CN113438862A - Heat dissipation device of CT detector assembly and design method thereof - Google Patents

Heat dissipation device of CT detector assembly and design method thereof Download PDF

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CN113438862A
CN113438862A CN202110683391.1A CN202110683391A CN113438862A CN 113438862 A CN113438862 A CN 113438862A CN 202110683391 A CN202110683391 A CN 202110683391A CN 113438862 A CN113438862 A CN 113438862A
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air
air supply
supply manifold
detector
duct
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CN113438862B (en
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张宇
马兴江
金坚诚
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FMI Technologies Inc
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    • H—ELECTRICITY
    • H05—ELECTRIC TECHNIQUES NOT OTHERWISE PROVIDED FOR
    • H05K—PRINTED CIRCUITS; CASINGS OR CONSTRUCTIONAL DETAILS OF ELECTRIC APPARATUS; MANUFACTURE OF ASSEMBLAGES OF ELECTRICAL COMPONENTS
    • H05K7/00—Constructional details common to different types of electric apparatus
    • H05K7/20—Modifications to facilitate cooling, ventilating, or heating
    • H05K7/20009—Modifications to facilitate cooling, ventilating, or heating using a gaseous coolant in electronic enclosures
    • H05K7/20136—Forced ventilation, e.g. by fans
    • H05K7/20145—Means for directing air flow, e.g. ducts, deflectors, plenum or guides
    • H—ELECTRICITY
    • H05—ELECTRIC TECHNIQUES NOT OTHERWISE PROVIDED FOR
    • H05K—PRINTED CIRCUITS; CASINGS OR CONSTRUCTIONAL DETAILS OF ELECTRIC APPARATUS; MANUFACTURE OF ASSEMBLAGES OF ELECTRICAL COMPONENTS
    • H05K7/00—Constructional details common to different types of electric apparatus
    • H05K7/20—Modifications to facilitate cooling, ventilating, or heating
    • H05K7/20009—Modifications to facilitate cooling, ventilating, or heating using a gaseous coolant in electronic enclosures
    • H05K7/20136—Forced ventilation, e.g. by fans
    • H05K7/20181—Filters; Louvers
    • H—ELECTRICITY
    • H05—ELECTRIC TECHNIQUES NOT OTHERWISE PROVIDED FOR
    • H05K—PRINTED CIRCUITS; CASINGS OR CONSTRUCTIONAL DETAILS OF ELECTRIC APPARATUS; MANUFACTURE OF ASSEMBLAGES OF ELECTRICAL COMPONENTS
    • H05K7/00—Constructional details common to different types of electric apparatus
    • H05K7/20—Modifications to facilitate cooling, ventilating, or heating
    • H05K7/20009—Modifications to facilitate cooling, ventilating, or heating using a gaseous coolant in electronic enclosures
    • H05K7/20209—Thermal management, e.g. fan control

Abstract

The invention belongs to the technical field of CT, and particularly relates to a heat dissipation device of a CT detector assembly and a design method thereof. The detector comprises a CT detector, wherein a plurality of detector modules are arranged in the CT detector, and the detector is characterized by further comprising an air feeder, a static pressure box and air feeding manifolds, wherein the number of the air feeding manifolds is the same as that of the detector modules; the air supply outlet of the air feeder is opposite to the static pressure box; the air inlet of the air supply manifold is communicated with the static pressure box; the air inlets of the air supply manifolds are opposite to the detector modules; the air supply manifolds correspond to the detector modules one to one. The invention is suitable for detectors with various specifications, and has the characteristics of ensuring the constant temperature of each module and being beneficial to reducing the noise of the detectors during operation.

Description

Heat dissipation device of CT detector assembly and design method thereof
Technical Field
The invention belongs to the technical field of CT, and particularly relates to a heat dissipation device of a CT detector assembly and a design method thereof.
