CN106570332B - A method of improving power equipment line loss calculation result - Google Patents
A method of improving power equipment line loss calculation result Download PDFInfo
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- CN106570332B CN106570332B CN201610983755.7A CN201610983755A CN106570332B CN 106570332 B CN106570332 B CN 106570332B CN 201610983755 A CN201610983755 A CN 201610983755A CN 106570332 B CN106570332 B CN 106570332B
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- G—PHYSICS
- G01—MEASURING; TESTING
- G01R—MEASURING ELECTRIC VARIABLES; MEASURING MAGNETIC VARIABLES
- G01R27/00—Arrangements for measuring resistance, reactance, impedance, or electric characteristics derived therefrom
- G01R27/02—Measuring real or complex resistance, reactance, impedance, or other two-pole characteristics derived therefrom, e.g. time constant
- G01R27/26—Measuring inductance or capacitance; Measuring quality factor, e.g. by using the resonance method; Measuring loss factor; Measuring dielectric constants ; Measuring impedance or related variables
- G01R27/2688—Measuring quality factor or dielectric loss, e.g. loss angle, or power factor
- G01R27/2694—Measuring dielectric loss, e.g. loss angle, loss factor or power factor
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- G—PHYSICS
- G06—COMPUTING; CALCULATING OR COUNTING
- G06Q—INFORMATION AND COMMUNICATION TECHNOLOGY [ICT] SPECIALLY ADAPTED FOR ADMINISTRATIVE, COMMERCIAL, FINANCIAL, MANAGERIAL OR SUPERVISORY PURPOSES; SYSTEMS OR METHODS SPECIALLY ADAPTED FOR ADMINISTRATIVE, COMMERCIAL, FINANCIAL, MANAGERIAL OR SUPERVISORY PURPOSES, NOT OTHERWISE PROVIDED FOR
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- G—PHYSICS
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Abstract
The present invention provides a kind of method for improving power equipment line loss calculation result, comprising: S1, marks off multiple line loss gross datas according to voltage class；Wherein, the multiple line loss gross data includes the corresponding line loss gross data of 0.4kV voltage class, the corresponding line loss gross data of 10kV voltage class and at least corresponding line loss gross data of 110kV voltage class；S2, it determines currently selected line loss gross data, and according to currently selected line loss gross data, determines corresponding calculating mode, obtain by the currently selected calculated line loss of line loss gross data.Implement the embodiment of the present invention, it can be achieved that datamation is counted and calculated, and can be improved the accuracy of line loss calculation result.
Description
Technical field
The present invention relates to power equipment line loss calculation technical field more particularly to a kind of improvement power equipment line loss calculation knots
The method of fruit.
Background technique
Line loss per unit is an important economic and technical norms in power supply enterprise's production run, and measures power supply enterprise's technology
Horizontal and management level important symbol, however line loss per unit depends on the accurate calculating of theory wire loss value, therefore manages according to line loss
By calculating as a result, just can be carried out the effective analysis and effective formulation of reducing loss measure of line loss.
Currently, the domestic system with line loss statistical function mainly has a marketing system and metering automation system, but with
In terms of the line loss theoretical calculation that the two matches, it is also limited to manual construction power network topology, parameter typing and calculates data, simultaneously
In calculating process, only chooses representative reference point or calculated with reference to corresponding parameter values of key points such as days, made
The accuracy for obtaining calculated result remains to be discussed.
Summary of the invention
A kind of power equipment line loss calculation result is improved the technical problem to be solved by the embodiment of the invention is that providing
Method is, it can be achieved that datamation is counted and calculated, and can be improved the accuracy of line loss calculation result.
In order to solve the above-mentioned technical problem, the embodiment of the invention provides a kind of improvement power equipment line loss calculation results
Method the described method comprises the following steps:
Step S1, multiple line loss gross datas are marked off according to voltage class；Wherein, the multiple line loss gross data packet
Include the corresponding line loss gross data of 0.4kV voltage class, the corresponding line loss gross data of 10kV voltage class and at least 110kV
The corresponding line loss gross data of voltage class；
Step S2, it determines currently selected line loss gross data, and according to currently selected line loss gross data, determines phase
The calculating mode answered is obtained by the currently selected calculated line loss of line loss gross data；Wherein, 0.4kV power grid is based on actual measurement
Line loss is calculated, 10kV power grid is calculated based on equivalent resistance and the power grid of at least 110kV is based respectively on overhead transmission line, electricity
Cable road, two-winding transformer and three-winding transformer carry out loss calculation；
Wherein, the step S2 is specifically included:
The currently selected line loss gross data be at least 110kV voltage class corresponding line loss gross data when,
The power grid that voltage is at least 110kV is based respectively on overhead transmission line, cable run, double wrap under same preset second calculation interval
Group transformer and three-winding transformer carry out loss calculation, obtain corresponding first calculated result, the second calculated result, third meter
Result and the 4th calculated result are calculated, and first calculated result, the second calculated result, third calculated result and the 4th are calculated
As a result it carries out cumulative later as line loss output；
Wherein, described that the power grid that voltage is at least 110kV is based on overhead line under same preset second calculation interval
Road carries out loss calculation, and the specific steps for obtaining corresponding first calculated result include:
Obtain the active energy of each overhead transmission line and capacity of idle power and each overhead transmission line under second calculation interval
Voltage rating, and according to voltage rating, active energy and the capacity of idle power of each overhead transmission line got, it obtains each aerial
The average value of line load electric current, and according to the average value of obtained each overhead transmission line load current, determine each overhead line
The rms current on road；
It determines the resistance under each overhead transmission line normal temperature, and obtains working as each overhead transmission line under second calculation interval
Preceding temperature and number of lead wires, the length of each conducting wire and its corresponding conducting wire allow current-carrying value and split bar number, according to described each
The rms current and Current Temperatures and number of lead wires of overhead transmission line, the length of each conducting wire and its corresponding conducting wire allow to carry
Resistance under each overhead transmission line normal temperature is changed to the element electricity of each overhead transmission line by flow valuve and split bar number respectively
Resistance；
According to the duration of the rms current of each overhead transmission line, component resistance and the second calculation interval, obtain each
The electric energy loss of overhead transmission line；
Obtain the rated current for being series at the reactor at each overhead transmission line both ends and the loss of unit time rated no-load, and root
It is lost according to the rated current and unit time nominal load of each reactor got, obtains total electric energy damage of reactor
Consumption；
The electric energy loss of each overhead transmission line is added up, and further with total electric energy loss of the reactor into
It is exported after row is cumulative as the first calculated result.
Wherein, the step S2 is specifically included:
When the currently selected line loss gross data is 0.4kV voltage class corresponding line loss gross data, by 0.4kV
Power grid is based on actual measurement line loss and is calculated；
The 0.4kV power grid is divided into multiple low voltage electric networks by load character, and each low voltage electric network includes identical
Multiple load types；
In the multiple low voltage electric network multiple areas are chosen to each load type respectively, and obtains each low tension
The capacity of distribution transform in the area Wang Zhonggetai, and obtain the area each low voltage electric network Zhong Getai actually measured power supply volume and electricity sales amount；
According to the area each low voltage electric network Zhong Getai got actually measured power supply volume and electricity sales amount, calculate every
The electric energy loss in one area low voltage electric network Zhong Getai, and the area each low voltage electric network Zhong Getai further got according to matches
Varying capacity and its calculated electric energy loss calculate the corresponding electric energy loss rate of each load type in each low voltage electric network；
According to corresponding area's total capacity of load type each in preset each low voltage electric network and calculated every
The corresponding electric energy loss rate of each load type in one low voltage electric network obtains the corresponding electric energy of each load type in each low voltage electric network
Loss, and the corresponding electric energy loss of load type each in obtained each low voltage electric network is added up, it obtains each low
The electric energy loss of voltage electric grid；
The electric energy loss of obtained each low voltage electric network is carried out after adding up, it is corresponding to obtain the 0.4kV power grid
The whole network electric energy loss and as line loss export.
