A kind of novel air jar structure of protection water supplying pump system
Technical field
The present invention relates to the technical field of water conveying, more particularly to fill for protecting water hammer in long distance water transmission pipeline system
A kind of novel air jar structure of the protection water supplying pump system water hammer in putting.
Background technology
Due to reasons such as power failure or maloperations, often there is pump-stopping water hammer, cause in reality in the operation of pump water-carriage system
Water pump water outlet pipeline, valve and water pump assembly wreck, and supply water and interrupt, cause serious loss.Generation pump-stopping water hammer thing
Therefore when, if can prevent pump discharge pressure from reducing in time, then in pipeline, pressure will not also be too high.
At present, when preventing water hammer from occurring, the method for reduced pressure has two kinds:One kind be to water filling in pipeline, another kind be to
Gas injection in pipeline.The protecting water hammer device of the water filling into pipeline mainly includes single, double to surge tower, air tank, the note into pipeline
The protecting water hammer measure of gas mainly has air tank.But air cock only can just enter when the pressure in pipeline is less than atmospheric pressure
Gas, it is impossible to timely and effectively prevent manifold pressure from reducing.
Air tank is a kind of special protecting water hammer device for preventing positive/negative-pressure of hydraulic pipeline system, and it is installed in
Near exit of pump, when there is water hammer accident, pump outlet pipeline causes pressure drop due to flow reduction to air tank, empty
In gas tank, more than fluid pressure in pipeline, the water in air tank is pressed in pipeline initial gas pressure, to supplement pipeline
The flow reduction of interior liquid, so that alleviate the pressure drop of pump outlet;When barotropic wave reaches pump outlet, in pipeline
Pressure more than the gas pressure in air tank, the liquid in pipeline is pressed in tank body due to the effect of pressure reduction, so as to slow
The pressure rise of solution exit of pump.In air tank, the presence of compressed gas can discharge pressure energy or the pressure in extraction duct
Ripple.
Therefore air tank needs the factor of consideration more in the design phase, initial gas in the volume, tank including air tank
Connection tube impedance of original liquid volume, tank body and aqueduct etc. in pressure, tank, current engineers generally rely on engineering and set
Meter experience and chart carry out air tank parameter select, typically will through comparatively laborious tentative calculation process, belong to quite time-consuming and
And the method for clumsiness.
At present, conventional air tank has two types, non-divergence type air tank and Split type air tank, for non-divergence type
For air tank, there is, at air and the contact surface of water, the phenomenon that air is dissolved in water, but either Split type air tank is still
Non- divergence type air tank, all has a problem that to be exactly gas loss, it is therefore desirable to which air compressor carries out QI invigorating to which.Remove this
Outside, have high demands for long distance water transfer project or to protecting water hammer, the engineering that regulating power is big, the appearance of the air tank of needs
Product is excessive, and this allows for traditional air tank and is difficult large-scale promotion in practical engineering application.
Content of the invention
For above-mentioned problem of the prior art, there is provided simple structure, air and water respectively in two jars one is made
Plant the novel air jar structure of protection water supplying pump system water hammer.
The technical scheme that the present invention is provided:
A kind of novel air jar structure of protection water supplying pump system water hammer, including air tank, air relief valve, high-pressure gas
Tank, check-valves, the air tank are connected by air delivering pipeline with high pressure tank, sequentially arrange non-return in the air delivering pipeline
Valve, normally open solenoid valve, air relief valve, service valve, the air tank are also linked in sequence normally closed solenoid valve and air cock.
The novel air jar structure of the protection water supplying pump system water hammer is after protection pump discharge valve, or installs
In the middle of aqueduct.
Water and gas are divided among two by the method for the protection water supplying pump system water hammer and novel air jar structure completely
In jar.
