JP2005295799A

JP2005295799A - Universal gravitation and elemental particle

Info

Publication number: JP2005295799A
Application number: JP2005174230A
Authority: JP
Inventors: Shizu Kobori; しづ小堀
Original assignee: Individual
Current assignee: Individual
Priority date: 2005-05-18
Filing date: 2005-05-18
Publication date: 2005-10-20

Abstract

<P>PROBLEM TO BE SOLVED: To elucidate the formula for orbital energy of rotation of love of an electron from the viewpoint of a universal gravitation constant on the basis of the following assumption that (1) a magnetic photon, in which an orbit of 1 m with one atom is 1.63×10<SP>-31</SP>J, causes the universal gravitation and a movement amount of the magnetic photon is 1.63×10<SP>-31</SP>(J m) and (2) the conventional formula for the orbital energy of rotation of love of an electron is 10<SP>-33</SP>(J m)÷orbit or energy, however, the orbital energy of rotation of love of an electron in the orbit of 1 m is 10<SP>-33</SP>J and about 1/100 of 1.63×10<SP>-31</SP>J on the basis of the formula of 10<SP>-33</SP>(J m)÷orbit or energy. <P>SOLUTION: Suppose that the actual formula for the orbital energy of rotation of love of an electron is 100 times the conventional formula for the orbital energy of rotation of love of an electron from the universal gravitation constant. The formula for the orbital energy of rotation of love is 10<SP>-31</SP>(J m)÷orbit or energy. The orbit of the magnetic photon of 1 m is 1.63×10<SP>-31</SP>J by the universal gravitation constant. The movement amount for one second of the magnetic photon is 1.63×10<SP>-31</SP>(J m) and the movement amount for one second of rotation of love of an electron. It means that the movement amount for one second of rotation of love of an electron is 1.63×10<SP>-31</SP>(J m). Therefore, one can understand that the formula for the orbital energy of rotation of love of an electron is 1.63×10<SP>-31</SP>(J m)÷orbit or energy and the formula for the orbital energy is unchanged because the movement amount of the photon is unchanged even on the earth and in an atom. <P>COPYRIGHT: (C)2006,JPO&NCIPI

Description

この発明は万有引力と素粒子に関する。 The present invention relates to universal gravitation and elementary particles.

従来、万有引力は重さによってできるとされている。
１原子でできる万有引力は１．６３×１０^−３１Ｊです。Conventionally, universal gravitation is said to be generated by weight.
The universal attractive force that can be generated by one atom is 1.63 × 10 ⁻³¹ J.

１．どうして万有引力定数によって、電子のラブの自転の運動量が解るか。
２．ラブの公転の運動量はいくらか。ラブの公転の軌道エネルギーの式はいくらか。
３．ラブの自転の運動量はいくらか。ラブの自転の軌道エネルギーの式はいくらか。
４．ラブの公転の運動によって電気ができる。
５．ラブの自転の運動によって磁気ができる。
６．万有引力は、ラブの自転の運動量である。
７．電気は、ラブの公転の運動量である。
８．ラブの公転の運動量は電気の光子の運動量に変換し、保存される。
９．ラブの自転の運動量は磁気の光子の運動量に変換し、保存される。
１０．電子のラブの公転軌道はどれ位か。
１１．１秒間に何回公転するか。１秒間に何個の電気の光子ができるか。
１２．電気の光子１個のエネルギーはどれ位か。
１３．電気の光子１個の運動量はいくらか。電気の光子１個の軌道エネルギーの式はどれ位か。
１４．１０^−７ｍの軌道から光子が放出するとしますと、電気の光子１個のエネルギーはどれ位か。１秒間に放出する電気の光子１０^１６個の総エネルギーはいくらか。
１５．１０^−７ｍの軌道から、１秒間に放出する電気の光子のエネルギーは、１秒間にできた電気の光子の何倍か。
１６．１ｍの軌道では、電気の光子１個のエネルギーはいくらか。電気の光子１０^１６個の総エネルギーはいくらか。
１７．１ｍの軌道に於いて、電気の光子１０^１６個の総エネルギーは、１秒間にできた電気の光子のエネルギーの何倍か。
１８．電子のラブの自転軌道はどれ位か。
１９．１秒間に何回自転するか。１秒間に何個の磁気の光子ができるか。
２０．磁気の光子１個のエネルギーはどれ位か。
２１．磁気の光子１個の運動量はいくらか。磁気の光子１個の軌道エネルギーの式はどれ位か。
２２．１０^−７ｍの軌道から光子が放出するとしますと、磁気の光子１個のエネルギーはどれ位か。１秒間に放出する磁気の光子１０^２４個の総エネルギーはいくらか。
２３．１０^−７ｍの軌道から、１秒間に放出する磁気の光子のエネルギーは、１秒間にできた磁気の光子の何倍か。
２４．１ｍの軌道では、磁気の光子１個のエネルギーはいくらか。磁気の光子１０^２４個の総エネルギーはいくらか。
２５．１ｍの軌道に於いて、磁気の光子１０^２４個の総エネルギーは、１秒間にできた磁気の光子のエネルギーの何倍か。
２６．光子の軌道エネルギー＝運動量は、原子の中であっても、地上であっても同じです。
２７．夜行性の動物はどの軌道の光子を目に受けているか。1. Why does the universal gravitational constant determine the momentum of rotation of the electron lab?
2. What is the momentum of love revolution? What is the orbital energy formula for the revolution of the love?
3. What is the momentum of love's rotation? What is the formula for the orbital energy of Love's rotation?
4). Electricity can be generated by the revolving motion of the love.
5). Magnetism is generated by the rotation of the lab.
6). Universal gravitation is the momentum of the lab's rotation.
7). Electricity is the momentum of the revolution of the lab.
8). The momentum of the revolution of the love is converted into the momentum of the electric photon and stored.
9. The momentum of Love's rotation is converted to the momentum of magnetic photons and stored.
10. What is the revolution trajectory of the electronic love?
11. How many times to revolve in a second? How many electric photons can be produced per second?
12 How much energy is one photon of electricity?
13. What is the momentum of an electric photon? What is the equation for the orbital energy of an electric photon?
If the photon is emitted from the orbit of 14.10 ⁻⁷ m, how much energy is one photon of electricity? What is the total energy of 10 ¹⁶ electrical photons emitted per second?
15. The energy of an electric photon emitted per second from an orbit of 15.10 ⁻⁷ m is several times the electric photon generated per second.
What is the energy of a single photon in an orbit of 16.1m? What is the total energy of 10 ¹⁶ photons of electricity?
In a 17.1 m orbit, the total energy of 10 ¹⁶ electric photons is several times the energy of an electric photon made per second.
18. What is the rotation orbit of the electronic love?
19. How many rotations per second? How many magnetic photons are produced per second?
20. What is the energy of one magnetic photon?
21. What is the momentum of one magnetic photon? What is the equation for the orbital energy of a single magnetic photon?
If a photon is emitted from an orbit of 22.10 ⁻⁷ m, how much energy is one magnetic photon in? Magnetic photon 10 ²⁴ Total energy emitted per second somewhat.
How many times the energy of a magnetic photon emitted per second from an orbit of 23.10 ⁻⁷ m is several times that of a magnetic photon generated per second.
In a 24.1m orbit, what is the energy of one magnetic photon? Magnetic photon ^{10 24} Total energy somewhat.
In the trajectory of 25.1M, magnetic photon 10 ²⁴ Total energy, some multiple of the magnetic photon of energy can be 1 second.
26. The photon's orbital energy = momentum is the same whether in the atom or on the ground.
27. Which orbital photon is seen by the nocturnal animals?

