JP4962883B2 - stool - Google Patents

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JP4962883B2
JP4962883B2 JP2006075702A JP2006075702A JP4962883B2 JP 4962883 B2 JP4962883 B2 JP 4962883B2 JP 2006075702 A JP2006075702 A JP 2006075702A JP 2006075702 A JP2006075702 A JP 2006075702A JP 4962883 B2 JP4962883 B2 JP 4962883B2
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triangle
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surface constituting
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JP2007244779A (en
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石井宗一郎
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石井 宗一郎
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    • AHUMAN NECESSITIES
    • A47FURNITURE; DOMESTIC ARTICLES OR APPLIANCES; COFFEE MILLS; SPICE MILLS; SUCTION CLEANERS IN GENERAL
    • A47CCHAIRS; SOFAS; BEDS
    • A47C5/00Chairs of special materials
    • A47C5/005Chairs of special materials of paper, cardboard or similar pliable material

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Description

本発明は、1枚のシートを折り曲げてできる頑丈なスツールに関するものである。   The present invention relates to a sturdy stool that can be formed by bending a single sheet.

金属製または木製の椅子や足台などのスツールは頑丈ではあるものの重いため持ち運びに労力を要するほか、イベント会場など多数の椅子を扱う場合などにはその運搬、および使用前後の収納、などにも難点がある。
他方、包装材料として使用されているダンボールは、安価、軽量で、緩衝性を有するほか、リサイクル可能なため使用後廃棄処分することも出来るという利点がある。
このため、これまでもダンボール製の椅子が数多く提案されているが、組み立てが複雑、強度が低い、座り心地が悪い、外観が劣る、等の問題点があった。
特開平6−237832号公報 特開平9−322839号公報
Stool such as a metal or wooden chair or footrest is sturdy but heavy, so it requires labor to carry, and when handling many chairs such as event venues, it is also transported and stored before and after use There are difficulties.
On the other hand, corrugated cardboard used as a packaging material has the advantage that it is inexpensive and lightweight, has a cushioning property, and can be discarded after use because it is recyclable.
For this reason, many cardboard chairs have been proposed so far, but there are problems such as complicated assembly, low strength, poor sitting comfort, and poor appearance.
Japanese Patent Laid-Open No. 6-237832 Japanese Patent Laid-Open No. 9-322839

本発明は、1枚のシートを折るだけで組み立てが出来、強度が高く、見栄えの良いダンボール製スツールの提供を目的とする。   An object of the present invention is to provide a corrugated cardboard stool that can be assembled simply by folding a single sheet, has high strength, and has a good appearance.

