CN117274004A - Primary school site selection method based on shortest path planning and space syntax - Google Patents

Primary school site selection method based on shortest path planning and space syntax Download PDF

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CN117274004A
CN117274004A CN202311542409.1A CN202311542409A CN117274004A CN 117274004 A CN117274004 A CN 117274004A CN 202311542409 A CN202311542409 A CN 202311542409A CN 117274004 A CN117274004 A CN 117274004A
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吴志华
潘聪
王梦姣
段英姿
宋晓杰
方勇
谢慧
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Abstract

The invention discloses a primary school address selection method based on shortest path planning and space syntax, which comprises the following steps: s1) constructing a basic model of a target area, and drawing a global axis map; s2) endowing the entrance and exit of each residential district with a pedestrian initial value; s3) calculating the integration degree of each point on the axis of the global axis map; s4) generating a global integration map; s5) calculating the comprehensive integration degree of the axial line segment; s6) selecting primary school candidate points; s7) solving the shortest path of the corresponding relation group between the school coverage area and the residential district entrance; s8) comparing the shortest paths, and obtaining the primary school address selection scheme according to actual requirements. The invention carries out scientific weighting on the paths in the Dijkstra algorithm, adopts the integration degree to replace the space distance as the path value, and has more scientific and accurate calculation result; meanwhile, the primary school service range is considered, the corresponding relations between schools and entrances and exits of residential communities are matched one by one, and a plurality of primary schools comprehensive optimal sites and travel paths are comprehensively calculated.

Description

基于最短路径规划和空间句法的小学选址方法Primary school site selection method based on shortest path planning and space syntax

技术领域Technical field

本发明涉及计算机辅助规划选址技术领域,具体涉及一种基于最短路径规划和空间句法的小学选址方法。The invention relates to the technical field of computer-aided planning and site selection, and specifically relates to a primary school site selection method based on shortest path planning and space syntax.

背景技术Background technique

根据《中小学校设计规范》(GB50099-2011)城镇完全小学的服务半径宜为500m,因此,目前小学选址大多以500m作为半径对现状小学服务区域进行评估,从而在服务未覆盖区选出规划小学选点。然而,该方法没有考虑到不同区域的人行活动的实际情况,其选址方案的科学性和适应性有待增强。因此,有必要引入更精细化和定量的研究方法,提高小学选址的科学性和合理性。According to the "Design Code for Primary and Secondary Schools" (GB50099-2011), the service radius of a complete primary school in an urban area should be 500m. Therefore, most current primary school site selections use 500m as a radius to evaluate the current primary school service area, so as to select plans in areas not covered by services. Primary school selection. However, this method does not take into account the actual conditions of pedestrian activities in different areas, and the scientific nature and adaptability of its site selection plan need to be enhanced. Therefore, it is necessary to introduce more refined and quantitative research methods to improve the scientificity and rationality of primary school site selection.

为提高小学选址的科学性和效率,有学者尝试使用Dijkstra算法、空间句法、P-重心法等量化方法来进行小学选址。Dijkstra算法是一种最短路径规划的经典算法,其原始算法仅适用于找到两个顶点之间的最短路径。但将其在运用于小学选址过程中,具有一定局限性:一是其最优解仅能在预先设定的选址点中产生;二是仅以空间距离的最短路径作为小学选址的标准,未考虑“人”的因素,难以适应小学选址需考虑多因素现实要求。In order to improve the scientificity and efficiency of primary school location selection, some scholars have tried to use quantitative methods such as Dijkstra algorithm, space syntax, and P-center of gravity method to select primary school locations. Dijkstra's algorithm is a classic algorithm for shortest path planning. Its original algorithm is only suitable for finding the shortest path between two vertices. However, it has certain limitations when applied to the primary school site selection process: first, its optimal solution can only be generated in preset site selection points; second, only the shortest path of spatial distance is used as the primary school site selection The standard does not take into account the "human" factor and is difficult to adapt to the practical requirements of primary school site selection, which requires consideration of multiple factors.

空间句法是一种传统网络分析方法,其中提到的整合度指标可以用来度量城市道路及其沿线地区的可达性程度。空间句法是基于“可见即可达”的原理,但是无法对小学选址中最重要的两个要素——服务人口和人的出行特征予以考虑,在运用于小学选址中具有局限性。此外,传统空间句法仅能求出区域内整合度最高点作为小学选址点,在需要进行多个小学综合选址时存在局限性。Space syntax is a traditional network analysis method, and the integration index mentioned in it can be used to measure the accessibility of urban roads and areas along them. Space syntax is based on the principle of "visible and accessible", but it cannot take into account the two most important factors in primary school location selection - the service population and people's travel characteristics, so it has limitations in its application in primary school location selection. In addition, traditional space syntax can only find the point with the highest degree of integration in the region as the primary school site selection point, which has limitations when comprehensive site selection of multiple primary schools is required.

发明内容Contents of the invention

为了解决上述现有技术的不足之处,本发明提出一种基于最短路径规划和空间句法的小学选址方法,将学校与居住小区之间的路径对应关系进行一一匹配,综合计算区域范围内多个小学分期选址方案和评价多个小学选址方案。In order to solve the above-mentioned shortcomings of the prior art, the present invention proposes a primary school site selection method based on shortest path planning and space syntax, which matches the path correspondence between the school and the residential area one by one, and comprehensively calculates the location within the area. Multiple primary school staging plans and evaluation of multiple primary school site plans.