The boundary condition of the novel air jar structure is:
To equation 1 using Newton-Raphson method, following iterative equation is obtained:
Wherein:
When | Δ Qs|≤10-4When, solve QsTerminate, otherwise make Qs(j)=Qs(j)+ΔQs, repeat said process until full
Sufficient condition;
Wherein parameter:
Hp (j) be pump head, unit:m;
Qp(j) pump capacity, unit:m3/s;
Q (N, j) be flow out node N pipeline flow, unit:m3/s;
(N, is j) node N heads to H, unit:m;
QsJ () is the flow of the orifice by air tank, unit:m3/s;
A be valve basal area, unit:㎡;
Resistance coefficients of the ε for valve;
W be orifice basal area, unit:㎡;
Hs is water level in air tank, unit:m;
Hh (j) is head in air tank, unit:m;
Vs (j) be air tank gas volume, unit:m3;
Ps (j) be air tank gas pressure intensity, unit:pa;
As be air tank basal area, unit:㎡;
H is atmospheric pressure, unit:m3;
K is air tank orifice resistance coefficient;
Hair be air relief valve initial pressure head, unit:m.
The present invention has following features:Protection water hammer effect is good;Installation site is not limited by orographic condition, is typically mounted at
Near exit of pump;Simple structure, safe and reliable to operation;Maintenance easy to use, easy.
Description of the drawings
In order to be illustrated more clearly that the embodiment of the present invention or technical scheme of the prior art, below will be to embodiment or existing
Accompanying drawing to be used needed for having technology description is briefly described, it should be apparent that, drawings in the following description are only this
Some embodiments of invention, for those of ordinary skill in the art, without having to pay creative labor, may be used also
To obtain other accompanying drawings according to these accompanying drawings.
Fig. 1 is the structural representation of implementation model of the present invention.
Fig. 2 is embodiment engineering schematic diagram.
Fig. 3 minimax pressure head envelopes.
Fig. 4 water pump dimensionless Feature change curves.
Fig. 5 water pump discharge pressure change curves.
SEA LEVEL VARIATION curve in Fig. 6 novel air jar structures of the present invention.
Air quality change curve in Fig. 7 novel air jar structures of the present invention.
Wherein:1- water pumps;2- two benches buffer butterfly valves;3- air tanks;4- high pressure tanks;5- check-valves;The normally opened electricity of 6-
Magnet valve;7- air relief valve;8- service valves;9- normally closed solenoid valves;10- air cocks.
Specific embodiment
Below in conjunction with the accompanying drawing of the present invention, technical scheme is clearly and completely described, it is clear that institute
The embodiment of description is only a part of embodiment of the invention, rather than whole embodiment.Embodiment in based on the present invention,
The every other embodiment obtained under the premise of creative work is not made by those of ordinary skill in the art, belongs to this
The scope of bright protection.
A kind of novel air jar structure of protection water supplying pump system water hammer, including air tank, air relief valve, high-pressure gas
Tank, check-valves, the air tank are connected by air delivering pipeline with high pressure tank, sequentially arrange non-return in the air delivering pipeline
Valve, normally open solenoid valve, air relief valve, service valve, the air tank are also linked in sequence normally closed solenoid valve and air cock.
When the effect of check-valves is to prevent pressure increase in pipeline, the water in air tank enters high pressure tank, and water pump is just
When often working, normally closed solenoid valve is closed, and only when water pump occurs accident power-off, normally closed solenoid valve is just opened.This
When, the air expansion in high pressure tank allows the water in air tank to enter pipeline, so as to play a part of protecting water hammer.
The model boundary condition algorithm of the pressurized tank calculates process:
Basic parameter:Hp (j) be pump head, m;Qp(j) pump capacity, m3/s;Q (N, j) be flow out node N pipeline
Flow, m3/s;(N, is j) node N heads to H, m;QsJ () is the flow of the orifice by air tank, m3/s;A is valve
Basal area,;Resistance coefficients of the ε for valve;W is orifice basal area,;Hs is water level in air tank, m;Hh (j) is sky
Head in gas tank, m;Vs (j) be air tank gas volume, m3;Ps (j) be air tank gas pressure intensity, pa;As is air tank section
Product,;H is atmospheric pressure, m3;K is air tank orifice resistance coefficient;Hair be air relief valve initial pressure head, m.
