TW472130B - Control method and device capable of determining required energy based on output power for making the heating source of freezing and air conditioning system generate corresponding energy - Google Patents
Control method and device capable of determining required energy based on output power for making the heating source of freezing and air conditioning system generate corresponding energy Download PDFInfo
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472130 月(1) 本發明 值以提供冷 控制方法與 率運轉I。 按早期 根據冷凍ί 組之運轉與 爹少,導致 空調系統的 一冷凍空調 交換機組1 定單元F 1 閱第二圖所 調區R 1 〇 ~ 2 0根 1 1之 笔算後, 々、輪出 时應於凤 女式進步 1 .此 調區 量卻 以額472130 months (1) The present invention is to provide a cold control method and rate operation I. According to the early operation of the refrigeration group and the lack of parents, a refrigeration air-conditioning switch group 1 of the air-conditioning system was set up. Unit F 1 After reading the area adjusted by R 1 〇 ~ 2 0 11 in the second picture, 々, turn out Shi Yingyu Women's Progress 1
係關於一種可根據輪出 凍空調系統其”二f ί值计算出需用能量 ^ ^ 、、原機組使產生對應能量供應之 ^ θ以使系統維持在一最佳化節能與高效It is about a kind of refrigeration energy-saving air-conditioning system which can calculate the required energy according to the value of "two f", the original unit makes the corresponding energy supply ^ θ to maintain the system at an optimized energy saving and high efficiency
F 空 的冷凍空 調房(區 否,完全 能源過度 改良問市 負載侧熱 2設有一 1、一感 示者), 提供冷凍 據感測單 設定值Τ 驅動輸出 電力給風 扇馬達Μ ,惟在能 系統對於 的需求變 無法與其 定的能量F Empty refrigerating and air-conditioning room (area, complete energy over-improvement, city load side heat 2 is provided with 1-1, 1 sensor), providing refrigeration data sensing single set value T drive output power to fan motor M, but The energy demand of the system cannot change
第4頁 乃有第一圖所 調系統 )選擇 不問冷 的浪費 ’此系 交換機 熱交換 測單元 藉由以 &調供 元Τ 1Page 4 is the system tuned in the first picture.) Choose not to waste the cold. ‘This is a switch heat exchange test unit. By using &
As, 單元1 扇馬達 1之轉 f使用 風扇馬 化調變 作同步 在供應 其熱源 空調供 康空調 ’於是 統主要 組1 2 器1 3 T 1 1 上元件 應(即 1測得 經由中 2 3' Μ 1以 速控制 上仍存 達轉速 風量的 對應控 ,完全 機組的 應與否 房(區 由一熱 ,該冷 、風扇 及控制 組成之 熱源供 之感測 央微處 電源供 控制其 ,已較 有以下 之控制 變化, 制;也 不問冷 運轉方 ,來決 )的需 源機組 凍空調 馬達Μ 器1 2 系統, 應), 值Τ A 理單元 應單元 轉速, 傳統的 缺點: ,雖然 但熱源 就是說 凍空調 式,僅能 定熱源機 求到底要 示的冷涞 1 1配置 負載側熱 1、一設 0 (請參 對冷凍空 其中控制 與設定單 1 2 1比 1 2 2之 雖然此系 定風量控 已能根據 機組的熱 ,熱源機 區R 1 0 472130 五、發明說明(2) 的需求狀況為何,導致熱源供應量大多時段是處於大於負 載的狀態,主機必需採用開開、停停的運轉方式提供適量 的熱源來調節冷凍空調區R 1 0的熱負荷。 2 ·如上第1點所述,造成能源浪費的原因’乃在於 熱源機組不能隨機測知空調負載侧熱交換機組的能量需求 ’並採行對應之熱源供應量,亦即在冷凍空調負栽甸熱交 換機組未能將其需求隨機反應提供給熱源機組,而形成能 源使用的重大缺失。 本案發明人有鑑於此,乃針對其缺失加以研究改進, 終於完成本案之發明,本發明之目的: (一)在於提供一種可根據冷凍空調負載侧輪出功率 值计算出需用能量值之控制方法,藉以使熱源機組產生對 f熱源供應量,使熱源機組可隨機根據冷凍空調負載側熱 父換機組的空調需用能量值進行對應調整,進而達到節能 目的者。 值叶^ 一 i在於提供一種可根據冷珠空調負載侧輸出功率 應^源t需,能量值的控制裝置’藉以使熱源機組產生對 交f應量’使熱源機組可隨機根據冷康空調負載侧熱 目沾土 ^ 门㈤用此®值進行對應調整,進而達到節能 實施例:二配合圖式、圖號說明,詳細介紹本發明其具體 第二圖為本發明其 置主要由一控制器2 ? 控制裝置之方塊示意圖,其中該裝 1為主體,具有以下單元:As, the rotation of unit 1 fan motor 1 uses fan horsepower modulation to synchronize the supply of its heat source air conditioner for health air conditioner. Therefore, the main component of the system 1 2 device 1 3 T 1 1 should be (ie, 1 measured by 2 3 'Μ 1 speed control still has the corresponding control of the speed and air volume, the complete unit should be room or not (the area consists of a heat, the cooling, fan and control heat source composed of the power supply for the central micro-control power supply to control its The following control changes have been made; the cold-runner is not required, it depends on the source air-conditioning unit, the refrigeration air-conditioning motor, and the system. The value of the TA unit should be the unit speed. The traditional disadvantages are: Although the heat source is the freezing and air-conditioning type, it can only determine the cold source to be displayed. 