CN110364907A - A kind of 7 strand steel-cored aluminium strand compression bonding methods of round wires concentric gallows empty conductor - Google Patents

A kind of 7 strand steel-cored aluminium strand compression bonding methods of round wires concentric gallows empty conductor Download PDF

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Publication number
CN110364907A
CN110364907A CN201910731289.7A CN201910731289A CN110364907A CN 110364907 A CN110364907 A CN 110364907A CN 201910731289 A CN201910731289 A CN 201910731289A CN 110364907 A CN110364907 A CN 110364907A
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steel
aluminum pipe
aluminium
unit
strand
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CN201910731289.7A
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CN110364907B (en
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张仁奇
张瑾
刘雨菲
张义钊
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Guizhou Power Grid Co Ltd
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Guizhou Power Grid Co Ltd
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    • H—ELECTRICITY
    • H01—ELECTRIC ELEMENTS
    • H01R—ELECTRICALLY-CONDUCTIVE CONNECTIONS; STRUCTURAL ASSOCIATIONS OF A PLURALITY OF MUTUALLY-INSULATED ELECTRICAL CONNECTING ELEMENTS; COUPLING DEVICES; CURRENT COLLECTORS
    • H01R11/00—Individual connecting elements providing two or more spaced connecting locations for conductive members which are, or may be, thereby interconnected, e.g. end pieces for wires or cables supported by the wire or cable and having means for facilitating electrical connection to some other wire, terminal, or conductive member, blocks of binding posts
    • H01R11/01—Individual connecting elements providing two or more spaced connecting locations for conductive members which are, or may be, thereby interconnected, e.g. end pieces for wires or cables supported by the wire or cable and having means for facilitating electrical connection to some other wire, terminal, or conductive member, blocks of binding posts characterised by the form or arrangement of the conductive interconnection between the connecting locations
    • H—ELECTRICITY
    • H01—ELECTRIC ELEMENTS
    • H01R—ELECTRICALLY-CONDUCTIVE CONNECTIONS; STRUCTURAL ASSOCIATIONS OF A PLURALITY OF MUTUALLY-INSULATED ELECTRICAL CONNECTING ELEMENTS; COUPLING DEVICES; CURRENT COLLECTORS
    • H01R11/00—Individual connecting elements providing two or more spaced connecting locations for conductive members which are, or may be, thereby interconnected, e.g. end pieces for wires or cables supported by the wire or cable and having means for facilitating electrical connection to some other wire, terminal, or conductive member, blocks of binding posts
    • H01R11/03—Individual connecting elements providing two or more spaced connecting locations for conductive members which are, or may be, thereby interconnected, e.g. end pieces for wires or cables supported by the wire or cable and having means for facilitating electrical connection to some other wire, terminal, or conductive member, blocks of binding posts characterised by the relationship between the connecting locations
    • H01R11/09—Individual connecting elements providing two or more spaced connecting locations for conductive members which are, or may be, thereby interconnected, e.g. end pieces for wires or cables supported by the wire or cable and having means for facilitating electrical connection to some other wire, terminal, or conductive member, blocks of binding posts characterised by the relationship between the connecting locations the connecting locations being identical
    • H—ELECTRICITY
    • H01—ELECTRIC ELEMENTS
    • H01R—ELECTRICALLY-CONDUCTIVE CONNECTIONS; STRUCTURAL ASSOCIATIONS OF A PLURALITY OF MUTUALLY-INSULATED ELECTRICAL CONNECTING ELEMENTS; COUPLING DEVICES; CURRENT COLLECTORS
    • H01R4/00—Electrically-conductive connections between two or more conductive members in direct contact, i.e. touching one another; Means for effecting or maintaining such contact; Electrically-conductive connections having two or more spaced connecting locations for conductors and using contact members penetrating insulation
    • H01R4/10—Electrically-conductive connections between two or more conductive members in direct contact, i.e. touching one another; Means for effecting or maintaining such contact; Electrically-conductive connections having two or more spaced connecting locations for conductors and using contact members penetrating insulation effected solely by twisting, wrapping, bending, crimping, or other permanent deformation
    • H01R4/18—Electrically-conductive connections between two or more conductive members in direct contact, i.e. touching one another; Means for effecting or maintaining such contact; Electrically-conductive connections having two or more spaced connecting locations for conductors and using contact members penetrating insulation effected solely by twisting, wrapping, bending, crimping, or other permanent deformation by crimping
    • H01R4/183—Electrically-conductive connections between two or more conductive members in direct contact, i.e. touching one another; Means for effecting or maintaining such contact; Electrically-conductive connections having two or more spaced connecting locations for conductors and using contact members penetrating insulation effected solely by twisting, wrapping, bending, crimping, or other permanent deformation by crimping for cylindrical elongated bodies, e.g. cables having circular cross-section
    • H—ELECTRICITY
    • H01—ELECTRIC ELEMENTS
    • H01R—ELECTRICALLY-CONDUCTIVE CONNECTIONS; STRUCTURAL ASSOCIATIONS OF A PLURALITY OF MUTUALLY-INSULATED ELECTRICAL CONNECTING ELEMENTS; COUPLING DEVICES; CURRENT COLLECTORS
    • H01R4/00—Electrically-conductive connections between two or more conductive members in direct contact, i.e. touching one another; Means for effecting or maintaining such contact; Electrically-conductive connections having two or more spaced connecting locations for conductors and using contact members penetrating insulation
    • H01R4/10—Electrically-conductive connections between two or more conductive members in direct contact, i.e. touching one another; Means for effecting or maintaining such contact; Electrically-conductive connections having two or more spaced connecting locations for conductors and using contact members penetrating insulation effected solely by twisting, wrapping, bending, crimping, or other permanent deformation
    • H01R4/18—Electrically-conductive connections between two or more conductive members in direct contact, i.e. touching one another; Means for effecting or maintaining such contact; Electrically-conductive connections having two or more spaced connecting locations for conductors and using contact members penetrating insulation effected solely by twisting, wrapping, bending, crimping, or other permanent deformation by crimping
    • H01R4/20—Electrically-conductive connections between two or more conductive members in direct contact, i.e. touching one another; Means for effecting or maintaining such contact; Electrically-conductive connections having two or more spaced connecting locations for conductors and using contact members penetrating insulation effected solely by twisting, wrapping, bending, crimping, or other permanent deformation by crimping using a crimping sleeve
    • H—ELECTRICITY
    • H01—ELECTRIC ELEMENTS
    • H01R—ELECTRICALLY-CONDUCTIVE CONNECTIONS; STRUCTURAL ASSOCIATIONS OF A PLURALITY OF MUTUALLY-INSULATED ELECTRICAL CONNECTING ELEMENTS; COUPLING DEVICES; CURRENT COLLECTORS
    • H01R43/00—Apparatus or processes specially adapted for manufacturing, assembling, maintaining, or repairing of line connectors or current collectors or for joining electric conductors
    • H01R43/04—Apparatus or processes specially adapted for manufacturing, assembling, maintaining, or repairing of line connectors or current collectors or for joining electric conductors for forming connections by deformation, e.g. crimping tool
    • H01R43/048—Crimping apparatus or processes

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  • Engineering & Computer Science (AREA)
  • Manufacturing & Machinery (AREA)
  • Connections Effected By Soldering, Adhesion, Or Permanent Deformation (AREA)

Abstract

The invention discloses a kind of 7 strand steel-cored aluminium strand compression bonding methods of round wires concentric gallows empty conductor, this method are as follows: the aluminum stranded conductor of docking is peeled off into a distance first and exposes center strand, aluminium splicing sleeve is inserted in conducting wire, then, steel-cored aluminium strand is penetrated in outer inlay aluminum pipe, again by conducting wire setting ring set on steel-cored aluminium strand, inline layer aluminum pipe is inserted among interior aluminum stranded conductor layer and steel core again, after the aluminum stranded conductor of opening is repaired, steel core is connected into embedding aluminium pipe sleeve in two conducting wire steel core line ends of docking, full tension steel pipe sleeve is connected again to connect outside embedding aluminium pipe sleeve in steel core, crimping is so that steel core connects embedding aluminium pipe sleeve and engages with steel core, aluminium splicing sleeve is finally moved back to crimping position, crimping is so that inline layer aluminum pipe, outer inlay aluminum pipe fits closely.The present invention avoids steel-cored aluminium strand from weighing wounded, is under-voltage, loose stock, and connection reliability is good, and easy to manufacture, crimp quality is higher, exempts from non-destructive testing, reduces labor intensity and engineering cost.

Description

A kind of 7 strand steel-cored aluminium strand compression bonding methods of round wires concentric gallows empty conductor
Technical field
The invention belongs to 7 strand steel-cored aluminium strand banjo fixing butt jointing technical fields of round wires concentric gallows empty conductor, and in particular to A kind of 7 strand steel-cored aluminium strand compression bonding methods of round wires concentric gallows empty conductor.
Background technique
The existing full tension splicing sleeve of steel-cored aluminium strand is mainly made of steel aluminium hydraulic pressed connecting pipe and aluminium aluminium hydraulic pressed connecting pipe, when crimping, first by aluminium Twisted wire exploits one section of exposing steel strand wires, crimps steel strand wires with steel aluminium hydraulic pressed connecting pipe, is then again connect aluminium alloy with aluminium alloy aluminium hydraulic pressed connecting pipe Continuous pipe, aluminum stranded conductor, steel strand wires are crimped together.This traditional compression bonding method is easy to appear two aspect problems:
(1) steel core splicing sleeve crimps the damage to steel core.
