CN110470954A - Active power distribution network fault distance-finding method - Google Patents
Active power distribution network fault distance-finding method Download PDFInfo
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- CN110470954A CN110470954A CN201910873765.9A CN201910873765A CN110470954A CN 110470954 A CN110470954 A CN 110470954A CN 201910873765 A CN201910873765 A CN 201910873765A CN 110470954 A CN110470954 A CN 110470954A
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- G—PHYSICS
- G01—MEASURING; TESTING
- G01R—MEASURING ELECTRIC VARIABLES; MEASURING MAGNETIC VARIABLES
- G01R31/00—Arrangements for testing electric properties; Arrangements for locating electric faults; Arrangements for electrical testing characterised by what is being tested not provided for elsewhere
- G01R31/08—Locating faults in cables, transmission lines, or networks
- G01R31/081—Locating faults in cables, transmission lines, or networks according to type of conductors
- G01R31/086—Locating faults in cables, transmission lines, or networks according to type of conductors in power transmission or distribution networks, i.e. with interconnected conductors
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- G—PHYSICS
- G01—MEASURING; TESTING
- G01R—MEASURING ELECTRIC VARIABLES; MEASURING MAGNETIC VARIABLES
- G01R31/00—Arrangements for testing electric properties; Arrangements for locating electric faults; Arrangements for electrical testing characterised by what is being tested not provided for elsewhere
- G01R31/08—Locating faults in cables, transmission lines, or networks
- G01R31/088—Aspects of digital computing
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- Y—GENERAL TAGGING OF NEW TECHNOLOGICAL DEVELOPMENTS; GENERAL TAGGING OF CROSS-SECTIONAL TECHNOLOGIES SPANNING OVER SEVERAL SECTIONS OF THE IPC; TECHNICAL SUBJECTS COVERED BY FORMER USPC CROSS-REFERENCE ART COLLECTIONS [XRACs] AND DIGESTS
- Y04—INFORMATION OR COMMUNICATION TECHNOLOGIES HAVING AN IMPACT ON OTHER TECHNOLOGY AREAS
- Y04S—SYSTEMS INTEGRATING TECHNOLOGIES RELATED TO POWER NETWORK OPERATION, COMMUNICATION OR INFORMATION TECHNOLOGIES FOR IMPROVING THE ELECTRICAL POWER GENERATION, TRANSMISSION, DISTRIBUTION, MANAGEMENT OR USAGE, i.e. SMART GRIDS
- Y04S10/00—Systems supporting electrical power generation, transmission or distribution
- Y04S10/50—Systems or methods supporting the power network operation or management, involving a certain degree of interaction with the load-side end user applications
- Y04S10/52—Outage or fault management, e.g. fault detection or location
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Abstract
The present invention provides a kind of active power distribution network fault distance-finding methods, comprising the following steps: one, failure occur after, protective device obtain section head end voltageElectric currentThe voltage of segment endsElectric currentThe equivalent current of DG injection node jTwo, since main power source section, k indicates node, enables k=1；Three, it initializesFour, fault distance x is calculated1、x2；Five, convergence rate is compared with threshold value；Six, fault distance is compared with section length；Seven, judge whether k is last section, is, carries out step 8, otherwise carries out step 9；Eight, by k=k+1, the head end voltage and head end electric current of adjacent sections, return step three are calculated；Nine, pseudo-fault point identification is carried out；Compared with the prior art, the time for shortening transmission line of electricity section fault point location significantly reduces the operation risk of electric system.It is insufficient for the accuracy of identification of pseudo-fault point simultaneously, reduce the interference of pseudo-fault point, improves the accuracy of identification of fault point.
Description
Technical field
The present invention relates to a kind of relay protection method of power system, especially a kind of guard method of power distribution network.
Background technique
The complicated multiplicity of China distribution net work structure, when breaking down, using manual patrol line maintenance, both increased O&M at
This reduces power supply efficiency again, cannot fault location and recovery electricity consumption in time.After distributed generation resource is incorporated to power distribution network, to matching
The trend of power grid is run, and the adjusting of relay protection and control has great influence.Therefore, active power distribution network event how is quickly identified
Barrier, the power supply reduced scope of power outage and restore important load region rapidly, avoid socio-economic efficiency from losing, safe and reliable to supply
Electricity, the safety management and stable operation for promoting power distribution network are of great significance to.
