Disclosure of Invention
The invention aims to avoid the defects of the prior art, provides a phasor product active method for judging a fault phase and selecting a line, qualitatively judges the fault phase and the line instead of quantitatively, does not depend on accurately calculating the fault phasor for judgment, avoids the influence of various uncertain factors and transient quantities, overcomes the defect of quantitatively judging the fault phase and the line selection at present, does not need to accurately calculate the fault quantity by Fourier transform and the like, realizes hundred percent accurate judgment of the fault phase and the line selection, and ensures the safe operation of a system.
The invention adopts the following technical scheme for solving the technical problems:
the method for judging the fault phase and selecting the line by the phasor product active method has the characteristics that:
phasors
Is expressed as u
E(t) is: u. of
E(t)=Ksin(ωt+α),
Phasors
Is expressed as u
F(t) is: u. of
F(t)=Psin(ωt+α+β),
K and P are phasors
And phasor
A and a + beta are phasors, respectively
And phasor
Beta is phasor
And phasor
The included angle of (A);
phasor
And phasor
Phasor product of
Is marked as
Phasor product
The phasor product of (A) is recorded as W
E*FProduct of phasors
The function expression of (a) is denoted as g (t);
WE*F=KPcosβ
g(t)=WE*F-KPsin(2ωt+2α+β)
phasor product
Phasor of (2) by active power W
E*FIs characterized by equation (1.1):
u
E(t
i)、u
F(t
i) And g (t)
i) Are phasors, respectively
Phasors
Product of sum and phasor
Synchronous sample value at time ti, n being phasor
And phasor
The sampling number of half cycle or integral multiple of half cycle, and n is a natural number not less than 2;
the criterion characterized by equation (1.2) is obtained according to equation (1.1):
and calculating phasor product active power according to the formula (1.1), and judging the phase relation between phasors according to the formula (1.2) and the magnitude and the positive and negative of the phasor product active power to realize the judgment and line selection of the fault phase during single-phase grounding.
The phasor product active method for judging the fault phase and selecting the line is also characterized in that:
for a power grid system with m outgoing lines, when a single-phase earth fault occurs in the power grid system,
to be provided with
And
representing the phase voltages of the leading phase, lagging phase and faulted phase, respectively, and applying the same
And
defining a set of three-phase symmetrical reference phasors;
to be provided with
And
respectively representing line voltages of a leading phase relative to a fault phase, a lagging phase relative to a leading phase and a lagging phase relative to a fault phase, and converting the line voltages into the voltage values
And
defining as another set of three-phase symmetrical reference phasors, dividing said set
Defining the reference phasor as a line selection;
to be provided with
And
respectively representing the voltages relative to the ground of the leading phase, the lagging phase and the fault phase to
Represents a neutral point voltage, by
And
and
defining as a fault phasor;
theta represents phasor
And phasor
The included angle of (A);
to be provided with
The capacitance current of the ith outlet is represented, i is 1,2, …, m is a natural number not less than 1, and
representing the capacitive current of the faulty line,
and
the fault phasor has the relation (2.1):
constructing a set of three-phase symmetric reference phasors
And
the three-phase symmetrical reference phasor
And
leading three-phase voltage
And
are all in phase
Will be provided with
The value is randomly selected in the range of (-30 degrees and 60 degrees); or will be
Tracking neutral voltage according to equations (2.1) and (2.2)
Dynamically take value to
And
the included angle is acute and minimum;
constructing a set of three-phase symmetric reference phasors
And
the three-phase symmetrical reference phasor
And
leading three-phase voltage
And
are all in phase
Will be provided with
Any value is taken in the range of (-30.5 degrees and 59.5 degrees); or will be
Tracking neutral voltage according to equations (2.1) and (2.3)
Dynamically take value to
And
the included angle is acute and minimum;
constructing a line selection reference phasor
The reference phasor
Advance in
Phase is
Will be provided with
The value is randomly selected in the interval of (0 degrees and 90 degrees); or will be
Tracking neutral voltage according to equations (2.1) and (2.4)
Dynamically take value to
And
the included angle is acute and minimum;
the phasor product for judging a fault phase by a power method is as follows: multiplying the fault phasor by the fault phasor or multiplying the fault phasor by the three-phase symmetrical reference phasor;
