TWI707580B - Partitioning of zero unit - Google Patents

Partitioning of zero unit Download PDF

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TWI707580B
TWI707580B TW108122735A TW108122735A TWI707580B TW I707580 B TWI707580 B TW I707580B TW 108122735 A TW108122735 A TW 108122735A TW 108122735 A TW108122735 A TW 108122735A TW I707580 B TWI707580 B TW I707580B
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unit
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divided
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張凱
張莉
劉鴻彬
莊孝強
王悅
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大陸商北京字節跳動網絡技術有限公司
美商字節跳動有限公司
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    • H04N19/157Assigned coding mode, i.e. the coding mode being predefined or preselected to be further used for selection of another element or parameter
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    • H04N19/169Methods or arrangements for coding, decoding, compressing or decompressing digital video signals using adaptive coding characterised by the coding unit, i.e. the structural portion or semantic portion of the video signal being the object or the subject of the adaptive coding
    • H04N19/17Methods or arrangements for coding, decoding, compressing or decompressing digital video signals using adaptive coding characterised by the coding unit, i.e. the structural portion or semantic portion of the video signal being the object or the subject of the adaptive coding the unit being an image region, e.g. an object
    • H04N19/176Methods or arrangements for coding, decoding, compressing or decompressing digital video signals using adaptive coding characterised by the coding unit, i.e. the structural portion or semantic portion of the video signal being the object or the subject of the adaptive coding the unit being an image region, e.g. an object the region being a block, e.g. a macroblock
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Abstract

Zero units (ZU) are used in coding or decoding of video. One example method of video processing includes determining that a block of video data is to be coded as a ZU block, due to the block of video data having dimensions S×T at least one of S and T being a non-power-of two number; partitioning the ZU block into one of two units, three units, or four units; and generating a bitstream by coding the units.

Description

零單元的劃分Zero unit division

本專利文件一般地涉及圖像和視頻編碼技術。 This patent document generally relates to image and video coding technology.

[相關申請的交叉引用] [Cross references to related applications]

根據適用的專利法和/或依據巴黎公約的規則,本申請及時要求於2018年6月29日提交的國際專利申請第PCT/CN2018/093631號、於2018年7月2日提交的美國臨時專利申請第62/693,415號以及於2018年7月6日提交的國際專利申請第PCT/CN2018/094767號的優先權和權益。該國際專利申請第PCT/CN2018/093631號、美國臨時申請第62/693,415號和國際專利申請第PCT/CN2018/094767號的全部公開內容通過引用併入作為本申請的公開內容的一部分。 In accordance with applicable patent laws and/or in accordance with the rules of the Paris Convention, this application promptly requests the International Patent Application No. PCT/CN2018/093631 filed on June 29, 2018, and the U.S. Provisional Patent filed on July 2, 2018 The priority and rights of application No. 62/693,415 and International Patent Application No. PCT/CN2018/094767 filed on July 6, 2018. The entire disclosures of the International Patent Application No. PCT/CN2018/093631, U.S. Provisional Application No. 62/693,415 and International Patent Application No. PCT/CN2018/094767 are incorporated by reference as part of the disclosure of this application.

數位視訊佔據網際網路和其它數位通信網路上最大的頻寬使用。隨著能夠接收和顯示視頻的所連接的使用者設備的數量增加,預計數位視訊使用的頻寬需求將繼續增長。 Digital video occupies the largest bandwidth usage on the Internet and other digital communication networks. As the number of connected user devices capable of receiving and displaying video increases, it is expected that the demand for bandwidth used by digital video will continue to grow.

描述了與專用編碼單元(CU)和/或編碼樹單元(CTU)相關的用於提高編碼效率的設備、系統和方法。具體地,本公開的技術公開了提供增強例如處理位於視頻數據塊的邊界處的子塊(例如,在圖片、條帶、片等中)的零單元。所描述的方法可以應用於現有的視頻編碼標準(例如,高效視頻編碼(HEVC))和未來的視頻編碼標準或視頻編解碼器兩者。 Described are devices, systems, and methods related to dedicated coding units (CU) and/or coding tree units (CTU) for improving coding efficiency. In particular, the technology of the present disclosure discloses zero units that provide enhancements such as processing sub-blocks (eg, in pictures, slices, slices, etc.) located at the boundaries of video data blocks. The described method can be applied to both existing video coding standards (for example, High Efficiency Video Coding (HEVC)) and future video coding standards or video codecs.

在一個代表性方面中,所公開的技術可以被用於提供視頻編碼的方法,其可以實現在視訊編碼器中。該方法包括由於視頻數據塊具有尺寸S×T、S和T的至少一個是非二的冪數,確定視頻數據塊將被編碼為零單元(ZU)塊;將ZU塊劃分為兩個單元、三個單元或四個單元中的一個;以及通過編碼單元生成位元流。 In a representative aspect, the disclosed technology can be used to provide a method of video encoding, which can be implemented in a video encoder. The method includes determining that the video data block will be encoded as a zero unit (ZU) block because the video data block has a size S×T, and at least one of S and T is a power of two; dividing the ZU block into two units, three One unit or one of four units; and the bit stream is generated by the coding unit.

在另一示例方面,公開了另一種視頻處理的方法。該方法包括接收對應於編碼為零單元(ZU)塊的視頻數據塊的位元流,該零單元(ZU)塊被劃分為兩個單元、三個單元或四個單元,視頻數據塊具有尺寸S×T;以及通過解碼位元流生成視頻數據塊。 In another example aspect, another method of video processing is disclosed. The method includes receiving a bit stream corresponding to a video data block encoded as a zero unit (ZU) block, the zero unit (ZU) block is divided into two units, three units, or four units, and the video data block has a size S×T; and the video data block is generated by decoding the bit stream.

在另一示例方面,公開了另一種視頻處理的方法。該方法包括由於塊具有非二的冪數的高度或寬度,確定視頻數據塊將被編碼為零單元(ZU)塊;使用劃分方案來劃分視頻數據塊,其中,劃分方案將視頻數據塊劃分為兩個單元、三個單元或四個單元中的一個;通過編碼視頻數據塊生成位元流,其中,劃分方案使用與用於對作為非零單元塊的另一塊的劃分的信令通知相同的 語法來發信令通知。 In another example aspect, another method of video processing is disclosed. The method includes determining that the video data block will be encoded as a zero unit (ZU) block because the block has a height or width that is not a power of two; and dividing the video data block using a partitioning scheme, where the partitioning scheme divides the video data block into One of two units, three units, or four units; a bit stream is generated by encoding video data blocks, where the division scheme uses the same signaling as used for the division of another block that is a non-zero unit block Syntax to signal.

在另一示例方面,公開了另一種視頻處理的方法。該方法包括接收對應於視頻數據塊的位元流,視頻數據塊由於視頻數據塊具有尺寸S×T、S和T的至少一個是非二的冪數,而被編碼為零單元(ZU)塊,其中,使用將視頻數據塊劃分為兩個單元、三個單元或四個單元中的一個的劃分方案將視頻數據塊劃分,並且其中,劃分方案在位元流中使用與用於信令通知非零單元塊的劃分相同的語法來信令通知;基於信令通知,解碼位元流解碼以生成視頻數據塊。 In another example aspect, another method of video processing is disclosed. The method includes receiving a bit stream corresponding to a video data block, the video data block being encoded as a zero unit (ZU) block because the video data block has a size of S×T, at least one of S and T is a power of two, Among them, the video data block is divided using a division scheme of dividing the video data block into two units, three units, or one of four units, and wherein the division scheme is used in the bit stream and used for signaling non The division of zero unit blocks is signaled with the same syntax; based on the signalling, the decoded bit stream is decoded to generate video data blocks.

在另一示例方面,公開了另一種視頻處理的方法。該方法包括由於視頻數據塊具有尺寸S×T、S和T的至少一個是非二的冪數,確定視頻數據塊將被編碼為零單元(ZU)塊;使用從ZU塊劃分方案的組中選擇的劃分方案將ZU塊劃分為兩個單元、三個單元或四個單元中的一個;編碼該單元;以及在位元流中信令通知被編碼的單元。這裡,ZU塊劃分方案的組是可用於分割編碼單元(CU)的劃分方案的組的子集。 In another example aspect, another method of video processing is disclosed. The method includes determining that the video data block will be encoded as a zero unit (ZU) block because the video data block has a size of S×T, and at least one of S and T is a power of two; using a selection from the group of ZU block division schemes The partitioning scheme of the ZU block is divided into two units, three units or one of four units; the unit is encoded; and the encoded unit is signaled in the bit stream. Here, the group of ZU block partitioning schemes is a subset of the group of partitioning schemes available for partitioning coding units (CU).

在另一示例方面,公開了另一種視頻處理的方法。該方法包括接收對應於視頻數據塊的位元流,視頻數據塊具有尺寸;接收信令通知,該信令通知指示由於視頻數據塊具有尺寸S×T、S和T的至少一個是非二的冪數,視頻數據塊作為零單元(ZU)塊被劃分,使用從ZU塊劃分方案的組中選擇的劃分方案將塊劃分;以及基於信令通知,解碼對應於單元的位元流以重建視頻數據塊。 這裡,ZU塊劃分方案的組是可用於分割編碼單元(CU)的劃分方案的組的子集。 In another example aspect, another method of video processing is disclosed. The method includes receiving a bit stream corresponding to a video data block, the video data block having a size; receiving a signaling notification indicating that since the video data block has a size S×T, at least one of S and T is a power of two The video data block is divided as a zero unit (ZU) block, and the block is divided using a division scheme selected from the group of ZU block division schemes; and based on signaling, the bit stream corresponding to the unit is decoded to reconstruct the video data Piece. Here, the group of ZU block partitioning schemes is a subset of the group of partitioning schemes available for partitioning coding units (CU).

在另一示例方面,公開了另一種視頻處理的方法。該方法包括由於視頻數據塊具有尺寸,尺寸的至少一個是非二的冪數,確定視頻數據塊將被編碼為零單元(ZU)塊;在確定ZU塊位於I條帶或幀內編碼圖片中時,將ZU塊劃分為兩個單元、三個單元或四個單元中的一個;編碼單元;以及在位元流中信令通知編碼的單元。 In another example aspect, another method of video processing is disclosed. The method includes determining that the video data block will be encoded as a zero unit (ZU) block because the video data block has a size, and at least one of the sizes is a power of two; when determining that the ZU block is located in an I slice or an intra-coded picture , Divide the ZU block into one of two units, three units, or four units; coding units; and signaling coding units in the bit stream.

在另一示例方面,公開了另一種視頻處理的方法。該方法包括接收對應於視頻數據塊的位元流,視頻數據塊具有尺寸;接收信令通知,該信令通知指示視頻數據塊包括從零單元(ZU)塊劃分的單元,零單元(ZU)塊具有至少高度或寬度為非二的冪數,並且在無變換和殘差編碼的情況下被編碼,劃分的ZU塊位於I條帶或幀內編碼圖片中;以及基於信令通知,解碼對應於單元的位元流以重建視頻數據塊。 In another example aspect, another method of video processing is disclosed. The method includes receiving a bit stream corresponding to a video data block, the video data block having a size; receiving a signaling notification indicating that the video data block includes a unit divided from a zero unit (ZU) block, the zero unit (ZU) A block has at least a height or width that is a non-power of two, and is coded without transform and residual coding. The divided ZU block is located in the I slice or intra-coded picture; and based on the signaling notification, the corresponding decoding The bit stream of the unit is used to reconstruct the video data block.

在另一代表性方面中,上述方法以處理器可執行代碼的形式體現並且儲存在電腦可讀程式介質中。 In another representative aspect, the above method is embodied in the form of processor executable code and stored in a computer-readable program medium.

在另一代表性方面中,公開了一種配置為或可操作為進行上述方法的設備。該設備可以包括處理器,該處理器被程式設計以實現該方法。 In another representative aspect, an apparatus configured or operable to perform the above method is disclosed. The device may include a processor that is programmed to implement the method.

在另一代表性方面中,視頻解碼器裝置可實現如本文所述的方法。 In another representative aspect, a video decoder device may implement the method as described herein.

在附圖、說明書和權利要求中更詳細地描述了本公開的技術的上述和其它方面和特徵。 The above and other aspects and features of the technology of the present disclosure are described in more detail in the drawings, specification and claims.

1400、1500、1800、1900:方法 1400, 1500, 1800, 1900: methods

1410~1420、1510~1530、1802~1806、1902~1904:步驟 1410~1420, 1510~1530, 1802~1806, 1902~1904: steps

1600:電腦系統 1600: computer system

1605:一個或多個處理器 1605: one or more processors

1610:記憶體 1610: memory

1615:網路介面控制器 1615: network interface controller

1625:互連 1625: Interconnect

1700:移動設備 1700: mobile devices

1701:處理器/控制器 1701: processor/controller

1702:記憶體 1702: memory

1703:I/O介面 1703: I/O interface

1704:顯示器 1704: display

圖1示出了典型的高效視頻編碼(HEVC)視訊轉碼器和解碼器的示例框圖。 Figure 1 shows an example block diagram of a typical High Efficiency Video Coding (HEVC) video transcoder and decoder.

圖2示出了H.264/AVC中的巨集區塊(MB)劃分的示例。 Figure 2 shows an example of macro block (MB) division in H.264/AVC.

圖3示出了將編碼塊(CB)分割成預測塊(PB)的示例。 Fig. 3 shows an example of dividing a coding block (CB) into prediction blocks (PB).

圖4A和圖4B分別示出了將編碼樹塊(CTB)細分為CB和變換塊(TB)以及相應的四叉樹的示例。 4A and 4B respectively show examples of subdividing the coding tree block (CTB) into CB and transform block (TB) and the corresponding quadtree.

圖5示出了一幀的劃分結構的示例。 Fig. 5 shows an example of the division structure of one frame.

圖6A和圖6B分別示出了在圖5中的示例性幀中突出顯示的CTB的細分和信令方法。 6A and 6B respectively show the subdivision and signaling method of CTB highlighted in the exemplary frame in FIG. 5.

圖7A和圖7B示出了用於最大編碼單元(LCU)的細分和相應的QTBT(四叉樹加二叉樹)的示例。 Figures 7A and 7B show examples of subdivision for the largest coding unit (LCU) and the corresponding QTBT (quadtree plus binary tree).

圖8A至圖8E示出了劃分編碼塊的示例。 8A to 8E show examples of dividing coding blocks.

圖9示出了基於QTBT的CB的示例細分。 Figure 9 shows an example subdivision of QTBT-based CB.

圖10A至圖10I示出了支援多樹類型(MTT)的CB的劃分的示例,其中多樹類型(MTT)是QTBT的一般化。 FIGS. 10A to 10I show examples of the division of CBs that support the multi-tree type (MTT), where the multi-tree type (MTT) is a generalization of QTBT.

圖11示出了樹類型信令的示例。 Fig. 11 shows an example of tree type signaling.

圖12A至圖12C示出了跨越圖片邊界的CTB的示例。 12A to 12C show examples of CTB crossing the picture boundary.

圖13示出了圖片邊界處的零單元的示例。 Fig. 13 shows an example of zero cells at the picture boundary.

圖14示出了根據本公開的技術的用於視頻編碼的示例方法的流程圖。 FIG. 14 shows a flowchart of an example method for video encoding according to the technology of the present disclosure.

圖15示出了根據本公開的技術的用於視頻解碼的另一示例方法的流程圖。 FIG. 15 shows a flowchart of another example method for video decoding according to the technology of the present disclosure.

圖16是示出可用於實現本公開技術的各個部分的電腦系統或其它控制設備的架構的示例的框圖。 FIG. 16 is a block diagram showing an example of the architecture of a computer system or other control device that can be used to implement various parts of the disclosed technology.

圖17示出了可用於實現本公開技術的各個部分的移動設備的示例實施例的框圖。 FIG. 17 shows a block diagram of an example embodiment of a mobile device that can be used to implement various parts of the disclosed technology.

圖18是視頻處理的示例方法的流程圖。 Figure 18 is a flowchart of an example method of video processing.

圖19是視頻處理的示例方法的流程圖。 Figure 19 is a flowchart of an example method of video processing.

由於對更高解析度視頻的需求日益增加,視頻編碼方法和技術在現代技術中無處不在。視頻轉碼器通常包括壓縮或解壓縮數位視訊的電子電路或軟體,並且視頻轉碼器被不斷改進以提供更高的編碼效率。視頻轉碼器將未壓縮視訊轉換為壓縮格式,或反之亦然。視頻品質、用於表示視頻的資料量(由位元速率確定)、編碼和解碼演算法的複雜性、對資料去失和錯誤的敏感性、編輯便利性、隨機訪問以及端到端延遲(遲延)之間存在複雜的關係。壓縮格式通常符合標準視訊壓縮規範,例如高效視頻編碼(HEVC)標準(也稱為H.265或MPEG-H第2部分)、即將最終 確定的通用視頻編碼標準,或其它當前和/或未來的視頻編碼標準。 Due to the increasing demand for higher-resolution video, video coding methods and technologies are ubiquitous in modern technologies. Video transcoders usually include electronic circuits or software that compress or decompress digital video, and video transcoders are continuously improved to provide higher coding efficiency. The video codec converts uncompressed video to a compressed format, or vice versa. Video quality, the amount of data used to represent the video (determined by the bit rate), the complexity of encoding and decoding algorithms, the sensitivity to data loss and error, editing convenience, random access, and end-to-end latency (delay ) Has a complicated relationship. The compression format usually conforms to standard video compression specifications, such as the High Efficiency Video Coding (HEVC) standard (also known as H.265 or MPEG-H Part 2), which will be finalized Determined general video coding standards, or other current and/or future video coding standards.

