WO2011116720A2 - Method, device and base station for allocating power - Google Patents

Method, device and base station for allocating power Download PDF

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Publication number
WO2011116720A2
WO2011116720A2 PCT/CN2011/073531 CN2011073531W WO2011116720A2 WO 2011116720 A2 WO2011116720 A2 WO 2011116720A2 CN 2011073531 W CN2011073531 W CN 2011073531W WO 2011116720 A2 WO2011116720 A2 WO 2011116720A2
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WIPO (PCT)
Prior art keywords
power
ratio
total
maximum
user
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PCT/CN2011/073531
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French (fr)
Chinese (zh)
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WO2011116720A3 (en
Inventor
徐修强
徐志昆
张舜卿
陈雁
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华为技术有限公司
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Priority to PCT/CN2011/073531 priority Critical patent/WO2011116720A2/en
Priority to CN201180000497.1A priority patent/CN102577531B/en
Publication of WO2011116720A2 publication Critical patent/WO2011116720A2/en
Publication of WO2011116720A3 publication Critical patent/WO2011116720A3/en

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    • HELECTRICITY
    • H04ELECTRIC COMMUNICATION TECHNIQUE
    • H04WWIRELESS COMMUNICATION NETWORKS
    • H04W52/00Power management, e.g. TPC [Transmission Power Control], power saving or power classes
    • H04W52/04TPC

Definitions

  • the present invention relates to the field of wireless communications, and in particular, to a power allocation method and apparatus, and a base station. Background technique
  • the reference signal is a known signal for channel estimation provided by the transmitting end to the receiving end. Transmitting a high-power reference signal ensures channel estimation accuracy, ensures cell coverage, and improves signal detection performance. On the other hand, improving the transmission power used to transmit user data information can also improve system performance.
  • the total transmission power used for reference signal transmission and user data transmission is limited, the power occupied by the reference signal (hereinafter referred to as “reference signal power”) and the power occupied by user data (hereinafter referred to as “user data power”)
  • reference signal power the power occupied by the reference signal
  • user data power the power occupied by user data
  • the relationship is the same, that is, if the power used for the reference signal transmission is large, the power used for user data transmission is correspondingly small, and vice versa, if the power used for the reference signal transmission is small, The power of user data transmission will be correspondingly large.
  • how to properly allocate the power for reference signals and user data is a matter of great concern to the industry. question.
  • the prior art proposes a channel threshold-based power allocation method in an OFDM (Frequency Division Multiplexing) system, which is based on channel gain and total system power limit. owned.
  • the specific power allocation expression is as follows:
  • MMSE the minimum mean square error estimate of the data on the first subcarrier.
  • the channel threshold, which is obtained by the following system total power limit conditions.
  • the above prior art utilizes small-scale channel information (instantaneous channel information), that is, channel information with fast time-scale changes for power allocation, it is necessary to frequently feed back a large amount of channel information and inform the receiver of power allocation information, which leads to Additional signaling overhead.
  • the above prior art only considers the allocation of power (power for user data transmission) on the subcarriers, and how to perform power allocation when using the reference signal for channel estimation is not involved, and only the mutual information amount is the largest. The power distribution is not considered, and the power distribution scheme is designed from the perspective of optimal energy efficiency.
  • Embodiments of the present invention provide a power allocation method and apparatus, and a base station, which provide optimal energy efficiency for the system.
  • An embodiment of the present invention provides a power allocation method, including: calculating a ratio of a reference signal power to a predetermined value a and a user data power of a user U m to a predetermined value when a total transmission power is a fixed value Example jS m, Um said user is any user in the system in a connected state; and said ratio according to the ratio of /, determines the transmission power of a total system energy efficiency to whether the maximum value, if yes, obtaining Calculating the ratio and ratio, otherwise, updating the total transmission power to calculate the ratio a and the ratio ⁇ ⁇ after updating the total transmission power P t , and determining whether the energy efficiency of the system is maximum after the total transmission power P t is updated, if Then, the ratio "sum ratio" calculated after the total transmission power update is obtained.
  • An embodiment of the present invention provides a power allocation method, including: acquiring a total transmission power P t when the energy efficiency of the system is maximum, a ratio a when the reference signal power accounts for the fixed total power P t is a fixed value, and a user of the user 1 ⁇
  • the ratio of the data power to the total power of the transmission is the fixed value; if the product of the sum, P t a is greater than or equal to the minimum value of the reference signal power, the ratio a and the ratio are used as the power distribution ratio of the reference signal and the power of the user data, the conversion to the final transmission to the power conversion efficiency;??
  • An embodiment of the present invention provides a power distribution apparatus, including: a ratio calculation module, configured to calculate a ratio a of a reference signal power to a predetermined value when a total transmit power is a fixed value, and a user data power of a user U m
  • the ratio of the value ⁇ ⁇ , the user U m is any user in the connected state in the system
  • the judgment processing module is configured to calculate the ratio “and the ratio according to the ratio calculation module, and determine that the total power of the transmission is Whether the energy efficiency of the system is the largest when the value is stated, and if so, the ratio and ratio are obtained, otherwise the total power of the transmission is updated.
  • the ratio calculation module is further configured to calculate the ratio and the ratio ⁇ ⁇ after the total transmission power/ ⁇ update, and the determining processing module is further configured to determine whether the energy efficiency of the system is the largest after the total transmission power P t is updated. If yes, the ratio "sum ratio" calculated after the total transmission power update is obtained.
  • An embodiment of the present invention provides a base station, where the base station includes the foregoing power distribution device.
  • An embodiment of the present invention provides a power distribution apparatus, including: a first acquiring module, configured to acquire a total transmission power P f when the energy efficiency of the system is maximum, and a ratio of a reference signal power to a total value of the total transmission power/ ⁇ a user data power of a and user Um occupies a ratio ⁇ ⁇ when the total transmission power / ⁇ is a fixed value; a second obtaining module, configured to: if the product of the sum, and ? is greater than or equal to a minimum value of the reference signal power, the proportion and the ratio are used as a ratio of the reference signal power to the user data power , the conversion efficiency of the conversion to the final transmission power;
  • a third obtaining module configured to: if the product of the sum and the sum does not satisfy a condition that is greater than or equal to a minimum value of the reference signal power, re-acquire and transmit the condition that the reference signal power is equal to the / ⁇
  • the ratio of the reference signal power to the fixed value a and the user data power of the user Um occupy the ratio ⁇ ⁇ of the fixed value.
  • An embodiment of the present invention provides a base station, where the base station includes the foregoing power distribution device.
  • the embodiment of the present invention considers the power allocation from the ratio of the reference signal power to the ratio of the total transmission power to a certain fixed value and the ratio of the user data power to the fixed value.
  • the technology only considers the different allocation of user data power, taking into account the situation of channel estimation using reference signals.
  • the joint design reference signal power and user data power of the present invention can further reduce system power consumption based on optimizing total power.
  • the method provided by the embodiment of the present invention determines whether the energy efficiency of the system is the largest when the total power is a certain value, and the reference signal power and the user are allocated according to the ratio a and the ratio ⁇ ⁇ obtained when the energy efficiency of the system is maximum.
  • the data power therefore, the invention transmits the total power from the perspective of optimal energy efficiency, and the overall energy consumption of the system air interface is greatly reduced compared with the traditional method of transmitting the maximum transmission power of the system, thereby achieving high efficiency and energy saving.
  • FIG. 1 is a schematic flowchart of a power allocation method according to an embodiment of the present invention.
  • FIG. 2 is a schematic flowchart of an iterative search ratio and scale method according to an embodiment of the present invention
  • FIG. 3 is a flowchart of a power allocation method according to another embodiment of the present invention
  • FIG. 4 is a flowchart of a power allocation method according to another embodiment of the present invention
  • FIG. 5 is a flowchart of a power allocation method according to another embodiment of the present invention
  • FIG. 4 is a flowchart of a power allocation method according to another embodiment of the present invention
  • FIG. 5 is a flowchart of a power allocation method according to another embodiment of the present invention.
  • FIG. 6 is a schematic diagram of a logical structure of a power distribution apparatus according to an embodiment of the present invention.
  • FIG. 7 is a schematic diagram of a logic structure of a power distribution apparatus according to another embodiment of the present invention
  • FIG. 8 is a schematic diagram of a logic structure of a power distribution apparatus according to another embodiment of the present invention
  • FIG. 9 is a schematic diagram of another embodiment of the present invention.
  • FIG. 10 is a schematic diagram of a logical structure of a power distribution apparatus according to another embodiment of the present invention
  • FIG. 11 is a schematic diagram of a logical structure of a base station according to an embodiment of the present invention;
  • FIG. 12 is a schematic diagram of a logical structure of a power distribution apparatus according to another embodiment of the present invention
  • FIG. 13 is a schematic diagram of a logical structure of a power distribution apparatus according to another embodiment of the present invention
  • FIG. 15 is a schematic diagram showing the logical structure of a power distribution device according to another embodiment of the present invention
  • FIG. 16 is a schematic diagram showing the logical structure of a power distribution device according to another embodiment of the present invention
  • FIG. 17 is a schematic diagram of a logical structure of a power distribution apparatus according to another embodiment of the present invention
  • FIG. 18 is a schematic diagram of a logical structure of a power distribution apparatus according to another embodiment of the present invention
  • FIG. 20 is a schematic diagram of a logical structure of a base station according to another embodiment of the present invention.
  • Embodiments of the present invention provide a power allocation method and apparatus, and a base station, which provide optimal energy efficiency for the system.
  • Method in this embodiment Mainly includes the steps:
  • the total power to be transmitted includes two parts, that is, power for transmitting the reference signal (the cartridge is referred to as “reference signal power”) and power for transmitting user data (the cartridge is called “user data power”).
  • Reference signal power the reference signal
  • user data power the cartridge is called “user data power”
  • the fixed value may be the maximum total transmission power of the total transmission power, that is, the total transmission power Power / ⁇ is the maximum total transmit power P.
  • the reference signal power is calculated to account for the maximum total transmission power P.
  • the ratio a and the user data power account for the maximum transmitted total power P.
  • the ratio ⁇ ⁇ then, can gradually reduce the total transmitted power.
  • step S101 Calculate the ratio and the ratio calculated according to step S101, and determine whether the energy efficiency of the system is the maximum when the total transmission power/ ⁇ is the fixed value. If yes, obtain the ratio and ratio. Otherwise, update the total transmission power.
  • determining whether the energy efficiency of the system is maximum when the total value of the total power is transmitted may be: determining, according to the ratio and the ratio, the total power of the transmission P t At the maximum, the system has the highest energy efficiency.
  • the energy efficiency 7 of the system is defined as the amount of information transmitted under unit energy consumption. which is:
  • P f is the total power transmitted by the system
  • is the sum of the circuit loss and the static power consumption
  • M is the number of users in the connected state in the system
  • ⁇ / is the subcarrier bandwidth
  • N m is the number of subcarriers occupied by the user m
  • 7 is the conversion efficiency of the total transmit power P t converted to the final transmit power.
  • the ratio of the reference signal power to the total transmit power P t is the ratio of the user data power of the mth user to the total transmit power/ ⁇ , which is the large-scale channel gain of the mth user, and is the noise power of the mth user.
  • L m is the number of resolvable multipaths of the mth user experiencing the channel.
  • the ratio of the reference signal power to the maximum total transmission power CC and the user data power of the user UTM to the maximum total transmission power ⁇ ⁇ are obtained, the ratio (and the ratio ⁇ ⁇ according to the allocated reference signal power and the user data power) .
  • the ratio a and the ratio of the total power P t updated in the step S102 are calculated, and the ratio of the reference signal power to the maximum total transmission power and the user of the user U when calculating the total transmission power ⁇ maximum is calculated.
  • the ratio of the data power to the maximum total transmission power is similar, and the difference is only that the total power used for the calculation of the used parameters is changed.
  • the energy efficiency of the system after the total power is updated may be compared with the energy efficiency of the system before the update, and the total power is updated to determine the energy efficiency when updating. Whether the growth rate reaches the set accuracy, and if so, the total transmission power is judged.
  • the energy efficiency of the system is maximized after the update.
  • the setting accuracy is assumed to be the energy efficiency of the system before the total power is updated; ⁇ , the energy efficiency of the system after the total power update is caravan, if i) ⁇ i is established, then the energy efficiency growth rate of the total power update is determined to be set.
  • the accuracy, otherwise, the total transmission power is updated again and it is judged whether the energy efficiency growth rate at the time when the total transmission power is updated again reaches the set accuracy fl .
  • the power allocation is considered in terms of the ratio of the reference signal power to the maximum transmission total power and the ratio of the user data power to the maximum transmission total power, so that only the user is considered in the prior art.
  • the allocation of data power is different, taking into account the situation of channel estimation using reference signals.
  • the joint design of reference signal power and user data power of the present invention can further reduce system power consumption based on optimizing total power.
  • the method provided by the embodiment of the present invention determines whether the energy efficiency of the system is the largest when the total power is a certain value, and the reference signal power and the user are allocated according to the ratio a and the ratio ⁇ ⁇ obtained when the energy efficiency of the system is maximum.
  • the data power therefore, the invention transmits the total power from the perspective of optimal energy efficiency, and the overall energy consumption of the system air interface is greatly reduced compared with the traditional method of transmitting the maximum transmission power of the system, thereby achieving high efficiency and energy saving.
  • the initial value set by the maximum transmission total power and the ratio, and the ratio of the user data power of the user Um to the maximum total transmission power is obtained ⁇ ⁇ ;
  • the expression is specifically
  • N m is the number of subcarriers occupied by the user UTM
  • P For the maximum transmitted total power, p is the corpse.
  • is the large-scale channel gain of the user UTM
  • the noise power of the user Um L m is the number of resolvable multipaths that the user Um experiences the channel
  • V is the Lagrangian multiplier, Satisfied ⁇ ;! ! ⁇ , ⁇ )) ⁇ - , can use the dichotomy to find the optimal V
  • M is the number of connected / 3 ⁇ 4 in the system.
  • determining the ratio of the initial value is set when the ratio of a set initial value satisfies the acquired acquired ⁇ , places ⁇ ⁇ acquired at this time and the initial value of the ratio, respectively, as a set of The ratio of the user data power to the maximum transmission total power and the reference signal power to the maximum transmission total power, otherwise, updating the value of the ratio (S204), where £ 3 is the empirical value, one- 1 (1 to - 5.
  • £ 3 is the empirical value, one- 1 (1 to - 5.
  • the step / / 2 can be the selected fixed value or the optimal step size obtained by some optimization method, such as the dichotomy.
  • optimization problem 1 (ie, energy efficiency function 7) is a quasi-convex function, and constraint 1 is a linear constraint. Therefore, optimization problem 1 is a quasi-convex problem. According to the optimization theory, it is easy to obtain the above problem. There is a unique ratio of the optimal total transmission power, the reference signal power, and the user data power to the optimal total transmission power.
  • the total transmit power takes the maximum value P. Whether the energy efficiency of the system is the largest, if the maximum, the user data power of the user U m respectively obtained by the sum ratio a obtained at this time accounts for the maximum total transmission power P. The ratio and reference signal power account for the maximum transmitted total power P. proportion.
  • the following method when determining whether the energy efficiency of the system is maximum when the total transmission power is maximum, the following method may be implemented:
  • the energy efficiency function 7 is 1 mg ol ⁇ L m+ N m a) where ⁇ / is the subcarrier bandwidth, N m
  • the number of subcarriers is occupied, / ⁇ is the sum of circuit loss and static power consumption, ? is the conversion efficiency of the conversion to final transmission power, ⁇ is the large-scale channel gain of user U, and the noise power of user Um , L m is the number of resolvable multipaths that the user U experiences the channel, and M is the number of users in the system that are connected.
  • is the large-scale channel gain of the user U
  • the power allocation algorithm based on the prior art based on small-scale channel information (that is, channel information with fast time-scale changes, for example, instantaneous channel information, etc.)
  • the power distribution method according to the embodiment of the present invention is provided by the present invention, according to the channel large-scale channel information (that is, the channel information that is invariant for a long time, such as path loss, shadow fading, and large-scale channel gain, etc.).
  • the amount of channel information required is small, and the feedback frequency is low. If the partial derivative ⁇ is at the total transmission power / ⁇ is the maximum transmission total power P.
  • the value of time that is, greater than or equal to 0, determines that the system has the highest energy efficiency when the total transmission power is maximum.
  • the foregoing determines the principle of whether the energy efficiency of the system is maximum when the total power/ ⁇ maximum is transmitted.
  • ⁇ 0, indicating that the energy efficiency function 7 is an increasing function with respect to the total power of transmission P f , and its physical meaning is dP t
  • the system energy efficiency increases as P f increases, so when it reaches its maximum value P. At this time, the energy efficiency 7 of the system is obviously the largest.
  • FIG. 3 it is a flowchart of a power allocation method according to another embodiment of the present invention. It can be used as a supplementary description of the power allocation method provided in the example of FIG.
  • set the transmit power / ⁇ to the maximum value P. can be the maximum value of the power amplifier.
  • the iterative algorithm exemplified in FIG. 2 can be used to calculate the reference signal power as the maximum total transmission power P according to ⁇ /, N m , ⁇ , ⁇ ⁇ , a m 2 , L m , and the like.
  • the ratio "and user data power accounts for the maximum transmitted total power P. proportion. ⁇ /, N m , ⁇ , ⁇ ⁇ , ⁇ , L m , ⁇ ⁇ have the same meanings as ⁇ /, N , ⁇ , ⁇ , ⁇ , L , in the previous examples, do not like
  • the total transmit power at w iterations, A is the iteration step size, which can be set to a fixed value, or set to the optimal value found by some optimization algorithm (for example, dichotomy).
  • the method is similar to S302, that is, the iterative algorithm illustrated in Fig. 2 can be employed.
  • the difference is that the total transmitted power at this time is the maximum value P. Change to a different value.
  • the setting accuracy is fl (generally set to 10 - 1 ⁇ 10- 5 ), assuming that the total power is transmitted / ⁇ before the update (that is, the total transmitted power at the w - l iterations / ⁇ ) ;; ⁇ , after the total power is sent (ie, the total power transmitted at the wth iteration), the energy efficiency of the system is;; negligence, if n ) ⁇ , the energy efficiency obtained by this iteration is judged; Energy efficiency; 7 mesh-i, the growth rate can reach the set accuracy.
  • the reference signal power and the user data power can be allocated according to the ratio as long as the ratio and the ratio are solved.
  • the following embodiments are the same and will not be described again.
  • the reference signal may have other uses besides being used for channel estimation, for example, to ensure a certain cell coverage. Therefore, the reference signal power takes a value higher than a certain threshold, that is, paP t ⁇ ⁇ ⁇ , where ⁇ is the minimum value of the reference signal power, and the meanings of ⁇ , and are the same as in the previous embodiment. That is to say, when the constraint 7 ⁇ 4 is added, the optimization problem 1 is converted into the following optimization problem 2:
  • the value is the maximum total transmission power of the total transmission power.
  • the total transmission power p f and the reference signal power of the system when the energy efficiency of the system is maximized are The proportion of the ratio a and the user data of the user U m when the total transmission power is the fixed value is: the total transmission power when the energy efficiency of the system is maximized, and the reference signal power accounts for the maximum transmission total.
  • the ratio of the power a and the user data power of the user U m account for the ratio of the maximum transmitted total power.
  • step S402. If the product of Pt and a obtained in step S401 is greater than or equal to a minimum value of the reference signal power, the ratio and the ratio are used as a ratio of the reference signal power and the user data power.
  • ? is converted to the conversion efficiency of the final transmission power. If / ⁇ is established, the total transmit power and power ratio at this time is also the optimal solution for optimization problem 2, and the solution process ends.
  • the total transmit power is reacquired under the condition that the reference signal power is equal to the / ⁇ .
  • the ratio of the reference signal power to the fixed value when the value is fixed "the ratio of the user data power of the user U m to the fixed value ⁇ ⁇ .
  • the ratio of data power to the maximum transmitted total power ⁇ ⁇ including steps
  • the energy efficiency of the system is the largest when the sum of the user data powers ⁇ ⁇ of the plurality of users is the largest.
  • it is determined whether the energy efficiency of the system is the maximum when the total transmission power is maximum, and the steps include:
  • N m is occupied by the user U m
  • the sum of power consumption is the large-scale channel gain of the user u m
  • the noise power of the user 1 L M is the number of resolvable multipaths that the user U m experiences the channel
  • M is the number of users in the system in the connected state.
  • the principle of determining whether the energy efficiency of the system is maximum when the sum of the user data powers of the plurality of users is the maximum ⁇ ⁇ is: ⁇ 0 indicates that the energy efficiency function 7 is an increasing function, and the physical meaning is that the system energy efficiency is The increase is increased, so when the maximum value is taken, the energy efficiency 7 of the system is obviously the largest.
  • determining whether the energy efficiency of the system after maximizing / ⁇ is updated includes: determining whether the energy efficiency growth rate at the time of updating reaches the set accuracy, and if so, determining that the energy efficiency of the system after the update is updated The biggest.
  • the setting accuracy is f 4 , assuming that the energy efficiency of the system before the update is; ⁇ , the energy efficiency of the system after updating is 7;, if ( d) ⁇ 4 , it is judged that the energy efficiency growth rate of the system reaches the set accuracy when updating. Otherwise, it is again / / and judges whether the energy efficiency growth rate at the time of the update is up to the set accuracy.
  • the method of summing the data powers may be: placing the / ⁇ where ⁇ is the updated value of / ⁇ , ⁇ subtitle-i is the ⁇
  • the method further includes:
  • FIG. 5 is a flowchart of a power allocation method according to another embodiment of the present invention
  • Mainly includes the steps:
  • the method and the steps illustrated in Figure 4 S4031 calculates the sum of the user data powers of the plurality of users ⁇ ⁇ is the maximum when the user data power of the user U m is proportional to the ratio y m of ⁇ ⁇ .
  • the difference is that the sum ⁇ ⁇ of the user data powers of a plurality of users at this time is changed from the maximum value ⁇ 0 - ⁇ ⁇ ⁇ to other values.
  • the partial derivative of ⁇ . ⁇ / is the subcarrier bandwidth
  • is the large-scale channel gain of the user u m
  • the noise power of the user UTM L m is the number of resolvable multipaths that the user UTM experiences the channel
  • M is the number of users in the system that are connected.
  • the setting accuracy is £ 4 (generally set to 10 - 5 - 10" 10 ), assuming the sum of the user data powers of multiple users / ⁇ before the update (ie the total transmit power at the w -1 iterations) / ⁇ )
  • the energy efficiency of the system is; ⁇ , the sum of the user data powers of multiple users ⁇ after updating (ie, the total power transmitted at the Wth iteration), the energy efficiency of the system is; if ("U ⁇ ⁇ 4 , then judge this The energy efficiency obtained from the next iteration and the last iteration
  • the energy efficiency growth rate reaches the set accuracy.
  • £ 5 - generally may be set to 10-1 (1 ⁇ 10-5.
  • the reference signal power and the user data power can be allocated according to the ratio as long as the ratio and the ratio are solved.
  • the power allocation is considered in terms of the ratio of the reference signal power to the maximum transmission total power and the ratio of the user data power to the maximum transmission total power, so that only the user is considered in the prior art.
  • the allocation of data power is different, taking into account the situation of channel estimation using reference signals.
  • the joint design of reference signal power and user data power of the present invention can further reduce system power consumption based on optimizing total power.
  • the method provided by the embodiment of the present invention determines whether the energy efficiency of the system is the largest when the total power is a certain value, and the reference signal power and the user are allocated according to the ratio a and the ratio ⁇ ⁇ obtained when the energy efficiency of the system is maximum.
  • the present invention designs the system to transmit the total power from the perspective of optimal energy efficiency and guarantees a certain basis on this basis.
  • the cell coverage greatly reduces the overall energy consumption of the system air interface and achieves high efficiency and energy saving.
  • FIG. 6 is a schematic diagram showing the logical structure of a power distribution device according to an embodiment of the present invention.
