JP2014027788A - Neutron - Google Patents

Abstract

PROBLEM TO BE SOLVED: To determine whether the state of neutrons is E=mcor E=mc×A, in atoms or elements.SOLUTION: The neutron can exist only in the energy of a field of nuclear fusion. Energy of the neutron is A=3873. A proton revolves in a revolving orbit of A=1836, and the neutron revolves in a revolving orbit of A=3873. The revolving orbit of the neutron is the revolving orbit of an electron÷3873=1.05836×10m÷3873=2.733×10m. Energy is 8.665×10Jm÷(2.733×10m)=3.1705×10J. Since the rest mass of the neutron is 1.67495×10Kg, it is E=mc=1.67495×10×9×10=1.50745×10J. It is defined that the energy of the neutron÷mc=3.1705×10J÷(1.50745×10J)=2.1. It is defined that E of the neutron=3.1705×10J=mc×2.1, and it is not E=mc. It is E=mc×A.

Description

The present invention relates to neutrons. Specifically, how are neutrons in atoms? How are neutrons made up of elements? Is E = mc ² correct? Mass = 9.628 × 10 ^-41 Kgm ÷ Is the orbital formula correct? This is considered from the energy and mass of neutrons. How does electromagnetism look when accelerated to light speed?

Proton's mass energy is 938.272 MeV. The mass energy of neutron is 939.56535 MeV. The mass energy of electrons is 0.5109989 MeV.
E = mc ² . In the Japanese Patent Application 2012-109671 filed on May 11, 2012, I thought that E = mc ² × A in the high energy field.
And, in Japanese Patent Application No. 2012-150959 filed on July 5, 2012, E = 8.665 × 10 ⁻²⁴ Jm ÷ orbital, and E = mc ² formula, mass = 9.628 × 10 ⁻⁴¹ Kgm ÷ orbital, It was.
In Japanese Patent Application No. 2012-160064 filed on July 19, 2012, in Table 1, the energy of a magnetic photon of one Higgs particle is 2.0075 × 10 ⁻⁸ J ÷ (4.34 × 10 ⁴ ), and orbit = 6.1420 × 10 ^-34 m × 3.14 ÷ (4.34 × 10 ⁴ ).

Japanese Patent Application 2006-357550 Japanese Patent Application 2012-109671 Japanese Patent Application 2012-150959 Japanese Patent Application 2012-160064

1. Which orbit is the neutron revolving around in the atom?
2. The mass energy of neutron is 939.56535 MeV. Proton's mass energy is 938.272 MeV. What is the trajectory?
3. The orbital energy = 8.665 x 10 ^-24 Jm, the orbit of revolution is calculated as follows: Neutron revolution orbit = 5.756138 x 10 ^-14 m ≒ Proton orbit = 5.640407 x 10 ^-14 m. The irrationality of this thing.
4). How do neutrons and protons rotate in the elements?
5. The orbit of the neutron lab is 2.733 × 10 ^-14 m. In this case, what is the energy of neutrons?
6). The neutron rest mass is 1.67495 × 10 ^-27 Kg. The energy of neutron 3.1705 × 10 ^-10 J is E = mc ² = 1.507455 × 10 ^-10 J. What does this mean?
7. In Japanese Patent Application No. 2012-150959 filed on July 5, 2012, E = 8.665 × 10 ⁻²⁴ Jm ÷ orbital and E = mc ² formula, mass = 9.628 × 10 ⁻⁴¹ Kgm ÷ orbital, It was. This formula is incorrect. E = mc ² × A.
8). What is the phenomenon when neutrons decay?
9. How does electromagnetism look when accelerated to light speed?
10. What kind of particles are considered Higgs particles?

Neutrons can exist for the first time in the energy of a fusion field. The energy of neutron is A = 3873. Proton revolves around the orbit of A = 1836, and neutron revolves around the orbit of A = 3873. The orbit of neutron is orbit of electron ÷ 3873 = 1.5836 × 10 ⁻¹⁰ m ÷ 3873 = 2.733 × 10 ⁻¹⁴ m. The energy is 8.665 × 10 ⁻²⁴ Jm ÷ (2.733 × 10 ⁻¹⁴ m) = 3.1705 × 10 ⁻¹⁰ J. Since the neutron static mass is 1.67495 × 10 ⁻²⁷ Kg, E = mc ² = 1.67495 × 10 ⁻²⁷ × 9 × 10 ¹⁶ = 1.50745 × 10 ⁻¹⁰ J. Neutron energy ÷ mc ² = 3.1705 × 10 ⁻¹⁰ J ÷ (1.50745 × 10 ⁻¹⁰ J) = 2.1.
Neutron E = 3.1705 × 10 ⁻¹⁰ J = mc ² × 2.1, not E = mc ² E = mc ² × A.