1 1 Configure the load side heat 1, and set 0 (please refer to the control and setting sheet for the free space 1 2 1 to 1 2 2 Although the fixed air volume control has been based on the heat of the unit, the heat source area R 1 0 472130 V. What is the demand situation of the invention description (2)? As a result, the supply of heat source is more than the load most of the time, the host must use The open-and-stop operation mode provides a proper amount of heat source to adjust the heat load of the refrigerating and air-conditioning area R 1 0. 2 · As mentioned in point 1 above, the cause of energy waste is that the heat source unit cannot randomly detect the air-conditioning load side. The energy demand of the heat exchanger group 'and the corresponding heat source supply are adopted, that is, the refrigerating air-conditioning load heat exchanger group fails to provide its demand to the heat source unit at random, resulting in a major lack of energy use. The inventor of this case In view of this, research and improvement have been made in view of its shortcomings, and the invention of this case has finally been completed. The purpose of the present invention is: (1) To provide a control method that can calculate the required energy value according to the output power value of the load side wheel of a refrigeration air conditioner Make the heat source unit generate the supply of f heat source, so that the heat source unit can randomly adjust the air-conditioning energy value corresponding to the heat parent unit of the refrigerating and air-conditioning load side to achieve the purpose of energy saving. The output power of the load side of the cold bead air conditioner should be required by the source and the control device of the energy value ', so that the heat source unit generates The quantity 'enables the heat source unit to randomly adjust the soil according to the hot air on the load side of the Lengkang air conditioner. The door ㈤ uses this value to make corresponding adjustments to achieve energy saving. Example: Second, the detailed description of the present invention with its specific The second figure is a schematic block diagram of the device of the present invention, which is mainly composed of a controller 2 and a control device. The device 1 is the main body and has the following units:
第5頁 472130 五、發明說明(3) 一中央微 收各種偵測數 應數值、控制 一個感測 件用以偵測目 單元2 2 1 1 ~~設定單 單元之設定操 數值比對運算 —輸出單 之控制訊號控 調負載侧熱交 馬達]V[ 2 1 ( 處理單元2 2 值與設定數值 訊號等功能, 單元T 2 1 , 標區之溫度值 ,元F 2 1 ,係 作,以提供中 y 元 2 2 1 3, 制電源供應單 換機組2 2風 或其他空調箱 11,係為一CPU,具有接 ,經由其比對運算後,輸出對 係具有至少一個以上之感測元 ’並將此值傳輸給中央微處理 用以設定數值之單元,經由此 央微處理單元2 2 1 1與偵測 中央微處理單元2 2 ^ 1 2的電力供給冷 ;M21 ,如蒸發器 内送風機...等之風扇;5 根據 元2 扇馬 、室 —電源供應單元2 2 1 電力及冷凍空調負載侧熱交 (如空調箱、室内送風機... I源; 一功率數值偵測單元2 2 2 1 3所輸出之功率數值 藉由上述單元之組成, 據功率數值偵測單元2 2 1 以運算為冷凍空調需用能量 Qlan、Q2a2、...、 換機 等之Page 5 472130 V. Description of the invention (3) A central micro-receiving value of various detection numbers should be controlled, and a sensor should be used to detect the target unit 2 2 1 1 ~~ Set single unit setting operation value comparison operation — The control signal of the output sheet controls the load-side heat transfer motor] V [2 1 (Processing unit 2 2 value and set value signal and other functions, unit T 2 1, temperature value in the standard area, yuan F 2 1 Provide middle y element 2 2 1 3, power supply single replacement unit 2 2 wind or other air-conditioning box 11, is a CPU, has a connection, after its comparison operation, the output pair has at least one sensor element 'And transmit this value to the central micro processing unit for setting the value, the power supply to the central micro processing unit 2 2 1 1 and the detection of the central micro processing unit 2 2 ^ 1 2 is cold; M21, such as in the evaporator Fans ... etc. Fans; 5 according to 2 fan horses, room-power supply unit 2 2 1 electricity and refrigeration air-conditioning load side heat transfer (such as air-conditioning box, indoor fan ... I source; a power value detection unit 2 2 2 1 3 The output power value is composed of the above units According to the power value detection unit 221 to computing the energy required for the refrigerating and air Qlan, Q2a2, ..., replacement, etc.