In the subsequent process of traditional project of transmitting and converting electricity aerial condutor, the galvanized strand wires of steel-cored aluminium strand and ground wire (or aluminum-cladding stranded wire) connector directly entangles steel strand wires hydraulic connecting with steel splicing sleeve, if steel splicing sleeve and steel strand wires hardness It mismatches, the off size reason of crimp, crimping pressure deficiency, is easy to appear under-voltage, loose stock, over-voltage, steel wire surface damage etc. Defect causes the power that holds of connector to be unsatisfactory for standard requirements.Cause steel-cored aluminium strand and ground wire steel strand wires crimping defect because In element, steel splicing sleeve and steel strand wires hardness mismatch are least avoided that, in the production technology of aluminum-cladding stranded wire, cold-drawn steel Silk passes through liquid aluminium and aluminizes, and has mutually regarded primary tempering, and (cold-)drawn (steel)wire hardness reduces, and causes steel strand wires hardness than steel splicing sleeve hardness Low, steel connects inside pipe wall and bites steel strand wires steel wire when crimping, and lead to connector holds power reduction.
(2) aluminium splicing sleeve crimp quality is difficult to ensure.
In the subsequent process of traditional project of transmitting and converting electricity aerial condutor, since steel core yield strength is strong much larger than the surrender of aluminium Degree, aluminum stranded conductor and aluminium alloy splicing sleeve generate plastic deformation hardening at crimping, and single aluminum stranded conductor section attenuates.
In summer, when temperature increases, steel core expands outward squeezes aluminum stranded conductor, and aluminum stranded conductor and aluminium alloy splicing sleeve are also to introversion Outer expansion continues to squeeze steel core, since steel core yield strength is much larger than the yield strength of aluminium, continues to generate modeling at aluminum stranded conductor crimping Property strain hardening, single aluminum stranded conductor section continue to attenuate.
In winter, when the temperature decreases, since steel core is in elastic range, steel core section attenuates, and steel core is applied to aluminium strand The section of the pressure reduction of line, aluminum stranded conductor is also shunk, but since aluminum stranded conductor has occurred and that surrender hardening, the section of aluminum stranded conductor is not It is expanded because of the reduction of pressure, this results in generating gap between aluminum stranded conductor.
Rainwater, atmosphere, dirt, corrosive medium permeate gap between the aluminum stranded conductor of crimp head, and aluminum stranded conductor surface is made to generate oxygen Change, generate aluminum oxide, leads to contact resistance increase fever, ultimate failure at steel-cored aluminium strand splicing sleeve crimping.
In order to which the damage and the aluminium splicing sleeve crimp quality that solve the steel core that traditional compression bonding method is easy to appear are unstable etc. Problem, it is necessary to design a kind of novel embedding aluminium compression joint technique of the full tension of steel-cored aluminium strand, make steel-cored aluminium strand docking crimping more It is easy to implement, crimp quality is higher, and crimp head can lower labor intensity and engineering cost in order to avoid non-destructive testing.
Summary of the invention
The technical problem to be solved by the present invention is providing a kind of 7 strand steel-cored aluminium strand pressures of round wires concentric gallows empty conductor Method is connect, to solve problems of the prior art.
The technical scheme adopted by the invention is as follows: a kind of 7 strand steel-cored aluminium strand compression bonding methods of round wires concentric gallows empty conductor, Method includes the following steps:
1) aluminum stranded conductor of the both ends steel-cored aluminium strand of docking is cutd open and is removed, every end is cutd open except segment length=steel connects length of tube/2+ 20mm；
2) two connector of steel-cored aluminium strand is straightened to 10 meters, steel-cored aluminium strand one end connector is inserted in aluminium splicing sleeve, and will Aluminium splicing sleeve, which moves on to, does not influence next step procedure position；
3) one end steel-cored aluminium strand is penetrated in outer inlay aluminum pipe, outer inlay aluminum pipe inner hole is stepped hole, large diameter end court Connector, outer inlay aluminum pipe, which is moved to, does not influence next step procedure position；
4) conducting wire setting ring set is entered on the steel-cored aluminium strand of docking, conducting wire setting ring is fixed on steel core aluminum stranded conductor aluminium and is twisted Layer connects the place end inline layer aluminum pipe length+20mm；
5) it unclamps steel-cored aluminium strand and connects end aluminum stranded conductor layer, inline layer aluminum pipe is inserted in 7 strand steel cores, and by inline layer aluminium Pipe is entirely insertable between aluminum stranded conductor layer and steel core；
6) it twists by each aluminum stranded conductor layer of steel-cored aluminium strand to aluminum stranded conductor is repaired, outer inlay aluminum pipe is moved to steel core aluminum stranded conductor aluminium Twisted layer connects end, packs into conducting wire setting ring, reparation aluminum stranded conductor, inline layer aluminum pipe, steel core all in outer inlay aluminum pipe；
7) step 3) -6 is repeated), it completes inline layer aluminum pipe, outer inlay aluminum pipe on the steel-cored aluminium strand of other end docking and leads Then both ends steel-cored aluminium strand is docked in the assembling of linear location ring；
8) steel core embedding aluminum pipe is connected to be embedded into steel splicing sleeve；
9) the steel-core-aluminium steel strand wires of two docking are connected embedding aluminum pipe both ends from steel core to be inserted into, it is ensured that two steel-core-aluminium steel strand wires are inserted Enter deep equality；
10) steel splicing sleeve is crimped using crimp, so that steel core connects embedding aluminum pipe and tightly engages steel-cored aluminium strand surface And gap forms steel core pressure joint between filling steel splicing sleeve and steel-cored aluminium strand；
11) by aluminium splicing sleeve movable sleeving outside the outer inlay aluminum pipe that steel-cored aluminium strand two connects head；
12) aluminium splicing sleeve both ends pressure connection terminal is crimped using crimp, so that inlay aluminum pipe tightly engages outside two connecting ends Steel-cored aluminium strand and aluminium splicing sleeve, inline layer aluminum pipe tightly engage interior aluminum stranded conductor layer and steel strand wires, form aluminum stranded conductor pressure joint.
Stress is crimped after the crimping steel splicing sleeve of crimp in step 10):
If press machine non-stopping time after the crimping molding of steel core splicing sleeve, steel splicing sleeve inside radius are rfe, it is thick that steel connects tube hub Degree is dfe, the steel core twisted wire pitch diameter of thread is d2, the embedding aluminum pipe central diameter of steel core connecting is with a thickness of dal, the steel splicing sleeve trade mark is Q345；
According to the relationship of material trus stress σ and true strain ε
σ=E ε (1)
In formula (1), E---- is the Young's modulus of material；
After press machine shutdown is removed after the crimping molding of steel core splicing sleeve, if it is σ that steel core, which connects embedding aluminum pipe wall compression chord,1, Steel splicing sleeve inside radius is rfe+Δrfe, steel splicing sleeve center thickness is dfe+Δdfe, steel core twisted wire pitch diameter of thread radius of circle is R+ Δ R, steel core connect embedding aluminum pipe central diameter with a thickness of dal+Δdal
After press pressure releases after the crimping molding of steel core splicing sleeve, each thickness increment relationship is
ΔrfeΔ R=Δ dal (5)
After then press pressure releases after steel core splicing sleeve crimping molding, steel core, steel core connect embedding aluminum pipe, steel splicing sleeve it Between compression be
In formula (7):
σ1After press pressure releases after the crimping molding of ----steel core splicing sleeve,
Steel core, steel core connect embedding aluminum pipe, steel pipe compression, unit pa；
σ --- before press pressure releases after the crimping molding of-steel core splicing sleeve,
Steel core, steel core connect embedding aluminum pipe, steel pipe compression, unit pa；
rfeInside radius after the crimping of ----steel pipe, unit pa；
R---- steel core twisted wire pitch diameter of thread d2Half, unit mm；
dal----steel core connects embedding aluminum pipe equivalent thickness, unit mm；
EfeThe Young's modulus of ----steel；
EalThe Young's modulus of ----aluminium alloy.
