CN115688025A - Method and system for estimating probability distribution of equipment failure repair time - Google Patents

Method and system for estimating probability distribution of equipment failure repair time Download PDF

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CN115688025A
CN115688025A CN202211311441.4A CN202211311441A CN115688025A CN 115688025 A CN115688025 A CN 115688025A CN 202211311441 A CN202211311441 A CN 202211311441A CN 115688025 A CN115688025 A CN 115688025A
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component
repair
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邵松世
胡俊波
马龙
阮旻智
李华
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Naval University of Engineering PLA
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Abstract

The invention discloses a method and a system for estimating probability distribution of equipment fault repairing time, and belongs to the field of equipment fault index quantification. The method comprises the following steps: in the task time, the cumulative working time of each component is combined, and the gamma distribution density function integral subject to the service life is calculated to obtain the failure probability of each component; according to the inspection sequence and the probability of the fault of each component in the task time, calculating the repair weight coefficient of each component; according to the checking sequence, checking the consumed time according to the state of each component and the consumed time for repairing each failed component, and calculating a repair completion time array; arranging elements in the repair completion time array in an ascending order to obtain the ordered part numbers and the corresponding repair completion time; and according to the sequence after sequencing, cumulatively calculating the repair weight coefficients of all the parts to obtain the probability distribution of the equipment fault repair time. The invention realizes the prediction of the probability distribution of the equipment fault repairing time, and can describe the equipment maintainability performance in more detail.

Description

一种设备故障修复时间的概率分布的估计方法和系统Method and system for estimating probability distribution of equipment failure repair time

技术领域technical field

本发明属于设备故障指标量化领域,更具体地,涉及一种设备故障修复时间的概率分布的估计方法和系统。The invention belongs to the field of equipment failure index quantification, and more specifically relates to a method and system for estimating the probability distribution of equipment failure repair time.

背景技术Background technique

当装备出现某种故障现象后,一般首先对多个可能引起该故障现象的零部件逐一进行检查,直至找到失效的零部件,然后对该失效件采取更换备件等修理方式完成修复。当故障现象和故障原因是一对多的关系时,因失效件的不确定性,会导致每次完成修复的时间也并不相同。目前常采用平均修复时间(mean time to repair,MTTR)来描述装备维修性。When a certain fault occurs in the equipment, generally the multiple parts that may cause the fault are checked one by one until the failed parts are found, and then the failed parts are repaired by replacing spare parts and other repair methods. When the fault phenomenon and the fault cause are in a one-to-many relationship, due to the uncertainty of the failed parts, the time to complete the repair will be different each time. At present, the mean time to repair (MTTR) is often used to describe the maintainability of equipment.

对于海军舰船装备而言,舰员级修理是一种在海上执行任务期间、装备发生故障后在装备现场进行的修理,也是一种在修理设施、修理工具、修理人员数量和水平等方面都极为有限的修理。舰员级MTTR指标对战时恢复装备作战能力至关重要,受到装备生产方和军方的高度重视。生产方采取各种措施来满足军方的MTTR指标,例如采用自动测试技术帮助舰员快速找到故障原因,广泛采用模块化技术来设计装备,使得舰员能快速拆除失效件、更换备件从而修复装备。当前在使用MTTR时,存在着两个较大问题:一是在落实MTTR指标时,装备设计/生产方和军方大多采用“针对双方约定好的某具体故障进行MTTR指标考核”的方式。这种方式的背后原因,在于不能在更一般、更广泛的情况下估计MTTR,只好退而求其次,通过“实现”部分或有代表性故障的平均修复时间来“体现”装备的整体MTTR性能。二是MTTR的数学本质是均值,是一种在宏观、总体层面进行描述的指标,但实际上即便同一种故障现象,由于失效件不同、故障排查时间的不确定性,因此修复时间实际上是分布在某个范围内的。在实际工作中,即便知道类似“修复该故障的平均耗时46分钟”这样的结论,也仍然更希望能得到“在哪些时间内以多大的概率可完成修复?”这类问题的答案。For naval ship equipment, crew-level repair is a kind of repair at the equipment site after the equipment fails during the mission at sea. Very limited repairs. Crew-level MTTR indicators are crucial to recovering equipment combat capabilities during wartime, and are highly valued by equipment manufacturers and the military. The manufacturer takes various measures to meet the military's MTTR index, such as using automatic testing technology to help the crew find the cause of the failure quickly, and widely adopting modular technology to design equipment, so that the crew can quickly remove failed parts and replace spare parts to repair equipment . Currently, there are two major problems in the use of MTTR: First, when implementing MTTR indicators, equipment design/manufacturers and the military mostly adopt the method of "assessing MTTR indicators for a specific failure agreed upon by both parties". The reason behind this method is that MTTR cannot be estimated in a more general and broader situation, so we have to settle for the next best thing and "reflect" the overall MTTR performance of equipment by "realizing" the average repair time of partial or representative failures . The second is that the mathematical essence of MTTR is the mean value, which is an indicator for describing at the macro and overall level, but in fact, even for the same fault phenomenon, due to the different failed parts and the uncertainty of troubleshooting time, the repair time is actually distributed within a certain range. In actual work, even if you know the conclusion like "the average time to repair the fault is 46 minutes", you still hope to get the answer to the question "in which time and with what probability can the repair be completed?".

