JPS6118205B2 - - Google Patents

Description

DETAILED DESCRIPTION OF THE INVENTION The present invention relates to a step-by-step sequence controller. There are two types of sequence controllers: progressive type and scanning type. The step-by-step type controls in such a way that when the operation corresponding to a certain step of the control program is completed, the program is made to advance by one step in response to the completion detection signal and the operation of the next step is started. It is. In the scanning type, data indicating the state of the controlled system is input to the input device of the control device, and the control device constantly scans the input device to detect the state of the controlled system and determines the state according to the state. It is now possible to carry out controlled controls. The scanning type allows virtually continuous control, but it is difficult to create a control program and the control device is complicated and expensive. Step-by-step control devices have the disadvantage that the controlled system operates in stages and can sometimes only be controlled in a clumsy manner, but the control devices are easy to program and can be made by anyone, and are relatively inexpensive. Moreover, since there are many controlled objects for which stepwise control is actually sufficient, the sequence controller is very economical for such objects.

The present invention is directed to the above-mentioned step-type sequence controller. Conventionally, this type of sequence controller used a pin board and pins to create a program and input it to a control device (sequence controller). The program can be input to the control device by operating several keys arranged on the keyboard, and
This was done for the purpose of making it possible to set complex program contents such as counting operations even though it is a step-by-step type.

With a pinboard type sequence controller, the program is input to the sequence controller by inserting a pin into a predetermined position of a pin hole in a predetermined row of the pinboard for each step of the program, so the entire created program is based on the pin arrangement. On the other hand, the reliability is not sufficient due to poor pin contact, and managing them is troublesome because a large number of pins are required.If the number of steps in the program is large, the pinboard There are disadvantages such as a large area. According to the present invention, a program can be input into the memory of a sequence controller by operating keys on a keyboard, so there is no need to manage pins, cause poor pin contact, and if the number of steps in a program increases, the sequence controller must have a large pin board. This eliminates the problems associated with pinboard design, and provides superior management, reliability, and cost (especially when the number of program steps is large) to the pinboard version. Furthermore, in the present invention, one key is used for inputting one command and one data, and the meaning of key operations is determined according to the order of key operations. In addition to reducing the number of key operations in
By displaying the input/output terminal numbers, etc., key operations can be performed while visually confirming the specific contents of each step of the program, thereby simplifying the operational and structural aspects. The present invention will be explained below with reference to Examples.

FIG. 1 is a front view of an operation panel of a sequence controller according to an embodiment of the present invention. A group of keys 1 in the lower right corner of the panel are input keys for operation, commands, data, etc.The keys with numbers written on them are used for both inputting commands and inputting data numbers.
The keys with Roman characters written on them are operation keys. The two upper and lower display sections 2 and 3 on the upper left are rows of output terminal display lamps, numbered 32 from number 1 to number 32.The lamp at the position indicating the output terminal specified in a certain program step will light up. ing. The two rows of displays 4 and 4' on the upper right are a row of input terminal indicator lamps numbered 1 to 32, and when an input is applied to the input terminal specified in a certain program step, the corresponding lamp lights up. do. Display section 3
The number display section 5 below has four frames 51, 52,
53 and 54, the leftmost frame 51 displays the step number in two digits, and the right frame 52 displays the type of instruction in one digit number, and the number 4 in the example in the figure is For example, it means an AND command. A translation table of this command word and its code number is shown in frame 6 below number part 5.
It is listed in. 3rd from the left in number display section 5,
The rightmost frames 53 and 54 are each two-digit numbers, each representing a numerical value of data.