I understood the following.
1． Among the atoms, the electron lab exists in the A = 1 orbit, the proton lab exists in the A = 1836 orbit, and the neutron lab exists in the A = 3873 orbit.
Within the atom, the electron lab revolves around 1.05836 × 10 ^-10 m, the proton lab revolves around 5.564 × 10 ^-14 m, and the neutron lab revolves around 2.733 × 10 ^-14 m. Revolve.
2． Orbit of the neutron lab = 8.665 × 10 ⁻²⁴ Jm ÷ (1.5053495 × 10 ⁻¹⁰ J) = 5.756138 × 10 ⁻¹⁴ m.
Proton's love orbit = 8.665 × 10 ⁻²⁴ Jm ÷ (1.5032773 × 10 ⁻¹⁰ J) = 5.76407 × 10 ⁻¹⁴ m.
3． The direction of proton rotation and the direction of neutron rotation are opposite. Nevertheless, the same trajectory cannot be rotated in the opposite direction.
Thus, the proton lab revolves around 5.564 × 10 ^-14 m, and the neutron lab revolves around 2.733 × 10 ^-14 m.
Four. Many neutron labs in the element revolve around 2.733 × 10 ^-14 m orbit. Rotate in the negative direction.
Many proton labs in the element revolve around orbits of 5.564 × 10 ^-14 m. Rotate in the plus direction.
Five. The orbit of the neutron lab is 2.733 × 10 ^-14 m. The energy of neutron is 3.1705 × 10 ^-10 J.
6． Neutron energy 3.1705 × 10 ⁻¹⁰ J is 2.1032 times E = mc ² = 1.507455 × 10 ⁻¹⁰ J.
Also on the earth's surface, it shows that E = mc ² × A ÷ A of the proton's revolution orbit in the revolution orbit above the proton energy.
7． As considered in Japanese Patent Application No. 2012-109671, E = mc ² × A in a high energy field.
In a high energy field, the energy increases, but the mass does not change.
8． The neutron decayed and released the rotating electromagnetics around the proton, electron and neutron lab.
9． The energy of one magnetic photon produced by a proton lab by one rotation is 4.435 × 10 ⁻¹⁶ J, so 4.34 × 10 ⁴ magnetic photons are attracted to form one magnetic photon.
10. The energy of one electric photon = the energy of one magnetic photon.

In Fig. 1, the electron lab is revolving while revolving along the orbit of A = 1 = 1.05836 × 10 ⁻¹⁰ m. The proton's lab is revolving while rotating on the orbit of A = 1836 = 1.05836 × 10 ⁻¹⁰ m ÷ 1836 = 5.76407 × 10 ⁻¹⁴ m. The neutron lab revolves while rotating on the orbit of A = 3873 = 1.05836 × 10 ⁻¹⁰ m ÷ 3873 = 2.733 × 10 ⁻¹⁴ m. Figure 2 shows that many neutron labs in the element revolve around an orbit of 2.733 × 10 ^-14 m. Rotate in the negative direction. Many proton labs in the element revolve around orbits of 5.564 × 10 ^-14 m. Rotate in the plus direction. Figure 3 shows that the orbit of neutron is 2.733 × 10 ⁻¹⁴ m. The energy of the neutron is 8.665 × 10 ⁻²⁴ Jm ÷ (2.733 × 10 ⁻¹⁴ m) = 3.1705 × 10 ⁻¹⁰ J. The neutron rest mass is 1.67495 × 10 ⁻²⁷ Kg. E = mc ² = 1.67495 × 10 ⁻²⁷ Kg × 9 × 10 ¹⁶ = 1.507455 × 10 ⁻¹⁰ J. 3.1705 × 10 ⁻¹⁰ J ÷ (1.507455 × 10 ⁻¹⁰ J) = 2.1032. Therefore, neutron energy = 3.1705 × 10 ⁻¹⁰ J = mc ² × 2.1. This is not E = mc ² . E = mc ² × A.