本发明提出的一种基于最短路径规划和空间句法的小学选址方法,其特殊之处在于,所述方法包括如下步骤:The invention proposes a primary school site selection method based on shortest path planning and space syntax. Its special feature is that the method includes the following steps:

S1)构建目标区域的基础模型,导入目标区域的线状道路网图,绘制目标区域内的人行步道,将每一条人行步道绘制为轴线,形成全局轴线图;S1) Build a basic model of the target area, import the linear road network diagram of the target area, draw the pedestrian trails in the target area, and draw each pedestrian trail as an axis to form a global axis diagram;

S2)将目标区域内每一个居住小区出入口作为起点O,将居住小区适龄儿童总量平均分摊到每个居住小区出口作为起点初始值R,对每个出入口点赋予人行初始值RO jj=1,2,…,N,表示研究区域内居住小区出入口的个数;S2) Take each entrance and exit of the residential area in the target area as the starting point O , allocate the total number of school-age children in the residential area equally to the exit of each residential area as the starting point initial value R, and assign each entrance and exit point an initial pedestrian value RO j , j = 1,2,…, N , represents the number of entrances and exits of residential areas in the study area;

S3)对于全局轴线图每一轴线上每一个点i计算基于居住小区出入口Oj的整合度RQ ij=RO j×D×Z×J,其中,D为距离系数、Z为阻力系数、J为角度系数;S3) For each point i on each axis of the global axis diagram, calculate the integration degree RQ ij = RO j × D × Z × J based on the entrance and exit of the residential area O j , where D is the distance coefficient, Z is the resistance coefficient, and J is angle coefficient;

S4)以全局轴线图上每一轴线为路径,遍历计算所有出入口的人流初始值分布在轴线上点i的初始人行整合度RQ iNRQ iN=Σ(Q i1+Q i2+Q i3+……+Q iN) ,根据全局轴线图上每一轴线上每个点的整合度值生成全局整合度图;S4) Taking each axis on the global axis diagram as a path, iteratively calculate the initial pedestrian integration degree RQ iN of the initial value distribution of all entrances and exits at point i on the axis, RQ iN =Σ( Q i1 + Q i2 + Q i3 +… …+ Q iN ), generate a global integration graph based on the integration value of each point on each axis on the global axis graph;

S5)计算轴线段综合整合度,将全局轴线图每一轴线根据相交点划分为若干个起点为A、终点为B的轴线段AB,计算轴线段AB的综合整合度;S5) Calculate the comprehensive integration degree of the axis segment, divide each axis of the global axis diagram into several axis segments AB with the starting point A and the end point B according to the intersection points, and calculate the comprehensive integration degree of the axis segment AB;

S6)小学备选点选取,结合片区内规划现状居住用地、审批信息,结合邻避设施布局,提取符合面积大小要求的空白地块作为小学备选点M个,m=1,2,…MS6) Selection of primary school alternative sites. Combined with the current planned residential land and approval information in the area, and the layout of NIMBY facilities, extract blank plots that meet the area size requirements as M primary school alternative sites, m =1,2,… M ;

S7)运用Dijkstra算法,求解学校X m覆盖范围内与居住小区出入口O j的对应关系组的最短路径P(X m,O j),具体步骤为: S7 ) Use the Dijkstra algorithm to find the shortest path P (

设集合G={V,E};Let the set G={V,E};

其中,顶点集合V为居住小区出入口O j、学校X m、轴线段交点A、B的集合,边权值数据E为轴线段AB综合整合度的倒数;Among them, the vertex set V is the set of the entrance and exit of the residential area O j , the school X m , and the intersection points A and B of the axis segment, and the edge weight data E is the reciprocal of the comprehensive integration degree of the axis segment AB;

定义集合S为已求出最短路径顶点的集合、集合T为尚未求出最短路径顶点的集合;Define set S as the set of shortest path vertices that have been found, and set T as the set of shortest path vertices that have not yet been found;

求解与学校X 1对应的居住小区出入口O 1的最短路径P(O 1,X 1)的过程为:The process of solving the shortest path P ( O 1 , X 1 ) of the residential area entrance and exit O 1 corresponding to the school X 1 is:

a. 初始时,令集合S={O 1},T=V-S={其余顶点};a. Initially, let the set S={ O 1 }, T=VS={the remaining vertices};

O 1可以到达顶点V,则P(O 1,V)为最短路径值;If O 1 can reach the vertex V, then P( O 1 ,V) is the shortest path value;

O 1不可以到达顶点V,则P(O 1,V)为无穷大;If O 1 cannot reach the vertex V, then P( O 1 ,V) is infinite;

b. 从集合T中选取一个与集合S中顶点有关联边且边权值数据E最小的顶点W,加入到集合S中,此时计算点O 1到点W的距离作为最短路径P(O 1,W);b. Select a vertex W from the set T that has an edge associated with the vertex in the set S and has the smallest edge weight data E, and adds it to the set S. At this time, the distance from point O 1 to point W is calculated as the shortest path P ( O 1 ,W);

c. 计算点O 1到集合T中其余顶点的距离值进行修改;c. Calculate the distance value from point O 1 to the remaining vertices in set T and modify it;

重复上述步骤2、3,直到集合S包含集合V中所有点为止;Repeat steps 2 and 3 above until set S contains all points in set V;

d. 最短路径P(O 1,X 1)即为从出发点O 1到学校X 1的最短路径值,同理,求得P(O 2,3…j,X 2,3…m); d . The shortest path P ( O 1 , X 1 ) is the shortest path value from the starting point O 1 to the school X 1. In the same way, P ( O 2,3 …j ,

S8)比较学校X m与服务范围内的居住小区出入口O j对应关系组中各项最短路径P(X m,O j),根据实际需求得到小学选址方案。 S8 ) Compare the shortest paths P ( _

优选地,步骤S4)中,生成全局整合度图之前对初始人行整合度RQ iN进行修正,得到修正后的轴线整合度Q zi=RQ iN×T iT i为场所向量,将Q zi作为轴线上点i的最终整合度,生成全局整合度图。Preferably, in step S4), before generating the global integration map, the initial pedestrian integration degree RQ iN is corrected to obtain the corrected axis integration degree Q zi = RQ iN × T i , where T i is the place vector, and Q zi is taken as The final integration degree of point i on the axis generates a global integration degree map.