所公開的技術的實施例可以應用於現有的視頻編碼標準(例如,HEVC,H.265)和未來的標準以改善壓縮性能。在本文件中使用章節標題來提高描述的可讀性而不是以任何方式將討論或實施例(和/或實現方式)僅限於各個章節。 The embodiments of the disclosed technology can be applied to existing video coding standards (for example, HEVC, H.265) and future standards to improve compression performance. In this document, chapter headings are used to improve the readability of the description, rather than limiting the discussion or embodiments (and/or implementation) to each chapter in any way.

在本文件中使用章節標題以便於理解,並且不將章節中公開的實施例僅限於該章節。此外,雖然參考通用視頻編碼或其它特定視頻轉碼器描述了某些實施例,但是所公開的技術還可應用於其它視頻編碼技術。此外,雖然一些實施例詳細描述了視頻編碼步驟,但是應當理解的是,撤銷編碼的相應解碼步驟將由解碼器實現。此外,術語視頻處理包括視頻編碼或壓縮、視頻解碼或解壓縮以及視頻轉碼,其中視頻像素從一種壓縮格式表示為另一壓縮格式或以不同的壓縮位元速率表示。 The chapter titles are used in this document to facilitate understanding, and the embodiments disclosed in the chapter are not limited to this chapter. In addition, although certain embodiments have been described with reference to general video coding or other specific video transcoders, the disclosed technology can also be applied to other video coding technologies. In addition, although some embodiments describe the video encoding step in detail, it should be understood that the corresponding decoding step of de-encoding will be implemented by the decoder. In addition, the term video processing includes video encoding or compression, video decoding or decompression, and video transcoding, in which video pixels are expressed from one compression format to another compression format or at different compression bit rates.

1.視頻編碼的示例實施例 1. Example embodiment of video encoding

圖1示出了典型HEVC視訊編碼器和解碼器的示例性框圖。產生符合HEVC的位元流的編碼演算法通常如下進行。每個圖片被分割為塊狀區域,其中精確的塊劃分被傳送到解碼器。視頻序列的第一圖片(以及在對視頻序列的每個乾淨隨機訪問點處的第一圖片)僅使用幀內預測(在同一圖片內使用區域到區域的空間上的資料的一些預測,而不基於其它圖片)進行編碼。對於序列的所有剩餘圖片或隨機訪問點之間的圖片,對於大多數塊通 常使用幀間時間預測編碼模式。幀間預測的編碼過程包括選擇包含選定的參考圖片和運動向量(MV)的運動資料,該參考圖片和運動向量(MV)將被應用於預測每個塊的樣本。編碼器和解碼器通過應用運動補償(MC)來生成相同的幀間預測信號,該運動補償(MC)使用作為輔助信息發送的MV和模式決定資料。 Figure 1 shows an exemplary block diagram of a typical HEVC video encoder and decoder. The coding algorithm for generating a bit stream conforming to HEVC usually proceeds as follows. Each picture is divided into block regions, where the precise block division is transmitted to the decoder. The first picture of the video sequence (and the first picture at each clean random access point of the video sequence) only uses intra prediction (some predictions of the data from area to area are used in the same picture, without Based on other pictures) for encoding. For all remaining pictures of the sequence or pictures between random access points, for most blocks The inter-frame temporal prediction coding mode is often used. The encoding process of inter prediction includes selecting motion data containing selected reference pictures and motion vectors (MV), which will be applied to predict the samples of each block. The encoder and decoder generate the same inter prediction signal by applying motion compensation (MC), which uses MV and mode decision data sent as auxiliary information.

通過線性空間變換對幀內預測或幀間預測的殘差信號進行變換,其中該殘差信號是原始塊與其預測之間的差異。然後對變換係數進行縮放、量化、熵編碼並與預測信息一起發送。 The residual signal of intra-frame prediction or inter-frame prediction is transformed by linear spatial transformation, where the residual signal is the difference between the original block and its prediction. Then the transform coefficients are scaled, quantized, entropy coded and sent with the prediction information.

編碼器複製解碼器處理環路(見圖1中的灰色陰影框),使得兩者都將為後續資料生成相同的預測。因此,量化的變換係數通過逆縮放構造,並且然後進行逆變換以複製殘差信號的解碼的近似值。然後將殘差加入到預測中,並且然後可以將該加法的結果輸入一個或兩個環路濾波器,以平滑由逐塊處理和量化引起的偽影(artifact)。最終的圖片表示(即解碼器輸出的複製)儲存在解碼的圖片緩衝器中以用於後續圖片的預測。通常,圖片的編碼或解碼處理的順序常常不同於它們從來源到達的順序,需要區分解碼器的解碼順序(即位元流順序)和輸出順序(即顯示順序)。 The encoder replicates the decoder processing loop (see the gray shaded box in Figure 1) so that both will generate the same prediction for subsequent data. Therefore, the quantized transform coefficient is constructed by inverse scaling, and then inversely transformed to reproduce the decoded approximation of the residual signal. The residual is then added to the prediction, and the result of this addition can then be input to one or two loop filters to smooth out artifacts caused by block-by-block processing and quantization. The final picture representation (ie, a copy of the decoder output) is stored in the decoded picture buffer for prediction of subsequent pictures. Generally, the order of encoding or decoding processing of pictures is often different from the order in which they arrive from the source, and it is necessary to distinguish the decoding order (ie, bit stream order) and output order (ie, display order) of the decoder.

通常期望將由HEVC編碼的視頻材料作為逐行掃描圖像輸入(由於源視頻源自該格式或者由於由編碼之前的去隔行(deinterlacing)產生)。在HEVC設計中不存在顯式編碼特徵以支援隔行掃描的使用,因為隔行掃描不再用於顯示器,並且在分佈時變得非常不常見。但是,已經在HEVC中提供了中繼資料語 法以允許編碼器指示,隔行掃描的視頻已經通過將隔行掃描視頻的每個場(即每個視頻幀的偶數或奇數行)編碼為單獨的圖片而被發送,或者隔行掃描的視頻已經通過將每個隔行掃描的幀編碼為HEVC編碼的圖片而被發送。這提供了一種有效的編碼隔行掃描的視頻的方法,而無需加重解碼器需支援隔行掃描的視頻的特殊的解碼過程的負擔。 It is generally desirable to input video material encoded by HEVC as a progressive image (because the source video originates from this format or because it is produced by deinterlacing before encoding). There is no explicit coding feature in the HEVC design to support the use of interlaced scanning, because interlaced scanning is no longer used in displays and becomes very uncommon in distribution. However, the metadata language has been provided in HEVC The method allows the encoder to indicate that the interlaced video has been transmitted by encoding each field of the interlaced video (that is, the even or odd lines of each video frame) as a separate picture, or that the interlaced video has been transmitted Each interlaced frame is coded as a HEVC coded picture and sent. This provides an effective method of encoding interlaced video without adding to the burden of a special decoding process that the decoder needs to support interlaced video.

1.1.H.264/AVC中的劃分樹結構的示例 1.1. Example of partition tree structure in H.264/AVC

先前標準中的編碼層的核心是巨集塊,包含16×16的亮度(luma)樣本塊、以及在4:2:0顏色採樣的通常情況下的兩個對應的8×8的色度(chroma)樣本塊。 The core of the coding layer in the previous standard is a macro block, which contains a block of 16×16 luma samples and two corresponding 8×8 chroma in the usual case of 4:2:0 color sampling ( chroma) Sample block.

幀內編碼塊使用空間預測來利用像素之間的空間相關性。兩種劃分被定義為:16x16和4x4。 Intra-coded blocks use spatial prediction to take advantage of the spatial correlation between pixels. Two divisions are defined as: 16x16 and 4x4.

幀間編碼塊通過估計圖片之間的運動來使用時間預測而不是空間預測。可以對於16x16巨集區塊或其任何子巨集區塊劃分16x8、8x16、8x8、8x4、4x8、4x4來獨立地估計運動,如圖2所示。每子巨集區塊劃分僅允許一個運動向量(MV)。 The inter coding block uses temporal prediction instead of spatial prediction by estimating the motion between pictures. The 16x16 macro block or any of its sub-macro blocks can be divided into 16x8, 8x16, 8x8, 8x4, 4x8, 4x4 to independently estimate the motion, as shown in FIG. 2. Only one motion vector (MV) is allowed per sub-macro block partition.

1.2.HEVC中的劃分樹結構的示例 1.2. Example of partition tree structure in HEVC

在HEVC中,通過使用表示為編碼樹的四叉樹結構將編碼樹單元(CTU)劃分成編碼單元(CU),以適應各種局部特性。使用幀間(時間)預測還是幀內(空間)預測來對圖片區域進行編碼的決定是在CU級做出的。根據預測單元(PU)劃分類型,每個CU可以進一步劃分成一個、兩個或四個PU。在一個PU內 部,應用相同的預測過程,並且在PU的基礎上將相關信息發送到解碼器。在通過基於PU劃分類型應用預測過程而獲得了殘差塊之後,可以根據類似於CU的編碼樹的另一個四叉樹結構將CU劃分為變換單元(TU)。HEVC結構的關鍵特徵之一是它具有多個劃分概念,包括CU、PU和TU。 In HEVC, a coding tree unit (CTU) is divided into coding units (CU) by using a quad-tree structure expressed as a coding tree to adapt to various local characteristics. The decision to use inter (temporal) prediction or intra (spatial) prediction to encode picture regions is made at the CU level. According to the prediction unit (PU) division type, each CU can be further divided into one, two or four PUs. In one PU Part, apply the same prediction process, and send relevant information to the decoder based on the PU. After the residual block is obtained by applying a prediction process based on the PU division type, the CU may be divided into transformation units (TU) according to another quad-tree structure similar to the coding tree of the CU. One of the key features of the HEVC structure is that it has multiple partition concepts, including CU, PU, and TU.

對使用HEVC的混合視頻編碼中涉及的某些特徵包括: Some of the features involved in hybrid video encoding using HEVC include:

(1)編碼樹單元(CTU)和編碼樹塊(CTB)結構:HEVC中的類似結構是編碼樹單元(CTU),其具有由編碼器選擇的尺寸並且可以大於傳統巨集區塊。CTU由亮度CTB和相應的色度CTB以及語法元素組成。亮度CTB的尺寸L×L可以被選擇為L=16、32或64個樣本,較大的尺寸通常能夠實現更好的壓縮。然後,HEVC支援使用樹結構和類似四叉樹的信令來將CTB劃分為更小的塊。 (1) Coding tree unit (CTU) and coding tree block (CTB) structure: A similar structure in HEVC is a coding tree unit (CTU), which has a size selected by the encoder and can be larger than a traditional macro block. CTU is composed of luminance CTB and corresponding chrominance CTB and syntax elements. The size of the luminance CTB L×L can be selected as L=16, 32, or 64 samples, and a larger size can usually achieve better compression. Then, HEVC supports the use of tree structure and quadtree-like signaling to divide the CTB into smaller blocks.

(2)編碼單元(CU)和編碼塊(CB):CTU的四叉樹語法指定其亮度CB和色度CB的尺寸和位置。四叉樹的根與CTU相關聯。因此,亮度CTB的尺寸是亮度CB的最大支持尺寸。將CTU劃分成亮度CB和色度CB是信令聯合的。一個亮度CB和通常兩個色度CB以及相關聯的語法一起形成編碼單元(CU)。CTB可以僅包含一個CU或者可以被劃分以形成多個CU,並且每個CU具有相關聯的、向預測單元(PU)以及變換單元(TU)的樹的劃分。 (2) Coding Unit (CU) and Coding Block (CB): The quadtree syntax of CTU specifies the size and location of its luminance CB and chrominance CB. The root of the quadtree is associated with the CTU. Therefore, the size of the brightness CTB is the maximum supported size of the brightness CB. The division of CTU into luminance CB and chrominance CB is combined in signaling. One luma CB and usually two chroma CBs and the associated syntax together form a coding unit (CU). The CTB may contain only one CU or may be divided to form multiple CUs, and each CU has an associated division into a tree of prediction units (PU) and transformation units (TU).

(3)預測單元和預測塊(PB):使用幀間圖片預測還是 幀內圖片預測來對圖片區域編碼的決策是在CU級進行的。PU劃分結構的根在CU級。取決於基本預測類型決策,然後可以在尺寸上進一步劃分亮度CB和色度CB,並根據亮度和色度預測塊(PB)對其進行預測。HEVC支援從64×64到4×4樣本的可變PB尺寸。圖3示出了對於M×M CU所允許的PB的示例。 (3) Prediction unit and prediction block (PB): whether to use inter picture prediction or The decision of intra-picture prediction to encode picture regions is made at the CU level. The root of the PU partition structure is at the CU level. Depending on the basic prediction type decision, the luminance CB and chrominance CB can then be further divided in size and predicted based on the luminance and chrominance prediction blocks (PB). HEVC supports variable PB sizes from 64×64 to 4×4 samples. Fig. 3 shows an example of PB allowed for M×M CU.

(4)變換單元(TU)和變換塊:使用塊變換對預測殘差進行編碼。TU樹結構的根在CU級。亮度CB殘差可以與亮度變換塊(TB)相同,或者可以被進一步劃分成更小的亮度TB。這同樣適用於色度TB。對於正方形TB尺寸4×4、8×8、16×16和32×32,定義類似於離散余弦變換(DCT)的整數基函數。對於亮度幀內圖片預測殘差的4×4變換,可以替代地指定從離散正弦變換(DST)的形式導出的整數變換。 (4) Transform unit (TU) and transform block: use block transform to encode prediction residuals. The root of the TU tree structure is at the CU level. The luminance CB residual may be the same as the luminance transform block (TB), or may be further divided into smaller luminance TB. The same applies to chroma TB. For square TB sizes of 4×4, 8×8, 16×16, and 32×32, an integer basis function similar to a discrete cosine transform (DCT) is defined. For the 4×4 transform of the luma intra picture prediction residuals, an integer transform derived from the form of discrete sine transform (DST) can be specified instead.

1.2.1.樹結構的劃分到TB和TU的示例 1.2.1. Example of dividing the tree structure into TB and TU

對於殘差編碼,可以將CB遞迴地劃分為變換塊(TB)。由殘差四叉樹信令通知劃分。僅指定正方形CB和TB劃分,其中塊可以被遞迴地劃分到象限(quadrant),如圖4所示。對於尺寸為M×M的給定亮度CB,標誌(flag)表明是否將該CB劃分成四個尺寸為M/2×M/2的塊。如果如SPS中指示的殘差四叉樹的最大深度所信令通知的,每個象限能夠進一步劃分,則為每個象限分配標誌,該標誌指示是否將其劃分成四個象限。由殘差四叉樹產生的葉節點塊是變換塊,通過變換編碼對其進一步處理。編碼器指示它將使用的最大和最小亮度TB尺寸。當CB尺寸大於最大 TB尺寸時,劃分是隱含的。當劃分將導致亮度TB尺寸小於所指示的最小值時,不劃分是隱含的。除了當亮度TB尺寸為4×4時,色度TB尺寸在每個維度上是亮度TB尺寸的一半,在亮度TB尺寸為4×4的情況下,單個4×4色度TB被用於由四個4×4亮度TB覆蓋的區域。在幀內圖片預測的CU的情況下,最近鄰的TB(在CB內或在CB外)的解碼後樣本被用作用於幀內圖片預測的參考資料。 For residual coding, CB can be recursively divided into transform blocks (TB). The division is notified by residual quadtree signaling. Only square CB and TB divisions are specified, where blocks can be recursively divided into quadrants, as shown in Figure 4. For a given brightness CB with a size of M×M, a flag indicates whether to divide the CB into four blocks with a size of M/2×M/2. If, as signaled by the maximum depth of the residual quadtree indicated in the SPS, each quadrant can be further divided, a flag is assigned to each quadrant, which indicates whether to divide it into four quadrants. The leaf node block generated by the residual quadtree is a transform block, which is further processed by transform coding. The encoder indicates the maximum and minimum brightness TB size it will use. When the CB size is greater than the maximum In TB size, the division is implicit. When the division will result in the luminance TB size being smaller than the indicated minimum value, no division is implicit. Except when the luminance TB size is 4×4, the chrominance TB size is half of the luminance TB size in each dimension. When the luminance TB size is 4×4, a single 4×4 chrominance TB is used by Area covered by four 4×4 brightness TBs. In the case of a CU for intra picture prediction, the decoded samples of the nearest neighbor TB (within or outside the CB) are used as reference material for intra picture prediction.

與先前的標準相反,HEVC設計允許TB跨越多個PB以用於幀間預測的CU,以使四叉樹結構的TB劃分的潛在編碼效率益處最大化。 Contrary to previous standards, the HEVC design allows TBs to span multiple PBs for inter-predicted CUs, so as to maximize the potential coding efficiency benefits of quad-tree TB partitioning.

1.2.2.圖片邊界編碼的示例 1.2.2. Example of picture boundary coding

圖片的邊界以最小允許的亮度CB大小為單位定義。因此,在圖片的右邊界和底邊界,一些CTU可能會覆蓋部分位於圖片邊界之外的區域。該條件被解碼器檢測到,並且CTU四叉樹根據需要被隱式地分割,以將CB大小減小到整個CB將適合到圖片中的程度。 The boundary of the picture is defined in units of the minimum allowable brightness CB size. Therefore, at the right and bottom borders of the picture, some CTUs may cover part of the area outside the picture boundary. This condition is detected by the decoder, and the CTU quadtree is implicitly partitioned as needed to reduce the CB size to the extent that the entire CB will fit in the picture.

圖5示出了一個幀的劃分結構的示例,其中解析度為416×240像素,尺寸為7CTB×4CTB,其中CTB的大小為64×64。如圖5所示,部分位於右邊界和底邊界之外的CTB具有隱含的分割(虛線,表示為502),並且完全落在外面的CU就被跳過(不被編碼)。 FIG. 5 shows an example of the division structure of a frame, where the resolution is 416×240 pixels, the size is 7CTB×4CTB, and the size of CTB is 64×64. As shown in FIG. 5, the CTB partially located outside the right and bottom borders has an implicit segmentation (dashed line, denoted as 502), and the CUs that are completely outside are skipped (not encoded).

