CN114580124A - Design method for variable-section uniform air supply pipeline of rail transit vehicle - Google Patents

Design method for variable-section uniform air supply pipeline of rail transit vehicle Download PDF

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CN114580124A
CN114580124A CN202210208696.1A CN202210208696A CN114580124A CN 114580124 A CN114580124 A CN 114580124A CN 202210208696 A CN202210208696 A CN 202210208696A CN 114580124 A CN114580124 A CN 114580124A
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王友君
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Shanghai Ocean University
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Abstract

The invention discloses a method for designing a variable-section uniform air supply pipeline of a rail transit vehicle, which comprises the following steps of: s1, dividing air conditioner zones, and determining necessary parameters and limiting conditions for designing an air supply pipeline; s2, calculating the wind speed v of the minimum section wind pipe of the air supply pipeliner(ii) a S3, setting the number of pipe sections divided by the variable cross-section air pipe to be n; s4, calculating the minimum width w of the air outletomin(ii) a S5, calculating the minimum sectional area S of the section 0 of the variable-section air pipe0min(ii) a S6, calculating the minimum conveying power delta P of the air supply branch pipelineemin(ii) a S7, calculating the width w of the air outleto(ii) a S8, calculating the sectional area S of each section of the variable-section air supply pipelineiHeight HiWidth Wi. The method can be used for not only designing the variable cross-section air supply pipeline of the vehicle ventilation air-conditioning system, but also evaluating the finished variable cross-section air supply pipeline of the vehicle ventilation air-conditioning system. The invention can also be used in other engineering fields.

Description

Design method for variable-section uniform air supply pipeline of rail transit vehicle
Technical Field
The invention belongs to the field of design methods of ventilation and air conditioning engineering, and particularly relates to a design method of a variable-section uniform air supply pipeline of a rail transit vehicle.
Background
In the air conditioning system of the rail transit vehicle, an air supply pipeline is an intermediate link for connecting an air processing unit and a carriage passenger room. Whether the designed air output can be uniformly delivered into the passenger room or not is important for realizing reasonable air flow organization distribution of the passenger room and ensuring the air quality of the passenger room. With regard to the uniform air supply of rail transit vehicles, the technical results disclosed in foreign countries are relatively few, and china tries active research and development while introducing foreign technologies.
Document one (Chenjian cloud, zang subway train air conditioning uniform supply air duct overview [ J ] refrigeration, 2017, 36 (141): 53-59.) points out: at present, the air supply pipelines adopted by rail transit vehicles at home and abroad are mainly of 4 types: circular tube type air supply, large-section quasi-static pressure air supply, strip seam type static pressure air supply and novel variable-section air supply. The application and research status of various types of air supply pipelines are as follows:
(1) the circular tube type air supply pipeline is an air pipe which determines the pipe diameters of different pipe sections by carrying out detailed resistance calculation and test section by section so as to meet the air supply requirements of different positions. Document two (Longjing, King Shuao. subway vehicle air conditioning system air supply duct analysis [ J ]. electric locomotives and urban rail vehicles, 2004, 27 (4): 40-42.) states: this type of air duct is used in many foreign rail vehicles, for example: vienna subway, melbourne subway, newcastle subway, oslo subway. However, the whole design, manufacture and construction process of the subway train is more complicated, and domestic subways only adopt the air pipes of the type in individual lines, such as: guangzhou subway line III and Shanghai pearl line II.
(2) The large-section quasi-static-pressure air supply pipeline is an equal-section air pipe which can realize quasi-uniform air supply based on the principle that the cross-sectional area of the air pipe is large enough, the dynamic pressure in the air pipe is small, the static pressure is large and the change along the way is small. The large-section quasi-static pressure air supply pipeline is more suitable for vehicles with larger roof space, such as railway passenger cars and subway A-type vehicles. The structural characteristics and the design method of the air duct of the domestic A-type vehicle adopting the static pressure principle are introduced in the third document (Zhou-survivor, vehicle city sword, design analysis of the air duct of the domestic subway type vehicle air-conditioning system [ J ]. urban rail transit research, 2008, (9):36-39.), and further numerical simulation results show that: because of the limitation of the size of the A-type vehicle, the air duct is not static pressure in the complete sense, thereby having adverse effect on the uniformity of the outlet air.
(3) A strip slit type static pressure air supply pipeline is an improvement on a subway vehicle air supply pipeline by using the design idea of large-section quasi-static pressure air supply of a railway passenger car. The fourth document (Wang Shuao, talking over, development of air-conditioned passenger car uniform air supply duct [ J ]. railway vehicle, 1992, (8): 112- & 114 ]) states that: most of domestic subway vehicles generally adopt a strip-seam type static pressure air supply pipeline, such as: the subway train comprises subway vehicles in cities such as Changchun, Dalian, Beijing, Tianjin, Nanjing and Shanghai. The results of researches on the performance of the fifth document (Yang evening passenger car air conditioner static pressure uniform air supply duct and the development of an inducer [ D ]. Qingdao Islands: Qingdao institute of architecture engineering, 2002), the sixth document (Liuyang, Yikou, Li Yiming. design of air outlet uniformity of a subway vehicle air duct system [ J ]. electric locomotives and urban rail vehicles, 2011, 32 (1): 48-50.), and the seventh document (Yijiabi, Wangxiang, Shiyi, etc.. the uniform air supply duct for subway trains: CN201020298338.7[ P ].2011-07-20 ]) show that: due to the limitation of the size of an actual subway vehicle, the sectional area of an air duct cannot be large enough, and the air duct cannot realize static pressure air supply in the true sense. In practical engineering, the slit type static pressure air supply pipeline has to adopt a method of changing the shape and the size of an air outlet or arranging a block in an air duct to improve the air supply uniformity. Therefore, certain difficulties are brought to design, manufacture and construction.
(4) The novel variable cross-section air supply pipeline is an air pipe type which realizes uniform air supply by changing the sectional area of the air supply pipeline, enabling the dynamic pressure difference to overcome resistance and keeping the static pressure of the pipeline unchanged. The air supply pipeline is more suitable for rail transit vehicles with limited sectional areas, particularly B-type vehicles and C-type vehicles, but the design difficulty is higher. With the development of the CFD technology, research on variable-section air supply pipelines is carried out on eight documents (Wang Liu. air supply duct of subway coach air conditioner and airflow organization optimization research in passenger room [ D ]. Wuhan: China university of science and technology, 2008), nine documents (Mayinhong. air supply duct air outlet performance numerical simulation and optimization [ D ]. Wuhan: China university of science and technology, 2008.), ten documents (Suwei Hua, Wu V, Zhangliang, and the like. optimization research on the internal structure of variable-section air duct of subway train [ J ]. report on railroad science and engineering, 2021, 18 (8): 2137 + 2144.). However, the results of the past studies have had the following drawbacks: : (a) it is impossible to judge whether the air volume born by the air supply duct is reasonable. (b) The pipeline is still internally provided with baffles or flow deflectors and other barriers, and the advantage of uniform air supply with variable cross sections is not fully exerted. (c) The selection of the cross-sectional dimension and the change ratio is random and empirical, and a calculation method of the cross-sectional dimension and the change ratio cannot be given. (d) The past optimization scheme only aims at a specific engineering project, and when a new project and a new vehicle model meet the specific engineering project, a great amount of manpower and time are needed for scheme trial and comparison, so that the optimal design cannot be given in one step. (e) The CFD technology has high requirements on professional quality of designers, and the skilled application of the CFD technology needs to be proficient in the capabilities of high hydrodynamics, high heat transfer, computer programming and the like, so that the requirement on quick engineering design cannot be met.
In summary, the variable cross-section uniform air supply pipeline is an advanced concept, but a design method which meets the rapid engineering requirement is not provided.
Disclosure of Invention
The invention provides a design method of a variable cross-section uniform air supply pipeline of a rail transit vehicle, which aims to adapt to vehicles of various scales, avoid adding a resistor in the pipeline, reduce the conveying resistance and energy consumption, judge whether the maximum flow speed in the pipeline, the maximum layout area of an air outlet, the maximum layout area of a variable cross-section pipeline, the minimum conveying power of an air supply branch and even the air conditioner partition born by the air supply branch are reasonable or not, provide a calculation method of the cross-section dimension and the change proportion of the variable cross-section pipeline, realize the completely meaningful static pressure air supply and meet the requirement of rapid engineering design.
