TW402700B - Method of allocating the service request - Google Patents

Method of allocating the service request Download PDF

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Publication number
TW402700B
TW402700B TW87117463A TW87117463A TW402700B TW 402700 B TW402700 B TW 402700B TW 87117463 A TW87117463 A TW 87117463A TW 87117463 A TW87117463 A TW 87117463A TW 402700 B TW402700 B TW 402700B
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Taiwan
Prior art keywords
service
service request
updated
server
servo device
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TW87117463A
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Chinese (zh)
Inventor
Char-Ching Lin
Ya-Ping Chen
Jun-Lin Liu
Yueh-Min Huang
Shiao-Li Tsao
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Ind Tech Res Inst
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Abstract

A method of allocating the service request with data stored by round robin. Each service request is served by a real server respectively and stores the present data block read now and the the shift data block saved previously respectively by the buffer block series having several buffer blocks. The method includes the following steps. Firstly, decide the server for updating that corresponds to each service request respectively. Secondly, search the service request loop sequence which includes parts of the service requests according to the real server and the server for updating that corresponds to the respective service requests. In the service request loop sequence, one of the real server of the service request is the same as the server for updating of the previous service request, and the server for updating is the same as the real server of the next service request. Finally, change the real server of each service request in the loop sequence to reduce the number of buffer blocks.

Description

五、發明說明(1) 4U ^V U ϋ 本發明係有關於一種可擴充多媒體系統(scaUbie system)的服務要求(service ^^“。配置 特別是—種動態的服務要求配置方法,㊣夠讓系統 ^供低初始延遲(low initial delay)以及低緩衝區需求 Clow bUffer requirement)的多媒體系統服務。 在多媒體系統中,一般需要很大的頻寬來傳送資料給 寥戶端(client)或者是從硬碟或其他儲存媒介上讀取資 料同時系統必須要具備擴充性(sc a 1 ab i 1 i ty),以便因 應服務客戶數量的增加。然而,當為了儲存更豐富的多媒 體資料而增加硬碟,或是需要服務的客戶大量增加時,將 會導致客戶端的初始延遲增加。這種情況對於需要低初始 延遲特性的某些多媒體系統,例如隨選視訊系統(V丨d⑸V. Description of the invention (1) 4U ^ VU ϋ The present invention relates to service requirements (service ^^ "of a scalable multimedia system (scaUbie system). Configuration is particularly a dynamic service requirement configuration method, which is enough for the system ^ For multimedia system services with low initial delay and low buffer requirement. In multimedia systems, a large bandwidth is generally required to transmit data to a few clients or from hard Read data on discs or other storage media and the system must be expandable (sc a 1 ab i 1 it ty) in order to respond to the increase in the number of service customers. However, when adding hard disks to store richer multimedia data, When the number of customers who need services increases, the initial delay of the client will increase. This is the case for some multimedia systems that require low initial delay characteristics, such as on-demand video systems (V 丨 d⑸

On Demand ’ V0D),是必須解決的問題。 θ 一般系統的即時(real time)特性,主要的因素 疋起始回應時間(startup response time),也就是初始On Demand ’V0D) is a problem that must be solved. θ Real-time characteristics of general systems, the main factors 疋 Startup response time, which is the initial

延遲。當實際的延遲時間越短,系統的即時特性就越好°。 但是如前所述,低初始延遲的特性是會隨著資料量和客戶 的增加而破壞’此時系統必須額外付出代價,例如採用更 快速的輸入/輸出(input/output,I/O)存取裝置、或者是 使用處理速度更快速的微處理器、亦或者是使用較多的緩 衝區(buffer size)來加速存取的動作。例如在5 Ghandehar i z adeh,S. H. Kim,W. Shi,Rdelay. The shorter the actual delay time, the better the instantaneous characteristics of the system. But as mentioned before, the characteristics of low initial delay will be destroyed with the increase of data volume and customers. At this time, the system must pay extra costs, such as using faster input / output (I / O) memory. The fetching device either uses a faster microprocessor or uses more buffer sizes to speed up the access operation. For example, in 5 Ghandehar i z adeh, S. H. Kim, W. Shi, R

Latency in SPIE Vol.Latency in SPIE Vol.

Zimmermann , "On Minimizing Startup Scalable Continuous Media Servers"Zimmermann, " On Minimizing Startup Scalable Continuous Media Servers "

M.27Q0 五 '發明說明(2) 3020, 1 997這篇論文中,其利用複製資料(replication data)和要求遞移(request migration)的方式,來達到負 載平衡以及減少初始延遲兩個問題,不過系統卻必須額外 使用到大量的緩衝區。 以下配合圖式,分別說明在可擴充多媒體系統中初始 延遲現象’以及習知技術中用以解決初始延遲現象的兩種 方式’第一種是資料複製(data replication)方式,第二 種則是分散式頻寬(shared bandwidth)方式。 第1圖表示是一般可擴充多媒體系統架構的示意圖。 在第1圖中’可擴充多媒體系統包括一允許/分配伺服器 (administrate and dispatch server)30、數個伺服裝置 (21 '22)以及數個儲存裝置(i〇、11、12)。允許/分配飼 服器30是負責將來自客戶端(未圖示)之服務要求,進行允 許和分配的工作,以及系統内部各裝置間的整合和溝通協 調。飼服裝置(2 1、2 2 )則是根據允許/分配伺服器3 〇所分 配到的客戶服務要求,對於儲存裝置(丨〇、11、1 2 )進行資 料的讀取動作,在實際應用上,儲存裝置可以是硬碟、光 碟等等可儲存資料的媒介。這些系統内的裝置則是透過傳 輸媒介99進行控制信號和資料的交換,例如利用M.27Q0 Five 'Invention Description (2) 3020, 1 997 In this paper, it uses replication data and request migration to achieve load balancing and reduce initial delay. However, the system must use a lot of extra buffers. The following describes the initial delay phenomenon in scalable multimedia systems and the two methods used to solve the initial delay phenomenon in the conventional technology with the diagrams. The first is a data replication method, and the second is Distributed bandwidth (shared bandwidth) method. Figure 1 shows a schematic diagram of a general scalable multimedia system architecture. In FIG. 1, the 'extensible multimedia system includes an allowance / dispatch server (administrate and dispatch server) 30, a plurality of servo devices (21'22), and a plurality of storage devices (i0, 11, 12). The allowance / distribution feeder 30 is responsible for permitting and assigning service requests from clients (not shown), as well as integration and communication coordination among various devices in the system. The feeding device (21, 2 2) reads data from the storage device (丨 〇, 11, 12) in accordance with the customer service requirements assigned by the allowance / distribution server 30. In practical applications In the above, the storage device may be a medium capable of storing data, such as a hard disk, an optical disk. The devices in these systems exchange control signals and data through transmission media 99, such as using

Ethernet >FDDI 'Fast-Ethernet ' Gigabit-Ethernet ^ ATM等等所構成的網路’或者是SSA、Fiber channel等等 的輸出入匯流排。在系統中的這些伺服裝置和儲存裝置, 可以在規格内自由地新增、減少或換取,以調整系統整體 的效能。另外,在一般可擴充多媒體系統中大都是採用資Ethernet > FDDI 'Fast-Ethernet' Gigabit-Ethernet ^ ATM, etc. 'or an input / output bus of SSA, Fiber channel, etc. These servo devices and storage devices in the system can be freely added, reduced or exchanged within the specifications to adjust the overall system performance. In addition, in general scalable multimedia systems,

五、發明說明(3) 料分散處理(data stripping)的技術,也就是將每部多媒 體貧料分散成數個資料區塊’分散存放在每個儲存裝置上 以達到負載平衡(1 oad balance),而每個伺服器則會輪流 地去讀取’原來依照循環方式(r 〇und r〇b i n)存放在每個 儲存裝置上的資料區塊。 第2圖表示一可擴充多媒體系統的系統簡化示意圖, 用以說明上述的資料分散處理以及巡迴服務模式。在此簡 化的系統中包括了四個伺服裝置(分別標示為s丨、S 2、 S3、S4)以及四個儲存裝置(分別標示為HM、HD2、HD3、 HD4)。在第2圖中,系統是以硬碟機來當作儲存裝置,每 個儲存裝置則可能具有一個以上的硬碟,也可以是一磁碟 陣列,其内的小方格表示存放在這儲存裝置上的多媒體資 :。在此所假設的情況{’提供一部電影影片當做系統的 夕媒體資料’而此多媒體資料則是以連續循序R〇und R〇bln的方式,存放在每個儲存裝置内。每個儲存裝置内 =方格内數目字,則是代表此電影資料區塊編號(data 2H^UenCe nUmber),詳言之,第0個資料區塊放在 =存裝置上,第i個資料區塊放在儲存裝置hd2上其 餘依此類推。 、 另外在第2圖中每個伺服裝置(S1、s2、δ3 ' S4)八 包::四個小方格’代表可以容納客戶的服務要求二此 =子中⑽假設每㈣服裝置同時至多可以服務四個要 求。 如圖所示,在飼服裝置S1上的第―個小方格内已經填V. Description of the invention (3) The technology of data stripping, that is, dispersing each multimedia lean material into several data blocks, which are stored on each storage device to achieve load balance (1 oad balance). And each server will take turns reading the data blocks originally stored on each storage device in a circular manner (r0und r0bin). FIG. 2 is a simplified system schematic diagram of an expandable multimedia system, which is used to describe the above-mentioned data decentralized processing and patrol service mode. This simplified system includes four servo devices (labeled s 丨, S2, S3, S4) and four storage devices (labeled HM, HD2, HD3, HD4). In Figure 2, the system uses a hard disk drive as the storage device. Each storage device may have more than one hard disk or a disk array. The small squares in it indicate that it is stored in this storage. Multimedia resources on the device :. The hypothetical situation here is {'provide a movie film as the system's evening media data', and this multimedia data is stored in each storage device in a continuous sequential Round Robln way. In each storage device = the number in the square, it represents the movie data block number (data 2H ^ UenCe nUmber). In detail, the 0th data block is placed on the = storage device and the i-th data area The blocks are placed on the storage device hd2, and so on. In addition, in the second figure, each servo device (S1, s2, δ3 'S4) is eight packets: Four small squares represent service requirements that can accommodate the customer. This ============================================================================================================== =========================================================================================== Four small squares to represent the service requirements of the client to be able to accommodate the second request; and assuming that each serving device is at most at the same time Can serve four requirements. As shown in the figure, the first small square on the feeding device S1 has been filled

