TW455800B - Device, system, and method for modem communication utilizing two-step mapping - Google Patents

Device, system, and method for modem communication utilizing two-step mapping Download PDF

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Publication number
TW455800B
TW455800B TW86115260A TW86115260A TW455800B TW 455800 B TW455800 B TW 455800B TW 86115260 A TW86115260 A TW 86115260A TW 86115260 A TW86115260 A TW 86115260A TW 455800 B TW455800 B TW 455800B
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Taiwan
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points
modem
mapping
cost
network
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TW86115260A
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Chinese (zh)
Inventor
Guozhu Long
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Cirrus Logic Inc
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Priority claimed from US08/731,500 external-priority patent/US5926505A/en
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Publication of TW455800B publication Critical patent/TW455800B/en

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Abstract

Modem technology is implemented in a system including a personal computer (PC) to enable communication over a PSTN using communication software which includes a mapping algorithm for mapping data into u-law signal points, which are divided into segments with different distances.

Description

455800 經濟部中央標準局負工消費合作社印製 A7 B7 五、發明説明(1) Ϊ.發明範圍 - 本發明總體而言係關於一種數據機裝置、一種以數據機 為基礎的系統及一種用於信號通訊的方法,具體而言則是 關於利用二步映射技術的高速數據機通訊。 2 .發明背景 若干已知的傳統數據機裝置、系統與方法係在個人電腦 ' 之間,經由公用交換電話網路(PSTN)傳遞訊號。為不進行 該種通訊,先前已使用信息框映射技術,而且目前亦使用 中。但由於數據機性能的改良,進行各種信息框映射技術 以便將一設定之形態増益的平均功率減至最小程度的需要 性即日漸增加。 發明概述 根據本發明’一經由一 PSTN傳輸和接收信號的PC係使用 一種二步映射演算法將一設定形態増益之平均功率予以減 少或減至最小的程度。該PC包括—經由該PSTN與一種裝 置,例如另一 PC、一迷你電腦、—主機電腦、一傳真機等 通訊的數據機。該數據機包含一種二步映射裝置,該裝置 使用一次級產生函數以盡量減小(或減少)使用具最小距離 的訊號點,以及減少錯誤率。 圖式之簡單說明 ' 圖1 A是本發明中使用公用交換電話網路之PC通訊系統區 塊圖。 . 圖1B是本發明中之pc區塊圖。 圖1C是本發明中之傳輸訊號頻譜。 -4- 本紙張尺度適用中國國家掠準(CNS ) Α4規格(210 X 297公麥) (請先閲讀背面之注意事項再填寫本頁) 訂 _'線 經濟部中央標準局負工消費合作社印裂 455800 A7 B7 五、發明説明(2) 圖2是本發明中之56k鮑率數據機通訊系統區塊圖。 圖3是本發明之56k鮑率數據機通訊系統的已編碼解碼器 區塊圖。 圖4是本發明之56k鮑率數據機通訊系統的未編碼解碼器 區塊圖。 .圖5是本發明之56]^鮑率數據機通訊系統的具頻譜編碼解 1 碼器區塊圖。 圖6是本發明之56]^鮑率數據機通訊系統的具頻譜未編碼 解碼器區塊圖。 圖7是本發明之類比端半多工數據機接收器區塊圖。 圖8是本發明之類比端半多工數據機接收器的一種可能 的具體實施例之區塊圖。 圖9是本發明之類比端全多工數據機接收器的區塊圖。 圖10是本發明之類比端全多工數據機接收器的可替換具 體貫施例之區塊圖。 圖11是本發明之類比端全多工數據機接收器的一種可能 的具體實施例之區塊圖。 較佳具體實施例之詳細說明 參考圖1A,該圖顯示一根據本發明的配置,其中PC 1〇〇 包含數據機101 ’並經由PSTN 1〇3與裝置102通訊,該裝置 例如其他的PC、迷你電腦、主機電腦、傳真機等。數據機 101可在一 14,400 (14.4k)、18,800 (28.8k)、33,60 (33.6k)、 56,000 (56k)或其化訊號率(如鮑率)之數位訊號傳輸/接收率 上操作。該數據機並包含二步映射裝置104,該裝置利用 -5- 本紙張尺度適用中國國家標皁(CNS > A4規格(21〇χ297公瘦> (請先99讀背面之注意事項再填寫本頁)455800 Printed by the Central Standards Bureau of the Ministry of Economic Affairs and Consumer Cooperatives A7 B7 V. Description of the invention (1) 范围. Scope of the invention-The present invention relates generally to a modem device, a modem-based system, and a device for The method of signal communication is specifically about high-speed modem communication using two-step mapping technology. 2. Background of the Invention Several known conventional modem devices, systems, and methods are transmitted between personal computers' via a public switched telephone network (PSTN). To avoid this type of communication, information frame mapping technology has been used previously and is currently in use. However, due to the improvement of the performance of the modem, the need for various information frame mapping techniques to reduce the average power of a set form to a minimum is increasing. SUMMARY OF THE INVENTION According to the present invention '-a PC transmitting and receiving signals via a PSTN uses a two-step mapping algorithm to reduce or minimize the average power of a set shape benefit. The PC includes a modem that communicates with a device, such as another PC, a mini computer, a host computer, a facsimile machine, etc., via the PSTN. The modem includes a two-step mapping device that uses a first-order generation function to minimize (or reduce) the use of signal points with a minimum distance and to reduce the error rate. Brief Description of the Drawings' FIG. 1A is a block diagram of a PC communication system using a public switched telephone network in the present invention. Figure 1B is a pc block diagram in the present invention. FIG. 1C is a transmission signal spectrum in the present invention. -4- This paper size is applicable to China National Graduation Standard (CNS) Α4 size (210 X 297 gram) (please read the precautions on the back before filling this page) Crack 455800 A7 B7 V. Description of the invention (2) Figure 2 is a block diagram of a 56k baud rate modem communication system in the present invention. Fig. 3 is a block diagram of a codec of a 56k baud rate modem communication system according to the present invention. Fig. 4 is a block diagram of an uncoded decoder of a 56k baud rate modem communication system according to the present invention. Fig. 5 is a block diagram of the encoder with spectrum encoding and resolution of the 56] baud rate modem communication system of the present invention. Fig. 6 is a block diagram of an unencoder with a spectrum of a 56] baud rate modem communication system of the present invention. Fig. 7 is a block diagram of an analog half-duplex modem receiver according to the present invention. Fig. 8 is a block diagram of a possible specific embodiment of an analog half-duplex modem receiver of the present invention. FIG. 9 is a block diagram of an analog full-duplex modem receiver according to the present invention. FIG. 10 is a block diagram of a specific alternative embodiment of an analog full-duplex modem receiver of the present invention. Fig. 11 is a block diagram of a possible specific embodiment of an analog full-duplex modem receiver according to the present invention. For a detailed description of a preferred embodiment, refer to FIG. 1A, which shows a configuration according to the present invention, in which a PC 100 includes a modem 101 'and communicates with a device 102 via PSTN 103, such as another PC, Mini computers, host computers, fax machines, etc. The modem 101 can operate at a digital signal transmission / reception rate of 14,400 (14.4k), 18,800 (28.8k), 33,60 (33.6k), 56,000 (56k) or its signal rate (such as baud rate). The modem also includes a two-step mapping device 104, which uses -5- this paper size to apply Chinese National Standard Soap (CNS > A4 specification (21〇χ297 Male Thin)) (Please read the precautions on the back before you fill out (This page)

