TWI240781B - Screw rotor mechanism - Google Patents
Screw rotor mechanism Download PDFInfo
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- TWI240781B TWI240781B TW93125473A TW93125473A TWI240781B TW I240781 B TWI240781 B TW I240781B TW 93125473 A TW93125473 A TW 93125473A TW 93125473 A TW93125473 A TW 93125473A TW I240781 B TWI240781 B TW I240781B
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!240781 -------- - 五、發明說明(1) . ' "一" ------ 〜一"" ------ 【本發明所屬之技術領域】 汽的ί ^明係關於一種由齒條所產生之曲線做為轉子之輪 二护、紅轉子機構,特別涉及可調整力矩分配及高效率之 评卞機構,以及具有此種輪廓之一對螺旋轉子。 1先前技術】 前之研究顯示螺旋棒子輪廓對於螺旋轉子機構之效 =有恨大影響,在2 0世紀7 0年代初期,非對稱輪廓線形取 代對稱圓弧輪廓線形後,壓縮機效率提高1 0 %,近年來, 為了達到降低噪音、節省能源的要求,在線形的設計上更 /入了 S午多考量,如熱變形、受力變形等,一旦成功的設 5十出高效率之轉子輪廓,將使得整組螺旋轉子機構之性能 在市場上更加有競爭力。目前所廣泛使用之螺旋轉子機構 ,的轉子具有螺旋齒肋以及安插於其間的齒溝,以便在機器 的工作空間内繞平行軸旋轉,其中之一轉子為母轉子,其 每一齒溝的主要部份位在節圓内部,而其它小部份則位在 郎圓外側;另一轉子為公轉子,其每一齒肋的主要部份則 位在節圓外側,而其它小部份位在節圓内部。 先前已有多項專利顯示此種螺旋轉子機構的轉子輪 廟,這些先期技術對此類型輪廓有充份討論,並且也大大 地改進了該等機構的操作性能。例如美國專利第2 6 22 7 87 號、第3787154號、第4412796號、第4890992號及第 4 4 0 6 6 0 2號等。只是這些先期設計均是用傳統產生轉子線 形之程序’即是以在一轉子上定義主要齒形曲線,然後根 據共辆理論’在另一個轉子上創成一個相對應的共輛齒形! 240781 ---------V. Description of the invention (1). '&Quot; 一 " ------ ~ 一 " " ------ [Technical field to which this invention belongs的 ^ Ming is about a kind of second wheel protection, red rotor mechanism of the curve produced by the rack as the rotor, especially the evaluation mechanism with adjustable torque distribution and high efficiency, and one pair with this profile Spiral rotor. 1 Previous technology] Previous studies have shown that the effect of spiral rod profiles on the spiral rotor mechanism has a great impact. In the early 1970s, after the asymmetrical contours replaced the symmetrical arc contours, the compressor efficiency increased by 10. %, In recent years, in order to meet the requirements of reducing noise and saving energy, more considerations have been taken into the design of the linear shape, such as thermal deformation and deformation by force. Once a successful 50% rotor profile is set, Will make the performance of the whole set of spiral rotor mechanism more competitive in the market. The widely used spiral rotor mechanism has a rotor with helical ribs and grooves inserted between them to rotate around a parallel axis in the working space of the machine. One of the rotors is a female rotor. Some are located inside the pitch circle, while other small parts are located outside the Lang circle; the other rotor is a male rotor, and the main part of each rib is located outside the pitch circle, while other small parts are located Pitch circle inside. Several previous patents have shown the rotor wheel temples of such helical rotor mechanisms. These advanced technologies have fully discussed this type of profile, and have also greatly improved the operational performance of these mechanisms. For example, U.S. Patent Nos. 2 6 22 7 87, 3787154, 4412796, 4899992, and 4 0 6 6 0 2 etc. However, these pre-designs are traditionally used to generate the rotor profile. It is to define the main tooth profile curve on one rotor, and then create a corresponding common car profile on the other rotor according to the common car theory.
