CN115146354B - Automatic generation method of column reinforcement - Google Patents

Automatic generation method of column reinforcement Download PDF

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CN115146354B
CN115146354B CN202210824992.4A CN202210824992A CN115146354B CN 115146354 B CN115146354 B CN 115146354B CN 202210824992 A CN202210824992 A CN 202210824992A CN 115146354 B CN115146354 B CN 115146354B
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赵广坡
王逸凡
康永君
周盟
方长建
饶明航
赖逸峰
白蜀珺
刘济凡
黄扬
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China Southwest Architectural Design and Research Institute Co Ltd
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Abstract

The invention relates to the technical field of building design and discloses an automatic generation method of column reinforcementA method, comprising: s1, a stirrup allowable diameter meter and a longitudinal stirrup allowable diameter meter corresponding to a custom rectangular column; s2, respectively determining the diameters dj of first corner ribs of the B side of the rectangular column 1 The diameter dj of the first corner rib 1 The diameter of the corresponding first middle longitudinal ribs and the number of the first middle longitudinal ribs; s3, determining the first middle longitudinal rib number corresponding to the B side of the rectangular column and the second middle longitudinal rib number corresponding to the H side, and comparing whether the difference between the first middle longitudinal rib number and the second middle longitudinal rib number exceeds a threshold value or not; s4, determining the diameter of the first stirrup corresponding to the side B according to the determined diameter of the first middle longitudinal bar and the number of the first middle longitudinal bars; s5, calculating the stirrup spacing of the column stirrup non-encryption area according to the stirrup non-encryption area calculated value, the stirrup diameter and the industry specification requirement. The invention can automatically complete the drawing of the detailed reinforcing bar drawing.

Description

Automatic generation method of column reinforcement
Technical Field
The invention relates to the technical field of building design, in particular to an automatic generation method of column reinforcement.
Background
The construction drawing plane integral design method (plain method) of the building structure is generally adopted in the structural design, and the size and the reinforcing bars of the structural members are simply represented in a plane writing mode.
In the present design of construction drawings of building engineering structures, how to efficiently and accurately design structural members becomes an important point and a difficult point of the industry. Typically, structural computing software can generate column reinforcement, but its reinforcement accuracy and construction requirements are difficult to meet specification standards and design requirements. In addition, many mistakes are inevitably made during manual drawing, and the mistakes are needed to be avoided and solved.
Disclosure of Invention
The invention provides an automatic generation method of column reinforcement, which can automatically generate a concrete rectangular column reinforcement detailed diagram based on computer programming, automatically complete the drawing of the reinforcement detailed diagram according to parameters such as the size, the position, the elevation, the calculation information, the concrete strength grade, the earthquake resistant grade and the like of a frame column in a concrete structure, and the column reinforcement diagram drawn by the method meets the national standard requirements, and considers economy and structural design rationality as much as possible to meet the design requirements.
The invention is realized by the following technical scheme:
an automatic column reinforcement generation method comprises the following steps:
s1, customizing a stirrup allowable diameter meter and a longitudinal bar allowable diameter meter corresponding to a rectangular column according to own reinforcement habit of a designer;
s2, respectively determining the diameters dj of first corner ribs of the B side of the rectangular column 1 Second corner bead diameter dj of H edge 2 Taking the diameter dj of the first corner rib 1 And a second angular rib diameter dj 2 The middle and larger value is the diameter dj of the corner rib corresponding to the rectangular column;
s3, determining a first middle longitudinal rib number, a corresponding first middle longitudinal rib diameter, a corresponding second middle longitudinal rib number and a corresponding second middle longitudinal rib diameter according to the determined angle rib diameter dj and the longitudinal rib calculated value, comparing whether the difference between the first middle longitudinal rib number and the second middle longitudinal rib number exceeds a threshold value, returning to the step if yes, and re-determining the first middle longitudinal rib number and the second middle longitudinal rib number, otherwise, jumping to S4;
s4, determining a first stirrup diameter corresponding to the B side and a second stirrup diameter corresponding to the H side according to the determined first middle longitudinal bar diameter, the determined first middle longitudinal bar number, the determined second middle longitudinal bar diameter, the determined second middle longitudinal bar number, the determined stirrup allowable diameter table, the determined stirrup calculation value and the determined industry specification requirement, and taking the larger value of the first stirrup diameter and the determined second stirrup diameter as the stirrup diameter corresponding to the rectangular column;
s5, calculating the stirrup spacing of the stirrup non-encryption area of the column according to the calculated value of the stirrup non-encryption area, the stirrup diameter corresponding to the rectangular column and the industry specification requirement;
and S6, drawing a column reinforcement detailed diagram according to the results obtained in the steps S2-S5.