本発明者は、２００５年５月１０日に提出した「素粒子３」で、１３番として、万有引力と成っている磁気の光子は、１電子から毎秒１．０４３×１０^−９ｍの軌道で、８×１０^−４６Ｊの磁気の光子が２×１０^１４個放出します。このエネルギーは１．６３×１０^−３１Ｊです。
この磁気の光子の軌道は、原子の中では１．０４×１０^−９ｍで、地上に出ると、１．２５×１０^−４ｍになります。と記しました。
しかし、１秒間に１０^２４個できる磁気の光子のうち２×１０^１４個だけが放出される事は無い。１０^２４個放出される。
又、光子の軌道が大きくなると、エネルギーは減少するはずなのに、
３０番では、どうして、地上に於ける軌道エネルギーの式は、原子の中における軌道エネルギーの式の１０^８倍に成るのか。
この事は、エネルギーは変わらないけれど、軌道が大きくなるという事です。と記した。
これは誤りです。
今回は、万有引力定数から電子のラブの軌道エネルギーの式（電子のラブの自転の運動量）を見直します。
万有引力定数は、１ｋｇと１ｋｇの物質が１ｍ離れた磁気の光子の軌道エネルギーです。
万有引力は磁気の光子によってできる磁気力です。
１原子で１ｍの軌道が１．６３×１０^−３１Ｊの磁気の光子が万有引力になっています。
この磁気の光子の運動量は１．６３×１０^−３１Ｊ・ｍです。
従来、本発明者は、電子のラブの自転の軌道エネルギーの式は、１０^−３３Ｊ・ｍ÷軌道又はエネルギーであると考えてきました。
しかし、これで考えると、１ｍの軌道の、電子のラブの自転の軌道エネルギーは１０^−３３Ｊであり、１．６３×１０^−３１Ｊの約１００分の１です。
万有引力定数から、従来考えてきた電子のラブの自転の軌道エネルキーの式の１００倍が、真実の電子のラブの自転の軌道エネルギーの式であると考えられる。
それで、ラブの自転の軌道エネルギーの式は、１０^−３１Ｊ・ｍ÷軌道又はエネルギーと考える。
電子のラブの自転の軌道エネルギーの式は１．６３×１０^−３１Ｊ・ｍ÷軌道又はエネルギーです。
電子のラブの自転の軌道エネルギーの式を、１．６３×１０^−３１Ｊ・ｍ÷軌道又はエネルギーとして考える場合、
電子のラブの自転軌道は、１．６３×１０^−３１Ｊ・ｍ÷（８×１０^−１４Ｊ）＝２×１０^−１８ｍです。
自転の回数は１秒間に１０^２４回で、１自転でできる１個の磁気の光子のエネルギーを８×１０^−３８Ｊとする。電子のラブの秒速は、１０^２４回×３．１４×２×１０^−１８ｍ＝６．２８×１０^６ｍです。
しかし、今回は、より簡潔に、電子のラブの自転の軌道エネルギーの式を、１０^−３１Ｊ・ｍ÷軌道又はエネルギーとして考え、計算する。The present inventor is "elementary particle 3" filed on May 10, 2005, No. 13, and a magnetic photon that has a universal gravitational force is trajectory from one electron to 1.043 × 10 ^-9 m / s. , 8 × 10 ⁻⁴⁶ J magnetic photons are emitted 2 × 10 ¹⁴ . This energy is 1.63 × 10 ⁻³¹ J.
The orbit of this magnetic photon is 1.04 × 10 ⁻⁹ m in the atom, and 1.25 × 10 ⁻⁴ m when it goes out to the ground. I wrote.
However, only 2 × 10 ¹⁴ out of 10 ²⁴ magnetic photons generated per second are never emitted. 10 ²⁴ are released.
Also, as the photon trajectory grows, the energy should decrease,
In No. 30, why, expression in orbital energy on the ground, whether made in 10 ^eight times the expression of orbital energies in the atoms.
This means that the energy will not change, but the trajectory will grow. It was written.
This is wrong.
This time, we will review the formula of the orbital energy of the electron lab (the momentum of rotation of the electron lab) from the universal gravitational constant.
The universal gravitational constant is the orbital energy of magnetic photons where 1kg and 1kg matter are 1m apart.
Universal gravitation is magnetic force generated by magnetic photons.
A single photon with 1 atom orbit of 1.63 × 10 ⁻³¹ J has a gravitational attraction.
The momentum of this magnetic photon is 1.63 × 10 ⁻³¹ J · m.
In the past, the present inventor has considered that the orbital energy formula for the rotation of an electron ^lab is 10 ⁻³³ J · m ÷ orbital or energy.
However, considering this, the orbital energy of an electron lab's rotation in a 1 m orbit is 10 ⁻³³ J, which is about 1/100 of 1.63 × 10 ⁻³¹ J.
From the universal gravitational constant, it can be considered that 100 times the formula of the electron lab rotation orbital energy that has been considered in the past is the formula of the true electron lab rotation orbit energy.
Therefore, the equation for the orbit energy of the rotation of the ^lab is considered as 10 ⁻³¹ J · m ÷ orbit or energy.
The formula for the orbital energy of rotation of the electron ^lab is 1.63 × 10 ⁻³¹ J · m ÷ orbital or energy.
When considering the equation of the orbital energy of the rotation of the electron ^{lab as} 1.63 × 10 ⁻³¹ J · m ÷ orbital or energy,
The rotation of the electron lab is 1.63 × 10 ⁻³¹ J · m ÷ (8 × 10 ⁻¹⁴ J) = 2 × 10 ⁻¹⁸ m.
The number of rotation is ^{10 24} times per second, and one magnetic energy 8 × ^{10 -38} J photons that can be in one rotation. The speed of the electron lab is 10 ²⁴ times x 3.14 x 2 x 10 ^-18 m = 6.28 x 10 ⁶ m.
However, this time, more simply, the calculation of the orbital energy of the rotation of the electron ^lab is considered as 10 ⁻³¹ J · m ÷ orbital or energy.