第6頁 1240781 五、發明說明(2) 而’這些齒形並非為轉子輪廓之最佳設計, 及贺逄卜66妓抓·+ . a 〇 . 15 有其實用及製造上的缺點,·近來,發展了另外一種齒形 ▲的方法,即是以在曲率半徑無窮大的齒條上定義主^ ,然後刀別創成兩轉子齒形,例如美國專利第 曲線 然 產生 曲線,然後M W刊· 丁面形,例如美國專利第 46436 54號及英國專利第96 1 028 9. 2號,其優點在於利 義齒條線形即可分別創成共軛之公、母轉子輪廓,在 上之每一點,均可創成出轉子線形上相對應之一點,$ 於整段曲線創成,且齒條線形上之直線段將會在轉子、屬 成相應之漸開線段,確保兩轉子在節圓附近的相 ^生 近理想之滾動接觸,有利於力矩之傳遞,同時在保 接 吹孔情況下,轉子在整個接觸長度上維持密封,而小回 :創成之母料葉片彳比任冑其他現有之螺旋式屋縮:: :具有更大之截面積與更強壯之葉片,將有助於 子爻力矩的分配。 母轉 【本發明之内容】 習知之螺旋轉子輪廓,其係利用公轉子齒頂、 轉;iHi壓縮時密封氣體’㈣為在輪靡之設計上: :之齒厚彺往不足而導致抗彎強度太小,或 母 2曲線之S力u t而造成轉子受力不均,•加上= _於轉子會受熱膨脹以及受到氣體 7 和持”造成公轉子齒頂或公、母轉子間的磨損 又動$ g的形成,進而影響壓縮機的效率。 貝 積極i發:!鑑於現有之螺旋轉子在設計上未盡精良,乃 進仃研究改良,經不斷的嘗試與試驗後,發展出確具Page 6 1240781 V. Description of the invention (2) And 'these tooth shapes are not the best design for the outline of the rotor, and He Qiaobu 66 prostitute. +. A 0.15 has its practical and manufacturing shortcomings, recently Developed another method of tooth profile ▲, which is to define the main ^ on a rack with an infinite radius of curvature, and then create a two-rotor tooth profile, for example, the U.S. patent curve produces a curve, and then the MW publication Shape, such as U.S. Patent No. 46436 54 and U.S. Patent No. 96 1 028 9.2, which has the advantage that the linear shape of the denture rack can be used to create the conjugate male and female rotor profiles, and at each point above, it can be created A point corresponding to the linear shape of the rotor is created in the entire curve, and the straight line segment on the rack linear shape will be in the rotor and belong to the corresponding involute segment to ensure that the two rotors are close to each other near the pitch circle. The rolling contact is conducive to the transmission of torque, and at the same time, the rotor maintains a seal over the entire contact length under the condition of maintaining the blow hole. : With bigger And stronger cross-sectional area of the blade, will help distribute child Yao torque. Female rotor [Content of the invention] The conventional spiral rotor profile uses the male rotor tooth tip and rotation; iHi's sealed gas is compressed when it is compressed: The tooth thickness is insufficient to cause bending resistance The strength is too small, or the rotor is uneven due to the S force of the female 2 curve. • Plus = _ because the rotor will be thermally expanded and subject to the gas 7 and holding it, which will cause wear of the male rotor tooth top or male and female rotors. In addition, the formation of $ g affects the efficiency of the compressor. Bei Zhengjifa: In view of the fact that the existing spiral rotors are not perfect in design, they have been researched and improved. After continuous trials and tests, they have developed
