JPS63172382A - Relative position analyzing system for 2-dimensional coordinate space data - Google Patents

Relative position analyzing system for 2-dimensional coordinate space data

Info

Publication number
JPS63172382A
JPS63172382A JP466787A JP466787A JPS63172382A JP S63172382 A JPS63172382 A JP S63172382A JP 466787 A JP466787 A JP 466787A JP 466787 A JP466787 A JP 466787A JP S63172382 A JPS63172382 A JP S63172382A
Authority
JP
Japan
Prior art keywords
point
points
data
quadrant
dimensional coordinate
Prior art date
Legal status (The legal status is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the status listed.)
Granted
Application number
JP466787A
Other languages
Japanese (ja)
Other versions
JPH0664608B2 (en
Inventor
Takeshi Hazama
狭間 武
Junichi Akahori
赤堀 順一
Current Assignee (The listed assignees may be inaccurate. Google has not performed a legal analysis and makes no representation or warranty as to the accuracy of the list.)
Fujitsu Ltd
Original Assignee
Fujitsu Ltd
Priority date (The priority date is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the date listed.)
Filing date
Publication date
Application filed by Fujitsu Ltd filed Critical Fujitsu Ltd
Priority to JP466787A priority Critical patent/JPH0664608B2/en
Publication of JPS63172382A publication Critical patent/JPS63172382A/en
Publication of JPH0664608B2 publication Critical patent/JPH0664608B2/en
Anticipated expiration legal-status Critical
Expired - Lifetime legal-status Critical Current

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Abstract

PURPOSE:To increase a processing speed with the titled system by obtaining the relative position relation between two points in a 2-dimensional coordinate space from a monotonous increase function. CONSTITUTION:The relative position relation between at least two points A and B are obtained out of a group of data acquired in a 2-dimensional coordinate space. in this case, the position data on the point A are defined as AX and AY1 with the position data on the point B defined as BX and BY2 respectively. Then the distance R3 between both points A and B is calculated from an equation I. The comparison of values are carried out between said defined AX and BX as well as AY and BY respectively. Then the position of the point B relative to the point A is obtained from a function shown in a table based on the quadrant data obtained from said comparison of values as well as the data 3 on the distance R between both points.

Description

【発明の詳細な説明】 〔概要〕 2次元座標空間上のデータとして得られるチ゛−タ群を
解析する中で、2点の相対位置関係を調べる上で必要と
なる逆三角関数の級数計算に起因する該データ処理の性
能の低下を解決する為に、上記2点間の距離(■υを求
める手段と、該2点の内、一方の点に対する他方の点の
象限データを、該2点の座標データの大小比較で求める
手段とを設けることにより、上記他方の点の一方の点と
の相対位置関係を、上記2点間の距離(R)と、上記象
限データとに基づいて、ji’を調増加関数として6B
)られるようにしたものである。
[Detailed Description of the Invention] [Summary] While analyzing a group of tracers obtained as data on a two-dimensional coordinate space, it is necessary to calculate a series of inverse trigonometric functions necessary to investigate the relative positional relationship between two points. In order to resolve the resulting deterioration in data processing performance, we have developed a method for determining the distance (■υ) between the two points, and the quadrant data of one of the two points with respect to the other point. By providing means for determining the relative positional relationship between the other point and one point based on the distance (R) between the two points and the quadrant data, ji ' as a key increasing function 6B
).

〔産業上の利用分野〕[Industrial application field]

本発明は、2次元座標空間上のデータの相対位置を解析
する方式に関する。
The present invention relates to a method for analyzing the relative position of data on a two-dimensional coordinate space.

最近の計算機システムの性能の向上に伴って、コンピュ
ータグラフィックス等の各種の分野において、該計算機
システムによる図形処理が行われるようになっ”ζきた
With the recent improvement in the performance of computer systems, graphics processing using these computer systems has come to be performed in various fields such as computer graphics.

