TWI255419B - The comparing and testing method for video or audio data in storage devices - Google Patents

The comparing and testing method for video or audio data in storage devices Download PDF

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TWI255419B
TWI255419B TW93120103A TW93120103A TWI255419B TW I255419 B TWI255419 B TW I255419B TW 93120103 A TW93120103 A TW 93120103A TW 93120103 A TW93120103 A TW 93120103A TW I255419 B TWI255419 B TW I255419B
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data
test
binary
sound
image
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TW93120103A
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TW200602966A (en
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Li-Shen Chan
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Wavetronex Inc
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Abstract

The comparing and testing method for video or audio data in storage devices is a video or audio comparing and testing method and includes at least two major modules. In the first video-audio module, different video or audio data via the software encode/decode program or hardware encode/decode IC achieves the functions: play video/audio data, record video/audio data, and playback video/audio data. In the second testing module, we use related location comparing method and video/audio comparing method to compare and test the video/audio data which is in the first video-audio module and stored in different type storage devices, and get the results of similarity and test.

Description

1255419 九、發明說明: 【發明所屬之技術領域】 t發明係關於 ίτ, 種透過軟體編碼/解石焉 (EnC〇de/Decode)程序或是硬體 le 、、、 ^ 像及聲音紀錄資料相對於儲存f置;2之原始影 對測試方法’且特別關於一二;:目 =影像及聲音的相對位置來做比對测試 【先前技術】 舊有技術大多使用於固定時問芬心门 :::的4音資料比對’換句話說,也就是原 比對貧料之間並無時間或是儲存媒介 二二/ ,對。(請參考第-圖)。在此比對方式之;以 ΐ=ΐ可以知道並控制影音資料開始播放及停止老 放的日守間,同時比對之影音資料的儲存方式及格^ 完全相同,因此可以利用我們先前的發明方式來做^ 對。 隨著消費者對於影音系統的要求越來越多, 處理系統的功能也越來越複雜,然而也就產生了所二 可重複錄影並播放影音資訊的系統,例如·1255419 IX. Description of the invention: [Technical field to which the invention pertains] t invention is related to ίτ, through the EnC〇de/Decode program or the hardware le, , , ^ image and sound recording data. In the storage of f; 2 the original shadow pair test method 'and especially about one or two;: the target = the relative position of the image and sound to do the comparison test [prior art] the old technology is mostly used in the fixed time Fenxin door ::: 4 sound data comparison 'In other words, there is no time between the original comparison of poor materials or storage medium 22 /, right. (Please refer to the figure - figure). In this comparison mode; ΐ=ΐ can know and control the video and audio data to start playing and stop the old day-to-day, while the comparison of the audio and video data is stored in the same way, so we can use our previous invention Come do ^ right. As consumers demand more and more audio and video systems, the functions of the processing system become more and more complex, but they also produce two systems that can repeatedly record and play video and audio information, such as

Player + DVD R/W燒錄或是可儲存在硬碟再播放 相關功能的裝置(如:DVD Recordable Device)。 在这類裝置中扮演主要角色的裝置即為可再 影之影音控制晶片。這類的晶片的控制功能比傳統的' 影音控制晶片複雜(傳統的影音控制晶片如. VCD/DVD Player控制晶片),這種新型的晶片控制流 1255419 程必須經過好幾道手續才能完成全部的處理程序。例 如:必須先將影像資料由影音紀錄媒體上讀取(Ph 出來(功—能類似單純之VCD/DVD Player裝置),讀取 後的資料會經過一道編碼/解碼的動作 (Encode/Decode)將資料轉化成另一種可儲存於儲存 裝置的精簡型態。(例如:MPEG2或是MPEG4或^ 其他方式之壓縮及解壓縮的過程)。影音資料儲 (Reco⑷在儲存裝置後,此種新型的控制晶片還必須 將,音資料透過轉化程序(例如:MPEG2或是MPEG4 或是其他方式之壓縮及解壓縮的過程儲 出來⑺ayback)並顯示在顯示裝置上面(例如:電= 疋電腦螢幕或是其他可顯示影音資 2 所謂,,回放,,的程序(play back)。 )也就疋 此,f型的影音控制晶片必須經由特定程序由 原始之衫曰儲存媒體(如VCD/DVD光碑f ”來並轉存於另一類型的儲存裝置先碟= :後^回放(Play baek)程序使用。在此m的過程 :,由於程序繁瑣也增加了此類型晶片的測試複^ 片的好壞。4方法就無法有效的測試出晶 先前技術具有可以比對相同時間戳記的會立次 似關聯性的功能,然而對於'型二 :、轉化影音資料(Encode/Dec〇de)、^ 曰貝料(ReeGrd)及回放影音㈣加k)資料等相^ 1255419 =的優劣,因此,如何能夠利用 新型影立曰 崎的方法有效iffr 、ι 立曰=曰曰日片複雜的程序測試問題,%決 内容中提供解決方式。 *方式,將會在本發明 【發明内容】 $ $ T係提供一種原始資料與 枓的比對測試方法,特別是—=破置中之影音資 將u影音内容比對。藉由此種測试it時 $新型影音控制晶片複貝】t方法’可以 =ode/Dec〇de)程序透過適方的:2 /解碼 解決原先影音測試方式之不足的方式來做檢測,用以 少可包含兩項主要模組及相關流程及程序。 模組一:影音模組 模組二:測試模組 本發明之儲存裝置中之影音資料 至少具有下Μ項主要㈣: 〇以方法程序 lp模組一中,受測試端有播放影像/ 次 (pia幻、紀錄影像/聲音資料(Record)及回:貝料 錄之影像/聲音資料(Playback)的程序。 則述紀 2.模組二中,本發明之測試方式使用相對位置演算法(例如· p Recognition演算法)找到影像及聲音串流中之正確的影像時 位置及聲音時間戳記位置並完成對齊動作(Line up)。 θ 3·模組二中,本發明之測試方式所利用之影像/聲音比對演算法/ 用影像職像素的二進位值變化度(Checksum方式)或是其他類1 1255419 以及聲音頻率之強度值來比較相同時間戳記位置的影像或是聲 :貢料^否相同或是是否在門檻值之内。(註:在灰階的影像系 統中只會使用到黑白兩色的像素變化值)。其中包含: $存並比較原始播放(Play)之影像/聲音資料與紀錄細⑹及回 放(Playback)程序中之影像/聲音資料。 4·流程如下: 巾之歸聲音#料:㈣數學處理程 (4) 利用相同時間戳記點的影像資 =皆值及聲音頻率分佈值強度比二=或疋 (5) 利用相同時間戳記點的影像資料之rgb 火階值及聲音頻率分佈值強度比較 二 5.利用不同門檻值的設定來決定卜 & M3 、# β 』门U值的°又疋不决疋上述比較結果是通過 运疋失敗(Pass or Fail)。 =考第三圖,在模組一:影音模",至少包含了下列三項 (1)從輸出裝置播放(Play)影音資料。 ⑵=裝置儲存(Record)在上一程序中從輸出裝置所播放之 影音資料。 (3)從儲存裝置回放(playback)已經儲存之影音資料。 模組一之主要流程方式如下: ο)影音來源媒體中儲存要播放的原始影音資料。 1255419 音資料的編碼s解曰= 軟的體處^=的编影音資料可《透過影 ~c〇de);^; ^ ^ 2=來以被紀錄到儲存㈣,同時也可以 透過知員不虞置直接讓使用者看見或是聽見。 影音資料都會傳輸到模組二:測試模組以供測試用途 請參考第四® ’在第二侧試模組巾,至少有下列三項子模組: (1) 影像子模組··處理影像資料。 (2) 聲音子模組:處理聲音資料。 (3) 相關位置比較模組:比對影像及聲音相關位置。 同時在第二項測試模組中,至少完成下列兩項測試程序: ⑴影音枝資料比對職及對齊⑽祕udiG st纖加如 and Line up)程序—利用相關位置比較演算方法達成下列 功能: 、 (A) 播放和儲存之影音資料比較(playvs Rec〇rd):比對輸出裝 置播放(Play)之影音資料,及儲存裝置儲存(如⑺岀) 之影音資料,並找出相對的時間戳記位置,同時將相同時 間戳記的影音資料對齊(Line up),以利於做品質測試 (Quality Test)。 (B) 播放和回放之影音資料比較(Play vs· Playback):比對輸出 裝置播放(Play)影音資料,及儲存裝置回放(piayback) 之影音資料,並找出相對的時間戳記位置,同時將相同時 間戳記的影音資料對齊(Line up),以利於做後續之品質 測試(Quality Test)。 (2)品質測試(Quality Test)程序-以影像/聲音比對演算法,做出 1255419 衫像及聲音資料比對及測試,並由門檻值的不同,來判斷比對 /則喊結果為成功還是失敗(Pass or Fail)。 模組二之主要流程方式如下: 模組一傳送過來的影音資料透過下列方式比較及測 5式處理。 (1) 媒體一:原始之儲存媒體(如:VCD/DVD光碟片)。 (2) 媒體二:原始影音資料經過編碼/解碼轉化後之 轉存媒體(如:硬碟或是記憶體)。 (3) 媒體二:儲存比較資料的儲存媒體,如硬碟或是記 憶體。 ° (3) 流程一 ··抓取媒體一中的影音資料並轉化成Μι儲 存在記憶及儲存媒體之中。同時將在儲存媒體一中的資料轉 存到媒體三。轉存到媒體三影音資料會當成播放和儲存之影 音資料比較(Play vs· Record)的基準比較記憶資料庫M2,並儲存在 記憶及儲存媒體之中。在比較測試播放和儲存之影音資料的時候, 此基準比較記憶資料庫M2會被同步即時(Real time)傳送到影像及 聲音處理子模組中,並利用影像/聲音比對演算法比對。 (4) 流程二··抓取媒體二中的影音資料,並轉化儲存媒 體二中的資料到媒體三。此影音資料會當成播放和回放之影 音資料比較(Play vs· Playback)的基準比較記憶資料庫M3,並儲^ 在圮憶及儲存媒體之中。在比較測試播放和儲存之影音資料的時 候,此基準比較記憶資料庫M3會被同步即時(Realtime)傳送到景$ 像及聲音處理子模組中,並利用影像/聲音比對演算法比對。〜 (5) 流程三:利用相對位置比對方式,如模塊比對 1255419 (Pattern Recognition)方法比對 M1/M2 及 M1/M3 之間 的差異性,並找出相關位置及時間戳記點。同時將資料送到影 像及聲音處理子模組巾,並糊影像/聲音轉演算法比對並得出 結果。 (6)流程四··將結果透過相關傳輸方式傳輸出去,如RS232介面。 轉化M1/M2/M3之方式為: (1) 影像資料··將所有畫面中的像素轉化成二進 位值儲存。 (2) 聲音資料··將所有聲音資料利用傅利葉公式 轉化成頻域資料並用二進位值方式儲存聲音資 料0 、 相對位置比較演算法之模塊比對”州⑽ Recognition)方法: 由於時間戳記並沒有附加在影像及聲音資料 上,因此我們並須應用一些相關方法找出顯示之影像 及聲音資料之正讀時間戳記位置,以便使用影像/聲 音比對演算法來比對相似度及測試結果。相關的方法有 很多,我們在此發明中也可以運用模塊比對(Pattern Recognition)的方法來說明相對位置的比較渖曾法。 在這裡我們舉例說明一般的模塊比對(";attern Recognition)流程: 1 ·資料收集並做資料訓練的動作。 2·資料簡化。 3·資料分區塊劃分區域並同時做比對動作 4 ·物件辨識 。 5 ·影像辨別(或是聲音波型之辨別)。 本發明中我們使用的模塊比對(Pattern Recogniti(m) 12 1255419 方法,同時參考下列論文的演算法技術: (1) Ρ·Α· Devi jy er, J. Kittler, Pattern Recognition: A Statistical Approach, Englewood Clils, London, 1982· (2) K· Fukunaga, Introduction to Statistical PatternPlayer + DVD R/W burns or can be stored on a hard drive to play related functions (such as: DVD Recordable Device). A device that plays a major role in such devices is a rewritable video control chip. The control function of this type of wafer is more complicated than the traditional 'audio control chip (traditional AV control chip such as VCD/DVD Player control chip). This new type of wafer control flow 1255419 has to go through several procedures to complete the processing. program. For example, you must first read the image data from the audio-visual recording media (Ph out (power-can be similar to a simple VCD/DVD player device), and the read data will undergo an encoding/decoding action (Encode/Decode). The data is converted into another streamlined state that can be stored in the storage device (for example: MPEG2 or MPEG4 or other methods of compression and decompression). Video and audio storage (Reco (4) after storage device, this new type of control The chip must also store the audio data on the display device through a conversion program (for example, MPEG2 or MPEG4 or other methods of compression and decompression (7) ayback) (for example: electric = computer screen or other This shows that the audio and video control chip of the f-type must be stored in the original shirt storage medium (such as VCD/DVD light monument f) via a specific program. Transfer to another type of storage device first