  • the function module/unit included in the power distribution device of the example of Fig. 6 may be a software module/unit, a hardware module/unit or a combination of hardware and software modules/units, including a proportional calculation module 601 and a judgment processing module 602, where:
  • the ratio calculation module 601 is configured to calculate a ratio of a reference signal power to the fixed value when the total transmission power is a fixed value, and a ratio of a user data power of the user Um to the fixed value, where the user Um is connected in the system. Any user of the status;
  • the determining processing module 602 is configured to calculate, according to the ratio a and the ratio ⁇ ⁇ calculated by the ratio calculating module 601, whether the energy efficiency of the system is maximum when the total transmitting power is the fixed value, and if yes, obtain the ratio a And the ratio p m , otherwise updating the total transmission power P t ;
  • the ratio calculation module 601 is further configured to calculate the ratio and the ratio of the total transmission power/update, and the determining processing module 602 is further configured to determine whether the energy efficiency of the system is the largest after the total transmission power P t is updated. If yes, the ratio "and ratio" calculated after the total transmission power update is obtained.
  • the value is the maximum total transmission power of the total transmission power
  • the ratio calculation module 601 is configured to calculate the maximum total transmission power when the total transmission power is maximum.
  • the proportion a and the user data power of the user U m account for the ratio of the maximum total transmission power ⁇ ⁇
  • the determination processing module 602 is configured to calculate the ratio and the ratio according to the ratio calculation module 601, and determine the judgment in the sending Whether the energy efficiency of the system is the largest when the total power is maximum, and if so, the ratio and ratio are obtained, otherwise the total transmission power is updated.
  • the judgment processing module 602 of the example of FIG. 6 may further include a judging unit 701, as shown in FIG. 7, a power distribution device according to another embodiment of the present invention, wherein:
  • the determining unit 701 is configured to determine whether the energy efficiency growth rate of the total transmission power update is set The accuracy is determined, and if so, it is judged that the energy efficiency of the system is maximized after the total transmission power is updated.
  • the setting accuracy is fl , assuming that the total power is transmitted ⁇ the energy efficiency of the system before updating; ⁇ , the energy efficiency of the system after the total power is updated is; if (H) ⁇ l , the energy efficiency growth rate when the total power is updated is judged
  • the set accuracy is reached. Otherwise, the total transmission power is updated again and it is judged whether the energy efficiency growth rate at the time of the total transmission power/ ⁇ is updated to reach the set accuracy fl .
  • the example ratio calculation module 601 of FIG. 6 or FIG. 7 is specifically configured to calculate, according to the maximum transmission total power, an ratio of a reference signal power to the maximum transmission total power and a user U m when the total transmission power is maximum.
  • User data power occupies a ratio ⁇ ⁇ of the maximum transmission total power, which includes an initial value preset unit 801, a ratio acquisition unit 802, and a ratio determination unit 803, and the power distribution provided by another embodiment of the present invention as shown in FIG.
  • the device is:
  • the initial value preset unit 801 is configured to set an initial value of the ratio
  • the ratio obtaining unit 802 is configured to obtain the ratio of the maximum transmitted total power and the initial value, and the expression is specifically:
  • N m is the number of subcarriers occupied by the user UTM, P. For the maximum transmitted total power, 7 is the P.
  • the ratio determining unit 803 is further configured to use the ratio according to the formula ⁇ ⁇
  • the processing module 602 is further configured to use the total transmit power according to the formula / ⁇ as the updated value of the total transmit power P f , where The / ⁇ is an iteration step.
  • the judgment processing module 602 illustrated in FIGS. 6 to 8 includes a partial derivative calculation unit 901 and a determination unit 902, such as the power distribution apparatus provided in another embodiment of the present invention, wherein:
  • the partial derivative calculation unit 901 is configured to calculate a partial derivative of the energy efficiency function 7 with respect to the total power transmitted, the ⁇ is £ g 2 d+ 2 H ) , ⁇ / is the subcarrier bandwidth, and N m is the user 11 « occupied subcarrier
  • the number of waves, ⁇ is the sum of circuit loss and static power consumption, 7 is the conversion efficiency of the P f converted to the final transmit power, is the large-scale channel gain of the user UTM, and is the noise power of the user UTM, L m
  • M is the number of users in the system in the connected state;
  • the determining unit 902 is configured to determine, if the value of the partial derivative obtained by the partial derivative calculation unit 901 is greater than or equal to 0 when the total transmit power is the maximum transmit power, determine the energy efficiency of the system when the total transmit power is maximum maximum.
  • the power distribution device illustrated in FIGS. 6 to 9 further includes a precision determination module 1001, such as the power distribution device provided by another embodiment of the present invention, as shown in FIG.
  • the accuracy judging module 1001 is configured to determine whether the total energy of the transmission/ ⁇ update (that is, the total transmit power at the w-1th iteration/ ⁇ is updated to the total transmit power at the (0th) iteration)
  • the set accuracy is achieved. For example, by determining whether the establishment, £ 2 - generally can be set to 10- 1 () ⁇ ⁇ - 5. If dr] ⁇ 2 is established, the energy efficiency growth rate reaches the set accuracy.
  • each functional module is only an example, and the actual application may be as needed, for example, the configuration requirements of the corresponding hardware or the real software.
  • the above-mentioned function allocation is completed by different functional modules, that is, the internal structure of the power distribution device is divided into different functional modules to complete all or part of the functions described above.
  • the corresponding functional modules in this embodiment may be implemented by corresponding hardware, or may be executed by corresponding hardware.
  • the foregoing proportional calculation module may have the foregoing calculation and transmission.
  • the ratio of the reference signal power to the maximum total transmission power a and the user data power of the user U m to the ratio of the maximum total transmission power ⁇ ⁇ may also be able to perform corresponding
  • the computer program thus completes the foregoing functions of a general processor or other hardware device; and the foregoing determining processing module may have the function of performing the foregoing determination, whether the energy efficiency of the system is maximum when the total transmission power is maximum, and if so, acquiring the ratio And the ratio, otherwise the hardware that updates the function of transmitting the total power, such as the judgment processor, may also be a general processor or other hardware device capable of executing the corresponding computer program to perform the aforementioned functions.
  • the embodiment of the present invention considers the power allocation from the ratio of the reference signal power to the maximum transmission total power ratio a and the ratio of the user data power to the maximum transmission total power ⁇ ⁇ .
  • the joint design reference signal power and user data power of the present invention can be further reduced on the basis of optimizing the total power. System power consumption.
  • the method provided by the embodiment of the present invention determines whether the energy efficiency of the system is maximum when the total power/ ⁇ is a certain value, and the reference signal power and the user are allocated according to the ratio a and the ratio obtained when the energy efficiency of the system is maximum.
  • the invention designs the system to transmit the total power from the perspective of optimal energy efficiency and guarantees a certain cell coverage on the basis of the core, which greatly reduces the overall system air interface compared with the traditional method of transmitting the maximum transmission power of the system. Energy consumption, achieving energy efficiency.
  • FIG. 11 a schematic diagram of a logical structure of a base station, which can be used in an Orthogonal Frequency Division Multiplexing (OFDM) system, is provided in an embodiment of the present invention.
  • the function module/unit included in the base station provided by the example of FIG. 11 may be a software module/unit, a hardware module/unit or a combination of hardware and software modules/units, including a reference signal power configuration module 1102, a user data power configuration module 1103, and a sub-module.
  • the power distribution device 1101 is configured to calculate a ratio of a reference signal power to the maximum transmission total power and a ratio of user data power of the user U m to the maximum transmission total power when the total transmission power is maximum, according to the ratio and the ratio Determining whether the energy efficiency of the system is the largest when the total transmission power is maximum, and if yes, acquiring the ratio and the ratio, otherwise updating the total transmission power to calculate the ratio and the ratio ⁇ after updating the total transmission power P t , Determining whether the energy efficiency of the system after the total transmission power is updated is the largest, and if yes, obtaining the ratio and proportion calculated after the total transmission power/ ⁇ update;
  • the reference signal power configuration module 1102 is configured to allocate the reference signal power to the coded modulated reference signal according to the ratio of the reference signal power calculated by the power distribution device 1101 to the maximum total transmission power.
  • the user data power configuration module 1103 is configured to configure the user data power to the encoded and modulated user data according to the ratio ⁇ ⁇ of the user data power calculated by the power distribution device 1101 to the maximum total transmission power;
  • a subcarrier mapping module 1104 configured to map the configured reference signal and user data to the subcarriers
  • An inverse Fourier transform module 1105 is configured to perform inverse Fourier transform on the data mapped by the subcarrier mapping module 1104.
  • the cyclic prefix module 1106 is configured to perform the cyclic prefix (CP, Cyclic Prefix) processing on the data transformed by the inverse Fourier transform module 1105.
  • a digital-to-analog conversion module 1107 configured to convert the digital signal output by the cyclic prefix prefix module 1106 into an analog signal
  • the radio frequency module 1108 is configured to: the analog signal output by the digital-to-analog conversion module 1107 is amplified by a power amplifier, and the amplitude of the transmitted analog signal is adjusted according to the total transmission power obtained by the power distribution device 1101, and then transmitted through the radio frequency antenna.
  • the function module/unit included in the power distribution device provided by the example of FIG. 12 may be a software module/unit, a hardware module/unit or a combination of hardware and software modules/units, including a first acquisition module 1202, a second acquisition module 1202 and a The three acquisition module 1203, wherein:
  • the first obtaining module 1201 is configured to acquire a total transmit power P f when the energy efficiency of the system is maximum, a ratio a when the reference signal power accounts for the total transmit power/ ⁇ , and a user data power of the user U m .
  • the second obtaining module 1202 is configured to: when the product of the P f , and ? is greater than or equal to the minimum value of the reference signal power, the ratio and the ratio acquired by the first acquiring module 1201 are used as the reference a ratio of signal power to the user data power, said conversion being the conversion efficiency of the final transmission power;
  • the third obtaining module 1203 is configured to: if the product of the ?, and the sum does not satisfy a condition that is greater than or equal to a minimum value of the reference signal power / ⁇ , then the reference signal power is equal to the ⁇ ⁇ to obtain the total power transmission when the power of the reference signal value representing a ratio of the value of Um and the user account of the user data power ratio value e m.
  • the value is the maximum total transmit power of the total transmit power.
  • the first acquisition module 1201 is configured to acquire the total transmit power reference signal power when the system has the highest energy efficiency.
  • the ratio of the maximum transmission total power a and the user data power of the user U m to the maximum transmission total power, the third obtaining module 1203 is configured to: if the product of the sum and the sum does not satisfy the greater than or equal to the a condition of a minimum value of reference signal power / ⁇ , a ratio of the reference signal power to the fixed value when the fixed signal power is reacquired under the condition that the reference signal power is equal to the / ⁇
  • the ratio of the user data power of the user Um to the fixed value is: if the product of the ?, P f and the sum does not satisfy the condition that is greater than or equal to the minimum value of the reference signal power, then the reference is The signal power is equal to the condition of the ⁇ Obtaining a ratio of the reference signal power to the maximum transmission total power when the
  • the first acquisition module 1201 illustrated in FIG. 12 includes a first ratio calculation sub-module 1301 and a first determination processing sub-module 1302, such as the power distribution apparatus provided by another embodiment of the present invention, as shown in FIG.
  • a first user data power ratio calculation sub-module 1301 for calculating a ratio of the total power transmission and the user account U m maximum total transmit power is the maximum power of the reference signal representing the total maximum transmission power ratio, the user Um is any user in the connected state within the system;
  • the first determination processing sub-module 1302 is configured to calculate, according to the first ratio calculation sub-module 1301, a ratio “and a ratio, determine whether the energy efficiency of the system is maximum when the total transmission power is maximum, and if yes, obtain the ratio and Proportion, otherwise update the total transmit power
  • the first ratio calculating sub-module 1301 is further configured to calculate the ratio and the ratio p m after the sending total power update
  • the first determining processing sub-module 1302 is further configured to determine the total sending power/ ⁇ after updating. Whether the energy efficiency of the system is the largest, and if so, the ratio and proportion calculated after the total power transmission is updated.
  • the first determination processing sub-module 1302 of the example of FIG. 13 includes a first determining unit 1401, such as the power distribution apparatus provided by another embodiment of the present invention, as shown in FIG.
  • the first determining unit 1401 is configured to determine whether the energy efficiency growth rate of the total transmission power update reaches the set accuracy, and if yes, determine that the energy efficiency of the system is maximized after the total transmission power is updated.
  • the third obtaining module 1203 illustrated in FIGS. 12 to 14 includes a third ratio calculating sub-module 1501 and a third judging processing sub-module 1502, as shown in FIG. 15, a power distribution device according to another embodiment of the present invention, wherein :
  • a third user data power ratio calculation sub-module 1501 user data for the maximum sum of the power P p Um user computing a plurality of user accounts for the / ⁇ is the ratio of the maximum / ⁇ . Transmitting the total power for the maximum;
  • the third determination processing sub-module 1502 is configured to determine, according to the calculated ratio y m calculated by the third ratio calculation sub-module 1501, that the energy efficiency of the system is greater when the sum of the user data powers of the plurality of users is maximum No, if yes, the ratio and ratio are obtained according to the method, otherwise the / ⁇ is updated and it is determined whether the energy efficiency of the system after the update is maximum.
  • the third obtaining module 1203 illustrated in FIGS. 12 to 15 further includes an energy efficiency determining sub-module 1601, such as the power distribution device provided by another embodiment of the present invention shown in FIG. 16, wherein:
  • the energy efficiency judging sub-module 1601 is configured to determine whether the energy-efficiency growth rate at the time of the update reaches a set precision, and if yes, determine that the energy efficiency of the system is maximized after the update and update.
  • the third ratio calculation sub-module 1501 illustrated in FIG. 15 or FIG. 16 further includes a variable replacement unit.
  • the ratio calculation unit 1702 is configured to calculate, according to the ratio of the user data power of the user 1 ⁇ obtained by the maximum energy efficiency of the system to the maximum total transmission power,
  • the third determination processing sub-module 1502 illustrated in Fig. 15 or Fig. 16 further includes a partial derivative calculation unit 1801 and a determination unit 1802, as shown in Fig. 18, which is a power distribution device according to another embodiment of the present invention, wherein:
  • the partial derivative calculation unit 1801 is configured to calculate a partial derivative of the energy efficiency function 7 with respect to the ⁇ , where 7 is V AfN m log 2 (1 + ⁇ ⁇ ⁇ _ )
  • is the sum of the circuit loss and the static power consumption
  • is the large-scale channel gain of the user u m
  • is the noise power of the user 1
  • L m is the number of resolvable multipaths experienced by the user U m through the channel
  • M is the number of connected users in the system
  • the determining unit 1802 is configured to determine, when the partial derivative is the maximum sum of the user data powers of the plurality of users, or the value after the / ⁇ update is greater than or equal to 0, determine the number of users in the multiple users
  • the system has the highest energy efficiency according to the sum of the powers ⁇ ⁇ max.
  • the power distribution device of any of the examples of Figures 15 to 18 further includes a precision determination module 1901, such as the power distribution device of another embodiment of the present invention shown in Figure 18, wherein:
  • the accuracy judging module 1901 is configured to determine whether the sum of the user data powers of the plurality of users is updated, and whether the energy growth rate reaches the set accuracy.
  • the power distribution device according to the embodiment of the present invention as shown in the above-mentioned FIG. 12 to FIG. 19, can be considered that the ratio of the reference signal power to the maximum total transmission power and the ratio of the user data power to the maximum transmission total power are considered in the embodiment of the present invention. Power allocation, in this way, different from the prior art, only considering the allocation of user data power, taking into account the case of using the reference signal for channel estimation, the joint design reference signal power and user data power of the present invention can optimize the total power. Further reduce system power consumption. On the other hand, the method provided by the embodiment of the present invention is to determine the total power transmitted.
  • the energy efficiency of the system is the largest, and the reference signal power and the user data power are allocated according to the ratio a and the ratio obtained when the energy efficiency of the system is maximum. Therefore, the present invention designs the system to transmit the total power from the perspective of optimal energy efficiency. And ensuring a certain cell coverage on the basis of this foundation, compared with the traditional method of transmitting the maximum transmission power of the system, the overall energy consumption of the system air interface is greatly reduced, and energy saving is realized.
  • the function module/unit included in the base station provided by the example of FIG. 20 may be a software module/unit, a hardware module/unit or a combination of hardware and software modules/units, including a reference signal power configuration module 2002, a user data power configuration module 2003, a sub- A power distribution device 2001 of any one of the carrier mapping module 2004, the inverse Fourier transform module 2005, the cyclic prefix module 2006, the digital to analog conversion module 2007, the radio frequency module 2008, and the accompanying drawings 12 to 19, wherein:
  • the power distribution device 2001 is configured to calculate a ratio of the reference signal power to the maximum transmission total power a when the total transmission power P t is maximum, and a ratio of user data power of the user U m to the maximum transmission total power, according to the ratio And the ratio, determining the energy of the system when the total transmission power is maximum Whether the effect is the largest, if yes, the ratio and the ratio are obtained, otherwise the total transmission power is updated to calculate the ratio and the ratio ⁇ after the total transmission power P t is updated, and it is determined whether the energy efficiency of the system after the total transmission power is updated Maximum, if yes, obtain the ratio and proportion calculated after the total transmission power / ⁇ update;
  • the reference signal power configuration module 2002 is configured to allocate the reference signal power to the coded modulated reference signal according to the ratio of the reference signal power calculated by the power distribution device 2001 to the maximum total transmission power.
  • the user data power configuration module 2003 is configured to configure the user data power to the encoded and modulated user data according to the ratio ⁇ ⁇ of the user data power calculated by the power distribution device 2001 to the maximum total transmission power;
  • a subcarrier mapping module 2004, configured to map the configured reference signal and user data to the subcarriers
  • An inverse Fourier transform module 2005 configured to perform inverse Fourier transform on the data mapped by the subcarrier mapping module 2004;
  • a cyclic prefix module 2006 configured to perform a cyclic prefix (CP, Cyclic Prefix) process on the data transformed by the inverse Fourier transform module 2005;
  • a digital-to-analog conversion module 2007, configured to convert the digital signal output by the cyclic prefix module 2006 into an analog signal
  • the RF module 2008 is configured to: the analog signal output by the digital-to-analog conversion module 2007 is amplified by a power amplifier, and the amplitude of the transmitted analog signal is adjusted according to the total transmission power obtained by the power distribution device 2001, and then transmitted through the RF antenna.
  • the program may be stored in a computer readable storage medium, and the storage medium may include: Read only memory (ROM, Read Only Memory), Random Access Memory (RAM), disk or optical disk.
  • ROM Read only memory
  • RAM Random Access Memory

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Abstract

A method, a device and a base station for allocating power, which can provide optimal energy efficiency for a system, are disclosed in the embodiments of the present invention, wherein the method includes: when total transmitting power Pt is a fixed value, computing a proportion α of reference signal power to the fixed value and a proportion βm of user data power of a user Um to the fixed value, wherein the user Um is any user in connection state in the system; according to the proportion α and proportion βm, judging whether the energy efficiency of the system is maximum when the total transmitting power Pt is the fixed value; if yes, obtaining the proportion α and proportion βm, otherwise, updating the total transmitting power Pt; computing the proportion α and proportion βm after the total transmitting power Pt is updated, and judging whether the energy efficiency of the system is maximum after the total transmitting power Pt is updated; if yes, obtaining the computed proportion α and proportion βm after the total transmitting power Pt is updated. The method provided in the present invention can further reduce system power consumption based on optimizing total power, reduce total energy consumption of the air interface of the system greatly, and realize efficient power saving.

Description

一种功率分配方法、 装置和一种基站 技术领域  Power distribution method, device and base station
本发明涉及无线通信领域,尤其涉及一种功率分配方法、装置和一种基站。 背景技术  The present invention relates to the field of wireless communications, and in particular, to a power allocation method and apparatus, and a base station. Background technique
随着人们对无线通信业务需求的不断提高,通信业务类型已经从传统低速 语音通信业务扩展到高速多媒体数据业务。 从香农(Shannon )信息论可知, 数据率的提高需要占用更多的带宽和消耗更多的功率。在频谱资源已经十分稀 缺的情况下, 系统性能的提高不能够单纯依靠增大系统带宽来实现,现有的系 统采取的策略大部分是在增加系统带宽的同时, 提高系统的发射功率。  As people's demand for wireless communication services continues to increase, the types of communication services have expanded from traditional low-speed voice communication services to high-speed multimedia data services. According to Shannon's information theory, the increase in data rate requires more bandwidth and consumes more power. In the case that the spectrum resources are already scarce, the improvement of system performance cannot be realized by simply increasing the system bandwidth. Most of the strategies adopted by the existing systems are to increase the system bandwidth while increasing the system's transmit power.
发射功率的提高在带来高数据率和高吞吐量的同时往往会带来较大的负 面影响。从环境保护的角度来看, 高发射功率将导致更多用于通信方面的能量 消耗, 从而间接带来更多的环境污染; 从通信设备供应商的角度来看, 高功耗 将导致设备制造成本的大幅提高, 尤其对于靠电池供电的移动通信设备, 例如 手机, 高能耗往往会导致设备使用寿命的大大缩短。 因此, 如何设计高效节能 的通信系统已成为一个备受关注的课题。传统的通信系统往往以吞吐量最大化 为设计目标,在这一设计准则下, 系统往往以最大的发送功率进行发射。然而, 这种设计准则下虽然最大化吞吐量但并不能保证能够有效利用发送功率,如何 从能量有效的角度来确定系统的发送总功率是一个新的课题。  The increase in transmit power tends to have a large negative impact while at the same time bringing high data rates and high throughput. From the perspective of environmental protection, high transmission power will lead to more energy consumption for communication, which indirectly leads to more environmental pollution; from the perspective of communication equipment suppliers, high power consumption will lead to equipment manufacturing. Significantly increased costs, especially for battery-powered mobile communication devices, such as cell phones, high energy consumption often leads to a significant reduction in equipment life. Therefore, how to design an energy-efficient communication system has become a topic of great concern. Traditional communication systems are often designed with maximum throughput. Under this design rule, systems often transmit at the maximum transmit power. However, while this design criterion maximizes throughput but does not guarantee efficient use of transmit power, how to determine the total transmit power of the system from an energy efficient perspective is a new topic.
参考信号是由发射端提供给接收端的用于信道估计的已知信号。发送高功 率的参考信号可以保证信道估计的准确度,保证小区覆盖, 进而提高信号检测 性能。 另一方面, 提高用于传输用户数据信息的发送功率, 同样可以提高系统 性能。 然而, 用于参考信号发送和用户数据传输的总发送功率是有限的, 参考 信号占用的功率(以下筒称 "参考信号功率" )和用户数据占用的功率(以下 筒称 "用户数据功率" )是此消彼长的关系, 即, 若用于参考信号发送的功率 较大, 则用于用户数据传输的功率会相应较小, 反之, 若用于参考信号发送的 功率较小, 则用于用户数据传输的功率会相应较大。在发送总功率受限的系统 中 ,如何合理地分配用于参考信号和用户数据的功率是业界十分关注的一个问 题。 The reference signal is a known signal for channel estimation provided by the transmitting end to the receiving end. Transmitting a high-power reference signal ensures channel estimation accuracy, ensures cell coverage, and improves signal detection performance. On the other hand, improving the transmission power used to transmit user data information can also improve system performance. However, the total transmission power used for reference signal transmission and user data transmission is limited, the power occupied by the reference signal (hereinafter referred to as "reference signal power") and the power occupied by user data (hereinafter referred to as "user data power") The relationship is the same, that is, if the power used for the reference signal transmission is large, the power used for user data transmission is correspondingly small, and vice versa, if the power used for the reference signal transmission is small, The power of user data transmission will be correspondingly large. In a system with limited total power transmission, how to properly allocate the power for reference signals and user data is a matter of great concern to the industry. question.