优选地,所述场所向量T i的计算方法为:通过采集街景照片,将道路性质按照楼荫路/林荫路、地面坡度分类,以加权计算或直接赋值的方式得到每一轴线的场所向量T iPreferably, the calculation method of the place vector Ti is: by collecting street view photos, classifying the road properties according to the building-lined road/boulevard road and ground slope, and obtaining the place vector of each axis by weighted calculation or direct assignment. Ti .

优选地,步骤S3)中,所述距离系数D表示任意点i到出入口点j的距离参数,根据实际距离设定0~1以内的参数值或者计算获得。Preferably, in step S3), the distance coefficient D represents the distance parameter from any point i to the entrance and exit point j , and is set to a parameter value within 0 to 1 based on the actual distance or obtained by calculation.

优选地,步骤S3)中,所述阻力系数Z表示任意点i到出入口点j的阻力参数,根据实际距离设定0~1以内的参数值,包括普通人行步道阻力系数Z 0、斑马线阻力系数Z 1、立体交通设施阻力系数Z 2,且0<Z 2<Z 1<Z 0<1。Preferably, in step S3), the resistance coefficient Z represents the resistance parameter from any point i to the entrance and exit point j , and is set to a parameter value within 0~1 according to the actual distance, including the resistance coefficient Z 0 of ordinary pedestrian paths and the resistance coefficient of zebra crossings Z 1 , resistance coefficient of three-dimensional transportation facilities Z 2 , and 0< Z 2 < Z 1 < Z 0 <1.

优选地,步骤S3)中,所述角度系数J根据相邻轴线段之间的夹角设置,根据实际设定0~1以内的参数值或者计算获得。Preferably, in step S3), the angle coefficient J is set according to the angle between adjacent axis segments, and is obtained by actual setting of a parameter value within 0 to 1 or calculation.

优选地,所述距离系数D通过计算获得,计算方法为:Preferably, the distance coefficient D is obtained by calculation, and the calculation method is:

式中,x为任意点i到出入口点j的距离,σ2为方差,μ为预计发生最高人数衰减的距离值,当x≥500m时,D=0。In the formula, x is the distance from any point i to the entrance and exit point j , σ 2 is the variance, and μ is the distance value at which the highest number of people is expected to attenuate. When x ≥ 500m, D = 0.

优选地,步骤S5)中,轴线段AB的综合整合度的计算方法为:将起点为A、终点为B的轴线段AB进行米制分段,即每1m取一个分段点,直到所取之点覆盖B点;依次计算轴线段AB上包括AB在内的每个分段点的整合度,取所有分段点的整合度中位值为轴线段AB的综合整合度。Preferably, in step S5), the comprehensive integration degree of the axis segment AB is calculated as follows: segment the axis segment AB with the starting point A and the end point B into metric segments, that is, a segmentation point is taken every 1m until the Point covers point B; calculate the integration degree of each segment point including AB on axis segment AB in turn, and take the median integration degree of all segment points as the comprehensive integration degree of axis segment AB.

优选地,步骤S8)中输出小学选址方案的步骤为:Preferably, the step of outputting the primary school site selection plan in step S8) is:

计算每个小学备选点的最短路径值综合评分:Calculate the comprehensive score of the shortest path value for each primary school alternative point:

;

依次计算P(O 1,2,…j,X 2)、P(O 1,2,…j,X 3)、…、P(O 1,2,…j,X m);将综合评分最低的点作为第一个小学选址点,运用背包算法,生成若干名小学选址方案;按照综合评分从低到高排序,将选址方案分为三组,依次为小学近期建设推荐点、小学中期建设推荐点和小学远期建设推荐点。Calculate P ( O 1,2,…j , X 2 ), P ( O 1,2,…j , X 3 ),…, P ( O 1,2,…j , As the first primary school site selection point, the knapsack algorithm is used to generate several primary school site selection plans; according to the comprehensive score from low to high, the site selection plans are divided into three groups, which are recommended points for the recent construction of primary schools, primary schools Recommended points for medium-term construction and recommended points for long-term construction of primary schools.

优选地,步骤S8)中输出多组小学选址方案评价结果的步骤为:Preferably, the step of outputting the evaluation results of multiple groups of primary school site selection plans in step S8) is:

计算每个小学备选点的最短路径值综合评分:Calculate the comprehensive score of the shortest path value for each primary school alternative point:

,

依次计算P(O 1,2,…j,X 2)、P(O 1,2,…j,X 3)、…、P(O 1,2,…j,X m);Calculate P ( O 1,2,…j , X 2 ), P ( O 1,2,…j , X 3 ),…, P ( O 1,2,…j , X m ) in sequence;

针对目标区域提出三组小学选址布局方案,并分别计算每一组方案中所有小学备选点的最短路径值综合评分的平均值作为该方案的综合评分值;Three groups of primary school location layout plans are proposed for the target area, and the average of the comprehensive scores of the shortest path values of all primary school alternative points in each group of plans is calculated as the comprehensive score of the plan;

将综合评分值最小的方案作为推荐方案,该方案对应的小学备选点为输出的小学推荐点。The plan with the smallest comprehensive score is used as the recommended plan, and the primary school alternative point corresponding to this plan is the output primary school recommended point.

