JP2701776B2 - Disk unit - Google Patents

Description

DETAILED DESCRIPTION OF THE INVENTION

[0001]

BACKGROUND OF THE INVENTION 1. Field of the Invention The present invention relates to a disk drive,
In particular, the present invention relates to a disk device suitable for recording digital data and data such as digital image / audio / system data on an optical disk, a magneto-optical disk, a phase change disk, and the like.

[0002]

2. Description of the Related Art Conventionally, a disk (optical disk, magneto-optical disk, phase change disk, etc.) device for recording digital data and image / audio data has a CAV as a recording method.
And CLV and MCAV were used. As shown in FIG. 6, the track configuration was recorded only on land tracks or groove tracks.

[0003] CAV is a recording system in which the disk rotation speed is constant. This method has the advantage that high-speed search can be realized because the number of rotations is constant irrespective of the head position, simultaneous reproduction at another position during recording is possible, and the spindle servo is simple. There is a disadvantage that the recording wavelength is determined at the innermost circumference and is not suitable for high-density recording.

[0004] CLV is a recording method in which the linear velocity is constant. This method has the advantage that the recording speed is constant and suitable for high-density recording because the relative speed is constant over the entire surface of the disk, but on the other hand, the disk rotation speed changes depending on the head position, and therefore it is suitable for high-speed search. However, there are drawbacks in that it is impossible to perform simultaneous reproduction at different positions during recording and that the spindle servo is complicated.

[0005] MCAV is a recording system integrating the advantages of CAV and CLV. The number of data to be recorded on one track is increased in proportion to the radius while keeping the disk rotation speed constant.
That is, since the rotation speed is constant, the recording bit rate can be increased in proportion to the radius, and variable clock recording and variable clock reproduction are performed. In this method, the recording wavelength is constant over the entire surface of the disk, and the disk rotation speed is constant, so that high-speed search is possible, simultaneous reproduction at different positions during recording is possible, and the spindle servo is simple. With benefits.

[0006] That is, MCAV is a system capable of simultaneously realizing high-density recording and high functionality.

Japanese Patent Application No. 5-275325 (Japanese Patent Application Laid-Open No. 7-1)
No. 30103) proposes an apparatus for realizing MCAV.

According to this conventional example, a moving image or the like can be continuously recorded by generating a pause track in which the number of rotations of the disk is fixed and one track is returned during recording and recording is stopped, and one track is returned during reproduction by a predetermined algorithm. That is.

Although different from the recording method, there is a method called land / groove recording in which recording is performed using both the land side and the groove side of a disk track. When recording is performed by this method, it is possible to obtain twice the recording density as compared with conventional land recording or groove recording, and there is an advantage that a longer recording time can be realized.

Japanese Patent Application No. 63-329790 (Japanese Unexamined Patent Application Publication No.
No. 177027) discloses a technology relating to land / groove recording.

[0011]

However, in the above conventional example, according to Japanese Patent Application No. 5-275325, land recording or groove recording is possible, but with one head, high recording density by land / groove recording is used as an algorithm. There was an inconvenience that it could not be realized.

Japanese Patent Application No. 63-329790 discloses that recording is performed on each land / groove, but means for continuous recording is not shown. For example, a land track is recorded on a disk. A method is conceivable in which scanning is performed over all tracks and then scanning is performed on all groove tracks. However, continuous recording is not possible with one head because time lag must be absorbed when moving from a land track to a groove track. There was a problem.

[0013]

SUMMARY OF THE INVENTION It is an object of the present invention to improve the disadvantages of the prior art, and particularly to a disk drive capable of high-density recording by land / groove continuous recording when recording on a disk with one head and a constant recording wavelength. Is to provide.

[0014]

Accordingly, in the present invention, there is provided a method for controlling
A track jump means for performing a one-track return jump in a predetermined track jump area each time recording of a track is completed;
Each time the integrated value of the difference between the data amount recorded per track and the data amount input per track becomes equal, a one-track return jump is performed again between the previous track jump area and the next track jump area. And an intermediate track jumping means for increasing the number of recording bits per track in each of the equally divided recording areas in the track direction in proportion to the radius of the disk, and controlling the track jumping means and the intermediate track jumping means to control a land / land track. A control means for continuously storing data in both tracks of the groove is provided. This aims to achieve the above-mentioned object.