The invention is realized by the following technical scheme:
a method for designing a variable-section uniform air supply pipeline of a rail transit vehicle comprises the following steps:
s1, dividing air conditioner zones, and determining necessary parameters and limiting conditions for designing an air supply pipeline;
s2, calculating the wind speed v of the minimum section wind pipe of the air supply pipelinerJudgment of vrWhether the maximum allowable wind speed v is exceededrmax
If v appears in step S2r≤vrmaxCarrying out the next step; if v isr>vrmaxIf so, the branch is judged to bear too large air supply volume and the air conditioner is not reasonable in partition, and the step returns to the step S1;
s3, drawing the number of the pipe sections divided by the variable cross-section air pipe to be n, and calculating the air quantity Q of each cross sectioniAnd length L of each pipe sectionmAir volume QmSum air quantity Qi-(i+1)
S4, calculating the minimum width w of the air outletominJudgment of wominWhether or not to exceed the maximum width w of the air outlet which can be arrangedob
If w appears in step S4omin≤wobCarrying out the next step; if w isomin>wobIf so, the branch is judged to bear too large air supply volume and the air conditioner is not reasonable in partition, and the step returns to the step S1;
s5, calculating the minimum sectional area S of the section 0 of the variable-section air pipe0min(ii) a Judgment S0minWhether the maximum cross-sectional area S which can be arranged by the variable cross-section air pipe is exceededb
If S appears in step S50min≤SbCarrying out the next step; if S is0min>SbIf so, the branch is judged to bear too large air supply volume and the air conditioner is not reasonable in partition, and the step returns to the step S1;
s6, calculating the minimum conveying power delta P of the air supply branch pipelineeminJudgment of Δ PeminWhether the maximum full pressure Δ P of the alternative power plant is exceededbmax
If Δ P occurs in step S6emin≤ΔPbmaxCarrying out the next step; if Δ Pemin>ΔPbmaxIf the pressure is too high, the air conditioner is not reasonable in partition, and the process returns to step S1;
s7, calculating the width w of the air outleto
S8, calculating the sectional area S of each section of the variable-section air supply pipelineiHeight HiWidth WiThe ratio of change k in the height of the cross section of each pipe sectionH[(i-(i+1)]And the variation ratio k of the cross-sectional widthW[(i-(i+1)]And the conveying power delta P of the air supply branch pipelinee
Preferably, the necessary parameters and the limiting conditions for designing the blowing duct in step S1 include the following: total air supply Q born by air supply pipeline and sectional area S of branch minimum section air piperHigh HrWidth W ofrAnd length LrThe ratio of protrusion of the inlet of the minimum cross-section air duct CtMaximum allowable wind speed v of air supply ductrmaxMaximum sectional area S where variable cross-section air pipes can be arrangedbHigh HbWidth WbAnd length LbPipe material for air supply duct, type of air outlet and maximum area f that can be arrangedobWidth wobLength l, length lobMaximum full pressure Δ P of optional power plantbmax
Preferably, v in the step S2rThe calculation method comprises the following steps:
vr=Q/Sr
vr-wind speed of the minimum cross section wind pipe, m/s;
q-total air supply volume, m, born by the air supply branch pipeline3/s;
Sr-cross-sectional area, m, of the minimum cross-sectional air duct of the air supply branch2
Preferably, the method for determining the number of each section and each pipe section and the length L of each pipe section in the step S3mAir volume QmSum air quantity Qi-(i+1)And the air quantity Q of each sectioniThe calculation method comprises the following steps:
s31, setting the number of pipe sections divided by the variable cross-section air pipe to be n, wherein the cross sections of the pipe sections from the head to the tail are 0, 1, 2, … … i … …, n-1 and n; the pipe sections are 0-1, 1-2, … … i- (1+1) … …, (n-1) -n;
s32, calculating the length L of each pipe section of the variable cross-section air pipem
Lm=Lb/n
Lm-the length, m, of each section of the variable cross-section air duct;
Lbthe maximum length, m, that the variable cross-section air duct can be arranged;
n is the number of the pipe sections divided by the wind pipe with the planned variable cross section;
s33, calculating the air output Q of each section of the variable cross-section air pipem
Qm=Q/n
QmAir output of each section of the variable cross-section air pipe, m3/s;
S34, calculating air quantity Q of each section of the variable-section air pipeiAnd the air quantity Q of each pipe sectioni-(i+1)
Qi=Q-Qm×i
Qi-(i+1)=Q-Qm×i
QiThe value range of the air volume of each section of the variable-section air pipe, i is 0 to n, m3/s;
Qi-(i+1)The air volume m of each section of the variable cross-section air duct3/s。
Preferably, the minimum width w of the air outlet in the step S4ominThe calculation method comprises the following steps:
s41, determining the maximum allowable flow velocity v of the air outlet of the passenger compartment of the carriage according to the air supply requirement of the passenger compartment of the carriageomax
S42, according to the maximum allowable flow velocity v of the air outletomaxCalculating the minimum area f of the air outletomin
fomin=Q/vomax
fominMinimum area of the outlet, m2
vomax-the maximum allowable flow velocity at the outlet, m/s;
s43, according to the minimum area f of the air outletominAnd the air outlet can be arrangedobCalculating the minimum width w of the air outletomin
womin=fomin/lob
womin-minimum width of the outlet, m;
lobthe maximum length, m, that the air outlet can be arranged.
Preferably, the minimum cross-sectional area S of the section 0 in the step S50minThe calculation method comprises the following steps:
s51, setting up the maximum allowable flow velocity v of the air outletomax
S52, drawing up the minimum outflow angle alpha of the air outletminDetermining the outflow coefficient mu;
s53, according to the maximum allowable flow velocity v of the air outletomaxAnd the outflow coefficient mu, calculating the maximum static pressure velocity v of the air outletjmax
vjmax=vomax
vjmax-the maximum static pressure velocity of the outlet, m/s;
mu-flow coefficient of the air outlet;
s54, according to the maximum static pressure velocity v of the air outletjmaxCalculating the maximum static pressure P of the air outletjmax
Pjmax=ρvjmax 2/2
Pjmax-the maximum static pressure, Pa, of the air outlet;
rho-density of fluid transported in pipeline, kg/m3Air is 1.20kg/m3
S55, according to the maximum static pressure velocity v of the air outletjmaxAnd a minimum outflow angle αminCalculating the maximum dynamic pressure velocity v of the cross section 00dmax
v0dmax=vjmax/tan(αmin)
v0dmax-maximum dynamic pressure velocity of section 0, m/s;
s56, according to the maximum dynamic pressure velocity v of the section 00dmaxCalculating the minimum cross-sectional area S of the cross-section 00min
S0min=Q/v0dmax
S0minMinimum cross-sectional area of section 0, m2
Preferably, Δ P in step S6eminThe calculation method comprises the following steps:
s601. according to the height H of the air pipe with the minimum sectionrAnd width WrCalculating the flow equivalent diameter D of the branch minimum section air piper
Figure BDA0003532243700000081
DrFlow velocity equivalent diameter, m, of the smallest cross section air duct (flexible coupling duct);
Wr-flexible jointThe width of the air receiving pipe is m;
Hr-height, m, of the flexible connecting duct;
s602. according to the air quantity Q and the flow equivalent diameter D of the flexible connecting air piperChecking the specific friction resistance R of the flexible connecting air piper
S603, according to the specific friction resistance R of the flexible connection air piperAnd length LrCalculating the on-way resistance delta P of the flexible connecting air pipery
ΔPry=Rr×Lr
ΔPryThe on-way resistance of the flexible connecting air pipe is Pa/m;
Rrthe specific friction resistance of the flexible connecting air pipe is Pa/m;
Lr-length of flexible coupling duct, m;
s604, according to the wind speed v of the flexible connection air piperCalculating the dynamic pressure P of the flexible connecting air piperd
Prd=ρvr 2/2
Prd-dynamic pressure, Pa, of the flexible connecting duct;
s605. according to the sudden shrinkage ratio C of the inlet of the flexible connecting air pipetsChecking the local resistance system epsilon of the sudden shrinkage of the inlet of the flexible connecting air piperCounting;
s606, according to the local resistance system epsilon of the flexible connection air pipe inlet sudden shrinkagerNumber and dynamic pressure PrdCalculating the local resistance delta P of the flexible connecting air piperj
ΔPrj=εr×Prd
ΔPrj-local resistance, Pa, of the flexible connecting duct;
εr-a local resistance system of the flexible connection air duct for the sudden contraction of the inlet;
s607, according to the on-way resistance delta P of the flexible connecting air piperyAnd local resistance Δ PrjCalculating the total resistance delta P of the flexible connecting air piper
ΔPr=ΔPry+ΔPrj
ΔPr-the total resistance of the flexible connecting duct, Pa;
s608, according to the air quantity Q of the section 0 of the variable-section air pipe0And a maximum cross-sectional area S that can be arrangedbCalculating the minimum dynamic pressure velocity v of the cross section 00dmin
v0dmin=Q/Sb
v0dmin-minimum dynamic pressure velocity of section 0, m/s;
s609, according to the minimum dynamic pressure velocity v of the section 00dminCalculating the minimum dynamic pressure P of the cross section 00dmin
P0dmin=ρv0dmin 2/2
P0dmin-minimum dynamic pressure, Pa, of section 0;
s610, according to the minimum outflow angle alpha of the air outlet of the pipe section 0-1minDetermining the outflow coefficient mu of the air outlet of the pipe section 0-1;
s611, according to the minimum dynamic pressure velocity v of the section 00dminAnd the minimum outflow angle alpha of the air outletminCalculating the minimum hydrostatic velocity vjmin
vjmin=v0dmin×tan(αmin)
vjmin-minimum static pressure velocity, m/s, of the pipe section 0-1 air outlet;
s612, according to the minimum static pressure velocity v of the air outletjminCalculating the minimum static pressure P of the air outletjmin
Pjmin=ρvjmin 2/2
Pjmin-minimum static pressure, Pa, of the air outlet;
s613, calculating sudden expansion ratio C of section 0 inlet (soft connection outlet)tk
Ctk=A0/A1
A0The cross-sectional area, m, of the small-section pipe at the sudden expansion or contraction2
A1The cross-sectional area, m, of the large-section pipe at the sudden expansion or contraction2
S614, according to the sudden expansion ratio C of the section 0 inlet (soft connection outlet)tkChecking the local resistance system epsilon of the section 00Counting;
s615, according to the local resistance system epsilon of the section 00Number and minimum dynamic pressure P0dminCalculating the minimum local resistance DeltaP of the section 00jmin
ΔP0jmin=ε0×P0dmin
ΔP0jmin-minimum local resistance of section 0, Pa;
ε0-local drag coefficient of section 0;
s616, according to the minimum dynamic pressure P of the section 00dminMinimum local resistance Δ P0jminAnd minimum static pressure P of air outletjminAnd, calculating the minimum total pressure P of the section 00qmin
P0qmin=P0dmin+ΔP0jmin+Pjmin
P0qmin-minimum total pressure, Pa, of section 0;
s617, determining resistance delta P of other irregular local resistance componentsx
S618, determining the minimum margin K of the conveying power of the air supply branchmin
S619, according to the total resistance delta P of the flexible connection air piperMinimum total pressure P of section 00qminResistance Δ P of other irregular local resistance membersxAnd a minimum margin K of power deliveredminCalculating the minimum conveying power delta P of the air supply branchemin
ΔPemin=(1+Kmin)×(ΔPr+P0qmin+ΔPx)
ΔPemin-minimum delivery power, Pa, of the air supply branch;
Kmin-the minimum richness of the delivery power of the air supply branch;
ΔPx-the resistance, Pa, of other irregular local resistance members.