五、發明說明(4) 上:A,這表示祠服裝置以目前分配到 經在傳送第0個影片資料區塊給服務要求A。並且已 因為電影影片資料是以循環方式放置在四個别所述, 置上,所以對於每個伺服裝置而言也同 j的儲存裝 方式’週期性地到每一個儲存裝置±去讀取^ =輪流的 料區塊。也就是說,伺服裝置會在每個 片資 個1週期(Avice round,所謂的服務週 伺服裝置服務完所有的客戶一次的時間稱之)月疋匕所有的 、務週期過後’所有的伺服裝置會同時會換到另一等個服 5二去Λ取所需的資料。在第2圖中最上方的部分服 第。個影片資料區塊,另外,小方塊上有兩個;m 小箭頭,指向小方塊的小箭頭代表飼服裝㈣從儲存^的置 HD1讀取影片資料區塊出來’並且存放到緩衝區内;指 小方塊的小箭頭代表送給客戶端的資料。因此,在下一個 服務週期+,伺服裝置51會變換到健存裝置舰,繼續讀 出影片的下一個(第1個)資料區塊,其餘依此類推。此 假設系統使用單一緩衝區方式(〇ne buffer schenie),而 且假設伺服裝置讀取影片的資料量永遠夠客戶端的消耗。 在以下面的討論中,皆以類似於第2圖的系統簡化示意圖 來進行說明。 以下根據第3圖及其所示的範例,詳細解釋初始延遲 的現象。假設系統剛開始的情況如第2圖所示,在第1個服 務週期中出現一個新的服務要求A,此時系統會將服務要V. Description of the invention (4) Above: A, which means that the temple service device is currently assigned to the service request A by transmitting the 0th movie data block. And because the movie film data is placed in a circular manner on the four other devices, so for each servo device, it is stored in the same way as j 'periodically to each storage device ± to read ^ = Rotating material blocks. That is to say, the servo device will have 1 cycle (Avice round, so-called service week, the service device will serve all customers once). At the same time, it will switch to another server 5 to get the required information. The top part in Figure 2 takes the lead. There are two video data blocks, in addition, there are two on the small box; m small arrow, the small arrow pointing to the small box represents feeding clothing ㈣ read the video data block from the stored HD1 'and store it in the buffer; The small arrow pointing to the small box represents the data sent to the client. Therefore, in the next service cycle +, the servo device 51 will switch to the surviving device ship, and continue to read the next (first) data block of the movie, and so on. This assumes that the system uses a single buffer scheme (One Buffer Scheme), and assumes that the amount of data that the server reads the movie will always be sufficient for the client. In the following discussion, a simplified system schematic diagram similar to FIG. 2 is used for explanation. The phenomenon of initial delay will be explained in detail based on Figure 3 and the example shown. Assume that the system is just starting as shown in Figure 2. A new service request A appears in the first service cycle. At this time, the system will

C:\Program Files\Patent\〇356-3848-E.ptd第 8 頁 40 五、發明說明(5) 求A配置給祠服裝置以進行服務 取存放有第Μ固資料區塊的儲罢Ηηι」服裝置S1正在/ 務要求A讀取第0個資料區^。存裝侧上,所以可以幫服 接著’假設在第2個服務週期中出現另一個新的服務 由於㈣裝置輪流讀取的關係’ 存裝置腿的是伺服裝置S4,所以系統會將服務要求B配置 :伺服裝置S4上。在此同時’词服裝置。則換到儲存裝置 HD2,為服務要求A進行第i個資料區塊的讀取。 接下來的幾個服務週期内,則是分別在第5個服務週 ,接收到服務要求C、D,在第7個服務週期接收到服 求E ,在第9個服務週期接收到服務要求F。其中,每個服 務要求是配置在當時正在讀取儲存裝置〇1的伺服裝置, 2 Γ圖1、13圈2:第3圖表示在第9服務週期時的系統簡 化不意圖。如圖所不’目前伺服裝置S1中有服務要求A、 c、D、F,伺服裝置S3中有服務要求E,服務要求S4中有服 務要求B,而在伺服裝置S2令則沒有任何服務要求。 在上述允許/分配的控制機制下,當服務要求出現, 系統會優先交由目前正在存取(access)存放有第〇個 區塊之儲存裝酬的伺服裝置。然而,這種允許/分配的 控—制機制在剛開始運作時還可接受,但是運作一段 後,报容易造成服務要求集中在某一個特定的伺服裝置 上,例如伺服務裝置S1 ;或是某一伺服裝置使用率 低,例如伺服裝置S2,此即為負載不平衡的情況。初始 遲的現象也可以根據第3圖來說明,如果有任何服務要°求C: \ Program Files \ Patent \ 〇356-3848-E.ptd page 8 40 5. Description of the invention (5) Ask A to configure the temple service device for services to access the storage where the M solid data block is stored. The server S1 is requesting A to read the 0th data area ^. On the storage side, it can help. Then, "Assuming another new service appears in the second service cycle, because the device reads in turn." The storage device is based on the servo device S4, so the system will request service B. Configuration: on servo device S4. At the same time, the verbal device. Then change to the storage device HD2, and request A to read the i-th data block for the service. In the next few service cycles, service requests C and D were received in the 5th service week, service request E was received in the 7th service cycle, and service request F was received in the 9th service cycle. . Among them, each service request is a servo device that is configured to read the storage device 0 at that time. 2 Γ Figure 1, circle 13: Figure 3 shows that the system is not intended to be simplified during the 9th service cycle. As shown in the figure, there is a service request A, c, D, and F in the servo device S1, a service request E in the servo device S3, and a service request B in the service request S4, and there is no service request in the servo device S2. . Under the above-mentioned permission / distribution control mechanism, when a service request occurs, the system will give priority to the servo device that is currently accessing the storage charge stored in the 0th block. However, this permission / distribution control-control mechanism is still acceptable at the beginning of operation, but after a period of operation, the report easily causes the service request to be concentrated on a specific servo device, such as the server S1; or A servo device has a low utilization rate, such as the servo device S2, which is a case of unbalanced load. The phenomenon of initial delay can also be explained according to Figure 3. If there is any service requirement

五 '發明說明(6)^ ^ / 0 y 一 ' 是在第9個服務週期時加入’或是在當伺服裝置s 1輪換到 健存褒置HD 1的服務週期内加入,由於伺服裝置s丨中所能 夠接收的服務要求已經額滿’系統就無法直接配置在伺服 裝置S1上,此時系統會延遲開始服務這個服務要求的時 間’等到有足夠服務能力的伺服裝置輪到可存取儲存裝置 HD1上時’才開始服務此一新的服務要求,因此也就造成 新服務要求的初始延遲,而這種情況尤其在系統趨近滿載 時更容易發生。因此,傳統多媒體系統存在兩個問題,第 一個便是負載不平衡,第二個就是初始延遲的現象。 目前解決負載平衡和初始延遲的方法有兩種,一種是 利用資料複製的方式,預先複製影片初始的幾個資料區塊 到每個儲存裝置上’另一種則是利用某些伺服裝置的額外 頻寬來協助處理影片開始幾個資料區塊的讀取。以下配合 圖式’說明這兩種習知技術的内容。 第4圖表示系統利用資料複製方式處理情況下的系統 簡化示意圖。如圖所示’在儲存裝置HD2、HD3、HD4中, 分別存放著一些額外的資料區塊。在儲存裝置HD2中存放 著第0個資料區塊’在儲存裝置HD3中存放著第〇個和第1個 資料區塊’在儲存裝置HD4中存放著第〇個、第1個和第2個 資料區塊。也就是說,每個儲存裝置(除了HD1外)分別額 外存放著同一影片資料内的開始幾個資料區塊。Five 'invention descriptions (6) ^ ^ / 0 y a' is added at the 9th service cycle 'or is added during the service cycle when the servo device s 1 is rotated to the health storage device HD 1, because the servo device s丨 The service request that can be received is full. The system cannot be directly configured on the servo device S1. At this time, the system will delay the time to start the service request. Wait until the server device with sufficient service capacity can access the storage. This new service request is only started when the device HD1 is on, so it also causes the initial delay of the new service request, and this situation is more likely to occur especially when the system is approaching full load. Therefore, there are two problems with traditional multimedia systems. The first is load imbalance and the second is initial delay. At present, there are two methods to solve the load balancing and initial delay. One is to use data replication. The first few data blocks of the video are copied to each storage device in advance. The other is to use the additional frequency of some servo devices. Wide to assist in processing the movie to start reading several data blocks. The contents of these two conventional techniques will be described below with reference to the drawings. Fig. 4 shows a simplified diagram of the system in the case where the system uses a data copying method. As shown in the figure ', in the storage devices HD2, HD3, and HD4, there are stored some additional data blocks, respectively. The 0th data block is stored in the storage device HD2 'The 0th and 1st data blocks are stored in the storage device HD3' The 0th, 1st, and 2nd data blocks are stored in the storage device HD4 Data block. That is, each storage device (except HD1) separately stores the first few data blocks in the same movie data.