Background
The detector is a core component in the CT system, and the stability of the output signal of the CT detector has a very large relationship with the temperature, and in the system using the CT detector, the temperature of the detector must be stabilized by adjusting the heating or cooling. The CT detector needs to maintain a constant temperature during operation, but the power consumption of an image processing chip is large, each module needs the image processing chip, and the number of the modules is large.
In the current market, a common heat dissipation method is to arrange a plurality of heat dissipation fans above the detector, but the above method has the following problems:
1. gaps are inevitably formed between the fans, and poor heat dissipation can exist in the middle modules;
2. the multiple cooling fans are high in running noise and power, generated air flows are mutually influenced, and actual cooling efficiency is low;
3. the filter screen area of a plurality of fans is big, and it is inconvenient to remove dust.
Therefore, it is necessary to design a heat dissipation device for a CT detector, which can ensure the temperature of each module to be constant, is suitable for detectors of various specifications, and is also beneficial to reducing the noise generated during the operation of the detector.
For example, chinese utility model patent with application number CN201820434043.4 a CT detector heat abstractor, including detector assembly roof and the fan apron of being connected with the detector assembly roof, be equipped with a plurality of fans on the fan apron, the roof mouth has been seted up on the detector assembly roof, be equipped with the wind channel between detector assembly roof and the fan apron, the roof mouth is connected to the one end in wind channel, and the air outlet of fan is connected to the other end. Although the air duct is arranged on the fan cover plate, air passing through the ventilation opening can be completely gathered at the air inlet of the top plate, the air passing through the dustproof device is greatly utilized, the air duct is designed, and the utilization efficiency of the air blown by the cooling fan is improved, so that the detector is efficiently cooled, the heat dissipation is stable, and the heat dissipation efficiency is remarkable; therefore, the air cooling efficiency is improved, but the defects of poor heat dissipation of the middle module, low actual heat dissipation efficiency and inconvenient dust removal are caused because the heat dissipation mode adopts the mode of arranging the plurality of fans on the fan cover plate.
Disclosure of Invention
The invention provides a CT detector assembly heat dissipation device which can ensure the constant temperature of each module, is suitable for detectors with various specifications and is beneficial to reducing the noise of the detectors during operation and a design method thereof, aiming at overcoming the problems that the heat dissipation of an intermediate module is poor, the actual heat dissipation efficiency is low and the dust removal is inconvenient in the existing heat dissipation mode that a plurality of heat dissipation fans are arranged above the detectors in the prior art.
In order to achieve the purpose, the invention adopts the following technical scheme:
the CT detector assembly heat dissipation device comprises a CT detector, wherein a plurality of detector modules are arranged in the CT detector, and the CT detector further comprises an air feeder, a static pressure box and air feeding manifolds, wherein the number of the air feeding manifolds is the same as that of the detector modules; the air supply outlet of the air feeder is opposite to the static pressure box; the air inlet of the air supply manifold is communicated with the static pressure box; the air inlets of the air supply manifolds are opposite to the detector modules; the air supply manifolds correspond to the detector modules one to one.
Preferably, the air inlets of the air supply manifolds have the same area.
Preferably, a necking air duct for balancing air pressure loss along the air duct is arranged in each pipeline of the air supply manifolds.
Preferably, a filter screen is arranged in the static pressure box.
The invention also provides a design method of the heat dissipation device of the CT detector assembly, which comprises the following steps:
s1, calculating the on-way air pressure loss of the air flow on each air supply manifold, and obtaining on-way resistance values in the pipelines of each air supply manifold;
s2, calculating the air pressure loss at the necking air channel in each air supply manifold to obtain the pressure loss value at the necking position in each air supply manifold;
s3, calculating the diameter of the neck air duct in each air supply manifold according to the on-way resistance value in each air supply manifold pipeline and the pressure loss value of the neck in each air supply manifold obtained in the steps S1 and S2;
and S4, finishing the design of the heat dissipation device of the CT detector assembly according to the diameter value of the neck air channel in each air supply manifold obtained in the step S3.