Embodiment of the Invention

１．どうして万有引力定数によって、電子のラブの自転の運動量が解るか。
電子のラブには磁気の性質と電気の性質がある。
磁気の性質は自転として現れる。
電気の性質は公転として現れる。
電子のラブの自転の運動量が磁気の光子の運動量に成る。
電子のラブの公転の運動量が電気の光子の運動量に成る。
万有引力は磁気の光子のエネルギーである。
万有引力定数は磁気の光子の軌道が１ｍのエネルギーである。
磁気の光子の軌道が１ｍのエネルギーは１．６３×１０^−３１Ｊである。
磁気の光子の１秒間の運動量は１．６３×１０^−３１Ｊ・ｍである。
磁気の光子の１秒間の運動量は、電子のラブの１秒間の自転の運動量である。
よって、電子のラブの１秒間の自転の運動量は１．６３×１０^−３１Ｊ・ｍである。
２．ラブの公転の運動量はいくらか。ラブの公転の軌道エネルギーの式はいくらか。
本発明者は今まで、ラブの公転の運動量は１０^−２５Ｊ・ｍであると考えていた。しかし、万有引力が原子から出る磁気の光子のよってできる、と考えると、ラブの公転の運動量は自転の運動量の１０^８倍であるから、１０^−３１Ｊ・ｍ×１０^８＝１０^−２３Ｊ・ｍです。
ラブの公転の軌道エネルギーの式は、１０^−２３Ｊ・ｍ÷軌道又はエネルギーです。
３．ラブの自転の運動量はいくらか。ラブの自転の軌道エネルギーの式はいくらか。
本発明者は今まで、ラブの自転の運動量は１０^−３３Ｊ・ｍであると考えていた。
しかし、万有引力が原子から出る磁気の光子のよってできる、と考える。
ラブの自転の運動量が１０^−３３Ｊ・ｍであると、１ｍの軌道に於ける磁気の光子のエネルギーは１０^−３３Ｊになる。
しかし、万有引力を作っている１ｍの軌道に於ける磁気の光子のエネルギーは１．６３×１０^−３１Ｊですから、磁気の光子の１秒間の運動量は１．６３×１０^−３１Ｊ・ｍです。
ラブの１秒間の自転の運動量は１．６３×１０^−３１Ｊ・ｍです。
それで、ラブの自転の軌道エネルギーの式は、１．６３×１０^−３１Ｊ・ｍ÷軌道又はエネルギーです。
しかし、今回はより簡潔に、ラブの自転の運動量は１０^−３１Ｊ・ｍ、ラブの自転の軌道エネルギーの式を、１０^−３１Ｊ・ｍ÷軌道又はエネルギーと考え、計算します。
４．ラブの公転の運動によって電気ができる。
５．ラブの自転の運動によって磁気ができる。
６．万有引力は、ラブの自転の運動量である。
即ち、１ｍの軌道で、１０^−３１Ｊの磁気エネルギーである。
７．電気は、ラブの公転の運動量である。
即ち、１ｍの軌道で、１０^−２３Ｊの電気エネルギーである。
８．ラブの公転の運動量は電気の光子の運動量に変換し、保存される。
９．ラブの自転の運動量は磁気の光子の運動量に変換し、保存される。
１０．電子のラブの公転軌道はどれ位か。
ラブの公転の軌道エネルギーの式は、１０^−２３Ｊ・ｍ÷軌道又はエネルギーですから、１０^−２３Ｊ・ｍ÷（８×１０^−１４Ｊ）＝１．２５×１０^−１０ｍです。
１１．１秒間に何回公転するか。１秒間に何個の電気の光子ができるか。
電子のラブの秒速を４×１０^６ｍとする。
１秒間に、４×１０^６ｍ÷（１．２５×１０^−１０ｍ×３．１４）＝１０^１６回公転する。
１秒間に１０^１６個の電気の光子ができる。
１２．電気の光子１個のエネルギーはどれ位か。
電子のラブの１秒間の運動エネルギーが電気の光子の１秒間の運動エネルギーになるから、電気の光子１個のエネルギーは
８×１０^−１４Ｊ÷１０^１６個＝８×１０^−３０Ｊです。
１３．電気の光子１個の運動量はいくらか。電気の光子１個の軌道エネルギーの式はどれ位か。
電気の光子１個の運動量＝電気の光子１個のエネルギー×軌道ですから、
電気の光子１個の運動量＝８×１０^−３０Ｊ×１．２５×１０^−１０ｍ＝１０^−３９Ｊ・ｍです。
よって、電気の光子１個の軌道エネルギーの式は、１０^−３９Ｊ・ｍ÷軌道又はエネルギーです。
１４．１０^−７ｍの軌道から光子が放出するとしますと、電気の光子１個のエネルギーはどれ位か。１秒間に放出する電気の光子１０^１６個の総エネルギーはいくらか。
本発明者は、原子から放出する光子の軌道は１０^−９ｍであると考えてきた。
しかし、今回の考えで、光子の軌道は１００倍に成ったので、原子から放出する光子の軌道は１０^−９ｍ×１００＝１０^−７ｍである。それで、原子から放出する電気の光子の軌道は１０^−７ｍである。
電気の光子１個の軌道エネルギーの式は、１０^−３９Ｊ・ｍ÷軌道又はエネルギーですから、１０^−７ｍの電気の光子１個のエネルギーは、
１０^−３９Ｊ・ｍ÷１０^−７ｍ＝１０^−３２Ｊです。
１秒間に放出する電気の光子の１０^１６個の総エネルギーは、
１０^−３２Ｊ×１０^１６個＝１０^−１６Ｊです。
１５．１０^−７ｍの軌道から、１秒間に放出する電気の光子のエネルギーは、１秒間にできた電気の光子の何倍か。
１秒間にできた電気の光子は、８×１０^−１４Ｊです。
１０^−７ｍの軌道から、１秒間に放出する電気の光子のエネルギーは、１０^−１６Ｊです。
１０^−７ｍの軌道から、１秒間に放出する電気の光子のエネルギーは、１秒間にできた電気の光子の、１０^−１６Ｊ÷（８×１０^−１４Ｊ）＝１．２５×１０^−３倍です。１÷（１．２５×１０^−３）＝８×１０^２分の１です。
軌道が１０^−７ｍ÷（１．２５×１０^−１０ｍ）＝８×１０^２倍になったので、エネルギーは８×１０^２分の１になった。
１６．１ｍの軌道では、電気の光子１個のエネルギーはいくらか。電気の光子１０^１６個の総エネルギーはいくらか。
１ｍの軌道では、電気の光子１個のエネルギーは、
電気の光子１個の軌道エネルギーの式は、１０^−３９Ｊ・ｍ÷軌道又はエネルギーですから、１０^−３９Ｊ・ｍ÷１ｍ＝１０^−３９Ｊです。
電気の光子１０^１６個の総エネルギーは、１０^−３９Ｊ×１０^１６個＝１０^−２３Ｊです。
１７．１ｍの軌道に於いて、電気の光子１０^１６個の総エネルギーは、１秒間にできた電気の光子のエネルギーの何倍か。
１ｍの軌道に於いて、電気の光子１０^１６個の総エネルギーは１０^−２３Ｊです。
