US6111834A - Data storage system having efficient block code implementation - Google Patents
Data storage system having efficient block code implementation Download PDFInfo
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- US6111834A US6111834A US09/020,874 US2087498A US6111834A US 6111834 A US6111834 A US 6111834A US 2087498 A US2087498 A US 2087498A US 6111834 A US6111834 A US 6111834A
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- G—PHYSICS
- G11—INFORMATION STORAGE
- G11B—INFORMATION STORAGE BASED ON RELATIVE MOVEMENT BETWEEN RECORD CARRIER AND TRANSDUCER
- G11B5/00—Recording by magnetisation or demagnetisation of a record carrier; Reproducing by magnetic means; Record carriers therefor
- G11B5/012—Recording on, or reproducing or erasing from, magnetic disks
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- G—PHYSICS
- G11—INFORMATION STORAGE
- G11B—INFORMATION STORAGE BASED ON RELATIVE MOVEMENT BETWEEN RECORD CARRIER AND TRANSDUCER
- G11B20/00—Signal processing not specific to the method of recording or reproducing; Circuits therefor
- G11B20/10—Digital recording or reproducing
- G11B20/14—Digital recording or reproducing using self-clocking codes
- G11B20/1403—Digital recording or reproducing using self-clocking codes characterised by the use of two levels
- G11B20/1423—Code representation depending on subsequent bits, e.g. delay modulation, double density code, Miller code
- G11B20/1426—Code representation depending on subsequent bits, e.g. delay modulation, double density code, Miller code conversion to or from block codes or representations thereof
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- G—PHYSICS
- G11—INFORMATION STORAGE
- G11B—INFORMATION STORAGE BASED ON RELATIVE MOVEMENT BETWEEN RECORD CARRIER AND TRANSDUCER
- G11B5/00—Recording by magnetisation or demagnetisation of a record carrier; Reproducing by magnetic means; Record carriers therefor
- G11B5/02—Recording, reproducing, or erasing methods; Read, write or erase circuits therefor
- G11B5/09—Digital recording
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- G—PHYSICS
- G11—INFORMATION STORAGE
- G11B—INFORMATION STORAGE BASED ON RELATIVE MOVEMENT BETWEEN RECORD CARRIER AND TRANSDUCER
- G11B20/00—Signal processing not specific to the method of recording or reproducing; Circuits therefor
- G11B20/10—Digital recording or reproducing
- G11B20/14—Digital recording or reproducing using self-clocking codes
- G11B20/1403—Digital recording or reproducing using self-clocking codes characterised by the use of two levels
- G11B20/1423—Code representation depending on subsequent bits, e.g. delay modulation, double density code, Miller code
- G11B20/1426—Code representation depending on subsequent bits, e.g. delay modulation, double density code, Miller code conversion to or from block codes or representations thereof
- G11B2020/1446—16 to 17 modulation
Definitions
- the present invention relates to disc drives. More particularly, the present invention relates to block codes used in data channels of disc drives.
- a typical disc drive includes one or more magnetic discs mounted for rotation on a hub or spindle.
- a typical disc drive also includes a transducer supported by an air bearing which flies above each magnetic disc. The transducer and the air bearing are collectively referred to as a data head.
- a drive controller is conventionally used for controlling the disc drive based on commands received from a host system. The drive controller controls the disc drive to retrieve information from the magnetic discs and to store information on the magnetic discs.
- An electromechanical actuator operates within a negative feedback, closed-loop servo system.
- the actuator moves the data head radially over the disc surface for track seek operations and holds the transducer directly over a track on the disc surface for track following operations.
- Information is typically encoded and stored in concentric tracks on the surface of magnetic discs by providing a write signal to the data head to encode flux reversals on the surface of the magnetic disc representing the data to be stored.
- the drive controller controls the electromechanical actuator so that the data head flies above the magnetic disc, sensing the flux reversals on the magnetic disc, and generating a read signal based on those flux reversals.
- the read signal is typically conditioned and then decoded by a read channel or the drive controller to recover data represented by flux reversals stored on the magnetic disc, and consequently represented in the read signal provided by the data head.
- a communication channel represented by such a disc drive includes an encoder which encodes user input data, the data head, the medium (e.g., the magnetic or optical disc), preconditioning logic (such as amplifiers, filters, a gain loop, a sampler, a timing loop, and clock generation), a data detector, and a decoder for decoding the detected data to provide an output indicative of estimated user data.
- the medium e.g., the magnetic or optical disc
- preconditioning logic such as amplifiers, filters, a gain loop, a sampler, a timing loop, and clock generation
- a data detector e.g., a data detector
- decoder for decoding the detected data to provide an output indicative of estimated user data.
- Block coding techniques are typically used in disc drives and are well suited for correcting burst errors and imposing certain properties (constraints) in the encoded data which are useful in subsequent data processing.
- One type of block code is a Run-Length-Limited (RLL) code which limits the number of flux transitions which occur in a sequence.
- RLL Run-Length-Limited
- a block encoder and decoder having a rate of m/n for encoding data in blocks can be implemented using two tables which are related to the size of the block.
- the encoder is formed by a table having 2 m ⁇ n data entries and the decoder may be formed by a table having 2 n ⁇ m data entries.
- the encoder is formed by a table having 2 m ⁇ n data entries
- the decoder may be formed by a table having 2 n ⁇ m data entries.
- these tables become prohibitively large and cannot be practically implemented in a disc drive storage system.
- One approach which is used to implement block encoding in systems having relatively large values of m and n is to only encode a portion of each data word. The remainder of the data word is left unencoded.
- a common technique to implement a 16/17 rate code is to leave the first eight bits unencoded and encode the remaining eight bits into nine bits. In this manner, the complexity of the encoder is comparable to that of a 8/9 rate encoder.
- the disadvantage is that eight bits are passed through unencoded and cannot be used to impose code constraints, such as run length limits.
- the present invention provides a solution to this and other problems, and offers advantages over the prior art.
- the present invention relates to storage systems having block encoders which solve the above-mentioned problem.