為提供控制器太 之風戶κ 所需之:屬馬達Μ 9 T 組 風扇馬達)邃轉 4 ,係用 之電力供In order to provide the controller too, the wind household κ is required: it is a motor M 9 T group fan motor) turn 4 and it is used for power supply
以侦剛輪出單元 央微處理單元9Immigration wheel out unit Central Micro Processing Unit 9
第6頁 472130 五、翻酬(4) 再將其傳輸給空調需用能量值計算單元B 2 1計算出總冷 凍空調需用能量值Σ Q,而此總冷凍空調需用能量值計算 單元B 2 1係具有統計各控制器2 2 1冷凍空調需用能量 值之功能,並將其計算出之總冷凍空調需用能量值Σ q傳 輸給熱源機組控制器A 2 〇,使該控制器a 2 0根據Σ Q 值對應控制熱源機組2 1的熱源供應量q e,日該熱源機 組控制器A 2 0亦可與一電腦中心c連線。Page 6 472130 V. Remuneration (4) Retransmit it to the air conditioner energy value calculation unit B 2 1 to calculate the total refrigeration air conditioner energy value Σ Q, and this total refrigeration air conditioner needs the energy value calculation unit B 2 1 has the function of counting the energy values of the controllers 2 2 1 and transmits the total energy value Σ q required for refrigeration and air conditioning to the heat source unit controller A 2 〇, so that the controller a 2 0 controls the heat source supply quantity qe of the heat source unit 21 according to the Σ Q value, and the heat source unit controller A 2 0 can also be connected to a computer center c.
請再參閱第四圖所示者,為本發明單機配置系統之實 施例系統圖,此系統2之主要由一熱源機組2 1匹配—冷 凍空調負載侧熱交換機組2 2所組成,其中: V 一熱源機組2 1 ,係與一熱源機組控制器A 2 〇連接 ,並接受其訊號對應控制輸給冷凍空調負載側熱交換機組 2 2之熱源供應量Q e者; 一冷凍空調負栽侧熱交換機組2 2,係由一控制器Please refer to the figure shown in the fourth figure again, which is a system diagram of an embodiment of the single machine configuration system of the present invention. This system 2 is mainly composed of a heat source unit 21 1 matching-refrigeration air-conditioning load-side heat exchanger group 2 2 of which: V A heat source unit 21 is connected to a heat source unit controller A 2 0 and receives its signal correspondingly to control the heat source supply quantity Q e of the refrigerating and air-conditioning load-side heat exchanger group 22; a refrigerating and air-conditioning load side heat Switch group 2 2 by a controller
第7頁 472130 請-C率 (5)e 功 於 靜量至 I應 五供 者 示 所 圖 三 第 閱 參 照 對Page 7 472130 Please -C rate (5) e thanks to the static to I should be shown by the five donors Figure III
—MR 專ί. Ρ#根 值e' 率Q 冷 數總 成 換 功 出 輸 侧 β 負 得 測 所 4 IX 2 2 元 單 測 值 rl # 定 扇 風 量 應 供 源 熱 及 Q Σ 值 量 能 用 需1 周 η I a 空f Γν W a 風 的 達 馬 扇 風 道 知 9J 我 下 以 有 具 間 Q 力 能 同 空 *·^ν^ 冷 與 Ρ 率 功 耗 消 > 3 轉 、 · · F係 量關 1 3 8 F' 風 的為 達義 馬意 扇的 風8 即 比 正 成 3 速 幃 J5I 達 馬 扇 風 與 F 量 比 正 成 輸 扇 侧 風 載 與 負 ? 即 Q ( 量 率 能 功 用 耗 需 消。調 達}空 馬Ρ床 與OC冷 3 3即 速即{ 轉C力 心匕 匕匕 白 t 倉 達正調 馬成空 扇}束 風P冷 . 值 . 2 率3 功 出 即 比 正 成 P 值 率 功 。耗 消 Q達 8馬 F與 即 Q C力 比能 正調 成空 F^ 量冷 風· 的4 達 馬 出 輸 侧a 載1 負Q 據、 根1 到 a 演1 推Q 步即 -( 進Q 更值 , 量 bb οβ 倉 係調 的空 Q為 8算 :ρ換 \ly 上 P Q由值 8 率 P 功 ο- IX Σ a 有1 具Q 間 -- )Q η Σ 3 , η值 Q數 、係 i的 2 ^—MR 专 ί. Ρ # root value e 'rate Q cold number assembly power output side β negative measured 4 IX 2 2 yuan single measured value rl # fixed fan air volume should be used for source heat and Q Σ value energy It takes 1 week η I a empty f Γν W a wind Dama fan knows 9J I have the same Q force energy with the same space * · ^ ν ^ Cold and P rate power consumption > 3 turns, · · F system quantity off 1 3 8 F 'wind is the wind of the fan of the Italian fan. It is 3 times faster than J5I. The ratio between the wind of the Dama fan and F is positive. The wind load on the fan side is negative. Energy consumption needs to be consumed. Transferred} empty horse P bed and OC cold 3 3 immediately that is {turn C force heart dagger white t Cangda is tuned horse into empty fan} beam wind P cold. Value. 