KR20120006823A - A revising control method of heating time in proportion to change rate of indoor temperature - Google Patents

Abstract

PURPOSE: A method for correcting heating time according to room temperature change is provided to minimize unnecessary heating and too little heating. CONSTITUTION: A method for correcting heating time according to room temperature change comprises as follows. The heating operation is determined by comparing a currently measured temperature to a set temperature after heating operation is started(S200). If the temperature difference is higher than a reference temperature difference, a current heating time and the time, when the heating has been performed, are successively calculated(S400,S500). A heating operation correction time is calculated by using the temperature difference and an indoor temperature change rate. The present heating operation time and the heating operation is determined(S700). The present indoor temperature is measured at every minute.

Description

A REVISING CONTROL METHOD OF HEATING TIME IN PROPORTION TO CHANGE RATE OF INDOOR TEMPERATURE}

The present invention relates to a heating time compensation control method according to the room temperature change rate of each room in the heating control system of each room using a temperature measuring cycle, and more particularly, to the room temperature change rate of each room after heating starts, that is, the thermal characteristics of the ondol system. The heating time compensation control method according to the indoor temperature change rate is configured to minimize unnecessary overheating or underheating in each room by controlling the heating time in real time as the change of the indoor temperature is slow or fast due to the change of the external environment. It is about.

In general, the thermostat applied to each room heating system compares the present temperature with the set temperature and stops heating when the present temperature reaches the set temperature, or repeatedly operates and stops the heating at a set time. In addition, these two methods are applied in combination.

However, the conventional heating temperature control method has a problem that causes a sudden change in the room temperature and waste of unnecessary heating heat, in particular, in the case of the heating control method for controlling the heating time according to the temperature difference between the set temperature and the room temperature When measuring indoor temperature, indoor air temperature is measured, not indoor floor temperature.

At this time, when heated by the boiler, the indoor floor warms up and the heat storage gradually warms up the indoor air, and the indoor air goes up after a certain heating time, so the indoor floor temperature must be heated much higher than the set temperature. The temperature will reach the set temperature.

As a result, even if the indoor temperature reaches the set temperature, even if the heating of the boiler is stopped, the indoor air is continuously heated by the heat storage of the indoor floor, resulting in an overheating condition in which the indoor temperature exceeds the set temperature.

Patent No. 371896, developed to improve this conventional problem, sets a temperature measurement period, which is a measurement period of the indoor temperature T1 by a temperature sensor, and then sets the temperature when the indoor temperature T1 is a set temperature T0. Boiler heating is terminated during the measurement period, and if the room temperature (T1) <set temperature (T0), the boiler is heated for the heating time set according to the magnitude of the temperature difference (ΔT). A heating control method using a temperature measurement cycle has been published, which is characterized by controlling the boiler heating to be stopped for a time.

However, the heating control method using the temperature measurement cycle described above does not take into account the characteristics of the ondol system and the rate of change of the indoor temperature during heating due to the change of the external environment, and the heating time is simply determined by the magnitude of the temperature difference (ΔT). There is a problem, such as overcooling or overheating, in which the efficiency is low and the heating time is absolutely insufficient or unnecessarily increased.

In addition, since the heating control method using the temperature measurement cycle described above usually proceeds with a heating operation cycle of 60 minutes, the heating control method cannot adequately cope with various characteristics of each ondol system, and eventually ignores sensitive changes in the room temperature at regular intervals. There is a problem that causes overheating or subcooling of the heating by repeating the heating start and stop.

The present invention was devised to improve the problem of the heating control method using the conventional temperature measuring cycle, and control the heating operation by calculating the heating operation correction time correcting the current heating operation time according to the room temperature change rate after heating operation. Therefore, the object of the present invention is to provide a heating time compensation control method according to the rate of change of indoor temperature, which is configured to prevent unnecessary overheating or underheating.