在圖5所示的示例中,突出顯示的CTB(504),其行CTB 索引等於2且列CTB索引等於3,在當前圖片內具有64×48像素,並且不適合64×64CTB。因此,它被強制分割為32×32而沒有分割標誌信號。對於左上角的32×32,它被幀完全覆蓋。當它選擇根據速率-失真成本以較小的塊編碼時(對於左上角的16×16用8×8,並且其餘的以16×16編碼),需要編碼幾個分割標誌。這些分割標誌(用於是否將左上角的32×32分割為四個16×16塊的一個標誌,以及用於信令通知一個16×16是否被進一步分割,以及對於在左上角的16×16中的四個8×8塊中的每一個是否進一步分割8×8的標誌)必須被明確地信令通知。右上角的32×32塊存在類似情況。對於兩個底部32×32塊,因為它們部分位於圖片邊界(506)的外部,需要應用進一步的QT分割而不用信令通知。圖6A和6B分別示出了圖5中突出顯示的CTB(504)的細分和信令方法。 In the example shown in Figure 5, the highlighted CTB (504), the line CTB The index is equal to 2 and the column CTB index is equal to 3, which has 64×48 pixels in the current picture and is not suitable for 64×64 CTB. Therefore, it is forcibly divided into 32×32 without a division flag signal. For the 32×32 in the upper left corner, it is completely covered by the frame. When it chooses to encode in smaller blocks according to the rate-distortion cost (8x8 for 16x16 in the upper left corner, and 16x16 for the rest), it needs to encode several segmentation marks. These division flags (a flag for whether to divide the 32×32 in the upper left corner into four 16×16 blocks, and for signaling whether a 16×16 is further divided, and for the 16×16 in the upper left corner Whether each of the four 8×8 blocks is further divided by the 8×8 flag) must be clearly signaled. A similar situation exists in the 32×32 block in the upper right corner. For the two bottom 32×32 blocks, because they are partially located outside the picture boundary (506), further QT segmentation needs to be applied without signaling. 6A and 6B respectively show the subdivision and signaling method of the CTB (504) highlighted in FIG. 5.

1.2.3.CTB大小指示的示例 1.2.3. Example of CTB size indication

表1中示出了用於一般序列參數集的示例RBSP(原始字節序列有效載荷)語法表。 An example RBSP (Raw Byte Sequence Payload) syntax table for the general sequence parameter set is shown in Table 1.

Figure 108122735-A0305-02-0015-1
Figure 108122735-A0305-02-0015-1
Figure 108122735-A0305-02-0016-2
Figure 108122735-A0305-02-0016-2

相應的語義包括:log2_min_luma_coding_block_size_minus3 加3指定最小亮度編碼塊大小;以及log2_diff_max_min_luma_coding_block_size 指定最大亮度編碼塊大小和最小亮度編碼塊大小之間的差異。 The corresponding semantics include: log2_min_luma_coding_block_size_minus3 plus 3 specifies the minimum luminance coding block size; and log2_diff_max_min_luma_coding_block_size specifies the difference between the maximum luminance coding block size and the minimum luminance coding block size.

變數:MinCbLog2SizeY,CtbLog2SizeY,MinCbSizeY,CtbSizeY,PicWidthInMinCbsY,PicWidthInCtbsY,PicHeightInMinCbsY,PicHeightInCtbsY,PicSizeInMinCbsY,PicSizeInCtbsY,PicSizeInSamplesY,PicWidthInSamplesC和PicHeightInSamplesC通過以下得到:MinCbLog2SizeY=log2_min_luma_coding_block_size_minus3+3 Variables: MinCbLog2SizeY, CtbLog2SizeY, MinCbSizeY, CtbSizeY, PicWidthInMinCbsY, PicWidthInCtbsY, PicHeightInMinCbsY, PicHeightInCtbsY, PicSizeInMinCbsY, PicSizeInCtbsY, PicSizeInSamplesY, PicWidthInSamplesC and PicHeightInSamplesC obtained by: MinCbLog2SizeY = log2_min_luma_coding_block_size_minus3 + 3

CtbLog2SizeY=MinCbLog2SizeY+log2_diff_max_min_luma_coding_block_size CtbLog2SizeY=MinCbLog2SizeY+log2_diff_max_min_luma_coding_block_size

MinCbSizeY=1<<MinCbLog2SizeY MinCbSizeY=1<<MinCbLog2SizeY

CtbSizeY=1<<CtbLog2SizeY CtbSizeY=1<<CtbLog2SizeY

PicWidthInMinCbsY=pic_width_in_luma_samples/MinCbSizeY PicWidthInMinCbsY=pic_width_in_luma_samples/MinCbSizeY

PicWidthInCtbsY=Ceil (pic_width_in_luma_samples÷CtbSizeY) PicWidthInCtbsY=Ceil (pic_width_in_luma_samples÷CtbSizeY)

PicHeightInMinCbsY=pic_height_in_luma_samples/MinCbSizeY PicHeightInMinCbsY=pic_height_in_luma_samples/MinCbSizeY

PicHeightInCtbsY=Ceil(pic_height_in_luma_samples÷CtbSizeY) PicHeightInCtbsY=Ceil(pic_height_in_luma_samples÷CtbSizeY)

PicSizeInMinCbsY=PicWidthInMinCbsY*PicHeightInMinCbsY PicSizeInMinCbsY=PicWidthInMinCbsY*PicHeightInMinCbsY

PicSizeInCtbsY=PicWidthInCtbsY*PicHeightInCtbsY PicSizeInCtbsY=PicWidthInCtbsY*PicHeightInCtbsY

PicSizeInSamplesY=pic_width_in_luma_samples*pic_height_in_luma_samples PicSizeInSamplesY=pic_width_in_luma_samples*pic_height_in_luma_samples

PicWidthInSamplesC=pic_width_in_luma_samples/SubWidthC PicWidthInSamplesC=pic_width_in_luma_samples/SubWidthC

PicHeightInSamplesC=pic_height_in_luma_samples/SubHeightC PicHeightInSamplesC=pic_height_in_luma_samples/SubHeightC

變數CtbWidthC和CtbHeightC,其分別指定每個色度CTB陣列的寬度和高度,通過以下得到:如果chroma_format_idc等於0(單色)或者separate_colour_plane_flag等於1,則CtbWidthC和CtbHeightC都等於0;否則,CtbWidthC和CtbHeightC通過以下得到:CtbWidthC=CtbSizeY/SubWidthC The variables CtbWidthC and CtbHeightC, which respectively specify the width and height of each chroma CTB array, are obtained by the following: if chroma_format_idc is equal to 0 (monochrome) or separate_colour_plane_flag is equal to 1, then CtbWidthC and CtbHeightC are both equal to 0; otherwise, CtbWidthC and CtbHeightC pass The following gets: CtbWidthC=CtbSizeY/SubWidthC

CtbHeightC=CtbSizeY/SubHeightC CtbHeightC=CtbSizeY/SubHeightC

1.3.在JEM中具有較大CTU的四叉樹加二叉樹塊結構的示例 1.3. Example of quadtree plus binary tree block structure with larger CTU in JEM

在一些實施例中,使用被稱為聯合探索模型(JEM)的參考軟體探索未來的視頻編碼技術。除二叉樹結構外,JEM還描述了四叉樹加二叉樹(QTBT)和三叉樹(TT)結構。 In some embodiments, reference software called Joint Exploration Model (JEM) is used to explore future video coding technologies. In addition to the binary tree structure, JEM also describes the quad-tree plus binary tree (QTBT) and tri-tree (TT) structures.

1.3.1.QTBT塊劃分結構的示例 1.3.1. Example of QTBT block partition structure

與HEVC相比,QTBT結構消除了多種劃分類型的概念,即它消除了CU、PU和TU概念的區別,並為CU劃分形狀提供了更大的靈活性。在QTBT塊結構中,CU可以具有正方形或矩形形狀。如圖7A所示,首先用四叉樹結構劃分編碼樹單元(CTU)。四叉樹葉節點進一步由二叉樹結構劃分。在二叉樹分割中有兩種分割類型,對稱水平分割和對稱垂直分割。二叉樹葉節點被稱為編碼單元(CU),並且該分段用於預測和變換處理而無需任何進一步劃分。這意味著CU、PU和TU在QTBT編碼塊結構中具有相同的塊大小。在JEM中,CU有時由不同顏色分量的編碼塊(CB)組成--例如,一個CU在4:2:0色度格式的P和B條帶的情況下包含一個亮度CB和兩個色度CB;並且有時由單個分量的CB組成--例如,一個CU在I條帶的情況下僅包含一個亮度CB或僅兩個的色度CB。 Compared with HEVC, the QTBT structure eliminates the concept of multiple partition types, that is, it eliminates the difference between the concepts of CU, PU, and TU, and provides greater flexibility for CU partition shapes. In the QTBT block structure, the CU may have a square or rectangular shape. As shown in FIG. 7A, the coding tree unit (CTU) is first divided by a quadtree structure. The quad leaf node is further divided by a binary tree structure. There are two types of segmentation in binary tree segmentation, symmetric horizontal segmentation and symmetric vertical segmentation. The binary leaf node is called a coding unit (CU), and the segment is used for prediction and transformation processing without any further division. This means that CU, PU and TU have the same block size in the QTBT coding block structure. In JEM, a CU is sometimes composed of coding blocks (CB) of different color components - for example, a CU contains a luminance CB and two colors in the case of P and B strips in 4:2:0 chroma format. Degree CB; and sometimes composed of a single component CB-for example, a CU contains only one luminance CB or only two chrominance CB in the case of I stripe.

為QTBT劃分方案定義了以下參數: The following parameters are defined for the QTBT division scheme:

- CTU大小:四叉樹的根節點大小,與HEVC中的概念相同 -CTU size: the size of the root node of the quadtree, the same concept as in HEVC

- MinQTSize:最小允許的四叉樹葉節點大小 -MinQTSize: the minimum allowable quad leaf node size

- MaxBTSize:最大允許的二叉樹根節點大小 -MaxBTSize: the maximum allowable size of the root node of the binary tree

- MaxBTDepth:最大允許的二叉樹深度 -MaxBTDepth: Maximum allowable binary tree depth

- MinBTSize:最小允許的二叉樹葉節點大小 -MinBTSize: the minimum allowable size of a binary leaf node

在QTBT劃分結構的一個示例中,CTU大小設置為128×128個亮度樣本,以及兩個相應的64×64色度樣本塊,MinQTSize設置為16×16,MaxBTSize設置為64×64,MinBTSize(對於寬度和高度兩者)設置為4×4,並且MaxBTDepth設置為4。四叉樹劃分首先應用於CTU以生成四叉樹葉節點。四叉樹葉節點可以具有從16×16(即,MinQTSize)到128×128(即,CTU大小)的大小。如果四叉樹葉節點為128×128,則它將不會被二叉樹進一步分割,因為大小超過了MaxBTSize(即64×64)。否則,四叉樹葉節點可以被二叉樹進一步分割。因此,四叉樹葉節點也是二叉樹的根節點,並且其具有二叉樹深度為0。當二叉樹深度達到MaxBTDepth(即4)時,不考慮進一步的分割。當二叉樹節點的寬度等於MinBTSize(即4)時,不考慮進一步的水平分割。類似地,當二叉樹節點的高度等於MinBTSize時,不考慮進一步的垂直分割。通過預測和變換處理進一步處理二叉樹的葉節點,而無需任何進一步的劃分。在JEM中,最大CTU大小為256×256亮度樣本。 In an example of the QTBT division structure, the CTU size is set to 128×128 luma samples and two corresponding 64×64 chroma sample blocks, MinQTSize is set to 16×16, MaxBTSize is set to 64×64, MinBTSize (for Both width and height) are set to 4×4, and MaxBTDepth is set to 4. The quadtree division is first applied to CTU to generate quad-leaf nodes. The quad leaf node may have a size from 16×16 (ie, MinQTSize) to 128×128 (ie, CTU size). If the quad leaf node is 128×128, it will not be further divided by the binary tree because the size exceeds MaxBTSize (ie 64×64). Otherwise, the quad leaf node can be further divided by the binary tree. Therefore, the quad leaf node is also the root node of the binary tree, and it has a binary tree depth of zero. When the depth of the binary tree reaches MaxBTDepth (ie 4), no further division is considered. When the width of the binary tree node is equal to MinBTSize (ie 4), no further horizontal division is considered. Similarly, when the height of the binary tree node is equal to MinBTSize, no further vertical division is considered. The leaf nodes of the binary tree are further processed through prediction and transformation processing without any further division. In JEM, the maximum CTU size is 256×256 luminance samples.

圖7A示出了通過使用QTBT進行塊劃分的示例。圖7B示出了相應的樹表示。實線指示四叉樹分割,並且虛線指示二叉 樹分割。在二叉樹的每個分割(即,非葉)節點中,用信號通知一個標誌以指示使用哪種分割類型(即,水平或垂直),其中0指示水平分割,並且1指示垂直分割。對於四叉樹分割,不需要指示分割類型,因為四叉樹分割總是同時水平和垂直地分割塊以產生具有相同大小的4個子塊。 FIG. 7A shows an example of block division by using QTBT. Figure 7B shows the corresponding tree representation. The solid line indicates the quadtree division, and the dashed line indicates the binary Tree split. In each split (ie, non-leaf) node of the binary tree, a flag is signaled to indicate which split type (ie, horizontal or vertical) is used, where 0 indicates horizontal split, and 1 indicates vertical split. For quadtree partitioning, there is no need to indicate the partition type, because quadtree partitioning always splits the block horizontally and vertically at the same time to generate 4 sub-blocks with the same size.

此外,QTBT方案支援亮度和色度具有單獨的QTBT結構的能力。目前,對於P和B條帶,一個CTU中的亮度和色度CTB共用相同的QTBT結構。然而,對於I條帶,亮度CTB通過QTBT結構劃分為CU,並且色度CTB通過另一QTBT結構劃分為色度CU。這意味著I條帶中的CU由亮度分量的編碼塊或兩個色度分量的編碼塊組成,並且P或B條帶中的CU由所有三個顏色分量的編碼塊組成。 In addition, the QTBT solution supports the ability to have separate QTBT structures for luminance and chrominance. Currently, for P and B strips, the luminance and chrominance CTB in a CTU share the same QTBT structure. However, for the I slice, the luma CTB is divided into CUs by the QTBT structure, and the chroma CTB is divided into chrominance CUs by another QTBT structure. This means that the CU in the I slice consists of coding blocks of the luma component or two chrominance components, and the CU in the P or B slice consists of coding blocks of all three color components.

在HEVC中,限制小塊的幀間預測以減少運動補償的記憶體訪問,使得對於4×8和8×4塊不支持雙向預測,並且對於4×4塊不支持幀間預測。在JEM的QTBT中,這些限制被移除。 In HEVC, inter prediction of small blocks is restricted to reduce memory access for motion compensation, so that bi-directional prediction is not supported for 4×8 and 8×4 blocks, and inter prediction is not supported for 4×4 blocks. In JEM's QTBT, these restrictions are removed.

1.4.用於多功能視頻編碼(VVC)的三叉樹(TT) 1.4. Trinomial Tree (TT) for Multifunctional Video Coding (VVC)

圖8A示出了四叉樹(QT)劃分的示例,並且圖8B和8C分別示出了垂直和水平二叉樹(BT)劃分的示例。在一些實施例中,除了四叉樹和二叉樹之外,還支持三叉樹(TT)劃分,例如水平和垂直中心側三叉樹(如圖8D和8E所示)。 FIG. 8A shows an example of quadtree (QT) division, and FIGS. 8B and 8C show examples of vertical and horizontal binary tree (BT) division, respectively. In some embodiments, in addition to quadtrees and binary trees, tri-tree (TT) division is also supported, such as horizontal and vertical center-side tri-trees (as shown in FIGS. 8D and 8E).

在一些實現方式中,支援兩個級別的樹:區域樹(四叉樹)和預測樹(二叉樹或三叉樹)。首先通過區域樹(RT)對CTU 進行劃分。RT葉可以進一步用預測樹(PT)分割。還可以用PT進一步分割PT葉,直到達到最大PT深度。PT葉是基本的編碼單元。為方便起見,它仍被稱為CU。CU無法進一步分割。預測和變換都以與JEM相同的方式應用於CU。整個劃分結構稱為“多類型樹”。 In some implementations, two levels of trees are supported: regional trees (quadtrees) and prediction trees (binary trees or ternary trees). First pass the area tree (RT) to the CTU Divide. The RT leaf can be further divided by prediction tree (PT). PT can also be used to further segment the PT leaf until the maximum PT depth is reached. The PT leaf is the basic coding unit. For convenience, it is still called CU. CU cannot be divided further. Both prediction and transformation are applied to CU in the same way as JEM. The whole partition structure is called "multi-type tree".

1.5.替代視頻編碼技術中的劃分結構的示例 1.5. Examples of alternative partition structures in video coding technology

在一些實施例中,支持稱為多樹類型(MTT)的樹結構(其是QTBT的一般化)。在QTBT中,如圖9所示,首先用四叉樹結構劃分編碼樹單元(CTU)。四叉樹葉節點進一步由二叉樹結構劃分。 In some embodiments, a tree structure called a multi-tree type (MTT) (which is a generalization of QTBT) is supported. In QTBT, as shown in FIG. 9, the coding tree unit (CTU) is first divided by a quadtree structure. The quad leaf node is further divided by a binary tree structure.

