CN1246867C - Low-consumption inductance ballast - Google Patents

Abstract

The present invention discloses a low consumption inductance ballast, which relates to a low consumption inductance ballast with ballasting effect. The present invention proposes a solution to the problem that the existing inductance ballast is large. The low consumption inductance ballast utilizes a resonance theory to make the magnetic field energy and the electric energy of an inductance ballast in a circuit obtain sufficient conversion on a load. Compared with the existing ballast m the present invention has the advantages of obvious effect on energy saving and production material saving.

Description

A kind of method that reduces Inductive ballast power consumption in the circuit

Technical field

The present invention relates to a kind of method that is used for reducing circuit inductance ballast power consumption.

Background technology

In the existing Inductive ballast technology, Inductive ballast is very big to the power consumption of self in the load ballast in circuit.For example, the Inductive ballast that is used for all gases discharge lamp generally is about 20% of lamp power, and with world-renowned brand 40W fluorescent lamp, circuital current is 0.41A, and ballast instrumental music is reduced to 168V, and the fluorescent tube pressure drop is 108V, and the ballast oneself power consumption is 8W.

In the design of existing Inductive ballast (for example fluorescent lamp Inductive ballast) if satisfy " electronic energy-saving lamp and electric ballast " (P14-15) formula in gets final product for People's Telecon Publishing House, 2004 the 1st time printed copy:

Area of core section: $S=0.75\sqrt{P}\left({\mathrm{cm}}^2\right)$

The ballast operating voltage: $U_0=\sqrt{\frac{{{\mathrm{<figure-callout\; id="1"\; label="U"\; filenames="C20041001275000071.png"\; state="\{\{state\}\}">U</figure-callout>}}_1}^2-{{1.5\mathrm{<figure-callout\; id="1"\; label="U"\; filenames="C20041001275000071.png"\; state="\{\{state\}\}">U</figure-callout>}}_1}^2}{1.15}}\left(V\right)$

Umber of turn: $N=\frac{U_0}{4.44\mathrm{fBS}}\&times;{10}^4$

The winding conducting wire diameter: $d=1.13\sqrt{\frac{I_L}{J}}\left(\mathrm{mm}\right)$

Wherein, P is lamp rated power (W), U ₁Be supply voltage (v), U _LBe light working voltage (V) that f is supply frequency (50Hz), B is magnetic flux density (Gauss), I _LBe lamp operating current (A) that J is the nominal current density (A/mm of lead ²).

With above-mentioned existing design formula, for example just can determine area of core section, umber of turn, winding conducting wire diameter to the requirement of operating voltage according to the requirement of designed Inductive ballast.

Summary of the invention

The present invention aims to provide a kind of method that reduces Inductive ballast power consumption in the circuit, wherein this circuit comprises load and the Inductive ballast that plays the ballast effect, described Inductive ballast comprises iron core (1) and coil windings (2), by reducing Inductive ballast pressure drop in the circuit, make ballast pressure drop and load pressure drop satisfy following relation :-12.2%≤(ballast pressure drop-load pressure drop)/load pressure drop * 100%≤+ 12.2%; Preferably make ballast pressure drop and load pressure drop satisfy following relation :-10.8%≤(ballast pressure drop-load pressure drop)/load pressure drop * 100%≤+ 10.8%; More preferably make ballast pressure drop and load pressure drop satisfy following relation :-0.9%≤(ballast pressure drop-load pressure drop)/load pressure drop * 100%≤+ 0.9% equals the load pressure drop; Most preferably make the ballast pressure drop equal the load pressure drop.

The Inductive ballast that uses among the present invention, include iron core (1), coil windings (2), based on the pressure drop of Inductive ballast and the relation of load (3) pressure drop in the calculating formula basis circuit that provides of existing inductance type ballast, just can select the every structure and the voltage parameter of corresponding Inductive ballast.This method is utilized resonance principle, and the magnetic field energy and the electric energy that work in the circuit inductance ballast are changed in load fully.Compare with existing Inductive ballast under the identical situation of power that load obtains, the meritorious power consumption of Inductive ballast circuit has been compared with the meritorious power consumption of existing Inductive ballast circuit significantly and has been reduced, and circuit power factor improves, and reduces with copper with iron.

The existing Inductive ballast circuit that is used for gaseous discharge lamp does not have feature of the present invention.As supply power voltage is that the pressure drop of the 20W fluorescent lamp Inductive ballast of 220V is 200V, the pressure drop of load (fluorescent tube) is 60V, the pressure drop of 150W high-pressure sodium lamp Inductive ballast is 192V, load (fluorescent tube) pressure drop is 90V, the pressure drop of 125W high-pressure mercury lamp Inductive ballast is 176V, load (bulb) pressure drop is 111V, and 175W metal halide lamp Inductive ballast is 174V, and load (fluorescent tube) is 111V.Supply power voltage is that the 3.5KW cast dysprosium lamp ballast pressure drop of 380V is 300V, and load (fluorescent tube) pressure drop is 200V.

Description of drawings:

Accompanying drawing is gas discharge lamp circuit figure, and 1 is iron core; 2 is coil windings; 3 are load (bulb or fluorescent tube).

