CN110516834A - A kind of optimization method of Tube Sizing - Google Patents
A kind of optimization method of Tube Sizing Download PDFInfo
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- 238000004513 sizing Methods 0.000 title claims abstract description 21
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- 238000005520 cutting process Methods 0.000 claims description 25
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Abstract
A kind of optimization method of Tube Sizing provided by the invention, it is obtaining after the length range with tubing and Target pipe, the Target pipe with pipe length is waited for integral multiple, take corresponding number and length wait match tubing dispensing, size is greater than wait match tubing length limit, and it does not wait in integral multiple with the Target pipe in tubing length range, take corresponding number and length wait match tubing dispensing, and a remaining segment length is less than the Target pipe wait match tubing lower limit, the tubing of dispensing Target pipe is whole Zhi Guancai in such marker method, it reduces the tubing number of splicing and number is cut to tubing, reduce loss, improve the utilization rate of tubing；For all Target pipe sort merges being less than wait match pipe length lower limit, integral multiple is reached to overall length after combination and waits for the Target pipe with pipe length, it takes by corresponding number and length to cut dispensing with tubing, reduce useless tubing clout, the utilization efficiency for improving tubing optimizes Tube Sizing mode.
Description
Technical field
The present invention relates to pipeline processing technical fields, and in particular to a kind of optimization method of Tube Sizing.
Background technique
In Industrial Construction Project, pipeline construction program is complicated and larger workload, conduit assembly substantial amounts are having
When pipeline construction condition, the short time limit of Pipe installing is left for, phenomenon of trying to meet the deadline for the project often occurs in task weight, in this way can be to a certain degree
On influence Pipe installing quality.This just needs to carry out the prefabricated processing of batch production for pipeline, i.e. the various structures of pipeline projects are matched
Part is just previously fabricated good by each professional factory before construction, then is transported to construction site and assembled.
As a part of the prefabricated processing of pipe factoryization, discharge is designed usually by designer according to design drawing upper tube
Segment length and existing pipe length carry out tentative calculation, and artificial calculation method generally rule of thumb carries out, and efficiency and accuracy rate are relatively not
It is high.Furthermore, on the one hand, in the design drawings such as piping diagram, each pipeline group section design length differs greatly, and tubing can not directly make
With needing to cut tubing and connected；On the other hand, there are errors for tubing arrival length, can not carry out with regard to single length
Calculation, each of which increases discharge difficulty, the extra short material of more piece occur after making discharge blanking, are not used to other projects, cause
Waste of material.
Summary of the invention
Therefore, the technical problem to be solved in the present invention is that overcoming in discharge design, low for tubing utilization rate is lacked
It falls into, to provide a kind of optimization method of Tube Sizing.
The present invention provides a kind of optimization method of Tube Sizing, comprising:
Obtain the numberical range [a, b] to the length xi with tubing；
Obtain the size of the Target pipe in piping diagram, wherein the size of Target pipe is yi；
When the size yi range of the Target pipe is at N [a, b], wherein N is integer, selects N root overall size for yi's
It is described splice simultaneously dispensing wait match tubing；
When the size yi range of the Target pipe is greater than b and not at N [a, b], wherein N is integer, if selection dispensing
To with tubing and the remaining Target pipe of the segment length less than a described in the Heavenly Stems and Earthly Branches；
Remaining length is less than the institute of a after with tubing described in the Target pipe and dispensing of the size yi range less than a
It states Target pipe and carries out sort merge dispensing, the sort merge dispensing includes: that each Target pipe is classified, to mutual group
Total length reaches the Target pipe of N [a, b] after conjunction, takes the dispensing after cutting with tubing by corresponding number and length.
The step of obtaining numberical range [a, the b] to the length xi with tubing includes: that acquisition is described to being averaged with tubing
Length A, calculating is described wait match deviation ratio Φ of the tubing relative to average length,
Φ=((max (xi)-A)/A) * 100%；A=A (1- Φ), b=A (1+ Φ).
Sort merge dispensing includes:
S1, remaining length is less than the mesh of a after with tubing described in Target pipe and dispensing of the size yi range less than a
Mark pipeline is divided into three classes according to length:
First kind Target pipe having a size of mi, mi ∈ (0,0.5A (1- Φ)]；
Second class target line size be ni, ni ∈ (0.5A (1- Φ), 0.5A (1+ Φ)]；
Tertiary target line size is pi, pi ∈ (0.5A (1+ Φ), A (1- Φ))；
S2, first kind Target pipe match respectively with tertiary target pipeline, choose total length in [A (1- Φ), A (1+
The Φ)] matching way in range takes the dispensing after cutting with tubing by corresponding number and length；
S3, the second class Target pipe match two-by-two, take the dispensing after cutting with tubing by corresponding number and length, if
Second class Target pipe interior conduit quantity is even number, then there is no the remaining Target pipes to dispensing, if the second class Target pipe
Interior conduit quantity is odd number, then dispensing after a remaining Target pipe is to be sorted；
S4 classifies described in dispensing according to the remaining possibility of all kinds of Target pipes wait match tubing.