As optimization, in step S2, determining a first corner diameter dj corresponding to the B side of the rectangular column 1 The specific steps of the value range of (a) are as follows:
s2.1, selecting a first minimum angle rib diameter dj meeting the angle rib calculated value of the B side in the longitudinal rib allowable diameter table 1min ；
S2.2 based on the first minimum fillet diameter dj 1min On the premise of ensuring that the spacing between longitudinal bars in the middle meets the requirement of industry specifications, the diameters of the angle bars are gradually increased and adjusted, the reinforcement form of a single row of the angle bars is adopted, the calculated value of the B-edge reinforcement (calculated value of the B-edge reinforcement=calculated value of the B-edge corner bar+calculated value of the B-edge middle longitudinal bar) is combined, the number of first middle longitudinal bars and the diameters of the first middle longitudinal bars in the same row corresponding to the B-edge are calculated, so that the calculation requirement of the 'middle longitudinal bar area+angle bar area is larger than or equal to the calculated value of the B-edge reinforcement' can be met by arranging the first middle longitudinal bars in the same row, and at the moment, the minimum angle bar diameter meeting the calculation requirement is the first angle bar diameter dj 1 Is a value range of (a);
s2.3, if the maximum value in the longitudinal bar allowable diameter table in the step S2.2, which is obtained by increasing the diameter of the corner bar, still cannot meet the calculation requirement that the area of the middle longitudinal bar and the area of the corner bar are not smaller than the output calculated value, reinforcing bars are arranged in a form of corner bar parallel bars, and at the moment, the maximum value of the longitudinal bar diameter in the longitudinal bar allowable diameter table is the first corner bar diameter dj 1 。
As an optimization of this process,in step S2, determining a second corner rib diameter dj corresponding to the H-edge of the rectangular column 2 The specific steps of (a) are as follows:
s2.4, selecting a second minimum angle rib diameter dj meeting the angle rib calculated value of the H side in the longitudinal rib allowable diameter table 2min ；
S2.5 based on the second minimum angular rib diameter dj 2min On the premise of ensuring that the spacing between longitudinal bars meets the requirement of industry specifications, adopting a bar arrangement form of a single row of the angle bars, and calculating the number of second middle longitudinal bars and the diameter of the second middle longitudinal bars in the same row corresponding to the H side by combining the calculated value of the H side bar, so that the calculated requirement of 'the area of the middle longitudinal bars and the area of the angle bars are more than or equal to the calculated value of the H side bar' can be met by arranging the second middle longitudinal bars of the single row on the H side in the same row, and at the moment, the minimum angle bar diameter meeting the calculated requirement is the second angle bar diameter dj 2 Is a value range of (a);
s2.6, if the maximum value in the longitudinal bar allowable diameter table in the step S2.5 is still unable to meet the calculation requirement that the area of the middle longitudinal bar and the area of the angle bar are not less than the output calculated value, reinforcing bars in the form of parallel bars are adopted, and at the moment, the maximum value of the longitudinal bar diameter in the longitudinal bar allowable diameter table is the second angle bar diameter dj 2 。
As optimization, the number of the first intermediate longitudinal ribs, the diameter of the first intermediate longitudinal ribs and the diameter dj of the first corner ribs 1 The relation between the two is:
wherein N is BM1 The number of the first middle longitudinal ribs d BM1 For the diameter of the first middle longitudinal rib, A sB Calculating a value for reinforcing bars on the side B, A sM Representing the middle longitudinal bar arrangement area;
the number of the second intermediate longitudinal ribs, the diameter of the second intermediate longitudinal ribs and the diameter dj of the second corner ribs 2 The relation between the two is:
wherein N is BM2 The number of the second middle longitudinal ribs d BM2 Is the diameter of the second middle longitudinal rib, A sH Calculated value for reinforcing bar of H edge, A sM The middle longitudinal bar arrangement area is shown.
As an optimization, the first corner bead diameter dj 1 The diameter dj of the first corner rib 1 Corresponding diameter d of first middle longitudinal rib BM1 Number N of first middle longitudinal ribs BM1 The screening conditions of (2) are as follows:
a1, if the number N of the same first middle longitudinal ribs corresponding to the B side BM1 Corresponding to the diameters d of a plurality of first middle longitudinal ribs BM1 Selecting the corresponding smallest diameter d of the first middle longitudinal rib BM1 Carrying out the next operation;
a2, if the number N of the first intermediate longitudinal ribs is obtained BM1 So that the interval of the first middle longitudinal ribs does not meet the requirement of industry specification, and the number N of the first middle longitudinal ribs is not selected BM1 ；
A3, if no first intermediate longitudinal rib number N is selected BM1 If the requirement of industry specification is met, judging that the reinforcement fails; if there is a first intermediate longitudinal rib number N BM1 If meeting the industry specification requirement, selecting the number N of the first middle longitudinal ribs BM1 Corresponding diameter d of first middle longitudinal rib BM1 And a first angular rib diameter dj 1 The method comprises the steps of carrying out a first treatment on the surface of the If there are at least two different first intermediate longitudinal rib numbers N BM1 If meeting the industry specification requirement, selecting the largest two first middle longitudinal rib diameters d BM1 Corresponding first middle longitudinal rib number N BM1 ；
A4, selecting the minimum stirrup diameter in the diameter table based on the stirrups for trial calculation, and if the number N of the two first middle longitudinal ribs screened by the A3 is smaller than the number N BM1 The calculated value of the stirrup encryption area is satisfied, a smaller first middle longitudinal rib number N is selected BM1 The method comprises the steps of carrying out a first treatment on the surface of the If the number N of the two first middle longitudinal ribs screened by A3 BM1 Only one calculated value meeting the stirrup encryption area is selected and used, and the first intermediate longitudinal rib number N meeting the calculated value of the stirrup encryption area is selected BM1 The method comprises the steps of carrying out a first treatment on the surface of the If the number N of the two first middle longitudinal ribs screened by A3 BM1 If the calculated value of the stirrup encryption area is not satisfied, the diameter of the first-stage stirrup is increased, and the step is returned to continue trial calculation;
a5, if the calculated value of the stirrup in the encryption area cannot be met even if the maximum available stirrup diameter in the diameter table is selected as the stirrup in A4, the first number N of middle longitudinal bars is not selected BM1 The reinforcement fails.
