SU1522386A1 - Generator of magnetic scanning - Google Patents

Abstract

The invention relates to a pulse technique and can be used in information display devices with magnetic beam deflection. The aim of the invention is to increase the reliability of the generator by excluding from the circuit a powerful transistor switch and introducing a switch. The generator contains an amplifying element 1, an input 3, a deflection coil 5, a switch 7, the input 8 of which is connected to the second output of the deflection coil, the first output 9 to the non-inverting input of the amplifying element, and the second output 10 to its inverting input, the input 11 of the switch with control bus, resistors 2, 4, 6 and 12. 1 sludge.

Description

(L

. . 315

The invention relates to a pulse technique and can be used, for example, in information display devices with magnetic beam deflection.

The purpose of the invention is to increase the reliability of the device by excluding from the circuit a powerful transistor switch.

On. Figure 1 shows the structural electrical circuit of the device; FIG. 2, epics explaining his work.

Magnetic Sweep Generator

VC

at

women Since the voltage at the inverting input is equal to pa; the voltage across the resistor 6, the divergence current i, flowing through the resistor 6, must be zero. The input voltage value U does not have this value.

At time t ;, (FIG. 2a), the voltage Ijjnp takes on the value of logical 1, the second output of the commutator is disconnected from its input, and the first output is connected. Now the scheme is positive about

holds the amplifying element I, invert-5 connection over current I with resistor 6

thirty

35

tATING input which through the first resistor 2 is connected to the signal input 3 of the device, and through the second resistor 4 -.c output of the amplifier. element 1, which is connected to the first output, deflection coils 5, the second vygeod of which through the third resistor 6 is connected to the common bus of the device, switch 7, input 8 of which is connected to the second output of the deviation coil 5, first output 9 - to a inverting input the amplifying element, the second output with its inverting input, and the control input 11 with the control bus of the device, and the resistance value of the first and second resistors is the same. The reinforcement element can be made, for example, on the basis of the 544UD2B chip, a switch based on the 564КП1.

The device works as follows

In the initial state, the signal at the control input is equal to logical O () and the input 8 of the switch 7 is connected to the second output 10 of the switch and the upper (FIG. 1) output of the resistor 6 is closed to the inverting input of the amplifying element I Non-inverting input of the amplifier through the output the resistance of the first output 9 of the switch (in FIG. 1 is shown as a resistor 12) is connected to a common bus. At the same time, the non-inverting input voltage of the amplifying element 1 is zero, and the inverting input is connected to the upper output of the resistor 6. Due to the negative feedback, the amplifying element 1, the gain of which is large, will maintain the voltage on the inverting input equal to the voltage non-inverting input, i.e. voltage total

to the non-inverting input of the amplifying element I and negative feedback for the voltage from the output of element 1 to its inverting input. The output voltage of amplifying element 1 is now equal to the sum of the inverted voltage UgK (the resistances of resistors 2 and 4 are the same and the transfer coefficient for the signal U is 25 minus one) and twice the voltage on resistor 6 (the transfer coefficient for the non-inverting input of the amplifying element 1 is two ). Since the resistance of the resistor 6 is chosen equal to the active resistance of the coil 5, the voltage applied to the inductance of the coil 5 is exactly equal to the input voltage Ug .. Since the current through the ideal inductance is proportional to the integral over time of the voltage t on / inductance, then starting from the moment t. current I begins to change as in45

50

55

tagged off - and

8X

40

No) --- s

UBX df,

where L is the inductance of the deflection coil 5.

Fig. 26 shows the voltage Ue, x is negative and constant in the interval. Outside this interval, it is equal to zero. Since in the interval Ugn 0, the current I in this interval is equal to zero (Fig. 2c). In the interval tj-tj, the current I accumulates, that t J (when U is zero), No change. The voltage form Ugj, the output of the amplifying element 1 is shown in Fig. 2d. It is equal to:

BS

and starting from the moment it becomes equal

exit ujx

+ 2IR

6

where Rg is the resistance of the resistor 6.

0

five

0

to the non-inverting input of the amplifying element I and negative feedback for the voltage from the output of element 1 to its inverting input. The output voltage of amplifying element 1 is now equal to the sum of the inverted voltage UgK (the resistances of resistors 2 and 4 are the same and the transfer coefficient for signal U is 5 minus one) and twice the voltage on resistor 6 (the transfer coefficient for non-inverting input of amplifying element 1 is two ). Since the resistance of the resistor 6 is chosen equal to the active resistance of the coil 5, the voltage applied to the inductance of the coil 5 is exactly equal to the input voltage Ug .. Since the current through the ideal inductance is proportional to the time integral of the voltage t / inductance, then starting from the moment t. the current I begins to change as an integral of - and

8X

40

No) --- s

UBX df,

five

0

five

where L is the inductance of the deflection coil 5.

Fig. 26 shows the voltage Ue, x is negative and constant in the interval. Outside this interval, it is equal to zero. Since in the interval Ugn 0, the current I in this interval is equal to zero (Fig. 2c). In the interval tj-tj, the current I accumulates, that t J (when U is zero), No change. The voltage form Ugj, the output of the amplifying element 1 is shown in Fig. 2d. It is equal to:

BS

and starting from the moment it becomes Ujx

+ 2IR

6

where Rg is the resistance of the resistor 6.

At time t ,, the signal and.

-c P1 ncwi J cpr becomes zero. The switch 7 switches to the initial state and the amplifying element 1. Starts to set the voltage on the resistor 6 to zero. But since the current I of the coil 5 does not immediately decrease, the amplifying element 1 goes into overload mode (due to a too large voltage difference between its inputs), and the maximum negative voltage is set at its output ( fig, 2d). Under the influence of this, if the current I decreases rapidly, the current will not reach zero. The circuit returns to its original state. Form la invention

The magnetic sweep generator, containing an amplifying element, is in-

the rotating input of which through the first resistor is connected to the generator input, and through the second resistor to the output of the amplifying element, to the first output of the deflection coil, the second output of which through the third resistor is connected to the common busbar of the generator, in order to increase the reliability of operation, a switch is inserted into it, the input of which is connected to the second output of the deflection coil, the first output is with the inverting input of the amplifying element, the second, the output is with its non-inverting input, and the control input is with second oscillator control, wherein the resistance value of the first and second resistors is the same.

Claims (1)

Claim A magnetic sweep generator comprising an amplifying element, in10 1522386 6 whose verification input is connected through the first resistor to the generator input, and through the second resistor to the output of the amplifying element, to the first output of the deflection coil, the second output of which through the third resistor is connected to the common generator bus, The reason is that, in order to increase the reliability of operation, a switch is introduced into it, the input of which is connected to the second output of the deflection coil, the first output is with the inverting input of the amplifying element, the second, the output is with its non-inverting input, and the control input is shino generator control, and the magnitude of the first and second resistors is the same