MTT的結構由兩種類型的樹節點構成:區域樹(RT)和預測樹(PT),支援九種類型的劃分,如圖10A至10I所示。區域樹可以遞迴地將CTU分割成方形塊,直到分成4×4大小的區域的葉節點。在區域樹中的每個節點處,可以從三種樹類型中的一個形成預測樹:二叉樹、三叉樹和非對稱二叉樹。在PT分割中,禁止在預測樹的分支中具有四叉樹劃分。與在JEM中一樣,亮度樹和色度樹在I條帶中分開。 The structure of MTT is composed of two types of tree nodes: regional tree (RT) and prediction tree (PT), which supports nine types of divisions, as shown in Figures 10A to 10I. The area tree can recursively divide the CTU into square blocks until it is divided into leaf nodes of 4×4 areas. At each node in the area tree, a prediction tree can be formed from one of three tree types: binary tree, trinomial tree, and asymmetric binary tree. In PT partitioning, it is prohibited to have quadtree partitions in the branches of the prediction tree. As in JEM, the luminance tree and the chrominance tree are separated in the I strip.

通常,除了上下文推導之外,RT信令與JEM中的QT信令相同。對於PT信令,需要多達4個額外的二進位位元(bin),如圖11所示。第一個二進位位元指示PT是否被進一步分割。該二進位位元的上下文基於對進一步分割的可能性與當前塊與其相鄰塊的相對大小高度相關的觀察來計算。如果進一步分割PT,則 第二個二進位位元指示其是水平劃分還是垂直劃分。在一些實施例中,中心側三叉樹和非對稱二叉樹(ABT)的存在增加了“高”塊或“寬”塊的出現。第三個二進位位元表示劃分的樹的類型,即它是二叉樹/三叉樹還是非對稱二叉樹。在二叉樹/三叉樹的情況下,第四個二進位位元表示樹的類型。在非對稱二叉樹的情況下,第四個二進位位元指示對於水平劃分樹的向上或向下類型,對於垂直劃分樹的向右或向左類型。 Generally, RT signaling is the same as QT signaling in JEM except for context derivation. For PT signaling, up to 4 additional binary bits (bin) are required, as shown in Figure 11. The first binary bit indicates whether the PT is further divided. The context of the binary bit is calculated based on the observation that the possibility of further segmentation is highly correlated with the relative size of the current block and its neighboring blocks. If the PT is further divided, then The second binary bit indicates whether it is divided horizontally or vertically. In some embodiments, the presence of center-side trinomial trees and asymmetric binary trees (ABT) increases the appearance of "high" blocks or "wide" blocks. The third binary bit indicates the type of the divided tree, that is, whether it is a binary tree/trinomial tree or an asymmetrical binary tree. In the case of a binary tree/trinomial tree, the fourth binary bit indicates the type of tree. In the case of an asymmetric binary tree, the fourth binary bit indicates the upward or downward type for horizontally divided trees, and the right or leftward type for vertically divided trees.

1.5.1.圖片邊界處的限制的示例 1.5.1. Examples of restrictions at the picture boundary

在一些實施例中,如果CTB/LCU大小由M×N指示(通常M等於N,如HEVC/JEM中所定義),並且對於位於圖片(或片或條帶或其它類型)邊界的CTB,K×L個樣本處於圖片邊界內。 In some embodiments, if the CTB/LCU size is indicated by M×N (usually M is equal to N, as defined in HEVC/JEM), and for CTB located at the boundary of a picture (or slice or slice or other types), K ×L samples are within the picture boundary.

在圖片底邊界和右邊界上的CU分割規則可以應用於任何編碼樹配置QTBT+TT、QTBT+ABT或QTBT+TT+ABT。它們包括以下兩個方面: The CU segmentation rules on the bottom and right edges of the picture can be applied to any coding tree configuration QTBT+TT, QTBT+ABT or QTBT+TT+ABT. They include the following two aspects:

(1)如果給定編碼樹節點(CU)的一部分部分地位於圖片外部,則總是允許沿著相關邊界方向(沿著底邊界的水平分割定向,如圖12A所示,沿右邊界的垂直分割定向,如圖12B所示)的CU的二元對稱分割。如果當前CU的右下角在幀外(如圖12C所示),則只允許CU的四叉樹分割。另外,如果當前二叉樹深度大於最大二叉樹深度並且當前CU在幀邊界上,則啟用二元分割以確保到達幀邊界。 (1) If a part of a given coding tree node (CU) is partially located outside the picture, it is always allowed along the relevant boundary direction (horizontal split orientation along the bottom boundary, as shown in Figure 12A, along the vertical Splitting orientation, as shown in Figure 12B) for binary symmetrical splitting of CU. If the lower right corner of the current CU is outside the frame (as shown in FIG. 12C), only the quadtree division of the CU is allowed. In addition, if the current binary tree depth is greater than the maximum binary tree depth and the current CU is on the frame boundary, binary segmentation is enabled to ensure that the frame boundary is reached.

(2)關於三叉樹分割過程,在產生的子CU之間的第一邊界或第二邊界恰好位於圖片的邊界上的情況下,允許三叉樹分割。如果分割線(由分割產生的兩個子CU之間的邊界)與圖片邊界完全匹配,則允許不對稱二叉樹分割。 (2) Regarding the trinomial tree segmentation process, in the case where the first boundary or the second boundary between the generated sub-CUs is exactly on the boundary of the picture, the trinomial tree segmentation is allowed. If the partition line (the boundary between the two sub-CUs resulting from the partition) exactly matches the picture boundary, an asymmetric binary tree partition is allowed.

2.現有實現方式的示例 2. Examples of existing implementations

現有實現方式,CTU或CU的寬度或高度可能不等於2N,其中N是正整數。這些情況很難處理。具體來說,如果行數或列數不是2N的形式,則可能難以設計具有不包括除法的整數運算的變換。 In existing implementations, the width or height of the CTU or CU may not be equal to 2 N , where N is a positive integer. These situations are difficult to handle. Specifically, if the number of rows or the number of columns is not in the form of 2N , it may be difficult to design a transformation with integer operations that does not include division.

在一個示例中,為了避免CTU或CU具有不等於2N的寬度或高度,CTU或CU被強制分割為更小,直到寬度和高度兩者都是2N的形式或通過填充或使用變換跳過。如果以更靈活的方式處理這些塊,則可以進一步改善編碼增益。 In one example, in order to prevent the CTU or CU from having a width or height that is not equal to 2 N , the CTU or CU is forced to be divided into smaller ones until both the width and height are in the form of 2 N or skip by padding or using transform . If these blocks are processed in a more flexible way, the coding gain can be further improved.

在另一個示例中,對於寬度或高度不是2N形式的CU定義變換。這種變換在實際的視頻編碼應用中是不期望的。 In another example, a transformation is defined for a CU whose width or height is not in the form of 2N . This transformation is undesirable in actual video coding applications.

3.使用基於本公開的技術的零單元的示例方法 3. Example method using zero unit based on the technology of the present disclosure

本公開的技術的實施例克服了現有實施方式的缺點,從而為視頻編碼提供了更高的效率。具體地,提出零單元塊作為特殊的CU/CTU,並且塊在當且僅當其高度和/或寬度不是2N的形式時被解釋為零單元。 The embodiments of the technology of the present disclosure overcome the shortcomings of existing implementations, thereby providing higher efficiency for video encoding. Specifically, a zero unit block is proposed as a special CU/CTU, and the block is interpreted as a zero unit if and only if its height and/or width are not in the form of 2N .

在以下針對各種實現方式所描述的示例中闡明了使用零單元來提高視頻編碼效率並增強現有和未來的視頻編碼標準。下 面提供的本公開的技術的示例解釋了一般概念,並不意欲被解釋為限制。在示例中,除非明確地相反指示,否則可以組合這些示例中描述的各種特徵。在另一示例中,這些示例中描述的各種特徵可以應用於使用向後相容的塊大小的圖片邊界編碼和使用劃分樹進行可視媒體編碼的方法。圖13示出了圖片邊界處的零單元(具有像素或樣本的尺寸)的示例。 In the following examples described for various implementations, the use of zero units to improve video coding efficiency and enhance existing and future video coding standards is clarified. under The examples of the technology of the present disclosure provided above explain general concepts and are not intended to be construed as limitations. In the examples, unless explicitly indicated to the contrary, the various features described in these examples may be combined. In another example, the various features described in these examples can be applied to a method of picture boundary coding using a backward compatible block size and visual media coding using a partition tree. FIG. 13 shows an example of a zero unit (having the size of pixels or samples) at the picture boundary.

示例A. 零單元可以進一步分割為兩個單元(BT或ABT)、三個單元(TT、FTT)或四個單元(QT、EQT)。從零單元分割的分割單元可以是零單元,或者它可以是正常CU,其具有2N的形式的寬度或高度。假設零單位Z的大小為S×T。 Example A. The zero unit can be further divided into two units (BT or ABT), three units (TT, FTT) or four units (QT, EQT). The division unit divided from the zero unit may be a zero unit, or it may be a normal CU, which has a width or height in the form of 2N . Assume that the size of the zero unit Z is S×T.

(a)在一個示例中,Z可以用BT分割為兩個單元,二者具有大小為S/2×T。 (a) In an example, Z can be divided into two units using BT, both of which have a size of S/2×T.

(b)在一個示例中,Z可以用BT分割為兩個單元,二者具有大小為S×T/2。 (b) In an example, Z can be divided into two units using BT, both of which have a size of S×T/2.

(c)在一個示例中,假設2N<S

Figure 108122735-A0305-02-0024-3
2N+1,Z可以用BT分割為兩個單元,其具有大小為2N×T和(S-2N)×T,或(S-2N)×T和2N×T。 (c) In an example, assume that 2 N <S
Figure 108122735-A0305-02-0024-3
Figure 108122735-A0305-02-0024-3
2 N+1 , Z can be divided into two units by BT, which have sizes of 2 N ×T and (S-2 N )×T, or (S-2 N )×T and 2 N ×T.

(d)在一個示例中,假設2N<T

Figure 108122735-A0305-02-0024-4
2N+1,Z可以用BT分割為兩個單元,其具有大小為S×2N和S×(T-2N),或S×(T-2N)和S×2N。 (d) In an example, assume that 2 N <T
Figure 108122735-A0305-02-0024-4
Figure 108122735-A0305-02-0024-4
2 N+1 , Z can be divided into two units with BT, which have sizes of S×2 N and S×(T-2 N ), or S×(T-2 N ) and S×2 N.

(e)在一個示例中,Z可以用TT分割為三個單元,其具有大小為S/4×T、S/2×T和S/4×T。 (e) In an example, Z can be divided into three units with TT, which have sizes of S/4×T, S/2×T, and S/4×T.

(f)在一個示例中,Z可以用TT分割為三個單元,其具有大小為S×T/4、S×T/2和S×T/4。 (f) In an example, Z can be divided into three units with TT, which have sizes of S×T/4, S×T/2, and S×T/4.

(g)在一個示例中,假設2N<S<2N+1,Z可以用TT分割為三個單元,其具有大小為2N-1×T、2N-1×T和(S-2N)×T,或2N-1×T、(S-2N)×T和2N-1×T,或(S-2N)×T、2N-1×T和2N-1×T。 (g) In an example, assuming that 2 N <S <2 N +1, Z can be divided into three units by TT, which have sizes 2 N-1 ×T, 2 N-1 ×T and (S- 2 N )×T, or 2 N-1 ×T, (S-2 N )×T and 2 N-1 ×T, or (S-2 N )×T, 2 N-1 ×T and 2 N- 1 ×T.

(h)在一個示例中,假設2N<T

Figure 108122735-A0305-02-0025-5
2N+1,Z可以用TT分割為三個單元,其具有大小為S×2N-1、S×2N-1和S×(T-2N),或S×2N-1、S×(T-2N)和S×2N-1,或S×(T-2N)、S×2N-1和S×2N-1。 (h) In an example, assume that 2 N <T
Figure 108122735-A0305-02-0025-5
Figure 108122735-A0305-02-0025-5
2 N+1 , Z can be divided into three units with TT, which have sizes of S×2 N-1 , S×2 N-1 and S×(T-2 N ), or S×2 N-1 , S×(T-2 N ) and S×2 N-1 , or S×(T-2 N ), S×2 N-1 and S×2 N-1 .

(i)在一個示例中,Z可以用QT分割為四個單元,均具有大小為S/2×T/2。 (i) In an example, Z can be divided into four units by QT, each of which has a size of S/2×T/2.

(j)在一個示例中,假設2N<S

Figure 108122735-A0305-02-0025-6
2N+1,Z可以用QT分割為四個單元,具有大小為2N×T/2、2N×T/2、(S-2N)×T/2和(S-2N)×T/2,或(S-2N)×T/2、(S-2N)×T/2、2N×T/2和2N×T/2。 (j) In an example, assume that 2 N <S
Figure 108122735-A0305-02-0025-6
Figure 108122735-A0305-02-0025-6
2 N+1 , Z can be divided into four units by QT, with sizes of 2 N ×T/2, 2 N ×T/2, (S-2 N )×T/2 and (S-2 N )× T/2, or (S-2 N )×T/2, (S-2 N )×T/2, 2 N ×T/2, and 2 N ×T/2.

(k)在一個示例中,假設2N<T

Figure 108122735-A0305-02-0025-8
2N+1,Z可以用QT分割為四個單元,具有大小為S/2×2N、S/2×2N、S/2×(T-2N)和S/2×(T-2N),或S/2×(T-2N)、S/2×(T-2N)、S/2×2N和S/2×2N。 (k) In an example, assume that 2 N <T
Figure 108122735-A0305-02-0025-8
Figure 108122735-A0305-02-0025-8
2 N+1 , Z can be divided into four units by QT, with sizes S/2×2 N , S/2×2 N , S/2×(T-2 N ) and S/2×(T- 2 N ), or S/2×(T-2 N ), S/2×(T-2 N ), S/2×2 N and S/2×2 N.

(l)在一個示例中,假設2N<S

Figure 108122735-A0305-02-0025-9
2N+1和2M<T
Figure 108122735-A0305-02-0025-10
2M+1,Z可以用QT分割為四個單元,具有大小為2N×2M、2N×2M、(S-2N)×(T-2M)和(S-2N)×(T-2M),或(S-2N)×(T-2M)、(S-2N)×(T-2M)、2N×2M和2N×2M,或2N×(T-2M)、2N×(T-2M)、(S-2N)×2M和(S-2N)×2M,或(S-2N)×2M、(S-2N)×2M、2N×(T-2M)和2N×(T-2M)。 (l) In an example, assume that 2 N <S
Figure 108122735-A0305-02-0025-9
Figure 108122735-A0305-02-0025-9
Figure 108122735-A0305-02-0025-9
2 N+1 and 2 M <T
Figure 108122735-A0305-02-0025-10
Figure 108122735-A0305-02-0025-10
2 M+1 , Z can be divided into four units by QT, with sizes of 2 N × 2 M , 2 N × 2 M , (S-2 N ) × (T-2 M ) and (S-2 N ) ×(T-2 M ), or (S-2 N )×(T-2 M ), (S-2 N )×(T-2M), 2 N ×2 M and 2 N ×2 M , or 2 N × (T-2 M ), 2 N × (T-2 M ), (S-2 N ) × 2M and (S-2 N ) × 2 M , or (S-2 N ) × 2 M , ( S-2 N )×2 M , 2 N ×(T-2 M ) and 2 N ×(T-2 M ).

(m)在一個示例中,所有分割單元的寬度/高度應為偶 數。如果一個劃分結構導致單元的寬度或高度為奇數,則自動禁止這樣的劃分結構。 (m) In an example, the width/height of all division units should be even number. If a division structure results in an odd number of unit width or height, such division structure is automatically prohibited.

或者,此外,跳過這種劃分結構的信令。 Or, in addition, skip the signaling of this division structure.

(n)在一個示例中,Z可以用TT分割為三個單元。 (n) In an example, Z can be divided into three units with TT.

在一個示例中,假設3*2N<S<=3*2N+1,三個單元的大小分別為2N×T、2N+1×T和(S-3*2N)×T。 In an example, assuming 3*2 N <S<=3*2 N+1 , the sizes of the three units are 2 N ×T, 2 N+1 ×T, and (S-3*2 N )×T .

在一個示例中,假設3*2N<T<=3*2N+1,三個單元的大小分別為Sx2N、Sx2N+1和S×(T-3*2N)。 In an example, assuming 3*2 N <T<=3*2 N +1, the sizes of the three units are Sx2 N , Sx2 N+1, and S×(T-3*2 N ).

(o)在一個示例中,所有分割單元的寬度和/或高度應為K * M的形式,其中M是允許的編碼單元/預測單元的最小寬度和/或高度,諸如4;K是大於0的整數。如果一個劃分結構導致單元的寬度或高度不是這樣的形式,則自動禁止該劃分結構。 (o) In an example, the width and/or height of all partition units should be in the form of K*M, where M is the minimum width and/or height of the allowed coding unit/prediction unit, such as 4; K is greater than 0 The integer. If a division structure causes the width or height of the unit to be not in this form, the division structure is automatically prohibited.

例如,假設劃分結構中分割單元的寬度和高度為W和H,如果W<M或H<M或(W&(M-1)!=0)或(H&(M-1)!=0),則禁止該劃分結構。 For example, assuming that the width and height of the division unit in the division structure are W and H, if W<M or H<M or (W&(M-1)!=0) or (H&(M-1)!=0), The division structure is prohibited.

或者,此外,跳過這種劃分結構的信令。 Or, in addition, skip the signaling of this division structure.

或者,所有分割的非ZU的寬度和/或高度應為K*M的形式,其中M是允許的編碼單元/預測單元的最小寬度和/或高度,諸如4。在這種情況下,如果分割的零單元不遵循此限制但非ZU遵循此限制,則仍允許劃分結構。 Alternatively, the width and/or height of all partitioned non-ZUs should be in the form of K*M, where M is the minimum width and/or height of the allowed coding unit/prediction unit, such as 4. In this case, if the divided zero unit does not follow this restriction but the non-ZU follows this restriction, the structure is still allowed to be divided.