The Fault Locating Method of the prior art is exited and matches in distributed generation resource DG (distributed generation)
It is carried out under conditions of power grid, has seriously affected the accuracy and efficiency of distribution network line fault position positioning.It is automatic in power distribution network
In the case that change degree is higher and higher, it is desirable that DG is when being incorporated to power distribution network operation, accurate quick in the case where not having a power failure
The position of active distribution network line fault is positioned, to reduce economic loss.
Summary of the invention
The object of the present invention is to provide a kind of active power distribution network fault distance-finding method, technical problems to be solved are to improve to have
The accuracy and speed of source distribution network failure positioning.
To solve the above problems, the present invention is implemented with the following technical solutions: a kind of active power distribution network fault distance-finding method,
The following steps are included:
One, after failure occurs, protective device obtains the voltage of section head endElectric currentThe electricity of segment ends
PressureElectric currentThe equivalent current of DG injection node j
Two, since main power source section, k indicates node, enables k=1；
Three, it initializes
Calculate current in the fault point
In formula,Section head end electric current after occurring for failure,Front section head end electric current occurs for failure；
Four, fault distance x is calculated1、x2；
According to Π shape equivalent circuit principle in Steady-State Analysis of Power System:
In formula, A=E+0.5x2·Z·Y；
B=-xZ；
C=- (xY+0.25x3·Z·Y2)；
D=E+0.5x2·Z·Y；
A, B, C, D are the general constant of the Π shape equivalent circuit of fault distance X, x ∈ [0, L] section in section length L；Z
For section impedance matrix；Y is section admittance matrix over the ground；
Calculate fault point voltageAre as follows:
Calculate fault point reactive powerAre as follows:
In formula, ' * ' it is conjugate phasors；
Consider that transition resistance consumption reactive power is zero, imaginary part is taken to calculate
Calculate fault distance x1、x2Are as follows:
Wherein,
A, b, c ax2+ bx+c=0 equation coefficient；Z is section impedance matrix；Y is section admittance matrix over the ground；
By convergence rate and threshold value comparison are as follows:
In formula, i is the number of iterations, and ε is threshold value, takes 10-5；
According to Steady-State Analysis of Power System Π shape equivalent circuit principle:
In formula, A '=E+0.5 (L-x)2ZY,
B '=- (L-x) Z,
C '=- ((L-x) Y+0.25 (L-x)3·Z·Y2),
D '=E+0.5 (L-x)2ZY,
A ', B ', C ', D ' be length L-x section Π shape equivalent circuit general constant；
Calculation of sector terminal voltage
Calculation of sector end current
In formula, ZjFor the self-impedance of matrix Z interior joint j, Zj,kFor the mutual impedance between matrix Z interior joint j and k,For
DG injects the equivalent current of node j,The equivalent current of node k is injected for DG, N is system node number, '+' transported for pseudoinverse
It calculates；
Segment ends electric currentIt can indicate again are as follows:
Electric current behind calculating fault point
In formula, α0=[D '+(Zjj)+·B′]+；α1=[C '+(Zjj)+·D′]·D；α2=[C '+(Zjj)+·D′]·B；
Electric current before calculating fault point
According to Kirchhoff's current law (KCL), current in the fault point is calculated
According to Π shape equivalent circuit principle:
In formula,
A "=E+0.5L2ZY,
B "=- LZ,
C "=- (LY+0.25L3·Z·Y2),
D "=E+0.5L2·Z·Y；
The general constant of A ", B ", the Π shape equivalent circuit that C ", D " is length L section；
Calculation of sector end current
Calculate the equivalent current of injection node j
In formula,After removing section ij and jk, the equivalent current of node j.Z′jjFor hindering certainly for matrix Z ' interior joint j
It is anti-, Z 'j,kFor the mutual impedance between matrix Z ' interior joint j and k,The equivalent current of node j is injected for DG,For DG injection
The equivalent current of node k, N are system node number, '+' it is pseudo-inverse operation；
According to Kirchhoff's current law (KCL), the head end electric current of adjacent sections is calculated
Calculate the head end voltage of adjacent sections
Calculation of sector fault point measures voltage
Calculation of sector fault point measures voltage and head end voltage minimal error:
M is system power supply number in formula, and Error is pseudo-fault point identification；
Five, convergence rate is compared with threshold value；
Six, fault distance is compared with section length；
Seven, judge whether k is last section, is, carries out step 8, otherwise carries out step 9；
Eight, by k=k+1, the head end voltage and head end electric current of adjacent sections, return step three are calculated；
Nine, pseudo-fault point identification is carried out；
Further, the fault distance x of the iteration n-th1(n)、x2(n) are as follows:
Further, the fault distance x of the iteration i-th1(i)、x2(i) are as follows:
Further, the iteration (i-1)-th time fault distance x1(i-1)、x2(i-1) are as follows:
Further, the step 5 be specially by i-th fault distance and (i-1)-th fault distance absolute value of the difference with
Threshold value comparison, judges whether convergence rate is less than threshold value, when convergence rate is less than threshold value, judges whether fault distance is less than area
Segment length.