45 5 8 0 0 A7 B7 五、發明説明(3 ) 一二次產生函數來盡量減小(或減少)使用具有最小距離的 訊號點,以及減少錯誤率。 參考圖1B »圖中PC 100包括經由傳統資料和指令匯流排 108連接到中央處理單元(CPU)107tPC系統軟體1〇5和%數 據機軟體106。CPU 107操作數據機软體1〇6,以協調該數據 機控制器(未示於圖中)的運作,並經由數據機丨〇6引導該訊 ' 號的傳輸。在CPU 107操作數據機軟體1〇6期間,數位信號 隨即於數據機101之訊息框内產生並排序;如係資料信號 傳輸時,該等數位信號可應於一螢幕影像,或者,如係一 聲晋信號之傳輸之情形’則該等信號可對應於一個語音的 區塊。每一個訊息框均含有與N符號結合的資訊,並由κ 二進位元予以界定。該等艮二進位元在一數位信號流内排 序’且被分成數個區段。 參考圖2,圖中所示的一種56k鮑率數據機通訊系統數位 數據機101經由PSTN 103連接至與裝置102相連的類比數據 機201。其樣本率為8 kHz。在各樣本中,一拌碼器(未示於 圖中)運作一輸入位元集。一編碼器(未示於圖中)使用該 經濟部中央標準局貞工消費合作社印製 (請先閱讀背面之注意事項再填寫本頁) 拌碼器的輸出,以產生輸出信號樣本,此等樣本經由數位 網路203送到#定律d/A 205,並轉換成類比信號。 #定律D/A 205使用一具有總數達255可能輸入之數位值 的付號數量格式。該等255值分成16個區段:+1、+2、…、 +8 ' -1、-2、…、_8。在第i區段的兩相鄰點間之旌離是。 為簡單纣論且不限制該值起見,設c = i。+1和_丨區段為最 小之距離為1 ’ 〇點則由該兩區段共用。此等兩個最小距 -6- 本纸張尺度適用中國國家標準(CNS ) A4規格(21{5Χ297·^~|· 經濟部中央標準局貝工消費合作社印製 455800 A7 ____B7 五、發明説明(4) 離為1的區段可因無顯著的傳輸品質或接收品質之損失而 不予計入,故尚餘224點。以此類推,一對次小的點亦可 不計,俾增加該最小距離◦每當剔除32點時,該最小距離 加倍,而得到6dB噪音容限的増益。 在可用於訊號傳輸的各點間,該等在外部的點具有最大 距’離》而成為可用的較佳點。 " 為了多用該等較大之點,可能要修改和應用一傳統的殼 式映射演算法。例如,利用一傳統的v . 34數據機將該二維 信號星群劃分成Μ個環,每一個μ環皆具有相同的點數。 此等Μ環依據該環的平均功率排序。該殼式映射演算法較 常選擇該等内邵的環來減少該總平均功率。 本發明中,該等一維點分成2m個區段:±(9-m)、·.·、±7、 ±8 ’ m=l,3,…,7。該+ i和_i區段合併成—具有區段指標8-i之 區段。該區段指標從最大能量至最小能量予以排序a 參考圖3 ’其中所示的編碼器3〇1連接到數位網路203, 並接收多重輸入。編碼器301包括區段映射器303和交織編 碼器304,此兩者皆提供輸入訊號至位元映射305。編碼器 在將該等傳輸訊號編碼後,便立刻將其從位元映射305傳 輸至數位網路203。 現在更具體地選擇Μ個可用點及傳輸N符號之一信息框 中的Κ個位元,則該資料率為8000 Κ/Ν位元/秒=該Μ個點 分成0,1,…,m-Ι的m=M/32個區段。注意,不論是每符號位元 的K/N或K均須為整數。非整數K的情形可能要應用信息框 交換技術。但為簡化討論,可假設K是一整數。如果在一 本紙張尺度適用中國國家標準(CNS ) A4規格(210X297公釐) (請先閲讀背面之注$項再填寫本頁) -訂_ 455800 經濟部中央標準局負工消費合作社印製 Α7 Β7 五、發明説明() 區段内選擇一點需要5位元,則可使用k == K-5N位元來做” 區段映射’’。k的最大可能值可由下列不等式獲得:2k ^ 。例如,如果使用192點且該映射框之大小為8,則m=6 且k S 20.68。如果使用k = 20,則每一符號傳輸7·5位元且該 資料率為(k+5N)*8000/N=60 kbps。 為送出訊號資訊’傳統上每6個符號使用(截取)ι位元, 、 但条干舊的編碼解碼器則用各符號的1位元。因此,每6個 符號取一位元’則餘留LSB位元做為該截取信號位元,可 供使用之點共有M/2個。但須注意,本發明可予以修改俾 符合較舊.的編碼解碼器之需求。利用M/2個之可能點,4位 元可用來選擇一個偶數點。而該資料率即減少 8000/6=1333.33 bps .對若干舊的編碼解碼器而言,該截取的 位元係用於每一符號’因此該資料率減少8 kbps。 並不一定需要使用最大可能的k 如果使用一個小k ,則45 5 8 0 0 A7 B7 V. Description of the invention (3) Generate the function once or twice to minimize (or reduce) the use of signal points with the smallest distance and reduce the error rate. Referring to FIG. 1B, the PC 100 in the figure includes a 107tPC system software 105 and a data processor software 106 connected to a central processing unit (CPU) 107 via a conventional data and instruction bus 108. The CPU 107 operates the modem software 106 to coordinate the operation of the modem controller (not shown), and directs the transmission of the signal via the modem 060. During the operation of the modem software 106 by the CPU 107, the digital signals are generated and sequenced in the message box of the modem 101. If the data signals are transmitted, the digital signals can be applied to a screen image, or The situation of the transmission of sound signals' These signals may correspond to a block of speech. Each message box contains information combined with the N symbol and is defined by the κ binary. The bins are ordered ' within a digital signal stream and are divided into sections. Referring to FIG. 2, a 56k baud modem communication system digital modem 101 is shown connected to an analog modem 201 connected to a device 102 via a PSTN 103. Its sample rate is 8 kHz. In each sample, a coder (not shown) operates on a set of input bits. An encoder (not shown) is printed by the Zhengong Consumer Cooperative of the Central Standards Bureau of the Ministry of Economics (please read the precautions on the back before filling this page). The output of the coder is used to generate output signal samples. The samples are sent to #Law d / A 205 via digital network 203 and converted into analog signals. # 法律 D / A 205 uses a payout number format with a total of 255 digits that can be entered. The 255 values are divided into 16 segments: +1, +2, ..., +8 '-1, -2, ..., _8. The distance between two adjacent points in the i-th segment is. For simplicity and without limiting this value, let c = i. The minimum distance between the +1 and _ 丨 sections is 1 ′ 〇 and the two sections are shared. These two minimum distances -6- This paper size applies to the Chinese National Standard (CNS) A4 specifications (21 {5 × 297 · ^ ~ || · Printed by the Bayer Consumer Cooperative of the Central Standards Bureau of the Ministry of Economic Affairs 455800 A7 ____B7 V. Description of the invention ( 4) Segments with a distance of 1 may not be counted because there is no significant loss of transmission quality or reception quality, so there are 224 points left. By analogy, a pair of small points can be ignored, so increase the minimum Distance ◦ Every time 32 points are removed, the minimum distance is doubled, and the benefit of 6dB noise margin is obtained. Among the points that can be used for signal transmission, these external points have the maximum distance 'away' and become available. Good point. In order to use these larger points more, a traditional shell mapping algorithm may be modified and applied. For example, a traditional v. 34 data machine is used to divide the two-dimensional signal constellation into M Ring, each μ ring has the same number of points. These M rings are sorted according to the average power of the ring. The shell mapping algorithm more often selects these inner rings to reduce the total average power. In the present invention , These one-dimensional points are divided into 2m sections: ± (9-m) ···, ± 7, ± 8 'm = 1, 3, ..., 7. The + i and _i sections are combined into a section with a section index 8-i. The section index ranges from the maximum energy to The minimum energy is sorted a. Refer to Figure 3, where the encoder 3101 is connected to a digital network 203 and receives multiple inputs. The encoder 301 includes a section mapper 303 and an interleaving encoder 304, both of which provide Input signal to bitmap 305. After the encoder encodes these transmission signals, it immediately transmits them from bitmap 305 to digital network 203. Now more specifically select one of the M available points and transmit N symbols K bits in the information frame, the data rate is 8000 K / N bits / second = the M points are divided into 0,1, ..., m−1 m = M / 32 sections. Note that regardless of K / N or K for each symbol bit must be an integer. In the case of non-integer K, the information frame exchange technology may be applied. However, to simplify the discussion, it can be assumed that K is an integer. If China is applied to a paper scale Standard (CNS) A4 size (210X297 mm) (Please read the note on the back before filling in this page)-Order _ 455800 Central Standard of the Ministry of Economic Affairs Printed by the Bureau of Work and Consumer Cooperatives A7 Β7 V. Description of the Invention () Selecting a point in the section requires 5 bits, you can use k == K-5N bits to do "section mapping". The maximum possible value of k It can be obtained from the following inequality: 2k ^. For example, if 192 points are used and the size of the mapping box is 8, then m = 6 and k S 20.68. If k = 20, each symbol transmits 7.5 bits and the The data rate is (k + 5N) * 8000 / N = 60 kbps. To send signal information, 'traditionally' (bits) are used every 6 symbols, but the old codec uses 1 for each symbol. Bit. Therefore, if one bit is taken every 6 symbols', the remaining LSB bits are used as the intercepted signal bits, and there are M / 2 points available for use. However, it should be noted that the present invention can be modified to meet the requirements of older codecs. With M / 2 possible points, 4 bits can be used to select an even point. The data rate is reduced by 8000/6 = 1333.33 bps. For some older codecs, the truncated bits are used for each symbol ’, so the data rate is reduced by 8 kbps. It is not necessary to use the largest possible k. If a small k is used, then

由於可自由使用外部點而可得到"距離增益,,D 如果選擇N = 8 ’則所用的該區段映射演算法可能與用於 傳統V.34數據機之殼式映射演算法相同。在殼式映射演算 法中’成本函數趨近於線性函數’該線性函數極適於估算 如何盡量減小平均功率,但不適於平均距離。 如果一準則是用來盡量減小該平均距離,則理想的成本 函數應與該距離成反比,該距離係屬一指數函數,例如, 如果使用7個區段與一線性成本函數,並選擇2個區段$ 點、1個區段4點、與1個區段6點’則其成本均相同,伸 該等平均在距離則分別為128和(256+64)/2=160。因此,评相 -8, 本紙張尺度適用中國國家標準(CNS ) Α4規格(210Χ297公釐) {請先閲讀背面之注意事項再填寫本頁〕Because of the free use of external points and the "distance gain", D, if N = 8 'is selected, the segment mapping algorithm used may be the same as the shell mapping algorithm used in traditional V.34 modems. In the shell mapping algorithm, the 'cost function approaches the linear function'. This linear function is very suitable for estimating how to minimize the average power, but not for the average distance. If a criterion is used to minimize the average distance, the ideal cost function should be inversely proportional to the distance. The distance is an exponential function. For example, if you use 7 segments and a linear cost function, choose 2 The cost of each segment is $ points, 1 segment is 4 points, and 1 segment is 6 points. The cost is the same, and the average distance is 128 and (256 + 64) / 2 = 160. Therefore, the rating is -8. This paper size is applicable to China National Standard (CNS) Α4 specification (210 × 297 mm) {Please read the precautions on the back before filling this page]

4 5 58 0 0 A7 B7 五、發明説明(6 ) 的方式應為修改該映射演算法’以獲得最大的-平均距離。 —殼式映射演算法的另一方式是,假設有7環,且可達 成下列之產生函數: g 1 = 1+x+x2+x3+x4+x5+x6 二 g2=gl*gl=l+2x+3x2+4x3+5x4+6x5+7x6+0X7+5X8+4X9+3X10+2Xu+xt2 g4=g2*g2=l+...x24 ; g8=g4*g4=l+...x',s 〆 ' 遠G4表的大小為4m-4·,G8表的大小為8ηι-8,其中m為環 數。 - 如k = 7,則修改該成本函數為0,1,2,4,8,16,32,而該產生函 數即成為:4 5 58 0 0 A7 B7 5. The method of the invention description (6) should be to modify the mapping algorithm 'to obtain the maximum-average distance. —Another way of the shell-mapping algorithm is to assume that there are 7 rings and the following generation functions can be achieved: g 1 = 1 + x + x2 + x3 + x4 + x5 + x6 two g2 = gl * gl = l + 2x + 3x2 + 4x3 + 5x4 + 6x5 + 7x6 + 0X7 + 5X8 + 4X9 + 3X10 + 2Xu + xt2 g4 = g2 * g2 = l + ... x24; g8 = g4 * g4 = l + ... x ', s 〆 'The size of the far G4 table is 4m-4 · and the size of the G8 table is 8η-8, where m is the number of rings. -If k = 7, modify the cost function to 0,1,2,4,8,16,32, and the generation function becomes:

