CN1889185A - Method for coding high density optical disk modulating code - Google Patents

Method for coding high density optical disk modulating code Download PDF

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CN1889185A
CN1889185A CN 200610019694 CN200610019694A CN1889185A CN 1889185 A CN1889185 A CN 1889185A CN 200610019694 CN200610019694 CN 200610019694 CN 200610019694 A CN200610019694 A CN 200610019694A CN 1889185 A CN1889185 A CN 1889185A
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CN100547671C (en
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胡迪青
谢长生
刘丹
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Wuhan Guanggu Gaoqing Technology Development Co Ltd
Huazhong University of Science and Technology
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Abstract

一种用于高密度光盘的调制码的编码方法,其特征在于:采用游程长度RLL(1,10),码率取4/6;在源数据中加DC控制位,提高控制直流分量的能力;6位码字中满足d-k要求的码字共有21种,从中挑选出16种作为基本编码码字构成基本编码表,剩余的5种码字中首尾都为0的码字作为连接符,替换表就是基本码字与连接符的组合,替换表长为56;采用前视编码解决码字的级联冲突问题,每次调制时前视4个bit的源数据,若当前数据调制后的码字与前视数据调制后的码字级联有冲突,则用替换表中的码字代替这2组产生冲突的码字;否则,则对当前数据进行调制。具有比DVD高的容量和编码效率,单面双层容量可以达到13G,满足高清视频节目的要求。同时,其直流分量在可接受的范围内,最大DSV为DVD的2倍,码率比DVD提高33.3%,编码效率比DVD高一个百分点。

Figure 200610019694

A coding method for modulation codes for high-density optical discs, characterized in that: run length RLL (1, 10) is used, and the code rate is 4/6; DC control bits are added to the source data to improve the ability to control the DC component ; Among the 6-bit codewords, there are 21 kinds of codewords that meet the requirement of d-k, and 16 kinds of codewords are selected as the basic codewords to form the basic coding table. Among the remaining 5 codewords, the codewords whose beginning and end are 0 are used as connectors , the replacement table is the combination of basic codewords and connectors, and the length of the replacement table is 56; the lookahead encoding is used to solve the cascading conflict problem of codewords, and the source data of 4 bits is looked ahead at each modulation. If the current data is modulated If there is a conflict between the codewords and the concatenated codewords modulated by the forward-looking data, the codewords in the replacement table are used to replace the two groups of conflicting codewords; otherwise, the current data is modulated. It has higher capacity and encoding efficiency than DVD, and the single-sided and double-layer capacity can reach 13G, meeting the requirements of high-definition video programs. At the same time, its DC component is within an acceptable range, the maximum DSV is twice that of DVD, the code rate is 33.3% higher than DVD, and the coding efficiency is 1% higher than DVD.

Figure 200610019694

Description

用于高密度光盘的调制码的编码方法Coding method for modulation code used in high-density optical disk

                            技术领域Technical field

本发明属于光盘存储技术领域,具体涉及光盘调制码的设计,可以在高密度光存储设备中应用。The invention belongs to the technical field of optical disc storage, and in particular relates to the design of optical disc modulation codes, which can be applied in high-density optical storage devices.

                            技术背景 technical background

目前,传统的DVD碟片容量已无法满足观看高清晰视频节目的高容量要求,虽然国外已经出了蓝光光盘(其容量单面单层可以达到25G),但是其昂贵的成本使其在目前的市场中无法推广,因此,开发一种基于红光技术的高容量碟片势在必行。与此同时,我国DVD碟机的生产厂商因为DVD版权专利的问题,其生存受到很大威胁。为了摆脱昂贵的专利费负担,急需设计一种具有自有知识产权的新的多媒体光盘调制码,以使我国的多媒体碟机生产具有较强的市场竞争力。At present, the capacity of traditional DVD discs can no longer meet the high-capacity requirements for watching high-definition video programs. Although Blu-ray discs have been produced abroad (the capacity of which can reach 25G on a single side and a single layer), its expensive cost makes it in the current market. Can not promote in the market, therefore, it is imperative to develop a kind of high-capacity disc based on red light technology. At the same time, the survival of the manufacturers of DVD players in my country is greatly threatened because of the problem of DVD copyright patents. In order to get rid of the burden of expensive patent fees, it is urgent to design a new modulation code for multimedia discs with its own intellectual property rights, so that the production of multimedia disc players in our country has strong market competitiveness.