本発明は、三角形と台形からなる1枚のシートを折り曲げて組み立てられるスツールであって、 前記1枚のシートは、三角形と台形を組み合わせた4つの頂部構成部材からなる頂部と、4つの前記頂部構成部材と隣接する4つの2等辺三角形の側部構成部材Aを含む5つの2等辺三角形の側部構成部材A、および5つの前記側部構成部材Aと隣接する4つの2等辺三角形の側部構成部材Bとからなる側部と、前記4つの側部構成部材Bと隣接する4つの2等辺三角形の側部内面構成部材Aと、4つの側部内面構成部材Aと隣接する三角形をした8つの側部内面構成部材Bとからなる側部内面と、から構成され、前記頂部構成部材は、上底がa−t−d、下底がa−t、高さがa/2−tの台形と、底辺がa、高さがdで、頂点Pから下ろした垂線が底辺と交わる点が底辺の中心よりtだけ底辺の1端にずれた三角形が、台形の斜辺と三角形の短い方の斜辺を結合させた形状であり、4つの前記頂部構成部材と隣接する4つの側部構成部材Aを含む5つの側部構成部材Aは、4つの側部構成部材Bを交互に挟んで横並びするように配置され、側部構成部材Aの第3辺を側部構成部材Bの第1辺に、側部構成部材Aの第2辺を側部構成部材B4の第2辺に、各々隣接され、前記側部構成部材Bの4つは前記側部構成部材Bの三角形の第1辺、第2辺が前記側部構成部材Aの三角形の第2辺、第3辺と隣接し、前記側部構成部材Bの三角形の第3辺が前記側部内面構成部材Aの三角形の第1辺と隣接し、  The present invention is a stool that is assembled by folding a single sheet of triangles and trapezoids, wherein the single sheet is composed of four top components formed by combining triangles and trapezoids, and the four tops. 5 isosceles triangle side component members A including four isosceles triangle side component members A adjacent to the component members, and four isosceles triangle side portions adjacent to the five side component members A A side portion composed of the component member B, four isosceles triangle side inner surface component members A adjacent to the four side component members B, and four triangles adjacent to the four side inner surface member A 8 A side inner surface comprising two side inner surface constituent members B, the top constituent member having an upper base at a-t-d, a lower base at a-t, and a height of a / 2-t. Trapezoid, base is a, height is d, lowered from apex P The triangle where the perpendicular intersects with the base is shifted from the center of the base to the end of the base by t, and the trapezoidal hypotenuse and the shorter hypotenuse of the triangle are combined and adjacent to the four top components. The five side component members A including the four side component members A are arranged side by side with the four side component members B alternately interposed therebetween, and the third side of the side component member A is configured as a side portion. The second side of the side component member A is adjacent to the first side of the member B, and the second side of the side component member B4 is adjacent to the second side of the side component member B4. The first side and the second side of the triangle are adjacent to the second side and the third side of the triangle of the side component member A, and the third side of the triangle of the side component member B is the side inner surface component member A. Adjacent to the first side of the triangle
前記側部内面構成部材Aの4つは、前記側部内面構成部材Aの三角形の第1辺が前記側部構成部材Bの三角形の第3辺と隣接し、前記側部内面構成部材Aの三角形の第2辺と第3辺は前記側部内面構成部材Bの斜辺と隣接し、4つの前記側部内面構成部材Aの第1辺が1直線上に配列され、前記側部内面構成部材Bの8つの内1つは、その斜辺が1直線上に配列される前記側部内面構成部材Aの1端部の第2辺と隣接し、他の1つは、その斜辺が1直線上に配列される前記側部内面構成部材Aの他端部の第3辺と隣接し、残りの6つは、その内の2つずつが第2辺を隣接させながら1直線上に配列される前記側部内面構成部材Aと斜面を前記側部内面構成部材Aの第2辺と第3辺と隣接させて交互に配列されることを特徴とする。  Four of the side inner surface constituting members A are such that the first side of the triangle of the side inner surface constituting member A is adjacent to the third side of the triangle of the side inner constituent member B, and The second side and the third side of the triangle are adjacent to the oblique side of the side inner surface constituting member B, and the first sides of the four side inner surface constituting members A are arranged on one straight line. One of the eight of B is adjacent to the second side at one end of the side inner surface constituting member A in which the hypotenuse is arranged on one straight line, and the other one has the hypotenuse on one straight line. The other six sides of the side-surface inner surface constituting member A are arranged on a straight line with two of the two sides being adjacent to each other. The side inner surface constituting member A and the slope are alternately arranged adjacent to the second side and the third side of the side inner surface constituting member A.
ここで、aは三角形の底辺で、組み立て後のスツールの頂部及び底部を形成する正方形の1辺に該当し、任意に決定できる数値、tは素材の板厚、dは三角形の高さを示し、a/2−tである。  Here, a is the base of the triangle, corresponds to one side of the square that forms the top and bottom of the assembled stool, and can be arbitrarily determined, t is the thickness of the material, and d is the height of the triangle , A / 2-t.

前記4つの頂部構成部材の三角形Aが頂部表面を形成し、5つの側部構成部材Aの内の4つの三角形の第2辺と第3辺が、5つの側部構成部材Bの内の4つの三角形の第1辺と第2辺と交互に隣接して8つの側部表面を形成し、残り1つの側部構成部材Aが、側部表面の内側に潜入して側部を形成し、4つの側部内面構成部材Aが側部内表面を形成し、4つの側部内面構成部材Aの間に挟まれた6つの側部内面構成部材Bと4つの側部内面構成部材Aの両端の2つの側部内面構成部材Bが側部の内側に潜入して側部内面を構成することを特徴とする。The triangle A of the four top components forms the top surface, and the second and third sides of the four triangles of the five side components A are the four of the five side components B. Forming two side surfaces alternately adjacent to the first side and the second side of two triangles, and the remaining one side component member A infiltrates inside the side surface to form a side part; Four side inner surface constituting members A form side inner surfaces, and six side inner surface constituting members B sandwiched between the four side inner surface constituting members A and at both ends of the four side inner surface constituting members A are arranged. Two side surface inner surface constituting members B infiltrate inside the side portion to constitute the side surface.