示例B. ZU的分割信令方法與正常CU的分割信令方法相同。 Example B. The split signaling method of ZU is the same as that of normal CU.

a.在一個示例中,可以使用不同的上下文來編碼ZU或非ZU。 a. In one example, different contexts can be used to encode ZU or non-ZU.

b.或者,對於ZU,僅允許正常CU的部分分割方法。 b. Or, for ZU, only partial division methods of normal CU are allowed.

i.對ZU所允許的正常CU的分割方法的子集由ZU大小和/或圖片/條帶/片邊界位置(底部、右部、右下部等)和/或條帶類型確定。 i. The subset of normal CU segmentation methods allowed by ZU is determined by ZU size and/or picture/strip/slice boundary position (bottom, right, bottom right, etc.) and/or strip type.

ii.在一個示例中,對於ZU只允許QT和BT劃分結構。 ii. In one example, only QT and BT partition structures are allowed for ZU.

iii.或者,此外,在ZU分割信息中不發信號通知是否使用TT以及如何使用TT(以及除QT/BT之外的其它種類的劃分結構)。 iii. Or, in addition, the ZU division information does not signal whether to use TT and how to use TT (and other types of division structures except QT/BT).

iv.或者,此外,ZU的分割信令方法仍然與正常CU的分割信令方法保持相同,然而,TT(或其它類型的劃分結構)的指示的上下文可以進一步取決於當前塊是否是ZU。 iv. Or, in addition, the split signaling method of ZU remains the same as the split signaling method of normal CU, however, the context of the indication of TT (or other type of partition structure) may further depend on whether the current block is a ZU.

示例C. 在一個實施例中,ZU必須在I條帶或幀內編碼圖像中分割。 Example C. In one embodiment, ZU must be segmented in I-slice or intra-coded images.

在一個示例中,ZU的寬度或高度不是2N的形式。 In one example, the width or height of ZU is not in the form of 2N.

在一個示例中,則當以下條件成立時,CU被視為ZU, In one example, when the following conditions are true, CU is regarded as ZU,

i)W>=T0且H>=T1。T0和/或T1是諸如128或256的整數。 i) W>=T0 and H>=T1. T0 and/or T1 are integers such as 128 or 256.

ii)W>=T0或H>=T1。T0和/或T1是諸如128或256的整數。 ii) W>=T0 or H>=T1. T0 and/or T1 are integers such as 128 or 256.

iii)W×H>=T。T是諸如16384或65536的整數。 iii) W×H>=T. T is an integer such as 16384 or 65536.

上述示例可以結合在下面描述的方法的上下文中--例如,方法1400和1500,其可以在視頻解碼器和/或視訊轉碼器處實現。 The above examples can be combined in the context of the methods described below-for example, methods 1400 and 1500, which can be implemented at the video decoder and/or video transcoder.

圖14示出了用於視頻編碼的示例性方法的流程圖,其可以在視訊轉碼器中實現。方法1400包括,在步驟1410處,確定視頻數據塊的尺寸。 Figure 14 shows a flowchart of an exemplary method for video encoding, which can be implemented in a video transcoder. The method 1400 includes, at step 1410, determining the size of the video data block.

方法1400包括,在步驟1420處,在確定至少一個尺寸是非二的冪時,將視頻數據塊作為零單元(ZU)塊來信令通知,其是不可變換的。 The method 1400 includes, at step 1420, when it is determined that at least one size is a power of two, signaling the video data block as a zero unit (ZU) block, which is not transformable.

在一些實施例中,非二的冪是不能以2N的形式表示的任何非零數字。例如,不包括二的冪的整數(例如,1,3,5,6,7,9,10,11,12,13,14,15,17,18,...)的每個都是非二的冪。 In some embodiments, a non-two power is any non-zero number that cannot be expressed in the form of 2N. For example, each integer that does not include a power of two (for example, 1, 3, 5, 6, 7, 9, 10, 11, 12, 13, 14, 15, 17, 18,...) is non-two The power of.

在一些實施例中,可以在示例2的上下文中定義不可變換,使得不對零單元調用變換、逆變換、量化和去量化操作。例如,零單元的不可變換屬性是其被推斷為用跳過模式進行編碼,並且因此,不需要明確地用信令通知跳過模式。在其它實施例中,可以在示例3的上下文中定義不可變換,使得儘管可能存在非零殘差,但對於零單元沒有定義變換和逆變換操作。 In some embodiments, non-transformable can be defined in the context of Example 2, so that transform, inverse transform, quantization, and dequantization operations are not invoked on zero units. For example, the non-transformable property of a zero unit is that it is inferred to be encoded with skip mode, and therefore, there is no need to explicitly signal skip mode. In other embodiments, non-transformation may be defined in the context of Example 3, so that although there may be non-zero residuals, the transformation and inverse transformation operations are not defined for the zero unit.

圖15示出了用於視頻編碼的另一示例性方法的流程圖,該方法可以在視頻解碼器中實現。該流程圖包括與圖14中所示並且在上面描述的類似的一些特徵和/或步驟。本章節中可能未單獨描述這些特徵和/或步驟中的至少一些。 FIG. 15 shows a flowchart of another exemplary method for video encoding, which may be implemented in a video decoder. The flowchart includes some features and/or steps similar to those shown in FIG. 14 and described above. At least some of these features and/or steps may not be separately described in this section.

方法1500包括,在步驟1510處,接收對應於視頻數據塊的位元流。 The method 1500 includes, at step 1510, receiving a bit stream corresponding to a block of video data.

方法1500包括,在步驟1520處,接收信令,其指示視頻數據塊是零單元(ZU)塊,該零單元(ZU)塊是不可變換的,並且具有非二的冪的至少一個尺寸。 The method 1500 includes, at step 1520, receiving signaling indicating that the video data block is a zero unit (ZU) block, the zero unit (ZU) block is not transformable, and has at least one size that is not a power of two.

方法1500包括,在步驟1530處,基於信令解碼位元流以重建視頻數據塊。 The method 1500 includes, at step 1530, decoding the bitstream based on the signaling to reconstruct the video data block.

在一些實施例中,方法1400和方法1500,以及如在示例1的上下文中所描述的,可以進一步包括視頻數據塊的尺寸是偶數,具有2N形式,或者具有2KN的形式,其中K=1,2,3,4...。在其它實施例中,信令可以不包括合併索引或跳過標記、和/或不包括prediction_mode_flag、和/或包括ZU塊的至少一個尺寸的最大值或最小值。在示例中,信令在視頻參數集(VPS)、序列參數集(SPS)、圖片參數集(PPS)、條帶標頭、編碼樹單元(CTU)或編碼單元(CU)中。 In some embodiments, the method 1400 and the method 1500, and as described in the context of Example 1, may further include that the size of the video data block is an even number, has a form of 2N, or has a form of 2KN, where K=1, 2, 3, 4.... In other embodiments, the signaling may not include a merge index or skip flag, and/or not include prediction_mode_flag, and/or include the maximum or minimum value of at least one size of the ZU block. In an example, the signaling is in a video parameter set (VPS), a sequence parameter set (SPS), a picture parameter set (PPS), a slice header, a coding tree unit (CTU), or a coding unit (CU).

在一些實施例中,ZU塊的運動信息從大小為2N×2M的相鄰塊的運動信息繼承。 In some embodiments, the motion information of the ZU block is inherited from the motion information of neighboring blocks of size 2N×2M.

在一個實施例中,並且如在示例7的上下文中所描述的,ZU塊被分割為兩個或更多個單元。在示例中,兩個或更多個單元中的至少一個是零單元。在另一個示例中,在兩個或更多個單元中的至少一個是尺寸為2N×2M的編碼單元(CU)。 In one embodiment, and as described in the context of Example 7, the ZU block is divided into two or more units. In an example, at least one of the two or more cells is a zero cell. In another example, at least one of the two or more units is a coding unit (CU) with a size of 2N×2M.

4.所公開的技術的示例實現方式 4. Example implementation of the disclosed technology

圖16是示出可以用於實現本公開的技術的各個部分的電腦系統或其它控制設備1600的架構的示例的框圖,本公開的技術包括(但不限於)方法1400和方法1500。在圖16中,電腦系統1600包括經由互連1625連接的一個或多個處理器1605和記憶體1610。互連1625可以代表通過適當的橋接器、適配器連接的任何一個或多個單獨的物理匯流排、點對點連接或兩者。因此,互連1625可以包括例如,系統匯流排、周邊元件連接(PCI)匯流排、雙向傳輸匯流排(HyperTransport)或工業標準架構(ISA)匯流排、小型電腦系統介面(SCSI)匯流排、通用序列匯流排(USB)、IIC(I2C)匯流排或電氣和電子工程師協會(IEEE)標準674匯流排,有時也稱為「Firewire」。 16 is a block diagram showing an example of the architecture of a computer system or other control device 1600 that can be used to implement various parts of the technology of the present disclosure. The technology of the present disclosure includes (but is not limited to) the method 1400 and the method 1500. In FIG. 16, a computer system 1600 includes one or more processors 1605 and a memory 1610 connected via an interconnection 1625. Interconnect 1625 may represent any one or more separate physical buses, point-to-point connections, or both, connected by suitable bridges, adapters. Therefore, the interconnection 1625 may include, for example, a system bus, a peripheral component connection (PCI) bus, a two-way transmission bus (HyperTransport) or an industry standard architecture (ISA) bus, a small computer system interface (SCSI) bus, a universal Serial bus (USB), IIC (I2C) bus or Institute of Electrical and Electronics Engineers (IEEE) standard 674 bus, sometimes called "Firewire".

(一個或多個)處理器1605可以包括中央處理單元(CPU)以控制例如主機電腦的整體操作。在某些實施例中,(一個或多個)處理器1605通過執行記憶體1610中儲存的軟體或韌體來實現這一點。(一個或多個)處理器1605可以是或可以包括一個或多個可程式設計通用或專用微處理器、數位訊號處理器(DSP)、可程式設計控制器、專用積體電路(ASIC)、可程式設計邏輯器件(PLD)等,或這些器件的組合。 The processor(s) 1605 may include a central processing unit (CPU) to control, for example, the overall operation of the host computer. In some embodiments, the processor(s) 1605 implements this by executing software or firmware stored in the memory 1610. The processor(s) 1605 may be or may include one or more programmable general-purpose or special-purpose microprocessors, digital signal processors (DSP), programmable controllers, special-purpose integrated circuits (ASIC), Programmable logic device (PLD), etc., or a combination of these devices.

記憶體1610可以是或可以包括電腦系統的主記憶體。記憶體1610表示任何合適形式的隨機存取記憶體(RAM)、唯讀記憶體(ROM)、快閃記憶體等,或其組合。在使用中,記憶體1610可以包含機器指令集,當由處理器1605執行該機器指令集時,使 得處理器1605進行操作以實現本公開技術的實施例。 The memory 1610 may be or include the main memory of the computer system. The memory 1610 represents any suitable form of random access memory (RAM), read-only memory (ROM), flash memory, etc., or a combination thereof. In use, the memory 1610 may contain a machine instruction set, and when the machine instruction set is executed by the processor 1605, The processor 1605 operates to implement the embodiments of the disclosed technology.

通過互連1625也連接到(一個或多個)處理器1605的是(可選的)網路介面控制器1615。網路介面控制器1615向電腦系統1600提供與遠端設備通信的能力,遠端設備例如儲存器用戶端和/或其它儲存器伺服器,並且網路介面控制器1615可以是例如乙太網介面控制器或光纖通道介面控制器。 Also connected to the processor(s) 1605 via the interconnect 1625 is an (optional) network interface controller 1615. The network interface controller 1615 provides the computer system 1600 with the ability to communicate with remote devices, such as a storage client and/or other storage servers, and the network interface controller 1615 may be, for example, an Ethernet interface Controller or Fibre Channel interface controller.

圖17示出了可用於實現本公開技術的各個部分的移動設備1700的示例實施例的框圖,包括(但不限於)方法1400和方法1500。移動設備1700可以是膝上型電腦、智慧型電話、平板電腦、可擕式攝像機或能夠處理視頻的其它類型的設備。移動設備1700包括用於處理資料的處理器或控制器1701,以及與處理器1701通信以儲存和/或緩衝資料的記憶體1702。例如,處理器1701可以包括中央處理單元(CPU)或微控制器單元(MCU)。在一些實現方式中,處理器1701可以包括現場可程式設計閘陣列(FPGA)。在一些實現方式中,移動設備1700包括用於智慧型電話設備的各種可視和/或通信資料處理功能的圖形處理單元(GPU)、視頻處理單元(VPU)和/或無線通訊單元或與之通信。例如,記憶體1702可以包括並儲存處理器可執行代碼,其在由處理器1701執行時配置移動設備1700以執行各種操作,例如接收信息、命令和/或資料,處理信息和資料,並且將處理後的信息/資料發送或提供給諸如致動器或外部顯示器的另一個設備。 FIG. 17 shows a block diagram of an example embodiment of a mobile device 1700 that can be used to implement various parts of the disclosed technology, including (but not limited to) method 1400 and method 1500. The mobile device 1700 may be a laptop computer, a smart phone, a tablet computer, a camcorder, or other types of devices capable of processing video. The mobile device 1700 includes a processor or controller 1701 for processing data, and a memory 1702 that communicates with the processor 1701 to store and/or buffer data. For example, the processor 1701 may include a central processing unit (CPU) or a microcontroller unit (MCU). In some implementations, the processor 1701 may include a field programmable gate array (FPGA). In some implementations, the mobile device 1700 includes or communicates with a graphics processing unit (GPU), a video processing unit (VPU) and/or a wireless communication unit for various visual and/or communication data processing functions of a smart phone device . For example, the memory 1702 may include and store processor-executable code, which when executed by the processor 1701 configures the mobile device 1700 to perform various operations, such as receiving information, commands and/or data, processing information and data, and processing The latter information/material is sent or provided to another device such as an actuator or external display.

為了支援移動設備1700的各種功能,記憶體1702可以 儲存信息和資料,諸如指令、軟體、值、圖像以及由處理器1701處理或參考的其它資料。例如,各種類型的隨機存取記憶體(RAM)設備、唯讀記憶體(ROM)設備、快閃記憶體設備和其它合適的儲存介質可已被用於實現記憶體1702的儲存功能。在一些實現方式中,移動設備1700包括輸入/輸出(I/O)介面1703,以將處理器1701和/或記憶體1702與其它模組、單元或設備介面。例如,I/O介面1703可以利用與典型資料通信標準(例如,在雲中的一個或多個電腦與使用者設備之間的)相容的各種類型的無線介面,以將處理器1701與記憶體1702介面。在一些實現方式中,移動設備1700可以經由I/O介面1703使用有線連接與其它設備介面。移動設備1700還可以與其它外部介面(例如資料記憶體)和/或視覺或音訊顯示器1704介面,以取回和傳送資料和信息,該資料和信息可由處理器處理、儲存在記憶體中或在顯示器1704或外部設備的輸出單元上展示。例如,顯示器1704可以顯示包括塊(CU、PU或TU)的視頻幀,該塊基於是否使用運動補償演算法並根據所公開的技術對塊進行編碼來應用塊內複製。 To support the various functions of the mobile device 1700, the memory 1702 can Store information and data, such as instructions, software, values, images, and other data processed or referenced by the processor 1701. For example, various types of random access memory (RAM) devices, read-only memory (ROM) devices, flash memory devices, and other suitable storage media may have been used to implement the storage function of the memory 1702. In some implementations, the mobile device 1700 includes an input/output (I/O) interface 1703 to interface the processor 1701 and/or the memory 1702 with other modules, units, or devices. For example, the I/O interface 1703 can utilize various types of wireless interfaces compatible with typical data communication standards (for example, between one or more computers in the cloud and the user equipment) to connect the processor 1701 with the memory Body 1702 interface. In some implementations, the mobile device 1700 can interface with other devices via the I/O interface 1703 using a wired connection. The mobile device 1700 can also interface with other external interfaces (such as data memory) and/or a visual or audio display 1704 to retrieve and transmit data and information. The data and information can be processed by a processor, stored in memory or in Display on the display 1704 or the output unit of the external device. For example, the display 1704 may display a video frame including a block (CU, PU, or TU) that applies intra-block copy based on whether a motion compensation algorithm is used and the block is encoded according to the disclosed technology.

在一些實施例中,視頻解碼器設備可以實現使用如本文中所描述的零單元的方法以用於視頻解碼。該方法的各種特徵可以類似於上述各種方法。 In some embodiments, the video decoder device may implement a method using zero units as described herein for video decoding. The various features of this method can be similar to the various methods described above.

在一些實施例中,視頻解碼方法可以使用解碼設備來實現,該解碼設備在如圖16和圖17中所述的硬體平臺上實現。 In some embodiments, the video decoding method may be implemented using a decoding device, which is implemented on a hardware platform as described in FIG. 16 and FIG. 17.

可以使用以下解決方案的列表來捕獲本文描述的一些實 施例。 The following list of solutions can be used to capture some of the practices described in this article Examples.

1.一種視頻編碼方法(例如,圖18中所描述的方法1800),包括:確定(步驟1802)視頻數據塊將被編碼為零單元(ZU)塊,視頻數據塊具有尺寸S×T;將ZU塊劃分(步驟1804)為兩個單元、三個單元或四個單元中的一個;以及通過編碼單元生成(步驟1806)位元流。 1. A video encoding method (for example, the method 1800 described in FIG. 18), comprising: determining (step 1802) that a video data block will be encoded into a zero unit (ZU) block, the video data block having a size of S×T; The ZU block is divided (step 1804) into one of two units, three units or four units; and a bit stream is generated (step 1806) through the coding unit.