发明内容Contents of the invention

针对现有技术的缺陷,本发明的目的在于提供一种设备故障修复时间的概率分布的估计方法和系统,旨在解决现有技术无法预测设备故障修复时间的概率分布的问题。In view of the defects of the prior art, the object of the present invention is to provide a method and system for estimating the probability distribution of equipment failure repair time, aiming to solve the problem that the prior art cannot predict the probability distribution of equipment failure repair time.

为实现上述目的,第一方面,本发明提供了一种设备故障修复时间的概率分布的估计方法,所述设备包括多个部件,所述部件的寿命均服从于伽马分布,整个任务时间内任意时刻最多一个部件发生故障,故障排查时各部件的状态检查的次序独立不相关,该方法包括:In order to achieve the above object, in the first aspect, the present invention provides a method for estimating the probability distribution of equipment fault repair time. The equipment includes a plurality of components, and the life of the components all obeys the gamma distribution. At most one component fails at any time, and the order of status checks of each component is independent and irrelevant during troubleshooting. The method includes:

S1.获取各部件的寿命服从的伽马分布密度函数、状态检查消耗时间和累计工作时间,获取修理各失效部件消耗时间和故障发生后对所有部件的检查次序,并将设备的一段工作时期作为任务时间;S1. Obtain the gamma distribution density function that the life of each component obeys, the time spent on state inspection and the cumulative working time, and the time spent on repairing each failed component and the order of inspection of all components after the failure occurs, and a certain working period of the equipment as task time;

S2.在任务时间内,结合各部件的累计工作时间,对其寿命服从的伽马分布密度函数积分计算,得到任务时间内各部件发生故障的概率;S2. During the task time, combined with the cumulative working time of each component, the integral calculation of the gamma distribution density function obeyed by its life expectancy, the probability of failure of each component within the task time is obtained;

S3.按照检查次序,根据任务时间内各部件发生故障的概率,计算任务时间内各部件的修理权重系数;S3. According to the inspection sequence, according to the failure probability of each component within the task time, calculate the repair weight coefficient of each component within the task time;

S4.按照检查次序,根据各部件的状态检查消耗时间和修理各失效部件消耗时间,计算修复完成时间数组;S4. According to the inspection order, calculate the repair completion time array according to the state inspection time of each component and the repair time of each failed component;

S5.升序排列修复完成时间数组内各元素,得到排序后的部件编号和对应修复完成时间;S5. Sort the elements in the repair completion time array in ascending order, and obtain the sorted part numbers and corresponding repair completion time;

S6.按照排序后的次序,累计计算各部件的修理权重系数,得到设备发生故障后在各修复完成时间内完成修复的概率分布。S6. Calculate the repair weight coefficients of each component accumulatively according to the sorted order, and obtain the probability distribution of repair completion within each repair completion time after the equipment fails.

优选地,步骤S2包括:Preferably, step S2 includes:

S21.设置部件编号i=1;S21. Set part number i=1;

S22.计算任务时间Tw内部件i发生故障的概率PfiS22. Calculate the probability Pf i of failure of internal component i within the task time Tw:

Figure BDA0003908069920000031
Figure BDA0003908069920000031

当k=时,

Figure BDA0003908069920000032
When k=,
Figure BDA0003908069920000032

当k≠i时,

Figure BDA0003908069920000033
When k≠i,
Figure BDA0003908069920000033

其中,n表示部件的数量,gk(t)表示部件k的条件概率,ak、bk分别表示部件k的寿命服从的伽马分布密度函数中的形状参数和尺度参数,Γ表示伽马函数,tk表示部件k的累计工作时间;Among them, n represents the number of components, g k (t) represents the conditional probability of component k, a k and b k represent the shape parameters and scale parameters in the gamma distribution density function that the lifetime of component k obeys, Γ represents the gamma function, t k represents the accumulative working time of component k;

S23.i=i+1,若i≤n,进入步骤S22,否则,进入步骤S3。S23.i=i+1, if i≤n, go to step S22, otherwise, go to step S3.