Round wires concentric gallows empty conductor 7 aluminium amount s twisted between steel-cored aluminium strand of insertion after the crimping molding of steel core splicing sleeve, The trade mark that steel core connects embedding aluminum pipe is 5A05:
In formula (8), r---- steel core twisted wire steel wire radius, unit mm；
The steel core that insertion needs connects embedding aluminum pipe thickness
In formula (9), r---- steel core twisted wire steel wire radius, unit mm；
Then steel core connects embedding aluminum pipe with a thickness of δal
δal=δq+1 (10)
Steel core connects embedding aluminum pipe outer diameter DalFor
Dal=6r+1+2 δal (11)
In formula (11), r---- steel core twisted wire steel wire radius, unit mm；
It is two steel core twisted wire pitches that steel core, which connects embedding aluminum pipe length,；
Steel splicing sleeve uses the trade mark for Q345 high-strength steel；Steel connects tube thickness δfeFor
In formula (20),
Fb----conducting wire (or ground wire) calculates Fracture Force, unit N；
σsfe----steel pipe yield strength, unit Pa；
Dal----steel core connects embedding aluminum pipe outer diameter, unit mm；
Then steel connecting pipe outside diameter is
Dfe=Dal+2δfe (13)
It is that steel core connects embedding aluminum pipe length that steel, which connects length of tube,；
Crimp the crimping area of section that steel connects pipe mold:
Steel core crimps sectional area sx
In formula (14), r---- steel core twisted wire steel wire radius, unit mm；
Steel core connects embedding aluminum pipe section sqFor
In formula (15),
R---- steel core twisted wire steel wire radius, unit mm；
Dal---- steel core connects embedding aluminum pipe outer diameter, unit mm；
Steel splicing sleeve sectional area sgFor
In formula (16),
Dfe---- outer diameter of steel pipes, unit mm；
Dal---- steel core connects embedding aluminum pipe outer diameter, unit mm；
Crimp crimps area of section syFor
sy=sx+sq+sg (17)
Regular hexagon pressing mold side length α is
Regular hexagon pressing mold diagonal line b is 60 °=2a of b=a+2a cos (19)
Stress is crimped after crimp crimping aluminium splicing sleeve:
The crimping stress being subject to after crimp crimping aluminium splicing sleeve can be considered that thin-walled cylinder is by uniformly distributed in plastoelasticity Stress problems, the aluminium splicing sleeve trade mark are 5A05.If steel-cored aluminium strand is located in polar coordinate system, ρ is polar coordinates, by inlay aluminum pipe Remaining longitudinal stress after surrender after plastic deformation is σρ, lateral stress isThe inlay aluminum pipe trade mark is 5A05,1A99.Pressing mold moves Except the yield stress that rear aluminium splicing sleeve and outer inlay aluminum pipe are received is q2, inline layer pipe outer radius is r1, connecting aluminum pipe radius is R0:
Boundary condition requirement are as follows:
Design conditions are considered as axisymmetrical stress, then answer condition are as follows:
In formula (21):
σρ----aluminum stranded conductor is single by the remaining radial stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position Pa；
----aluminum stranded conductor is single by the remaining circumference stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position Pa；
----aluminum stranded conductor is single by remaining diameter ring cutting stress after being plastically deformed after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position Pa；
A, B, C---- constant (similarly hereinafter)；
It brings boundary condition (1) into, solves:
In formula (22):
r1----inline layer aluminum pipe outer radius, original radius, unit mm；
R0----aluminium splicing sleeve outer radius, original radius, unit mm；
q1The yield stress that ----inline layer aluminium is subject to, unit Pa；
q2The yield stress that ----aluminium splicing sleeve and outer inlay aluminum pipe are subject to, unit Pa；
Interlayer remnants radial stress can be acquired and circumferential direction is answered by enabling B=0 that constant A, 2C that formula (22) solves are substituted into formula (21) Power are as follows:
In formula (23):
σρ----aluminum stranded conductor is single by the remaining radial stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position pa；
----aluminum stranded conductor is single by the remaining circumference stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position pa；
r1----inline layer aluminum pipe outer radius, original radius, unit mm；
R0----aluminium splicing sleeve outer radius, original radius, unit mm；
q1The yield stress that ----inline layer aluminium is subject to, unit Pa；
q2The yield stress that ----aluminium splicing sleeve and outer inlay aluminum pipe are subject to, unit Pa；
There are gaps mutually displacement occurs under the action of circumferential residual stress and radial residual stress, between twisted wire, then counts Calculate diameter are as follows:
In formula (24):
uρRadial displacement between ----twisted wire, unit mm；
Circumferential displacement between ----twisted wire, unit mm；
E---- steel-cored aluminium strand elasticity modulus, unit Pa；
Since thin-walled cylinder is belonged to plane strain problems by well-distributed pressure problem, therefore in above formula Instead of then having
The outer radius of inline layer aluminum pipe is after crimping
The outer radius of outer inlay aluminum pipe is after crimping
The knots modification of radial thickness is
Calculate radius RH=R- Δ R (29)
In formula (25)-formula (29)
σρ----aluminum stranded conductor is single by the remaining radial stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position Pa；
----aluminum stranded conductor is single by the remaining circumference stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position Pa；
urThe outer radius of inline layer pipe, unit mm after ----crimping；
uRThe outer radius of outer inlay aluminum pipe, unit mm after ----crimping；
μ --- the Poisson's ratio of-aluminium takes 0.33；
The knots modification of Δ R---- radial thickness, unit mm；
RHRadius, unit mm are calculated after ----crimping.
The aluminium amount that steel strand wires are embedded in after the crimping molding of inline layer aluminum pipe is D, and angle is θ, steel strand wires between two strands of steel strand wires Outermost layer radical is n, and single steel strand radius is r, and the trade mark of selected inline layer aluminum pipe is 5A05, then:
In formula (31), r---- single steel strand radius, unit mm；
If the aluminium amount for being embedded in aluminum stranded conductor after crimping molding is T, angle is β between two strands of aluminum stranded conductors of innermost layer, and aluminum stranded conductor is most Internal layer radical is u, and single aluminum stranded conductor radius is r1, the trade mark of selected inline layer aluminum pipe is 5A05, then:
In formula (33), r---- single steel strand radius, unit mm；
R2----single aluminum stranded conductor radius, unit mm；
Then total embedded quantity is
W=D+T (34)
In formula (34): being embedded in the aluminium amount of steel strand wires, unit mm after D---- crimping molding2；
T---- sets the aluminium amount of insertion aluminum stranded conductor after crimping molding, unit mm2；
Then it is embedded in unlined aluminium tube thickness are as follows:
In formula (35), r---- single steel strand radius, unit mm；
δal=δq+1 (36)
Inline layer aluminum pipe outer diameter are as follows:
Dal=6r+1+2 δal (37)
In formula (37), r---- single steel strand radius, unit mm；
The steel core pitch diameter length that inline layer aluminum pipe length is 1.5 times, the selection trade mark are 5A05；
Outer inlay aluminum pipe includes large diameter section and small interior through section, and large diameter section wraps up inline layer aluminum pipe section and small interior through Duan Wei Wrap up inline layer aluminum pipe section；
The outer inlay aluminum pipe of inline layer aluminum pipe section is wrapped up, it is 1A99 that outer inlay aluminum pipe, which selects the trade mark, wraps up inline layer aluminum pipe The radius of single aluminum stranded conductor is r in the outer inlay aluminum pipe of section1, outer inlay aluminum pipe internal diameter
R=Dal+2nr2 (38)
In formula (38), Dal----inline layer aluminum pipe outer diameter, unit mm；
r2----single aluminum stranded conductor radius, mm；
The n---- aluminum stranded conductor number of plies；
The aluminium amount of aluminum stranded conductor is embedded in after crimping molding
In formula (39), two strands of aluminum stranded conductor angles of α ----outermost layer, unit °；
The outer inlay aluminum pipe internal diameter of R----, unit mm；
r2----single aluminum stranded conductor radius, unit mm；
M---- outer layer aluminum stranded conductor radical；
It is embedded in the outer layer aluminum pipe thickness needed
δal'=δq1+1 (41)
In formula (40), (41), the outer inlay aluminum pipe internal diameter of R----, unit mm；
Outer inlay aluminum pipe outer diameter is
Dal'=2R+1+2 δal' (42)
In formula (42), the outer inlay aluminum pipe internal diameter of R----, unit mm；
δal' ----outer inlay aluminum pipe thickness, unit mm；
The length for wrapping up the outer inlay aluminum pipe of inline layer aluminum pipe section is equal to inline layer aluminum pipe length, and outer inlay aluminum pipe selects board Number be 1A99.
The thickness of the outer inlay aluminum pipe of inline layer aluminum pipe section is not wrapped up, and it is 1A99 that outer inlay aluminum pipe, which selects the trade mark:
δal1=(Dal′-d-1)/2 (43)
In formula (43), Dal' ----outer inlay aluminum pipe outer diameter, unit mm；
D---- steel-cored aluminium strand outer diameter, unit mm；
The length for not wrapping up the outer inlay aluminum pipe of inline layer aluminum pipe section is 1.1 times of pitch lengths, and outer inlay aluminum pipe selects board Number be 1A99.
Conducting wire setting ring length takes 10mm, and internal diameter, which is equal to, does not wrap up inline layer aluminium section lead outer diameter, and outer diameter is less than in package The outer inlay aluminum pipe internal diameter of inlay aluminum pipe section, it is 1A99 that conducting wire shaping ring, which selects the trade mark,.And place it in package inline layer aluminum pipe Section outer inlay aluminum pipe and do not wrap up the outer inlay aluminum pipe joint of inline layer aluminum pipe section to reach fixed conducting wire, prevent its broken lot Effect.
Aluminium connects tube thickness:
Total specified pull-off force of steel-cored aluminium strand is Fb, the yield strength of aluminium splicing sleeve is σal, then aluminium splicing sleeve with a thickness of δfeFor the trade mark that aluminium splicing sleeve is selected is 5A05:
In formula (44), Fb----calculate pull-off force, unit N；
Dal' ----outer inlay aluminum pipe outer diameter, unit mm；
σalThe yield strength of ----aluminium splicing sleeve, unit Mpa；
Aluminium connects pipe outside diameter
DAL=Dal'+2δal+1 (45)
In formula (45), DAL----aluminium connects pipe outside diameter, unit mm；
Dal' ----outer inlay aluminum pipe outer diameter, unit mm；
δal----aluminium connects tube thickness, unit mm；
Aluminium connects length of tube: 2 outer inlay aluminum pipe total lengths+steel connects length of tube+tolerance, the trade mark that aluminium splicing sleeve is selected For 5A05.