disc =: Playback (Play baek) program is used. In this process of m:, due to the cumbersome procedures, the test of this type of wafer has been added. Good or bad. 4 methods can not effectively test the crystal prior art has the ability to compare the similar time-sequences of the same time stamp, but for the 'type two:, transform audio and video data (Encode /Dec〇de), ^ e贝料 (ReeGrd) and playback video (4) plus k) data and other phase ^ 1255419 = good and bad, therefore, how to use the new method of 曰立曰崎 effective Iffr, ι 曰 = 曰曰 日 complex test The problem is that the solution is provided in the content of the content. * The method will be in the invention [invention] The $ $ T system provides a comparison test method between the original data and the 枓, especially the -= Video and audio content comparison. With this test it is a new type of video control chip Fubei] t method 'can be = ode /Dec〇de) program through the appropriate side: 2 / decoding to solve the problem of the original video test method For testing, it can contain two main modules and related processes and procedures. Module 1: Audio and video module module 2: Test module The audio and video data in the storage device of the present invention has at least the following items (4) : 〇方法方法In the lp module one, the test end has a program for playing images/times (pia illusion, recording image/sound data (Record) and back: shell recording video/sound data (Playback). In the second method, the test method of the present invention uses a relative position algorithm (for example, the p recognition algorithm) to find the position and sound time stamp position of the correct image in the image and sound stream and complete the line up. θ 3 In Module 2, the image/sound comparison algorithm used in the test mode of the present invention is compared with the binary value change degree (Checksum mode) of the image pixel or other class 1 1255419 and the intensity value of the sound frequency. The image or sound of the same time stamp position: the tribute ^ is the same or is within the threshold. (Note: Only the black and white pixel change values are used in the grayscale image system). It contains: $Save and compare the image/sound data in the original playback (Play) image/sound data and record fine (6) and playback (Playback) programs. 4· The process is as follows: The sound of the towel is #material: (4) Mathematical processing (4) The image value of the same time stamp is used = the value of the sound value and the sound frequency distribution value ratio is 2 = or 疋 (5) The rgb fire level value and the sound frequency distribution value intensity comparison of the image data are two. 5. The setting of the different threshold values is used to determine the U value of the & M3 and #β 』 gates, and the above comparison result is passed through Pass or Fail. = Test the third picture, in the module one: video mode ", at least the following three items (1) play (Play) audio and video data from the output device. (2) = Device The audio and video material played back from the output device in the previous program. (3) Playback of the already stored video and audio material from the storage device. The main process of module one is as follows: ο) The original audio and video material to be played is stored in the video source media. 1255419 The encoding of the audio data s = 软 = soft body ^ = the audio and video material can be "through the shadow ~ c〇de"; ^; ^ ^ 2 = to be recorded to store (four), but also through the knowledge Set directly to the user to see or hear. Audio and video data will be transmitted to Module 2: Test module for test purposes, please refer to the fourth ® 'In the second side test module towel, at least the following three sub-modules: (1) Image sub-module · · Processing video material. (2) Sound sub-module: processing sound data. (3) Related position comparison module: Compare the position of the image and sound. At the same time, in the second test module, at least the following two test procedures are completed: (1) video and audio data comparison and alignment (10) secret udiG st fiber plus and line up) program - use the relevant position comparison algorithm to achieve the following functions: (A) Play and store video data comparison (playvs Rec〇rd): compare the audio and video data played by the output device (Play), and the audio and video data stored by the storage device (such as (7) ,), and find the relative time stamp. Position, and simultaneously line up the video data of the same time stamp to facilitate the quality test (Quality Test). (B) Play vs. Playback: Play the playback device (Play) video data, and store the device's piayback video data, and find the relative time stamp position, and The line-of-picture data of the same time stamp is aligned to facilitate subsequent Quality Test. (2) Quality Test program - use the image/sound comparison algorithm to make 1255419 shirt image and sound data comparison and test, and judge the comparison/squeeze result by the difference of threshold value. Still failed (Pass or Fail). The main flow of Module 2 is as follows: The video and audio data transmitted by the module is compared and measured in the following manner. (1) Media 1: Original storage media (eg VCD/DVD discs). (2) Media 2: The original audio and video data is encoded/decoded and transferred to the media (such as hard disk or memory). (3) Media 2: Storage media for storing comparative data, such as hard disk or memory. ° (3) Process 1 · Grab the video and audio material in the media and convert it into a memory stored in the memory and storage media. At the same time, the data in the storage medium 1 is transferred to the media three. The transfer to the media three audio and video data will be used as a reference for the playback and storage of the video data comparison (Play vs. Record) comparison memory database M2, and stored in the memory and storage media. When comparing the audio and video data played and stored, the benchmark comparison memory database M2 is transmitted to the image and sound processing sub-module by Real time and is compared by the image/sound comparison algorithm. (4) Process 2··Catch the audio and video materials in Media 2 and convert the data in Storage Media 2 to Media 3. This video data will be compared to the Play vs. Playback reference comparison memory database M3 and stored in the memory and storage media. When comparing the audio and video data played and stored, the benchmark comparison memory database M3 is synchronously transmitted to the scene and the sound processing sub-module, and is compared by the image/sound comparison algorithm. . ~ (5) Process 3: Use the relative position comparison method, such as the module comparison 1255419 (Pattern Recognition) method to compare the difference between M1/M2 and M1/M3, and find the relevant position and time stamp. At the same time, the data is sent to the image and sound processing sub-module towel, and the paste image/sound algorithm is compared and the result is obtained. (6) Process 4··Transfer the results through the relevant transmission method, such as the RS232 interface. The way to convert M1/M2/M3 is: (1) Image data · Convert all pixels in the screen to binary value storage. (2) Sound data·· Convert all sound data into frequency domain data using Fourier formula and store sound data in binary value method. Module comparison of relative position comparison algorithm “State (10) Recognition) Method: Since the time stamp does not Attached to the image and sound data, we must also apply some relevant methods to find the position of the displayed time and time of the displayed image and sound data, so that the image/sound comparison algorithm can be used to compare the similarity and test results. There are many methods. In this invention, we can also use the method of Pattern Recognition to illustrate the comparison of relative positions. Here we illustrate the general module comparison (";attern Recognition) process. : 1 · Data collection and data training activities 2. Data simplification 3. Data partition block division area and simultaneous comparison action 4 · Object recognition 5 · Image discrimination (or discrimination of sound waveforms) In the invention we used the module alignment (Pattern Recogniti (m) 12 1255419 method, with reference to the following papers Algorithmic techniques: (1) Ρ·Α· Devi jy er, J. Kittler, Pattern Recognition: A Statistical Approach, Englewood Clils, London, 1982· (2) K· Fukunaga, Introduction to Statistical Pattern

