JPS6137625B2 - - Google Patents

Description

DETAILED DESCRIPTION OF THE INVENTION The present invention relates to the control of an electrophotographic copying machine, and particularly relates to an electrophotographic copying machine in which not only copying control but also control including photoreceptor replacement is performed by one control element. . Generally, in the case of electrophotographic copying machines, etc., there are
For example, a microswitch or the like is provided, and the operating state of this microswitch controls mechanisms for performing various copying processes.

Here, to briefly explain the electrostatic copying operation, a photoreceptor with a photoconductive layer formed on the top surface of a conductive layer is used.
The photoconductive layer of this photoreceptor is uniformly charged. By exposing the photoconductive layer of the photoreceptor to a light image, an electrostatic latent image corresponding to the light image is formed on its surface. Thereafter, toner is applied to the electrostatic latent image in a developing section to make it into a visible image. Then, the fed plain paper is brought into close contact with the photoreceptor, the toner image is transferred to the plain paper, the plain paper is sent to the fixing section, the transferred toner image is fixed, and then sent out to the exit. ing.

The above is a general dry type copying machine.

Here, the copying process, that is, the control of each process such as charging, exposure, development, transfer, and fixing, is performed by detecting the paper feeding state or the rotational position of the photoreceptor drum at various locations, as mentioned earlier. Microswitches and the like are appropriately arranged, and various controls are performed depending on the operating state of the microswitches.

If the control circuit is to connect a large number of TTL-ICs and perform charging, for example, depending on the operating state of the switch group, the control circuit outputs a charging unit control signal, and the charging unit is activated via the driver circuit. That's what I do.

Further, the photoreceptor for forming images is replaced with a new one after a certain number of copies have been made. in this case,
A control circuit for controlling photoconductor replacement is provided separately from a control circuit for controlling copying. Therefore, including the copy control circuit and the exchange control circuit,
The circuit configuration of the entire copying machine has become extremely complex.

On the other hand, copying machines use various detection signals, including output signals when detecting paper jams, as means to convert them into electrical signals and mechanical outputs for control.
A solenoid is used. The copying machine as a whole, including these solenoids, becomes a noise source for the electronic control circuit. Furthermore, it is clear that the complicated wiring and the fact that it requires a considerable line length make it susceptible to electronic noise sources. Moreover, the copying machine itself performs various operations in synchronization with the rotating photoreceptor drum.
For example, charging, exposure, and movement of the document table are performed, but the control circuit is controlled by operating status signals from a group of switches that enter asynchronously, so it is inherently weak in terms of noise resistance. It was hot.

Therefore, even though the copying control is being executed, the photoconductor replacement control circuit is operated due to noise when the solenoid is activated, and the photoconductor replacement control is also performed. Conversely, during photoconductor exchange control, a copying operation may be executed at the same time.

Therefore, the present invention selectively controls copying control and photoreceptor exchange control using the same control means. Incidentally, the copying machine has a sufficiently long control time for copying time, photoreceptor replacement time, etc., and the operating state can be serially determined as long as time permits, without having to determine the switch groups, etc. in parallel. This means that extra wiring can be omitted, and the above-mentioned effect of increasing the margin in noise resistance becomes greater.

In order to realize this, the present invention provides, for example, 1
Chip, ROM using MOS-FET in one package
- Copy control and photoreceptor exchange control are performed using a RAM type microprocessor.

The above-mentioned microprocessor performs read/write operations for subdivided digital control and arithmetic circuits using a set of instructions written in read-only memory (ROM).
This is a processing device that operates including mutual transmission with memory (Read Write Memory, RAM).

As mentioned earlier, the effective use of microprocessors in copying machines was briefly mentioned, but the control time of a series of copying machines was long enough to compensate for the disadvantages of processors in terms of processing time. It will be put to very good use.

In particular, by using MOS-FET, power consumption is significantly lower than that of TTL, and the degree of integration is also improved, so it can be used efficiently.

In addition, by using a microprocessor to control the copying machine, the electronic control circuit can be significantly miniaturized.In other words, the conventional control circuit can be replaced with just one microprocessor, which greatly reduces the number of parts and improves reliability. In order to improve performance and serviceability, prevent the influence of external noise, and check various conditions of the copying machine, such as the detection status of a group of microswitches, serial control is performed, so interconnect wiring can be reduced. Furthermore, changes in peripheral devices and specifications expected in the future can be handled by modifying the ROM of the microprocessor itself, making it easy to make significant improvements compared to copiers using conventional control methods. The results were also great.

Hereinafter, the present invention, in which a copying machine is controlled by a microprocessor, will be explained in detail.

First, the configuration of the copying machine according to the present invention will be explained. In FIG. 1, reference numeral 1 denotes a rotating drum that is rotated in the direction of the arrow at a constant speed around a shaft 2, and the drum 1 has a master paper, that is, a surface formed with a photoconductor, on its outer circumferential surface. A photoreceptor 3 whose back surface is made of a conductive layer is detachably attached. Although not shown in the drawings, the photoreceptor 3 is fixed to the outer circumferential surface of the drum 1 by being held down by a presser claw attached to the circumferential surface of the rotating drum 1 at its leading end. Also, when converting the photoreceptor 3, the presser claw opens, the old photoreceptor is transported to the outside, that is, the paper output port 5, and a new photoreceptor 3 is inserted from the photoreceptor insertion port 4, and its tip is inserted into the presser claw. It is held down and fixed. This operation is automatically performed in conjunction with the rotation of the drum 1. A micro switch MS ₇ installed near the photoconductor insertion slot 4 detects that the photoconductor 3 has been inserted, and when this switch MS ₇ is turned on, the photoconductor 3 is replaced as will be explained later. Then, the photoconductor is replaced. The automatic replacement of the photoreceptor 3 is carried out by a known mechanism that has been developed in the past in this type of apparatus, and therefore a description thereof will be omitted.
Various devices are provided near the rotating drum 1 to form an image corresponding to a document on the surface of the photoreceptor 3. In the figure, reference numeral 6 denotes a charger for uniformly charging the surface of the photoreceptor 3. The charger 6 generates high voltage by energizing the charging high voltage generating unit CHVU as shown in the circuit diagram of FIG.
surface is uniformly charged. The energization at this time is carried out by energizing the charging relay and closing its contact CHVR-a.

Reference numeral 7 denotes an exposure section, which irradiates the charged photoreceptor 3 with a light image to form an electrostatic latent image. This exposure is performed by illuminating the transparent glass surface of the document table 8 on which the copy document is placed with an illumination device 9, and transmitting the reflected light through an optical system 10.

Here, the document table 8 is configured to move in synchronization with the rotating drum 1. That is, the movement of the original platen 8 is started at the same time as the photoreceptor of the rotating drum 1 comes to the exposure section 7, and the moving speed at this time is naturally equal to the rotational speed (peripheral speed of the drum 1).

Reference numeral 11 denotes a developing device for visualizing the electrostatic latent image, which attaches toner to the area where the electrostatic latent image is formed to form a toner image.

Reference numeral 12 denotes a transfer charger for transferring the toner image onto the transfer paper 13. The transfer paper 13 is automatically fed by a paper feed roller 20, and the first roller 2
The paper is conveyed into the copying machine at 1, and is fed through each roller in synchronization with the rotation of the rotating drum 1. Once the paper is fed, it is stopped at a paper stopper 14 provided in the paper section. will be stopped. The micro switch MS ₁ installed in the paper sheet section detects this state of paper input, and if the rotating drum 1 rotates to a certain position while the micro switch MS ₁ is detecting the paper paper, The stopper 14 opens and the transfer paper 18 is fed, synchronized with the rotating drum 1 at a good timing, and brought into close contact with the photoreceptor 3 on which the toner image has been formed. The toner image is then charged by a transfer charger 12 and transferred onto a transfer paper 13. or,
Reference numeral 15 denotes a device for peeling off the transfer paper 13 from which the toner image has been transferred and which has been brought into close contact with the photoreceptor 3 of the drum 1 .

When the transfer paper 13 is peeled off from the photoreceptor 3, it is attracted to a conveyor belt 15a by air suction force (direction indicated by an arrow) in a peeling device 15 and sent to the next process. A micro switch MS ₂ provided near the peeling device 15 detects when the transfer paper 13 is peeled off.

At this point, the toner image transferred to the transfer paper 13 is still in an unstable state and not completely fixed on the transfer paper 13, and it is necessary to fix the toner.
This is because the transfer paper 13 is conveyed by the conveyor belt 15a of the peeling device 15, sent to the fixing section 16,
The toner image is fixed.

The toner fixing section 16 is provided with a heater lamp HL serving as a heat source, and thermal fixing is performed using this heat source. Further, there is an optimum temperature range for toner fixing in the fixing section 16, and unless the temperature rises above this temperature, the copying operation will not be executed. The above temperature is about 300°C. Further, the transfer paper holder 17 of the fixing unit 16 is at the position shown by the solid line when the power is turned on, and at the position shown by the dotted line when the power is turned on. The micro switch _MS8 detects this state. For example, the fixing unit 16 moves this pedestal 17 as shown by the dotted line when power is no longer supplied.
If a jam occurs in the transfer paper, the power supply section is opened, and at this time, it is kept away from the heater lamp HL to prevent the transfer paper 13 from catching fire in the fixing section 16, and also to facilitate the removal of the transfer paper 13. ing.

The transfer paper 13 conveyed within the fixing section 16 is conveyed out from the paper outlet 5 by the rotation of the conveyance roller 22. A micro switch MS ₃ installed near the paper output port 5 detects this paper output. Note that 23 is for detecting the slip roller jam, and roller 23a is a driving roller and 23b is a driven roller.If the transfer paper 13 is being conveyed normally, the rotation of the driving roller 23a is transmitted to the roller 23b. If the paper is not conveyed normally, for example if a jam occurs, the rotation will not be transmitted and the jam will be detected.

On the other hand, the reference numeral 18 in the figure is a static eliminator for removing static from the transfer paper 13, and unlike the other chargers 6 and 12, the static electricity is removed by alternating current corona discharge. Also, although the photoreceptor 13 is not shown in the figure, it is equipped with a heater lamp.
The charge is removed by the light beam from the HL, and the surface is cleaned by the cleaner brush 19, in preparation for the next electrostatic latent image formation.

Here, the static eliminator 18 and the transfer charger 1
In both cases, when the high voltage generating unit THVU is energized, static electricity is removed by corona discharge and charging for transfer is performed.
The THVU is energized when the relay is turned on by a control signal from the control circuit and its contact THVR-a is closed.

Further, the document table 8 starts to move (feed) in synchronization with the movement of the rotary drum 1 to reach a predetermined rotational position, and returns to the original position when the movement exceeds a predetermined length (hereinafter referred to as overrun). controlled. Therefore, a micro switch MS ₄ installed opposite the actuating piece 8a that is interlocked with the movement of the document table 8 detects the initial stop position of the document table 8, and a micro switch MS4 that detects an overrun of the document table 8 is used. Micro switch installed opposite to switch MS _4
MS5 .

The present invention is directed to the control of various mechanisms in the general copying machine constructed as described above, such as the feed and return of the driving document table 8 of the rotating drum 1, the conveyance of transfer paper, the chargers 6 and 12, the static eliminator 18, etc. is controlled by a one-chip microprocessor. A series of operations of the copying machine configured as shown in FIG. 1 will be briefly explained.

First, when the power switch MSW is turned on, the main motor MM rotates. Also, power relay contacts
PR-a and PR-b (see Figure 2) are closed, heater lamps HL ₂ and HL ₃ are turned on to raise the temperature of the fixing section 16, and when the temperature reaches the specified temperature, a message indicating that copying is possible is displayed. Ru. Therefore, when the print switch PSW is pressed, the rotary drum 1 rotates, and in synchronization with this, various mechanisms operate depending on the operating state of each microswitch. Therefore, when the rotating drum 1 reaches a certain position, the light source lamp of the lighting device 9
CL lights up, the surface of the photoreceptor 3 is charged by each charger, and the document table 8 starts moving. On the other hand, if the microswitch MS ₁ detects paper entry, the paper stopper 14 opens in synchronization with the rotation of the drum 1, and the transfer paper 13 is transported by the transport roller 21.

On the other hand, an electrostatic latent image is formed on the photoreceptor 3 in the exposure section 7, and this latent image becomes a toner image in the developing device 11 and is sent to the transfer section for the next step. The transfer paper 13 conveyed to the photoreceptor 3 is brought into close contact with the photoreceptor 3 in a well-timed manner, and the toner image is transferred onto the transfer paper 13 by the transfer charger 12. After that, the transfer paper on which the toner image has been transferred is peeled off from the photoreceptor 3 of the drum 1, and in the peeling device 15, it is attracted to the conveyor belt 15a by air suction force, and the static electricity is removed by the static eliminator 18, and the heater lamp EL is removed. The image is transported to the built-in fixing unit 16. Then, the transfer paper 13 is transferred to the fixing section 1
6 and is transported to the outside from the paper output port 5 by the delivery roller 22.

On the other hand, as the drum 1 rotates, the surface of the photoreceptor 3 is neutralized by light beams from the heater lamp HL of the fixing section 16, and the surface of the photoreceptor 3 is neutralized and cleaned through the cleaner brush 19, in preparation for forming the next electrostatic latent image. It will be done. Furthermore, the document table 8 is in an overrun state,
When the state is detected by micro switch MS ₅ and returned to the original stop position, switch MS ₄ detects this and stops. Further, the rotating drum 1 also stops at the initial stop position. In this case, the number of copies is one, and in the case of multiple copies, after the above operation is repeated several times and a predetermined number of copies are made,
Copy operation stops. For example, when making multiple copies, a multi-copy dial is provided and the copying operation is stopped when this dial reaches 0. This is detected by the micro switch MS ₆ installed in the multi-copy dial section. be.