- a storage device includes a storage medium and a write element positioned adjacent the storage medium to write information to the storage medium in response to a write signal input.
- a data input is provided which has a plurality of data input bits.
- a first encoder is coupled to the data input and includes a first encoded data output as a function of a first portion of the plurality of data input bits along with a state output. The first encoded data output is coupled to the write signal input of the write element.
- a second encoder is coupled to the data input and includes a second encoded data output as a function of a second portion of the plurality of data input bits and the state output. The second encoded data output is coupled to the write signal input of the write element.
- a storage device in another embodiment, includes a storage medium and a read element positioned adjacent the storage medium to read information to the storage medium and provide a read signal output.
- a first decoder is coupled to the read element and includes a first decoded data output as a function of a first portion of the read signal output and a state output. The first decoded data output is coupled to a system output.
- a second decoder is coupled to the read element and including a second decoded data output as a function of the read signal output and as a function of the state output. The second decoded data output is coupled to the system output.
- FIG. 1 is a simplified block diagram of a data storage system in accordance with the present invention.
- FIG. 2 is a diagram of a prior art block encoder.
- FIG. 3 is a diagram of a prior art block decoder.
- FIG. 4 is a diagram of a block encoder in accordance with one embodiment of the present invention.
- FIG. 5 is a diagram of a block decoder in accordance with one embodiment of the present invention.
- FIG. 6 is a block diagram of an encoder in accordance with a second embodiment of the present invention.
- FIG. 7 is a block diagram of a decoder in accordance with a second embodiment of the present invention.
- System 100 may be any type of storage device including magnetic, optical, magneto optical, etc.
- System 100 includes disc 102, read circuitry 104 and write circuitry 106 coupled to a transducing head 108 through switch 110.
- Transducing head 108 is positioned over a data surface of disc 102 and in one preferred embodiment comprises a head for reading and writing magnetically encoded information.
- Information received from input circuitry 112 is written onto disc 102 by write circuitry 106 which applies a write signal to transducing element 108.
- a signal is generated by transducing head 108 which is representative of a data signal stored on disc 102 and is provided to read circuitry 104.
- Read circuitry 104 decodes data carried in the data signal and provides an output through output circuitry 114.
- Write circuitry 106 includes encoding section 120 and amplification circuitry 122.
- Encoding section 120 is shown generally with a block encoder 124 and a PR4 precoder 126.
- Read circuitry 104 includes amplifier 130 and decoding section 131.
- Decoding section 131 generally includes a Partial Response Maximum Likelihood (PRML) detection 132 and a block decoder 134 in accordance with the present invention.
- Block encoder 124 and block decoder 134 are in accordance with the present invention and are described below in greater detail.
- Class 4 Partial Response (PR4) precoder 126 provides encoding to the data which is useful for PRML channels.
- Block encoder 124 and block decoder 134 operate in accordance with the present invention and efficiently encodes and decodes all bits of long data words without the large look-up tables required by the prior art.
- block encoder 124 and block decoder 134 partition the data word to reduce the complexity of the encoding and decoding.
- the technique is useful for implementing higher rate codes such as codes with a 16/17 rate or greater, and imposing properties on the code that are useful when followed by a PR4 precoder 126 for use with PRML channels.
- code constraints are imposed which have the following properties:
- g global Run-Length-Limited (RLL) constrains. Maximum run of 0's anywhere in the encoded sequence.
- I interleave RLL constraint. Maximum run of 0's per interleave.
- Minimum code energy Number of one's in the encoded pattern. This is an indication of the amount of timing information on each codeword. With the preferred embodiment, the following constraints may be obtained:
- FIGS. 2 and 3 are block diagrams of prior art 16/17 rate block encoder and decoder, respectively.
- the 16/17 rate block encoder of FIG. 2 receives 16 data bits of input (D0-D15) and provides a 17 code bit output (bits C0-C16) using a 2 16 ⁇ 17 look-up table.
- 17 data bits (C0-C16) are decoded using a 2 17 ⁇ 16 look-up table into 16 data bits (D0-D15).
- This prior art approach provides the desired code output, however, it requires relatively large look-up tables which are inefficient and may be impractical in most systems.
- FIG. 4 is a diagram of a block encoder 124 in accordance with one embodiment of the present invention.
- Block encoder 124 includes a first (Part A) encoder 152 and a second (Part B) encoder 154.
- the preferred embodiment partitions the input data into two parts.
- Data bits A0-A7 i.e., 8 bits
- Data bits B0-B7 i.e., 8 bits
- Encoder 152 provides a first encoded data output having bits Y0-Y6 which correspond to bits C0-C6 of FIG. 2.
- encoder 154 provides an encoded data output signal having bits Z0-Z9 which correspond to bits C7-C16 of FIG. 2.
- Encoder 152 provides a state number output 156 to encoder 154.
- Each entry in the table of encoder 152 is a 7 bit codeword along with a state number of two bits which is communicated to encoder 154.
- there are 3 ⁇ 127 381 possible combinations of codewords for encoder 152 and the corresponding state number.
- some Part A codewords in encoder 152 may be eliminated and/or some Part B state and Part A codewords may be disallowed.
- FIG. 5 is a diagram of block decoder 134.
- Decoder 134 includes a first (Part B) decoder 162 and a second (Part A) decoder 164.
- Decoder 162 receives 10 data bits (Z0-Z9) and provides 8 decoded data bits (B0-B7) and a state number output 166.
- Decoder 164 receives 7 data bits (Y0-Y6) along with the state number from decoder 162 and provides an 8 data bit output (A0-A7).
- decoder 162 is a table of 2 10 ⁇ (8+2) (8 bits of data and 2 bits of state) and decoder 164 is a table of 3 ⁇ 2 7 ⁇ 8.
- One important property of a preferred decoder implementation is that an error in bits Y0-Y6 will only affect a single byte (decoded bits A0-A7) of the decoded data. This is preferred because it limits the error propagation of the decoder to a maximum of 3 bytes. Error events that are 8 bits or less in length are guaranteed to affect only 3 bytes of data. Longer error events, for example one that starts in part B of one codeword and ends in part B of the next codeword, can be restricted by eliminating some part A patterns. For an embodiment using EPR4, it is sufficient to eliminate all part A patterns that are all zero in either interleave.