Recognition, 2nd Edition, Academic Press, New York, 1 990· (3) N.R. Pal, S.K. Pal, A review on image segmentatio techniques, Pattern Recognition 26 (9) (1993) 1277-1294. 舉例來說:Recognition, 2nd Edition, Academic Press, New York, 1 990. (3) N.R. Pal, S.K. Pal, A review on image segmentatio techniques, Pattern Recognition 26 (9) (1993) 1277-1294. For example:

2. 3· 資料收集並做資料訓練的動作:我們可以紀錄所 有影像晝面之RGB晝素的所有二進位值資料,並 存入資料庫作為後續比對之第一基準值。 貧^簡化··所有的影像資料之二進位值資料庫可 以簡化為統計資料並以此統計資料作為後續比 對之第二基準比對值。 資^分區塊劃分區域並同時做比對動作:所有影 f資料的顯示區域可以晝分為不同區域並在小 範圍的區域中與第一基準值,及第二基準值比對 並即時相減比對同時產生結果。 物:辨識:當第一基準值及第二基準值相減比對 f結果相同或是超越某一門檻值,則我們可知道 ^ 一物件為相同之物件的可能性相當高。如此一 :,可迅速找出影像或是聲音資料之正確時間 估ί位置。(例如:第一基準值為1 00,第二基準 三101 ’門根值為5,則我們可以假定此兩者 一影像、/聲音資料)。因為101-100二1 < 5。 =—,1 (或是聲音波型之辨別)··當物件辨識結 岑^七日:咬^我們可以利用此結果來判定相關的 〜象或疋〃耳胃波形之關聯性或是相似度。例如: 13 5. 1255419 ,們發現某兩影像/聲音資料實際上為同一影像/ 聲音資料則可以假定其時間戳記位置為相同。如 此一來便可以將兩個影像/聲音資料做對齊 ^ 作(Line Up) 〇 影像/聲音比對演算法: 1 ·影像子模組: (1)紀錄所有影像像素的色階。利用影像的色階有 RGB之區分每個R、G、B各為8 bits的二進位值 所構成。舉例來說r值的二進位值為〇〇〇〇丨丨丨丨,G 值的二進位值為11 1 10000,B值的二進位值為 01011010則在時間戳記〇的位置上之影像框架 (Video-Frame)RGB 組合後 的值為 00001 1 1 1 1 1 1 100000101 1010。依此類推則可將時間 戳記上所有的影像像素之二進位值全部紀錄下 來。並儲存於記憶體或是硬碟中。 (2) 將影像像素的色階紀錄在資料庫中。 (3) 將比較的影像資料和紀錄在資料庫中的影 :料:Checksum比較,也就是比較所有影像之二進 :::合,如果兩者之二進位值的總合相同或是 在門榼值内則可判斷為相同的影像資料。 2 ·聲音子模組: 、 (1)紀錄聲音變化的頻率 小夕π八λα - & …川耳耳日▽ m幅有 〇的時;下值:構成。舉例來說在時間^ 成為二進位值的時候,此點的振幅…二轉: 14 1255419 (Η⑽。依此類推則可將時間戮記上所有的影像 曰麻^ Γ進位值全部紀錄下來。並儲存於記憶體或 疋硬碟中。 ⑺將聲音變化的頻帛響應紀錄在資料庫中。 =)將比車乂的聲t貧料和紀錄纟資料冑中的聲音資 埒做Checksum比較,也就是比較所有聲音之二進 =值的總合,如果兩者之二進位值的總合相同或是 在門檻值内則可判斷為相同的聲音資料。 本發明至少具有下列優點。首*,mi/m2/m3 2 ίϋ儲存方式及編碼/解碼過程所產生。因此不 _L =合二料的儲存格式上或是儲存資料的時間戳記 ili些許的不同,這造成了原來的影音比較演算 可以、Λ、較技術之盲點。然而,透過新的測試比較方法,我們 =^成不同儲存媒體,及不同時間戳記上之影音内容的比較及測 ;i捲弟;。’.本發明供對於影像及聲音資料的對齊處 ,r lne Up method),可用於在不時間戳記下 』旦面的對齊效果,並能夠應用在不同媒體間轉換 爾存方式之控制晶片的測試比對。 【實施方式】 體實施你丨 依 片 片 後 據本發明之第—具體實施例4 DVD R⑽dable晶 及DVD R/W晶片的測試方式。DVD Rec〇rdaMe晶 ^ DVD R/W的功能是播放或儲存影音資料並在日 重新播放(回放Playback),以供使用者完成儲存大 15 1255419 量影音資料的目的。 測試流程如下·· 2 1、收集所有影音資料’並在DVD PUyer播放 光碟片的時候儲存影音資料並將影音 貝:轉化成二進位資料成為參考資料庫Ml。 二木所有影音資料’並在DVD Piayer播放 VD光碟片的時候儲存影音資料在硬碟中 f將硬碟中之影音資料轉化成二進位資 =參考資料庫M2。(此時mi/m堵 袼式不同)。 t 收集所有影音資料,並將硬碟中之影音 轉化播放出來,播放影音資料的同時並將此 :?的影音資料轉化成二進位資料成為來 考貝料庫M3。(此時Ml/M2/M3的儲存格 都不同)。 ° ^ 4 舉例來說,當實際的晶片測試開始的時候, 中總共有九十分鐘的影音資料的資料庫 貪料,測試方式為隨機將九十分鐘的影立次 料取出五分鐘的影音資料並錄製在4 4 中,我們將這五分鐘的影音資料轉化成 影音資料紀錄在硬碟後,會有回放過程將這 五分鐘影音資料從硬碟中重新播放出來, 們將這重新播放出來的影音資料轉化 M3。 Λ 馬 16 比對測試過士 則之某五八V 需要知道原始資料 二五刀1里的影音資料片段,和硬碟 名i’n之賁料M2,是否相同以確保控制晶 編碼/解碼並儲存影音資料進入硬碟的 過紅中所有的資料都是正確的。在這個情 况下我們利用相對位置比較法的pattern2. 3. Data collection and data training actions: We can record all binary data of all RGB elements in all images and store them in the database as the first reference value for subsequent comparison. Simplified simplification · All binar data pools of image data can be reduced to statistical data and used as a second benchmark for subsequent comparisons. The partitioning area divides the area and performs the comparison action at the same time: the display area of all the shadow data can be divided into different areas and compared with the first reference value and the second reference value in a small range area and immediately subtracted. The comparison produces results at the same time. Object: Identification: When the first reference value and the second reference value are subtracted from the same result or exceed a threshold value, we can know that the probability that an object is the same object is quite high. As a result, you can quickly find the correct time to estimate the image or sound data. (For example, if the first benchmark value is 100 and the second benchmark 3 101' gate root value is 5, then we can assume that the two images, / sound data). Because 101-100 two 1 < 5. =—,1 (or the discrimination of the sound waveform)··When the object identification is knotted ^7: bite ^ We can use this result to determine the correlation or similarity of the related ~ elephant or 疋〃 ear and stomach waveform . For example: 13 5. 1255419, we can find that a certain image/sound data is actually the same image/sound data, and the position of the time stamp can be assumed to be the same. In this way, the two image/sound data can be aligned (Line Up) 影像 Image/sound comparison algorithm: 1 · Image sub-module: (1) Record the color gradation of all image pixels. The color gradation of the image is composed of RGB, and each of R, G, and B is a binary value of 8 bits. For example, the binary value of the r value is 〇〇〇〇丨丨丨丨, the binary value of the G value is 11 1 10000, and the binary value of the B value is 01011010, and the image frame at the position of the time stamp ( Video-Frame) The combined value of RGB is 00001 1 1 1 1 1 1 100000101 1010. And so on, you can record all the binary values of all image pixels in the time stamp. And stored in memory or hard drive. (2) Record the color gradation of the image pixels in the database. (3) Compare the image data and records in the database: Material: Checksum comparison, that is, compare the binary of all images:::, if the sum of the two binary values is the same or at the door Within the threshold, it can be judged as the same image data. 2 · Sound sub-module: , (1) Record the frequency of sound change Xiao Xi π 八λα - & ... Chuan ear ear ▽ m amplitude has 〇 time; lower value: composition. For example, when time ^ becomes a binary value, the amplitude of this point... two turns: 14 1255419 (Η (10). By analogy, all the images of the castor ^ Γ carry value can be recorded. Stored in memory or hard disk. (7) Record the frequency response of sound changes in the database. =) Compare the sounds of the sounds of the ruts and the sounds of the records and data. That is, the sum of the binary values of all the sounds is compared, and if the sum of the two binary values is the same or within the threshold value, the same sound data can be judged. The present invention has at least the following advantages. The first*, mi/m2/m3 2 ϋ storage method and encoding/decoding process are generated. Therefore, _L = the storage format of the two materials or the time stamp of the stored data is slightly different, which results in the original video and audio comparison calculus, Λ, and more technical blind spots. However, through the new test comparison method, we =^ into different storage media, and the comparison and measurement of audio and video content on different time stamps; '. The present invention is for the alignment of image and sound data, r lne Up method), can be used for the alignment effect of the surface without the time stamp, and can be applied to the control wafer test of the conversion mode between different media. Comparison. [Embodiment] The method of testing the DVD R (10) dable crystal and the DVD R/W wafer according to the fourth embodiment of the present invention after the implementation of the film. DVD Rec〇rdaMe Crystal ^ The function of DVD R/W is to play or store audio and video data and replay (Playback Playback) on the day for users to complete the storage of large 12 1255419 audio and video materials. The test procedure is as follows: 2 1. Collect all audio and video data' and store the audio and video data when the DVD PUyer plays the optical disc and convert the video and audio into a binary data to become the reference database Ml. All the audio and video materials of the two woods and store the audio and video data on the hard disk when the DVD Piayer plays the VD disc. f Convert the audio and video data in the hard disk into the binary resource = reference database M2. (At this time, the mi/m block is different). t Collect all audio and video data, and convert the video and audio on the hard disk, play the video and audio data, and convert the video data into binary data to become the M3. (At this time, the Ml/M2/M3 cells are different). ° ^ 4 For example, when the actual wafer test starts, there is a total of 90 minutes of data and audio data in the data library. The test method is to randomly take 90 minutes of shadow data to take out five minutes of video and audio data. And recorded in 4 4, we converted the five minutes of audio and video data into audio and video data recorded on the hard disk, there will be a playback process to replay the five minutes of video and audio data from the hard disk, we will replay this Video and audio data is converted to M3. Λ 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 16 All the information in the storage of audio and video data into the hard disk is correct. In this case we use the pattern of relative position comparison