本発明は、1枚のダンボールのようなシートを折り曲げて出来るスツールであり、大人の椅子として充分な強度を有するほか、大人が踏み台として使用することも出来る。
また、本発明のスツールは、折るだけで作成可能であり、支柱や枠等を必要とせず、ダンボールの場合など切り口が殆ど外に出ないため外観がよく、使用しない場合はシート状にして保管が出来ると言うメリットがある。
The present invention is a stool formed by bending a sheet such as a cardboard, and has sufficient strength as an adult chair, and can also be used as a step by an adult.
In addition, the stool of the present invention can be created simply by folding, does not require a support column or frame, and has a good appearance because the cut end hardly protrudes in the case of corrugated cardboard. There is a merit that you can.

以下、図面を参照して詳細に説明する。   Hereinafter, it will be described in detail with reference to the drawings.

図1は、本発明のスツールをシート状に展開した図である。
図1において、点線は各部材の境界を示しており、点線に沿って折ることによりスツールが完成する。1点鎖線は、各部材内部における図形の境界を示す。
本実施例の素材はダンボールで、本発明のスツールは、図1の展開図のダンボールを点線の折り目に沿って折ることにより作成する。
図1に示す通り、展開図は、三角形と台形を組み合わせた4つの頂部構成部材からなる頂部と、4つの前記頂部構成部材と隣接する5つの二等辺三角形の側部構成部材A、および5つの前記側部構成部材Aと隣接する4つの二等辺三角形の側部構成部材Bとからなる側部と、前記4つの側部構成部材Bと隣接する4つの二等辺三角形の側部内面構成部材Aと、4つの側部内面構成部材Aと隣接する三角形をした8つの側部内面構成部材Bとからなる側部内面と、から構成される。
FIG. 1 is a developed view of a stool of the present invention in a sheet form.
In FIG. 1, the dotted line indicates the boundary of each member, and the stool is completed by folding along the dotted line. An alternate long and short dash line indicates a boundary between figures within each member.
The material of this embodiment is corrugated cardboard, and the stool of the present invention is created by folding the corrugated cardboard in the developed view of FIG. 1 along the broken line crease.
As shown in FIG. 1, the developed view includes a top portion composed of four top constituent members combining triangles and trapezoids, four isosceles triangular side constituent members A adjacent to the top constituent members, and five The side part composed of four isosceles triangular side part members B adjacent to the side part member A, and four isosceles side part inner surface part members A adjacent to the four side part members B And four side inner surface constituent members A and eight side inner surface constituent members B having an adjacent triangle.

展開図に示す三角形及び台形の寸法は以下のように設定する。
頂部構成部材は、台形と三角形から構成され、台形は、上底をa−t−d、下底をa−t、高さをa/2−tとし、三角形は、底辺をa、高さをd、頂点Pから下ろした垂線が底辺と交わる点が底辺の中心よりtだけ図1において底辺の左側にずれた三角形とし、台形の斜辺と三角形の短い方の斜辺を結合させたものとする。
ここで、aは三角形の底辺で、組み立て後のスツールの頂部及び底部を形成する正方形の1辺に該当し、任意の値に設定できる数値であるが本実施例では40cmとした。本実施例では、ε=tとした。εは、組み立てに必要な遊びであり、構成部材の厚みと同程度である。頂点Pへの各部材の重なりを逃がす働きをするものである。
tは素材の板厚で本実施例では5mmのものを使用した。
dは三角形の高さを示し、a/2−tより19.5cmとなる。
The dimensions of the triangle and trapezoid shown in the developed view are set as follows.
The top component is composed of a trapezoid and a triangle. The trapezoid has an upper base at a-t-d, a lower base at a-t, and a height a / 2-t. A triangle has a base a and a height. , And the point where the perpendicular line drawn from the apex P intersects with the base is a triangle shifted from the center of the base by t to the left of the base in FIG. 1, and the trapezoid hypotenuse and the shorter hypotenuse of the triangle are combined. .
Here, a is the base of the triangle, corresponds to one side of the square that forms the top and bottom of the stool after assembly, and is a numerical value that can be set to any value, but in this embodiment it is 40 cm. In this embodiment, ε = t. ε is a play necessary for assembly and is about the same as the thickness of the constituent members. It functions to release the overlap of each member to the vertex P.
t is the thickness of the material, and 5 mm was used in this embodiment.
d shows the height of a triangle and becomes 19.5 cm from a / 2-t.