DVD的光盘调制编码特性如下:The modulation and coding characteristics of DVD discs are as follows:

1.编码原理1. Coding principle

DVD采用的是EFM-Plus调制码,游程长度为RLL(2,10),码率为8/16。当d=2,k=10时,码的最大容量为0.5418,故码率只能为1/2左右。DVD uses EFM-Plus modulation code, the run length is RLL (2, 10), and the code rate is 8/16. When d=2, k=10, the maximum capacity of the code is 0.5418, so the code rate can only be about 1/2.

EFM-Plus采用的是状态依赖固定长度分组码。在状态依赖码中,与一个固定长度的信源码字相关联的固定长度编码码字被设计为依赖于前一个编码码字。EFM-Plus码有4个状态,每一状态由进入、离开给定状态的码字的类型来划分。规定了划分条件后,可以引入ti,j表示4*4状态转移矩阵T中离开状态i而进入状态j的码字数。EFM-Plus uses state-dependent fixed-length block codes. In state-dependent codes, the fixed-length encoded codeword associated with a fixed-length source codeword is designed to depend on the previous encoded codeword. The EFM-Plus code has 4 states, and each state is divided by the type of codeword entering and leaving a given state. After specifying the division conditions, t i, j can be introduced to represent the number of codewords in the 4*4 state transition matrix T that leave state i and enter state j.

TT == 138138 9696 9696 22twenty two 145145 9090 9090 2727 132132 102102 102102 1515 164164 113113 113113 2525

从T的每一行中看出,从每一个状态至少有351个码字输出。编码器把输入的源码字指派给每一状态中的351个输出码字与之对应,超出的码字被删除。设立对应关系后,给出源码字和给定编码器状态,则编码器就可输出相应的通道码字,同时还给出下一状态的信息。由于输入只需容纳256个源码字,故EFM-Plus有2张编码表,一张是256项的主表(见图1),另一张是87项的备选表(见图2),这样编码时前87个源码字就有2张表可选,从而达到控制减小低频成分的作用。From each row of T, there are at least 351 codewords output from each state. The encoder assigns the input source codewords to the corresponding 351 output codewords in each state, and the excess codewords are deleted. After the corresponding relationship is established, given the source codeword and the given encoder state, the encoder can output the corresponding channel codeword, and at the same time give the information of the next state. Since the input only needs to accommodate 256 source code words, EFM-Plus has 2 coding tables, one is a main table with 256 items (see Figure 1), and the other is an alternative table with 87 items (see Figure 2). In this way, there are 2 tables for the first 87 source code words to choose during encoding, so as to achieve the effect of controlling and reducing low-frequency components.

2.解码原理2. Decoding principle

当前的通道码加下一个通道码的X3位和X15位,即可解出信源码字。The current channel code plus X 3 bits and X 15 bits of the next channel code can solve the source code word.

              B(t)=H-1{X(t),X15(t+1),X3(t+1)}B(t)=H -1 {X(t), X 15 (t+1), X 3 (t+1)}

3.直流控制3. DC control

EFM-Plus的低频成分抑制或直流控制的方法是控制码字的RDS(Running digitalsum)。多出的88个通道码用来作为源码字0-87个备选通道码,选择备选通道码的原则是使整体通道码的RDS最小。The low-frequency component suppression or DC control method of EFM-Plus is to control the RDS (Running digital sum) of the codeword. The extra 88 channel codes are used as the source code word 0-87 candidate channel codes, and the principle of selecting the candidate channel codes is to minimize the RDS of the overall channel codes.

同时,同步码的选择也可以帮助控制RDS。EFM-Plus设计了7组同步码(见图3),一定状态下的同步码可以在主同步码和备选同步码中选择,从而得到较小的DSV(Digital Sum Value)。At the same time, the choice of synchronization code can also help to control RDS. EFM-Plus has designed 7 sets of synchronization codes (see Figure 3). The synchronization codes in a certain state can be selected from the main synchronization code and the alternative synchronization code, so as to obtain a smaller DSV (Digital Sum Value).