Next, we will outline the operation method for the above panel. Program writing. First, power switch PS
Turn the program console switch CS to the on side, then turn the step to “0”.
To reset, flip switch S2 once to the reset side. Also, it is assumed here that all memory for storing programs has been cleared. Then, input each step of the program in sequence. Each step of the program starts with a key in the key group at the beginning of writing.
Press the INS key and then the command key. Since the command for each step is always one word, pressing the numeric key after the INS key automatically becomes a command input operation, and subsequent key operations automatically become data input. Therefore, the same key can function either for command input or for data entry, depending on the order in which it is pressed during a write operation. First, write the instruction for the 0th step.
Press the INS key, then press the number 2 key.
The number 2 key is a return command, that is, a command to return to the starting point.The first frame 51 from the left of the number display section is "00" and the second frame 52 is "2". Press the key. This key commands reading and writing to the memory.A return command is written in the memory, and by pressing the R/W key, the step is automatically advanced, and the first frame 51 of the numeric display section is The display will be "01" and all other frames will be 0. Now input the command for the first step. For example, if this step is to output an output to output terminals 2 and 4 by inputting an AND between input terminals 1 and 3, first press the INS key and press the number key 4, which indicates an AND command. The number 4 is displayed in the frame 51 of the number display section. Since a command is limited to one word, the next key pressed naturally becomes a data input operation. In this case, the command is to AND the inputs of input terminals 1 and 3, so press the numeric key "0" and then "0".
Press. The display in frame 53 of the number display section becomes 01,
Next, press the number key "0" and then press "3", and the display in the frame 54 of the number display section will change to 03, and the number display section will display the contents of the first step of the program as "AND", "01", "03", etc. ” is displayed. Next, press the OUT key to specify the output terminal, and the display 3
The number 1 lamp flashes. Next, when you press the OFF key, the lamp above the number 1 on the display section 3 disappears and the lamp above the number 2 blinks. Next, press the ON key, the lamp above the number 2 will light up, and the output terminal 2 will turn on.
The content of the command to be output is displayed, and the lamp above the next number 3 starts blinking. Output is made to terminals 2 and 4, so press the OFF key again. Therefore, by pressing the above OFF key, the number 3 on display section 3 will be displayed.
The lamp above goes out, and by pressing the ON key, the fourth output terminal is designated. Now that the configuration of the first step command is complete, press the R/W key to write the first step command in the memory and advance the program step one step. “02”
Display. Thereafter, the program contents are input into the memory one step at a time by the operations described above. Thus, if the last step is to run the entire program 15 times, press the keys in the following order: "INS"
"8" (repeated instruction code number) "1", "5" (15
(Meaning from step 1 of the program, meaning that steps from step 1 to this step will be repeated 15 times.) Press "R/W". The final step in the program format is the "END" command, and in the next step after the above-mentioned repeat command, the entire program is completed by key operations in the order of "INS,""END," and "R/W."

Next, to run the above program, turn the program console switch CS to the OFF side, turn the switch S1 to the "auto" side, and turn the start switch S3 downward once. The program will now start running. While the program is being executed, the indicator light 55 to the right of the number display section 5 is lit. Each frame of the numerical display section 5 numerically displays the number of the program step currently being executed, the contents of the program, etc. For example, while the first step is being executed, the number 01 appears in the first frame 51 of the number display section 5, indicating that it is the first step, and the command for this step is executed.
When it is AND, the second frame 52 shows the number 04, and the two input terminals for which the AND condition should be satisfied are 1.
and number 3, the third frame 53 of the number display section shows
The number 01 appears, and the number 03 appears in the fourth frame 54. In this first step, the output is output to the designated output terminals 2 and 4, and the lamps 2 and 4 of the display section 2 are turned on. The first step is input terminal 1
When an input signal is input to both 3 and 3, the program progresses by one step, and the display of the numeric display section changes to the content display of the second step, and at the same time, execution of the second step is started. That is, as the program progresses, when the command contents of a certain step, that is, the setting conditions are satisfied, the step is incremented and the next step is executed.

