CN2902996Y - Bearing middle part high speed automatic staircase or automatic footway mechanism - Google Patents
Bearing middle part high speed automatic staircase or automatic footway mechanism Download PDFInfo
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- CN2902996Y CN2902996Y CN 200620058915 CN200620058915U CN2902996Y CN 2902996 Y CN2902996 Y CN 2902996Y CN 200620058915 CN200620058915 CN 200620058915 CN 200620058915 U CN200620058915 U CN 200620058915U CN 2902996 Y CN2902996 Y CN 2902996Y
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Abstract
Disclosed is a load bearing central system for the high speed escalator or the moving sidewalk, comprising two parallel main guides, two parallel auxiliary guides, the multi-group support frames and the support bars, the main wheels at the lower end of the two sides of the support frames separately arranged on the parallel main guides. The adjacent support frames are connected with each other by a wire rope between a shaft of the support frame and a rack of the adjacent support frames. The utility model has the advantages that through the increase or decrease of the relative distance of the auxiliary and main guide surface, the wire rope used for connecting with adjacent system shrink or extend, making the relative distance of adjacent system correspondingly decrease or increase, thereby the speed of the bearing central of the high speed escalator or the moving sidewalk is faster than the operating speed of the position of passengers at the upper and lower.
Description
Technical field
The utility model relates to a kind of mechanism that is applied to the carrying middle part high-speed cruising of escalator or moving sidewalk.
Background technology
In recent years, be provided with a large amount of high-lift escalators and the moving sidewalk of long span in places such as subway station, adrms.For this class escalator and moving sidewalk, because the restriction of speed, the passenger must stand under the static state on step or the footway for a long time, has both allowed the people feel uncomfortable and has also expended time in.Therefore, the running velocity that needs to improve escalator and moving sidewalk is arranged, still, in order to make passenger safety escalator or moving sidewalk up and down, locating speed up and down the passenger can not be too fast.
The utility model content
In order to overcome above-mentioned defective, the utility model provides a kind of passenger the up and down slow and carrying middle part running velocity of the running speed mechanism of escalator or moving sidewalk faster, and the moving velocity of step or pavement is compared relatively with the speed that goes up hypomere step or pavement for the passenger and improved in the middle of making.
To achieve these goals, the utility model adopts following technical scheme:
Carrying middle part high speed escalator or moving sidewalk mechanism, it comprises two parallel main guide rails, two parallel auxiliary guide rails, organizes bracing frame, strut bar, tooth bar, guide groove, movable pulley, fixed pulley, steel cable more.The bracing frame side is provided with the strut bar guide groove symmetrically, and its effect is that strut bar can only be moved on the vertical direction of bracing frame.Strut bar is installed on the strut bar guide groove of bracing frame, and strut bar and strut bar guide groove contact surface are the plane, with the rich bracing frame rotation of restriction strut bar.Movable pulley is loaded on the strut bar, and fixed pulley is loaded on the main shaft.One end of steel cable is walked around movable pulley and is connected on the main shaft, and the other end faces the bolted connection on the tooth bar of bracing frame mutually by fixed pulley and another, and transmission device drives tooth bar, and tooth bar connects steel cable and drives the main axle moving of facing mutually on the bracing frame.Main shaft 6 is connected as a single entity the bracing frame both sides, and the main shaft two ends are separately installed with main wheel, and monosymmetric main wheel is installed in respectively on the two parallel main guide rails.Auxiliary wheel is fixed on strut bar symmetry down either side end, and monosymmetric auxiliary wheel is installed in respectively on the auxiliary guide rail, the speed change form of the curve shape of this auxiliary guide rail decision entire mechanism.Tooth bar one end is loaded on the main shaft of bracing frame, and the main shaft of can having mercy on rotates freely, and the tooth bar other end is provided with guide groove and connects with the main shaft that another faces bracing frame mutually, and this main shaft of can having mercy on rotates freely.
The utility model has the advantages that: the relative distance by auxiliary guide rail face and leading rail level increases or reduces, be used in and connect mutually the steel cable contraction or the extension of structure as the occasion requires, feasible phase is the corresponding minimizing of relative distance or the increase of structure as the occasion requires, thus the running velocity that the running velocity at the carrying middle part of escalator or moving sidewalk is located up and down faster than the passenger.
