CN110298133B - Method for calculating cracks of reinforced concrete beam of main control building of all-indoor substation - Google Patents
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Abstract
本发明公开了一种全户内变电站主控楼钢筋混凝土梁裂缝计算方法,包括以下步骤:1)根据平均裂缝宽度wm的经验公式,构建出平均裂缝宽度wm用曲率
表达的公式;2)根据当受拉纵筋刚屈服时的两种情况(第一种情况:受压混凝土边缘应变εc≤峰值压应变ε0;第二种情况:受压混凝土边缘应变εc>峰值压应变ε0),以及适筋梁受压混凝土达到极限压应变时的情况,构建曲率的表达式;3)将步骤2)中曲率表达式代入步骤1)的公式中,即得考虑了钢筋应力影响的裂缝宽度的计算公式。本发明推导出了受拉钢筋屈服后的钢筋混凝土梁裂缝的计算方法,相较于传统的计算方法,本发明的方法计算出的裂缝宽度与实际的裂缝宽度更贴近。The invention discloses a method for calculating the cracks of reinforced concrete beams of the main control building of an all-indoor substation, which comprises the following steps: 1) constructing the average crack width w m with the curvature according to the empirical formula of the average crack width w m
The expression formula; 2) According to the two situations when the tensile longitudinal reinforcement just yields (the first situation: the edge strain of the compressed concrete ε c ≤ the peak compressive strain ε 0 ; the second situation: the edge strain of the compressed concrete εc >Peak compressive strain ε 0 ), and when the compressive concrete of the well-reinforced beam reaches the ultimate compressive strain, construct the expression of curvature; 3) Substitute the curvature expression in step 2) into the formula of step 1), and then consider The calculation formula of crack width affected by steel stress is given. The invention deduces the calculation method for the cracks of the reinforced concrete beam after the tensile steel bar yields. Compared with the traditional calculation method, the crack width calculated by the method of the invention is closer to the actual crack width.Description
技术领域Technical Field
本发明属于土木工程技术领域,具体涉及一种全户内变电站主控楼钢筋混凝土梁裂缝计算方法。The invention belongs to the technical field of civil engineering, and in particular relates to a method for calculating cracks in reinforced concrete beams of a main control building of a fully indoor substation.
背景技术Background Art
在钢筋混凝土梁弹塑性分析时,若弯矩调幅系数取值过大,调幅后的钢筋在外荷载的作用下可能发生屈服。我们通常在计算裂缝宽度时采用规范中提出的公式,在计算时此公式中并未考虑钢筋应力的影响,而构件的裂缝宽度在钢筋屈服之后将不再发生变化,这与实际是不相符的,因而按照采用规范中提出的公式得到的裂缝宽度准确度不高。In the elastoplastic analysis of reinforced concrete beams, if the moment modulation coefficient is too large, the modulated steel bars may yield under the action of external loads. We usually use the formula proposed in the specification to calculate the crack width. This formula does not take into account the influence of steel bar stress during calculation, and the crack width of the component will no longer change after the steel bar yields, which is inconsistent with the actual situation. Therefore, the crack width obtained by using the formula proposed in the specification is not accurate.
通常钢筋混凝土结构在偶然荷载的作用下也可能发生屈服,钢筋屈服后构件的变形及裂缝宽度等是判断结构是否可修以及决定修复加固程度的重要指标,国内外针对钢筋屈服之后构件的裂缝宽度的研究很少,所以推导钢筋屈服之后的裂缝计算方法是非常必要的。Usually reinforced concrete structures may also yield under the action of accidental loads. The deformation and crack width of the components after the steel bar yields are important indicators for judging whether the structure is repairable and determining the degree of repair and reinforcement. There are few studies on the crack width of components after the steel bar yields at home and abroad, so it is very necessary to derive a method for calculating cracks after the steel bar yields.