第7頁 1240781 五、發明說明(3) --------------- 實用功效之一種可符人 備最佳效率、力矩分二I,,合設計的轉子,以便構成具 太發明棵# ί 合理的螺旋轉子機構。 本發明螺奴轉子機構的技 而可在機器的工作外門如从τ々茶為,、有訂互相嚙合 子上各有數個具有;“::行之軸心線旋轉的轉子,轉 之-轉子為公轉子:、二=巧可互為交插的齒溝,其中 母轉子’其輪廓亦*產J J J所產纟’·另-轉子為 本發明所提供之螺之同-歯條所生成》 合的公轉子和母II + 、 的優點在於兩個相互喷 生,此方法可廓線都是由-齒條輪廓線所產 廓線包括有::=:線齒形創成過程…,齒條4 值,在齒條底部增加一 J °周整長軸與短軸之比 =度圓狐,用以保護公轉:齒m轉子齒頂生成-段 ::齒:壓力角以及母轉子之轉::廓之左 可依照4:2:以適當分配於公 '母轉子》同Ϊ ; 齒條輪廓以得到:5;:不旋轉子機構類型來調整 強度 巧對合適之螺旋轉子,可於Μ μ 【本發ί之;:以】減…及提升效Γ 子抗, 者,所明本發明之螺旋轉子機構,需陳明 在本Ξ 之些許修正而不脫離本發:::果依據該 本的申請專利範圍之内。"之精神_,仍應該 "閱第一圖及第三圖,本發明 η <螺旋轉子機構,包 第8頁 1240781 五、發明說明(4) 括公轉子1 〇與母轉子3 〇 ;其中,公轉子丨〇具有五個螺旋形 齒肋1 1 (在第一圖中僅顯示一個完整之齒肋),以及相同數 目且安插於其間的螺旋形溝槽1 2 (在第一圖中僅顯示二 個),其具有節圓14及轉軸16。與公轉子10相嚙合的轉子 為母轉子30,母轉子30上有可與公轉子10嚙合的輪廓; 々 如第二圖所示,母轉子30具有六個螺旋形齒肋31 (在 第二圖中僅顯示二個完整之齒肋),以及相等數目且安插 於其間的螺旋溝槽3 2 (在第二圖中僅顯示一個)相對於公轉 子10,母轉子30具有節圓34及轉軸36 ;如第三圖所示,當 兩轉子在機殼41内共同作用且互為嚙合時,公轉子1〇的轉 軸16與母轉子30的轉軸36位在一共同平面40上。 請參照第四圖,母轉子3〇和公轉子丨〇輪廓的形成說明 ,如下: 定義長度dl為0.005〜〇·〇5倍的轉子間中心距長度; 長度d2為0.15〜0·35倍的轉子間中心距長度,以母轉子3〇 的轉軸3 6作為圓心,轉子間中心距乘上母轉子齒數再除以 兩轉子齒數和之長度為半徑作節圓3 4,以具有較節圓3 4半 徑小d2長度的半徑作齒根圓34b,並以具有較節圓34半徑 大d 1長度的半徑作齒頂圓3 4 a ;另以公轉子1 〇的轉軸1 6作 為圓心,轉子間中心距乘上公轉子齒數再除以兩轉子齒數 和之長度為半徑作節圓i 4,以具有較節圓丨4半徑大d2長度 的半徑作齒頂圓1 4a,並以具有較節圓丨4半徑小dl之齒根 圓1 4b ’其中’圓1 4、1 4a、14b分別外切於圓34、34b、 34a。齒頂圓14a及齒根圓34b與由轉轴16、36所成的平面Page 7 1240781 V. Description of the invention (3) --------------- One of the practical effects can meet the best efficiency, the torque is divided into two I, and the designed rotor, so that Constitute with Tai Invention Tree # ί Reasonable spiral rotor mechanism. The technology of the screw-rotor rotor mechanism of the present invention can be used on the machine's working outer door, such as from τ 、 tea, and there are several interlocking elements on each of the interlocking elements; The rotor is a male rotor: two = the cogging grooves can be interspersed with each other, in which the female rotor 'its profile is also produced by JJJ's 纟' · another-the rotor is the same as the snail provided by the invention 》 The advantages of the combined male and female rotor II + are that the two spray out each other. In this method, the profile can be produced by the -rack contour line. The value of bar 4 is added at the bottom of the rack by a ratio of the entire long axis to the short axis = degree round fox to protect the revolution: tooth m rotor tooth top generation-segment :: tooth: pressure angle and rotation of the female rotor :: The left side of the profile can be allocated in accordance with 4: 2: the same as that of the male and female rotors; the rack profile can be obtained to: 5 ;: the strength of the non-rotating sub-mechanism can be adjusted. The appropriate spiral rotor can be used in M μ [本 发 ί 之 ::] To reduce ... and improve the efficiency Γ reactance, the spiral rotor mechanism of the present invention, it is necessary to Chen Ming Amendment without departing from the present invention :: If it is within the scope of the patent application according to this book. "The spirit of", you should still read the first and third drawings, the present invention < spiral rotor mechanism, including the first Page 8 1240781 V. Description of the invention (4) Including male rotor 1 〇 and female rotor 3 〇; Among them, the male rotor 丨 〇 has five spiral ribs 1 1 (only one complete rib is shown in the first figure) , And the same number of helical grooves 1 2 (only two are shown in the first figure), which have a pitch circle 14 and a rotating shaft 16. The rotor meshing with the male rotor 10 is a female rotor 30, The rotor 30 has a contour that can be engaged with the male rotor 10; 々 As shown in the second figure, the female