针对上述业界关注的问题,现有技术提出了一种在正交频分复用( OFDM, Frequency Division Multiplexing ) 系统中基于信道门限的功率分配方法, 该门 限设计是根据信道增益和系统总功率限制得到的。 具体功率分配的表达式如 下:
Figure imgf000004_0001
In view of the above-mentioned problems in the industry, the prior art proposes a channel threshold-based power allocation method in an OFDM (Frequency Division Multiplexing) system, which is based on channel gain and total system power limit. owned. The specific power allocation expression is as follows:
Figure imgf000004_0001
I _  I _
p . = MMSE;1 (min{l, η Ι γΛ) , > ηp . = MMSE; 1 (min{l, η Ι γΛ) , > η
Figure imgf000004_0002
Figure imgf000004_0002
其中 是第 个子载波上的功率, 为第 个子载波上的信道增益与噪声 功率的比值, MMSE . (p^ )是第 个子载波上的数据进行最小均方误差 ( Minimum Mean Square Error, MMSE )估计的估计均方误差, η为信道门限, 该门限通过如下系统总功率限制条件求得。
Figure imgf000004_0003
与传统的灌水功率算法相比,该方法可以更好地适应发射信号离散非高斯分布 的特性。
Where is the power on the first subcarrier, which is the ratio of the channel gain to the noise power on the first subcarrier, MMSE. (p^) is the minimum mean square error (MMSE) estimate of the data on the first subcarrier. Estimated mean square error, η is the channel threshold, which is obtained by the following system total power limit conditions.
Figure imgf000004_0003
Compared with the traditional irrigation power algorithm, this method can better adapt to the characteristics of discrete non-Gaussian distribution of transmitted signals.
由于上述现有技术是利用小尺度信道信息(瞬时信道信息), 即时间尺度 变化很快的信道信息进行功率分配,因此需要频繁地反馈大量信道信息和告知 接收机功率分配信息, 这些都导致了额外的信令开销。 另一方面, 上述现有技 术只考虑了子载波上的功率(用于用户数据传输的功率)分配, 在利用参考信 号进行信道估计时如何进行功率分配则没有涉及,并且只是从互信息量最大化 角度进行功率分配, 没有考虑如何从能效最优的角度设计功率分配方案。  Since the above prior art utilizes small-scale channel information (instantaneous channel information), that is, channel information with fast time-scale changes for power allocation, it is necessary to frequently feed back a large amount of channel information and inform the receiver of power allocation information, which leads to Additional signaling overhead. On the other hand, the above prior art only considers the allocation of power (power for user data transmission) on the subcarriers, and how to perform power allocation when using the reference signal for channel estimation is not involved, and only the mutual information amount is the largest. The power distribution is not considered, and the power distribution scheme is designed from the perspective of optimal energy efficiency.
发明内容 Summary of the invention
本发明实施例提供一种功率分配方法、装置和一种基站, 为系统提供最优 能效。  Embodiments of the present invention provide a power allocation method and apparatus, and a base station, which provide optimal energy efficiency for the system.
本发明实施例提供一种功率分配方法, 包括: 计算发送总功率 ^为定值时 参考信号功率占所述定值的比例 a和用户 Um的用户数据功率占所述定值的比 例 jSm , 所述用户 Um是系统内处于连接状态的任一用户; 根据所述比例 和比 例/ , 判断在所述发送总功率 为所述定值时系统的能效是否最大, 若是, 则 获取所述比例 和比例 , 否则, 更新所述发送总功率 计算所述发送总功 率 Pt更新后所述比例 a和比例 βΜ , 判断所述发送总功率 Pt更新后系统的能效是 否最大, 若是, 则获取所述发送总功率 更新后计算所得的比例《和比例 。 An embodiment of the present invention provides a power allocation method, including: calculating a ratio of a reference signal power to a predetermined value a and a user data power of a user U m to a predetermined value when a total transmission power is a fixed value Example jS m, Um said user is any user in the system in a connected state; and said ratio according to the ratio of /, determines the transmission power of a total system energy efficiency to whether the maximum value, if yes, obtaining Calculating the ratio and ratio, otherwise, updating the total transmission power to calculate the ratio a and the ratio β Μ after updating the total transmission power P t , and determining whether the energy efficiency of the system is maximum after the total transmission power P t is updated, if Then, the ratio "sum ratio" calculated after the total transmission power update is obtained.
本发明实施例提供一种功率分配方法, 包括: 获取系统的能效最大时的发 送总功率 Pt、参考信号功率占所述发送总功率 Pt为定值时的比例 a和用户 1^的 用户数据功率占所述发送总功率 为所述定值时的比例 ; 若所述 、 和 的乘积 ? Pt a大于或等于所述参考信号功率的最小值 ^ , 则以所述比例 a和比 例 作为分配所述参考信号功率和所述用户数据功率的比例,所述 ?为所述 转化为最终发送功率的转换效率; 若所述 ?、 Pf和 的乘积 不满足大于 或等于所述参考信号功率的最小值 ^这一条件,则在所述参考信号功率等于所 述/ ^的条件下重新获取发送总功率 为所述定值时所述参考信号功率占所述 定值的比例 a和所述用户 Um的用户数据功率占所述定值的比例 。 An embodiment of the present invention provides a power allocation method, including: acquiring a total transmission power P t when the energy efficiency of the system is maximum, a ratio a when the reference signal power accounts for the fixed total power P t is a fixed value, and a user of the user 1^ The ratio of the data power to the total power of the transmission is the fixed value; if the product of the sum, P t a is greater than or equal to the minimum value of the reference signal power, the ratio a and the ratio are used as the power distribution ratio of the reference signal and the power of the user data, the conversion to the final transmission to the power conversion efficiency;?? if the, P f, and the product does not satisfy the reference signal is greater than or equal to the power a minimum value of this condition, when the reference signal power is equal to the /^ condition, re-acquiring the ratio a of the reference signal power to the fixed value when the total transmission power is the fixed value and the ratio The user data power of the user Um accounts for the ratio of the fixed value.
本发明实施例提供一种功率分配装置, 包括: 比例计算模块, 用于计算发 送总功率 为定值时参考信号功率占所述定值的比例 a和用户 Um的用户数据 功率占所述定值的比例 βΜ , 所述用户 Um是系统内处于连接状态的任一用户; 判断处理模块,用于根据所述比例计算模块计算所得比例《和比例 ,判 断在所述发送总功率 为所述定值时系统的能效是否最大, 若是, 则获取所述 比例 和比例 , 否则更新所述发送总功率 An embodiment of the present invention provides a power distribution apparatus, including: a ratio calculation module, configured to calculate a ratio a of a reference signal power to a predetermined value when a total transmit power is a fixed value, and a user data power of a user U m The ratio of the value β Μ , the user U m is any user in the connected state in the system; the judgment processing module is configured to calculate the ratio “and the ratio according to the ratio calculation module, and determine that the total power of the transmission is Whether the energy efficiency of the system is the largest when the value is stated, and if so, the ratio and ratio are obtained, otherwise the total power of the transmission is updated.
所述比例计算模块还用于计算所述发送总功率/ ^更新后所述比例 和比 例 βΜ ,所述判断处理模块还用于判断所述发送总功率 Pt更新后系统的能效是否 最大, 若是, 则获取所述发送总功率 更新后计算所得比例《和比例 。 The ratio calculation module is further configured to calculate the ratio and the ratio β Μ after the total transmission power/^ update, and the determining processing module is further configured to determine whether the energy efficiency of the system is the largest after the total transmission power P t is updated. If yes, the ratio "sum ratio" calculated after the total transmission power update is obtained.
本发明实施例提供一种基站, 所述基站包括上述功率分配装置。  An embodiment of the present invention provides a base station, where the base station includes the foregoing power distribution device.
本发明实施例提供一种功率分配装置, 包括: 第一获取模块, 用于获取系 统的能效最大时的发送总功率 Pf、 参考信号功率占所述发送总功率 /^为定值时 的比例 a和用户 Um的用户数据功率占所述发送总功率/^为定值时的比例 βΜ; 第二获取模块, 用于若所述 、 和 ?的乘积 大于或等于所述参考 信号功率的最小值 ^, 则以所述比例 和比例 作为分配所述参考信号功率 和所述用户数据功率的比例, 所述 ?为所述 转化为最终发送功率的转换效 率; An embodiment of the present invention provides a power distribution apparatus, including: a first acquiring module, configured to acquire a total transmission power P f when the energy efficiency of the system is maximum, and a ratio of a reference signal power to a total value of the total transmission power/^ a user data power of a and user Um occupies a ratio β Μ when the total transmission power / ^ is a fixed value; a second obtaining module, configured to: if the product of the sum, and ? is greater than or equal to a minimum value of the reference signal power, the proportion and the ratio are used as a ratio of the reference signal power to the user data power , the conversion efficiency of the conversion to the final transmission power;
第三获取模块, 用于若所述 、 和 的乘积 不满足大于或等于所 述参考信号功率的最小值 ^这一条件, 则在所述参考信号功率等于所述 /^的 条件下重新获取发送总功率 为所述定值时所述参考信号功率占所述定值的 比例 a和所述用户 Um的用户数据功率占所述定值的比例 βΜa third obtaining module, configured to: if the product of the sum and the sum does not satisfy a condition that is greater than or equal to a minimum value of the reference signal power, re-acquire and transmit the condition that the reference signal power is equal to the /^ When the total power is the fixed value, the ratio of the reference signal power to the fixed value a and the user data power of the user Um occupy the ratio β Μ of the fixed value.
本发明实施例提供一种基站, 所述基站包括上述功率分配装置。  An embodiment of the present invention provides a base station, where the base station includes the foregoing power distribution device.
从上述本发明实施例可知,本发明实施例从参考信号功率占发送总功率为 某个定值的比例 a和用户数据功率占所述定值的比例 两方面考虑功率分配, 如此, 与现有技术只考虑用户数据功率的分配不同, 兼顾了利用参考信号进行 信道估计的情形,本发明这种联合设计参考信号功率和用户数据功率的方式可 以在优化总功率的基础之上进一步降低系统功耗。 另一方面, 由于本发明实施 例提供的方法是判断在发送总功率 为某个值时系统的能效是否最大,按照系 统的能效最大时求得的比例 a和比例 βΜ分配参考信号功率和用户数据功率,因 此, 本发明从能效最优的角度设计系统发送总功率, 与传统以系统最大发送功 率进行传输的方法相比, 大大降低系统空口的总体能耗, 实现高效节能。 As can be seen from the foregoing embodiments of the present invention, the embodiment of the present invention considers the power allocation from the ratio of the reference signal power to the ratio of the total transmission power to a certain fixed value and the ratio of the user data power to the fixed value. The technology only considers the different allocation of user data power, taking into account the situation of channel estimation using reference signals. The joint design reference signal power and user data power of the present invention can further reduce system power consumption based on optimizing total power. . On the other hand, the method provided by the embodiment of the present invention determines whether the energy efficiency of the system is the largest when the total power is a certain value, and the reference signal power and the user are allocated according to the ratio a and the ratio β obtained when the energy efficiency of the system is maximum. The data power, therefore, the invention transmits the total power from the perspective of optimal energy efficiency, and the overall energy consumption of the system air interface is greatly reduced compared with the traditional method of transmitting the maximum transmission power of the system, thereby achieving high efficiency and energy saving.
附图说明 DRAWINGS
为了更清楚地说明本发明实施例的技术方案,下面将对现有技术或实施例 描述中所需要使用的附图作筒单地介绍,显而易见地, 下面描述中的附图仅仅 是本发明的一些实施例,对于本领域普通技术人员来讲,在不付出创造性劳动 性的前提下, 还可以如这些附图获得其他的附图。  In order to more clearly illustrate the technical solutions of the embodiments of the present invention, the drawings used in the description of the prior art or the embodiments will be briefly described below. Obviously, the drawings in the following description are only the present invention. For some embodiments, other drawings may be obtained as those of ordinary skill in the art without any inventive labor.
图 1是本发明实施例提供的功率分配方法流程示意图;  1 is a schematic flowchart of a power allocation method according to an embodiment of the present invention;
图 2是本发明实施例提供的迭代搜索比例 和比例 方法流程示意图; 图 3是本发明另一实施例提供的功率分配方法流程图;  2 is a schematic flowchart of an iterative search ratio and scale method according to an embodiment of the present invention; FIG. 3 is a flowchart of a power allocation method according to another embodiment of the present invention;
图 4是本发明另一实施例提供的功率分配方法流程图; 图 5是本发明另一实施例提供的功率分配方法流程图; 4 is a flowchart of a power allocation method according to another embodiment of the present invention; FIG. 5 is a flowchart of a power allocation method according to another embodiment of the present invention; FIG.
图 6是本发明实施例提供的一种功率分配装置逻辑结构示意图;  6 is a schematic diagram of a logical structure of a power distribution apparatus according to an embodiment of the present invention;
图 7是本发明另一实施例提供的一种功率分配装置逻辑结构示意图; 图 8是本发明另一实施例提供的一种功率分配装置逻辑结构示意图; 图 9是本发明另一实施例提供的一种功率分配装置逻辑结构示意图; 图 10是本发明另一实施例提供的一种功率分配装置逻辑结构示意图; 图 11是本发明实施例提供的一种基站逻辑结构示意图;  FIG. 7 is a schematic diagram of a logic structure of a power distribution apparatus according to another embodiment of the present invention; FIG. 8 is a schematic diagram of a logic structure of a power distribution apparatus according to another embodiment of the present invention; FIG. 9 is a schematic diagram of another embodiment of the present invention. FIG. 10 is a schematic diagram of a logical structure of a power distribution apparatus according to another embodiment of the present invention; FIG. 11 is a schematic diagram of a logical structure of a base station according to an embodiment of the present invention;
图 12是本发明另一实施例提供的一种功率分配装置逻辑结构示意图; 图 13是本发明另一实施例提供的一种功率分配装置逻辑结构示意图; 图 14是本发明另一实施例提供的一种功率分配装置逻辑结构示意图; 图 15是本发明另一实施例提供的一种功率分配装置逻辑结构示意图; 图 16是本发明另一实施例提供的一种功率分配装置逻辑结构示意图; 图 17是本发明另一实施例提供的一种功率分配装置逻辑结构示意图; 图 18是本发明另一实施例提供的一种功率分配装置逻辑结构示意图; 图 19是本发明另一实施例提供的一种功率分配装置逻辑结构示意图; 图 20是本发明另一实施例提供的一种基站逻辑结构示意图。  FIG. 12 is a schematic diagram of a logical structure of a power distribution apparatus according to another embodiment of the present invention; FIG. 13 is a schematic diagram of a logical structure of a power distribution apparatus according to another embodiment of the present invention; FIG. 15 is a schematic diagram showing the logical structure of a power distribution device according to another embodiment of the present invention; FIG. 16 is a schematic diagram showing the logical structure of a power distribution device according to another embodiment of the present invention; FIG. 17 is a schematic diagram of a logical structure of a power distribution apparatus according to another embodiment of the present invention; FIG. 18 is a schematic diagram of a logical structure of a power distribution apparatus according to another embodiment of the present invention; A schematic diagram of a logical structure of a power distribution device; FIG. 20 is a schematic diagram of a logical structure of a base station according to another embodiment of the present invention.
具体实施方式 detailed description
本发明实施例提供一种功率分配方法、装置和一种基站, 为系统提供最优 能效。  Embodiments of the present invention provide a power allocation method and apparatus, and a base station, which provide optimal energy efficiency for the system.
下面将结合本发明实施例中的附图,对本发明实施例中的技术方案进行清 楚、 完整地描述, 显然, 所描述的实施例仅仅是本发明一部分实施例, 而不是 全部的实施例。基于本发明中的实施例, 本领域普通技术人员在没有做出创造 性劳动前提下所获得的所有其他实施例, 都属于本发明保护的范围。  BRIEF DESCRIPTION OF THE DRAWINGS The technical solutions in the embodiments of the present invention will be described in detail below with reference to the accompanying drawings. All other embodiments obtained by a person of ordinary skill in the art based on the embodiments of the present invention without the creative work are all within the scope of the present invention.
请参阅附图 1 , 是本发明实施例提供的功率分配方法流程示意图, 本方法 可用于各种需要发送信号的设备上, 例如各种通信基站等。本实施例中的方法 主要包括步骤: 1 is a schematic flowchart of a power allocation method according to an embodiment of the present invention. The method can be applied to various devices that need to send signals, such as various communication base stations. Method in this embodiment Mainly includes the steps:
5101 , 计算发送总功率 Pf为定值时参考信号功率占所述定值的比例 a和用 户 U 的用户数据功率占所述定值的比例 βΜ5101. Calculate a ratio β of the reference signal power to the fixed value when the total transmit power P f is a fixed value, and a ratio β Μ of the user data power of the user U to the fixed value.
在本发明实施例中, 发送总功率 ^包括两部分, 即, 用于发送参考信号的 功率 (筒称 "参考信号功率" )和用于传输用户数据的功率 (筒称 "用户数据 功率 ")。 用户 U 是系统内处于连接状态的任一用户。  In the embodiment of the present invention, the total power to be transmitted includes two parts, that is, power for transmitting the reference signal (the cartridge is referred to as "reference signal power") and power for transmitting user data (the cartridge is called "user data power"). . User U is any user in the system that is connected.
由于功率放大器的线性放大区域是有限的,发送总功率总会受最大总功率 的限制, 因此, 作为本发明实施例, 定值可以是发送总功率 的最大发送总功 率, 即, 可以从发送总功率/ ^为最大发送总功率 P。时开始计算参考信号功率占 最大发送总功率 P。的比例 a和用户数据功率占所述最大发送总功率 P。的比例 βΜ , 然后, 可以逐步缩小发送总功率 。 显然, 本发明提供的实施例的限制条 件为: Since the linear amplification area of the power amplifier is limited, the total transmission power is always limited by the maximum total power. Therefore, as an embodiment of the present invention, the fixed value may be the maximum total transmission power of the total transmission power, that is, the total transmission power Power / ^ is the maximum total transmit power P. At the beginning, the reference signal power is calculated to account for the maximum total transmission power P. The ratio a and the user data power account for the maximum transmitted total power P. The ratio β Μ , then, can gradually reduce the total transmitted power. Obviously, the limitations of the embodiments provided by the present invention are:
pt≤p0 o<J<i 限制条件1 0≤ ≤1, m = l,..., M 这里, P。是最大发送总功率, 例如, 取功率放大器的最大值, M是系统内 处于连接态用户的数量。 p t ≤p 0 o<J<i Restriction condition 1 0 ≤ ≤1, m = l,..., M Here, P. Is the maximum total transmit power, for example, taking the maximum value of the power amplifier, and M is the number of connected users in the system.
5102,根据步骤 S101计算所得比例 和比例 ,判断在所述发送总功率/^ 为所述定值时系统的能效是否最大, 若是, 则获取所述比例 和比例 否则 更新所述发送总功率  5102. Calculate the ratio and the ratio calculated according to step S101, and determine whether the energy efficiency of the system is the maximum when the total transmission power/^ is the fixed value. If yes, obtain the ratio and ratio. Otherwise, update the total transmission power.
作为本发明一个实施例,根据所述比例 和比例 ,判断在所述发送总功 率 所述定值时系统的能效是否最大可以是: 根据所述比例 和比例 , 判断 在所述发送总功率 Pt最大时系统的能效是否最大。 As an embodiment of the present invention, according to the ratio and the ratio, determining whether the energy efficiency of the system is maximum when the total value of the total power is transmitted may be: determining, according to the ratio and the ratio, the total power of the transmission P t At the maximum, the system has the highest energy efficiency.
在本发明实施例中, 系统的能效 7定义为单位能量消耗下传输的信息量, 即:In the embodiment of the present invention, the energy efficiency 7 of the system is defined as the amount of information transmitted under unit energy consumption. which is:
Figure imgf000009_0001
Figure imgf000009_0001
pt + pc p t + p c
此处, Pf是系统发送总功率, ^是电路损耗和静态功耗之和, M是系统内 处于连接态用户的数量, Cm是第 m个用户的系统容量; 进一步表示为: Cm =學 g2 (1 + 2Here, P f is the total power transmitted by the system, ^ is the sum of the circuit loss and the static power consumption, M is the number of users in the connected state in the system, and C m is the system capacity of the mth user; further expressed as: C m = learning g2 (1 + 2
am (Lm m + Nma) 此处, Δ/为子载波带宽, Nm是用户 m占用子载波个数, 7为系统发送总 功率 Pt转化为最终发送功率的转换效率, 《为参考信号功率所占发送总功率 Pt 的比例, 是第 m个用户的用户数据功率占发送总功率 /^的比例, 是第 m个 用户的大尺度信道增益, 是第 m个用户的噪声功率, Lm是第 m个用户经历 信道的可分辨多径数目。 a m (L mm + N m a) where Δ/ is the subcarrier bandwidth, N m is the number of subcarriers occupied by the user m, and 7 is the conversion efficiency of the total transmit power P t converted to the final transmit power. The ratio of the reference signal power to the total transmit power P t is the ratio of the user data power of the mth user to the total transmit power/^, which is the large-scale channel gain of the mth user, and is the noise power of the mth user. , L m is the number of resolvable multipaths of the mth user experiencing the channel.
当获取了参考信号功率占最大发送总功率的比例 CC和用户 U™的用户数据 功率占最大发送总功率的比例 βΜ后, 就可以比例 (和比例 βΜ按照分配参考信 号功率和用户数据功率。 When the ratio of the reference signal power to the maximum total transmission power CC and the user data power of the user UTM to the maximum total transmission power β Μ are obtained, the ratio (and the ratio β Μ according to the allocated reference signal power and the user data power) .
S103 ,计算步骤 S102中发送总功率 更新后的比例 和比例 ,判断所述 发送总功率 ^更新后系统的能效是否最大, 若是, 则获取所述发送总功率 ^更 新后计算所得比例 a和比例 βΜS103. Calculate a ratio and a ratio of the total power update after the step S102 is sent, determine whether the energy efficiency of the system after the total transmission power is updated is the largest, and if yes, obtain the ratio a and the ratio β calculated after the total transmission power is updated. Oh .
在本发明实施例中, 计算步骤 S102中发送总功率 Pt更新后的比例 a和比例 ,其方法与计算发送总功率 ^最大时参考信号功率占最大发送总功率的比例 a和用户 U 的用户数据功率占所述最大发送总功率的比例 类似, 不同的仅 仅是计算使用到的参量发送总功率 改变了。 In the embodiment of the present invention, the ratio a and the ratio of the total power P t updated in the step S102 are calculated, and the ratio of the reference signal power to the maximum total transmission power and the user of the user U when calculating the total transmission power ^ maximum is calculated. The ratio of the data power to the maximum total transmission power is similar, and the difference is only that the total power used for the calculation of the used parameters is changed.
作为本发明一个实施例,在判断发送总功率 Pt更新后系统的能效是否最大 时, 可以将发送总功率 更新后系统的能效与更新前系统的能效相比, 判断发 送总功率 ^更新时能效增长率是否达到设定的精度, 若是, 则判断发送总功率 更新后系统的能效达到最大。 例如, 设定精度为 假设发送总功率 更新 前系统的能效是; ^, 发送总功率 更新后系统的能效是 „, 若 i)≤ i 成立, 则判断发送总功率 更新时能效增长率达到设定的精度, 否则, 再次更 新发送总功率 并判断发送总功率 再次更新时能效增长率是否达到所述设 定的精度 flAs an embodiment of the present invention, when determining whether the energy efficiency of the system is maximum after the total transmission power P t is updated, the energy efficiency of the system after the total power is updated may be compared with the energy efficiency of the system before the update, and the total power is updated to determine the energy efficiency when updating. Whether the growth rate reaches the set accuracy, and if so, the total transmission power is judged. The energy efficiency of the system is maximized after the update. For example, the setting accuracy is assumed to be the energy efficiency of the system before the total power is updated; ^, the energy efficiency of the system after the total power update is „, if i) ≤ i is established, then the energy efficiency growth rate of the total power update is determined to be set. The accuracy, otherwise, the total transmission power is updated again and it is judged whether the energy efficiency growth rate at the time when the total transmission power is updated again reaches the set accuracy fl .