发明内容Summary of the invention
本发明的目的是提供一种考虑钢筋应力影响的全户内变电站主控楼钢筋混凝土梁裂缝计算方法,提高计算出裂缝宽度的准确度。The purpose of the present invention is to provide a method for calculating cracks in reinforced concrete beams of a main control building of an indoor substation taking into account the influence of steel bar stress, so as to improve the accuracy of calculating the crack width.
本发明这种全户内变电站主控楼钢筋混凝土梁裂缝计算方法,包括以下步骤:The method for calculating cracks in reinforced concrete beams of the main control building of the fully indoor substation of the present invention comprises the following steps:
1)根据平均裂缝宽度的经验公式,构建出平均裂缝宽度用曲率表达的公式;1) Based on the empirical formula of average crack width, a formula for expressing the average crack width in terms of curvature is constructed;
2)根据当适筋梁受拉钢筋刚屈服时的两种情况(第一种情况:受压混凝土边缘应变εc≤峰值压应变ε0;第二种情况:受压混凝土边缘应变εc>峰值压应变ε0),以及适筋梁受压混凝土达到极限压应变时的情况,构建曲率的表达式;2) Based on the two cases when the tension reinforcement of the properly reinforced beam just yields (the first case: the edge strain of the compressive concrete ε c ≤ the peak compressive strain ε 0 ; the second case: the edge strain of the compressive concrete ε c > the peak compressive strain ε 0 ), and the case when the compressive concrete of the properly reinforced beam reaches the ultimate compressive strain, an expression for the curvature is constructed;
3)将步骤2)中曲率表达式代入步骤1)的公式中,即得考虑了钢筋应力影响的裂缝宽度的计算公式。3) Substitute the curvature expression in step 2) into the formula in step 1) to obtain the calculation formula for the crack width that takes into account the influence of steel bar stress.
所述步骤1)中,经验公式为:In the step 1), the empirical formula is:
式中,wm为平均裂缝宽度,εsm为纵向受拉钢筋的平均拉应变,εctm为与纵向受拉钢筋相同水平处侧表面混凝土的平均拉应变,lm为平均裂缝区段的钢筋混凝土梁计算长度。Where wm is the average crack width, εsm is the average tensile strain of the longitudinal tensile reinforcement, εctm is the average tensile strain of the side surface concrete at the same level as the longitudinal tensile reinforcement, and lm is the calculated length of the reinforced concrete beam in the average crack section.
所述构建出平均裂缝宽度用曲率表达的公式,具体包括以下步骤:The formula for constructing the average crack width expressed by curvature specifically includes the following steps:
1.1根据经验公式,考虑梁屈服后裂缝附近的粘结作用的消失,取为0.95,则平均裂缝计算公式为:wm=0.95εsmlm;1.1 According to the empirical formula, considering the disappearance of the bonding effect near the crack after the beam yields, Take it as 0.95, then the average crack calculation formula is: w m = 0.95ε sm l m ;
1.2构件的平均曲率与εsm的关系式如下:1.2 Average curvature of the component The relationship with ε sm is as follows:
其中:h0为截面有效高度;x为构件的受压区高度;Where: h0 is the effective height of the section; x is the height of the compression zone of the component;
1.3将步骤1.2中的公式代入步骤1.1公式中,得到平均裂缝宽度用曲率表达的公式为:1.3 Substitute the formula in step 1.2 into the formula in step 1.1 to obtain the formula for expressing the average crack width in terms of curvature:
所述步骤2)中,适受筋梁受拉钢筋刚屈服时的第一种情况:受压混凝土边缘应变εc≤峰值压应变ε0时,构建曲率的表达式包括以下步骤:In the step 2), the first case of the reinforced beam when the tensile reinforcement just yields: when the edge strain ε c of the compressive concrete is ≤ the peak compressive strain ε 0 , constructing the expression of the curvature includes the following steps:
2.1.1设截面屈服曲率为受拉钢筋屈服时受压区混凝土水平应变为εc,受压区高度为xc,2.1.1 Assume that the yield curvature of the section is When the tensile reinforcement yields, the horizontal strain of the concrete in the compression zone is ε c , and the height of the compression zone is x c .