Wherein, the low voltage electric network includes city net, suburb net and rural area net.
Wherein, the load type includes heavy load, middle load and light load.
Wherein, the step S2 is specific further include:
When the currently selected line loss gross data is 10kV voltage class corresponding line loss gross data, by 10kV electricity
Net is calculated based on equivalent resistance；
The 10kV power grid is divided into multiple wirings, and includes multiple distribution transformings in each wiring；
It determines in the voltage rating and the 10kV power grid of the 10kV power grid contained by wiring sum and each wiring
With parameter, and further determine that the unit time rated no-load loss of each distribution transforming, and according to each wiring institute of the determination
What is contained matches parameter, counts distribution transforming sum in the 10kV power grid；
Obtain the rated capacity and its loss of corresponding nominal load of each distribution transforming, and according to it is described get each match
The voltage rating and distribution transforming sum of the rated capacity of change and its loss of corresponding nominal load and 10kV power grid, calculate institute
State the distribution transforming substitutional resistance of 10kV power grid；
Obtain the resistance of each wiring, and according to the resistance and its contained distribution number of each wiring got,
And wiring sum in 10kV power grid, calculate the wiring substitutional resistance of the 10kV power grid；
The active energy and capacity of idle power of 10kV power grid under preset first calculation interval are obtained, and is got according to described
10kV power grid voltage rating, active energy and capacity of idle power, obtain the average value of 10kV network load electric current, and according to institute
The average value for the 10kV network load electric current stated determines the rms current of the 10kV power grid；
Total according to the rms current of the 10kV power grid, distribution transforming substitutional resistance and wiring substitutional resistance and distribution transforming,
The duration of unit time the rated no-load loss and the first calculation interval of each distribution transforming, obtains the whole network electric energy of the 10kV power grid
It is lost and is exported as line loss.
Wherein, described that the power grid that voltage is at least 110kV is based on cable under same preset second calculation interval
Road carries out loss calculation, obtains the specific steps of corresponding second calculated result further include:
Obtain the active energy of each cable run and capacity of idle power and each cable run under second calculation interval
Voltage rating, and according to voltage rating, active energy and the capacity of idle power of each cable run got, obtain each cable
The average value of line load electric current, and according to the average value of obtained each cable run load current, determine each cable
The rms current on road；
It determines the resistance under each cable run normal temperature, and obtains each cable run under second calculation interval
Current Temperatures and number of lead wires, the length of each conducting wire and its corresponding conducting wire allow current-carrying value and split bar number, according to institute
State the rms current and Current Temperatures and number of lead wires of each cable run, the length of each conducting wire and its corresponding conducting wire are held
Resistance under each cable run normal temperature is changed to the element of each cable run by current-carrying value and split bar number perhaps respectively
Resistance；
According to the duration of the rms current of each cable run, component resistance and the second calculation interval, obtain each
The electric energy loss of overhead transmission line；
According to the number of lead wires of each cable run, the length of each conducting wire, pass through mean geometrical distance between adjacent wires
Calculate the electromagnetic consumable of each cable run；
The electric energy loss of the cable run is added up, and the electromagnetic consumable of the cable run is added up,
And further two the sum of cumulative are added are exported as the second calculated result.
Wherein, described that the power grid that voltage is at least 110kV is based on double winding under same preset second calculation interval
Transformer carries out loss calculation, obtains the specific steps of corresponding third calculated result further include:
The on high-tension side active energy of each two-winding transformer under second calculation interval and capacity of idle power are obtained, and each
The on high-tension side voltage rating of two-winding transformer, and according to the on high-tension side specified electricity of each two-winding transformer got
Pressure, active energy and capacity of idle power, obtain the average value of each two-winding transformer high-pressure side load current, and obtain according to described
Each two-winding transformer high-pressure side load current average value, determine the on high-tension side rms current of each two-winding transformer；
Determine the unit time rated no-load loss of each two-winding transformer, and according to the list of each two-winding transformer
The duration of position time rated no-load loss and the second calculation interval, obtains each two-winding transformer under second calculation interval
Total specified no-load loss；
Determine the rated capacity and its loss of corresponding unit time nominal load of each two-winding transformer, and according to described
Rated capacity, high-pressure side voltage rating and the loss of unit time nominal load of each two-winding transformer, obtain each double winding and become
The equivalent resistance of depressor winding；
When being calculated according to the equivalent resistance of each two-winding transformer winding, on high-tension side rms current and second
The duration of section, obtains the electric energy loss of each two-winding transformer；
It determines the rated current for each reactor being installed in each two-winding transformer low-pressure side and its corresponds to double winding
The voltage rating of step down side, and according to the rated current of each reactor and its corresponding two-winding transformer low pressure
The voltage rating of side and on high-tension side voltage obtain each reactor reduction on high-tension side electric current；
Determine the unit time nominal loss of each reactor, and according to each reactor reduction on high-tension side electric current,
Unit time nominal loss and its corresponding on high-tension side rms current of two-winding transformer obtain the electric energy damage of each reactor
Consumption；
Total specified no-load loss of each two-winding transformer is added up, and by the electric energy of each two-winding transformer
Loss adds up, and the electric energy loss of each reactor is added up, and further by three is the sum of cumulative be added after make
For the output of third calculated result.