从上述本发明实施例可知,本发明实施例从参考信号功率占最大发送总功 率的比例 a和用户数据功率占最大发送总功率的比例 两方面考虑功率分配, 如此, 与现有技术只考虑用户数据功率的分配不同, 兼顾了利用参考信号进行 信道估计的情形,本发明这种联合设计参考信号功率和用户数据功率的方式可 以在优化总功率的基础之上进一步降低系统功耗。 另一方面, 由于本发明实施 例提供的方法是判断在发送总功率 为某个值时系统的能效是否最大,按照系 统的能效最大时求得的比例 a和比例 βΜ分配参考信号功率和用户数据功率,因 此, 本发明从能效最优的角度设计系统发送总功率, 与传统以系统最大发送功 率进行传输的方法相比, 大大降低系统空口的总体能耗, 实现高效节能。 It can be seen from the foregoing embodiments of the present invention that the power allocation is considered in terms of the ratio of the reference signal power to the maximum transmission total power and the ratio of the user data power to the maximum transmission total power, so that only the user is considered in the prior art. The allocation of data power is different, taking into account the situation of channel estimation using reference signals. The joint design of reference signal power and user data power of the present invention can further reduce system power consumption based on optimizing total power. On the other hand, the method provided by the embodiment of the present invention determines whether the energy efficiency of the system is the largest when the total power is a certain value, and the reference signal power and the user are allocated according to the ratio a and the ratio β obtained when the energy efficiency of the system is maximum. The data power, therefore, the invention transmits the total power from the perspective of optimal energy efficiency, and the overall energy consumption of the system air interface is greatly reduced compared with the traditional method of transmitting the maximum transmission power of the system, thereby achieving high efficiency and energy saving.
在本发明一个实施例中,计算发送总功率 最大时参考信号功率占所述最 大发送总功率的比例 a和用户 Um的用户数据功率占所述最大发送总功率的比 例 可以是根据所述最大发送总功率,采用迭代搜索计算发送总功率 Pf最大时 参考信号功率占所述最大发送总功率的比例 a和用户 Um的用户数据功率占所 述最大发送总功率的比例 。 采用迭代搜索计算发送总功率最大时参考信号 功率占所述最大发送总功率的比例 a和用户 1^的用户数据功率占所述最大发 送总功率的比例 βΜ具体包括附图 2示例的步骤: In an embodiment of the present invention, calculating a ratio of a reference signal power to the maximum transmission total power and a ratio of a user data power of the user U m to the maximum transmission total power when the total transmission power is maximum may be according to the maximum The total power is transmitted, and the ratio of the reference signal power to the maximum total transmission power a and the user data power of the user U m to the maximum transmission total power when the total transmission power P f is maximum is calculated by using an iterative search. Iterative search for the maximum total power calculates the transmission power of the reference signal representing the maximum total transmit power of the user 1 ^ A and a proportion of user data representing the maximum transmission power ratio β Μ total power comprises the step of Figure 2 example:
5201 , 将参考信号功率占最大发送总功率的比例 a设定一个初值;  5201, setting the reference signal power to the ratio of the maximum transmitted total power a to set an initial value;
5202, 由最大发送总功率和比例 设定的初值, 获取用户 Um的用户数据 功率占所述最大发送总功率的比例 βΜ; 在本发明实施例中, 的表达式具体为 5202. The initial value set by the maximum transmission total power and the ratio, and the ratio of the user data power of the user Um to the maximum total transmission power is obtained β Μ ; In the embodiment of the present invention, the expression is specifically
-Nmcip mcP0 +2 )+叫 (p aP0 +7 J -^{ρΨηιοΡ0 - ) -N m cip m cP 0 +2 )+ (p aP 0 +7 J -^{ρ Ψηι οΡ 0 - )
其中, Nm为用户 U™占用子载波个数, P。为所述最大发送总功率, p为所 述尸。转化为最终发送功率的转换效率, ^为用户 U™的大尺度信道增益, 为 用户 Um的噪声功率, Lm为用户 Um经历信道的可分辨多径数目, V为拉格朗日 乘子, 满足^;!!^ ,^^)) ^- , 可以利用二分法求取最优 V , M为系统内处 于连接态用/ ¾数量。 Where N m is the number of subcarriers occupied by the user UTM, P. For the maximum transmitted total power, p is the corpse. Converting to the conversion efficiency of the final transmit power, ^ is the large-scale channel gain of the user UTM, the noise power of the user Um, L m is the number of resolvable multipaths that the user Um experiences the channel, and V is the Lagrangian multiplier, Satisfied ^;! ! ^ , ^^)) ^- , can use the dichotomy to find the optimal V, M is the number of connected / 3⁄4 in the system.
S203, 判断比例 设定的初值与获取的 若比例 a设定的初值与获取的 关系满足 < , 则以此 时获取的 βΜ和所述比例 a设定的初值分别作为
Figure imgf000011_0001
户数据功率占 所述最大发送总功率的比例和参考信号功率占所述最大发送总功率的比例,否 则, 更新所述比例 的值(S204), 此处, £3为经验值, 一 - 1(1〜 - 5。 在上述实施例中, 对于比例 的更新, 可按照公式
S203, determining the ratio of the initial value is set when the ratio of a set initial value satisfies the acquired acquired <, places β Μ acquired at this time and the initial value of the ratio, respectively, as a set of
Figure imgf000011_0001
The ratio of the user data power to the maximum transmission total power and the reference signal power to the maximum transmission total power, otherwise, updating the value of the ratio (S204), where £ 3 is the empirical value, one- 1 (1 to - 5. In the above embodiment, for the update of the ratio, according to the formula
Figure imgf000011_0002
Figure imgf000011_0002
更新, 公式中, „为比例 更新后的值, //2为步长。 步长/ /2可以是选定的固 定值或通过某种优化方法, 例如二分法求出的最优步长。 Update, in the formula, „ is the updated value, // 2 is the step size. The step / / 2 can be the selected fixed value or the optimal step size obtained by some optimization method, such as the dichotomy.
由于存在附图 1所示本发明实施例的限制条件, 因此, 附图 1所示本发明实 施例的技术方案的实现过程实际上是 1。 其中, 符号 "max" 表示求取目标函数, 即, 能效函数
Figure imgf000011_0003
的最大值,
Since the limitation of the embodiment of the present invention shown in FIG. 1 exists, the implementation process of the technical solution of the embodiment of the present invention shown in FIG. 1 is actually 1. Where the symbol "max" represents the objective function, ie, the energy function
Figure imgf000011_0003
Maximum value,
"s.t." 下面的项目表示限制条件 1。 Ρ ΡThe item below "st" indicates the constraint 1. Ρ Ρ .
优化问题 1的目标函数(即能效函数 7 )是一个准凸函数, 限制条件 1为线 性约束条件, 因此, 优化问题 1是一个准凸问题。 根据优化理论, 可以容易得 出上述问题存在唯一的最优发送总功率、参考信号功率和用户数据功率占所述 最优发送总功率的比例。  The objective function of optimization problem 1 (ie, energy efficiency function 7) is a quasi-convex function, and constraint 1 is a linear constraint. Therefore, optimization problem 1 is a quasi-convex problem. According to the optimization theory, it is easy to obtain the above problem. There is a unique ratio of the optimal total transmission power, the reference signal power, and the user data power to the optimal total transmission power.
对于优化问题 1的求解, 可以首先求解发送总功率 取一个特殊值时, 即,
Figure imgf000012_0001
For the solution of optimization problem 1, you can first solve for the total power of the transmission when taking a special value, ie
Figure imgf000012_0001
s-t. Pt <P0 St. P t <P 0
M 0<r<l 优化问题 1 M 0<r<l Optimization problem 1
0≤ m≤l, m = l,---, 0 ≤ m ≤ l, m = l, ---,
发送总功率 取最大值 P。时系统的能效是否最大, 若最大, 则以此时取得的 和比例 a分别作为用户 Um的用户数据功率占所述最大发送总功率 P。的比例和 参考信号功率占所述最大发送总功率 P。的比例。 The total transmit power takes the maximum value P. Whether the energy efficiency of the system is the largest, if the maximum, the user data power of the user U m respectively obtained by the sum ratio a obtained at this time accounts for the maximum total transmission power P. The ratio and reference signal power account for the maximum transmitted total power P. proportion.
作为本发明一个实施例,在判断在所述发送总功率 最大时系统的能效是 否最大时, 可以采用下述方法实现:  As an embodiment of the present invention, when determining whether the energy efficiency of the system is maximum when the total transmission power is maximum, the following method may be implemented:
51, 计算能效函数 关于发送总功率 的偏导数^; 51, calculate the energy efficiency function, the partial derivative of the total power transmitted ^;
p  p
能效函数 7即 1 m g ol{L m+Nma) 此处, Δ/为子载波带宽, Nm The energy efficiency function 7 is 1 mg ol{L m+ N m a) where Δ/ is the subcarrier bandwidth, N m
Pt+Pc P t +P c
为用户 U 占用子载波个数, /^为电路损耗和静态功耗之和, ?为所述 转化 为最终发送功率的转换效率, ^为用户 U 的大尺度信道增益, 为用户 Um 的噪声功率, Lm为用户 U 经历信道的可分辨多径数目, M是系统内处于连接 态用户的数量。 For user U, the number of subcarriers is occupied, /^ is the sum of circuit loss and static power consumption, ? is the conversion efficiency of the conversion to final transmission power, ^ is the large-scale channel gain of user U, and the noise power of user Um , L m is the number of resolvable multipaths that the user U experiences the channel, and M is the number of users in the system that are connected.
需要说明的是, 由于 ^为用户 U 的大尺度信道增益, 因此, 与现有技术 基于小尺度信道信息(即时间尺度变化很快的信道信息, 例如, 瞬时信道信息 等 )的功率分配算法相比, 本发明根据信道大尺度信道信息(即在较长时间内 不变的信道信息, 例如路径损耗、 阴影衰落和大尺度信道增益等)进行功率分 配, 本发明实施例提供的功率分配方法所需信道信息反馈量小, 反馈频率低。 , 若偏导数 ^在所述发送总功率/ ^为最大发送总功率 P。时的值, 即, 大于或等于 0, 则判断在所述发送总功率 最大时系统的能效最大。
Figure imgf000012_0002
It should be noted that since ^ is the large-scale channel gain of the user U, the power allocation algorithm based on the prior art based on small-scale channel information (that is, channel information with fast time-scale changes, for example, instantaneous channel information, etc.) The power distribution method according to the embodiment of the present invention is provided by the present invention, according to the channel large-scale channel information (that is, the channel information that is invariant for a long time, such as path loss, shadow fading, and large-scale channel gain, etc.). The amount of channel information required is small, and the feedback frequency is low. If the partial derivative ^ is at the total transmission power / ^ is the maximum transmission total power P. The value of time, that is, greater than or equal to 0, determines that the system has the highest energy efficiency when the total transmission power is maximum.
Figure imgf000012_0002
本实施例中,上述判断在发送总功率/^最大时系统的能效是否最大的原理 在于: ≥0, 表明能效函数7是关于发送总功率 Pf的增函数, 其物理意义是 dPt In this embodiment, the foregoing determines the principle of whether the energy efficiency of the system is maximum when the total power/^ maximum is transmitted. 在于: ≥ 0, indicating that the energy efficiency function 7 is an increasing function with respect to the total power of transmission P f , and its physical meaning is dP t
系统能效随着 Pf增大而提高, 因此, 当 取到其最大值 P。时, 此时系统的能 效 7显然是最大。 The system energy efficiency increases as P f increases, so when it reaches its maximum value P. At this time, the energy efficiency 7 of the system is obviously the largest.
请参阅附图 3, 是本发明另一实施例提供的功率分配方法流程图, 可以作 为对附图 1示例提供的功率分配方法的补充说明, 主要包括步骤:  Referring to FIG. 3, it is a flowchart of a power allocation method according to another embodiment of the present invention. It can be used as a supplementary description of the power allocation method provided in the example of FIG.
5301, 设定最大发送功率;  5301, setting a maximum transmit power;
例如, 将发送功率/ ^设定最大值 P。, 可以是功率放大器的最大值。  For example, set the transmit power / ^ to the maximum value P. , can be the maximum value of the power amplifier.
5302, 迭代搜索确定比例 和比例 ;  5302, iterative search determines the proportion and proportion;
可以采用附图 2示例的迭代算法, 根据 Δ/, Nm, ρ, ψΜ , am 2 , Lm, 等, 求取参考信号功率占最大发送总功率 P。的比例《和用户数据功率占所述最大 发送总功率 P。的比例 。 Δ/, Nm , ρ , ψη , σ , Lm, Ρε的含义与前述实施 例中 Δ/, N , ρ, ψ , σ , L , 的含义相同, 不做赞 The iterative algorithm exemplified in FIG. 2 can be used to calculate the reference signal power as the maximum total transmission power P according to Δ/, N m , ρ, ψ Μ , a m 2 , L m , and the like. The ratio "and user data power accounts for the maximum transmitted total power P. proportion. Δ /, N m , ρ , ψ η , σ , L m , Ρ ε have the same meanings as Δ /, N , ρ, ψ , σ , L , in the previous examples, do not like
下:  Next:
305;
Figure imgf000013_0001
305;
Figure imgf000013_0001
S305, 更新发送总功率 ^ 即, 将发送总功率 按照表达式 Pn = Pn_x + μλ
Figure imgf000013_0002
更新, 其中, Ρ„为第 dPt
S305, updating the total transmit power ^, that is, sending the total power according to the expression P n = P n _ x + μ λ
Figure imgf000013_0002
Update, where Ρ„ is the dP t
w次迭代时的发送总功率, A为迭代步长, 该步长可以设定为固定值, 或设定 为通过某种优化算法(例如, 二分法)找到的最优值。 The total transmit power at w iterations, A is the iteration step size, which can be set to a fixed value, or set to the optimal value found by some optimization algorithm (for example, dichotomy).
S306, 迭代搜索确定比例 和比例 ;  S306, iteratively searching to determine the proportion and proportion;
方法与 S302类似, 即, 可以采用附图 2示例的迭代算法。 区别在于, 此时 的发送总功率 由最大值 P。改变为其他值。  The method is similar to S302, that is, the iterative algorithm illustrated in Fig. 2 can be employed. The difference is that the total transmitted power at this time is the maximum value P. Change to a different value.
S307, 计算能效函数;7„以及/7„关于发送总功率的偏导数。 偏导数 的表达式与本实施例 S303中偏导数的表达式相同。 S307, calculating the energy efficiency function; 7„ and /7„ the partial derivative of the total power transmitted. The expression of the partial derivative is the same as the expression of the partial derivative in the embodiment S303.
S308 , 判断此次迭代得到的能效; ;„与上次迭代得到的能效; 7„— i相比的能效 增长率是否达到设定的精度。  S308, judging the energy efficiency obtained by the iteration; „the energy efficiency obtained from the last iteration; the energy efficiency growth rate compared with 7„-i reaches the set precision.
例如, 设定精度为 fl (一般可设定为 10-1 ~ 10-5 ), 假设发送总功率/ ^更新 前(即第 w - l次迭代时的发送总功率/^ ) 系统的能效是;;^ , 发送总功率 更 新后 (即第 w次迭代时的发送总功率 ) 系统的能效是;;„, 若 n ) ^ , 则判断此次迭代得到的能效; ;„与上次迭代得到的能效; 7„— i相比, 能 增长率达 到设定的精度。 For example, the setting accuracy is fl (generally set to 10 - 1 ~ 10- 5 ), assuming that the total power is transmitted / ^ before the update (that is, the total transmitted power at the w - l iterations / ^) ;;^ , after the total power is sent (ie, the total power transmitted at the wth iteration), the energy efficiency of the system is;; „, if n ) ^ , the energy efficiency obtained by this iteration is judged; Energy efficiency; 7„-i, the growth rate can reach the set accuracy.
进一步地, 还可以判断发送总功率 更新时(即由第 w -1次迭代时的发送 总 能效增长速度是否达到设定 的 f2—般可设定为 10- 1(1 ~ 10- 精度, 否则返回步骤 S305 (
Figure imgf000014_0001
Further, it can also be determined that when the total transmission power is updated (that is, whether the total energy efficiency growth rate at the w-1th iteration reaches the set f 2 can be set to 10 - 1 (1 ~ 10- precision, Otherwise return to step S305 (
Figure imgf000014_0001
需要说明的是, 在上述本发明实施例中, 只要求解到比例 和比例 , 即 可按照这个比例分配参考信号功率和用户数据功率。 以下的实施例相同, 不再 另外做说明。  It should be noted that, in the above embodiment of the present invention, the reference signal power and the user data power can be allocated according to the ratio as long as the ratio and the ratio are solved. The following embodiments are the same and will not be described again.
在实际通信系统中, 参考信号除了用于进行信道估计还会有其他用途, 例 如, 保证一定的小区覆盖。 因此, 参考信号功率的取值要高于某个门限值, 即 paPt≥ Ρα , 其中, ^为参考信号功率的最小值, ρ、 和 的含义与前述实施 例相同。 这就是说, 在增加了限制条件 7 ≥4时, 优化问题 1转化为以下的 优化问题 2: In an actual communication system, the reference signal may have other uses besides being used for channel estimation, for example, to ensure a certain cell coverage. Therefore, the reference signal power takes a value higher than a certain threshold, that is, paP t ≥ Ρ α , where ^ is the minimum value of the reference signal power, and the meanings of ρ, and are the same as in the previous embodiment. That is to say, when the constraint 7 ≥ 4 is added, the optimization problem 1 is converted into the following optimization problem 2:
其中, 符号 "max" 表示求取目标函数, 即, 能效函数 1 m g ol{L m + Nmay 的最大值, "s.t. " 下面的项目表示限制条 件。 ^ Wherein the symbol "max" represents the objective function, that is, the maximum value of the energy function 1 mg ol{L m + N m ay , and the items below "st " indicate the constraint. ^
优化问题 2的求解过程如附图 4所示本发明实施例提供的功率分配方法^ ∑ m log 2 (1 + " Hm ' ) The solution process of the optimization problem 2 is as shown in FIG. 4, and the power distribution method provided by the embodiment of the present invention is provided. ∑ m log 2 (1 + " Hm ' )
om (L + Nm ) o m (L + N m )
max  Max
Pt + Pc P t + P c
s-t. Pt≤P0 St. P t ≤P 0
p Pt≥ Pa p P t ≥ P a
M  M
"+∑ = i  "+∑ = i
m=\  m=\
.优化问题 2 .Optimization problem 2
0 < α≤1 0 < α≤1
0≤βη≤1, m = l,..., 程示意图, 主要包括步骤: 0≤β η ≤1, m = l,..., schematic diagram, mainly including steps:
S401 , 获取系统的能效最大时的发送总功率 、 参考信号功率占所述发送 总功率为定值时的比例 a和用户 Um的用户数据功率占所述发送总功率 为所 述定值时的比例 。 S401, obtaining the total system energy efficiency of the transmission power at the maximum, the reference signal representing the transmission power ratio when the total power of a predetermined value and the user data of the user U m representing the transmission power of the predetermined total power value when proportion.
在本发明一个实施例中, 所述定值为所述发送总功率 的最大发送总功 率, 此时, 获取系统的能效最大时的发送总功率 pf、 参考信号功率占所述发送 总功率为定值时的比例 a和用户 Um的用户数据功率占所述发送总功率为所述 定值时的比例 为: 获取系统的能效最大时的发送总功率 、参考信号功率占 所述最大发送总功率的比例 a和用户 Um的用户数据功率占所述最大发送总功 率的比例 。 In an embodiment of the present invention, the value is the maximum total transmission power of the total transmission power. At this time, the total transmission power p f and the reference signal power of the system when the energy efficiency of the system is maximized are The proportion of the ratio a and the user data of the user U m when the total transmission power is the fixed value is: the total transmission power when the energy efficiency of the system is maximized, and the reference signal power accounts for the maximum transmission total. The ratio of the power a and the user data power of the user U m account for the ratio of the maximum transmitted total power.
求解优化问题 2的基本思路是首先求解优化问题 1得到^ a、 { } =1 (符 号 " U "表示第 1个用户至第 M个用户的用户数据功率占最大发送总功率的 比例), 即包括如下步骤: The basic idea of solving the optimization problem 2 is to first solve the optimization problem 1 to get ^ a, { } =1 (the symbol " U " indicates the ratio of the user data power of the first user to the Mth user to the maximum total transmission power), ie Including the following steps:
S4011 , 计算发送总功率/ ^最大时参考信号功率占所述最大发送总功率的 比例 a和用户 Um的用户数据功率占所述最大发送总功率的比例 , 所述用户 Um是系统内处于连接状态的任一用户; S4011, calculation of the total power transmission / ^ maximum reference signal power the maximum proportion of the total transmission power of a user and the user data U m representing the maximum transmission power ratio of the total power of the user within the system is U m Any user of the connection status;
54012, 根据所述比例 和比例 , 判断在所述发送总功率/ ^最大时系统 的能效是否最大, 若是, 则获取所述比例《和比例 , 否则更新所述发送总功 率/^  54012. Determine, according to the ratio and the ratio, whether the energy efficiency of the system is the largest when the total power of transmission/maximum is maximum, and if yes, obtain the ratio “sum ratio, otherwise update the total power of the transmission/^
54013 , 计算所述发送总功率 /^更新后所述比例 和比例 , 判断所述发 送总功率 更新后系统的能效是否最大, 若是, 则获取所述发送总功率 更新 后计算所得比例 a和比例 βΜ54013, calculating the ratio and ratio after the total transmission power/^ is updated, and determining the After updating the total power transmission system if the maximum energy efficiency, if yes, obtaining the resulting transmission ratio and a ratio of the total power update computation β Μ.
关于优化问题 1的求解, 其更为详细的步骤可参阅前述实施例。  Regarding the solution of the optimization problem 1, the more detailed steps can be referred to the foregoing embodiment.
S402 , 若 ?与步骤 S401求得的 Pt和 a的乘积 大于或等于参考信号功 率的最小值 则以所述比例 和比例 作为分配所述参考信号功率和所述 用户数据功率的比例。 S402. If the product of Pt and a obtained in step S401 is greater than or equal to a minimum value of the reference signal power, the ratio and the ratio are used as a ratio of the reference signal power and the user data power.
在本实施例中, ?为/^转化为最终发送功率的转换效率。 如果 /^成 立, 说明此时的发送总功率和功率比例也是优化问题 2的最优解, 求解过程结 束。  In the present embodiment, ? is converted to the conversion efficiency of the final transmission power. If /^ is established, the total transmit power and power ratio at this time is also the optimal solution for optimization problem 2, and the solution process ends.
S403 , 若所述 ?、 和 的乘积 不满足大于或等于所述参考信号功 率的最小值/ ^这一条件, 则在所述参考信号功率等于所述/ ^的条件下重新获 取发送总功率 为所述定值时所述参考信号功率占所述定值的比例《和所述 用户 Um的用户数据功率占所述定值的比例 βΜS403. If the product of the sum and the sum does not satisfy the condition that the value of the reference signal power is greater than or equal to ^, the total transmit power is reacquired under the condition that the reference signal power is equal to the /^. The ratio of the reference signal power to the fixed value when the value is fixed "the ratio of the user data power of the user U m to the fixed value β Μ .
在定值为所述发送总功率 的最大发送总功率的实施例中, 所述若所述 p、 和 的乘积 ? 不满足大于或等于所述参考信号功率的最小值/ ^这一 条件,则在所述参考信号功率等于所述 的条件下重新获取发送总功率 所述 定值时所述参考信号功率占所述定值的比例 和所述用户 Um的用户数据功率 占所述定值的比例 为: 若所述 ?、 Pf和 的乘积 不满足大于或等于所 述参考信号功率的最小值 ^这一条件, 则在所述参考信号功率等于所述 /^的 条件下重新获取发送总功率 最大时所述参考信号功率占所述最大发送总功 率的比例 a和所述用户 Um的用户数据功率占所述最大发送总功率的比例 βΜIn an embodiment of the maximum transmit total power of the total transmit power, if the product of the p and the sum does not satisfy a condition that is greater than or equal to a minimum value of the reference signal power / ^, then Ratio of the reference signal power to the fixed value and the ratio of the user data power of the user Um to the fixed value when the fixed value of the total power is re-acquired under the condition that the reference signal power is equal to the condition is:? if the, P f, and the product does not meet the minimum value is greater than or equal to the reference signal power ^ this condition, the total transmit power to reacquire the reference signal at a power equal to said / ^ of The ratio of the reference signal power to the maximum transmission total power and the ratio of the user data power of the user Um to the maximum transmission total power β Μ .