The operation principle of the present invention:Pressure phase at pressure when water pump normally runs in air tank and aqueduct P points
Deng now full of water in air tank.When unexpected termination of pumping, it will the rotating speed decline and its flow for causing water pump can also reduce,
At this moment air pressure inside the tank is higher than the pressure of aqueduct point P, and when the pressure in air tank sets pressure less than air relief valve
During Hair values, air relief valve will be opened from high pressure tank to QI invigorating in air tank, make the water in air tank flow out supply pipeline,
So as to slow down the speed of water flow in pipeline flow velocity decline, to avoid manifold pressure from dropping to below atmospheric pressure or vapour pressure
Power.Similarly, when in pipeline current flow backwards, two benches close butterfly valve will close rapidly, make the pressure rise in pipeline.When
The pressure value of point P more than in air tank during pressure value, so as to slowing down flow rate of water flow in pipeline in the water air inlet tank in pipeline
Rate of change, therefore inhibit the rising of manifold pressure.
The mathematical model of pressurized tank is:
Basic parameter:Hp (j) be pump head, m;Qp(j) be pump capacity, m3/s;Q (N, j) be flow out node N pipe
Road flow, m3/s;(N, is j) node N heads to H, m;QsJ () is the flow of the orifice by air tank, m3/s;A is valve
Basal area,;Resistance coefficients of the ε for valve;W is orifice basal area,;Hs is water level in air tank, m;Hh (j) is sky
Head in gas tank, m;Vs (j) be air tank gas volume, m3;Ps (j) be air tank gas pressure intensity, pa;As is air tank section
Product,;H be air pressure head, m;K is air tank orifice resistance coefficient;Hair be air relief valve initial pressure head, m.
The first situation:As air pressure inside the tank hh (j)≤Hair
(1) air pressure inside the tank and air relief valve set relation between pressure as:
Hh (j)=Hair
(2) flux balance equations:
Qp(j)+Qs(j)=Q (N, j)
(3) air tank water level Hs, gas volume V and flow QsRelation:
V (j)=V (j-1)+0.5dt [Qs(j)+Qs(j-1)]
(4) assume not considering the elasticity of water body and tank skin in tank, then and the piezometric head H of node P (N, j), water in tank
Head hh (j) and air tank water level HsJ the relation of () is:
(5) characteristic strips equation:
H (N, j)=CM+BQ(N,j)
Second situation:As air pressure inside the tank hh (j) > Hair
(1) air pressure inside the tank:
Ps (j) * Vs (j)=Ps (j-1) * Vs (j-1)
(2) flux balance equations:
Qp(j)+Qs(j)=Q (N, j)
(3) air tank water level Hs, gas volume V and flow QsRelation:
V (j)=V (j-1)+0.5dt [Qs(j)+Qs(j-1)]
(4) assume not considering the elasticity of water body and tank skin in tank, then and the piezometric head H of node P (N, j), water in tank
Head hh (j) and air tank water level HsJ the relation of () is:
(5) characteristic strips equation:
H (N, j)=CM+BQ(N,j)
The third situation:When pump discharge valve Close All
(1) air pressure inside the tank:
Ps (j) * Vs (j)=Ps (j-1) * Vs (j-1)
(2) flux balance equations:
Qs(j)=Q (N, j)
(3) air tank water level Hs, gas volume V and flow QsRelation:
V (j)=V (j-1)+0.5dt [Qs(j)+Qs(j-1)]
(4) assume not considering the elasticity of water body and tank skin in tank, then and the piezometric head H of node P (N, j), water in tank
Head hh (j) and air tank water level HsJ the relation of () is:
(5) characteristic strips equation:
H (N, j)=CM+BQ(N,j)
Generation method is lied prostrate using newton thunder solution is iterated to the boundary condition under above-mentioned three kinds different operating modes respectively.