gl=l+x+x2+x4H g2^1*gl=l+Z\^2\^+2x5+2x6+2xs+2x9+2XI0+2X12+2X164-.. —ΙΪ 1- -I - I I = - ιν_-^ I - li I . {請先閲讀背面之注i項再填寫本頁) g4=g2*g2=R.··: g8=g4*g4=K...x: 128 .256 經濟部中央標準局員H消費合作社印製 雖然有若干個Ο,但該G4表的大小為l+2k ; G8表的大小 則為 l+2k+1。 雖然能使用同一映射演算法,但是該等表格大了許多, 且亦較為複雜。 另一方面,較大的平均距離可能不是唯一的準則。另一 準則是將該最小區段之頻率減至最小°由於錯誤似乎多在 最小區段發生’所以此準則可能改善結果。為得到此結 -9- 本紙張尺度適用中國國家榇準(CNS ) Α4規格(210Χ297公釐) 45 58 0 0 A7 B7 五、發明説明( 7 經濟部中央揉準局員工消費合作社印製 果,該產生函數可為: gl = l+X+X2+X3+x4+X54-X41 在此情形中,該最小區段内任何具有至少一點的8點兔 合的成本南於各種不具有任何一點的8點組合。換言之, 唯有在使用各種不具有該點的組合後,才選取該區段。一 個特例是,如果該最小距離的極小頻率是难一的準則,貝* 可採用一較簡單的產生函數如:' gl=6+X 在此情形中,其成本函數為 段不得使用。 另一可行準則為減少該次小區段的使用 述產生函數而獲得: gl=5+x+x9 在此情形中,其成本函數為〇,〇〇,〇,〇,i9 一 的2個區段不應使用。該表格大小是合宜的,而其效能 上述的另一種實施例略佳。 如果使用該等成本函數之_,則成本並非僅指該區段 標。例如,如果使用最後的成本函數,成本〇即意謂區段 至4 ’成本i意謂區段5,成本9意謂區段6。在此情形中 應使用的區段可藉採行第二產生函數來決定。與上述殼』 映射算式相似’搜尋該zs表, a、、 」传8個仃唬的總成本。d 果孩總成本為〇,則可能須採行第二產生函數如: hl=l+x+x2+x3+x4 h2=hl*hl 且僅該最小 此準則可藉 且僅有該最 f請先聞讀背面之注意事項再填寫本頁j "裝. 訂' -10- 本紙杀μ劍t ϋ n家標準210χ297^7 A7 B7 4 5 58〇〇 ------- 五、發明説明(8 h4=h2*h2 然後使用相同的映射演算法,則可得到範圍從0至4之8 個區段指標。 如果8個符號的總成本不是〇 ,則繼績使用料表將8個 '成本分成4個符號的兩個成本。如果該四個符號成本 中的一個成本為〇,則轉到匕表以求得〇至4的四個區段指 饮。同樣’如果該四個符號的成本不是0 ’則繼續用§2表 將孩四個符號的成本分成兩個符號的兩個成本。如該兩個 符破成本中有一個成本為0,則用Μ表以求得兩個區段指 標。注意.,h表非常小。 8個區段指標(從〇至m_丨)是得自„區段映射,,。指標〇意 謂+ 8與_8之區段,共32個點。之後,用5位元拾取該等32 點的其中之一。對第6個符號而言,由於該LSE是截取之信 號位元’所以僅用4位元來選取該16點的其中之一。 又織碼是一種可改善效能之有效技術。使用交織編碼器 304時’一 4D碼可能用在如v.34之數據機。符號是一維且4 個符號可合併一 4D信號,從而應用於該4D碼。其成本是每 4D用1位元’即每符號用〇 25位元,或2 kbpS。在每4個符 號中,輸入3編碼位元及產生4位元供選取次集,則可能1 位元做為每一個符號的LSB供其在偶數點和奇數點間選 取。在此種情形中,每個映射信息框有k+27位元。在上例 中,k=15且該資料率為56.67 kbps。 因為該截取位元亦在LSB上,該LSB係在偶數點和奇數點 間選取,故須特別考慮到每個第6個符號中的截取符號位 本紙張尺度適用中國國家榡率(CNS > Μ規格(2! 〇 X 297公釐) --------裝---^----訂-----1.線 (請先閲讀背面之注意事項再填寫本頁) 經濟部中央標準局員工消費合作社印聚 455800 A7 —B7 9 五、發明説明( (請先閲讀背面之注意事項再填寫本頁) 兀如何處理該父織碼"~個可能的方法是用該編碼位元做 為該等具有气f力位元之符號的第1位元,亦即,對該等特 別符號而言’該訊號距離加倍。Viterbi解碼器將為該符號 把菽信號做各種切分。.在該情形中,資料率中有一 1333 bps的損失。 '汪意,該截取的訊號位元影響該區段内之點的選取,但 不影響該區段映射本身。所以該映射框的大小不需為6。 例如,上述的殼式映射演算法可用大小為8之同類映射 框。 用於1/6截取足信號位元的剖析器如後。界定一具有%個 符號的大型訊息框,即3個各有8個符號的映射框,或6個 各有4個符號的編碼框。在第丨個大型框中,有处個區段映 射位元,18個編碼位元’與92個未編碼位元。 .{Si,〇,i,Sit〇,2,".Si,0,k}, {Ili'〇J2i-〇5l3i>〇}>{QiA〇-IiW i.0,2,2, - · Qi,0,2,4}, {Qi.0,3,1.Qi.0,3,2, · · Qi,〇,3j4} > {IluJ2uJ3,J){Qi>1AlAl,0,2,..;Qi)li〇4}){Qiu U,2.2,".Qu,2,4},{Qi,l,3,l,Qi,l,3,2,· - .Qi,i,3,4)-.r · 經濟部中央標準局員工消費合作社印製gl = l + x + x2 + x4H g2 ^ 1 * gl = l + Z \ ^ 2 \ ^ + 2x5 + 2x6 + 2xs + 2x9 + 2XI0 + 2X12 + 2X164- .. —ΙΪ 1- -I-II =- ιν _- ^ I-li I. {Please read the note i on the back before filling this page) g4 = g2 * g2 = R .. :: g8 = g4 * g4 = K ... x: 128 .256 Ministry of Economy Although printed by the Central Standards Bureau member H Consumer Cooperative, the size of the G4 table is l + 2k; the size of the G8 table is l + 2k + 1. Although the same mapping algorithm can be used, these tables are much larger and more complex. On the other hand, a larger average distance may not be the only criterion. Another criterion is to minimize the frequency of the smallest segment. Since the error seems to occur more often in the smallest segment ', this criterion may improve the results. In order to obtain this result, the paper size is in accordance with China National Standards (CNS) A4 (210 × 297 mm) 45 58 0 0 A7 B7 V. Description of the invention (7 The printed fruits of the Consumer Cooperatives of the Central Government Bureau of the Ministry of Economic Affairs, The generating function can be: gl = l + X + X2 + X3 + x4 + X54-X41. In this case, the cost of any 8-point bundling with at least one point in the minimum section is lower than that of all kinds without any point. 8-point combination. In other words, the section is selected only after using various combinations that do not have the point. A special case is that if the minimum frequency of the minimum distance is a difficult criterion, Bayes can use a simpler The generation function is as follows: 'gl = 6 + X In this case, its cost function is a segment that must not be used. Another feasible criterion is to reduce the usage of the sub-section to obtain the generation function: gl = 5 + x + x9 here In this case, the 2 segments whose cost function is 〇, 〇〇, 〇, 〇, i9 should not be used. The table size is appropriate, and its performance is slightly better in the other embodiment described above. If you use _ Of the cost function, then the cost does not just refer to the segment. For example, if Using the final cost function, cost 0 means segment to 4 'cost i means segment 5 and cost 9 means segment 6. The segment that should be used in this case can be obtained by using the second generation function. Decision. Similar to the above shell "mapping expression" search the zs table, a ,, and "pass the total cost of 8 bluffs. D If the total cost of the child is 0, you may need to use the second generation function such as: hl = l + x + x2 + x3 + x4 h2 = hl * hl and only the minimum This rule can be borrowed and only the minimum f Please read the notes on the back before filling in this page j " binding. Order '-10- this paper Kill μ sword t ϋ n standard 210χ297 ^ 7 A7 B7 4 5 58〇 〇 --- 5. Description of the invention (8 h4 = h2 * h2 Then use the same mapping algorithm, you can get the range from 0 8 segment indicators from 4 to 4. If the total cost of the 8 symbols is not 0, then use the material table to divide the 8 'cost into two costs of 4 symbols. If one of the four symbol costs is 〇, then go to the dagger table to find the four segments of 0 to 4. Refer to the same. 'If the cost of the four symbols is not 0, then continue to use the § 2 table to cost the four symbols Two costs into two symbols. If the cost of one of the two break costs is 0, use the M table to obtain two segment indicators. Note that the h table is very small. 8 segment indicators ( From 0 to m_ 丨) is derived from the section map,. The index 0 means the section between + 8 and _8, which has a total of 32 points. After that, pick one of these 32 points with 5 bits For the sixth symbol, because the LSE is a truncated signal bit, only four bits are used to select one of the 16 points. Weaving code is an effective technique that can improve performance. When an interleaved encoder 304 is used, a 4D code may be used in a modem such as v.34. The symbol is one-dimensional and 4 symbols can be combined into a 4D signal to be applied to the 4D code. The cost is 1 bit ' per 4D, i.e. 25 bits per symbol, or 2 kbpS. In every 4 symbols, input 3 encoding bits and generate 4 bits for selecting the secondary set. It is possible that 1 bit is used as the LSB of each symbol for selection between even and odd points. In this case, each mapping information frame has k + 27 bits. In the above example, k = 15 and the data rate is 56.67 kbps. Because the truncation bit is also on the LSB, the LSB is selected between even and odd points, so special consideration must be given to the truncation symbol bit in each 6th symbol. The paper scale applies to the Chinese national rate (CNS > Μ specifications (2! 〇X 297 mm) -------- install --- ^ ---- order ----- 1. Line (please read the precautions on the back before filling this page) The Consumers' Cooperative of the Central Standards Bureau of the Ministry of Economic Affairs, Printed Together 455800 A7 —B7 9 V. Description of the Invention ((Please read the precautions on the back before filling this page) How to deal with this parent weaving code " ~ A possible way is to use this The coding bit is used as the first bit of these symbols with dynamic bits, that is, for these special symbols, 'the signal distance is doubled. The Viterbi decoder will cut the chirp signal for this symbol in various ways. Min .. In this case, there is a loss of 1333 bps in the data rate. 'Wang Yi, the intercepted signal bits affect the selection of points within the segment, but do not affect the segment mapping itself. So the mapping box The size does not need to be 6. For example, the above-mentioned shell mapping algorithm can use a similar mapping box of size 8. Use The parser for 1/6 intercepting the foot signal bits is as follows. Define a large message box with% symbols, that is, 3 mapping boxes with 8 symbols each, or 6 coding boxes with 4 symbols each. In the large frame, there are segment mapping bits, 18 coded bits' and 92 uncoded bits.. {Si, 〇, i, Sit〇, 2, " .Si, 0, k}, {Ili'〇J2i-〇5l3i > 〇} > {QiA〇-IiW i.0,2,2,-· Qi, 0,2,4}, {Qi.0,3,1.Qi .0,3,2, · Qi, 〇, 3j4} > {IluJ2uJ3, J) {Qi > 1AlAl, 0,2, ..; Qi) li〇4}) {Qiu U, 2.2, ". Qu, 2,4}, {Qi, l, 3, l, Qi, l, 3,2, ·-.Qi, i, 3,4)-. R · Printed by the Consumer Cooperatives of the Central Standards Bureau of the Ministry of Economic Affairs

Qu。,,..如 12- 本紙張尺度適用中國國家標準(CNS ) A4規格(2丨0X297公釐) 4 5 5 8 0 0 A7 ,B7 五、發明説明(1Q)Qu. ,, .. Such as 12- This paper size applies Chinese National Standard (CNS) A4 specification (2 丨 0X297mm) 4 5 5 8 0 0 A7, B7 V. Description of invention (1Q)

i,2A2»· •Qi,2,2.4}»{Qi,2,3,l>QiA3,2>Q〇,33} Ji, 2A2 »· • Qi, 2,2.4}» {Qi, 2,3, l > QiA3,2 > Q〇, 33} J

{lii,3.12^3,13;^},{Qji3i〇,i,Qi>3,〇)2,...Qi>3i〇i4}>{Qi.3,iiiJQi,3.1,2i---Qi13>lt4}3{Qi,3,2,1>Q{lii, 3.12 ^ 3,13; ^}, {Qji3i〇, i, Qi > 3, 〇) 2, ... Qi > 3i〇i4} > {Qi.3, iiiJQi, 3.1,2i --- Qi13 > lt4} 3 {Qi, 3,2,1 > Q

