CN114113924B - Method for evaluating damage degree of short-circuit electrodynamic force to epoxy resin - Google Patents

Method for evaluating damage degree of short-circuit electrodynamic force to epoxy resin Download PDF

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CN114113924B
CN114113924B CN202111232401.6A CN202111232401A CN114113924B CN 114113924 B CN114113924 B CN 114113924B CN 202111232401 A CN202111232401 A CN 202111232401A CN 114113924 B CN114113924 B CN 114113924B
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周利军
陈田东
朱秋月
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Guangdong Deguang Transformer Co ltd
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Southwest Jiaotong University
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Abstract

一种短路电动力对环氧树脂破坏程度的评估方法，本方法包括以下步骤：首先取两份相同的环氧树脂试样，对其中一份施加等效短路电动力，另一份用于对照，不对其施加等效短路电动力，之后对这两份环氧树脂试样进行局部放电实验，然后根据实验数据计算放电次数差异指数、放电总能量差异指数和最大放电量差异指数，最后计算短路电动力对环氧树脂破坏程度评估因子。

Figure 202111232401

A method for evaluating the damage degree of epoxy resin caused by short-circuit electromotive force. The method includes the following steps: firstly, two identical epoxy resin samples are taken, and an equivalent short-circuit electromotive force is applied to one of them, and the other is used for comparison , do not apply equivalent short-circuit electric power to it, and then conduct partial discharge experiments on the two epoxy resin samples, and then calculate the difference index of discharge times, the difference index of total discharge energy and the difference index of maximum discharge according to the experimental data, and finally calculate the short-circuit Evaluation factor for the degree of damage to epoxy resins by electrodynamics.

Figure 202111232401

Description

一种短路电动力对环氧树脂破坏程度的评估方法A method for evaluating the damage degree of epoxy resin by short-circuit electrodynamic force

技术领域technical field

本发明属于变压器绝缘材料环氧树脂的性能测试领域，具体涉及一种短路电动力对环氧树脂破坏程度的评估方法。The invention belongs to the field of performance testing of transformer insulating material epoxy resin, and particularly relates to a method for evaluating the damage degree of epoxy resin caused by short-circuit electromotive force.

背景技术Background technique

由于干式变压器有重量轻、不易爆炸、安全可靠的优点，在电力行业受到了越来越多的应用，干式变压器对绝缘材料的性能要求也在不断发展，环氧树脂由于具有良好的机械和电气性能，故常常作为干式变压器的绝缘材料，但是当变压器遭受短路故障时，短路电动力会对环氧树脂产生破坏作用，使其机械和电气能力下降，为变压器的安全稳定运行埋下了隐患，因此需要对环氧树脂耐受短路电动力的能力进行评估，目前的测试评估方法没有提出具体的指标来定量表征短路电动力对环氧树脂的破坏程度，因此需要一种测试和评估方法来实现短路电动力对环氧树脂破坏程度的评估。Because dry-type transformers have the advantages of light weight, non-explosion, safety and reliability, they have been used more and more in the power industry. The performance requirements of dry-type transformers for insulating materials are also developing. Epoxy resin has good mechanical properties. It is often used as an insulating material for dry-type transformers, but when the transformer suffers from a short-circuit fault, the short-circuit electromotive force will destroy the epoxy resin, reducing its mechanical and electrical capabilities, laying the groundwork for the safe and stable operation of the transformer. Therefore, it is necessary to evaluate the ability of epoxy resin to withstand short-circuit electromotive force. The current test evaluation method does not propose specific indicators to quantitatively characterize the damage degree of short-circuit electromotive force to epoxy resin. Therefore, a test and evaluation are needed. A method to realize the evaluation of the damage degree of epoxy resin by short-circuit electrodynamic force.