８． 中性子が崩壊するときの現象はどのようであるか。
中性子が崩壊するとき、中性子の中に存在していた物が放出する。
中性子の中に存在していた物は、中性子のラブ(陽子のラブに電子のラブが付着した物)と中性子のラブが作った電磁気です。
中性子のエネルギー＝陽子のエネルギー＋電子のエネルギー＋電磁気のエネルギー
電磁気のエネルギー＝中性子のエネルギー−(陽子のエネルギー＋電子のエネルギー)＝939.56535MeV−(938.27201MeV＋0.51099MeV)＝939.56535MeV−938.783MeV＝0.78235MeV
電磁気のエネルギーは0.78235MeVです。
中性子のラブの公転軌道は、2.733×10^-14mです。
この軌道の電気の光子1個のエネルギーは、電気の光子の軌道エネルギー÷電気の光子の軌道＝1.233×10⁻⁴¹Jm÷(2.733×10^-14m)＝4.5115×10⁻²⁸J、です。
電気の光子の数は、電磁気のエネルギー÷電気の光子1個のエネルギー＝0.78235MeV÷(4.5115×10⁻²⁸J)＝0.78235×10⁶×1.6021765×10^-19J÷(4.5115×10⁻²⁸J)＝2.778×10¹⁴(個)
電気の光子の数は2.778×10¹⁴個です。この個数は。中性子のラブが1秒間に作る電気の光子の数にほぼ等しいです。
中性子(陽子)のラブが1秒間に作る電気の光子の数＝7.96×10⁷×4.34×10⁴＝3.455×10¹²、個です。
そして、陽子のラブは1秒間に作った電磁気を自分の周囲に回転させています。(この事については、2006年12月30日に提出した、特願2006−357550に記した)
よって、中性子は崩壊し、陽子と電子と中性子のラブの周囲に回転していた電磁気を放出した。
この事を表に示す。
表2

９． 光速に加速した場合、電磁気はどのようであるか。
2012年7月19日に提出した、特願2012-160064では、表1において、ヒッグス粒子1個の磁気の光子のエネルギーを2.0075×10^-8J÷(4.34×10⁴個)とし、軌道＝6.1420×10^-34m×3.14÷(4.34×10⁴個)と記した。
私は、特願2012-160064の「請求項18」で次のように記した。
・光速に加速された陽子のラブが1公転で作る電気の光子1個の軌道は6.404×10^-31mで、エネルギーは1.925×10^-11Jです。
・光速に加速された陽子のラブが1公転で作る磁気の光子4.34×10⁴個の軌道は6.404×10^-31mで、エネルギーは1.925×10^-11Jです。
光速に加速された陽子のラブが1自転で作る磁気の光子1個の軌道は4.633×10^-35mで、エネルギーは、電気の光子エネルギー÷1公転の磁気の光子の数＝1.925×10^-11J
J÷(4.34×10⁴)＝4.435×10^-１６J、です。
・光速に加速された陽子のラブが1自転で作る磁気の光子1個の軌道は4.633×10^-35mで、エネルギーは4.435×10^-１６Jです。
しかし、この場では、1公転でできる磁気の光子は、4.34×10⁴個が集合し、1個の磁気の光子に成っている。
光速に加速された陽子のラブが1自転で作る磁気の光子1個の軌道は4.633×10^-35mで、エネルギーは、電気の光子エネルギー÷1公転の磁気の光子の数＝1.925×10^-11J
J÷(4.34×10⁴)＝4.435×10^-１６J、です。
陽子のラブが1自転で作る磁気の光子1個のエネルギーは4.435×10^-１６J、ですから、4.34×10⁴個の磁気の光子は引き合い、1つの磁気の光子に成っている。
即ち、1公転でできる磁気の光子は、4.34×10⁴個が集合し、1個の磁気の光子に成っている。
よって、光速に加速された陽子のラブが1公転で作る磁気の光子１個の軌道は6.404×10^-31mで、エネルギーは1.925×10^-11Jです。
光速に加速された陽子のラブが1公転で作る電気の光子1個と磁気の光子1個の軌道は6.404×10^-31mで、エネルギーは1.925×10^-11Jです。
この事を表に示す。
表3

１０． ヒッグス粒子と見なされた粒子はどのような粒子か。
ヒッグス粒子と見なされた粒子は陽子の130倍の質量であるといいます。これは、9×10¹⁶倍のエネルギーにされた陽子のラブが作る電磁気です。その電磁気は、1公転で、4.34×10⁴回の自転で作られた磁気の光子は1つにまとまった。1個の電気の光子のエネルギー＝1個の磁気の光子のエネルギー、に成っています。
次の表のようになっています。
表4