In order to operate and copy as described above, the control of the present invention is performed by a microprocessor. FIG. 3 is a control block diagram of the copying machine according to the present invention. In FIG. 3, numeral 30 is a microprocessor (hereinafter referred to as a control element) consisting of one chip and one package, and a solenoid, which operates a copying operation via a driver circuit 32 in response to a control signal 31 from this control element 30, Energizing relays, etc. (hereinafter, “ON” means when energized, “OFF” means when not energized)
Described as . )I do. For example, when the drum feed clutch DFC is turned on, the rotating drum 1 starts rotating. In order to control these various solenoids, relays, etc., a synchronization signal 33 for the copying operation accompanying the rotation of the drum 1 is input to the control element 30, and the synchronization signal 33 controls the various copying operations explained in FIG. A signal 35 (hereinafter referred to as a strobe signal) for confirming the detection state of the microswitch group 34 to be detected is derived from the control element 30. By applying this strobe signal 35 to a group of switches, etc., and inputting its output to the control element 30, the current state of each microswitch can be confirmed. The confirmation state at this time and the synchronization signal 33 are combined to output the control signal 31 as described above from the control element 30,
Controls copying of the copying machine.

The synchronizing signal 33 input to the control element 30 is generated by a signal generating section 37 as the rotary drum 1 rotates. In other words, the synchronizing signal generating section 37 is formed by a slit Pa on the outer periphery of a disc 24 shown in FIG.
A slit Pb is provided on the inner periphery, and photoelectric conversion devices each comprising a light emitting element and a light receiving element are arranged through the slit. Therefore, a signal 33 synchronized with the rotation of the drum 1 is output from the synchronization signal generator 37. The position indicated by the arrow in FIG. 4 is the initial stop position of the rotating drum 1. or,
In this state, a synchronizing signal is obtained via the slits Pa-0 and Pb-1. In addition, 38 in the figure is the control element 30.
The control element 30 is set to the initial state when the power of the copying machine is turned on.

Reference numeral 39 denotes a WTL level control circuit which controls the temperature in the fixing section 16 and keeps the temperature constant by controlling two heater lamps HL ₂ and HL ₃ . The output from this circuit is input to the control element 30. If the output from the circuit 39 is a logical value "1", the temperature of the fixing unit 16 has reached the specified value, and if the output is a logical value "0", the temperature of the fixing unit 16 has reached the specified value. It is configured to be input to the control element 30 as being below a specified value.

Furthermore, 40 is a circuit for detecting the slippage roller jam. That is, if an abnormality occurs in the operation of the roller 23 explained in FIG. 1, it is detected and the control element 3
The signal of that state is input to 0. In short, if the logic value is "1", it is a signal indicating that a jam state has been detected, and if the logic value is "0", it is a signal indicating normal operation.

To briefly explain the operation of the block diagram shown in FIG. 3, the main motor MM rotates by closing the power switch MSW shown in FIG. Element 30 is set to an initial state. Thereafter, the drum and document table 8 rotate and move, respectively, and stop at the stop positions. Now, if the signal from the WTL circuit 39 is "1", when the print switch PSW is pressed, the control signal 31 is output from the control element 30 and is passed through the driver circuit 32 to the drum feed clutch DFC.
turns ON and rotating drum 1 rotates. This rotation of the drum 1 causes a synchronization signal 33 to be input to the control element 30. Therefore, the control element 30 derives a strobe signal 35, checks the operating state of each microswitch, etc., and outputs the control signal 31 at that time to the driver circuit 32. The control signal 31 causes a solenoid, relay, etc. to be activated via the driver circuit 32.
When it is turned on, charging or document table movement is controlled and copying operations are performed sequentially.

Next, the control element 30, which is the gist of the present invention, will be explained. The control element 30 has a lead for reading.
Only memory section (hereinafter referred to as ROM), read/write memory section for reading and writing (hereinafter referred to as RAM), accumulator section for arithmetic control, input/output section, clock generation section for timing, and power supply It consists of an input section. FIG. 5 is a block diagram showing the internal structure of the control element 30, and the ROM 41 has an 8-bit parallel output I ₁ to _{I 8 .}
It memorizes instructions consisting of signals, and uses 64 words (steps) as one delimiter.
It consists of pages _P0 to _P13 .

That is, the ROM 41 stores various instructions necessary for controlling the copying machine according to the present invention.
The stored instructions are sequentially read out, and the signals I ₁ to I ₈ composing the read instructions are input to each control circuit, as will be explained later, and are also processed by the logic processing of this control circuit. The control element 30 is configured to derive signals such as control signals to the outside of the control element 30.

To explain in more detail, the control section of the ROM 41 has a 6-bit counter PL for addressing an arbitrary step on each page, and this counter PL is used to output jump command instructions from the ROM. Other than that, the count-up is done one step at a time. It also has a 4-bit counter Pu for addressing any page from page _P0 to page _P13 . This counter Pu differs from the above-mentioned counter PL in that the contents of the counter change at the time of a specific instruction. counter
The address signal from the PL is passed through the decoder 42 to address an arbitrary step in the ROM 41, so that the ROM 41 outputs all instructions for the same step from page _P0 to page _P13 . The signal is input to the gate circuit 43. This gate circuit 43 receives a signal from a counter Pu that addresses a page via a decoder 45, and outputs code signals _I1 to _I8 of an arbitrary page instruction. This output instruction code signal I ₁
~ _I8 is transferred to the instruction matrix ROM 44 which decodes the instruction. This instruction matrix ROM4
4 outputs the opening/closing control of the logic circuit of each control unit that processes the read instructions, that is, the micro-order serving as the input condition. This is one of the characteristics of microprocessors.

The above counters PL and Pu are counted up by one after the instruction is executed, and the counter Pu is maintained in the same state, except when jumping to an arbitrary step by an instruction. Instructions written in the ROM 41 are read out. On the other hand, it has stack registers SL and Su, which have the same bit configuration as counters PL and Pu. That is, when the instruction indicating the jump command is read from the ROM 41, the contents of the counter PL that is currently being executed incremented by one are stored in the stack register SL, and the contents of the counter Pu are stored as they are in the stack register. Memorized by Su. Then, change the jump destination from the jump instruction to the counter PL,
In this state, the instructions are executed as described above, and the contents of the counter PL are sequentially counted up and the instructions are sequentially read out. After that, when the instruction to return from the jump destination is read out from the ROM 41, the contents of the stack registers SL and Su are transferred to the counters PL and Pu, and one step from the step from which the jump instruction was read out,
Return to count up state.

The above is an overview of the ROM 41.

The instructions written next to the ROM 41 are shown in FIG. In Figure 6,
Instructions for controlling the address of the ROM 41 include TR ₁ , TR ₀ , SSR, RTN, and RTN ₁ . Here, ROM41 has a subroutine page.
Although P ₀ , P ₁ , P ₂ , and P ₃ are predetermined, it is also possible to use all pages as the main routine. During the main routine, when this instruction is read by the ROM 41, the SSR above generates instruction code signals _I1 to _I4 .
This is an instruction to transfer the file to the stack register Su. As the code of this SSR is shown in FIG. 6, I ₈ to _{I 1} are “0111××××”. By inputting this code to the instruction matrix ROM 44, micro-orders that are input conditions for various logic circuits such as the counters PL, Pu, stack registers SL, and Su mentioned above for processing SSR instructions are output. be done. From this, the logic circuit of the stack register Su is as shown in FIG.
〜109a, and this ANDGADE 106
a~179a becomes valid, or gate 106~
109, _I1 to _I4 are connected to the stack registers, respectively.
Input into Su ₁ to _{Su 4} .

During the main routine, TR ₀ is the instruction code I ₁ to I ₆ on the same page.
This is an instruction to jump to 63 steps. The code at this time is "10××××××", which causes the instruction matrix
A micro order is output from the ROM 44.
That is, in FIG. 8, the instruction code
Since _I8 is “1”, AND gate 71a~
76a becomes valid, and the contents of codes I ₁ to I ₆ are sent to counters PL ₁ to PL 1 through OR gates 71 to 76.
It is input to PL ₆ and its contents are changed to the contents shown in the codes I ₁ to I ₆ above, and the steps of the contents shown in the codes I ₁ to I ₆ are addressed.

Also, if data is stored in the stack register Su, the contents are transferred to the counter Pu,
Jump to any page. This is SSR and TR ₀
This composes a compound instruction, and when SSR is first read, the stack register Su
When TR _{0 is} read out, the contents of the stack register Su are transferred to the counter Pu, and the contents of I ₁ to _{I 6 are} input to the counter PL. This means that the page jumps to the step specified by the counter PL of an arbitrary page.

Next, TR ₁ is an instruction that jumps to a subroutine when this instruction is read during the main routine. At this time, subroutine P jumps to page ₀ . In this case, the codes I ₈ to I ₁ are "11××××××" and the micro order is not output. First, in Figure 10,
The contents of counters PL ₁ to _{PL 6} are set to 1 by the adder 46.
Step count up and stack register
Transferred to SL ₁ to _{SL 6} . Since I ₈ = I ₇ = “1”, as will be explained later, the contents of counters PL ₁ to _{PL 6} are incremented by one step at the timing of clock C ₁ and are stored in stack registers SL 1 to SL ₁ .
Transferred to SL ₆ . In addition, in FIG. 7, since the micro order is not output, the AND gate 106
b to 109b become valid, and the contents of counters Pu ₁ to _{Pu 4} are transferred to stack registers Su ₁ to _{Su 4} . On the other hand, no signals are input to the counters Pu ₁ to Pu ₄ , and the counters Pu ₁ to _{Pu 4} all become "0" and designate the P ₀ page, which is the subroutine page.
Furthermore, in FIG. 8, since the code _I8 is "1", the contents of _I1 to _I6 are transferred to the counters _PL1 to _PL6 , which instruct the step of the contents of _I1 to _I6 of page _P0 . .

Further, RTN is an instruction for returning from a subroutine to the main routine, and returns to the next step after jumping to the subroutine with the instruction _TR1 . In other words, when RTN is read during a subroutine, it is used to instruct the next step after the subroutine jump.
Set the contents of Pu and PL counters. When instruction TR ₁ that performs a subroutine jump is read, the contents of counter Pu are moved to stack register Su, while the contents of counter PL are incremented by one step and transferred to stack register SL. ing. Therefore, it will be understood that the contents of the stack register Su should be transferred to the counter Pu, and the contents of the stack register SL should be transferred to the counter PL. The code of this RTN instruction is "01011110", and the micro order is derived.

That is, in FIG. 9, the AND gate 89
a, 90h, 91a, 92a become valid, OR gate 89, AND gate 90, OR gate 9
1,92, the stack registers Su ₁ to _{Su 4}
The contents of are transferred to counters Pu ₁ to _{Pu 4} , respectively.
Here, ACL in the figure is a signal from the signal generation source 37 at the time of power-on described in FIG. 3, which is output at a certain time when the power is turned on. That is, the signal is
Counter Pu ₁ is “1” when input to ACL
Pu ₂ is “0”, Pu ₃ is “1”, and Pu ₄ is “1”.
P13 page of ROM41 is specified. Similar to the instruction RTN above, RTN ₁ returns from the subroutine to the main routine, and TR ₁
Skips the instruction written in the step following the step that jumps to the subroutine with the instruction. That is,
The second step instruction is derived from the step of the instruction in TR ₁ and executed. This is because the output signal of the flip-flop J for skipping the next step instruction is input to the gate circuit 43 via the inverter, and if the flip-flop J is set, the next step instruction is skipped. be done. Therefore, when RTN1 is read,
Flip-flop J is set and the instruction next to the step that jumps to the subroutine by the instruction TR1 is skipped.

As described above, the ROM41 is controlled and the ROM41 is controlled.
When the instructions written in 41 are read out, micro-orders are output that serve as input conditions for various logic circuits that process the instructions. With this micro-order output,
The read instructions are processed, and as will be explained in detail later, a control signal for controlling the copying machine is derived from the output section.

Next, the RAM 50 in the control element 30 will be explained. The control section of the RAM 50 has a 4-bit counter BL for addressing arbitrary words (steps), similar to the ROM, and the count contents of this counter BL can be changed by instructions. There is. However, if the instruction does not change the contents of the counter BL, the counter BL always retains its contents. Also, RAM50 block 0~
It has a 2-bit counter Bu that addresses any block of 3, and like the counter BL, it has a ROM
The instructions read from 41 maintain the contents of the counter Bu except for those that change the contents.

The output of the counter BL is input to the decoder 51, and the output of the decoder 51 addresses an arbitrary word in blocks 0 to 3 of the same step of the RAM 50, and the addressed arbitrary word is input to the gate circuit 51.
Input/output is possible via 3. Also, counter Bu
The output is input to the decoder 54, and the decoded output enables the gate section of the gate circuit 53 of any selected block among blocks 0 to 3 of the RAM 50. Therefore, any step in one block of RAM 50 can be input/output by the outputs of counters BL and Bu.

Further, the input/output signal is input/outputted via the gate circuit 53 in a 4-bit parallel manner. That is, the input signal
The contents of M ₁ I to M ₄ I are stored in any step addressed by the counter BL in any block addressed by the counter Bu. Contrary to the above, the output signals M ₁₀ to _{M 40} are output signals of the contents stored in an arbitrary step in an arbitrary block.

Here, as shown in the time chart of FIG. 11, the clock signal C ₁ ,
C ₂ and C ₃ are output, and the above input signal M ₁ I~
_M4I is RAM50 at the timing of clock signal _C1 .
The content can be entered into the
The contents stored in the RAM 50 are output as an output signal via the gate circuit 53 at the timing of the clock signal _C3 .
Output as M ₁₀ to M ₄₀ . Although it is not described in the ROM 41 section, reading instructions from the ROM 41 is performed using the clock signal mentioned above.
This is done at the timing of _C1 , and the time it takes to read the next step instruction is approximately 10μ.
sec.

On the other hand, the decoder 51 addresses the RAM 50 and outputs a decoded output to the outside of the control element. This output signal is derived from the terminal S ₁ when the content of the counter BL is "15", the terminal S ₂ when the content is "14", the terminal S ₃ when the content is "13", etc. ”, a signal is derived from the signal terminal _S7 . This output terminal
The signals S ₁ to _{S 7} are used, for example, as key strobe signals when the keys of the input section of a computer are connected, and as will be explained later in the present invention, they are used as key strobe signals when the keys of the input section of a computer are connected. It is used to check the operating status of the group.

The RAM 50 section is configured as described above, and its operation will be briefly explained below using instructions read from the ROM 41.