當系統在一開始時接收到服務要求A時,會將其配置 在伺服裝置S1進行服務,如果此時又有另一個服務要求BWhen the system receives the service request A at the beginning, it will be configured in the server S1 for service. If there is another service request B at this time

C:\ProgramFiles\Patent\0356-3848-E.ptd第 1〇 頁C: \ ProgramFiles \ Patent \ 0356-3848-E.ptd page 1〇

服裝置S2、或伺服裝置S3、成 例子中,4脾服铱I 5 戈裝置S4上。在第4圖的 第2圖所示的系統情況,飼„置^ =上。:果依照 資料的第〇個資料區塊认客戶疋無法立即讀取影片 S2此時ί 保留了第〇個資料區塊,因此伺服裝置 個資料區塊。另一 S it 同時取得第°個和第1 服務蓉冰R 面,在延種解決方案下,系統必須為 —個ΐ務可以容納兩個資料區塊的緩衝區。進入下 恢彳# il 1:卷月時伺服裝置52會輪換到儲存裝置HD3 ’也 的存取狀態。此時,飼服裝置s2只需要為服務 宏玲嫂i第2個資料區塊,而在此同時發出服務要求B的 正消耗掉第0個資料區'鬼,所以緩衝區中保存的 = 和第2個資料區塊,其餘服務週期的情況亦可依此 類推。 在第一種方式中’是事先複製影片剛開始的幾個資料 品,到各個儲存裝置,所以,系統不僅可以立即允許服费 要求的加入,也可以達到負載平衡。然而這種方式有三項 缺點。第一,每一個儲存裝置必須額外多花—些儲存空間 來存=資料開端的一些資料區塊。第二,系統必須提供額 外$緩衝區間來放置為了服務要求而可能需要事先讀出來 的貝料區塊。第三’伺服裝置需要在開始服務新的服務要 f時’為單一個服務要求讀取一塊以上的資料區塊,也就 疋為要伺服裝置進行瞬間大量讀取(burst data retrieve),自然對於系統有不良的影響。In the example, the server device S2 or the servo device S3 is used, and the spleen server I4 is used on the device S4. In the system situation shown in Figure 4 and Figure 2, set ^ = on .: If the customer is identified according to the 0th data block of the data, the movie S2 cannot be read immediately. At this time, the 0th data is retained. Block, so the servo device has one data block. The other S it simultaneously obtains the first and first service Rongbing R planes. Under the extended solution, the system must be a service that can accommodate two data blocks. Enter the next buffer # il 1: Servo device 52 will rotate to the storage device HD3 when the month is full. At this time, the feeding device s2 only needs to serve the second data of Hongling 嫂 i. Block, and at the same time a service request B is currently consuming the 0th data area 'ghost, so the = and 2 data blocks stored in the buffer, and the rest of the service cycle can also be deduced by analogy. In the first method, the first few data items of the movie are copied in advance to each storage device. Therefore, the system can not only allow the addition of service fees immediately, but also achieve load balancing. However, this method has three disadvantages. First, every storage device must You need to spend extra-some storage space to store = some data blocks at the beginning of the data. Second, the system must provide an extra $ buffer space to place shell material blocks that may need to be read out in advance for service requirements. The third 'servo The device needs to read more than one block of data for a single service when it starts to service a new service, which means that the server needs to perform a burst of data retrieval (burst data retrieve), which is naturally bad for the system. influences.

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五、發明說明(8) 4ΤΓ27ΙΓ0 '一'〜 --- 、接著根據第5圖,說明第二種達到系統負載平衡和 初始延遲的分散式頻寬方法。分散式頻寬方式主要是在服 務要求的剛開始階段,利用數個伺服裝置來同時進行讀取 的動作’以達到低初始延遲的目的。參考第5圖,當系統 在一開始時接收到服務要求A時,會將其配置在伺服裝置 S1進行服務。如果此時又有另一個服務要求B加入的話, 根據負載平衡的原則,系統會將服務要求B配置在飼服裝 置S2。但是,為由於伺服裝置S2目前所服務的是儲存裝置 HD2,其中並1不含第〇個資料區塊,所以系統在一開始^在 伺服裝置S1中放上一個暫時性的服務請求b。藉此,伺服 裝置si和伺服裝置S2會在同一個服務週期内,完成第〇個 和第1個資料區塊的讀取。在下一個服務週期中,伺服裝 置S1中的暫時性服務請求b會被取消,而伺服裝置S2則^ 巡迴服務到儲存裝置HD3,繼續進行服務。與前一方法$ 同的是’系統也要使用一定緩衝區數量來暫存這些預先 出的資料區塊。 ° 利用分散式頻寬的方式’也可以讓系統達到負載平衡 和低初始延遲的目的。再與前一資料複製方式相比較不 僅不需要額外的儲存空間來存放影片資料的開始部分,也 不會造成特定伺服器的瞬間讀取需求’使得系統負荷趨於 碎載時可能發生不穩定情形的問題。不過與資料複製方式 一樣,系統對於一些服務請求,必須付出大量的緩衝區來 存放那些事先讀出的資料區塊。 歸納來說,雖然資料複製或是分散式頻寬都可以解決V. Description of the invention (8) 4ΤΓ27ΙΓ0 '一' ~ --- Then, according to Fig. 5, the second distributed bandwidth method to achieve system load balance and initial delay will be described. The decentralized bandwidth method is mainly used at the beginning of the service request, using several servo devices to perform the reading operation at the same time 'to achieve the purpose of low initial delay. Referring to FIG. 5, when the system receives the service request A at the beginning, it will be configured in the servo device S1 for service. If another service request B joins at this time, according to the principle of load balancing, the system will configure service request B in feed clothing S2. However, since the servo device S2 currently serves the storage device HD2, and 1 does not include the 0th data block, the system initially places a temporary service request b in the servo device S1. As a result, the servo device si and the servo device S2 will complete reading of the 0th and 1st data blocks in the same service cycle. In the next service cycle, the temporary service request b in the servo device S1 will be canceled, and the servo device S2 will tour the service to the storage device HD3 and continue the service. Same as the previous method $, the system also needs to use a certain number of buffers to temporarily store these pre-exported data blocks. ° Using distributed bandwidth mode ’also allows the system to achieve load balancing and low initial latency. Compared with the previous data copying method, not only does it not require additional storage space to store the beginning of the video data, it also does not cause the instantaneous reading demand of a particular server. 'It may cause unstable situations when the system load is fragmented. The problem. However, like the data copy method, the system must pay a large number of buffers for some service requests to store those data blocks that are read in advance. In summary, although data replication or distributed bandwidth can solve

五、發明說明(9) 負載平衡以及 的問題,也就 塊,提供額外 有鑑於此 求的參理和配 始延遲的前提 的資料區塊緩 根據上述 法。此方法可 循環方式儲存 置’用以輪流 塊。每一服務 置進行服務, 串列,用以分 目前資料區塊 上述服務要求 裝置的條件為 所需的偏移資 務時所需的偏 別對應的實際 分服務要求的 中,某一個服 待更新伺服裝 服務要求的實V. Description of the invention (9) Load balancing and the problem, that is, block, provide additional data blocks with the premise of considering the requirements and delay of deployment according to the above method. This method can be stored in a cyclic manner 'for rotating blocks. Each service set performs a service, and is arranged in order to divide the current data block. The condition of the above service request device is the required offset when the required offset service corresponds to the actual sub-service request. Update the requirements of the server installation service