2 rate 3 work out That is, the power is higher than the positive P value. Consumption Q reaches 8 horses F and the QC force ratio can be positively adjusted to the empty F ^ amount of cold air. The 4 horses on the output side of the D a load 1 negative Q data, the root 1 to a play 1 push The Q step is-(into Q, the value is changed, the amount bb ο β empty Q adjusted by the bin system is 8: ρ change \ ly on the PQ by the value 8 rate P work ο-IX Σ a has 1 Q interval-) Q η Σ 3, η value Q number, 2 ^ i
轉, 式η 程a 為 η K Q (IT 係; 關 的 P KTurn, the formula η Cheng a is η K Q (IT system; related P K
2 a 1 Q 換 交 熱 側 β --3- .負 。調 空 P凍 K冷 -I據 Q根 Σ可 II , e成 Q組 以之 所件 ,元 e述 Q上 II 用 Q利 Σ 而2 a 1 Q change to the hot side β --3-. Negative. Adjust P to K and cold -I according to the Q root Σ can be II, e into the Q group, the element e described in Q on II uses Q to benefit Σ and
Σ其 值統 量系 匕匕周 A月 用空 需束 調冷 空制 康控 冷ο 總2 的A ο器 2制 R控 房組 調機 空源 凍熱 冷由 對, 2 小 2大 組的 機QThe value of Σ is the number of weeks. A month uses air-demand to adjust the cold and air to control the cold. Ο 2 A ο 2 units of R control room group. The air source is cold and hot, 2 small and 2 large groups. Machine Q
e Q 2 T 元 單 測 感 由 即 2 F 元 單 定 設 與 a T 值 度 溫 量境 應環 供之 源ο 熱2 的R 1 房 2調 組空 機凍 源冷 熱得 測The e Q 2 T element is measured by the 2 F element setting and the a T value. The temperature and the environment should be supplied by the source. The heat and cold of the R 1 room and 2 air conditioning unit are measured by the cold and heat source.
第8頁 472130 五、發明說明(6) 所設定之設定值T a s ,經由控制器2 2 1其中央微處理 單元2 2 1 1運算比對後,輸出一控制訊號給輸出單元2 2 1 3 ,以控制輸給風扇馬達Μ 2 1之電源功率,而功率 數值偵測單元2 2 1 4則偵測輸出單元2 2 1 3所輸出電 源功率之數值ρ 1 a 1 ,並傳給中央微處理單元2 2 1 1 運算成冷凍空調需用能量值Q1 a 1 ,再將此數值Q1 a 1再傳給冷凍空調需用能量值計算單元B21,並由此單 元統計出總冷凍空調需用能量值Σ Q,再由熱源機組控制 器A 2 0根據此值與設定值Q S之比對結果,以控制熱源 機組2 1的熱源供應量Q e。 第五圖所示者,為本發明單區域配置系統之實施例圖 ,其中此系統3由一熱源機組3 1匹配多組冷凍空調負載 侧熱交換機組3 2、3 3、3 4、…,以對冷凍空調區域 R 3 0提供熱源供應,而每一冷凍空調負載側熱交換機組 32、33、34、…之控制器 321 、331 、34 1 、…,與第三圖所示之方塊圖相同,係將所測得之各功 率數值P 1 a 1、P 1 a 2 ..... P 1 a η經運算後轉換 成空調需用能量值Qlal 、Qla2 .....Qian傳 輸給空調需用能量值計算單元B 3 1 ,統計出該單區域空 調需用能量值QA1 (此時QA1值等於Σ(3值),再由 熱源機組控制器A 3 0根據此值與設定值Q S之比對結 果,以控制熱源機組3 1的熱源供應量Q e。 第六圖所示者,為本發明多區域配置系統之實施例圖 ,其中此系統4係由一熱源機組4 1匹配多個冷凍空調區Page 8 472130 V. Description of the invention (6) The set value T as set by the controller 2 2 1 and its central micro processing unit 2 2 1 1 after calculation and comparison, outputs a control signal to the output unit 2 2 1 3 To control the power supply to the fan motor M 2 1, and the power value detection unit 2 2 1 4 detects the value ρ 1 a 1 of the output power output from the output unit 2 2 1 3 and transmits it to the central microprocessing Unit 2 2 1 1 calculates the energy value Q1 a 1 for the refrigeration air conditioner, and then transmits this value Q1 a 1 to the energy value calculation unit B21 for the refrigeration air conditioner, and the unit calculates the total energy value for the refrigeration air conditioner. Σ Q, and the heat source unit controller A 2 0 then controls the heat source supply quantity Q e of the heat source unit 21 according to the comparison result between this value and the set value QS. The one shown in the fifth figure is a diagram of an embodiment of a single-zone configuration system according to the present invention. In this system 3, a heat