优选地,步骤S3包括:Preferably, step S3 includes:

S31.设置部件检查序号i=1;S31. Set the component inspection sequence number i=1;

S32.计算任务时间内检查序号i对应的部件的修理权重系数:S32. Calculate the repair weight coefficient of the component corresponding to the inspection sequence number i within the task time:

Figure BDA0003908069920000034
Figure BDA0003908069920000034

并按照以下方式赋值两个中间变量:And assign the two intermediate variables as follows:

Tci=tcj,Txi=txjTc i =tc j , Tx i =tx j ;

其中,n表示部件的数量,j=gIndi,Pfj表示编号为j的部件任务时间内发生故障的概率,gInd表示故障发生后对所有部件的检查次序,tcj表示编号为j的部件的状态检查消耗时间,txj表示修理编号为j的失效部件的消耗时间;Among them, n represents the number of components, j=gInd i , Pf j represents the failure probability of the component numbered j within the mission time, gInd represents the inspection order of all components after the fault occurs, tc j represents the component number j Status inspection time consumption, tx j represents the time consumed to repair the failed component numbered j;

S33.i=i+1,若i≤n,进入步骤S32,否则,进入步骤S4。S33. i=i+1, if i≤n, go to step S32, otherwise, go to step S4.

优选地,步骤S4包括:Preferably, step S4 includes:

S41.设置部件检查序号i=1;S41. Set the component inspection sequence number i=1;

S42.计算修复完成时间数组

Figure BDA0003908069920000041
S42. Calculate repair completion time array
Figure BDA0003908069920000041

S43.i=i+1,若i≤n,进入步骤S42,否则,进入步骤S5。S43. i=i+1, if i≤n, go to step S42, otherwise, go to step S5.

优选地,步骤S6包括:Preferably, step S6 includes:

S61.设置排序后的排序序号i=1;S61. Set the sorting sequence number i=1 after sorting;

S62.计算在时间xti内完成修复的概率PriS62. Calculate the probability Pr i of completing the restoration within the time xt i :

Figure BDA0003908069920000042
Figure BDA0003908069920000042

其中,xti表示排序结果中排序序号为i的部件修复完成时间,Pti=wj,j=ixi,ixi表示排序结果中排序序号为i的部件编号,wj表示任务时间内该部件的修理权重系数;Among them, xt i represents the repair completion time of the component with the sequence number i in the sorting result, Pt i =w j , j=ix i , ix i represents the component number with the sequence number i in the sorting result, and w j represents the component number with the sequence number i in the task time The repair weight factor of the component;

S63.i=i+1,若i≤n,进入步骤S52,否则,终止计算,输出所有xti和PriS63.i=i+1, if i≤n, go to step S52, otherwise, terminate the calculation and output all xt i and Pr i .

优选地,该方法还包括:Preferably, the method also includes:

S7.选择期望时间,将距离期望时间最近的xti对应的概率Pri,作为期望时间内完成修复的概率;S7. Select the expected time, and use the probability Pr i corresponding to the xt i closest to the expected time as the probability of completing the restoration within the expected time;

其中,xti表示排序结果中排序序号为i的部件修复完成时间,Pri表示在时间xti内完成修复的概率。Among them, xt i represents the repair completion time of the component with the sort number i in the sorting result, and Pr i represents the probability of completing the repair within time xt i .

为实现上述目的,第二方面,本发明提供了一种设备故障修复时间的概率分布的估计系统,包括处理器和存储器;所述存储器,用于存储计算机执行指令;所述处理器,用于执行所述计算机执行指令,使得第一方面所述的方法被执行。In order to achieve the above object, in the second aspect, the present invention provides a system for estimating the probability distribution of equipment failure repair time, including a processor and a memory; the memory is used to store computer execution instructions; the processor is used to Execution of the computer-implemented instructions causes the method described in the first aspect to be performed.

总体而言,通过本发明所构思的以上技术方案与现有技术相比,具有以下有益效果:Generally speaking, compared with the prior art, the above technical solution conceived by the present invention has the following beneficial effects:

本发明公开了一种设备故障修复时间的概率分布的估计方法和系统,按照检查次序,根据任务时间内各部件发生故障的概率,计算任务时间内各部件的修理权重系数,根据各部件的状态检查消耗时间和修理各失效部件消耗时间,计算修复完成时间数组,升序排列修复完成时间数组内各元素,得到排序后的部件编号和对应修复完成时间,再按照排序后的次序,累计计算各部件的修理权重系数,得到设备发生故障后在各修复完成时间内完成修复的概率分布,从而实现设备故障修复时间的概率分布的预测,能更具体、详尽地描述装备维修性性能。The invention discloses a method and system for estimating the probability distribution of equipment failure repair time. According to the inspection sequence, according to the failure probability of each component within the task time, the repair weight coefficient of each component within the task time is calculated, and according to the state of each component Check the time consumed and the time consumed to repair each failed component, calculate the repair completion time array, arrange the elements in the repair completion time array in ascending order, obtain the sorted part number and the corresponding repair completion time, and then calculate the cumulative calculation of each component according to the sorted order The repair weight coefficient of the equipment can be used to obtain the probability distribution of repair completion within each repair completion time after the equipment fails, so as to realize the prediction of the probability distribution of equipment repair time and describe the maintainability performance of equipment more specifically and in detail.