Preferably, the width w of the air outlet in the step S7oThe calculation method comprises the following steps:
s71, drawing up an average outflow speed v of an air outlet according to the requirement of a passenger compartment of a carriage on an air supply speedo
S72, setting the average outflow speed v of the air outlet according to the drawingoCalculating the total area f of the air outleto
fo=Q/vo
foTotal area of the outlet, m2
vo-drawing up the average outflow speed of the air outlet in m/s;
s73, setting up the length l of the air outleto
S74, according to the total area f of the air outletoAnd a proposed length loCalculating the width w of the air outleto
wo=fo/lo
woWidth of the outlet, m.
Preferably, in the step S8, the sectional area S of each section of the variable-section blowing ductiHeight HiWidth WiThe ratio of change k in the height of the cross section of each pipe sectionH[(i-(i+1)]And the variation ratio k of the cross-sectional widthW[(i-(i+1)]And the conveying power delta P of the air supply branch pipelineeThe calculation method comprises the following steps:
s801, drawing up the outlet flow speed v of the air outlet according to the air supply requirement of the passenger roomo
S802, calculating the relative flow Q of the air outlet of the pipe section 0-1m-0A ratio;
Qm-0=Qm/Q0-1
Qm-0-relative flow of the pipe segment 0-1 outlet;
Q0-1air volume of pipe section 0-1, m3/s;
S803, drawing up an air outlet outflow angle alpha according to the air supply requirement of the passenger room;
s804, according to the relative flow Q of the air outlet of the pipe section 0-1m-0And angle of outflowAlpha, determining the outflow coefficient mu;
s805, according to the outflow speed v of the air outletoAnd the outflow coefficient mu, calculating the static pressure velocity v of the air outletj
vj=vo
vj-the static pressure velocity of the outlet, m/s;
mu-outflow coefficient of the air outlet;
vo-drawing up the outflow speed of the air outlet in m/s;
s806. according to the static pressure velocity v of the air outletjCalculating the static pressure P of the tuyerej
Pj=ρvj 2/2
Pj-static pressure, Pa, of the air outlet;
s807. according to the static pressure velocity v of the air outletjAnd drawing up the outflow angle alpha to calculate the dynamic pressure velocity v of the cross section 00d
v0d=vj/tanα
v0d-dynamic pressure velocity of section 0, m/s;
alpha-drawing up an outflow angle alpha of the air outlet;
s808, dynamic pressure velocity v according to section 00dSum flow rate Q0Calculating the sectional area S of the section 00Judgment S0And SbThe relative size of (d);
S0=Q0/v0d
S0section area of section 0, m2
If S in step S8080≤SbCarrying out the next step; if S is0>SbReturning to step S801;
s809, drawing up the height H of the section 00
S810, according to the height H of the planned section 00And cross-sectional area S0Calculating the width W of the cross section 00
W0=S0/H0
W0Width of section 0, m;
S0area of cross-section 0, m2
H0Height of section 0, m;
s811 dynamic pressure velocity v according to section 00dCalculating dynamic pressure P of section 00d
P0d=ρv0d 2/2
P0d-dynamic pressure, Pa, of section 0;
s812, calculating sudden expansion ratio C of inlet (soft connection outlet) of section 0tk
Ctk=A0/A1
A0The cross-sectional area, m, of the small-section pipe at the sudden expansion or contraction2
A1The cross-sectional area, m, of the large-section pipe at the sudden expansion or contraction2
S813, according to the sudden expansion ratio C of the inlet (soft connection outlet) of the section 0tkChecking the sudden expansion local resistance system epsilon of the section 00Counting;
s814, sudden expansion local resistance system epsilon according to section 00Number and dynamic pressure P0dCalculating the sudden expansion local resistance P of the section 00j
P0j=ε0×P0d
P0j-sudden local resistance, Pa, of section 0;
ε0-sudden expansion local drag coefficient of section 0;
s815. dynamic pressure P according to section 00dStatic pressure PjAnd sudden local resistance P0jCalculating the total pressure P of the cross section 00q
P0q=Pj+P0d+P0j
P0q-full pressure, Pa, of section 0;
s816, determining the resistance delta P of other irregular local resistance componentsx
S817, determining the abundance K of the conveying power of the air supply branch;
s818, according to total resistance delta P of the flexible connection air piperFull pressure P of section 00qResistance Δ P of other irregular local resistance membersxAnd the margin K of the conveying power, and calculating the conveying power delta P of the air supply brancheJudgment of Δ PeWhether the judgment is reasonable or not;
ΔPe=(1+K)×(ΔPr+P0q+ΔPx)
ΔPethe conveying power Pa of the air supply branch;
k is the margin of the power delivered by the air supply branch;
ΔPx-the resistance of other irregular local resistance members, Pa;
if Δ P in step S818e≤ΔPbmaxThe design is reasonable, and the next step is carried out; if Δ Pe>ΔPbmaxIf the design is not reasonable, go back to step S801;
s819. Width W according to section 00And high H0Calculating the flow equivalent diameter D of the cross section 00
Figure BDA0003532243700000151
D0Flow equivalent diameter, m, of section 0;
W0width of section 0, m;
H0height of section 0, m;
s820, according to air quantity Q of pipe section 0-10-1Flow equivalent diameter D of section 00For an approximation of the pipe section 0-1, the specific friction resistance R of the pipe section 0-1 is examined(0-1)
S821. according to the specific friction resistance R of the pipe section 0-1(0-1)And length LmCalculating the on-way resistance delta P of the pipe section 0-1(0-1)y
ΔP(0-1)y=R(0-1)×Lm
ΔP(0-1)yBy the path of the pipe section 0-1Resistance, Pa;
R(0-1)-specific friction resistance of pipe section 0-1, Pa/m;
s822, according to the relative flow Q of the air outlet of the pipe section 0-1m-0Checking the local drag coefficient epsilon of the 0-1 straight-through part of the pipe section(0-1)
S823. dynamic pressure P according to section 00dAnd the local drag coefficient epsilon of the 0-1 through part of the pipe section(0-1)Calculating the local resistance delta P of the pipe section 0-1(0-1)j
ΔP(0-1)j=ε(0-1)×P0d
ΔP(0-1)j-local resistance, Pa, of the pipe section 0-1;
ε(0-1)-local drag coefficient of pipe section 0-1;
s824, total pressure P according to section 00qOn-way resistance delta P of pipe section 0-1(0-1)yAnd local resistance Δ P(0-1)jCalculating the total pressure P of the section 11q
P1q=P0q-(ΔP(0-1)y+ΔP(0-1)j)
P1q-full pressure, Pa, of section 1;
s825. according to the total pressure P of the section 11qAnd static pressure P for keeping air supply from the air outlet uniformjCalculating the dynamic pressure P of the section 11dJudgment of P1dWhether the judgment is reasonable or not;
P1d=P1q-Pj
P1d-dynamic pressure, Pa, of section 1;
if P is in step S8251dThe design is reasonable, and the next step is carried out; if P is1dIf not more than 0, the design returns to step S801;
s826. dynamic pressure P according to section 11dCalculating the dynamic pressure velocity v of the cross section 11d
Figure BDA0003532243700000161
v1d-dynamic pressure velocity of section 1, m/s;
s827. dynamic pressure velocity v according to section 11dSum air quantity Q1Calculating the sectional area S of the section 11
S1=Q1/v1d
S1Section area of section 1, m2
S828, drawing up the height H of the section 11
S829, cross-sectional area S according to section 11And a predetermined height H1Calculating the width W of the cross section 11
W1=S1/H1
H1Height of section 1, m;
W1width of section 1, m;
s830, according to the height H of the section 00And height H of cross section 11Calculating the change ratio k of the section height of 0-1 of the pipe sectionH(0-1)
kH(0-1)=H1/H0
kH(0-1)-the ratio of the variation of the height of the section 0-1 of the pipe section;
s831. according to the width W of the section 00And the width W of the cross section 11Calculating the variation ratio k of the section width of 0-1 of the pipe sectionW(0-1)
kW(0-1)=W1/W0
kW(0-1)-the ratio of variation of the section width of the pipe section 0-1;
s832, repeating the steps S819-S831 to calculate the height H of the subsequent sectioniAnd width WiThe ratio k of the change in the cross-sectional height of the subsequent tube sectionH[i-(i+1)]And the variation ratio k of the cross-sectional widthW[i-(i+1)]
If the subsequent tube section employs the same ratio of change in cross-sectional height and change in cross-sectional width as the preceding adjacent tube section, then, in some cases,
Hi=H(i-1)×kH[(i-1)-i]
Wi=W(i-1)×kW[(i-1)-i]
Hi-height of section i, m;
Hi-height of section i, m;
kH[(i-1)-i]tube section [ (i-1) -i)]The cross-sectional height variation ratio of (a);
Withe width of the section i, m;
Withe width of the section i, m;
kW[(i-1)-i]tube section [ (i-1) -i)]The cross-sectional width change ratio of (a).