source unit 31 is matched with a plurality of refrigeration air-conditioning load-side heat exchanger groups 3 2, 3 3, 3 4, ..., In order to provide heat source supply for the refrigerating and air-conditioning area R 3 0, the controllers 321, 331, 34 1, ... of each refrigerating and air-conditioning load-side heat exchanger group 32, 33, 34, ..., and the block diagram shown in the third figure In the same way, the measured power values P 1 a 1, P 1 a 2 ..... P 1 a η are converted into air-conditioning energy values Qlal, Qla2, ..... The energy value calculation unit B 3 1 for the air conditioner calculates the energy value QA1 for the single area air conditioner (at this time, the value of QA1 is equal to Σ (3 value), and then the heat source unit controller A 3 0 according to this value and the set value QS The comparison result is used to control the heat source supply quantity Q e of the heat source unit 31. The one shown in the sixth figure is an embodiment of the multi-zone configuration system of the present invention, where the system 4 is matched by a heat source unit 41 Freezing and air-conditioning area
第9頁 472130 五、發明說明(7) 域R41、R42、R43、…提供熱源供應,而每一冷 凍空調區域R4 1 、R4 2、R4 3 -----,各設有至少一 組以上冷凍空調負載側熱交換機組4 2、4 3、4 4、4 5 、4 6、4 7、…,且在每一冷凍空調負載侧熱交換機 組42 、43 、…内各具有一控制器42 1 、431 、4 4 1 、4 5 1 、4 6 1 、4 7 1 、…,與第三圖相同,係 將所測得之各功率數值P 1 a 1、P 1 a 2 .....P 1 a n ' P 2 a 1 、…、P 2 a n 、…、P n a 1 、…、P n a nPage 9 472130 V. Description of the invention (7) The domains R41, R42, R43, ... provide heat source supply, and each refrigerating and air-conditioning area R4 1, R4 2, R4 3 -----, each has at least one group or more Refrigerating and air-conditioning load-side heat exchanger groups 4 2, 4 3, 4 4, 4 5, 4 6, 4 7, ..., and each of the refrigerating and air-conditioning load-side heat exchanger groups 42, 43, ... has a controller 42 each 1, 431, 4 4 1, 4 5 1, 4 6 1, 4 7 1, ..., the same as the third figure, the measured power values P 1 a 1, P 1 a 2 .... .P 1 an 'P 2 a 1, ..., P 2 an, ..., P na 1, ..., P nan
轉換成空調需用能量值Q1 a 1 .....Qian.....Q 2 a 1 、…、Q 2 a n、…、Q n a 1 、…、Q n a n 後, 再傳輸給各對應之冷凍空調區域R4 1、R4 2、R4 3 、…的冷凍空調需用能量值計算單元B41 'B42、B 4 3、…,並統計出各該區域的冷凍空調需用能量值分別 為A1 、A2 、A3 .....An,並由空調需用能量值計 算單元B4 1再計算出總需用能量值Σ(3 (即Σ(3等於Q A 1 + Q A 2 +…+ Q A η ),再由熱源機組控制器A 4 0根據Σ Q值與設定值Q S之比對結果,以控制熱源機組 4 1的熱源供應量Q e。 上述實施例中之熱源機組2 1、3 1 、4 1 、…為了 提高其運轉能量的管理,可與一電腦中心C連線,藉由此 電腦中心C對整個冷凍空調系統之監管,使冷凍空調能量 的運用更趨有效率運轉,以獲得能源最有效之運用者。 第七圖所至第十圖所示者,為本發明之控制方法,其 步驟為:The energy values Q1 a 1 ..... Qian ..... Q 2 a 1, ..., Q 2 an, ..., Q na 1, ..., Q nan are converted into air conditioners and then transmitted to the corresponding ones. The refrigerating and air-conditioning areas R4 1, R4 2, R4 3, ... need to use energy value calculation units B41 'B42, B 4 3, ..., and calculate the refrigerating and air-conditioning energy values for each area are A1, A2 , A3 ..... An, and calculate the total required energy value Σ (3 (that is, Σ (3 is equal to QA 1 + QA 2 +… + QA η)) from the energy value calculation unit B4 1 of the air conditioner, and then The heat source unit controller A 4 0 controls the heat source supply quantity Q e of the heat source unit 41 according to the comparison result of the Σ Q value and the set value QS. The heat source units 2 1, 3 1, 4 1, … In order to improve the management of its operating energy, it can be connected to a computer center C. By this computer center C's supervision of the entire refrigeration and air-conditioning system, the use of refrigeration and air-conditioning energy can be operated more efficiently to obtain the most effective energy. Operators The ones shown in Figures 7 to 10 are the control method of the present invention, and the steps are as follows:
第10頁 472130 五、發明說明(8) 1 ·輸入功率數值 PI a 1、···、PI an、···、P nan換算成冷凍空調需用能量值Qlal 、Qla2 .....Qnan、設定值QS、差值X:各控制器221 (321、331、341 ..... 421、431、44 1 、4 5 1 、4 6 1 、…)根據功率數值偵測單元2 2 1Page 10 472130 V. Description of the invention (8) 1 · Input power value PI a 1 ···· PI an ····, P nan is converted into refrigeration air conditioner to use energy values Qlal, Qla2 ..... Qnan , Set value QS, difference X: each controller 221 (321, 331, 341 ..... 421, 431, 44 1, 4 5 1, 4 6 1, ...) detects the unit based on the power value 2 2 1
4所測得之偵測值P傳輸至中央微處理單元2 2 1 1經過 運算後,轉換成各個別冷凍空調需用能量值Q 1 a 1 ( Q 2 a 1、…Q 1 a η、...、Q n a 1、Q n a η )後,再 輸入冷凍空調需用能量值計算單元Β2 1 (或Β3 1 、Β 4 1); 2 _選擇運轉型態,根據配置分為: ( (1 )單機運轉型態(請參閱第四、八圖),其流程為: , i I .當 EQ = Qlal ,EQ>QS+X.時,表示冷 凍空調負載側熱交換機組2 2的總冷凍空調需用能量值Σ Q (即能量需求)大於設定值Q S加上差值X,此時熱源 機組控制器A 2 0控制熱源機組2 1之熱源供應量Q e為 最大值MAX ; Π·當QSSSQSQS+X時,熱源機組21之熱 源供應量Q e維持在與Σ Q值成正比關係,即提供與冷凍 空調負荷相當之冷凍空調能力於系統,以達最佳效率之運 , 轉; ' 皿·當EQ<QS時,表示冷凍空調負載側熱交換機 ( 組2 2能量需求低於設定值Q S,此時熱源機組2 1之熱 源供應量Q為最為小值m i η ;4 The measured detection value P is transmitted to the central micro processing unit 2 2 1 1 After calculation, it is converted into the energy values Q 1 a 1 (Q 2 a 1, ... Q 1 a η,... .., Q na 1, Q na η), and then enter the energy value calculation unit B2 1 (or B3 1, B 4 1) required for refrigeration and air-conditioning; 2 _Select the operation mode, which is divided into: ((1 ) Stand-alone operation type (please refer to Figures 4 and 8). The flow is:, i I. When EQ = Qlal, EQ> QS + X., It means the total refrigerating and air-conditioning of the heat exchanger group 2 2 on the refrigerating and air-conditioning load side. It is required that the energy value Σ Q (that is, the energy demand) is greater than the set value QS plus the difference X. At this time, the heat source unit controller A 2 0 controls the heat source supply quantity Q e of the heat source unit 21 to the maximum MAX; Π · When QSSSQSQS At + X, the heat source supply Q e of the heat source unit 21 is maintained in a proportional relationship with the Σ Q value, that is, to provide refrigeration and air-conditioning capacity equivalent to the refrigeration and air-conditioning load to the system to achieve the best efficiency operation. When EQ < QS, it means that the heat exchanger of the refrigeration air conditioning load side (group 2 2 energy demand is lower than the set value QS, at this time the heat source of the heat source unit 21 The supply Q is the minimum value m i η;
第11頁 五、發明說明(9) (2 ) 區域運轉 I ·當 Σ Q a η,Σ Q > q 總冷凍空調需用 值Q S加上差值 機組3 1之熱源 Π ·當 Q S 源供應量Q維持 調負荷相當之冷 轉; 皿·當Σ Q 量需求低於設定 Qe為最小值min (3 )多區域運 I ·當 Σ Q 區域之冷;東空調 1 a 2 + ··· + Q 卜…Q 2 a η, Q n a η ),且 冷凍空調需用量R 4 2、R 4 3 設定值Q S加上 該熱源機組4 1n ·當 q s 型態(請參閱第五、九圖)其流程為··=Q1 a l+Ql a2 + …+ Q1 時,表示該冷凍空調區域r 3 0的 EQ (即區域能量需求)大於設定 k熱源機組控制器A 3 0控制熱源 Qe為最大值MAX ; · $QS + X時,熱源機組3 1之熱 Q值成正比關係,即提供與冷凍空 能力於系統,以達最佳效率之運Page 11 V. Description of the invention (9) (2) Regional operation I · When Σ Q a η, Σ Q > q Total refrigeration air-conditioning needs QS plus the heat source of differential unit 31 1 · When QS source is supplied The quantity Q maintains