- the sequence of the part A codewords and the part B states can then be constrained to guarantee that the combined code energy (the sum of the code energy of part A and part B) is also 7 or greater, as shown below in Table 3:
- a minimum code energy (or Hamming weight) of 7 can also be achieved if the minimum code energy of each part B codeword is 4 and the minimum code energy of each part A codeword is 3.
- Table 4 is a table for use as encoder 152 of FIG. 4 and shows the data input along with the corresponding codeword output (CW) and state number output (Nx St).
- Table 5 is the encoding table for encoder 154 of FIG. 4 when state number 156 is zero.
- Table 6 is the encoding table when state number 156 is 1.
- Table 7 is the encoding table when state number 156 is 2.
- FIG. 6 shows a block diagram for an encoder 200 for producing a rate 16/17 code with minimum Hamming weight of 7 and a run-length-limited constraint of 6 for the entire encoded sequence and 6 for each interleave in the sequence.
- Encoder 200 is divided into two parts, part A and part B. Part A consists of code tester (A) 202 and encoder (A) 204 and part B consists of code tester (B) 206 and encoder (B) 208.
- Encoder (A) 204 receives the 8 most significant bits (D 15 -D 8 ) of a 16 bit input data word (D 15:0 ) along input bus 220. These 8 bits are denoted as A 7:0 in encoder (A) 204, which is shorthand for a string of 8 bits: A 7 A 6 A 5 A 4 A 3 A 2 A 1 A 0 . Of the 8 bits received by encoder (A) 204, code tester (A) 202 receives the least significant 7 bits, denoted as WA 6:0 in code tester (A) 202, along bus 222.
- Code tester (A) 202 produces output TA 203 which is input to encoder (A) 204. Based on TA 203 and inputs A 7:0 , encoder (A) 204 produces 7 code bits Y 6:0 on output bus 210. Encoder (A) 204 also produces three state variables S 0 , S 1 and S 2 and two part B bits WB 8 and WB 9 .
- Part B bits WB 8 and WB 9 are input to code tester (B) 206, along lines 216 and 218, respectively.
- Code tester (B) 206 also receives the least significant 8 bits (D 7 -D 0 ) of the input data word along input data bus 224. These bits are denoted as input bits WB 7:0 in code tester (B) 206. Based on inputs WB 7:0 , WB 8 and WB 9 , code tester (B) 206 produces an output TB 214 which is input to encoder (B) 208.
- encoder (B) 208 receives state variables S 0 , S 1 and S 2 along lines 228, 230 and 232, respectively, and the least significant 8 bits (D 7 -D 0 ) of the input data word along input bus 226. Within encoder (B) 208, the least significant 8 bits of the input data word are denoted as B 7:0 . Based upon all of the input values, encoder (B) 208 produces 10 output code bits Z 9:0 along output bus 212.
- code tester (A) 202 code tester (A) 202, encoder (A) 204, code tester (B) 206, and encoder (B) 208 is described below using the following symbols:
- Code tester (A) 202 produces output TA 203 based upon inputs WA 6:0 using the following equations:
- Encoder (A) 204 produces output 210 (Y 6:0 ) using input bits A 7:0 and TA 203 in equations 7 through 29 below.
- Encoder (A) 204 produces state variables S 0 , S 1 and S 2 using the following equations:
- Code tester (B) 206 produces output TB 214 using input bits WB 7:0 of the input data word and bits WB 8 and WB 9 from encoder (A) 204 in the following equations:
- Encoder (B) 208 produces output bits 212 (Z 9:0 ) using the least significant 8 bits of the input data word (B 7:0 ), the three state variables S 0 , S 1 and S 2 and TB 214 in the following equations:
- the 7 output bits 210 (Y 6:0 ) and the 10 output bits 212 (Z 9:0 ) are concatenated together to form a 17 bit codeword.
- FIG. 7 is a block diagram of a decoder 250 for decoding the codewords produced by encoder 200.
- Decoder 250 includes a part A and a part B, where part A includes code tester (A) 252 and decoder (A) 254, and part B includes code tester (B) 256 and decoder (B) 258.
- code tester (B) 256 receives the same 10 code bits along input bus 262, but denotes the 10 bits as WB 9:0 . Code tester (B) 256 uses these input bits to produce output TB 264 using equations 35 through 42 described above. Thus, code tester (B) 256 contains the same combinational logic as code tester (B) 206 of FIG. 6.
- the code tester circuit 206 may be shared by the encoder (FIG. 6) and the decoder (FIG. 7).
- Output TB 264 is input to decoder (B) 258 along with the 10 least significant bits of the codeword (Z 9:0 ) Decoder (B) 258 uses these inputs to produce state outputs S 0 ,S 1 and S 2 , along lines 266, 268 and 270, respectively, invalid codeword indicator FB on line 272, and the 8 least significant bits (B 7:0 ) of the recovered data word along output bus 274.
- Invalid codeword indicator FB is simply the inverse of TB 264and variables S 0 , S 1 and S 2 and recovered data bits B 7:0 are produced using the following equations:
- Code tester (A) 252 receives the 7 most significant bits of the codeword, which are represented as WA 6:0 in code tester (A) 252, along input bus 276. Code tester (A) 252 uses equations 1 through 6 described above together with the input bits to produce output TA 278, which is provided to decoder (A) 254. Thus, code tester (A) 252 contains the same combinational logic as code tester (A) 202 of FIG. 6.
- Decoder (A) 254 also receives the most significant 7 bits (Y 6:0 ) of the codeword along input bus 280 and state variables S 0 , S 1 and S 2 from decoder (B) 258 along lines 266, 268, and 270, respectively. Decoder (A) 254 uses these input values to produce the 8 most significant bits (A 7:0 ) of the recovered data word and an invalid codeword indicator FA along output bus 282 and line 284, respectively.
