JPH03129884A - Led drive circuit - Google Patents

Led drive circuit

Info

Publication number
JPH03129884A
JPH03129884A JP1266300A JP26630089A JPH03129884A JP H03129884 A JPH03129884 A JP H03129884A JP 1266300 A JP1266300 A JP 1266300A JP 26630089 A JP26630089 A JP 26630089A JP H03129884 A JPH03129884 A JP H03129884A
Authority
JP
Japan
Prior art keywords
transistor
turned
voltage
capacitor
input terminal
Prior art date
Legal status (The legal status is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the status listed.)
Granted
Application number
JP1266300A
Other languages
Japanese (ja)
Other versions
JP2860405B2 (en
Inventor
Hisashi Ito
壽 伊藤
Current Assignee (The listed assignees may be inaccurate. Google has not performed a legal analysis and makes no representation or warranty as to the accuracy of the list.)
New Japan Radio Co Ltd
Original Assignee
New Japan Radio Co Ltd
Priority date (The priority date is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the date listed.)
Filing date
Publication date
Application filed by New Japan Radio Co Ltd filed Critical New Japan Radio Co Ltd
Priority to JP26630089A priority Critical patent/JP2860405B2/en
Publication of JPH03129884A publication Critical patent/JPH03129884A/en
Application granted granted Critical
Publication of JP2860405B2 publication Critical patent/JP2860405B2/en
Anticipated expiration legal-status Critical
Expired - Fee Related legal-status Critical Current

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Abstract

PURPOSE:To enable a drive circuit to easily and efficiently raise an output voltage by a method wherein a first and a second transistor are turned ON by a fourth transistor when the voltage of an output terminal is lower than a prescribed value, and a third transistor is turned ON when higher than a prescribed value. CONSTITUTION:A voltage V0 is applied to an LED 9 from an output terminal 8 and falls as power is consumed, and when the voltage V0 decreases to a voltage lower than a prescribed value, a fourth transistor Q1 is turned ON, a transistor Q2 is turned ON, a transistor Q3 is turned OFF, a third transistor Q7 is turned OFF, a transistor Q4 is turned OFF, a transistor Q5 and a second transistor Q6 are turned ON, and a first transistor Q8 is turned ON when the transistor Q5 is turned ON. In result, a current flowing from an input terminal 7 is made to charge a capacitor C3 flowing through the transistor Q8, the capacitor C3, and the transistor Q6. When the voltage V0 reaches a prescribed value, the transistor Q1 is turned OFF, the transistor Q2 is turned OFF, the transistor Q3 is turned ON to turn the transistor Q7 ON, the transistor Q4 is turned ON to turn the transistors Q5, Q6, and Q8 OFF, and a voltage is applied onto the ground terminal of the capacitor C3 via the input terminal 7 and the transistor Q7 to raise the voltage V0. By this setup, an input voltage can be efficiently raised.

Description

【発明の詳細な説明】 〔産業上の利用分野〕 本発明は、LED (発光ダイオード)駆動に必要な昇
圧回路を具備するLED駆動回路に関する。
DETAILED DESCRIPTION OF THE INVENTION [Field of Industrial Application] The present invention relates to an LED drive circuit including a booster circuit necessary for driving an LED (light emitting diode).

〔従来の技術〕[Conventional technology]

例えば、1個の乾電池を電源として使用する装置(カセ
ットテーププレーヤ等)では、その乾電池の電圧が使用
消耗により1.5vから1v程度まで低下することは通
常であるので、この1v程度でも正常に動作するように
回路部分の設計が行われる。
For example, in a device that uses a single dry battery as a power source (such as a cassette tape player), it is normal for the battery voltage to drop from 1.5v to around 1v due to wear and tear. The circuit portion is designed to work.

その内で、特に表示素子としてLED (順方向電圧が
1.4 v程度)を組み込む場合は、その駆動回路に昇
圧回路を組み込むことが行われている。
Among these, especially when incorporating an LED (forward voltage of about 1.4 V) as a display element, a booster circuit is incorporated into its drive circuit.