Wherein, described that the power grid that voltage is at least 110kV is based on three winding under same preset second calculation interval
Transformer carries out loss calculation, and the specific steps for obtaining corresponding 4th calculated result include:
Obtain each three-winding transformer medium voltage side and the corresponding active energy of low-pressure side under second calculation interval
And capacity of idle power and each three-winding transformer medium voltage side and the corresponding voltage rating of low-pressure side, and according to the acquisition
Each three-winding transformer medium voltage side and the corresponding voltage rating of low-pressure side, active energy and capacity of idle power arrived obtains each
Three-winding transformer medium voltage side and low-pressure side respectively correspond the average value of load current, and are become according to obtained each three winding
Depressor medium voltage side and low-pressure side respectively correspond the average value of load current, determine each three-winding transformer medium voltage side and low-pressure side point
Not corresponding rms current；
Determine the unit time rated no-load loss of each three-winding transformer, and according to the list of each three-winding transformer
The duration of position time rated no-load loss and the second calculation interval, obtains each three-winding transformer under second calculation interval
Total specified no-load loss；
Determine the high pressure rated capacity, middle pressure rated capacity, low-voltage rated capacity, the specified electricity of high pressure of each three-winding transformer
Pressure, middle pressure voltage rating and low-voltage rated voltage, and determine the unit time high pressure nominal load of each three-winding transformer
Loss, the loss of unit time mesolow nominal load and the loss of unit time high-low pressure nominal load；
According to the high pressure rated capacity of each three-winding transformer, high pressure voltage rating, middle pressure rated capacity and unit
The loss of time high pressure nominal load, obtains the equivalent resistance of high pressure winding after each three-winding transformer reduction to high-pressure side,
And it is high according to the high pressure rated capacity of each three-winding transformer, high pressure voltage rating, low-voltage rated capacity and unit time
Low-voltage rated load loss obtains the equivalent resistance of high-low pressure winding after each three-winding transformer reduction to high-pressure side, goes forward side by side one
Step is according to the high pressure rated capacity of each three-winding transformer, high pressure voltage rating, middle pressure rated capacity, low-voltage rated capacity
And the loss of unit time mesolow nominal load, obtain the equivalent of mesolow winding after each three-winding transformer reduction to high-pressure side
Resistance；
According to high pressure winding, high-low pressure winding and mesolow winding after each three-winding transformer reduction to high-pressure side
Corresponding equivalent resistance calculates the high-pressure side equivalent resistance, medium voltage side equivalent resistance and low pressure of each three-winding transformer
Side equivalent resistance；
According to the high-pressure side equivalent resistance of each three-winding transformer, medium voltage side equivalent resistance and the equivalent electricity of low-pressure side
The duration of resistance and each three-winding transformer medium voltage side and low-pressure side corresponding rms current and the second calculation interval,
Obtain the electric energy loss of each three-winding transformer；
It determines the rated current for each reactor being installed on each three-winding transformer medium voltage side and its corresponds to three winding
The high pressure voltage rating of transformer and middle pressure voltage rating, and according to the rated current of each reactor and its corresponding three around
The high pressure voltage rating and middle pressure voltage rating and low-voltage rated voltage of group transformer, obtain each reactor reduction of medium voltage side and arrive
On high-tension side electric current, and further determine that each reactor being installed in each three-winding transformer low-pressure side rated current and
Its high pressure voltage rating and low-voltage rated voltage for corresponding to three-winding transformer, according to the rated current of each reactor and
Its high pressure voltage rating and low-voltage rated voltage for corresponding to three-winding transformer, obtain each reactor reduction of low-pressure side to high pressure
The electric current of side；
Determine the unit time nominal loss of each reactor in medium voltage side and low-pressure side, and according to same three winding transformation
The unit time nominal loss of the corresponding rms current of medium voltage side and low-pressure side, medium voltage side reactor that are obtained on device and
It corresponds to reduction to the unit time nominal loss of on high-tension side electric current and low pressure reactor and its correspondence reduction to high pressure
The electric current of side obtains the electric energy loss of reactor on each three-winding transformer；
Total specified no-load loss of each three-winding transformer is added up, and by the electric energy of each three-winding transformer
Loss adds up, and the electric energy loss of reactor on each three-winding transformer is added up, and further tire out three
It is used as the 4th calculated result to export with after being added in addition.
The implementation of the embodiments of the present invention has the following beneficial effects:
In embodiments of the present invention, due to marking off multiple line loss gross datas according to voltage class, in different line losses
In gross data, using different parameters carry out that the higher line loss of accuracy is calculated, it can be achieved that datamation statistics and
It calculates, and can be improved the accuracy of line loss calculation result.
Detailed description of the invention
In order to more clearly explain the embodiment of the invention or the technical proposal in the existing technology, to embodiment or will show below
There is attached drawing needed in technical description to be briefly described, it should be apparent that, the accompanying drawings in the following description is only this
Some embodiments of invention, for those of ordinary skill in the art, without any creative labor, according to
These attached drawings obtain other attached drawings and still fall within scope of the invention.
Fig. 1 is a kind of flow chart of method for improving power equipment line loss calculation result provided in an embodiment of the present invention.
Specific embodiment
To make the object, technical solutions and advantages of the present invention clearer, the present invention is made into one below in conjunction with attached drawing
Step ground detailed description.
As shown in Figure 1, for a kind of method for improving power equipment line loss calculation result provided in an embodiment of the present invention, it is described
Method includes:
Step S1, multiple line loss gross datas are marked off according to voltage class；Wherein, the multiple line loss gross data packet
Include the corresponding line loss gross data of 0.4kV voltage class, the corresponding line loss gross data of 10kV voltage class and at least 110kV
The corresponding line loss gross data of voltage class；
Step S2, it determines currently selected line loss gross data, and according to currently selected line loss gross data, determines phase
The calculating mode answered is obtained by the currently selected calculated line loss of line loss gross data；Wherein, 0.4kV power grid is based on actual measurement
Line loss is calculated, 10kV power grid is calculated based on equivalent resistance and the power grid of at least 110kV is based respectively on overhead transmission line, electricity
Cable road, two-winding transformer and three-winding transformer carry out loss calculation.
In embodiments of the present invention, three grades is divided into according to the size of network voltage: 0.4kV low voltage electric network, 10kV
Power distribution network and 110kV and the above high-voltage fence, and the corresponding line loss gross data of above-mentioned three kinds of voltage class is selected to carry out respectively
Line loss calculation obtains three kinds of different line losses, so that the accuracy of line loss calculation result is higher.
Using above-mentioned three kinds of line loss gross datas calculate line loss concrete steps are accomplished as follows:
(I) 0.4kV low voltage electric network:
It step S201, will when currently selected line loss gross data is 0.4kV voltage class corresponding line loss gross data
0.4kV power grid is based on actual measurement line loss and is calculated；
Step S202,0.4kV power grid is divided into multiple low voltage electric networks by load character, and each low voltage electric network includes phase
Same multiple load types；In one embodiment, low voltage electric network includes city net, suburb net and rural area net；Load type packet
Include heavy load, middle load, light load；
Step S203, in multiple low voltage electric networks multiple areas are chosen to each load type respectively, and obtained each
The capacity of distribution transform in the area low voltage electric network Zhong Getai, and obtain the area each low voltage electric network Zhong Getai actually measured power supply volume and sale of electricity
Amount；
Step S204, power supply volume and electricity sales amount actually measured according to the area each low voltage electric network Zhong Getai got, meter
The electric energy loss in the area each low voltage electric network Zhong Getai is calculated, and further according to the area each low voltage electric network Zhong Getai got
Capacity of distribution transform and its calculated electric energy loss calculate the corresponding electric energy loss rate of each load type in each low voltage electric network；
Step S205, according to corresponding area's total capacity of load type each in preset each low voltage electric network, and
The corresponding electric energy loss rate of each load type, obtains each load type in each low voltage electric network in calculated each low voltage electric network
Corresponding electric energy loss, and the corresponding electric energy loss of load type each in obtained each low voltage electric network is added up, it obtains
The electric energy loss of each low voltage electric network；
Step S206, the electric energy loss of obtained each low voltage electric network is carried out after adding up, it is corresponding obtains 0.4kV power grid
The whole network electric energy loss and as line loss export.