Step S4 includes:
A, the only described first kind Target pipe is remaining, then:
If ∑ mi < A (1- Φ), appoint take in [A (1- Φ), A (1+ Φ)] range it is described to tubing, according to
Each Target pipe length carries out cutting dispensing；
If in ∑ mi ∈ N [A (1- Φ), A (1+ Φ)] range, N round numbers then chooses corresponding N branch and is added length equal to ∑
Mi's is described to carry out cutting dispensing according to each Target pipe length with tubing；
If ∑ mi > A (1+ Φ) andIn range, N round numbers, then:
K=3 takes k mi to be added, and judges whether in [A (1- Φ), A (1+ Φ)] range, if so, taking k mi
The described of total length is cut wait match tubing according to each Target pipe length；If it is not, then k+1, returns to judgment step, mistake
Until the remaining first kind Target pipe quantity of Cheng Zhizhi is less than k value；
After above-mentioned steps, length summation is not greater than not then by the not matched residue first kind Target pipe if it exists
The residue first kind Target pipe total length and length difference matched are described to be spliced with tubing less than A (1- Φ), after
It is cut according to each Target pipe length；
B, the only described second class Target pipe is remaining, then:
When only the second class Target pipe exist it is remaining, then appoint take in [A (1- Φ), A (1+ Φ)] range it is described to
It is cut with tubing according to the Target pipe length；
C, the only described tertiary target pipeline is remaining, and i is this class target number of tubes, then:
If i=1, appoint described in taking in [A (1- Φ), A (1+ Φ)] range wait match tubing according to the tertiary target pipe
Road length carries out cutting dispensing；
If i >=2, from the third classification for the different number combination for meeting ∑ pi ∈ N [A (1- Φ), A (1+ Φ)]
It marks in pipeline, chooses the remaining least assembled scheme of third class pipe number, and choose corresponding number and be added length and be equal to
∑ pi's is described to carry out cutting dispensing according to each tertiary target duct length with tubing；
Length summation is then greater than described in not matched residue by the not matched residue tertiary target pipeline if it exists
Tertiary target pipeline total length and length difference are less than to be spliced with tubing described in more of A (1- Φ), and according to each institute
It states tertiary target duct length and cuts dispensing；
D, the only described first kind Target pipe and the second class Target pipe are remaining, then:
The residue for combining the remaining second class Target pipe with the different number first kind Target pipe progress
Match, whether pipeline total length is in N [A (1- Φ), A (1+ Φ)] range after judging matching；
If selection has the combination of max (mi), identical with pipeline total length after the matching with N number of total length
It is described wait match tubing, cut dispensing according to all kinds of Target pipe length correspondences after splicing, remaining tubing is held according to step a
Row；
If not existing, not matched residue the second class Target pipe with 0.5A (1- Φ) is that boundary is divided into two sections, and
Two segment length (0,0.5A (1- Φ)] in, and according to step a execute；
There is residue in e, the only described second class Target pipe and the tertiary target pipeline, then:
After the remaining second class Target pipe of judgement is combined with each remaining described tertiary target pipeline respectively
Whether length is in [A (1- Φ), A (1+ Φ)] range, if taking the combination with max (pi), and take corresponding length
Described to cut dispensing wait match tubing, the remaining tertiary target pipeline is executed according to step c；If not existing, remaining institute is judged
State the total length after the residue tertiary target pipeline that the second class Target pipe is combined with different number respectively is matched
When whether in the N [A (1- Φ), A (1+ Φ)]；
If, the combination with max (pi) is taken, and corresponding number and the described of length is taken to cut dispensing wait match tubing,
The residue tertiary target pipeline stayed is executed according to step c；
If not existing, when being 1 with the remaining matched residue tertiary target number of tubes of second class Target pipe,
Then cut dispensing two it is spliced described to which with tubing, remaining clout deficiency list Zhi Suoshu waits matching tubing；When with described in residue
The matched residue tertiary target number of tubes of second class Target pipe is more than or equal to 2, then length summation is greater than residue
The second class Target pipe is with the remaining tertiary target pipeline overall length and length difference is described wait match less than A (1- Φ)
Tubing is spliced, and is cut according to each Target pipe length, and remaining clout deficiency list Zhi Suoshu is waited for tubing；
There is residue in f, the only described first kind Target pipe and the tertiary target pipeline, then:
The residue first kind Target pipe for taking different number to combine combine respectively with different number remaining described the
The matching of tertiary target pipeline, the total length after matching is within N [A (1- Φ), A (1+ Φ)]；Take the remaining Target pipe number
Least combination is measured, and distributes the described to cut dispensing according to the Target pipe length with tubing of respective numbers；
Not matched remaining first kind Target pipe if it exists, then remaining first kind Target pipe is executed by step a, if
In the presence of not matched remaining tertiary target pipeline, then remaining tertiary target pipeline is executed by step b；
G, the first kind Target pipe and the second class Target pipe and the tertiary target pipeline all exist
Residue, then:
The remaining second class Target pipe is divided into two sections with 0.5A (1- Φ) for boundary, and two segment length are in mi long
It spends in range, is handled as the first kind Target pipe, executed according to step f.
Φ≦1/3。
It is welding to the connection type with tubing, the consumption wait match tubing is included in described to in pipe length.