この昇圧回路として、第2図に示すコイルの逆起電力を
利用する方法がある。これは、制御回路lによりスイッ
チSlをオンして、入力端子2から流入する電流をコイ
ルLとスイッチS 1’を経由して接地に流してそのコ
イルしにエネルギーを蓄え、次にスイッチS1をオフし
た時にそのコイルLから放出されるエネルギー電圧をダ
イオードDIを経由してコンデンサC1に充電し出力端
子3に出力するようにしたものである。
As this booster circuit, there is a method of utilizing the back electromotive force of a coil shown in FIG. This is done by turning on the switch Sl by the control circuit l, causing the current flowing from the input terminal 2 to flow through the coil L and the switch S1' to ground, storing energy in the coil, and then turning on the switch S1. The energy voltage released from the coil L when turned off is charged to the capacitor C1 via the diode DI, and outputted to the output terminal 3.

また、第3図に示すように、チャージポンプを使用する
方法もある。これは、発振回路4によりまずスイッチS
2をオフ、スイッチS3をオンして入力端子5から流入
する電流をダオオードD2、コンデンサC2およびスイ
ッチS3を経由して接地に流してそのコンデンサC3を
入力端子5に印加している電圧まで充電し、その後にス
イッチS3をオフ、スイッチS2をオンして、ダイオー
ドD3を介して入力端子5の電圧をコンデンサC2に印
加して、出力端子6に入力端子5に印加した電圧の2倍
の電圧を出力させるようにしたものである。
Furthermore, as shown in FIG. 3, there is also a method of using a charge pump. This is first caused by the oscillation circuit 4 to switch S.
2 is turned off, switch S3 is turned on, and the current flowing from input terminal 5 is passed to the ground via diode D2, capacitor C2, and switch S3, and the capacitor C3 is charged to the voltage applied to input terminal 5. , then turn off the switch S3, turn on the switch S2, apply the voltage at the input terminal 5 to the capacitor C2 via the diode D3, and apply a voltage twice the voltage applied to the input terminal 5 to the output terminal 6. This is how it is output.

〔発明が解決しようとするf!題〕[The invention tries to solve f! Title]

ところが、第2図に示す回路では、制御回路1が必要と
なって回路が複雑化し、また第3図に示す回路ではダイ
オードD2、D3でその順方向電圧(I=IO,7v)
が消費されるので、低電圧入力の場合にはこの回路を複
数段構成し複数のコンデンサを使用しなければならない
という問題があった。
However, in the circuit shown in Fig. 2, the control circuit 1 is required, making the circuit complicated, and in the circuit shown in Fig. 3, the forward voltage (I = IO, 7v) is
is consumed, so in the case of low voltage input, there is a problem in that this circuit must be configured in multiple stages and multiple capacitors must be used.

本発明はこのような点に鑑みてなされたものであり、そ
の目的は、簡単で効率高く昇圧できる回路を具備するL
ED駆動回路を提供することである。
The present invention has been made in view of these points, and its purpose is to provide an L
An object of the present invention is to provide an ED drive circuit.

(課題を解決するための手段〕 このために本発明は、一端が出力端子に接続されるコン
デンサの電圧によりLEDを駆動するLED駆動回路に
おいて、 入力端子と上記コンデンサの上記一端に接続した第1の
トランジスタと、接地側と上記コンデンサの他端に接続
した第2のトランジスタと、上記入力端子と上記コンデ
ンサの上記他端に接続した第3のトランジスタと、上記
出力端子の電圧が所定値より低いとき上記第1および第
2のトランジスタをオンさせ、高いとき上記第3のトラ
ンジスタをオンさせる第4のトランジスタとから構成し
た。
(Means for Solving the Problems) For this purpose, the present invention provides an LED drive circuit that drives an LED by the voltage of a capacitor whose one end is connected to an output terminal, and a first capacitor connected to the input terminal and the one end of the capacitor. a second transistor connected to the ground side and the other end of the capacitor, a third transistor connected to the input terminal and the other end of the capacitor, and a voltage at the output terminal is lower than a predetermined value. and a fourth transistor that turns on the first and second transistors when the voltage is high, and turns on the third transistor when the voltage is high.