1. Which orbit is the neutron revolving around in the atom?
Neutrons are generated in the middle of the sun at a field of 1.5 × 10 ⁷ ° C. Neutrons can only exist in a field of 1.5 × 10 ⁷ ° C.
Therefore, the field where neutrons exist in the atom is also the field of A = (1.5 × 10 ⁷ ℃) ^1/2 = 3873.
The energy of the proton is 1836 times the energy of the electron. A = 1836.
The orbit of the proton lab is the orbit of the electron lab ÷ 1836 = Bohr radius x 2 ÷ 1836 = 5.2918 x 10 ^-11 m x 2 ÷ 1836 = 1.05836 x 10 ^-10 m ÷ 1836 = 5.564 x 10 ^-14 m ,is.
The orbit of the neutron lab (proton lab attached to the electron lab) is the orbit of the electron lab ÷ 3873 = 1.5836 × 10 ^-10 m ÷ 3873 = 2.733 × 10 ^-14 m.
That is, in the atom, the electron lab exists in the A = 1 orbit, the proton lab exists in the A = 1836 orbit, and the neutron lab exists in the A = 3873 orbit.
That is, in the atom, the electron lab revolves around 1.05836 × 10 ^-10 m, the proton lab revolves around 5.564 × 10 ^-14 m, and the neutron lab revolves 2.733 × 10 ^-14 m. Revolve the orbit.
A = 3873 is 3873 ÷ 1836 = 2.1095, twice that of A = 1836. Therefore, the orbit of neutrons is 2.1095 times that of protons.
2. The mass energy of neutron is 939.56535 MeV. Proton's mass energy is 938.272 MeV. What is the trajectory?
Neutron energy = 939.56535 × 10 ⁶ × 1.6021765 × 10 ⁻¹⁹ J = 1.5053495 × 10 ⁻¹⁰ J.
Orbit of the neutron lab = 8.665 × 10 ⁻²⁴ Jm ÷ (1.5053495 × 10 ⁻¹⁰ J) = 5.756138 × 10 ⁻¹⁴ m.
The orbital energy of the lab is calculated as: 8.665 × 10 ⁻²⁴ Jm, and the orbit of the neutron lab is 5.756138 × 10 ⁻¹⁴ m.
Proton energy = 938.272 × 10 ⁶ × 1.6021765 × 10 ^-19 J = 1.5032773 × 10 ^-10 J.
Proton's love orbit = 8.665 × 10 ⁻²⁴ Jm ÷ (1.5032773 × 10 ⁻¹⁰ J) = 5.76407 × 10 ⁻¹⁴ m.
The orbit of the proton love is 5.76407 × 10 ^-14 m.
3. The orbital energy = 8.665 x 10 ^-24 Jm, the orbit of revolution is calculated as follows: Neutron revolution orbit = 5.756138 x 10 ^-14 m ≒ Proton orbit = 5.640407 x 10 ^-14 m. The irrationality of this thing.
The direction of proton rotation and the direction of neutron rotation are opposite. Nevertheless, the same trajectory cannot be rotated in the opposite direction.
Proton's orbit and neutron's orbit are not the same.
Thus, the proton lab revolves around 5.564 × 10 ^-14 m, and the neutron lab revolves around 2.733 × 10 ^-14 m.
4). How do neutrons and protons rotate in the elements?
Among the elements, the neutron love orbit revolves around 2.733 × 10 ^-14 m. Many neutron labs in the element revolve around 2.733 × 10 ^-14 m orbit. Rotate in the negative direction.
Among the elements, the proton love revolves around an orbit of 5.564 × 10 ^-14 m. Many proton labs in the element revolve around orbits of 5.564 × 10 ^-14 m. Rotate in the plus direction.
However, the neutron energy and proton energy in the element are slightly different, so they appear in orbit.
5. The orbit of the neutron lab is 2.733 × 10 ^-14 m. In this case, what is the energy of neutrons?
Neutron energy = 8.665 × 10 ⁻²⁴ Jm ÷ (2.733 × 10 ⁻¹⁴ m) = 3.1705 × 10 ⁻¹⁰ J.
3.1705 × 10 ^-10 J ÷ (10 ⁶ × 1.6021765 × 10 ^-19 J) ＝ 1.97887 × 10 ³ MeV
The energy of neutron is 3.1705 × 10 ^-10 J = 1978.87MeV.
6). The neutron rest mass is 1.67495 × 10 ^-27 Kg. The energy of neutron 3.1705 × 10 ^-10 J is E = mc ² = 1.507455 × 10 ^-10 J. What does this mean?
The mass energy of neutron is E = mc ² = 1.67495 × 10 ⁻²⁷ Kg × 9 × 10 ¹⁶ = 1.507455 × 10 ⁻¹⁰ J.
The orbit of neutron is 2.733 × 10 ^-14 m and the energy is 3.1705 × 10 ^-10 J.
・ The energy of neutron 3.1705 × 10 ⁻¹⁰ J is E = mc ² = 1.507455 × 10 ⁻¹⁰ J.
3.1705 × 10 ⁻¹⁰ J ÷ (1.507455 × 10 ⁻¹⁰ J) = 2.1032.
Neutron energy 3.1705 × 10 ⁻¹⁰ J is 2.1032 times E = mc ² = 1.507455 × 10 ⁻¹⁰ J.
This is because the neutron field orbit A is 3873 ÷ 1836 = 2.109 times the proton orbit A.
That is, neutron energy = mc ² × neutron revolution orbit A ÷ proton revolution orbit A.
・ What does this mean?
In the Japanese Patent Application 2012-109671 filed on May 11, 2012, I thought that E = mc ² × A in the high energy field.
When the energy on the surface of the earth was 1 ° C and the energy at the site was A times the energy of the surface of the earth, we thought that E = mc ² × A.
However, as in neutrons, when A = 3873, E = mc ² × A of neutron revolution orbit ÷÷ Proton revolution orbit A = mc ² × 3873 ÷ 1836 = mc ² × 2.1
This indicates that E = mc ² × A ÷ A of the proton's revolution orbit in the revolution orbit above the proton energy.
7). In Japanese Patent Application No. 2012-150959 filed on July 5, 2012, E = 8.665 × 10 ⁻²⁴ Jm ÷ orbital and E = mc ² formula, mass = 9.628 × 10 ⁻⁴¹ Kgm ÷ orbital. . This formula is incorrect. E = mc ² × A.
There are also high energy fields in the surface atoms. The energy of the orbit where neutrons exist is 3873 times the energy of the orbit where electrons revolve.
And this energy cannot be calculated with E = mc ² . E = mc ² × 3873 ÷ 1836 = mc ² × 2.1.
Therefore, as considered in Japanese Patent Application No. 2012-109671, E = mc ² × A in a high energy field.
In a high energy field, the energy increases, but the mass does not change.
Make this a table.
table 1