With the selection that the embodiment of actual field illustrates art solutions parameters of the present invention:
Yulin City industrial park water supply project is by water source project, booster station engineering, head-tank engineering, the water delivery Heavenly Stems and Earthly Branches
Pipeline engineering and five part of management road engineering composition.Water supply project by water source project from getting water from water head site, through level Four pumping plant
After classification pressurization, by delivery main (two-tube) water delivery of 35km length to industrial park water treatment plant, the task of the engineering is to work
Industry garden supplies water, and meets garden production, domestic water, and takes into account water supply each village resident living water needs along the line, supplies water and protect
Card rate is not less than 95%.
The design water delivery flow 1.11m of the water supply project3/ s, total water delivery distance about 35km.Every grade of booster station is respectively provided with 4
Platform centrifugal pump parallel running, and 3 work 1 are standby.According to Fig. 2, the single-pump flow of one-level booster station is 0.37m3/
S, lift are 149.5m, and the length of pipeline of one-level booster station to two-stage pressurizing pumping plant is 1340.73m.Two-stage pressurizing pumping plant
Single-pump flow is 0.37m3/ s, lift is 128.9m, and two-stage pressurizing pumping plant to the length of pipeline of three times' lifting pumping plant is
1883.10m.The single-pump flow of three times' lifting pumping plant is 0.37m3/ s, lift are 137.4m, and three times' lifting pumping plant is to level Four pressurization
The length of pipeline of pumping plant is 10507.89m, and the single-pump flow of level Four booster station is 0.37m3/ s, lift is 139.7m, level Four
The length of pipeline of booster station to head-tank is 15478.18m, and one-level booster station adopted to the pipeline between head-tank
Seamless steel pipe with DN800.The characterisitic parameter of one-level pumping plant is as shown in table 1.
1 one-level pumping plant characterisitic parameter table of table
Sequence |
Title |
Unit |
Quantity |
Remarks |
No. 1 |
Design total (pumping) head |
m |
149.50 |
|
2 |
Design net lift |
m |
143.44 |
|
3 |
Water pump OMEGA300-700A |
Platform |
4 |
qSingle=0.37m3/ s, |
4 |
Necessary electromotor |
Platform |
4 |
DN=Single6=3791m0mkW |
5 |
Total 50 dress 1- machines, 4 power of Y pumps PT stations Z4 |
kW |
2840 |
|
6 |
Pump efficiency |
% |
82.7 |
|
7 |
The rated speed of water pump |
r/min |
1492 |
|
8 |
The rotary inertia of water pump |
kg·m2 |
8.2 |
|
9 |
The rotary inertia of motor |
kg·m2 |
25 |
|
10 |
Water pump assembly always rotates used |
kg·m2 |
33.2 |
|
The safe operation for demonstrate,proving pumping station system is measured for guarantor, and reaches expected protecting water hammer purpose, selecting pump-stopping water hammer
It is noted that the factor of the following aspects during safeguard procedures:Selected protecting water hammer measure, should be with residing pumping plant and pipeline
The scale of system, requirement of the effect to safety and technically must safe and reliable, economically on relatively reasonable, management and maintenance
Eaily safeguard procedures;Technically mainly embodied from the following aspects:A. the extreme water hammer pressure on pipeline
Should be less than 1.3~1.5 times of exit of pump rated pressure;B. the reversing rotating speed of water pump assembly is not to be exceeded specified turn of 1.2 times
Speed, and reversing must not exceed 2 minutes;C. should there is not the water column separation phenomenon of great harm in full pipeline;The selection of safeguard procedures,
Must analyze with pump-stopping water hammer and calculate and cooperate while carrying out.