根据平截面假定有:According to the plane section assumptions:
式中h0为截面有效高度,εy为为受拉区纵向普通钢筋应变;Where h0 is the effective height of the section, εy is the strain of the longitudinal ordinary reinforcement in the tension zone;
2.1.2根据力的平衡有:2.1.2 According to the balance of forces:
σ′sA′s+C=fyAs σ′ s A′ s + C = f y A s
式中σ′s为受压区钢筋应力;C为混凝土受压区合力;A′s为受压区纵向钢筋的截面面积,fy为钢筋抗拉强度设计值,As为受拉区纵向钢筋的截面面积;Where σ ′s is the stress of the steel bar in the compression zone; C is the resultant force of the concrete in the compression zone; A ′s is the cross-sectional area of the longitudinal steel bar in the compression zone, fy is the design value of the tensile strength of the steel bar, and As is the cross-sectional area of the longitudinal steel bar in the tension zone;
则有:Then we have:
其中Es为钢筋的弹性模量,ε′s为受压区钢筋应变,a′s为受压区纵向钢筋合力点到截面受压边缘的距离;b为钢筋混凝土梁截面宽度,fc为混凝土轴心抗压强度设计值;Where E s is the elastic modulus of the steel bar, ε′ s is the strain of the steel bar in the compression zone, a′ s is the distance from the resultant force point of the longitudinal steel bar in the compression zone to the compression edge of the section; b is the cross-sectional width of the reinforced concrete beam, and f c is the design value of the axial compressive strength of the concrete;
2.1.3将步骤2.1.1中的公式代入步骤2.1.2中的第三个公式中得:2.1.3 Substitute the formula in step 2.1.1 into the third formula in step 2.1.2 to obtain:
2.1.4将步骤2.1.2中的第二个公式和步骤2.1.3的公式,代入步骤2.1.2中的第一个公式得:2.1.4 Substitute the second formula in step 2.1.2 and the formula in step 2.1.3 into the first formula in step 2.1.2 to obtain:
2.1.5对步骤2.1.4中的公式进行化简,在计算时忽略因子,将代入上式,则有:2.1.5 Simplify the formula in step 2.1.4 and ignore Factor, will Substituting into the above formula, we have:
则此时的屈服曲率为:The yield curvature at this time is:
式中:Where:
a2=Esε0εyA′s+2fcbh0εy+fyAsε0 a 2 =E s ε 0 ε y A′ s +2f c bh 0 ε y +f y A s ε 0
所述步骤2)中,适受筋梁受拉钢筋刚屈服时的第二种情况:受压混凝土边缘应变εc>峰值压应变ε0时,构建曲率的表达式包括以下步骤:In the step 2), the second case of the reinforced beam when the tensile reinforcement just yields: when the edge strain ε c of the compressive concrete is greater than the peak compressive strain ε 0 , constructing the expression of the curvature includes the following steps:
2.2.1设受压混凝土边缘应变达到峰值压应变ε0时的受压区高度为x0,2.2.1 Assume that the height of the compression zone when the edge strain of the compressed concrete reaches the peak compressive strain ε 0 is x 0 ,
根据平截面假定,有如下的变形协调方程:According to the plane section assumption, the following deformation coordination equation is obtained:
其中:ε为混凝土应变,x为混凝土应变达到ε时的混凝土受压区高度;Where: ε is the concrete strain, x is the height of the concrete compression zone when the concrete strain reaches ε;
2.2.2则根据受压混凝土的本构关系可知,压区混凝土的应力应变曲线为两段,一段为抛物线上升段,一段为水平段,所以对混凝土的积分应进行分段积分才能得到压应力合力C为:2.2.2 According to the constitutive relationship of compressed concrete, the stress-strain curve of the compression zone concrete is divided into two sections, one is a parabolic ascending section and the other is a horizontal section. Therefore, the integral of the concrete should be segmented to obtain the compressive stress resultant C:
则根据力平衡公式σ′sA′s+C=fyAs和可得:According to the force balance formula σ′ s A′ s + C = f y A s and We can get:
其中σ′s为受压区钢筋应力,A′s为受压区纵向钢筋的截面面积,C为混凝土受压区合力,fy为钢筋抗拉强度设计值,As为受拉区纵向钢筋的截面面积;Es为钢筋的弹性模量,ε′s为受压区钢筋应变,a′s为受压区纵向钢筋合力点到截面受压边缘的距离;b为钢筋混凝土梁截面宽度,fc为混凝土轴心抗压强度设计值;Where σ′ s is the stress of the steel bar in the compression zone, A′ s is the cross-sectional area of the longitudinal steel bar in the compression zone, C is the resultant force in the compression zone of the concrete, f y is the design value of the tensile strength of the steel bar, A s is the cross-sectional area of the longitudinal steel bar in the tension zone; E s is the elastic modulus of the steel bar, ε′ s is the strain of the steel bar in the compression zone, a′ s is the distance from the resultant force point of the longitudinal steel bar in the compression zone to the compression edge of the section; b is the cross-sectional width of the reinforced concrete beam, and f c is the design value of the axial compressive strength of the concrete;
2.2.3将代入步骤2.2.2最后得到的公式中,可得:2.2.3 Substituting into the formula obtained at the end of step 2.2.2, we get:
则此时的屈服曲率可通过上式计算得到:The yield curvature at this time can be calculated by the above formula:
式中:Where:
b1=3EsA′s(h0-a′s)b 1 =3E s A′ s (h 0 -a′ s )
b2=3EsA′sεy-3fcbh0+3fyAs b 2 =3E s A′ s ε y -3f c bh 0 +3f y A s
b3=3fcbεy+fcbε0。b 3 =3f c bε y +f c bε 0 .
所述步骤2)中,适筋梁受压混凝土达到极限压应变εcu时,构建曲率的表达式包括以下步骤:In the step 2), when the compressive concrete of the reinforced beam reaches the ultimate compressive strain ε cu , constructing the expression of curvature includes the following steps:
2.3.1受压混凝土应力达到抗压强度fc,此时受拉钢筋应变大于屈服应变,可求得:2.3.1 When the stress of the compressed concrete reaches the compressive strength f c , the strain of the tensile reinforcement is greater than the yield strain, and we can obtain:
式中εs为受拉钢筋应变,xcu为受压混凝土达到极限压应变时的混凝土极限受压区高度;Where ε s is the strain of the tensile reinforcement, x cu is the height of the ultimate compression zone of the concrete when the compressive concrete reaches the ultimate compressive strain;
2.3.2在此种状态下,混凝土合力C的表达式为:2.3.2 Under this condition, the expression of concrete resultant force C is:
其中b为钢筋混凝土梁截面宽度,x0为受压混凝土边缘应变达到峰值压应变时的混凝土极限受压区高度,fc为混凝土轴心抗压强度设计值;Where b is the cross-sectional width of the reinforced concrete beam, x 0 is the height of the ultimate compression zone of the concrete when the edge strain of the compressed concrete reaches the peak compressive strain, and f c is the design value of the axial compressive strength of the concrete;
则根据力的平衡有σ′sA′s+C=fyAs和可得出:According to the balance of forces, we have σ′ s A′ s +C=f y A s and It can be concluded that:
σ′s为受压区钢筋应力,A′s为受压区纵向钢筋的截面面积,C为混凝土受压区合力,fy为钢筋抗拉强度设计值,As为受拉区纵向钢筋的截面面积;Es为钢筋的弹性模量,ε′s为受压区钢筋应变,a′s为受压区纵向钢筋合力点到截面受压边缘的距离;b为钢筋混凝土梁截面宽度,fc为混凝土轴心抗压强度设计值;σ′ s is the stress of the steel bar in the compression zone, A′ s is the cross-sectional area of the longitudinal steel bar in the compression zone, C is the resultant force in the compression zone of the concrete, f y is the design value of the tensile strength of the steel bar, A s is the cross-sectional area of the longitudinal steel bar in the tension zone; E s is the elastic modulus of the steel bar, ε′ s is the strain of the steel bar in the compression zone, a′ s is the distance from the resultant force point of the longitudinal steel bar in the compression zone to the compression edge of the section; b is the cross-sectional width of the reinforced concrete beam, and f c is the design value of the axial compressive strength of the concrete;
2.3.3将步骤2.3.2中最后得到的公式,用的形式表示为:2.3.3 Use the formula obtained in step 2.3.2 to The form is expressed as:
则此时的屈服曲率可通过上式计算得到:The yield curvature at this time can be calculated by the above formula:
c1=3Esa′sA′s c 1 = 3E s a′ s A′ s
c2=3EsεcuA′s-3fyAs-fcbx0 c 2 =3E s ε cu A′ s -3f y A s -f c bx 0
c3=-2fcbεcu。c 3 = -2f c bε cu .