In one embodiment, 0.4kV low voltage electric network is divided into city net, suburb net and rural area net, and load type point
For heavy load, middle load, light load；
By taking city is netted as an example, m is chosen respectively to three types loadiThe area Ge Tai (i=1,2,3), determines heavy load platform
Area capacity of distribution transform SHTj(j=1,2 ... .., m1), middle load platform area capacity of distribution transform SMTj(j=1,2 ... .., m2) and underload
Platform area capacity of distribution transform SLTj(j=1,2 ... .., m3), and the further power supply volume and electricity sales amount in actually measured each area；It answers
When explanation, all areas all should comply with following condition: load is normal, measures complete, ammeter normal operation, and no stealing is existing
As；
According to the power supply volume and electricity sales amount in each actually measured area, the electric energy loss Δ in heavy load platform area is calculated
AHTj(j=1,2 ... .., m1), the electric energy loss Δ A in middle load platform areaMTj(j=1,2 ... .., m2) and underload platform area
Electric energy loss Δ ALTj(j=1,2 ... .., m3)；Wherein, the electric energy loss in platform area=platform area power supply volume-platform area sale of electricity
Amount；
Calculate the corresponding electric energy loss rate L in heavy load platform areaavH, the corresponding electric energy loss rate L in middle load platform areaavMWith it is low
The corresponding electric energy loss rate L in load platform areaavL, it may be assumed that
Determine heavy load Tai Qu, middle load platform area and the corresponding total capacity S in underload platform areaH,SM,SL；Wherein, SH
=SHJ1+...+SHTj+...+SHTm1；SM=SMJ1+...+SMTj+...+SMTm2；SL=SLJ1+...+SLTj+...+SLTm3
Therefore, the electric energy loss of city net are as follows: Δ A1=LavHSH+LavMSM+LavLSL；
Above-mentioned calculating is repeated, city net, suburb net and rural area is can get and nets corresponding electric energy loss Δ Ak(k=1,
2,3) the whole network electric energy loss of 0.4kV low voltage electric network, is thus obtained are as follows:And the whole network electric energy loss that will be obtained
It is exported as line loss.
(II) 10kV power distribution network:
It, will when step 211, currently selected line loss gross data are 10kV voltage class corresponding line loss gross data
10kV power grid is calculated based on equivalent resistance；
Step 212,10kV power grid are divided into multiple wirings, and include multiple distribution transformings in each wiring；
In step 213, the voltage rating for determining 10kV power grid and 10kV power grid contained by wiring sum and each wiring
With parameter, and further determine that the unit time rated no-load loss of each distribution transforming, and according to each wiring institute of the determination
What is contained matches parameter, counts distribution transforming sum in 10kV power grid；
Step 214, the rated capacity for obtaining each distribution transforming and its loss of corresponding nominal load, and it is every according to what is got
The voltage rating and distribution transforming sum of the rated capacity of one distribution transforming and its loss of corresponding nominal load and 10kV power grid, calculate
The distribution transforming substitutional resistance of 10kV power grid out；
Step 215, the resistance for obtaining each wiring, and according to the resistance and its contained distribution of each wiring got
Wiring sum, calculates the wiring substitutional resistance of 10kV power grid in several and 10kV power grid；
Step 216, the active energy and capacity of idle power for obtaining 10kV power grid under preset first calculation interval, and according to obtaining
Voltage rating, active energy and the capacity of idle power for the 10kV power grid got obtain the average value of 10kV network load electric current, and root
According to the average value of obtained 10kV network load electric current, the rms current of 10kV power grid is determined；
Step 217, according to the rms current of 10kV power grid, distribution transforming substitutional resistance and wiring substitutional resistance and distribution transforming
The unit time rated no-load of total, each distribution transforming is lost and the duration of the first calculation interval, obtains the whole network electricity of 10kV power grid
It can be lost and be exported as line loss.
In one embodiment, 10kV power grid building equivalent resistance model is calculated, 10kV power grid is equivalent at this time
Multiple wirings comprising distribution transforming are constituted；Wherein, distribution transforming contained by wiring has multiple；
It counts and matches parameter contained by wiring sum and each wiring, parameter is matched according to contained by each wiring, is counted
Distribution transforming is total, and the distribution transforming substitutional resistance R of 10kV power grid is calculated according to formula (1)Tdz:
In formula (1), U is the voltage rating of 10kV power grid, SiFor the rated capacity of i-th distribution transforming, PkiFor i-th distribution transforming
Nominal load loss, n are distribution transforming sum in 10kV power grid；
The wiring substitutional resistance R of 10kV power grid is calculated according to formula (2)Ldz:
In formula (2), rjFor the resistance of j-th of wiring, LjTo match parameter contained by j-th of wiring, n is in 10kV power distribution network
Distribution transforming sum, m are wiring sum in 10kV power grid；
The active energy and capacity of idle power for determining 10kV power grid in the first calculation interval obtain 10kV electricity according to formula (3)
The average value I of net load currentave:
In formula (3), TmFor the duration of the first calculation interval, E is the active energy of 10kV power grid, and Q is 10kV power distribution network
Capacity of idle power, U are the voltage rating of 10kV power grid；
By the average value I of 10kV network load electric currentaveIt is calculated by formula (4), obtains the root mean square of 10kV power grid
Electric current Ijf:
Ijf=kIave (4)
In formula (4), k is current shape coefficient；Wherein, the operating parameter for influencing current curve shape has rate of load condensate f and most
Smaller load rate α, i.e. current shape coefficient k are that the function representation of f and α is k=F (f, α), according to " power network line losses calculate
Directive/guide ", as f > 0.5, thenAs f < 0.5 and f > α, have
Determine the unit time rated no-load loss of each distribution transforming, and according to the root mean square of 10kV power grid obtained above electricity
Flow Ijf, distribution transforming substitutional resistance RTdzWith wiring substitutional resistance RLdzAnd distribution transforming sum n and the first calculation interval Tm, pass through formula
(5), it obtains the whole network electric energy loss Δ A of 10kV power distribution network and is exported as line loss:
In formula (5), P0iIt is lost for the unit time rated no-load of i-th of distribution transforming.
It should be noted that 10kV power grid can also realize the output of line loss calculation result based on power flow algorithm.
(III) high-voltage fence of 110kV or more:
Currently selected line loss gross data be at least 110kV voltage class corresponding line loss gross data when, same
The power grid that voltage is at least 110kV overhead transmission line, cable run, double winding is based respectively under preset second calculation interval to become
Depressor and three-winding transformer carry out loss calculation, obtain corresponding first calculated result, the second calculated result, third and calculate knot
Fruit and the 4th calculated result, and the first calculated result, the second calculated result, third calculated result and the 4th calculated result are carried out
It is exported after cumulative as line loss.
Therefore, when the corresponding line loss gross data of at least 110kV voltage class calculates, four elements can be divided into: aerial
Route (including series reactance), cable run, two-winding transformer (including series reactance), three-winding transformer (including series connection
Reactance) it is respectively calculated, and four calculated results are the sum of cumulative as final line loss.
(a) loss calculation is carried out based on overhead transmission line, the specific steps for obtaining the first calculated result include:
Step 2211 obtains under the second calculation interval the active energy of each overhead transmission line and capacity of idle power and each aerial
The voltage rating of route, and according to the voltage rating of each overhead transmission line got, active energy and capacity of idle power, obtain each frame
The average value of ceases to be busy road load current, and according to the average value of obtained each overhead transmission line load current, determine each overhead transmission line
Rms current；
Step 2212 determines resistance under each overhead transmission line normal temperature, and obtains each overhead line under the second calculation interval
The Current Temperatures and number of lead wires on road, the length of each conducting wire and its corresponding conducting wire allow current-carrying value and split bar number, according to
The rms current and Current Temperatures and number of lead wires of each overhead transmission line, the length of each conducting wire and its corresponding conducting wire are allowed
Resistance under each overhead transmission line normal temperature is changed to the component resistance of each overhead transmission line by current-carrying value and split bar number respectively；
Step 2213, according to the duration of the rms current of each overhead transmission line, component resistance and the second calculation interval, obtain
To the electric energy loss of each overhead transmission line；
Step 2214, acquisition are series at the rated current and unit time rated no-load of the reactor at each overhead transmission line both ends
Loss, and be lost according to the rated current of each reactor got and unit time nominal load, obtain reactor
Total electric energy loss；
Step 2215 adds up the electric energy loss of each overhead transmission line, and further with total electric energy loss of reactor
It carries out cumulative later as the output of the first calculated result.