As optimization, the second angle rib diameter dj 2 The diameter dj of the second angle rib 2 Corresponding second middle longitudinal rib diameter d BM2 Number N of second middle longitudinal ribs BM2 The screening conditions of (2) are as follows:
b1, the number N of the same second middle longitudinal ribs corresponding to the H edge BM2 Corresponding to the diameters d of a plurality of first middle longitudinal ribs BM2 Selecting the corresponding smallest diameter d of the first middle longitudinal rib BM2 Carrying out the next operation;
b2, if the number N of the second intermediate longitudinal ribs is obtained BM2 So that the spacing of the second middle longitudinal ribs does not meet the industry specification requirement, and the number N of the second middle longitudinal ribs is not selected BM2 ；
B3, if no second intermediate longitudinal ribs N are selected BM2 If the requirement of industry specification is met, judging that the reinforcement fails; if there is a second intermediate longitudinal rib number N BM2 The number N of the second middle longitudinal ribs is selected if the requirement of industry specification is met BM2 Corresponding second middle longitudinal rib diameter d BM2 And a second angular rib diameter dj 2 The method comprises the steps of carrying out a first treatment on the surface of the If there are at least two different second intermediate longitudinal rib numbers N BM2 Meeting the industry specification requirement, selecting the largest two second middle longitudinal rib diameters d BM2 Corresponding second intermediate longitudinal rib number N BM2 ；
B4, selecting the minimum stirrup diameter in the diameter table based on the stirrups for trial calculation, and if the number N of the two second middle longitudinal ribs screened by the B3 is smaller than the number N BM2 The calculated value of the stirrup encryption area is satisfied, and then the second smaller intermediate longitudinal rib number N is selected BM2 The method comprises the steps of carrying out a first treatment on the surface of the If the number N of the two second middle longitudinal ribs screened by B3 BM2 Only one meeting the stirrup encryption areaSelecting the second intermediate longitudinal bar number N meeting the calculated value of the stirrup encryption area BM2 The method comprises the steps of carrying out a first treatment on the surface of the If the number N of the two second middle longitudinal ribs screened by B3 BM2 If the calculated value of the stirrup encryption area is not satisfied, the diameter of the first-stage stirrup is increased, and the step is returned to continue trial calculation;
b5, if the calculated value of the stirrup in the encryption area cannot be met even if the maximum available stirrup diameter in the diameter table is selected as the stirrup in the B4, the number N of the second middle longitudinal ribs is not selected BM2 The reinforcement fails.
As optimization, the specific steps of step S3 are:
s3.1, enabling the number of unidirectional stirrups in the column encryption area to be equal to the number of middle longitudinal ribs in the direction, wherein the number of the stirrups is generally equal to the number of single-row longitudinal ribs;
s3.2, respectively calculating a first minimum stirrup diameter required by the B side and a second minimum stirrup diameter required by the H side according to the set stirrup spacing and the stirrup calculation value of the column encryption area;
s3.3, judging whether the first minimum stirrup diameter is equal to the second minimum stirrup diameter, if not, considering that the difference between the first middle longitudinal rib number and the second middle longitudinal rib number is overlarge, and adjusting the first middle longitudinal rib diameter and/or the second middle longitudinal rib diameter to adjust the first middle longitudinal rib number and/or the second middle longitudinal rib number until the difference between the first middle longitudinal rib number and the second middle longitudinal rib number is smaller than a threshold value.
As optimization, in S4, the specific calculation mode of the first stirrup diameter is: the program column stirrup interval is 100, and the stirrup diameter is setWherein dv is B The diameter of the first stirrup corresponding to the B side is A sv Calculating a larger value for stirrups in a column node core area and a column stirrup encryption area, and n B The number of the stirrup limbs on the side B is the number.
As optimization, in S4, the specific calculation mode of the second stirrup diameter is: the program column stirrup interval is 100, and the stirrup diameter is setWherein dv is H The diameter of the second stirrup on the H side is A sv Calculating a larger value for stirrups in a column node core area and a column stirrup encryption area, and n H The number of H-edge stirrups is the number of the H-edge stirrups.
As optimization, in S5, the specific calculation mode of the stirrup spacing in the non-encrypted area of the column stirrup is as follows: in general, the diameters of the hoops in the encryption area and the non-encryption area are equal, the hoops in the non-encryption area are half of the hoops in the encryption area, namely, the hoops in the encryption area are 100, the hoops in the non-encryption area are 200, and the requirements of industry specifications are met, for example, the diameters of the longitudinal reinforcing steel bars of the first-stage frame column and the second-stage frame column are not larger than 10 times, and the diameters of the longitudinal reinforcing steel bars of the third-stage frame column and the fourth-stage frame column are not larger than 15 times.
Compared with the prior art, the invention has the following advantages and beneficial effects:
according to the method, the concrete rectangular column reinforcement detailed diagram can be automatically generated, the drawing of the concrete rectangular column reinforcement detailed diagram is automatically completed according to parameters such as the size, the position, the elevation, the calculation information, the concrete strength grade, the earthquake resistant grade and the like of the frame column in the concrete structure, the column reinforcement diagram drawn by the method meets the national standard requirements, economy and structural design rationality are considered as much as possible to meet the design requirements, the drawing efficiency of the column reinforcement diagram is improved, and errors possibly occurring in the aspects of specification and labeling of manual drawing are reduced.
Drawings
In order to more clearly illustrate the technical solutions of the exemplary embodiments of the present invention, the drawings that are needed in the examples will be briefly described below, it being understood that the following drawings only illustrate some examples of the present invention and therefore should not be considered as limiting the scope, and that other related drawings may be obtained from these drawings without inventive effort for a person skilled in the art. In the drawings:
FIG. 1 is a flow chart of an automatic column reinforcement generation method according to the present invention;
FIG. 2 is an exemplary chart of a stirrup allowable diameter table and a longitudinal stirrup allowable diameter table;
FIG. 3 is a graph showing calculated values of column KZ180 in the example;
fig. 4 is a schematic diagram of the reinforcement results automatically generated by column KZ180 according to the present invention.
Detailed Description
For the purpose of making apparent the objects, technical solutions and advantages of the present invention, the present invention will be further described in detail with reference to the following examples and the accompanying drawings, wherein the exemplary embodiments of the present invention and the descriptions thereof are for illustrating the present invention only and are not to be construed as limiting the present invention.