- Invalid codeword indicator FA is simply the inverse of TA 278 from code tester (A) 252. Recovered data bits A 7:0 are determined using the following equations:
- the preferred embodiment includes a storage device 100 having a storage medium 102 and a write element 108 positioned adjacent the storage medium 102 to write information to the storage medium 102 in response to a write signal input.
- the device 100 also includes a data input 112 providing a plurality of data input bits to a first block encoder 152.
- the first block encoder 152 provides a first encoded data output to the write element 108 as a function of a portion of the data input 112.
- the first encoder also provides a state number output 156 as a function of the data input.
- the second encoder 154 also couples the data input 112 and provides a second encoded output to the write element 108 as a function of a portion of the data input 112 and as a function of the state number output 156. Further, the first and second encoder output may be provided to a PRML precoder 126 which responsively provides the write signal to the write element 108.
- storage device 100 includes read element 108 which reads information from storage medium 102 and responsively provides a read signal output.
- a first decoder 162 is coupled to the read element and provides a state number output 166 and a first decoded data output as a function of a portion of a read signal output from the read element 108.
- the first decoded output is provided to a system data output 114.
- a second decoder couples to the read element 108 and provides a second decoded data output 114 as a function of the read signal output and as a function of the state number output 166.
- the second decoded output is also provided to the data output 114.
- a PRML detector 132 may also be provided between read element 108 and decoders 162 and 164.
- the present encoder/decoder greatly reduces the number of entries in a table of the type used in encoding and decoding.
- the encoder/decoder provides a plurality of block encoding/decoding tables in which an output from one table is used as an input to another table. This allows the overall number of data entries to be reduced without sacrificing the constraints placed on the code.
- the encoder/decoder may be implemented as appropriate including software or hardware implementations. Further, the particular codes, number of tables, number of state, etc., may change for any particular application.
- the encoder/decoder may use other techniques as desired including algorithm based or adaptive data translation techniques. Aspects of the invention include the division of codewords into two unequal parts and implementation of state dependent encoding/decoding with a different number of states for each pair. Further, each part of the decoder input has the same length.
- the code tester can be used to reduce logic count because the input data pattern can be used directly as the codeword if it satisfies the code constraints.
- the code tester checks the constraints and sends a signal to the encoder if the input word directly satisfies the constraints.
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Abstract
Description
TABLE 1 ______________________________________ Maximum Error Minimum Code g i Propagation (Bytes) Energy ______________________________________ 4 7 3 4 5 6 3 6 6 6 3 7 ______________________________________
TABLE 2 ______________________________________ State Part B Minimum Code Energy ______________________________________ 0 3 1 4 2 5 ______________________________________