FIG. 2 is a block diagram showing the internal structure of the above-mentioned device. The block marked CPU is the central control unit in this device, which is a microcomputer, and M is the memory for storing the program to be executed by this sequence control device, and the program is stored by the above-mentioned program write operation. Assume that a certain step in a program is currently being executed and the output specified by that step is being output. At that time, the CPU reads out the instruction of the above step from the memory M and stores it in the accumulator in the CPU.On the other hand, it constantly scans the input terminals IN1 to INn to check their input states, and records this input state and the accumulator. The CPU's built-in arithmetic judgment circuit compares the input terminal number and conditions in the instruction for that step stored in the mulrator, and if they match, 1 is added to the number of addresses specified in memory M, and the next step is read out. Perform the same operation as above. That is, this device uses a step-by-step type of external load control, but internally performs a scanning-type sequence control.
However, this scanning sequence control is constant as described above, regardless of the operations to be executed externally, and this internal control program is executed by the CPU.
It is stored in the internal read-only memory (ROM). When writing a program to control an external load, the CPU reads an internal control program for program writing from the ROM, and according to the program, the aforementioned panel key group 1, console switch CS, switch S2, etc. are connected. Repeatedly scans the input state of the internal input circuit. To be exact
The CPU controls the console switch connected to each input terminal IN1 to INn of the external input circuit IN and the internal input terminal according to the internal control program written in the ROM.
It scans the open/close states of CS, switch S2, etc., key group 1, etc., and identifies program writing, program execution, or other operations depending on the input state of the internal input circuit. The following actions are now being performed. In this case, the input state of the internal input circuit is program writing, so as mentioned above, only key group 1 and the internal input circuit are scanned, and the commands set by the key group are sequentially written to memory M. Go.
Furthermore, during program writing, execution, and other operations, the CPU displays the contents of the steps of the program being written, the contents of the steps of the program being executed, the contents of specified steps in the program, etc. on the numerical display section 5. The actions to be displayed in sections 2, 3, etc.
Executes according to internal control program in ROM.

In short, the CPU is operated by an internal control program written in the ROM that controls the CPU itself, and the internal control program that controls the CPU is switched depending on the input state of the internal input circuit. The target operation switches to writing the external load control program, executing the program, etc.

The basic operation of the above device is AND instruction and OR
The configuration and operation of the device will be specifically explained in relation to the instructions. As an example, the 35th step of the program uses an AND instruction to input the 12th IN12 and 13th input terminals.
If input is input to number IN13, step is 1.
Progress and the steps (35th step)
Assume that the content is to output signals to output terminals 1, 2, 3, 5, and 8. The display format of display sections 2, 3 and 5 is as shown in FIG. When the execution of the program progresses and the operation of the 34th step is completed, the count of the step counter becomes 35, and this count becomes the address designation information of the memory M in which the program was written, and the instruction at address 35 of the memory M, that is, the 35th step. The step command is read and the third
It is displayed on the display sections 2, 3, and 5 in the format shown in the figure. At the same time, outputs are output to output terminals 1, 2, 3, 5, and 8 specified in the 35th step. The CPU determines the type of instruction, and if it is found to be an AND instruction, it checks the input state of the input terminal IN12 in the input circuit, and repeats the check until this input is present. When the input of IN12 becomes present, the input circuit IN13 is checked. And input circuit IN1
Input terminal IN12, IN until 3 input is present.
The operation of checking 13 input states is repeated. During this process, when the input of IN12 becomes 0, the operation returns to repeating checking only the input terminal IN12. In this way, input terminals IN12 and IM
When it is detected that both 13 and 13 are input, the step counter is incremented by several 1 and the next step instruction is read. The program for the above operations in the CPU is written in the ROM. The step counter may use a random access memory RAM included in the CPU, or may use memory M. The RAM described above may be used as the memory M for writing programs.

FIG. 4 is a flowchart showing the operation of the CPU in the above-mentioned AND instruction.

The display format of display sections 2, 3, and 5 for the OR instruction is the same as for AND, and the number on the display section 52 representing the type of instruction is 5, which is the code for the OR instruction. Therefore, borrowing FIG. 3 to explain the display format of the OR command, the display section 53,
The numbers shown at 54 indicate the numbers of the two input terminals, and if an output is output to output terminals 1, 2, 3, 5, and 8 at the same time, and an input signal is input to either input terminal 12 or 13, the next step is started. The next step is to execute the instruction.

FIG. 5 shows a flowchart of the OR instruction execution operation in the CPU. The instruction read from memory M is
When it is determined that it is an OR instruction, the contents of the instruction are displayed on the display sections 2, 3, and 5, and the output terminals 1, 2, 3, 5,
8, checks the input terminal IN12, and if there is no input, checks IN13. If an input is detected at any input terminal, it adds 1 to the count of the step counter and reads the next step command. Move on to execution.