For example, when instruction LB is read from ROM 41, instruction code I ₁
~Move the contents of I ₅ to address counters Bu, BL,
This is to specify an arbitrary location in the RAM 50.
The content of counter BL is “0000” “1100”
It is set to either "1101", "1110", or "1111". Further, the counter Bu can specify 0 to 3 blocks. This state is shown in FIG. In other words, as shown in Fig. 6, when LB is read out, a micro order is output, and this micro order and instruction code _I3 are sent to a counter via an AND gate.
Input to BL ₁ , counter BL ₂ receives AND gate output of and I ₄ , BL ₃ receives AND gate output of I ₃ , I ₄ , I ₅ , and same as BL ₃ .
A control circuit is configured to input the OR outputs and AND gate outputs of I ₃ , I ₄ , and I ₅ to BL ₄ , respectively. Therefore, from FIG. 12, when setting the contents of the counter BL to "0000", the instruction code only needs to be "000" for I ₅ , I ₄ , and I ₃ , and the counter
When setting the contents of BL to “1100” When setting I ₅ , I ₄ , and I ₃ to “100” and setting the contents of counter BL to “1101”
If I ₅ , I ₄ , I ₃ are “001”, “1110”, “010”,
You will understand that if you want to set it to "1111", you should set it to "011".

On the other hand, instruction codes I ₂ and I ₁ are RAM
It specifies one of the blocks, and the AND gate output of instruction code _I1 and micro order is sent to counter _Bu1 , and _I2
The AND gate output of and is input to counter Bu ₂ . That is, when specifying block "0" in the RAM 50, the contents of the Bu counter are "00" and the codes I ₂ and I ₁ need only be set to "00". Similarly, if I ₂ and I ₁ are “01”, the counter Bu will be “01” and the first block of RAM blocks will be
If I ₂ and I ₁ are "10", the counter Bu becomes "10" and designates the second block, and if I ₂ and I ₁ are "11", the counter Bu becomes "11" and designates the third block.

Here, instruction LB from ROM41
is read out and the code at that time is “01000100”, since I ₅ , I ₄ , and I ₃ are “011” and I ₂ and I ₁ are “00”, the contents of the counter BL are “ 1101", and the contents of counter B become "00". Therefore, as shown in FIG.
It can be seen that the 13th step, 4, is specified. still,
Each step consists of 4 bits, and each bit corresponds to each input/output signal M ₁ I to M ₄ I, M ₁₀ as described above.
~ _M40 , and one bit consists of one flip-flop.

Also, instruction SM (“000011××”)
When this is output, for example, out of the 4 bits of the RAM 50 addressed by LB, 1 bit specified by the instruction codes I ₂ and I ₁ is set. That is, the above codes I ₂ and I ₁ are "00" for the 0th bit, "01" for the 1st bit,
“10” sets the 2nd bit, and “11” sets the 3rd bit. For example, when setting the third bit,
It is sufficient if I ₂ and I ₁ are “11”, and at this time the input signal
The logic circuit is configured so that M ₄ I becomes "1". Also, the previous state of the other bits is maintained. Further, when RSM is output, one bit specified by instructions I ₂ and I ₁ out of the 4 bits addressed in the opposite direction to the instruction SM is reset. The instruction code I ₈ to _{I 1} at this time is “000001××”, and since I ₄ is “1” in the SM instruction and I ₄ is “0” in this RSM,
By inputting the code I ₄ to one input terminal of the AND gate and inputting I ₂ , I ₁ to the other input terminal, I ₂ , I ₁
The input signals M ₁ I to M ₄ I of the bits specified by are input to the gate circuit 53 as "0", and the specified bits are reset. Here, the micro-order derived at the time of RSM and SM is 〓, and this 〓 is used as the control signal of the gate and the ROM 41
It constitutes the logic circuit explained above. Next, the accumulator section shown in FIG. 5 will be explained. This accumulator section serves as a relay section for data transfer. Also, this accumulator section has accumulators _A1 to _A4 of 4-bit configuration,
The clock signal input to the accumulator is such that the clock signal C ₁ is input to the accumulator only when an instruction for executing transfer is read out, and this instruction causes the accumulator A ₁ to _A4 is set or reset. Also, accumulator A ₁
~ _A4 is connected to 4-bit binary adders FA1 _{to FA4 ,} and during addition or transfer, it is executed via a carry flip-flop C, and all arithmetic control is performed by the accumulator _A1 . ~ Done via _A4 .

Here, the instructions shown in Figure 6
When KTA is read, the contents of counters _K1 to _K4 are transferred to the accumulator. At this time, the micro orders 〓 and 〓 are derived from the instruction matrix 44. Therefore, in FIG. 14, the OR gates 61 to 64, which are the set inputs of the accumulators _A1 to _A4 , are the AND gates 61a to 64, since the micro order 〓 is derived.
4a becomes valid and outputs the contents of counters _K1 to _K4 . Therefore, the contents of the counters _K1 to K4 are input to each of _the accumulators A1 to _A4 , and since the micro order is derived, the contents of the counters _K1 to _A4 are input to the accumulators _A1 to _A4 at the timing of the clock _C1.
~K ₄ contents are transferred. Also, when the instruction TAM is read, the accumulator A ₁ ~
If the output signals _M10 to _M40 from the RAM 50 addressed as _A4 match, the instruction in the next step of the ROM 41 is not executed, but the second instruction is executed. That is, if they match, it is skipped. At this time, the micro order is output. By outputting the micro order, AND gates 81, 82b, 83, 84b, 85, 86b, 8 are activated as shown in the logic circuit of FIG.
7, 88b are enabled, and _AND gates ₈₁ , _{83 ,} 85,
The contents of the accumulators A ₄ to _{A 1} are input through the input terminals b ₄ to b ₁ through the OR gates 8
Output of RAM50 via 2, 84, 86, 88
_M40 to _M10 are entered. Here, the accumulators A ₄ to _{A 1} input to the adders FA ₄ to FA ₁
and the outputs M ₄₀ to _{M 10} of the RAM 50 through matching gates, check whether they match or not, AND each output from the matching gates, and perform a skip using the output of the flip-flop J. is being entered.

That is, the output of accumulators A ₄ to A ₁ and RAM 50
If the contents of _M40 to _M10 match, a logic output "1" is derived from each match gate, and the output is input to flip-flop J via an AND gate. Therefore, the flip-flop J is set and the next instruction is skipped.

Conversely, if the contents of the accumulators _A4 to _A1 and the outputs _M40 to _M10 of the RAM 50 do not match, the flip-flop J will not be set and the next instruction will be read and executed. be done.

On the other hand, regarding the input/output section, this input/output section is
It is controlled by instructions read from the ROM 41.

First, as an input section according to the present invention, the strobe signal derived from the control element 30 explained in FIG. ₃ is inputted via the switch group according to the present invention. There are synchronization signal input sections α and β for synchronizing the driven copying machine. These input parts α and β are the rotary drum 1
The slit of the disk 24 provided on the same axis as
A signal from a synchronization signal generator obtained via Pa and Pb is input. A signal obtained from the slit Pa of the disk 24 is input to the input section α, and a signal obtained from the slit Pb of the disk 24 is input to the input section β. In the following explanation, PA and PB will be described as synchronization signals.

Further, there is an input section _KN1 for inputting a signal from the WTL circuit 39, and an input section KF for inputting a signal from the slip-roller jam detection circuit.

Furthermore, as explained in FIG. 3 as an input section, there is an ACL input section that performs initial settings when the power is turned on, and when a signal is input to this input section ACL, the flip-flops are reset and the ROM 41 is reset.
P13 page is now set.

On the other hand, the output section is a 4-bit register.
There are registers _F1 to _F4 and 15-bit registers _W1 to _W15 , which are output in parallel. The registers W ₁ to W ₁₅ are output when the flip-flop Np is set.

That is, in the present invention, various controls of the copying machine are performed by signals output in parallel from the registers _F1 to _F4 and registers _W1 to _W15 . Note that clock signals C ₁ to _{C 3} for operating each circuit in the control element 30
is output from a clock generator 60, and this clock generator 60 is executed by inputting a signal from an externally connected clock generating means 59 to a clock signal input section φ. Clock signals C ₁ , C ₂ and C ₃ are generated in the relationship as shown. Further, the power input section is for supplying power to the control element 30 to operate it, and its explanation will be omitted.

As described above, the inside of the microprocessor or control element 30 according to the present invention is configured.

Therefore, instructions for controlling the copying machine according to the present invention are stored in the ROM 41 in the control element 30. the above
The contents of the instructions written in P ₀ to _{P 13} of the ROM 41 are shown for each page in FIGS. 15 to 28. This content controls the copying machine having the configuration shown in FIG. 1, and if it is desired to add other functions, this can be easily done by changing the content of the instructions written in the ROM 41.

The flowchart diagrams for the instructions shown in Figures 15 to 28 are shown in Figures 29 to 3.
The copy control according to the present invention will be described in detail below with reference to this flowchart.

First, when the power switch of the copying machine is turned on, the main switch MSW shown in the circuit diagram shown in FIG. This signal is input to ACL, and this signal input causes ROM4
The counter Pu that addresses pages P ₀ to P ₁₃ of 1 is
Pu ₁ becomes "1", Pu ₂ becomes "0", Pu ₃ becomes "1", Pu ₄ becomes "1", and the P13 page is specified. On the other hand, all counters PL become "0".

Therefore, the registers F ₁ to _{F 4} in the control element 30 are cleared, and the contents of the RAM 50 are all set to “0”.
Make it. This means that when the power is turned on, the contents of the counter Pu specify "1101" and the counter PL is "0".
Therefore, the 0th step instruction LAX on page P13 of ROM41 (see Figure 15)
is read out. This LAX is for inputting instruction codes I ₄ to I ₁ to the accumulator, and the codes of I ₄ to I ₁ at this time are "0000".
After executing this instruction, the next instruction ATF is read from the ROM 41 in order to increment the counter PL by one step.
The above ATF is an instruction for transferring the data of the accumulators A ₁ to _{A 4} to the registers F ₁ to F ₄ , and the above registers F ₁ to _{F 4} are cleared. That is, no control signal is output. after that
An instruction called IDFS is read.
The instruction IDFS is for setting the flip-flop IDF in the control element 30, and the input terminal of the flip-flop IDF has a gate opened by the micro-order derived at the time of this instruction, and a set input is applied to the input terminal of the flip-flop IDF. The flipflop IDF is set. Here, the output of the flip-flop IDF is output as a control signal for the jam lamp JL, which will be explained later. Subsequently, the NPR is read out and the flip-flop NP is reset in order to derive a control signal to the outside. Furthermore, when the next instruction RSC is read out, the flip-flop C is reset. The above-mentioned flip-flop C applies its output to the gate 52 to derive a strobe signal, and in the set state, all strobe signals are sent to the terminal _S1.
-S7 , and if it has been reset, a strobe signal is output from any terminal _S1 - _S7 depending on the contents of the counter BL.

After the above instruction is completed, the instruction LB is read out. This instruction LB is as explained in the RAM 51, and since the codes _I5 to _I1 at this time are "00000", the 0 step of the 0th block is written to the counters Bu and BL.
Specify in. As shown in FIG. 12, designated location 0 of the RAM 50 is designated.

Then, the next instruction _TR1 is read out and a subroutine jump is performed. With this instruction, the contents of the counter Pu are transferred to the stack register Su, and the contents of the counter PL are counted up by one step and transferred to the stack register SL. This is as explained in the control of the ROM 41. They will be omitted in the following description. Note that the content of the counter Bu is "00" and the content of the counter BL is "0000". After the instruction TR ₁ is read out, the program jumps to page P0 of the subroutine (see FIG. 28), and the sixth step instruction TR ₁ is read out. TR ₁ read on this subroutine page P0 jumps to subroutine page _{P 1} , and in FIG. ₂
~Pu ₄ becomes “0”. Therefore, counter Pu specifies page P1. On the other hand, the contents of the counter PL become "110110". Therefore, the 54th step instruction LAX on page P1 is read out.

The above instruction LAX is as explained above, and since the codes I ₄ to I ₁ at this time are "0000", the contents of the accumulator A are "0000". After this instruction is completed, EXCI is read. The above EXCI exchanges the contents of the accumulator A and the contents of the addressed RAM 50, and at the same time exchanges the instruction codes I ₁ and I ₂ and the contents of the address counters Bu ₁ and Bu ₂ of the currently addressed RAM block, and Although not shown, the output through the mismatch circuit is used as an address counter.
This is what is input to Bu. Furthermore, the address counter BL of each step is counted up, and if the content of BL is "1111", the instruction of the next step is skipped.

When this instruction EXCI is read, the contents of the RAM 50 at the 0th step of the 0th block become "0000", and the contents of the counter Bu become "00" since the codes I ₁ and I ₂ are "0". ,
On the other hand, the counter BL becomes "0001" and designates the 1st step of the 0th block. Here, since the content of the counter BL is "0001", the next instruction TRO is read out. This instruction jumps within the same page, and codes I ₁ to I ₆ are input to the counter PL, so the content of the counter becomes "110110". Therefore, the program jumps to step 54 on page P1, and the instruction LAX for this step is read out.

In short, the above operation is repeated and RAM50
The contents of each step of the 0th block are all “0”
, and if the count content of BL reaches "1111", instruction TRO will not be executed and the next instruction RTN will be output. The RTN stores the contents of the stack registers Su and SL as a counter.
Pu, PL, that is, return to the next step from which the jump instruction was read, and in this case return from the subroutine to the main routine. Therefore, the counter Pu becomes "1011" and the counter PL becomes "000111", and the instruction LB at that address is read out. RAM50 with this LB
The address counter Bu becomes "01" and the counter BL becomes "0000", specifying the 0 step of the first block of the RAM 50. (See Figure 12) Instruction TR ₁ is read out from the above, and the first
The contents of each step of the block are all set to "0".

The same goes for the second and third blocks, and the contents of the RAM 50 are set to "0". That is, the above-described operation sets the control element 30 to an initial state.

Next, return to flowchart Figure 29 and 0→
Once the RAM operation is complete, perform a test run. This test diagram is used to check whether each operation is executed reliably after manufacturing the copying machine according to the present invention, and in this explanation, all
It shall be judged as NO.

When the test adjustment is completed as described above, the contact JR-a of the jam relay JR is then adjusted. If a jam occurs in the transfer paper, etc., please contact the above contact point.
JR-a closes and notifies the user that there is a jam. For convenience of explanation, we will use Jam Relay JR here.
It is assumed that JR-a is not operating and its contact JR-a is open.