8). What is the phenomenon when neutrons decay?
When the neutron decays, what was in the neutron is released.
The things that existed in the neutrons are electromagnetics created by neutron labs (things with electron labs attached to proton labs) and neutron labs.
Neutron energy = Proton energy + Electron energy + Electromagnetic energy Electromagnetic energy = Neutron energy-(Proton energy + Electron energy) = 939.56535 MeV-(938.27201 MeV + 0.51099 MeV) = 939.56535 MeV-938.783 MeV = 0.78235 MeV
The electromagnetic energy is 0.78235MeV.
The orbit of the neutron lab is 2.733 × 10 ^-14 m.
The energy of one electric photon in this orbit is: electric photon orbit energy ÷ electric photon orbit = 1.233 × 10 ⁻⁴¹ Jm ÷ (2.733 × 10 ⁻¹⁴ m) = 4.5115 × 10 ⁻²⁸ J.
The number of electric photons is: electromagnetic energy / energy of one photon = 0.78235 MeV / (4.5115 × 10 ⁻²⁸ J) = 0.78235 × 10 ⁶ × 1.6021765 × 10 ⁻¹⁹ J ÷ (4.5115 × 10 ⁻²⁸ J ) = 2.778 × 10 ¹⁴ (pieces)
The number of electrical photons is 2.778 × 10 ¹⁴ . This number. It is almost equal to the number of electric photons that a neutron lab makes per second.
The number of electric photons made by a neutron (proton) lab per second = 7.96 x 10 ⁷ x 4.34 x 10 ⁴ = 3.455 x 10 ¹² .
And Yoko's love is rotating the electromagnetic made in one second around him. (This was described in Japanese Patent Application No. 2006-357550 filed on December 30, 2006)
Thus, the neutron decayed and released the rotating electromagnetic around the proton, electron and neutron lab.
This is shown in the table.
Table 2

9. How does electromagnetism look when accelerated to light speed?
In Japanese Patent Application No. 2012-160064 filed on July 19, 2012, in Table 1, the energy of a magnetic photon of one Higgs particle is 2.0075 × 10 ⁻⁸ J ÷ (4.34 × 10 ⁴ ), and orbit = 6.1420 × 10 ^-34 m × 3.14 ÷ (4.34 × 10 ⁴ ).
I wrote in "claim 18" of Japanese Patent Application 2012-160064 as follows.
・ The orbit of an electric photon produced by a proton lab accelerated at the speed of light in one revolution is 6.404 × 10 ^-31 m, and the energy is 1.925 × 10 ^-11 J.
・ A proton lab accelerated at the speed of light makes a magnetic revolution 4.34 × 10 ⁴ orbits are 6.404 × 10 ^-31 m and energy is 1.925 × 10 ^-11 J.
In single photon trajectory of magnetism Rab accelerated protons in the speed of light to make one rotation is 4.633 × 10 ^-35 m, the energy, the number of magnetic photons electrical photon energy ÷ 1 revolution = 1.925 × 10 ^{- 11} J
J ÷ (4.34 × 10 ⁴ ) = 4.435 × 10 ⁻¹⁶ J.
-A proton photolab accelerated at the speed of light makes one orbit of a magnetic photon of 4.633 × 10 ⁻³⁵ m and its energy is 4.435 × 10 ⁻¹⁶ J.
However, in this field, 4.34 × 10 ⁴ magnetic photons that can be produced in one revolution are assembled into one magnetic photon.
In single photon trajectory of magnetism Rab accelerated protons in the speed of light to make one rotation is 4.633 × 10 ^-35 m, the energy, the number of magnetic photons electrical photon energy ÷ 1 revolution = 1.925 × 10 ^{- 11} J
J ÷ (4.34 × 10 ⁴ ) = 4.435 × 10 ⁻¹⁶ J.
The energy of one magnetic photon produced by a proton lab by one rotation is 4.435 × 10 ⁻¹⁶ J, so 4.34 × 10 ⁴ magnetic photons are attracted to form one magnetic photon.
In other words, 4.34 × 10 ⁴ magnetic photons that can be generated in one revolution are assembled into one magnetic photon.
Therefore, the orbit of one magnetic photon produced by one revolution of a proton lab accelerated at the speed of light is 6.404 × 10 ⁻³¹ m and the energy is 1.925 × 10 ⁻¹¹ J.
The orbit of one electric photon and one magnetic photon made by a proton lab accelerated at the speed of light is 6.404 × 10 ^-31 m, and the energy is 1.925 × 10 ^-11 J.
This is shown in the table.
Table 3