Description of drawings
Fig. 1 is a constructional drawing of the present utility model;
Fig. 2 is the left view of Fig. 1;
Fig. 3 is applied to the overall schematic of escalator for the utility model;
Fig. 4 is applied to the local amplification assumption diagram of escalator for the utility model;
Fig. 5 is applied to the cover plate partial enlarged drawing of escalator for the utility model;
Fig. 6 is applied to the overall schematic of moving sidewalk for the utility model;
Fig. 7 is applied to the cover plate partial enlarged drawing of moving sidewalk for the utility model;
Fig. 8 is transmission principle figure of the present utility model;
Fig. 9 ∽ Figure 13 is a calculating auxiliary view of the present utility model.
The specific embodiment
As Fig. 1 is the constructional drawing of bracing frame one side, and in conjunction with Fig. 2, shown in Figure 8, the bilateral symmetry of bracing frame 1 is respectively equipped with a strut bar guide groove 12, and its effect is that strut bar 2 can only be moved on the vertical direction of bracing frame.Strut bar 2 is installed on the monosymmetric strut bar guide groove 12 of bracing frame, and strut bar 2 is planes with strut bar guide groove 12 contacted two sides, with the rich bracing frame rotation of restriction strut bar.Movable pulley 3 is fixed on the strut bar 2, and fixed pulley 5 is fixed on the main shaft 6.One end of steel cable 4 is walked around movable pulley 3 and is connected on the main shaft 6, and the other end is crossed fixed pulley 5 and connected with the bolt 10 that another faces on the tooth bar 9 of bracing frame mutually, and transmission device drives tooth bar, and tooth bar connects steel cable and drives the main shaft 6 that faces mutually on the bracing frame and move.Main shaft 6 is connected as a single entity the bracing frame both sides, and main shaft both sides outermost end is separately installed with main wheel 8, and monosymmetric main wheel 8 is installed in respectively on the two parallel main guide rails 15.Auxiliary wheel 7 is fixed on the lower end of strut bar symmetry both sides, and monosymmetric auxiliary wheel 7 is installed in respectively on the auxiliary guide rail 15, the speed change form of the curve shape of this auxiliary guide rail decision entire mechanism.Tooth bar 9 one ends are loaded on the main shaft of bracing frame, and the main shaft of can having mercy on rotates freely, and the tooth bar other end is provided with a guide groove 11, and this guide groove connects with the main shaft that another faces bracing frame mutually, and this main shaft of can having mercy on rotates freely.
Figure 3 shows that the utility model is applied to the overall schematic of escalator, Fig. 4 is a partial enlarged drawing, Fig. 5 is applied to the cover plate partial enlarged drawing of escalator for the utility model, in conjunction with Fig. 3 and Fig. 4, shown in Fig. 5, the 21st, pedal, be used to support the pedestrian, the 22nd, riser, the 23rd, swash plate, pedal 21, riser 22 is connected with swash plate 23 rigidity, shape invariance, riser be shaped as curve, the position of curvilinear equation and second auxiliary guide rail 27 and the effective length of connecting rod 25 are relevant, concrete calculating with extensively the method for calculating of the common escalator riser shape of utilization is identical at present, 24 is support, effect is with pedal 21, riser 22, swash plate 23 and connecting rod 25 are connected as a single entity, connecting rod 25 is connected with main shaft, and the main shaft of can having mercy on rotates freely.26 is rollers, moves along second auxiliary guide rail 27, with control pedal 21 maintenance level in the process of whole conveying people.
The variation of motion process is as shown in Figure 4:
Making among the figure from left to right, each mechanism position is called position 1, position 2, position 3, position 4, position 5, position 6 along number.An existing A of mechanism from the position 1 through position 2, position 3, position 4, position 5 is to position 6 motions, the mechanism with it faces mutually on the A of mechanism the right is called the B of mechanism, the A of mechanism from the position 1 when move position 2 and the relative distance of the B of mechanism shortening, so the pedal 21 of the A of mechanism relatively moves along the swash plate 23 of the B of mechanism, when two mechanism's relative distances reach swash plate 23 and riser 22 boundarys that pedal 21 edges of the A of mechanism have the most in short-term arrived the B of mechanism, this moment, the relative distance of A of mechanism and the B of mechanism no longer shortened, escalator moves to horizontal segment, this moment, the main wheel of the B of mechanism began to move on curve, the roller 26 of the A of mechanism also begins in the motion of the segment of curve of second auxiliary guide rail, is in horizontality with the pedal 21 of maintaining body A.The pedal 21 of the A of mechanism moves along the riser 22 of the B of mechanism at this moment, because the track of its relative motion is a curve, so the shape of riser 22 is curves.When the main wheel of the A of mechanism arrives horizontal segment, the pedal 21 of the A of mechanism will with the pedal 21 of the B of mechanism on same horizontal surface.