In this case, the above judgment is determined as NO, and the next microswitch _MS1 is turned on. This micro switch MS ₁ , each micro switch MS ₂ ~
MS ₈ , the jam relay contact JR-a, which closes when the master is replaced, and one of the print switches PSW are connected to the strobe output terminals S ₁ to _{S 7} of the control element 30, as shown in FIG.
The other end is commonly connected to terminals TAB, AK, and KN ₂ of the input section of the control element 30. The above is one feature of the present invention, and as is clear from FIG. 37, it will be seen that the number of connection lines to the control element 30 of the microswitch group is significantly reduced. That is, in the present invention, the state of each switch is serially viewed, and unlike the case of parallel viewing, there is no need for each connection line from each switch.In short, each strobe signal S Instead of deriving all of _S1 to _S7 , for example, one of the signals _S1 to _S7 is derived in accordance with the rotation of the drum 1.

Therefore, when changing the microswitch _MS1 , the 37th step _TR1 is read out from the ROM 41 in the instruction shown in FIG. So subroutine PO page 12
Jump on the first step. Therefore, the jump destination instruction LB is read out and stored in RAM5.
9 of the 14th step of the first block of 0 is specified, and the next instruction TR ₁ starts the subroutine.
Jumps to page P1 and the instruction SSR at the jump destination is read. Here, the counter BL which addresses the step by the above-mentioned instruction LB has its content "1110" and a strobe signal is outputted from the gate 52 via the decoder 50 from the terminal _S2 . This strobe signal _S2 is applied to a micro switch as shown in Fig. 37.
MS ₁ is input to this micro switch MS ₁
The NC side of is connected to the input part TAB of the control element 30, and the NO side is the input part TAB of the control element 30.
Connected to KN ₂ . That is, micro switch MS ₁
If is on the NC side, strobe signal _S2 is input to TAB. Note that the micro switch MS ₁ is for detecting paper entry, and at the moment there is no paper entry and it is lying on the contact NC side.

When the jump destination instruction SSR mentioned above is read out, a compound instruction is executed with the next instruction TRO, and the program jumps to the subroutine P2 page again. At this time, the jump destination is the 0th step of page P2 from the codes _I8 to _I1 , and the instruction LAX there is read out. Therefore, the contents of accumulator A are set to "0000" and the next instruction is
EXC is read. The above EXC shows the contents of accumulators A ₁ to _{A 4} and the addressed RAM 5.
This is an instruction for exchanging the contents of 0 (14th step of the 1st block), and
Codes I ₁ and I ₂ are used as RAM block address counters.
The signal passed through the mismatch circuit between Bu ₁ and Bu ₂ is input to the counter Bu. i.e. the RAM being addressed
Change the block from the next step. Therefore, since I ₂ =I ₁ =“1” in the RAM block, the counter Bu becomes “10” and the second block is designated. At this time, the designated location 10 of the RAM 50 shown in FIG. 12 is designated. After executing the above instruction, instruction LAX is read and accumulator A becomes "0000", and the next instruction EXC sets the contents of the 14th step of the second block of RAM 50 to "0000", and the address counter is set to "0000". Set Bu to “01” to specify the first block.

After the above, when instruction LAX of the fourth step on page P2 (see FIG. 26) is read out, 3, ie, "0011" is input to accumulator A. Then, instruction TTAB is output. This TTAB is the input part of the control element 30
If TAB is "1", the next instruction will be skipped. Therefore, since the microswitch _S1 is tilted to the NC side, the strobe signal _S2 of "1" is input to the input section TAB, and the operating state of the microswitch _MS1 can be confirmed. Therefore, since the input terminal TAB is "1", the next instruction TRO is skipped. This will cause the 7th step on page P2 to be
ADD11 is executed. Here, ADD is the data of accumulator A and the RAM being addressed.
, and sets the addition result to accumulator A.
11 skips the next step instruction if the carry from the adder FA is "0" in the above addition result.

Therefore, the contents of the accumulators A ₁ to A 4 are input to each input terminal a of the adder FA, and the contents of the accumulators A 1 to _{A 4} are input to the input terminal b of the adder FA.
The output data M ₁₀ to _{M 40} of the RAM 50 are input and addition is performed, and the first bit of the flip-flop C is also added. Note that flip-flop C has been reset. i.e. output data
Since _M10 to _M40 are "0000", the addition output from the adder FA is "0011", the carry output is "0", and the output "0011" is transferred to the accumulator A.

Therefore, the ninth step EXC is executed next. With this instruction, the contents of the accumulator A are stored in the designated location (9) of the 14th step of the first block of the RAM 50. Here, since the codes I ₂ and I ₁ are "00", the first block of the RAM 50 is designated without changing the contents of the counter Bu ("10"). After that, the 10th step instruction TRO is executed. Therefore, the process returns to step 4 on the same page and LAX is executed. As a result, the accumulator A becomes "0011" and the confirmation of the microswitch _MS1 is executed again in the next instruction TTAB, and the ADD11 in the 7th step is read. And earlier
“0011” stored in the designated location (9) of the RAM 50 and “0011” of the accumulator A are added, and the content (“0110”) is set in the accumulator A, and 9
At the step instruction EXC, the contents of the accumulator A are stored in the RAM 50 at address (9).

As described above, the above-mentioned operation is repeated, and 7
When the step instruction ADD11 is read out, if the addition contents of the adders _FA1 to _FA4 are 15 or more, the carry becomes "1" and the next instruction TRO is read out and executed. . Therefore, it jumps to 32 steps on the same page, the instruction RSC is read, and
Flip-flop C is reset. and,
When the instruction RTN is read out, the process returns to the main routine and the instruction in step 38 on page P13 is read out.

The operational status of the microswitch MS ₁ is confirmed by reading and executing the instructions as described above, but such confirmation is not made by checking a single signal, but by using an adder.
The addition is performed until a carry "1" is output from the FA, and the determination is made by repeatedly checking the strobe signal "1" input to the input terminal TAB. That is,
It will be seen that confirmation of the operating state of the micro switch MS ₁ becomes more reliable. In this example, the micro switch repeats the operation six times.
Checking the operating status of MS ₁ .

In other words, if a signal is input to the input terminal TAB or KN ₂ due to external noise, etc., the operation of the micro switch MS ₁ will not be automatically checked due to this erroneous signal, improving reliability. Probably.

On the other hand, the contact JR of the jam relay JR mentioned earlier
-When changing a, use the above micro switch.
This is the same as for MS ₁ , and the operating status of each microswitch MS ₂ to MS ₈ is also checked in the same way.

As explained above, here we will use the micro switch.
MS ₁ is judged as “NO” and the next micro switch MS ₂ is switched. Here, if the microswitches MS ₁ and MS ₂ are determined as Yes, the jam is processed as a jam, but this will be explained later. The above micro switch MS ₂ is used to detect the peeling of the transfer paper 13, and in this state it is not operating and is tilted toward the NC side, causing the strobe signal
_S3 is output and input to the input section TAB of the control element 30. Therefore, the operating status of the micro switch MS ₂ mentioned above has been checked many times, and the micro switch
MS ₂ is judged as “NO”. Next, the micro switch MS ₈ is activated. This micro switch MS ₈ detects the pedestal 17 of the fixing section 16, and as mentioned above, when the power switch is turned on, the pedestal 17 rises and detects this. Therefore, when the micro switch MS ₈ is determined to be NO, that is, it is determined that the rise of the pedestal 17 cannot be detected, the micro switch MS ₈ is switched again. Therefore, if the micro switch MS ₈ is judged as Yes, then the CSSR
is teased. This CSSR is set to the NO side (closed state) as shown in Fig. 37 by turning on the set of the relay CSSR when replacing the photoreceptor 3.
In this case, the above relay
CSSR is not on the NO side and is judged as “NO”. If the CSSR is NO, then a control signal for turning on the power relay PR is output from the output section of the control element 30. However, the control signal is not yet derived at the local point. This can be explained using the instructions in FIG. 15. TR ₁ of step 52 on page P13 is read and a jump is made to the subroutine. Therefore, the instruction LB for the P0 page step 53 is output, and the 0th block 13 step of the RAM 50, that is, (4) in FIG. 12 is specified. Then, when the instruction SM is read out, the second bit of the four bits at the specified location (4) is set. Here, the operating status of each load shown in the block diagram is as shown in Figure 35.
50, which is the 0th block, steps 12 to 15. Therefore, "1" is stored in the second bit of the designated location (4) of the RAM 50 in the power relay PR as ON.

After the above, when the instruction RTN is read on the subroutine P0 page, the program returns to the main routine, and jumps to the subroutine P0 page again to perform the test jump. Therefore
A test shot is performed, but if the answer is NO for explanation purposes, the WTL is shot next. The WTL inputs a signal of "1" from the WTL level control circuit 39 to the input section KN ₁ of the control element 30 when the temperature near the heater described in the fixing section 16 reaches a required temperature or higher. Therefore, the WTL jersey is “1” in the input section KN ₁ above.
If a signal is input, if it is judged as Yes, the ready lamp is turned off and the drum feed clutch DFC is turned on. Conversely, if the determination is NO, the above operation is performed after turning on the heater lamp relay HLR. If WTL is determined as NO at this time, in Figure 35, RAM
"1" is stored in the 0th bit of the specified location (8), "1" is stored in the 12th bit, and "0" is stored in the 1st bit. To explain the above with reference to FIG. 15, when the WTL flag is determined as NO, the subroutine returns to the main routine, the LB at step 59 on page P13 is read from the ROM 41, and the RAM 50 is read out.
The designated area (12) shown in Figure 12 is designated, and
According to the SM instruction, "1" is stored in the 0th bit of the specified location (12). Then SSR
Then, with the compound instruction TRO, the program jumps to _P12 , reads out the 0-step instruction _TR1, and jumps to the subroutine. In the instruction LB at this jump destination, RAM50
The designated location (12) is designated, the first bit of the designated location (12) is reset in the RSM, and "0" is stored, and the designated location (8) is designated with the next instruction LB. Therefore, in the next instruction SM, the 0th bit of the specified location (8) becomes "1", and it is stored that the drum feed clutch DFC is in the ON state. Then, TR ₁ is read out and stored in the RAM mentioned above.
The contents of designated locations (16), (4), (8), and (12) of the 0th block of 50 (see FIG. 35) are transferred to registers _W1 to _W15 to derive control signals. This is explained in TR ₁ above.
Jump to P ₁ and jump again to P ₂ with SSR and TRO instructions. NPR, which is the jump destination at this time, is read out and the flip-flop
NP is reset, the contents of register W are not output, and the control signal is stopped. Above register W
The control signal from the register W stores the contents of RAM50.
After the signal is transferred to , a flip-flop NP is set to derive the above signals in parallel.
Here, if the flip-flop NP is reset, the control signal will no longer be output, but this time is extremely short, so it does not pose a problem.

In this operation, the contents of the RAM 50 are transferred to the register W. After the instruction NPR is read, the next LB is read, and the specified location (16), which is the 0th block of the RAM 50, is specified. Therefore,
When TM is output, the 1st bit of the specified location (16) stores whether CSSR is set and is currently "0", so the next instruction TRO is issued and the same Jump to the page and read out the instruction W ₁ R. This W ₁ R inputs "0" to W ₁ of the register W and shifts it to the right once. In addition, there is W ₁ S, which is the opposite of the above and has “1” in register W ₁ .
This is an instruction to input and shift once to the right.

Therefore, when instruction W ₁ R is read, "0" is input to register W ₁ and shifted to the right. After that, TM is output and the second bit of the specified location (16) of the RAM 50 is output, and if this output is "1", the next instruction is skipped. The second bit stores the reset state of the CSSR similar to that described above, and its output is naturally "0", and this "0" is input to register _W1 and shifted to the right.

As described above, the contents of RAM50 are stored in the register.
For example, when the _instruction INCB is read out, the counter BL is counted up and its contents are set to " ₁₁₀₁ ". That is, the designated location (4) of the RAM 50 is designated. Therefore, the contents of this designated location (4) are transferred to registers W ₁ to W ₁₅ . Here, the power relay PR is stored in the second bit of the specified location (4), and this second bit is output as "1" and transferred to the register W.
Then, the contents of the RAM shown in Figure 35 are stored in the register.
Instructions when all are transferred to W ₁ to W ₁₅
When NPS is read and flip-flop NP is set, the contents of registers _W1 to _W15 are derived as control signals. In this case, the drum feed clutch DFC, power relay PR, and heater lamp relay HLR are turned on and the rotating drum 1
rotates and heater lamps HL ₂ , HL ₃ and HL ₁ are also turned on to act to increase the temperature in the fixing section. Meanwhile, jump to the main routine at the next instruction RTN. The reason why the rotary drum 1 rotates is to set the initial state of the drum 1, that is, the initial state of the copying machine. Therefore, if the copier is in its initial state and WTL is Yes, the print ready status will be displayed and the print switch will be pressed.
By pressing PSW, you can move to the copy cycle, but
For convenience of explanation, the explanation will be made according to the flowchart of FIG. 29. In the flowchart of FIG. 29, flip-flop D is reset. This flip-flop D is a flip-flop within the RAM 50, and is designated as a flip-flop within the RAM 50 as shown in FIG. In short, in the current state, all the flip-flops shown in FIG. 36 are in the reset state. After resetting the above D flip-flop, wait time level
WTL is jockeyed. As described above, if the temperature is above a certain temperature, it is determined as Yes, and the heater lamp relay HLR is turned off and the micro switch _MS4 is turned on. In other words, if the WTL does not exceed the specified temperature, the heater lamp relay HLR will be activated.
Turn on the three heater lamps HL ₁ to _{HL 3}
The temperature is further increased at .

On the other hand, the micro switch MS ₄ detects the initial stop position of the document table 8 as explained in FIG. 1, and if the document table 8 is in the initial state, it is determined as Yes. Therefore, turn off the document table return solenoid TRS and turn micro switch MS ₇ . The above micro switch
The conditions for MS ₄ are the same as those for the micro switch MS ₁ explained earlier, and the conditions have been confirmed and determined many times. Further, the document table return solenoid TRS merely returns the document table 3 to its original position, whereas TFC moves the document table 8.