In one embodiment, by taking one section of overhead transmission line as an example, according to the voltage rating of the overhead transmission line, active energy and
Capacity of idle power obtains the average value of the overhead transmission line load current by formula (3), and according to the overhead transmission line load current
Average value determines the rms current of the overhead transmission line by formula (4)；
Determine the resistance under the overhead transmission line normal temperature, due to manufacturer provide normal temperature (such as 20 DEG C) when lead
The resistance value of every kilometer of line, therefore in actually calculating, temperature rise caused by load current and ambient air temperature are considered as to electricity
The influence of resistive, is modified resistance, and when the overhead transmission line has n kind model conducting wire, and various conductor lengths, division number are not
Together, at this moment the all-in resistance of whole overhead transmission line is calculated by formula (6):
In formula (6), CiFor the length of i kind model conducting wire, Ri(20C)It is i-th kind of conducting wire in the overhead transmission line at 20 DEG C
Resistance value, IjfFor the rms current value of the overhead transmission line, IpiCurrent-carrying value, N are allowed for i-th kind of conducting wireciFor i-th kind of conducting wire point
The item number split, tmFor Current Temperatures；
According to formula (7), the electric energy loss Δ E of the overhead transmission line is obtainedl:
ΔEl=3Ijf 2RT (7)
In formula (7), T is the duration of the second calculation interval；
It determines the rated current for being series at the reactor at the overhead transmission line both ends and the loss of unit time rated no-load, and leads to
Formula (8) are crossed, the electric energy loss Δ E of reactor is obtainedr:
In formula (8), IrFor the rated current of r-th of reactor on the overhead transmission line, PrFor r-th of electricity on the overhead transmission line
The unit time rated no-load of anti-device is lost；
By the electric energy loss Δ E of the overhead transmission linelWith the electric energy loss Δ E of reactorrAddition obtains the damage of the overhead transmission line
Consumption；
It repeats the above steps, obtains the loss of all overhead transmission lines, and the loss of all overhead transmission lines is added up it
It is exported afterwards as the first calculated result.
(b) loss calculation is carried out based on cable run, the specific steps for obtaining the second calculated result include:
Step 2221 obtains the active energy of each cable run and capacity of idle power and each cable under the second calculation interval
The voltage rating of route, and according to the voltage rating of each cable run got, active energy and capacity of idle power, obtain each electricity
The average value of cable road load current, and according to the average value of obtained each cable run load current, determine each cable run
Rms current；
Step 2222 determines resistance under each cable run normal temperature, and obtains each cable under the second calculation interval
The Current Temperatures and number of lead wires on road, the length of each conducting wire and its corresponding conducting wire allow current-carrying value and split bar number, according to
The rms current and Current Temperatures and number of lead wires of each cable run, the length of each conducting wire and its corresponding conducting wire are allowed
Resistance under each cable run normal temperature is changed to the component resistance of each cable run by current-carrying value and split bar number respectively；
Step 2223, according to the duration of the rms current of each cable run, component resistance and the second calculation interval, obtain
To the electric energy loss of each overhead transmission line；
Step 2224, the number of lead wires according to each cable run, the length of each conducting wire, pass through average geometric between adjacent wires
Distance calculates the electromagnetic consumable of each cable run；
The electric energy loss of cable run is added up, and the electromagnetic consumable of cable run is added up by step 2225,
And further two the sum of cumulative are added are exported as the second calculated result.
It should be noted that corresponding to the loss calculation of overhead transmission line, the loss calculation based on cable run is not only wrapped
Include the loss calculation of overhead transmission line, it is also necessary to which considering transmission line of electricity, there are electromagnetic induction phenomenon, this electromagnetism to neighbouring route
Induction can be calculated by mean geometrical distance between conducting wire.Therefore, not for the loss calculation of aforementioned existing overhead transmission line
Embodiment explanation is carried out again.
(c) loss calculation is carried out based on two-winding transformer, the specific steps for obtaining third calculated result include:
Step 2231 obtains the on high-tension side active energy of each two-winding transformer and capacity of idle power under the second calculation interval,
And each on high-tension side voltage rating of two-winding transformer, and according to the on high-tension side specified electricity of each two-winding transformer got
Pressure, active energy and capacity of idle power, obtain the average value of each two-winding transformer high-pressure side load current, and each according to what is obtained
The average value of two-winding transformer high-pressure side load current determines the on high-tension side rms current of each two-winding transformer；
Step 2232, the unit time rated no-load loss for determining each two-winding transformer, and according to each double winding transformation
The unit time rated no-load of device is lost and the duration of the second calculation interval, obtains each double winding transformation under the second calculation interval
Total specified no-load loss of device；
Step 2233, the rated capacity for determining each two-winding transformer and its loss of corresponding unit time nominal load,
And be lost according to the rated capacity, high-pressure side voltage rating and unit time nominal load of each two-winding transformer, it obtains
The equivalent resistance of each two-winding transformer winding；
Step 2234, the equivalent resistance according to each two-winding transformer winding, on high-tension side rms current and second
The duration of calculation interval obtains the electric energy loss of each two-winding transformer；
Step 2235 determines the rated current of each reactor being installed in each two-winding transformer low-pressure side and its right
The voltage rating of two-winding transformer low-pressure side is answered, and according to the rated current of each reactor and its corresponding two-winding transformer
The voltage rating of low-pressure side and on high-tension side voltage obtain each reactor reduction on high-tension side electric current；
Step 2236, the unit time nominal loss for determining each reactor, and according to each reactor reduction to high pressure
Electric current, unit time nominal loss and its corresponding on high-tension side rms current of two-winding transformer of side, obtain each reactor
Electric energy loss；
Step 2237 adds up total specified no-load loss of each two-winding transformer, and each double winding is become
The electric energy loss of depressor adds up, and the electric energy loss of each reactor is added up, and three is further added up it
Be added after as third calculated result export.
In one embodiment, by taking a two-winding transformer as an example, according to the on high-tension side specified electricity of the two-winding transformer
Pressure, active energy and capacity of idle power, obtain the average value of the two-winding transformer high-pressure side load current by formula (3), and
According to the average value of the two-winding transformer high-pressure side load current, which is determined by formula (4)
Rms current；
Determine the unit time rated no-load loss P of the two-winding transformer0, by formula (9), obtain double winding change
Δ E is lost in the rated no-load of depressor0:
ΔE0=P0T (9)
The substitutional resistance r of the two-winding transformerTIs defined as: as rated current InWhen flowing through, nominal load loss is generated
Pk, i.e.,Therefore substitutional resistance rTIt can be obtained by formula (10):
In formula (10), UnFor the two-winding transformer high-pressure side voltage rating, S is the two-winding transformer rated capacity；
Further according to formula (11), the electric energy loss Δ E of the two-winding transformer is obtainedT:
ΔET=3Ijf 2rTT (11)
In formula (11), IjfFor the on high-tension side rms current of the two-winding transformer；
It is I in view of the two-winding transformer low-pressure side is often equipped with rated current2kr, nominal loss pr2Reactor, can
By the rated current reduction of current-limiting reactor to high-pressure side, current valueIt is obtained by formula (12), and further passes through public affairs
Formula (13) obtains the electric energy loss Δ E of the two-winding transformer low pressure reactorL:
In formula (12), U1nFor the two-winding transformer low-pressure side voltage rating；
Therefore, the electric energy loss of the two-winding transformer are as follows:
It repeats the above steps, acquires the electric energy loss of all two-winding transformers, and all electric energy losses are added and are made
For the output of third calculated result.