According to above-mentioned points for attention, comprehensive Practical Project, a kind of protection water supplying pump system water hammer of the present invention is selected
Novel air jar structure, according to Fig. 1, after two benches buffer butterfly valve, water pump is normal for novel air jar structure
During operation, air tank is equal with the pressure in pipeline full of the pressure in water, and air tank.When power failure suddenly or termination of pumping,
The rotating speed of water pump declines and flow reduces, and at this moment at the same time air pressure inside the tank works as air higher than the pressure of aqueduct
When pressure in tank sets pressure less than air relief valve, normally closed solenoid valve is opened, and it is empty that high pressure tank fills into compression into air tank
Gas, so that the water inflow pipe in air tank, to slow down the speed of water flow in pipeline flow velocity decline, it is to avoid under manifold pressure
It is down to below atmospheric pressure or steam pressure.Similarly, when in pipeline current flow backwards, two benches buffer butterfly valve will be closed rapidly
Close, make the pressure rise in pipeline.When manifold pressure value is more than pressure value in air tank, the water air inlet tank in pipeline
The interior rate of change so as to slow down flow rate of water flow in pipeline, therefore inhibits the rising of manifold pressure.
In embodiment, in the accumulation of energy pot type pilot slow-closure butterfly valve that exit of pump installs DN400, and the master after exit of pump
Pressurized tank of the present invention is installed on pipeline, hydrostatic pressing of the air relief valve maximum set pressure no more than exit of pump, at this
No more than 1.454MPa in engineering.From Water And Drainage System Design handbook:(1) diameter of air tank outlet conduit is generally main
The 1/4~1/2 of caliber;(2) little from the loss of air tank water head-drop, and the loss of flood peak of intaking is big, its ratio is generally 1:
2.5;(3) in order to prevent when minimum pressure occurs in pipeline, the air in air tank enters pipeline, and therefore the volume of air tank can
Take 1.1~1.3 times of required minimum volume.
Variable during pressurized tank optimization of the present invention is calculated has:The quick closing's time t of pilot slow-closure butterfly valve1, quick closing valve angle
Degree θ1, slow close time t2, air tank outlet resistance coefficient ξ1, air tank outlet pipe diameter D1, air tank diameter Ds,
Eight variables such as the height Hs of air tank and its air relief valve pressure Hair, will be analyzed to above-mentioned eight variables below respectively,
The final pressurized tank volume of the present invention for determining optimum.
1) work as θ1=65 °, t2=60s, ξ1=1.6, D1=0.35m, Ds=1.5m, Hs=5m, Hair=1.378MPa
When, the quick closing's time t for calculating pilot slow-closure butterfly valve using MATLAB1Hydraulic hammer calculation result when taking different value is as shown in table 2 below.
Table 2:t1Take hydraulic hammer calculation result during different value
As shown in Table 2:When its dependent variable is certain, with the prolongation of quick closing's time, the liter of the maximum pressure of exit of pump
High obvious, the minimum pressure of pipeline does not change, and the lowest water level in air tank is on a declining curve.Meeting pump
On the premise of design specification of standing, the quick closing's time for selecting pilot slow-closure butterfly valve is t1=1.5s.
2) work as t1=1.5s, t2=60s, ξ1=1.6, D1=0.35m, Ds=1.5m, Hs=5m, Hair=1.378MPa
When, the quick closing valve angle, θ for calculating pilot slow-closure butterfly valve using MATLAB1Hydraulic hammer calculation result when taking different value is as shown in table 3 below.
3 θ of table1Take hydraulic hammer calculation result during different value
θ1(°) |
60 |
65 |
70 |
75 |
80 |
n |
1.032 |
1.027 |
1.025 |
1.024 |
1.023 |
Hmin(m) |
2.137 |
2.137 |
2.137 |
2.137 |
2.137 |
Hsmin(m) |
0.965 |
1.173 |
1.301 |
1.370 |
1.401 |
V(m3) |
8.83 |
8.83 |
8.83 |
8.83 |
8.83 |
As can be seen from Table 3:When its dependent variable is certain, with the increase of quick closing valve angle, the maximum pressure of exit of pump
It is gradually reduced, the minimum pressure of pipeline does not change, and the lowest water level in air tank gradually increases.Set pumping plant is met
On the premise of meter specification, the quick closing valve angle for selecting pilot slow-closure butterfly valve is θ1=80 °.