三角形の側部構成部材Aと三角形の側部構成部材Bは合同で、底辺がa=40cm、高さがbの二等辺三角形である。
ここで、図3より、bは任意に決定できる組み立て後のスツールの高さhから下記(数1)で算定できる。本実施例では高さhを35cmとしたため、bは下記の式より36cmとなる。ただし、c=8.28cm
b=(h+c1/2 ただし、c=1/2(21/2―1)a
次に、三角形の側部内面構成部材Aは、底辺がa=40cm、高さがb’の二等辺三角形であり、b’={h+(a/2)1/2であるため、本実施例では、b’は40.3cmとなる。
三角形の側部内面構成部材Bは、側部内面構成部材Aの二等辺三角形を垂線で2分割した直角三角形において垂線の長さをb=36cmとした三角形となる。
Triangular side component A and triangular side component B are congruent and are isosceles triangles with a base of a = 40 cm and height of b.
Here, from FIG. 3, b can be calculated by the following (Equation 1) from the height h of the assembled stool that can be arbitrarily determined. In this embodiment, since the height h is 35 cm, b is 36 cm from the following formula. However, c = 8.28cm
b = (h 2 + c 2 ) 1/2 where c = 1/2 (2 1/2 −1) a
Next, the triangular inner side surface component A is an isosceles triangle having a base of a = 40 cm and a height of b ′, and b ′ = {h 2 + (a / 2) 2 } 1/2 . Therefore, in this embodiment, b ′ is 40.3 cm.
Triangular side inner surface constituting member B is a triangle in which the length of the perpendicular is b = 36 cm in a right triangle obtained by dividing the isosceles triangle of side inner surface constituting member A by a perpendicular.

次に各部材の配列方法について説明する。
4つの頂部構成部材2は、台形と隣接する三角形の第2辺11が、各々4つの側部構成部材A3の第1辺12と隣接する。
4つの頂部構成部材2と隣接する4つの側部構成部材A3を含む5つの側部構成部材A3は、4つの側部構成部材B4を交互に挟んで図1に示す通り横並びするように配置する。この際、側部構成部材A3の第3辺14を側部構成部材B4の第1辺15に、側部構成部材A3の第2辺13を側部構成部材B4の第2辺16に、各々隣接させる。
図1の右端には、頂部構成部材2を1つ追加して全部で5つとすることが出来る。あるいは5つ目の頂部構成部材として2辺がa、a−tの長方形を配置することが出来る。これは、頂部最下部を構成するもので、頂部(座面)の強度を増すために付加されるものであるが、強度の高い素材の場合には省略しても良い、
また、図1で、右端または左端の側部内面構成部材B6またはB7は、一枚が冗長な組み立て時の補強であるが、組み立てを容易にするために何れか一方を省略しても良い。
図1に示す通り、側部構成部材A3の第1辺12と、側部構成部材B4の第3辺17は一直線上に並ぶ。
Next, a method for arranging the members will be described.
In the four top constituent members 2, the second sides 11 of the triangles adjacent to the trapezoid are adjacent to the first sides 12 of the four side constituent members A3, respectively.
The five side component members A3 including the four top component members 2 and the four side component members A3 adjacent to each other are arranged side by side as shown in FIG. . At this time, the third side 14 of the side component A3 is set to the first side 15 of the side component B4, and the second side 13 of the side component A3 is set to the second side 16 of the side component B4. Adjacent.
At the right end of FIG. 1, one top component 2 can be added to make a total of five. Alternatively, a rectangle having two sides a and at can be arranged as the fifth top component. This constitutes the lowest part of the top and is added to increase the strength of the top (seat surface), but may be omitted in the case of a high strength material,
Further, in FIG. 1, one of the right and left end side inner surface constituting members B6 or B7 is a reinforcing member during redundant assembly, but either one may be omitted for easy assembly.
As shown in FIG. 1, the first side 12 of the side member A3 and the third side 17 of the side member B4 are aligned on a straight line.

図1において、4つの側部構成部材B4の三角形の第3辺17は、4つの側部内面構成部材A5の三角形の第1辺18と各々隣接するように配置するが、4つの側部内面構成部材A5の三角形の第1辺18は1直線なるように4つの側部内面構成部材A5を配列する。
また、側部内面構成部材A5の4つは、側部内面構成部材A5の三角形の第1辺18が側部構成部材B4の三角形の第3辺17と隣接し、側部内面構成部材A5の三角形の第2辺19と第3辺20は側部内面構成部材B6の第1辺(斜辺)21と隣接し、4つの側部内面構成部材A5の第1辺18が1直線上に配列されるように配置する。
In FIG. 1, the triangular third sides 17 of the four side component members B4 are arranged so as to be adjacent to the triangular first sides 18 of the four side inner surface component members A5. The four side surface inner constituent members A5 are arranged so that the triangular first side 18 of the constituent member A5 is a straight line.
Further, four of the side inner surface constituting members A5 are arranged such that the first side 18 of the triangle of the side inner surface constituting member A5 is adjacent to the third side 17 of the triangle of the side inner constituent member B4, and the side inner surface constituting member A5. The second side 19 and the third side 20 of the triangle are adjacent to the first side (slanted side) 21 of the side inner surface constituting member B6, and the first sides 18 of the four side inner surface constituting members A5 are arranged on one straight line. Arrange so that.