低初始延遲 是系統必須 的緩衝區域 ’本發明的 置方法,能 下,有效地 衝區域,藉 之目的,本 適用於一系 —資料的複 服務上述儲 要求分別由 並且對應於 別儲存透過 以及預存之 所對應之待 ’當服務要 料區塊數量 移資料區塊 伺服裝置和 服務要求迴 務要求的實 置相同,並 際伺服裝置 的問題,但是都會引進另一個新 為某些服務請求預存的資料區 主要目 夠在維 減少習 此提供 發明提 統中, 數個資 存裝置 上述伺 包含至 上述實 偏移資 更新伺 求由待 ’會低 數量。 待更新 圈序列 際伺服 且其待 相同。 的,在於提供一 持系統負載平衡 知技術中所需要 系統的整體效能 出一種服務要求 其包括複數儲存 料區塊,以及複 ,依序讀取上述 服裝置中之一實 少一緩衝 際伺服裝 料區塊。 服裝置, 更新伺服 於由實際 接著,根 伺服裝置 。在服務 裝置與前 區塊之 置所目 首先, 上述待 裝置進 伺服裝 據服務 ,搜尋 要求迴 種服務要 以及低初 額外提供 〇 配置方 裝置,以 數伺服裝 的資料區 際伺服裝 緩衝區塊 前讀取之 分別決定 更新伺服 行服務時 置進行服 要求所分 出包含部 圈序列 一個服務要求的 更新伺服裝置則與後一個 最後,對於每一個搜尋出Low initial delay is a necessary buffer area of the system. The method of the present invention can effectively and effectively flush the area. For the purpose of this, this applies to a series of data recovery services. The above storage requirements are respectively and correspond to other storage through and Correspondence of pre-storage when the number of service required blocks is shifted. The data block server device and service request are the same as the service request. The problem with the servo device is introduced, but another new request for pre-storage for some service will be introduced. The main purpose of the data area is to reduce the number of inventory storage devices to the above-mentioned actual offset asset update requests in the maintenance and reduction of the invention. The to-be-updated circle sequence is internationally servoed and it remains the same. The purpose is to provide a system that supports the overall performance of the system load balancing technology. A service requires that it includes a plurality of storage material blocks, and that one of the above-mentioned service devices is sequentially read and one buffer server is installed. Material block. Server, update the servo from the actual next, the root servo. In terms of the service device and the previous block, first, the above-mentioned devices to be included in the servo data loading service. The search request will be returned to the service as well as an additional provision at the beginning. The device on the deployment side will be equipped with the servo data buffer area. The read before the block decides to update the service line when the service request is separated. The update server that contains the service sequence and the service request is separated from the last one. For each search,

C:\ProgramFiles\PatentA0356-3848-E.ptd第 13 頁 五、發明說明(10) 的服務要求迴圈序列中每一個服務 置設定成其對應之待更新飼服裝£ 將,實際伺服裝 的緩衝區數量變少,所以可U 糟5,由於整體需要 由於伺服裝置的改變是根據遞=序成=區,’而 維持負載平衡以及低初始延遲的要求來决疋,所以也能夠 另外,如果每一服務要求所 是當服務要求由待更新祠服裝置進裝置, 塊數量為零者,則可以達到系統最佳丁二 =偏㈣:區 的待更新伺服裝置’是指盆所 政果。此一最佳 著在對應服務要求的緩衝“串;二置’存放 區塊。 甲幻甲目刖正在使用的資料 另外,尚可以包含一設定步驟, 求的實際祠服裝罟以;5 ϋΦ缸據每一服務要 不:貰際”服裝置以及待更新伺服裝i,設定對 :求並且由實際伺服裝置指向待更新伺服裝置的有向邊。 =在搜尋步驟中,可以根據這些有向邊是否構成有向迴 圈(directed Cycle),搜尋出所需要的服務要求迴圈序 列。如果存在有數個服務要求,其均對應於相同的實際飼 服裝置和待更新伺服裝f ’此時則可以利用單—個有向邊 表示這些服務要求,達到簡化有向圖的目的。 當一新服務要求加入時,則是根據負載平衡法則,決 定對應的實際伺服裝置。而在決定上述新服務要求所對應 之待更新伺服裝置後,搜尋出可能形成之包含新服務要求 的服務要求迴圈序列。當新服務要求包含於不同的服務要 求迴圈序列時,則根據能夠經調整步驟後減少最多偏移資 C:\ProgramFiles\Patent\0356-3848-E.ptd第 14 頁C: \ ProgramFiles \ PatentA0356-3848-E.ptd page 13 V. Service requirements of invention description (10) Each service setting in the loop sequence is set to its corresponding feed clothing to be updated. Will, the actual servo installed buffer The number of zones becomes smaller, so it can be reduced to 5. Since the overall needs are changed due to the change of the servo device according to the requirements of maintaining load balance and low initial delay, it can also be added. A service request is when the service request is entered into the device by the temple service device to be updated. If the number of blocks is zero, the best system can be achieved. This best effort is in the buffer “string” corresponding to the service requirements; two sets of “storage blocks” are used. In addition, the information about the current use of the magic armor order can also include a setting step to find the actual temple clothing; 5 ϋΦ cylinder According to each service or not: the "international" server device and the servo device to be updated, set the pair: find and point the actual servo device to the directed edge of the server device to be updated. = In the search step, the required service request loop sequence can be searched according to whether these directed edges constitute a directed cycle. If there are several service requirements, all of which correspond to the same actual feeding device and the servo device to be updated f ', then a single directed edge can be used to represent these service requirements to achieve the purpose of simplifying the directed graph. When a new service is requested to join, the corresponding actual servo device is determined according to the load balancing law. After determining the server device to be updated corresponding to the new service request, a service request loop sequence including the new service request may be searched out. When new service requirements are included in different service request loop sequences, the maximum offset data can be reduced according to the adjustment steps C: \ ProgramFiles \ Patent \ 0356-3848-E.ptd page 14

料區塊數量的法則 圈序列。亦即,如 所找到包含上述新 過一個以上時,則 料區塊數量之法則 序列。 决疋需要進行調整步驟的服務要求迴 果當加入新服務要求時,由搜尋步驟中 服務要求之服務要求迴圈序列的數量超 根據能夠經調整步驟後減少最多偏移資 ,決定出需要進行調整的服務要求迴圈 圖式之簡單說明: 的、特徵和優點能更明顯易懂’ 並配合所附圖式,作詳細說明如 為使本發明之上述目 下文特舉一較佳實施例, 下: ί示是一般可擴充多媒體系統架構的示意圖。 環方在可擴充多媒體系統中,用以說明利用循 裒方式儲存資料之系統簡化示意圖 第3圖表示用以說明初始延遲現象的系統簡化示意 團。 資料複製方式解決負載爭 第4圖表示習知技術中利用 衡問題的系統簡化示意圖。 頻寬方式解決負載 結構的示意圖。 明有向圖結構之系 第5圖表示習知技術中利用分散式 平衡問題的系統簡化示意圖。 第6圖表示本發明實施例中有向邊 第7圖表示本發明實施例中用以說 統簡化示意圖。 第8圖表示對應於第7圖的有向圖。 第9圖表示本發明實施例第一範例在要求遞移處理前Law of the number of data blocks That is, if a sequence containing more than one of the new ones is found, the rule sequence of the number of blocks is found. Determine the service requirements that need to be adjusted. If a new service request is added, the number of service request loop sequences in the service step in the search step exceeds the maximum offset amount that can be reduced after the adjustment step. A simple description of the loop diagram of the service requirements: ", features and advantages can be more obvious and easy to understand 'and in conjunction with the accompanying drawings, a detailed description. To make the above-mentioned objectives of the present invention a preferred embodiment is given below, : The display is a schematic diagram of a general scalable multimedia system architecture. In the extensible multimedia system, Huanfang is used to explain the simplified schematic diagram of the system that stores data in a cyclical manner. Figure 3 shows a simplified diagram of the system used to explain the initial delay phenomenon. Data replication method to resolve load contention Figure 4 shows a simplified schematic diagram of the system using the balance problem in the conventional technology. Schematic diagram of bandwidth structure to solve load structure. System of Directed Graph Structure Figure 5 shows a simplified schematic diagram of a system using a distributed balance problem in the conventional technique. Fig. 6 shows a directed edge in the embodiment of the present invention. Fig. 7 shows a simplified schematic diagram in the embodiment of the present invention. FIG. 8 shows a directed graph corresponding to FIG. 7. Figure 9 shows the first example of the embodiment of the present invention

五、發明說明(12) 的系統簡化示意圖。 第1 0圖表示本發明實施例第— 的系統簡化示意圖。 丨第耗例在要求遞移處理後 第11圖表不本發明實絲彻楚-_ 的系統簡化示意圖實把例第-祀例在要求遞移處理前 “ Γ二圖卜表:i發明實施例第二範例在要求遞移處理後 的糸統簡化不意圖。 第1 3圖表不本發明實祐存丨士 圖 系統簡化示意圖。實施例…說明搜尋迴圈程序的 第14圖表示第13圖在經過簡化處理後之系統簡化示意 第15圖表不利用第13圖進行深度優純尋時的搜尋樹 示意圖。 第1 6圖表示在模擬系統中服務要求總量和緩衝區數量 間的關係示意圖。 符號說明: 10、11、12〜儲存裝置;21、22〜伺服裝置;30~允許/ 分配飼服器;99〜傳輸媒介;S1-S4 -伺服裝置;HD卜HD4〜 儲存裝置;40〜表示實際伺服裝置的節點;4卜表示服務要 求的有向邊;42〜表示待更新伺服裝置的節點。 實施例: 本發明所揭示之服務要求配置處理方法,主要是用來 ---------- -•一—-— 減少服務要求巧需要他緩衝區數量,而手段則是. 環 式要\求遞移(cyclic request migration)方式達..成。詳言V. Simplified schematic diagram of the system of the invention description (12). FIG. 10 shows a simplified schematic diagram of a system according to the first embodiment of the present invention.丨 The 11th diagram of the consumption example after the transfer process is required is not as simple as the present invention. A simplified system schematic diagram of the first example is shown before the transfer process is required. The second example does not intend to simplify the system after the transfer process. The 13th diagram is not a simplified diagram of the present invention. The system is simplified. Example: The 14th diagram showing the search loop procedure is shown in the 13th diagram. The simplified diagram of the system after the simplified processing. Figure 15 shows the search tree diagram for deep optimal pure search without using Figure 13. Figure 16 shows the relationship between the total service requirements and the number of buffers in the simulation system. Description: 10, 11, 12 ~ storage device; 21, 22 ~ servo device; 30 ~ allow / distribute feeders; 99 ~ transmission medium; S1-S4-servo device; HD and HD4 ~ storage device; 40 ~ means actual The nodes of the servo device; 4 indicates the directed edge of the service request; 42 ~ indicates the nodes of the servo device to be updated. Embodiment: The service request configuration processing method disclosed in the present invention is mainly used for -------- ----• One —-— Less Qiao number of service requirements needed him buffers, and the means is. Ring to \ requirements transitive (cyclic request migration) way to reach ... In detail