Preferably, step S1 further includes the steps of:
s11, calculating the Reynolds number Re,
Figure BDA0003123593590000031
whereinRho is air density, unit KG/M2(ii) a V is wind speed, unit is M2(ii) a d is the diameter of the air supply manifold, and the unit is M; eta is the aerodynamic viscosity coefficient;
s12, looking up the Modisco diagram, looking up the corresponding abscissa on the Modisco diagram, looking up the table 'absolute roughness Delta of the pipe wall of the pipeline', dividing the absolute roughness Delta by the diameter d of the air supply manifold, and calculating Delta/d, wherein the value of Delta/d corresponds to the right ordinate of the Modisco diagram and the curve of the center of the Modisco diagram area; correspondingly determining a point on the central curve of the Modi diagram area according to the Reynolds number Re of the abscissa obtained in the step S11 and the Delta/d of the ordinate on the right side, wherein the point corresponds to the on-way resistance coefficient lambda of the ordinate on the left side of the Modi diagram;
s13 according to the formula
Figure BDA0003123593590000032
Calculating on-way resistance values in each air supply manifold pipeline;
wherein λ is an on-way resistance coefficient of the air in the duct obtained in step S12, V is a wind speed, ρ is an air density, D is a diameter of the air supply manifold, and L is a length of the air supply manifold.
Preferably, step S2 further includes the steps of:
s21, because the airflow passes through the neck-in air duct in each air supply manifold, according to the Bernoulli equation:
Figure BDA0003123593590000033
wherein p is1Is the pressure of the air flow at a point A before the air flow passes through the neck-down air duct in the air supply manifold2Is the pressure intensity, V, of the air flow passing through a point B at the neck-down duct in the supply manifold1And V2Flow velocities at the air flow midpoint a and point B, respectively, γ represents the gravity per unit volume of air, γ ═ ρ g, ρ is the air density, g is the acceleration of gravity, z is the acceleration of gravity, and1and z2Are all constant;
s22, according to the Bernoulli equation of the step S21, obtaining the local loss of the variable diameter in the air supply manifold as follows:
Figure BDA0003123593590000041
because the air volume passing through the cross section at the point A and the point B is consistent, the following results are obtained:
V1Aa＝V2Ab
wherein A isaIs the cross-sectional area at point A, AbCross-sectional area at point B;
s23, consider AaAnd AbThe distance between the sections is short, the surface forces on the side surfaces are disregarded, and the momentum equation is then obtained as:
P1Ab-P2Ab＝ρV2Ab(V1-V2)
the momentum equation and the continuous equation are substituted to obtain the pressure loss delta P at the necking air duct of each air supply manifoldx＝P1-P2＝ρV2(V1-V2)，
Figure BDA0003123593590000042
Wherein, the longest air supply manifold is not provided with a necking air duct, so the total air pressure loss of the longest air supply manifold is P ═ delta PMI.e. by
Figure BDA0003123593590000043
Preferably, step S3 further includes the steps of:
s31, setting the length of the air duct of the air supply manifold as L from long to short1，L2，L3，L4，……Ln(ii) a The diameter of each air supply manifold at the non-necking air duct is D1Wherein, the longest air supply manifold is not provided with a necking air duct; the diameter of the necked air duct of the 2 nd to nth blowing manifolds is D2，D3，D4，……，DnAnd the sectional area of the necking part of each air duct is obtained
Figure BDA0003123593590000044
Figure BDA0003123593590000045
S32, adding and equalizing the pressure loss at the necking duct of each air supply manifold and the on-way resistance loss in the pipeline, namely Pn＝△Pxn+△PMnEqual; since the first section of the longest air supply manifold is not provided with a necking air duct, delta Px1＝0；
S33, let P1＝P2＝P3……＝Pn，
Figure BDA0003123593590000046
Figure BDA0003123593590000047
Figure BDA0003123593590000048
Figure BDA0003123593590000051
Figure BDA0003123593590000052
Figure BDA0003123593590000053
Is finally obtained when
Figure BDA0003123593590000054
Meanwhile, the pressure loss in the nth section of air supply manifold is the same as that in the 1 st section of air supply manifold;
s34, mixing L1，Ln，D1，V2Substituting into formula
Figure BDA0003123593590000055
Then the corresponding D can be calculatednThe value is obtained.