本发明与现有技术相比具有如下优点和有益效果:Compared with the prior art, the present invention has the following advantages and beneficial effects:

(1) 本发明在传统空间句法的基础上对人的行为、环境对人行路径的影响等因素进行量化并将其纳入原有整合度的计算;(1) This invention quantifies factors such as human behavior and the impact of the environment on pedestrian paths based on traditional space syntax and incorporates them into the calculation of the original integration degree;

(2) 本发明通过模拟人的出行特征及喜好,对出行过程中楼荫、林荫覆盖情况、地面坡度等影响出行的因素进行测算,使其更加贴近人行实际情况;(2) By simulating people’s travel characteristics and preferences, this invention calculates the factors that affect travel such as building shade, tree shade coverage, and ground slope during travel, making it closer to the actual situation of pedestrians;

(3)本发明方法对Dijkstra算法中的路径进行科学赋权,采用改进型空间句法的整合度代替空间距离作为边权值,使Dijkstra算法计算结果更为科学、准确;(3) The method of the present invention scientifically weights the paths in the Dijkstra algorithm, and uses the integration degree of the improved space syntax to replace the spatial distance as the edge weight, making the Dijkstra algorithm calculation results more scientific and accurate;

(4)本发明考虑小学服务半径,构建学校服务区,并将学校与居住小区之间的对应关系进行一一匹配,综合计算区域范围内多个小学综合最优选址和出行路径。(4) This invention considers the service radius of primary schools, constructs school service areas, matches the corresponding relationships between schools and residential areas one by one, and comprehensively calculates the comprehensive optimal addresses and travel routes for multiple primary schools within the area.

附图说明Description of the drawings

图1是本发明方法的整体网络模型结构示意图;Figure 1 is a schematic structural diagram of the overall network model of the method of the present invention;

图2为实施例一中全局轴线图;Figure 2 is a global axis diagram in Embodiment 1;

图3为实施例一中全局整合度图(局部);Figure 3 is a global integration degree diagram (partial) in Embodiment 1;

图4为实施例一中综合整合度图(局部);Figure 4 is a comprehensive integration degree diagram (partial) in Embodiment 1;

图5为实施例一中小学备选点分布图;Figure 5 is a distribution map of candidate points for primary and secondary schools in Embodiment 1;

图6为实施例一中小学近中远期选址方案图;Figure 6 is a diagram of the near, medium and long-term site selection plan for primary and secondary schools in Embodiment 1;

图7为实施例二中小学选址方案一图示;Figure 7 is a diagram of the primary and secondary school site selection plan in Embodiment 2;

图8为实施例二中小学选址方案二图示;Figure 8 is a diagram of the second primary and secondary school site selection plan in Embodiment 2;

图9为实施例二中小学选址方案三图示;Figure 9 is a diagram of the third primary and secondary school site selection plan in Embodiment 2;

图10为实施例二中对应关系组示意图(方案一);Figure 10 is a schematic diagram of the correspondence relationship group in Embodiment 2 (Option 1);

图11为实施例二中对应关系组示意图(方案二);Figure 11 is a schematic diagram of the correspondence relationship group in Embodiment 2 (Option 2);

图12为实施例二中对应关系组示意图(方案三);Figure 12 is a schematic diagram of the correspondence relationship group in Embodiment 2 (Option 3);

图13为实施例二中最短路径示意图。Figure 13 is a schematic diagram of the shortest path in Embodiment 2.

具体实施方式Detailed ways

为使本发明的目的、技术方案和优点更加清楚明了,下面结合具体实施方式并参照附图,对本发明进一步详细说明。应该理解,这些描述只是示例性的,而并非要限制本发明的范围。In order to make the purpose, technical solutions and advantages of the present invention more clear, the present invention will be further described in detail below with reference to the specific embodiments and the accompanying drawings. It should be understood that these descriptions are exemplary only and are not intended to limit the scope of the invention.

实施例一Embodiment 1

本发明提出一种基于最短路径规划和空间句法的小学选址方法,包括如下步骤:The present invention proposes a primary school site selection method based on shortest path planning and space syntax, which includes the following steps:

S0)小学备选点准备。导入目标区域的线状道路网图,输入已核发行政许可地块、现状居住用地、现状小学点位覆盖面,将小学附近500m作为缓冲区,提取面积大于2公顷的空白地作为小学备选点。S0) Preparation of primary school alternative points. Import the linear road network map of the target area, enter the approved administrative permit land, current residential land, and current primary school point coverage, use 500m near the primary school as a buffer zone, and extract blank land with an area greater than 2 hectares as an alternative primary school site.

S1)构建目标区域的基础模型,标注道路网格区域内各地块的性质,绘制目标区域内的人行步道,人行步道包括普通步道、天桥和地下通道;将每一条人行步道绘制为轴线,形成全局轴线图。S1) Construct a basic model of the target area, mark the properties of each block in the road grid area, and draw pedestrian trails in the target area. The pedestrian trails include ordinary trails, overpasses, and underground passages; draw each pedestrian trail as an axis to form Global axis chart.