The area of crimp crimping aluminium splicing sleeve:
Inline layer aluminum pipe crimps sectional area
In formula (46), Sj' ----inline layer aluminum pipe crimps sectional area, unit mm2；
Dal----inline layer aluminum pipe outer diameter, unit mm；
R---- single steel strand radius, unit mm；
Outer layer inlay aluminum pipe sectional area is SqAre as follows:
In formula (47), Dal' ----outer inlay aluminum pipe outer diameter, unit mm；
The outer inlay aluminum pipe internal diameter of R----, unit mm；
Aluminium splicing sleeve sectional area is Sl:
DAL'=Dal′+1
In formula (48), DAL----aluminium connects pipe outside diameter, unit mm；
DAL' ----aluminium connects bore, unit mm；
Then crimp sectional area is SmAre as follows:
Sm=Sq+Sj+Sl+Sal-W-S (49)
Sj----inline layer aluminum pipe sectional area, unit mm2, see formula (46)；
Sq----outer inlay aluminum pipe sectional area, unit mm2, see formula (47)；
Sl----aluminium splicing sleeve sectional area, unit mm2, see formula (48)；
Sal----steel-cored aluminium strand sectional area, unit mm2；
W--- inline layer aluminum pipe embedded quantity, unit mm2, see formula (34)；
The outer inlay aluminum pipe embedded quantity of S----, unit mm2, see formula (39)；
Regular hexagon pressing mold side length a are as follows:
Regular hexagon pressing mold diagonal line b1Are as follows:
b160 °=2a of=a+2a cos (51)
Pressure joint calculation of contact resistance:
(1) contact area
Contact length is calculated by the pitch diameter of thread, then it is l that every molding, which connects middle electrical path length,j, altogether crimp b mould, contact length with it is embedding Layer aluminium connects length of tube lqProduct be inlay aluminium splicing sleeve aluminum stranded conductor contact area Sc:
Sc=b × lj×lq (52)
In formula (52), ljElectrical path length in ----crimping, unit mm；
lq----outer inlay aluminum pipe length, unit mm；
B---- crimps modulus；
The contact area S of inlay aluminium splicing sleeve aluminum stranded conductor when calculatingcGreater than twice conductor cross-section area；
(2) contact resistance
Since film resistance is difficult to calculate, therefore contact resistance is calculated with empirical equation, it may be assumed that
F=σρ·Sc (53)
In formula (53), F-contact pressure, unit N；
σρ----aluminum stranded conductor is single by the remaining radial stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position kN；
ScThe contact area of-inlay aluminium splicing sleeve aluminum stranded conductor, unit mm2；
In formula (54), Rj- contact resistance, unit Ω；
F---- contact pressure, unit N；
L---- constant related with contact form, for point contact l=0.5-0.7, face contact l=1；
K---- constant related with contact material, contact surface processing method, contact surface situation, when contact surface does not have oxygen Change, the K value between aluminium and aluminium is (3-6.7) × 10-3。
Beneficial effects of the present invention: compared with prior art, the present invention increases between the steel strand wires of docking are socketed steel splicing sleeve Add steel core to connect embedding aluminum pipe, steel strand wires and aluminum stranded conductor interlayer increase by one layer of inline layer aluminum pipe, aluminium splicing sleeve and steel-cored aluminium strand it Between increase by one layer of outer inlay aluminum pipe, high moulding and high confficient of static friction using aluminum pipe, avoid steel strand wires steel wire and aluminium strand Line layer aluminium wire and steel splicing sleeve and steel-cored aluminium strand crimping when occur steel-cored aluminium strand weighed wounded, be under-voltage, loose stock phenomenon, together When meet connector again hold force request, make steel-cored aluminium strand crimping be easier to implement, crimp quality is higher, crimp head can in order to avoid Labor intensity and engineering cost are lowered in non-destructive testing.
Detailed description of the invention
Fig. 1 is aluminium splicing sleeve structural schematic diagram, and both ends are crimp segment in figure, and middle part is non-crimp segment；
Fig. 2 is aluminium splicing sleeve crimp segment cross section structure schematic diagram；
Fig. 3 is the non-crimp segment cross section structure schematic diagram of aluminium splicing sleeve；
Fig. 4 is inline layer aluminium pipe structure schematic diagram；
Fig. 5 is that inline layer aluminum pipe wraps up embedded interval aluminum pipe cross section structure schematic diagram；
Fig. 6 is that inline layer aluminum pipe does not wrap up inline layer aluminum pipe section cross section structure schematic diagram；
Fig. 7 is the qualitative ring structure schematic diagram of conducting wire；
Fig. 8 is the qualitative ring left view structural representation of conducting wire；
Fig. 9 is inline layer aluminium pipe structure schematic diagram；
Figure 10 is inline layer aluminum pipe left view structural representation；
Figure 11 is that steel-cored aluminium strand is connected place's structural schematic diagram；
Figure 12 is the 1-1 schematic cross-section in Figure 11；
Figure 13 is the 2-2 schematic cross-section in Figure 11；
Figure 14 is the 3-3 schematic cross-section in Figure 11；
Figure 15 is the 4-4 schematic cross-section in Figure 11.
Specific embodiment
With reference to the accompanying drawing and the present invention is described further in specific embodiment.
Embodiment 1: as shown in figures 1-15, a kind of 7 strand steel-cored aluminium strand crimping structures of round wires concentric gallows empty conductor, packet It includes aluminium splicing sleeve 1, steel splicing sleeve 2, steel core and connects embedding aluminum pipe 3, inline layer aluminum pipe 4, outer inlay aluminum pipe 5 and the qualitative ring 6 of conducting wire, steel Core connects embedding aluminum pipe 3 and is socketed on the steel strand wires 7 of two docking, and steel connects pipe sleeve 2 and connects outside the embedding aluminum pipe 3 of steel core connecting, crimping Steel connects pipe sleeve 2 and the embedding aluminum pipe 3 of steel core connecting is made to fit closely the formation steel strand wires pressure joint of steel strand wires 3；By inline layer aluminum pipe 4 It is placed between the steel strand wires 7 and interior aluminum stranded conductor layer 8 for docking every end steel-cored aluminium strand, docks outside being socketed with outside every end steel-cored aluminium strand Inlay aluminum pipe 5 on the two outer inlay aluminum pipes 5 that aluminium splicing sleeve 1 is socketed on the steel-cored aluminium strand of two docking, crimps aluminium splicing sleeve 1 Both ends make that inline layer aluminum pipe 4 fits closely steel strand wires 7 and interior aluminum stranded conductor layer 8, outer inlay aluminum pipe 5 fit closely steel-cored aluminium strand With aluminium splicing sleeve 1, form aluminum stranded conductor pressure joint, steel strand wires pressure joint is located in aluminium splicing sleeve, steel strand wires pressure joint with Aluminum stranded conductor pressure joint collectively constitutes 7 embedding aluminium pressure joints of the full tension of strand steel-cored aluminium strand of round wires concentric gallows empty conductor.
1 both ends of aluminium splicing sleeve are crimp segment 9, are in class hexagon after the crimping of crimp segment 9, and outer 5 inner hole of inlay aluminum pipe is step Hole, towards at connector docking, package inline layer aluminum pipe section diameter of bore is less than that not wrap up inline layer aluminum pipe section inner hole straight at large diameter end Diameter is convenient for Fast Installation.
Preferably, above-mentioned steel splicing sleeve 2 and steel core connect embedding 3 equal length of aluminum pipe, are two steel strand wires pitches.
Inline layer aluminum pipe 4, outer inlay aluminum pipe 5 provide crimping portion steel wire, aluminium wire insertion packing material respectively, are closed using aluminium Tap pressure is changed into tension stress by the high confficient of static friction of gold, and that improves connector holds power.
Embodiment 2: a kind of 7 strand steel-cored aluminium strand compression bonding methods of round wires concentric gallows empty conductor, this method includes following Step:
1) aluminum stranded conductor of the both ends steel-cored aluminium strand of docking is cutd open and is removed, every end is cutd open except segment length=steel connects length of tube/2+ 20mm；
2) two connector of steel-cored aluminium strand is straightened to 10 meters, steel-cored aluminium strand one end connector is inserted in aluminium splicing sleeve, and will Aluminium splicing sleeve, which moves on to, does not influence next step procedure position；
3) one end steel-cored aluminium strand is penetrated in outer inlay aluminum pipe, outer inlay aluminum pipe inner hole is stepped hole, large diameter end court Connector, outer inlay aluminum pipe, which is moved to, does not influence next step procedure position；
4) conducting wire setting ring set is entered on the steel-cored aluminium strand of docking, conducting wire setting ring is fixed on steel core aluminum stranded conductor aluminium and is twisted Layer connects the place end inline layer aluminum pipe length+20mm；
5) it unclamps steel-cored aluminium strand and connects end aluminum stranded conductor layer, inline layer aluminum pipe is inserted in 7 strand steel cores, and by inline layer aluminium Pipe is entirely insertable between aluminum stranded conductor layer and steel core；
6) it twists by each aluminum stranded conductor layer of steel-cored aluminium strand to aluminum stranded conductor is repaired, outer inlay aluminum pipe is moved to steel core aluminum stranded conductor aluminium Twisted layer connects end, packs into conducting wire setting ring, reparation aluminum stranded conductor, inline layer aluminum pipe, steel core all in outer inlay aluminum pipe；
7) step 3) -6 is repeated), it completes inline layer aluminum pipe, outer inlay aluminum pipe on the steel-cored aluminium strand of other end docking and leads Then both ends steel-cored aluminium strand is docked in the assembling of linear location ring；
8) steel core embedding aluminum pipe is connected to be embedded into steel splicing sleeve；
9) the steel-core-aluminium steel strand wires of two docking are connected embedding aluminum pipe both ends from steel core to be inserted into, it is ensured that two steel-core-aluminium steel strand wires are inserted Enter deep equality；
10) steel splicing sleeve is crimped using crimp, so that steel core connects embedding aluminum pipe and tightly engages steel-cored aluminium strand surface And gap forms steel core pressure joint between filling steel splicing sleeve and steel-cored aluminium strand；
11) by aluminium splicing sleeve movable sleeving outside the outer inlay aluminum pipe that steel-cored aluminium strand two connects head；
12) aluminium splicing sleeve both ends pressure connection terminal is crimped using crimp, so that inlay aluminum pipe tightly engages outside two connecting ends Steel-cored aluminium strand and aluminium splicing sleeve, inline layer aluminum pipe tightly engage interior aluminum stranded conductor layer and steel strand wires, form aluminum stranded conductor pressure joint.