This concludes the overall description of the apparatus according to the embodiment of the present invention, and the characteristic functional operations of the present invention will be described below using the apparatus according to the embodiment of the present invention.

Count command. This is an operation in which a certain signal is counted a set number of times. The number 6 appears at 52 on the display, and this 6 means a count command. Needless to say, when setting up a program, press the number 6 key after the INS key. The number appearing on the next display section 53 indicates the specified number of times.
The number 4 indicates the input terminal number. The operation is such that each time the input state of a designated input terminal changes, 1 is subtracted from the set number of times stored in the memory, and when the set number of times in the memory becomes 0, the program advances to the next step. FIG. 6 shows a flowchart for executing the count instruction. When a count command is detected at a certain step of the program, the input state of the input terminal displayed on the display section 54 is stored in the memory, and then the stored value is compared with the input state of the input terminal, and if there is no change (NO ), this comparison operation is repeated until a change is found (YES), and when a change is found, subtract 1 from the number displayed on the display section 53, check whether the result is 0, and if it is not 0. The input state of the specified input terminal after the above change is stored in the memory, and the same operation as described above is repeated until the displayed number on the display section 53 becomes 0. When the number becomes 0, the program moves to the next step.

The sequence controller of the present invention has the above-mentioned configuration, and since it belongs to the step-by-step type, it is easy to create a program.Furthermore, since the program is written by key operations on the keyboard, compared to the conventional pinboard type, There is no need to worry about poor pin contact, and since a pin board is not required, it can be made smaller, and since a counter operation is added, it has features such as being able to perform more complex control even though it is a step-by-step type. In addition, the command input keys and data input keys can be used in combination, and the meaning of a key operation is determined by the order of operations, such as command input, input terminal designation, count value setting, etc., so the number of operation keys is reduced. ,
Since the meaning of each key is determined by the order in which it is operated, there is no need for a separate key to specify what a certain key operation means, which reduces the number of key operations needed to input commands for one step, and allows the display of the step contents. By providing a display section with a display format that has the same content arrangement as the order of key operations, the contents of the steps can be visually checked.The display format is the same as the arrangement of meanings determined by the order of key operations, making the display easy to understand. Since there is no need for an explanatory display specifically indicating the display contents, the configuration of the display means is also simplified.

[Brief explanation of the drawing]

FIG. 1 is a front view of an apparatus according to an embodiment of the present invention, and FIG.
This figure is a block diagram showing the internal configuration, FIG. 3 is a display format of the AND instruction, FIG. 4 is a flowchart of the device operation related to the execution of the AND instruction, and FIG. 5 is the same.
Flowchart of OR instruction execution operation. FIG. 6 shows a flowchart of execution of a count instruction. 1... Keys of the key group, 2, 3, 5... Display section,
CPU...Central control unit, M...Memory for writing sequence control programs, IN1 to INn
...Input terminal, OUT1 to OUTn...Output terminal.

Claims (1)

[Claims] 1 Scan the input key group in which one key is used for command input and data input, the external load control program memory, the external input terminal group, the output terminal group, and the key-in status of the above input key group. The meaning of the key operation is determined by the operation order of the input key group, the command set by the input key group is determined and written to the memory, the program written to the memory is read, and the command is read from the external input terminal. An internal control program was written to control the external load by scanning the group and outputting a signal to the output terminal according to the contents of the program read above.
It has a ROM and a step content display means having a display format of an arrangement of instruction contents that is the same as the order of key operations, and a key that is also used for inputting a count instruction as one key in the input key group, and an external load. When the control program is written to the above memory, when the key used for inputting the above count command is pressed at a certain step, one of the two numerical data that was subsequently keyed in at that step is input externally according to the input order. The above-mentioned internal control program includes a count instruction in which a terminal designation code is used as data specifying the number of times the input state of the input terminal changes, and the contents of the instruction are displayed on the display means.
Sequence controller installed in ROM.