Recognition方式將M2即時並且不間斷的和Recognition method will M2 instant and uninterrupted and

Ml中所有的影音資料做比對,比對方式為 將M2中每個影音框架(Vide〇_Audi〇Compare all the audio and video materials in Ml, and compare them to each audio and video frame in M2 (Vide〇_Audi〇

Frame),都和M1中的所有影音框架做相減 的動作’找出在門檻值以下的比對結果,此 比對結果所代表之Ml中的某個影音框架, 其所代表之時間戳記點就是M2的影音資料 之相對應之時間戳記位置。例如:九十分鐘 的Ml衫s框架數目為9〇x6〇x3〇 = i62,〇〇〇個 框架/每秒,而五分鐘的M2中的影音框架數 目為5X60X30 = 9, 000個框架/每秒。M2框芊 要由第零個…置同步向:持 9, 000個框架直到找到正確的框架範圍為 止。框架相減的方式為將所有影像像素的二 進位值都做相減。聲音波形所代表之二進位 值也做相減。 比對測試過程中,同時我們也需要知道原始 資料Ml中之某五分鐘的影音資料片段和硬 碟所回放之影音資料M3是否相同以確保控 1255419 制晶片在編碼/解石馬及回放硬碟中的影音資 枓的過程中,所有的資、 上述第五點之方法…二正確的。頰似 丄丄 我們也是利用影音框牟 7 之相減結果來找出M3框架之正確 ,、 ‘在利用完上述之PatteFn p 崎位置 找出正確之框架位ReC〇^lti〇n方式Frame), and all the audio and video frames in M1 do the subtractive action 'find the comparison result below the threshold value, the comparison result represents a certain audio and video frame in Ml, the timestamp point it represents It is the corresponding time stamp position of the M2 video and audio data. For example: the number of frames for the 90-minute Ml shirt is 9〇x6〇x3〇= i62, one frame per second, and the number of video frames in the five-minute M2 is 5X60X30 = 9, 000 frames per second. M2 box 芊 To be synchronized by the zeroth... Hold 9,000 frames until the correct frame range is found. The frame subtraction is done by subtracting the binary values of all image pixels. The binary value represented by the sound waveform is also subtracted. During the comparison test, we also need to know whether the five-minute video data segment in the original data Ml and the video data M3 played back on the hard disk are the same to ensure that the 1255419 chip is in the encoding/resolving horse and playing back the hard disk. In the process of video and audio assets, all the funds, the method of the above fifth point... two correct. Cheek like 丄丄 We also use the subtraction result of the video frame 牟 7 to find out the correctness of the M3 frame, ‘in the use of the above-mentioned PatteFn p position to find the correct frame position ReC〇^lti〇n way

Checks⑽方式比對相同以利用 及聲音資料是否相之影像 内。—的原it 值之 的_值轉化成二進位數值,同時也將= ί::力所之振幅值轉化成為二進位數 =並作加總的動作。比較影像及聲音 :候;就f接將二進位數值總合做比對以、完 植值内的話,二對結果在門 之則為不相似=二為相似或是pass。反 此外,使用灰階的影俊 ㈣不饵“卞並透過上述程序也可以奉 到很不錯的對齊及比料从 Φ ^ ^ ^ +的效果。灰階的影像與上述) 式中的影像的不同處名#义土 、 I^A ,在别者只用到黑白兩色,而卷 者用的色階由RGB二種多音洛知人L 信 —裡顔色組合而成。 雖然本發明已 限定本發明, 精神和範圍内 以具體實施例揭露如上,然其並非用以 壬^热習此技藝者,在不脫離本發明之 ,當可作各種之更動與潤飾,因此本發 18 1255419 月之保°蔓範圍當視後附之申請專利範圍所界定者為 準0 , 【圖式簡單說明】 5 1圖係先前技術之流程方塊圖。 第2圖係本發明之代表示意圖。 ,3圖係影音模組之流程示意方塊圖 第4圖係測試模組之流程示意方塊圖 主要元件符號說明 1 〇 1 ·控制模組。 報告子模組C 純文字檔。 其他程式。 記憶體。 聲音子模組〇 影音模組(模 ] 103 105 107 109 111 201 I 0 2 ·監視子模組。 104 · RS232 PORT 。 106 · XML 檔。 108 ·主控台。 II 〇 ·影像子模組。 11 2 ·測試模組。 組 ):具有播放程序、紀錄程序 口放秩序及其他程序。 =料播放程序(Play):播放存在原始影音媒體中的 203 ·紀錄程序(Record):紀錄播放之f彡立眘 2〇4 ·回放簌皮u 了、馆從々〜日貝枓。 双牙王序(Playback) ··回放儲在太 之影音資料。 u孜储存在儲存裝置中 2〇5儲存裝置(如硬碟或是記情妒) 類比或是數位眘枓心…士 L體).所有可以當傲 憶體或是非插 已3吏亲揮發性記 Λ疋非揮發性記憶體。 1255419 206 u子模組:處理影像之比對及相似性測試。 .卑曰子模組:處理聲音之比對及相似性測試。 208相關位置比較方法模組:處理並搜尋在不同儲 存媒體中之影音資料的時間戳記點及其相關位置。 209·測試模組(模組二):具有影像子模組、聲音子 模組、相關位置比較方法模組。 210 .冗憶及儲存模組:類似上述儲存裝置的功能,例 士更業揮發性記憶體或是非揮發性記憶體。 211 ’傳輸介面:包含RS232 PORT。 原始影音媒體(EX: VCD/DVD”儲存原始之影音 = ·/:音顯示裝置(顯示器或是喇叭):所有可以將 衫像或疋聲音資料播放出來的裝置,包含顯示器或是 214 ·其他程序:其他未來可能之相關控制程序。 301 ·影音來源媒體(如VCD/DVD光碟片)。 3 0 2 ·影音模組(模組一)。 3 0 3 ·儲存裝置(如硬碟或是記憶體)。 304 ·影音顯示裝置(顯示器或是喇u八)。 3 0 5 ·模組二。 306 ·其他程序(others):軟體編碼/ 硬體解碼編碼晶片。 巧私序或疋 307·回放程序(piayback)。 308·紀錄程序(Rec〇rd)。 309 ·播放程序(Play) 401 ·媒體一 402 ·媒體二 20 1255419 403 ·媒體三。 4 0 5 ·流程二。 407 ·影像子模組。 409 ·相對位置比較方法。 41 0 ·測試模組(模組二)。 411 ·測試結果·流程四。 41 3 ·測試結果:流程三。 41 4 ·記憶及儲存模組。 4 0 4 ·流程一。 4 0 6 ·轉存。 408 ·聲音子模組。 4 1 2 ·傳輸介面。The Checks (10) method is the same as the comparison to see if the sound data is in the same image. The _ value of the original it value is converted into a binary value, and the amplitude value of the = ί:: force is converted into a binary digit = and the action is added. Compare the image and sound: Wait; if the sum of the binary values is compared with the sum of the values, the two pairs of results are not similar in the door = the second is similar or pass. In addition, the use of gray-scale shadows (four) do not bait "卞 and through the above procedures can also be very good alignment and material ratio from Φ ^ ^ ^ + effect. Grayscale image with the above) Different places name #义土, I^A, in other cases only use black and white, and the color scale used by the volume is composed of RGB two kinds of multi-tone Luo Zhiren L letter - the color combination. Although the invention has been limited The present invention has been disclosed in the above embodiments in the spirit and scope of the present invention. However, it is not intended to be used by those skilled in the art, and various changes and modifications may be made without departing from the invention. The scope of the patent application is defined as 0. [Simplified description of the drawings] 5 1 is a flow chart of the prior art. Fig. 2 is a schematic diagram of the representative of the present invention. The flow chart of the audio and video module is shown in Figure 4. The flow chart of the test module is shown in the block diagram. The main component symbol description 1 ·1 · Control module. Report submodule C plain text file. Other programs. Memory. Group video module (modulo) 103 105 107 1 09 111 201 I 0 2 · Monitor sub-module 104 · RS232 PORT 106 · XML file 108 · Main console II 〇 · Video sub-module 11 2 · Test module. Group): With playback program, Recording program order and other procedures. = material playback program (Play): play the original video and audio media 203 · Recording program (Record): record playback f彡 Li Shen 2〇 4 · playback suede u, the museum From 々 日 日 日 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 双 Play Play Play Play Play Play Play Play Play Play Play Be careful with the heart...L body). All can be arrogant or non-inserted. It is a non-volatile memory. 1255419 206 u sub-module: processing image comparison and similarity test. Despicable sub-module: processing sound comparison and similarity test 208 related position comparison method module: processing and searching for time-stamp points of audio and video data in different storage media and their related positions. 209·Test module (Module 2): with image sub-module, sound sub-module Related location comparison method module 210. Reverberation and storage module: similar to the functions of the above storage device, such as volatile memory or non-volatile memory. 211 'Transport interface: including RS232 PORT. Original audio and video media (EX: VCD/DVD) stores the original audio and video = · / : audio display device (display or speaker): all devices that can play the shirt image or sound data, including the display or 214 · Other programs: other future Possible related control procedures. 301 · Video source media (such as VCD/DVD discs). 3 0 2 · Audio and video module (module one). 3 0 3 · Storage device (such as hard disk or memory). 304 · Audio and video display device (monitor or raj). 3 0 5 · Module 2. 306 Other programs: software coding / hardware decoding coded chips. Clever private order or 疋 307. Playback program (piayback). 308. Recording procedure (Rec〇rd). 309 · Playback program (Play) 401 · Media one 402 · Media two 20 1255419 403 · Media three. 4 0 5 · Process 2. 407 · Image sub-module. 409 · Relative position comparison method. 41 0 · Test module (module 2). 411 · Test results · Process 4. 41 3 · Test results: Process 3. 41 4 · Memory and storage module. 4 0 4 · Process 1. 4 0 6 · Transfer. 408 · Sound sub-module. 4 1 2 · Transmission interface.