Technical solution of the present invention has the advantages that
1. a kind of optimization method of Tube Sizing provided by the invention, wherein obtaining to tubing and Target pipe
After length range, wait for the Target pipe with pipe length to integral multiple, take corresponding number and length to tubing dispensing,
In addition, be greater than size wait match tubing length limit, and do not wait in integral multiple with the Target pipe in tubing length range, takes pair
Answer quantity and length to tubing dispensing, and a remaining segment length is less than the Target pipe wait match tubing lower limit, such row
The tubing of dispensing Target pipe is whole Zhi Guancai in material mode, reduces the tubing number of splicing and cuts number to tubing,
Splicing and cutting loss are reduced, the utilization rate of tubing is improved；In addition, for all mesh being less than wait match pipe length lower limit
Pipeline sort merge is marked, integral multiple is reached to overall length after combination and waits for the Target pipe with pipe length, by corresponding number and length
Take to cut dispensing with tubing, such marker method, after combining the Target pipe of insufficient whole Zhi Guancai long the whole branch of dispensing to
With tubing, reduces useless tubing clout, improve the utilization efficiency of tubing, optimize Tube Sizing mode, save people
The time of work tentative calculation.
2. a kind of optimization method of Tube Sizing provided by the invention, wherein sort merge dispensing includes: by Target pipe
According to 0.5 times to tubing lower limit and 0.5 times to be divided into three classes with the tubing upper limit for boundary, and by the first kind and tertiary target pipe
Whether road is according to total length to which with being matched in tubing length range, the second class Target pipe matches two-by-two, such row
In material mode, due to the second class target duct length (0.5A (1- Φ), 0.5A (1+ Φ)] range, two-by-two match after it is total
Length by whole branch to cut dispensing with tubing to be conducive to fast selecting dispensing target, improve in tubing length range
Dispensing efficiency.
3. a kind of optimization method of Tube Sizing provided by the invention, wherein classification dispensing wait for tubing step be according to
All residues of all kinds of Target pipes can be carried out classification, and Target pipe of all categories is not sharp by after with tubing dispensing
Tubing number is few, improves the utilization efficiency of tubing, optimizes Tube Sizing mode.
Detailed description of the invention
It, below will be to specific in order to illustrate more clearly of the specific embodiment of the invention or technical solution in the prior art
Embodiment or attached drawing needed to be used in the description of the prior art be briefly described, it should be apparent that, it is described below
Attached drawing is some embodiments of the present invention, for those of ordinary skill in the art, before not making the creative labor
It puts, is also possible to obtain other drawings based on these drawings.
Fig. 1 is the schematic diagram of the optimization method of Tube Sizing in embodiment of the present invention；
Fig. 2 is the schematic diagram of sort merge dispensing in the optimization method of Tube Sizing in embodiment of the present invention；
Specific embodiment
Technical solution of the present invention is clearly and completely described below in conjunction with attached drawing, it is clear that described implementation
Example is a part of the embodiment of the present invention, instead of all the embodiments.Based on the embodiments of the present invention, ordinary skill
Personnel's every other embodiment obtained without making creative work, shall fall within the protection scope of the present invention.
In the description of the present invention, it should be noted that term " center ", "upper", "lower", "left", "right", "vertical",
The orientation or positional relationship of the instructions such as "horizontal", "inner", "outside" be based on the orientation or positional relationship shown in the drawings, merely to
Convenient for description the present invention and simplify description, rather than the device or element of indication or suggestion meaning must have a particular orientation,
It is constructed and operated in a specific orientation, therefore is not considered as limiting the invention.In addition, term " first ", " second ",
" third " is used for descriptive purposes only and cannot be understood as indicating or suggesting relative importance.
In the description of the present invention, it should be noted that unless otherwise clearly defined and limited, term " installation ", " phase
Even ", " connection " shall be understood in a broad sense, for example, it may be being fixedly connected, may be a detachable connection, or be integrally connected；It can
To be mechanical connection, it is also possible to be electrically connected；It can be directly connected, can also can be indirectly connected through an intermediary
Connection inside two elements.For the ordinary skill in the art, above-mentioned term can be understood at this with concrete condition
Concrete meaning in invention.
As long as in addition, the non-structure each other of technical characteristic involved in invention described below different embodiments
It can be combined with each other at conflict.
It as shown in Figure 1, is A (1- Φ) to the deviation range lower limit with tubing, wait be piped to be A with tubing average length
The deviation range lower limit of material is A (1+ Φ), i.e. a=A (1- Φ), b=A (1+ Φ), wait match the numberical range of pipe length xi
[a, b] is [A (1- Φ), A (1+ Φ)]；
The a length of integral multiple of Target pipe is when matching tubing deviation range in piping diagram, it may be assumed that
[1*A (1- Φ), 1*A (1+ Φ)], [2*A (1- Φ), 2*A (1+ Φ)], [3*A (1- Φ), 3*A (1
+ Φ)] ... [N*A (1- Φ), N*A (1+ Φ)], desirable corresponding 1,2,3 ... quantity are matched after welding wait match tubing
It gives.
N is, as N >=1/ (2 Φ) -0.5, to be somebody's turn to do to corresponding with N+1 with the corresponding target tube road length of tubing number wait match tubing number
Target pipe length there is lap, i.e. (N+1) * A* (1- Φ)≤N*A* (1+ Φ), so, N >=1/ (2 Φ)-
0.5, NminFor the minimum value of N, then when Target pipe length is greater than NminWhen the lower limit length of corresponding target tube road length, there is correspondence
Integral multiple after with tubing welded after dispensing.