附图说明Description of drawings

图1为本发明实施例提供的一种设备故障修复时间的概率分布的估计方法流程图。Fig. 1 is a flow chart of a method for estimating the probability distribution of equipment failure repair time provided by an embodiment of the present invention.

图2为本发明实施例提供的分别采用仿真法和本发明方法得到的修复时间在20~145分钟范围内完成修复的概率分布结果。Fig. 2 shows the probability distribution results of the restoration within the range of 20 to 145 minutes obtained by using the simulation method and the method of the present invention respectively provided by the embodiment of the present invention.

具体实施方式Detailed ways

为了使本发明的目的、技术方案及优点更加清楚明白,以下结合附图及实施例,对本发明进行进一步详细说明。应当理解,此处所描述的具体实施例仅用以解释本发明,并不用于限定本发明。In order to make the object, technical solution and advantages of the present invention clearer, the present invention will be further described in detail below in conjunction with the accompanying drawings and embodiments. It should be understood that the specific embodiments described here are only used to explain the present invention, not to limit the present invention.

本发明涉及的设备包括多个部件,所述部件的寿命均服从于伽马分布,整个任务时间内任意时刻最多一个部件发生故障,故障排查时各部件的状态检查的次序独立不相关。图1为本发明实施例提供的一种设备故障修复时间的概率分布的估计方法流程图。如图1所示,该方法包括:The equipment involved in the present invention includes a plurality of components, and the service life of the components is subject to the gamma distribution. At most one component fails at any time during the entire task time, and the order of status inspection of each component is independent and irrelevant during troubleshooting. Fig. 1 is a flow chart of a method for estimating the probability distribution of equipment failure repair time provided by an embodiment of the present invention. As shown in Figure 1, the method includes:

步骤S1.获取各部件的寿命服从的伽马分布密度函数、状态检查消耗时间和累计工作时间,获取修理各失效部件消耗时间和故障发生后对所有部件的检查次序,并将设备的一段工作时期作为任务时间。Step S1. Obtain the gamma distribution density function that the service life of each component obeys, the time spent on status inspection and the cumulative working time, obtain the time spent on repairing each failed component and the order of inspection of all components after the failure occurs, and set a working period of the equipment as task time.

伽马分布是一种常见的分布类型,适用于描述工程实际中装备性能逐步连续退化的过程,例如刀具的磨损是一个典型的连续时间、连续状态的性能退化过程,其寿命可用伽马分布来表示。伽马型单元指该单元寿命服从伽马分布Ga(a,b),其密度函数

Figure BDA0003908069920000061
其中,a为形状参数,b为尺度参数,Γ()为伽马函数。Gamma distribution is a common distribution type, which is suitable for describing the process of gradual and continuous degradation of equipment performance in engineering practice. For example, tool wear is a typical continuous time and continuous state performance degradation process, and its life can be calculated by gamma distribution. express. The gamma type unit means that the unit life obeys the gamma distribution Ga(a,b), and its density function
Figure BDA0003908069920000061
Among them, a is the shape parameter, b is the scale parameter, and Γ() is the gamma function.

本发明约定:The present invention agrees:

(1)某装备由多个伽马型单元组成,为便于描述,以时间来描述各单元的寿命。(1) A certain equipment is composed of multiple gamma-type units. For the convenience of description, the life of each unit is described by time.

(2)在任意时刻,至多有1个单元发生故障。当某单元发生故障时会影响装备的正常工作,装备会出现某些故障现象,此时需要进行开展修理工作。(2) At any moment, at most one unit fails. When a unit breaks down, it will affect the normal operation of the equipment, and some failures will occur in the equipment, and repair work is required at this time.

(3)在进行故障确认时,对这些单元进行状态检查的次序是独立不相关的,即:不存在“必须先检查单元A、然后再检查单元B”这类对检查次序有特定要求的情况。(3) When performing fault confirmation, the order of checking the status of these units is independent and irrelevant, that is, there is no special requirement for the inspection order such as "you must check unit A first, and then check unit B". .

(4)已知各单元的寿命分布规律、对每个单元进行(正常与否的)状态检查所消耗的时间、各失效单元的修理时间、各单元的累积已工作时间、即将执行任务的时间和某故障现象发生后对所有相关单元的检查次序。(4) The life distribution of each unit is known, the time it takes to check the status (normal or not) of each unit, the repair time of each failed unit, the accumulated working time of each unit, and the time to perform the task and the inspection sequence of all related units after a certain fault phenomenon occurs.