\Patent\0356-3848-E.ptd第 16 頁 五、發明說明(13) 之’如果在各伺服裝置内 變換配置4其他飼服裝置的方求之間,可以透過 式要求遞移的方式來達到本發明 態。換言之,° ,黑宜_;,不可以改變系統負載平衡的狀 程中被^屮\ $個飼服裝置的原有服務要求在遞移過 出’就必須同時也移入一個服務要求,同樣地, 程中移入服務要求。 務要求’也不可以在遞移過 有向=·實施例中,則是利用有向邊(directed咖)和 :1 recte(1 graph )的觀念,來決定出可以進行要求 =的一組服務要求。首先說明本實施例中有向g元件的 疋義· (1) 節點:表示有向圖中的點,對應於系統中的伺服 器裝置; (2) 有向邊:表示在有向圖中存在於兩節點之間的有 向邊’對應於系統已接收的服務要求’其方向是由此一服 務要求的實際伺服裝置(後述)所對應的節點,指向此一服 務要求的待更新伺服裝置(後述)所對應的節點。 第6圖表示一有向邊結構的示意圖。在第6圖中,兩端 的節點(40、42)分別代表服務要求A (41)的實際伺服裝置 以及待更新伺服裝置,圖中所示情況分別為伺服裝置S1和 S3。實際伺服裝置是指系統原先實際配置給服務要求a的 伺服裝置。待更新伺服裝置則是系統中另一個伺服裝置, 表示如果將服務要求A改由該待更新伺服裝置來服務時所\ Patent \ 0356-3848-E.ptd page 16 5. Description of the invention (13) 'If the requirements of 4 other feeding devices are changed and arranged in each servo device, you can use the method of recursive request to Reach the present invention. In other words, °, Hei Yi _ ;, the original service requirements of the feeding device cannot be changed during the load balancing of the system, and must be moved into a service request at the same time. , Move into the service requirements during the process. Service requirements' can not be transferred in directed =. In the embodiment, the concepts of directed edges (directed coffee) and: 1 recte (1 graph) are used to determine a set of services that can perform requirements = Claim. First explain the meaning of the directed g element in this embodiment. (1) Node: indicates a point in a directed graph, which corresponds to a server device in the system; (2) Directed edge: indicates that it exists in a directed graph. The directed edge between two nodes 'corresponds to the service request that the system has received' whose direction is the node corresponding to the actual servo device (described later) of this service request, pointing to the server device to be updated for this service request ( Nodes described later). Figure 6 shows a schematic of a directed edge structure. In Fig. 6, the nodes (40, 42) at both ends represent the actual servo device of the service request A (41) and the servo device to be updated. The situations shown in the figure are the servo devices S1 and S3, respectively. The actual servo device refers to the servo device that was originally allocated to the service request a by the system. The server device to be updated is another server device in the system, which means that if the service request A is changed to be served by the server device to be updated

C:\ProgramFiles\Patent\0356-3848-E.ptd第 Π 頁 五、發明說明Q4) =要的,衝區數量,會低於由實際伺服裝置進行服務時所 的要的緩衝區數量。將系統内的所有服務要求均以個別有 向邊加以表示時,就可以構成系統對應的有向圖。 以下則根據第7圖所示的系統服務要求狀態,來說明 上述的有向邊和有向圖的觀念。第7圖中所採用的符號與 上述=2〜5圖相同,此處不再贅述。在第7圖中伺服裝置 S1包含服務要求A和服務要求E,伺服裝置S2包含服務要求 j服裝置S3包含服務要求c,飼服裝置S4包含服務要求 \。每個服務要求分別配置了 2到3個緩衝區,在每個緩衝 ,串列中,最左邊代表目前客戶端所消耗(或使用)的資料 區,,例如服務要求A中的第2個資料區塊;最右邊則代表 ^ 正^過實際词服裝置所讀取的資料區&,例如服務要 求A的第4個資料區塊。 以服務要求A為例說明。服務要求A目前是由伺服裝置 際伺服裝置)所服務。在目前服務週期内,服務要求 A疋透過飼服裝置81讀取儲存在儲存裝置Hm的第*個資料 二鬼次Μ在r此同時,客戶端則正在使用事先讀入緩衝區的第 2個貝料區塊。換言之,服務要求人所對應的緩衝區串列包 3 了二塊緩衝區,其中一個是客戶端正在存取的緩衝區 括即第Λ個’其他兩個則是事先儲存的緩衝區(包 括第3個和第4個資料區塊)。 括下=服Ϊ要求Α所對應的可能待更新伺服裝置,包 ί Π = 2是待更新伺服裝置是設定在伺服裝置 ’此時衝區數量由3個變成2個’這是因為不需要儲C: \ ProgramFiles \ Patent \ 0356-3848-E.ptd page Π 5. Description of the invention Q4) = Yes, the number of punching areas will be lower than the number of buffers required by the actual servo device for service. When all service requirements in the system are represented by individual directed edges, a directed graph corresponding to the system can be constructed. The following describes the concept of directed edges and directed graphs based on the system service request status shown in Figure 7. The symbols used in Figure 7 are the same as those in Figures 2 to 5 above, and are not repeated here. In FIG. 7, the servo device S1 includes a service request A and a service request E, the servo device S2 includes a service request j, the service device S3 includes a service request c, and the feeding device S4 includes a service request \. Each service request is configured with 2 to 3 buffers. In each buffer and series, the leftmost represents the data area consumed (or used) by the current client, such as the second data in service request A. Block; the rightmost represents the data area & read by the actual word server, such as the fourth data block of service request A. Take service request A as an example. Service request A is currently served by a servo device. In the current service cycle, the service request A 疋 reads the * th data stored in the storage device Hm through the feeding device 81. At the same time, the client is using the second data read into the buffer in advance. Shell material block. In other words, the buffer queue corresponding to the service requester contains two buffers, one of which is the buffer being accessed by the client, namely the Λ ', and the other two are the buffers stored in advance (including the first 3 and 4 data blocks). The following are the possible pending servo devices corresponding to the service request A, including ί Π = 2 is the servo device to be updated, which is set in the servo device ’The number of punching areas changed from 3 to 2’ This is because no storage is required

五'發明說明(15) 存第4個資料區塊的緩衝區。第2種是待更 定在伺服裝置S3,此時為最佳化的情況巧= 可以由3個變成^ ’也就是不需要儲存任何預數量 移資料區塊。在此種最佳化情況下的待更新伺服裝買:的: 實可以根據服務要求Λ目前正在消耗的資料區塊,β 在目前由那個伺服裝置所存取的儲存裝置,而此疋·子 即為所需要的待更新伺服裝置。在本實施例中,主a 、 最佳化的情況說明,但是對於熟知此技藝者而+要是以 據實際之需要來選擇待更新伺服裝置。因此,ς務=I根 會對應於由伺服裝置S1指向伺服裝置S3的有向邊。要求Α 根據與上述服務要求A相同的處理模式,可 4 Μ決定料 應於其他服務要求的有向邊,如第8圖所示的有向 中,服務要求Β對應於由伺服裝置S2指向伺服裝置Si的= 向邊’服務要求C對應於由伺服裝置S3指向伺服裝置Sl 有向邊,服務要求D對應於由伺服裝置S4指向伺^裝置$ 的有向邊’服務要求E則對應於由伺服裝置S1指向 置S4的有向邊。 °服裝 根據類似於第8圖的有向圖,可以直接觀家屮点 . 。π m母個服 務要求可以進行要求遞移處理的條件。基本上,翠_有。 邊並不能構成要求遞移的要件。如前所述,在進杆並七、& Ί丁要來 移時,除了必須達到減少緩衝區數量的效果之外,還需要 維持系統原有的負載平衡。因此在本實施例中,σ ^ w /、計對構 成服務要求迴圈序列的服務要求,進行要求遞移,以便維 持負載平衡。一個服務要求迴圈序列在有向圖上為_迴圈Five 'invention description (15) buffer area for storing the fourth data block. The second type is to be changed in the servo device S3, which is an optimized situation at this time. It can be changed from 3 to ^ ', that is, it does not need to store any pre-quantity data block. In this optimization case, the servo server to be updated is: according to the service request, the data block currently being consumed, β is the storage device currently accessed by that servo device, and this It is the required servo device to be updated. In this embodiment, the main situation a and optimization are described, but for those who are familiar with this skill, + if the servo device to be updated is selected according to actual needs. Therefore, the service = I root will correspond to the directed edge pointed by the servo device S1 to the servo device S3. Request A According to the same processing mode as the above service request A, 4M can decide that it should be on the directed edge of other service requests. As shown in Figure 8, the service request B corresponds to the servo device S2 pointing to the servo. For device Si = directed edge, service request C corresponds to directed edge from servo device S3 to servo device Sl, and service request D corresponds to directed edge directed from servo device S4 to servo device $. Service request E corresponds to Servo device S1 points to the directed edge of S4. ° Clothing According to a directed graph similar to that in Figure 8, you can directly look at the house. π m mother and child service requirements can be performed under conditions that require recursive processing. Basically, Cui_has. Edges do not constitute a requirement for transfer. As mentioned earlier, when you move forward and move forward, in addition to the effect of reducing the number of buffers, you also need to maintain the original load balance of the system. Therefore, in this embodiment, σ ^ w / is used to calculate the service requirements that constitute the service request loop sequence, and the requirements are shifted in order to maintain load balance. A service requires the loop sequence to be a _loop on a directed graph