Novel 7 embedding aluminium crimping structures of the full tension of strand steel-cored aluminium strand of round wires concentric gallows empty conductor, it is connected by aluminium Pipe 1, Quan Zhangli steel splicing sleeve 2, steel core connect embedding aluminum pipe 3, inline layer aluminum pipe 4, outer inlay aluminum pipe 5 and conducting wire setting ring 6 and constitute, See Figure 11, aluminium splicing sleeve 1 provides round wires concentric gallows empty conductor and docks main tension stress and tap pressure, inline layer aluminum pipe 4, Outer inlay aluminum pipe 5 provides crimping portion steel wire, aluminium wire insertion packing material respectively, will be connect using the high confficient of static friction of aluminium alloy Head pressure transition is tension stress, and that improves connector holds power.
Since inlay aluminum pipe hardness is low, it is concentric that 7 strand steel-cored aluminium strand round wires of round wires concentric gallows empty conductor will not be weighed wounded 7 strand steel-cored aluminium strands of gallows empty conductor, as long as mold is matched with aluminium hydraulic pressed connecting pipe, crimp head is not in under-voltage, loose stock phenomenon, can Not have to carry out non-destructive testing crimp head.
Stress is crimped after the crimping steel splicing sleeve of crimp in step 10):
If press machine non-stopping time after the crimping molding of steel core splicing sleeve, steel splicing sleeve inside radius are rfe, it is thick that steel connects tube hub Degree is dfe, the steel core twisted wire pitch diameter of thread is d2, the embedding aluminum pipe central diameter of steel core connecting is with a thickness of dal, the steel splicing sleeve trade mark is Q345；
According to the relationship of material trus stress σ and true strain ε
σ=E ε (1)
In formula (1), E---- is the Young's modulus of material；
After press machine shutdown is removed after the crimping molding of steel core splicing sleeve, if it is σ that steel core, which connects embedding aluminum pipe wall compression chord,1, Steel splicing sleeve inside radius is rfe+Δrfe, steel splicing sleeve center thickness is dfe+Δdfe, steel core twisted wire pitch diameter of thread radius of circle is R+ Δ R, steel core connect embedding aluminum pipe central diameter with a thickness of dal+Δdal
After press pressure releases after the crimping molding of steel core splicing sleeve, each thickness increment relationship is
ΔrfeΔ R=Δ dal (5)
After then press pressure releases after steel core splicing sleeve crimping molding, steel core, steel core connect embedding aluminum pipe, steel splicing sleeve it Between compression be
In formula (7):
σ1After press pressure releases after the crimping molding of ----steel core splicing sleeve,
Steel core, steel core connect embedding aluminum pipe, steel pipe compression, unit pa；
σ --- before press pressure releases after the crimping molding of-steel core splicing sleeve,
Steel core, steel core connect embedding aluminum pipe, steel pipe compression, unit pa；
rfeInside radius after the crimping of ----steel pipe, unit pa；
R---- steel core twisted wire pitch diameter of thread d2Half, unit mm；
dal----steel core connects embedding aluminum pipe equivalent thickness, unit mm；
EfeThe Young's modulus of ----steel；
EalThe Young's modulus of ----aluminium alloy.
Round wires concentric gallows empty conductor 7 aluminium amount s twisted between steel-cored aluminium strand of insertion after the crimping molding of steel core splicing sleeve, The trade mark that steel core connects embedding aluminum pipe is 5A05:
In formula (8), r---- steel core twisted wire steel wire radius, unit mm；
The steel core that insertion needs connects embedding aluminum pipe thickness
In formula (9), r---- steel core twisted wire steel wire radius, unit mm；
Then steel core connects embedding aluminum pipe with a thickness of δal
δal=δq+1 (10)
Steel core connects embedding aluminum pipe outer diameter DalFor
Dal=6r+1+2 δal (11)
In formula (11), r---- steel core twisted wire steel wire radius, unit mm；
It is two steel core twisted wire pitches that steel core, which connects embedding aluminum pipe length,；
Steel splicing sleeve uses the trade mark for Q345 high-strength steel, and steel connects tube thickness δfeFor
In formula (20),
Fb----conducting wire (or ground wire) calculates Fracture Force, unit N；
σsfe----steel pipe yield strength, unit Pa；
Dal----steel core connects embedding aluminum pipe outer diameter, unit mm；
Then steel connecting pipe outside diameter is
Dfe=Dal+2δfe (13)
It is that steel core connects embedding aluminum pipe length that steel, which connects length of tube,；
Crimp the crimping area of section that steel connects pipe mold:
Steel core crimps sectional area sx
In formula (14), r---- steel core twisted wire steel wire radius, unit mm；
Steel core connects embedding aluminum pipe section sqFor
In formula (15),
R---- steel core twisted wire steel wire radius, unit mm；
Dal----steel core connects embedding aluminum pipe outer diameter, unit mm；
Steel splicing sleeve sectional area sgFor
In formula (16),
Dfe----outer diameter of steel pipes, unit mm；
Dal----steel core connects embedding aluminum pipe outer diameter, unit mm；
Crimp crimps area of section syFor
sy=sx+sq+sg (17)
Regular hexagon pressing mold side length α is
Regular hexagon pressing mold diagonal line b is 60 °=2a of b=a+2a cos (19).
Stress is crimped after crimp crimping aluminium splicing sleeve:
The crimping stress being subject to after crimp crimping aluminium splicing sleeve can be considered that thin-walled cylinder is by uniformly distributed in plastoelasticity Stress problems, the aluminium splicing sleeve trade mark are 5A05.If steel-cored aluminium strand is located in polar coordinate system, ρ is polar coordinates, by inlay aluminum pipe Remaining longitudinal stress after surrender after plastic deformation is σρ, lateral stress isThe inlay aluminum pipe trade mark is 5A05,1A99.Pressing mold moves Except the yield stress that rear aluminium splicing sleeve and outer inlay aluminum pipe are received is q2, inline layer pipe outer radius is r1, connecting aluminum pipe radius is R0:
Boundary condition requirement are as follows:
Design conditions are considered as axisymmetrical stress, then answer condition are as follows:
In formula (21):
σρ----aluminum stranded conductor is single by the remaining radial stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position Pa；
----aluminum stranded conductor is single by the remaining circumference stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position Pa；
----aluminum stranded conductor is single by remaining diameter ring cutting stress after being plastically deformed after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position Pa；
A, B, C---- constant (similarly hereinafter)；
It brings boundary condition (1) into, solves:
In formula (22):
r1----inline layer aluminum pipe outer radius, original radius, unit mm；
R0----aluminium splicing sleeve outer radius, original radius, unit mm；
q1The yield stress that ----inline layer aluminium is subject to, unit Pa；
q2The yield stress that ----aluminium splicing sleeve and outer inlay aluminum pipe are subject to, unit Pa；
Interlayer remnants radial stress can be acquired and circumferential direction is answered by enabling B=0 that constant A, 2C that formula (22) solves are substituted into formula (21) Power are as follows:
In formula (23):
σρ----aluminum stranded conductor is single by the remaining radial stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position pa；
----aluminum stranded conductor is single by the remaining circumference stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position pa；
r1----inline layer aluminum pipe outer radius, original radius, unit mm；
R0----aluminium splicing sleeve outer radius, original radius, unit mm；
q1The yield stress that ----inline layer aluminium is subject to, unit Pa；
q2The yield stress that ----aluminium splicing sleeve and outer inlay aluminum pipe are subject to, unit Pa；
There are gaps mutually displacement occurs under the action of circumferential residual stress and radial residual stress, between twisted wire, then counts Calculate diameter are as follows:
In formula (24):
uρRadial displacement between ----twisted wire, unit mm；
Circumferential displacement between ----twisted wire, unit mm；
E---- steel-cored aluminium strand elasticity modulus, unit Pa；
Since thin-walled cylinder is belonged to plane strain problems by well-distributed pressure problem, therefore in above formulaInstead of then having
The outer radius of inline layer aluminum pipe is after crimping
The outer radius of outer inlay aluminum pipe is after crimping
The knots modification of radial thickness is
Calculate radius RH=R- Δ R (29)
In formula (25)-formula (29)
σρ----aluminum stranded conductor is single by the remaining radial stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position Pa；
----aluminum stranded conductor is single by the remaining circumference stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position Pa；
urThe outer radius of inline layer pipe, unit mm after ----crimping；
uRThe outer radius of outer inlay aluminum pipe, unit mm after ----crimping；
μ --- the Poisson's ratio of-aluminium takes 0.33；
The knots modification of Δ R---- radial thickness, unit mm；
RHRadius, unit mm are calculated after ----crimping.