Has the advantages that: compared with the traditional equal-section conveying pipeline, the pipeline can adapt to vehicles with various scales; compared with the traditional variable cross-section air supply pipeline, the variable cross-section air supply pipeline has the advantages that the resistance in the pipeline can be reduced, and the conveying resistance and the energy consumption are reduced; compared with the traditional equal-section and variable-section air supply pipeline, the static pressure uniform air supply can be realized; compared with a CFD simulation method, the method can adapt to the requirement of rapid engineering;
in addition, the invention also provides a calculation method for judging whether the maximum flow velocity in the pipeline, the maximum layout area of the air outlet, the maximum layout sectional area of the variable-section pipeline, the minimum conveying power of the air supply branch and even the air conditioner subareas borne by the air supply branch are reasonable or not and the section scale and the change proportion of the variable-section pipeline, thereby avoiding the blindness and the heuristics of the past design method, saving the material cost and the time cost required by the test, and providing an optimization scheme with uniform air supply and low operation energy consumption;
the method can be used for not only designing the variable cross-section air supply pipeline of the vehicle ventilation air-conditioning system, but also evaluating the finished variable cross-section air supply pipeline of the vehicle ventilation air-conditioning system. The invention can also be used for the design and evaluation of uniform and non-uniform outflow ducts for other vehicles, other spaces, other equipment, other fluids, other engineering fields, other outlet types.
Drawings
FIG. 1 is a schematic view of a No. 1 branch variable cross-section air supply pipeline of an air conditioning system of a certain subway train in Shanghai, which is designed by the invention.
Fig. 2 is a general technical route diagram of the present invention.
FIG. 3 is a technical schematic diagram of step S3 according to the present invention.
FIG. 4 is a technical scheme of step S4 according to the present invention.
FIG. 5 is a technical schematic diagram of step S5 according to the present invention.
FIG. 6 is a technical schematic diagram of step S6 according to the present invention.
FIG. 7 is a technical schematic diagram of step S7 according to the present invention.
FIG. 8 is a technical schematic diagram of step S8 according to the present invention.
Detailed Description
The embodiments of the present invention will be described in detail below with reference to the accompanying drawings: the present embodiment is implemented on the premise of the technical solution of the present invention, and a detailed implementation manner and a specific operation process are given, but the protection scope of the present invention is not limited to the following embodiments.
As shown in fig. 1-8:
example I, design of No. 1 branch variable cross-section air supply pipeline of air conditioning system of Shanghai subway train
S1, dividing air conditioner zones, and determining necessary parameters and limiting conditions for designing an air supply pipeline;
the total air supply quantity Q born by the No. 1 branch air supply pipeline of the air conditioning system of a certain subway train of Shanghai subway is 800m3/h(0.22m3S); cross-sectional area S of branch minimum cross-section air pipe (i.e. flexible connection air pipe, uniform cross-section)r=0.03m2High Hr0.10m wide Wr0.30m and length Lr2.00m, the projecting and shrinking ratio C of the inlet of the air pipe with the minimum sectionts0.4; maximum allowable wind speed vrmaxMaximum section area S which can be arranged in the variable section air pipe of 10m/Sb=0.12m2High Hb0.15m, width Wb0.80m and length Lb4.60 m; the pipes of the air supply pipeline are made of common galvanized steel sheets; the air outlet is strip-shaped, and the maximum area f of the air outlet can be arrangedob=1.38m2Width wob0.30m longob4.60 m; maximum full pressure Δ P for alternative power plantsbmax=100pa;
S2, calculating the wind speed v of the minimum section wind pipe of the air supply pipelinerJudgment of vrWhether the maximum allowable wind speed v is exceededrmax
vr=Q/Sr=0.22÷0.03=7.33m/s
vr-wind speed of the minimum cross section wind pipe, m/s;
q-total air supply volume, m, born by the air supply branch pipeline3/s;
Sr-cross-sectional area, m, of the minimum cross-sectional air duct of the air supply branch2
(vr=7.33m/s)<(vrmax10m/s), the next step is carried out;
s3, setting the number of the pipe sections divided by the variable cross-section air pipe to be n, and calculating the air quantity Q of each cross sectioniAnd length L of each pipe sectionmAir output QmSum air quantity Qi-(i+1)
S31, setting the number of pipe sections divided by the designed variable-section air pipe to be n-2, wherein the sections of the pipe from the head to the tail are 0, 1 and 2, and the pipe sections are 0-1 and 1-2;
s32, calculating the length L of each pipe section of the variable cross-section air pipem
Lm=Lb/n=4.6/2=2.3m
Lm-the length, m, of each section of the variable cross-section air duct;
Lb-the maximum length, m, that the variable cross-section air duct can be arranged;
n is the number of the pipe sections divided by the wind pipe with the planned variable cross section;
s33, calculating the air output Q of each section of the variable cross-section air pipem
Qm=Q/n=0.22/2=0.11m3/s
QmAir output of each section of the variable cross-section air duct, m3/s;
S34, calculating air quantity Q of each section of the variable-section air pipeiAnd the air quantity Q of each pipe sectioni-(i+1)
Q0=Q=0.22m3/s
Q1=Q-Qm×i=0.22-0.11×1=0.11m3/s
Q2=Q-Qm×i=0.22-0.11×2=0m3/s
Q0-1=Q=0.22m3/s
Q1-2=Q-Qm×i=0.22-0.11×1=0.11m3/s
QiThe value range of the air volume of each section of the variable-section air pipe, i is 0 to n, m3/s;
Qi-(i+1)The air volume m of each section of the variable cross-section air duct3/s;
S4, calculating the minimum width w of the air outletominJudgment of wominWhether or not to exceed the maximum width w of the air outlet which can be arrangedob
S41, determining the maximum allowable flow velocity v of an air outlet of a carriage passenger room according to the air supply requirement of the carriage passenger roomomax=2.0m/s;;
S42, according to the maximum allowable flow velocity v of the air outletomaxCalculating the minimum area f of the air outletomin
fomin=Q/vomax=0.22/2.0=0.11m2
fominMinimum area of the outlet, m2
vomax-the maximum allowable flow velocity at the outlet, m/s;
s43, according to the minimum area f of the air outletominAnd the air outlet can be arrangedobCalculating the minimum width w of the air outletomin
womin=fomin/lob=0.11/4.6=0.02m
womin-minimum width of the outlet, m;
lobthe maximum length, m, at which the outlet can be arranged;
(womin0.02m)<(wob0.30m), the next step was performed;
s5, calculating the minimum sectional area of the section 0 of the variable-section air pipeS0min(ii) a Judgment S0minWhether the maximum sectional area S of the variable-section air pipe which can be arranged is exceededb
S51, setting up the maximum allowable flow velocity v of the air outletomax=2.00m/s;
S52, drawing up the minimum outflow angle alpha of the air outletminDetermining an outflow coefficient mu;
setting the minimum outflow angle alpha of the air outletmin60 degrees, investigate the outflow coefficient of sharp-edged orifice in fig. 4-1-6, compiled by xiaoyun encourage (fourth edition), fluid distribution network (fluid distribution network), to obtain μ 0.6;
s53, according to the maximum allowable flow velocity v of the air outletomaxAnd the outflow coefficient mu, calculating the maximum static pressure velocity v of the air outletjmax
vjmax=vomax/μ=2.00/0.6=3.33m/s
vjmax-the maximum static pressure velocity of the outlet, m/s;
mu-flow coefficient of the air outlet;
s54, according to the maximum static pressure velocity v of the air outletjmaxCalculating the maximum static pressure P of the air outletjmax
Pjmax=ρvjmax 2/2=1.20×(3.33m/s)2/2=6.65Pa
Pjmax-the maximum static pressure, Pa, of the air outlet;
rho-density of fluid transported in pipeline, kg/m3Air is 1.20kg/m3
S55, according to the maximum static pressure velocity v of the air outletjmaxAnd a minimum outflow angle αminCalculating the maximum dynamic pressure velocity v of the cross section 00dmax
v0dmax=vjmax/tan(αmin)=3.33/1.73=1.92m/s
v0dmax-maximum dynamic pressure velocity of section 0, m/s;
s56, according to the maximum dynamic pressure velocity v of the section 00dmaxCalculating the minimum cross-sectional area S of the cross-section 00min
S0min=Q/v0dmax=0.22/1.92=0.11m2
S0minMinimum cross-sectional area of section 0, m2
(S0min=0.11m2)<(Sb=0.12m2) Carrying out the next step;
s6, calculating the minimum conveying power delta P of the air supply branch pipelineeminJudgment of Δ PeminWhether the maximum full pressure Δ P of the alternative power plant is exceededbmax
S601. according to the height H of the air pipe with the minimum sectionrAnd width WrCalculating the flow equivalent diameter D of the branch minimum section air piper
Figure BDA0003532243700000231
DrFlow velocity equivalent diameter, m, of the smallest cross section air duct (flexible coupling duct);
Wr-the width of the flexible connecting duct, m;