the phasor product for realizing the line selection by the power method is as follows: multiplying the capacitance current of each outgoing line by the reference phasor of the selected line, or multiplying the capacitance current of each outgoing line by the voltage of the fault phase-to-ground;
the phasor product active method for judging the fault phase and selecting the line is also characterized in that:
and aiming at the G-phase single-phase earth fault of the system, judging the fault phase according to any criterion as follows:
criterion 1: multiplying the fault phasor by the fault phasor, namely: will be provided with
Are respectively connected with
And
multiply to obtain
And
wherein,
the phasor product of (a) is the largest and positive in active power;
criterion 2: multiplying the fault phasor by the three-phase symmetric reference phasor, namely: will be provided with
Are respectively connected with
And
multiply to obtain
And
wherein,
the phasor product of (a) is the largest and positive in active power;
criterion 3: multiplying the fault phasor by the three-phase symmetric reference phasor, namely: will be provided with
Are respectively connected with
And
multiply to obtain
And
wherein,
the phasor product of (a) is the largest and positive in active power;
criterion 4: multiplying the fault phasor by the three-phase symmetric reference phasor, namely:
and
respectively with the same name
And
multiplying to obtain:
and
wherein,
the phasor product of (a) is the largest and positive in active power;
criterion 5: multiplying the fault phasor by the three-phase symmetric reference phasor, namely: will be provided with
And
respectively with the same name
And
multiply to obtain
And
wherein,
the phasor product of (a) is the largest and positive in active power;
criterion 6: multiplying the fault phasor by the three-phase symmetric reference phasor, namely: will be provided with
Are respectively connected with
And
multiplying to obtain:
and
wherein
The phasor product of (a) is the largest and positive in active power;
criterion 7: multiplying the fault phasor by the three-phase symmetric reference phasor, namely: will be provided with
And
respectively with the same name
And
multiplying to obtain:
and
wherein,
the phasor product of (a) is the largest and positive in active power;
the phasor product active method for judging the fault phase and selecting the line is also characterized in that:
and aiming at the G-phase single-phase earth fault of the system, fault line selection is carried out according to any line selection criterion from the following criteria I to the third criterion:
criterion one is as follows: and multiplying the fault phasor by the line selection reference phasor to obtain a phasor product active power, namely: each line to be led out
And
obtained by multiplication
Phasor product active power of fault line
Is all that
The medium phasor product has the largest active power and is a positive value;
criterion two: and multiplying the fault phasor by the fault phasor and the line selection reference phasor to obtain a phasor product active:
if it is
Multiplying the fault phasor by the fault phasor to obtain phasor product active power, each outgoing line
And
obtained by multiplication
Phasor product active power of fault line
Is all that
The medium phasor product has the largest active power and is a positive value;
if it is
And then, multiplying the fault phasor by the line selection reference phasor to obtain a phasor product active power, namely: each line to be led out
And
obtained by multiplication
Phasor product active power of fault line
Is all that
The medium phasor product has the largest active power and is a positive value;
criterion three: and multiplying the fault phasor by the line selection reference phasor to obtain a phasor product active power, namely: each line to be led out
And
obtained by multiplication
Phasor product active power of fault line
Is all that
The medium phasor product has the largest active power and is a positive value.
The phasor product active method for judging the fault phase and selecting the line is also characterized in that:
when G-phase single-phase grounding occurs in the system, phase voltage sampling values of three phases are obtained in any mode as follows:
the first method is as follows: leading phase voltage
Voltage of lagging phase
And fault phase voltage
Is equal to the sampling value of the phase-to-ground voltage of the same name phase minus the synchronous sampling value of the neutral point voltage, and is represented by the formula (5.1);
the second method comprises the following steps: the method comprises the steps of measuring by using a voltage transformer, sampling the voltage of the secondary side of the voltage transformer to obtain a phase voltage sampling value, and ungrounded a primary side neutral point of the voltage transformer.