側部内面構成部材B6の8つの三角形は、最小角をなす頂点を4つの側部内面構成部材A5の第1辺が18なす1直線上に置き、三角形の斜辺21を側部内面構成部材A5の第2辺19、第3辺20と隣接させ、4つの側部内面構成部材A5の間に挟まれる側部内面構成部材B6の6つの三角形6は2つずつ第2辺22を隣接させて配置する。   In the eight triangles of the side inner surface constituting member B6, the apex forming the minimum angle is placed on one straight line formed by the first sides of the four side inner surface constituting members A5, and the triangular hypotenuse 21 is placed on the side inner surface constituting member A5. 6 triangles 6 of the side inner surface constituting member B6 that are adjacent to the second side 19 and the third side 20 and sandwiched between the four side inner surface constituting members A5 are adjacent to each other. Deploy.

組み立てた状態で、4つの頂部構成部材2は頂部表面部を形成し、5つの側部構成部材A3の内の4つの三角形の第2辺13と第3辺14が、5つの側部構成部材B4の内の4つの三角形の第1辺15と第2辺16と交互に隣接して8つの側部表面を形成し、残り1つの側部構成部材A3が、側部表面の内側に潜入して側部を形成する。
また、4つの側部内面構成部材A5が側部内表面を形成し、4つの側部内面構成部材A5の間に挟まれた6つの側部内面構成部材B6と4つの側部内面構成部材A5の両端の2つの側部内面構成部材B6が側部の内側に潜入して側部内面を構成することになる。
なお、本発明は、1枚のダンボールのようなシートを折り曲げて出来るスツールに関するものであるが、展開シートが1枚のシートから型取りできない場合は、複数のシートを張り合わせて前記展開シートを作成することも含まれるものとする。
In the assembled state, the four top constituent members 2 form a top surface portion, and the four second side portions 13 and the third side 14 of the five side constituent members A3 are the five side side constituent members. Four side surfaces of four triangles of B4 that are alternately adjacent to the first side 15 and the second side 16 are formed, and the remaining one side component member A3 infiltrates inside the side surface. The side is formed.
Further, four side inner surface constituting members A5 form a side inner surface, and six side inner surface constituting members B6 and four side inner surface constituting members A5 sandwiched between the four side inner surface constituting members A5. Two side inner surface constituting members B6 at both ends infiltrate inside the side portion to constitute the side inner surface.
The present invention relates to a stool that can be formed by bending a sheet such as a single cardboard. However, when the unfolded sheet cannot be formed from a single sheet, the unfolded sheet is created by laminating a plurality of sheets. To be included.

次に本実施例によるダンボール製スツールの組み立て方を図2、3を参照して説明する。
図1の展開シートで、頂部構成部材2は左端部から101,102,103,104,105、側部構成部材A3は、左端部から111,112,113,114,115,側部構成部材B4は、左端部から121,122,123,124,125,側部内面構成部材A5は、左端部から131,132,133,134,側部内面構成部材B6は、左端部から141,142,143,144,145,146,147,148とする。
実施例では、頂部構成部材2の105,側部構成部材B4の125を追加した場合について説明する。
また、紙面の垂直上方向に折り曲げることを内部に折り曲げると定義して説明する。
Next, a method for assembling the cardboard stool according to this embodiment will be described with reference to FIGS.
1, the top component 2 is 101, 102, 103, 104, 105 from the left end, the side component A3 is 111, 112, 113, 114, 115 from the left end, and the side component B4. 121, 122, 123, 124, 125 from the left end, 131, 132, 133, 134 from the left end, and 131, 132, 133, 134 from the left end, 141, 142, 143 from the left end. , 144, 145, 146, 147, 148.
In the embodiment, a case where 105 of the top constituent member 2 and 125 of the side constituent member B4 are added will be described.
Further, the description will be made by defining that folding in the vertical upward direction of the page is folding inward.