如果 c^≥ /^不成立, 则求解如下优化问题 3: 为求解优化问题 3 , 可以将变量进行替换, 即, 由关系式 = Ρ。- / ?和 Ym = β„Ά Ι(Ά - Ρα ' Ρ)替换出^ = (l + 4 / ΡβΡ)。
Figure imgf000017_0001
If c^≥ /^ does not hold, solve the following optimization problem 3: To solve the optimization problem 3, the variable can be replaced, ie, by the relation = Ρ. - / ? and Y m = β„Ά Ι(Ά - Ρα ' Ρ) Replace ^ = (l + 4 / Ρ β Ρ).
Figure imgf000017_0001
s.t. Pt≤ P0 St P t ≤ P 0
p Pt = Pa .优化问题 3 m=l p P t = P a . Optimization problem 3 m=l
0< ≤l 0< ≤l
≤βΜ≤1, m = l,...,M ≤β Μ ≤1, m = l,...,M
优化问题 3转化如下为优化问题 4:  Optimization problem 3 is transformed as an optimization question 4:
Figure imgf000017_0002
Figure imgf000017_0002
s.t. Ρβ≤Ρ0αΙρ St Ρ β ≤Ρ 0α Ιρ
Μ .优化问题 4 Μ .Optimization problem 4
∑rm = i ∑r m = i
m=l  m=l
Q≤Ym <\, m = l,...,M 其中, ^表示用于多个用户的用户数据功率之和, 表示用户 U 的用户 数据功率与/ ^的比值。 由于 = Ρ。- /?, 因此, 若发送总功率/ ^最大(为 Ρ。), 则也 最大。 这就是说, 优化问题 4的求解实际上等效于在参考信号功率等于 ^的条件下重新获取发送总功率 ^最大时参考信号功率占所述最大发送总功 率的比例 a和用户 Um的用户数据功率占所述最大发送总功率的比例 βΜ , 包括 步骤 Q ≤ Y m <\, m = l, ..., M where ^ represents the sum of the user data powers for a plurality of users, and represents the ratio of the user data power of the user U to /^. Thanks = Ρ. - /?, Therefore, if the total power / ^ maximum (which is Ρ.) is sent, it is also the largest. That is to say, the solution of the optimization problem 4 is actually equivalent to re-acquiring the ratio of the reference signal power to the maximum transmission total power a and the user U m when the reference signal power is equal to ^. The ratio of data power to the maximum transmitted total power β Μ , including steps
S4031 ,计算多个用户的用户数据功率之和 Ρβ最大时用户 Um的用户数据功 率占 的比例 ym , ^最大为 Ρ-ΡαΙρ , Ρ。为最大发送总功率; S4031, calculating the sum of the user data powers of the plurality of users Ρ β is the ratio y m of the user data power of the user Um when max is maximal, and the maximum is Ρ-Ρ α Ιρ , Ρ. Send the total power for maximum;
即, 由关系式 = Ρ。- /?和^ =^P。/CP。- 替换出
Figure imgf000017_0003
That is, by the relation = Ρ. - /? And ^ =^P. /CP. - Replace it
Figure imgf000017_0003
根据系统的能效最大时获取的用户 Um的用户数据功率占所述最大发送总功率 的比 , 计算出: According to the ratio of the user data power of the user U m obtained when the energy efficiency of the system is maximum to the maximum total transmission power, the following is calculated:
ΎπιΎπι
Figure imgf000017_0004
S4032, 根据比例步骤 S4031求取的比例 , 判断在多个用户的用户数据 功率之和/ ^最大时系统的能效是否最大, 若是, 则根据所述比例^求取所述 比例 和比例 , 否则, 更新所述/^并判断所述/ ^更新后系统的能效是否最 大。
Figure imgf000017_0004
S4032: determining, according to the ratio obtained by the proportional step S4031, whether the energy efficiency of the system is the largest when the sum of the user data powers of the plurality of users is greater than ^, and if so, determining the ratio and the proportion according to the ratio ^, otherwise, Update the /^ and determine whether the energy efficiency of the system after the /^ update is the largest.
本实施例中,判断在多个用户的用户数据功率之和 ρβ最大时系统的能效是 否最大与前述本发明实施例中判断在发送总功率 最大时系统的能效是否最 大类似, 包括步骤: In this embodiment, it is determined whether the energy efficiency of the system is the largest when the sum of the user data powers ρ β of the plurality of users is the largest. In the foregoing embodiment of the present invention, it is determined whether the energy efficiency of the system is the maximum when the total transmission power is maximum, and the steps include:
S40321 , 计算能效函数 关于/ ^的偏导数; 能效函数 7为 ,其中, Δ /为子载波带宽,  S40321, calculating the energy efficiency function with respect to the partial derivative of / ^; the energy efficiency function 7 is , where Δ / is the subcarrier bandwidth,
Nm为用户 Um占用
Figure imgf000018_0001
功耗之和, 为用户 um 的大尺度信道增益, 为用户1^的噪声功率, LM为用户 Um经历信道的可分辨 多径数目, M是系统内处于连接态用户的数量。
N m is occupied by the user U m
Figure imgf000018_0001
The sum of power consumption is the large-scale channel gain of the user u m , the noise power of the user 1 , L M is the number of resolvable multipaths that the user U m experiences the channel, and M is the number of users in the system in the connected state.
7关于 的偏导数为:
Figure imgf000018_0002
The partial derivative of 7 is:
Figure imgf000018_0002
S40321 , 若所述偏导数在所述多个用户的用户数据功率之和 Ρρ最大时的 值大于或等于 0, 则判断在所述多个用户的用户数据功率之和/^最大时系统的 能效最大。 S40321, if the partial derivatives of the plurality of users in a user data value and the maximum powers of Ρ ρ is greater than or equal to 0, it is determined that the power of the user data and the plurality of users / ^ maximum system The most energy efficient.
本实施例中,上述判断在多个用户的用户数据功率之和 Ρβ最大时系统的能 效是否最大的原理在于: ≥0表明能效函数7是关于 的增函数, 其物理 意义是系统能效随着 增大 提高, 因此, 当/^取到其最大值 时, 此 时系统的能效 7显然是最大。 In this embodiment, the principle of determining whether the energy efficiency of the system is maximum when the sum of the user data powers of the plurality of users is the maximum 在于β is: ≥ 0 indicates that the energy efficiency function 7 is an increasing function, and the physical meaning is that the system energy efficiency is The increase is increased, so when the maximum value is taken, the energy efficiency 7 of the system is obviously the largest.
在本实施例中, 判断/ ^更新后系统的能效是否最大包括: 判断 更新时 能效增长率是否达到设定的精度,若是,则判断 更新更新后系统的能效达到 最大。 例如, 设定精度为 f4 , 假设 更新前系统的能效是;^, 更新后系统 的能效是; 7„,若 (d )≤ 4 ,则判断 更新时系统的能效增长率达到设定的 精度, 否则, 再次 ¾f所述/ ^并判断所述 再次更新时能效增长率是否达到 所述设定的精度。 In this embodiment, determining whether the energy efficiency of the system after maximizing / ^ is updated includes: determining whether the energy efficiency growth rate at the time of updating reaches the set accuracy, and if so, determining that the energy efficiency of the system after the update is updated The biggest. For example, the setting accuracy is f 4 , assuming that the energy efficiency of the system before the update is; ^, the energy efficiency of the system after updating is 7;, if ( d) ≤ 4 , it is judged that the energy efficiency growth rate of the system reaches the set accuracy when updating. Otherwise, it is again / / and judges whether the energy efficiency growth rate at the time of the update is up to the set accuracy.
数据功率之和 /^的方法可以是: 将所 述/ ^ 其中, ρ„为/^更新后的值, ρ„— i为所 述 ^
Figure imgf000019_0001
The method of summing the data powers may be: placing the /^ where ρ is the updated value of /^, ρ„-i is the ^
Figure imgf000019_0001
在判断所述 更新时能效增长率是否达到设定的精度之后还包括: 判断所  After determining whether the energy-efficiency growth rate at the time of the update reaches the set accuracy, the method further includes:
Figure imgf000019_0002
Figure imgf000019_0002
精度, 其中, £5为算法精度, 可根据精度要求进行设置, 一般可设置为 10- 5 ~Accuracy, where £ 5 is the accuracy of the algorithm and can be set according to the accuracy requirements. Generally, it can be set to 10- 5 ~
10- 1010- 10 .
请参阅附图 5 , 是本发明另一实施例提供的功率分配方法流程图, 将/^和 { }:=1进行迭代优化, 可以作为对附图 4示例提供的功率分配方法的补充说明, 主要包括步骤: Referring to FIG. 5, which is a flowchart of a power allocation method according to another embodiment of the present invention, iteratively optimizing /^ and { }: =1 can be used as a supplementary explanation for the power allocation method provided in the example of FIG. Mainly includes the steps:
5501 , 将/^设定为最大值  5501, set /^ to the maximum value
Ρβ、 Ρ0、 /^和 的含义分别与附图 4示例的 、 Ρ0、 /^和 ?的含义相同。The meanings of Ρ β , Ρ 0 , /^ and are the same as those of Ρ 0 , /^ and ? as exemplified in Fig. 4, respectively.
5502 , 求取 d ; 5502, seeking d;
irJL中,符号 " { iti "表示第 1个用户至第 M个用户的用户数据功率占 ρβ 的比例。 可以根据 Δ/、 Nm、 p、 y/m、 σ 、 Lm、 Pc、 ^以及求解优化问题 1时得 到的
Figure imgf000019_0003
其中, v为拉格朗日乘子, V满足 max(0,y„»)=l , 可利用二分法求得最
In irJL, the symbol "{ iti " indicates the ratio of the user data power of the first user to the Mth user to ρ β . Can be obtained according to Δ/, N m , p, y/ m , σ , L m , P c , ^ and solving the optimization problem 1
Figure imgf000019_0003
Where v is the Lagrangian multiplier and V satisfies m ax (0, y„») = l, which can be obtained by the dichotomy
, 否则
Figure imgf000020_0001
, 进入步骤
Otherwise
Figure imgf000020_0001
, enter the step
Figure imgf000020_0002
Figure imgf000020_0002
长。 long.
5506, 计算 ^更新后的比例 ;  5506, calculating the proportion of the updated ^;
根据 Δ/ , Nm , p , ¥m , am 2 , Lm, Pc, ^等系统输入量和更新后的/ V 计算 ^更新后的比例 γΜ , 方法与附图 4示例的步骤 S4031计算多个用户的用户 数据功率之和 Ρβ最大时用户 Um的用户数据功率占 Ρβ的比例 ym类似。区别在于, 此时的多个用户的用户数据功率之和 ρβ由最大值 Ρ0αίρ改变为其他值。 According to Δ / , N m , p , ¥ m , a m 2 , L m , P c , ^ and other system inputs and the updated / V calculation ^ updated ratio γ Μ , the method and the steps illustrated in Figure 4 S4031 calculates the sum of the user data powers of the plurality of users Ρ β is the maximum when the user data power of the user U m is proportional to the ratio y m of Ρ β . The difference is that the sum ρ β of the user data powers of a plurality of users at this time is changed from the maximum value Ρ 0 - Ρ α ίρ to other values.
5507, 计算能效函数 及其关于 的偏导数;  5507, calculating the energy efficiency function and its partial derivatives;
关于 ^的偏导数。 Δ /为子载波带宽,  The partial derivative of ^. Δ / is the subcarrier bandwidth,
Nm
Figure imgf000020_0003
和, ^为用户 um 的大尺度信道增益, 为用户 U™的噪声功率, Lm为用户 U™经历信道的可分辨 多径数目, M是系统内处于连接态用户的数量。
N m
Figure imgf000020_0003
And, ^ is the large-scale channel gain of the user u m , the noise power of the user UTM, L m is the number of resolvable multipaths that the user UTM experiences the channel, and M is the number of users in the system that are connected.
7关于 的偏导数为:
Figure imgf000021_0001
The partial derivative of 7 is:
Figure imgf000021_0001
{Pp+Pc +P pf '{P p +P c +P pf '
S508 , 判断此次迭代得到的能效; ;„与上次迭代得到的能效; 7„— i相比的能效 增长率是否达到设定的精度。 S508, judging the energy efficiency obtained by the iteration; „the energy efficiency obtained from the last iteration; the energy efficiency growth rate compared with 7„-i reaches the set precision.
例如, 设定精度为 £4 (一般可设定为 10- 5 - 10"10 ), 假设多个用户的用户数 据功率之和/ ^更新前(即第 w -l次迭代时的发送总功率/^ )系统的能效是;^, 多个用户的用户数据功率之和 ^更新后(即第 W次迭代时的发送总功率 )系 统的能效是; 若 ("U ≤ε4 , 则判断此次迭代得到的能效 与上次迭代得
Figure imgf000021_0002
For example, the setting accuracy is £ 4 (generally set to 10 - 5 - 10" 10 ), assuming the sum of the user data powers of multiple users / ^ before the update (ie the total transmit power at the w -1 iterations) /^) The energy efficiency of the system is; ^, the sum of the user data powers of multiple users ^ after updating (ie, the total power transmitted at the Wth iteration), the energy efficiency of the system is; if ("U ≤ ε 4 , then judge this The energy efficiency obtained from the next iteration and the last iteration
Figure imgf000021_0002
到的能效 相比, 能效增长率达到设定的精度。 Compared to the energy efficiency, the energy efficiency growth rate reaches the set accuracy.
进一步地, 还可以判断多个用户的用户数据功率之和 更新时 (即由第 w -l次迭代时的 d 更新为第/ί次迭代时的 P„ ) 能效增长速度是否达到设定 的精度。例如,可以判断 < £·5 是否成立, £5—般可设定为 10- 1(1 ~ 10- 5Furthermore, when a plurality of users can also determine the powers of the user data and update (i.e., a d w -l updated first iteration of P "when the first / ί iterations) the growth rate of the energy efficiency reaches a set precision For example, based on <£ · 5 is established, £ 5 - generally may be set to 10-1 (1 ~ 10-5.
Figure imgf000021_0003
Figure imgf000021_0003
若成立, 则结束, 否则返回步骤 S505。 需要说明的是, 在上述本发明实施例中, 只要求解到比例 和比例 , 即 可按照这个比例分配参考信号功率和用户数据功率。 If it is true, it ends, otherwise it returns to step S505. It should be noted that, in the above embodiment of the present invention, the reference signal power and the user data power can be allocated according to the ratio as long as the ratio and the ratio are solved.
从上述本发明实施例可知,本发明实施例从参考信号功率占最大发送总功 率的比例 a和用户数据功率占最大发送总功率的比例 两方面考虑功率分配, 如此, 与现有技术只考虑用户数据功率的分配不同, 兼顾了利用参考信号进行 信道估计的情形,本发明这种联合设计参考信号功率和用户数据功率的方式可 以在优化总功率的基础之上进一步降低系统功耗。 另一方面, 由于本发明实施 例提供的方法是判断在发送总功率 为某个值时系统的能效是否最大,按照系 统的能效最大时求得的比例 a和比例 βΜ分配参考信号功率和用户数据功率,因 此,本发明从能效最优的角度设计系统发送总功率以及在此基础上保证一定的 小区覆盖, 与传统以系统最大发送功率进行传输的方法相比, 大大降低系统空 口的总体能耗, 实现高效节能。 It can be seen from the foregoing embodiments of the present invention that the power allocation is considered in terms of the ratio of the reference signal power to the maximum transmission total power and the ratio of the user data power to the maximum transmission total power, so that only the user is considered in the prior art. The allocation of data power is different, taking into account the situation of channel estimation using reference signals. The joint design of reference signal power and user data power of the present invention can further reduce system power consumption based on optimizing total power. On the other hand, the method provided by the embodiment of the present invention determines whether the energy efficiency of the system is the largest when the total power is a certain value, and the reference signal power and the user are allocated according to the ratio a and the ratio β obtained when the energy efficiency of the system is maximum. Data power, therefore, the present invention designs the system to transmit the total power from the perspective of optimal energy efficiency and guarantees a certain basis on this basis. Compared with the traditional method of transmitting the maximum transmit power of the system, the cell coverage greatly reduces the overall energy consumption of the system air interface and achieves high efficiency and energy saving.
进一步, 本发明实施例还给出了实施上述方法的功率分配装置, 该功率分 配装置用于执行上述方法实施例中的方法。 请参阅附图 6, 是本发明实施例提 供的一种功率分配装置逻辑结构示意图。 为了便于说明,仅仅示出了与本发明 实施例相关的部分。 附图 6示例的功率分配装置包含的功能模块 /单元可以是软 件模块 /单元、硬件模块 /单元或软硬件相结合模块 /单元,包括比例计算模块 601 和判断处理模块 602, 其中:  Further, the embodiment of the present invention further provides a power distribution device for implementing the above method, and the power distribution device is configured to perform the method in the foregoing method embodiment. Referring to FIG. 6, FIG. 6 is a schematic diagram showing the logical structure of a power distribution device according to an embodiment of the present invention. For the convenience of description, only the parts related to the embodiment of the present invention are shown. The function module/unit included in the power distribution device of the example of Fig. 6 may be a software module/unit, a hardware module/unit or a combination of hardware and software modules/units, including a proportional calculation module 601 and a judgment processing module 602, where:
比例计算模块 601 , 用于计算发送总功率 为定值时参考信号功率占所述 定值的比例 a和用户 Um的用户数据功率占所述定值的比例 , 所述用户 Um是 系统内处于连接状态的任一用户;  The ratio calculation module 601 is configured to calculate a ratio of a reference signal power to the fixed value when the total transmission power is a fixed value, and a ratio of a user data power of the user Um to the fixed value, where the user Um is connected in the system. Any user of the status;
判断处理模块 602,用于根据所述比例计算模块 601计算所得比例 a和比例 βΜ , 判断在所述发送总功率 为所述定值时系统的能效是否最大, 若是, 则获 取所述比例 a和比例 pm , 否则更新所述发送总功率 PtThe determining processing module 602 is configured to calculate, according to the ratio a and the ratio β Μ calculated by the ratio calculating module 601, whether the energy efficiency of the system is maximum when the total transmitting power is the fixed value, and if yes, obtain the ratio a And the ratio p m , otherwise updating the total transmission power P t ;
所述比例计算模块 601还用于计算所述发送总功率 /^更新后所述比例 和 比例 , 所述判断处理模块 602还用于判断所述发送总功率 Pt更新后系统的能 效是否最大,若是,则获取所述发送总功率 更新后计算所得比例 "和比例 。 The ratio calculation module 601 is further configured to calculate the ratio and the ratio of the total transmission power/update, and the determining processing module 602 is further configured to determine whether the energy efficiency of the system is the largest after the total transmission power P t is updated. If yes, the ratio "and ratio" calculated after the total transmission power update is obtained.
在本发明一个实施例中, 所述定值为所述发送总功率 的最大发送总功 率, 此时所述比例计算模块 601用于计算发送总功率 最大时参考信号功率占 所述最大发送总功率的比例 a和用户 Um的用户数据功率占所述最大发送总功 率的比例 βΜ , 所述判断处理模块 602用于根据所述比例计算模块 601计算所得 比例 和比例 , 判断判断在所述发送总功率 最大时系统的能效是否最大, 若是, 则获取所述比例 和比例 , 否则更新所述发送总功率 。 In an embodiment of the present invention, the value is the maximum total transmission power of the total transmission power, and the ratio calculation module 601 is configured to calculate the maximum total transmission power when the total transmission power is maximum. The proportion a and the user data power of the user U m account for the ratio of the maximum total transmission power β Μ , the determination processing module 602 is configured to calculate the ratio and the ratio according to the ratio calculation module 601, and determine the judgment in the sending Whether the energy efficiency of the system is the largest when the total power is maximum, and if so, the ratio and ratio are obtained, otherwise the total transmission power is updated.
附图 6示例的判断处理模块 602可以进一步包括判断单元 701 ,如附图 7所示 本发明另一实施例提供的功率分配装置, 其中:  The judgment processing module 602 of the example of FIG. 6 may further include a judging unit 701, as shown in FIG. 7, a power distribution device according to another embodiment of the present invention, wherein:
判断单元 701 , 用于判断所述发送总功率 更新时能效增长率是否达到设 定的精度,若是,则判断所述发送总功率 更新后系统的能效达到最大。例如, 设定精度为 fl ,假设发送总功率 ^更新前系统的能效是;^,发送总功率 更新 后系统的能效是; 若 (H )≤ l, 则判断发送总功率 更新时能效增长率The determining unit 701 is configured to determine whether the energy efficiency growth rate of the total transmission power update is set The accuracy is determined, and if so, it is judged that the energy efficiency of the system is maximized after the total transmission power is updated. For example, the setting accuracy is fl , assuming that the total power is transmitted ^ the energy efficiency of the system before updating; ^, the energy efficiency of the system after the total power is updated is; if (H) ≤ l , the energy efficiency growth rate when the total power is updated is judged
Figure imgf000023_0001
Figure imgf000023_0001
达到设定的精度, 否则, 再次更新发送总功率 并判断发送总功率 /^再次更新 时能效增长率是否达到所述设定的精度 flThe set accuracy is reached. Otherwise, the total transmission power is updated again and it is judged whether the energy efficiency growth rate at the time of the total transmission power/^ is updated to reach the set accuracy fl .
附图 6或附图 7示例比例计算模块 601具体用于根据所述最大发送总功率, 采用迭代搜索计算发送总功率 最大时参考信号功率占所述最大发送总功率 的比例 a和用户 Um的用户数据功率占所述最大发送总功率的比例 βΜ , 其包括 初值预设单元 801、 比例获取单元 802和比例确定单元 803 ,如附图 8所示本发明 另一实施例提供的功率分配装置其中: The example ratio calculation module 601 of FIG. 6 or FIG. 7 is specifically configured to calculate, according to the maximum transmission total power, an ratio of a reference signal power to the maximum transmission total power and a user U m when the total transmission power is maximum. User data power occupies a ratio β Μ of the maximum transmission total power, which includes an initial value preset unit 801, a ratio acquisition unit 802, and a ratio determination unit 803, and the power distribution provided by another embodiment of the present invention as shown in FIG. The device is:
初值预设单元 801 , 用于设定所述比例 的初值;  The initial value preset unit 801 is configured to set an initial value of the ratio;
比例获取单元 802, 用于由所述最大发送总功率和所述初值, 获取所述比 例 , 的表达式具体为:  The ratio obtaining unit 802 is configured to obtain the ratio of the maximum transmitted total power and the initial value, and the expression is specifically:
Figure imgf000023_0002
Figure imgf000023_0002
Nm为用户 U™占用子载波个数, P。为所述最大发送总功率, 7为所述 P。转化为 最终发送功率的转换效率, ^为用户 m的大尺度信道增益, 为用户 U™的噪 声功率, Lm为用户 Um经历信道的可分辨多径数目, V为拉格朗日乘子, V满足 max(0, ^m (v)) = l - a , M为系统内处于连接态用户的数量; 比例确定单元 803 , 用于若所述初值预设单元 801设定的比例 a的初值与获 取的 关系满足 < ,则以此时获取的 和所述初值分别
Figure imgf000023_0003
N m is the number of subcarriers occupied by the user UTM, P. For the maximum transmitted total power, 7 is the P. The conversion efficiency converted to the final transmission power, ^ is the large-scale channel gain of the user m, the noise power of the user UTM, L m is the number of resolvable multipaths that the user U m experiences the channel, and V is the Lagrangian multiplier , V satisfies max(0, ^ m (v)) = l - a , where M is the number of users in the connected state in the system; and the ratio determining unit 803 is used to set the ratio a of the initial value preset unit 801 The initial value and the acquired relationship satisfy < , and the obtained initial value is
Figure imgf000023_0003
作为所述用户 Um的用户数据功率占所述最大发送总功率的比例和所述参考信 号功率占所述最大发送总功率的比例, 否则, 更新所述比例 的值, 所述 f3为 经验值 a ratio of the user data power of the user U m to the maximum transmission total power and a ratio of the reference signal power to the maximum transmission total power, otherwise, updating the value of the ratio, where f 3 is Experience
比例确定单元 803还用于将所述比例 按照公式 αη The ratio determining unit 803 is further configured to use the ratio according to the formula α η
Figure imgf000024_0001
Figure imgf000024_0001
更新, 所述 „为所述比例 更新后的值, //2为步长; Update, the value of „ is the updated value of the ratio, // 2 is the step size;
理模块 602还用于将所述发送总功率按照公式 / ^为所述发送总功率 Pf更新后的值,所述 ^为
Figure imgf000024_0002
所述/ ^为迭代步长。
The processing module 602 is further configured to use the total transmit power according to the formula / ^ as the updated value of the total transmit power P f , where
Figure imgf000024_0002
The / ^ is an iteration step.