Examples
As shown in fig. 1, a flowchart of the automatic column reinforcement generating method according to the present invention specifically includes:
s1, customizing a stirrup allowable diameter table and a longitudinal bar allowable diameter table corresponding to the rectangular column according to own reinforcement habit of a designer.
As shown in fig. 2, an example of the stirrup allowable diameter table and the longitudinal bar allowable diameter table is shown. Different stirrup allowable diameter meters and longitudinal bar allowable diameter meters are defined according to the own reinforcement habit of a designer. The parameters of the allowable diameter table of the stirrup and the allowable diameter table of the longitudinal bar represent the use values of the diameter of the stirrup and the diameter of the longitudinal bar, respectively.
S2, respectively determining the diameters dj of first corner ribs of the B side of the rectangular column 1 Second corner bead diameter dj of H edge 2 Taking the diameter dj of the first corner rib 1 And a second angular rib diameter dj 2 The middle and larger value is the diameter dj of the corner rib corresponding to the rectangular column; for example, if the minimum first fillet diameter dj meets the calculation requirement 1 22, second corner bead diameter dj 2 18, the corresponding corner rib diameter dj of the rectangular column is 22.
1. Firstly, considering a reinforcement scheme (B1) of one pair of sides (B sides) of a rectangular column:
in this embodiment, a first corner rib diameter dj corresponding to the B side of the rectangular column is determined 1 The specific steps of (a) are as follows:
s2.1, selecting a first minimum angle rib diameter dj meeting the angle rib calculated value of the B side in the longitudinal rib allowable diameter table 1min 。
In a user-defined available 'longitudinal bar allowable diameter table', the minimum corner bar diameter meeting the requirements of the corner bar calculation value of the side B is selected. The calculation software (commonly used software for structural calculation such as PKPM or YJK, which is the prior art) can output the calculation value of the column angle rib (according to the stress condition, the mechanics principle and the industry standard), and the real angle rib area needs to be not smaller than the angle rib calculation value of the B side.
S2.2 based on the first minimum fillet diameter dj 1min On the premise of ensuring that the spacing between longitudinal bars in the middle meets the requirement of industry specifications, the diameters of the angle bars are gradually increased and adjusted, the reinforcement form of a single row of the angle bars is adopted, the calculated value of the B-edge reinforcement (calculated value of the B-edge reinforcement=calculated value of the B-edge corner bar+calculated value of the B-edge middle longitudinal bar) is combined, the number of first middle longitudinal bars and the diameters of the first middle longitudinal bars in the same row corresponding to the B-edge are calculated, so that the calculation requirement of the 'middle longitudinal bar area+angle bar area is larger than or equal to the calculated value of the B-edge reinforcement' can be met by arranging the first middle longitudinal bars in the same row, and at the moment, the minimum angle bar diameter meeting the calculation requirement is the first angle bar diameter dj 1 Is a range of values.
S2.3, if the maximum value in the longitudinal bar allowable diameter table in the step S2.2 is still unable to meet the calculation requirement that the area of the middle longitudinal bar plus the area of the angle bar is larger than or equal to the output calculation value (B-side bar arrangement calculation value), the bar arrangement is performed in a form of parallel bars of the angle bars, and at the moment, the maximum value of the longitudinal bar diameter in the longitudinal bar allowable diameter table is the first angle bar diameter dj 1 And then the number of the first middle longitudinal ribs of the B side in the same row is recalculated.
Assuming that the diameter of the angle rib is larger than or equal to the diameter of the first middle longitudinal rib, under the condition that the distance between the first middle longitudinal ribs is ensured to meet the requirements of industry specifications (the industry specifications include but not limited to the requirements of building earthquake-resistant design specifications GB50011-2010, & high-rise building concrete structure specifications JGJ3-2010, & concrete structure specifications GB 50010-2010) and the requirements of the angle rib are met, the diameter of the angle rib is tried to be adjusted, so that the calculated requirement can be met by arranging only a single row (same row) of first middle longitudinal ribs on the side B (the area of the middle longitudinal rib and the area of the angle rib are larger than or equal to the calculated value of software, the diameter of the middle reinforcing rib cannot be larger than the diameter of the angle rib, for example, the diameter of the angle rib is 16, the diameter of the middle reinforcing rib is 16 at most, and according to the calculated value, the middle reinforcing rib is 10 reinforcing ribs, but because of the specification distance limitation is provided, only 8 reinforcing ribs can be selected for the middle reinforcing ribs, if the diameter of the angle rib is 18, if the angle rib is not met, the maximum value is not met, the diameter of the maximum value of the rib can not be found, and the required by the diameter of the rib is found.
In this embodiment, the number of first intermediate longitudinal ribs, the diameter of the first intermediate longitudinal ribs, and the diameter dj of the first corner ribs 1 The relation between the two is:
wherein N is BM1 The number of the first middle longitudinal ribs d BM1 For the diameter of the first middle longitudinal rib, A sB Calculating a value for reinforcing bars on the side B, A sM The middle longitudinal bar arrangement area is shown.
According to the diameter and form of the arranged angle bars (parallel bars or non-parallel bars) and the calculated value of the bar arrangement on the side B (obtained by outputting calculation software), combining with industry specification requirements (building earthquake-proof design specifications GB50011-2010, high-rise building concrete structure technical specifications JGJ3-2010 and concrete structure design specifications GB 50010-2010), reversely calculating the configuration scheme of the first middle longitudinal bar on the side B (assuming that the calculated value of the bar arrangement on the side B is A) sB The diameter of the first corner rib is dj 1 When the angle rib is a parallel rib, dj 1 Is equivalent in diameter, the reinforcement amount of the first middle longitudinal reinforcement isN BM The number of the first middle longitudinal ribs of the B side (N is rounded up) and d BM The diameter of the first middle longitudinal rib on the side B.