10. What kind of particles are considered Higgs particles?
Particles regarded as Higgs particles are said to have a mass 130 times that of protons. This is the electromagnetism produced by a proton lab that is 9 × 10 ¹⁶ times more energy. The electromagnetism is one revolution, and the number of magnetic photons created by 4.34 × 10 ⁴ rotations is one. The energy of one electric photon = the energy of one magnetic photon.
It looks like the following table.
Table 4

  Understanding the inside of atoms and elements is the foundation of industry.

1 Love of electrons 2 Love of protons 3 Love of neutrons 4 A = 1 revolution orbit = 1.05836 × 10 ⁻¹⁰ m
5 A = 1836 orbit = 5.76407 × 10 ⁻¹⁴ m
6 Orbit of A = 3873 = 2.733 × 10 ⁻¹⁴ m
7-Rotation direction 8 + Rotation direction 9 Elemental electron labs 10 Elemental proton labs 11 Elemental neutron labs 12 Neutron revolution orbit is 2.733 × 10 ⁻¹⁴ m, energy is 3.1705 × 10 ^-10 J.
13 The neutron rest mass is 1.67495 × 10 ⁻²⁷ Kg, E = mc ² = 1.67495 × 10 ⁻²⁷ Kg × 9 × 10 ¹⁶ = 1.507455 × 10 ⁻¹⁰ J.
14 Neutron energy = 3.1705 × 10 ⁻¹⁰ J = mc ² × 2.1. That is, E = mc ² × neutron A ÷ proton A. E = mc ² × A.

Claims (10)