TABLE 3 ______________________________________ Part A Code Energy Valid State Transitions ______________________________________ 2 2 3 1 or 2 4 0, 1 or 2 ______________________________________
TABLE 4 __________________________________________________________________________ State Diagram of 7-bit codeword mapping for 16/17 (0, 6/6) code [Min Hwt = 3] Data CW Nx St Data CW Nx St Data CW Nx St Data CW Nx St __________________________________________________________________________ 00 0E S0 40 4E S0 80 0F S0 C0 4F S0 01 16 S0 41 2B S0 81 17 S0 C1 6B S0 02 26 S0 42 3A S0 82 27 S0 C2 7A S0 03 36 S0 43 43 S1 83 37 S0 C3 43 S2 04 46 S0 44 2D S0 84 47 S0 C4 6D S0 05 56 S0 45 39 S0 85 57 S0 C5 79 S0 06 66 S0 46 46 S1 86 67 S0 C6 46 S2 07 76 S0 47 47 S1 87 77 S0 C7 47 S2 08 61 S0 48 25 S0 88 71 S0 C8 35 S0 09 62 S0 49 49 S1 89 72 S0 C9 49 S2 0A 63 S0 4A 4A S1 8A 73 S0 CA 4A S2 0B 0B S1 4B 4B S1 8B 0B S2 CB 4B S2 0C 65 S0 4C 4C S1 8C 75 S0 CC 4C S2 0D 0D S1 4D 4D S1 8D 0D S2 CD 4D S2 0E 0E S1 4E 4E S1 8E 0E S2 CE 4E S2 0F 0F S1 4F 4F S1 8F 0F S2 CF 4F S2 10 1E S0 50 5E S0 90 1F S0 D0 5F S0 11 1B S0 51 3B S0 91 5B S0 D1 7B S0 12 1A S0 52 52 S1 92 5A S0 D2 52 S2 13 13 S1 53 53 S1 93 13 S2 D3 53 S2 14 1D S0 54 3D S0 94 5D S0 D4 7D S0 15 19 S0 55 29 S0 95 59 S0 D5 69 S0 16 16 S1 56 56 S1 96 16 S2 D6 56 S2 17 17 S1 57 57 S1 97 17 S2 D7 57 S2 18 23 S0 58 58 S1 98 43 S0 D8 58 S2 19 19 S1 59 59 S1 99 19 S2 D9 59 S2 1A 1A S1 5A 5A S1 9A 1A S2 DA 5A S2 1B 1B S1 5B 5B S1 9B 1B S2 DB 5B S2 1C 1C S1 5C 5C S1 9C 1C S2 DC 5C S2 1D 1D S1 5D 5D S1 9D 1D S2 DD 5D S2 1E 1E S1 5E 5E S1 9E 1E S2 DE 5E S2 1F 1F S1 5F 5F S1 9F 1F S2 DF 5F S2 20 2E S0 60 6E S0 A0 2F S0 E0 6F S0 21 0B S0 61 61 S1 A1 4B S0 E1 61 S2 22 6A S0 62 62 S1 A2 4A S0 E2 62 S2 23 23 S1 63 63 S1 A3 23 S2 E3 63 S2 24 0D S0 64 64 S1 A4 4D S0 E4 64 S2 25 25 S1 65 65 S1 A5 25 S2 E5 65 S2 26 26 S1 66 66 S1 A6 26 S2 E6 66 S2 27 27 S1 67 67 S1 A7 27 S2 E7 67 S2 28 33 S0 68 68 S1 A8 53 S0 E8 68 S2 29 29 S1 69 69 S1 A9 29 S2 E9 69 S2 2A 32 S0 6A 6A S1 AA 52 S0 EA 6A S2 2B 2B S1 6B 6B S1 AB 2B S2 EB 6B S2 2C 2C S1 6C 6C S1 AC 2C S2 EC 6C S2 2D 2D S1 6D 6D S1 AD 2D S2 ED 6D S2 2E 2E S1 6E 6E S1 AE 2E S2 EE 6E S2 2F 2F S1 6F 6F S1 AF 2F S2 EF 6F S2 30 3E S0 70 7E S0 B0 3F S0 F0 7F S0 31 31 S1 71 71 S1 B1 31 S2 F1 71 S2 32 32 S1 72 72 S1 B2 32 S2 F2 72 S2 33 33 S1 73 73 S1 B3 33 S2 F3 73 S2 34 34 S1 74 74 S1 B4 34 S2 F4 74 S2 35 35 S1 75 75 S1 B5 35 S2 F5 75 S2 36 36 S1 76 76 S1 B6 36 S2 F6 76 S2 37 37 S1 77 77 S1 B7 37 S2 F7 77 S2 38 38 S1 78 78 S1 B8 38 S2 F8 78 S2 39 39 S1 79 79 S1 B9 39 S2 F9 79 S2 3A 3A S1 7A 7A S1 BA 3A S2 FA 7A S2 3B 3B S1 7B 7B S1 BB 3B S2 FB 7B S2 3C 3C S1 7C 7C S1 BC 3C S2 FC 7C S2 3D 3D S1 7D 7D S1 BD 3D S2 FD 7D S2 3E 3E S1 7E 7E S1 BE 3E S2 FE 7E S2 3F 3F S1 7F 7F S1 BF 3F S2 FF 7F S2 __________________________________________________________________________
TABLE 5 __________________________________________________________________________ State 0 of 10-bit codewords for 16/17 (0, 6/6) code [Min Hwt = 4] 0 1 2 3 4 5 6 7 8 9 A B C D E F __________________________________________________________________________ 0X 02F 04D 04E 04F 097 096 095 207 03B 03C 039 03A 03F 20D 20E 20F 1X 071 05D 05E 213 067 066 216 217 04B 219 21A 21B 21C 21D 21E 21F 2X 072 06D 06E 06F 087 225 226 227 05B 05C 059 05A 22C 22D 22E 22F 3X 073 231 232 233 234 235 236 237 238 239 23A 23B 23C 23D 23E 23F 4X 074 02D 02E 243 057 056 246 247 063 249 24A 24B 24C 24D 24E 24F 5X 075 03D 252 253 037 036 256 257 258 259 25A 25B 25C 25D 25E 25F 6X 076 261 262 263 264 265 266 267 268 269 