1. According to the formula, calculating each first middle longitudinal ribDiameter d BM1 Corresponding to the number N of the needed first middle longitudinal ribs BM1 A group of d-N (d BM1 -N BM1 ) Is a reinforcement scheme of a first middle longitudinal reinforcement.
2. Screening the scheme, wherein the column encryption area stirrup interval is assumed to be 100mm, and the number of unidirectional stirrup limbs is equal to the number of first middle longitudinal ribs in the direction:
(1) And if the same first middle longitudinal rib number N corresponding to the B side corresponds to a plurality of first middle longitudinal rib diameters d, selecting the corresponding smallest first middle longitudinal rib diameter d for next operation.
That is, if there are two sets of schemes, n1=n2 and d1< d2, scheme 2 is deleted, i.e., a scheme in which the first intermediate bead diameter d is smaller is retained.
(2) If the number N of the first middle longitudinal ribs in the scheme does not meet the requirements of the specifications of building earthquake-proof design Specification GB50011-2010, the technical specifications of high-rise building concrete structure JGJ3-2010 and the concrete structure design Specification GB50010-2010, the scheme is deleted. The relationship between the number N of first intermediate vertical bars and the first intermediate vertical bar pitch is that the first intermediate vertical bars are equally distributed in the same row within a predetermined length, and the pitch between adjacent first intermediate vertical bars is the first intermediate vertical bar pitch.
(3) If no residual scheme exists, the reinforcement fails; if one scheme is remained, selecting the scheme; if two or more schemes remain (the first intermediate longitudinal ribs N of the two schemes are different), two schemes (called scheme a and scheme B) with the largest diameter d of the first intermediate longitudinal rib are selected. The two schemes with the largest diameter of the first middle longitudinal ribs are selected to reduce the number of the longitudinal ribs, so that the total number of the steel bars on the section of the column is reduced, and the construction is facilitated.
(3.1) selecting different stirrup diameters for trial calculation, and performing trial calculation according to the following formula:
pi.dv.dv/4.n is greater than or equal to Asv, wherein dv is the diameter of stirrups, n is the number of stirrups, and Asv is a calculated value output by software; starting from the minimum value of the stirrups, if the schemes A, B meet the calculated value of the stirrup encryption area, selecting a scheme with smaller N value (the number of first middle longitudinal ribs); if the scheme A, B only has one calculated value meeting the stirrup encryption area, selecting the scheme; if the scheme A, B does not meet the calculated value of the stirrup encryption area, increasing the diameter of the first-stage stirrup and continuing trial calculation;
(3.2) if the number of first middle longitudinal bars N in a certain scheme cannot meet the calculated value of the stirrups in the encryption area even if the maximum available stirrup diameter is selected, deleting the scheme, namely, the number of the stirrups is too small, namely, the number of the longitudinal bars is too small.
2. Secondly, considering the reinforcement scheme (H1) of the other opposite side (H side) of the rectangular column, the method is the same as that of the B side, and the description is omitted here. The schemes B1 and H1 are then coordinated so that they share one corner bead configuration (the corner bead configuration in which the total area of the corner beads is larger is taken as the shared configuration).
S3, determining a first middle longitudinal rib number, a corresponding first middle longitudinal rib diameter, a corresponding second middle longitudinal rib number and a corresponding second middle longitudinal rib diameter according to the determined angle rib diameter dj and the longitudinal rib calculated value, comparing whether the difference between the first middle longitudinal rib number and the second middle longitudinal rib number exceeds a threshold value, returning to the step if yes, and re-determining the first middle longitudinal rib number and the second middle longitudinal rib number, otherwise, jumping to S4.
In this embodiment, the specific steps of step S3 are as follows:
s3.1, enabling the number of unidirectional stirrups in the column encryption area to be equal to the number of middle longitudinal ribs in the direction, wherein the number of the stirrups is generally equal to the number of single-row longitudinal ribs;
s3.2, respectively calculating a first minimum stirrup diameter required by the B side and a second minimum stirrup diameter required by the H side according to the set stirrup spacing and the stirrup calculation value of the column encryption area;
s3.3, judging whether the first minimum stirrup diameter is equal to the second minimum stirrup diameter, if not, considering that the difference between the first middle longitudinal rib number and the second middle longitudinal rib number is overlarge, and adjusting the first middle longitudinal rib diameter and/or the second middle longitudinal rib diameter to adjust the first middle longitudinal rib number and/or the second middle longitudinal rib number until the difference between the first middle longitudinal rib number and the second middle longitudinal rib number is smaller than a threshold value. The threshold value is determined according to the actual situation, and will not be described again.
Assuming that the column encryption area stirrup distance is 100mm and the number of unidirectional stirrup limbs is equal to the number of longitudinal stirrups in the direction, respectively reversely calculating the minimum stirrup diameters required by the schemes B1 and H1 according to the calculated value of the stirrups in the encryption area, and if the calculated minimum stirrup diameters of the schemes B1 and H1 are not equal, considering that the difference of the number of the middle longitudinal stirrups of the schemes B1 and H1 is too large, and carrying out coordination. The specific method comprises the following steps: if the number of first intermediate longitudinal bars of B1 is greater than the number of second intermediate longitudinal bars of H1, the number of first intermediate longitudinal bars of B1 solution is reduced by using bars of greater diameter (not exceeding the diameter of the corner bars) (the number should not be less than the corresponding number of H1 solution), and vice versa.
S4, determining a first stirrup diameter corresponding to the B side and a second stirrup diameter corresponding to the H side according to the determined first middle longitudinal bar diameter, the determined first middle longitudinal bar number, the determined second middle longitudinal bar diameter, the determined second middle longitudinal bar number, the determined stirrup allowable diameter table, the determined stirrup calculation value and the determined industry specification requirement, and taking the larger value of the first stirrup diameter and the determined second stirrup diameter as the stirrup diameter corresponding to the rectangular column.