The third method comprises the following steps: leading phase voltage
Voltage of lagging phase
And fault phase voltage
The sampled value of (2) is obtained according to an equipotential sampled value of the three-phase ground voltage before the single-phase ground fault, wherein the equipotential sampled value refers to:
sampling is carried out on an alternating current signal f (T) with the period T, and the alternating current signal f (T) when the system normally operates is recorded as f1(t) mixing tτThe AC signal f (t) after the system fault at the moment is recorded as f2(t),f1(t) after the occurrence of a failure t2Sampling value f of time1(t2) And has the following components:
k is a natural number not less than 1, f1(t1) Is f1(t2) Before failure, then:
f1(t2)=f1(t1) (5.3)
f (t) at t2Fault increment at time:
Δf(t2)=f2(t2)-f1(t2) (5.4)
f (t) represents the relative voltage of the system, f
1(t) represents the phase power of the systemPress and press
And
with f
2(t) represents the relative ground voltage of the system after single-phase grounding
And
normal operation of the system f (t) ═ f
1(t), f (t) f after single-phase grounding
2(t)。
The phasor product active method for judging the fault phase and selecting the line is also characterized in that:
line voltage of leading phase to fault phase, lagging phase to leading phase and lagging phase to fault phase
And
is obtained by any of the following ways:
the first mode is as follows: according to the formula (2.1),
and
the sampled values are respectively composed of the phase voltages of a leading phase, a lagging phase and a fault phase
And
subtracting the synchronous sampling values to obtain;
the second mode is as follows: according to the formula (6.1),
and
the sampling values of the two phases are respectively from the voltages to the ground of the leading phase, the lagging phase and the fault phase
And
subtracting the synchronous sampling values to obtain;
and if the difference between the two phasors is equal to the third phasor, subtracting the synchronous sampling value of the two phasors by the synchronous sampling value of the third phasor, and applying to vector subtraction operation.
The phasor product active method for judging the fault phase and selecting the line is also characterized in that: the sampling value of the neutral point voltage is obtained by adding synchronous sampling values of three phases of voltage to ground according to the formula (2.1) or obtained by converting the sampling value of the open triangular voltage of the voltage transformer;
and if the sum of the two phasors is equal to the third phasor, adding the synchronous sampling values of the two phasors to the synchronous sampling value of the third phasor, and applying to vector addition operation.
The phasor product active method for judging the fault phase and selecting the line is also characterized in that: the line selection criterion is suitable for a power grid system with a neutral point resistor grounded.
The phasor product active method for judging the fault phase and selecting the line is also characterized in that: phasor setting
And phasor
The phasor product active power of is W
E1*F1Phasors
And phasor
The phasor product active power of is W
E2*F2;
If WE1*F1≥WE2*F2Then, there are:
or:
n
1is a number of samples greater than half a cycle time period, u
E1(t
i)、u
F1(t
i)、u
E2(t
i) And u
F2(t
i) Are respectively as
And
at t
iThe sampled value of the moment.
Compared with the prior art, the invention has the beneficial effects that:
1. the device for judging the fault phase and the line selection by the phasor product active power method is originally created, judges the fault phase and the line selection qualitatively rather than quantitatively, does not depend on accurate calculation of each fault quantity to carry out judgment, does not need Fourier transform and other accurate calculation of the fault quantity, thereby abandoning the transient process in which the variable magic measurement is difficult to capture the law, and eliminating the complicated transient data to judge the fault phase and the line selection, thereby realizing the hundred percent of accuracy.
2. The invention provides a phasor product active method, the algorithm is simple and only has arithmetic operation, the average value of the product of two phasor sampling values in half cycle integral multiple time has low requirement on sampling frequency, and the functional requirement of a CPU is low.
3. The invention provides a phasor product active method, wherein the included angle of two phasors is acute angle and positive active power, the included angle is obtuse angle and negative active power, the reference phasor is set according to the phase region in which the fault phasor falls, so that the included angle between the reference phasor and the fault phasor can be kept at an acute angle under any condition, and reliable guarantee is provided for qualitatively judging the fault phasor and selecting a line.