发明内容SUMMARY OF THE INVENTION

本发明包括以下步骤：The present invention includes the following steps:

第一步：取两份相同的环氧树脂试样，对其中一份施加等效短路电动力F，另一份用于对照，不施加等效短路电动力；Step 1: Take two identical epoxy resin samples, apply the equivalent short-circuit electric force F to one of them, and apply the equivalent short-circuit electric force F to the other for the control, without applying the equivalent short-circuit electric force;

第二步：对施加过等效短路电动力的环氧树脂试样和未施加过等效短路电动力的环氧树脂试样进行局部放电实验，使用阶梯升压法对环氧树脂试样进行加压，依次施加0.8U0、1.0U0、1.2U0、1.4U0、1.6U0、1.8U0、2.0U0的电压，其中U0表示未施加过等效短路电动力的环氧树脂试样的起始放电电压，每个电压等级持续5分钟，记录未施加过等效短路电动力的环氧树脂试样每秒钟的放电次数N0 t、放电总能量W0 t和最大放电量Q0 t，记录施加过等效短路电动力的环氧树脂试样每秒钟的放电次数N1 t、放电总能量W1 t、最大放电量Q1 t，其中t表示测量时间，单位是秒，t＝1，2，3……，2100；Step 2: Partial discharge experiments are performed on the epoxy resin samples that have been applied with equivalent short-circuit electric power and the epoxy resin samples that have not been applied with equivalent short-circuit electric power. Pressurize, apply voltages of 0.8U 0 , 1.0U 0 , 1.2U 0 , 1.4U 0 , 1.6U 0 , 1.8U 0 , 2.0U 0 in sequence, where U 0 represents epoxy that has not been applied with equivalent short-circuit electromotive force The initial discharge voltage of the resin sample, each voltage level lasts for 5 minutes, record the number of discharges per second N 0 t , the total discharge energy W 0 t and the maximum discharge energy W 0 t of the epoxy resin sample that has not been applied with equivalent short-circuit electromotive force. Discharge quantity Q 0 t , record the number of discharges N 1 t per second, the total discharge energy W 1 t , and the maximum discharge quantity Q 1 t of the epoxy resin sample applied with the equivalent short-circuit electromotive force per second, where t represents the measurement time, The unit is second, t=1, 2, 3..., 2100;

第三步：计算放电次数差异指数λN，通过(t，N0 t)拟合N0 t关于时间t的函数f0(t)，通过(t，N1 t)拟合N1 t关于时间t的函数f1(t)，根据公式(1)计算放电次数差异指数λN，Step 3: Calculate the difference index of discharge times λ N , fit the function f 0 (t) of N 0 t with respect to time t by (t, N 0 t ), and fit N 1 t with respect to time t by (t, N 1 t ) The function f 1 (t) of time t, according to formula (1), the difference index of discharge times λ N is calculated,

Figure BDA0003316538360000011
Figure BDA0003316538360000011

其中f0'(t)表示f0(t)关于时间t的一阶导函数，f1'(t)表示f1(t)关于时间t的一阶导函数；where f 0 '(t) represents the first-order derivative function of f 0 (t) with respect to time t, and f 1 '(t) represents the first-order derivative function of f 1 (t) with respect to time t;

第四步：计算放电总能量差异指数λW，通过(t，W0 t)拟合W0 t关于时间t的函数g0(t)，通过(t，W1 t)拟合W1 t关于时间t的函数g1(t)，根据公式(2)计算放电次数差异指数λW，The fourth step: calculate the total discharge energy difference index λ W , fit the function g 0 (t) of W 0 t with respect to time t by (t, W 0 t ), and fit W 1 t by (t, W 1 t ) Regarding the function g 1 (t) of the time t, the discharge times difference index λ W is calculated according to the formula (2),

Figure BDA0003316538360000021
Figure BDA0003316538360000021

其中g0'(t)表示g0(t)关于时间t的一阶导函数，g1'(t)表示g1(t)关于时间t的一阶导函数；其中g0”(t)表示g0(t)关于时间t的二阶导函数，g1”(t)表示g1(t)关于时间t的二阶导函数；where g 0 '(t) represents the first-order derivative of g 0 (t) with respect to time t, and g 1 '(t) represents the first-order derivative of g 1 (t) with respect to time t; where g 0 "(t) represents the second-order derivative function of g 0 (t) with respect to time t, and g 1 ”(t) represents the second-order derivative function of g 1 (t) with respect to time t;