本实施例中选取某某区-某某街作为目标区域,目标区域总规模18.8平方公里,其中居住用地6.1平方公里,全局轴线图如图2所示。In this embodiment, a certain district - a certain street is selected as the target area. The total size of the target area is 18.8 square kilometers, of which 6.1 square kilometers are residential land. The global axis diagram is shown in Figure 2.

S2)将目标区域内每一个居住小区出入口作为起点O,将居住小区适龄儿童总量平均分摊到每个居住小区出口作为起点初始值R,对每个出入口点赋予人行初始值RO jj=1,2,…,N,表示研究区域内居住小区出入口的个数。S2) Take each entrance and exit of the residential area in the target area as the starting point O , allocate the total number of school-age children in the residential area equally to the exit of each residential area as the starting point initial value R, and assign each entrance and exit point an initial pedestrian value RO j , j = 1,2,…, N , represents the number of entrances and exits of residential areas in the study area.

S3)对于全局轴线图每一轴线上每一个点i计算基于此点的整合度RQ ij=RO j×D×Z×J,其中,D为距离系数、Z为阻力系数、J为角度系数。S3) For each point i on each axis of the global axis diagram, calculate the integration degree RQ ij = RO j × D × Z × J based on this point, where D is the distance coefficient, Z is the resistance coefficient, and J is the angle coefficient.

距离系数D、阻力系数Z和角度系数J为0~1以内的参数值,分别表示任意点i到出入口点j的距离参数、阻力参数和角度系数,这些系数可以通过不同等级设计参数值,也可以根据实际需求计算获得。The distance coefficient D, the resistance coefficient Z and the angle coefficient J are parameter values within 0~1, which respectively represent the distance parameter, resistance parameter and angle coefficient from any point i to the entrance and exit point j . These coefficients can be designed through different levels of parameter values, also It can be calculated based on actual needs.

具体地,距离系数D计算方法为:Specifically, the distance coefficient D is calculated as:

式中,x为任意点i到出入口点j的距离,σ2为方差,μ为预计发生最高人数衰减的距离值,当x≥500m时,D=0。In the formula, x is the distance from any point i to the entrance and exit point j , σ 2 is the variance, and μ is the distance value at which the highest number of people is expected to attenuate. When x ≥ 500m, D = 0.

阻力系数Z根据实际距离设定0~1以内的参数值,包括普通人行步道阻力系数Z 0、斑马线阻力系数Z 1、立体交通设施阻力系数Z 2,且0<Z 2<Z 1<Z 0<1。The resistance coefficient Z is set to a parameter value within 0~1 according to the actual distance, including the resistance coefficient Z 0 of ordinary pedestrian paths, the resistance coefficient Z 1 of zebra crossings, and the resistance coefficient Z 2 of three-dimensional transportation facilities, and 0 < Z 2 < Z 1 < Z 0 <1.

角度系数J根据相邻轴线段之间的夹角设置,根据实际设定0~1以内的参数值或者计算获得。The angle coefficient J is set according to the angle between adjacent axis segments, and is obtained based on the actual parameter value within 0~1 or calculation.

S4)以全局轴线图上每一轴线为路径,遍历计算所有出入口的人流初始值分布在轴线上点i的初始人行整合度RQ iNRQ iN=Σ(Q i1+Q i2+Q i3+……+Q iN) ,根据全局轴线图上每一轴线上每个点的整合度值生成全局整合度图。S4) Taking each axis on the global axis diagram as a path, iteratively calculate the initial pedestrian integration degree RQ iN of the initial value distribution of all entrances and exits at point i on the axis, RQ iN =Σ( Q i1 + Q i2 + Q i3 +… …+ Q iN ), a global integration graph is generated based on the integration value of each point on each axis on the global axis graph.

生成全局整合度图之前,通过采集街景照片,计算场所向量T i,作为整合度的修正。Before generating the global integration map, the place vector Ti is calculated by collecting street view photos as a correction for the integration.

场所向量T i的计算方法为:通过采集街景照片,将道路性质分类,以加权计算或直接赋值的方式得到每一轴线的场所向量T iThe calculation method of place vector Ti is as follows: by collecting street view photos, classifying road properties, and obtaining the place vector Ti of each axis by weighted calculation or direct assignment.

T i主要考虑道路是否为楼荫路/林荫路、地面坡度等。楼荫路/林荫路是通过街景影像进行判读,判断地面坡度是通过道路的修规数据获得,本实施例中的赋值方案如下表所示。 T i mainly considers whether the road is a building-shaded road/boulevard road, the ground slope, etc. Louyin Road/Lin-lined Road is interpreted through street view images, and the ground slope is determined through road repair data. The assignment scheme in this embodiment is as shown in the table below.

得到修正后的轴线整合度Q zi=RQ iN×T iT i为场所向量,将Q zi作为轴线上点i的最终整合度,生成全局整合度图(局部),如图3所示。The corrected axis integration degree Q zi = RQ iN × T i is obtained, where T i is the site vector. Taking Q zi as the final integration degree of point i on the axis, a global integration degree map (partial) is generated, as shown in Figure 3 .

S5)计算轴线段综合整合度,将全局轴线图每一轴线根据相交点划分为若干个起点为A、终点为B的轴线段AB,计算轴线段AB的综合整合度QABS5) Calculate the comprehensive integration degree of the axis segment, divide each axis of the global axis diagram into several axis segments AB with the starting point A and the end point B according to the intersection point, and calculate the comprehensive integration degree Q AB of the axis segment AB.