該図形処理の中に、ディスプレイ七に表示されている複
数個の図形の1つを、オペレータによる、例えば、カー
ソルで指示して抽出し、該図形を特定の色で塗り潰すこ
とが要求されることがある。
During the graphic processing, an operator is required to extract one of the plurality of graphics displayed on the display 7 by, for example, using a cursor, and fill the graphic with a specific color. Sometimes.

この複数個の図形の中から特定の図形をピックアンプす
る際、該オペレータのカーソルで指示した点が、当該図
形の中にあるか否かを判定することが必要になるが、該
判定処理は、該図形の特定の1点との相対位置関係を求
める処理となる。
When picking a specific shape from among these multiple shapes, it is necessary to determine whether or not the point indicated by the operator's cursor is within the shape. , is a process of determining the relative positional relationship with a specific point of the figure.

然して、該2点間の相対位置を求める処理は、該図面処
理の前処理に過ぎない為、できる限り、簡4’iであっ
て、且つ全体の図形処理に影言を与えない解析処理であ
るごとが必要とされる。
However, since the process of determining the relative position between the two points is only a pre-processing of the drawing process, it should be as simple as possible and an analysis process that does not affect the overall graphic process. Everything is needed.

〔従来の技術と発明が解決しようとする問題点〕第3図
は従来の2次元座標空間データの相対位置解析方式を説
明する図である。
[Prior art and problems to be solved by the invention] FIG. 3 is a diagram illustrating a conventional relative position analysis method for two-dimensional coordinate space data.

従来方式においては、本図の(a)図に示したように、
2次元座標空間−ヒの2点を、例えば、該2次元座標空
間の水平方向をX軸、垂直方向をY軸とした座標系の中
心点(0,0)と点(X、Y)に写像し、該点(X、 
Y)のX軸に対する角度θを求めることにより、該2点
の相対位置関係を解析していた。
In the conventional method, as shown in (a) of this figure,
For example, the two points in the two-dimensional coordinate space A are the center point (0, 0) and the point (X, Y) of a coordinate system with the horizontal direction as the X axis and the vertical direction as the Y axis. The point (X,
By determining the angle θ of Y) with respect to the X axis, the relative positional relationship between the two points was analyzed.

この場合、sinθ−Y/(X2+Y2) ””= α
としたとき、該角度θは逆正弦として求めることができ
る。即ち、 θ= 5in−’α 一α十 (l/2・3)α3 +  ((1・3)/ 
 (2・4 ・5)) α5+  ((l・3 ・5)
/  (2・4 ・6 ・7)) αフ罎゛−−− で示される級数関数を求めることになる。
In this case, sinθ−Y/(X2+Y2) ””= α
The angle θ can be determined as an arc sine. That is, θ= 5in-'α - α10 (l/2・3)α3 + ((1・3)/
(2・4 ・5)) α5+ ((l・3 ・5)
/ (2・4 ・6 ・7)) We will find the series function shown by α ゛゛---.

上記の関数は、(b)図に示すように、−1% ) I
 Q−π/2〜π/2 へのl対l対応の関数である。
The above function is -1%) I as shown in figure (b)
It is a function of l to l correspondence from Q-π/2 to π/2.

従って、1−記X、Yの値を吟味して象限を求め、該θ
の正しい値を最終的に求める処理となる為、単に、2点
の相対的位置関係を求める処理に、上記の如き級数関数
の数値計算の為の、多大の時間が必要であると云う問題
があった。
Therefore, by carefully examining the values of X and Y in 1-1 and finding the quadrant,
The problem is that simply calculating the relative positional relationship between two points requires a large amount of time for the numerical calculation of the series function as described above. there were.

本発明は上記従来の欠点に鑑み、2次元座標空間上の、
例えば、2点の相対位置関係を簡単な処理で高速に求め
る方法を提供することを目的とするものである。
In view of the above-mentioned conventional drawbacks, the present invention provides
For example, it is an object of the present invention to provide a method for quickly determining the relative positional relationship between two points using simple processing.