Claims (1)

1255419 十、申請專利範圍: 1 · 一種儲存裝置中之影音資料的比對測試方法,其中 至少包含兩個模組,並利用事先以人工挑選過之黃金樣 品(Golden Sample)儲存在資料庫的二進位影音資料, 再透過比對測試及對齊方式完成品質測試(Quality巧沁程序並透 過適當之傳輸方式輸出結果(Pass or Fai 1)到外部系 統; ’、 在第一項影音模組中,不同的影音資料透過編碼/解碼 (Encode/Decode)之軟硬體方式,至少達成下列三項主要影音程序: (1) ·從輸出裝置播放(Play)影音資料,包含編碼/解碼 (Encode/Decode)之軟硬體方式; (2) ·儲存裝置儲存(Record)在上一程序中從輸出裝置所 播放之影音資料; (3) ·從儲存裝置回放(Playback)已經儲存之影音資料; 在第二項測試模組中,至少有下列三項子模組: (1) 景>像子模組··處理影像資料,包含輪入裝置並同時 處理儲存影像資料; (2) 聲音子模組:處理聲音資料,包含輸入裝置並同時 處理儲存聲音資料; 、 (3) 相關位置比較模組:比對影像及聲音相關位置; 在第二項測試模組中,至少完成下列兩項測試程序: ⑴影音串流資料比對測試及對齊(Video/Audio Stream Data Test and Line up)程序-利用相關位置比較演算方法達成: (a·)比對受測品透過輸入裝置轉換之二進位影音資料庫, 及儲存裝置儲存(Record)之黃金樣品(G〇lden Sample)的二進位影音資料,並找出相對的時間戳記 位置,同時將相同時間戳記的影音資料對齊,以利於做^ 22 !255419 質測試(Quality Test),以及(b·)比對受測品透過輸入裝置 播放(Play)影音資料,及儲存裝置回放(Playback)之黃 金樣品(Golden Sample)的二進位影音資料並找 出相對的時間戳記位置同時將相同時間戳記的影音資料對 齊(Line up)以利於做後續之品質測試(Quality Test); (2)品質測試(Quality Test)程序-以影像/聲音比對演算法做 出影像及聲音資料比對及測試並由門檻值的不同來判斷比 封測試結果為成功還是失敗(Pass or Fail)。 ^品~申請專利範圍第1項所述之方法,其中之黃金 準g (QG〇lden Sa_le)為人工挑選符合預期的比對標 3音H 專利範圍第1項所述之方法,其中在第一項影 不限於 之編碼/解碼(Enc〇de/Decode)之軟硬體方式至少包含但 MpU下列方式:JPEG、Motion JPEG、MPEG]、MPEG-2 了 解瑪、、會WMV、WMA及同質性之影音編碼/ Λ、异法所製成之軟體程序及硬體晶片。 音ΐ U專之』項f八述之方法,其中在第-項影 Playa 輸出凌置至少包含但不限於下列裝置:VCD 用以撤廿 I layer、CD Player、MP3 Player,及可 性裝^ 位/類比影像或是數位/類比聲音之同質 至少包人:f利範圍第1項所述之方法,其中儲存裝 碟、礎帶i同置:揮發f記憶體、非揮發性記憶體、 、/、有類比或是數位資料之儲存功能的裝置。 23 1255419 匕申^專利範圍$ 1 2 3項所述之方法,其中在第二項洌 到之”相難置比補算方法,,可包含:模塊7 碰vH(Iattem Recogniti〇n)、色差比對技術方法、頻 :;像:立)頻番率發生位置比較技術方法及同質性 二二 比對演算法技術並和時間戳記結 口 以達成相關位置搜尋的目的。 專利範圍第1項所述之方法,其中在第二項測 且中所提到之,,影像/聲音比對演算法,,可包含:模塊比 ^«Pattern Recognition)、色差比對技術、頻譜分析技 =以及RGB二進位值轉換演算法 演Λ法,以達 對^試。〜象或疋茸音貢料在相同時間戳記點之比 K《I : ί f範圍,第1項所述之方法,其中在第二項測 利用,,相_ ί到4影像7聲音輯演算法,,同時也可以達成 二才,二置比較演算方法,’料之影音資料時_己點之對齊 工儿成自動重新訓練影音資料及重新比對影音資料之功能。 ^二申:專f乾圍第1項所述之方法,其中在第二3 趣、、且中所提到之相對的時間戮記位 時間戳記位置及相對時間之時間戳1=置巴。對時間 之方法,其中在第二項 影像資料相似度門檻 制資料之門檻值;當 24 1 0 ·如申請專利範圍第i項所述 2 測試模組中所提到之門檻值包含·· 3 值、聲音資料相似度_門檻值、控 1255419 ί fF: t i測資測試品質低於門檻值則失 檻值之定義方右广於門檻值則通過(pass);門 挪試結果及_/般樣=:黃金樣品(G〇lden Sa—e)的 性的定義;各至乂 :口 ,測§式結果之差異性來做相對 二:V羡品的測試結果為95,而我們可容忍ί …為正負5%’則我們可定義門檻值為9〇,的 :二”利範圍第1項所述之方法,其中在第二項 聲:‘取且卡:輸入裝置至少包含但不限於下列裝置:影像擷取卡、 ^擷取卡’其功能在於將第一項影音模组中輸出裝置的資料掏取 如申請專利範圍第1項所述之方法,其中在第-, 的輸人裝置以 -像及/立料的格式為第一項影音模組中輸出之 像及耳9 -貝料透過輸入裝置擷取後的資料之二途 像ΐ分別計算該輸入資料之每-輸Λ 料;5嗲立4 、〜之輸入影像像素的RGB 24位元資 參數’其中影像像素資料及聲音振幅ΐ ” 5座:別ί應成為*同之矩陣#料並儲存於記 ^貝r、,影像資料的色階有RGB之區分每個R、 當、二為二 β 為 111,G值的二進位值為 斜庫的里彡德1值的二進位值為01011010則在記憶資 ”、 ^ 貝料值為 000〇lUlllll〇〇00〇i(Hi〇i〇;聲 1255419 音振幅參數的二進位值構成方式如下,a & 20dB,轉化成為二進位值的時候 田卑曰振幅為 Mts的000 1 0 1 00,則在記憶資料庫辰幅值為8 值為000 1 0 1 00 ;當儲存於矩陣 耳s振巾田芩數 音資料都是矩陣的-部份,因此在不::3影像及聲 及聲音資料集合起來就是一個报大不:=:=像 陣資料庫。 扪一進位影音矩 13.如申請專利範圍第1項所述之 =項測試模組/受測品的影音資料經由輸/裝置中進在= ,,了以即時(Real Time)的透過專利範圍第項所 =ί Γ進位轉換格式轉換輸入資料成為二進位矩陣 ’並與原來的黃金樣品(G〇lden Sample)所轉 =成的二進位矩陣資料庫做比對,達成即時處理 CKeal lime process)的效能。 14·如申請專利範圍第丨項所述之方法,其中,適當 之傳輸方式可包含但不限於下列傳輸介面:RS232、USB、 1 394 > SCSI-1 >SCSI-II> pci > PCI Express > Wi re 1 ess # LAN 、 Wired LAN 、 COM P〇rt 、 Parallel P〇rt 。 1 5 · —種儲存裝置中之影像資料的比對測試方法,其 中至少包含兩個模組,並利用事先以人工挑選過之黃金 樣品(Golden Sample)儲存在資料庫的二進位影像資 料’再透過比對測試及對齊方式完成品質測試(QualityTest)程序並 透過適^之傳輸方式輸出結果(pass 〇Γ Fail)到外部 26 1255419 系統; 在第一項影像模組中,不同的影像資料透過蝙瑪/解石馬 (Encode/Decode)之軟硬體方式,至少達成下列三項主要影像程序/ (1) ·從輸出裝置播放(Play)影像資料,包含編石馬/解石、 (Encode/Decode)之軟硬體方式; (2) ·儲存裝置儲存(Record)在上一程序中從輪出裝置所 播放之影像資料; < (3) ·從儲存裝置回放(Playback)已經儲存之影像資料· 在第二項測試模組中,至少有下列兩項子模組: ' (1) ·影像子模組:處理影像資料,包含輸入裝置並同時 處理儲存影像資料; · (2) ·相關位置比較核組·比對影像相關位置; 在第二項測試模組中,至少完成下列兩項測試程序: (3) 影像串流資料比對測試及對齊(Video Stream Data Test and ' Line up)程序-利用相關位置比較演算方法達成:(a·)比對 . 受測品透過輸入裝置轉換之二進位影像資料庫,及儲存 裝置儲存(Record)之黃金樣品(Golden Sample) 的二進位影像資料,並找出相對的時間戳記位置,同時 將相同時間戳記的影像資料對齊,以利於做品質測試鲁 (Quality Test),以及(b·)比對受測品透過輸入裝置播放 (Play)影像資料,及儲存裝置回放(Playback)之黃金 樣品(Golden Sample)的二進位影像資料並找出 相對的時間戳記位置同時將相同時間戳記的影像資料對齊 (Line up)以利於做後續之品質測試(Quality Test); (4) 品質測試(Quality Test)程序-以影像比對演算法做出影像 貝料比對及測試並由門植值的不同來判斷比對測試結果為 成功還是失敗(Pass or Fail)。 27 1255419 1 6 ·如申請專利範圍第1 5項所述之方法,其中之黃 金樣品(Golden Sample)為人工挑選符合預期的比對 標準物。 17·如申請專利範圍第15項所述之方法,其中在第一 項影像模組中之編碼/解碼(Encode/Decode)之軟硬體方式至少包 含但不限於下列方式:JPEG、Motion JPEG、MPEG_1、 MPEG-2、MPEG-4、WMV及同質性之影像編碼/解碼 演算法所製成之軟體程序及硬體晶片。 1 8·如申請專利範圍第15項所述之方法,其中在第一項 影像模組中之輸出裝置至少包含但不限於下列裝置:VCD Player、DVD Player,及可用以撥放數位/類比影像之 同質性裝置。 ’ 1 9 ·如申請專利範圍第1 5項所述之方法,其中儲存 置至少包含但不限於下列裝置:揮發性記憶體、非揮發性記情 硬碟、磁帶及同質性具有類比或是數位資料之儲存功能的裝 1置_。' 2 0 ·如申請專利範圍第1 5項所述之方法,其中 項測試模組中所提到之”相關位置比較演算方法,,可包含·二 塊比對技術方法(Pattern Recognition)、色差比對技術方、去模 頻譜分析方法及同質性之影像位置比對演算法/ 並和時間戳記結合,以達成相關位置搜尋的目的。術 2 1.如申請專利範圍第 項測試模組中所提到之 技#f (Pattern Recognition)、 , 仕第 影像比對演异法可包含:模塊比 色差比對技術、頻譜分析技] 28 1255419 =及RfB二進位值轉換演算法之比對方法及同質性 拳ΪΪΪίϊ:?算法,以達成兩份儲存在不同儲存 、置之衫像貝料在相同時間戳記點之比對測試。 範圍第15 ’所述之方法’其中在第二項 ,相關位置比較演算方法,,搜尋之影像資料時間戮記點之對齊^ 式,元成自動重新訓練影像資料及重新比對影像資料之功能。 23·如申請專利範圍第15項所述之方法,苴 測,組中戶斤提到之相對的時間戳記位置可包含:、絕^ t員 之時間戳記位置及相對時間之時間戳記位置。 如申請專利範圍第15項所述之方法,其中在第二 ;Γ=中所提到之門檻值包含:影像資料相似度門一檻 資料之門檻值;當影像受測資料之測試品質 =門檻值則失敗(Fa⑴,反之,若高於⑽值則^ ^ (PaSS),門檻值之定義方式可以從黃金樣口 golden Sa.ple) ^ ^ ^ # ^ ^ ^ ^ 之〜、性來做相對性的定義;當黃金樣品(Μ — e的測试結果為丨〇〇,一般樣品的測試結果為 義門:Γ;1可容忍的誤差度為正15%,則我們可定 義門檻值為9 0。 η心 25、·如申請專利範圍第15項所述之方法,其中 W&細_了繼:影像操取 J此在於將第-項影像模組中輸出裝置的資料操取下來。 29 1255419 26.如申請專利範圍第15項所述之方法,豆中 :測試f組中所提到之影像資料的輸入裝置及儲存處— 理,其儲存資料的格式為第一項影像模組中輸出= 像資料透過輸入裝置擷取後的資料之二進位值,〜 進位值係分別計算該輸入資料之每一 ; (PlXel)所對應之輸入影像像素的RGB 24位元資料 其中影像像素資料對應成為不同之、 ΓΓΓΛ中;影像資料的色階有⑽之區分= h.、心各為8 blts的二進位值所構成(共有24 =)’二R值的二進位值為〇〇〇〇11u,g值 值為1 1 1 10000,B值的-推办伯攻A 運位 情資f斗座沾 值為01011010則在記 枓庫的影像資料插^ oooomun则咖u㈣;當儲存 為 矩陣的一部份,因此在不二二 ΐ料庫是—個报大的二進位影像矩陣 27.如申請專利範圍第15項所述之 第二項測試模組中受測品的法,其中其中在 入後,可以即時一lm:;:透貝 所述之二進位轉換格式轉換轸^ 1乾圍第26項 陣資料庫,並與原來的黃金樣品^ =成為二進位矩 轉換成的二進位矩陣資料庫Q = Sample)所 ⑽"…rocess)的效:做比對,達成即時處理 28.如申請專利範圍第15項所述之方法,其中,適當 30 1255419 之傳輸方式可包含但不限於下列傳輸介面:RS232、USB、 1 3 94、SCSI-1、SCSI-I I、PCI、PCI Express、Wireless LAN、Wired LAN、COM Port、Para 11e 1 Port 〇 29· —種儲存裝置中之聲音資料的比對測試方法,其中 至少包含兩個模組,並利用事先以人工挑選過之黃金樣 品(Golden Sample)儲存在資料庫的二進位聲音資料, 再透過比對測試及對齊方式完成品質測試(Quality Test)程序並透 過適當之傳輸方式輸出結果(Pass or Fai 1)到外部系、 統; 在第一項聲音模組中,不同的聲音資料透過編碼/解碼 (Encode/Decode)之軟硬體方式,至少達成下列三項主要聲音程序· (1) ·從輸出裝置播放(Play)聲音資料,包含編碼/解碼 (Encode/Decode)之軟硬體方式; (2) ·儲存裝置儲存(Rec〇rd)在上一程序中從輸出裝置所 播放之聲音資料; X (3) ·從儲存裝置回放(Playback)已經儲存之聲音資料; 在第二項測試模組中,至少有下列兩項子模組: 、 (3) .聲音子模組:處理聲音資料’包含輸入裝置並同 時處理儲存聲音資料; (4) ·相關位置比較模組:比對聲音相關位置·, 在第二項測試模組中,至少完成下列兩項測試程序: (5)聲音串流資料比對測試及對齊(Audi〇 Stream Data Test and Line up)程序-利用相關位置比較演算方法達成:) 比對受測品透過輸入裝置轉換之二進位聲音資料庫,及 儲存裴置儲存(Record)之黃金樣^Mu〇iden Samp i e )的二進位聲音資料,並找出相對的時間戮記 31 1255419 位置,同時將相同時間戳記的聲音資料對齊,以利於做品 質測試(Quality Test),以及(b·)比對受測品透過輸入裝置 播放(Play)聲音資料,及儲存裝置回放(Playback)之 頁金樣品(Golden Sample)的二進位聲音資料 並找出相對的時間戳記位置同時將相同時間戳記的聲音 貧料對齊(Line up)以利於做後續之品質測試(Quai办 Test); (6)品質測試(Quality Test)程序-以聲音比對演算法做出聲 音資料比對及測試並由門檻值的不同來判斷比對測試結 果為成功還是失敗(Pass or Fail)。 3 〇 金樣Γ (申睛專利範圍第2 9項所述之方法’其中之黃 標^物G 01 d e n S a m ρ 1 e )為人工挑選符合預期的比對 項1聲利範圍第29項所述之方法’其中在第一1255419 X. Patent application scope: 1 · A comparison test method for audio and video data in a storage device, which includes at least two modules, and stores the gold sample in the database by using a manually selected gold sample (Golden Sample). Carrying audio and video data, and then completing the quality test through the comparison test and alignment (Quality and the program output the result through the appropriate transmission method (Pass or Fai 1) to the external system; ', in the first audio and video module, different The audio and video data of the Encode/Decode can achieve at least the following three main audio and video programs: (1) Play (Play) audio and video data from the output device, including encoding/decoding (Encode/Decode) (2) storage device (Record) audio and video data played back from the output device in the previous program; (3) playback (playback) of the stored audio and video data from the storage device; In the test module, there are at least the following three sub-modules: (1) Scenery > Sub-module · Processing image data, including wheeling device and processing storage image at the same time (2) Sound sub-module: processing sound data, including input device and processing stored sound data at the same time; (3) related position comparison module: comparing image and sound related position; in the second test module, Complete at least the following two test procedures: (1) Video/Audio Stream Data Test and Line up program - Use the relevant position comparison calculation method to achieve: (a·) Compare the test object through the input The device converts the binary video library, and the storage device stores the binary data of the gold sample (G〇lden Sample), and finds the relative time stamp position, and aligns the video data of the same time stamp. In order to facilitate the ^ 22 ! 