附图 6至附图 8示例的判断处理模块 602包括偏导计算单元 901和判断单元 902, 如附图 9所示本发明另一实施例提供的功率分配装置, 其中:  The judgment processing module 602 illustrated in FIGS. 6 to 8 includes a partial derivative calculation unit 901 and a determination unit 902, such as the power distribution apparatus provided in another embodiment of the present invention, wherein:
偏导计算单元 901 ,用于计算能效函数 7关于发送总功率 的偏导数,所述 η为 £ g2d+ 2 H ) , Δ /为子载波带宽, Nm为用户 11«占用子载 The partial derivative calculation unit 901 is configured to calculate a partial derivative of the energy efficiency function 7 with respect to the total power transmitted, the η is £ g 2 d+ 2 H ) , Δ / is the subcarrier bandwidth, and N m is the user 11 « occupied subcarrier
Pt + Pc P t + P c
波个数, ^为电路损耗和静态功耗之和, 7为所述 Pf转化为最终发送功率的转 换效率, 为用户 U™的大尺度信道增益, 为用户 U™的噪声功率, Lm为用户 Um经历信道的可分辨多径数目, M是系统内处于连接态用户的数量; The number of waves, ^ is the sum of circuit loss and static power consumption, 7 is the conversion efficiency of the P f converted to the final transmit power, is the large-scale channel gain of the user UTM, and is the noise power of the user UTM, L m For the user U m to experience the number of resolvable multipaths of the channel, M is the number of users in the system in the connected state;
判断单元 902 ,用于若所述偏导计算单元 901计算所得偏导数在所述发送总 功率 为最大发送总功率时的值大于或等于 0 , 则判断在所述发送总功率 最 大时系统的能效最大。  The determining unit 902 is configured to determine, if the value of the partial derivative obtained by the partial derivative calculation unit 901 is greater than or equal to 0 when the total transmit power is the maximum transmit power, determine the energy efficiency of the system when the total transmit power is maximum maximum.
附图 6至附图 9示例的功率分配装置还包括精度判断模块 1001 , 如附图 10 所示本发明另一实施例提供的功率分配装置, 其中:  The power distribution device illustrated in FIGS. 6 to 9 further includes a precision determination module 1001, such as the power distribution device provided by another embodiment of the present invention, as shown in FIG.
精度判断模块 1001 , 用于判断所述发送总功率/ ^更新(即由第 w -1次迭代 时的发送总功率/^ 更新为第/ί次迭代时的发送总功率 ) 时能效增长速度是 否达到设定的精度。 例如, 可以通过判断 是否成立, £2—般可设定 为 10— 1() ~ ιο— 5。 若 dr]2成立, 则能效增长速度达到设定的精度。 The accuracy judging module 1001 is configured to determine whether the total energy of the transmission/^ update (that is, the total transmit power at the w-1th iteration/^ is updated to the total transmit power at the (0th) iteration) The set accuracy is achieved. For example, by determining whether the establishment, £ 2 - generally can be set to 10- 1 () ~ ιο- 5. If dr]2 is established, the energy efficiency growth rate reaches the set accuracy.
需要说明的是, 以上功率分配装置的实施方式中,各功能模块的划分仅是 举例说明, 实际应用中可以根据需要, 例如相应硬件的配置要求或者软件的实 现的便利考虑, 而将上述功能分配由不同的功能模块完成, 即将所述功率分配 装置的内部结构划分成不同的功能模块, 以完成以上描述的全部或者部分功 能。 而且, 实际应用中, 本实施例中的相应的功能模块可以是由相应的硬件实 现, 也可以由相应的硬件执行相应的软件完成, 例如, 前述的比例计算模块, 可以是具有执行前述计算发送总功率 最大时参考信号功率占所述最大发送 总功率的比例 a和用户 Um的用户数据功率占所述最大发送总功率的比例 βΜ的 硬件, 例如比例计算器,也可以是能够执行相应计算机程序从而完成前述功能 的一般处理器或者其他硬件设备; 再如前述的判断处理模块, 可以是具有执行 前述判断在所述发送总功率 最大时系统的能效是否最大, 若是, 则获取所述 比例 和比例 , 否则更新所述发送总功率 等功能的硬件, 如判断处理器, 也可以是能够执行相应计算机程序从而完成前述功能的一般处理器或者其他 硬件设备。 It should be noted that, in the implementation manner of the foregoing power distribution apparatus, the division of each functional module is only an example, and the actual application may be as needed, for example, the configuration requirements of the corresponding hardware or the real software. For the convenience of convenience, the above-mentioned function allocation is completed by different functional modules, that is, the internal structure of the power distribution device is divided into different functional modules to complete all or part of the functions described above. Moreover, in practical applications, the corresponding functional modules in this embodiment may be implemented by corresponding hardware, or may be executed by corresponding hardware. For example, the foregoing proportional calculation module may have the foregoing calculation and transmission. When the total power is maximum, the ratio of the reference signal power to the maximum total transmission power a and the user data power of the user U m to the ratio of the maximum total transmission power β Μ , such as a proportional calculator, may also be able to perform corresponding The computer program thus completes the foregoing functions of a general processor or other hardware device; and the foregoing determining processing module may have the function of performing the foregoing determination, whether the energy efficiency of the system is maximum when the total transmission power is maximum, and if so, acquiring the ratio And the ratio, otherwise the hardware that updates the function of transmitting the total power, such as the judgment processor, may also be a general processor or other hardware device capable of executing the corresponding computer program to perform the aforementioned functions.
从上述本发明实施例提供的功率分配装置可知,本发明实施例从参考信号 功率占最大发送总功率的比例 a和用户数据功率占最大发送总功率的比例 βΜ 两方面考虑功率分配, 如此, 与现有技术只考虑用户数据功率的分配不同, 兼 顾了利用参考信号进行信道估计的情形,本发明这种联合设计参考信号功率和 用户数据功率的方式可以在优化总功率的基 之上进一步降低系统功耗。另一 方面, 由于本发明实施例提供的方法是判断在发送总功率/^为某个值时系统的 能效是否最大,按照系统的能效最大时求得的比例 a和比例 分配参考信号功 率和用户数据功率, 因此, 本发明从能效最优的角度设计系统发送总功率以及 在此基石出上保证一定的小区覆盖,与传统以系统最大发送功率进行传输的方法 相比, 大大降低系统空口的总体能耗, 实现高效节能。 According to the power distribution apparatus provided by the embodiment of the present invention, the embodiment of the present invention considers the power allocation from the ratio of the reference signal power to the maximum transmission total power ratio a and the ratio of the user data power to the maximum transmission total power β Μ . Different from the prior art, only considering the allocation of user data power, taking into account the case of using the reference signal for channel estimation, the joint design reference signal power and user data power of the present invention can be further reduced on the basis of optimizing the total power. System power consumption. On the other hand, the method provided by the embodiment of the present invention determines whether the energy efficiency of the system is maximum when the total power/^ is a certain value, and the reference signal power and the user are allocated according to the ratio a and the ratio obtained when the energy efficiency of the system is maximum. The data power, therefore, the invention designs the system to transmit the total power from the perspective of optimal energy efficiency and guarantees a certain cell coverage on the basis of the core, which greatly reduces the overall system air interface compared with the traditional method of transmitting the maximum transmission power of the system. Energy consumption, achieving energy efficiency.
请参阅附图 11 , 本发明实施例提供的一种基站逻辑结构示意图, 该基站 可用于正交频分复用 ( OFDM, Orthogonal Frequency Division Multiplexing )系 统。 为了便于说明, 仅仅示出了与本发明实施例相关的部分。 附图 11示例提 供的基站包含的功能模块 /单元可以是软件模块 /单元、硬件模块 /单元或软硬件 相结合模块 /单元, 其包括参考信号功率配置模块 1102、 用户数据功率配置模 块 1103、子载波映射模块 1104、逆傅里叶变换模块 1105、加循环前缀模块 1106、 数模变换模块 1107、 射频模块 1108和附图 6至附图 10任一示例的功率分配 装置 1101 , 其中: Referring to FIG. 11, a schematic diagram of a logical structure of a base station, which can be used in an Orthogonal Frequency Division Multiplexing (OFDM) system, is provided in an embodiment of the present invention. System. For the convenience of description, only parts related to the embodiment of the present invention are shown. The function module/unit included in the base station provided by the example of FIG. 11 may be a software module/unit, a hardware module/unit or a combination of hardware and software modules/units, including a reference signal power configuration module 1102, a user data power configuration module 1103, and a sub-module. The carrier mapping module 1104, the inverse Fourier transform module 1105, the add cyclic prefix module 1106, the digital to analog conversion module 1107, the radio frequency module 1108, and the power distribution device 1101 of any of the examples of FIGS. 6 to 10, wherein:
功率分配装置 1101 ,用于计算发送总功率 最大时参考信号功率占所述最 大发送总功率的比例 a和用户 Um的用户数据功率占所述最大发送总功率的比 例 , 根据所述比例 和比例 , 判断在所述发送总功率 最大时系统的能 效是否最大,若是,则获取所述比例 和比例 ,否则更新所述发送总功率 计算所述发送总功率 Pt更新后所述比例 和比例 β , 判断所述发送总功率 更 新后系统的能效是否最大, 若是, 则获取所述发送总功率/ ^更新后计算所得比 例 和比例 ; The power distribution device 1101 is configured to calculate a ratio of a reference signal power to the maximum transmission total power and a ratio of user data power of the user U m to the maximum transmission total power when the total transmission power is maximum, according to the ratio and the ratio Determining whether the energy efficiency of the system is the largest when the total transmission power is maximum, and if yes, acquiring the ratio and the ratio, otherwise updating the total transmission power to calculate the ratio and the ratio β after updating the total transmission power P t , Determining whether the energy efficiency of the system after the total transmission power is updated is the largest, and if yes, obtaining the ratio and proportion calculated after the total transmission power/^ update;
参考信号功率配置模块 1102,用于按照功率分配装置 1101计算得到的参考 信号功率占最大发送总功率的比例《 ,将参考信号功率配置到经过编码调制后 的参考信号;  The reference signal power configuration module 1102 is configured to allocate the reference signal power to the coded modulated reference signal according to the ratio of the reference signal power calculated by the power distribution device 1101 to the maximum total transmission power.
用户数据功率配置模块 1103 ,用于按照功率分配装置 1101计算得到的用户 数据功率占最大发送总功率的比例 βΜ , 将用户数据功率配置到经过编码调制 后的各个用户数据上; The user data power configuration module 1103 is configured to configure the user data power to the encoded and modulated user data according to the ratio β Μ of the user data power calculated by the power distribution device 1101 to the maximum total transmission power;
子载波映射模块 1104,用于将配置好的参考信号和用户数据映射到子载波 上;  a subcarrier mapping module 1104, configured to map the configured reference signal and user data to the subcarriers;
逆傅里叶变换模块 1105 ,用于将所述子载波映射模块 1104映射后的数据进 行逆傅里叶变换;  An inverse Fourier transform module 1105 is configured to perform inverse Fourier transform on the data mapped by the subcarrier mapping module 1104.
加循环前缀模块 1106,用于将所述逆傅里叶变换模块 1105变换后的数据进 行加循环前缀(CP, Cyclic Prefix )处理;  The cyclic prefix module 1106 is configured to perform the cyclic prefix (CP, Cyclic Prefix) processing on the data transformed by the inverse Fourier transform module 1105.
数模变换模块 1107,用于将所述加循环前缀模块 1106输出的数字信号转换 成模拟信号; 射频模块 1108 ,用于将所述数模变换模块 1107输出的模拟信号经过其中功 率放大器的放大,根据功率分配装置 1101得到的发送总功率, 调整发射模拟信 号的幅度后经过射频天线发射出去。 a digital-to-analog conversion module 1107, configured to convert the digital signal output by the cyclic prefix prefix module 1106 into an analog signal; The radio frequency module 1108 is configured to: the analog signal output by the digital-to-analog conversion module 1107 is amplified by a power amplifier, and the amplitude of the transmitted analog signal is adjusted according to the total transmission power obtained by the power distribution device 1101, and then transmitted through the radio frequency antenna.
请参阅附图 12, 本发明实施例提供的一种功率分配装置逻辑结构示意图。 为了便于说明,仅仅示出了与本发明实施例相关的部分。 附图 12示例提供的功 率分配装置包含的功能模块 /单元可以是软件模块 /单元、硬件模块 /单元或软硬 件相结合模块 /单元, 其包括第一获取模块 1202、 第二获取模块 1202和第三获 取模块 1203 , 其中:  Referring to FIG. 12, a schematic diagram of a logical structure of a power distribution apparatus according to an embodiment of the present invention is shown. For the convenience of description, only parts related to the embodiment of the present invention are shown. The function module/unit included in the power distribution device provided by the example of FIG. 12 may be a software module/unit, a hardware module/unit or a combination of hardware and software modules/units, including a first acquisition module 1202, a second acquisition module 1202 and a The three acquisition module 1203, wherein:
第一获取模块 1201 , 用于获取系统的能效最大时的发送总功率 Pf、 参考信 号功率占所述发送总功率/^为定值时的比例 a和用户 Um的用户数据功率占所 述发送总功率 Pf为定值时的比例 βΜThe first obtaining module 1201 is configured to acquire a total transmit power P f when the energy efficiency of the system is maximum, a ratio a when the reference signal power accounts for the total transmit power/^, and a user data power of the user U m . The ratio β Μ when the total power P f is fixed;
第二获取模块 1202 , 用于若所述 Pf 、 和 ?的乘积 大于或等于所述 参考信号功率的最小值 ^, 则以所述第一获取模块 1201获取的比例 和比例 作为分配所述参考信号功率和所述用户数据功率的比例,所述 ?为所述 /^转 化为最终发送功率的转换效率; The second obtaining module 1202 is configured to: when the product of the P f , and ? is greater than or equal to the minimum value of the reference signal power, the ratio and the ratio acquired by the first acquiring module 1201 are used as the reference a ratio of signal power to the user data power, said conversion being the conversion efficiency of the final transmission power;
第三获取模块 1203 , 用于若所述 ?、 和 的乘积 不满足大于或等 于所述参考信号功率的最小值/ ^这一条件, 则在所述参考信号功率等于所述 ^的条件下重新获取发送总功率 ^为所述定值时所述参考信号功率占所述定 值的比例 a和所述用户 Um的用户数据功率占所述定值的比例 emThe third obtaining module 1203 is configured to: if the product of the ?, and the sum does not satisfy a condition that is greater than or equal to a minimum value of the reference signal power / ^, then the reference signal power is equal to the ^ ^ to obtain the total power transmission when the power of the reference signal value representing a ratio of the value of Um and the user account of the user data power ratio value e m.
在本发明一个实施例中, 所述定值为所述发送总功率 的最大发送总功 率,此时,所述第一获取模块 1201用于获取系统的能效最大时的发送总功率 参考信号功率占所述最大发送总功率的比例 a和用户 Um的用户数据功率占所 述最大发送总功率的比例 , 所述第三获取模块 1203用于若所述 、 和 的 乘积 不满足大于或等于所述参考信号功率的最小值/ ^这一条件, 则在所 述参考信号功率等于所述/ ^的条件下重新获取发送总功率 所述定值时所述 参考信号功率占所述定值的比例 和所述用户 Um的用户数据功率占所述定值 的比例 为: 若所述 ?、 Pf和 的乘积 不满足大于或等于所述参考信号 功率的最小值 ^这一条件, 则在所述参考信号功率等于所述 ^的条件下重新 获取发送总功率 最大时所述参考信号功率占所述最大发送总功率的比例《 和所述用户 Um的用户数据功率占所述最大发送总功率的比例 βΜIn an embodiment of the present invention, the value is the maximum total transmit power of the total transmit power. At this time, the first acquisition module 1201 is configured to acquire the total transmit power reference signal power when the system has the highest energy efficiency. The ratio of the maximum transmission total power a and the user data power of the user U m to the maximum transmission total power, the third obtaining module 1203 is configured to: if the product of the sum and the sum does not satisfy the greater than or equal to the a condition of a minimum value of reference signal power / ^, a ratio of the reference signal power to the fixed value when the fixed signal power is reacquired under the condition that the reference signal power is equal to the / ^ The ratio of the user data power of the user Um to the fixed value is: if the product of the ?, P f and the sum does not satisfy the condition that is greater than or equal to the minimum value of the reference signal power, then the reference is The signal power is equal to the condition of the ^ Obtaining a ratio of the reference signal power to the maximum transmission total power when the total transmission power is maximum, and a ratio of the user data power of the user U m to the maximum transmission total power β Μ .
附图 12示例的第一获取模块 1201包括第一比例计算子模块 1301和第一判 断处理子模块 1302,如附图 13所示本发明另一实施例提供的功率分配装置, 其 中:  The first acquisition module 1201 illustrated in FIG. 12 includes a first ratio calculation sub-module 1301 and a first determination processing sub-module 1302, such as the power distribution apparatus provided by another embodiment of the present invention, as shown in FIG.
第一比例计算子模块 1301 ,用于计算发送总功率 最大时参考信号功率占 所述最大发送总功率的比例 a和用户 Um的用户数据功率占所述最大发送总功 率的比例 , 所述用户 Um是系统内处于连接状态的任一用户; A first user data power ratio calculation sub-module 1301 for calculating a ratio of the total power transmission and the user account U m maximum total transmit power is the maximum power of the reference signal representing the total maximum transmission power ratio, the user Um is any user in the connected state within the system;
第一判断处理子模块 1302,用于根据所述第一比例计算子模块 1301计算所 得比例《和比例 , 判断在所述发送总功率 最大时系统的能效是否最大, 若 是, 则获取所述比例 和比例 , 否则更新所述发送总功率  The first determination processing sub-module 1302 is configured to calculate, according to the first ratio calculation sub-module 1301, a ratio “and a ratio, determine whether the energy efficiency of the system is maximum when the total transmission power is maximum, and if yes, obtain the ratio and Proportion, otherwise update the total transmit power
所述第一比例计算子模块 1301还用于计算所述发送总功率 更新后所述 比例 和比例 pm ,所述第一判断处理子模块 1302还用于判断所述发送总功率/^ 更新后系统的能效是否最大, 若是, 则获取所述发送总功率 更新后计算所得 比例 和比例 。 The first ratio calculating sub-module 1301 is further configured to calculate the ratio and the ratio p m after the sending total power update, and the first determining processing sub-module 1302 is further configured to determine the total sending power/^ after updating. Whether the energy efficiency of the system is the largest, and if so, the ratio and proportion calculated after the total power transmission is updated.
附图 13示例的第一判断处理子模块 1302包括第一判断单元 1401 ,如附图 14 所示本发明另一实施例提供的功率分配装置, 其中:  The first determination processing sub-module 1302 of the example of FIG. 13 includes a first determining unit 1401, such as the power distribution apparatus provided by another embodiment of the present invention, as shown in FIG.
第一判断单元 1401 ,用于判断所述发送总功率 更新时能效增长率是否达 到设定的精度, 若是, 则判断所述发送总功率 更新后系统的能效达到最大。  The first determining unit 1401 is configured to determine whether the energy efficiency growth rate of the total transmission power update reaches the set accuracy, and if yes, determine that the energy efficiency of the system is maximized after the total transmission power is updated.
附图 12至附图 14示例的第三获取模块 1203包括第三比例计算子模块 1501 和第三判断处理子模块 1502,如附图 15所示本发明另一实施例提供的功率分配 装置, 其中:  The third obtaining module 1203 illustrated in FIGS. 12 to 14 includes a third ratio calculating sub-module 1501 and a third judging processing sub-module 1502, as shown in FIG. 15, a power distribution device according to another embodiment of the present invention, wherein :
第三比例计算子模块 1501 ,用于计算多个用户的用户数据功率之和 Pp最大 时用户 Um的用户数据功率占所述/^的比例 所述 最大为 所述/ ^。 为所述最大发送总功率; A third user data power ratio calculation sub-module 1501, user data for the maximum sum of the power P p Um user computing a plurality of user accounts for the / ^ is the ratio of the maximum / ^. Transmitting the total power for the maximum;
第三判断处理子模块 1502,用于根据所述第三比例计算子模块 1501计算所 得比例 ym , 判断在所述多个用户的用户数据功率之和 ^最大时系统的能效是 否最大, 若是, 则根据所述 求取所述比例 和比例 , 否则更新所述 /^并 判断所述/^更新后系统的能效是否最大。 The third determination processing sub-module 1502 is configured to determine, according to the calculated ratio y m calculated by the third ratio calculation sub-module 1501, that the energy efficiency of the system is greater when the sum of the user data powers of the plurality of users is maximum No, if yes, the ratio and ratio are obtained according to the method, otherwise the /^ is updated and it is determined whether the energy efficiency of the system after the update is maximum.
附图 12至附图 15示例的第三获取模块 1203还包括能效判断子模块 1601 ,如 附图 16所示本发明另一实施例提供的功率分配装置, 其中:  The third obtaining module 1203 illustrated in FIGS. 12 to 15 further includes an energy efficiency determining sub-module 1601, such as the power distribution device provided by another embodiment of the present invention shown in FIG. 16, wherein:
能效判断子模块 1601 ,用于判断所述 更新时能效增长率是否达到设定的 精度, 若是, 则判断所述 更新更新后系统的能效达到最大。  The energy efficiency judging sub-module 1601 is configured to determine whether the energy-efficiency growth rate at the time of the update reaches a set precision, and if yes, determine that the energy efficiency of the system is maximized after the update and update.
附图 15或附图 16示例的第三比例计算子模块 1501还包括变量替换单元 The third ratio calculation sub-module 1501 illustrated in FIG. 15 or FIG. 16 further includes a variable replacement unit.
1701和比例计算单元 1702,如附图 17所示本发明另一实施例提供的功率分配装 置, 其中: 1701 and a ratio calculation unit 1702, as shown in FIG. 17, a power distribution apparatus according to another embodiment of the present invention, wherein:
变量替换单元 1701 , 用于由关系式 = Ρ。 - ^ /?和^ = βηΡ0 /( 0 - P p)替换 出^ = (1+ /^ ?); The variable replacement unit 1701 is used by the relation = Ρ. - ^ /? And ^ = β η Ρ 0 / ( 0 - P p) replace ^ = (1+ /^ ?);
比例计算单元 1702, 用于根据系统的能效最大时获取的用户1^的用户数 据功率占所述最大发送总功率的比例 , 计算出  The ratio calculation unit 1702 is configured to calculate, according to the ratio of the user data power of the user 1^ obtained by the maximum energy efficiency of the system to the maximum total transmission power,
Figure imgf000029_0001
Figure imgf000029_0001
附图 15或附图 16示例的第三判断处理子模块 1502还包括偏导计算单元 1801和判断单元 1802, 如附图 18所示本发明另一实施例提供的功率分配装置, 其中:  The third determination processing sub-module 1502 illustrated in Fig. 15 or Fig. 16 further includes a partial derivative calculation unit 1801 and a determination unit 1802, as shown in Fig. 18, which is a power distribution device according to another embodiment of the present invention, wherein:
偏导计算单元 1801 , 用于计算能效函数 7关于所述 ^的偏导数, 所述 7为 V AfNm log 2 (1 + ΡΡαΨΜ _ ) The partial derivative calculation unit 1801 is configured to calculate a partial derivative of the energy efficiency function 7 with respect to the ^, where 7 is V AfN m log 2 (1 + Ρ Ρ αΨΜ _ )
^ (pLm7mPfi + NmPa) , 其中, Δ/为子载波带宽, Nm为用户 1^占 ^ (pL m 7 m P fi + N m P a ) , where Δ/ is the subcarrier bandwidth and N m is the user 1^
Pp + Pc + Pa l p P p + P c + P a lp
用子载波个数, ^为电路损耗和静态功耗之和, ^为用户 um的大尺度信道增 益, 为用户1^的噪声功率, Lm为用户 Um经历信道的可分辨多径数目, M是 系统内处于连接态用户的数量; Using the number of subcarriers, ^ is the sum of the circuit loss and the static power consumption, ^ is the large-scale channel gain of the user u m , is the noise power of the user 1 , and L m is the number of resolvable multipaths experienced by the user U m through the channel , M is the number of connected users in the system;
判断单元 1802,用于若所述偏导数在所述多个用户的用户数据功率之和 最大时或者所述/ ^更新后的值大于或等于 0, 则判断在所述多个用户的用户数 据功率之和 Ρβ最大时系统的能效最大。 The determining unit 1802 is configured to determine, when the partial derivative is the maximum sum of the user data powers of the plurality of users, or the value after the /^ update is greater than or equal to 0, determine the number of users in the multiple users The system has the highest energy efficiency according to the sum of the powers Ρ β max.