The aluminium amount that steel strand wires are embedded in after the crimping molding of inline layer aluminum pipe is D, and angle is θ, steel strand wires between two strands of steel strand wires Outermost layer radical is n, and single steel strand radius is r, and the trade mark of selected inline layer aluminum pipe is 5A05, then:
In formula (31), r---- single steel strand radius, unit mm；
If the aluminium amount for being embedded in aluminum stranded conductor after crimping molding is T, angle is β between two strands of aluminum stranded conductors of innermost layer, and aluminum stranded conductor is most Internal layer radical is u, and single aluminum stranded conductor radius is r1, the trade mark of selected inline layer aluminum pipe is 5A05, then:
In formula (33), r---- single steel strand radius, unit mm；
R2----single aluminum stranded conductor radius, unit mm；
Then total embedded quantity is
W=D+T (34)
In formula (34): being embedded in the aluminium amount of steel strand wires, unit mm after D---- crimping molding2；
T---- sets the aluminium amount of insertion aluminum stranded conductor after crimping molding, unit mm2；
Then it is embedded in unlined aluminium tube thickness are as follows:
In formula (35), r---- single steel strand radius, unit mm；
δal=δq+1 (36)
Inline layer aluminum pipe outer diameter are as follows:
Dal=6r+1+2 δal (37)
In formula (37), r---- single steel strand radius, unit mm；
The steel core pitch diameter length that inline layer aluminum pipe length is 1.5 times, the selection trade mark are 5A05；
Outer inlay aluminum pipe includes large diameter section and small interior through section, and large diameter section wraps up inline layer aluminum pipe section and small interior through Duan Wei Wrap up inline layer aluminum pipe section；
The outer inlay aluminum pipe 1 of inline layer aluminum pipe section is wrapped up, it is 1A99 that outer inlay aluminum pipe 1, which selects the trade mark:
The radius for wrapping up single aluminum stranded conductor in the outer inlay aluminum pipe 1 of inline layer aluminum pipe section is r1, outer inlay aluminum pipe internal diameter
R=Dal+2nr2 (38)
In formula (38), Dal----inline layer aluminum pipe outer diameter, unit mm；
r2----single aluminum stranded conductor radius, mm；
The n---- aluminum stranded conductor number of plies；
The aluminium amount of aluminum stranded conductor is embedded in after crimping molding
In formula (39), two strands of aluminum stranded conductor angles of α ----outermost layer, unit °；
The outer inlay aluminum pipe internal diameter of R----, unit mm；
r2----single aluminum stranded conductor radius, unit mm；
M---- outer layer aluminum stranded conductor radical；
It is embedded in the outer layer aluminum pipe thickness needed
δal'=δq1+1 (41)
In formula (40), (41), the outer inlay aluminum pipe internal diameter of R----, unit mm；
Outer inlay aluminum pipe outer diameter is
Dal'=2R+1+2 δal' (42)
In formula (42), the outer inlay aluminum pipe internal diameter of R----, unit mm；
δal' ----outer inlay aluminum pipe thickness, unit mm；
The length for wrapping up the outer inlay aluminum pipe 1 of inline layer aluminum pipe section is equal to inline layer aluminum pipe length, and outer inlay aluminum pipe 1 is selected The trade mark is 1A99.
The outer inlay aluminum pipe 2 of inline layer aluminum pipe section is not wrapped up, and it is 1A99 that outer inlay aluminum pipe 2, which selects the trade mark:
δal1=(Dal′-d-1)/2 (43)
In formula (43), Dal' ----outer inlay aluminum pipe outer diameter, unit mm；
D---- steel-cored aluminium strand outer diameter, unit mm；
The length for not wrapping up the outer inlay aluminum pipe 2 of inline layer aluminum pipe section is 1.1 times of pitch lengths, outer inlay aluminum pipe (2) choosing It is 1A99 with the trade mark.
Conducting wire setting ring length takes 10mm, and internal diameter, which is equal to, does not wrap up inline layer aluminium section lead outer diameter, and outer diameter is less than in package Outer 1 internal diameter of inlay aluminum pipe of inlay aluminum pipe section, it is 1A99 that conducting wire shaping ring, which selects the trade mark,.And place it in package inline layer aluminum pipe The outer inlay aluminum pipe 1 of section, to reach fixed conducting wire, prevents it from dissipating with outer 1 joint of inlay aluminum pipe for not wrapping up inline layer aluminum pipe section The effect of stock.
Aluminium connects tube thickness:
Total specified pull-off force of steel-cored aluminium strand is Fb, the yield strength of aluminium splicing sleeve is σal, then aluminium splicing sleeve with a thickness of δfeFor the trade mark that aluminium splicing sleeve is selected is 5A05:
In formula (44), Fb----calculate pull-off force, unit N；
Dal' ----outer inlay aluminum pipe outer diameter, unit mm；
σalThe yield strength of ----aluminium splicing sleeve, unit Mpa；
Aluminium connects pipe outside diameter
DAL=Dal'+2δal+1 (45)
In formula (45), DAL----aluminium connects pipe outside diameter, unit mm；
Dal' ----outer inlay aluminum pipe outer diameter, unit mm；
δal----aluminium connects tube thickness, unit mm；
Aluminium connects length of tube: 2 outer inlay aluminum pipe total lengths+steel connects length of tube+tolerance, the trade mark that aluminium splicing sleeve is selected For 5A05.
The area of crimp crimping aluminium splicing sleeve:
Inline layer aluminum pipe crimps sectional area
In formula (46), Sj' ----inline layer aluminum pipe crimps sectional area, unit mm2；
Dal----inline layer aluminum pipe outer diameter, unit mm；
R---- single steel strand radius, unit mm；
Outer layer inlay aluminum pipe sectional area is SqAre as follows:
In formula (47), Dal' ----outer inlay aluminum pipe outer diameter, unit mm；
The outer inlay aluminum pipe internal diameter of R----, unit mm；
Aluminium splicing sleeve sectional area is Sl:
DAL'=Dal′+1
In formula (48), DAL----aluminium connects pipe outside diameter, unit mm；
DAL' ----aluminium connects bore, unit mm；
Then crimp sectional area is SmAre as follows:
Sm=Sq+Sj+Sl+Sal-W-S (49)
Sj----inline layer aluminum pipe sectional area, unit mm2, see formula (46)；
Sq----outer inlay aluminum pipe sectional area, unit mm2, see formula (47)
Sl----aluminium splicing sleeve sectional area, unit mm2, see formula (48)
Sal----steel-cored aluminium strand sectional area, unit mm2；
W--- inline layer aluminum pipe embedded quantity, unit mm2, see formula (34)；
The outer inlay aluminum pipe embedded quantity of S----, unit mm2, see formula (39)；
Regular hexagon pressing mold side length a are as follows:
Regular hexagon pressing mold diagonal line b1Are as follows:
b160 °=2a of=a+2a cos (51)
Pressure joint calculation of contact resistance:
(1) contact area
Contact length is calculated by the pitch diameter of thread, then it is l that every molding, which connects middle electrical path length,j, altogether crimp b mould, contact length with it is embedding Layer aluminium connects length of tube lqProduct be inlay aluminium splicing sleeve aluminum stranded conductor contact area Sc:
Sc=b × lj×lq (52)
In formula (52)
ljElectrical path length in ----crimping, unit mm；
lq----outer inlay aluminum pipe length, unit mm；
B---- crimps modulus；
The contact area S of inlay aluminium splicing sleeve aluminum stranded conductor when calculatingcGreater than twice conductor cross-section area；
(2) contact resistance
Since film resistance is difficult to calculate, therefore contact resistance is calculated with empirical equation, it may be assumed that
F=σρ·Sc (53)
In formula (53), F-contact pressure, unit N；
σρ----aluminum stranded conductor is single by the remaining radial stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve Position kN；
ScThe contact area of-inlay aluminium splicing sleeve aluminum stranded conductor, unit mm2；
In formula (54), Rj- contact resistance, unit Ω；
F---- contact pressure, unit N；
L---- constant related with contact form, for point contact l=0.5-0.7, face contact l=1；
K---- constant related with contact material, contact surface processing method, contact surface situation, when contact surface does not have oxygen Change, the K value between aluminium and aluminium is (3-6.7) × 10-3。
Table 1, steel-cored aluminium strand parameter
Table 2, steel core connect embedding aluminum pipe parameter and calculate
Table 3, steel splicing sleeve parameter calculate
Table 4, steel core connect embedding aluminum pipe parameter and calculate
Table 5, inside and outside inlay aluminum pipe parameter calculate
Table 6, aluminium splicing sleeve parameter calculate
Table 7, pressing mold parameter calculate
Crimping length parameter under table 8, contact resistance, pull-off force consider calculates
The above description is merely a specific embodiment, but scope of protection of the present invention is not limited thereto, any Those familiar with the art in the technical scope disclosed by the present invention, can easily think of the change or the replacement, and should all contain Within protection scope of the present invention, therefore, protection scope of the present invention should be based on the protection scope of the described claims lid.