〔実施例〕〔Example〕

以下、本発明の実施例について説明する。第1図はその
一実施例の回路を示す図である。7は入力端子、8は出
力端子、9がLEDである。Qlは出力電圧Voを抵抗
R12、R13で分割した電圧がベースに印加し、その
出力電圧Voが所定電圧以下になるとオンするトランジ
スタ(第4のトランジスタ)である、Q2は上記トラン
ジスタQlがオンすることによりオンするトランジスタ
で、そのオンにより、トランジスタQ3、Q4をオフさ
せる。Q5はトランジスタQ4がオフすることによりオ
ンしてトランジスタQ8 (第1のトランジスタ)をオ
ンさせるトランジスタである。
Examples of the present invention will be described below. FIG. 1 is a diagram showing a circuit of one embodiment. 7 is an input terminal, 8 is an output terminal, and 9 is an LED. Ql is a transistor (fourth transistor) to which a voltage obtained by dividing the output voltage Vo by resistors R12 and R13 is applied to the base, and turns on when the output voltage Vo becomes less than a predetermined voltage. Q2 turns on the transistor Ql. This is a transistor that turns on due to this, and turning on turns off transistors Q3 and Q4. Q5 is a transistor that turns on when transistor Q4 turns off, turning on transistor Q8 (first transistor).

Q6もトランジスタQ4がオフすることよりオンしてコ
ンデンサC3の片端を接地電位に落とすトランジスタ(
第2のトランジスタ)である、Q7はトランジスタQ3
がオンすることによりオンしてコンデンサC3の片端に
ほぼ入力電圧Viを印加する嵩上げ用のトランジスタ(
第3のトランジスタ)である、トランジスタQ8はコン
デンサC3の充電用として働(。
Q6 is also a transistor that turns on when transistor Q4 turns off and drops one end of capacitor C3 to ground potential (
Q7 is the transistor Q3
When C3 is turned on, a raising transistor (
Transistor Q8, which is the third transistor (3rd transistor), serves to charge the capacitor C3 (3rd transistor).

さて、出力端子8の出力電圧Voが零のときは、トラン
ジスタQ1のベース電位が低下しているので、そのトラ
ンジスタQ1がオンして、トランジスタQ2がオンする
。よって、トランジスタQ3がオフしてトランジスタQ
7がオフし、またトランジスタQ4がオフしてトランジ
スタQ5、Q6がオンする。そして、トランジスタQ5
のオンによりトランジスタQ8がオンする。
Now, when the output voltage Vo of the output terminal 8 is zero, the base potential of the transistor Q1 is lowered, so the transistor Q1 is turned on and the transistor Q2 is turned on. Therefore, transistor Q3 turns off and transistor Q
7 is turned off, transistor Q4 is also turned off, and transistors Q5 and Q6 are turned on. And transistor Q5
Turning on turns on transistor Q8.

この結果、入力端子7から流入する電流が、トランジス
タQ8→コンデンサ03→トランジスタQ6を経由して
流れて、そのコンデンサC3に電荷が充電される。つま
り、このコンデンサの電圧VCIは、トランジスタQ6
、Q8のコレクタ・エミッタ間電圧を各々VCE& 、
VCt@とすると、Vcs= V i  VCl2  
Vcim       ・・・(tlを目標として充電
される。もし、完全充電されればそのときの出力電圧■
0は、 V O= Vc3+ Vcti = V i −Vet
o    ・・・(2)となる。
As a result, the current flowing from the input terminal 7 flows through the transistor Q8, the capacitor 03, and the transistor Q6, and the capacitor C3 is charged with electric charge. In other words, the voltage VCI of this capacitor is
, the collector-emitter voltage of Q8 is VCE & , respectively.
If VCt@, Vcs= V i VCl2
Vcim... (Charged with the target of tl. If fully charged, the output voltage at that time is
0 is VO=Vc3+Vcti=Vi-Vet
o...(2).