Further, when convergence rate is greater than threshold value, current failure distance value is updated to current in the fault point value, and return
Return step 4.
Further, the step 6 specifically: by i-th fault distance compared with section length, when i-th failure away from
When from being less than section length, fault distance value, current in the fault point value and nodal scheme value at this time is recorded.
Further, when i-th fault distance is greater than section length, judge whether it is last section.
The present invention compared with the prior art, in the case where considering transmission line of electricity distribution capacity and Coupling Between Phases, proposes one
The improved impedance method active power distribution network fault distance-finding method of kind, is applicable in different faults type, shortens transmission line of electricity section fault
The time of point location significantly reduces the operation risk of electric system.It is insufficient for the accuracy of identification of pseudo-fault point simultaneously, pass through
Threshold voltage and true value voltage difference minimum principle are measured, reduces the interference of pseudo-fault point, improves the accuracy of identification of fault point.
Detailed description of the invention
Fig. 1 is the Π shape equivalent circuit diagram of the embodiment of the present invention.
Fig. 2 is the active power distribution network local fault section equivalent circuit diagram of the embodiment of the present invention.
Fig. 3 is the active power distribution network part adjacent sections equivalent circuit diagram of the embodiment of the present invention.
Fig. 4 is active power distribution network fault distance-finding method flow chart of the invention.
Specific embodiment
Invention is further described in detail with reference to the accompanying drawings and examples.
The active power distribution network fault distance-finding method (method) invented herein is used for active power distribution network fault localization.
Active power distribution network is to have referred to the accession to main power source and distributed generation resource DG, and the power distribution network of to and fro flow of power is active to match
Power grid can reflect that distributed generation resource includes the physical features of voltage, electric current well.Main power source refers in no access DG, is
Power distribution network provides the power supply of electric energy, can be power transmission network or regional power plant.To and fro flow of power refers in no access DG,
Power flow direction flows to the flow direction of user from main power source, and after DG access, power flow direction can flow to the flow direction of main power source from user.
Active power distribution network includes main power source, distributed generation resource, transmission line of electricity, node.Node, which refers to, transmits electricity middle and long distance
Route is divided into the endpoint of transmission line of electricity section, flows to the direction of user from main power source by power flow direction, transmission line of electricity section
Head end, end are known as headend node, endpoint node.It, cannot because the loss of voltage is larger in middle and long distance transmission line of electricity
Ignore susceptance B.Middle and long distance transmission line of electricity is the overhead transmission line between 100~300km and the cable no more than 100km
Route.
In order to facilitate analyzing and calculating, the equivalent circuit of lumped parameter is commonly used to describe transmission line of electricity in active power distribution network
Electrical characteristic.Method of the invention will include the part active power distribution network of main power source, distributed generation resource, transmission line of electricity, node
Π type equivalent circuit is converted to be analyzed and calculated.
As shown in Figure 1, at Π type equivalent circuit both ends, respectively the two of active power distribution network node: headend node i and end
End node j is connected with transmission line of electricity between i and j, or is transmission line of electricity section (section) between i and j, connects on section
It is connected with transmission line of electricity total impedance Z, is equivalent two parts Y/2 by transmission line of electricity resultant admittance Y=jB points, is connected in parallel respectively
Between the first and end and ground connection of transmission line of electricity section.Main power source is connected on headend node i, and the voltage of i is head end voltage
The electric current for flowing to Z from i is head end electric currentThe voltage of j is terminal voltageThe electric current for flowing to j from Z is end current
When active power distribution network does not access DG, electric energy is provided for active power distribution network by main power source, by the section containing main power source
It is defined as main power source section.