Fig. 6 is applied to the overall schematic of moving sidewalk for the utility model, be the expression keystone configuration, omitted part-structure, 36 is moving sidewalk end caps among the figure, its effect be with the ground transition be connected, as Fig. 6, shown in Figure 7, the 31st, main pedal, the 34th, accessory pedal, main pedal 31 and accessory pedal 34 can support the pedestrian, and main pedal 31 is connected with brace 40 and straight-bar 37 rigidity.The 32nd, the accessory pedal guide rail, the 33rd, roller, the roller 33 of accessory pedal are loaded on mutually on the accessory pedal guide rail 32 of structure as the occasion requires, and accessory pedal 34 can be had mercy on and actively be connected 35 and rotate freely.Cross bar 38 connects main shaft and support roller 39, and support roller 39 is installed on second auxiliary guide rail 41.Straight-bar 37 connects support roller and main pedal 31, and brace 40 connects main shaft and main pedal 31.The structure of being made up of main shaft, cross bar 38, support roller 39, straight-bar 37 and brace 40 can guarantee that main pedal 31 remains level in load bearing process.When the distance of structure changed as the occasion requires mutually, accessory pedal 34 promptly can move freely along accessory pedal guide rail 32, and can bear the power of vertical direction.When the main wheel of mechanism moved to the end segment of curve, promptly main pedal will be when curve moves in the end, and accessory pedal 34 is rich actively to be connected 35 and rotate, and can force corresponding rolling wheel 33 to move on the accessory pedal guide rail simultaneously, shown in Fig. 5 end.
As shown in Figure 8, the motion process transmission principle is: from left to right residing five positions of mechanism are called position 1, position 2, position 3, position 4, position 5.Auxiliary wheel when mechanism is in position 2 is in the starting position of auxiliary guide rail segment of curve, the auxiliary guide rail face that is 2 left sides, position is parallel with leading rail level, the distance of 2 the right, position 4 auxiliary guide rail and main guide rail to the position is shortening, and the auxiliary guide rail face on 4 the right, position recovers parallel again with leading rail level.Suppose the A of mechanism from the position 2 to position 3 motion, because the auxiliary wheel of the B of another mechanism that its left side is faced mutually is in parallel-segment always, be the B of mechanism from the position 1 to the position 2, the main wheel of the B of mechanism and the distance of auxiliary wheel do not change, so going up the steel cable of the A of bindiny mechanism tooth bar, do not extend the B of mechanism, therefore identical by position 2 speed with the B of mechanism in 3 motion processes of position at the A of mechanism.The A of mechanism by position 3 when the motion of position 4, because the auxiliary wheel of the B of mechanism that faces mutually on the mechanism A left side has arrived the segment of curve of auxiliary guide rail, be that the B of mechanism is in the position 2, the B of mechanism from the position 2 when the motion of position 3 distance of main wheel and the auxiliary wheel of the B of mechanism in shortening, the corresponding minimizing of the movable pulley of the B of mechanism with the distance of fixed pulley, the B of mechanism goes up the steel cable of the A of bindiny mechanism tooth bar in elongation, because steel cable remains tensioning, therefore the A of mechanism speed at this moment can be faster than mechanism B, be that the A of mechanism 3 begins to have an acceleration/accel a1 from the position, this acceleration/accel is relevant to the curve shape of the auxiliary guide rail of position 3 with position 2.The A of mechanism by position 4 when the motion of position 5, the B of mechanism is moved to position 4 by position 3, the auxiliary wheel of the B of mechanism still moves at the segment of curve of auxiliary guide rail, therefore the distance of the main wheel of the B of mechanism and auxiliary wheel is shortening, the distance of corresponding movable pulley and fixed pulley is also reducing, the steel cable of the A of the bindiny mechanism tooth bar on the B of mechanism is in elongation, because steel cable remains tensioning, therefore the kinematic velocity of the A of mechanism relatively can be faster than mechanism B, be that the relative A of mechanism of the B of mechanism has an acceleration/accel a2 again, this acceleration/accel is relevant to the shape of the auxiliary guide rail of