To in liberal supply with tubing.
By above-mentioned condition it is found that if being then 9m to the deviation range lower limit with tubing for Φ=0.1 with A=10m, to
The deviation range upper limit with tubing is 11m；As a length of 9m-11m of Target pipe, 18m-22m, 27m-33m ... in piping diagram
When then can use corresponding 1,2,3 ... quantity wait match tubing, dispensing uses after being welded.When N >=1/ (2 Φ) -0.5, i.e. N
>=4.5, N are integer, so Nmin=5, the corresponding a length of 4.5m-5.5m of Target pipe, work as N=6, then correspond to target tube road length
For 5.4m-6.6m, 5.5 > 5.4, then, 4.5m-6.6m have corresponding integral multiple to match after welding with tubing
It gives.N=6 known to similarly, the case where 7,8 ...；So when Target pipe length in 4.5m or more, then have integral multiple wait match
Tubing can be used after welding with dispensing.
When Target pipe is long be greater than A (1+ Φ), but length not in integral multiple to in tubing deviation range, i.e. target tube
Road length is not in N [A (1- Φ), A (1+ Φ)] range, N round numbers；Then need dispensing several to one section of tubing and residue
Less than to the Target pipe length with deviation range lower limit described in tubing, i.e. Target pipe length is greater than NA (1+ Φ), N maximum value
Wait for that, with tubing quantity, the remaining length of Target pipe waits mending for dispensing, length to be mended is less than A (1- Φ), subsequent supplement distribution
Wait match tubing and the integral multiple dispensing after with tubing welding.
Equally with A=10m, for Φ=0.1, if Target pipe a length of 13m or 24m etc., it is greater than 11m, and not in 18m-
In the ranges such as 22m, 27m-33m ..., then belongs to the Target pipe of (11,18) m length range for 13m Target pipe etc., match
It waits mending wait match tubing, the length lacked to one within the scope of 9m-11m；Similarly, 24m Target pipe etc. is belonged to (22,
27) m length range Target pipe, then dispensing two be added ranges in 18m-22m wait match tubing, residue length waits mending, institute
Surplus length is less than 9m.
In the present embodiment, the whole branch of dispensing, can remaining mesh in this step according to needed for subsequent step wait match pipe length
Mark pipeline length is adjusted.
When target tube road length is less than A (1- Φ), then by the residue length for being similarly less than A (1- Φ) to be mended in above-mentioned steps
Degree makees same treatment；
The tubing of dispensing Target pipe is whole Zhi Guancai in such marker method, reduces the tubing number of splicing and right
Tubing cuts number, reduces splicing and cutting loss, improves the utilization rate of tubing；In addition, being less than for all wait match
The Target pipe sort merge of pipe length lower limit reaches integral multiple to overall length after combination and waits for the Target pipe with pipe length,
It takes by corresponding number and length to cut dispensing, such marker method, by the Target pipe of insufficient whole Zhi Guancai long with tubing
The whole branch of dispensing reduces useless tubing clout, improves the utilization efficiency of tubing wait match tubing after combination, optimizes tubing row
Material mode saves the time of artificial tentative calculation.
Such as Fig. 2, all Target pipes less than A (1- Φ) are divided into three classes:
First kind mi ∈ (0,0.5A (1- Φ)], the second class ni ∈ (0.5A (1- Φ), 0.5A (1+ Φ)],
Third class pi ∈ (0.5A (1+ Φ), A (1- Φ)).
Firstly, Target pipe is matched from the Target pipe in the first kind is one-to-one from long to short in third class, choose
Target pipe total length is in [A (1- Φ), A (1+ Φ)] range, if preferentially choosing max (pi) there are many matching way
A kind of matching way preferentially chooses the matching way of min (mi) under the conditions of tertiary target pipeline length is identical.Take which energy
Make the first kind and third class in the case where can satisfy matching range, due to being mode that length Target pipe is mutually matched,
Will not be remaining, the whole section of utilization rate wait match tubing is improved, reduces to connect number with tubing, reduces to disappear with tubing
Consumption.
After the completion of such matching, by Target pipe of the total length in [A (1- Φ), A (1+ Φ)] length range to
It is long with tubing, take a dispensing after cutting with tubing by corresponding length.If having the remaining first kind or tertiary target pipeline, to
Dispensing after classification.
Secondly, the second class Target pipe matches two-by-two, due to the second class target duct length all [0.5*A (1- Φ),
0.5*A (1+ Φ)] in, then the second class Target pipe after matching two-by-two, total length is all in [A (1- Φ), A (1+ Φ)] length
It, can be by corresponding length to be cut according to matched two Target pipes length with tubing and dispensing in range.If the second class
Target pipe number is even number in Target pipe, then the Target pipe that there is no remaining to dispensing, if odd number, then a remaining mesh
Mark pipeline rear dispensing to be sorted.