3) work as θ1=80 °, t1=1.5s, ξ1=1.6, D1=0.35m, Ds=1.5m, Hs=5m, Hair=1.378MPa
When, the slow pass time t for calculating pilot slow-closure butterfly valve using MATLAB2Hydraulic hammer calculation result when taking different value is as shown in table 4 below.
4 t of table2Take hydraulic hammer calculation result during different value
As shown in Table 4:When its dependent variable is certain, with the prolongation for closing the time slowly, the maximum pressure and pipe of exit of pump
The minimum pressure in road does not change, and the lowest water level in air tank is on a declining curve.Before Code for design of pumping cstations is met
Put, the slow pass time for selecting pilot slow-closure butterfly valve is t2=2.5s.
4) work as θ1=80 °, t1=1.5s, t2=2.5s, D1=0.35m, Ds=1.5m, Hs=5m, Hair=1.378MPa
When, the resistance coefficient ξ for calculating pressurized tank outlet of the present invention using MATLAB1Hydraulic hammer calculation result when taking different value is such as
Shown in table 5 below.
5 ξ of table1Take hydraulic hammer calculation result during different value
ξ1 |
1.5 |
1.7 |
1.9 |
2.1 |
2.3 |
2.5 |
2.7 |
n |
1.023 |
1.023 |
1.022 |
1.022 |
1.021 |
1.020 |
1.019 |
Hmin(m) |
2.140 |
2.034 |
2.127 |
2.121 |
2.114 |
2.108 |
2.098 |
Hsmin(m) |
1.385 |
1.443 |
1.499 |
1.553 |
1.630 |
1.655 |
1.704 |
V(m3) |
8.83 |
8.83 |
8.83 |
8.83 |
8.83 |
8.83 |
8.83 |
As shown in Table 5:When its dependent variable is certain, with the increasing of the resistance coefficient that pressurized tank of the present invention is exported
Greatly, the minimum pressure of the maximum pressure and pipeline of exit of pump is in reduction trend, but which changes little, the minimum in air tank
Water level is in increase tendency.Consider above-mentioned factor, the resistance coefficient for selecting pressurized tank outlet of the present invention is ξ1=
2.1.
5) work as θ1=80 °, t1=1.5s, t2=2.5s, ξ1=2.1, Ds=1.5m, Hs=5m, Hair=1.378MPa
When, the pipe diameter D for calculating pressurized tank outlet of the present invention using MATLAB1Hydraulic hammer calculation result when taking different value is such as
Shown in table 6 below.
6 D of table1Take hydraulic hammer calculation result during different value
As shown in Table 6:When its dependent variable is certain, with the increasing of the pipe diameter that pressurized tank of the present invention is exported
Greatly, the maximum pressure of exit of pump is in increase tendency, but is not particularly evident;The minimum pressure of pipeline is significantly increased, and air
Lowest water level in tank constantly reduces.From Water And Drainage System Design handbook:The diameter of air tank outlet conduit is generally main pipe
The 1/4~1/2 of footpath, therefore takes the pipe diameter D of pressurized tank outlet of the present invention1=0.25m.
6) work as θ1=80 °, t1=1.5s, t2=2.5s, ξ1=2.1, D1=0.25m, Hs=5m, Hair=1.378MPa
When, the diameter Ds for calculating pressurized tank of the present invention using MATLAB takes hydraulic hammer calculation result such as table 7 below institute during different value
Show.