position 4 with position 3.Hence one can see that the A of mechanism is a1+a2 by position 4 acceleration/accel of relative main guide rail when 5 motions of position.The auxiliary wheel of the A of mechanism 5 B of mechanism when continuing to move right from the position is again to parallel-segment, and promptly the B of mechanism is in position 4, so the steel cable of the A of the bindiny mechanism tooth bar on the B of mechanism can not extend, therefore, the kinematic velocity of A of mechanism and the B of mechanism is consistent.And the like, the speed that is in position 5 the right mechanisms can be consistent.Make in the position 5 and mechanism's uniform movement on 5 the right, position need a1+a2=0.In like manner, if auxiliary guide rail length can allow two groups of above phases relative speed change of structure as the occasion requires, then need a1+a2+a3+ ... an=0
The mechanism kinematic form is calculated and the auxiliary guide rail design:
Suppose that the main wheel center of circle is Hmax to the ultimate range in the auxiliary wheel center of circle, minor increment is Hmin, the shortest distance of facing the center of circle in the main wheel motion process mutually is L, be steel cable when shrinking fully face mutually the main wheel distance of center circle from, then the ratio of the speed of (section of dropping off the guests on the elevator) is [2 (Hmax-Hmin)/L]+1 when speed during the elevator high speed and elevator low speed.Wherein the coefficient of algebraic expression (Hmax-Hmin)/L is by the canoe decision of fixed pulley and movable pulley or assembly pulley, since the length of guide groove less than L (more than or equal under the situation of L mutually as the occasion requires the distance of structure can disturb the most in short-term), 2 (Hmax-Hmin) are less than guide groove again, so 2 (Hmax-Hmin)/L+1＜2, if guide groove is designed to collapsible structure, then algebraic expression [2 (Hmax-Hmin)/L]+1 can be greater than 2.
Determine the speed and the acceleration/accel of mechanism's diverse location below according to the guide rail curve.
As shown in Figure 9:
Make that the main wheel deferent is the x axle, direction is crossed the auxiliary guide rail segment of curve and is made x axle vertical line with the horizon points of tangency to the right, makes that this line is the y axle, and direction makes progress, and makes the auxiliary wheel center of circle expression of path curves in this rectangular coordinate system be:
y＝f(x)……①
If the main wheel A center of circle is x1 to the initial point distance sometime, x1 is smaller or equal to L (L is for facing main wheel center of circle minor increment mutually), and this moment, main wheel A central coordinate of circle was (x1,0).Then be the center of circle with (x1,0) this moment, with the equation of the tangent circle of curve y=f (x) is:
(x-x1)
2+y
2＝R
2……②
R is the distance in the main wheel A center of circle and the auxiliary wheel center of circle, and 1. 2. substitution gets:
(x-x1)
2+f
2(x)＝R
2……③
Because circle is a tangent relation with curve, 3. equation is quadratic equation with one unknown, so equation root 3. must have only one, promptly the Δ value equals 0, and the size that can obtain R thus is R0.Main wheel A speed is Vmin this moment, supposes elapsed time Δ t (Δ t infinitely small), and the displacement of main wheel A is Δ tVmin, and then the coordinate in the main wheel A center of circle is (Δ tVmin+x1,0) at this moment.3. can get according to equation:
(x-Δt·Vmin-x1)
2+f
2(x)＝R
2……④
In like manner this equation also is a quadratic equation with one unknown, and its Δ value equals 0, and the R value that can obtain this moment is Rt, then
ΔR＝|R0-Rt|……⑤
Then the distance of the movable pulley of the main wheel A institution where he works and fixed pulley has shortened Δ R=|R0-Rt|, be this main wheel institution where he works be used to connect mutually as the occasion requires that the steel cable of structure has extended 2 Δ R=2|R0-Rt| on leading rail level, then by the steel cable institute bonded assembly the right in the main wheel A institution where he works mutually as the occasion requires the displacement of the main wheel B of structure be:
Δs＝2ΔR+Vmin·Δt……⑥
Promptly
Δs＝2|R0-Rt|+Vmin·Δt……⑦
Then the speed of main wheel B is the derivative of Δ s, that is:
V＝(2|R0-Rt|)’+Vmin……⑧
Then the acceleration/accel of main wheel B is the second derivative of Δ s, that is:
a＝(2|R0-Rt|)”……⑨
Because the second order inverse of algebraic expression Vmin Δ t is 0, so the size of acceleration/accel a and speed Vmin are irrelevant.