Compared with the prior art, the invention has the beneficial effects that: (1) the invention adopts a blower to blow air into the detector through the blowing manifold, determines the number of air channels according to the number of detector modules, calculates the air resistance of different air channels based on the length of the air channels to determine the ventilation sectional areas of different air channels, and ensures that the ventilation volume in a plurality of air channels is basically consistent through calculation, thereby ensuring the constant temperature of each module; (2) the invention can be suitable for detectors with different specifications and is beneficial to reducing the noise of the detectors during operation.
Drawings
FIG. 1 is a schematic structural diagram of a heat dissipation device of a CT detector assembly according to the present invention;
FIG. 2 is a cross-sectional view of a supply manifold in accordance with the present invention at a necked air duct;
FIG. 3 is a Modisco diagram.
In the figure: the device comprises a blower 1, a filter screen 2, a static pressure box 3, a blower manifold 4, a CT detector 5 and a detector module 6.
Detailed Description
In order to more clearly illustrate the embodiments of the present invention, the following description will explain the embodiments of the present invention with reference to the accompanying drawings. It is obvious that the drawings in the following description are only some examples of the invention, and that for a person skilled in the art, other drawings and embodiments can be derived from them without inventive effort.
Example 1:
the heat dissipation device of the CT detector assembly shown in fig. 1 comprises a CT detector 5, wherein a plurality of detector modules 6 are arranged in the CT detector, and the heat dissipation device further comprises a blower 1, a plenum box 3 and a blower manifold 4 with the same number as the detector modules; the air supply outlet of the air feeder is opposite to the static pressure box; the air inlet of the air supply manifold is communicated with the static pressure box; the air inlets of the air supply manifolds are opposite to the detector modules; the air supply manifolds correspond to the detector modules one to one.
Wherein the blower adopts a direct-current centrifugal fan; the static pressure box is a necessary accessory for reducing dynamic pressure, increasing static pressure, stabilizing airflow and reducing airflow vibration of the air supply system, and the static pressure box can enable the air supply effect to be more ideal. A plenum box is a device that both allows airflow to pass through and effectively prevents or attenuates the outward propagation of acoustic energy.
Furthermore, the air inlets of the air supply manifolds have the same area. The inlet areas of the air supply manifolds are ensured to be the same, so that the inlet air quantity at the inlet of the air supply manifolds is ensured to be the same.
Furthermore, a necking air duct for balancing air duct along-way air pressure loss is arranged in each air supply manifold pipeline. The cross section of the necking air channel is calculated and adjusted to balance the on-way air pressure loss of the air channel, and the air resistance in each air supply manifold is kept the same, so that the air quantity and the air speed and the air pressure passing through each detector module are ensured to be consistent.
Further, a filter screen 2 is arranged in the static pressure box. The static pressure box is internally designed with a filter screen, and the filter screen can be cleaned by opening the static pressure box.
Based on embodiment 1, the invention further provides a design method of the heat dissipation device of the CT detector assembly, which comprises the following steps:
s1, calculating the on-way air pressure loss of the air flow on each air supply manifold, and obtaining on-way resistance values in the pipelines of each air supply manifold;
s2, calculating the air pressure loss at the necking air channel in each air supply manifold to obtain the pressure loss value at the necking position in each air supply manifold;
s3, calculating the diameter of the neck air duct in each air supply manifold according to the on-way resistance value in each air supply manifold pipeline and the pressure loss value of the neck in each air supply manifold obtained in the steps S1 and S2;
and S4, finishing the design of the heat dissipation device of the CT detector assembly according to the diameter value of the neck air channel in each air supply manifold obtained in the step S3.