ここで、出力電圧■0が上記式(2)を満足する値とな
った時に、トランジスタQlがオフするように抵抗R1
2とR13による分割比を設定しておけば、その式(2
)を満足した時点で、今度は上記と反対にトランジスタ
Q2オフ、トランジスタQ3、Q4オンとなる。トラン
ジスタQ3のオンによりトランジスタQフオン、トラン
ジスタQ4のオンによりトランジスタQ5、Q6、Q8
がオフとなる。
Here, the resistor R1 is set so that the transistor Ql is turned off when the output voltage ■0 reaches a value that satisfies the above formula (2).
2 and R13, the formula (2
), the transistor Q2 is turned off and the transistors Q3 and Q4 are turned on, contrary to the above. When transistor Q3 is turned on, transistor Q is turned on, and when transistor Q4 is turned on, transistors Q5, Q6, Q8 are turned on.
is turned off.

この結果、コンデンサC3の接地側の端子に入力端子7
からトランジスタQ7を経由する電圧Vaが印加し出力
電圧Voを嵩上げするようになる。
As a result, input terminal 7 is connected to the ground side terminal of capacitor C3.
From there, a voltage Va is applied via the transistor Q7 to raise the output voltage Vo.

このときトランジスタQ7のコレクタ・エミッタ間電圧
をvcxtとすると、印加する電圧Vaは、Va=Vi
−Vcta            ・・・(3)とな
る。従って、出力電圧Voは、この式(3)と上記式(
2)とから、 Vo= (V i −Vcii −Vcta ) + 
(V i −V(H)−2Vi−3Vct      
    ・・・(4)となる。但し、Vci= Vct
&= Vc配’+=vctsである。
At this time, if the collector-emitter voltage of transistor Q7 is vcxt, the applied voltage Va is Va=Vi
-Vcta...(3). Therefore, the output voltage Vo is calculated by combining this equation (3) and the above equation (
2), Vo= (V i -Vcii -Vcta) +
(Vi-V(H)-2Vi-3Vct
...(4). However, Vci=Vct
&=Vc distribution'+=vcts.

この電圧Voは出力端子8からLED9に印加され消費
されるので、(2)式に示す電圧よりも低下すれば、再
度トランジスタQ1がオンしてコンデンサC3への充電
が行われて、その後(2)式に示す電圧に達するとその
コンデンサC3の電圧の嵩上げが行われ、これが繰り返
される。このような発振が継続してLED9が継続的に
駆動される。
This voltage Vo is applied to the LED 9 from the output terminal 8 and is consumed, so when the voltage falls below the voltage shown in equation (2), the transistor Q1 is turned on again to charge the capacitor C3, and then (2 ) When the voltage of the capacitor C3 is reached, the voltage of the capacitor C3 is increased, and this process is repeated. Such oscillation continues and the LED 9 is continuously driven.

オン時のコレクタ・エミッタ間電圧VC1は、例えば0
.2V程度であり、上記した(4)式は、V o = 
2 V i −0,6”・(5)となる。従って、入力
電圧Viが1V程度の低電圧であっても、出力電圧Vo
を1.4V程度にまで昇圧することができ、LED9を
駆動するに充分な電圧が得られることになる。
The collector-emitter voltage VC1 when turned on is, for example, 0.
.. The voltage is about 2V, and the above equation (4) is expressed as V o =
2 V i −0,6”・(5) Therefore, even if the input voltage Vi is as low as 1V, the output voltage Vo
can be boosted to about 1.4V, and a voltage sufficient to drive the LED 9 can be obtained.

〔発明の効果) 以上説明したように、本発明によれば、入力電圧を効率
高く昇圧することができ、1V程度の低い入力電圧でL
EDを確実に駆動させることがでるという利点がある。
[Effects of the Invention] As explained above, according to the present invention, the input voltage can be boosted with high efficiency, and the L
This has the advantage that the ED can be driven reliably.