In this embodiment, the specific calculation mode of the first stirrup diameter is: the program column stirrup interval is 100, and the stirrup diameter is setWherein dv is B The diameter of the first stirrup corresponding to the B side is A sv Calculating a larger value for stirrups in a column node core area and a column stirrup encryption area, and n B The number of the stirrup limbs on the side B is the number.
In this embodiment, the specific calculation mode of the second stirrup diameter is: the program column stirrup interval is 100, and the stirrup diameter is setWherein dv is H The diameter of the second stirrup on the H side is A sv Calculating a larger value for stirrups in a column node core area and a column stirrup encryption area, and n H The number of H-edge stirrups is the number of the H-edge stirrups.
S5, calculating the stirrup spacing of the non-encryption area of the column stirrup according to the calculated value of the non-encryption area of the stirrup, the diameter of the stirrup and the requirements of industry specifications;
in this embodiment, the specific calculation mode of the stirrup spacing in the non-encrypted area of the column stirrup is as follows: in S5, the specific calculation mode of the stirrup spacing of the column stirrup non-encryption area is as follows: in general, the diameters of the hoops in the encryption area and the non-encryption area are equal, the hoops in the non-encryption area are half of the hoops in the encryption area, namely, the hoops in the encryption area are 100, the hoops in the non-encryption area are 200, and the requirements of industry specifications are met, for example, the diameters of the longitudinal reinforcing steel bars of the first-stage frame column and the second-stage frame column are not larger than 10 times, and the diameters of the longitudinal reinforcing steel bars of the third-stage frame column and the fourth-stage frame column are not larger than 15 times.
And S6, drawing a column reinforcement detailed diagram according to the results obtained in the steps S2-S5.
As shown in FIG. 3, it can be seen that the column KZ180, the calculated value of the B-side longitudinal bar is 12cm 2 H-edge longitudinal rib calculated value is 19cm 2 The calculated value of the angle rib is 2.6cm 2 The calculated value of stirrups in the core area of the column node is 1.2cm 2 The calculated value of the stirrup encryption area is 1.1cm 2 Calculated value of the stirrup non-encryption area is 0.7cm 2 。
As shown in fig. 4, the column KZ180 is an automatically generated reinforcement result by the present invention.
As can be seen from fig. 4, the actual reinforcement values 2d25+2d20=16 > 12 on the B side, 2d25+3d22=21 > 19 on the h side, the angular tendon diameter d25=4.9 > 2.6, the stirrup encryption area c8@150 four-limb hoop, 1.3 > max (1.2,1.1) on the real side, the stirrup non-encryption area c8@200 four-limb hoop, 1.0 > 0.7 on the real side, and all the real reinforcement values meet the calculation value requirements, thereby verifying the reliability of the method.
The foregoing description of the embodiments has been provided for the purpose of illustrating the general principles of the invention, and is not meant to limit the scope of the invention, but to limit the invention to the particular embodiments, and any modifications, equivalents, improvements, etc. that fall within the spirit and principles of the invention are intended to be included within the scope of the invention.

Claims (8)

1. The automatic column reinforcement generation method is characterized by comprising the following steps of:
s1, a stirrup allowable diameter meter and a longitudinal stirrup allowable diameter meter corresponding to a custom rectangular column;
s2, respectively determining the diameters dj of first corner ribs of the B side of the rectangular column 1 Second corner bead diameter dj of H edge 2 Taking the diameter dj of the first corner rib 1 And a second angular rib diameter dj 2 The middle and larger value is the diameter dj of the corner rib corresponding to the rectangular column;
s3, determining a first middle longitudinal rib number, a corresponding first middle longitudinal rib diameter, a corresponding second middle longitudinal rib number and a corresponding second middle longitudinal rib diameter according to the determined angle rib diameter dj and the reinforcement calculated value, comparing whether the difference between the first middle longitudinal rib number and the second middle longitudinal rib number exceeds a threshold value, returning to the step if yes, and re-determining the first middle longitudinal rib number and the second middle longitudinal rib number, otherwise, jumping to S4;
the step S3 specifically comprises the following steps:
s3.1, enabling the number of unidirectional stirrups in the column encryption area to be equal to the number of middle longitudinal ribs in the direction;
s3.2, respectively calculating a first minimum stirrup diameter required by the B side and a second minimum stirrup diameter required by the H side according to the set stirrup spacing and the stirrup calculation value of the column encryption area;
s3.3, judging whether the first minimum stirrup diameter is equal to the second minimum stirrup diameter, if not, considering that the difference between the first middle longitudinal rib number and the second middle longitudinal rib number is overlarge, and adjusting the first middle longitudinal rib diameter and/or the second middle longitudinal rib diameter to adjust the first middle longitudinal rib number and/or the second middle longitudinal rib number until the difference between the first middle longitudinal rib number and the second middle longitudinal rib number is smaller than a threshold value;
the number of the first middle longitudinal ribs, the diameter of the first middle longitudinal ribs and the diameter dj of the first corner ribs 1 The relation between the two is:
wherein N is BM1 The number of the first middle longitudinal ribs d BM1 For the diameter of the first middle longitudinal rib, A sB Calculating a value for reinforcing bars on the side B, A sM Representing the middle longitudinal bar arrangement area;
the number of the second intermediate longitudinal ribs, the diameter of the second intermediate longitudinal ribs and the diameter dj of the second corner ribs 2 The relation between the two is:
wherein N is BM2 The number of the second middle longitudinal ribs d BM2 Is the diameter of the second middle longitudinal rib, A sH Calculated value for reinforcing bar of H edge, A sM Representing the middle longitudinal bar arrangement area;
the diameter of the first middle longitudinal rib and the diameter of the second middle longitudinal rib are not larger than the diameter dj of the angle rib;
s4, determining a first stirrup diameter corresponding to the B side and a second stirrup diameter corresponding to the H side according to the determined first middle longitudinal bar diameter, the determined first middle longitudinal bar number, the determined second middle longitudinal bar diameter, the determined second middle longitudinal bar number, the determined stirrup allowable diameter table, the determined stirrup calculation value and the determined industry specification requirement, and taking the larger value of the first stirrup diameter and the determined second stirrup diameter as the stirrup diameter corresponding to the rectangular column;
s5, calculating the stirrup spacing of the stirrup non-encryption area of the column according to the calculated value of the stirrup non-encryption area, the stirrup diameter corresponding to the rectangular column and the industry specification requirement;
and S6, drawing a column reinforcement detailed diagram according to the results obtained in the steps S2-S5.