In order to achieve the above object, the present invention, when heating operation is started in accordance with the heating operation cycle, heating the temperature difference (△ t) between the measured current room temperature (T _c ) and the set temperature (T _s ) compared to the reference temperature difference After the operation is determined, if the temperature difference Δt is greater than or equal to the reference temperature difference, the current heating operation time HT _c , which is the time of heating up to the present, and the room temperature change rate Δt _e are calculated in order, and then the temperature difference △ t) and calculating the heating operation correction time HT _o using the room temperature change rate Δt _e , and comparing the current heating operation time HT _c to determine whether the heating operation is enabled. The heating time compensation control method according to the change rate is provided.

The present invention configured as described above can calculate the accurate heating up time according to the thermal characteristics and external environmental conditions of the ondol system, it is possible to flexibly apply the heating up time, from which unnecessary excessive heating or under-heating It can provide effects such as minimization.

1 is a flow chart illustrating a heating time compensation control method according to the room temperature change rate according to the present invention;
2 is a heating operation graph illustrating a heating operation cycle in the heating time compensation control method according to the room temperature change rate according to the present invention.

Hereinafter, with reference to the accompanying drawings will be described a preferred embodiment of the present invention;

According to one embodiment of the present invention, as shown in FIG. 1, after the heating operation is started, a step (S100) of measuring a present room temperature (T _c ), a set temperature (T _s ), and a present room temperature ( Calculating the temperature difference Δt of T _c ), controlling the heating operation in comparison with the temperature difference Δt and the reference temperature difference 0.5 ° C. (S300), and the current heating operation time HT _c. Calculating the indoor temperature change rate (Δt _e ) at the step S400, the current room temperature (T _c ) -the first room temperature (T _o )] × τ / the current heating operation time (HT _c ) ( S500), setting the heating operation correction time HT _o at Δt [1 + ρ (1-Δt _e )] × τ (S600), the current heating operation time HT _c and the heating operation correction. It is configured to control the heating operation in preparation for the time (HT _o ) (S700).

At this time, the current room temperature (T _c ) is measured every minute, and heating stops immediately if the temperature difference (△ t) between the set temperature (T _s ) and the present room temperature (T _c ) is less than the reference temperature difference of 0.5 ℃ after heating operation. Although controlled, if the reference temperature difference is 0.5 ° C or higher, the heating operation time is continued while the heating operation time is calculated from the heating start to the present to calculate the current heating operation time (HT _c ).

In the present invention, the rate of change of indoor temperature (Δt _e ) is calculated through the formula [current room temperature (T _c ) -first room temperature (T _o )] × τ / current heating running time (HT _c ), In the above formula, τ is a variable of indoor and outdoor thermal environment weights, and normally 10 is applied, but a value less than 10 may be applied when the amount of heat supplied is large, and a value greater than 10 may be applied when the amount of loss due to ambient temperature is large. have.

In other words, τ in the present invention is a variable of weight that is related to the indoor and outdoor thermal environment, that is, the thickness determined by the thickness of the floor and the outside temperature and / or the water temperature to be returned, for example, the measured outside temperature is less than 20 ° C. In the case of being set to a value larger than 10, it can be configured to be automatically controlled so that a value smaller than 10 is set when the measured outside temperature is 20 ° C or more.

Here, the heating operation correction time (HT _o ) in the present invention is calculated through Δt [1 + ρ (1-Δt _e )] × τ, where ρ is a correction rate obtained through experimental data, which is usually 1 Will apply.

Example 1-1

(1) When the initial room temperature (T _o ) is 23 ° C, the set temperature (T _s ) is 25 ° C, and the present room temperature (T _c ) is measured at 23 ° C,

(2) Temperature difference (△ t) = set temperature T _s )-present room temperature (T _c ) = 2 ℃

(3) Since the temperature difference (Δt) = 2 ° C is the reference temperature difference of 0.5 ° C or more,

(4) If the current heating run time (HT _c ) is 10 minutes,

(5) Room temperature change rate (Δt _e ) = [Current room temperature (T _c ) -First room temperature (T _o )] × τ / Current heating run time (HT _c ) = (23 ℃ -23 ℃) × 10 / 20 = 0

(6) Heating operation correction time (HT _o ) = Δt [1 + ρ (1- △ t _e )] × τ = 2 ℃ [1 + 1 (1-0)] × 10 = 40 (min)

(7) The first room temperature (T _o ) and the current room temperature (T _c ) do not change, and the room temperature change rate (Δt _e ) is calculated as "0", so that the room temperature is almost unchanged. In addition, it is interpreted that the heat capacity of the ondol system is very large and little influenced by the change of the external environment from the indoor temperature change rate (Δt _e ) so that the current heating operation time (HT _c ) is 20 minutes. _o ) It means that the current room temperature (T _c ) 23 ℃ can reach the set temperature (T _s ) 25 ℃ only after heating for 40 minutes by 40 minutes.