第三步：计算最大放电量差异指数λQ，通过(t，Q0 t)拟合Q0 t关于时间t的函数h0(t)，通过(t，Q1 t)拟合Q1 t关于时间t的函数h1(t)，根据公式(3)计算放电次数差异指数λQ，The third step: calculate the maximum discharge difference index λ Q , fit the function h 0 (t) of Q 0 t with respect to time t by (t, Q 0 t ), and fit Q 1 t by (t, Q 1 t ) Regarding the function h 1 (t) of the time t, the discharge times difference index λ Q is calculated according to the formula (3),

Figure BDA0003316538360000022
Figure BDA0003316538360000022

其中h0'(t)表示h0(t)关于时间t的一阶导函数，h1'(t)表示h1(t)关于时间t的一阶导函数；其中h0”(t)表示h0(t)关于时间t的二阶导函数，h1”(t)表示h1(t)关于时间t的二阶导函数；where h 0 '(t) represents the first derivative of h 0 (t) with respect to time t, and h 1 '(t) represents the first derivative of h 1 (t) with respect to time t; where h 0 "(t) represents the second-order derivative function of h 0 (t) with respect to time t, and h 1 ”(t) represents the second-order derivative function of h 1 (t) with respect to time t;

第五步：计算短路电动力对环氧树脂破坏程度评估因子λ，Step 5: Calculate the evaluation factor λ of the damage degree of the epoxy resin caused by the short-circuit electromotive force,

Figure BDA0003316538360000023
Figure BDA0003316538360000023

若0<λ≤5.6，则表示短路电动力对环氧树脂试样未造成破坏，若5.6<λ≤10.25，则表示短路电动力对环氧树脂试样造成了轻微破坏，若10.25<λ≤50，则表示短路电动力对环氧树脂试样造成了中度破坏，若λ>50，则表示短路电动力对环氧树脂试样造成了重度破坏。If 0<λ≤5.6, it means that the short-circuit electromotive force did not cause damage to the epoxy resin sample. If 5.6<λ≤10.25, it means that the short-circuit electromotive force caused slight damage to the epoxy resin sample. If 10.25<λ≤ 50, it means that the short-circuit electromotive force has caused moderate damage to the epoxy resin sample, and if λ>50, it means that the short-circuit electrodynamic force has caused serious damage to the epoxy resin sample.

附图说明Description of drawings

图1为一种短路电动力对环氧树脂破坏程度的评估方法的流程图。Fig. 1 is a flow chart of a method for evaluating the damage degree of epoxy resin caused by short-circuit electrodynamic force.

具体实施方式Detailed ways

下面结合附图和具体实施过程对本发明进行进一步说明，一种短路电动力对环氧树脂破坏程度的评估方法，包括以下步骤：The present invention will be further described below in conjunction with the accompanying drawings and the specific implementation process, a method for evaluating the damage degree of epoxy resin by short-circuit electrodynamic force, comprising the following steps:

第一步：取两份相同的环氧树脂试样，对其中一份施加等效短路电动力F，另一份用于对照，不施加等效短路电动力；Step 1: Take two identical epoxy resin samples, apply the equivalent short-circuit electric force F to one of them, and apply the equivalent short-circuit electric force F to the other for the control, without applying the equivalent short-circuit electric force;