Further, step S1 includes the following steps:
s11, calculating the Reynolds number Re,
Figure BDA0003123593590000071
wherein rho is air density and unit KG/M2(ii) a V is wind speed, unit is M2(ii) a d is the diameter of the air supply manifold, and the unit is M; eta is the aerodynamic viscosity coefficient;
s12, looking up a Modisco diagram which is shown in figure 3, looking up a corresponding abscissa on the Modisco diagram, looking up a table of 'absolute roughness delta of the pipe wall of the pipeline', dividing the absolute roughness delta by the diameter d of the air supply manifold, and calculating delta/d, wherein the value of the delta/d corresponds to the right ordinate of the Modisco diagram and the curve of the center of the Modisco diagram area; correspondingly determining a point on the central curve of the Modi diagram area according to the Reynolds number Re of the abscissa obtained in the step S11 and the Delta/d of the ordinate on the right side, wherein the point corresponds to the on-way resistance coefficient lambda of the ordinate on the left side of the Modi diagram;
s13 according to the formula
Figure BDA0003123593590000072
Calculating on-way resistance values in each air supply manifold pipeline;
wherein λ is an on-way resistance coefficient of the air in the duct obtained in step S12, V is a wind speed, ρ is an air density, D is a diameter of the air supply manifold, and L is a length of the air supply manifold.
Further, as shown in fig. 2, step S2 further includes the following steps:
s21, because the airflow passes through the neck-in air duct in each air supply manifold, according to the Bernoulli equation:
Figure BDA0003123593590000073
wherein p is1Is the pressure of the air flow at a point A before the air flow passes through the neck-down air duct in the air supply manifold2Is the pressure intensity, V, of the air flow passing through a point B at the neck-down duct in the supply manifold1And V2Corresponding to the air flow midpoint A and BFlow velocity, γ represents gravity per unit volume of air, γ ═ ρ g, ρ is air density, g is gravitational acceleration, z is1And z2Are all constant;
s22, according to the Bernoulli equation of the step S21, obtaining the local loss of the variable diameter in the air supply manifold as follows:
Figure BDA0003123593590000081
because the air volume passing through the cross section at the point A and the point B is consistent, the following results are obtained:
V1Aa＝V2Ab
wherein A isaIs the cross-sectional area at point A, AbCross-sectional area at point B;
s23, consider AaAnd AbThe distance between the sections is short, the surface forces on the side surfaces are disregarded, and the momentum equation is then obtained as:
P1Ab-P2Ab＝ρV2Ab(V1-V2)
the momentum equation and the continuous equation are substituted to obtain the pressure loss delta P at the necking air duct of each air supply manifoldx＝P1-P2＝ρV2(V1-V2)，
Figure BDA0003123593590000082
Wherein, the longest air supply manifold is not provided with a necking air duct, so the total air pressure loss of the longest air supply manifold is P ═ delta PMI.e. by
Figure BDA0003123593590000083
Further, step S3 includes the following steps:
s31, setting the length of the air duct of the air supply manifold as L from long to short1，L2，L3，L4，……Ln(ii) a Non-necking air duct for each air supply manifoldHas a diameter of D1Wherein, the longest air supply manifold is not provided with a necking air duct; the diameter of the necked air duct of the 2 nd to nth blowing manifolds is D2，D3，D4，……，DnAnd the sectional area of the necking part of each air duct is obtained
Figure BDA0003123593590000084
Figure BDA0003123593590000085
S32, adding and equalizing the pressure loss at the necking duct of each air supply manifold and the on-way resistance loss in the pipeline, namely Pn＝△Pxn+△PMnEqual; since the first section of the longest air supply manifold is not provided with a necking air duct, delta Px1＝0；
S33, let P1＝P2＝P3……＝Pn，
Figure BDA0003123593590000086
Figure BDA0003123593590000087
Figure BDA0003123593590000091
Figure BDA0003123593590000092
Figure BDA0003123593590000093
Figure BDA0003123593590000094
Is finally obtained when
Figure BDA0003123593590000095
Meanwhile, the pressure loss in the nth section of air supply manifold is the same as that in the 1 st section of air supply manifold;
s34, mixing L1，Ln，D1，V2Substituting into formula
Figure BDA0003123593590000096
Then the corresponding D can be calculatednThe value is obtained.