2. The automatic column reinforcement generation method according to claim 1, wherein in step S2, a first corner reinforcement diameter dj corresponding to the B side of the rectangular column is determined 1 The specific steps of (a) are as follows:
s2.1, selecting a first minimum angle rib diameter dj meeting the angle rib calculated value of the B side in the longitudinal rib allowable diameter table 1min ；
S2.2 based on the first minimum fillet diameter dj 1min On the premise of ensuring that the spacing between longitudinal bars meets the requirement of industry specifications, adopting a bar arrangement form of a single row of the angle bars, and calculating the number of first middle longitudinal bars and the first middle longitudinal bar diameter in the same row corresponding to the B side by combining the calculated value of the B side, so that the calculated requirement of 'the area of the middle longitudinal bar + the calculated value of the bar arrangement with the area of the angle bar being larger than or equal to the calculated value of the B side' can be met by arranging the first middle longitudinal bars of the single row on the B side in the same row, and at the moment, the minimum angle bar diameter meeting the calculated requirement is the first angle bar diameter dj 1 ；
S2.3, if the maximum value in the longitudinal bar allowable diameter table in the step S2.2, which is obtained by increasing the diameter of the corner bar, still cannot meet the calculation requirement that the area of the middle longitudinal bar and the area of the corner bar are not smaller than the output calculated value, reinforcing bars are arranged in a form of corner bar parallel bars, and at the moment, the maximum value of the longitudinal bar diameter in the longitudinal bar allowable diameter table is the first corner bar diameter dj 1 。
3. The automatic column reinforcement generation method according to claim 2, wherein in step S2, a second corner reinforcement diameter dj corresponding to the H side of the rectangular column is determined 2 The specific steps of (a) are as follows:
s2.4, selecting a second minimum angle rib diameter dj meeting the angle rib calculated value of the H side in the longitudinal rib allowable diameter table 2min ；
S2.5 based on the second minimum angular rib diameter dj 2min On the premise of ensuring that the spacing between longitudinal bars meets the requirement of industry specifications, adopting a bar arrangement form of a single row of the angle bars, and calculating the number of second middle longitudinal bars and the diameter of the second middle longitudinal bars in the same row corresponding to the H side by combining the calculated value of the H side bar, so that the calculated requirement of 'the area of the middle longitudinal bars and the area of the angle bars are more than or equal to the calculated value of the H side bar' can be met by arranging the second middle longitudinal bars of the single row on the H side in the same row, and at the moment, the minimum angle bar diameter meeting the calculated requirement is the second angle bar diameter dj 2 ；
S2.6, if the diameter of the angle rib is increased to the maximum value in the permitted diameter table of the longitudinal rib in S2.5If the value still cannot meet the calculation requirement that the area of the middle longitudinal bar plus the area of the angle bar is larger than or equal to the output calculation value, the angle bar is reinforced in a mode of combining the angle bars, and at the moment, the maximum value of the diameter of the longitudinal bar in the permitted diameter table of the longitudinal bar is the diameter dj of the second angle bar 2 。
4. The automatic column reinforcement generation method according to claim 1, wherein the first corner bead diameter dj 1 The diameter dj of the first corner rib 1 Corresponding diameter d of first middle longitudinal rib BM1 Number N of first middle longitudinal ribs BM1 The screening conditions of (2) are as follows:
a1, if the number N of the same first middle longitudinal ribs corresponding to the B side BM1 Corresponding to the diameters d of a plurality of first middle longitudinal ribs BM1 Selecting the corresponding smallest diameter d of the first middle longitudinal rib BM1 Carrying out the next operation;
a2, if the number N of the first intermediate longitudinal ribs is obtained BM1 So that the interval of the first middle longitudinal ribs does not meet the requirement of industry specification, and the number N of the first middle longitudinal ribs is not selected BM1 ；
A3, if no first intermediate longitudinal rib number N is selected BM1 If the requirement of industry specification is met, judging that the reinforcement fails; if there is a first intermediate longitudinal rib number N BM1 If meeting the industry specification requirement, selecting the number N of the first middle longitudinal ribs BM1 Corresponding diameter d of first middle longitudinal rib BM1 And a first angular rib diameter dj 1 The method comprises the steps of carrying out a first treatment on the surface of the If there are at least two different first intermediate longitudinal rib numbers N BM1 If meeting the industry specification requirement, selecting the largest two first middle longitudinal rib diameters d BM1 Corresponding first middle longitudinal rib number N BM1 ；
A4, selecting the minimum stirrup diameter in the diameter table based on the stirrups for trial calculation, and if the number N of the two first middle longitudinal ribs screened by the A3 is smaller than the number N BM1 The calculated value of the stirrup encryption area is satisfied, a smaller first middle longitudinal rib number N is selected BM1 The method comprises the steps of carrying out a first treatment on the surface of the If the number N of the two first middle longitudinal ribs screened by A3 BM1 Only one calculated value meeting the stirrup encryption area is selected and usedCalculated first intermediate longitudinal rib number N BM1 The method comprises the steps of carrying out a first treatment on the surface of the If the number N of the two first middle longitudinal ribs screened by A3 BM1 If the calculated value of the stirrup encryption area is not satisfied, the diameter of the first-stage stirrup is increased, and the step is returned to continue trial calculation;
a5, if the calculated value of the stirrup in the encryption area cannot be met even if the maximum available stirrup diameter in the diameter table is selected as the stirrup in A4, the first number N of middle longitudinal bars is not selected BM1 The reinforcement fails.