[0015]

The control means can realize a constant recording wavelength by increasing the number of recording bits per track in each recording area equally divided in the track direction in proportion to the disk radius.

When the recording for one track is completed, the control means instructs the track jump means to jump back one track. Thus, data can be recorded continuously and alternately between the land track and the groove track.

When the integrated value of the difference between the amount of data input during one-track recording and the amount of data recorded on one track becomes equal to the amount of data input during one-track recording, the control means causes the intermediate track jump means to On the other hand, an instruction is made to perform a one-track return jump again between the previous track jump area and the next track jump area.
This makes it possible to compensate for the difference between the data input speed and the recording speed.

[0018]

DETAILED DESCRIPTION OF THE PREFERRED EMBODIMENTS One embodiment of the present invention will be described below with reference to FIGS.

(I). In the first embodiment, as shown in FIG. 1, a track jump means 1 for performing a one-track return control in a predetermined track jump area every time recording of one track is completed, and an input per track. Each time the integrated value of the difference between the data amount and the data amount recorded per track becomes equal to the data amount input per track, the intermediate value between the previous track jump area and the next track jump area is increased by 1 again. Intermediate track jump means 2 for performing track return control; and track jump means 1 and intermediate track jump means for increasing the number of recording bits per track in each recording area equally divided in the track direction in proportion to the disk radius. And control means 3 for controlling data 2 and continuously storing data on both land / groove tracks.

The track jump means 1 is a means for controlling the positioning of the head of the disk drive, and controls the movement of the head between a land track and a groove track. Here, every time recording of one track is completed, a one-track return jump is performed in a predetermined track jump area.

The intermediate track jump means 2 is a means for absorbing the difference between the data input speed and the recording speed due to the difference in the rotational speed of the disk and the recording density between the inner and outer circumferences.
Here, the difference between the amount of data input per track and the amount of data recorded per track was detected, and this integrated value became equal to the amount of data input per track. When doing track jumps. That is, the intermediate track jump means 2 eliminates the difference between the data input speed and the recording speed in units of a half track.

Next, the operation of the first embodiment will be described. Here, the data recorded on the disc is, for example, image data that has been fixed-length coded in a field, and
The field is 8 blocks (hereinafter, sync block: SB)
Described).

Further, it is assumed that a recording area (hereinafter referred to as a clock block: CBLK) is divided into nine equal parts in the track direction. CBLK0, CBLK1, CBLK2,... From the innermost circumference to the outer circumference.
.., CBLK8.

FIGS. 2 and 3 show recording track formats.
This will be described with reference to FIG. Here, reference numeral 11 indicates a track number, reference numeral 12 indicates a field number, and reference numeral 13 indicates a clock block number.

In the innermost circumference, CBLK0, data of one field per track, that is, data of eight fields in all tracks is recorded.

The CBLK 1 records one field + 1 SB (the first block of the next field) per track, that is, data of nine fields in all tracks.

That is, as shown in FIG. 2 and FIG.
In Kn, data of one field + nSB per track, that is, data of (8 + n) fields is recorded in all tracks.

Similarly, data of two fields per track, that is, data of 16 fields in all tracks, is recorded in the outermost circumference CBLK8.

Next, tracks for land / groove recording will be described with reference to FIG.

As shown in FIG.
Are land tracks, and odd tracks 22 are groove tracks. Reference numeral 23 denotes a track jump area determined for each track, and reference numeral 24 denotes an area located between the track jump area 23 and the track jump area 23 and performing a one-track return jump again.

FIGS. 5 and 6 show track jumps in each track. Reference numeral 31 is a track number, reference numeral 32 is a field number, reference numeral 33 is a clock block number, reference numeral 34 is a jump back one track, and reference numeral 35 is recording stop (do not stop on a medium capable of overwriting).
Is indicated by hatching.

Now, in order to record image data in this disk device, it is assumed that the disk is rotating at a constant angular velocity such that the required time per track is one field (8 SB). That is, one field data is input every time the disk makes one rotation.

(1). First, input data is recorded in CBLK0.