rotor 30 has six spiral ribs 31 (only two complete ribs are shown in the second figure), and the equivalent Number of spiral grooves 3 2 (only one is shown in the second figure). With respect to the male rotor 10, the female rotor 30 has a pitch circle 34 and a rotating shaft 36. As shown in the third figure, when the two rotors are in the machine When the shells 41 cooperate and mesh with each other, the rotating shaft 16 of the male rotor 10 and the rotating shaft 36 of the female rotor 30 It is located on a common plane 40. Please refer to the fourth figure, the description of the formation of the outlines of the female rotor 30 and the male rotor 丨 〇 is as follows: Define the length of the center-to-center distance between the rotors 0.005 to 0.005 times; the length d2 The center-to-center distance between the rotors is 0.15 to 0.35 times. The center axis of the rotor 30 is used as the center of the rotor. The center-to-center distance is multiplied by the number of teeth of the rotor and divided by the number of teeth of the two rotors. 4. A radius with a length smaller than the radius of the pitch circle 34 is d2 as the tooth root circle 34b, and a radius with a length larger than the radius of the pitch circle 34 is d1 as the tooth tip circle 3 4a; The shaft 16 is the center of the circle. The center distance between the rotors is multiplied by the number of teeth of the male rotor and then divided by the sum of the number of teeth of the two rotors. The radius is the pitch circle i 4. 4a, and a tooth root circle 1 4b having a radius dl smaller than the pitch circle 4 and a circle 1 4b 'wherein' the circles 1, 4, 14a, 14b are circumscribed to the circles 34, 34b, 34a, respectively. Tooth circle 14a and root circle 34b and the plane formed by the rotating shafts 16, 36
第9頁 1240781Page 9 1240781
4〇在點50相交,在兩節圓相切點處畫一垂直平面4〇之 =為節線60,定義一齒條70,其齒節距“為公轉子1〇 W14圓周長除以公轉子1〇齒數; 直線 之節 ;齒條70之一側以1〜2倍dl的長度為半徑rl作圓lc, 0弧71之起點71a與齒頂線60a相切,其圓心距垂直平面 =方〇. 3〜〇. 5倍齒節距處,定義高壓側壓力角u介於6。〜 :之間,圓弧之起點71a、終點7lb與圓心之夾角tl定義 為90 — U,故終點711^不一定落於節線60上,視u&rl而決 定、,且rl過大會增加壓縮機内部壓縮氣體之洩漏;過小貝、 將導致加工困難; 度之逆時針方向 7 2且得到終點 取 以點71 b為起點,沿與水平線夾u角 小於2 · 〇 X d 1 -r 1之長度畫一直線(曲線) 72a ; (如第六圓所示,圖中之節圓34為示意,非實際之尺 寸)從點7 2 a沿直線7 2之法線方向延伸一大於Γ1之距離k得 點7 3a,沿直線7 2之法線反方向延伸交節線6 〇於點9 0,將 節圓34之初始位置移至點9〇,將點73a固連於節圓34上, 點7 3a與節圓34之相對位置在滾動中為保持不變,將節圓 34從初始位置點9〇開始在節線6〇上向下滚動1/1 8〜1/6圈的 範圍至末點1 〇 〇,而固連於節圓3 4之點7 3 a即可畫出一條特 定長度之轨跡線,此軌跡線即為擺線7 3 c,求得擺線(曲 線)7 3 c法線方向之擺線等距線7 3,使得擺線等距線(曲 線)7 3與直線(曲線)7 2於點7 2 a相切,延伸距離k將決定母 轉子3 0齒形在節圓3 4處之曲率半徑大小;4〇 Intersect at point 50. Draw a vertical plane at the tangent point of the two circles. 40 == pitch line 60. Define a rack 70 whose tooth pitch is “the circumference of the male rotor 10W14 divided by the male rotor. 