4. The phasor product active fault phase judgment method gives various characteristic criteria, and various criteria verify mutually, so that the accuracy of the phasor product active fault phase judgment method is effectively guaranteed, and the technical problem that the fault phase is difficult to accurately judge is solved.
5. The phasor product active line selection gives three characteristic criteria, and the three criteria are verified mutually, so that the accuracy of line selection of the invention is effectively guaranteed, and the technical problem of line selection is overcome.
6. The invention provides an algorithm of an equipotential sampling value of a phase voltage after a fault, provides a basic condition for selection of a reference phasor, and is suitable for all vectors.
7. The sampling value of the line voltage is obtained by directly subtracting the sampling values of the phase voltages, and a new method is provided for calculating vector sum and difference sampling values.
In a particular embodiment of the present invention,
any value between-30 degrees and 60 degrees can be selected
Has an optimal value of 15 degrees, and the fault point falls on the fault point railAt any point on the trace semicircle,
with three-phase symmetrical reference phasors constructed
And
in (1)
The included angles are all less than 45 degrees, which is most beneficial
The phasor product of (a) is the largest.
Of course, it is also possible to
Tracking neutral voltage
The dynamic values, as shown in figure 1,
according to equation (2.2), then:
advance in
Thus, the device is provided with
And
is acute and close to 0, then,
the phasor product of the method is more outstandingAnd the method is more favorable for fault phase judgment.
Constructing a set of three-phase symmetric reference phasors
And
three-phase symmetrical reference phasor
And
leading three-phase voltage
And
are all in phase
Will be provided with
Any value is taken in the range of (-30.5 degrees and 59.5 degrees); or will be
Tracking neutral voltage according to equations (2.1) and (2.3)
Dynamically take value to
And
the included angle is acute and minimum;
referring to fig. 1, in Δ OQJ, there are:
the formula (2.3) is derived from the formulae (2.3.1) to (2.3.3)
Calculated from equation (2.3):
advance in
The phase position is between-3 degrees and 30 degrees,
the optimal value of the fault point is 13.5 degrees, the fault point falls on any point on the semicircle of the fault point track,
with three-phase symmetrical reference phasors constructed
And
in (1)
The included angles are all less than 16.5 degrees, which is most beneficial
The phasor product of (a) is the largest.
Of course, it is also possible to
Tracking neutral voltage
Dynamically take value to
And
is acute and close to 0, then,
the phasor product of the three-phase current transformer is more outstanding in power, and is more beneficial to fault phase judgment.
Constructing a line selection reference phasor
Reference phasor
Advance in
Phase is
Will be provided with
The value is randomly selected in the interval of (0 degrees and 90 degrees); or will be
Tracking neutral voltage according to equations (2.1) and (2.4)
Dynamically take value to
And
the included angle is acute and minimum;
with reference to figure 1 of the drawings,
advance in
Phase 90-180 DEG, capacitance current of fault line
Hysteresis
The phase position is 90 degrees,
advance in
The phase is 0 to 90 degrees,
is preferably 45 deg., so that
And
the included angle of (a) is acute under various grounding conditions,
the phasor product of (1) is
The active power is the largest and positive.
Of course, it is also possible to
Tracking neutral voltage
The dynamic value of the numerical control system is taken,
so that
And
is acute and close to 0, then,
the phasor product of (1) is
The active power is the largest and positive.
The phasor product for judging a fault phase by a power method is as follows: multiplying the fault phasor by the fault phasor or multiplying the fault phasor by the three-phase symmetrical reference phasor;
the phasor product for realizing the line selection by the power method is as follows: multiplying the capacitance current of each outgoing line by the reference phasor of the selected line, or multiplying the capacitance current of each outgoing line by the voltage of the fault phase-to-ground;
if the included angle between the reference phasor and the fault phasor is obtuse, i.e. the direction of the reference phasor is opposite to that of the fault phasor, the phasor product active of the reference phasor and the fault phasor is the most negative.
If the phase A in the system is a fault phase, the phase C is a leading phase, and the phase B is a lagging phase; if the phase B in the system is a fault phase, the phase A is a leading phase, and the phase C is a lagging phase; if the system C phase is a fault phase, the B phase is a leading phase, and the A phase is a lagging phase.