另外,88到255的源码字进行编码时,若状态为1或4,则可以在1状态或者4状态中选择一个编码码字,在满足游程长度限制的前提下,选择的标准为DSV越小越好。该调制码的主要不足为:In addition, when encoding source codewords from 88 to 255, if the state is 1 or 4, you can select an encoding codeword in 1 state or 4 state. Under the premise of satisfying the run length limit, the selection standard is that the smaller the DSV the better. The main disadvantages of this modulation code are:

容量较小,DVD的调制码取的RLL参数d=2,码的最大容量为0.5418,故码率只能为1/2左右,这对于新一代高密度红光光盘单面15GB的标准是不够的,编码效率有待提高。The capacity is small, the RLL parameter d=2 is taken by the modulation code of DVD, and the maximum capacity of the code is 0.5418, so the code rate can only be about 1/2, which is not enough for the standard of 15 GB per side of a new generation of high-density red-ray disc Yes, the coding efficiency needs to be improved.

                              发明内容Contents of Invention

本发明的目的是设计一种用于高密度光盘的调制码的编码方法,适合NVD(下一代通用光盘)通道特性的调制编码,该调制码具有更高的编码效率,以使光盘具有较大的有效存储容量,其直流分量控制能力不下降太多。The purpose of this invention is to design a kind of coding method for the modulation code of high-density optical disk, the modulation coding that is suitable for NVD (next generation universal optical disk) channel characteristic, this modulation code has higher coding efficiency, so that the optical disk has larger The effective storage capacity, its DC component control ability does not drop too much.

本发明的技术方案是:一种用于高密度光盘的调制码的编码方法,其特征在于:采用游程长度RLL(1,10),码率取4/6;在源数据中加DC控制位,提高控制直流分量的能力;The technical scheme of the present invention is: a kind of coding method for the modulation code of high-density optical disk, it is characterized in that: adopt run-length length RLL (1,10), code rate is taken 4/6; Add DC control bit in source data , improve the ability to control the DC component;

6位码字中满足d-k要求的码字共有21种,从中挑选出16种作为基本编码码字构成基本编码表,剩余的5种码字中首尾都为0的码字作为连接符,替换表就是基本码字与连接符的组合,替换表长为56;Among the 6-bit codewords, there are 21 kinds of codewords that meet the requirements of d-k, and 16 kinds of them are selected as the basic coding codewords to form the basic coding table. Among the remaining 5 kinds of codewords, the codewords with 0 at the beginning and the end are used as connectors, and the replacement table It is the combination of basic codewords and connectors, and the replacement table length is 56;

采用前视编码解决码字的级联冲突问题,每次调制时前视4个bit的源数据,若当前数据调制后的码字与前视数据调制后的码字级联有冲突,则用替换表中的码字代替这2组产生冲突的码字;否则,则对当前数据进行调制。Use look-ahead coding to solve the problem of cascading conflicts of codewords. For each modulation, look forward to 4 bits of source data. The code words in the replacement table replace the two groups of conflicting code words; otherwise, the current data is modulated.

如上所述的用于高密度光盘的调制码的编码方法,其特征在于:在源数据中每隔288字节加入一个P控制位,调制后选择DSV较小的P来实现对DSV的控制。The method for encoding modulation codes for high-density optical discs as described above is characterized in that a P control bit is added every 288 bytes in the source data, and after modulation, P with a smaller DSV is selected to control the DSV.

如上所述的用于高密度光盘的调制码的编码方法,其特征在于:对调制后的数据每108字节加入同步码,同步码有2组,根据当前码字的状态加入。The method for encoding modulation codes for high-density optical discs as described above is characterized in that a synchronization code is added to the modulated data every 108 bytes, and there are 2 groups of synchronization codes, which are added according to the state of the current code word.