Hr-height of the flexible connecting duct, m;
s602. according to the air quantity Q and the flow equivalent diameter D of the flexible connecting air piperChecking the specific friction resistance R of the flexible connecting air piper
According to the air quantity Q of the flexible connecting air pipe is 0.22m3S and flow equivalent diameter Dr0.26m, encourage Xiaoyi folk editors (fourth edition) in the section of fluid distribution pipe network (3-6-1), R can be known as the linear calculation of frictional resistance per unit length of ventilation ductr=1.05Pa/m;
S603, according to the specific friction resistance R of the flexible connection air piperAnd length LrCalculating the on-way resistance delta P of the flexible connecting air pipery
ΔPry=Rr×Lr=1.05Pa/m×2.0m=2.10Pa
ΔPryThe on-way resistance of the flexible connecting air pipe is Pa/m;
Rrthe specific friction resistance of the flexible connecting air pipe is Pa/m;
Lr-length of the flexible connecting duct, m;
s604, according to the wind speed v of the flexible connection air piperCalculating the dynamic pressure P of the flexible connecting air piperd
Prd=ρvr 2/2=1.20kg/m3×(7.33m/s)2=64.47Pa
Prd-dynamic pressure, Pa, of the flexible coupling duct;
s605, according to the sudden shrinkage ratio C of the inlet of the flexible connecting air pipetsChecking the local resistance system epsilon of the sudden shrinkage of the inlet of the flexible connecting air piperCounting;
the protruding shrinkage ratio of the inlet of the flexible connecting air pipe is CtsWhen the local resistance coefficient epsilon is 0.4, the local resistance coefficient epsilon of the sudden contraction of the inlet of the flexible connecting air pipe is obtained by looking up an appendix local resistance coefficient table of < fluid transmission and distribution pipe network (third edition) > in the auspicious encourage showy folkrIs 0.34;
s606, according to the local resistance system epsilon of the flexible connection air pipe inlet sudden shrinkagerNumber and dynamic pressure PrdCalculating the local resistance delta P of the flexible connecting air piperj
ΔPrj=εr×Prd=0.34×64.47Pa=21.92Pa
ΔPrj-local resistance, Pa, of the flexible connecting duct;
εr-a local resistance system of the flexible connection air duct for the sudden contraction of the inlet;
s607, according to the on-way resistance delta P of the flexible connecting air piperyAnd local resistance Δ PrjCalculating the total resistance delta P of the flexible connecting air piper
ΔPr=ΔPry+ΔPrj=2.10Pa+21.92Pa=24.02Pa
ΔPr-the total resistance of the flexible connecting duct, Pa;
s608, according to the air quantity Q of the section 0 of the variable-section air pipe0And a maximum cross-sectional area S that can be arrangedbCalculating the minimum dynamic pressure velocity v of the cross section 00dmin
v0dmin=Q/Sb=0.22m3/s÷0.12m2=1.83m/s
v0dmin-minimum dynamic pressure velocity of section 0, m/s;
s609, according to the minimum dynamic pressure velocity v of the section 00dminCalculating the minimum dynamic pressure P of the cross section 00dmin
P0dmin=ρv0dmin 2/2=1.2kg/m3×(1.83m/s)2÷2=2.01Pa
P0dmin-minimum dynamic pressure, Pa, of section 0;
s610, according to the minimum outflow angle alpha of the air outlet of the pipe section 0-1minDetermining the outflow coefficient mu of the air outlet of the pipe section 0-1;
according to the minimum outflow angle alpha of the air outletmin60 degrees, find out and pay encourage shu yi shi mai compiled "fluid distribution network (fourth edition)" fig. 4-1-6 sharp edge orifice outflow coefficient, get μ 0.6;
s611, according to the minimum dynamic pressure velocity v of the section 00dminAnd the minimum outflow angle alpha of the air outletminCalculating the minimum hydrostatic velocity vjmin
vjmin=v0dmin×tan(αmin)=v0dmin×1.73=1.83m/s×1.73=3.17m/s
vjmin-minimum static pressure velocity, m/s, of the pipe section 0-1 air outlet;
s612, according to the minimum static pressure velocity v of the air outletjminCalculating the minimum static pressure P of the air outletjmin
Pjmin=ρvjmin 2/2=1.2kg/m3×(3.17m/s)2÷2=6.02Pa
Pjmin-minimum static pressure, Pa, of the air outlet;
s613, calculating sudden expansion ratio C of section 0 inlet (soft connection outlet)tk
Ctk=A0/A1=0.03m2/0.12m2=0.25
A0The cross-sectional area, m, of the small-section pipe at the sudden expansion or contraction2
A1The cross-sectional area, m, of the large-section pipe at the sudden expansion or contraction2
S614, according to the sudden expansion ratio C of the section 0 inlet (soft connection outlet)tkChecking the local resistance system epsilon of the section 00Counting;
sudden expansion ratio C of section 0 entrancetkWhen 0.25, the inventor consults encourage Biaoyi Bianzhi (third edition) annex local resistance coefficient table to obtain local resistance coefficient epsilon0Is 0.57;
s615, according to the local resistance system epsilon of the section 00Number and minimum dynamic pressure P0dminCalculating the minimum local resistance DeltaP of the section 00jmin
ΔP0jmin=ε0×P0dmin=0.57×2.01Pa=1.15Pa
ΔP0jmin-minimum local resistance of section 0, Pa;
ε0-local drag coefficient of section 0;
s616, according to the minimum dynamic pressure P of the section 00dminMinimum local resistance Δ P0jminAnd minimum static pressure P of air outletjminAnd, calculating the minimum total pressure P of the section 00qmin
P0qmin=P0dmin+ΔP0jmin+Pjmin=2.01Pa+1.15Pa+6.02Pa=9.18Pa
P0qmin-minimum total pressure, Pa, of section 0;
s617, determining resistance delta P of other irregular local resistance componentsx
Without other resistance, Δ P, in the branchx=0Pa;
S618, determining the minimum margin K of the conveying power of the air supply branchmin
Get Kmin=10%;
S619, according to the total resistance delta P of the flexible connection air piperMinimum total pressure P of section 00qminResistance Δ P of other irregular local resistance membersxAnd a minimum margin K of power deliveredminCalculating the air supply branchMinimum conveying power DeltaP of roademin
ΔPemin=(1+Kmin)×(ΔPr+P0qmin+ΔPx)=(1+10%)×(24.02Pa+9.18Pa+0Pa)=36.52Pa
ΔPemin-the minimum delivery power, Pa, of the air supply branch;
Kmin-the minimum richness of the delivery power of the air supply branch;
ΔPx-the resistance of other irregular local resistance members, Pa;
(ΔPemin=36.52Pa)<(ΔPbmax100Pa), the next step is performed;
s7, calculating the width w of the air outleto
S71, drawing up an average outflow speed v of an air outlet according to the requirement of a passenger compartment of a carriage on an air supply speedo=1.00m/s;
S72, setting the average outflow speed v of the air outlet according to the drawingoCalculating the total area f of the air outleto
fo=Q/vo=0.22m3/s÷1.00m/s=0.22m2
foTotal area of the outlet, m2
vo-drawing up the average outflow speed of the air outlet in m/s;
s73, setting up the length l of the air outleto
The maximum arrangeable length of the air outlet is taken as the length of the air outlet,/o=lob=4.6m;
S74, according to the total area f of the air outletoAnd a proposed length loCalculating the width w of the air outleto
wo=fo/lo=0.22m2÷4.6=0.05m
wo-width of the outlet, m;
s8, calculating the sectional area S of each section of the variable-section air supply pipelineiHeight HiWidth WiSection of each pipe sectionVariation ratio k of surface heightH[(i-(i+1)]And the variation ratio k of the cross-sectional widthW[(i-(i+1)]And the conveying power delta P of the air supply branch pipelinee
S801, drawing up the outflow speed v of an air outlet according to the air supply requirement of a passenger roomo
Drawing up v according to the air supply requirement of passenger roomo=1.92m/s;
S802, calculating the relative flow Q of the air outlet of the pipe section 0-1m-0A ratio;
Qm-0=Qm/Q0-1=0.11m3/s÷0.22m3/s=0.5;
Qm-0-relative flow at the outlet of the pipe section 0-1;
Q0-1air volume of pipe section 0-1, m3/s;
S803, drawing up an air outlet outflow angle alpha according to the air supply requirement of the passenger room;
according to the air supply requirement of the passenger room, setting alpha as 60 degrees;
s804, according to the relative flow Q of the air outlet of the pipe section 0-1m-0And an outflow angle alpha, determining an outflow coefficient mu;
according to Qm-00.5 and an outflow angle α of 60 °, investigating encourage the outflow coefficients of sharp-edged orifices in fig. 2-3-9 in "fluid distribution network (third edition)" by showy folks, to obtain μ of 0.6;
s805, according to the outflow speed v of the air outletoAnd the outflow coefficient mu, calculating the static pressure velocity v of the air outletj
vj=vo/μ=1.92m/s÷0.6=3.20m/s
vj-the static pressure velocity of the outlet, m/s;
mu-outflow coefficient of the air outlet;
vo-drawing up the outflow speed of the air outlet in m/s;
s806. according to the static pressure velocity v of the air outletjCalculating the static pressure P of the tuyerej
Pj=ρvj 2/2=1.2kg/m3×(3.20m/s)2÷2=6.14Pa
Pj-static pressure, Pa, of the air outlet;
s807, according to the static pressure velocity v of the air outletjAnd drawing out the flow angle alpha to calculate the dynamic pressure velocity v of the cross section 00d
v0d=vj/tanα=3.20m/s÷tan60=1.85m/s
v0d-dynamic pressure velocity of section 0, m/s;
alpha-drawing up an outflow angle alpha of the air outlet;
s808, dynamic pressure velocity v according to section 00dSum flow rate Q0Calculating the sectional area S of the section 00Judgment S0And SbThe relative size of (d);
S0=Q0/v0d=0.22m3/s÷1.85m/s=0.12m2