Furthermore, the micro switch MS ₇ detects the insertion of the photoconductor 3 when replacing the photoconductor 3. In Fig. 37, it is normally tilted toward the NC side, and if it is switched, it is judged as NO. Turn off the photoconductor stopper solenoid MSS. After that, Slipprowler Gyam SRJ is shot. This SRJ is detected by the roller 23 described in FIG. 1, and its signal is inputted to the input section KF of the control element 30 from the slip roller jam detection circuit 40 in the block diagram shown in FIG. Therefore, in this case, the determination is NO and the synchronization signal PB is adjusted.

As for the synchronization signal PB, the instruction _TR1 of _P12 is read out, jumps to the subroutine PO, and then jumps to _P1 . Therefore, the 0 step LAX of _P1 is read out, the accumulator A is set to "0000", and then the instruction TB is output. The above TB skips the next instruction if the synchronization signal input part β is "1", while there is an instruction TA, which skips the next instruction if the synchronization signal input part α is "1". Skip the next instruction like TB. In addition, the synchronization signal is input to the input section α above.
When PA is input, there is a flip-flop αF to be set, and the instruction of TA resets the flip-flop αF. Then, by reading TB, if the synchronization signal PB is input to the input section β of the control element 30, ADX is read, and if it is not input, the instruction RTN to return to the main routine is read. the above
Reading the RTN indicates that the drum 1 is not in the initial state, and the operation of changing the WTL again is repeated. then sync signal
When PB is input, it is judged as Yes based on the PB direction. Synchronous signal in the above PB jersey
Since PB is input, ADX is read, and “0000” of accumulator A and codes I ₄ to _{I 1}
"0101" is added by the adder FA, and the contents are transferred to the accumulator A. On the other hand, adder FA does not output a carry, the next instruction RTN ₁ is skipped, TRO is executed, and instruction TB is read again.
From this, ADX is also executed, "0101" of accumulator A and "0101" of I ₄ to I ₁ are added, and the content "1010" is transferred to accumulator A. The above is repeated, and when a carry "1" is output from the adder FA, the instruction RTN ₁ is read out, the process returns to the main routine, and the 12-step instruction LB of _P12 is read out. And the next instruction TA
is output, and if the flip-flop αF is "1", that is, if the synchronization signal PA is input, the next instruction TR ₁ is executed,
Jump to subroutine PO to change WTL. Each operation below WTL is the same as that described above, and its explanation will be omitted.

Next, in the flowchart of Figure 29, PB
If the judge determines Yes, then PA
A ceremony will be held. Here, when PB is Yes, that is, when the synchronization signal PB-1 is input to the control element 30, PA is turned on twice (Pa-1 shown in FIG. 4).
1 and Pa-0) is detected, it is determined that the drum 1 is in the initial state, and an operation is performed to stop the rotation of the drum. In other words, when PB is Yes, the synchronization signal PA
If -11 is input to the control element, the signal on PA is Yes and the signal on flip-flop D is shifted. However, if PA is determined as NO, the wait time level WTL is again determined. Therefore, if PA is determined as Yes, the process moves to the D flip-flop, but since this flip-flop is not set ("1"), it is determined as NO. Next, the D flip-flop is set (to "1"). In this case, "1" is stored in the third bit of the designated location (0) of the RAM 50 shown in FIG. 36, and the D flip-flop is set. After WTL confirmation is executed again, the input state of PA-0 is confirmed. Therefore, the synchronization signal PA-0 is set to α of the control element 30.
If it is input to the terminal, it will be judged as Yes by the PA jack. At this time, if the next D flip-flop is changed, it will be determined as Yes since the previous flip-flop has been set. Incidentally, by executing the subsequent instruction, "0" is input to the third bit of the designated location (0) in the RAM, and this is stored. After the above-mentioned operation is completed, the A flip-flop is jumped, but the A flip-flop is in the reset state and is judged as NO, and the same goes for the next B flip-flop. Furthermore, the same applies to CSSR, and it is judged as NO. Note that the CSSR is used when replacing the photoreceptor 3, and will be omitted in the following explanation.

Based on the above, the high voltage generation relay THVR and drum feed clutch DFC are then turned OFF.
The relay THVR is as explained in FIG. 1, and when the relay THVR is turned on, the chargers 12 and 18
Charging is performed at Relay THVR is a power switch
It has been turned off since the MSW was turned on, and on the other hand,
The feed clutch DFC is turned ON and the rotation of the drum 1 is stopped. Incidentally, as will be explained later, the rotation of the drum 1 starts when the power is turned on.
The drum 1 starts rotating in any state, and stops when the drum 1 rotates to its initial state.
That is, the drum 1 is stopped based on the mutual relationship between the synchronizing signals PA and PB input to the α and β terminals of the control element 30.

To briefly explain what has happened so far, when the power switch MSW is turned on, the inside of the control element 30 is set to the initial state, the power relay PR is turned on, and the fixing unit 1 is turned on.
Turn on heater lamps HL ₂ and HL ₃ of 6. Also, set the drum 1 etc. to the initial state. Incidentally, if HL ₁ is required in addition to heater lamps HL ₂ and HL ₃ of the fixing section 16, the heater lamp relay HLR is turned on to light the heater lamp HL ₁ .

Once the copier is set to its initial state as described above,
In order to perform the next operation, instructions are sequentially read from the ROM 41 and various copying controls are executed.

Once the power is turned on and the initial state is set, the third
In the flowchart of Figure 0, first the micro switch MS ₄ is turned on. In the case of this MS ₄ , as described above, the strobe signal S ₁ is output, this signal is input to the input section KN ₂ , and the micro switch MS ₄ is judged as Yes. Therefore, the document table return solenoid
Turn TRS OFF (previously OFF) and turn on slipper roller jamb SRJ and micro switch MS ₂ . This jersey is NO in any case
It is judged that. On the other hand, if the microswitch MS ₂ is operating in this state, it will be treated as a jam.

Next, PB is adjusted, but since the rotary drum 1 is in its initial state, this synchronizing signal PB is naturally input to the input section β of the control element 30, and the result is determined as Yes. In addition, if the judgment of the above PB is NO, the drum feed clutch DFC is turned on to search for the initial position of the rotating drum 1 again.
and the operations described above are performed.

After the above, change WTL, but here,
If the temperature in the fixing section 16 is equal to or higher than the specified value,
WTL is judged as Yes, but if it is below the specified value, it is judged as NO and turns on the heater lamp relay HLR and turns off the ready lamp RL.
Then, the same operation described above is repeated. Then, when the temperature of the fixing section 16 rises and exceeds the specified value, a signal of "1" is input from the wait time level detection circuit 39 to the input section KN ₁ .
WTL is judged as Yes, and heater lamp relay HLR is turned OFF. After that, micro switch MS ₄ is judged as Yes and TRS, CHVR,
THVR and CLR are turned off. Here, CLR is a relay for the light source lamp of the illumination device, and when the relay is turned on, the lamp CL (see FIG. 2) lights up, illuminating the document table 8.

As the next operation, the preheat PH is adjusted. This preheating refers to the time when the power is turned on and the fixing unit 1
This means that the temperature of No. 6 was kept at a relatively low steady state. In other words, when changing the PH, the instruction LB at the 12th step of P11 can be explained using the instructions in Fig. 17.
is read out, the address counter BL of the RAM 50 becomes "1100", Bu becomes "01", and (17) is specified. The address counter BL is counted down by the next instruction DECB, and its contents become "1011". Here, as the counter BL becomes "1011", the strobe signal is sent to the terminal _S5 .
The signal is output from the input terminal AK of the control element 30 through a diode. On the other hand, the next instruction TR ₁ jumps to subroutine PO, but since TR ₁ is read at the jump destination, it jumps to subroutine P1 again.
Jump to P3 with the combined instruction of SSR and TRO and proceed to the 45th step as shown in Figure 25.
LAX is read. According to this instruction, the accumulator A becomes “0000” at LAX, and “0011” of the codes I ₄ to I ₁ at this time is added to the contents of the above accumulator A at the next ADX, and the result of the addition is added to the accumulator A. is input. the above
Since no carry is output from the adder FA in ADX, the next instruction is skipped and the instruction TAK is executed. This TAK
Since the strobe signal output from the terminal _S5 is input to the input terminal AK via the diode, the next instruction is skipped. This means that PH is judged as Yes, and the above operation is repeated and, like a micro switch, etc., the judgment is made by checking that the strobe signal is input to the input section many times. That's why we do it. Therefore, when a carry "1" is output from the adder FA by the ADX instruction, the instruction RTN ₁ to return to the main routine is read, and PH is judged as Yes.
Instructions for performing the test exercises
TR ₁ is read.

The preheating PH is provided because, for example, if the copying machine is turned on and left unattended, the heater lamp HL in the fixing section remains lit, which wastes power. Therefore, as mentioned above, a diode DPH is used to perform preheating PH.
are connected as shown in FIG. 37, and the auto preheat state is set after, for example, two minutes have elapsed from the time when the PH is adjusted. That is,
In this state, the power supply to the heater lamp HL is controlled to reduce power consumption. Also, the PH lamp indicating the auto preheat state is turned on to notify that it is in that state.

On the other hand, if the diode DPH shown in FIG. 37 is not connected, the auto preheat state will not occur after 2 minutes have passed. In other words, NO in PH
It is judged as.

If I explain the above in detail, if it is judged as Yes in the PH jersey, it will be NO in the Test jersey.
, and a two-minute timer circuit is formed.
The two minute timer is formed within the control element 30.
As mentioned above, the time from when an instruction is read to when that instruction is executed and when the next instruction is read is approximately 10 μsec. This is achieved by counting the number of times instructions are executed. This timer will be explained in detail later.

Next, a 2-minute timer is checked, and this check is determined as Yes after 2 minutes have elapsed.
Therefore, if you print from the time the power is turned on and leave it as it is, the auto preheat state will be automatically set after 2 minutes have passed. At this time, the 2 minute timer is reset and the heater lamp relay HLR is activated.
ON, ready lamp OFF, and preheat PH are ON. When the heater lamp relay HLR is turned on, the heater lamp HL ₁ , which is a preliminary heater, is turned on, but on the other hand, when the preheat PH is turned on, the heater lamps HL _{2, 2} , which are not shown in the figure, are turned on.
HL ₃ can be turned off under the control of the WTL circuit 39. In other words, the RAM 50 shown in FIG.
The contents of specified locations (16), (4), (8), and (12) are register W ₁
~ _W15 , a control signal is output from the register _W2 , and the driver circuit 32 lights up an indicator lamp or the like indicating the preheat state to notify the user. Further, the control signal from the register W ₂ is inputted to the WTL circuit 39 via the driver circuit 32 etc. to control the heater lamps HL ₂ and HL ₃ , for example, to turn them off.

Next, the micro switch MS ₄ will be activated.
It is judged as. Also, since drum 1 is in the initial state, the PB jack is judged as Yes, and the next slip roller jamb SRJ is jacked, and the micro switch MS ₂ and print switch are turned on.
PSW is judged and both are judged as NO. This causes the microswitch to be turned on again and the same operation can be repeated. In short, it was set to auto preheat mode. or,
The above print switch PSW doubles as a switch for canceling the auto preheat state and a switch for printing. Pressing the print switch PSW here cancels the auto preheat state and instructs the ready state. .
On the other hand, pressing PSW in the ready state enters the print cycle.

That is, when the print switch PSW is pressed in the auto preheat state, the PSW's status is judged as Yes and the preheat is turned off, the lamp that was informing the auto preheat state goes out, and the heater lamps HL ₂ and HL ₃ are turned off. lights up. The G flip-flop is flipped and the F flip-flop is set to return the copier to its initial state.

As described above, when the copying machine is left unattended, after two minutes it enters the auto preheat state and power consumption is reduced.

On the other hand, before entering auto preheat, that is, 2
If the answer to the minute timer question is NO, a two minute timer is started. If the F flip-flop is jacked but is in the auto preheat state and is jacked after the auto preheat state is canceled, it will be determined as Yes, but here we will explain the case where it is determined as NO. Therefore, the micro switch MS ₇
is changed, the ready lamp RL is turned on, and the print switch PSW is changed. In the case of this print switch PSW,
Output strobe signal from terminal _S3 to turn ON and OFF
We are currently checking. Here, if the print switch PSW is determined to be NO, the F flip-flop is reset and the same operation is repeated again. This indicates a so-called ready state, and a ready lamp RL indicating this is lit. In addition, in this state, the print switch
The reason why the PSW is changed twice in succession is to distinguish the print switch PSW from being used both as a switch for canceling auto preheat and as a switch for executing a copy cycle. That is, the F flip-flop is set so that the first PSW jump after auto-preheating is canceled will not be judged as Yes, and the PSW will not be jacked through the F flip-flop jump. In the so-called auto-preheat state, when the print switch PSW is pressed to cancel auto-preheat, the copy cycle is prevented. Here, even if the copy cycle starts at the same time, the fixing unit 16
If the temperature is above the specified value, the ready lamp
RL is lit and there is no problem, but if it is lower than that, it will be determined as NO in the WTL jersey and an operation to turn off the ready lamp RL will be executed, and even if you press the print switch PSW, this PSW will not be confirmed. No signal is output and the copy cycle does not start.

The above is an explanation of the ready state, that is, the copy-enabled state and the auto-preheat state.In addition, the operation so far has been from the time the power is turned on, to the setting of the initial state of the copier itself, to the ready state, and to the copy-ready state. This is an explanation of how it is done.

Next, the copy cycle will be explained.

Now, the ready lamp RL is lit, and when the print switch PSW is pressed, the PSW is judged as Yes in the flowchart of FIG. 30, and the copy cycle begins. From this, a control signal for turning on the high voltage generation relay THVR is derived from the output section of the control element 30, and the above-mentioned two-minute timer is reset.

For example, in FIG. 18 showing the instructions, the 28th step instruction _TR1 jumps to the subroutine PO to change the PSW, and the changes are made in the same manner as the microswitch group operations described above. Since the print switch PSW is pressed at this time, it is determined as Yes. Therefore, the TRO at the 29th step in P ₁₀
is skipped and the next instruction LAX is executed. At LAX, the instruction codes _I4 to _I1 at this time are input to the accumulator A, and the accumulator A becomes "0010". next
An instruction called ATF is read out, and this ATF is an instruction for transferring the contents of accumulator A to register F from which control signals for the copying machine according to the present invention are derived. Therefore, register F becomes "0010". At this time, the contents of the register F are led out as a control signal to the outside of the control element 30, and are sent to the relay THVR via the driver.
is turned on. Therefore, the contact THVR-a is closed and the charger 12 and the static eliminator 18 start operating.
In addition, in the above register F, the contents of register _F1 are used to connect the high voltage generation relay CHVR, the contents of _F2 are used to connect the above-mentioned relay THVR, and the contents of _F3 are used to connect the light source lamp CL.
The contents of _F4 control the relay CLR, and the document table return solenoid TRS is set to "1" to turn on and "0" to turn off.