Which orbit is the neutron revolving around in the atom?
Neutrons are generated in the middle of the sun at a field of 1.5 × 10 ⁷ ° C. Neutrons can only exist in a field of 1.5 × 10 ⁷ ° C.
Therefore, the field where neutrons exist in the atom is also the field of A = (1.5 × 10 ⁷ ℃) ^1/2 = 3873.
The energy of the proton is 1836 times the energy of the electron. A = 1836.
The orbit of the proton lab is the orbit of the electron lab ÷ 1836 = Bohr radius x 2 ÷ 1836 = 5.2918 x 10 ^-11 m x 2 ÷ 1836 = 1.05836 x 10 ^-10 m ÷ 1836 = 5.564 x 10 ^-14 m ,is.
The orbit of the neutron lab (proton lab attached to the electron lab) is the orbit of the electron lab ÷ 3873 = 1.5836 × 10 ^-10 m ÷ 3873 = 2.733 × 10 ^-14 m.
That is, in the atom, the electron lab exists in the A = 1 orbit, the proton lab exists in the A = 1836 orbit, and the neutron lab exists in the A = 3873 orbit.
That is, in the atom, the electron lab revolves around 1.05836 × 10 ^-10 m, the proton lab revolves around 5.564 × 10 ^-14 m, and the neutron lab revolves 2.733 × 10 ^-14 m. Revolve the orbit.
A = 3873 is 3873 ÷ 1836 = 2.1095, twice that of A = 1836. Therefore, the orbit of neutrons is 2.1095 times that of protons. The mass energy of neutron is 939.56535 MeV. Proton's mass energy is 938.272 MeV. What is the trajectory?
Neutron energy = 939.56535 × 10 ⁶ × 1.6021765 × 10 ⁻¹⁹ J = 1.5053495 × 10 ⁻¹⁰ J.
Orbit of the neutron lab = 8.665 × 10 ⁻²⁴ Jm ÷ (1.5053495 × 10 ⁻¹⁰ J) = 5.756138 × 10 ⁻¹⁴ m.
The orbital energy of the lab is calculated as: 8.665 × 10 ⁻²⁴ Jm, and the orbit of the neutron lab is 5.756138 × 10 ⁻¹⁴ m.
Proton energy = 938.272 × 10 ⁶ × 1.6021765 × 10 ^-19 J = 1.5032773 × 10 ^-10 J.
Proton's love orbit = 8.665 × 10 ⁻²⁴ Jm ÷ (1.5032773 × 10 ⁻¹⁰ J) = 5.76407 × 10 ⁻¹⁴ m.
The orbit of the proton love is 5.76407 × 10 ^-14 m. The orbital energy = 8.665 x 10 ^-24 Jm, the orbit of revolution is calculated as follows: Neutron revolution orbit = 5.756138 x 10 ^-14 m ≒ Proton orbit = 5.640407 x 10 ^-14 m. The irrationality of this thing.
The direction of proton rotation and the direction of neutron rotation are opposite. Nevertheless, the same trajectory cannot be rotated in the opposite direction.
Proton's orbit and neutron's orbit are not the same.
Thus, the proton lab revolves around 5.564 × 10 ^-14 m, and the neutron lab revolves around 2.733 × 10 ^-14 m. How do neutrons and protons rotate in the elements?
Among the elements, the neutron love orbit revolves around 2.733 × 10 ^-14 m. Many neutron labs in the element revolve around 2.733 × 10 ^-14 m orbit. Rotate in the negative direction.
Among the elements, the proton love revolves around an orbit of 5.564 × 10 ^-14 m. Many proton labs in the element revolve around orbits of 5.564 × 10 ^-14 m. Rotate in the plus direction.
However, the neutron energy and proton energy in the element are slightly different, so they appear in orbit. The orbit of the neutron lab is 2.733 × 10 ^-14 m. In this case, what is the energy of neutrons?
Neutron energy = 8.665 × 10 ⁻²⁴ Jm ÷ (2.733 × 10 ⁻¹⁴ m) = 3.1705 × 10 ⁻¹⁰ J.
3.1705 × 10 ^-10 J ÷ (10 ⁶ × 1.6021765 × 10 ^-19 J) ＝ 1.97887 × 10 ³ MeV
The energy of neutron is 3.1705 × 10 ^-10 J = 1978.87MeV. The neutron rest mass is 1.67495 × 10 ^-27 Kg. The energy of neutron 3.1705 × 10 ^-10 J is E = mc ² = 1.507455 × 10 ^-10 J. What does this mean?
The mass energy of neutron is E = mc ² = 1.67495 × 10 ⁻²⁷ Kg × 9 × 10 ¹⁶ = 1.507455 × 10 ⁻¹⁰ J.
The orbit of neutron is 2.733 × 10 ^-14 m and the energy is 3.1705 × 10 ^-10 J.
・ The energy of neutron 3.1705 × 10 ⁻¹⁰ J is E = mc ² = 1.507455 × 10 ⁻¹⁰ J.
3.1705 × 10 ⁻¹⁰ J ÷ (1.507455 × 10 ⁻¹⁰ J) = 2.1032.
Neutron energy 3.1705 × 10 ⁻¹⁰ J is 2.1032 times E = mc ² = 1.507455 × 10 ⁻¹⁰ J.
This is because the neutron field orbit A is 3873 ÷ 1836 = 2.109 times the proton orbit A.
That is, neutron energy = mc ² × neutron revolution orbit A ÷ proton revolution orbit A.
・ What does this mean?
In the Japanese Patent Application 2012-109671 filed on May 11, 2012, I thought that E = mc ² × A in the high energy field.
When the energy on the surface of the earth was 1 ° C and the energy at the site was A times the energy of the surface of the earth, we thought that E = mc ² × A.
However, as in neutrons, when A = 3873, E = mc ² × A of neutron revolution orbit ÷÷ Proton revolution orbit A = mc ² × 3873 ÷ 1836 = mc ² × 2.1
This indicates that E = mc ² × A ÷ A of the proton's revolution orbit in the revolution orbit above the proton energy. In Japanese Patent Application No. 2012-150959 filed on July 5, 2012, E = 8.665 × 10 ⁻²⁴ Jm ÷ orbital and E = mc ² formula, mass = 9.628 × 10 ⁻⁴¹ Kgm ÷ orbital. . This formula is incorrect. E = mc ² × A.
There are also high energy fields in the surface atoms. The energy of the orbit where neutrons exist is 3873 times the energy of the orbit where electrons revolve.
And this energy cannot be calculated with E = mc ² . E = mc ² × 3873 ÷ 1836 = mc ² × 2.1.
Therefore, as considered in Japanese Patent Application No. 2012-109671, E = mc ² × A in a high energy field.
In a high energy field, the energy increases, but the mass does not change.
Make this a table.
Table 5