Equally with A=10m, for Φ=0.1, first kind Target pipe length range: (0,4.5] m, the second class target tube
Road length range: (4.5,5.5] m, tertiary target duct length range: (5.5,9) m；
If first kind Target pipe length is respectively as follows: 2m, 3m, 4m；Second class target duct length be respectively as follows: 4.8m, 5m,
5.4m；Tertiary target duct length is respectively as follows: 6m, 7m, 8m；
First consider longest 8m long Target pipe in tertiary target pipeline, matching object meet after matching length [9,
11] in m, so 2m, 3m Target pipe can all meet condition, then matched with shortest 2m Target pipe, take 10m long to
With tubing, be cut into 2m long and 8m long carries out corresponding dispensing wait match tubing；The mesh of 7m long in tertiary target pipeline is matched again
Mark pipeline, the first kind Target pipe of 3m and 4m long can be matched, matched with shortest 3m Target pipe, take 10m long to
With tubing, be cut into 3m and 7m long to carry out corresponding dispensing with tubing, similarly known to 6m and 4m Target pipe matching way and
As a result.There is no the remaining first kind or tertiary target pipelines in this example.
Second class Target pipe matches two-by-two, and length may after matching are as follows: 9.8m, 10.2m, 10.4m are in [9,11] m model
In enclosing, a kind of matching way is randomly selected, such as: 4.8m match with 5m long Target pipe, and correspondence cuts dispensing to wait matching tubing long,
Leave a 5.4m Target pipe rear dispensing to be sorted.If Target pipe number is even number in the second class Target pipe, such as only two
A: 4.8m and 5m then will not leave behind to dispensing Target pipe.
In such marker method, due to the second class target duct length (0.5A (1- Φ), 0.5A (1+ Φ)] model
It encloses, the total length after matching two-by-two by whole branch to cut dispensing with tubing to be conducive to quick in tubing length range
Dispensing target is chosen, dispensing efficiency is improved.
As disposable embodiment, the second class Target pipe matches selected matching way two-by-two can be after
Remaining Target pipe length is adjusted in this step needed for continuous step.
The residue of different target pipeline is possible: first kind Target pipe, the second class Target pipe, tertiary target pipeline is all
It is likely to occur residue, so working as:
A, only first kind Target pipe are remaining, then:
If ∑ mi < A (1- Φ), appoints and take wait match tubing in [A (1- Φ), A (1+ Φ)] range, according to each mesh
Mark duct length carries out cutting dispensing；
If in ∑ mi ∈ N [A (1- Φ), A (1+ Φ)] range, N round numbers then chooses corresponding N branch and is added length equal to ∑
Mi's carries out cutting dispensing wait match tubing according to each Target pipe length；
If ∑ mi > A (1+ Φ) andIn range, N round numbers, then:
K=3 takes k mi to be added, and judges whether in [A (1- Φ), A (1+ Φ)] range, if so, taking k mi
Total length is cut wait match tubing according to each Target pipe length；If it is not, then k+1, returns to judgment step, process is until surplus
Until remaining first kind Target pipe quantity is less than k value；
After above-mentioned steps, length summation, then be greater than not matched by not matched remaining first kind Target pipe if it exists
Remaining first kind Target pipe total length and length difference less than A (1- Φ) to being welded with tubing, after according to each target tube
Road length cuts dispensing；
Equally with A=10m, for Φ=0.1, if remaining first kind Target pipe is 2m, 3m, 3m, 9m is less than after addition,
It is rounded minimum value 9m of the section wait match tubing, cuts dispensing according to each Target pipe of the remaining first kind, leaves 1m long to take with tubing
To clout be made minimum with tubing minimum value, in the useless situation of clout, material is more saved, is improved benefit.
It is 20m after addition, in [18,22] m range if first kind residue Target pipe is the Target pipe of 10 sections of 2m long
It is interior, then 2 are taken wait match tubing, and total length 20m, according to target pipeline length cuts dispensing.
It is 16m after addition, not in [9N, 11N] m range if first kind residue Target pipe is 8 sections of 2m long Target pipes
Interior, N is integer, then 3 Target pipes is taken to be added, and whole matching way total lengths are both less than 9m, then is added Target pipe increase
1, take 4 Target pipes to be added, whole matching way total lengths are less than 9m, until 5 Target pipes is taken to add up to 10m, [9,
11] within the scope of m, remaining Target pipe, which is added, is less than 9m, then 9m is taken to wait for cutting dispensing according to remaining Target pipe, institute with tubing
Remaining material deficiency is singly propped up wait match tubing.
B, only the second class Target pipe are remaining, then:
When only the second class Target pipe presence residue, then appoints and take in [A (1- Φ), A (1+ Φ)] range to be pressed with tubing
It is cut according to Target pipe length；
Equally with A=10m, for Φ=0.1, if the second a length of 5m of class Target pipe of residue, then 9m is taken to wait for cutting out with tubing
5m, the dispensing Target pipe are cut out, remaining clout is 4m, less than one to long with tubing.