Charging is started in the manner described above, the next instruction _TR1 is read out, and the two-minute timer is reset. This action is executed by jumping to a subroutine, and when the instruction RTN to return to the main routine is read from the subroutine, the SSR of the 33rd step of _R10 is derived, and with the next instruction TRO, _P9 (step The program jumps to step 0 (see Figure 19), and the micro switch _MS1 at the 0th step is switched. This micro switch MS ₁ detects paper input, and at the moment no transfer paper 13 is input.
It is judged as NO. After that, LB is read out and (4) of the RAM 50 shown in FIG.
The next instruction SM specified in Bu
Then, "1" is set in the third bit of the specified location (4). This means that the paper feed solenoid PFS as shown in FIG. 3 is turned on. Also, the next instruction TR ₁ calls the subroutine PO
Jump to (see Figure 28) and LB at step 32.
Read out. This LB specifies (12) of RAM50, the first bit of the specified location (12) is set to "0" in RSM, and the ready lamp RL is turned on.
It becomes OFF. Further instruction LB
RAM50 (8) is specified, and in the next instruction SM, the 0th bit of the specified location (8) is set to “1”.
is set. Then subroutine P ₁ in TR ₁
Jump to P ₂ again using the combined instruction of SSR and TRO. Therefore P ₂
The 42nd step instruction NPR (see Figure 26) is read out, and the flip-flop NP
is reset, and the control signals output from registers _W1 to _W15 are temporarily stopped. As explained earlier, this is to transfer the contents of RAM 50 shown in Fig. 35 to registers W ₁ to W _15. After that, follow the instructions to finish transferring the contents of RAM 50 to registers W ₁ to _{W 15} . , the instruction NPS is read out and the flip-flop
When NP is set, the contents of the registers _W1 to _W15 are output as control signals. At this time, the time from when the control signal stops until it is derived is extremely short, so the above time can be ignored. In response to the above control signal, the paper feed solenoid PFS, drum feed clutch DFC, and high pressure generation relay THVR operate, and the transfer paper 13 is fed into the copying machine by the paper feed roller 20. transfer paper 1
3 is transported. Meanwhile, the rotating drum 1 starts rotating. As described above, after pressing the print switch PSW, control signals for performing a copying operation are derived and various mechanisms are operated. Its operating state is shown in the time charts of FIGS. 38a and 38b. continue,
In the flowchart shown in FIG. 31a, the micro switch MS ₄ is checked, and it is determined as Yes, and the document table return solenoid is turned on.
TRS is turned OFF. Next, check the input status of the synchronization signal PA. After that, turn on the micro switch again.
MS ₄ is confirmed, and the TRS is turned OFF and the slipper rollers SRJ and CSSR are checked, as well as the micro switch MS ₂ , but it is judged as "NO" in all cases. Then, check the input state of the synchronization signal PA. At this time, the synchronization signal PA is determined when 1 of PA is input to input terminal α, and at this time, Yes
Judging as. However, the above synchronization signal PA-1
The micro switch mentioned above is not input.
The same cycle of re-jaging MS ₄ ,
Repeat until synchronization signal PA-1 is input.
If the input of the synchronization signal PA-1 is confirmed, the paper feed solenoid PFS is turned off and 1 is input to the memory M. Here, M+1 is to input 1 into the RAM 50 to remember that 1 of the synchronization signal PA has been input, and when the next synchronization signal PA-2 is input, M+1 is performed again and 2 is stored in the memory. This is the translation. After the above M+1, perform M=6.
That is, if the memory content is 6, it is determined as Yes. In this case, since the synchronizing signal PA-1 has been input, M=1, which is determined as NO. Similarly, NO for the next M=7 and M=8
It is determined that the micro switch MS ₄ is used. The above steps are performed every time a synchronization signal is input, and when the result of M=8 is determined as Yes, the process moves to the next step.

The above operation will be explained using instructions.

In P9 (see Figure 19), 17 steps are completed.
TR ₁ is read and the PA is changed.
In this case, TR ₁ at the jump destination is read by jumping to PO (see FIG. 28) at TR ₁ and confirming the input state of the synchronization signal. Therefore, it will be seen that the program jumps to P ₁ (see FIG. 27) and the 48th step instruction TA is read out. This TA checks whether the synchronization signal PA is input to the input terminal α. For example, if there is no signal at the input terminal α, the next instruction
RTN is read. That is, the PA is judged as NO and the process returns to the main routine, microswitch MS ₄ is changed and the operation described above is repeated. On the other hand, in the above TA, input terminal α
If the synchronization signal PA is input to
LAX is executed. Therefore, the content of accumulator A is set to “0000” at LAX above and the next ADX is
At this point, "0000" of the accumulator A and "0001" of the codes I ₄ to I ₁ at this time are added by the adder FA, and the addition result is input to the accumulator A. The contents of accumulator A at this time become "0001". Since the carry "1" is not output from the adder FA in the execution of the above ADX, the next instruction is skipped, the second TR ₀ is executed, and the instruction is executed again.
ADX is executed. By repeating this operation, when a carry "1" is derived from the adder FA, the instruction RTN ₁ is read out. As a result, PA was rejected as Yes.

On the other hand, when RTN ₁ is read, the process returns to the main routine and the LB at the 19th step is read as shown in FIG.
I think you can understand that the following instructions are read out. This LB specifies (4) in the address counters BL and Bu of the RAM 50 as shown in FIG. Then, it jumps to PO at the next TR ₁ , the jump destination TR ₁ (30th step) is read out, it jumps again to P ₁ , and the instruction TM there (44th step) is read out. executed. In FIG. 35, the third bit of the specified location (4) stores information regarding the paper feed solenoid PFS, and currently, as explained earlier, "1" is stored and paper feeding is being executed. Therefore
Since the third bit of the designated location (5) in TM is "1", the next instruction RTN (45th step) is skipped and the next instruction RSM is executed. As a result, the third bit of the designated location (4) is reset to "0". The subsequent operation is M→W, that is, _the contents of the RAM 50 shown in FIG. 35 are transferred to registers W ₁ to W ₁₅ , and
The contents of W ₁₅ are derived as a control signal. In this case, the paper feed solenoid PFS is turned off via the driver circuit 32. (See the time chart for details) Next, M+1 is executed, and at this time, instruction TR ₁ (21st step of _P9 ) is read out. From this, the jump destination LB (PO's 2
(step 3) is read out and (3) of the RAM 50 is specified. After that, jump to step 51 of P ₃ with the next combined instruction SSR and TR ₀ . At this jump destination LAX, the contents of accumulator A are set to "0001" and the next LAX is read out, but if LAXs are consecutive, the next LAX is skipped. Therefore, ADD11 is executed. Addressed as the contents of accumulator A in ADD11 above.
The contents of the designated location (3) of the RAM 50 are added and the addition result is transferred to the accumulator A. As a result, the content of accumulator A becomes "0001".
Further, when the adder FA is carry "0", the ADD 11 skips the next instruction, and the next instruction is read out and executed. From the above, instruction EXC is executed, and the content "0001" of the accumulator A is transferred to the designated location (3) of the addressed RAM 50, and the content of the designated location (3) becomes "0001". after that
RTN is read and returns to main routine P ₉ , 22
The LAX of the step is read.

From the above, it follows that the first synchronization signal PA-1 is stored in the RAM 50.

Next is the jersey with M=6, but the above LAX
The contents of the accumulator A are set to "0110" at the next TAM, and it is confirmed in the next TAM that the contents of the accumulator A match the contents of the currently addressed designated location (3) of the RAM 50. In this case, it is determined that the contents do not match, that is, it is determined as NO. Next M=7M=8
The same is true for the jacket, so I will omit the explanation, but
Each judgment is determined as NO, and the operating state of the micro switch MS ₄ is checked again as shown in the flowchart of FIG. 31a.

The above-described operations are repeated, the rotating drum 1 rotates, and a synchronization signal is obtained from this rotation.
When the sixth pulse of the PA is input to the input terminal α of the control element 30, the contents of the specified location (3) of the RAM 50 become “6”, that is, “0110”, and it is judged as Yes in the case of M=6. The B flip-flop is adjusted, but the B flip-flop is connected to the photoreceptor 3.
This is related to the exchange of
It is judged as. Therefore, the above-described operation is repeated again, and the seventh pulse of the synchronizing signal PA is input, and it is stored in the designated location (3) of the RAM 50. At this time, the content of designated location (3) becomes "0111".
From the above, it is natural that in the case of M=6,
NO, it is judged as Yes at M=7, and CSSR is judged, but this judgment is
The answer is NO.

After the above, the 8th pulse PA− of the synchronization signal PA
If 8 is input, Yes in the case of M=8
It can be understood that it is judged as Therefore, the contents of the designated location (3) of the RAM 50 are set to "0000". The micro switch MS ₄ is then confirmed, but the document table 8 is not moving and has fallen to the NO side, and the initial state of the document table 8 is detected. Therefore, in this MS ₄ confirmation, it is determined as Yes, so the document table return solenoid TRS is turned OFF.
be made into Next, in the slipper roller SRJ ₁ , since there is no transfer paper 13, it is determined as NO. PA is criticized for this.
This PA change is to change the 9th pulse PA-9 of the synchronization signal PA, and the above signal PA-
When 9 is input to the input terminal α, it is judged as Yes and the next WTL is changed. If the temperature of the fixing section reaches the specified value in this WTL, SRJ,
After the adjustment of MS ₄ , the adjustment of micro switch MS ₁ is performed. Here, the micro switch MS ₁ has detected the paper input state of the transfer paper 13 and is tilted to the NO side. In short, the paper feed solenoid PFS
When turned ON, the paper feed roller 20 receives the transfer paper 13, and the transfer paper 13 is transported inside by the transport roller 21. Then, the transfer paper 13 is stopped by the paper stopper PS, and at this time, the state of paper entry is detected by the micro switch _MS1 . Therefore,
When checking the operating status of micro switch MS ₁ , a strobe signal is output from terminal S ₂ and connected to the input terminal via the diode and the NO side of MS ₁ .
Entered into KN ₂ . From this, it is confirmed that the microswitch MS ₁ is on the NO side, and it is determined as Yes. In other words, the paper loading state of the transfer paper 13 is confirmed. As a result, high voltage generation relay CHVR,
The light source lamp relay CLR is turned on. Note that in the figure, TRS-OFF and DEC-ON are indicated, but these are the same as before. The control signal for turning on CHVR and CLR is the output signal from the registers F ₁ to _{F 4} described above. That is,
All you have to do is input "1" to register F ₁ and "1" to F ₃ , so use instruction LAX to set the contents of accumulator A to "0101" and use the next instruction ATF to register the contents of accumulator A. I think you can understand that all you have to do is transfer it to F.
However, in this case, the relay for high voltage generation
Instructions because THVR is ON
The contents of accumulator A are set to “0111” by LAX.
And it is sufficient.

As described above, the rotary drum 1 rotates, and in the time charts shown in FIGS. 38a and 38b, the synchronization signal
When the ninth PA signal PA-9 is generated, the light source lamp CL is turned on, and the charger 6 also operates to uniformly charge the photoreceptor 3.

Next, do the PA shot, then the PB shot. At this time, the synchronizing signal PB is used to transport the transfer paper 13, which is stopped by the paper stopper PS, in synchronization with the rotation of the rotary drum 1. Therefore, when the synchronization signal PB-2 is input, the stopper solenoid PSS is turned on to release the stopped state of the transfer paper 13. On the other hand, as for the synchronization signal PA, the developing device and document table 8 are driven by the tenth pulse signal. Here, are the synchronization signals PB-2 and PA-10 input simultaneously?
Alternatively, either one is input first, or the manufacturing of the copying machine is slightly different, so that the slits Pa-10 and Pb-2 of the corresponding part can be changed in the disk PT. Therefore, the slits Pa-10 and Pb-2 of the disk 24 are set to match the rotation of the rotary drum 1, so that the driving of the transfer paper 13, document table 8, etc. is synchronized.

Therefore, in the case of PB, the synchronization signal PB-
If 2 is input first, the stopper solenoid
PSS is turned on and PA is juggled until synchronization signal PA-10 is input. Then, when the above synchronization signal PA-10 is input, the developing motor relay
DMR and document platen feed clutch TFC are turned on. Conversely, when the synchronization signal PA-10 is input, the developing motor relay DMR and the document platen feed clutch TFC are turned on, and when PB-2 is input next, the stopper solenoid PSS is turned on. Therefore, as shown in the time chart, motor relays DMR and TFC for developing are turned on, and PSS is turned on.
It is turned ON, and the developing device 11 and document table 8 become operational. On the other hand, the transfer paper 13 is also conveyed. In this case, the micro switch MS ₄ will fall to the NC side.

After the above operation, M+1 is executed and synchronization signal PA
Specified location of RAM50 (3) indicates that -10 has been input.
At the same time, the E, H, and O flip-flops are changed, but since each flip-flop is not set, it is judged as NO, and the next microswitch _MS5 is changed. However, the micro switch MS ₅ detects an overrun of the document table 8 and is currently not turned on (open state), so it is determined as NO. Now let's move on to the micro switch MS ₁ . This micro switch MS ₁ falls to the NC side when the rear end of the transferred transfer paper 13 passes by, but in this case, it does not fall to the NC side again and is determined as Yes, and the switch shifts to PA. The PA check is for confirming the input state of the synchronization signal PA-11. Then, when the drum 1 rotates and the synchronization signal PA-11 is input, the judgment of PA is determined as Yes, and M+1 is performed. This M+1 is as described above, and the value obtained by adding "1" to the specified location (3) of the RAM 50 is stored. In other words, the synchronization signal PA-1
When 0 is input, M+1 is executed earlier and "1" is stored in the designated location (3) of RAM50, so if synchronization signal PA-11 is input, RAM5
M=2 is stored in the designated location (3) of 0. Therefore,
Since the designated location (3) of the RAM 50 is M=2 in the next match with M=1, it is determined as NO, and the process moves on to the matches with M=4, 5, 6, 7, 8, and 9. In this case, the judgment is NO and the E flip-flop is judged.
As described above, the above-described operation is repeated, and each time the synchronization signal PA is input, M+1 is executed and the number of times the synchronization signal PA has been input is stored. In other words, the position of the rotating drum 1 can be confirmed.