第二步：对施加过等效短路电动力的环氧树脂试样和未施加过等效短路电动力的环氧树脂试样进行局部放电实验，使用阶梯升压法对环氧树脂试样进行加压，依次施加0.8U0、1.0U0、1.2U0、1.4U0、1.6U0、1.8U0、2.0U0的电压，其中U0表示未施加过等效短路电动力的环氧树脂试样的起始放电电压，每个电压等级持续5分钟，记录未施加过等效短路电动力的环氧树脂试样每秒钟的放电次数N0 t、放电总能量W0 t和最大放电量Q0 t，记录施加过等效短路电动力的环氧树脂试样每秒钟的放电次数N1 t、放电总能量W1 t、最大放电量Q1 t，其中t表示测量时间，单位是秒，t＝1，2，3……，2100；Step 2: Partial discharge experiments are performed on the epoxy resin samples that have been applied with equivalent short-circuit electric power and the epoxy resin samples that have not been applied with equivalent short-circuit electric power. Pressurize, apply voltages of 0.8U 0 , 1.0U 0 , 1.2U 0 , 1.4U 0 , 1.6U 0 , 1.8U 0 , 2.0U 0 in sequence, where U 0 represents epoxy that has not been applied with equivalent short-circuit electromotive force The initial discharge voltage of the resin sample, each voltage level lasts for 5 minutes, record the number of discharges per second N 0 t , the total discharge energy W 0 t and the maximum discharge energy W 0 t of the epoxy resin sample that has not been applied with equivalent short-circuit electromotive force. Discharge quantity Q 0 t , record the number of discharges N 1 t per second, the total discharge energy W 1 t , and the maximum discharge quantity Q 1 t of the epoxy resin sample applied with the equivalent short-circuit electromotive force per second, where t represents the measurement time, The unit is second, t=1, 2, 3..., 2100;

第三步：计算放电次数差异指数λN，通过(t，N0 t)拟合N0 t关于时间t的函数f0(t)，通过(t，N1 t)拟合N1 t关于时间t的函数f1(t)，根据公式(1)计算放电次数差异指数λN，Step 3: Calculate the difference index of discharge times λ N , fit the function f 0 (t) of N 0 t with respect to time t by (t, N 0 t ), and fit N 1 t with respect to time t by (t, N 1 t ) The function f 1 (t) of time t, according to formula (1), the difference index of discharge times λ N is calculated,

Figure BDA0003316538360000031
Figure BDA0003316538360000031

其中f0'(t)表示f0(t)关于时间t的一阶导函数，f1'(t)表示f1(t)关于时间t的一阶导函数；where f 0 '(t) represents the first-order derivative function of f 0 (t) with respect to time t, and f 1 '(t) represents the first-order derivative function of f 1 (t) with respect to time t;

第四步：计算放电总能量差异指数λW，通过(t，W0 t)拟合W0 t关于时间t的函数g0(t)，通过(t，W1 t)拟合W1 t关于时间t的函数g1(t)，根据公式(2)计算放电次数差异指数λW，The fourth step: calculate the total discharge energy difference index λ W , fit the function g 0 (t) of W 0 t with respect to time t by (t, W 0 t ), and fit W 1 t by (t, W 1 t ) Regarding the function g 1 (t) of the time t, the discharge times difference index λ W is calculated according to the formula (2),

Figure BDA0003316538360000032
Figure BDA0003316538360000032

其中g0'(t)表示g0(t)关于时间t的一阶导函数，g1'(t)表示g1(t)关于时间t的一阶导函数；其中g0”(t)表示g0(t)关于时间t的二阶导函数，g1”(t)表示g1(t)关于时间t的二阶导函数；where g 0 '(t) represents the first-order derivative of g 0 (t) with respect to time t, and g 1 '(t) represents the first-order derivative of g 1 (t) with respect to time t; where g 0 "(t) represents the second-order derivative function of g 0 (t) with respect to time t, and g 1 ”(t) represents the second-order derivative function of g 1 (t) with respect to time t;

第三步：计算最大放电量差异指数λQ，通过(t，Q0 t)拟合Q0 t关于时间t的函数h0(t)，通过(t，Q1 t)拟合Q1 t关于时间t的函数h1(t)，根据公式(3)计算放电次数差异指数λQ，The third step: calculate the maximum discharge difference index λ Q , fit the function h 0 (t) of Q 0 t with respect to time t by (t, Q 0 t ), and fit Q 1 t by (t, Q 1 t ) Regarding the function h 1 (t) of the time t, the discharge times difference index λ Q is calculated according to the formula (3),

Figure BDA0003316538360000033
Figure BDA0003316538360000033

其中h0'(t)表示h0(t)关于时间t的一阶导函数，h1'(t)表示h1(t)关于时间t的一阶导函数；其中h0”(t)表示h0(t)关于时间t的二阶导函数，h1”(t)表示h1(t)关于时间t的二阶导函数；where h 0 '(t) represents the first derivative of h 0 (t) with respect to time t, and h 1 '(t) represents the first derivative of h 1 (t) with respect to time t; where h 0 "(t) represents the second-order derivative function of h 0 (t) with respect to time t, and h 1 ”(t) represents the second-order derivative function of h 1 (t) with respect to time t;