a cold turn equivalent to the load regulation; ·· When the Σ Q quantity demand is lower than the set Qe to the minimum value min (3) Multi-zone operation I · When the Σ Q area is cold; East air conditioner 1 a 2 + ··· + Q Bu ... Q 2 a η, Q na η), and the amount of refrigerating and air-conditioning required R 4 2, R 4 3 set value QS plus the heat source unit 4 1n · When qs type (see Figures 5 and 9), When the flow is ·· = Q1 a l + Ql a2 +… + Q1, it means that the EQ of the refrigeration and air-conditioning area r 3 0 (that is, the area energy demand) is greater than the set k heat source unit controller A 3 0 to control the heat source Qe to the maximum MAX ; When $ QS + X, the heat Q value of the heat source unit 31 is directly proportional, that is, to provide the system with refrigeration capacity to achieve the best efficiency.
=A 1 S + X 能量值 X,此 供應量 ^ Σ Q 在與Σ 凍空調 < Q S 值Q S 轉型態 =Q A 需用能 lan···,Q Σ Q > 值Σ Q 、…的 差值X 之熱源 ^ Σ Q 時’表不冷凍空調區域R3 〇 ,此時熱源機組3丨之熱源供= A 1 S + X Energy value X, this supply amount ^ Σ Q is in the transition state with Σ freezer air conditioner < QS value QS = QA requires energy lan ··, Q Σ Q > value Σ Q, ... When the heat source of the difference X is ^ Σ Q, 'represents the refrigerating and air-conditioning area R3 〇, at this time, the heat source of the heat source unit 3 丨
(請參 1 + Q 量值分 ,Q A Α π = Q S + (即各 冷凍空 ,此時 供應量 ^ Q S(Please refer to 1 + Q quantity points, Q A Α π = Q S + (that is, each frozen space, at this time the supply amount ^ Q S
閱第六、十圖)其流程 八2 +…+ QAn (而 別為 Q A 1 = Q 1 a 1 2 - Q(See Figures 6 and 10.) The process 8 2 + ... + QAn (not Q A 1 = Q 1 a 1 2-Q
Q a + Q 2Q a + Q 2
之能 應量為:各個 + Q a rial+Qna2 + -< X時,表示該多區域整 個別冷凍空調區域R 4 調需用能量值的總和) 熱源、機組控制器A 4 Q Qe為最大值MAX ; + x時,熱源機組4 1 體總 1、 大於 控制 之熱The energy capacity is: each + Q a rial + Qna2 +-< X, it means the sum of the R 4 power requirements for the entire refrigerating and air-conditioning area in the multi-zone) The heat source and unit controller A 4 Q Qe is the maximum When the value is MAX; + x, the total heat source unit 4 1 is larger than the heat of control
第12頁 472130 五、發明說明(10) 源供應量Q e維持在與Σ Q值成正比關係,即提供與冷凍 空調負荷相當之冷凍空調能力於系統,以達最佳效率之運 轉; 皿·當Σ Q < Q S時,表示該多區域整體的總能量需 求低於設定值Q S,此時熱源機組4 1之熱源供應量Q為 最小值m i η ° 綜上所述,本發明之控制方法與裝置,可根據冷凍空 碉負載侧輸出功率值計算出空調需用能量值,並藉以使熱 源機組產生相對應熱源供應量,使熱源機組可隨機根據負 載側的冷凍空調需用能量值進行對應調整,使系統於任一 時間,皆維持在最佳效率狀況下蓮轉,進而達到節能目的 者。Page 12 472130 V. Description of the invention (10) The source supply Q e is maintained in a proportional relationship with the Σ Q value, that is, to provide refrigeration and air-conditioning capacity equivalent to the refrigeration and air-conditioning load to the system to achieve the best efficiency operation; When Σ Q < QS, it means that the total energy demand of the whole region is lower than the set value QS. At this time, the heat source supply Q of the heat source unit 41 is the minimum value mi η ° In summary, the control method of the present invention And the device can calculate the energy value required for air conditioning according to the output power value of the load side of the refrigeration airspace, so that the heat source unit can generate a corresponding heat source supply, so that the heat source unit can randomly respond to the energy value of the refrigeration air conditioner on the load side. Adjust so that the system can maintain the optimal efficiency at any time, and then achieve energy saving.