As shown in Fig. 2, after Π type equivalent circuit node j accesses DG, the equivalent current that DG flows into node j is
If section length is L, when section point f breaks down, the distance of i to fault point f is x, the equivalent resistance of i to f
Resist for xZ/L, the equivalent impedance of f to j is (L-x) Z/L, and the electric current for flowing to xZ/L from i is head end electric current after failureFrom xZ/L
The electric current for flowing to f is electric current before fault pointElectric current from f flow direction (L-x) Z/L is electric current behind fault pointThe voltage of f is
Fault point voltageResistance between f and ground connection is transition resistance Rf, R is flowed to from ffElectric current be current in the fault point(figure
In 2, heavy line indicates node, and fine line indicates that transmission line of electricity, dotted line indicate DG access node, and arrow indicates PRE-FAULT CURRENT
Direction.)
After f breaks down, it is arranged between i and xZ/L, the protective device of (L-x) between Z/L and j can obtain section
According to after failure, the difference of failure front section head end electric current amplitude, current in the fault pointAre as follows:
When active power distribution network fault point, f breaks down, the system structure that active power distribution network is constituted is complicated, branch is more, right
Fault location becomes more complicated, in order to simplify system, according to (document 1, " Steady-State Analysis of Power System ", Chen Hang, China Power
Publishing house, in November, 2015, the 44-51 pages), section first and last end voltage and current relationship are as follows:
In formula (2), A, B, C, D are the general constant of fault distance x, x ∈ [0, L] section equivalent circuit in section length L,
General constant is used to indicate that the variation relation of the segment voltage and electric current.(document 2, " circuit ", Qiu Guanyuan, Luo Xianjue are high
Education publishing house, in May, 2006, the 418-429 pages), A=E+0.5x2ZY, B=-xZ, C=- (xY+0.25x3·
Z·Y2), D=E+0.5x2ZY, (document 3, " Steady-State Analysis of Power System ", Chen Hang, China Electric Power Publishing House, 2015 11
Month, the 109-121 pages), in distribution network, according to Circuit theory interior joint voltage equation, matrix operation is carried out, by network
It is summed up in relation to parameter and variable and its correlation, can reflect the mathematical equation group of performance.Wherein, E is unit square
Battle array, Z are section impedance matrix, are the physical quantitys for indicating electrical property in element function or one section of circuit, and Y is section admittance matrix,
It is the energy size of system release when voltage changes, for describing degree of difficulty of the alternating current by circuit or system when, generally
The admittance Y of active power distribution network cannot ignore.
According to formula (2), fault point voltageAre as follows:
According to formula (1), (3), in conjunction with (document 4, " circuit ", Qiu Guanyuan, Luo Xianjue, Higher Education Publishing House, 2006
May, the 238-241 pages) complex power formula, fault point reactive powerAre as follows:
In formula (4)The conjugate phasors of current in the fault point are expressed as, in order to seek the negative value of phase.
Assuming that transition resistance is in purely resistive, break down at the x apart from section head end, then the reactive power of its consumption is
Zero, i.e.,Formula (2) and (3) are substituted into formula (4) and take imaginary-part operation, obtains fault distance x and current in the fault pointRelational expression.
ax2+ bx+c=0 (6)
Formula (6) is an One- place 2-th Order range equation.
Wherein:
Fault distance value x1、x2Are as follows:
X may be solved according to formula (10) available fault distance1、x2, wherein formula (7), (8), a, b, c are formula (6) in (9)
The coefficient of quadratic equation with one unknown, equation are used to calculate the possibility solution of fault distance, are obtained according to formula (5) simplification, coefficient is just
According to radical formula calculating fault distance value x1、x2。
Due to system loading influence of fluctuations, when calculating fault distance value, the fault distance x of nth iteration1(n)、x2(n)
Are as follows:
According to formula (11), the fault distance x of i-th iteration1(i)、x2(i) are as follows:
According to formula (11), (i-1)-th iteration fault distance x1(i-1)、x2(i-1) are as follows:
By convergence rate and threshold value comparison are as follows:
In formula, i is the number of iterations, and ε is threshold value, takes 10-5。
According to Π shape equivalent circuit principle in " Steady-State Analysis of Power System ":
In formula (15), A '=E+0.5 (L-x)2ZY, B '=- (L-x) Z, C '=- ((L-x) Y+0.25 (L-x
)3·Z·Y2), D '=E+0.5 (L-x)2ZY, A ', B ', C ', D ' are that fault distance is Π shape of L-x section etc. in section L
It is worth the general constant of circuit.
Segment ends voltageAre as follows:
Segment ends electric current containing DGAre as follows:
In formula (17), ZjjFor the self-impedance of matrix Z interior joint j, Zj,kFor the mutual impedance between matrix Z interior joint j and k,The equivalent current of node j is injected for DG,The equivalent current of node k is injected for DG, N is system node number, '+' it is pseudo-
Inverse operation.