During 7 Hs=5m of table, Ds takes hydraulic hammer calculation result during different value
In the case where other parameters are constant, during Hs=4m, the straight of pressurized tank of the present invention is calculated using MATLAB
Hydraulic hammer calculation result when footpath Ds takes different value is as shown in table 8 below.
During 8 Hs=4m of table, Ds takes hydraulic hammer calculation result during different value
In the case where other parameters are constant, during Hs=3.5m, pressurized tank of the present invention is calculated using MATLAB
Hydraulic hammer calculation result when diameter Ds takes different value is as shown in table 9 below.
During 9 Hs=3.5m of table, Ds takes hydraulic hammer calculation result during different value
Can be seen that by 7~table of table 9:When other specification constant, with pressurized tank of the present invention height reduce, this
When the diameter of the described pressurized tank of invention takes different value, the minimum pressure of pipeline is all higher than zero.But the institute of the present invention in Hs≤4m
What the lowest water level of the pressurized tank that states had occurs in that negative value, i.e., the air in pressurized tank of the present invention enter main pipeline
Interior.
Therefore, the setting pressure of air relief valve can on the premise of protecting water hammer requirement is met, be reduced.In other parameters not
In the case of change, when Hs=3.0m, Hair=1.329MPa, using the diameter Ds of MATLAB calculating pressurized tank of the present invention
Hydraulic hammer calculation result when taking different value is as shown in table 10 below.
10 Hs=3.0m of table, during Hair=1.329MPa, Ds takes hydraulic hammer calculation result during different value
In the case where other parameters are constant, when Hs=2.8m, Hair=1.329MPa, the present invention is calculated using MATLAB
Hydraulic hammer calculation result when the diameter Ds of described pressurized tank takes different value is as shown in table 11 below.
11 Hs=2.8m of table, during Hair=1.329MPa, Ds takes hydraulic hammer calculation result during different value
In the case where other parameters are constant, when Hs=2.7m, Hair=1.329MPa, air tank is calculated using MATLAB
Hydraulic hammer calculation results of diameter Ds when taking different value as shown in table 12 below.
12 Hs=2.7m of table, during Hair=1.329MPa, Ds takes hydraulic hammer calculation result during different value
In the case where other parameters are constant, when Hs=2.6m, Hair=1.329MPa, air tank is calculated using MATLAB
Hydraulic hammer calculation results of diameter Ds when taking different value as shown in table 13 below.
13 Hs=2.6m of table, during Hair=1.329MPa, Ds takes hydraulic hammer calculation result during different value
Can be seen that from table 10~13:Work as Hair=1.329MPa, when other specification is constant, with of the present invention
The height of pressurized tank reduces, and the minimum pressure of pipeline is gradually reduced.Because there is water column separation in -9.95m in water.For safety
For the sake of, minimum sub-atmospheric pressure is taken herein less than -5m, it can be seen that, when the height of pressurized tank of the present invention is less than 2.6m, negative pressure
Will no longer satisfy requirement.
7) on the basis of above-mentioned conclusion, different value, basic parameter θ are taken to the pressure of air relief valve1=80 °, t1=1.5s,
t2=2.5s, ξ1=2.1, D1=0.25m does not change.
Work as Hs=2.6m, during Ds=1.1m, hydraulic hammer calculation during different value is taken using MATLAB calculating air relief valve pressure PP
As a result as shown in table 14 below.
14 Hs=2.6m of table, during Ds=1.1m, Hair takes hydraulic hammer calculation result during different value
Work as Hs=2.7m, during Ds=1.10m, water hammer meter during different value is taken using MATLAB calculating air relief valve pressure Hair
Calculate result as shown in table 15 below.
15 Hs=2.7m of table, during Ds=1.10m, Hair takes hydraulic hammer calculation result during different value
Work as Hs=2.7m, during Ds=1.05m, water hammer meter during different value is taken using MATLAB calculating air relief valve pressure Hair
Calculate result as shown in table 16 below.