〔問題点を解決するための手段〕[Means for solving problems]

第1図は本発明の2次元座標空間データの相対位置解析
方式の構成の概念図である。
FIG. 1 is a conceptual diagram of the configuration of a relative position analysis method for two-dimensional coordinate space data according to the present invention.

本発明においては、 2次元座標空間中に存在するデータの相対位置を解析す
る方式、であって、 該2次元座標空間中で得られたデータ群の中の、少なく
とも2つの点(へ点、助飄)の相対的な位置関係を求め
る際、 A点の位置データとして、AX、AM lを、B点の位
置データとして、BX、BY 2を、を定義し、該2点
間の距Alt(R) 3を、R=  ((BX−AX)
”)(BY−AV)21  ””で計算する手段と、 上記、B点のA点に対する象限を求めるのに、上記、定
義されたAXとBx、及びAVとBYとの間の大小比較
4を行う手段とを設け、 上記大小比較手段によって求められる象限データと、該
2点間の距離(R)のデータ3に基づいて、第1象限の
B点を−(BX−AX) /I?第2象限のB点を−(
八Y−BY)/R+1.0第3象限(7)B点を−(A
X−BX)/R+2.0第4象限のB点を−(BY−八
Y)/R+3.0で示す関数で、該A点に対するB点の
相対位置を求めるように構成する。
In the present invention, there is provided a method for analyzing the relative position of data existing in a two-dimensional coordinate space, the method comprising: analyzing the relative position of data existing in a two-dimensional coordinate space; When calculating the relative positional relationship between the two points, define AX, AM l as the position data of point A, BX, BY 2 as the position data of point B, and calculate the distance Alt between the two points. (R) 3, R= ((BX-AX)
``)(BY-AV)21'' To find the quadrant of point B with respect to point A, use the magnitude comparison 4 between AX and Bx and AV and BY defined above. Based on the quadrant data obtained by the size comparison means and the data 3 of the distance (R) between the two points, point B in the first quadrant is determined by -(BX-AX) /I? Point B in the second quadrant is −(
8Y-BY)/R+1.0 3rd quadrant (7) Point B -(A
X-BX)/R+2.0 The function is to indicate point B in the fourth quadrant as -(BY-8Y)/R+3.0, and is configured to determine the relative position of point B with respect to point A.

〔作用〕[Effect]

即ら、本発明によれば、2次元座標空間上のデータとし
て(:#られるデータ群を解析する中で、2点の相対位
置関係を調べる上で必要となる逆三角関数の級数計算に
よる該データ処理の性能の低下を解決する為に、上記2
点間の距離(I?)を求める手段と、該2点の内、一方
の点に対する他方の点の象限データを、該2点の座標デ
ータの大小比較で求める手段とを設けることにより、上
記他方の点の一方の点との相対位置関係を、上記2点間
の距離(R)と、上記象限データとに基づいて、単調増
加関数とし°ζ得られるようにしたものであるので、2
次元座標空間上における2点の相対位置関係を単調増加
関数により、高速に求めることができる効果がある。
That is, according to the present invention, when analyzing a data group that is represented as data on a two-dimensional coordinate space, the calculation of a series of inverse trigonometric functions, which is necessary to examine the relative positional relationship between two points, is performed. In order to solve the decline in data processing performance, the above 2.
By providing means for determining the distance (I?) between points and means for determining the quadrant data of one of the two points with respect to the other point by comparing the magnitude of the coordinate data of the two points, the above-described method can be achieved. Since the relative positional relationship between the other point and one point can be obtained as a monotonically increasing function based on the distance (R) between the two points and the quadrant data, 2
This has the advantage that the relative positional relationship between two points on a dimensional coordinate space can be determined quickly using a monotonically increasing function.

〔実施例〕〔Example〕

以下本発明の実施例を図面によって詳述する。 Embodiments of the present invention will be described in detail below with reference to the drawings.