According to formula (15) segment ends electric currentIt can also indicate are as follows:
Electric current behind fault pointAre as follows:
In formula (19), α0=[D '+(Zjj)+·B′]+；α1=[C '+(Zjj)+·D′]·D；α2=[C '+(Zjj)+·
D′]·B。
Electric current before fault pointAre as follows:
According to Kirchhoff's current law (KCL), current in the fault pointAre as follows:
According in formula (14), by convergence rate and threshold value comparison.If convergence rate is less than threshold value, comparing fault distance is
It is no to be less than section length.Otherwise current in the fault point value just is updated with current failure distance value.
According to formula (22) by fault distance compared with section length.If fault distance is less than section length, record at this time
Fault distance value, current in the fault point value and nodal scheme value.Otherwise judge whether the section is last section.
As shown in figure 3, carrying out the identification of pseudo-fault point if k is last section.Otherwise Fig. 2 calculation method is utilized, into
The head end voltage of row adjacent sections, electric current calculate.
According to Π shape equivalent circuit principle in " Steady-State Analysis of Power System ":
A "=E+0.5L in formula (23)2ZY, B "=- LZ, C "=- (LY+0.25L3·Z·Y2), D "=E+
0.5L2·Z·Y.The general constant of A ", B ", the Π shape equivalent circuit that C ", D " is length L section.
Segment ends electric currentAre as follows:
Inject the equivalent current of node jAre as follows:
In formula (25),After removing section ij and jk, the equivalent current of node j.Z′jjFor matrix Z ' interior joint j's
Self-impedance, Z 'j,kFor the mutual impedance between matrix Z ' interior joint j and k,The equivalent current of node j is injected for DG,For DG
The equivalent current of node k is injected, N is system node number, '+' it is pseudo-inverse operation.
According to Kirchhoff's current law (KCL), the head end electric current of adjacent sectionsAre as follows:
The head end voltage of adjacent sectionsAre as follows:
Section fault point measures voltageAre as follows:
Section fault point measures voltage and head end voltage minimal error Error are as follows:
M is system power supply number in formula (29), carries out the identification of pseudo-fault point.
Due to the complexity of active power distribution network and the uncertainty of transition resistance, line distribution capacitance is comprehensively considered herein,
The influence of the factors such as Coupling Between Phases proposes a kind of impedance method of improving for prior art fault location precision is low and speed is slow
Active power distribution network fault distance-finding method improves the accuracy of fault location and fast suitable for the fault location of various fault types
Speed.
Claims (8)
1. a kind of active power distribution network fault distance-finding method, it is characterised in that: the following steps are included:
One, after failure occurs, protective device obtains the voltage of section head endElectric currentThe voltage of segment endsElectric currentThe equivalent current of DG injection node j
Two, since main power source section, k indicates node, enables k=1；
Three, it initializes
Calculate current in the fault point
In formula,Section head end electric current after occurring for failure,Front section head end electric current occurs for failure；
Four, fault distance x is calculated1、x2；
According to Π shape equivalent circuit principle in Steady-State Analysis of Power System:
In formula, A=E+0.5x2·Z·Y；
B=-xZ；
C=- (xY+0.25x3·Z·Y2)；
D=E+0.5x2·Z·Y；
A, B, C, D are the general constant of the Π shape equivalent circuit of fault distance X, x ∈ [0, L] section in section length L；Z is area
Section impedance matrix；Y is section admittance matrix over the ground；
Calculate fault point voltageAre as follows:
Calculate fault point reactive powerAre as follows:
In formula, ' * ' it is conjugate phasors；
Consider that transition resistance consumption reactive power is zero, imaginary part is taken to calculate
Calculate fault distance x1、x2Are as follows:
Wherein,
A, b, c ax2+ bx+c=0 equation coefficient；Z is section impedance matrix；Y is section admittance matrix over the ground；
By convergence rate and threshold value comparison are as follows:
In formula, i is the number of iterations, and ε is threshold value, takes 10-5；
According to Steady-State Analysis of Power System Π shape equivalent circuit principle:
In formula, A '=E+0.5 (L-x)2ZY,
B '=- (L-x) Z,
C '=- ((L-x) Y+0.25 (L-x)3·Z·Y2),
D '=E+0.5 (L-x)2ZY,
A ', B ', C ', D ' be length L-x section Π shape equivalent circuit general constant；
Calculation of sector terminal voltage
Calculation of sector end current
In formula, ZjjFor the self-impedance of matrix Z interior joint j, Zj,kFor the mutual impedance between matrix Z interior joint j and k,For DG note