第五步：计算短路电动力对环氧树脂破坏程度评估因子λ，Step 5: Calculate the evaluation factor λ of the damage degree of the epoxy resin caused by the short-circuit electromotive force,

Figure BDA0003316538360000034
Figure BDA0003316538360000034

若0<λ≤5.6，则表示短路电动力对环氧树脂试样未造成破坏，若5.6<λ≤10.25，则表示短路电动力对环氧树脂试样造成了轻微破坏，若10.25<λ≤50，则表示短路电动力对环氧树脂试样造成了中度破坏，若λ>50，则表示短路电动力对环氧树脂试样造成了重度破坏。If 0<λ≤5.6, it means that the short-circuit electromotive force did not cause damage to the epoxy resin sample. If 5.6<λ≤10.25, it means that the short-circuit electromotive force caused slight damage to the epoxy resin sample. If 10.25<λ≤ 50, it means that the short-circuit electromotive force has caused moderate damage to the epoxy resin sample, and if λ>50, it means that the short-circuit electrodynamic force has caused serious damage to the epoxy resin sample.

Claims (1)

1.一种短路电动力对环氧树脂破坏程度的评估方法，其特征在于，包括以下步骤：1. a short-circuit electromotive force is to the evaluation method of epoxy resin damage degree, is characterized in that, comprises the following steps: 第一步：取两份相同的环氧树脂试样，对其中一份施加等效短路电动力F，另一份用于对照，不施加等效短路电动力；Step 1: Take two identical epoxy resin samples, apply the equivalent short-circuit electric force F to one of them, and apply the equivalent short-circuit electric force F to the other for the control, without applying the equivalent short-circuit electric force; 第二步：对施加过等效短路电动力的环氧树脂试样和未施加过等效短路电动力的环氧树脂试样进行局部放电实验，使用阶梯升压法对环氧树脂试样进行加压，依次施加0.8U0、1.0U0、1.2U0、1.4U0、1.6U0、1.8U0、2.0U0的电压，其中U0表示未施加过等效短路电动力的环氧树脂试样的起始放电电压，每个电压等级持续5分钟，记录未施加过等效短路电动力的环氧树脂试样每秒钟的放电次数N0 t、放电总能量W0 t和最大放电量Q0 t，记录施加过等效短路电动力的环氧树脂试样每秒钟的放电次数N1 t、放电总能量W1 t、最大放电量Q1 t，其中t表示测量时间，单位是秒，t＝1，2，3……，2100；Step 2: Partial discharge experiments are performed on the epoxy resin samples that have been applied with equivalent short-circuit electric power and the epoxy resin samples that have not been applied with equivalent short-circuit electric power. Pressurize, apply voltages of 0.8U 0 , 1.0U 0 , 1.2U 0 , 1.4U 0 , 1.6U 0 , 1.8U 0 , 2.0U 0 in sequence, where U 0 represents epoxy that has not been applied with equivalent short-circuit electromotive force The initial discharge voltage of the resin sample, each voltage level lasts for 5 minutes, record the number of discharges per second N 0 t , the total discharge energy W 0 t and the maximum discharge energy W 0 t of the epoxy resin sample that has not been applied with equivalent short-circuit electromotive force. Discharge quantity Q 0 t , record the number of discharges N 1 t per second, the total discharge energy W 1 t , and the maximum discharge quantity Q 1 t of the epoxy resin sample applied with the equivalent short-circuit electromotive force per second, where t represents the measurement time, The unit is second, t=1, 2, 3..., 2100; 第三步：计算放电次数差异指数λN，通过(t，N0 t)拟合N0 t关于时间t的函数f0(t)，通过(t，N1 t)拟合N1 t关于时间t的函数f1(t)，根据公式(1)计算放电次数差异指数λN，The third step: calculate the difference index λ N of the number of discharges, fit the function f 0 (t) of N 0 t with respect to time t by (t, N 0 t ), and fit N 1 t with respect to time t by (t, N 1 t ) The function f 1 (t) of time t, according to formula (1), the difference index of discharge times λ N is calculated,