S0cross section 0 cross section area, m2
(S0=0.12m2)=(Sb=0.12m2) Carrying out the next step;
s809, drawing up the height H of the section 00
Synthesis of H0=0.15m;
S810, according to the height H of the planned section 00And cross-sectional area S0Calculating the width W of the cross section 00
W0=S0/H0=0.12m2÷0.15m=0.80m
W0Width of section 0, m;
S0area of cross-section 0, m2
H0Height of section 0, m;
s811 dynamic pressure velocity v according to section 00dCalculating dynamic pressure P of section 00d
P0d=ρv0d 2/2=1.2kg/m3×(1.85m/s)2÷2=2.05Pa
P0dSection 0The dynamic pressure of (a), Pa;
s812, calculating sudden expansion ratio C of inlet (soft connection outlet) of section 0tk
Ctk=A0/A1=0.03m2/0.12m2=0.25
A0The cross-sectional area, m, of the small-section pipe at the sudden expansion or contraction2
A1The cross-sectional area, m, of the large-section pipe at the sudden expansion or contraction2
S813, according to the sudden expansion ratio C of the inlet (soft connection outlet) of the section 0tkChecking the sudden expansion local resistance system epsilon of the section 00Counting;
sudden expansion ratio C of section 0 entrancetkWhen 0.25, the inventor consults encourage Biaoyi Bianzhi (third edition) annex local resistance coefficient table to obtain local resistance coefficient epsilon0Is 0.57;
s814, sudden expansion local resistance system epsilon according to section 00Number and dynamic pressure P0dCalculating the sudden expansion local resistance P of the section 00j
P0j=ε0×P0d=0.57×2.05Pa=1.17Pa
P0j-sudden local resistance, Pa, of section 0;
ε0-sudden expansion local drag coefficient of section 0;
s815. dynamic pressure P according to section 00dStatic pressure PjAnd sudden local resistance P0jCalculating the total pressure P of the section 00q
P0q=Pj+P0d+P0j=6.14Pa+2.05Pa+1.17Pa=9.36Pa
P0q-total pressure of section 0, Pa;
s816, determining the resistance delta P of other irregular local resistance componentsx
The branch having no other resistance, Δ Px=0Pa;
S817, determining the abundance K of the conveying power of the air supply branch;
taking K as 15%;
s818, according to total resistance delta P of the flexible connection air piperFull pressure P of section 00qResistance Δ P of other irregular local resistance membersxAnd the margin K of the conveying power, and calculating the conveying power delta P of the air supply brancheJudgment of Δ PeWhether the judgment is reasonable or not;
ΔPe=(1+K)×(ΔPr+P0q+ΔPx)=(1+15%)×(24.02Pa+9.36Pa+0Pa)=38.39
ΔPe-the delivery power of the air supply branch Pa;
k is the margin of the power delivered by the air supply branch;
ΔPx-the resistance of other irregular local resistance members, Pa;
(ΔPe=38.39Pa)<(ΔPbmax100Pa), the next step is performed;
s819. Width W according to section 00And high H0Calculating the flow equivalent diameter D of the cross section 00
Figure BDA0003532243700000311
D0Flow equivalent diameter, m, of section 0;
W0width of section 0, m;
H0height of section 0, m;
s820, according to air quantity Q of pipe section 0-10-1Flow equivalent diameter D of section 00For an approximation of the pipe section 0-1, the specific friction resistance R of the pipe section 0-1 is examined(0-1)
According to the air quantity Q of the pipe section 0-10-1=0.22m3Flow equivalent diameter D of/s and section 000.36m, Zhenxiang encourage Xiaoyi folk, in the section "fluid distribution pipe network (fourth edition)" in fig. 3-6-1, the graphic for calculating the frictional resistance per unit length of ventilation duct is known as R(0-1)=0.18Pa/m;
S821. according to the specific friction resistance R of the pipe section 0-1(0-1)And length LmCalculating the on-way resistance delta P of the pipe section 0-1(0-1)y
ΔP(0-1)y=R(0-1)×Lm=0.18Pa/m×2.30m=0.41Pa
ΔP(0-1)y-on-way resistance, Pa, of the pipe section 0-1;
R(0-1)-specific friction resistance of pipe section 0-1, Pa/m;
s822, according to the relative flow Q of the air outlet of the pipe section 0-1m-0Checking the local drag coefficient epsilon of the 0-1 straight-through part of the pipe section(0-1)
According to the relative flow Q of the air outlet of the pipe section 0-1m-00.50, the local resistance coefficient of air flowing through the straight-through part of the side hole in Table 2-3-6 compiled by Shoudu encourage Shoudu (third edition) was investigated to obtain the local resistance coefficient epsilon of the straight-through part of the pipe section 0-1(0-1)=0.07;
S823. dynamic pressure P according to section 00dAnd the local drag coefficient epsilon of the 0-1 through part of the pipe section(0-1)Calculating the local resistance delta P of the pipe section 0-1(0-1)j
ΔP(0-1)j=ε(0-1)×P0d=0.07×2.05Pa=0.14Pa
ΔP(0-1)j-local resistance, Pa, of the pipe section 0-1;
ε(0-1)-local drag coefficient of pipe section 0-1;
s824, total pressure P according to section 00qOn-way resistance delta P of pipe section 0-1(0-1)yAnd local resistance Δ P(0-1)jCalculating the total pressure P of the section 11q
P1q=P0q-(ΔP(0-1)y+ΔP(0-1)j)=9.36Pa-(0.41Pa+0.14Pa)=8.81Pa
P1q-full pressure, Pa, of section 1;
s825. according to the total pressure P of the section 11qAnd static pressure P for keeping air supply from the air outlet uniformjCalculating the dynamic pressure P of the cross section 11dJudgment of P1dWhether the judgment is reasonable or not;
P1d=P1q-Pj=8.81Pa-6.14Pa=2.67Pa
P1d-dynamic pressure, Pa, of section 1;
(P1d2.67Pa) > 0, the design is reasonable, and the next step is carried out;
s826. dynamic pressure P according to section 11dCalculating the dynamic pressure velocity v of the cross section 11d
Figure BDA0003532243700000321
v1d-dynamic pressure velocity of section 1, m/s;
s827. dynamic pressure velocity v according to section 11dSum air quantity Q1Calculating the sectional area S of the section 11
S1=Q1/v1d=0.11m3/s÷2.11m/s=0.052m2
S1Section area of section 1, m2
S828, drawing up the height H of the section 11
Defining a height H of the cross-section 11=0.10m;
S829, cross-sectional area S according to section 11And a predetermined height H1Calculating the width W of the cross section 11
W1=S1/H1=0.052m2÷0.10m=0.52m
H1Height of section 1, m;
W1width of section 1, m;
s830, according to the height H of the section 00And height H of cross section 11Calculating the change ratio k of the section height of 0-1 of the pipe sectionH(0-1)
kH(0-1)=H1/H0=0.10m÷0.15m=0.67
kH(0-1)-the ratio of the variation of the height of the section 0-1 of the pipe section;
s831. according to the width W of the section 00And the width W of the cross section 11Calculating the variation ratio k of the section width of 0-1 of the pipe sectionW(0-1)
kW(0-1)=W1/W0=0.52m÷0.80m=0.65
kW(0-1)-the ratio of variation of the section width of the pipe section 0-1;
s832, repeating the steps S819-S831 to calculate the height H of the subsequent sectioniAnd width WiThe ratio of change k in the cross-sectional height of the subsequent pipe sectionH[i-(i+1)]And the variation ratio k of the cross-sectional widthW[i-(i+1)]
The same ratio of change in the height of the cross section and the same ratio of change in the width of the cross section are used for the pipe 1-2 and the pipe 0-1, and then,
H2=H1×kH(0-1)=0.1×0.67=0.07m
W2=W1×kW(0-1)=0.52×0.65=0.34m
example two, the total air supply Q carried by the air supply duct is 1200m3/h(0.33m3S), other conditions are the same as in example one
Proceeding to S2, v will appearr=Q/Sr=0.33÷0.03=11m/s,(vr=7.33m/s)>(vrmax10m/S), the air-conditioning air area is unreasonable, the branch bears the overlarge air supply amount, and the step S1 needs to be returned to perform air-conditioning partition again;
example three, the maximum sectional area S that the variable cross section air pipe can be arrangedb=0.08m2High Hb0.10m, other conditions and design procedure were the same as in example one
Proceeding to S56, it will appear (S)0min=0.11m2)>(Sb=0.08m2) If the air-conditioning air area is unreasonable, the branch bears overlarge air supply amount, and the step S1 is required to be returned to perform air-conditioning partition again;
the method for designing the variable-section uniform air supply pipeline of the rail transit vehicle can be applied to the design of other vehicles, other spaces, equipment and other fluids; the method can also be applied to the design of an equal-section air supply pipeline, a non-strip air outlet and a non-uniform air supply pipeline; the method can also be applied to the design of an exhaust pipeline; or to the evaluation of designed variable-section supply ducts.
The invention is not only used in the field of vehicle engineering, but also applicable in the engineering fields of construction, chemical engineering, environment, medicine, mine, electronics, animal husbandry and the like which need uniform fluid transportation and distribution, and the application principle and the design method are the same.
The foregoing shows and describes the general principles and broad features of the present invention and advantages thereof. It will be understood by those skilled in the art that the present invention is not limited to the embodiments described above, which are described in the specification and illustrated only to illustrate the principle of the present invention, but that various changes and modifications may be made therein without departing from the spirit and scope of the present invention, which fall within the scope of the invention as claimed. The scope of the invention is defined by the appended claims and equivalents thereof.