{Si,2,l,S 似,".3以}, I {II i,4,12^4,13^4), {Qi(4(〇>bQi,4,0,2>'--Qi,4,0,4},{Qu.l.wQiAl,2j---Qi,4,I.3}^Qi.4.2,l»Q ! i,4,2,2,…Qi,4,2,4),{Qi,4,3,i,QiA3,2,…Qi,4,3,4)。 {I li,5,Kj^JSi sJ^Qj^hQi,5,〇.2>'**Qi,5,0,4}>{Qi,5,U>Qi.5,l,2)· i,5,2,2,…Qi,5,2,4 },{ Qi.SAwQiMAQiWj} 0 l/6截取信號位元的資料率為(k*KB6,67)。各種M值的資料 率列示於下表。 (請先閲读背面之注意事項再填馬衣育」 裝 Μ m 距離 k 資料率(kbps) 完全截取的資料率 224 7 2 22 58.67 52 192 6 4 20 56.67 50 160 5 6 18 54.67 48 128 4 16 16 52.67 46 96 3 32 12 48.67 42 64 2 64 8 44.67 38 32 1 128 0 36.67 30 今 經濟部中央標準局負工消费合作社印製 表1 .資料率與Μ值 在冗全截取的資料率ι情形中’該剖析器較為簡單。其 週期為_ 一映射框。 {SuA2,...Si,k} >{Si, 2, l, S, " .3 to}, I {II i, 4,12 ^ 4,13 ^ 4), {Qi (4 (〇 > bQi, 4,0,2 > ' --Qi, 4,0,4}, {Qu.l.wQiAl, 2j --- Qi, 4, I.3} ^ Qi.4.2, l »Q! I, 4,2,2, ... Qi, 4,2,4), {Qi, 4,3, i, QiA3,2, ... Qi, 4,3,4). {I li, 5, Kj ^ JSi sJ ^ Qj ^ hQi, 5, 〇.2 > '** Qi, 5,0,4} > {Qi, 5, U > Qi.5, l, 2) · i, 5,2,2, ... Qi, 5,2,4}, {Qi.SAwQiMAQiWj} 0 l / 6 The data rate of the intercepted signal bits is (k * KB6,67). The data rates for various M values are shown in the table below. (Please read the precautions on the back first and then fill in the horse clothing training. ”Load Μ m Distance k Data rate (kbps) Fully intercepted data rate 224 7 2 22 58.67 52 192 6 4 20 56.67 50 160 5 6 18 54.67 48 128 4 16 16 52.67 46 96 3 32 12 48.67 42 64 2 64 8 44.67 38 32 1 128 0 36.67 30 Today, the Central Standards Bureau, Ministry of Economic Affairs, Consumers Cooperatives printed the table 1. The data rate and the value of M are redundantly intercepted data rate In this case, the profiler is relatively simple. Its period is _ a mapping box. {SuA2, ... Si, k} >

川 i,〇’I2 丨,。A,。}, {Q;,。,。山 QiA〇>2,Qw W川 i, 〇'I2 丨,. A ,. }, {Q;,. . Mountain QiA〇 > 2, Qw W

Ql〇,2,3 },{Qi.oAhQi.mQm]}, , 〇;;Q;>1〇3},{Qi,1,1,1,Qi,1,1,2sQi(11 3}s{Q; j 2 lsQ, : ^ -13- 本紙張尺度適用中國國家標準(CNS ) A4規格(210x297公釐) '--------- 4 5 58 0 0 A7 —B7 五、發明説明( 11, 經濟部中央標準局J工消費合作社印製 每-個有8個符號的映射框中,有k個區段映射位元,6 個編碼位元,與24個未編碼位元。該資料率為(㈣)柳厂 各種Μ值的資.料率列示於上表。 自忒表中可知支援一 56k鮑率之資料率,僅需I”點, 其最小距離為4。因此,達到合宜效能則約需一40 dB之 SNR。如考慮該區段映射增益和編碼增益,則聊之遞 即已足1符合此需求並不太困難。如果該迴路不支援此 需求’則將Μ減到160。之後,用如扣、 心攸用3〇 dB·^ SNR即可運作一 54.67 kbps的資料率。’ :自該表中,亦可知如果也減!,則让通常會減2 ,且龙资 料率減2kbpSDmW可提供—6犯之噪音容限。因此,以功 減1代替使用編碼’以獲得一具較佳噪音容限的類似 率,並使編碼器401較容易達成工作,如圖4所示。下表 示未編碼時的資料率。 所需之SNR 46 40 34 28 22 16 10 表2 ·未編碼情形之資料率 命注意的是該慣用的回旋狀碼是無效牵 —---------------------------------〜斗'的,其原因部分 是由於信號的分佈不均勻。在外部區段中’,、μ二 刀 丁,孩等信號因分 隔太達而不需要編碼*僅最小區段才有需要 — • 14- —有效之步 Μ m 距離 k 資料率(kbps) 224 7 2 22 60.67 192 6 4 20 58.67 160 5 8 18 56.67 128 4 16 16 54.67 96 3 32 12 50.67 64 2 64 8 46.67 32 1 128 0 38.67 本紙張尺度適用中國國家標準(CNS ) Α4規格(210X297公瘦) (請先閲讀背面之注$項再填寫本頁) 訂 455800Ql〇, 2,3}, {Qi.oAhQi.mQm]},, 〇 ;; Q; > 1〇3}, {Qi, 1,1,1, Qi, 1,1,2sQi (11 3) s {Q; j 2 lsQ,: ^ -13- This paper size applies Chinese National Standard (CNS) A4 (210x297 mm) '--------- 4 5 58 0 0 A7 —B7 V. Description of the Invention (11, printed by J Industrial Consumer Cooperative of the Central Standards Bureau of the Ministry of Economic Affairs, each 8-symbol mapping box has k sector mapping bits, 6 coding bits, and 24 uncoding bits The data rate is listed in the table above. The data rate is listed in the table above. From the table, it can be seen that the data rate supporting a 56k baud rate requires only I ”points, and its minimum distance is 4. Therefore To achieve proper performance, an SNR of about 40 dB is required. If the mapping gain and coding gain of the segment are considered, it is not difficult to meet this requirement. If the circuit does not support this requirement, then it will Μ is reduced to 160. After that, a data rate of 54.67 kbps can be operated with a 30dB · ^ SNR using a button, for example. ': From this table, it is also known that if it is also reduced !, it is usually reduced by 2 And the data rate of the dragon minus 2kbpSDmW can provide -6 noise margin. Because Therefore, use power minus 1 instead of using coding to obtain a similar rate with better noise tolerance, and make the encoder 401 easier to achieve the work, as shown in Figure 4. The data rate when not coding is shown below. SNR 46 40 34 28 22 16 10 Table 2 · The data of the uncoded case must be noted that the conventional convolutional code is invalid —------------------ --------------- ~ dou ', the reason is partly due to the uneven distribution of the signal. In the external section, the signals such as μ, μ, etc., are separated due to too much separation. No coding is required * Only the smallest segment is required — • 14- — Effective steps M m Distance k Data rate (kbps) 224 7 2 22 60.67 192 6 4 20 58.67 160 5 8 18 56.67 128 4 16 16 54.67 96 3 32 12 50.67 64 2 64 8 46.67 32 1 128 0 38.67 This paper size applies to China National Standard (CNS) Α4 size (210X297 male thin) (Please read the note on the back before filling this page) Order 455800