c:\Program Files\Patent\0356-3848-E.ptd第 19 頁 五、發明說明(16) 40^700 ' 形式,例如在第8圖中包含服務要求a、c的迴圈以及包 服務要求B、E、D的迴圈。在符合的服務要求迴圈序列 中,每個服務要求的實際伺服裝置,會與前一個服務要 的待更新词服裝置相同;另一方面’每個服務要求 新伺服裝置亦與下一個服務要求的實際伺服裝置相同。合 發現這樣的服務要求迴圈序列時,可以將每個服務要求二 待更新伺服裝置’變更為實際伺服裝置,亦即轉移各服務 要求所在的伺服裝置。藉此,整體所需要的緩衝區數量就 可以減少,達到本發明的目的。 以下根據第8圖中所示的兩個迴圈,分別以兩個範例 來說明要求遞移的處理。 第一範例: 第9圖表示第一範例之服務要求迴圈序列(包含服務要 求A、C)在要求遞移處理前的系統簡化示意圖,第丨〇圖則 疋經過要求遞移處理後的系統簡化示意圖。如第9圖所 示’目前服務要求A是由伺服裝置S1進行服務,而服務要 求C是由伺服裝置S 3進行服務,兩個服務要求目前各使用 三塊緩衝區。另外由第9圖可以發現,服務要求a目前正在 消耗儲存裝置HD3上所儲存的第2個資料區塊,而目前儲存 裝置HD3正由伺服裝置S3所存取,根據上述的定義,可以 決定祠服裝置S3為服務要求A的待更新飼服裝置。另一方 面,服務要求C目前正在消耗儲存裝置hdi上所儲存的第〇 個資料區塊,而目前儲存裝置HD1正由伺服裝置S1所存 取,根據上述的定義,可以決定伺服裝置S1為服務要求cc: \ Program Files \ Patent \ 0356-3848-E.ptd page 19 5. Description of the invention (16) 40 ^ 700 'form, for example, Figure 8 contains the service requirements a, c loop and package service requirements B, E, D loops. In the compliant service request loop sequence, the actual servo device for each service request will be the same as the server to be updated for the previous service; on the other hand, each new service device for each service request is also the same as the next service request. The actual servos are the same. When we find such a service request loop sequence, we can change the server device to be updated for each service request to the actual server device, that is, transfer the server device where each service request is located. Thereby, the total number of buffers required can be reduced, and the object of the present invention is achieved. Following the two loops shown in Figure 8, the following two examples are used to illustrate the process of requesting recursion. First example: Figure 9 shows the simplified system schematic diagram of the service request loop sequence (including service requirements A and C) before the request relocation process in the first example, and Figure 丨 the system after the request relocation process Simplified diagram. As shown in FIG. 9 ', the current service request A is served by the server S1, and the service request C is served by the server S3. The two service requests currently use three buffers each. In addition, it can be found from FIG. 9 that the service request a is currently consuming the second data block stored on the storage device HD3, and the current storage device HD3 is being accessed by the servo device S3. According to the above definition, the temple can be determined The serving device S3 is a feeding device to be updated with service request A. On the other hand, the service request C is currently consuming the 0th data block stored on the storage device hdi, and the current storage device HD1 is being accessed by the servo device S1. According to the above definition, the servo device S1 can be determined as a service Requirement c

C:\ProgramFiles\Patent\0356-3848-E. ptd第 20 頁C: \ ProgramFiles \ Patent \ 0356-3848-E. Ptd page 20

五、發明說明(17) 4〇2?〇〇 的待更新伺 會構成有向 因此, 際伺服裝置 的實際伺服 週期内即如 會輪換到儲 客戶端目前 緩衝區即可 換到儲存裝 戶端目前正 緩衝區即可 要的六個資 平衡的條件 服裝置。此時,對應 圖上的迴圈。 在目前的服務週期内 ’改變設定成伺服裝 裝置’改變設定成伺 第10圖所示的情況, 存裝置HD4,讀取第3 正在消耗的資料區塊 。另一方面,服務要 置HD2,讀取第1個資 在消耗的資料區塊, 。透過上述的資料遞 料區塊,減少成兩個 並未改變。 於服務要求A、C的有向邊 ’可以將服務要求A的實 置S3,同時將服務要求c 服裝置S1。在下一個服務 服務要求A的伺服裝置S3 個資料區塊,同時這也是 ,所以整個只需要單一個 求c的伺服裝置S1則會輪 料區塊,也因為這正是客 所以整個也只需要單一個 移動作,可以將原本所需 資料區塊,同時系統負載 第二範例: 第二範例與第一範例不同之處,在於迴圈内的服務要 求數量。第11圖表示第二範例之服務要求迴圈序列(包含 服務要求B、D、E)在要求遞移處理前的系統簡化示意圖, 第1 2圖則是經過要求遞移處理後的系統簡化示意圖。如第 11圖所示,目前服務要求B、d、E分別由伺服裝置S2、 S4、S1進行服務’同時分別使用了 2、3、2塊緩衝區。透 過各服務要求的客戶端所正在消耗的資料區塊,可以決定 出其對應的待更新伺服裝置分別為S 1、S2、S4。同樣地, 對應於服務要求B、D、E的有向邊會構成有向圖上的迴V. Description of the invention (17) The server to be updated from 40 to 200 has a direction. Therefore, if the actual servo cycle of the international servo device is rotated to the storage client, the current buffer can be changed to the storage client. Currently six buffered condition service devices are available in the buffer zone. At this time, it corresponds to the loop on the graph. In the current service cycle, the ‘change setting is set to servo device’ is changed to set the server as shown in FIG. 10, the device is stored in HD4, and the third data block being consumed is read. On the other hand, the service requires HD2 to read the first data block consumed by the data. Through the above-mentioned data delivery block, the reduction was reduced to two unchanged. For the directed edges of service request A and C, the service request A can be implemented with S3 and the service request c can be served with device S1. In the next service, the servo device S3 data block of A is required, and this is also the same, so only a single servo device S1 that needs to find c will rotate the block, and because this is exactly the customer, the whole need only be a single A mobile operation can load the originally required data blocks while the system loads the second example: The second example differs from the first example in the number of service requests in the loop. Figure 11 shows the simplified system schematic diagram of the service request loop sequence (including service requirements B, D, and E) before the request relocation process in the second example, and Figure 12 is the simplified system schematic diagram after the request relocation process. . As shown in FIG. 11, the current service requirements B, d, and E are serviced by the servo devices S2, S4, and S1, respectively. At the same time, 2, 3, and 2 buffers are used. Based on the data blocks being consumed by the clients required by each service, it can be determined that the corresponding servo devices to be updated are S1, S2, and S4, respectively. Similarly, the directed edges corresponding to the service requirements B, D, E will constitute a return on the directed graph.