2.一種視頻解碼方法(例如,圖19中所描述的方法1900)包括:接收(步驟1902)對應於編碼為零單元(ZU)塊的視頻數據塊的位元流,該零單元(ZU)塊被劃分為兩個單元、三個單元或四個單元,該視頻數據塊具有尺寸S×T;以及通過解碼位元流生成(步驟1904)視頻數據塊。 2. A video decoding method (for example, the method 1900 described in FIG. 19) includes: receiving (step 1902) a bit stream corresponding to a video data block encoded as a zero unit (ZU) block, the zero unit (ZU) The block is divided into two units, three units, or four units, the video data block has a size of S×T; and the video data block is generated (step 1904) by decoding the bit stream.

3.如解決方案1或2所述的方法,其中,ZU塊使用二叉樹劃分方案被劃分為兩個單元,每個ZU塊具有尺寸S/2×T。 3. The method according to solution 1 or 2, wherein the ZU block is divided into two units using a binary tree division scheme, and each ZU block has a size of S/2×T.

4.如解決方案1或2所述的方法,其中,ZU塊使用二叉樹劃分方案被劃分為兩個單元,每個單元具有尺寸S×T/2。 4. The method according to solution 1 or 2, wherein the ZU block is divided into two units using a binary tree division scheme, and each unit has a size of S×T/2.

5.如解決方案1或2所述的方法,其中,作為2N<S

Figure 108122735-A0305-02-0033-11
2N+1的ZU塊使用二叉樹劃分方案被劃分為兩個單元的結果,兩個單元的第一單元具有尺寸2N×T並且兩個單元的第二單元具有尺寸(S-2N)×T。 5. The method as described in solution 1 or 2, wherein, as 2 N <S
Figure 108122735-A0305-02-0033-11
Figure 108122735-A0305-02-0033-11
2 N+1 ZU block is divided into two units using a binary tree division scheme. The first unit of the two units has a size of 2 N × T and the second unit of the two units has a size of (S-2 N )× T.

6.如解決方案1或2所述的方法,其中,作為2N<S

Figure 108122735-A0305-02-0033-12
2N+1的ZU塊使用二叉樹劃分方案被劃分為兩個單元的結果,兩個單元的第一單元具有尺寸(S-2N)×T並且兩個單元的第二單元具有尺 寸2N×T。 6. The method according to solution 1 or 2, wherein, as 2 N <S
Figure 108122735-A0305-02-0033-12
Figure 108122735-A0305-02-0033-12
2 N+1 ZU block is divided into two units using a binary tree division scheme. The first unit of the two units has size (S-2 N )×T and the second unit of the two units has size 2 N × T.

7.如解決方案1或2所述的方法,其中,作為2N<T

Figure 108122735-A0305-02-0034-13
2N+1的ZU塊使用二叉樹劃分方案被劃分為兩個單元的結果,兩個單元的第一單元具有尺寸S×2N並且兩個單元的第二單元具有尺寸S×(T-2N)。 7. The method according to solution 1 or 2, wherein, as 2 N <T
Figure 108122735-A0305-02-0034-13
Figure 108122735-A0305-02-0034-13
2 N+1 ZU block is divided into two units using a binary tree division scheme. The first unit of the two units has a size of S×2 N and the second unit of the two units has a size of S×(T-2 N ).

8.如解決方案1或2所述的方法,其中,作為2N<T

Figure 108122735-A0305-02-0034-14
2N+1的ZU塊使用二叉樹劃分方案被劃分為兩個單元的結果,兩個單元的第一單元具有尺寸S×(T-2N)並且兩個單元的第二單元具有尺寸S×2N。 8. The method according to solution 1 or 2, wherein as 2 N <T
Figure 108122735-A0305-02-0034-14
Figure 108122735-A0305-02-0034-14
2 N+1 ZU block is divided into two units using a binary tree division scheme. The first unit of the two units has size S×(T-2 N ) and the second unit of the two units has size S×2 N.

9.如解決方案1或2所述的方法,其中,ZU塊使用三叉樹劃分方案被劃分為三個單元,三個單元中的兩個單元的每一個具有尺寸S/4×T並且三個單元中的一個單元具有尺寸S/2×T。 9. The method of solution 1 or 2, wherein the ZU block is divided into three units using a three-prong tree division scheme, and each of the two units of the three units has a size of S/4×T and three One of the cells has a size of S/2×T.

10.如解決方案1或2所述的方法,其中,ZU塊使用三叉樹劃分方案被劃分為三個單元,三個單元中的兩個具有尺寸S×T/4並且三個單元中的一個具有尺寸S×T/2。 10. The method according to solution 1 or 2, wherein the ZU block is divided into three units using a trigeminal tree division scheme, two of the three units have a size of S×T/4 and one of the three units It has a size of S×T/2.

11.如解決方案1或2所述的方法,其中,作為2N<S

Figure 108122735-A0305-02-0034-15
2N+1的ZU塊使用三叉樹劃分方案被劃分為三個單元的結果,第一單元具有尺寸2N-1×T,第二單元具有尺寸(S-2N)×T,並且第三單元具有尺寸2N-1×T。 11. The method according to solution 1 or 2, wherein as 2 N <S
Figure 108122735-A0305-02-0034-15
Figure 108122735-A0305-02-0034-15
2 N+1 ZU block is divided into three units using the trigeminal tree division scheme. The first unit has a size of 2 N-1 ×T, the second unit has a size of (S-2 N )×T, and the third The cell has a size of 2 N-1 ×T.

12.如解決方案1或2所述的方法,其中,作為2N<T

Figure 108122735-A0305-02-0034-17
2N+1的ZU塊使用三叉樹劃分方案被劃分為三個單元的結果,第一單元具有尺寸S×2N-1,第二單元具有尺寸S×(T-2N),並且第三單元具 有尺寸S×2N-1。 12. The method according to solution 1 or 2, wherein, as 2 N <T
Figure 108122735-A0305-02-0034-17
Figure 108122735-A0305-02-0034-17
2 N+1 ZU block is divided into three units using the tri-tree division scheme. The first unit has size S×2 N-1 , the second unit has size S×(T-2 N ), and the third The unit has a size of S×2 N-1 .

13.如解決方案1或2所述的方法,其中,ZU塊使用四叉樹劃分方案被劃分為四個單元,每個單元具有尺寸S/2×T/2。 13. The method of solution 1 or 2, wherein the ZU block is divided into four units using a quadtree division scheme, and each unit has a size of S/2×T/2.

14.如解決方案1或2所述的方法,其中,作為2N<S

Figure 108122735-A0305-02-0035-18
2N+1的ZU塊使用四叉樹劃分方案被劃分為四個單元的結果,第一單元具有尺寸2N×T/2,第二單元具有尺寸2N×T/2,並且第三單元具有尺寸S/2×(T-2N),並且第四單元具有尺寸S/2×(T-2N)。 14. The method according to solution 1 or 2, wherein as 2 N <S
Figure 108122735-A0305-02-0035-18
Figure 108122735-A0305-02-0035-18
2 N+1 ZU block is divided into four units using a quadtree division scheme. The first unit has a size of 2 N × T/2, the second unit has a size of 2 N × T/2, and the third unit It has a size of S/2×(T-2 N ), and the fourth cell has a size of S/2×(T-2 N ).

15.如解決方案1或2所述的方法,其中,作為2N<T

Figure 108122735-A0305-02-0035-19
2N+1的ZU塊使用四叉樹劃分方案被劃分為四個單元的結果,第一單元具有尺寸S/2×2N,第二單元具有尺寸S/2×2N,並且第三單元具有尺寸S/2×(T-2N),並且第四單元具有尺寸S/2×(T-2N)。 15. The method according to solution 1 or 2, wherein, as 2 N <T
Figure 108122735-A0305-02-0035-19
Figure 108122735-A0305-02-0035-19
2 N+1 ZU block is divided into four units using the quadtree division scheme. The first unit has size S/2×2 N , the second unit has size S/2×2 N , and the third unit It has a size of S/2×(T-2 N ), and the fourth cell has a size of S/2×(T-2 N ).

16.如解決方案1或2所述的方法,其中,作為2N<S

Figure 108122735-A0305-02-0035-20
2N+1並且2M<T
Figure 108122735-A0305-02-0035-21
2M+1的ZU塊使用四叉樹劃分方案被劃分為四個單元的結果,第一單元具有尺寸2N×2M,第二單元具有尺寸2N×2M,並且第三單元具有尺寸(S-2N)×(T-2M),並且第四單元具有尺寸(S-2N)×(T-2M)。 16. The method according to solution 1 or 2, wherein as 2 N <S
Figure 108122735-A0305-02-0035-20
Figure 108122735-A0305-02-0035-20
Figure 108122735-A0305-02-0035-20
2 N+1 and 2 M <T
Figure 108122735-A0305-02-0035-21
The ZU block of 2 M+1 is divided into four units using the quadtree division scheme. The first unit has a size of 2 N × 2 M , the second unit has a size of 2 N × 2 M , and the third unit has a size (S-2 N )×(T-2 M ), and the fourth unit has a size (S-2 N )×(T-2 M ).

17.如解決方案1或2所述的方法,其中,作為2N<S

Figure 108122735-A0305-02-0035-22
2N+1並且2M<T
Figure 108122735-A0305-02-0035-23
2M+1的ZU塊使用四叉樹劃分方案被劃分為四個單元的結果,第一單元具有尺寸2N×(T-2M),第二單元具有尺寸2N×(T-2M),並且第三單元具有尺寸(S-2N)×2M,並且第四單元具有尺寸(S-2N)×2M。 17. The method as described in solution 1 or 2, wherein as 2 N <S
Figure 108122735-A0305-02-0035-22
Figure 108122735-A0305-02-0035-22
Figure 108122735-A0305-02-0035-22
2 N+1 and 2 M <T
Figure 108122735-A0305-02-0035-23
The ZU block of 2 M+1 is divided into four units using the quadtree division scheme. The first unit has a size of 2 N ×(T-2 M ), and the second unit has a size of 2 N ×(T-2 M ), and the third unit has a size (S-2 N )×2 M , and the fourth unit has a size (S-2 N )×2M.

18.如解決方案1或2所述的方法,其中,ZU塊的每個 單元的高度和/或寬度是偶數。 18. The method according to solution 1 or 2, wherein each of the ZU blocks The height and/or width of the cell are even numbers.

19.如解決方案1或2所述的方法,其中,ZU塊使用三叉樹劃分方案被分割為三個單元。 19. The method of solution 1 or 2, wherein the ZU block is divided into three units using a tri-tree division scheme.

20.如解決方案19所述的方法,其中,作為3*2N<S

Figure 108122735-A0305-02-0036-24
3*2N+1的ZU塊被劃分的結果,三個單元中的第一單元具有尺寸2N×T,三個單元中的第二單元具有尺寸(S-3*2N)×T,並且三個單元中的第三單元具有尺寸2N+1×T。 20. The method according to solution 19, wherein, as 3*2 N <S
Figure 108122735-A0305-02-0036-24
As a result of dividing the 3*2 N+1 ZU block, the first of the three units has a size of 2 N × T, and the second of the three units has a size of (S-3*2 N ) × T, And the third cell of the three cells has a size of 2N+1 ×T.

21.如解決方案19所述的方法,其中,作為3*2N<T

Figure 108122735-A0305-02-0036-26
3*2N+1的ZU塊被劃分的結果,三個單元中的第一單元具有尺寸S×2N,三個單元中的第二單元具有尺寸S×(T-3*2N),並且三個單元中的第三單元具有尺寸S×2N+1。 21. The method according to solution 19, wherein, as 3*2 N <T
Figure 108122735-A0305-02-0036-26
As a result of dividing the 3*2 N+1 ZU block, the first of the three units has a size of S×2 N , and the second of the three units has a size of S×(T-3*2 N ), And the third cell among the three cells has a size of S×2 N+1 .

22.如解決方案1或2所述的方法,其中,單元具有K*M形式的尺寸,其中M和K是整數。 22. The method of solution 1 or 2, wherein the unit has a size of the form K*M, where M and K are integers.

23.如解決方案1或2所述的方法,其中,單元具有K*M形式的尺寸,M是允許的編碼單元的最小高度或最小寬度並且單元從非ZU塊劃分。 23. The method of solution 1 or 2, wherein the unit has a size in the form of K*M, M is the minimum height or minimum width of the allowed coding unit and the unit is divided from non-ZU blocks.

24.如解決方案22所述的方法,其中,導致不以K*M形式的單元的ZU塊劃分方案的信令通知被跳過。 24. The method of solution 22, wherein the signaling of the ZU block division scheme that causes units not in the form of K*M is skipped.

25.如解決方案23所述的方法,其中,導致從非ZU塊劃分的不以K*M形式的單元的劃分方案的信令通知被跳過。 25. The method of solution 23, wherein the signaling of a division scheme that causes a unit not in the form of K*M divided from a non-ZU block is skipped.

26.一種視頻編碼方法,包括:確定視頻數據塊將被編碼為零單元(ZU)塊;使用劃分方案來劃分視頻數據塊,其中, 劃分方案將視頻數據塊劃分為兩個單元、三個單元或四個單元中的一個;通過編碼視頻數據塊生成位元流,其中,劃分方案使用與用於對作為非零單元塊的另一視頻數據塊的劃分的信令通知相同的語法來發信令通知。 26. A video encoding method, comprising: determining that a block of video data will be encoded into zero unit (ZU) blocks; using a division scheme to divide the video data block, wherein, The division scheme divides the video data block into one of two units, three units or four units; the bit stream is generated by encoding the video data block, where the division scheme uses the other as a non-zero unit block. The division of the video data block is signaled by the same syntax.

27.一種視頻解碼方法,包括:接收對應於被編碼為零單元(ZU)塊的視頻數據塊的位元流,其中,使用將視頻數據塊劃分為兩個單元、三個單元或四個單元中的一個的劃分方案將視頻數據塊劃分,並且其中,劃分方案在位元流中使用與用於信令通知非零單元塊的劃分相同的語法來信令通知;基於信令通知,解碼位元流以生成視頻數據塊。 27. A video decoding method, comprising: receiving a bit stream corresponding to a video data block encoded as a zero unit (ZU) block, wherein the video data block is divided into two units, three units, or four units using One of the division schemes divides the video data block, and wherein the division scheme uses the same syntax as used to signal the division of non-zero unit blocks in the bit stream for signaling; based on the signaling, the bit is decoded Stream to generate video data blocks.

28.一種視頻編碼方法,包括:確定視頻數據塊將被編碼為零單元(ZU)塊,視頻數據塊具有尺寸;使用從ZU塊劃分方案的組中選擇的劃分方案將ZU塊劃分為兩個單元、三個單元或四個單元中的一個;編碼單元;以及在位元流中信令通知編碼的單元。這裡,ZU塊劃分方案的組是可用於分割編碼單元(CU)的劃分方案的組的子集。 28. A video encoding method, comprising: determining that a block of video data will be encoded into zero unit (ZU) blocks, the video data block has a size; and dividing the ZU block into two using a division scheme selected from a group of ZU block division schemes Unit, one of three units, or four units; coding unit; and signaling coding unit in the bit stream. Here, the group of ZU block partitioning schemes is a subset of the group of partitioning schemes available for partitioning coding units (CU).

29.一種視頻解碼方法,包括:接收對應於視頻數據塊的位元流,視頻數據塊具有尺寸;接收信令通知,該信令通知指示視頻數據塊包括從零單元(ZU)塊劃分的單元,使用從ZU塊劃分方案的組中選擇的劃分方案來將該劃分的ZU塊劃分;以及基於信令通知,解碼對應於單元的位元流以重建視頻數據塊。這裡,ZU塊劃分方案的組是可用於分割編碼單元(CU)的劃分方案的 組的子集。 29. A video decoding method, comprising: receiving a bit stream corresponding to a video data block, the video data block having a size; receiving a signaling notification indicating that the video data block includes units divided from zero unit (ZU) blocks , Using a division scheme selected from the group of ZU block division schemes to divide the divided ZU blocks; and based on signaling, decoding the bit stream corresponding to the unit to reconstruct the video data block. Here, the group of ZU block partitioning schemes can be used to partition a coding unit (CU) partitioning scheme A subset of the group.

30.如解決方案28或29所述的方法,其中,ZU塊劃分方案的組基於ZU塊的大小或者與圖片、條帶、片或條帶類型的一個有關的ZU塊的位置中的一個。 30. The method of solution 28 or 29, wherein the group of ZU block division schemes is based on one of the size of the ZU block or the position of the ZU block related to one of picture, slice, slice, or slice types.

31.如解決方案28或29所述的方法,其中,可用的ZU塊劃分方案的組限於四叉樹劃分方案和二叉樹劃分方案。 31. The method of solution 28 or 29, wherein the group of available ZU block division schemes is limited to the quadtree division scheme and the binary tree division scheme.

32.如解決方案28或29所述的方法,其中,ZU塊使用三叉樹劃分方案被劃分為三個單元,並且ZU塊的信令通知不包括與劃分方案有關的信息。 32. The method according to solution 28 or 29, wherein the ZU block is divided into three units using a trigeminal tree division scheme, and the signaling of the ZU block does not include information related to the division scheme.

33.如解決方案28或29所述的方法,其中,ZU塊劃分方案的組與可用於分割編碼單元(CU)的劃分方案的組相同,並且基於視頻數據塊是ZU塊來選擇用於信令通知分割ZU塊的指示的上下文。 33. The method of solution 28 or 29, wherein the group of ZU block division schemes is the same as the group of division schemes that can be used to divide coding units (CU), and the video data block is selected based on whether the video data block is a ZU block. Let the context of the instruction to divide the ZU block be notified.