The invention provides a phasor product active method, wherein the included angle of two phasors is acute angle and positive active power, the included angle is obtuse angle and negative active power, the reference phasor is set according to the phase region in which the fault phasor falls, so that the included angle between the reference phasor and the fault phasor can be kept at an acute angle under any condition, and reliable guarantee is provided for qualitatively judging the fault phasor and selecting a line.
The device for judging the fault phase and the line selection by the phasor product active power method is originally created, judges the fault phase and the line selection qualitatively rather than quantitatively, does not depend on accurate calculation of each fault quantity to carry out judgment, does not need Fourier transform and other accurate calculation of the fault quantity, thereby abandoning the transient process in which the variable magic measurement is difficult to capture the law, and eliminating the complicated transient data to judge the fault phase and the line selection, thereby realizing the hundred percent of accuracy.
In specific implementation, for a G-phase single-phase earth fault of a system, fault phase judgment is carried out according to any criterion as follows:
criterion 1: multiplying the fault phasor by the fault phasor, namely: will be provided with
Are respectively connected with
And
multiply to obtain
And
wherein,
the phasor product of (a) is the largest and positive in active power;
referring to fig. 1, the fault point falls on a fault point trajectory semicircle, regardless of the ground impedance, and, in addition to the metallic ground,
and
included angle less than
And
at an included angle, an
Is greater than
Of a die, thereby
The phasor product active power is greater than
The phasor product of (a) is active, and the two are equal when the metal is grounded;
and
included angle of 90 deg., so
And
the phasor product of (2) is 0, so
And the leading phase
The phasor product of (a) is the largest and positive.
Criterion 2: multiplying the fault phasor by the three-phase symmetric reference phasor, namely: will be provided with
Are respectively connected with
And
multiply to obtain
And
wherein,
the phasor product of (a) is the largest and positive in active power;
referring to fig. 1, no matter how large the ground impedance is, the fault point falls on the fault point trajectory semicircle,
advance in
The phase is between-30 degrees and 60 degrees, the included angle between the two is always acute angle of 60 degrees at most, the included angle is 60 degrees when the two are grounded by metal, the included angle is less than 60 degrees in other cases,
the phasor product active of (a) is positive;
advance in
The phase is between 60 DEG and 150 DEG, the metallic grounding is 60 DEG, and the other conditions are all more than 60 DEG,
and
the moulds are the same, and the mould is the same,
the phasor product active power is greater than
The phasor product of (a) is active;
and
the included angle is 90-180 degrees,
the phasor product of (c) has a positive value. Therefore, the temperature of the molten metal is controlled,
the phasor product of (a) is the largest and positive.
Criterion 3: multiplying the fault phasor by the three-phase symmetric reference phasor, namely: will be provided with
Are respectively connected with
And
multiply to obtain
And
wherein,
the phasor product of (a) is the largest and positive in active power;
referring to fig. 1, no matter how large the ground impedance is, the fault point falls on the fault point trajectory semicircle,
advance in
The phase is between-60 degrees and 30 degrees, the included angle between the two is always acute angle of 60 degrees at most, the included angle is 30 degrees when the metal is grounded, the included angle is less than 60 degrees in other cases,
the phasor product active of (a) is positive;
advance in
The phase is between 90 DEG and 180 DEG, the metallic grounding is 90 DEG, and the other conditions are all larger than 90 DEG,
the phasor product active power of (a) is a negative value;
and
the included angle is 60-150 degrees,
and
the included angle is always larger than 60 degrees,
the phasor product active power is always less than
The phasor product of (a) is active. Therefore, the temperature of the molten metal is controlled,
the phasor product of (a) is the largest and positive.
Criterion 4: multiplying the fault phasor by the three-phase symmetric reference phasor, namely:
and
respectively with the same name
And
multiplying to obtain:
and
wherein,
the phasor product of (a) is the largest and positive in active power;
referring to fig. 1, no matter how large the ground impedance is, the fault point falls on the fault point trajectory semicircle,
and at the same ground impedance
And
included angle less than
And
at an angle of inclination of
And at the same ground impedance
And
included angle less than
And
at an angle of inclination of
The phasor product of (a) is active; therefore, the temperature of the molten metal is controlled,
the phasor product of (a) is the largest and positive.