On the other hand, when the microswitch _MS1 detects the rear end of the transferred transfer paper 13, that is, falls toward the NC side, the stopper solenoid PSS is turned OFF, and the transfer paper 13 for the next copy is stopped at that part. This is determined to be NO by the micro switch MS ₁ , and the PSS is turned OFF. In the time chart, B ₅ , A ₄ , and B ₄ indicate the size of the transfer paper 13.

Further, if the content of the designated location (3) of the RAM 50 is "0100", that is, if the synchronization signal PA-1 is input, the P and C flip-flops are switched and the stopper solenoid PSS is switched. Here, Fig. 38a
In the time chart, if the size of the transfer paper 13 is _B5 , the micro switch MS ₁ will be activated before the second synchronization signal PA-1 is input.
It has fallen to the NC side, and after the MS ₁ jump, the stopper solenoid PSS is turned OFF. Note that if the size is A ₄ or B ₄ , the micro switch MS ₁ has detected the paper input state of the transfer paper 13, and the stopper solenoid PSS remains in the ON state. Therefore, when the synchronization signal PA-1 is input and M=4, if the transfer paper is _B5 in the PSS case, then
If NO, and transfer paper A ₄ and B ₄ , it is determined as Yes. For convenience of explanation, the case where the transfer paper 13 is _B5 will be described here.

Therefore, after changing the PSS, the C flip-flop is set. By the way, in Figure 36
“1” is stored in the second bit of the designated location (2) of the RAM 50. After that, the M=6, M=9, and M=8 changes are performed, and then the E flip-flop is changed again.

Next, the synchronizing signal PA-2 is inputted, M+1 is made at the change of PA, and the designated location (3) of the RAM 50 becomes "0101". Therefore, since such a flip-flop has been set in the C flip-flop jump, after this jump, the P flip-flop is set and the operation moves to the E flip-flop in the same manner as described above. and
In the case of PA, if the synchronizing signal PA-3 is input to the input terminal α of the control element 30, after confirming the input state, the content of the specified location (3) of the RAM 50 becomes "1010".

After the F flip-flop is switched, the developing motor relay DMR is turned OFF. This is done so that the developing motor of the developing device 11 is stopped in accordance with the size of the transfer paper 13. For example A ₄
If the size is M=8, that is, when the synchronization signal PA-5 is input, if the size is _B4 , the synchronization signal PA
Development stops when -6 is input.

Returning to the original explanation, in the case of M=6,
Since the designated location (3) of the RAM 50 is "0110", the E flip-flop is set as the next operation. Therefore, the operating state of the microswitch _MS2 is checked after the next E flip-flop jump. In this case, the micro switch MS ₂ is activated when the transfer paper 13 that is in close contact with the photoreceptor of the drum 1 is peeled off.
It falls to the NO side and detects the peeling state. In other words, if the micro switch MS ₂ is tilted toward the NC side, the transfer paper 13 remains in close contact with the drum 1 and is processed as a jam. However, here we will explain the case where it is determined as Yes. The subsequent operations are as explained above, and the PA is re-judged.
The PA switch at this time is the synchronization signal PA-4,
If it is in the input state, M+1 is executed. after that,
M = 6, M = 9 and M = 8 in any case.
Since it is NO, we return to the E flip-flop again and move on to the next synchronization signal PA-5, but when we checked the micro switch _MS5 before the PA switch, we found that the document table 8 was in an overrun state. If there is, MS ₅ turns ON and confirms it. Therefore, the strobe signal is derived from the terminal _S1 and input to the input terminal AK, and the ON state is confirmed. Then, the process moves to the PSS, and the relay CHVR of the charging high voltage generator and the document table feed clutch TFC are turned off, and after the 0 flip-flop is turned on, the H flip-flop is set. The above H and 0 flip-flops are connected to a 220ms timer which will be explained later. The document table 8 stops due to the above operation, and the charging relay CHVR turns OFF, so the charger 6
The charging operation also stops.

In the current state, the microswitch MS ₁ is not detecting the input state of the transfer paper 13, and the transfer paper stopper solenoid PSS is OFF. Micro switch MS ₂ detects peeling of transfer paper 13.
Falling on the NO side. Micro switch MS ₃ has not yet detected the output of transfer paper 13 and has fallen to the NC side. Also, the micro switch MS ₄ is on the document table 8.
was moved when the document platen feed clutch was turned on and was not in its initial state, so it fell to the NC side. Furthermore, micro switch MS ₅ detected an overrun of document platen 8, so the document platen feed clutch TFC was turned off.
When turned off, the document table 8 is in a stopped state and the charger 6 is also in a stopped state.

In the above state, the input state of the synchronizing signal PA-5 is checked, and if it is not input, the process moves to flip-flops E and H. Here, the H flip-flop is in the set state as explained earlier,
A 220msec timer is set. This 220msec timer runs from when the document table feed clutch TFC turns OFF to when the document table return solenoid turns ON.
The document table 8 is driven reliably by stopping the document table for 220 msec. For example, if the document table 8 is stopped and the TRS is immediately turned ON and returned, it will cause a problem with the clutch gear etc. related to the drive of the document table 8, which may cause a failure.In order to eliminate these problems, a 220 msec timer is set. It is set up.

The above-mentioned timer is not provided separately but is configured within the control element 30.

Therefore, the above timer is set and the synchronization signal is
Confirmation of PA-5 is executed, and if this confirmation is not made, the above-mentioned cycle is repeated, and after 220 msec has elapsed, the document table return solenoid TRS is turned on to return the document table. In other words, after changing the 220msec timer, the 220msec timer is reset,
Also, the H flip-flop is reset and the C flip-flop is set. Therefore, the O flip-flop judgment is determined as Yes, and the confirmation of the microswitch _MS4 is executed. At this time, the micro switch MS ₄ is tilted toward the NC side because the document table 8 is not in the initial state, and a control signal is output from the control element 30 to turn on the document table return solenoid TRS. After the above, the synchronization signal PA
If -5 is input, the content of the specified location (3) of the RAM 50 becomes "1000".

Therefore, after being checked as Yes in the M=8 case, the E flip-flop is reset and the transition is made to the microswitch _MS6 case.
This micro switch MS ₆ is used to confirm the multi-copy dial, and in the case of single copy, it is always OFF (see Figure 37) and is determined as NO. After the above, we return to the E flip-flop instructions. Incidentally, if the above-mentioned dial is set to a plurality of sheets, after checking the operating state of the micro switch MS ₁ and turning on the paper feed solenoid PFS, the above-mentioned operation can be repeated.

After the above, if synchronization signal PA-6 is input,
M+1 is executed and the contents of the designated location (3) in the RAM 50 become "1001" (M=9). Therefore, after adjusting M=9, after turning off PFS, DMR, and TFC (all are already turned off), check the micro switch MS ₄ and turn the document table return solenoid on.
Turns TRS ON or OFF. That is, if the document table 8 has returned to its original stop position at this point,
Microswitch MS ₄ detects this. This confirmation is performed by outputting a strobe signal from terminal _S1 , and the document table return solenoid TRS is activated.
It will be turned off. Next, check the input state of the synchronizing signal PA-7, and after checking, move on to changing the micro switch _MS3 . This micro switch MS ₃ detects the output of the transfer paper 13 on which the toner image has been fixed, and in this state it is naturally tilted to the NO side. However, if paper output is not detected in this state, the conveyance of the transfer paper 13 is not normal and the transfer paper 13 has become jammed in the conveyance path, and it is determined that there is a jam.
After the above micro switch MS ₃ is turned on, the total counter TC is turned on and incremented by 1.
After adjusting the micro switch MS ₄ again, check the synchronization signal PA-8 and check the PSS, CHVR, CLR,
Then, the TC is turned off, the contents of the specified location (3) of the RAM 50 are set to "0000", the timer is turned off, and each O, C, and P flip-flop is reset.

After completing the above operations, move on to the micro switch MS ₄ (see *11 in Figure 31a). After this adjustment, check the synchronization signal PA-9 and check the signal input status from the WTL circuit. Then, check the micro switch MS ₄ again until the micro switch is reversed to the NO side. At this time, the drum feed clutch DFC is turned off and the rotating drum 1 stops. The above micro switch MS ₄
By flipping it to the NO side, you can move on to the micro switch MS ₁ . Here, when making multiple copies, as explained earlier, the paper feed solenoid PFS
It is turned on and paper is being loaded. Therefore, the process moves to a continuous copy cycle. On the other hand, the micro switch
If the MS ₁ does not detect paper entry, the operation for searching for the initial stop position of the rotary drum 1 described above is executed. Therefore, moving to the flowchart shown in FIG. 29, the ready lamp RL is turned off, the drum feed clutch DFC is turned on, and the rotary drum 1 is rotated again.

The subsequent operations are as explained at the beginning, and the explanation will be simplified. When moving to this cycle, the micro switch MS ₄ is reversed to the NO side, the document table return solenoid is turned off, and the document table 8 is returned to the initial stop position. On the other hand, while the synchronizing signal PB (slit Pb-2) is being input in the PB judgment, the PA judgment is performed, and the next PB judgment (the PB judgment not surrounded by the dotted line) is performed. This PB gear is the synchronization signal PB−
1, if the synchronizing signal PA-11 is input while this signal is input, the D flip-flop is set, and when the next synchronizing signal PA-0 is input, the D flip-flop is reset. , drum feed clutch DFC turns OFF. That is, when the synchronization signal PB-1 is input, if the synchronization signals PA-11 and PA-0 are input, the drum 1 is in its initial state, and the drum 1 stops. After that, it enters the ready state and the ready lamp turns on.
RL is turned on and a message indicating that copying is possible is displayed.

As described above, the copying machine according to the present invention is controlled by the one-chip control element 30. Here, in the past, each micro switch MS ₁ ~
Various controls are performed based on signals sent from MS ₈ , etc., and connection lines are required from each switch MS ₁ to MS ₈ . However, in the present invention, in order to check the state of any micro switch MS using the synchronization signals PA and PB obtained by the rotation of the drum 1,
A strobe signal is derived from the control element 30, and the operating state of the microswitch is confirmed based on the input state of this strobe signal. i.e. synchronization signal
As shown in FIG. 37, it can be seen that the number of lines led out from the microswitch group is reduced by checking the microswitches that match the input conditions of PA and PB. In addition, the number of components that can be configured within the control element 30 can be significantly reduced without providing a separate timer or the like. Further, in combination with the above-mentioned timer, an auto preheat function etc. can be easily configured, and the document table 8 is reliably driven.

The above explanation is for copying, and if a so-called jam condition occurs in which the transfer paper 13 is not being conveyed normally during this operation, it is necessary to notify this. In this case, it is detected by the slippery roller jamb SRJ or each micro switch MS, and the jam cycle is started. This flowchart is shown in FIG.

In FIG. 32 above, if a jam is detected, all loads are first turned off. To explain this using instructions, in FIG. 23, the LB at the 56th step of _P5 is read out.
This LB specifies (0) of the RAM 50. Then, the next instruction TR ₁ jumps to the subroutine PO (Fig. 28), the jump destination instruction reads TR ₁ (P ₀ , 6 steps), jumps to P ₁ again, and LAX ( P ₁ 54th step) is executed. At this LAX, accumulator A is “0000”
and (0) of the RAM 50 specified by EXCI is set to "0000". After this operation is repeated and the contents of the RAM 50 shown in FIG. 35 are all set to "0", the instruction RTN is read out and the subroutine returns to the main routine. Therefore, LAX at the 58th step of P5 is executed, and at the next instruction ATF, register F becomes "0000" and no control signal is output.

Next, in the instruction LB, set up RAM50.
(12) (see Figure 35) is specified. And SSR,
Jump to P10 with TRo's compound instruction. Therefore, in the jump destination instruction SM (35th step), "1" is written in the 3rd bit in (12) of the RAM 50 specified by the LB. This means that jam relay JR is turned on in FIG. 35. The next instruction TR ₁ jumps to the subroutine and stores the contents of the RAM shown in Figure 35 in register W _1.
~ _W15 is performed in the control element 30, flip-flop NP is set, and the register W1 _~ is set.
The control signal that turns on jam relay JR is derived from W ₁₅ . After this operation is completed, the jam relay contact JR-a as shown in the flowchart of FIG.
A ceremony will be held. If the jam relay contact JR-a operates in this jam, the jam relay JR
Turn off. Here, once the jam relay JR operates, its contact JR-a is held. Therefore, even if jam relay JR is turned OFF, contact JR-a
can be manually released in the same state.

Check the jam relay contact JR-a until this contact JR-a operates and falls to the NO side, and after checking, turn off the jam relay JR.
Make it. Then, the jam lamp timer JLT is reset to O, and the adjustment of the contact JR-a is executed again. In this case, it is judged as Yes and moves on to the next operation, but somehow the contact JR−
If a is released, the above operation is repeated. In this case, assuming that it is judged as Yes, the jam lamp timer JLT is started,
The jam lamp timer JLT is executed. Therefore, in the case of the jam lamp timer JLT, after a predetermined time has elapsed, it is judged as Yes, and the jam lamp JL is turned on to indicate a jam, and furthermore, the K flip-flop is set. Thereafter, the above-described operation of resetting the jam lamp timer JLT and starting the timer is repeated. If the judgment of the jam lamp timer JLT turns out to be Yes, the process moves to the K flip-flop judgment. Here, since the above K flip-flop is set, the jam lamp
JL is turned off and the lamp goes out. Furthermore, the K flip-flop is reset. The subsequent operation is the same as described above, and by repeating this operation, the jam lamp JL blinks at each set time of the jam lamp timer JLT to indicate a jam. The above setting time is 500msec. Here, the above blinking operation will be explained in detail, and the timer will also be explained. Note that the timer described earlier also has a similar configuration to this timer.