１秒間にできた電気の光子のエネルギーは８×１０^−１４Ｊです。
１ｍの軌道に於いて、電気の光子１０^１６個の総エネルギーは、１秒間にできた電気の光子のエネルギーの、
１０^−２３Ｊ÷（８×１０^−１４Ｊ）＝１．２５×１０^−１０倍です。１÷（１．２５×１０^−１０）＝８×１０^９分の１です。
軌道が、１ｍ÷（１．２５×１０^−１０ｍ）＝８×１０^９倍になったので、エネルギーは８×１０^９分の１になった。
１８．電子のラブの自転軌道はどれ位か。
ラブの自転の軌道エネルギーの式は、１０^−３１Ｊ・ｍ÷軌道又はエネルギーですから、電子のラブの自転軌道は、
１０^−３１Ｊ・ｍ÷（８×１０^−１４Ｊ）＝１．２５×１０^−１８ｍです。
１９．１秒間に何回自転するか。１秒間に何個の磁気の光子ができるか。
電子のラブの秒速を４×１０^６ｍとする。
１秒間に、４×１０^６ｍ÷（１．２５×１０^−１８ｍ×３．１４）＝１０^２４回自転する。
１秒間に１０^２４個の磁気の光子ができる。
２０．磁気の光子１個のエネルギーはどれ位か。
電子のラブの１秒間の運動エネルギーが電気の光子の１秒間の運動エネルギーになるから、電気の光子１個のエネルギーは
８×１０^−１４Ｊ÷１０^２４個＝８×１０^−３８Ｊです。
２１．磁気の光子１個の運動量はいくらか。磁気の光子１個の軌道エネルギーの式はどれ位か。
磁気の光子１個の運動量＝磁気の光子１個のエネルギー×軌道ですから、
磁気の光子１個の運動量＝８×１０^−３８Ｊ×１．２５×１０^−１８ｍ−１０^−５５Ｊ・ｍです。
よって、磁気の光子１個の軌道エネルギーの式は、１０^−５５Ｊ・ｍ÷軌道又はエネルギーです。
２２．１０^−７ｍの軌道から光子が放出するとしますと、磁気の光子１個のエネルギーはどれ位か。１秒間に放出する磁気の光子１０^２４個の総エネルギーはいくらか。
本発明者は、原子から放出する光子の軌道は１０^−９ｍであると考えてきた。
しかし、今回の考えで、光子の軌道は１００倍に成ったので、原子から放出する光子の軌道は１０^−９ｍ×１００＝１０^−７ｍである。それで、原子から放出する磁気の光子の軌道は１０^−７ｍである。
磁気の光子１個の軌道エネルギーの式は、１０^−５５Ｊ・ｍ÷軌道又はエネルギーですから、１０^−７ｍの磁気の光子１個のエネルギーは、
１０^−５５Ｊ・ｍ÷１０^−７ｍ＝１０^−４８Ｊです。
１秒間に放出する磁気の光子の１０^２４個の総エネルギーは、
１０^−４８Ｊ×１０^２４個＝１０^−２４Ｊです。
２３．１０^−７ｍの軌道から、１秒間に放出する磁気の光子のエネルギーは、１秒間にできた磁気の光子の何倍か。
１秒間にできた磁気の光子は、８×１０^−１４Ｊです。
１０^−７ｍの軌道から、１秒間に放出する磁気の光子のエネルギーは、１０^−２４Ｊです。
１０^−７ｍの軌道から、１秒間に放出する磁気の光子のエネルギーは、１秒間にできた磁気の光子の、１０^−２４Ｊ÷（８×１０^−１４Ｊ）＝１．２５×１０^−１１倍です。１÷（１．２５×１０^−１１）＝８×１０^１０分の１です。
軌道が、１０^−７ｍ÷（１．２５×１０^−１８ｍ）＝８×１０^１０倍になったので、エネルギーは８×１０^１０分の１になった。
２４．１ｍの軌道では、磁気の光子１個のエネルギーはいくらか。磁気の光子１０^２４個の総エネルギーはいくらか。
１ｍの軌道では、磁気の光子１個のエネルギーは、
磁気の光子１個の軌道エネルギーの式は、１０^−５５Ｊ・ｍ÷軌道又はエネルギーですから、１０^−５５Ｊ・ｍ÷１ｍ＝１０^−５５Ｊです。
磁気の光子１０^２４個の総エネルギーは、１０^−５５Ｊ×１０^２４個＝１０^−３１Ｊです。
この磁気の光子のエネルギーが１ｍの軌道に於けるエネルギーで、１原子でできる、万有引力定数になっています。
２５．１ｍの軌道に於いて、磁気の光子１０^２４個の総エネルギーは、１秒間にできた磁気の光子のエネルギーの何倍か。
１ｍの軌道に於いて、磁気の光子１０^２４個の総エネルギーは１０^−３１Ｊです。
１秒間にできた磁気の光子のエネルギーは８×１０^−１４Ｊです。
１ｍの軌道に於いて、磁気の光子１０^２４個の総エネルギーは、１秒間にできた磁気の光子のエネルギーの、
１０^−３１Ｊ÷（８×１０^−１４Ｊ）＝１．２５×１０^−１８倍です。１÷（１．２５×１０^−１８）＝８×１０^１７分の１です。
軌道が、１÷（１．２５×１０^−１８ｍ）＝８×１０^１７倍になったので、エネルギーは８×１０^１７分の１になった。
２６．光子の軌道エネルギー＝運動量は、原子の中であっても、地上であっても同じです。
本発明者は、２００５年５月１０日に提出した特許願の１１番において、地上では、電気の光子の軌道エネルギーの式と、磁気の光子の軌道エネルギーの式はどれ位か。について記した。
地上では、
電気の光子１個の軌道エネルギーの式は、１０^−３３Ｊ・ｍ÷軌道又はエネルギーです。
磁気の光子の１０^８個の軌道エネルギーの式は、１０^−４１Ｊ・ｍ÷軌道又はエネルギーです。
磁気の光子の１個の軌道エネルギーの式は、１０^−４９Ｊ・ｍ÷軌道又はエネルギーです。
と記したが、これは間違いです。
光子の軌道×エネルギー＝運動量は、原子の中であっても、地上であっても同じです。
電気の光子１個の運動量は、１０^−３９Ｊ・ｍであり、
電気の光子１個の軌道エネルギーの式は、１０^−３９Ｊ・ｍ÷軌道又はエネルギーです。
磁気の光子１個の運動量は、１０^−５５Ｊ・ｍであり、
磁気の光子１個の軌道エネルギーの式は、１０^−５５Ｊ・ｍ÷軌道又はエネルギーです。
磁気の光子１０^８個の運動量は、１０^−４７Ｊ・ｍであり、
磁気の光子１０^８個の軌道エネルギーの式は、１０^−４７Ｊ・ｍ÷軌道又はエネルギーです。
２７．夜行性の動物はどの軌道の光子を目に受けているか。
夜行性の動物は、原子から放出する１０^−７ｍの軌道の光子を受けている。
電気の光子１個のエネルギーは、１０^−３２Ｊです。
磁気の光子１個のエネルギーは、１０^−４８Ｊで、１０^８個のエネルギーは、１０^−４０Ｊです。
以上の事をまとめて表にします。