第13頁 472130 圖式簡單說明 <圖式部份> 第一圖:習式冷凍空調之系統圖。 第二圖:習式之控制方塊圖。 第三圖:本發明其控制裝置之方塊示意圖。 第四圖:本發明於單機配置系統之實施例圖。 第五圖:本發明於單區域配置系統之實施例圖。 第六圖:本發明於多區域配置之實施例圖。 第七圖:本發明其控制流程圖(一)。 第八圖:本發明其控制流程圖(二)。 第九圖:本發明其控制流程圖(三)。 第十圖:本發明其控制流程圖(四)。 <圖號部份> 2、3、4 _冷凍空調系統 1 1 一熱源機組 1 2 —冷凍空調負載侧熱交換機組 1 2 0 _控制器 1 2 1 —中央處理單元 1 2 2 _電源供應單元 1 2 3 -輸出單元 1 3 -熱交換器 Ml —風扇馬達 F 1 1—設定單元 T A S —設定值Page 13 472130 Schematic illustration < Schematic part > Figure 1: System diagram of Xi'an refrigerated air conditioner. Figure 2: Control block diagram of the habit. FIG. 3 is a block diagram of a control device of the present invention. Fourth figure: The embodiment of the present invention in a stand-alone configuration system. Fifth Figure: The embodiment of the present invention in a single area configuration system. FIG. 6 is a diagram of an embodiment of the present invention in a multi-zone configuration. Figure 7: Control flow chart (1) of the present invention. Figure 8: The control flow chart (2) of the present invention. Figure 9: The control flow chart (3) of the present invention. Fig. 10: The control flow chart (4) of the present invention. < Figure No. > 2, 3, 4 _ Refrigeration and air-conditioning system 1 1 A heat source unit 1 2 —Cooling and air-conditioning load-side heat exchanger unit 1 2 0 _Controller 1 2 1 —Central processing unit 1 2 2 _Power supply Supply unit 1 2 3-Output unit 1 3-Heat exchanger Ml-Fan motor F 1 1-Setting unit TAS-Setting value
第14頁 472130 圖式簡單說明 T 1 1 一感測單元 T A —感測值 A 2 0、A 3 0 _熱源機控制器 2 1、3 1、4 1 —熱源機組 22、32、33、34 —冷凍空調負載側熱交換機組 42、43 、44、45 、46 、47 —冷凉·空調負載側 熱交換機組 221、321、331、341—控制器 421、431、441—控制器 451 、461 、471-控制器 2 2 1 1 —中央微處理單元 2 2 1 2 _電源供應單元 2 2 1 3 —輸出單元 2 2 1 4 -功率數值偵測單元Page 14 472130 Brief description of the diagram T 1 1-sensing unit TA — sensing value A 2 0, A 3 0 _ heat source machine controller 2 1, 3 1, 4 1 — heat source unit 22, 32, 33, 34 -Refrigeration and air conditioning load-side heat exchanger groups 42, 43, 44, 45, 46, 47-Cooling and air conditioning load-side heat exchanger groups 221, 321, 331, 341-Controllers 421, 431, 441-Controllers 451, 461 471-controller 2 2 1 1 —Central microprocessor unit 2 2 1 2 _Power supply unit 2 2 1 3 —Output unit 2 2 1 4 -Power value detection unit
第15頁 472130 圖式簡單說明 Q.nal 、Qna2 、...、Qnan —冷康空調需用能量 值 RIO、R20、R30_冷凍空調房 R41 、R42、R43 —冷凍空調房 T 2 1 —感測單元 F21—設定單元 Q S —設定值 T A S _設定值 T a —環境溫度值 Q e —熱源機組之冷凍空調熱源供應量 X _差值 ω —轉速 F —風量 Q —冷凍空調能力 Ρ —功率數值Page 15 472130 The diagram briefly explains Q.nal, Qna2, ..., Qnan — the energy values for cold air conditioners RIO, R20, R30 — refrigerated air-conditioned rooms R41, R42, R43 — refrigerated air-conditioned rooms T 2 1 — sense Measuring unit F21—Setting unit QS—Setting value TAS _Setting value T a —Ambient temperature value Q e —Cooling and air conditioning heat source supply of the heat source unit X _Difference ω —Speed F —Air flow Q —Chilling and air conditioning capacity P —Power value
Plal、Pla2、-..、Plan —功率數值 P2a 1、P2a2、...、P2an —功率數值 i* n an —功率數值 C 一電腦中心Plal, Pla2,-.., Plan — power value P2a 1, P2a2, ..., P2an — power value i * n an — power value C—computer center
第16頁Page 16
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