(Example 1-2)

(1) When the initial room temperature (T _o ) is 23 ° C, the set temperature (T _s ) is 25 ° C, and the present room temperature (T _c ) is measured at 23.5 ° C,

(2) Temperature difference (△ t) = Set temperature T _s )-Present room temperature (T _c ) = 25 ℃ -23.5 ℃ = 1.5 ℃

(3) Since the temperature difference (Δt) = 1.5 ° C is the reference temperature difference of 0.5 ° C or more,

(4) Assuming that the current heating time (HT _c ) is 15 minutes,

(5) Room temperature change rate (Δt _e ) = [current room temperature (T _c )-initial room temperature (T _o )] × τ / current operating time (HT _c ) = (23.5 ° C-23 ° C) x 10 / 15 ≒ 0.33

(6) Heating operation correction time (HT _o ) = Δt [1 + ρ (1- △ t _e )] × τ = 1.5 ° C [1 + 1 (1-0.33)] × 10 ≒ 25 (min)

(7) The first room temperature (T _o ) changes from 23 ° C to the current room temperature (T _c ) 23.5 ° C, and the room temperature gradually changes as the rate of change of the room temperature (Δt _e ) is calculated as "0.33". If the current heating time (HT _c ) is 15 minutes by analyzing the heat capacity and the external environment change of the ondol system from the room temperature change rate (Δt _e ), the heating operation correction time (HT _o ) for 25 minutes Further heating means that the current room temperature (T _c ) 23.5 ℃ can reach the set temperature (T _s ) 25 ℃.

(Example 1-3)

(1) When the initial room temperature (T _o ) is 23 ° C, the set temperature (T _s ) is 25 ° C, and the present room temperature (T _c ) is measured at 24 ° C,

(2) Temperature difference (△ t) = Set temperature T _s )-Present room temperature (T _c ) = 25 ℃ -24 ℃ = 1 ℃

(3) Since the temperature difference (Δt) = 1 ° C is the reference temperature difference of 0.5 ° C or more,

(4) Assuming that the current heating run time (HT _c ) is 10 minutes,

(5) Room temperature change rate (Δt _e ) = [Current room temperature (T _c )-Initial room temperature (T _o )] × τ / Initial heating run time (HT _c ) = (24 ℃ -23 ℃) × 10 / 10 = 1

(6) Heating operation correction time (HT _o ) = Δt [1 + ρ (1- △ t _e )] × τ = 1 ° C [1 + 1 (1-1)] × 10 = 10 (min)

(7) As the current room temperature (T _c ) increases by 1 ° C from the first room temperature (T _o ), the room temperature changes more rapidly as the rate of change (△ t _e ) is calculated from "1". In this case, since the current heating operation time (HT _c ) and heating operation correction time (HT _o ) is 10 minutes, it means that the heating operation should be stopped immediately.

 (Example 1-4)

(1) When the initial room temperature (T _o ) is 23 ° C, the set temperature (T _s ) is 25 ° C, and the present room temperature (T _c ) is measured at 24.5 ° C,

(2) Temperature difference (△ t) = Set temperature T _s )-Present room temperature (T _c ) = 25 ℃ -24.5 ℃ = 0.5 ℃

(3) Since the temperature difference (Δt) = 0.5 ° C is equal to the reference temperature difference of 0.5 ° C,

(4) Assuming that the current heating run time (HT _c ) is 5 minutes,

(5) Room temperature change rate (Δt _e ) = [Current room temperature (T _c )-Initial room temperature (T _o )] × τ / Current heating run time (HT _c ) = (24.5 ℃ -23 ℃) × 10 / 5 = 3

(6) Heating operation correction time (HT _o ) = Δt [1 + ρ (1- △ t _e )] × τ = 0.5 ° C [1 + 1 (1-3)] × 10 = -5

(7) If the room temperature change rate (Δt _e ) is "2" or more, the heating operation correction time (HT _o ) has a value of "━". In this case, it is controlled to stop the heating operation immediately.