まず、図2、3に示すように、図1の展開シートの右端部の105,115,125を内側に折り曲げる。
次に、5つの頂部構成部材を点線部である第2辺11から内部に直角に折り曲げるとともに、側部内面構成部材A5の131〜134及び側部内面構成部材Bの141〜148を内側に、側部構成部材A3の111〜115、側部構成部材B4の121〜125に重なるように折り曲げる。
側部構成部材A3の115,側部構成部材B4の125をさらに折り込み、頂部構成部材105の先端を頂部構成部材104の内部(下部)に、頂部構成部材104の先端を頂部構成部材103の内部(下部)に、頂部構成部材103の先端を頂部構成部材102の内部(下部)に、頂部構成部材102の先端を頂部構成部材101の内部(下部)に、頂部構成部材101の先端を、頂部構成部材104の内部(下部)に順次挿入した状態で、側部構成部材B4の125を左端の側部構成部材B4の121の内側に、側部構成部材A3の115を、左端の側部構成部材A3の111の内側に挿入すると、同時に、頂部構成部材2の101〜104の台形部及び105の長方形が各々頂部構成部材2の101〜104の三角部の内部(下部)に挿入され、組み立てが完成する。
First, as shown in FIGS. 2 and 3, the right end portions 105, 115, and 125 of the unfolded sheet of FIG. 1 are bent inward.
Next, the five top constituent members are bent at a right angle from the second side 11 which is a dotted line portion, and 131 to 134 of the side inner surface constituent member A5 and 141 to 148 of the side inner surface constituent member B are set to the inside. It is bent so as to overlap with 111 to 115 of the side component member A3 and 121 to 125 of the side component member B4.
Further, 115 of the side component member A3 and 125 of the side component member B4 are further folded, and the tip of the top component member 105 is inside (lower part) of the top component member 104, and the tip of the top component member 104 is inside the top component member 103. (The lower part), the tip of the top component member 103 is inside the top component member 102 (the lower part), the tip of the top component member 102 is inside the top part member 101 (the lower part), and the tip of the top component member 101 is the top part In a state of being sequentially inserted into the inside (lower part) of the constituent member 104, the side constituent member B4 125 is placed inside the left end side constituent member B4 121, and the side constituent member A3 115 is placed on the left end side part. When inserted into the inside of the member A3 111, at the same time, the trapezoidal portions 101 to 104 of the top constituting member 2 and the rectangle 105 are respectively placed inside (lower portions) of the triangular portions 101 to 104 of the top constituting member 2. Is input, the assembly is completed.

本発明のスツールでは、5つの側部構成部材A3と5つの側部構成部材B4、4つの側部内面構成部材A5、8つの側部内面構成部材B6がスツール頂部にかかる荷重を支える構造となっている。しかも、側部内面構成部材A5、B6は、頂部四角形(正方形)の2つの対角線上で荷重を支える構造であるために、体重による頂部正方形内の歪みは最小に抑えられるようになっている。
このため、大人の椅子として充分な強度を有するほか、大人が踏み台として使用することも出来る。
In the stool of the present invention, the five side component members A3, the five side component members B4, the four side inner surface component members A5, and the eight side inner surface component members B6 have a structure that supports the load applied to the top of the stool. ing. In addition, since the side inner surface constituting members A5 and B6 have a structure for supporting a load on two diagonal lines of the top quadrangle (square), distortion in the top square due to the body weight can be suppressed to the minimum.
For this reason, in addition to having sufficient strength as an adult chair, adults can also use it as a stepping board.

本発明のシートの展開図である。It is an expanded view of the sheet | seat of this invention. 本発明の実施例の組み立て手順を示す図である。It is a figure which shows the assembly procedure of the Example of this invention. 本発明の実施例の組み立て手順を示す図である。It is a figure which shows the assembly procedure of the Example of this invention. 各部材の関連を示す図面である。It is drawing which shows the relationship of each member.