Claims (9)

1. a kind of 7 strand steel-cored aluminium strand compression bonding methods of round wires concentric gallows empty conductor, it is characterised in that: this method includes following Step:
1) aluminum stranded conductor of the both ends steel-cored aluminium strand of docking is cutd open and is removed, every end is cutd open except segment length=steel connects length of tube/2+20mm；
2) two connector of steel-cored aluminium strand is straightened to 10 meters, steel-cored aluminium strand one end connector is inserted in aluminium splicing sleeve, and aluminium is connect Continuous pipe, which moves on to, does not influence next step procedure position；
3) one end steel-cored aluminium strand is penetrated in outer inlay aluminum pipe, outer inlay aluminum pipe inner hole is stepped hole, large diameter end towards connector, Outer inlay aluminum pipe, which is moved to, does not influence next step procedure position；
4) conducting wire setting ring set is entered on the steel-cored aluminium strand of docking, conducting wire setting ring is fixed on steel core aluminum stranded conductor aluminium twisted layer and is connect The place continuous end inline layer aluminum pipe length+20mm；
5) it unclamps steel-cored aluminium strand and connects end aluminum stranded conductor layer, inline layer aluminum pipe is inserted in 7 strand steel cores, and inline layer aluminum pipe is complete Portion is inserted between aluminum stranded conductor layer and steel core；
6) it twists by each aluminum stranded conductor layer of steel-cored aluminium strand to aluminum stranded conductor is repaired, outer inlay aluminum pipe is moved to steel core aluminum stranded conductor aluminium twisted layer End is connected, packs into conducting wire setting ring, reparation aluminum stranded conductor, inline layer aluminum pipe, steel core all in outer inlay aluminum pipe；
7) step 3) -6 is repeated), it is fixed to complete inline layer aluminum pipe, outer inlay aluminum pipe and conducting wire on the steel-cored aluminium strand of other end docking Property ring assembling, then dock both ends steel-cored aluminium strand；
8) steel core embedding aluminum pipe is connected to be embedded into steel splicing sleeve；
9) the steel-core-aluminium steel strand wires of two docking are connected embedding aluminum pipe both ends from steel core to be inserted into, it is ensured that the insertion of two steel-core-aluminium steel strand wires is deep It spends equal；
10) steel splicing sleeve is crimped using crimp, so that steel core connects embedding aluminum pipe and tightly engages steel-cored aluminium strand surface and fill out It fills gap between steel splicing sleeve and steel-cored aluminium strand and forms steel core pressure joint；
11) by aluminium splicing sleeve movable sleeving outside the outer inlay aluminum pipe that steel-cored aluminium strand two connects head；
12) aluminium splicing sleeve both ends pressure connection terminal is crimped using crimp, so that inlay aluminum pipe tightly engages steel core outside two connecting ends Aluminum stranded conductor and aluminium splicing sleeve, inline layer aluminum pipe tightly engage interior aluminum stranded conductor layer and steel strand wires, form aluminum stranded conductor pressure joint.
2. 7 strand steel-cored aluminium strand compression bonding methods of a kind of round wires concentric gallows empty conductor according to claim 1, feature It is: crimps stress after the crimping steel splicing sleeve of crimp in step 10):
If press machine non-stopping time after the crimping molding of steel core splicing sleeve, steel splicing sleeve inside radius are rfe, steel splicing sleeve center thickness is dfe, the steel core twisted wire pitch diameter of thread is d2, the embedding aluminum pipe central diameter of steel core connecting is with a thickness of dal；
According to the relationship of material trus stress σ and true strain ε
σ=E ε (1)
In formula (1), E---- is the Young's modulus of material；
After press machine shutdown is removed after the crimping molding of steel core splicing sleeve, if it is σ that steel core, which connects embedding aluminum pipe wall compression chord,1, steel connecting Pipe inside radius is rfe+Δrfe, steel splicing sleeve center thickness is dfe+Δdfe, steel core twisted wire pitch diameter of thread radius of circle is R+ Δ R, steel Core connects embedding aluminum pipe central diameter with a thickness of dal+Δdal
After press pressure releases after the crimping molding of steel core splicing sleeve, each thickness increment relationship is
ΔrfeΔ R=Δ dal (5)
After then press pressure releases after steel core splicing sleeve crimping molding, steel core, steel core are connected between embedding aluminum pipe, steel splicing sleeve Compression is
In formula (7):
σ1After press pressure releases after the crimping molding of ----steel core splicing sleeve,
Steel core, steel core connect embedding aluminum pipe, steel pipe compression, unit pa；
σ --- before press pressure releases after the crimping molding of-steel core splicing sleeve,
Steel core, steel core connect embedding aluminum pipe, steel pipe compression, unit pa；
rfeInside radius after the crimping of ----steel pipe, unit mm；
R---- steel core twisted wire pitch diameter of thread d2Half, unit mm；
dal----steel core connects embedding aluminum pipe equivalent thickness, unit mm；
EfeThe Young's modulus of ----steel；
EalThe Young's modulus of ----aluminium alloy.
3. 7 strand steel-cored aluminium strand compression bonding methods of a kind of round wires concentric gallows empty conductor according to claim 1, feature It is: round wires concentric gallows empty conductor 7 aluminium amount s twisted between steel-cored aluminium strand of insertion after the crimping molding of steel core splicing sleeve:
In formula (8), r---- steel core twisted wire steel wire radius, unit mm；
The steel core that insertion needs connects embedding aluminum pipe thickness
In formula (9), r---- steel core twisted wire steel wire radius, unit mm；
Then steel core connects embedding aluminum pipe with a thickness of δal
δal=δq+1 (10)
Steel core connects embedding aluminum pipe outer diameter DalFor
Dal=6r+1+2 δal (11)
In formula (11), r---- steel core twisted wire steel wire radius, unit mm；
It is two steel core twisted wire pitches that steel core, which connects embedding aluminum pipe length,；
Steel connects tube thickness δfeFor
In formula (20),
Fb----conducting wire (or ground wire) calculates Fracture Force, unit N；
σsfe----steel pipe yield strength, units MPa；
Dal----steel core connects embedding aluminum pipe outer diameter, unit mm；
Then steel connecting pipe outside diameter is
Dfe=Dal+2δfe (13)
It is that steel core connects embedding aluminum pipe length that steel, which connects length of tube,；
Crimp the crimping area of section that steel connects pipe mold:
Steel core crimps sectional area sx
In formula (14), r---- steel core twisted wire steel wire radius, unit mm；
Steel core connects embedding aluminum pipe section sqFor
In formula (15),
R---- steel core twisted wire steel wire radius, unit mm；
Dal----steel core connects embedding aluminum pipe outer diameter, unit mm；
Steel splicing sleeve sectional area sgFor
In formula (16),
Dfe----outer diameter of steel pipes, unit mm；
Dal----steel core connects embedding aluminum pipe outer diameter, unit mm；
Crimp crimps area of section syFor
sy=sx+sq+sg (17)
Regular hexagon pressing mold side length α is
Regular hexagon pressing mold diagonal line b is
B=a+2acos60 °=2a (19).
4. 7 strand steel-cored aluminium strand compression bonding methods of a kind of round wires concentric gallows empty conductor according to claim 1, feature It is: crimps stress after crimp crimping aluminium splicing sleeve:
If steel-cored aluminium strand is located in polar coordinate system, ρ is polar coordinates, vertical by the remnants after plastic deformation after the surrender of inlay aluminum pipe It is σ to stressρ, lateral stress isThe yield stress that aluminium splicing sleeve and outer inlay aluminum pipe are received after pressing mold removes is q2, inline layer Pipe outer radius is r1, connecting aluminum pipe radius is R0:
Boundary condition requirement are as follows:
Design conditions are considered as axisymmetrical stress, then answer condition are as follows:
In formula (21):
σρ----aluminum stranded conductor is by the remaining radial stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve, unit Pa；
----aluminum stranded conductor is by the remaining circumference stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve, unit Pa；
----aluminum stranded conductor is by remaining diameter ring cutting stress after being plastically deformed after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve, unit Pa；
A, B, C---- constant；
It brings boundary condition (1) into, solves:
In formula (22):
r1----inline layer aluminum pipe outer radius, original radius, unit mm；
R0----aluminium splicing sleeve outer radius, original radius, unit mm；
q1The yield stress that ----inline layer aluminium is subject to, unit Pa；
q2The yield stress that ----aluminium splicing sleeve and outer inlay aluminum pipe are subject to, unit Pa；
Interlayer remnants radial stress and circumference stress can be acquired by enabling B=0 that constant A, 2C that formula (22) solves are substituted into formula (21) are as follows:
In formula (23):
σρ----aluminum stranded conductor is by the remaining radial stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve, unit pa；
----aluminum stranded conductor is by the remaining circumference stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve, unit pa；
r1----inline layer aluminum pipe outer radius, original radius, unit mm；
R0----aluminium splicing sleeve outer radius, original radius, unit mm；
q1The yield stress that ----inline layer aluminium is subject to, unit Pa；
q2The yield stress that ----aluminium splicing sleeve and outer inlay aluminum pipe are subject to, unit Pa；
There are gaps mutually displacement occurs under the action of circumferential residual stress and radial residual stress, between twisted wire, then calculates straight Diameter are as follows:
In formula (24):
uρRadial displacement between ----twisted wire, unit mm；
Circumferential displacement between ----twisted wire, unit mm；
E---- steel-cored aluminium strand elasticity modulus, unit Pa；
In above formula (24)Instead of then having
The outer radius of inline layer aluminum pipe is after crimping
The outer radius of outer inlay aluminum pipe is after crimping
The knots modification of radial thickness is
Calculate radius RH=R- Δ R (29)
In formula (25)-formula (29)
σρ----aluminum stranded conductor is by the remaining radial stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve, unit Pa；
----aluminum stranded conductor is by the remaining circumference stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve, unit Pa；
urThe outer radius of inline layer pipe, unit mm after ----crimping；
uRThe outer radius of outer inlay aluminum pipe, unit mm after ----crimping；
μ --- the Poisson's ratio of-aluminium takes 0.33；
The knots modification of Δ R---- radial thickness, unit mm；
RHRadius, unit mm are calculated after ----crimping.