34.一種視頻編碼方法,包括:確定視頻數據塊將被編碼為零單元(ZU)塊,視頻數據塊具有尺寸;在確定ZU塊位於I條帶或幀內編碼圖片中時,將ZU塊劃分為兩個單元、三個單元或四個單元中的一個;編碼單元;以及在位元流中信令通知編碼的單元。 34. A video encoding method, comprising: determining that a video data block will be encoded as a zero unit (ZU) block, the video data block has a size; when determining that the ZU block is located in an I slice or an intra-coded picture, dividing the ZU block It is one of two units, three units, or four units; a coding unit; and a unit that signals coding in the bit stream.

35.一種視頻解碼方法,包括:接收對應於視頻數據塊的位元流,視頻數據塊具有尺寸;接收信令通知,該信令通知指示視頻數據塊包括從零單元(ZU)塊劃分的單元,劃分的ZU塊位於I條帶或幀內編碼圖片中;以及基於信令通知,解碼對應於 單元的位元流以重建視頻數據塊。 35. A video decoding method, comprising: receiving a bit stream corresponding to a video data block, the video data block having a size; receiving a signaling notification indicating that the video data block includes units divided from zero unit (ZU) blocks , The divided ZU block is located in the I slice or intra-coded picture; and based on the signaling notification, the decoding corresponds to The bit stream of the unit to reconstruct the video data block.

36.如解決方案34或35所述的方法,其中,ZU塊的至少一個尺寸是非二的冪數。 36. The method of solution 34 or 35, wherein at least one size of the ZU block is a non-power of two.

37.如解決方案34或35所述的方法,其中,視頻數據塊是編碼單元(CU)塊,並且其中,CU塊由於至少一個尺寸為大於閾值的整數而被看待為ZU塊。 37. The method of solution 34 or 35, wherein the video data block is a coding unit (CU) block, and wherein the CU block is treated as a ZU block because at least one size is an integer greater than a threshold.

38.一種視頻系統中的裝置,包括處理器和其上具有指令的非暫態性的記憶體,其中,當由處理器執行指令時,使得處理器實現如解決方案1到37中的任一個所述的方法。 38. A device in a video system, comprising a processor and a non-transitory memory with instructions thereon, wherein when the instructions are executed by the processor, the processor is made to implement any one of solutions 1 to 37 The method described.

39.一種儲存在非暫態性的電腦可讀介質上的電腦程式產品,電腦程式產品包括用於執行解決方案1到37中的任一個中的方法的程式碼。 39. A computer program product stored on a non-transitory computer-readable medium, the computer program product including program code for executing the method in any one of solutions 1 to 37.

40.如本文件中所描述的方法、裝置或系統。 40. The method, device or system as described in this document.

從前述內容可以理解,本文已經出於說明的目的描述了本公開技術的具體實施例,但是可以在不脫離本發明範圍的情況下進行各種修改。因此,本公開的技術除了所附權利要求外不受限制。 It can be understood from the foregoing that the specific embodiments of the disclosed technology have been described herein for illustrative purposes, but various modifications can be made without departing from the scope of the present invention. Therefore, the technology of the present disclosure is not limited except for the appended claims.

本專利文件中描述的主題和功能操作的實現方式可以以各種系統、數位電子電路實現,或者以電腦軟體、韌體或硬體實現,包括說明書中公開的結構及其結構等同物,或者以它們中的一個或多個的組合實現。公開和其它實施例可以實現為一個或多個電腦程式產品,即,在有形且非暫態性的電腦可讀介質上編碼 的一個或多個電腦程式指令模組,用於由資料處理裝置執行或控制資料處理裝置的操作。電腦可讀介質可以是機器可讀存放裝置、機器可讀儲存基板、記憶體設備、影響機器可讀傳播信號的物質組合、或者它們中的一個或多個的組合。術語「資料處理單元」或「資料處理裝置」涵蓋用於處理資料的所有裝置、設備和機器,包括例如可程式設計處理器、電腦或多個處理器或電腦。除了硬體之外,該裝置還可以包括為所討論的電腦程式創建執行環境的代碼,例如,構成處理器韌體、協定疊、資料庫管理系統、作業系統、或者它們中的一個或多個的組合的代碼。 The subject and functional operation described in this patent document can be realized by various systems, digital electronic circuits, or by computer software, firmware or hardware, including the structure disclosed in the specification and its structural equivalents, or by using them A combination of one or more of them. The disclosed and other embodiments can be implemented as one or more computer program products, ie, encoded on a tangible and non-transitory computer readable medium One or more computer program instruction modules for the data processing device to execute or control the operation of the data processing device. The computer-readable medium may be a machine-readable storage device, a machine-readable storage substrate, a memory device, a combination of substances that affect a machine-readable propagation signal, or a combination of one or more of them. The term "data processing unit" or "data processing device" covers all devices, equipment, and machines used to process data, including, for example, a programmable processor, computer, or multiple processors or computers. In addition to hardware, the device may also include code that creates an execution environment for the computer program in question, for example, constituting processor firmware, protocol stack, database management system, operating system, or one or more of them The code of the combination.

電腦程式(也稱為程式、軟體、軟體應用、腳本或代碼)可以用任何形式的程式設計語言編寫,包括編譯或解釋語言,並且可以以任何形式來部署電腦程式,包括獨立程式或適合在計算環境中使用的模組、元件、子常式或其它單元。電腦程式並不必需對應於文件案系統中的文件。程式可以儲存在文件的保存其它程式或資料(例如,儲存在標記語言文件中的一個或多個腳本)的部分中,儲存在專用於所討論的程式的單個文件中,或儲存在多個協調文件中(例如,儲存一個或多個模組、副程式或代碼部分的文件)。可以部署電腦程式以在一個電腦上或在位於一個網站上或分佈在多個網站上並通過通信網路互連的多個電腦上執行。 Computer programs (also called programs, software, software applications, scripts or codes) can be written in any form of programming language, including compiled or interpreted languages, and computer programs can be deployed in any form, including stand-alone programs or suitable for computing Modules, components, subroutines, or other units used in the environment. The computer program does not necessarily correspond to the files in the file system. The program can be stored in the part of the document that holds other programs or data (for example, one or more scripts stored in a markup language document), in a single file dedicated to the program in question, or in multiple coordination In a document (for example, a document that stores one or more modules, subprograms, or code parts). Computer programs can be deployed to be executed on one computer or on multiple computers located on one website or distributed on multiple websites and interconnected by a communication network.

本說明書中描述的過程和邏輯流程可以由執行一個或多個電腦程式的一個或多個可程式設計處理器執行,以通過對輸入資料進行操作並生成輸出來執行功能。過程和邏輯流程也可以由 專用邏輯電路執行,並且裝置也可以實現為專用邏輯電路,例如FPGA(現場可程式設計閘陣列)或ASIC(專用積體電路)。 The processes and logic flows described in this specification can be executed by one or more programmable processors that execute one or more computer programs to perform functions by operating on input data and generating output. Process and logic flow can also be A dedicated logic circuit is implemented, and the device can also be implemented as a dedicated logic circuit, such as FPGA (Field Programmable Gate Array) or ASIC (Dedicated Integrated Circuit).

舉例來說,適合於執行電腦程式的處理器包括通用和專用微處理器、以及任何種類的數位電腦的任何一個或多個處理器。通常,處理器將從唯讀記憶體或隨機存取記憶體或兩者接收指令和資料。電腦的基本元件是用於執行指令的處理器和用於儲存指令和資料的一個或多個記憶體設備。通常,電腦還將包括或可操作地耦合到用於儲存資料的一個或多個大型存放區設備,例如磁片、磁光碟或光碟,以從該一個或多個大型存放區設備接收資料,或將資料傳輸到該一個或多個大型存放區設備,或者既接收又傳遞資料。然而,電腦不需要具有這樣的設備。適用於儲存電腦程式指令和資料的電腦可讀介質包括所有形式的非易失性記憶體、介質和記憶體設備,包括例如半導體記憶體設備,例如EPROM、EEPROM和快閃記憶體設備。處理器和記憶體可以由專用邏輯電路補充或併入專用邏輯電路中。 For example, processors suitable for executing computer programs include general-purpose and special-purpose microprocessors, and any one or more processors of any kind of digital computer. Generally, the processor will receive commands and data from read-only memory or random access memory or both. The basic components of a computer are a processor for executing instructions and one or more memory devices for storing instructions and data. Generally, the computer will also include or be operatively coupled to one or more large storage area devices for storing data, such as floppy disks, magneto-optical discs or optical discs, to receive data from the one or more large storage area devices, or Transmit data to the one or more large storage area devices, or both receive and transmit data. However, the computer does not need to have such equipment. Computer-readable media suitable for storing computer program instructions and data include all forms of non-volatile memory, media, and memory devices, including, for example, semiconductor memory devices such as EPROM, EEPROM, and flash memory devices. The processor and memory can be supplemented by or incorporated into a dedicated logic circuit.

說明書和附圖旨在被認為僅是示例性的,其中示例性意味著示例。如這裡所使用的,單數形式的「一」、「一個」和「該」旨在也包括複數形式,除非上下文另有明確說明。另外,除非上下文另有明確說明,否則“或”的使用旨在包括「和/或」。 The description and drawings are intended to be considered only exemplary, where exemplary means example. As used herein, the singular forms of "a", "an" and "the" are intended to also include the plural form, unless the context clearly dictates otherwise. In addition, the use of "or" is intended to include "and/or" unless the context clearly dictates otherwise.

雖然本專利文件包含許多細節,但這些細節不應被解釋為對任何發明或可要求保護的範圍的限制,而是作為特定於特定發明的特定實施例的特徵的描述。在本專利文件中,在單獨的實 施例的上下文中描述的某些特徵也可以在單個實施例中組合實現。相反,在單個實施例的上下文中描述的各種特徵也可以單獨地或以任何合適的子組合在多個實施例中實現。此外,儘管上面的特徵可以描述為以某些組合起作用並且甚至最初如此要求權利保護,但是在某些情況下,可以從所要求保護的組合中去除來自該組合的一個或多個特徵,並且所要求保護的組合可以指向子組合或子組合的變型。 Although this patent document contains many details, these details should not be construed as limitations on the scope of any invention or claimable, but as descriptions of features specific to specific embodiments of specific inventions. In this patent document, in a separate implementation Certain features described in the context of an embodiment can also be implemented in combination in a single embodiment. Conversely, various features described in the context of a single embodiment can also be implemented in multiple embodiments individually or in any suitable subcombination. In addition, although the above features can be described as working in certain combinations and even as claimed initially, in some cases, one or more features from the combination can be removed from the claimed combination, and The claimed combination can refer to a sub-combination or a variant of the sub-combination.

類似地,雖然在附圖中以特定順序描繪了操作,但是這不應該被理解為要求以所示的特定順序或按循序執行這樣的操作,或者執行所有示出的操作,以實現期望的結果。此外,在本專利文件中描述的實施例中的各種系統元件的分離不應被理解為在所有實施例中都要求這種分離。 Similarly, although operations are depicted in a specific order in the drawings, this should not be understood as requiring that such operations be performed in the specific order shown or in a sequential order, or that all the operations shown are performed to achieve the desired result . In addition, the separation of various system elements in the embodiments described in this patent document should not be understood as requiring such separation in all embodiments.

僅描述了幾個實現方式和示例,並且可以基於本專利文件中描述和示出的內容來做出其它實現方式、增強和變型。 Only a few implementations and examples are described, and other implementations, enhancements and modifications can be made based on the content described and shown in this patent document.

1800‧‧‧方法 1800‧‧‧Method

1802~1806‧‧‧步驟 1802~1806‧‧‧Step

Claims (39)