符号の説明Explanation of symbols

1 シート展開図
2 頂部構成部材
3 側部構成部材A
4 側部構成部材B
5 側部内面構成部材A
6 側部内面構成部材B
10 頂部構成部材の三角形の第1辺
11 頂部構成部材の三角形の第2辺
12 側部構成部材Aの三角形の第1辺
13 側部構成部材Aの三角形の第2辺
14 側部構成部材Aの三角形の第3辺
15 側部構成部材Bの三角形の第1辺
16 側部構成部材Bの三角形の第2辺
17 側部構成部材Bの三角形の第3辺
18 側部内面構成部材A三角形の第1辺
19 側部内面構成部材A三角形の第2辺
20 側部内面構成部材A三角形の第3辺
21 側部内面構成部材B三角形の第1辺
22 側部内面構成部材B三角形の第2辺
23 側部内面構成部材B三角形の第3辺
101,102,103,104,105 頂部構成部材
111,112,113,114,115 側部構成部材A
121,122,123,124,125 側部構成部材B
131,132,133,134 側部内面構成部材A
141,142,143,144,145,146,147,148 側部内面構成部材B
a 頂部構成部材の三角形の第2辺、側部構成部材Aの三角形の第1辺、側部構成部材Bの三角形の第3辺
b 側部構成部材Aの三角形と、側部構成部材B三角形の高さ
b‘ 側部内面構成部材Aの高さ={h+(a/2)1/2
c =1/2(21/2―1)a
d 頂部構成部材の三角形の高さ
h スツールの高さ
t ダンボール厚
ε ずれ
1 Sheet development view 2 Top component 3 Side component A
4 Side component B
5 Side part inner surface component A
6 Side part inner surface component B
DESCRIPTION OF SYMBOLS 10 1st edge | side of the triangle of a top component member 11 2nd edge | side of the triangle of a vertex component member 12 1st edge | side of the triangle of the side component member 13 2nd triangle edge | side of the side component member 14 14 side component member A The third side 15 of the triangle 15 The first side of the triangle of the side component B 16 The second side of the triangle of the side component B 17 The third side of the triangle of the side component B 18 The side inner surface component A triangle of the side 18 First side 19 side inner surface component A triangle second side 20 side inner surface component A triangle third side 21 side inner surface component B triangle first side 22 side inner surface component B triangle first 2 side 23 side inner surface component B third side of triangle 101, 102, 103, 104, 105 top component 111, 112, 113, 114, 115 side component A
121, 122, 123, 124, 125 Side component member B
131, 132, 133, 134 Side surface inner surface constituting member A
141, 142, 143, 144, 145, 146, 147, 148
a triangle second side of the top component member, first triangle side of the side component member A, third side of the triangle of the side component member B b triangle of the side component member A and triangle of the side component member B B ′ Height of the side surface inner part constituting member A = {h 2 + (a / 2) 2 } 1/2
c = 1/2 (2 1/2 -1) a
d Triangular height of top component h Height of stool t Cardboard thickness ε Deviation

Claims (2)