所述步骤3)中,将步骤2)中的曲率表达式代入步骤1)中,得到受压混凝土边缘应变εc≤峰值压应变ε0时:In step 3), the curvature expression in step 2) is substituted into step 1) to obtain the following when the edge strain ε c of the compressive concrete is ≤ the peak compressive strain ε 0 :
受压混凝土边缘应变εc>峰值压应变ε0时:When the edge strain ε c of the compressive concrete is greater than the peak compressive strain ε 0 :
适筋梁受压混凝土达到极限压应变εcu时:When the compressive concrete of the properly reinforced beam reaches the ultimate compressive strain ε cu :
本发明的有益效果:本发明在考虑受拉钢筋屈服后的两个节点,即适筋梁受拉钢筋刚屈服时和适筋梁受压混凝土达到极限压应变时的基础上,考虑平均伸长与相应水平处构件侧表面混凝土平均伸长的差值来计算平均裂缝宽度,推导出了受拉钢筋屈服后的钢筋混凝土梁裂缝的计算方法,相较于传统的计算方法,本发明的方法计算出的裂缝宽度与实际的裂缝宽度更贴近。Beneficial effects of the present invention: The present invention calculates the average crack width by considering the difference between the average elongation and the average elongation of the concrete on the side surface of the component at the corresponding level, based on the two nodes after the yield of the tensile steel bars, namely, when the tensile steel bars of the properly reinforced beam have just yielded and when the compressive concrete of the properly reinforced beam has reached the ultimate compressive strain. The method for calculating the cracks in the reinforced concrete beam after the yield of the tensile steel bars is derived. Compared with the traditional calculation method, the crack width calculated by the method of the present invention is closer to the actual crack width.
附图说明BRIEF DESCRIPTION OF THE DRAWINGS
图1实施例2中受压混凝土边缘应变εc≤峰值压应变ε0,受力简图;FIG. 1 shows a force diagram of the compressed concrete edge strain ε c ≤ peak compressive strain ε 0 in Example 2;
图2实施例2中受压混凝土边缘应变εc>峰值压应变ε0,受力简图;FIG2 shows the stress diagram of the edge strain ε c of the compressed concrete in Example 2, which is greater than the peak compressive strain ε 0 ;
图3实施例3中适筋梁受压混凝土达到极限压应变εcu时,受力简图。FIG3 is a schematic diagram of the forces when the compressive concrete of the properly reinforced beam in Example 3 reaches the ultimate compressive strain ε cu .
具体实施方式DETAILED DESCRIPTION
说明书中的和都是代表曲率,是同一参数,只是为了区分在不同情况下的推导过程,修改了下标。In the manual and They all represent curvature and are the same parameter, but the subscripts are modified to distinguish the derivation process in different cases.