What is the phenomenon when neutrons decay?
When the neutron decays, what was in the neutron is released.
The things that existed in the neutrons are electromagnetics created by neutron labs (things with electron labs attached to proton labs) and neutron labs.
Neutron energy = Proton energy + Electron energy + Electromagnetic energy Electromagnetic energy = Neutron energy-(Proton energy + Electron energy) = 939.56535 MeV-(938.27201 MeV + 0.51099 MeV) = 939.56535 MeV-938.783 MeV = 0.78235 MeV
The electromagnetic energy is 0.78235MeV.
The orbit of the neutron lab is 2.733 × 10 ^-14 m.
The energy of one electric photon in this orbit is: electric photon orbit energy ÷ electric photon orbit = 1.233 × 10 ⁻⁴¹ Jm ÷ (2.733 × 10 ⁻¹⁴ m) = 4.5115 × 10 ⁻²⁸ J.
The number of electric photons is: electromagnetic energy / energy of one photon = 0.78235 MeV / (4.5115 × 10 ⁻²⁸ J) = 0.78235 × 10 ⁶ × 1.6021765 × 10 ⁻¹⁹ J ÷ (4.5115 × 10 ⁻²⁸ J ) = 2.778 × 10 ¹⁴ (pieces)
The number of electrical photons is 2.778 × 10 ¹⁴ . This number. It is almost equal to the number of electric photons that a neutron lab makes per second.
The number of electric photons made by a neutron (proton) lab per second = 7.96 x 10 ⁷ x 4.34 x 10 ⁴ = 3.455 x 10 ¹² .
And Yoko's love is rotating the electromagnetic made in one second around him. (This was described in Japanese Patent Application No. 2006-357550 filed on December 30, 2006)
Thus, the neutron decayed and released the rotating electromagnetic around the proton, electron and neutron lab.
This is shown in the table.
Table 6

How does electromagnetism look when accelerated to light speed?
In Japanese Patent Application No. 2012-160064 filed on July 19, 2012, in Table 1, the energy of a magnetic photon of one Higgs particle is 2.0075 × 10 ⁻⁸ J ÷ (4.34 × 10 ⁴ ), and orbit = 6.1420 × 10 ^-34 m × 3.14 ÷ (4.34 × 10 ⁴ ).
I wrote in "claim 18" of Japanese Patent Application 2012-160064 as follows.
・ The orbit of an electric photon produced by a proton lab accelerated at the speed of light in one revolution is 6.404 × 10 ^-31 m, and the energy is 1.925 × 10 ^-11 J.
・ A proton lab accelerated at the speed of light makes a magnetic revolution 4.34 × 10 ⁴ orbits are 6.404 × 10 ^-31 m and energy is 1.925 × 10 ^-11 J.
In single photon trajectory of magnetism Rab accelerated protons in the speed of light to make one rotation is 4.633 × 10 ^-35 m, the energy, the number of magnetic photons electrical photon energy ÷ 1 revolution = 1.925 × 10 ^{- 11} J
J ÷ (4.34 × 10 ⁴ ) = 4.435 × 10 ⁻¹⁶ J.
-A proton photolab accelerated at the speed of light makes one orbit of a magnetic photon of 4.633 × 10 ⁻³⁵ m and its energy is 4.435 × 10 ⁻¹⁶ J.
However, in this field, 4.34 × 10 ⁴ magnetic photons that can be produced in one revolution are assembled into one magnetic photon.
In single photon trajectory of magnetism Rab accelerated protons in the speed of light to make one rotation is 4.633 × 10 ^-35 m, the energy, the number of magnetic photons electrical photon energy ÷ 1 revolution = 1.925 × 10 ^{- 11} J
J ÷ (4.34 × 10 ⁴ ) = 4.435 × 10 ⁻¹⁶ J.
The energy of one magnetic photon produced by a proton lab by one rotation is 4.435 × 10 ⁻¹⁶ J, so 4.34 × 10 ⁴ magnetic photons are attracted to form one magnetic photon.
In other words, 4.34 × 10 ⁴ magnetic photons that can be generated in one revolution are assembled into one magnetic photon.
Therefore, the orbit of one magnetic photon produced by one revolution of a proton lab accelerated at the speed of light is 6.404 × 10 ⁻³¹ m and the energy is 1.925 × 10 ⁻¹¹ J.
The orbit of one electric photon and one magnetic photon made by a proton lab accelerated at the speed of light is 6.404 × 10 ^-31 m, and the energy is 1.925 × 10 ^-11 J.
This is shown in the table.
Table 7

What kind of particles are considered Higgs particles?
Particles regarded as Higgs particles are said to have a mass 130 times that of protons. This is the electromagnetism produced by a proton lab that is 9 × 10 ¹⁶ times more energy. The electromagnetism is one revolution, and the number of magnetic photons created by 4.34 × 10 ⁴ rotations is one. The energy of one electric photon = the energy of one magnetic photon.
It looks like the following table.
Table 8

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