Claims (9)

1. A method for designing a variable-section uniform air supply pipeline of a rail transit vehicle is characterized by comprising the following steps of:
s1, dividing air conditioner zones, and determining necessary parameters and limiting conditions for designing an air supply pipeline;
s2, calculating the wind speed v of the minimum section wind pipe of the air supply pipelinerJudgment of vrWhether the maximum allowable wind speed v is exceededrmax
If v appears in step S2r≤vrmaxCarrying out the next step; if v isr>vrmaxIf so, the branch is judged to bear too large air supply volume and the air conditioner is not reasonable in partition, and the step returns to the step S1;
s3, drawing the number of the pipe sections divided by the variable cross-section air pipe to be n, and calculating the air quantity Q of each cross sectioniAnd length L of each pipe sectionmAir volume QmAnd the air quantity Qi-(i+1)
S4, calculating the minimum width w of the air outletominJudgment of wominWhether or not to exceed the maximum width w of the air outlet which can be arrangedob
If w appears in step S4omin≤wobProceed to the next stepA step of; if w isomin>wobIf so, the branch is judged to bear too large air supply volume and the air conditioner is not reasonable in partition, and the step returns to the step S1;
s5, calculating the minimum sectional area S of the section 0 of the variable-section air pipe0min(ii) a Judgment S0minWhether the maximum cross-sectional area S which can be arranged by the variable cross-section air pipe is exceededb
If S appears in step S50min≤SbCarrying out the next step; if S is0min>SbIf so, the branch is judged to bear too large air supply volume and the air conditioner is not reasonable in partition, and the step returns to the step S1;
s6, calculating the minimum conveying power delta P of the air supply branch pipelineeminJudgment of Δ PeminWhether the maximum full pressure Δ P of the alternative power plant is exceededbmax
If Δ P occurs in step S6emin≤ΔPbmaxCarrying out the next step; if Δ Pemin>ΔPbmaxIf the pressure is too high, the air conditioner is not reasonable in partition, and the process returns to step S1;
s7, calculating the width w of the air outleto
S8, calculating the sectional area S of each section of the variable-section air supply pipelineiHeight HiWidth WiThe ratio of change k in the height of the cross section of each pipe sectionH[(i-(i+1)]And the variation ratio k of the cross-sectional widthW[(i-(i+1)]And the conveying power delta P of the air supply branch pipelinee
2. The method for designing the variable-section uniform air supply pipeline of the rail transit vehicle as claimed in claim 1, wherein the step S1 includes the following steps: determining total air supply quantity Q born by air supply pipeline and sectional area S of branch minimum section air piperHigh HrWidth W ofrAnd length LrThe ratio of protrusion of the inlet of the minimum cross-section air duct CtMaximum allowable wind speed v of air supply ductrmaxMaximum sectional area S where variable cross-section air pipes can be arrangedbHigh HbWidth WbAnd a length LbPipe material of air supply pipeline and air outletType and maximum area f that can be arrangedobWidth wobLength l, length lobMaximum full pressure Δ P of optional power plantbmax
3. The method for designing the variable-section uniform air supply pipeline of the rail transit vehicle as claimed in claim 1, wherein v in the step S2rThe calculation method comprises the following steps:
vr=Q/Sr
vr-wind speed of the minimum cross section wind pipe, m/s;
q-total air supply volume, m, born by the air supply branch pipeline3/s;
Sr-cross-sectional area, m, of the minimum cross-sectional air duct of the air supply branch2
4. The method for designing the variable-section uniform air supply pipeline of the rail transit vehicle as claimed in claim 1, wherein the method for determining the number of each section and each pipe section and the length L of each pipe section in the step S3mAir volume QmSum air quantity Qi-(i+1)And the air quantity Q of each sectioniThe calculation method comprises the following steps:
s31, setting the number of pipe sections divided by the variable cross-section air pipe to be n, wherein the cross sections of the pipe sections from the head to the tail are 0, 1, 2, … … i … …, n-1 and n; the pipe sections are 0-1, 1-2, … … i- (1+1) … …, (n-1) -n;
s32, calculating the length L of each pipe section of the variable cross-section air pipem
Lm=Lb/n
Lm-the length, m, of each section of the variable cross-section air duct;
Lbthe maximum length, m, that the variable cross-section air duct can be arranged;
n is the number of the pipe sections divided by the wind pipe with the planned variable cross section;
s33, calculating the air output Q of each section of the variable cross-section air pipem
Qm=Q/n
Qm-variable cross-section air ducts eachAir output of pipe section, m3/s;
S34, calculating air quantity Q of each section of the variable-section air pipeiAnd the air quantity Q of each pipe sectioni-(i+1)
Qi=Q-Qm×i
Qi-(i+1)=Q-Qm×i
QiThe value range of the air volume of each section of the variable-section air pipe, i is 0 to n, m3/s;
Qi-(i+1)The air volume m of each section of the variable cross-section air duct3/s。
5. The method for designing the variable-section uniform air supply pipeline of the rail transit vehicle as claimed in claim 1, wherein the minimum width w of the air outlet in the step S4ominThe calculation method comprises the following steps:
s41, determining the maximum allowable flow velocity v of an air outlet of a carriage passenger room according to the air supply requirement of the carriage passenger roomomax
S42, according to the maximum allowable flow velocity v of the air outletomaxCalculating the minimum area f of the air outletomin
fomin=Q/vomax
fominMinimum area of air outlet, m2
vomax-the maximum allowable flow velocity at the outlet, m/s;
s43, according to the minimum area f of the air outletominAnd the air outlet can be arrangedobCalculating the minimum width w of the air outletomin
womin=fomin/lob
womin-minimum width of the outlet, m;
lobthe maximum length, m, that the air outlet can be arranged.
6. The method for designing the variable-section uniform air supply pipeline of the rail transit vehicle as claimed in claim 1, wherein in the step S5Minimum cross-sectional area S of cross-section 00minThe calculation method comprises the following steps:
s51, drawing up the maximum allowable flow velocity v of the air outletomax
S52, drawing up the minimum outflow angle alpha of the air outletminDetermining the outflow coefficient mu;
s53, according to the maximum allowable flow velocity v of the air outletomaxAnd the outflow coefficient mu, calculating the maximum static pressure velocity v of the air outletjmax
vjmax=vomax
vjmax-the maximum static pressure velocity of the outlet, m/s;
mu-flow coefficient of the air outlet;
s54, according to the maximum static pressure velocity v of the air outletjmaxCalculating the maximum static pressure P of the air outletjmax
Pjmax=ρvjmax 2/2
Pjmax-the maximum static pressure, Pa, of the air outlet;
rho-density of fluid transported in pipeline, kg/m3Air is 1.20kg/m3
S55, according to the maximum static pressure velocity v of the air outletjmaxAnd a minimum outflow angle αminCalculating the maximum dynamic pressure velocity v of the cross section 00dmax
v0dmax=vjmax/tan(αmin)
v0dmax-maximum dynamic pressure velocity of section 0, m/s;
s56, according to the maximum dynamic pressure velocity v of the section 00dmaxCalculating the minimum cross-sectional area S of the cross-section 00min
S0min=Q/v0dmax
S0minMinimum cross-sectional area of section 0, m2
7. The method for designing the variable-section uniform air supply pipeline of the rail transit vehicle as claimed in claim 1, wherein Δ P in the step S6eminIs calculated byThe method comprises the following steps:
s601. according to the height H of the air pipe with the minimum sectionrAnd width WrCalculating the flow equivalent diameter D of the branch minimum section air piper
Figure FDA0003532243690000051
DrFlow velocity equivalent diameter, m, of the smallest cross section air duct (flexible coupling duct);
Wr-the width of the flexible connecting duct, m;
Hr-height of the flexible connecting duct, m;
s602. according to the air quantity Q and the flow equivalent diameter D of the flexible connecting air piperChecking the specific friction resistance R of the flexible connecting air piper
S603, according to the specific friction resistance R of the flexible connection air piperAnd length LrCalculating the on-way resistance delta P of the flexible connecting air pipery
ΔPry=Rr×Lr
ΔPryThe on-way resistance of the flexible connecting air pipe is Pa/m;
Rrthe specific friction resistance of the flexible connecting air pipe is Pa/m;
Lr-length of the flexible connecting duct, m;
s604, according to the wind speed v of the flexible connection air piperCalculating the dynamic pressure P of the flexible connecting air piperd
Prd=ρvr 2/2
Prd-dynamic pressure, Pa, of the flexible connecting duct;
s605. according to the sudden shrinkage ratio C of the inlet of the flexible connecting air pipetsChecking the local resistance system epsilon of the sudden shrinkage of the inlet of the flexible connecting air piperCounting;
s606, according to the local resistance system epsilon of the flexible connection air pipe inlet sudden shrinkagerNumber and dynamic pressure PrdCalculating the local resistance delta P of the flexible connecting air piperj
ΔPrj=εr×Prd
ΔPrj-local resistance, Pa, of the flexible connecting duct;
εr-a local resistance system of the flexible connection air duct for the sudden contraction of the inlet;
s607, according to the on-way resistance delta P of the flexible connecting air piperyAnd local resistance Δ PrjCalculating the total resistance delta P of the flexible connecting air piper
ΔPr=ΔPry+ΔPrj
ΔPr-the total resistance of the flexible connecting duct, Pa;
s608, according to the air quantity Q of the section 0 of the variable-section air pipe0And a maximum cross-sectional area S that can be arrangedbCalculating the minimum dynamic pressure velocity v of the cross section 00dmin
v0dmin=Q/Sb
v0dmin-minimum dynamic pressure velocity of section 0, m/s;
s609, according to the minimum dynamic pressure velocity v of the section 00dminCalculating the minimum dynamic pressure P of the cross section 00dmin
P0dmin=ρv0dmin 2/2
P0dmin-minimum dynamic pressure, Pa, of section 0;
s610, according to the minimum outflow angle alpha of the air outlet of the pipe section 0-1minDetermining the outflow coefficient mu of the air outlet of the pipe section 0-1;
s611, according to the minimum dynamic pressure velocity v of the section 00dminAnd the minimum outflow angle alpha of the air outletminCalculating the minimum hydrostatic velocity vjmin
vjmin=v0dmin×tan(αmin)
vjmin-minimum static pressure velocity, m/s, of the pipe section 0-1 air outlet;
s612, according to the minimum static pressure velocity v of the air outletjminCalculating the minimum static pressure P of the air outletjmin
Pjmin=ρvjmin 2/2
Pjmin-minimum static pressure, Pa, of the air outlet;
s613, calculating sudden expansion ratio C of section 0 inlet (soft connection outlet)tk
Ctk=A0/A1
A0The cross-sectional area, m, of the small-section pipe at the sudden expansion or contraction2
A1The cross-sectional area, m, of the large-section pipe at the sudden expansion or contraction2
S614, according to the sudden expansion ratio C of the section 0 inlet (soft connection outlet)tkChecking the local resistance system epsilon of the section 00Counting;
s615, according to the local resistance system epsilon of the section 00Number and minimum dynamic pressure P0dminCalculating the minimum local resistance DeltaP of the section 00jmin
ΔP0jmin=ε0×P0dmin
ΔP0jmin-minimum local resistance of section 0, Pa;
ε0-local drag coefficient of section 0;
s616, according to the minimum dynamic pressure P of the section 00dminMinimum local resistance Δ P0jminAnd minimum static pressure P of air outletjminAnd, calculating the minimum total pressure P of the section 00qmin
P0qmin=P0dmin+ΔP0jmin+Pjmin
P0qmin-minimum total pressure of section 0, Pa;
s617, determining resistance delta P of other irregular local resistance componentsx
S618, determining the minimum margin K of the conveying power of the air supply branchmin
S619, according to the total resistance delta P of the flexible connection air piperMinimum total pressure P of section 00qminResistance Δ P of other irregular local resistance membersxAnd a minimum margin K of power deliveredminCalculating the minimum conveying power delta P of the air supply branchemin
ΔPemin=(1+Kmin)×(ΔPr+P0qmin+ΔPx)
ΔPemin-the minimum delivery power, Pa, of the air supply branch;
Kmin-the minimum richness of the delivery power of the air supply branch;
ΔPx-the resistance, Pa, of the other irregular local resistance members.