一種視頻編碼方法,包括:由於視頻數據塊具有尺寸S×T、S和T中的至少一個是非二的冪數,確定所述視頻數據塊將被編碼為零單元(ZU)塊,其中所述零單元不可變換,使得不對零單元調用變換、逆變換、量化和去量化操作;將所述ZU塊劃分為兩個單元、三個單元或四個單元中的一個;以及通過編碼所述單元生成位元流。 A video encoding method includes: since a video data block has a size of S×T, and at least one of S and T is a power of two, determining that the video data block will be encoded as a zero unit (ZU) block, wherein the The zero unit cannot be transformed, so that transform, inverse transform, quantization, and dequantization operations are not called on the zero unit; divide the ZU block into one of two units, three units, or four units; and generate by encoding the unit Bit stream. 一種視頻解碼方法,包括:接收對應於編碼為零單元(ZU)塊的視頻數據塊的位元流,該零單元(ZU)塊被劃分為兩個單元、三個單元或四個單元,所述視頻數據塊具有尺寸S×T,其中所述零單元不可變換,使得不對零單元調用變換、逆變換、量化和去量化操作;以及通過解碼所述位元流生成所述視頻數據塊。 A video decoding method includes: receiving a bit stream corresponding to a video data block encoded as a zero unit (ZU) block, the zero unit (ZU) block is divided into two units, three units, or four units, so The video data block has a size of S×T, wherein the zero unit is not transformable, so that transform, inverse transform, quantization, and dequantization operations are not called on the zero unit; and the video data block is generated by decoding the bit stream. 如申請專利範圍第1或2項所述的方法,其中,所述ZU塊使用二叉樹劃分方案被劃分為兩個單元,每個單元具有尺寸S/2×T。 The method described in item 1 or 2 of the scope of patent application, wherein the ZU block is divided into two units using a binary tree division scheme, and each unit has a size of S/2×T. 如申請專利範圍第1或2項所述的方法,其中,所述ZU塊使用二叉樹劃分方案被劃分為兩個單元,每個單元具有尺寸S×T/2。 The method described in item 1 or 2 of the scope of patent application, wherein the ZU block is divided into two units using a binary tree division scheme, and each unit has a size of S×T/2. 如申請專利範圍第1或2項所述的方法,其中,作為2N<S
Figure 108122735-A0305-02-0045-27
2N+1的ZU塊使用二叉樹劃分方案被劃分為兩個單元的結果,所述兩個單元中的第一單元具有尺寸2N×T,並且所述兩個單元中的第二單元具有尺寸(S-2N)×T。
The method described in item 1 or 2 of the scope of patent application, wherein, as 2 N <S
Figure 108122735-A0305-02-0045-27
2 N+1 ZU block is divided into two units using a binary tree division scheme, the first unit of the two units has a size of 2 N × T, and the second unit of the two units has a size of (S-2 N )×T.
如申請專利範圍第1或2項所述的方法,其中,作為2N<S
Figure 108122735-A0305-02-0045-28
2N+1的ZU塊使用二叉樹劃分方案被劃分為兩個單元的結果,所述兩個單元中的第一單元具有尺寸(S-2N)×T,並且所述兩個單元中的第二單元具有尺寸2N×T。
The method described in item 1 or 2 of the scope of patent application, wherein, as 2 N <S
Figure 108122735-A0305-02-0045-28
2 N+1 ZU block is divided into two units using a binary tree division scheme, the first unit of the two units has a size (S-2 N )×T, and the first unit of the two units The two units have dimensions 2 N × T.
如申請專利範圍第1或2項所述的方法,其中,作為2N<T
Figure 108122735-A0305-02-0045-29
2N+1的ZU塊使用二叉樹劃分方案被劃分為兩個單元的結果,所述兩個單元中的第一單元具有尺寸S×2N,並且所述兩個單元中的第二單元具有尺寸S×(T-2N)。
Such as the method described in item 1 or 2 of the scope of patent application, wherein, as 2 N <T
Figure 108122735-A0305-02-0045-29
2 N+1 ZU block is divided into two units using a binary tree division scheme. The first unit of the two units has a size of S×2 N , and the second unit of the two units has a size S×(T-2 N ).
如申請專利範圍第1或2項所述的方法,其中,作為2N<T
Figure 108122735-A0305-02-0045-30
2N+1的ZU塊使用二叉樹劃分方案被劃分為兩個單元的結果,所述兩個單元中的第一單元具有尺寸S×(T-2N)並且所述兩個單元中的第二單元具有尺寸S×2N
Such as the method described in item 1 or 2 of the scope of patent application, wherein, as 2 N <T
Figure 108122735-A0305-02-0045-30
2 N+1 ZU block is divided into two units using a binary tree division scheme. The first unit of the two units has a size of S×(T-2 N ) and the second unit of the two units The unit has the size S×2 N.
如申請專利範圍第1或2項所述的方法,其中,所述ZU塊使用三叉樹劃分方案被劃分為三個單元,所述三個單元中的兩個單元的每一個具有尺寸S/4×T,並且所述三個單元中的一個單元具有尺寸S/2×T。 The method described in item 1 or 2 of the scope of the patent application, wherein the ZU block is divided into three units using a trigeminal tree division scheme, and each of the two units of the three units has a size of S/4 ×T, and one of the three cells has a size of S/2×T. 如申請專利範圍第1或2項所述的方法,其中,所述ZU塊使用三叉樹劃分方案被劃分為三個單元,所述三個單元中的兩個具有尺寸S×T/4,並且所述三個單元中的一個具有尺寸S×T/2。 The method according to item 1 or 2 of the scope of patent application, wherein the ZU block is divided into three units using a trigeminal tree division scheme, two of the three units have a size of S×T/4, and One of the three cells has a size of S×T/2. 如申請專利範圍第1或2項所述的方法,其中,作為2N<S
Figure 108122735-A0305-02-0046-31
2N+1的ZU塊使用三叉樹劃分方案被劃分為三個單元的結果,第一單元具有尺寸2N-1×T,第二單元具有尺寸(S-2N)×T,並且第三單元具有尺寸2N-1×T。
The method described in item 1 or 2 of the scope of patent application, wherein, as 2 N <S
Figure 108122735-A0305-02-0046-31
2 N+1 ZU block is divided into three units using the trigeminal tree division scheme. The first unit has a size of 2 N-1 ×T, the second unit has a size of (S-2 N )×T, and the third The cell has a size of 2 N-1 ×T.
如申請專利範圍第1或2項所述的方法,其中,作為2N<T
Figure 108122735-A0305-02-0046-32
2N+1的ZU塊使用三叉樹劃分方案被劃分為三個單元的結果,第一單元具有尺寸S×2N-1,第二單元具有尺寸S×(T-2N),並且第三單元具有尺寸S×2N-1
Such as the method described in item 1 or 2 of the scope of patent application, wherein, as 2 N <T
Figure 108122735-A0305-02-0046-32
2 N+1 ZU block is divided into three units using the tri-tree division scheme. The first unit has size S×2 N-1 , the second unit has size S×(T-2 N ), and the third The unit has a size of S×2 N-1 .
如申請專利範圍第1或2項所述的方法,其中,所述ZU塊使用四叉樹劃分方案被劃分為四個單元,每個單元具有尺寸S/2×T/2。 The method described in item 1 or 2 of the scope of patent application, wherein the ZU block is divided into four units using a quadtree division scheme, and each unit has a size of S/2×T/2. 如申請專利範圍第1或2項所述的方法,其中,作為2N<S
Figure 108122735-A0305-02-0046-34
2N+1的ZU塊使用四叉樹劃分方案被劃分為四個單元的結果,第一單元具有尺寸2N×T/2,第二單元具有尺寸2N×T/2,並且第三單元具有尺寸S/2×(T-2N),並且第四單元具有尺寸S/2×(T-2N)。
The method described in item 1 or 2 of the scope of patent application, wherein, as 2 N <S
Figure 108122735-A0305-02-0046-34
2 N+1 ZU block is divided into four units using a quadtree division scheme. The first unit has a size of 2 N × T/2, the second unit has a size of 2 N × T/2, and the third unit It has a size of S/2×(T-2 N ), and the fourth cell has a size of S/2×(T-2 N ).
如申請專利範圍第1或2項所述的方法,其中,作為2N<T
Figure 108122735-A0305-02-0046-35
2N+1的ZU塊使用四叉樹劃分方案被劃分為四個單元的結 果,第一單元具有尺寸S/2×2N,第二單元具有尺寸S/2×2N,並且第三單元具有尺寸S/2×(T-2N),並且第四單元具有尺寸S/2×(T-2N)。
Such as the method described in item 1 or 2 of the scope of patent application, wherein, as 2 N <T
Figure 108122735-A0305-02-0046-35
2 N+1 ZU block is divided into four units using the quadtree division scheme. The first unit has size S/2×2 N , the second unit has size S/2×2 N , and the third unit It has a size of S/2×(T-2 N ), and the fourth cell has a size of S/2×(T-2 N ).
如申請專利範圍第1或2項所述的方法,其中,作為2N<S
Figure 108122735-A0305-02-0047-36
2N+1且2M<T
Figure 108122735-A0305-02-0047-37
2M+1的ZU塊使用四叉樹劃分方案被劃分為四個單元的結果,第一單元具有尺寸2N×2M,第二單元具有尺寸2N×2M,並且第三單元具有尺寸(S-2N)×(T-2M),並且第四單元具有尺寸(S-2N)×(T-2M)。
The method described in item 1 or 2 of the scope of patent application, wherein, as 2 N <S
Figure 108122735-A0305-02-0047-36
2 N+1 and 2 M <T
Figure 108122735-A0305-02-0047-37
The ZU block of 2 M+1 is divided into four units using the quadtree division scheme. The first unit has a size of 2 N × 2 M , the second unit has a size of 2 N × 2 M , and the third unit has a size (S-2 N )×(T-2 M ), and the fourth unit has a size (S-2N)×(T-2 M ).
如申請專利範圍第1或2項所述的方法,其中,作為2N<S
Figure 108122735-A0305-02-0047-38
2N+1且2M<T
Figure 108122735-A0305-02-0047-39
2M+1的ZU塊使用四叉樹劃分方案被劃分為四個單元的結果,第一單元具有尺寸2N×(T-2M),第二單元具有尺寸2N×(T-2M),第三單元具有尺寸(S-2N)×2M,並且第四單元具有尺寸(S-2N)×2M
The method described in item 1 or 2 of the scope of patent application, wherein, as 2 N <S
Figure 108122735-A0305-02-0047-38
2 N+1 and 2 M <T
Figure 108122735-A0305-02-0047-39
The ZU block of 2 M+1 is divided into four units using the quadtree division scheme. The first unit has a size of 2 N ×(T-2 M ), and the second unit has a size of 2 N ×(T-2 M ), the third unit has a size (S-2 N )×2 M , and the fourth unit has a size (S-2 N )×2 M.
如申請專利範圍第1或2項所述的方法,其中,所述ZU塊的每個單元的高度和/或寬度是偶數。 The method according to item 1 or 2 of the scope of patent application, wherein the height and/or width of each unit of the ZU block is an even number. 如申請專利範圍第1或2項所述的方法,其中,所述ZU塊使用三叉樹劃分方案被分割為三個單元。 The method according to item 1 or 2 of the scope of the patent application, wherein the ZU block is divided into three units using a tri-tree division scheme. 如申請專利範圍第19項所述的方法,其中,作為3*2N<S
Figure 108122735-A0305-02-0047-40
3*2N+1的ZU塊被劃分的結果,所述三個單元中的第一單元具有尺寸2N×T,所述三個單元中的第二單元具有尺寸(S-3*2N)×T,並且所述三個單元中的第三單元具有尺寸2N+1×T。
The method described in item 19 of the scope of patent application, wherein, as 3*2 N <S
Figure 108122735-A0305-02-0047-40
As a result of the 3*2 N+1 ZU block being divided, the first unit of the three units has a size of 2 N × T, and the second unit of the three units has a size of (S-3*2 N )×T, and the third cell of the three cells has a size of 2N+1 ×T.
如申請專利範圍第19項所述的方法,其中,作為3*2N<T
Figure 108122735-A0305-02-0047-41
3*2N+1的ZU塊被劃分的結果,所述三個單元中的第一單元 具有尺寸S×2N,所述三個單元中的第二單元具有尺寸S×(T-3*2N),並且所述三個單元中的第三單元具有尺寸S×2N+1
The method described in item 19 of the scope of patent application, wherein, as 3*2 N <T
Figure 108122735-A0305-02-0047-41
As a result of dividing a 3*2 N+1 ZU block, the first of the three units has a size of S×2 N , and the second of the three units has a size of S×(T-3* 2 N ), and the third cell of the three cells has a size of S×2 N+1 .
如申請專利範圍第1或2項所述的方法,其中,所述單元具有K*M形式的尺寸,其中M和K是整數。 The method according to item 1 or 2 of the scope of patent application, wherein the unit has a size in the form of K*M, where M and K are integers. 如申請專利範圍第1或2項所述的方法,其中,所述單元具有K*M形式的尺寸,M是允許的編碼單元的最小高度或最小寬度,並且所述單元是從非ZU塊劃分得到的。 The method described in item 1 or 2 of the scope of patent application, wherein the unit has a size in the form of K*M, M is the minimum height or width of the allowed coding unit, and the unit is divided from a non-ZU block owned. 如申請專利範圍第22項所述的方法,其中,導致非K*M形式的單元的ZU塊劃分方案的信令通知被跳過。 The method described in item 22 of the scope of the patent application, wherein the signaling of the ZU block division scheme that causes non-K*M units to be skipped. 如申請專利範圍第23項所述的方法,其中,導致從非ZU塊劃分的非K*M形式的單元的劃分方案的信令通知被跳過。 The method described in item 23 of the scope of patent application, wherein the signaling notification of the division scheme of the non-K*M form unit divided from the non-ZU block is skipped. 一種視頻編碼方法,包括:由於所述塊具有非二的冪數的高度或寬度,確定視頻數據塊將被編碼為零單元(ZU)塊,其中所述零單元不可變換,使得不對零單元調用變換、逆變換、量化和去量化操作;使用劃分方案來劃分所述視頻數據塊,其中,所述劃分方案將所述視頻數據塊劃分為兩個單元、三個單元或四個單元中的一個;以及通過編碼所述視頻數據塊生成位元流,其中,所述劃分方案使用與用於對作為非零單元塊的另一視頻數據塊進行劃分的信令通知相同的語法來發信令通知。 A video encoding method, including: since the block has a height or width that is not a power of two, determining that a video data block will be encoded as a zero unit (ZU) block, wherein the zero unit is not transformable, so that the zero unit is not called Transformation, inverse transformation, quantization, and dequantization operations; use a partitioning scheme to divide the video data block, wherein the partitioning scheme divides the video data block into one of two units, three units, or four units And generating a bit stream by encoding the video data block, wherein the division scheme uses the same syntax as the signaling used to divide another video data block that is a non-zero unit block to signal . 一種視頻解碼方法,包括: 接收對應於視頻數據塊的位元流,由於所述視頻數據塊具有尺寸S×T、S和T中的至少一個是非二的冪數,所述視頻數據塊被編碼為零單元(ZU)塊,其中,使用將所述視頻數據塊劃分為兩個單元、三個單元或四個單元中的一個的劃分方案將所述視頻數據塊劃分,並且其中,所述劃分方案在所述位元流中使用與用於信令通知非零單元塊的劃分相同的語法來發信令通知,其中所述零單元不可變換,使得不對零單元調用變換、逆變換、量化和去量化操作;以及基於所述信令通知,解碼所述位元流以生成所述視頻數據塊。 A video decoding method, including: Receive a bit stream corresponding to a video data block, since the video data block has a size of S×T, and at least one of S and T is a power of two, the video data block is encoded as a zero unit (ZU) block , Wherein the video data block is divided using a division scheme of dividing the video data block into two units, three units, or one of four units, and wherein the division scheme is in the bit stream Use the same syntax as that used to signal the division of non-zero unit blocks, where the zero unit is not transformable, so that transform, inverse transform, quantization, and dequantization operations are not called on the zero unit; and The signaling informs that the bit stream is decoded to generate the video data block. 一種視頻編碼方法,包括:由於視頻數據塊具有尺寸S×T、S和T的至少一個是非二的冪數,確定所述視頻數據塊將被編碼為零單元(ZU)塊,其中所述零單元不可變換,使得不對零單元調用變換、逆變換、量化和去量化操作;使用從ZU塊劃分方案的組中選擇的劃分方案將所述ZU塊劃分為兩個單元、三個單元或四個單元中的一個;編碼所述單元;以及在位元流中信令通知被編碼的單元;其中,所述ZU塊劃分方案的組是可用於劃分編碼單元(CU)的劃分方案的組的子集。 A video encoding method includes: since a video data block has a size of S×T, and at least one of S and T is a power of two, determining that the video data block will be encoded as a zero unit (ZU) block, wherein the zero The unit is not transformable, so that the transform, inverse transform, quantization, and dequantization operations are not called on the zero unit; the ZU block is divided into two units, three units, or four using a division scheme selected from the group of ZU block division schemes One of the units; encoding the unit; and signaling the coded unit in the bit stream; wherein the group of the ZU block partitioning scheme is a child of the group of partitioning schemes that can be used to partition the coding unit (CU) set. 一種視頻解碼方法,包括: 接收對應於視頻數據塊的位元流,所述視頻數據塊具有尺寸;接收信令通知,所述信令通知指示由於所述視頻數據塊具有尺寸S×T、S和T中的至少一個是非二的冪數,所述視頻數據塊作為零單元(ZU)塊被劃分,使用從ZU塊劃分方案的組中選擇的劃分方案將所述塊劃分,其中所述零單元不可變換,使得不對零單元調用變換、逆變換、量化和去量化操作;以及基於所述信令通知,解碼對應於所述單元的所述位元流以重建所述視頻數據塊;其中,所述ZU塊劃分方案的組是可用於分割編碼單元(CU)的劃分方案的組的子集。 A video decoding method, including: Receiving a bit stream corresponding to a video data block, the video data block having a size; receiving a signaling notification, the signaling notification indicating that because the video data block has a size of S×T, at least one of S and T is wrong A power of two, the video data block is divided as a zero unit (ZU) block, and the block is divided using a division scheme selected from the group of ZU block division schemes, wherein the zero unit is not transformable, making it non-zero The unit calls transform, inverse transform, quantization, and dequantization operations; and based on the signaling, decodes the bit stream corresponding to the unit to reconstruct the video data block; wherein the ZU block division scheme A group is a subset of groups that can be used to partition a coding unit (CU) division scheme. 如申請專利範圍第28或29項所述的方法,其中,所述ZU塊劃分方案的組基於所述ZU塊的大小或者與圖片、條帶、片或條帶類型的一個有關的所述ZU塊的位置中的一個。 The method according to item 28 or 29 of the scope of patent application, wherein the group of the ZU block division scheme is based on the size of the ZU block or the ZU related to one of the picture, strip, slice, or strip type One of the location of the block. 如申請專利範圍第28或29項所述的方法,其中,可用的所述ZU塊劃分方案的組限於四叉樹劃分方案和二叉樹劃分方案。 The method according to item 28 or 29 of the scope of patent application, wherein the group of available ZU block division schemes is limited to the quadtree division scheme and the binary tree division scheme. 如申請專利範圍第28或29項所述的方法,其中,所述ZU塊使用三叉樹劃分方案被劃分為三個單元,並且所述ZU塊的信令通知不包括與所述劃分方案有關的信息。 The method according to item 28 or 29 of the scope of patent application, wherein the ZU block is divided into three units using a trigeminal tree division scheme, and the signaling notification of the ZU block does not include information related to the division scheme information. 如申請專利範圍第28或29項所述的方法,其中,所述ZU塊劃分方案的組與可用於分割所述編碼單元(CU)的所述劃分 方案的組相同,並且基於所述視頻數據塊是所述ZU塊來選擇用於信令通知分割所述ZU塊的指示的上下文。 The method according to item 28 or 29 of the scope of the patent application, wherein the group of the ZU block division scheme and the division that can be used to divide the coding unit (CU) The groups of the schemes are the same, and based on the video data block being the ZU block, the context for signaling the indication of dividing the ZU block is selected. 一種視頻編碼方法,包括:由於所述視頻數據塊具有尺寸,並且所述尺寸的高和寬中的至少一個是非二的冪數,確定視頻數據塊將被編碼為零單元(ZU)塊,其中所述零單元不可變換,使得不對零單元調用變換、逆變換、量化和去量化操作;在確定所述ZU塊位於I條帶或幀內編碼的圖片中時,將所述ZU塊劃分為兩個單元、三個單元或四個單元中的一個;編碼所述單元;以及在位元流中信令通知被編碼的單元。 A video encoding method includes: since the video data block has a size, and at least one of the height and the width of the size is a power of two, determining that the video data block will be encoded as a zero unit (ZU) block, wherein The zero unit cannot be transformed, so that the transform, inverse transform, quantization, and dequantization operations are not called for the zero unit; when it is determined that the ZU block is located in an I-slice or intra-coded picture, the ZU block is divided into two One of three units, three units, or four units; encoding the unit; and signaling the encoded unit in the bitstream. 一種視頻解碼方法,包括:接收對應於視頻數據塊的位元流,所述視頻數據塊具有尺寸;接收信令通知,所述信令通知指示所述視頻數據塊包括從零單元(ZU)塊劃分的單元,所述零單元(ZU)塊至少高度或寬度為非二的冪數,並且在無變換和殘差編碼的情況下被編碼,所述劃分的ZU塊位於I條帶或幀內編碼圖片中,其中所述零單元不可變換,使得不對零單元調用變換、逆變換、量化和去量化操作;以及基於所述信令通知,解碼對應於所述單元的所述位元流以重建所述視頻數據塊。 A video decoding method, comprising: receiving a bit stream corresponding to a video data block, the video data block having a size; receiving a signaling notification, the signaling notification indicating that the video data block includes a zero unit (ZU) block The divided unit, the zero unit (ZU) block is at least a power of two in height or width, and is coded without transformation and residual coding, and the divided ZU block is located in an I slice or frame In the coded picture, the zero unit is not transformable, so that transform, inverse transform, quantization, and dequantization operations are not called on the zero unit; and based on the signaling notification, the bit stream corresponding to the unit is decoded to reconstruct The video data block. 如申請專利範圍第34或35項所述的方法,其中,所述ZU塊的尺寸的高和寬中的至少一個是非二的冪數。 The method according to item 34 or 35 of the scope of patent application, wherein at least one of the height and the width of the size of the ZU block is a non-power of two. 如申請專利範圍第34或35項所述的方法,其中,所述視頻數據塊是編碼單元(CU)塊,並且其中,所述CU塊由於至少一個尺寸為大於閾值的整數而被看待為ZU塊。 The method according to item 34 or 35 of the scope of patent application, wherein the video data block is a coding unit (CU) block, and wherein the CU block is treated as a ZU because at least one size is an integer greater than a threshold Piece. 一種視頻系統中的設備,包括處理器和其上儲存有指令的非暫態性記憶體,其中,當由所述處理器執行所述指令時,使得所述處理器實現如申請專利範圍第1到37項中的一個或多個所述的方法。 A device in a video system includes a processor and a non-transitory memory on which instructions are stored, wherein, when the instructions are executed by the processor, the processor realizes the first To one or more of the 37 methods. 一種儲存在非暫態性的電腦可讀介質上的電腦程式產品,所述電腦程式產品包括用於執行如申請專利範圍第1到37項中的一個或多個所述的方法的程式碼。 A computer program product stored on a non-transitory computer readable medium. The computer program product includes program code for executing one or more of the methods described in items 1 to 37 in the scope of the patent application.
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* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
US20180109812A1 (en) * 2016-10-14 2018-04-19 Media Tek Inc. Block partitioning using tree structures
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* Cited by examiner, † Cited by third party
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