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五、發明說明(18) 圈。 所以、如果在目刖的服務週期内將將服務要求B、D、 E進行要求遞移,設定在其對應的待更新词服裝置,則在 下一個:務週期内即如第12圖所示的情況。服務要求b的 新伺服裝置si會輪換到儲存褒置HD2,讀取第5個資料區 塊;服務^求D的新伺服震置S2會輪換到儲存裝置hd3,讀 3 VI〗料!塊二服務要求E的新伺服裝置S4會輪換到儲 存裝ίΓ 取第4個資料區塊。這些都是客戶端正在消 耗的資料區塊’所以只需要單一個緩衝區即可。透過上述 的資料遞移動作’可以將原本所需要的七個資料區塊 少成二個資料區塊’同時系統負載平衡的條件並未改變。 ,根據以上所述可知,透過要求遞移的方式的確能夠 少緩衝區的數量,同時兼顧負載平衡。目前僅剩下的問 是如何在有向圖上找尋迴圈,因為如果系統的服務要求非 常多,可以想見的是系統必須付出額外的計算時間 (computing time)在有向圖中尋找迴圈,這對於初始 會有相當程度的影響,所以為了確保系統服務具有低f 延遲的特性’有必要降低其複雜度。 ° 當一個新的服務要求加入時,為了負載平衡,此 有幾個可能的伺服裝置,符合服務此服務要求的條· 系統則會配置一實際伺服裝置給新加入的服務要求◊另一 方面’因為影片的第〇個資料區塊所在之儲存裝置是確— 並且唯一(在不使用資料複製的情形下),而此服務要心 入的那一個服務週期中,在讀取第〇個資料區塊的儲存~V. Description of the invention (18) circle. Therefore, if the service requirements B, D, and E are recursively requested during the current service cycle, and set to the corresponding server to be updated, then in the next: service cycle, as shown in Figure 12 Happening. The new servo device si of service request b will be rotated to the storage device HD2 and read the fifth data block; the new servo device S2 of service ^ for D will be rotated to the storage device hd3 and read 3 VI. The new servo device S4 of block two service request E will rotate to the storage device Γ to take the fourth data block. These are the data blocks that the client is consuming, so only a single buffer is needed. Through the above-mentioned data transfer operation, “the seven data blocks originally required can be reduced to two data blocks” and the conditions for system load balancing have not changed. According to the above, it can be known that the number of buffers can be reduced through the method of requesting shifts, while taking into account load balancing. The only remaining question is how to find the loops on the directed graph, because if the system has a lot of service requirements, it is conceivable that the system must pay extra computing time to find the loops in the directed graph. This will have a considerable impact on the initial stage, so it is necessary to reduce its complexity in order to ensure that the system service has the characteristics of low f latency. ° When a new service is requested to join, for load balancing, there are several possible servo devices that meet the requirements for serving this service. The system will configure an actual servo device to the newly added service request. On the other hand, ' Because the storage device for the 0th data block of the movie is indeed — and the only one (without the use of data replication), and in the service cycle that the service wants to focus on, the 0th data area is read Block storage ~

4Q27Q0 五、發明說明(19) 置之伺服器也是確定的,所 裝置是在加入時就可決定。 用一種深度優先(depth fir 理。如前所述,系統中的允 (administrate/dispatch s 時,立即配置其實際的伺服 裝置為已知。接著則可以透 圈,亦即以新加入服務要求 以系統所指定的實際伺服裝 待更新伺服裝置處為起點、 向邊組成的有向路控(d i r e c 務要求的加入將會形成一有 理’使得迴圈内所有服務要 的0 另外,本實施例亦同時 圖。第一、有向圖中只記錄 務要求’也就是有用來預存 僅使用一個緩衝區的服務要 能同時包含有數千或數萬個 同服務要求卻呈現相同的有 僅以單一有向邊來表示複數 務要求可以消去某個迴圈時 向邊上加以刪除,並且如果 求所形成之有向邊僅具有此 以實際伺服裝置和待更新伺服 根據此一關係,本實施例中採 st)搜尋的方式來進行搜尋處 許/分配伺服器 erver)會在收到新服務要求 裝置,換言之’此時實際伺服 過深度優先搜尋方式來找出迴 的待更新伺服裝置為根,並且 置為終點,若可以找到一條從 以實際伺服裝置為終點,由有 ted path),則可知此一新服 向迴圈’再利用要求遞移的處 求都可以達到減少緩衝區的目 採用了其他方式來簡化有向 目前使用兩個以上緩衝區的服 的偏移緩衝區,並不需要記錄 求。第二、在複雜系統中,可 服務要求,因此很可能出現不 向邊之情况。此時,本實際例 個服務要求,而當新加入之服 ,就將其中某個服務要求在有 在原來的有向圖中,該服務 一服務要求時,則消去該有向4Q27Q0 V. Description of the invention (19) The server to be installed is also determined, and the device can be determined upon joining. Use a depth-first principle. As mentioned earlier, when the system allows / administrates / dispatch s, it immediately configures its actual servo device as known. Then it can pass through the circle, that is, by adding a new service request to The actual servo device designated by the system is the starting point of the servo device to be updated, and the direction is composed of directed road control (the addition of the direc service request will form a rational 'so that all the services in the loop will be 0. In addition, this embodiment also Simultaneous graphs. First, the directed graph only records service requirements', that is, there is a service that uses only one buffer to pre-store and can contain thousands or tens of thousands of the same service requirements but present the same. It indicates to the edge that the complex service request can be deleted on the edge when a certain loop is eliminated, and if the directed edge formed only has this, the actual servo device and the servo to be updated are based on this relationship. In this embodiment, st) The search method to search for the allocation / server erver) will receive the new service request device, in other words' At this time the actual servo is too deep-first search party To find the back-to-be-updated servo device as the root and set it as the end point, if you can find a path from the actual servo device as the end point (there is a ted path), then you can know that this new service moves to the loop 'reuse request. All the requirements can be achieved by reducing the buffer. Other methods are used to simplify the offset buffer of the server that currently uses more than two buffers, and there is no need to record the request. Second, in complex systems, serviceability is required, so it is very likely that the situation will not go to the side. At this time, this actual example is a service request, and when a new service is added, one of the service requirements is in the original directed graph. When the service is a service request, the directed service is cancelled.

發明說明(20) 第1 3圖表示某一系統中現有服 飼服裝置SH4間具有服務要求A〜p要向圖,其中 某些有向邊,例如從伺服裝置S4指 4圖中有向圖 求C、D、N,可以簡化成一個有 服裝置S1的服務 即表示經過簡化後之有向圖。 ,’,,代表,第1 4圖 此時’假設一個服務要求Q準備 載平衡历目彳所晰f W +筒加入服務,如果根據 戰十衡原則所配置的實際伺服裝f 服務週期β,伺服裝置S4正服Is2,並且假設在此 在裝署n 務存有第個資料區塊的儲 為根二二後土司服裝置為S4)’則可以由词服裝置 ==優先搜尋’直到找到所配置的實際词服裝 阁為士。第15圖表示此一深度優先搜尋的搜尋樹狀態 1先從@服裝置S4向飼服裝置Slit行搜尋(有向邊為 務要求C、D、N) ’但是從伺服裝置以沒有其他有向邊指 ,因此中止此部分的搜尋。接著再從伺服裝置S4向伺服 置S2進行搜尋(有向邊為服務要求E、j、p)。此時已經 到實際飼服裝置S2,所以完成此搜尋,如第14圖和第15 所示。由於新加入的服務要求q和原來的服務要求E、 、P會構成一迴圈’所以可以透過上述要求遞移的處理, 減少所需要的緩衝區數量。Description of the invention (20) Fig. 13 shows that there are service requirements A ~ p in the existing feeding and feeding device SH4 in a certain system, and some directed edges, for example, the servo device S4 refers to the directed graph in Fig. 4 Finding C, D, and N can be simplified into a service of the service device S1, which means a simplified directed graph. ",", Representative, Figure 14 at this time. "Suppose a service requires Q to prepare a load balance history, as shown in fW + tube to join the service. If the actual servo is configured according to the ten-balance principle, the service cycle β, Servo device S4 is serving Is2, and it is assumed here that the storage of the first data block in the deployment n service is root. After two toast service devices are S4), then the word service device == priority search until it is found. The actual word clothing court is configured as a taxi. Figure 15 shows the state of the search tree for this depth-first search. First search from @ 服装 置 S4 to the feeding device Slit (directed edge is required for services C, D, N) 'but from the servo device there is no other directed Edge finger, so the search for this part was stopped. Then search from servo device S4 to servo device S2 (directed edges are service requests E, j, p). At this point, the actual feeding device S2 has been reached, so this search is completed, as shown in Figures 14 and 15. Since the newly added service request q and the original service request E,, P will form a circle ', the number of buffers required can be reduced through the processing of the above-mentioned request transfer.

另外’在以上所說明者雖然是以深度優先法則,來找 出新加入服務要求在有向圖中所構成的迴圈,但是並非用 以限定其範圍。應用時亦可以採用其他的搜尋法則來決定 负加入服務要求的實際伺服裝置,甚至可以在找出數個IIn addition, although the above description is based on the principle of depth first to find the loop formed by the newly added service request in the directed graph, it is not intended to limit its scope. In the application, other search rules can also be used to determine the actual servo device that negatively joins the service request. It can even find several I