1. Why does the universal gravitational constant determine the momentum of rotation of the electron lab?
An electronic lab has both magnetic and electrical properties.
The nature of magnetism appears as rotation.
The nature of electricity appears as a revolution.
The momentum of the electron lab's rotation becomes the momentum of the magnetic photon.
The momentum of the revolution of the electron lab becomes the momentum of the electric photon.
Universal gravitation is the energy of magnetic photons.
The universal gravitational constant is the energy of 1 m of the magnetic photon trajectory.
The energy of 1 m of magnetic photon trajectory is 1.63 × 10 ⁻³¹ J.
The momentum of magnetic photons per second is 1.63 × 10 ⁻³¹ J · m.
The one second momentum of the magnetic photon is the one second rotation momentum of the electron lab.
Therefore, the momentum of rotation of the electron lab for 1 second is 1.63 × 10 ⁻³¹ J · m.
2. What is the momentum of love revolution? What is the orbital energy formula for the revolution of the love?
The present inventor has so far considered that the momentum of revolution of the love is 10 ⁻²⁵ J · m. However, considering that the gravitational attractive force is generated by magnetic photons emitted from the atoms, the revolution momentum of the love is 10 ⁸ times the rotational momentum, so 10 ⁻³¹ J · m × 10 ⁸ = 10 ⁻²³ J · m.
The equation for the orbital energy of the revolution of the ^lab is 10 ⁻²³ J · m ÷ orbital or energy.
3. What is the momentum of love's rotation? What is the formula for the orbital energy of Love's rotation?
The present inventor has so far considered that the momentum of rotation of the ^lab is 10 ⁻³³ J · m.
However, I think that the universal attractive force can be generated by magnetic photons emitted from atoms.
When the momentum of rotation of the ^lab is 10 ⁻³³ J · m, the energy of magnetic photons in a 1 m orbit becomes 10 ⁻³³ J.
However, since the energy of a magnetic photon in a 1 m orbit creating a universal gravitation is 1.63 × 10 ⁻³¹ J, the momentum of a magnetic photon per second is 1.63 × 10 ⁻³¹ J · m.
The momentum of rotation of the lab per second is 1.63 × 10 ⁻³¹ J · m.
Therefore, the equation for the orbit energy of the rotation of the lab is 1.63 × 10 ⁻³¹ J · m ÷ orbit or energy.
However, this time, more concisely, the momentum of the rotation of the ^lab is 10 ⁻³¹ J · m, and the orbit energy of the rotation of the ^lab is 10 ⁻³¹ J · m ÷ orbital or energy.
4). Electricity can be generated by the revolving motion of the love.
5). Magnetism is generated by the rotation of the lab.
6). Universal gravitation is the momentum of the lab's rotation.
That is, the magnetic energy is 10 ⁻³¹ J in a 1 m orbit.
7). Electricity is the momentum of the revolution of the lab.
That is, the electric energy is 10 ⁻²³ J in a 1 m orbit.
8). The momentum of the revolution of the love is converted into the momentum of the electric photon and stored.
9. The momentum of Love's rotation is converted to the momentum of magnetic photons and stored.
10. What is the revolution trajectory of the electronic love?
The formula for the orbital energy of the revolution of the ^lab is 10 ⁻²³ J · m ÷ orbital or energy, so 10 ⁻²³ J · m ÷ (8 × 10 ⁻¹⁴ J) = 1.25 × 10 ⁻¹⁰ m.
11. How many revolutions per second? How many electric photons can be produced per second?
The speed of the electron love is 4 × 10 ⁶ m.
4 × 10 ⁶ m ÷ (1.25 × 10 ⁻¹⁰ m × 3.14) = 10 ¹⁶ revolutions per second.
There are 10 ¹⁶ electrical photons per second.
12 How much energy is one photon of electricity?
Since the kinetic energy per second of the electron lab becomes the kinetic energy per second of the electric photon, the energy of one electric photon is 8 × 10 ⁻¹⁴ J ÷ 10 ¹⁶ = 8 × 10 ⁻³⁰ J.
13. What is the momentum of an electric photon? What is the equation for the orbital energy of an electric photon?
Since the momentum of one electric photon = the energy of one electric photon x the orbit,
The momentum of a single photon is 8 × 10 ⁻³⁰ J × 1.25 × 10 ⁻¹⁰ m = 10 ⁻³⁹ J · m.
Thus, the equation for the orbital energy of an electric photon is 10 ⁻³⁹ J · m ÷ orbital or energy.
14 If a photon is emitted from an orbit of 10 ⁻⁷ m, how much energy is one photon of electricity? What is the total energy of 10 ¹⁶ electrical photons emitted per second?
The inventor has considered that the orbit of a photon emitted from an atom is 10 ⁻⁹ m.
However, since the photon's trajectory has increased 100 times in this idea, the photon's trajectory emitted from the atom is 10 ⁻⁹ m × 100 = 10 ⁻⁷ m. Therefore, the trajectory of the electric photon emitted from the atom is 10 ⁻⁷ m.
The equation for the orbital energy of one electric photon is 10 ⁻³⁹ J · m ÷ orbital or energy, so the energy of one electric photon of 10 ⁻⁷ m is
10 ⁻³⁹ J · m ÷ 10 ⁻⁷ m = 10 ⁻³² J.
The total energy of 10 ¹⁶ electrical photons emitted per second is
10 ⁻³² J × 10 ¹⁶ pieces = 10 ⁻¹⁶ J.
15. How many times the energy of an electric photon emitted per second from an orbit of 10 ⁻⁷ m is several times that of an electric photon generated per second.
The electrical photon generated in 1 second is 8 × 10 ⁻¹⁴ J.
The energy of an electric photon emitted per second from an orbit of 10 ⁻⁷ m is 10 ⁻¹⁶ J.
The energy of an electric photon emitted per second from an orbit of 10 ⁻⁷ m is 10 ⁻¹⁶ J ÷ (8 × 10 ⁻¹⁴ J) = 1.25 × 10 ^{− of} the electric photon generated per second. ³ times. 1 ÷ (1.25 × 10 ⁻³ ) = 8 × 10 ^1/2 .
Since the trajectory was 10 ⁻⁷ m ÷ (1.25 × 10 ⁻¹⁰ m) = 8 × 10 ² times, the energy was reduced to 8 × 10 ^1/2 .
16. What is the energy of a single photon in a 1 meter orbit? What is the total energy of 10 ¹⁶ photons of electricity?
In a 1m orbit, the energy of one electric photon is
The equation for the orbital energy of an electric photon is 10 ⁻³⁹ J · m ÷ orbital or energy, so 10 ⁻³⁹ J · m ÷ 1 m = 10 ⁻³⁹ J.
The total energy of 10 ¹⁶ photons of electricity is 10 ⁻³⁹ J × 10 ¹⁶ = 10 ⁻²³ J.
17. In a 1 meter orbit, the total energy of 10 ¹⁶ electrical photons is several times the energy of an electrical photon produced per second.
In a 1 m orbit, the total energy of 10 ¹⁶ electrical photons is 10 ⁻²³ J.
The energy of an electric photon generated per second is 8 × 10 ⁻¹⁴ J.
In a 1 meter orbit, the total energy of 10 ¹⁶ electrical photons is the energy of the electrical photons produced in 1 second.
10 ⁻²³ J ÷ (8 × 10 ⁻¹⁴ J) = 1.25 × 10 ⁻¹⁰ times. ^{1 ÷ (1.25 × 10 -10)} = 8 × is one of 10 ⁹ minutes.
Since the orbit increased by 1 m ÷ (1.25 × 10 ⁻¹⁰ m) = 8 × 10 ⁹ times, the energy was reduced to 1 × 8 × 10 ⁹ .
18. What is the rotation orbit of the electronic love?
The formula for the orbital energy of the lab rotation is 10 ⁻³¹ J · m ÷ orbital or energy.
10 ⁻³¹ J · m ÷ (8 × 10 ⁻¹⁴ J) = 1.25 × 10 ⁻¹⁸ m.
19. How many rotations per second? How many magnetic photons are produced per second?
The speed of the electron love is 4 × 10 ⁶ m.
In one second, 4 × 10 ⁶ m ÷ (1.25 × 10 ⁻¹⁸ m × 3.14) = 10 ²⁴ times of rotation.
Can ^{10 24} magnetic photons per second.
20. What is the energy of one magnetic photon?
Since the kinetic energy per second of the electron lab becomes the kinetic energy per second of the electric photon, the energy of one electric photon is 8 × 10 ⁻¹⁴ J ÷ 10 ²⁴ = 8 × 10 ⁻³⁸ J.
21. What is the momentum of one magnetic photon? What is the equation for the orbital energy of a single magnetic photon?
The momentum of one magnetic photon = the energy of one magnetic photon x the orbit.
The momentum of one magnetic photon is 8 × 10 ⁻³⁸ J × 1.25 × 10 ⁻¹⁸ m−10 ⁻⁵⁵ J · m.
Therefore, the equation for the orbital energy of one magnetic photon is 10 ⁻⁵⁵ J · m ÷ orbital or energy.
22. If a photon is emitted from an orbit of 10 ⁻⁷ m, how much energy is one magnetic photon in? Magnetic photon 10 ²⁴ Total energy emitted per second somewhat.
The inventor has considered that the orbit of a photon emitted from an atom is 10 ⁻⁹ m.
However, since the photon's trajectory has increased 100 times in this idea, the photon's trajectory emitted from the atom is 10 ⁻⁹ m × 100 = 10 ⁻⁷ m. Therefore, the orbit of magnetic photons emitted from atoms is 10 ⁻⁷ m.
The equation for the orbital energy of one magnetic photon is 10 ⁻⁵⁵ J · m ÷ orbital or energy, so the energy of one magnetic photon of 10 ⁻⁷ m is
10 ⁻⁵⁵ J · m ÷ 10 ⁻⁷ m = 10 ⁻⁴⁸ J.
Magnetic 10 ²⁴ total energy of photons emitted per second,
10 ⁻⁴⁸ J × 10 ²⁴ pieces = 10 ⁻²⁴ J.
23. How many times the energy of a magnetic photon emitted per second from a 10 ⁻⁷ m orbit is several times that of a magnetic photon generated per second.
The magnetic photon produced in 1 second is 8 × 10 ⁻¹⁴ J.
The energy of a magnetic photon emitted per second from a 10 ⁻⁷ m orbit is 10 ⁻²⁴ J.
The energy of a magnetic photon emitted per second from a trajectory of 10 ⁻⁷ m is 10 ⁻²⁴ J ÷ (8 × 10 ⁻¹⁴ J) = 1.25 × 10 ^{− of} the magnetic photon generated per second. ¹¹ times. 1 ÷ (1.25 × 10 ⁻¹¹ ) = 8 × 10 ^1/10 .
Orbit, became so ^{^{10 -7 m ÷ (1.25 × 10}} -18 m) = 8 × 10 10 times, energy has become the first 8 × ^{10 10} minutes.
24. What is the energy of one magnetic photon in a 1 m orbit? Magnetic photon ^{10 24} Total energy somewhat.
In a 1m orbit, the energy of one magnetic photon is
The formula for the orbital energy of one magnetic photon is 10 ⁻⁵⁵ J · m ÷ orbital or energy, so 10 ⁻⁵⁵ J · m ÷ 1 m = 10 ⁻⁵⁵ J.
The total energy of 10 ²⁴ magnetic photons is 10 ⁻⁵⁵ J × 10 ²⁴ = 10 ⁻³¹ J.
The energy of this magnetic photon is the energy in an orbit of 1 m, and it is a universal gravitational constant that can be formed by one atom.
25. In the path of 1 m, the magnetic photon 10 ²⁴ Total energy, some multiple of the magnetic photon of energy can be 1 second.
In the orbit of 1m, the magnetic photon ^{10 24} of the total energy is ^{10 -31} J.
The energy of a magnetic photon generated per second is 8 × 10 ⁻¹⁴ J.
In the path of 1 m, the magnetic photon 10 ²⁴ Total energy, the energy of the magnetic photon made per second,
10 ⁻³¹ J ÷ (8 × 10 ⁻¹⁴ J) = 1.25 × 10 ⁻¹⁸ times. ^{1 ÷ (1.25 × 10 -18)} = 8 × is one of ^{10 17} minutes.
Orbit, became so ^{1 ÷ (1.25 × 10 -18 m} ) = 8 × 10 17 times, energy has become the first 8 × ^{10 17} minutes.
26. The photon's orbital energy = momentum is the same whether in the atom or on the ground.
In the eleventh patent application filed on May 10, 2005, the present inventor is on the ground what are the equations for the orbital energy of the electric photons and the orbital energy of the magnetic photons. I wrote about.
On the ground,
The equation for the orbital energy of an electric photon is 10 ⁻³³ J · m ÷ orbital or energy.
The formula for 10 ⁸ orbital energies of magnetic photons is 10 ⁻⁴¹ J · m ÷ orbital or energy.
The formula for one orbital energy of a magnetic photon is 10 ⁻⁴⁹ J · m ÷ orbital or energy.
This is a mistake.
Photon's orbit × energy = momentum is the same whether in the atom or on the ground.
The momentum of one electric photon is 10 ⁻³⁹ J · m,
The equation for the orbital energy of an electric photon is 10 ⁻³⁹ J · m ÷ orbital or energy.
The momentum of one magnetic photon is 10 ⁻⁵⁵ J · m,
The formula for the orbital energy of one magnetic photon is 10 ⁻⁵⁵ J · m ÷ orbital or energy.
The momentum of 10 ⁸ magnetic photons is 10 ⁻⁴⁷ J · m,
Wherein the magnetic photon 10 ⁸ orbital energy ^{is 10 -47} J · m ÷ orbital or energy.
27. Which orbital photon is seen by the nocturnal animals?
Nocturnal animals are receiving ^10-7 m orbital photons emitted from atoms.
The energy of one photon of electricity is ^10-32 J.
The energy of one magnetic photon is 10 ⁻⁴⁸ J, and the energy of 10 ⁸ is 10 ⁻⁴⁰ J.
The above is summarized in a table.