A7 SI 五、發明説明( 12、 騾即僅須在最小區段中加入冗餘。 混合變歷:器在DC時有頻譜失效現象,但該隨機資料信號 有一自0至4 kHz之平頻譜。故該傳輸信號不應有dc且组件 的頻率須極低。 為消瞭上述之DC组件’已編碼與未編碼之編碼器, 601的另一種具體實施例示於圖5與圖6,包括形成頻譜之 DC抑制器(頻譜形成器)503。每4個符號的前3個符號如常 產生。所有以前送出之信號的運行總和仍然保持不變。如 果該運行總和為負值’則該第4個符號為正值:反之亦 然。如此.,該DC信號及極低頻之組件即受到抑制。總之, 對隨機輸入資料而言,第4個符號為正值或負值的機率是 相同的。 依此設計’該資料率表改成如下。 (請先閲讀背面之注項再填寫本頁) "裝. 訂 經濟部中央標準局員工消費合作社印製 Μ n 1 距離 k 資料率(未編碼) 224 7 2 22 58.67 192 6 4 20 56.67 160 5 8 18 54.6.7—— · 128 4 16 16 52.67 〆 96 3 32 12 48.67 64 2 64 8 44.67 32 1 128 0 36.67 表3 • 具DC抑制器的資料率 注意’ 56 kbps仍是可能的 -15- 56.67 54.67 52.67 50.67 46.67 42.67 34.67 本紙張尺度適财關緖準(CNS ) A4規格(210;297公釐)— 455800 A7 --- -Μ_____ 五、發明説明(13) 當保持相同之最小距離時,Μ可能增加16。尤其,其他 每個點均可用於該最小區段^例如,第2區段可用16個 點’同時第3區段至第8區段用IN點,並保持最小距離4 β 為使用該映射演算法,每一组的點數應一致。因此,將Μ 個的總數點分成m = 組’亦即將一正常區段分成2組, 且僅有一半點數的最小區段為1組。則rn的範園為1至15。 ‘ 我們用4位元自各组中選取一個點。經使用更多的點,資 料率即可能增加1或2 kbps "在該映射演算法中,奇數m的 產生函數可為: gi=(m-3.)+3x; hl=l+x+x2+ · · +xm"4; 或 gi=(m-5)+2x+3X9; hl=l+x+x2+...+xm'6; 相關效能的資料率表如下: (請先閲讀背面之注意事項再填寫本頁} 經濟部中央榡準局員工消費合作社印裝 M m 距離 k 資料率(未编碼) 資料率(已编碼) 240 15 2 31 59.67. 57.67 224 14 2 30 58.67 56.67 · 208 13 4 29 57.67 55.67 192 12 4 28 56.67 — 54.67 176 11 8 27 55.67 53.67 160 10 8 26 54.67 52.67 144 9 16 25 53.67 51.67 128 8 16 24 52.67 50.67 112 7 32 22 50.67 . 48.67 -16- 本紙張尺度適用中國國家標準(CNS } A4規格(210X297公釐) 455800 A7 £7 表4 .使用減少點數的資料率 再參考圖2,該64kb/s數位信號通過數位網路203,之後 經過//定律D/A轉換器205轉換成類比信號。該類比信號通 過該類比.區域迴路抵達56k數據機接收器201。 經濟部中央標準局員工消費合作社印策 五、發明説明(14) 96 6 32 20 48.67 46.67 80 5 64 18 46.67 44.67 64 4 64 16 44.67 42.67 48 3 128 12 40.67 38.67 32 2 128 8 36.67 34,67 16 1 256 0 28.67 26.67 (請先閲讀背面之注意事項再填寫本頁) 參考圖7’其中顯示半雙工的56k類比數據機接收器 701。來自該區域迴路的類比信號由—線性A/D轉換器轉換 成數位。由於妥善控制該輸入類比信號位準及抽樣計時器 並不容易,所以在該位置上尚未完成一从定律d/a。取而 代之的是在抽掉DC、AGC、内插器與等化器後,使用—線 性A/D轉換器以及將〆定律入該線性轉換器。在該區域之 申心處’該等化器之輸出應與該以定律D/a輸出的線性定 量信號相匹配。該等化言輸出由#定律轉換成線性轉換以 獲得該網路所送出的數位信號。在該解碼器(為已編碼版 本之Viterbi解碼器,及未編碼版本之簡易切割器)將該已接 收Ί5號丁以解碼後,該區段映射解碼器即行運作以便獲得 該等k個映射位元。該截取的信號位元和頻譜形成位元即 被除去,而該解散器(descrambler)即運作以獲得使用者的資 料。 -17- 本紙張尺度適用中國國家標準(CNS > A4規格(210X297公釐) 4 5 5 8 0 0 Α7 ------^___ 五、發明説明(15) 涊等化器以一 8k之抽樣率運作,因此對一 4〇個符號的跨 距而言,約需96個分接頭。由於僅有—個區域迴路需等 化,所以該跨距可減小。但因信號頻譜較寬且頻道在Dc;時 失效以及在接近4 kHz有衰減,故可能需要相對較長的跨 距。 .為避免該線性等化器增強噪音,可採用決策回饋等化 * ' 器,尤其是當未使用編碼時,因而解碼延遲亦未消除。圖 8示該決策回饋等化器。 多考圖9 ’其中顯示全雙工的56k數據機801。前述56k傳 輸足方向.僅為自數位至類比。另—方向時則需一較小的基 本操作。 經濟部中央樣隼局負工消費合作社印製 (請先閲讀背面之注意事碩再填寫本頁) 注意,因為沒有近回音,所以僅需要—遠回音消除器。 如果使用頻譜,則對該回音消除器的輸入為不具有一個平 頻譜的已傳輸的信號。如此可能影響初始的輻合速度。該 运回音消除器的輸入和輸入抽.樣率皆為8k。因為該已傳輸 的信號僅在8位元時為真,所以我們可在該遠回音的總延 遲線的兩個樣本用一個字。故一個來回的遲延如為1.2秒 時,則延遲線需要4.8個字》—個與3429鮑率V.34遠處回音 消除器類似的時間跨距可能需要96個分接頭。注意,該輸 入延遲線亦需96個字。 在該回音消除後進行自動增益控制(AGO)和解調。在該 内插器之前使用一個丨:2的抽樣器以増加抽樣率至16 kHz。 一個基頻第3 sine内插器可同時用於16k至3χ的轉換器及該 時間回復之上。在該内插器之後的裝置與操作方法均屬傳 -18 - 本紙浪尺度適用中國國家標羋(CNS ) Μ規格(210x297公釐) 經濟部中央榡準局貝工消費合作社印裝 455800 A7 _B7_ 五、發明説明(16) 統性質。 - 此架構的缺點之一是在一8 kHz抽樣率上完成解調。此舉 使得用於該解調的正弦/餘弦表非常長。為避免此問題, 圖10顯示另一具體實施例。 在AGC後用一 1 : 3的上抽樣器以增加該抽樣率至24k。其 後再用一個3x之解調器進行通頻抽樣率轉換和時序回復, , 如此所需要的正弦/餘弦表較短。 、 參考顯示雙工數據機1101之圖11。注意,由於該已接收 的56k訊號係用抽樣時序8 kHz,且其頻譜高達4 kHz,則該 I. 向下抽樣器的輸出率應為2 8 kHz。除2400鮑率時應用4x 夕卜,3x率是可接受的。但在2400鮑率時,每一個次消除器 可用較少的分接頭。例如,在其他各鲍率時每一個次消除 器可使用40個分接頭,2400鮑率時僅用30個分接頭,所以 分接頭的總數仍為120。 在該回音消除及AGC後,使用一個上抽樣器以便得到 mnx抽樣率。因為該抽樣已接收的8k信號有一較基頻3x V.34信號寬之-4 kHz至4 kHz的頻譜,所以需要該上抽樣 器。對第3 sine内插器而言,m = 3似乎是適當的。一基頻第 三序sine内插器可同時用於該mnx至8k轉換及該時序回復兩 者。 再參考上述圖1、2,56k數據機101,102所用的符號率是8 kHz。該編碼器取該已拌合的輸入二進位資料以便產生輸 出數位符號。該等符號經由數位網路送至另一側的#定律 D/A,並轉換成類比訊號。 -19- 本紙張尺度適用中国國家標準(CNS ) A4規格(210X297公釐) (請先閲讀背面之注意事項再填寫本頁)A7 SI V. Description of the invention (12. 骡 Only need to add redundancy in the smallest section. Hybrid calendar: the device has a spectrum failure phenomenon at DC, but the random data signal has a flat spectrum from 0 to 4 kHz. Therefore, the transmission signal should not have dc and the frequency of the component must be extremely low. In order to eliminate the above-mentioned DC component 'encoded and unencoded encoders, another specific embodiment of 601 is shown in Fig. 5 and Fig. 6, including forming a frequency spectrum DC suppressor (spectrum shaper) 503. The first 3 symbols of every 4 symbols are generated as usual. The running sum of all previously sent signals remains unchanged. If the running sum is negative, then the 4th symbol Positive values: vice versa. In this way, the DC signal and extremely low frequency components are suppressed. In short, for random input data, the probability of the fourth symbol being positive or negative is the same. Design 'the data rate table is changed as follows. (Please read the note on the back before filling this page) " booking. Order printed by the Ministry of Economic Affairs Central Standard Bureau employee consumer cooperative Μ n 1 distance k data rate (uncoded) 224 7 2 22 58.67 192 6 4 20 56.67 160 5 8 18 54.6.7-· 128 4 16 16 52.67 〆 96 3 32 12 48.67 64 2 64 8 44.67 32 1 128 0 36.67 Table 3 • Data rate with DC suppressor Note that '56 kbps is still possible- 15- 56.67 54.67 52.67 50.67 46.67 42.67 34.67 The size of this paper is suitable for financial standards (CNS) A4 specifications (210; 297 mm) — 455800 A7 --- -M _____ 5. Description of the invention (13) When keeping the same minimum distance M may increase by 16. In particular, every other point can be used for the smallest segment ^ For example, 16 points can be used for the second segment 'while IN points are used for the third to eighth segments and the minimum distance is maintained 4 β In order to use this mapping algorithm, the number of points in each group should be the same. Therefore, divide the total number of M points into m = groups, that is, divide a normal section into 2 groups, and the smallest section with only half points Is 1 group. Then the range of rn is from 1 to 15. 'We use 4 bits to select a point from each group. By using more points, the data rate may increase by 1 or 2 kbps " In the method, the generation function of the odd number m can be: gi = (m-3.) + 3x; hl = l + x + x2 + · · + xm "4; or gi = (m-5) + 2x + 3X9; hl = l + x + x2 + ... + xm'6; The performance rate table is as follows: (Please read the precautions on the back before filling this page} Load M m Distance k Data rate (uncoded) Data rate (coded) 240 15 2 31 59.67. 57.67 224 14 2 30 58.67 56.67 · 208 13 4 29 57.67 55.67 192 12 4 28 56.67 — 54.67 176 11 8 27 55.67 53.67 160 10 8 26 54.67 52.67 144 9 16 25 53.67 51.67 128 8 16 24 52.67 50.67 112 7 32 22 50.67. 48.67 -16- This paper size applies to the Chinese national standard (CNS) A4 size (210X297 mm) 455 800 A7 £ 7 Table 4. Using the data rate of reduced points and referring to FIG. 2 again, the 64 kb / s digital signal passes through the digital network 203, and then is converted into an analog signal by the // law D / A converter 205. The analog signal passes through the analog. Area loop to the 56k modem receiver 201. Printed by the Consumer Standards Cooperative of the Central Standards Bureau of the Ministry of Economic Affairs V. Invention Description (14) 96 6 32 20 48.67 46.67 80 5 64 18 46.67 44.67 64 4 64 16 44.67 42.67 48 3 128 12 40.67 38.67 32 2 128 8 36.67 34,67 16 1 256 0 28.67 26.67 (Please read the notes on the back before filling out this page) Refer to Figure 7 'which shows a half-duplex 56k analog modem receiver 701. The analog signal from the loop in this area is converted to digital by a linear A / D converter. Since it is not easy to properly control the input analog signal level and the sampling timer, a slave law d / a has not been completed at this position. Instead, after the DC, AGC, interpolator, and equalizer are removed, a linear A / D converter is used and the law of martingale is incorporated into the linear converter. At the center of the area, the output of these equalizers should match the linear quantified signal output with the law D / a. The verbalization output is converted from # law to linear conversion to obtain the digital signal sent by the network. After the decoder (the coded version of the Viterbi decoder and the uncoded version of the simple cutter) decodes the received No. 5 D, the segment mapping decoder operates immediately to obtain the k mapping bits. yuan. The intercepted signal bits and spectrum forming bits are removed, and the descrambler operates to obtain user data. -17- This paper size applies to Chinese national standards (CNS > A4 size (210X297 mm) 4 5 5 8 0 0 Α7 ------ ^ ___ V. Description of the invention (15) 涊 Equalizer to 8k The sampling rate works, so for a span of 40 symbols, about 96 taps are needed. Since there is only one regional loop to be equalized, the span can be reduced. However, because the signal spectrum is wider And the channel fails at Dc; and there is attenuation at near 4 kHz, so a relatively long span may be required. To avoid this linear equalizer to enhance noise, a decision feedback equalizer can be used, especially when the When encoding is used, the decoding delay is not eliminated. Figure 8 shows the decision feedback equalizer. Consider Figure 9 'which shows a full-duplex 56k modem 801. The aforementioned 56k transmission foot direction is only from digital to analog. In the other direction, a small basic operation is required. Printed by the Consumers Cooperative of the Central Sample Bureau of the Ministry of Economic Affairs (please read the note on the back before filling out this page) Note that because there is no recent response, you only need— Far Echo Canceller. Cancels this echo if spectrum is used The input of the amplifier is a transmitted signal that does not have a flat spectrum. This may affect the initial convergence speed. The input and input decimation of the echo canceller are both 8k. Because the transmitted signal is only at 8 The bit time is true, so we can use one word for the two samples of the total delay line of the far echo. Therefore, if a round-trip delay is 1.2 seconds, the delay line requires 4.8 words. A similar time span of the V.34 distant echo canceller may require 96 taps. Note that the input delay line also requires 96 words. Automatic gain control (AGO) and demodulation are performed after the echo cancellation. Inside this Before the interpolator, a sampler of 2 is used to increase the sampling rate to 16 kHz. A fundamental frequency 3 sine interpolator can be used for 16k to 3χ converters and the time response at the same time. On the interpolator The subsequent devices and operating methods are -18. This paper wave scale is applicable to the Chinese National Standard (CNS) M specifications (210x297 mm). Printed by the Bayer Consumer Cooperative of the Central Bureau of Standards of the Ministry of Economy. 455800 A7 _B7_ V. Description of the invention ( 16) systemic nature-this One of the disadvantages of the architecture is that demodulation is performed at an 8 kHz sampling rate. This makes the sine / cosine table used for this demodulation very long. To avoid this problem, Figure 10 shows another specific embodiment. After AGC A 1: 3 upsampler is used to increase the sampling rate to 24k. Then a 3x demodulator is used to perform the pass sampling rate conversion and timing recovery, so the sine / cosine table required is shorter. Refer to Figure 11 showing the duplex modem 1101. Note that since the received 56k signal has a sampling timing of 8 kHz and its spectrum is as high as 4 kHz, the output rate of the I. downsampler should be 2 8 kHz . Except for 2400 baud rate, 4x rate is used, 3x rate is acceptable. However, at 2400 baud, fewer taps can be used per eliminator. For example, in the other baud rates, each time the eliminator can use 40 taps, and in the 2400 baud rate, only 30 taps are used, so the total number of taps is still 120. After the echo cancellation and AGC, an up-sampler is used to obtain the mnx sampling rate. The up-sampler is needed because the 8k signal received for this sample has a spectrum that is -4 kHz to 4 kHz wider than the baseband 3x V.34 signal. For the 3rd sine interpolator, m = 3 seems appropriate. A fundamental third sequence sine interpolator can be used for both the mnx to 8k conversion and the timing response. Referring again to Figures 1, 2, and 56k, the symbol rates used by the modems 101, 102 are 8 kHz. The encoder takes the mixed input binary data to generate the output digital symbols. These symbols are sent to the #Law D / A on the other side via a digital network and converted into analog signals. -19- This paper size applies to Chinese National Standard (CNS) A4 (210X297 mm) (Please read the precautions on the back before filling this page)