本发明的相关变量约定如下:The relevant variables of the present invention are agreed as follows:

单元数量记为n;检查次序记为gInd,数组gInd中保存的是待检查的单元编号,按照数组中提供的单元编号依次检查相关单元直至找到失效件为止;单元i的寿命服从伽马分布Ga(ai,bi);单元i的累积已工作时间记为ti;对单元i的状态检查时间记为tci;修理失效单元i的时间记为txi;任务时间记为Tw。The number of units is recorded as n; the inspection sequence is recorded as gInd, and the number of units to be inspected is stored in the array gInd, and the relevant units are checked in turn according to the unit numbers provided in the array until a failure is found; the life of unit i obeys the gamma distribution Ga (a i , b i ); the cumulative working time of unit i is recorded as t i ; the status inspection time of unit i is recorded as tc i ; the time of repairing failed unit i is recorded as txi ; the task time is recorded as Tw.

步骤S2.在任务时间内,结合各部件的累计工作时间,对其寿命服从的伽马分布密度函数积分计算,得到任务时间内各部件发生故障的概率。Step S2. During the task time, combined with the cumulative working time of each component, the integral calculation of the gamma distribution density function obeyed by the service life is performed to obtain the failure probability of each component within the task time.

优选地,步骤S2包括:Preferably, step S2 includes:

S21.设置部件编号i=1;S21. Set part number i=1;

S22.计算任务时间Tw内部件i发生故障的概率PfiS22. Calculate the probability Pf i of failure of internal component i within the task time Tw:

Figure BDA0003908069920000071
Figure BDA0003908069920000071

当k=i时,

Figure BDA0003908069920000072
When k=i,
Figure BDA0003908069920000072

当k≠i时,

Figure BDA0003908069920000073
When k≠i,
Figure BDA0003908069920000073

其中,n表示部件的数量,gk(t)表示部件k的条件概率,ak、bk分别表示部件k的寿命服从的伽马分布密度函数中的形状参数和尺度参数,Γ表示伽马函数,tk表示部件k的累计工作时间;Among them, n represents the number of components, g k (t) represents the conditional probability of component k, a k and b k represent the shape parameters and scale parameters in the gamma distribution density function that the lifetime of component k obeys, Γ represents the gamma function, t k represents the accumulative working time of component k;

S23.i=i+1,若i≤n,进入步骤S22,否则,进入步骤S3。S23.i=i+1, if i≤n, go to step S22, otherwise, go to step S3.

步骤S3.按照检查次序,根据任务时间内各部件发生故障的概率,计算任务时间内各部件的修理权重系数。Step S3. According to the inspection sequence, the repair weight coefficient of each component within the task time is calculated according to the failure probability of each component within the task time.

优选地,步骤S3包括:Preferably, step S3 includes:

S31.设置部件检查序号i=1。S31. Set the component inspection sequence number i=1.

S32.计算任务时间内检查序号i对应的部件的修理权重系数:S32. Calculate the repair weight coefficient of the component corresponding to the inspection sequence number i within the task time:

Figure BDA0003908069920000074
Figure BDA0003908069920000074

并按照以下方式赋值两个中间变量:And assign the two intermediate variables as follows:

Tci=tcj,Txi=txjTc i =tc j , Tx i =tx j ;

其中,n表示部件的数量,j=gIndi,Pfj表示编号为j的部件任务时间内发生故障的概率,gInd表示故障发生后对所有部件的检查次序,tcj表示编号为j的部件的状态检查消耗时间,txj表示修理编号为j的失效部件的消耗时间。Among them, n represents the number of components, j=gInd i , Pf j represents the failure probability of the component numbered j within the mission time, gInd represents the inspection order of all components after the fault occurs, tc j represents the component number j The status check takes time, and tx j represents the time spent in repairing the failed component with the number j.

对Tr中的元素进行排序,排序结果记为xt,该排序结果在Tr中的元素编号结果记为ix。例如:Tr=[32 12 45],重排序后,xt=[12 32 45],ix=[2 1 3]。The elements in Tr are sorted, the sorting result is recorded as xt, and the element number result of the sorting result in Tr is recorded as ix. For example: Tr=[32 12 45], after reordering, xt=[12 32 45], ix=[2 1 3].

S33.i=i+1,若i≤n,进入步骤S32,否则,进入步骤S4。S33. i=i+1, if i≤n, go to step S32, otherwise, go to step S4.

步骤S4.按照检查次序,根据各部件的状态检查消耗时间和修理各失效部件消耗时间,计算修复完成时间数组。Step S4. According to the inspection order, calculate the repair completion time array according to the state inspection time of each component and the repair time of each failed component.

优选地,步骤S4包括:Preferably, step S4 includes:

S41.设置部件检查序号i=1;S41. Set the component inspection sequence number i=1;

S42.计算修复完成时间数组

Figure BDA0003908069920000081
S42. Calculate repair completion time array
Figure BDA0003908069920000081

S43.i=i+1,若i≤n,进入步骤S42,否则,进入步骤S5。S43. i=i+1, if i≤n, go to step S42, otherwise, go to step S5.