实施例1平均裂缝宽度计算公式的构建Example 1 Construction of the average crack width calculation formula
平均裂缝宽度等于构件裂缝区段内钢筋的平均伸长与相应水平处构件侧表面混凝土平均伸长的差值:The average crack width is equal to the difference between the average elongation of the steel bars in the crack section of the component and the average elongation of the concrete on the side surface of the component at the corresponding level:
式中:εsm为纵向受拉钢筋的平均拉应变,εctm为与纵向受拉钢筋相同水平处侧表面混凝土的平均拉应变,lm为平均裂缝区段的钢筋混凝土梁计算长度。。Where: ε sm is the average tensile strain of the longitudinal tensile reinforcement, ε ctm is the average tensile strain of the side surface concrete at the same level as the longitudinal tensile reinforcement, and l m is the calculated length of the reinforced concrete beam in the average crack section.
考虑梁屈服后裂缝附近的粘结作用的消失,取为0.95,则平均裂缝计算公式为:Considering the disappearance of the bonding effect near the crack after the beam yields, Take it as 0.95, then the average crack calculation formula is:
wm=0.95εsmlm (2)w m =0.95ε sm l m (2)
构件的平均曲率为 The average curvature of the component is
将式(2)用平均曲率的形式表示为:Formula (2) can be expressed in the form of mean curvature as:
式中x为构件的受压区高度。Where x is the height of the compression zone of the component.
实施例2筋梁受拉钢筋刚屈服时的裂缝计算方法Example 2 Calculation method for cracks in reinforced beam when tensile reinforcement just yields
适筋梁在受拉纵筋刚屈服时,以受压区边缘混凝土应变是否达到受压混凝土峰值应变为界限可分为以下两种情况考虑:When the tensile longitudinal reinforcement of the properly reinforced beam just yields, the following two situations can be considered based on whether the concrete strain at the edge of the compression zone reaches the peak strain of the compression concrete:
(1)当受拉纵筋刚屈服时,受压混凝土边缘应变εc≤峰值压应变ε0,受力简图如图1所示。(1) When the tensile longitudinal reinforcement just yields, the edge strain ε c of the compressive concrete is ≤ the peak compressive strain ε 0 . The force diagram is shown in Figure 1.
设截面屈服曲率为受拉钢筋屈服时受压区混凝土水平应变为εc,受压区高度为xc,计算简图如图2所示:Assume the yield curvature of the section is When the tensile reinforcement yields, the horizontal strain of the concrete in the compression zone is ε c , and the height of the compression zone is x c . The calculation diagram is shown in Figure 2:
根据平截面假定有:According to the plane section assumptions:
其中h0为截面有效高度,εy为为受拉区纵向普通钢筋应变。Where h0 is the effective height of the section and εy is the strain of the longitudinal ordinary reinforcement in the tension zone.
根据力的平衡有:According to the balance of forces:
σ′sA′s+C=fyAs (7)σ′ s A′ s +C=f y A s (7)
式中σ′s为受压区钢筋应力;C为混凝土受压区合力;A′s为受压区纵向钢筋的截面面积,fy为钢筋抗拉强度设计值,As为受拉区纵向钢筋的截面面积;Where σ ′s is the stress of the steel bar in the compression zone; C is the resultant force of the concrete in the compression zone; A ′s is the cross-sectional area of the longitudinal steel bar in the compression zone, fy is the design value of the tensile strength of the steel bar, and As is the cross-sectional area of the longitudinal steel bar in the tension zone;
则有:Then we have:
式中Es为钢筋的弹性模量,ε′s为受压区钢筋应变,a′s为受压区纵向钢筋合力点到截面受压边缘的距离;b为钢筋混凝土梁截面宽度,fc为混凝土轴心抗压强度设计值;Where E s is the elastic modulus of the steel bar, ε′ s is the strain of the steel bar in the compression zone, a′ s is the distance from the resultant force point of the longitudinal steel bar in the compression zone to the compression edge of the section; b is the cross-sectional width of the reinforced concrete beam, and f c is the design value of the axial compressive strength of the concrete;
将式(6)代入式(9)中得:Substituting formula (6) into formula (9), we get:
将式(8)和式(10),代入式(7)中得:Substituting equation (8) and equation (10) into equation (7), we get:
对式(11)进行化简,在计算时忽略因子,将代入上式,则有:Simplify formula (11) and ignore Factor, will Substituting into the above formula, we have:
则此时的屈服曲率为:The yield curvature at this time is:
式中:Where:
a2=Esε0εyA′s+2fcbh0εy+fyAsε0 (15)a 2 =E s ε 0 ε y A′ s +2f c bh 0 ε y +f y A s ε 0 (15)
将以上屈服曲率公式代入公式(4)中,可得第一种情况下的裂缝计算公式Substituting the above yield curvature formula into formula (4), we can obtain the crack calculation formula for the first case:
(2)当受拉纵筋刚屈服时,且受压混凝土边缘应变εc>峰值压应变ε0 (2) When the tensile longitudinal reinforcement has just yielded and the compressive concrete edge strain ε c > peak compressive strain ε 0
设受压混凝土边缘应变达到峰值压应变ε0时的受压区高度为x0。Assume that the height of the compression zone when the edge strain of the compressed concrete reaches the peak compressive strain ε 0 is x 0 .