The equivalent current of ingress j,The equivalent current of node k is injected for DG, N is system node number, '+' it is pseudo-inverse operation；
Segment ends electric currentIt can indicate again are as follows:
Electric current behind calculating fault point
In formula, α0=[D '+(Zjj)+·B′]+；α1=[C '+(Zjj)+·D′]·D；α2=[C '+(Zjj)+·D′]·B；
Electric current before calculating fault point
According to Kirchhoff's current law (KCL), current in the fault point is calculated
According to Π shape equivalent circuit principle:
In formula,
A "=E+0.5L2ZY,
B "=- LZ,
C "=- (LY+0.25L3·Z·Y2),
D "=E+0.5L2·Z·Y；
The general constant of A ", B ", the Π shape equivalent circuit that C ", D " is length L section；
Calculation of sector end current
Calculate the equivalent current of injection node j
In formula,After removing section ij and jk, the equivalent current of node j.Z′jjFor the self-impedance of matrix Z ' interior joint j,
Z′j,kFor the mutual impedance between matrix Z ' interior joint j and k,The equivalent current of node j is injected for DG,Node is injected for DG
The equivalent current of k, N are system node number, '+' it is pseudo-inverse operation；
According to Kirchhoff's current law (KCL), the head end electric current of adjacent sections is calculated
Calculate the head end voltage of adjacent sections
Calculation of sector fault point measures voltage
Calculation of sector fault point measures voltage and head end voltage minimal error:
M is system power supply number in formula, and Error is pseudo-fault point identification；
Five, convergence rate is compared with threshold value；
Six, fault distance is compared with section length；
Seven, judge whether k is last section, is, carries out step 8, otherwise carries out step 9；
Eight, by k=k+1, the head end voltage and head end electric current of adjacent sections, return step three are calculated；
Nine, pseudo-fault point identification is carried out.
2. active power distribution network fault distance-finding method according to claim 1, it is characterised in that: the event of the iteration n-th
Hinder distance x1(n)、x2(n) are as follows:
3. active power distribution network fault distance-finding method according to claim 2, it is characterised in that: the event of the iteration i-th
Hinder distance x1(i)、x2(i) are as follows:
4. active power distribution network fault distance-finding method according to claim 2, it is characterised in that: the iteration (i-1)-th time
Fault distance x1(i-1)、x2(i-1) are as follows:
5. active power distribution network fault distance-finding method according to claim 1, it is characterised in that: the step 5 is specially will
I-th fault distance and (i-1)-th fault distance absolute value of the difference and threshold value comparison, judge whether convergence rate is less than threshold value,
When convergence rate is less than threshold value, judge whether fault distance is less than section length.
6. active power distribution network fault distance-finding method according to claim 5, it is characterised in that: when convergence rate is greater than threshold value
When, current failure distance value is updated to current in the fault point value, and return step four.
7. active power distribution network fault distance-finding method according to claim 1, it is characterised in that: the step 6 specifically:
By i-th fault distance compared with section length, when i-th fault distance is less than section length, record failure at this time away from
From value, current in the fault point value and nodal scheme value.
8. active power distribution network fault distance-finding method according to claim 7, it is characterised in that: when i-th fault distance is big
When section length, last section is judged whether it is.
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Cited By (2)
| Publication number | Priority date | Publication date | Assignee | Title |
|---|---|---|---|---|
| RU2793555C1 (en) * | 2022-06-22 | 2023-04-04 | федеральное государственное бюджетное образовательное учреждение высшего образования "Нижегородский государственный технический университет им. Р.Е. Алексеева" (НГТУ) | Method for determining location of a short circuit on an overhead power line with unsynchronized measurements from its two ends |
| CN116773970A (en) * | 2023-08-21 | 2023-09-19 | 国网山东省电力公司日照供电公司 | Multi-branch distribution network feeder short-circuit fault positioning method, system, medium and equipment |
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| CN116773970A (en) * | 2023-08-21 | 2023-09-19 | 国网山东省电力公司日照供电公司 | Multi-branch distribution network feeder short-circuit fault positioning method, system, medium and equipment |
| CN116773970B (en) * | 2023-08-21 | 2023-11-03 | 国网山东省电力公司日照供电公司 | Multi-branch distribution network feeder short-circuit fault positioning method, system, medium and equipment |
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Application publication date: 20191119 |