步骤S5.升序排列修复完成时间数组内各元素,得到排序后的部件编号和对应修复完成时间。Step S5. Arrange the elements in the repair completion time array in ascending order to obtain the sorted part numbers and corresponding repair completion times.

步骤S6.按照排序后的次序,累计计算各部件的修理权重系数,得到设备发生故障后在各修复完成时间内完成修复的概率分布。Step S6. According to the sorted order, the repair weight coefficients of each component are calculated accumulatively, and the probability distribution of repair completion within each repair completion time after the equipment fails is obtained.

优选地,步骤S6包括:Preferably, step S6 includes:

S61.设置排序后的排序序号i=1;S61. Set the sorting sequence number i=1 after sorting;

S62.计算在时间xti内完成修复的概率PriS62. Calculate the probability Pr i of completing the restoration within the time xt i :

Figure BDA0003908069920000082
Figure BDA0003908069920000082

其中,xti表示排序结果中排序序号为i的部件修复完成时间,Pti=wj,j=ixi,ixi表示排序结果中排序序号为i的部件编号,wj表示任务时间内该部件的修理权重系数;Among them, xt i represents the repair completion time of the component with the sequence number i in the sorting result, Pt i =w j , j=ix i , ix i represents the component number with the sequence number i in the sorting result, and w j represents the component number with the sequence number i in the task time The repair weight factor of the component;

S63.i=i+1,若i≤n,进入步骤S52,否则,终止计算,输出所有xti和PriS63.i=i+1, if i≤n, go to step S52, otherwise, terminate the calculation and output all xt i and Pr i .

优选地,该方法还包括:S7.选择期望时间,将距离期望时间最近的xti对应的概率Pri,作为期望时间内完成修复的概率;其中,xti表示排序结果中排序序号为i的部件修复完成时间,Pri表示在时间xti内完成修复的概率。Preferably, the method further includes: S7. Selecting the expected time, taking the probability Pr i corresponding to the xt i closest to the expected time as the probability of completing the repair within the expected time; wherein, xt i represents the number i in the sorting result Completion time of component repair, Pr i represents the probability of completing repair within time xt i .

本发明提供了一种设备故障修复时间的概率分布的估计系统,包括处理器和存储器;所述存储器,用于存储计算机执行指令;所述处理器,用于执行所述计算机执行指令,使得上述方法被执行。The present invention provides a system for estimating the probability distribution of equipment fault repair time, including a processor and a memory; the memory is used to store computer-executed instructions; the processor is used to execute the computer-executed instructions, so that the above-mentioned method is executed.

实施例:已知某部件由10个伽马分布单元组成,各单元的相关信息如表1,即将执行100小时的任务。约定发生故障后,依次按照单元序号2、9、8、6、1、4、10、7、5、3进行状态检查,直至找到失效单元后,对该单元进行修理,完成修复。采用上述方法,计算修复该故障的时间分布结果,并估计在一个半小时内完成修复的概率是多少?Example: It is known that a certain component is composed of 10 gamma distribution units, and the relevant information of each unit is shown in Table 1, and a task of 100 hours is about to be performed. It is agreed that after a fault occurs, the status inspection shall be carried out according to the unit serial number 2, 9, 8, 6, 1, 4, 10, 7, 5, and 3, until the failed unit is found, and the unit shall be repaired to complete the repair. Using the above method, calculate the time distribution result of repairing the fault, and estimate the probability that the repair will be completed within one and a half hours?

表1各单元的相关信息Table 1 Relevant information of each unit

Figure BDA0003908069920000091
Figure BDA0003908069920000091

1)遍历计算各单元发生故障的概率Pf,单元1至单元10单元发生故障的概率分别为:0.066、0.056、0.155、0.076、0.227、0.094、0.132、0.101、0.006、0.019。1) Traversingly calculate the failure probability Pf of each unit, the failure probability of unit 1 to unit 10 is respectively: 0.066, 0.056, 0.155, 0.076, 0.227, 0.094, 0.132, 0.101, 0.006, 0.019.

2)按照检查次序gInd,遍历计算修理权重系数w为0.060、0.006、0.108、0.101、0.071、0.081、0.021、0.141、0.244、0.166;Tc为13、18、11、18、6、13、14、23、9、7;Tx为7、5、21、19、10、14、6、9、10、13。2) According to the inspection sequence gInd, the traversal calculation repair weight coefficient w is 0.060, 0.006, 0.108, 0.101, 0.071, 0.081, 0.021, 0.141, 0.244, 0.166; Tc is 13, 18, 11, 18, 6, 13, 14, 23, 9, 7; Tx is 7, 5, 21, 19, 10, 14, 6, 9, 10, 13.