Figure FDA0003316538350000011
Figure FDA0003316538350000011
 其中f0'(t)表示f0(t)关于时间t的一阶导函数，f1'(t)表示f1(t)关于时间t的一阶导函数；where f 0 '(t) represents the first-order derivative function of f 0 (t) with respect to time t, and f 1 '(t) represents the first-order derivative function of f 1 (t) with respect to time t; 第四步：计算放电总能量差异指数λW，通过(t，W0 t)拟合W0 t关于时间t的函数g0(t)，通过(t，W1 t)拟合W1 t关于时间t的函数g1(t)，根据公式(2)计算放电次数差异指数λW，The fourth step: calculate the total discharge energy difference index λ W , fit the function g 0 (t) of W 0 t with respect to time t by (t, W 0 t ), and fit W 1 t by (t, W 1 t ) Regarding the function g 1 (t) of the time t, the discharge times difference index λ W is calculated according to the formula (2),
Figure FDA0003316538350000012
Figure FDA0003316538350000012
 其中g0'(t)表示g0(t)关于时间t的一阶导函数，g1'(t)表示g1(t)关于时间t的一阶导函数；其中g0”(t)表示g0(t)关于时间t的二阶导函数，g1”(t)表示g1(t)关于时间t的二阶导函数；where g 0 '(t) represents the first-order derivative of g 0 (t) with respect to time t, and g 1 '(t) represents the first-order derivative of g 1 (t) with respect to time t; where g 0 "(t) represents the second-order derivative function of g 0 (t) with respect to time t, and g 1 ”(t) represents the second-order derivative function of g 1 (t) with respect to time t; 第三步：计算最大放电量差异指数λQ，通过(t，Q0 t)拟合Q0 t关于时间t的函数h0(t)，通过(t，Q1 t)拟合Q1 t关于时间t的函数h1(t)，根据公式(3)计算放电次数差异指数λQ，The third step: calculate the maximum discharge difference index λ Q , fit the function h 0 (t) of Q 0 t with respect to time t by (t, Q 0 t ), and fit Q 1 t by (t, Q 1 t ) Regarding the function h 1 (t) of the time t, the discharge times difference index λ Q is calculated according to the formula (3),
Figure FDA0003316538350000013
Figure FDA0003316538350000013
 其中h0'(t)表示h0(t)关于时间t的一阶导函数，h1'(t)表示h1(t)关于时间t的一阶导函数；其中h0”(t)表示h0(t)关于时间t的二阶导函数，h1”(t)表示h1(t)关于时间t的二阶导函数；where h 0 '(t) represents the first derivative of h 0 (t) with respect to time t, and h 1 '(t) represents the first derivative of h 1 (t) with respect to time t; where h 0 "(t) represents the second-order derivative function of h 0 (t) with respect to time t, and h 1 ”(t) represents the second-order derivative function of h 1 (t) with respect to time t; 第五步：计算短路电动力对环氧树脂破坏程度评估因子λ，Step 5: Calculate the evaluation factor λ of the damage degree of the epoxy resin caused by the short-circuit electromotive force,
Figure FDA0003316538350000021
Figure FDA0003316538350000021
 若0<λ≤5.6，则表示短路电动力对环氧树脂试样未造成破坏，若5.6<λ≤10.25，则表示短路电动力对环氧树脂试样造成了轻微破坏，若10.25<λ≤50，则表示短路电动力对环氧树脂试样造成了中度破坏，若λ>50，则表示短路电动力对环氧树脂试样造成了重度破坏。If 0<λ≤5.6, it means that the short-circuit electromotive force did not cause damage to the epoxy resin sample. If 5.6<λ≤10.25, it means that the short-circuit electromotive force caused slight damage to the epoxy resin sample. If 10.25<λ≤ 50, it means that the short-circuit electromotive force has caused moderate damage to the epoxy resin sample, and if λ>50, it means that the short-circuit electrodynamic force has caused serious damage to the epoxy resin sample.
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