255419 quality test (Quality Test), and (b ·) comparison of the test object through the input device to play (Play) audio and video materials, and storage device playback (Playback) gold sample (Golden Sample) two Carry in the video and audio data and find the relative time stamp position and line up the video data of the same time stamp to facilitate the subsequent quality test (Quality Test); (2) Quality Test program - image/sound comparison algorithm to make image and sound data comparison and test and judge the success or failure of the test result by the difference of threshold value (Pass Or Fail). The method described in item 1 of the patent application, in which the gold standard g (QG〇lden Sa_le) is a manual method for selecting the expected matching standard 3 tone H patent range item 1 The software and hardware method in which the first item is not limited to encoding/decoding (Enc〇de/Decode) includes at least but MpU in the following ways: JPEG, Motion JPEG, MPEG], MPEG-2, and WMV. WMA and homogenous audio and video coding / software programs and hardware chips made by different methods. ΐ ΐ U 』 项 f 八 八 八 , , , , , , Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play Play The analogy of the bit/analog image or the digital/analog sound is at least included in the method of the first item, wherein the storage device and the base tape are co-located: volatile f memory, non-volatile memory, /, device with analogy or digital data storage function. 23 1255419 匕申^ Patent method range of $1 2 3, in the second item of the "difficult to set ratio" method, which may include: module 7 touch vH (Iattem Recogniti〇n), color difference Comparison technical method, frequency:; like: vertical) frequency occurrence position comparison technical method and homogeneity two-two comparison algorithm technology and time stamp junction to achieve the purpose of the relevant location search. Patent scope 1 The method described, wherein in the second test, the image/sound comparison algorithm may include: module ratio ^«Pattern Recognition, color difference comparison technique, spectrum analysis technique= and RGB II The carry value conversion algorithm deductive method, in order to reach the test. ~ Elephant or 疋 音 贡 tributary in the same time stamp point ratio K "I: ί f range, the method described in item 1, where in the second The use of the project, the phase _ ί to 4 image 7 sound algorithm, at the same time can also achieve two talents, two sets of comparative calculation method, 'material audio and video data _ point point of the work into automatic re-training audio and video materials And re-compare the function of audio and video data. ^ II Shen: The method described in Item 1, wherein the relative time mentioned in the second and third interest, and the time stamp of the bit time stamp position and relative time 1 = set the bar. The method, wherein the threshold value of the threshold data in the second image data similarity threshold; when 24 1 0 · the threshold value mentioned in the 2 test module described in item i of the patent application scope includes ·· 3 value, Sound data similarity _ threshold value, control 1255419 ί fF: ti test test quality is lower than the threshold value, the definition of the missing value is right outside the threshold value is passed (pass); door miss test results and _ / general sample = : The definition of the sex of the gold sample (G〇lden Sa-e); each to the mouth: the difference between the results of the § formula to do the relative two: the test result of the V product is 95, and we can tolerate ί ... Positive and negative 5% 'we can define a threshold value of 9 〇, the two: the method described in item 1, wherein in the second item: 'take and card: the input device at least includes but is not limited to the following devices: Image capture card, ^ capture card' function is to capture the data of the output device in the first audio and video module The method of claim 1, wherein the input device of the first-, and the image of the first audio-visual module in the form of image-and/or material is transmitted through the input device. The second data of the obtained data is used to calculate the input and output data of the input data separately; 5 the RGB 24-bit parameter of the input image pixel of 4 〜, and the image pixel data and sound amplitude ΐ ” :Do not ί should become *the same matrix #料 and stored in the record ^贝r,, the color spectrum of the image data has RGB distinction, each R, when, two is two β is 111, the binary value of the G value is oblique The binary value of the Liede 1 value of the library is 01011010, and the value of the binary value of the sound amplitude parameter is as follows: , a & 20dB, when converted to a binary value, the amplitude of the field is Mts 000 1 0 1 00, then the amplitude of the memory database is 8 value 000 1 0 1 00; when stored in the matrix ear s The sound data of the vibrating ridges are all part of the matrix, so in the no::3 video and sound and sound data collection It is not a big newspaper: =: = array like database.扪一进影影音 13. As for the test item of the test item/test item mentioned in item 1 of the patent application, the video and audio data of the test item are passed through the transmission/device, and the real time is passed through the patent range. The first item = Γ Γ carry conversion format converts the input data into a binary matrix' and compares it with the binary matrix database converted by the original gold sample (G〇lden Sample) to achieve immediate processing CKeal lime process) Performance. 14. The method of claim 2, wherein the appropriate transmission method may include, but is not limited to, the following transmission interfaces: RS232, USB, 1 394 > SCSI-1 >SCSI-II> pci > PCI Express > Wi re 1 ess # LAN , Wired LAN , COM P〇rt , Parallel P〇rt . 1 5 · A comparison test method for image data in a storage device, comprising at least two modules, and storing the binary image data stored in the database by using a manually selected golden sample (Golden Sample) Through the comparison test and alignment method to complete the quality test (QualityTest) program and output the result (pass 〇Γ Fail) to the external 26 1255419 system through the appropriate transmission; in the first image module, different image data through the bat In the soft and hardware mode of Encode/Decode, at least the following three main video programs are achieved / (1) • Play (Play) image data from the output device, including the stone/stone, (Encode/ Decode) software and hardware mode; (2) storage device to store the image data played by the device in the previous program; < (3) Playback (Playback) the stored image from the storage device Information · In the second test module, there are at least the following two sub-modules: ' (1) · Image sub-module: processing image data, including input device and processing stored image data at the same time; · (2) Correlation position comparison core group and comparison image related position; In the second test module, at least the following two test procedures are completed: (3) Video stream data comparison test and alignment (Video Stream Data Test and ' Line up Procedure - Use the relevant position comparison calculation method to achieve: (a·) comparison. The binary image database converted by the input device through the input device, and the binary image of the golden sample of the storage device (Golden Sample) Data, and find the relative timestamp position, and align the image data of the same time stamp to facilitate the quality test (Quality Test), and (b) compare the test object through the input device to play (Play) image Data, and the binary image data of the Golden Sample of the Playback Playback and find the relative time stamp position and simultaneously line up the image data of the same time stamp to facilitate subsequent quality testing ( Quality Test); (4) Quality Test program - image comparison and testing with image comparison algorithm and different threshold values Judgment than the success or failure (Pass or Fail) on the test results. 