3)计算修复完成时间数组Tr,Tr为20、36、63、79、76、93、99、125、135、145。3) Calculate the repair completion time array Tr, where Tr is 20, 36, 63, 79, 76, 93, 99, 125, 135, 145.

4)按照从小到大,对Tr中的元素进行排序,排序结果xt为20、36、63、76、79、93、99、125、135、145;该排序结果在Tr中的元素编号结果ix为1、2、3、5、4、6、7、8、9、10。4) Sort the elements in Tr from small to large, and the sorting result xt is 20, 36, 63, 76, 79, 93, 99, 125, 135, 145; the sorting result is the element number result ix in Tr 1, 2, 3, 5, 4, 6, 7, 8, 9, 10.

5)计算修复时间分布概率Pr,Pr为0.06、0.07、0.17、0.24、0.35、0.43、0.45、0.59、0.83、1.00。5) Calculate the repair time distribution probability Pr, Pr is 0.06, 0.07, 0.17, 0.24, 0.35, 0.43, 0.45, 0.59, 0.83, 1.00.

6)终止计算,输出xt、Pr。通过查表可知,xt中最接近一个半小时的是93分钟,因此在一个半小时内完成修复工作的概率大概为0.43。6) Terminate the calculation and output xt, Pr. It can be seen from the table lookup that the closest one and a half hours in xt is 93 minutes, so the probability of completing the repair work within one and a half hours is about 0.43.

可建立仿真模型验证上述方法的正确性,仿真模型简述如下:A simulation model can be established to verify the correctness of the above method. The simulation model is briefly described as follows:

(1)产生n个随机数simTi,1≤i≤n,simTi服从单元i的寿命分布规律,且要求所有的simTi>ti成立,则各单元的剩余寿命sTi=simTi-ti(1) Generate n random numbers simT i , 1≤i≤n, simT i obeys the life distribution law of unit i, and requires all simT i >t i to be established, then the remaining life of each unit sT i =simT i - t i .

(2)在所有sTi中寻找最小数,对应的序号记为m,即:sTm≤sTi,1≤i≤n。(2) Find the smallest number among all sT i , and record the corresponding number as m, namely: sT m ≤ sT i , 1≤i≤n.

(3)若sTm<Tw成立,则本次仿真有效,根据检查次序可得到消耗的检查时间,其与该单元的修理时间之和,即为本次修复时间的模拟结果。(3) If sT m < Tw holds true, this simulation is valid, and the sum of the consumed inspection time and the repair time of the unit is obtained according to the inspection order, which is the simulation result of this repair time.

在大量多次模拟后,可统计得到修复该故障所消耗时间的概率分布结果。After a large number of simulations, the probability distribution results of the time consumed to repair the fault can be obtained statistically.

在大量多次模拟后,可统计得到修复时间的概率分布。图2为本发明实施例提供的分别采用仿真法和本发明方法得到的修复时间在20~145分钟范围内完成修复的概率分布结果。考虑到仿真的随机性,图2表明二者的结果极为一致。仿真结果表明:该故障的平均修复时间为106.7分钟,修复时间的根方差为34.8分钟。因其修复时间的变化波动较大,以平均修复时间来开展维修管理计划等方面的工作还是较为粗略。After a large number of simulations, the probability distribution of repair time can be obtained statistically. Fig. 2 shows the probability distribution results of the restoration completed in the range of 20 to 145 minutes by using the simulation method and the method of the present invention respectively provided by the embodiment of the present invention. Considering the randomness of the simulation, Figure 2 shows that the results of the two are very consistent. The simulation results show that the average repair time of the fault is 106.7 minutes, and the root variance of the repair time is 34.8 minutes. Because the change of repair time fluctuates greatly, it is relatively rough to use the average repair time to carry out maintenance management planning and other aspects.

大量仿真验证结果表明:本发明方法能同时考虑装备的可靠性(各单元的寿命分布规律)、装备的健康状态(累积已工作时间)、装备基本组成单元的维修性(各单元的状态检查时间和修理时间)和任务时间等因素的影响,准确估计修复时间的概率分布,相比MTTR指标,能更具体、详尽地描述装备的维修性,可用于装备设计阶段的维修性设计方案评估、装备使用阶段的维修方案优化。A large number of simulation verification results show that: the method of the present invention can simultaneously consider the reliability of the equipment (the life distribution law of each unit), the health status of the equipment (accumulated working time), the maintainability of the basic components of the equipment (the state inspection time of each unit) and repair time) and task time, and accurately estimate the probability distribution of repair time. Compared with the MTTR index, it can describe the maintainability of equipment more specifically and in detail, and can be used in the evaluation of maintainability design schemes and equipment Maintenance program optimization in the phase of use.