455800 A7 B7 五、發明説明(17) 該β定律D/A使用劃分成16區段:+1+2,^而 總數為255的可能信號位準。第丨區段中相鄰兩點間的距離 為〇*2丨’丨。為簡便起見,設c=i。 區段+ 1及-1有最小距離1,而〇點則由兩區段共用。進 而言之’許多編碼/解碼器在此等小點上的效能較差。因 此’我們經常剔除此兩區段,而使用剩餘的224點。然而 ' 仍然可使用此等小點,此將於稍後討論。我們也能剔除更 多的小點,以便增加該最小距離。每剔除32點,則最小距 離加倍,因此得到6dB_的噪音容限。在修正期間,該5处接 收器測量.該頻道的情沉,如SNR和編碼/解碼器的特性,決 定應使用多少個點,以及通知遠距傳輸器。 因為該等點數不是2冪’為使該資料率成為極大,我們 可用該信息框映射技術,其例子是V 34所用的殼式映射算 式。 在V.34數據機中,該殼式映射算式將二進位資料映射到 一維QAM信號點。在56k數據機中,所有訊號點皆是_維。 我們可將所有想要使用的點分成m组。在私定律編碼/解碼 器中’遠寺一維之點可分成16個區段。假設我們使用該等 經濟部中央標準局員工消費合作社印製 (請先閲讀背面之注意事項再填寫本頁) 16個區段中的2«1個:±(9-111),...±7,±8,111=1,2,.‘.7。一種自然 劃分這些點的方式是將+ i及-1區段分成一具有群组指標 之群組。即,外部區段有較小的群組指標.在我們可用的 所有點中’因.為外部點有較大的距離,所以我們較常用 之。此與該V.34殼式映射相反,在殼式映射中,我們常用 小點以便將該平均功率化為極小而獲得若干形態增益。為 -20- 本纸張尺度適用中國國家榇準(CNS ) A4規格(2丨0X297公釐) 455800 A7 五、發明説明(18)^ " ~~ - 達成該目標,此_ 此時可於V.34採用殼式映射演算法,但必須 修改其成本函數。 (請先閲讀背面之注意事項再填寫本頁) 56k數據機的映射設計詳述於後。 在V.34中’我們將該等環從最小能量至最大能量依序排 歹a! ’ t將該環指標做為成本函數。此時,我們將該等環指 “自最大此I至最小能量依序排列。假如們能使用μ點, ’且在:個Ν符號的信息框送出κ位元,則該資料率是麵 謂么几/秒^琢等乂點分成具有指標^‘㈣等之^以加 组。汪意,表示每符號位元數的Κ/Ν不一定是整數,甚至κ 亦然。一種類似V. 34信息框的轉換設計可用於非整數艮的 情況。為簡便計,我們可假設艮為一整數。我們需要5點 以便於琢组中選取—點,因此我們用k = K_5N位元進行該” 群組映射,,,類似V.34的殼式映射。k的最大可能值可自下 列不等式得出:455800 A7 B7 V. Description of the invention (17) The β-law D / A uses 16 signal segments divided into + 1 + 2, ^ and a total of 255 possible signal levels. The distance between two adjacent points in the first section is 0 * 2 丨 ’丨. For simplicity, let c = i. Zones +1 and -1 have a minimum distance of 1, and 0 is shared by both zones. Furthermore, many encoders / decoders perform poorly at these small points. So 'we often cull these two segments and use the remaining 224 points. However, these small points are still available and will be discussed later. We can also eliminate more small points in order to increase the minimum distance. For every 32 points removed, the minimum distance is doubled, so a noise margin of 6dB_ is obtained. During the correction, the five receivers measure the affection of the channel, such as the SNR and encoder / decoder characteristics, decide how many points should be used, and notify the remote transmitter. Because these points are not powers of two, to make the data rate extremely large, we can use this information frame mapping technique, an example of which is the shell-type mapping formula used in V 34. In a V.34 modem, this shell mapping algorithm maps binary data to one-dimensional QAM signal points. In a 56k modem, all signal points are _dimensional. We can group all the points we want to use into m groups. In the private law encoder / decoder, the one-dimensional point of the distant temple can be divided into 16 sections. Assume that we use these consumer co-operatives printed by the Central Bureau of Standards of the Ministry of Economic Affairs (please read the notes on the back before filling this page) 2 «1 of the 16 sections: ± (9-111), ... 7, ± 8, 111 = 1,2,. '. 7. A natural way to divide these points is to divide the + i and -1 sections into a group with a group index. That is, the outer segment has a smaller group index. Of all the points we have available, it is more commonly used because it has a larger distance from the outer point. This is in contrast to the V.34 shell mapping. In the shell mapping, we often use small dots in order to minimize the average power to obtain several morphological gains. -20- This paper size is applicable to China National Standards (CNS) A4 specifications (2 丨 0X297 mm) 455800 A7 V. Description of the invention (18) ^ " ~~-To achieve this goal, this _ is available at V.34 uses a shell mapping algorithm, but its cost function must be modified. (Please read the notes on the back before filling out this page) The mapping design of the 56k modem is detailed later. In V.34, 'we rank the loops in order from minimum energy to maximum energy 歹 a!' T as a cost function. At this time, we refer to these ring fingers as "sequentially from the largest to the smallest energy. If we can use μ points, 'and send out k-bits in the information frame of N symbols, then the data rate is face to face. The number of points per second is divided into groups with indexes ^ '㈣ and the like to add groups. Wang Yi, K / N representing the number of bits per symbol is not necessarily an integer, even κ. A similar V. 34 The design of the transformation of the information box can be used in the case of non-integer Gen. For simplicity, we can assume that Gen is an integer. We need 5 points in order to select-points in the group, so we use k = K_5N bits for this group. Group mapping,, similar to V.34 shell mapping. The maximum possible value of k can be obtained from the following inequality:

2kSmN 例如,如果我們用192點,且該映射框的大小是8 ’則 m=6 ’且k έ 20.68。假設我們用k = 2〇,則我們將送出每符 號 7.5位 7G,而其資料率將為(k+5N)*8〇〇〇/N=6〇〇kbps。 經濟部中央標準局貞工消費合作社印策 類似V.34的殼式映射,我們不需要用k的最大可能值。 換言之,同一個k時,我們不需要用m的最小可能值。在 V.34例子中,如果我們使用一較大的M,則得到若干形態 增益。於此,對較大的m而言,我們必須使用若干較小的 點’從而減少該極小距離。但因為該等最小點是極重要的 點’所以通常不採用一個較大的m。 -21 - 1本紙張尺度適用中國國家楼準(CNS M4規格(2I0X297公楚) 455800 A7 B7 19、 五、發明説明( 如果假設N = 8,則該區段映射演算法可類似於該叉“的 殼式映射演算法。關鍵是在選取一個合適的成本函數以便 請 閱 讀 背 & 之 注 意 事 項 再 填」 窝 本 頁 使性能達到最適宜的程度,而同時能維持該記憶體與複雜 性於較低的程度。 在V.34所用的殼式映射演算法中,所選的成本函數為斜 坡函數(ramp function),亦即,該成本等於該環指標。此成 本函數可用一產生函數表示之: gl = l+X+x2+x3+X4+x5 + ...xn'-I „ 訂 經濟部中夬標準局員工消費合作社印裝 因為在一環中的平均功率約與該環指數成正比,所以這 是一個可.將該平均功率減至最小程度的最佳成本函數。如 果我們在此使用相同的成本函數,則我們將獲得比内部群 組更多的外部群组,但是效能則不是最佳,例如,為簡便 計’我們設N = 2,且m = 7,第丨組的成本為I,i=〇;1,…6。 則在第0组使用一個符號,在第6組用另一個符號時,將產 生一個比在第4组中用兩個符號時的總成本(4+4=8)更低的 總成本(0+6=6)。由於前者不用最小之點,且該等最小之點 易於發生錯誤’故前者較常使用。該斜坡成本函數可將該 等平均群组指標減至最小,但不能將錯誤率減至最小,因 為不同群組的錯誤機率極為不同。總錯誤機率P為 P = P〇f〇+P!fl+...+Pm.1fm.l 其中’ Pi為第i组點的錯誤機率,fi為第i組的相對發生頻 率(機率)’ i=0,ls..,m-l。因為 ρ;(ΐ=ί),1,...πι-2)比 Pm_i為小,所 以該總錯誤機率約等於l -此處一個較佳的準則是將 該最小组之頻率減至最小。使用下列成本函數可達成此 -22- 本紙張尺度適用中國國家榡準(CNS ) Α4規格(2ΙΟχ:297公瘦) 4 5 5 80 0 A7 B7 五 發明説明( 20、 項工作: (0,l,2,‘..,m-2,8(m-2)+l) m = 7的產生函數為: ί請先閲讀背面之注意事碩再填寫本頁〕 gl = l+X+X2+X3+X4+x5+x41。 在此例中,任一在其最小群組中至少 /胥—點的八2kSmN For example, if we use 192 points and the size of the mapping box is 8 ′ then m = 6 ’and k 20.68. Suppose we use k = 2〇, we will send 7.5 bits 7G per symbol, and its data rate will be (k + 5N) * 800 / N = 600kbps. The policy of Zhengong Consumer Cooperative of the Central Standards Bureau of the Ministry of Economic Affairs is similar to the shell mapping of V.34. We do not need to use the maximum possible value of k. In other words, we do not need to use the smallest possible value of m for the same k. In the V.34 example, if we use a larger M, we get several morphological gains. Here, for larger m, we must use several smaller points' to reduce the minimum distance. However, since these minimum points are extremely important points', a larger m is generally not used. -21-1 This paper size is applicable to China National Building Standard (CNS M4 specification (2I0X297)) 455800 A7 B7 19. V. Description of the invention (If N = 8 is assumed, the segment mapping algorithm can be similar to the fork " The key is to choose a suitable cost function so that you can read the “Notes” and fill it in again. ”This page allows the performance to reach the optimal level, while maintaining the memory and complexity. Lower degree. In the shell mapping algorithm used in V.34, the selected cost function is a ramp function, that is, the cost is equal to the ring index. This cost function can be expressed by a production function : Gl = l + X + x2 + x3 + X4 + x5 + ... xn'-I „Ordered by the Consumer Affairs Cooperative of the Standards Bureau of the Ministry of Economic Affairs, because the average power in a ring is approximately proportional to the index of the ring, So this is the best cost function that can minimize the average power. If we use the same cost function here, we will get more external groups than internal groups, but the performance is not the most good, For example, for the sake of simplicity, we set N = 2 and m = 7, and the cost of group 丨 is I, i = 0; 1, ... 6. Then use one symbol in group 0 and another in group 6 Sign, it will produce a lower total cost (0 + 6 = 6) than the total cost (4 + 4 = 8) when two symbols are used in group 4. Since the former does not use the smallest point, and The smallest point is prone to errors, so the former is used more often. The slope cost function can minimize the average group index, but it cannot minimize the error rate, because the error probability of different groups is very different. Total error The probability P is P = P〇f〇 + P! Fl + ... + Pm.1fm.l where 'Pi is the probability of error of the i-th group point and fi is the relative frequency (probability) of the i-th group i = 0 , Ls .., ml. Because ρ; (ΐ = ί), 1, ... π-2) is smaller than Pm_i, the total error probability is approximately equal to l-a better criterion here is to set the most The frequency of the group is minimized. This can be achieved by using the following cost function-22- This paper size applies to the Chinese National Standard (CNS) A4 specification (2ΙΟχ: 297 male thin) 4 5 5 80 0 A7 B7 Five invention descriptions (2 Item 0: (0, l, 2, '.., m-2,8 (m-2) + l) The generation function of m = 7 is: ί Please read the notes on the back before filling in this page ] Gl = l + X + X2 + X3 + X4 + x5 + x41. In this example, any one in its smallest group is at least / 胥 —point eight