根据平截面假定,有如下的变形协调方程:According to the plane section assumption, the following deformation coordination equation is obtained:
则根据受压混凝土的本构关系可知,压区混凝土的应力应变曲线为两段,一段为抛物线上升段,一段为水平段,所以对混凝土的积分应进行分段积分才能得到压应力合力C为:According to the constitutive relationship of compressed concrete, the stress-strain curve of the compression zone concrete is divided into two sections, one is a parabolic ascending section, and the other is a horizontal section. Therefore, the integral of the concrete should be segmented to obtain the compressive stress resultant C:
则式(7)变为:Then formula (7) becomes:
将代入上式,可得:Will Substituting into the above formula, we can get:
则此时的屈服曲率可通过上式计算得到:The yield curvature at this time can be calculated by the above formula:
式中:Where:
b2=3EsA′sεy-3fcbh0+3fyAs (23)b 2 =3E s A′ s ε y -3f c bh 0 +3f y A s (23)
b3=3fcbεy+fcbε0 (24)b 3 =3f c bε y +f c bε 0 (24)
将屈服曲率公式代入公式(4)中,可得第二种情况下的裂缝计算公式。Substituting the yield curvature formula into formula (4), we can obtain the crack calculation formula for the second case.
实施例3适筋梁受压混凝土达到极限压应变时裂缝计算方法Example 3 Calculation method for cracks when the compression concrete of the reinforced beam reaches the ultimate compressive strain
适筋梁受压混凝土达到极限压应变εcu时,受压混凝土应力达到抗压强度fc,此时受拉钢筋应变大于屈服应变,则达到极限变形时的应力图形和应变图形如图3所示。When the compressive concrete of the properly reinforced beam reaches the ultimate compressive strain ε cu , the compressive concrete stress reaches the compressive strength f c , and the strain of the tensile reinforcement is greater than the yield strain. The stress and strain diagrams when the ultimate deformation is reached are shown in Figure 3.
通过图3中的几何条件可求得:Through the geometric conditions in Figure 3, we can obtain:
则混凝土合力为:The resultant force of concrete is:
则根据力的平衡有:According to the balance of forces:
将上式用的形式表示为:Use the above formula The form is expressed as:
则此时的屈服曲率可通过上式计算得到:The yield curvature at this time can be calculated by the above formula:
c1=3Esa′sA′s (30)c 1 =3E s a′ s A′ s (30)
c2=3EsεcuA′s-3fyAs-fcbx0 (31)c 2 =3E s ε cu A′ s -3f y A s -f c bx 0 (31)
c3=-2fcbεcu (32)c 3 = -2f c bε cu (32)
将屈服曲率公式代入公式(4)中,可得第三种情况下的裂缝计算公式,Substituting the yield curvature formula into formula (4), we can obtain the crack calculation formula for the third case:
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