在本实施方案中轴线段AB的综合整合度的计算方法为:将起点为A、终点为B的轴线段AB进行米制分段,即每1m取一个分段点,直到取到第i个点时覆盖到B点;若轴线AB不是1m的整数倍,最后一个分段点到B点的距离不必为1m;依次计算轴线段AB上包括AB在内的每个分段点的整合度,取所有分段点的整合度中位值为轴线段AB的综合整合度。本实施例中综合整合度图(局部)如图4所示。In this embodiment, the calculation method for the comprehensive integration degree of axis segment AB is: segment the axis segment AB with the starting point A and the end point B into metric segments, that is, a segmentation point is taken every 1m until the i- th point is obtained. when covering point B; if axis AB is not an integer multiple of 1m, the distance from the last segment point to point B does not have to be 1m; calculate the integration degree of each segment point including AB on axis segment AB in turn, and take The median integration degree of all segmentation points is the comprehensive integration degree of axis segment AB. The comprehensive integration degree diagram (partial) in this embodiment is shown in Figure 4.

S6)小学备选点选取,结合片区内规划现状居住用地、审批信息,结合邻避设施布局,提取符合面积大小要求的空白地块作为小学备选点M个,m=1,2,…M;小学备选点分布图如图5所示。S6) Selection of primary school alternative sites. Combined with the current planned residential land and approval information in the area, and the layout of NIMBY facilities, extract blank plots that meet the area size requirements as M primary school alternative sites, m =1,2,… M ;The distribution map of primary school candidate points is shown in Figure 5.

S7)运用Dijkstra算法,将整合度替换Dijkstra算法中的相应路径距离的权重值来进行Dijkstra运算,求解学校X m覆盖范围内与居住小区出入口O j的对应关系组的最短路径。S7) Use the Dijkstra algorithm, replace the integration degree with the weight value of the corresponding path distance in the Dijkstra algorithm to perform the Dijkstra operation, and find the shortest path of the correspondence group between the school X m coverage and the residential area entrance and exit O j .

具体步骤为:The specific steps are:

设集合G={V,E};Let the set G={V,E};

其中,顶点集合V为居住小区出入口O j、学校X m、轴线段交点A、B的集合,边权值数据E=Among them, the vertex set V is the set of the entrance and exit of the residential area O j , the school X m , and the axis segment intersection points A and B. The edge weight data E= ;

定义集合S为已求出最短路径顶点的集合、集合T为尚未求出最短路径顶点的集合;Define set S as the set of shortest path vertices that have been found, and set T as the set of shortest path vertices that have not yet been found;

求解与学校X 1对应的居住小区出入口O 1的最短路径P(O 1,X 1)的过程为:The process of solving the shortest path P ( O 1 , X 1 ) of the residential area entrance and exit O 1 corresponding to the school X 1 is:

a. 初始时,令集合S={O 1},T=V-S={其余顶点};a. Initially, let the set S={ O 1 }, T=VS={the remaining vertices};

O 1可以到达顶点V,则P(O 1,V)为最短路径值;If O 1 can reach the vertex V, then P( O 1 ,V) is the shortest path value;

O 1不可以到达顶点V,则P(O 1,V)为无穷大;If O 1 cannot reach the vertex V, then P( O 1 ,V) is infinite;

b. 从集合T中选取一个与集合S中顶点有关联边且权值最小的顶点W,加入到集合S中,此时计算点O 1到点W的距离作为最短路径P(O 1,W);b. Select a vertex W from the set T that has an associated edge with the vertex in the set S and has the smallest weight, and adds it to the set S. At this time, the distance from point O 1 to point W is calculated as the shortest path P ( O 1 ,W );

c. 计算点O 1到集合T中其余顶点的距离值进行修改;c. Calculate the distance value from point O 1 to the remaining vertices in set T and modify it;

重复上述步骤2、3,直到集合S包含集合V中所有点为止;Repeat steps 2 and 3 above until set S contains all points in set V;

d. 最短路径P(O 1,X 1)即为从出发点O 1到学校X 1的最短路径值,同理,求得P(O 2,3…j,X 2,3…m)。 d . The shortest path P ( O 1 , X 1 ) is the shortest path value from the starting point O 1 to the school X 1. In the same way, P ( O 2,3 …j ,

S8)比较学校X m与服务范围内的居住小区出入口O j对应关系组中各项最短路径P(X m,O j),根据实际需求得到小学选址方案。 S8 ) Compare the shortest paths P ( _

本实施例采用综合评分排名的方法计算与各居住小区出入口距离最近的小学选址点排名,根据排名情况输出小学选址方案。具体方法为:This embodiment uses the comprehensive score ranking method to calculate the ranking of primary school site selection points closest to the entrance and exit of each residential area, and outputs the primary school site selection plan based on the ranking. The specific methods are:

计算每个小学备选点的最短路径值综合评分Calculate the comprehensive score of the shortest path value for each primary school alternative point

,依次计算P(O 1,2,…j,X 2)、P(O 1,2,…j,X 3)、…、P(O 1,2,…j,X m);将综合评分最高的点作为第一个小学选址点,运用背包算法,生成12个小学选址方案;按照综合评分从低到高排序,将排序为1~4名的选址点,作为小学近期建设推荐点;排名为5~8名的作为小学中期建设推荐点;排名9~12名的作为小学远期建设推荐点,小学近中远期选址方案图如图6所示。 , calculate P ( O 1,2,…j , X 2 ), P ( O 1,2,…j , X 3 ),…, P ( O 1,2,…j , The highest point is used as the first primary school site selection point. The knapsack algorithm is used to generate 12 primary school site selection plans. According to the comprehensive score from low to high, the site selection points ranked 1 to 4 are used as recommendations for the recent construction of primary schools. Points; those ranked 5 to 8 are recommended sites for mid-term construction of primary schools; those ranked 9 to 12 are recommended sites for long-term construction of primary schools. The short-term, mid-term and long-term site selection plan for primary schools is shown in Figure 6.