The invention's effect

万有引力定数により、磁気の光子１ｍの軌道が１．６３×１０^−３１Ｊです。
それで、磁気の光子の１秒間の運動量は１．６３×１０^−３１Ｊ・ｍです。
磁気の光子の１秒間の運動量は、電子のラブの１秒間の自転の運動量です。
電子のラブの１秒間の自転の運動量は、１．６３×１０^−３１Ｊ・ｍであるから、電子のラブの自転の軌道エネルギーの式は、１．６３×１０^−３１Ｊ・ｍ÷軌道又はエネルギーである事が理解できた。地上でも、原子の中でも、光子の運動量は変わらないので、軌道エネルギーの式も変わらないことが理解できた。
夜行性の動物は、１０^−７ｍの光子を目に受けている事が理解できた。
この発明によって、原子の中の、電子のラブの自転運動量と公転運動量と電気の光子の運動量と磁気の光子の運動量と万有引力の統一ができた。Due to the universal gravitational constant, the orbit of magnetic photon 1m is 1.63 × 10 ⁻³¹ J.
Therefore, the momentum of magnetic photons per second is 1.63 × 10 ⁻³¹ J · m.
The momentum of magnetic photons per second is the momentum of rotation of the electron lab per second.
Since the momentum of rotation of the electron lab for one second is 1.63 × 10 ⁻³¹ J · m, the equation of the orbital energy of the rotation of the electron lab is 1.63 × 10 ⁻³¹ J · m ÷ orbital. Or I understood that it is energy. I understand that the photon momentum does not change on the ground or in atoms, so the orbital energy equation does not change either.
It was understood that nocturnal animals received 10 ^-7 m photons in their eyes.
This invention has made it possible to unify the rotational momentum and revolution momentum of the electron lab, the momentum of the electric photon, the momentum of the magnetic photon, and the universal attractive force in the atom.

従来の考えである軌道とエネルギーです。原子の中において、１秒間に、１電子でできる軌道１ｍの磁気の光子のエネルギーは、１０^−３３Ｊ・ｍ÷１ｍ＝１０^−３３Ｊです。Orbits and energy, which is the traditional idea. In an atom, the energy of a magnetic photon with an orbit of 1 m generated by one electron per second is 10 ⁻³³ J · m ÷ 1 m = 10 ⁻³³ J. 万有引力定数で、原子の中において、１秒間に、１電子でできる軌道１ｍの磁気の光子のエネルギーは、１．６３×１０^−３１Ｊです。It is a universal gravitational constant, and the energy of an orbital 1m magnetic photon produced by one electron per second in an atom is 1.63 × 10 ⁻³¹ J. 万有引力定数により、電子のラブの１秒間の運動量は１．６３×１０^−３１Ｊ・ｍです。電子のラブは１．２５×１０^−１８ｍの軌道を１自転し、１個の磁気の光子を作る。１個の磁気の光子のエネルギーは８×１０^−３８Ｊです。Due to the universal gravitational constant, the momentum of the electron ^lab is 1.63 × 10 ⁻³¹ J · m. The electron ^lab rotates on a 1.25 × 10 ⁻¹⁸ m orbit and makes one magnetic photon. The energy of one magnetic photon is 8 × 10 ⁻³⁸ J. 電子のラブは１０^８回自転し、１公転する。１公転の軌道は１．２５×１０^−１０ｍで、この電気の光子１個のエネルギーは８×１０^−３０Ｊです。The electronic lab spins 10 ⁸ times and makes one revolution. The trajectory of one revolution is 1.25 × 10 ⁻¹⁰ m, and the energy of one photon of this electricity is 8 × 10 ⁻³⁰ J.