的成本比所有無任何點的八點組的成, S ^问°因此,#田 此成本函數時八元組的順序如下。 文用 (〇SG),(lSG),(2SG),...(8SG)(犯:最小群組) 因為2k通常小於mN,.所以我們通常不m 金鄙的八 .組合,我.們可用較小的群組剔除之以便 、且的 錯誤率。 ^ H彳之而减少 孩成本函數的缺點是該產生函數排序太高,其 的表格和較高的複雜性。為避免此等問題’建議== 一種二步映射演算法。使用此種新算法時, ^ 複雜性類似基於斜坡成本函數的映射演算法,然卻能達成 相同的效果,如以上所述者。 經濟部中央標準局貝工消費合作社印裝 因為該等最小之點的最小频率是唯則,故我們可 用一極簡單的產生函數表示之: gi=(m-l)+x 在此例+,該成本函數為〇,〇A…,M,除該最小群组 外,我們可不必顧慮使用那—個群組。 使用此成本函數,則其成本不D θu p ,t &令+ /、疋该群的指標而已。例 如成本0意謂第0至m-ι組,成本t意謂有最小距離之第 1組。問題出在成本0 ’我們如何能說使用那—個組。為解 -23“ 本紙張尺度_中國iii準(CNS) Α4·_ (―210^^· 4 5 5 80 0 Α7 Β7 五、發明説明(21) 決此問題’我們可用一次級產生函數: g'l = l+X+X2 + ...+xm-2 g,2=g,l*g'l g,4=g’2*g’2〜Z,4 g'8=g'4*g’4—Z,8 相似於該V.34的殼式映射演算法’我們首先經由目前長 , 度僅為8之第一個表搜尋以便找出該8個符號的總成本。 如果該總成本是〇,則轉至該次級產生函數,經由Z,8表搜 尋,並以相同於處理V.34殼式映射的方法進行其他映射以 便根據該.次級產生函數獲得從〇至m-2的8個群组指標。 經濟部中央標準局貝工消費合作社印製 (請先聞讀背面之注意事項再填寫本頁) 如果該8個符號之總成本不是〇,則繼績使用表以分割 該8個符號之成本成為2個4個符號的成本。如果4個符號 的成本之一是0,則轉至該次級產生函數,使用其餘以便 經由ZU(或簡單使用表)搜尋出該次級的4個符號的成 本’而於最後找出從〇至m-2的· 4個群組指標。同樣地,如 果該4個符號的成本之一是〇,則轉至該次級產生函數以便 計算該次級的兩個符號的成本,最後計算出從0至m-2的兩 個群指標。注意,第一组及第二組之表皆是小的^該表的 大小約與V.34型之斜坡成本函數之表相同β其複雜性亦類 似。 我們従群組映射得到8個群组指標(自0至m-1)。指標i意 謂實質的區段+(8-i)及-(δ-i),共有32個點°之後使用5個位 元拾取32個點中之一個點。 該資料率是(k+40)kbps。各種Μ的資料率列示如下表。 -24- 本紙張尺度通用中國國家榇隼(CNS > Α4規格(210Χ297公釐〉 4 Μ濟部中央標準局貝工消費合作社印製 5 5 80 0 A7 -—____£7 五、發明説明(22) M m 最小距離 k 資料率(kbps) fm. 1(新方法) in-】(斜坡)fm.!(新方法) U斜坡) 224 7 2 22 62 0.0831 0.105 0.791 192 6 4 20 60 Γ 0,0824 0.1123 0.734 160 5 8 18 1 58 1 0.125 0.1436 0.87 128 4 16 16 56 ' 0.25 0.25 . 1.0 96 3 32 12 52 0.234 0.2448 0.956 64 2 64 8 48 0.5 ‘0.5 1.0 32 1 128 0 40 1.0 1.0 1.0 表5 .資料率對Μ值 表中’該最小群組的相對頻率使用該新算法及原具 有斜坡成本函數之V 34型映射,其比例亦列於表中。我們 可知道對實際有益處的m值(相對較大)而言,心減少超過 2〇%(該錯誤率亦然)。對小m而言,因為我們必須用完其 全數’或幾乎所有可得的八個符號的組合,所以新算法其 只/又有任何其法能予協助。但此等例子的確有些微的益 處。 從表中,我們知道如果m減少i,則k即減少2,而諸資 料率減少2 kbps。m減少1意謂該最小距離加倍,給我們約 6dB以上的噪音容限。因此,如果使用任何編碼技術面改 善該效能,則以1 /4或較小的位元/符號的成本即可獲得多 於6dB的編碼增益》 當維持相同的最小距離時,亦可使]VI增加16。尤其,我 們可使用比我們另外使用之群组為小的群組中相隔的每— -25 - 本紙張尺度適用標準(CNS ) ( 210X297公釐) " ------- (請先聞讀背面之注意事項再填寫本頁〕 •裂 .-Ι1Τ 45 580 0 A7 ______J37 五、發明説明(23) 個點。例如,我們可用第6組的16個點同時使用第〇至5组 的192點,並維持最小距離4。為使用該群組映射算法’每 組的點數必須相同。因此我們可將M點總數.分成 組,亦即我們前述的一組現已分成兩個較小的组,而M為 從1至15。我們用4位元從每纽中選取一點。用更多的點: 我們即可增加資料率,一般而言是1或2肋1^。在該峡射算 法中,奇數m的產生函數為: gi=(m-3)+3x 成本0的次級產生函數為: .g、=l+x+x2+".+xm·4 成本1的次級產生函數為: g" I=l+X+X2 對偶數Μ而言,我們可用g1=(m_2)+2x=2[(m/2-l)+x],隹其 結果與我們先前使用者相同。 ' 其資料率為(k+32)kbps,如下表所列。 (請先閱請背面之注意事頊再填^本耳) 經濟部中央榡準局—工消費合作杜印製 -26- 本紙張尺度適用中國國家標準(CNS ) A4規格(210X297公楚) 4 5 5 8 0 Ο Α7 _β7 24、 五、發明説明() Μ m 最小距離k 資料率(kbps)fmin新fmin斜坡fmin新/fmin斜坡 240 15 2 31 63 0.1560 0.1676 0.9308 224 14 2 30 62 0.0831 0.1055 0.7877 208 13 4 29 61 0.1476 0.1668 0.8849 192 12 4 28 60 0.0824 0.1125 0.7324 176 11 8 27 59 0.1729 0.1964 0.8803 160 10 8 26 58 0.1250 0.1442 0.8669 144 9 16 25 57 _0.2685 0.2783 0.9648 1?8 8 16 24 56 0.25 0.25 1 112 7 32 22 54 0.3485 0.3575 0.9748 Q6 6 32 20 52 0.2340 0.2470 0.9474 80 5 64 18 50 0.5061 0.5261 0.9731' 64 4 64 __ 16 48 0.5 0.5 1 48 3 128 12 44 1 1 1 32 9 128 8 40 1 1 1 16 1 256 0 32 1 1 1 ----'J裝-- (請先閱讀背面之注意事項再填寫本頁) -丁 經濟部中央標準局員工消費合作社印m 表6.包含fmin的資料率 該表亦列示fmin、具有最小距離用於所建議之成本函數 及V.34殼式映射所用之斜坡成本函數的各點的機率,及其 比例。由之可知當增加16點時’雖然該極小距離未改變, 但該等最小之點的數目增加了 50% ’因此使用此等最小點 的機率通常亦增加,其錯誤機率亦然。故資料率的增加並 ,非完全沒有效能的成本.在内。 -27- 本紙張尺度適用中國國家榇準{ CNS ) A4規格(210X297公釐> *1εξ-~£·β 455800 A7 JB7 五、發明説明(25) 圖式元件符號說明 100 個人電腦(PC) 101 數據機(modem) 102 裝置 103 公用交換電話網路(PSTN) 104 二步映射裝置 - 105 系統軟體 106 數據機軟體 107 中央處理單元(CPU) 108 指令匯流排 201 類比數據機 203 數位網路 205 /z定律數位至類比轉換器(D/A) 301 編碼器 303 區段映射器 304 交織編碼器 305 位元映射 401 編碼器 經濟部中央標準扃貝工消費合作社印聚 (請先閲讀背面之注意事項再填寫本頁) 501 編碼器 503 頻譜形成器 601 編碼器 701 56k類比數據機接收器 901 56k數據機 1101 雙工數據機 -28- 本紙乐尺度適用中國國家標準(CNS ) A4規格(210X297公釐) 4 5 5 8 0 0 A7 -B7 五、發明説明( 26、 此外,由於較大的m值與k值,故雖然其棱尚屬合理, 但表格的大小與複雜性亦增加。 表中所列之資料率的計算並未考慮因其他原因導致的減 少’例如所截取的信號位元。該等位元鄉耗用資料率的 1 -33 kbps ° (请先閱讀背而之注意事項舟填寫本頁) -裝 訂 經濟部中央標準扃員工消贤合作社印製 29 本紙張尺度適用中國國家標準(CNS ) A4規格(2丨Ο X 297公釐)The cost is higher than that of all octets without any points. Therefore, the order of octets in this cost function is as follows. Text (〇SG), (lSG), (2SG), ... (8SG) (commit: the smallest group) Because 2k is usually less than mN, so we usually do not m. Smaller groups can be used to eliminate this error rate. ^ H is reduced and the disadvantage of the cost function is that the ordering of the generating function is too high, its table and high complexity. To avoid these problems ’suggestion == a two-step mapping algorithm. When using this new algorithm, the complexity is similar to the mapping algorithm based on the slope cost function, but it can achieve the same effect, as described above. Printed by the Central Standards Bureau of the Ministry of Economic Affairs of the Bayer Consumer Cooperative, because the minimum frequency of these smallest points is a rule, we can use a very simple generation function to express it: gi = (ml) + x In this example +, the cost The function is 〇, 〇A ..., M, except for this minimum group, we don't have to worry about using that group. Using this cost function, its cost is not D θu p, t & let + /, 疋 the index of the group. For example, cost 0 means group 0 to m-ι, and cost t means group 1 with minimum distance. The problem is at cost 0 ’how can we say to use that group. To solve -23 "this paper size _ 中国 iii 准 (CNS) Α4 · _ (―210 ^^ · 4 5 5 80 0 Α7 Β7 V. Description of the invention (21) To solve this problem, we can generate the function in one order: g 'l = l + X + X2 + ... + xm-2 g, 2 = g, l * g'l g, 4 = g'2 * g'2 ~ Z, 4 g'8 = g'4 * g'4—Z, 8 is similar to the V.34 shell mapping algorithm. 'We first search through the first table that is currently only 8 degrees long in order to find the total cost of the 8 symbols. If the cost is 0, go to the secondary generation function, search through the Z, 8 table, and perform other mappings in the same way as the V.34 shell mapping to obtain from 0 to m- 8 group indicators of 2. Printed by the Shellfish Consumer Cooperative of the Central Standards Bureau of the Ministry of Economic Affairs (please read the precautions on the back before filling this page). If the total cost of the 8 symbols is not 0, use the following table to The cost of splitting the 8 symbols becomes the cost of 2 4 symbols. If one of the 4 symbols' cost is 0, go to the secondary generation function and use the rest to find out the ZU (or simply use the table) 4 symbols of the secondary Cost 'and finally find 4 group indicators from 0 to m-2. Similarly, if one of the costs of the 4 symbols is 0, go to the secondary generation function to calculate the secondary The cost of two symbols, and finally calculated the two group indicators from 0 to m-2. Note that the tables of the first group and the second group are small ^ The size of the table is about the cost of the slope of V.34 type The function table is the same β and its complexity is also similar. We 従 group map to get 8 group indicators (from 0 to m-1). The indicator i means the substantial section + (8-i) and-(δ- i), after a total of 32 points, use 5 bits to pick one of the 32 points. The data rate is (k + 40) kbps. The data rates of various M are listed in the following table. -24- This paper scale GM China National Standard (CNS > Α4 size (210 × 297 mm) 4 Μ Printed by the Bayer Consumer Cooperative of the Central Bureau of Standards of the Ministry of Economic Affairs 5 5 80 0 A7-____ £ 7 V. Description of the invention (22) M m k data rate (kbps) fm. 1 (new method) in-] (slope) fm.! (new method) U slope) 224 7 2 22 62 0.0831 0.105 0.791 192 6 4 20 60 Γ 0,0824 0.1123 0.734 160 5 8 18 1 58 1 0.125 0.1436 0.87 128 4 16 16 56 '0.25 0.25. 1.0 96 3 32 12 52 0.234 0.2448 0.956 64 2 64 8 48 0.5' 0.5 1.0 32 1 128 0 40 1.0 1.0 1.0 Table 5. Data rate Use the new algorithm and the original V 34 mapping with the slope cost function for the relative frequency of the smallest group in the M value table. The proportions are also listed in the table. We know that for practically useful m-values (relatively large), the heart is reduced by more than 20% (and the error rate is the same). For small m, the new algorithm can only / have any other method to help because we have to run out of its full number 'or almost all available combinations of eight symbols. But these examples do have some minor benefits. From the table, we know that if m decreases by i, k decreases by 2 and the data rate decreases by 2 kbps. A decrease of m means that the minimum distance is doubled, giving us a noise margin of about 6dB or more. Therefore, if any coding technology is used to improve the performance, a coding gain of more than 6dB can be obtained at the cost of 1/4 or less bits / symbol. "When maintaining the same minimum distance, you can also use] VI Increase by 16. In particular, we can use each of the groups smaller than the group we use separately — -25-Applicable Standard (CNS) (210X297 mm) for this paper size " ------- (Please first Please read the notes on the back of the page and fill in this page again.] • Crack. -Ι1Τ 45 580 0 A7 ______J37 V. Description of the invention (23) points. For example, we can use the 16 points of the 6th group to use the 0th to 5th groups at the same time. 192 points, and maintain a minimum distance of 4. In order to use the group mapping algorithm, the number of points in each group must be the same. Therefore, we can divide the total number of M points. Group, and M is from 1 to 15. We use 4 bits to select a point from each button. With more points: we can increase the data rate, generally 1 or 2 ribs 1 ^. In this gorge In the projection algorithm, the generation function of the odd number m is: gi = (m-3) + 3x The secondary generation function of cost 0 is: .g, = l + x + x2 + ". + Xm · 4 the cost of 1 The generation function is: g " I = l + X + X2 For even number M, we can use g1 = (m_2) + 2x = 2 [(m / 2-l) + x], and the result is the same as our previous use. The same. 'The data rate is (k +32) kbps, as listed in the table below. (Please read the notes on the back, and then fill in ^ this ear.) Central Bureau of Standards, Ministry of Economic Affairs, Industrial and Consumer Cooperation Du printed -26- This paper size applies Chinese national standards ( CNS) A4 specification (210X297) 4 5 5 8 0 〇 Α7 _β7 24. V. Description of the invention (m) Minimum distance k Data rate (kbps) fmin new fmin slope fmin new / fmin slope 240 15 2 31 63 0.1560 0.1676 0.9308 224 14 2 30 62 0.0831 0.1055 0.7877 208 13 4 29 61 0.1476 0.1668 0.8849 192 12 4 28 60 0.0824 0.1125 0.7324 176 11 8 27 59 0.1729 0.1964 0.8803 160 10 8 26 58 0.1250 0.1442 0.8669 144 9 16 25 57 _0.2685 0.2783 0.9648 1? 8 8 16 24 56 0.25 0.25 1 112 7 32 22 54 0.3485 0.3575 0.9748 Q6 6 32 20 52 0.2340 0.2470 0.9474 80 5 64 18 50 0.5061 0.5261 0.9731 '64 4 64 __ 16 48 0.5 0.5 1 48 3 128 12 44 1 1 1 32 9 128 8 40 1 1 1 16 1 256 0 32 1 1 1 ---- 'J Pack-(Please read the precautions on the back before filling this page)-Ding Staff of Central Standards Bureau, Ministry of Economic Affairs Consumption cooperatives print m Table 6. Data rate including fmin This table also lists fmin, has The probability of each point of the ramp function and the cost function cost V.34 shell mapping for a small distance of the proposed use of, and the proportions thereof. It can be seen that when 16 points are added ', although the minimum distance has not changed, the number of such minimum points has increased by 50%', so the probability of using these minimum points also generally increases, as does the probability of errors. Therefore, the increase of the data rate is not entirely without the cost of performance. -27- This paper size applies to China National Standard {CNS) A4 specification (210X297 mm > * 1εξ- ~ £ · β 455800 A7 JB7 V. Description of the invention (25) Symbol description of graphic components 100 Personal Computer (PC) 101 Modem 102 Device 103 Public Switched Telephone Network (PSTN) 104 Two-step Mapping Device-105 System Software 106 Modem Software 107 Central Processing Unit (CPU) 108 Instruction Bus 201 Analog Modem 203 Digital Network 205 / z Law Digital-to-Analog Converter (D / A) 301 Encoder 303 Section Mapper 304 Interleaved Encoder 305 Bit Mapping 401 Encoder Central Standard of the Ministry of Economy Please fill in this page again) 501 encoder 503 spectrum generator 601 encoder 701 56k analog modem receiver 901 56k modem 1101 duplex modem-28- This paper music standard is applicable to China National Standard (CNS) A4 specification (210X297 male) 4) 5 5 8 0 0 A7-B7 V. Description of the invention (26. In addition, due to the large m and k values, although the edges are reasonable, the size and complexity of the table also increase. The calculation of the data rates listed below does not take into account the reduction due to other reasons, such as the intercepted signal bits. These bits consume 1-33 kbps of the data rate (please read the precautions in the back first) (This page)-Binding Central Standard of the Ministry of Economics, printed by employee Xiaoxian Cooperative Co., Ltd. This paper size applies to Chinese National Standard (CNS) A4 (2 丨 〇 X 297 mm)