[0034] The control means 3 records the input data of one field on the 0th track (land track). Then, when the recording is completed, the track at the end point becomes the second track (land track), so that the track jump means 1 is instructed to return one track. Then, the next track becomes the first track (groove track).
In this manner, by performing the one-track return jump at the time when the recording is completed, it is possible to record continuously on the land track and the groove track alternately.

[0035] The control means 3 records the input data of the next one field on the first track (groove track). Then, when the recording is completed, the track at the end point becomes the third track (groove track), so that the track jump means 1 is instructed to return one track. Then, the next track becomes the second track (land track).

[0036] The control means 3 continuously performs this operation, and when the recording up to the seventh track is completed, instructs the track jump means 1 to return one track. Then, the next track becomes the eighth track.

(2). Next, the input data is recorded in CBLK1.

[0038] The control means 3 calculates the next one field +1
The SB, that is, 9SB input data is recorded on the eighth track. When the recording is completed, the track at the end point is the tenth track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the ninth track.

[0039] The control means 3 records the next 9 SB of input data on the ninth track. Then, when the recording is completed, the track at the end point is the eleventh track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the tenth track.

[0040] The control means 3 continuously performs this operation, and instructs the track jump means 1 to return one track when the recording up to the fifteenth track is completed. Then, the next track becomes the 16th track.

At this time, the number of SBs (8 SB) input is the integrated value of the difference between the number of SBs (8 SB) input during one rotation of the disk and the number of SBs (9 SB) recorded on the disk.
Has been reached, the control means 3 stops recording on the next track (does not stop on the overwritable medium), and gives the intermediate track jump means 2 an intermediate position between the one-track return position and the one-track return position. At the hit position, one track return is instructed again. Then, the next track becomes the 16th track. At the same time, the control means 3 calculates 8
SB is subtracted (or the integrated value is reset to 0).

That is, since the amount of data to be recorded is larger than the amount of data to be input, the recording operation is stopped once (for one rotation of the disk) to compensate for the lack of recorded data. .

(3). Next, the input data is recorded in CBLK2.

[0044] The control means 3 calculates the following one field + 2
The SB, that is, 10 SB input data is recorded on the 16th track. When the recording is completed, the track at the end point is the eighteenth track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the seventeenth track.

[0045] The control means 3 records the next 10 SB of input data on the 17th track. Then, when the recording is completed, the track at the end point is the nineteenth track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the 18th track.

[0046] The control means 3 performs this operation continuously, and instructs the track jump means 1 to return one track when the recording up to the nineteenth track is completed. Then, the next track becomes the twentieth track.

At this time, an integrated value of the difference between the number of SBs (8 SB) input during one rotation of the disk and the number of SBs (10 SB) recorded on the disk is input to the input SB number (8 SB).
Since the condition (B) has been reached, the control means 3 stops recording on the next track (does not stop on the overwritable medium), and instructs the intermediate track jumping means 2 to return one track and return one track. Again in the middle of
Instructs a track return. Then the next track is 20th
Become a truck. At the same time, the control means 3 subtracts 8 SB from the integrated value (or resets the integrated value to 0).

[0048] The control means 3 records the next 10 SB of input data on the twentieth track. Then, when the recording is completed, the track at the end point is the 22nd track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the 21st track.

[0049] The control means 3 continuously performs this operation, and instructs the track jump means 1 to return one track when the recording up to the 23rd track is completed. Then, the next track becomes the 24th track.

At this time, an integrated value of the difference between the number of SBs (8 SB) input during one rotation of the disk and the number of SBs (10 SB) recorded on the disk is input to the input SB number (8S).
Since the condition (B) has been reached, the control means 3 stops recording on the next track (does not stop on the overwritable medium), and instructs the intermediate track jumping means 2 to return one track and return one track. Again in the middle of
Instructs a track return. Then the next track is 24th
Become a truck. At the same time, the control means 3 subtracts 8 SB from the integrated value (or resets the integrated value to 0).

(4). Similarly, CBLK3 to CBLK3 to C
The input data is recorded on BLK7.

(5). Finally, the input data is recorded in CBLK8.

[0053] The control means 3 records the input data of the next two fields on the 64th track. Then, when the recording is completed, the track at the end point is the 66th track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the 65th track.