Said DnThe value is the diameter value of the neck air duct in each air supply manifold. According to DnAnd (4) data is obtained, and the design and the manufacture of the heat dissipation device of the CT detector assembly are completed.
The invention comprises a blower, a filter screen, a static pressure box and a plurality of blower manifolds. The areas of the inlets of the manifolds are ensured to be the same, so that the inlet air quantity at the inlet of the manifold is ensured to be the same, and the shorter the manifold is, the smaller the air pressure loss in the pipeline is, the larger the air pressure loss of the longer manifold is, and if the air enters a section of reduced section (as shown in figure 2), certain pressure loss can be generated. The invention adds a necking air duct on the design of each manifold pipeline, balances the on-way air pressure loss of the air duct by calculating and adjusting the sectional area of the necking air duct, keeps the same wind resistance in each manifold, and ensures that the wind volume and the wind speed and the wind pressure of each air inlet module are consistent.
The invention adopts a blower to blow air into the detector through the blowing manifold, determines the number of air channels according to the number of detector modules, calculates the air resistance of different air channels based on the length of the air channels to determine the ventilation sectional areas of different air channels, and ensures that the ventilation volume in a plurality of air channels is basically consistent through calculation, thereby ensuring the constant temperature of each module; the invention can be suitable for detectors with different specifications and is beneficial to reducing the noise of the detectors during operation.
The foregoing has outlined rather broadly the preferred embodiments and principles of the present invention and it will be appreciated that those skilled in the art may devise variations of the present invention that are within the spirit and scope of the appended claims.

Claims (8)

  1. The heat dissipation device for the CT detector assembly comprises a CT detector, wherein a plurality of detector modules are arranged in the CT detector, and the heat dissipation device is characterized by further comprising an air feeder, a static pressure box and air feeding manifolds, wherein the number of the air feeding manifolds is the same as that of the detector modules; the air supply outlet of the air feeder is opposite to the static pressure box; the air inlet of the air supply manifold is communicated with the static pressure box; the air inlets of the air supply manifolds are opposite to the detector modules; the air supply manifolds correspond to the detector modules one to one.
  2. 2. The CT detector assembly heat sink of claim 1, wherein the air inlets of the air supply manifolds have the same area.
  3. 3. The heat sink assembly as claimed in claim 2, wherein each of the air supply manifolds has a necked-down duct disposed therein for balancing along-the-way air pressure loss.
  4. 4. The heat sink for a CT detector assembly according to any of claims 1-3, wherein a filter screen is disposed in the static pressure chamber.
  5. 5. The method for designing the heat sink of the CT detector assembly according to claim 3, comprising the following steps:
    s1, calculating the on-way air pressure loss of the air flow on each air supply manifold, and obtaining on-way resistance values in the pipelines of each air supply manifold;
    s2, calculating the air pressure loss at the necking air channel in each air supply manifold to obtain the pressure loss value at the necking position in each air supply manifold;
    s3, calculating the diameter of the neck air duct in each air supply manifold according to the on-way resistance value in each air supply manifold pipeline and the pressure loss value of the neck in each air supply manifold obtained in the steps S1 and S2;
    and S4, finishing the design of the heat dissipation device of the CT detector assembly according to the diameter value of the neck air channel in each air supply manifold obtained in the step S3.