Data item Example 1-1 Examples 1-2 Example 1-3 Example 1-4 Initial room temperature (T _o ) 23 ℃ 23 ℃ 23 ℃ 23 ℃ Set temperature (T _s ) 25 ℃ 25 ℃ 25 ℃ 25 ℃ Current room temperature (T _c ) 23 ℃ 23.5 ℃ 24 ℃ 24.5 ℃ Temperature difference (△ t) 2 ℃ 1.5 ℃ 1 ℃ 0.5 ℃ △ t <0.5 ℃ No No No No Heating heating time (HT _c ) 20 minutes 15 minutes 10 minutes 5 minutes Change rate of room temperature (△ t _e ) 0 0.333 1.0 3.0 Heating operation correction time (HT _o ) 40 minutes 25 minutes 10 minutes -5 minutes HT _c 〈HT _o Yes Yes No No Heating operation Operation Operation Immediate stop Immediate stop

Table 1 summarizes the embodiments 1-1 to 1-4 of the present invention, and the ondol from the room temperature change rate Δt _e which is the ratio of the temperature difference Δt and the current heating operation time HT _c . As a result of operating the heating during the current heating operation time (HT _c ) by analyzing the thermal characteristics of the system and changes in the external environment, it is necessary for the current room temperature (T _c ) measured every minute to reach the set temperature T _s ). It is configured to set the heating up time.

That is, the present invention calculates the heating operation correction time (HT _o ) through the calculation formula including the temperature difference (Δt) and the room temperature change rate (Δt _e ) to compare the heating operation time (HT _c ) with the heating operation If the correction time (HT _o ) is large, the heating operation proceeds as much as the difference, but if the heating operation correction time (HT _o ) is less than or equal to the heating operation is configured to stop immediately.

Example 2-1

(1) The initial room temperature (T _o ) is 23 ° C, the set temperature (T _s ) is 25 ° C, the measured current room temperature (T _c ) is 23 ° C, and the outside air temperature 25 ° C (set temperature 20 ° C), return water In the case of temperature 45 degrees Celsius (set temperature 40 degrees Celsius),

(2) Temperature difference (△ t) = set temperature T _s )-present room temperature (T _c ) = 2 ℃

(3) Since the temperature difference (Δt) = 2 ° C is the reference temperature difference of 0.5 ° C or more,

(4) If the current heating run time (HT _c ) is 10 minutes,

(5) Room temperature change rate (Δt _e ) = [Current room temperature (T _c ) -First room temperature (T _o )] × τ / Current heating run time (HT _c ) = (23 ℃ -23 ℃) × 10 / 20 = 0

(6) τ is a variable of weight that is related to the indoor and outdoor thermal environment, that is, the thickness of the floor and the temperature of the outside air and / or the water to be returned, etc., which is greater than 10 when the measured outside temperature is less than 20 ° C. Although it is set to 20 ℃ or higher, a value smaller than 10 is set.In this experiment, the value is calculated from a relational expression of τ = 10 (reference value) + (ambient temperature correction value + return temperature correction value), and the ambient temperature correction value is ( The outside air set temperature-the outside air temperature) / 5 and the return water temperature correction value are calculated from (the return water set temperature-the return temperature) / 5.

Therefore, since outside air temperature correction value = (20 degreeC-25 degreeC) / 5 = -1, and return water temperature correction value = (40 degreeC-45 degreeC) / 5 = -1, (tau) = 10 + (-1-1) = 8 is obtained.

(7) Heating operation correction time (HT _o ) = Δt [1 + ρ (1- △ t _e )] × τ = 2 ℃ [1 + 1 (1-0)] × 8 = 32 (min)

(8) From the initial room temperature (T _o ) and the current room temperature (T _c ) do not change, from which it can be seen that the room temperature is almost unchanged as the rate of change of temperature (△ t _e ) is calculated as "0". If the current heating operation time (HT _c ) is 20 minutes, heating should be further performed for 12 minutes by 32 minutes of heating operation correction time (HT _o ).