16 Hs=2.7m of table, during Ds=1.05m, Hair takes hydraulic hammer calculation result during different value
Work as Hs=2.8m, during Ds=1.05m, water hammer meter during different value is taken using MATLAB calculating air relief valve pressure Hair
Calculate result as shown in table 17 below.
17 Hs=2.8m of table, during Ds=1.05m, Hair takes hydraulic hammer calculation result during different value
Work as Hs=3.0m, during Ds=1.05m, water hammer meter during different value is taken using MATLAB calculating air relief valve pressure Hair
Calculate result as shown in table 18 below.
18 Hs=3.0m of table, during Ds=1.05m, Hair takes hydraulic hammer calculation result during different value
Can be seen that from table 14~17:When one timing of height and diameter of pressurized tank of the present invention, with air relief valve
The increase of pressure, maximum pressure hardly change, and the minimum pressure of pipeline gradually increases, and pressurized tank of the present invention
Lowest water level constantly reduce.When Prevention of Water Hammer in Pump Station requirement is met and minimum pressure is not less than -5m, the pressure of air relief valve
For Hair=1.329MPa, the volume of pressurized tank of the present invention is 2.42m3.
The pass valve program of the safeguard procedures is:80 degree of quick closing valve lasts 1.5s, and remaining 10 degree of slow passes are lasted 2.5s and closed, and close valve
4s is always lasted.Air relief valve pressure is Hair=1.329MPa, and the volume of pressurized tank of the present invention is 2.42m3.According to this side
The hydraulic hammer calculation result of case is as shown in Fig. 3~Fig. 7:
Can be seen that from Fig. 3~Fig. 7:Protecting water hammer effect of the present invention complies fully with the requirement of Code for design of pumping cstations i.e.:(point
The implication of Fig. 37 is not described)
From Fig. 3 minimax press packet winding thread change as can be seen that maximum pressure be not above exit of pump can level pressure
1.3~1.5 times of power, water-carriage system are not in water column fracture.
The maximum inversion speed that pump be can be seen that from Fig. 4 relative rotation speeds change line is not above 1.2 times of rated speed.
It is 1.06 times of normal pressure that exit of pump maximum pressure be can be seen that from Fig. 5 water pump discharge pressure head lines, far
It is less than 1.3~1.5 times.
The lowest water level of pressurized tank be can be seen that close to 0 from Fig. 6 air tank SEA LEVEL VARIATIONs, therefore pressurized tank volume takes
1.25 times of minimum volume.
It is 41.06Kg that air inflow in pressurized tank be can be seen that from the hollow gas mass-change curve of Fig. 7 pressurized tanks.
(1) maximum pressure is not to be exceeded 1.3~1.5 times of exit of pump rated pressure;
(2) should there is not water column fracture in any position of water-carriage system;
(3) centrifugal pump maximum inversion speed is not to be exceeded 1.2 times of rated speed;Exceed the persistent period of rated speed not
2min should be exceeded.
(4) 1.06 times for normal pressure of exit of pump maximum pressure, far smaller than 1.3~1.5 times of normal pressure;
(5) water pump assembly is reversed;
(6) there is negative pressure along full pipeline local, peak suction is -4.88m, and which is less than -7.5m, therefore will not produce
Raw water hammer due to cavities collapsing;
(7) lowest water level of novel air jar structure of the present invention is close to 0, of the present invention new in order to prevent
Air in type air jar structure is entered in main pipeline, and the volume of novel air jar structure of the present invention takes minimum volume
The volume of 1.25 times, i.e. air tank is 3.03m3;
(8) air inflow in novel air jar structure of the present invention is 41.06kg.
The above, the only specific embodiment of the present invention, but protection scope of the present invention is not limited thereto, any
Those familiar with the art the invention discloses technical scope in, change or replacement can be readily occurred in, should all be contained
Cover within protection scope of the present invention.Therefore, protection scope of the present invention described should be defined by scope of the claims.