10 number of teeth; straight section; one side of the rack 70 with a length of 1 to 2 times dl as the radius rl to make a circle lc, the starting point 71a of the 0 arc 71 is tangent to the tooth tip line 60a, and the center of the circle is perpendicular to the square = square 〇. 3 ~ 〇. 5 times the tooth pitch, define the high-pressure side pressure angle u between 6. ~: between the starting point 71a of the arc, the end angle 7lb and the center of the circle t1 is defined as 90-U, so the end point 711 ^ It does not necessarily fall on the node line 60, it depends on u & rl, and if rl is too large, it will increase the leakage of compressed gas inside the compressor; if it is too small, it will cause processing difficulties; the degree of counterclockwise is 72 and the end point is taken Starting from point 71 b, draw a straight line (curve) 72a along the length of the angle u with the horizontal line less than 2 · 〇X d 1 -r 1; (as shown in the sixth circle, the pitch circle 34 in the figure is a schematic, non- Actual size) Extending a distance k greater than Γ1 from point 7 2 a along the normal direction of line 7 2 to get point 7 3a, extending the intersection in the opposite direction of the normal line of line 7 2 Line 6 0 at point 90 moves the initial position of pitch circle 34 to point 90 and fixes point 73a to pitch circle 34. The relative position of point 7 3a and pitch circle 34 remains unchanged during rolling. Scroll the pitch circle 34 from the initial position point 90 to the pitch line 60 and scroll down the range of 1/1 8 to 1/6 turns to the end point 1 00, and be fixed to the pitch circle 34 at point 7 3 a can draw a trajectory of a certain length. This trajectory is the cycloid 7 3 c. Find the cycloid (curve) 7 3 c. The equidistant line (curve) 7 3 is tangent to the straight line (curve) 7 2 at point 7 2 a. The extension distance k will determine the radius of curvature of the female rotor 30 tooth profile at the pitch circle 34.
第10頁 1240781Page 10 1240781
(如第六圖所示,圖中之節圓丨4為示意,非實際之尺 寸)沿曲線73之終點73b法線方向延伸一大於rl之距離得 點7 4a,將節圓14之初始位置移至點1〇〇,將點7“固連於 節圓14亡,點74a與節圓14之相對位置在滾動中為保持不 變,將節圓14從初始位置點1〇〇開始在節線6〇上向上滾動 1 /1 8 1 / 6圈的範圍至末點〗丨〇,而固連於節圓丨4之點7 4 &即 可Λ出條特疋長度之轨跡線,此軌跡線即為擺線W c, ,付擺線(曲線)74c法線方向之擺線等距線74,使得擺線 等距線(曲線)74與擺線等距線(曲線)73於點73b相切,延 伸距離將決定公轉子齒形在齒頂圓1 4 a處之曲率半徑大 小; 節圓14與命圓3 4相切於一點8 〇,以點8 〇為圓心,長度 d2為半徑得到相切於點5〇及點74b之圓弧(曲線)75,點“ =圓弧兩端點50、74b間夾有一沒角作為齒條創成公轉子 形上之齒頂保護角,角度介於〇。〜1〇。; ,義擺線等距線(曲線)73與擺線等距線(曲線)74之長 以能夠滿足在接點73b上相切且曲線74末點74b之法線能 通過點8 0之條件為原則; 卞在齒條7 〇另一側於齒頂線6 〇 a上距點7丨a 一個齒節距之 $取點7 9 a ’沿齒頂線6 0 a取0 · 〇 2〜0 · 〇 6倍中心距的長 ^ : 一直線(曲線)79並得到終點79b,直線(曲線)79的 P將會影響所創成之母轉子3〇齒厚,長度愈長,母轉子 旱愈大,能承受較大負載;長度愈小,母轉子齒厚也愈 、,所能承受的負載也較小且變形量會較大·,(As shown in the sixth figure, the pitch circle 4 in the figure is a schematic, non-actual size.) Extending a distance greater than rl along the normal direction of the end point 73b of the curve 73 to obtain a point 7 4a, the initial position of the pitch circle 14 Move to point 100 and fix point 7 "to the pitch circle 14. The relative position of point 74a and pitch circle 14 will remain the same during the rolling. The pitch circle 14 will be at the pitch from the initial position point 100. Scroll up on the line 60 from the range of 1/1 8 1/6 turns to the end point 丨 〇, and fixed to the pitch circle 丨 4 point 7 4 & you can draw a trajectory line with a special length, This trajectory is the cycloid W c,, and the cycloid isometric line 74 in the direction of the normal line of the cycloid (curve) 74c, so that the cycloidal isometric (curve) 74 and the cycloidal isometric (curve) 73 are at The