Explanation of symbols

１磁気の光子の軌道
２電子のラブ
３電子のラブの自転軌道
４電子のラブの公転軌道、１回の公転で、１０^８個の磁気の光子ができる。DESCRIPTION OF SYMBOLS 1 Magnetic photon orbit 2 Electron lab 3 Electron lab rotation orbit 4 Electron lab revolution orbit In one revolution, 10 ⁸ magnetic photons are generated.

Claims

Why does the universal gravitational constant determine the momentum of rotation of the electron lab?
An electronic lab has both magnetic and electrical properties.
The nature of magnetism appears as rotation.
The nature of electricity appears as a revolution.
The momentum of the electron lab's rotation becomes the momentum of the magnetic photon.
The momentum of the revolution of the electron lab becomes the momentum of the electric photon.
Universal gravitation is the energy of magnetic photons.
The universal gravitational constant is the energy of 1 m of the magnetic photon trajectory.
The energy of 1 m of magnetic photon trajectory is 1.63 × 10 ⁻³¹ J.
The momentum of magnetic photons per second is 1.63 × 10 ⁻³¹ J · m.
The one second momentum of the magnetic photon is the one second rotation momentum of the electron lab.
Therefore, the momentum of rotation of the electron lab for 1 second is 1.63 × 10 ⁻³¹ J · m.

What is the momentum of love revolution? What is the orbital energy formula for the revolution of the love?
The present inventor has so far considered that the momentum of revolution of the love is 10 ⁻²⁵ J · m. However, considering that the gravitational attractive force is generated by magnetic photons emitted from the atoms, the revolution momentum of the love is 10 ⁸ times the rotational momentum, so 10 ⁻³¹ J · m × 10 ⁸ = 10 ⁻²³ J · m.
The equation for the orbital energy of the revolution of the ^lab is 10 ⁻²³ J · m ÷ orbital or energy.

What is the momentum of love's rotation? What is the formula for the orbital energy of Love's rotation?
The present inventor has so far considered that the momentum of rotation of the ^lab is 10 ⁻³³ J · m.
However, I think that the universal attractive force can be generated by magnetic photons emitted from atoms.
If the momentum of the rotation of the club is at ^{10 -33} J · m, Eneruki photon trajectories of in magnetic 1m becomes ^{10 -33} J.
However, since the energy of a magnetic photon in a 1 m orbit creating a universal gravitation is 1.63 × 10 ³¹ J, the momentum of a magnetic photon per second is 1.63 × 10 ⁻³¹ J · m.
The momentum of rotation of the lab per second is 1.63 × 10 ⁻³¹ J · m.
Therefore, the equation for the orbit energy of the rotation of the lab is 1.63 × 10 ⁻³¹ J · m ÷ orbit or energy.
However, this time, more concisely, the momentum of the rotation of the ^lab is 10 ⁻³¹ J · m, and the orbit energy of the rotation of the ^lab is 10 ⁻³¹ J · m ÷ orbital or energy.

Electricity can be generated by the revolving motion of the love.

Magnetism is generated by the rotation of the lab.

Universal gravitation is the momentum of the lab's rotation.
That is, the magnetic energy is 10 ⁻³¹ J in a 1 m orbit.

Electricity is the momentum of the revolution of the lab.
That is, the electric energy is 10 ⁻²³ J in a 1 m orbit.

The momentum of the revolution of the love is converted into the momentum of the electric photon and stored.

The momentum of Love's rotation is converted to the momentum of magnetic photons and stored.

What is the revolution trajectory of the electronic love?
The formula for the orbital energy of the revolution of the ^lab is 10 ⁻²³ J · m ÷ orbital or energy, so 10 ⁻²³ J · m ÷ (8 × 10 ⁻¹⁴ J) = 1.25 × 10 ⁻¹⁰ m.

How many revolutions per second? How many electric photons can be produced per second?
The speed of the electron love is 4 × 10 ⁶ m.
4 × 10 ⁶ m ÷ (1.25 × 10 ⁻¹⁰ m × 3.14) = 10 ¹⁶ revolutions per second.
There are 10 ¹⁶ electrical photons per second.

How much energy is one photon of electricity?
Since the kinetic energy per second of the electron lab becomes the kinetic energy per second of the electric photon, the energy of one electric photon is 8 × 10 ⁻¹⁴ J ÷ 10 ¹⁶ = 8 × 10 ⁻³⁰ J.

What is the momentum of an electric photon? What is the equation for the orbital energy of an electric photon?
Since the momentum of one electric photon = the energy of one electric photon x the orbit,
The momentum of a single photon is 8 × 10 ⁻³⁰ J × 1.25 × 10 ⁻¹⁰ m = 10 ⁻³⁹ J · m.
Thus, the equation for the orbital energy of an electric photon is 10 ⁻³⁹ J · m ÷ orbital or energy.

If a photon is emitted from an orbit of 10 ⁻⁷ m, how much energy is one photon of electricity? What is the total energy of 10 ¹⁶ electrical photons emitted per second?
The inventor has considered that the orbit of a photon emitted from an atom is 10 ⁻⁹ m.
However, since the photon's trajectory has increased 100 times in this idea, the photon's trajectory emitted from the atom is 10 ⁻⁹ m × 100 = 10 ⁻⁷ m. Therefore, the trajectory of the electric photon emitted from the atom is 10 ⁻⁷ m.
The equation for the orbital energy of one electric photon is 10 ⁻³⁹ J · m ÷ orbital or energy, so the energy of one electric photon of 10 ⁻⁷ m is
10 ⁻³⁹ J · m ÷ 10 ⁻⁷ m = 10 ⁻³² J.
The total energy of 10 ¹⁶ electrical photons emitted per second is
10 ⁻³² J × 10 ¹⁶ pieces = 10 ⁻¹⁶ J.

How many times the energy of an electric photon emitted per second from an orbit of 10 ⁻⁷ m is several times that of an electric photon generated per second.
The electrical photon generated in 1 second is 8 × 10 ⁻¹⁴ J.
The energy of an electric photon emitted per second from an orbit of 10 ⁻⁷ m is 10 ⁻¹⁶ J.
The energy of an electric photon emitted per second from an orbit of 10 ⁻⁷ m is 10 ⁻¹⁶ J ÷ (8 × 10 ⁻¹⁴ J) = 1.25 × 10 ^{− of} the electric photon generated per second. ³ times. 1 ÷ (1.25 × 10 ⁻³ ) = 8 × 10 ^1/2 .
Since the trajectory was 10 ⁻⁷ m ÷ (1.25 × 10 ⁻¹⁰ m) = 8 × 10 ² times, the energy was reduced to 8 × 10 ^1/2 .

What is the energy of a single photon in a 1 meter orbit? What is the total energy of 10 ¹⁶ photons of electricity?
In a 1m orbit, the energy of one electric photon is
The equation for the orbital energy of an electric photon is 10 ⁻³⁹ J · m ÷ orbital or energy, so 10 ⁻³⁹ J · m ÷ 1 m = 10 ⁻³⁹ J.
The total energy of 10 ¹⁶ photons of electricity is 10 ⁻³⁹ J × 10 ¹⁶ = 10 ⁻²³ J.