C, only tertiary target pipeline are remaining, and i is this class target number of tubes, then
If i=1, appoints and take in [A (1- Φ), A (1+ Φ)] range to be cut out with tubing according to Target pipe length
It cuts；
If i >=2, from the tertiary target pipe for the different number combination for meeting ∑ pi ∈ N [A (1- Φ), A (1+ Φ)]
In road, the least assembled scheme of remaining Target pipe number is chosen, and chooses corresponding N branch and is added length equal to ∑ pi wait match tubing
It is cut according to each Target pipe length；
It is total to be then greater than not matched remaining tertiary target pipeline by not matched remaining third class if it exists for length summation
Length and length difference less than A (1- Φ) to being welded with tubing, after cut according to each Target pipe length；
Equally with A=10m, for Φ=0.1, if remaining tertiary target pipeline is one section, long 8m, then dispensing 9m long to
With tubing, remaining clout is that 1m deficiency is singly propped up to long with tubing.
It is all 6m, overall length then takes within the scope of [27,33] m without remaining target if remaining tertiary target pipeline is 5 sections
The 5*6 of pipeline is combined, and takes three overall lengths in 30m to carry out cutting dispensing with tubing.
Existing remaining tertiary target pipeline long respectively 8m, 8m, 8m are set out, then total length and different number pattern length
Not in N [9,11] m length range, N is integer, and reselection is greater than 3 of Target pipe overall length 24m to long minimum with tubing
Value 27m carries out cutting dispensing, and remaining clout 3m deficiency is singly propped up wait match tubing
D, the only first kind and the second class Target pipe are remaining, then:
The remaining first kind Target pipe that the second class Target pipe of residue is combined with different number is matched, judgement
With rear total length whether at N [A (1- Φ), A (1+ Φ)]；
If selection has the combination of max (mi), identical with Target pipe total length wait be piped with N number of total length
Material cuts dispensing according to Target pipe length is corresponding after welding, and remaining tubing is executed according to step a；
If not existing, will not matched remaining second class Target pipe with 0.5A (1- Φ) be boundary be divided into two sections, and two sections
Length (0,0.5A (1- Φ)] in, and according to step a execute；
Equally with A=10m, for Φ=0.1, if remaining first kind Target pipe is 1m, 2m, 3m, 4m, the second class target
Pipeline is remaining as 5m, and there are combination of the overall length within the scope of [9,11] m, selects the second class Target pipe 5m and remaining first classification
Pipeline 4m matching combination is marked, 9m is chosen and waits for carrying out cutting dispensing with tubing, remaining first kind Target pipe is put in step a and holds
Row；
If remaining first kind Target pipe is 3.5m, 3.5m, the second class Target pipe remaining as 5m, total length not N [9,
11] in range, then the second class Target pipe is divided into 4.5m and two sections of 0.5m by selection, by all remaining Target pipes according to step
A is executed.
E, only the second class and tertiary target pipeline are remaining, then
Whether judge the length after remaining second class Target pipe is combined with each residue tertiary target pipeline respectively
In [A (1- Φ), A (1+ Φ)] range, if, take the combination with max (pi), and take corresponding length wait match tubing
Dispensing is cut, remaining tertiary target pipeline is executed according to step c；If not existing, remaining second class Target pipe difference is judged
The remaining tertiary target pipeline combined with different number matched after total length when whether in N [A (1- Φ), A (1+
In Φ)]；
If, take the combination with max (pi), and take corresponding number and length to cut dispensing with tubing, stayed
Remaining tertiary target pipeline executed according to step c；
If not existing, when being 1 with the remaining matched remaining tertiary target number of tubes of second class Target pipe, then cuts and match
To, wait match tubing, remaining clout deficiency is singly propped up wait match tubing after two welding；When matched surplus with remaining second class Target pipe
Tertiary target number of tubes of remaininging is more than or equal to 2, then length summation is greater than remaining second class Target pipe and remaining third class
Target pipe overall length and length difference less than A (1- Φ) to being welded with tubing, after cut according to each Target pipe length,
Remaining clout deficiency is singly propped up wait match tubing；
Equally with A=10m, for Φ=0.1, if remaining second class Target pipe is 5m, remaining tertiary target pipeline
For 5.7m, 6m, 7m, 8m, then 5m and 5.7m, 5m and 6m, combine total length within the scope of [9,11] m, selection is surplus with longest
Remaining the combination of tertiary target pipeline, i.e. the second class Target pipe 5m of residue and remaining tertiary target pipeline 6m, 11m is taken to wait matching
Tubing cuts dispensing, and remaining tertiary target pipeline is put in step c execution；
If remaining second class Target pipe is 5m, remaining tertiary target pipeline is 6.5m, 7m, 8m, remaining second classification
Pipeline and each remaining tertiary target pipeline pattern length are marked not within the scope of [9,11] m, then chooses remaining second classification
The remaining tertiary target pipeline pattern length that mark pipeline is combined with different number takes with the remaining tertiary target pipeline of longest
Combination, then choose the second class Target pipe 5m of residue and remaining tertiary target pipeline 7m and 8m, remaining tertiary target pipe
Road is executed according to step c；
If remaining second class Target pipe is 5m, remaining tertiary target pipeline is 8m, then appoints and two [9,11] m is taken to wait matching
After tubing welding, each Target pipe of dispensing is cut；
If remaining second class Target pipe is 5.2m, remaining tertiary target pipeline is 8.5m, 8.7m then remaining target tube
Road total length is 22.4m, and in [11 (N-1), 9N] range, N=3 is greater than two wait match tubing length limit, less than three
Branch wait match pipe length lower limit, take three after being welded with tubing according to remaining second class Target pipe and remaining third class
Target pipe length carries out cutting dispensing, and remaining clout deficiency is singly propped up wait match tubing.