point 73b is tangent, and the extension distance will determine the radius of curvature of the male rotor tooth shape at the tooth top circle 1 4 a; the pitch circle 14 and the life circle 34 are tangent to a point 800, with the point 800 as the center of the circle and the length d2 For the radius to obtain an arc (curve) 75 tangent to points 50 and 74b, the point "= an angle between the two ends 50 and 74b of the arc is used as the rack top to create a tooth top protection angle in the shape of a male rotor, angle Between 0. ~ 10. ;, The length of the equidistant line (curve) 73 and the cycloidal line (curve) 74 is so long as to be able to meet the condition that the contact point 73b is tangent and the normal of the end point 74b of the curve 74 can pass the point 80. Is the principle; 距 on the other side of the rack 7 〇 on the tooth top line 6 〇a from the point 7 丨 a a tooth pitch $ take point 7 9 a 'along the tooth top line 6 0 a take 0 · 〇2 ~ 0 · 〇6 times the center distance ^: a straight line (curve) 79 and get the end point 79b, the P of the straight line (curve) 79 will affect the female rotor 30 tooth thickness created, the longer the length, the greater the drought of the female rotor , Can withstand larger loads; the smaller the length, the thicker the tooth thickness of the female rotor, the smaller the load it can bear and the larger the amount of deformation,
1240781 五、發明說明(7) "" — - 以1〜5倍dl的長度為半徑r2作圓78a,圓弧78之起點 7 9b與齒頂線60a相切,其圓心在垂直平面4〇下方齒節距扣 掉d 1距離處,定義低壓側壓力角v介於3 〇。〜4 5。之間,圓 弧之起點79b、終點78b與圓心之夾角t2定義為90。— v,故 終點78b不一定落於節線6〇上,視¥及r2而決定, 半徑將會使製造困難; 且過】、的 以點78b為起點,沿與水平線夾v角度之方向取小於6 倍dl減去r2的長度畫一直線(曲線)77且得到終點。在 求得點77a與點50後,選取一最適當之橢圓弧76,此 弧76之選擇必需滿足其在接點5〇與點77a處為保持切線連 續及,點連續之條件,重要的是,為了滿足切線連續與接 點連績,需放寬橢圓弧之自由度以滿足連續條件,故設計 上先給定〇· 5〜3· 5倍中心距之橢圓長軸長度,然後在滿足 連續條件下求得橢圓圓心之位置、橢圓繞其圓心轉動之角 度以及橢圓弧區間參數範圍; 如第五圖所示,當齒條70沿著節線60做水平移動而母 轉子30對其轉軸36做相對轉動時,母轉子3〇之單一齒形輪 廓可藉由此相對運動關係以及嚙合條件求得,且齒條7〇上 之曲線分別生成相對應之母轉子30輪廓曲線,每條相對應 曲線在運動時為完全嚙合; s齒條7 0沿著節線6 0做水平移動而公轉子丨〇對其轉軸 1 6做相對轉動時,公轉子丨〇之輪廓可藉由此相對運動關係 以及嚙合條件求得,且齒條7〇上之曲線分別生成相對應之 A轉子1 0輪廓之曲線,母條相對應曲線在運動時亦為完全1240781 V. Description of the invention (7) " " —-Make a circle 78a with a radius r2 of 1 to 5 times dl, the starting point 7 9b of the arc 78 is tangent to the top line 60a, and its center is in the vertical plane 4 〇 The lower tooth pitch is deducted by a distance of d1, and the low-pressure side pressure angle v is defined as 3 〇. ~ 4 5. The angle t2 between the start point 79b, the end point 78b, and the center of the arc is defined as 90. — V, so the end point 78b does not necessarily fall on the nodal line 60. It is determined by ¥ and r2. The radius will make it difficult to manufacture; and] Take the point 78b as the starting point and take it in the direction of the v angle with the horizontal line. Less than 6 times dl minus r2, draw a straight line (curve) 77 and get the end point. After finding point 77a and point 50, select the most appropriate elliptical arc 76. The choice of this arc 76 must meet the conditions for maintaining tangent continuity and point continuity at contact 50 and 77a. It is important that In order to meet the continuous performance of tangent and