本发明的基本原理是:Basic principle of the present invention is:

1.较长的通道位长度和较高的码率1. Longer channel bit length and higher code rate

(d=1,k=10)的限制表明实际记录斑点的游长在2T到11T之间,其中T为通道位长度。理论上(d=1,k=10)的码容量为0.6909,设计中取码率为4/6;与此对照,(d=2,k=10)的码容量为0.5418,而EFM码的码率为8/17,EFM+的码率为8/16=1/2。因此本调制码具有较高的效率,增加了记录容量。The constraint of (d=1, k=10) indicates that the run length of the actual recording spot is between 2T and 11T, where T is the channel bit length. Theoretically the code capacity of (d=1, k=10) is 0.6909, and the code fetching rate is 4/6 in the design; In contrast, the code capacity of (d=2, k=10) is 0.5418, while the EFM code The code rate is 8/17, and the code rate of EFM+ is 8/16=1/2. Therefore, the modulation code has higher efficiency and increases the recording capacity.

RLL调制码有2个重要的性能指标:调制率和密度率。调制率R=m/n,R越大表明编码的效率越高;密度率DR=R(1+d),DR表示的是调制方式对存储密度的提高能力。表4比较了RLL(1,10)码和当前几种流行的RLL调制码的主要性能参数指标。RLL modulation codes have two important performance indicators: modulation rate and density rate. The modulation rate R=m/n, the larger the R is, the higher the encoding efficiency is; the density rate DR=R(1+d), DR represents the ability of the modulation method to improve the storage density. Table 4 compares the main performance parameter indexes of RLL (1, 10) codes and several popular RLL modulation codes at present.

2.在源数据的比特流中添加DC控制位2. Add DC control bits to the bitstream of the source data

与EFM及EFM+中DC控制位添加在通道位码流中不同,(1,10)调制码的DC控制位是添加在源数据的比特流中。举例说明如下:Unlike EFM and EFM+, where the DC control bits are added to the channel bit stream, the DC control bits of the (1, 10) modulation code are added to the source data bit stream. Examples are as follows:

考虑源数据比特流“P010 0110”,其中‘P’为添加的DC控制位(或称合并位)。如果‘P’=‘1’,那么经过调制后(参考表3)得到“100010 010010”,再经过一次NRZI转换得到“000011 100011”,其数字游程和DSV=+1;如果‘P’=‘0’,那么经过调制后得到“001001 010010”,再经过一次NRZI转换得到“110001 100011”,其数字游程和DSV=0。这样通过选择合适的‘P’的取值,就可以控制DSV的极性,从而控制记录信号的直流成分和低频分量。并且,在源数据中添加DC控制位的开销也比较小,约为0.1494%;与此对照,EFMPlus码在码字流中添加DC控制位,开销约为58%。Consider the source data bit stream "P010 0110", where 'P' is the added DC control bit (or merging bit). If 'P'='1', after modulation (refer to Table 3), "100010 010010" is obtained, and then NRZI conversion is performed to obtain "000011 100011", and its digital run length and DSV=+1; if 'P'=' 0', then "001001 010010" is obtained after modulation, and "110001 100011" is obtained through NRZI conversion again, and its digital run length and DSV=0. In this way, by selecting an appropriate value of 'P', the polarity of the DSV can be controlled, thereby controlling the DC component and low frequency component of the recording signal. Moreover, the overhead of adding DC control bits in the source data is relatively small, about 0.1494%. In contrast, the EFMPlus code adds DC control bits in the codeword stream, and the overhead is about 58%.

3.采用前视编码3. Use look-ahead coding

根据即将到来的编码码字情况来确定对当前的编码码字是否应该替换为另一种编码码字。It is determined whether the current codeword should be replaced with another codeword according to the situation of the codeword to come.

6位码字中满足d-k要求的码字共有21种,以‘1‘结尾和以‘1’开头的码字级联就会产生d的冲突,因此根据尽量减少冲突但又要预留足够连接符的原则,从中挑选出16种作为基本编码码字。There are 21 codewords that meet the requirements of d-k in the 6-bit codeword. The concatenation of codewords ending with '1' and starting with '1' will cause d conflicts. Therefore, according to minimize conflicts but reserve enough connections According to the principle of symbols, 16 kinds are selected as the basic coding codewords.