8. The method for designing the variable-section uniform air supply pipeline of the rail transit vehicle as claimed in claim 1, wherein the width w of the air outlet in the step S7oThe calculation method comprises the following steps:
s71, drawing up an average outflow speed v of an air outlet according to the requirement of a passenger compartment of a carriage on an air supply speedo
S72, according to the average outflow speed v of the drawn air outletoCalculating the total area f of the air outleto
fo=Q/vo
foTotal area of the outlet, m2
vo-drawing up the average outflow speed of the air outlet in m/s;
s73, drawing up the length l of the air outleto
S74, according to the total area f of the air outletoAnd a proposed length loCalculating the width w of the air outleto
wo=fo/lo
woWidth of the outlet, m.
9. The method for designing the variable cross-section uniform air supply pipeline of the rail transit vehicle as claimed in claim 1, wherein the cross-sectional area S of each cross-section of the variable cross-section air supply pipeline in the step S8iHeight HiWidth WiThe ratio of change k in the height of the cross section of each pipe sectionH[(i-(i+1)]And the variation ratio k of the cross-sectional widthW[(i-(i+1)]And air supply branch pipeRoad transport power Δ PeThe calculation method comprises the following steps:
s801, drawing up the outlet flow speed v of the air outlet according to the air supply requirement of the passenger roomo
S802, calculating the relative flow Q of the air outlet of the pipe section 0-1m-0A ratio;
Qm-0=Qm/Q0-1
Qm-0-relative flow at the outlet of the pipe section 0-1;
Q0-1air volume of pipe section 0-1, m3/s;
S803, drawing up an air outlet outflow angle alpha according to the air supply requirement of the passenger room;
s804, according to the relative flow Q of the air outlet of the pipe section 0-1m-0And an outflow angle alpha, determining an outflow coefficient mu;
s805, according to the outflow speed v of the air outletoAnd the outflow coefficient mu, calculating the static pressure velocity v of the air outletj
vj=vo
vj-the static pressure velocity of the outlet, m/s;
mu is the outflow coefficient of the air outlet;
vo-drawing up the outflow speed of the air outlet in m/s;
s806. according to the static pressure velocity v of the air outletjCalculating the static pressure P of the tuyerej
Pj=ρvj 2/2
Pj-static pressure, Pa, of the outlet;
s807, according to the static pressure velocity v of the air outletjAnd drawing out the flow angle alpha to calculate the dynamic pressure velocity v of the cross section 00d
v0d=vj/tanα
v0d-dynamic pressure velocity of section 0, m/s;
alpha-drawing up an outflow angle alpha of the air outlet;
s808, dynamic pressure velocity v according to section 00dSum flow rate Q0Calculating the sectional area S of the section 00Judgment S0And SbRelative size of (a);
S0=Q0/v0d
S0section area of section 0, m2
If S in step S8080≤SbCarrying out the next step; if S is0>SbReturning to step S801;
s809, drawing up the height H of the section 00
S810, according to the height H of the planned section 00And cross-sectional area S0Calculating the width W of the cross section 00
W0=S0/H0
W0The width of section 0, m;
S0area of cross-section 0, m2
H0Height of section 0, m;
s811 dynamic pressure velocity v according to section 00dCalculating dynamic pressure P of section 00d
P0d=ρv0d 2/2
P0d-dynamic pressure, Pa, of section 0;
s812, calculating sudden expansion ratio C of inlet (soft connection outlet) of section 0tk
Ctk=A0/A1
A0The cross-sectional area, m, of the small-section pipe at the sudden expansion or contraction2
A1The cross-sectional area, m, of the large-section pipe at the sudden expansion or contraction2
S813, according to the sudden expansion ratio C of the inlet (soft connection outlet) of the section 0tkChecking the sudden local resistance system epsilon of the section 00Counting;
s814, sudden expansion local resistance system epsilon according to section 00Number and dynamic pressure P0dCalculating the sudden expansion local resistance P of the section 00j
P0j=ε0×P0d
P0j-sudden local resistance, Pa, of section 0;
ε0-sudden expansion local drag coefficient of section 0;
s815. dynamic pressure P according to section 00dStatic pressure PjAnd sudden local resistance P0jCalculating the total pressure P of the section 00q
P0q=Pj+P0d+P0j
P0q-full pressure, Pa, of section 0;
s816, determining the resistance delta P of other irregular local resistance componentsx
S817, determining the abundance K of the conveying power of the air supply branch;
s818, according to total resistance delta P of the flexible connection air piperFull pressure P of section 00qResistance Δ P of other irregular local resistance membersxAnd the margin K of the conveying power, and calculating the conveying power delta P of the air supply brancheJudgment of Δ PeWhether the judgment is reasonable or not;
ΔPe=(1+K)×(ΔPr+P0q+ΔPx)
ΔPethe conveying power Pa of the air supply branch;
k is the richness of the power transmitted by the air supply branch;
ΔPx-the resistance, Pa, of the other irregular local resistance members;
if Δ P in step S818e≤ΔPbmaxThe design is reasonable, and the next step is carried out; if Δ Pe>ΔPbmaxIf the design is not reasonable, go back to step S801;
s819. Width W according to section 00And high H0Calculating the flow equivalent diameter D of the cross section 00
Figure FDA0003532243690000121
D0Flow equivalent diameter, m, of section 0;
W0width of section 0, m;
H0height of section 0, m;
s820, according to air quantity Q of pipe section 0-10-1Flow equivalent diameter D of section 00For an approximation of the pipe section 0-1, the specific friction resistance R of the pipe section 0-1 is examined(0-1)
S821, according to the specific friction resistance R of the pipe section 0-1(0-1)And length LmCalculating the on-way resistance delta P of the pipe section 0-1(0-1)y
ΔP(0-1)y=R(0-1)×Lm
ΔP(0-1)y-on-way resistance, Pa, of the pipe section 0-1;
R(0-1)-specific friction resistance of pipe section 0-1, Pa/m;
s822, according to the relative flow Q of the air outlet of the pipe section 0-1m-0Checking the local drag coefficient epsilon of the 0-1 straight-through part of the pipe section(0-1)
S823. dynamic pressure P according to section 00dAnd the local drag coefficient epsilon of the 0-1 through part of the pipe section(0-1)Calculating the local resistance delta P of the pipe section 0-1(0-1)j
ΔP(0-1)j=ε(0-1)×P0d
ΔP(0-1)j-local resistance, Pa, of the pipe section 0-1;
ε(0-1)-local drag coefficient of pipe section 0-1;
s824, total pressure P according to section 00qOn-way resistance delta P of pipe section 0-1(0-1)yAnd local resistance Δ P(0-1)jCalculating the total pressure P of the section 11q
P1q=P0q-(ΔP(0-1)y+ΔP(0-1)j)
P1q-full pressure, Pa, of section 1;
s825. according to the total pressure P of the section 11qAnd static pressure P for keeping air supply from the air outlet uniformjCalculating the dynamic pressure P of the section 11dJudgment of P1dWhether the judgment is reasonable or not;
P1d=P1q-Pj
P1d-dynamic pressure, Pa, of section 1;
if P is in step S8251dThe design is reasonable, and the next step is carried out; if P is1dIf not more than 0, the design returns to step S801;
s826. dynamic pressure P according to section 11dCalculating the dynamic pressure velocity v of the cross section 11d
Figure FDA0003532243690000131
v1d-dynamic pressure velocity of section 1, m/s;
s827. dynamic pressure velocity v according to section 11dSum air quantity Q1Calculating the sectional area S of the section 11
S1=Q1/v1d
S1Section area of section 1, m2
S828, drawing up the height H of the section 11
S829, cross-sectional area S according to section 11And defining a height H1Calculating the width W of the cross section 11
W1=S1/H1
H1Height of section 1, m;
W1width of section 1, m;
s830, according to the height H of the section 00And height H of cross section 11Calculating the change ratio k of the section height of 0-1 of the pipe sectionH(0-1)
kH(0-1)=H1/H0
kH(0-1)-the ratio of the variation of the section height of the pipe section 0-1;
s831. according to the width W of the section 00And the width W of the cross section 11Calculating the variation ratio k of the section width of 0-1 of the pipe sectionW(0-1)
kW(0-1)=W1/W0
kW(0-1)-the ratio of variation of the section width of the pipe section 0-1;
s832, repeating the steps S819-S831 to calculate the height H of the subsequent sectioniAnd width WiThe ratio of change k in the cross-sectional height of the subsequent pipe sectionH[i-(i+1)]And the variation ratio k of the cross-sectional widthW[i-(i+1)]
If the subsequent tube section employs the same ratio of change in cross-sectional height and change in cross-sectional width as the preceding adjacent tube section, then, in some cases,
Hi=H(i-1)×kH[(i-1)-i]
Wi=W(i-1)×kW[(i-1)-i]
Hi-height of section i, m;
Hi-height of section i, m;
kH[(i-1)-i]tube section [ (i-1) -i)]The cross-sectional height variation ratio of (a);
Withe width of the section i, m;
Withe width of the section i, m;
kW[(i-1)-i]tube section [ (i-1) -i)]The cross-sectional width change ratio of (a).
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