contact, the degree of freedom of the elliptical arc needs to be relaxed to meet the continuous condition. Therefore, the length of the ellipse major axis with a center distance of 0.5 to 3.5 is given in the design, and then the continuous condition is satisfied. The position of the center of the ellipse, the angle of rotation of the ellipse around the center of the ellipse, and the parameter range of the ellipse arc are obtained. As shown in the fifth figure, when the rack 70 moves horizontally along the pitch line 60 and the female rotor 30 makes its rotation axis 36 During relative rotation, the single tooth profile of the female rotor 30 can be obtained from the relative motion relationship and meshing conditions, and the curve on the rack 70 generates the corresponding female rotor 30 contour curve, each corresponding curve During the movement, it is fully meshed; s rack 7 0 moves horizontally along the pitch line 60 and the male rotor 丨 〇 rotates its rotating shaft 16 relatively, the outline of the male rotor 丨 〇 can be based on this relative motion relationship and Finding the meshing conditions, The rack 7〇 curve A rotor generates the corresponding profile of the curve 10, the curve corresponding to the mother strip is also fully in motion
11 1 IKW 1IHB 第12頁11 1 IKW 1IHB Page 12
1240781 五、發明說明(8) 嚙合; 經由以上所述,可得如下結論: A ?齒條7 0由數條曲線組成了;令每條曲線可 做適當之调整。例如,可改變半徑r丨及β之大小 軸長度、每條直線之長度、角度点、u、v及延伸 ,藉,,得到適用於各種應用情沉下 媒壓縮機、空氣壓縮機、···等}。 B )經由同一齒條7 〇可辟且lL丄、 形,且生成之公、Γ轉;公轉子與母 設計上更加簡單。間破此共輛’將使得轉 C)藉由如Α)項之調整齒條上之 性質、不同場合下之轉子皆# 啄j得應 效率且力矩合理分配於公齒若:整適當, ⑸公轉子丨。的齒形由齒子:形》 線間在做創成運動(如第五廟對/曲線,相對應之 合,屬於整段齒條曲線創成圖,中之上圖所示)時為 與齒根圓14b之間。 且&個輪廓介於齒 E)母轉子30的齒形由齒條7〇 曲線創成母轉子齒形上之相^ 成,齒條7 0 線間在做創成運動(如第 '心線,相對應之 合,屬於整段齒條曲線創成圖,中之下圖所示)時為 與齒根圓34b之間》 t個輪廓介於齒 依據需要 、橢圓長 長度k、 (例如冷 轉子齒 子齒形的 用於不同 將得到高 上的每條 曲線與曲 完全喃 頂圓14a 上的每條 曲線與曲 完全 頂圓34a1240781 V. Description of the invention (8) Engagement; through the above, the following conclusions can be drawn: A? Rack 70 is composed of several curves; each curve can be adjusted appropriately. For example, you can change the length of the major and minor axes of the radius r 丨 and β, the length of each straight line, the angle point, u, v, and the extension. By this, you can get a suitable medium compressor, air compressor, ... ·Wait}. B) Through the same rack 70, it can be opened and shaped, and the generated male and Γ turns; the design of the male rotor and the female is simpler. Breaking this car in total will make the rotor C) adjust the properties on the rack by items such as A), and the rotors in different occasions will be pecked efficiently and the torque will be reasonably distributed to the male teeth. If: properly, ⑸ Male rotor 丨. The tooth shape is formed by the teeth: shape. When the line is in the creation movement (such as the fifth temple pair / curve, the corresponding combination belongs to the entire rack curve creation chart, shown in the upper figure), it is the same as the tooth root. Between circles 14b. And the profile of the female rotor 30 with a contour between the teeth E) is formed by the rack 70 curve to form the shape of the female rotor ^, and the rack 70 is making a movement between the lines (such as the first heart line, Corresponding combination belongs to the entire segment of the rack curve creation chart, as shown in the lower and middle figures.) When it is between the tooth root circle 34b and the t contours between the teeth, the ellipse length k, (such as cold rotor teeth) The use of subtooths for each curve will give you a complete apex circle on each curve and curve 14a