  6. 6. The method for designing a heat sink for a CT detector assembly as claimed in claim 5, wherein the step S1 further comprises the steps of:
    s11, calculating the Reynolds number Re,
    Figure FDA0003123593580000011
    wherein rho is air density and unit KG/M2(ii) a V is wind speed, unit is M2(ii) a d is the diameter of the air supply manifold, and the unit is M; eta is the aerodynamic viscosity coefficient;
    s12, looking up the Modisco diagram, looking up the corresponding abscissa on the Modisco diagram, looking up the table 'absolute roughness Delta of the pipe wall of the pipeline', dividing the absolute roughness Delta by the diameter d of the air supply manifold, and calculating Delta/d, wherein the value of Delta/d corresponds to the right ordinate of the Modisco diagram and the curve of the center of the Modisco diagram area; correspondingly determining a point on the central curve of the Modi diagram area according to the Reynolds number Re of the abscissa obtained in the step S11 and the Delta/d of the ordinate on the right side, wherein the point corresponds to the on-way resistance coefficient lambda of the ordinate on the left side of the Modi diagram;
    s13 according to the formula
    Figure FDA0003123593580000021
    Calculating on-way resistance values in each air supply manifold pipeline;
    wherein λ is an on-way resistance coefficient of the air in the duct obtained in step S12, V is a wind speed, ρ is an air density, D is a diameter of the air supply manifold, and L is a length of the air supply manifold.
  7. 7. The method for designing a heat sink for a CT detector assembly as claimed in claim 6, wherein the step S2 further comprises the steps of:
    s21, because the airflow passes through the neck-in air duct in each air supply manifold, according to the Bernoulli equation:
    Figure FDA0003123593580000022
    wherein p is1Is the pressure of the air flow at a point A before the air flow passes through the neck-down air duct in the air supply manifold2Is the pressure intensity, V, of the air flow passing through a point B at the neck-down duct in the supply manifold1And V2Flow velocities at the air flow midpoint a and point B, respectively, γ represents the gravity per unit volume of air, γ ═ ρ g, ρ is the air density, g is the acceleration of gravity, z is the acceleration of gravity, and1and z2Are all constant;
    s22, according to the Bernoulli equation of the step S21, obtaining the local loss of the variable diameter in the air supply manifold as follows:
    Figure FDA0003123593580000023
    because the air volume passing through the cross section at the point A and the point B is consistent, the following results are obtained:
    V1Aa＝V2Ab
    wherein A isaIs the cross-sectional area at point A, AbCross-sectional area at point B;
    s23, consider AaAnd AbThe distance between the sections is short, the surface forces on the side surfaces are disregarded, and the momentum equation is then obtained as:
    P1Ab-P2Ab＝ρV2Ab(V1-V2)
    the momentum equation and the continuous equation are substituted to obtain the pressure loss delta P at the necking air duct of each air supply manifoldx＝P1-P2＝ρV2(V1-V2)，
    Figure FDA0003123593580000031
    Wherein, the longest air supply manifold is not provided with a necking air duct, so the total air pressure loss of the longest air supply manifold is P ═ delta PMI.e. by
    Figure FDA0003123593580000032
  8. 8. The method for designing a heat sink for a CT detector assembly as claimed in claim 7, wherein the step S3 further comprises the steps of:
    s31, setting the length of the air duct of the air supply manifold as L from long to short1，L2，L3，L4，……Ln(ii) a The diameter of each air supply manifold at the non-necking air duct is D1Wherein, the longest air supply manifold is not provided with a necking air duct; the diameter of the necked air duct of the 2 nd to nth blowing manifolds is D2，D3，D4，……，DnAnd the sectional area of the necking part of each air duct is obtained
    Figure FDA0003123593580000033
    Figure FDA0003123593580000034
    S32, adding and equalizing the pressure loss at the necking duct of each air supply manifold and the on-way resistance loss in the pipeline, namely Pn＝△Pxn+△PMnEqual; since the first section of the longest air supply manifold is not provided with a necking air duct, delta Px1＝0；
    S33, let P1＝P2＝P3……＝Pn，
    Figure FDA0003123593580000035
    Figure FDA0003123593580000036
    Figure FDA0003123593580000037
    Figure FDA0003123593580000038
    Figure FDA0003123593580000039
    Figure FDA00031235935800000310
    Is finally obtained when
    Figure FDA0003123593580000041
    Meanwhile, the pressure loss in the nth section of air supply manifold is the same as that in the 1 st section of air supply manifold;
    s34, mixing L1，Ln，D1，V2Substituting into formula
    Figure FDA0003123593580000042
    Then the corresponding D can be calculatednThe value is obtained.
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