本领域的技术人员容易理解,以上所述仅为本发明的较佳实施例而已,并不用以限制本发明,凡在本发明的精神和原则之内所作的任何修改、等同替换和改进等,均应包含在本发明的保护范围之内。It is easy for those skilled in the art to understand that the above descriptions are only preferred embodiments of the present invention, and are not intended to limit the present invention. Any modifications, equivalent replacements and improvements made within the spirit and principles of the present invention, All should be included within the protection scope of the present invention.

Claims (7)

1. A method for estimating a probability distribution of a time for failure recovery of a device, wherein the device comprises a plurality of components, the lives of the components are subject to a gamma distribution, at most one component fails at any time in the whole task time, and the order of state checking of the components is independent and irrelevant when troubleshooting, the method comprising:
s1, acquiring a gamma distribution density function, state inspection consumption time and accumulated working time of the service life obeying of each component, acquiring the inspection sequence of all components after the consumption time and the fault of each failed component are repaired, and taking a working period of equipment as task time;
s2, in the task time, the accumulated working time of each component is combined, the gamma distribution density function integral subject to the service life is calculated, and the probability of each component in the task time of failure is obtained;
s3, according to the inspection sequence and according to the probability of the faults of all the components in the task time, calculating the repair weight coefficient of all the components in the task time;
s4, according to the checking sequence, checking the time consumption of each component according to the state of each component and the time consumption of repairing each failed component, and calculating a repair completion time array;
s5, arranging elements in the repair completion time array in an ascending order to obtain the ordered part numbers and the corresponding repair completion time;
and S6, according to the sequence after sequencing, cumulatively calculating the repair weight coefficients of all the parts to obtain the probability distribution of completing repair within each repair completion time after the equipment fails.
2. The method of claim 1, wherein step S2 comprises:
s21, setting a part number i =1;
s22, calculating the failure probability Pf of the component i in the task time Tw i
Figure FDA0003908069910000011
When k = is set to a value of k = b,
Figure FDA0003908069910000012
when k ≠ i, it is,
Figure FDA0003908069910000021
wherein n represents the number of parts, g k (t) represents the conditional probability of component k, a k 、b k Shape parameter and scale parameter in gamma distribution density function respectively representing life obeys of component k, gamma represents gamma function, t k Represents the cumulative operating time of the component k;
s23.I = i +1, if i ≦ n, go to step S22, otherwise, go to step S3.
3. The method of claim 1, wherein step S3 comprises:
s31, setting a component checking serial number i =1;
s32, calculating the repair weight coefficient of the component corresponding to the inspection serial number i in the task time:
Figure FDA0003908069910000022
and two intermediate variables are assigned as follows:
Tc i =tc j ,Tx i =tx j
wherein,n denotes the number of parts, j = gInd i ,Pf j Indicates the probability of failure occurrence in the component task time of number j, gInd indicates the inspection order for all components after failure occurrence, tc j The time consumed for checking the state of the part denoted by the number j, tx j Indicating the elapsed time for repairing the failed part numbered j;
and S33.I = i +1, if i is less than or equal to n, the step S32 is carried out, otherwise, the step S4 is carried out.
4. The method of claim 3, wherein step S4 comprises:
s41, setting a component checking serial number i =1;
s42, calculating a repair completion time array
Figure FDA0003908069910000023
S43.I = i +1, if i ≦ n, proceed to step S42, otherwise, proceed to step S5.
5. The method of claim 4, wherein step S6 comprises:
s61, setting a sorted sorting serial number i =1;
s62, calculating the time xt i Probability Pr of internal completion repair i
Figure FDA0003908069910000031
Wherein xt is i Represents the repair completion time of the component with the sequence number i in the sequencing result, pt i =w j ,j=ix i ,ix i The part number with the sequence number i in the sequencing result, w j A repair weight coefficient representing the component at the mission time;
s63.I = i +1, if i is less than or equal to n, the step S52 is entered, otherwise, the calculation is terminated, and all xt are output i And Pr i
6. The method of claim 1, further comprising:
s7, selecting expected time, and enabling xt closest to the expected time i Corresponding probability Pr i As the probability of completing the repair within the desired time;
wherein xt is i Representing the repair completion time, pr, of the component with the sequence number i in the sequencing result i Is expressed at time xt i Probability of completing the repair internally.
7. A system for estimating a probability distribution of device failure recovery times, comprising a processor and a memory;
the memory is used for storing computer execution instructions;
the processor, configured to execute the computer-executable instructions to cause the method of any one of claims 1 to 6 to be performed.
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Cited By (2)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
CN116579494A (en) * 2023-05-23 2023-08-11 中国人民解放军海军工程大学 Spare parts inventory prediction method and system for electromechanical equipment based on time-consuming maintenance
CN116579494B (en) * 2023-05-23 2024-03-19 中国人民解放军海军工程大学 Spare part inventory prediction method and system based on electromechanical equipment under maintenance time consumption

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