At this time, an integrated value of the difference between the number of SBs (8SB) input during one rotation of the disk and the number of SBs (16SB) recorded on the disk is input to the number of SBs (8S) input.
Since the condition (B) has been reached, the control means 3 stops recording on the next track (does not stop on the overwritable medium), and instructs the intermediate track jumping means 2 to return one track and return one track. Again in the middle of
Instructs a track return. Then the next track is 65
Become a truck. At the same time, the control means 3 subtracts 8 SB from the integrated value (or resets the integrated value to 0).

[0055] The control means 3 records the input data of the next two fields on the 65th track. Then, when the recording is completed, the track at the end point is the 67th track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the 66th track.

At this time, an integrated value of the difference between the number of SBs (8 SB) input during one rotation of the disk and the number of SBs (16 SB) recorded on the disk is input to the input SB number (8 SB).
Since the condition (B) has been reached, the control means 3 stops recording on the next track (does not stop on the overwritable medium), and instructs the intermediate track jumping means 2 to return one track and return one track. Again in the middle of
Instructs a track return. Then the next track is the 67th
Become a truck. At the same time, the control means 3 subtracts 8 SB from the integrated value (or resets the integrated value to 0).

[0057] In the same manner, the control means 3 sets the sixth
Input data is recorded on tracks 7 to 71.

(II). Next, a second embodiment will be described.

In the second embodiment, as shown in FIG.
In the intermediate track jumping means 2 in the first embodiment,
FIF that temporarily stores input data and performs first-in first-out
An O memory 4 and a memory monitoring means 5 for performing a one-track return jump again between the previous track jump area and the next track jump area every time the data amount stored in the FIFO memory 4 falls below a certain value. It is provided.

It is assumed that image data is input to this disk device, and the disk is rotating at a constant angular velocity that makes the required time per track one field (8 SB). That is, each time the disk makes one revolution,
Field data is input to the FIFO memory 4.

The FIFO memory 4 already has 16
When the SB data is written, and when the SB data becomes 8 SB or less, the jump back by one track is performed again in the middle of the track jump area.

(1). First, input data is recorded in CBLK0.

[0063] The control means 3 reads the input data of one field from the FIFO memory 4 and records it on the 0th track. When the recording ends, the track at the end point becomes the second track.
To return one track. Then, the next track becomes the first track.

[0064] The control means 3 reads the input data of the next one field from the FIFO memory 4 and records it on the first track. When the recording is completed, the track at the end point is the third track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the second track.

[0065] The control means 3 performs this operation continuously, and instructs the track jump means 1 to return one track when the recording up to the seventh track is completed. Then, the next track becomes the eighth track.

(2). Next, the input data is recorded in CBLK1.

. The control means 3 calculates the next one field +1
The input data of SB, ie, 9SB, is read from the FIFO memory 4 and recorded on the eighth track. When the recording is completed, the track at the end point is the tenth track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the ninth track.

[0068] The control means 3 reads the next 9 SB of input data from the FIFO memory 4 and records it on the ninth track. When the recording is completed, the track at the time of the end is the eleventh track.
To return one track. Then, the next track becomes the tenth track.

[0069] The control means 3 continuously performs this operation, and instructs the track jump means 1 to return one track when the recording up to the fifteenth track is completed. Then, the next track becomes the 16th track.

At this time, the difference between the number of SBs (8 SB) written to the FIFO memory 4 and the number of SBs read from the FIFO memory (9 SB) indicates that the number of SBs stored in the FIFO memory 4 is 8 SB. , The memory monitoring means 5 notifies the control means 3.

Then, the control means 3 stops recording on the next track (does not stop on the overwritable medium),
It instructs the intermediate track jumping means 2 to return to the next track again at the intermediate position between the one-track return position and the one-track return position. As a result, the next 8 SB data is written to the FIFO memory 4, and the number of SBs stored in the FIFO memory 4 returns to 16 SB.

At the same time, the next track becomes the 16th track.

(3). Next, the input data is recorded in CBLK2.

[0074] The control means 3 calculates the following one field + 2
The input data of SB, that is, 10 SB is stored in the FIFO memory 4
And recorded on the 16th track. When the recording is completed, the track at the end point is the eighteenth track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the seventeenth track.