Criterion 5: multiplying the fault phasor by the three-phase symmetric reference phasor, namely: will be provided with
And
respectively with the same name
And
multiply to obtain
And
wherein,
the phasor product of (a) is the largest and positive in active power;
referring to fig. 1, no matter how large the ground impedance is, the fault point falls on the fault point trajectory semicircle,
and at the same ground impedance
And
included angle less than
And
at an angle of inclination of
Therefore, the temperature of the molten metal is controlled,
the phasor product of (a) is the largest and positive.
Criterion 6: multiplying the fault phasor by the three-phase symmetric reference phasor, namely: will be provided with
Are respectively connected with
And
multiplying to obtain:
and
wherein
The phasor product of (a) is the largest and positive in active power;
and
to construct a set of three-phase symmetric reference phasors
And
leading three-phase voltage
And
are all in phase
Will be provided with
The value is randomly selected in the range of (-30 degrees and 60 degrees); or will be
Tracking neutral voltage according to equations (2.1) and (2.2)
Dynamically take value to
And
the included angle of (a) is acute and minimal.
With reference to figure 1 of the drawings,
advance in
The phase position is between-30 degrees and 60 degrees,
the optimal value of the fault point is 15 degrees, the fault point falls on any point on the semicircle of the fault point track,
with three-phase symmetrical reference phasors constructed
And
in (1)
The included angles are all less than 45 degrees, which is most beneficial
The phasor product of (a) is the largest.
Of course, it is also possible to
Tracking neutral voltage
The dynamic value of the numerical control system is taken,
advance in
Make it
And
is acute and close to 0, then,
the phasor product of the three-phase current transformer is more outstanding in power, and is more beneficial to fault phase judgment.
Criterion 7: multiplying the fault phasor by the three-phase symmetric reference phasor, namely: will be provided with
And
respectively with the same name
And
multiplying to obtain:
and
wherein,
the phasor product of (a) is the largest and positive in active power;
and
to construct a set of three-phase symmetric reference phasors
And
leading and triphase phase voltages
And
are all in phase
Will be provided with
Any value is taken in the range of (-30.5 degrees and 59.5 degrees); or will be
Tracking neutral voltage according to equations (2.1) and (2.3)
Dynamically take value to
And
the included angle of (a) is acute and minimal.
With reference to figure 1 of the drawings,
advance in
The phase position is between-3 degrees and 30 degrees,
the optimal value of the fault point is 13.5 degrees, the fault point falls on any point on the semicircle of the fault point track,
with three-phase symmetrical reference phasors constructed
And
in (1)
The included angles are all less than 16.5 degrees, which is most beneficial
The phasor product of (a) is the largest.
Of course, it is also possible to
Tracking neutral voltage
Dynamically take value to
And
is acute and close to 0, then,
the phasor product of the three-phase current transformer is more outstanding in power, and is more beneficial to fault phase judgment.
For intermittent arc grounding, the criterion of the fault phase of the invention is still valid and has higher accuracy:
referring to fig. 2, the intermittent single-phase grounding for power frequency arc quenching is realized by that, at the moment of arc quenching,
is perpendicular to the Y-axis,
is/are as follows
At the maximum, the number of the first,
and
the positive and negative values are in the same direction, namely in the same positive and negative directions, or in the same negative direction; moment of arc extinction
After the arc is extinguished,
a constant value equal to the arc-quenching time, and a leading phase voltage relative to ground
Until the arc light is re-ignited at the next fault point,
and
the same positive and negative then
The phasor product of (a) is still positive and maximal.
For the single-phase grounding of high-frequency arc quenching, the high-frequency arc quenching time and the power frequency arc quenching time have the same voltage memory characteristics:
and
the judgment method has the advantages that the judgment is carried out in the same direction, namely, in the same positive and negative directions, and is positive or negative at the same time, so that the judgment accuracy is not influenced, and the judgment accuracy is improved.