(Example 2-2)

(1) The initial room temperature (T _o ) is 23 ° C, the set temperature (T _s ) is 25 ° C, the measured current room temperature (T _c ) is 23.5 ° C, and the outside temperature is 10 ° C (set temperature 20 ° C), return water In the case of temperature 35 degrees Celsius (set temperature 40 degrees Celsius),

(2) Temperature difference (△ t) = Set temperature T _s )-Present room temperature (T _c ) = 25 ℃ -23.5 ℃ = 1.5 ℃

(3) Since the temperature difference (Δt) = 1.5 ° C is the reference temperature difference of 0.5 ° C or more,

(4) Assuming that the current heating time (HT _c ) is 15 minutes,

(5) Room temperature change rate (Δt _e ) = [current room temperature (T _c )-initial room temperature (T _o )] × τ / current operating time (HT _c ) = (23.5 ° C-23 ° C) x 10 / 15 ≒ 0.333

(6) In this experiment, the outside air temperature correction value = (20 ℃-10 ℃) / 5 = 2, return water temperature correction value = (40 ℃-35 ℃) / 5 = 1, τ = 10 + (2 + 1 ) = 13 is obtained.

(7) Heating operation correction time (HT _o ) = Δt [1 + ρ (1- △ t _e )] × τ = 1.5 ° C [1 + 1 (1-0.333)] × 13 ≒ 33 (min)

(8) If the current heating operation time (HT _c ) is 15 minutes, heating shall be continued for 18 minutes by 33 minutes of heating operation correction time (HT _o ).

(Example 2-3)

(1) The initial room temperature (T _o ) is 23 ° C, the set temperature (T _s ) is 25 ° C, the measured current room temperature (T _c ) is 24 ° C, and the outside temperature is 15 ° C (set temperature 20 ° C), return water In the case of temperature 30 degrees Celsius (set temperature 40 degrees Celsius),

(2) Temperature difference (△ t) = Set temperature T _s )-Present room temperature (T _c ) = 25 ℃ -24 ℃ = 1 ℃

(3) Since the temperature difference (Δt) = 1 ° C is the reference temperature difference of 0.5 ° C or more,

(4) Assuming that the current heating run time (HT _c ) is 15 minutes,

(5) Room temperature change rate (Δt _e ) = [Current room temperature (T _c )-Initial room temperature (T _o )] × τ / Initial heating run time (HT _c ) = (24 ℃ -23 ℃) × 10 / 10 = 1

(6) In this experiment, the outside air temperature correction value = (20 ℃ -15 ℃) / 5 = 1, and the return water temperature correction value = (40 ℃ -30 ℃) / 5 = 2, τ = 10 + (1 + 2 ) = 13 is obtained.

(7) Heating operation correction time (HT _o ) = Δt [1 + ρ (1- △ t _e )] × τ = 1 ° C [1 + 1 (1-1)] × 13 = 13 (min)

(8) If the current heating operation time (HT _c ) is 15 minutes, it means that heating operation should be stopped immediately because the heating operation correction time (HT _o ) is 13 minutes.

Data item Example 2-1 Example 2-2 Example 2-3 Remarks Temperature difference (△ t) 2 ℃ 1.5 ℃ 1 ℃ Change rate of room temperature (△ t _e ) 0 0.333 1.0 Outside temperature 25 ℃ 10 ℃ 15 ℃ 20 ℃ setting Return temperature 45 ℃ 35 ℃ 30 ℃ 40 ℃ setting Ambient temperature correction value (20-25) / 5 = -1 (20-10) / 5 = 2 (20-15) / 5 = 1 Return temperature correction value (40-45) / 5 = -1 (40-35) / 5 = 1 (40-30) / 5 = 2 Weight variableτ 10 + (-1-1) = 8 10+ (2 + 1) = 13 10+ (1 + 2) = 13 Heating operation correction time (HT _o ) 32 minutes 33 minutes 13 minutes Heating heating time (HT _c ) 20 minutes 15 minutes 15 minutes HT _c 〈HT _o Yes Yes No Heating operation Operation Operation Immediate stop

Table 2 summarizes the embodiments 2-1 to 2-4 of the present invention, and analyzes the thermal characteristics and the external environment change of the ondol system from the outside air temperature and the return temperature, during the current heating operation time (HT _c ). As a result of the heating operation, it is configured to set the heating operation time required for the current room temperature T _c , which is measured every minute, to reach the set temperature T _s ).