基本编码表中,每个码字本身均符合游程长度的限制,而它们中的部分码字进行级联时则将违反游程长度的限制,如A与I级联则违反d的限制。因此当这样的码字级联时,就用替换表中的码字代替。替换表由基本码字与连接符的组合构成。In the basic coding table, each codeword itself conforms to the limit of the run length, and some codewords in them will violate the limit of the run length when they are concatenated. For example, the concatenation of A and I will violate the limit of d. Therefore, when such codewords are concatenated, they are replaced with the codewords in the substitution table. The substitution table consists of the combination of basic codewords and connectors.

且替换时,若原码字以0开头,则替换后的码字也必须以0开头,否则会产生新的冲突。And when replacing, if the original codeword starts with 0, then the replaced codeword must also start with 0, otherwise new conflicts will occur.

4.同步码的设计4. Design of synchronization code

有2组同步码:“100000000000”和“000000000001”。There are 2 sets of synchronization codes: "100000000000" and "000000000001".

对编码后的数据每108字节加入同步码,若当前通道码字状态为0(即‘0’开头)则加入同步码“000000000001”;若当前通道码字状态为1(即‘1’开头)则加入同步码“100000000000”。Add a synchronization code to the encoded data every 108 bytes. If the current channel code word status is 0 (that is, start with '0'), add the synchronization code "000000000001"; if the current channel code word status is 1 (that is, start with '1' ) then add the synchronization code "100000000000".

本发明的优点和有益效果是:Advantage and beneficial effect of the present invention are:

采用游程长度RLL(1,10),有较长的通道位长度和较大的码容量;码率取4/6,有较高的编码效率;采用前视(look-ahead)编码,解决码字的级联冲突问题;在源数据中加DC控制位,提高控制直流分量的能力。利用本发明申请提出的调制编码方法,将源数据进行4/6的调制,编码效率比EFM-Plus增加1%,并通过添加DC控制位,大大降低了直流分量,比未添加时降低约90%。The run length RLL (1, 10) is used, which has a longer channel bit length and a larger code capacity; the code rate is 4/6, which has a higher coding efficiency; the look-ahead (look-ahead) coding is used to solve the code Word cascading conflicts; add DC control bits to the source data to improve the ability to control the DC component. Using the modulation and coding method proposed in the application of the present invention, the source data is modulated by 4/6, and the coding efficiency is increased by 1% compared with EFM-Plus, and by adding DC control bits, the DC component is greatly reduced, which is about 90% lower than that without adding %.

具有比DVD高的容量和编码效率,单面双层容量可以达到13G,满足高清视频节目的要求。同时,其直流分量在可接受的范围内,最大DSV为DVD的2倍,码率比DVD提高33.3%,编码效率比DVD高一个百分点。It has higher capacity and encoding efficiency than DVD, and the single-sided and double-layer capacity can reach 13G, meeting the requirements of high-definition video programs. At the same time, its DC component is within an acceptable range, the maximum DSV is twice that of DVD, the code rate is 33.3% higher than DVD, and the coding efficiency is 1% higher than DVD.

                         附图说明Description of drawings

图1,是表1部分的EFM-Plus编码表主表。Figure 1 is the main table of the EFM-Plus coding table in Table 1.

图2,是表2部分的EFM-Plus编码表备选表。Figure 2 is the EFM-Plus coding table alternative table in Table 2.

图3,是表3EFM-Plus的同步码。Figure 3 is the synchronization code of Table 3 EFM-Plus.

图4,是表4RLL调制方式主要性能参数的比较。Fig. 4 is a comparison of main performance parameters of the RLL modulation modes in Table 4.

图5,是表5本发明实施例的RLL(1,10)调制基本编码表。FIG. 5 is a table 5 of the RLL (1, 10) modulation basic coding table of the embodiment of the present invention.

图6,是表6针对d=1限制的替换表。Fig. 6 is a replacement table for the restriction of d=1 in Table 6.

图7,本发明实施例的多媒体数据调制编码流程图1。FIG. 7 is a flow chart 1 of multimedia data modulation and encoding according to an embodiment of the present invention.

图8,本发明实施例的多媒体数据调制编码流程图2。FIG. 8 is a flow chart 2 of multimedia data modulation and encoding according to an embodiment of the present invention.