26A 26B 26C 26D 26E 26F 7X 077 271 272 273 274 275 276 277 278 279 27A 27B 27C 27D 27E 27F 8X 078 08D 08E 08F 047 285 286 287 06B 06C 069 06A 28C 28D 28E 28F 9X 079 291 292 293 294 295 296 297 298 299 29A 29B 29C 29D 29E 29F AX 07A 09D 09E 09F 2A4 2A5 2A6 2A7 09B 09C 099 09A 2AC 2AD 2AE 2AF BX 07B 2B1 2B2 2B3 2B4 2B5 2B6 2B7 2B8 2B9 2BA 2BB 2BC 2BD 2BE 2BF CX 07C 2C1 2C2 2C3 2C4 2C5 2C6 2C7 2C8 2C9 2CA 2CB 2CC 2CD 2CE 2CF DX 07D 2D1 2D2 2D3 2D4 2D5 2D6 2D7 2D8 2D9 2DA 2DB 2DC 2DD 2DE 2DF EX 07E 2E1 2E2 2E3 2E4 2E5 2E6 2E7 2E8 2E9 2EA 2EB 2EC 2ED 2EE 2EF FX 07F 2F1 2F2 2F3 2F4 2F5 2F6 2F7 2F8 2F9 2FA 2FB 2FC 2FD 2FE 2FF __________________________________________________________________________
TABLE 6 __________________________________________________________________________ State 1 of 10-bit codewords for 16/17 (0, 6/6) code [Min Hwt = 4] 0 1 2 3 4 5 6 7 8 9 A B C D E F __________________________________________________________________________ 0X 0B5 0B4 0B7 0B6 0C6 0C7 0C9 107 0A5 0A6 0A7 10B 0B1 10D 10E 10F 1X 0D1 0B8 0B9 113 0CA 0CB 116 117 0AC 119 11A 11B 11C 11D 11E 11F 2X 0D2 0BC 0BD 123 0C5 125 126 127 0AD 129 12A 12B 12C 12D 12E 12F 3X 0D3 131 132 133 134 135 136 137 138 139 13A 13B 13C 13D 13E 13F 4X 0D4 0BA 0BB 143 0CC 0CD 146 147 0AE 149 14A 14B 14C 14D 14E 14F 5X 0D5 0B2 152 153 0CE 0CF 156 157 158 159 15A 15B 15C 15D 15E 15F 6X 0D6 161 162 163 164 165 166 167 168 169 16A 16B 16C 16D 16E 16F 7X 0D7 171 172 173 174 175 176 177 178 179 17A 17B 17C 17D 17E 17F 8X 0D8 0BE 0BF 183 0C3 185 186 187 0AF 189 18A 18B 18C 18D 18E 18F 9X 0D9 191 192 193 194 195 196 197 198 199 19A 19B 19C 19D 19E 19F AX 0DA 1A1 1A2 1A3 1A4 1A5 1A6 1A7 1A8 1A9 1AA 1AB 1AC 1AD 1AE 1AF BX 0DB 1B1 1B2 1B3 1B4 1B5 1B6 1B7 1B8 1B9 1BA 1BB 1BC 1BD 1BE 1BF CX 0DC 1C1 1C2 1C3 1C4 1C5 1C6 1C7 1C8 1C9 1CA 1CB 1CC 1CD 1CE 1CF DX 0DD 1D1 1D2 1D3 1D4 1D5 1D6 1D7 1D8 1D9 1DA 1DB 1DC 1DD 1DE 1DF EX 0DE 1E1 1E2 1E3 1E4 1E5 1E6 1E7 1E8 1E9 1EA 1EB 1EC 1ED 1EE 1EF FX 0DF 1F1 1F2 1F3 1F4 1F5 1F6 1F7 1F8 1F9 1FA 1FB 1FC 1FD 1FE 1FF __________________________________________________________________________
TABLE 7 __________________________________________________________________________ State 2 of 10-bit codewords for 16/17 (0, 6/6) code [Min Hwt = 4] 0 1 2 3 4 5 6 7 8 9 A B C D E F __________________________________________________________________________ 0X 0E1 0E4 0E2 303 0E8 0EC 306 307 0E3 309 30A 30B 30C 30D 30E 30F 1X 0F1 0E5 312 313 0E9 0ED 316 317 318 319 31A 31B 31C 31D 31E 31F 2X 0F2 321 322 323 324 325 326 327 328 329 32A 32B 32C 32D 32E 32F 3X 0F3 331 332 333 334 335 336 337 338 339 33A 33B 33C 33D 33E 33F 4X 0F4 0E6 342 343 0EA 0EE 346 347 348 349 34A 34B 34C 34D 34E 34F 5X 0F5 0E7 352 353 0EB 0EF 356 357 358 359 35A 35B 35C 35D 35E 35F 6X 0F6 361 362 363 364 365 366 367 368 369 36A 36B 36C 36D 36E 36F 7X 0F7 371 372 373 374 375 376 377 378 379 37A 37B 37C 37D 37E 37F 8X 0F8 381 382 383 384 385 386 387 388 389 38A 38B 38C 38D 38E 38F 9X 0F9 391 392 393 394 395 396 397 398 399 39A 39B 39C 39D 39E 39F AX 0FA 3A1 3A2 3A3 3A4 3A5 3A6 3A7 3A8 3A9 3AA 3AB 3AC 3AD 3AE 3AF BX 0FB 3B1 3B2 3B3 3B4 3B5 3B6 3B7 3B8 3B9 3BA 3BB 3BC 3BD 3BE 3BF CX 0FC 3C1 3C2 3C3 3C4 3C5 3C6 3C7 3C8 3C9 3CA 3CB 3CC 3CD 3CE 3CF DX 0FD 3D1 3D2 3D3 3D4 3D5 3D6 3D7 3D8 3D9 3DA 3DB 3DC 3DD 3DE 3DF EX 0FE 3E1 3E2 3E3 3E4 3E5 3E6 3E7 3E8 3E9 3EA 3EB 3EC 3ED 3EE 3EF LLFX 0FF 3F1 3F2 3F3 3F4 3F5 3F6 3F7 3F8 3F9 3FA 3FB 3FC 3FD 3FE 3FF __________________________________________________________________________