F, the only first kind and tertiary target pipeline are remaining, then
The remaining tertiary target that the remaining first kind Target pipe for taking different number to combine is combined with different number respectively
Pipeline matching, the total length after matching are waited in integral multiple within tubing deviation range；Take least group of remaining Target pipe number
Conjunction mode, and distribute respective integer times to cut dispensing according to Target pipe length with tubing；
Not matched remaining first kind Target pipe if it exists, then remaining first kind Target pipe is executed by step a, if
In the presence of not matched remaining tertiary target pipeline, then remaining tertiary target pipeline is executed by step b；
Equally with A=10m, for Φ=0.1, if remaining first kind Target pipe length is respectively 1m, 2m, 4m, 5m；It is surplus
Tertiary target duct length of remaininging is respectively 6m, 7m, 8m；Take the remaining least combination of Target pipe number, as 1m, 2m and 8m group
It closes, 4m combines with 7m, and 5m is combined with 6m, and length is all within the scope of [9,11] m after combination, and without remaining Target pipe.
All there is residue in g, the first kind and the second class and third class, then:
Remaining second class Target pipe is divided into two sections with 0.5A (1- Φ) for boundary, and two segment length are in mi length model
It in enclosing, is handled as first kind Target pipe, is executed according to step f.
Class dispensing waits for that with tubing step be that can be carried out classification, mesh of all categories according to all residues of all kinds of Target pipes
Pipeline is marked by reducing notch and weldering as far as possible after with after tubing dispensing, less than one tubing of unused tubing number is long
Under the premise of seam, the utilization efficiency of tubing is improved, optimizes Tube Sizing mode.
In the present embodiment, length is less than the Target pipe of A (1- Φ) a, is divided into three classes, wherein pi ∈ (0.5A (1+
Φ), A (1- Φ)), then ((Φ≤1/3 1- Φ) , 1+ Φ)≤A 0.5A.
In the present embodiment, welding manner consumption is required to in pipe length to enter with tubing meter.
Obviously, the above embodiments are merely examples for clarifying the description, and does not limit the embodiments.It is right
For those of ordinary skill in the art, can also make on the basis of the above description it is other it is various forms of variation or
It changes.There is no necessity and possibility to exhaust all the enbodiments.And it is extended from this it is obvious variation or
It changes still within the protection scope of the invention.
Claims (6)
1. a kind of optimization method of Tube Sizing characterized by comprising
Obtain the numberical range [a, b] to the length xi with tubing；
Obtain the size of the Target pipe in piping diagram, wherein the size of Target pipe is yi；
When the size yi range of the Target pipe is at N [a, b], wherein N is integer, selects N root overall size for the described of yi
To splice simultaneously dispensing with tubing；
When the size yi range of the Target pipe is greater than b and not at N [a, b], wherein N is integer, selects dispensing several
The Target pipe to tubing and one segment length of residue less than a；
Remaining length is less than the mesh of a after with tubing described in the Target pipe and dispensing of the size yi range less than a
It marks pipeline and carries out sort merge dispensing, the sort merge dispensing includes: that each Target pipe is classified, after intercombination
Total length reaches the Target pipe of N [a, b], takes the dispensing after cutting with tubing by corresponding number and length.
2. the optimization method of Tube Sizing according to claim 1, which is characterized in that the length obtained wait match tubing
The step of numberical range [a, b] of xi includes: to obtain the average length A wait match tubing, is calculated described to opposite with tubing
In the deviation ratio Φ of average length,
Φ=((max (xi)-A)/A) * 100%；A=A (1- Φ), b=A (1+ Φ).
3. the optimization method of Tube Sizing according to claim 2, which is characterized in that the sort merge dispensing includes:
S1, remaining length is less than the target tube of a after with tubing described in Target pipe and dispensing of the size yi range less than a
Road is divided into three classes according to length:
First kind Target pipe having a size of mi, mi ∈ (0,0.5A (1- Φ)]；
Second class target line size be ni, ni ∈ (0.5A (1- Φ), 0.5A (1+ Φ)]；
Tertiary target line size is pi, pi ∈ (0.5A (1+ Φ), A (1- Φ))；
S2, first kind Target pipe match respectively with tertiary target pipeline, choose total length at [A (1- Φ), A (1+ Φ)]
Matching way in range takes the dispensing after cutting with tubing by corresponding number and length；
S3, the second class Target pipe match two-by-two, take the dispensing after cutting with tubing by corresponding number and length, if second
Class Target pipe interior conduit quantity is even number, then there is no the remaining Target pipes to dispensing, if the second class Target pipe inner tube
Road quantity is odd number, then dispensing after a remaining Target pipe is to be sorted；
S4 classifies described in dispensing according to the remaining possibility of all kinds of Target pipes wait match tubing.