前述の第1図は、本発明の2次元座標空間データの相対
位置解析方式の構成の概念図であり、第2図は本発明の
一実施例を示した図であり、第1図における2点間の距
Am(R)を求める手段3と。
The above-mentioned FIG. 1 is a conceptual diagram of the configuration of the relative position analysis method for two-dimensional coordinate space data of the present invention, and FIG. 2 is a diagram showing an embodiment of the present invention. and means 3 for determining the distance Am(R) between points.

該2点の座標の大小比較によって、A点に対する13点
の象限を求める手段と、該2点間の距iX’1f(R)
と、象限データとによって学制増加関数を求める手段が
本発明を実施するのに必要な手段である。
Means for determining the quadrant of 13 points for point A by comparing the magnitude of the coordinates of the two points, and the distance iX'1f(R) between the two points.
Means for determining the educational system increasing function using the above and quadrant data is a necessary means for carrying out the present invention.

尚、全図を通して、同じ符号は同じ対象物を示している
Note that the same reference numerals indicate the same objects throughout the figures.

以下、第1図、第2図によって本発明の2次元座標空間
データの相対位置解析方式を説明する。
Hereinafter, the relative position analysis method of two-dimensional coordinate space data of the present invention will be explained with reference to FIGS. 1 and 2.

本発明においては、A点から見たB点の相対的な位置を
、従来の角度θとは別の定量として表す関数を導入する
In the present invention, a function is introduced that expresses the relative position of point B as seen from point A as a quantitative value different from the conventional angle θ.

その為に、先ず、各点の位置データとして、A点: (
AX、AV) I B点: (IX、[) 2 を定義し、(a)図に示したように、A点の真上の位置
を0°とし′ζ、例えば、右回りに単調増加するような
関数を考える。具体的には、 ■ 最初に、(b)図に示した、A点とB点との距^1
1(R) 3を、 R=  ((RX−AX)2+(IIY−AV)2 )
  ””で求める。
For that purpose, first, as the position data of each point, point A: (
AX, AV) I B point: Define (IX, [) 2, (a) As shown in the figure, the position directly above point A is 0°, and ′ζ, for example, increases monotonically clockwise. Consider a function like Specifically, ■ First, the distance between point A and point B shown in figure (b)^1
1(R) 3, R= ((RX-AX)2+(IIY-AV)2)
Find with "".

■ 次に、B点のA点を中心とした2次元座標系におけ
る象限を求める。具体的には、上記定義した2点の座標
から、AXとIIX、 AVとBYの各々の大小比較4
を行い、表1を元に象限を求める。
(2) Next, find the quadrant of point B in the two-dimensional coordinate system centered on point A. Specifically, from the coordinates of the two points defined above, compare the sizes of AX and IIX, and AV and BY.
and find the quadrant based on Table 1.

表1 ■ ■で求めた象限データに基づいて、以下の数値を求
める。即ち、 第1象限−(BX−Δ×)/R 第2象限−(AV−11Y)/R+ 1.0第3象限−
(AX−BX)/R+ 2.0第4象限−(BY−AV
) /R13,0以上のようにし°ζ求めた数値は、0
〜4迄の単調増加関数として得られる数値であることが
分かる。
Based on the quadrant data obtained in Table 1 ■ ■, calculate the following values. That is, 1st quadrant - (BX-Δx)/R 2nd quadrant - (AV-11Y)/R+ 1.0 3rd quadrant -
(AX-BX)/R+ 2.0 4th quadrant - (BY-AV
) /R13,0 The numerical value obtained by °ζ is 0
It can be seen that the numerical value is obtained as a monotonically increasing function up to 4.

第2図は、本発明の一実施例を示した図であり、P点を
中心とし、Q点、R点を端点とした扇形をピックアップ
する例である。
FIG. 2 is a diagram showing an embodiment of the present invention, and is an example of picking up a fan shape with point P as the center and point Q and point R as end points.