In a 1 meter orbit, the total energy of 10 ¹⁶ electrical photons is several times the energy of an electrical photon produced per second.
In a 1 m orbit, the total energy of 10 ¹⁶ electrical photons is 10 ⁻²³ J.
The energy of an electric photon generated per second is 8 × 10 ⁻¹⁴ J.
In a 1 meter orbit, the total energy of 10 ¹⁶ electrical photons is the energy of the electrical photons produced in 1 second.
10 ⁻²³ J ÷ (8 × 10 ⁻¹⁴ J) = 1.25 × 10 ⁻¹⁰ times. ^{1 ÷ (1.25 × 10 -10)} = 8 × is one of 10 ⁹ minutes.
Since the orbit increased by 1 m ÷ (1.25 × 10 ⁻¹⁰ m) = 8 × 10 ⁹ times, the energy was reduced to 1 × 8 × 10 ⁹ .

What is the rotation orbit of the electronic love?
The formula for the orbital energy of the lab rotation is 10 ⁻³¹ J · m ÷ orbital or energy.
10 ⁻³¹ J · m ÷ (8 × 10 ⁻¹⁴ J) = 1.25 × 10 ⁻¹⁸ m.

How many rotations per second? How many magnetic photons are produced per second?
The speed of the electron love is 4 × 10 ⁶ m.
In one second, 4 × 10 ⁶ m ÷ (1.25 × 10 ⁻¹⁸ m × 3.14) = 10 ²⁴ times of rotation.
Can ^{10 24} magnetic photons per second.

What is the energy of one magnetic photon?
Since the kinetic energy per second of the electron lab becomes the kinetic energy per second of the electric photon, the energy of one electric photon is 8 × 10 ⁻¹⁴ J ÷ 10 ²⁴ = 8 × 10 ⁻³⁸ J.

What is the momentum of one magnetic photon? What is the equation for the orbital energy of a single magnetic photon?
The momentum of one magnetic photon = the energy of one magnetic photon x the orbit.
The momentum of one magnetic photon = 8 × 10 ⁻³⁸ J × 1.25 × 10 ⁻¹⁸ m = 10 ⁻⁵⁵ J · m.
Therefore, the equation for the orbital energy of one magnetic photon is 10 ⁻⁵⁵ J · m ÷ orbital or energy.

If a photon is emitted from an orbit of 10 ⁻⁷ m, how much energy is one magnetic photon in? Magnetic photon 10 ²⁴ Total energy emitted per second somewhat.
The inventor has considered that the orbit of a photon emitted from an atom is 10 ⁻⁹ m.
However, since the photon's trajectory has increased 100 times in this idea, the photon's trajectory emitted from the atom is 10 ⁻⁹ m × 100 = 10 ⁻⁷ m. Therefore, the orbit of magnetic photons emitted from atoms is 10 ⁻⁷ m.
The equation for the orbital energy of one magnetic photon is 10 ⁻⁵⁵ J · m ÷ orbital or energy, so the energy of one magnetic photon of 10 ⁻⁷ m is
10 ⁻⁵⁵ J · m ÷ 10 ⁻⁷ m = 10 ⁻⁴⁸ J.
Magnetic 10 ²⁴ total energy of photons emitted per second,
10 ⁻⁴⁸ J × 10 ²⁴ pieces = 10 ⁻²⁴ J.

How many times the energy of a magnetic photon emitted per second from a 10 ⁻⁷ m orbit is several times that of a magnetic photon generated per second.
The magnetic photon produced in 1 second is 8 × 10 ⁻¹⁴ J.
The energy of a magnetic photon emitted per second from a 10 ⁻⁷ m orbit is 10 ⁻²⁴ J.
The energy of a magnetic photon emitted per second from an orbit of 10 ⁻⁷ m is 10 ⁻²⁴ J ÷ (8 × 10 ⁻¹⁴ J) = 1.25 × 10 ^{− of} the magnetic photon generated per second. ¹¹ times. 1 ÷ (1.25 × 10 ⁻¹¹ ) = 8 × 10 ^1/10 .
Orbit, became so ^{^{10 -7 m ÷ (1.25 × 10}} -18 m) = 8 × 10 10 times, energy has become the first 8 × ^{10 10} minutes.

What is the energy of one magnetic photon in a 1 m orbit? Magnetic photon ^{10 24} Total energy somewhat.
In a 1m orbit, the energy of one magnetic photon is
The equation for the orbital energy of one magnetic photon is 10 ⁻⁵⁵ J · m ÷ orbital or energy, so 10 ⁻⁵⁵ J · m ÷ 1 m = 10 ⁻⁵⁵ .
The total energy of 10 ²⁴ magnetic photons is 10 ⁻⁵⁵ J × 10 ²⁴ = 10 ⁻³¹ J.
The energy of this magnetic photon is the energy in an orbit of 1 m, and it is a universal gravitational constant that can be formed by one atom.

In the path of 1 m, the magnetic photon 10 ²⁴ Total energy, some multiple of the magnetic photon of energy can be 1 second.
In the orbit of 1m, the magnetic photon ^{10 24} of the total energy is ^{10 -31} J.
The energy of a magnetic photon generated per second is 8 × 10 ⁻¹⁴ J.
In the path of 1 m, the magnetic photon 10 ²⁴ Total energy, the energy of the magnetic photon made per second,
10 ⁻³¹ J ÷ (8 × 10 ⁻¹⁴ J) = 1.25 × 10 ⁻¹⁸ times. ^{1 ÷ (1.25 × 10 -18)} = 8 × is one of ^{10 17} minutes.
Orbit, became so ^{1 ÷ (1.25 × 10 -18 m} ) = 8 × 10 17 times, energy has become the first 8 × ^{10 17} minutes.

The photon's orbital energy = momentum is the same whether in the atom or on the ground.
In the eleventh patent application filed on May 10, 2005, the present inventor is on the ground what is the equation for the orbital energy of an electric photon and the equation for the orbital energy of a magnetic photon. I wrote about.
On the ground,
The equation for the orbital energy of an electric photon is 10 ⁻³³ J · m ÷ orbital or energy.
The formula for 10 ⁸ orbital energies of magnetic photons is 10 ⁻⁴¹ J · m ÷ orbital or energy.
The formula for one orbital energy of a magnetic photon is 10 ⁻⁴⁹ J · m ÷ orbital or energy.
This is a mistake.
Photon's orbit × energy = momentum is the same whether in the atom or on the ground.
The momentum of one electric photon is 10 ⁻³⁹ J · m,
The equation for the orbital energy of an electric photon is 10 ⁻³⁹ J · m ÷ orbital or energy.
The momentum of one magnetic photon is 10 ⁻⁵⁵ J · m,
The formula for the orbital energy of one magnetic photon is 10 ⁻⁵⁵ J · m ÷ orbital or energy.
The momentum of 10 ⁸ magnetic photons is 10 ⁻⁴⁷ J · m,
Wherein the magnetic photon 10 ⁸ orbital energy ^{is 10 -47} J · m ÷ orbital or energy.

Which orbital photon is seen by the nocturnal animals?
Nocturnal animals are receiving ^10-7 m orbital photons emitted from atoms.
The energy of one photon of electricity is ^10-32 J.
The energy of one magnetic photon is 10 ⁻⁴⁸ J, and the energy of 10 ⁸ is 10 ⁻⁴⁰ J.
The above is summarized in a table.