4. the optimization method of Tube Sizing according to claim 3, which is characterized in that the step S4 includes:
A, the only described first kind Target pipe is remaining, then:
If ∑ mi < A (1- Φ), appoint wait match tubing described in taking in [A (1- Φ), A (1+ Φ)] range, according to each institute
Target pipe length is stated to carry out cutting dispensing；
If in ∑ mi ∈ N [A (1- Φ), A (1+ Φ)] range, N round numbers then chooses corresponding N branch and is added length equal to ∑ mi's
It is described to carry out cutting dispensing according to each Target pipe length wait match tubing；
If ∑ mi > A (1+ Φ) andIn range, N round numbers, then:
K=3 takes k mi to be added, and judges whether in [A (1- Φ), A (1+ Φ)] range, if so, taking k mi overall length
The described of degree is cut wait match tubing according to each Target pipe length；If it is not, then k+1, return judgment step, process are straight
Until the remaining first kind Target pipe quantity is less than k value；
After above-mentioned steps, length summation, then be greater than not matched by the not matched residue first kind Target pipe if it exists
The remaining first kind Target pipe total length and length difference is described to be spliced with tubing less than A (1- Φ), after according to
Each Target pipe length is cut；
B, the only described second class Target pipe is remaining, then:
When the only described second class Target pipe presence residue, then appoint described in taking in [A (1- Φ), A (1+ Φ)] range wait be piped
Material is cut according to the Target pipe length；
C, the only described tertiary target pipeline is remaining, and i is this class target number of tubes, then:
If i=1, appoint described in taking in [A (1- Φ), A (1+ Φ)] range to long according to the tertiary target pipeline with tubing
Degree carries out cutting dispensing；
If i >=2, from the tertiary target pipe for the different number combination for meeting ∑ pi ∈ N [A (1- Φ), A (1+ Φ)]
In road, the remaining least assembled scheme of third class pipe number is chosen, and chooses corresponding number and is added length and be equal to ∑ pi
It is described to according to each tertiary target duct length carry out cutting dispensing with tubing；
Length summation is then greater than the not matched residue third by the not matched residue tertiary target pipeline if it exists
Class Target pipe total length and length difference less than described in more of A (1- Φ) to be spliced with tubing, and according to each described the
Tertiary target duct length cuts dispensing；
D, the only described first kind Target pipe and the second class Target pipe are remaining, then:
The residue first kind Target pipe that the remaining second class Target pipe is combined with different number is matched, is sentenced
Whether pipeline total length is in N [A (1- Φ), A (1+ Φ)] range after disconnected matching；
If selection has the combination of max (mi), identical with pipeline total length after the matching described with N number of total length
Wait match tubing, dispensing is cut according to all kinds of Target pipe length are corresponding after splicing, remaining tubing is executed according to step a；
If not existing, will not matched residue the second class Target pipe with 0.5A (1- Φ) be boundary be divided into two sections, and two sections
Length (0,0.5A (1- Φ)] in, and according to step a execute；
There is residue in e, the only described second class Target pipe and the tertiary target pipeline, then:
Judge the length after the remaining second class Target pipe is combined with each remaining described tertiary target pipeline respectively
Whether in [A (1- Φ), A (1+ Φ)] range, if taking the combination with max (pi), and take the described of corresponding length
To cut dispensing with tubing, the remaining tertiary target pipeline is executed according to step c；If not existing, remaining described the is judged
The residue tertiary target pipeline that two class Target pipes are combined with different number respectively matched after total length when be
It is no interior in N [A (1- Φ), A (1+ Φ)]；
If taking the combination with max (pi), and corresponding number and the described of length is taken to cut dispensing wait match tubing, being stayed
The residue tertiary target pipeline executed according to step c；
If not existing, when being 1 with the remaining matched residue tertiary target number of tubes of second class Target pipe, then cut out
Cut distribution is spliced described wait match tubing to two, and remaining clout deficiency list Zhi Suoshu is waited for tubing；When with residue described second
The matched residue tertiary target number of tubes of class Target pipe is more than or equal to 2, then length summation is greater than described in residue
Second class Target pipe is with the remaining tertiary target pipeline overall length and length difference is described wait match tubing less than A (1- Φ)
Spliced, and cut according to each Target pipe length, remaining clout deficiency list Zhi Suoshu is waited for tubing；
There is residue in f, the only described first kind Target pipe and the tertiary target pipeline, then:
The residue third class that the residue first kind Target pipe for taking different number to combine is combined with different number respectively
Target pipe matching, the total length after matching is within N [A (1- Φ), A (1+ Φ)]；Take the remaining Target pipe quantity most
Few combination, and distribute the described to cut dispensing according to the Target pipe length with tubing of respective numbers；
Not matched remaining first kind Target pipe if it exists, then remaining first kind Target pipe is executed by step a, if it exists
Not matched remaining tertiary target pipeline, then remaining tertiary target pipeline is executed by step b；
All there is residue in g, the first kind Target pipe and the second class Target pipe and the tertiary target pipeline,
Then:
The remaining second class Target pipe is divided into two sections with 0.5A (1- Φ) for boundary, and two segment length are in mi length model
It in enclosing, is handled as the first kind Target pipe, is executed according to step f.
5. the optimization method of Tube Sizing according to claim 3, which is characterized in that Φ≤1/3.
6. the optimization method of Tube Sizing according to claim 1, which is characterized in that the connection type wait match tubing
For welding, the consumption wait match tubing is included in described to in pipe length.
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