图9,本发明实施例的解码流程图。Fig. 9 is a decoding flowchart of the embodiment of the present invention.

                        具体的实施方式Specific implementation methods

本发明的实施例通过图5(表5)、图6(表6)、图8和图9给予了表述。以下结合附图(表),做进一步的描述。Embodiments of the present invention are represented by FIG. 5 (Table 5), FIG. 6 (Table 6), FIG. 8 and FIG. 9 . Below in conjunction with accompanying drawing (table), do further description.

1.基本编码表设计1. Basic coding table design

基本编码表见图5,有码字16种。满足d=1,k=10的6bit长的码字一共有21种,从中挑选出16种作为基本编码码字。The basic coding table is shown in Fig. 5, and there are 16 kinds of code words. There are altogether 21 kinds of 6-bit long codewords satisfying d=1, k=10, and 16 kinds are selected as basic coding codewords.

首先根据基本编码表编码,当当前码字与前视码字调制后的编码码字级联无冲突时,则采用基本编码表中的编码码字。Firstly, it is coded according to the basic coding table. When there is no conflict between the current code word and the code word modulated by the look-ahead code word, the code word in the basic coding table is used.

一般来说,DC控制的方法就是让尽可能多的输入码字经过调制后有2种可选的码字,且这2个码字中“1”的极性不同。由于本设计考虑采用的DC控制方法是在源码中加入DC控制位,所以设计码表时就要使源码中汉明距离为1的源码码字对应的编码码字“1”的极性相反。例如,“0000”对应的编码码字“1”的极性为奇数,则“0001”、“0010”、“0100”和“1000”对应的编码码字“1”的极性就为偶数。Generally speaking, the method of DC control is to allow as many input codewords as possible to have two optional codewords after modulation, and the polarities of "1" in these two codewords are different. Since the DC control method considered in this design is to add DC control bits to the source code, when designing the code table, the polarity of the code word "1" corresponding to the source code word with a Hamming distance of 1 in the source code must be reversed. For example, the polarity of the encoded codeword "1" corresponding to "0000" is odd, and the polarity of the encoded codeword "1" corresponding to "0001", "0010", "0100" and "1000" is even.

2.替换码表设计2. Replacement code table design

把当前4位码字称为P,把下一个4位码字称为S。针对d=1限制的替换表见图6。The current 4-bit codeword is called P, and the next 4-bit codeword is called S. See Figure 6 for a substitution table for the d=1 constraint.

基本编码表中的16种码字,其中有的码字可以与任何其他的编码码字级联而不会违反d的限制,如000010,像这样的码字就作为“连接符”。Among the 16 codewords in the basic coding table, some codewords can be concatenated with any other codewords without violating the restriction of d, such as 000010, and such codewords are used as "connectors".

当基本编码表中的码字产生级联冲突时,就用一个基本码字加上一个连接符来代替原来相冲突的2个基本码字,解决级联的冲突。如:0000与1000级联时,查基本编码表(见图5)的码字得到100001.100000,产生了d的冲突,因此查替换表(见图6),得到替换码字:000001.001010来代替原基本码字,解决了d的冲突。When the codewords in the basic coding table produce cascading conflicts, a basic codeword plus a connector is used to replace the original two conflicting basic codewords to resolve the cascading conflicts. For example: when 0000 and 1000 are cascaded, look up the codeword of the basic code table (see Figure 5) to get 100001.100000, which produces a conflict of d, so check the replacement table (see Figure 6), and get the replacement codeword: 000001.001010 to replace the original basic The codeword resolves the conflict of d.

由于基本编码表中以“1”结尾的码字共有7个,以“1”开头的码字有8个,因此共有56种级联冲突,因此替换表长为56(见图6)。Since there are 7 codewords ending with "1" and 8 codewords starting with "1" in the basic coding table, there are 56 kinds of cascading conflicts in total, so the replacement table length is 56 (see Figure 6).

3.同步码设计3. Synchronous code design

2组同步码:000000000001和100000000000。2 sets of synchronization codes: 000000000001 and 100000000000.