[0075] The control means 3 reads the next 10 SB of input data from the FIFO memory 4 and records it on the 17th track. Then, when the recording is completed, the track at the end point is the nineteenth track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the 18th track.

. The control means 3 performs this operation continuously, and instructs the track jump means 1 to return one track when the recording up to the nineteenth track is completed. Then, the next track becomes the twentieth track.

At this time, the difference between the number of SBs (8 SB) written to the FIFO memory 4 and the number of SBs (10 SB) read from the FIFO memory indicates that the number of SBs stored in the FIFO memory 4 is 8 SB. , The memory monitoring means 5 notifies the control means 3.

Then, the control means 3 stops the recording on the next track (does not stop on the overwritable medium),
It instructs the intermediate track jumping means 2 to return to the next track again at the intermediate position between the one-track return position and the one-track return position. As a result, the next 8 SB data is written to the FIFO memory 4, and the number of SBs stored in the FIFO memory 4 returns to 16 SB.

At the same time, the next track becomes the twentieth track.

[0080] The control means 3 reads the next 10 SB of input data from the FIFO memory 4 and records it on the twentieth track. Then, when the recording is completed, the track at the end point is the 22nd track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the 21st track.

[0081] The control means 3 continuously performs this operation, and instructs the track jump means 1 to return one track when the recording up to the 23rd track is completed. Then, the next track becomes the 24th track.

At this time, the difference between the number of SBs (8 SB) written to the FIFO memory 4 and the number of SBs (10 SB) read from the FIFO memory indicates that the number of SBs stored in the FIFO memory 4 is 8 SB. , The memory monitoring means 5 notifies the control means 3.

Then, the control means 3 stops recording on the next track (does not stop on a medium capable of overwriting),
It instructs the intermediate track jumping means 2 to return to the next track again at the intermediate position between the one-track return position and the one-track return position. As a result, the next 8 SB data is written to the FIFO memory 4, and the number of SBs stored in the FIFO memory 4 returns to 16 SB.

At the same time, the next track is the 24th track.

(4). Similarly, CBLK3 to CBLK3 to C
The input data is recorded on BLK7.

(5). Finally, the input data is recorded in CBLK8.

[0087] The control means 3 reads the next two fields of input data from the FIFO memory 4 and records them on the 64th track. Then, when the recording is completed, the track at the end point is the 66th track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the 65th track.

At this time, the difference between the number of SBs (8 SB) written to the FIFO memory 4 and the number of SBs (16 SB) read from the FIFO memory indicates that the number of SBs stored in the FIFO memory 4 is 8 SB. , The memory monitoring means 5 notifies the control means 3.

Then, the control means 3 stops the recording on the next track (does not stop on the overwritable medium),
It instructs the intermediate track jumping means 2 to return to the next track again at the intermediate position between the one-track return position and the one-track return position. As a result, the next 8 SB data is written to the FIFO memory 4, and the number of SBs stored in the FIFO memory 4 returns to 16 SB.

At the same time, the next track is the 65th track.

[0091] The control means 3 reads the input data of the next two fields from the FIFO memory 4 and records it on the 65th track. Then, when the recording is completed, the track at the end point is the 67th track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the 66th track.

At this time, the difference between the number of SBs (8 SB) written to the FIFO memory 4 and the number of SBs (16 SB) read from the FIFO memory indicates that the number of SBs stored in the FIFO memory 4 is 8 SB. , The memory monitoring means 5 notifies the control means 3.

Then, the control means 3 stops the recording on the next track (does not stop on the overwritable medium),
It instructs the intermediate track jumping means 2 to return to the next track again at the intermediate position between the one-track return position and the one-track return position. As a result, the next 8 SB data is written to the FIFO memory 4, and the number of SBs stored in the FIFO memory 4 returns to 16 SB.

At the same time, the next track is the 66th track.

[0095] In the same manner, the control means 3 sets the sixth
Input data is recorded on tracks 7 to 71.

The operation when the number of rotations of the disk is large will be described. .