实施例二Embodiment 2

本实施例与实施例一的主要区别在于可评价多组小学选址方案。The main difference between this embodiment and Embodiment 1 is that multiple groups of primary school site selection plans can be evaluated.

本实施例在执行步骤S6)选取小学备选点时,先生成覆盖方案,导入规划范围,以人行500m实际出行距离为半径,生成M组小学服务区覆盖方案,其中小学位置计为X m,即用最少数量的小学,覆盖全部居住用地。In this embodiment, when performing step S6) to select the primary school alternative point, a coverage plan is first generated, the planning range is imported, and M groups of primary school service area coverage plans are generated using the actual travel distance of 500m for pedestrians as the radius, in which the location of the primary school is counted as X m , That is, using a minimum number of primary schools to cover all residential land.

在本实施例中,对于目标区域提出三组方案,分别如图7、图8、图9所示,三组方案中的小学选址能够覆盖居住用地90%以上。In this embodiment, three sets of plans are proposed for the target area, as shown in Figures 7, 8, and 9 respectively. The primary school locations in the three sets of plans can cover more than 90% of the residential land.

在同一小学服务区内,匹配预选学校X及居住小区出入口O,构建学校X m与出入口O j的对应关系组,三组方案的对应关系组示意图分别如图10、图11、图12所示。In the same primary school service area, match the pre - selected school .

运用Dijkstra算法求所有学校X m服务范围内的所有居住小区出入口O j到达学校X m的最短路径值P(X m,O j)。Use Dijkstra's algorithm to find the shortest path value P ( X m , O j ) from all entrances and exits O j of residential areas within the service range of all schools

针对三组小学选址布局方案,分别计算每一组方案中所有小学备选点的最短路径值综合评分的平均值作为该方案的综合评分值,得分最小的一组作为推荐方案,即方案二;该方案对应的小学备选点为输出的小学推荐点,最短路径示意图(局部)如图13所示。For the three groups of primary school site selection and layout plans, the average of the comprehensive scores of the shortest path values of all primary school alternative points in each group of plans is calculated as the comprehensive score value of the plan, and the group with the smallest score is used as the recommended plan, that is, Plan 2 ; The primary school alternative point corresponding to this plan is the output primary school recommendation point. The shortest path diagram (partial) is shown in Figure 13.

本说明书未作详细描述的内容属于本领域专业技术人员公知的现有技术。Contents not described in detail in this specification belong to the prior art known to those skilled in the art.

最后需要说明的是,以上具体实施方式仅用以说明本专利技术方案而非限制,尽管参照较佳实施例对本专利进行了详细说明,本领域的普通技术人员应当理解,可以对本专利的技术方案进行修改或者等同替换,而不脱离本专利技术方案的精神和范围,其均应涵盖在本专利的权利要求范围当中。Finally, it should be noted that the above specific embodiments are only used to illustrate the technical solution of this patent and not to limit it. Although this patent is described in detail with reference to the preferred embodiments, those of ordinary skill in the art should understand that the technical solution of this patent can be modified Modifications or equivalent substitutions without departing from the spirit and scope of the technical solution of this patent shall be covered by the claims of this patent.

Claims (10)