______________________________________ UA0 = WA6 | WA5 | WA4 | WA3 Eq. 1 UA1 = WA3 | WA2 | WA1 | WA0 Eq. 2 UA2 = WA6 | WA4 | WA2 | WA0 Eq. 3 UA3 = WA5 | WA3 | WA1 Eq. 4 { HWA = WA6+WA5+WA4+WA3+WA2+WA1+WA0 if (HWA>2) UA4=1 else UA4=0 } Eq. 5 TA = UA0 & UA1 & UA2 & UA3 & UA4 Eq. 6 ______________________________________
______________________________________ NH0 = A7 & A6 & A5 & A4 Eq. 7 NH8 = A7 & A6 & A5 & A4 Eq. 8 NL1 = A3 & A2 & A1 & A0 Eq. 9 NL2 = A3 & A2 & A1 & A0 Eq. 10 NL4 = A3 & A2 & A1 & A0 Eq. 11 NL5 = A3 & A2 & A1 & A0 Eq. 12 GA = A3&A2&A1&A0 Eq. 13 HA = (A6|A5 |A4)&(NL4 |NL1) Eq. 14 JA = (A6|A5 |A4)&(NL5 |NL2) Eq. 15 KA = (A6&A5&A4)&(A3&(A2|A1 |A0)) Eq. 16 LA = A3&(NH8 | NH0) Eq. 17 MA = (A6|A5 | A4)&A3 Eq. 18 YY6 = (KA&A2) | LA | (MA&(A7&A6)) Eq. 19 Y6 = (TA&A6) | (TA&( (GA&A6) | (HA&A7) | (JA&(A7 | (A7&A5)))|YY6 Eq. 20 YY5 = (KA&A1) |LA| (MA&(A7|A6)) Eq. 21 Y5 = (TA&A5) | (TA&((GA&A5)| (HA&A6) | (JA&(A6 | (A7&A5))) |YY5 Eq. 22 YY4 = (KA&A∩) | (LA&A7) | (MA&(A5|(A7& A6))) Eq. 23 Y4 = (TA&A4) | (TA&((GA&A4) | (HA&A4) | (JA&(A6 A4)) | YY4 )) Eq. 24 Y3 = (TA&A3) | (TA&( GA|HA|JA Eq. 25 Y2 = (TA&A2) | (TA&( GA| (HA&A2) | KA | (LA&A2) | (MA&A6) )) Eq. 26 Y1 = (TA&A1) | (TA&( GA|((HA|LA)&A0) | ((JA|LA)&A1) | KA| (MA&A6) Eq. 27 YY0 = (KA&A7) | (LA&A0) | (MA&A1) Eq. 28 Y0 = (TA&A0) | (TA&( ((GA|KA)&A7) |HA| (JA&A0) | YY0 )) Eq. 29 ______________________________________
______________________________________ S2 = A7 & TA Eq. 30 S1 = A7 & TA Eq. 31 S0 = TA Eq. 32 ______________________________________
______________________________________ WB9 = S2|S0 Eq. 33 WB8 = S2|S1 Eq. 34 ______________________________________
______________________________________ UB0 = WB9 | WB8 | WB7| WB6 | Eq. 35 UB1 = WB8 | WB7 | WB6| WB5 | WB4 | WB3| WB2 Eq. 36 UB2 = WB7 | WB6 | WB5| WB4 | WB3 | WB2| WB1 Eg. 37 UB3 = WB3 | WB2 | WB1| WB0 Eq. 38 UB4 = WB7 | WB5 | WB3| WB1 Eq. 39 UB5 = WB8 | WB6 | WB4| WB2 Eq. 40 { HWB =WB9+WB8+WB7+WB6+WB5+WB4+ WB3+WB2+WB1+WB0 if (HWB>3) UB6= 1 else UB6=0 } Eq. 41 TB = UB0 & UB1 & UB2 & UB3 & Eq. 42 UB4 & UB5 & UB6 ______________________________________
______________________________________ NH0 = B7&B6&B5&B4 Eq. 43 GB = (B7|B6|B5|B4) & (B3&B2&B1&B0) Eq. 44 HB = ( TB&S2&(GB ) Eq. 45 JB = ( TB&S1&GB& ((B3&B2) | (B3&B2)) ) Eq. 46 KB = ( TB&S1&(B3 B2) ) Eq. 47 LB = ( TB&S0&B3&B2) Eq. 48 MB = ( TB&S0&B3&B2) Eq. 49 NB = ( TB&S0&GB&((B3&B2) | (B3&B23)) ) Eq. 50 Z9 = (TB&(S2 | S0)) Eq. 51 Z8 = (TB&(S1 | S2)) Eq. 52 ZZ7 = (MB&B7&B6&B4) | (NB&B7) Eq. 53 Z7 = (TB&B7) | (TB&(ZZ7 | ((S2|S1)&GB) | Eq. 54 HB|JB|KB|(LB&B7&B5) )) ZZ6 = (MB&((B6 B4) | B7)) | (NB&B7&B6&(B1|B0)) Z6 = (TB&B6) | (TB&(Z6|GB|HB|(KB&B2) | Eq. 55 (LB&(B6 | B4 | (B7 B5))) )) Eq. 56 ZZ5 = (MB&B4) | (NB&(B6 | (B5&B7) | (B1&B0))) Eq. 57 Z5 = (TB&B5) | (TB&(Z5 | ((S2|S0)&GB) | Eq. 58 HB|JB|(KB&B3)|(LB&B5&B4) )) ZZ4 = (MB&((B7&B5&B4)|B6))| Eq. 59 NB&(B4 |B3|(B7&B5))) Z4 = (TB&B4) | (TB&(ZZ4|GB|JB| Eq. 60 (LB&(B5 | (B7&B6&B4))) )) ZZ3 = (KB&( (B2&(B6|B4|B1) ) | Eq. 61 (B3&(B7|B6|B5|B4)))) | (LB&B6) |NB Z3 = (TB&B3) | (TB&(Z3 | (GB&B7) (HB&B2) | (JB&(B7 | B5 | (B6 B4))) Eq. 62 ZZ2 = (KB&((B7&B1&(B6|B4)) |B3)) | Eq. 63 (LB&B1&B0) |MB|NB Z2 = (TB&B2) | (TB&(ZZ2|(GB&B6) | Eq. 64 (HB&B0) | (JB&(B7|B5|(NH0&B3))) )) ZZ1A = (LB&((B1&B0) | (B1&B0)))| Eq. 65 (MB&B1)|(NB&(B1|(B1&B0))) ZZ1 = (KB&((B2&B5&B1&(B6|B4))| Eq. 66 (B3&(B7|B6|B1|B0))))|ZZ1A Z1 = (TB&B1) | (TB&(ZZ1 | (GB&B5) | (HB&(B6.v ertline. Eq. 67 B3|B1))|(JB&(B7|B6|(NH0&B1))) )) ZZ0A = (LB&B0) | (MB&B0) | (NB&(B0 | (B1&B0))) Eq. 68 ZZ0 = (KB&((B2&(B7|B5|B1|B0))| Eq. 69 (B3&(B7|B5|B1|(NH0&B0)))))|ZZ0A Z0 = (TB&B0) | (TB&(Z0 | (GB&B4) | Eq. 70 (HB&(B4 | (B2&B1&B0))) | (JB&B0) )) ______________________________________
______________________________________ P0 = (Z7 | (Z6 & Z5)) &(Z6 | Z5 | Z4) Eq. 71 GZ = Z6 & Z4 & (Z7 | Z5) Eq. 72 HZ = Z7 & Z6 & Z5 & Z4 Eq. 73 JZ, = Z7 & Z6 & Z5 & Z4 Eq. 74 KZ = Z7 & Z4 & (Z6 Z5) Eq. 75 LZ = P0 & ( (Z3 & (Z2 | (Z1 & Z0))) | (Z3 & Z2) ) Eq. 76 MZ = P0 & (Z3 & Z2) NZ = P0 & (Z3 & Z2 & (Z1 | Z0)) Eq. 77 Eq. 78 BB7 = (LZ&(Z7 | (Z6&Z5&Z3))) | Eq. 79 (MZ&Z7&Z6&Z5&Z4) | (NZ&Z7) B07 = BB7 | (GZ&Z3) | (JZ&Z3&Z2&Z1) Eq. 80ine. (KZ&((Z3,&Z2) | (Z5&Z3&Z1&Z0))) BB6A= (LZ&Z3) | (MZ&Z7&Z4) | Eq. 81 (NZ&Z6&Z5&(Z1 | Z0)) BB6 = BB6A | (KZ&((Z5&Z3&Z2) | Eq. 82 (Z5&Z3&Z1&Z0))) B06 = BB6 | (GZ&Z2) | (HZ&Z1&(Z3 | Z2)) Eq. 83 | (JZ&Z2 &Z1) BB5A = (LZ&(Z7 | (Z6&Z4))) | (MZ&Z7&Zn4) Eq. 84 | (NZ&( (Z7&Z4) | (Z6&Z5))) BB5 = BSA | (KZ&((Z2&Z1 &Z0)&((Z6&Z3))) Eq. 85 | Z5&Z3)))) B05 = BB5 | (GZ&Z1) | (JZ&Z3&Z2&Z1) Eq. 86 BB4A= (LZ&(Z6&Z5 &Z4)) | (MZ&Z5) Eq. 87 (NZ&Z4& (Z6|(Z7&Z1))) BB4 = BB4A | (KZ&((Z6&Z3&Z1) Eq. 88 (Z5&Z1&Z0))) B04 = BB4 | (GZ&Z0) | (HZ&Z0& Eq. 89 (Z3 | Z2)) | (JZ&Z2&(Z3 Z1)) BB3 = (LZ) | (NZ&Z5&Z4&Z1) Eq. 90 B03 = BB3 | (HZ&Z3&Z2&Z1&Z0) | Eq. 91 (JZ&Z3&Z2&Z1&Z0) | (KZ&Z5) BB2 = (MZ) | (NZ&Z5&Z4&Z1) Eq. 92 B02 = BB2 | (HZ&Z3) Eq. 93 (JZ&Z3&Z2&Z1&Z0) | (KZ&Z6) BB1A = (LZ&(Z3&Z2&(Z1|Z0))) | Eq. 94 (MZ&Z1) | (NZ&Z1&(Z7|Z6|Z0)) BB1 = BB1A | (KZ&((Z6&Z2&Z1) | Eq. 95 (Z5&Z3&Z1&Z0))) B01 = BB1 | (HZ&Z3&Z2&Z1&Z0) | Eq. 96 (JZ&((Z3&Z2&Z1) | (Z3&Z0))) BB0A = (LZ&Z0) | (MZ&Z0) | Eq. 97 (NZ&Z0&(Z7|Z6|Z1)) BB0 = BB0A | (KZ&((Z6&Z0&((Z1&Z2) | Eq. 98 (Z3&(Z1|Z2)) )) | (Z5&Z3&Z1&Z0))) B00 = BB0 | (HZ&Z2) | (JZ&Z0) Eq. 99 ZZ = Z9&Z8 Eq. 100 S2 = (Z9&Z8) | (ZZ&Z7&Z6&Z5) Eq. 101 S1 = (Z9&Z8) | (ZZ&(Z7&(Z6 Z5))) Eq. 102 S0 = (Z9&Z8) | ( ZZ&(Z7|(Z6&Z5))) Eq. 103 B7 = ( ZZ & B07) | (ZZ & Z7) Eq. 104 B6 = ( ZZ & B06) | (ZZ & Z6) Eq. 105 B5 = ( ZZ & B05) | (ZZ & Z5) Eq. 106 B4 = ( ZZ & B04) | (ZZ & Z4) Eq. 107 B3 = ( ZZ & B03) | (ZZ & Z3) Eq. 108 B2 = ( ZZ & B02) | (ZZ & Z2) Eq. 109 B1 = ( ZZ & B01) | (ZZ & Z1) Eq. 110 BO = ( ZZ & B00) | (ZZ & Z0) Eq. 111 ______________________________________
______________________________________ GY = Y3&Y2&Y1 Eq. 112 HY = Y3&Y0&(Y2 Y1) Eq. 113 JY = Y3&Y2&(Y1 ee Y0) Eq. 114 KY = Y3&Y2&Y1 Eq. 115 LY = Y6&Y5&Y3 & (Y2|Y1) Eq. 116 MY = Y3&KY&LY Eq. 117 A07 = (GY|KY)&Y0) | (HY&Y6) | (JY&Y6&(Y4.vertli ne.Y5|Y1)) Eq. 118 | (LY&Y4) | (MY&(Y6|(Y4&Y2))) A06 = (GY&Y6) | (HY&Y5) | (JY&(Y5&(Y4|Y0))) | (MY&Y2) A05 = (GY&Y5)| (HY&Y5&Y4) | (JY&Y6&Y4&((Y5&Y1) |(Y5)) | (MY&(Y4&Y1)) A04 = (GY|HY)&Y4) | (JY&((Y5&Y4) | Eq. 119 (Y4&Y0))) | (MY&(Y4&Y2)) Eq. 120 A03 = LY | MY Eq. 121 A02 = (HY&Y2) | (JY&Y0) | (KY&Y6) | (LY&Y2) A01 = ((JY&Y1) | (KY&Y5) | Eq. 122 (LY&Y1&Y0) | (MY&Y1&Y0) Eq. 123 A00 = (HY&Y1) | (JY&Y0) | (KY&Y4) | (LY&Y1&Y0) Eq. 124 S12 = S2 | S1 Eq. 125 A7 = (S2) | (S0 & A07) Eq. 126 A6 = ( S12 & Y6) | (S0 & A06) Eq. 127 A5 = ( S12 & Y5) | (S0 & A05) Eq. 128 A4 = ( S12 & Y4) | (S0 & A04) Eq. 129 A3 = ( S12 & Y3) | (S0 & A03) Eq. 130 A2 = ( S12 & Y2) | (S0 & A02) Eq. 131 A1 = ( S12 & Y1) | (S0 & A01) Eq. 132 A0 = ( S12 & Y0) | (S0 & A00) Eq. 133 ______________________________________
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Also Published As
Publication number | Publication date |
---|---|
GB2343056A (en) | 2000-04-26 |
DE19882603T1 (en) | 2000-10-26 |
CN1306659A (en) | 2001-08-01 |
GB0001559D0 (en) | 2000-03-15 |
JP2001512880A (en) | 2001-08-28 |
KR100571743B1 (en) | 2006-04-18 |
WO1999008264A1 (en) | 1999-02-18 |
GB2343056B (en) | 2001-09-12 |
CN1157713C (en) | 2004-07-14 |
KR20010022814A (en) | 2001-03-26 |
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