Embodiment:

Example 1

Use gaseous discharge lamp (40W fluorescent lamp) circuit of existing Inductive ballast, the pressure drop of input voltage 220V Inductive ballast is 175V, load (fluorescent tube) pressure drop is 115V, circuital current is 0.38A, the circuit power consumption 49W that gains merit, wherein, (ballast pressure drop-load pressure drop)/load pressure drop * 100%=(175V-115V)/115V * 100%=52.2%.

Use gaseous discharge lamp (40W fluorescent lamp) the circuit input voltage 164V Inductive ballast pressure drop of the Inductive ballast of the method according to this invention to be 101V, load (above-mentioned same fluorescent tube) pressure drop 115V, circuital current 0.38A, the circuit power consumption 42W that gains merit.Inductive ballast pressure drop this moment levels off to the pressure drop of load (fluorescent tube), wherein, and (ballast pressure drop-load pressure drop)/load pressure drop * 100%=(101V-115V)/115V * 100%=-12.2%.

Use the Inductive ballast economize on electricity 7W of the method according to this invention.

Example 2

Use gaseous discharge lamp (40W fluorescent lamp) circuit of existing Inductive ballast, the pressure drop of input voltage 232V Inductive ballast is 189V, load (fluorescent tube) pressure drop is 11V, circuital current is 0.43A, the circuit power consumption 53W that gains merit, wherein, (ballast pressure drop-load pressure drop)/load pressure drop * 100%=(189V-111V)/111V * 100%=70.3%.

Use gaseous discharge lamp (40W fluorescent lamp) the circuit input voltage 171V Inductive ballast pressure drop of the Inductive ballast of the method according to this invention to be 111V, load (above-mentioned same fluorescent tube) pressure drop 110V, circuital current 0.43A, the circuit power consumption 46W that gains merit.Inductive ballast pressure drop this moment levels off to the pressure drop of load (fluorescent tube), wherein, and (ballast pressure drop-load pressure drop)/load pressure drop * 100%=(111V-110V)/100V * 100%=0.9%.

Use the Inductive ballast economize on electricity 7W of the method according to this invention.

Example 3

Use gaseous discharge lamp (20W fluorescent lamp) circuit of existing Inductive ballast, input voltage 226V, the Inductive ballast pressure drop is 200V, load (fluorescent tube) pressure drop is 60V, circuital current is 0.31A, the circuit power consumption 31W that gains merit, wherein, (ballast pressure drop-load pressure drop)/load pressure drop * 100%=(200V-60V)/60V * 100%=233.3%.

Use gaseous discharge lamp (20W fluorescent lamp) circuit of the Inductive ballast of the method according to this invention, input voltage 97V, the Inductive ballast pressure drop is 60V, and load (above-mentioned same fluorescent tube) pressure drop is 60V, and circuital current is 0.31A, the circuit power consumption 21W that gains merit.This moment, the circuit ballast pressure drop equaled the pressure drop of load (fluorescent tube), wherein, and (ballast pressure drop-load pressure drop)/load pressure drop * 100%=(60V-60V)/60V * 100%=0%.

Use the Inductive ballast economize on electricity 10W of the method according to this invention.

Example 4

Use the ballasting circuit of existing Inductive ballast, input voltage 220V, the Inductive ballast pressure drop is 200V, load (184 Ω resistance) pressure drop is 65V, circuital current is 0.31A, the circuit power consumption 39W that gains merit, wherein, (ballast pressure drop-load pressure drop)/load pressure drop * 100%=(200V-65V)/65V * 100%=207.7%.

Use the ballasting circuit of the Inductive ballast of the method according to this invention, input voltage 93V, the Inductive ballast pressure drop is 58V, load (184 Ω resistance) pressure drop is 65V, circuital current is 0.32A, the circuit power consumption 25W that gains merit, wherein, (ballast pressure drop-load pressure drop)/load pressure drop * 100%=(58V-65V)/65V * 100%=-10.8%.

Use the energy-conservation 14W of Inductive ballast connecting resistance load of the method according to this invention.

Claims (4)

1, a kind of method that reduces Inductive ballast power consumption in the circuit, wherein this circuit comprises load and the Inductive ballast that plays the ballast effect, described Inductive ballast comprises iron core (1) and coil windings (2), it is characterized in that:

Reduce Inductive ballast pressure drop in the circuit, make ballast pressure drop and load pressure drop satisfy following relation :-12.2%≤(ballast pressure drop-load pressure drop)/load pressure drop * 100%≤+ 12.2%.

2, method according to claim 1, it is characterized in that: reduce Inductive ballast pressure drop in the circuit, make ballast pressure drop and load pressure drop satisfy following relation :-10.8%≤(ballast pressure drop-load pressure drop)/load pressure drop * 100%≤+ 10.8%.

3, method according to claim 2 is characterized in that: reduce Inductive ballast pressure drop in the circuit, make ballast pressure drop and load pressure drop satisfy following relation :-0.9%≤(ballast pressure drop-load pressure drop)/load pressure drop * 100%≤+ 0.9%.

4, according to any one described method of claim 1-3, it is characterized in that: reduce Inductive ballast pressure drop in the circuit, make the ballast pressure drop equal the load pressure drop.

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