In other words, the heating operation correction time (HT _o ) by automatically setting the variable τ of the weight, which is related to the indoor and outdoor thermal environment, that is, the thickness of the floor and the outside temperature and / or the water temperature to be returned from the outside temperature and the return temperature. Will be reflected in.

On the other hand, the heating operation cycle according to the present invention slows down the heating operation when the current room temperature (T _c ), which is measured every minute, rises or remains as it is, of frequent heating stops due to a sensitive change of the current room temperature (T _c ). In order to solve the problem, a minimum value of 30 minutes is given, and a maximum value of 90 minutes is set to solve a problem of overcooling due to a too long heating stop time caused by a slow change of the current room temperature T _c .

In addition, the heating operation cycle according to the present invention is at least 30 because the current room temperature (T _c ) measured every minute even after the heating is stopped does not immediately drop, but rather rises to form a peak point (Peak), can be lowered at least 30 During the period of 90 minutes to 90 minutes, the current room temperature (T _c ) is set to start heating when the temperature falls below a certain temperature as it passes the peak point.

In other words, in the present invention, as shown in Figure 2 has a heating operation cycle of at least 30 minutes up to 90 minutes after the heating is stopped, the current room temperature (T _c ) measured every minute is past the peak point (Peak) It is configured to start heating when it starts to descend and becomes 0.5 ℃ or more lower than the temperature at the peak point.

As described above, specific embodiments have been described in the detailed description of the present invention, but various modifications may be made without departing from the scope of the present invention.

Therefore, the substantial scope of the present invention should not be limited by the above-described embodiment, but should be defined by the same structure as the claims as well as the claims described below.

S100: Measuring step of the current room temperature T _c S200: Calculating step of the temperature difference Δt S300: Contrast step between the temperature difference Δt and the reference temperature difference 0.5 ° C S400: Calculating step of the current heating operating time HT _c S500: Calculation step of room temperature change rate? T _e S600: Setting step of heating operation correction time HT _o S700: Contrast step of current heating operation time HT _c and heating operation correction time HT _o

Claims (4)

When the heating operation is started according to the heating operation cycle, the temperature difference (△ t) between the measured current room temperature (T _c ) and the set temperature (T _s ) is determined by comparing with the reference temperature difference, and then the temperature difference (△ If t) is equal to or greater than the reference temperature difference, the current heating operation time (HT _c ), which is the time of heating up to now, and the room temperature change rate (Δt _e ) are calculated in order, and then the temperature difference (Δt) and the room temperature change rate (Δt _e). Heating time correction control method according to the room temperature change rate, characterized in that configured to determine whether the heating operation by comparing with the current heating operation time (HT _c ) while calculating the heating operation correction time (HT _o ). The method according to claim 1,
The rate of change of indoor temperature (Δt _e ) is calculated from a relation formula of [current room temperature (T _c ) -first room temperature (T _o )] × weight value τ / current heating operation time (HT _c ), and the heating operation correction time (HT _o ) is a heating time compensation control method according to the room temperature change rate, characterized in that it is configured to calculate from the relation of the temperature difference (Δt) [1 + correction rate ρ (1-Δt _e )] × weight value τ. The method according to claim 1,
The heating operation cycle has an operation cycle of at least 30 minutes up to 90 minutes after the heating is stopped, and the current room temperature T _c , which is measured every minute, begins to fall past the peak point and starts at the peak point. Heating time correction control method according to the room temperature change rate, characterized in that configured to start the heating operation when the lower than 0.5 ℃. The method according to claim 2,
The weight? Is a heating time compensation control method according to the room temperature change rate, characterized in that the variable corrected according to the measured outside temperature and / or the return temperature.

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