5. 7 strand steel-cored aluminium strand compression bonding methods of a kind of round wires concentric gallows empty conductor according to claim 1, feature Be: the aluminium amount that steel strand wires are embedded in after the crimping molding of inline layer aluminum pipe is D, and angle is θ between two strands of steel strand wires, and steel strand wires are outermost Layer radical is n, and single steel strand radius is r, then:
In formula (31), r---- single steel strand radius, unit mm；
If the aluminium amount for being embedded in aluminum stranded conductor after crimping molding is T, angle is β, aluminum stranded conductor innermost layer between two strands of aluminum stranded conductors of innermost layer Radical is u, and single aluminum stranded conductor radius is r1, the trade mark of selected inline layer aluminum pipe is 5A05, then:
In formula (33), r---- single steel strand radius, unit mm；
R2----single aluminum stranded conductor radius, unit mm；
Then total embedded quantity is
W=D+T (34)
In formula (34): being embedded in the aluminium amount of steel strand wires, unit mm after D---- crimping molding2；
T---- sets the aluminium amount of insertion aluminum stranded conductor after crimping molding, unit mm2；
Then it is embedded in unlined aluminium tube thickness are as follows:
In formula (35), r---- single steel strand radius, unit mm；
δal=δq+1 (36)
Inline layer aluminum pipe outer diameter are as follows:
Dal=6r+1+2 δal (37)
In formula (37), r---- single steel strand radius, unit mm；
The steel core pitch diameter length that inline layer aluminum pipe length is 1.5 times；
Outer inlay aluminum pipe includes large diameter section and small interior through section, large diameter section package inline layer aluminum pipe section and small interior is not wrapped up through section Inline layer aluminum pipe section；
The radius for wrapping up single aluminum stranded conductor in the outer inlay aluminum pipe (1) of inline layer aluminum pipe section is r1, outer inlay aluminum pipe internal diameter
R=Dal+2nr2 (38)
In formula (38), Dal----inline layer aluminum pipe outer diameter, unit mm；
r2----single aluminum stranded conductor radius, mm；
The n---- aluminum stranded conductor number of plies；
The aluminium amount of aluminum stranded conductor is embedded in after crimping molding
In formula (39), two strands of aluminum stranded conductor angles of α ----outermost layer, unit °；
The outer inlay aluminum pipe internal diameter of R----, unit mm；
r2----single aluminum stranded conductor radius, unit mm；
M---- outer layer aluminum stranded conductor radical；
It is embedded in the outer layer aluminum pipe thickness needed
δal'=δq1+1 (41)
In formula (40), (41), the outer inlay aluminum pipe internal diameter of R----, unit mm；
Outer inlay aluminum pipe outer diameter is
Dal'=2R+1+2 δal' (42)
In formula (42), the outer inlay aluminum pipe internal diameter of R----, unit mm；
δal' ----outer inlay aluminum pipe thickness, unit mm；
The length for wrapping up the outer inlay aluminum pipe (1) of inline layer aluminum pipe section is equal to inline layer aluminum pipe length；
The thickness of the outer inlay aluminum pipe (2) of inline layer aluminum pipe section is not wrapped up:
δal1=(Dal′-d-1)/2 (43)
In formula (43), Dal' ----outer inlay aluminum pipe outer diameter, unit mm；
D---- steel-cored aluminium strand outer diameter, unit mm；
The length for not wrapping up the outer inlay aluminum pipe (2) of inline layer aluminum pipe section is 1.1 times of pitch lengths.
6. 7 strand steel-cored aluminium strand compression bonding methods of a kind of round wires concentric gallows empty conductor according to claim 1, feature Be: conducting wire setting ring length takes 10mm, and internal diameter, which is equal to, does not wrap up inline layer aluminium section lead outer diameter, and outer diameter is less than package inline layer Outer inlay aluminum pipe (1) internal diameter of aluminum pipe section, and place it in the outer inlay aluminum pipe (1) of package inline layer aluminum pipe section and do not wrap up interior Outer inlay aluminum pipe (1) joint of inlay aluminum pipe section is to reach fixed conducting wire.
7. 7 strand steel-cored aluminium strand compression bonding methods of a kind of round wires concentric gallows empty conductor according to claim 1, feature Be: aluminium connects tube thickness:
Total specified pull-off force of steel-cored aluminium strand is Fb, the yield strength of aluminium splicing sleeve is σal, then aluminium splicing sleeve is with a thickness of δfeAre as follows:
In formula (44), Fb----calculate pull-off force, unit N；
Dal' ----outer inlay aluminum pipe outer diameter, unit mm；
σalThe yield strength of ----aluminium splicing sleeve, unit Mpa；
Aluminium connects pipe outside diameter
DAL=Dal'+2δal+1 (45)
In formula (45), DAL----aluminium connects pipe outside diameter, unit mm；
Dal' ----outer inlay aluminum pipe outer diameter, unit mm；
δal----aluminium connects tube thickness, unit mm；
Aluminium connects length of tube: 2 outer inlay aluminum pipe total lengths+steel connects length of tube+tolerance, and the trade mark that aluminium splicing sleeve is selected is 5A05。
8. 7 strand steel-cored aluminium strand compression bonding methods of a kind of round wires concentric gallows empty conductor according to claim 1, feature It is: the area of crimp crimping aluminium splicing sleeve:
Inline layer aluminum pipe crimps sectional area
In formula (46), Sj' ----inline layer aluminum pipe crimps sectional area, unit mm2；
Dal----inline layer aluminum pipe outer diameter, unit mm；
R---- single steel strand radius, unit mm；
Outer layer inlay aluminum pipe sectional area is SqAre as follows:
In formula (47), Dal' ----outer inlay aluminum pipe outer diameter, unit mm；
The outer inlay aluminum pipe internal diameter of R----, unit mm；
Aluminium splicing sleeve sectional area is Sl:
DAL'=Dal′+1
In formula (48), DAL----aluminium connects pipe outside diameter, unit mm；
DAL' ----aluminium connects bore, unit mm；
Then crimp sectional area is SmAre as follows:
Sm=Sq+Sj+Sl+Sal-W-S (49)
Sj----inline layer aluminum pipe sectional area, unit mm2, see formula (46)；
Sq----outer inlay aluminum pipe sectional area, unit mm2, see formula (47)；
Sl----aluminium splicing sleeve sectional area, unit mm2, see formula (48)；
Sal----steel-cored aluminium strand sectional area, unit mm2；
W--- inline layer aluminum pipe embedded quantity, unit mm2, see formula (34)；
The outer inlay aluminum pipe embedded quantity of S----, unit mm2, see formula (39)；
Regular hexagon pressing mold side length a are as follows:
Regular hexagon pressing mold diagonal line b1Are as follows:
b1=a+2acos60 °=2a (51)
9. 7 strand steel-cored aluminium strand compression bonding methods of a kind of round wires concentric gallows empty conductor according to claim 1, feature It is: pressure joint calculation of contact resistance:
(1) contact area
Contact length is calculated by the pitch diameter of thread, then it is l that every molding, which connects middle electrical path length,j, b mould is crimped altogether, and contact length connects with inlay aluminium Continuous length of tube lqProduct be inlay aluminium splicing sleeve aluminum stranded conductor contact area Sc:
Sc=b × lj×lq (52)
In formula (52)
ljElectrical path length in ----crimping, unit mm；
lq----outer inlay aluminum pipe length, unit mm；
B---- crimps modulus；
The contact area S of inlay aluminium splicing sleeve aluminum stranded conductor when calculatingcGreater than twice conductor cross-section area；
(2) contact resistance
Contact resistance is calculated with empirical equation, it may be assumed that
F=σρ·Sc (53)
In formula (53), F-contact pressure, unit N；
σρ----aluminum stranded conductor is by the remaining radial stress after plastic deformation after outer inlay aluminum pipe and the surrender of aluminium splicing sleeve, unit kN；
ScThe contact area of-inlay aluminium splicing sleeve aluminum stranded conductor, unit mm2；
In formula (54), Rj- contact resistance, unit Ω；
F---- contact pressure, unit N；
L---- constant related with contact form, for point contact l=0.5-0.7, face contact l=1；
K---- constant related with contact material, contact surface processing method, contact surface situation, when contact surface does not aoxidize, aluminium K value between aluminium is (3-6.7) × 10-3。
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CN101764290A (en) * 2009-12-21 2010-06-30 中国电力科学研究院 Connecting tube used for large-section conducting wire
JP5794434B2 (en) * 2013-02-28 2015-10-14 株式会社ビスキャス Connecting the power cable
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