苐13頁 1240781_ 圖式簡單說明 第一圖係本發明所定義的公轉子部份輪廓圖。 第二圖係本發明所定義的母轉子部份輪廓圖。 第三圖係本發明螺旋轉子嚙合的整體輪廓圖。 第四圖係本發明的轉子局部放大視圖。 第五A圖與第五B圖係齒條與公、母轉子相對運動座標 圖。 第六圖係齒條之擺線形成圖。 【圖式中元件名稱與符號對照】 10 :公轉子 30 :母轉子 1 1、31 :螺旋形齒助 ' 12、32 :螺旋形溝槽 1 4 :公轉子節圓 1 4 a :公轉子齒頂圓 1 4 b :公轉子齒根圓 1 6、3 6 :轉軸 3 4 :母轉子節圓 34a:母轉子齒頂圓 34b :母轉子齒根圓 40 轉軸平面 41 機殼 50 切點 60 節線苐 Page 13 1240781_ Brief description of the drawing The first drawing is the outline drawing of the male rotor defined by the present invention. The second figure is a partial outline view of the mother rotor defined by the present invention. The third figure is an overall outline view of the engagement of the spiral rotor of the present invention. The fourth figure is a partially enlarged view of the rotor of the present invention. Figures A and B are coordinate diagrams of the relative movement of the rack and the male and female rotors. The sixth diagram is a cycloid formation diagram of the rack. [Comparison of component names and symbols in the figure] 10: Male rotor 30: Female rotor 1 1, 31: Spiral teeth 12 ', 32: Spiral grooves 1 4: Male rotor pitch circle 1 4a: Male rotor teeth Top circle 1 4 b: Male rotor tooth root circle 1 6, 3 6: Rotary shaft 3 4: Female rotor tooth circle 34a: Female rotor tooth circle 34b: Female rotor tooth root circle 40 Rotary plane 41 Cabinet 50 Tangent point 60 pitch line
第14頁 1240781 圖式簡單說明 6 0a :齒頂線 7 0 :齒條 71 :圓弧(曲線) 7 1 a ·起點 7 1 b :終點 71 c :圓 7 2 :直線(曲線) 7 2 a :點 7 3 :擺線等距線(曲線) 73a 、 73b :點 7 3 c :擺線(曲線) 7 3 d :直線 74 :擺線等距線(曲線) 7 4 a、7 4 b :點 7 4 c :擺線(曲線) 75 :圓弧(曲線) 76 ·•橢圓(曲線) 77 :直線(曲線) 77a :點 78 :圓弧(曲線) 7 8a·圓 7 8b :點 7 9 :直線(曲線) 7 9 a ·起點Page 141240781 Brief description of the diagram 6 0a: Tooth line 7 0: Rack 71: Arc (curve) 7 1 a · Start point 7 1 b: End point 71 c: Circle 7 2: Straight line (curve) 7 2 a : Point 7 3: Cycloidal isometric lines (curves) 73a, 73b: Point 7 3 c: Cycloidal (curves) 7 3 d: Straight line 74: Cycloidal isometric (curves) 7 4 a, 7 4 b: Point 7 4 c: Cycloid (curve) 75: Arc (curve) 76 · • Ellipse (curve) 77: Straight line (curve) 77a: Point 78: Arc (curve) 7 8a · Circle 7 8b: Point 7 9 : Straight line (curve) 7 9 a · starting point
第15頁 1240781 圖式簡單說明 7 9 b :終點 80 :點 90 :點 1 0 0 ' 1 1 0 :點 pi :齒節距 dl、d2 :長度 r 1、r2 :半徑 u :高壓側壓力角 v :低壓側壓力角Page 15 1240781 Brief description of drawings 7 9 b: End point 80: Point 90: Point 1 0 0 '1 1 0: Point pi: Tooth pitch dl, d2: Length r 1, r2: Radius u: High pressure side pressure angle v: low pressure side pressure angle
第16頁Page 16
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TWI482920B (en) * | 2013-01-11 | 2015-05-01 | Univ Nat Pingtung Sci & Tech | Clearance Calculation of Helical Rotor Between Twin Screw Compressor |
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