Here, it is assumed that the disk is rotating at a constant angular velocity that makes the required time per track 7 SB. It is assumed that one field data is input to the FIFO memory 4 every time the disk makes one rotation.

(1). First, input data is recorded in CBLK0.

[0099] The control means 3 reads the input data of one field from the FIFO memory 4 and records it on the 0th track. When the recording ends, the track at the end point becomes the second track.
To return one track. Then, the next track becomes the first track.

[0100] The control means 3 reads the input data of the next one field from the FIFO memory 4 and records it on the first track. When the recording is completed, the track at the end point is the third track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the second track.

. The control means 3 performs this operation continuously, and instructs the track jump means 1 to return one track when the recording up to the seventh track is completed. Then, the next track becomes the eighth track.

However, since the disc is rotating at 7/8 fields, only seven fields have elapsed at this point. That is, the data stored in the FIFO memory 4 decreases by one field (8 SB),
Since it is SB, the memory monitoring unit 5 notifies the control unit 3.

Then, the control means 3 stops the recording on the next track (does not stop on the overwritable medium),
It instructs the intermediate track jumping means 2 to return to the next track again at the intermediate position between the one-track return position and the one-track return position. As a result, the next 8 SB data is written to the FIFO memory 4, and the number of SBs stored in the FIFO memory 4 returns to 16 SB.

At the same time, the next track becomes the eighth track.

Although the recording bit wavelength becomes larger than the original value due to the high rotation speed, the measure is taken by reducing the track jump area by that much.

(2). Similarly, normal recording is possible for CBLK1 to CBLK8 by the track jump.

Next, the disc rotates at an angular velocity in the 0th area where the required time per track is one field time, and in the first area the required time per track is 1 field + 1SB ( 9 SB), and in the n-th region, the required time per track is 1 field + nSB (8 + nS).
B) A case in which the rotation is performed at an angular velocity that is the time of minutes will be described. That is, a case where the rotation speed of the disk is variable will be described.

(1). First, input data is recorded in CBLK0. Here, one field data is input to the FIFO memory 4 per one rotation of the disk.

[0109] The control means 3 reads the input data of one field from the FIFO memory 4 and records it on the 0th track. When the recording ends, the track at the end point becomes the second track.
To return one track. Then, the next track becomes the first track.

[0110] The control means 3 reads the input data of the next one field from the FIFO memory 4 and records it on the first track. When the recording is completed, the track at the end point is the third track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the second track.

[0111] The control means 3 performs this operation continuously, and instructs the track jump means 1 to return one track when the recording up to the seventh track is completed. Then, the next track becomes the eighth track.

(2). Next, the input data is recorded in CBLK1. Here, data of 1 field + 1 SB, that is, 9 SB, is input to the FIFO memory 4 per one rotation of the disk.

[0113] The control means 3 calculates the next one field +1
The input data of SB, ie, 9SB, is read from the FIFO memory 4 and recorded on the eighth track. When the recording is completed, the track at the end point is the tenth track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the ninth track.

[0114] The control means 3 reads the next 9 SB of input data from the FIFO memory 4 and records it on the ninth track. When the recording is completed, the track at the time of the end is the eleventh track.
To return one track. Then, the next track becomes the tenth track.

. The control means 3 continuously performs this operation, and instructs the track jump means 1 to return one track when the recording up to the fifteenth track is completed. Then, the next track becomes the 16th track.

(3). Next, the input data is recorded in CBLK2. Here, the data of one field + 2 SB, that is, 10 SB per rotation of the disk is stored in the FIFO memory 4.
Is input to

[0117] The control means 3 calculates the following one field + 2
The input data of SB, that is, 10 SB is stored in the FIFO memory 4
And recorded on the 16th track. When the recording is completed, the track at the end point is the eighteenth track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the seventeenth track.

[0118] The control means 3 reads the next 10 SB of input data from the FIFO memory 4 and records it on the 17th track. Then, when the recording is completed, the track at the end point is the nineteenth track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the 18th track.

[0119] The control means 3 continuously performs this operation, and instructs the track jump means 1 to return one track when the recording up to the 23rd track is completed. Then, the next track becomes the 24th track.

(4). Similarly, CBLK3 to CBLK3 to C
The input data is recorded on BLK7.