当前状态为0(同步码后面的码字首位为‘0’),选择同步码000000000001;当前状态为1(同步码后面的码字首位为‘1’),选择同步码100000000000。这样可以保证同步码与数据码字的连接不违反d的规定。由于k=10,所以当检测到超过11T的信号时,即可判定出现了同步码。If the current state is 0 (the first digit of the code word after the synchronization code is '0'), select the synchronization code 000000000001; if the current state is 1 (the first digit of the code word after the synchronization code is '1'), select the synchronization code 100000000000. This can ensure that the connection of the synchronization code and the data code word does not violate the regulation of d. Since k=10, when a signal exceeding 11T is detected, it can be determined that a synchronization code has appeared.

4.编码流程4. Coding process

编码流程如图7和图8所示。其中,encode()的过程如下:The encoding process is shown in Figure 7 and Figure 8. Among them, the process of encode() is as follows:

1)向编码器中输入4位码字和下一个4位码字;1) Input the 4-bit codeword and the next 4-bit codeword into the encoder;

2)根据RLL(1,10)调制的基本编码表对当前4位输入码字和下一4位码字进行码型变换,得到2个6位的码字P和S;2) According to the basic coding table modulated by RLL (1, 10), the current 4-bit input codeword and the next 4-bit codeword are converted into code patterns to obtain two 6-bit codewords P and S;

3)判断码字P和S是否违反d=1的限制,若是,则按照针对d=1限制的替换表对P和S进行替换,得到合法的新P和新S,然后进入步骤4);若否,直接进入步骤5);3) judge whether codeword P and S violate the restriction of d=1, if so, then replace P and S according to the substitution table for d=1 restriction, obtain legal new P and new S, then enter step 4); If not, go directly to step 5);

4)在当前时钟输出码字P,进行等待,在下一时钟输出码字S,然后回到步骤1),循环上述步骤,直到编码完毕;4) Output the code word P at the current clock, wait, output the code word S at the next clock, then get back to step 1), and cycle the above steps until the encoding is completed;

5)在当前时钟输出码字P,把S赋给P作为新的当前码字;读入下一个4位码字,并根据RLL(1,10)调制的基本编码表对新的4位码字进行码型变换得到新的S,然后回到步骤3);若已到文件结束没有码字可以读入,则直接在下一时钟输出码字P;循环上述步骤,直到编码完毕。5) Output codeword P at the current clock, assign S to P as a new current codeword; read in the next 4-bit codeword, and perform a new 4-bit code according to the basic code table modulated by RLL (1, 10) Word is carried out code pattern conversion to obtain new S, then returns to step 3); If no code word can be read in at the end of the file, then directly output code word P at the next clock; cycle above-mentioned steps, until coding finishes.

5.解码流程5. Decoding process

编码流程如图9所示。其中,decode()的过程如下:The encoding process is shown in Figure 9. Among them, the process of decode() is as follows:

1)向解码器中输入6位码字P和下一码字6位S;1) Input 6-bit codeword P and next codeword 6-bit S in the decoder;

2)判断P和Q是否是为了消除违反d=1限制而用来替换的特殊码字,若是,则根据编码时采用的针对d=1限制的替换表对码字P和S进行变换,然后进入步骤3);若否,则直接进入步骤4);2) judge whether P and Q are special codewords used for replacement in order to eliminate violations of the d=1 restriction, if so, transform the codewords P and S according to the substitution table for the d=1 restriction adopted during encoding, and then Enter step 3); if not, then directly enter step 4);

3)在当前时钟输出码字P的变换,在下一时钟输出码字S的变换,然后回到步骤1),直到解码结束;3) output the conversion of the codeword P at the current clock, and output the conversion of the codeword S at the next clock, then get back to step 1), until the end of decoding;

4)根据编码时采用的RLL(1,10)调制基本编码表对P进行变换,并在当前时钟输出码字P的变换,把S赋给P,并读入新的6位码字S,然后回到步骤2,直到解码结束。4) Transform P according to the RLL (1, 10) modulation basic coding table adopted during encoding, and output the transformation of codeword P at the current clock, assign S to P, and read in a new 6-bit codeword S, Then go back to step 2 until the decoding ends.