C:\ProgramFiles\Patent\0356-3848-E.ptd第 24 頁 -402700 ______ 五'發明說明(21) -- ,構成迴圈的情況’再選用其中減少最多緩衝區數量的迴 圈。然而,、過多的計算可能會導致延遲時間加長,因此實 、際應用時可以根據操作環境和需要來決定找尋迴圈的方 根據以上所述,本發明的優點是在於維持負載平衡的 條件下,可以大量減少系統的緩衝區數量。以下以一實例 來說明透過要求遞移所可以達到的效果。在此實例中,影 片的總長度為36 00個服務週期,亦即分割成36〇〇個資料^ 塊分別儲存在儲存裝置中。假設伺服裝置的數量為丨6個, 而從客戶端來的服務要求呈現p〇 i ss〇n分佈,此時服務要 求總量和緩衝區數量間關係如第丨6圖所示。在第丨6圖中, a表示採用分散式頻寬處理但是尚未進行要求遞移時的情 況,b表示進行要求遞移後的情況。由圖可知,在服務要 求數量不高時,兩者的差別並不大,但是當服務要求數量 、增多時,兩種情況中所需要的緩衝區數量就會出現明顯的 區別。由此可余口,本發明對應高負載的系統具有相當優異 本發明雖以一較佳實施例 定本發明’任何熟習此項技藝 和範圍内,當可做些許的更動 範圍當視後附之申請專利範圍 揭露如上,然其並非用以限 者’在不脫離本發明之精神 與潤飾,因此本發明之保護 所界定者為準。C: \ ProgramFiles \ Patent \ 0356-3848-E.ptd page 24 -402700 ______ Five 'invention description (21)-, the case of forming a loop ’Then select the loop in which the maximum number of buffers is reduced. However, too many calculations may lead to a longer delay time. Therefore, in actual and practical applications, the party to find the loop can be determined according to the operating environment and needs. According to the above, the advantage of the present invention is that the load balance is maintained. Can greatly reduce the number of system buffers. The following uses an example to illustrate the effect that can be achieved by requesting recursion. In this example, the total length of the movie is 36,000 service cycles, that is, it is divided into 3600 pieces of data ^ and stored in the storage device. Assume that the number of servo devices is six, and the service requirements from the client have a poisson distribution, and the relationship between the total number of service requirements and the number of buffers is shown in Figure 6-6. In Fig.6, a indicates the situation when distributed bandwidth processing is used but the required retransmission has not yet been performed, and b indicates the case after the required retransmission has been performed. As can be seen from the figure, when the number of service requirements is not high, the difference between the two is not large, but when the number of service requirements increases, the number of buffers required in the two cases will obviously differ. Therefore, it can be said that the system corresponding to the high load of the present invention is quite excellent. Although the present invention is based on a preferred embodiment, the present invention can be used within any skill and scope of the present invention. The patent scope is disclosed as above, but it is not intended to limit the scope of the invention without departing from the spirit and decoration of the present invention. Therefore, the protection defined by the present invention shall prevail.

Claims (1)

六、申請專利範圍 1 .—種服務要求配置方法,可適用於一以循環方 儲存的系統中’上述系統包括複數儲存裝置,用以依:循 環方式儲存一資料之複數資料區塊,以及至少一伺服裝 置,用以輪流存取上述儲存裝置,依序讀取上述資料^ 塊;每一資料存取服務要求分別由上述伺服裝置中之二 際伺服裝置進行服務,並且對應於包含至少一緩衝區塊之 緩衝區塊串列,用以分別儲存正在消耗之目前資料區塊以 及預先讀取之偏移資料區塊,其包括下列步驟: 分別決定上述服務要求所對應之待更新伺服裝置,其 中上述服務要求由上述待更新伺服裝置進行服務時所需^ 偏移資料區塊數量,低於由上述實際伺服裝 所需的偏移資龍塊數量; 根據上述服務要求所分別對應之實際伺服裝置和待更 新伺服裝置,搜尋出包含部分上述服務要求之服務要求迴 圈序列,上述服務要求迴圈序列中某一服務要求的實際伺 服裝置與前一服務要求的待更新伺服裝置相同,其待更新 祠服裝置與後一服務要求的實際伺服裝置相同;以及 調整上述服務要求迴圈序列中之每一服務要求的實際 祠服裝置,成為其對應之待更新伺服裝置。 2 .如申請專利範圍第1項所述之服務要求配置方法, 其中每一服務要求所對應的待更新伺服裝置,係為上述服 務要求由上述待更新伺服裝置進行服務時,所需的偏移資 料區塊數量為零者。 3·如申請專利範圍第2項所述之服務要求配置方法,6. Scope of Patent Application 1. A service request configuration method can be applied to a system that is stored on a circular basis. The above system includes a plurality of storage devices for storing a plurality of data blocks of a data in a cyclic manner, and at least A servo device is used to access the storage device in turn, and sequentially read the data ^ blocks; each data access service request is served by a second servo device among the above-mentioned servo devices, and corresponds to including at least one buffer. The buffer block sequence of the block is used to store the current data block that is being consumed and the offset data block that is read in advance, which includes the following steps: Determine the server device to be updated corresponding to the above service request, where The above service requires that the number of offset data blocks required by the above-mentioned servo device to perform the service is lower than the number of offset asset blocks required by the above-mentioned actual servo device; according to the actual service device corresponding to the above service request, respectively And the server device to be updated, and search for a service request loop sequence including part of the above service requests. The actual servo device of a service request in the service request loop sequence is the same as the server device to be updated of the previous service request, and the service server to be updated is the same as the actual server device of the latter service request; and the above service request loop is adjusted Each actual service device required by each service in the sequence becomes its corresponding servo device to be updated. 2. The service request configuration method described in item 1 of the scope of patent application, wherein each of the service devices to be updated corresponding to the service request is an offset required when the above service request is served by the server to be updated. The number of data blocks is zero. 3. The service request configuration method described in item 2 of the scope of patent application, C:\Program Files\Patent\〇356-3848-E.ptd第 26 頁C: \ Program Files \ Patent \ 〇356-3848-E.ptd page 26 六、申請專利範園 正在存取之儲存裝置,存 串列中目前正在使用之資 述之服務要求配置方法, 上述伺服裝置各以節點表 的實際伺服裝置以及待更 務要求、並且由上述實際 待更新伺服裝置所對應之 中’係根據上述有向邊是 務要求迴圈序列。 述之服務要求配置方法, 和待更新伺服裝置之服務 述之服務要求配置方法, 新伺服裝置,係為上述服 行服務時’所需的偏移資 i t亡述待更新伺服裝置所目前 放者在上述服務要求 料區塊。 戈衝&塊 其中V:括申請專利範圍第1項所 其中尚包括-設定步驟,將每一 不’並且分別根據每一服務要求 新伺服裝置,設定對應於上述服 词服裝置所對應之節點指, 節點的有向邊;在上述搜以 否構成有向迴圈,搜尋出上述服 5.如申請專利範圍第4項所 其中對應於相同的實際伺服裝置 要求,係由單一有向邊表示。 如申請專利範圍第4項所 其中母一服務要求所對應的待更 務要求由上述待更新伺服裝置進 料區塊數量為零者。 7·如申請專利範圍第1項所述之服務要求配置方法, 其中尚包括一加入步驟,用以加入一新服務要求,並且根 據一負載平衡法則’決定上述實際伺服裝置;在上述決定 步驟中,決定上述新服務要求所對應之待更新伺服裝置; 在上述搜尋步驟中,根據一搜尋法則,以上述待更新伺服 裝置為根,以上述實際伺服裝置為終點進行搜尋,決定出 包含上述新服務要求之服務要求迴圈序列。6. The storage device that is being accessed by the patent application park, and the service request configuration method currently listed in the list is stored. The above servo devices are each based on the actual server device of the node table and the service request to be updated. The corresponding to the servo device to be updated is a loop sequence according to the above-mentioned directed edge service. The service request configuration method described above and the service request configuration method of the server device to be updated. The new server device is the required offset data for the above-mentioned service. The above service requires material blocks. Ge Chong & block of which V: including the first scope of the patent application scope which also includes-setting steps, each new 'and each new service device according to each service request, setting corresponding to the above service server Node refers to the directed edge of the node. In the above search, whether the search constitutes a directed loop, and the above service is found. 5. As described in item 4 of the scope of patent application, which corresponds to the same actual servo device requirement, it consists of a single directed edge. Means. As mentioned in item 4 of the scope of patent application, the waiting service corresponding to the parent service request requires the number of blocks to be updated by the servo device to be updated to be zero. 7. The service request configuration method as described in item 1 of the scope of patent application, which further includes an adding step for adding a new service request, and determining the above-mentioned actual servo device according to a load balancing rule; in the above-mentioned determining step To determine the servo device to be updated corresponding to the new service request; in the above search step, according to a search rule, the search is performed with the to-be-updated servo device as the root, and the actual servo device as the end point to search to determine that the new service is included The requested service requires a loop sequence. C:\ProgramFiles\Patent\0356-3848-E.ptd第 27 頁 六、申請專矛祕— 8 ·如申請專利範圍第7項所述之服務要求配置方法, 其中在上述搜尋步驟中,搜尋出包含上述新服務要求之服 務要求迴圈彳列的數量㈣一個寺,係根據經調整步 驟後能夠減少最多偏移資料區塊數量之法則’決定 行上述調整步驟之服務要求迴圈序列。 9 .如申請專利範圍第8項所十 其中每一服務要求所對應的待更新 務要求配置方法, 務要求由上述待更新伺服裝置進一司服裳置’係為上述服 料區塊數量為零者。 仃服務時,所需的偏移資C: \ ProgramFiles \ Patent \ 0356-3848-E.ptd page 27 6. Application for special secrets — 8 · The service request configuration method described in item 7 of the scope of patent application, where in the above search step, search out The number of service request loop queues containing the above-mentioned new service requirements is based on a rule that determines the service request loop sequence for the above adjustment steps according to the rule that the maximum number of offset data blocks can be reduced after the adjustment steps. 9. According to the service request configuration method corresponding to each of the service requirements in item 8 of the scope of the patent application, the service request is configured by the server to be updated, which means that the number of service blocks is zero. By.仃 The required offset data when serving C:\ProgramFiles\Patent\0356-3848-E. ptd第 28 頁C: \ ProgramFiles \ Patent \ 0356-3848-E. Ptd page 28
TW87117463A 1998-10-22 1998-10-22 Method of allocating the service request TW402700B (en)

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