附图 15至附图 18任一示例的功率分配装置还包括精度判断模块 1901 ,如附 图 18所示本发明另一实施例提供的功率分配装置, 其中:  The power distribution device of any of the examples of Figures 15 to 18 further includes a precision determination module 1901, such as the power distribution device of another embodiment of the present invention shown in Figure 18, wherein:
精度判断模块 1901 ,用于判断所述多个用户的用户数据功率之和 更新时 能效增长速度是否达到设定的精度。 从上述附图 12至附图 19本发明实施例提供的功率分配装置可知,本发明实 施例从参考信号功率占最大发送总功率的比例《和用户数据功率占最大发送 总功率的比例 两方面考虑功率分配, 如此, 与现有技术只考虑用户数据功 率的分配不同, 兼顾了利用参考信号进行信道估计的情形, 本发明这种联合设 计参考信号功率和用户数据功率的方式可以在优化总功率的基础之上进一步 降低系统功耗。 另一方面, 由于本发明实施例提供的方法是判断在发送总功率 The accuracy judging module 1901 is configured to determine whether the sum of the user data powers of the plurality of users is updated, and whether the energy growth rate reaches the set accuracy. The power distribution device according to the embodiment of the present invention, as shown in the above-mentioned FIG. 12 to FIG. 19, can be considered that the ratio of the reference signal power to the maximum total transmission power and the ratio of the user data power to the maximum transmission total power are considered in the embodiment of the present invention. Power allocation, in this way, different from the prior art, only considering the allocation of user data power, taking into account the case of using the reference signal for channel estimation, the joint design reference signal power and user data power of the present invention can optimize the total power. Further reduce system power consumption. On the other hand, the method provided by the embodiment of the present invention is to determine the total power transmitted.
Pt为某个值时系统的能效是否最大, 按照系统的能效最大时求得的比例 a和比 例 分配参考信号功率和用户数据功率, 因此, 本发明从能效最优的角度设 计系统发送总功率以及在此基石出上保证一定的小区覆盖,与传统以系统最大发 送功率进行传输的方法相比, 大大降低系统空口的总体能耗, 实现高效节能。 When the P t is a certain value, the energy efficiency of the system is the largest, and the reference signal power and the user data power are allocated according to the ratio a and the ratio obtained when the energy efficiency of the system is maximum. Therefore, the present invention designs the system to transmit the total power from the perspective of optimal energy efficiency. And ensuring a certain cell coverage on the basis of this foundation, compared with the traditional method of transmitting the maximum transmission power of the system, the overall energy consumption of the system air interface is greatly reduced, and energy saving is realized.
请参阅附图 20, 本发明另一实施例提供的一种基站逻辑结构示意图。 为 了便于说明, 仅仅示出了与本发明实施例相关的部分。 附图 20示例提供的基 站包含的功能模块 /单元可以是软件模块 /单元、硬件模块 /单元或软硬件相结合 模块 /单元,其包括参考信号功率配置模块 2002、用户数据功率配置模块 2003、 子载波映射模块 2004、 逆傅里叶变换模块 2005、 加循环前缀模块 2006、 数模 变换模块 2007、射频模块 2008和附图 12至附图 19任一示例的功率分配装置 2001 , 其中:  Referring to FIG. 20, a schematic diagram of a logical structure of a base station according to another embodiment of the present invention is shown. For the convenience of description, only the parts related to the embodiment of the present invention are shown. The function module/unit included in the base station provided by the example of FIG. 20 may be a software module/unit, a hardware module/unit or a combination of hardware and software modules/units, including a reference signal power configuration module 2002, a user data power configuration module 2003, a sub- A power distribution device 2001 of any one of the carrier mapping module 2004, the inverse Fourier transform module 2005, the cyclic prefix module 2006, the digital to analog conversion module 2007, the radio frequency module 2008, and the accompanying drawings 12 to 19, wherein:
功率分配装置 2001 ,用于计算发送总功率 Pt最大时参考信号功率占所述最 大发送总功率的比例 a和用户 Um的用户数据功率占所述最大发送总功率的比 例 , 根据所述比例 和比例 , 判断在所述发送总功率 最大时系统的能 效是否最大,若是,则获取所述比例 和比例 ,否则更新所述发送总功率 计算所述发送总功率 Pt更新后所述比例 和比例 β , 判断所述发送总功率 更 新后系统的能效是否最大, 若是, 则获取所述发送总功率/ ^更新后计算所得比 例 和比例 ; The power distribution device 2001 is configured to calculate a ratio of the reference signal power to the maximum transmission total power a when the total transmission power P t is maximum, and a ratio of user data power of the user U m to the maximum transmission total power, according to the ratio And the ratio, determining the energy of the system when the total transmission power is maximum Whether the effect is the largest, if yes, the ratio and the ratio are obtained, otherwise the total transmission power is updated to calculate the ratio and the ratio β after the total transmission power P t is updated, and it is determined whether the energy efficiency of the system after the total transmission power is updated Maximum, if yes, obtain the ratio and proportion calculated after the total transmission power / ^ update;
参考信号功率配置模块 2002,用于按照功率分配装置 2001计算得到的参考 信号功率占最大发送总功率的比例《 ,将参考信号功率配置到经过编码调制后 的参考信号;  The reference signal power configuration module 2002 is configured to allocate the reference signal power to the coded modulated reference signal according to the ratio of the reference signal power calculated by the power distribution device 2001 to the maximum total transmission power.
用户数据功率配置模块 2003 ,用于按照功率分配装置 2001计算得到的用户 数据功率占最大发送总功率的比例 βΜ , 将用户数据功率配置到经过编码调制 后的各个用户数据上; The user data power configuration module 2003 is configured to configure the user data power to the encoded and modulated user data according to the ratio β Μ of the user data power calculated by the power distribution device 2001 to the maximum total transmission power;
子载波映射模块 2004,用于将配置好的参考信号和用户数据映射到子载波 上;  a subcarrier mapping module 2004, configured to map the configured reference signal and user data to the subcarriers;
逆傅里叶变换模块 2005 ,用于将所述子载波映射模块 2004映射后的数据进 行逆傅里叶变换;  An inverse Fourier transform module 2005, configured to perform inverse Fourier transform on the data mapped by the subcarrier mapping module 2004;
加循环前缀模块 2006,用于将所述逆傅里叶变换模块 2005变换后的数据进 行加循环前缀( CP, Cyclic Prefix )处理;  And adding a cyclic prefix module 2006, configured to perform a cyclic prefix (CP, Cyclic Prefix) process on the data transformed by the inverse Fourier transform module 2005;
数模变换模块 2007 ,用于将所述加循环前缀模块 2006输出的数字信号转换 成模拟信号;  a digital-to-analog conversion module 2007, configured to convert the digital signal output by the cyclic prefix module 2006 into an analog signal;
射频模块 2008,用于将所述数模变换模块 2007输出的模拟信号经过其中功 率放大器的放大,根据功率分配装置 2001得到的发送总功率,调整发射模拟信 号的幅度后经过射频天线发射出去。  The RF module 2008 is configured to: the analog signal output by the digital-to-analog conversion module 2007 is amplified by a power amplifier, and the amplitude of the transmitted analog signal is adjusted according to the total transmission power obtained by the power distribution device 2001, and then transmitted through the RF antenna.
需要说明的是, 上述装置各模块 /单元之间的信息交互、 执行过程等内容, 由于与本发明方法实施例基于同一构思,其带来的技术效果与本发明方法实施 例相同, 具体内容可参见本发明方法实施例中的叙述, 此处不再赘述。  It should be noted that the information interaction, the execution process, and the like between the modules/units of the foregoing device are the same as the embodiment of the method of the present invention. Reference is made to the description in the method embodiment of the present invention, and details are not described herein again.
本领域普通技术人员可以理解上述实施例的各种方法中的全部或部分步 骤是可以通过程序来指令相关的硬件来完成,该程序可以存储于一计算机可读 存储介质中, 存储介质可以包括: 只读存储器(ROM, Read Only Memory ) 、 随机存取存储器(RAM, Random Access Memory ) 、 磁盘或光盘等。 A person skilled in the art may understand that all or part of the various steps of the foregoing embodiments may be completed by a program instructing related hardware. The program may be stored in a computer readable storage medium, and the storage medium may include: Read only memory (ROM, Read Only Memory), Random Access Memory (RAM), disk or optical disk.
以上对本发明实施例提供的一种功率分配方法、装置和一种基站进行了详 细介绍, 本文中应用了具体个例对本发明的原理及实施方式进行了阐述, 以上 实施例的说明只是用于帮助理解本发明的方法及其核心思想; 同时,对于本领 域的一般技术人员,依据本发明的思想,在具体实施方式及应用范围上均会有 改变之处, 综上所述, 本说明书内容不应理解为对本发明的限制。  The power distribution method and device and a base station provided by the embodiments of the present invention are described in detail. The principles and implementations of the present invention are described in the following. The description of the foregoing embodiments is only for helping. The method of the present invention and its core idea are understood; at the same time, for those skilled in the art, according to the idea of the present invention, there will be changes in the specific embodiments and application scopes. It should be understood that the invention is limited.

Claims

权 利 要 求 Rights request
1、 一种功率分配方法, 其特征在于, 所述方法包括: A power distribution method, the method comprising:
计算发送总功率 为定值时参考信号功率占所述定值的比例 a和用户 Um 的用户数据功率占所述定值的比例 βΜ , 所述用户 Um是系统内处于连接状态的 任一用户; Calculating a ratio β of the reference signal power to the fixed value when the total transmission power is a fixed value and a ratio β Μ of the user data power of the user U m to the predetermined value, where the user U m is in the connected state in the system. One user
根据所述比例 和比例 βΜ ,判断在所述发送总功率/^为所述定值时系统的 能效是否最大, 若是, 则获取所述比例《和比例 否则, 更新所述发送总功 率/^ Determining, according to the ratio and the ratio β Μ , whether the energy efficiency of the system is the maximum when the total transmission power/^ is the fixed value, and if yes, acquiring the ratio “and the ratio otherwise, updating the total transmission power/^
计算所述发送总功率 Pt更新后所述比例 和比例 βΜ ,判断所述发送总功率 /^更新后系统的能效是否最大, 若是, 则获取所述发送总功率 更新后计算所 得的比例 和比例 。 Calculating the ratio and the ratio β Μ after the updated total transmission power P t is updated, determining whether the energy efficiency of the system after the total transmission power/update is maximum, and if yes, obtaining the ratio calculated after the total transmission power is updated. proportion.
2、如权利要求 1所述的方法, 其特征在于, 所述定值为所述发送总功率 Pf 的最大发送总功率; The method according to claim 1, wherein the value is a maximum transmission total power of the total transmission power P f ;
所述计算发送总功率 Pf为定值时参考信号功率占所述定值的比例《和用 户1^的用户数据功率占所述定值的比例 为: 计算发送总功率/ ^最大时参考 信号功率占所述最大发送总功率的比例 a和用户 Um的用户数据功率占所述最 大发送总功率的比例 ; The ratio of the reference signal power to the fixed value when the total transmit power P f is a fixed value is calculated as “the ratio of the user data power of the user 1 ^ to the fixed value is: calculating the total transmit power / ^ maximum reference signal a ratio of power to the maximum total transmission power a and a ratio of user data power of the user U m to the maximum total transmission power;
所述^ ^据所述比例 和比例 ,判断在所述发送总功率/ ^所述定值时系统 的能效是否最大为: ^^据所述比例 "和比例 , 判断在所述发送总功率 最大 时系统的能效是否最大。  According to the ratio and the ratio, it is determined whether the energy efficiency of the system is the maximum when the total power is transmitted / ^ the fixed value: ^^ according to the ratio "and the ratio, determining that the total transmission power is the largest When the system is most energy efficient.
3、 如权利要求 2所述的方法, 其特征在于, 所述判断所述发送总功率/ ^更 新后系统的能效是否最大包括:  The method according to claim 2, wherein the determining whether the energy efficiency of the system after the sending total power/^ update is maximum comprises:
判断所述发送总功率 更新时能效增长率是否达到设定的精度, 若是, 则 判断所述发送总功率 Pt更新后系统的能效达到最大。 It is judged whether the energy efficiency growth rate of the total transmission power update reaches the set accuracy, and if so, it is determined that the energy efficiency of the system reaches the maximum after the total transmission power P t is updated.
4、 如权利要求 2所述的方法, 其特征在于, 所述计算发送总功率 最大时 参考信号功率占所述最大发送总功率的比例 a和用户 Um的用户数据功率占所 述最大发送总功率的比例 为: 根据所述最大发送总功率, 采用迭代搜索计 算发送总功率 最大时参考信号功率占所述最大发送总功率的比例《和用户 Um的用户数据功率占所述最大发送总功率的比例 βΜ , 所述采用迭代搜索计算 发送总功率最大时参考信号功率占所述最大发送总功率的比例 a和用户 1^的 用户数据功率占所述最大发送总功率的比例 βΜ包括: The method according to claim 2, wherein the calculating the ratio of the reference signal power to the maximum total transmission power and the user data power of the user U m when the total transmission power is maximum accounts for the maximum transmission total The ratio of the power is: according to the maximum total transmission power, an iterative search is used to calculate the ratio of the reference signal power to the maximum total transmission power when the total transmission power is maximum. The ratio of the user data power of the U m to the maximum total transmission power is β Μ , and the iterative search is used to calculate the ratio of the reference signal power to the maximum total transmission power and the user data power of the user 1 ^ when the total transmission power is maximum representing the maximum transmission power ratio of the total β Μ comprising:
设定所述比例 a的初值;  Setting the initial value of the ratio a;
由所述最大发送总功率和所述初值, 获取所述比例 , 的表达式具体  Obtaining the expression of the ratio by the maximum transmitted total power and the initial value,
Nm为用户 U™占用子载波个数, P。为所述最大发送总功率, 7为所述 P。转化为 最终发送功率的转换效率, ^为用户 U™的大尺度信道增益, 为用户 U™的噪 声功率, Lm为用户 Um经历信道的可分辨多径数目, V为拉格朗日乘子, V满足 ¾ 量; N m is the number of subcarriers occupied by the user UTM, P. For the maximum transmitted total power, 7 is the P. Converting to the conversion efficiency of the final transmit power, ^ is the large-scale channel gain of the user UTM, the noise power of the user UTM, L m is the number of resolvable multipaths experienced by the user U m , and V is the Lagrangian multiplication Child, V satisfies 3⁄4 quantity;
< ε , 则以此时获取的 βη
Figure imgf000034_0001
所述最大发送总功率的 比例和所述参考信号功率占所述最大发送总功率的比例, 否则, 更新所述比例 的值, 所述 £3为经验值。
< ε , then β η obtained at this time
Figure imgf000034_0001
The ratio of the maximum transmitted total power and the ratio of the reference signal power to the maximum transmitted total power, otherwise, updating the value of the ratio, the £ 3 being an empirical value.
5、 如权利要求 4所述的方法, 其特征 所述更新所述比例 的值为: 将所述比例 按照公式" = a- u (a - 吏新, 所述 „为所述比例
Figure imgf000034_0002
5. The method according to claim 4, characterized in that said updating said value of said ratio is: said ratio is according to the formula " = a - u (a - 吏 new, said „ is said ratio
Figure imgf000034_0002
更新后的值, //2为步长。 The updated value, // 2 is the step size.
6、 如权利要求 3所述的方法, 其特征在于, 所述判断所述发送总功率/ ^更 新时能效增长率是否达到设定的精度之后还包括:  The method according to claim 3, wherein the determining whether the energy-efficiency growth rate of the total transmission power/^ update reaches the set accuracy further comprises:
判断所述发送总功率 Pt更新时能效增长速度是否达到设定的精度。 It is judged whether the energy efficiency increase speed when the total transmission power P t is updated reaches the set accuracy.
7、如权利要求 2所述的方法,其特征在于,所述根据所述比例 和比例 , 判断在所述发送总功率/^最大时系统的能效是否最大包括:  The method according to claim 2, wherein said determining, according to said ratio and ratio, whether the energy efficiency of the system at the time of said total transmission power/max is maximum:
的偏导数, 所述 7 为
Figure imgf000034_0003
, Nm为用户 11«占用子载
Partial derivative, the 7 is
Figure imgf000034_0003
, N m is the user 11 « occupied sub-load
Pt + Pc P t + P c
波个数, ^为电路损耗和静态功耗之和, 为所述 Pf转化为最终发送功率的转 换效率, 为用户 U™的大尺度信道增益, 为用户 U™的噪声功率, Lm为用户The number of waves, ^ is the sum of the circuit loss and the static power consumption, and the conversion of the P f to the final transmission power Conversion efficiency, the large-scale channel gain for the user UTM, the noise power of the user UTM, L m is the user
Um经历信道的可分辨多径数目, M是系统内处于连接态用户的数量; U m experiences the number of resolvable multipaths of the channel, and M is the number of users in the connected state in the system;
若所述偏导数在所述发送总功率/ ^为最大发送总功率时的值大于或等于 If the partial derivative is greater than or equal to the value of the total transmit power / ^ is the maximum transmit total power
0, 则判断在所述发送总功率 Pt最大时系统的能效最大。 0, it is judged that the system has the highest energy efficiency when the total transmission power P t is maximum.
8、 如权利要求 2所述的方法, 其特征在于, 所述更新所述发送总功率 /^或 再次更新所述发送总功率 Pt为: The method according to claim 2, wherein the updating the total transmission power/^ or updating the total transmission power Pt is:
将所述发送总功率按照公式 Ρη = Ρη.γ + μχ- 更新,所述 为所述发送 dPt Transmitting the total transmitted power according to the formula Ρ η = Ρ η . γ + μ χ - updating, the transmitting dP t
总功率 更新后的值, 所述/ ^为所述发送总功率 更新前的值, 所述 A为迭 代步长。 The total power updated value, the / ^ is the value before the transmission total power update, and the A is an iteration step.
9、 一种功率分配方法, 其特征在于, 所述方法包括:  9. A power distribution method, the method comprising:
获取系统的能效最大时的发送总功率 、参考信号功率占所述发送总功率 为定值时的比例 a和用户 Um的用户数据功率占所述发送总功率 /^为所述定 值时的比例 ; Obtaining the total power of the system when the energy efficiency of the system is maximum, the ratio of the reference signal power to the total value of the total transmission power, and the user data power of the user U m occupying the total value of the transmission power/^ proportion;
若所述 ?、 /^和《的乘积 ? Pt a大于或等于所述参考信号功率的最小值 , 则以所述比例 和比例 作为分配所述参考信号功率和所述用户数据功率的 比例, 所述 ?为所述 转化为最终发送功率的转换效率; If the product of ?, /^, and "P t a is greater than or equal to the minimum value of the reference signal power, then the ratio and the ratio are used as the ratio of the reference signal power to the user data power. The ? is the conversion efficiency of the conversion to the final transmission power;
若所述 ?、 /^和 的乘积 ? Pt a不满足大于或等于所述参考信号功率的最 小值/ ^这一条件, 则在所述参考信号功率等于所述/ ^的条件下重新获取发送 总功率 为所述定值时所述参考信号功率占所述定值的比例 a和所述用户 Um 的用户数据功率占所述定值的比例 βΜIf the product of ?, /^ and ? P t a does not satisfy the condition that the value of the reference signal power is at least / ^, then re-acquired under the condition that the reference signal power is equal to the / ^ The ratio of the reference signal power to the predetermined value a and the ratio of the user data power of the user Um to the predetermined value when the total power is transmitted is β Μ .
10、如权利要求 9所述的方法,其特征在于,所述定值为所述发送总功率 的最大发送总功率;  10. The method of claim 9, wherein the fixed value is a maximum transmitted total power of the total transmitted power;
所述获取系统的能效最大时的发送总功率 参考信号功率占所述发送总 功率为定值时的比例 和用户 Um的用户数据功率占所述发送总功率为所述定 值时的比例 为: 获取系统的能效最大时的发送总功率 、参考信号功率占所 述最大发送总功率的比例 a和用户 Um的用户数据功率占所述最大发送总功率 的比例 所述若所述 、 和 的乘积 Pt α不满足大于或等于所述参考信号功率 的最小值/ ^这一条件, 则在所述参考信号功率等于所述/ ^的条件下重新获取 发送总功率 ^所述定值时所述参考信号功率占所述定值的比例《和所述用户 Um的用户数据功率占所述定值的比例 为: 若所述 ?、 和 的乘积 不 满足大于或等于所述参考信号功率的最小值/ ^这一条件,则在所述参考信号功 率等于所述 /^的条件下重新获取发送总功率 最大时所述参考信号功率占所 述最大发送总功率的比例 a和所述用户 Um的用户数据功率占所述最大发送总 功率的比例 。 The ratio of the total power reference signal power when the energy efficiency of the acquisition system is the largest, the ratio of the total transmission power to the fixed value, and the user data power of the user U m , when the total transmission power is the fixed value, is : the ratio of the total transmit power when the energy efficiency of the system is maximized, the ratio of the reference signal power to the maximum total transmit power, and the ratio of the user data power of the user U m to the maximum transmit total power. If the product P t α of the sum and the sum does not satisfy a condition that is greater than or equal to a minimum value / ^ of the reference signal power, re-acquiring the total transmission under the condition that the reference signal power is equal to the / ^ The ratio of the reference signal power to the fixed value when the power is fixed is "the ratio of the user data power of the user Um to the fixed value is: if the product of ? and " does not satisfy greater than or a condition equal to a minimum value of the reference signal power / ^, and the reference signal power occupies the maximum total transmission power when the total power of the transmission is re-acquired under the condition that the reference signal power is equal to the /^ The proportion of the user data power of the ratio a and the user U m to the maximum total transmission power.
11、 如权利要求 9所述的方法, 其特征在于, 所述获取系统的能效最大时 的发送总功率 Pf、参考信号功率占所述最大发送总功率的比例 a和用户 Um的用 户数据功率占所述最大发送总功率的比例 包括: The method according to claim 9, wherein the total transmission power P f when the energy efficiency of the acquisition system is maximum, the ratio a of the reference signal power to the maximum transmission total power, and the user data of the user U m The ratio of power to the maximum transmitted total power includes:
计算发送总功率 最大时参考信号功率占所述最大发送总功率的比例《 和用户 Um的用户数据功率占所述最大发送总功率的比例 βΜ , 所述用户 um是系 统内处于连接状态的任一用户; Calculating a ratio of the reference signal power to the maximum total transmission power when the total transmission power is maximum, and a ratio of user data power of the user U m to the maximum total transmission power β Μ , the user u m is in a connected state in the system Any user;
根据所述比例 a和比例 βΜ ,判断在所述发送总功率/^最大时系统的能效是 否最大, 若是, 则获取所述比例《和比例 , 否则更新所述发送总功率 Determining, according to the ratio a and the ratio β Μ , whether the energy efficiency of the system is the largest when the total power of transmission/^ is maximum, and if yes, acquiring the ratio “and ratio, otherwise updating the total transmission power”
计算所述发送总功率 更新后所述比例 和比例 ,判断所述发送总功率 ^更新后系统的能效是否最大, 若是, 则获取所述发送总功率 更新后计算所 得比例 和比例 。  Calculating the proportion and proportion of the total transmission power after updating, determining whether the energy efficiency of the system after the total transmission power is updated is the largest, and if yes, obtaining the ratio and proportion of the total transmission power after updating.