According to 3., the R value when making x1=L is R
L1, then during x1=L the position of main wheel B at (2Hmax-2R
L1, 0).
As from the foregoing:
As x1 during smaller or equal to L, the speed that is positioned at the relative guide rail of main wheel of (x1,0) is Vmin, and acceleration/accel is 0.
As x1 greater than L smaller or equal to (2Hmax-2R
L1) time, the speed that is positioned at the relative guide rail of main wheel of (x1,0) is V=(2|R0-Rt|) '+Vmin, promptly formula 8., acceleration/accel is a=(2|R0-Rt|) ", promptly formula 9..
As shown in figure 10: the center of circle of establishing main wheel A sometime is x1 to the initial point distance, x1 greater than L smaller or equal to (2Hmax-2R
L), then the coordinate in this main wheel center of circle is (x1,0), the position in the center of circle of establishing this moment the left side main wheel C that faces mutually with this main wheel is at (x ', 0), as shown in FIG., according to 2. getting
(x-x’)
2+f
2(x)＝R
2……⑩
According to the Δ value of this quadratic equation with one unknown is 0 can determine the relational expression of R ' and x '.Then center of circle this moment (x ', 0) to the distance in the center of circle (x1,0) is:
x1-x’＝L+2(Hmax-R’)……(11)
Solve an equation (11) can obtain the size of x ', 8. the substitution equation can obtain the speed V1 that the main wheel center of circle is positioned at the main wheel A that (x1,0) locates, with and acceleration/accel a1.3. get according to equation
(x-x1)
2+f
2(x)＝R
2……(12)
According to the Δ value of this quadratic equation with one unknown is 0 can determine the size of R1.The R value that in like manner can get behind the elapsed time Δ t (infinitely small) is Rt, then the steel cable institute bonded assembly the right by the main wheel A institution where he works mutually as the occasion requires the displacement of the relative main wheel B of the main wheel B of structure be:
Δs＝2|R1-Rt|……(13)
Then the speed of the relative main wheel A of main wheel B is the derivative of Δ s, and promptly the speed of main wheel B is:
V＝(2|R1-Rt|)’+V1……(14)
The second derivative of the acceleration/accel of the relative main wheel A of the main wheel B Δ s that is then
a2＝(2|R1-Rt|)”……(15)
The acceleration/accel that is main wheel B is:
a＝a1+a2……(16)
The acceleration/accel that is main wheel B is relevant with two sections curve shapes, and is irrelevant with speed Vmin.
According to 3., make x1=(2Hmax-2R
L1) time the R value be R
L2, x1=(2Hmax-2R then
L1) time main wheel B the position at (2Hmax-2R
L2, 0).
As from the foregoing:
When x1 greater than (2Hmax-2R
L) smaller or equal to (2Hmax-2R
L2) time, the speed that is positioned at the relative guide rail of main wheel of (x1,0) is V=(2|R1-Rt|) '+V1, i.e. formula (14), and acceleration/accel is a=a1+a2, i.e. formula (16).X1 is greater than (2Hmax-2R
L2) situation under method of calculating in like manner.
More than for mechanism is in the speed of accelerating sections and the method for calculating of acceleration/accel, the method for calculating that mechanism is in the speed of braking section and acceleration/accel is in like manner.