【図面の簡単な説明】[Brief explanation of the drawing]

第1図は本発明の一実施例のLED駆動回路の回路図、
第2図と第3図は従来の昇圧回路の回路図である。 1・・・制御回路、2・・・入力端子、3・・・出力端
子、4・・・発振回路、5・・・入力端子、6・・・出
力端子、7・・・入力端子、8・・・出力端子、9・・
・LED。
FIG. 1 is a circuit diagram of an LED drive circuit according to an embodiment of the present invention,
FIGS. 2 and 3 are circuit diagrams of conventional booster circuits. DESCRIPTION OF SYMBOLS 1... Control circuit, 2... Input terminal, 3... Output terminal, 4... Oscillation circuit, 5... Input terminal, 6... Output terminal, 7... Input terminal, 8 ...Output terminal, 9...
・LED.

Claims (1)

【特許請求の範囲】[Claims] (1)、一端が出力端子に接続されるコンデンサの電圧
によりLEDを駆動するLED駆動回路において、 入力端子と上記コンデンサの上記一端に接続した第1の
トランジスタと、接地側と上記コンデンサの他端に接続
した第2のトランジスタと、上記入力端子と上記コンデ
ンサの上記他端に接続した第3のトランジスタと、上記
出力端子の電圧が所定値より低いとき上記第1および第
2のトランジスタをオンさせ、高いとき上記第3のトラ
ンジスタをオンさせる第4のトランジスタとからなるこ
とを特徴とするLED駆動回路。
(1) In an LED drive circuit that drives an LED by the voltage of a capacitor whose one end is connected to an output terminal, the first transistor is connected to the input terminal and the one end of the capacitor, and the ground side and the other end of the capacitor. a second transistor connected to the input terminal and the other end of the capacitor; and a third transistor connected to the input terminal and the other end of the capacitor, and turning on the first and second transistors when the voltage at the output terminal is lower than a predetermined value. , and a fourth transistor that turns on the third transistor when the voltage is high.
JP26630089A 1989-10-16 1989-10-16 LED drive circuit Expired - Fee Related JP2860405B2 (en)

Priority Applications (1)

Application Number Priority Date Filing Date Title
JP26630089A JP2860405B2 (en) 1989-10-16 1989-10-16 LED drive circuit

Applications Claiming Priority (1)

Application Number Priority Date Filing Date Title
JP26630089A JP2860405B2 (en) 1989-10-16 1989-10-16 LED drive circuit

Publications (2)

Publication Number Publication Date
JPH03129884A true JPH03129884A (en) 1991-06-03
JP2860405B2 JP2860405B2 (en) 1999-02-24

Family

ID=17429024

Family Applications (1)

Application Number Title Priority Date Filing Date
JP26630089A Expired - Fee Related JP2860405B2 (en) 1989-10-16 1989-10-16 LED drive circuit

Country Status (1)

Country Link
JP (1) JP2860405B2 (en)

Cited By (3)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
US6628252B2 (en) 2000-05-12 2003-09-30 Rohm Co., Ltd. LED drive circuit
JP2005136157A (en) * 2003-10-30 2005-05-26 Rohm Co Ltd Light emitting element driving device, display module having same driving device, and electronic device having same module
JP2013157331A (en) * 2013-04-12 2013-08-15 Kazuo Yamada Led lighting circuit by low-voltage power supply, and device having led lighting circuit

Cited By (3)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
US6628252B2 (en) 2000-05-12 2003-09-30 Rohm Co., Ltd. LED drive circuit
JP2005136157A (en) * 2003-10-30 2005-05-26 Rohm Co Ltd Light emitting element driving device, display module having same driving device, and electronic device having same module
JP2013157331A (en) * 2013-04-12 2013-08-15 Kazuo Yamada Led lighting circuit by low-voltage power supply, and device having led lighting circuit

Also Published As

Publication number Publication date
JP2860405B2 (en) 1999-02-24

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