(d) loss calculation is carried out based on three-winding transformer, the specific steps for obtaining the 4th calculated result include:
Each three-winding transformer medium voltage side and low-pressure side are corresponding active under step 2241, the second calculation interval of acquisition
Electricity and capacity of idle power and each three-winding transformer medium voltage side and the corresponding voltage rating of low-pressure side, and according to acquisition
Each three-winding transformer medium voltage side and the corresponding voltage rating of low-pressure side, active energy and capacity of idle power arrived obtains each
Three-winding transformer medium voltage side and low-pressure side respectively correspond the average value of load current, and according to obtained each three-winding transformer
Medium voltage side and low-pressure side respectively correspond the average value of load current, determine that each three-winding transformer medium voltage side and low-pressure side are right respectively
The rms current answered；
Step 2242, the unit time rated no-load loss for determining each three-winding transformer, and according to each three winding transformation
The unit time rated no-load of device is lost and the duration of the second calculation interval, obtains each three winding transformation under the second calculation interval
Total specified no-load loss of device；
Step 2243, the high pressure rated capacity for determining each three-winding transformer, middle pressure rated capacity, low-voltage rated capacity,
High pressure voltage rating, middle pressure voltage rating and low-voltage rated voltage, and determine the unit time senior middle school of each three-winding transformer
Press nominal load loss, the loss of unit time mesolow nominal load and the loss of unit time high-low pressure nominal load；
Step 2244, according to the high pressure rated capacity of each three-winding transformer, high pressure voltage rating, middle pressure rated capacity and
The loss of unit time high pressure nominal load, obtains the equivalent electricity of high pressure winding after each three-winding transformer reduction to high-pressure side
Resistance, and according to the high pressure rated capacity of each three-winding transformer, high pressure voltage rating, low-voltage rated capacity and unit time height
Nominal load loss is pressed, obtains the equivalent resistance of high-low pressure winding after each three-winding transformer reduction to high-pressure side, and further
According to the high pressure rated capacity of each three-winding transformer, high pressure voltage rating, middle pressure rated capacity, low-voltage rated capacity and
The loss of unit time mesolow nominal load, obtains the equivalent electricity of mesolow winding after each three-winding transformer reduction to high-pressure side
Resistance；
Step 2245, according to high pressure winding after each three-winding transformer reduction to high-pressure side, high-low pressure winding and in it is low
The corresponding equivalent resistance of winding is pressed, high-pressure side equivalent resistance, the medium voltage side equivalent resistance of each three-winding transformer are calculated
With low-pressure side equivalent resistance；
Step 2246, according to high-pressure side equivalent resistance, medium voltage side equivalent resistance and low-pressure side of each three-winding transformer etc.
Imitate resistance and each three-winding transformer medium voltage side and the corresponding rms current of low-pressure side and the second calculation interval when
It is long, obtain the electric energy loss of each three-winding transformer；
Step 2247 determines the rated current of each reactor being installed on each three-winding transformer medium voltage side and its right
The high pressure voltage rating and middle pressure voltage rating of three-winding transformer are answered, and according to the rated current and its correspondence of each reactor
The high pressure voltage rating of three-winding transformer and middle pressure voltage rating and low-voltage rated voltage obtain each reactor of medium voltage side and return
On high-tension side electric current is calculated, and further determines that the specified electricity for each reactor being installed in each three-winding transformer low-pressure side
The high pressure voltage rating and low-voltage rated voltage of stream and its corresponding three-winding transformer, according to the rated current of each reactor and
Its high pressure voltage rating and low-voltage rated voltage for corresponding to three-winding transformer, obtain each reactor reduction of low-pressure side to high pressure
The electric current of side；
Step 2248, the unit time nominal loss for determining each reactor in medium voltage side and low-pressure side, and according to same
The unit time of the corresponding rms current of medium voltage side and low-pressure side, medium voltage side reactor that are obtained on three-winding transformer
The unit time nominal loss and its correspondence of nominal loss and its corresponding reduction on high-tension side electric current and low pressure reactor
Reduction obtains the electric energy loss of reactor on each three-winding transformer on high-tension side electric current；
Step 2249 adds up total specified no-load loss of each three-winding transformer, and by each three-winding transformer
Electric energy loss add up, the electric energy loss of reactor on each three-winding transformer is added up, and further will
Three is the sum of cumulative be added after exported as the 4th calculated result.
In one embodiment, by taking a three-winding transformer as an example, the parameter of the three-winding transformer is determined:
High pressure, middle pressure and low pressure winding rated capacity are respectively S1, S2, S3；High pressure, middle pressure and low-pressure side voltage rating point
It Wei not Un, U1n, U2n；P is lost in rated no-load0；High pressure, high-low pressure, the loss of mesolow winding nominal load are respectively Pk12,
Pk13, Pk23；High-pressure side rated current In；
By formula (9), the rated no-load loss Δ E of the three-winding transformer is obtained0；
Due to low-pressure side coil volume S3Often than middle pressure winding S2Few half, therefore, it is necessary to reduction is lost in respective load
To high-pressure side winding rated capacity S1Under:
High pressure, high-low pressure, mesolow winding substitutional resistance after reduction to high-pressure side are respectively rT12、rT13、rT14, i.e.,
Since the substitutional resistance of above-mentioned high pressure, high-low pressure, mesolow winding meets following conditions (14):
In formula (14), rT1For the three-winding transformer high-pressure side substitutional resistance, rT2For the three-winding transformer medium voltage side etc.
It is worth resistance, rT3For the three-winding transformer low-pressure side substitutional resistance；
To derive formula (15), obtain three-winding transformer high-pressure side, medium voltage side and low pressure according to formula (14)
Side substitutional resistance:
According to the three-winding transformer medium voltage side and the corresponding active energy of low-pressure side and capacity of idle power and this three
Winding transformer medium voltage side and the corresponding voltage rating of low-pressure side obtain pressing in the three-winding transformer by formula (3)
Side and low-pressure side respectively correspond the average value of load current, determine the three-winding transformer medium voltage side and low pressure by formula (4)
The corresponding rms current I in side2jfAnd I3jf；
Further according to formula (16), the electric energy loss Δ E of the three-winding transformer is obtainedT:
ΔET=3 [(I2jf+I3jf)2rT1+I2jf 2rT2+I3jf 2rT3]T (17)
In view of the three-winding transformer medium voltage side and low-pressure side may be equipped with current-limiting reactor, their rated current point
It Wei not I2knAnd I3kn, nominal loss is respectively pn2And pn3, the rated current reduction of current-limiting reactor is respectively corresponded to high-pressure side
Are as follows:Wherein, I '2knFor the rated current after medium voltage side current-limiting reactor reduction,
I′3knFor the rated current after low-pressure side current-limiting reactor reduction；
According to formula (18), obtain in the three-winding transformer, the reactor electric energy loss Δ E of low-pressure sideL:
Therefore, the electric energy loss of the three-winding transformer are as follows:
It repeats the above steps, acquires the electric energy loss of all three-winding transformers, and all electric energy losses are added and are made
For the output of the 4th calculated result.
In embodiments of the present invention, by step (a) into step (d), the first calculated result for respectively obtaining, second are calculated
As a result, third calculated result is added with the 4th calculated result, could be as final line loss.