Following design calculation auxiliary guide rail
Acceleration and deceleration are steady when guaranteeing this device carrying passenger, and the shape of auxiliary guide rail need satisfy some conditions, and design calculation is as follows:
As shown in figure 11, circle 1 amplifies for the part to be done, and does not represent auxiliary wheel.Under the smaller situation of slope of a curve, the solid line of crossing point (x0,0) is the center of circle of main wheel A and the actual position of auxiliary wheel circle center line connecting, crosses point (x0+Vmin Δ t, 0) solid line was the actual position after the Δ t time, went up the line segment that corresponding dotted line is vertical and X-axis at 2.As shown in Fig. 1 enlarged drawing, the variable in distance of main wheel A and auxiliary wheel is Δ h=h behind the process Δ t, because curve is less at this slope over 10, so α is close with the β angle, the size of h and h ' is also approaching, so the size of available h ' is estimated the size of Δ h.Because of α is very little, so
Δh＝Vmin·Δt·sin?α……(17)
Then the steel cable institute bonded assembly the right by the main wheel A institution where he works mutually as the occasion requires the displacement of the relative main wheel A of main wheel B of structure be
Δs＝Vmin·Δt+2Vmin·Δt·sinα……(18)
Then the speed of the relative main wheel A of main wheel B is
V＝Δs’＝Vmin+2Vmin·sinα……(19)
Then the acceleration/accel of the relative main wheel A of main wheel B is
a＝V’＝(2Vmin·sin?α)’……(20)
Cause setting curve equation is y=f (x), then
sinα＝x/[x
2+f
2(x)]……(21)
Substitution (20) can get
a＝{2Vmin·x/[x
2+f
2(x)]}’……(22)
More than estimation only is used for the less situation in angle of inclination, can be used for initial setting and estimation.
As shown in Figure 12:
The length that makes the cooresponding main guide rail of auxiliary guide rail segment of curve is Ls, suppose that an auxiliary wheel A is in auxiliary guide rail segment of curve starting position, auxiliary wheel B is on the auxiliary guide rail segment of curve, and auxiliary wheel C is at auxiliary guide rail segment of curve end position, and they are made as A ', B ', C ' by cooresponding main wheel.The coordinate in the center of circle of the main wheel B ' that then mediates is (L, 0), 3. gets according to equation
(x-L)
2+f
2(x)＝R
2……(23)
This equation is a quadratic equation with one unknown, and its Δ value equals 0, can solve Rm, and the center of circle that then is in rightmost main wheel C ' is L+2 (Hmax-Rm) to the distance in the center of circle of middle main wheel B ', then this auxiliary guide rail segment of curve the length of corresponding main guide rail be
Ls＝2L+2(Hmax-Rm)……(24)
If the main wheel center of circle is a3 at the acceleration/accel of the relative main guide rail of main wheel on point (Ls, 0) the right, and is according to the front acceleration calculation, necessary
a3＝a1+a2＝0……(25)
Wherein 9. a1 can be by obtaining, and a2 can be obtained by (15), and there is functional relation (25) in the shape of curve A B section that hence one can see that and segment of curve BC, can try to achieve BC section curvilinear equation after promptly configuring AB section curvilinear equation.
Suppose
Ls＜2L+2Hmax-2Rm……(26)
Then auxiliary guide rail BC section falls short of, be that a2 has one section to equal 0, according to (25), then corresponding a1 must equal 0, i.e. (2|R0-Rt|) " to equal 0; and this section rate of curve is certain as can be known according to the character of second derivative, i.e. linear portion then has one section straight line in the auxiliary guide rail curve during Ls＜2L+2Hmax-2Rm as can be known.
As shown in figure 13:
Suppose
Ls＞2L+2Hmax-2Rm……(27)
Point A and some C remain auxiliary guide rail segment of curve starting position and the pairing auxiliary wheel home position of end position, and have only two auxiliary wheels between some A and the some C, have an auxiliary wheel center of circle to be positioned at a C this moment, point D and some B are respectively two other auxiliary wheel home positions that is positioned on the segment of curve, figure mid point (x1,0), (x2,0), (Ls, 0) represents corresponding main wheel home position respectively, as can be known according to (11)
x2-x1＝L+2Hmax-2R1……(28)
Wherein the relational expression of R1 and x1 can be obtained by (10).In like manner as can be known:
Ls-x2＝L+2Hmax-2R2……(29)
Wherein the relational expression of R2 and x2 can be obtained by (10), the group of then solving an equation (28) (29) can draw x1, the size of x2, promptly can determine a D and the position of putting B, in like manner can be positioned at point (Ls in the hope of the main wheel center of circle, 0) the acceleration/accel equation of the relative guide rail of the right main wheel, and this accekeration equals 0, promptly can determine BC section curvilinear equation.
As between fruit dot A and the some C plural auxiliary wheel being arranged, method of calculating in like manner.