(5). Finally, the input data is recorded in CBLK8. Here, two fields of data are input to the FIFO memory 4 for each rotation of the disk.

. The control means 3 reads the next two fields of input data from the FIFO memory 4 and records them on the 64th track. Then, when the recording is completed, the track at the end point is the 66th track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the 65th track.

[0123] The control means 3 reads the input data of the next two fields from the FIFO memory 4 and records it on the 65th track. Then, when the recording is completed, the track at the end point is the 67th track, so that the track jump means 1 is instructed to return one track. Then, the next track becomes the 66th track.

. In the same manner, the control means 3 sets the sixth
Input data is recorded on tracks 7 to 71.

In this embodiment, one field is recorded per track at the innermost circumference. However, the same processing can be performed even if the value is not divisible by a field such as 7SB.

In the above description, when the rotation speed is variable, the rotation speed is changed for each clock block. However, the same processing can be performed by changing the rotation speed in more or less steps.

[0127]

Since the present invention is constructed and functions as described above, according to this, the track jump means performs the track jump when the recording of one track is completed, so that the track jump means is continuously connected to both the land and groove tracks. In addition, the intermediate track jumping means determines that the integrated value of the difference between the data amount recorded on one track and the input data amount is equal to the data amount input during one track recording. At this time, since the track jump is performed, the difference between the data input speed and the recording speed can be compensated. For this reason, it is possible to provide an unprecedented excellent disk device that enables high-density recording and high-speed search with one head without being affected by the rotational speed of the disk.

[Brief description of the drawings]

FIG. 1 is a configuration diagram showing a first embodiment of the present invention.

FIG. 2 is an explanatory diagram showing a former stage of a recording track format.

FIG. 3 is an explanatory diagram showing a latter stage of a recording track format.

FIG. 4 is an explanatory diagram for explaining tracks for land / groove recording.

FIG. 5 is an explanatory diagram showing a preceding stage of a track jump in each track.

FIG. 6 is an explanatory diagram showing a subsequent stage of a track jump in each track.

FIG. 7 is a configuration diagram showing a second embodiment of the present invention.

FIG. 8 is an explanatory diagram for explaining a track according to a conventional recording method.

[Explanation of symbols]

Reference Signs List 1 track jump means 2 intermediate track jump means 3 control means 4 FIFO memory 5 memory monitoring means 11 track number 12 field number 13 clock block number 21 land track 22 groove track 23 track jump area determined for each track 24 track jump area The area where the one-track return jump is performed again between the track jump area and the track jump area 31 Track number 32 Field number 33 Clock block number 34 1-track return jump position 35 Recording stop position (does not stop on overwritable media)

Claims (5)

(57) [Claims] 1. A disk device having control means for increasing the number of recording bits per track in each recording area equally divided in a track direction in proportion to a disk radius and storing the same, wherein: Track jump means for performing one-track return control in a predetermined track jump area each time recording of a track is completed, and integration of the difference between the amount of data input per track and the amount of data recorded per track Intermediate track jump means for performing one-track return control again between the previous track jump area and the next track jump area each time the value becomes equal to the amount of data input per track. Disk device. 2. An intermediate memory according to claim 1, wherein said intermediate track jump means temporarily stores input data and performs FIFO on a first-in first-out basis, and each time an amount of data stored in said FIFO memory falls below a predetermined value, a preceding track jump area is stored. 2. The disk drive according to claim 1, further comprising a memory monitoring means for performing one-track return control again in the middle of a next track jump area. 3. The recording apparatus according to claim 1, wherein the control unit has a function of controlling a recording timing by shortening a predetermined track jump area when the angular velocity of the track is higher than a predetermined value. The disk device as described above. 4. The disk device according to claim 1, wherein said control means has an angular velocity adjusting function for changing an angular velocity for each track. 5. A disk drive having control means for increasing the number of recording bits per track in each recording area equally divided in a track direction in proportion to a disk radius and storing the same, wherein: A track jump means for performing one-track return control in a predetermined track jump area each time recording of a track is completed, so that the amount of data input per track is equal to the amount of data recorded per track. A disk device having an angular velocity adjusting function of changing the angular velocity of each track and keeping the recording clock frequency constant for all tracks.