The implementation of the embodiments of the present invention has the following beneficial effects:
In embodiments of the present invention, due to marking off multiple line loss gross datas according to voltage class, in different line losses
In gross data, using different parameters carry out that the higher line loss of accuracy is calculated, it can be achieved that datamation statistics and
It calculates, and can be improved the accuracy of line loss calculation result.
Those of ordinary skill in the art will appreciate that implement the method for the above embodiments be can be with
Relevant hardware is instructed to complete by program, the program can be stored in a computer readable storage medium,
The storage medium, such as ROM/RAM, disk, CD.
The above disclosure is only the preferred embodiments of the present invention, cannot limit the right model of the present invention with this certainly
It encloses, therefore equivalent changes made in accordance with the claims of the present invention, is still within the scope of the present invention.
Claims (8)
1. a kind of method for improving power equipment line loss calculation result, which is characterized in that the described method comprises the following steps:
Step S1, multiple line loss gross datas are marked off according to voltage class；Wherein, the multiple line loss gross data includes
The corresponding line loss gross data of 0.4kV voltage class, the corresponding line loss gross data of 10kV voltage class and at least 110kV electricity
Press the corresponding line loss gross data of grade；
Step S2, it determines currently selected line loss gross data, and according to currently selected line loss gross data, determines corresponding
Calculating mode is obtained by the currently selected calculated line loss of line loss gross data；Wherein, 0.4kV power grid is based on actual measurement line loss
It is calculated, 10kV power grid is calculated based on equivalent resistance and the power grid of at least 110kV is based respectively on overhead transmission line, cable
Road, two-winding transformer and three-winding transformer carry out loss calculation；
Wherein, the step S2 is specifically included:
The currently selected line loss gross data be at least 110kV voltage class corresponding line loss gross data when, same
The power grid that voltage is at least 110kV overhead transmission line, cable run, double winding is based respectively under preset second calculation interval to become
Depressor and three-winding transformer carry out loss calculation, obtain corresponding first calculated result, the second calculated result, third and calculate knot
Fruit and the 4th calculated result, and by first calculated result, the second calculated result, third calculated result and the 4th calculated result
It carries out cumulative later as line loss output；
Wherein, it is described under same preset second calculation interval by voltage be at least 110kV power grid be based on overhead transmission line into
Row loss calculation, the specific steps for obtaining corresponding first calculated result include:
Obtain the specified of the active energy of each overhead transmission line and capacity of idle power and each overhead transmission line under second calculation interval
Voltage, and according to voltage rating, active energy and the capacity of idle power of each overhead transmission line got, obtain each overhead transmission line
The average value of load current, and according to the average value of obtained each overhead transmission line load current, determine each overhead transmission line
Rms current；
It determines the resistance under each overhead transmission line normal temperature, and obtains the current temperature of each overhead transmission line under second calculation interval
Degree and number of lead wires, the length of each conducting wire and its corresponding conducting wire allow current-carrying value and split bar number, according to described each aerial
The rms current and Current Temperatures and number of lead wires of route, the length of each conducting wire and its corresponding conducting wire allow current-carrying value
With split bar number, the resistance under each overhead transmission line normal temperature is changed to the component resistance of each overhead transmission line respectively；
According to the duration of the rms current of each overhead transmission line, component resistance and the second calculation interval, obtain each aerial
The electric energy loss of route；
The rated current for being series at the reactor at each overhead transmission line both ends and the loss of unit time rated no-load are obtained, and according to institute
The rated current and the loss of unit time nominal load for stating each reactor got, obtain total electric energy loss of reactor；
The electric energy loss of each overhead transmission line is added up, and is further carried out with total electric energy loss of the reactor tired
In addition it is exported afterwards as the first calculated result.
2. the method as described in claim 1, which is characterized in that the step S2 is specifically included:
When the currently selected line loss gross data is 0.4kV voltage class corresponding line loss gross data, by 0.4kV power grid
It is calculated based on actual measurement line loss；
The 0.4kV power grid is divided into multiple low voltage electric networks by load character, and each low voltage electric network includes identical multiple
Load type；
In the multiple low voltage electric network multiple areas are chosen to each load type respectively, and obtained in each low voltage electric network
The capacity of distribution transform in each area, and obtain the area each low voltage electric network Zhong Getai actually measured power supply volume and electricity sales amount；
According to the area each low voltage electric network Zhong Getai got actually measured power supply volume and electricity sales amount, calculate each low
The electric energy loss in the area voltage electric grid Zhong Getai, and the area each low voltage electric network Zhong Getai further got according to match transfiguration
Amount and its calculated electric energy loss calculate the corresponding electric energy loss rate of each load type in each low voltage electric network；
According to corresponding area's total capacity of load type each in preset each low voltage electric network and calculated each low
The corresponding electric energy loss rate of each load type in voltage electric grid obtains the corresponding electric energy damage of each load type in each low voltage electric network
Consumption, and the corresponding electric energy loss of load type each in obtained each low voltage electric network is added up, obtain each low pressure
The electric energy loss of power grid；
The electric energy loss of obtained each low voltage electric network is carried out after adding up, it is corresponding complete to obtain the 0.4kV power grid
Net electric energy loss is simultaneously exported as line loss.
3. method according to claim 2, which is characterized in that the low voltage electric network includes city net, suburb net and rural area net.
4. method according to claim 2, which is characterized in that the load type includes heavy load, middle load and light load.
5. the method as described in claim 1, which is characterized in that the step S2 is specific further include:
When the currently selected line loss gross data is 10kV voltage class corresponding line loss gross data, by 10kV power grid base
It is calculated in equivalent resistance；
The 10kV power grid is divided into multiple wirings, and includes multiple distribution transformings in each wiring；
Determine in the voltage rating and the 10kV power grid of the 10kV power grid distribution transforming contained by wiring sum and each wiring
Number, and further determine that the unit time rated no-load loss of each distribution transforming, and according to contained by each wiring of the determination
With parameter, distribution transforming sum in the 10kV power grid is counted；
The rated capacity and its loss of corresponding nominal load of each distribution transforming are obtained, and according to each distribution transforming got
The voltage rating and distribution transforming sum of rated capacity and its loss of corresponding nominal load and 10kV power grid, calculate described
The distribution transforming substitutional resistance of 10kV power grid；
The resistance of each wiring is obtained, and according to the resistance and its contained distribution number of each wiring got, and
Wiring sum, calculates the wiring substitutional resistance of the 10kV power grid in 10kV power grid；
It obtains the active energy and capacity of idle power of 10kV power grid under preset first calculation interval, and is got according to described
Voltage rating, active energy and the capacity of idle power of 10kV power grid, obtain the average value of 10kV network load electric current, and according to described
The average value of obtained 10kV network load electric current determines the rms current of the 10kV power grid；
It is total, each according to the rms current of the 10kV power grid, distribution transforming substitutional resistance and wiring substitutional resistance and distribution transforming
The duration of unit time the rated no-load loss and the first calculation interval of distribution transforming, obtains the whole network electric energy loss of the 10kV power grid
And it is exported as line loss.