1. A primary school location method based on shortest path planning and space syntax is characterized in that: the method comprises the following steps:
s1) constructing a basic model of a target area, importing a linear road network diagram of the target area, drawing sidewalks in the target area, drawing each sidewalk as an axis, and forming a global axis diagram;
s2) taking the entrance and exit of each residential district in the target area as a starting pointOAverage allocation of the total amount of children suitable for the age of the residential district to the exit of each residential district as the initial value of the starting pointRA pedestrian initial value is given to each entrance pointRO jj=1,2,…,NRepresenting the number of residential district entrances and exits in the study area;
s3) for each point on each axis of the global axis mapiCalculation is based on residential district access & exitO j Is integrated with (a)RQ ij = RO j ×D×Z×JWherein, the method comprises the steps of, wherein,Dis a distance coefficient,ZIs a resistance coefficient,JIs an angle coefficient;
s4) taking each axis on the global axis diagram as a path, traversing and calculating the point on the axis where the initial values of the people flow at all the entrances and exits are distributediInitial human integration degree of (2)RQ iNRQ iN =Σ(Q i1 + Q i2 + Q i3 +……+ Q iN ) Generating a global integration map according to the integration value of each point on each axis on the global axis map;
s5) calculating the comprehensive integration degree of the axis segments, dividing each axis of the global axis map into a plurality of axis segments AB with a starting point A and a finishing point B according to the intersection points, and calculating the comprehensive integration degree of the axis segments AB;
s6) selecting primary school candidate points, combining with current living land planning and approval information in the area and combining with adjacent facilities layout, and extracting blank land blocks meeting the area and size requirements as primary school candidate pointsMThe number of the two-dimensional space-saving type,m =1,2,…M
s7) application ofDijkstraAlgorithm for solving schoolX m In-coverage and residential district access & exitO j Shortest path of corresponding relation group of (a)P(X m ,O j ) The method comprises the following specific steps of:
let set g= { V, E };
wherein the vertex set V is the entrance and exit of residential districtO j School and schoolX m The collection of the intersection points A, B of the axis segments, and the edge weight data E is the reciprocal of the comprehensive integration degree of the axis segments;
defining a set S as a set with the shortest path vertexes already solved, and defining a set T as a set with the shortest path vertexes not yet solved;
solution and schoolX 1 Corresponding residential district access & exitO 1 Is the shortest path of (a)P(O 1 , X 1 ) The process of (1) is as follows:
a. initially, let set s= {O 1 T=v-s= { remaining vertices };
if it isO 1 Can reach the vertex V, P #O 1 V) is the shortest path value;
if it isO 1 If it can not reach the vertex V, P #O 1 V) is infinity;
b. selecting a vertex W with the smallest edge weight data E from the set T, adding the vertex W to the set S, and calculating the point at the momentO 1 The distance to the point W is taken as the shortest path P #, the distance to the point W isO 1 ,W);
c. Calculation pointO 1 Modifying the distance values to the rest vertexes in the set T;
repeating the steps 2 and 3 until the set S contains all points in the set V;
d. shortest pathP(O 1 , X 1 ) I.e. from the startO 1 To schoolX 1 The shortest path value of (1) is obtained by the same methodP(O 2,3…j ,X 2,3…m );
S8) comparison schoolX m And service scopeResidential district access & exit in enclosingO j Shortest paths in corresponding relation groupP(X m ,O j ) And obtaining a primary school address selection scheme according to actual requirements.
2. The primary school addressing method based on shortest path planning and space syntax according to claim 1, wherein: in step S4), the initial pedestrian integration degree is compared with the global integration degree mapRQ iN Correcting to obtain the corrected axis integration degreeQ zi =RQ In ×T iT i Is a place vector, willQ zi As an on-axis pointiAnd (3) generating a global integration map.
3. The primary school addressing method based on shortest path planning and space syntax according to claim 2, wherein: the location vectorT i The calculation method of (1) is as follows: by collecting street view photos, road properties are classified according to building shadows/boulders and ground slopes, and the place vector of each axis is obtained by means of weighted calculation or direct assignmentT i
4. The primary school addressing method based on shortest path planning and space syntax according to claim 1, wherein: in step S3), the distance coefficientDRepresenting arbitrary pointsiTo the entrance pointjSetting a parameter value within 0-1 according to the actual distance or calculating the parameter value.
5. The primary school addressing method based on shortest path planning and space syntax according to claim 1, wherein: in step S3), the drag coefficientZRepresenting arbitrary pointsiTo the entrance pointjSetting a parameter value within 0-1 according to the actual distance, including the resistance coefficient of a common sidewalkZ 0 Coefficient of zebra stripes resistanceZ 1 Drag coefficient of three-dimensional traffic facilitiesZ 2 And 0 is<Z 2 <Z 1 <Z 0 <1。
6. The primary school addressing method based on shortest path planning and space syntax according to claim 1, wherein: in step S3), the angle coefficientJAnd setting according to the included angle between the adjacent axis segments, and setting a parameter value within 0-1 according to actual setting or calculating to obtain the angle.
7. The primary school addressing method based on shortest path planning and space syntax according to claim 4, wherein: the distance coefficientDThe method is obtained through calculation, and the calculation method comprises the following steps:
wherein x is any pointiTo the entrance pointjDistance sigma of (2) 2 For variance, μ is the distance value at which the highest number of people is expected to decay, d=0 when x is ≡500 m.
8. The primary school addressing method based on shortest path planning and space syntax according to claim 1, wherein: in step S5), the method for calculating the comprehensive integration degree of the axis line segment AB includes: metric segmentation is carried out on an axis segment AB with a starting point of A and an ending point of B, namely, a segmentation point is taken every 1m until the taken point covers the point B; and sequentially calculating the integration degree of each segment point including the axis segment AB, and taking the median value of the integration degree of all segment points as the integrated integration degree of the axis segment AB.
9. The primary school addressing method based on shortest path planning and space syntax according to claim 1, wherein: the step of outputting the primary school addressing scheme in the step S8) is as follows:
calculating a shortest path value composite score for each primary candidate point
Sequentially calculatingP(O 1,2,…j , X 2 )、P(O 1,2,…j , X 3 )、…、P(O 1,2,…j , X m ) The method comprises the steps of carrying out a first treatment on the surface of the Taking the point with the lowest comprehensive score as a first primary school address point, and generating a plurality of primary school address schemes by using a knapsack algorithm; and sorting the site selection schemes into three groups according to the comprehensive scores from low to high, wherein the three groups are a near-term construction recommended point of primary school, a medium-term construction recommended point of primary school and a long-term construction recommended point of primary school in sequence.
10. The primary school addressing method based on shortest path planning and space syntax according to claim 1, wherein: the step of outputting the primary school addressing scheme in the step S8) is as follows:
calculating the shortest path value composite score of each primary candidate point:
sequentially calculatingP(O 1,2,…j , X 2 )、P(O 1,2,…j , X 3 )、…、P(O 1,2,…j , X m );
Three groups of primary school address layout schemes are provided for a target area, and the average value of the shortest path value comprehensive scores of all primary school candidate points in each group of schemes is calculated as the comprehensive score value of the scheme;
and taking the scheme with the smallest comprehensive score value as a recommended scheme, wherein the primary candidate points corresponding to the scheme are output primary recommended points.
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