As from the foregoing:
When auxiliary guide rail horizontal length Ls＜2L+2Hmax-2Rm, its curve middle part section of having straight line.Two sections curvilinear equations that linear portion separated satisfy a3=a1+a2=0, i.e. formula (25).
When auxiliary guide rail horizontal length Ls=2L+2Hmax-2Rm, its curve is formed by two sections, and these two sections curvilinear equations also satisfy a3=a1+a2=0, i.e. formula (25).
When auxiliary guide rail horizontal length Ls＞2L+2Hmax-2Rm, its curve is made up of multistage, and the acceleration/accel that is positioned at the main wheel on the horizontal segment on curve the right satisfies
a＝a1+a2+a3+…+an＝0。
More than for mechanism is in the auxiliary guide rail method of designing of accelerating sections, the auxiliary guide rail method of designing that mechanism is in braking section is in like manner.
Claims (1)
1. carry middle part high speed escalator or moving sidewalk mechanism, it is characterized in that: it comprises two parallel main guide rails, article two, parallel auxiliary guide rail, many group bracing frames, strut bar, the main wheel of lower end, bracing frame two sides is installed in respectively on two parallel main guide rails, be connected by the steel cable between the tooth bar on bracing frame main shaft and the adjacent supports frame between the adjacent supports frame, strut bar is installed on the bracing frame, the auxiliary wheel of strut bar both side ends is installed on two parallel auxiliary guide rails, bracing frame two sides symmetry is respectively equipped with a strut bar guide groove, strut bar is installed on the strut bar guide groove of bracing frame, strut bar and the contacted side of strut bar guide groove are the planes, movable pulley is loaded on the strut bar, fixed pulley is loaded on the main shaft, one end of steel cable is walked around movable pulley and is connected on the main shaft, and the other end faces the bolted connection on the tooth bar of bracing frame mutually by fixed pulley and another; Main shaft links into an integrated entity the bracing frame two sides, and the main shaft both side ends is equipped with main wheel, and monosymmetric main wheel is installed in respectively on the two parallel main guide rails; Auxiliary wheel is fixed on strut bar symmetry down either side end, and monosymmetric auxiliary wheel is installed on the auxiliary guide rail respectively; Tooth bar one end is loaded on the main shaft of bracing frame, and the tooth bar other end is provided with a guide groove, and this guide groove connects with the main shaft that another faces bracing frame mutually, and transmission device drives tooth bar.
Priority Applications (1)
| Application Number | Priority Date | Filing Date | Title |
|---|---|---|---|
| CN 200620058915 CN2902996Y (en) | 2006-05-16 | 2006-05-16 | Bearing middle part high speed automatic staircase or automatic footway mechanism |
Applications Claiming Priority (1)
| Application Number | Priority Date | Filing Date | Title |
|---|---|---|---|
| CN 200620058915 CN2902996Y (en) | 2006-05-16 | 2006-05-16 | Bearing middle part high speed automatic staircase or automatic footway mechanism |
Publications (1)
| Publication Number | Publication Date |
|---|---|
| CN2902996Y true CN2902996Y (en) | 2007-05-23 |
Family
ID=38078404
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| Application Number | Title | Priority Date | Filing Date |
|---|---|---|---|
| CN 200620058915 Expired - Fee Related CN2902996Y (en) | 2006-05-16 | 2006-05-16 | Bearing middle part high speed automatic staircase or automatic footway mechanism |
Country Status (1)
| Country | Link |
|---|---|
| CN (1) | CN2902996Y (en) |
Cited By (1)
| Publication number | Priority date | Publication date | Assignee | Title |
|---|---|---|---|---|
| CN107662867A (en) * | 2016-07-29 | 2018-02-06 | 奥的斯电梯公司 | The step roller monitoring of passenger conveyor and maintenance operation monitored by personnel |
-
2006
- 2006-05-16 CN CN 200620058915 patent/CN2902996Y/en not_active Expired - Fee Related
Cited By (1)
| Publication number | Priority date | Publication date | Assignee | Title |
|---|---|---|---|---|
| CN107662867A (en) * | 2016-07-29 | 2018-02-06 | 奥的斯电梯公司 | The step roller monitoring of passenger conveyor and maintenance operation monitored by personnel |
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Granted publication date: 20070523 |