Gb, and +1 or -1 at a position of the spare leftover subcarrier; wherein Ga and Gb are complementary ;
    根据资源分配信息中的RU大小和RU位置，发送所述HE-LTF序列。The HE-LTF sequence is transmitted according to the RU size and the RU location in the resource allocation information.
  2. 根据权利要求1的方法，所述HE-LTF序列还包括：连续的-Ga和-Gb，或者，连续的+Ga和-Gb，或者，连续的-Ga和+Gb，或者，或者，连续的+Gb和-Ga，或者，部分的Ga，Gb，-Ga，或者-Gb。The method of claim 1, the HE-LTF sequence further comprising: continuous -Ga and -Gb, or consecutive +Ga and -Gb, or continuous -Ga and +Gb, or, or, continuous +Gb and -Ga, or part of Ga, Gb, -Ga, or -Gb.
  3. 根据权利要求1或者2的方法，所述HE-LTF序列是AP发送的下行的HE-LTF序列，或者，是STA发送的上行的HE-LTF序列。The method according to claim 1 or 2, wherein the HE-LTF sequence is a downlink HE-LTF sequence sent by the AP, or is an uplink HE-LTF sequence sent by the STA.
  4. 一种可以用于执行上述权利要求1-3所述方法的装置。An apparatus that can be used to perform the method of claims 1-3 above.
  5. 包含权利要求4所述的装置的站点。A station comprising the apparatus of claim 4.
  6. 包含权利要求4所述的装置的接入点。 An access point comprising the apparatus of claim 4.
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