この扇形をピックアップする為には、該扇形中の8点が
与えられた時(例えば、カーソルによる指示点が、該8
点であったとする)、該8点が扇形の内部の点であるか
どうかを判断して、該扇形の内部にあることを認識する
必要がある。
In order to pick up this fan shape, when 8 points in the fan shape are given (for example, the point indicated by the cursor is
It is necessary to judge whether the eight points are points inside the fan shape and recognize that they are inside the fan shape.

該8点が当該扇形の内部にあることの条件としては、次
の2つがあげられる。
The following two conditions are listed as conditions for the eight points to be inside the sector.

1)PQ間(又は、PR間)の距離より、1.5間の距
朋が短いこと。
1) The distance between 1.5 points is shorter than the distance between PQs (or between PRs).

1i)Q点からR点に右回りにサーチした時、8点がサ
ーチされること。
1i) When searching clockwise from point Q to point R, 8 points are searched.

上記の条件において、i)は、特に問題はないが、i)
を調べる際に、本発明の単調増加関数を使用する。具体
的には、P点を中心として、Q、I+’。
Under the above conditions, there is no particular problem with i), but i)
In examining , we use the monotonically increasing function of the present invention. Specifically, centering on point P, Q, I+'.

5O)3点に対して、上記本発明の関数による数値を算
出し、該3点の大小関係が、 Qの値〈Sの値くRの値 であれば、上記ii)の条件は成り立つことになる。
5O) Calculate numerical values using the function of the present invention for the three points, and if the magnitude relationship of the three points is the value of Q < the value of S minus the value of R, then condition ii) above is satisfied. become.

このようにして、扇形(P、 u、 R)をピックアッ
プし、例えば、該扇形を特定の色で塗り潰す画像処理を
行う。
In this way, the fan shape (P, u, R) is picked up, and image processing is performed to fill the fan shape with a specific color, for example.

このように、本発明は、2次元座標空間内の2点の相対
位置を解析するのに、該2点の2次元座標空間内のX輔
(又はY輔)に対する角度θを求めるのではなく、該2
点の一方を中心にした座標系上の距離(R)と、該2点
の座標の大小比較による象限データを求めて、該距離(
R)と、象限データに基づいて算出した単調増加関数の
数値で、相対位置を認識するようにした所に特徴がある
In this way, the present invention analyzes the relative position of two points in a two-dimensional coordinate space, instead of finding the angle θ of the two points with respect to X (or Y) in the two-dimensional coordinate space. , said 2
Find the distance (R) on the coordinate system centered on one of the points and the quadrant data by comparing the magnitude of the coordinates of the two points, and calculate the distance (R).
R) and the numerical value of a monotonically increasing function calculated based on quadrant data.

〔発明の効果〕〔Effect of the invention〕

以上、詳細に説明したように、本発明の2次元座標空間
データの相対位置解析方式は、2次元座標空間上のデー
タとして得られるデータ群を解析ずろ中で、2点の相対
位置関係を調べる上で必要となる逆三角関数の級数計算
による該データ処理の性能の低下を解決する為に、上記
2点間の距離(R)を求める手段と、該2点の内、−・
方の点に対する他方の点の象限データを、該2点の座標
データの大小比較で求める手段とを設けることにより、
上記他方の点の一方の点との相対位置関係を、上記2点
間の距離(I?)と、上記象限データとに基づいて、単
調増加関数として得られるようにしたものであるので、
2次元座標空間上における2点の相対位置関係を単調増
加関数により、高速に求めることができる効果がある。
As explained above in detail, the relative position analysis method for two-dimensional coordinate space data of the present invention examines the relative positional relationship between two points while analyzing a data group obtained as data on a two-dimensional coordinate space. In order to solve the deterioration in the performance of data processing due to the series calculation of inverse trigonometric functions required above, a means for calculating the distance (R) between the two points, and a means for calculating the distance (R) between the two points -
By providing means for obtaining quadrant data of one point with respect to the other point by comparing the magnitude of the coordinate data of the two points,
The relative positional relationship between the other point and one point can be obtained as a monotonically increasing function based on the distance (I?) between the two points and the quadrant data.
This has the advantage that the relative positional relationship between two points on a two-dimensional coordinate space can be determined quickly using a monotonically increasing function.