5. The automatic column reinforcement generation method according to claim 4, wherein the second corner bead diameter dj 2 The diameter dj of the second angle rib 2 Corresponding second middle longitudinal rib diameter d BM2 Number N of second middle longitudinal ribs BM2 The screening conditions of (2) are as follows:
b1, the number N of the same second middle longitudinal ribs corresponding to the H edge BM2 Corresponding to the diameters d of a plurality of first middle longitudinal ribs BM2 Selecting the corresponding smallest diameter d of the first middle longitudinal rib BM2 Carrying out the next operation;
b2, if the number N of the second intermediate longitudinal ribs is obtained BM2 So that the spacing of the second middle longitudinal ribs does not meet the industry specification requirement, and the number N of the second middle longitudinal ribs is not selected BM2 ；
B3, if no second intermediate longitudinal ribs N are selected BM2 If the requirement of industry specification is met, judging that the reinforcement fails; if there is a second intermediate longitudinal rib number N BM2 The number N of the second middle longitudinal ribs is selected if the requirement of industry specification is met BM2 Corresponding second middle longitudinal rib diameter d BM2 And a second angular rib diameter dj 2 The method comprises the steps of carrying out a first treatment on the surface of the If there are at least two different second intermediate longitudinal rib numbers N BM2 Meeting the industry specification requirement, selecting the largest two second middle longitudinal rib diameters d BM2 Corresponding second intermediate longitudinal rib number N BM2 ；
B4, selecting the minimum stirrup diameter in the diameter table based on the stirrups for trial calculation, and if the number N of the two second middle longitudinal ribs screened by the B3 is smaller than the number N BM2 All satisfy the calculated value of the stirrup encryption areaSelecting a smaller number N of second middle longitudinal ribs BM2 The method comprises the steps of carrying out a first treatment on the surface of the If the number N of the two second middle longitudinal ribs screened by B3 BM2 Only one calculated value meeting the stirrup encryption area is selected and used, and the number N of the second middle longitudinal ribs meeting the calculated value of the stirrup encryption area is selected BM2 The method comprises the steps of carrying out a first treatment on the surface of the If the number N of the two second middle longitudinal ribs screened by B3 BM2 If the calculated value of the stirrup encryption area is not satisfied, the diameter of the first-stage stirrup is increased, and the step is returned to continue trial calculation;
b5, if the calculated value of the stirrup in the encryption area cannot be met even if the maximum available stirrup diameter in the diameter table is selected as the stirrup in the B4, the number N of the second middle longitudinal ribs is not selected BM2 The reinforcement fails.
6. The automatic column reinforcement generation method according to claim 1, wherein in step S4, the specific calculation mode of the first stirrup diameter is: the program column stirrup interval is 100, and the stirrup diameter is setWherein dv is B The diameter of the first stirrup corresponding to the B side is A sv Calculating a larger value for stirrups in a column node core area and a column stirrup encryption area, and n B The number of the stirrup limbs on the side B is the number.
7. The automatic column reinforcement generation method according to claim 1, wherein in step S4, the specific calculation mode of the second stirrup diameter is: the program column stirrup interval is 100, and the stirrup diameter is setWherein dv is H The diameter of the second stirrup on the H side is A sv For the larger value of the calculated stirrup value of the core area of the column node and the calculated stirrup value of the encrypted area of the column stirrup, n H The number of H-edge stirrups is the number of the H-edge stirrups.
8. The automatic column reinforcement generation method according to claim 1, wherein in step S5, the specific calculation mode of the reinforcement pitch of the non-encryption area of the column reinforcement is: the diameters of the hoops in the encryption area and the non-encryption area are equal, the hoops in the non-encryption area are half of the hoops in the encryption area, namely, the hoops in the encryption area are 100, the hoops in the non-encryption area are 200, and the hoops in the encryption area, the diameter, the hoops in the non-encryption area and the diameter meet the requirements of industry specifications.
CN202210824992.4A 2022-07-14 2022-07-14 Automatic generation method of column reinforcement Active CN115146354B (en)

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Citations (3)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
CN106326556A (en) * 2016-08-24 2017-01-11 广州地铁设计研究院有限公司 Calculation and three-dimensional modeling method of structural reinforcing bars
CN108532953A (en) * 2018-05-18 2018-09-14 宝业湖北建工集团有限公司 Overhanging board construction method based on BIM and construction techniques
CN109344506A (en) * 2018-09-30 2019-02-15 深圳市华阳国际建筑产业化有限公司 In-depth figure automatic generation method, equipment and the storage medium of BIM threedimensional model

Patent Citations (3)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
CN106326556A (en) * 2016-08-24 2017-01-11 广州地铁设计研究院有限公司 Calculation and three-dimensional modeling method of structural reinforcing bars
CN108532953A (en) * 2018-05-18 2018-09-14 宝业湖北建工集团有限公司 Overhanging board construction method based on BIM and construction techniques
CN109344506A (en) * 2018-09-30 2019-02-15 深圳市华阳国际建筑产业化有限公司 In-depth figure automatic generation method, equipment and the storage medium of BIM threedimensional model

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