6. the method as described in claim 1, which is characterized in that it is described under same preset second calculation interval by voltage extremely
Cable run is based on for the power grid of 110kV less and carries out loss calculation, and the specific steps for obtaining corresponding second calculated result include:
Obtain the specified of the active energy of each cable run and capacity of idle power and each cable run under second calculation interval
Voltage, and according to voltage rating, active energy and the capacity of idle power of each cable run got, obtain each cable run
The average value of load current, and according to the average value of obtained each cable run load current, determine each cable run
Rms current；
It determines the resistance under each cable run normal temperature, and obtains working as each cable run under second calculation interval
Preceding temperature and number of lead wires, the length of each conducting wire and its corresponding conducting wire allow current-carrying value and split bar number, according to described each
The rms current and Current Temperatures and number of lead wires of cable run, the length of each conducting wire and its corresponding conducting wire allow to carry
Resistance under each cable run normal temperature is changed to the element electricity of each cable run by flow valuve and split bar number respectively
Resistance；
According to the duration of the rms current of each cable run, component resistance and the second calculation interval, obtain each aerial
The electric energy loss of route；
According to the number of lead wires of each cable run, the length of each conducting wire, calculated by mean geometrical distance between adjacent wires
The electromagnetic consumable of each cable run out；
The electric energy loss of the cable run is added up, and the electromagnetic consumable of the cable run is added up, is gone forward side by side
One step exports two the sum of cumulative are added as the second calculated result.
7. the method as described in claim 1, which is characterized in that it is described under same preset second calculation interval by voltage extremely
Two-winding transformer is based on for the power grid of 110kV less and carries out loss calculation, obtains the specific steps of corresponding third calculated result
Further include:
Obtain the on high-tension side active energy of each two-winding transformer under second calculation interval and capacity of idle power and each double wrap
Group high voltage side of transformer voltage rating, and according to the on high-tension side voltage rating of each two-winding transformer got, have
Function electricity and capacity of idle power, obtain the average value of each two-winding transformer high-pressure side load current, and according to it is described obtain it is each
The average value of two-winding transformer high-pressure side load current determines the on high-tension side rms current of each two-winding transformer；
Determine the unit time rated no-load loss of each two-winding transformer, and when according to the unit of each two-winding transformer
Between the duration of rated no-load loss and the second calculation interval, obtain the total of each two-winding transformer under second calculation interval
Rated no-load loss；
Determine the rated capacity and its loss of corresponding unit time nominal load of each two-winding transformer, and according to described each pair
Rated capacity, high-pressure side voltage rating and the loss of unit time nominal load of winding transformer, obtain each two-winding transformer
The equivalent resistance of winding；
According to the equivalent resistance of each two-winding transformer winding, on high-tension side rms current and the second calculation interval
Duration obtains the electric energy loss of each two-winding transformer；
Determine the rated current and its corresponding double winding transformation of each reactor being installed in each two-winding transformer low-pressure side
The voltage rating of device low-pressure side, and according to the rated current of each reactor and its correspond to two-winding transformer low-pressure side
Voltage rating and on high-tension side voltage obtain each reactor reduction on high-tension side electric current；
Determine the unit time nominal loss of each reactor, and according to each reactor reduction on high-tension side electric current, unit
Time nominal loss and its corresponding on high-tension side rms current of two-winding transformer, obtain the electric energy loss of each reactor；
Total specified no-load loss of each two-winding transformer is added up, and by the electric energy loss of each two-winding transformer
Add up, the electric energy loss of each reactor added up, and further by three is the sum of cumulative be added after as the
The output of three calculated results.
8. the method as described in claim 1, which is characterized in that it is described under same preset second calculation interval by voltage extremely
Three-winding transformer is based on for the power grid of 110kV less and carries out loss calculation, obtains the specific steps of corresponding 4th calculated result
Include:
Obtain each three-winding transformer medium voltage side and the corresponding active energy of low-pressure side and nothing under second calculation interval
Function electricity and each three-winding transformer medium voltage side and the corresponding voltage rating of low-pressure side, and got according to described
Each three-winding transformer medium voltage side and the corresponding voltage rating of low-pressure side, active energy and capacity of idle power, obtain each three around
Group transformer medium voltage side and low-pressure side respectively correspond the average value of load current, and according to obtained each three-winding transformer
Medium voltage side and low-pressure side respectively correspond the average value of load current, determine that each three-winding transformer medium voltage side and low-pressure side are right respectively
The rms current answered；
Determine the unit time rated no-load loss of each three-winding transformer, and when according to the unit of each three-winding transformer
Between the duration of rated no-load loss and the second calculation interval, obtain the total of each three-winding transformer under second calculation interval
Rated no-load loss；
Determine the high pressure rated capacity of each three-winding transformer, middle pressure rated capacity, low-voltage rated capacity, high pressure voltage rating,
Middle pressure voltage rating and low-voltage rated voltage, and determine the unit time high pressure nominal load damage of each three-winding transformer
Consumption, the loss of unit time mesolow nominal load and the loss of unit time high-low pressure nominal load；
According to the high pressure rated capacity of each three-winding transformer, high pressure voltage rating, middle pressure rated capacity and unit time
The loss of high pressure nominal load, obtains the equivalent resistance of high pressure winding after each three-winding transformer reduction to high-pressure side, and root
According to the high pressure rated capacity of each three-winding transformer, high pressure voltage rating, low-voltage rated capacity and unit time high-low pressure
Nominal load loss, obtains the equivalent resistance of high-low pressure winding after each three-winding transformer reduction to high-pressure side, and further root
According to the high pressure rated capacity of each three-winding transformer, high pressure voltage rating, middle pressure rated capacity, low-voltage rated capacity and list
Position time mesolow nominal load loss, obtains the equivalent electricity of mesolow winding after each three-winding transformer reduction to high-pressure side
Resistance；
According to high pressure winding, high-low pressure winding and mesolow winding difference after each three-winding transformer reduction to high-pressure side
Corresponding equivalent resistance calculates high-pressure side equivalent resistance, medium voltage side equivalent resistance and low-pressure side of each three-winding transformer etc.
Imitate resistance；
According to the high-pressure side equivalent resistance, medium voltage side equivalent resistance and low-pressure side equivalent resistance of each three-winding transformer, with
And the duration of each three-winding transformer medium voltage side and low-pressure side corresponding rms current and the second calculation interval, it obtains each
The electric energy loss of three-winding transformer；
Determine the rated current and its corresponding three winding transformation of each reactor being installed on each three-winding transformer medium voltage side
The high pressure voltage rating of device and middle pressure voltage rating, and become according to the rated current of each reactor and its corresponding three winding
The high pressure voltage rating of depressor and middle pressure voltage rating and low-voltage rated voltage obtain each reactor reduction of medium voltage side to high pressure
The electric current of side, and further determine that the rated current of each reactor being installed in each three-winding transformer low-pressure side and its right
The high pressure voltage rating and low-voltage rated voltage for answering three-winding transformer, according to the rated current of each reactor and its right
The high pressure voltage rating and low-voltage rated voltage for answering three-winding transformer obtain each reactor reduction of low-pressure side on high-tension side
Electric current；
Determine the unit time nominal loss of each reactor in medium voltage side and low-pressure side, and according on same three-winding transformer
The unit time nominal loss of the obtained corresponding rms current of medium voltage side and low-pressure side, medium voltage side reactor and its right
Answer reduction to the unit time nominal loss of on high-tension side electric current and low pressure reactor and its corresponding reduction on high-tension side
Electric current obtains the electric energy loss of reactor on each three-winding transformer；
Total specified no-load loss of each three-winding transformer is added up, and by the electric energy loss of each three-winding transformer
It adds up, the electric energy loss of reactor on each three-winding transformer is added up, and three is further added up it
Be added after as the 4th calculated result export.
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