27 1255419 1 6 · The method of claim 15, wherein the Golden Sample is a manual selection of the expected alignment standard. The method of claim 15, wherein the software/hardware method of encoding/decoding (Encode/Decode) in the first image module includes at least but not limited to the following methods: JPEG, Motion JPEG, Software programs and hardware chips made by MPEG_1, MPEG-2, MPEG-4, WMV, and homogenous image encoding/decoding algorithms. The method of claim 15, wherein the output device in the first image module includes at least but not limited to the following devices: VCD Player, DVD Player, and can be used to play digital/analog images. Homogeneous device. The method of claim 15, wherein the storage includes at least but not limited to the following devices: volatile memory, non-volatile hard disk, tape and homogeneity with analog or digital The storage function of the data is set to _. ' 2 0 · The method described in claim 15 of the patent application, wherein the related position comparison calculation method mentioned in the item test module may include two methods of pattern recognition, color difference Compare the technical side, the demographic spectrum analysis method and the homogenous image position comparison algorithm / and the time stamp to achieve the purpose of the relevant position search. 2 2. As in the test module of the scope of the patent application The technique #f (Pattern Recognition), and the image comparison algorithm may include: module colorimetric comparison technique, spectrum analysis technique] 28 1255419 = and RfB binary value conversion algorithm comparison method and Homogeneity Boxing ΪΪΪ ϊ ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? Comparing the calculation method, the search image data time 戮 之 alignment, Yuan Cheng automatically re-train the image data and re-compare the image data function. 23 · If you apply for the scope of the 15th item The method described, speculation, the relative time stamp position mentioned by the group in the group may include: the time stamp position of the member and the time stamp position of the relative time. The method described in claim 15 The threshold value mentioned in the second; Γ = includes: the threshold value of the image data similarity threshold; when the test quality of the image under test = the threshold value fails (Fa (1), otherwise, if higher than (10) The value is ^ ^ (PaSS), the threshold value can be defined from the golden sample of golden Sa.ple) ^ ^ ^ # ^ ^ ^ ^ ~, sex to make a relative definition; when the gold sample (Μ - e The test result is 丨〇〇, the test result of the general sample is Yimen: Γ; 1 can tolerate the error degree is positive 15%, then we can define the threshold value of 90. η心25, · If the patent scope The method of claim 15, wherein the method of image processing is to take the data of the output device in the first image module. 29 1255419 26. As described in claim 15 Method, in the bean: test the loss of the image data mentioned in the f group Device and storage - The format of the stored data is the output of the first image module = the binary value of the data captured by the input device, and the value of the carry value is calculated for each of the input data; (PlXel) corresponds to the RGB 24-bit data of the input image pixels. The image pixel data corresponds to different ΓΓΓΛ; the color gradation of the image data has (10) distinction = h., and the heart is 8 blts binary value Composition (total 24 =) 'The binary value of the two R values is 〇〇〇〇11u, the value of g is 1 1 1 10000, and the value of B is - push the attack A. The value of the position is 01011010 In the case of the image data of the library, oooomun is used. (4); when stored as a part of the matrix, it is a large binary image matrix in the database. 27. The method of the tested product in the second test module mentioned in the item, wherein after entering, the instant lm:;: the binary conversion format conversion described by the 贝^1 dry circumference 26th array data Library, and with the original gold sample ^ = become a binary moment into a binary The matrix database Q = Sample) (10) "...rocess) effect: to do the comparison, to achieve immediate processing 28. The method of claim 15, wherein the appropriate transmission method of 30 1255419 may include but is not limited to The following transmission interfaces: RS232, USB, 1 3 94, SCSI-1, SCSI-I I, PCI, PCI Express, Wireless LAN, Wired LAN, COM Port, Para 11e 1 Port 〇 29 · Sound data in a storage device The comparison test method, which includes at least two modules, and uses the manually selected gold sample (Golden Sample) to store the binary sound data in the database, and then completes the quality test through the comparison test and alignment ( The Quality Test program outputs the results (Pass or Fai 1) to the external system through appropriate transmission methods. In the first sound module, different sound data are transmitted and decoded (Encode/Decode). In this way, at least the following three main sound programs are achieved. (1) Play (Play) sound data from the output device, including software/hardware mode of Encode/Decode; (2) Storage device Store (Rec〇rd) the sound data played from the output device in the previous program; X (3) • Playback (Playback) the stored sound data; In the second test module, at least the following Two sub-modules: , (3). Sound sub-module: processing sound data 'contains input device and processes stored sound data at the same time; (4) · Relevant position comparison module: compares sound related position ·, in second In the test module, at least the following two test procedures are completed: (5) Audio stream data test and line up program - using the relevant position comparison algorithm to achieve :) Comparison The binary sound data of the test product converted through the input device, and the binary sound data of the golden sample ^Mu〇iden Samp ie stored in the storage device, and find the relative time to record the position of 31 1255419, Align the sound data of the same time stamp to facilitate the quality test (Quality Test), and (b) compare the test object through the input device to play (Play) sound data, and the storage device playback (Playb Ack) The golden sample of the binary sample and find the relative timestamp position and line up the sound of the same time stamp to facilitate subsequent quality testing (Quai Test); (6) Quality Test program - The sound comparison algorithm and the sound comparison algorithm are used to judge and compare the threshold value to the success or failure (Pass or Fail). 3 〇金样Γ (The method described in item 29 of the scope of the patent application 'the yellow label ^ G 01 den S am ρ 1 e ) is manually selected to meet the expected comparison item 1 vocabulary range item 29 The method described therein riayer、D Μ-仏1土/ 旦个 π^、·〜机且· VL;13 用以撥放 Player、MP3 Player、CO Player,及可 " 數位/類比聲音之同質性裝置。Riayer, D Μ-仏1 soil / Dan π^, · machine and · VL; 13 for Player, MP3 Player, CO Player, and homophonic device for digital/ analog sound. 凊專利範圍 包人曰寻刊乾圍第2 9項所述之方法,其中儲存裳 磁=仁不限於下列裝置··揮發性記憶體、非揮發性記憶體、 ’及同貝性具有類比或是數位資料之儲存功能的裝置。 1255419 34、·如申請專利範圍第29項所述之方法,其中在 ,测試模組中所提到之,,相關位置比較演算方法,,可包含:- 瑨,析方法及頻率發生位置比較技術方法及同質性 之聲音位置比對演算法技術並和時間戳記結合,以 成相關位置搜尋的目的。 思 35.如申請專利範圍第29項所述之方法,其中在 項測試模組中所提到之,,聲音比對演算法,,可包含:頻雄- ,技術之比對方法及同質性之聲音比對演算法,二二 $兩份儲存在不同儲存裝置之聲音資料在相同時間 鉞纪點之比對測試。 才Π 3上ίΓί專利範圍第29,所述之方法,其中在第二項 ^ 立比較决异方法’’搜尋之聲音資料時間戳記點之對齊方 式’完成自動重新訓練聲音資料及重新比對聲音資料之功能。 Ϊ專!I範圍$29工員所述之方法,其中在第二項 〜士吴、、且中所提到之相對的時間戳記位置可包含:絕對時間 之時間戳記位置及相對時間之時間戳記位置。 38·如申請專利範圍第29項所述之方法,其中在第一項 枯、缺生丨次士丨 之門榼值包含:聲音資料相似度門檻 低於門檻值則失敗二測資料之測試品質 通過(Pass);門彳若高於門檻值則 1 ^值之疋義方式可以從黃金樣品 33 1255419 (Golden Sample)的測試結果及一 之差異性來做相對性的定義;者1 ’人°〇、測試結果 Sample)的測試結果為i⑽,般^品(Golden 義門檻值為90。 差度為正負5% ’則我們可定 39.如申請專利範圍第29項所述之方 項測試模、組中的輸入裝置至少包含但不限置 ^ 卡,其功能在於將第-猶音模組中_置的=二擷取 後如申請專利範圍第29項㈣ 項測試模組中所提到之聲音f料的輸 ^ =二 理,其儲存資料的格式為及儲存處 資料透過輸入裝置擷取後的資核輸出之聲音 位值係分別計算該輸入資:V;%進位值,此二進 數,士曰振巾田,數的二進位值構成方式,者心 振幅為20dB,轉化成為二進位值 田耳曰 幅值為8 bUW _10100,則在記”二=振 振幅ί數值為000 1 _;當儲存於矩陣中 音資料集合起來就是-個很大^^時間點的聲 庫。 U很大的—進位聲音矩陣資料 41 •如申請專利範圍第29項所述之方法甘士廿 ^二項測試模、组中受測品的聲音資料、經由入、置中在 後,可以即時(Real Time)的透装置進入 幻边幻專利乾圍第40項所 1255419 述之二進位轉換格式轉換輸入資料成為二進位矩陣 資料庫’並與原來的黃金樣品(G〇lderi Sample)所轉 換成的二進位矩陣資料庫做比對,達成即時處理 (Real Time process)的效能。 42·如申請專利範圍第29項所述之方法,其中,適當 之傳輸方式可包含但不限於下列傳輸介面:RS232、USB、 1394、SCSI-I、SCSI-11、PCI、 LAN 、 Wired LAN 、 COM Port 、 PCI Express、Wireless Parallel P〇rt° 種測試方法,其可以測試在不同儲存媒體中之 =類型資料(影像或是聲音及其同 之相似度,包含: 貝付) 一資料輸出裴置,供輸出一特定類型資料· 一資料輸入擷取裝置,供接收一特定類型資 一種訓練程序可以將儲存在不同 類型資料(如影像或是聲音)訓練成一種相似的2 :型態(如二進位資料矩陣)並儲存在資料庫、硬 】應:憶體或是其他儲存媒體中,以供日後之: :種同步比對不同格式及儲存媒體中 式,可以即時同步比較原始輪出裝置 咏认方 資特定資料’以及已經儲存在 =所輪出 :身料,並在比對完成後,即時輸^二中的特定 —種輸出方式,可將測試結果輸出到外部?統中。 35 1255419 4 4 · 一種測試的方法, 可比對原始輸出之影音資用時:1戳:的對齊方式, 裝置中的影音資料内及"X谷,及隨機紀錄在紀錄 異性;當原始資料為_ f f问儲存格式中的資料差 分時々為—小呀(時間戳記紀錄方式為時: 刀己點為 00:00:00 〜02.00.00)之 Dvn 1 碟片,隨機抓取由於φ h w.uu.oo)之DVD光 一小時(時間戳吃纪輸出么置所撥放之DVD影音内容 為00..59:08〜〇1.5/式為時:分:秒,時間戳記點 錄裝置(硬碟n )\f音内容並儲存紀錄在紀 記對齊的方式胳! 