三角形と台形からなる1枚のシートを折り曲げて組み立てられるスツールであって、  A stool that can be assembled by folding a single sheet of triangles and trapezoids,
前記1枚のシートは、  The one sheet is
三角形と台形を組み合わせた4つの頂部構成部材からなる頂部と、  A top composed of four top components combining a triangle and a trapezoid;
4つの前記頂部構成部材と隣接する4つの2等辺三角形の側部構成部材Aを含む5つの2等辺三角形の側部構成部材A、および5つの前記側部構成部材Aと隣接する4つの2等辺三角形の側部構成部材Bとからなる側部と、  Five isosceles triangular side components A including four isosceles triangular side components A adjacent to the four top components, and four isosceles adjacent to the five side components A A side portion composed of triangular side component members B;
前記4つの側部構成部材Bと隣接する4つの2等辺三角形の側部内面構成部材Aと、4つの側部内面構成部材Aと隣接する三角形をした8つの側部内面構成部材Bとからなる側部内面と、  It consists of four isosceles triangular side inner surface components A adjacent to the four side component members B, and eight side inner surface component members B that are adjacent to the four side inner surface members A. Side inner surface,
から構成され、  Consisting of
前記頂部構成部材は、上底がa−t−d、下底がa−t、高さがa/2−tの台形と、底辺がa、高さがdで、頂点Pから下ろした垂線が底辺と交わる点が底辺の中心よりtだけ底辺の1端にずれた三角形が、台形の斜辺と三角形の短い方の斜辺を結合させた形状であり、  The top component is a trapezoid with an upper base of atd, a lower base of at, a height of a / 2-t, a base of a, a height of d, and a perpendicular drawn from the apex P. A triangle in which the point at which the base crosses the base is shifted from the center of the base by one end of the base by t is a shape in which the hypotenuse of the trapezoid and the hypotenuse of the shorter triangle are combined,
4つの前記頂部構成部材と隣接する4つの側部構成部材Aを含む5つの側部構成部材Aは、4つの側部構成部材Bを交互に挟んで横並びするように配置され、側部構成部材Aの第3辺を側部構成部材Bの第1辺に、側部構成部材Aの第2辺を側部構成部材B4の第2辺に、各々隣接され、  The five side component members A including the four side component members A adjacent to the four top component members are arranged so as to be arranged side by side with the four side component members B alternately interposed therebetween. The third side of A is adjacent to the first side of the side component member B, the second side of the side component member A is adjacent to the second side of the side component member B4, respectively.
前記側部構成部材Bの4つは前記側部構成部材Bの三角形の第1辺、第2辺が前記側部構成部材Aの三角形の第2辺、第3辺と隣接し、前記側部構成部材Bの三角形の第3辺が前記側部内面構成部材Aの三角形の第1辺と隣接し、  Four of the side component members B are the first side of the triangle of the side unit member B, the second side is adjacent to the second side and the third side of the triangle of the side unit member A, and the side unit The third side of the triangle of the component B is adjacent to the first side of the triangle of the side inner surface component A,
前記側部内面構成部材Aの4つは、前記側部内面構成部材Aの三角形の第1辺が前記側部構成部材Bの三角形の第3辺と隣接し、前記側部内面構成部材Aの三角形の第2辺と第3辺は前記側部内面構成部材Bの斜辺と隣接し、4つの前記側部内面構成部材Aの第1辺が1直線上に配列され、  Four of the side inner surface constituting members A are such that the first side of the triangle of the side inner surface constituting member A is adjacent to the third side of the triangle of the side inner constituent member B, and The second side and the third side of the triangle are adjacent to the oblique side of the side inner surface constituting member B, and the first sides of the four side inner surface constituting members A are arranged on one straight line,
前記側部内面構成部材Bの8つの内1つは、その斜辺が1直線上に配列される前記側部内面構成部材Aの1端部の第2辺と隣接し、他の1つは、その斜辺が1直線上に配列される前記側部内面構成部材Aの他端部の第3辺と隣接し、残りの6つは、その内の2つずつが第2辺を隣接させながら1直線上に配列される前記側部内面構成部材Aと斜面を前記側部内面構成部材Aの第2辺と第3辺と隣接させて交互に配列されることを特徴とするスツール。  One of the eight of the side inner surface constituting members B is adjacent to the second side of one end of the side inner surface constituting member A whose oblique sides are arranged on one straight line, and the other one is The oblique sides are adjacent to the third side of the other end portion of the side portion inner surface constituting member A arranged on one straight line, and the remaining six are 1 while two of them are adjacent to the second side. The stool, wherein the side inner surface constituting members A and the slopes arranged on a straight line are alternately arranged adjacent to the second side and the third side of the side inner surface constituting member A.
ここで、aは三角形の底辺で、組み立て後のスツールの頂部及び底部を形成する正方形の1辺に該当し、任意に決定できる数値、tは素材の板厚、dは三角形の高さを示し、a/2−tである。  Here, a is the base of the triangle, corresponds to one side of the square that forms the top and bottom of the assembled stool, and can be arbitrarily determined, t is the thickness of the material, and d is the height of the triangle , A / 2-t.
前記4つの頂部構成部材の三角形Aが頂部表面を形成し、5つの側部構成部材Aの内の4つの三角形の第2辺と第3辺が、5つの側部構成部材Bの内の4つの三角形の第1辺と第2辺と交互に隣接して8つの側部表面を形成し、残り1つの側部構成部材Aが、側部表面の内側に潜入して側部を形成し、The triangle A of the four top components forms the top surface, and the second and third sides of the four triangles of the five side components A are the four of the five side components B. Forming two side surfaces alternately adjacent to the first side and the second side of two triangles, and the remaining one side component member A infiltrates inside the side surface to form a side part;
4つの側部内面構成部材Aが側部内表面を形成し、4つの側部内面構成部材Aの間に挟まれた6つの側部内面構成部材Bと4つの側部内面構成部材Aの両端の2つの側部内面構成部材Bが側部の内側に潜入して側部内面を構成することを特徴とする請求項1記載のスツール。  Four side inner surface constituting members A form side inner surfaces, and six side inner surface constituting members B sandwiched between the four side inner surface constituting members A and at both ends of the four side inner surface constituting members A are arranged. 2. The stool according to claim 1, wherein the two side surface inner surface constituting members B enter inside the side portion to constitute the side surface.
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