本发明实施方案中,调制编码的评估如下:In the embodiment of the present invention, the evaluation of modulation coding is as follows:

根据高密度光盘多媒体应用的特点,对源数据进行了RLL(1,10;4,6)的调制编码。According to the characteristics of high-density optical disc multimedia applications, the source data is modulated and coded by RLL (1, 10; 4, 6).

其容量比DVD的调制码增加了33.3%,编码效率提高了一个百分点。Its capacity is 33.3% higher than the modulation code of DVD, and the coding efficiency is increased by one percentage point.

最大DSV比不加DC控制位时减小了1到2个数量级,但最大值约为DVD的2倍。The maximum DSV is reduced by 1 to 2 orders of magnitude than without the DC control bit, but the maximum value is about 2 times that of DVD.

因此,该调制码具有应用于高密度光盘提高光盘有效存储容量的可行性。Therefore, the modulation code has the feasibility of being applied to a high-density optical disc to improve the effective storage capacity of the optical disc.

Claims (3)

1、一种用于高密度光盘的调制码的编码方法,其特征在于:采用游程长度RLL(1,10),码率取4/6;在源数据中加DC控制位,提高控制直流分量的能力;1, a kind of coding method that is used for the modulation code of high-density optical disk, it is characterized in that: adopt run length RLL (1,10), code rate gets 4/6; Add DC control bit in source data, improve control DC component Ability; 6位码字中满足d-k要求的码字共有21种,从中挑选出16种作为基本编码码字构成基本编码表,剩余的5种码字中首尾都为0的码字作为连接符,替换表就是基本码字与连接符的组合,替换表长为56;Among the 6-bit codewords, there are 21 kinds of codewords that meet the requirements of d-k, and 16 kinds of them are selected as the basic coding codewords to form the basic coding table. Among the remaining 5 kinds of codewords, the codewords with 0 at the beginning and the end are used as connectors, and the replacement table It is the combination of basic codewords and connectors, and the replacement table length is 56; 采用前视编码解决码字的级联冲突问题,每次调制时前视4个bit的源数据,若当前数据调制后的码字与前视数据调制后的码字级联有冲突,则用替换表中的码字代替这2组产生冲突的码字;否则,则对当前数据进行调制。Use look-ahead coding to solve the problem of cascading conflicts of codewords. For each modulation, look forward to 4 bits of source data. The code words in the replacement table replace the two groups of conflicting code words; otherwise, the current data is modulated. 2、如权利要求1所述的用于高密度光盘的调制码的编码方法,其特征在于:在源数据中每隔288字节加入一个P控制位,调制后选择DSV较小的P来实现对DSV的控制。2. The encoding method for modulation codes for high-density optical discs as claimed in claim 1, characterized in that: a P control bit is added every 288 bytes in the source data, and after modulation, a P with a smaller DSV is selected to realize Control over DSVs. 3、如权利要求1或2所述的用于高密度光盘的调制码的编码方法,其特征在于:对调制后的数据每108字节加入同步码,同步码有2组,根据当前码字的状态加入。3. The encoding method for modulation codes used in high-density optical discs as claimed in claim 1 or 2, characterized in that: a synchronization code is added to the modulated data every 108 bytes, there are 2 groups of synchronization codes, according to the current codeword status is added.
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CN111384962A (en) * 2018-12-28 2020-07-07 上海寒武纪信息科技有限公司 Data compression/decompression device and data compression method
CN111384963A (en) * 2018-12-28 2020-07-07 上海寒武纪信息科技有限公司 Data compression/decompression device and data decompression method
WO2025021045A1 (en) * 2023-07-25 2025-01-30 华为技术有限公司 Data modulation and coding method and apparatus

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JP3985173B2 (en) * 1998-05-29 2007-10-03 ソニー株式会社 Modulation apparatus and method, demodulation apparatus and method, and data storage medium
JP4461859B2 (en) * 2004-03-18 2010-05-12 富士ゼロックス株式会社 Run-length code decoding apparatus

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CN111384963A (en) * 2018-12-28 2020-07-07 上海寒武纪信息科技有限公司 Data compression/decompression device and data decompression method
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