Any one of the above features may be used to determine a faulty phase, or two or more features may be used together to determine a faulty phase.
The phasor product of the invention actively judges a plurality of characteristic criteria given by a fault phase, and the plurality of criteria can be verified mutually, thus effectively ensuring the accuracy of the invention in judging the fault phase by one hundred percent and overcoming the technical problem that the fault phase is difficult to accurately judge.
In specific implementation, for the G-phase single-phase earth fault of the system, the capacitance current I of the jth non-fault lineCjCharacterized by the formula (3.1):
capacitive current of faulty line
Characterized by the formula (3.2)
X
CCapacitive current of non-faulty line for system to ground capacitive reactance
And fault line capacitance current
Has a phase difference of 180 DEG, and a fault line capacitance current
Voltage to fault
In-phase and lagging neutral voltage
The phase position is 90 degrees,
and
all leading the fault phase voltage
Is between 0 and 90 degrees.
And carrying out fault line selection according to any line selection criterion from the following criteria I to the third criterion:
criterion one is as follows: and multiplying the fault phasor by the line selection reference phasor to obtain a phasor product active power, namely: each line to be led out
And
obtained by multiplication
Phasor product active power of fault line
Is all that
The medium phasor product has the largest active power and is a positive value.
Referring to fig. 1, the capacitive current of the faulty line
Advance in
The included angle of the two is less than 60 degrees and is between-30 degrees and 60 degrees, but not the fault phase capacitance current
And i
CThe phase difference is 180 degrees,
the phasor product of (a) is positive,
the middle power is negative, therefore,
the phasor product of (1) is
The active power is the largest and positive.
Criterion two: and multiplying the fault phasor by the fault phasor and the line selection reference phasor to obtain a phasor product active:
if it is
Multiplying the fault phasor by the fault phasor to obtain phasor product active power, each outgoing line
And
obtained by multiplication
Phasor product active power of fault line
Is all that
The medium phasor product has the largest active power and is a positive value;
if it is
And then, multiplying the fault phasor by the line selection reference phasor to obtain a phasor product active power, namely: each line to be led out
And
obtained by multiplication
Phasor product active power of fault line
Is all that
The medium phasor product has the largest active power and is a positive value;
while the capacitance current of the fault line is in phase with the fault phase-to-ground voltage, the capacitance current of the fault line is in metallic grounding
Near metallic ground
Is also very small, the transient process is easy to generate adverse effect, and is not beneficial to the value of phasor product success, so the criterion setting
Avoiding single-phase earthing close to metallic earthing, multiplying fault phasor by fault phasor, of each outgoing line
And
the multiplication is carried out in such a way that,
the phasor product of (1) is
The middle active power is the largest and positive; for single-phase earthing close to metallic earthing, i.e.
While, each line is out
And
the multiplication is carried out in such a way that,
the phasor product of (1) is
The active power is the largest and positive.
Criterion three: and multiplying the fault phasor by the line selection reference phasor to obtain a phasor product active power, namely: each line to be led out
And
obtained by multiplication
Phasor product active power of fault line
Is all that
The medium phasor product has the largest active power and is a positive value.
With reference to figure 1 of the drawings,
advance in
Phase 90-180 DEG, capacitance current of fault line
Hysteresis
The phase position is 90 degrees,
advance in
The phase is 0 to 90 degrees,
is preferably 45 deg., so that
And
the included angle of (a) is acute under various grounding conditions,
the phasor product of (1) is
The active power is the largest and positive.
Of course, it is also possible to
Tracking neutral voltage
The dynamic value of the numerical control system is taken,
so that
And
is acute and close to 0, then,
the phasor product of (1) is
The active power is the largest and positive.
If the included angle between the reference phasor and the fault phasor is obtuse, i.e. the direction of the reference phasor is opposite to that of the fault phasor, the phasor product active of the reference phasor and the fault phasor is the most negative.
Any one of the above features may be used to determine a faulty phase, or two or more features may be used together to determine a faulty phase.
The phasor product active line selection method provides three characteristic criteria which can be verified mutually, thus effectively guaranteeing the accuracy of the line selection method in one hundred percent and overcoming the technical problem of line selection.