貝性裳置)中’利用時間戳 存之…:做=^Γ斗及後續隨機抓取並儲 & 匕對(此時兩者資料的儲存格式不 ,^ VD光碟片中,後者在硬碟中),並得ώ 相似度或是差異值。 ’儿付出 45.種使用資訊的方法,包含: Hi識用二進位矩陣數值I收-筆輸入資 "、·、 /邊筆輸入資料轉換為一輸入二進位矩陣數 對忒辨識二進位矩陣數值及該輸入二進位 陣數值進行一運算,以取得一判斷二進位數值;以 及藉由α玄判断二進位數值的大小以使用存於該 識二進位矩陣中的資訊。 46 · 一種資訊紀錄及測試之方法,包含: 貝料擷取裝置,供接收一特定類型資料; 一影音模組’連接至該資料擷取裝置,供接收該特 1255419 定類型資料,將之轉換成二進位數值矩陣,並將兮 二進位數值矩陣經由運算產生一判斷用二進位= 值資料; 默 一記憶媒體,從該控制模組接收並存放該判 用二進位數值資料;以及, “ 一測試模組,該測試模組從該記憶媒體接收該 判斷用二進位數值資料,且該測試模組從該資料擷 取,置擷取一輸入資料,並且,該測試模組將該輪 入貧料轉換為一輸入二進位數值矩陣,而將該輸入 j進,數值矩陣與該判斷用二進位數值矩陣進行 :運算以取得一判斷二進位數值,經由解讀該判斷 —進位數值矩陣之比率大小以判斷該輸入二進位 數值矩陣與該判斷用二進位數值矩陣之關聯。 47· —種瑕疵產品檢測方法,包含: 在準備階段,蒐集各種類型之瑕疵產品;分別儲存 各種瑕疵產品之測試結果;將該些測試結果分別 轉為二進位數值矩陣,不同之瑕疵給定不同門檻比 率值,以及將该些二進位數值矩陣運算以產生一 判斷用二進位數值;並且,在產品生產階段,接收 一待測產品之一待測結果;將該待測結果轉為一 輸入一進位數值矩陣;將該判斷用二進位數值矩 陣與該輸入二進位t值矩p車進行一運#,以獲得一 判斷二進位數值;當該判斷二進位數值之大小超 ^門榼值呀,比對該判斷二進位數值之大小與各 37 1255419 類型之瑕疵所對應之該些二進位數值比率值,以判 斷該待測產品之一瑕疵類型。凊 凊 范围 凊 曰 曰 曰 曰 第 第 第 第 第 第 第 第 第 = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = It is a device for storing the digital data. 1255419 34. The method of claim 29, wherein, in the test module, the relative position calculation method may include: - 瑨, analysis method and frequency occurrence position comparison The technical method and the homogenous sound position are compared with the algorithm technique and combined with the time stamp to achieve the purpose of the relevant location search. 35. The method of claim 29, wherein the sound comparison algorithm mentioned in the test module may include: frequency matching, technical comparison method and homogeneity The sound comparison algorithm, two or two copies of the sound data stored in different storage devices at the same time 钺 time point comparison test. Π 上 上 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利 专利The function of the data. ΪSpecial! I range the method described by the $29 worker, wherein the relative timestamp position mentioned in the second item - Shi Wu, and can include: the time stamp position of the absolute time and the time stamp position of the relative time. 38. The method according to claim 29, wherein the threshold value of the first item of the lack of birth and the second place includes: the sound quality data similarity threshold is lower than the threshold value, and the test quality of the failed second test data is Pass (Pass); if the threshold is higher than the threshold value, the 1^ value can be defined from the gold sample 33 1255419 (Golden Sample) test results and a difference in the relative definition; 1 'person ° 〇, test result Sample) test results for i (10), the general product (Golden sense threshold is 90. The difference is plus or minus 5% ' then we can determine 39. As described in the scope of the application of the 29th test model The input device in the group includes at least but not limited to the card, and its function is to take the _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ The input of the sound material is the same as that of the storage unit. The format of the stored data is the sound value of the output of the data stored by the input device. The input value is calculated separately: V; % carry value, the second Into the number, the gentry vibrating field, the number of binary values The amplitude of the heart is 20dB, which translates into the binary value. The amplitude of the field is 8 bUW _10100, then the value of "two = vibration amplitude ί is 000 1 _; when stored in the matrix, the sound data is collected - very The sound library of the large ^^ time point. U large - the carry sound matrix data 41 • The method described in claim 29 of the patent scope, the two test molds, the sound data of the test article in the group, via After entering and placing in the middle, you can enter the real-time (Real Time) through the phantom edge patent 40th item 1255419. The binary conversion format conversion input data becomes the binary matrix database' and the original gold sample (G〇lderi Sample) converted into a binary matrix database for comparison, achieving the effect of Real Time process. 42. The method of claim 29, wherein the appropriate transmission method This can include, but is not limited to, the following transport interfaces: RS232, USB, 1394, SCSI-I, SCSI-11, PCI, LAN, Wired LAN, COM Port, PCI Express, Wireless Parallel P〇rt° test methods, which can be tested = type data (image or sound and its similarity in different storage media, including: Beifu) A data output device for outputting a specific type of data. A data input capture device for receiving a specific Type training program can train different types of data (such as images or sounds) into a similar 2: type (such as binary data matrix) and store it in the database, hard] should: remember or other In the storage medium, for later: : Synchronous comparison of different formats and storage media Chinese style, you can instantly synchronize the original round-up device to identify the specific information of the party's and have been stored in the = round: body, and in After the comparison is completed, the specific output mode of the instant input can be output to the outside. Unified. 35 1255419 4 4 · A test method that compares the audio and video resources of the original output: 1 stamp: the alignment, the audio and video data in the device and the "X Valley, and the random record in the record of the opposite sex; when the original data is _ ff asks the data difference in the storage format as — 小 小 小 小 ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( ( Uu.oo) DVD light for one hour (time stamp to eat the output of the DVD audio and video content is 00..59: 08 ~ 〇 1.5 / time is: minutes: seconds, time stamp recording device (hard disk) n)\f sound content and store the record in the way of the record of the record! Becky skirt set) in the use of timestamps to save...: do = ^ fight and follow the random grab and save & 匕 right (at this time The storage format of the two data is not, ^ VD disc, the latter in the hard disk), and the similarity or difference value. 'Children pay 45. Use information method, including: Hi recognize the binary matrix value I receive - pen input capital ", ·, / edge pen input data converted to an input binary matrix number pair 忒 identify binary matrix The value and the input binary array value are subjected to an operation to obtain a judgment binary value; and the size of the binary value is determined by α 玄 to use the information stored in the identification binary matrix. 46. A method for information recording and testing, comprising: a material picking device for receiving a specific type of data; an audio and video module 'connecting to the data capturing device for receiving the special type 1255419 type data, converting the same Forming a binary value matrix, and generating a binary value=value data by calculating the binary binary value matrix; receiving and storing the binary data of the judgment binary from the control module; and, “1 a test module, the test module receives the binary data of the judgment from the memory medium, and the test module extracts an input data from the data, and the test module enters the round The material is converted into an input binary value matrix, and the input j is entered, and the numerical matrix and the judgment are performed by a binary value matrix: an operation is performed to obtain a judgment binary value, and by interpreting the judgment - the ratio of the carry value matrix is Determining the association between the input binary value matrix and the binary value matrix for the determination. 47· In the preparation stage, various types of defective products are collected; the test results of various defective products are separately stored; the test results are respectively converted into binary numerical matrix, and different threshold ratio values are given, and the binary values are given. The matrix operation is to generate a judgment binary value; and, in the product production phase, one of the products to be tested is to be tested; the test result is converted into an input and a carry value matrix; the judgment is determined by the binary value The matrix and the input binary t value moment p are carried out to obtain a judgment binary value; when the size of the judgment binary value exceeds the threshold value, the size of the binary value is determined 37 1255419 The value of the binary value ratio corresponding to the type of 瑕疵 to determine the type of the product to be tested. 3838
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