【図面の簡単な説明】[Brief explanation of the drawing]

第1図は本発明の2次元座標空間データの相対位置解析
方式の構成の概念図。 第2図は本発明の一実施例を示した図。 第3図は従来の2次元座標空間データの相対位置解析方
式を説明する図。 である。 図面において、 1.2は2点の位置データ (座標)。 3は2点の距離(R)、   4は大小比較。 をそれぞれ示す。 (λ) (b) 専1 図
FIG. 1 is a conceptual diagram of the configuration of a relative position analysis method for two-dimensional coordinate space data according to the present invention. FIG. 2 is a diagram showing an embodiment of the present invention. FIG. 3 is a diagram illustrating a conventional relative position analysis method for two-dimensional coordinate space data. It is. In the drawing, 1.2 is the position data (coordinates) of two points. 3 is the distance (R) between two points, and 4 is the size comparison. are shown respectively. (λ) (b) Special 1 Figure

Claims (1)

【特許請求の範囲】 2次元座標空間中に存在するデータの相対位置を解析す
る方式であって、 該2次元座標空間中で得られたデータ群の中の、少なく
とも2つの点(A点、B点)の相対的な位置関係を求め
る際、 A点の位置データとして、AX、AY(1)を、B点の
位置データとして、BX、BY(2)を、を定義し、該
2点間の距離(R)(3)を、R={(BX−AX)^
2+(BY−AY)^2}^1^/^2で計算する手段
と、 上記、B点のA点に対する象限を求めるのに、上記、定
義されたAXとBX、及びAYとBYとの間の大小比較
(4)を行う手段とを設け、 上記大小比較手段によって求められる象限データと、該
2点間の距離(R)のデータ(3)に基づいて、第1象
限のB点を…(BX−AX)/R 第2象限のB点を…(AY−BY)/R+1.0第3象
限のB点を…(AX−BX)/R+2.0第4象限のB
点を…(BY−AY)/R+3.0で示す関数で、該A
点に対するB点の相対位置を求めることを特徴とする2
次元座標空間データの相対位置解析方式。
[Claims] A method for analyzing the relative position of data existing in a two-dimensional coordinate space, comprising at least two points (point A, point A, When calculating the relative positional relationship between point B), define AX, AY (1) as the position data of point A, BX, BY (2) as the position data of point B, and calculate the two points. The distance between (R) (3), R = {(BX-AX)^
2+(BY-AY)^2^1^/^2 To find the quadrant of point B to point A, we need to use the above defined AX and BX and AY and BY. and a means for performing a size comparison (4) between the two points, and the point B in the first quadrant is determined based on the quadrant data obtained by the size comparison means and the data (3) of the distance (R) between the two points. ...(BX-AX)/R Point B in the second quadrant...(AY-BY)/R+1.0 Point B in the third quadrant...(AX-BX)/R+2.0 B in the fourth quadrant
The point is expressed as...(BY-AY)/R+3.0, and the A
2 characterized by finding the relative position of point B with respect to point
Relative position analysis method for dimensional coordinate space data.
JP466787A 1987-01-12 1987-01-12 Angular relative position analyzer for two-dimensional coordinate space data Expired - Lifetime JPH0664608B2 (en)

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Application Number Priority Date Filing Date Title
JP466787A JPH0664608B2 (en) 1987-01-12 1987-01-12 Angular relative position analyzer for two-dimensional coordinate space data

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Application Number Priority Date Filing Date Title
JP466787A JPH0664608B2 (en) 1987-01-12 1987-01-12 Angular relative position analyzer for two-dimensional coordinate space data

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JPS63172382A true JPS63172382A (en) 1988-07-16
JPH0664608B2 JPH0664608B2 (en) 1994-08-22

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