In the instructions shown in Figure 18,
The LB at the 40th step is read. In this LB, the designated location (19) of RAM50 is specified, and the next
In TR ₁ , the specified location (19) of RAM50 above is “0”
be made into After that, it jumps to the subroutine at TR ₁ of the 42nd step, where the jam relay contact
JR-a's jersey is executed. In this case, Yes
Then TR ₁ at the 44th step is read and a timer is started. That is, the 57th step of _P0 on the subroutine page (see Figure 28)
instruction LB is read out and RAM50
(19) is specified. Therefore, jump to the same page in the next TRo, and jump to the SSR, TR ₁
The composite instruction jumps to the 51st step of _P3 (see FIG. 25) and the instruction LAX is read out. After the accumulator A is set to "0001" at this LAX, the next instruction LAX is skipped and the instruction ADD11 is executed. The instruction ADD11 adds the contents of the accumulator A and the contents of the addressed RAM 50 (in this case, the designated location (19) and the contents are "0000"), and the result is transferred to the accumulator A. Eventually, the accumulator A becomes "0001". Since the carry from the adder FA is "0" in ADD11, the next instruction is skipped and EXO is executed. Therefore, the content “0001” of storage unit A is being addressed.
It is input to the specified location (19) of RAM 50 and stored. After the above operations are completed, the RTN is read and the process returns to the main routine.

As the next operation, in FIG. 18, the 45th step TR ₁ is read and the Test instruction is executed, but as explained earlier, it is judged as NO, so the next instruction TRo is read and executed. be done. It will be understood that this TRo jumps to the same page and the instruction LB is read.

The specified location (11) of the RAM 50 is specified in the above LB. Then, in the next instruction TM, if the first bit of the specified location (11) is "1", the next instruction is skipped, but here the first bit is "0". The next instruction TRo jumps to the same page and jams relay contact JR-a. The above means that the jam lamp timer JLT has been adjusted, that is, when the first bit of the specification (11) of RAM50 becomes "1", the LB of the 52nd step is read and the value of the K flip-flop is changed. executed.

To briefly explain the above, the designated location (19) of RAM50 is "0001", but the designated location (11) of RAM50 is set to "0001" by the jam lamp timer JLT.
If it is “0010”, it is judged as Yes. In this case, the specified location (11) of the RAM 50 is naturally "0000" and is determined to be NO. As a result, the above-described operation is repeated. Eventually, by repeating this operation, the contents of the specified location (19) in RAM 50 will change. In other words, the number of times the above operation is performed is counted in the specified location (19) of the RAM 50, and if it is repeated 15 times, the content of the specified location (19) will be "1111". You will understand. And when it was the 16th time, the second
In Figure 5, accumulator A is set to “0001” at LAX at the 51st step, and accumulator A is addressed to “0001” at ADD11.
"1111" in the designated location (19) of RAM 50 is added. As a result, a carry “1” is output from the adder FA.
is output. So the following instructions
Since TRo is executed, EXCI is read and executed. Therefore, in this EXCI, the contents of accumulator A are moved to the specified location (19) of RAM50 (at this time "0000"), and
The counter BL that addresses step 0 is counted up, its content becomes "1101", and the designated location (7) of the RAM 50 (see FIG. 12) is designated. Then, LAX is read and the contents of accumulator A become “0000” and the next ADD11
At , the contents of the accumulator A, the contents of the addressed designated location (7) of the RAM 50, and the above-mentioned carry "1" are added, and the result of addition at EXC is input to the designated location (7). That is, "0001" is stored in the designated location (7). By repeating the above operations, when the specified location (11) becomes “0010”,
This means that 500 msec has passed. Therefore (18th
(See figure) In the jam lamp timer JLT setting, use the instruction LB to set RAM50 (11).
is specified, and in the next TM, the first bit specified by I ₁ and I ₂ at this time is “1”, so the next instruction is skipped and the instruction is
LB is executed and the process moves to the K flip-flop. Here, the designated location (11) is set to "0010" when the above operation is repeated 512 times. At this time, 500 msec has passed (one operation is executed in less than 1 msec). Also, the K flip-flop is as shown in Figure 36.
The state is stored in the 3rd bit of the RAM specified location (14), but in this case, since the 3rd bit is "0", the state is confirmed in the instruction TM of the 53rd step. Ru. Then, in the next instruction TRo, the program jumps to the same page and executes the 58-step instruction IDFR. This IDFR is for resetting the flip-flop IDF in the control element 30, and outputs the output IDF from the time flip-flop IDF as a control signal to the driver 32 to light the jam lamp JL. In other words, if the above IDF flip-flop is reset, the jam lamp will be reset.
JL lights up, and once set, jam lamp JL goes out.

Therefore, the jam lamp JL flashes every 500 msec.

The above is the jam state, and here again, a timer is configured in the control element 30 to blink the jam lamp JL.

Next, the exchange control of the photoreceptor 3 according to the present invention will be explained.

Incidentally, a time chart in that case is shown in FIG. In this case, the replacement of the photoreceptor 3 is completed after the rotating drum 1 has rotated three times. In FIG. 1, when the photoreceptor 3 is inserted through the insertion opening 4, the microswitch MS ₇ detects the inserted state. Naturally, the power is turned on here. The photoreceptor 3 above is a stopper MS
It has been temporarily stopped.

Therefore, the micro switch MS ₇ (see Fig. 30) determines Yes. Therefore, the process moves to the flowchart shown in FIG. 34 and the set side of CSSR is turned ON. As explained above, the CSS is a solenoid that drives a presser claw for releasing the photoreceptor 3 mounted on the rotating drum 1, and when the solenoid is turned on, the photoreceptor 3 is released. On the other hand, the above CSSR is a relay related to this, and if you turn on the set side of this relay, the contact will be turned on.
CSSR-a operates and maintains that state, and if it is turned on to the reset side, it returns to its original state.

As described above, when relay CSSR is turned ON to the SET side, its contact CSSR-a will fall to the ON side. Therefore
After changing CSSR-a, power relay PR
Then, the set side of relay CSSR is turned OFF, and solenoid CSS is turned ON. After the above, the drum 1 rotates, and various controls are performed in accordance with the input of synchronizing signals PA and PB. On the other hand, due to the rotation of the drum 1, the photoreceptor 3 is sent to a peeling device 15, where it is peeled off from the drum 1 and transported to the outside by each roller. When the synchronizing signal PA-7 is input, the post-judge contact CSSR-a of M=7 is confirmed in FIG. 31a. In this case, the contact CSSR-a is in the operating state (NO side) and the process moves on to the next micro switch _MS2 . In this case as well, it is determined as Yes and the micro switch MS ₃ is confirmed. Micro switch here
If the MS ₃ does not detect the removal of the photoreceptor 3, it will be detected as a jam and will notify you of this. On the other hand, if unloading is detected, the contents of the RAM that was counting the input of the synchronization signal PA are set to "0".

When the above operations are completed, the drum 1 continues to rotate and is controlled to search for an initial state. Therefore, as shown in the flowchart in Figure 29, the relay contact CSSR
-B flip-flop is set after the a change. Then, at the second rotation of drum 1, the synchronization signal is
When PA-6 is input, M
After the jump =6, the B flip-flop is jumped and judged as Yes. As a result, the 33rd
Moving on to the flowchart shown in the figure, after confirming the micro switch MS ₇ , the photoconductor stopper solenoid MSS
is turned on, and at the same time, the rotation of drum 1 is stopped.
Therefore, the stopper MS opens and the photoreceptor 3 is transported inside.

Further, the drum 1 stops for 1.5 msec and then starts rotating again. Thereafter, the rotating drum 1 is set to the initial state again, and it will be understood that in this state, the determination of the B flip-flop shown in FIG. 29 is made as Yes. Therefore, the process moves to the flowchart shown in FIG. 33, and after each process, the PA is adjusted. The PA jack is used to check the input status of the synchronization signal PA-1, and if the above signal PA-1 is input, the relay is activated.
Turn on the reset side of CSSR and turn off solenoid CSS. The leading end of the photoreceptor 3 transported at this time is fixed to the drum 1 with a claw. Then, after inputting the synchronization signal PA-2, the relay
Turn off the reset side of CSSR and reset the B flip-flop.

Thereafter, the rotating drum 1 rotates to the initial state and stops at that position. In addition, the reset side of CSSR
ON, when CSS is OFF, power relay PR is
ON, and heater lamps HL ₂ and HL ₃ light up.

The above is an explanation of the replacement cycle of the photoreceptor 3.

As described above, the present invention controls the copying machine using one component, that is, a microprocessor. That is, in the present invention, instructions for controlling copying and photoreceptor replacement of a copying machine are written in the memory section of a microprocessor, and a synchronization signal of the copying machine is input to this microprocessor. , which sequentially reads instructions written in the storage section and controls the copying machine.

Therefore, the complicated copying control and photoreceptor exchange control circuits as in the past have been reduced to 1.
Only one control element is required and many effects can be achieved. Due to a significant reduction in the number of parts, the control circuit can be made smaller, significantly reducing costs and power consumption.
Furthermore, it is possible to improve reliability and serviceability, and to prevent the influence of external noise in improving reliability. When checking the operation of a micro switch, etc., the input state of the micro switch's operating signal is not checked all at once, but it is checked using a signal to be sure of the operating state, and moreover, the operating state is determined after confirming it many times. Since the output is output, the confirmation becomes accurate and control can be performed without malfunction.

In addition, the operating state at this time is confirmed by outputting a confirmation signal from the control element and inputting it through the detection means, so the operating signal is input passively as in the past. Not only is it extremely easy and reliable to determine whether a signal is a noise signal or not, but you only need to check the operating status of the necessary detection means each time, and the signal line for input is For example, only two lines, one for ON and one for OFF, are sufficient, which greatly contributes to noise prevention.

Alternatively, the present invention can sufficiently compensate for the drawbacks of a microprocessor using the time flow of the copying machine itself, and can not only derive control signals but also input the operating state of the detection means all at once. Rather than checking the operating status of the detection means at this time based on the input synchronization signal, the detection means can be viewed sequentially, which not only prevents the effects of noise etc., but also improves the functionality of the microprocessor. can be fully utilized, and can fully serve the purpose of downsizing a copying machine. In addition, if the photoconductor replacement detection means detects replacement of the photoconductor using the above method,
The photoconductor replacement instructions stored in the storage section are sequentially read out, and the replacement control is executed according to the same synchronization signal as the copy control, making the copier extremely easy to handle. It's convenient.

[Brief explanation of the drawing]

FIG. 1 is a side sectional view for explaining the structure of a copying machine according to the present invention, FIG. 2 is a circuit diagram of a power supply section according to the present invention, FIG. 3 is a control block diagram of the copying machine according to the present invention, and FIG. The figure is a front view showing the disc that interlocks with the rotating drum and obtains a synchronization signal.
The figure is a block diagram for explaining the configuration of the control element according to the present invention, FIG. 6 is a diagram showing an instruction to write into the storage section in the control element, and FIGS. 7 to 10 are according to FIG. 5. A logic block diagram of a counter and a register for addressing a storage section. FIG. 7 is a logic block diagram of a stack register related to a page address, FIG. 8 is a logic block diagram of a counter related to a step address, and FIG. Figure 10 is a logical block diagram of a counter associated with a page address, Figure 10 is a logical block diagram of a stack register associated with a step address, and Figure 11 is a logical block diagram of a stack register associated with a step address.
5 is a time chart of a clock signal output from the clock generator shown in FIG. 5, and FIG. 12 is a diagram provided to explain the RAM shown in FIG. 5.
FIG. 13 is a logic gate diagram for explaining the adder shown in FIG. 5, FIG. 14 is a logic gate diagram for explaining the accumulator section shown in FIG. 5, and FIGS. Figure 2 shows instructions written from page P0 to page P13 of the ROM to perform copy control in
9 to 34 are flowcharts of the instructions shown in FIGS. 15 to 28,
Fig. 35 is a diagram for explaining the storage location of the controlled unit stored in the RAM, Fig. 36 is a diagram showing the storage location of the flip-flop stored in the RAM, and Fig. 37 is the input/output of the control element. 38A and 38B are time charts showing the operating states of the controlled parts, and FIG. 39 is a time chart for replacing the photoreceptor in the present invention. MS ₁ to MS ₈ : Micro switch, MS ₇ : Micro switch for photoconductor inspection for photoconductor replacement, 1: Rotating drum, 24: Synchronous disk, 30: Control element (1 chip), 31: Control signal, 33: Synchronization signal, 34:
Detection means for detecting the subject state (micro switch, etc.), 37: Synchronization signal generator, 41: ROM, 5
0: RAM.

Claims (1)

[Claims] 1. A photoreceptor that is replaceably held on a drum, a drive system that drives the photoreceptor, a synchronization signal generator that outputs a synchronization signal as the photoreceptor is driven, a charger that uniformly charges the photoreceptor, an optical system that exposes the image of the original onto the photoreceptor and includes a scanning means for the original; a developing section that visualizes the latent image formed on the photoreceptor; a transfer section that transfers the developed image onto paper; a fixing unit that fixes the image formed on the paper; a fixing unit that feeds the paper;
including a paper conveyance system that conveys the paper via the transfer section and the fixing section, and means for detecting replacement of the photoreceptor;
An exchange system for exchanging the photoconductor is provided, and a detection means for detecting the copying state accompanying the operation of each of the controlled objects is arranged in each part, and a control signal is generated based on the synchronization signal output from the synchronization signal generation section. In an electrophotographic copying machine that outputs and controls the above-mentioned objects, the electrophotographic copying machine includes a storage section that stores various instructions for controlling each of the above-mentioned controlled devices, and a storage section that decodes the instructions read out from the storage section and outputs the decoded signal. a control element having a decoding section that outputs an output; a processing section that reads out instructions from the storage section and processes the read instructions according to a decoding signal output from the decoding section; The section reads the instructions from the storage section based on the synchronization signal output as the photoreceptor is driven;
Processing instructions according to the decoding signal outputted through the decoding section, confirming the operation of the detection means according to the synchronization signal through instruction processing, and controlling the controlled section based on this confirmation. The storage unit stores various instructions for controlling the exchange system for replacing the photoreceptor as well as copy control, and drives the photoreceptor based on the operation of the means for detecting replacement of the photoreceptor. Then, based on the same synchronization signal as the above-mentioned copy control, the instruction for replacing the photoreceptor is read from the storage section, and the processing section checks the detection means according to the synchronization signal, and then An electrophotographic copying machine characterized in that a control signal is derived to a base exchange system, and copy control and photoreceptor exchange control are controlled by the same control element.