Claims (1)

4 經濟部中央標隼局員工消費合作社印製 5 80 0 as C8 D8 六、申請專利範圍 ..1.—種經由一網路用以傳輸及接收資料之數據機裝置, 包含: 一用以減少一設定之形態增益平均功率的二步映射 器。 2 . —種經由一個人電腦並以一網路為媒介用於資料通訊 之數據通訊系統,包含: 至少兩個連接位於間隔位置上的網路媒介裝置; 該二裝置之一包含一個人電腦,該電腦具有·· —經由該網·路媒介用於數位資料通訊之數位數據機, 該數位數據機包含用必減少一設定之形態增益平均功 率的二步映射器, 該二裝置之另一裝置具有 —用以自該網路媒介接收類比資料之類比數據機。 3 . —種用以經由一網路傳輸數位資料之方法·,包含下列 步驟: 藉由比較距離以映射數位資料,及 跳過該等近於0之資料點,俾減少—設定形態增益的 平均功率。 -30- 本紙張_^?^度通用中國國家揉率(€阳).八4^格(210乂297公釐) (請先聞讀背面之注意事項再填寫本頁) 訂.4 Printed by the Employees' Cooperative of the Central Bureau of Standards of the Ministry of Economic Affairs 5 80 0 as C8 D8 6. Scope of patent application: 1. A modem device for transmitting and receiving data via a network, including: A two-step mapper with a set shape gain average power. 2. A data communication system for data communication via a personal computer and using a network as a medium, comprising: at least two network media devices connected in spaced positions; one of the two devices includes a personal computer, the computer With ...-a digital modem for digital data communication via the network medium, the digital modem includes a two-step mapper that must reduce a set morphological gain average power, and the other device of the two devices has- An analog modem used to receive analog data from the network medium. 3. — A method for transmitting digital data through a network, including the following steps: Map digital data by comparing distances, and skip these data points that are close to 0, and reduce—set the average of the form gain power. -30- This paper is _ ^? ^ Degree universal Chinese national kneading rate (€ yang). 8 4 ^ grid (210 乂 297mm) (please read the precautions on the back before filling this page) Order.
TW86115260A 1996-10-16 1997-10-16 Device, system, and method for modem communication utilizing two-step mapping TW455800B (en)

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