12、 如权利要求 10所述的方法, 其特征在于, 所述在所述参考信号功率等 于所述 ^的条件下重新获取发送总功率 最大时所述参考信号功率占所述最 大发送总功率的比例 a和所述用户 Um的用户数据功率占所述最大发送总功率 的比例 包括: The method according to claim 10, wherein the reference signal power occupies the maximum transmit total power when the total transmit power is re-acquired under the condition that the reference signal power is equal to the ^ The proportion of the user data power of the ratio a and the user U m to the maximum total transmission power includes:
计算多个用户的用户数据功率之和 Ρβ最大时用户 Um的用户数据功率占所 述/^的比例 , 所述 最大为 所述 Ρ。为所述最大发送总功率; Calculating the ratio of the user data power of the user Um when the sum of the user data powers of the plurality of users is 最大β is the ratio of the /^, and the maximum is the Ρ. Transmitting the total power for the maximum;
根据所述比例 ym , 判断在所述多个用户的用户数据功率之和 /^最大时系 统的能效是否最大, 若是, 则根据所述 求取所述比例《和比例 , 否则, 更新所述 Ρβ并判断所述 Ρβ更新后系统的能效是否最大。 Determining, according to the ratio y m , whether the energy efficiency of the system is the largest when the sum of the user data powers of the plurality of users is maximal, and if so, determining the ratio according to the ratio "and the ratio, otherwise updating the Ρ β and judge whether the energy efficiency of the system after the Ρ β update is the largest.
13、如权利要求 12所述的方法, 其特征在于, 所述判断所述 更新后系统 的能效是否最大包括: The method according to claim 12, wherein the determining whether the energy efficiency of the updated system is maximum comprises:
判断所述/ ^更新时能效增长率是否达到设定的精度,若是,则判断所述 更新更新后系统的能效达到最大。  It is judged whether the energy efficiency growth rate at the time of the /^ update reaches the set accuracy, and if so, it is judged that the energy efficiency of the system is maximized after the update and update.
14、 如权利要求 12所述的方法, 其特征在于, 所述计算多个用户的用户数 据功率之和 Ρβ最大时用户 Um的用户数据功率占所述 的比例 ym包括: 14. The method as claimed in claim 12, wherein said plurality of user computing power of user data Ρ β maximum sum Um user account of the user data power ratio y m comprising:
由关系式 = -^/?和 } =Α„Ρ。/0Ρ。- 替换出 Ym = Pm + Pa IPW, 根据系统的能效最大时获取的用户 Um的用户数据功率占所述最大发送 总功
Figure imgf000037_0001
By relation = -^/? And } =Α„Ρ./0Ρ.- Replace Y m = P m + P a IPW, according to the user's data power obtained by the user U m when the energy efficiency of the system is the largest, the maximum total transmission power
Figure imgf000037_0001
15、 如权利要求 12所述的方法, 其特征在于, 所述根据所述比例 , 判断 在所述多个用户的用户数据功率之和 Ρβ最大时系统的能效是否最大包括: 计算能效函数7关于/ ^的偏导数, 所述 为 The method according to claim 12, wherein, according to the ratio, determining whether the energy efficiency of the system is maximum when the sum of user data powers Ρ β of the plurality of users is maximum comprises: calculating an energy efficiency function 7 Regarding the partial derivative of / ^, the
, 其中, Δ/为子载波带宽, Nm为用户 Um占用子
Figure imgf000037_0002
载波个数 耗和静 态功耗之和, 为用户 Um的大尺度信道增益, 为用户0«的噪声功率, ^为 用户 Um经历信道的可分辨多径数目, M是系统内处于连接态用户的数量; 若所述偏导数在所述多个用户的用户数据功率之和/ ^最大时的值大于或 等于 0,则判断在所述多个用户的用户数据功率之和 ρβ最大时系统的能效最大。
Where Δ/ is the subcarrier bandwidth and N m is the user U m occupant
Figure imgf000037_0002
The sum of the carrier number and the static power consumption is the large-scale channel gain of the user U m , which is the noise power of the user 0 « , ^ is the number of resolvable multipaths that the user Um experiences the channel, and M is the user in the connected state in the system. If the partial derivative is greater than or equal to 0 when the sum of the user data powers of the plurality of users is greater than or equal to 0, determining that the system ρ β is maximum when the user data powers of the plurality of users are maximum The most energy efficient.
16、 如权利要求 12所述的方法, 其特征在于, 所述更新所述多个用户的用 户数据功率之和 为:  The method according to claim 12, wherein the updating the sum of user data powers of the plurality of users is:
将所述 按照公式 Ρη = Ρη. + άη 更新, 所述/ ^为所述 /^更新后的 值, 所述/ ^为所述/^更新前的值, 所 ϊ¾ί—为迭代步长。 The value is updated according to the formula Ρ η = Ρ η . + άη , the / ^ is the value after the /^ update, the / ^ is the value before the /^ update, and the ϊ3⁄4ί- is the iteration step size .
17、如权利要求 13所述的方法, 其特征在于, 所述判断所述 ^更新时能效 增长率是否达到设定的精度之后还包括:  The method according to claim 13, wherein the determining whether the energy efficiency growth rate at the time of the update reaches the set accuracy further comprises:
判断所述多个用户的用户数据功率之和 更新时能效增长速度是否达到 设定的精度。 It is determined whether the sum of the user data powers of the plurality of users is updated to achieve a set accuracy.
18、 一种功率分配装置, 其特征在于, 所述装置包括: 18. A power distribution device, the device comprising:
比例计算模块,用于计算发送总功率 Pf为定值时参考信号功率占所述定值 的比例 (和用户 Um的用户数据功率占所述定值的比例 , 所述用户 Um是系统 内处于连接状态的任一用户; a ratio calculation module, configured to calculate a ratio of a reference signal power to the predetermined value when the total transmit power P f is a fixed value (and a ratio of user data power of the user Um to the fixed value, where the user Um is in the system Any user of the connection status;
判断处理模块,用于根据所述比例计算模块计算所得比例《和比例 βΜ ,判 断在所述发送总功率 为所述定值时系统的能效是否最大, 若是, 则获取所述 比例 a和比例 pm , 否则更新所述发送总功率 PtDetermining a processing module for the resulting ratio "and ratio β is calculated according to the proportion calculation module [mu], determines the total transmission power in the energy efficiency of the system if the fixed maximum value, if yes, obtaining a ratio and the ratio p m , otherwise updating the total transmit power P t ;
所述比例计算模块还用于计算所述发送总功率 更新后所述比例 和比 例 βΜ ,所述判断处理模块还用于判断所述发送总功率 Pt更新后系统的能效是否 最大, 若是, 则获取所述发送总功率 更新后计算所得比例《和比例 。 The ratio calculation module is further configured to calculate the ratio and the ratio β Μ after the sending total power update, and the determining processing module is further configured to determine whether the energy efficiency of the system is the largest after the sending total power P t is updated, and if so, Then, the ratio “sum ratio” calculated after the total transmission power update is obtained.
19、 如权利要求 18所述的装置, 其特征在于, 所述定值为所述发送总功率 的最大发送总功率;  19. The apparatus according to claim 18, wherein the value is a maximum transmission total power of the total transmission power;
所述比例计算模块用于计算发送总功率/ ^最大时参考信号功率占所述最 大发送总功率的比例 a和用户 Um的用户数据功率占所述最大发送总功率的比 例 ; The ratio calculation module is configured to calculate a ratio of a reference power of the total transmit power to the maximum transmit total power and a ratio of user data power of the user U m to the maximum transmit total power;
所述判断处理模块用于根据所述比例计算模块计算所得比例 a和比例 pm , 判断判断在所述发送总功率 最大时系统的能效是否最大, 若是, 则获取所述 比例 a和比例 pm , 否则更新所述发送总功率 PtThe determining processing module is configured to determine, according to the ratio a and the ratio p m calculated by the ratio calculating module, whether the energy efficiency of the system is maximum when the total transmitting power is maximum, and if yes, obtain the ratio a and the ratio p m , otherwise update the total transmit power P t .
20、 如权利要求 19所述的装置, 其特征在于, 所述判断处理模块包括: 判断单元,用于判断所述发送总功率 更新时能效增长率是否达到设定的 精度, 若是, 则判断所述发送总功率 更新后系统的能效达到最大。  The device of claim 19, wherein the determining processing module comprises: a determining unit, configured to determine whether the energy efficiency growth rate of the total power transmission update reaches a set accuracy, and if so, determine the location The energy efficiency of the system is maximized after the total power transmission is updated.
21、 如权利要求 19所述的装置, 其特征在于, 所述比例计算模块具体用于 根据所述最大发送总功率,采用迭代搜索计算发送总功率 最大时参考信号功 率占所述最大发送总功率的比例 a和用户 Um的用户数据功率占所述最大发送 总功率的比例 , 所述比例计算模块包括: The device according to claim 19, wherein the ratio calculation module is configured to calculate, according to the maximum total transmit power, an iterative search, when the total transmit power is maximum, the reference signal power accounts for the maximum transmit total power. The ratio of the user data power of the ratio a and the user U m to the maximum total transmission power, the ratio calculation module includes:
初值预设单元, 用于设定所述比例 的初值;  An initial value preset unit for setting an initial value of the ratio;
比例获取单元, 用于由所述最大发送总功率和所述初值, 获取所述比例 , 的表达式具体为:
Figure imgf000039_0001
The ratio obtaining unit, configured to obtain the ratio by the maximum transmitted total power and the initial value, is specifically:
Figure imgf000039_0001
Nm为用户 U™占用子载波个数, P。为所述最大发送总功率, ?为所述 P。转化为 最终发送功率的转换效率, 为用户 m的大尺度信道增益, 为用户 U™的噪 声功率, Lm为用户 Um经历信道的可分辨多径数目, V为拉格朗日乘子, V满足 ¾ max(0, ^m (v)) = l - a , M为系统内处于连接态用户的数量; 比例确定单元, 用于若所述初值与获取的 pm关系N m is the number of subcarriers occupied by the user UTM, P. For the maximum transmit total power, ? is the P. The conversion efficiency converted to the final transmission power is the large-scale channel gain of the user m, the noise power of the user UTM, L m is the number of resolvable multipaths that the user U m experiences the channel, and V is the Lagrangian multiplier. V satisfies 3⁄4 max(0, ^ m (v)) = l - a , where M is the number of users in the connected state in the system; a ratio determining unit is used to determine the relationship between the initial value and the obtained p m
Figure imgf000039_0002
Figure imgf000039_0002
, 则以此时获取的 和所述初值分别作为所述用户 Um的用户数据功率占所述 最大发送总功率的比例和所述参考信号功率占所述最大发送总功率的比例,否 则, 更新所述比例 的值, 所述 £3为经验值。 And taking the initial value obtained at this time as the ratio of the user data power of the user Um to the maximum transmission total power and the ratio of the reference signal power to the maximum transmission total power, otherwise, updating The value of the ratio, the £ 3 is an empirical value.
22、 如权利要求 19所述的装置, 其特征在于, 所述比例确定单元还用于将  22. The apparatus according to claim 19, wherein the ratio determining unit is further configured to
^^更新, 所述 为所述比例 "更新^^ update, the update for the ratio
Ν " Ν "
Figure imgf000039_0003
Figure imgf000039_0003
新前的值, 所述 A为迭代步长。 The new value, the A is the iteration step size.
23、 如权利要求 20所述的装置, 其特征在于, 所述装置还包括:  The device of claim 20, wherein the device further comprises:
精度判断模块,用于判断所述发送总功率 Pt更新时能效增长速度是否达到 设定的精度。 The accuracy judging module is configured to judge whether the energy-efficiency growth speed of the total transmission power P t is updated to a set accuracy.
24、 如权利要求 19所述的装置, 其特征在于, 所述判断处理模块包括: 关于发送总功率/^的偏导数, 所述; 为 子载;皮带宽, Nm为用户 1^占用子载 波
Figure imgf000039_0004
为所述 转化为最终发送功率的转 换效率, 为用户 U™的大尺度信道增益, 为用户 U™的噪声功率, Lm为用户 Um经历信道的可分辨多径数目, M是系统内处于连接态用户的数量; 判断单元,用于若所述偏导计算单元计算所得偏导数在所述发送总功率 为最大发送总功率时的值大于或等于 0, 则判断在所述发送总功率/ ^最大时系 统的能效最大。
The apparatus according to claim 19, wherein the determining processing module comprises: a partial derivative for transmitting total power /^, wherein; is a subcarrier; a skin bandwidth, and Nm is a user 1^ occupant Carrier
Figure imgf000039_0004
For the conversion efficiency of the final transmission power, the large-scale channel gain of the user UTM, the noise power of the user UTM, L m is the user U m experiences the number of resolvable multipaths of the channel, M is the number of users in the connected state in the system; and the judging unit is configured to: if the partial derivative of the partial derivation calculation unit is calculated, when the total transmit power is the maximum transmit total power If the value is greater than or equal to 0, it is judged that the system has the highest energy efficiency when the total transmission power / ^ is maximum.
25、 一种基站, 其特征在于, 所述基站包括权利要求 19至 24任意一项所述 的功率分配装置。  A base station, characterized in that the base station comprises the power distribution device according to any one of claims 19 to 24.
26、 一种功率分配装置, 其特征在于, 所述装置包括:  26. A power distribution device, the device comprising:
第一获取模块, 用于获取系统的能效最大时的发送总功率 、 参考信号功 率占所述发送总功率/^为定值时的比例 a和用户 Um的用户数据功率占所述发 送总功率 为定值时的比例 ; A first acquiring module, for acquiring the energy efficiency of the transmission system, the total power maximum, the reference signal power representing the total power transmission / ^ the transmission ratio of a total power and when the user U m value representing user data power The ratio at which the value is fixed;
第二获取模块, 用于若所述 、 和 ?的乘积 大于或等于所述参考 信号功率的最小值 , 则以所述比例 和比例 作为分配所述参考信号功率 和所述用户数据功率的比例, 所述 ?为所述 转化为最终发送功率的转换效 率;  a second obtaining module, configured to allocate, according to a ratio of the sum of the reference signal and the power of the reference signal, a ratio of the reference signal power to the user data power, The ? is the conversion efficiency of the conversion to the final transmission power;
第三获取模块, 用于若所述 ?、 和 的乘积 不满足大于或等于所 述参考信号功率的最小值 ^这一条件, 则在所述参考信号功率等于所述 /^的 条件下重新获取发送总功率 为所述定值时所述参考信号功率占所述定值的 比例 a和所述用户 Um的用户数据功率占所述定值的比例 βΜa third obtaining module, configured to: if the product of the ?, and the sum does not satisfy a condition that is greater than or equal to a minimum value of the reference signal power, re-acquire under the condition that the reference signal power is equal to the /^ The ratio of the reference signal power to the fixed value a and the ratio of the user data power of the user Um to the fixed value when the total power is transmitted is β Μ .
27、 如权利要求 26所述的装置, 其特征在于, 所述定值为所述发送总功率 的最大发送总功率;  27. The apparatus according to claim 26, wherein the fixed value is a maximum transmission total power of the total transmission power;
所述第一获取模块用于获取系统的能效最大时的发送总功率 、参考信号 功率占所述最大发送总功率的比例 a和用户 1^的用户数据功率占所述最大发 送总功率的比例 ;  The first acquiring module is configured to acquire a total transmission power when the energy efficiency of the system is maximum, a ratio a of the reference signal power to the maximum total transmission power, and a ratio of the user data power of the user 1^ to the maximum total transmission power;
所述第三获取模块用于若所述 ?、 和 的乘积 ? Pt a不满足大于或等于 所述参考信号功率的最小值 这一条件, 则在所述参考信号功率等于所述 的条件下重新获取发送总功率 ^所述定值时所述参考信号功率占所述定值的 比例 和所述用户 Um的用户数据功率占所述定值的比例 为:若所述 ?、 和 a的乘积 ? Pt a不满足大于或等于所述参考信号功率的最小值/ ^这一条件, 则 在所述参考信号功率等于所述/^的条件下重新获取发送总功率 最大时所述 参考信号功率占所述最大发送总功率的比例 a和所述用户 Um的用户数据功率 占所述最大发送总功率的比例 βΜThe third obtaining module is configured to: if the product of ? and , ? P t a does not satisfy a condition that is greater than or equal to a minimum value of the reference signal power, if the reference signal power is equal to the condition Retrieving the total power transmitted ^ The ratio of the reference signal power to the fixed value and the ratio of the user data power of the user Um to the fixed value are: if the product of ?, and a ? P t a is greater than or does not satisfy the minimum / ^ this condition is equal to the reference signal power, the When the maximum total transmission power reacquire the reference signal at a power equal to said / ^ of the reference signal representing the maximum transmission power ratio of a total power and the user data of the user U m, the maximum power accounted The ratio of total power sent is β Μ .
28、 如权利要求 27所述的装置, 其特征在于, 所述第一获取模块包括: 第一比例计算子模块,用于计算发送总功率 最大时参考信号功率占所述 最大发送总功率的比例 和用户 Um的用户数据功率占所述最大发送总功率的 比例 , 所述用户 Um是系统内处于连接状态的任一用户; The device according to claim 27, wherein the first obtaining module comprises: a first ratio calculating submodule, configured to calculate a ratio of a reference signal power to a maximum total transmitting power when the total transmitting power is maximum And the ratio of the user data power of the user U m to the maximum total transmission power, where the user Um is any user in the connected state in the system;
第一判断处理子模块,用于根据所述第一比例计算子模块计算所得比例 a 和比例 , 判断在所述发送总功率 最大时系统的能效是否最大, 若是, 则获 取所述比例 和比例 , 否则更新所述发送总功率  a first determining processing sub-module, configured to calculate a ratio a and a ratio calculated by the sub-module according to the first ratio, and determine whether the energy efficiency of the system is maximum when the total transmitting power is maximum, and if yes, obtain the ratio and the ratio, Otherwise update the total transmit power
所述第一比例计算子模块还用于计算所述发送总功率 更新后所述比例 a和比例 βΜ ,所述第一判断处理子模块还用于判断所述发送总功率/^更新后系 统的能效是否最大, 若是, 则获取所述发送总功率 更新后计算所得比例《和 比例 。 The first ratio calculation sub-module is further configured to calculate the ratio a and the ratio β Μ after the sending total power update, and the first determining processing sub-module is further configured to determine the total power/update system after the sending Whether the energy efficiency is the largest, and if so, the ratio and the ratio calculated after the total transmission power update is obtained.
29、 如权利要求 28所述的装置, 其特征在于, 所述第一判断处理子模块包 括:  The apparatus according to claim 28, wherein the first determining processing submodule comprises:
第一判断单元,用于判断所述发送总功率 Pt更新时能效增长率是否达到设 定的精度, 若是, 则判断所述发送总功率 更新后系统的能效达到最大。 The first determining unit is configured to determine whether the energy efficiency growth rate of the total transmission power P t is updated to a set accuracy, and if yes, determine that the energy efficiency of the system is maximized after the total transmission power is updated.
30、 如权利要求 28所述的装置, 其特征在于, 所述第三获取模块包括: 第三比例计算子模块,用于计算多个用户的用户数据功率之和 最大时用 户 Um的用户数据功率占所述/^的比例 所述 最大为 Ρ。- / 7 , 所述 Ρ。为所 述最大发送总功率;  The apparatus according to claim 28, wherein the third obtaining module comprises: a third ratio calculating sub-module, configured to calculate user data power of the user Um when the sum of the user data powers of the plurality of users is maximum The maximum is Ρ in the ratio of the /^. - / 7, , said Ρ. Transmitting the total power for the maximum;
第三判断处理子模块, 用于根据所述第三比例计算子模块计算所得比例 γη , 判断在所述多个用户的用户数据功率之和 ρβ最大时系统的能效是否最大, 若是,则根据所述 求取所述比例 和比例 ,否则更新所述 并判断所述 更新后系统的能效是否最大。 a third determining processing submodule, configured to calculate a ratio γ η calculated by the sub-module according to the third ratio, and determine whether the energy efficiency of the system is maximum when the sum of the user data powers ρ β of the plurality of users is maximum, and if yes, And determining the ratio and proportion according to the method, otherwise updating the method and determining whether the energy efficiency of the updated system is the largest.
31、 如权利要求 30所述的装置, 其特征在于, 所述第三获取模块还包括: 能效判断子模块, 用于判断所述 更新时能效增长率是否达到设定的精 度, 若是, 则判断所述 更新更新后系统的能效达到最大。 The device according to claim 30, wherein the third obtaining module further comprises: an energy efficiency determining sub-module, configured to determine whether the energy-efficiency growth rate of the update reaches a set precision Degree, if yes, determine that the energy efficiency of the system is maximized after the update is updated.
32、 如权利要求 30所述的装置, 其特征在于, 所述第三比例计算子模块包 括:  32. The apparatus of claim 30, wherein the third ratio calculation sub-module comprises:
变量替换单元, 用于由关系式 = Ρ。- /^ /?和^ =ΑΛ /ΟΡ。- 替换出 比例计算单元, 用于根据系统的能效最大时获取的用户 um的用户数据功 率占所述最大发送总功率的比例 , 计算出 The variable replacement unit is used by the relation = Ρ. - /^ /? And ^ =ΑΛ /ΟΡ. - replacing the ratio calculation unit, which is used to calculate the ratio of the user data power of the user u m obtained when the energy efficiency of the system is maximum to the maximum total transmission power
33、 如权利要求 30所述的装置, 其特征在于, 所述第三判断处理子模块包 括: 33. The apparatus according to claim 30, wherein the third determining processing submodule comprises:
效函数;关于所述 的偏导数, 所述 为
Figure imgf000042_0001
, 其中, Δ/为子载波带宽, Nm为用户 1^占
Effect function; regarding the partial derivative, the
Figure imgf000042_0001
, where Δ/ is the subcarrier bandwidth, and N m is the user 1^
Ρβ + Ρε + Ρα / ρ Ρ β + Ρ ε + Ρ α / ρ
用子载波个数, ^为电路损耗和静态功耗之和, ^为用户 Um的大尺度信道增 益, 为用户1^的噪声功率, Lm为用户 Um经历信道的可分辨多径数目, M是 系统内处于连接态用户的数量; Using the number of subcarriers, ^ is the sum of the circuit loss and the static power consumption, ^ is the large-scale channel gain of the user U m , is the noise power of the user 1 , and L m is the number of resolvable multipaths experienced by the user U m through the channel , M is the number of connected users in the system;
判断单元,用于若所述偏导数在所述多个用户的用户数据功率之和 Ρβ最大 时或者所述/ ^更新后的值大于或等于 0, 则判断在所述多个用户的用户数据功 率之和 Ρβ最大时系统的能效最大。 Determination means for, if the partial derivative maximum when the plurality of users and user data Ρ β, or powers of the / ^ updated value is greater than or equal to 0, it is determined that the user of the plurality of users The system has the highest energy efficiency when the sum of data powers Ρ β is maximum.
34、 如权利要求 29所述的装置, 其特征在于, 所述装置还包括: 精度判断模块,用于判断所述多个用户的用户数据功率之和 Ρβ更新时能效 增长速度是否达到设定的精度。 The device according to claim 29, wherein the device further comprises: a precision determining module, configured to determine whether a sum of user data powers of the plurality of users Ρ β is updated when the energy efficiency growth rate reaches a setting Precision.
35、 一种基站, 其特征在于, 所述基站包括权利要求 26至 34任意一项所 述的功率分配装置。  A base station, characterized in that the base station comprises the power distribution device according to any one of claims 26 to 34.
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